output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
bool sBs(const pair<int, int> &a, const pair<int, int> &b) {
return (a.second < b.second);
}
long long SUMD(long long n);
long long BS(vector<pair<long long, long long> > &PS, long long s, long long e,
long long ser);
long long MI(long long a, long long m);
l... | ### Prompt
Create a solution in CPP for the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team m... |
#include <bits/stdc++.h>
const long long mod = 1000000007;
using namespace std;
long long MOD = 998244353;
void solve() {
long long n, x;
cin >> n >> x;
vector<long long> a(n);
for (auto &i : a) {
cin >> i;
}
sort(a.begin(), a.end(), greater<long long>());
long long curr = 1, ans = 0;
for (long long... | ### Prompt
Create a solution in cpp for the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team m... |
#include <bits/stdc++.h>
using namespace std;
long long binomialCoeff(long long n, long long k) {
long long res = 1;
if (k > n - k) k = n - k;
for (long long i = 0; i < k; ++i) {
res *= (n - i);
res /= (i + 1);
}
return res;
}
struct MyComp {
bool operator()(const pair<int, int>& x, const pair<int, ... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
long long int t;
cin >> t;
while (t--) {
long long int n, x, ans = 0, j = 0;
cin >> n >> x;
vector<long long int> a(n);
for (long long int i = 0; i < n; i++) cin >> a[i... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
signed main() {
static const int _ = []() {
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
return 0;
}();
long long t = 1;
cin >> t;
while (t--) {
long long n, x;
cin >> n >> x;
vector<long long> a(n);
for (auto &i : a)... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
int n, x;
while (t--) {
cin >> n >> x;
int a[n];
for (int i = 0; i < n; ++i) {
cin >> a[i];
}
sort(a, a + n);
int teamselect = 0;
int no_of_teams = 0;
for (int i = n - 1; i >= 0; --i) {
if ((n... | ### Prompt
Please create a solution in CPP to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
using vi = vector<int>;
using pi = pair<int, int>;
void setIO(string name = "1380C") {
ios_base::sync_with_stdio(0);
cin.tie(0);
freopen((name + ".in").c_str(), "r", stdin);
freopen((name + ".out").c_str(), "w", stdout);
}
int main() {
int t;... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
const int mod = 1e9 + 7;
void SOLVE() {
long long n, x;
cin >> n >> x;
long long a[n], last = n, ans = 0;
for (auto &i : a) cin >> i;
sort(a, a + n);
for (long long i = n - 1; i > -1; i--) {
if (a[i] * (last - i) >= x) {
ans++;
last = i;
}
... | ### Prompt
Construct a cpp code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
const long long int N = 200006;
long long int power2(long long int x, long long int n) {
long long int m;
if (n == 0) return 1;
if (n % 2 == 0) {
m = power2(x, n / 2);
return (m * m) % 998244353;
;
} else
return (x * (power2(x, n - 1))) % 998244353;
... | ### Prompt
Generate a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
bool isprime(long long n) {
for (long long int i = 2; i * i <= n; i++) {
if (n % i == 0) return 0;
}
return 1;
}
long long gcd(long long int a, long long int b) {
if (b == 0) return a;
return gcd(b, a % b);
}
long long lcm(int a, int b) { return (a / gcd(a, b)... | ### Prompt
Please create a solution in cpp to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
template <class A, class B>
ostream& operator<<(ostream& out, const pair<A, B>& a) {
return out << "(" << a.first << ", " << a.second << ")";
}
template <class A>
ostream& operator<<(ostream& out, const vector<A>& v) {
out << "[";
for (int i = 0; i < v.size(); i++) {
... | ### Prompt
In CPP, your task is to solve the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
scanf("%d", &t);
while (t--) {
long long int n, x, count = 0, y, z;
scanf("%lld %lld", &n, &x);
long long int ara[n];
for (long long int i = 0; i < n; i++) scanf("%lld", &ara[i]);
sort(ara, ara + n);
for (long long int i = n... | ### Prompt
Generate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long t, n, x;
cin >> t;
while (t--) {
cin >> n >> x;
vector<long long> a(n);
for (long long i = 0; i < n; ++i) {
cin >> a[i];
}
sort(a.begin(), a.end());
long long r = n;
long long sum = 0;
for (long long i = n -... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
