output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
int const N = 11;
int v[N][N];
int main() {
int n;
cin >> n;
for (int i = 0; i < n; i++) v[0][i] = 1;
for (int i = 1; i < n; i++) {
v[i][0] = 1;
for (int j = 1; j < n; j++) v[i][j] = v[i][j - 1] + v[i - 1][j];
}
cout << v[n - 1][n - 1];
}
| ### Prompt
Please formulate a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
long long int fact(long long int n) {
if (n == 1)
return 1;
else
return n * fact(n - 1);
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
long long int n, a, b;
cin >> n;
if (n == 1) {
cout << 1 << "\n";
return 0;
}
a = fact(... | ### Prompt
Your task is to create a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
int n, a[11][11];
int main() {
cin >> n;
for (int i = 1; i <= n; ++i) a[1][i] = a[i][1] = 1;
for (int i = 2; i <= n; ++i)
for (int j = 2; j <= n; ++j) a[i][j] = a[i - 1][j] + a[i][j - 1];
cout << a[n][n] << endl;
}
| ### Prompt
Your challenge is to write a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int a[12][12];
int main() {
int n, m, i, j, sum;
while (scanf("%d", &n) != EOF) {
a[0][0] = 1;
for (i = 0; i < n; ++i) a[i][0] = a[0][i] = 1;
for (i = 1; i < n; ++i)
for (j = 1; j < n; ++j) a[i][j] = a[i - 1][j] + a[i][j - 1];
printf("%d\n", a[n - ... | ### Prompt
Develop a solution in Cpp to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
const int kMaxN = 11;
int n, a[kMaxN][kMaxN], ans;
int main() {
cin >> n;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
if (i == 1 || j == 1) {
a[i][j] = 1;
} else {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
}
... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, i, j, k, x, y;
cin >> n;
if (n == 1) {
cout << 1;
return 0;
} else if (n == 2) {
cout << 2;
return 0;
} else {
int ar[n + 1][n + 1];
for (i = 1; i <= n; i++) {
ar[i][1] = 1;
ar[1][i] = 1;
}
x = 2;
... | ### Prompt
Please formulate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
bool qf = false;
long long n, i, j, a[12][12];
int main() {
scanf("%lld", &n);
for (i = 1; i <= n; i++) a[1][i] = a[i][1] = 1;
for (i = 2; i <= n; i++) {
for (j = 2; j <= n; j++) a[i][j] = a[i - 1][j] + a[i][j - 1];
}
printf("%lld", a[n][n]);
return 0;
}
| ### Prompt
Please create a solution in Cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
long long fac(int n) {
if (n == 0) return 1;
return n * fac(n - 1);
}
int main() {
int n;
cin >> n;
n = (n - 1) * 2;
cout << fac(n) / (fac(n / 2) * fac(n / 2));
}
| ### Prompt
Your challenge is to write a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int map[12][12];
int n, m, i, j;
for (i = 0; i < 12; i++) map[0][i] = 1;
for (i = 0; i < 12; i++) map[i][0] = 1;
for (i = 1; i < 12; i++) {
for (j = 1; j < 12; j++) {
map[i][j] = map[i - 1][j] + map[i][j - 1];
}
}
scanf("%d", &n);
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
int a[12][12];
int main() {
int n, i, j;
while (scanf("%d", &n) != EOF) {
int maxi = 1;
for (i = 1; i <= n; i++) a[i][1] = a[1][i] = 1;
for (i = 2; i <= n; i++) {
for (j = 2; j <= n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
maxi = ma... | ### Prompt
Your task is to create a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, arr[10][10];
cin >> n;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == 0) {
arr[i][j] = 1;
} else if (j == 0) {
arr[i][j] = 1;
} else {
arr[i][j] = arr[i - 1][j] + arr[i][j - 1];
... | ### Prompt
Generate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
vector<vector<int> > board;
int main() {
int n;
cin >> n;
if (n == 1) cout << "1";
if (n == 2) cout << "2";
if (n == 3) cout << "6";
if (n == 4) cout << "20";
if (n == 5) cout << "70";
if (n == 6) cout << "252";
if (n == 7) cout << "924";
if (n == 8) cou... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
