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Write the same algorithm in Go as shown in this AutoHotKey implementation.
for_J(doFunction, start, stop, step:=1){ j := start while (j<=stop) && (start<=stop) && (step>0) %doFunction%(j), j+=step while (j>=stop) && (start>stop) && (step<0) %doFunction%(j), j+=step }
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Can you help me rewrite this code in C instead of AWK, keeping it the same logically?
BEGIN { prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 for (j=-three; j<=(3^3); j+=three) { main(j) } for (j=-seven; j<=seven; j+=x) { main(j) } for (j=555; j<=550-y; j++) { main(j) } for (j=22; j>=-28; j+=-three) { main(j) } for (j=1927; j<=1939; j++) { main(j) } for (j=x; j>=y; j+=z) { main(j) } for (j=(11^x); j<=(11^x)+1; j++) { main(j) } printf("sum = %d\n",sum) printf("prod = %d\n",prod) exit(0) } function main(x) { sum += abs(x) if (abs(prod) < (2^27) && x != 0) { prod *= x } } function abs(x) { if (x >= 0) { return x } else { return -x } }
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Maintain the same structure and functionality when rewriting this code in C#.
BEGIN { prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 for (j=-three; j<=(3^3); j+=three) { main(j) } for (j=-seven; j<=seven; j+=x) { main(j) } for (j=555; j<=550-y; j++) { main(j) } for (j=22; j>=-28; j+=-three) { main(j) } for (j=1927; j<=1939; j++) { main(j) } for (j=x; j>=y; j+=z) { main(j) } for (j=(11^x); j<=(11^x)+1; j++) { main(j) } printf("sum = %d\n",sum) printf("prod = %d\n",prod) exit(0) } function main(x) { sum += abs(x) if (abs(prod) < (2^27) && x != 0) { prod *= x } } function abs(x) { if (x >= 0) { return x } else { return -x } }
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Can you help me rewrite this code in C++ instead of AWK, keeping it the same logically?
BEGIN { prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 for (j=-three; j<=(3^3); j+=three) { main(j) } for (j=-seven; j<=seven; j+=x) { main(j) } for (j=555; j<=550-y; j++) { main(j) } for (j=22; j>=-28; j+=-three) { main(j) } for (j=1927; j<=1939; j++) { main(j) } for (j=x; j>=y; j+=z) { main(j) } for (j=(11^x); j<=(11^x)+1; j++) { main(j) } printf("sum = %d\n",sum) printf("prod = %d\n",prod) exit(0) } function main(x) { sum += abs(x) if (abs(prod) < (2^27) && x != 0) { prod *= x } } function abs(x) { if (x >= 0) { return x } else { return -x } }
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Port the provided AWK code into Java while preserving the original functionality.
BEGIN { prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 for (j=-three; j<=(3^3); j+=three) { main(j) } for (j=-seven; j<=seven; j+=x) { main(j) } for (j=555; j<=550-y; j++) { main(j) } for (j=22; j>=-28; j+=-three) { main(j) } for (j=1927; j<=1939; j++) { main(j) } for (j=x; j>=y; j+=z) { main(j) } for (j=(11^x); j<=(11^x)+1; j++) { main(j) } printf("sum = %d\n",sum) printf("prod = %d\n",prod) exit(0) } function main(x) { sum += abs(x) if (abs(prod) < (2^27) && x != 0) { prod *= x } } function abs(x) { if (x >= 0) { return x } else { return -x } }
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Change the following AWK code into Python without altering its purpose.
BEGIN { prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 for (j=-three; j<=(3^3); j+=three) { main(j) } for (j=-seven; j<=seven; j+=x) { main(j) } for (j=555; j<=550-y; j++) { main(j) } for (j=22; j>=-28; j+=-three) { main(j) } for (j=1927; j<=1939; j++) { main(j) } for (j=x; j>=y; j+=z) { main(j) } for (j=(11^x); j<=(11^x)+1; j++) { main(j) } printf("sum = %d\n",sum) printf("prod = %d\n",prod) exit(0) } function main(x) { sum += abs(x) if (abs(prod) < (2^27) && x != 0) { prod *= x } } function abs(x) { if (x >= 0) { return x } else { return -x } }
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Write a version of this AWK function in VB with identical behavior.
BEGIN { prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 for (j=-three; j<=(3^3); j+=three) { main(j) } for (j=-seven; j<=seven; j+=x) { main(j) } for (j=555; j<=550-y; j++) { main(j) } for (j=22; j>=-28; j+=-three) { main(j) } for (j=1927; j<=1939; j++) { main(j) } for (j=x; j>=y; j+=z) { main(j) } for (j=(11^x); j<=(11^x)+1; j++) { main(j) } printf("sum = %d\n",sum) printf("prod = %d\n",prod) exit(0) } function main(x) { sum += abs(x) if (abs(prod) < (2^27) && x != 0) { prod *= x } } function abs(x) { if (x >= 0) { return x } else { return -x } }
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Change the following AWK code into Go without altering its purpose.
BEGIN { prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 for (j=-three; j<=(3^3); j+=three) { main(j) } for (j=-seven; j<=seven; j+=x) { main(j) } for (j=555; j<=550-y; j++) { main(j) } for (j=22; j>=-28; j+=-three) { main(j) } for (j=1927; j<=1939; j++) { main(j) } for (j=x; j>=y; j+=z) { main(j) } for (j=(11^x); j<=(11^x)+1; j++) { main(j) } printf("sum = %d\n",sum) printf("prod = %d\n",prod) exit(0) } function main(x) { sum += abs(x) if (abs(prod) < (2^27) && x != 0) { prod *= x } } function abs(x) { if (x >= 0) { return x } else { return -x } }
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Write a version of this Common_Lisp function in C with identical behavior.
(let ((prod 1) (sum 0) (x 5) (y -5) (z -2) (one 1) (three 3) (seven 7)) (flet ((loop-body (j) (incf sum (abs j)) (if (and (< (abs prod) (expt 2 27)) (/= j 0)) (setf prod (* prod j))))) (do ((i (- three) (incf i three))) ((> i (expt 3 3))) (loop-body i)) (do ((i (- seven) (incf i x))) ((> i seven)) (loop-body i)) (do ((i 555 (incf i -1))) ((< i (- 550 y))) (loop-body i)) (do ((i 22 (incf i (- three)))) ((< i -28)) (loop-body i)) (do ((i 1927 (incf i))) ((> i 1939)) (loop-body i)) (do ((i x (incf i z))) ((< i y)) (loop-body i)) (do ((i (expt 11 x) (incf i))) ((> i (+ (expt 11 x) one))) (loop-body i))) (format t "~&sum = ~14<~:d~>" sum) (format t "~&prod = ~14<~:d~>" prod))
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Port the provided Common_Lisp code into C# while preserving the original functionality.
(let ((prod 1) (sum 0) (x 5) (y -5) (z -2) (one 1) (three 3) (seven 7)) (flet ((loop-body (j) (incf sum (abs j)) (if (and (< (abs prod) (expt 2 27)) (/= j 0)) (setf prod (* prod j))))) (do ((i (- three) (incf i three))) ((> i (expt 3 3))) (loop-body i)) (do ((i (- seven) (incf i x))) ((> i seven)) (loop-body i)) (do ((i 555 (incf i -1))) ((< i (- 550 y))) (loop-body i)) (do ((i 22 (incf i (- three)))) ((< i -28)) (loop-body i)) (do ((i 1927 (incf i))) ((> i 1939)) (loop-body i)) (do ((i x (incf i z))) ((< i y)) (loop-body i)) (do ((i (expt 11 x) (incf i))) ((> i (+ (expt 11 x) one))) (loop-body i))) (format t "~&sum = ~14<~:d~>" sum) (format t "~&prod = ~14<~:d~>" prod))
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Write the same code in C++ as shown below in Common_Lisp.
(let ((prod 1) (sum 0) (x 5) (y -5) (z -2) (one 1) (three 3) (seven 7)) (flet ((loop-body (j) (incf sum (abs j)) (if (and (< (abs prod) (expt 2 27)) (/= j 0)) (setf prod (* prod j))))) (do ((i (- three) (incf i three))) ((> i (expt 3 3))) (loop-body i)) (do ((i (- seven) (incf i x))) ((> i seven)) (loop-body i)) (do ((i 555 (incf i -1))) ((< i (- 550 y))) (loop-body i)) (do ((i 22 (incf i (- three)))) ((< i -28)) (loop-body i)) (do ((i 1927 (incf i))) ((> i 1939)) (loop-body i)) (do ((i x (incf i z))) ((< i y)) (loop-body i)) (do ((i (expt 11 x) (incf i))) ((> i (+ (expt 11 x) one))) (loop-body i))) (format t "~&sum = ~14<~:d~>" sum) (format t "~&prod = ~14<~:d~>" prod))
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Change the programming language of this snippet from Common_Lisp to Java without modifying what it does.
(let ((prod 1) (sum 0) (x 5) (y -5) (z -2) (one 1) (three 3) (seven 7)) (flet ((loop-body (j) (incf sum (abs j)) (if (and (< (abs prod) (expt 2 27)) (/= j 0)) (setf prod (* prod j))))) (do ((i (- three) (incf i three))) ((> i (expt 3 3))) (loop-body i)) (do ((i (- seven) (incf i x))) ((> i seven)) (loop-body i)) (do ((i 555 (incf i -1))) ((< i (- 550 y))) (loop-body i)) (do ((i 22 (incf i (- three)))) ((< i -28)) (loop-body i)) (do ((i 1927 (incf i))) ((> i 1939)) (loop-body i)) (do ((i x (incf i z))) ((< i y)) (loop-body i)) (do ((i (expt 11 x) (incf i))) ((> i (+ (expt 11 x) one))) (loop-body i))) (format t "~&sum = ~14<~:d~>" sum) (format t "~&prod = ~14<~:d~>" prod))
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Keep all operations the same but rewrite the snippet in Python.
