Instruction stringlengths 45 106 | input_code stringlengths 1 13.7k | output_code stringlengths 1 13.7k |
|---|---|---|
Produce a language-to-language conversion: from Arturo to VB, same semantics. | pi: 3.14
print [pi "->" type pi]
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Write the same code in C# as shown below in AWK. | 2
2.
.3
45e6
45e+6
78e-9
1.2E34
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Convert the following code from AWK to C++, ensuring the logic remains intact. | 2
2.
.3
45e6
45e+6
78e-9
1.2E34
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Change the programming language of this snippet from AWK to Java without modifying what it does. | 2
2.
.3
45e6
45e+6
78e-9
1.2E34
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Write the same code in Python as shown below in AWK. | 2
2.
.3
45e6
45e+6
78e-9
1.2E34
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Keep all operations the same but rewrite the snippet in VB. | 2
2.
.3
45e6
45e+6
78e-9
1.2E34
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Transform the following BBC_Basic implementation into C#, maintaining the same output and logic. |
PRINT -123.456E-1
PRINT 1000.0
PRINT 1E-5
PRINT 67.
PRINT 8.9E
PRINT .33E-
PRINT -.
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Write the same algorithm in C++ as shown in this BBC_Basic implementation. |
PRINT -123.456E-1
PRINT 1000.0
PRINT 1E-5
PRINT 67.
PRINT 8.9E
PRINT .33E-
PRINT -.
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Port the provided BBC_Basic code into Java while preserving the original functionality. |
PRINT -123.456E-1
PRINT 1000.0
PRINT 1E-5
PRINT 67.
PRINT 8.9E
PRINT .33E-
PRINT -.
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Convert this BBC_Basic block to Python, preserving its control flow and logic. |
PRINT -123.456E-1
PRINT 1000.0
PRINT 1E-5
PRINT 67.
PRINT 8.9E
PRINT .33E-
PRINT -.
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Convert this BBC_Basic snippet to VB and keep its semantics consistent. |
PRINT -123.456E-1
PRINT 1000.0
PRINT 1E-5
PRINT 67.
PRINT 8.9E
PRINT .33E-
PRINT -.
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Generate an equivalent C# version of this Elixir code. | iex(180)> 0.123
0.123
iex(181)> -123.4
-123.4
iex(182)> 1.23e4
1.23e4
iex(183)> 1.2e-3
0.0012
iex(184)> 1.23E4
1.23e4
iex(185)> 10_000.0
1.0e4
iex(186)> .5
** (SyntaxError) iex:186: syntax error before: '.'
iex(186)> 2. + 3
** (CompileError) iex:186: invalid call 2.+(3)
iex(187)> 1e4
** (SyntaxError) iex:187: syntax error before: e4
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Translate the given Elixir code snippet into C++ without altering its behavior. | iex(180)> 0.123
0.123
iex(181)> -123.4
-123.4
iex(182)> 1.23e4
1.23e4
iex(183)> 1.2e-3
0.0012
iex(184)> 1.23E4
1.23e4
iex(185)> 10_000.0
1.0e4
iex(186)> .5
** (SyntaxError) iex:186: syntax error before: '.'
iex(186)> 2. + 3
** (CompileError) iex:186: invalid call 2.+(3)
iex(187)> 1e4
** (SyntaxError) iex:187: syntax error before: e4
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Change the programming language of this snippet from Elixir to Java without modifying what it does. | iex(180)> 0.123
0.123
iex(181)> -123.4
-123.4
iex(182)> 1.23e4
1.23e4
iex(183)> 1.2e-3
0.0012
iex(184)> 1.23E4
1.23e4
iex(185)> 10_000.0
1.0e4
iex(186)> .5
** (SyntaxError) iex:186: syntax error before: '.'
iex(186)> 2. + 3
** (CompileError) iex:186: invalid call 2.+(3)
iex(187)> 1e4
** (SyntaxError) iex:187: syntax error before: e4
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Change the following Elixir code into Python without altering its purpose. | iex(180)> 0.123
0.123
iex(181)> -123.4
-123.4
iex(182)> 1.23e4
1.23e4
iex(183)> 1.2e-3
0.0012
iex(184)> 1.23E4
1.23e4
iex(185)> 10_000.0
1.0e4
iex(186)> .5
** (SyntaxError) iex:186: syntax error before: '.'
iex(186)> 2. + 3
** (CompileError) iex:186: invalid call 2.+(3)
iex(187)> 1e4
** (SyntaxError) iex:187: syntax error before: e4
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Change the following Elixir code into VB without altering its purpose. | iex(180)> 0.123
0.123
iex(181)> -123.4
-123.4
iex(182)> 1.23e4
1.23e4
iex(183)> 1.2e-3
0.0012
iex(184)> 1.23E4
1.23e4
iex(185)> 10_000.0
1.0e4
iex(186)> .5
** (SyntaxError) iex:186: syntax error before: '.'
iex(186)> 2. + 3
** (CompileError) iex:186: invalid call 2.+(3)
iex(187)> 1e4
** (SyntaxError) iex:187: syntax error before: e4
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Convert the following code from Factor to C#, ensuring the logic remains intact. | 3.14
+3.14
-3.14
10e5
10E+5
+10e-5
1.
.5
1/2.
1/3.
1/0.
-1/0.
0/0.
