output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
const int inf = 25;
int a[inf][inf]{0, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1};
int main() {
int n, m, i, j, k;
a[1][0] = 0;
for (i = 0; i <= 10; i++) {
for (j = 0; j <= 10; j++) {
a[i + 1][j + 1] = a[i][j + 1] + a[i + 1][j];
}
}
while (cin >> k) {
cout <<... | ### Prompt
Please provide a cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a[100][100], i, j, n, max;
i = 0;
j = 0;
cin >> n;
max = 0;
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
if (i == 0 || j == 0)
a[i][j] = 1;
else
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
for (i = 0; ... | ### Prompt
Create a solution in CPP for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int a[19][19];
int n;
int main() {
cin >> n;
for (int i = 1; i <= n; i++) {
a[i][1] = 1;
a[1][i] = 1;
}
for (int i = 2; i <= n; i++) {
for (int j = 2; j <= n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
cout << a[n][n];
return 0;
}
| ### Prompt
Develop a solution in CPP to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int a, arr[10][10];
int main() {
cin >> a;
for (int i = 0; i < a; i++) {
for (int j = 0; j < a; j++) {
if (i == 0) {
arr[i][j] = 1;
} else if (j == 0) {
arr[i][j] = 1;
} else {
arr[i][j] = arr[i - 1][j] + arr[i][j - 1];
... | ### Prompt
Please formulate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int a[11][11];
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++) a[i][j] = 1;
for (int i = 1; i < n; i++)
for (int j = 1; j < n; j++) a[i][j] = a[i - 1][j] + a[i][j - 1];
cout << a[n - 1][n - 1] << endl;
return 0;
}
| ### Prompt
Create a solution in Cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
long long int mod = 10000007;
long long int a[200][200];
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
long long int n, m, x, t, i, j, sum = 0;
cin >> n;
for (i = 1; i <= n; i++)
for (j = 1; j <= n; j++) {
if (i == 1 || ... | ### Prompt
Develop a solution in CPP to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, a[10][10], max = 0;
cin >> n;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == 0 || j == 0)
a[i][j] = 1;
else
a[i][j] = a[i - 1][j] + a[i][j - 1];
if (a[i][j] > max) max = a[i][j];
}
}... | ### Prompt
In CPP, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
int a[1001][1001];
int main() {
int n;
scanf("%d", &n);
for (int i = 1; i <= n; i++) {
a[i][1] = 1;
a[1][i] = 1;
}
for (int i = 2; i <= n; i++) {
for (int j = 2; j <= n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
printf("%d", a[n][n]... | ### Prompt
Construct a cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
const int inf = 1e9 + 100500;
const int maxn = 100500;
int arr[100][100];
int main() {
int n;
cin >> n;
if (n == 1) {
cout << "1" << endl;
return 0;
}
for (int i = 0; i < n; i++) {
arr[0][i] = 1;
}
for (int i = 0; i < n; i++) arr[i][0] = 1;
for (... | ### Prompt
Please formulate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int a[n][n];
for (int i = 1; i <= n; i++) {
a[1][i] = 1;
a[i][1] = 1;
}
if (n == 9)
cout << 12870;
else if (n == 10)
cout << 48620;
else {
for (int i = 2; i <= n; i++) {
for (int j = 2; j <= n; j++) a[i... | ### Prompt
Please create a solution in cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
int main() {
int n;
scanf("%d", &n);
if (n == 1) {
printf("1");
}
if (n == 2) {
printf("2");
}
if (n == 3) {
printf("6");
}
if (n == 4) {
printf("20");
}
if (n == 5) {
printf("70");
}
if (n == 6) {
printf("252");
}
if (n == 7) {
printf("... | ### Prompt
Your task is to create a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long x, z, ar[100000] = {1}, sum = 0, res = 0;
cin >> x;
for (int i = 0; i < x; i++) {
ar[i] = 1;
}
for (int i = 2; i <= x; i++) {
for (int j = 1; j <= x; j++) {
sum += ar[j];
ar[j] = sum;
}
sum = 0;
}
cout << ar[x... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int a[100][100];
int main() {
cin.tie(0);
ios::sync_with_stdio(false);
cout.setf(ios::fixed);
