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Keep all operations the same but rewrite the snippet in REXX.
#include <stdbool.h> #include <stdio.h> #include <stdlib.h> #include <time.h> bool sixesThrowAgain = true; void init() { srand((unsigned int)time(NULL)); } int rollDice() { return rand() % 6 + 1; } int nextSquare(int square) { switch (square) { case 4: return 14; case 9: return 31; case ...
parse arg np seed . if np=='' | np=="," then np= 3 if datatype(seed, 'W') then call random ,,seed pad= left('',7) do k=1 for 100; @.k= k end ...
Maintain the same structure and functionality when rewriting this code in REXX.
O_RDONLY, O_WRONLY, or O_RDWR. O_CREAT, O_EXCL, O_NOCTTY, and O_TRUNC
w=length(abc)
Transform the following C implementation into REXX, maintaining the same output and logic.
#include <stdio.h> #include <stdlib.h> #include <string.h> void farey(int n) { typedef struct { int d, n; } frac; frac f1 = {0, 1}, f2 = {1, n}, t; int k; printf("%d/%d %d/%d", 0, 1, 1, n); while (f2.n > 1) { k = (n + f1.n) / f2.n; t = f1, f1 = f2, f2 = (frac) { f2.d * k - t.d, f2.n * k - t.n }; printf(" %...
parse arg LO HI INC . if LO=='' | LO=="," then LO= 1 if HI=='' | HI=="," then HI= LO if INC=='' | INC=="," then INC= 1 sw= linesize() - 1 oLO= LO do j=abs(LO)...
Translate the given C code snippet into REXX without altering its behavior.
#include <stdio.h> #include <stdlib.h> #include <string.h> void farey(int n) { typedef struct { int d, n; } frac; frac f1 = {0, 1}, f2 = {1, n}, t; int k; printf("%d/%d %d/%d", 0, 1, 1, n); while (f2.n > 1) { k = (n + f1.n) / f2.n; t = f1, f1 = f2, f2 = (frac) { f2.d * k - t.d, f2.n * k - t.n }; printf(" %...
parse arg LO HI INC . if LO=='' | LO=="," then LO= 1 if HI=='' | HI=="," then HI= LO if INC=='' | INC=="," then INC= 1 sw= linesize() - 1 oLO= LO do j=abs(LO)...
Rewrite the snippet below in REXX so it works the same as the original C code.
#include<stdio.h> #include<stdlib.h> int isprime( int p ) { int i; if(p==2) return 1; if(!(p%2)) return 0; for(i=3; i*i<=p; i+=2) { if(!(p%i)) return 0; } return 1; } int main( void ) { int s=0, p, i=1; for(p=2;p<=999;p++) { if(isprime(p)) { if(i%2) { ...
parse arg hi . if hi=='' | hi=="," then hi= 1000 call genP title= 'odd indexed primes the sum of the odd indexed primes' say ' index │'center(title, 65) say '───────┼'center("" , 65, '─') found...
Maintain the same structure and functionality when rewriting this code in REXX.
#include<stdio.h> #include<stdlib.h> int isprime( int p ) { int i; if(p==2) return 1; if(!(p%2)) return 0; for(i=3; i*i<=p; i+=2) { if(!(p%i)) return 0; } return 1; } int main( void ) { int s=0, p, i=1; for(p=2;p<=999;p++) { if(isprime(p)) { if(i%2) { ...
parse arg hi . if hi=='' | hi=="," then hi= 1000 call genP title= 'odd indexed primes the sum of the odd indexed primes' say ' index │'center(title, 65) say '───────┼'center("" , 65, '─') found...
Change the programming language of this snippet from C to REXX without modifying what it does.
#include<stdlib.h> #include<string.h> #include<stdio.h> unsigned long long bruteForceProperDivisorSum(unsigned long long n){ unsigned long long i,sum = 0; for(i=1;i<(n+1)/2;i++) if(n%i==0 && n!=i) sum += i; return sum; } void printSeries(unsigned long long* arr,int size,char* type){ int i; printf("\n...
parse arg low high $L high= word(high low 10,1); low= word(low 1,1) if $L='' then $L=11 12 28 496 220 1184 12496 1264460 790 909 562 1064 1488 15355717786080 numeric digits 100 big= 2**47; NTlimit= 16 + 1 numeric digits max(9, length...
Convert the following code from C to REXX, ensuring the logic remains intact.
#include<stdlib.h> #include<string.h> #include<stdio.h> unsigned long long bruteForceProperDivisorSum(unsigned long long n){ unsigned long long i,sum = 0; for(i=1;i<(n+1)/2;i++) if(n%i==0 && n!=i) sum += i; return sum; } void printSeries(unsigned long long* arr,int size,char* type){ int i; printf("\n...
parse arg low high $L high= word(high low 10,1); low= word(low 1,1) if $L='' then $L=11 12 28 496 220 1184 12496 1264460 790 909 562 1064 1488 15355717786080 numeric digits 100 big= 2**47; NTlimit= 16 + 1 numeric digits max(9, length...
Can you help me rewrite this code in REXX instead of C, keeping it the same logically?
#include <stdio.h> main(){ unsigned char uc; char c; enum{e1, e2, e3}e123; short si; int i; long li; unsigned short su; unsigned u; unsigned long lu; float sf; float f; double lf; long double llf; union {char c; unsigned u; int i; float f; }ucuif; struct {char c; unsigned u; int i; float ...
digs=digits() ; say digs a=.1.2...$ ; say a a=+7 ; say a a='+66' ; say a a='- 66.' ; ...
Generate a REXX translation of this C snippet without changing its computational steps.
#include <stdio.h> main(){ unsigned char uc; char c; enum{e1, e2, e3}e123; short si; int i; long li; unsigned short su; unsigned u; unsigned long lu; float sf; float f; double lf; long double llf; union {char c; unsigned u; int i; float f; }ucuif; struct {char c; unsigned u; int i; float ...
digs=digits() ; say digs a=.1.2...$ ; say a a=+7 ; say a a='+66' ; say a a='- 66.' ; ...
Produce a functionally identical REXX code for the snippet given in C.
#include <stdio.h> #include <string.h> typedef int bool; typedef unsigned long long ull; #define TRUE 1 #define FALSE 0 bool is_prime(ull n) { ull d; if (n < 2) return FALSE; if (!(n % 2)) return n == 2; if (!(n % 3)) return n == 3; d = 5; while (d * d <= n) { if (!(n % d)) return F...
parse arg bet.1 bet.2 bet.3 highP . if bet.1=='' | bet.1=="," then bet.1= 1..45 if bet.2=='' | bet.2=="," then bet.2= 241..250 if bet.3=='' | bet.3=="," then bet.3= 391..400 if highP=='' | highP=="," then highP= 1000000 call genP do j=1 for 3...
Convert this C block to REXX, preserving its control flow and logic.
#include <stdbool.h> #include <stdint.h> #include <stdio.h> bool isPrime(uint64_t n) { uint64_t test; if (n < 2) return false; if (n % 2 == 0) return n == 2; if (n % 3 == 0) return n == 3; test = 5; while (test * test < n) { if (n % test == 0) return false; test += 2; ...
do j=1; if \isPrime(j) then iterate r= testMer(j) if r==0 then say right('M'j, 10) "──────── is a Mersenne prime." else say right('M'j, 50) "is composite, a factor:" r end ex...
Produce a functionally identical REXX code for the snippet given in C.
#include <stdbool.h> #include <stdint.h> #include <stdio.h> bool isPrime(uint64_t n) { uint64_t test; if (n < 2) return false; if (n % 2 == 0) return n == 2; if (n % 3 == 0) return n == 3; test = 5; while (test * test < n) { if (n % test == 0) return false; test += 2; ...
do j=1; if \isPrime(j) then iterate r= testMer(j) if r==0 then say right('M'j, 10) "──────── is a Mersenne prime." else say right('M'j, 50) "is composite, a factor:" r end ex...
Write the same algorithm in REXX as shown in this C implementation.