0x1.0p3
-0x1.0P-3
0b1.010001p3
0o1.21p3
1,234.123,456
+0x1.1234567891234p+0002
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Change the programming language of this snippet from Factor to C++ without modifying what it does. | 3.14
+3.14
-3.14
10e5
10E+5
+10e-5
1.
.5
1/2.
1/3.
1/0.
-1/0.
0/0.
0x1.0p3
-0x1.0P-3
0b1.010001p3
0o1.21p3
1,234.123,456
+0x1.1234567891234p+0002
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Preserve the algorithm and functionality while converting the code from Factor to Java. | 3.14
+3.14
-3.14
10e5
10E+5
+10e-5
1.
.5
1/2.
1/3.
1/0.
-1/0.
0/0.
0x1.0p3
-0x1.0P-3
0b1.010001p3
0o1.21p3
1,234.123,456
+0x1.1234567891234p+0002
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Translate this program into Python but keep the logic exactly as in Factor. | 3.14
+3.14
-3.14
10e5
10E+5
+10e-5
1.
.5
1/2.
1/3.
1/0.
-1/0.
0/0.
0x1.0p3
-0x1.0P-3
0b1.010001p3
0o1.21p3
1,234.123,456
+0x1.1234567891234p+0002
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Generate an equivalent VB version of this Factor code. | 3.14
+3.14
-3.14
10e5
10E+5
+10e-5
1.
.5
1/2.
1/3.
1/0.
-1/0.
0/0.
0x1.0p3
-0x1.0P-3
0b1.010001p3
0o1.21p3
1,234.123,456
+0x1.1234567891234p+0002
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Keep all operations the same but rewrite the snippet in C#. | println 1.00f
println 1.00d
println 1.00
println 1.00g
println 1.00e0
assert 1.00f instanceof Float
assert 1.00d instanceof Double
assert 1.00 instanceof BigDecimal
assert 1.00g instanceof BigDecimal
assert 1.00e0 instanceof BigDecimal
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Maintain the same structure and functionality when rewriting this code in C++. | println 1.00f
println 1.00d
println 1.00
println 1.00g
println 1.00e0
assert 1.00f instanceof Float
assert 1.00d instanceof Double
assert 1.00 instanceof BigDecimal
assert 1.00g instanceof BigDecimal
assert 1.00e0 instanceof BigDecimal
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Can you help me rewrite this code in Java instead of Groovy, keeping it the same logically? | println 1.00f
println 1.00d
println 1.00
println 1.00g
println 1.00e0
assert 1.00f instanceof Float
assert 1.00d instanceof Double
assert 1.00 instanceof BigDecimal
assert 1.00g instanceof BigDecimal
assert 1.00e0 instanceof BigDecimal
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Please provide an equivalent version of this Groovy code in Python. | println 1.00f
println 1.00d
println 1.00
println 1.00g
println 1.00e0
assert 1.00f instanceof Float
assert 1.00d instanceof Double
assert 1.00 instanceof BigDecimal
assert 1.00g instanceof BigDecimal
assert 1.00e0 instanceof BigDecimal
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Convert this Groovy snippet to VB and keep its semantics consistent. | println 1.00f
println 1.00d
println 1.00
println 1.00g
println 1.00e0
assert 1.00f instanceof Float
assert 1.00d instanceof Double
assert 1.00 instanceof BigDecimal
assert 1.00g instanceof BigDecimal
assert 1.00e0 instanceof BigDecimal
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Translate the given Haskell code snippet into C# without altering its behavior. | main = print [0.1,23.3,35e-1,56E+2,14.67e1]
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Generate an equivalent C++ version of this Haskell code. | main = print [0.1,23.3,35e-1,56E+2,14.67e1]
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Ensure the translated Java code behaves exactly like the original Haskell snippet. | main = print [0.1,23.3,35e-1,56E+2,14.67e1]
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Produce a functionally identical Python code for the snippet given in Haskell. | main = print [0.1,23.3,35e-1,56E+2,14.67e1]
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Change the programming language of this snippet from Haskell to VB without modifying what it does. | main = print [0.1,23.3,35e-1,56E+2,14.67e1]
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Change the programming language of this snippet from Icon to C# without modifying what it does. | procedure main()
every write( ![ 1., .1, 0.1, 2e10, 2E10, 3e-1, .4e2, 1.41e2, 8.e+3, 3.141e43 ])
end
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Produce a functionally identical C++ code for the snippet given in Icon. | procedure main()
every write( ![ 1., .1, 0.1, 2e10, 2E10, 3e-1, .4e2, 1.41e2, 8.e+3, 3.141e43 ])
end
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Port the provided Icon code into Java while preserving the original functionality. | procedure main()
every write( ![ 1., .1, 0.1, 2e10, 2E10, 3e-1, .4e2, 1.41e2, 8.e+3, 3.141e43 ])
end
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Transform the following Icon implementation into Python, maintaining the same output and logic. | procedure main()
every write( ![ 1., .1, 0.1, 2e10, 2E10, 3e-1, .4e2, 1.41e2, 8.e+3, 3.141e43 ])
end
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Generate a VB translation of this Icon snippet without changing its computational steps. | procedure main()
every write( ![ 1., .1, 0.1, 2e10, 2E10, 3e-1, .4e2, 1.41e2, 8.e+3, 3.141e43 ])
end
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Change the following J code into C# without altering its purpose. | 0 1 _2 3.4 3e4 3p4 3x4
0 1 _2 3.4 30000 292.227 163.794
16bcafe.babe _16b_cafe.babe _10b11
51966.7 46818.7 _9
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Write a version of this J function in C++ with identical behavior. | 0 1 _2 3.4 3e4 3p4 3x4
0 1 _2 3.4 30000 292.227 163.794
16bcafe.babe _16b_cafe.babe _10b11
51966.7 46818.7 _9
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Produce a language-to-language conversion: from J to Java, same semantics. | 0 1 _2 3.4 3e4 3p4 3x4
0 1 _2 3.4 30000 292.227 163.794
16bcafe.babe _16b_cafe.babe _10b11
51966.7 46818.7 _9
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Transform the following J implementation into Python, maintaining the same output and logic. | 0 1 _2 3.4 3e4 3p4 3x4
0 1 _2 3.4 30000 292.227 163.794
16bcafe.babe _16b_cafe.babe _10b11
51966.7 46818.7 _9
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Convert this J block to VB, preserving its control flow and logic. | 0 1 _2 3.4 3e4 3p4 3x4
0 1 _2 3.4 30000 292.227 163.794
16bcafe.babe _16b_cafe.babe _10b11
51966.7 46818.7 _9
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Convert the following code from Julia to C#, ensuring the logic remains intact. | 0.1
.1
1.
