output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, b;
cin >> n;
for (int i = 0; i < n; i++) {
cin >> b;
int a[b + 1];
for (int j = 0; j < b; j++) cin >> a[j];
sort(a, a + b);
int mn = 999999;
for (int j = 1; j < b; j++) {
mn = min(a[j] - a[j - 1], mn);
}
cout <... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, min;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
min = a[1] - a[0];
for (int j = 1; j < n - 1; j++) {
if (a[j + 1] - a[j] < min) min = a[j + 1] - a[j]... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
const int mxN = 2e5;
int n, a[mxN];
void solve() {
cin >> n;
for (int i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
int mindiff = a[1] - a[0];
for (int i = 1; i < n; i++) {
if (a[i] - a[i - 1] < mindiff) mindiff = a[i] - a[i - 1];
}
cout << min... | ### Prompt
Create a solution in CPP for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1000000007;
void solve();
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
solve();
return 0;
}
int mima(vector<int> vec, int f) {
int mi = vec[0], ma = vec[0];
for (int i = 1; i < vec.size(); i += 1) {
mi = min(mi, vec[i])... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int arr[n];
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr, arr + n);
int max = 100001;
for (int i = 0; i < n - 1; i++) {
int dif = arr[i + 1] - arr[i];
... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least on... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n;
cin >> t;
while (t--) {
cin >> n;
int Arr[n];
int sub, res;
for (int i = 0; i < n; i++) {
cin >> Arr[i];
}
sort(Arr, Arr + n);
res = INT_MAX;
for (int i = 0; i < n - 1; i++) {
sub = abs(Arr[i + 1] - Ar... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
long long n, a[100069], inf = 1e18;
int main() {
long long t, rr, i, z;
scanf("%lld", &t);
for (rr = 0; rr < t; rr++) {
scanf("%lld", &n);
for (i = 1; i <= n; i++) {
scanf("%lld", a + i);
}
sort(a + 1, a + n + 1);
z = inf;
for (i = 2; i <... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e5 + 5;
int main() {
std::ios::sync_with_stdio(false);
int t;
int a[maxn];
cin >> t;
while (t--) {
int n;
cin >> n;
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int ans = 0x3f3f3f3f;
for (int i = 0; i < n - 1; ... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> v;
for (int i = 0; i < n; ++i) {
int x;
cin >> x;
v.emplace_back(x);
}
sort(begin(v), end(v));
int res = ~(1 << 31);
for (int i = 1; i < n; ++i) ... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
template <typename T>
T gcd(T a, T b) {
if (b == 0) return a;
return gcd(b, a % b);
}
long long power(long long a, long long b, long long m = 1000000007) {
long long res = 1;
while (b > 0) {
if (b & 1) res = (res * a) % m;
a = (a * a) % m;
b >>= 1;
}
... | ### Prompt
Create a solution in cpp for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
long long n, k, x, y = INT_MAX;
cin >> x;
while (x--) {
set<int> s;
y = INT_MAX;
cin >> n;
vector<long long> v;
long long arr[n];
for (int i = 0; i < n; i++) {
cin >> k;
... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
long long int n, i, min = INT_MAX;
cin >> n;
long long int a[n];
;
for (i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
;
for (i = 0; i < n - 1; i++)
if (a[i + 1] - a[i] < min) min = a[i + 1] - a[i];
cout << min << endl;
}
int main() {
... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
int arr[10110];
int main() {
int t;
cin >> t;
while (t) {
int n, mi = 1000000;
cin >> n;
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr, arr + n);
for (int i = 1; i < n; i++) {
if (mi > (arr[i] - arr[i - 1])) {
mi =... | ### Prompt
Your task is to create a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
;
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int arr[n];
for (int i = 0; i < n; ++i) cin >> arr[i];
sort(arr, arr + n);
int diff = 1000;