#include <stdio.h> #include <stdlib.h> #include <stdbool.h> #include <math.h> #include <locale.h> bool *sieve(int limit) { int i, p; limit++; bool *c = calloc(limit, sizeof(bool)); c[0] = true; c[1] = true; for (i = 4; i < limit; i += 2) c[i] = true; p = 3; while (true) { ...
parse arg hi cols . if hi=='' | hi=="," then hi= 15000 if cols=='' | cols=="," then cols= 10 call genP w= 10 title= 'the smallest primes < ' commas(hi) ...
Rewrite the snippet below in REXX so it works the same as the original C code.
#include <stdio.h> #include <stdlib.h> #include <stdbool.h> #include <math.h> #include <locale.h> bool *sieve(int limit) { int i, p; limit++; bool *c = calloc(limit, sizeof(bool)); c[0] = true; c[1] = true; for (i = 4; i < limit; i += 2) c[i] = true; p = 3; while (true) { ...
parse arg hi cols . if hi=='' | hi=="," then hi= 15000 if cols=='' | cols=="," then cols= 10 call genP w= 10 title= 'the smallest primes < ' commas(hi) ...
Transform the following C implementation into REXX, maintaining the same output and logic.
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <locale.h> #define TRUE 1 #define FALSE 0 typedef unsigned char bool; void sieve(bool *c, int limit) { int i, p = 3, p2; c[0] = TRUE; c[1] = TRUE; for (;;) { p2 = p * p; if (p2 >= limit) { break;...
parse arg N endU end2 end3 end4 end5 . if N=='' | N=="," then N= 1000035 - 1 if endU=='' | endU=="," then endU= 10 if end2=='' | end2=="," then end2= 5 if end3=='' | end3=="," then end3= 5 if end4=='' | end4=="," then end4= 5 if end5=='' | end5...
Write the same code in REXX as shown below in C.
#include <stdio.h> #include <stdlib.h> typedef unsigned long long xint; typedef unsigned uint; typedef struct { uint x, y; xint value; } sum_t; xint *cube; uint n_cubes; sum_t *pq; uint pq_len, pq_cap; void add_cube(void) { uint x = n_cubes++; cube = realloc(cube, sizeof(xint) * (n_cubes + 1)); cube[n_cubes] ...
parse arg L.1 H.1 L.2 H.2 L.3 H.3 . if L.1=='' | L.1=="," then L.1= 1 if H.1=='' | H.1=="," then H.1= 25 if L.2=='' | L.2=="," then L.2= 454 if H.2=='' | H.2=="," then H.2= 456 if L.3=='' | L.3=="," then L.3=2000 if H.3=='' | H.3...
Please provide an equivalent version of this C code in REXX.
#include <stdbool.h> #include <stdint.h> #include <stdio.h> #include <stdlib.h> const int PRIMES[] = { 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211...
parse arg N kind _ . 1 . okind; upper kind if N=='' | N=="," then N= 36 if kind=='' | kind=="," then kind= 'STRONG' if _\=='' then call ser 'too many arguments specified.' if kind\=='WEAK' & kind\=='STRONG' then call ser 'invalid 2nd argument: ' okind ...
Generate a REXX translation of this C snippet without changing its computational steps.
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <gmp.h> void mpz_left_fac_ui(mpz_t rop, unsigned long op) { mpz_t t1; mpz_init_set_ui(t1, 1); mpz_set_ui(rop, 0); size_t i; for (i = 1; i <= op; ++i) { mpz_add(rop, rop, t1); mpz_mul_ui(t1, t1, i); } mpz_c...
parse arg bot top inc . if bot=='' | bot=="," then bot= 1 if top=='' | top=="," then top= bot if inc='' | inc=="," then inc= 1 tell= bot<0 bot= abs(bot) w= length(top) ...
Produce a functionally identical REXX code for the snippet given in C.
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <gmp.h> void mpz_left_fac_ui(mpz_t rop, unsigned long op) { mpz_t t1; mpz_init_set_ui(t1, 1); mpz_set_ui(rop, 0); size_t i; for (i = 1; i <= op; ++i) { mpz_add(rop, rop, t1); mpz_mul_ui(t1, t1, i); } mpz_c...
parse arg bot top inc . if bot=='' | bot=="," then bot= 1 if top=='' | top=="," then top= bot if inc='' | inc=="," then inc= 1 tell= bot<0 bot= abs(bot) w= length(top) ...
Change the programming language of this snippet from C to REXX without modifying what it does.
#include <stdbool.h> #include <stdio.h> #include <string.h> #define LIMIT 3000 void init_sieve(unsigned char sieve[], int limit) { int i, j; for (i = 0; i < limit; i++) { sieve[i] = 1; } sieve[0] = 0; sieve[1] = 0; for (i = 2; i < limit; i++) { if (sieve[i]) { for...
parse arg hi . if hi=='' | hi=="," then hi= 30 tell= hi>0; hi= abs(hi); hi= hi - 1 if tell>0 then say 'list of unique triplet strange primes whose sum is a prime.:' call genP finds= 0 ...
Change the following C code into REXX without altering its purpose.
#include <stdbool.h> #include <stdio.h> #include <string.h> #define LIMIT 3000 void init_sieve(unsigned char sieve[], int limit) { int i, j; for (i = 0; i < limit; i++) { sieve[i] = 1; } sieve[0] = 0; sieve[1] = 0; for (i = 2; i < limit; i++) { if (sieve[i]) { for...
parse arg hi . if hi=='' | hi=="," then hi= 30 tell= hi>0; hi= abs(hi); hi= hi - 1 if tell>0 then say 'list of unique triplet strange primes whose sum is a prime.:' call genP finds= 0 ...
Convert this C block to REXX, preserving its control flow and logic.
#include <locale.h> #include <stdbool.h> #include <stdint.h> #include <stdio.h> bool is_prime(uint64_t n) { if (n < 2) return false; if (n % 2 == 0) return n == 2; if (n % 3 == 0) return n == 3; for (uint64_t p = 5; p * p <= n; p += 4) { if (n % p == 0) retur...
numeric digits 92 parse arg n . if n=='' | n=="," then n= 42 w= length(n) + 1; wm= digits()%4 say center('n', w ) center("Motzkin[n]", wm) center(' primality', 11) say center('' , w, "─") center('' ...
Ensure the translated REXX code behaves exactly like the original C snippet.
#include <stdio.h> #define sqr(x) ((x) * (x)) #define greet printf("Hello There!\n") int twice(int x) { return 2 * x; } int main(void) { int x; printf("This will demonstrate function and label scopes.\n"); printf("All output is happening through printf(), a function declared in the header stdio.h, which is exte...
blarney = -0 signal do_add ttt = sinD(30) DO_Add: say 'calling the sub: add.2.args' call add.2.args 1, 7 ...
Convert this C snippet to REXX and keep its semantics consistent.
#include<stdio.h> #include<stdlib.h> #include<math.h> int isprime( int p ) { int i; if(p==2) return 1; if(!(p%2)) return 0; for(i=3; i*i<=p; i+=2) { if(!(p%i)) return 0; } return 1; } int main(void) { int np = 1, d, i, n; printf( "3 " ); for(d=1; d<6; d++) { for(i=3...
parse arg hi cols dig . if hi=='' | hi=="," then hi= 4000 if cols=='' | cols=="," then cols= 10 if dig=='' | dig=="," then dig= 3 call genP w= 10 title= ' primes N ...
Rewrite the snippet below in REXX so it works the same as the original C code.
#include<stdio.h> #include<stdlib.h> #include<math.h> int isprime( int p ) { int i; if(p==2) return 1; if(!(p%2)) return 0; for(i=3; i*i<=p; i+=2) { if(!(p%i)) return 0; } return 1; } int main(void) { int np = 1, d, i, n; printf( "3 " ); for(d=1; d<6; d++) { for(i=3...
parse arg hi cols dig . if hi=='' | hi=="," then hi= 4000 if cols=='' | cols=="," then cols= 10 if dig=='' | dig=="," then dig= 3 call genP w= 10 title= ' primes N ...
