Instruction stringlengths 45 106 | input_code stringlengths 1 13.7k | output_code stringlengths 1 13.7k |
|---|---|---|
Write the same algorithm in Go as shown in this AutoHotKey implementation. | for_J(doFunction, start, stop, step:=1){
j := start
while (j<=stop) && (start<=stop) && (step>0)
%doFunction%(j), j+=step
while (j>=stop) && (start>stop) && (step<0)
%doFunction%(j), j+=step
}
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Can you help me rewrite this code in C instead of AWK, keeping it the same logically? |
BEGIN {
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
for (j=-three; j<=(3^3); j+=three) { main(j) }
for (j=-seven; j<=seven; j+=x) { main(j) }
for (j=555; j<=550-y; j++) { main(j) }
for (j=22; j>=-28; j+=-three) { main(j) }
for (j=1927; j<=1939; j++) { main(j) }
for (j=x; j>=y; j+=z) { main(j) }
for (j=(11^x); j<=(11^x)+1; j++) { main(j) }
printf("sum = %d\n",sum)
printf("prod = %d\n",prod)
exit(0)
}
function main(x) {
sum += abs(x)
if (abs(prod) < (2^27) && x != 0) {
prod *= x
}
}
function abs(x) { if (x >= 0) { return x } else { return -x } }
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Maintain the same structure and functionality when rewriting this code in C#. |
BEGIN {
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
for (j=-three; j<=(3^3); j+=three) { main(j) }
for (j=-seven; j<=seven; j+=x) { main(j) }
for (j=555; j<=550-y; j++) { main(j) }
for (j=22; j>=-28; j+=-three) { main(j) }
for (j=1927; j<=1939; j++) { main(j) }
for (j=x; j>=y; j+=z) { main(j) }
for (j=(11^x); j<=(11^x)+1; j++) { main(j) }
printf("sum = %d\n",sum)
printf("prod = %d\n",prod)
exit(0)
}
function main(x) {
sum += abs(x)
if (abs(prod) < (2^27) && x != 0) {
prod *= x
}
}
function abs(x) { if (x >= 0) { return x } else { return -x } }
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Can you help me rewrite this code in C++ instead of AWK, keeping it the same logically? |
BEGIN {
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
for (j=-three; j<=(3^3); j+=three) { main(j) }
for (j=-seven; j<=seven; j+=x) { main(j) }
for (j=555; j<=550-y; j++) { main(j) }
for (j=22; j>=-28; j+=-three) { main(j) }
for (j=1927; j<=1939; j++) { main(j) }
for (j=x; j>=y; j+=z) { main(j) }
for (j=(11^x); j<=(11^x)+1; j++) { main(j) }
printf("sum = %d\n",sum)
printf("prod = %d\n",prod)
exit(0)
}
function main(x) {
sum += abs(x)
if (abs(prod) < (2^27) && x != 0) {
prod *= x
}
}
function abs(x) { if (x >= 0) { return x } else { return -x } }
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Port the provided AWK code into Java while preserving the original functionality. |
BEGIN {
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
for (j=-three; j<=(3^3); j+=three) { main(j) }
for (j=-seven; j<=seven; j+=x) { main(j) }
for (j=555; j<=550-y; j++) { main(j) }
for (j=22; j>=-28; j+=-three) { main(j) }
for (j=1927; j<=1939; j++) { main(j) }
for (j=x; j>=y; j+=z) { main(j) }
for (j=(11^x); j<=(11^x)+1; j++) { main(j) }
printf("sum = %d\n",sum)
printf("prod = %d\n",prod)
exit(0)
}
function main(x) {
sum += abs(x)
if (abs(prod) < (2^27) && x != 0) {
prod *= x
}
}
function abs(x) { if (x >= 0) { return x } else { return -x } }
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Change the following AWK code into Python without altering its purpose. |
BEGIN {
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
for (j=-three; j<=(3^3); j+=three) { main(j) }
for (j=-seven; j<=seven; j+=x) { main(j) }
for (j=555; j<=550-y; j++) { main(j) }
for (j=22; j>=-28; j+=-three) { main(j) }
for (j=1927; j<=1939; j++) { main(j) }
for (j=x; j>=y; j+=z) { main(j) }
for (j=(11^x); j<=(11^x)+1; j++) { main(j) }
printf("sum = %d\n",sum)
printf("prod = %d\n",prod)
exit(0)
}
function main(x) {
sum += abs(x)
if (abs(prod) < (2^27) && x != 0) {
prod *= x
}
}
function abs(x) { if (x >= 0) { return x } else { return -x } }
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Write a version of this AWK function in VB with identical behavior. |
BEGIN {
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
for (j=-three; j<=(3^3); j+=three) { main(j) }
for (j=-seven; j<=seven; j+=x) { main(j) }
for (j=555; j<=550-y; j++) { main(j) }
for (j=22; j>=-28; j+=-three) { main(j) }
for (j=1927; j<=1939; j++) { main(j) }
for (j=x; j>=y; j+=z) { main(j) }
for (j=(11^x); j<=(11^x)+1; j++) { main(j) }
printf("sum = %d\n",sum)
printf("prod = %d\n",prod)
exit(0)
}
function main(x) {
sum += abs(x)
if (abs(prod) < (2^27) && x != 0) {
prod *= x
}
}
function abs(x) { if (x >= 0) { return x } else { return -x } }
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Change the following AWK code into Go without altering its purpose. |
BEGIN {
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
for (j=-three; j<=(3^3); j+=three) { main(j) }
for (j=-seven; j<=seven; j+=x) { main(j) }
for (j=555; j<=550-y; j++) { main(j) }
for (j=22; j>=-28; j+=-three) { main(j) }
for (j=1927; j<=1939; j++) { main(j) }
for (j=x; j>=y; j+=z) { main(j) }
for (j=(11^x); j<=(11^x)+1; j++) { main(j) }
printf("sum = %d\n",sum)
printf("prod = %d\n",prod)
exit(0)
}
function main(x) {
sum += abs(x)
if (abs(prod) < (2^27) && x != 0) {
prod *= x
}
}
function abs(x) { if (x >= 0) { return x } else { return -x } }
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Write a version of this Common_Lisp function in C with identical behavior. | (let ((prod 1)
(sum 0)
(x 5)
(y -5)
(z -2)
(one 1)
(three 3)
(seven 7))
(flet ((loop-body (j)
(incf sum (abs j))
(if (and (< (abs prod) (expt 2 27))
(/= j 0))
(setf prod (* prod j)))))
(do ((i (- three) (incf i three)))
((> i (expt 3 3)))
(loop-body i))
(do ((i (- seven) (incf i x)))
((> i seven))
(loop-body i))
(do ((i 555 (incf i -1)))
((< i (- 550 y)))
(loop-body i))
(do ((i 22 (incf i (- three))))
((< i -28))
(loop-body i))
(do ((i 1927 (incf i)))
((> i 1939))
(loop-body i))
(do ((i x (incf i z)))
((< i y))
(loop-body i))
(do ((i (expt 11 x) (incf i)))
((> i (+ (expt 11 x) one)))
(loop-body i)))
(format t "~&sum = ~14<~:d~>" sum)
(format t "~&prod = ~14<~:d~>" prod))
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Port the provided Common_Lisp code into C# while preserving the original functionality. | (let ((prod 1)
(sum 0)
(x 5)
(y -5)
(z -2)
(one 1)
(three 3)
(seven 7))
(flet ((loop-body (j)
(incf sum (abs j))
(if (and (< (abs prod) (expt 2 27))
(/= j 0))
(setf prod (* prod j)))))
(do ((i (- three) (incf i three)))
((> i (expt 3 3)))
(loop-body i))
(do ((i (- seven) (incf i x)))
((> i seven))
(loop-body i))
(do ((i 555 (incf i -1)))
((< i (- 550 y)))
(loop-body i))
(do ((i 22 (incf i (- three))))
((< i -28))
(loop-body i))
(do ((i 1927 (incf i)))
((> i 1939))
(loop-body i))
(do ((i x (incf i z)))
((< i y))
(loop-body i))
(do ((i (expt 11 x) (incf i)))
((> i (+ (expt 11 x) one)))
(loop-body i)))
(format t "~&sum = ~14<~:d~>" sum)
(format t "~&prod = ~14<~:d~>" prod))
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Write the same code in C++ as shown below in Common_Lisp. | (let ((prod 1)
(sum 0)
(x 5)
(y -5)
(z -2)
(one 1)
(three 3)
(seven 7))
(flet ((loop-body (j)
(incf sum (abs j))
(if (and (< (abs prod) (expt 2 27))
(/= j 0))
(setf prod (* prod j)))))
(do ((i (- three) (incf i three)))
((> i (expt 3 3)))
(loop-body i))
(do ((i (- seven) (incf i x)))
((> i seven))
(loop-body i))
(do ((i 555 (incf i -1)))
((< i (- 550 y)))
(loop-body i))
(do ((i 22 (incf i (- three))))
((< i -28))
(loop-body i))
(do ((i 1927 (incf i)))
((> i 1939))
(loop-body i))
(do ((i x (incf i z)))
((< i y))
(loop-body i))
(do ((i (expt 11 x) (incf i)))
((> i (+ (expt 11 x) one)))
(loop-body i)))
(format t "~&sum = ~14<~:d~>" sum)
(format t "~&prod = ~14<~:d~>" prod))
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Change the programming language of this snippet from Common_Lisp to Java without modifying what it does. | (let ((prod 1)
(sum 0)
(x 5)
(y -5)
(z -2)
(one 1)
(three 3)
(seven 7))
(flet ((loop-body (j)
(incf sum (abs j))
(if (and (< (abs prod) (expt 2 27))
(/= j 0))
(setf prod (* prod j)))))
(do ((i (- three) (incf i three)))
((> i (expt 3 3)))
(loop-body i))
(do ((i (- seven) (incf i x)))
((> i seven))
(loop-body i))
(do ((i 555 (incf i -1)))
((< i (- 550 y)))
(loop-body i))
(do ((i 22 (incf i (- three))))
((< i -28))
(loop-body i))
(do ((i 1927 (incf i)))
((> i 1939))
(loop-body i))
(do ((i x (incf i z)))
((< i y))
(loop-body i))
(do ((i (expt 11 x) (incf i)))
((> i (+ (expt 11 x) one)))
(loop-body i)))
(format t "~&sum = ~14<~:d~>" sum)
(format t "~&prod = ~14<~:d~>" prod))
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Keep all operations the same but rewrite the snippet in Python. | (let ((prod 1)
(sum 0)
(x 5)
(y -5)
(z -2)
(one 1)
