choices dict | answerKey listlengths 1 1 | question stringlengths 8 751 | rationale stringlengths 8 1.53k | dataset stringclasses 1
value |
|---|---|---|---|---|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.045388",
"4.5388",
"453.88",
"473.88"
]
} | [
"A"
] | [ ( 3.242 x 14 ) / 100 ] = ? | "answer multiplying 3.242 x 14 = 4.5388 now divide 4.5388 by 100 so , 4.5388 Γ· 100 = 0.045388 β΄ shift the decimal two places to the left as 100 correct option : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"600",
"700",
"800",
"900"
]
} | [
"C"
] | i chose a number and divide it by 5 . then i subtracted 154 from the result and got 6 . what was the number i chose ? | "solution : let xx be the number i chose , then x / 5 β 154 = 6 x / 5 = 160 x = 800 answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.2",
"0.5",
"2.5",
"1.8"
]
} | [
"A"
] | if 0.60 : x : : 6 : 2 , then x is equal to | "sol . ( x Γ 6 ) = ( 0.60 Γ 2 ) β x = 0.60 / 6 = 0.2 . answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 2",
"1 / 8",
"3 / 4",
"1 / 4"
]
} | [
"D"
] | what is the probability of always having x + y > 0 , where y < 0 | "total value of x can be : 1 . x < 0 ; 2 . x = 0 ; 3 . x > 0 but less than y in magnitude 4 . x > 0 as well as | y | so probability of having x + y > 0 would be 1 / 4 answer : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"700 hours",
"350 hours",
"1400 hours",
"1010 hours"
]
} | [
"A"
] | speed of a boat in standing water is 14 kmph and the speed of the stream is 1.2 kmph . a man rows to a place at a distance of 4864 km and comes back to the starting point . the total time taken by him is | explanation : speed downstream = ( 14 + 1.2 ) = 15.2 kmph speed upstream = ( 14 - 1.2 ) = 12.8 kmph total time taken = ( 4864 / 15.2 ) + ( 4864 / 12.8 ) = 320 + 380 = 700 hours . answer : option a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"33.25",
"35.75",
"34.25",
"35"
]
} | [
"B"
] | the avearge score of a cricketer for 10 matches is 38.9 runs . if the average for the first 6 matches is 41 . then find the average for the last 4 matches ? | solution required average = ( 38.9 x 10 ) - ( 41 x 6 ) / 4 = 143 / 4 . = 35.75 answer b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"77.76",
"7.776",
"0.7776",
"0.07776"
]
} | [
"D"
] | 6 x 0.6 x 0.06 x 0.006 x 60 = ? | "explanation : ? = 6 x 6 / 10 x 6 / 100 x 6 / 1000 x 60 = 77760 / 1000000 = 7776 / 100000 = 0.07776 answer : option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0",
"1",
"2",
"3"
]
} | [
"A"
] | if z is a multiple of 8902 , what is the remainder when z ^ 2 is divided by 4 ? | "2 is a factor of 8902 , so 2 is a factor of z . then 2 ^ 2 = 4 is a factor of z ^ 2 . then the remainder when z ^ 2 is divided by 4 is 0 . the answer is a ." | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"10.6 kg",
"10.8 kg",
"7 kg",
"14.9 kg"
]
} | [
"C"
] | the average weight of 19 students is 15 kg . by the admission of a new student the average weight is reduced to 14.6 kg . the weight of the new student is ? | "answer weight of new student = total weight of all 20 students - total weight of initial 19 students = ( 20 x 14.6 - 19 x 15 ) kg = 7 kg . correct option : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 1200",
"rs . 1300",
"rs . 2500",
"rs . 2000"
]
} | [
"C"
] | a man invests rs . 5,000 at the rate of 5 % per annum . how much more should he invest at the rate of 8 % , so that he can earn a total of 6 % per annum ? | "explanation : interest on rs . 5000 at 5 % per annum = ( 5000 Γ 5 Γ 1 ) / 100 = rs . 250 let his additional investment at 8 % = x interest on rs . x at 8 % per annum = ( x Γ 8 Γ 1 ) / 100 = 2 x / 25 . to earn 6 % per annum for the total , interest = ( 5000 + x ) Γ 6 Γ 1 / 100 . = > 250 + 2 x / 25 = ( 5000 + x ) Γ 6 Γ ... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3 / 4",
"1 / 5",
"1 / 10",
"1 / 11"
]
} | [
"A"
] | what will be the fraction of 75 % | "explanation : it will 75 * 1 / 100 = 3 / 4 option a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5 / 3",
"9 / 5",
"41 / 4",
"41 / 12"
]
} | [
"A"
] | the value of ( 0.2 Γ 0.2 + 0.01 ) ( 0.1 Γ 0.1 + 0.02 ) - 1 is equal to | "solution given expression ( 0.2 Γ 0.2 + 0.01 ) / ( 0.1 Γ 0.1 Γ + 0.02 ) = 0.04 + 0.01 / 0.01 + 0.02 = 0.05 / 0.03 = 5 / 3 . answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4236",
"4306",
"4336",
"5336"
]
} | [
"D"
] | in a division sum , the divisor is 10 times the quotient and 5 times the remainder . if the remainder is 46 , the divident is | "solution divisor = ( 5 Γ 46 ) = 230 . also . 10 Γ q = 230 βΉ = βΊ q = 23 . and , r = 46 . dividend = ( 230 Γ 23 + 46 ) = 5336 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5 / 2",
"2 β 5",
"5",
"4 β 2"
]
} | [
"A"
] | 10 meters of wire is available to fence off a flower bed in the form of a circular sector . what must the radius of the circle in meters be , if we wish to have a flower bed with the greatest possible surface area ? | "area of sector , a = x / 360 * pi * r ^ 2 circumference of the sector = 10 = > x / 360 * 2 * pi * r + 2 r = 20 = > 2 a / r + 2 r = 10 or 2 a + 2 r ^ 2 = 10 r = > a = r 5 - r ^ 2 = r 5 - r ^ 2 we will now max using derivations i . e 5 - 2 r = 0 r = 5 / 2 a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"44 %",