Can you help me rewrite this code in REXX instead of C, keeping it the same logically?
#include<stdio.h> #include<stdlib.h> int isprime( int p ) { int i; if(p==2) return 1; if(!(p%2)) return 0; for(i=3; i*i<=p; i+=2) { if(!(p%i)) return 0; } return 1; } int nextprime( int p ) { int i=0; if(p==0) return 2; if(p<3) return p+1; while(!isprime(++i + p)); r...
parse arg hi cols . if hi=='' | hi=="," then hi= 100 if cols=='' | cols=="," then cols= 5 call genP hi do p=1 while @.p<hi end #m= # - 1 call genP @.# + @.#m - 1 w= 20 ...
Ensure the translated REXX code behaves exactly like the original C snippet.
#include<stdio.h> #include<stdlib.h> int isprime( int p ) { int i; if(p==2) return 1; if(!(p%2)) return 0; for(i=3; i*i<=p; i+=2) { if(!(p%i)) return 0; } return 1; } int nextprime( int p ) { int i=0; if(p==0) return 2; if(p<3) return p+1; while(!isprime(++i + p)); r...
parse arg hi cols . if hi=='' | hi=="," then hi= 100 if cols=='' | cols=="," then cols= 5 call genP hi do p=1 while @.p<hi end #m= # - 1 call genP @.# + @.#m - 1 w= 20 ...
Ensure the translated REXX code behaves exactly like the original C snippet.
#include <stdio.h> static int p[19] = {0, 0, 1, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0}; int isstrange(long n) { if (n < 10) return 0; for (; n >= 10; n /= 10) { if (!p[n%10 + (n/10)%10]) return 0; } return 1; } int main(void) { long n; int k = 0; for ...
parse arg LO HI . if LO=='' | LO=="," then LO= 101 if HI=='' | HI=="," then HI= 499 !.= 0; !.2= 1; !.3= 1; !.5= 1; !.7= 1 !.11= 1; !.13= 1; !.17= 1 $= #= 0 ...
Port the following code from C to REXX with equivalent syntax and logic.
#include <stdio.h> static int p[19] = {0, 0, 1, 1, 0, 1, 0, 1, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 0}; int isstrange(long n) { if (n < 10) return 0; for (; n >= 10; n /= 10) { if (!p[n%10 + (n/10)%10]) return 0; } return 1; } int main(void) { long n; int k = 0; for ...
parse arg LO HI . if LO=='' | LO=="," then LO= 101 if HI=='' | HI=="," then HI= 499 !.= 0; !.2= 1; !.3= 1; !.5= 1; !.7= 1 !.11= 1; !.13= 1; !.17= 1 $= #= 0 ...
Translate this program into REXX but keep the logic exactly as in C.
#include <locale.h> #include <stdbool.h> #include <stdint.h> #include <stdio.h> typedef uint32_t integer; integer next_prime_digit_number(integer n) { if (n == 0) return 2; switch (n % 10) { case 2: return n + 1; case 3: case 5: return n + 2; default: return 2 +...
parse arg n q if n=='' | n=="," then n= 25 if q='' then q= 100 1000 say '═══listing the first' n "SPDS primes═══" call spds n do i=1 for words(q)+1; y=word(q, i); if y=='' | y=="," then iterate ...
Convert this C snippet to REXX and keep its semantics consistent.
#include<stdlib.h> #include<ctype.h> #include<stdio.h> int** doublyEvenMagicSquare(int n) { if (n < 4 || n % 4 != 0) return NULL; int bits = 38505; int size = n * n; int mult = n / 4,i,r,c,bitPos; int** result = (int**)malloc(n*sizeof(int*)); for(i=0;i<n;i++) result[i] = (int*)malloc(n*sizeof(int)); fo...
n= 8; s= n%4; L= n%2-s+1; w= length(n**2) @.= 0; H= n%2+s call gen call diag call corn call midd call swap ...
Write the same code in REXX as shown below in C.
#include <stdio.h> #include <stdlib.h> #include <math.h> #define TRUE 1 #define FALSE 0 #define TRILLION 1000000000000 typedef unsigned char bool; typedef unsigned long long uint64; void sieve(uint64 limit, uint64 *primes, uint64 *length) { uint64 i, count, p, p2; bool *c = calloc(limit + 1, sizeof(bool)); ...
numeric digits 20 parse arg LO HI . if LO=='' | LO=="," then LO= 1 if HI=='' | HI=="," then HI= 145 sw= linesize() - 1 # = 0 $= ...
Generate a REXX translation of this C snippet without changing its computational steps.
#include <stdio.h> #include <stdlib.h> #include <time.h> typedef unsigned char bool; #define TRUE 1 #define FALSE 0 #define MILLION 1000000 #define BILLION 1000 * MILLION #define MAX_COUNT 2*BILLION + 9*9 + 1 void sieve(bool *sv) { int n = 0, s[8], a, b, c, d, e, f, g, h, i, j; for (a = 0; a < 2; ++a) { ...
parse arg n . if n=='' | n=="," then n= 50 tell = n>0; n= abs(n) @.= . do j=1 for n*10 $= j do...
Can you help me rewrite this code in REXX instead of C, keeping it the same logically?
#include <locale.h> #include <stdbool.h> #include <stdint.h> #include <stdio.h> uint64_t digit_sum(uint64_t n, uint64_t sum) { ++sum; while (n > 0 && n % 10 == 0) { sum -= 9; n /= 10; } return sum; } inline bool divisible(uint64_t n, uint64_t d) { if ((d & 1) == 0 && (n & 1) == 1...
parse arg lim . if lim=='' | lim==',' then lim= 10000000 numeric digits 2 + max(8, length(lim) ) gap= 0; old= 0 @gsa= 'gap starts at Niven #' call tell center('gap size', 12) cent...
Port the provided C code into REXX while preserving the original functionality.
#include<string.h> #include<stdlib.h> #include<ctype.h> #include<stdio.h> #define UNITS_LENGTH 13 int main(int argC,char* argV[]) { int i,reference; char *units[UNITS_LENGTH] = {"kilometer","meter","centimeter","tochka","liniya","diuym","vershok","piad","fut","arshin","sazhen","versta","milia"}; double factor, ...
numeric digits 200 KM= 1000; CM=100 sw= linesize() -1 parse arg N what _ __ if N=='' then call err 'no arguments specified.'...
Write a version of this C function in REXX with identical behavior.
#include <stdio.h> int pancake(int n) { int gap = 2, sum = 2, adj = -1; while (sum < n) { adj++; gap = gap * 2 - 1; sum += gap; } return n + adj; } int main() { int i, j; for (i = 0; i < 4; i++) { for (j = 1; j < 6; j++) { int n = i * 5 + j; ...
pad= center('' , 10) say pad center('pancakes', 10 ) center('pancake flips', 15 ) say pad center('' , 10, "─") center('', 15, "─") do #=1 for 20; say pad center(#, 10) center( pancake(#), 15) end exit 0...
Convert the following code from C to REXX, ensuring the logic remains intact.
#include <stdio.h> #include <math.h> #include <string.h> #define N 2200 int main(int argc, char **argv){ int a,b,c,d; int r[N+1]; memset(r,0,sizeof(r)); for(a=1; a<=N; a++){ for(b=a; b<=N; b++){ int aabb; if(a&1 && b&1) continue; aabb=a*a + b*b; for(c=b; c<=N; c++){ int aabbcc=aabb +...
parse arg hi . if hi=='' | hi=="," then hi=2200; high= 3 * hi @.=. !.=. do j=1 for high _= j*j; !._= j; if j<=hi then @.j= _ end d.=. ...
Generate an equivalent REXX version of this C code.
#include <stdbool.h> #include <stdio.h> #include <stdlib.h> typedef struct node_t { int x, y; struct node_t *prev, *next; } node; node *new_node(int x, int y) { node *n = malloc(sizeof(node)); n->x = x; n->y = y; n->next = NULL; n->prev = NULL; return n; } void free_node(node **n) { ...
all =.set~new Call time 'R' cnt.=0 do a=2 to 100 do b=a+1 to 100-2 p=a b if a+b>100 then leave b all~put(p) prd=a*b cnt.prd+=1 End End Say "There are" all~items "pairs where X+Y <=" max "(and X<Y)" spairs=.set~new Do Until all~items=0 do p over all d=decompositions(p) If take...
