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Maintain the same structure and functionality when rewriting this code in C++.
print( "Fire", "Police", "Sanitation" ) sol = 0 for f = 1, 7 do for p = 1, 7 do for s = 1, 7 do if s + p + f == 12 and p % 2 == 0 and f ~= p and f ~= s and p ~= s then print( f, p, s ); sol = sol + 1 end end end end print( string.format( "\n%d solutions fo...
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Produce a language-to-language conversion: from Lua to C++, same semantics.
print( "Fire", "Police", "Sanitation" ) sol = 0 for f = 1, 7 do for p = 1, 7 do for s = 1, 7 do if s + p + f == 12 and p % 2 == 0 and f ~= p and f ~= s and p ~= s then print( f, p, s ); sol = sol + 1 end end end end print( string.format( "\n%d solutions fo...
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Rewrite this program in Java while keeping its functionality equivalent to the Lua version.
print( "Fire", "Police", "Sanitation" ) sol = 0 for f = 1, 7 do for p = 1, 7 do for s = 1, 7 do if s + p + f == 12 and p % 2 == 0 and f ~= p and f ~= s and p ~= s then print( f, p, s ); sol = sol + 1 end end end end print( string.format( "\n%d solutions fo...
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Convert this Lua snippet to Java and keep its semantics consistent.
print( "Fire", "Police", "Sanitation" ) sol = 0 for f = 1, 7 do for p = 1, 7 do for s = 1, 7 do if s + p + f == 12 and p % 2 == 0 and f ~= p and f ~= s and p ~= s then print( f, p, s ); sol = sol + 1 end end end end print( string.format( "\n%d solutions fo...
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Translate this program into Python but keep the logic exactly as in Lua.
print( "Fire", "Police", "Sanitation" ) sol = 0 for f = 1, 7 do for p = 1, 7 do for s = 1, 7 do if s + p + f == 12 and p % 2 == 0 and f ~= p and f ~= s and p ~= s then print( f, p, s ); sol = sol + 1 end end end end print( string.format( "\n%d solutions fo...
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Change the programming language of this snippet from Lua to Python without modifying what it does.
print( "Fire", "Police", "Sanitation" ) sol = 0 for f = 1, 7 do for p = 1, 7 do for s = 1, 7 do if s + p + f == 12 and p % 2 == 0 and f ~= p and f ~= s and p ~= s then print( f, p, s ); sol = sol + 1 end end end end print( string.format( "\n%d solutions fo...
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Write the same code in VB as shown below in Lua.
print( "Fire", "Police", "Sanitation" ) sol = 0 for f = 1, 7 do for p = 1, 7 do for s = 1, 7 do if s + p + f == 12 and p % 2 == 0 and f ~= p and f ~= s and p ~= s then print( f, p, s ); sol = sol + 1 end end end end print( string.format( "\n%d solutions fo...
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Translate this program into VB but keep the logic exactly as in Lua.
print( "Fire", "Police", "Sanitation" ) sol = 0 for f = 1, 7 do for p = 1, 7 do for s = 1, 7 do if s + p + f == 12 and p % 2 == 0 and f ~= p and f ~= s and p ~= s then print( f, p, s ); sol = sol + 1 end end end end print( string.format( "\n%d solutions fo...
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Transform the following Lua implementation into Go, maintaining the same output and logic.
print( "Fire", "Police", "Sanitation" ) sol = 0 for f = 1, 7 do for p = 1, 7 do for s = 1, 7 do if s + p + f == 12 and p % 2 == 0 and f ~= p and f ~= s and p ~= s then print( f, p, s ); sol = sol + 1 end end end end print( string.format( "\n%d solutions fo...
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Produce a language-to-language conversion: from Lua to Go, same semantics.
print( "Fire", "Police", "Sanitation" ) sol = 0 for f = 1, 7 do for p = 1, 7 do for s = 1, 7 do if s + p + f == 12 and p % 2 == 0 and f ~= p and f ~= s and p ~= s then print( f, p, s ); sol = sol + 1 end end end end print( string.format( "\n%d solutions fo...
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Port the provided Mathematica code into C while preserving the original functionality.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Write the same algorithm in C as shown in this Mathematica implementation.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Rewrite the snippet below in C# so it works the same as the original Mathematica code.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Write the same algorithm in C# as shown in this Mathematica implementation.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Port the following code from Mathematica to C++ with equivalent syntax and logic.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Rewrite this program in C++ while keeping its functionality equivalent to the Mathematica version.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Generate an equivalent Java version of this Mathematica code.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Translate this program into Java but keep the logic exactly as in Mathematica.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Write a version of this Mathematica function in Python with identical behavior.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Rewrite this program in Python while keeping its functionality equivalent to the Mathematica version.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Translate this program into VB but keep the logic exactly as in Mathematica.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Preserve the algorithm and functionality while converting the code from Mathematica to VB.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Transform the following Mathematica implementation into Go, maintaining the same output and logic.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Generate a Go translation of this Mathematica snippet without changing its computational steps.