1e-1
1e+10
1e-10
0x01p-1
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Write a version of this Julia function in C++ with identical behavior. | 0.1
.1
1.
1e-1
1e+10
1e-10
0x01p-1
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Translate the given Julia code snippet into Java without altering its behavior. | 0.1
.1
1.
1e-1
1e+10
1e-10
0x01p-1
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Convert this Julia block to Python, preserving its control flow and logic. | 0.1
.1
1.
1e-1
1e+10
1e-10
0x01p-1
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Produce a functionally identical VB code for the snippet given in Julia. | 0.1
.1
1.
1e-1
1e+10
1e-10
0x01p-1
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Ensure the translated C# code behaves exactly like the original Lua snippet. | 3.14159
314.159E-2
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Preserve the algorithm and functionality while converting the code from Lua to C++. | 3.14159
314.159E-2
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Port the following code from Lua to Java with equivalent syntax and logic. | 3.14159
314.159E-2
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Rewrite the snippet below in Python so it works the same as the original Lua code. | 3.14159
314.159E-2
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Write the same code in VB as shown below in Lua. | 3.14159
314.159E-2
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Write the same code in C# as shown below in Mathematica. | These numbers are given in the default output format. Large numbers are given in scientific notation.
{6.7^-4,6.7^6,6.7^8}
{0.00049625,90458.4,4.06068*10^6}
This gives all numbers in scientific notation.
ScientificForm[%]
{4.9625*10^(-4),9.04584*10^(4),4.06068*10^(6)}
This gives the numbers in engineering notation, with exponents arranged to be multiples of three.
EngineeringForm[%]
{496.25*10^(-6),90.4584*10^(3),4.06068*10^(6)}
In accounting form, negative numbers are given in parentheses, and scientific notation is never used.
AccountingForm[{5.6,-6.7,10.^7}]
{5.6,(6.7),10000000.}
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Write the same algorithm in C++ as shown in this Mathematica implementation. | These numbers are given in the default output format. Large numbers are given in scientific notation.
{6.7^-4,6.7^6,6.7^8}
{0.00049625,90458.4,4.06068*10^6}
This gives all numbers in scientific notation.
ScientificForm[%]
{4.9625*10^(-4),9.04584*10^(4),4.06068*10^(6)}
This gives the numbers in engineering notation, with exponents arranged to be multiples of three.
EngineeringForm[%]
{496.25*10^(-6),90.4584*10^(3),4.06068*10^(6)}
In accounting form, negative numbers are given in parentheses, and scientific notation is never used.
AccountingForm[{5.6,-6.7,10.^7}]
{5.6,(6.7),10000000.}
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Convert this Mathematica snippet to Java and keep its semantics consistent. | These numbers are given in the default output format. Large numbers are given in scientific notation.
{6.7^-4,6.7^6,6.7^8}
{0.00049625,90458.4,4.06068*10^6}
This gives all numbers in scientific notation.
ScientificForm[%]
{4.9625*10^(-4),9.04584*10^(4),4.06068*10^(6)}
This gives the numbers in engineering notation, with exponents arranged to be multiples of three.
EngineeringForm[%]
{496.25*10^(-6),90.4584*10^(3),4.06068*10^(6)}
In accounting form, negative numbers are given in parentheses, and scientific notation is never used.
AccountingForm[{5.6,-6.7,10.^7}]
{5.6,(6.7),10000000.}
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Port the provided Mathematica code into Python while preserving the original functionality. | These numbers are given in the default output format. Large numbers are given in scientific notation.
{6.7^-4,6.7^6,6.7^8}
{0.00049625,90458.4,4.06068*10^6}
This gives all numbers in scientific notation.
ScientificForm[%]
{4.9625*10^(-4),9.04584*10^(4),4.06068*10^(6)}
This gives the numbers in engineering notation, with exponents arranged to be multiples of three.