Produce a functionally identical REXX code for the snippet given in C.
#include <stdio.h> #include <stdlib.h> #include <string.h> #define MAX 12 char *super = 0; int pos, cnt[MAX]; int fact_sum(int n) { int s, x, f; for (s = 0, x = 0, f = 1; x < n; f *= ++x, s += f); return s; } int r(int n) { if (!n) return 0; char c = super[pos - n]; if (!--cnt[n]) { cnt[n] = n; if (!r(n-...
parse arg cycles . if cycles=='' | cycles=="," then cycles= 7 do n=0 to cycles #= 0; $.= do pop=1 for n; @.pop= d2x(pop); $.0= $.0 || @.pop end do while aPerm(n, 0) ...
Convert this C block to REXX, preserving its control flow and logic.
#include <stdio.h> #include <complex.h> #include <math.h> #define FMTSPEC(arg) _Generic((arg), \ float: "%f", double: "%f", \ long double: "%Lf", unsigned int: "%u", \ unsigned long: "%lu", unsigned long long: "%llu", \ int: "%d", long: "%ld", long long: "%lld", \ default: "(invalid type (%p)") #...
* 22.06.2014 Walter Pachl using a complex data class * ooRexx Distribution contains an elaborate complex class * parts of which are used here * see REXX for Extra Credit implementation *--------------------------------------------------------------------*/ Numeric Digits 1000 Call test_integer .complex~new(1e+12,0e-3)...
Rewrite this program in REXX while keeping its functionality equivalent to the C version.
#include<stdlib.h> #include<string.h> #include<unistd.h> #include<stdio.h> int main(int argC,char* argV[]) { char str[100]; const char d[2] = " "; char* token; int i = 0,times,lag; long int sum = 0, idle, lastSum = 0,lastIdle = 0; long double idleFraction; if(argC!=3) printf("Usage : %s <number of times /pr...
signal on halt numeric digits 20 parse arg n wait iFID . if n=='' | n="," then n= 10 if wait=='' | wait="," then wait= 1 if iFID=='' | iFID="," then iFID= '/proc/stat' prevTot = 0; ...
Maintain the same structure and functionality when rewriting this code in REXX.
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <time.h> void fatal(const char* message) { fprintf(stderr, "%s\n", message); exit(1); } void* xmalloc(size_t n) { void* ptr = malloc(n); if (ptr == NULL) fatal("Out of memory"); return ptr; } void* xrealloc(void* p, size_...
parse arg $ if $='' | $="," then $= 10 100 1000 10000 do k=1 for words($) x= Ulam( word($, k) ) say 'the ' commas(#)th(#) ' Ulam number is: ' commas(x) end exit 0 ...
Generate an equivalent REXX version of this C code.
#include <stdio.h> int a[17][17], idx[4]; int find_group(int type, int min_n, int max_n, int depth) { int i, n; if (depth == 4) { printf("totally %sconnected group:", type ? "" : "un"); for (i = 0; i < 4; i++) printf(" %d", idx[i]); putchar('\n'); return 1; } for (i = min_n; i < max_n; i++) { for (n = ...
@.=0; #=17 do d=0 for #; @.d.d= 2 end do k=1 by 0 while k<=8 do i=0 for #; j= (i+k) // # @.i.j= 1; @.j.i= 1 end k= k + k ...
Preserve the algorithm and functionality while converting the code from C to REXX.
#include <stdio.h> #include <string.h> #include <gmp.h> char *power_of_six(unsigned int n, char *buf) { mpz_t p; mpz_init(p); mpz_ui_pow_ui(p, 6, n); mpz_get_str(buf, 10, p); mpz_clear(p); return buf; } char *smallest_six(unsigned int n) { static char nbuf[32], powbuf[1024]; unsigned i...
numeric digits 100 parse arg hi . if hi=='' | hi=="," then hi= 22 w= 50 @smp6= ' smallest power of six (expressed in decimal) which contains N' say ' N │ power │'center(@...
Convert the following code from C to REXX, ensuring the logic remains intact.
#include<stdio.h> #include<ctype.h> void typeDetector(char* str){ if(isalnum(str[0])!=0) printf("\n%c is alphanumeric",str[0]); if(isalpha(str[0])!=0) printf("\n%c is alphabetic",str[0]); if(iscntrl(str[0])!=0) printf("\n%c is a control character",str[0]); if(isdigit(str[0])!=0) printf("\n%c is a digit",s...
signal on noValue y= 1938 ; call showType y y= 77.1 ; call showType y y= ; call showType y y= ' ' ; call showType y y= 'abc' ; call showType y y= 'ABC' ; ...
Write the same algorithm in REXX as shown in this C implementation.
#include <stdio.h> #include <stdbool.h> bool steady(int n) { int mask = 1; for (int d = n; d != 0; d /= 10) mask *= 10; return (n * n) % mask == n; } int main() { for (int i = 1; i < 10000; i++) if (steady(i)) printf("%4d^2 = %8d\n", i, i * i); return 0; }
Numeric Digits 50 Call time 'R' n=1000000000 Say 'Steady squares below' n Do i=1 To n c=right(i,1) If pos(c,'156')>0 Then Do i2=i*i If right(i2,length(i))=i Then Say right(i,length(n)) i2 End End Say time('E')
Translate this program into REXX but keep the logic exactly as in C.
#include <stdbool.h> #include <stdio.h> int primes[] = { 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 233, 239, 241, 251, 257, 263,...
parse arg N kind _ . 1 . okind; upper kind if N=='' | N=="," then N= 35 if kind=='' | kind=="," then kind= 'SAFE' if _\=='' then call ser 'too many arguments specified.' if kind\=='SAFE' & kind\=='UNSAFE' then call ser 'invalid 2nd argument: ' okind ...
Transform the following C implementation into REXX, maintaining the same output and logic.
#include <stdio.h> #include <unistd.h> int main() { int i; printf("\033[?1049h\033[H"); printf("Alternate screen buffer\n"); for (i = 5; i; i--) { printf("\rgoing back in %d...", i); fflush(stdout); sleep(1); } printf("\033[?1049l"); return 0; }
parse value scrsize() with sd sw . parse value cursor(1,1) with curRow curCol . do original=1 for sd @line.original=scrRead(original,1, sw) end 'CLS' do sd % 2 ...
Change the programming language of this snippet from C to REXX without modifying what it does.
#include <sys/wait.h> #include <stdio.h> #include <stdlib.h> #include <unistd.h> void talk(const char *s) { pid_t pid; int status; pid = fork(); if (pid < 0) { perror("fork"); exit(1); } if (pid == 0) { execlp("espeak", "espeak", s, (void*)0); perror("espeak"); _exit(1); } waitpid(pid, &status, 0)...
parse arg t if t='' then exit dquote= '"' rate= 1 'NIRCMD' "speak text" dquote t dquote rate
Write the same algorithm in REXX as shown in this C implementation.
static unsigned char const k8[16] = { 14, 4, 13, 1, 2, 15, 11, 8, 3, 10, 6, 12, 5, 9, 0, 7 }; static unsigned char const k7[16] = { 15, 1, 8, 14, 6, 11, 3, 4, 9, 7, 2, 13, 12, 0, 5, 10 }; static unsigned char const k6[16] = { 10, 0, 9, 14, 6, 3, 15, 5, 1, 13, 12, 7, 11, 4, 2, 8 }; static ...
numeric digits 12 @.0 = 4 10 9 2 13 8 0 14 6 11 1 12 7 15 5 3 @.1 = 14 11 4 12 6 13 15 10 2 3 8 1 0 7 5 9 @.2 = 5 8 1 13 10 3 4 ...
Translate this program into REXX but keep the logic exactly as in C.
