Search is not available for this dataset
name stringlengths 2 112 | description stringlengths 29 13k | source int64 1 7 | difficulty int64 0 25 | solution stringlengths 7 983k | language stringclasses 4
values |
|---|---|---|---|---|---|
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
using namespace std;
int main(){
string s[3];
while(cin >> s[0], s[0] != "0"){
for(int i = 1 ; i < 3 ; i++){
cin >> s[i];
}
bool end = false;
for(int i = 0 ; i < 3 ; i++){
char ch = s[i][0];
bool ok = true;
for(int j = 1 ; j < 3 ; j++){
if(s[i][j] ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
#include<string>
using namespace std;
int main(){
int i, j;
string c[3];
char win;
while(1){
for(i=0; i<3; ++i){
cin >> c[i];
if(c[0] == "0") break;
}
if(c[0] == "0") break;
win = '0';
for(i=0; i<3; i++){
if(c[i][0] == c[i][1] && c[i][0] == c[i][2] &... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <bits/stdc++.h>
#define rep(i,a,n) for(int i=a;i<n;i++)
#define repb(i,a,b) for(int i=a;i>=b;i--)
#define all(a) a.begin(),a.end()
#define o(a) cout<<a<<endl
#define int long long
#define fi first
#define se second
using namespace std;
typedef vector<int> vi;
typedef vector<vi> vvi;
typedef pair<int,int> pii;
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
using namespace std;
bool judge(char a[3][3], char c)
{
if(a[0][0] == c && a[0][1] == c && a[0][2] == c ||
a[1][0] == c && a[1][1] == c && a[1][2] == c ||
a[2][0] == c && a[2][1] == c && a[2][2] == c ||
a[0][0] == c && a[1][0] == c && a[2][0] == c ||
a[0][1] == c && a[1][1] == c &... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
#include<algorithm>
#include<vector>
#include<queue>
using namespace std;
int main(){
string s[3];
while(cin>>s[0]&&s[0]!="0"){
cin>>s[1]>>s[2];
bool ak=false,bk=false;
for(int i=0;i<3;i++){
bool ak1=true,ak2=true;
bool bk1=true,bk2=true;
for(int j=0;j<3;j++){
if(s... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | // #define _CRT_SECURE_NO_WARNINGS
#define _USE_MATH_DEFINES
#include <iostream>
#include <cstdio>
#include <algorithm>
#include <string>
#include <vector>
#include <map>
#include <set>
#include <stack>
#include <cmath>
#include <cstdlib>
#include <functional>
#include <locale>
#include <cctype>
#include <sstream>
usin... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
using namespace std;
char field[3][3];
void check() {
for (int i = 0; i < 3; ++i) {
if (field[i][0] != '+' && field[i][0] == field[i][1]) {
if (field[i][1] == field[i][2]) {
cout << field[i][2] << endl; return;
}
}
}
for (int i = 0; i < 3; ++i) {
if (field[0][i] != '+' && field[0... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
using namespace std;
char mat[3][3];
char judge(){
for(int i = 0; i < 3; i++){
if(mat[i][0] != '+' && mat[i][0] == mat[i][1] && mat[i][1] == mat[i][2]) return mat[i][2];
if(mat[0][i] != '+' && mat[0][i] == mat[1][i] && mat[1][i] == mat[2][i]) return mat[2][i];
}
if(mat[1... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
using namespace std;
int main(void){
char t[10];
string s,s1,s2,s3;
while(getline(cin,s1)){
if(s1=="0") break;
getline(cin,s2);
getline(cin,s3);
s=s1+s2+s3;
for(int i=0;i<9;++i) t[i]=s[i];
bool o[10],x[10];
int i;
for(i=0;i<9;++i){
o[i]=(t[i]=='b')?true:false;
x[i]=(t[i]=='... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | def f(a):
for x in 'bw':
if a[0::4].count(x)==3 or a[2:7:2].count(x)==3:return x
for i in range(3):
if a[i*3:i*3+3].count(x)==3 or a[i::3].count(x)==3:return x
return 'NA'
while 1:
a=input()
if a =='0':break
print(f(a+input()+input())) | PYTHON3 |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
#include<string>
using namespace std;
int main() {
string a;
while (cin >> a&&a != "0") {
char b[3][3];
for (int i = 0; i < 3; i++)
b[0][i] = a[i];
for (int i = 1; i < 3; i++) {
cin >> a;
for (int j = 0; j < 3; j++)
b[i][j] = a[j];
}
string e;
for (int i = 0; i < 3; i++) {... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <stdio.h>
#pragma warning(disable : 4996)
char c[10]; const char d[3] = "bw";
int main() {
while (~scanf("%c", &c[0])) {
if (c[0] == '0') break;
for (int i = 1; i < 9; i++) {
if (i % 3 == 0) getchar();
scanf("%c", &c[i]);
}
bool ok = false;
for (int i = 0; i < 2; i++) {
