choices
dict | answerKey
listlengths 1
1
| question
stringlengths 8
751
| rationale
stringlengths 8
1.53k
| dataset
stringclasses 1
value |
|---|---|---|---|---|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 14000",
"rs 15000",
"rs 12000",
"rs 17000"
]
}
|
[
"C"
] |
a man took a loan at rate of 12 % per annum simple interest . after 3 years he had to pay 4320 interest . the principal amount borrowed by him was .
|
"explanation : s . i . = p â ˆ — r â ˆ — t / 100 = > p = s . i . â ˆ — 100 / r â ˆ — t = > p = 4320 â ˆ — 100 / 12 â ˆ — 3 = rs 12000 option c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 : 25",
"1 : 22",
"1 : 52",
"1 : 64"
]
}
|
[
"D"
] |
a cube of edge 8 cm is cut into cubes each of edge 1 cm . the ratio of the total surface area of one of the small cubes to that of the large cube is equal to :
|
"sol . required ratio = 6 * 1 * 1 / 6 * 8 * 8 = 1 / 64 = 1 : 64 . answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"315",
"345",
"425",
"335"
]
}
|
[
"C"
] |
what annual installment will discharge a debt of rs . 1428 due in 3 years at 12 % simple interest ?
|
"let each installment be rs . x then , ( x + ( ( x * 12 * 1 ) / 100 ) ) + ( x + ( ( x * 12 * 2 ) / 100 ) ) + x = 1428 = ( ( 28 x / 25 ) + ( 31 x / 25 ) + x ) = 1428 ï ƒ › ( 28 x + 31 x + 25 x ) = ( 1428 * 25 ) x = ( 1428 * 25 ) / 84 = rs . 425 . therefore , each installment = rs . 425 . answer is c ."
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 45,000",
"rs . 50,000",
"rs . 60,000",
"rs . 80,000"
]
}
|
[
"D"
] |
x and y invested in a business . they earned some profit which they divided in the ratio of 2 : 4 . if x invested rs . 40,000 . the amount invested by y is
|
"solution suppose y invested rs . y then , 40000 / y = 2 / 4 â € ¹ = â € º y = ( 40000 ã — 4 / 2 ) . â € ¹ = â € º y = 80000 . answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1865113",
"1775123",
"1764813",
"1675123"
]
}
|
[
"C"
] |
( 4300431 ) - ? = 2535618
|
"let 4300431 - x = 2535618 then x = 4300431 - 2535618 = 1764813 answer is c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"7",
"8",
"9",
"10"
]
}
|
[
"D"
] |
how many integers from 1 to 100 ( both inclusive ) have odd number of factors ?
|
all perfect squares have odd # of factors . squaring integers 1 - 10 produces 1 , 4 , 9 , 16 , . . . 100 which all have odd # of factors . answer is d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3 : 4",
"3 : 5",
"7 : 8",
"4 : 3"
]
}
|
[
"C"
] |
the ratio between the present age of p and q is 6 : 7 . if q is 4 years old then p , what will be the ratio of the ages of p and q after 4 year ?
|
"solution let p ' s age and q ' s age be 6 x years and 7 x years respectively . then , 7 x - 6 x = 4 ⇔ x = 4 . ∴ required ratio = ( 6 x + 4 ) : ( 7 x + 4 ) = 28 : 32 = 7 : 8 . answer c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"13.6 %",
"28.6 %",
"35.6 %",
"42.3 %"
]
}
|
[
"B"
] |
the cost price of an article is 70 % of the marked price . calculate the gain percent after allowing a discount of 10 % .
|
"sol . let marked price = rs . 100 . then , c . p . = rs . 70 . s . p = rs . 90 . â ˆ ´ gain % = [ 20 / 70 * 100 ] % = 28.6 % . answer b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"E"
],
"text": [
"215 / 216",
"216",
"1 / 216",
"2"
]
}
|
[
"A"
] |
lola rolls a die 3 times . what is the probability that she gets a 4 on the last one of the 3 rolls ?
|
the die has 6 sides and it was rolle 3 times , then 6 * 6 * 6 = 216 the number of ways to get 4 is 1 then 1 / 216 the probability would be 1 - 1 / 216 = 215 / 216 answer a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"33.33 %",
"25 %",
"81.81 %",
"66.66 %"
]
}
|
[
"C"
] |
if x is less than y by 45 % then y exceed x by :
|
"using formula ( x / ( 100 - x ) * 100 ) where x is percentage decrease ( here it is 25 % ) = > 45 / ( 100 - 45 ) * 100 = 81.81 % answer : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"18 / 50",
"16 / 50",
"7 / 20",
"19 / 50"
]
}
|
[
"C"
] |
convert 0.35 in to a vulgar fraction ?
|
"answer 0.35 = 35 / 100 = 7 / 20 correct option : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"80 kmph",
"60 kmph",
"72 kmph",
"90 kmph"
]
}
|
[
"C"
] |
a train travels 125 km in 2.5 hours and 270 km in 3 hours . find the average speed of train .
|
"as we know that speed = distance / time for average speed = total distance / total time taken thus , total distance = 125 + 270 = 395 km thus , total speed = 5.5 hrs or , average speed = 5 = 395 / 5.5 or , 72 kmph . answer : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"220",
"1314",
"1326",
"7920"
]
}
|
[
"A"
] |
the product of two numbers is 1320 and their h . c . f is 6 . the l . c . m of the numbers is
|
"solution l . c . m = product of numbers / h . c . f ‹ = › 1320 / 6 ‹ = › 220 . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4096",
"4098",
"5000",
"5096"
]
}
|
[
"A"
] |
a lady grows cabbage in her garden that is in the shape of a square . each cabbage takes 1 square foot of area in her garden . this year , she has increased her output by 127 cabbages when compared to last year . the shape of the area used for growing the cabbage has remained a square in both these years . how many cabbages did she produce this year ?
