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Generate a C++ translation of this Arturo snippet without changing its computational steps.
vsub: function [u v][ map couple u v 'pair -> pair\0 - pair\1 ] differences: function [block][ order: attr "order" if order = null -> order: 1 loop 1..order 'n -> block: vsub block drop block 1 return block ] print differences .order: 4 [90.5 47 58 29 22 32 55 5 55 73.5] print differences [1 2 3...
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Generate an equivalent Java version of this Arturo code.
vsub: function [u v][ map couple u v 'pair -> pair\0 - pair\1 ] differences: function [block][ order: attr "order" if order = null -> order: 1 loop 1..order 'n -> block: vsub block drop block 1 return block ] print differences .order: 4 [90.5 47 58 29 22 32 55 5 55 73.5] print differences [1 2 3...
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Write the same algorithm in Python as shown in this Arturo implementation.
vsub: function [u v][ map couple u v 'pair -> pair\0 - pair\1 ] differences: function [block][ order: attr "order" if order = null -> order: 1 loop 1..order 'n -> block: vsub block drop block 1 return block ] print differences .order: 4 [90.5 47 58 29 22 32 55 5 55 73.5] print differences [1 2 3...
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Keep all operations the same but rewrite the snippet in VB.
vsub: function [u v][ map couple u v 'pair -> pair\0 - pair\1 ] differences: function [block][ order: attr "order" if order = null -> order: 1 loop 1..order 'n -> block: vsub block drop block 1 return block ] print differences .order: 4 [90.5 47 58 29 22 32 55 5 55 73.5] print differences [1 2 3...
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Keep all operations the same but rewrite the snippet in Go.
vsub: function [u v][ map couple u v 'pair -> pair\0 - pair\1 ] differences: function [block][ order: attr "order" if order = null -> order: 1 loop 1..order 'n -> block: vsub block drop block 1 return block ] print differences .order: 4 [90.5 47 58 29 22 32 55 5 55 73.5] print differences [1 2 3...
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Please provide an equivalent version of this AutoHotKey code in C.
MsgBox % diff("2,3,4,3",1) MsgBox % diff("2,3,4,3",2) MsgBox % diff("2,3,4,3",3) MsgBox % diff("2,3,4,3",4) diff(list,ord) {  Loop %ord% { L = Loop Parse, list, `, %A_Space%%A_Tab% If (A_Index=1) p := A_LoopField Else L .= "," A_LoopField-p, p := A_LoopField ...
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Please provide an equivalent version of this AutoHotKey code in C#.
MsgBox % diff("2,3,4,3",1) MsgBox % diff("2,3,4,3",2) MsgBox % diff("2,3,4,3",3) MsgBox % diff("2,3,4,3",4) diff(list,ord) {  Loop %ord% { L = Loop Parse, list, `, %A_Space%%A_Tab% If (A_Index=1) p := A_LoopField Else L .= "," A_LoopField-p, p := A_LoopField ...
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Port the following code from AutoHotKey to C++ with equivalent syntax and logic.
MsgBox % diff("2,3,4,3",1) MsgBox % diff("2,3,4,3",2) MsgBox % diff("2,3,4,3",3) MsgBox % diff("2,3,4,3",4) diff(list,ord) {  Loop %ord% { L = Loop Parse, list, `, %A_Space%%A_Tab% If (A_Index=1) p := A_LoopField Else L .= "," A_LoopField-p, p := A_LoopField ...
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Maintain the same structure and functionality when rewriting this code in Java.
MsgBox % diff("2,3,4,3",1) MsgBox % diff("2,3,4,3",2) MsgBox % diff("2,3,4,3",3) MsgBox % diff("2,3,4,3",4) diff(list,ord) {  Loop %ord% { L = Loop Parse, list, `, %A_Space%%A_Tab% If (A_Index=1) p := A_LoopField Else L .= "," A_LoopField-p, p := A_LoopField ...
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Rewrite this program in Python while keeping its functionality equivalent to the AutoHotKey version.
MsgBox % diff("2,3,4,3",1) MsgBox % diff("2,3,4,3",2) MsgBox % diff("2,3,4,3",3) MsgBox % diff("2,3,4,3",4) diff(list,ord) {  Loop %ord% { L = Loop Parse, list, `, %A_Space%%A_Tab% If (A_Index=1) p := A_LoopField Else L .= "," A_LoopField-p, p := A_LoopField ...
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Generate an equivalent VB version of this AutoHotKey code.
MsgBox % diff("2,3,4,3",1) MsgBox % diff("2,3,4,3",2) MsgBox % diff("2,3,4,3",3) MsgBox % diff("2,3,4,3",4) diff(list,ord) {  Loop %ord% { L = Loop Parse, list, `, %A_Space%%A_Tab% If (A_Index=1) p := A_LoopField Else L .= "," A_LoopField-p, p := A_LoopField ...
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Produce a functionally identical Go code for the snippet given in AutoHotKey.