"125 %",
"144 %",
"40 %"
]
} | [
"B"
] | if the radius of a circle is increased by 50 % then the area is increased by : | "initially a = pi * r 2 now r 2 = 150 / 100 r then area = pi * ( 150 r / 100 ) 2 area = 225 r / 100 that is area increases from 100 to 225 = increase in area = 125 % answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1",
"8",
"12",
"16"
]
} | [
"A"
] | find the greatest number which leaves the same remainder when it divides 25 , 62 and 105 . | "105 - 62 = 43 62 - 25 = 37 105 - 25 = 80 the h . c . f of 37 , 43 and 80 is 1 . answer : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"18 %",
"20 %",
"21 %",
"23 %"
]
} | [
"A"
] | two kinds of vodka are mixed in the ratio 1 : 2 and 2 : 1 and they are sold fetching the profit 20 % and 20 % respectively . if the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4 / 3 and 5 / 3 times respectively , then the mixture will fetch the profit of | answer : a . | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"80",
"100",
"70.5",
"90"
]
} | [
"C"
] | if 85 % of 3 / 5 of a number is 36 , then the number is ? | "let the number be x . then 85 % of 3 / 5 of x = 36 85 / 100 * 3 / 5 * x = 36 x = ( 36 * 100 / 51 ) = 70.5 required number = 70.5 . correct option : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"84",
"102",
"76",
"70"
]
} | [
"C"
] | 4,7 , 11,18 , 29,47 , . . . ? . . , 123,199 | "the addition of difference between each no . is equal to latter no . so , difference between 47 and 76 is 29 which is previous no . of 47 answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"756",
"750",
"600",
"760"
]
} | [
"A"
] | in an office , totally there are 1800 employees and 60 % of the total employees are males . 30 % of the males in the office are at - least 50 years old . find the number of males aged below 50 years ? | "number of male employees = 1800 * 60 / 100 = 1080 required number of male employees who are less than 50 years old = 1080 * ( 100 - 30 ) % = 1080 * 70 / 100 = 756 . answer : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2300",
"600",
"250",
"300"
]
} | [
"D"
] | if 25 lines are drawn in a plane such that no two of them are parallel and no three are concurrent , then in how many points do they intersect ? | "1 st line - 0 points 2 nd line - new 1 point 3 td line - new 2 points + old 1 point 4 th line - new 3 points + old 2 + 1 points 5 th line - new 4 points + old 3 + 2 + 1 points n - th line - ( n - 1 ) points + ( n - 2 ) . . . . 3 + 2 + 1 therefore , s = 1 + 2 + 3 . . . ( n - 1 ) s = ( n - 1 ) n / 2 = 24 * 25 / 2 = 300 ... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"12 hours",
"68 hours",
"36 hours",
"58 hours"
]
} | [
"B"
] | speed of a boat in standing water is 9 kmph and the speed of the stream is 6 kmph . a man rows to place at a distance of 170 km and comes back to the starting point . the total time taken by him is : | "sol . speed upstream = 3 kmph ; speed downstream = 15 kmph . β΄ total time taken = [ 105 / 7.5 + 105 / 10.5 ] hours = 68 hours . answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20 % loss",
"6.25 % profit",
"33.33 % loss",
"30.33 % loss"
]
} | [
"B"
] | if the cost price of 17 articles is equal to the selling price of 16 articles , what is the percentage of profit or loss that the merchant makes ? | "explanation : let cost price of 1 article be re . 1 . therefore , cost price of 17 articles = rs . 17 . selling price of 16 articles = rs . 17 therefore , selling price of 17 articles is : - = > 17 / 16 Γ£ β 17 = > 18.06 therefore , profit = selling price - cost price . = > 18.06 Γ’ Λ β 17 = 1.06 hence , the percentage ... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"70.11",
"72.02",
"86.5",
"78.2"
]
} | [
"C"
] | the average expenditure of a labourer for 7 months was 85 and he fell into debt . in the next 4 months by reducing his monthly expenses to 60 he not only cleared off his debt but also saved 30 . his monthly income is | "income of 7 months = ( 7 Γ 85 ) β debt = 595 β debt income of the man for next 4 months = 4 Γ 60 + debt + 30 = 270 + debt β΄ income of 10 months = 865 average monthly income = 865 Γ· 10 = 86.5 answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"7580",
"12960",
"8290",
"8640"
]
} | [
"B"
] | a leak in the bottom of a tank can empty the full tank in 9 hours . an inlet pipe fills water at the rate of 6 litres a minute . when the tank is full , the inlet is opened and due to the leak , the tank is empty in 12 hours . how many litres does the cistern hold ? | "solution work done by the inlet in 1 hour = ( 1 / 9 - 1 / 12 ) = 1 / 36 work done by the inlet in 1 min . = ( 1 / 36 Γ 1 / 60 ) = 0.000463 volume of 0.000463 part = 6 litres . therefore , volume of whole = 1 / 0.000463 x 6 βΉ = βΊ 12960 litres . answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"160",
"80",
"200",
"220"
]
} | [
"B"
