Instruction
stringlengths
45
106
input_code
stringlengths
1
13.7k
output_code
stringlengths
1
13.7k
Port the following code from Delphi to Go with equivalent syntax and logic.
function Factorize(n : Integer) : String; begin if n <= 1 then Exit('1'); var k := 2; while n >= k do begin while (n mod k) = 0 do begin Result += ' * '+IntToStr(k); n := n div k; end; Inc(k); end; Result:=SubStr(Result, 4); end; var i : Integer; for i := 1 to 22 do PrintLn(IntToStr(i) + ': ' + Factorize(i));
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Please provide an equivalent version of this Elixir code in C.
defmodule RC do def factor(n), do: factor(n, 2, []) def factor(n, i, fact) when n < i*i, do: Enum.reverse([n|fact]) def factor(n, i, fact) do if rem(n,i)==0, do: factor(div(n,i), i, [i|fact]), else: factor(n, i+1, fact) end end Enum.each(1..20, fn n -> IO.puts "
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Translate the given Elixir code snippet into C# without altering its behavior.
defmodule RC do def factor(n), do: factor(n, 2, []) def factor(n, i, fact) when n < i*i, do: Enum.reverse([n|fact]) def factor(n, i, fact) do if rem(n,i)==0, do: factor(div(n,i), i, [i|fact]), else: factor(n, i+1, fact) end end Enum.each(1..20, fn n -> IO.puts "
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Convert the following code from Elixir to C++, ensuring the logic remains intact.
defmodule RC do def factor(n), do: factor(n, 2, []) def factor(n, i, fact) when n < i*i, do: Enum.reverse([n|fact]) def factor(n, i, fact) do if rem(n,i)==0, do: factor(div(n,i), i, [i|fact]), else: factor(n, i+1, fact) end end Enum.each(1..20, fn n -> IO.puts "
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Please provide an equivalent version of this Elixir code in Java.
defmodule RC do def factor(n), do: factor(n, 2, []) def factor(n, i, fact) when n < i*i, do: Enum.reverse([n|fact]) def factor(n, i, fact) do if rem(n,i)==0, do: factor(div(n,i), i, [i|fact]), else: factor(n, i+1, fact) end end Enum.each(1..20, fn n -> IO.puts "
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Convert this Elixir snippet to Python and keep its semantics consistent.
defmodule RC do def factor(n), do: factor(n, 2, []) def factor(n, i, fact) when n < i*i, do: Enum.reverse([n|fact]) def factor(n, i, fact) do if rem(n,i)==0, do: factor(div(n,i), i, [i|fact]), else: factor(n, i+1, fact) end end Enum.each(1..20, fn n -> IO.puts "
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Write the same code in VB as shown below in Elixir.
defmodule RC do def factor(n), do: factor(n, 2, []) def factor(n, i, fact) when n < i*i, do: Enum.reverse([n|fact]) def factor(n, i, fact) do if rem(n,i)==0, do: factor(div(n,i), i, [i|fact]), else: factor(n, i+1, fact) end end Enum.each(1..20, fn n -> IO.puts "
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Produce a language-to-language conversion: from Elixir to Go, same semantics.
defmodule RC do def factor(n), do: factor(n, 2, []) def factor(n, i, fact) when n < i*i, do: Enum.reverse([n|fact]) def factor(n, i, fact) do if rem(n,i)==0, do: factor(div(n,i), i, [i|fact]), else: factor(n, i+1, fact) end end Enum.each(1..20, fn n -> IO.puts "
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Generate an equivalent C version of this F# code.
let factorsOf (num) = Seq.unfold (fun (f, n) -> let rec genFactor (f, n) = if f > n then None elif n % f = 0 then Some (f, (f, n/f)) else genFactor (f+1, n) genFactor (f, n)) (2, num) let showLines = Seq.concat (seq { yield seq{ yield(Seq.singleton 1)}; yield (Seq.skip 2 (Seq.initInfinite factorsOf))}) showLines |> Seq.iteri (fun i f -> printfn "%d = %s" (i+1) (String.Join(" * ", Seq.toArray f)))
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Transform the following F# implementation into C#, maintaining the same output and logic.
let factorsOf (num) = Seq.unfold (fun (f, n) -> let rec genFactor (f, n) = if f > n then None elif n % f = 0 then Some (f, (f, n/f)) else genFactor (f+1, n) genFactor (f, n)) (2, num) let showLines = Seq.concat (seq { yield seq{ yield(Seq.singleton 1)}; yield (Seq.skip 2 (Seq.initInfinite factorsOf))}) showLines |> Seq.iteri (fun i f -> printfn "%d = %s" (i+1) (String.Join(" * ", Seq.toArray f)))
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Transform the following F# implementation into C++, maintaining the same output and logic.
let factorsOf (num) = Seq.unfold (fun (f, n) -> let rec genFactor (f, n) = if f > n then None elif n % f = 0 then Some (f, (f, n/f)) else genFactor (f+1, n) genFactor (f, n)) (2, num) let showLines = Seq.concat (seq { yield seq{ yield(Seq.singleton 1)}; yield (Seq.skip 2 (Seq.initInfinite factorsOf))}) showLines |> Seq.iteri (fun i f -> printfn "%d = %s" (i+1) (String.Join(" * ", Seq.toArray f)))
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Port the following code from F# to Java with equivalent syntax and logic.
let factorsOf (num) = Seq.unfold (fun (f, n) -> let rec genFactor (f, n) = if f > n then None elif n % f = 0 then Some (f, (f, n/f)) else genFactor (f+1, n) genFactor (f, n)) (2, num) let showLines = Seq.concat (seq { yield seq{ yield(Seq.singleton 1)}; yield (Seq.skip 2 (Seq.initInfinite factorsOf))}) showLines |> Seq.iteri (fun i f -> printfn "%d = %s" (i+1) (String.Join(" * ", Seq.toArray f)))
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Write the same algorithm in Python as shown in this F# implementation.
let factorsOf (num) = Seq.unfold (fun (f, n) -> let rec genFactor (f, n) = if f > n then None elif n % f = 0 then Some (f, (f, n/f)) else genFactor (f+1, n) genFactor (f, n)) (2, num) let showLines = Seq.concat (seq { yield seq{ yield(Seq.singleton 1)}; yield (Seq.skip 2 (Seq.initInfinite factorsOf))}) showLines |> Seq.iteri (fun i f -> printfn "%d = %s" (i+1) (String.Join(" * ", Seq.toArray f)))
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Rewrite the snippet below in VB so it works the same as the original F# code.
let factorsOf (num) = Seq.unfold (fun (f, n) -> let rec genFactor (f, n) = if f > n then None elif n % f = 0 then Some (f, (f, n/f)) else genFactor (f+1, n) genFactor (f, n)) (2, num) let showLines = Seq.concat (seq { yield seq{ yield(Seq.singleton 1)}; yield (Seq.skip 2 (Seq.initInfinite factorsOf))}) showLines |> Seq.iteri (fun i f -> printfn "%d = %s" (i+1) (String.Join(" * ", Seq.toArray f)))
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Write the same code in Go as shown below in F#.
let factorsOf (num) = Seq.unfold (fun (f, n) -> let rec genFactor (f, n) = if f > n then None elif n % f = 0 then Some (f, (f, n/f)) else genFactor (f+1, n) genFactor (f, n)) (2, num) let showLines = Seq.concat (seq { yield seq{ yield(Seq.singleton 1)}; yield (Seq.skip 2 (Seq.initInfinite factorsOf))}) showLines |> Seq.iteri (fun i f -> printfn "%d = %s" (i+1) (String.Join(" * ", Seq.toArray f)))
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Produce a language-to-language conversion: from Factor to C, same semantics.