bool flag = false;
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
using namespace std;
int checkYoko( char stage[4][4], int i )
{
if( stage[i][0] == stage[i][1] && stage[i][1] == stage[i][2] ) {
if( stage[i][0] == 'b' ) return 1;
else if( stage[i][0] == 'w' ) return 2;
else return 0;
}
return 0;
}
int checkTate( char stage[4][4], int i )
{
if( stage[... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <functional>
#include <algorithm>
#include <iostream>
#include <numeric>
#include <iomanip>
#include <utility>
#include <cstdlib>
#include <sstream>
#include <bitset>
#include <vector>
#include <cstdio>
#include <ctime>
#include <queue>
#include <deque>
#include <cmath>
#include <stack>
#include <list>
#includ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<cstdio>
#include<cstdlib>
#include<cstring>
#include<cmath>
#include<cassert>
#include<iostream>
#include<sstream>
#include<string>
#include<vector>
#include<queue>
#include<set>
#include<map>
#include<utility>
#include<numeric>
#include<algorithm>
#include<bitset>
#include<complex>
using namespace std;
type... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
int main(){
std::string m[3], w;
while(std::cin >> m[0], m[0][0] != '0'){
for(int i=1;i<3;i++)std::cin >> m[i];
w = "NA";
char c;
for(int i=0;i<3;i++){
c = m[i][0];
if(2*c - m[i][1] - m[i][2] == 0 && c - '+')w = c;
c = m[0][i];
if(2*c - m[1][i] - m[2][i] == 0 && c - '+')w = c;
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | b,w = ["b"]*3,["w"]*3
t = range(3)
while 1:
try:
bw = [list(raw_input()) for i in t]
ans = "NA"
for i in range(3):
if b == bw[i] or b == [bw[j][i] for j in t]: ans = "b"
if w == bw[i] or w == [bw[j][i] for j in t]: ans = "w"
if b == [bw[i][i] for i in t] or b == [bw[i][2-i] for i in t]: ans = "b"
if w ... | PYTHON |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <string>
using namespace std;
int main()
{
string s[3];
while (cin >> s[0], s[0] != "0")
{
cin >> s[1] >> s[2];
if (s[0][0] == s[0][1] && s[0][1] == s[0][2] && s[0][0] != '+')
{
cout << s[0][0] << endl;
}
else if (s[1][0] == s[1][1] && s[1][1] == s[1][2] && s[1][0] != '... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | def f(a):
for x in ['b','w']:
if a[0::4].count(x)==3 or a[2:7:2].count(x)==3:return x
for i in range(3):
if a[i*3:i*3+3].count(x)==3 or a[i::3].count(x)==3:return x
return 'NA'
while 1:
a=input()
if a=='0':break
a+=input()+input()
print(f(list(a))) | PYTHON3 |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | //Name: Black-and-White
//Level: 1
//Category: 実装
//Note:
/**
* 縦、横、斜めそれぞれについて、同じ文字が1列に並んでいるか、並んでいればどの文字かを判定する。
*/
#include <iostream>
#include <string>
#include <array>
using namespace std;
array<string,3> field;
char check_inner(int r, int c, int dr, int dc) {
if(field[r][c] == field[r+dr][c+dc] && field[r][... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | import java.util.*;
public class Main {
/**
* @param args
*/
public static void main(String[] args) throws java.io.IOException {
// TODO 自動生成されたメソッド・スタブ
Scanner sc = new Scanner(System.in);
char bor[][] = new char[3][3];
while (true){
if(sc.hasNextInt())break;
for (int i = 0; i < 3; i++) {
bo... | JAVA |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<cstdio>
#include<algorithm>
using namespace std;
int f(int a,int b,int c)
{
if(a==b&&b==c&&a-'+')return a;
return 0;
}
int main()
{
char s[10];
int i,c;
while(c=0,scanf("%s",s),s[0]-'0')
{
scanf("%s%s",&s[3],&s[6]);
for(i=0;i<3;++i)c=max(max(c,f(s[i*3],s[i*3+1],s[i*3+2])),f(s[i],s[i+3],s[i+6]));
c=... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
#include<string>
using namespace std;
char s[3][3];
int judgeB(){
for(int i = 0; i < 3; i++){
if(s[i][0] == 'b' && s[i][1] == 'b' && s[i][2] == 'b') return 1;
}
for(int i = 0; i < 3; i++){
if(s[0][i] == 'b' && s[1][i] == 'b' && s[2][i] == 'b') return 1;
}
if(s[0][0] == 'b' && s[1... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <cstdio>
#include <iostream>
#include <string>
using namespace std;
int a[3][3];
void bw(string str,int n){
for(int i=0;i<3;i++){
if(str[i] == 'b') a[n][i] = 1;
else if(str[i] == 'w') a[n][i] = 2;
else if(str[i] == '+') a[n][i] = 0;
}
}
int main(){