long long int max(long long int a, long long int b) {
if (a > b) {
return a;
}
return b;
}
long long int gcd(long long int a, long long int b) {
if (a == 0) {
return b;
}
return gcd(b % a, a);
}
long long int lcm(long long int a, long long int b) {
ret... | ### Prompt
Create a solution in cpp for the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team m... |
#include <bits/stdc++.h>
using namespace std;
template <class T>
void _R(T &x) {
cin >> x;
}
void _R(int &x) { scanf("%d", &x); }
void _R(int64_t &x) { scanf("%lld", &x); }
void _R(double &x) { scanf("%lf", &x); }
void _R(char &x) { scanf(" %c", &x); }
void _R(char *x) { scanf("%s", x); }
void R() {}
template <class ... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
long long n, t, k;
int main() {
cin >> t;
while (t--) {
cin >> n;
cin >> k;
vector<long long> a(n);
for (long long i = 0; i < n; i++) cin >> a[i];
sort((a).begin(), (a).end(), greater<long long>());
int sol = 0;
int cmin;
long long len = ... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, m;
cin >> n >> m;
int a[n + 1];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
reverse(a, a + n);
int ans = 0, lst = -1;
for (int i = 0; i < n; i++)
if (a[i] * (i - lst)... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
#pragma GCC optimize "03"
using namespace std;
const long long int inf = 1e15;
const long long int MOD = 1e9 + 7;
const long long int N = 2e5 + 5;
signed main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
;
long long int t;
cin >> t;
while (t--) {
long long int n, x;
cin >... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, x;
cin >> n >> x;
vector<int> a(n);
for (int i = 0; i < n; i++) {
cin >> a[i];
}
int k = n, ans = 0;
sort(a.begin(), a.end());
for (int i = n - 1; i >= 0; i--) {
if (a[i] * ... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
long long t;
cin >> t;
while (t--) {
long long n, x;
cin >> n >> x;
vector<long long> v(n);
for (long long i = 0; i < n; i++) {
cin >> v[i];
}
sort(v.begin(), v.end(... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long t;
cin >> t;
while (t--) {
long long n, x;
cin >> n >> x;
vector<long long> a(n);
for (__typeof(n) i = 0; i < n; i++) {
cin >> a[i];
}
sort(a.rbegin(), a.rend());
long long val, no = 0, mul = 1;
for (__typeo... | ### Prompt
Please create a solution in CPP to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int a, b, c, d, i, j, k, l, p, q, r = 0, s = 1;
scanf("%lld", &d);
while (d--) {
scanf("%lld %lld", &a, &b);
long long int arr1[a + 5], arr2[a + 5], arr3[a + 5];
for (i = 1; i <= a; i++) {
scanf("%lld", &arr3[i]);
}
sor... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
long long n, x;
cin >> n >> x;
long long i;
long long ar[n];
for (i = 0; i < n; i++) {
cin >> ar[i];
}
sort(ar, ar + n, greater<int>());
long long count = 0;
long long p = 1;
i =... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n;
long long int x;
cin >> n >> x;
long long int a[n];
for (int i = 0; i < n; i++) cin >> a[i];
;
sort(a, a + n, greater<int>());
int ans = 0;
int curr_len = 0;
for (int i = 0; i < n; i++) {
if (a[i] >= x) {
ans++;
cont... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
template <class c>
struct rge {
c b, e;
};
template <class c>
rge<c> range(c i, c j) {
return rge<c>{i, j};
}
template <class c>
auto dud(c* x) -> decltype(cerr << *x, 0);
template <class c>
char dud(...);
struct debug {
template <class c>
debug& operator<<(const c&... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
#pragma GCC optimize("O3")
using namespace std;
using namespace std;
double pi = 1.57079632679489661923;
long long modu = 1e9 + 7;
long long t = 1, n = 1, x = 1;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> t;
for (int ti = 1; ti <= t; ti++) {
cin >> n >> ... | ### Prompt
In CPP, your task is to solve the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team ... |
#include <bits/stdc++.h>
using namespace std;
long long int tt;
vector<long long int> a;
long long int check(long long int x) {
long long int n = a.size();
long long int s = 0;
long long int ans = 0;
for (long long int i = n - 1; i >= 0; i--) {
s++;
long long int x1;
x1 = ceil(x / double(a[i]));
... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
long long int mod = 998244353;
