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Generate a PHP translation of this Groovy snippet without changing its computational steps.
def str = 'abcdefgh' def n = 2 def m = 3 println str[n..n+m-1] println str[n..<(n+m)] println str[n..-1] println str[0..-2] def index1 = str.indexOf('d') println str[index1..index1+m-1] println str[index1..<(index1+m)] def index2 = str.indexOf('de') println str[index2..index2+m-1] println str[index2..<(index2+m...
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Produce a functionally identical PHP code for the snippet given in Haskell.
t45 n c s | null sub = [] | otherwise = take n. head $ sub where sub = filter(isPrefixOf c) $ tails s
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Produce a language-to-language conversion: from Icon to PHP, same semantics.
procedure main(arglist) write("Usage: substring <string> <first position> <second position> <single character> <substring>") s := \arglist[1] | "aardvarks" n := \arglist[2] | 5 m := \arglist[3] | 4 c := \arglist[4] | "d" ss := \arglist[5] | "ard" write( s[n+:m] ) write( s[n:0] ) ...
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Generate an equivalent PHP version of this J code.
5{.3}.'Marshmallow' shmal 3}.'Marshmallow' shmallow }.'Marshmallow' arshmallow }:'Marshmallow' Marshmallo 5{.(}.~ i.&'m')'Marshmallow' mallo 5{.(}.~ I.@E.~&'sh')'Marshmallow' shmal
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Preserve the algorithm and functionality while converting the code from Julia to PHP.
julia> s = "abcdefg" "abcdefg" julia> n = 3 3 julia> s[n:end] "cdefg" julia> m=2 2 julia> s[n:n+m] "cde" julia> s[1:end-1] "abcdef" julia> s[search(s,'c')] 'c' julia> s[search(s,'c'):search(s,'c')+m] "cde"
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Rewrite this program in PHP while keeping its functionality equivalent to the Lua version.
str = "abcdefghijklmnopqrstuvwxyz" n, m = 5, 15 print( string.sub( str, n, m ) ) print( string.sub( str, n, -1 ) ) print( string.sub( str, 1, -2 ) ) pos = string.find( str, "i" ) if pos ~= nil then print( string.sub( str, pos, pos+m ) ) end pos = string.find( str, "ijk" ) if pos ~= nil then print( string....
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Write a version of this Mathematica function in PHP with identical behavior.
n = 2 m = 3 StringTake["Mathematica", {n+1, n+m-1}] StringDrop["Mathematica", n] pos = StringPosition["Mathematica", "e"][[1]][[1]] StringTake["Mathematica", {pos, pos+m-1}] pos = StringPosition["Mathematica", "the"][[1]] StringTake["Mathematica", {pos, pos+m-1}]
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Translate the given MATLAB code snippet into PHP without altering its behavior.
s(n+(1:m)) s(n+1:n+m) s(n+1:end) s(1:end-1) s(find(s==c,1)+[0:m-1]) s(strfind(s,pattern)+[0:m-1])
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Change the programming language of this snippet from Nim to PHP without modifying what it does.
import strformat, strutils, unicode let s1 = "abcdefgh" s2 = "àbĉdéfgĥ" n = 2 m = 3 c = 'd' cs1 = "de" cs2 = "dé" var pos: int echo "ASCII string: ", s1 echo &"Starting from n = {n} characters in and of m = {m} length: ", s1[(n - 1)..(n + m - 2)] echo &"Starting from n = {n} characters in, u...
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Convert this OCaml block to PHP, preserving its control flow and logic.
$ ocaml # let s = "ABCDEFGH" ;; val s : string = "ABCDEFGH" # let n, m = 2, 3 ;; val n : int = 2 val m : int = 3 # String.sub s n m ;; - : string = "CDE" # String.sub s n (String.length s - n) ;; - : string = "CDEFGH" # String.sub s 0 (String.length s - 1) ;; - : string = "ABCDEFG" # String.sub s (String.index s '...
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Maintain the same structure and functionality when rewriting this code in PHP.
s[n..n+m] s[n..high(nativeUInt)] s[1..length(s)-1] s[pos(c, s)..pos(c, s)+m] s[pos(p, s)..pos(p, s)+m]
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Convert this Perl snippet to PHP and keep its semantics consistent.
my $str = 'abcdefgh'; print substr($str, 2, 3), "\n"; print substr($str, 2), "\n"; print substr($str, 0, -1), "\n"; print substr($str, index($str, 'd'), 3), "\n"; print substr($str, index($str, 'de'), 3), "\n";
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Change the programming language of this snippet from PowerShell to PHP without modifying what it does.
$s = "abcdefgh" $n, $m, $c, $s2 = 2, 3, [char]'d', $s2 = 'cd' $s.Substring($n-1, $m) $s.Substring($n-1) $s.Substring(0, $s.Length - 1) $s.Substring($s.IndexOf($c), $m) $s.Substring($s.IndexOf($s2), $m)
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Write the same algorithm in PHP as shown in this R implementation.
s <- "abcdefgh" n <- 2; m <- 2; char <- 'd'; chars <- 'cd' substring(s, n, n + m) substring(s, n) substring(s, 1, nchar(s)-1) indx <- which(strsplit(s, '')[[1]] %in% strsplit(char, '')[[1]]) substring(s, indx, indx + m) indx <- which(strsplit(s, '')[[1]] %in% strsplit(chars, '')[[1]])[1] substring(s, indx, indx + m)
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Translate this program into PHP but keep the logic exactly as in Racket.
#lang racket (define str "abcdefghijklmnopqrstuvwxyz") (define n 10) (define m 2) (define start-char #\x) (define start-str "xy") (substring str n (+ n m)) (substring str m) (substring str 0 (sub1 (string-length str))) (substring str (caar (regexp-match-positions (regexp-quote (string start-char)) ...
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Convert the following code from COBOL to PHP, ensuring the logic remains intact.
identification division. program-id. substring. environment division. configuration section. repository. function all intrinsic. data division. working-storage section. 01 original. 05 value "this is a string". 01 starting pic 99 val...
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Rewrite the snippet below in PHP so it works the same as the original REXX code.
options replace format comments java crossref savelog symbols s = 'abcdefghijk' n = 4 m = 3 say s say s.substr(n, m) say s.substr(n) say s.substr(1, s.length - 1) say s.substr(s.pos('def'), m) say s.substr(s.pos('g'), m) return
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Port the following code from Ruby to PHP with equivalent syntax and logic.
str = 'abcdefgh' n = 2 m = 3 puts str[n, m] puts str[n..m] puts str[n..-1] puts str[0..-2] puts str[str.index('d'), m] puts str[str.index('de'), m] puts str[/a.*d/]
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Please provide an equivalent version of this Scala code in PHP.
fun main(args: Array<String>) { val s = "0123456789" val n = 3 val m = 4 val c = '5' val z = "12" var i: Int println(s.substring(n, n + m)) println(s.substring(n)) println(s.dropLast(1)) i = s.indexOf(c) println(s.substring(i, i + m)) i = s.indexOf(z) println(s.subs...
