Instruction stringlengths 45 106 | input_code stringlengths 1 13.7k | output_code stringlengths 1 13.7k |
|---|---|---|
Rewrite the snippet below in C++ so it works the same as the original Fortran code. | program Primes
use ISO_FORTRAN_ENV
implicit none
integer(int64), dimension(7) :: data = (/2099726827, 15780709, 1122725370, 15808973, 576460741, 12878611, 12757923/)
integer(int64), dimension(100) :: outprimes
integer(int64) :: largest_factor = 0, largest = 0, minim = 0, val = 0
integer(int16) :: count = 0, OMP_GET_THREAD_NUM
call omp_set_num_threads(4);
do val = 1, 7
outprimes = 0
call find_factors(data(val), outprimes, count)
minim = minval(outprimes(1:count))
if (minim > largest_factor) then
largest_factor = minim
largest = data(val)
end if
write(*, fmt = '(A7,i0,A2,i12,100i12)') 'Thread ', OMP_GET_THREAD_NUM(), ': ', data(val), outprimes(1:count)
end do
write(*, fmt = '(i0,A26,i0)') largest, ' have the Largest factor: ', largest_factor
return
contains
subroutine find_factors(n, d, count)
integer(int64), intent(in) :: n
integer(int64), dimension(:), intent(out) :: d
integer(int16), intent(out) :: count
integer(int16) :: i
integer(int64) :: div, next, rest
i = 1
div = 2; next = 3; rest = n
do while (rest /= 1)
do while (mod(rest, div) == 0)
d(i) = div
i = i + 1
rest = rest / div
end do
div = next
next = next + 2
end do
count = i - 1
end subroutine find_factors
end program Primes
| #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
Translate the given Fortran code snippet into C without altering its behavior. | program Primes
use ISO_FORTRAN_ENV
implicit none
integer(int64), dimension(7) :: data = (/2099726827, 15780709, 1122725370, 15808973, 576460741, 12878611, 12757923/)
integer(int64), dimension(100) :: outprimes
integer(int64) :: largest_factor = 0, largest = 0, minim = 0, val = 0
integer(int16) :: count = 0, OMP_GET_THREAD_NUM
call omp_set_num_threads(4);
do val = 1, 7
outprimes = 0
call find_factors(data(val), outprimes, count)
minim = minval(outprimes(1:count))
if (minim > largest_factor) then
largest_factor = minim
largest = data(val)
end if
write(*, fmt = '(A7,i0,A2,i12,100i12)') 'Thread ', OMP_GET_THREAD_NUM(), ': ', data(val), outprimes(1:count)
end do
write(*, fmt = '(i0,A26,i0)') largest, ' have the Largest factor: ', largest_factor
return
contains
subroutine find_factors(n, d, count)
integer(int64), intent(in) :: n
integer(int64), dimension(:), intent(out) :: d
integer(int16), intent(out) :: count
integer(int16) :: i
integer(int64) :: div, next, rest
i = 1
div = 2; next = 3; rest = n
do while (rest /= 1)
do while (mod(rest, div) == 0)
d(i) = div
i = i + 1
rest = rest / div
end do
div = next
next = next + 2
end do
count = i - 1
end subroutine find_factors
end program Primes
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Generate a Java translation of this Fortran snippet without changing its computational steps. | program Primes
use ISO_FORTRAN_ENV
implicit none
integer(int64), dimension(7) :: data = (/2099726827, 15780709, 1122725370, 15808973, 576460741, 12878611, 12757923/)
integer(int64), dimension(100) :: outprimes
integer(int64) :: largest_factor = 0, largest = 0, minim = 0, val = 0
integer(int16) :: count = 0, OMP_GET_THREAD_NUM
call omp_set_num_threads(4);
do val = 1, 7
outprimes = 0
call find_factors(data(val), outprimes, count)
minim = minval(outprimes(1:count))
if (minim > largest_factor) then
largest_factor = minim
largest = data(val)
end if
write(*, fmt = '(A7,i0,A2,i12,100i12)') 'Thread ', OMP_GET_THREAD_NUM(), ': ', data(val), outprimes(1:count)
end do
write(*, fmt = '(i0,A26,i0)') largest, ' have the Largest factor: ', largest_factor
return
contains
subroutine find_factors(n, d, count)
integer(int64), intent(in) :: n
integer(int64), dimension(:), intent(out) :: d
integer(int16), intent(out) :: count
integer(int16) :: i
integer(int64) :: div, next, rest
i = 1
div = 2; next = 3; rest = n
do while (rest /= 1)
do while (mod(rest, div) == 0)
d(i) = div
i = i + 1
rest = rest / div
end do
div = next
next = next + 2
end do
count = i - 1
end subroutine find_factors
end program Primes
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Convert this Fortran snippet to Python and keep its semantics consistent. | program Primes
use ISO_FORTRAN_ENV
implicit none
integer(int64), dimension(7) :: data = (/2099726827, 15780709, 1122725370, 15808973, 576460741, 12878611, 12757923/)
integer(int64), dimension(100) :: outprimes
integer(int64) :: largest_factor = 0, largest = 0, minim = 0, val = 0
integer(int16) :: count = 0, OMP_GET_THREAD_NUM
call omp_set_num_threads(4);
do val = 1, 7
outprimes = 0
call find_factors(data(val), outprimes, count)
minim = minval(outprimes(1:count))
if (minim > largest_factor) then
largest_factor = minim
largest = data(val)
end if
write(*, fmt = '(A7,i0,A2,i12,100i12)') 'Thread ', OMP_GET_THREAD_NUM(), ': ', data(val), outprimes(1:count)
end do
write(*, fmt = '(i0,A26,i0)') largest, ' have the Largest factor: ', largest_factor
return
contains
subroutine find_factors(n, d, count)
integer(int64), intent(in) :: n
integer(int64), dimension(:), intent(out) :: d
integer(int16), intent(out) :: count
integer(int16) :: i
integer(int64) :: div, next, rest
i = 1
div = 2; next = 3; rest = n
do while (rest /= 1)
do while (mod(rest, div) == 0)
d(i) = div
i = i + 1
rest = rest / div
end do
div = next
next = next + 2
end do
count = i - 1
end subroutine find_factors
end program Primes
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Write the same algorithm in C as shown in this Haskell implementation. | import Control.Parallel.Strategies (parMap, rdeepseq)
import Control.DeepSeq (NFData)
import Data.List (maximumBy)
import Data.Function (on)
nums :: [Integer]
nums =
[ 112272537195293
, 112582718962171
, 112272537095293
, 115280098190773
, 115797840077099
, 1099726829285419
]
lowestFactor
:: Integral a
=> a -> a -> a
lowestFactor s n
| even n = 2
| otherwise = head y
where
y =
[ x
| x <- [s .. ceiling . sqrt $ fromIntegral n] ++ [n]
, n `rem` x == 0
, odd x ]
primeFactors
:: Integral a
=> a -> a -> [a]
primeFactors l n = f n l []
where
f n l xs =
if n > 1
then f (n `div` l) (lowestFactor (max l 3) (n `div` l)) (l : xs)
else xs
minPrimes
:: (Control.DeepSeq.NFData a, Integral a)
=> [a] -> (a, [a])
minPrimes ns =
(\(x, y) -> (x, primeFactors y x)) $
maximumBy (compare `on` snd) $ zip ns (parMap rdeepseq (lowestFactor 3) ns)
main :: IO ()
main = print $ minPrimes nums
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Translate the given Haskell code snippet into C# without altering its behavior. | import Control.Parallel.Strategies (parMap, rdeepseq)
import Control.DeepSeq (NFData)
import Data.List (maximumBy)
import Data.Function (on)
nums :: [Integer]
nums =
[ 112272537195293
, 112582718962171
, 112272537095293
, 115280098190773
, 115797840077099
, 1099726829285419
]
lowestFactor
:: Integral a
=> a -> a -> a
lowestFactor s n
| even n = 2
| otherwise = head y
where
y =
[ x
| x <- [s .. ceiling . sqrt $ fromIntegral n] ++ [n]
, n `rem` x == 0
, odd x ]
primeFactors
:: Integral a
=> a -> a -> [a]
primeFactors l n = f n l []
where
f n l xs =
if n > 1
then f (n `div` l) (lowestFactor (max l 3) (n `div` l)) (l : xs)
else xs
minPrimes
:: (Control.DeepSeq.NFData a, Integral a)
=> [a] -> (a, [a])
minPrimes ns =
(\(x, y) -> (x, primeFactors y x)) $
maximumBy (compare `on` snd) $ zip ns (parMap rdeepseq (lowestFactor 3) ns)
main :: IO ()
main = print $ minPrimes nums
| using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
Rewrite the snippet below in C++ so it works the same as the original Haskell code. | import Control.Parallel.Strategies (parMap, rdeepseq)
import Control.DeepSeq (NFData)
import Data.List (maximumBy)
import Data.Function (on)
nums :: [Integer]
nums =
[ 112272537195293
, 112582718962171
, 112272537095293
, 115280098190773
, 115797840077099
, 1099726829285419
]
lowestFactor
:: Integral a
=> a -> a -> a
lowestFactor s n
| even n = 2
| otherwise = head y
where
y =
[ x
| x <- [s .. ceiling . sqrt $ fromIntegral n] ++ [n]
, n `rem` x == 0
, odd x ]
primeFactors
:: Integral a
=> a -> a -> [a]
primeFactors l n = f n l []
where
f n l xs =
if n > 1
then f (n `div` l) (lowestFactor (max l 3) (n `div` l)) (l : xs)
else xs
minPrimes
:: (Control.DeepSeq.NFData a, Integral a)
=> [a] -> (a, [a])
minPrimes ns =
(\(x, y) -> (x, primeFactors y x)) $
maximumBy (compare `on` snd) $ zip ns (parMap rdeepseq (lowestFactor 3) ns)
main :: IO ()
main = print $ minPrimes nums
| #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
Ensure the translated Java code behaves exactly like the original Haskell snippet. | import Control.Parallel.Strategies (parMap, rdeepseq)
import Control.DeepSeq (NFData)
import Data.List (maximumBy)
import Data.Function (on)
nums :: [Integer]
nums =
[ 112272537195293
, 112582718962171
, 112272537095293
, 115280098190773
, 115797840077099
, 1099726829285419
]
lowestFactor
:: Integral a
=> a -> a -> a
lowestFactor s n
| even n = 2
| otherwise = head y
where
y =
[ x
| x <- [s .. ceiling . sqrt $ fromIntegral n] ++ [n]
, n `rem` x == 0
, odd x ]
primeFactors
:: Integral a
=> a -> a -> [a]
primeFactors l n = f n l []
where
f n l xs =
if n > 1
then f (n `div` l) (lowestFactor (max l 3) (n `div` l)) (l : xs)
else xs
minPrimes
:: (Control.DeepSeq.NFData a, Integral a)
=> [a] -> (a, [a])
minPrimes ns =
(\(x, y) -> (x, primeFactors y x)) $
maximumBy (compare `on` snd) $ zip ns (parMap rdeepseq (lowestFactor 3) ns)
main :: IO ()
main = print $ minPrimes nums
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Change the programming language of this snippet from Haskell to Python without modifying what it does. | import Control.Parallel.Strategies (parMap, rdeepseq)
import Control.DeepSeq (NFData)
import Data.List (maximumBy)
import Data.Function (on)
nums :: [Integer]
nums =
[ 112272537195293
, 112582718962171
, 112272537095293
, 115280098190773
, 115797840077099
, 1099726829285419
]
lowestFactor
:: Integral a
=> a -> a -> a
lowestFactor s n
| even n = 2
| otherwise = head y
where
y =
[ x
| x <- [s .. ceiling . sqrt $ fromIntegral n] ++ [n]
, n `rem` x == 0
, odd x ]
primeFactors
:: Integral a
=> a -> a -> [a]
primeFactors l n = f n l []
where
f n l xs =
if n > 1
then f (n `div` l) (lowestFactor (max l 3) (n `div` l)) (l : xs)
else xs
minPrimes
:: (Control.DeepSeq.NFData a, Integral a)
=> [a] -> (a, [a])
minPrimes ns =
(\(x, y) -> (x, primeFactors y x)) $
maximumBy (compare `on` snd) $ zip ns (parMap rdeepseq (lowestFactor 3) ns)
main :: IO ()
main = print $ minPrimes nums
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Write the same algorithm in Go as shown in this Haskell implementation. | import Control.Parallel.Strategies (parMap, rdeepseq)
import Control.DeepSeq (NFData)
import Data.List (maximumBy)
import Data.Function (on)
nums :: [Integer]
nums =
[ 112272537195293
, 112582718962171
, 112272537095293
, 115280098190773
, 115797840077099
, 1099726829285419
]
lowestFactor
:: Integral a
=> a -> a -> a
lowestFactor s n
| even n = 2
| otherwise = head y
where
y =
[ x
| x <- [s .. ceiling . sqrt $ fromIntegral n] ++ [n]
, n `rem` x == 0
, odd x ]
primeFactors
:: Integral a
=> a -> a -> [a]
primeFactors l n = f n l []
where
f n l xs =
if n > 1
then f (n `div` l) (lowestFactor (max l 3) (n `div` l)) (l : xs)
else xs
minPrimes
:: (Control.DeepSeq.NFData a, Integral a)
=> [a] -> (a, [a])
minPrimes ns =
(\(x, y) -> (x, primeFactors y x)) $
maximumBy (compare `on` snd) $ zip ns (parMap rdeepseq (lowestFactor 3) ns)
main :: IO ()
main = print $ minPrimes nums