int i,j,tate1,tate2,yoko1,yoko2,na1,na2,na... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <bits/stdc++.h>
#define FOR(i,a,b) for(int i=(a);i<(b);i++)
#define RFOR(i,a,b) for(int i=(b) - 1;i>=(a);i--)
#define REP(i,n) for(int i=0;i<(n);i++)
#define RREP(i,n) for(int i=n-1;i>=0;i--)
#define PB push_back
#define INF INT_MAX/3
#define ALL(a) (a).begin(),(a).end()
#define CLR(a) memset(a,0,sizeof(a))
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
#include<math.h>
#include<vector>
#include<algorithm>
#include<cstdio>
#include <string>
#include <complex>
#include <functional>
using namespace std;
typedef pair<int,int> P;
string r[3];
void solve(){
for(int i=0;i<3;i++){
if(r[i][0]==r[i][1]
&&r[i][1]==r[i][2]
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <string>
using namespace std;
int main()
{
string s,t;
while(cin >> s, s!="0")
{
for(int i=0; i<2; i++)
{
cin >> t;
s+=t;
}
int b=0, w=0;
for(int i=0; i<9; i++)
{
if(s[i] == 'b') b++;
if(s[i] == 'w') w++;
}
bool bw=false, ww=false;
for(int i=0; i<9; i+=3)
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #define _USE_MATH_DEFINES
#define INF 10000000
#include <iostream>
#include <sstream>
#include <cmath>
#include <algorithm>
#include <queue>
#include <stack>
#include <limits>
#include <map>
#include <string>
#include <cstring>
#include <set>
#include <deque>
#include <bitset>
using namespace std;
typedef long long l... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <bits/stdc++.h>
using namespace std;
#define FOR(i,a,b) for(int i=(a);i<(b);i++)
#define REP(i,n) FOR(i,0,n)
#define ALL(v) (v).begin(),(v).end()
#define fi first
#define se second
template<typename A, typename B> inline bool chmax(A &a, B b) { if (a<b) { a=b; return 1; } return 0; }
template<typename A, ty... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <cmath>
#include <climits>
#include <string>
#include <vector>
#include <algorithm>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <list>
#include <bitset>
using namespace std;
typedef vector<int> vi;
typedef... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
#include<string>
using namespace std;
int main() {
string s1, s2, s3;
while (cin >> s1){
if (s1 == "0")return 0;
cin >> s2 >> s3;
if (s1[0] != '+') {
if (s1[0] == s1[1] && s1[0] == s1[2]) { cout << s1[0]; goto heaven; }
else if (s1[0] == s2[1] && s1[0] == s3[2]) { cout << s1[0]; goto he... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
int main(){
std::string m[3], w;
while(std::cin >> m[0], m[0][0] != '0'){
for(int i=1;i<3;i++)std::cin >> m[i];
w = "NA";
for(int i=0;i<3;i++){
char c = m[i][0];
if(2 * c - m[i][1] - m[i][2] == 0 && c - '+')w = c;
c = m[0][i];
if(2 * c - m[1][i] - m[2][i] == 0 && c - '+')w = c;
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <string>
using namespace std;
int main(){
string s1,s2,s3,mas;
bool judge;
while(1){
cin >> s1;
if(s1 == "0") break;
cin >> s2 >> s3;
mas = s1 + s2 + s3;
judge = false;
for(int i=0;i<9;i+=3){
if(mas.substr(i,3) == "bbb... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | import java.util.Scanner;
public class Main {
public static void main(String[] args){
Scanner sc = new Scanner(System.in);
while(true){
int[][] board = new int[3][3];
for(int i = 0; i < 3; i++){
char[] strs = sc.nextLine().toCharArray();
if(strs[0] == '0'){
return;
}
... | JAVA |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
using namespace std;
bool judge( char a, char b, char c )
{
if( a == b && b == c && a != '+' )
return true;
return false;
}
int main()
{
char c[3][3];
while( cin >> c[0][0] )
{
if( c[0][0] == '0' )
break;
cin >> c[0][1] >> c[0][2];
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | def f(a):
for x in ['b','w']:
if a[0::4].count(x)==3 or a[2:7:2].count(x)==3:return x
for i in range(3):
if a[i*3:i*3+3].count(x)==3 or a[i::3].count(x)==3:return x
return 'NA'
while 1:
a=list(input())
if len(a)==1:break
a+=list(input())+list(input())
print(f(a)) | PYTHON3 |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <string>
#include <vector>
using namespace std;
int main() {
vector<string> bd(3);
while (cin >> bd[0], bd[0] != "0") {
for (int i=1; i<3; ++i) cin >> bd[i];
string res = "NA";
for (int k=0; k<3; ++k) {