|
"explanatory answer the shape of the area used for growing cabbage has remained a square in both the years . let the side of the square area used for growing cabbage this year be x ft . therefore , the area of the ground used for cultivation this year = x 2 sq . ft . let the side of the square area used for growing cabbage last year be y ft . therefore , the area of the ground used for cultivation last year = y 2 sq . ft . as the number of cabbage grown has increased by 127 , the area would have increased by 127 sq ft because each cabbage takes 1 sq ft space . hence , x 2 - y 2 = 127 ( x + y ) ( x - y ) = 127 . 127 is a prime number and hence it will have only two factors . i . e . , 127 and 1 . therefore , 127 can be expressed as product of 2 numbers in only way = 127 * 1 i . e . , ( x + y ) ( x - y ) = 127 * 1 so , ( x + y ) should be 127 and ( x - y ) should be 1 . solving the two equations we get x = 64 and y = 63 . therefore , number of cabbage produced this year = x 2 = 642 = 4096 . alternative approach : use answer choices the area in both the years are squares of two numbers . that rules out choice b , c and d . as 4098,5000 and 5096 are not the square of any number . check choice a : if this year ' s produce is 4096 , last year ' s produce would have been 4096 - 127 = 3969 3969 is the square of 63 . so , 4096 is the answer . choice a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3 : 1",
"5 : 1",
"3 : 5",
"3 : 7"
]
}
|
[
"B"
] |
if the volume of two cubes are in the ratio 125 : 1 , the ratio of their edges is :
|
"explanation : let the edges be a and b of two cubes , then a 3 / b 3 = 125 / 1 = > ( a / b ) 3 = ( 5 / 1 ) 3 a / b = 5 / 1 = > a : b = 5 : 1 option b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"22 kg",
"21.6 kg",
"22.4 kg",
"10 kg"
]
}
|
[
"D"
] |
the average weight of 29 students is 28 kg . by the admission of a new student , the average weight is reduced to 27.4 kg . the weight of the new student is
|
"exp . the total weight of 29 students = 29 * 28 the total weight of 30 students = 30 * 27.4 weight of the new student = ( 30 * 27.4 – 29 * 28 ) = 822 - 812 = 10 answer : d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"29 / 34",
"47 / 100",
"3 / 20",
"13 / 102"
]
}
|
[
"D"
] |
two cards are drawn together from a pack of 52 cards . the probability that one is a club and other is a diamond , is :
|
explanation : one card drawn . probability of being it club or diamond = ( 13 x 2 ) / 52 . another card drawn . now , probability of being it of other suit ( the suit among the two , not selected in first draw ) = 13 / 51 . hence , probability of event = ( ( 13 x 2 ) / 52 ) x ( 13 / 51 ) = 13 / 102 . answer : d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2 : 1",
"4 : 7",
"8 : 77",
"4 : 81"
]
}
|
[
"D"
] |
the ratio of radius of a circle and the side of a square is 2 : 9 . find the ratio of their areas :
|
"radius / side = 2 / 9 â ‡ ’ area of circle / area of square = 4 / 81 answer : d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2",
"4",
"70",
"76"
]
}
|
[
"D"
] |
the average runs of a cricket player of 10 innings was 32 . how many runs must he makes ih his next innings so as to increase his average of runs by 4 ?
|
"sol . average after 11 innings = 36 . therefore required numbert of runs = ( 36 × 11 ) – ( 32 × 10 ) = 396 - 320 = 76 . answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20 %",
"25 %",
"18 %",
"30 %"
]
}
|
[
"A"
] |
if the given two numbers are respectively 6 % and 30 % of a third number , then what percentage is the first of the second ?
|
here , l = 6 and m = 30 therefore , first number = l / m x 100 % of second number = 6 / 30 x 100 % of second number = 20 % of second number answer : a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"225",
"325",
"125",
"145"
]
}
|
[
"B"
] |
0 , 1 , 4 , 15 , 64 , ____
|
"0 , 1,4 , 15,64 . . . . . 0 * 1 + 1 = 1 1 * 2 + 2 = 4 4 * 3 + 3 = 15 15 * 4 + 4 = 64 64 * 5 + 5 = 325 answer : b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"761200",
"761400",
"761800",
"17500"
]
}
|
[
"D"
] |
simplify : 200 x 200 - 150 x 150
|
"( 200 ) ^ 2 - ( 150 ) ^ 2 = ( 200 + 150 ) ( 200 - 150 ) = 350 x 50 = 17500 . answer is d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 2592",
"rs . 2520",
"rs . 2880",
"rs . 3360"
]
}
|
[
"A"
] |
a , b and c started a business with a total investment of rs . 90000 . a invests rs . 6000 more than b and b invests rs . 3000 less than c . if the total profit at the end of a year is rs . 8640 , find b ' s share .
|
"explanation : let c ' s investment = rs . x b ' s investment = rs . ( x - 3000 ) a ' s investment = rs . ( x - 3000 + 6000 ) = rs . ( x + 3000 ) now , ( a + b + c ) ' s investment = rs . 90000 = > x + ( x - 3000 ) + ( x + 3000 ) = 90000 = > 3 x = 90000 = > x = 30000 hence , a ' s investment = rs . 33000 b ' s investment = rs . 27000 c ' s investment = rs . 30000 ratio of the capitals of a , b and c = 33000 : 27000 : 30000 = 11 : 9 : 10 a ' s share = rs . [ ( 9 / 30 ) ã — 8640 ] = rs . 2592 answer : option a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"93700",
"97300",
"93800",
"98300"
]
}
|
[
"D"
] |
evaluate : 983 x 207 - 983 x 107
|
"983 x 207 - 983 x 107 = 983 x ( 207 - 107 ) = 983 x 100 = 98300 . answer is d ."
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4",
"5",
"6",
"12"
]
}
|
[
"D"
] |
suresh can complete a job in 15 hours . ashutosh alone can complete the same job in 30 hours . suresh works for 9 hours and then the remaining job is completed by ashutosh . how many hours will it take ashutosh to complete the remaining job alone ?
|
"the part of job that suresh completes in 9 hours = 9 â „ 15 = 3 â „ 5 remaining job = 1 - 3 â „ 5 = 2 â „ 5 remaining job can be done by ashutosh in 2 â „ 5 ã — 30 = 12 hours answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"110', '",
"111', '",
"113', '",
"112', '"
]
}
|
[
"D"
] |
2.2 cubic dm of lead is to be drawn into a cylindrical wire 0.50 cm diameter . find the length of the wire in meters .
|
let the length of the wire be h meters . then , ∏ ( 0.50 / ( 2 x 100 ) ) ^ 2 x h = 2.2 / 1000 = h = ( ( 2.2 / 1000 ) x ( 100 x 100 ) / ( 0.25 x 0.25 ) x ( 7 / 22 ) ) = 112 m . answer is d .