USING: io kernel math.primes.factors math.ranges prettyprint sequences ; : .factors ( n -- ) dup pprint ": " write factors [ " × " write ] [ pprint ] interleave nl ; "1: 1" print 2 20 [a,b] [ .factors ] each
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Can you help me rewrite this code in C# instead of Factor, keeping it the same logically?
USING: io kernel math.primes.factors math.ranges prettyprint sequences ; : .factors ( n -- ) dup pprint ": " write factors [ " × " write ] [ pprint ] interleave nl ; "1: 1" print 2 20 [a,b] [ .factors ] each
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Port the following code from Factor to C++ with equivalent syntax and logic.
USING: io kernel math.primes.factors math.ranges prettyprint sequences ; : .factors ( n -- ) dup pprint ": " write factors [ " × " write ] [ pprint ] interleave nl ; "1: 1" print 2 20 [a,b] [ .factors ] each
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Rewrite the snippet below in Java so it works the same as the original Factor code.
USING: io kernel math.primes.factors math.ranges prettyprint sequences ; : .factors ( n -- ) dup pprint ": " write factors [ " × " write ] [ pprint ] interleave nl ; "1: 1" print 2 20 [a,b] [ .factors ] each
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Translate the given Factor code snippet into Python without altering its behavior.
USING: io kernel math.primes.factors math.ranges prettyprint sequences ; : .factors ( n -- ) dup pprint ": " write factors [ " × " write ] [ pprint ] interleave nl ; "1: 1" print 2 20 [a,b] [ .factors ] each
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Port the provided Factor code into VB while preserving the original functionality.
USING: io kernel math.primes.factors math.ranges prettyprint sequences ; : .factors ( n -- ) dup pprint ": " write factors [ " × " write ] [ pprint ] interleave nl ; "1: 1" print 2 20 [a,b] [ .factors ] each
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Rewrite this program in Go while keeping its functionality equivalent to the Factor version.
USING: io kernel math.primes.factors math.ranges prettyprint sequences ; : .factors ( n -- ) dup pprint ": " write factors [ " × " write ] [ pprint ] interleave nl ; "1: 1" print 2 20 [a,b] [ .factors ] each
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Transform the following Forth implementation into C, maintaining the same output and logic.
: .factors 2 begin 2dup dup * >= while 2dup /mod swap if drop 1+ 1 or else -rot nip dup . ." x " then repeat drop . ; : main ." 1 : 1" cr 1+ 2 ?do i . ." : " i .factors cr loop ; 15 main bye
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Produce a language-to-language conversion: from Forth to C#, same semantics.
: .factors 2 begin 2dup dup * >= while 2dup /mod swap if drop 1+ 1 or else -rot nip dup . ." x " then repeat drop . ; : main ." 1 : 1" cr 1+ 2 ?do i . ." : " i .factors cr loop ; 15 main bye
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Can you help me rewrite this code in C++ instead of Forth, keeping it the same logically?
: .factors 2 begin 2dup dup * >= while 2dup /mod swap if drop 1+ 1 or else -rot nip dup . ." x " then repeat drop . ; : main ." 1 : 1" cr 1+ 2 ?do i . ." : " i .factors cr loop ; 15 main bye
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Preserve the algorithm and functionality while converting the code from Forth to Java.
: .factors 2 begin 2dup dup * >= while 2dup /mod swap if drop 1+ 1 or else -rot nip dup . ." x " then repeat drop . ; : main ." 1 : 1" cr 1+ 2 ?do i . ." : " i .factors cr loop ; 15 main bye
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Convert this Forth block to Python, preserving its control flow and logic.
: .factors 2 begin 2dup dup * >= while 2dup /mod swap if drop 1+ 1 or else -rot nip dup . ." x " then repeat drop . ; : main ." 1 : 1" cr 1+ 2 ?do i . ." : " i .factors cr loop ; 15 main bye
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Please provide an equivalent version of this Forth code in VB.
: .factors 2 begin 2dup dup * >= while 2dup /mod swap if drop 1+ 1 or else -rot nip dup . ." x " then repeat drop . ; : main ." 1 : 1" cr 1+ 2 ?do i . ." : " i .factors cr loop ; 15 main bye
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Convert this Forth snippet to Go and keep its semantics consistent.
: .factors 2 begin 2dup dup * >= while 2dup /mod swap if drop 1+ 1 or else -rot nip dup . ." x " then repeat drop . ; : main ." 1 : 1" cr 1+ 2 ?do i . ." : " i .factors cr loop ; 15 main bye
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Generate an equivalent C# version of this Fortran code.
module prime_mod integer, dimension(:), allocatable :: sieve_table private :: PrimeQ contains subroutine sieve(n) integer, intent(in) :: n integer :: status, i, j if ((n .lt. 1) .or. allocated(sieve_table)) deallocate(sieve_table) if (n .lt. 1) return allocate(sieve_table(n), stat=status) if (status .ne. 0) stop 'cannot allocate space' sieve_table(1) = 1 do i=2,int(sqrt(real(n)))+1 if (sieve_table(i) .eq. 0) then do j = i*i, n, i sieve_table(j) = i end do end if end do end subroutine sieve subroutine check_sieve(n) integer, intent(in) :: n if (.not. (allocated(sieve_table) .and. ((1 .le. n) .and. (n .le. size(sieve_table))))) stop 'Call sieve first' end subroutine check_sieve logical function isPrime(p) integer, intent(in) :: p call check_sieve(p) isPrime = PrimeQ(p) end function isPrime logical function isComposite(p) integer, intent(in) :: p isComposite = .not. isPrime(p) end function isComposite logical function PrimeQ(p) integer, intent(in) :: p PrimeQ = sieve_table(p) .eq. 0 end function PrimeQ subroutine prime_factors(p, rv, n) integer, intent(in) :: p integer, dimension(:), intent(out) :: rv integer, intent(out) :: n integer :: i, m call check_sieve(p) m = p i = 1 if (p .ne. 1) then do while ((.not. PrimeQ(m)) .and. (i .lt. size(rv))) rv(i) = sieve_table(m) m = m/rv(i) i = i+1 end do end if if (i .le. size(rv)) rv(i) = m n = i end subroutine prime_factors end module prime_mod program count_in_factors use prime_mod integer :: i, n integer, dimension(8) :: factors call sieve(40) do i=1,40 factors = 0 call prime_factors(i, factors, n) write(6,*)'assert',i,'= */',factors(:n) end do call sieve(0) end program count_in_factors
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Convert this Fortran snippet to C++ and keep its semantics consistent.