(let ((prod 1) (sum 0) (x 5) (y -5) (z -2) (one 1) (three 3) (seven 7)) (flet ((loop-body (j) (incf sum (abs j)) (if (and (< (abs prod) (expt 2 27)) (/= j 0)) (setf prod (* prod j))))) (do ((i (- three) (incf i three))) ((> i (expt 3 3))) (loop-body i)) (do ((i (- seven) (incf i x))) ((> i seven)) (loop-body i)) (do ((i 555 (incf i -1))) ((< i (- 550 y))) (loop-body i)) (do ((i 22 (incf i (- three)))) ((< i -28)) (loop-body i)) (do ((i 1927 (incf i))) ((> i 1939)) (loop-body i)) (do ((i x (incf i z))) ((< i y)) (loop-body i)) (do ((i (expt 11 x) (incf i))) ((> i (+ (expt 11 x) one))) (loop-body i))) (format t "~&sum = ~14<~:d~>" sum) (format t "~&prod = ~14<~:d~>" prod))
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Maintain the same structure and functionality when rewriting this code in VB.
(let ((prod 1) (sum 0) (x 5) (y -5) (z -2) (one 1) (three 3) (seven 7)) (flet ((loop-body (j) (incf sum (abs j)) (if (and (< (abs prod) (expt 2 27)) (/= j 0)) (setf prod (* prod j))))) (do ((i (- three) (incf i three))) ((> i (expt 3 3))) (loop-body i)) (do ((i (- seven) (incf i x))) ((> i seven)) (loop-body i)) (do ((i 555 (incf i -1))) ((< i (- 550 y))) (loop-body i)) (do ((i 22 (incf i (- three)))) ((< i -28)) (loop-body i)) (do ((i 1927 (incf i))) ((> i 1939)) (loop-body i)) (do ((i x (incf i z))) ((< i y)) (loop-body i)) (do ((i (expt 11 x) (incf i))) ((> i (+ (expt 11 x) one))) (loop-body i))) (format t "~&sum = ~14<~:d~>" sum) (format t "~&prod = ~14<~:d~>" prod))
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Write the same algorithm in Go as shown in this Common_Lisp implementation.
(let ((prod 1) (sum 0) (x 5) (y -5) (z -2) (one 1) (three 3) (seven 7)) (flet ((loop-body (j) (incf sum (abs j)) (if (and (< (abs prod) (expt 2 27)) (/= j 0)) (setf prod (* prod j))))) (do ((i (- three) (incf i three))) ((> i (expt 3 3))) (loop-body i)) (do ((i (- seven) (incf i x))) ((> i seven)) (loop-body i)) (do ((i 555 (incf i -1))) ((< i (- 550 y))) (loop-body i)) (do ((i 22 (incf i (- three)))) ((< i -28)) (loop-body i)) (do ((i 1927 (incf i))) ((> i 1939)) (loop-body i)) (do ((i x (incf i z))) ((< i y)) (loop-body i)) (do ((i (expt 11 x) (incf i))) ((> i (+ (expt 11 x) one))) (loop-body i))) (format t "~&sum = ~14<~:d~>" sum) (format t "~&prod = ~14<~:d~>" prod))
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Rewrite this program in C while keeping its functionality equivalent to the Delphi version.
program with_multiple_ranges; uses System.SysUtils; var prod: Int64 = 1; sum: Int64 = 0; function labs(value: Int64): Int64; begin Result := value; if value < 0 then Result := -Result; end; procedure process(j: Int64); begin sum := sum + (abs(j)); if (labs(prod) < (1 shl 27)) and (j <> 0) then prod := prod * j; end; function ipow(n: Integer; e: Cardinal): Int64; var pr: Int64; max, i: Cardinal; begin result := n; if e = 0 then Exit(1); max := e; for i := 2 to max do result := result * n; end; var j: Int64; p: Int64; const x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; begin p := ipow(11, x); j := -three; while j <= ipow(3, 3) do begin process(j); inc(j, three); end; j := -seven; while j <= seven do begin process(j); inc(j, x); end; j := 555; while j <= (550 - y) do begin process(j); inc(j, x); end; j := 22; while j >= -28 do begin process(j); dec(j, three); end; j := 1927; while j <= 1939 do begin process(j); inc(j); end; j := x; while j >= y do begin process(j); dec(j, -z); end; j := p; while j <= p + one do begin process(j); inc(j); end; writeln(format('sum = %d ', [sum])); writeln(format('prod = %d ', [prod])); Readln; end.
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Convert this Delphi snippet to C# and keep its semantics consistent.
program with_multiple_ranges; uses System.SysUtils; var prod: Int64 = 1; sum: Int64 = 0; function labs(value: Int64): Int64; begin Result := value; if value < 0 then Result := -Result; end; procedure process(j: Int64); begin sum := sum + (abs(j)); if (labs(prod) < (1 shl 27)) and (j <> 0) then prod := prod * j; end; function ipow(n: Integer; e: Cardinal): Int64; var pr: Int64; max, i: Cardinal; begin result := n; if e = 0 then Exit(1); max := e; for i := 2 to max do result := result * n; end; var j: Int64; p: Int64; const x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; begin p := ipow(11, x); j := -three; while j <= ipow(3, 3) do begin process(j); inc(j, three); end; j := -seven; while j <= seven do begin process(j); inc(j, x); end; j := 555; while j <= (550 - y) do begin process(j); inc(j, x); end; j := 22; while j >= -28 do begin process(j); dec(j, three); end; j := 1927; while j <= 1939 do begin process(j); inc(j); end; j := x; while j >= y do begin process(j); dec(j, -z); end; j := p; while j <= p + one do begin process(j); inc(j); end; writeln(format('sum = %d ', [sum])); writeln(format('prod = %d ', [prod])); Readln; end.
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Translate this program into C++ but keep the logic exactly as in Delphi.
program with_multiple_ranges; uses System.SysUtils; var prod: Int64 = 1; sum: Int64 = 0; function labs(value: Int64): Int64; begin Result := value; if value < 0 then Result := -Result; end; procedure process(j: Int64); begin sum := sum + (abs(j)); if (labs(prod) < (1 shl 27)) and (j <> 0) then prod := prod * j; end; function ipow(n: Integer; e: Cardinal): Int64; var pr: Int64; max, i: Cardinal; begin result := n; if e = 0 then Exit(1); max := e; for i := 2 to max do result := result * n; end; var j: Int64; p: Int64; const x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; begin p := ipow(11, x); j := -three; while j <= ipow(3, 3) do begin process(j); inc(j, three); end; j := -seven; while j <= seven do begin process(j); inc(j, x); end; j := 555; while j <= (550 - y) do begin process(j); inc(j, x); end; j := 22; while j >= -28 do begin process(j); dec(j, three); end; j := 1927; while j <= 1939 do begin process(j); inc(j); end; j := x; while j >= y do begin process(j); dec(j, -z); end; j := p; while j <= p + one do begin process(j); inc(j); end; writeln(format('sum = %d ', [sum])); writeln(format('prod = %d ', [prod])); Readln; end.
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Generate an equivalent Java version of this Delphi code.
program with_multiple_ranges; uses System.SysUtils; var prod: Int64 = 1; sum: Int64 = 0; function labs(value: Int64): Int64; begin Result := value; if value < 0 then Result := -Result; end; procedure process(j: Int64); begin sum := sum + (abs(j)); if (labs(prod) < (1 shl 27)) and (j <> 0) then prod := prod * j; end; function ipow(n: Integer; e: Cardinal): Int64; var pr: Int64; max, i: Cardinal; begin result := n; if e = 0 then Exit(1); max := e; for i := 2 to max do result := result * n; end; var j: Int64; p: Int64; const x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; begin p := ipow(11, x); j := -three; while j <= ipow(3, 3) do begin process(j); inc(j, three); end; j := -seven; while j <= seven do begin process(j); inc(j, x); end; j := 555; while j <= (550 - y) do begin process(j); inc(j, x); end; j := 22; while j >= -28 do begin process(j); dec(j, three); end; j := 1927; while j <= 1939 do begin process(j); inc(j); end; j := x; while j >= y do begin process(j); dec(j, -z); end; j := p; while j <= p + one do begin process(j); inc(j); end; writeln(format('sum = %d ', [sum])); writeln(format('prod = %d ', [prod])); Readln; end.
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Preserve the algorithm and functionality while converting the code from Delphi to Python.
program with_multiple_ranges; uses System.SysUtils; var prod: Int64 = 1; sum: Int64 = 0; function labs(value: Int64): Int64; begin Result := value; if value < 0 then Result := -Result; end; procedure process(j: Int64); begin sum := sum + (abs(j)); if (labs(prod) < (1 shl 27)) and (j <> 0) then prod := prod * j; end; function ipow(n: Integer; e: Cardinal): Int64; var pr: Int64; max, i: Cardinal; begin result := n; if e = 0 then Exit(1); max := e; for i := 2 to max do result := result * n; end; var j: Int64; p: Int64; const x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; begin p := ipow(11, x); j := -three; while j <= ipow(3, 3) do begin process(j); inc(j, three); end; j := -seven; while j <= seven do begin process(j); inc(j, x); end; j := 555; while j <= (550 - y) do begin process(j); inc(j, x); end; j := 22; while j >= -28 do begin process(j); dec(j, three); end; j := 1927; while j <= 1939 do begin process(j); inc(j); end; j := x; while j >= y do begin process(j); dec(j, -z); end; j := p; while j <= p + one do begin process(j); inc(j); end; writeln(format('sum = %d ', [sum])); writeln(format('prod = %d ', [prod])); Readln; end.