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"500 km",
"630 km",
"900 km",
"660 km"
]
}
|
[
"C"
] |
two trains start from p and q respectively and travel towards each other at a speed of 50 km / hr and 40 km / hr respectively . by the time they meet , the first train has travelled 100 km more than the second . the distance between p and q is :
|
"sol . at the time of meeting , let the distane travelled byb the second train be x km . then , distance covered by the first train is ( x + 100 ) km ∴ x / 40 = ( x + 100 ) / 50 ⇔ 50 x = 40 x 4000 ⇔ x = 400 . so , distance between p and q = ( x + x + 100 ) km = 900 km . answer c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"+ 20 %",
"- 25 %",
"+ 305",
"- 30 %"
]
}
|
[
"A"
] |
in the science city , kolkata the rate of the ticket is increased by 50 % to increased the revenue but simultaneously 20 % of the visitor decreased . what is percentage change in the revenue . if it is known that the science city collects one revenue only from the visitors and it has no other financial supports :
|
solution : let the initial revenue be 100 . 100 - - - - - 50 % ↑ ( ticket up ) - - - - - > 150 - - - - - 20 % ↓ ( visitors down ) - - - - - > 120 . there is 20 % increase in the revenue . answer : option a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"90 , 85,60', '",
"85 , 75,60', '",
"90 , 75,70', '",
"90 , 75,60', '"
]
}
|
[
"D"
] |
if the length , breadth and the height of a cuboid are in the ratio 6 : 5 : 4 and if the total surface area is 33300 cm 2 cm 2 , then the length , breadth and height in cms , are respectively .
|
explanation : let length = 6 x , breadth = 5 x and height = 4 x in cm 2 ( 6 x × 5 x + 5 x × 4 x + 6 x × 4 x ) = 33300 148 x 2 = 33300 ⇒ x 2 = 33300 / 148 = 225 ⇒ x = 15 length = 90 cm , breadth = 75 cm and height = 60 cm correct option : d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"899.015",
"752.804",
"714.642",
"629.906"
]
}
|
[
"D"
] |
789.009 - ? + 56.84 = 215.943
|
"explanation : 629.906 answer : option d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3",
"14",
"9",
"21"
]
}
|
[
"C"
] |
√ ( 9 ) ^ 2
|
"explanation √ ( 9 ) ^ 2 = ? or , ? = 9 answer c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"189 km",
"225 km",
"255 km",
"199 km"
]
}
|
[
"B"
] |
a car that moves at an average speed of 60 kmph , reaches its destination on time . when its average speed becomes 50 kmph , then it reaches its destination 45 minutes late . find the length of journey .
|
sol . difference between timings = 45 min = 3 / 4 hr . let the length of journey be x km . then , x / 50 - x / 60 = 1 / 4 â ‡ ” 6 x - 5 x = 225 â ‡ ” x = 225 km . answer b
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"81 : 121",
"9 : 11",
"25 : 144",
"27 : 121"
]
}
|
[
"C"
] |
the ratio of the volumes of two cubes is 125 : 1728 . what is the ratio of their total surface areas ?
|
"ratio of the sides = â ³ â ˆ š 125 : â ³ â ˆ š 1728 = 5 : 12 ratio of surface areas = 5 ^ 2 : 12 ^ 2 = 25 : 144 answer : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 million",
"2 million",
"4 million",
"8 million"
]
}
|
[
"A"
] |
one bacterium splits into 8 bacteria of the next generation . but due to environment , only 50 % of one generation can produced the next generation . if the seventh generation number is 4096 million , what is the number in first generation ?
|
solution : let the number of bacteria in the 1 st generation be x , then number of bacteria in 2 nd , 3 rd , 4 th . . . . . generation would be 8 ( x / 2 ) , 8 ( 4 x / 2 ) , 8 ( 16 x / 2 ) . . . . and so on . as x , 4 x , 16 x , 64 x . . . . . it is in gp with common ratio 4 . hence , 7 th term of gp , x ( 4 ) 6 = 4096 or , x = 1 or 1 million . answer : option a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"220.3",
"224.5",
"190.3",
"150"
]
}
|
[
"B"
] |
evaluate : 28 % of 400 + 45 % of 250
|
explanation : 28 % of 400 + 45 % of 250 = ( 28 / 100 * 400 + 45 / 100 * 250 ) = ( 112 + 112.5 ) = 224.5 answer b
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"857",
"859",
"869",
"4320"
]
}
|
[
"A"
] |
the least number which when increased by 7 each divisible by each one of 24 , 32 , 36 and 54 is :
|
"solution required number = ( l . c . m . of 24 , 32 , 36 , 54 ) - 7 = 864 - 7 = 857 . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 15000",
"rs . 15550",
"rs . 15600",
"rs . 16500"
]
}
|
[
"D"
] |
the length of a room is 5.5 m and width is 3.75 m . find the cost of paving the floor by slabs at the rate of rs . 800 per sq . metre .
|
"solution area of the floor = ( 5.5 × 3.75 ) m 2 = 20.625 m 2 ∴ cost of paving = rs . ( 800 × 20.625 ) = 16500 . answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"35",
"42",
"44",
"46"
]
}
|
[
"A"
] |
if p and q are positive integers each greater than 1 , and 17 ( p + 1 ) = 20 ( q + 1 ) , what is the least possible value of p + q ?