EngineeringForm[%]
{496.25*10^(-6),90.4584*10^(3),4.06068*10^(6)}
In accounting form, negative numbers are given in parentheses, and scientific notation is never used.
AccountingForm[{5.6,-6.7,10.^7}]
{5.6,(6.7),10000000.}
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Convert the following code from Mathematica to VB, ensuring the logic remains intact. | These numbers are given in the default output format. Large numbers are given in scientific notation.
{6.7^-4,6.7^6,6.7^8}
{0.00049625,90458.4,4.06068*10^6}
This gives all numbers in scientific notation.
ScientificForm[%]
{4.9625*10^(-4),9.04584*10^(4),4.06068*10^(6)}
This gives the numbers in engineering notation, with exponents arranged to be multiples of three.
EngineeringForm[%]
{496.25*10^(-6),90.4584*10^(3),4.06068*10^(6)}
In accounting form, negative numbers are given in parentheses, and scientific notation is never used.
AccountingForm[{5.6,-6.7,10.^7}]
{5.6,(6.7),10000000.}
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Convert this Nim snippet to C# and keep its semantics consistent. | var x: float
x = 2.3
x = 2.0
x = 0.3
x = 123_456_789.000_000_1
x = 2e10
x = 2.5e10
x = 2.523_123E10
x = 5.2e-10
var y = 2'f32
var z = 2'f64
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Produce a functionally identical C++ code for the snippet given in Nim. | var x: float
x = 2.3
x = 2.0
x = 0.3
x = 123_456_789.000_000_1
x = 2e10
x = 2.5e10
x = 2.523_123E10
x = 5.2e-10
var y = 2'f32
var z = 2'f64
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Rewrite the snippet below in Java so it works the same as the original Nim code. | var x: float
x = 2.3
x = 2.0
x = 0.3
x = 123_456_789.000_000_1
x = 2e10
x = 2.5e10
x = 2.523_123E10
x = 5.2e-10
var y = 2'f32
var z = 2'f64
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Can you help me rewrite this code in Python instead of Nim, keeping it the same logically? | var x: float
x = 2.3
x = 2.0
x = 0.3
x = 123_456_789.000_000_1
x = 2e10
x = 2.5e10
x = 2.523_123E10
x = 5.2e-10
var y = 2'f32
var z = 2'f64
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Port the following code from Nim to VB with equivalent syntax and logic. | var x: float
x = 2.3
x = 2.0
x = 0.3
x = 123_456_789.000_000_1
x = 2e10
x = 2.5e10
x = 2.523_123E10
x = 5.2e-10
var y = 2'f32
var z = 2'f64
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Convert this OCaml snippet to C# and keep its semantics consistent. | 0.5
1.0
1.
1e-10
3.14159_26535_89793
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Port the provided OCaml code into C++ while preserving the original functionality. | 0.5
1.0
1.
1e-10
3.14159_26535_89793
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Preserve the algorithm and functionality while converting the code from OCaml to Java. | 0.5
1.0
1.
1e-10
3.14159_26535_89793
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Produce a language-to-language conversion: from OCaml to Python, same semantics. | 0.5
1.0
1.
1e-10
3.14159_26535_89793
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Can you help me rewrite this code in VB instead of OCaml, keeping it the same logically? | 0.5
1.0
1.
1e-10
3.14159_26535_89793
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Port the provided Perl code into C# while preserving the original functionality. |
.5;
0.5;
1.23345e10;
1.23445e-10;
100_000_000;
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Change the following Perl code into C++ without altering its purpose. |
.5;
0.5;
1.23345e10;
1.23445e-10;
100_000_000;
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Preserve the algorithm and functionality while converting the code from Perl to Java. |
.5;
0.5;
1.23345e10;
1.23445e-10;
100_000_000;
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Keep all operations the same but rewrite the snippet in Python. |
.5;
0.5;
1.23345e10;
1.23445e-10;
100_000_000;
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Generate a VB translation of this Perl snippet without changing its computational steps. |
.5;
0.5;
1.23345e10;
1.23445e-10;
100_000_000;
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Port the following code from Racket to C# with equivalent syntax and logic. | #lang racket
.2
2.
2.+0i
2e0
#x10.8
#o1e2
2.0f0
1.0t0
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Preserve the algorithm and functionality while converting the code from Racket to C++. | #lang racket
.2
2.
2.+0i
2e0
#x10.8
#o1e2
2.0f0
1.0t0
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Generate a Java translation of this Racket snippet without changing its computational steps. | #lang racket
.2
2.
2.+0i
2e0
#x10.8
#o1e2
2.0f0
1.0t0
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Translate this program into Python but keep the logic exactly as in Racket. | #lang racket
.2
2.
2.+0i
2e0
#x10.8
#o1e2
2.0f0
1.0t0
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Convert the following code from Racket to VB, ensuring the logic remains intact. | #lang racket
.2
2.