long long nCr(long long n, long long r) {
long long sum = 1, mn = min(r, (n - r));
for (long long i = n, j = 1; j <= mn; i--, j++) sum = (sum * i) / j;
return sum;
}
int main() {
long long n;
cin >> n;
long long ans = nCr(2 * (n - 1), (n - 1));
cout << ans << ... | ### Prompt
Construct a cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a[11][11] = {0}, n;
cin >> n;
for (int i = 0; i < n; i++) {
a[0][i] = 1;
a[i][0] = 1;
}
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
cout << a[n - 1][n - 1] << "\n";... | ### Prompt
Please provide a CPP coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int i, j, n;
int a[11][11];
cin >> n;
if (n == 1) {
cout << "1" << endl;
return 0;
}
for (i = 0; i < n; i++)
for (j = 0; j < n; j++) {
if (i == 0 || j == 0)
a[i][j] = 1;
else {
a[i][j] = a[i][j - 1] + a[i - 1]... | ### Prompt
Construct a Cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, sum = 0;
scanf("%d", &n);
if (n == 1) {
puts("1");
return 0;
}
if (n == 2) {
puts("2");
return 0;
}
if (n == 3) {
puts("6");
return 0;
}
if (n == 4) {
puts("20");
return 0;
}
if (n == 5) {
puts("7... | ### Prompt
Generate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int a[n][n];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (j == 0 || i == 0) {
a[i][j] = 1;
} else {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
}
cout << a[n - 1][n - 1] << e... | ### Prompt
Your task is to create a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
switch (n) {
case 1:
cout << 1;
break;
case 2:
cout << 2;
break;
case 3:
cout << 6;
break;
case 4:
cout << 20;
break;
case 5:
cout << 70;
break;
case 6:
... | ### Prompt
Develop a solution in cpp to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int i, j, t, k, c, cnt, n, d, d1, cnt1, l, sum;
cin >> t;
long long int a[t][t];
for (i = 1; i < t; i++) a[0][i] = 1;
for (i = 0; i < t; i++) a[i][0] = 1;
for (i = 1; i < t; i++) {
for (j = 1; j < t; j++) {
a[i][j] = a[i][j - 1] ... | ### Prompt
Please formulate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a[10][10];
for (int i = 0; i < 10; ++i)
for (int j = 0; j < 10; ++j) {
if (i == 0 || j == 0)
a[i][j] = 1;
else
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
int n;
cin >> n;
cout << a[n - 1][n - 1] << endl;
return 0;... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int ara[n][n];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == 0 || j == 0)
ara[i][j] = 1;
else
ara[i][j] = ara[i - 1][j] + ara[i][j - 1];
}
}
cout << ara[n - 1][n - 1] << end... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
void maxi() {
long long int n;
cin >> n;
long long int a[n][n];
for (long long int i = 0; i < n; i++) {
for (long long int j = 0; j < n; j++) {
if (i == 0 || j == 0) {
a[i][j] = 1;
} else {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int a[1000001];
int main() {
int x;
cin >> x;
if (x == 1) {
cout << "1";
}
if (x == 5) {
cout << "70";
}
if (x == 2) {
cout << "2";
}
if (x == 3) {
cout << "6";
}
if (x == 4) {
cout << "20";
}
if (x == 6) {
cout << "252";
... | ### Prompt
Create a solution in Cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int n;
int a[15][15];
int main() {
int i, j;
while (scanf("%d", &n) > 0) {
for (i = 1; i <= n; i++) {
for (j = 1; j <= n; j++) {
if (i == 1) {
a[i][j] = 1;
} else {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
... | ### Prompt
Please formulate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int i, j, t, k, c, cnt, n, d, d1, cnt1, l, sum;
cin >> t;
long long int a[t][t];
for (i = 0; i < t; i++) a[0][i] = 1;
for (i = 0; i < t; i++) a[i][0] = 1;
for (i = 1; i < t; i++) {
for (j = 1; j < t; j++) {
a[i][j] = a[i][j - 1] ... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, a = 1;
long long b = 1;
scanf("%d", &n);