| package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
Keep all operations the same but rewrite the snippet in C. | numbers =. 12757923 12878611 12878893 12757923 15808973 15780709 197622519
factors =. q:&.> parallelize 2 numbers
ind =. (i. >./) <./@> factors
ind { numbers ;"_1 factors
┌────────┬───────────┐
│12878611│47 101 2713│
└────────┴───────────┘
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Port the provided J code into C# while preserving the original functionality. | numbers =. 12757923 12878611 12878893 12757923 15808973 15780709 197622519
factors =. q:&.> parallelize 2 numbers
ind =. (i. >./) <./@> factors
ind { numbers ;"_1 factors
┌────────┬───────────┐
│12878611│47 101 2713│
└────────┴───────────┘
| using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
Rewrite this program in Java while keeping its functionality equivalent to the J version. | numbers =. 12757923 12878611 12878893 12757923 15808973 15780709 197622519
factors =. q:&.> parallelize 2 numbers
ind =. (i. >./) <./@> factors
ind { numbers ;"_1 factors
┌────────┬───────────┐
│12878611│47 101 2713│
└────────┴───────────┘
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Convert this J snippet to Python and keep its semantics consistent. | numbers =. 12757923 12878611 12878893 12757923 15808973 15780709 197622519
factors =. q:&.> parallelize 2 numbers
ind =. (i. >./) <./@> factors
ind { numbers ;"_1 factors
┌────────┬───────────┐
│12878611│47 101 2713│
└────────┴───────────┘
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Translate the given J code snippet into Go without altering its behavior. | numbers =. 12757923 12878611 12878893 12757923 15808973 15780709 197622519
factors =. q:&.> parallelize 2 numbers
ind =. (i. >./) <./@> factors
ind { numbers ;"_1 factors
┌────────┬───────────┐
│12878611│47 101 2713│
└────────┴───────────┘
| package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
Write the same algorithm in C as shown in this Julia implementation. | using Primes
factortodict(d, n) = (d[minimum(collect(keys(factor(n))))] = n)
numbers = [64921987050997300559, 70251412046988563035, 71774104902986066597,
83448083465633593921, 84209429893632345702, 87001033462961102237,
87762379890959854011, 89538854889623608177, 98421229882942378967,
259826672618677756753, 262872058330672763871, 267440136898665274575,
278352769033314050117, 281398154745309057242, 292057004737291582187]
mins = Dict()
Base.@sync(
Threads.@threads for n in numbers
factortodict(mins, n)
end
)
answer = maximum(keys(mins))
println("The number that has the largest minimum prime factor is $(mins[answer]), with a smallest factor of $answer")
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Ensure the translated C# code behaves exactly like the original Julia snippet. | using Primes
factortodict(d, n) = (d[minimum(collect(keys(factor(n))))] = n)
numbers = [64921987050997300559, 70251412046988563035, 71774104902986066597,
83448083465633593921, 84209429893632345702, 87001033462961102237,
87762379890959854011, 89538854889623608177, 98421229882942378967,
259826672618677756753, 262872058330672763871, 267440136898665274575,
278352769033314050117, 281398154745309057242, 292057004737291582187]
mins = Dict()
Base.@sync(
Threads.@threads for n in numbers
factortodict(mins, n)
end
)
answer = maximum(keys(mins))
println("The number that has the largest minimum prime factor is $(mins[answer]), with a smallest factor of $answer")
| using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
Keep all operations the same but rewrite the snippet in C++. | using Primes
factortodict(d, n) = (d[minimum(collect(keys(factor(n))))] = n)
numbers = [64921987050997300559, 70251412046988563035, 71774104902986066597,
83448083465633593921, 84209429893632345702, 87001033462961102237,
87762379890959854011, 89538854889623608177, 98421229882942378967,
259826672618677756753, 262872058330672763871, 267440136898665274575,
278352769033314050117, 281398154745309057242, 292057004737291582187]
mins = Dict()
Base.@sync(
Threads.@threads for n in numbers
factortodict(mins, n)
end
)
answer = maximum(keys(mins))
println("The number that has the largest minimum prime factor is $(mins[answer]), with a smallest factor of $answer")
| #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
Change the programming language of this snippet from Julia to Java without modifying what it does. | using Primes
factortodict(d, n) = (d[minimum(collect(keys(factor(n))))] = n)
numbers = [64921987050997300559, 70251412046988563035, 71774104902986066597,
83448083465633593921, 84209429893632345702, 87001033462961102237,
87762379890959854011, 89538854889623608177, 98421229882942378967,
259826672618677756753, 262872058330672763871, 267440136898665274575,
278352769033314050117, 281398154745309057242, 292057004737291582187]
mins = Dict()
Base.@sync(
Threads.@threads for n in numbers
factortodict(mins, n)
end
)
answer = maximum(keys(mins))
println("The number that has the largest minimum prime factor is $(mins[answer]), with a smallest factor of $answer")
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Translate the given Julia code snippet into Python without altering its behavior. | using Primes
factortodict(d, n) = (d[minimum(collect(keys(factor(n))))] = n)
numbers = [64921987050997300559, 70251412046988563035, 71774104902986066597,
83448083465633593921, 84209429893632345702, 87001033462961102237,
87762379890959854011, 89538854889623608177, 98421229882942378967,
259826672618677756753, 262872058330672763871, 267440136898665274575,
278352769033314050117, 281398154745309057242, 292057004737291582187]
mins = Dict()
Base.@sync(
Threads.@threads for n in numbers
factortodict(mins, n)
end
)
answer = maximum(keys(mins))
println("The number that has the largest minimum prime factor is $(mins[answer]), with a smallest factor of $answer")
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Change the following Julia code into Go without altering its purpose. | using Primes
factortodict(d, n) = (d[minimum(collect(keys(factor(n))))] = n)
numbers = [64921987050997300559, 70251412046988563035, 71774104902986066597,
83448083465633593921, 84209429893632345702, 87001033462961102237,
87762379890959854011, 89538854889623608177, 98421229882942378967,
259826672618677756753, 262872058330672763871, 267440136898665274575,
278352769033314050117, 281398154745309057242, 292057004737291582187]
mins = Dict()
Base.@sync(
Threads.@threads for n in numbers
factortodict(mins, n)
end
)
answer = maximum(keys(mins))
println("The number that has the largest minimum prime factor is $(mins[answer]), with a smallest factor of $answer")
| package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
Generate a C translation of this Mathematica snippet without changing its computational steps. | hasSmallestFactor[data_List]:=Sort[Transpose[{ParallelTable[FactorInteger[x][[1, 1]], {x, data}],data}]][[1, 2]]
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Please provide an equivalent version of this Mathematica code in C#. | hasSmallestFactor[data_List]:=Sort[Transpose[{ParallelTable[FactorInteger[x][[1, 1]], {x, data}],data}]][[1, 2]]
| using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
Please provide an equivalent version of this Mathematica code in C++. | hasSmallestFactor[data_List]:=Sort[Transpose[{ParallelTable[FactorInteger[x][[1, 1]], {x, data}],data}]][[1, 2]]
| #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
Transform the following Mathematica implementation into Java, maintaining the same output and logic. | hasSmallestFactor[data_List]:=Sort[Transpose[{ParallelTable[FactorInteger[x][[1, 1]], {x, data}],data}]][[1, 2]]
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Write the same code in Python as shown below in Mathematica. | hasSmallestFactor[data_List]:=Sort[Transpose[{ParallelTable[FactorInteger[x][[1, 1]], {x, data}],data}]][[1, 2]]
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Convert the following code from Mathematica to Go, ensuring the logic remains intact. | hasSmallestFactor[data_List]:=Sort[Transpose[{ParallelTable[FactorInteger[x][[1, 1]], {x, data}],data}]][[1, 2]]
| package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
Convert this Nim block to C, preserving its control flow and logic. | import strformat, strutils, threadpool
const Numbers = [576460752303423487,
576460752303423487,
576460752303423487,
112272537195293,
115284584522153,
115280098190773,
115797840077099,
112582718962171,
299866111963290359]
proc lowestFactor(n: int64): int64 =
if n mod 2 == 0: return 2
if n mod 3 == 0: return 3
var p = 5
var delta = 2
while p * p < n:
if n mod p == 0: return p
inc p, delta
delta = 6 - delta
result = n
proc factors(n, lowest: int64): seq[int64] =
var n = n
var lowest = lowest
while true:
result.add lowest
n = n div lowest
if n == 1: break
lowest = lowestFactor(n)
var responses: array[Numbers.len, FlowVar[int64]]
for i, n in Numbers:
responses[i] = spawn lowestFactor(n)
var maxMinfact = 0i64
var maxIdx: int
for i in 0..responses.high:
let minfact = ^responses[i]
echo &"For n = {Numbers[i]}, the lowest factor is {minfact}."
if minfact > maxMinfact:
maxMinfact = minfact
maxIdx = i
let result = Numbers[maxIdx]
echo ""
echo "The first number with the largest minimum prime factor is: ", result
echo "Its factors are: ", result.factors(maxMinfact).join(", ")
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Change the programming language of this snippet from Nim to C# without modifying what it does. | import strformat, strutils, threadpool
const Numbers = [576460752303423487,
576460752303423487,
576460752303423487,
112272537195293,
115284584522153,
115280098190773,
115797840077099,
112582718962171,
299866111963290359]
proc lowestFactor(n: int64): int64 =
if n mod 2 == 0: return 2
if n mod 3 == 0: return 3
var p = 5
var delta = 2
while p * p < n:
if n mod p == 0: return p
inc p, delta
delta = 6 - delta
result = n
proc factors(n, lowest: int64): seq[int64] =
var n = n
var lowest = lowest
while true:
result.add lowest
n = n div lowest
if n == 1: break
lowest = lowestFactor(n)
var responses: array[Numbers.len, FlowVar[int64]]
for i, n in Numbers:
responses[i] = spawn lowestFactor(n)
var maxMinfact = 0i64
var maxIdx: int
for i in 0..responses.high:
let minfact = ^responses[i]
echo &"For n = {Numbers[i]}, the lowest factor is {minfact}."
if minfact > maxMinfact:
maxMinfact = minfact
maxIdx = i
let result = Numbers[maxIdx]
echo ""
echo "The first number with the largest minimum prime factor is: ", result
echo "Its factors are: ", result.factors(maxMinfact).join(", ")
| using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
Ensure the translated C++ code behaves exactly like the original Nim snippet. | import strformat, strutils, threadpool
const Numbers = [576460752303423487,
576460752303423487,
576460752303423487,
112272537195293,
115284584522153,
115280098190773,
115797840077099,
112582718962171,
299866111963290359]
proc lowestFactor(n: int64): int64 =
if n mod 2 == 0: return 2
if n mod 3 == 0: return 3
var p = 5
var delta = 2
while p * p < n:
if n mod p == 0: return p
inc p, delta
delta = 6 - delta
result = n
proc factors(n, lowest: int64): seq[int64] =
var n = n
var lowest = lowest
while true:
result.add lowest
n = n div lowest
if n == 1: break
lowest = lowestFactor(n)
var responses: array[Numbers.len, FlowVar[int64]]
for i, n in Numbers:
responses[i] = spawn lowestFactor(n)
var maxMinfact = 0i64
var maxIdx: int
for i in 0..responses.high:
let minfact = ^responses[i]
echo &"For n = {Numbers[i]}, the lowest factor is {minfact}."