module prime_mod integer, dimension(:), allocatable :: sieve_table private :: PrimeQ contains subroutine sieve(n) integer, intent(in) :: n integer :: status, i, j if ((n .lt. 1) .or. allocated(sieve_table)) deallocate(sieve_table) if (n .lt. 1) return allocate(sieve_table(n), stat=status) if (status .ne. 0) stop 'cannot allocate space' sieve_table(1) = 1 do i=2,int(sqrt(real(n)))+1 if (sieve_table(i) .eq. 0) then do j = i*i, n, i sieve_table(j) = i end do end if end do end subroutine sieve subroutine check_sieve(n) integer, intent(in) :: n if (.not. (allocated(sieve_table) .and. ((1 .le. n) .and. (n .le. size(sieve_table))))) stop 'Call sieve first' end subroutine check_sieve logical function isPrime(p) integer, intent(in) :: p call check_sieve(p) isPrime = PrimeQ(p) end function isPrime logical function isComposite(p) integer, intent(in) :: p isComposite = .not. isPrime(p) end function isComposite logical function PrimeQ(p) integer, intent(in) :: p PrimeQ = sieve_table(p) .eq. 0 end function PrimeQ subroutine prime_factors(p, rv, n) integer, intent(in) :: p integer, dimension(:), intent(out) :: rv integer, intent(out) :: n integer :: i, m call check_sieve(p) m = p i = 1 if (p .ne. 1) then do while ((.not. PrimeQ(m)) .and. (i .lt. size(rv))) rv(i) = sieve_table(m) m = m/rv(i) i = i+1 end do end if if (i .le. size(rv)) rv(i) = m n = i end subroutine prime_factors end module prime_mod program count_in_factors use prime_mod integer :: i, n integer, dimension(8) :: factors call sieve(40) do i=1,40 factors = 0 call prime_factors(i, factors, n) write(6,*)'assert',i,'= */',factors(:n) end do call sieve(0) end program count_in_factors
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Write the same algorithm in C as shown in this Fortran implementation.
module prime_mod integer, dimension(:), allocatable :: sieve_table private :: PrimeQ contains subroutine sieve(n) integer, intent(in) :: n integer :: status, i, j if ((n .lt. 1) .or. allocated(sieve_table)) deallocate(sieve_table) if (n .lt. 1) return allocate(sieve_table(n), stat=status) if (status .ne. 0) stop 'cannot allocate space' sieve_table(1) = 1 do i=2,int(sqrt(real(n)))+1 if (sieve_table(i) .eq. 0) then do j = i*i, n, i sieve_table(j) = i end do end if end do end subroutine sieve subroutine check_sieve(n) integer, intent(in) :: n if (.not. (allocated(sieve_table) .and. ((1 .le. n) .and. (n .le. size(sieve_table))))) stop 'Call sieve first' end subroutine check_sieve logical function isPrime(p) integer, intent(in) :: p call check_sieve(p) isPrime = PrimeQ(p) end function isPrime logical function isComposite(p) integer, intent(in) :: p isComposite = .not. isPrime(p) end function isComposite logical function PrimeQ(p) integer, intent(in) :: p PrimeQ = sieve_table(p) .eq. 0 end function PrimeQ subroutine prime_factors(p, rv, n) integer, intent(in) :: p integer, dimension(:), intent(out) :: rv integer, intent(out) :: n integer :: i, m call check_sieve(p) m = p i = 1 if (p .ne. 1) then do while ((.not. PrimeQ(m)) .and. (i .lt. size(rv))) rv(i) = sieve_table(m) m = m/rv(i) i = i+1 end do end if if (i .le. size(rv)) rv(i) = m n = i end subroutine prime_factors end module prime_mod program count_in_factors use prime_mod integer :: i, n integer, dimension(8) :: factors call sieve(40) do i=1,40 factors = 0 call prime_factors(i, factors, n) write(6,*)'assert',i,'= */',factors(:n) end do call sieve(0) end program count_in_factors
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Can you help me rewrite this code in Java instead of Fortran, keeping it the same logically?
module prime_mod integer, dimension(:), allocatable :: sieve_table private :: PrimeQ contains subroutine sieve(n) integer, intent(in) :: n integer :: status, i, j if ((n .lt. 1) .or. allocated(sieve_table)) deallocate(sieve_table) if (n .lt. 1) return allocate(sieve_table(n), stat=status) if (status .ne. 0) stop 'cannot allocate space' sieve_table(1) = 1 do i=2,int(sqrt(real(n)))+1 if (sieve_table(i) .eq. 0) then do j = i*i, n, i sieve_table(j) = i end do end if end do end subroutine sieve subroutine check_sieve(n) integer, intent(in) :: n if (.not. (allocated(sieve_table) .and. ((1 .le. n) .and. (n .le. size(sieve_table))))) stop 'Call sieve first' end subroutine check_sieve logical function isPrime(p) integer, intent(in) :: p call check_sieve(p) isPrime = PrimeQ(p) end function isPrime logical function isComposite(p) integer, intent(in) :: p isComposite = .not. isPrime(p) end function isComposite logical function PrimeQ(p) integer, intent(in) :: p PrimeQ = sieve_table(p) .eq. 0 end function PrimeQ subroutine prime_factors(p, rv, n) integer, intent(in) :: p integer, dimension(:), intent(out) :: rv integer, intent(out) :: n integer :: i, m call check_sieve(p) m = p i = 1 if (p .ne. 1) then do while ((.not. PrimeQ(m)) .and. (i .lt. size(rv))) rv(i) = sieve_table(m) m = m/rv(i) i = i+1 end do end if if (i .le. size(rv)) rv(i) = m n = i end subroutine prime_factors end module prime_mod program count_in_factors use prime_mod integer :: i, n integer, dimension(8) :: factors call sieve(40) do i=1,40 factors = 0 call prime_factors(i, factors, n) write(6,*)'assert',i,'= */',factors(:n) end do call sieve(0) end program count_in_factors
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Can you help me rewrite this code in Python instead of Fortran, keeping it the same logically?