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Ensure the translated PHP code behaves exactly like the original Swift snippet.
let string = "Hello, Swift language" let (n, m) = (5, 4) do { let start = string.startIndex.advancedBy(n) let end = start.advancedBy(m) _ = string[start..<end] string.substringWithRange(start..<end) } do { _ = String( string.characters.suffix(string.characters.count - n) ) _ = string.s...
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Ensure the translated PHP code behaves exactly like the original Tcl snippet.
set str "abcdefgh" set n 2 set m 3 puts [string range $str $n [expr {$n+$m-1}]] puts [string range $str $n end] puts [string range $str 0 end-1] puts [string range [string range $str [string first "d" $str] end] [expr {$m-1}]] puts [string range [string range $str [string first "de" $str] end] [expr {$m-1}]] puts...
<?php $str = 'abcdefgh'; $n = 2; $m = 3; echo substr($str, $n, $m), "\n"; //cde echo substr($str, $n), "\n"; //cdefgh echo substr($str, 0, -1), "\n"; //abcdefg echo substr($str, strpos($str, 'd'), $m), "\n"; //def echo substr($str, strpos($str, 'de'), $m), "\n"; //def ?>
Convert the following code from C# to Rust, ensuring the logic remains intact.
using System; namespace SubString { class Program { static void Main(string[] args) { string s = "0123456789"; const int n = 3; const int m = 2; const char c = '3'; const string z = "345"; Console.WriteLine(s.S...
let s = "abc文字化けdef"; let n = 2; let m = 3; println!("{}", s.chars().skip(n).take(m).collect::<String>()); println!("{}", s.chars().skip(n).collect::<String>()); println!("{}", s.chars().rev().skip(1).collect::<String>()); let cpos = s.find('b').unwrap(); println!("{}", s[cpos..].chars().take(m)...
Generate an equivalent Rust version of this Java code.
public static String Substring(String str, int n, int m){ return str.substring(n, n+m); } public static String Substring(String str, int n){ return str.substring(n); } public static String Substring(String str){ return str.substring(0, str.length()-1); } public static String Substring(String str, char c, in...
let s = "abc文字化けdef"; let n = 2; let m = 3; println!("{}", s.chars().skip(n).take(m).collect::<String>()); println!("{}", s.chars().skip(n).collect::<String>()); println!("{}", s.chars().rev().skip(1).collect::<String>()); let cpos = s.find('b').unwrap(); println!("{}", s[cpos..].chars().take(m)...
Maintain the same structure and functionality when rewriting this code in Rust.
package main import ( "fmt" "strings" ) func main() { s := "ABCDEFGH" n, m := 2, 3 fmt.Println("Index: ", "01234567") fmt.Println("String:", s) fmt.Printf("Start %d, length %d: %s\n", n, m, s[n : n+m]) fmt.Printf("Start %d, to end: %s\n", n, s[n:]) fmt.P...
let s = "abc文字化けdef"; let n = 2; let m = 3; println!("{}", s.chars().skip(n).take(m).collect::<String>()); println!("{}", s.chars().skip(n).collect::<String>()); println!("{}", s.chars().rev().skip(1).collect::<String>()); let cpos = s.find('b').unwrap(); println!("{}", s[cpos..].chars().take(m)...
Generate a Python translation of this Rust snippet without changing its computational steps.
let s = "abc文字化けdef"; let n = 2; let m = 3; println!("{}", s.chars().skip(n).take(m).collect::<String>()); println!("{}", s.chars().skip(n).collect::<String>()); println!("{}", s.chars().rev().skip(1).collect::<String>()); let cpos = s.find('b').unwrap(); println!("{}", s[cpos..].chars().take(m)...
>>> s = 'abcdefgh' >>> n, m, char, chars = 2, 3, 'd', 'cd' >>> >>> s[n-1:n+m-1] 'bcd' >>> >>> s[n-1:] 'bcdefgh' >>> >>> s[:-1] 'abcdefg' >>> >>> indx = s.index(char) >>> s[indx:indx+m] 'def' >>> >>> indx = s.index(chars) >>> s[indx:indx+m] 'cde' >>>
Please provide an equivalent version of this Rust code in VB.
let s = "abc文字化けdef"; let n = 2; let m = 3; println!("{}", s.chars().skip(n).take(m).collect::<String>()); println!("{}", s.chars().skip(n).collect::<String>()); println!("{}", s.chars().rev().skip(1).collect::<String>()); let cpos = s.find('b').unwrap(); println!("{}", s[cpos..].chars().take(m)...
Public Sub substring() sentence = "the last thing the man said was the" n = 10: m = 5 Debug.Print Mid(sentence, n, 5) Debug.Print Right(sentence, Len(sentence) - n + 1) Debug.Print Left(sentence, Len(sentence) - 1) k = InStr(1, sentence, "m") Debug.Print Mi...
Keep all operations the same but rewrite the snippet in Rust.
#define _CRT_SECURE_NO_WARNINGS #include <stdio.h> #include <stdlib.h> #include <string.h> void putm(char* string, size_t m) { while(*string && m--) putchar(*string++); } int main(void) { char string[] = "Programs for other encodings (such as 8-bit ASCII, or EUC-JP)." int n = 3; ...
let s = "abc文字化けdef"; let n = 2; let m = 3; println!("{}", s.chars().skip(n).take(m).collect::<String>()); println!("{}", s.chars().skip(n).collect::<String>()); println!("{}", s.chars().rev().skip(1).collect::<String>()); let cpos = s.find('b').unwrap(); println!("{}", s[cpos..].chars().take(m)...
Port the following code from C++ to Rust with equivalent syntax and logic.
#include <iostream> #include <string> int main() { std::string s = "0123456789"; int const n = 3; int const m = 4; char const c = '2'; std::string const sub = "456"; std::cout << s.substr(n, m)<< "\n"; std::cout << s.substr(n) << "\n"; std::cout << s.substr(0, s.size()-1) << "\n"; std::cout << s.su...
let s = "abc文字化けdef"; let n = 2; let m = 3; println!("{}", s.chars().skip(n).take(m).collect::<String>()); println!("{}", s.chars().skip(n).collect::<String>()); println!("{}", s.chars().rev().skip(1).collect::<String>()); let cpos = s.find('b').unwrap(); println!("{}", s[cpos..].chars().take(m)...
Write the same code in C# as shown below in Ada.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Binomial is function Binomial (N, K : Natural) return Natural is Result : Natural := 1; M : Natural; begin if N < K then raise Constraint_Error; end if; if K > N/2 then M := N - K; else M := K; ...
using System; namespace BinomialCoefficients { class Program { static void Main(string[] args) { ulong n = 1000000, k = 3; ulong result = biCoefficient(n, k); Console.WriteLine("The Binomial Coefficient of {0}, and {1}, is equal to: {2}", n, k, result); ...