if minfact > maxMinfact:
maxMinfact = minfact
maxIdx = i
let result = Numbers[maxIdx]
echo ""
echo "The first number with the largest minimum prime factor is: ", result
echo "Its factors are: ", result.factors(maxMinfact).join(", ")
| #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
Convert the following code from Nim to Java, ensuring the logic remains intact. | import strformat, strutils, threadpool
const Numbers = [576460752303423487,
576460752303423487,
576460752303423487,
112272537195293,
115284584522153,
115280098190773,
115797840077099,
112582718962171,
299866111963290359]
proc lowestFactor(n: int64): int64 =
if n mod 2 == 0: return 2
if n mod 3 == 0: return 3
var p = 5
var delta = 2
while p * p < n:
if n mod p == 0: return p
inc p, delta
delta = 6 - delta
result = n
proc factors(n, lowest: int64): seq[int64] =
var n = n
var lowest = lowest
while true:
result.add lowest
n = n div lowest
if n == 1: break
lowest = lowestFactor(n)
var responses: array[Numbers.len, FlowVar[int64]]
for i, n in Numbers:
responses[i] = spawn lowestFactor(n)
var maxMinfact = 0i64
var maxIdx: int
for i in 0..responses.high:
let minfact = ^responses[i]
echo &"For n = {Numbers[i]}, the lowest factor is {minfact}."
if minfact > maxMinfact:
maxMinfact = minfact
maxIdx = i
let result = Numbers[maxIdx]
echo ""
echo "The first number with the largest minimum prime factor is: ", result
echo "Its factors are: ", result.factors(maxMinfact).join(", ")
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Write the same code in Python as shown below in Nim. | import strformat, strutils, threadpool
const Numbers = [576460752303423487,
576460752303423487,
576460752303423487,
112272537195293,
115284584522153,
115280098190773,
115797840077099,
112582718962171,
299866111963290359]
proc lowestFactor(n: int64): int64 =
if n mod 2 == 0: return 2
if n mod 3 == 0: return 3
var p = 5
var delta = 2
while p * p < n:
if n mod p == 0: return p
inc p, delta
delta = 6 - delta
result = n
proc factors(n, lowest: int64): seq[int64] =
var n = n
var lowest = lowest
while true:
result.add lowest
n = n div lowest
if n == 1: break
lowest = lowestFactor(n)
var responses: array[Numbers.len, FlowVar[int64]]
for i, n in Numbers:
responses[i] = spawn lowestFactor(n)
var maxMinfact = 0i64
var maxIdx: int
for i in 0..responses.high:
let minfact = ^responses[i]
echo &"For n = {Numbers[i]}, the lowest factor is {minfact}."
if minfact > maxMinfact:
maxMinfact = minfact
maxIdx = i
let result = Numbers[maxIdx]
echo ""
echo "The first number with the largest minimum prime factor is: ", result
echo "Its factors are: ", result.factors(maxMinfact).join(", ")
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Produce a language-to-language conversion: from Nim to Go, same semantics. | import strformat, strutils, threadpool
const Numbers = [576460752303423487,
576460752303423487,
576460752303423487,
112272537195293,
115284584522153,
115280098190773,
115797840077099,
112582718962171,
299866111963290359]
proc lowestFactor(n: int64): int64 =
if n mod 2 == 0: return 2
if n mod 3 == 0: return 3
var p = 5
var delta = 2
while p * p < n:
if n mod p == 0: return p
inc p, delta
delta = 6 - delta
result = n
proc factors(n, lowest: int64): seq[int64] =
var n = n
var lowest = lowest
while true:
result.add lowest
n = n div lowest
if n == 1: break
lowest = lowestFactor(n)
var responses: array[Numbers.len, FlowVar[int64]]
for i, n in Numbers:
responses[i] = spawn lowestFactor(n)
var maxMinfact = 0i64
var maxIdx: int
for i in 0..responses.high:
let minfact = ^responses[i]
echo &"For n = {Numbers[i]}, the lowest factor is {minfact}."
if minfact > maxMinfact:
maxMinfact = minfact
maxIdx = i
let result = Numbers[maxIdx]
echo ""
echo "The first number with the largest minimum prime factor is: ", result
echo "Its factors are: ", result.factors(maxMinfact).join(", ")
| package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
Produce a language-to-language conversion: from Perl to C, same semantics. | use ntheory qw/factor vecmax/;
use threads;
use threads::shared;
my @results :shared;
my $tnum = 0;
$_->join() for
map { threads->create('tfactor', $tnum++, $_) }
(qw/576460752303423487 576460752303423487 576460752303423487 112272537195293
115284584522153 115280098190773 115797840077099 112582718962171 299866111963290359/);
my $lmf = vecmax( map { $_->[1] } @results );
print "Largest minimal factor of $lmf found in:\n";
print " $_->[0] = [@$_[1..$
sub tfactor {
my($tnum, $n) = @_;
push @results, shared_clone([$n, factor($n)]);
}
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Port the provided Perl code into C# while preserving the original functionality. | use ntheory qw/factor vecmax/;
use threads;
use threads::shared;
my @results :shared;
my $tnum = 0;
$_->join() for
map { threads->create('tfactor', $tnum++, $_) }
(qw/576460752303423487 576460752303423487 576460752303423487 112272537195293
115284584522153 115280098190773 115797840077099 112582718962171 299866111963290359/);
my $lmf = vecmax( map { $_->[1] } @results );
print "Largest minimal factor of $lmf found in:\n";
print " $_->[0] = [@$_[1..$
sub tfactor {
my($tnum, $n) = @_;
push @results, shared_clone([$n, factor($n)]);
}
| using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
Port the following code from Perl to C++ with equivalent syntax and logic. | use ntheory qw/factor vecmax/;
use threads;
use threads::shared;
my @results :shared;
my $tnum = 0;
$_->join() for
map { threads->create('tfactor', $tnum++, $_) }
(qw/576460752303423487 576460752303423487 576460752303423487 112272537195293
115284584522153 115280098190773 115797840077099 112582718962171 299866111963290359/);
my $lmf = vecmax( map { $_->[1] } @results );
print "Largest minimal factor of $lmf found in:\n";
print " $_->[0] = [@$_[1..$
sub tfactor {
my($tnum, $n) = @_;
push @results, shared_clone([$n, factor($n)]);
}
| #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
Change the following Perl code into Java without altering its purpose. | use ntheory qw/factor vecmax/;
use threads;
use threads::shared;
my @results :shared;
my $tnum = 0;
$_->join() for
map { threads->create('tfactor', $tnum++, $_) }
(qw/576460752303423487 576460752303423487 576460752303423487 112272537195293
115284584522153 115280098190773 115797840077099 112582718962171 299866111963290359/);
my $lmf = vecmax( map { $_->[1] } @results );
print "Largest minimal factor of $lmf found in:\n";
print " $_->[0] = [@$_[1..$
sub tfactor {
my($tnum, $n) = @_;
push @results, shared_clone([$n, factor($n)]);
}
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Rewrite this program in Python while keeping its functionality equivalent to the Perl version. | use ntheory qw/factor vecmax/;
use threads;
use threads::shared;
my @results :shared;
my $tnum = 0;
$_->join() for
map { threads->create('tfactor', $tnum++, $_) }
(qw/576460752303423487 576460752303423487 576460752303423487 112272537195293
115284584522153 115280098190773 115797840077099 112582718962171 299866111963290359/);
my $lmf = vecmax( map { $_->[1] } @results );
print "Largest minimal factor of $lmf found in:\n";
print " $_->[0] = [@$_[1..$
sub tfactor {
my($tnum, $n) = @_;
push @results, shared_clone([$n, factor($n)]);
}
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Rewrite the snippet below in Go so it works the same as the original Perl code. | use ntheory qw/factor vecmax/;
use threads;
use threads::shared;
my @results :shared;
my $tnum = 0;
$_->join() for
map { threads->create('tfactor', $tnum++, $_) }
(qw/576460752303423487 576460752303423487 576460752303423487 112272537195293
115284584522153 115280098190773 115797840077099 112582718962171 299866111963290359/);
my $lmf = vecmax( map { $_->[1] } @results );
print "Largest minimal factor of $lmf found in:\n";
print " $_->[0] = [@$_[1..$
sub tfactor {
my($tnum, $n) = @_;
push @results, shared_clone([$n, factor($n)]);
}
| package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
Generate an equivalent C version of this Racket code. | #lang racket
(require math)
(provide main)
(define (smallest-factor n)
(list (first (first (factorize n))) n))
(define numbers
'(112272537195293 112582718962171 112272537095293
115280098190773 115797840077099 1099726829285419))
(define (main)
(define ps
(for/list ([_ numbers])
(place ch
(place-channel-put
ch
(smallest-factor
(place-channel-get ch))))))
(map place-channel-put ps numbers)
(argmax first (map place-channel-get ps)))
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Produce a functionally identical C# code for the snippet given in Racket. | #lang racket
(require math)
(provide main)
(define (smallest-factor n)
(list (first (first (factorize n))) n))
(define numbers
'(112272537195293 112582718962171 112272537095293
115280098190773 115797840077099 1099726829285419))
(define (main)
(define ps
(for/list ([_ numbers])
(place ch
(place-channel-put
ch
(smallest-factor
(place-channel-get ch))))))
(map place-channel-put ps numbers)
(argmax first (map place-channel-get ps)))
| using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
Generate a C++ translation of this Racket snippet without changing its computational steps. | #lang racket
(require math)
(provide main)
(define (smallest-factor n)
(list (first (first (factorize n))) n))
(define numbers
'(112272537195293 112582718962171 112272537095293
115280098190773 115797840077099 1099726829285419))
(define (main)
(define ps
(for/list ([_ numbers])
(place ch
(place-channel-put
ch
(smallest-factor
(place-channel-get ch))))))
(map place-channel-put ps numbers)
(argmax first (map place-channel-get ps)))
| #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
Rewrite the snippet below in Java so it works the same as the original Racket code. | #lang racket
(require math)
(provide main)
(define (smallest-factor n)
(list (first (first (factorize n))) n))
(define numbers
'(112272537195293 112582718962171 112272537095293
115280098190773 115797840077099 1099726829285419))
(define (main)
(define ps
(for/list ([_ numbers])
(place ch
(place-channel-put
ch
(smallest-factor
(place-channel-get ch))))))
(map place-channel-put ps numbers)
(argmax first (map place-channel-get ps)))
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Change the programming language of this snippet from Racket to Python without modifying what it does. | #lang racket
(require math)
(provide main)
(define (smallest-factor n)
(list (first (first (factorize n))) n))
(define numbers
'(112272537195293 112582718962171 112272537095293
115280098190773 115797840077099 1099726829285419))
(define (main)
(define ps
(for/list ([_ numbers])
(place ch
(place-channel-put
ch
(smallest-factor
(place-channel-get ch))))))
(map place-channel-put ps numbers)
(argmax first (map place-channel-get ps)))
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Translate the given Racket code snippet into Go without altering its behavior. | #lang racket
(require math)
(provide main)
(define (smallest-factor n)
(list (first (first (factorize n))) n))
(define numbers
'(112272537195293 112582718962171 112272537095293
115280098190773 115797840077099 1099726829285419))
(define (main)
(define ps
(for/list ([_ numbers])
(place ch
(place-channel-put
ch
(smallest-factor
(place-channel-get ch))))))
(map place-channel-put ps numbers)
(argmax first (map place-channel-get ps)))
| package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
Rewrite the snippet below in C so it works the same as the original REXX code. |
object1 = .example~new
object2 = .example~new
say object1~primes(1,11111111111,11111111114)
say object2~primes(2,11111111111,11111111114)
say "Main ended at" time()
exit
::class example
::method primes
use arg which,bot,top
reply "Start primes"which':' time()
Select
When which=1 Then Call pd1 bot top
When which=2 Then Call pd2 bot top
End
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Convert the following code from REXX to C#, ensuring the logic remains intact. |
object1 = .example~new
object2 = .example~new
say object1~primes(1,11111111111,11111111114)
say object2~primes(2,11111111111,11111111114)
say "Main ended at" time()
exit
::class example
::method primes
use arg which,bot,top
reply "Start primes"which':' time()
Select
When which=1 Then Call pd1 bot top
When which=2 Then Call pd2 bot top
End
| using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
Port the following code from REXX to C++ with equivalent syntax and logic. |
object1 = .example~new
object2 = .example~new
say object1~primes(1,11111111111,11111111114)
say object2~primes(2,11111111111,11111111114)
say "Main ended at" time()
exit
::class example
::method primes
use arg which,bot,top
reply "Start primes"which':' time()
Select
When which=1 Then Call pd1 bot top
When which=2 Then Call pd2 bot top
End