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Keep all operations the same but rewrite the snippet in VB.
program with_multiple_ranges; uses System.SysUtils; var prod: Int64 = 1; sum: Int64 = 0; function labs(value: Int64): Int64; begin Result := value; if value < 0 then Result := -Result; end; procedure process(j: Int64); begin sum := sum + (abs(j)); if (labs(prod) < (1 shl 27)) and (j <> 0) then prod := prod * j; end; function ipow(n: Integer; e: Cardinal): Int64; var pr: Int64; max, i: Cardinal; begin result := n; if e = 0 then Exit(1); max := e; for i := 2 to max do result := result * n; end; var j: Int64; p: Int64; const x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; begin p := ipow(11, x); j := -three; while j <= ipow(3, 3) do begin process(j); inc(j, three); end; j := -seven; while j <= seven do begin process(j); inc(j, x); end; j := 555; while j <= (550 - y) do begin process(j); inc(j, x); end; j := 22; while j >= -28 do begin process(j); dec(j, three); end; j := 1927; while j <= 1939 do begin process(j); inc(j); end; j := x; while j >= y do begin process(j); dec(j, -z); end; j := p; while j <= p + one do begin process(j); inc(j); end; writeln(format('sum = %d ', [sum])); writeln(format('prod = %d ', [prod])); Readln; end.
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Write the same code in Go as shown below in Delphi.
program with_multiple_ranges; uses System.SysUtils; var prod: Int64 = 1; sum: Int64 = 0; function labs(value: Int64): Int64; begin Result := value; if value < 0 then Result := -Result; end; procedure process(j: Int64); begin sum := sum + (abs(j)); if (labs(prod) < (1 shl 27)) and (j <> 0) then prod := prod * j; end; function ipow(n: Integer; e: Cardinal): Int64; var pr: Int64; max, i: Cardinal; begin result := n; if e = 0 then Exit(1); max := e; for i := 2 to max do result := result * n; end; var j: Int64; p: Int64; const x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; begin p := ipow(11, x); j := -three; while j <= ipow(3, 3) do begin process(j); inc(j, three); end; j := -seven; while j <= seven do begin process(j); inc(j, x); end; j := 555; while j <= (550 - y) do begin process(j); inc(j, x); end; j := 22; while j >= -28 do begin process(j); dec(j, three); end; j := 1927; while j <= 1939 do begin process(j); inc(j); end; j := x; while j >= y do begin process(j); dec(j, -z); end; j := p; while j <= p + one do begin process(j); inc(j); end; writeln(format('sum = %d ', [sum])); writeln(format('prod = %d ', [prod])); Readln; end.
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Change the programming language of this snippet from F# to C without modifying what it does.
let x,y,z,one,three,seven=5,-5,-2,1,3,7 let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1] printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Convert this F# snippet to C# and keep its semantics consistent.
let x,y,z,one,three,seven=5,-5,-2,1,3,7 let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1] printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Write a version of this F# function in C++ with identical behavior.
let x,y,z,one,three,seven=5,-5,-2,1,3,7 let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1] printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Write the same algorithm in Java as shown in this F# implementation.
let x,y,z,one,three,seven=5,-5,-2,1,3,7 let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1] printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Translate this program into Python but keep the logic exactly as in F#.
let x,y,z,one,three,seven=5,-5,-2,1,3,7 let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1] printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Change the following F# code into VB without altering its purpose.
let x,y,z,one,three,seven=5,-5,-2,1,3,7 let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1] printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Preserve the algorithm and functionality while converting the code from F# to Go.
let x,y,z,one,three,seven=5,-5,-2,1,3,7 let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1] printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Port the provided Factor code into C while preserving the original functionality.
USING: formatting kernel locals math math.functions math.ranges sequences sequences.generalizations tools.memory.private ; [let 1 :> prod 0 :> sum 5 :> x -5 :> y -2 :> z 1 :> one 3 :> three 7 :> seven three neg 3 3 ^ three <range> seven neg seven x <range> 555 550 y - [a,b] 22 -28 three neg <range> 1927 1939 [a,b] x y z <range> 11 x ^ 11 x ^ 1 + [a,b] 7 narray [ [ :> j j abs sum + sum prod abs 2 27 ^ < j zero? not and [ prod j * prod ] each ] each sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf ]
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Write the same algorithm in C# as shown in this Factor implementation.
USING: formatting kernel locals math math.functions math.ranges sequences sequences.generalizations tools.memory.private ; [let 1 :> prod 0 :> sum 5 :> x -5 :> y -2 :> z 1 :> one 3 :> three 7 :> seven three neg 3 3 ^ three <range> seven neg seven x <range> 555 550 y - [a,b] 22 -28 three neg <range> 1927 1939 [a,b] x y z <range> 11 x ^ 11 x ^ 1 + [a,b] 7 narray [ [ :> j j abs sum + sum prod abs 2 27 ^ < j zero? not and [ prod j * prod ] each ] each sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf ]
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Rewrite the snippet below in C++ so it works the same as the original Factor code.
USING: formatting kernel locals math math.functions math.ranges sequences sequences.generalizations tools.memory.private ; [let 1 :> prod 0 :> sum 5 :> x -5 :> y -2 :> z 1 :> one 3 :> three 7 :> seven three neg 3 3 ^ three <range> seven neg seven x <range> 555 550 y - [a,b] 22 -28 three neg <range> 1927 1939 [a,b] x y z <range> 11 x ^ 11 x ^ 1 + [a,b] 7 narray [ [ :> j j abs sum + sum prod abs 2 27 ^ < j zero? not and [ prod j * prod ] each ] each sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf ]
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Write the same code in Java as shown below in Factor.
USING: formatting kernel locals math math.functions math.ranges sequences sequences.generalizations tools.memory.private ; [let 1 :> prod 0 :> sum 5 :> x -5 :> y -2 :> z 1 :> one 3 :> three 7 :> seven three neg 3 3 ^ three <range> seven neg seven x <range> 555 550 y - [a,b] 22 -28 three neg <range> 1927 1939 [a,b] x y z <range> 11 x ^ 11 x ^ 1 + [a,b] 7 narray [ [ :> j j abs sum + sum prod abs 2 27 ^ < j zero? not and [ prod j * prod ] each ] each sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf ]
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Change the programming language of this snippet from Factor to Python without modifying what it does.
USING: formatting kernel locals math math.functions math.ranges sequences sequences.generalizations tools.memory.private ; [let 1 :> prod 0 :> sum 5 :> x -5 :> y -2 :> z 1 :> one 3 :> three 7 :> seven three neg 3 3 ^ three <range> seven neg seven x <range> 555 550 y - [a,b] 22 -28 three neg <range> 1927 1939 [a,b] x y z <range> 11 x ^ 11 x ^ 1 + [a,b] 7 narray [ [ :> j j abs sum + sum prod abs 2 27 ^ < j zero? not and [ prod j * prod ] each ] each sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf ]
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Change the programming language of this snippet from Factor to VB without modifying what it does.
USING: formatting kernel locals math math.functions math.ranges sequences sequences.generalizations tools.memory.private ; [let 1 :> prod 0 :> sum 5 :> x -5 :> y -2 :> z 1 :> one 3 :> three 7 :> seven three neg 3 3 ^ three <range> seven neg seven x <range> 555 550 y - [a,b] 22 -28 three neg <range> 1927 1939 [a,b] x y z <range> 11 x ^ 11 x ^ 1 + [a,b] 7 narray [ [ :> j j abs sum + sum prod abs 2 27 ^ < j zero? not and [ prod j * prod ] each ] each sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf ]
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Convert this Factor snippet to Go and keep its semantics consistent.
USING: formatting kernel locals math math.functions math.ranges sequences sequences.generalizations tools.memory.private ; [let 1 :> prod 0 :> sum 5 :> x -5 :> y -2 :> z 1 :> one 3 :> three 7 :> seven three neg 3 3 ^ three <range> seven neg seven x <range> 555 550 y - [a,b] 22 -28 three neg <range> 1927 1939 [a,b] x y z <range> 11 x ^ 11 x ^ 1 + [a,b] 7 narray [ [ :> j j abs sum + sum prod abs 2 27 ^ < j zero? not and [ prod j * prod ] each ] each sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf ]
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Ensure the translated C code behaves exactly like the original Groovy snippet.
def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7] for ( j in ( ((-three) .. (3**3) ).step(three) + ((-seven) .. (+seven) ).step(x) + (555 .. (550-y) ) + (22 .. (-28) ).step(three) + (1927 .. 1939 ) + (x .. y ).step(z) + (11**x .. (11**x + one)) ) ) { sum = sum + j.abs() if ( prod.abs() < 2**27 && j != 0) prod *= j } println " sum= ${sum}" println "prod= ${prod}"
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Change the following Groovy code into C# without altering its purpose.
def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7] for ( j in ( ((-three) .. (3**3) ).step(three) + ((-seven) .. (+seven) ).step(x) + (555 .. (550-y) ) + (22 .. (-28) ).step(three) + (1927 .. 1939 ) + (x .. y ).step(z) + (11**x .. (11**x + one)) ) ) { sum = sum + j.abs() if ( prod.abs() < 2**27 && j != 0) prod *= j } println " sum= ${sum}" println "prod= ${prod}"
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Port the provided Groovy code into C++ while preserving the original functionality.