Keep all operations the same but rewrite the snippet in C.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Binomial is function Binomial (N, K : Natural) return Natural is Result : Natural := 1; M : Natural; begin if N < K then raise Constraint_Error; end if; if K > N/2 then M := N - K; else M := K; ...
#include <stdio.h> #include <limits.h> static unsigned long gcd_ui(unsigned long x, unsigned long y) { unsigned long t; if (y < x) { t = x; x = y; y = t; } while (y > 0) { t = y; y = x % y; x = t; } return x; } unsigned long binomial(unsigned long n, unsigned long k) { unsigned long d, g, r = 1;...
Produce a functionally identical C++ code for the snippet given in Ada.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Binomial is function Binomial (N, K : Natural) return Natural is Result : Natural := 1; M : Natural; begin if N < K then raise Constraint_Error; end if; if K > N/2 then M := N - K; else M := K; ...
double Factorial(double nValue) { double result = nValue; double result_next; double pc = nValue; do { result_next = result*(pc-1); result = result_next; pc--; }while(pc>2); nValue = result; return nValue; } double binomialC...
Produce a language-to-language conversion: from Ada to Go, same semantics.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Binomial is function Binomial (N, K : Natural) return Natural is Result : Natural := 1; M : Natural; begin if N < K then raise Constraint_Error; end if; if K > N/2 then M := N - K; else M := K; ...
package main import "fmt" import "math/big" func main() { fmt.Println(new(big.Int).Binomial(5, 3)) fmt.Println(new(big.Int).Binomial(60, 30)) }
Change the programming language of this snippet from Ada to Java without modifying what it does.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Binomial is function Binomial (N, K : Natural) return Natural is Result : Natural := 1; M : Natural; begin if N < K then raise Constraint_Error; end if; if K > N/2 then M := N - K; else M := K; ...
public class Binomial { private static long binomialInt(int n, int k) { if (k > n - k) k = n - k; long binom = 1; for (int i = 1; i <= k; i++) binom = binom * (n + 1 - i) / i; return binom; } private static Object binomialIntReliable(int n...
Change the programming language of this snippet from Ada to Python without modifying what it does.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Binomial is function Binomial (N, K : Natural) return Natural is Result : Natural := 1; M : Natural; begin if N < K then raise Constraint_Error; end if; if K > N/2 then M := N - K; else M := K; ...
def binomialCoeff(n, k): result = 1 for i in range(1, k+1): result = result * (n-i+1) / i return result if __name__ == "__main__": print(binomialCoeff(5, 3))
Change the following Ada code into VB without altering its purpose.
with Ada.Text_IO; use Ada.Text_IO; procedure Test_Binomial is function Binomial (N, K : Natural) return Natural is Result : Natural := 1; M : Natural; begin if N < K then raise Constraint_Error; end if; if K > N/2 then M := N - K; else M := K; ...
Function binomial(n,k) binomial = factorial(n)/(factorial(n-k)*factorial(k)) End Function Function factorial(n) If n = 0 Then factorial = 1 Else For i = n To 1 Step -1 If i = n Then factorial = n Else factorial = factorial * i End If Next End If End Function WScript.StdOut.Write "the binom...
Write the same code in C as shown below in Arturo.
factorial: function [n]-> product 1..n binomial: function [x,y]-> (factorial x) / (factorial y) * factorial x-y print binomial 5 3
#include <stdio.h> #include <limits.h> static unsigned long gcd_ui(unsigned long x, unsigned long y) { unsigned long t; if (y < x) { t = x; x = y; y = t; } while (y > 0) { t = y; y = x % y; x = t; } return x; } unsigned long binomial(unsigned long n, unsigned long k) { unsigned long d, g, r = 1;...
Generate a C# translation of this Arturo snippet without changing its computational steps.
factorial: function [n]-> product 1..n binomial: function [x,y]-> (factorial x) / (factorial y) * factorial x-y print binomial 5 3
using System; namespace BinomialCoefficients { class Program { static void Main(string[] args) { ulong n = 1000000, k = 3; ulong result = biCoefficient(n, k); Console.WriteLine("The Binomial Coefficient of {0}, and {1}, is equal to: {2}", n, k, result); ...
Produce a functionally identical C++ code for the snippet given in Arturo.
factorial: function [n]-> product 1..n binomial: function [x,y]-> (factorial x) / (factorial y) * factorial x-y print binomial 5 3
double Factorial(double nValue) { double result = nValue; double result_next; double pc = nValue; do { result_next = result*(pc-1); result = result_next; pc--; }while(pc>2); nValue = result; return nValue; } double binomialC...
Port the provided Arturo code into Java while preserving the original functionality.
factorial: function [n]-> product 1..n binomial: function [x,y]-> (factorial x) / (factorial y) * factorial x-y print binomial 5 3
public class Binomial { private static long binomialInt(int n, int k) { if (k > n - k) k = n - k; long binom = 1; for (int i = 1; i <= k; i++) binom = binom * (n + 1 - i) / i; return binom; } private static Object binomialIntReliable(int n...
Can you help me rewrite this code in Python instead of Arturo, keeping it the same logically?
factorial: function [n]-> product 1..n binomial: function [x,y]-> (factorial x) / (factorial y) * factorial x-y print binomial 5 3
def binomialCoeff(n, k): result = 1 for i in range(1, k+1): result = result * (n-i+1) / i return result if __name__ == "__main__": print(binomialCoeff(5, 3))
Write the same code in VB as shown below in Arturo.
factorial: function [n]-> product 1..n binomial: function [x,y]-> (factorial x) / (factorial y) * factorial x-y print binomial 5 3
Function binomial(n,k) binomial = factorial(n)/(factorial(n-k)*factorial(k)) End Function Function factorial(n) If n = 0 Then factorial = 1 Else For i = n To 1 Step -1 If i = n Then factorial = n Else factorial = factorial * i End If Next End If End Function WScript.StdOut.Write "the binom...
Write the same algorithm in Go as shown in this Arturo implementation.
factorial: function [n]-> product 1..n binomial: function [x,y]-> (factorial x) / (factorial y) * factorial x-y print binomial 5 3
package main import "fmt" import "math/big" func main() { fmt.Println(new(big.Int).Binomial(5, 3)) fmt.Println(new(big.Int).Binomial(60, 30)) }
Generate an equivalent C version of this AutoHotKey code.
MsgBox, % Round(BinomialCoefficient(5, 3)) BinomialCoefficient(n, k) { r := 1 Loop, % k < n - k ? k : n - k { r *= n - A_Index + 1 r /= A_Index } Return, r }
#include <stdio.h> #include <limits.h> static unsigned long gcd_ui(unsigned long x, unsigned long y) { unsigned long t; if (y < x) { t = x; x = y; y = t; } while (y > 0) { t = y; y = x % y; x = t; } return x; } unsigned long binomial(unsigned long n, unsigned long k) { unsigned long d, g, r = 1;...