for (int i = 0; i < n - 1; ... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int aa, n;
cin >> aa;
while (aa--) {
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
}
int max = 1000001;
for (int i = 0; i < n; i++) {
for (int j = i + 1; j < n; j++)
if (abs(a[i] - a[j]) < max) ... | ### Prompt
Generate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
template <typename T, typename... Args>
void err(istream_iterator<string> it, T a, Args... args) {
cerr << *it << " = " << a << ", ";
err(++it, args...);
}
long long mod(long long n) {
return (n % 1000000007 + 1000000007) % 1000000007;
}
string test = "---------------... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
long long int gcd(long long int a, long long int b) {
if (a == 0) return b;
return gcd(b % a, a);
}
long long int findGCD(long long int arr[], long long int n) {
long long int result = arr[0];
for (int i = 1; i < n; i++) {
result = gcd(arr[i], result);
if (r... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
unsigned long long i, j, k, t, l, r, n, m, x, y, a, b, c;
cin >> t;
while (t--) {
cin >> n;
unsigned long long arr[n];
for (i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr, arr + n);
unsigned long long ans = INT_MIN;
for (... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
using namespace std;
int s[1050];
int main() {
int ttc, n, a, b;
cin >> ttc;
for (int i = 0; i < ttc; ++i) {
cin >> n;
int j = 0;
for (; j < n; ++j) {
cin >> s[j];
}
sort(s, s + j);
int minresult = 99999;
for (int k = 1; k < n; ++k) {
minresult = mi... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at lea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int cnt;
cin >> cnt;
while (cnt--) {
int num;
cin >> num;
int t[1005] = {0};
for (int i = 0; i < num; ++i) {
cin >> t[i];
}
sort(t, t + num);
int min_val = 0x0FFFFFFF;
for (int i = 1; i < num; ++i) {
min_val = m... | ### Prompt
Generate a cpp solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n], i, min1 = 10000, s = 0;
for (i = 0; i < n; i++) {
cin >> a[i];
}
sort(a, a + n);
for (i = 0; i < n - 1; i++) {
s = abs(a[i + 1] - a[i]);
min1 = min(min... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must h... |
#include <bits/stdc++.h>
int main() {
int i, j, t, n, min, a, b, c, k;
scanf("%d", &t);
for (i = 0; i < t; i++) {
scanf("%d", &n);
int arr[n];
for (j = 0; j < n; j++) scanf("%d", &arr[j]);
min = fabs(arr[0] - arr[1]);
for (j = 0; j < n - 1; j++) {
a = arr[j];
for (k = j + 1; k < n;... | ### Prompt
Create a solution in cpp for the following problem:
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete — the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
int main() {
int t;
cin >> t;
while (t--) {
ll n, x;
cin >> n >> x;
ll ar[n];
for (int i = 0; i < n; i++) {
cin >> ar[i];
}
sort(ar, ar + n);
ll ans = 0;
ll num = 0;
for (int i = n - 1; i >= 0; i--) {
... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
int main() {
std::ios::sync_with_stdio(false);
cin.tie(NULL);
int t;
cin >> t;
while (t--) {
long long n, x, sum;
cin >> n >> x;
vector<long long> a(n);
for (int i = 0; i < n; i++) cin >> a[i];
sort(a.begin(), a.end());
int cnt = 0, j = 1;
... | ### Prompt
Please create a solution in CPP to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int tests;
cin >> tests;
while (tests--) {
int n, x;
cin >> n >> x;
vector<int> a(n);
for (int& it : a) cin >> it;
sort(a.rbegin(), a.rend());
int ans = 0, last = -1;... | ### Prompt
Please create a solution in cpp to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int a[100001];
int Solve() {
int n, m;
scanf("%d%d", &n, &m);
for (int i = 1; i <= n; ++i) {
scanf("%d", &a[i]);
}
sort(a + 1, a + n + 1);
int ans = 0;
for (int i = n, k = 0; i > 0; --i) {
++k;
if (1ll * k * a[i] >= m) {
++ans;
k = 0;
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int t;
cin >> t;
for (int i = (0); (1) > 0 ? i < (t) : i >= (t); i += (1)) {
int n, x;
cin >> n >> x;
vector<int> num(n);
