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Please provide an equivalent version of this Scala code in VB.
fun median(x: DoubleArray, start: Int, endInclusive: Int): Double { val size = endInclusive - start + 1 require (size > 0) { "Array slice cannot be empty" } val m = start + size / 2 return if (size % 2 == 1) x[m] else (x[m - 1] + x[m]) / 2.0 } fun fivenum(x: DoubleArray): DoubleArray { require(x....
#define floor(x) ((x*2.0-0.5) Shr 1) Sub rapidSort (array()As Single, l As Integer, r As Integer) Dim As Integer n, wert, nptr, rep Dim As Single arr, LoVal = array(l), HiVal = array(r) For n = l To r If LoVal > array(n) Then LoVal = array(n) If HiVal < array(n) Then HiVal = array(n) Ne...
Port the provided Scala code into VB while preserving the original functionality.
fun median(x: DoubleArray, start: Int, endInclusive: Int): Double { val size = endInclusive - start + 1 require (size > 0) { "Array slice cannot be empty" } val m = start + size / 2 return if (size % 2 == 1) x[m] else (x[m - 1] + x[m]) / 2.0 } fun fivenum(x: DoubleArray): DoubleArray { require(x....
#define floor(x) ((x*2.0-0.5) Shr 1) Sub rapidSort (array()As Single, l As Integer, r As Integer) Dim As Integer n, wert, nptr, rep Dim As Single arr, LoVal = array(l), HiVal = array(r) For n = l To r If LoVal > array(n) Then LoVal = array(n) If HiVal < array(n) Then HiVal = array(n) Ne...
Write the same code in Go as shown below in Scala.
fun median(x: DoubleArray, start: Int, endInclusive: Int): Double { val size = endInclusive - start + 1 require (size > 0) { "Array slice cannot be empty" } val m = start + size / 2 return if (size % 2 == 1) x[m] else (x[m - 1] + x[m]) / 2.0 } fun fivenum(x: DoubleArray): DoubleArray { require(x....
package main import ( "fmt" "math" "sort" ) func fivenum(a []float64) (n5 [5]float64) { sort.Float64s(a) n := float64(len(a)) n4 := float64((len(a)+3)/2) / 2 d := []float64{1, n4, (n + 1) / 2, n + 1 - n4, n} for e, de := range d { floor := int(de - 1) ceil := int(math.C...
Generate an equivalent Go version of this Scala code.
fun median(x: DoubleArray, start: Int, endInclusive: Int): Double { val size = endInclusive - start + 1 require (size > 0) { "Array slice cannot be empty" } val m = start + size / 2 return if (size % 2 == 1) x[m] else (x[m - 1] + x[m]) / 2.0 } fun fivenum(x: DoubleArray): DoubleArray { require(x....
package main import ( "fmt" "math" "sort" ) func fivenum(a []float64) (n5 [5]float64) { sort.Float64s(a) n := float64(len(a)) n4 := float64((len(a)+3)/2) / 2 d := []float64{1, n4, (n + 1) / 2, n + 1 - n4, n} for e, de := range d { floor := int(de - 1) ceil := int(math.C...
Keep all operations the same but rewrite the snippet in Rust.
#include <stdio.h> #include <stdlib.h> double median(double *x, int start, int end_inclusive) { int size = end_inclusive - start + 1; if (size <= 0) { printf("Array slice cannot be empty\n"); exit(1); } int m = start + size / 2; if (size % 2) return x[m]; return (x[m - 1] + x[m]...
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
Write the same algorithm in Rust as shown in this C implementation.
#include <stdio.h> #include <stdlib.h> double median(double *x, int start, int end_inclusive) { int size = end_inclusive - start + 1; if (size <= 0) { printf("Array slice cannot be empty\n"); exit(1); } int m = start + size / 2; if (size % 2) return x[m]; return (x[m - 1] + x[m]...
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
Produce a functionally identical Rust code for the snippet given in C++.
#include <algorithm> #include <iostream> #include <ostream> #include <vector> template<std::size_t> struct int_ {}; template <class Tuple, size_t Pos> std::ostream& print_tuple(std::ostream& out, const Tuple& t, int_<Pos>) { out << std::get< std::tuple_size<Tuple>::value - Pos >(t) << ", "; return print_t...
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
Can you help me rewrite this code in Rust instead of Go, keeping it the same logically?
package main import ( "fmt" "math" "sort" ) func fivenum(a []float64) (n5 [5]float64) { sort.Float64s(a) n := float64(len(a)) n4 := float64((len(a)+3)/2) / 2 d := []float64{1, n4, (n + 1) / 2, n + 1 - n4, n} for e, de := range d { floor := int(de - 1) ceil := int(math.C...
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
Transform the following Rust implementation into Python, maintaining the same output and logic.
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
from __future__ import division import math import sys def fivenum(array): n = len(array) if n == 0: print("you entered an empty array.") sys.exit() x = sorted(array) n4 = math.floor((n+3.0)/2.0)/2.0 d = [1, n4, (n+1)/2, n+1-n4, n] sum_array = [] for e in range(5):...
Produce a language-to-language conversion: from Rust to VB, same semantics.
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
Option Base 1 Private Function median(tbl As Variant, lo As Integer, hi As Integer) Dim l As Integer: l = hi - lo + 1 Dim m As Integer: m = lo + WorksheetFunction.Floor_Precise(l / 2) If l Mod 2 = 1 Then median = tbl(m) Else median = (tbl(m - 1) + tbl(m)) / 2 End if End Function Pri...
Convert this C++ block to Rust, preserving its control flow and logic.
#include <algorithm> #include <iostream> #include <ostream> #include <vector> template<std::size_t> struct int_ {}; template <class Tuple, size_t Pos> std::ostream& print_tuple(std::ostream& out, const Tuple& t, int_<Pos>) { out << std::get< std::tuple_size<Tuple>::value - Pos >(t) << ", "; return print_t...
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
Generate an equivalent Rust version of this C# code.
using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace Fivenum { public static class Helper { public static string AsString<T>(this ICollection<T> c, string format = "{0}") { StringBuilder sb = new StringBuilder("["); int count = 0; ...
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
Translate the given C# code snippet into Rust without altering its behavior.
using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace Fivenum { public static class Helper { public static string AsString<T>(this ICollection<T> c, string format = "{0}") { StringBuilder sb = new StringBuilder("["); int count = 0; ...
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
Write the same algorithm in Rust as shown in this Java implementation.
import java.util.Arrays; public class Fivenum { static double median(double[] x, int start, int endInclusive) { int size = endInclusive - start + 1; if (size <= 0) throw new IllegalArgumentException("Array slice cannot be empty"); int m = start + size / 2; return (size % 2 == 1) ? ...
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
Preserve the algorithm and functionality while converting the code from Java to Rust.
import java.util.Arrays; public class Fivenum { static double median(double[] x, int start, int endInclusive) { int size = endInclusive - start + 1; if (size <= 0) throw new IllegalArgumentException("Array slice cannot be empty"); int m = start + size / 2; return (size % 2 == 1) ? ...
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
Port the following code from Go to Rust with equivalent syntax and logic.
package main import ( "fmt" "math" "sort" ) func fivenum(a []float64) (n5 [5]float64) { sort.Float64s(a) n := float64(len(a)) n4 := float64((len(a)+3)/2) / 2 d := []float64{1, n4, (n + 1) / 2, n + 1 - n4, n} for e, de := range d { floor := int(de - 1) ceil := int(math.C...
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
Produce a language-to-language conversion: from Rust to Python, same semantics.
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
from __future__ import division import math import sys def fivenum(array): n = len(array) if n == 0: print("you entered an empty array.") sys.exit() x = sorted(array) n4 = math.floor((n+3.0)/2.0)/2.0 d = [1, n4, (n+1)/2, n+1-n4, n] sum_array = [] for e in range(5):...
Generate an equivalent VB version of this Rust code.
#[derive(Debug)] struct FiveNum { minimum: f64, lower_quartile: f64, median: f64, upper_quartile: f64, maximum: f64, } fn median(samples: &[f64]) -> f64 { let n = samples.len(); let m = n / 2; if n % 2 == 0 { (samples[m] + samples[m - 1]) / 2.0 } else { samples[...
Option Base 1 Private Function median(tbl As Variant, lo As Integer, hi As Integer) Dim l As Integer: l = hi - lo + 1 Dim m As Integer: m = lo + WorksheetFunction.Floor_Precise(l / 2) If l Mod 2 = 1 Then median = tbl(m) Else median = (tbl(m - 1) + tbl(m)) / 2 End if End Function Pri...