Change the programming language of this snippet from AutoHotKey to C# without modifying what it does.
MsgBox, % Round(BinomialCoefficient(5, 3)) BinomialCoefficient(n, k) { r := 1 Loop, % k < n - k ? k : n - k { r *= n - A_Index + 1 r /= A_Index } Return, r }
using System; namespace BinomialCoefficients { class Program { static void Main(string[] args) { ulong n = 1000000, k = 3; ulong result = biCoefficient(n, k); Console.WriteLine("The Binomial Coefficient of {0}, and {1}, is equal to: {2}", n, k, result); ...
Write the same code in C++ as shown below in AutoHotKey.
MsgBox, % Round(BinomialCoefficient(5, 3)) BinomialCoefficient(n, k) { r := 1 Loop, % k < n - k ? k : n - k { r *= n - A_Index + 1 r /= A_Index } Return, r }
double Factorial(double nValue) { double result = nValue; double result_next; double pc = nValue; do { result_next = result*(pc-1); result = result_next; pc--; }while(pc>2); nValue = result; return nValue; } double binomialC...
Transform the following AutoHotKey implementation into Java, maintaining the same output and logic.
MsgBox, % Round(BinomialCoefficient(5, 3)) BinomialCoefficient(n, k) { r := 1 Loop, % k < n - k ? k : n - k { r *= n - A_Index + 1 r /= A_Index } Return, r }
public class Binomial { private static long binomialInt(int n, int k) { if (k > n - k) k = n - k; long binom = 1; for (int i = 1; i <= k; i++) binom = binom * (n + 1 - i) / i; return binom; } private static Object binomialIntReliable(int n...
Translate this program into Python but keep the logic exactly as in AutoHotKey.
MsgBox, % Round(BinomialCoefficient(5, 3)) BinomialCoefficient(n, k) { r := 1 Loop, % k < n - k ? k : n - k { r *= n - A_Index + 1 r /= A_Index } Return, r }
def binomialCoeff(n, k): result = 1 for i in range(1, k+1): result = result * (n-i+1) / i return result if __name__ == "__main__": print(binomialCoeff(5, 3))
Maintain the same structure and functionality when rewriting this code in VB.
MsgBox, % Round(BinomialCoefficient(5, 3)) BinomialCoefficient(n, k) { r := 1 Loop, % k < n - k ? k : n - k { r *= n - A_Index + 1 r /= A_Index } Return, r }
Function binomial(n,k) binomial = factorial(n)/(factorial(n-k)*factorial(k)) End Function Function factorial(n) If n = 0 Then factorial = 1 Else For i = n To 1 Step -1 If i = n Then factorial = n Else factorial = factorial * i End If Next End If End Function WScript.StdOut.Write "the binom...
Port the provided AutoHotKey code into Go while preserving the original functionality.
MsgBox, % Round(BinomialCoefficient(5, 3)) BinomialCoefficient(n, k) { r := 1 Loop, % k < n - k ? k : n - k { r *= n - A_Index + 1 r /= A_Index } Return, r }
package main import "fmt" import "math/big" func main() { fmt.Println(new(big.Int).Binomial(5, 3)) fmt.Println(new(big.Int).Binomial(60, 30)) }
Ensure the translated C code behaves exactly like the original AWK snippet.
BEGIN { main(5,3) main(100,2) main(33,17) exit(0) } function main(n,k, i,r) { r = 1 for (i=1; i<k+1; i++) { r *= (n - i + 1) / i } printf("%d %d = %d\n",n,k,r) }
#include <stdio.h> #include <limits.h> static unsigned long gcd_ui(unsigned long x, unsigned long y) { unsigned long t; if (y < x) { t = x; x = y; y = t; } while (y > 0) { t = y; y = x % y; x = t; } return x; } unsigned long binomial(unsigned long n, unsigned long k) { unsigned long d, g, r = 1;...
Convert this AWK block to C#, preserving its control flow and logic.
BEGIN { main(5,3) main(100,2) main(33,17) exit(0) } function main(n,k, i,r) { r = 1 for (i=1; i<k+1; i++) { r *= (n - i + 1) / i } printf("%d %d = %d\n",n,k,r) }
using System; namespace BinomialCoefficients { class Program { static void Main(string[] args) { ulong n = 1000000, k = 3; ulong result = biCoefficient(n, k); Console.WriteLine("The Binomial Coefficient of {0}, and {1}, is equal to: {2}", n, k, result); ...
Generate a C++ translation of this AWK snippet without changing its computational steps.
BEGIN { main(5,3) main(100,2) main(33,17) exit(0) } function main(n,k, i,r) { r = 1 for (i=1; i<k+1; i++) { r *= (n - i + 1) / i } printf("%d %d = %d\n",n,k,r) }
double Factorial(double nValue) { double result = nValue; double result_next; double pc = nValue; do { result_next = result*(pc-1); result = result_next; pc--; }while(pc>2); nValue = result; return nValue; } double binomialC...
Produce a language-to-language conversion: from AWK to Java, same semantics.
BEGIN { main(5,3) main(100,2) main(33,17) exit(0) } function main(n,k, i,r) { r = 1 for (i=1; i<k+1; i++) { r *= (n - i + 1) / i } printf("%d %d = %d\n",n,k,r) }
public class Binomial { private static long binomialInt(int n, int k) { if (k > n - k) k = n - k; long binom = 1; for (int i = 1; i <= k; i++) binom = binom * (n + 1 - i) / i; return binom; } private static Object binomialIntReliable(int n...
Rewrite this program in Python while keeping its functionality equivalent to the AWK version.
BEGIN { main(5,3) main(100,2) main(33,17) exit(0) } function main(n,k, i,r) { r = 1 for (i=1; i<k+1; i++) { r *= (n - i + 1) / i } printf("%d %d = %d\n",n,k,r) }
def binomialCoeff(n, k): result = 1 for i in range(1, k+1): result = result * (n-i+1) / i return result if __name__ == "__main__": print(binomialCoeff(5, 3))
Generate an equivalent VB version of this AWK code.
BEGIN { main(5,3) main(100,2) main(33,17) exit(0) } function main(n,k, i,r) { r = 1 for (i=1; i<k+1; i++) { r *= (n - i + 1) / i } printf("%d %d = %d\n",n,k,r) }
Function binomial(n,k) binomial = factorial(n)/(factorial(n-k)*factorial(k)) End Function Function factorial(n) If n = 0 Then factorial = 1 Else For i = n To 1 Step -1 If i = n Then factorial = n Else factorial = factorial * i End If Next End If End Function WScript.StdOut.Write "the binom...
Change the following AWK code into Go without altering its purpose.
BEGIN { main(5,3) main(100,2) main(33,17) exit(0) } function main(n,k, i,r) { r = 1 for (i=1; i<k+1; i++) { r *= (n - i + 1) / i } printf("%d %d = %d\n",n,k,r) }
package main import "fmt" import "math/big" func main() { fmt.Println(new(big.Int).Binomial(5, 3)) fmt.Println(new(big.Int).Binomial(60, 30)) }
Keep all operations the same but rewrite the snippet in C.