#include <stdio.h> #define JOBS 12 #define jobs(a) for (switch_to(a = 0); a < JOBS || !printf("\n"); switch_to(++a)) typedef struct { int seq, cnt; } env_t; env_t env[JOBS] = {{0, 0}}; int *seq, *cnt; void hail() { printf("% 4d", *seq); if (*seq == 1) return; ++*cnt; *seq = (*seq & 1) ? 3 * *seq + 1 : *seq / 2; ...
parse arg n . if n=='' | n=="," then n= 12 @.= do i=1 for n; @.i= i end w= length(n) do forever until @.0; @.0= 1 ...
Change the programming language of this snippet from C to REXX without modifying what it does.
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <unistd.h> #include "wren.h" void C_xrandr(WrenVM* vm) { const char *arg = wrenGetSlotString(vm, 1); char command[strlen(arg) + 8]; strcpy(command, "xrandr "); strcat(command, arg); system(command); } void C_usleep(WrenVM* vm...
parse arg cols lines . 'MODE' "CON: COLS="cols 'LINES='lines
Convert the following code from C to REXX, ensuring the logic remains intact.
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <unistd.h> #include "wren.h" void C_xrandr(WrenVM* vm) { const char *arg = wrenGetSlotString(vm, 1); char command[strlen(arg) + 8]; strcpy(command, "xrandr "); strcat(command, arg); system(command); } void C_usleep(WrenVM* vm...
parse arg cols lines . 'MODE' "CON: COLS="cols 'LINES='lines
Produce a functionally identical REXX code for the snippet given in C.
#include <windows.h> #include <wchar.h> int main() { CONSOLE_SCREEN_BUFFER_INFO info; COORD pos; HANDLE conout; long len; wchar_t c; conout = CreateFileW(L"CONOUT$", GENERIC_READ | GENERIC_WRITE, FILE_SHARE_READ | FILE_SHARE_WRITE, NULL, OPEN_EXISTING, 0, NULL); if (conout == INVALID_HANDLE_VALUE) ...
row = 6 col = 3 howMany = 1 stuff = scrRead(row, col, howMany) other = scrRead(40, 3, 1)
Port the following code from C to REXX with equivalent syntax and logic.
#include <stdbool.h> #include <stdint.h> #include <stdio.h> uint64_t modpow(uint64_t a, uint64_t b, uint64_t n) { uint64_t x = 1, y = a; while (b > 0) { if (b % 2 == 1) { x = (x * y) % n; } y = (y * y) % n; b /= 2; } return x % n; } struct Solution { u...
Numeric Digits 1000000 ttest ='[(10, 13), (56, 101), (1030, 10009), (44402, 100049)]' Do While pos('(',ttest)>0 Parse Var ttest '(' n ',' p ')' ttest r = tonelli(n, p) Say "n =" n "p =" p Say " roots :" r (p - r) End Exit legendre: Procedure Parse Arg a, p return pow(a, (p - 1) % 2, p) tonelli...
Convert the following code from C to REXX, ensuring the logic remains intact.
#include <stdbool.h> #include <stdint.h> #include <stdio.h> uint64_t modpow(uint64_t a, uint64_t b, uint64_t n) { uint64_t x = 1, y = a; while (b > 0) { if (b % 2 == 1) { x = (x * y) % n; } y = (y * y) % n; b /= 2; } return x % n; } struct Solution { u...
Numeric Digits 1000000 ttest ='[(10, 13), (56, 101), (1030, 10009), (44402, 100049)]' Do While pos('(',ttest)>0 Parse Var ttest '(' n ',' p ')' ttest r = tonelli(n, p) Say "n =" n "p =" p Say " roots :" r (p - r) End Exit legendre: Procedure Parse Arg a, p return pow(a, (p - 1) % 2, p) tonelli...
Please provide an equivalent version of this C code in REXX.
#include <math.h> #include <stdbool.h> #include <stdio.h> #include <stdlib.h> struct RealSet { bool(*contains)(struct RealSet*, struct RealSet*, double); struct RealSet *left; struct RealSet *right; double low, high; }; typedef enum { CLOSED, LEFT_OPEN, RIGHT_OPEN, BOTH_OPEN, } RangeTy...
call quertySet 1, 3, '[1,2)' call quertySet , , '[0,2) union (1,3)' call quertySet , , '[0,1) union (2,3]' call quertySet , , '[0,2] inter (1,3)' call quertySet , , '(1,2) ∩ (2,3]' call quertySet , , '[0,2) \ (1,3)' say; say center(' star...
Rewrite the snippet below in REXX so it works the same as the original C code.
#include <math.h> #include <stdbool.h> #include <stdio.h> #include <stdlib.h> struct RealSet { bool(*contains)(struct RealSet*, struct RealSet*, double); struct RealSet *left; struct RealSet *right; double low, high; }; typedef enum { CLOSED, LEFT_OPEN, RIGHT_OPEN, BOTH_OPEN, } RangeTy...
call quertySet 1, 3, '[1,2)' call quertySet , , '[0,2) union (1,3)' call quertySet , , '[0,1) union (2,3]' call quertySet , , '[0,2] inter (1,3)' call quertySet , , '(1,2) ∩ (2,3]' call quertySet , , '[0,2) \ (1,3)' say; say center(' star...
Write a version of this C function in REXX with identical behavior.
#include <stdio.h> #include <stdlib.h> #include <string.h> #define USE_FAKES 1 const char *states[] = { #if USE_FAKES "New Kory", "Wen Kory", "York New", "Kory New", "New Kory", #endif "Alabama", "Alaska", "Arizona", "Arkansas", "California", "Colorado", "Connecticut", "Delaware", "Florida", "Georgia", "Hawa...
!='Alabama, Alaska, Arizona, Arkansas, California, Colorado, Connecticut, Delaware, Florida, Georgia,', 'Hawaii, Idaho, Illinois, Indiana, Iowa, Kansas, Kentucky, Louisiana, Maine, Maryland, Massachusetts, ', 'Michigan, Minnesota, Mississippi, Missouri, Montana, Nebraska, Nevada, New Hampshire, ...
Ensure the translated REXX code behaves exactly like the original C snippet.
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <gmp.h> int main() { for (unsigned int d = 2; d <= 9; ++d) { printf("First 10 super-%u numbers:\n", d); char digits[16] = { 0 }; memset(digits, '0' + d, d); mpz_t bignum; mpz_init(bignum); for (unsig...
numeric digits 100 parse arg n LO HI . if n=='' | n=="," then n= 10 if LO=='' | LO=="," then LO= 2 if HI=='' | HI=="," then HI= 9 do d=LO to HI...
Convert the following code from C to REXX, ensuring the logic remains intact.
#include <stdio.h> #include <stdlib.h> #include <string.h> #include <gmp.h> int main() { for (unsigned int d = 2; d <= 9; ++d) { printf("First 10 super-%u numbers:\n", d); char digits[16] = { 0 }; memset(digits, '0' + d, d); mpz_t bignum; mpz_init(bignum); for (unsig...
numeric digits 100 parse arg n LO HI . if n=='' | n=="," then n= 10 if LO=='' | LO=="," then LO= 2 if HI=='' | HI=="," then HI= 9 do d=LO to HI...
Write the same algorithm in REXX as shown in this C implementation.
#include <stdio.h> #include <stdlib.h> #include <math.h> #include <string.h> int pRec(int n) { static int *memo = NULL; static size_t curSize = 0; if (curSize <= (size_t) n) { size_t lastSize = curSize; while (curSize <= (size_t) n) curSize += 1024 * sizeof(int); memo = r...
numeric digits 40 parse arg n nF Ln cL . if n=='' | n=="," then n= 20 if nF=='' | nF=="," then nF= 64 if Ln=='' | Ln=="," then Ln= 10 if cL=='' | cL=="," then cL= 32 PR= 1.3247179572447...
Convert the following code from C to REXX, ensuring the logic remains intact.