Rewrite this program in C# while keeping its functionality equivalent to the Ada version.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Nth_Root is generic type Real is digits <>; function Nth_Root (Value : Real; N : Positive) return Real; function Nth_Root (Value : Real; N : Positive) return Real is type Index is mod 2; X : array (Index) of Real := (Value, Value); ...
static void Main(string[] args) { Console.WriteLine(NthRoot(81,2,.001)); Console.WriteLine(NthRoot(1000,3,.001)); Console.ReadLine(); } public static double NthRoot(double A,int n, double p) { double _n= (double) n; double[] x = new double[2]; x[0] = A; x[1] = A/_n; while(Math.Abs(x[0] -x[1] )...
Generate an equivalent C version of this Ada code.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Nth_Root is generic type Real is digits <>; function Nth_Root (Value : Real; N : Positive) return Real; function Nth_Root (Value : Real; N : Positive) return Real is type Index is mod 2; X : array (Index) of Real := (Value, Value); ...
#include <stdio.h> #include <float.h> double pow_ (double x, int e) { int i; double r = 1; for (i = 0; i < e; i++) { r *= x; } return r; } double root (int n, double x) { double d, r = 1; if (!x) { return 0; } if (n < 1 || (x < 0 && !(n&1))) { return 0.0 / 0...
Translate the given Ada code snippet into C++ without altering its behavior.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Nth_Root is generic type Real is digits <>; function Nth_Root (Value : Real; N : Positive) return Real; function Nth_Root (Value : Real; N : Positive) return Real is type Index is mod 2; X : array (Index) of Real := (Value, Value); ...
double NthRoot(double m_nValue, double index, double guess, double pc) { double result = guess; double result_next; do { result_next = (1.0/index)*((index-1.0)*result+(m_nValue)/(pow(result,(index-1.0)))); result = result_next; pc--; }while(pc>1); ...
Generate a Go translation of this Ada snippet without changing its computational steps.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Nth_Root is generic type Real is digits <>; function Nth_Root (Value : Real; N : Positive) return Real; function Nth_Root (Value : Real; N : Positive) return Real is type Index is mod 2; X : array (Index) of Real := (Value, Value); ...
func root(a float64, n int) float64 { n1 := n - 1 n1f, rn := float64(n1), 1/float64(n) x, x0 := 1., 0. for { potx, t2 := 1/x, a for b := n1; b > 0; b >>= 1 { if b&1 == 1 { t2 *= potx } potx *= potx } x0, x = x, rn*(n1f*x...
Can you help me rewrite this code in Java instead of Ada, keeping it the same logically?
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Nth_Root is generic type Real is digits <>; function Nth_Root (Value : Real; N : Positive) return Real; function Nth_Root (Value : Real; N : Positive) return Real is type Index is mod 2; X : array (Index) of Real := (Value, Value); ...
public static double nthroot(int n, double A) { return nthroot(n, A, .001); } public static double nthroot(int n, double A, double p) { if(A < 0) { System.err.println("A < 0"); return -1; } else if(A == 0) { return 0; } double x_prev = A; double x = A / n; while(Math.abs(x - x_prev) > p) { x_prev = x; ...
Preserve the algorithm and functionality while converting the code from Ada to Python.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Nth_Root is generic type Real is digits <>; function Nth_Root (Value : Real; N : Positive) return Real; function Nth_Root (Value : Real; N : Positive) return Real is type Index is mod 2; X : array (Index) of Real := (Value, Value); ...
from decimal import Decimal, getcontext def nthroot (n, A, precision): getcontext().prec = precision n = Decimal(n) x_0 = A / n x_1 = 1 while True: x_0, x_1 = x_1, (1 / n)*((n - 1)*x_0 + (A / (x_0 ** (n - 1)))) if x_0 == x_1: return x_1
Generate an equivalent VB version of this Ada code.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Nth_Root is generic type Real is digits <>; function Nth_Root (Value : Real; N : Positive) return Real; function Nth_Root (Value : Real; N : Positive) return Real is type Index is mod 2; X : array (Index) of Real := (Value, Value); ...
Private Function nth_root(y As Double, n As Double) Dim eps As Double: eps = 0.00000000000001 Dim x As Variant: x = 1 Do While True d = (y / x ^ (n - 1) - x) / n x = x + d e = eps * x If d > -e And d < e Then Exit Do End If Loop Debug.Print y; n;...
Please provide an equivalent version of this Arturo code in C.
nthRoot: function [a,n][ N: to :floating n result: a x: a / N while [0.000000000000001 < abs result-x][ x: result result: (1//n) * add (n-1)*x a/pow x n-1 ] return result ] print nthRoot 34.0 5 print nthRoot 42.0 10 print nthRoot 5.0 2
#include <stdio.h> #include <float.h> double pow_ (double x, int e) { int i; double r = 1; for (i = 0; i < e; i++) { r *= x; } return r; } double root (int n, double x) { double d, r = 1; if (!x) { return 0; } if (n < 1 || (x < 0 && !(n&1))) { return 0.0 / 0...
Convert the following code from Arturo to C#, ensuring the logic remains intact.
nthRoot: function [a,n][ N: to :floating n result: a x: a / N while [0.000000000000001 < abs result-x][ x: result result: (1//n) * add (n-1)*x a/pow x n-1 ] return result ] print nthRoot 34.0 5 print nthRoot 42.0 10 print nthRoot 5.0 2
static void Main(string[] args) { Console.WriteLine(NthRoot(81,2,.001)); Console.WriteLine(NthRoot(1000,3,.001)); Console.ReadLine(); } public static double NthRoot(double A,int n, double p) { double _n= (double) n; double[] x = new double[2]; x[0] = A; x[1] = A/_n; while(Math.Abs(x[0] -x[1] )...
Port the following code from Arturo to C++ with equivalent syntax and logic.
nthRoot: function [a,n][ N: to :floating n result: a x: a / N while [0.000000000000001 < abs result-x][ x: result result: (1//n) * add (n-1)*x a/pow x n-1 ] return result ] print nthRoot 34.0 5 print nthRoot 42.0 10 print nthRoot 5.0 2
double NthRoot(double m_nValue, double index, double guess, double pc) { double result = guess; double result_next; do { result_next = (1.0/index)*((index-1.0)*result+(m_nValue)/(pow(result,(index-1.0)))); result = result_next; pc--; }while(pc>1); ...
Rewrite this program in Java while keeping its functionality equivalent to the Arturo version.
nthRoot: function [a,n][ N: to :floating n result: a x: a / N while [0.000000000000001 < abs result-x][ x: result result: (1//n) * add (n-1)*x a/pow x n-1 ] return result ] print nthRoot 34.0 5 print nthRoot 42.0 10 print nthRoot 5.0 2
public static double nthroot(int n, double A) { return nthroot(n, A, .001); } public static double nthroot(int n, double A, double p) { if(A < 0) { System.err.println("A < 0"); return -1; } else if(A == 0) { return 0; } double x_prev = A; double x = A / n; while(Math.abs(x - x_prev) > p) { x_prev = x; ...
Port the following code from Arturo to Python with equivalent syntax and logic.
nthRoot: function [a,n][ N: to :floating n result: a x: a / N while [0.000000000000001 < abs result-x][ x: result result: (1//n) * add (n-1)*x a/pow x n-1 ] return result ] print nthRoot 34.0 5 print nthRoot 42.0 10 print nthRoot 5.0 2
from decimal import Decimal, getcontext def nthroot (n, A, precision): getcontext().prec = precision n = Decimal(n) x_0 = A / n x_1 = 1 while True: x_0, x_1 = x_1, (1 / n)*((n - 1)*x_0 + (A / (x_0 ** (n - 1)))) if x_0 == x_1: return x_1
Convert the following code from Arturo to VB, ensuring the logic remains intact.
nthRoot: function [a,n][ N: to :floating n result: a x: a / N while [0.000000000000001 < abs result-x][ x: result result: (1//n) * add (n-1)*x a/pow x n-1 ] return result ] print nthRoot 34.0 5 print nthRoot 42.0 10 print nthRoot 5.0 2
Private Function nth_root(y As Double, n As Double) Dim eps As Double: eps = 0.00000000000001 Dim x As Variant: x = 1 Do While True d = (y / x ^ (n - 1) - x) / n x = x + d e = eps * x If d > -e And d < e Then Exit Do End If Loop Debug.Print y; n;...
Produce a functionally identical Go code for the snippet given in Arturo.
nthRoot: function [a,n][ N: to :floating n result: a x: a / N while [0.000000000000001 < abs result-x][ x: result result: (1//n) * add (n-1)*x a/pow x n-1 ] return result ] print nthRoot 34.0 5 print nthRoot 42.0 10 print nthRoot 5.0 2
func root(a float64, n int) float64 { n1 := n - 1 n1f, rn := float64(n1), 1/float64(n) x, x0 := 1., 0. for { potx, t2 := 1/x, a for b := n1; b > 0; b >>= 1 { if b&1 == 1 { t2 *= potx } potx *= potx } x0, x = x, rn*(n1f*x...