cout.precision(20);
int n;
cin >> n;
for (int i = (0); i < (int)(n); ++i)
for (int j = (0); j < (int)(n); ++j)
if (!i || !j) a[i][j] = 1;
for (int i = (0)... | ### Prompt
Create a solution in Cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
long long factorial(long long n) {
return (n == 1 || n == 0) ? 1 : factorial(n - 1) * n;
}
int main() {
ios_base::sync_with_stdio(false);
int n;
cin >> n;
if (n == 1)
cout << 1;
else if (n == 2)
cout << 2;
else
cout << factorial(2 * n - 2) / (facto... | ### Prompt
Please provide a cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a[20][20];
int n;
int i, j;
scanf("%d", &n);
for (i = 0; i < n; i++) a[0][i] = 1;
for (i = 0; i < n; i++) a[i][0] = 1;
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
cout ... | ### Prompt
Your task is to create a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a[14][14], n;
cin >> n;
for (int i = 1; i <= n; i++) {
a[1][i] = 1;
a[i][1] = 1;
}
for (int i = 2; i <= n; i++) {
for (int k = 2; k <= n; k++) {
a[i][k] = a[i][k - 1] + a[i - 1][k];
}
}
cout << a[n][n];
return 0;
}
| ### Prompt
Construct a Cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int arr[n][n];
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
if (!i || !j)
arr[i][j] = 1;
else
arr[i][j] = arr[i - 1][j] + arr[i][j - 1];
cout << arr[n - 1][n - 1];
}
| ### Prompt
Generate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
int main() {
int n;
std::cin >> n;
int a[n][n];
for (int i = 0; i < n; ++i) {
a[0][i] = 1;
}
for (int i = 0; i < n; ++i) {
a[i][0] = 1;
}
for (int i = 1; i < n; ++i) {
for (int j = 1; j < n; ++j) a[i][j] = a[i - 1][j] + a[i][j - 1];
}
std::cout << a[n - 1][n - 1]... | ### Prompt
Construct a Cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
int main() {
int i, j, n;
scanf("%d", &n);
int a[50][50];
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
if (i == 0 || j == 0) {
a[i][j] = 1;
} else {
a[i][j] = 0;
}
}
}
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++) {
a[i]... | ### Prompt
Please create a solution in cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int m[11][11];
for (int i = 1; i < 11; i++) {
for (int j = 1; j < 11; j++) {
if (i == 1 || j == 1)
m[i][j] = 1;
else
m[i][j] = m[i][j - 1] + m[i - 1][j];
}
}
int n;
cin >> n;
cout << m[n][n];
}
| ### Prompt
Generate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
long long cal_n(long long n) {
long long temp = 1;
for (long long i = 2; i <= n; i++) temp = temp * i;
return temp;
}
long long nCr(long long n, long long r) {
return cal_n(n) / (cal_n(r) * cal_n(n - r));
}
void solve() {
long long n;
cin >> n;
long long m = n... | ### Prompt
Generate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
int a[15][15];
scanf("%d", &n);
for (int i = 1; i <= n; i++) {
a[i][1] = 1;
a[1][i] = 1;
}
for (int i = 2; i <= n; i++)
for (int j = 2; j <= n; j++) a[i][j] = a[i - 1][j] + a[i][j - 1];
printf("%d\n", a[n][n]);
}
| ### Prompt
In cpp, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
int a[11][11];
int main() {
int n;
scanf("%d", &n);
for (int i = 1; i <= n; i++) {
a[1][i] = a[i][1] = 1;
}
for (int i = 2; i <= n; i++) {
for (int j = 2; j <= n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
printf("%d", a[n][n]);
return... | ### Prompt
Create a solution in cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
if (n == 1) {
cout << "1" << endl;
}
if (n == 2) {
cout << "2" << endl;
}
if (n == 3) {
cout << "6" << endl;
}
if (n == 4) {
cout << "20" << endl;
}
if (n == 5) {
cout << "70" << endl;
}
if (n == 6)... | ### Prompt
Create a solution in CPP for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a;
cin >> a;
int ara[a][a];
for (int l = 0; l < a; l++) {
ara[0][l] = 1;
ara[l][0] = 1;
}
for (int l = 1; l < a; l++) {
for (int l1 = 1; l1 < a; l1++) {
ara[l][l1] = ara[l][l1 - 1] + ara[l - 1][l1];
}
}
cout << ara[a - ... | ### Prompt
Develop a solution in CPP to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
long long fact(int a) {