| #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
Translate this program into Java but keep the logic exactly as in REXX. |
object1 = .example~new
object2 = .example~new
say object1~primes(1,11111111111,11111111114)
say object2~primes(2,11111111111,11111111114)
say "Main ended at" time()
exit
::class example
::method primes
use arg which,bot,top
reply "Start primes"which':' time()
Select
When which=1 Then Call pd1 bot top
When which=2 Then Call pd2 bot top
End
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Keep all operations the same but rewrite the snippet in Python. |
object1 = .example~new
object2 = .example~new
say object1~primes(1,11111111111,11111111114)
say object2~primes(2,11111111111,11111111114)
say "Main ended at" time()
exit
::class example
::method primes
use arg which,bot,top
reply "Start primes"which':' time()
Select
When which=1 Then Call pd1 bot top
When which=2 Then Call pd2 bot top
End
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Change the following REXX code into Go without altering its purpose. |
object1 = .example~new
object2 = .example~new
say object1~primes(1,11111111111,11111111114)
say object2~primes(2,11111111111,11111111114)
say "Main ended at" time()
exit
::class example
::method primes
use arg which,bot,top
reply "Start primes"which':' time()
Select
When which=1 Then Call pd1 bot top
When which=2 Then Call pd2 bot top
End
| package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
Please provide an equivalent version of this Ruby code in C. | var nums = [1275792312878611, 12345678915808973,
1578070919762253, 14700694496703910,];
var factors = nums.map {|n| prime_factors.ffork(n) }.map { .wait }
say ((nums ~Z factors)->max_by {|m| m[1][0] })
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Convert this Ruby snippet to C# and keep its semantics consistent. | var nums = [1275792312878611, 12345678915808973,
1578070919762253, 14700694496703910,];
var factors = nums.map {|n| prime_factors.ffork(n) }.map { .wait }
say ((nums ~Z factors)->max_by {|m| m[1][0] })
| using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
Convert this Ruby block to C++, preserving its control flow and logic. | var nums = [1275792312878611, 12345678915808973,
1578070919762253, 14700694496703910,];
var factors = nums.map {|n| prime_factors.ffork(n) }.map { .wait }
say ((nums ~Z factors)->max_by {|m| m[1][0] })
| #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
Port the following code from Ruby to Java with equivalent syntax and logic. | var nums = [1275792312878611, 12345678915808973,
1578070919762253, 14700694496703910,];
var factors = nums.map {|n| prime_factors.ffork(n) }.map { .wait }
say ((nums ~Z factors)->max_by {|m| m[1][0] })
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Please provide an equivalent version of this Ruby code in Python. | var nums = [1275792312878611, 12345678915808973,
1578070919762253, 14700694496703910,];
var factors = nums.map {|n| prime_factors.ffork(n) }.map { .wait }
say ((nums ~Z factors)->max_by {|m| m[1][0] })
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Change the programming language of this snippet from Ruby to Go without modifying what it does. | var nums = [1275792312878611, 12345678915808973,
1578070919762253, 14700694496703910,];
var factors = nums.map {|n| prime_factors.ffork(n) }.map { .wait }
say ((nums ~Z factors)->max_by {|m| m[1][0] })
| package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
Generate an equivalent C version of this Scala code. |
import java.util.stream.Collectors
fun primeFactorInfo(n: Int): Triple<Int, Int, List<Int>> {
if (n <= 1) throw IllegalArgumentException("Number must be more than one")
if (isPrime(n)) return Triple(n, n, listOf(n))
val factors = mutableListOf<Int>()
var factor = 2
var nn = n
while (true) {
if (nn % factor == 0) {
factors.add(factor)
nn /= factor
if (nn == 1) return Triple(n, factors.min()!!, factors)
if (isPrime(nn)) factor = nn
}
else if (factor >= 3) factor += 2
else factor = 3
}
}
fun isPrime(n: Int) : Boolean {
if (n < 2) return false
if (n % 2 == 0) return n == 2
if (n % 3 == 0) return n == 3
var d = 5
while (d * d <= n) {
if (n % d == 0) return false
d += 2
if (n % d == 0) return false
d += 4
}
return true
}
fun main(args: Array<String>) {
val numbers = listOf(
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
)
val info = numbers.stream()
.parallel()
.map { primeFactorInfo(it) }
.collect(Collectors.toList())
val maxFactor = info.maxBy { it.second }!!.second
val results = info.filter { it.second == maxFactor }
println("The following number(s) have the largest minimal prime factor of $maxFactor:")
for (result in results) {
println(" ${result.first} whose prime factors are ${result.third}")
}
}
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Translate this program into C# but keep the logic exactly as in Scala. |
import java.util.stream.Collectors
fun primeFactorInfo(n: Int): Triple<Int, Int, List<Int>> {
if (n <= 1) throw IllegalArgumentException("Number must be more than one")
if (isPrime(n)) return Triple(n, n, listOf(n))
val factors = mutableListOf<Int>()
var factor = 2
var nn = n
while (true) {
if (nn % factor == 0) {
factors.add(factor)
nn /= factor
if (nn == 1) return Triple(n, factors.min()!!, factors)
if (isPrime(nn)) factor = nn
}
else if (factor >= 3) factor += 2
else factor = 3
}
}
fun isPrime(n: Int) : Boolean {
if (n < 2) return false
if (n % 2 == 0) return n == 2
if (n % 3 == 0) return n == 3
var d = 5
while (d * d <= n) {
if (n % d == 0) return false
d += 2
if (n % d == 0) return false
d += 4
}
return true
}
fun main(args: Array<String>) {
val numbers = listOf(
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
)
val info = numbers.stream()
.parallel()
.map { primeFactorInfo(it) }
.collect(Collectors.toList())
val maxFactor = info.maxBy { it.second }!!.second
val results = info.filter { it.second == maxFactor }
println("The following number(s) have the largest minimal prime factor of $maxFactor:")
for (result in results) {
println(" ${result.first} whose prime factors are ${result.third}")
}
}
| using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
Translate this program into C++ but keep the logic exactly as in Scala. |
import java.util.stream.Collectors
fun primeFactorInfo(n: Int): Triple<Int, Int, List<Int>> {
if (n <= 1) throw IllegalArgumentException("Number must be more than one")
if (isPrime(n)) return Triple(n, n, listOf(n))
val factors = mutableListOf<Int>()
var factor = 2
var nn = n
while (true) {
if (nn % factor == 0) {
factors.add(factor)
nn /= factor
if (nn == 1) return Triple(n, factors.min()!!, factors)
if (isPrime(nn)) factor = nn
}
else if (factor >= 3) factor += 2
else factor = 3
}
}
fun isPrime(n: Int) : Boolean {
if (n < 2) return false
if (n % 2 == 0) return n == 2
if (n % 3 == 0) return n == 3
var d = 5
while (d * d <= n) {
if (n % d == 0) return false
d += 2
if (n % d == 0) return false
d += 4
}
return true
}
fun main(args: Array<String>) {
val numbers = listOf(
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
)
val info = numbers.stream()
.parallel()
.map { primeFactorInfo(it) }
.collect(Collectors.toList())
val maxFactor = info.maxBy { it.second }!!.second
val results = info.filter { it.second == maxFactor }
println("The following number(s) have the largest minimal prime factor of $maxFactor:")
for (result in results) {
println(" ${result.first} whose prime factors are ${result.third}")
}
}
| #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
Translate the given Scala code snippet into Java without altering its behavior. |
import java.util.stream.Collectors
fun primeFactorInfo(n: Int): Triple<Int, Int, List<Int>> {
if (n <= 1) throw IllegalArgumentException("Number must be more than one")
if (isPrime(n)) return Triple(n, n, listOf(n))
val factors = mutableListOf<Int>()
var factor = 2
var nn = n
while (true) {
if (nn % factor == 0) {
factors.add(factor)
nn /= factor
if (nn == 1) return Triple(n, factors.min()!!, factors)
if (isPrime(nn)) factor = nn
}
else if (factor >= 3) factor += 2
else factor = 3
}
}
fun isPrime(n: Int) : Boolean {
if (n < 2) return false
if (n % 2 == 0) return n == 2
if (n % 3 == 0) return n == 3
var d = 5
while (d * d <= n) {
if (n % d == 0) return false
d += 2
if (n % d == 0) return false
d += 4
}
return true
}
fun main(args: Array<String>) {
val numbers = listOf(
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
)
val info = numbers.stream()
.parallel()
.map { primeFactorInfo(it) }
.collect(Collectors.toList())
val maxFactor = info.maxBy { it.second }!!.second
val results = info.filter { it.second == maxFactor }
println("The following number(s) have the largest minimal prime factor of $maxFactor:")
for (result in results) {
println(" ${result.first} whose prime factors are ${result.third}")
}
}
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Keep all operations the same but rewrite the snippet in Python. |
import java.util.stream.Collectors
fun primeFactorInfo(n: Int): Triple<Int, Int, List<Int>> {
if (n <= 1) throw IllegalArgumentException("Number must be more than one")
if (isPrime(n)) return Triple(n, n, listOf(n))
val factors = mutableListOf<Int>()
var factor = 2
var nn = n
while (true) {
if (nn % factor == 0) {
factors.add(factor)
nn /= factor
if (nn == 1) return Triple(n, factors.min()!!, factors)
if (isPrime(nn)) factor = nn
}
else if (factor >= 3) factor += 2
else factor = 3
}
}
fun isPrime(n: Int) : Boolean {
if (n < 2) return false
if (n % 2 == 0) return n == 2
if (n % 3 == 0) return n == 3
var d = 5
while (d * d <= n) {
if (n % d == 0) return false
d += 2
if (n % d == 0) return false
d += 4
}
return true
}
fun main(args: Array<String>) {
val numbers = listOf(
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
)
val info = numbers.stream()
.parallel()
.map { primeFactorInfo(it) }
.collect(Collectors.toList())
val maxFactor = info.maxBy { it.second }!!.second
val results = info.filter { it.second == maxFactor }
println("The following number(s) have the largest minimal prime factor of $maxFactor:")
for (result in results) {
println(" ${result.first} whose prime factors are ${result.third}")
}
}
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Produce a functionally identical Go code for the snippet given in Scala. |
import java.util.stream.Collectors
fun primeFactorInfo(n: Int): Triple<Int, Int, List<Int>> {
if (n <= 1) throw IllegalArgumentException("Number must be more than one")
if (isPrime(n)) return Triple(n, n, listOf(n))
val factors = mutableListOf<Int>()
var factor = 2
var nn = n
while (true) {
if (nn % factor == 0) {
factors.add(factor)
nn /= factor
if (nn == 1) return Triple(n, factors.min()!!, factors)
if (isPrime(nn)) factor = nn
}
else if (factor >= 3) factor += 2
else factor = 3
}
}
fun isPrime(n: Int) : Boolean {
if (n < 2) return false
if (n % 2 == 0) return n == 2
if (n % 3 == 0) return n == 3
var d = 5
while (d * d <= n) {
if (n % d == 0) return false
d += 2
if (n % d == 0) return false
d += 4
}
return true
}
fun main(args: Array<String>) {
val numbers = listOf(
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
)
val info = numbers.stream()
.parallel()
.map { primeFactorInfo(it) }
.collect(Collectors.toList())
val maxFactor = info.maxBy { it.second }!!.second
val results = info.filter { it.second == maxFactor }
println("The following number(s) have the largest minimal prime factor of $maxFactor:")
for (result in results) {
println(" ${result.first} whose prime factors are ${result.third}")
}
}
| package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
Maintain the same structure and functionality when rewriting this code in C. | import BigInt
import Foundation
extension BinaryInteger {
@inlinable
public func primeDecomposition() -> [Self] {
guard self > 1 else { return [] }
func step(_ x: Self) -> Self {
return 1 + (x << 2) - ((x >> 1) << 1)
}
let maxQ = Self(Double(self).squareRoot())
var d: Self = 1
var q: Self = self & 1 == 0 ? 2 : 3
while q <= maxQ && self % q != 0 {
q = step(d)
d += 1
}
return q <= maxQ ? [q] + (self / q).primeDecomposition() : [self]
}
}
let numbers = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419,
1275792312878611,
BigInt("64921987050997300559")
]
func findLargestMinFactor<T: BinaryInteger>(for nums: [T], then: @escaping ((n: T, factors: [T])) -> ()) {
let waiter = DispatchSemaphore(value: 0)
let lock = DispatchSemaphore(value: 1)
var factors = [(n: T, factors: [T])]()
DispatchQueue.concurrentPerform(iterations: nums.count) {i in
let n = nums[i]
print("Factoring \(n)")
let nFacs = n.primeDecomposition().sorted()
print("Factored \(n)")
lock.wait()
factors.append((n, nFacs))
if factors.count == nums.count {
waiter.signal()
}
lock.signal()
}
waiter.wait()
then(factors.sorted(by: { $0.factors.first! > $1.factors.first! }).first!)