|
"17 ( p + 1 ) = 29 ( q + 1 ) - - > ( p + 1 ) / ( q + 1 ) = 20 / 17 - - > the least positive value of p + 1 is 20 , so the least value of p is 19 and the least positive value of q + 1 is 17 , so the least value of q is 16 - - > the least value of p + q is 19 + 16 = 35 . answer : a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4",
"5",
"45",
"6970"
]
}
|
[
"D"
] |
the difference between the place values of 7 and 3 in the number 527435 is
|
"sol . = ( place value of 7 ) – ( place value of 3 ) = ( 700 - 30 ) = 6970 answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 3",
"1 / 6",
"1 / 2",
"1 / 8"
]
}
|
[
"C"
] |
three unbiased coins are tossed , what is the probability of ge ƫ ng at least 2 tails ?
|
"explanation : total cases are = 2 * 2 * 2 = 8 , which are as follows [ ttt , hhh , tth , tht , htt , thh , hth , hht ] favoured cases are = [ tth , tht , htt , ttt ] = 4 so required probability = 4 / 8 = 1 / 2 answer : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"899600",
"856200",
"875200",
"896200"
]
}
|
[
"A"
] |
the difference between the place values of 9 and 4 in the number 927435 is
|
sol . = ( place value of 9 ) – ( place value of 4 ) = ( 900000 - 400 ) = 899600 answer a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"24",
"26",
"28",
"30"
]
}
|
[
"A"
] |
in a two - digit , if it is known that its unit ' s digit exceeds its 10 ' s digit by 2 and that the product of the given number and the sum of its digits is equal to 144 , then the number is ?
|
let the ten ' s digit be x . then , unit ' s digit = x + 2 . number = 10 x + ( x + 2 ) = 11 x + 2 . sum of digits = x + ( x + 2 ) = 2 x + 2 . ( 11 x + 2 ) ( 2 x + 2 ) = 144 22 x 2 + 26 x - 140 = 0 11 x 2 + 13 x - 70 = 0 ( x - 2 ) ( 11 x + 35 ) = 0 x = 2 . hence , required number = 11 x + 2 = 24 . option a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"950",
"1234",
"1289",
"1345"
]
}
|
[
"A"
] |
jaclyn buys $ 40 000 worth of debentures in a company . she earns 9.5 % p . a . simple interest , paid to her quarterly ( that is , every 3 months ) . if the agreed period of the debenture was 18 months : calculate the amount of interest jaclyn will earn for each quarter
|
"explanation : i = ( p x r x t ) / 100 = 40000 * 9.5 / 100 * ( 18 / 12 ) ^ 1 / 6 = 950 answer : a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20,304",
"19,780",
"19,680",
"19,380"
]
}
|
[
"A"
] |
sonika bought a v . c . r . at the list price of 18,800 . if the rate of sales tax was 8 % , find the amount she had to pay for purchasing the v . c . r .
|
"sol . list price of v . c . r . = 18,800 rate of sales tax = 8 % ∴ sales tax = 8 % of 18,800 = 8 ⁄ 100 × 18800 = 1504 so , total amount which sonika had to pay for purchasing the v . c . r . = 18,800 + 1504 = 20,304 . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"10",
"100",
"1000",
"10000"
]
}
|
[
"C"
] |
how many cubes of 10 cm edge can be put in a cubical box of 1 m edge
|
"explanation : number of cubes = ( 100 x 100 x 100 ) / ( 10 x 10 x 10 ) = 1000 answer : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"600",
"700",
"120",
"900"
]
}
|
[
"C"
] |
i chose a number and divide it by 6 . then i subtracted 15 from the result and got 5 . what was the number i chose ?
|
"solution : let xx be the number i chose , then x / 6 â ˆ ’ 15 = 5 x / 6 = 20 x = 120 answer c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 292.50",
"rs . 297.50",
"rs . 298",
"rs . 298.50"
]
}
|
[
"A"
] |
out of 9 persons , 8 persons spent rs . 30 each for their meals . the ninth one spent rs . 20 more than the average expenditure of all the 9 . the total money spent by all of them was
|
explanation : let the average expenditure be rs . x then , 9 x = [ 8 × 30 + ( x + 20 ) ] ⇔ 9 x = x + 260 ⇔ x = 32.50 total money spent = 9 x = rs . ( 9 x 32.5 o ) = rs 292 . 50 answer : a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1638",
"1863",
"1683",
"1836"
]
}
|
[
"C"
] |
find the least number which when divided by 5 , 6,7 , and 8 leaves a remainder 3 , but when divided by 9 leaves no remainder .
|
"l . c . m . of 5,6 , 7,8 = 840 . required number is of the form 840 k + 3 least value of k for which ( 840 k + 3 ) is divisible by 9 is k = 2 . required number = ( 840 x 2 + 3 ) = 1683 answer is c ."
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0.3408",
"3.408",
"34.08",
"340.8"
]
}
|
[
"B"
] |
if 213 × 16 = 3408 , then 1.6 × 2.13 is equal to :
|
"solution 1.6 × 2.13 = ( 16 / 10 x 213 / 100 ) = ( 16 x 213 / 1000 ) = 3408 / 100 = 3.408 . answer b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"12.5 %",
"17.5 %",
"19 %",
"21 %"
]
}
|
[
"C"
] |
weights of two friends ram and shyam are in the ratio of 4 : 5 . ram ’ s weight increases by 10 % and the total weight of ram and shyam together becomes 82.8 kg , with an increase of 15 % . by what per cent did the weight of shyam increase ?
|
let the weights of ram and shyam be 4 x and 5 x . now , according to question , 4 x × 110 / 100 + shyam ? snewwt 4 x × 110100 + shyam ? s new wt = 82.8 . . . . . . . . ( i ) and 4 x + 5 x = 9 x + 115 / 100 = 82.8 . . . . . . . . ( ii ) from ( ii ) , x = 8 putting in ( i ) , we get shyam ’ s new wt = ( 82.8 – 35.2 ) = 47.6 % increase in shyam ’ s wt = ( 47.6 − 40 / 40 × 100 ) = 19 answer c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1951609",
"1981709",
"18362619",
"2031719"
]
}
|
[
"A"
] |
1397 x 1397
|
"1397 x 1397 = ( 1397 ) 2 = ( 1400 - 3 ) 2 = ( 1400 ) 2 + ( 3 ) 2 - ( 2 x 1400 x 3 ) = 1960000 + 9 - 8400 = 1960009 - 8400 = 1951609 . answer : option a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
". 2",
"0.002",
". 05",
". 02"
]
}
|
[
"D"
] |
what decimal fraction is 20 ml of a litre ?
|
"answer required fraction = 20 / 1000 = 2 / 100 = . 02 correct option : d"
|
MathQA
|
{
"label": [
"B",
"C",
"D",
"E"
],
"text": [
"12 p . m .",
"3 pm .",
"2 p . m .",
"1 p . m ."