] | a number whose fifth part increased by 2 is equal to its fourth part diminished by 2 is ? | "answer let the number be n . then , ( n / 5 ) + 2 = ( n / 4 ) - 2 Γ’ β‘ β ( n / 4 ) - ( n / 5 ) = 4 Γ’ β‘ β ( 5 n - 4 n ) / 20 = 4 Γ’ Λ Β΄ n = 80 option : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"25",
"90",
"100",
"140"
]
} | [
"B"
] | if the average ( arithmetic mean ) of a and b is 45 and the average of b and c is 90 , what is the value of c Γ’ Λ β a ? | "the arithmetic mean of a and b = ( a + b ) / 2 = 45 - - a + b = 90 - - 1 similarly for b + c = 180 - - 2 subtracting 1 from 2 we have c - a = 90 ; answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20,20",
"20,8",
"25,15",
"30,10"
]
} | [
"B"
] | the ages of two persons differ by 12 years . if 5 years ago , the elder one be 5 times as old as the younger one , their present ages ( in years ) are respectively | "explanation : let their ages be x and ( x + 12 ) years . 5 ( x - 5 ) = ( x + 12 - 5 ) or 4 x = 32 or x = 8 . their present ages are 20 years and 8 years option b" | MathQA |
{
"label": [
"A",
"C",
"D",
"E"
],
"text": [
"$ 68.25",
"$ 6825.00",
"$ 6.82",
"$ 682.50"
]
} | [
"E"
] | peter takes a loan of $ 100000 with 12 % annual interest : the interest is paid once , at the end of the year . martha takes a loan of $ 100000 with 12 % annual interest , compounding monthly at the end of each month . at the end of one full year , compared to peter ' s loan interest , approximately how much more does ... | peters interest = $ 100000 * 0.12 = $ 12000 or $ 1000 each month . martha β s interest , 12 % / 12 = 1 % each month : for the 1 st month = $ 100000 * 0.01 = $ 1000 ; for the 2 nd month = $ 1000 + 1 % of 1000 = $ 1010 , so we would have interest earned on interest ( very small amount ) ; for the 3 rd month = $ 1010 + 1 ... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"17",
"15",
"12",
"- 8 / 5"
]
} | [
"C"
] | β 289 - β 625 Γ· β 25 is equal to ? | answer β 289 - β 625 Γ· β 25 = β 17 x 17 - β 25 x 25 Γ· β 5 x 5 = 17 - 25 Γ· 5 = 17 - 5 = 12 correct option : c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3572021",
"3570221",
"3572012",
"3752012"
]
} | [
"A"
] | find the missing value : ? - 1936248 = 1635773 | "let x - 1936248 = 1635773 . then , x = 1635773 + 1936248 = 3572021 answer is a ." | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 209.20",
"rs . 309.20",
"rs . 409.20",
"rs . 509.20"
]
} | [
"C"
] | a tank is 25 m long 12 m wide and 6 m deep . the cost of plastering its walls and bottom at 55 paise per sq m is | explanation : area to be plastered = [ 2 ( l + b ) Γ£ β h ] + ( l Γ£ β b ) = [ 2 ( 25 + 12 ) Γ£ β 6 ] + ( 25 Γ£ β 12 ) = 744 sq m cost of plastering = 744 Γ£ β ( 55 / 100 ) = rs . 409.20 answer : c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 473",
"rs . 374",
"rs . 495",
"rs . 788"
]
} | [
"D"
] | compound interest of rs . 5000 at 10 % per annum for 1 1 / 2 years will be ( interest compounded half yearly ) . | "10 % interest per annum will be 5 % interest half yearly for 3 terms ( 1 1 / 2 years ) so compound interest = 5000 [ 1 + ( 5 / 100 ) ] ^ 3 - 5000 = 5000 [ ( 21 / 20 ) ^ 3 - 1 ] = 5000 ( 9261 - 8000 ) / 8000 = 5 * 1261 / 8 = 788 answer : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 13123.20",
"rs 14103.48",
"rs 12172.48",
"rs 14172.48"
]
} | [
"D"
] | what will be the compound interest on rs . 35000 after 3 years at the rate of 12 % per annum | "explanation : ( 35000 Γ ( 1 + 12 / 100 ) 3 ) = > 35000 Γ 28 / 25 Γ 28 / 25 Γ 28 / 25 = > 49172.48 so compound interest will be 49172.48 - 35000 = rs 14172.48 option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"34",
"41",
"68",
"88"
]
} | [
"B"
] | a rectangular field is to be fenced on three sides leaving a side of 20 feet uncovered . if the area of the field is 210 sq . feet , how many feet of fencing will be required ? | "explanation we have : l = 20 ft and lb = 210 sq . ft . so , b = 10.5 ft . length of fencing = ( l + 2 b ) = ( 20 + 21 ) ft = 41 ft . answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"896",
"1008",
"1120",
"1024"
]
} | [
"B"
] | find the smallest four - digit number which is a multiple of 112 . | "the smallest four digit number is 1000 . if 1000 is divided by 112 , the remainder is 104 . 112 - 104 = 8 , if 8 is added to 1000 , it will become the smallest four digit number and a multiple of 112 . answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0",
"6993",
"699930",
"996330"
]
} | [
"C"
] | the difference between the place values of two sevens in the numerical 69758472 is | "required difference = ( 700000 - 70 ) = 699930 . answer is c" | MathQA |
{
"label": [
"A",
"B",
"C",
"E"
],
"text": [
"2",
"0",
"- 1",
"1"
]
} | [
"A"
] | a set s = { x , - 8 , - 5 , - 3 , 3 , 6 , 9 , y } with elements arranged in increasing order . if the median and the mean of the set are the same , what is the value of | x | - | y | ? | "median of the set = ( - 3 + 3 ) / 2 = 0 as per statement , mean of the set = 0 mean of the set | y | - | x | + 18 - 16 = 0 ( where x is negative n y is positive ) | y | - | x | = - 2 so the absolute difference between two numbers is 2 answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 : 3",
"2 : 3",
"3 : 4",
"7 : 9"
]
} | [
"D"