MsgBox % diff("2,3,4,3",1) MsgBox % diff("2,3,4,3",2) MsgBox % diff("2,3,4,3",3) MsgBox % diff("2,3,4,3",4) diff(list,ord) {  Loop %ord% { L = Loop Parse, list, `, %A_Space%%A_Tab% If (A_Index=1) p := A_LoopField Else L .= "," A_LoopField-p, p := A_LoopField ...
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Convert this AWK snippet to C and keep its semantics consistent.
BEGIN { if (p<1) {p = 1}; } function diff(s, p) { n = split(s, a, " "); for (j = 1; j <= p; j++) { for(i = 1; i <= n-j; i++) { a[i] = a[i+1] - a[i]; } } s = ""; for (i = 1; i <= n-p; i++) s = s" "a[i]; return s; } { print diff($0, p); }
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Rewrite the snippet below in C# so it works the same as the original AWK code.
BEGIN { if (p<1) {p = 1}; } function diff(s, p) { n = split(s, a, " "); for (j = 1; j <= p; j++) { for(i = 1; i <= n-j; i++) { a[i] = a[i+1] - a[i]; } } s = ""; for (i = 1; i <= n-p; i++) s = s" "a[i]; return s; } { print diff($0, p); }
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Port the provided AWK code into C++ while preserving the original functionality.
BEGIN { if (p<1) {p = 1}; } function diff(s, p) { n = split(s, a, " "); for (j = 1; j <= p; j++) { for(i = 1; i <= n-j; i++) { a[i] = a[i+1] - a[i]; } } s = ""; for (i = 1; i <= n-p; i++) s = s" "a[i]; return s; } { print diff($0, p); }
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Preserve the algorithm and functionality while converting the code from AWK to Java.
BEGIN { if (p<1) {p = 1}; } function diff(s, p) { n = split(s, a, " "); for (j = 1; j <= p; j++) { for(i = 1; i <= n-j; i++) { a[i] = a[i+1] - a[i]; } } s = ""; for (i = 1; i <= n-p; i++) s = s" "a[i]; return s; } { print diff($0, p); }
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Change the following AWK code into Python without altering its purpose.
BEGIN { if (p<1) {p = 1}; } function diff(s, p) { n = split(s, a, " "); for (j = 1; j <= p; j++) { for(i = 1; i <= n-j; i++) { a[i] = a[i+1] - a[i]; } } s = ""; for (i = 1; i <= n-p; i++) s = s" "a[i]; return s; } { print diff($0, p); }
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Please provide an equivalent version of this AWK code in VB.
BEGIN { if (p<1) {p = 1}; } function diff(s, p) { n = split(s, a, " "); for (j = 1; j <= p; j++) { for(i = 1; i <= n-j; i++) { a[i] = a[i+1] - a[i]; } } s = ""; for (i = 1; i <= n-p; i++) s = s" "a[i]; return s; } { print diff($0, p); }
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Change the following AWK code into Go without altering its purpose.
BEGIN { if (p<1) {p = 1}; } function diff(s, p) { n = split(s, a, " "); for (j = 1; j <= p; j++) { for(i = 1; i <= n-j; i++) { a[i] = a[i+1] - a[i]; } } s = ""; for (i = 1; i <= n-p; i++) s = s" "a[i]; return s; } { print diff($0, p); }
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Write the same code in C as shown below in BBC_Basic.
DIM A(9) A() = 90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0 PRINT "Original array: " FNshowarray(A()) PROCforward_difference(1, A(), B()) PRINT "Forward diff 1: " FNshowarray(B()) PROCforward_difference(2, A(), C()) PRINT "Forward diff 2: " FNshowarray(C()) P...
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Generate an equivalent C# version of this BBC_Basic code.
DIM A(9) A() = 90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0 PRINT "Original array: " FNshowarray(A()) PROCforward_difference(1, A(), B()) PRINT "Forward diff 1: " FNshowarray(B()) PROCforward_difference(2, A(), C()) PRINT "Forward diff 2: " FNshowarray(C()) P...
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Rewrite this program in C++ while keeping its functionality equivalent to the BBC_Basic version.
DIM A(9) A() = 90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0 PRINT "Original array: " FNshowarray(A()) PROCforward_difference(1, A(), B()) PRINT "Forward diff 1: " FNshowarray(B()) PROCforward_difference(2, A(), C()) PRINT "Forward diff 2: " FNshowarray(C()) P...
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Preserve the algorithm and functionality while converting the code from BBC_Basic to Java.
DIM A(9) A() = 90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0 PRINT "Original array: " FNshowarray(A()) PROCforward_difference(1, A(), B()) PRINT "Forward diff 1: " FNshowarray(B()) PROCforward_difference(2, A(), C()) PRINT "Forward diff 2: " FNshowarray(C()) P...
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Convert the following code from BBC_Basic to Python, ensuring the logic remains intact.
DIM A(9) A() = 90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0 PRINT "Original array: " FNshowarray(A()) PROCforward_difference(1, A(), B()) PRINT "Forward diff 1: " FNshowarray(B()) PROCforward_difference(2, A(), C()) PRINT "Forward diff 2: " FNshowarray(C()) P...