]
}
|
[
"E"
] |
the distance between 2 cities a and b is 1000 km . a train starts from a at 8 a . m . and travels towards b at 100 km / hr . another starts from b at 9 a . m . and travels towards a at 150 km / hr . at what time do they meet ?
|
"suppose they meet x hrs after 8 a . m . distance moved by first in x hrs + distance moved by second in ( x - 1 ) hrs = 1000 100 x + 150 ( x - 1 ) = 1000 x = 4.60 = 5 hrs they meet at 8 + 5 = 1 p . m . answer is e"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5200",
"3050",
"4400",
"4500"
]
}
|
[
"A"
] |
if 15 % of 30 % of 50 % of a number is 117 , then what is the number ?
|
"let the number be a given , 15 / 100 * 30 / 100 * 50 / 100 * a = 117 = > 3 / 20 * 3 / 10 * 1 / 2 * a = 117 = > a = 10 * 20 * 10 * 2 = 5200 . answer : a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5",
"10",
"15",
"20"
]
}
|
[
"D"
] |
the length of a rectangle is twice its breadth . if its length is decreased by 5 cm and breadth is increased by 5 cm , the area of the rectangle is increased by 75 sq . cm . find the length of the rectangle .
|
"let breadth = x . then , length = 2 x . then , ( 2 x - 5 ) ( x + 5 ) - 2 x * x = 75 < = > 5 x - 25 = 75 < = > x = 20 . therefore , length of the rectangle = 20 cm . answer is d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"144",
"288",
"24",
"256"
]
}
|
[
"C"
] |
in how many ways 4 boys and 1 girls can be seated in a row so that they are alternate .
|
solution : let the arrangement be , b b b b g 4 boys can be seated in 4 ! ways . girl can be seated in 1 ! ways . required number of ways , = 4 ! * 1 ! = 24 . answer : option c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20,088",
"19,780",
"19,680",
"19,380"
]
}
|
[
"A"
] |
sonika bought a v . c . r . at the list price of 18,600 . if the rate of sales tax was 8 % , find the amount she had to pay for purchasing the v . c . r .
|
"sol . list price of v . c . r . = 18,600 rate of sales tax = 8 % ∴ sales tax = 8 % of 18,600 = 8 ⁄ 100 × 18600 = 1488 so , total amount which sonika had to pay for purchasing the v . c . r . = 18,600 + 1488 = 20,088 . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 1435",
"rs . 12,628",
"rs . 1685",
"rs . 18,942"
]
}
|
[
"A"
] |
suganya and suriya are partners in a business . suganya invests rs . 38,000 for 8 months and suriya invests rs . 40,000 for 10 months . out of a profit of rs . 31,570 . suganya ' s share is
|
"solution ratio of their shares = ( 35000 ã — 8 ) : ( 42000 ã — 10 ) = 2 : 44 . suganya ' s share = rs . ( 31570 ã — 2 / 44 ) = rs . 1435 . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5.02 %",
"50.2 %",
"209 %",
"502 %"
]
}
|
[
"D"
] |
5.02 can be expressed in terms of percentage as
|
"explanation : while calculation in terms of percentage we need to multiply by 100 , so 5.02 * 100 = 502 answer : option d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 45,000",
"rs . 40,000",
"rs . 60,000",
"rs . 80,000"
]
}
|
[
"B"
] |
x and y invested in a business . they earned some profit which they divided in the ratio of 1 : 2 . if x invested rs . 20,000 . the amount invested by y is
|
"solution suppose y invested rs . y then , 20000 / y = 1 / 2 â € ¹ = â € º y = ( 20000 ã — 2 / 1 ) . â € ¹ = â € º y = 40000 . answer b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"4",
"5",
"8",
"12"
]
}
|
[
"C"
] |
suresh can complete a job in 15 hours . ashutosh alone can complete the same job in 20 hours . suresh works for 9 hours and then the remaining job is completed by ashutosh . how many hours will it take ashutosh to complete the remaining job alone ?
|
the part of job that suresh completes in 9 hours = 9 â „ 15 = 3 â „ 5 remaining job = 1 - 3 â „ 5 = 2 â „ 5 remaining job can be done by ashutosh in 2 â „ 5 ã — 20 = 8 hours answer c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"56 m",
"88 m",
"120 m",
"137 m"
]
}
|
[
"A"
] |
44 cubic centimetres of silver is drawn into a wire 1 mm in diameter . the length of the wire in metres will be :
|
"sol . let the length of the wire b h . radius = 1 / 2 mm = 1 / 20 cm . then , 22 / 7 * 1 / 20 * 1 / 20 * h = 44 ⇔ = [ 44 * 20 * 20 * 7 / 22 ] = 5600 cm = 56 m . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"3 : 1",
"3 : 2",
"3 : 5",
"3 : 7"
]
}
|
[
"B"
] |
if the volume of two cubes are in the ratio 27 : 8 , the ratio of their edges is :
|
"explanation : let the edges be a and b of two cubes , then a 3 / b 3 = 27 / 8 = > ( a / b ) 3 = ( 3 / 2 ) 3 a / b = 3 / 2 = > a : b = 3 : 2 option b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"25",
"50",
"250",
"300"
]
}
|
[
"A"
] |
if 5 a = 3125 , then the value of 5 ( a - 3 ) is
|
"sol . 5 a = 3125 = 5 a = 55 a = 5 . 5 ( 1 - 3 ) = 5 ( 5 - 3 ) = 5 ( 2 ) = 25 . answer a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2008",
"2009",
"2010",
"2011"
]
}
|
[
"D"
] |
. the price of commodity p increases by 40 paise every year , while the price of commodity q increases by 15 paise every year . if in 2001 , the price of commodity p was rs . 4.20 and that of q was rs . 6.30 , in which year commodity p will cost 40 paise more than the commodity q ?