Select[Permutations[Range[7], {3}], Total[#] == 12 && EvenQ[First[#]] &]
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Write the same algorithm in C as shown in this Nim implementation.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Transform the following Nim implementation into C, maintaining the same output and logic.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Write the same code in C# as shown below in Nim.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Keep all operations the same but rewrite the snippet in C#.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Generate an equivalent C++ version of this Nim code.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Convert the following code from Nim to C++, ensuring the logic remains intact.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Write the same algorithm in Java as shown in this Nim implementation.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Can you help me rewrite this code in Java instead of Nim, keeping it the same logically?
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Produce a functionally identical Python code for the snippet given in Nim.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Port the following code from Nim to Python with equivalent syntax and logic.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Transform the following Nim implementation into VB, maintaining the same output and logic.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Convert this Nim snippet to VB and keep its semantics consistent.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Port the following code from Nim to Go with equivalent syntax and logic.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Port the provided Nim code into Go while preserving the original functionality.
type Solution = tuple[p, s, f: int] iterator solutions(max, total: Positive): Solution = for p in countup(2, max, 2): for s in 1..max: if s == p: continue let f = total - p - s if f notin [p, s] and f in 1..max: yield (p, s, f) echo "P S F" for sol in solutions(7, 12): echo sol.p, " ...
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Maintain the same structure and functionality when rewriting this code in C.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Change the programming language of this snippet from OCaml to C without modifying what it does.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Port the following code from OCaml to C# with equivalent syntax and logic.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Produce a functionally identical C# code for the snippet given in OCaml.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Produce a functionally identical C++ code for the snippet given in OCaml.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Translate the given OCaml code snippet into C++ without altering its behavior.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Transform the following OCaml implementation into Java, maintaining the same output and logic.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Translate the given OCaml code snippet into Java without altering its behavior.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Generate a Python translation of this OCaml snippet without changing its computational steps.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Write a version of this OCaml function in Python with identical behavior.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Rewrite this program in VB while keeping its functionality equivalent to the OCaml version.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Transform the following OCaml implementation into Go, maintaining the same output and logic.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Rewrite this program in Go while keeping its functionality equivalent to the OCaml version.
type sfp = {s : int; f : int; p : int} let print_sfp e = Printf.printf "%d %d %d\n" e.s e.f e.p let print_sfp_list l = l |> List.iter print_sfp let sum l = List.fold_left (+) 0 l let element_in_list e l = l |> List.find_map (fun x -> if x == e then Some(e) else None) <> None let uniq l = l...
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Write a version of this Perl function in C with identical behavior.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Change the programming language of this snippet from Perl to C without modifying what it does.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Rewrite the snippet below in C# so it works the same as the original Perl code.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Generate an equivalent C# version of this Perl code.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Can you help me rewrite this code in C++ instead of Perl, keeping it the same logically?
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Write the same algorithm in C++ as shown in this Perl implementation.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Port the following code from Perl to Java with equivalent syntax and logic.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Convert the following code from Perl to Java, ensuring the logic remains intact.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Rewrite the snippet below in Python so it works the same as the original Perl code.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Convert the following code from Perl to Python, ensuring the logic remains intact.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Rewrite the snippet below in VB so it works the same as the original Perl code.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Port the following code from Perl to VB with equivalent syntax and logic.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Write the same algorithm in Go as shown in this Perl implementation.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Maintain the same structure and functionality when rewriting this code in Go.
my @even_numbers; for (1..7) { if ( $_ % 2 == 0) { push @even_numbers, $_; } } print "Police\tFire\tSanitation\n"; foreach my $police_number (@even_numbers) { for my $fire_number (1..7) { for my $sanitation_number (1..7) { if ( $police_number + $fire_number + $sanitation_number == 12 &...
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Translate the given Racket code snippet into C without altering its behavior.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Generate an equivalent C version of this Racket code.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Change the following Racket code into C# without altering its purpose.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Can you help me rewrite this code in C# instead of Racket, keeping it the same logically?
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Maintain the same structure and functionality when rewriting this code in C++.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Maintain the same structure and functionality when rewriting this code in C++.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Translate the given Racket code snippet into Java without altering its behavior.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Rewrite the snippet below in Java so it works the same as the original Racket code.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Rewrite the snippet below in Python so it works the same as the original Racket code.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Convert the following code from Racket to Python, ensuring the logic remains intact.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Write the same code in VB as shown below in Racket.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Generate a VB translation of this Racket snippet without changing its computational steps.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Port the provided Racket code into Go while preserving the original functionality.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Translate this program into Go but keep the logic exactly as in Racket.
#lang racket (cons '(police fire sanitation) (filter (λ (pfs) (and (not (check-duplicates pfs)) (= 12 (apply + pfs)) pfs)) (cartesian-product (range 2 8 2) (range 1 8) (range 1 8))))
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Write the same code in C as shown below in COBOL.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Change the programming language of this snippet from COBOL to C without modifying what it does.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Port the provided COBOL code into C# while preserving the original functionality.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Change the programming language of this snippet from COBOL to C# without modifying what it does.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Change the programming language of this snippet from COBOL to C++ without modifying what it does.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Generate an equivalent C++ version of this COBOL code.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Port the following code from COBOL to Java with equivalent syntax and logic.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Keep all operations the same but rewrite the snippet in Java.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...