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Please provide an equivalent version of this BBC_Basic code in VB.
DIM A(9) A() = 90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0 PRINT "Original array: " FNshowarray(A()) PROCforward_difference(1, A(), B()) PRINT "Forward diff 1: " FNshowarray(B()) PROCforward_difference(2, A(), C()) PRINT "Forward diff 2: " FNshowarray(C()) P...
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Write a version of this BBC_Basic function in Go with identical behavior.
DIM A(9) A() = 90.0, 47.0, 58.0, 29.0, 22.0, 32.0, 55.0, 5.0, 55.0, 73.0 PRINT "Original array: " FNshowarray(A()) PROCforward_difference(1, A(), B()) PRINT "Forward diff 1: " FNshowarray(B()) PROCforward_difference(2, A(), C()) PRINT "Forward diff 2: " FNshowarray(C()) P...
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Generate an equivalent C version of this Common_Lisp code.
(defn fwd-diff [nums order] (nth (iterate #(map - (next %) %) nums) order))
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Convert this Common_Lisp snippet to C# and keep its semantics consistent.
(defn fwd-diff [nums order] (nth (iterate #(map - (next %) %) nums) order))
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Maintain the same structure and functionality when rewriting this code in C++.
(defn fwd-diff [nums order] (nth (iterate #(map - (next %) %) nums) order))
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Convert this Common_Lisp block to Java, preserving its control flow and logic.
(defn fwd-diff [nums order] (nth (iterate #(map - (next %) %) nums) order))
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Please provide an equivalent version of this Common_Lisp code in Python.
(defn fwd-diff [nums order] (nth (iterate #(map - (next %) %) nums) order))
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Port the provided Common_Lisp code into VB while preserving the original functionality.
(defn fwd-diff [nums order] (nth (iterate #(map - (next %) %) nums) order))
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Translate the given Common_Lisp code snippet into Go without altering its behavior.
(defn fwd-diff [nums order] (nth (iterate #(map - (next %) %) nums) order))
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Generate an equivalent C version of this D code.
T[] forwardDifference(T)(in T[] data, in int level) pure nothrow in { assert(level >= 0 && level < data.length); } body { auto result = data.dup; foreach (immutable i; 0 .. level) foreach (immutable j, ref el; result[0 .. $ - i - 1]) el = result[j + 1] - el; result.length -= level; ...
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Port the following code from D to C# with equivalent syntax and logic.
T[] forwardDifference(T)(in T[] data, in int level) pure nothrow in { assert(level >= 0 && level < data.length); } body { auto result = data.dup; foreach (immutable i; 0 .. level) foreach (immutable j, ref el; result[0 .. $ - i - 1]) el = result[j + 1] - el; result.length -= level; ...
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Keep all operations the same but rewrite the snippet in C++.
T[] forwardDifference(T)(in T[] data, in int level) pure nothrow in { assert(level >= 0 && level < data.length); } body { auto result = data.dup; foreach (immutable i; 0 .. level) foreach (immutable j, ref el; result[0 .. $ - i - 1]) el = result[j + 1] - el; result.length -= level; ...
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Please provide an equivalent version of this D code in Java.
T[] forwardDifference(T)(in T[] data, in int level) pure nothrow in { assert(level >= 0 && level < data.length); } body { auto result = data.dup; foreach (immutable i; 0 .. level) foreach (immutable j, ref el; result[0 .. $ - i - 1]) el = result[j + 1] - el; result.length -= level; ...
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Convert this D block to Python, preserving its control flow and logic.
T[] forwardDifference(T)(in T[] data, in int level) pure nothrow in { assert(level >= 0 && level < data.length); } body { auto result = data.dup; foreach (immutable i; 0 .. level) foreach (immutable j, ref el; result[0 .. $ - i - 1]) el = result[j + 1] - el; result.length -= level; ...
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Change the following D code into VB without altering its purpose.
T[] forwardDifference(T)(in T[] data, in int level) pure nothrow in { assert(level >= 0 && level < data.length); } body { auto result = data.dup; foreach (immutable i; 0 .. level) foreach (immutable j, ref el; result[0 .. $ - i - 1]) el = result[j + 1] - el; result.length -= level; ...
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Change the following D code into Go without altering its purpose.
T[] forwardDifference(T)(in T[] data, in int level) pure nothrow in { assert(level >= 0 && level < data.length); } body { auto result = data.dup; foreach (immutable i; 0 .. level) foreach (immutable j, ref el; result[0 .. $ - i - 1]) el = result[j + 1] - el; result.length -= level; ...
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Transform the following Elixir implementation into C, maintaining the same output and logic.
defmodule Diff do def forward(list,i\\1) do forward(list,[],i) end def forward([_],diffs,1), do: IO.inspect diffs def forward([_],diffs,i), do: forward(diffs,[],i-1) def forward([val1,val2|vals],diffs,i) do forward([val2|vals],diffs++[val2-val1],i) end end Enum.each(1..9, fn i -> Diff.forward(...