2.+0i
2e0
#x10.8
#o1e2
2.0f0
1.0t0
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Write the same code in C# as shown below in REXX. |
options replace format comments java crossref symbols nobinary
numeric digits 40 -- make lots of space for big numbers
numeric form scientific -- set output form for exponential notation
say 'Sample using objects of type "Rexx" (default):'
fv = 1.5; say '1.5'.right(20) '==' normalize(fv).right(20) -- 1.5
fv = -1.5; say '-1.5'.right(20) '==' normalize(fv).right(20) -- -1.5
fv = 15e-1; say '15e-1'.right(20) '==' normalize(fv).right(20) -- 1.5
fv = 3e-12; say '3e-12'.right(20) '==' normalize(fv).right(20) -- 3E-12
fv = 3e+12; say '3e+12'.right(20) '==' normalize(fv).right(20) -- 3000000000000
fv = 17.3E-12; say '17.3E-12'.right(20) '==' normalize(fv).right(20) -- 1.73E-11
fv = 17.3E+12; say '17.3E+12'.right(20) '==' normalize(fv).right(20) -- 17300000000000
fv = 17.3E+40; say '17.3E+40'.right(20) '==' normalize(fv).right(20) -- 1.73E+41
fv = 0.033e+9; say '0.033e+9'.right(20) '==' normalize(fv).right(20) -- 33000000
fv = 0.033e-9; say '0.033e-9'.right(20) '==' normalize(fv).right(20) -- 3.3E-11
say
say 'Sample using primitive type "float":'
ff = float
ff = float 15e-1; say '15e-1'.right(20) '==' normalize(ff).right(20) -- 1.5
ff = float 17.3E-12; say '17.3E-12'.right(20) '==' normalize(ff).right(20) -- 1.73E-11
ff = float 17.3E+12; say '17.3E+12'.right(20) '==' normalize(ff).right(20) -- 17300000000000
ff = float 0.033E+9; say '0.033E+9'.right(20) '==' normalize(ff).right(20) -- 33000000
ff = float 0.033E-9; say '0.033E-9'.right(20) '==' normalize(ff).right(20) -- 3.3E-11
say
say 'Sample using primitive type "double":'
fd = double
fd = 15e-1; say '15e-1'.right(20) '==' normalize(fd).right(20) -- 1.5
fd = 17.3E-12; say '17.3E-12'.right(20) '==' normalize(fd).right(20) -- 1.73E-11
fd = 17.3E+12; say '17.3E+12'.right(20) '==' normalize(fd).right(20) -- 17300000000000
fd = 17.3E+40; say '17.3E+40'.right(20) '==' normalize(fd).right(20) -- 1.73E+41
fd = 0.033E+9; say '0.033E+9'.right(20) '==' normalize(fd).right(20) -- 33000000
fd = 0.033E-9; say '0.033E-9'.right(20) '==' normalize(fd).right(20) -- 3.3E-11
say
return
* Convert input to a Rexx object and add zero to the value which forces NetRexx to change its internal representation
*
* @param fv a Rexx object containing the floating point value
* @return a Rexx object which allows NetRexx string manipulation methods to act on it
*/
method normalize(fv) private constant
return fv + 0
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Rewrite the snippet below in C++ so it works the same as the original REXX code. |
options replace format comments java crossref symbols nobinary
numeric digits 40 -- make lots of space for big numbers
numeric form scientific -- set output form for exponential notation
say 'Sample using objects of type "Rexx" (default):'
fv = 1.5; say '1.5'.right(20) '==' normalize(fv).right(20) -- 1.5
fv = -1.5; say '-1.5'.right(20) '==' normalize(fv).right(20) -- -1.5
fv = 15e-1; say '15e-1'.right(20) '==' normalize(fv).right(20) -- 1.5
fv = 3e-12; say '3e-12'.right(20) '==' normalize(fv).right(20) -- 3E-12
fv = 3e+12; say '3e+12'.right(20) '==' normalize(fv).right(20) -- 3000000000000
fv = 17.3E-12; say '17.3E-12'.right(20) '==' normalize(fv).right(20) -- 1.73E-11
fv = 17.3E+12; say '17.3E+12'.right(20) '==' normalize(fv).right(20) -- 17300000000000
fv = 17.3E+40; say '17.3E+40'.right(20) '==' normalize(fv).right(20) -- 1.73E+41
fv = 0.033e+9; say '0.033e+9'.right(20) '==' normalize(fv).right(20) -- 33000000
fv = 0.033e-9; say '0.033e-9'.right(20) '==' normalize(fv).right(20) -- 3.3E-11
say
say 'Sample using primitive type "float":'
ff = float
ff = float 15e-1; say '15e-1'.right(20) '==' normalize(ff).right(20) -- 1.5
ff = float 17.3E-12; say '17.3E-12'.right(20) '==' normalize(ff).right(20) -- 1.73E-11
ff = float 17.3E+12; say '17.3E+12'.right(20) '==' normalize(ff).right(20) -- 17300000000000
ff = float 0.033E+9; say '0.033E+9'.right(20) '==' normalize(ff).right(20) -- 33000000
ff = float 0.033E-9; say '0.033E-9'.right(20) '==' normalize(ff).right(20) -- 3.3E-11
say
say 'Sample using primitive type "double":'
fd = double
fd = 15e-1; say '15e-1'.right(20) '==' normalize(fd).right(20) -- 1.5
fd = 17.3E-12; say '17.3E-12'.right(20) '==' normalize(fd).right(20) -- 1.73E-11
fd = 17.3E+12; say '17.3E+12'.right(20) '==' normalize(fd).right(20) -- 17300000000000
fd = 17.3E+40; say '17.3E+40'.right(20) '==' normalize(fd).right(20) -- 1.73E+41