for (auto& j : num) cin >> j;
sort((num).begin(), (num).end());
int ... | ### Prompt
Generate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int t;
cin >> t;
while (t--) {
long long int n, x;
cin >> n >> x;
vector<long long int> v(n);
for (int i = 0; i < n; i++) {
cin >> v[i];
}
sort(v.begin(), v.end(), greater<long long int>());
long long int mn = L... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
#pragma GCC optimize("unroll-loops,no-stack-protector")
#pragma GCC target("sse,sse2,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
using namespace std;
const int MOD = 1e9 + 7;
const int INF32 = 1 << 30;
const long long INF64 = 1LL << 60;
void solve() {
int t;
cin >> t;
while (t--) {
lo... | ### Prompt
Please formulate a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
long long int n, x, count = 0, sum = 0;
cin >> n >> x;
long long int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
if (x % a[i] == 0)
a[i] = x / a[i];
else
a[i] = x / a[i]... | ### Prompt
Generate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
scanf("%d", &t);
while (t--) {
int n, x, cont = 0, cant = 1;
scanf("%d%d", &n, &x);
int arr[n];
for (int i = 0; i < n; i++) scanf("%d", &arr[i]);
sort(arr, arr + n);
for (int i = n - 1; i >= 0; i--) {
if (cant * arr[i]... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
const int N = 1e6 + 5;
long long a[N], b[N], p[N];
long long cnt1, cnt2, ans1, ans2, ou, ji, sum, y, d, ans, m, n, i,
t = 0, j, k, l, cnt, x, z, c;
string s;
bool cmp(int a, int b) { return a > b; }
int main() {
cin >> t;
while (t--) {
ans = 0;
cnt = 1;
... | ### Prompt
In CPP, your task is to solve the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team ... |
#include <bits/stdc++.h>
using namespace std;
using ll = long long;
vector<ll> a;
int main() {
ll t;
cin >> t;
while (t--) {
ll n, k;
cin >> n >> k;
ll m = n;
a.clear();
ll cnt = 0;
while (m--) {
ll xx;
cin >> xx;
a.push_back(xx);
}
sort(a.rbegin(), a.rend());
... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team ... |
#include <bits/stdc++.h>
using namespace std;
bool sortcol(vector<int>& v1, vector<int>& v2) { return v1[1] < v2[1]; }
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t;
cin >> t;
while (t--) {
int n;
long long x;
cin >> n >> x;
vector<long long> a(n);
for (int i = 0; i <... | ### Prompt
Please formulate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
long long sum = 0, cnt = 0, flag = 0, blb = 0, i, j, mn = LLONG_MAX,
mx = LLONG_MIN, m;
const long long a = 1e9 + 7;
void ts() { cout << "Hello\n"; }
void ss() {
if (blb == 0)
cout << "Yes\n";
else
cout << "No\n";
}
int main() {
int t;
cin >> t;
... | ### Prompt
Create a solution in cpp for the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team m... |
#include <bits/stdc++.h>
using namespace std;
const int inf = 1e9 + 7;
const int N = 1;
void solve() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n, x;
cin >> n >> x;
vector<int> v(n);
for (int i = 0; i < n; i++) cin >> v[i];
sort(v.begin(), v.end());
int ans = 0;
for (int i = n - 1, j = ... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int t;
cin >> t;
while (t--) {
int n, ans = 0;
cin >> n;
long long x, t;
cin >> x;
vector<long long> a;
for (int i = 0; i < n; i++) {
cin >> t;
if (t >= x... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int main(int argc, char *argv[]) {
ios::sync_with_stdio(false);
cin.tie(0);
int T;
cin >> T;
while (T--) {
long long n, x;
cin >> n >> x;
vector<long long> a(n);
for (int i = 0; i < n; i++) cin >> a[i];
sort(a.begin(), a.end());
vector<long... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int t, n, mt[100000], m[100000], ti;
long long int x, a[100000];
int f(int i) {
if (i == n) return 0;
if (i > n) return -1;
if (mt[i] == ti) return m[i];
mt[i] = ti;
int next = ((x + a[i] - 1) / a[i]) - 1, ans;
ans = max(1 + f(i + next + 1), f(i + 1));