(three 3)
(seven 7))
(flet ((loop-body (j)
(incf sum (abs j))
(if (and (< (abs prod) (expt 2 27))
(/= j 0))
(setf prod (* prod j)))))
(do ((i (- three) (incf i three)))
((> i (expt 3 3)))
(loop-body i))
(do ((i (- seven) (incf i x)))
((> i seven))
(loop-body i))
(do ((i 555 (incf i -1)))
((< i (- 550 y)))
(loop-body i))
(do ((i 22 (incf i (- three))))
((< i -28))
(loop-body i))
(do ((i 1927 (incf i)))
((> i 1939))
(loop-body i))
(do ((i x (incf i z)))
((< i y))
(loop-body i))
(do ((i (expt 11 x) (incf i)))
((> i (+ (expt 11 x) one)))
(loop-body i)))
(format t "~&sum = ~14<~:d~>" sum)
(format t "~&prod = ~14<~:d~>" prod))
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Maintain the same structure and functionality when rewriting this code in VB. | (let ((prod 1)
(sum 0)
(x 5)
(y -5)
(z -2)
(one 1)
(three 3)
(seven 7))
(flet ((loop-body (j)
(incf sum (abs j))
(if (and (< (abs prod) (expt 2 27))
(/= j 0))
(setf prod (* prod j)))))
(do ((i (- three) (incf i three)))
((> i (expt 3 3)))
(loop-body i))
(do ((i (- seven) (incf i x)))
((> i seven))
(loop-body i))
(do ((i 555 (incf i -1)))
((< i (- 550 y)))
(loop-body i))
(do ((i 22 (incf i (- three))))
((< i -28))
(loop-body i))
(do ((i 1927 (incf i)))
((> i 1939))
(loop-body i))
(do ((i x (incf i z)))
((< i y))
(loop-body i))
(do ((i (expt 11 x) (incf i)))
((> i (+ (expt 11 x) one)))
(loop-body i)))
(format t "~&sum = ~14<~:d~>" sum)
(format t "~&prod = ~14<~:d~>" prod))
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Write the same algorithm in Go as shown in this Common_Lisp implementation. | (let ((prod 1)
(sum 0)
(x 5)
(y -5)
(z -2)
(one 1)
(three 3)
(seven 7))
(flet ((loop-body (j)
(incf sum (abs j))
(if (and (< (abs prod) (expt 2 27))
(/= j 0))
(setf prod (* prod j)))))
(do ((i (- three) (incf i three)))
((> i (expt 3 3)))
(loop-body i))
(do ((i (- seven) (incf i x)))
((> i seven))
(loop-body i))
(do ((i 555 (incf i -1)))
((< i (- 550 y)))
(loop-body i))
(do ((i 22 (incf i (- three))))
((< i -28))
(loop-body i))
(do ((i 1927 (incf i)))
((> i 1939))
(loop-body i))
(do ((i x (incf i z)))
((< i y))
(loop-body i))
(do ((i (expt 11 x) (incf i)))
((> i (+ (expt 11 x) one)))
(loop-body i)))
(format t "~&sum = ~14<~:d~>" sum)
(format t "~&prod = ~14<~:d~>" prod))
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Rewrite this program in C while keeping its functionality equivalent to the Delphi version. | program with_multiple_ranges;
uses
System.SysUtils;
var
prod: Int64 = 1;
sum: Int64 = 0;
function labs(value: Int64): Int64;
begin
Result := value;
if value < 0 then
Result := -Result;
end;
procedure process(j: Int64);
begin
sum := sum + (abs(j));
if (labs(prod) < (1 shl 27)) and (j <> 0) then
prod := prod * j;
end;
function ipow(n: Integer; e: Cardinal): Int64;
var
pr: Int64;
max, i: Cardinal;
begin
result := n;
if e = 0 then
Exit(1);
max := e;
for i := 2 to max do
result := result * n;
end;
var
j: Int64;
p: Int64;
const
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
begin
p := ipow(11, x);
j := -three;
while j <= ipow(3, 3) do
begin
process(j);
inc(j, three);
end;
j := -seven;
while j <= seven do
begin
process(j);
inc(j, x);
end;
j := 555;
while j <= (550 - y) do
begin
process(j);
inc(j, x);
end;
j := 22;
while j >= -28 do
begin
process(j);
dec(j, three);
end;
j := 1927;
while j <= 1939 do
begin
process(j);
inc(j);
end;
j := x;
while j >= y do
begin
process(j);
dec(j, -z);
end;
j := p;
while j <= p + one do
begin
process(j);
inc(j);
end;
writeln(format('sum = %d ', [sum]));
writeln(format('prod = %d ', [prod]));
Readln;
end.
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Convert this Delphi snippet to C# and keep its semantics consistent. | program with_multiple_ranges;
uses
System.SysUtils;
var
prod: Int64 = 1;
sum: Int64 = 0;
function labs(value: Int64): Int64;
begin
Result := value;
if value < 0 then
Result := -Result;
end;
procedure process(j: Int64);
begin
sum := sum + (abs(j));
if (labs(prod) < (1 shl 27)) and (j <> 0) then
prod := prod * j;
end;
function ipow(n: Integer; e: Cardinal): Int64;
var
pr: Int64;
max, i: Cardinal;
begin
result := n;
if e = 0 then
Exit(1);
max := e;
for i := 2 to max do
result := result * n;
end;
var
j: Int64;
p: Int64;
const
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
begin
p := ipow(11, x);
j := -three;
while j <= ipow(3, 3) do
begin
process(j);
inc(j, three);
end;
j := -seven;
while j <= seven do
begin
process(j);
inc(j, x);
end;
j := 555;
while j <= (550 - y) do
begin
process(j);
inc(j, x);
end;
j := 22;
while j >= -28 do
begin
process(j);
dec(j, three);
end;
j := 1927;
while j <= 1939 do
begin
process(j);
inc(j);
end;
j := x;
while j >= y do
begin
process(j);
dec(j, -z);
end;
j := p;
while j <= p + one do
begin
process(j);
inc(j);
end;
writeln(format('sum = %d ', [sum]));
writeln(format('prod = %d ', [prod]));
Readln;
end.
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Translate this program into C++ but keep the logic exactly as in Delphi. | program with_multiple_ranges;
uses
System.SysUtils;
var
prod: Int64 = 1;
sum: Int64 = 0;
function labs(value: Int64): Int64;
begin
Result := value;
if value < 0 then
Result := -Result;
end;
procedure process(j: Int64);
begin
sum := sum + (abs(j));
if (labs(prod) < (1 shl 27)) and (j <> 0) then
prod := prod * j;
end;
function ipow(n: Integer; e: Cardinal): Int64;
var
pr: Int64;
max, i: Cardinal;
begin
result := n;
if e = 0 then
Exit(1);
max := e;
for i := 2 to max do
result := result * n;
end;
var
j: Int64;
p: Int64;
const
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
begin
p := ipow(11, x);
j := -three;
while j <= ipow(3, 3) do
begin
process(j);
inc(j, three);
end;
j := -seven;
while j <= seven do
begin
process(j);
inc(j, x);
end;
j := 555;
while j <= (550 - y) do
begin
process(j);
inc(j, x);
end;
j := 22;
while j >= -28 do
begin
process(j);
dec(j, three);
end;
j := 1927;
while j <= 1939 do
begin
process(j);
inc(j);
end;
j := x;
while j >= y do
begin
process(j);
dec(j, -z);
end;
j := p;
while j <= p + one do
begin
process(j);
inc(j);
end;
writeln(format('sum = %d ', [sum]));
writeln(format('prod = %d ', [prod]));
Readln;
end.
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Generate an equivalent Java version of this Delphi code. | program with_multiple_ranges;
uses
System.SysUtils;
var
prod: Int64 = 1;
sum: Int64 = 0;
function labs(value: Int64): Int64;
begin
Result := value;
if value < 0 then
Result := -Result;
end;
procedure process(j: Int64);
begin
sum := sum + (abs(j));
if (labs(prod) < (1 shl 27)) and (j <> 0) then
prod := prod * j;
end;
function ipow(n: Integer; e: Cardinal): Int64;
var
pr: Int64;
max, i: Cardinal;
begin
result := n;
if e = 0 then
Exit(1);
max := e;
for i := 2 to max do
result := result * n;
end;
var
j: Int64;
p: Int64;
const
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
begin
p := ipow(11, x);
j := -three;
while j <= ipow(3, 3) do
begin
process(j);
inc(j, three);
end;
j := -seven;
while j <= seven do
begin
process(j);
inc(j, x);
end;
j := 555;
while j <= (550 - y) do
begin
process(j);
inc(j, x);
end;
j := 22;
while j >= -28 do
begin
process(j);
dec(j, three);
end;
j := 1927;
while j <= 1939 do
begin
process(j);
inc(j);
end;
j := x;
while j >= y do
begin
process(j);
dec(j, -z);
end;
j := p;
while j <= p + one do
begin
process(j);
inc(j);
end;
writeln(format('sum = %d ', [sum]));
writeln(format('prod = %d ', [prod]));
Readln;
end.
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Preserve the algorithm and functionality while converting the code from Delphi to Python. | program with_multiple_ranges;
uses
System.SysUtils;
var
prod: Int64 = 1;
sum: Int64 = 0;
function labs(value: Int64): Int64;
begin
Result := value;
if value < 0 then
Result := -Result;
end;
procedure process(j: Int64);
begin
sum := sum + (abs(j));
if (labs(prod) < (1 shl 27)) and (j <> 0) then
prod := prod * j;
end;
function ipow(n: Integer; e: Cardinal): Int64;
var
pr: Int64;
max, i: Cardinal;
begin
result := n;
if e = 0 then
Exit(1);
max := e;
for i := 2 to max do
result := result * n;
end;
var
j: Int64;
p: Int64;
const
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
begin
p := ipow(11, x);
j := -three;
while j <= ipow(3, 3) do
begin
process(j);
inc(j, three);
end;
j := -seven;
while j <= seven do
begin
process(j);
inc(j, x);
end;
j := 555;
while j <= (550 - y) do
begin
process(j);
inc(j, x);
end;
j := 22;
while j >= -28 do
begin
process(j);
dec(j, three);
end;
j := 1927;
while j <= 1939 do
begin
process(j);
inc(j);
end;
j := x;
while j >= y do
begin
process(j);
dec(j, -z);
end;
j := p;
while j <= p + one do
begin
process(j);
inc(j);
end;
writeln(format('sum = %d ', [sum]));
writeln(format('prod = %d ', [prod]));
Readln;
end.