|
explanation : let the commodity p costs 40 paise more than the commodity q after n years price of the commodity p in 2001 = rs . 4.20 since the price of the commodity p increases by rs 0.40 every year , price of the commodity p after n years from 2001 = rs . 4.20 + ( n × . 40 ) price of the commodity q in 2001 = rs . 6.30 since the price of the commodity q increases by rs 0.15 every year , price of the commodity q after n years from 2001 = rs . 6.30 + ( n × . 15 ) since the commodity p costs rs . 0.40 more that the commodity q after n years from 2001 , 4.20 + ( n × . 40 ) = 6.30 + ( n × . 15 ) + 0.40 = > ( 40 n - . 15 n ) = 6.30 - 4.20 + 0.40 = 2.5 = > . 25 n = 2.5 ⇒ n = 2.5 / . 25 = 250 / 25 = 101.15 ¯ = > commodity p costs rs . 0.40 more that the commodity q after 10 years from 2001 . i . e . , in 2011 . answer : option d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"661",
"600",
"620",
"616"
]
}
|
[
"D"
] |
in an office , totally there are 2200 employees and 40 % of the total employees are males . 30 % of the males in the office are at - least 50 years old . find the number of males aged below 50 years ?
|
"number of male employees = 2200 * 40 / 100 = 880 required number of male employees who are less than 50 years old = 880 * ( 100 - 30 ) % = 880 * 75 / 100 = 616 . answer : d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
". 8",
". 09",
". 009",
". 0009"
]
}
|
[
"A"
] |
. 008 / ? = . 01
|
"let . 008 / x = . 01 ; then x = . 008 / . 01 = . 8 / 1 = . 8 answer is a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"5500",
"4500",
"2500",
"6970"
]
}
|
[
"A"
] |
the difference between the place values of 6 and 5 in the number 826533 is
|
sol . = ( place value of 6 ) – ( place value of 5 ) = ( 6000 - 500 ) = 5500 answer a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 : 2",
"2 : 3",
"1 : 3",
"4 : 1"
]
}
|
[
"D"
] |
x starts a business with rs . 52000 . y joins in the business after 6 months with rs . 26000 . what will be the ratio in which they should share the profit at the end of the year ?
|
"explanation : ratio in which they should share the profit = ratio of the investments multiplied by the time period = 52000 * 12 : 26000 * 6 = 52 * 12 : 26 * 6 = 24 : 6 = 4 : 1 . answer : option d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1 / 2",
"2 / 3",
"3 / 4",
"4 / 3"
]
}
|
[
"B"
] |
if a * b * c = 130 , b * c * d = 65 , c * d * e = 750 and d * e * f = 250 the ( a * f ) / ( c * d ) = ?
|
"explanation : a â ˆ — b â ˆ — c / b â ˆ — c â ˆ — d = 130 / 65 = > a / d = 2 d â ˆ — e â ˆ — f / c â ˆ — d â ˆ — e = 250 / 750 = > f / c = 1 / 3 a / d * f / c = 2 * 1 / 3 = 2 / 3 answer : b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"7 hours",
"7.1 hours",
"7.2 hours",
"7.3 hours"
]
}
|
[
"C"
] |
a cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 9 hours . if both the taps are opened simultaneously , then after how much time cistern will get filled ?
|
"explanation : when we have question like one is filling the tank and other is empting it , then we subtraction as , filled in 1 hour = 1 / 4 empties in 1 hour = 1 / 9 net filled in 1 hour = 1 / 4 - 1 / 9 = 5 / 36 so cistern will be filled in 36 / 5 hours i . e . 7.2 hours option c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"197600",
"168000",
"278000",
"192700"
]
}
|
[
"D"
] |
evaluate : 986 x 237 - 986 x 37
|
"986 x 237 - 986 x 37 = 986 x ( 237 - 37 ) = 986 x 200 = 197200 . answer is d ."
|
MathQA
|
{
"label": [
"A",
"B",
"D",
"E"
],
"text": [
"4 hours', '",
"11 hours', '",
"3 hours', '",
"14 hours']"
]
}
|
[
"D"
] |
rain is falling at a rate of 10 centimeters per hour all over north carolina . somewhere downtown in north carolina a group of people are waiting for the rain to stop . if the rain filled a round puddle the with a base area of 300 square centimeters and a depth of 30 centimeters , how long did the people wait for the rain to stop ?
|
answer is : d , 3 hours the volume of the puddle is irrelevant and only height matters since rain fell all over the city . thus , it takes only 30 / 10 = 3 hours of rain to fill the puddle
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"9800000",
"2000000",
"7500000",
"1200000"
]
}
|
[
"B"
] |
a wooden box of dimensions 4 m x 2 m x 4 m is to carry rectangularboxes of dimensions 4 cm x 2 cm x 2 cm . the maximum number ofboxes that can be carried in the wooden box , is
|
explanation : number = ( 400 * 200 * 400 ) / 4 * 2 * 2 = 2000000 answer : b
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 840",
"rs 1320",
"rs 1620",
"rs 1680"
]
}
|
[
"C"
] |
if 4 men working 10 hours a day earn rs . 1200 per week , then 9 men working 6 hours a day will earn how much per week ?
|
"explanation : ( men 4 : 9 ) : ( hrs / day 10 : 6 ) : : 1200 : x hence 4 * 10 * x = 9 * 6 * 1200 or x = 9 * 6 * 1200 / 4 * 10 = 1620 answer : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"18 %",
"20 %",
"21 %",
"33 %"
]
}
|
[
"D"
] |
two kinds of vodka are mixed in the ratio 1 : 2 and 2 : 1 and they are sold fetching the profit 40 % and 20 % respectively . if the vodkas are mixed in equal ratio and the individual profit percent on them are increased by 4 / 3 and 5 / 3 times respectively , then the mixture will fetch the profit of
|
answer : d .