def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7] for ( j in ( ((-three) .. (3**3) ).step(three) + ((-seven) .. (+seven) ).step(x) + (555 .. (550-y) ) + (22 .. (-28) ).step(three) + (1927 .. 1939 ) + (x .. y ).step(z) + (11**x .. (11**x + one)) ) ) { sum = sum + j.abs() if ( prod.abs() < 2**27 && j != 0) prod *= j } println " sum= ${sum}" println "prod= ${prod}"
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Convert this Groovy block to Java, preserving its control flow and logic.
def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7] for ( j in ( ((-three) .. (3**3) ).step(three) + ((-seven) .. (+seven) ).step(x) + (555 .. (550-y) ) + (22 .. (-28) ).step(three) + (1927 .. 1939 ) + (x .. y ).step(z) + (11**x .. (11**x + one)) ) ) { sum = sum + j.abs() if ( prod.abs() < 2**27 && j != 0) prod *= j } println " sum= ${sum}" println "prod= ${prod}"
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Keep all operations the same but rewrite the snippet in Python.
def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7] for ( j in ( ((-three) .. (3**3) ).step(three) + ((-seven) .. (+seven) ).step(x) + (555 .. (550-y) ) + (22 .. (-28) ).step(three) + (1927 .. 1939 ) + (x .. y ).step(z) + (11**x .. (11**x + one)) ) ) { sum = sum + j.abs() if ( prod.abs() < 2**27 && j != 0) prod *= j } println " sum= ${sum}" println "prod= ${prod}"
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Can you help me rewrite this code in VB instead of Groovy, keeping it the same logically?
def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7] for ( j in ( ((-three) .. (3**3) ).step(three) + ((-seven) .. (+seven) ).step(x) + (555 .. (550-y) ) + (22 .. (-28) ).step(three) + (1927 .. 1939 ) + (x .. y ).step(z) + (11**x .. (11**x + one)) ) ) { sum = sum + j.abs() if ( prod.abs() < 2**27 && j != 0) prod *= j } println " sum= ${sum}" println "prod= ${prod}"
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Produce a language-to-language conversion: from Groovy to Go, same semantics.
def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7] for ( j in ( ((-three) .. (3**3) ).step(three) + ((-seven) .. (+seven) ).step(x) + (555 .. (550-y) ) + (22 .. (-28) ).step(three) + (1927 .. 1939 ) + (x .. y ).step(z) + (11**x .. (11**x + one)) ) ) { sum = sum + j.abs() if ( prod.abs() < 2**27 && j != 0) prod *= j } println " sum= ${sum}" println "prod= ${prod}"
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Produce a functionally identical C code for the snippet given in Haskell.
loop :: (b -> a -> b) -> b -> [[a]] -> b loop = foldl . foldl example = let x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 in loop ( \(sum, prod) j -> ( sum + abs j, if abs prod < 2^27 && j /= 0 then prod * j else prod ) ) (0, 1) [ [-three, -three + three .. 3^3] , [-seven, -seven + x .. seven] , [555 .. 550 - y] , [22, 22 - three .. -28] , [1927 .. 1939] , [x, x + z .. y] , [11^x .. 11^x + one] ]
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Ensure the translated C# code behaves exactly like the original Haskell snippet.
loop :: (b -> a -> b) -> b -> [[a]] -> b loop = foldl . foldl example = let x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 in loop ( \(sum, prod) j -> ( sum + abs j, if abs prod < 2^27 && j /= 0 then prod * j else prod ) ) (0, 1) [ [-three, -three + three .. 3^3] , [-seven, -seven + x .. seven] , [555 .. 550 - y] , [22, 22 - three .. -28] , [1927 .. 1939] , [x, x + z .. y] , [11^x .. 11^x + one] ]
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Translate this program into C++ but keep the logic exactly as in Haskell.
loop :: (b -> a -> b) -> b -> [[a]] -> b loop = foldl . foldl example = let x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 in loop ( \(sum, prod) j -> ( sum + abs j, if abs prod < 2^27 && j /= 0 then prod * j else prod ) ) (0, 1) [ [-three, -three + three .. 3^3] , [-seven, -seven + x .. seven] , [555 .. 550 - y] , [22, 22 - three .. -28] , [1927 .. 1939] , [x, x + z .. y] , [11^x .. 11^x + one] ]
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Ensure the translated Java code behaves exactly like the original Haskell snippet.
loop :: (b -> a -> b) -> b -> [[a]] -> b loop = foldl . foldl example = let x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 in loop ( \(sum, prod) j -> ( sum + abs j, if abs prod < 2^27 && j /= 0 then prod * j else prod ) ) (0, 1) [ [-three, -three + three .. 3^3] , [-seven, -seven + x .. seven] , [555 .. 550 - y] , [22, 22 - three .. -28] , [1927 .. 1939] , [x, x + z .. y] , [11^x .. 11^x + one] ]
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Write a version of this Haskell function in Python with identical behavior.
loop :: (b -> a -> b) -> b -> [[a]] -> b loop = foldl . foldl example = let x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 in loop ( \(sum, prod) j -> ( sum + abs j, if abs prod < 2^27 && j /= 0 then prod * j else prod ) ) (0, 1) [ [-three, -three + three .. 3^3] , [-seven, -seven + x .. seven] , [555 .. 550 - y] , [22, 22 - three .. -28] , [1927 .. 1939] , [x, x + z .. y] , [11^x .. 11^x + one] ]
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Can you help me rewrite this code in VB instead of Haskell, keeping it the same logically?
loop :: (b -> a -> b) -> b -> [[a]] -> b loop = foldl . foldl example = let x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 in loop ( \(sum, prod) j -> ( sum + abs j, if abs prod < 2^27 && j /= 0 then prod * j else prod ) ) (0, 1) [ [-three, -three + three .. 3^3] , [-seven, -seven + x .. seven] , [555 .. 550 - y] , [22, 22 - three .. -28] , [1927 .. 1939] , [x, x + z .. y] , [11^x .. 11^x + one] ]
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Maintain the same structure and functionality when rewriting this code in Go.
loop :: (b -> a -> b) -> b -> [[a]] -> b loop = foldl . foldl example = let x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 in loop ( \(sum, prod) j -> ( sum + abs j, if abs prod < 2^27 && j /= 0 then prod * j else prod ) ) (0, 1) [ [-three, -three + three .. 3^3] , [-seven, -seven + x .. seven] , [555 .. 550 - y] , [22, 22 - three .. -28] , [1927 .. 1939] , [x, x + z .. y] , [11^x .. 11^x + one] ]
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Change the following J code into C without altering its purpose.
TO=: {{ 'N M'=. 2{.y,1 x:x+M*i.>.(1+N-x)%M }} BY=: , {{ PROD=: 1 SUM=: 0 X=: +5 Y=: -5 Z=: -2 ONE=: 1 THREE=: 3 SEVEN=: 7 for_J. ;do >cutLF {{)n < (-THREE) TO (3^3) BY THREE < (-SEVEN) TO (+SEVEN) BY X < 555 TO 550-Y < 22 TO _28 BY -THREE < 1927 TO 1939 < X TO Y BY Z < (11^X) TO (11^X) + ONE }} do. SUM=: SUM+|J if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end. end. echo ' SUM= ',":SUM echo 'PROD= ',":PROD }}0
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Translate the given J code snippet into C# without altering its behavior.
TO=: {{ 'N M'=. 2{.y,1 x:x+M*i.>.(1+N-x)%M }} BY=: , {{ PROD=: 1 SUM=: 0 X=: +5 Y=: -5 Z=: -2 ONE=: 1 THREE=: 3 SEVEN=: 7 for_J. ;do >cutLF {{)n < (-THREE) TO (3^3) BY THREE < (-SEVEN) TO (+SEVEN) BY X < 555 TO 550-Y < 22 TO _28 BY -THREE < 1927 TO 1939 < X TO Y BY Z < (11^X) TO (11^X) + ONE }} do. SUM=: SUM+|J if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end. end. echo ' SUM= ',":SUM echo 'PROD= ',":PROD }}0
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Port the following code from J to C++ with equivalent syntax and logic.
TO=: {{ 'N M'=. 2{.y,1 x:x+M*i.>.(1+N-x)%M }} BY=: , {{ PROD=: 1 SUM=: 0 X=: +5 Y=: -5 Z=: -2 ONE=: 1 THREE=: 3 SEVEN=: 7 for_J. ;do >cutLF {{)n < (-THREE) TO (3^3) BY THREE < (-SEVEN) TO (+SEVEN) BY X < 555 TO 550-Y < 22 TO _28 BY -THREE < 1927 TO 1939 < X TO Y BY Z < (11^X) TO (11^X) + ONE }} do. SUM=: SUM+|J if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end. end. echo ' SUM= ',":SUM echo 'PROD= ',":PROD }}0
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Produce a language-to-language conversion: from J to Java, same semantics.
TO=: {{ 'N M'=. 2{.y,1 x:x+M*i.>.(1+N-x)%M }} BY=: , {{ PROD=: 1 SUM=: 0 X=: +5 Y=: -5 Z=: -2 ONE=: 1 THREE=: 3 SEVEN=: 7 for_J. ;do >cutLF {{)n < (-THREE) TO (3^3) BY THREE < (-SEVEN) TO (+SEVEN) BY X < 555 TO 550-Y < 22 TO _28 BY -THREE < 1927 TO 1939 < X TO Y BY Z < (11^X) TO (11^X) + ONE }} do. SUM=: SUM+|J if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end. end. echo ' SUM= ',":SUM echo 'PROD= ',":PROD }}0
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Ensure the translated Python code behaves exactly like the original J snippet.