@%=&1010 PRINT "Binomial (5,3) = "; FNbinomial(5, 3) PRINT "Binomial (100,2) = "; FNbinomial(100, 2) PRINT "Binomial (33,17) = "; FNbinomial(33, 17) END DEF FNbinomial(N%, K%) LOCAL R%, D% R% = 1 : D% = N% - K% IF D% > K% THEN K% = D% : D% = N% - K% ...
#include <stdio.h> #include <limits.h> static unsigned long gcd_ui(unsigned long x, unsigned long y) { unsigned long t; if (y < x) { t = x; x = y; y = t; } while (y > 0) { t = y; y = x % y; x = t; } return x; } unsigned long binomial(unsigned long n, unsigned long k) { unsigned long d, g, r = 1;...
Translate the given BBC_Basic code snippet into C# without altering its behavior.
@%=&1010 PRINT "Binomial (5,3) = "; FNbinomial(5, 3) PRINT "Binomial (100,2) = "; FNbinomial(100, 2) PRINT "Binomial (33,17) = "; FNbinomial(33, 17) END DEF FNbinomial(N%, K%) LOCAL R%, D% R% = 1 : D% = N% - K% IF D% > K% THEN K% = D% : D% = N% - K% ...
using System; namespace BinomialCoefficients { class Program { static void Main(string[] args) { ulong n = 1000000, k = 3; ulong result = biCoefficient(n, k); Console.WriteLine("The Binomial Coefficient of {0}, and {1}, is equal to: {2}", n, k, result); ...
Port the following code from BBC_Basic to C++ with equivalent syntax and logic.
@%=&1010 PRINT "Binomial (5,3) = "; FNbinomial(5, 3) PRINT "Binomial (100,2) = "; FNbinomial(100, 2) PRINT "Binomial (33,17) = "; FNbinomial(33, 17) END DEF FNbinomial(N%, K%) LOCAL R%, D% R% = 1 : D% = N% - K% IF D% > K% THEN K% = D% : D% = N% - K% ...
double Factorial(double nValue) { double result = nValue; double result_next; double pc = nValue; do { result_next = result*(pc-1); result = result_next; pc--; }while(pc>2); nValue = result; return nValue; } double binomialC...
Write the same algorithm in Java as shown in this BBC_Basic implementation.
@%=&1010 PRINT "Binomial (5,3) = "; FNbinomial(5, 3) PRINT "Binomial (100,2) = "; FNbinomial(100, 2) PRINT "Binomial (33,17) = "; FNbinomial(33, 17) END DEF FNbinomial(N%, K%) LOCAL R%, D% R% = 1 : D% = N% - K% IF D% > K% THEN K% = D% : D% = N% - K% ...
public class Binomial { private static long binomialInt(int n, int k) { if (k > n - k) k = n - k; long binom = 1; for (int i = 1; i <= k; i++) binom = binom * (n + 1 - i) / i; return binom; } private static Object binomialIntReliable(int n...
Produce a language-to-language conversion: from BBC_Basic to Python, same semantics.
@%=&1010 PRINT "Binomial (5,3) = "; FNbinomial(5, 3) PRINT "Binomial (100,2) = "; FNbinomial(100, 2) PRINT "Binomial (33,17) = "; FNbinomial(33, 17) END DEF FNbinomial(N%, K%) LOCAL R%, D% R% = 1 : D% = N% - K% IF D% > K% THEN K% = D% : D% = N% - K% ...
def binomialCoeff(n, k): result = 1 for i in range(1, k+1): result = result * (n-i+1) / i return result if __name__ == "__main__": print(binomialCoeff(5, 3))
Convert the following code from BBC_Basic to VB, ensuring the logic remains intact.
@%=&1010 PRINT "Binomial (5,3) = "; FNbinomial(5, 3) PRINT "Binomial (100,2) = "; FNbinomial(100, 2) PRINT "Binomial (33,17) = "; FNbinomial(33, 17) END DEF FNbinomial(N%, K%) LOCAL R%, D% R% = 1 : D% = N% - K% IF D% > K% THEN K% = D% : D% = N% - K% ...
Function binomial(n,k) binomial = factorial(n)/(factorial(n-k)*factorial(k)) End Function Function factorial(n) If n = 0 Then factorial = 1 Else For i = n To 1 Step -1 If i = n Then factorial = n Else factorial = factorial * i End If Next End If End Function WScript.StdOut.Write "the binom...
Translate this program into Go but keep the logic exactly as in BBC_Basic.
@%=&1010 PRINT "Binomial (5,3) = "; FNbinomial(5, 3) PRINT "Binomial (100,2) = "; FNbinomial(100, 2) PRINT "Binomial (33,17) = "; FNbinomial(33, 17) END DEF FNbinomial(N%, K%) LOCAL R%, D% R% = 1 : D% = N% - K% IF D% > K% THEN K% = D% : D% = N% - K% ...
package main import "fmt" import "math/big" func main() { fmt.Println(new(big.Int).Binomial(5, 3)) fmt.Println(new(big.Int).Binomial(60, 30)) }
Translate this program into C but keep the logic exactly as in Clojure.
(defn binomial-coefficient [n k] (let [rprod (fn [a b] (reduce * (range a (inc b))))] (/ (rprod (- n k -1) n) (rprod 1 k))))
#include <stdio.h> #include <limits.h> static unsigned long gcd_ui(unsigned long x, unsigned long y) { unsigned long t; if (y < x) { t = x; x = y; y = t; } while (y > 0) { t = y; y = x % y; x = t; } return x; } unsigned long binomial(unsigned long n, unsigned long k) { unsigned long d, g, r = 1;...
Change the following Clojure code into C# without altering its purpose.
(defn binomial-coefficient [n k] (let [rprod (fn [a b] (reduce * (range a (inc b))))] (/ (rprod (- n k -1) n) (rprod 1 k))))
using System; namespace BinomialCoefficients { class Program { static void Main(string[] args) { ulong n = 1000000, k = 3; ulong result = biCoefficient(n, k); Console.WriteLine("The Binomial Coefficient of {0}, and {1}, is equal to: {2}", n, k, result); ...
Keep all operations the same but rewrite the snippet in C++.
(defn binomial-coefficient [n k] (let [rprod (fn [a b] (reduce * (range a (inc b))))] (/ (rprod (- n k -1) n) (rprod 1 k))))
double Factorial(double nValue) { double result = nValue; double result_next; double pc = nValue; do { result_next = result*(pc-1); result = result_next; pc--; }while(pc>2); nValue = result; return nValue; } double binomialC...
Transform the following Clojure implementation into Java, maintaining the same output and logic.