long long x = 1;
for (int i = 2; i <= a; i++) {
x *= i;
}
return x;
}
long long entekhab(int a, int b) {
long long x = fact(b), y = fact(a), z = fact(b - a);
return x / (y * z);
}
int main() {
int n;
cin >> n;
cout << entekhab(n... | ### Prompt
Construct a Cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
int main(void) {
int n, a[12][12];
cin >> n;
memset(a, 0, sizeof(a));
for (int i = 1; i <= n; i++) {
a[1][i] = 1;
a[i][1] = 1;
}
for (int i = 2; i <= n; i++) {
for (int j = 2; j <= n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
cout... | ### Prompt
Generate a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
a[i] = 1;
}
for (int i = 0; i < n - 1; i++) {
for (int j = 1; j < n; j++) {
a[j] += a[j - 1];
}
}
cout << a[n - 1] << endl;
}
| ### Prompt
Please create a solution in CPP to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
int main() {
int n;
scanf("%d", &n);
int a[n][n];
int i, j;
for (i = 0; i < n; i++) {
a[0][i] = 1;
}
for (i = 1; i < n; i++) {
a[i][0] = 1;
}
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++) {
a[i][j] = a[i][j - 1] + a[i - 1][j];
}
}
printf("%d\n", a... | ### Prompt
Please formulate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int s[100][100];
int main() {
int n, i, j;
scanf("%d", &n);
for (i = 1; i <= n; i++) {
for (j = 1; j <= n; j++) {
if (i == 1)
s[i][j] = 1;
else
s[i][j] = s[i - 1][j] + s[i][j - 1];
}
}
int max = 0;
for (i = 1; i <= n; i++) {
... | ### Prompt
Your task is to create a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
int a[20][20];
int main() {
int n;
scanf("%d", &n);
int i, j;
for (i = 1; i <= n; i++) a[1][i] = 1;
for (i = 1; i <= n; i++) a[i][1] = 1;
int mx = 1;
for (i = 2; i <= n; i++)
for (j = 2; j <= n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
mx = ... | ### Prompt
Generate a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int a[20][20];
int main() {
int n;
cin >> n;
for (int i = 0; i < n; i++) a[i][0] = 1, a[0][i] = 1;
for (int i = 1; i < n; i++)
for (int j = 1; j < n; j++) a[i][j] = a[i - 1][j] + a[i][j - 1];
printf("%d\n", a[n - 1][n - 1]);
return 0;
}
| ### Prompt
In CPP, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
int main() {
int n;
scanf("%d", &n);
int num_list[n], num_list_new[n], i, j, k;
for (i = 0; i < n; i++) {
num_list[i] = 1;
}
k = n;
for (k = 1; k < n; k++) {
for (i = 0; i < n; i++) {
for (j = i; j >= 0; j--) {
if (j == i) {
num_list_new[i] = 0;
... | ### Prompt
Develop a solution in cpp to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long x, z, ar[100000], sum, res = 0;
cin >> x;
if (x == 1) cout << 1;
if (x == 2) cout << 2;
if (x == 3) cout << 6;
if (x == 4) cout << 20;
if (x == 5) cout << 70;
if (x == 6) cout << 252;
if (x == 7) cout << 924;
if (x == 8) cout << 34... | ### Prompt
Please provide a cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
const long long mod = 1e9 + 7;
using namespace std;
int c = 0;
void solve() {
int n, k = 0;
cin >> n;
vector<vector<int>> a(10, vector<int>(10, -1));
a[0][0] = 1;
for (int i = 1; i < 10; i++) {
a[0][i] = 1;
a[i][0] = 1;
}
for (int i = 1; i < n; i++) {
for (int j = i; j... | ### Prompt
Create a solution in CPP for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
long long a[12][12] = {0};
long long ans = 0;
int main() {
int n, i, j;
cin >> n;
for (i = 1; i <= n; i++) {
for (j = 1; j <= n; j++) {
if (i == 1 || j == 1) {
a[i][j] = 1;
} else {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
ans... | ### Prompt
Create a solution in CPP for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int a[n][n];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == 0 || j == 0)
a[i][j] = 1;
else
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
cout << a[n - 1][n - 1] << "\n";
}
| ### Prompt
Your challenge is to write a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int A[10][10];
int n;
int m = 0;
cin >> n;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == 0 || j == 0) {
A[i][j] = 1;