Generate a C translation of this AutoHotKey snippet without changing its computational steps.
p := 0.000001 MsgBox, % nthRoot( 10, 7131.5**10, p) "`n" . nthRoot( 5, 34.0 , p) "`n" . nthRoot( 2, 2 , p) "`n" . nthRoot(0.5, 7 , p) "`n" nthRoot(n, A, p) {  x1 := A x2 := A / n While Abs(x1 - x2) > p { x1 := x2 x2 := ((n-1)*x2+A/x2**(n-1)...
#include <stdio.h> #include <float.h> double pow_ (double x, int e) { int i; double r = 1; for (i = 0; i < e; i++) { r *= x; } return r; } double root (int n, double x) { double d, r = 1; if (!x) { return 0; } if (n < 1 || (x < 0 && !(n&1))) { return 0.0 / 0...
Translate the given AutoHotKey code snippet into C# without altering its behavior.
p := 0.000001 MsgBox, % nthRoot( 10, 7131.5**10, p) "`n" . nthRoot( 5, 34.0 , p) "`n" . nthRoot( 2, 2 , p) "`n" . nthRoot(0.5, 7 , p) "`n" nthRoot(n, A, p) {  x1 := A x2 := A / n While Abs(x1 - x2) > p { x1 := x2 x2 := ((n-1)*x2+A/x2**(n-1)...
static void Main(string[] args) { Console.WriteLine(NthRoot(81,2,.001)); Console.WriteLine(NthRoot(1000,3,.001)); Console.ReadLine(); } public static double NthRoot(double A,int n, double p) { double _n= (double) n; double[] x = new double[2]; x[0] = A; x[1] = A/_n; while(Math.Abs(x[0] -x[1] )...
Port the following code from AutoHotKey to C++ with equivalent syntax and logic.
p := 0.000001 MsgBox, % nthRoot( 10, 7131.5**10, p) "`n" . nthRoot( 5, 34.0 , p) "`n" . nthRoot( 2, 2 , p) "`n" . nthRoot(0.5, 7 , p) "`n" nthRoot(n, A, p) {  x1 := A x2 := A / n While Abs(x1 - x2) > p { x1 := x2 x2 := ((n-1)*x2+A/x2**(n-1)...
double NthRoot(double m_nValue, double index, double guess, double pc) { double result = guess; double result_next; do { result_next = (1.0/index)*((index-1.0)*result+(m_nValue)/(pow(result,(index-1.0)))); result = result_next; pc--; }while(pc>1); ...
Write a version of this AutoHotKey function in Java with identical behavior.
p := 0.000001 MsgBox, % nthRoot( 10, 7131.5**10, p) "`n" . nthRoot( 5, 34.0 , p) "`n" . nthRoot( 2, 2 , p) "`n" . nthRoot(0.5, 7 , p) "`n" nthRoot(n, A, p) {  x1 := A x2 := A / n While Abs(x1 - x2) > p { x1 := x2 x2 := ((n-1)*x2+A/x2**(n-1)...
public static double nthroot(int n, double A) { return nthroot(n, A, .001); } public static double nthroot(int n, double A, double p) { if(A < 0) { System.err.println("A < 0"); return -1; } else if(A == 0) { return 0; } double x_prev = A; double x = A / n; while(Math.abs(x - x_prev) > p) { x_prev = x; ...
Convert this AutoHotKey block to Python, preserving its control flow and logic.
p := 0.000001 MsgBox, % nthRoot( 10, 7131.5**10, p) "`n" . nthRoot( 5, 34.0 , p) "`n" . nthRoot( 2, 2 , p) "`n" . nthRoot(0.5, 7 , p) "`n" nthRoot(n, A, p) {  x1 := A x2 := A / n While Abs(x1 - x2) > p { x1 := x2 x2 := ((n-1)*x2+A/x2**(n-1)...
from decimal import Decimal, getcontext def nthroot (n, A, precision): getcontext().prec = precision n = Decimal(n) x_0 = A / n x_1 = 1 while True: x_0, x_1 = x_1, (1 / n)*((n - 1)*x_0 + (A / (x_0 ** (n - 1)))) if x_0 == x_1: return x_1
Rewrite this program in VB while keeping its functionality equivalent to the AutoHotKey version.
p := 0.000001 MsgBox, % nthRoot( 10, 7131.5**10, p) "`n" . nthRoot( 5, 34.0 , p) "`n" . nthRoot( 2, 2 , p) "`n" . nthRoot(0.5, 7 , p) "`n" nthRoot(n, A, p) {  x1 := A x2 := A / n While Abs(x1 - x2) > p { x1 := x2 x2 := ((n-1)*x2+A/x2**(n-1)...
Private Function nth_root(y As Double, n As Double) Dim eps As Double: eps = 0.00000000000001 Dim x As Variant: x = 1 Do While True d = (y / x ^ (n - 1) - x) / n x = x + d e = eps * x If d > -e And d < e Then Exit Do End If Loop Debug.Print y; n;...
Convert this AutoHotKey block to Go, preserving its control flow and logic.
p := 0.000001 MsgBox, % nthRoot( 10, 7131.5**10, p) "`n" . nthRoot( 5, 34.0 , p) "`n" . nthRoot( 2, 2 , p) "`n" . nthRoot(0.5, 7 , p) "`n" nthRoot(n, A, p) {  x1 := A x2 := A / n While Abs(x1 - x2) > p { x1 := x2 x2 := ((n-1)*x2+A/x2**(n-1)...
func root(a float64, n int) float64 { n1 := n - 1 n1f, rn := float64(n1), 1/float64(n) x, x0 := 1., 0. for { potx, t2 := 1/x, a for b := n1; b > 0; b >>= 1 { if b&1 == 1 { t2 *= potx } potx *= potx } x0, x = x, rn*(n1f*x...
Convert this AWK block to C, preserving its control flow and logic.
BEGIN { print nthroot(8,3) print nthroot(16,2) print nthroot(16,4) print nthroot(125,3) print nthroot(3,3) print nthroot(3,2) } function nthroot(y,n) { eps = 1e-15; x = 1; do { d = ( y / ( x^(n-1) ) - x ) / n ; x += d; e = eps*x; } while ( d < -e || d > e ) return ...
#include <stdio.h> #include <float.h> double pow_ (double x, int e) { int i; double r = 1; for (i = 0; i < e; i++) { r *= x; } return r; } double root (int n, double x) { double d, r = 1; if (!x) { return 0; } if (n < 1 || (x < 0 && !(n&1))) { return 0.0 / 0...
Rewrite the snippet below in C# so it works the same as the original AWK code.
BEGIN { print nthroot(8,3) print nthroot(16,2) print nthroot(16,4) print nthroot(125,3) print nthroot(3,3) print nthroot(3,2) } function nthroot(y,n) { eps = 1e-15; x = 1; do { d = ( y / ( x^(n-1) ) - x ) / n ; x += d; e = eps*x; } while ( d < -e || d > e ) return ...
static void Main(string[] args) { Console.WriteLine(NthRoot(81,2,.001)); Console.WriteLine(NthRoot(1000,3,.001)); Console.ReadLine(); } public static double NthRoot(double A,int n, double p) { double _n= (double) n; double[] x = new double[2]; x[0] = A; x[1] = A/_n; while(Math.Abs(x[0] -x[1] )...
Convert this AWK snippet to C++ and keep its semantics consistent.
BEGIN { print nthroot(8,3) print nthroot(16,2) print nthroot(16,4) print nthroot(125,3) print nthroot(3,3) print nthroot(3,2) } function nthroot(y,n) { eps = 1e-15; x = 1; do { d = ( y / ( x^(n-1) ) - x ) / n ; x += d; e = eps*x; } while ( d < -e || d > e ) return ...
double NthRoot(double m_nValue, double index, double guess, double pc) { double result = guess; double result_next; do { result_next = (1.0/index)*((index-1.0)*result+(m_nValue)/(pow(result,(index-1.0)))); result = result_next; pc--; }while(pc>1); ...
Convert this AWK block to Java, preserving its control flow and logic.