] | find the ratio in which rice at rs . 7.20 a kg be mixed with rice at rs . 5.60 a kg to produce a mixture worth rs . 6.30 a kg ? | "solution required ratio = 70 : 90 = 7 : 9 answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"186",
"176",
"175",
"96"
]
} | [
"A"
] | a train passes a man standing on a platform in 8 seconds and also crosses the platform which is 279 metres long in 20 seconds . the length of the train ( in metres ) is : | "explanation : let the length of train be l m . acc . to question ( 279 + l ) / 20 = l / 8 2232 + 8 l = 20 l l = 2232 / 12 = 186 m answer a" | MathQA |
{
"label": [
"A",
"C",
"D",
"E"
],
"text": [
"144 %",
"96 %",
"80 %",
"64 %"
]
} | [
"A"
] | mary ' s income is 60 % more than tim ' s income and tim ' s income is 10 % less than juan ' s income . what % of juan ' s income is mary ' s income . | "even i got 96 % j = 100 t = 100 * 0.9 = 90 m = 90 * 1.6 = 144 if mary ' s income is x percent of j m = j * x / 100 x = m * 100 / j = 144 * 100 / 100 = 144 ans : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"784598562",
"765858254",
"784569825",
"786461346"
]
} | [
"D"
] | 78654 * 9999 | "explanation : 78654 * ( 10000 - 1 ) = 786540000 - 78654 = 786461346 option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"14 / 15",
"43 / 45",
"4 / 5",
"5 / 4"
]
} | [
"B"
] | jack and jill are marathon runners . jack can finish a marathon ( 43 km ) in 4.5 hours and jill can run a marathon in 4.3 hours . what is the ratio of their average running speed ? ( jack : jill ) | "average speed of jack = distance / time = 43 / ( 9 / 2 ) = 86 / 9 average speed of jill = 43 / ( 4.2 ) = 10 ratio of average speed of jack to jill = ( 86 / 9 ) / 10 = 86 / 90 = 43 / 45 answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3 : 5",
"9 : 25",
"5 : 2",
"25 : 9"
]
} | [
"C"
] | two interconnected , circular gears travel at the same circumferential rate . if gear a has a diameter of 20 centimeters and gear b has a diameter of 50 centimeters , what is the ratio of the number of revolutions that gear a makes per minute to the number of revolutions that gear b makes per minute ? | "same circumferential rate means that a point on both the gears would take same time to come back to the same position again . hence in other words , time taken by the point to cover the circumference of gear a = time take by point to cover the circumference of gear b time a = 2 * pi * 25 / speed a time b = 2 * pi * 10... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 950",
"rs . 1500",
"rs . 1000",
"rs . 1400"
]
} | [
"D"
] | a trader sells 40 metres of cloth for rs . 8200 at a profit of rs . 35 per metre of cloth . how much profit will the trder earn on 40 metres of cloth ? | "explanation : sp of 1 metre cloth = 8200 / 40 = rs . 205 . cp of 1 metre cloth = rs . 205 β 35 = rs . 170 cp on 40 metres = 170 x 40 = rs . 6800 profit earned on 40 metres cloth = rs . 8200 β rs . 6800 = rs . 1400 . answer : option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 186",
"rs . 258",
"rs . 486",
"rs . 586"
]
} | [
"A"
] | a tank is 25 m long 12 m wide and 6 m deep . the cost of plastering its walls and bottom at 25 paise per sq m is | "explanation : area to be plastered = [ 2 ( l + b ) Γ£ β h ] + ( l Γ£ β b ) = [ 2 ( 25 + 12 ) Γ£ β 6 ] + ( 25 Γ£ β 12 ) = 744 sq m cost of plastering = 744 Γ£ β ( 25 / 100 ) = rs . 186 answer : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20 %",
"25 %",
"18 %",
"33 1 / 3 %"
]
} | [
"D"
] | if the given two numbers are respectively 6 % and 18 % of a third number , then what percentage is the first of the second ? | "here , l = 6 and m = 18 therefore , first number = l / m x 100 % of second number = 6 / 18 x 100 % of second number = 33 1 / 3 % of second number answer : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"50.25 m', '",
"50.5 m', '",
"50.65 m', '",
"50.85', '"
]
} | [
"B"
] | a housing society has been allotted a square piece of land measuring 2550.25 sq . m . what is the side of the plot ? | solution side = β 2550.25 = β 255025 / 100 = 505 / 10 = 50.5 m . answer b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1.17 kmph",
"1.67 kmph",
"0.69 kmph",
"1.45 kmph"
]
} | [
"B"
] | jake took a bus from home to market , that travels at 10 kmph . while walking back at 2 kmph , halfway through , he suddenly realized he was getting late and he cycled back the remaining distance in 50 kmph . find the average speed . | let the distance be 2 x ( one way ) time taken by bus = 2 x / 10 , by walking = x / 2 , by cycling = x / 50 hours : . average speed = total distance / total time = 2 x / x / 5 + x / 2 + x / 50 = 2 * 60 / 12 + 30 + 1.2 = 1.67 answer : b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2 kg",
"2.4 kg",
"2.5 kg",
"10 kg"
]
} | [
"C"
] | fresh grapes contain 90 % by weight while dried grapes contain 20 % water by weight . what is the weight of dry grapes available from 20 kg of fresh grapes ? | "the weight of non - water in 20 kg of fresh grapes ( which is 100 - 90 = 10 % of whole weight ) will be the same as the weight of non - water in x kg of dried grapes ( which is 100 - 20 = 80 % of whole weight ) , so 20 β 0.1 = x β 0.8 - - > x = 2.5 answer : c ." | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 2",
