Instruction stringlengths 45 106 | input_code stringlengths 1 13.7k | output_code stringlengths 1 13.7k |
|---|---|---|
Preserve the algorithm and functionality while converting the code from Go to Rust. | package main
import (
"fmt"
"math/big"
)
var (
zero = big.NewInt(0)
one = big.NewInt(1)
prev = big.NewInt(factorial(20))
)
func factorial(n int64) int64 {
res := int64(1)
for k := n; k > 1; k-- {
res *= k
}
return res
}
func wilson(n int64, memo bool) bool {
if n <= 1 || (n%2 == 0 && n != 2) {
return false
}
if n <= 21 {
return (factorial(n-1)+1)%n == 0
}
b := big.NewInt(n)
r := big.NewInt(0)
z := big.NewInt(0)
if !memo {
z.MulRange(2, n-1)
} else {
prev.Mul(prev, r.MulRange(n-2, n-1))
z.Set(prev)
}
z.Add(z, one)
return r.Rem(z, b).Cmp(zero) == 0
}
func main() {
numbers := []int64{2, 3, 9, 15, 29, 37, 47, 57, 67, 77, 87, 97, 237, 409, 659}
fmt.Println(" n prime")
fmt.Println("--- -----")
for _, n := range numbers {
fmt.Printf("%3d %t\n", n, wilson(n, false))
}
fmt.Println("\nThe first 120 prime numbers are:")
for i, count := int64(2), 0; count < 1015; i += 2 {
if wilson(i, true) {
count++
if count <= 120 {
fmt.Printf("%3d ", i)
if count%20 == 0 {
fmt.Println()
}
} else if count >= 1000 {
if count == 1000 {
fmt.Println("\nThe 1,000th to 1,015th prime numbers are:")
}
fmt.Printf("%4d ", i)
}
}
if i == 2 {
i--
}
}
fmt.Println()
}
| fn factorial_mod(mut n: u32, p: u32) -> u32 {
let mut f = 1;
while n != 0 && f != 0 {
f = (f * n) % p;
n -= 1;
}
f
}
fn is_prime(p: u32) -> bool {
p > 1 && factorial_mod(p - 1, p) == p - 1
}
fn main() {
println!(" n | prime?\n------------");
for p in vec![2, 3, 9, 15, 29, 37, 47, 57, 67, 77, 87, 97, 237, 409, 659] {
println!("{:>3} | {}", p, is_prime(p));
}
println!("\nFirst 120 primes by Wilson's theorem:");
let mut n = 0;
let mut p = 1;
while n < 120 {
if is_prime(p) {
n += 1;
print!("{:>3}{}", p, if n % 20 == 0 { '\n' } else { ' ' });
}
p += 1;
}
println!("\n1000th through 1015th primes:");
let mut i = 0;
while n < 1015 {
if is_prime(p) {
n += 1;
if n >= 1000 {
i += 1;
print!("{:>3}{}", p, if i % 16 == 0 { '\n' } else { ' ' });
}
}
p += 1;
}
}
|
Change the following Rust code into Python without altering its purpose. | fn factorial_mod(mut n: u32, p: u32) -> u32 {
let mut f = 1;
while n != 0 && f != 0 {
f = (f * n) % p;
n -= 1;
}
f
}
fn is_prime(p: u32) -> bool {
p > 1 && factorial_mod(p - 1, p) == p - 1
}
fn main() {
println!(" n | prime?\n------------");
for p in vec![2, 3, 9, 15, 29, 37, 47, 57, 67, 77, 87, 97, 237, 409, 659] {
println!("{:>3} | {}", p, is_prime(p));
}
println!("\nFirst 120 primes by Wilson's theorem:");
let mut n = 0;
let mut p = 1;
while n < 120 {
if is_prime(p) {
n += 1;
print!("{:>3}{}", p, if n % 20 == 0 { '\n' } else { ' ' });
}
p += 1;
}
println!("\n1000th through 1015th primes:");
let mut i = 0;
while n < 1015 {
if is_prime(p) {
n += 1;
if n >= 1000 {
i += 1;
print!("{:>3}{}", p, if i % 16 == 0 { '\n' } else { ' ' });
}
}
p += 1;
}
}
| from math import factorial
def is_wprime(n):
return n == 2 or (
n > 1
and n % 2 != 0
and (factorial(n - 1) + 1) % n == 0
)
if __name__ == '__main__':
c = int(input('Enter upper limit: '))
print(f'Primes under {c}:')
print([n for n in range(c) if is_wprime(n)])
|
Ensure the translated C# code behaves exactly like the original Ada snippet. | with Ada.Integer_Text_IO; use Ada.Integer_Text_IO;
with Ada.Text_IO; use Ada.Text_IO;
procedure Fraction_Reduction is
type Int_Array is array (Natural range <>) of Integer;
function indexOf(haystack : Int_Array; needle : Integer) return Integer is
idx : Integer := 0;
begin
for straw of haystack loop
if straw = needle then
return idx;
else
idx := idx + 1;
end if;
end loop;
return -1;
end IndexOf;
function getDigits(n, le : in Integer;
digit_array : in out Int_Array) return Boolean is
n_local : Integer := n;
le_local : Integer := le;
r : Integer;
begin
while n_local > 0 loop
r := n_local mod 10;
if r = 0 or indexOf(digit_array, r) >= 0 then
return False;
end if;
le_local := le_local - 1;
digit_array(le_local) := r;
n_local := n_local / 10;
end loop;
return True;
end getDigits;
function removeDigit(digit_array : Int_Array;
le, idx : Integer) return Integer is
sum : Integer := 0;
pow : Integer := 10 ** (le - 2);
begin
for i in 0 .. le - 1 loop
if i /= idx then
sum := sum + digit_array(i) * pow;
pow := pow / 10;
end if;
end loop;
return sum;
end removeDigit;
lims : constant array (0 .. 3) of Int_Array (0 .. 1) :=
((12, 97), (123, 986), (1234, 9875), (12345, 98764));
count : Int_Array (0 .. 4) := (others => 0);
omitted : array (0 .. 4) of Int_Array (0 .. 9) :=
(others => (others => 0));
begin
Ada.Integer_Text_IO.Default_Width := 0;
for i in lims'Range loop
declare
nDigits, dDigits : Int_Array (0 .. i + 1);
digit, dix, rn, rd : Integer;
begin
for n in lims(i)(0) .. lims(i)(1) loop
nDigits := (others => 0);
if getDigits(n, i + 2, nDigits) then
for d in n + 1 .. lims(i)(1) + 1 loop
dDigits := (others => 0);
if getDigits(d, i + 2, dDigits) then
for nix in nDigits'Range loop
digit := nDigits(nix);
dix := indexOf(dDigits, digit);
if dix >= 0 then
rn := removeDigit(nDigits, i + 2, nix);
rd := removeDigit(dDigits, i + 2, dix);
if n*rd = rn*d then
count(i) := count(i) + 1;
omitted(i)(digit) :=
omitted(i)(digit) + 1;
if count(i) <= 12 then
Put (n);
Put ("/");
Put (d);
Put (" = ");
Put (rn);
Put ("/");
Put (rd);
Put (" by omitting ");
Put (digit);
Put_Line ("'s");
end if;
end if;
end if;
end loop;
end if;
end loop;
end if;
end loop;
end;
New_Line;
end loop;
for i in 2 .. 5 loop
Put ("There are ");
Put (count(i - 2));
Put (" ");
Put (i);
Put_Line ("-digit fractions of which:");
for j in 1 .. 9 loop
if omitted(i - 2)(j) /= 0 then
Put (omitted(i - 2)(j), Width => 6);
Put (" have ");
Put (j);
Put_Line ("'s omitted");
end if;
end loop;
New_Line;
end loop;
end Fraction_Reduction;
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Convert the following code from Ada to C, ensuring the logic remains intact. | with Ada.Integer_Text_IO; use Ada.Integer_Text_IO;
with Ada.Text_IO; use Ada.Text_IO;
procedure Fraction_Reduction is
type Int_Array is array (Natural range <>) of Integer;
function indexOf(haystack : Int_Array; needle : Integer) return Integer is
idx : Integer := 0;
begin
for straw of haystack loop
if straw = needle then
return idx;
else
idx := idx + 1;
end if;
end loop;
return -1;
end IndexOf;
function getDigits(n, le : in Integer;
digit_array : in out Int_Array) return Boolean is
n_local : Integer := n;
le_local : Integer := le;
r : Integer;
begin
while n_local > 0 loop
r := n_local mod 10;
if r = 0 or indexOf(digit_array, r) >= 0 then
return False;
end if;
le_local := le_local - 1;
digit_array(le_local) := r;
n_local := n_local / 10;
end loop;
return True;
end getDigits;
function removeDigit(digit_array : Int_Array;
le, idx : Integer) return Integer is
sum : Integer := 0;
pow : Integer := 10 ** (le - 2);
begin
for i in 0 .. le - 1 loop
if i /= idx then
sum := sum + digit_array(i) * pow;
pow := pow / 10;
end if;
end loop;
return sum;
end removeDigit;
lims : constant array (0 .. 3) of Int_Array (0 .. 1) :=
((12, 97), (123, 986), (1234, 9875), (12345, 98764));
count : Int_Array (0 .. 4) := (others => 0);
omitted : array (0 .. 4) of Int_Array (0 .. 9) :=
(others => (others => 0));
begin
Ada.Integer_Text_IO.Default_Width := 0;
for i in lims'Range loop
declare
nDigits, dDigits : Int_Array (0 .. i + 1);
digit, dix, rn, rd : Integer;
begin
for n in lims(i)(0) .. lims(i)(1) loop
nDigits := (others => 0);
if getDigits(n, i + 2, nDigits) then
for d in n + 1 .. lims(i)(1) + 1 loop
dDigits := (others => 0);
if getDigits(d, i + 2, dDigits) then
for nix in nDigits'Range loop
digit := nDigits(nix);
dix := indexOf(dDigits, digit);
if dix >= 0 then
rn := removeDigit(nDigits, i + 2, nix);
rd := removeDigit(dDigits, i + 2, dix);
if n*rd = rn*d then
count(i) := count(i) + 1;
omitted(i)(digit) :=
omitted(i)(digit) + 1;
if count(i) <= 12 then
Put (n);
Put ("/");
Put (d);
Put (" = ");
Put (rn);
Put ("/");
Put (rd);
Put (" by omitting ");
Put (digit);
Put_Line ("'s");
end if;
end if;
end if;
end loop;
end if;
end loop;
end if;
end loop;
end;
New_Line;
end loop;
for i in 2 .. 5 loop
Put ("There are ");
Put (count(i - 2));
Put (" ");
Put (i);
Put_Line ("-digit fractions of which:");
for j in 1 .. 9 loop
if omitted(i - 2)(j) /= 0 then
Put (omitted(i - 2)(j), Width => 6);
Put (" have ");
Put (j);
Put_Line ("'s omitted");
end if;
end loop;
New_Line;
end loop;
end Fraction_Reduction;
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Please provide an equivalent version of this Ada code in C++. | with Ada.Integer_Text_IO; use Ada.Integer_Text_IO;
with Ada.Text_IO; use Ada.Text_IO;
procedure Fraction_Reduction is
type Int_Array is array (Natural range <>) of Integer;
function indexOf(haystack : Int_Array; needle : Integer) return Integer is
idx : Integer := 0;
begin
for straw of haystack loop
if straw = needle then
return idx;
else
idx := idx + 1;
end if;
end loop;
return -1;
end IndexOf;
function getDigits(n, le : in Integer;
digit_array : in out Int_Array) return Boolean is
n_local : Integer := n;
le_local : Integer := le;
r : Integer;
begin
while n_local > 0 loop
r := n_local mod 10;
if r = 0 or indexOf(digit_array, r) >= 0 then
return False;
end if;
le_local := le_local - 1;
digit_array(le_local) := r;
n_local := n_local / 10;
end loop;
return True;
end getDigits;
function removeDigit(digit_array : Int_Array;
le, idx : Integer) return Integer is
sum : Integer := 0;
pow : Integer := 10 ** (le - 2);
begin
for i in 0 .. le - 1 loop
if i /= idx then
sum := sum + digit_array(i) * pow;
pow := pow / 10;
end if;
end loop;
return sum;
end removeDigit;
lims : constant array (0 .. 3) of Int_Array (0 .. 1) :=
((12, 97), (123, 986), (1234, 9875), (12345, 98764));
count : Int_Array (0 .. 4) := (others => 0);
omitted : array (0 .. 4) of Int_Array (0 .. 9) :=
(others => (others => 0));
begin
Ada.Integer_Text_IO.Default_Width := 0;
for i in lims'Range loop
declare
nDigits, dDigits : Int_Array (0 .. i + 1);
digit, dix, rn, rd : Integer;
begin
for n in lims(i)(0) .. lims(i)(1) loop
nDigits := (others => 0);
if getDigits(n, i + 2, nDigits) then
for d in n + 1 .. lims(i)(1) + 1 loop
dDigits := (others => 0);
if getDigits(d, i + 2, dDigits) then
for nix in nDigits'Range loop
digit := nDigits(nix);
dix := indexOf(dDigits, digit);
if dix >= 0 then
rn := removeDigit(nDigits, i + 2, nix);
rd := removeDigit(dDigits, i + 2, dix);
if n*rd = rn*d then
count(i) := count(i) + 1;
omitted(i)(digit) :=
omitted(i)(digit) + 1;
if count(i) <= 12 then
Put (n);
Put ("/");
Put (d);
Put (" = ");
Put (rn);
Put ("/");
Put (rd);
Put (" by omitting ");
Put (digit);
Put_Line ("'s");
end if;
end if;
end if;
end loop;
end if;
end loop;
end if;
end loop;
end;
New_Line;
end loop;
for i in 2 .. 5 loop
Put ("There are ");
Put (count(i - 2));
Put (" ");
Put (i);
Put_Line ("-digit fractions of which:");
for j in 1 .. 9 loop
if omitted(i - 2)(j) /= 0 then
Put (omitted(i - 2)(j), Width => 6);
Put (" have ");
Put (j);
Put_Line ("'s omitted");
end if;
end loop;
New_Line;
end loop;
end Fraction_Reduction;
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Write a version of this Ada function in Go with identical behavior. | with Ada.Integer_Text_IO; use Ada.Integer_Text_IO;
with Ada.Text_IO; use Ada.Text_IO;
procedure Fraction_Reduction is
type Int_Array is array (Natural range <>) of Integer;
function indexOf(haystack : Int_Array; needle : Integer) return Integer is
idx : Integer := 0;
begin
for straw of haystack loop
if straw = needle then
return idx;
else
idx := idx + 1;
end if;
end loop;
return -1;
end IndexOf;
function getDigits(n, le : in Integer;
digit_array : in out Int_Array) return Boolean is
n_local : Integer := n;
le_local : Integer := le;
r : Integer;
begin
while n_local > 0 loop
r := n_local mod 10;
if r = 0 or indexOf(digit_array, r) >= 0 then
return False;
end if;
le_local := le_local - 1;
digit_array(le_local) := r;
n_local := n_local / 10;
end loop;
return True;
end getDigits;
function removeDigit(digit_array : Int_Array;
le, idx : Integer) return Integer is
sum : Integer := 0;
pow : Integer := 10 ** (le - 2);
begin
for i in 0 .. le - 1 loop
if i /= idx then
sum := sum + digit_array(i) * pow;
pow := pow / 10;
end if;
end loop;
return sum;
end removeDigit;
lims : constant array (0 .. 3) of Int_Array (0 .. 1) :=
((12, 97), (123, 986), (1234, 9875), (12345, 98764));
count : Int_Array (0 .. 4) := (others => 0);
omitted : array (0 .. 4) of Int_Array (0 .. 9) :=
(others => (others => 0));
begin
Ada.Integer_Text_IO.Default_Width := 0;
for i in lims'Range loop
declare
nDigits, dDigits : Int_Array (0 .. i + 1);
digit, dix, rn, rd : Integer;
begin
for n in lims(i)(0) .. lims(i)(1) loop
nDigits := (others => 0);
if getDigits(n, i + 2, nDigits) then
for d in n + 1 .. lims(i)(1) + 1 loop
dDigits := (others => 0);
if getDigits(d, i + 2, dDigits) then
for nix in nDigits'Range loop
digit := nDigits(nix);
dix := indexOf(dDigits, digit);
if dix >= 0 then
rn := removeDigit(nDigits, i + 2, nix);
rd := removeDigit(dDigits, i + 2, dix);
if n*rd = rn*d then
count(i) := count(i) + 1;
omitted(i)(digit) :=
omitted(i)(digit) + 1;
if count(i) <= 12 then
Put (n);
Put ("/");
Put (d);
Put (" = ");
Put (rn);
Put ("/");
Put (rd);
Put (" by omitting ");
Put (digit);
Put_Line ("'s");
end if;
end if;
end if;
end loop;
end if;
end loop;
end if;
end loop;
end;
New_Line;
end loop;
for i in 2 .. 5 loop
Put ("There are ");
Put (count(i - 2));
Put (" ");
Put (i);
Put_Line ("-digit fractions of which:");
for j in 1 .. 9 loop
if omitted(i - 2)(j) /= 0 then
Put (omitted(i - 2)(j), Width => 6);
Put (" have ");
Put (j);
Put_Line ("'s omitted");
end if;
end loop;
New_Line;
end loop;
end Fraction_Reduction;
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Port the provided Ada code into Java while preserving the original functionality. | with Ada.Integer_Text_IO; use Ada.Integer_Text_IO;
with Ada.Text_IO; use Ada.Text_IO;
procedure Fraction_Reduction is
type Int_Array is array (Natural range <>) of Integer;
function indexOf(haystack : Int_Array; needle : Integer) return Integer is
idx : Integer := 0;
begin
for straw of haystack loop
if straw = needle then
return idx;
else
idx := idx + 1;
end if;
end loop;
return -1;
end IndexOf;
function getDigits(n, le : in Integer;
digit_array : in out Int_Array) return Boolean is
n_local : Integer := n;
le_local : Integer := le;
r : Integer;
begin
while n_local > 0 loop
r := n_local mod 10;
if r = 0 or indexOf(digit_array, r) >= 0 then
return False;
end if;
le_local := le_local - 1;
digit_array(le_local) := r;
n_local := n_local / 10;
end loop;
return True;
end getDigits;
function removeDigit(digit_array : Int_Array;
le, idx : Integer) return Integer is
sum : Integer := 0;
pow : Integer := 10 ** (le - 2);
begin
for i in 0 .. le - 1 loop
if i /= idx then
sum := sum + digit_array(i) * pow;
pow := pow / 10;
end if;
end loop;
return sum;
end removeDigit;
lims : constant array (0 .. 3) of Int_Array (0 .. 1) :=
((12, 97), (123, 986), (1234, 9875), (12345, 98764));
count : Int_Array (0 .. 4) := (others => 0);
omitted : array (0 .. 4) of Int_Array (0 .. 9) :=
(others => (others => 0));
begin
Ada.Integer_Text_IO.Default_Width := 0;
for i in lims'Range loop
declare
nDigits, dDigits : Int_Array (0 .. i + 1);
digit, dix, rn, rd : Integer;
begin
for n in lims(i)(0) .. lims(i)(1) loop
nDigits := (others => 0);
if getDigits(n, i + 2, nDigits) then
for d in n + 1 .. lims(i)(1) + 1 loop
dDigits := (others => 0);
if getDigits(d, i + 2, dDigits) then
for nix in nDigits'Range loop
digit := nDigits(nix);
dix := indexOf(dDigits, digit);
if dix >= 0 then
rn := removeDigit(nDigits, i + 2, nix);
rd := removeDigit(dDigits, i + 2, dix);
if n*rd = rn*d then
count(i) := count(i) + 1;
omitted(i)(digit) :=
omitted(i)(digit) + 1;
if count(i) <= 12 then
Put (n);
Put ("/");
Put (d);
Put (" = ");
Put (rn);
Put ("/");
Put (rd);
Put (" by omitting ");
Put (digit);
Put_Line ("'s");
end if;
end if;
end if;
end loop;
end if;
end loop;
end if;
end loop;
end;
New_Line;
end loop;
for i in 2 .. 5 loop
Put ("There are ");
Put (count(i - 2));
Put (" ");
Put (i);
Put_Line ("-digit fractions of which:");
for j in 1 .. 9 loop
if omitted(i - 2)(j) /= 0 then
Put (omitted(i - 2)(j), Width => 6);
Put (" have ");
Put (j);
Put_Line ("'s omitted");
end if;
end loop;
New_Line;
end loop;
end Fraction_Reduction;
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Keep all operations the same but rewrite the snippet in Python. | with Ada.Integer_Text_IO; use Ada.Integer_Text_IO;
with Ada.Text_IO; use Ada.Text_IO;
procedure Fraction_Reduction is
type Int_Array is array (Natural range <>) of Integer;
function indexOf(haystack : Int_Array; needle : Integer) return Integer is
idx : Integer := 0;
begin
for straw of haystack loop
if straw = needle then
return idx;
else
idx := idx + 1;
end if;
end loop;
return -1;
end IndexOf;
function getDigits(n, le : in Integer;
digit_array : in out Int_Array) return Boolean is
n_local : Integer := n;
le_local : Integer := le;
r : Integer;
begin
while n_local > 0 loop
r := n_local mod 10;
if r = 0 or indexOf(digit_array, r) >= 0 then
return False;
end if;
le_local := le_local - 1;
digit_array(le_local) := r;
n_local := n_local / 10;
end loop;
return True;
end getDigits;
function removeDigit(digit_array : Int_Array;
le, idx : Integer) return Integer is
sum : Integer := 0;
pow : Integer := 10 ** (le - 2);
begin
for i in 0 .. le - 1 loop
if i /= idx then
sum := sum + digit_array(i) * pow;
pow := pow / 10;
end if;
end loop;
return sum;
end removeDigit;
lims : constant array (0 .. 3) of Int_Array (0 .. 1) :=
((12, 97), (123, 986), (1234, 9875), (12345, 98764));
count : Int_Array (0 .. 4) := (others => 0);
omitted : array (0 .. 4) of Int_Array (0 .. 9) :=
(others => (others => 0));
begin
Ada.Integer_Text_IO.Default_Width := 0;
for i in lims'Range loop
declare
nDigits, dDigits : Int_Array (0 .. i + 1);
digit, dix, rn, rd : Integer;
begin
for n in lims(i)(0) .. lims(i)(1) loop
nDigits := (others => 0);
if getDigits(n, i + 2, nDigits) then
for d in n + 1 .. lims(i)(1) + 1 loop
dDigits := (others => 0);
if getDigits(d, i + 2, dDigits) then
for nix in nDigits'Range loop
digit := nDigits(nix);
dix := indexOf(dDigits, digit);
if dix >= 0 then
rn := removeDigit(nDigits, i + 2, nix);
rd := removeDigit(dDigits, i + 2, dix);
if n*rd = rn*d then
count(i) := count(i) + 1;
omitted(i)(digit) :=
omitted(i)(digit) + 1;
if count(i) <= 12 then
Put (n);
Put ("/");
Put (d);
Put (" = ");
Put (rn);
Put ("/");
Put (rd);
Put (" by omitting ");
Put (digit);
Put_Line ("'s");
end if;
end if;
end if;
end loop;
end if;
end loop;
end if;
end loop;
end;
New_Line;
end loop;
for i in 2 .. 5 loop
Put ("There are ");
Put (count(i - 2));
Put (" ");
Put (i);
Put_Line ("-digit fractions of which:");
for j in 1 .. 9 loop
if omitted(i - 2)(j) /= 0 then
Put (omitted(i - 2)(j), Width => 6);
Put (" have ");
Put (j);
Put_Line ("'s omitted");
end if;
end loop;
New_Line;
end loop;
end Fraction_Reduction;
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Translate this program into VB but keep the logic exactly as in Ada. | with Ada.Integer_Text_IO; use Ada.Integer_Text_IO;
with Ada.Text_IO; use Ada.Text_IO;
procedure Fraction_Reduction is
type Int_Array is array (Natural range <>) of Integer;
function indexOf(haystack : Int_Array; needle : Integer) return Integer is
idx : Integer := 0;
begin
for straw of haystack loop
if straw = needle then
return idx;
else
idx := idx + 1;
end if;
end loop;
return -1;
end IndexOf;
function getDigits(n, le : in Integer;
digit_array : in out Int_Array) return Boolean is
n_local : Integer := n;
le_local : Integer := le;
r : Integer;
begin
while n_local > 0 loop
r := n_local mod 10;
if r = 0 or indexOf(digit_array, r) >= 0 then
return False;
end if;
le_local := le_local - 1;
digit_array(le_local) := r;
n_local := n_local / 10;
end loop;
return True;
end getDigits;
function removeDigit(digit_array : Int_Array;
le, idx : Integer) return Integer is
sum : Integer := 0;
pow : Integer := 10 ** (le - 2);
begin
for i in 0 .. le - 1 loop
if i /= idx then
sum := sum + digit_array(i) * pow;
pow := pow / 10;
end if;
end loop;
return sum;
end removeDigit;
lims : constant array (0 .. 3) of Int_Array (0 .. 1) :=
((12, 97), (123, 986), (1234, 9875), (12345, 98764));
count : Int_Array (0 .. 4) := (others => 0);
omitted : array (0 .. 4) of Int_Array (0 .. 9) :=
(others => (others => 0));
begin
Ada.Integer_Text_IO.Default_Width := 0;
for i in lims'Range loop
declare
nDigits, dDigits : Int_Array (0 .. i + 1);
digit, dix, rn, rd : Integer;
begin
for n in lims(i)(0) .. lims(i)(1) loop
nDigits := (others => 0);
if getDigits(n, i + 2, nDigits) then
for d in n + 1 .. lims(i)(1) + 1 loop
dDigits := (others => 0);
if getDigits(d, i + 2, dDigits) then
for nix in nDigits'Range loop
digit := nDigits(nix);
dix := indexOf(dDigits, digit);
if dix >= 0 then
rn := removeDigit(nDigits, i + 2, nix);
rd := removeDigit(dDigits, i + 2, dix);
if n*rd = rn*d then
count(i) := count(i) + 1;
omitted(i)(digit) :=
omitted(i)(digit) + 1;
if count(i) <= 12 then
Put (n);
Put ("/");
Put (d);
Put (" = ");
Put (rn);
Put ("/");
Put (rd);
Put (" by omitting ");
Put (digit);
Put_Line ("'s");
end if;
end if;
end if;
end loop;
end if;
end loop;
end if;
end loop;
end;
New_Line;
end loop;
for i in 2 .. 5 loop
Put ("There are ");
Put (count(i - 2));
Put (" ");
Put (i);
Put_Line ("-digit fractions of which:");
for j in 1 .. 9 loop
if omitted(i - 2)(j) /= 0 then
Put (omitted(i - 2)(j), Width => 6);
Put (" have ");
Put (j);
Put_Line ("'s omitted");
end if;
end loop;
New_Line;
end loop;
end Fraction_Reduction;
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Generate an equivalent C version of this D code. | import std.range;
import std.stdio;
int indexOf(Range, Element)(Range haystack, scope Element needle)
if (isInputRange!Range) {
int idx;
foreach (straw; haystack) {
if (straw == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, int[] digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(int[] digits, int le, int idx) {
enum pows = [ 1, 10, 100, 1_000, 10_000 ];
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
void main() {
auto lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ];
int[5] count;
int[10][5] omitted;
for (int i = 0; i < lims.length; i++) {
auto nDigits = new int[i + 2];
auto dDigits = new int[i + 2];
for (int n = lims[i][0]; n <= lims[i][1]; n++) {
nDigits[] = 0;
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i][1] + 1; d++) {
dDigits[] = 0;
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.length; nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if (cast(double)n / d == cast(double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
writefln("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit);
}
}
}
}
}
}
writeln;
}
for (int i = 2; i <= 5; i++) {
writefln("There are %d %d-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
writefln("%6s have %d's omitted", omitted[i - 2][j], j);
}
writeln;
}
}
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Convert this D snippet to C# and keep its semantics consistent. | import std.range;
import std.stdio;
int indexOf(Range, Element)(Range haystack, scope Element needle)
if (isInputRange!Range) {
int idx;
foreach (straw; haystack) {
if (straw == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, int[] digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(int[] digits, int le, int idx) {
enum pows = [ 1, 10, 100, 1_000, 10_000 ];
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
void main() {
auto lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ];
int[5] count;
int[10][5] omitted;
for (int i = 0; i < lims.length; i++) {
auto nDigits = new int[i + 2];
auto dDigits = new int[i + 2];
for (int n = lims[i][0]; n <= lims[i][1]; n++) {
nDigits[] = 0;
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i][1] + 1; d++) {
dDigits[] = 0;
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.length; nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if (cast(double)n / d == cast(double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
writefln("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit);
}
}
}
}
}
}
writeln;
}
for (int i = 2; i <= 5; i++) {
writefln("There are %d %d-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
writefln("%6s have %d's omitted", omitted[i - 2][j], j);
}
writeln;
}
}
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Generate an equivalent C++ version of this D code. | import std.range;
import std.stdio;
int indexOf(Range, Element)(Range haystack, scope Element needle)
if (isInputRange!Range) {
int idx;
foreach (straw; haystack) {
if (straw == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, int[] digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(int[] digits, int le, int idx) {
enum pows = [ 1, 10, 100, 1_000, 10_000 ];
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
void main() {
auto lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ];
int[5] count;
int[10][5] omitted;
for (int i = 0; i < lims.length; i++) {
auto nDigits = new int[i + 2];
auto dDigits = new int[i + 2];
for (int n = lims[i][0]; n <= lims[i][1]; n++) {
nDigits[] = 0;
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i][1] + 1; d++) {
dDigits[] = 0;
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.length; nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if (cast(double)n / d == cast(double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
writefln("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit);
}
}
}
}
}
}
writeln;
}
for (int i = 2; i <= 5; i++) {
writefln("There are %d %d-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
writefln("%6s have %d's omitted", omitted[i - 2][j], j);
}
writeln;
}
}
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Port the provided D code into Java while preserving the original functionality. | import std.range;
import std.stdio;
int indexOf(Range, Element)(Range haystack, scope Element needle)
if (isInputRange!Range) {
int idx;
foreach (straw; haystack) {
if (straw == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, int[] digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(int[] digits, int le, int idx) {
enum pows = [ 1, 10, 100, 1_000, 10_000 ];
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
void main() {
auto lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ];
int[5] count;
int[10][5] omitted;
for (int i = 0; i < lims.length; i++) {
auto nDigits = new int[i + 2];
auto dDigits = new int[i + 2];
for (int n = lims[i][0]; n <= lims[i][1]; n++) {
nDigits[] = 0;
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i][1] + 1; d++) {
dDigits[] = 0;
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.length; nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if (cast(double)n / d == cast(double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
writefln("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit);
}
}
}
}
}
}
writeln;
}
for (int i = 2; i <= 5; i++) {
writefln("There are %d %d-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
writefln("%6s have %d's omitted", omitted[i - 2][j], j);
}
writeln;
}
}
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Change the programming language of this snippet from D to Python without modifying what it does. | import std.range;
import std.stdio;
int indexOf(Range, Element)(Range haystack, scope Element needle)
if (isInputRange!Range) {
int idx;
foreach (straw; haystack) {
if (straw == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, int[] digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(int[] digits, int le, int idx) {
enum pows = [ 1, 10, 100, 1_000, 10_000 ];
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
void main() {
auto lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ];
int[5] count;
int[10][5] omitted;
for (int i = 0; i < lims.length; i++) {
auto nDigits = new int[i + 2];
auto dDigits = new int[i + 2];
for (int n = lims[i][0]; n <= lims[i][1]; n++) {
nDigits[] = 0;
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i][1] + 1; d++) {
dDigits[] = 0;
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.length; nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if (cast(double)n / d == cast(double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
writefln("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit);
}
}
}
}
}
}
writeln;
}
for (int i = 2; i <= 5; i++) {
writefln("There are %d %d-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
writefln("%6s have %d's omitted", omitted[i - 2][j], j);
}
writeln;
}
}
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Write the same algorithm in VB as shown in this D implementation. | import std.range;
import std.stdio;
int indexOf(Range, Element)(Range haystack, scope Element needle)
if (isInputRange!Range) {
int idx;
foreach (straw; haystack) {
if (straw == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, int[] digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(int[] digits, int le, int idx) {
enum pows = [ 1, 10, 100, 1_000, 10_000 ];
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
void main() {
auto lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ];
int[5] count;
int[10][5] omitted;
for (int i = 0; i < lims.length; i++) {
auto nDigits = new int[i + 2];
auto dDigits = new int[i + 2];
for (int n = lims[i][0]; n <= lims[i][1]; n++) {
nDigits[] = 0;
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i][1] + 1; d++) {
dDigits[] = 0;
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.length; nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if (cast(double)n / d == cast(double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
writefln("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit);
}
}
}
}
}
}
writeln;
}
for (int i = 2; i <= 5; i++) {
writefln("There are %d %d-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
writefln("%6s have %d's omitted", omitted[i - 2][j], j);
}
writeln;
}
}
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Maintain the same structure and functionality when rewriting this code in Go. | import std.range;
import std.stdio;
int indexOf(Range, Element)(Range haystack, scope Element needle)
if (isInputRange!Range) {
int idx;
foreach (straw; haystack) {
if (straw == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, int[] digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(int[] digits, int le, int idx) {
enum pows = [ 1, 10, 100, 1_000, 10_000 ];
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
void main() {
auto lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ];
int[5] count;
int[10][5] omitted;
for (int i = 0; i < lims.length; i++) {
auto nDigits = new int[i + 2];
auto dDigits = new int[i + 2];
for (int n = lims[i][0]; n <= lims[i][1]; n++) {
nDigits[] = 0;
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i][1] + 1; d++) {
dDigits[] = 0;
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.length; nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if (cast(double)n / d == cast(double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
writefln("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit);
}
}
}
}
}
}
writeln;
}
for (int i = 2; i <= 5; i++) {
writefln("There are %d %d-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
writefln("%6s have %d's omitted", omitted[i - 2][j], j);
}
writeln;
}
}
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Produce a language-to-language conversion: from Groovy to C, same semantics. | class FractionReduction {
static void main(String[] args) {
for (int size = 2; size <= 5; size++) {
reduce(size)
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits)
int min = (int) Math.pow(10, numDigits - 1)
int max = (int) Math.pow(10, numDigits) - 1
List<Integer> values = new ArrayList<>()
for (int number = min; number <= max; number++) {
if (isValid(number)) {
values.add(number)
}
}
Map<Integer, Integer> cancelCount = new HashMap<>()
int size = values.size()
int solutions = 0
for (int nIndex = 0; nIndex < size - 1; nIndex++) {
int numerator = values.get(nIndex)
for (int dIndex = nIndex + 1; dIndex < size; dIndex++) {
int denominator = values.get(dIndex)
for (int commonDigit : digitsInCommon(numerator, denominator)) {
int numRemoved = removeDigit(numerator, commonDigit)
int denRemoved = removeDigit(denominator, commonDigit)
if (numerator * denRemoved == denominator * numRemoved) {
solutions++
cancelCount.merge(commonDigit, 1, { v1, v2 -> v1 + v2 })
if (solutions <= 12) {
println(" When $commonDigit is removed, $numerator/$denominator = $numRemoved/$denRemoved")
}
}
}
}
}
println("Number of fractions where cancellation is valid = $solutions.")