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Keep all operations the same but rewrite the snippet in VB. | program with_multiple_ranges;
uses
System.SysUtils;
var
prod: Int64 = 1;
sum: Int64 = 0;
function labs(value: Int64): Int64;
begin
Result := value;
if value < 0 then
Result := -Result;
end;
procedure process(j: Int64);
begin
sum := sum + (abs(j));
if (labs(prod) < (1 shl 27)) and (j <> 0) then
prod := prod * j;
end;
function ipow(n: Integer; e: Cardinal): Int64;
var
pr: Int64;
max, i: Cardinal;
begin
result := n;
if e = 0 then
Exit(1);
max := e;
for i := 2 to max do
result := result * n;
end;
var
j: Int64;
p: Int64;
const
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
begin
p := ipow(11, x);
j := -three;
while j <= ipow(3, 3) do
begin
process(j);
inc(j, three);
end;
j := -seven;
while j <= seven do
begin
process(j);
inc(j, x);
end;
j := 555;
while j <= (550 - y) do
begin
process(j);
inc(j, x);
end;
j := 22;
while j >= -28 do
begin
process(j);
dec(j, three);
end;
j := 1927;
while j <= 1939 do
begin
process(j);
inc(j);
end;
j := x;
while j >= y do
begin
process(j);
dec(j, -z);
end;
j := p;
while j <= p + one do
begin
process(j);
inc(j);
end;
writeln(format('sum = %d ', [sum]));
writeln(format('prod = %d ', [prod]));
Readln;
end.
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Write the same code in Go as shown below in Delphi. | program with_multiple_ranges;
uses
System.SysUtils;
var
prod: Int64 = 1;
sum: Int64 = 0;
function labs(value: Int64): Int64;
begin
Result := value;
if value < 0 then
Result := -Result;
end;
procedure process(j: Int64);
begin
sum := sum + (abs(j));
if (labs(prod) < (1 shl 27)) and (j <> 0) then
prod := prod * j;
end;
function ipow(n: Integer; e: Cardinal): Int64;
var
pr: Int64;
max, i: Cardinal;
begin
result := n;
if e = 0 then
Exit(1);
max := e;
for i := 2 to max do
result := result * n;
end;
var
j: Int64;
p: Int64;
const
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
begin
p := ipow(11, x);
j := -three;
while j <= ipow(3, 3) do
begin
process(j);
inc(j, three);
end;
j := -seven;
while j <= seven do
begin
process(j);
inc(j, x);
end;
j := 555;
while j <= (550 - y) do
begin
process(j);
inc(j, x);
end;
j := 22;
while j >= -28 do
begin
process(j);
dec(j, three);
end;
j := 1927;
while j <= 1939 do
begin
process(j);
inc(j);
end;
j := x;
while j >= y do
begin
process(j);
dec(j, -z);
end;
j := p;
while j <= p + one do
begin
process(j);
inc(j);
end;
writeln(format('sum = %d ', [sum]));
writeln(format('prod = %d ', [prod]));
Readln;
end.
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Change the programming language of this snippet from F# to C without modifying what it does. |
let x,y,z,one,three,seven=5,-5,-2,1,3,7
let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1]
printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Convert this F# snippet to C# and keep its semantics consistent. |
let x,y,z,one,three,seven=5,-5,-2,1,3,7
let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1]
printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Write a version of this F# function in C++ with identical behavior. |
let x,y,z,one,three,seven=5,-5,-2,1,3,7
let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1]
printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Write the same algorithm in Java as shown in this F# implementation. |
let x,y,z,one,three,seven=5,-5,-2,1,3,7
let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1]
printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Translate this program into Python but keep the logic exactly as in F#. |
let x,y,z,one,three,seven=5,-5,-2,1,3,7
let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1]
printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Change the following F# code into VB without altering its purpose. |
let x,y,z,one,three,seven=5,-5,-2,1,3,7
let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1]
printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Preserve the algorithm and functionality while converting the code from F# to Go. |
let x,y,z,one,three,seven=5,-5,-2,1,3,7
let Range=[-three..three..pown 3 3]@[-7..x..seven]@[555..550-y]@[22..-three.. -28]@[1927..1939]@[x..z..y]@[pown 11 x..(pown 11 x)+1]
printfn "Sum=%d Product=%d" (Range|>Seq.sumBy(abs)) (Range|>Seq.filter((<>)0)|>Seq.fold(fun n g->if abs n<pown 2 27 then n*g else n) 1)
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Port the provided Factor code into C while preserving the original functionality. | USING: formatting kernel locals math math.functions math.ranges
sequences sequences.generalizations tools.memory.private ;
[let
1 :> prod
0 :> sum
5 :> x
-5 :> y
-2 :> z
1 :> one
3 :> three
7 :> seven
three neg 3 3 ^ three <range>
seven neg seven x <range>
555 550 y - [a,b]
22 -28 three neg <range>
1927 1939 [a,b]
x y z <range>
11 x ^ 11 x ^ 1 + [a,b] 7 narray
[
[
:> j j abs sum + sum
prod abs 2 27 ^ < j zero? not and
[ prod j * prod
] each
] each
sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf
]
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Write the same algorithm in C# as shown in this Factor implementation. | USING: formatting kernel locals math math.functions math.ranges
sequences sequences.generalizations tools.memory.private ;
[let
1 :> prod
0 :> sum
5 :> x
-5 :> y
-2 :> z
1 :> one
3 :> three
7 :> seven
three neg 3 3 ^ three <range>
seven neg seven x <range>
555 550 y - [a,b]
22 -28 three neg <range>
1927 1939 [a,b]
x y z <range>
11 x ^ 11 x ^ 1 + [a,b] 7 narray
[
[
:> j j abs sum + sum
prod abs 2 27 ^ < j zero? not and
[ prod j * prod
] each
] each
sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf
]
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Rewrite the snippet below in C++ so it works the same as the original Factor code. | USING: formatting kernel locals math math.functions math.ranges
sequences sequences.generalizations tools.memory.private ;
[let
1 :> prod
0 :> sum
5 :> x
-5 :> y
-2 :> z
1 :> one
3 :> three
7 :> seven
three neg 3 3 ^ three <range>
seven neg seven x <range>
555 550 y - [a,b]
22 -28 three neg <range>
1927 1939 [a,b]
x y z <range>
11 x ^ 11 x ^ 1 + [a,b] 7 narray
[
[
:> j j abs sum + sum
prod abs 2 27 ^ < j zero? not and
[ prod j * prod
] each
] each
sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf
]
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Write the same code in Java as shown below in Factor. | USING: formatting kernel locals math math.functions math.ranges
sequences sequences.generalizations tools.memory.private ;
[let
1 :> prod
0 :> sum
5 :> x
-5 :> y
-2 :> z
1 :> one
3 :> three
7 :> seven
three neg 3 3 ^ three <range>
seven neg seven x <range>
555 550 y - [a,b]
22 -28 three neg <range>
1927 1939 [a,b]
x y z <range>
11 x ^ 11 x ^ 1 + [a,b] 7 narray
[
[
:> j j abs sum + sum
prod abs 2 27 ^ < j zero? not and
[ prod j * prod
] each
] each
sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf
]
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Change the programming language of this snippet from Factor to Python without modifying what it does. | USING: formatting kernel locals math math.functions math.ranges
sequences sequences.generalizations tools.memory.private ;
[let
1 :> prod
0 :> sum
5 :> x
-5 :> y
-2 :> z
1 :> one
3 :> three
7 :> seven
three neg 3 3 ^ three <range>
seven neg seven x <range>
555 550 y - [a,b]
22 -28 three neg <range>
1927 1939 [a,b]
x y z <range>
11 x ^ 11 x ^ 1 + [a,b] 7 narray
[
[
:> j j abs sum + sum
prod abs 2 27 ^ < j zero? not and
[ prod j * prod
] each
] each
sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf
]
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Change the programming language of this snippet from Factor to VB without modifying what it does. | USING: formatting kernel locals math math.functions math.ranges
sequences sequences.generalizations tools.memory.private ;
[let
1 :> prod
0 :> sum
5 :> x
-5 :> y
-2 :> z
1 :> one
3 :> three
7 :> seven
three neg 3 3 ^ three <range>
seven neg seven x <range>
555 550 y - [a,b]
22 -28 three neg <range>
1927 1939 [a,b]
x y z <range>
11 x ^ 11 x ^ 1 + [a,b] 7 narray
[
[
:> j j abs sum + sum
prod abs 2 27 ^ < j zero? not and
[ prod j * prod
] each
] each
sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf
]
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Convert this Factor snippet to Go and keep its semantics consistent. | USING: formatting kernel locals math math.functions math.ranges
sequences sequences.generalizations tools.memory.private ;
[let
1 :> prod
0 :> sum
5 :> x
-5 :> y
-2 :> z
1 :> one
3 :> three
7 :> seven
three neg 3 3 ^ three <range>
seven neg seven x <range>
555 550 y - [a,b]
22 -28 three neg <range>
1927 1939 [a,b]
x y z <range>
11 x ^ 11 x ^ 1 + [a,b] 7 narray
[
[
:> j j abs sum + sum
prod abs 2 27 ^ < j zero? not and
[ prod j * prod
] each
] each
sum prod [ commas ] bi@ " sum= %s\nprod= %s\n" printf
]
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Ensure the translated C code behaves exactly like the original Groovy snippet. | def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7]
for (
j in (
((-three) .. (3**3) ).step(three)
+ ((-seven) .. (+seven) ).step(x)
+ (555 .. (550-y) )
+ (22 .. (-28) ).step(three)
+ (1927 .. 1939 )
+ (x .. y ).step(z)
+ (11**x .. (11**x + one))
)
) {
sum = sum + j.abs()
if ( prod.abs() < 2**27 && j != 0) prod *= j
}
println " sum= ${sum}"
println "prod= ${prod}"