} else {
A[i][j] = A[i - 1][j] + A[i][j - 1];
}
}
}
for (int i = ... | ### Prompt
Please formulate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int a;
cin >> a;
if (a <= 1) {
cout << a;
} else if (a == 2) {
cout << 2;
} else if (a == 3) {
cout << 6;
} else if (a == 4) {
cout << 20;
} else if (a == 5) {
cout << 70;
} else if (a == 6) {
cout << 252;
} e... | ### Prompt
Create a solution in CPP for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int i, j, t, k, c, cnt, n, d, d1, cnt1, l, sum;
cin >> t;
long long int a[t][t];
for (i = 0; i < t; i++) {
for (j = 0; j < t; j++) {
a[0][j] = 1;
a[i][0] = 1;
}
}
for (i = 1; i < t; i++) {
for (j = 1; j < t; j++) {
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
int n;
int a[15][15];
void dp() {
for (int i = 1; i <= n; i++) a[i][1] = 1;
for (int j = 1; j <= n; j++) a[1][j] = 1;
for (int i = 2; i <= n; i++) {
for (int j = 2; j <= n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
}
int main() {
scanf("%d", &n);
dp();
printf("... | ### Prompt
Your task is to create a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
int arr[11][11];
int main() {
int n;
cin >> n;
for (int i = 1; i <= n; i++) {
arr[1][i] = 1;
}
for (int i = 2; i <= n; i++) {
for (int j = 1; j <= n; j++) {
arr[i][j] = arr[i - 1][j] + arr[i][j - 1];
}
}
cout << arr[n][n] << endl;
return 0;... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int ele(int row, int col) {
if (row == 1 || col == 1) return 1;
return ele(row - 1, col) + ele(row, col - 1);
}
int main() {
ios_base ::sync_with_stdio(false), cin.tie(NULL), cout.tie(0);
int i;
cin >> i;
cout << ele(i, i);
return 0;
}
| ### Prompt
Construct a CPP code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
int f(int x, int y) {
if (x == 1 || y == 1)
return 1;
else
return f(x - 1, y) + f(x, y - 1);
}
int main() {
int n;
while (cin >> n) {
cout << f(n, n) << endl;
}
return 0;
}
| ### Prompt
In cpp, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, s, m = 0;
cin >> n;
int a[n][n];
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (n == 1 || m == 1) {
a[i][j] = 1;
} else {
a[0][j] = 1;
a[i][0] = 1;
a[i][j] = a[i - 1][j] + a[i][j - ... | ### Prompt
Generate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int grid[11][11];
int main() {
setvbuf(stdout, NULL, _IONBF, 0);
int n;
scanf("%d", &n);
for (int i = 0; i <= n; ++i) {
grid[i][0] = 1;
grid[0][i] = 1;
}
for (int i = 1; i <= n; ++i) {
for (int j = 1; j <= n; ++j) {
grid[i][j] = grid[i - 1][j] ... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int a[11][11] = {0};
for (int i = 0; i < n; i++) {
a[i][0] = 1;
a[0][i] = 1;
}
int maxx = 1;
for (int j = 1; j < n; j++)
for (int i = 1; i < n; i++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
if (a[i][j] > maxx... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
int arr[1000][1000];
int main() {
int m, n, i, j, k;
int v;
scanf("%d", &n);
v = n - 1;
for (i = 0; i < n; i++) {
arr[i][0] = 1;
arr[0][i] = 1;
}
for (k = 1; k < n; k++) {
for (j = 1; j < n; j++) {
arr[k][j] = arr[k - 1][j] + arr[k][j - 1];
}
}
printf("%d... | ### Prompt
Generate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
int main() {
int n, arr[10][10] = {
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1}, {1, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{1, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {1, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{1, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {1, 0, 0, 0, 0, 0, 0, 0, 0, 0},
{1, 0, 0, 0, ... | ### Prompt
Create a solution in cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
long long int fact(long long int a) {
if (a == 0) {
return 1;
}
return a * fact(a - 1);
}
int main() {
long long int i, x, n;
scanf("%I64d", &n);
x = (n - 1) * 2;
i = fact(x) / (fact(x / 2) * fact(x / 2));
printf("%I64d\n", i);
return 0;
}
| ### Prompt
Please formulate a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int n;
cin >> n;
int num[n][n];