List<Integer> sorted = new ArrayList<>(cancelCount.keySet())
Collections.sort(sorted)
for (int removed : sorted) {
println(" The digit $removed was removed ${cancelCount.get(removed)} times.")
}
println()
}
private static int[] powers = [1, 10, 100, 1000, 10000, 100000]
private static int removeDigit(int n, int removed) {
int m = 0
int pow = 0
while (n > 0) {
int r = n % 10
if (r != removed) {
m = m + r * powers[pow]
pow++
}
n /= 10
}
return m
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10]
List<Integer> common = new ArrayList<>()
while (n1 > 0) {
int r = n1 % 10
count[r] += 1
n1 /= 10
}
while (n2 > 0) {
int r = n2 % 10
if (count[r] > 0) {
common.add(r)
}
n2 /= 10
}
return common
}
private static boolean isValid(int num) {
int[] count = new int[10]
while (num > 0) {
int r = num % 10
if (r == 0 || count[r] == 1) {
return false
}
count[r] = 1
num /= 10
}
return true
}
}
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Rewrite this program in C# while keeping its functionality equivalent to the Groovy version. | class FractionReduction {
static void main(String[] args) {
for (int size = 2; size <= 5; size++) {
reduce(size)
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits)
int min = (int) Math.pow(10, numDigits - 1)
int max = (int) Math.pow(10, numDigits) - 1
List<Integer> values = new ArrayList<>()
for (int number = min; number <= max; number++) {
if (isValid(number)) {
values.add(number)
}
}
Map<Integer, Integer> cancelCount = new HashMap<>()
int size = values.size()
int solutions = 0
for (int nIndex = 0; nIndex < size - 1; nIndex++) {
int numerator = values.get(nIndex)
for (int dIndex = nIndex + 1; dIndex < size; dIndex++) {
int denominator = values.get(dIndex)
for (int commonDigit : digitsInCommon(numerator, denominator)) {
int numRemoved = removeDigit(numerator, commonDigit)
int denRemoved = removeDigit(denominator, commonDigit)
if (numerator * denRemoved == denominator * numRemoved) {
solutions++
cancelCount.merge(commonDigit, 1, { v1, v2 -> v1 + v2 })
if (solutions <= 12) {
println(" When $commonDigit is removed, $numerator/$denominator = $numRemoved/$denRemoved")
}
}
}
}
}
println("Number of fractions where cancellation is valid = $solutions.")
List<Integer> sorted = new ArrayList<>(cancelCount.keySet())
Collections.sort(sorted)
for (int removed : sorted) {
println(" The digit $removed was removed ${cancelCount.get(removed)} times.")
}
println()
}
private static int[] powers = [1, 10, 100, 1000, 10000, 100000]
private static int removeDigit(int n, int removed) {
int m = 0
int pow = 0
while (n > 0) {
int r = n % 10
if (r != removed) {
m = m + r * powers[pow]
pow++
}
n /= 10
}
return m
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10]
List<Integer> common = new ArrayList<>()
while (n1 > 0) {
int r = n1 % 10
count[r] += 1
n1 /= 10
}
while (n2 > 0) {
int r = n2 % 10
if (count[r] > 0) {
common.add(r)
}
n2 /= 10
}
return common
}
private static boolean isValid(int num) {
int[] count = new int[10]
while (num > 0) {
int r = num % 10
if (r == 0 || count[r] == 1) {
return false
}
count[r] = 1
num /= 10
}
return true
}
}
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Keep all operations the same but rewrite the snippet in C++. | class FractionReduction {
static void main(String[] args) {
for (int size = 2; size <= 5; size++) {
reduce(size)
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits)
int min = (int) Math.pow(10, numDigits - 1)
int max = (int) Math.pow(10, numDigits) - 1
List<Integer> values = new ArrayList<>()
for (int number = min; number <= max; number++) {
if (isValid(number)) {
values.add(number)
}
}
Map<Integer, Integer> cancelCount = new HashMap<>()
int size = values.size()
int solutions = 0
for (int nIndex = 0; nIndex < size - 1; nIndex++) {
int numerator = values.get(nIndex)
for (int dIndex = nIndex + 1; dIndex < size; dIndex++) {
int denominator = values.get(dIndex)
for (int commonDigit : digitsInCommon(numerator, denominator)) {
int numRemoved = removeDigit(numerator, commonDigit)
int denRemoved = removeDigit(denominator, commonDigit)
if (numerator * denRemoved == denominator * numRemoved) {
solutions++
cancelCount.merge(commonDigit, 1, { v1, v2 -> v1 + v2 })
if (solutions <= 12) {
println(" When $commonDigit is removed, $numerator/$denominator = $numRemoved/$denRemoved")
}
}
}
}
}
println("Number of fractions where cancellation is valid = $solutions.")
List<Integer> sorted = new ArrayList<>(cancelCount.keySet())
Collections.sort(sorted)
for (int removed : sorted) {
println(" The digit $removed was removed ${cancelCount.get(removed)} times.")
}
println()
}
private static int[] powers = [1, 10, 100, 1000, 10000, 100000]
private static int removeDigit(int n, int removed) {
int m = 0
int pow = 0
while (n > 0) {
int r = n % 10
if (r != removed) {
m = m + r * powers[pow]
pow++
}
n /= 10
}
return m
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10]
List<Integer> common = new ArrayList<>()
while (n1 > 0) {
int r = n1 % 10
count[r] += 1
n1 /= 10
}
while (n2 > 0) {
int r = n2 % 10
if (count[r] > 0) {
common.add(r)
}
n2 /= 10
}
return common
}
private static boolean isValid(int num) {
int[] count = new int[10]
while (num > 0) {
int r = num % 10
if (r == 0 || count[r] == 1) {
return false
}
count[r] = 1
num /= 10
}
return true
}
}
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Keep all operations the same but rewrite the snippet in Java. | class FractionReduction {
static void main(String[] args) {
for (int size = 2; size <= 5; size++) {
reduce(size)
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits)
int min = (int) Math.pow(10, numDigits - 1)
int max = (int) Math.pow(10, numDigits) - 1
List<Integer> values = new ArrayList<>()
for (int number = min; number <= max; number++) {
if (isValid(number)) {
values.add(number)
}
}
Map<Integer, Integer> cancelCount = new HashMap<>()
int size = values.size()
int solutions = 0
for (int nIndex = 0; nIndex < size - 1; nIndex++) {
int numerator = values.get(nIndex)
for (int dIndex = nIndex + 1; dIndex < size; dIndex++) {
int denominator = values.get(dIndex)
for (int commonDigit : digitsInCommon(numerator, denominator)) {
int numRemoved = removeDigit(numerator, commonDigit)
int denRemoved = removeDigit(denominator, commonDigit)
if (numerator * denRemoved == denominator * numRemoved) {
solutions++
cancelCount.merge(commonDigit, 1, { v1, v2 -> v1 + v2 })
if (solutions <= 12) {
println(" When $commonDigit is removed, $numerator/$denominator = $numRemoved/$denRemoved")
}
}
}
}
}
println("Number of fractions where cancellation is valid = $solutions.")
List<Integer> sorted = new ArrayList<>(cancelCount.keySet())
Collections.sort(sorted)
for (int removed : sorted) {
println(" The digit $removed was removed ${cancelCount.get(removed)} times.")
}
println()
}
private static int[] powers = [1, 10, 100, 1000, 10000, 100000]
private static int removeDigit(int n, int removed) {
int m = 0
int pow = 0
while (n > 0) {
int r = n % 10
if (r != removed) {
m = m + r * powers[pow]
pow++
}
n /= 10
}
return m
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10]
List<Integer> common = new ArrayList<>()
while (n1 > 0) {
int r = n1 % 10
count[r] += 1
n1 /= 10
}
while (n2 > 0) {
int r = n2 % 10
if (count[r] > 0) {
common.add(r)
}
n2 /= 10
}
return common
}
private static boolean isValid(int num) {
int[] count = new int[10]
while (num > 0) {
int r = num % 10
if (r == 0 || count[r] == 1) {
return false
}
count[r] = 1
num /= 10
}
return true
}
}
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Please provide an equivalent version of this Groovy code in Python. | class FractionReduction {
static void main(String[] args) {
for (int size = 2; size <= 5; size++) {
reduce(size)
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits)
int min = (int) Math.pow(10, numDigits - 1)
int max = (int) Math.pow(10, numDigits) - 1
List<Integer> values = new ArrayList<>()
for (int number = min; number <= max; number++) {
if (isValid(number)) {
values.add(number)
}
}
Map<Integer, Integer> cancelCount = new HashMap<>()
int size = values.size()
int solutions = 0
for (int nIndex = 0; nIndex < size - 1; nIndex++) {
int numerator = values.get(nIndex)
for (int dIndex = nIndex + 1; dIndex < size; dIndex++) {
int denominator = values.get(dIndex)
for (int commonDigit : digitsInCommon(numerator, denominator)) {
int numRemoved = removeDigit(numerator, commonDigit)
int denRemoved = removeDigit(denominator, commonDigit)
if (numerator * denRemoved == denominator * numRemoved) {
solutions++
cancelCount.merge(commonDigit, 1, { v1, v2 -> v1 + v2 })
if (solutions <= 12) {
println(" When $commonDigit is removed, $numerator/$denominator = $numRemoved/$denRemoved")
}
}
}
}
}
println("Number of fractions where cancellation is valid = $solutions.")
List<Integer> sorted = new ArrayList<>(cancelCount.keySet())
Collections.sort(sorted)
for (int removed : sorted) {
println(" The digit $removed was removed ${cancelCount.get(removed)} times.")
}
println()
}
private static int[] powers = [1, 10, 100, 1000, 10000, 100000]
private static int removeDigit(int n, int removed) {
int m = 0
int pow = 0
while (n > 0) {
int r = n % 10
if (r != removed) {
m = m + r * powers[pow]
pow++
}
n /= 10
}
return m
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10]
List<Integer> common = new ArrayList<>()
while (n1 > 0) {
int r = n1 % 10
count[r] += 1
n1 /= 10
}
while (n2 > 0) {
int r = n2 % 10
if (count[r] > 0) {
common.add(r)
}
n2 /= 10
}
return common
}
private static boolean isValid(int num) {
int[] count = new int[10]
while (num > 0) {
int r = num % 10
if (r == 0 || count[r] == 1) {
return false
}
count[r] = 1
num /= 10
}
return true
}
}
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Rewrite the snippet below in VB so it works the same as the original Groovy code. | class FractionReduction {
static void main(String[] args) {
for (int size = 2; size <= 5; size++) {
reduce(size)
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits)
int min = (int) Math.pow(10, numDigits - 1)
int max = (int) Math.pow(10, numDigits) - 1
List<Integer> values = new ArrayList<>()
for (int number = min; number <= max; number++) {
if (isValid(number)) {
values.add(number)
}
}
Map<Integer, Integer> cancelCount = new HashMap<>()
int size = values.size()
int solutions = 0
for (int nIndex = 0; nIndex < size - 1; nIndex++) {
int numerator = values.get(nIndex)
for (int dIndex = nIndex + 1; dIndex < size; dIndex++) {
int denominator = values.get(dIndex)
for (int commonDigit : digitsInCommon(numerator, denominator)) {
int numRemoved = removeDigit(numerator, commonDigit)
int denRemoved = removeDigit(denominator, commonDigit)
if (numerator * denRemoved == denominator * numRemoved) {
solutions++
cancelCount.merge(commonDigit, 1, { v1, v2 -> v1 + v2 })
if (solutions <= 12) {
println(" When $commonDigit is removed, $numerator/$denominator = $numRemoved/$denRemoved")
}
}
}
}
}
println("Number of fractions where cancellation is valid = $solutions.")
List<Integer> sorted = new ArrayList<>(cancelCount.keySet())
Collections.sort(sorted)
for (int removed : sorted) {
println(" The digit $removed was removed ${cancelCount.get(removed)} times.")
}
println()
}
private static int[] powers = [1, 10, 100, 1000, 10000, 100000]
private static int removeDigit(int n, int removed) {
int m = 0
int pow = 0
while (n > 0) {
int r = n % 10
if (r != removed) {
m = m + r * powers[pow]
pow++
}
n /= 10
}
return m
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10]
List<Integer> common = new ArrayList<>()
while (n1 > 0) {
int r = n1 % 10
count[r] += 1
n1 /= 10
}
while (n2 > 0) {
int r = n2 % 10
if (count[r] > 0) {
common.add(r)
}
n2 /= 10
}
return common
}
private static boolean isValid(int num) {
int[] count = new int[10]
while (num > 0) {
int r = num % 10
if (r == 0 || count[r] == 1) {
return false
}
count[r] = 1
num /= 10
}
return true
}
}
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Change the programming language of this snippet from Groovy to Go without modifying what it does. | class FractionReduction {
static void main(String[] args) {
for (int size = 2; size <= 5; size++) {
reduce(size)
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits)
int min = (int) Math.pow(10, numDigits - 1)
int max = (int) Math.pow(10, numDigits) - 1
List<Integer> values = new ArrayList<>()
for (int number = min; number <= max; number++) {
if (isValid(number)) {
values.add(number)
}
}
Map<Integer, Integer> cancelCount = new HashMap<>()
int size = values.size()
int solutions = 0
for (int nIndex = 0; nIndex < size - 1; nIndex++) {
int numerator = values.get(nIndex)
for (int dIndex = nIndex + 1; dIndex < size; dIndex++) {
int denominator = values.get(dIndex)
for (int commonDigit : digitsInCommon(numerator, denominator)) {
int numRemoved = removeDigit(numerator, commonDigit)
int denRemoved = removeDigit(denominator, commonDigit)
if (numerator * denRemoved == denominator * numRemoved) {
solutions++
cancelCount.merge(commonDigit, 1, { v1, v2 -> v1 + v2 })
if (solutions <= 12) {
println(" When $commonDigit is removed, $numerator/$denominator = $numRemoved/$denRemoved")
}
}
}
}
}
println("Number of fractions where cancellation is valid = $solutions.")
List<Integer> sorted = new ArrayList<>(cancelCount.keySet())
Collections.sort(sorted)
for (int removed : sorted) {
println(" The digit $removed was removed ${cancelCount.get(removed)} times.")
}
println()
}
private static int[] powers = [1, 10, 100, 1000, 10000, 100000]
private static int removeDigit(int n, int removed) {
int m = 0
int pow = 0
while (n > 0) {
int r = n % 10
if (r != removed) {
m = m + r * powers[pow]
pow++
}
n /= 10
}
return m
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10]
List<Integer> common = new ArrayList<>()
while (n1 > 0) {
int r = n1 % 10
count[r] += 1
n1 /= 10
}
while (n2 > 0) {
int r = n2 % 10
if (count[r] > 0) {
common.add(r)
}
n2 /= 10
}
return common
}
private static boolean isValid(int num) {
int[] count = new int[10]
while (num > 0) {
int r = num % 10
if (r == 0 || count[r] == 1) {
return false
}
count[r] = 1
num /= 10
}
return true
}
}
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Port the provided Haskell code into C while preserving the original functionality. | import Control.Monad (guard)
import Data.List (intersect, unfoldr, delete, nub, group, sort)
import Text.Printf (printf)
type Fraction = (Int, Int)
type Reduction = (Fraction, Fraction, Int)
validIntegers :: [Int] -> [Int]
validIntegers xs = [x | x <- xs, not $ hasZeros x, hasUniqueDigits x]
where
hasZeros = elem 0 . digits 10
hasUniqueDigits n = length ds == length ul
where
ds = digits 10 n
ul = nub ds
possibleFractions :: [Int] -> [Fraction]
possibleFractions = (\ys -> [(n,d) | n <- ys, d <- ys, n < d, gcd n d /= 1]) . validIntegers
digits :: Integral a => a -> a -> [a]
digits b = unfoldr (\n -> guard (n /= 0) >> pure (n `mod` b, n `div` b))
digitsToIntegral :: Integral a => [a] -> a
digitsToIntegral = sum . zipWith (*) (iterate (*10) 1)
findReductions :: Fraction -> [Reduction]
findReductions z@(n1, d1) = [ (z, (n2, d2), x)
| x <- digits 10 n1 `intersect` digits 10 d1,
let n2 = dropDigit x n1
d2 = dropDigit x d1
decimalWithDrop = realToFrac n2 / realToFrac d2,
decimalWithDrop == decimal ]
where dropDigit d = digitsToIntegral . delete d . digits 10
decimal = realToFrac n1 / realToFrac d1
findGroupReductions :: [Int] -> [Reduction]
findGroupReductions = (findReductions =<<) . possibleFractions
showReduction :: Reduction -> IO ()
showReduction ((n1,d1),(n2,d2),d) = printf "%d/%d = %d/%d by dropping %d\n" n1 d1 n2 d2 d
showCount :: [Reduction] -> Int -> IO ()
showCount xs n = do
printf "There are %d %d-digit fractions of which:\n" (length xs) n
mapM_ (uncurry (printf "%5d have %d's omitted\n")) (countReductions xs) >> printf "\n"
where
countReductions = fmap ((,) . length <*> head) . group . sort . fmap (\(_, _, x) -> x)
main :: IO ()
main = do
mapM_ (\g -> mapM_ showReduction (take 12 g) >> printf "\n") groups
mapM_ (uncurry showCount) $ zip groups [2..]
where
groups = [ findGroupReductions [10^1..99], findGroupReductions [10^2..999]
, findGroupReductions [10^3..9999], findGroupReductions [10^4..99999] ]
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Generate a C# translation of this Haskell snippet without changing its computational steps. | import Control.Monad (guard)
import Data.List (intersect, unfoldr, delete, nub, group, sort)
import Text.Printf (printf)
type Fraction = (Int, Int)
type Reduction = (Fraction, Fraction, Int)
validIntegers :: [Int] -> [Int]
validIntegers xs = [x | x <- xs, not $ hasZeros x, hasUniqueDigits x]
where
hasZeros = elem 0 . digits 10
hasUniqueDigits n = length ds == length ul
where
ds = digits 10 n
ul = nub ds
possibleFractions :: [Int] -> [Fraction]
possibleFractions = (\ys -> [(n,d) | n <- ys, d <- ys, n < d, gcd n d /= 1]) . validIntegers
digits :: Integral a => a -> a -> [a]
digits b = unfoldr (\n -> guard (n /= 0) >> pure (n `mod` b, n `div` b))
digitsToIntegral :: Integral a => [a] -> a
digitsToIntegral = sum . zipWith (*) (iterate (*10) 1)
findReductions :: Fraction -> [Reduction]
findReductions z@(n1, d1) = [ (z, (n2, d2), x)
| x <- digits 10 n1 `intersect` digits 10 d1,
let n2 = dropDigit x n1
d2 = dropDigit x d1
decimalWithDrop = realToFrac n2 / realToFrac d2,
decimalWithDrop == decimal ]
where dropDigit d = digitsToIntegral . delete d . digits 10
decimal = realToFrac n1 / realToFrac d1
findGroupReductions :: [Int] -> [Reduction]
findGroupReductions = (findReductions =<<) . possibleFractions
showReduction :: Reduction -> IO ()
showReduction ((n1,d1),(n2,d2),d) = printf "%d/%d = %d/%d by dropping %d\n" n1 d1 n2 d2 d
showCount :: [Reduction] -> Int -> IO ()
showCount xs n = do
printf "There are %d %d-digit fractions of which:\n" (length xs) n
mapM_ (uncurry (printf "%5d have %d's omitted\n")) (countReductions xs) >> printf "\n"
where
countReductions = fmap ((,) . length <*> head) . group . sort . fmap (\(_, _, x) -> x)
main :: IO ()
main = do
mapM_ (\g -> mapM_ showReduction (take 12 g) >> printf "\n") groups
mapM_ (uncurry showCount) $ zip groups [2..]
where
groups = [ findGroupReductions [10^1..99], findGroupReductions [10^2..999]
, findGroupReductions [10^3..9999], findGroupReductions [10^4..99999] ]
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Generate a C++ translation of this Haskell snippet without changing its computational steps. | import Control.Monad (guard)
import Data.List (intersect, unfoldr, delete, nub, group, sort)
import Text.Printf (printf)
type Fraction = (Int, Int)
type Reduction = (Fraction, Fraction, Int)
validIntegers :: [Int] -> [Int]
validIntegers xs = [x | x <- xs, not $ hasZeros x, hasUniqueDigits x]
where
hasZeros = elem 0 . digits 10
hasUniqueDigits n = length ds == length ul
where
ds = digits 10 n
ul = nub ds
possibleFractions :: [Int] -> [Fraction]
possibleFractions = (\ys -> [(n,d) | n <- ys, d <- ys, n < d, gcd n d /= 1]) . validIntegers
digits :: Integral a => a -> a -> [a]
digits b = unfoldr (\n -> guard (n /= 0) >> pure (n `mod` b, n `div` b))
digitsToIntegral :: Integral a => [a] -> a
digitsToIntegral = sum . zipWith (*) (iterate (*10) 1)
findReductions :: Fraction -> [Reduction]
findReductions z@(n1, d1) = [ (z, (n2, d2), x)
| x <- digits 10 n1 `intersect` digits 10 d1,
let n2 = dropDigit x n1
d2 = dropDigit x d1
decimalWithDrop = realToFrac n2 / realToFrac d2,
decimalWithDrop == decimal ]
where dropDigit d = digitsToIntegral . delete d . digits 10
decimal = realToFrac n1 / realToFrac d1
findGroupReductions :: [Int] -> [Reduction]
findGroupReductions = (findReductions =<<) . possibleFractions
showReduction :: Reduction -> IO ()
showReduction ((n1,d1),(n2,d2),d) = printf "%d/%d = %d/%d by dropping %d\n" n1 d1 n2 d2 d
showCount :: [Reduction] -> Int -> IO ()
showCount xs n = do
printf "There are %d %d-digit fractions of which:\n" (length xs) n
mapM_ (uncurry (printf "%5d have %d's omitted\n")) (countReductions xs) >> printf "\n"
where
countReductions = fmap ((,) . length <*> head) . group . sort . fmap (\(_, _, x) -> x)
main :: IO ()
main = do
mapM_ (\g -> mapM_ showReduction (take 12 g) >> printf "\n") groups
mapM_ (uncurry showCount) $ zip groups [2..]