(defn binomial-coefficient [n k] (let [rprod (fn [a b] (reduce * (range a (inc b))))] (/ (rprod (- n k -1) n) (rprod 1 k))))
public class Binomial { private static long binomialInt(int n, int k) { if (k > n - k) k = n - k; long binom = 1; for (int i = 1; i <= k; i++) binom = binom * (n + 1 - i) / i; return binom; } private static Object binomialIntReliable(int n...
Convert this Clojure block to Python, preserving its control flow and logic.
(defn binomial-coefficient [n k] (let [rprod (fn [a b] (reduce * (range a (inc b))))] (/ (rprod (- n k -1) n) (rprod 1 k))))
def binomialCoeff(n, k): result = 1 for i in range(1, k+1): result = result * (n-i+1) / i return result if __name__ == "__main__": print(binomialCoeff(5, 3))
Port the following code from Clojure to VB with equivalent syntax and logic.
(defn binomial-coefficient [n k] (let [rprod (fn [a b] (reduce * (range a (inc b))))] (/ (rprod (- n k -1) n) (rprod 1 k))))
Function binomial(n,k) binomial = factorial(n)/(factorial(n-k)*factorial(k)) End Function Function factorial(n) If n = 0 Then factorial = 1 Else For i = n To 1 Step -1 If i = n Then factorial = n Else factorial = factorial * i End If Next End If End Function WScript.StdOut.Write "the binom...
Write the same algorithm in Go as shown in this Clojure implementation.
(defn binomial-coefficient [n k] (let [rprod (fn [a b] (reduce * (range a (inc b))))] (/ (rprod (- n k -1) n) (rprod 1 k))))
package main import "fmt" import "math/big" func main() { fmt.Println(new(big.Int).Binomial(5, 3)) fmt.Println(new(big.Int).Binomial(60, 30)) }
Port the provided Common_Lisp code into C while preserving the original functionality.
(defun fac (n) (if (zp n) 1 (* n (fac (1- n))))) (defun binom (n k) (/ (fac n) (* (fac (- n k)) (fac k)))
#include <stdio.h> #include <limits.h> static unsigned long gcd_ui(unsigned long x, unsigned long y) { unsigned long t; if (y < x) { t = x; x = y; y = t; } while (y > 0) { t = y; y = x % y; x = t; } return x; } unsigned long binomial(unsigned long n, unsigned long k) { unsigned long d, g, r = 1;...
Translate this program into C# but keep the logic exactly as in Common_Lisp.
(defun fac (n) (if (zp n) 1 (* n (fac (1- n))))) (defun binom (n k) (/ (fac n) (* (fac (- n k)) (fac k)))
using System; namespace BinomialCoefficients { class Program { static void Main(string[] args) { ulong n = 1000000, k = 3; ulong result = biCoefficient(n, k); Console.WriteLine("The Binomial Coefficient of {0}, and {1}, is equal to: {2}", n, k, result); ...
Ensure the translated C++ code behaves exactly like the original Common_Lisp snippet.
(defun fac (n) (if (zp n) 1 (* n (fac (1- n))))) (defun binom (n k) (/ (fac n) (* (fac (- n k)) (fac k)))
double Factorial(double nValue) { double result = nValue; double result_next; double pc = nValue; do { result_next = result*(pc-1); result = result_next; pc--; }while(pc>2); nValue = result; return nValue; } double binomialC...
Generate an equivalent Java version of this Common_Lisp code.
(defun fac (n) (if (zp n) 1 (* n (fac (1- n))))) (defun binom (n k) (/ (fac n) (* (fac (- n k)) (fac k)))
public class Binomial { private static long binomialInt(int n, int k) { if (k > n - k) k = n - k; long binom = 1; for (int i = 1; i <= k; i++) binom = binom * (n + 1 - i) / i; return binom; } private static Object binomialIntReliable(int n...
Write a version of this Common_Lisp function in Python with identical behavior.
(defun fac (n) (if (zp n) 1 (* n (fac (1- n))))) (defun binom (n k) (/ (fac n) (* (fac (- n k)) (fac k)))
def binomialCoeff(n, k): result = 1 for i in range(1, k+1): result = result * (n-i+1) / i return result if __name__ == "__main__": print(binomialCoeff(5, 3))
Write the same code in VB as shown below in Common_Lisp.
(defun fac (n) (if (zp n) 1 (* n (fac (1- n))))) (defun binom (n k) (/ (fac n) (* (fac (- n k)) (fac k)))
Function binomial(n,k) binomial = factorial(n)/(factorial(n-k)*factorial(k)) End Function Function factorial(n) If n = 0 Then factorial = 1 Else For i = n To 1 Step -1 If i = n Then factorial = n Else factorial = factorial * i End If Next End If End Function WScript.StdOut.Write "the binom...
Please provide an equivalent version of this Common_Lisp code in Go.
(defun fac (n) (if (zp n) 1 (* n (fac (1- n))))) (defun binom (n k) (/ (fac n) (* (fac (- n k)) (fac k)))
package main import "fmt" import "math/big" func main() { fmt.Println(new(big.Int).Binomial(5, 3)) fmt.Println(new(big.Int).Binomial(60, 30)) }
Transform the following D implementation into C, maintaining the same output and logic.
T binomial(T)(in T n, T k) pure nothrow { if (k > (n / 2)) k = n - k; T bc = 1; foreach (T i; T(2) .. k + 1) bc = (bc * (n - k + i)) / i; return bc; } void main() { import std.stdio, std.bigint; foreach (const d; [[5, 3], [100, 2], [100, 98]]) writefln("(%3d %3d) = %s",...
#include <stdio.h> #include <limits.h> static unsigned long gcd_ui(unsigned long x, unsigned long y) { unsigned long t; if (y < x) { t = x; x = y; y = t; } while (y > 0) { t = y; y = x % y; x = t; } return x; } unsigned long binomial(unsigned long n, unsigned long k) { unsigned long d, g, r = 1;...
Maintain the same structure and functionality when rewriting this code in C#.
T binomial(T)(in T n, T k) pure nothrow { if (k > (n / 2)) k = n - k; T bc = 1; foreach (T i; T(2) .. k + 1) bc = (bc * (n - k + i)) / i; return bc; } void main() { import std.stdio, std.bigint; foreach (const d; [[5, 3], [100, 2], [100, 98]]) writefln("(%3d %3d) = %s",...
using System; namespace BinomialCoefficients { class Program { static void Main(string[] args) { ulong n = 1000000, k = 3; ulong result = biCoefficient(n, k); Console.WriteLine("The Binomial Coefficient of {0}, and {1}, is equal to: {2}", n, k, result); ...
Translate this program into C++ but keep the logic exactly as in D.
T binomial(T)(in T n, T k) pure nothrow { if (k > (n / 2)) k = n - k; T bc = 1; foreach (T i; T(2) .. k + 1) bc = (bc * (n - k + i)) / i; return bc; } void main() { import std.stdio, std.bigint; foreach (const d; [[5, 3], [100, 2], [100, 98]]) writefln("(%3d %3d) = %s",...
double Factorial(double nValue) { double result = nValue; double result_next; double pc = nValue; do { result_next = result*(pc-1); result = result_next; pc--; }while(pc>2); nValue = result; return nValue; } double binomialC...