long long int ceil1(long long int n, long long int k) {
if (n % k) return n / k + 1;
return n / k;
}
long long int pow1(long long int n, long long int k) {
long long int ans = 1;
while (k != 0) {
if (k % 2) ans = (ans * n) % mod;
... | ### Prompt
In cpp, your task is to solve the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team ... |
#include <bits/stdc++.h>
using namespace std;
void input(long long int n, long long int arr[]) {
for (__typeof(n) i = (0) - ((0) > (n)); i != (n) - ((0) > (n));
i += 1 - 2 * ((0) > (n)))
cin >> arr[i];
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
long long int t;
... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
long long seive[1000001];
void buildseive() {
for (int i = 0; i < 1000001; i++) seive[i] = 1;
for (int i = 2; i * i < 1000001; i++) {
if (seive[i]) {
for (int j = i; j * i < 1000001; j++) {
seive[i * j] = 0;
}
}
}
}
int main() {
int t;
... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
vector<int> v;
int dp[100005];
int main() {
int t;
cin >> t;
while (t--) {
int n, x;
cin >> n >> x;
v.clear();
for (int i = 1; i <= n; i++) {
int a;
cin >> a;
int k = x / a;
if (x % a > 0) k++;
v.push_back(k);
}
so... | ### Prompt
Generate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
void __print(int x) { cerr << x; }
void __print(long long x) { cerr << x; }
void __print(unsigned long long x) { cerr << x; }
void __print(double x) { cerr << x; }
void __print(long double x) { cerr << x; }
void __print(char x) { cerr << '\'' << x << '\''; }
void __print(co... | ### Prompt
Please formulate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t;
cin >> t;
while (t--) {
int n, x;
cin >> n >> x;
vector<int> arr;
for (int i = 0; i < n; i++) {
int temp;
cin >> temp;
arr.push_back(temp);
}
sort(arr.be... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
const int N = 1e6 + 1;
void solve() {
int n, x;
cin >> n >> x;
vector<int> a(n);
for (int i = 0; i < n; i++) cin >> a[i];
sort(a.begin(), a.end(), greater<int>());
int ans = 0;
int j = 1;
for (int i = 0; i < n; i++) {
if ((x + a[i] - 1) / a[i] == j) {
... | ### Prompt
Generate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
const long long int N = 2e5 + 5;
void solve() {
long long int n, x;
cin >> n >> x;
vector<long long int> v(n);
for (auto &it : v) cin >> it;
;
sort(v.begin(), v.end());
long long int ans = 0;
vector<long long int> a;
for (long long int i = 0; i < n; i++) {... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
void tmkc() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(0);
}
int main() {
tmkc();
int t;
cin >> t;
while (t--) {
long long n, x, i, j, k, r = 0;
cin >> n >> x;
vector<long long> a;
for (i = 0; i < n; i++) {
cin >> j;
... | ### Prompt
Please create a solution in CPP to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
void Open() {
freopen("Input.txt", "r", stdin);
freopen("Output.txt", "w", stdout);
}
long long gcd(long long a, long long b) { return b == 0 ? a : gcd(b, a % b); }
void madesetprobblem() {}
long long n, *a, x;
int main() {
ios::sync_with_stdio(false);
cin.tie(NULL)... | ### Prompt
Generate a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int L;
cin >> L;
for (int LL = 1; LL <= L; LL++) {
int n, x;
cin >> n >> x;
int s[n + 1];
for (int i = 1; i <= n; i++) cin >> s[i];
sort(s + 1, s + n + 1);
int ans = 0, f = 0, xx;
for (int i = n; i >= 1; i--) {
f++;
... | ### Prompt
Generate a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n, k;
cin >> n >> k;
int a[n];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int m = 1;
int team = 0;
for (int i = n - 1; i >= 0; i--) {
if (a[i] * m >= k) {
team++;
m = 1;
} else {
m++;
}
}
cou... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
bool compare(long long int a, long long int b) { return a > b; }
int32_t main() {
int t;
cin >> t;
while (t--) {
long long int n, x;
cin >> n >> x;
long long int a[n + 1];
a[0] = 0;
for (int i = 1; i < n + 1; i++) {
cin >> a[i];
a[i] = ... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
cin.tie(0);
ios_base::sync_with_stdio(false);
long long t;
cin >> t;
while (t--) {
long long n, x, c = 0, i, j, k = 1;
cin >> n >> x;
vector<long long> v(n);
for (auto &it : v) cin >> it;
sort((v).rbegin(), (v).rend());