TO=: {{ 'N M'=. 2{.y,1 x:x+M*i.>.(1+N-x)%M }} BY=: , {{ PROD=: 1 SUM=: 0 X=: +5 Y=: -5 Z=: -2 ONE=: 1 THREE=: 3 SEVEN=: 7 for_J. ;do >cutLF {{)n < (-THREE) TO (3^3) BY THREE < (-SEVEN) TO (+SEVEN) BY X < 555 TO 550-Y < 22 TO _28 BY -THREE < 1927 TO 1939 < X TO Y BY Z < (11^X) TO (11^X) + ONE }} do. SUM=: SUM+|J if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end. end. echo ' SUM= ',":SUM echo 'PROD= ',":PROD }}0
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Please provide an equivalent version of this J code in VB.
TO=: {{ 'N M'=. 2{.y,1 x:x+M*i.>.(1+N-x)%M }} BY=: , {{ PROD=: 1 SUM=: 0 X=: +5 Y=: -5 Z=: -2 ONE=: 1 THREE=: 3 SEVEN=: 7 for_J. ;do >cutLF {{)n < (-THREE) TO (3^3) BY THREE < (-SEVEN) TO (+SEVEN) BY X < 555 TO 550-Y < 22 TO _28 BY -THREE < 1927 TO 1939 < X TO Y BY Z < (11^X) TO (11^X) + ONE }} do. SUM=: SUM+|J if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end. end. echo ' SUM= ',":SUM echo 'PROD= ',":PROD }}0
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Change the programming language of this snippet from J to Go without modifying what it does.
TO=: {{ 'N M'=. 2{.y,1 x:x+M*i.>.(1+N-x)%M }} BY=: , {{ PROD=: 1 SUM=: 0 X=: +5 Y=: -5 Z=: -2 ONE=: 1 THREE=: 3 SEVEN=: 7 for_J. ;do >cutLF {{)n < (-THREE) TO (3^3) BY THREE < (-SEVEN) TO (+SEVEN) BY X < 555 TO 550-Y < 22 TO _28 BY -THREE < 1927 TO 1939 < X TO Y BY Z < (11^X) TO (11^X) + ONE }} do. SUM=: SUM+|J if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end. end. echo ' SUM= ',":SUM echo 'PROD= ',":PROD }}0
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Rewrite the snippet below in C so it works the same as the original Julia code.
using Formatting function PL1example() prod = 1; sum = 0; x = +5; y = -5; z = -2; one = 1; three = 3; seven = 7; for j in [ -three : three : 3^3 ; -seven : x : +seven ; 555 : 550 - y ; 22 : -three : -28 ; 1927 : 1939 ; x : z : y ; 11^x : 11^x + one ] sum = sum + abs(j); if abs(prod) < 2^27 && j !=0 prod = prod*j end; end println(" sum = $(format(sum, commas=true))"); println("prod = $(format(prod, commas=true))"); end PL1example()
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Ensure the translated C# code behaves exactly like the original Julia snippet.
using Formatting function PL1example() prod = 1; sum = 0; x = +5; y = -5; z = -2; one = 1; three = 3; seven = 7; for j in [ -three : three : 3^3 ; -seven : x : +seven ; 555 : 550 - y ; 22 : -three : -28 ; 1927 : 1939 ; x : z : y ; 11^x : 11^x + one ] sum = sum + abs(j); if abs(prod) < 2^27 && j !=0 prod = prod*j end; end println(" sum = $(format(sum, commas=true))"); println("prod = $(format(prod, commas=true))"); end PL1example()
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Write a version of this Julia function in C++ with identical behavior.
using Formatting function PL1example() prod = 1; sum = 0; x = +5; y = -5; z = -2; one = 1; three = 3; seven = 7; for j in [ -three : three : 3^3 ; -seven : x : +seven ; 555 : 550 - y ; 22 : -three : -28 ; 1927 : 1939 ; x : z : y ; 11^x : 11^x + one ] sum = sum + abs(j); if abs(prod) < 2^27 && j !=0 prod = prod*j end; end println(" sum = $(format(sum, commas=true))"); println("prod = $(format(prod, commas=true))"); end PL1example()
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Can you help me rewrite this code in Java instead of Julia, keeping it the same logically?
using Formatting function PL1example() prod = 1; sum = 0; x = +5; y = -5; z = -2; one = 1; three = 3; seven = 7; for j in [ -three : three : 3^3 ; -seven : x : +seven ; 555 : 550 - y ; 22 : -three : -28 ; 1927 : 1939 ; x : z : y ; 11^x : 11^x + one ] sum = sum + abs(j); if abs(prod) < 2^27 && j !=0 prod = prod*j end; end println(" sum = $(format(sum, commas=true))"); println("prod = $(format(prod, commas=true))"); end PL1example()
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Keep all operations the same but rewrite the snippet in Python.
using Formatting function PL1example() prod = 1; sum = 0; x = +5; y = -5; z = -2; one = 1; three = 3; seven = 7; for j in [ -three : three : 3^3 ; -seven : x : +seven ; 555 : 550 - y ; 22 : -three : -28 ; 1927 : 1939 ; x : z : y ; 11^x : 11^x + one ] sum = sum + abs(j); if abs(prod) < 2^27 && j !=0 prod = prod*j end; end println(" sum = $(format(sum, commas=true))"); println("prod = $(format(prod, commas=true))"); end PL1example()
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Transform the following Julia implementation into VB, maintaining the same output and logic.
using Formatting function PL1example() prod = 1; sum = 0; x = +5; y = -5; z = -2; one = 1; three = 3; seven = 7; for j in [ -three : three : 3^3 ; -seven : x : +seven ; 555 : 550 - y ; 22 : -three : -28 ; 1927 : 1939 ; x : z : y ; 11^x : 11^x + one ] sum = sum + abs(j); if abs(prod) < 2^27 && j !=0 prod = prod*j end; end println(" sum = $(format(sum, commas=true))"); println("prod = $(format(prod, commas=true))"); end PL1example()
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Write a version of this Julia function in Go with identical behavior.
using Formatting function PL1example() prod = 1; sum = 0; x = +5; y = -5; z = -2; one = 1; three = 3; seven = 7; for j in [ -three : three : 3^3 ; -seven : x : +seven ; 555 : 550 - y ; 22 : -three : -28 ; 1927 : 1939 ; x : z : y ; 11^x : 11^x + one ] sum = sum + abs(j); if abs(prod) < 2^27 && j !=0 prod = prod*j end; end println(" sum = $(format(sum, commas=true))"); println("prod = $(format(prod, commas=true))"); end PL1example()
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Maintain the same structure and functionality when rewriting this code in C.
function T(t) return setmetatable(t, {__index=table}) end table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end unpack = unpack or table.unpack function mrl(tt) local s=T{} for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end return ipairs(s) end prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7 for _,j in mrl{ { -three, 3^3, three }, { -seven, seven, x }, { 555, 550-y }, { 22, -28, -three }, { 1927, 1939 }, { x, y, z }, { 11^x, 11^x+1 }} do sum = sum + math.abs(j) if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end end print(" sum= " .. sum) print("prod= " .. prod)
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Change the following Lua code into C# without altering its purpose.
function T(t) return setmetatable(t, {__index=table}) end table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end unpack = unpack or table.unpack function mrl(tt) local s=T{} for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end return ipairs(s) end prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7 for _,j in mrl{ { -three, 3^3, three }, { -seven, seven, x }, { 555, 550-y }, { 22, -28, -three }, { 1927, 1939 }, { x, y, z }, { 11^x, 11^x+1 }} do sum = sum + math.abs(j) if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end end print(" sum= " .. sum) print("prod= " .. prod)
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Convert this Lua snippet to C++ and keep its semantics consistent.
function T(t) return setmetatable(t, {__index=table}) end table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end unpack = unpack or table.unpack function mrl(tt) local s=T{} for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end return ipairs(s) end prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7 for _,j in mrl{ { -three, 3^3, three }, { -seven, seven, x }, { 555, 550-y }, { 22, -28, -three }, { 1927, 1939 }, { x, y, z }, { 11^x, 11^x+1 }} do sum = sum + math.abs(j) if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end end print(" sum= " .. sum) print("prod= " .. prod)
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Write the same algorithm in Java as shown in this Lua implementation.
function T(t) return setmetatable(t, {__index=table}) end table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end unpack = unpack or table.unpack function mrl(tt) local s=T{} for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end return ipairs(s) end prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7 for _,j in mrl{ { -three, 3^3, three }, { -seven, seven, x }, { 555, 550-y }, { 22, -28, -three }, { 1927, 1939 }, { x, y, z }, { 11^x, 11^x+1 }} do sum = sum + math.abs(j) if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end end print(" sum= " .. sum) print("prod= " .. prod)
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Ensure the translated Python code behaves exactly like the original Lua snippet.
function T(t) return setmetatable(t, {__index=table}) end table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end unpack = unpack or table.unpack function mrl(tt) local s=T{} for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end return ipairs(s) end prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7 for _,j in mrl{ { -three, 3^3, three }, { -seven, seven, x }, { 555, 550-y }, { 22, -28, -three }, { 1927, 1939 }, { x, y, z }, { 11^x, 11^x+1 }} do sum = sum + math.abs(j) if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end end print(" sum= " .. sum) print("prod= " .. prod)
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Transform the following Lua implementation into VB, maintaining the same output and logic.