module prime_mod integer, dimension(:), allocatable :: sieve_table private :: PrimeQ contains subroutine sieve(n) integer, intent(in) :: n integer :: status, i, j if ((n .lt. 1) .or. allocated(sieve_table)) deallocate(sieve_table) if (n .lt. 1) return allocate(sieve_table(n), stat=status) if (status .ne. 0) stop 'cannot allocate space' sieve_table(1) = 1 do i=2,int(sqrt(real(n)))+1 if (sieve_table(i) .eq. 0) then do j = i*i, n, i sieve_table(j) = i end do end if end do end subroutine sieve subroutine check_sieve(n) integer, intent(in) :: n if (.not. (allocated(sieve_table) .and. ((1 .le. n) .and. (n .le. size(sieve_table))))) stop 'Call sieve first' end subroutine check_sieve logical function isPrime(p) integer, intent(in) :: p call check_sieve(p) isPrime = PrimeQ(p) end function isPrime logical function isComposite(p) integer, intent(in) :: p isComposite = .not. isPrime(p) end function isComposite logical function PrimeQ(p) integer, intent(in) :: p PrimeQ = sieve_table(p) .eq. 0 end function PrimeQ subroutine prime_factors(p, rv, n) integer, intent(in) :: p integer, dimension(:), intent(out) :: rv integer, intent(out) :: n integer :: i, m call check_sieve(p) m = p i = 1 if (p .ne. 1) then do while ((.not. PrimeQ(m)) .and. (i .lt. size(rv))) rv(i) = sieve_table(m) m = m/rv(i) i = i+1 end do end if if (i .le. size(rv)) rv(i) = m n = i end subroutine prime_factors end module prime_mod program count_in_factors use prime_mod integer :: i, n integer, dimension(8) :: factors call sieve(40) do i=1,40 factors = 0 call prime_factors(i, factors, n) write(6,*)'assert',i,'= */',factors(:n) end do call sieve(0) end program count_in_factors
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Write the same algorithm in VB as shown in this Fortran implementation.
module prime_mod integer, dimension(:), allocatable :: sieve_table private :: PrimeQ contains subroutine sieve(n) integer, intent(in) :: n integer :: status, i, j if ((n .lt. 1) .or. allocated(sieve_table)) deallocate(sieve_table) if (n .lt. 1) return allocate(sieve_table(n), stat=status) if (status .ne. 0) stop 'cannot allocate space' sieve_table(1) = 1 do i=2,int(sqrt(real(n)))+1 if (sieve_table(i) .eq. 0) then do j = i*i, n, i sieve_table(j) = i end do end if end do end subroutine sieve subroutine check_sieve(n) integer, intent(in) :: n if (.not. (allocated(sieve_table) .and. ((1 .le. n) .and. (n .le. size(sieve_table))))) stop 'Call sieve first' end subroutine check_sieve logical function isPrime(p) integer, intent(in) :: p call check_sieve(p) isPrime = PrimeQ(p) end function isPrime logical function isComposite(p) integer, intent(in) :: p isComposite = .not. isPrime(p) end function isComposite logical function PrimeQ(p) integer, intent(in) :: p PrimeQ = sieve_table(p) .eq. 0 end function PrimeQ subroutine prime_factors(p, rv, n) integer, intent(in) :: p integer, dimension(:), intent(out) :: rv integer, intent(out) :: n integer :: i, m call check_sieve(p) m = p i = 1 if (p .ne. 1) then do while ((.not. PrimeQ(m)) .and. (i .lt. size(rv))) rv(i) = sieve_table(m) m = m/rv(i) i = i+1 end do end if if (i .le. size(rv)) rv(i) = m n = i end subroutine prime_factors end module prime_mod program count_in_factors use prime_mod integer :: i, n integer, dimension(8) :: factors call sieve(40) do i=1,40 factors = 0 call prime_factors(i, factors, n) write(6,*)'assert',i,'= */',factors(:n) end do call sieve(0) end program count_in_factors
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Please provide an equivalent version of this Groovy code in C.
def factors(number) { if (number == 1) { return [1] } def factors = [] BigInteger value = number BigInteger possibleFactor = 2 while (possibleFactor <= value) { if (value % possibleFactor == 0) { factors << possibleFactor value /= possibleFactor } else { possibleFactor++ } } factors } Number.metaClass.factors = { factors(delegate) } ((1..10) + (6351..6359)).each { number -> println "$number = ${number.factors().join(' x ')}" }
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Produce a language-to-language conversion: from Groovy to C#, same semantics.
def factors(number) { if (number == 1) { return [1] } def factors = [] BigInteger value = number BigInteger possibleFactor = 2 while (possibleFactor <= value) { if (value % possibleFactor == 0) { factors << possibleFactor value /= possibleFactor } else { possibleFactor++ } } factors } Number.metaClass.factors = { factors(delegate) } ((1..10) + (6351..6359)).each { number -> println "$number = ${number.factors().join(' x ')}" }
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Produce a functionally identical C++ code for the snippet given in Groovy.
def factors(number) { if (number == 1) { return [1] } def factors = [] BigInteger value = number BigInteger possibleFactor = 2 while (possibleFactor <= value) { if (value % possibleFactor == 0) { factors << possibleFactor value /= possibleFactor } else { possibleFactor++ } } factors } Number.metaClass.factors = { factors(delegate) } ((1..10) + (6351..6359)).each { number -> println "$number = ${number.factors().join(' x ')}" }
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Translate the given Groovy code snippet into Java without altering its behavior.
def factors(number) { if (number == 1) { return [1] } def factors = [] BigInteger value = number BigInteger possibleFactor = 2 while (possibleFactor <= value) { if (value % possibleFactor == 0) { factors << possibleFactor value /= possibleFactor } else { possibleFactor++ } } factors } Number.metaClass.factors = { factors(delegate) } ((1..10) + (6351..6359)).each { number -> println "$number = ${number.factors().join(' x ')}" }
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Generate a Python translation of this Groovy snippet without changing its computational steps.
def factors(number) { if (number == 1) { return [1] } def factors = [] BigInteger value = number BigInteger possibleFactor = 2 while (possibleFactor <= value) { if (value % possibleFactor == 0) { factors << possibleFactor value /= possibleFactor } else { possibleFactor++ } } factors } Number.metaClass.factors = { factors(delegate) } ((1..10) + (6351..6359)).each { number -> println "$number = ${number.factors().join(' x ')}" }
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Translate this program into VB but keep the logic exactly as in Groovy.
def factors(number) { if (number == 1) { return [1] } def factors = [] BigInteger value = number BigInteger possibleFactor = 2 while (possibleFactor <= value) { if (value % possibleFactor == 0) { factors << possibleFactor value /= possibleFactor } else { possibleFactor++ } } factors } Number.metaClass.factors = { factors(delegate) } ((1..10) + (6351..6359)).each { number -> println "$number = ${number.factors().join(' x ')}" }
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Translate the given Groovy code snippet into Go without altering its behavior.
def factors(number) { if (number == 1) { return [1] } def factors = [] BigInteger value = number BigInteger possibleFactor = 2 while (possibleFactor <= value) { if (value % possibleFactor == 0) { factors << possibleFactor value /= possibleFactor } else { possibleFactor++ } } factors } Number.metaClass.factors = { factors(delegate) } ((1..10) + (6351..6359)).each { number -> println "$number = ${number.factors().join(' x ')}" }
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Please provide an equivalent version of this Haskell code in C.