if (bd[0][k] != '+' && bd[0][k] == bd[1][k]... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<cstdio>
#include<cstdlib>
#include<cmath>
#include<cstring>
#include<cctype>
#include<iostream>
#include<algorithm>
#include<vector>
#include<string>
#include<stack>
#include<queue>
#include<map>
using namespace std;
const int dx[] = {1,0,-1,0},dy[] = {0,1,0,-1};
#define INF 999999
#define rep(i,j) for(int i=... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <string>
using namespace std;
int main()
{
string s[3];
while (cin >> s[0], s[0] != "0"){
cin >> s[1] >> s[2];
bool c = true;
for (int i = 0; i < 3; i++){
if (s[i] == "www"){
cout << "w" << endl;
c = false;
break;
}
else if (s[i] == "bbb"){
cout << "b"... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
using namespace std;
int main(){
char s[3][3];
while(true){
cin >> s[0][0];
if(s[0][0]=='0') break;
for(int i = 0 ; i < 3 ; i++){
for(int j = 0 ; j < 3 ; j++){
if(!i&&!j) continue;
else cin >> s[i][j];
}
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
using namespace std;
int main() {
char hyou[3][3];
while (cin >> hyou[0][0]) {
if (hyou[0][0] == '0') {
break;
}
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
if (i != 0 || j != 0) {
cin >> hyou[i][j];
}
}
}
bool hantei = true;
for (int i = 0; i <... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <string>
using namespace std;
int main() {
for(string s1, s2, s3; cin >> s1, s1 != "0"; ) {
cin >> s2 >> s3;
string s = s1 + s2 + s3;
string bit[] = {
"111000000",
"000111000",
"000000111",
"100100100",
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <bits/stdc++.h>
using namespace std;
using ll = long long;
using pii = pair<int, int>;
int main() {
cin.tie(0);
ios_base::sync_with_stdio(false);
cout << fixed << setprecision(10);
string s[3];
while (cin >> s[0], s[0] != "0") {
cin >> s[1] >> s[2];
string ans = "NA";
for (int i = 0; ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | import java.util.Scanner;
public class Main{
public static void main(String[] args){
new Main().run();
}
public void run(){
Scanner scan = new Scanner(System.in);
int[][] dx = {{0,1,2},{0,3,6},{0,4,8},{1,4,7},{3,4,5},{6,7,8},{2,4,6},{2,5,8}};
int fl = 0;
int t = 0;
while(sca... | JAVA |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <cstdlib>
#include <cmath>
#include <climits>
#include <cfloat>
#include <map>
//#include <utility>
#include <set>
#include <iostream>
//#include <memory>
#include <string>
#include <vector>
#include <algorithm>
//#include <functional>
#include <sstream>
//#include <deque>
#include <complex>
#include <stack>
#... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | import java.util.Scanner;
//Black-and-White
public class Main{
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while(true){
String s = sc.next();
if(s.equals("0"))break;
char[][] m = new char[3][3];
m[0] = s.toCharArray();
for(int i=1;i<3;i++)m[i]=sc.next().toCharArra... | JAVA |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <string>
#include <vector>
using namespace std;
string solve( vector< string >& map )
{
char row, col, rd, ld, comp;
rd = map[ 0 ][ 0 ];
ld = map[ 0 ][ 2 ];
for( int i = 0; i < 3; ++i ){
row = map[ 0 ][ i ];
col = map[ i ][ 0 ];
for( int j = 0; j < 3; ++j ){
if( row != map[ j ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 |
import java.awt.geom.Point2D;
import java.io.*;
import java.math.BigInteger;
import java.util.ArrayDeque;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Collections;
import java.util.Comparator;
import java.util.Deque;
import java.util.HashMap;
import java.util.HashSet;
import java.util.List;
im... | JAVA |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
using namespace std;
int main() {
string str[3];
while(1) {
for(int i=0;i<3;i++) {
getline(cin,str[i]);
if(cin.eof()) return 0;
// cout << str[i] << endl;
}
bool r = false;
for(int i=0;i<3;i++) { //yoko
if(str[i][0] == str[i][1] && str[i][1] == str... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <fstream>
#include <algorithm>
#include <cassert>
#include <cctype>
#include <complex>
#include <cstdio>
#include <map>
#include <math.h>
#include <queue>
#include <set>
#include <stack>
#include <string>