Rewrite the snippet below in Java so it works the same as the original D code.
T binomial(T)(in T n, T k) pure nothrow { if (k > (n / 2)) k = n - k; T bc = 1; foreach (T i; T(2) .. k + 1) bc = (bc * (n - k + i)) / i; return bc; } void main() { import std.stdio, std.bigint; foreach (const d; [[5, 3], [100, 2], [100, 98]]) writefln("(%3d %3d) = %s",...
public class Binomial { private static long binomialInt(int n, int k) { if (k > n - k) k = n - k; long binom = 1; for (int i = 1; i <= k; i++) binom = binom * (n + 1 - i) / i; return binom; } private static Object binomialIntReliable(int n...
Preserve the algorithm and functionality while converting the code from D to Python.
T binomial(T)(in T n, T k) pure nothrow { if (k > (n / 2)) k = n - k; T bc = 1; foreach (T i; T(2) .. k + 1) bc = (bc * (n - k + i)) / i; return bc; } void main() { import std.stdio, std.bigint; foreach (const d; [[5, 3], [100, 2], [100, 98]]) writefln("(%3d %3d) = %s",...
def binomialCoeff(n, k): result = 1 for i in range(1, k+1): result = result * (n-i+1) / i return result if __name__ == "__main__": print(binomialCoeff(5, 3))
Produce a functionally identical VB code for the snippet given in D.
T binomial(T)(in T n, T k) pure nothrow { if (k > (n / 2)) k = n - k; T bc = 1; foreach (T i; T(2) .. k + 1) bc = (bc * (n - k + i)) / i; return bc; } void main() { import std.stdio, std.bigint; foreach (const d; [[5, 3], [100, 2], [100, 98]]) writefln("(%3d %3d) = %s",...
Function binomial(n,k) binomial = factorial(n)/(factorial(n-k)*factorial(k)) End Function Function factorial(n) If n = 0 Then factorial = 1 Else For i = n To 1 Step -1 If i = n Then factorial = n Else factorial = factorial * i End If Next End If End Function WScript.StdOut.Write "the binom...
Port the provided D code into Go while preserving the original functionality.
T binomial(T)(in T n, T k) pure nothrow { if (k > (n / 2)) k = n - k; T bc = 1; foreach (T i; T(2) .. k + 1) bc = (bc * (n - k + i)) / i; return bc; } void main() { import std.stdio, std.bigint; foreach (const d; [[5, 3], [100, 2], [100, 98]]) writefln("(%3d %3d) = %s",...
package main import "fmt" import "math/big" func main() { fmt.Println(new(big.Int).Binomial(5, 3)) fmt.Println(new(big.Int).Binomial(60, 30)) }
Translate this program into C but keep the logic exactly as in Delphi.
program Binomial; function BinomialCoff(N, K: Cardinal): Cardinal; var L: Cardinal; begin if N < K then Result:= 0 else begin if K > N - K then K:= N - K; Result:= 1; L:= 0; while L < K do begin Result:= Result * (N - L); Inc(L); Result:= Result div L; ...
#include <stdio.h> #include <limits.h> static unsigned long gcd_ui(unsigned long x, unsigned long y) { unsigned long t; if (y < x) { t = x; x = y; y = t; } while (y > 0) { t = y; y = x % y; x = t; } return x; } unsigned long binomial(unsigned long n, unsigned long k) { unsigned long d, g, r = 1;...
Rewrite this program in C# while keeping its functionality equivalent to the Delphi version.
program Binomial; function BinomialCoff(N, K: Cardinal): Cardinal; var L: Cardinal; begin if N < K then Result:= 0 else begin if K > N - K then K:= N - K; Result:= 1; L:= 0; while L < K do begin Result:= Result * (N - L); Inc(L); Result:= Result div L; ...
using System; namespace BinomialCoefficients { class Program { static void Main(string[] args) { ulong n = 1000000, k = 3; ulong result = biCoefficient(n, k); Console.WriteLine("The Binomial Coefficient of {0}, and {1}, is equal to: {2}", n, k, result); ...
Convert this Delphi snippet to C++ and keep its semantics consistent.
program Binomial; function BinomialCoff(N, K: Cardinal): Cardinal; var L: Cardinal; begin if N < K then Result:= 0 else begin if K > N - K then K:= N - K; Result:= 1; L:= 0; while L < K do begin Result:= Result * (N - L); Inc(L); Result:= Result div L; ...
double Factorial(double nValue) { double result = nValue; double result_next; double pc = nValue; do { result_next = result*(pc-1); result = result_next; pc--; }while(pc>2); nValue = result; return nValue; } double binomialC...
Translate the given Delphi code snippet into Java without altering its behavior.
program Binomial; function BinomialCoff(N, K: Cardinal): Cardinal; var L: Cardinal; begin if N < K then Result:= 0 else begin if K > N - K then K:= N - K; Result:= 1; L:= 0; while L < K do begin Result:= Result * (N - L); Inc(L); Result:= Result div L; ...
public class Binomial { private static long binomialInt(int n, int k) { if (k > n - k) k = n - k; long binom = 1; for (int i = 1; i <= k; i++) binom = binom * (n + 1 - i) / i; return binom; } private static Object binomialIntReliable(int n...
Write the same algorithm in Python as shown in this Delphi implementation.
program Binomial; function BinomialCoff(N, K: Cardinal): Cardinal; var L: Cardinal; begin if N < K then Result:= 0 else begin if K > N - K then K:= N - K; Result:= 1; L:= 0; while L < K do begin Result:= Result * (N - L); Inc(L); Result:= Result div L; ...
def binomialCoeff(n, k): result = 1 for i in range(1, k+1): result = result * (n-i+1) / i return result if __name__ == "__main__": print(binomialCoeff(5, 3))
Translate the given Delphi code snippet into VB without altering its behavior.
program Binomial; function BinomialCoff(N, K: Cardinal): Cardinal; var L: Cardinal; begin if N < K then Result:= 0 else begin if K > N - K then K:= N - K; Result:= 1; L:= 0; while L < K do begin Result:= Result * (N - L); Inc(L); Result:= Result div L; ...
Function binomial(n,k) binomial = factorial(n)/(factorial(n-k)*factorial(k)) End Function Function factorial(n) If n = 0 Then factorial = 1 Else For i = n To 1 Step -1 If i = n Then factorial = n Else factorial = factorial * i End If Next End If End Function WScript.StdOut.Write "the binom...