"1 / 4",
"3 / 4",
"2 / 3"
]
} | [
"C"
] | if a * b * c = 195 , b * c * d = 65 , c * d * e = 1000 and d * e * f = 250 the ( a * f ) / ( c * d ) = ? | explanation : a Γ’ Λ β b Γ’ Λ β c / b Γ’ Λ β c Γ’ Λ β d = 195 / 65 = > a / d = 3 d Γ’ Λ β e Γ’ Λ β f / c Γ’ Λ β d Γ’ Λ β e = 250 / 1000 = > f / c = 1 / 4 a / d * f / c = 3 * 1 / 4 = 3 / 4 answer : c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"26 m Β³",
"28 m Β³",
"44 m Β³",
"46 m Β³"
]
} | [
"C"
] | a circular well with a diameter of 2 metres , is dug to a depth of 4 metres . what is the volume of the earth dug out ? | "sol . volume = β r Β² h = [ 22 / 7 * 1 * 1 * 14 ] m Β³ = 44 m Β³ answer c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"14",
"10",
"8",
"9.5"
]
} | [
"A"
] | the average of 5 quantities is 8 . the average of 3 of them is 4 . what is the average of remaining 2 numbers ? | "answer : a ( 5 x 8 - 3 x 4 ) / 2 = 14" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"40",
"400",
"800",
"1600"
]
} | [
"A"
] | find 80 / ? = ? / 20 | "answer let 80 / y = y / 20 then , y 2 = 80 x 20 = 1600 β΄ y = β 1600 = 40 . option : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"15",
"70",
"20",
"60"
]
} | [
"D"
] | find the average of all the numbers between 40 and 80 which are divisible by 3 . | "sol . average = ( 42 + 45 + 48 + 51 + 54 + 57 + 60 + 63 + 66 + 69 + 72 + 75 + 78 / 13 ) = 780 / 5 = 60 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"14 / 13",
"13 / 17",
"16 / 17",
"13 / 18"
]
} | [
"C"
] | reduce 4128 / 4386 to its lowest terms | explanation : hcf of 4128 and 4386 4128 ) 4386 ( 1 4128 - - - - - 258 ) 4128 ( 16 4128 - - - - 0 hence hcf of 4128 and 4386 is 258 . 4128 / 258 = 16 4386 / 258 = 17 4128 / 4386 = 16 / 17 answer : option c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"15",
"6",
"13",
"9"
]
} | [
"A"
] | a contractor undertook to do a piece of work in 9 days . he employed certain number of laboures but 6 of them were absent from the very first day and the rest could finish the work in only 15 days . find the number of men originally employed . | let the number of men originally employed be x . 9 x = 15 ( x β 6 ) or x = 15 answer a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 1950",
"rs 2000",
"rs 745",
"rs 765"
]
} | [
"A"
] | if an amount of rs 42900 is distributed equally amongst 22 persons , how much amount would each person get ? | required amount = 42900 / 22 = rs 1950 answer a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"9,6",
"6,3",
"9,3",
"10,2"
]
} | [
"D"
] | a man can row downstream at the rate of 12 km / hr and upstream at 8 km / hr . find man ' s rate in still water and the rate of current ? | "explanation : rate of still water = 1 / 2 ( 12 + 8 ) = 10 km / hr rate of current = 1 / 2 ( 12 - 8 ) = 2 km / hr answer : option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"10",
"30",
"40",
"25"
]
} | [
"D"
] | the sum of the squares of three numbers is 225 , while the sum of their products taken two at a time is 200 . their sum is : | "x ^ + y ^ 2 + z ^ 2 = 225 xy + yz + zx = 200 as we know . . ( x + y + z ) ^ 2 = x ^ 2 + y ^ 2 + z ^ 2 + 2 ( xy + yz + zx ) so ( x + y + z ) ^ 2 = 225 + ( 2 * 200 ) ( x + y + z ) ^ 2 = 625 so x + y + z = 25 answer : d" | MathQA |
{
"label": [
"A",
"B",
"D",
"E"
],
"text": [
"17 %",
"25.6 %",
"33.3 %",
"50 %"
]
} | [
"D"
] | the price of food in the area where the sims family lives is scheduled to increase by 50 % next year . since the sims family can not afford an increase in their food bill , how much will they have to reduce consumption to keep their cost the same ? | solution : let the current food expense be represented by rs . 100 . the cost of food rises 50 % . so , to buy same amount of food , they need to increase their expense , = ( 100 + 50 % of 100 ) = rs . 150 . but , they want to keep food expense the same , so they have to cut rs . by 50 to keep it to rs . = 100 . the % ... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20 %",
"25 %",
"18 %",
"50 %"
]
} | [
"D"
] | if the given two numbers are respectively 8 % and 16 % of a third number , then what percentage is the first of the second ? | "here , l = 8 and m = 16 therefore , first number = l / m x 100 % of second number = 8 / 16 x 100 % of second number = 50 % of second number answer : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 13",
"2 / 13",
"1 / 26",
"1 / 52"
]
} | [
"C"
] | a card is drawn from a pack of 52 cards . the probability of ge Ζ« ng a queen of club or a king of heart is | "explanation : total number of cases = 52 favourable cases = 2 probability = 2 / 56 = 1 / 26 answer : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"690",
"674",
"672",
"960"
]
} | [
"C"