import Data.List (intercalate) showFactors n = show n ++ " = " ++ (intercalate " * " . map show . factorize) n showFactors = ((++) . show) <*> ((" = " ++) . intercalate " * " . map show . factorize)
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Port the following code from Haskell to C# with equivalent syntax and logic.
import Data.List (intercalate) showFactors n = show n ++ " = " ++ (intercalate " * " . map show . factorize) n showFactors = ((++) . show) <*> ((" = " ++) . intercalate " * " . map show . factorize)
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Produce a functionally identical C++ code for the snippet given in Haskell.
import Data.List (intercalate) showFactors n = show n ++ " = " ++ (intercalate " * " . map show . factorize) n showFactors = ((++) . show) <*> ((" = " ++) . intercalate " * " . map show . factorize)
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Produce a functionally identical Java code for the snippet given in Haskell.
import Data.List (intercalate) showFactors n = show n ++ " = " ++ (intercalate " * " . map show . factorize) n showFactors = ((++) . show) <*> ((" = " ++) . intercalate " * " . map show . factorize)
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Produce a language-to-language conversion: from Haskell to Python, same semantics.
import Data.List (intercalate) showFactors n = show n ++ " = " ++ (intercalate " * " . map show . factorize) n showFactors = ((++) . show) <*> ((" = " ++) . intercalate " * " . map show . factorize)
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Port the provided Haskell code into VB while preserving the original functionality.
import Data.List (intercalate) showFactors n = show n ++ " = " ++ (intercalate " * " . map show . factorize) n showFactors = ((++) . show) <*> ((" = " ++) . intercalate " * " . map show . factorize)
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Write a version of this Haskell function in Go with identical behavior.
import Data.List (intercalate) showFactors n = show n ++ " = " ++ (intercalate " * " . map show . factorize) n showFactors = ((++) . show) <*> ((" = " ++) . intercalate " * " . map show . factorize)
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Translate this program into C but keep the logic exactly as in Icon.
procedure main() write("Press ^C to terminate") every f := [i:= 1] | factors(i := seq(2)) do { writes(i," : [") every writes(" ",!f|"]\n") } end link factors
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Can you help me rewrite this code in C# instead of Icon, keeping it the same logically?
procedure main() write("Press ^C to terminate") every f := [i:= 1] | factors(i := seq(2)) do { writes(i," : [") every writes(" ",!f|"]\n") } end link factors
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Change the programming language of this snippet from Icon to C++ without modifying what it does.
procedure main() write("Press ^C to terminate") every f := [i:= 1] | factors(i := seq(2)) do { writes(i," : [") every writes(" ",!f|"]\n") } end link factors
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Translate the given Icon code snippet into Java without altering its behavior.
procedure main() write("Press ^C to terminate") every f := [i:= 1] | factors(i := seq(2)) do { writes(i," : [") every writes(" ",!f|"]\n") } end link factors
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Keep all operations the same but rewrite the snippet in Python.
procedure main() write("Press ^C to terminate") every f := [i:= 1] | factors(i := seq(2)) do { writes(i," : [") every writes(" ",!f|"]\n") } end link factors
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Write the same algorithm in VB as shown in this Icon implementation.
procedure main() write("Press ^C to terminate") every f := [i:= 1] | factors(i := seq(2)) do { writes(i," : [") every writes(" ",!f|"]\n") } end link factors
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Port the following code from Icon to Go with equivalent syntax and logic.
procedure main() write("Press ^C to terminate") every f := [i:= 1] | factors(i := seq(2)) do { writes(i," : [") every writes(" ",!f|"]\n") } end link factors
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Change the programming language of this snippet from J to C without modifying what it does.
q:
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Write the same code in C# as shown below in J.
q:
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Transform the following J implementation into C++, maintaining the same output and logic.
q:
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Preserve the algorithm and functionality while converting the code from J to Java.
q:
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Port the following code from J to Python with equivalent syntax and logic.
q:
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Produce a language-to-language conversion: from J to VB, same semantics.
q:
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Generate a Go translation of this J snippet without changing its computational steps.
q:
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Preserve the algorithm and functionality while converting the code from Julia to C.
using Primes, Printf function strfactor(n::Integer) n > -2 || return "-1 × " * strfactor(-n) isprime(n) || n < 2 && return dec(n) f = factor(Vector{typeof(n)}, n) return join(f, " × ") end lo, hi = -4, 40 println("Factor print $lo to $hi:") for n in lo:hi @printf("%5d = %s\n", n, strfactor(n)) end
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Port the provided Julia code into C# while preserving the original functionality.
using Primes, Printf function strfactor(n::Integer) n > -2 || return "-1 × " * strfactor(-n) isprime(n) || n < 2 && return dec(n) f = factor(Vector{typeof(n)}, n) return join(f, " × ") end lo, hi = -4, 40 println("Factor print $lo to $hi:") for n in lo:hi @printf("%5d = %s\n", n, strfactor(n)) end
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Convert the following code from Julia to C++, ensuring the logic remains intact.
using Primes, Printf function strfactor(n::Integer) n > -2 || return "-1 × " * strfactor(-n) isprime(n) || n < 2 && return dec(n) f = factor(Vector{typeof(n)}, n) return join(f, " × ") end lo, hi = -4, 40 println("Factor print $lo to $hi:") for n in lo:hi @printf("%5d = %s\n", n, strfactor(n)) end
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Generate an equivalent Java version of this Julia code.
using Primes, Printf function strfactor(n::Integer) n > -2 || return "-1 × " * strfactor(-n) isprime(n) || n < 2 && return dec(n) f = factor(Vector{typeof(n)}, n) return join(f, " × ") end lo, hi = -4, 40 println("Factor print $lo to $hi:") for n in lo:hi @printf("%5d = %s\n", n, strfactor(n)) end
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Rewrite this program in Python while keeping its functionality equivalent to the Julia version.
using Primes, Printf function strfactor(n::Integer) n > -2 || return "-1 × " * strfactor(-n) isprime(n) || n < 2 && return dec(n) f = factor(Vector{typeof(n)}, n) return join(f, " × ") end lo, hi = -4, 40 println("Factor print $lo to $hi:") for n in lo:hi @printf("%5d = %s\n", n, strfactor(n)) end
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Convert this Julia block to VB, preserving its control flow and logic.
using Primes, Printf function strfactor(n::Integer) n > -2 || return "-1 × " * strfactor(-n) isprime(n) || n < 2 && return dec(n) f = factor(Vector{typeof(n)}, n) return join(f, " × ") end lo, hi = -4, 40 println("Factor print $lo to $hi:") for n in lo:hi @printf("%5d = %s\n", n, strfactor(n)) end
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Write a version of this Julia function in Go with identical behavior.
using Primes, Printf function strfactor(n::Integer) n > -2 || return "-1 × " * strfactor(-n) isprime(n) || n < 2 && return dec(n) f = factor(Vector{typeof(n)}, n) return join(f, " × ") end lo, hi = -4, 40 println("Factor print $lo to $hi:") for n in lo:hi @printf("%5d = %s\n", n, strfactor(n)) end
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Produce a functionally identical C code for the snippet given in Lua.