#include <stdio.h> #include <stdlib.h> #include <stdbool.h> typedef enum type { INT, STRING } Type; typedef struct maybe { int i; char *s; Type t; _Bool is_something; } Maybe; void print_Maybe(Maybe *m) { if (m->t == INT) printf("Just %d : INT\n", m->i); else if (m->t == STRING) printf("Just...
call add 1, 2 call add 1, 2.0 call add 1, 2.0, -6 call add self, 2 exit 0 add: void= 'VOID'; f= do j=1 for arg() call bind( arg(j) ); f= f arg(j) end say ...
Convert this C block to REXX, preserving its control flow and logic.
#include <stdbool.h> #include <stdio.h> #include <stdlib.h> #include <glib.h> char text_char(char c) { switch (c) { case 'a': case 'b': case 'c': return '2'; case 'd': case 'e': case 'f': return '3'; case 'g': case 'h': case 'i': return '4'; case 'j': case 'k': case 'l': ...
parse arg iFID . if iFID=='' | iFID=="," then iFID='UNIXDICT.TXT' @.= 0 !.=; $.= alphabet= 'ABCDEFGHIJKLMNOPQRSTUVWXYZ' digitKey= 22233344455566677778889999 digKey= 0; ...
Write the same algorithm in REXX as shown in this C implementation.
#include <stdbool.h> #include <stdio.h> #include <stdint.h> typedef struct cidr_tag { uint32_t address; unsigned int mask_length; } cidr_t; bool cidr_parse(const char* str, cidr_t* cidr) { int a, b, c, d, m; if (sscanf(str, "%d.%d.%d.%d/%d", &a, &b, &c, &d, &m) != 5) return false; if (m ...
parse arg a . if a=='' | a=="," then a= '87.70.141.1/22' , '36.18.154.103/12' , '62.62.197.11/29' , '67.137.119.181/4' , '161.214.74.21/24' , ...
Port the following code from C to REXX with equivalent syntax and logic.
#include <stdbool.h> #include <stdio.h> #include <stdint.h> typedef struct cidr_tag { uint32_t address; unsigned int mask_length; } cidr_t; bool cidr_parse(const char* str, cidr_t* cidr) { int a, b, c, d, m; if (sscanf(str, "%d.%d.%d.%d/%d", &a, &b, &c, &d, &m) != 5) return false; if (m ...
parse arg a . if a=='' | a=="," then a= '87.70.141.1/22' , '36.18.154.103/12' , '62.62.197.11/29' , '67.137.119.181/4' , '161.214.74.21/24' , ...
Rewrite the snippet below in REXX so it works the same as the original C code.
#include <gmp.h> void perm(mpz_t out, int n, int k) { mpz_set_ui(out, 1); k = n - k; while (n > k) mpz_mul_ui(out, out, n--); } void comb(mpz_t out, int n, int k) { perm(out, n, k); while (k) mpz_divexact_ui(out, out, k--); } int main(void) { mpz_t x; mpz_init(x); perm(x, 1000, 969); gmp_printf("P(1000,969...
numeric digits 100 do j=1 for 12; _= do k=1 for j _=_ 'P('j","k')='perm(j,k)" " end say strip(_) end say ...
Change the programming language of this snippet from C to REXX without modifying what it does.
#include "gmp.h" void agm (const mpf_t in1, const mpf_t in2, mpf_t out1, mpf_t out2) { mpf_add (out1, in1, in2); mpf_div_ui (out1, out1, 2); mpf_mul (out2, in1, in2); mpf_sqrt (out2, out2); } int main (void) { mpf_set_default_prec (300000); mpf_t x0, y0, resA, resB, Z, var; mpf_init_set_ui (x0, 1); mpf_init_...
parse arg d .; if d=='' | d=="," then d= 500 numeric digits d+5 z= 1/4; a= 1; g= sqrt(1/2) n= 1 do j=1 until a==old; old= a x= (a+g) * .5; g= sqrt(a*g) z= z - n*(x-a)**2; n= n+n; a= x end ...
Convert the following code from C to REXX, ensuring the logic remains intact.
#include "gmp.h" void agm (const mpf_t in1, const mpf_t in2, mpf_t out1, mpf_t out2) { mpf_add (out1, in1, in2); mpf_div_ui (out1, out1, 2); mpf_mul (out2, in1, in2); mpf_sqrt (out2, out2); } int main (void) { mpf_set_default_prec (300000); mpf_t x0, y0, resA, resB, Z, var; mpf_init_set_ui (x0, 1); mpf_init_...
parse arg d .; if d=='' | d=="," then d= 500 numeric digits d+5 z= 1/4; a= 1; g= sqrt(1/2) n= 1 do j=1 until a==old; old= a x= (a+g) * .5; g= sqrt(a*g) z= z - n*(x-a)**2; n= n+n; a= x end ...
Write the same algorithm in REXX as shown in this C implementation.
#include <stdio.h> #include <stdlib.h> #define TRUE 1 #define FALSE 0 typedef int bool; void sieve(int limit, int primes[], int *count) { bool *c = calloc(limit + 1, sizeof(bool)); int i, p = 3, p2, n = 0; p2 = p * p; while (p2 <= limit) { for (i = p2; i <= limit; i += 2 * p) ...
parse arg a if a='' | a="," then a= '500 -500 -1000 -2000 -4000 -8000 -16000' , '-32000 -64000 -128000 -512000 -1024000' do k=1 for words(a); H=word(a, k) neg= H<1 H= abs(H) ...
Preserve the algorithm and functionality while converting the code from C to REXX.
#include <inttypes.h> #include <math.h> #include <stdlib.h> #include <stdio.h> #include <stdint.h> #include <string.h> #include <gmp.h> int es_check(uint32_t *sieve, uint64_t n) { if ((n != 2 && !(n & 1)) || (n < 2)) return 0; else return !(sieve[n >> 6] & (1 << (n >> 1 & 31))); } uint32_t *e...
parse arg N H . if N=='' | N==',' then N= 10 if H=='' | H==',' then H= 100000 numeric digits 600000 w= length( commas( digits() ) ) @.=.; @.0= 1; @.1= 2; @.2= 3; @.3= 5; @.4= 7; @.5= 11; @.6= 13...
Please provide an equivalent version of this C code in REXX.
#include <stdbool.h> #include <stdint.h> #include <stdio.h> typedef int64_t integer; struct Pair { integer md; int tc; }; integer mod(integer x, integer y) { return ((x % y) + y) % y; } integer gcd(integer a, integer b) { if (0 == a) return b; if (0 == b) return a; if (a == b) return a; ...
parse arg fract '' -1 t; z=$egyptF(fract) if t\==. then say fract ' ───► ' z return z $egyptF: parse arg z 1 zn '/' zd,,$; if zd=='' then zd=1 if z='' then call erx "no fraction was specified." if zd==0 then call erx "denominator can'...
Transform the following C implementation into REXX, maintaining the same output and logic.
#include <stdbool.h> #include <stdint.h> #include <stdio.h> typedef int64_t integer; struct Pair { integer md; int tc; }; integer mod(integer x, integer y) { return ((x % y) + y) % y; } integer gcd(integer a, integer b) { if (0 == a) return b; if (0 == b) return a; if (a == b) return a; ...
parse arg fract '' -1 t; z=$egyptF(fract) if t\==. then say fract ' ───► ' z return z $egyptF: parse arg z 1 zn '/' zd,,$; if zd=='' then zd=1 if z='' then call erx "no fraction was specified." if zd==0 then call erx "denominator can'...
Ensure the translated REXX code behaves exactly like the original C snippet.
#include <stdio.h> #include <math.h> #define N 5 double Pi; double lroots[N]; double weight[N]; double lcoef[N + 1][N + 1] = {{0}}; void lege_coef() { int n, i; lcoef[0][0] = lcoef[1][1] = 1; for (n = 2; n <= N; n++) { lcoef[n][0] = -(n - 1) * lcoef[n - 2][0] / n; for (i = 1; i <= n; i++) lcoef[n][i] = ((2 ...
* 31.10.2013 Walter Pachl Translation from REXX (from PL/I) * using ooRexx' rxmath package * which limits the precision to 16 digits *--------------------------------------------------------------------*/ prec=60 Numeric Digits prec epsilon=1/10**prec pi=3.14159265358...