for (i ... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int a[100005];
int main() {
int T;
scanf("%d", &T);
while (T--) {
int n, x;
scanf("%d%d", &n, &x);
for (int i = 1; i <= n; i++) {
scanf("%d", &a[i]);
}
sort(a + 1, a + 1 + n);
int l = 1, ans = 0;
for (int i = n; i >= 1; i--) {
i... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
long long power(long long a, long long b) {
long long r = 1;
while (b != 0) {
if (b % 2 != 0) {
r = r * a;
r %= 998244353ll;
}
a = a * a;
a = a % 998244353ll;
b = b / 2;
}
return r;
}
int main() {
ios_base::sync_with_stdio(false);
... | ### Prompt
Generate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long tc;
cin >> tc;
long long n, x;
while (tc--) {
cin >> n >> x;
long long a[n];
for (long long i = 0; i < n; i++) cin >> a[i];
sort(a, a + n, greater<long long>());
long long cnt = 0, pn = 1;
for (long long i = 0; i < n; i... | ### Prompt
In cpp, your task is to solve the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team ... |
#include <bits/stdc++.h>
using namespace std;
const int maxN = 1e5 + 10;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(nullptr);
int t;
cin >> t;
while (t--) {
int n, x, a[maxN], cur = 1, res = 0;
cin >> n >> x;
for (int i = 1; i <= n; ++i) cin >> a[i];
sort(a + 1, a + 1 + n, greater<int>... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
template <typename T>
inline T gcd(T a, T b) {
T t;
if (a < b) {
while (a) {
t = a;
a = b % a;
b = t;
}
return b;
} else {
while (b) {
t = b;
b = a % b;
a = t;
}
return a;
}
}
template <typename T>
inline T... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
const int MOD = 1e9 + 7;
const int v1 = 1e5 + 5;
const int N = 3e5 + 6;
using namespace std;
int32_t main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
;
long long t = 0;
cin >> t;
while (t--) {
long long n = 0;
long long k = 0;
cin >> n >> k;
vect... | ### Prompt
Construct a cpp code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
long long int mod = 1e9 + 7;
long double Pi = 3.14159265359;
auto clk = clock();
mt19937_64 rang(
chrono::high_resolution_clock::now().time_since_epoch().count());
int rng(int lim) {
uniform_int_distribution<int> uid(0, lim - 1);
return uid(rang);
}
int main() {
i... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long t = 0;
cin >> t;
while (t--) {
long long n, x, ans = 0, end;
cin >> n >> x;
long long a[n];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
end = n;
for (long long i = n - 1; i >= 0; i--) {
long long y ... | ### Prompt
Create a solution in CPP for the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team m... |
#include <bits/stdc++.h>
using namespace std;
int a[100005], t, n, x;
int main() {
scanf("%d", &t);
while (t--) {
scanf("%d%d", &n, &x);
for (int i = 0; i < n; ++i) scanf("%d", a + i);
a[n] = 0;
sort(a, a + n, greater<int>());
int ans = 0, i = 0, now = 1;
while (i < n) {
while (i < n &... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int a[100010];
int main() {
int t;
cin >> t;
while (t--) {
int n, k, ans = 0;
cin >> n >> k;
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
for (int i = n - 1; i >= 0; i--) {
int mm = a[i], g = 0;
if (mm >= k) {
ans++;... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
for (int q = 1; q <= t; q++) {
long long int n;
long long int x;
cin >> n >> x;
vector<long long int> skls;
for (int i = 0; i < n; i++) {
long long int inp;
cin >> inp;
skls.push_back(inp);
}
... | ### Prompt
Please formulate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int T;
cin >> T;
while (T--) {
string s;
cin >> s;
int n = s.size();
int x;
cin >> x;
vector<char> ans(n, '1');
for (int i = 0; i < n; i++) {
if (s[i] == '0') {
if (i + x < n) ans[i + x] = '0';
if (i - x >... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:... |
#include <bits/stdc++.h>
using namespace std;
long long p, f, s, a, sw, aw, ps = 0, pa = 0, fs = 0, fa = 0;
int main() {
int t;
cin >> t;
while (t--) {
string a;
cin >> a;
int n = a.length(), x;
cin >> x;
vector<int> s(n + 1, -1);
for (int i = 1; i <= n; i++) s[i] = a[i - 1] - '0';
vec... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if ... |
#include <bits/stdc++.h>
using namespace std;
template <typename Arg1>
void __f(const char* name, Arg1&& arg1) {
cerr << name << " : " << arg1 << '\n';