BEGIN { print nthroot(8,3) print nthroot(16,2) print nthroot(16,4) print nthroot(125,3) print nthroot(3,3) print nthroot(3,2) } function nthroot(y,n) { eps = 1e-15; x = 1; do { d = ( y / ( x^(n-1) ) - x ) / n ; x += d; e = eps*x; } while ( d < -e || d > e ) return ...
public static double nthroot(int n, double A) { return nthroot(n, A, .001); } public static double nthroot(int n, double A, double p) { if(A < 0) { System.err.println("A < 0"); return -1; } else if(A == 0) { return 0; } double x_prev = A; double x = A / n; while(Math.abs(x - x_prev) > p) { x_prev = x; ...
Generate a Python translation of this AWK snippet without changing its computational steps.
BEGIN { print nthroot(8,3) print nthroot(16,2) print nthroot(16,4) print nthroot(125,3) print nthroot(3,3) print nthroot(3,2) } function nthroot(y,n) { eps = 1e-15; x = 1; do { d = ( y / ( x^(n-1) ) - x ) / n ; x += d; e = eps*x; } while ( d < -e || d > e ) return ...
from decimal import Decimal, getcontext def nthroot (n, A, precision): getcontext().prec = precision n = Decimal(n) x_0 = A / n x_1 = 1 while True: x_0, x_1 = x_1, (1 / n)*((n - 1)*x_0 + (A / (x_0 ** (n - 1)))) if x_0 == x_1: return x_1
Produce a language-to-language conversion: from AWK to VB, same semantics.
BEGIN { print nthroot(8,3) print nthroot(16,2) print nthroot(16,4) print nthroot(125,3) print nthroot(3,3) print nthroot(3,2) } function nthroot(y,n) { eps = 1e-15; x = 1; do { d = ( y / ( x^(n-1) ) - x ) / n ; x += d; e = eps*x; } while ( d < -e || d > e ) return ...
Private Function nth_root(y As Double, n As Double) Dim eps As Double: eps = 0.00000000000001 Dim x As Variant: x = 1 Do While True d = (y / x ^ (n - 1) - x) / n x = x + d e = eps * x If d > -e And d < e Then Exit Do End If Loop Debug.Print y; n;...
Translate the given AWK code snippet into Go without altering its behavior.
BEGIN { print nthroot(8,3) print nthroot(16,2) print nthroot(16,4) print nthroot(125,3) print nthroot(3,3) print nthroot(3,2) } function nthroot(y,n) { eps = 1e-15; x = 1; do { d = ( y / ( x^(n-1) ) - x ) / n ; x += d; e = eps*x; } while ( d < -e || d > e ) return ...
func root(a float64, n int) float64 { n1 := n - 1 n1f, rn := float64(n1), 1/float64(n) x, x0 := 1., 0. for { potx, t2 := 1/x, a for b := n1; b > 0; b >>= 1 { if b&1 == 1 { t2 *= potx } potx *= potx } x0, x = x, rn*(n1f*x...
Translate this program into C but keep the logic exactly as in BBC_Basic.
*FLOAT 64 @% = &D0D PRINT "Cube root of 5 is "; FNroot(3, 5, 0) PRINT "125th root of 5643 is "; FNroot(125, 5643, 0) END DEF FNroot(n%, a, d) LOCAL x0, x1 : x0 = a / n% : REPEAT x1 = ((n% - 1)*x0 + a/x0^(n%-1)) / n% SWAP x0, x1 UNTIL ABS (x0 ...
#include <stdio.h> #include <float.h> double pow_ (double x, int e) { int i; double r = 1; for (i = 0; i < e; i++) { r *= x; } return r; } double root (int n, double x) { double d, r = 1; if (!x) { return 0; } if (n < 1 || (x < 0 && !(n&1))) { return 0.0 / 0...
Rewrite the snippet below in C# so it works the same as the original BBC_Basic code.
*FLOAT 64 @% = &D0D PRINT "Cube root of 5 is "; FNroot(3, 5, 0) PRINT "125th root of 5643 is "; FNroot(125, 5643, 0) END DEF FNroot(n%, a, d) LOCAL x0, x1 : x0 = a / n% : REPEAT x1 = ((n% - 1)*x0 + a/x0^(n%-1)) / n% SWAP x0, x1 UNTIL ABS (x0 ...
static void Main(string[] args) { Console.WriteLine(NthRoot(81,2,.001)); Console.WriteLine(NthRoot(1000,3,.001)); Console.ReadLine(); } public static double NthRoot(double A,int n, double p) { double _n= (double) n; double[] x = new double[2]; x[0] = A; x[1] = A/_n; while(Math.Abs(x[0] -x[1] )...
Preserve the algorithm and functionality while converting the code from BBC_Basic to C++.
*FLOAT 64 @% = &D0D PRINT "Cube root of 5 is "; FNroot(3, 5, 0) PRINT "125th root of 5643 is "; FNroot(125, 5643, 0) END DEF FNroot(n%, a, d) LOCAL x0, x1 : x0 = a / n% : REPEAT x1 = ((n% - 1)*x0 + a/x0^(n%-1)) / n% SWAP x0, x1 UNTIL ABS (x0 ...
double NthRoot(double m_nValue, double index, double guess, double pc) { double result = guess; double result_next; do { result_next = (1.0/index)*((index-1.0)*result+(m_nValue)/(pow(result,(index-1.0)))); result = result_next; pc--; }while(pc>1); ...
Port the following code from BBC_Basic to Java with equivalent syntax and logic.
*FLOAT 64 @% = &D0D PRINT "Cube root of 5 is "; FNroot(3, 5, 0) PRINT "125th root of 5643 is "; FNroot(125, 5643, 0) END DEF FNroot(n%, a, d) LOCAL x0, x1 : x0 = a / n% : REPEAT x1 = ((n% - 1)*x0 + a/x0^(n%-1)) / n% SWAP x0, x1 UNTIL ABS (x0 ...
public static double nthroot(int n, double A) { return nthroot(n, A, .001); } public static double nthroot(int n, double A, double p) { if(A < 0) { System.err.println("A < 0"); return -1; } else if(A == 0) { return 0; } double x_prev = A; double x = A / n; while(Math.abs(x - x_prev) > p) { x_prev = x; ...
Translate this program into Python but keep the logic exactly as in BBC_Basic.
*FLOAT 64 @% = &D0D PRINT "Cube root of 5 is "; FNroot(3, 5, 0) PRINT "125th root of 5643 is "; FNroot(125, 5643, 0) END DEF FNroot(n%, a, d) LOCAL x0, x1 : x0 = a / n% : REPEAT x1 = ((n% - 1)*x0 + a/x0^(n%-1)) / n% SWAP x0, x1 UNTIL ABS (x0 ...
from decimal import Decimal, getcontext def nthroot (n, A, precision): getcontext().prec = precision n = Decimal(n) x_0 = A / n x_1 = 1 while True: x_0, x_1 = x_1, (1 / n)*((n - 1)*x_0 + (A / (x_0 ** (n - 1)))) if x_0 == x_1: return x_1
Port the provided BBC_Basic code into VB while preserving the original functionality.
*FLOAT 64 @% = &D0D PRINT "Cube root of 5 is "; FNroot(3, 5, 0) PRINT "125th root of 5643 is "; FNroot(125, 5643, 0) END DEF FNroot(n%, a, d) LOCAL x0, x1 : x0 = a / n% : REPEAT x1 = ((n% - 1)*x0 + a/x0^(n%-1)) / n% SWAP x0, x1 UNTIL ABS (x0 ...
Private Function nth_root(y As Double, n As Double) Dim eps As Double: eps = 0.00000000000001 Dim x As Variant: x = 1 Do While True d = (y / x ^ (n - 1) - x) / n x = x + d e = eps * x If d > -e And d < e Then Exit Do End If Loop Debug.Print y; n;...
Translate the given BBC_Basic code snippet into Go without altering its behavior.
*FLOAT 64 @% = &D0D PRINT "Cube root of 5 is "; FNroot(3, 5, 0) PRINT "125th root of 5643 is "; FNroot(125, 5643, 0) END DEF FNroot(n%, a, d) LOCAL x0, x1 : x0 = a / n% : REPEAT x1 = ((n% - 1)*x0 + a/x0^(n%-1)) / n% SWAP x0, x1 UNTIL ABS (x0 ...
func root(a float64, n int) float64 { n1 := n - 1 n1f, rn := float64(n1), 1/float64(n) x, x0 := 1., 0. for { potx, t2 := 1/x, a for b := n1; b > 0; b >>= 1 { if b&1 == 1 { t2 *= potx } potx *= potx } x0, x = x, rn*(n1f*x...
Produce a language-to-language conversion: from Clojure to C, same semantics.