where
groups = [ findGroupReductions [10^1..99], findGroupReductions [10^2..999]
, findGroupReductions [10^3..9999], findGroupReductions [10^4..99999] ]
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Convert this Haskell block to Java, preserving its control flow and logic. | import Control.Monad (guard)
import Data.List (intersect, unfoldr, delete, nub, group, sort)
import Text.Printf (printf)
type Fraction = (Int, Int)
type Reduction = (Fraction, Fraction, Int)
validIntegers :: [Int] -> [Int]
validIntegers xs = [x | x <- xs, not $ hasZeros x, hasUniqueDigits x]
where
hasZeros = elem 0 . digits 10
hasUniqueDigits n = length ds == length ul
where
ds = digits 10 n
ul = nub ds
possibleFractions :: [Int] -> [Fraction]
possibleFractions = (\ys -> [(n,d) | n <- ys, d <- ys, n < d, gcd n d /= 1]) . validIntegers
digits :: Integral a => a -> a -> [a]
digits b = unfoldr (\n -> guard (n /= 0) >> pure (n `mod` b, n `div` b))
digitsToIntegral :: Integral a => [a] -> a
digitsToIntegral = sum . zipWith (*) (iterate (*10) 1)
findReductions :: Fraction -> [Reduction]
findReductions z@(n1, d1) = [ (z, (n2, d2), x)
| x <- digits 10 n1 `intersect` digits 10 d1,
let n2 = dropDigit x n1
d2 = dropDigit x d1
decimalWithDrop = realToFrac n2 / realToFrac d2,
decimalWithDrop == decimal ]
where dropDigit d = digitsToIntegral . delete d . digits 10
decimal = realToFrac n1 / realToFrac d1
findGroupReductions :: [Int] -> [Reduction]
findGroupReductions = (findReductions =<<) . possibleFractions
showReduction :: Reduction -> IO ()
showReduction ((n1,d1),(n2,d2),d) = printf "%d/%d = %d/%d by dropping %d\n" n1 d1 n2 d2 d
showCount :: [Reduction] -> Int -> IO ()
showCount xs n = do
printf "There are %d %d-digit fractions of which:\n" (length xs) n
mapM_ (uncurry (printf "%5d have %d's omitted\n")) (countReductions xs) >> printf "\n"
where
countReductions = fmap ((,) . length <*> head) . group . sort . fmap (\(_, _, x) -> x)
main :: IO ()
main = do
mapM_ (\g -> mapM_ showReduction (take 12 g) >> printf "\n") groups
mapM_ (uncurry showCount) $ zip groups [2..]
where
groups = [ findGroupReductions [10^1..99], findGroupReductions [10^2..999]
, findGroupReductions [10^3..9999], findGroupReductions [10^4..99999] ]
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Produce a language-to-language conversion: from Haskell to Python, same semantics. | import Control.Monad (guard)
import Data.List (intersect, unfoldr, delete, nub, group, sort)
import Text.Printf (printf)
type Fraction = (Int, Int)
type Reduction = (Fraction, Fraction, Int)
validIntegers :: [Int] -> [Int]
validIntegers xs = [x | x <- xs, not $ hasZeros x, hasUniqueDigits x]
where
hasZeros = elem 0 . digits 10
hasUniqueDigits n = length ds == length ul
where
ds = digits 10 n
ul = nub ds
possibleFractions :: [Int] -> [Fraction]
possibleFractions = (\ys -> [(n,d) | n <- ys, d <- ys, n < d, gcd n d /= 1]) . validIntegers
digits :: Integral a => a -> a -> [a]
digits b = unfoldr (\n -> guard (n /= 0) >> pure (n `mod` b, n `div` b))
digitsToIntegral :: Integral a => [a] -> a
digitsToIntegral = sum . zipWith (*) (iterate (*10) 1)
findReductions :: Fraction -> [Reduction]
findReductions z@(n1, d1) = [ (z, (n2, d2), x)
| x <- digits 10 n1 `intersect` digits 10 d1,
let n2 = dropDigit x n1
d2 = dropDigit x d1
decimalWithDrop = realToFrac n2 / realToFrac d2,
decimalWithDrop == decimal ]
where dropDigit d = digitsToIntegral . delete d . digits 10
decimal = realToFrac n1 / realToFrac d1
findGroupReductions :: [Int] -> [Reduction]
findGroupReductions = (findReductions =<<) . possibleFractions
showReduction :: Reduction -> IO ()
showReduction ((n1,d1),(n2,d2),d) = printf "%d/%d = %d/%d by dropping %d\n" n1 d1 n2 d2 d
showCount :: [Reduction] -> Int -> IO ()
showCount xs n = do
printf "There are %d %d-digit fractions of which:\n" (length xs) n
mapM_ (uncurry (printf "%5d have %d's omitted\n")) (countReductions xs) >> printf "\n"
where
countReductions = fmap ((,) . length <*> head) . group . sort . fmap (\(_, _, x) -> x)
main :: IO ()
main = do
mapM_ (\g -> mapM_ showReduction (take 12 g) >> printf "\n") groups
mapM_ (uncurry showCount) $ zip groups [2..]
where
groups = [ findGroupReductions [10^1..99], findGroupReductions [10^2..999]
, findGroupReductions [10^3..9999], findGroupReductions [10^4..99999] ]
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Write the same code in VB as shown below in Haskell. | import Control.Monad (guard)
import Data.List (intersect, unfoldr, delete, nub, group, sort)
import Text.Printf (printf)
type Fraction = (Int, Int)
type Reduction = (Fraction, Fraction, Int)
validIntegers :: [Int] -> [Int]
validIntegers xs = [x | x <- xs, not $ hasZeros x, hasUniqueDigits x]
where
hasZeros = elem 0 . digits 10
hasUniqueDigits n = length ds == length ul
where
ds = digits 10 n
ul = nub ds
possibleFractions :: [Int] -> [Fraction]
possibleFractions = (\ys -> [(n,d) | n <- ys, d <- ys, n < d, gcd n d /= 1]) . validIntegers
digits :: Integral a => a -> a -> [a]
digits b = unfoldr (\n -> guard (n /= 0) >> pure (n `mod` b, n `div` b))
digitsToIntegral :: Integral a => [a] -> a
digitsToIntegral = sum . zipWith (*) (iterate (*10) 1)
findReductions :: Fraction -> [Reduction]
findReductions z@(n1, d1) = [ (z, (n2, d2), x)
| x <- digits 10 n1 `intersect` digits 10 d1,
let n2 = dropDigit x n1
d2 = dropDigit x d1
decimalWithDrop = realToFrac n2 / realToFrac d2,
decimalWithDrop == decimal ]
where dropDigit d = digitsToIntegral . delete d . digits 10
decimal = realToFrac n1 / realToFrac d1
findGroupReductions :: [Int] -> [Reduction]
findGroupReductions = (findReductions =<<) . possibleFractions
showReduction :: Reduction -> IO ()
showReduction ((n1,d1),(n2,d2),d) = printf "%d/%d = %d/%d by dropping %d\n" n1 d1 n2 d2 d
showCount :: [Reduction] -> Int -> IO ()
showCount xs n = do
printf "There are %d %d-digit fractions of which:\n" (length xs) n
mapM_ (uncurry (printf "%5d have %d's omitted\n")) (countReductions xs) >> printf "\n"
where
countReductions = fmap ((,) . length <*> head) . group . sort . fmap (\(_, _, x) -> x)
main :: IO ()
main = do
mapM_ (\g -> mapM_ showReduction (take 12 g) >> printf "\n") groups
mapM_ (uncurry showCount) $ zip groups [2..]
where
groups = [ findGroupReductions [10^1..99], findGroupReductions [10^2..999]
, findGroupReductions [10^3..9999], findGroupReductions [10^4..99999] ]
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Generate an equivalent Go version of this Haskell code. | import Control.Monad (guard)
import Data.List (intersect, unfoldr, delete, nub, group, sort)
import Text.Printf (printf)
type Fraction = (Int, Int)
type Reduction = (Fraction, Fraction, Int)
validIntegers :: [Int] -> [Int]
validIntegers xs = [x | x <- xs, not $ hasZeros x, hasUniqueDigits x]
where
hasZeros = elem 0 . digits 10
hasUniqueDigits n = length ds == length ul
where
ds = digits 10 n
ul = nub ds
possibleFractions :: [Int] -> [Fraction]
possibleFractions = (\ys -> [(n,d) | n <- ys, d <- ys, n < d, gcd n d /= 1]) . validIntegers
digits :: Integral a => a -> a -> [a]
digits b = unfoldr (\n -> guard (n /= 0) >> pure (n `mod` b, n `div` b))
digitsToIntegral :: Integral a => [a] -> a
digitsToIntegral = sum . zipWith (*) (iterate (*10) 1)
findReductions :: Fraction -> [Reduction]
findReductions z@(n1, d1) = [ (z, (n2, d2), x)
| x <- digits 10 n1 `intersect` digits 10 d1,
let n2 = dropDigit x n1
d2 = dropDigit x d1
decimalWithDrop = realToFrac n2 / realToFrac d2,
decimalWithDrop == decimal ]
where dropDigit d = digitsToIntegral . delete d . digits 10
decimal = realToFrac n1 / realToFrac d1
findGroupReductions :: [Int] -> [Reduction]
findGroupReductions = (findReductions =<<) . possibleFractions
showReduction :: Reduction -> IO ()
showReduction ((n1,d1),(n2,d2),d) = printf "%d/%d = %d/%d by dropping %d\n" n1 d1 n2 d2 d
showCount :: [Reduction] -> Int -> IO ()
showCount xs n = do
printf "There are %d %d-digit fractions of which:\n" (length xs) n
mapM_ (uncurry (printf "%5d have %d's omitted\n")) (countReductions xs) >> printf "\n"
where
countReductions = fmap ((,) . length <*> head) . group . sort . fmap (\(_, _, x) -> x)
main :: IO ()
main = do
mapM_ (\g -> mapM_ showReduction (take 12 g) >> printf "\n") groups
mapM_ (uncurry showCount) $ zip groups [2..]
where
groups = [ findGroupReductions [10^1..99], findGroupReductions [10^2..999]
, findGroupReductions [10^3..9999], findGroupReductions [10^4..99999] ]
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Please provide an equivalent version of this J code in C. | Filter=: (#~`)(`:6)
assert 'ac' -: 1 0 1"_ Filter 'abc'
intersect=:-.^:2
assert 'ab' -: 'abc'intersect'razb'
odometer=: (4$.$.)@:($&1)
Note 'odometer 2 3'
0 0
0 1
0 2
1 0
1 1
1 2
)
common=: 0 e. ~:
assert common 1 2 1
assert -. common 1 2 3
o=: '123456789' {~ [: -.@:common"1 Filter odometer@:(#&9)
f=: ,:"1/&g~
mask=: [: </~&i. #
av=: (([: , mask) # ,/)@:f
c=: [: common@:,/"2 Filter av
fac=: [: ([: common ,&:~.&:q:&:"./)"2 Filter c
cancellation=: monad define
NDL =. c y
ND =. ". NDL
MASK=. ([: common ,&:~.&:q:/)"1 ND
FRAC=. _2 x: MASK # ND
CANDIDATES=. MASK # NDL
rat=. , 'r'&,
result=. 0 3 $ a:
for_i. i. # CANDIDATES do.
fraction =. i { FRAC
pair=. i { CANDIDATES
for_d. intersect/ pair do.
trial=. pair -."1 d
if. fraction = _2 x: ". trial do.
result =. result , (rat/pair) ; (rat/trial) ; d
end.
end.
end.
result
)
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Convert this J snippet to C# and keep its semantics consistent. | Filter=: (#~`)(`:6)
assert 'ac' -: 1 0 1"_ Filter 'abc'
intersect=:-.^:2
assert 'ab' -: 'abc'intersect'razb'
odometer=: (4$.$.)@:($&1)
Note 'odometer 2 3'
0 0
0 1
0 2
1 0
1 1
1 2
)
common=: 0 e. ~:
assert common 1 2 1
assert -. common 1 2 3
o=: '123456789' {~ [: -.@:common"1 Filter odometer@:(#&9)
f=: ,:"1/&g~
mask=: [: </~&i. #
av=: (([: , mask) # ,/)@:f
c=: [: common@:,/"2 Filter av
fac=: [: ([: common ,&:~.&:q:&:"./)"2 Filter c
cancellation=: monad define
NDL =. c y
ND =. ". NDL
MASK=. ([: common ,&:~.&:q:/)"1 ND
FRAC=. _2 x: MASK # ND
CANDIDATES=. MASK # NDL
rat=. , 'r'&,
result=. 0 3 $ a:
for_i. i. # CANDIDATES do.
fraction =. i { FRAC
pair=. i { CANDIDATES
for_d. intersect/ pair do.
trial=. pair -."1 d
if. fraction = _2 x: ". trial do.
result =. result , (rat/pair) ; (rat/trial) ; d
end.
end.
end.
result
)
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Port the provided J code into C++ while preserving the original functionality. | Filter=: (#~`)(`:6)
assert 'ac' -: 1 0 1"_ Filter 'abc'
intersect=:-.^:2
assert 'ab' -: 'abc'intersect'razb'
odometer=: (4$.$.)@:($&1)
Note 'odometer 2 3'
0 0
0 1
0 2
1 0
1 1
1 2
)
common=: 0 e. ~:
assert common 1 2 1
assert -. common 1 2 3
o=: '123456789' {~ [: -.@:common"1 Filter odometer@:(#&9)
f=: ,:"1/&g~
mask=: [: </~&i. #
av=: (([: , mask) # ,/)@:f
c=: [: common@:,/"2 Filter av
fac=: [: ([: common ,&:~.&:q:&:"./)"2 Filter c
cancellation=: monad define
NDL =. c y
ND =. ". NDL
MASK=. ([: common ,&:~.&:q:/)"1 ND
FRAC=. _2 x: MASK # ND
CANDIDATES=. MASK # NDL
rat=. , 'r'&,
result=. 0 3 $ a:
for_i. i. # CANDIDATES do.
fraction =. i { FRAC
pair=. i { CANDIDATES
for_d. intersect/ pair do.
trial=. pair -."1 d
if. fraction = _2 x: ". trial do.
result =. result , (rat/pair) ; (rat/trial) ; d
end.
end.
end.
result
)
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Port the following code from J to Java with equivalent syntax and logic. | Filter=: (#~`)(`:6)
assert 'ac' -: 1 0 1"_ Filter 'abc'
intersect=:-.^:2
assert 'ab' -: 'abc'intersect'razb'
odometer=: (4$.$.)@:($&1)
Note 'odometer 2 3'
0 0
0 1
0 2
1 0
1 1
1 2
)
common=: 0 e. ~:
assert common 1 2 1
assert -. common 1 2 3
o=: '123456789' {~ [: -.@:common"1 Filter odometer@:(#&9)
f=: ,:"1/&g~
mask=: [: </~&i. #
av=: (([: , mask) # ,/)@:f
c=: [: common@:,/"2 Filter av
fac=: [: ([: common ,&:~.&:q:&:"./)"2 Filter c
cancellation=: monad define
NDL =. c y
ND =. ". NDL
MASK=. ([: common ,&:~.&:q:/)"1 ND
FRAC=. _2 x: MASK # ND
CANDIDATES=. MASK # NDL
rat=. , 'r'&,
result=. 0 3 $ a:
for_i. i. # CANDIDATES do.
fraction =. i { FRAC
pair=. i { CANDIDATES
for_d. intersect/ pair do.
trial=. pair -."1 d
if. fraction = _2 x: ". trial do.
result =. result , (rat/pair) ; (rat/trial) ; d
end.
end.
end.
result
)
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Translate this program into Python but keep the logic exactly as in J. | Filter=: (#~`)(`:6)
assert 'ac' -: 1 0 1"_ Filter 'abc'
intersect=:-.^:2
assert 'ab' -: 'abc'intersect'razb'
odometer=: (4$.$.)@:($&1)
Note 'odometer 2 3'
0 0
0 1
0 2
1 0
1 1
1 2
)
common=: 0 e. ~:
assert common 1 2 1
assert -. common 1 2 3
o=: '123456789' {~ [: -.@:common"1 Filter odometer@:(#&9)
f=: ,:"1/&g~
mask=: [: </~&i. #
av=: (([: , mask) # ,/)@:f
c=: [: common@:,/"2 Filter av
fac=: [: ([: common ,&:~.&:q:&:"./)"2 Filter c
cancellation=: monad define
NDL =. c y
ND =. ". NDL
MASK=. ([: common ,&:~.&:q:/)"1 ND
FRAC=. _2 x: MASK # ND
CANDIDATES=. MASK # NDL
rat=. , 'r'&,
result=. 0 3 $ a:
for_i. i. # CANDIDATES do.
fraction =. i { FRAC
pair=. i { CANDIDATES
for_d. intersect/ pair do.
trial=. pair -."1 d
if. fraction = _2 x: ". trial do.
result =. result , (rat/pair) ; (rat/trial) ; d
end.
end.
end.
result
)
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Please provide an equivalent version of this J code in VB. | Filter=: (#~`)(`:6)
assert 'ac' -: 1 0 1"_ Filter 'abc'
intersect=:-.^:2
assert 'ab' -: 'abc'intersect'razb'
odometer=: (4$.$.)@:($&1)
Note 'odometer 2 3'
0 0
0 1
0 2
1 0
1 1
1 2
)
common=: 0 e. ~:
assert common 1 2 1
assert -. common 1 2 3
o=: '123456789' {~ [: -.@:common"1 Filter odometer@:(#&9)
f=: ,:"1/&g~
mask=: [: </~&i. #
av=: (([: , mask) # ,/)@:f
c=: [: common@:,/"2 Filter av
fac=: [: ([: common ,&:~.&:q:&:"./)"2 Filter c
cancellation=: monad define
NDL =. c y
ND =. ". NDL
MASK=. ([: common ,&:~.&:q:/)"1 ND
FRAC=. _2 x: MASK # ND
CANDIDATES=. MASK # NDL
rat=. , 'r'&,
result=. 0 3 $ a:
for_i. i. # CANDIDATES do.
fraction =. i { FRAC
pair=. i { CANDIDATES
for_d. intersect/ pair do.
trial=. pair -."1 d
if. fraction = _2 x: ". trial do.
result =. result , (rat/pair) ; (rat/trial) ; d
end.
end.
end.
result
)
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Write the same algorithm in Go as shown in this J implementation. | Filter=: (#~`)(`:6)
assert 'ac' -: 1 0 1"_ Filter 'abc'
intersect=:-.^:2
assert 'ab' -: 'abc'intersect'razb'
odometer=: (4$.$.)@:($&1)
Note 'odometer 2 3'
0 0
0 1
0 2
1 0
1 1
1 2
)
common=: 0 e. ~:
assert common 1 2 1
assert -. common 1 2 3
o=: '123456789' {~ [: -.@:common"1 Filter odometer@:(#&9)
f=: ,:"1/&g~
mask=: [: </~&i. #
av=: (([: , mask) # ,/)@:f
c=: [: common@:,/"2 Filter av
fac=: [: ([: common ,&:~.&:q:&:"./)"2 Filter c
cancellation=: monad define
NDL =. c y
ND =. ". NDL
MASK=. ([: common ,&:~.&:q:/)"1 ND
FRAC=. _2 x: MASK # ND
CANDIDATES=. MASK # NDL
rat=. , 'r'&,
result=. 0 3 $ a:
for_i. i. # CANDIDATES do.
fraction =. i { FRAC
pair=. i { CANDIDATES
for_d. intersect/ pair do.
trial=. pair -."1 d
if. fraction = _2 x: ". trial do.
result =. result , (rat/pair) ; (rat/trial) ; d
end.
end.
end.
result
)
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Preserve the algorithm and functionality while converting the code from Julia to C. | using Combinatorics
toi(set) = parse(Int, join(set, ""))
drop1(c, set) = toi(filter(x -> x != c, set))
function anomalouscancellingfractions(numdigits)
ret = Vector{Tuple{Int, Int, Int, Int, Int}}()
for nset in permutations(1:9, numdigits), dset in permutations(1:9, numdigits)
if nset < dset
for c in nset
if c in dset
n, d, nn, dd = toi(nset), toi(dset), drop1(c, nset), drop1(c, dset)
if n // d == nn // dd
push!(ret, (n, d, nn, dd, c))
end
end
end
end
end
ret
end
function testfractionreduction(maxdigits=5)
for i in 2:maxdigits
results = anomalouscancellingfractions(i)
println("\nFor $i digits, there were ", length(results),
" fractions with anomalous cancellation.")
numcounts = zeros(Int, 9)
for r in results
numcounts[r[5]] += 1
end
for (j, count) in enumerate(numcounts)
count > 0 && println("The digit $j was crossed out $count times.")
end
println("Examples:")
for j in 1:min(length(results), 12)
r = results[j]
println(r[1], "/", r[2], " = ", r[3], "/", r[4], " ($(r[5]) crossed out)")
end
end
end
testfractionreduction()
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Produce a language-to-language conversion: from Julia to C#, same semantics. | using Combinatorics
toi(set) = parse(Int, join(set, ""))
drop1(c, set) = toi(filter(x -> x != c, set))
function anomalouscancellingfractions(numdigits)
ret = Vector{Tuple{Int, Int, Int, Int, Int}}()
for nset in permutations(1:9, numdigits), dset in permutations(1:9, numdigits)
if nset < dset
for c in nset
if c in dset
n, d, nn, dd = toi(nset), toi(dset), drop1(c, nset), drop1(c, dset)
if n // d == nn // dd
push!(ret, (n, d, nn, dd, c))
end
end
end
end
end
ret
end
function testfractionreduction(maxdigits=5)
for i in 2:maxdigits
results = anomalouscancellingfractions(i)
println("\nFor $i digits, there were ", length(results),
" fractions with anomalous cancellation.")
numcounts = zeros(Int, 9)
for r in results
numcounts[r[5]] += 1
end
for (j, count) in enumerate(numcounts)
count > 0 && println("The digit $j was crossed out $count times.")
end
println("Examples:")
for j in 1:min(length(results), 12)
r = results[j]
println(r[1], "/", r[2], " = ", r[3], "/", r[4], " ($(r[5]) crossed out)")
end
end
end
testfractionreduction()
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Maintain the same structure and functionality when rewriting this code in C++. | using Combinatorics
toi(set) = parse(Int, join(set, ""))
drop1(c, set) = toi(filter(x -> x != c, set))
function anomalouscancellingfractions(numdigits)
ret = Vector{Tuple{Int, Int, Int, Int, Int}}()
for nset in permutations(1:9, numdigits), dset in permutations(1:9, numdigits)
if nset < dset
for c in nset
if c in dset
n, d, nn, dd = toi(nset), toi(dset), drop1(c, nset), drop1(c, dset)
if n // d == nn // dd
push!(ret, (n, d, nn, dd, c))
end
end
end
end
end
ret
end
function testfractionreduction(maxdigits=5)
for i in 2:maxdigits
results = anomalouscancellingfractions(i)
println("\nFor $i digits, there were ", length(results),
" fractions with anomalous cancellation.")
numcounts = zeros(Int, 9)
for r in results
numcounts[r[5]] += 1
end
for (j, count) in enumerate(numcounts)
count > 0 && println("The digit $j was crossed out $count times.")
end
println("Examples:")
for j in 1:min(length(results), 12)
r = results[j]
println(r[1], "/", r[2], " = ", r[3], "/", r[4], " ($(r[5]) crossed out)")
end
end
end
testfractionreduction()
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Generate a Java translation of this Julia snippet without changing its computational steps. | using Combinatorics
toi(set) = parse(Int, join(set, ""))
drop1(c, set) = toi(filter(x -> x != c, set))
function anomalouscancellingfractions(numdigits)
ret = Vector{Tuple{Int, Int, Int, Int, Int}}()
for nset in permutations(1:9, numdigits), dset in permutations(1:9, numdigits)
if nset < dset
for c in nset
if c in dset
n, d, nn, dd = toi(nset), toi(dset), drop1(c, nset), drop1(c, dset)
if n // d == nn // dd
push!(ret, (n, d, nn, dd, c))
end
end
end
end
end
ret
end
function testfractionreduction(maxdigits=5)
for i in 2:maxdigits
results = anomalouscancellingfractions(i)
println("\nFor $i digits, there were ", length(results),
" fractions with anomalous cancellation.")
numcounts = zeros(Int, 9)
for r in results
numcounts[r[5]] += 1
end
for (j, count) in enumerate(numcounts)
count > 0 && println("The digit $j was crossed out $count times.")
end
println("Examples:")
for j in 1:min(length(results), 12)
r = results[j]
println(r[1], "/", r[2], " = ", r[3], "/", r[4], " ($(r[5]) crossed out)")
end
end
end
testfractionreduction()
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Transform the following Julia implementation into Python, maintaining the same output and logic. | using Combinatorics
toi(set) = parse(Int, join(set, ""))
drop1(c, set) = toi(filter(x -> x != c, set))
function anomalouscancellingfractions(numdigits)
ret = Vector{Tuple{Int, Int, Int, Int, Int}}()
for nset in permutations(1:9, numdigits), dset in permutations(1:9, numdigits)
if nset < dset
for c in nset
if c in dset
n, d, nn, dd = toi(nset), toi(dset), drop1(c, nset), drop1(c, dset)
if n // d == nn // dd
push!(ret, (n, d, nn, dd, c))
end
end
end
end
end
ret
end
function testfractionreduction(maxdigits=5)
for i in 2:maxdigits
results = anomalouscancellingfractions(i)
println("\nFor $i digits, there were ", length(results),
" fractions with anomalous cancellation.")
numcounts = zeros(Int, 9)
for r in results
numcounts[r[5]] += 1
end
for (j, count) in enumerate(numcounts)
count > 0 && println("The digit $j was crossed out $count times.")
end
println("Examples:")
for j in 1:min(length(results), 12)
r = results[j]
println(r[1], "/", r[2], " = ", r[3], "/", r[4], " ($(r[5]) crossed out)")
end
end
end
testfractionreduction()
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Change the programming language of this snippet from Julia to VB without modifying what it does. | using Combinatorics
toi(set) = parse(Int, join(set, ""))
drop1(c, set) = toi(filter(x -> x != c, set))
function anomalouscancellingfractions(numdigits)
ret = Vector{Tuple{Int, Int, Int, Int, Int}}()
for nset in permutations(1:9, numdigits), dset in permutations(1:9, numdigits)
if nset < dset
for c in nset
if c in dset
n, d, nn, dd = toi(nset), toi(dset), drop1(c, nset), drop1(c, dset)
if n // d == nn // dd
push!(ret, (n, d, nn, dd, c))
end
end
end
end
end
ret
end
function testfractionreduction(maxdigits=5)
for i in 2:maxdigits
results = anomalouscancellingfractions(i)
println("\nFor $i digits, there were ", length(results),
" fractions with anomalous cancellation.")
numcounts = zeros(Int, 9)
for r in results
numcounts[r[5]] += 1
end
for (j, count) in enumerate(numcounts)
count > 0 && println("The digit $j was crossed out $count times.")
end
println("Examples:")
for j in 1:min(length(results), 12)
r = results[j]
println(r[1], "/", r[2], " = ", r[3], "/", r[4], " ($(r[5]) crossed out)")
end
end
end
testfractionreduction()
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Produce a functionally identical Go code for the snippet given in Julia. | using Combinatorics
toi(set) = parse(Int, join(set, ""))
drop1(c, set) = toi(filter(x -> x != c, set))
function anomalouscancellingfractions(numdigits)
ret = Vector{Tuple{Int, Int, Int, Int, Int}}()
for nset in permutations(1:9, numdigits), dset in permutations(1:9, numdigits)
if nset < dset
for c in nset
if c in dset
n, d, nn, dd = toi(nset), toi(dset), drop1(c, nset), drop1(c, dset)
if n // d == nn // dd
push!(ret, (n, d, nn, dd, c))
end
end
end
end
end
ret
end
function testfractionreduction(maxdigits=5)
for i in 2:maxdigits
results = anomalouscancellingfractions(i)
println("\nFor $i digits, there were ", length(results),
" fractions with anomalous cancellation.")
numcounts = zeros(Int, 9)
for r in results
numcounts[r[5]] += 1
end
for (j, count) in enumerate(numcounts)
count > 0 && println("The digit $j was crossed out $count times.")