#include <vector>
using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
int l[]... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | // 0183
#include <iostream>
#include <string>
using namespace std;
bool check(char bw[3][3], char x){
for(int i=0;i<3;i++)
if((bw[i][0] == x) && (bw[i][1] == x) && (bw[i][2] == x))
return true;
else if((bw[0][i] == x) && (bw[1][i] == x) && (bw[2][i] == x))
return true;
if((bw[0][0] == x) && (bw[1][1] == ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | import java.util.Scanner;
public class Main {
/**
* @param args
*/
static String[] field = new String[3];
public static void main(String[] args) {
Scanner cin = new Scanner(System.in);
label:while(true){
field = new String[3];
field[0]=cin.next();
if(field[0].equals("0")){
break;
}
field... | JAVA |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
#include<algorithm>
#include<vector>
#include<stack>
#include<map>
#include<set>
#include<queue>
#include<cstdio>
#include<climits>
#include<cmath>
#include<cstring>
#include<string>
#include<sstream>
#include<numeric>
#include<cassert>
#define f first
#define s second
#define mp make_pair
#define ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <bits/stdc++.h>
using namespace std;
int main(void){
std::deque<char> deq1;
std::deque<char> deq2;
std::deque<char> deq3;
string s;
while(cin>>s) {
if (s=="0") {
break;
} else {
for (int i=0;i<3;i++) {
deq1.emplace_back(s.at(i));
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <iomanip>
#include <vector>
#include <string>
#include <stack>
#include <queue>
#include <deque>
#include <set>
#include <map>
#include <algorithm>
#include <sstream>
#include <cstdlib>
#include <cstring>
#include <functional>
#include <numeric>
#include <cmath>
#include <climits>
#include ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 |
#define _CRT_SECURE_NO_WARNINGS
#define _USE_MATH_DEFINES
#include <cfloat>
#include <climits>
#include <cmath>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <ctime>
#include <iostream>
#include <memory>
#include <string>
#include <algorithm>
#include <complex>
#include <list>
#include <map>
#inclu... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <cstdio>
using namespace std;
int main(){
int i,j;
char g[3][3];
char win;
while(1){
for(i=0;i<3;i++){
for(j=0;j<3;j++){
cin >> g[i][j];
if(g[0][0]=='0') return 0;
if(g[i][j]=='+') g[i][j]=(j+1)*(i+1);
}
}
for(i=0;i<3;i++){
if(g[i][0]==g... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
using namespace std;
int main()
{
char field[3][3];
while(true){
for(int i=0;i<3;i++){
for(int j=0;j<3;j++){
cin >> field[i][j];
if(field[i][j] == '0')
return 0;
}
}
bool flag = false;
for(int i=0;i<3;i++){
if(field[i][1] == field[i][0] && field[i][1] == field[i][2] ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
using namespace std;
int main(){
while(true){
string s[3];
cin >> s[0];
if(s[0] == "0")break;
cin >> s[1];
cin >> s[2];
if(s[0][0] == s[0][1] && s[0][1] == s[0][2] && s[0][0] != '+'){
cout << s[0][0] << endl;
continue;
}
if(s[0][0] == s[1][0] && s[1][... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | import java.util.Scanner;
public class Main {
static char[][] f;
public static void main(String[] args) {
Scanner stdIn = new Scanner(System.in);
while(true){
f = new char[3][3];
for(int i=0;i<3;i++){
char[] input = stdIn.nextLine().toCharArray();
if(input[0]=='0') return;
f[i] = new char[3];
... | JAVA |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | import java.util.*;
import java.io.*;
public class Main {
static void solve (FastScanner in, PrintWriter out, Methods ms) {
while (true) {
char[][] map = new char[3][3];
String s = in.next();
if (s.equals("0")) return;
map[0] = s.toCharArray();
map[1] = in.next().toCharArray();
map[2] = in.n... | JAVA |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
using namespace std;
int main(){
char board[3][4];
int i;
char w;
while(true){
w='0';
for(i=0;i<3;i++){
cin>>board[i];
if(board[i][0] == '0' && board[i][1] == '\0'){
break;
}
}
if(i<3) break;
for(i=0;i<3;i++){
if(board[i][0]==board[i][1] && board[i][0]==board[i][2] && b... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | def f(a):
for x in ['b','w']:
if a[0::4].count(x)==3 or a[2:7:2].count(x)==3:return x
for i in range(3):
if a[i*3:i*3+3].count(x)==3 or a[i::3].count(x)==3:return x
return 'NA'
while 1:
a=input()
if a=='0':break
print(f(a+input()+input())) | PYTHON3 |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <fstream>
#include <sstream>
#include <iomanip>
#include <complex>
#include <string>
#include <vector>
#include <list>
#include <deque>
#include <stack>
#include <queue>
#include <set>
#include <map>
#include <bitset>
#include <functional>
#include <utility>
#include <algorithm>
#include <n... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <string>
#include <vector>
#include <algorithm>
#define REP(i,k,n) for(int i=k;i<n;i++)
#define rep(i,n) for(int i=0;i<n;i++)
using namespace std;
int main()
{
string s;
while(cin >> s)
{
if(s == "0") break;
vector<string> v;
v.push_back(s);
rep(i,2)
{
string temp;
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | /* {{{ Shinobu kawaii */
/*
______ __ _ __
.' ____ \ [ | (_) [ |
| (___ \_| | |--. __ _ .--. .--. | |.--. __ _
_.____`. | .-. | [ | [ `.-. |/ .'`\ \| '/'`\ \[ | | |
| \____) | | | | | | | | | | || \__. || \__/ | | ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | //38
#include<iostream>
using namespace std;
int main(){
for(;;){
char g[3][3];
for(int i=0;i<3;i++){
for(int j=0;j<3;j++){
cin>>g[i][j];
if(g[i][j]=='0')return 0;
}
}
for(int i=0;i<3;i++){
if(g[i][0]!='+'&&g[i][0]==g[i][1]&&g[i][0]==g[i][2]){
cout<<g[i][0]<<endl;
goto next;
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <algorithm>
#include <map>
#include <set>
#include <queue>
#include <stack>
#include <numeric>
#include <bitset>
#include <cmath>
static const int MOD = 1000000007;
using ll = long long;
using u32 = unsigned;
using u64 = unsigned long long;
using namespace std;
template<class T> constexpr... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <cstdio>
#include <vector>
#include <algorithm>
#include <complex>
#include <cstring>
#include <cstdlib>
#include <string>
#include <cmath>
#include <queue>
using namespace std;
#define REP(i,n) for(int i=0;i<(int)n;++i)
#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 |
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
new Main().run();
}
private void run() {
Scanner scanner = new Scanner(System.in);
while (true) {
String line1 = scanner.next();
if (line1.equals("0"))
break;
char[][] map = new char[3][3];
map[0] = line1.... | JAVA |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
using namespace std;
int main(void){
for(;;){
char a[3][3];
int f=0,z=0;
for (int i=0;i<3;i++){
cin>>a[i];
if(a[i][0]=='0'){
z++;
break;
}
}
if(z!=0)break;
for(int i=0;i<1;i++){
for(int j=0;j<3;j++){
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <vector>
#include <string>
using namespace std;
int main( void )
{
while ( 1 )
{
vector <string> M(3);
bool not_found;
cin >> M[0];
if ( M[0] == "0" ) break;
cin >> M[1] >> M[2];
not_found = true;
for ( int i = 0; not_found && i < 3; i++ )
{
if ( M[i][0] == M[i][1] &&... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
#include<string>
using namespace std;
int main(){
string s[3];
while(cin>>s[0]){
if(s[0]=="0")break;
cin>>s[1]>>s[2];
if(s[0][0]!='+'&&s[0][0]==s[0][1]&&s[0][1]==s[0][2]){cout<<s[0][0]<<endl;continue;}
if(s[1][0]!='+'&&s[1][0]==s[1][1]&&s[1][1]==s[1][2]){cout<<s[1][0]<<endl;continue;}
if(s[2][0]!='+'... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <stdio.h>
#define NON 0
#define BLK 1
#define WHT -1
#define SIZE 3
int isGameSet(int iField[SIZE][SIZE]);
int main(void){
int board[SIZE][SIZE];
char buf[4];
while(1){
for (int y=0; y<SIZE; y++){
scanf("%s", buf);
if (buf[0]=='0') return 0;
for (... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
using namespace std;
string a[3];
char tate(){
for(int i=0;i<3;i++){
if(a[0][i]==a[1][i]&&a[0][i]==a[2][i]&&a[0][i]!='+'){
return a[0][i];
}
}
return '+';
}
char yoko(){
for(int i=0;i<3;i++){
if(a[i][0]==a[i][1]&&a[i][0]==a[i][2]&&a[i][0]!='+'){
return a[i][0];
}
}
return '+';
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
int board[3][3];
int main(){
char c;
while(cin >> c){
if(c == '0'){
return 0;
}
//テ、ツスツソテァツ板ィテ」ツδ愿」ツδシテ」ツδ嘉」ツつ?テ」ツ?ァテ・ツ按敕ヲツ慊淌・ツ個?