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args) {
const char* comma = strchr(names + 1, ',');
cerr.write(nam... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
string s;
cin >> s;
int x;
cin >> x;
int n = s.length();
string t = "";
for (int i = 0; i < n; i++) t += "1";
for (int i = 0; i < n; i++)
if (s[i] == '0') {
if (i - x >= 0) t[i -... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, x, no = 0;
string s;
cin >> s >> x;
n = s.length();
char w[n];
for (int a = 0; a < n; a++) w[a] = 'x';
for (int a = 0; a < n; a++) {
if (s[a] == '0') {
if ((a + x) < n) w[a + ... | ### Prompt
Create a solution in cpp for the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 2e5 + 5;
char w[100005], s[100005];
void solve() {
scanf("%s", s);
int x;
scanf("%d", &x);
int n = strlen(s);
for (int i = 0; i < n; i++) w[i] = '2';
for (int i = 0; i < n; i++) {
if (s[i] == '1') {
if (i - x >= 0 && w[i - x] == '1' ||... | ### Prompt
Generate a cpp solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the c... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int64_t n, x, i;
string str;
cin >> str;
cin >> x;
string ans = "";
for (int64_t i = 0; i < str.size(); i++) {
ans += "1";
}
for (int64_t i = 0; i < str.size(); i++) {
if (str[i] == '0') {
if (i - x >= 0) ans[i - x] = '0';
... | ### Prompt
Please formulate a Cpp solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* ... |
#include <bits/stdc++.h>
using namespace std;
template <typename P, typename Q>
P CeilDiv(P _dividend, Q _divider) {
return static_cast<P>((_dividend - 1LL + _divider) / _divider);
}
template <typename Tp>
inline void outarr(Tp _begin, Tp _end, const char* _delim = " ") {
for (Tp current = _begin; current != _end; ... | ### Prompt
Develop a solution in CPP to the problem described below:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* ... |
#include <bits/stdc++.h>
using namespace std;
const int N = 1e6 + 5;
const int MOD = 1e9 + 7;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(NULL);
cout.tie(NULL);
long long int t;
cin >> t;
while (t--) {
string s;
cin >> s;
long long int x;
cin >> x;
string res;
for (int i = 0; ... | ### Prompt
Create a solution in CPP for the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the... |
#include <bits/stdc++.h>
const int alldx[] = {1, -1, 0, 0, 1, -1, 1, -1};
const int alldy[] = {0, 0, 1, -1, 1, -1, -1, 1};
const int dx[] = {1, -1, 0, 0};
const int dy[] = {0, 0, 1, -1};
struct matrix {
int a[2][2];
matrix operator*(matrix &b) {
matrix product;
for (int i = 0; i < 2; i++) {
for (int j... | ### Prompt
In CPP, your task is to solve the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if th... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);
int t;
cin >> t;
while (t--) {
string s;
cin >> s;
int x;
cin >> x;
int n = s.size();
vector<char> ans(n, '1');
for (int i = 0; i < n; i++) {
if (s[i] == '0') {
... | ### Prompt
Generate a Cpp solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the c... |
#include <bits/stdc++.h>
using namespace std;
const int mod = (int)1e9 + 7;
class apurvakb {
public:
apurvakb() {
string s;
cin >> s;
int x;
cin >> x;
int n = s.size();
string str = string(n, '1');
for (int i = 0; i < n; i++) {
if (s[i] == '0') {
if (i - x > -1) str[i - x] =... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if ... |
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1e9 + 7;
const long long mod = 1e9 + 7;
const int mxN = 1e5 + 9;
char s[mxN];
void solve() {
string res;
int x;
cin >> res >> x;
int n = res.length();
for (int i = 0; i < n; i++) s[i] = '1';
for (int i = 0; i < n; i++) {
if (res[i] == '0') {
... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as foll... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long t;
scanf("%ld", &t);
while (t--) {
int x, i, n;
string w, s;
cin >> s >> x;
n = s.length();
w = string(n, '1');
for (i = 0; i < n; i++) {
if (s[i] == '0') {
if (i - x >= 0) w[i - x] = '0';
if (i + x < n) ... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as foll... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
long long int t;
cin >> t;
while (t--) {
string s;
cin >> s;
long long int x;
cin >> x;
string temp = "";
long long int n = s.length();
for (long long int i = 0; i < s.length(); ++i) {
temp += '1';
}