function T(t) return setmetatable(t, {__index=table}) end table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end unpack = unpack or table.unpack function mrl(tt) local s=T{} for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end return ipairs(s) end prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7 for _,j in mrl{ { -three, 3^3, three }, { -seven, seven, x }, { 555, 550-y }, { 22, -28, -three }, { 1927, 1939 }, { x, y, z }, { 11^x, 11^x+1 }} do sum = sum + math.abs(j) if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end end print(" sum= " .. sum) print("prod= " .. prod)
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Change the programming language of this snippet from Lua to Go without modifying what it does.
function T(t) return setmetatable(t, {__index=table}) end table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end unpack = unpack or table.unpack function mrl(tt) local s=T{} for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end return ipairs(s) end prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7 for _,j in mrl{ { -three, 3^3, three }, { -seven, seven, x }, { 555, 550-y }, { 22, -28, -three }, { 1927, 1939 }, { x, y, z }, { 11^x, 11^x+1 }} do sum = sum + math.abs(j) if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end end print(" sum= " .. sum) print("prod= " .. prod)
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Write a version of this Mathematica function in C with identical behavior.
prod = 1; sum = 0; x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; Do[ sum += Abs[j]; If[Abs[prod] < 2^27 \[And] j != 0, prod *= j]; , {j, Join[ Range[-three, 3^3, three], Range[-seven, seven, x], Range[555, 550 - y], Range[22, -28, -three], Range[1927, 1939], Range[x, y, z], Range[11^x, 11^x + one] ] } ] sum prod
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Write the same code in C# as shown below in Mathematica.
prod = 1; sum = 0; x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; Do[ sum += Abs[j]; If[Abs[prod] < 2^27 \[And] j != 0, prod *= j]; , {j, Join[ Range[-three, 3^3, three], Range[-seven, seven, x], Range[555, 550 - y], Range[22, -28, -three], Range[1927, 1939], Range[x, y, z], Range[11^x, 11^x + one] ] } ] sum prod
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Produce a functionally identical C++ code for the snippet given in Mathematica.
prod = 1; sum = 0; x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; Do[ sum += Abs[j]; If[Abs[prod] < 2^27 \[And] j != 0, prod *= j]; , {j, Join[ Range[-three, 3^3, three], Range[-seven, seven, x], Range[555, 550 - y], Range[22, -28, -three], Range[1927, 1939], Range[x, y, z], Range[11^x, 11^x + one] ] } ] sum prod
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Write the same algorithm in Java as shown in this Mathematica implementation.
prod = 1; sum = 0; x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; Do[ sum += Abs[j]; If[Abs[prod] < 2^27 \[And] j != 0, prod *= j]; , {j, Join[ Range[-three, 3^3, three], Range[-seven, seven, x], Range[555, 550 - y], Range[22, -28, -three], Range[1927, 1939], Range[x, y, z], Range[11^x, 11^x + one] ] } ] sum prod
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Convert the following code from Mathematica to Python, ensuring the logic remains intact.
prod = 1; sum = 0; x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; Do[ sum += Abs[j]; If[Abs[prod] < 2^27 \[And] j != 0, prod *= j]; , {j, Join[ Range[-three, 3^3, three], Range[-seven, seven, x], Range[555, 550 - y], Range[22, -28, -three], Range[1927, 1939], Range[x, y, z], Range[11^x, 11^x + one] ] } ] sum prod
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Convert the following code from Mathematica to VB, ensuring the logic remains intact.
prod = 1; sum = 0; x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; Do[ sum += Abs[j]; If[Abs[prod] < 2^27 \[And] j != 0, prod *= j]; , {j, Join[ Range[-three, 3^3, three], Range[-seven, seven, x], Range[555, 550 - y], Range[22, -28, -three], Range[1927, 1939], Range[x, y, z], Range[11^x, 11^x + one] ] } ] sum prod
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Translate the given Mathematica code snippet into Go without altering its behavior.
prod = 1; sum = 0; x = 5; y = -5; z = -2; one = 1; three = 3; seven = 7; Do[ sum += Abs[j]; If[Abs[prod] < 2^27 \[And] j != 0, prod *= j]; , {j, Join[ Range[-three, 3^3, three], Range[-seven, seven, x], Range[555, 550 - y], Range[22, -28, -three], Range[1927, 1939], Range[x, y, z], Range[11^x, 11^x + one] ] } ] sum prod
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Port the provided Nim code into C while preserving the original functionality.
import math, strutils var prod = 1 sum = 0 let x = +5 y = -5 z = -2 one = 1 three = 3 seven = 7 proc body(j: int) = sum += abs(j) if abs(prod) < 2^27 and j != 0: prod *= j for j in countup(-three, 3^3, three): body(j) for j in countup(-seven, seven, x): body(j) for j in countup(555, 550 - y): body(j) for j in countdown(22, -28, three): body(j) for j in countup(1927, 1939): body(j) for j in countdown(x, y, -z): body(j) for j in countup(11^x, 11^x + one): body(j) let s = ($sum).insertSep(',') let p = ($prod).insertSep(',') let m = max(s.len, p.len) echo " sum = ", s.align(m) echo "prod = ", p.align(m)
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Generate an equivalent C# version of this Nim code.
import math, strutils var prod = 1 sum = 0 let x = +5 y = -5 z = -2 one = 1 three = 3 seven = 7 proc body(j: int) = sum += abs(j) if abs(prod) < 2^27 and j != 0: prod *= j for j in countup(-three, 3^3, three): body(j) for j in countup(-seven, seven, x): body(j) for j in countup(555, 550 - y): body(j) for j in countdown(22, -28, three): body(j) for j in countup(1927, 1939): body(j) for j in countdown(x, y, -z): body(j) for j in countup(11^x, 11^x + one): body(j) let s = ($sum).insertSep(',') let p = ($prod).insertSep(',') let m = max(s.len, p.len) echo " sum = ", s.align(m) echo "prod = ", p.align(m)
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Keep all operations the same but rewrite the snippet in C++.
import math, strutils var prod = 1 sum = 0 let x = +5 y = -5 z = -2 one = 1 three = 3 seven = 7 proc body(j: int) = sum += abs(j) if abs(prod) < 2^27 and j != 0: prod *= j for j in countup(-three, 3^3, three): body(j) for j in countup(-seven, seven, x): body(j) for j in countup(555, 550 - y): body(j) for j in countdown(22, -28, three): body(j) for j in countup(1927, 1939): body(j) for j in countdown(x, y, -z): body(j) for j in countup(11^x, 11^x + one): body(j) let s = ($sum).insertSep(',') let p = ($prod).insertSep(',') let m = max(s.len, p.len) echo " sum = ", s.align(m) echo "prod = ", p.align(m)
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Produce a language-to-language conversion: from Nim to Java, same semantics.
import math, strutils var prod = 1 sum = 0 let x = +5 y = -5 z = -2 one = 1 three = 3 seven = 7 proc body(j: int) = sum += abs(j) if abs(prod) < 2^27 and j != 0: prod *= j for j in countup(-three, 3^3, three): body(j) for j in countup(-seven, seven, x): body(j) for j in countup(555, 550 - y): body(j) for j in countdown(22, -28, three): body(j) for j in countup(1927, 1939): body(j) for j in countdown(x, y, -z): body(j) for j in countup(11^x, 11^x + one): body(j) let s = ($sum).insertSep(',') let p = ($prod).insertSep(',') let m = max(s.len, p.len) echo " sum = ", s.align(m) echo "prod = ", p.align(m)
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Change the programming language of this snippet from Nim to Python without modifying what it does.
import math, strutils var prod = 1 sum = 0 let x = +5 y = -5 z = -2 one = 1 three = 3 seven = 7 proc body(j: int) = sum += abs(j) if abs(prod) < 2^27 and j != 0: prod *= j for j in countup(-three, 3^3, three): body(j) for j in countup(-seven, seven, x): body(j) for j in countup(555, 550 - y): body(j) for j in countdown(22, -28, three): body(j) for j in countup(1927, 1939): body(j) for j in countdown(x, y, -z): body(j) for j in countup(11^x, 11^x + one): body(j) let s = ($sum).insertSep(',') let p = ($prod).insertSep(',') let m = max(s.len, p.len) echo " sum = ", s.align(m) echo "prod = ", p.align(m)
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Ensure the translated VB code behaves exactly like the original Nim snippet.
import math, strutils var prod = 1 sum = 0 let x = +5 y = -5 z = -2 one = 1 three = 3 seven = 7 proc body(j: int) = sum += abs(j) if abs(prod) < 2^27 and j != 0: prod *= j for j in countup(-three, 3^3, three): body(j) for j in countup(-seven, seven, x): body(j) for j in countup(555, 550 - y): body(j) for j in countdown(22, -28, three): body(j) for j in countup(1927, 1939): body(j) for j in countdown(x, y, -z): body(j) for j in countup(11^x, 11^x + one): body(j) let s = ($sum).insertSep(',') let p = ($prod).insertSep(',') let m = max(s.len, p.len) echo " sum = ", s.align(m) echo "prod = ", p.align(m)
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Convert this Nim snippet to Go and keep its semantics consistent.