m[i] = ... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
long long n, x;
cin >> n >> x;
vector<long long> arr(n);
for (long long i = 0; i < n; i++) cin >> arr[i];
sort(arr.rbegin(), arr.rend());
long long cnt = 0;
long long start = -1;
for (long long i = 0; i < n; i++) {
if ((i - start) * arr[i]... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
const int N = 3e5 + 10;
int a[N];
int main() {
int T;
cin >> T;
while (T--) {
int n, x;
scanf("%d%d", &n, &x);
for (int i = 1; i <= n; i++) scanf("%d", &a[i]);
sort(a + 1, a + n + 1);
int ans = 0;
int lim = n + 1;
for (int i = n; i; i--) {
... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
void merge_sort(int i, int j, int a[], int aux[]);
int main() {
int t;
cin >> t;
while (t--) {
int n, x;
cin >> n >> x;
int team[n], aux[n], temp;
for (int i = 0; i < n; i++) {
cin >> temp;
team[i] = temp;
}
int i;
merge_sort(0,... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int t;
cin >> t;
while (t--) {
long long int n, x, size = 0, ans = 0;
cin >> n >> x;
vector<long long int> v(n);
for (long long int i = 0; i < n; i++) cin >> v[i];
... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team ... |
#include <bits/stdc++.h>
using namespace std;
const long long fix = (long long)1e9 + 7;
long long po2(long long a) {
double temp = a;
if (log2(temp) == (long long)log2(temp)) return log2(temp);
return -1;
}
void tc(long long i) { cout << "Case #" << i + 1 << ": "; }
void yes() { cout << "YES" << '\n'; }
void no()... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
scanf("%d", &t);
while (t--) {
int n, x;
scanf("%d", &n), scanf("%d", &x);
int a[n];
for (int i = 0; i < n; ++i) scanf("%d", &a[i]);
sort(a, a + n);
int ans;
int p = lower_bound(a, a + n, x) - a;
ans = n - p;
for... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1e9 + 7;
vector<long long> adj[1000001];
long long v[1000001] = {0};
int32_t main() {
long long t;
cin >> t;
while (t--) {
long long n, x, c = 1, d = 0;
cin >> n >> x;
vector<long long> a(n);
for (long long i = 0; i < n; i++) cin ... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
const long long MOD = 1e9 + 7;
const long long INF = 1e18;
const string nl = "\n";
long long n, k, ans, hld;
deque<long long> a;
void solve() {
cin >> n >> k;
a.resize(n);
for (auto& i : a) {
cin >> i;
}
ans = hld = 0;
sort(a.rbegin(), a.rend());
for (long... | ### Prompt
In cpp, your task is to solve the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team ... |
#include <bits/stdc++.h>
using namespace std;
int getBits(long long int num) { return (int)log2(num) + 1; }
vector<int> gV(int n) {
vector<int> v;
int input;
for (int i = 0; i < n; i++) {
cin >> input;
v.push_back(input);
}
return v;
}
int* gA(int n) {
int* arr = new int[n];
for (int i = 0; i < n;... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
long long n, x;
cin >> n >> x;
deque<long long> a;
for (long long i = 0; i < n; ++i) {
long long ai;
cin >> ai;
a.push_back(ai);
}
sort(a.begin(), a.end());
reverse(a.begin(), a.end());
long long la = -1;
long long ans = 0;
for... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n, x;
cin >> n >> x;
long long a[n];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
reverse(a, a + n);
long long ans = 0, cnt = 0;
for (int i = 0; i < n; i++) {
long long tmp = (x + a[i] - 1) / a[i];
tmp--;
if (cnt >=... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int i, j, k, l, o, p;
cin >> k;
while (k--) {
cin >> o >> p;
int a[o];
for (i = 0; i < o; i++) cin >> a[i];
sort(a, a + o);
l = 0;
j = 0;
for (i = o - 1; i >= 0; i--) {
j++;
if (a[i] * j >= p) {
l++;
... | ### Prompt
Please formulate a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long t;
cin >> t;
while (t--) {
long long n, k, i, t = 1, ans = 0, s;
cin >> n >> k;
long long a[n];
for (i = 0; i < n; i++) cin >> a[i];
sort(a, a + n, greater<long long>());
for (i = 0; i < n; i++) {
s = a[i] * t;
... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
#pragma GCC optimize("O2,unroll-loops")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,mmx,avx,avx2")
using namespace std;
const int MAXN = (1e5 + 5);
int dp[MAXN];
int x;
vector<int> a;
int n;
int sol(int k) {
if (k > n) {
return -(1 << 30);
;
}
if (k == n) {
return 0;
... | ### Prompt
Create a solution in cpp for the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team m... |
#include <bits/stdc++.h>
using namespace std;
long long n, i, j, k, m;
void solve() {
cin >> n >> m;
long long int a[n];
for (i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
long long int count = 0;
k = n;
for (i = n - 1; i >= 0; i--) {
j = (m / a[i]);
if (m % a[i]) j++;
if (i + j - 1 < k) {
... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
void Msort(int t[], int L, int R) {
int temp[R - L + 1];
int M = (L + R) / 2;
int k = 0;
int i = L;
int j = M + 1;
while (i <= M && j <= R) {
if (t[i] <= t[j]) {
temp[k] = t[i];
i++;
k++;
} else {
temp[k] = t[j];
j++;
k++;
}
}
whil... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
int t;
cin >> t;
while (t--) {
int n, m;
cin >> n >> m;
int arr[n];
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr, arr + n);
int past = n, ans = 0;
for (int i = ... | ### Prompt
Develop a solution in CPP to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
long long int mod_pow(long long int x, int n) {
if (n == 0) return 1;
long long int res = 1;
while (n > 0) {
if (n & 1) res = res * x % 100000007;
x = x * x % 100000007;
n >>= 1;
}
return res;
}
vector<long long int> allDivisors(long long int n) {
ve... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
template <typename Arg1>
void __f(const char *name, Arg1 &&arg1) {
cerr << name << " : " << arg1 << endl;
}
template <typename Arg1, typename... Args>
void __f(const char *names, Arg1 &&arg1, Args &&...args) {
const char *comma = strchr(names + 1, ',');
cerr.write(nam... | ### Prompt
Construct a Cpp code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, x;
cin >> n >> x;
vector<int> as(n);
for (int i = 0; i < n; i++) {
cin >> as[i];
}
sort(as.begin(), as.end());
int j = n;
int i = n;
int factor = 1;
int ans = 0;
while... | ### Prompt
Generate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
void solve() {
long long n, x;
std::cin >> n >> x;
std::vector<long long> a(n);
for (long long i = 0; i < n; i++) {
std::cin >> a[i];
}
std::sort(a.begin(), a.end());
long long res = 0;
long long i = n - 1;
while (i >= 0 && a[i] >= x) {
res++;
i--;
}
while (i >... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long t;
cin >> t;
while (t-- > 0) {
long long n, x;
cin >> n >> x;
vector<long long> a(n);
for (long long i = 0; i < n; i++) cin >> a[i];
sort(a.begin(), a.end());
long long m = 0;
long long ans = 0;
for (long long i =... | ### Prompt
Generate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
int t, n, x, a[100100];
bool cmp(int a, int b) { return a > b; }
int main() {
scanf("%d", &t);
while (t--) {
scanf("%d%d", &n, &x);
for (int i = 0; i < n; i++) scanf("%d", &a[i]);
sort(a, a + n, cmp);
int i = 0, j, sum = 0;
for (j = 0; j < n; j++)
... | ### Prompt
Develop a solution in Cpp to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
long long int tt;
vector<long long int> a;
bool check(long long int sz, long long int x) {
if (sz == 0) {
return true;
}
long long int n = a.size();
long long int s = 0;
long long int ans = 0;
for (long long int i = n - 1; i >= 0; i--) {
s++;
long lo... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
int main(int argc, char const *argv[]) {
int t = 1;
scanf("%d", &t);
while (t--) {
int n, k;
scanf("%d %d", &n, &k);
vector<int> a(n);
for (int &i : a) scanf("%d", &i);
sort(a.rbegin(), a.rend());
int cnt = 0, pr = 0, mn = 1e9;
for (int i =... | ### Prompt
Your task is to create a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
long long int n, x, c = 0;