for (long... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as foll... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t;
cin >> t;
while (t--) {
string str;
cin >> str;
int x;
cin >> x;
int n = str.size();
vector<char> v(n, '$');
for (int i = 0; i < n; i++) {
if (str[i] == '0') {
... | ### Prompt
In CPP, your task is to solve the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if th... |
#include <bits/stdc++.h>
using namespace std;
const long long int mod = 1000000007;
void __print(long long int x) { cerr << x; }
void __print(float x) { cerr << x; }
void __print(double x) { cerr << x; }
void __print(long double x) { cerr << x; }
void __print(char x) { cerr << '\'' << x << '\''; }
void __print(const ch... | ### Prompt
Generate a CPP solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the c... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
string a;
int x;
cin >> a >> x;
int n = a.length();
vector<int> o(n, -1);
for (int i = 0; i < n; i++) {
if (i - x < 0 && i + x < n) {
if (o[i + x] == -1) o[i + x] = a[i] - '0';
if (o[i + x] != a[i] - '0') {
cout << "-1";
... | ### Prompt
Generate a cpp solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the c... |
#include <bits/stdc++.h>
using namespace std;
int t, x, sum, flag = 1;
char a[200000];
bool b[200000];
int main() {
bool flag = false;
cin >> t;
while (t--) {
flag = false;
int j;
cin >> a >> x;
j = strlen(a);
memset(b, true, sizeof(b));
for (int i = 0; i < j; i++) {
if (i - x >= 0 &... | ### Prompt
Your task is to create a cpp solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:... |
#include <bits/stdc++.h>
using namespace std;
long long gcd(long long a, long long b) {
if (a == 0) return b;
return gcd(b % a, a);
}
long long lcm(long long a, long long b) { return (a * b) / gcd(a, b); }
void func() {
string s;
cin >> s;
int n, x;
cin >> x;
n = s.size();
std::vector<int> w(n, 1);
fo... | ### Prompt
Please create a solution in Cpp to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* ... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
string a;
int x;
cin >> a >> x;
int n = a.length();
vector<int> o(n, -1);
for (int i = 0; i < n; i++) {
if (i - x < 0 && i + x < n)
o[i + x] = a[i] - '0';
else if (i + x >= n && i - x >= 0) {
if (o[i - x] == -1) o[i - x] = a[i]... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as foll... |
#include <bits/stdc++.h>
using namespace std;
const int INF = 0x3f3f3f3f;
int t;
void solve() {
int x;
string s;
cin >> s >> x;
int a = s.size();
string st(a, '1');
for (int j = 0; j < a; j++) {
if (s[j] == '0') {
if (j - x >= 0) st[j - x] = '0';
if (j + x < a) st[j + x] = '0';
}
}
f... | ### Prompt
Create a solution in cpp for the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const int MAXN = 1e5 + 5;
ll x;
string s;
int ans[MAXN];
void init() {
;
;
}
void solve(int casei) {
ll n = s.length();
s = "#" + s;
for (int i = 1; i <= n; ++i) {
ans[i] = -1;
}
for (int i = 1; i <= n; ++i) {
if (s[i] == '0') {
... | ### Prompt
Generate a cpp solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the c... |
#include <bits/stdc++.h>
using namespace std;
bool compare(const pair<int, int> &i, const pair<int, int> &j) {
return (i.second == j.second) ? (i.first < j.first) : (i.second < j.second);
}
const long long mod = 1e9 + 7;
int main() {
long long t;
cin >> t;
while (t--) {
string s;
cin >> s;
long long... | ### Prompt
In cpp, your task is to solve the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if th... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long int t;
cin >> t;
while (t--) {
string s;
long int x;
cin >> s >> x;
string w = "";
long int n = s.length();
for (long int i = 0; i < n; i++) w += "1";
for (long int i = 0; i < n; i++) {
if (s[i] == '0') {
if ... | ### Prompt
Construct a cpp code solution to the problem outlined:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if ... |
#include <bits/stdc++.h>
using namespace std;
const double pi = acos(-1.0);
const double pii = 2 * pi;
const double eps = 1e-6;
const long long MOD = 1e9 + 7;
void solve() {
int n, x;
string s;
cin >> s;
cin >> x;
n = s.size();
vector<int> ans(n, 1);
for (int i = 0; i < n; i++)
if (s[i] == '0') {
... | ### Prompt
Generate a Cpp solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the c... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long int;