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Change the following Groovy code into C# without altering its purpose. | def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7]
for (
j in (
((-three) .. (3**3) ).step(three)
+ ((-seven) .. (+seven) ).step(x)
+ (555 .. (550-y) )
+ (22 .. (-28) ).step(three)
+ (1927 .. 1939 )
+ (x .. y ).step(z)
+ (11**x .. (11**x + one))
)
) {
sum = sum + j.abs()
if ( prod.abs() < 2**27 && j != 0) prod *= j
}
println " sum= ${sum}"
println "prod= ${prod}"
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Port the provided Groovy code into C++ while preserving the original functionality. | def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7]
for (
j in (
((-three) .. (3**3) ).step(three)
+ ((-seven) .. (+seven) ).step(x)
+ (555 .. (550-y) )
+ (22 .. (-28) ).step(three)
+ (1927 .. 1939 )
+ (x .. y ).step(z)
+ (11**x .. (11**x + one))
)
) {
sum = sum + j.abs()
if ( prod.abs() < 2**27 && j != 0) prod *= j
}
println " sum= ${sum}"
println "prod= ${prod}"
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Convert this Groovy block to Java, preserving its control flow and logic. | def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7]
for (
j in (
((-three) .. (3**3) ).step(three)
+ ((-seven) .. (+seven) ).step(x)
+ (555 .. (550-y) )
+ (22 .. (-28) ).step(three)
+ (1927 .. 1939 )
+ (x .. y ).step(z)
+ (11**x .. (11**x + one))
)
) {
sum = sum + j.abs()
if ( prod.abs() < 2**27 && j != 0) prod *= j
}
println " sum= ${sum}"
println "prod= ${prod}"
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Keep all operations the same but rewrite the snippet in Python. | def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7]
for (
j in (
((-three) .. (3**3) ).step(three)
+ ((-seven) .. (+seven) ).step(x)
+ (555 .. (550-y) )
+ (22 .. (-28) ).step(three)
+ (1927 .. 1939 )
+ (x .. y ).step(z)
+ (11**x .. (11**x + one))
)
) {
sum = sum + j.abs()
if ( prod.abs() < 2**27 && j != 0) prod *= j
}
println " sum= ${sum}"
println "prod= ${prod}"
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Can you help me rewrite this code in VB instead of Groovy, keeping it the same logically? | def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7]
for (
j in (
((-three) .. (3**3) ).step(three)
+ ((-seven) .. (+seven) ).step(x)
+ (555 .. (550-y) )
+ (22 .. (-28) ).step(three)
+ (1927 .. 1939 )
+ (x .. y ).step(z)
+ (11**x .. (11**x + one))
)
) {
sum = sum + j.abs()
if ( prod.abs() < 2**27 && j != 0) prod *= j
}
println " sum= ${sum}"
println "prod= ${prod}"
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Produce a language-to-language conversion: from Groovy to Go, same semantics. | def (prod, sum, x, y, z, one, three, seven) = [1, 0, +5, -5, -2, 1, 3, 7]
for (
j in (
((-three) .. (3**3) ).step(three)
+ ((-seven) .. (+seven) ).step(x)
+ (555 .. (550-y) )
+ (22 .. (-28) ).step(three)
+ (1927 .. 1939 )
+ (x .. y ).step(z)
+ (11**x .. (11**x + one))
)
) {
sum = sum + j.abs()
if ( prod.abs() < 2**27 && j != 0) prod *= j
}
println " sum= ${sum}"
println "prod= ${prod}"
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Produce a functionally identical C code for the snippet given in Haskell. | loop :: (b -> a -> b) -> b -> [[a]] -> b
loop = foldl . foldl
example = let
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
in
loop
(
\(sum, prod) j ->
(
sum + abs j,
if abs prod < 2^27 && j /= 0
then prod * j else prod
)
)
(0, 1)
[ [-three, -three + three .. 3^3]
, [-seven, -seven + x .. seven]
, [555 .. 550 - y]
, [22, 22 - three .. -28]
, [1927 .. 1939]
, [x, x + z .. y]
, [11^x .. 11^x + one] ]
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Ensure the translated C# code behaves exactly like the original Haskell snippet. | loop :: (b -> a -> b) -> b -> [[a]] -> b
loop = foldl . foldl
example = let
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
in
loop
(
\(sum, prod) j ->
(
sum + abs j,
if abs prod < 2^27 && j /= 0
then prod * j else prod
)
)
(0, 1)
[ [-three, -three + three .. 3^3]
, [-seven, -seven + x .. seven]
, [555 .. 550 - y]
, [22, 22 - three .. -28]
, [1927 .. 1939]
, [x, x + z .. y]
, [11^x .. 11^x + one] ]
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Translate this program into C++ but keep the logic exactly as in Haskell. | loop :: (b -> a -> b) -> b -> [[a]] -> b
loop = foldl . foldl
example = let
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
in
loop
(
\(sum, prod) j ->
(
sum + abs j,
if abs prod < 2^27 && j /= 0
then prod * j else prod
)
)
(0, 1)
[ [-three, -three + three .. 3^3]
, [-seven, -seven + x .. seven]
, [555 .. 550 - y]
, [22, 22 - three .. -28]
, [1927 .. 1939]
, [x, x + z .. y]
, [11^x .. 11^x + one] ]
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Ensure the translated Java code behaves exactly like the original Haskell snippet. | loop :: (b -> a -> b) -> b -> [[a]] -> b
loop = foldl . foldl
example = let
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
in
loop
(
\(sum, prod) j ->
(
sum + abs j,
if abs prod < 2^27 && j /= 0
then prod * j else prod
)
)
(0, 1)
[ [-three, -three + three .. 3^3]
, [-seven, -seven + x .. seven]
, [555 .. 550 - y]
, [22, 22 - three .. -28]
, [1927 .. 1939]
, [x, x + z .. y]
, [11^x .. 11^x + one] ]
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Write a version of this Haskell function in Python with identical behavior. | loop :: (b -> a -> b) -> b -> [[a]] -> b
loop = foldl . foldl
example = let
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
in
loop
(
\(sum, prod) j ->
(
sum + abs j,
if abs prod < 2^27 && j /= 0
then prod * j else prod
)
)
(0, 1)
[ [-three, -three + three .. 3^3]
, [-seven, -seven + x .. seven]
, [555 .. 550 - y]
, [22, 22 - three .. -28]
, [1927 .. 1939]
, [x, x + z .. y]
, [11^x .. 11^x + one] ]
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Can you help me rewrite this code in VB instead of Haskell, keeping it the same logically? | loop :: (b -> a -> b) -> b -> [[a]] -> b
loop = foldl . foldl
example = let
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
in
loop
(
\(sum, prod) j ->
(
sum + abs j,
if abs prod < 2^27 && j /= 0
then prod * j else prod
)
)
(0, 1)
[ [-three, -three + three .. 3^3]
, [-seven, -seven + x .. seven]
, [555 .. 550 - y]
, [22, 22 - three .. -28]
, [1927 .. 1939]
, [x, x + z .. y]
, [11^x .. 11^x + one] ]
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Maintain the same structure and functionality when rewriting this code in Go. | loop :: (b -> a -> b) -> b -> [[a]] -> b
loop = foldl . foldl
example = let
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
in
loop
(
\(sum, prod) j ->
(
sum + abs j,
if abs prod < 2^27 && j /= 0
then prod * j else prod
)
)
(0, 1)
[ [-three, -three + three .. 3^3]
, [-seven, -seven + x .. seven]
, [555 .. 550 - y]
, [22, 22 - three .. -28]
, [1927 .. 1939]
, [x, x + z .. y]
, [11^x .. 11^x + one] ]
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Change the following J code into C without altering its purpose. | TO=: {{
'N M'=. 2{.y,1
x:x+M*i.>.(1+N-x)%M
}}
BY=: ,
{{
PROD=: 1
SUM=: 0
X=: +5
Y=: -5
Z=: -2
ONE=: 1
THREE=: 3
SEVEN=: 7
for_J. ;do >cutLF {{)n
< (-THREE) TO (3^3) BY THREE
< (-SEVEN) TO (+SEVEN) BY X
< 555 TO 550-Y
< 22 TO _28 BY -THREE
< 1927 TO 1939
< X TO Y BY Z
< (11^X) TO (11^X) + ONE
}} do.
SUM=: SUM+|J
if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end.
end.
echo ' SUM= ',":SUM
echo 'PROD= ',":PROD
}}0
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Translate the given J code snippet into C# without altering its behavior. | TO=: {{
'N M'=. 2{.y,1
x:x+M*i.>.(1+N-x)%M
}}
BY=: ,
{{
PROD=: 1
SUM=: 0
X=: +5
Y=: -5
Z=: -2
ONE=: 1
THREE=: 3
SEVEN=: 7
for_J. ;do >cutLF {{)n
< (-THREE) TO (3^3) BY THREE
< (-SEVEN) TO (+SEVEN) BY X
< 555 TO 550-Y
< 22 TO _28 BY -THREE
< 1927 TO 1939
< X TO Y BY Z
< (11^X) TO (11^X) + ONE
}} do.
SUM=: SUM+|J
if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end.
end.
echo ' SUM= ',":SUM
echo 'PROD= ',":PROD
}}0
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Port the following code from J to C++ with equivalent syntax and logic. | TO=: {{
'N M'=. 2{.y,1
x:x+M*i.>.(1+N-x)%M
}}
BY=: ,
{{
PROD=: 1
SUM=: 0
X=: +5
Y=: -5
Z=: -2
ONE=: 1
THREE=: 3
SEVEN=: 7
for_J. ;do >cutLF {{)n
< (-THREE) TO (3^3) BY THREE
< (-SEVEN) TO (+SEVEN) BY X
< 555 TO 550-Y
< 22 TO _28 BY -THREE
< 1927 TO 1939
< X TO Y BY Z
< (11^X) TO (11^X) + ONE
}} do.
SUM=: SUM+|J
if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end.
end.
echo ' SUM= ',":SUM
echo 'PROD= ',":PROD
}}0
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Produce a language-to-language conversion: from J to Java, same semantics. | TO=: {{
'N M'=. 2{.y,1
x:x+M*i.>.(1+N-x)%M
}}
BY=: ,
{{
PROD=: 1
SUM=: 0
X=: +5
Y=: -5
Z=: -2
ONE=: 1
THREE=: 3
SEVEN=: 7
for_J. ;do >cutLF {{)n
< (-THREE) TO (3^3) BY THREE
< (-SEVEN) TO (+SEVEN) BY X
< 555 TO 550-Y
< 22 TO _28 BY -THREE
< 1927 TO 1939
< X TO Y BY Z
< (11^X) TO (11^X) + ONE
}} do.
SUM=: SUM+|J
if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end.
end.
echo ' SUM= ',":SUM
echo 'PROD= ',":PROD
}}0
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Ensure the translated Python code behaves exactly like the original J snippet. | TO=: {{
'N M'=. 2{.y,1
x:x+M*i.>.(1+N-x)%M
}}
BY=: ,
{{
PROD=: 1
SUM=: 0
X=: +5
Y=: -5
Z=: -2
ONE=: 1
THREE=: 3
SEVEN=: 7
for_J. ;do >cutLF {{)n
< (-THREE) TO (3^3) BY THREE
< (-SEVEN) TO (+SEVEN) BY X
< 555 TO 550-Y
< 22 TO _28 BY -THREE
< 1927 TO 1939
< X TO Y BY Z
< (11^X) TO (11^X) + ONE
}} do.