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Port the following code from Elixir to C# with equivalent syntax and logic.
defmodule Diff do def forward(list,i\\1) do forward(list,[],i) end def forward([_],diffs,1), do: IO.inspect diffs def forward([_],diffs,i), do: forward(diffs,[],i-1) def forward([val1,val2|vals],diffs,i) do forward([val2|vals],diffs++[val2-val1],i) end end Enum.each(1..9, fn i -> Diff.forward(...
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Keep all operations the same but rewrite the snippet in Java.
defmodule Diff do def forward(list,i\\1) do forward(list,[],i) end def forward([_],diffs,1), do: IO.inspect diffs def forward([_],diffs,i), do: forward(diffs,[],i-1) def forward([val1,val2|vals],diffs,i) do forward([val2|vals],diffs++[val2-val1],i) end end Enum.each(1..9, fn i -> Diff.forward(...
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Transform the following Elixir implementation into Python, maintaining the same output and logic.
defmodule Diff do def forward(list,i\\1) do forward(list,[],i) end def forward([_],diffs,1), do: IO.inspect diffs def forward([_],diffs,i), do: forward(diffs,[],i-1) def forward([val1,val2|vals],diffs,i) do forward([val2|vals],diffs++[val2-val1],i) end end Enum.each(1..9, fn i -> Diff.forward(...
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Port the following code from Elixir to VB with equivalent syntax and logic.
defmodule Diff do def forward(list,i\\1) do forward(list,[],i) end def forward([_],diffs,1), do: IO.inspect diffs def forward([_],diffs,i), do: forward(diffs,[],i-1) def forward([val1,val2|vals],diffs,i) do forward([val2|vals],diffs++[val2-val1],i) end end Enum.each(1..9, fn i -> Diff.forward(...
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Rewrite the snippet below in Go so it works the same as the original Elixir code.
defmodule Diff do def forward(list,i\\1) do forward(list,[],i) end def forward([_],diffs,1), do: IO.inspect diffs def forward([_],diffs,i), do: forward(diffs,[],i-1) def forward([val1,val2|vals],diffs,i) do forward([val2|vals],diffs++[val2-val1],i) end end Enum.each(1..9, fn i -> Diff.forward(...
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Write a version of this Erlang function in C with identical behavior.
-module(forward_difference). -export([difference/1, difference/2]). -export([task/0]). -define(TEST_DATA,[90, 47, 58, 29, 22, 32, 55, 5, 55, 73]). difference([X|Xs]) -> {Result,_} = lists:mapfoldl(fun (N_2,N_1) -> {N_2 - N_1, N_2} end, X, Xs), Result. difference([],_) -> []; difference(List,0) -> List; diffe...
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Rewrite this program in C# while keeping its functionality equivalent to the Erlang version.
-module(forward_difference). -export([difference/1, difference/2]). -export([task/0]). -define(TEST_DATA,[90, 47, 58, 29, 22, 32, 55, 5, 55, 73]). difference([X|Xs]) -> {Result,_} = lists:mapfoldl(fun (N_2,N_1) -> {N_2 - N_1, N_2} end, X, Xs), Result. difference([],_) -> []; difference(List,0) -> List; diffe...
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Translate this program into C++ but keep the logic exactly as in Erlang.
-module(forward_difference). -export([difference/1, difference/2]). -export([task/0]). -define(TEST_DATA,[90, 47, 58, 29, 22, 32, 55, 5, 55, 73]). difference([X|Xs]) -> {Result,_} = lists:mapfoldl(fun (N_2,N_1) -> {N_2 - N_1, N_2} end, X, Xs), Result. difference([],_) -> []; difference(List,0) -> List; diffe...
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Convert the following code from Erlang to Java, ensuring the logic remains intact.
-module(forward_difference). -export([difference/1, difference/2]). -export([task/0]). -define(TEST_DATA,[90, 47, 58, 29, 22, 32, 55, 5, 55, 73]). difference([X|Xs]) -> {Result,_} = lists:mapfoldl(fun (N_2,N_1) -> {N_2 - N_1, N_2} end, X, Xs), Result. difference([],_) -> []; difference(List,0) -> List; diffe...
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Convert this Erlang block to Python, preserving its control flow and logic.
-module(forward_difference). -export([difference/1, difference/2]). -export([task/0]). -define(TEST_DATA,[90, 47, 58, 29, 22, 32, 55, 5, 55, 73]). difference([X|Xs]) -> {Result,_} = lists:mapfoldl(fun (N_2,N_1) -> {N_2 - N_1, N_2} end, X, Xs), Result. difference([],_) -> []; difference(List,0) -> List; diffe...
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Convert this Erlang block to VB, preserving its control flow and logic.