cin >> n >> x;
vector<long long int> v(n);
for (int i = 0; i < n; i++) {
cin >> v[i];
}
sort(v.begin(), v.end());
for (int i = n - 1; i >= 0; i--) {
if (v[i]... | ### Prompt
Create a solution in cpp for the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team m... |
#include <bits/stdc++.h>
using ll = long long;
using ld = long double;
using ull = unsigned long long;
void solve() {
int n, x;
std::cin >> n >> x;
std::vector<int> a(n);
for (int i = 0; i < n; i++) std::cin >> a[i];
std::sort(a.rbegin(), a.rend());
int teams = 0;
int i = 0;
while (i < n) {
int size... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t-- > 0) {
long long int n, x;
cin >> n >> x;
long long int arr[n];
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr, arr + n);
long long int ans = 0;
long long int prev = 0;
for (in... | ### Prompt
Please formulate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int n;
long long x;
long long a[100005];
int main() {
int test;
scanf("%d", &test);
while (test--) {
scanf("%d%lld", &n, &x);
for (int i = 0; i < n; i++) {
scanf("%lld", &a[i]);
}
sort(a, a + n);
long long num = 0;
long long ans = 0;
... | ### Prompt
Generate a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
template <class T>
inline bool chmax(T &a, T b) {
if (a < b) {
a = b;
return true;
}
return false;
}
template <class T>
inline bool chmin(T &a, T b) {
if (a > b) {
a = b;
return true;
}
return false;
}
template <typename Arg1>
void __f(const char... | ### Prompt
In CPP, your task is to solve the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team ... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1e9 + 7;
const long long mxr = 1e5 + 5;
bool cmp(int a, int b) { return a > b; }
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
int t;
cin >> t;
while (t--) {
int n, x;
cin >> n >> x;
vector<int> pr(n);
for (int i ... | ### Prompt
Create a solution in CPP for the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team m... |
#include <bits/stdc++.h>
using namespace std;
bool comparePairs(const std::pair<int, int>& lhs,
const std::pair<int, int>& rhs) {
if (lhs.second < rhs.second) return 1;
return 0;
}
void solve() {
int n, x;
int arr[100000];
std::vector<pair<int, int> > v;
int i;
cin >> n >> x;
for (i = ... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
const int N = 1e5 + 100, M = 1e6 + 100, SQ = sqrt(2e5), LG = 23, base = 2,
second = 1e3 + 100;
const long long mod = 1e9 + 7, MOD = 1e9 + 9, Inf = 9223372036854775807;
const long long INF = 1e9, inf = 1e18, super_inf = ~0ull / 4;
const long double Pi = (22 * 1.0) / (7 * 1.0);
using na... | ### Prompt
Generate a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
int solve() {
long long n, x;
cin >> n >> x;
long long i;
long long a[n], ans = 0;
for (i = 0; i < n; i++) {
cin >> a[i];
if (a[i] >= x) {
ans++;
}
}
sort(a, a + n);
int cnt = 0;
for (i = n - 1; i >= 0; i--) {
if (a[i] >= x) {
c... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
int INF = 0x3f3f3f3f;
long long MOD = 1000000007;
long long binpow(long long a, long long b, long long c = 1e18) {
long long res = 1;
while (b > 0) {
if (b & 1) {
res *= a;
res %= c;
}
a *= a;
a %= c;
b >>= 1;
}
return res;
}
int main... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, y, cnt = 0;
cin >> n >> y;
int a[n];
for (int i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
int k = 0;
for (int i = n - 1; i >= 0; i--) {
k++;
if (k * a[i] >= y) {
cnt... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
vector<int> gV(int n) {
vector<int> v(n);
for (int i = 0; i < n; i++) {
cin >> v[i];
}
return v;
}
int* gA(int n) {
int* arr = new int[n];
for (int i = 0; i < n; i++) cin >> arr[i];
return arr;
}
void solve() {
long long int n, x, ans = 0;
cin >> n >> ... | ### Prompt
Construct a cpp code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
long long mod = 1000000007;
struct hash_pair {