for (int i = 0; i < n; i++) {
num[0][i] = 1;
num[i][0] = 1;
}
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
num[i]... | ### Prompt
Please create a solution in Cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
int main() {
int n, i, j,
a[11][11] = {
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1}, {1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1}, {1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
{1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1}, {1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1},
... | ### Prompt
Construct a cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
vector<vector<int> > a;
a.resize(n, vector<int>(n, 1));
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
cout << a[n - 1][n - 1];
}
| ### Prompt
Please create a solution in cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int numbers[10][10], n;
cin >> n;
for (int i = 0; i < n; i++)
for (int j = 0; j < n; j++)
if (i == 0 || j == 0)
numbers[i][j] = 1;
else
numbers[i][j] = numbers[i - 1][j] + numbers[i][j - 1];
cout << numbers[n - 1][n - 1];... | ### Prompt
Please formulate a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int n, a[100][100]{};
int main() {
cin >> n;
for (int i = 0; i < n; i++) a[i][0] = a[0][i] = 1;
for (int i = 1; i < n; i++)
for (int j = 1; j < n; j++) a[i][j] = a[i - 1][j] + a[i][j - 1];
cout << a[n - 1][n - 1];
}
| ### Prompt
Create a solution in Cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int a[n][n];
for (int i = 0; i < n; i++) a[0][i] = 1, a[i][0] = 1;
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) a[i][j] = a[i - 1][j] + a[i][j - 1];
}
cout << a[n - 1][n - 1];
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, i, j;
cin >> n;
int arr[n][n];
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
if (i == 0 || j == 0) {
arr[i][j] = 1;
} else {
arr[i][j] = 0;
}
}
}
for (i = 0; i < n; i++) {
for (j = 0; j < n;... | ### Prompt
Develop a solution in cpp to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
long long x;
long long factorial(int n) {
return (n == 1 || n == 0) ? 1 : factorial(n - 1) * n;
}
int main() {
long long n;
cin >> n;
--n;
cout << factorial(2 * n) / (factorial(n) * factorial(n));
return 0;
}
| ### Prompt
Please create a solution in Cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
int a[100][100];
cin >> n;
for (int i = 0; i < n; ++i) {
a[0][i] = 1;
a[i][0] = 1;
}
for (int i = 1; i < n; ++i) {
for (int j = 1; j < n; ++j) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
cout << a[n - 1][n - 1] << end... | ### Prompt
Construct a CPP code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int m[n][n];
long long sum = 0;
for (int i = 0; i < n; i++) {
m[0][i] = 1;
m[i][0] = 1;
}
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
m[i][j] = m[i - 1][j] + m[i][j - 1];
}
}
cout << m[n -... | ### Prompt
Generate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long int n, t, a[10] = {1, 2, 6, 20, 70, 252, 924, 3432, 12870, 48620};
cin >> n;
cout << a[n - 1];
}
| ### Prompt
In cpp, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
int main() {
int a[12][12] = {0};
int n;
int i, j;
while (scanf("%d", &n) != EOF) {
for (i = 1; i <= n; i++) {
a[1][i] = 1;
}
for (i = 2; i <= n; i++) {
for (j = 1; j <= n; j++) {
a[i][j] = a[i][j - 1] + a[i - 1][j];
}
}
printf("%d\n", a[n][... | ### Prompt
Your task is to create a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
const double PI = acos(-1.0);
const unsigned long long MAX = LONG_MAX;
unsigned long long in() {
unsigned long long a;
scanf("%llu", &a);
return a;
}
double din() {
double a;
scanf("%lf", &a);
return a;
}
long long gcd(long long a, long long b) {
if (b == 0)
... | ### Prompt
Please create a solution in Cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n;
cin >> n;
long long a[n][n];
for (int j = 0; j < n; j++) {
a[0][j] = 1;
}
for (int i = 0; i < n; i++) {
a[i][0] = 1;
}
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1]... | ### Prompt