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"600",
"650",
"700",
"750"
]
}
|
[
"C"
] |
there are 280 female managers in a certain company . find the total number of female employees in the company , if 2 / 5 of all the employees are managers and 2 / 5 of all male employees are managers .
|
as per question stem 2 / 5 m ( portion of men employees who are managers ) + 280 ( portion of female employees who are managers ) = 2 / 5 t ( portion of total number of employees who are managers ) , thus we get that 2 / 5 m + 280 = 2 / 5 t , or 2 / 5 ( t - m ) = 280 , from here we get that t - m = 700 , that would be total number of female employees and the answer ( c )
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"13000",
"7000",
"10000",
"2800"
]
}
|
[
"D"
] |
a textile manufacturing firm employees 125 looms . it makes fabrics for a branded company . the aggregate sales value of the output of the 125 looms is rs 5 , 00,000 and the monthly manufacturing expenses is rs 1 , 50,000 . assume that each loom contributes equally to the sales and manufacturing expenses are evenly spread over the number of looms . monthly establishment charges are rs 75000 . if one loom breaks down and remains idle for one month , the decrease in profit is :
|
"explanation : profit = 5 , 00,000 â ˆ ’ ( 1 , 50,000 + 75,000 ) = rs . 2 , 75,000 . since , such loom contributes equally to sales and manufacturing expenses . but the monthly charges are fixed at rs 75,000 . if one loan breaks down sales and expenses will decrease . new profit : - = > 500000 ã — ( 124 / 125 ) â ˆ ’ 150000 ã — ( 124 / 125 ) â ˆ ’ 75000 . = > rs 2 , 72,200 . decrease in profit = > 2 , 75,000 â ˆ ’ 2 , 72,200 = > rs . 2,800 . answer : d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20 %",
"45 %",
"33.33 %",
"18 %"
]
}
|
[
"B"
] |
a milk man has 20 liters of milk . if he mixes 25 liters of water , which is freely available , in 20 liters of pure milk . if the cost of pure milk is rs . 18 per liter , then the profit of the milkman , when he sells all the mixture at cost price is :
|
"explanation : when the water is freely available and all the water is sold at the price of the milk , then the water gives the profit on the cost of 20 liters of milk . therefore , profit percentage = 45 % . answer : b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"350 m",
"200 m",
"400 m",
"500 m"
]
}
|
[
"C"
] |
a thief is spotted by a policeman from a distance of 100 meters . when the policeman starts the chase , the thief also starts running . if the speed of the thief be 8 km / hr and that of the policeman 10 km / hr , how far the thief will have run before he is overtaken ?
|
"relative speed of the policeman = ( 10 - 8 ) km / hr = 2 km / hr . time taken by police man to cover ( 100 m / 1000 ) x 1 / 2 hr = 1 / 20 hr . in 1 / 20 hrs , the thief covers a distance of 8 x 1 / 20 km = 2 / 5 km = 400 m answer is c ."
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"10 %",
"15 %",
"20 %",
"40 %"
]
}
|
[
"C"
] |
the rate at which a sum becomes 4 times of itself in 15 years at s . i . , will be :
|
sol . let sum = x . then , s . i . = 3 x ∴ rate = [ 100 * s . i . / p * t ] = [ 100 * 3 x / x * 15 ] % = 20 % . answer c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"20162",
"18322",
"13032",
"18662"
]
}
|
[
"A"
] |
109 × 109 + 91 × 91 = ?
|
"explanation : ( a + b ) 2 + ( a − b ) 2 = 2 ( a 2 + b 2 ) ( reference : basic algebraic formulas ) 1092 + 912 = ( 100 + 9 ) 2 + ( 100 − 9 ) 2 = 2 ( 1002 + 92 ) = 2 ( 10000 + 81 ) = 20162 . answer : option a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"21 : 11",
"11 : 21",
"22 : 23",
"25 : 23"
]
}
|
[
"A"
] |
x starts a business with rs . 56000 . y joins in the business after 4 months with rs . 44000 . what will be the ratio in which they should share the profit at the end of the year ?
|
"explanation : ratio in which they should share the profit = ratio of the investments multiplied by the time period = 56000 * 12 : 44000 * 8 = 56 * 12 : 44 * 8 = 7 * 3 : 11 = 21 : 11 . answer : option a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"586411",
"586413",
"486411",
"486413"
]
}
|
[
"B"
] |
587 * 999 = ?
|
"explanation : trick : 587 * ( 1000 - 1 ) = 587000 - 587 = 586413 option b"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"55",
"56",
"60",
"58"
]
}
|
[
"C"
] |
a rectangular plot measuring 90 metres by 60 metres is to be enclosed by wire fencing . if the poles of the fence are kept 5 metres apart , how many poles will be needed ?
|
"solution perimeter of the plot = 2 ( 90 + 60 ) = 300 m . ∴ number of poles = [ 300 / 5 ] = 60 m answer c"
|
MathQA
|
{
"label": [
"B",
"C",
"D",
"E"
],
"text": [
"1 hour",
"1 hour 15 min",
"1 hour 30 min",
"1 hour 10 min"
]
}
|
[
"C"
] |
a boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes . how long will it take to go 5 km in stationary water ?
|
"speed ( upstream ) = 2 / 1 = 2 kmhr speed ( downstream ) = 1 / ( 10 / 60 ) = 6 kmhr speed in still water = 1 / 2 ( 2 + 6 ) = 4 kmhr time taken in stationary = 5 / 4 = 1 hrs 15 min answer : c"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"81 : 121",
"9 : 11",
"729 : 1331",
"1 : 4"
]
}
|
[
"D"
] |
the ratio of the volumes of two cubes is 125 : 1000 . what is the ratio of their total surface areas ?
|
"ratio of the sides = â ³ â ˆ š 125 : â ³ â ˆ š 1000 = 5 : 10 ratio of surface areas = 5 ^ 2 : 10 ^ 2 = 25 : 100 = 1 : 4 answer : d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"2200",
"2000",
"2100",
"2300"
]
}
|
[
"C"
] |
one boss decided to increase the salary of an employee by 5 % . how much will he get if his salary was rs . 2000 ?