template <class T1, class T2>
size_t operator()(const pair<T1, T2>& p) const {
auto hash1 = hash<T1>{}(p.first);
auto hash2 = hash<T2>{}(p.second);
return hash1 ^ hash2;
}
};
int main() {
ios_base::sync_with... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int test;
scanf("%d", &(test));
for (int t = 1; t <= test; t++) {
long long int x, n, cnt = 0;
scanf("%lld", &(n)), scanf("%lld", &(x));
long long int a[n + 5];
for (int i = 1; i <= n; i++) scanf("%lld", &(a[i]));
sort(a + 1, a + n + 1... | ### Prompt
Please provide a cpp coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
long long t;
cin >> t;
while (t--) {
long long n, x;
cin >> n >> x;
long long arr[n];
for (long long i = 0; i < n; i++) cin >> arr[i];
sort(arr, arr + n);
long long cnt = 0;
long long ans = 0;
for (long long i = n - 1; ... | ### Prompt
Generate a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int t;
cin >> t;
while (t--) {
long long n, x;
cin >> n >> x;
long long a[n];
for (long long i = 0; i < n; i++) cin >> a[i];
;
sort(a, a + n);
long long cnt = 0, ans = 0;
for (lo... | ### Prompt
Please create a solution in Cpp to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
long long t;
cin >> t;
while (t--) {
long long n, x;
cin >> n >> x;
long long a[n];
for (long long i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
long long ans = 0;
l... | ### Prompt
Generate a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
using namespace chrono;
void _print(long long t) { cerr << t; }
void _print(string t) { cerr << t; }
void _print(char t) { cerr << t; }
void _print(long double t) { cerr << t; }
void _print(double t) { cerr << t; }
void _print(unsigned long long t) { cerr << t; }
template <... | ### Prompt
Please provide a CPP coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, x, a = 0, e = 0;
cin >> n >> x;
int arr[n];
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
sort(arr, arr + n, greater<int>());
for (int i = 0; i < n; i++) {
e++;
if (e * a... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
bool testing = false;
bool stress = false;
bool recursion = false;
using ll = long long;
using ull = unsigned long long;
using ld = long double;
template <typename T1, typename T2>
ostream &operator<<(ostream &os, pair<T1, T2> p) {
os << p.first << " " << p.second;
retu... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
long long t = 1;
cin >> t;
while (t--) {
long long n, x;
cin >> n >> x;
vector<long long> a(n);
for (long long i = 0; i < n; i++) {
cin >> a[i];
}
sort(a.begin(), a.... | ### Prompt
Generate a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
vector<int> vec;
int n, x;
void Fun(int l, int r, int& c) {
if (l >= n) return;
int t = ceil(1.0 * x / vec[l]);
if (r - t + 1 >= l) {
++c;
Fun(l + 1, r - t + 1, c);
}
return;
}
void Solve() {
cin >> n >> x;
vec.resize(n);
for (auto& el : vec) cin >> ... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int T, n, x;
int num[100001];
int main() {
cin >> T;
while (T--) {
cin >> n >> x;
for (int i = 0; i < n; ++i) cin >> num[i];
sort(num, num + n);
int ans = 0, cnt = 0;
for (int i = n - 1; i >= 0; i--) {
if (++cnt * num[i] >= x) {
ans++;
... | ### Prompt
Generate a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
using namespace std;
using ll = long long;
using ld = long double;
using VI = vector<ll>;
using VV = vector<VI>;
using VS = vector<string>;
using PII = pair<ll, ll>;
template <typename A, typename B>
string to_string(pair<A, B> p);
template <typename A, typename B,... | ### Prompt
Your task is to create a CPP solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
long long n, m, x, y, z, v, d, i, j, k, sum, t, ans, Q;
cin >> t;
while (t--) {
cin >> n >> x;
long long a[n];
for (i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
long long cnt = 1, mn = a[n - 1];
ans = 0;
for (i = n - 1; ... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