}
findLargestMinFactor(for: numbers) {res in
let (n, factors) = res
print("Number with largest min prime factor: \(n); factors: \(factors)")
exit(0)
}
dispatchMain()
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Port the provided Swift code into C# while preserving the original functionality. | import BigInt
import Foundation
extension BinaryInteger {
@inlinable
public func primeDecomposition() -> [Self] {
guard self > 1 else { return [] }
func step(_ x: Self) -> Self {
return 1 + (x << 2) - ((x >> 1) << 1)
}
let maxQ = Self(Double(self).squareRoot())
var d: Self = 1
var q: Self = self & 1 == 0 ? 2 : 3
while q <= maxQ && self % q != 0 {
q = step(d)
d += 1
}
return q <= maxQ ? [q] + (self / q).primeDecomposition() : [self]
}
}
let numbers = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419,
1275792312878611,
BigInt("64921987050997300559")
]
func findLargestMinFactor<T: BinaryInteger>(for nums: [T], then: @escaping ((n: T, factors: [T])) -> ()) {
let waiter = DispatchSemaphore(value: 0)
let lock = DispatchSemaphore(value: 1)
var factors = [(n: T, factors: [T])]()
DispatchQueue.concurrentPerform(iterations: nums.count) {i in
let n = nums[i]
print("Factoring \(n)")
let nFacs = n.primeDecomposition().sorted()
print("Factored \(n)")
lock.wait()
factors.append((n, nFacs))
if factors.count == nums.count {
waiter.signal()
}
lock.signal()
}
waiter.wait()
then(factors.sorted(by: { $0.factors.first! > $1.factors.first! }).first!)
}
findLargestMinFactor(for: numbers) {res in
let (n, factors) = res
print("Number with largest min prime factor: \(n); factors: \(factors)")
exit(0)
}
dispatchMain()
| using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
Maintain the same structure and functionality when rewriting this code in C++. | import BigInt
import Foundation
extension BinaryInteger {
@inlinable
public func primeDecomposition() -> [Self] {
guard self > 1 else { return [] }
func step(_ x: Self) -> Self {
return 1 + (x << 2) - ((x >> 1) << 1)
}
let maxQ = Self(Double(self).squareRoot())
var d: Self = 1
var q: Self = self & 1 == 0 ? 2 : 3
while q <= maxQ && self % q != 0 {
q = step(d)
d += 1
}
return q <= maxQ ? [q] + (self / q).primeDecomposition() : [self]
}
}
let numbers = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419,
1275792312878611,
BigInt("64921987050997300559")
]
func findLargestMinFactor<T: BinaryInteger>(for nums: [T], then: @escaping ((n: T, factors: [T])) -> ()) {
let waiter = DispatchSemaphore(value: 0)
let lock = DispatchSemaphore(value: 1)
var factors = [(n: T, factors: [T])]()
DispatchQueue.concurrentPerform(iterations: nums.count) {i in
let n = nums[i]
print("Factoring \(n)")
let nFacs = n.primeDecomposition().sorted()
print("Factored \(n)")
lock.wait()
factors.append((n, nFacs))
if factors.count == nums.count {
waiter.signal()
}
lock.signal()
}
waiter.wait()
then(factors.sorted(by: { $0.factors.first! > $1.factors.first! }).first!)
}
findLargestMinFactor(for: numbers) {res in
let (n, factors) = res
print("Number with largest min prime factor: \(n); factors: \(factors)")
exit(0)
}
dispatchMain()
| #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
Port the provided Swift code into Java while preserving the original functionality. | import BigInt
import Foundation
extension BinaryInteger {
@inlinable
public func primeDecomposition() -> [Self] {
guard self > 1 else { return [] }
func step(_ x: Self) -> Self {
return 1 + (x << 2) - ((x >> 1) << 1)
}
let maxQ = Self(Double(self).squareRoot())
var d: Self = 1
var q: Self = self & 1 == 0 ? 2 : 3
while q <= maxQ && self % q != 0 {
q = step(d)
d += 1
}
return q <= maxQ ? [q] + (self / q).primeDecomposition() : [self]
}
}
let numbers = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419,
1275792312878611,
BigInt("64921987050997300559")
]
func findLargestMinFactor<T: BinaryInteger>(for nums: [T], then: @escaping ((n: T, factors: [T])) -> ()) {
let waiter = DispatchSemaphore(value: 0)
let lock = DispatchSemaphore(value: 1)
var factors = [(n: T, factors: [T])]()
DispatchQueue.concurrentPerform(iterations: nums.count) {i in
let n = nums[i]
print("Factoring \(n)")
let nFacs = n.primeDecomposition().sorted()
print("Factored \(n)")
lock.wait()
factors.append((n, nFacs))
if factors.count == nums.count {
waiter.signal()
}
lock.signal()
}
waiter.wait()
then(factors.sorted(by: { $0.factors.first! > $1.factors.first! }).first!)
}
findLargestMinFactor(for: numbers) {res in
let (n, factors) = res
print("Number with largest min prime factor: \(n); factors: \(factors)")
exit(0)
}
dispatchMain()
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Keep all operations the same but rewrite the snippet in Python. | import BigInt
import Foundation
extension BinaryInteger {
@inlinable
public func primeDecomposition() -> [Self] {
guard self > 1 else { return [] }
func step(_ x: Self) -> Self {
return 1 + (x << 2) - ((x >> 1) << 1)
}
let maxQ = Self(Double(self).squareRoot())
var d: Self = 1
var q: Self = self & 1 == 0 ? 2 : 3
while q <= maxQ && self % q != 0 {
q = step(d)
d += 1
}
return q <= maxQ ? [q] + (self / q).primeDecomposition() : [self]
}
}
let numbers = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419,
1275792312878611,
BigInt("64921987050997300559")
]
func findLargestMinFactor<T: BinaryInteger>(for nums: [T], then: @escaping ((n: T, factors: [T])) -> ()) {
let waiter = DispatchSemaphore(value: 0)
let lock = DispatchSemaphore(value: 1)
var factors = [(n: T, factors: [T])]()
DispatchQueue.concurrentPerform(iterations: nums.count) {i in
let n = nums[i]
print("Factoring \(n)")
let nFacs = n.primeDecomposition().sorted()
print("Factored \(n)")
lock.wait()
factors.append((n, nFacs))
if factors.count == nums.count {
waiter.signal()
}
lock.signal()
}
waiter.wait()
then(factors.sorted(by: { $0.factors.first! > $1.factors.first! }).first!)
}
findLargestMinFactor(for: numbers) {res in
let (n, factors) = res
print("Number with largest min prime factor: \(n); factors: \(factors)")
exit(0)
}
dispatchMain()
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Transform the following Swift implementation into Go, maintaining the same output and logic. | import BigInt
import Foundation
extension BinaryInteger {
@inlinable
public func primeDecomposition() -> [Self] {
guard self > 1 else { return [] }
func step(_ x: Self) -> Self {
return 1 + (x << 2) - ((x >> 1) << 1)
}
let maxQ = Self(Double(self).squareRoot())
var d: Self = 1
var q: Self = self & 1 == 0 ? 2 : 3
while q <= maxQ && self % q != 0 {
q = step(d)
d += 1
}
return q <= maxQ ? [q] + (self / q).primeDecomposition() : [self]
}
}
let numbers = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419,
1275792312878611,
BigInt("64921987050997300559")
]
func findLargestMinFactor<T: BinaryInteger>(for nums: [T], then: @escaping ((n: T, factors: [T])) -> ()) {
let waiter = DispatchSemaphore(value: 0)
let lock = DispatchSemaphore(value: 1)
var factors = [(n: T, factors: [T])]()
DispatchQueue.concurrentPerform(iterations: nums.count) {i in
let n = nums[i]
print("Factoring \(n)")
let nFacs = n.primeDecomposition().sorted()
print("Factored \(n)")
lock.wait()
factors.append((n, nFacs))
if factors.count == nums.count {
waiter.signal()
}
lock.signal()
}
waiter.wait()
then(factors.sorted(by: { $0.factors.first! > $1.factors.first! }).first!)