import math, strutils var prod = 1 sum = 0 let x = +5 y = -5 z = -2 one = 1 three = 3 seven = 7 proc body(j: int) = sum += abs(j) if abs(prod) < 2^27 and j != 0: prod *= j for j in countup(-three, 3^3, three): body(j) for j in countup(-seven, seven, x): body(j) for j in countup(555, 550 - y): body(j) for j in countdown(22, -28, three): body(j) for j in countup(1927, 1939): body(j) for j in countdown(x, y, -z): body(j) for j in countup(11^x, 11^x + one): body(j) let s = ($sum).insertSep(',') let p = ($prod).insertSep(',') let m = max(s.len, p.len) echo " sum = ", s.align(m) echo "prod = ", p.align(m)
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Rewrite the snippet below in C so it works the same as the original Perl code.
use constant one => 1; use constant three => 3; use constant seven => 7; use constant x => 5; use constant yy => -5; use constant z => -2; my $prod = 1; sub from_to_by { my($begin,$end,$skip) = @_; my $n = 0; grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin; } sub commatize { (my $s = reverse shift) =~ s/(.{3})/$1,/g; $s =~ s/,(-?)$/$1/; $s = reverse $s; } for my $j ( from_to_by(-three,3**3,three), from_to_by(-seven,seven,x), 555 .. 550 - yy, from_to_by(22,-28,-three), 1927 .. 1939, from_to_by(x,yy,z), 11**x .. 11**x+one, ) { $sum += abs($j); $prod *= $j if $j and abs($prod) < 2**27; } printf "%-8s %12s\n", 'Sum:', commatize $sum; printf "%-8s %12s\n", 'Product:', commatize $prod;
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Maintain the same structure and functionality when rewriting this code in C#.
use constant one => 1; use constant three => 3; use constant seven => 7; use constant x => 5; use constant yy => -5; use constant z => -2; my $prod = 1; sub from_to_by { my($begin,$end,$skip) = @_; my $n = 0; grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin; } sub commatize { (my $s = reverse shift) =~ s/(.{3})/$1,/g; $s =~ s/,(-?)$/$1/; $s = reverse $s; } for my $j ( from_to_by(-three,3**3,three), from_to_by(-seven,seven,x), 555 .. 550 - yy, from_to_by(22,-28,-three), 1927 .. 1939, from_to_by(x,yy,z), 11**x .. 11**x+one, ) { $sum += abs($j); $prod *= $j if $j and abs($prod) < 2**27; } printf "%-8s %12s\n", 'Sum:', commatize $sum; printf "%-8s %12s\n", 'Product:', commatize $prod;
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Ensure the translated C++ code behaves exactly like the original Perl snippet.
use constant one => 1; use constant three => 3; use constant seven => 7; use constant x => 5; use constant yy => -5; use constant z => -2; my $prod = 1; sub from_to_by { my($begin,$end,$skip) = @_; my $n = 0; grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin; } sub commatize { (my $s = reverse shift) =~ s/(.{3})/$1,/g; $s =~ s/,(-?)$/$1/; $s = reverse $s; } for my $j ( from_to_by(-three,3**3,three), from_to_by(-seven,seven,x), 555 .. 550 - yy, from_to_by(22,-28,-three), 1927 .. 1939, from_to_by(x,yy,z), 11**x .. 11**x+one, ) { $sum += abs($j); $prod *= $j if $j and abs($prod) < 2**27; } printf "%-8s %12s\n", 'Sum:', commatize $sum; printf "%-8s %12s\n", 'Product:', commatize $prod;
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Convert this Perl block to Java, preserving its control flow and logic.
use constant one => 1; use constant three => 3; use constant seven => 7; use constant x => 5; use constant yy => -5; use constant z => -2; my $prod = 1; sub from_to_by { my($begin,$end,$skip) = @_; my $n = 0; grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin; } sub commatize { (my $s = reverse shift) =~ s/(.{3})/$1,/g; $s =~ s/,(-?)$/$1/; $s = reverse $s; } for my $j ( from_to_by(-three,3**3,three), from_to_by(-seven,seven,x), 555 .. 550 - yy, from_to_by(22,-28,-three), 1927 .. 1939, from_to_by(x,yy,z), 11**x .. 11**x+one, ) { $sum += abs($j); $prod *= $j if $j and abs($prod) < 2**27; } printf "%-8s %12s\n", 'Sum:', commatize $sum; printf "%-8s %12s\n", 'Product:', commatize $prod;
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Translate this program into Python but keep the logic exactly as in Perl.
use constant one => 1; use constant three => 3; use constant seven => 7; use constant x => 5; use constant yy => -5; use constant z => -2; my $prod = 1; sub from_to_by { my($begin,$end,$skip) = @_; my $n = 0; grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin; } sub commatize { (my $s = reverse shift) =~ s/(.{3})/$1,/g; $s =~ s/,(-?)$/$1/; $s = reverse $s; } for my $j ( from_to_by(-three,3**3,three), from_to_by(-seven,seven,x), 555 .. 550 - yy, from_to_by(22,-28,-three), 1927 .. 1939, from_to_by(x,yy,z), 11**x .. 11**x+one, ) { $sum += abs($j); $prod *= $j if $j and abs($prod) < 2**27; } printf "%-8s %12s\n", 'Sum:', commatize $sum; printf "%-8s %12s\n", 'Product:', commatize $prod;
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Rewrite the snippet below in VB so it works the same as the original Perl code.
use constant one => 1; use constant three => 3; use constant seven => 7; use constant x => 5; use constant yy => -5; use constant z => -2; my $prod = 1; sub from_to_by { my($begin,$end,$skip) = @_; my $n = 0; grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin; } sub commatize { (my $s = reverse shift) =~ s/(.{3})/$1,/g; $s =~ s/,(-?)$/$1/; $s = reverse $s; } for my $j ( from_to_by(-three,3**3,three), from_to_by(-seven,seven,x), 555 .. 550 - yy, from_to_by(22,-28,-three), 1927 .. 1939, from_to_by(x,yy,z), 11**x .. 11**x+one, ) { $sum += abs($j); $prod *= $j if $j and abs($prod) < 2**27; } printf "%-8s %12s\n", 'Sum:', commatize $sum; printf "%-8s %12s\n", 'Product:', commatize $prod;
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Port the following code from Perl to Go with equivalent syntax and logic.
use constant one => 1; use constant three => 3; use constant seven => 7; use constant x => 5; use constant yy => -5; use constant z => -2; my $prod = 1; sub from_to_by { my($begin,$end,$skip) = @_; my $n = 0; grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin; } sub commatize { (my $s = reverse shift) =~ s/(.{3})/$1,/g; $s =~ s/,(-?)$/$1/; $s = reverse $s; } for my $j ( from_to_by(-three,3**3,three), from_to_by(-seven,seven,x), 555 .. 550 - yy, from_to_by(22,-28,-three), 1927 .. 1939, from_to_by(x,yy,z), 11**x .. 11**x+one, ) { $sum += abs($j); $prod *= $j if $j and abs($prod) < 2**27; } printf "%-8s %12s\n", 'Sum:', commatize $sum; printf "%-8s %12s\n", 'Product:', commatize $prod;
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Change the following REXX code into C without altering its purpose.
prod= 1; sum= 0; x= +5; y= -5; z= -2; one= 1; three= 3; seven= 7; do j= -three to 3**3 by three ; call meat; end; do j= -seven to seven by x ; call meat; end; do j= 555 to 550 - y ; call meat; end; do j= 22 to -28 by -three ; call meat; end; do j= 1927 to 1939 ; call meat; end; do j= x to y by z ; call meat; end; do j= 11**x to 11**x + one ; call meat; end; say ' sum= ' || commas( sum); say 'prod= ' || commas(prod); exit; commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M") e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4 do j=e to b by -3; _= insert(',', _, j); end; return _ meat: sum= sum + abs(j); if abs(prod)<2**27 & j\==0 then prod= prod * j; return;
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }
Can you help me rewrite this code in C# instead of REXX, keeping it the same logically?
prod= 1; sum= 0; x= +5; y= -5; z= -2; one= 1; three= 3; seven= 7; do j= -three to 3**3 by three ; call meat; end; do j= -seven to seven by x ; call meat; end; do j= 555 to 550 - y ; call meat; end; do j= 22 to -28 by -three ; call meat; end; do j= 1927 to 1939 ; call meat; end; do j= x to y by z ; call meat; end; do j= 11**x to 11**x + one ; call meat; end; say ' sum= ' || commas( sum); say 'prod= ' || commas(prod); exit; commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M") e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4 do j=e to b by -3; _= insert(',', _, j); end; return _ meat: sum= sum + abs(j); if abs(prod)<2**27 & j\==0 then prod= prod * j; return;
using System; using System.Collections.Generic; using System.Linq; public static class LoopsWithMultipleRanges { public static void Main() { int prod = 1; int sum = 0; int x = 5; int y = -5; int z = -2; int one = 1; int three = 3; int seven = 7; foreach (int j in Concat( For(-three, 3.Pow(3), three), For(-seven, seven, x), For(555, 550 - y), For(22, -28, -three), For(1927, 1939), For(x, y, z), For(11.Pow(x), 11.Pow(x) + one) )) { sum += Math.Abs(j); if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j; } Console.WriteLine($" sum = {sum:N0}"); Console.WriteLine($"prod = {prod:N0}"); } static IEnumerable<int> For(int start, int end, int by = 1) { for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i; } static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r)); static int Pow(this int b, int e) => (int)Math.Pow(b, e); }
Port the following code from REXX to C++ with equivalent syntax and logic.