fd = 0.033E+9; say '0.033E+9'.right(20) '==' normalize(fd).right(20) -- 33000000
fd = 0.033E-9; say '0.033E-9'.right(20) '==' normalize(fd).right(20) -- 3.3E-11
say
return
* Convert input to a Rexx object and add zero to the value which forces NetRexx to change its internal representation
*
* @param fv a Rexx object containing the floating point value
* @return a Rexx object which allows NetRexx string manipulation methods to act on it
*/
method normalize(fv) private constant
return fv + 0
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Can you help me rewrite this code in Java instead of REXX, keeping it the same logically? |
options replace format comments java crossref symbols nobinary
numeric digits 40 -- make lots of space for big numbers
numeric form scientific -- set output form for exponential notation
say 'Sample using objects of type "Rexx" (default):'
fv = 1.5; say '1.5'.right(20) '==' normalize(fv).right(20) -- 1.5
fv = -1.5; say '-1.5'.right(20) '==' normalize(fv).right(20) -- -1.5
fv = 15e-1; say '15e-1'.right(20) '==' normalize(fv).right(20) -- 1.5
fv = 3e-12; say '3e-12'.right(20) '==' normalize(fv).right(20) -- 3E-12
fv = 3e+12; say '3e+12'.right(20) '==' normalize(fv).right(20) -- 3000000000000
fv = 17.3E-12; say '17.3E-12'.right(20) '==' normalize(fv).right(20) -- 1.73E-11
fv = 17.3E+12; say '17.3E+12'.right(20) '==' normalize(fv).right(20) -- 17300000000000
fv = 17.3E+40; say '17.3E+40'.right(20) '==' normalize(fv).right(20) -- 1.73E+41
fv = 0.033e+9; say '0.033e+9'.right(20) '==' normalize(fv).right(20) -- 33000000
fv = 0.033e-9; say '0.033e-9'.right(20) '==' normalize(fv).right(20) -- 3.3E-11
say
say 'Sample using primitive type "float":'
ff = float
ff = float 15e-1; say '15e-1'.right(20) '==' normalize(ff).right(20) -- 1.5
ff = float 17.3E-12; say '17.3E-12'.right(20) '==' normalize(ff).right(20) -- 1.73E-11
ff = float 17.3E+12; say '17.3E+12'.right(20) '==' normalize(ff).right(20) -- 17300000000000
ff = float 0.033E+9; say '0.033E+9'.right(20) '==' normalize(ff).right(20) -- 33000000
ff = float 0.033E-9; say '0.033E-9'.right(20) '==' normalize(ff).right(20) -- 3.3E-11
say
say 'Sample using primitive type "double":'
fd = double
fd = 15e-1; say '15e-1'.right(20) '==' normalize(fd).right(20) -- 1.5
fd = 17.3E-12; say '17.3E-12'.right(20) '==' normalize(fd).right(20) -- 1.73E-11
fd = 17.3E+12; say '17.3E+12'.right(20) '==' normalize(fd).right(20) -- 17300000000000
fd = 17.3E+40; say '17.3E+40'.right(20) '==' normalize(fd).right(20) -- 1.73E+41
fd = 0.033E+9; say '0.033E+9'.right(20) '==' normalize(fd).right(20) -- 33000000
fd = 0.033E-9; say '0.033E-9'.right(20) '==' normalize(fd).right(20) -- 3.3E-11
say
return
* Convert input to a Rexx object and add zero to the value which forces NetRexx to change its internal representation
*
* @param fv a Rexx object containing the floating point value
* @return a Rexx object which allows NetRexx string manipulation methods to act on it
*/
method normalize(fv) private constant
return fv + 0
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Generate an equivalent Python version of this REXX code. |
options replace format comments java crossref symbols nobinary
numeric digits 40 -- make lots of space for big numbers
numeric form scientific -- set output form for exponential notation
say 'Sample using objects of type "Rexx" (default):'
fv = 1.5; say '1.5'.right(20) '==' normalize(fv).right(20) -- 1.5
fv = -1.5; say '-1.5'.right(20) '==' normalize(fv).right(20) -- -1.5
fv = 15e-1; say '15e-1'.right(20) '==' normalize(fv).right(20) -- 1.5
fv = 3e-12; say '3e-12'.right(20) '==' normalize(fv).right(20) -- 3E-12
fv = 3e+12; say '3e+12'.right(20) '==' normalize(fv).right(20) -- 3000000000000
fv = 17.3E-12; say '17.3E-12'.right(20) '==' normalize(fv).right(20) -- 1.73E-11
fv = 17.3E+12; say '17.3E+12'.right(20) '==' normalize(fv).right(20) -- 17300000000000
fv = 17.3E+40; say '17.3E+40'.right(20) '==' normalize(fv).right(20) -- 1.73E+41
fv = 0.033e+9; say '0.033e+9'.right(20) '==' normalize(fv).right(20) -- 33000000
fv = 0.033e-9; say '0.033e-9'.right(20) '==' normalize(fv).right(20) -- 3.3E-11
say
say 'Sample using primitive type "float":'
ff = float
ff = float 15e-1; say '15e-1'.right(20) '==' normalize(ff).right(20) -- 1.5
ff = float 17.3E-12; say '17.3E-12'.right(20) '==' normalize(ff).right(20) -- 1.73E-11
ff = float 17.3E+12; say '17.3E+12'.right(20) '==' normalize(ff).right(20) -- 17300000000000
ff = float 0.033E+9; say '0.033E+9'.right(20) '==' normalize(ff).right(20) -- 33000000