SUM=: SUM+|J
if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end.
end.
echo ' SUM= ',":SUM
echo 'PROD= ',":PROD
}}0
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Please provide an equivalent version of this J code in VB. | TO=: {{
'N M'=. 2{.y,1
x:x+M*i.>.(1+N-x)%M
}}
BY=: ,
{{
PROD=: 1
SUM=: 0
X=: +5
Y=: -5
Z=: -2
ONE=: 1
THREE=: 3
SEVEN=: 7
for_J. ;do >cutLF {{)n
< (-THREE) TO (3^3) BY THREE
< (-SEVEN) TO (+SEVEN) BY X
< 555 TO 550-Y
< 22 TO _28 BY -THREE
< 1927 TO 1939
< X TO Y BY Z
< (11^X) TO (11^X) + ONE
}} do.
SUM=: SUM+|J
if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end.
end.
echo ' SUM= ',":SUM
echo 'PROD= ',":PROD
}}0
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Change the programming language of this snippet from J to Go without modifying what it does. | TO=: {{
'N M'=. 2{.y,1
x:x+M*i.>.(1+N-x)%M
}}
BY=: ,
{{
PROD=: 1
SUM=: 0
X=: +5
Y=: -5
Z=: -2
ONE=: 1
THREE=: 3
SEVEN=: 7
for_J. ;do >cutLF {{)n
< (-THREE) TO (3^3) BY THREE
< (-SEVEN) TO (+SEVEN) BY X
< 555 TO 550-Y
< 22 TO _28 BY -THREE
< 1927 TO 1939
< X TO Y BY Z
< (11^X) TO (11^X) + ONE
}} do.
SUM=: SUM+|J
if. ((|PROD)<2^27) * J~:0 do. PROD=: PROD*J end.
end.
echo ' SUM= ',":SUM
echo 'PROD= ',":PROD
}}0
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Rewrite the snippet below in C so it works the same as the original Julia code. | using Formatting
function PL1example()
prod = 1;
sum = 0;
x = +5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
for j in [ -three : three : 3^3 ;
-seven : x : +seven ;
555 : 550 - y ;
22 : -three : -28 ;
1927 : 1939 ;
x : z : y ;
11^x : 11^x + one ]
sum = sum + abs(j);
if abs(prod) < 2^27 && j !=0 prod = prod*j
end;
end
println(" sum = $(format(sum, commas=true))");
println("prod = $(format(prod, commas=true))");
end
PL1example()
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Ensure the translated C# code behaves exactly like the original Julia snippet. | using Formatting
function PL1example()
prod = 1;
sum = 0;
x = +5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
for j in [ -three : three : 3^3 ;
-seven : x : +seven ;
555 : 550 - y ;
22 : -three : -28 ;
1927 : 1939 ;
x : z : y ;
11^x : 11^x + one ]
sum = sum + abs(j);
if abs(prod) < 2^27 && j !=0 prod = prod*j
end;
end
println(" sum = $(format(sum, commas=true))");
println("prod = $(format(prod, commas=true))");
end
PL1example()
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Write a version of this Julia function in C++ with identical behavior. | using Formatting
function PL1example()
prod = 1;
sum = 0;
x = +5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
for j in [ -three : three : 3^3 ;
-seven : x : +seven ;
555 : 550 - y ;
22 : -three : -28 ;
1927 : 1939 ;
x : z : y ;
11^x : 11^x + one ]
sum = sum + abs(j);
if abs(prod) < 2^27 && j !=0 prod = prod*j
end;
end
println(" sum = $(format(sum, commas=true))");
println("prod = $(format(prod, commas=true))");
end
PL1example()
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Can you help me rewrite this code in Java instead of Julia, keeping it the same logically? | using Formatting
function PL1example()
prod = 1;
sum = 0;
x = +5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
for j in [ -three : three : 3^3 ;
-seven : x : +seven ;
555 : 550 - y ;
22 : -three : -28 ;
1927 : 1939 ;
x : z : y ;
11^x : 11^x + one ]
sum = sum + abs(j);
if abs(prod) < 2^27 && j !=0 prod = prod*j
end;
end
println(" sum = $(format(sum, commas=true))");
println("prod = $(format(prod, commas=true))");
end
PL1example()
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Keep all operations the same but rewrite the snippet in Python. | using Formatting
function PL1example()
prod = 1;
sum = 0;
x = +5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
for j in [ -three : three : 3^3 ;
-seven : x : +seven ;
555 : 550 - y ;
22 : -three : -28 ;
1927 : 1939 ;
x : z : y ;
11^x : 11^x + one ]
sum = sum + abs(j);
if abs(prod) < 2^27 && j !=0 prod = prod*j
end;
end
println(" sum = $(format(sum, commas=true))");
println("prod = $(format(prod, commas=true))");
end
PL1example()
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Transform the following Julia implementation into VB, maintaining the same output and logic. | using Formatting
function PL1example()
prod = 1;
sum = 0;
x = +5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
for j in [ -three : three : 3^3 ;
-seven : x : +seven ;
555 : 550 - y ;
22 : -three : -28 ;
1927 : 1939 ;
x : z : y ;
11^x : 11^x + one ]
sum = sum + abs(j);
if abs(prod) < 2^27 && j !=0 prod = prod*j
end;
end
println(" sum = $(format(sum, commas=true))");
println("prod = $(format(prod, commas=true))");
end
PL1example()
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Write a version of this Julia function in Go with identical behavior. | using Formatting
function PL1example()
prod = 1;
sum = 0;
x = +5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
for j in [ -three : three : 3^3 ;
-seven : x : +seven ;
555 : 550 - y ;
22 : -three : -28 ;
1927 : 1939 ;
x : z : y ;
11^x : 11^x + one ]
sum = sum + abs(j);
if abs(prod) < 2^27 && j !=0 prod = prod*j
end;
end
println(" sum = $(format(sum, commas=true))");
println("prod = $(format(prod, commas=true))");
end
PL1example()
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Maintain the same structure and functionality when rewriting this code in C. |
function T(t) return setmetatable(t, {__index=table}) end
table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end
table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end
table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end
unpack = unpack or table.unpack
function mrl(tt)
local s=T{}
for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end
return ipairs(s)
end
prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7
for _,j in mrl{
{ -three, 3^3, three },
{ -seven, seven, x },
{ 555, 550-y },
{ 22, -28, -three },
{ 1927, 1939 },
{ x, y, z },
{ 11^x, 11^x+1 }} do
sum = sum + math.abs(j)
if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end
end
print(" sum= " .. sum)
print("prod= " .. prod)
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Change the following Lua code into C# without altering its purpose. |
function T(t) return setmetatable(t, {__index=table}) end
table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end
table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end
table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end
unpack = unpack or table.unpack
function mrl(tt)
local s=T{}
for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end
return ipairs(s)
end
prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7
for _,j in mrl{
{ -three, 3^3, three },
{ -seven, seven, x },
{ 555, 550-y },
{ 22, -28, -three },
{ 1927, 1939 },
{ x, y, z },
{ 11^x, 11^x+1 }} do
sum = sum + math.abs(j)
if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end
end
print(" sum= " .. sum)
print("prod= " .. prod)
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Convert this Lua snippet to C++ and keep its semantics consistent. |
function T(t) return setmetatable(t, {__index=table}) end
table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end
table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end
table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end
unpack = unpack or table.unpack
function mrl(tt)
local s=T{}
for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end
return ipairs(s)
end
prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7
for _,j in mrl{
{ -three, 3^3, three },
{ -seven, seven, x },
{ 555, 550-y },
{ 22, -28, -three },
{ 1927, 1939 },
{ x, y, z },
{ 11^x, 11^x+1 }} do
sum = sum + math.abs(j)
if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end
end
print(" sum= " .. sum)
print("prod= " .. prod)
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Write the same algorithm in Java as shown in this Lua implementation. |
function T(t) return setmetatable(t, {__index=table}) end
table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end
table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end
table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end
unpack = unpack or table.unpack
function mrl(tt)
local s=T{}
for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end
return ipairs(s)
end
prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7
for _,j in mrl{
{ -three, 3^3, three },
{ -seven, seven, x },
{ 555, 550-y },
{ 22, -28, -three },
{ 1927, 1939 },
{ x, y, z },
{ 11^x, 11^x+1 }} do
sum = sum + math.abs(j)
if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end
end
print(" sum= " .. sum)
print("prod= " .. prod)
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Ensure the translated Python code behaves exactly like the original Lua snippet. |
function T(t) return setmetatable(t, {__index=table}) end
table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end
table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end
table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end
unpack = unpack or table.unpack
function mrl(tt)
local s=T{}
for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end
return ipairs(s)
end
prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7
for _,j in mrl{
{ -three, 3^3, three },
{ -seven, seven, x },
{ 555, 550-y },
{ 22, -28, -three },
{ 1927, 1939 },
{ x, y, z },
{ 11^x, 11^x+1 }} do
sum = sum + math.abs(j)
if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end