prod= 1; sum= 0; x= +5; y= -5; z= -2; one= 1; three= 3; seven= 7; do j= -three to 3**3 by three ; call meat; end; do j= -seven to seven by x ; call meat; end; do j= 555 to 550 - y ; call meat; end; do j= 22 to -28 by -three ; call meat; end; do j= 1927 to 1939 ; call meat; end; do j= x to y by z ; call meat; end; do j= 11**x to 11**x + one ; call meat; end; say ' sum= ' || commas( sum); say 'prod= ' || commas(prod); exit; commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M") e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4 do j=e to b by -3; _= insert(',', _, j); end; return _ meat: sum= sum + abs(j); if abs(prod)<2**27 & j\==0 then prod= prod * j; return;
#include <iostream> #include <cmath> #include <vector> using std::abs; using std::cout; using std::pow; using std::vector; int main() { int prod = 1, sum = 0, x = 5, y = -5, z = -2, one = 1, three = 3, seven = 7; auto summingValues = vector<int>{}; for(int n = -three; n <= pow(3, 3); n += three) summingValues.push_back(n); for(int n = -seven; n <= seven; n += x) summingValues.push_back(n); for(int n = 555; n <= 550 - y; ++n) summingValues.push_back(n); for(int n = 22; n >= -28; n -= three) summingValues.push_back(n); for(int n = 1927; n <= 1939; ++n) summingValues.push_back(n); for(int n = x; n >= y; n += z) summingValues.push_back(n); for(int n = pow(11, x); n <= pow(11, x) + one; ++n) summingValues.push_back(n); for(auto j : summingValues) { sum += abs(j); if(abs(prod) < pow(2, 27) && j != 0) prod *= j; } cout << "sum = " << sum << "\n"; cout << "prod = " << prod << "\n"; }
Convert this REXX snippet to Java and keep its semantics consistent.
prod= 1; sum= 0; x= +5; y= -5; z= -2; one= 1; three= 3; seven= 7; do j= -three to 3**3 by three ; call meat; end; do j= -seven to seven by x ; call meat; end; do j= 555 to 550 - y ; call meat; end; do j= 22 to -28 by -three ; call meat; end; do j= 1927 to 1939 ; call meat; end; do j= x to y by z ; call meat; end; do j= 11**x to 11**x + one ; call meat; end; say ' sum= ' || commas( sum); say 'prod= ' || commas(prod); exit; commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M") e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4 do j=e to b by -3; _= insert(',', _, j); end; return _ meat: sum= sum + abs(j); if abs(prod)<2**27 & j\==0 then prod= prod * j; return;
import java.util.ArrayList; import java.util.List; public class LoopsWithMultipleRanges { private static long sum = 0; private static long prod = 1; public static void main(String[] args) { long x = 5; long y = -5; long z = -2; long one = 1; long three = 3; long seven = 7; List<Long> jList = new ArrayList<>(); for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j); for ( long j = -seven ; j <= seven ; j += x ) jList.add(j); for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j); for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j); for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j); for ( long j = x ; j >= y ; j += z ) jList.add(j); for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j); List<Long> prodList = new ArrayList<>(); for ( long j : jList ) { sum += Math.abs(j); if ( Math.abs(prod) < pow(2, 27) && j != 0 ) { prodList.add(j); prod *= j; } } System.out.printf(" sum = %,d%n", sum); System.out.printf("prod = %,d%n", prod); System.out.printf("j values = %s%n", jList); System.out.printf("prod values = %s%n", prodList); } private static long pow(long base, long exponent) { return (long) Math.pow(base, exponent); } }
Write the same code in Python as shown below in REXX.
prod= 1; sum= 0; x= +5; y= -5; z= -2; one= 1; three= 3; seven= 7; do j= -three to 3**3 by three ; call meat; end; do j= -seven to seven by x ; call meat; end; do j= 555 to 550 - y ; call meat; end; do j= 22 to -28 by -three ; call meat; end; do j= 1927 to 1939 ; call meat; end; do j= x to y by z ; call meat; end; do j= 11**x to 11**x + one ; call meat; end; say ' sum= ' || commas( sum); say 'prod= ' || commas(prod); exit; commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M") e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4 do j=e to b by -3; _= insert(',', _, j); end; return _ meat: sum= sum + abs(j); if abs(prod)<2**27 & j\==0 then prod= prod * j; return;
from itertools import chain prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7 def _range(x, y, z=1): return range(x, y + (1 if z > 0 else -1), z) print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}') print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}') for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x), _range(555, 550 - y), _range(22, -28, -three), _range(1927, 1939), _range(x, y, z), _range(11**x, 11**x + 1)): sum_ += abs(j) if abs(prod) < 2**27 and (j != 0): prod *= j print(f' sum= {sum_}\nprod= {prod}')
Change the programming language of this snippet from REXX to VB without modifying what it does.
prod= 1; sum= 0; x= +5; y= -5; z= -2; one= 1; three= 3; seven= 7; do j= -three to 3**3 by three ; call meat; end; do j= -seven to seven by x ; call meat; end; do j= 555 to 550 - y ; call meat; end; do j= 22 to -28 by -three ; call meat; end; do j= 1927 to 1939 ; call meat; end; do j= x to y by z ; call meat; end; do j= 11**x to 11**x + one ; call meat; end; say ' sum= ' || commas( sum); say 'prod= ' || commas(prod); exit; commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M") e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4 do j=e to b by -3; _= insert(',', _, j); end; return _ meat: sum= sum + abs(j); if abs(prod)<2**27 & j\==0 then prod= prod * j; return;
Dim prod As Long, sum As Long Public Sub LoopsWithMultipleRanges() Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long prod = 1 sum = 0 x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 For j = -three To pow(3, 3) Step three: Call process(j): Next j For j = -seven To seven Step x: Call process(j): Next j For j = 555 To 550 - y: Call process(j): Next j For j = 22 To -28 Step -three: Call process(j): Next j For j = 1927 To 1939: Call process(j): Next j For j = x To y Step z: Call process(j): Next j For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j Debug.Print " sum= " & Format(sum, "#,##0") Debug.Print "prod= " & Format(prod, "#,##0") End Sub Private Function pow(x As Long, y As Integer) As Long pow = WorksheetFunction.Power(x, y) End Function Private Sub process(x As Long) sum = sum + Abs(x) If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x End Sub
Generate a Go translation of this REXX snippet without changing its computational steps.
prod= 1; sum= 0; x= +5; y= -5; z= -2; one= 1; three= 3; seven= 7; do j= -three to 3**3 by three ; call meat; end; do j= -seven to seven by x ; call meat; end; do j= 555 to 550 - y ; call meat; end; do j= 22 to -28 by -three ; call meat; end; do j= 1927 to 1939 ; call meat; end; do j= x to y by z ; call meat; end; do j= 11**x to 11**x + one ; call meat; end; say ' sum= ' || commas( sum); say 'prod= ' || commas(prod); exit; commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M") e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4 do j=e to b by -3; _= insert(',', _, j); end; return _ meat: sum= sum + abs(j); if abs(prod)<2**27 & j\==0 then prod= prod * j; return;
package main import "fmt" func pow(n int, e uint) int { if e == 0 { return 1 } prod := n for i := uint(2); i <= e; i++ { prod *= n } return prod } func abs(n int) int { if n >= 0 { return n } return -n } func commatize(n int) string { s := fmt.Sprintf("%d", n) if n < 0 { s = s[1:] } le := len(s) for i := le - 3; i >= 1; i -= 3 { s = s[0:i] + "," + s[i:] } if n >= 0 { return " " + s } return "-" + s } func main() { prod := 1 sum := 0 const ( x = 5 y = -5 z = -2 one = 1 three = 3 seven = 7 ) p := pow(11, x) var j int process := func() { sum += abs(j) if abs(prod) < (1<<27) && j != 0 { prod *= j } } for j = -three; j <= pow(3, 3); j += three { process() } for j = -seven; j <= seven; j += x { process() } for j = 555; j <= 550-y; j++ { process() } for j = 22; j >= -28; j -= three { process() } for j = 1927; j <= 1939; j++ { process() } for j = x; j >= y; j -= -z { process() } for j = p; j <= p+one; j++ { process() } fmt.Println("sum = ", commatize(sum)) fmt.Println("prod = ", commatize(prod)) }
Ensure the translated C code behaves exactly like the original Ruby snippet.
x, y, z, one, three, seven = 5, -5, -2, 1, 3, 7 enums = (-three).step(3**3, three) + (-seven).step(seven, x) + 555 .step(550-y, -1) + 22 .step(-28, -three) + (1927..1939) + x .step(y, z) + (11**x) .step(11**x + one) puts "Sum of absolute numbers: prod = enums.inject(1){|prod, j| ((prod.abs < 2**27) && j!=0) ? prod*j : prod} puts "Product (but not really):
#include <stdio.h> #include <stdlib.h> #include <locale.h> long prod = 1L, sum = 0L; void process(int j) { sum += abs(j); if (labs(prod) < (1 << 27) && j) prod *= j; } long ipow(int n, uint e) { long pr = n; int i; if (e == 0) return 1L; for (i = 2; i <= e; ++i) pr *= n; return pr; } int main() { int j; const int x = 5, y = -5, z = -2; const int one = 1, three = 3, seven = 7; long p = ipow(11, x); for (j = -three; j <= ipow(3, 3); j += three) process(j); for (j = -seven; j <= seven; j += x) process(j); for (j = 555; j <= 550 - y; ++j) process(j); for (j = 22; j >= -28; j -= three) process(j); for (j = 1927; j <= 1939; ++j) process(j); for (j = x; j >= y; j -= -z) process(j); for (j = p; j <= p + one; ++j) process(j); setlocale(LC_NUMERIC, ""); printf("sum = % 'ld\n", sum); printf("prod = % 'ld\n", prod); return 0; }