for (int i = 1; i < n; i++) a *= i, b *= 2 * n - i - 1;
printf("%d", b / a);
}
| ### Prompt
In CPP, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
long long sum = 1;
cin >> n;
for (int i = 1; i < n; i++) {
sum = sum * (n + i - 1);
}
for (int i = 1; i < n; i++) {
sum = sum / i;
}
cout << sum;
return 0;
}
| ### Prompt
Generate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1e9 + 7;
const int N = 1e5 + 5;
int a[10][10];
int main() {
int n;
cin >> n;
for (int i = 1; i <= 10; i++) {
for (int j = 1; j <= 10; j++) {
a[i][1] = 1;
a[1][j] = 1;
}
}
for (int i = 2; i <= 10; i++) {
for (int j = 2;... | ### Prompt
Construct a cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
const int EPS = 1e-6;
const int INF = (int)(INT_MAX - 100);
const long long mod = (int)(1e+9 + 7);
const int N = (int)(0);
int main() {
int n;
cin >> n;
int t[n][n];
for (int it = 0; it < n; it++) {
t[it][0] = 1;
t[0][it] = 1;
}
for (int f = (1); f <= (n... | ### Prompt
Construct a cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, j, i, a[15][15];
cin >> n;
for (i = 0; i < n; i++)
for (j = 0; j < n; j++) a[i][j] = 1;
for (i = 1; i < n; i++)
for (j = 1; j < n; j++) a[i][j] = a[i - 1][j] + a[i][j - 1];
cout << a[n - 1][n - 1];
return 0;
}
| ### Prompt
Generate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
const int SZ = 52;
const double EPS = 1e-9;
const int MOD = 100000008;
const int INF = (1 << 30) - 1;
const double PI = 2 * acos(0.0);
template <class T>
T MIN(T a, T b) {
return (a < b) ? a : b;
}
template <class T>
T MAX(T a, T b) {
return (a > b) ? a : b;
}
template ... | ### Prompt
Please provide a cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
const int oo = (int)1e9;
const double PI = 2 * acos(0.0);
const double eps = 1e-9;
const int MAXN = 1e5 + 10;
int arr[100][100];
int main() {
std::ios_base::sync_with_stdio(false);
int n;
cin >> n;
for (int i = 0; i < n; i++) {
arr[i][0] = 1;
arr[0][i] = 1;
... | ### Prompt
Your task is to create a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
vector<long long int> V;
int main() {
long long int i, j, n, k, T, d1, d2, c = 0, m = 0;
cin >> n;
long long int A[11][11];
for (i = 1; i <= 10; i++) {
for (j = 1; j <= 10; j++) {
if (i == 1 || j == 1)
A[i][j] = 1;
else
A[i][j] = A[i ... | ### Prompt
Generate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, a[10][10], i, j;
cin >> n;
for (i = 0; i < n; i++) {
a[0][i] = 1;
}
for (i = 1; i < n; i++) {
a[i][0] = 1;
for (j = 1; j < n; j++) {
if (i > j)
a[i][j] = a[j][i];
else
a[i][j] = a[i - 1][j] + a[i][j - 1];... | ### Prompt
Generate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1e9 + 7;
signed main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
;
long long n;
cin >> n;
long long a[n + 5][n + 5];
for (long long i = 1; i <= n; i++) {
if (i == 1) {
for (long long j = 1; j <= n; j++) {
... | ### Prompt
Construct a CPP code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
int main(int argc, char const *argv[]) {
int n;
cin >> n;
int arr[n][n];
for (int i = 0; i < n; ++i) {
arr[i][0] = 1;
arr[0][i] = 1;
}
int max = 1;
for (int i = 1; i < n; ++i) {
for (int j = 1; j < n; ++j) {
arr[i][j] = arr[i - 1][j] + arr[i]... | ### Prompt
Develop a solution in Cpp to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
vector<vector<int>> v(n, vector<int>(n, 1));
for (int x = 1; x < n; x++)
for (int y = 1; y < n; y++) v[x][y] = v[x - 1][y] + v[x][y - 1];
cout << v[n - 1][n - 1] << endl;
}
| ### Prompt
In CPP, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
int main(void) {
int n;
scanf("%d", &n);
int ar[n][n];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == 0 || j == 0)
ar[i][j] = 1;
else
ar[i][j] = ar[i - 1][j] + ar[i][j - 1];
}
}
printf("%d\n", ar[n - 1][n - 1]);
return 0;
}... | ### Prompt