Keep all operations the same but rewrite the snippet in REXX.
#include <stdio.h> #include <stdlib.h> int main() { int i; srand(time(NULL)); for (i = 0; i < 10; i++) puts((rand() % 2) ? "heads" : "tails"); return 0; }
y = random(100, 200)
Change the following C code into REXX without altering its purpose.
#include <stdio.h> #include <stdlib.h> int main() { int i; srand(time(NULL)); for (i = 0; i < 10; i++) puts((rand() % 2) ? "heads" : "tails"); return 0; }
y = random(100, 200)
Can you help me rewrite this code in REXX instead of C, keeping it the same logically?
#include <stdio.h> #include <stdlib.h> #include <string.h> typedef unsigned char byte; byte *grid = 0; int w, h, len; unsigned long long cnt; static int next[4], dir[4][2] = {{0, -1}, {-1, 0}, {0, 1}, {1, 0}}; void walk(int y, int x) { int i, t; if (!y || y == h || !x || x == w) { cnt += 2; return; } t = y...
numeric digits 20 parse arg N .; if N=='' | N=="," then N= 10 dir.= 0; dir.0.1= -1; dir.1.0= -1; dir.2.1= 1; dir.3.0= 1 do y=2 to N; say do x=1 for y; if x//2 & y//2 then iterate z= solve(y,x,1); _= comm...
Produce a functionally identical REXX code for the snippet given in C.
#include <stdio.h> #include <stdlib.h> #include <string.h> typedef unsigned char byte; byte *grid = 0; int w, h, len; unsigned long long cnt; static int next[4], dir[4][2] = {{0, -1}, {-1, 0}, {0, 1}, {1, 0}}; void walk(int y, int x) { int i, t; if (!y || y == h || !x || x == w) { cnt += 2; return; } t = y...
numeric digits 20 parse arg N .; if N=='' | N=="," then N= 10 dir.= 0; dir.0.1= -1; dir.1.0= -1; dir.2.1= 1; dir.3.0= 1 do y=2 to N; say do x=1 for y; if x//2 & y//2 then iterate z= solve(y,x,1); _= comm...
Maintain the same structure and functionality when rewriting this code in REXX.
#include <limits.h> #include <math.h> #include <stdbool.h> #include <stdio.h> #include <stdlib.h> typedef long long llong_t; struct PrimeArray { llong_t *ptr; size_t size; size_t capacity; }; struct PrimeArray allocate() { struct PrimeArray primes; primes.size = 0; primes.capacity = 10; p...
numeric digits 20 parse arg N . if N=='' | N=="," then N= 200 Nth= N<0; N= abs(N) @.=0; @.0=1; @.2=1; @.3=1; @.4=1; @.5=1; @.6=1; @.8=1 sw= linesize() - 1; if sw<1 then sw= 79 w=12; ...
Maintain the same structure and functionality when rewriting this code in REXX.
#include<graphics.h> #include<stdlib.h> #include<stdio.h> #include<math.h> #include<time.h> #define pi M_PI int main(){ time_t t; double side, vertices[3][3],seedX,seedY,windowSide; int i,iter,choice; printf("Enter triangle side length : "); scanf("%lf",&side); printf("Enter number of iterations : "); sc...
parse value scrsize() with sd sw . sw= sw - 2 sd= sd - 4 parse arg pts chr seed . if pts=='' | pts=="," then pts= 1000000 if chr=='' | chr=="," then chr= '∙' if datatype(seed,'W...
Write a version of this C function in REXX with identical behavior.
#include<graphics.h> #include<stdlib.h> #include<stdio.h> #include<math.h> #include<time.h> #define pi M_PI int main(){ time_t t; double side, vertices[3][3],seedX,seedY,windowSide; int i,iter,choice; printf("Enter triangle side length : "); scanf("%lf",&side); printf("Enter number of iterations : "); sc...
parse value scrsize() with sd sw . sw= sw - 2 sd= sd - 4 parse arg pts chr seed . if pts=='' | pts=="," then pts= 1000000 if chr=='' | chr=="," then chr= '∙' if datatype(seed,'W...
Ensure the translated REXX code behaves exactly like the original C snippet.
#include <stdbool.h> #include <stdio.h> #include <stdlib.h> #include <string.h> int compare(const void *a, const void *b) { int int_a = *((int *)a); int int_b = *((int *)b); return (int_a > int_b) - (int_a < int_b); } char results[7]; bool next_result() { char *ptr = results + 5; int num = 0; ...
results = '000000' games = '12 13 14 23 24 34' points.=0 records.=0 Do Until nextResult(results)=0 records.=0 Do i=1 To 6 r=substr(results,i,1) g=word(games,i); Parse Var g g1 +1 g2 Select When r='2' Then records.g1=records.g1+3 When r='1' Th...
Translate the given C code snippet into REXX without altering its behavior.
#include <sys/types.h> #include <regex.h> #include <stdio.h> typedef struct { const char *s; int len, prec, assoc; } str_tok_t; typedef struct { const char * str; int assoc, prec; regex_t re; } pat_t; enum assoc { A_NONE, A_L, A_R }; pat_t pat_eos = {"", A_NONE, 0}; pat_t pat_ops[] = { {"^\\)", A_NONE, -1}, ...
parse arg x if x='' then x= '3 + 4 * 2 / ( 1 - 5 ) ^ 2 ^ 3' ox=x x='(' space(x) ") " #=words(x) do i=1 for #; @.i=word(x, i) end tell=1 ...
Convert this C snippet to REXX and keep its semantics consistent.
#include<stdlib.h> #include<stdio.h> #include<math.h> int p[512]; double fade(double t) { return t * t * t * (t * (t * 6 - 15) + 10); } double lerp(double t, double a, double b) { return a + t * (b - a); } double grad(int hash, double x, double y, double z) { int h = hash & 15; doubl...
_= 97a0895b5a0f830dc95f6035c2e907e18c24671e458e086325f0150a17be0694f778ea4b001ac53e5efcdbcb75230b2039b12158ed953857ae147d88aba844af, ||4aa547868b301ba64d929ee7536fe57a3cd385e6dc695c29372ef528f4668f3641193fa101d85049d14c84bbd05912a9c8c4878274bc9f56a4646dc6adba0340, ||34d9e2fa7c7b05ca2693767eff5255d4cfce3be32f103a11b6...
Rewrite the snippet below in REXX so it works the same as the original C code.
#include <stdio.h> #include <math.h> #include <stdlib.h> int header[] = {46, 115, 110, 100, 0, 0, 0, 24, 255, 255, 255, 255, 0, 0, 0, 3, 0, 0, 172, 68, 0, 0, 0, 1}; int main(int argc, char *argv[]){ float freq, dur; long i, v; if (argc < 3) { p...
parse arg freq time . if freq=='' | freq=="," then freq= 880 if time=='' | time=="," then time= 5 call sound freq, time exit 0
Maintain the same structure and functionality when rewriting this code in REXX.
#include <stdio.h> #include <stdlib.h> #define SWAP(a,b) do{t=(a);(a)=(b);(b)=t;}while(0) void _mr_unrank1(int rank, int n, int *vec) { int t, q, r; if (n < 1) return; q = rank / n; r = rank % n; SWAP(vec[r], vec[n-1]); _mr_unrank1(q, n-1, vec); } int _mr_rank1(int n, int *vec, int *inv) { ...
parse arg N y seed . if N=='' | N=="," then N= 4 if y=='' | y=="," then y= 17 if datatype(seed,'W') then call random ,,seed permutes= permSets(N) w= length(permutes) @.= do p=0 f...
Transform the following C implementation into REXX, maintaining the same output and logic.
#include <stdio.h> #include <stdlib.h> #define SWAP(a,b) do{t=(a);(a)=(b);(b)=t;}while(0) void _mr_unrank1(int rank, int n, int *vec) { int t, q, r; if (n < 1) return; q = rank / n; r = rank % n; SWAP(vec[r], vec[n-1]); _mr_unrank1(q, n-1, vec); } int _mr_rank1(int n, int *vec, int *inv) { ...
parse arg N y seed . if N=='' | N=="," then N= 4 if y=='' | y=="," then y= 17 if datatype(seed,'W') then call random ,,seed permutes= permSets(N) w= length(permutes) @.= do p=0 f...