}
findLargestMinFactor(for: numbers) {res in
let (n, factors) = res
print("Number with largest min prime factor: \(n); factors: \(factors)")
exit(0)
}
dispatchMain()
| package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
Can you help me rewrite this code in C instead of Tcl, keeping it the same logically? | package require Tcl 8.6
package require Thread
namespace eval pooled {
variable poolSize 3;
proc computation {computationDefinition entryPoint values} {
variable result
variable poolSize
append computationDefinition [subst -nocommands {
proc poolcompute {value target} {
set outcome [$entryPoint \$value]
set msg [list set ::pooled::result(\$value) \$outcome]
thread::send -async \$target \$msg
}
}]
set pool [tpool::create -initcmd $computationDefinition \
-maxworkers $poolSize]
unset -nocomplain result
array set result {}
foreach value $values {
tpool::post $pool [list poolcompute $value [thread::id]]
}
while {[array size result] < [llength $values]} {vwait pooled::result}
tpool::release $pool
return [array get result]
}
}
| #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
Generate an equivalent C# version of this Tcl code. | package require Tcl 8.6
package require Thread
namespace eval pooled {
variable poolSize 3;
proc computation {computationDefinition entryPoint values} {
variable result
variable poolSize
append computationDefinition [subst -nocommands {
proc poolcompute {value target} {
set outcome [$entryPoint \$value]
set msg [list set ::pooled::result(\$value) \$outcome]
thread::send -async \$target \$msg
}
}]
set pool [tpool::create -initcmd $computationDefinition \
-maxworkers $poolSize]
unset -nocomplain result
array set result {}
foreach value $values {
tpool::post $pool [list poolcompute $value [thread::id]]
}
while {[array size result] < [llength $values]} {vwait pooled::result}
tpool::release $pool
return [array get result]
}
}
| using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
Generate a C++ translation of this Tcl snippet without changing its computational steps. | package require Tcl 8.6
package require Thread
namespace eval pooled {
variable poolSize 3;
proc computation {computationDefinition entryPoint values} {
variable result
variable poolSize
append computationDefinition [subst -nocommands {
proc poolcompute {value target} {
set outcome [$entryPoint \$value]
set msg [list set ::pooled::result(\$value) \$outcome]
thread::send -async \$target \$msg
}
}]
set pool [tpool::create -initcmd $computationDefinition \
-maxworkers $poolSize]
unset -nocomplain result
array set result {}
foreach value $values {
tpool::post $pool [list poolcompute $value [thread::id]]
}
while {[array size result] < [llength $values]} {vwait pooled::result}
tpool::release $pool
return [array get result]
}
}
| #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
Ensure the translated Java code behaves exactly like the original Tcl snippet. | package require Tcl 8.6
package require Thread
namespace eval pooled {
variable poolSize 3;
proc computation {computationDefinition entryPoint values} {
variable result
variable poolSize
append computationDefinition [subst -nocommands {
proc poolcompute {value target} {
set outcome [$entryPoint \$value]
set msg [list set ::pooled::result(\$value) \$outcome]
thread::send -async \$target \$msg
}
}]
set pool [tpool::create -initcmd $computationDefinition \
-maxworkers $poolSize]
unset -nocomplain result
array set result {}
foreach value $values {
tpool::post $pool [list poolcompute $value [thread::id]]
}
while {[array size result] < [llength $values]} {vwait pooled::result}
tpool::release $pool
return [array get result]
}
}
| import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
Produce a language-to-language conversion: from Tcl to Python, same semantics. | package require Tcl 8.6
package require Thread
namespace eval pooled {
variable poolSize 3;
proc computation {computationDefinition entryPoint values} {
variable result
variable poolSize
append computationDefinition [subst -nocommands {
proc poolcompute {value target} {
set outcome [$entryPoint \$value]
set msg [list set ::pooled::result(\$value) \$outcome]
thread::send -async \$target \$msg
}
}]
set pool [tpool::create -initcmd $computationDefinition \
-maxworkers $poolSize]
unset -nocomplain result
array set result {}
foreach value $values {
tpool::post $pool [list poolcompute $value [thread::id]]
}
while {[array size result] < [llength $values]} {vwait pooled::result}
tpool::release $pool
return [array get result]
}
}
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Port the following code from Tcl to Go with equivalent syntax and logic. | package require Tcl 8.6
package require Thread
namespace eval pooled {
variable poolSize 3;
proc computation {computationDefinition entryPoint values} {
variable result
variable poolSize
append computationDefinition [subst -nocommands {
proc poolcompute {value target} {
set outcome [$entryPoint \$value]
set msg [list set ::pooled::result(\$value) \$outcome]
thread::send -async \$target \$msg
}
}]
set pool [tpool::create -initcmd $computationDefinition \
-maxworkers $poolSize]
unset -nocomplain result
array set result {}
foreach value $values {
tpool::post $pool [list poolcompute $value [thread::id]]
}
while {[array size result] < [llength $values]} {vwait pooled::result}
tpool::release $pool
return [array get result]
}
}
| package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
Rewrite the snippet below in Rust so it works the same as the original C code. | #include <stdio.h>
#include <omp.h>
int main()
{
int data[] = {12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519};
int largest, largest_factor = 0;
omp_set_num_threads(4);
#pragma omp parallel for shared(largest_factor, largest)
for (int i = 0; i < 7; i++) {
int p, n = data[i];
for (p = 3; p * p <= n && n % p; p += 2);
if (p * p > n) p = n;
if (p > largest_factor) {
largest_factor = p;
largest = n;
printf("thread %d: found larger: %d of %d\n",
omp_get_thread_num(), p, n);
} else {
printf("thread %d: not larger: %d of %d\n",
omp_get_thread_num(), p, n);
}
}
printf("Largest factor: %d of %d\n", largest_factor, largest);
return 0;
}
|
extern crate rayon;
extern crate prime_decomposition;
use rayon::prelude::*;
pub fn largest_min_factor(numbers: &[usize]) -> usize {
numbers
.par_iter()
.map(|n| {
prime_decomposition::factor(*n)[0]
})
.max()
.unwrap()
}
fn main() {
let numbers = &[
1_122_725, 1_125_827, 1_122_725, 1_152_800, 1_157_978, 1_099_726,
];
let max = largest_min_factor(numbers);
println!("The largest minimal factor is {}", max);
}
|
Port the provided C++ code into Rust while preserving the original functionality. | #include <iostream>
#include <iterator>
#include <vector>
#include <ppl.h>
#include <concurrent_vector.h>
struct Factors
{
int number;
std::vector<int> primes;
};
const int data[] =
{
12757923, 12878611, 12878893, 12757923, 15808973, 15780709, 197622519
};
int main()
{
Concurrency::concurrent_vector<Factors> results;
Concurrency::parallel_for_each(std::begin(data), std::end(data), [&](int n)
{
Factors factors;
factors.number = n;
for (int f = 2; n > 1; ++f)
{
while (n % f == 0)
{
factors.primes.push_back(f);
n /= f;
}
}
results.push_back(factors);
});
auto max = std::max_element(results.begin(), results.end(), [](const Factors &a, const Factors &b)
{
return a.primes.front() < b.primes.front();
});
std::for_each(results.begin(), results.end(), [&](const Factors &f)
{
if (f.primes.front() == max->primes.front())
{
std::cout << f.number << " = [ ";
std::copy(f.primes.begin(), f.primes.end(), std::ostream_iterator<int>(std::cout, " "));
std::cout << "]\n";
}
});
return 0;
}
|
extern crate rayon;
extern crate prime_decomposition;
use rayon::prelude::*;
pub fn largest_min_factor(numbers: &[usize]) -> usize {
numbers
.par_iter()
.map(|n| {
prime_decomposition::factor(*n)[0]
})
.max()
.unwrap()
}
fn main() {
let numbers = &[
1_122_725, 1_125_827, 1_122_725, 1_152_800, 1_157_978, 1_099_726,
];
let max = largest_min_factor(numbers);
println!("The largest minimal factor is {}", max);
}
|
Convert this Java block to Rust, preserving its control flow and logic. | import static java.lang.System.out;
import static java.util.Arrays.stream;
import static java.util.Comparator.comparing;
public interface ParallelCalculations {
public static final long[] NUMBERS = {
12757923,
12878611,
12878893,
12757923,
15808973,
15780709,
197622519
};
public static void main(String... arguments) {
stream(NUMBERS)
.unordered()
.parallel()
.mapToObj(ParallelCalculations::minimalPrimeFactor)
.max(comparing(a -> a[0]))
.ifPresent(res -> out.printf(
"%d has the largest minimum prime factor: %d%n",
res[1],
res[0]
));
}
public static long[] minimalPrimeFactor(long n) {
for (long i = 2; n >= i * i; i++) {
if (n % i == 0) {
return new long[]{i, n};
}
}
return new long[]{n, n};
}
}
|
extern crate rayon;
extern crate prime_decomposition;
use rayon::prelude::*;
pub fn largest_min_factor(numbers: &[usize]) -> usize {
numbers
.par_iter()
.map(|n| {
prime_decomposition::factor(*n)[0]
})
.max()
.unwrap()
}
fn main() {
let numbers = &[
1_122_725, 1_125_827, 1_122_725, 1_152_800, 1_157_978, 1_099_726,
];
let max = largest_min_factor(numbers);
println!("The largest minimal factor is {}", max);
}
|
Port the following code from Go to Rust with equivalent syntax and logic. | package main
import (
"fmt"
"math/big"
)
var numbers = []*big.Int{
big.NewInt(12757923),
big.NewInt(12878611),
big.NewInt(12878893),
big.NewInt(12757923),
big.NewInt(15808973),
big.NewInt(15780709),
}
func main() {
rs := lmf(numbers)
fmt.Println("largest minimal factor:", rs[0].decomp[0])
for _, r := range rs {
fmt.Println(r.number, "->", r.decomp)
}
}
type result struct {
number *big.Int
decomp []*big.Int
}
func lmf([]*big.Int) []result {
rCh := make(chan result)
for _, n := range numbers {
go decomp(n, rCh)
}
rs := []result{<-rCh}
for i := 1; i < len(numbers); i++ {
switch r := <-rCh; r.decomp[0].Cmp(rs[0].decomp[0]) {
case 1:
rs = rs[:1]
rs[0] = r
case 0:
rs = append(rs, r)
}
}
return rs
}
func decomp(n *big.Int, rCh chan result) {
rCh <- result{n, Primes(new(big.Int).Set(n))}
}
var (
ZERO = big.NewInt(0)
ONE = big.NewInt(1)
)
func Primes(n *big.Int) []*big.Int {
res := []*big.Int{}
mod, div := new(big.Int), new(big.Int)
for i := big.NewInt(2); i.Cmp(n) != 1; {
div.DivMod(n, i, mod)
for mod.Cmp(ZERO) == 0 {
res = append(res, new(big.Int).Set(i))
n.Set(div)
div.DivMod(n, i, mod)
}
i.Add(i, ONE)
}
return res
}
|
extern crate rayon;
extern crate prime_decomposition;
use rayon::prelude::*;
pub fn largest_min_factor(numbers: &[usize]) -> usize {
numbers
.par_iter()
.map(|n| {
prime_decomposition::factor(*n)[0]
})
.max()
.unwrap()
}
fn main() {
let numbers = &[
1_122_725, 1_125_827, 1_122_725, 1_152_800, 1_157_978, 1_099_726,
];
let max = largest_min_factor(numbers);
println!("The largest minimal factor is {}", max);
}
|
Rewrite the snippet below in Rust so it works the same as the original C# code. | using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
public static List<int> PrimeFactors(int number)
{
var primes = new List<int>();
for (int div = 2; div <= number; div++)
{
while (number % div == 0)
{
primes.Add(div);
number = number / div;
}
}
return primes;
}
static void Main(string[] args)
{
int[] n = { 12757923, 12878611, 12757923, 15808973, 15780709, 197622519 };
var factors = n.AsParallel().Select(PrimeFactors).ToList();
var smallestFactors = factors.Select(thisNumbersFactors => thisNumbersFactors.Min()).ToList();
int biggestFactor = smallestFactors.Max();
int whatIndexIsThat = smallestFactors.IndexOf(biggestFactor);