-module(forward_difference). -export([difference/1, difference/2]). -export([task/0]). -define(TEST_DATA,[90, 47, 58, 29, 22, 32, 55, 5, 55, 73]). difference([X|Xs]) -> {Result,_} = lists:mapfoldl(fun (N_2,N_1) -> {N_2 - N_1, N_2} end, X, Xs), Result. difference([],_) -> []; difference(List,0) -> List; diffe...
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Rewrite this program in Go while keeping its functionality equivalent to the Erlang version.
-module(forward_difference). -export([difference/1, difference/2]). -export([task/0]). -define(TEST_DATA,[90, 47, 58, 29, 22, 32, 55, 5, 55, 73]). difference([X|Xs]) -> {Result,_} = lists:mapfoldl(fun (N_2,N_1) -> {N_2 - N_1, N_2} end, X, Xs), Result. difference([],_) -> []; difference(List,0) -> List; diffe...
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Translate the given F# code snippet into C without altering its behavior.
let rec ForwardDifference input n = match n with | _ when input = [] || n < 0 -> [] | 0 -> input | _ -> ForwardDifference (input.Tail |> Seq.zip input |> Seq.map (fun (a, b) -> b-a)...
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Change the programming language of this snippet from F# to C# without modifying what it does.
let rec ForwardDifference input n = match n with | _ when input = [] || n < 0 -> [] | 0 -> input | _ -> ForwardDifference (input.Tail |> Seq.zip input |> Seq.map (fun (a, b) -> b-a)...
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Transform the following F# implementation into C++, maintaining the same output and logic.
let rec ForwardDifference input n = match n with | _ when input = [] || n < 0 -> [] | 0 -> input | _ -> ForwardDifference (input.Tail |> Seq.zip input |> Seq.map (fun (a, b) -> b-a)...
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Write the same code in Java as shown below in F#.
let rec ForwardDifference input n = match n with | _ when input = [] || n < 0 -> [] | 0 -> input | _ -> ForwardDifference (input.Tail |> Seq.zip input |> Seq.map (fun (a, b) -> b-a)...
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Convert the following code from F# to Python, ensuring the logic remains intact.
let rec ForwardDifference input n = match n with | _ when input = [] || n < 0 -> [] | 0 -> input | _ -> ForwardDifference (input.Tail |> Seq.zip input |> Seq.map (fun (a, b) -> b-a)...
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Change the following F# code into VB without altering its purpose.
let rec ForwardDifference input n = match n with | _ when input = [] || n < 0 -> [] | 0 -> input | _ -> ForwardDifference (input.Tail |> Seq.zip input |> Seq.map (fun (a, b) -> b-a)...
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Please provide an equivalent version of this F# code in Go.
let rec ForwardDifference input n = match n with | _ when input = [] || n < 0 -> [] | 0 -> input | _ -> ForwardDifference (input.Tail |> Seq.zip input |> Seq.map (fun (a, b) -> b-a)...
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Transform the following Factor implementation into C, maintaining the same output and logic.
USING: kernel math math.vectors sequences ; IN: rosetacode : 1-order ( seq -- seq' ) [ rest-slice ] keep v- ; : n-order ( seq n -- seq' ) dup 0 <= [ drop ] [ [ 1-order ] times ] if ;
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Maintain the same structure and functionality when rewriting this code in C#.
USING: kernel math math.vectors sequences ; IN: rosetacode : 1-order ( seq -- seq' ) [ rest-slice ] keep v- ; : n-order ( seq n -- seq' ) dup 0 <= [ drop ] [ [ 1-order ] times ] if ;
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Produce a language-to-language conversion: from Factor to C++, same semantics.
USING: kernel math math.vectors sequences ; IN: rosetacode : 1-order ( seq -- seq' ) [ rest-slice ] keep v- ; : n-order ( seq n -- seq' ) dup 0 <= [ drop ] [ [ 1-order ] times ] if ;
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Convert this Factor snippet to Java and keep its semantics consistent.
USING: kernel math math.vectors sequences ; IN: rosetacode : 1-order ( seq -- seq' ) [ rest-slice ] keep v- ; : n-order ( seq n -- seq' ) dup 0 <= [ drop ] [ [ 1-order ] times ] if ;
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Please provide an equivalent version of this Factor code in Python.
USING: kernel math math.vectors sequences ; IN: rosetacode : 1-order ( seq -- seq' ) [ rest-slice ] keep v- ; : n-order ( seq n -- seq' ) dup 0 <= [ drop ] [ [ 1-order ] times ] if ;
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Rewrite this program in VB while keeping its functionality equivalent to the Factor version.
USING: kernel math math.vectors sequences ; IN: rosetacode : 1-order ( seq -- seq' ) [ rest-slice ] keep v- ; : n-order ( seq n -- seq' ) dup 0 <= [ drop ] [ [ 1-order ] times ] if ;
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Can you help me rewrite this code in Go instead of Factor, keeping it the same logically?
USING: kernel math math.vectors sequences ; IN: rosetacode : 1-order ( seq -- seq' ) [ rest-slice ] keep v- ; : n-order ( seq n -- seq' ) dup 0 <= [ drop ] [ [ 1-order ] times ] if ;
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Rewrite this program in C while keeping its functionality equivalent to the Forth version.