] | in an office in singapore there are 60 % female employees . 50 % of all the male employees are computer literate . if there are total 62 % employees computer literate out of total 1600 employees , then the no . of female employees who are computer literate ? | "solution : total employees , = 1600 female employees , 60 % of 1600 . = ( 60 * 1600 ) / 100 = 960 . then male employees , = 640 50 % of male are computer literate , = 320 male computer literate . 62 % of total employees are computer literate , = ( 62 * 1600 ) / 100 = 992 computer literate . thus , female computer lite... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"120', '",
"80', '",
"60', '",
"40', '"
]
} | [
"C"
] | the breadth of a rectangular hall is two - thirds of its length . if the area of the hall is 2400 sq metres , what is the length in metres ? | let the length of the rectangular hall be β x β m , then the breadth of the rectangular hall = 2 x β 3 m . area of hall = 2 x β 3 Γ x = 2 x 2 β 3 or , 2 x 2 β 3 = 2400 or x = 60 m answer c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"76",
"5776",
"304",
"5184"
]
} | [
"D"
] | find β ? / 18 = 4 ? | "answer let β n / 18 = 4 then β n = 18 x 4 = 72 β΄ n = 72 x 72 = 5184 . correct option : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"9 %",
"9.27 %",
"27 %",
"15.76 %"
]
} | [
"D"
] | the population of a city increases by 6 % per year but due to migration it decrease by 1 % per years . what will be the percentage increase in population in 3 years ? | actual increase in population = 5 % let , earlier population = 100 then the population after 3 years = 100 ( 1 + 5 / 100 ) ^ 3 = 115.7625 β΄ required percentage = 15.7625 % answer : d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 692.80",
"rs . 820",
"rs . 990",
"rs . 1385"
]
} | [
"C"
] | average monthly income of a family of 4 earning members was rs . 735 . one of the earning members died and therefore , the average income came down to rs 650 . the income of the deceased was ? | "answer income of the deceased = total income of 4 members - total income of remaining 3 members . = 735 x 4 - 650 x 3 rs . = 990 rs . correct option : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"210 kms",
"30 kms",
"20 kms",
"40 kms"
]
} | [
"A"
] | a car travels a certain distance taking 7 hrs in forward journey , during the return journey increased speed 12 km / hr takes the times 5 hrs . what is the distance traveled | if x is the distance , then difference in speeds = x / 5 - x / 7 = 12 2 x / 35 = 12 x = 12 * 35 / 2 = 210 kms . answer : a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2 / 3",
"0.17",
"3 / 2",
"0.71"
]
} | [
"B"
] | which is greatest in 16 ( 2 / 3 ) % , 2 / 5 and 0.17 ? | 16 ( 2 / 3 ) % = [ ( 50 / 3 ) * ) 1 / 100 ) ] = 1 / 6 = 0.166 , 2 / 15 = 0.133 . clearly , 0.17 is the greatest . answer is b . | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1.3 kg",
"1.5 kg",
"1.7 kg",
"1.9 kg"
]
} | [
"A"
] | when processing flower - nectar into honey bees ' extract , a considerable amount of water gets reduced . how much flower - nectar must be processed to yield 1 kg of honey , if nectar contains 50 % water , and the honey obtained from this nectar contains 35 % water ? | explanation : flower - nectar contains 50 % of non - water part . in honey this non - water part constitutes 65 % ( 100 - 35 ) . therefore 0.5 x amount of flower - nectar = 0.65 x amount of honey = 0.65 x 1 kg therefore amount of flower - nectar needed = ( 0.65 / 0.51 ) kg = 1.3 kgs answer : a | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 200",
"rs . 350",
"rs . 275",
"rs . 425"
]
} | [
"D"
] | the mean daily profit made by a shopkeeper in a month of 30 days was rs . 350 . if the mean profit for the first fifteen days was rs . 275 , then the mean profit for the last 15 days would be | "average would be : 350 = ( 275 + x ) / 2 on solving , x = 425 . answer : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"30 %",
"55 %",
"90 %",
"100 %"
]
} | [
"B"
] | in a restaurant , the profit is 150 % of the cost . if the cost increases by 12 % but the selling price remains constant , approximately what percentage of the selling price is the profit ? | "explanation : let c . p . = rs . 100 . then , profit = rs . 150 , s . p . = rs . 250 . new c . p . = 112 % of rs . 100 = rs . 112 new s . p . = rs . 250 . profit = rs . ( 250 - 112 ) = rs . 138 . required percentage = ( 138 / 250 * 100 ) % = 55 % appox answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 460",
"rs 484",
"rs 550",
"rs 664"
]
} | [
"B"
] | abhinav and bhupathi together have rs . 1210 . if 4 / 15 of abhinav ' s amount is equal to 2 / 5 of bhupathi ' s amount , how much amount does bhupathi have ? | explanation : let a = abhinav , b = bhupathi . 4 / 15 a = 2 / 5 b = > a = ( 2 / 515 / 4 ) b = > a = 3 / 2 b = > a / b = 3 / 2 = > a : b = 3 : 2 b ' s share = rs . ( 12102 / 5 ) = rs . 484 . answer : b | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2 : 3",
"4 : 3",
"6 : 7",
"9 : 16"
]
} | [
"B"
] | two trains , one from howrah to patna and the other from patna to howrah , start simultaneously . after they meet , the trains reach their destinations after 9 hours and 16 hours respectively the ratio of their speeds is | "solution let us name the trains as a and b . = ( a ' s speed ) : ( b ' s speed ) = β b : β a = β 16 : β 9 = 4 : 3 answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"9800000",