Generate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int arr[n][n];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == 0)
arr[0][j] = 1;
else if (j == 0)
arr[i][0] = 1;
else
arr[i][j] = arr[i - 1][j] + arr[i][j - 1];
}
... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
int main() {
int n, i, j;
scanf("%d", &n);
long int arr[n][n];
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
if (i == 0 || j == 0) {
arr[i][j] = 1;
} else {
arr[i][j] = arr[i - 1][j] + arr[i][j - 1];
}
}
}
printf("%ld", arr[n - 1][n - ... | ### Prompt
Construct a CPP code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
long long int fact(long long int n) {
long long int i = 1;
long long int prod = 1;
for (i = 1; i <= n; i++) {
prod = prod * i;
}
return prod;
}
int main() {
long long int n, i, prod, y;
prod = 1;
scanf("%lld", &n);
long long int x = 2 * (n - 1);
long long int l = n - 1;
... | ### Prompt
Generate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
int main() {
int i, j, n, max = 0;
scanf("%d", &n);
int a[n][n];
for (i = 0; i < n; i++)
for (j = 0; j < n; j++) {
if (i == 0 || j == 0)
a[i][j] = 1;
else
a[i][j] = a[i - 1][j] + a[i][j - 1];
int m = a[i][j];
max = max < m ? m : max;
}
p... | ### Prompt
Please create a solution in CPP to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int a[n][n];
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++) {
if (i == 0 || j == 0)
a[i][j] = 1;
else {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
cout << a[n - 1][n - 1];
return 0;
}... | ### Prompt
In CPP, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int x[10][10];
for (int i = 0; i < 10; i++) {
for (int j = 0; j < 10; j++) {
if (i == 0 || j == 0)
x[i][j] = 1;
else
x[i][j] = x[i - 1][j] + x[i][j - 1];
}
}
int n;
cin >> n;
cout << x[n - 1][n - 1] << endl;
}
| ### Prompt
Please formulate a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n;
scanf("%lld", &n);
long long x[n][n], y[n][n];
for (long long i = 0; i < 1; i++) {
for (long long j = 0; j < n; j++) x[i][j] = 1;
}
for (long long i = 0; i < n; i++) {
for (long long j = 0; j < 1; j++) y[i][j] = 1;
}
if (n =... | ### Prompt
Create a solution in cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int maxd, n, f[20][20];
int main() {
scanf("%d", &n);
for (int i = 1; i <= n; i++) f[i][1] = f[1][i] = 1;
maxd = 1;
for (int i = 2; i <= n; i++)
for (int j = 1; j <= n; j++)
f[i][j] = f[i - 1][j] + f[i][j - 1], maxd = max(f[i][j], maxd);
printf("%d\n", m... | ### Prompt
In CPP, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
int fun(int a, int b) {
if (a == 1 || b == 1)
return 1;
else
return fun(a - 1, b) + fun(a, b - 1);
}
int main() {
int n;
scanf("%d", &n);
printf("%d", fun(n, n));
}
| ### Prompt
Please create a solution in Cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int arr[n][n];
for (int x = 0; x < n; x++) {
arr[0][x] = 1;
}
for (int y = 0; y < n; y++) {
arr[y][0] = 1;
}
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
arr[i][j] = arr[i - 1][j] + arr[i][j - 1]... | ### Prompt
Please create a solution in cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, i, j;
cin >> n;
int a[n][n];
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
a[i][0] = 1;
a[0][j] = 1;
}
}
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
... | ### Prompt
Develop a solution in cpp to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int v[10] = {1, 2, 6, 20, 70, 252, 924, 3432, 12870, 48620};
int n;
cin >> n;
cout << v[n - 1];
return 0;
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int a[n + 5][n + 5];
for (int i = 0; i < n; i++) a[0][i] = 1;
for (int i = 0; i < n; i++) a[i][0] = 1;
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
a[i][j] = a[i][j - 1] + a[i - 1][j];
}
}
cout << a[... | ### Prompt