for(int i=0;i<3;i++){
for(int j=0;j<3;j++){
board[i][j] = 0;
}
}
for(int... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | all_b = "bbb"
all_w = "www"
while True:
r1 = input()
if r1 == "0":
break
r2 = input()
r3 = input()
cands = [r1, r2, r3]
for i in range(3):
col = r1[i] + r2[i] + r3[i]
cands.append(col)
cands.append(r1[0] + r2[1] + r3[2])
cands.append(r1[2] + r2[1] + r3[0])
for cand in cands:
if cand ==... | PYTHON3 |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | //AOJ 0183
#include <iostream>
#include <string>
using namespace std;
int main(){
string s[3];
char w;
while (1) {
w = 'q';
for (auto& i : s) {
cin>>i;
if(i == "0") return 0;
}
bool end = false;
for (int i = 0; i < 3; i++) {
char c = s[i][0];
bool flag = true;
for (int j = 0; j < 3; j++)
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <string>
using namespace std;
string m[3];
string solve(){
for(int i=0 ; i < 3 ; i++ ){
if( m[i] == "bbb" )
return "b";
if( m[i] == "www" )
return "w";
if( m[0][i] == 'b' && m[1][i] == 'b' && m[2][i] == 'b' )
return "b";
if( m[0][i] == 'w' && m[1][i] == 'w' && m[2][i] ==... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
void dwrite(int i){
std::cout << i << std::endl;
}
int main(){
std::string m[3], w;
while(std::cin >> m[0], m[0][0] != '0'){
for(int i=1;i<3;i++)std::cin >> m[i];
w = "NA";
for(int i=0;i<3;i++){
if(m[i][0] + m[i][1] - m[i][2] * 2 == 0 && m[i][0] - '+')w = m[i][0];
if(m[0][i] + m[1][... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
#include<cstdio>
#include<algorithm>
using namespace std;
const int dy[8] = {-1,-1,0,1,1,1,0,-1}, dx[8] = {0,1,1,1,0,-1,-1,-1};
int main(){
char fld[3][3];
while(true){
for(int i=0;i<3;i++){
for(int j=0;j<3;j++){
cin>>fld[i][j];
if(fld[i][j]=='0') return 0;
}
}
for(int i=0;i<3... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
#include<string>
using namespace std;
char T[3][3];
string blackwhite() {
for (int i = 0; i < 3; i++) {
if (T[i][0] == T[i][1] && T[i][1] == T[i][2]) {
if (T[i][0] == 'b') { return "b"; }
if (T[i][0] == 'w') { return "w"; }
}
}
for (int i = 0; i < 3; i++) {
if (T[0][i] == T[1][i] && ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <vector>
#include <algorithm>
using namespace std;
#define rep(i,n) for(int i=0;i<n;i++)
int di[][3] = {
{0,1,2},{3,4,5},{6,7,8},
{0,3,6},{1,4,7},{2,5,8},
{0,4,8},{2,4,6}
};
int main(){
string t;
while(cin >> t , t != "0"){
string ans = "NA";
string s; s += t;
rep(i,2)cin >> t ,... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
#include<string>
using namespace std;
int main() {
char b[5][5];
while (cin >> b[0] ) {
if (b[0][0] == '0')break;
cin >> b[1] >> b[2];
string x;
if (b[0][0] == b[0][1] && b[0][1] == b[0][2] && b[0][0] != '+') { x = b[0][0]; }
else if (b[1][0] == b[1][1] && b[1][1] == b[1][2] && b[1][0] ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <bits/stdc++.h>
using namespace std;
int main()
{
char c;
while (cin >> c, c != '0') {
char b[3][3]; b[0][0] = c;
for (int i = 1; i < 9; i++) {
cin >> b[i/3][i%3];
}
auto win = [&](char c) -> bool {
for (int i = 0; i < 3; i++) {
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | import java.util.regex.*;class Main{public static void main(String[]z)throws Exception{String r;for(byte[]x=new byte[12];System.in.read(x)>11;System.out.println(r)){r="NA";for(String y:"b w".split(" "))for(int i=0;i<5;++i)if(i!=1&&Pattern.compile(String.format(".*%1$s.{%2$s}%1$s.{%2$s}%1$s.*",y,i),Pattern.DOTALL).match... | JAVA |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<bits/stdc++.h>
#define rep(i,n)for(int i=0;i<n;i++)
using namespace std;
typedef pair<int, int>P;
char a[3][3];
int main() {
while (cin >> a[0][0], a[0][0] != 48) {
rep(i, 3)rep(j, 3)if (i || j)cin >> a[i][j];
rep(i, 3) {
if (a[i][0] == a[i][1] && a[i][1] == a[i][2] && a[i][0] != '+') {
cout << a[... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
using namespace std;
int main() {
char c[3][4],a;
int i;
while(cin >> c[0]) {
if (c[0][0]=='0') break;
cin >> c[1] >> c[2];
a='+';
if (((c[0][0]==c[1][1] && c[1][1]==c[2][2]) || (c[0][2]==c[1][1] && c[1][1]==c[2][0])) && c[1][1]!='+') a=c[1][1];
else {
for (i=0;i<3;i++) {