ff = float 0.033E-9; say '0.033E-9'.right(20) '==' normalize(ff).right(20) -- 3.3E-11
say
say 'Sample using primitive type "double":'
fd = double
fd = 15e-1; say '15e-1'.right(20) '==' normalize(fd).right(20) -- 1.5
fd = 17.3E-12; say '17.3E-12'.right(20) '==' normalize(fd).right(20) -- 1.73E-11
fd = 17.3E+12; say '17.3E+12'.right(20) '==' normalize(fd).right(20) -- 17300000000000
fd = 17.3E+40; say '17.3E+40'.right(20) '==' normalize(fd).right(20) -- 1.73E+41
fd = 0.033E+9; say '0.033E+9'.right(20) '==' normalize(fd).right(20) -- 33000000
fd = 0.033E-9; say '0.033E-9'.right(20) '==' normalize(fd).right(20) -- 3.3E-11
say
return
* Convert input to a Rexx object and add zero to the value which forces NetRexx to change its internal representation
*
* @param fv a Rexx object containing the floating point value
* @return a Rexx object which allows NetRexx string manipulation methods to act on it
*/
method normalize(fv) private constant
return fv + 0
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Maintain the same structure and functionality when rewriting this code in VB. |
options replace format comments java crossref symbols nobinary
numeric digits 40 -- make lots of space for big numbers
numeric form scientific -- set output form for exponential notation
say 'Sample using objects of type "Rexx" (default):'
fv = 1.5; say '1.5'.right(20) '==' normalize(fv).right(20) -- 1.5
fv = -1.5; say '-1.5'.right(20) '==' normalize(fv).right(20) -- -1.5
fv = 15e-1; say '15e-1'.right(20) '==' normalize(fv).right(20) -- 1.5
fv = 3e-12; say '3e-12'.right(20) '==' normalize(fv).right(20) -- 3E-12
fv = 3e+12; say '3e+12'.right(20) '==' normalize(fv).right(20) -- 3000000000000
fv = 17.3E-12; say '17.3E-12'.right(20) '==' normalize(fv).right(20) -- 1.73E-11
fv = 17.3E+12; say '17.3E+12'.right(20) '==' normalize(fv).right(20) -- 17300000000000
fv = 17.3E+40; say '17.3E+40'.right(20) '==' normalize(fv).right(20) -- 1.73E+41
fv = 0.033e+9; say '0.033e+9'.right(20) '==' normalize(fv).right(20) -- 33000000
fv = 0.033e-9; say '0.033e-9'.right(20) '==' normalize(fv).right(20) -- 3.3E-11
say
say 'Sample using primitive type "float":'
ff = float
ff = float 15e-1; say '15e-1'.right(20) '==' normalize(ff).right(20) -- 1.5
ff = float 17.3E-12; say '17.3E-12'.right(20) '==' normalize(ff).right(20) -- 1.73E-11
ff = float 17.3E+12; say '17.3E+12'.right(20) '==' normalize(ff).right(20) -- 17300000000000
ff = float 0.033E+9; say '0.033E+9'.right(20) '==' normalize(ff).right(20) -- 33000000
ff = float 0.033E-9; say '0.033E-9'.right(20) '==' normalize(ff).right(20) -- 3.3E-11
say
say 'Sample using primitive type "double":'
fd = double
fd = 15e-1; say '15e-1'.right(20) '==' normalize(fd).right(20) -- 1.5
fd = 17.3E-12; say '17.3E-12'.right(20) '==' normalize(fd).right(20) -- 1.73E-11
fd = 17.3E+12; say '17.3E+12'.right(20) '==' normalize(fd).right(20) -- 17300000000000
fd = 17.3E+40; say '17.3E+40'.right(20) '==' normalize(fd).right(20) -- 1.73E+41
fd = 0.033E+9; say '0.033E+9'.right(20) '==' normalize(fd).right(20) -- 33000000
fd = 0.033E-9; say '0.033E-9'.right(20) '==' normalize(fd).right(20) -- 3.3E-11
say
return
* Convert input to a Rexx object and add zero to the value which forces NetRexx to change its internal representation
*
* @param fv a Rexx object containing the floating point value
* @return a Rexx object which allows NetRexx string manipulation methods to act on it
*/
method normalize(fv) private constant
return fv + 0
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Generate a C# translation of this Ruby snippet without changing its computational steps. | say 1.234;
say .1234;
say 1234e-5;
say 12.34e5;
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Change the programming language of this snippet from Ruby to C++ without modifying what it does. | say 1.234;
say .1234;
say 1234e-5;
say 12.34e5;
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Produce a language-to-language conversion: from Ruby to Java, same semantics. | say 1.234;
say .1234;
say 1234e-5;
say 12.34e5;
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Convert the following code from Ruby to Python, ensuring the logic remains intact. | say 1.234;
say .1234;
say 1234e-5;
say 12.34e5;
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Preserve the algorithm and functionality while converting the code from Ruby to VB. | say 1.234;
say .1234;
say 1234e-5;
say 12.34e5;
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Write the same code in C# as shown below in Scala. | 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