ll a[200004], b[200005];
ll fnc(ll n) {
ll cnt;
return cnt;
}
int main() {
int t;
cin >> t;
while (t--) {
ll n, m, sum = 0, cnt = 0;
string s, s1;
map<ll, ll> mp;
cin >> s >> n;
for (int i = 0; i < s.size(); i++) {
... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:... |
#include <bits/stdc++.h>
using namespace std;
template <class T>
T nrem(T x, T y) {
return ((x % y) + y) % y;
}
const long long M = 1e9 + 7;
long long mod(long long x) { return ((x % M + M) % M); }
void in() {}
void solve() {
string s;
cin >> s;
int len = s.length();
int x;
cin >> x;
string ans = string(l... | ### Prompt
Develop a solution in CPP to the problem described below:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t;
cin >> t;
while (t--) {
int x;
string s;
cin >> s >> x;
int n = s.length();
char w[n + 2];
for (int i = 0; i < n + 2; i++) {
w[i] = '@';
}
bool canchange[n +... | ### Prompt
In cpp, your task is to solve the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if th... |
#include <bits/stdc++.h>
using namespace std;
bool vis[100100];
string s;
bool process(string s, int x, string Res) {
for (int i = 0; i < s.size(); i++) {
char curr = '0';
if ((i - x >= 0 && s[i - x] == '1') ||
(i + x < s.size() && s[i + x] == '1'))
curr = '1';
if (curr != Res[i]) return fal... | ### Prompt
In CPP, your task is to solve the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if th... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, x, n;
string s, ans;
cin >> t;
while (t--) {
cin >> s >> x;
n = s.length();
ans = string(n, '1');
for (int i = 0; i < n; i++) {
if (s[i] == '0') {
if (i - x >= 0) ans[i - x] = '0';
if (i + x < n) ans[i + x] =... | ### Prompt
Create a solution in CPP for the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the... |
#include <bits/stdc++.h>
using namespace std;
priority_queue<pair<long long, long long>, vector<pair<long long, long long> >,
greater<pair<long long, long long> > >
pq;
priority_queue<long long, vector<long long>, greater<long long> > pq1;
long long result(long long a, long long b, long long p) {
l... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as foll... |
#include <bits/stdc++.h>
using namespace std;
bool prime[100005];
void Sieve(int n) {
memset(prime, true, sizeof(prime));
for (int p = 2; p * p <= n; p++) {
if (prime[p] == true) {
for (int i = p * p; i <= n; i += p) prime[i] = false;
}
}
}
void solve() {
string s;
int x;
cin >> s >> x;
stri... | ### Prompt
In cpp, your task is to solve the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if th... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1000000007;
int32_t main() {
long long t;
cin >> t;
while (t--) {
string s;
long long x;
cin >> s >> x;
string c, p;
long long n = s.size();
for (long long i = 0; i < n; i++) {
c.push_back('0');
p.push_back('1'... | ### Prompt
Please create a solution in CPP to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* ... |
#include <bits/stdc++.h>
using namespace std;
template <typename T>
void drop(const T &x) {
cout << x << '\n';
exit(0);
}
void solve() {
string s;
cin >> s;
int x;
cin >> x;
int n = int(s.size());
string w(n, '1');
for (int i = 0; i < n; ++i) {
if (s[i] == '0') {
if (i - x >= 0) {
w[... | ### Prompt
Generate a CPP solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the c... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
;
int test, cs = 1;
cin >> test;
while (test--) {
string s, res;
cin >> s;
int x, i, j, n = (int)(s.size());
cin >> x;
res.resize(n, '1');
for (i = 0; i < n; i++) {
... | ### Prompt
Generate a CPP solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the c... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t;
cin >> t;
while (t--) {
string s;
cin >> s;
int x;
cin >> x;
int n = s.size();
vector<char> w(s.size(), '1');
for (int i = 0; i < s.size(); i++) {
if (s[i] == '1... | ### Prompt
In CPP, your task is to solve the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if th... |
#include <bits/stdc++.h>
const int MAX = 1e5 + 7;
const int mod = 1e9 + 7;
using namespace std;
int n;
string s;
string check(string w) {
string tmp = w;
for (int i = 0; i < w.size(); ++i) {
if (i - n >= 0 && w[i - n] == '1' || i + n < w.size() && w[i + n] == '1')