(ns test-project-intellij.core (:gen-class)) (defn abs [x] " Absolute value" (if (< x 0) (- x) x)) (defn power [x n] " x to power n, where n = 0, 1, 2, ... " (apply * (repeat n x))) (defn calc-delta [A x n] " nth rooth algorithm delta calculation " (/ (- (/ A (power x (- n 1))) x) n)) (defn nth-root ...
#include <stdio.h> #include <float.h> double pow_ (double x, int e) { int i; double r = 1; for (i = 0; i < e; i++) { r *= x; } return r; } double root (int n, double x) { double d, r = 1; if (!x) { return 0; } if (n < 1 || (x < 0 && !(n&1))) { return 0.0 / 0...
Convert this Clojure snippet to C# and keep its semantics consistent.
(ns test-project-intellij.core (:gen-class)) (defn abs [x] " Absolute value" (if (< x 0) (- x) x)) (defn power [x n] " x to power n, where n = 0, 1, 2, ... " (apply * (repeat n x))) (defn calc-delta [A x n] " nth rooth algorithm delta calculation " (/ (- (/ A (power x (- n 1))) x) n)) (defn nth-root ...
static void Main(string[] args) { Console.WriteLine(NthRoot(81,2,.001)); Console.WriteLine(NthRoot(1000,3,.001)); Console.ReadLine(); } public static double NthRoot(double A,int n, double p) { double _n= (double) n; double[] x = new double[2]; x[0] = A; x[1] = A/_n; while(Math.Abs(x[0] -x[1] )...
Generate a C++ translation of this Clojure snippet without changing its computational steps.
(ns test-project-intellij.core (:gen-class)) (defn abs [x] " Absolute value" (if (< x 0) (- x) x)) (defn power [x n] " x to power n, where n = 0, 1, 2, ... " (apply * (repeat n x))) (defn calc-delta [A x n] " nth rooth algorithm delta calculation " (/ (- (/ A (power x (- n 1))) x) n)) (defn nth-root ...
double NthRoot(double m_nValue, double index, double guess, double pc) { double result = guess; double result_next; do { result_next = (1.0/index)*((index-1.0)*result+(m_nValue)/(pow(result,(index-1.0)))); result = result_next; pc--; }while(pc>1); ...
Generate an equivalent Java version of this Clojure code.
(ns test-project-intellij.core (:gen-class)) (defn abs [x] " Absolute value" (if (< x 0) (- x) x)) (defn power [x n] " x to power n, where n = 0, 1, 2, ... " (apply * (repeat n x))) (defn calc-delta [A x n] " nth rooth algorithm delta calculation " (/ (- (/ A (power x (- n 1))) x) n)) (defn nth-root ...
public static double nthroot(int n, double A) { return nthroot(n, A, .001); } public static double nthroot(int n, double A, double p) { if(A < 0) { System.err.println("A < 0"); return -1; } else if(A == 0) { return 0; } double x_prev = A; double x = A / n; while(Math.abs(x - x_prev) > p) { x_prev = x; ...
Ensure the translated Python code behaves exactly like the original Clojure snippet.
(ns test-project-intellij.core (:gen-class)) (defn abs [x] " Absolute value" (if (< x 0) (- x) x)) (defn power [x n] " x to power n, where n = 0, 1, 2, ... " (apply * (repeat n x))) (defn calc-delta [A x n] " nth rooth algorithm delta calculation " (/ (- (/ A (power x (- n 1))) x) n)) (defn nth-root ...
from decimal import Decimal, getcontext def nthroot (n, A, precision): getcontext().prec = precision n = Decimal(n) x_0 = A / n x_1 = 1 while True: x_0, x_1 = x_1, (1 / n)*((n - 1)*x_0 + (A / (x_0 ** (n - 1)))) if x_0 == x_1: return x_1
Write the same code in VB as shown below in Clojure.
(ns test-project-intellij.core (:gen-class)) (defn abs [x] " Absolute value" (if (< x 0) (- x) x)) (defn power [x n] " x to power n, where n = 0, 1, 2, ... " (apply * (repeat n x))) (defn calc-delta [A x n] " nth rooth algorithm delta calculation " (/ (- (/ A (power x (- n 1))) x) n)) (defn nth-root ...
Private Function nth_root(y As Double, n As Double) Dim eps As Double: eps = 0.00000000000001 Dim x As Variant: x = 1 Do While True d = (y / x ^ (n - 1) - x) / n x = x + d e = eps * x If d > -e And d < e Then Exit Do End If Loop Debug.Print y; n;...
Produce a language-to-language conversion: from Clojure to Go, same semantics.
(ns test-project-intellij.core (:gen-class)) (defn abs [x] " Absolute value" (if (< x 0) (- x) x)) (defn power [x n] " x to power n, where n = 0, 1, 2, ... " (apply * (repeat n x))) (defn calc-delta [A x n] " nth rooth algorithm delta calculation " (/ (- (/ A (power x (- n 1))) x) n)) (defn nth-root ...
func root(a float64, n int) float64 { n1 := n - 1 n1f, rn := float64(n1), 1/float64(n) x, x0 := 1., 0. for { potx, t2 := 1/x, a for b := n1; b > 0; b >>= 1 { if b&1 == 1 { t2 *= potx } potx *= potx } x0, x = x, rn*(n1f*x...
Write a version of this Common_Lisp function in C with identical behavior.
(defun nth-root (n a &optional (epsilon .0001) (guess (1- n))) (assert (and (> n 1) (> a 0))) (flet ((next (x) (/ (+ (* (1- n) x) (/ a (expt x (1- n)))) n))) (do* ((xi guess xi+1) (xi+1 (next xi) (next xi))) ((< (abs (- xi+1 xi)) epsilon) xi+1))))
#include <stdio.h> #include <float.h> double pow_ (double x, int e) { int i; double r = 1; for (i = 0; i < e; i++) { r *= x; } return r; } double root (int n, double x) { double d, r = 1; if (!x) { return 0; } if (n < 1 || (x < 0 && !(n&1))) { return 0.0 / 0...
Translate the given Common_Lisp code snippet into C# without altering its behavior.
(defun nth-root (n a &optional (epsilon .0001) (guess (1- n))) (assert (and (> n 1) (> a 0))) (flet ((next (x) (/ (+ (* (1- n) x) (/ a (expt x (1- n)))) n))) (do* ((xi guess xi+1) (xi+1 (next xi) (next xi))) ((< (abs (- xi+1 xi)) epsilon) xi+1))))
static void Main(string[] args) { Console.WriteLine(NthRoot(81,2,.001)); Console.WriteLine(NthRoot(1000,3,.001)); Console.ReadLine(); } public static double NthRoot(double A,int n, double p) { double _n= (double) n; double[] x = new double[2]; x[0] = A; x[1] = A/_n; while(Math.Abs(x[0] -x[1] )...
Convert this Common_Lisp block to C++, preserving its control flow and logic.
(defun nth-root (n a &optional (epsilon .0001) (guess (1- n))) (assert (and (> n 1) (> a 0))) (flet ((next (x) (/ (+ (* (1- n) x) (/ a (expt x (1- n)))) n))) (do* ((xi guess xi+1) (xi+1 (next xi) (next xi))) ((< (abs (- xi+1 xi)) epsilon) xi+1))))
double NthRoot(double m_nValue, double index, double guess, double pc) { double result = guess; double result_next; do { result_next = (1.0/index)*((index-1.0)*result+(m_nValue)/(pow(result,(index-1.0)))); result = result_next; pc--; }while(pc>1); ...
Convert the following code from Common_Lisp to Java, ensuring the logic remains intact.
(defun nth-root (n a &optional (epsilon .0001) (guess (1- n))) (assert (and (> n 1) (> a 0))) (flet ((next (x) (/ (+ (* (1- n) x) (/ a (expt x (1- n)))) n))) (do* ((xi guess xi+1) (xi+1 (next xi) (next xi))) ((< (abs (- xi+1 xi)) epsilon) xi+1))))
public static double nthroot(int n, double A) { return nthroot(n, A, .001); } public static double nthroot(int n, double A, double p) { if(A < 0) { System.err.println("A < 0"); return -1; } else if(A == 0) { return 0; } double x_prev = A; double x = A / n; while(Math.abs(x - x_prev) > p) { x_prev = x; ...
Change the programming language of this snippet from Common_Lisp to Python without modifying what it does.
(defun nth-root (n a &optional (epsilon .0001) (guess (1- n))) (assert (and (> n 1) (> a 0))) (flet ((next (x) (/ (+ (* (1- n) x) (/ a (expt x (1- n)))) n))) (do* ((xi guess xi+1) (xi+1 (next xi) (next xi))) ((< (abs (- xi+1 xi)) epsilon) xi+1))))
from decimal import Decimal, getcontext def nthroot (n, A, precision): getcontext().prec = precision n = Decimal(n) x_0 = A / n x_1 = 1 while True: x_0, x_1 = x_1, (1 / n)*((n - 1)*x_0 + (A / (x_0 ** (n - 1)))) if x_0 == x_1: return x_1
Convert the following code from Common_Lisp to VB, ensuring the logic remains intact.