Console.WriteLine("{0} has the largest minimum prime factor: {1}", n[whatIndexIsThat], biggestFactor);
Console.WriteLine(string.Join(" ", factors[whatIndexIsThat]));
}
}
|
extern crate rayon;
extern crate prime_decomposition;
use rayon::prelude::*;
pub fn largest_min_factor(numbers: &[usize]) -> usize {
numbers
.par_iter()
.map(|n| {
prime_decomposition::factor(*n)[0]
})
.max()
.unwrap()
}
fn main() {
let numbers = &[
1_122_725, 1_125_827, 1_122_725, 1_152_800, 1_157_978, 1_099_726,
];
let max = largest_min_factor(numbers);
println!("The largest minimal factor is {}", max);
}
|
Transform the following Rust implementation into Python, maintaining the same output and logic. |
extern crate rayon;
extern crate prime_decomposition;
use rayon::prelude::*;
pub fn largest_min_factor(numbers: &[usize]) -> usize {
numbers
.par_iter()
.map(|n| {
prime_decomposition::factor(*n)[0]
})
.max()
.unwrap()
}
fn main() {
let numbers = &[
1_122_725, 1_125_827, 1_122_725, 1_152_800, 1_157_978, 1_099_726,
];
let max = largest_min_factor(numbers);
println!("The largest minimal factor is {}", max);
}
| from concurrent import futures
from math import floor, sqrt
NUMBERS = [
112272537195293,
112582718962171,
112272537095293,
115280098190773,
115797840077099,
1099726829285419]
def lowest_factor(n, _start=3):
if n % 2 == 0:
return 2
search_max = int(floor(sqrt(n))) + 1
for i in range(_start, search_max, 2):
if n % i == 0:
return i
return n
def prime_factors(n, lowest):
pf = []
while n > 1:
pf.append(lowest)
n //= lowest
lowest = lowest_factor(n, max(lowest, 3))
return pf
def prime_factors_of_number_with_lowest_prime_factor(NUMBERS):
with futures.ProcessPoolExecutor() as executor:
low_factor, number = max( (l, f) for l, f in zip(executor.map(lowest_factor, NUMBERS), NUMBERS) )
all_factors = prime_factors(number, low_factor)
return number, all_factors
def main():
print('For these numbers:')
print('\n '.join(str(p) for p in NUMBERS))
number, all_factors = prime_factors_of_number_with_lowest_prime_factor(NUMBERS)
print(' The one with the largest minimum prime factor is {}:'.format(number))
print(' All its prime factors in order are: {}'.format(all_factors))
if __name__ == '__main__':
main()
|
Convert this Ada block to C#, preserving its control flow and logic. | with Ada.Text_IO; use Ada.Text_IO;
with Interfaces; use Interfaces;
with Interfaces.C; use Interfaces.C;
with System; use System;
with Ada.Unchecked_Conversion;
procedure Shared_Library_Call is
type HANDLE is new Unsigned_32;
function LoadLibrary (lpFileName : char_array) return HANDLE;
pragma Import (stdcall, LoadLibrary, "LoadLibrary", "_LoadLibraryA");
function GetProcAddress (hModule : HANDLE; lpProcName : char_array)
return Address;
pragma Import (stdcall, GetProcAddress, "GetProcAddress", "_GetProcAddress");
type MessageBox is access function
( hWnd : Address := Null_Address;
lpText : char_array;
lpCaption : char_array := To_C ("Greeting");
uType : Unsigned_16 := 0
) return Integer_16;
pragma Convention (Stdcall, MessageBox);
function To_MessageBox is new Ada.Unchecked_Conversion (Address, MessageBox);
Library : HANDLE := LoadLibrary (To_C ("user32.dll"));
Pointer : Address := GetProcAddress (Library, To_C ("MessageBoxA"));
begin
if Pointer /= Null_Address then
declare
Result : Integer_16;
begin
Result := To_MessageBox (Pointer) (lpText => To_C ("Hello!"));
end;
else
Put_Line ("Unable to load the library " & HANDLE'Image (Library));
end if;
end Shared_Library_Call;
| using System.Runtime.InteropServices;
class Program {
[DllImport("fakelib.dll")]
public static extern int fakefunction(int args);
static void Main(string[] args) {
int r = fakefunction(10);
}
}
|
Port the provided Ada code into C while preserving the original functionality. | with Ada.Text_IO; use Ada.Text_IO;
with Interfaces; use Interfaces;
with Interfaces.C; use Interfaces.C;
with System; use System;
with Ada.Unchecked_Conversion;
procedure Shared_Library_Call is
type HANDLE is new Unsigned_32;
function LoadLibrary (lpFileName : char_array) return HANDLE;
pragma Import (stdcall, LoadLibrary, "LoadLibrary", "_LoadLibraryA");
function GetProcAddress (hModule : HANDLE; lpProcName : char_array)
return Address;
pragma Import (stdcall, GetProcAddress, "GetProcAddress", "_GetProcAddress");
type MessageBox is access function
( hWnd : Address := Null_Address;
lpText : char_array;
lpCaption : char_array := To_C ("Greeting");
uType : Unsigned_16 := 0
) return Integer_16;
pragma Convention (Stdcall, MessageBox);
function To_MessageBox is new Ada.Unchecked_Conversion (Address, MessageBox);
Library : HANDLE := LoadLibrary (To_C ("user32.dll"));
Pointer : Address := GetProcAddress (Library, To_C ("MessageBoxA"));
begin
if Pointer /= Null_Address then
declare
Result : Integer_16;
begin
Result := To_MessageBox (Pointer) (lpText => To_C ("Hello!"));
end;
else
Put_Line ("Unable to load the library " & HANDLE'Image (Library));
end if;
end Shared_Library_Call;
| #include <stdio.h>
#include <stdlib.h>
#include <dlfcn.h>
int myopenimage(const char *in)
{
static int handle=0;
fprintf(stderr, "internal openimage opens %s...\n", in);
return handle++;
}
int main()
{
void *imglib;
int (*extopenimage)(const char *);
int imghandle;
imglib = dlopen("./fakeimglib.so", RTLD_LAZY);
if ( imglib != NULL ) {
*(void **)(&extopenimage) = dlsym(imglib, "openimage");
imghandle = extopenimage("fake.img");
} else {
imghandle = myopenimage("fake.img");
}
printf("opened with handle %d\n", imghandle);
if (imglib != NULL ) dlclose(imglib);
return EXIT_SUCCESS;
}
|
Please provide an equivalent version of this Ada code in Go. | with Ada.Text_IO; use Ada.Text_IO;
with Interfaces; use Interfaces;
with Interfaces.C; use Interfaces.C;
with System; use System;
with Ada.Unchecked_Conversion;
procedure Shared_Library_Call is
type HANDLE is new Unsigned_32;
function LoadLibrary (lpFileName : char_array) return HANDLE;
pragma Import (stdcall, LoadLibrary, "LoadLibrary", "_LoadLibraryA");
function GetProcAddress (hModule : HANDLE; lpProcName : char_array)
return Address;
pragma Import (stdcall, GetProcAddress, "GetProcAddress", "_GetProcAddress");
type MessageBox is access function
( hWnd : Address := Null_Address;
lpText : char_array;
lpCaption : char_array := To_C ("Greeting");
uType : Unsigned_16 := 0
) return Integer_16;
pragma Convention (Stdcall, MessageBox);
function To_MessageBox is new Ada.Unchecked_Conversion (Address, MessageBox);
Library : HANDLE := LoadLibrary (To_C ("user32.dll"));
Pointer : Address := GetProcAddress (Library, To_C ("MessageBoxA"));
begin
if Pointer /= Null_Address then
declare
Result : Integer_16;
begin
Result := To_MessageBox (Pointer) (lpText => To_C ("Hello!"));
end;
else
Put_Line ("Unable to load the library " & HANDLE'Image (Library));
end if;
end Shared_Library_Call;
| package main
import "C"
import (
"fmt"
"os"
"unsafe"
)
var handle = -1
func myOpenImage(s string) int {
fmt.Fprintf(os.Stderr, "internal openImage opens %s...\n", s)
handle++
return handle
}
func main() {
libpath := C.CString("./fakeimglib.so")
defer C.free(unsafe.Pointer(libpath))
imglib := C.dlopen(libpath, C.RTLD_LAZY)
var imghandle int
if imglib != nil {
openimage := C.CString("openimage")
defer C.free(unsafe.Pointer(openimage))
fp := C.dlsym(imglib, openimage)
if fp != nil {
fi := C.CString("fake.img")
defer C.free(unsafe.Pointer(fi))
imghandle = int(C.bridge_someFunc(C.someFunc(fp), fi))
} else {
imghandle = myOpenImage("fake.img")
}
C.dlclose(imglib)
} else {
imghandle = myOpenImage("fake.img")
}
fmt.Printf("opened with handle %d\n", imghandle)
}
|
Convert the following code from Ada to Java, ensuring the logic remains intact. | with Ada.Text_IO; use Ada.Text_IO;
with Interfaces; use Interfaces;
with Interfaces.C; use Interfaces.C;
with System; use System;
with Ada.Unchecked_Conversion;
procedure Shared_Library_Call is
type HANDLE is new Unsigned_32;
function LoadLibrary (lpFileName : char_array) return HANDLE;
pragma Import (stdcall, LoadLibrary, "LoadLibrary", "_LoadLibraryA");
function GetProcAddress (hModule : HANDLE; lpProcName : char_array)
return Address;
pragma Import (stdcall, GetProcAddress, "GetProcAddress", "_GetProcAddress");
type MessageBox is access function
( hWnd : Address := Null_Address;
lpText : char_array;
lpCaption : char_array := To_C ("Greeting");
uType : Unsigned_16 := 0
) return Integer_16;
pragma Convention (Stdcall, MessageBox);
function To_MessageBox is new Ada.Unchecked_Conversion (Address, MessageBox);
Library : HANDLE := LoadLibrary (To_C ("user32.dll"));
Pointer : Address := GetProcAddress (Library, To_C ("MessageBoxA"));
begin
if Pointer /= Null_Address then
declare
Result : Integer_16;
begin
Result := To_MessageBox (Pointer) (lpText => To_C ("Hello!"));
end;
else
Put_Line ("Unable to load the library " & HANDLE'Image (Library));
end if;
end Shared_Library_Call;
|
import java.util.Collections;
import java.util.Random;
public class TrySort {
static boolean useC;
static {
try {
System.loadLibrary("TrySort");
useC = true;
} catch(UnsatisfiedLinkError e) {
useC = false;
}
}
static native void sortInC(int[] ary);
static class IntList extends java.util.AbstractList<Integer> {
int[] ary;
IntList(int[] ary) { this.ary = ary; }
public Integer get(int i) { return ary[i]; }
public Integer set(int i, Integer j) {
Integer o = ary[i]; ary[i] = j; return o;
}
public int size() { return ary.length; }
}
static class ReverseAbsCmp
implements java.util.Comparator<Integer>
{
public int compare(Integer pa, Integer pb) {
int a = pa > 0 ? -pa : pa;
int b = pb > 0 ? -pb : pb;
return a < b ? -1 : a > b ? 1 : 0;
}
}
static void sortInJava(int[] ary) {
Collections.sort(new IntList(ary), new ReverseAbsCmp());
}
public static void main(String[] args) {
int[] ary = new int[1000000];
Random rng = new Random();
for (int i = 0; i < ary.length; i++)
ary[i] = rng.nextInt();
if (useC) {
System.out.print("Sorting in C... ");
sortInC(ary);
} else {
System.out.print
("Missing library for C! Sorting in Java... ");
sortInJava(ary);
}
for (int i = 0; i < ary.length - 1; i++) {
int a = ary[i];
int b = ary[i + 1];
if ((a > 0 ? -a : a) > (b > 0 ? -b : b)) {
System.out.println("*BUG IN SORT*");
System.exit(1);
}
}
System.out.println("ok");
}
}
|
Transform the following Ada implementation into Python, maintaining the same output and logic. | with Ada.Text_IO; use Ada.Text_IO;
with Interfaces; use Interfaces;
with Interfaces.C; use Interfaces.C;
with System; use System;
with Ada.Unchecked_Conversion;
procedure Shared_Library_Call is
type HANDLE is new Unsigned_32;
function LoadLibrary (lpFileName : char_array) return HANDLE;
pragma Import (stdcall, LoadLibrary, "LoadLibrary", "_LoadLibraryA");
function GetProcAddress (hModule : HANDLE; lpProcName : char_array)
return Address;
pragma Import (stdcall, GetProcAddress, "GetProcAddress", "_GetProcAddress");
type MessageBox is access function
( hWnd : Address := Null_Address;
lpText : char_array;
lpCaption : char_array := To_C ("Greeting");
uType : Unsigned_16 := 0
) return Integer_16;
pragma Convention (Stdcall, MessageBox);
function To_MessageBox is new Ada.Unchecked_Conversion (Address, MessageBox);
Library : HANDLE := LoadLibrary (To_C ("user32.dll"));
Pointer : Address := GetProcAddress (Library, To_C ("MessageBoxA"));
begin
if Pointer /= Null_Address then
declare
Result : Integer_16;
begin
Result := To_MessageBox (Pointer) (lpText => To_C ("Hello!"));
end;
else
Put_Line ("Unable to load the library " & HANDLE'Image (Library));
end if;
end Shared_Library_Call;
| import ctypes
user32_dll = ctypes.cdll.LoadLibrary('User32.dll')
print user32_dll.GetDoubleClickTime()
|