"1000000",
"7500000",
"2000000"
]
} | [
"D"
] | a wooden box of dimensions 8 m x 7 m x 6 m is to carry rectangularboxes of dimensions 4 cm x 7 cm x 6 cm . the maximum number ofboxes that can be carried in the wooden box , is | explanation : number = ( 800 * 700 * 600 ) / 8 * 7 * 6 = 2000000 answer : d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 55.50",
"rs . 67.50",
"rs . 86.50",
"rs . 91.00"
]
} | [
"D"
] | the sides of a rectangular field are in the ratio 3 : 4 . if the area of the field is 8112 sq . m , the cost of fencing the field @ 25 paise per metre is | "solution let length = ( 3 x ) metres and breadth = ( 4 x ) metres . then , 3 x Γ 4 x = 7600 β 12 x 2 = 8112 β x 2 = 676 β x = 26 so , length = 78 m and breadth = 104 m . perimeter = [ 2 ( 78 + 104 ) ] m = 364 m . β΄ cost of fencing = rs . ( 0.25 Γ 364 ) = rs . 91 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2 : 5",
"3 : 7",
"10 : 9",
"7 : 3"
]
} | [
"C"
] | if 30 % of a number is equal to one - third of another number , what is the ratio of first number to the second number ? | "explanation : let 30 % of a = 1 / 3 b then , 30 a / 100 = 1 b / 3 = > 3 a / 10 = b / 3 = > a : b = 10 : 9 answer : c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"75",
"100",
"125",
"150"
]
} | [
"B"
] | out of 450 students of a school , 325 play football , 175 play cricket and 50 neither play football nor cricket . how many students play both football and cricket ? | "explanation : students who play cricket , n ( a ) = 325 students who play football , n ( b ) = 175 total students who play either or both games , = n ( a βͺ b ) = 450 β 50 = 400 required number , n ( a β© b ) = n ( a ) + n ( b ) β n ( a βͺ b ) = 325 + 175 β 400 = 100 option b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20 m",
"50 m",
"45 m",
"60 m"
]
} | [
"B"
] | in a 200 m race , a covers the distance in 45 seconds and b in 60 second . in this race a beats b by : | "solution distance covered by b in 15 sec . = ( 200 / 60 x 15 ) m = 50 m . β΄ a beats b by 50 metres . answer b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20 m",
"125 m",
"120 m",
"160 m"
]
} | [
"D"
] | in a 400 m race , a covers the distance in 60 seconds and b in 100 second . in this race a beats b by : | "solution distance covered by b in 40 sec . = ( 400 / 100 x 40 ) m = 160 m . β΄ a beats b by 160 metres . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"10.22 %",
"20.22 %",
"21.22 %",
"30 %"
]
} | [
"D"
] | a shop owner professes to sell his articles at certain cost price but he uses false weights with which he cheats by 30 % while buying and by 10 % while selling . what is his percentage profit ? | "the owner buys 100 kg but actually gets 130 kg ; the owner sells 100 kg but actually gives 90 kg ; profit : ( 130 - 90 ) / 90 * 100 = 30 % answer : d ." | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1.01",
"1.1",
"0.11",
"11"
]
} | [
"D"
] | if 2805 / 2.55 = 1100 , then 280.5 / 25.5 is equal to ? | "answer given expression 280.5 / 25.5 = 2805 / 255 = 2805 / ( 2.55 x 100 ) = 1100 / 100 = 11 correct option : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1240",
"1120",
"1190",
"2150"
]
} | [
"D"
] | the banker ' s gain on a sum due 6 years hence at 12 % per annum is rs . 900 . what is the banker ' s discount ? | "explanation : td = ( bg Γ 100 ) / tr = ( 900 Γ 100 ) / ( 6 Γ 12 ) = rs . 1250 bg = bd β td = > 900 = bd - 1250 = > bd = 2150 answer : option d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.96",
"9.4",
"0.094",
"94"
]
} | [
"A"
] | subtracting 4 % of a from a is equivalent to multiplying a by how much ? | "answer let a - 4 % of a = ab . β ( 96 x a ) / 100 = ab β΄ b = 0.96 correct option : a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"48 m', '",
"52 m', '",
"54 m', '",
"60 m', '"
]
} | [
"D"
] | the width of a rectangle is 10 meter and its area is 150 square meter . if length of the rectangle is increased then its new area is 4 / 3 times of the original area . what is the new perimeter of the rectangle ? | let length of new rectangle be x m then x Γ 10 = 150 Γ 4 / 3 = 200 or , x = 20 m hence new perimeter = 2 ( 10 + 20 ) = 60 m answer : d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4",
"0.4",
"0.04",
"40"
]
} | [
"C"
] | 0.0004 ? = 0.01 | "explanation : required answer = 0.0004 / 0.01 = 0.04 / 1 = 0.04 . answer : option c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"430",
"516",
"660",
"860"
]
} | [
"D"
] | 860 % of 50 + 50 % of 860 = ? | "solution given expression = [ 860 / 100 x 50 + 50 / 100 x 860 ] = 430 + 430 = 860 . answer d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 1600",
"rs 1800",
"rs 2000",
"rs 2200"
]
} | [
"C"
] | the ratio of income of anand to that of balu is 5 : 4 and the expenditure of anand to that of balu is 3 : 2 . if at the end of the year , each saves rs , 800 , the income of anand is : | explanation : let the income of anand and balu be 5 x and 4 x and . the expenditures of anand and balu be 3 y and 2 y . then , 5 x 3 y = 800 and 4 x 2 y = 800 . on solving we get : x = 400 . as income = 5 x = rs . 2000 . answer : c | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 473",