Change the following C code into REXX without altering its purpose.
#include <math.h> #include <stdio.h> int p(int l, int n) { int test = 0; double logv = log(2.0) / log(10.0); int factor = 1; int loop = l; while (loop > 10) { factor *= 10; loop /= 10; } while (n > 0) { int val; test++; val = (int)(factor * pow(10.0,...
parse arg L n b . if L=='' | L=="," then L= 12 if n=='' | n=="," then n= 1 if b=='' | b=="," then b= 2 LL= length(L) fd= left(L, 1) fr= substr(L, 2) ...
Produce a functionally identical REXX code for the snippet given in C.
#include <math.h> #include <stdio.h> int p(int l, int n) { int test = 0; double logv = log(2.0) / log(10.0); int factor = 1; int loop = l; while (loop > 10) { factor *= 10; loop /= 10; } while (n > 0) { int val; test++; val = (int)(factor * pow(10.0,...
parse arg L n b . if L=='' | L=="," then L= 12 if n=='' | n=="," then n= 1 if b=='' | b=="," then b= 2 LL= length(L) fd= left(L, 1) fr= substr(L, 2) ...
Rewrite this program in REXX while keeping its functionality equivalent to the C version.
#include <stdbool.h> #include <stdint.h> #include <stdio.h> #include <stdlib.h> #include <string.h> const int PRIMES[] = { 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 127, 131, 137, 139, 149, 151, 157,...
parse arg n . if n=='' | n=="," then n= 50 numeric digits n big= copies(9, digits() ) @.= '2nd'; @.1= '1st' do t=1 to -1 by -2; usum= 0; vsum= 0; s= 0 #...
Can you help me rewrite this code in REXX instead of C, keeping it the same logically?
#include <stdbool.h> #include <stdint.h> #include <stdio.h> #include <stdlib.h> #include <gmp.h> void* xmalloc(size_t n) { void* ptr = malloc(n); if (ptr == NULL) { fprintf(stderr, "Out of memory\n"); exit(1); } return ptr; } void* xrealloc(void* p, size_t n) { void* ptr = realloc(...
numeric digits 200 parse arg LOx HIx LOn HIn . if LOx=='' | LOx=="," then LOx= 1 if HIx=='' | HIx=="," then HIx= LOx + 24 if LOn=='' | LOn=="," then LOn= 2 if HIn=='' | HIn=="," then HIn= LOn + 27 call genP HIn ...
Translate the given C code snippet into REXX without altering its behavior.
#include <assert.h> #include <stdbool.h> #include <stdint.h> #include <stdio.h> #include <stdlib.h> typedef struct bit_array_tag { uint32_t size; uint32_t* array; } bit_array; bool bit_array_create(bit_array* b, uint32_t size) { uint32_t* array = calloc((size + 31)/32, sizeof(uint32_t)); if (array == ...
parse arg what do until what=='' parse var what x n what; parse var x x '-' y parse var n n '-' m if x=='' | x=="," then x= 19 if y=='' | y=="," then y= x if n=='' | n==",...
Preserve the algorithm and functionality while converting the code from C to REXX.
#include <stdbool.h> #include <stdio.h> #include <stdlib.h> typedef struct stirling_cache_tag { int max; int* values; } stirling_cache; int stirling_number1(stirling_cache* sc, int n, int k) { if (k == 0) return n == 0 ? 1 : 0; if (n > sc->max || k > n) return 0; return sc->values[...
parse arg lim . if lim=='' | lim=="," then lim= 12 olim= lim lim= abs(lim) numeric digits max(9, 2*lim) @.=; @.0.0= 1 do n=0 for...
Maintain the same structure and functionality when rewriting this code in REXX.
#include <stdbool.h> #include <stdio.h> #include <stdlib.h> typedef struct stirling_cache_tag { int max; int* values; } stirling_cache; int stirling_number1(stirling_cache* sc, int n, int k) { if (k == 0) return n == 0 ? 1 : 0; if (n > sc->max || k > n) return 0; return sc->values[...
parse arg lim . if lim=='' | lim=="," then lim= 12 olim= lim lim= abs(lim) numeric digits max(9, 2*lim) @.=; @.0.0= 1 do n=0 for...
Write the same algorithm in REXX as shown in this C implementation.
#include <assert.h> #include <math.h> #include <stdio.h> typedef struct point_tag { double x; double y; } point_t; double perpendicular_distance(point_t p, point_t p1, point_t p2) { double dx = p2.x - p1.x; double dy = p2.y - p1.y; double d = sqrt(dx * dx + dy * dy); return fabs(p.x * dy - p....
parse arg epsilon pts if epsilon='' | epsilon="," then epsilon= 1 if pts='' then pts= '(0,0) (1,0.1) (2,-0.1) (3,5) (4,6) (5,7) (6,8.1) (7,9) (8,9) (9,9)' pts= space(pts) say ' error threshold: ' epsilon say ' points spe...
Translate the given C code snippet into REXX without altering its behavior.
#include <assert.h> #include <math.h> #include <stdio.h> typedef struct point_tag { double x; double y; } point_t; double perpendicular_distance(point_t p, point_t p1, point_t p2) { double dx = p2.x - p1.x; double dy = p2.y - p1.y; double d = sqrt(dx * dx + dy * dy); return fabs(p.x * dy - p....
parse arg epsilon pts if epsilon='' | epsilon="," then epsilon= 1 if pts='' then pts= '(0,0) (1,0.1) (2,-0.1) (3,5) (4,6) (5,7) (6,8.1) (7,9) (8,9) (9,9)' pts= space(pts) say ' error threshold: ' epsilon say ' points spe...
Port the following code from C to REXX with equivalent syntax and logic.
#include<stdio.h> #include<math.h> #define pi M_PI typedef struct{ double x,y; }vector; vector initVector(double r,double theta){ vector c; c.x = r*cos(theta); c.y = r*sin(theta); return c; } vector addVector(vector a,vector b){ vector c; c.x = a.x + b.x; c.y = a.y + b.y; return c; } vector subtra...
v=.vector~new(12,-3); Say "v=.vector~new(12,-3) =>" v~print v~ab(1,1,6,4); Say "v~ab(1,1,6,4) =>" v~print v~al(45,2); Say "v~al(45,2) =>" v~print w=v~'+'(v); Say "w=v~'+'(v) =>" w~print x=v~'-'(w); Say "x=v~'-'(w) =>" x~print y=x~'*'(3); ...
Convert this C snippet to REXX and keep its semantics consistent.
#include <stdio.h> #include <math.h> #define C 7 typedef struct { double x, y; } pt; pt zero(void) { return (pt){ INFINITY, INFINITY }; } int is_zero(pt p) { return p.x > 1e20 || p.x < -1e20; } pt neg(pt p) { return (pt){ p.x, -p.y }; } pt dbl(pt p) { if (is_zero(p)) return p; pt r; double L = (3 * p.x * p.x)...
numeric digits 100 a= func(1) ; say ' a = ' show(a) b= func(2) ; say ' b = ' show(b) c= add(a, b) ; say ' c = (a+b) =' show(c) d= neg(c) ...
Write a version of this C function in REXX with identical behavior.
#include <stdio.h> #include <math.h> #define C 7 typedef struct { double x, y; } pt; pt zero(void) { return (pt){ INFINITY, INFINITY }; } int is_zero(pt p) { return p.x > 1e20 || p.x < -1e20; } pt neg(pt p) { return (pt){ p.x, -p.y }; } pt dbl(pt p) { if (is_zero(p)) return p; pt r; double L = (3 * p.x * p.x)...
numeric digits 100 a= func(1) ; say ' a = ' show(a) b= func(2) ; say ' b = ' show(b) c= add(a, b) ; say ' c = (a+b) =' show(c) d= neg(c) ...