end
print(" sum= " .. sum)
print("prod= " .. prod)
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Transform the following Lua implementation into VB, maintaining the same output and logic. |
function T(t) return setmetatable(t, {__index=table}) end
table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end
table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end
table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end
unpack = unpack or table.unpack
function mrl(tt)
local s=T{}
for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end
return ipairs(s)
end
prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7
for _,j in mrl{
{ -three, 3^3, three },
{ -seven, seven, x },
{ 555, 550-y },
{ 22, -28, -three },
{ 1927, 1939 },
{ x, y, z },
{ 11^x, 11^x+1 }} do
sum = sum + math.abs(j)
if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end
end
print(" sum= " .. sum)
print("prod= " .. prod)
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Change the programming language of this snippet from Lua to Go without modifying what it does. |
function T(t) return setmetatable(t, {__index=table}) end
table.range = function(t,a,b,c) local s=T{} for i=a,b,c or 1 do s[#s+1]=i end return s end
table.clone = function(t) local s=T{} for k,v in ipairs(t) do s[k]=v end return s end
table.chain = function(t,u) local s=t:clone() for i=1,#u do s[#s+1]=u[i] end return s end
unpack = unpack or table.unpack
function mrl(tt)
local s=T{}
for _,t in ipairs(tt) do s=s:chain(T{}:range(unpack(t))) end
return ipairs(s)
end
prod,sum,x,y,z,one,three,seven = 1,0,5,-5,-2,1,3,7
for _,j in mrl{
{ -three, 3^3, three },
{ -seven, seven, x },
{ 555, 550-y },
{ 22, -28, -three },
{ 1927, 1939 },
{ x, y, z },
{ 11^x, 11^x+1 }} do
sum = sum + math.abs(j)
if math.abs(prod) < 2^27 and j~=0 then prod = prod * j end
end
print(" sum= " .. sum)
print("prod= " .. prod)
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Write a version of this Mathematica function in C with identical behavior. | prod = 1;
sum = 0;
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
Do[
sum += Abs[j];
If[Abs[prod] < 2^27 \[And] j != 0, prod *= j];
,
{j,
Join[
Range[-three, 3^3, three],
Range[-seven, seven, x],
Range[555, 550 - y],
Range[22, -28, -three],
Range[1927, 1939],
Range[x, y, z],
Range[11^x, 11^x + one]
]
}
]
sum
prod
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Write the same code in C# as shown below in Mathematica. | prod = 1;
sum = 0;
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
Do[
sum += Abs[j];
If[Abs[prod] < 2^27 \[And] j != 0, prod *= j];
,
{j,
Join[
Range[-three, 3^3, three],
Range[-seven, seven, x],
Range[555, 550 - y],
Range[22, -28, -three],
Range[1927, 1939],
Range[x, y, z],
Range[11^x, 11^x + one]
]
}
]
sum
prod
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Produce a functionally identical C++ code for the snippet given in Mathematica. | prod = 1;
sum = 0;
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
Do[
sum += Abs[j];
If[Abs[prod] < 2^27 \[And] j != 0, prod *= j];
,
{j,
Join[
Range[-three, 3^3, three],
Range[-seven, seven, x],
Range[555, 550 - y],
Range[22, -28, -three],
Range[1927, 1939],
Range[x, y, z],
Range[11^x, 11^x + one]
]
}
]
sum
prod
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Write the same algorithm in Java as shown in this Mathematica implementation. | prod = 1;
sum = 0;
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
Do[
sum += Abs[j];
If[Abs[prod] < 2^27 \[And] j != 0, prod *= j];
,
{j,
Join[
Range[-three, 3^3, three],
Range[-seven, seven, x],
Range[555, 550 - y],
Range[22, -28, -three],
Range[1927, 1939],
Range[x, y, z],
Range[11^x, 11^x + one]
]
}
]
sum
prod
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Convert the following code from Mathematica to Python, ensuring the logic remains intact. | prod = 1;
sum = 0;
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
Do[
sum += Abs[j];
If[Abs[prod] < 2^27 \[And] j != 0, prod *= j];
,
{j,
Join[
Range[-three, 3^3, three],
Range[-seven, seven, x],
Range[555, 550 - y],
Range[22, -28, -three],
Range[1927, 1939],
Range[x, y, z],
Range[11^x, 11^x + one]
]
}
]
sum
prod
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Convert the following code from Mathematica to VB, ensuring the logic remains intact. | prod = 1;
sum = 0;
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
Do[
sum += Abs[j];
If[Abs[prod] < 2^27 \[And] j != 0, prod *= j];
,
{j,
Join[
Range[-three, 3^3, three],
Range[-seven, seven, x],
Range[555, 550 - y],
Range[22, -28, -three],
Range[1927, 1939],
Range[x, y, z],
Range[11^x, 11^x + one]
]
}
]
sum
prod
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Translate the given Mathematica code snippet into Go without altering its behavior. | prod = 1;
sum = 0;
x = 5;
y = -5;
z = -2;
one = 1;
three = 3;
seven = 7;
Do[
sum += Abs[j];
If[Abs[prod] < 2^27 \[And] j != 0, prod *= j];
,
{j,
Join[
Range[-three, 3^3, three],
Range[-seven, seven, x],
Range[555, 550 - y],
Range[22, -28, -three],
Range[1927, 1939],
Range[x, y, z],
Range[11^x, 11^x + one]
]
}
]
sum
prod
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Port the provided Nim code into C while preserving the original functionality. | import math, strutils
var
prod = 1
sum = 0
let
x = +5
y = -5
z = -2
one = 1
three = 3
seven = 7
proc body(j: int) =
sum += abs(j)
if abs(prod) < 2^27 and j != 0: prod *= j
for j in countup(-three, 3^3, three): body(j)
for j in countup(-seven, seven, x): body(j)
for j in countup(555, 550 - y): body(j)
for j in countdown(22, -28, three): body(j)
for j in countup(1927, 1939): body(j)
for j in countdown(x, y, -z): body(j)
for j in countup(11^x, 11^x + one): body(j)
let s = ($sum).insertSep(',')
let p = ($prod).insertSep(',')
let m = max(s.len, p.len)
echo " sum = ", s.align(m)
echo "prod = ", p.align(m)
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Generate an equivalent C# version of this Nim code. | import math, strutils
var
prod = 1
sum = 0
let
x = +5
y = -5
z = -2
one = 1
three = 3
seven = 7
proc body(j: int) =
sum += abs(j)
if abs(prod) < 2^27 and j != 0: prod *= j
for j in countup(-three, 3^3, three): body(j)
for j in countup(-seven, seven, x): body(j)
for j in countup(555, 550 - y): body(j)
for j in countdown(22, -28, three): body(j)
for j in countup(1927, 1939): body(j)
for j in countdown(x, y, -z): body(j)
for j in countup(11^x, 11^x + one): body(j)
let s = ($sum).insertSep(',')
let p = ($prod).insertSep(',')
let m = max(s.len, p.len)
echo " sum = ", s.align(m)
echo "prod = ", p.align(m)
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Keep all operations the same but rewrite the snippet in C++. | import math, strutils
var
prod = 1
sum = 0
let
x = +5
y = -5
z = -2
one = 1
three = 3
seven = 7
proc body(j: int) =
sum += abs(j)
if abs(prod) < 2^27 and j != 0: prod *= j
for j in countup(-three, 3^3, three): body(j)
for j in countup(-seven, seven, x): body(j)
for j in countup(555, 550 - y): body(j)
for j in countdown(22, -28, three): body(j)
for j in countup(1927, 1939): body(j)
for j in countdown(x, y, -z): body(j)
for j in countup(11^x, 11^x + one): body(j)
let s = ($sum).insertSep(',')
let p = ($prod).insertSep(',')
let m = max(s.len, p.len)
echo " sum = ", s.align(m)
echo "prod = ", p.align(m)
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Produce a language-to-language conversion: from Nim to Java, same semantics. | import math, strutils
var
prod = 1
sum = 0
let
x = +5
y = -5
z = -2
one = 1
three = 3
seven = 7
proc body(j: int) =
sum += abs(j)
if abs(prod) < 2^27 and j != 0: prod *= j
for j in countup(-three, 3^3, three): body(j)
for j in countup(-seven, seven, x): body(j)
for j in countup(555, 550 - y): body(j)
for j in countdown(22, -28, three): body(j)
for j in countup(1927, 1939): body(j)
for j in countdown(x, y, -z): body(j)
for j in countup(11^x, 11^x + one): body(j)
let s = ($sum).insertSep(',')
let p = ($prod).insertSep(',')
let m = max(s.len, p.len)
echo " sum = ", s.align(m)
echo "prod = ", p.align(m)
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Change the programming language of this snippet from Nim to Python without modifying what it does. | import math, strutils
var
prod = 1
sum = 0
let
x = +5
y = -5
z = -2
one = 1
three = 3
seven = 7
proc body(j: int) =
sum += abs(j)
if abs(prod) < 2^27 and j != 0: prod *= j
for j in countup(-three, 3^3, three): body(j)
for j in countup(-seven, seven, x): body(j)
for j in countup(555, 550 - y): body(j)
for j in countdown(22, -28, three): body(j)
for j in countup(1927, 1939): body(j)
for j in countdown(x, y, -z): body(j)
for j in countup(11^x, 11^x + one): body(j)
let s = ($sum).insertSep(',')
let p = ($prod).insertSep(',')
let m = max(s.len, p.len)
echo " sum = ", s.align(m)
echo "prod = ", p.align(m)
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Ensure the translated VB code behaves exactly like the original Nim snippet. | import math, strutils
var
prod = 1
sum = 0
let
x = +5
y = -5
z = -2
one = 1
three = 3
seven = 7
proc body(j: int) =
sum += abs(j)
if abs(prod) < 2^27 and j != 0: prod *= j
for j in countup(-three, 3^3, three): body(j)
for j in countup(-seven, seven, x): body(j)
for j in countup(555, 550 - y): body(j)
for j in countdown(22, -28, three): body(j)
for j in countup(1927, 1939): body(j)
for j in countdown(x, y, -z): body(j)
for j in countup(11^x, 11^x + one): body(j)
let s = ($sum).insertSep(',')
let p = ($prod).insertSep(',')
let m = max(s.len, p.len)