: forward-difference dup 0 ?do swap rot over i 1+ - 0 ?do dup i cells + dup cell+ @ over @ - swap ! loop swap rot loop - ; create a 90 , 47 , 58 , 29 , 22 , 32 , 55 , 5 , 55 , 73 , : test a 10 9 forward-difference bounds ?do i ? loop ; test
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Ensure the translated C# code behaves exactly like the original Forth snippet.
: forward-difference dup 0 ?do swap rot over i 1+ - 0 ?do dup i cells + dup cell+ @ over @ - swap ! loop swap rot loop - ; create a 90 , 47 , 58 , 29 , 22 , 32 , 55 , 5 , 55 , 73 , : test a 10 9 forward-difference bounds ?do i ? loop ; test
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Keep all operations the same but rewrite the snippet in C++.
: forward-difference dup 0 ?do swap rot over i 1+ - 0 ?do dup i cells + dup cell+ @ over @ - swap ! loop swap rot loop - ; create a 90 , 47 , 58 , 29 , 22 , 32 , 55 , 5 , 55 , 73 , : test a 10 9 forward-difference bounds ?do i ? loop ; test
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Ensure the translated Java code behaves exactly like the original Forth snippet.
: forward-difference dup 0 ?do swap rot over i 1+ - 0 ?do dup i cells + dup cell+ @ over @ - swap ! loop swap rot loop - ; create a 90 , 47 , 58 , 29 , 22 , 32 , 55 , 5 , 55 , 73 , : test a 10 9 forward-difference bounds ?do i ? loop ; test
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Write the same code in Python as shown below in Forth.
: forward-difference dup 0 ?do swap rot over i 1+ - 0 ?do dup i cells + dup cell+ @ over @ - swap ! loop swap rot loop - ; create a 90 , 47 , 58 , 29 , 22 , 32 , 55 , 5 , 55 , 73 , : test a 10 9 forward-difference bounds ?do i ? loop ; test
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Ensure the translated VB code behaves exactly like the original Forth snippet.
: forward-difference dup 0 ?do swap rot over i 1+ - 0 ?do dup i cells + dup cell+ @ over @ - swap ! loop swap rot loop - ; create a 90 , 47 , 58 , 29 , 22 , 32 , 55 , 5 , 55 , 73 , : test a 10 9 forward-difference bounds ?do i ? loop ; test
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Change the programming language of this snippet from Forth to Go without modifying what it does.
: forward-difference dup 0 ?do swap rot over i 1+ - 0 ?do dup i cells + dup cell+ @ over @ - swap ! loop swap rot loop - ; create a 90 , 47 , 58 , 29 , 22 , 32 , 55 , 5 , 55 , 73 , : test a 10 9 forward-difference bounds ?do i ? loop ; test
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Translate the given Fortran code snippet into C# without altering its behavior.
MODULE DIFFERENCE IMPLICIT NONE CONTAINS SUBROUTINE Fdiff(a, n) INTEGER, INTENT(IN) :: a(:), n INTEGER :: b(SIZE(a)) INTEGER :: i, j, arraysize b = a arraysize = SIZE(b) DO i = arraysize-1, arraysize-n, -1 DO j = 1, i b(j) = b(j+1) - b(j) END DO END DO W...
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Port the following code from Fortran to C++ with equivalent syntax and logic.
MODULE DIFFERENCE IMPLICIT NONE CONTAINS SUBROUTINE Fdiff(a, n) INTEGER, INTENT(IN) :: a(:), n INTEGER :: b(SIZE(a)) INTEGER :: i, j, arraysize b = a arraysize = SIZE(b) DO i = arraysize-1, arraysize-n, -1 DO j = 1, i b(j) = b(j+1) - b(j) END DO END DO W...
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Change the following Fortran code into C without altering its purpose.
MODULE DIFFERENCE IMPLICIT NONE CONTAINS SUBROUTINE Fdiff(a, n) INTEGER, INTENT(IN) :: a(:), n INTEGER :: b(SIZE(a)) INTEGER :: i, j, arraysize b = a arraysize = SIZE(b) DO i = arraysize-1, arraysize-n, -1 DO j = 1, i b(j) = b(j+1) - b(j) END DO END DO W...
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Change the following Fortran code into Java without altering its purpose.
MODULE DIFFERENCE IMPLICIT NONE CONTAINS SUBROUTINE Fdiff(a, n) INTEGER, INTENT(IN) :: a(:), n INTEGER :: b(SIZE(a)) INTEGER :: i, j, arraysize b = a arraysize = SIZE(b) DO i = arraysize-1, arraysize-n, -1 DO j = 1, i b(j) = b(j+1) - b(j) END DO END DO W...
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Translate this program into Python but keep the logic exactly as in Fortran.