(defun nth-root (n a &optional (epsilon .0001) (guess (1- n))) (assert (and (> n 1) (> a 0))) (flet ((next (x) (/ (+ (* (1- n) x) (/ a (expt x (1- n)))) n))) (do* ((xi guess xi+1) (xi+1 (next xi) (next xi))) ((< (abs (- xi+1 xi)) epsilon) xi+1))))
Private Function nth_root(y As Double, n As Double) Dim eps As Double: eps = 0.00000000000001 Dim x As Variant: x = 1 Do While True d = (y / x ^ (n - 1) - x) / n x = x + d e = eps * x If d > -e And d < e Then Exit Do End If Loop Debug.Print y; n;...
Write a version of this Common_Lisp function in Go with identical behavior.
(defun nth-root (n a &optional (epsilon .0001) (guess (1- n))) (assert (and (> n 1) (> a 0))) (flet ((next (x) (/ (+ (* (1- n) x) (/ a (expt x (1- n)))) n))) (do* ((xi guess xi+1) (xi+1 (next xi) (next xi))) ((< (abs (- xi+1 xi)) epsilon) xi+1))))
func root(a float64, n int) float64 { n1 := n - 1 n1f, rn := float64(n1), 1/float64(n) x, x0 := 1., 0. for { potx, t2 := 1/x, a for b := n1; b > 0; b >>= 1 { if b&1 == 1 { t2 *= potx } potx *= potx } x0, x = x, rn*(n1f*x...
Please provide an equivalent version of this D code in C.
import std.stdio, std.math; real nthroot(in int n, in real A, in real p=0.001) pure nothrow { real[2] x = [A, A / n]; while (abs(x[1] - x[0]) > p) x = [x[1], ((n - 1) * x[1] + A / (x[1] ^^ (n-1))) / n]; return x[1]; } void main() { writeln(nthroot(10, 7131.5 ^^ 10)); writeln(nthroot(6, 64)...
#include <stdio.h> #include <float.h> double pow_ (double x, int e) { int i; double r = 1; for (i = 0; i < e; i++) { r *= x; } return r; } double root (int n, double x) { double d, r = 1; if (!x) { return 0; } if (n < 1 || (x < 0 && !(n&1))) { return 0.0 / 0...
Change the programming language of this snippet from D to C# without modifying what it does.
import std.stdio, std.math; real nthroot(in int n, in real A, in real p=0.001) pure nothrow { real[2] x = [A, A / n]; while (abs(x[1] - x[0]) > p) x = [x[1], ((n - 1) * x[1] + A / (x[1] ^^ (n-1))) / n]; return x[1]; } void main() { writeln(nthroot(10, 7131.5 ^^ 10)); writeln(nthroot(6, 64)...
static void Main(string[] args) { Console.WriteLine(NthRoot(81,2,.001)); Console.WriteLine(NthRoot(1000,3,.001)); Console.ReadLine(); } public static double NthRoot(double A,int n, double p) { double _n= (double) n; double[] x = new double[2]; x[0] = A; x[1] = A/_n; while(Math.Abs(x[0] -x[1] )...
Preserve the algorithm and functionality while converting the code from D to C++.
import std.stdio, std.math; real nthroot(in int n, in real A, in real p=0.001) pure nothrow { real[2] x = [A, A / n]; while (abs(x[1] - x[0]) > p) x = [x[1], ((n - 1) * x[1] + A / (x[1] ^^ (n-1))) / n]; return x[1]; } void main() { writeln(nthroot(10, 7131.5 ^^ 10)); writeln(nthroot(6, 64)...
double NthRoot(double m_nValue, double index, double guess, double pc) { double result = guess; double result_next; do { result_next = (1.0/index)*((index-1.0)*result+(m_nValue)/(pow(result,(index-1.0)))); result = result_next; pc--; }while(pc>1); ...
Keep all operations the same but rewrite the snippet in Java.
import std.stdio, std.math; real nthroot(in int n, in real A, in real p=0.001) pure nothrow { real[2] x = [A, A / n]; while (abs(x[1] - x[0]) > p) x = [x[1], ((n - 1) * x[1] + A / (x[1] ^^ (n-1))) / n]; return x[1]; } void main() { writeln(nthroot(10, 7131.5 ^^ 10)); writeln(nthroot(6, 64)...
public static double nthroot(int n, double A) { return nthroot(n, A, .001); } public static double nthroot(int n, double A, double p) { if(A < 0) { System.err.println("A < 0"); return -1; } else if(A == 0) { return 0; } double x_prev = A; double x = A / n; while(Math.abs(x - x_prev) > p) { x_prev = x; ...
Produce a functionally identical Python code for the snippet given in D.
import std.stdio, std.math; real nthroot(in int n, in real A, in real p=0.001) pure nothrow { real[2] x = [A, A / n]; while (abs(x[1] - x[0]) > p) x = [x[1], ((n - 1) * x[1] + A / (x[1] ^^ (n-1))) / n]; return x[1]; } void main() { writeln(nthroot(10, 7131.5 ^^ 10)); writeln(nthroot(6, 64)...
from decimal import Decimal, getcontext def nthroot (n, A, precision): getcontext().prec = precision n = Decimal(n) x_0 = A / n x_1 = 1 while True: x_0, x_1 = x_1, (1 / n)*((n - 1)*x_0 + (A / (x_0 ** (n - 1)))) if x_0 == x_1: return x_1
Can you help me rewrite this code in VB instead of D, keeping it the same logically?
import std.stdio, std.math; real nthroot(in int n, in real A, in real p=0.001) pure nothrow { real[2] x = [A, A / n]; while (abs(x[1] - x[0]) > p) x = [x[1], ((n - 1) * x[1] + A / (x[1] ^^ (n-1))) / n]; return x[1]; } void main() { writeln(nthroot(10, 7131.5 ^^ 10)); writeln(nthroot(6, 64)...
Private Function nth_root(y As Double, n As Double) Dim eps As Double: eps = 0.00000000000001 Dim x As Variant: x = 1 Do While True d = (y / x ^ (n - 1) - x) / n x = x + d e = eps * x If d > -e And d < e Then Exit Do End If Loop Debug.Print y; n;...
Write the same code in Go as shown below in D.
import std.stdio, std.math; real nthroot(in int n, in real A, in real p=0.001) pure nothrow { real[2] x = [A, A / n]; while (abs(x[1] - x[0]) > p) x = [x[1], ((n - 1) * x[1] + A / (x[1] ^^ (n-1))) / n]; return x[1]; } void main() { writeln(nthroot(10, 7131.5 ^^ 10)); writeln(nthroot(6, 64)...
func root(a float64, n int) float64 { n1 := n - 1 n1f, rn := float64(n1), 1/float64(n) x, x0 := 1., 0. for { potx, t2 := 1/x, a for b := n1; b > 0; b >>= 1 { if b&1 == 1 { t2 *= potx } potx *= potx } x0, x = x, rn*(n1f*x...
Transform the following Delphi implementation into C, maintaining the same output and logic.
USES Math; function NthRoot(A, Precision: Double; n: Integer): Double; var x_p, X: Double; begin x_p := Sqrt(A); while Abs(A - Power(x_p, n)) > Precision do begin x := (1/n) * (((n-1) * x_p) + (A/(Power(x_p, n - 1)))); x_p := x; end; Result := x_p; end;
#include <stdio.h> #include <float.h> double pow_ (double x, int e) { int i; double r = 1; for (i = 0; i < e; i++) { r *= x; } return r; } double root (int n, double x) { double d, r = 1; if (!x) { return 0; } if (n < 1 || (x < 0 && !(n&1))) { return 0.0 / 0...
Change the following Delphi code into C# without altering its purpose.
USES Math; function NthRoot(A, Precision: Double; n: Integer): Double; var x_p, X: Double; begin x_p := Sqrt(A); while Abs(A - Power(x_p, n)) > Precision do begin x := (1/n) * (((n-1) * x_p) + (A/(Power(x_p, n - 1)))); x_p := x; end; Result := x_p; end;
static void Main(string[] args) { Console.WriteLine(NthRoot(81,2,.001)); Console.WriteLine(NthRoot(1000,3,.001)); Console.ReadLine(); } public static double NthRoot(double A,int n, double p) { double _n= (double) n; double[] x = new double[2]; x[0] = A; x[1] = A/_n; while(Math.Abs(x[0] -x[1] )...