|
solution : actual salary is 2000 rupees 5 % of 2000 = 2000 * 5 / 100 = 100 so 100 rupees increased = 2000 + 100 = 2100 he will get salary of 2100 answer c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"35",
"25",
"20",
"27"
]
}
|
[
"D"
] |
a ratio between two numbers is 7 : 9 and their l . c . m . is 189 . the second number is
|
"sol . let the required numbers be 7 x and 9 x . then , their l . c . m . is 63 x . ∴ 63 x = 189 ⇔ x = 3 . hence , the second number is 27 . answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0",
"2",
"4",
"8"
]
}
|
[
"D"
] |
for how many values of q , is | | | q - 5 | - 10 | - 5 | = 2 ? ( those ls are mods )
|
i think its 8 | | | q - 5 | - 10 | - 5 | = 2 let | q - 5 | = a which makes above | | a - 10 | - 5 | = 2 let | a - 10 | = b which makes | b - 5 | = 2 now for the above b can take 3 , 7 for every b = 3 a can have 13 , 7 and for b = 7 a can have 17 and 3 so ' a ' has four solutions 13 , 7 , 17 and 3 for a = 13 ; q has 18 or - 8 thus has 2 for every combination hence 4 x 2 = 8 answer d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"9800000",
"1000000",
"7500000",
"4000000"
]
}
|
[
"D"
] |
a wooden box of dimensions 8 m x 10 m x 6 m is to carry rectangularboxes of dimensions 4 cm x 5 cm x 6 cm . the maximum number ofboxes that can be carried in the wooden box , is
|
explanation : number = ( 800 * 1000 * 600 ) / 4 * 5 * 6 = 4000000 answer : d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"50.25",
"52.25",
"51.95",
"53.25"
]
}
|
[
"C"
] |
a school has 4 section of chemistry in class x having 65 , 35 , 45 and 42 students . the mean marks obtained in chemistry test are 50 , 60 , 55 and 45 respectively for the 4 sections . determine the overall average of marks per student .
|
required average marks = 65 ã — 50 + 35 ã — 60 + 45 ã — 55 + 42 ã — 45 / 65 + 35 + 45 + 42 = 3250 + 2100 + 2475 + 1890 / 187 = 9715 â „ 187 = 51.95 answer c
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"240 mts",
"270 mts",
"260 mts",
"250 mts"
]
}
|
[
"A"
] |
a 260 m long train running at the speed of 120 km / hr crosses another train running in opposite direction at the speed of 80 km / hr in 9 sec . what is the length of the other train ?
|
explanation : relative speed = 120 + 80 = 200 km / hr . = 200 x 5 / 18 = 500 / 9 m / sec . let the length of the other train be l mts . then , ( l + 260 ) / 9 = 500 / 9 = > l = 240 mts . answer is a
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1628.4",
"1534",
"1492",
"158.25"
]
}
|
[
"D"
] |
25 people went to a hotel for combine dinner party 15 of them spent rs . 5 each on their dinner and rest spent 4 more than the average expenditure of all the 25 . what was the total money spent by them .
|
"solution : let average expenditure of 25 people be x . then , 25 x = 15 * 5 + 10 * ( x + 4 ) ; or , 25 x = 15 * 5 + 10 x + 20 ; or , x = 6.33 ; so , total money spent = 6.33 * 25 = rs . 158.25 . answer : option d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs 7.41",
"rs 9.81",
"rs 10.41",
"rs 11.81"
]
}
|
[
"A"
] |
a fruit seller sells mangoes at the rate of rs . 6 per kg and thereby loses 15 % . at what price per kg , he should have sold them to make a profit of 5 %
|
"explanation : 85 : 6 = 105 : x x = ( 6 × 105 / 85 ) = rs 7.41 option a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 8503.49",
"rs . 9720",
"rs . 10123.20",
"rs . 10483.20"
]
}
|
[
"A"
] |
what will be the compound interest on a sum of rs . 21,000 after 3 years at the rate of 12 % p . a . ?
|
"amount = [ 21000 * ( 1 + 12 / 100 ) 3 ] = 21000 * 28 / 25 * 28 / 25 * 28 / 25 = rs . 29503.49 c . i . = ( 29503.49 - 21000 ) = rs . 8503.49 answer : a"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"0",
"2",
"4",
"8"
]
}
|
[
"D"
] |
for how many values of n , is | | | n - 5 | - 10 | - 5 | = 2 ? ( those ls are mods )
|
i think its 8 | | | n - 5 | - 10 | - 5 | = 2 let | n - 5 | = a which makes above | | a - 10 | - 5 | = 2 let | a - 10 | = b which makes | b - 5 | = 2 now for the above b can take 3 , 7 for every b = 3 a can have 13 , 7 and for b = 7 a can have 17 and 3 so ' a ' has four solutions 13 , 7 , 17 and 3 for a = 13 ; x has 18 or - 8 thus has 2 for every combination hence 4 x 2 = 8 answer d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 45,000",
"rs . 50,000",
"rs . 60,000",
"rs . 90,000"
]
}
|
[
"D"
] |
x and y invested in a business . they earned some profit which they divided in the ratio of 2 : 3 . if x invested rs . 60,000 . the amount invested by y is
|
"solution suppose y invested rs . y then , 60000 / y = 2 / 3 â € ¹ = â € º y = ( 60000 ã — 3 / 2 ) . â € ¹ = â € º y = 90000 . answer d"
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"rs . 660",
"rs . 760",
"rs . 860",
"rs . 1040"
]
}
|
[
"D"
] |
a man buys an item at rs . 1300 and sells it at the loss of 20 percent . then what is the selling price of that item
|
explanation : here always remember , when ever x % loss , it means s . p . = ( 100 - x ) % of c . p when ever x % profit , it means s . p . = ( 100 + x ) % of c . p so here will be ( 100 - x ) % of c . p . = 80 % of 1300 = 80 / 100 * 1300 = 1040 option d
|
MathQA
|
{
"label": [
"A",
"B",
"C",
"D"
],
"text": [
"1.9832",
"1.0025",
"1.5693",
"1.0266"
]
}
|
[
"A"
] |
given that 268 x 74 = 19832 , find the value of 2.68 x . 74 .
|
solution sum of decimals places = ( 2 + 2 ) = 4 . therefore , = 2.68 × . 74 = 1.9832 answer a
|
MathQA
|
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