"rs . 374",
"rs . 495",
"rs . 945"
]
} | [
"D"
] | compound interest of rs . 6000 at 10 % per annum for 1 1 / 2 years will be ( interest compounded half yearly ) . | "10 % interest per annum will be 5 % interest half yearly for 3 terms ( 1 1 / 2 years ) so compound interest = 6000 [ 1 + ( 5 / 100 ) ] ^ 3 - 6000 = 6000 [ ( 21 / 20 ) ^ 3 - 1 ] = 6000 ( 9261 - 8000 ) / 8000 = 6 * 1261 / 8 = 945 answer : d" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"112.50",
"125",
"150",
"167.5"
]
} | [
"A"
] | a person borrows 5000 for 2 years at 4 % p . a . simple interest . he immediately lends it to another person at 61 β 4 % p . a . for 2 years . find his gain in the transaction per year . | "gain in 2 years = [ ( 5000 Γ 25 / 4 Γ 2 / 100 ) β ( 5000 Γ 4 Γ 2 / 100 ) ] = ( 625 β 400 ) = 225 . β΄ gain in 1 year = ( 225 β 2 ) = 112.50 answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4",
"7",
"8",
"12"
]
} | [
"D"
] | two sets of 3 consecutive positive odd integers have exactly one integer in common . the sum of the integers in the set with greater numbers is how much greater than the sum of the integers in the other set ? | a = ( 1 , 3,5 ) , sum of this = 9 b = ( 5 , 7,9 ) , sum of this = 21 , the differenct between 21 - 9 = 12 hence , 12 is the answer i . e . d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"116",
"120",
"130",
"140"
]
} | [
"C"
] | a man has 1044 candles . after burning , he can make a new candle from 9 stubs left behind . find the maximum number of candles that can be made . | explanation : since , 1 candle is made from 9 stubs . therefore , from 1044 stubs , 1044 / 9 i . e 116 candles will be made . now , from 116 stubs , 116 / 9 i . e 12 candles can be made and 8 stubs will be left . thus , total stubs left is ( 12 + 8 ) = 20 out of which 20 / 9 i . e 2 candles can be made and 2 stubs will... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"300",
"400",
"600",
"500"
]
} | [
"C"
] | a merchant has 1000 kg of sugar part of which he sells at 8 % profit and the rest at 18 % profit . he gains 14 % on the whole . the quantity sold at 18 % profit is | explanation : by the rule of alligation , we have profit % by selling 1 st part profit % by selling 2 nd part 8 18 net % profit 14 18 - 14 = 4 14 - 8 = 6 = > quantity of part 1 : quantity of part 2 = 4 : 6 = 2 : 3 total quantity is given as 1000 kg so quantity of part 2 ( quantity sold at 18 % profit ) = 1000 Γ 35 = 60... | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 950",
"rs . 1500",
"rs . 1000",
"rs . 1200"
]
} | [
"C"
] | a trader sells 40 metres of cloth for rs . 8200 at a profit of rs . 25 per metre of cloth . how much profit will the trder earn on 40 metres of cloth ? | "explanation : sp of 1 metre cloth = 8200 / 40 = rs . 205 . cp of 1 metre cloth = rs . 205 β 25 = rs . 180 cp on 40 metres = 180 x 40 = rs . 7200 profit earned on 40 metres cloth = rs . 8200 β rs . 7200 = rs . 1000 . answer : option c" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1394",
"1294",
"1194",
"1094"
]
} | [
"A"
] | find the least number which when divided by 20 , 2535 and 40 leaves remainders 14 , 1929 and 34 respectively . | here , ( 20 - 14 ) = 6 , ( 25 β 19 ) = 6 , ( 35 - 29 ) = 6 and ( 40 - 34 ) = 6 . therefore , required number = ( l . c . m . of 2025 , 3540 ) β 6 = 1394 . answer is a . | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"150",
"200",
"250",
"350"
]
} | [
"A"
] | in a school with 600 students , the average age of the boys is 12 years and that of the girls is 11 years . if the average age of the school is 11 years 9 months , then the number of girls in the school is | "sol . let the number of grils be x . then , number of boys = ( 600 - x ) . then , ( 11 3 / 4 Γ 600 ) β 11 x + 12 ( 600 - x ) β x = 7200 - 7050 β 150 . answer a" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"167",
"243",
"252",
"336"
]
} | [
"B"
] | the least number which when divided by 3 , 4 , 5 and 8 leaves a remainder 3 , but when divided by 9 leaves no remainder , is | "explanation : l . c . m of 3 , 4 , 5 , 8 = 120 therefore required number is of the form 120 k + 3 . least value of k for which ( 120 k + 3 ) is divisible by 9 is k = 2 therefore required number = ( 120 x 2 + 3 ) = 243 answer : b" | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"30 / 25",
"28 / 13",
"28 / 29",
"8 / 13"
]
} | [
"D"
] | reduce 368 / 598 to the lowest terms | explanation : we can do it easily by in two steps step 1 : we get the hcf of 368 and 598 which is 46 step 2 : divide both by 46 , we will get the answer 8 / 13 answer : option d | MathQA |
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 500",
"rs . 600",
"rs . 650",
"rs . 720"
]
} | [
"B"
] | a man invested rs . 14,400 in rs . 100 shares of a company at 20 % premium . if the company declares 5 % dividend at the end of the year , then how much does he get ? | "solution number of shares = ( 14400 / 120 ) = 120 . face value = rs . ( 100 x 120 ) = rs . 12000 . annual income = rs . ( 5 / 100 x 12000 ) = rs . 600 . answer b" | MathQA |
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