Please formulate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, i, j, k;
cin >> n;
int arr[n][n];
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
if (!i || !j) {
arr[i][j] = 1;
} else
arr[i][j] = 0;
}
}
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++) {
a... | ### Prompt
Please formulate a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int a[11][11];
for (int i = 1; i <= n; ++i) {
a[i][1] = 1;
a[1][i] = 1;
}
for (int i = 2; i <= n; ++i) {
for (int j = 2; j <= n; ++j) a[i][j] = a[i - 1][j] + a[i][j - 1];
}
cout << a[n][n];
}
| ### Prompt
Generate a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, i, j;
cin >> n;
int m[n][n];
for (i = 0; i < n; i++) {
m[i][0] = 1;
m[0][i] = 1;
}
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++) {
m[i][j] = m[i - 1][j] + m[i][j - 1];
}
}
cout << m[n - 1][n - 1];
return 0;
}
| ### Prompt
Create a solution in Cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
int main() {
int n, a[10], b[10], i = 0, t;
scanf("%d", &n);
for (i = 0; i < n; i++) {
a[i] = 1;
}
t = n;
while (n - 1) {
b[0] = 1;
for (i = 1; i < t; i++) {
b[i] = a[i] + b[i - 1];
}
for (i = 0; i < t; i++) {
a[i] = b[i];
}
n--;
}
printf(... | ### Prompt
Develop a solution in cpp to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int a[40][40];
int n;
int main() {
cin >> n;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
if (i == 1 || j == 1) {
a[i][j] = 1;
} else {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
}
cout << a[n][n] << endl;
;... | ### Prompt
In CPP, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
long long fact(long long i) {
if (i <= 0)
return 1;
else
return i * fact(i - 1);
}
long long comb(long long n, long long r) {
return fact(n) / (fact(r) * fact(n - r));
}
int main() {
int n;
cin >> n;
n--;
cout << comb(2 * n, n);
}
| ### Prompt
Develop a solution in CPP to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
const int N = 2e5 + 3;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
long long t, i, j, n, m, l, r;
cin >> n;
long long a[n + 1][n + 1];
for (i = 0; i < n; i++) a[0][i] = a[i][0] = 1;
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++... | ### Prompt
Generate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int nCn(int n, int r, vector<vector<int>>& dp) {
if (r == 0 || r == n) return 1;
if (n == 1) return 1;
if (dp[n][r] != -1) return dp[n][r];
dp[n][r] = nCn(n - 1, r - 1, dp) + nCn(n - 1, r, dp);
return dp[n][r];
}
int main() {
long long n;
cin >> n;
vector<ve... | ### Prompt
Construct a CPP code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
int main(int argc, char *argv[]) {
int i, n;
long long res = 1;
scanf("%d", &n);
for (i = n; i < 2 * n - 1; i++) res *= i;
for (i = 2; i < n; i++) res /= i;
printf("%d", res);
return 0;
}
| ### Prompt
Your challenge is to write a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int i, j, a;
scanf("%d", &a);
int n[a][a];
for (i = 0; i < a; i++) {
for (j = 0; j < a; j++) {
n[i][j] = 1;
}
}
for (i = 1; i < a; i++) {
for (j = 1; j < a; j++) {
n[i][j] = n[i - 1][j] + n[i][j - 1];
}
}
printf("%d\n... | ### Prompt
Generate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
long long C(long long n, long long r) {
if (r > n) return 0;
if (r == 1) return n;
if (r == 0) return 1;
return C(n - 1, r) + C(n - 1, r - 1);
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int n;
cin >> n;
if (n == 1)
cout << "1";
else {
co... | ### Prompt
Develop a solution in Cpp to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
long long int n, c = 0;
cin >> n;
long long int a[n][n], i, j;
for (i = 0; i < n; i++) {
a[i][0] = 1;
a[0][i] = 1;
}
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++)... | ### Prompt
Please create a solution in cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, i, j;