Generate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int n, m, i, j, k, x, y, z;
int ret;
int a[11][11];
int main() {
cin >> n;
for (i = 1; i <= n; i++)
for (j = 1; j <= n; j++) {
if (i == 1 || j == 1)
a[i][j] = 1;
else
a[i][j] = a[i - 1][j] + a[i][j - 1];
ret = max(ret, a[i][j]);
... | ### Prompt
Create a solution in cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int a[11][11];
int main() {
int n;
memset(a, 0, sizeof(a));
for (int i = 1; i <= 10; ++i) a[1][i] = 1;
for (int i = 2; i <= 10; ++i) {
a[i][1] = 1;
for (int j = 2; j <= 10; ++j) a[i][j] = a[i - 1][j] + a[i][j - 1];
}
while (cin >> n) cout << a[n][n] << e... | ### Prompt
Please create a solution in CPP to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
long long int f(int n) { return ((n == 0) ? 1 : (n * f(n - 1))); }
int main() {
int n;
cin >> n;
n--;
cout << f(2 * n) / (f(n) * f(n)) << endl;
}
| ### Prompt
Please create a solution in Cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
int b[12][12];
int main() {
int a;
int i, j;
int sum;
scanf("%d", &a);
memset(b, 0, sizeof(b));
for (i = 1; i <= 10; i++)
for (j = 1; j <= 10; j++) {
b[1][j] = b[i][1] = 1;
b[i][j] = b[i - 1][j] + b[i][j - 1];
}
printf("%d", b[a][a]);
}
| ### Prompt
Please provide a CPP coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, i = 0, j = 0;
cin >> n;
int a[n][n];
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
if (i == 0 || j == 0) {
a[i][j] = 1;
} else {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
}
cout << a[n - 1][n - 1... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int tt[15][15];
int main() {
int n;
for (int i = 1; i <= 15; i++) {
tt[1][i] = 1;
tt[i][1] = 1;
}
for (int i = 2; i <= 15; i++) {
for (int j = 2; j <= 15; j++) {
tt[i][j] = tt[i - 1][j] + tt[i][j - 1];
}
}
while (~scanf("%d", &n)) {
pri... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a;
cin >> a;
int c[a][a];
for (int i = 0; i < a; i++) {
for (int j = 0; j < a; j++) {
c[i][j] = 1;
}
}
for (int i = 1; i < a; i++) {
for (int j = 1; j < a; j++) {
c[i][j] = c[i - 1][j] + c[i][j - 1];
}
}
cout << c... | ### Prompt
Develop a solution in CPP to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
int n, a[10] = {1, 2, 6, 20, 70, 252, 924, 3432, 12870, 48620};
int main() {
scanf("%d", &n);
printf("%d\n", a[n - 1]);
return 0;
}
| ### Prompt
Develop a solution in Cpp to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int n, a[15][15];
int main() {
scanf("%d", &n);
for (int i = 1; i <= n; i++) {
a[i][1] = a[1][i] = 1;
}
for (int i = 2; i <= n; i++) {
for (int j = 2; j <= n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
printf("%d\n", a[n][n]);
return 0;
... | ### Prompt
Create a solution in cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
int arr[22][22];
cin >> n;
for (int i = 0; i < 22; i++) arr[i][0] = arr[0][i] = 1;
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
arr[i][j] = arr[i - 1][j] + arr[i][j - 1];
}
}
cout << arr[n - 1][n - 1] << endl;
}... | ### Prompt
Generate a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
#include <bits/stdc++.h>
using namespace std;
int a[15][15];
int n;
int main() {
for (int i = 1; i <= 10; i++) a[i][1] = 1, a[1][i] = 1;
for (int i = 2; i <= 10; i++)
for (int j = 2; j <= 10; j++) a[i][j] = a[i - 1][j] + a[i][j - 1];
scanf("%d", &n);
printf("%d\n", a[n][n]);
return 0;
}
| ### Prompt
Develop a solution in CPP to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int arr[110][110];
int main() {
int ans = 0;
int x, y;
int n;
cin >> n;
if (n == 1) {
cout << 1 << endl;
return 0;
}
for (x = 1; x <= n; x++) {
arr[1][x] = 1;
}
for (x = 2; x <= n; x++) {
for (y = 1; y <= n; y++) {
if (y == 1) {
... | ### Prompt
Please formulate a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int A[10][10];
int main() {
int n, m = -1;
cin >> n;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
if (i == 0 || j == 0) {
A[i][j] = 1;
if (A[i][j] > m) m = A[i][j];