end
println("Examples:")
for j in 1:min(length(results), 12)
r = results[j]
println(r[1], "/", r[2], " = ", r[3], "/", r[4], " ($(r[5]) crossed out)")
end
end
end
testfractionreduction()
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Maintain the same structure and functionality when rewriting this code in C. | function indexOf(haystack, needle)
for idx,straw in pairs(haystack) do
if straw == needle then
return idx
end
end
return -1
end
function getDigits(n, le, digits)
while n > 0 do
local r = n % 10
if r == 0 or indexOf(digits, r) > 0 then
return false
end
le = le - 1
digits[le + 1] = r
n = math.floor(n / 10)
end
return true
end
function removeDigit(digits, le, idx)
local pows = { 1, 10, 100, 1000, 10000 }
local sum = 0
local pow = pows[le - 2 + 1]
for i = 1, le do
if i ~= idx then
sum = sum + digits[i] * pow
pow = math.floor(pow / 10)
end
end
return sum
end
function main()
local lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} }
local count = { 0, 0, 0, 0, 0 }
local omitted = {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
}
for i,_ in pairs(lims) do
local nDigits = {}
local dDigits = {}
for j = 1, i + 2 - 1 do
nDigits[j] = -1
dDigits[j] = -1
end
for n = lims[i][1], lims[i][2] do
for j,_ in pairs(nDigits) do
nDigits[j] = 0
end
local nOk = getDigits(n, i + 2 - 1, nDigits)
if nOk then
for d = n + 1, lims[i][2] + 1 do
for j,_ in pairs(dDigits) do
dDigits[j] = 0
end
local dOk = getDigits(d, i + 2 - 1, dDigits)
if dOk then
for nix,_ in pairs(nDigits) do
local digit = nDigits[nix]
local dix = indexOf(dDigits, digit)
if dix >= 0 then
local rn = removeDigit(nDigits, i + 2 - 1, nix)
local rd = removeDigit(dDigits, i + 2 - 1, dix)
if (n / d) == (rn / rd) then
count[i] = count[i] + 1
omitted[i][digit + 1] = omitted[i][digit + 1] + 1
if count[i] <= 12 then
print(string.format("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit))
end
end
end
end
end
end
end
end
print()
end
for i = 2, 5 do
print("There are "..count[i - 2 + 1].." "..i.."-digit fractions of which:")
for j = 1, 9 do
if omitted[i - 2 + 1][j + 1] > 0 then
print(string.format("%6d have %d's omitted", omitted[i - 2 + 1][j + 1], j))
end
end
print()
end
end
main()
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Maintain the same structure and functionality when rewriting this code in C#. | function indexOf(haystack, needle)
for idx,straw in pairs(haystack) do
if straw == needle then
return idx
end
end
return -1
end
function getDigits(n, le, digits)
while n > 0 do
local r = n % 10
if r == 0 or indexOf(digits, r) > 0 then
return false
end
le = le - 1
digits[le + 1] = r
n = math.floor(n / 10)
end
return true
end
function removeDigit(digits, le, idx)
local pows = { 1, 10, 100, 1000, 10000 }
local sum = 0
local pow = pows[le - 2 + 1]
for i = 1, le do
if i ~= idx then
sum = sum + digits[i] * pow
pow = math.floor(pow / 10)
end
end
return sum
end
function main()
local lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} }
local count = { 0, 0, 0, 0, 0 }
local omitted = {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
}
for i,_ in pairs(lims) do
local nDigits = {}
local dDigits = {}
for j = 1, i + 2 - 1 do
nDigits[j] = -1
dDigits[j] = -1
end
for n = lims[i][1], lims[i][2] do
for j,_ in pairs(nDigits) do
nDigits[j] = 0
end
local nOk = getDigits(n, i + 2 - 1, nDigits)
if nOk then
for d = n + 1, lims[i][2] + 1 do
for j,_ in pairs(dDigits) do
dDigits[j] = 0
end
local dOk = getDigits(d, i + 2 - 1, dDigits)
if dOk then
for nix,_ in pairs(nDigits) do
local digit = nDigits[nix]
local dix = indexOf(dDigits, digit)
if dix >= 0 then
local rn = removeDigit(nDigits, i + 2 - 1, nix)
local rd = removeDigit(dDigits, i + 2 - 1, dix)
if (n / d) == (rn / rd) then
count[i] = count[i] + 1
omitted[i][digit + 1] = omitted[i][digit + 1] + 1
if count[i] <= 12 then
print(string.format("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit))
end
end
end
end
end
end
end
end
print()
end
for i = 2, 5 do
print("There are "..count[i - 2 + 1].." "..i.."-digit fractions of which:")
for j = 1, 9 do
if omitted[i - 2 + 1][j + 1] > 0 then
print(string.format("%6d have %d's omitted", omitted[i - 2 + 1][j + 1], j))
end
end
print()
end
end
main()
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Rewrite the snippet below in C++ so it works the same as the original Lua code. | function indexOf(haystack, needle)
for idx,straw in pairs(haystack) do
if straw == needle then
return idx
end
end
return -1
end
function getDigits(n, le, digits)
while n > 0 do
local r = n % 10
if r == 0 or indexOf(digits, r) > 0 then
return false
end
le = le - 1
digits[le + 1] = r
n = math.floor(n / 10)
end
return true
end
function removeDigit(digits, le, idx)
local pows = { 1, 10, 100, 1000, 10000 }
local sum = 0
local pow = pows[le - 2 + 1]
for i = 1, le do
if i ~= idx then
sum = sum + digits[i] * pow
pow = math.floor(pow / 10)
end
end
return sum
end
function main()
local lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} }
local count = { 0, 0, 0, 0, 0 }
local omitted = {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
}
for i,_ in pairs(lims) do
local nDigits = {}
local dDigits = {}
for j = 1, i + 2 - 1 do
nDigits[j] = -1
dDigits[j] = -1
end
for n = lims[i][1], lims[i][2] do
for j,_ in pairs(nDigits) do
nDigits[j] = 0
end
local nOk = getDigits(n, i + 2 - 1, nDigits)
if nOk then
for d = n + 1, lims[i][2] + 1 do
for j,_ in pairs(dDigits) do
dDigits[j] = 0
end
local dOk = getDigits(d, i + 2 - 1, dDigits)
if dOk then
for nix,_ in pairs(nDigits) do
local digit = nDigits[nix]
local dix = indexOf(dDigits, digit)
if dix >= 0 then
local rn = removeDigit(nDigits, i + 2 - 1, nix)
local rd = removeDigit(dDigits, i + 2 - 1, dix)
if (n / d) == (rn / rd) then
count[i] = count[i] + 1
omitted[i][digit + 1] = omitted[i][digit + 1] + 1
if count[i] <= 12 then
print(string.format("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit))
end
end
end
end
end
end
end
end
print()
end
for i = 2, 5 do
print("There are "..count[i - 2 + 1].." "..i.."-digit fractions of which:")
for j = 1, 9 do
if omitted[i - 2 + 1][j + 1] > 0 then
print(string.format("%6d have %d's omitted", omitted[i - 2 + 1][j + 1], j))
end
end
print()
end
end
main()
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Preserve the algorithm and functionality while converting the code from Lua to Java. | function indexOf(haystack, needle)
for idx,straw in pairs(haystack) do
if straw == needle then
return idx
end
end
return -1
end
function getDigits(n, le, digits)
while n > 0 do
local r = n % 10
if r == 0 or indexOf(digits, r) > 0 then
return false
end
le = le - 1
digits[le + 1] = r
n = math.floor(n / 10)
end
return true
end
function removeDigit(digits, le, idx)
local pows = { 1, 10, 100, 1000, 10000 }
local sum = 0
local pow = pows[le - 2 + 1]
for i = 1, le do
if i ~= idx then
sum = sum + digits[i] * pow
pow = math.floor(pow / 10)
end
end
return sum
end
function main()
local lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} }
local count = { 0, 0, 0, 0, 0 }
local omitted = {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
}
for i,_ in pairs(lims) do
local nDigits = {}
local dDigits = {}
for j = 1, i + 2 - 1 do
nDigits[j] = -1
dDigits[j] = -1
end
for n = lims[i][1], lims[i][2] do
for j,_ in pairs(nDigits) do
nDigits[j] = 0
end
local nOk = getDigits(n, i + 2 - 1, nDigits)
if nOk then
for d = n + 1, lims[i][2] + 1 do
for j,_ in pairs(dDigits) do
dDigits[j] = 0
end
local dOk = getDigits(d, i + 2 - 1, dDigits)
if dOk then
for nix,_ in pairs(nDigits) do
local digit = nDigits[nix]
local dix = indexOf(dDigits, digit)
if dix >= 0 then
local rn = removeDigit(nDigits, i + 2 - 1, nix)
local rd = removeDigit(dDigits, i + 2 - 1, dix)
if (n / d) == (rn / rd) then
count[i] = count[i] + 1
omitted[i][digit + 1] = omitted[i][digit + 1] + 1
if count[i] <= 12 then
print(string.format("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit))
end
end
end
end
end
end
end
end
print()
end
for i = 2, 5 do
print("There are "..count[i - 2 + 1].." "..i.."-digit fractions of which:")
for j = 1, 9 do
if omitted[i - 2 + 1][j + 1] > 0 then
print(string.format("%6d have %d's omitted", omitted[i - 2 + 1][j + 1], j))
end
end
print()
end
end
main()
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Please provide an equivalent version of this Lua code in Python. | function indexOf(haystack, needle)
for idx,straw in pairs(haystack) do
if straw == needle then
return idx
end
end
return -1
end
function getDigits(n, le, digits)
while n > 0 do
local r = n % 10
if r == 0 or indexOf(digits, r) > 0 then
return false
end
le = le - 1
digits[le + 1] = r
n = math.floor(n / 10)
end
return true
end
function removeDigit(digits, le, idx)
local pows = { 1, 10, 100, 1000, 10000 }
local sum = 0
local pow = pows[le - 2 + 1]
for i = 1, le do
if i ~= idx then
sum = sum + digits[i] * pow
pow = math.floor(pow / 10)
end
end
return sum
end
function main()
local lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} }
local count = { 0, 0, 0, 0, 0 }
local omitted = {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
}
for i,_ in pairs(lims) do
local nDigits = {}
local dDigits = {}
for j = 1, i + 2 - 1 do
nDigits[j] = -1
dDigits[j] = -1
end
for n = lims[i][1], lims[i][2] do
for j,_ in pairs(nDigits) do
nDigits[j] = 0
end
local nOk = getDigits(n, i + 2 - 1, nDigits)
if nOk then
for d = n + 1, lims[i][2] + 1 do
for j,_ in pairs(dDigits) do
dDigits[j] = 0
end
local dOk = getDigits(d, i + 2 - 1, dDigits)
if dOk then
for nix,_ in pairs(nDigits) do
local digit = nDigits[nix]
local dix = indexOf(dDigits, digit)
if dix >= 0 then
local rn = removeDigit(nDigits, i + 2 - 1, nix)
local rd = removeDigit(dDigits, i + 2 - 1, dix)
if (n / d) == (rn / rd) then
count[i] = count[i] + 1
omitted[i][digit + 1] = omitted[i][digit + 1] + 1
if count[i] <= 12 then
print(string.format("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit))
end
end
end
end
end
end
end
end
print()
end
for i = 2, 5 do
print("There are "..count[i - 2 + 1].." "..i.."-digit fractions of which:")
for j = 1, 9 do
if omitted[i - 2 + 1][j + 1] > 0 then
print(string.format("%6d have %d's omitted", omitted[i - 2 + 1][j + 1], j))
end
end
print()
end
end
main()
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Write the same code in VB as shown below in Lua. | function indexOf(haystack, needle)
for idx,straw in pairs(haystack) do
if straw == needle then
return idx
end
end
return -1
end
function getDigits(n, le, digits)
while n > 0 do
local r = n % 10
if r == 0 or indexOf(digits, r) > 0 then
return false
end
le = le - 1
digits[le + 1] = r
n = math.floor(n / 10)
end
return true
end
function removeDigit(digits, le, idx)
local pows = { 1, 10, 100, 1000, 10000 }
local sum = 0
local pow = pows[le - 2 + 1]
for i = 1, le do
if i ~= idx then
sum = sum + digits[i] * pow
pow = math.floor(pow / 10)
end
end
return sum
end
function main()
local lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} }
local count = { 0, 0, 0, 0, 0 }
local omitted = {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
}
for i,_ in pairs(lims) do
local nDigits = {}
local dDigits = {}
for j = 1, i + 2 - 1 do
nDigits[j] = -1
dDigits[j] = -1
end
for n = lims[i][1], lims[i][2] do
for j,_ in pairs(nDigits) do
nDigits[j] = 0
end
local nOk = getDigits(n, i + 2 - 1, nDigits)
if nOk then
for d = n + 1, lims[i][2] + 1 do
for j,_ in pairs(dDigits) do
dDigits[j] = 0
end
local dOk = getDigits(d, i + 2 - 1, dDigits)
if dOk then
for nix,_ in pairs(nDigits) do
local digit = nDigits[nix]
local dix = indexOf(dDigits, digit)
if dix >= 0 then
local rn = removeDigit(nDigits, i + 2 - 1, nix)
local rd = removeDigit(dDigits, i + 2 - 1, dix)
if (n / d) == (rn / rd) then
count[i] = count[i] + 1
omitted[i][digit + 1] = omitted[i][digit + 1] + 1
if count[i] <= 12 then
print(string.format("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit))
end
end
end
end
end
end
end
end
print()
end
for i = 2, 5 do
print("There are "..count[i - 2 + 1].." "..i.."-digit fractions of which:")
for j = 1, 9 do
if omitted[i - 2 + 1][j + 1] > 0 then
print(string.format("%6d have %d's omitted", omitted[i - 2 + 1][j + 1], j))
end
end
print()
end
end
main()
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Generate an equivalent Go version of this Lua code. | function indexOf(haystack, needle)
for idx,straw in pairs(haystack) do
if straw == needle then
return idx
end
end
return -1
end
function getDigits(n, le, digits)
while n > 0 do
local r = n % 10
if r == 0 or indexOf(digits, r) > 0 then
return false
end
le = le - 1
digits[le + 1] = r
n = math.floor(n / 10)
end
return true
end
function removeDigit(digits, le, idx)
local pows = { 1, 10, 100, 1000, 10000 }
local sum = 0
local pow = pows[le - 2 + 1]
for i = 1, le do
if i ~= idx then
sum = sum + digits[i] * pow
pow = math.floor(pow / 10)
end
end
return sum
end
function main()
local lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} }
local count = { 0, 0, 0, 0, 0 }
local omitted = {
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
{ 0, 0, 0, 0, 0, 0, 0, 0, 0, 0 },
}
for i,_ in pairs(lims) do
local nDigits = {}
local dDigits = {}
for j = 1, i + 2 - 1 do
nDigits[j] = -1
dDigits[j] = -1
end
for n = lims[i][1], lims[i][2] do
for j,_ in pairs(nDigits) do
nDigits[j] = 0
end
local nOk = getDigits(n, i + 2 - 1, nDigits)
if nOk then
for d = n + 1, lims[i][2] + 1 do
for j,_ in pairs(dDigits) do
dDigits[j] = 0
end
local dOk = getDigits(d, i + 2 - 1, dDigits)
if dOk then
for nix,_ in pairs(nDigits) do
local digit = nDigits[nix]
local dix = indexOf(dDigits, digit)
if dix >= 0 then
local rn = removeDigit(nDigits, i + 2 - 1, nix)
local rd = removeDigit(dDigits, i + 2 - 1, dix)
if (n / d) == (rn / rd) then
count[i] = count[i] + 1
omitted[i][digit + 1] = omitted[i][digit + 1] + 1
if count[i] <= 12 then
print(string.format("%d/%d = %d/%d by omitting %d's", n, d, rn, rd, digit))
end
end
end
end
end
end
end
end
print()
end
for i = 2, 5 do
print("There are "..count[i - 2 + 1].." "..i.."-digit fractions of which:")
for j = 1, 9 do
if omitted[i - 2 + 1][j + 1] > 0 then
print(string.format("%6d have %d's omitted", omitted[i - 2 + 1][j + 1], j))
end
end
print()
end
end
main()
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Preserve the algorithm and functionality while converting the code from Mathematica to C. | ClearAll[AnomalousCancellationQ2]
AnomalousCancellationQ2[frac : {i_?Positive, j_?Positive}] :=
Module[{samedigits, idig, jdig, ff, p, q, r, tmp},
idig = IntegerDigits[i];
jdig = IntegerDigits[j];
samedigits = Intersection[idig, jdig];
ff = i/j;
If[samedigits != {},
r = {};
Do[
p = Flatten[Position[idig, s]];
q = Flatten[Position[jdig, s]];
p = FromDigits[Delete[idig, #]] & /@ p;
q = FromDigits[Delete[jdig, #]] & /@ q;
tmp = Select[Tuples[{p, q}], #[[1]]/#[[2]] == ff &];
If[Length[tmp] > 0,
r = Join[r, Join[#, {i, j, s}] & /@ tmp];
];
,
{s, samedigits}
];
r
,
{}
]
]
ijs = Select[Select[Range[1, 9999], IntegerDigits /* FreeQ[0]], IntegerDigits /* DuplicateFreeQ];
res = Reap[
Do[
Do[
num = ijs[[i]];
den = ijs[[j]];
out = AnomalousCancellationQ2[{num, den}];
If[Length[out] > 0,
Sow[out]
]
,
{i, 1, j - 1}
]
,
{j, Length[ijs]}
]
][[2, 1]];
tmp = Catenate[res];
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 2 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 3 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 4 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Rewrite this program in C++ while keeping its functionality equivalent to the Mathematica version. | ClearAll[AnomalousCancellationQ2]
AnomalousCancellationQ2[frac : {i_?Positive, j_?Positive}] :=
Module[{samedigits, idig, jdig, ff, p, q, r, tmp},
idig = IntegerDigits[i];
jdig = IntegerDigits[j];
samedigits = Intersection[idig, jdig];
ff = i/j;
If[samedigits != {},
r = {};
Do[
p = Flatten[Position[idig, s]];
q = Flatten[Position[jdig, s]];
p = FromDigits[Delete[idig, #]] & /@ p;
q = FromDigits[Delete[jdig, #]] & /@ q;
tmp = Select[Tuples[{p, q}], #[[1]]/#[[2]] == ff &];
If[Length[tmp] > 0,
r = Join[r, Join[#, {i, j, s}] & /@ tmp];
];
,
{s, samedigits}
];
r
,
{}
]
]
ijs = Select[Select[Range[1, 9999], IntegerDigits /* FreeQ[0]], IntegerDigits /* DuplicateFreeQ];
res = Reap[
Do[
Do[
num = ijs[[i]];
den = ijs[[j]];
out = AnomalousCancellationQ2[{num, den}];
If[Length[out] > 0,
Sow[out]
]
,
{i, 1, j - 1}
]
,
{j, Length[ijs]}
]
][[2, 1]];
tmp = Catenate[res];
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 2 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 3 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 4 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Ensure the translated Java code behaves exactly like the original Mathematica snippet. | ClearAll[AnomalousCancellationQ2]
AnomalousCancellationQ2[frac : {i_?Positive, j_?Positive}] :=
Module[{samedigits, idig, jdig, ff, p, q, r, tmp},
idig = IntegerDigits[i];
jdig = IntegerDigits[j];
samedigits = Intersection[idig, jdig];
ff = i/j;
If[samedigits != {},
r = {};
Do[
p = Flatten[Position[idig, s]];
q = Flatten[Position[jdig, s]];
p = FromDigits[Delete[idig, #]] & /@ p;
q = FromDigits[Delete[jdig, #]] & /@ q;
tmp = Select[Tuples[{p, q}], #[[1]]/#[[2]] == ff &];
If[Length[tmp] > 0,
r = Join[r, Join[#, {i, j, s}] & /@ tmp];
];
,
{s, samedigits}
];
r
,
{}
]
]
ijs = Select[Select[Range[1, 9999], IntegerDigits /* FreeQ[0]], IntegerDigits /* DuplicateFreeQ];
res = Reap[
Do[
Do[
num = ijs[[i]];
den = ijs[[j]];
out = AnomalousCancellationQ2[{num, den}];
If[Length[out] > 0,
Sow[out]
]
,
{i, 1, j - 1}
]
,
{j, Length[ijs]}
]
][[2, 1]];
tmp = Catenate[res];
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 2 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 3 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 4 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Rewrite the snippet below in Python so it works the same as the original Mathematica code. | ClearAll[AnomalousCancellationQ2]
AnomalousCancellationQ2[frac : {i_?Positive, j_?Positive}] :=
Module[{samedigits, idig, jdig, ff, p, q, r, tmp},
idig = IntegerDigits[i];
jdig = IntegerDigits[j];
samedigits = Intersection[idig, jdig];
ff = i/j;
If[samedigits != {},
r = {};
Do[
p = Flatten[Position[idig, s]];
q = Flatten[Position[jdig, s]];
p = FromDigits[Delete[idig, #]] & /@ p;
q = FromDigits[Delete[jdig, #]] & /@ q;
tmp = Select[Tuples[{p, q}], #[[1]]/#[[2]] == ff &];
If[Length[tmp] > 0,
r = Join[r, Join[#, {i, j, s}] & /@ tmp];
];
,
{s, samedigits}
];
r
,
{}
]
]
ijs = Select[Select[Range[1, 9999], IntegerDigits /* FreeQ[0]], IntegerDigits /* DuplicateFreeQ];
res = Reap[
Do[
Do[
num = ijs[[i]];
den = ijs[[j]];
out = AnomalousCancellationQ2[{num, den}];
If[Length[out] > 0,
Sow[out]
]
,
{i, 1, j - 1}
]
,
{j, Length[ijs]}
]
][[2, 1]];
tmp = Catenate[res];
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 2 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 3 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 4 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Maintain the same structure and functionality when rewriting this code in VB. | ClearAll[AnomalousCancellationQ2]
AnomalousCancellationQ2[frac : {i_?Positive, j_?Positive}] :=
Module[{samedigits, idig, jdig, ff, p, q, r, tmp},
idig = IntegerDigits[i];
jdig = IntegerDigits[j];
samedigits = Intersection[idig, jdig];
ff = i/j;
If[samedigits != {},
r = {};
Do[
p = Flatten[Position[idig, s]];
q = Flatten[Position[jdig, s]];
p = FromDigits[Delete[idig, #]] & /@ p;
q = FromDigits[Delete[jdig, #]] & /@ q;
tmp = Select[Tuples[{p, q}], #[[1]]/#[[2]] == ff &];
If[Length[tmp] > 0,
r = Join[r, Join[#, {i, j, s}] & /@ tmp];
];
,
{s, samedigits}
];
r
,
{}
]
]
ijs = Select[Select[Range[1, 9999], IntegerDigits /* FreeQ[0]], IntegerDigits /* DuplicateFreeQ];
res = Reap[
Do[
Do[
num = ijs[[i]];
den = ijs[[j]];
out = AnomalousCancellationQ2[{num, den}];
If[Length[out] > 0,
Sow[out]
]
,
{i, 1, j - 1}
]
,
{j, Length[ijs]}
]
][[2, 1]];
tmp = Catenate[res];
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 2 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 3 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 4 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Rewrite the snippet below in Go so it works the same as the original Mathematica code. | ClearAll[AnomalousCancellationQ2]
AnomalousCancellationQ2[frac : {i_?Positive, j_?Positive}] :=
Module[{samedigits, idig, jdig, ff, p, q, r, tmp},
idig = IntegerDigits[i];
jdig = IntegerDigits[j];
samedigits = Intersection[idig, jdig];
ff = i/j;
If[samedigits != {},
r = {};
Do[
p = Flatten[Position[idig, s]];
q = Flatten[Position[jdig, s]];
p = FromDigits[Delete[idig, #]] & /@ p;
q = FromDigits[Delete[jdig, #]] & /@ q;
tmp = Select[Tuples[{p, q}], #[[1]]/#[[2]] == ff &];
If[Length[tmp] > 0,
r = Join[r, Join[#, {i, j, s}] & /@ tmp];
];
,
{s, samedigits}
];
r
,
{}
]
]
ijs = Select[Select[Range[1, 9999], IntegerDigits /* FreeQ[0]], IntegerDigits /* DuplicateFreeQ];
res = Reap[
Do[
Do[
num = ijs[[i]];
den = ijs[[j]];
out = AnomalousCancellationQ2[{num, den}];
If[Length[out] > 0,
Sow[out]
]
,
{i, 1, j - 1}
]
,
{j, Length[ijs]}
]
][[2, 1]];
tmp = Catenate[res];
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 2 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 3 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
sel = Sort@Select[tmp, IntegerLength[#[[3]]] == IntegerLength[#[[4]]] == 4 &];
Length[sel]
t = Take[sel, UpTo[12]];
Column[Row[{#3, "/", #4, " = ", #1, "/", #2, " by removing ", #5}] & @@@ t]
SortBy[Tally[sel[[All, -1]]], First]
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Change the following Nim code into C without altering its purpose. |
import strformat
import times
type Result = tuple[n: int, nine: array[1..9, int]]
template find[T; N: static int](a: array[1..N, T]; value: T): int =
system.find(a, value) + 1
func toNumber(digits: seq[int]; removeDigit: int = 0): int =
var digits = digits
if removeDigit != 0:
let idx = digits.find(removeDigit)
digits.delete(idx)
for d in digits:
result = 10 * result + d
func nDigits(n: int): seq[Result] =
var digits = newSeq[int](n + 1)
var used: array[1..9, bool]
for i in 1..n:
digits[i] = i
used[i] = true
var terminated = false
while not terminated:
var nine: array[1..9, int]
for i in 1..9:
if used[i]:
nine[i] = digits.toNumber(i)
result &= (n: digits.toNumber(), nine: nine)
block searchLoop:
terminated = true
for i in countdown(n, 1):
let d = digits[i]
doAssert(used[d], "Encountered an inconsistency with 'used' array")
used[d] = false
for j in (d + 1)..9:
if not used[j]:
used[j] = true
digits[i] = j
for k in (i + 1)..n:
digits[k] = used.find(false)
used[digits[k]] = true
terminated = false
break searchLoop
let start = gettime()
for n in 2..6:
let rs = nDigits(n)
var count = 0
var omitted: array[1..9, int]
for i in 1..<rs.high:
let (xn, rn) = rs[i]
for j in (i + 1)..rs.high:
let (xd, rd) = rs[j]
for k in 1..9:
let yn = rn[k]
let yd = rd[k]
if yn != 0 and yd != 0 and xn * yd == yn * xd:
inc count
inc omitted[k]
if count <= 12:
echo &"{xn}/{xd} => {yn}/{yd} (removed {k})"
echo &"{n}-digit fractions found: {count}, omitted {omitted}\n"
echo &"Took {gettime() - start}"
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Rewrite the snippet below in C# so it works the same as the original Nim code. |
import strformat
import times
type Result = tuple[n: int, nine: array[1..9, int]]
template find[T; N: static int](a: array[1..N, T]; value: T): int =
system.find(a, value) + 1
func toNumber(digits: seq[int]; removeDigit: int = 0): int =
var digits = digits
if removeDigit != 0:
let idx = digits.find(removeDigit)
digits.delete(idx)
for d in digits:
result = 10 * result + d
func nDigits(n: int): seq[Result] =
var digits = newSeq[int](n + 1)
var used: array[1..9, bool]
for i in 1..n:
digits[i] = i
used[i] = true
var terminated = false
while not terminated:
var nine: array[1..9, int]
for i in 1..9:
if used[i]:
nine[i] = digits.toNumber(i)
result &= (n: digits.toNumber(), nine: nine)
block searchLoop:
terminated = true
for i in countdown(n, 1):
let d = digits[i]
doAssert(used[d], "Encountered an inconsistency with 'used' array")
used[d] = false
for j in (d + 1)..9:
if not used[j]:
used[j] = true
digits[i] = j
for k in (i + 1)..n:
digits[k] = used.find(false)
used[digits[k]] = true
terminated = false
break searchLoop
let start = gettime()
for n in 2..6:
let rs = nDigits(n)
var count = 0
var omitted: array[1..9, int]
for i in 1..<rs.high:
let (xn, rn) = rs[i]
for j in (i + 1)..rs.high:
let (xd, rd) = rs[j]
for k in 1..9:
let yn = rn[k]
let yd = rd[k]
if yn != 0 and yd != 0 and xn * yd == yn * xd:
inc count
inc omitted[k]
if count <= 12:
echo &"{xn}/{xd} => {yn}/{yd} (removed {k})"
echo &"{n}-digit fractions found: {count}, omitted {omitted}\n"
echo &"Took {gettime() - start}"
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Generate an equivalent C++ version of this Nim code. |
import strformat
import times
type Result = tuple[n: int, nine: array[1..9, int]]
template find[T; N: static int](a: array[1..N, T]; value: T): int =
system.find(a, value) + 1
func toNumber(digits: seq[int]; removeDigit: int = 0): int =
var digits = digits
if removeDigit != 0:
let idx = digits.find(removeDigit)
digits.delete(idx)
for d in digits:
result = 10 * result + d
func nDigits(n: int): seq[Result] =
var digits = newSeq[int](n + 1)
var used: array[1..9, bool]
for i in 1..n:
digits[i] = i
used[i] = true
var terminated = false
while not terminated:
var nine: array[1..9, int]
for i in 1..9:
if used[i]:
nine[i] = digits.toNumber(i)
result &= (n: digits.toNumber(), nine: nine)
block searchLoop:
terminated = true
for i in countdown(n, 1):
let d = digits[i]
doAssert(used[d], "Encountered an inconsistency with 'used' array")
used[d] = false
for j in (d + 1)..9:
if not used[j]:
used[j] = true
digits[i] = j
for k in (i + 1)..n:
digits[k] = used.find(false)
used[digits[k]] = true
terminated = false
break searchLoop
let start = gettime()
for n in 2..6:
let rs = nDigits(n)
var count = 0
var omitted: array[1..9, int]
for i in 1..<rs.high:
let (xn, rn) = rs[i]
for j in (i + 1)..rs.high:
let (xd, rd) = rs[j]
for k in 1..9:
let yn = rn[k]
let yd = rd[k]
if yn != 0 and yd != 0 and xn * yd == yn * xd:
inc count
inc omitted[k]
if count <= 12:
echo &"{xn}/{xd} => {yn}/{yd} (removed {k})"
echo &"{n}-digit fractions found: {count}, omitted {omitted}\n"
echo &"Took {gettime() - start}"
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Generate an equivalent Java version of this Nim code. |
import strformat
import times
type Result = tuple[n: int, nine: array[1..9, int]]
template find[T; N: static int](a: array[1..N, T]; value: T): int =
system.find(a, value) + 1
func toNumber(digits: seq[int]; removeDigit: int = 0): int =
var digits = digits
if removeDigit != 0:
let idx = digits.find(removeDigit)
digits.delete(idx)
for d in digits:
result = 10 * result + d
func nDigits(n: int): seq[Result] =
var digits = newSeq[int](n + 1)
var used: array[1..9, bool]
for i in 1..n:
digits[i] = i
used[i] = true
var terminated = false
while not terminated:
var nine: array[1..9, int]
for i in 1..9:
if used[i]:
nine[i] = digits.toNumber(i)
result &= (n: digits.toNumber(), nine: nine)
block searchLoop:
terminated = true
for i in countdown(n, 1):
let d = digits[i]
doAssert(used[d], "Encountered an inconsistency with 'used' array")
used[d] = false
for j in (d + 1)..9:
if not used[j]:
used[j] = true
digits[i] = j
for k in (i + 1)..n:
digits[k] = used.find(false)
used[digits[k]] = true
terminated = false
break searchLoop
let start = gettime()
for n in 2..6:
let rs = nDigits(n)
var count = 0
var omitted: array[1..9, int]
for i in 1..<rs.high:
let (xn, rn) = rs[i]
for j in (i + 1)..rs.high:
let (xd, rd) = rs[j]
for k in 1..9:
let yn = rn[k]
let yd = rd[k]
if yn != 0 and yd != 0 and xn * yd == yn * xd:
inc count
inc omitted[k]
if count <= 12:
echo &"{xn}/{xd} => {yn}/{yd} (removed {k})"
echo &"{n}-digit fractions found: {count}, omitted {omitted}\n"
echo &"Took {gettime() - start}"
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Convert the following code from Nim to Python, ensuring the logic remains intact. |
import strformat
import times
type Result = tuple[n: int, nine: array[1..9, int]]
template find[T; N: static int](a: array[1..N, T]; value: T): int =
system.find(a, value) + 1
func toNumber(digits: seq[int]; removeDigit: int = 0): int =
var digits = digits
if removeDigit != 0:
let idx = digits.find(removeDigit)
digits.delete(idx)
for d in digits:
result = 10 * result + d
func nDigits(n: int): seq[Result] =
var digits = newSeq[int](n + 1)
var used: array[1..9, bool]
for i in 1..n:
digits[i] = i
used[i] = true
var terminated = false
while not terminated:
var nine: array[1..9, int]
for i in 1..9:
if used[i]:
nine[i] = digits.toNumber(i)
result &= (n: digits.toNumber(), nine: nine)
block searchLoop:
terminated = true
for i in countdown(n, 1):
let d = digits[i]
doAssert(used[d], "Encountered an inconsistency with 'used' array")
used[d] = false
for j in (d + 1)..9:
if not used[j]:
used[j] = true
digits[i] = j
for k in (i + 1)..n:
digits[k] = used.find(false)
used[digits[k]] = true
terminated = false
break searchLoop
let start = gettime()
for n in 2..6:
let rs = nDigits(n)
var count = 0
var omitted: array[1..9, int]
for i in 1..<rs.high:
let (xn, rn) = rs[i]
for j in (i + 1)..rs.high:
let (xd, rd) = rs[j]
for k in 1..9:
let yn = rn[k]
let yd = rd[k]
if yn != 0 and yd != 0 and xn * yd == yn * xd:
inc count
inc omitted[k]
if count <= 12:
echo &"{xn}/{xd} => {yn}/{yd} (removed {k})"
echo &"{n}-digit fractions found: {count}, omitted {omitted}\n"
echo &"Took {gettime() - start}"
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Convert the following code from Nim to VB, ensuring the logic remains intact. |
import strformat
import times
type Result = tuple[n: int, nine: array[1..9, int]]
template find[T; N: static int](a: array[1..N, T]; value: T): int =
system.find(a, value) + 1
func toNumber(digits: seq[int]; removeDigit: int = 0): int =
var digits = digits
if removeDigit != 0:
let idx = digits.find(removeDigit)
digits.delete(idx)
for d in digits:
result = 10 * result + d
func nDigits(n: int): seq[Result] =
var digits = newSeq[int](n + 1)
var used: array[1..9, bool]
for i in 1..n:
digits[i] = i
used[i] = true
var terminated = false
while not terminated:
var nine: array[1..9, int]
for i in 1..9:
if used[i]:
nine[i] = digits.toNumber(i)
result &= (n: digits.toNumber(), nine: nine)
block searchLoop:
terminated = true
for i in countdown(n, 1):
let d = digits[i]
doAssert(used[d], "Encountered an inconsistency with 'used' array")
used[d] = false
for j in (d + 1)..9:
if not used[j]:
used[j] = true
digits[i] = j
for k in (i + 1)..n:
digits[k] = used.find(false)
used[digits[k]] = true
terminated = false
break searchLoop
let start = gettime()
for n in 2..6:
let rs = nDigits(n)
var count = 0
var omitted: array[1..9, int]
for i in 1..<rs.high:
let (xn, rn) = rs[i]
for j in (i + 1)..rs.high:
let (xd, rd) = rs[j]
for k in 1..9:
let yn = rn[k]
let yd = rd[k]
if yn != 0 and yd != 0 and xn * yd == yn * xd:
inc count
inc omitted[k]
if count <= 12:
echo &"{xn}/{xd} => {yn}/{yd} (removed {k})"
echo &"{n}-digit fractions found: {count}, omitted {omitted}\n"
echo &"Took {gettime() - start}"
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Write the same code in Go as shown below in Nim. |
import strformat
import times
type Result = tuple[n: int, nine: array[1..9, int]]
template find[T; N: static int](a: array[1..N, T]; value: T): int =
system.find(a, value) + 1
func toNumber(digits: seq[int]; removeDigit: int = 0): int =
var digits = digits
if removeDigit != 0:
let idx = digits.find(removeDigit)
digits.delete(idx)
for d in digits:
result = 10 * result + d
func nDigits(n: int): seq[Result] =
var digits = newSeq[int](n + 1)
var used: array[1..9, bool]
for i in 1..n:
digits[i] = i
used[i] = true
var terminated = false
while not terminated:
var nine: array[1..9, int]
for i in 1..9:
if used[i]:
nine[i] = digits.toNumber(i)
result &= (n: digits.toNumber(), nine: nine)
block searchLoop:
terminated = true
for i in countdown(n, 1):
let d = digits[i]
doAssert(used[d], "Encountered an inconsistency with 'used' array")
used[d] = false
for j in (d + 1)..9:
if not used[j]:
used[j] = true
digits[i] = j
for k in (i + 1)..n:
digits[k] = used.find(false)
used[digits[k]] = true
terminated = false
break searchLoop
let start = gettime()
for n in 2..6:
let rs = nDigits(n)
var count = 0
var omitted: array[1..9, int]
for i in 1..<rs.high:
let (xn, rn) = rs[i]
for j in (i + 1)..rs.high:
let (xd, rd) = rs[j]
for k in 1..9:
let yn = rn[k]
let yd = rd[k]
if yn != 0 and yd != 0 and xn * yd == yn * xd:
inc count
inc omitted[k]
if count <= 12:
echo &"{xn}/{xd} => {yn}/{yd} (removed {k})"
echo &"{n}-digit fractions found: {count}, omitted {omitted}\n"
echo &"Took {gettime() - start}"
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Ensure the translated C code behaves exactly like the original Pascal snippet. | program FracRedu;
uses
SysUtils;
type
tdigit = 0..9;
const
cMaskDgt: array [tdigit] of Uint32 = (1, 2, 4, 8, 16, 32, 64, 128, 256, 512
);
cMaxDigits = High(tdigit);
type
tPermfield = array[tdigit] of uint32;
tpPermfield = ^tPermfield;
tDigitCnt = array[tdigit] of Uint32;
tErg = record
numUsedDigits : Uint32;
numUnusedDigit : array[tdigit] of Uint32;
numNormal : Uint64;
dummy : array[0..7] of byte;
end;
tpErg = ^tErg;
var
Erg: array of tErg;
pf_x, pf_y: tPermfield;
DigitCnt :tDigitCnt;
permcnt, UsedDigits,Anzahl: NativeUint;
function Fakultaet(i: integer): integer;
begin
Result := 1;
while i > 1 do
begin
Result := Result * i;
Dec(i);
end;
end;
procedure OutErg(dgt: Uint32;pi,pJ:tpErg);
begin
writeln(dgt:3,' ', pi^.numUnusedDigit[dgt],'/',pj^.numUnusedDigit[dgt]
,' = ',pi^.numNormal,'/',pj^.numNormal);
end;
function Check(pI,pJ : tpErg;Nud :Word):integer;
var
dgt: NativeInt;
Begin
result := 0;
dgt := 1;
NUD := NUD SHR 1;
repeat
IF NUD AND 1 <> 0 then
Begin
If pI^.numNormal*pJ^.numUnusedDigit[dgt] = pJ^.numNormal*pI^.numUnusedDigit[dgt] then
Begin
inc(result);
inc(DigitCnt[dgt]);
IF Anzahl < 110 then
OutErg(dgt,pI,pJ);
end;
end;
inc(dgt);
NUD := NUD SHR 1;
until NUD = 0;
end;
procedure CheckWithOne(pI : tpErg;j,Nud:Uint32);
var
pJ : tpErg;
l : NativeUInt;
Begin
pJ := pI;
if UsedDigits <5 then
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
IF l <> 0 then
inc(Anzahl,Check(pI,pJ,l));
end;
end
else
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
inc(Anzahl,Check(pI,pJ,l));
end;
end;
end;
procedure SearchMultiple;
var
pI : tpErg;
i : NativeUInt;
begin
pI := @Erg[0];
for i := 0 to permcnt do
Begin
CheckWithOne(pI,i,pI^.numUsedDigits);
inc(pI);
end;
end;
function BinomCoeff(n, k: byte): longint;
var
i: longint;
begin
if k > n div 2 then
k := n - k;
Result := 1;
if k <= n then
for i := 1 to k do
Result := Result * (n - i + 1) div i;
end;
procedure InsertToErg(var E: tErg; const x: tPermfield);
var
n : Uint64;
k,i,j,dgt,nud: NativeInt;
begin
k := UsedDigits;
n := 0;
nud := 0;
for i := 1 to k do
begin
dgt := x[i];
nud := nud or cMaskDgt[dgt];
n := n * 10 + dgt;
end;
with E do
begin
numUsedDigits := nud;
numNormal := n;
end;
For J := k downto 1 do
Begin
n := 0;
for i := 1 to j-1 do
n := n * 10 + x[i];
for i := j+1 to k do
n := n * 10 + x[i];
E.numUnusedDigit[x[j]] := n;
end;
end;
procedure PermKoutofN(k, n: nativeInt);
var
x, y: tpPermfield;
i, yi, tmp: NativeInt;
begin
x := @pf_x;
y := @pf_y;
permcnt := 0;
if k > n then
k := n;
if k = n then
k := k - 1;
for i := 1 to n do
x^[i] := i;
for i := 1 to k do
y^[i] := i;
InserttoErg(Erg[permcnt], x^);
i := k;
repeat
yi := y^[i];
if yi < n then
begin
Inc(permcnt);
Inc(yi);
y^[i] := yi;
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
i := k;
InserttoErg(Erg[permcnt], x^);
end
else
begin
repeat
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
Dec(yi);
until yi <= i;
y^[i] := yi;
Dec(i);
end;
until (i = 0);
end;
procedure OutDigitCount;
var
i : tDigit;
Begin
writeln('omitted digits 1 to 9');
For i := 1 to 9do
write(DigitCnt[i]:UsedDigits);
writeln;
end;
procedure ClearDigitCount;
var
i : tDigit;
Begin
For i := low(DigitCnt) to high(DigitCnt) do
DigitCnt[i] := 0;
end;
var
t1, t0: TDateTime;
begin
For UsedDigits := 8 to 9 do
Begin
writeln('Used digits ',UsedDigits);
T0 := now;
ClearDigitCount;
setlength(Erg, Fakultaet(UsedDigits) * BinomCoeff(cMaxDigits, UsedDigits));
Anzahl := 0;
permcnt := 0;
PermKoutOfN(UsedDigits, cMaxDigits);
SearchMultiple;
T1 := now;
writeln('Found solutions ',Anzahl);
OutDigitCount;
writeln('time taken ',FormatDateTime('HH:NN:SS.zzz', T1 - T0));
setlength(Erg, 0);
writeln;
end;
end.
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Write the same code in C# as shown below in Pascal. | program FracRedu;
uses
SysUtils;
type
tdigit = 0..9;
const
cMaskDgt: array [tdigit] of Uint32 = (1, 2, 4, 8, 16, 32, 64, 128, 256, 512
);
cMaxDigits = High(tdigit);
type
tPermfield = array[tdigit] of uint32;
tpPermfield = ^tPermfield;
tDigitCnt = array[tdigit] of Uint32;
tErg = record
numUsedDigits : Uint32;
numUnusedDigit : array[tdigit] of Uint32;
numNormal : Uint64;
dummy : array[0..7] of byte;
end;
tpErg = ^tErg;
var
Erg: array of tErg;
pf_x, pf_y: tPermfield;
DigitCnt :tDigitCnt;
permcnt, UsedDigits,Anzahl: NativeUint;
function Fakultaet(i: integer): integer;
begin
Result := 1;
while i > 1 do
begin
Result := Result * i;
Dec(i);
end;
end;
procedure OutErg(dgt: Uint32;pi,pJ:tpErg);
begin
writeln(dgt:3,' ', pi^.numUnusedDigit[dgt],'/',pj^.numUnusedDigit[dgt]
,' = ',pi^.numNormal,'/',pj^.numNormal);
end;
function Check(pI,pJ : tpErg;Nud :Word):integer;
var
dgt: NativeInt;
Begin
result := 0;
dgt := 1;
NUD := NUD SHR 1;
repeat
IF NUD AND 1 <> 0 then
Begin
If pI^.numNormal*pJ^.numUnusedDigit[dgt] = pJ^.numNormal*pI^.numUnusedDigit[dgt] then
Begin
inc(result);
inc(DigitCnt[dgt]);
IF Anzahl < 110 then
OutErg(dgt,pI,pJ);
end;
end;
inc(dgt);
NUD := NUD SHR 1;
until NUD = 0;
end;
procedure CheckWithOne(pI : tpErg;j,Nud:Uint32);
var
pJ : tpErg;
l : NativeUInt;
Begin
pJ := pI;
if UsedDigits <5 then
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
IF l <> 0 then
inc(Anzahl,Check(pI,pJ,l));
end;
end
else
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
inc(Anzahl,Check(pI,pJ,l));
end;
end;
end;
procedure SearchMultiple;
var
pI : tpErg;
i : NativeUInt;
begin
pI := @Erg[0];
for i := 0 to permcnt do
Begin
CheckWithOne(pI,i,pI^.numUsedDigits);
inc(pI);
end;
end;
function BinomCoeff(n, k: byte): longint;
var
i: longint;
begin
if k > n div 2 then
k := n - k;
Result := 1;
if k <= n then
for i := 1 to k do
Result := Result * (n - i + 1) div i;
end;
procedure InsertToErg(var E: tErg; const x: tPermfield);
var
n : Uint64;
k,i,j,dgt,nud: NativeInt;
begin
k := UsedDigits;
n := 0;
nud := 0;
for i := 1 to k do
begin
dgt := x[i];
nud := nud or cMaskDgt[dgt];
n := n * 10 + dgt;
end;
with E do
begin
numUsedDigits := nud;
numNormal := n;
end;
For J := k downto 1 do
Begin
n := 0;
for i := 1 to j-1 do
n := n * 10 + x[i];
for i := j+1 to k do
n := n * 10 + x[i];
E.numUnusedDigit[x[j]] := n;
end;
end;
procedure PermKoutofN(k, n: nativeInt);
var
x, y: tpPermfield;
i, yi, tmp: NativeInt;
begin
x := @pf_x;
y := @pf_y;
permcnt := 0;
if k > n then
k := n;
if k = n then
k := k - 1;
for i := 1 to n do
x^[i] := i;
for i := 1 to k do
y^[i] := i;
InserttoErg(Erg[permcnt], x^);
i := k;
repeat
yi := y^[i];
if yi < n then
begin
Inc(permcnt);
Inc(yi);
y^[i] := yi;
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
i := k;
InserttoErg(Erg[permcnt], x^);
end
else
begin
repeat
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
Dec(yi);
until yi <= i;
y^[i] := yi;
Dec(i);
end;
until (i = 0);
end;
procedure OutDigitCount;
var
i : tDigit;
Begin
writeln('omitted digits 1 to 9');
For i := 1 to 9do
write(DigitCnt[i]:UsedDigits);
writeln;
end;
procedure ClearDigitCount;
var
i : tDigit;
Begin
For i := low(DigitCnt) to high(DigitCnt) do
DigitCnt[i] := 0;
end;
var
t1, t0: TDateTime;
begin
For UsedDigits := 8 to 9 do
Begin
writeln('Used digits ',UsedDigits);
T0 := now;
ClearDigitCount;
setlength(Erg, Fakultaet(UsedDigits) * BinomCoeff(cMaxDigits, UsedDigits));
Anzahl := 0;
permcnt := 0;
PermKoutOfN(UsedDigits, cMaxDigits);
SearchMultiple;
T1 := now;
writeln('Found solutions ',Anzahl);
OutDigitCount;
writeln('time taken ',FormatDateTime('HH:NN:SS.zzz', T1 - T0));
setlength(Erg, 0);
writeln;
end;
end.
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Generate an equivalent C++ version of this Pascal code. | program FracRedu;
uses
SysUtils;
type
tdigit = 0..9;
const
cMaskDgt: array [tdigit] of Uint32 = (1, 2, 4, 8, 16, 32, 64, 128, 256, 512
);
cMaxDigits = High(tdigit);
type
tPermfield = array[tdigit] of uint32;
tpPermfield = ^tPermfield;
tDigitCnt = array[tdigit] of Uint32;
tErg = record
numUsedDigits : Uint32;
numUnusedDigit : array[tdigit] of Uint32;
numNormal : Uint64;
dummy : array[0..7] of byte;
end;
tpErg = ^tErg;
var
Erg: array of tErg;
pf_x, pf_y: tPermfield;
DigitCnt :tDigitCnt;
permcnt, UsedDigits,Anzahl: NativeUint;
function Fakultaet(i: integer): integer;
begin
Result := 1;
while i > 1 do
begin
Result := Result * i;
Dec(i);
end;
end;
procedure OutErg(dgt: Uint32;pi,pJ:tpErg);
begin
writeln(dgt:3,' ', pi^.numUnusedDigit[dgt],'/',pj^.numUnusedDigit[dgt]
,' = ',pi^.numNormal,'/',pj^.numNormal);
end;
function Check(pI,pJ : tpErg;Nud :Word):integer;
var
dgt: NativeInt;
Begin
result := 0;
dgt := 1;
NUD := NUD SHR 1;
repeat
IF NUD AND 1 <> 0 then
Begin
If pI^.numNormal*pJ^.numUnusedDigit[dgt] = pJ^.numNormal*pI^.numUnusedDigit[dgt] then
Begin
inc(result);
inc(DigitCnt[dgt]);
IF Anzahl < 110 then
OutErg(dgt,pI,pJ);
end;
end;
inc(dgt);
NUD := NUD SHR 1;
until NUD = 0;
end;
procedure CheckWithOne(pI : tpErg;j,Nud:Uint32);
var
pJ : tpErg;
l : NativeUInt;
Begin
pJ := pI;
if UsedDigits <5 then
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
IF l <> 0 then
inc(Anzahl,Check(pI,pJ,l));
end;
end
else
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
inc(Anzahl,Check(pI,pJ,l));
end;
end;
end;
procedure SearchMultiple;
var
pI : tpErg;
i : NativeUInt;
begin
pI := @Erg[0];
for i := 0 to permcnt do
Begin
CheckWithOne(pI,i,pI^.numUsedDigits);
inc(pI);
end;
end;
function BinomCoeff(n, k: byte): longint;
var
i: longint;
begin
if k > n div 2 then
k := n - k;
Result := 1;
if k <= n then
for i := 1 to k do
Result := Result * (n - i + 1) div i;
end;
procedure InsertToErg(var E: tErg; const x: tPermfield);
var
n : Uint64;
k,i,j,dgt,nud: NativeInt;
begin
k := UsedDigits;
n := 0;
nud := 0;
for i := 1 to k do
begin
dgt := x[i];
nud := nud or cMaskDgt[dgt];
n := n * 10 + dgt;
end;
with E do
begin
numUsedDigits := nud;
numNormal := n;
end;
For J := k downto 1 do
Begin
n := 0;
for i := 1 to j-1 do
n := n * 10 + x[i];
for i := j+1 to k do
n := n * 10 + x[i];
E.numUnusedDigit[x[j]] := n;
end;
end;
procedure PermKoutofN(k, n: nativeInt);
var
x, y: tpPermfield;
i, yi, tmp: NativeInt;
begin
x := @pf_x;
y := @pf_y;
permcnt := 0;
if k > n then
k := n;
if k = n then
k := k - 1;
for i := 1 to n do
x^[i] := i;
for i := 1 to k do
y^[i] := i;
InserttoErg(Erg[permcnt], x^);
i := k;
repeat
yi := y^[i];
if yi < n then
begin
Inc(permcnt);
Inc(yi);
y^[i] := yi;
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
i := k;
InserttoErg(Erg[permcnt], x^);
end
else
begin
repeat
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
Dec(yi);
until yi <= i;
y^[i] := yi;
Dec(i);
end;
until (i = 0);
end;
procedure OutDigitCount;
var
i : tDigit;
Begin
writeln('omitted digits 1 to 9');
For i := 1 to 9do
write(DigitCnt[i]:UsedDigits);
writeln;
end;
procedure ClearDigitCount;
var
i : tDigit;
Begin
For i := low(DigitCnt) to high(DigitCnt) do
DigitCnt[i] := 0;
end;
var
t1, t0: TDateTime;
begin
For UsedDigits := 8 to 9 do
Begin
writeln('Used digits ',UsedDigits);
T0 := now;
ClearDigitCount;
setlength(Erg, Fakultaet(UsedDigits) * BinomCoeff(cMaxDigits, UsedDigits));
Anzahl := 0;
permcnt := 0;
PermKoutOfN(UsedDigits, cMaxDigits);
SearchMultiple;
T1 := now;
writeln('Found solutions ',Anzahl);
OutDigitCount;
writeln('time taken ',FormatDateTime('HH:NN:SS.zzz', T1 - T0));
setlength(Erg, 0);
writeln;
end;
end.
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Rewrite this program in Java while keeping its functionality equivalent to the Pascal version. | program FracRedu;
uses
SysUtils;
type
tdigit = 0..9;
const
cMaskDgt: array [tdigit] of Uint32 = (1, 2, 4, 8, 16, 32, 64, 128, 256, 512
);
cMaxDigits = High(tdigit);
type
tPermfield = array[tdigit] of uint32;
tpPermfield = ^tPermfield;
tDigitCnt = array[tdigit] of Uint32;
tErg = record
numUsedDigits : Uint32;
numUnusedDigit : array[tdigit] of Uint32;
numNormal : Uint64;
dummy : array[0..7] of byte;
end;
tpErg = ^tErg;
var
Erg: array of tErg;
pf_x, pf_y: tPermfield;
DigitCnt :tDigitCnt;
permcnt, UsedDigits,Anzahl: NativeUint;
function Fakultaet(i: integer): integer;
begin
Result := 1;
while i > 1 do
begin
Result := Result * i;
Dec(i);
end;
end;
procedure OutErg(dgt: Uint32;pi,pJ:tpErg);
begin
writeln(dgt:3,' ', pi^.numUnusedDigit[dgt],'/',pj^.numUnusedDigit[dgt]
,' = ',pi^.numNormal,'/',pj^.numNormal);
end;
function Check(pI,pJ : tpErg;Nud :Word):integer;
var
dgt: NativeInt;
Begin
result := 0;
dgt := 1;
NUD := NUD SHR 1;
repeat
IF NUD AND 1 <> 0 then
Begin
If pI^.numNormal*pJ^.numUnusedDigit[dgt] = pJ^.numNormal*pI^.numUnusedDigit[dgt] then
Begin
inc(result);
inc(DigitCnt[dgt]);
IF Anzahl < 110 then
OutErg(dgt,pI,pJ);
end;
end;
inc(dgt);
NUD := NUD SHR 1;
until NUD = 0;
end;
procedure CheckWithOne(pI : tpErg;j,Nud:Uint32);
var
pJ : tpErg;
l : NativeUInt;
Begin
pJ := pI;
if UsedDigits <5 then
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
IF l <> 0 then
inc(Anzahl,Check(pI,pJ,l));
end;
end
else
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
inc(Anzahl,Check(pI,pJ,l));
end;
end;
end;
procedure SearchMultiple;
var
pI : tpErg;
i : NativeUInt;
begin
pI := @Erg[0];
for i := 0 to permcnt do
Begin
CheckWithOne(pI,i,pI^.numUsedDigits);
inc(pI);
end;
end;
function BinomCoeff(n, k: byte): longint;
var
i: longint;
begin
if k > n div 2 then
k := n - k;
Result := 1;
if k <= n then
for i := 1 to k do
Result := Result * (n - i + 1) div i;
end;
procedure InsertToErg(var E: tErg; const x: tPermfield);
var
n : Uint64;
k,i,j,dgt,nud: NativeInt;
begin
k := UsedDigits;
n := 0;
nud := 0;
for i := 1 to k do
begin
dgt := x[i];
nud := nud or cMaskDgt[dgt];
n := n * 10 + dgt;
end;
with E do
begin
numUsedDigits := nud;
numNormal := n;
end;
For J := k downto 1 do
Begin
n := 0;
for i := 1 to j-1 do
n := n * 10 + x[i];
for i := j+1 to k do
n := n * 10 + x[i];
E.numUnusedDigit[x[j]] := n;
end;
end;
procedure PermKoutofN(k, n: nativeInt);
var
x, y: tpPermfield;
i, yi, tmp: NativeInt;
begin
x := @pf_x;
y := @pf_y;
permcnt := 0;
if k > n then
k := n;
if k = n then
k := k - 1;
for i := 1 to n do
x^[i] := i;
for i := 1 to k do
y^[i] := i;
InserttoErg(Erg[permcnt], x^);
i := k;
repeat
yi := y^[i];
if yi < n then
begin
Inc(permcnt);
Inc(yi);
y^[i] := yi;
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
i := k;
InserttoErg(Erg[permcnt], x^);
end
else
begin
repeat
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
Dec(yi);
until yi <= i;
y^[i] := yi;
Dec(i);
end;
until (i = 0);
end;
procedure OutDigitCount;
var
i : tDigit;
Begin
writeln('omitted digits 1 to 9');
For i := 1 to 9do
write(DigitCnt[i]:UsedDigits);
writeln;
end;
procedure ClearDigitCount;
var
i : tDigit;
Begin
For i := low(DigitCnt) to high(DigitCnt) do
DigitCnt[i] := 0;
end;
var
t1, t0: TDateTime;
begin
For UsedDigits := 8 to 9 do
Begin
writeln('Used digits ',UsedDigits);
T0 := now;
ClearDigitCount;
setlength(Erg, Fakultaet(UsedDigits) * BinomCoeff(cMaxDigits, UsedDigits));
Anzahl := 0;
permcnt := 0;
PermKoutOfN(UsedDigits, cMaxDigits);
SearchMultiple;
T1 := now;
writeln('Found solutions ',Anzahl);
OutDigitCount;
writeln('time taken ',FormatDateTime('HH:NN:SS.zzz', T1 - T0));
setlength(Erg, 0);
writeln;
end;
end.
