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which in some particular coordinate system has the three components (đ„, đ„, đ;), |
and that b is another vector which has the three components (b„, b„,b„). Ñow |
let us invent three new numbers (a„ + Ö„,d„ + b„,a„ + b;). Do these form a |
vector? “Well,” we might say, “they are three numbers, and every three numbers |
form a vector.” Ño, no£ every three numbers form a vector! In order for it to be |
a vector, not only must there be three numbers, but these must be associated |
with a coordinate system in such a way that 1Ý we turn the coordinate system, |
the three numbers “revolve” on each other, get “mixed up” in each other, by |
the precise laws we have already described. So the question is, if we now rotate |
the coordinate system so that (a„, #,,ø„) become (đx, đ„,øz:) and (b„, b„, b„) |
--- Trang 222 --- |
become (b„¿, b„/, b„;), what do (az„ + bạ, ay + bự, ø„ + b„) become? Do they become |
(Ga + bạ, dự -E bu,a„; + by) or not? The answer is, oÝ course, yes, because |
the prototype transformations of Eq. (11.5) constitute what we call a ii¿mear |
transformation. If we apply those transformations to ø„ and Ö„ to get aœ„ + bạ, |
we fnd that the transformed a„ -+ b„ is indeed the same as ø„; + b„;. When œ |
and ö are “added together” in this sense, they will form a vector which we may |
call e. We would write this as |
c=œa+b. |
Now e has the interesting property |
c=b+ea, |
as we can immediately see from i%s components. 'Thus also, |
œ-+(b+c)=(a+b)+c. |
W© can add vectors in any order. |
What is the geometric significance of œ + b? Suppose that œ and b were |
represented by lines on a piece of paper, what would e look like? 'This is shown |
in Eig. II-4. We see that we can add the components of b to those oŸ œ most |
conveniently if we place the rectangle representing the components of next to |
that representing the components of ø in the manner indicated. Since b just |
“fñts” into its rectangle, as does ø into its rectangle, this is the same as putting |
the “tail” of b on the “head” of ø, the arrow from the “tail” of œ to the “head” |
of b being the vector œ. OÝ course, if we added ø to b the other way around, we |
___— ' |
__— /. __—_— Ị |
I 1 Xx |
Fig. 11-4. The addition of vectors. |
--- Trang 223 --- |
would put the “tail” of œ on the “head” of b, and by the geometrical properties |
of parallelograms we would get the same result for c. Note that vectors can be |
added in this way without reference to any coordinate axes. |
Suppose we multiply a vector by a number œ, what does this mean? We |
deffne it to mean a new vector whose components are œø„, œa„, and œaz;. We |
leave 1t as a problem for the student to prove that it 7s a vector. |
Now let us consider vector subtraction. We may deñne subtraction in the |
same way as addition, but instead of adding, we subtract the components. Ôr |
we might defñne subtraction by defning a negative vector, —b = —1b, and then |
we would add the components. ÏIt comes to the same thing. The result ¡is shown |
in Eig. 11-5. This fñgure shows d = œ— b= ø-+ (—Ùb); we also note that the |
diference ø — b can be found very easily from ø and b by using the equivalent |
relatlon œ = b+ d. 'Thus the diference is even easier to find than the sum: we |
Jjust draw the vector from b to ø, to get œ — bÌ |
Fig. 11-5. The subtraction of vectors. |
Next we discuss velocity. Why is velocity a vector? lÝ position is given |
by the three coordinates (z,,z), what is the velocity? "The velocity is given |
by dz/dt, dụ/dt, and dz/dt. Is that a vector, or not? We can fnd out by |
differentiating the expressions in Eq. (11.5) to find out whether đ+ /đ transƒorms |
in the ripht way. We see that the components đz/đt and dụ/dt do transform |
according to the same law as # and , and therefore the time derivative 2s a |
vector. 5o the velocity is a vector. We can write the velocity in an interesting |
WayV aS |
= dr(dt. |
What the velocity is, and why i% is a vector, can also be understood more |
pictorially: How far does a particle move in a short time A£? Answer: Az, so if |
a particle is “here” at one instant and “there” at another instant, then the vector |
diference of the positions Am = rs — r, which is in the direction oŸ motion |
--- Trang 224 --- |
shown in Fig. 11-6, divided by the time interval Af = ‡a — f, is the “average |
velocity” vector. |
Ar = ra — |
T2 1 |
Fig. 11-6. The displacement of a particle in a short time interval Af = |
ta — tì. |
In other words, by vector velocity we mean the limit, as A# goes to 0, of the |
diference between the radius vectors at the time £ + A£ and the time ý, divided |
by Ai: |
ò= lim (Ar/At) = dr/át. (11.10) |
Thus velocity is a vector because it is the difference of two vectors. ÏIt is also the |
right defnition of velocity because its components are d+/dt, dụ/dt, and dz/di. |
In fact, we see from this argument that if we diferentiate amw vector with respect |
to time we produce a new vector. So we have several ways of producing new |
vectors: (1) multiply by a constant, (2) diferentiate with respect to time, (3) add |
or subtract bwo vectOrs. |
11-6 Newton°s laws in vector notation |
In order to write Newton”s laws in vector form, we have to go Just one step |
further, and defne the acceleration vector. 'This is the time derivative of the |
velocity vector, and it is easy to demonstrate that its components are the second |
derivatives of z, , and z with respect to ý: |
đu đÀ (dr đ?r |
dt dt dt đị2 |
duy d2z đuy dầu dù; d2z |
TC dị) C9 CA d) “5” đÐ — dự 112) |
--- Trang 225 --- |
With this defñnition, then, Newton's laws can be written in this way: |
ma = F (11.13) |
m(dŠr/dt?) = F. (11.14) |
Now the problem of proving the invariance of Ñewton”s laws under rotation |
of coordinates is this: prove that œ is a vector; this we have just done. Prove |
that #' is a vector; we swppose it is. So 1Í Íforce is a vector, then, since we know |
acceleration is a vector, q. (11.13) will look the same in any coordinate system. |
Writing ¡it in a form which does not explicitly contain zø”s, 's, and zˆs has the |
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