function factorize( n ) if n == 1 then return {1} end local k = 2 res = {} while n > 1 do while n % k == 0 do res[#res+1] = k n = n / k end k = k + 1 end return res end for i = 1, 22 do io.write( i, ": " ) fac = factorize( i ) io.write( fac[1] ) for j = 2, #fac do io.write( " * ", fac[j] ) end print "" end
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Keep all operations the same but rewrite the snippet in C#.
function factorize( n ) if n == 1 then return {1} end local k = 2 res = {} while n > 1 do while n % k == 0 do res[#res+1] = k n = n / k end k = k + 1 end return res end for i = 1, 22 do io.write( i, ": " ) fac = factorize( i ) io.write( fac[1] ) for j = 2, #fac do io.write( " * ", fac[j] ) end print "" end
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Maintain the same structure and functionality when rewriting this code in C++.
function factorize( n ) if n == 1 then return {1} end local k = 2 res = {} while n > 1 do while n % k == 0 do res[#res+1] = k n = n / k end k = k + 1 end return res end for i = 1, 22 do io.write( i, ": " ) fac = factorize( i ) io.write( fac[1] ) for j = 2, #fac do io.write( " * ", fac[j] ) end print "" end
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Convert this Lua snippet to Java and keep its semantics consistent.
function factorize( n ) if n == 1 then return {1} end local k = 2 res = {} while n > 1 do while n % k == 0 do res[#res+1] = k n = n / k end k = k + 1 end return res end for i = 1, 22 do io.write( i, ": " ) fac = factorize( i ) io.write( fac[1] ) for j = 2, #fac do io.write( " * ", fac[j] ) end print "" end
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Preserve the algorithm and functionality while converting the code from Lua to Python.
function factorize( n ) if n == 1 then return {1} end local k = 2 res = {} while n > 1 do while n % k == 0 do res[#res+1] = k n = n / k end k = k + 1 end return res end for i = 1, 22 do io.write( i, ": " ) fac = factorize( i ) io.write( fac[1] ) for j = 2, #fac do io.write( " * ", fac[j] ) end print "" end
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Produce a functionally identical VB code for the snippet given in Lua.
function factorize( n ) if n == 1 then return {1} end local k = 2 res = {} while n > 1 do while n % k == 0 do res[#res+1] = k n = n / k end k = k + 1 end return res end for i = 1, 22 do io.write( i, ": " ) fac = factorize( i ) io.write( fac[1] ) for j = 2, #fac do io.write( " * ", fac[j] ) end print "" end
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Write the same algorithm in Go as shown in this Lua implementation.
function factorize( n ) if n == 1 then return {1} end local k = 2 res = {} while n > 1 do while n % k == 0 do res[#res+1] = k n = n / k end k = k + 1 end return res end for i = 1, 22 do io.write( i, ": " ) fac = factorize( i ) io.write( fac[1] ) for j = 2, #fac do io.write( " * ", fac[j] ) end print "" end
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Translate the given Mathematica code snippet into C without altering its behavior.
n = 2; While[n < 100, Print[Row[Riffle[Flatten[Map[Apply[ConstantArray, #] &, FactorInteger[n]]],"*"]]]; n++]
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Transform the following Mathematica implementation into C#, maintaining the same output and logic.
n = 2; While[n < 100, Print[Row[Riffle[Flatten[Map[Apply[ConstantArray, #] &, FactorInteger[n]]],"*"]]]; n++]
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Maintain the same structure and functionality when rewriting this code in C++.
n = 2; While[n < 100, Print[Row[Riffle[Flatten[Map[Apply[ConstantArray, #] &, FactorInteger[n]]],"*"]]]; n++]
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Produce a functionally identical Java code for the snippet given in Mathematica.
n = 2; While[n < 100, Print[Row[Riffle[Flatten[Map[Apply[ConstantArray, #] &, FactorInteger[n]]],"*"]]]; n++]
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Port the following code from Mathematica to Python with equivalent syntax and logic.
n = 2; While[n < 100, Print[Row[Riffle[Flatten[Map[Apply[ConstantArray, #] &, FactorInteger[n]]],"*"]]]; n++]
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Translate the given Mathematica code snippet into VB without altering its behavior.
n = 2; While[n < 100, Print[Row[Riffle[Flatten[Map[Apply[ConstantArray, #] &, FactorInteger[n]]],"*"]]]; n++]
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Generate an equivalent Go version of this Mathematica code.
n = 2; While[n < 100, Print[Row[Riffle[Flatten[Map[Apply[ConstantArray, #] &, FactorInteger[n]]],"*"]]]; n++]
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Convert this Nim block to C, preserving its control flow and logic.
var primes = newSeq[int]() proc getPrime(idx: int): int = if idx >= primes.len: if primes.len == 0: primes.add 2 primes.add 3 var last = primes[primes.high] while idx >= primes.len: last += 2 for i, p in primes: if p * p > last: primes.add last break if last mod p == 0: break return primes[idx] for x in 1 ..< int32.high.int: stdout.write x, " = " var n = x var first = true for i in 0 ..< int32.high: let p = getPrime(i) while n mod p == 0: n = n div p if not first: stdout.write " x " first = false stdout.write p if n <= p * p: break if first > 0: echo n elif n > 1: echo " x ", n else: echo ""
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Please provide an equivalent version of this Nim code in C#.
var primes = newSeq[int]() proc getPrime(idx: int): int = if idx >= primes.len: if primes.len == 0: primes.add 2 primes.add 3 var last = primes[primes.high] while idx >= primes.len: last += 2 for i, p in primes: if p * p > last: primes.add last break if last mod p == 0: break return primes[idx] for x in 1 ..< int32.high.int: stdout.write x, " = " var n = x var first = true for i in 0 ..< int32.high: let p = getPrime(i) while n mod p == 0: n = n div p if not first: stdout.write " x " first = false stdout.write p if n <= p * p: break if first > 0: echo n elif n > 1: echo " x ", n else: echo ""
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Translate this program into C++ but keep the logic exactly as in Nim.
var primes = newSeq[int]() proc getPrime(idx: int): int = if idx >= primes.len: if primes.len == 0: primes.add 2 primes.add 3 var last = primes[primes.high] while idx >= primes.len: last += 2 for i, p in primes: if p * p > last: primes.add last break if last mod p == 0: break return primes[idx] for x in 1 ..< int32.high.int: stdout.write x, " = " var n = x var first = true for i in 0 ..< int32.high: let p = getPrime(i) while n mod p == 0: n = n div p if not first: stdout.write " x " first = false stdout.write p if n <= p * p: break if first > 0: echo n elif n > 1: echo " x ", n else: echo ""
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Produce a language-to-language conversion: from Nim to Java, same semantics.