Maintain the same structure and functionality when rewriting this code in Python.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Change the following COBOL code into Python without altering its purpose.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
from itertools import permutations def solve(): c, p, f, s = "\\,Police,Fire,Sanitation".split(',') print(f"{c:>3} {p:^6} {f:^4} {s:^10}") c = 1 for p, f, s in permutations(range(1, 8), r=3): if p + s + f == 12 and p % 2 == 0: print(f"{c:>3}: {p:^6} {f:^4} {s:^10}") c ...
Ensure the translated VB code behaves exactly like the original COBOL snippet.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Write the same code in VB as shown below in COBOL.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
Module Module1 Sub Main() For p = 2 To 7 Step 2 For s = 1 To 7 Dim f = 12 - p - s If s >= f Then Exit For End If If f > 7 Then Continue For End If If s = p OrE...
Rewrite this program in Go while keeping its functionality equivalent to the COBOL version.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Write the same code in Go as shown below in COBOL.
IDENTIFICATION DIVISION. PROGRAM-ID. DEPARTMENT-NUMBERS. DATA DIVISION. WORKING-STORAGE SECTION. 01 BANNER PIC X(24) VALUE "POLICE SANITATION FIRE". 01 COMBINATION. 03 FILLER PIC X(5) VALUE SPACES. 03 POLICE PIC 9. 03 FILL...
package main import "fmt" func main() { fmt.Println("Police Sanitation Fire") fmt.Println("------ ---------- ----") count := 0 for i := 2; i < 7; i += 2 { for j := 1; j < 8; j++ { if j == i { continue } for k := 1; k < 8; k++ { if k == i || k == j { ...
Please provide an equivalent version of this REXX code in C.
say 'police sanitation fire' say '══════ ══════════ ════' #=0 do p=1 for 7; if p//2 then iterate do s=1 for 7; if s==p then iterate do f=1 for 7; if f==s then iterate if p + s + ...
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Please provide an equivalent version of this REXX code in C.
say 'police sanitation fire' say '══════ ══════════ ════' #=0 do p=1 for 7; if p//2 then iterate do s=1 for 7; if s==p then iterate do f=1 for 7; if f==s then iterate if p + s + ...
#include<stdio.h> int main() { int police,sanitation,fire; printf("Police Sanitation Fire\n"); printf("----------------------------------"); for(police=2;police<=6;police+=2){ for(sanitation=1;sanitation<=7;sanitation++){ for(fire=1;fire<=7;fire++){ if(police!=sanitation && sanitation!=fir...
Generate a C# translation of this REXX snippet without changing its computational steps.
say 'police sanitation fire' say '══════ ══════════ ════' #=0 do p=1 for 7; if p//2 then iterate do s=1 for 7; if s==p then iterate do f=1 for 7; if f==s then iterate if p + s + ...
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Keep all operations the same but rewrite the snippet in C#.
say 'police sanitation fire' say '══════ ══════════ ════' #=0 do p=1 for 7; if p//2 then iterate do s=1 for 7; if s==p then iterate do f=1 for 7; if f==s then iterate if p + s + ...
using System; public class Program { public static void Main() { for (int p = 2; p <= 7; p+=2) { for (int s = 1; s <= 7; s++) { int f = 12 - p - s; if (s >= f) break; if (f > 7) continue; if (s == p || f == p) continue; ...
Can you help me rewrite this code in C++ instead of REXX, keeping it the same logically?
say 'police sanitation fire' say '══════ ══════════ ════' #=0 do p=1 for 7; if p//2 then iterate do s=1 for 7; if s==p then iterate do f=1 for 7; if f==s then iterate if p + s + ...
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Transform the following REXX implementation into C++, maintaining the same output and logic.
say 'police sanitation fire' say '══════ ══════════ ════' #=0 do p=1 for 7; if p//2 then iterate do s=1 for 7; if s==p then iterate do f=1 for 7; if f==s then iterate if p + s + ...
#include <iostream> #include <iomanip> int main( int argc, char* argv[] ) { int sol = 1; std::cout << "\t\tFIRE\t\tPOLICE\t\tSANITATION\n"; for( int f = 1; f < 8; f++ ) { for( int p = 1; p < 8; p++ ) { for( int s = 1; s < 8; s++ ) { if( f != p && f != s && p != s && !( p...
Generate an equivalent Java version of this REXX code.
say 'police sanitation fire' say '══════ ══════════ ════' #=0 do p=1 for 7; if p//2 then iterate do s=1 for 7; if s==p then iterate do f=1 for 7; if f==s then iterate if p + s + ...
public class DepartmentNumbers { public static void main(String[] args) { System.out.println("Police Sanitation Fire"); System.out.println("------ ---------- ----"); int count = 0; for (int i = 2; i <= 6; i += 2) { for (int j = 1; j <= 7; ++j) { if (j ...