if (c... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | // 2011/08/24 Tazoe
#include <iostream>
using namespace std;
int main()
{
while(true){
char brd[3][3];
for(int i=0; i<3; i++){
for(int j=0; j<3; j++){
cin >> brd[i][j];
if(brd[i][j]=='0') // ¶
return 0;
}
}
if(brd[0][0]!='+'&&brd[0][0]==brd[0][1]&&brd[0][1]==brd[0][2])
cout << brd[0... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <cstdio>
#include <algorithm>
#include <cmath>
#include <vector>
using namespace std;
int main()
{
string a[3];
char ans;
while(true){
cin >> a[0];
if(a[0][0] == '0'){
break;
}
cin >> a[1] >> a[2];
ans = '0';
for(int i = 0; i < 3; i++)... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
using namespace std;
char t[4][4];
char judge(void){
for(int i=0;i<3;i++){
int j;
for(j=1;j<3;j++){
if(t[i][j-1] != t[i][j]) break;
}
if(j == 3 && t[i][0] != '+'){
return t[i][0];
}
}
for(int j=0;j<3;j++){
int i;
for(i=1;i<3;i++){
if(t[i-1][j] != t[i][j]) break;
}
if(... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
using namespace std;
int main() {
while (true) {
char field[3][4];
for (int i = 0; i < 3; i++) {
cin >> field[i];
}
if (field[0][0] == '0') {
break;
}
if (field[1][1] != '+' &&
((field[1][1] == field[0][0] && fi... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <string>
using namespace std;
char solve(char board[9]) {
//テァツクツヲ
for (int i = 0; i < 3; i++)
if (board[i] != '+' && board[i] == board[i + 3] && board[i] == board[i + 3 * 2])
return board[i];
//テヲツィツェ
for (int i = 0; i < 9; i += 3)
if (board[i] != '+' && board[i] == board[i ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <string>
#include <cstdio>
#include <cstring>
using namespace std;
int main(){
char ban[9];
int hoge[9];
int tmp[8][3]={{0,1,2},{3,4,5},{6,7,8},{0,3,6},{1,4,7},{2,5,8},{0,4,8},{2,4,6}};
while(true){
int hatena = -1;
cin >> ban[0];
if(ban[0]=='0') break;
for(int i=1;i... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include<iostream>
#include<cmath>
#include<vector>
#include<string>
typedef unsigned long long ull;
#define rep(i,a) for(int i=0;i<a;i++)
#define loop(i,a,b) for(int i=a;i<b;i++)
using namespace std;
const double eps = 1e-10;
const double pi = acos(-1);
const double inf = (int)1e8;
int main(void){
char maze[3][3];
... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <bits/stdc++.h>
using namespace std;
#define FOR(i, s, n) for(int i = s; i < (int)n; ++i)
#define per(i, n) for(int i = n; i >= 0; i--)
#define ROF(i, s, n) for(int i = s; i >= (int)n; i--)
#define FORIT(i, A) for (auto i : A)
#define PRINT(x) cout << (x) << "\n"
#define ALL(a) (a).begin(),(a).end()
#define RA... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 |
import java.util.Scanner;
public class Main {
char [][] data;
private char check(int x, int y){
char ans = data[y][x];
//tate
if(ans == data[y+1][x] && ans == data[y-1][x]){
return ans;
}
//yoko
if(ans == data[y][x+1] && ans == data[y][x-1]){
return ans;
}
//naname
if(ans == data[y-1][x-1]... | JAVA |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#define rep(i,n) for(int i=0;i<(int)(n);i++)
using namespace std;
typedef pair<string, int> P;
/** Problem0183 : Black-and-White **/
int main()
{
string board;
while (cin>>board, board!="0") {
string s; cin>>s;
board+=s;
cin >>s; board+=s;
for (int i=0; i<3; i++) {
if (board[i*3] != '... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <bits/stdc++.h>
using namespace std;
string MapData[3];
void judge() {
for (int i = 0; i < 3; i++) {
//judgeByRow
if (MapData[i][0] != '+' && MapData[i][0] == MapData[i][1] && MapData[i][1] == MapData[i][2]) {
cout << MapData[i][0] << endl;
return;
}
//judgeByCol
if (MapData[0][i] != '+' ... | CPP |
p00183 Black-and-White | Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizon... | 7 | 0 | #include <iostream>
#include <string>
#define BLACK 'b'
#define WHITE 'w'
#define SPACE '+'
using namespace std;
char isWin(string data[3]) {
char temp;
temp = data[0][0];
if(temp != SPACE && data[1][1] == temp && data[2][2] == temp) return temp;
temp = data[2][0];
if(temp != SPACE && data[1][1] == temp &... | CPP |
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