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Can you help me rewrite this code in Python instead of Pascal, keeping it the same logically? | program FracRedu;
uses
SysUtils;
type
tdigit = 0..9;
const
cMaskDgt: array [tdigit] of Uint32 = (1, 2, 4, 8, 16, 32, 64, 128, 256, 512
);
cMaxDigits = High(tdigit);
type
tPermfield = array[tdigit] of uint32;
tpPermfield = ^tPermfield;
tDigitCnt = array[tdigit] of Uint32;
tErg = record
numUsedDigits : Uint32;
numUnusedDigit : array[tdigit] of Uint32;
numNormal : Uint64;
dummy : array[0..7] of byte;
end;
tpErg = ^tErg;
var
Erg: array of tErg;
pf_x, pf_y: tPermfield;
DigitCnt :tDigitCnt;
permcnt, UsedDigits,Anzahl: NativeUint;
function Fakultaet(i: integer): integer;
begin
Result := 1;
while i > 1 do
begin
Result := Result * i;
Dec(i);
end;
end;
procedure OutErg(dgt: Uint32;pi,pJ:tpErg);
begin
writeln(dgt:3,' ', pi^.numUnusedDigit[dgt],'/',pj^.numUnusedDigit[dgt]
,' = ',pi^.numNormal,'/',pj^.numNormal);
end;
function Check(pI,pJ : tpErg;Nud :Word):integer;
var
dgt: NativeInt;
Begin
result := 0;
dgt := 1;
NUD := NUD SHR 1;
repeat
IF NUD AND 1 <> 0 then
Begin
If pI^.numNormal*pJ^.numUnusedDigit[dgt] = pJ^.numNormal*pI^.numUnusedDigit[dgt] then
Begin
inc(result);
inc(DigitCnt[dgt]);
IF Anzahl < 110 then
OutErg(dgt,pI,pJ);
end;
end;
inc(dgt);
NUD := NUD SHR 1;
until NUD = 0;
end;
procedure CheckWithOne(pI : tpErg;j,Nud:Uint32);
var
pJ : tpErg;
l : NativeUInt;
Begin
pJ := pI;
if UsedDigits <5 then
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
IF l <> 0 then
inc(Anzahl,Check(pI,pJ,l));
end;
end
else
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
inc(Anzahl,Check(pI,pJ,l));
end;
end;
end;
procedure SearchMultiple;
var
pI : tpErg;
i : NativeUInt;
begin
pI := @Erg[0];
for i := 0 to permcnt do
Begin
CheckWithOne(pI,i,pI^.numUsedDigits);
inc(pI);
end;
end;
function BinomCoeff(n, k: byte): longint;
var
i: longint;
begin
if k > n div 2 then
k := n - k;
Result := 1;
if k <= n then
for i := 1 to k do
Result := Result * (n - i + 1) div i;
end;
procedure InsertToErg(var E: tErg; const x: tPermfield);
var
n : Uint64;
k,i,j,dgt,nud: NativeInt;
begin
k := UsedDigits;
n := 0;
nud := 0;
for i := 1 to k do
begin
dgt := x[i];
nud := nud or cMaskDgt[dgt];
n := n * 10 + dgt;
end;
with E do
begin
numUsedDigits := nud;
numNormal := n;
end;
For J := k downto 1 do
Begin
n := 0;
for i := 1 to j-1 do
n := n * 10 + x[i];
for i := j+1 to k do
n := n * 10 + x[i];
E.numUnusedDigit[x[j]] := n;
end;
end;
procedure PermKoutofN(k, n: nativeInt);
var
x, y: tpPermfield;
i, yi, tmp: NativeInt;
begin
x := @pf_x;
y := @pf_y;
permcnt := 0;
if k > n then
k := n;
if k = n then
k := k - 1;
for i := 1 to n do
x^[i] := i;
for i := 1 to k do
y^[i] := i;
InserttoErg(Erg[permcnt], x^);
i := k;
repeat
yi := y^[i];
if yi < n then
begin
Inc(permcnt);
Inc(yi);
y^[i] := yi;
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
i := k;
InserttoErg(Erg[permcnt], x^);
end
else
begin
repeat
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
Dec(yi);
until yi <= i;
y^[i] := yi;
Dec(i);
end;
until (i = 0);
end;
procedure OutDigitCount;
var
i : tDigit;
Begin
writeln('omitted digits 1 to 9');
For i := 1 to 9do
write(DigitCnt[i]:UsedDigits);
writeln;
end;
procedure ClearDigitCount;
var
i : tDigit;
Begin
For i := low(DigitCnt) to high(DigitCnt) do
DigitCnt[i] := 0;
end;
var
t1, t0: TDateTime;
begin
For UsedDigits := 8 to 9 do
Begin
writeln('Used digits ',UsedDigits);
T0 := now;
ClearDigitCount;
setlength(Erg, Fakultaet(UsedDigits) * BinomCoeff(cMaxDigits, UsedDigits));
Anzahl := 0;
permcnt := 0;
PermKoutOfN(UsedDigits, cMaxDigits);
SearchMultiple;
T1 := now;
writeln('Found solutions ',Anzahl);
OutDigitCount;
writeln('time taken ',FormatDateTime('HH:NN:SS.zzz', T1 - T0));
setlength(Erg, 0);
writeln;
end;
end.
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Translate this program into VB but keep the logic exactly as in Pascal. | program FracRedu;
uses
SysUtils;
type
tdigit = 0..9;
const
cMaskDgt: array [tdigit] of Uint32 = (1, 2, 4, 8, 16, 32, 64, 128, 256, 512
);
cMaxDigits = High(tdigit);
type
tPermfield = array[tdigit] of uint32;
tpPermfield = ^tPermfield;
tDigitCnt = array[tdigit] of Uint32;
tErg = record
numUsedDigits : Uint32;
numUnusedDigit : array[tdigit] of Uint32;
numNormal : Uint64;
dummy : array[0..7] of byte;
end;
tpErg = ^tErg;
var
Erg: array of tErg;
pf_x, pf_y: tPermfield;
DigitCnt :tDigitCnt;
permcnt, UsedDigits,Anzahl: NativeUint;
function Fakultaet(i: integer): integer;
begin
Result := 1;
while i > 1 do
begin
Result := Result * i;
Dec(i);
end;
end;
procedure OutErg(dgt: Uint32;pi,pJ:tpErg);
begin
writeln(dgt:3,' ', pi^.numUnusedDigit[dgt],'/',pj^.numUnusedDigit[dgt]
,' = ',pi^.numNormal,'/',pj^.numNormal);
end;
function Check(pI,pJ : tpErg;Nud :Word):integer;
var
dgt: NativeInt;
Begin
result := 0;
dgt := 1;
NUD := NUD SHR 1;
repeat
IF NUD AND 1 <> 0 then
Begin
If pI^.numNormal*pJ^.numUnusedDigit[dgt] = pJ^.numNormal*pI^.numUnusedDigit[dgt] then
Begin
inc(result);
inc(DigitCnt[dgt]);
IF Anzahl < 110 then
OutErg(dgt,pI,pJ);
end;
end;
inc(dgt);
NUD := NUD SHR 1;
until NUD = 0;
end;
procedure CheckWithOne(pI : tpErg;j,Nud:Uint32);
var
pJ : tpErg;
l : NativeUInt;
Begin
pJ := pI;
if UsedDigits <5 then
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
IF l <> 0 then
inc(Anzahl,Check(pI,pJ,l));
end;
end
else
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
inc(Anzahl,Check(pI,pJ,l));
end;
end;
end;
procedure SearchMultiple;
var
pI : tpErg;
i : NativeUInt;
begin
pI := @Erg[0];
for i := 0 to permcnt do
Begin
CheckWithOne(pI,i,pI^.numUsedDigits);
inc(pI);
end;
end;
function BinomCoeff(n, k: byte): longint;
var
i: longint;
begin
if k > n div 2 then
k := n - k;
Result := 1;
if k <= n then
for i := 1 to k do
Result := Result * (n - i + 1) div i;
end;
procedure InsertToErg(var E: tErg; const x: tPermfield);
var
n : Uint64;
k,i,j,dgt,nud: NativeInt;
begin
k := UsedDigits;
n := 0;
nud := 0;
for i := 1 to k do
begin
dgt := x[i];
nud := nud or cMaskDgt[dgt];
n := n * 10 + dgt;
end;
with E do
begin
numUsedDigits := nud;
numNormal := n;
end;
For J := k downto 1 do
Begin
n := 0;
for i := 1 to j-1 do
n := n * 10 + x[i];
for i := j+1 to k do
n := n * 10 + x[i];
E.numUnusedDigit[x[j]] := n;
end;
end;
procedure PermKoutofN(k, n: nativeInt);
var
x, y: tpPermfield;
i, yi, tmp: NativeInt;
begin
x := @pf_x;
y := @pf_y;
permcnt := 0;
if k > n then
k := n;
if k = n then
k := k - 1;
for i := 1 to n do
x^[i] := i;
for i := 1 to k do
y^[i] := i;
InserttoErg(Erg[permcnt], x^);
i := k;
repeat
yi := y^[i];
if yi < n then
begin
Inc(permcnt);
Inc(yi);
y^[i] := yi;
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
i := k;
InserttoErg(Erg[permcnt], x^);
end
else
begin
repeat
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
Dec(yi);
until yi <= i;
y^[i] := yi;
Dec(i);
end;
until (i = 0);
end;
procedure OutDigitCount;
var
i : tDigit;
Begin
writeln('omitted digits 1 to 9');
For i := 1 to 9do
write(DigitCnt[i]:UsedDigits);
writeln;
end;
procedure ClearDigitCount;
var
i : tDigit;
Begin
For i := low(DigitCnt) to high(DigitCnt) do
DigitCnt[i] := 0;
end;
var
t1, t0: TDateTime;
begin
For UsedDigits := 8 to 9 do
Begin
writeln('Used digits ',UsedDigits);
T0 := now;
ClearDigitCount;
setlength(Erg, Fakultaet(UsedDigits) * BinomCoeff(cMaxDigits, UsedDigits));
Anzahl := 0;
permcnt := 0;
PermKoutOfN(UsedDigits, cMaxDigits);
SearchMultiple;
T1 := now;
writeln('Found solutions ',Anzahl);
OutDigitCount;
writeln('time taken ',FormatDateTime('HH:NN:SS.zzz', T1 - T0));
setlength(Erg, 0);
writeln;
end;
end.
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Convert this Pascal block to Go, preserving its control flow and logic. | program FracRedu;
uses
SysUtils;
type
tdigit = 0..9;
const
cMaskDgt: array [tdigit] of Uint32 = (1, 2, 4, 8, 16, 32, 64, 128, 256, 512
);
cMaxDigits = High(tdigit);
type
tPermfield = array[tdigit] of uint32;
tpPermfield = ^tPermfield;
tDigitCnt = array[tdigit] of Uint32;
tErg = record
numUsedDigits : Uint32;
numUnusedDigit : array[tdigit] of Uint32;
numNormal : Uint64;
dummy : array[0..7] of byte;
end;
tpErg = ^tErg;
var
Erg: array of tErg;
pf_x, pf_y: tPermfield;
DigitCnt :tDigitCnt;
permcnt, UsedDigits,Anzahl: NativeUint;
function Fakultaet(i: integer): integer;
begin
Result := 1;
while i > 1 do
begin
Result := Result * i;
Dec(i);
end;
end;
procedure OutErg(dgt: Uint32;pi,pJ:tpErg);
begin
writeln(dgt:3,' ', pi^.numUnusedDigit[dgt],'/',pj^.numUnusedDigit[dgt]
,' = ',pi^.numNormal,'/',pj^.numNormal);
end;
function Check(pI,pJ : tpErg;Nud :Word):integer;
var
dgt: NativeInt;
Begin
result := 0;
dgt := 1;
NUD := NUD SHR 1;
repeat
IF NUD AND 1 <> 0 then
Begin
If pI^.numNormal*pJ^.numUnusedDigit[dgt] = pJ^.numNormal*pI^.numUnusedDigit[dgt] then
Begin
inc(result);
inc(DigitCnt[dgt]);
IF Anzahl < 110 then
OutErg(dgt,pI,pJ);
end;
end;
inc(dgt);
NUD := NUD SHR 1;
until NUD = 0;
end;
procedure CheckWithOne(pI : tpErg;j,Nud:Uint32);
var
pJ : tpErg;
l : NativeUInt;
Begin
pJ := pI;
if UsedDigits <5 then
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
IF l <> 0 then
inc(Anzahl,Check(pI,pJ,l));
end;
end
else
Begin
for j := j+1 to permcnt do
begin
inc(pJ);
l := NUD AND pJ^.numUsedDigits;
inc(Anzahl,Check(pI,pJ,l));
end;
end;
end;
procedure SearchMultiple;
var
pI : tpErg;
i : NativeUInt;
begin
pI := @Erg[0];
for i := 0 to permcnt do
Begin
CheckWithOne(pI,i,pI^.numUsedDigits);
inc(pI);
end;
end;
function BinomCoeff(n, k: byte): longint;
var
i: longint;
begin
if k > n div 2 then
k := n - k;
Result := 1;
if k <= n then
for i := 1 to k do
Result := Result * (n - i + 1) div i;
end;
procedure InsertToErg(var E: tErg; const x: tPermfield);
var
n : Uint64;
k,i,j,dgt,nud: NativeInt;
begin
k := UsedDigits;
n := 0;
nud := 0;
for i := 1 to k do
begin
dgt := x[i];
nud := nud or cMaskDgt[dgt];
n := n * 10 + dgt;
end;
with E do
begin
numUsedDigits := nud;
numNormal := n;
end;
For J := k downto 1 do
Begin
n := 0;
for i := 1 to j-1 do
n := n * 10 + x[i];
for i := j+1 to k do
n := n * 10 + x[i];
E.numUnusedDigit[x[j]] := n;
end;
end;
procedure PermKoutofN(k, n: nativeInt);
var
x, y: tpPermfield;
i, yi, tmp: NativeInt;
begin
x := @pf_x;
y := @pf_y;
permcnt := 0;
if k > n then
k := n;
if k = n then
k := k - 1;
for i := 1 to n do
x^[i] := i;
for i := 1 to k do
y^[i] := i;
InserttoErg(Erg[permcnt], x^);
i := k;
repeat
yi := y^[i];
if yi < n then
begin
Inc(permcnt);
Inc(yi);
y^[i] := yi;
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
i := k;
InserttoErg(Erg[permcnt], x^);
end
else
begin
repeat
tmp := x^[i];
x^[i] := x^[yi];
x^[yi] := tmp;
Dec(yi);
until yi <= i;
y^[i] := yi;
Dec(i);
end;
until (i = 0);
end;
procedure OutDigitCount;
var
i : tDigit;
Begin
writeln('omitted digits 1 to 9');
For i := 1 to 9do
write(DigitCnt[i]:UsedDigits);
writeln;
end;
procedure ClearDigitCount;
var
i : tDigit;
Begin
For i := low(DigitCnt) to high(DigitCnt) do
DigitCnt[i] := 0;
end;
var
t1, t0: TDateTime;
begin
For UsedDigits := 8 to 9 do
Begin
writeln('Used digits ',UsedDigits);
T0 := now;
ClearDigitCount;
setlength(Erg, Fakultaet(UsedDigits) * BinomCoeff(cMaxDigits, UsedDigits));
Anzahl := 0;
permcnt := 0;
PermKoutOfN(UsedDigits, cMaxDigits);
SearchMultiple;
T1 := now;
writeln('Found solutions ',Anzahl);
OutDigitCount;
writeln('time taken ',FormatDateTime('HH:NN:SS.zzz', T1 - T0));
setlength(Erg, 0);
writeln;
end;
end.
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Translate the given Perl code snippet into C without altering its behavior. | use strict;
use warnings;
use feature 'say';
use List::Util qw<sum uniq uniqnum head tail>;
for my $exp (map { $_ - 1 } <2 3 4>) {
my %reduced;
my $start = sum map { 10 ** $_ * ($exp - $_ + 1) } 0..$exp;
my $end = 10**($exp+1) - -1 + sum map { 10 ** $_ * ($exp - $_) } 0..$exp-1;
for my $den ($start .. $end-1) {
next if $den =~ /0/ or (uniqnum split '', $den) <= $exp;
for my $num ($start .. $den-1) {
next if $num =~ /0/ or (uniqnum split '', $num) <= $exp;
my %i;
map { $i{$_}++ } (uniq head -1, split '',$den), uniq tail -1, split '',$num;
my @set = grep { $_ if $i{$_} > 1 } keys %i;
next if @set < 1;
for (@set) {
(my $ne = $num) =~ s/$_//;
(my $de = $den) =~ s/$_//;
if ($ne/$de == $num/$den) {
$reduced{"$num/$den:$_"} = "$ne/$de";
}
}
}
}
my $digit = $exp + 1;
say "\n" . +%reduced . " $digit-digit reducible fractions:";
for my $n (1..9) {
my $cnt = scalar grep { /:$n/ } keys %reduced;
say "$cnt with removed $n" if $cnt;
}
say "\n 12 (or all, if less) $digit-digit reducible fractions:";
for my $f (head 12, sort keys %reduced) {
printf " %s => %s removed %s\n", substr($f,0,$digit*2+1), $reduced{$f}, substr($f,-1)
}
}
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Generate a C# translation of this Perl snippet without changing its computational steps. | use strict;
use warnings;
use feature 'say';
use List::Util qw<sum uniq uniqnum head tail>;
for my $exp (map { $_ - 1 } <2 3 4>) {
my %reduced;
my $start = sum map { 10 ** $_ * ($exp - $_ + 1) } 0..$exp;
my $end = 10**($exp+1) - -1 + sum map { 10 ** $_ * ($exp - $_) } 0..$exp-1;
for my $den ($start .. $end-1) {
next if $den =~ /0/ or (uniqnum split '', $den) <= $exp;
for my $num ($start .. $den-1) {
next if $num =~ /0/ or (uniqnum split '', $num) <= $exp;
my %i;
map { $i{$_}++ } (uniq head -1, split '',$den), uniq tail -1, split '',$num;
my @set = grep { $_ if $i{$_} > 1 } keys %i;
next if @set < 1;
for (@set) {
(my $ne = $num) =~ s/$_//;
(my $de = $den) =~ s/$_//;
if ($ne/$de == $num/$den) {
$reduced{"$num/$den:$_"} = "$ne/$de";
}
}
}
}
my $digit = $exp + 1;
say "\n" . +%reduced . " $digit-digit reducible fractions:";
for my $n (1..9) {
my $cnt = scalar grep { /:$n/ } keys %reduced;
say "$cnt with removed $n" if $cnt;
}
say "\n 12 (or all, if less) $digit-digit reducible fractions:";
for my $f (head 12, sort keys %reduced) {
printf " %s => %s removed %s\n", substr($f,0,$digit*2+1), $reduced{$f}, substr($f,-1)
}
}
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Write the same code in C++ as shown below in Perl. | use strict;
use warnings;
use feature 'say';
use List::Util qw<sum uniq uniqnum head tail>;
for my $exp (map { $_ - 1 } <2 3 4>) {
my %reduced;
my $start = sum map { 10 ** $_ * ($exp - $_ + 1) } 0..$exp;
my $end = 10**($exp+1) - -1 + sum map { 10 ** $_ * ($exp - $_) } 0..$exp-1;
for my $den ($start .. $end-1) {
next if $den =~ /0/ or (uniqnum split '', $den) <= $exp;
for my $num ($start .. $den-1) {
next if $num =~ /0/ or (uniqnum split '', $num) <= $exp;
my %i;
map { $i{$_}++ } (uniq head -1, split '',$den), uniq tail -1, split '',$num;
my @set = grep { $_ if $i{$_} > 1 } keys %i;
next if @set < 1;
for (@set) {
(my $ne = $num) =~ s/$_//;
(my $de = $den) =~ s/$_//;
if ($ne/$de == $num/$den) {
$reduced{"$num/$den:$_"} = "$ne/$de";
}
}
}
}
my $digit = $exp + 1;
say "\n" . +%reduced . " $digit-digit reducible fractions:";
for my $n (1..9) {
my $cnt = scalar grep { /:$n/ } keys %reduced;
say "$cnt with removed $n" if $cnt;
}
say "\n 12 (or all, if less) $digit-digit reducible fractions:";
for my $f (head 12, sort keys %reduced) {
printf " %s => %s removed %s\n", substr($f,0,$digit*2+1), $reduced{$f}, substr($f,-1)
}
}
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Translate this program into Java but keep the logic exactly as in Perl. | use strict;
use warnings;
use feature 'say';
use List::Util qw<sum uniq uniqnum head tail>;
for my $exp (map { $_ - 1 } <2 3 4>) {
my %reduced;
my $start = sum map { 10 ** $_ * ($exp - $_ + 1) } 0..$exp;
my $end = 10**($exp+1) - -1 + sum map { 10 ** $_ * ($exp - $_) } 0..$exp-1;
for my $den ($start .. $end-1) {
next if $den =~ /0/ or (uniqnum split '', $den) <= $exp;
for my $num ($start .. $den-1) {
next if $num =~ /0/ or (uniqnum split '', $num) <= $exp;
my %i;
map { $i{$_}++ } (uniq head -1, split '',$den), uniq tail -1, split '',$num;
my @set = grep { $_ if $i{$_} > 1 } keys %i;
next if @set < 1;
for (@set) {
(my $ne = $num) =~ s/$_//;
(my $de = $den) =~ s/$_//;
if ($ne/$de == $num/$den) {
$reduced{"$num/$den:$_"} = "$ne/$de";
}
}
}
}
my $digit = $exp + 1;
say "\n" . +%reduced . " $digit-digit reducible fractions:";
for my $n (1..9) {
my $cnt = scalar grep { /:$n/ } keys %reduced;
say "$cnt with removed $n" if $cnt;
}
say "\n 12 (or all, if less) $digit-digit reducible fractions:";
for my $f (head 12, sort keys %reduced) {
printf " %s => %s removed %s\n", substr($f,0,$digit*2+1), $reduced{$f}, substr($f,-1)
}
}
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Port the following code from Perl to Python with equivalent syntax and logic. | use strict;
use warnings;
use feature 'say';
use List::Util qw<sum uniq uniqnum head tail>;
for my $exp (map { $_ - 1 } <2 3 4>) {
my %reduced;
my $start = sum map { 10 ** $_ * ($exp - $_ + 1) } 0..$exp;
my $end = 10**($exp+1) - -1 + sum map { 10 ** $_ * ($exp - $_) } 0..$exp-1;
for my $den ($start .. $end-1) {
next if $den =~ /0/ or (uniqnum split '', $den) <= $exp;
for my $num ($start .. $den-1) {
next if $num =~ /0/ or (uniqnum split '', $num) <= $exp;
my %i;
map { $i{$_}++ } (uniq head -1, split '',$den), uniq tail -1, split '',$num;
my @set = grep { $_ if $i{$_} > 1 } keys %i;
next if @set < 1;
for (@set) {
(my $ne = $num) =~ s/$_//;
(my $de = $den) =~ s/$_//;
if ($ne/$de == $num/$den) {
$reduced{"$num/$den:$_"} = "$ne/$de";
}
}
}
}
my $digit = $exp + 1;
say "\n" . +%reduced . " $digit-digit reducible fractions:";
for my $n (1..9) {
my $cnt = scalar grep { /:$n/ } keys %reduced;
say "$cnt with removed $n" if $cnt;
}
say "\n 12 (or all, if less) $digit-digit reducible fractions:";
for my $f (head 12, sort keys %reduced) {
printf " %s => %s removed %s\n", substr($f,0,$digit*2+1), $reduced{$f}, substr($f,-1)
}
}
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Keep all operations the same but rewrite the snippet in VB. | use strict;
use warnings;
use feature 'say';
use List::Util qw<sum uniq uniqnum head tail>;
for my $exp (map { $_ - 1 } <2 3 4>) {
my %reduced;
my $start = sum map { 10 ** $_ * ($exp - $_ + 1) } 0..$exp;
my $end = 10**($exp+1) - -1 + sum map { 10 ** $_ * ($exp - $_) } 0..$exp-1;
for my $den ($start .. $end-1) {
next if $den =~ /0/ or (uniqnum split '', $den) <= $exp;
for my $num ($start .. $den-1) {
next if $num =~ /0/ or (uniqnum split '', $num) <= $exp;
my %i;
map { $i{$_}++ } (uniq head -1, split '',$den), uniq tail -1, split '',$num;
my @set = grep { $_ if $i{$_} > 1 } keys %i;
next if @set < 1;
for (@set) {
(my $ne = $num) =~ s/$_//;
(my $de = $den) =~ s/$_//;
if ($ne/$de == $num/$den) {
$reduced{"$num/$den:$_"} = "$ne/$de";
}
}
}
}
my $digit = $exp + 1;
say "\n" . +%reduced . " $digit-digit reducible fractions:";
for my $n (1..9) {
my $cnt = scalar grep { /:$n/ } keys %reduced;
say "$cnt with removed $n" if $cnt;
}
say "\n 12 (or all, if less) $digit-digit reducible fractions:";
for my $f (head 12, sort keys %reduced) {
printf " %s => %s removed %s\n", substr($f,0,$digit*2+1), $reduced{$f}, substr($f,-1)
}
}
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Transform the following Perl implementation into Go, maintaining the same output and logic. | use strict;
use warnings;
use feature 'say';
use List::Util qw<sum uniq uniqnum head tail>;
for my $exp (map { $_ - 1 } <2 3 4>) {
my %reduced;
my $start = sum map { 10 ** $_ * ($exp - $_ + 1) } 0..$exp;
my $end = 10**($exp+1) - -1 + sum map { 10 ** $_ * ($exp - $_) } 0..$exp-1;
for my $den ($start .. $end-1) {
next if $den =~ /0/ or (uniqnum split '', $den) <= $exp;
for my $num ($start .. $den-1) {
next if $num =~ /0/ or (uniqnum split '', $num) <= $exp;
my %i;
map { $i{$_}++ } (uniq head -1, split '',$den), uniq tail -1, split '',$num;
my @set = grep { $_ if $i{$_} > 1 } keys %i;
next if @set < 1;
for (@set) {
(my $ne = $num) =~ s/$_//;
(my $de = $den) =~ s/$_//;
if ($ne/$de == $num/$den) {
$reduced{"$num/$den:$_"} = "$ne/$de";
}
}
}
}
my $digit = $exp + 1;
say "\n" . +%reduced . " $digit-digit reducible fractions:";
for my $n (1..9) {
my $cnt = scalar grep { /:$n/ } keys %reduced;
say "$cnt with removed $n" if $cnt;
}
say "\n 12 (or all, if less) $digit-digit reducible fractions:";
for my $f (head 12, sort keys %reduced) {
printf " %s => %s removed %s\n", substr($f,0,$digit*2+1), $reduced{$f}, substr($f,-1)
}
}
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Produce a functionally identical C code for the snippet given in Racket. | #lang racket
(require racket/generator
syntax/parse/define)
(define-syntax-parser for**
[(_ [x:id {~datum <-} (e ...)] rst ...) #'(e ... (λ (x) (for** rst ...)))]
[(_ e ...) #'(begin e ...)])