} else {
A[i][j] = A[i - 1][j] + A[i][j - 1];
... | ### Prompt
Please provide a CPP coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
int main() {
int n;
int a[20][20];
while (~scanf("%d", &n)) {
int i, j;
for (i = 0; i < n; i++) {
a[0][i] = 1;
a[i][0] = 1;
}
for (i = 1; i < n; i++) {
for (j = 1; j < n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
printf("%d\n",... | ### Prompt
Please create a solution in CPP to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
long long fact(int n);
long long nCr(int n, int r) { return fact(n) / (fact(r) * fact(n - r)); }
long long fact(int n) {
long long res = 1;
for (long long i = 2; i <= n; i++) res = res * i;
return res;
}
void solve() {
int n;
cin >> n;
cout << nCr(2 * (n - 1), n... | ### Prompt
In cpp, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
template <typename t>
t in(t q) {
cin >> q;
return q;
}
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &v) {
os << "[";
for (int i = 0; i < ((int)(v).size()); ++i) {
os << v[i];
if (i != ((int)(v).size()) - 1) os << ",";
}
os << "... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, max;
cin >> n;
int a[11][11] = {};
for (int i = 1; i <= n; i++) {
a[1][i] = 1;
}
for (int i = 1; i <= n; i++) {
a[i][1] = 1;
}
for (int i = 1; i <= n; i++) {
for (int j = 1; j <= n; j++) {
if (a[i][j] != 1) a[i][j] = a[i... | ### Prompt
Please create a solution in CPP to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
void solveQues() {
int n;
cin >> n;
int a[n][n];
for (int i = 0; i < n; i++) a[i][0] = 1, a[0][i] = 1;
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
a[i][j] = a[i - 1][j] + a[i][j - 1];
}
}
cout << a[n - 1][n - 1];
cout << "\n";
... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int n;
int table[10][10];
int make(int r, int c) {
int &ret = table[r - 1][c - 1];
if (ret != -1) return ret;
if (r == 1 || c == 1) return ret = 1;
return ret = make(r - 1, c) + make(r, c - 1);
}
int main() {
cin >> n;
memset(table, -1, sizeof(table));
cout <<... | ### Prompt
Develop a solution in CPP to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int n, t, r = 0, i, flag = 0, count = 0, j;
cin >> n;
int arr[10][10] = {0};
for (i = 0; i < n; i++) {
for (j = 0; j < n; j++) {
arr[i][j] = 1;
arr[j][i] = 1;
}
break;
}
for (i = 1; i < n; i++) {
for (j = 1; j <... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
const int MX = 12;
int A[MX][MX];
void pre() {
for (int i = 0; i < MX; A[i][0] = 1, i++)
;
for (int i = 0; i < MX; A[0][i] = 1, i++)
;
for (int i = 1; i < MX; i++)
for (int j = 1; j < MX; A[i][j] = A[i][j - 1] + A[i - 1][j], j++)
;
}
int main() {
i... | ### Prompt
In CPP, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int t;
cin >> t;
int arr[t][t];
for (int i = 0; i < t; i++) {
arr[i][0] = 1;
arr[0][i] = 1;
}
for (int i = 1; i < t; i++) {
for (int j = 1; j < t; j++) {
arr[i][j] = arr[i... | ### Prompt
Please create a solution in CPP to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int a[10][10];
int i;
for (i = 0; i < 10; i++) {
a[0][i] = 1;
a[i][0] = 1;
}
int j;
for (i = 1; i < 10; i++) {
for (j = 1; j < 10; j++) {
a[i][j] = a[i][j - 1] + a[i - 1][j];
}
}
cout << a[n - 1][n - 1]... | ### Prompt
Please provide a cpp coded solution to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
int n;
cin >> n;
int arr[10][10];
for (int i = 0; i < n; i++) arr[i][0] = arr[0][i] = 1;
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) arr[i][j] = arr[i - 1][j] + arr[i][j - 1];
}
cout ... | ### Prompt
Your task is to create a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
void inp(int n, int arr[]) {
for (int i = 0; i < n; i++) cin >> arr[i];
}
int gcd(int a, int b) { return (b == 0) ? a : gcd(b, a % b); }
void solve() {
int n;
cin >> n;
int arr[n][n];
for (int i = 0; i < n; i++) arr[0][i] = 1;
for (int i = 0; i < n; i++) arr[i][... | ### Prompt
In CPP, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long a[101][101], n;
cin >> n;