cin >> n;
int a[n][n];
for (i = 0; i < n; i++) {
a[0][i] = 1;
a[i][0] = 1;
}
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
cout << a[n - 1][n - 1];
return 0;
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
long long Cruz(int a, int b) {
long long p1 = 1, p2 = 1;
for (int i = 0; i < b; i++) p1 *= a - i;
for (int i = 0; i < b; i++) p2 *= i + 1;
return p1 / p2;
}
int main() {
int n;
cin >> n;
if (n >= 1 && n <= 10) {
cout << Cruz(2 * n - 2, n - 1);
}
return... | ### Prompt
Create a solution in Cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int i, j, n, ar[11][11] = {};
cin >> n;
for (i = 1; i <= n; i++) {
for (j = 1; j <= n; j++) {
if ((i == 1) || (i == 2 && j == 1))
ar[i][j] = 1;
else
ar[i][j] = ar[i - 1][j] + ar[i][j - 1];
}
}
cout << ar[n][n] << en... | ### Prompt
Your task is to create a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
int solve(int i, int j) {
if (i == 1 || j == 1)
return 1;
else
return solve(i - 1, j) + solve(i, j - 1);
}
int main() {
int n;
scanf("%d", &n);
printf("%d\n", solve(n, n));
return 0;
}
| ### Prompt
Construct a cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int n, i, j;
long long int ar[100][100];
cin >> n;
for (i = 0; i < n; i++) {
ar[0][i] = 1;
ar[i][0] = 1;
}
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++) {
ar[i][j... | ### Prompt
Please formulate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
template <typename T>
T in() {
char ch;
T n = 0;
bool ng = false;
while (1) {
ch = getchar();
if (ch == '-') {
ng = true;
ch = getchar();
break;
}
if (ch >= '0' && ch <= '9') break;
}
while (1) {
n = n * 10 + (ch - '0');
ch = getchar();
... | ### Prompt
Generate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int tab[11][11];
int main() {
int n;
cin >> n;
tab[0][1] = 1;
for (int i = 1; i <= n; ++i) {
for (int j = 1; j <= n; ++j) {
tab[i][j] = tab[i - 1][j] + tab[i][j - 1];
}
}
cout << tab[n][n];
}
| ### Prompt
In CPP, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a[100][100];
int n;
cin >> n;
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
if (i == 1) {
a[i][j] = 1;
} else if (j == 1) {
a[i][j] = 1;
} else {
a[i][j] = a[i - 1][j] + a[i][j - 1];
... | ### Prompt
Please provide a cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
vector<pair<long long, long long> > vp;
vector<long long> v;
set<long long> st;
long long ara[100][100];
map<long long, long long> mp;
long long Set(long long N, long long pos) { return N = N | (1LL << pos); }
long long reset(long long N, long long pos) { return N = N & ~(1... | ### Prompt
Please formulate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int arr[n][n];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == 0 || j == 0) {
arr[i][j] = 1;
} else {
arr[i][j] = arr[i - 1][j] + arr[i][j - 1];
}
}
}
cout << arr[n - 1]... | ### Prompt
In cpp, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
int main() {
int n;
int i, j;
int *table;
scanf("%d", &n);
table = (int *)malloc(n * n * sizeof(int));
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
if (i == 0 || j == 0)
*(table + i * n + j) = 1;
else
*(table + i * n + j) =
*(table ... | ### Prompt
Create a solution in CPP for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int arr[10][10];
int main() {
ios_base::sync_with_stdio(0);
int n;
cin >> n;
for (int i = 0; i < n; ++i) {
arr[0][i] = 1;
arr[i][0] = 1;
}
for (int i = 1; i < n; ++i)
for (int j = 1; j < n; ++j) arr[i][j] = arr[i - 1][j] + arr[i][j - 1];
cout << ar... | ### Prompt
Develop a solution in CPP to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, N, fact1 = 1, fact2 = 1, i;
cin >> n;
if (n == 0)
N = 1;
else
N = (n - 1) * 2;
for (i = 2; i <= N; ++i) {
fact1 *= i;
if (i < n) fact2 *= i;
}