Generate a C++ translation of this Delphi snippet without changing its computational steps.
USES Math; function NthRoot(A, Precision: Double; n: Integer): Double; var x_p, X: Double; begin x_p := Sqrt(A); while Abs(A - Power(x_p, n)) > Precision do begin x := (1/n) * (((n-1) * x_p) + (A/(Power(x_p, n - 1)))); x_p := x; end; Result := x_p; end;
double NthRoot(double m_nValue, double index, double guess, double pc) { double result = guess; double result_next; do { result_next = (1.0/index)*((index-1.0)*result+(m_nValue)/(pow(result,(index-1.0)))); result = result_next; pc--; }while(pc>1); ...
Produce a functionally identical Java code for the snippet given in Delphi.
USES Math; function NthRoot(A, Precision: Double; n: Integer): Double; var x_p, X: Double; begin x_p := Sqrt(A); while Abs(A - Power(x_p, n)) > Precision do begin x := (1/n) * (((n-1) * x_p) + (A/(Power(x_p, n - 1)))); x_p := x; end; Result := x_p; end;
public static double nthroot(int n, double A) { return nthroot(n, A, .001); } public static double nthroot(int n, double A, double p) { if(A < 0) { System.err.println("A < 0"); return -1; } else if(A == 0) { return 0; } double x_prev = A; double x = A / n; while(Math.abs(x - x_prev) > p) { x_prev = x; ...
Write the same code in Python as shown below in Delphi.
USES Math; function NthRoot(A, Precision: Double; n: Integer): Double; var x_p, X: Double; begin x_p := Sqrt(A); while Abs(A - Power(x_p, n)) > Precision do begin x := (1/n) * (((n-1) * x_p) + (A/(Power(x_p, n - 1)))); x_p := x; end; Result := x_p; end;
from decimal import Decimal, getcontext def nthroot (n, A, precision): getcontext().prec = precision n = Decimal(n) x_0 = A / n x_1 = 1 while True: x_0, x_1 = x_1, (1 / n)*((n - 1)*x_0 + (A / (x_0 ** (n - 1)))) if x_0 == x_1: return x_1
Translate this program into VB but keep the logic exactly as in Delphi.
USES Math; function NthRoot(A, Precision: Double; n: Integer): Double; var x_p, X: Double; begin x_p := Sqrt(A); while Abs(A - Power(x_p, n)) > Precision do begin x := (1/n) * (((n-1) * x_p) + (A/(Power(x_p, n - 1)))); x_p := x; end; Result := x_p; end;
Private Function nth_root(y As Double, n As Double) Dim eps As Double: eps = 0.00000000000001 Dim x As Variant: x = 1 Do While True d = (y / x ^ (n - 1) - x) / n x = x + d e = eps * x If d > -e And d < e Then Exit Do End If Loop Debug.Print y; n;...
Generate an equivalent Go version of this Delphi code.
USES Math; function NthRoot(A, Precision: Double; n: Integer): Double; var x_p, X: Double; begin x_p := Sqrt(A); while Abs(A - Power(x_p, n)) > Precision do begin x := (1/n) * (((n-1) * x_p) + (A/(Power(x_p, n - 1)))); x_p := x; end; Result := x_p; end;
func root(a float64, n int) float64 { n1 := n - 1 n1f, rn := float64(n1), 1/float64(n) x, x0 := 1., 0. for { potx, t2 := 1/x, a for b := n1; b > 0; b >>= 1 { if b&1 == 1 { t2 *= potx } potx *= potx } x0, x = x, rn*(n1f*x...
Port the provided Elixir code into C while preserving the original functionality.
defmodule RC do def nth_root(n, x, precision \\ 1.0e-5) do f = fn(prev) -> ((n - 1) * prev + x / :math.pow(prev, (n-1))) / n end fixed_point(f, x, precision, f.(x)) end defp fixed_point(_, guess, tolerance, next) when abs(guess - next) < tolerance, do: next defp fixed_point(f, _, tolerance, next), do...
#include <stdio.h> #include <float.h> double pow_ (double x, int e) { int i; double r = 1; for (i = 0; i < e; i++) { r *= x; } return r; } double root (int n, double x) { double d, r = 1; if (!x) { return 0; } if (n < 1 || (x < 0 && !(n&1))) { return 0.0 / 0...
Generate a C# translation of this Elixir snippet without changing its computational steps.
defmodule RC do def nth_root(n, x, precision \\ 1.0e-5) do f = fn(prev) -> ((n - 1) * prev + x / :math.pow(prev, (n-1))) / n end fixed_point(f, x, precision, f.(x)) end defp fixed_point(_, guess, tolerance, next) when abs(guess - next) < tolerance, do: next defp fixed_point(f, _, tolerance, next), do...
static void Main(string[] args) { Console.WriteLine(NthRoot(81,2,.001)); Console.WriteLine(NthRoot(1000,3,.001)); Console.ReadLine(); } public static double NthRoot(double A,int n, double p) { double _n= (double) n; double[] x = new double[2]; x[0] = A; x[1] = A/_n; while(Math.Abs(x[0] -x[1] )...
Convert the following code from Elixir to C++, ensuring the logic remains intact.
defmodule RC do def nth_root(n, x, precision \\ 1.0e-5) do f = fn(prev) -> ((n - 1) * prev + x / :math.pow(prev, (n-1))) / n end fixed_point(f, x, precision, f.(x)) end defp fixed_point(_, guess, tolerance, next) when abs(guess - next) < tolerance, do: next defp fixed_point(f, _, tolerance, next), do...
double NthRoot(double m_nValue, double index, double guess, double pc) { double result = guess; double result_next; do { result_next = (1.0/index)*((index-1.0)*result+(m_nValue)/(pow(result,(index-1.0)))); result = result_next; pc--; }while(pc>1); ...
Produce a functionally identical Java code for the snippet given in Elixir.
defmodule RC do def nth_root(n, x, precision \\ 1.0e-5) do f = fn(prev) -> ((n - 1) * prev + x / :math.pow(prev, (n-1))) / n end fixed_point(f, x, precision, f.(x)) end defp fixed_point(_, guess, tolerance, next) when abs(guess - next) < tolerance, do: next defp fixed_point(f, _, tolerance, next), do...
public static double nthroot(int n, double A) { return nthroot(n, A, .001); } public static double nthroot(int n, double A, double p) { if(A < 0) { System.err.println("A < 0"); return -1; } else if(A == 0) { return 0; } double x_prev = A; double x = A / n; while(Math.abs(x - x_prev) > p) { x_prev = x; ...
Generate a Python translation of this Elixir snippet without changing its computational steps.
defmodule RC do def nth_root(n, x, precision \\ 1.0e-5) do f = fn(prev) -> ((n - 1) * prev + x / :math.pow(prev, (n-1))) / n end fixed_point(f, x, precision, f.(x)) end defp fixed_point(_, guess, tolerance, next) when abs(guess - next) < tolerance, do: next defp fixed_point(f, _, tolerance, next), do...
from decimal import Decimal, getcontext def nthroot (n, A, precision): getcontext().prec = precision n = Decimal(n) x_0 = A / n x_1 = 1 while True: x_0, x_1 = x_1, (1 / n)*((n - 1)*x_0 + (A / (x_0 ** (n - 1)))) if x_0 == x_1: return x_1
Translate the given Elixir code snippet into VB without altering its behavior.
defmodule RC do def nth_root(n, x, precision \\ 1.0e-5) do f = fn(prev) -> ((n - 1) * prev + x / :math.pow(prev, (n-1))) / n end fixed_point(f, x, precision, f.(x)) end defp fixed_point(_, guess, tolerance, next) when abs(guess - next) < tolerance, do: next defp fixed_point(f, _, tolerance, next), do...
Private Function nth_root(y As Double, n As Double) Dim eps As Double: eps = 0.00000000000001 Dim x As Variant: x = 1 Do While True d = (y / x ^ (n - 1) - x) / n x = x + d e = eps * x If d > -e And d < e Then Exit Do End If Loop Debug.Print y; n;...
Convert this Elixir block to Go, preserving its control flow and logic.
defmodule RC do def nth_root(n, x, precision \\ 1.0e-5) do f = fn(prev) -> ((n - 1) * prev + x / :math.pow(prev, (n-1))) / n end fixed_point(f, x, precision, f.(x)) end defp fixed_point(_, guess, tolerance, next) when abs(guess - next) < tolerance, do: next defp fixed_point(f, _, tolerance, next), do...
func root(a float64, n int) float64 { n1 := n - 1 n1f, rn := float64(n1), 1/float64(n) x, x0 := 1., 0. for { potx, t2 := 1/x, a for b := n1; b > 0; b >>= 1 { if b&1 == 1 { t2 *= potx } potx *= potx } x0, x = x, rn*(n1f*x...