Convert this Ada block to VB, preserving its control flow and logic. | with Ada.Text_IO; use Ada.Text_IO;
with Interfaces; use Interfaces;
with Interfaces.C; use Interfaces.C;
with System; use System;
with Ada.Unchecked_Conversion;
procedure Shared_Library_Call is
type HANDLE is new Unsigned_32;
function LoadLibrary (lpFileName : char_array) return HANDLE;
pragma Import (stdcall, LoadLibrary, "LoadLibrary", "_LoadLibraryA");
function GetProcAddress (hModule : HANDLE; lpProcName : char_array)
return Address;
pragma Import (stdcall, GetProcAddress, "GetProcAddress", "_GetProcAddress");
type MessageBox is access function
( hWnd : Address := Null_Address;
lpText : char_array;
lpCaption : char_array := To_C ("Greeting");
uType : Unsigned_16 := 0
) return Integer_16;
pragma Convention (Stdcall, MessageBox);
function To_MessageBox is new Ada.Unchecked_Conversion (Address, MessageBox);
Library : HANDLE := LoadLibrary (To_C ("user32.dll"));
Pointer : Address := GetProcAddress (Library, To_C ("MessageBoxA"));
begin
if Pointer /= Null_Address then
declare
Result : Integer_16;
begin
Result := To_MessageBox (Pointer) (lpText => To_C ("Hello!"));
end;
else
Put_Line ("Unable to load the library " & HANDLE'Image (Library));
end if;
end Shared_Library_Call;
| Declare Dynamic Library "Kernel32"
Sub SetLastError (ByVal dwErr As Long)
Function GetLastError& ()
End Declare
SetLastError 20
Print GetLastError
|
Generate a C translation of this Arturo snippet without changing its computational steps. | getCurlVersion: function [][
try? [
call.external:'curl "curl_version" .expect: :string []
]
else [
"library not found"
]
]
print ["curl version:" getCurlVersion]
| #include <stdio.h>
#include <stdlib.h>
#include <dlfcn.h>
int myopenimage(const char *in)
{
static int handle=0;
fprintf(stderr, "internal openimage opens %s...\n", in);
return handle++;
}
int main()
{
void *imglib;
int (*extopenimage)(const char *);
int imghandle;
imglib = dlopen("./fakeimglib.so", RTLD_LAZY);
if ( imglib != NULL ) {
*(void **)(&extopenimage) = dlsym(imglib, "openimage");
imghandle = extopenimage("fake.img");
} else {
imghandle = myopenimage("fake.img");
}
printf("opened with handle %d\n", imghandle);
if (imglib != NULL ) dlclose(imglib);
return EXIT_SUCCESS;
}
|
Generate a C# translation of this Arturo snippet without changing its computational steps. | getCurlVersion: function [][
try? [
call.external:'curl "curl_version" .expect: :string []
]
else [
"library not found"
]
]
print ["curl version:" getCurlVersion]
| using System.Runtime.InteropServices;
class Program {
[DllImport("fakelib.dll")]
public static extern int fakefunction(int args);
static void Main(string[] args) {
int r = fakefunction(10);
}
}
|
Write a version of this Arturo function in Java with identical behavior. | getCurlVersion: function [][
try? [
call.external:'curl "curl_version" .expect: :string []
]
else [
"library not found"
]
]
print ["curl version:" getCurlVersion]
|
import java.util.Collections;
import java.util.Random;
public class TrySort {
static boolean useC;
static {
try {
System.loadLibrary("TrySort");
useC = true;
} catch(UnsatisfiedLinkError e) {
useC = false;
}
}
static native void sortInC(int[] ary);
static class IntList extends java.util.AbstractList<Integer> {
int[] ary;
IntList(int[] ary) { this.ary = ary; }
public Integer get(int i) { return ary[i]; }
public Integer set(int i, Integer j) {
Integer o = ary[i]; ary[i] = j; return o;
}
public int size() { return ary.length; }
}
static class ReverseAbsCmp
implements java.util.Comparator<Integer>
{
public int compare(Integer pa, Integer pb) {
int a = pa > 0 ? -pa : pa;
int b = pb > 0 ? -pb : pb;
return a < b ? -1 : a > b ? 1 : 0;
}
}
static void sortInJava(int[] ary) {
Collections.sort(new IntList(ary), new ReverseAbsCmp());
}
public static void main(String[] args) {
int[] ary = new int[1000000];
Random rng = new Random();
for (int i = 0; i < ary.length; i++)
ary[i] = rng.nextInt();
if (useC) {
System.out.print("Sorting in C... ");
sortInC(ary);
} else {
System.out.print
("Missing library for C! Sorting in Java... ");
sortInJava(ary);
}
for (int i = 0; i < ary.length - 1; i++) {
int a = ary[i];
int b = ary[i + 1];
if ((a > 0 ? -a : a) > (b > 0 ? -b : b)) {
System.out.println("*BUG IN SORT*");
System.exit(1);
}
}
System.out.println("ok");
}
}
|
Port the provided Arturo code into Python while preserving the original functionality. | getCurlVersion: function [][
try? [
call.external:'curl "curl_version" .expect: :string []
]
else [
"library not found"
]
]
print ["curl version:" getCurlVersion]
| import ctypes
user32_dll = ctypes.cdll.LoadLibrary('User32.dll')
print user32_dll.GetDoubleClickTime()
|
Translate this program into VB but keep the logic exactly as in Arturo. | getCurlVersion: function [][
try? [
call.external:'curl "curl_version" .expect: :string []
]
else [
"library not found"
]
]
print ["curl version:" getCurlVersion]
| Declare Dynamic Library "Kernel32"
Sub SetLastError (ByVal dwErr As Long)
Function GetLastError& ()
End Declare
SetLastError 20
Print GetLastError
|
Can you help me rewrite this code in Go instead of Arturo, keeping it the same logically? | getCurlVersion: function [][
try? [
call.external:'curl "curl_version" .expect: :string []
]
else [
"library not found"
]
]
print ["curl version:" getCurlVersion]
| package main
import "C"
import (
"fmt"
"os"
"unsafe"
)
var handle = -1
func myOpenImage(s string) int {
fmt.Fprintf(os.Stderr, "internal openImage opens %s...\n", s)
handle++
return handle
}
func main() {
libpath := C.CString("./fakeimglib.so")
defer C.free(unsafe.Pointer(libpath))
imglib := C.dlopen(libpath, C.RTLD_LAZY)
var imghandle int
if imglib != nil {
openimage := C.CString("openimage")
defer C.free(unsafe.Pointer(openimage))
fp := C.dlsym(imglib, openimage)
if fp != nil {
fi := C.CString("fake.img")
defer C.free(unsafe.Pointer(fi))
imghandle = int(C.bridge_someFunc(C.someFunc(fp), fi))
} else {
imghandle = myOpenImage("fake.img")
}
C.dlclose(imglib)
} else {
imghandle = myOpenImage("fake.img")
}
fmt.Printf("opened with handle %d\n", imghandle)
}
|
Write a version of this AutoHotKey function in C with identical behavior. | ahkdll := DllCall("LoadLibrary", "str", "AutoHotkey.dll")
clientHandle := DllCall("AutoHotkey\ahkdll", "str", "dllclient.ahk", "str"
, "", "str", "parameter1 parameter2", "Cdecl Int")
| #include <stdio.h>
#include <stdlib.h>
#include <dlfcn.h>
int myopenimage(const char *in)
{
static int handle=0;
fprintf(stderr, "internal openimage opens %s...\n", in);
return handle++;
}
int main()
{
void *imglib;
int (*extopenimage)(const char *);
int imghandle;
imglib = dlopen("./fakeimglib.so", RTLD_LAZY);
if ( imglib != NULL ) {
*(void **)(&extopenimage) = dlsym(imglib, "openimage");
imghandle = extopenimage("fake.img");
} else {
imghandle = myopenimage("fake.img");
}
printf("opened with handle %d\n", imghandle);
if (imglib != NULL ) dlclose(imglib);
return EXIT_SUCCESS;
}
|
Change the programming language of this snippet from AutoHotKey to C# without modifying what it does. | ahkdll := DllCall("LoadLibrary", "str", "AutoHotkey.dll")
clientHandle := DllCall("AutoHotkey\ahkdll", "str", "dllclient.ahk", "str"
, "", "str", "parameter1 parameter2", "Cdecl Int")
| using System.Runtime.InteropServices;
class Program {
[DllImport("fakelib.dll")]
public static extern int fakefunction(int args);
static void Main(string[] args) {
int r = fakefunction(10);
}
}
|
Keep all operations the same but rewrite the snippet in Java. | ahkdll := DllCall("LoadLibrary", "str", "AutoHotkey.dll")
clientHandle := DllCall("AutoHotkey\ahkdll", "str", "dllclient.ahk", "str"
, "", "str", "parameter1 parameter2", "Cdecl Int")
|
import java.util.Collections;
import java.util.Random;
public class TrySort {
static boolean useC;
static {
try {
System.loadLibrary("TrySort");
useC = true;
} catch(UnsatisfiedLinkError e) {
useC = false;
}
}
static native void sortInC(int[] ary);
static class IntList extends java.util.AbstractList<Integer> {
int[] ary;
IntList(int[] ary) { this.ary = ary; }
public Integer get(int i) { return ary[i]; }
public Integer set(int i, Integer j) {
Integer o = ary[i]; ary[i] = j; return o;
}
public int size() { return ary.length; }
}
static class ReverseAbsCmp
implements java.util.Comparator<Integer>
{
public int compare(Integer pa, Integer pb) {
int a = pa > 0 ? -pa : pa;
int b = pb > 0 ? -pb : pb;
return a < b ? -1 : a > b ? 1 : 0;
}
}
static void sortInJava(int[] ary) {
Collections.sort(new IntList(ary), new ReverseAbsCmp());
}
public static void main(String[] args) {
int[] ary = new int[1000000];
Random rng = new Random();
for (int i = 0; i < ary.length; i++)
ary[i] = rng.nextInt();
if (useC) {
System.out.print("Sorting in C... ");
sortInC(ary);
} else {
System.out.print
("Missing library for C! Sorting in Java... ");
sortInJava(ary);
}
for (int i = 0; i < ary.length - 1; i++) {
int a = ary[i];
int b = ary[i + 1];
if ((a > 0 ? -a : a) > (b > 0 ? -b : b)) {
System.out.println("*BUG IN SORT*");
System.exit(1);
}
}
System.out.println("ok");
}
}
|
Convert this AutoHotKey snippet to Python and keep its semantics consistent. | ahkdll := DllCall("LoadLibrary", "str", "AutoHotkey.dll")
clientHandle := DllCall("AutoHotkey\ahkdll", "str", "dllclient.ahk", "str"
, "", "str", "parameter1 parameter2", "Cdecl Int")
| import ctypes
user32_dll = ctypes.cdll.LoadLibrary('User32.dll')
print user32_dll.GetDoubleClickTime()
|
Write a version of this AutoHotKey function in VB with identical behavior. | ahkdll := DllCall("LoadLibrary", "str", "AutoHotkey.dll")
clientHandle := DllCall("AutoHotkey\ahkdll", "str", "dllclient.ahk", "str"
, "", "str", "parameter1 parameter2", "Cdecl Int")
| Declare Dynamic Library "Kernel32"
Sub SetLastError (ByVal dwErr As Long)
Function GetLastError& ()
End Declare
SetLastError 20
Print GetLastError
|
Rewrite the snippet below in Go so it works the same as the original AutoHotKey code. | ahkdll := DllCall("LoadLibrary", "str", "AutoHotkey.dll")
clientHandle := DllCall("AutoHotkey\ahkdll", "str", "dllclient.ahk", "str"
, "", "str", "parameter1 parameter2", "Cdecl Int")
| package main
import "C"
import (
"fmt"
"os"
"unsafe"
)
var handle = -1
func myOpenImage(s string) int {
fmt.Fprintf(os.Stderr, "internal openImage opens %s...\n", s)
handle++
return handle
}
func main() {
libpath := C.CString("./fakeimglib.so")
defer C.free(unsafe.Pointer(libpath))
imglib := C.dlopen(libpath, C.RTLD_LAZY)
var imghandle int
if imglib != nil {
openimage := C.CString("openimage")
defer C.free(unsafe.Pointer(openimage))
fp := C.dlsym(imglib, openimage)
if fp != nil {
fi := C.CString("fake.img")
defer C.free(unsafe.Pointer(fi))
imghandle = int(C.bridge_someFunc(C.someFunc(fp), fi))
} else {
imghandle = myOpenImage("fake.img")
}
C.dlclose(imglib)
} else {
imghandle = myOpenImage("fake.img")
}
fmt.Printf("opened with handle %d\n", imghandle)
}
|
Convert this BBC_Basic snippet to C and keep its semantics consistent. | SYS "MessageBox", @hwnd%, "This is a test message", 0, 0
| #include <stdio.h>
#include <stdlib.h>
#include <dlfcn.h>
int myopenimage(const char *in)
{
static int handle=0;
fprintf(stderr, "internal openimage opens %s...\n", in);
return handle++;
}
int main()
{
void *imglib;
int (*extopenimage)(const char *);
int imghandle;
imglib = dlopen("./fakeimglib.so", RTLD_LAZY);
if ( imglib != NULL ) {
*(void **)(&extopenimage) = dlsym(imglib, "openimage");
imghandle = extopenimage("fake.img");
} else {
imghandle = myopenimage("fake.img");
}
printf("opened with handle %d\n", imghandle);
if (imglib != NULL ) dlclose(imglib);
return EXIT_SUCCESS;
}
|
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