cout << fact1 / (fact2 * fact2);
return 0;
}
| ### Prompt
Construct a Cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
long long fact(long long n) {
long long ret = 1;
for (long long i = 2; i <= n; i++) ret *= i;
return ret;
}
long long combinari(long long n, long long k) {
return fact(n) / fact(k) / fact(n - k);
}
long long n;
int main() {
cin >> n;
cout << combinari(2 * (n - 1... | ### Prompt
Construct a cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
using ull = unsigned long long;
using lln = long long int;
using ls = string;
using ch = char;
using lld = long double;
using lf = float;
using ll = int;
using ld = double;
int a, arr[10][10];
void solve() {
cin >> a;
for (int i = 0; i < a; i++) {
for (int j = 0; j ... | ### Prompt
In CPP, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
int a[20][20];
int main() {
int n;
scanf("%d", &n);
int res = 1;
for (int i = 1; i <= n; ++i) a[1][i] = 1, a[i][1] = 1;
for (int i = 2; i <= n; ++i)
for (int j = 2; j <= n; ++j)
res = max(res, a[i][j] = a[i - 1][j] + a[i][j - 1]);
printf("%d\n", res);
... | ### Prompt
Develop a solution in cpp to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int a[123][123];
int main() {
int n;
cin >> n;
if (n == 1) {
cout << "1" << endl;
return 0;
}
for (int i = 1; i <= n; i++) {
if (i == 1)
for (int j = 1; j <= n; j++) {
a[i][j] = 1;
}
else
a[i][1] = 1;
}
int p;
for (i... | ### Prompt
In CPP, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
int f(int x, int y) {
if (x == 1 || y == 1)
return 1;
else
return f(x - 1, y) + f(x, y - 1);
}
int main() {
int n;
cin >> n;
cout << f(n, n);
}
| ### Prompt
Your task is to create a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
template <typename T>
inline void checkMin(T &a, T b) {
if (b < a) a = b;
}
template <typename T>
inline void checkMax(T &a, T b) {
if (a < b) a = b;
}
int main() {
int n, a[11][11];
scanf("%d", &n);
for (int i = 1; i <= n; ++i) {
for (int j = 1; j <= n; ++j) ... | ### Prompt
Your task is to create a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int i = 1, j, k = 0, l, m = 0, c, n;
cin >> n;
int a[n][n];
for (i = 0; i < n; i++) {
a[0][i] = 1;
}
i = 0;
for (i = 0; i < n; i++) {
a[i][0] = 1;
}
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++) {
a[i][j] = a[i]... | ### Prompt
In cpp, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
int main() {
int x;
int arr[] = {1, 2, 6, 20, 70, 252, 924, 3432, 12870, 48620};
scanf("%d", &x);
printf("%d", arr[x - 1]);
}
| ### Prompt
Please create a solution in CPP to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int n, a[15][15];
int main() {
ios::sync_with_stdio(false), cout.tie(NULL), cin.tie(NULL);
;
scanf("%d", &(n));
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == 0 || j == 0) {
a[i][j] = 1;
continue;
}
a[i][j]... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
const long long INF = 1LL << 61;
int n;
int x[15][15];
int main() {
memset(x, 0, sizeof(x));
for (int i = 1; i <= 10; i++) x[i][1] = x[1][i] = 1;
for (int i = 2; i <= 10; i++) {
for (int j = 2; j <= 10; j++) {
x[i][j] = x[i - 1][j] + x[i][j - 1];
}
}
... | ### Prompt
Please provide a CPP coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
vector<long long> v;
int main() {
long long n;
cin >> n;
long long f[n][n];
for (int j = 1; j < n; j++) {
f[0][j] = 1;
}
for (int j = 0; j < n; j++) {
f[j][0] = 1;
}
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
f[i][j] = f[i ... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int a[10 + 10][10 + 10];
int main() {
int n;
scanf("%d", &n);
for (int i = 1; i <= n; i++) a[i][1] = a[1][i] = 1;
for (int i = 2; i <= n; ++i)
for (int j = 2; j <= n; ++j) a[i][j] = a[i - 1][j] + a[i][j - 1];
cout << a[n][n] << endl;
}
| ### Prompt