echo " sum = ", s.align(m)
echo "prod = ", p.align(m)
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Convert this Nim snippet to Go and keep its semantics consistent. | import math, strutils
var
prod = 1
sum = 0
let
x = +5
y = -5
z = -2
one = 1
three = 3
seven = 7
proc body(j: int) =
sum += abs(j)
if abs(prod) < 2^27 and j != 0: prod *= j
for j in countup(-three, 3^3, three): body(j)
for j in countup(-seven, seven, x): body(j)
for j in countup(555, 550 - y): body(j)
for j in countdown(22, -28, three): body(j)
for j in countup(1927, 1939): body(j)
for j in countdown(x, y, -z): body(j)
for j in countup(11^x, 11^x + one): body(j)
let s = ($sum).insertSep(',')
let p = ($prod).insertSep(',')
let m = max(s.len, p.len)
echo " sum = ", s.align(m)
echo "prod = ", p.align(m)
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Rewrite the snippet below in C so it works the same as the original Perl code. | use constant one => 1;
use constant three => 3;
use constant seven => 7;
use constant x => 5;
use constant yy => -5;
use constant z => -2;
my $prod = 1;
sub from_to_by {
my($begin,$end,$skip) = @_;
my $n = 0;
grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin;
}
sub commatize {
(my $s = reverse shift) =~ s/(.{3})/$1,/g;
$s =~ s/,(-?)$/$1/;
$s = reverse $s;
}
for my $j (
from_to_by(-three,3**3,three),
from_to_by(-seven,seven,x),
555 .. 550 - yy,
from_to_by(22,-28,-three),
1927 .. 1939,
from_to_by(x,yy,z),
11**x .. 11**x+one,
) {
$sum += abs($j);
$prod *= $j if $j and abs($prod) < 2**27;
}
printf "%-8s %12s\n", 'Sum:', commatize $sum;
printf "%-8s %12s\n", 'Product:', commatize $prod;
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Maintain the same structure and functionality when rewriting this code in C#. | use constant one => 1;
use constant three => 3;
use constant seven => 7;
use constant x => 5;
use constant yy => -5;
use constant z => -2;
my $prod = 1;
sub from_to_by {
my($begin,$end,$skip) = @_;
my $n = 0;
grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin;
}
sub commatize {
(my $s = reverse shift) =~ s/(.{3})/$1,/g;
$s =~ s/,(-?)$/$1/;
$s = reverse $s;
}
for my $j (
from_to_by(-three,3**3,three),
from_to_by(-seven,seven,x),
555 .. 550 - yy,
from_to_by(22,-28,-three),
1927 .. 1939,
from_to_by(x,yy,z),
11**x .. 11**x+one,
) {
$sum += abs($j);
$prod *= $j if $j and abs($prod) < 2**27;
}
printf "%-8s %12s\n", 'Sum:', commatize $sum;
printf "%-8s %12s\n", 'Product:', commatize $prod;
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Ensure the translated C++ code behaves exactly like the original Perl snippet. | use constant one => 1;
use constant three => 3;
use constant seven => 7;
use constant x => 5;
use constant yy => -5;
use constant z => -2;
my $prod = 1;
sub from_to_by {
my($begin,$end,$skip) = @_;
my $n = 0;
grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin;
}
sub commatize {
(my $s = reverse shift) =~ s/(.{3})/$1,/g;
$s =~ s/,(-?)$/$1/;
$s = reverse $s;
}
for my $j (
from_to_by(-three,3**3,three),
from_to_by(-seven,seven,x),
555 .. 550 - yy,
from_to_by(22,-28,-three),
1927 .. 1939,
from_to_by(x,yy,z),
11**x .. 11**x+one,
) {
$sum += abs($j);
$prod *= $j if $j and abs($prod) < 2**27;
}
printf "%-8s %12s\n", 'Sum:', commatize $sum;
printf "%-8s %12s\n", 'Product:', commatize $prod;
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Convert this Perl block to Java, preserving its control flow and logic. | use constant one => 1;
use constant three => 3;
use constant seven => 7;
use constant x => 5;
use constant yy => -5;
use constant z => -2;
my $prod = 1;
sub from_to_by {
my($begin,$end,$skip) = @_;
my $n = 0;
grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin;
}
sub commatize {
(my $s = reverse shift) =~ s/(.{3})/$1,/g;
$s =~ s/,(-?)$/$1/;
$s = reverse $s;
}
for my $j (
from_to_by(-three,3**3,three),
from_to_by(-seven,seven,x),
555 .. 550 - yy,
from_to_by(22,-28,-three),
1927 .. 1939,
from_to_by(x,yy,z),
11**x .. 11**x+one,
) {
$sum += abs($j);
$prod *= $j if $j and abs($prod) < 2**27;
}
printf "%-8s %12s\n", 'Sum:', commatize $sum;
printf "%-8s %12s\n", 'Product:', commatize $prod;
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Translate this program into Python but keep the logic exactly as in Perl. | use constant one => 1;
use constant three => 3;
use constant seven => 7;
use constant x => 5;
use constant yy => -5;
use constant z => -2;
my $prod = 1;
sub from_to_by {
my($begin,$end,$skip) = @_;
my $n = 0;
grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin;
}
sub commatize {
(my $s = reverse shift) =~ s/(.{3})/$1,/g;
$s =~ s/,(-?)$/$1/;
$s = reverse $s;
}
for my $j (
from_to_by(-three,3**3,three),
from_to_by(-seven,seven,x),
555 .. 550 - yy,
from_to_by(22,-28,-three),
1927 .. 1939,
from_to_by(x,yy,z),
11**x .. 11**x+one,
) {
$sum += abs($j);
$prod *= $j if $j and abs($prod) < 2**27;
}
printf "%-8s %12s\n", 'Sum:', commatize $sum;
printf "%-8s %12s\n", 'Product:', commatize $prod;
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Rewrite the snippet below in VB so it works the same as the original Perl code. | use constant one => 1;
use constant three => 3;
use constant seven => 7;
use constant x => 5;
use constant yy => -5;
use constant z => -2;
my $prod = 1;
sub from_to_by {
my($begin,$end,$skip) = @_;
my $n = 0;
grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin;
}
sub commatize {
(my $s = reverse shift) =~ s/(.{3})/$1,/g;
$s =~ s/,(-?)$/$1/;
$s = reverse $s;
}
for my $j (
from_to_by(-three,3**3,three),
from_to_by(-seven,seven,x),
555 .. 550 - yy,
from_to_by(22,-28,-three),
1927 .. 1939,
from_to_by(x,yy,z),
11**x .. 11**x+one,
) {
$sum += abs($j);
$prod *= $j if $j and abs($prod) < 2**27;
}
printf "%-8s %12s\n", 'Sum:', commatize $sum;
printf "%-8s %12s\n", 'Product:', commatize $prod;
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Port the following code from Perl to Go with equivalent syntax and logic. | use constant one => 1;
use constant three => 3;
use constant seven => 7;
use constant x => 5;
use constant yy => -5;
use constant z => -2;
my $prod = 1;
sub from_to_by {
my($begin,$end,$skip) = @_;
my $n = 0;
grep{ !($n++ % abs $skip) } $begin <= $end ? $begin..$end : reverse $end..$begin;
}
sub commatize {
(my $s = reverse shift) =~ s/(.{3})/$1,/g;
$s =~ s/,(-?)$/$1/;
$s = reverse $s;
}
for my $j (
from_to_by(-three,3**3,three),
from_to_by(-seven,seven,x),
555 .. 550 - yy,
from_to_by(22,-28,-three),
1927 .. 1939,
from_to_by(x,yy,z),
11**x .. 11**x+one,
) {
$sum += abs($j);
$prod *= $j if $j and abs($prod) < 2**27;
}
printf "%-8s %12s\n", 'Sum:', commatize $sum;
printf "%-8s %12s\n", 'Product:', commatize $prod;
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Change the following REXX code into C without altering its purpose. |
prod= 1;
sum= 0;
x= +5;
y= -5;
z= -2;
one= 1;
three= 3;
seven= 7;
do j= -three to 3**3 by three ; call meat; end;
do j= -seven to seven by x ; call meat; end;
do j= 555 to 550 - y ; call meat; end;
do j= 22 to -28 by -three ; call meat; end;
do j= 1927 to 1939 ; call meat; end;
do j= x to y by z ; call meat; end;
do j= 11**x to 11**x + one ; call meat; end;
say ' sum= ' || commas( sum);
say 'prod= ' || commas(prod);
exit;
commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M")
e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4
do j=e to b by -3; _= insert(',', _, j); end; return _
meat: sum= sum + abs(j);
if abs(prod)<2**27 & j\==0 then prod= prod * j;
return;
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
Can you help me rewrite this code in C# instead of REXX, keeping it the same logically? |
prod= 1;
sum= 0;
x= +5;
y= -5;
z= -2;
one= 1;
three= 3;
seven= 7;
do j= -three to 3**3 by three ; call meat; end;
do j= -seven to seven by x ; call meat; end;
do j= 555 to 550 - y ; call meat; end;
do j= 22 to -28 by -three ; call meat; end;
do j= 1927 to 1939 ; call meat; end;
do j= x to y by z ; call meat; end;
do j= 11**x to 11**x + one ; call meat; end;
say ' sum= ' || commas( sum);
say 'prod= ' || commas(prod);
exit;
commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M")
e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4
do j=e to b by -3; _= insert(',', _, j); end; return _
meat: sum= sum + abs(j);
if abs(prod)<2**27 & j\==0 then prod= prod * j;
return;
| using System;
using System.Collections.Generic;
using System.Linq;
public static class LoopsWithMultipleRanges
{
public static void Main() {
int prod = 1;
int sum = 0;
int x = 5;
int y = -5;
int z = -2;
int one = 1;
int three = 3;
int seven = 7;
foreach (int j in Concat(
For(-three, 3.Pow(3), three),
For(-seven, seven, x),
For(555, 550 - y),
For(22, -28, -three),
For(1927, 1939),
For(x, y, z),
For(11.Pow(x), 11.Pow(x) + one)
)) {
sum += Math.Abs(j);
if (Math.Abs(prod) < (1 << 27) && j != 0) prod *= j;
}
Console.WriteLine($" sum = {sum:N0}");
Console.WriteLine($"prod = {prod:N0}");
}
static IEnumerable<int> For(int start, int end, int by = 1) {
for (int i = start; by > 0 ? (i <= end) : (i >= end); i += by) yield return i;
}
static IEnumerable<int> Concat(params IEnumerable<int>[] ranges) => ranges.Aggregate((acc, r) => acc.Concat(r));
static int Pow(this int b, int e) => (int)Math.Pow(b, e);
}
|
Port the following code from REXX to C++ with equivalent syntax and logic. |
prod= 1;
sum= 0;
x= +5;
y= -5;
z= -2;
one= 1;
three= 3;
seven= 7;
do j= -three to 3**3 by three ; call meat; end;
do j= -seven to seven by x ; call meat; end;
do j= 555 to 550 - y ; call meat; end;