(define (permutations xs n yield #:lower [lower #f])
(let loop ([xs xs] [n n] [acc '()] [lower lower])
(cond
[(= n 0) (yield (reverse acc))]
[else (for ([x (in-list xs)] #:when (or (not lower) (>= x (first lower))))
(loop (remove x xs)
(sub1 n)
(cons x acc)
(and lower (= x (first lower)) (rest lower))))])))
(define (list->number xs) (foldl (λ (e acc) (+ (* 10 acc) e)) 0 xs))
(define (calc n)
(define rng (range 1 10))
(in-generator
(for** [numer <- (permutations rng n)]
[denom <- (permutations rng n #:lower numer)]
(for* (#:when (not (equal? numer denom))
[crossed (in-list numer)]
#:when (member crossed denom)
[numer* (in-value (list->number (remove crossed numer)))]
[denom* (in-value (list->number (remove crossed denom)))]
[numer** (in-value (list->number numer))]
[denom** (in-value (list->number denom))]
#:when (= (* numer** denom*) (* numer* denom**)))
(yield (list numer** denom** numer* denom* crossed))))))
(define (enumerate n)
(for ([x (calc n)] [i (in-range 12)])
(apply printf "~a/~a = ~a/~a (~a crossed out)\n" x))
(newline))
(define (stats n)
(define digits (make-hash))
(for ([x (calc n)]) (hash-update! digits (last x) add1 0))
(printf "There are ~a ~a-digit fractions of which:\n" (for/sum ([(k v) (in-hash digits)]) v) n)
(for ([digit (in-list (sort (hash->list digits) < #:key car))])
(printf " The digit ~a was crossed out ~a times\n" (car digit) (cdr digit)))
(newline))
(define (main)
(enumerate 2)
(enumerate 3)
(enumerate 4)
(enumerate 5)
(stats 2)
(stats 3)
(stats 4)
(stats 5))
(main)
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Can you help me rewrite this code in C# instead of Racket, keeping it the same logically? | #lang racket
(require racket/generator
syntax/parse/define)
(define-syntax-parser for**
[(_ [x:id {~datum <-} (e ...)] rst ...) #'(e ... (λ (x) (for** rst ...)))]
[(_ e ...) #'(begin e ...)])
(define (permutations xs n yield #:lower [lower #f])
(let loop ([xs xs] [n n] [acc '()] [lower lower])
(cond
[(= n 0) (yield (reverse acc))]
[else (for ([x (in-list xs)] #:when (or (not lower) (>= x (first lower))))
(loop (remove x xs)
(sub1 n)
(cons x acc)
(and lower (= x (first lower)) (rest lower))))])))
(define (list->number xs) (foldl (λ (e acc) (+ (* 10 acc) e)) 0 xs))
(define (calc n)
(define rng (range 1 10))
(in-generator
(for** [numer <- (permutations rng n)]
[denom <- (permutations rng n #:lower numer)]
(for* (#:when (not (equal? numer denom))
[crossed (in-list numer)]
#:when (member crossed denom)
[numer* (in-value (list->number (remove crossed numer)))]
[denom* (in-value (list->number (remove crossed denom)))]
[numer** (in-value (list->number numer))]
[denom** (in-value (list->number denom))]
#:when (= (* numer** denom*) (* numer* denom**)))
(yield (list numer** denom** numer* denom* crossed))))))
(define (enumerate n)
(for ([x (calc n)] [i (in-range 12)])
(apply printf "~a/~a = ~a/~a (~a crossed out)\n" x))
(newline))
(define (stats n)
(define digits (make-hash))
(for ([x (calc n)]) (hash-update! digits (last x) add1 0))
(printf "There are ~a ~a-digit fractions of which:\n" (for/sum ([(k v) (in-hash digits)]) v) n)
(for ([digit (in-list (sort (hash->list digits) < #:key car))])
(printf " The digit ~a was crossed out ~a times\n" (car digit) (cdr digit)))
(newline))
(define (main)
(enumerate 2)
(enumerate 3)
(enumerate 4)
(enumerate 5)
(stats 2)
(stats 3)
(stats 4)
(stats 5))
(main)
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Please provide an equivalent version of this Racket code in C++. | #lang racket
(require racket/generator
syntax/parse/define)
(define-syntax-parser for**
[(_ [x:id {~datum <-} (e ...)] rst ...) #'(e ... (λ (x) (for** rst ...)))]
[(_ e ...) #'(begin e ...)])
(define (permutations xs n yield #:lower [lower #f])
(let loop ([xs xs] [n n] [acc '()] [lower lower])
(cond
[(= n 0) (yield (reverse acc))]
[else (for ([x (in-list xs)] #:when (or (not lower) (>= x (first lower))))
(loop (remove x xs)
(sub1 n)
(cons x acc)
(and lower (= x (first lower)) (rest lower))))])))
(define (list->number xs) (foldl (λ (e acc) (+ (* 10 acc) e)) 0 xs))
(define (calc n)
(define rng (range 1 10))
(in-generator
(for** [numer <- (permutations rng n)]
[denom <- (permutations rng n #:lower numer)]
(for* (#:when (not (equal? numer denom))
[crossed (in-list numer)]
#:when (member crossed denom)
[numer* (in-value (list->number (remove crossed numer)))]
[denom* (in-value (list->number (remove crossed denom)))]
[numer** (in-value (list->number numer))]
[denom** (in-value (list->number denom))]
#:when (= (* numer** denom*) (* numer* denom**)))
(yield (list numer** denom** numer* denom* crossed))))))
(define (enumerate n)
(for ([x (calc n)] [i (in-range 12)])
(apply printf "~a/~a = ~a/~a (~a crossed out)\n" x))
(newline))
(define (stats n)
(define digits (make-hash))
(for ([x (calc n)]) (hash-update! digits (last x) add1 0))
(printf "There are ~a ~a-digit fractions of which:\n" (for/sum ([(k v) (in-hash digits)]) v) n)
(for ([digit (in-list (sort (hash->list digits) < #:key car))])
(printf " The digit ~a was crossed out ~a times\n" (car digit) (cdr digit)))
(newline))
(define (main)
(enumerate 2)
(enumerate 3)
(enumerate 4)
(enumerate 5)
(stats 2)
(stats 3)
(stats 4)
(stats 5))
(main)
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Change the following Racket code into Java without altering its purpose. | #lang racket
(require racket/generator
syntax/parse/define)
(define-syntax-parser for**
[(_ [x:id {~datum <-} (e ...)] rst ...) #'(e ... (λ (x) (for** rst ...)))]
[(_ e ...) #'(begin e ...)])
(define (permutations xs n yield #:lower [lower #f])
(let loop ([xs xs] [n n] [acc '()] [lower lower])
(cond
[(= n 0) (yield (reverse acc))]
[else (for ([x (in-list xs)] #:when (or (not lower) (>= x (first lower))))
(loop (remove x xs)
(sub1 n)
(cons x acc)
(and lower (= x (first lower)) (rest lower))))])))
(define (list->number xs) (foldl (λ (e acc) (+ (* 10 acc) e)) 0 xs))
(define (calc n)
(define rng (range 1 10))
(in-generator
(for** [numer <- (permutations rng n)]
[denom <- (permutations rng n #:lower numer)]
(for* (#:when (not (equal? numer denom))
[crossed (in-list numer)]
#:when (member crossed denom)
[numer* (in-value (list->number (remove crossed numer)))]
[denom* (in-value (list->number (remove crossed denom)))]
[numer** (in-value (list->number numer))]
[denom** (in-value (list->number denom))]
#:when (= (* numer** denom*) (* numer* denom**)))
(yield (list numer** denom** numer* denom* crossed))))))
(define (enumerate n)
(for ([x (calc n)] [i (in-range 12)])
(apply printf "~a/~a = ~a/~a (~a crossed out)\n" x))
(newline))
(define (stats n)
(define digits (make-hash))
(for ([x (calc n)]) (hash-update! digits (last x) add1 0))
(printf "There are ~a ~a-digit fractions of which:\n" (for/sum ([(k v) (in-hash digits)]) v) n)
(for ([digit (in-list (sort (hash->list digits) < #:key car))])
(printf " The digit ~a was crossed out ~a times\n" (car digit) (cdr digit)))
(newline))
(define (main)
(enumerate 2)
(enumerate 3)
(enumerate 4)
(enumerate 5)
(stats 2)
(stats 3)
(stats 4)
(stats 5))
(main)
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Can you help me rewrite this code in Python instead of Racket, keeping it the same logically? | #lang racket
(require racket/generator
syntax/parse/define)
(define-syntax-parser for**
[(_ [x:id {~datum <-} (e ...)] rst ...) #'(e ... (λ (x) (for** rst ...)))]
[(_ e ...) #'(begin e ...)])
(define (permutations xs n yield #:lower [lower #f])
(let loop ([xs xs] [n n] [acc '()] [lower lower])
(cond
[(= n 0) (yield (reverse acc))]
[else (for ([x (in-list xs)] #:when (or (not lower) (>= x (first lower))))
(loop (remove x xs)
(sub1 n)
(cons x acc)
(and lower (= x (first lower)) (rest lower))))])))
(define (list->number xs) (foldl (λ (e acc) (+ (* 10 acc) e)) 0 xs))
(define (calc n)
(define rng (range 1 10))
(in-generator
(for** [numer <- (permutations rng n)]
[denom <- (permutations rng n #:lower numer)]
(for* (#:when (not (equal? numer denom))
[crossed (in-list numer)]
#:when (member crossed denom)
[numer* (in-value (list->number (remove crossed numer)))]
[denom* (in-value (list->number (remove crossed denom)))]
[numer** (in-value (list->number numer))]
[denom** (in-value (list->number denom))]
#:when (= (* numer** denom*) (* numer* denom**)))
(yield (list numer** denom** numer* denom* crossed))))))
(define (enumerate n)
(for ([x (calc n)] [i (in-range 12)])
(apply printf "~a/~a = ~a/~a (~a crossed out)\n" x))
(newline))
(define (stats n)
(define digits (make-hash))
(for ([x (calc n)]) (hash-update! digits (last x) add1 0))
(printf "There are ~a ~a-digit fractions of which:\n" (for/sum ([(k v) (in-hash digits)]) v) n)
(for ([digit (in-list (sort (hash->list digits) < #:key car))])
(printf " The digit ~a was crossed out ~a times\n" (car digit) (cdr digit)))
(newline))
(define (main)
(enumerate 2)
(enumerate 3)
(enumerate 4)
(enumerate 5)
(stats 2)
(stats 3)
(stats 4)
(stats 5))
(main)
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Translate this program into VB but keep the logic exactly as in Racket. | #lang racket
(require racket/generator
syntax/parse/define)
(define-syntax-parser for**
[(_ [x:id {~datum <-} (e ...)] rst ...) #'(e ... (λ (x) (for** rst ...)))]
[(_ e ...) #'(begin e ...)])
(define (permutations xs n yield #:lower [lower #f])
(let loop ([xs xs] [n n] [acc '()] [lower lower])
(cond
[(= n 0) (yield (reverse acc))]
[else (for ([x (in-list xs)] #:when (or (not lower) (>= x (first lower))))
(loop (remove x xs)
(sub1 n)
(cons x acc)
(and lower (= x (first lower)) (rest lower))))])))
(define (list->number xs) (foldl (λ (e acc) (+ (* 10 acc) e)) 0 xs))
(define (calc n)
(define rng (range 1 10))
(in-generator
(for** [numer <- (permutations rng n)]
[denom <- (permutations rng n #:lower numer)]
(for* (#:when (not (equal? numer denom))
[crossed (in-list numer)]
#:when (member crossed denom)
[numer* (in-value (list->number (remove crossed numer)))]
[denom* (in-value (list->number (remove crossed denom)))]
[numer** (in-value (list->number numer))]
[denom** (in-value (list->number denom))]
#:when (= (* numer** denom*) (* numer* denom**)))
(yield (list numer** denom** numer* denom* crossed))))))
(define (enumerate n)
(for ([x (calc n)] [i (in-range 12)])
(apply printf "~a/~a = ~a/~a (~a crossed out)\n" x))
(newline))
(define (stats n)
(define digits (make-hash))
(for ([x (calc n)]) (hash-update! digits (last x) add1 0))
(printf "There are ~a ~a-digit fractions of which:\n" (for/sum ([(k v) (in-hash digits)]) v) n)
(for ([digit (in-list (sort (hash->list digits) < #:key car))])
(printf " The digit ~a was crossed out ~a times\n" (car digit) (cdr digit)))
(newline))
(define (main)
(enumerate 2)
(enumerate 3)
(enumerate 4)
(enumerate 5)
(stats 2)
(stats 3)
(stats 4)
(stats 5))
(main)
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Can you help me rewrite this code in Go instead of Racket, keeping it the same logically? | #lang racket
(require racket/generator
syntax/parse/define)
(define-syntax-parser for**
[(_ [x:id {~datum <-} (e ...)] rst ...) #'(e ... (λ (x) (for** rst ...)))]
[(_ e ...) #'(begin e ...)])
(define (permutations xs n yield #:lower [lower #f])
(let loop ([xs xs] [n n] [acc '()] [lower lower])
(cond
[(= n 0) (yield (reverse acc))]
[else (for ([x (in-list xs)] #:when (or (not lower) (>= x (first lower))))
(loop (remove x xs)
(sub1 n)
(cons x acc)
(and lower (= x (first lower)) (rest lower))))])))
(define (list->number xs) (foldl (λ (e acc) (+ (* 10 acc) e)) 0 xs))
(define (calc n)
(define rng (range 1 10))
(in-generator
(for** [numer <- (permutations rng n)]
[denom <- (permutations rng n #:lower numer)]
(for* (#:when (not (equal? numer denom))
[crossed (in-list numer)]
#:when (member crossed denom)
[numer* (in-value (list->number (remove crossed numer)))]
[denom* (in-value (list->number (remove crossed denom)))]
[numer** (in-value (list->number numer))]
[denom** (in-value (list->number denom))]
#:when (= (* numer** denom*) (* numer* denom**)))
(yield (list numer** denom** numer* denom* crossed))))))
(define (enumerate n)
(for ([x (calc n)] [i (in-range 12)])
(apply printf "~a/~a = ~a/~a (~a crossed out)\n" x))
(newline))
(define (stats n)
(define digits (make-hash))
(for ([x (calc n)]) (hash-update! digits (last x) add1 0))
(printf "There are ~a ~a-digit fractions of which:\n" (for/sum ([(k v) (in-hash digits)]) v) n)
(for ([digit (in-list (sort (hash->list digits) < #:key car))])
(printf " The digit ~a was crossed out ~a times\n" (car digit) (cdr digit)))
(newline))
(define (main)
(enumerate 2)
(enumerate 3)
(enumerate 4)
(enumerate 5)
(stats 2)
(stats 3)
(stats 4)
(stats 5))
(main)
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Preserve the algorithm and functionality while converting the code from REXX to C. |
parse arg high show .
if high=='' | high=="," then high= 4
if show=='' | show=="," then show= 12
say center(' some samples of reduced fractions by crossing out digits ', 79, "═")
$.=0
do L=2 to high; say
lim= 10**L - 1
do n=10**(L-1) to lim
if pos(0, n) \==0 then iterate
if hasDup(n) then iterate
do d=n+1 to lim
if pos(0, d)\==0 then iterate
if verify(d, n, 'M')==0 then iterate
if hasDup(d) then iterate
q= n/d
do e=1 for L; xo= substr(n, e, 1)
nn= space( translate(n, , xo), 0)
dd= space( translate(d, , xo), 0)
if nn/dd \== q then iterate
$.L= $.L + 1
$.L.xo= $.L.xo + 1
if $.L>show then iterate
say center(n'/'d " = " nn'/'dd " by crossing out the" xo"'s.", 79)
end
end
end
end
say; @with= ' with crossed-out'
do k=1 for 9
if $.k==0 then iterate
say; say center('There are ' $.k " "k'-digit fractions.', 79, "═")
@for= ' For '
do #=1 for 9; if $.k.#==0 then iterate
say @for k"-digit fractions, there are " right($.k.#, k-1) @with #"'s."
end
end
exit
hasDup: parse arg x;
do i=1 for L-1; if pos(substr(x,i,1), substr(x,i+1)) \== 0 then return 1
end
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Convert the following code from REXX to C#, ensuring the logic remains intact. |
parse arg high show .
if high=='' | high=="," then high= 4
if show=='' | show=="," then show= 12
say center(' some samples of reduced fractions by crossing out digits ', 79, "═")
$.=0
do L=2 to high; say
lim= 10**L - 1
do n=10**(L-1) to lim
if pos(0, n) \==0 then iterate
if hasDup(n) then iterate
do d=n+1 to lim
if pos(0, d)\==0 then iterate
if verify(d, n, 'M')==0 then iterate
if hasDup(d) then iterate
q= n/d
do e=1 for L; xo= substr(n, e, 1)
nn= space( translate(n, , xo), 0)
dd= space( translate(d, , xo), 0)
if nn/dd \== q then iterate
$.L= $.L + 1
$.L.xo= $.L.xo + 1
if $.L>show then iterate
say center(n'/'d " = " nn'/'dd " by crossing out the" xo"'s.", 79)
end
end
end
end
say; @with= ' with crossed-out'
do k=1 for 9
if $.k==0 then iterate
say; say center('There are ' $.k " "k'-digit fractions.', 79, "═")
@for= ' For '
do #=1 for 9; if $.k.#==0 then iterate
say @for k"-digit fractions, there are " right($.k.#, k-1) @with #"'s."
end
end
exit
hasDup: parse arg x;
do i=1 for L-1; if pos(substr(x,i,1), substr(x,i+1)) \== 0 then return 1
end
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Port the provided REXX code into C++ while preserving the original functionality. |
parse arg high show .
if high=='' | high=="," then high= 4
if show=='' | show=="," then show= 12
say center(' some samples of reduced fractions by crossing out digits ', 79, "═")
$.=0
do L=2 to high; say
lim= 10**L - 1
do n=10**(L-1) to lim
if pos(0, n) \==0 then iterate
if hasDup(n) then iterate
do d=n+1 to lim
if pos(0, d)\==0 then iterate
if verify(d, n, 'M')==0 then iterate
if hasDup(d) then iterate
q= n/d
do e=1 for L; xo= substr(n, e, 1)
nn= space( translate(n, , xo), 0)
dd= space( translate(d, , xo), 0)
if nn/dd \== q then iterate
$.L= $.L + 1
$.L.xo= $.L.xo + 1
if $.L>show then iterate
say center(n'/'d " = " nn'/'dd " by crossing out the" xo"'s.", 79)
end
end
end
end
say; @with= ' with crossed-out'
do k=1 for 9
if $.k==0 then iterate
say; say center('There are ' $.k " "k'-digit fractions.', 79, "═")
@for= ' For '
do #=1 for 9; if $.k.#==0 then iterate
say @for k"-digit fractions, there are " right($.k.#, k-1) @with #"'s."
end
end
exit
hasDup: parse arg x;
do i=1 for L-1; if pos(substr(x,i,1), substr(x,i+1)) \== 0 then return 1
end
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Transform the following REXX implementation into Java, maintaining the same output and logic. |
parse arg high show .
if high=='' | high=="," then high= 4
if show=='' | show=="," then show= 12
say center(' some samples of reduced fractions by crossing out digits ', 79, "═")
$.=0
do L=2 to high; say
lim= 10**L - 1
do n=10**(L-1) to lim
if pos(0, n) \==0 then iterate
if hasDup(n) then iterate
do d=n+1 to lim
if pos(0, d)\==0 then iterate
if verify(d, n, 'M')==0 then iterate
if hasDup(d) then iterate
q= n/d
do e=1 for L; xo= substr(n, e, 1)
nn= space( translate(n, , xo), 0)
dd= space( translate(d, , xo), 0)
if nn/dd \== q then iterate
$.L= $.L + 1
$.L.xo= $.L.xo + 1
if $.L>show then iterate
say center(n'/'d " = " nn'/'dd " by crossing out the" xo"'s.", 79)
end
end
end
end
say; @with= ' with crossed-out'
do k=1 for 9
if $.k==0 then iterate
say; say center('There are ' $.k " "k'-digit fractions.', 79, "═")
@for= ' For '
do #=1 for 9; if $.k.#==0 then iterate
say @for k"-digit fractions, there are " right($.k.#, k-1) @with #"'s."
end
end
exit
hasDup: parse arg x;
do i=1 for L-1; if pos(substr(x,i,1), substr(x,i+1)) \== 0 then return 1
end
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Maintain the same structure and functionality when rewriting this code in Python. |
parse arg high show .
if high=='' | high=="," then high= 4
if show=='' | show=="," then show= 12
say center(' some samples of reduced fractions by crossing out digits ', 79, "═")
$.=0
do L=2 to high; say
lim= 10**L - 1
do n=10**(L-1) to lim
if pos(0, n) \==0 then iterate
if hasDup(n) then iterate
do d=n+1 to lim
if pos(0, d)\==0 then iterate
if verify(d, n, 'M')==0 then iterate
if hasDup(d) then iterate
q= n/d
do e=1 for L; xo= substr(n, e, 1)
nn= space( translate(n, , xo), 0)
dd= space( translate(d, , xo), 0)
if nn/dd \== q then iterate
$.L= $.L + 1
$.L.xo= $.L.xo + 1
if $.L>show then iterate
say center(n'/'d " = " nn'/'dd " by crossing out the" xo"'s.", 79)
end
end
end
end
say; @with= ' with crossed-out'
do k=1 for 9
if $.k==0 then iterate
say; say center('There are ' $.k " "k'-digit fractions.', 79, "═")
@for= ' For '
do #=1 for 9; if $.k.#==0 then iterate
say @for k"-digit fractions, there are " right($.k.#, k-1) @with #"'s."
end
end
exit
hasDup: parse arg x;
do i=1 for L-1; if pos(substr(x,i,1), substr(x,i+1)) \== 0 then return 1
end
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Translate this program into VB but keep the logic exactly as in REXX. |
parse arg high show .
if high=='' | high=="," then high= 4
if show=='' | show=="," then show= 12
say center(' some samples of reduced fractions by crossing out digits ', 79, "═")
$.=0
do L=2 to high; say
lim= 10**L - 1
do n=10**(L-1) to lim
if pos(0, n) \==0 then iterate
if hasDup(n) then iterate
do d=n+1 to lim
if pos(0, d)\==0 then iterate
if verify(d, n, 'M')==0 then iterate
if hasDup(d) then iterate
q= n/d
do e=1 for L; xo= substr(n, e, 1)
nn= space( translate(n, , xo), 0)
dd= space( translate(d, , xo), 0)
if nn/dd \== q then iterate
$.L= $.L + 1
$.L.xo= $.L.xo + 1
if $.L>show then iterate
say center(n'/'d " = " nn'/'dd " by crossing out the" xo"'s.", 79)
end
end
end
end
say; @with= ' with crossed-out'
do k=1 for 9
if $.k==0 then iterate
say; say center('There are ' $.k " "k'-digit fractions.', 79, "═")
@for= ' For '
do #=1 for 9; if $.k.#==0 then iterate
say @for k"-digit fractions, there are " right($.k.#, k-1) @with #"'s."
end
end
exit
hasDup: parse arg x;
do i=1 for L-1; if pos(substr(x,i,1), substr(x,i+1)) \== 0 then return 1
end
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Convert the following code from REXX to Go, ensuring the logic remains intact. |
parse arg high show .
if high=='' | high=="," then high= 4
if show=='' | show=="," then show= 12
say center(' some samples of reduced fractions by crossing out digits ', 79, "═")
$.=0
do L=2 to high; say
lim= 10**L - 1
do n=10**(L-1) to lim
if pos(0, n) \==0 then iterate
if hasDup(n) then iterate
do d=n+1 to lim
if pos(0, d)\==0 then iterate
if verify(d, n, 'M')==0 then iterate
if hasDup(d) then iterate
q= n/d
do e=1 for L; xo= substr(n, e, 1)
nn= space( translate(n, , xo), 0)
dd= space( translate(d, , xo), 0)
if nn/dd \== q then iterate
$.L= $.L + 1
$.L.xo= $.L.xo + 1
if $.L>show then iterate
say center(n'/'d " = " nn'/'dd " by crossing out the" xo"'s.", 79)
end
end
end
end
say; @with= ' with crossed-out'
do k=1 for 9
if $.k==0 then iterate
say; say center('There are ' $.k " "k'-digit fractions.', 79, "═")
@for= ' For '
do #=1 for 9; if $.k.#==0 then iterate
say @for k"-digit fractions, there are " right($.k.#, k-1) @with #"'s."