Please provide a CPP coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n;
cin >> n;
vector<vector<int> > a(n, vector<int>(n));
for (int i = 0; i < n; i++) a[i][0] = 1, a[0][i] = 1;
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
a[i][j... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int a[100][100];
int main() {
ios_base::sync_with_stdio(false);
int n;
cin >> n;
for (int i = 1; i <= n; i++) {
a[1][i] = 1;
a[i][1] = 1;
}
int mx = 1;
for (int i = 2; i <= n; i++) {
for (int j = 2; j <= n; j++) {
a[i][j] = a[i - 1][j] + a[i]... | ### Prompt
Create a solution in CPP for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
const int NMax = 1e5 + 5;
const int LIM = 1e5;
int D[100][100];
int main() {
int n;
cin >> n;
for (int i = 1; i <= n; i++) {
D[1][i] = D[i][1] = 1;
}
for (int i = 2; i <= n; i++) {
for (int j = 2; j <= n; j++) {
D[i][j] = D[i - 1][j] + D[i][j - 1];
... | ### Prompt
Please formulate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int aa[10][10];
for (int j = 0; j < 10; j++) {
aa[0][j] = 1;
aa[j][0] = 1;
}
for (int l = 1; l < 10; l++) {
for (int t = 1; t < 10; t++) {
aa[l][t] = aa[l - 1][t] + aa[l][t - 1];
}
}
int i;
while (cin >> i) {
cout << aa[i... | ### Prompt
Your task is to create a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
int ar(int i, int j) {
if (j == 1 || i == 1)
return 1;
else
return ar(i - 1, j) + ar(i, j - 1);
}
int main() {
int n;
scanf("%d", &n);
printf("%d\n", ar(n, n));
return 0;
}
| ### Prompt
Your challenge is to write a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int a[15][15];
for (int i = 1; i <= 1; i++) {
for (int j = 1; j <= n; j++) a[i][j] = 1;
}
for (int i = 2; i <= n; i++) {
a[i][1] = 1;
for (int j = 2; j <= n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
... | ### Prompt
Please create a solution in cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, i, j, a[10][10];
cin >> n;
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
a[i][0] = 1;
a[0][j] = 1;
}
}
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
cout... | ### Prompt
Your task is to create a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
int tab[10][10];
cin >> n;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == 0) {
tab[i][j] = 1;
} else if (j == 0) {
tab[i][j] = 1;
} else {
tab[i][j] = tab[i - 1][j] + tab[i][j - ... | ### Prompt
Create a solution in Cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
int main() {
int n;
int i, j;
int table[10][10];
scanf("%d", &n);
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
if (i == 0 || j == 0)
table[i][j] = 1;
else
table[i][j] = table[i][j - 1] + table[i - 1][j];
}
}
printf("%d", table[i - 1][j - ... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
int main() {
int n, i = 0, j = 0;
scanf("%d", &n);
int a[11][11];
for (i = 0; i < n; i++) a[i][0] = 1;
for (j = 0; j < n; j++) a[0][j] = 1;
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
printf("%d\n", a[n - 1][n - 1]);... | ### Prompt
Construct a cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
int arr[11][11];
using namespace std;
int main() {
int n;
cin >> n;
for (int i = 1; i <= n; i++) {
arr[1][i] = 1;
arr[i][1] = 1;
}
for (int i = 2; i <= n; i++) {
for (int j = 2; j <= n; j++) {
arr[i][j] = arr[i - 1][j] + arr[i][j - 1];
}
}
cout << arr[n][n];
... | ### Prompt
Develop a solution in CPP to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int a, m[20][20];
int main() {
ios_base::sync_with_stdio(0), cin.tie(0), cout.tie(0);
cin >> a;
for (int i = 1; i <= a; i++) {
m[1][i] = 1;
m[i][1] = 1;
}
for (int i = 2; i <= a; i++) {
for (int j = 2; j <= a; j++) {
m[i][j] = m[i - 1][j] + m[i][... | ### Prompt
Create a solution in CPP for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
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