do j= 22 to -28 by -three ; call meat; end;
do j= 1927 to 1939 ; call meat; end;
do j= x to y by z ; call meat; end;
do j= 11**x to 11**x + one ; call meat; end;
say ' sum= ' || commas( sum);
say 'prod= ' || commas(prod);
exit;
commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M")
e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4
do j=e to b by -3; _= insert(',', _, j); end; return _
meat: sum= sum + abs(j);
if abs(prod)<2**27 & j\==0 then prod= prod * j;
return;
| #include <iostream>
#include <cmath>
#include <vector>
using std::abs;
using std::cout;
using std::pow;
using std::vector;
int main()
{
int prod = 1,
sum = 0,
x = 5,
y = -5,
z = -2,
one = 1,
three = 3,
seven = 7;
auto summingValues = vector<int>{};
for(int n = -three; n <= pow(3, 3); n += three)
summingValues.push_back(n);
for(int n = -seven; n <= seven; n += x)
summingValues.push_back(n);
for(int n = 555; n <= 550 - y; ++n)
summingValues.push_back(n);
for(int n = 22; n >= -28; n -= three)
summingValues.push_back(n);
for(int n = 1927; n <= 1939; ++n)
summingValues.push_back(n);
for(int n = x; n >= y; n += z)
summingValues.push_back(n);
for(int n = pow(11, x); n <= pow(11, x) + one; ++n)
summingValues.push_back(n);
for(auto j : summingValues)
{
sum += abs(j);
if(abs(prod) < pow(2, 27) && j != 0)
prod *= j;
}
cout << "sum = " << sum << "\n";
cout << "prod = " << prod << "\n";
}
|
Convert this REXX snippet to Java and keep its semantics consistent. |
prod= 1;
sum= 0;
x= +5;
y= -5;
z= -2;
one= 1;
three= 3;
seven= 7;
do j= -three to 3**3 by three ; call meat; end;
do j= -seven to seven by x ; call meat; end;
do j= 555 to 550 - y ; call meat; end;
do j= 22 to -28 by -three ; call meat; end;
do j= 1927 to 1939 ; call meat; end;
do j= x to y by z ; call meat; end;
do j= 11**x to 11**x + one ; call meat; end;
say ' sum= ' || commas( sum);
say 'prod= ' || commas(prod);
exit;
commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M")
e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4
do j=e to b by -3; _= insert(',', _, j); end; return _
meat: sum= sum + abs(j);
if abs(prod)<2**27 & j\==0 then prod= prod * j;
return;
| import java.util.ArrayList;
import java.util.List;
public class LoopsWithMultipleRanges {
private static long sum = 0;
private static long prod = 1;
public static void main(String[] args) {
long x = 5;
long y = -5;
long z = -2;
long one = 1;
long three = 3;
long seven = 7;
List<Long> jList = new ArrayList<>();
for ( long j = -three ; j <= pow(3, 3) ; j += three ) jList.add(j);
for ( long j = -seven ; j <= seven ; j += x ) jList.add(j);
for ( long j = 555 ; j <= 550-y ; j += 1 ) jList.add(j);
for ( long j = 22 ; j >= -28 ; j += -three ) jList.add(j);
for ( long j = 1927 ; j <= 1939 ; j += 1 ) jList.add(j);
for ( long j = x ; j >= y ; j += z ) jList.add(j);
for ( long j = pow(11, x) ; j <= pow(11, x) + one ; j += 1 ) jList.add(j);
List<Long> prodList = new ArrayList<>();
for ( long j : jList ) {
sum += Math.abs(j);
if ( Math.abs(prod) < pow(2, 27) && j != 0 ) {
prodList.add(j);
prod *= j;
}
}
System.out.printf(" sum = %,d%n", sum);
System.out.printf("prod = %,d%n", prod);
System.out.printf("j values = %s%n", jList);
System.out.printf("prod values = %s%n", prodList);
}
private static long pow(long base, long exponent) {
return (long) Math.pow(base, exponent);
}
}
|
Write the same code in Python as shown below in REXX. |
prod= 1;
sum= 0;
x= +5;
y= -5;
z= -2;
one= 1;
three= 3;
seven= 7;
do j= -three to 3**3 by three ; call meat; end;
do j= -seven to seven by x ; call meat; end;
do j= 555 to 550 - y ; call meat; end;
do j= 22 to -28 by -three ; call meat; end;
do j= 1927 to 1939 ; call meat; end;
do j= x to y by z ; call meat; end;
do j= 11**x to 11**x + one ; call meat; end;
say ' sum= ' || commas( sum);
say 'prod= ' || commas(prod);
exit;
commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M")
e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4
do j=e to b by -3; _= insert(',', _, j); end; return _
meat: sum= sum + abs(j);
if abs(prod)<2**27 & j\==0 then prod= prod * j;
return;
| from itertools import chain
prod, sum_, x, y, z, one,three,seven = 1, 0, 5, -5, -2, 1, 3, 7
def _range(x, y, z=1):
return range(x, y + (1 if z > 0 else -1), z)
print(f'list(_range(x, y, z)) = {list(_range(x, y, z))}')
print(f'list(_range(-seven, seven, x)) = {list(_range(-seven, seven, x))}')
for j in chain(_range(-three, 3**3, three), _range(-seven, seven, x),
_range(555, 550 - y), _range(22, -28, -three),
_range(1927, 1939), _range(x, y, z),
_range(11**x, 11**x + 1)):
sum_ += abs(j)
if abs(prod) < 2**27 and (j != 0):
prod *= j
print(f' sum= {sum_}\nprod= {prod}')
|
Change the programming language of this snippet from REXX to VB without modifying what it does. |
prod= 1;
sum= 0;
x= +5;
y= -5;
z= -2;
one= 1;
three= 3;
seven= 7;
do j= -three to 3**3 by three ; call meat; end;
do j= -seven to seven by x ; call meat; end;
do j= 555 to 550 - y ; call meat; end;
do j= 22 to -28 by -three ; call meat; end;
do j= 1927 to 1939 ; call meat; end;
do j= x to y by z ; call meat; end;
do j= 11**x to 11**x + one ; call meat; end;
say ' sum= ' || commas( sum);
say 'prod= ' || commas(prod);
exit;
commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M")
e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4
do j=e to b by -3; _= insert(',', _, j); end; return _
meat: sum= sum + abs(j);
if abs(prod)<2**27 & j\==0 then prod= prod * j;
return;
| Dim prod As Long, sum As Long
Public Sub LoopsWithMultipleRanges()
Dim x As Integer, y As Integer, z As Integer, one As Integer, three As Integer, seven As Integer, j As Long
prod = 1
sum = 0
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
For j = -three To pow(3, 3) Step three: Call process(j): Next j
For j = -seven To seven Step x: Call process(j): Next j
For j = 555 To 550 - y: Call process(j): Next j
For j = 22 To -28 Step -three: Call process(j): Next j
For j = 1927 To 1939: Call process(j): Next j
For j = x To y Step z: Call process(j): Next j
For j = pow(11, x) To pow(11, x) + one: Call process(j): Next j
Debug.Print " sum= " & Format(sum, "#,##0")
Debug.Print "prod= " & Format(prod, "#,##0")
End Sub
Private Function pow(x As Long, y As Integer) As Long
pow = WorksheetFunction.Power(x, y)
End Function
Private Sub process(x As Long)
sum = sum + Abs(x)
If Abs(prod) < pow(2, 27) And x <> 0 Then prod = prod * x
End Sub
|
Generate a Go translation of this REXX snippet without changing its computational steps. |
prod= 1;
sum= 0;
x= +5;
y= -5;
z= -2;
one= 1;
three= 3;
seven= 7;
do j= -three to 3**3 by three ; call meat; end;
do j= -seven to seven by x ; call meat; end;
do j= 555 to 550 - y ; call meat; end;
do j= 22 to -28 by -three ; call meat; end;
do j= 1927 to 1939 ; call meat; end;
do j= x to y by z ; call meat; end;
do j= 11**x to 11**x + one ; call meat; end;
say ' sum= ' || commas( sum);
say 'prod= ' || commas(prod);
exit;
commas: procedure; parse arg _; n= _'.9'; #= 123456789; b= verify(n, #, "M")
e= verify(n, #'0', , verify(n, #"0.", 'M') ) - 4
do j=e to b by -3; _= insert(',', _, j); end; return _
meat: sum= sum + abs(j);
if abs(prod)<2**27 & j\==0 then prod= prod * j;
return;
| package main
import "fmt"
func pow(n int, e uint) int {
if e == 0 {
return 1
}
prod := n
for i := uint(2); i <= e; i++ {
prod *= n
}
return prod
}
func abs(n int) int {
if n >= 0 {
return n
}
return -n
}
func commatize(n int) string {
s := fmt.Sprintf("%d", n)
if n < 0 {
s = s[1:]
}
le := len(s)
for i := le - 3; i >= 1; i -= 3 {
s = s[0:i] + "," + s[i:]
}
if n >= 0 {
return " " + s
}
return "-" + s
}
func main() {
prod := 1
sum := 0
const (
x = 5
y = -5
z = -2
one = 1
three = 3
seven = 7
)
p := pow(11, x)
var j int
process := func() {
sum += abs(j)
if abs(prod) < (1<<27) && j != 0 {
prod *= j
}
}
for j = -three; j <= pow(3, 3); j += three {
process()
}
for j = -seven; j <= seven; j += x {
process()
}
for j = 555; j <= 550-y; j++ {
process()
}
for j = 22; j >= -28; j -= three {
process()
}
for j = 1927; j <= 1939; j++ {
process()
}
for j = x; j >= y; j -= -z {
process()
}
for j = p; j <= p+one; j++ {
process()
}
fmt.Println("sum = ", commatize(sum))
fmt.Println("prod = ", commatize(prod))
}
|
Ensure the translated C code behaves exactly like the original Ruby snippet. | x, y, z, one, three, seven = 5, -5, -2, 1, 3, 7
enums = (-three).step(3**3, three) +
(-seven).step(seven, x) +
555 .step(550-y, -1) +
22 .step(-28, -three) +
(1927..1939) +
x .step(y, z) +
(11**x) .step(11**x + one)
puts "Sum of absolute numbers:
prod = enums.inject(1){|prod, j| ((prod.abs < 2**27) && j!=0) ? prod*j : prod}
puts "Product (but not really):
| #include <stdio.h>
#include <stdlib.h>
#include <locale.h>
long prod = 1L, sum = 0L;
void process(int j) {
sum += abs(j);
if (labs(prod) < (1 << 27) && j) prod *= j;
}
long ipow(int n, uint e) {
long pr = n;
int i;
if (e == 0) return 1L;
for (i = 2; i <= e; ++i) pr *= n;
return pr;
}
int main() {
int j;
const int x = 5, y = -5, z = -2;
const int one = 1, three = 3, seven = 7;
long p = ipow(11, x);
for (j = -three; j <= ipow(3, 3); j += three) process(j);
for (j = -seven; j <= seven; j += x) process(j);
for (j = 555; j <= 550 - y; ++j) process(j);
for (j = 22; j >= -28; j -= three) process(j);
for (j = 1927; j <= 1939; ++j) process(j);
for (j = x; j >= y; j -= -z) process(j);
for (j = p; j <= p + one; ++j) process(j);
setlocale(LC_NUMERIC, "");
printf("sum = % 'ld\n", sum);
printf("prod = % 'ld\n", prod);
return 0;
}
|
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