template <typename T>
void deb(initializer_list<T> l) {
for (auto& e : l) cout << e << ' ';
cout << endl;
}
void solve() {
long long n, x;
cin >> n >> x;
vector<long long> a(n);
for (auto& e : a) cin >> e;
sort(a.begin(), a.end(), greater<long long>());
long... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
;
long long t;
cin >> t;
while (t--) {
long long n, x;
cin >> n >> x;
long long a[n];
for (long long i = 0; i < n; i++) cin >> a[i];
sort(a, a + n);
long long count = 0, value = 0, prev = ... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
long int n, x, pos = 1;
cin >> n >> x;
long int* a = new long int[n];
for (auto i = 0; i < n; i++) {
cin >> a[i];
if (a[i] > x) {
a[i] = 0;
} else {
if (x % a[i] == 0) {
... | ### Prompt
In Cpp, your task is to solve the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team ... |
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 200;
long long a[N];
void solve() {
long long n, x;
cin >> n >> x;
for (int i = 1; i <= n; i++) {
cin >> a[i];
}
sort(a + 1, a + 1 + n);
reverse(a + 1, a + 1 + n);
long long mi = 1e9, ans = 0, k = 0;
for (int i = 1; i <= n; i++) {
... | ### Prompt
Your task is to create a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
void faster() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
}
const long long INF = 1e18;
const long long MAXN = 1 << 17;
const long long MOD = 998244353;
const long long LOG = ceil(log(MAXN) / log(2));
const long double EPS = 1e-9;
const int dx[8... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
using namespace std;
int gcd(int a, int b) {
if (b == 0) return a;
return gcd(b, a % b);
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int tc = 1;
cin >> tc;
while (tc--) {
int n, x;
cin >> n >> x;
int a[n + 1];
for (int i = 0; i < n; i++) cin >> ... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programme... |
#include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
using namespace std;
int a[100005];
void solve() {
int n;
cin >> n;
int x;
cin >> x;
for (int i = 1; i <= n; i++) cin >> a[i];
sort(a + 1, a + n + 1, greater<int>());
int sum = 0, ans = 0;
for (int i = 1; i <= n; i++) {
sum++;
if (sum * a[i]... | ### Prompt
Develop a solution in cpp to the problem described below:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the ... |
#include <bits/stdc++.h>
using namespace std;
int xx[4] = {0, 0, 1, -1};
int yy[4] = {-1, 1, 0, 0};
long long arr[100000];
long long tree[100001];
int main() {
long long t;
scanf("%lld", &t);
;
while (t--) {
long long n, m;
scanf("%lld %lld", &n, &m);
std::vector<long long> vec(n);
for (int i = ... | ### Prompt
Generate a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team mul... |
#include <bits/stdc++.h>
using namespace std;
int dx[] = {1, 0, -1, 0};
int dy[] = {0, 1, 0, -1};
char dir[] = {'D', 'R', 'U', 'L'};
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int t;
cin >> t;
while (t--) {
long long n, x;
cin >> n >> x;
vector<long long> a(n);... | ### Prompt
Your task is to create a Cpp solution to the following problem:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers i... |
#include <bits/stdc++.h>
using namespace std;
int T, n, x, p, tot, cuenta;
vector<int> a;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cin >> T;
for (int t = (1); t <= (T); t++) {
a.clear();
cin >> n >> x;
for (int i = (1); i <= (n); i++) {
cin >> p;
a.push_back(p);
... | ### Prompt
Construct a CPP code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n, x;
cin >> n >> x;
vector<int> a(n);
for (int& i : a) cin >> i;
sort(a.begin(), a.end());
reverse(a.begin(), a.end());
vector<int> dp(n + 1);
int ans = 0;
for (int i = 0; i < n; ++i) {
int cnt = (x + a[i] - 1) / a[i];
if (cnt >... | ### Prompt
Construct a cpp code solution to the problem outlined:
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the tea... |
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