MODULE DIFFERENCE IMPLICIT NONE CONTAINS SUBROUTINE Fdiff(a, n) INTEGER, INTENT(IN) :: a(:), n INTEGER :: b(SIZE(a)) INTEGER :: i, j, arraysize b = a arraysize = SIZE(b) DO i = arraysize-1, arraysize-n, -1 DO j = 1, i b(j) = b(j+1) - b(j) END DO END DO W...
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Produce a language-to-language conversion: from Fortran to VB, same semantics.
MODULE DIFFERENCE IMPLICIT NONE CONTAINS SUBROUTINE Fdiff(a, n) INTEGER, INTENT(IN) :: a(:), n INTEGER :: b(SIZE(a)) INTEGER :: i, j, arraysize b = a arraysize = SIZE(b) DO i = arraysize-1, arraysize-n, -1 DO j = 1, i b(j) = b(j+1) - b(j) END DO END DO W...
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Generate a PHP translation of this Fortran snippet without changing its computational steps.
MODULE DIFFERENCE IMPLICIT NONE CONTAINS SUBROUTINE Fdiff(a, n) INTEGER, INTENT(IN) :: a(:), n INTEGER :: b(SIZE(a)) INTEGER :: i, j, arraysize b = a arraysize = SIZE(b) DO i = arraysize-1, arraysize-n, -1 DO j = 1, i b(j) = b(j+1) - b(j) END DO END DO W...
<?php function forwardDiff($anArray, $times = 1) { if ($times <= 0) { return $anArray; } for ($accumilation = array(), $i = 1, $j = count($anArray); $i < $j; ++$i) { $accumilation[] = $anArray[$i] - $anArray[$i - 1]; } if ($times === 1) { return $accumilation; } return forwardDiff($accumilation, $times ...
Port the following code from Haskell to C with equivalent syntax and logic.
forwardDifference :: Num a => [a] -> [a] forwardDifference = tail >>= zipWith (-) nthForwardDifference :: Num a => [a] -> Int -> [a] nthForwardDifference = (!!) . iterate forwardDifference main :: IO () main = mapM_ print $ take 10 (iterate forwardDifference [90, 47, 58, 29, 22, 32, 55, 5, 55, 73])
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Transform the following Haskell implementation into C#, maintaining the same output and logic.
forwardDifference :: Num a => [a] -> [a] forwardDifference = tail >>= zipWith (-) nthForwardDifference :: Num a => [a] -> Int -> [a] nthForwardDifference = (!!) . iterate forwardDifference main :: IO () main = mapM_ print $ take 10 (iterate forwardDifference [90, 47, 58, 29, 22, 32, 55, 5, 55, 73])
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Convert this Haskell block to C++, preserving its control flow and logic.
forwardDifference :: Num a => [a] -> [a] forwardDifference = tail >>= zipWith (-) nthForwardDifference :: Num a => [a] -> Int -> [a] nthForwardDifference = (!!) . iterate forwardDifference main :: IO () main = mapM_ print $ take 10 (iterate forwardDifference [90, 47, 58, 29, 22, 32, 55, 5, 55, 73])
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Write the same algorithm in Java as shown in this Haskell implementation.
forwardDifference :: Num a => [a] -> [a] forwardDifference = tail >>= zipWith (-) nthForwardDifference :: Num a => [a] -> Int -> [a] nthForwardDifference = (!!) . iterate forwardDifference main :: IO () main = mapM_ print $ take 10 (iterate forwardDifference [90, 47, 58, 29, 22, 32, 55, 5, 55, 73])
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Generate a Python translation of this Haskell snippet without changing its computational steps.
forwardDifference :: Num a => [a] -> [a] forwardDifference = tail >>= zipWith (-) nthForwardDifference :: Num a => [a] -> Int -> [a] nthForwardDifference = (!!) . iterate forwardDifference main :: IO () main = mapM_ print $ take 10 (iterate forwardDifference [90, 47, 58, 29, 22, 32, 55, 5, 55, 73])
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Produce a language-to-language conversion: from Haskell to VB, same semantics.
forwardDifference :: Num a => [a] -> [a] forwardDifference = tail >>= zipWith (-) nthForwardDifference :: Num a => [a] -> Int -> [a] nthForwardDifference = (!!) . iterate forwardDifference main :: IO () main = mapM_ print $ take 10 (iterate forwardDifference [90, 47, 58, 29, 22, 32, 55, 5, 55, 73])
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Write the same code in Go as shown below in Haskell.
forwardDifference :: Num a => [a] -> [a] forwardDifference = tail >>= zipWith (-) nthForwardDifference :: Num a => [a] -> Int -> [a] nthForwardDifference = (!!) . iterate forwardDifference main :: IO () main = mapM_ print $ take 10 (iterate forwardDifference [90, 47, 58, 29, 22, 32, 55, 5, 55, 73])
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Translate this program into C but keep the logic exactly as in Icon.
procedure main(A) every order := 1 to (*A-1) do showList(order, fdiff(A, order)) end procedure fdiff(A, order) every 1 to order do { every put(B := [], A[i := 2 to *A] - A[i-1]) A := B } return A end procedure showList(order, L) writes(right(order,3),": ") every writes(!...