tmp[i] = '1';
else
tmp[i] = '0'... | ### Prompt
Develop a solution in cpp to the problem described below:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* ... |
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1000000007;
int add(int a, int b) {
a += b;
if (a >= MOD) a -= MOD;
if (a < 0) a += MOD;
return a;
}
int mult(int a, int b) { return a * 1ll * b % MOD; }
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int q;
cin >> q;
while (... | ### Prompt
In CPP, your task is to solve the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if th... |
#include <bits/stdc++.h>
using namespace std;
template <class A>
void read(vector<A> &v);
template <class A, size_t S>
void read(array<A, S> &a);
template <class T>
void read(T &x) {
cin >> x;
}
void read(double &d) {
string t;
read(t);
d = stod(t);
}
void read(long double &d) {
string t;
read(t);
d = sto... | ### Prompt
In CPP, your task is to solve the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if th... |
#include <bits/stdc++.h>
#pragma GCC optimize("Ofast,unroll-loops")
#pragma GCC target("avx,avx2,fma")
using namespace std;
const long long mod1 = 998244353;
const long long mod = 1e9 + 7;
long long mod_mul(long long a, long long b) {
a = a % mod;
b = b % mod;
return (((a * b) % mod) + mod) % mod;
}
long long inv... | ### Prompt
Construct a cpp code solution to the problem outlined:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if ... |
#include <bits/stdc++.h>
using namespace std;
int n, x, w[100003];
string s;
void in() {
cin >> s >> x;
n = s.length();
s = " " + s;
}
void xuly() {
memset(w, -1, sizeof w);
for (int i = 1; i <= n; i++)
if (s[i] == '0') {
if (i > x) w[i - x] = 0;
if (i + x <= n) w[i + x] = 0;
}
for (int ... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
;
long long t;
cin >> t;
while (t--) {
long long n, i, j;
string s;
cin >> s;
long long x;
cin >> x;
n = s.length();
string w = s;
for (i = 0; i < n; ... | ### Prompt
Construct a cpp code solution to the problem outlined:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if ... |
#include <bits/stdc++.h>
using namespace std;
const int mod = (int)1000000000 + 7;
const int MOD = (int)998244353;
const int INF = (int)1e18;
bool cmp(const pair<int, int>& a, const pair<int, int>& b) {
return a.second - a.first < b.second - b.first;
}
long long bit_ct1(long long x) {
long long ct = 0;
while (x >... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as foll... |
#include <bits/stdc++.h>
using namespace std;
int dx[4] = {-1, 0, 0, 1};
int dy[4] = {0, -1, 1, 0};
bool sortbysec(const pair<int, int> &a, const pair<int, int> &b) {
if (a.first == b.first) return a.second < b.second;
return (a.first < b.first);
}
long long a[10000005];
void sieve() {
for (int i = 1; i < 1000000... | ### Prompt
Please formulate a Cpp solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, i, flag, x, y;
vector<int> w;
cin >> t;
y = 0;
while (t--) {
y++;
string s;
cin >> s;
cin >> x;
i = 0;
while (s[i] != '\0') {
i++;
}
n = i;
w.clear();
w.resize(n, -1);
i = 0;
while (s[i] ... | ### Prompt
Please formulate a CPP solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* ... |
#include <bits/stdc++.h>
using namespace std;
long long mod = 1e9 + 7;
long long min(long long a, long long b) { return (a < b) ? a : b; }
long long max(long long a, long long b) { return (a > b) ? a : b; }
long long fp(long long a, long long b) {
if (b == 0) return 1;
long long x = fp(a, b / 2);
x = (x * x) % mo... | ### Prompt
Develop a solution in CPP to the problem described below:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* ... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1e9 + 7;
const long long modx = 998244353;
const long long Nx = 1e5 + 2;
const long long inf = (long long)(1e19 + 10LL);
void solve() {
string str;
cin >> str;
long long x;
cin >> x;
long long n = (long long)(str.size());
vector<char> ans(n... | ### Prompt
Generate a CPP solution to the following problem:
Consider the following process. You have a binary string (a string where each character is either 0 or 1) w of length n and an integer x. You build a new binary string s consisting of n characters. The i-th character of s is chosen as follows:
* if the c... |
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