Generate a Go translation of this Delphi snippet without changing its computational steps.
program Binomial; function BinomialCoff(N, K: Cardinal): Cardinal; var L: Cardinal; begin if N < K then Result:= 0 else begin if K > N - K then K:= N - K; Result:= 1; L:= 0; while L < K do begin Result:= Result * (N - L); Inc(L); Result:= Result div L; ...
package main import "fmt" import "math/big" func main() { fmt.Println(new(big.Int).Binomial(5, 3)) fmt.Println(new(big.Int).Binomial(60, 30)) }
Generate an equivalent C version of this Elixir code.
defmodule RC do def choose(n,k) when is_integer(n) and is_integer(k) and n>=0 and k>=0 and n>=k do if k==0, do: 1, else: choose(n,k,1,1) end def choose(n,k,k,acc), do: div(acc * (n-k+1), k) def choose(n,k,i,acc), do: choose(n, k, i+1, div(acc * (n-i+1), i)) end IO.inspect RC.choose(5,3) IO.inspect RC.ch...
#include <stdio.h> #include <limits.h> static unsigned long gcd_ui(unsigned long x, unsigned long y) { unsigned long t; if (y < x) { t = x; x = y; y = t; } while (y > 0) { t = y; y = x % y; x = t; } return x; } unsigned long binomial(unsigned long n, unsigned long k) { unsigned long d, g, r = 1;...
Preserve the algorithm and functionality while converting the code from Elixir to C#.
defmodule RC do def choose(n,k) when is_integer(n) and is_integer(k) and n>=0 and k>=0 and n>=k do if k==0, do: 1, else: choose(n,k,1,1) end def choose(n,k,k,acc), do: div(acc * (n-k+1), k) def choose(n,k,i,acc), do: choose(n, k, i+1, div(acc * (n-i+1), i)) end IO.inspect RC.choose(5,3) IO.inspect RC.ch...
using System; namespace BinomialCoefficients { class Program { static void Main(string[] args) { ulong n = 1000000, k = 3; ulong result = biCoefficient(n, k); Console.WriteLine("The Binomial Coefficient of {0}, and {1}, is equal to: {2}", n, k, result); ...
Preserve the algorithm and functionality while converting the code from Elixir to C++.
defmodule RC do def choose(n,k) when is_integer(n) and is_integer(k) and n>=0 and k>=0 and n>=k do if k==0, do: 1, else: choose(n,k,1,1) end def choose(n,k,k,acc), do: div(acc * (n-k+1), k) def choose(n,k,i,acc), do: choose(n, k, i+1, div(acc * (n-i+1), i)) end IO.inspect RC.choose(5,3) IO.inspect RC.ch...
double Factorial(double nValue) { double result = nValue; double result_next; double pc = nValue; do { result_next = result*(pc-1); result = result_next; pc--; }while(pc>2); nValue = result; return nValue; } double binomialC...
Produce a functionally identical Java code for the snippet given in Elixir.
defmodule RC do def choose(n,k) when is_integer(n) and is_integer(k) and n>=0 and k>=0 and n>=k do if k==0, do: 1, else: choose(n,k,1,1) end def choose(n,k,k,acc), do: div(acc * (n-k+1), k) def choose(n,k,i,acc), do: choose(n, k, i+1, div(acc * (n-i+1), i)) end IO.inspect RC.choose(5,3) IO.inspect RC.ch...
public class Binomial { private static long binomialInt(int n, int k) { if (k > n - k) k = n - k; long binom = 1; for (int i = 1; i <= k; i++) binom = binom * (n + 1 - i) / i; return binom; } private static Object binomialIntReliable(int n...
Produce a language-to-language conversion: from Elixir to VB, same semantics.
defmodule RC do def choose(n,k) when is_integer(n) and is_integer(k) and n>=0 and k>=0 and n>=k do if k==0, do: 1, else: choose(n,k,1,1) end def choose(n,k,k,acc), do: div(acc * (n-k+1), k) def choose(n,k,i,acc), do: choose(n, k, i+1, div(acc * (n-i+1), i)) end IO.inspect RC.choose(5,3) IO.inspect RC.ch...
Function binomial(n,k) binomial = factorial(n)/(factorial(n-k)*factorial(k)) End Function Function factorial(n) If n = 0 Then factorial = 1 Else For i = n To 1 Step -1 If i = n Then factorial = n Else factorial = factorial * i End If Next End If End Function WScript.StdOut.Write "the binom...
Generate an equivalent Go version of this Elixir code.
defmodule RC do def choose(n,k) when is_integer(n) and is_integer(k) and n>=0 and k>=0 and n>=k do if k==0, do: 1, else: choose(n,k,1,1) end def choose(n,k,k,acc), do: div(acc * (n-k+1), k) def choose(n,k,i,acc), do: choose(n, k, i+1, div(acc * (n-i+1), i)) end IO.inspect RC.choose(5,3) IO.inspect RC.ch...
package main import "fmt" import "math/big" func main() { fmt.Println(new(big.Int).Binomial(5, 3)) fmt.Println(new(big.Int).Binomial(60, 30)) }
Generate a C translation of this Erlang snippet without changing its computational steps.
choose(N, 0) -> 1; choose(N, K) when is_integer(N), is_integer(K), (N >= 0), (K >= 0), (N >= K) -> choose(N, K, 1, 1). choose(N, K, K, Acc) -> (Acc * (N-K+1)) div K; choose(N, K, I, Acc) -> choose(N, K, I+1, (Acc * (N-I+1)) div I).
#include <stdio.h> #include <limits.h> static unsigned long gcd_ui(unsigned long x, unsigned long y) { unsigned long t; if (y < x) { t = x; x = y; y = t; } while (y > 0) { t = y; y = x % y; x = t; } return x; } unsigned long binomial(unsigned long n, unsigned long k) { unsigned long d, g, r = 1;...
Write a version of this Erlang function in C# with identical behavior.
choose(N, 0) -> 1; choose(N, K) when is_integer(N), is_integer(K), (N >= 0), (K >= 0), (N >= K) -> choose(N, K, 1, 1). choose(N, K, K, Acc) -> (Acc * (N-K+1)) div K; choose(N, K, I, Acc) -> choose(N, K, I+1, (Acc * (N-I+1)) div I).
using System; namespace BinomialCoefficients { class Program { static void Main(string[] args) { ulong n = 1000000, k = 3; ulong result = biCoefficient(n, k); Console.WriteLine("The Binomial Coefficient of {0}, and {1}, is equal to: {2}", n, k, result); ...
Write the same algorithm in C++ as shown in this Erlang implementation.
choose(N, 0) -> 1; choose(N, K) when is_integer(N), is_integer(K), (N >= 0), (K >= 0), (N >= K) -> choose(N, K, 1, 1). choose(N, K, K, Acc) -> (Acc * (N-K+1)) div K; choose(N, K, I, Acc) -> choose(N, K, I+1, (Acc * (N-I+1)) div I).
double Factorial(double nValue) { double result = nValue; double result_next; double pc = nValue; do { result_next = result*(pc-1); result = result_next; pc--; }while(pc>2); nValue = result; return nValue; } double binomialC...