var primes = newSeq[int]() proc getPrime(idx: int): int = if idx >= primes.len: if primes.len == 0: primes.add 2 primes.add 3 var last = primes[primes.high] while idx >= primes.len: last += 2 for i, p in primes: if p * p > last: primes.add last break if last mod p == 0: break return primes[idx] for x in 1 ..< int32.high.int: stdout.write x, " = " var n = x var first = true for i in 0 ..< int32.high: let p = getPrime(i) while n mod p == 0: n = n div p if not first: stdout.write " x " first = false stdout.write p if n <= p * p: break if first > 0: echo n elif n > 1: echo " x ", n else: echo ""
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Can you help me rewrite this code in Python instead of Nim, keeping it the same logically?
var primes = newSeq[int]() proc getPrime(idx: int): int = if idx >= primes.len: if primes.len == 0: primes.add 2 primes.add 3 var last = primes[primes.high] while idx >= primes.len: last += 2 for i, p in primes: if p * p > last: primes.add last break if last mod p == 0: break return primes[idx] for x in 1 ..< int32.high.int: stdout.write x, " = " var n = x var first = true for i in 0 ..< int32.high: let p = getPrime(i) while n mod p == 0: n = n div p if not first: stdout.write " x " first = false stdout.write p if n <= p * p: break if first > 0: echo n elif n > 1: echo " x ", n else: echo ""
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Write a version of this Nim function in VB with identical behavior.
var primes = newSeq[int]() proc getPrime(idx: int): int = if idx >= primes.len: if primes.len == 0: primes.add 2 primes.add 3 var last = primes[primes.high] while idx >= primes.len: last += 2 for i, p in primes: if p * p > last: primes.add last break if last mod p == 0: break return primes[idx] for x in 1 ..< int32.high.int: stdout.write x, " = " var n = x var first = true for i in 0 ..< int32.high: let p = getPrime(i) while n mod p == 0: n = n div p if not first: stdout.write " x " first = false stdout.write p if n <= p * p: break if first > 0: echo n elif n > 1: echo " x ", n else: echo ""
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Write a version of this Nim function in Go with identical behavior.
var primes = newSeq[int]() proc getPrime(idx: int): int = if idx >= primes.len: if primes.len == 0: primes.add 2 primes.add 3 var last = primes[primes.high] while idx >= primes.len: last += 2 for i, p in primes: if p * p > last: primes.add last break if last mod p == 0: break return primes[idx] for x in 1 ..< int32.high.int: stdout.write x, " = " var n = x var first = true for i in 0 ..< int32.high: let p = getPrime(i) while n mod p == 0: n = n div p if not first: stdout.write " x " first = false stdout.write p if n <= p * p: break if first > 0: echo n elif n > 1: echo " x ", n else: echo ""
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Port the following code from OCaml to C with equivalent syntax and logic.
open Big_int let prime_decomposition x = let rec inner c p = if lt_big_int p (square_big_int c) then [p] else if eq_big_int (mod_big_int p c) zero_big_int then c :: inner c (div_big_int p c) else inner (succ_big_int c) p in inner (succ_big_int (succ_big_int zero_big_int)) x let () = let rec aux v = let ps = prime_decomposition v in print_string (string_of_big_int v); print_string " = "; print_endline (String.concat " x " (List.map string_of_big_int ps)); aux (succ_big_int v) in aux unit_big_int
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Rewrite this program in C# while keeping its functionality equivalent to the OCaml version.
open Big_int let prime_decomposition x = let rec inner c p = if lt_big_int p (square_big_int c) then [p] else if eq_big_int (mod_big_int p c) zero_big_int then c :: inner c (div_big_int p c) else inner (succ_big_int c) p in inner (succ_big_int (succ_big_int zero_big_int)) x let () = let rec aux v = let ps = prime_decomposition v in print_string (string_of_big_int v); print_string " = "; print_endline (String.concat " x " (List.map string_of_big_int ps)); aux (succ_big_int v) in aux unit_big_int
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }
Keep all operations the same but rewrite the snippet in C++.
open Big_int let prime_decomposition x = let rec inner c p = if lt_big_int p (square_big_int c) then [p] else if eq_big_int (mod_big_int p c) zero_big_int then c :: inner c (div_big_int p c) else inner (succ_big_int c) p in inner (succ_big_int (succ_big_int zero_big_int)) x let () = let rec aux v = let ps = prime_decomposition v in print_string (string_of_big_int v); print_string " = "; print_endline (String.concat " x " (List.map string_of_big_int ps)); aux (succ_big_int v) in aux unit_big_int
#include <iostream> #include <iomanip> using namespace std; void getPrimeFactors( int li ) { int f = 2; string res; if ( li == 1 ) res = "1"; else { while ( true ) { if( !( li % f ) ) { res += to_string(f); li /= f; if( li == 1 ) break; res += " x "; } else f++; } } cout << res << "\n"; } int main( int argc, char* argv[] ) { for ( int x = 1; x < 101; x++ ) { cout << right << setw( 4 ) << x << ": "; getPrimeFactors( x ); } cout << 2144 << ": "; getPrimeFactors( 2144 ); cout << "\n\n"; return system( "pause" ); }
Preserve the algorithm and functionality while converting the code from OCaml to Java.
open Big_int let prime_decomposition x = let rec inner c p = if lt_big_int p (square_big_int c) then [p] else if eq_big_int (mod_big_int p c) zero_big_int then c :: inner c (div_big_int p c) else inner (succ_big_int c) p in inner (succ_big_int (succ_big_int zero_big_int)) x let () = let rec aux v = let ps = prime_decomposition v in print_string (string_of_big_int v); print_string " = "; print_endline (String.concat " x " (List.map string_of_big_int ps)); aux (succ_big_int v) in aux unit_big_int
public class CountingInFactors{ public static void main(String[] args){ for(int i = 1; i<= 10; i++){ System.out.println(i + " = "+ countInFactors(i)); } for(int i = 9991; i <= 10000; i++){ System.out.println(i + " = "+ countInFactors(i)); } } private static String countInFactors(int n){ if(n == 1) return "1"; StringBuilder sb = new StringBuilder(); n = checkFactor(2, n, sb); if(n == 1) return sb.toString(); n = checkFactor(3, n, sb); if(n == 1) return sb.toString(); for(int i = 5; i <= n; i+= 2){ if(i % 3 == 0)continue; n = checkFactor(i, n, sb); if(n == 1)break; } return sb.toString(); } private static int checkFactor(int mult, int n, StringBuilder sb){ while(n % mult == 0 ){ if(sb.length() > 0) sb.append(" x "); sb.append(mult); n /= mult; } return n; } }
Transform the following OCaml implementation into Python, maintaining the same output and logic.