end
end
exit
hasDup: parse arg x;
do i=1 for L-1; if pos(substr(x,i,1), substr(x,i+1)) \== 0 then return 1
end
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Convert the following code from Ruby to C, ensuring the logic remains intact. | def indexOf(haystack, needle)
idx = 0
for straw in haystack
if straw == needle then
return idx
else
idx = idx + 1
end
end
return -1
end
def getDigits(n, le, digits)
while n > 0
r = n % 10
if r == 0 or indexOf(digits, r) >= 0 then
return false
end
le = le - 1
digits[le] = r
n = (n / 10).floor
end
return true
end
POWS = [1, 10, 100, 1000, 10000]
def removeDigit(digits, le, idx)
sum = 0
pow = POWS[le - 2]
i = 0
while i < le
if i == idx then
i = i + 1
next
end
sum = sum + digits[i] * pow
pow = (pow / 10).floor
i = i + 1
end
return sum
end
def main
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = Array.new(5, 0)
omitted = Array.new(5) { Array.new(10, 0) }
i = 0
for lim in lims
n = lim[0]
while n < lim[1]
nDigits = [0] * (i + 2)
nOk = getDigits(n, i + 2, nDigits)
if not nOk then
n = n + 1
next
end
d = n + 1
while d <= lim[1] + 1
dDigits = [0] * (i + 2)
dOk = getDigits(d, i + 2, dDigits)
if not dOk then
d = d + 1
next
end
nix = 0
while nix < nDigits.length
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0 then
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd) then
count[i] = count[i] + 1
omitted[i][digit] = omitted[i][digit] + 1
if count[i] <= 12 then
print "%d/%d = %d/%d by omitting %d's\n" % [n, d, rn, rd, digit]
end
end
end
nix = nix + 1
end
d = d + 1
end
n = n + 1
end
print "\n"
i = i + 1
end
i = 2
while i <= 5
print "There are %d %d-digit fractions of which:\n" % [count[i - 2], i]
j = 1
while j <= 9
if omitted[i - 2][j] == 0 then
j = j + 1
next
end
print "%6s have %d's omitted\n" % [omitted[i - 2][j], j]
j = j + 1
end
print "\n"
i = i + 1
end
end
main()
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
Write a version of this Ruby function in C# with identical behavior. | def indexOf(haystack, needle)
idx = 0
for straw in haystack
if straw == needle then
return idx
else
idx = idx + 1
end
end
return -1
end
def getDigits(n, le, digits)
while n > 0
r = n % 10
if r == 0 or indexOf(digits, r) >= 0 then
return false
end
le = le - 1
digits[le] = r
n = (n / 10).floor
end
return true
end
POWS = [1, 10, 100, 1000, 10000]
def removeDigit(digits, le, idx)
sum = 0
pow = POWS[le - 2]
i = 0
while i < le
if i == idx then
i = i + 1
next
end
sum = sum + digits[i] * pow
pow = (pow / 10).floor
i = i + 1
end
return sum
end
def main
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = Array.new(5, 0)
omitted = Array.new(5) { Array.new(10, 0) }
i = 0
for lim in lims
n = lim[0]
while n < lim[1]
nDigits = [0] * (i + 2)
nOk = getDigits(n, i + 2, nDigits)
if not nOk then
n = n + 1
next
end
d = n + 1
while d <= lim[1] + 1
dDigits = [0] * (i + 2)
dOk = getDigits(d, i + 2, dDigits)
if not dOk then
d = d + 1
next
end
nix = 0
while nix < nDigits.length
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0 then
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd) then
count[i] = count[i] + 1
omitted[i][digit] = omitted[i][digit] + 1
if count[i] <= 12 then
print "%d/%d = %d/%d by omitting %d's\n" % [n, d, rn, rd, digit]
end
end
end
nix = nix + 1
end
d = d + 1
end
n = n + 1
end
print "\n"
i = i + 1
end
i = 2
while i <= 5
print "There are %d %d-digit fractions of which:\n" % [count[i - 2], i]
j = 1
while j <= 9
if omitted[i - 2][j] == 0 then
j = j + 1
next
end
print "%6s have %d's omitted\n" % [omitted[i - 2][j], j]
j = j + 1
end
print "\n"
i = i + 1
end
end
main()
| using System;
namespace FractionReduction {
class Program {
static int IndexOf(int n, int[] s) {
for (int i = 0; i < s.Length; i++) {
if (s[i] == n) {
return i;
}
}
return -1;
}
static bool GetDigits(int n, int le, int[] digits) {
while (n > 0) {
var r = n % 10;
if (r == 0 || IndexOf(r, digits) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
static int RemoveDigit(int[] digits, int le, int idx) {
int[] pows = { 1, 10, 100, 1000, 10000 };
var sum = 0;
var pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
static void Main() {
var lims = new int[,] { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
var count = new int[5];
var omitted = new int[5, 10];
var upperBound = lims.GetLength(0);
for (int i = 0; i < upperBound; i++) {
var nDigits = new int[i + 2];
var dDigits = new int[i + 2];
var blank = new int[i + 2];
for (int n = lims[i, 0]; n <= lims[i, 1]; n++) {
blank.CopyTo(nDigits, 0);
var nOk = GetDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i, 1] + 1; d++) {
blank.CopyTo(dDigits, 0);
var dOk = GetDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (int nix = 0; nix < nDigits.Length; nix++) {
var digit = nDigits[nix];
var dix = IndexOf(digit, dDigits);
if (dix >= 0) {
var rn = RemoveDigit(nDigits, i + 2, nix);
var rd = RemoveDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i, digit]++;
if (count[i] <= 12) {
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}'s", n, d, rn, rd, digit);
}
}
}
}
}
}
Console.WriteLine();
}
for (int i = 2; i <= 5; i++) {
Console.WriteLine("There are {0} {1}-digit fractions of which:", count[i - 2], i);
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2, j] == 0) {
continue;
}
Console.WriteLine("{0,6} have {1}'s omitted", omitted[i - 2, j], j);
}
Console.WriteLine();
}
}
}
}
|
Translate the given Ruby code snippet into C++ without altering its behavior. | def indexOf(haystack, needle)
idx = 0
for straw in haystack
if straw == needle then
return idx
else
idx = idx + 1
end
end
return -1
end
def getDigits(n, le, digits)
while n > 0
r = n % 10
if r == 0 or indexOf(digits, r) >= 0 then
return false
end
le = le - 1
digits[le] = r
n = (n / 10).floor
end
return true
end
POWS = [1, 10, 100, 1000, 10000]
def removeDigit(digits, le, idx)
sum = 0
pow = POWS[le - 2]
i = 0
while i < le
if i == idx then
i = i + 1
next
end
sum = sum + digits[i] * pow
pow = (pow / 10).floor
i = i + 1
end
return sum
end
def main
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = Array.new(5, 0)
omitted = Array.new(5) { Array.new(10, 0) }
i = 0
for lim in lims
n = lim[0]
while n < lim[1]
nDigits = [0] * (i + 2)
nOk = getDigits(n, i + 2, nDigits)
if not nOk then
n = n + 1
next
end
d = n + 1
while d <= lim[1] + 1
dDigits = [0] * (i + 2)
dOk = getDigits(d, i + 2, dDigits)
if not dOk then
d = d + 1
next
end
nix = 0
while nix < nDigits.length
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0 then
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd) then
count[i] = count[i] + 1
omitted[i][digit] = omitted[i][digit] + 1
if count[i] <= 12 then
print "%d/%d = %d/%d by omitting %d's\n" % [n, d, rn, rd, digit]
end
end
end
nix = nix + 1
end
d = d + 1
end
n = n + 1
end
print "\n"
i = i + 1
end
i = 2
while i <= 5
print "There are %d %d-digit fractions of which:\n" % [count[i - 2], i]
j = 1
while j <= 9
if omitted[i - 2][j] == 0 then
j = j + 1
next
end
print "%6s have %d's omitted\n" % [omitted[i - 2][j], j]
j = j + 1
end
print "\n"
i = i + 1
end
end
main()
| #include <array>
#include <iomanip>
#include <iostream>
#include <vector>
int indexOf(const std::vector<int> &haystack, int needle) {
auto it = haystack.cbegin();
auto end = haystack.cend();
int idx = 0;
for (; it != end; it = std::next(it)) {
if (*it == needle) {
return idx;
}
idx++;
}
return -1;
}
bool getDigits(int n, int le, std::vector<int> &digits) {
while (n > 0) {
auto r = n % 10;
if (r == 0 || indexOf(digits, r) >= 0) {
return false;
}
le--;
digits[le] = r;
n /= 10;
}
return true;
}
int removeDigit(const std::vector<int> &digits, int le, int idx) {
static std::array<int, 5> pows = { 1, 10, 100, 1000, 10000 };
int sum = 0;
auto pow = pows[le - 2];
for (int i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
std::vector<std::pair<int, int>> lims = { {12, 97}, {123, 986}, {1234, 9875}, {12345, 98764} };
std::array<int, 5> count;
std::array<std::array<int, 10>, 5> omitted;
std::fill(count.begin(), count.end(), 0);
std::for_each(omitted.begin(), omitted.end(),
[](auto &a) {
std::fill(a.begin(), a.end(), 0);
}
);
for (size_t i = 0; i < lims.size(); i++) {
std::vector<int> nDigits(i + 2);
std::vector<int> dDigits(i + 2);
for (int n = lims[i].first; n <= lims[i].second; n++) {
std::fill(nDigits.begin(), nDigits.end(), 0);
bool nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (int d = n + 1; d <= lims[i].second + 1; d++) {
std::fill(dDigits.begin(), dDigits.end(), 0);
bool dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (size_t nix = 0; nix < nDigits.size(); nix++) {
auto digit = nDigits[nix];
auto dix = indexOf(dDigits, digit);
if (dix >= 0) {
auto rn = removeDigit(nDigits, i + 2, nix);
auto rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
std::cout << n << '/' << d << " = " << rn << '/' << rd << " by omitting " << digit << "'s\n";
}
}
}
}
}
}
std::cout << '\n';
}
for (int i = 2; i <= 5; i++) {
std::cout << "There are " << count[i - 2] << ' ' << i << "-digit fractions of which:\n";
for (int j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
std::cout << std::setw(6) << omitted[i - 2][j] << " have " << j << "'s omitted\n";
}
std::cout << '\n';
}
return 0;
}
|
Port the following code from Ruby to Java with equivalent syntax and logic. | def indexOf(haystack, needle)
idx = 0
for straw in haystack
if straw == needle then
return idx
else
idx = idx + 1
end
end
return -1
end
def getDigits(n, le, digits)
while n > 0
r = n % 10
if r == 0 or indexOf(digits, r) >= 0 then
return false
end
le = le - 1
digits[le] = r
n = (n / 10).floor
end
return true
end
POWS = [1, 10, 100, 1000, 10000]
def removeDigit(digits, le, idx)
sum = 0
pow = POWS[le - 2]
i = 0
while i < le
if i == idx then
i = i + 1
next
end
sum = sum + digits[i] * pow
pow = (pow / 10).floor
i = i + 1
end
return sum
end
def main
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = Array.new(5, 0)
omitted = Array.new(5) { Array.new(10, 0) }
i = 0
for lim in lims
n = lim[0]
while n < lim[1]
nDigits = [0] * (i + 2)
nOk = getDigits(n, i + 2, nDigits)
if not nOk then
n = n + 1
next
end
d = n + 1
while d <= lim[1] + 1
dDigits = [0] * (i + 2)
dOk = getDigits(d, i + 2, dDigits)
if not dOk then
d = d + 1
next
end
nix = 0
while nix < nDigits.length
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0 then
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd) then
count[i] = count[i] + 1
omitted[i][digit] = omitted[i][digit] + 1
if count[i] <= 12 then
print "%d/%d = %d/%d by omitting %d's\n" % [n, d, rn, rd, digit]
end
end
end
nix = nix + 1
end
d = d + 1
end
n = n + 1
end
print "\n"
i = i + 1
end
i = 2
while i <= 5
print "There are %d %d-digit fractions of which:\n" % [count[i - 2], i]
j = 1
while j <= 9
if omitted[i - 2][j] == 0 then
j = j + 1
next
end
print "%6s have %d's omitted\n" % [omitted[i - 2][j], j]
j = j + 1
end
print "\n"
i = i + 1
end
end
main()
| import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
public class FractionReduction {
public static void main(String[] args) {
for ( int size = 2 ; size <= 5 ; size++ ) {
reduce(size);
}
}
private static void reduce(int numDigits) {
System.out.printf("Fractions with digits of length %d where cancellation is valid. Examples:%n", numDigits);
int min = (int) Math.pow(10, numDigits-1);
int max = (int) Math.pow(10, numDigits) - 1;
List<Integer> values = new ArrayList<>();
for ( int number = min ; number <= max ; number++ ) {
if ( isValid(number) ) {
values.add(number);
}
}
Map<Integer,Integer> cancelCount = new HashMap<>();
int size = values.size();
int solutions = 0;
for ( int nIndex = 0 ; nIndex < size - 1 ; nIndex++ ) {
int numerator = values.get(nIndex);
for ( int dIndex = nIndex + 1 ; dIndex < size ; dIndex++ ) {
int denominator = values.get(dIndex);
for ( int commonDigit : digitsInCommon(numerator, denominator) ) {
int numRemoved = removeDigit(numerator, commonDigit);
int denRemoved = removeDigit(denominator, commonDigit);
if ( numerator * denRemoved == denominator * numRemoved ) {
solutions++;
cancelCount.merge(commonDigit, 1, (v1, v2) -> v1 + v2);
if ( solutions <= 12 ) {
System.out.printf(" When %d is removed, %d/%d = %d/%d%n", commonDigit, numerator, denominator, numRemoved, denRemoved);
}
}
}
}
}
System.out.printf("Number of fractions where cancellation is valid = %d.%n", solutions);
List<Integer> sorted = new ArrayList<>(cancelCount.keySet());
Collections.sort(sorted);
for ( int removed : sorted ) {
System.out.printf(" The digit %d was removed %d times.%n", removed, cancelCount.get(removed));
}
System.out.println();
}
private static int[] powers = new int[] {1, 10, 100, 1000, 10000, 100000};
private static int removeDigit(int n, int removed) {
int m = 0;
int pow = 0;
while ( n > 0 ) {
int r = n % 10;
if ( r != removed ) {
m = m + r*powers[pow];
pow++;
}
n /= 10;
}
return m;
}
private static List<Integer> digitsInCommon(int n1, int n2) {
int[] count = new int[10];
List<Integer> common = new ArrayList<>();
while ( n1 > 0 ) {
int r = n1 % 10;
count[r] += 1;
n1 /= 10;
}
while ( n2 > 0 ) {
int r = n2 % 10;
if ( count[r] > 0 ) {
common.add(r);
}
n2 /= 10;
}
return common;
}
private static boolean isValid(int num) {
int[] count = new int[10];
while ( num > 0 ) {
int r = num % 10;
if ( r == 0 || count[r] == 1 ) {
return false;
}
count[r] = 1;
num /= 10;
}
return true;
}
}
|
Translate the given Ruby code snippet into Python without altering its behavior. | def indexOf(haystack, needle)
idx = 0
for straw in haystack
if straw == needle then
return idx
else
idx = idx + 1
end
end
return -1
end
def getDigits(n, le, digits)
while n > 0
r = n % 10
if r == 0 or indexOf(digits, r) >= 0 then
return false
end
le = le - 1
digits[le] = r
n = (n / 10).floor
end
return true
end
POWS = [1, 10, 100, 1000, 10000]
def removeDigit(digits, le, idx)
sum = 0
pow = POWS[le - 2]
i = 0
while i < le
if i == idx then
i = i + 1
next
end
sum = sum + digits[i] * pow
pow = (pow / 10).floor
i = i + 1
end
return sum
end
def main
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = Array.new(5, 0)
omitted = Array.new(5) { Array.new(10, 0) }
i = 0
for lim in lims
n = lim[0]
while n < lim[1]
nDigits = [0] * (i + 2)
nOk = getDigits(n, i + 2, nDigits)
if not nOk then
n = n + 1
next
end
d = n + 1
while d <= lim[1] + 1
dDigits = [0] * (i + 2)
dOk = getDigits(d, i + 2, dDigits)
if not dOk then
d = d + 1
next
end
nix = 0
while nix < nDigits.length
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0 then
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd) then
count[i] = count[i] + 1
omitted[i][digit] = omitted[i][digit] + 1
if count[i] <= 12 then
print "%d/%d = %d/%d by omitting %d's\n" % [n, d, rn, rd, digit]
end
end
end
nix = nix + 1
end
d = d + 1
end
n = n + 1
end
print "\n"
i = i + 1
end
i = 2
while i <= 5
print "There are %d %d-digit fractions of which:\n" % [count[i - 2], i]
j = 1
while j <= 9
if omitted[i - 2][j] == 0 then
j = j + 1
next
end
print "%6s have %d's omitted\n" % [omitted[i - 2][j], j]
j = j + 1
end
print "\n"
i = i + 1
end
end
main()
| def indexOf(haystack, needle):
idx = 0
for straw in haystack:
if straw == needle:
return idx
else:
idx += 1
return -1
def getDigits(n, le, digits):
while n > 0:
r = n % 10
if r == 0 or indexOf(digits, r) >= 0:
return False
le -= 1
digits[le] = r
n = int(n / 10)
return True
def removeDigit(digits, le, idx):
pows = [1, 10, 100, 1000, 10000]
sum = 0
pow = pows[le - 2]
i = 0
while i < le:
if i == idx:
i += 1
continue
sum = sum + digits[i] * pow
pow = int(pow / 10)
i += 1
return sum
def main():
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = [0 for i in range(5)]
omitted = [[0 for i in range(10)] for j in range(5)]
i = 0
while i < len(lims):
n = lims[i][0]
while n < lims[i][1]:
nDigits = [0 for k in range(i + 2)]
nOk = getDigits(n, i + 2, nDigits)
if not nOk:
n += 1
continue
d = n + 1
while d <= lims[i][1] + 1:
dDigits = [0 for k in range(i + 2)]
dOk = getDigits(d, i + 2, dDigits)
if not dOk:
d += 1
continue
nix = 0
while nix < len(nDigits):
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0:
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd):
count[i] += 1
omitted[i][digit] += 1
if count[i] <= 12:
print "%d/%d = %d/%d by omitting %d's" % (n, d, rn, rd, digit)
nix += 1
d += 1
n += 1
print
i += 1
i = 2
while i <= 5:
print "There are %d %d-digit fractions of which:" % (count[i - 2], i)
j = 1
while j <= 9:
if omitted[i - 2][j] == 0:
j += 1
continue
print "%6s have %d's omitted" % (omitted[i - 2][j], j)
j += 1
print
i += 1
return None
main()
|
Rewrite this program in VB while keeping its functionality equivalent to the Ruby version. | def indexOf(haystack, needle)
idx = 0
for straw in haystack
if straw == needle then
return idx
else
idx = idx + 1
end
end
return -1
end
def getDigits(n, le, digits)
while n > 0
r = n % 10
if r == 0 or indexOf(digits, r) >= 0 then
return false
end
le = le - 1
digits[le] = r
n = (n / 10).floor
end
return true
end
POWS = [1, 10, 100, 1000, 10000]
def removeDigit(digits, le, idx)
sum = 0
pow = POWS[le - 2]
i = 0
while i < le
if i == idx then
i = i + 1
next
end
sum = sum + digits[i] * pow
pow = (pow / 10).floor
i = i + 1
end
return sum
end
def main
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = Array.new(5, 0)
omitted = Array.new(5) { Array.new(10, 0) }
i = 0
for lim in lims
n = lim[0]
while n < lim[1]
nDigits = [0] * (i + 2)
nOk = getDigits(n, i + 2, nDigits)
if not nOk then
n = n + 1
next
end
d = n + 1
while d <= lim[1] + 1
dDigits = [0] * (i + 2)
dOk = getDigits(d, i + 2, dDigits)
if not dOk then
d = d + 1
next
end
nix = 0
while nix < nDigits.length
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0 then
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd) then
count[i] = count[i] + 1
omitted[i][digit] = omitted[i][digit] + 1
if count[i] <= 12 then
print "%d/%d = %d/%d by omitting %d's\n" % [n, d, rn, rd, digit]
end
end
end
nix = nix + 1
end
d = d + 1
end
n = n + 1
end
print "\n"
i = i + 1
end
i = 2
while i <= 5
print "There are %d %d-digit fractions of which:\n" % [count[i - 2], i]
j = 1
while j <= 9
if omitted[i - 2][j] == 0 then
j = j + 1
next
end
print "%6s have %d's omitted\n" % [omitted[i - 2][j], j]
j = j + 1
end
print "\n"
i = i + 1
end
end
main()
| Module Module1
Function IndexOf(n As Integer, s As Integer()) As Integer
For ii = 1 To s.Length
Dim i = ii - 1
If s(i) = n Then
Return i
End If
Next
Return -1
End Function
Function GetDigits(n As Integer, le As Integer, digits As Integer()) As Boolean
While n > 0
Dim r = n Mod 10
If r = 0 OrElse IndexOf(r, digits) >= 0 Then
Return False
End If
le -= 1
digits(le) = r
n \= 10
End While
Return True
End Function
Function RemoveDigit(digits As Integer(), le As Integer, idx As Integer) As Integer
Dim pows = {1, 10, 100, 1000, 10000}
Dim sum = 0
Dim pow = pows(le - 2)
For ii = 1 To le
Dim i = ii - 1
If i = idx Then
Continue For
End If
sum += digits(i) * pow
pow \= 10
Next
Return sum
End Function
Sub Main()
Dim lims = {{12, 97}, {123, 986}, {1234, 9875}, {12345, 98764}}
Dim count(5) As Integer
Dim omitted(5, 10) As Integer
Dim upperBound = lims.GetLength(0)
For ii = 1 To upperBound
Dim i = ii - 1
Dim nDigits(i + 2 - 1) As Integer
Dim dDigits(i + 2 - 1) As Integer
Dim blank(i + 2 - 1) As Integer
For n = lims(i, 0) To lims(i, 1)
blank.CopyTo(nDigits, 0)
Dim nOk = GetDigits(n, i + 2, nDigits)
If Not nOk Then
Continue For
End If
For d = n + 1 To lims(i, 1) + 1
blank.CopyTo(dDigits, 0)
Dim dOk = GetDigits(d, i + 2, dDigits)
If Not dOk Then
Continue For
End If
For nixt = 1 To nDigits.Length
Dim nix = nixt - 1
Dim digit = nDigits(nix)
Dim dix = IndexOf(digit, dDigits)
If dix >= 0 Then
Dim rn = RemoveDigit(nDigits, i + 2, nix)
Dim rd = RemoveDigit(dDigits, i + 2, dix)
If (n / d) = (rn / rd) Then
count(i) += 1
omitted(i, digit) += 1
If count(i) <= 12 Then
Console.WriteLine("{0}/{1} = {2}/{3} by omitting {4}
End If
End If
End If
Next
Next
Next
Console.WriteLine()
Next
For i = 2 To 5
Console.WriteLine("There are {0} {1}-digit fractions of which:", count(i - 2), i)
For j = 1 To 9
If omitted(i - 2, j) = 0 Then
Continue For
End If
Console.WriteLine("{0,6} have {1}
Next
Console.WriteLine()
Next
End Sub
End Module
|
Port the following code from Ruby to Go with equivalent syntax and logic. | def indexOf(haystack, needle)
idx = 0
for straw in haystack
if straw == needle then
return idx
else
idx = idx + 1
end
end
return -1
end
def getDigits(n, le, digits)
while n > 0
r = n % 10
if r == 0 or indexOf(digits, r) >= 0 then
return false
end
le = le - 1
digits[le] = r
n = (n / 10).floor
end
return true
end
POWS = [1, 10, 100, 1000, 10000]
def removeDigit(digits, le, idx)
sum = 0
pow = POWS[le - 2]
i = 0
while i < le
if i == idx then
i = i + 1
next
end
sum = sum + digits[i] * pow
pow = (pow / 10).floor
i = i + 1
end
return sum
end
def main
lims = [ [ 12, 97 ], [ 123, 986 ], [ 1234, 9875 ], [ 12345, 98764 ] ]
count = Array.new(5, 0)
omitted = Array.new(5) { Array.new(10, 0) }
i = 0
for lim in lims
n = lim[0]
while n < lim[1]
nDigits = [0] * (i + 2)
nOk = getDigits(n, i + 2, nDigits)
if not nOk then
n = n + 1
next
end
d = n + 1
while d <= lim[1] + 1
dDigits = [0] * (i + 2)
dOk = getDigits(d, i + 2, dDigits)
if not dOk then
d = d + 1
next
end
nix = 0
while nix < nDigits.length
digit = nDigits[nix]
dix = indexOf(dDigits, digit)
if dix >= 0 then
rn = removeDigit(nDigits, i + 2, nix)
rd = removeDigit(dDigits, i + 2, dix)
if (1.0 * n / d) == (1.0 * rn / rd) then
count[i] = count[i] + 1
omitted[i][digit] = omitted[i][digit] + 1
if count[i] <= 12 then
print "%d/%d = %d/%d by omitting %d's\n" % [n, d, rn, rd, digit]
end
end
end
nix = nix + 1
end
d = d + 1
end
n = n + 1
end
print "\n"
i = i + 1
end
i = 2
while i <= 5
print "There are %d %d-digit fractions of which:\n" % [count[i - 2], i]
j = 1
while j <= 9
if omitted[i - 2][j] == 0 then
j = j + 1
next
end
print "%6s have %d's omitted\n" % [omitted[i - 2][j], j]
j = j + 1
end
print "\n"
i = i + 1
end
end
main()
| package main
import (
"fmt"
"time"
)
func indexOf(n int, s []int) int {
for i, j := range s {
if n == j {
return i
}
}
return -1
}
func getDigits(n, le int, digits []int) bool {
for n > 0 {
r := n % 10
if r == 0 || indexOf(r, digits) >= 0 {
return false
}
le--
digits[le] = r
n /= 10
}
return true
}
var pows = [5]int{1, 10, 100, 1000, 10000}
func removeDigit(digits []int, le, idx int) int {
sum := 0
pow := pows[le-2]
for i := 0; i < le; i++ {
if i == idx {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
func main() {
start := time.Now()
lims := [5][2]int{
{12, 97},
{123, 986},
{1234, 9875},
{12345, 98764},
{123456, 987653},
}
var count [5]int
var omitted [5][10]int
for i, lim := range lims {
nDigits := make([]int, i+2)
dDigits := make([]int, i+2)
blank := make([]int, i+2)
for n := lim[0]; n <= lim[1]; n++ {
copy(nDigits, blank)
nOk := getDigits(n, i+2, nDigits)
if !nOk {
continue
}
for d := n + 1; d <= lim[1]+1; d++ {
copy(dDigits, blank)
dOk := getDigits(d, i+2, dDigits)
if !dOk {
continue
}
for nix, digit := range nDigits {
if dix := indexOf(digit, dDigits); dix >= 0 {
rn := removeDigit(nDigits, i+2, nix)
rd := removeDigit(dDigits, i+2, dix)
if float64(n)/float64(d) == float64(rn)/float64(rd) {
count[i]++
omitted[i][digit]++
if count[i] <= 12 {
fmt.Printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit)
}
}
}
}
}
}
fmt.Println()
}
for i := 2; i <= 6; i++ {
fmt.Printf("There are %d %d-digit fractions of which:\n", count[i-2], i)
for j := 1; j <= 9; j++ {
if omitted[i-2][j] == 0 {
continue
}
fmt.Printf("%6d have %d's omitted\n", omitted[i-2][j], j)
}
fmt.Println()
}
fmt.Printf("Took %s\n", time.Since(start))
}
|
Port the following code from Scala to C with equivalent syntax and logic. | fun indexOf(n: Int, s: IntArray): Int {
for (i_j in s.withIndex()) {
if (n == i_j.value) {
return i_j.index
}
}
return -1
}
fun getDigits(n: Int, le: Int, digits: IntArray): Boolean {
var mn = n
var mle = le
while (mn > 0) {
val r = mn % 10
if (r == 0 || indexOf(r, digits) >= 0) {
return false
}
mle--
digits[mle] = r
mn /= 10
}
return true
}
val pows = intArrayOf(1, 10, 100, 1_000, 10_000)
fun removeDigit(digits: IntArray, le: Int, idx: Int): Int {
var sum = 0
var pow = pows[le - 2]
for (i in 0 until le) {
if (i == idx) {
continue
}
sum += digits[i] * pow
pow /= 10
}
return sum
}
fun main() {
val lims = listOf(
Pair(12, 97),
Pair(123, 986),
Pair(1234, 9875),
Pair(12345, 98764)
)
val count = IntArray(5)
var omitted = arrayOf<Array<Int>>()
for (i in 0 until 5) {
var array = arrayOf<Int>()
for (j in 0 until 10) {
array += 0
}
omitted += array
}
for (i_lim in lims.withIndex()) {
val i = i_lim.index
val lim = i_lim.value
val nDigits = IntArray(i + 2)
val dDigits = IntArray(i + 2)
val blank = IntArray(i + 2) { 0 }
for (n in lim.first..lim.second) {
blank.copyInto(nDigits)
val nOk = getDigits(n, i + 2, nDigits)
if (!nOk) {
continue
}
for (d in n + 1..lim.second + 1) {
blank.copyInto(dDigits)
val dOk = getDigits(d, i + 2, dDigits)
if (!dOk) {
continue
}
for (nix_digit in nDigits.withIndex()) {
val dix = indexOf(nix_digit.value, dDigits)
if (dix >= 0) {
val rn = removeDigit(nDigits, i + 2, nix_digit.index)
val rd = removeDigit(dDigits, i + 2, dix)
if (n.toDouble() / d.toDouble() == rn.toDouble() / rd.toDouble()) {
count[i]++
omitted[i][nix_digit.value]++
if (count[i] <= 12) {
println("$n/$d = $rn/$rd by omitting ${nix_digit.value}'s")
}
}
}
}
}
}
println()
}
for (i in 2..5) {
println("There are ${count[i - 2]} $i-digit fractions of which:")
for (j in 1..9) {
if (omitted[i - 2][j] == 0) {
continue
}
println("%6d have %d's omitted".format(omitted[i - 2][j], j))
}
println()
}
}
| #include <stdbool.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
typedef struct IntArray_t {
int *ptr;
size_t length;
} IntArray;
IntArray make(size_t size) {
IntArray temp;
temp.ptr = calloc(size, sizeof(int));
temp.length = size;
return temp;
}
void destroy(IntArray *ia) {
if (ia->ptr != NULL) {
free(ia->ptr);
ia->ptr = NULL;
ia->length = 0;
}
}
void zeroFill(IntArray dst) {
memset(dst.ptr, 0, dst.length * sizeof(int));
}
int indexOf(const int n, const IntArray ia) {
size_t i;
for (i = 0; i < ia.length; i++) {
if (ia.ptr[i] == n) {
return i;
}
}
return -1;
}
bool getDigits(int n, int le, IntArray digits) {
while (n > 0) {
int r = n % 10;
if (r == 0 || indexOf(r, digits) >= 0) {
return false;
}
le--;
digits.ptr[le] = r;
n /= 10;
}
return true;
}
int removeDigit(IntArray digits, size_t le, size_t idx) {
static const int POWS[] = { 1, 10, 100, 1000, 10000 };
int sum = 0;
int pow = POWS[le - 2];
size_t i;
for (i = 0; i < le; i++) {
if (i == idx) continue;
sum += digits.ptr[i] * pow;
pow /= 10;
}
return sum;
}
int main() {
int lims[4][2] = { { 12, 97 }, { 123, 986 }, { 1234, 9875 }, { 12345, 98764 } };
int count[5] = { 0 };
int omitted[5][10] = { {0} };
size_t upperBound = sizeof(lims) / sizeof(lims[0]);
size_t i;
for (i = 0; i < upperBound; i++) {
IntArray nDigits = make(i + 2);
IntArray dDigits = make(i + 2);
int n;
for (n = lims[i][0]; n <= lims[i][1]; n++) {
int d;
bool nOk;
zeroFill(nDigits);
nOk = getDigits(n, i + 2, nDigits);
if (!nOk) {
continue;
}
for (d = n + 1; d <= lims[i][1] + 1; d++) {
size_t nix;
bool dOk;
zeroFill(dDigits);
dOk = getDigits(d, i + 2, dDigits);
if (!dOk) {
continue;
}
for (nix = 0; nix < nDigits.length; nix++) {
int digit = nDigits.ptr[nix];
int dix = indexOf(digit, dDigits);
if (dix >= 0) {
int rn = removeDigit(nDigits, i + 2, nix);
int rd = removeDigit(dDigits, i + 2, dix);
if ((double)n / d == (double)rn / rd) {
count[i]++;
omitted[i][digit]++;
if (count[i] <= 12) {
printf("%d/%d = %d/%d by omitting %d's\n", n, d, rn, rd, digit);
}
}
}
}
}
}
printf("\n");
destroy(&nDigits);
destroy(&dDigits);
}
for (i = 2; i <= 5; i++) {
int j;
printf("There are %d %d-digit fractions of which:\n", count[i - 2], i);
for (j = 1; j <= 9; j++) {
if (omitted[i - 2][j] == 0) {
continue;
}
printf("%6d have %d's omitted\n", omitted[i - 2][j], j);
}
printf("\n");
}
return 0;
}
|
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