Change the programming language of this snippet from Erlang to C without modifying what it does.
fixed_point(F, Guess, Tolerance) -> fixed_point(F, Guess, Tolerance, F(Guess)). fixed_point(_, Guess, Tolerance, Next) when abs(Guess - Next) < Tolerance -> Next; fixed_point(F, _, Tolerance, Next) -> fixed_point(F, Next, Tolerance, F(Next)).
#include <stdio.h> #include <float.h> double pow_ (double x, int e) { int i; double r = 1; for (i = 0; i < e; i++) { r *= x; } return r; } double root (int n, double x) { double d, r = 1; if (!x) { return 0; } if (n < 1 || (x < 0 && !(n&1))) { return 0.0 / 0...
Rewrite this program in C# while keeping its functionality equivalent to the Erlang version.
fixed_point(F, Guess, Tolerance) -> fixed_point(F, Guess, Tolerance, F(Guess)). fixed_point(_, Guess, Tolerance, Next) when abs(Guess - Next) < Tolerance -> Next; fixed_point(F, _, Tolerance, Next) -> fixed_point(F, Next, Tolerance, F(Next)).
static void Main(string[] args) { Console.WriteLine(NthRoot(81,2,.001)); Console.WriteLine(NthRoot(1000,3,.001)); Console.ReadLine(); } public static double NthRoot(double A,int n, double p) { double _n= (double) n; double[] x = new double[2]; x[0] = A; x[1] = A/_n; while(Math.Abs(x[0] -x[1] )...
Rewrite the snippet below in C++ so it works the same as the original Erlang code.
fixed_point(F, Guess, Tolerance) -> fixed_point(F, Guess, Tolerance, F(Guess)). fixed_point(_, Guess, Tolerance, Next) when abs(Guess - Next) < Tolerance -> Next; fixed_point(F, _, Tolerance, Next) -> fixed_point(F, Next, Tolerance, F(Next)).
double NthRoot(double m_nValue, double index, double guess, double pc) { double result = guess; double result_next; do { result_next = (1.0/index)*((index-1.0)*result+(m_nValue)/(pow(result,(index-1.0)))); result = result_next; pc--; }while(pc>1); ...
Convert the following code from Erlang to Java, ensuring the logic remains intact.
fixed_point(F, Guess, Tolerance) -> fixed_point(F, Guess, Tolerance, F(Guess)). fixed_point(_, Guess, Tolerance, Next) when abs(Guess - Next) < Tolerance -> Next; fixed_point(F, _, Tolerance, Next) -> fixed_point(F, Next, Tolerance, F(Next)).
public static double nthroot(int n, double A) { return nthroot(n, A, .001); } public static double nthroot(int n, double A, double p) { if(A < 0) { System.err.println("A < 0"); return -1; } else if(A == 0) { return 0; } double x_prev = A; double x = A / n; while(Math.abs(x - x_prev) > p) { x_prev = x; ...
Maintain the same structure and functionality when rewriting this code in Python.
fixed_point(F, Guess, Tolerance) -> fixed_point(F, Guess, Tolerance, F(Guess)). fixed_point(_, Guess, Tolerance, Next) when abs(Guess - Next) < Tolerance -> Next; fixed_point(F, _, Tolerance, Next) -> fixed_point(F, Next, Tolerance, F(Next)).
from decimal import Decimal, getcontext def nthroot (n, A, precision): getcontext().prec = precision n = Decimal(n) x_0 = A / n x_1 = 1 while True: x_0, x_1 = x_1, (1 / n)*((n - 1)*x_0 + (A / (x_0 ** (n - 1)))) if x_0 == x_1: return x_1
Rewrite this program in VB while keeping its functionality equivalent to the Erlang version.
fixed_point(F, Guess, Tolerance) -> fixed_point(F, Guess, Tolerance, F(Guess)). fixed_point(_, Guess, Tolerance, Next) when abs(Guess - Next) < Tolerance -> Next; fixed_point(F, _, Tolerance, Next) -> fixed_point(F, Next, Tolerance, F(Next)).
Private Function nth_root(y As Double, n As Double) Dim eps As Double: eps = 0.00000000000001 Dim x As Variant: x = 1 Do While True d = (y / x ^ (n - 1) - x) / n x = x + d e = eps * x If d > -e And d < e Then Exit Do End If Loop Debug.Print y; n;...
Generate an equivalent Go version of this Erlang code.
fixed_point(F, Guess, Tolerance) -> fixed_point(F, Guess, Tolerance, F(Guess)). fixed_point(_, Guess, Tolerance, Next) when abs(Guess - Next) < Tolerance -> Next; fixed_point(F, _, Tolerance, Next) -> fixed_point(F, Next, Tolerance, F(Next)).
func root(a float64, n int) float64 { n1 := n - 1 n1f, rn := float64(n1), 1/float64(n) x, x0 := 1., 0. for { potx, t2 := 1/x, a for b := n1; b > 0; b >>= 1 { if b&1 == 1 { t2 *= potx } potx *= potx } x0, x = x, rn*(n1f*x...
Rewrite this program in C while keeping its functionality equivalent to the F# version.
let nthroot n A = let rec f x = let m = n - 1. let x' = (m * x + A/x**m) / n match abs(x' - x) with | t when t < abs(x * 1e-9) -> x' | _ -> f x' f (A / double n) [<EntryPoint>] let main args = if args.Length <> 2 then eprintfn "usage: nthroot n A" exi...
#include <stdio.h> #include <float.h> double pow_ (double x, int e) { int i; double r = 1; for (i = 0; i < e; i++) { r *= x; } return r; } double root (int n, double x) { double d, r = 1; if (!x) { return 0; } if (n < 1 || (x < 0 && !(n&1))) { return 0.0 / 0...
Convert this F# snippet to C# and keep its semantics consistent.
let nthroot n A = let rec f x = let m = n - 1. let x' = (m * x + A/x**m) / n match abs(x' - x) with | t when t < abs(x * 1e-9) -> x' | _ -> f x' f (A / double n) [<EntryPoint>] let main args = if args.Length <> 2 then eprintfn "usage: nthroot n A" exi...
static void Main(string[] args) { Console.WriteLine(NthRoot(81,2,.001)); Console.WriteLine(NthRoot(1000,3,.001)); Console.ReadLine(); } public static double NthRoot(double A,int n, double p) { double _n= (double) n; double[] x = new double[2]; x[0] = A; x[1] = A/_n; while(Math.Abs(x[0] -x[1] )...
Translate the given F# code snippet into C++ without altering its behavior.
let nthroot n A = let rec f x = let m = n - 1. let x' = (m * x + A/x**m) / n match abs(x' - x) with | t when t < abs(x * 1e-9) -> x' | _ -> f x' f (A / double n) [<EntryPoint>] let main args = if args.Length <> 2 then eprintfn "usage: nthroot n A" exi...
double NthRoot(double m_nValue, double index, double guess, double pc) { double result = guess; double result_next; do { result_next = (1.0/index)*((index-1.0)*result+(m_nValue)/(pow(result,(index-1.0)))); result = result_next; pc--; }while(pc>1); ...
Convert the following code from F# to Java, ensuring the logic remains intact.
let nthroot n A = let rec f x = let m = n - 1. let x' = (m * x + A/x**m) / n match abs(x' - x) with | t when t < abs(x * 1e-9) -> x' | _ -> f x' f (A / double n) [<EntryPoint>] let main args = if args.Length <> 2 then eprintfn "usage: nthroot n A" exi...
public static double nthroot(int n, double A) { return nthroot(n, A, .001); } public static double nthroot(int n, double A, double p) { if(A < 0) { System.err.println("A < 0"); return -1; } else if(A == 0) { return 0; } double x_prev = A; double x = A / n; while(Math.abs(x - x_prev) > p) { x_prev = x; ...
Generate a Python translation of this F# snippet without changing its computational steps.
let nthroot n A = let rec f x = let m = n - 1. let x' = (m * x + A/x**m) / n match abs(x' - x) with | t when t < abs(x * 1e-9) -> x' | _ -> f x' f (A / double n) [<EntryPoint>] let main args = if args.Length <> 2 then eprintfn "usage: nthroot n A" exi...
from decimal import Decimal, getcontext def nthroot (n, A, precision): getcontext().prec = precision n = Decimal(n) x_0 = A / n x_1 = 1 while True: x_0, x_1 = x_1, (1 / n)*((n - 1)*x_0 + (A / (x_0 ** (n - 1)))) if x_0 == x_1: return x_1