open Big_int let prime_decomposition x = let rec inner c p = if lt_big_int p (square_big_int c) then [p] else if eq_big_int (mod_big_int p c) zero_big_int then c :: inner c (div_big_int p c) else inner (succ_big_int c) p in inner (succ_big_int (succ_big_int zero_big_int)) x let () = let rec aux v = let ps = prime_decomposition v in print_string (string_of_big_int v); print_string " = "; print_endline (String.concat " x " (List.map string_of_big_int ps)); aux (succ_big_int v) in aux unit_big_int
from functools import lru_cache primes = [2, 3, 5, 7, 11, 13, 17] @lru_cache(maxsize=2000) def pfactor(n): if n == 1: return [1] n2 = n // 2 + 1 for p in primes: if p <= n2: d, m = divmod(n, p) if m == 0: if d > 1: return [p] + pfactor(d) else: return [p] else: if n > primes[-1]: primes.append(n) return [n] if __name__ == '__main__': mx = 5000 for n in range(1, mx + 1): factors = pfactor(n) if n <= 10 or n >= mx - 20: print( '%4i %5s %s' % (n, '' if factors != [n] or n == 1 else 'prime', 'x'.join(str(i) for i in factors)) ) if n == 11: print('...') print('\nNumber of primes gathered up to', n, 'is', len(primes)) print(pfactor.cache_info())
Generate an equivalent VB version of this OCaml code.
open Big_int let prime_decomposition x = let rec inner c p = if lt_big_int p (square_big_int c) then [p] else if eq_big_int (mod_big_int p c) zero_big_int then c :: inner c (div_big_int p c) else inner (succ_big_int c) p in inner (succ_big_int (succ_big_int zero_big_int)) x let () = let rec aux v = let ps = prime_decomposition v in print_string (string_of_big_int v); print_string " = "; print_endline (String.concat " x " (List.map string_of_big_int ps)); aux (succ_big_int v) in aux unit_big_int
Function CountFactors(n) If n = 1 Then CountFactors = 1 Else arrP = Split(ListPrimes(n)," ") Set arrList = CreateObject("System.Collections.ArrayList") divnum = n Do Until divnum = 1 For i = 0 To UBound(arrP)-1 If divnum = 1 Then Exit For ElseIf divnum Mod arrP(i) = 0 Then divnum = divnum/arrP(i) arrList.Add arrP(i) End If Next Loop arrList.Sort For i = 0 To arrList.Count - 1 If i = arrList.Count - 1 Then CountFactors = CountFactors & arrList(i) Else CountFactors = CountFactors & arrList(i) & " * " End If Next End If End Function Function IsPrime(n) If n = 2 Then IsPrime = True ElseIf n <= 1 Or n Mod 2 = 0 Then IsPrime = False Else IsPrime = True For i = 3 To Int(Sqr(n)) Step 2 If n Mod i = 0 Then IsPrime = False Exit For End If Next End If End Function Function ListPrimes(n) ListPrimes = "" For i = 1 To n If IsPrime(i) Then ListPrimes = ListPrimes & i & " " End If Next End Function WScript.StdOut.Write "2 = " & CountFactors(2) WScript.StdOut.WriteLine WScript.StdOut.Write "2144 = " & CountFactors(2144) WScript.StdOut.WriteLine
Convert this OCaml snippet to Go and keep its semantics consistent.
open Big_int let prime_decomposition x = let rec inner c p = if lt_big_int p (square_big_int c) then [p] else if eq_big_int (mod_big_int p c) zero_big_int then c :: inner c (div_big_int p c) else inner (succ_big_int c) p in inner (succ_big_int (succ_big_int zero_big_int)) x let () = let rec aux v = let ps = prime_decomposition v in print_string (string_of_big_int v); print_string " = "; print_endline (String.concat " x " (List.map string_of_big_int ps)); aux (succ_big_int v) in aux unit_big_int
package main import "fmt" func main() { fmt.Println("1: 1") for i := 2; ; i++ { fmt.Printf("%d: ", i) var x string for n, f := i, 2; n != 1; f++ { for m := n % f; m == 0; m = n % f { fmt.Print(x, f) x = "×" n /= f } } fmt.Println() } }
Port the following code from Pascal to C with equivalent syntax and logic.
program CountInFactors(output); type TdynArray = array of integer; function factorize(number: integer): TdynArray; var k: integer; begin if number = 1 then begin setlength(Result, 1); Result[0] := 1 end else begin k := 2; while number > 1 do begin while number mod k = 0 do begin setlength(Result, length(Result) + 1); Result[high(Result)] := k; number := number div k; end; inc(k); end; end end; var i, j: integer; fac: TdynArray; begin for i := 1 to 22 do begin write(i, ': ' ); fac := factorize(i); write(fac[0]); for j := 1 to high(fac) do write(' * ', fac[j]); writeln; end; end.
#include <stdio.h> #include <stdlib.h> typedef unsigned long long ULONG; ULONG get_prime(int idx) { static long n_primes = 0, alloc = 0; static ULONG *primes = 0; ULONG last, p; int i; if (idx >= n_primes) { if (n_primes >= alloc) { alloc += 16; primes = realloc(primes, sizeof(ULONG) * alloc); } if (!n_primes) { primes[0] = 2; primes[1] = 3; n_primes = 2; } last = primes[n_primes-1]; while (idx >= n_primes) { last += 2; for (i = 0; i < n_primes; i++) { p = primes[i]; if (p * p > last) { primes[n_primes++] = last; break; } if (last % p == 0) break; } } } return primes[idx]; } int main() { ULONG n, x, p; int i, first; for (x = 1; ; x++) { printf("%lld = ", n = x); for (i = 0, first = 1; ; i++) { p = get_prime(i); while (n % p == 0) { n /= p; if (!first) printf(" x "); first = 0; printf("%lld", p); } if (n <= p * p) break; } if (first) printf("%lld\n", n); else if (n > 1) printf(" x %lld\n", n); else printf("\n"); } return 0; }
Please provide an equivalent version of this Pascal code in C#.
program CountInFactors(output); type TdynArray = array of integer; function factorize(number: integer): TdynArray; var k: integer; begin if number = 1 then begin setlength(Result, 1); Result[0] := 1 end else begin k := 2; while number > 1 do begin while number mod k = 0 do begin setlength(Result, length(Result) + 1); Result[high(Result)] := k; number := number div k; end; inc(k); end; end end; var i, j: integer; fac: TdynArray; begin for i := 1 to 22 do begin write(i, ': ' ); fac := factorize(i); write(fac[0]); for j := 1 to high(fac) do write(' * ', fac[j]); writeln; end; end.
using System; using System.Collections.Generic; namespace prog { class MainClass { public static void Main (string[] args) { for( int i=1; i<=22; i++ ) { List<int> f = Factorize(i); Console.Write( i + ": " + f[0] ); for( int j=1; j<f.Count; j++ ) { Console.Write( " * " + f[j] ); } Console.WriteLine(); } } public static List<int> Factorize( int n ) { List<int> l = new List<int>(); if ( n == 1 ) { l.Add(1); } else { int k = 2; while( n > 1 ) { while( n % k == 0 ) { l.Add( k ); n /= k; } k++; } } return l; } } }