Float.MinPositiveValue
Float.NaN
Float.PositiveInfinity
Float.NegativeInfinity
Double.MinPositiveValue
Double.NaN
Double.PositiveInfinity
Double.NegativeInfinity
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Translate the given Scala code snippet into C++ without altering its behavior. | 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
Float.MinPositiveValue
Float.NaN
Float.PositiveInfinity
Float.NegativeInfinity
Double.MinPositiveValue
Double.NaN
Double.PositiveInfinity
Double.NegativeInfinity
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Produce a functionally identical Java code for the snippet given in Scala. | 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
Float.MinPositiveValue
Float.NaN
Float.PositiveInfinity
Float.NegativeInfinity
Double.MinPositiveValue
Double.NaN
Double.PositiveInfinity
Double.NegativeInfinity
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Convert this Scala block to Python, preserving its control flow and logic. | 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
Float.MinPositiveValue
Float.NaN
Float.PositiveInfinity
Float.NegativeInfinity
Double.MinPositiveValue
Double.NaN
Double.PositiveInfinity
Double.NegativeInfinity
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Generate a VB translation of this Scala snippet without changing its computational steps. | 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
Float.MinPositiveValue
Float.NaN
Float.PositiveInfinity
Float.NegativeInfinity
Double.MinPositiveValue
Double.NaN
Double.PositiveInfinity
Double.NegativeInfinity
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Change the following Swift code into C# without altering its purpose. | let double = 1.0 as Double
let float = 1.0 as Float
let scientific = 1.0E-12
let sum = double + float
let div = 1.1 / 2
let div1 = 1 / 2
| double d = 1;
d = 1d;
d = 1D;
d = 1.2;
d = 1.2d;
d = .2;
d = 12e-12;
d = 12E-12;
d = 1_234e-1_2;
float f = 1;
f = 1f;
f = 1F;
f = 1.2f;
f = .2f;
f = 12e-12f;
f = 12E-12f;
f = 1_234e-1_2f;
decimal m = 1;
m = 1m;
m = 1m;
m = 1.2m;
m = .2m;
m = 12e-12m;
m = 12E-12m;
m = 1_234e-1_2m;
|
Change the following Swift code into C++ without altering its purpose. | let double = 1.0 as Double
let float = 1.0 as Float
let scientific = 1.0E-12
let sum = double + float
let div = 1.1 / 2
let div1 = 1 / 2
| #include <iostream>
int main()
{
auto double1 = 2.5;
auto float1 = 2.5f;
auto longdouble1 = 2.5l;
auto double2 = 2.5e-3;
auto float2 = 2.5e3f;
auto double3 = 0x1p4;
auto float3 = 0xbeefp-8f;
std::cout << "\ndouble1: " << double1;
std::cout << "\nfloat1: " << float1;
std::cout << "\nlongdouble1: " << longdouble1;
std::cout << "\ndouble2: " << double2;
std::cout << "\nfloat2: " << float2;
std::cout << "\ndouble3: " << double3;
std::cout << "\nfloat3: " << float3;
std::cout << "\n";
}
|
Can you help me rewrite this code in Java instead of Swift, keeping it the same logically? | let double = 1.0 as Double
let float = 1.0 as Float
let scientific = 1.0E-12
let sum = double + float
let div = 1.1 / 2
let div1 = 1 / 2
| 1.
1.0
2432311.7567374
1.234E-10
1.234e-10
758832d
728832f
1.0f
758832D
728832F
1.0F
1 / 2.
1 / 2
|
Port the following code from Swift to Python with equivalent syntax and logic. | let double = 1.0 as Double
let float = 1.0 as Float
let scientific = 1.0E-12
let sum = double + float
let div = 1.1 / 2
let div1 = 1 / 2
| 2.3
.3
.3e4
.3e+34
.3e-34
2.e34
|
Maintain the same structure and functionality when rewriting this code in VB. | let double = 1.0 as Double
let float = 1.0 as Float
let scientific = 1.0E-12
let sum = double + float
let div = 1.1 / 2
let div1 = 1 / 2
| Sub Main()
Dim d As Double
Dim s As Single
d = -12.3456
d = 1000#
d = 0.00001
d = 67#
d = 8.9
d = 0.33
d = 0#
d = 2# * 10 ^ 3
d = 2E+50
d = 2E-50
s = -12.3456!
s = 1000!
s = 0.00001!
s = 67!
s = 8.9!
s = 0.33!
s = 0!
s = 2! * 10 ^ 3
End Sub
|
Translate this program into PHP but keep the logic exactly as in Rust. | 2.3
3.
2f64
1_000.2_f32
| .12
0.1234
1.2e3
7E-10
|
Convert this Ada snippet to PHP and keep its semantics consistent. | 3.141_592_6
1.0E-12
0.13
| .12
0.1234
1.2e3
7E-10
|
Keep all operations the same but rewrite the snippet in PHP. | 2
2.
.3
45e6
45e+6
78e-9
1.2E34
| .12
0.1234
1.2e3
7E-10
|
Translate the given BBC_Basic code snippet into PHP without altering its behavior. |
PRINT -123.456E-1
PRINT 1000.0
PRINT 1E-5
PRINT 67.
PRINT 8.9E
PRINT .33E-
PRINT -.
| .12
0.1234
1.2e3
7E-10
|
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