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Keep all operations the same but rewrite the snippet in C#.
procedure main(A) every order := 1 to (*A-1) do showList(order, fdiff(A, order)) end procedure fdiff(A, order) every 1 to order do { every put(B := [], A[i := 2 to *A] - A[i-1]) A := B } return A end procedure showList(order, L) writes(right(order,3),": ") every writes(!...
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Port the following code from Icon to C++ with equivalent syntax and logic.
procedure main(A) every order := 1 to (*A-1) do showList(order, fdiff(A, order)) end procedure fdiff(A, order) every 1 to order do { every put(B := [], A[i := 2 to *A] - A[i-1]) A := B } return A end procedure showList(order, L) writes(right(order,3),": ") every writes(!...
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Rewrite this program in Java while keeping its functionality equivalent to the Icon version.
procedure main(A) every order := 1 to (*A-1) do showList(order, fdiff(A, order)) end procedure fdiff(A, order) every 1 to order do { every put(B := [], A[i := 2 to *A] - A[i-1]) A := B } return A end procedure showList(order, L) writes(right(order,3),": ") every writes(!...
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Port the provided Icon code into Python while preserving the original functionality.
procedure main(A) every order := 1 to (*A-1) do showList(order, fdiff(A, order)) end procedure fdiff(A, order) every 1 to order do { every put(B := [], A[i := 2 to *A] - A[i-1]) A := B } return A end procedure showList(order, L) writes(right(order,3),": ") every writes(!...
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...
Produce a functionally identical VB code for the snippet given in Icon.
procedure main(A) every order := 1 to (*A-1) do showList(order, fdiff(A, order)) end procedure fdiff(A, order) every 1 to order do { every put(B := [], A[i := 2 to *A] - A[i-1]) A := B } return A end procedure showList(order, L) writes(right(order,3),": ") every writes(!...
Module ForwardDifference Sub Main() Dim lNum As New List(Of Integer)(New Integer() {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}) For i As UInteger = 0 To 9 Console.WriteLine(String.Join(" ", (From n In Difference(i, lNum) Select String.Format("{0,5}", n)).ToArray())) Next Con...
Keep all operations the same but rewrite the snippet in Go.
procedure main(A) every order := 1 to (*A-1) do showList(order, fdiff(A, order)) end procedure fdiff(A, order) every 1 to order do { every put(B := [], A[i := 2 to *A] - A[i-1]) A := B } return A end procedure showList(order, L) writes(right(order,3),": ") every writes(!...
package main import "fmt" func main() { a := []int{90, 47, 58, 29, 22, 32, 55, 5, 55, 73} fmt.Println(a) fmt.Println(fd(a, 9)) } func fd(a []int, ord int) []int { for i := 0; i < ord; i++ { for j := 0; j < len(a)-i-1; j++ { a[j] = a[j+1] - a[j] } } return a[:len(a)...
Write the same algorithm in C as shown in this J implementation.
fd=: 2&(-~/\)
#include <stdlib.h> #include <string.h> #include <stdio.h> double* fwd_diff(double* x, unsigned int len, unsigned int order) { unsigned int i, j; double* y; if (order >= len) return 0; y = malloc(sizeof(double) * len); if (!order) { memcpy(y, x, sizeof(double) * len); return y; } for (j = 0; j < orde...
Maintain the same structure and functionality when rewriting this code in C#.
fd=: 2&(-~/\)
using System; using System.Collections.Generic; using System.Linq; class Program { static IEnumerable<int> ForwardDifference(IEnumerable<int> sequence, uint order = 1u) { switch (order) { case 0u: return sequence; case 1u: return sequence....
Produce a language-to-language conversion: from J to C++, same semantics.
fd=: 2&(-~/\)
#include <vector> #include <iterator> #include <algorithm> template<typename InputIterator, typename OutputIterator> OutputIterator forward_difference(InputIterator first, InputIterator last, OutputIterator dest) { if (first == last) return dest; typedef typename...
Rewrite this program in Java while keeping its functionality equivalent to the J version.
fd=: 2&(-~/\)
import java.util.Arrays; public class FD { public static void main(String args[]) { double[] a = {90, 47, 58, 29, 22, 32, 55, 5, 55, 73}; System.out.println(Arrays.toString(dif(a, 1))); System.out.println(Arrays.toString(dif(a, 2))); System.out.println(Arrays.toString(dif(a, 9))); ...
Can you help me rewrite this code in Python instead of J, keeping it the same logically?
fd=: 2&(-~/\)
>>> dif = lambda s: [x-s[i] for i,x in enumerate(s[1:])] >>> >>> difn = lambda s, n: difn(dif(s), n-1) if n else s >>> s = [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 0) [90, 47, 58, 29, 22, 32, 55, 5, 55, 73] >>> difn(s, 1) [-43, 11, -29, -7, 10, 23, -50, 50, 18] >>> difn(s, 2) [54, -40, 22, 17, 13, -73, 100...