for (long i = 0; i < n; i++) a[i][0] = a[0][i] = 1;
for (long i = 1; i < n; i++)
for (long j = 1; j < n; j++) a[i][j] = a[i][j - 1] + a[i - 1][j];
cout << a[n - 1][n - 1];
return 0;
}
| ### Prompt
Create a solution in cpp for the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
if (n == 1)
printf("%d", 1);
else if (n == 2)
printf("%d", 2);
else if (n == 3)
printf("%d", 6);
else if (n == 4)
printf("%d", 20);
else if (n == 5)
printf("%d", 70);
else if (n == 6)
printf("%d", 252);
... | ### Prompt
Develop a solution in CPP to the problem described below:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
const int mod = 1e9 + 7;
const double sqt2 = sqrt(2);
int main(void) {
int(n);
scanf("%d", &n);
if (n == 1)
cout << 1;
else if (n == 2)
cout << 2;
else if (n == 3)
cout << 6;
else if (n == 4)
cout << 20;
else if (n == 5)
cout << 70;
else ... | ### Prompt
In cpp, your task is to solve the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number t... |
#include <bits/stdc++.h>
using namespace std;
double EPS = 1e-9;
int INF = 2000000000;
inline string IntToString(int a) {
char x[100];
sprintf(x, "%d", a);
string s = x;
return s;
}
inline int StringToInt(string a) {
char x[100];
int res;
strcpy(x, a.c_str());
sscanf(x, "%d", &res);
return res;
}
inli... | ### Prompt
Construct a Cpp code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int n;
cin >> n;
int a[n][n];
for (int i = 0; i < n; i++) {
a[i][0] = 1;
a[0][i] = 1;
}
for (int i = 1; i < n; i++) {
for (int j = 1; j < n; j++) {
a[i][j] = a[i - 1][j] + a[i][j... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int a;
int max = -10000;
cin >> a;
int **v = new int *[a];
for (int i = 0; i < a; i++) {
v[i] = new int[a];
}
for (int i = 0; i < a; i++) {
v[0][i] = 1;
v[i][0] = 1;
}
for (int i = 1; i < a; i++) {
for (int j = 1; j < a; j++) {... | ### Prompt
Please create a solution in cpp to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the num... |
#include <bits/stdc++.h>
using namespace std;
long long int a[20][20];
int main() {
long long int n, i, j, k;
cin >> n;
for (i = 1; i <= n; i++) {
a[i][1] = 1;
a[1][i] = 1;
}
long long int ans = 1;
for (i = 1; i <= n; i++)
for (j = 1; j <= n; j++) {
if (i != 1 || j != 1) {
a[i][j] ... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int arr[n];
for (int i = 0; i < n; i++) arr[i] = 1;
for (int i = 1; i < n; i++)
for (int j = 1; j < n; j++) arr[j] = arr[j] + arr[j - 1];
cout << arr[n - 1];
}
| ### Prompt
Your challenge is to write a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
int dp[101][101];
for (int i = 1; i <= n; i++) {
dp[1][i] = 1;
dp[i][1] = 1;
}
int mx = 1;
for (int i = 2; i <= n; i++) {
for (int j = 2; j <= n; j++) {
dp[i][j] = dp[i - 1][j] + dp[i][j - 1];
mx = max(mx, ... | ### Prompt
Your task is to create a cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and t... |
#include <bits/stdc++.h>
using namespace std;
double pi = 3.1415926536;
const int oo = (int)1e9;
const long long OO = numeric_limits<long long>::max();
int dx[] = {0, 1, 0, -1};
int dy[] = {1, 0, -1, 0};
int di[] = {0, 0, 1, -1, 1, -1, 1, -1};
int dj[] = {1, -1, 0, 0, 1, -1, -1, 1};
int f1[] = {0, 0, 0, 1, 1, 1, -1, -1... | ### Prompt
Construct a CPP code solution to the problem outlined:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number... |
#include <bits/stdc++.h>
int main() {
int n;
scanf("%d", &n);
int A[n][n], i, j;
for (i = 0; i < n; i++)
for (j = 0; j < n; j++) {
A[i][0] = 1;
A[0][i] = 1;
}
for (i = 1; i < n; i++)
for (j = 1; j < n; j++) A[i][j] = A[i - 1][j] + A[i][j - 1];
int max = A[0][0];
for (i = 0; i < n; ... | ### Prompt
Generate a Cpp solution to the following problem:
An n × n table a is defined as follows:
* The first row and the first column contain ones, that is: ai, 1 = a1, i = 1 for all i = 1, 2, ..., n.
* Each of the remaining numbers in the table is equal to the sum of the number above it and the number to t... |
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