text stringlengths 0 6.73k |
|---|
argument against the corpuscular theory; it was used by Huygens. If light were |
like a lot of arrows shooting along, how could other arrows go through them so |
easily? Such philosophical arguments are not of mụch weight. One could always |
say that light is made up of arrows which go through each otherl |
26-2 Reflection and refraction |
The discussion above gives enough of the basic iđeø of geometrical optics—now |
we have to go a little further into the quantitative features. Thus far we have light |
going only in straight lines bebween two points; now let us study the behavior |
of light when it hits various materials. The simplest object is a mirror, and the |
law for a mirror is that when the light hits the mirror, it does not continue in a |
straight line, but bounces of the mirror into a new straight line, which changes |
when we change the inclination of the mirror. 'Phe question for the aneients |
was, what is the relation between the two angles involved? This is a very simple |
relation, discovered long ago. 'Phe light striking a mirror travels in such a way |
that the two angles, between each beam and the mirror, are equal. For some |
reason iÈ is customary to measure the angles from the normal to the mirror |
surface. Thus the so-called law of refection 1s |
0; = Ú,. (26.1) |
'That is a simple enough proposition, but a more dificult problem is encoun- |
tered when light goes from one medium into another, for example from air into |
water; here also, we see that it does not go in a straight line. In the water the |
ray is a% an inclination to its path in the air; if we change the angle Ø; so that |
1t comes down more nearly vertically, then the angle of “breakage” is not as |
\ø, ro, Ế |
Fig. 26-1. The angle of incidence ¡s equal to the angle of reflection. |
--- Trang 455 --- |
Fig. 26-2. A light ray Is refracted when It posses from one medium |
Into another. |
Table 26-1 Table 26-2 |
Anglein air Angle in water Anglein air Angle in water |
10° 8° 10° 7-1/2° |
207 15-1/2 207 15° |
30 22-1/2° 30 22” |
400 29 40 29° |
502 35° 502 35° |
60° 40-1/2° 60° 40-1/2° |
702 45-1/2° 702 45” |
80 502 802 48” |
great. But iŸ we tilt the beam of light at quite an angle, then the deviation angle |
1s very large. The question is, what is the relation of one angle to the other? |
This also puzzled the ancients for a long time, and here they never found the |
answerl It is, however, one of the few places in all of Greek physics that one |
may fñnd any experimental results listed. Claudius Ptolemy made a list of the |
angle in water for each of a number of diferent angles in air. Table 26-1 shows |
the angles In the air, in degrees, and the corresponding angle as measured In |
the water. (Ordinarily it is said that Greek scientists never did any experiments. |
But it would be impossible to obtain this table of values without knowing the |
ripht law, except by experiment. It should be noted, however, that these do |
not represent independent careful measurements for each angle but only some |
numbers interpolated from a few measurements, for they all ft perfectly on a |
parabola.) |
--- Trang 456 --- |
'This, then, is one of the important steps in the development of physical law: |
frst we observe an efect, then we measure it and list it in a table; then we try |
to fnd the ruie by which one thing can be connected with another. The above |
numerical table was made in 140 A.D., but ít was not until 1621 that someone |
finally found the rule connecting the two anglesl The rule, found by Willebrord |
Snell, a Dutch mathematician, is as follows: if Ø; is the angle in air and Ø„ is the |
angle in the water, then i% turns out that the sine of Ø; is equal to some constant |
multiple of the sine of Ø,„: |
sin Ø¿ = n0sin Ø„. (26.2) |
For water the number ø is approximately 1.33. Equation (26.2) is called Šnells |
la; 1 permits us to predict how the light is goïng to bend when it goes Írom air |
into water. Table 26-2 shows the angles in air and in water according to Snells |
law. Note the remarkable agreement with Ptolemy's list. |
26-3 Eermat?s principle of least tỉme |
Now in the further development of science, we want more than just a formula. |
Pirst we have an observation, then we have numbers that we measure, then we |
have a law which summarizes all the numbers. But the real gior of science 1s |
that te can fnd a U0ay öƒ thinkứng súch that the law 1s cuident. |
The fñrst way of thinking that made the law about the behavior of light evident |
was discovered by Fermat in about 1650, and it is called ¿he pr¿inciple oƒ least |
time, or Ferma†s principle. His idea 1s thịs: that out of all possible paths that it |
might take to get from one point to another, light takes the path which requires |
the shortest từmc. |
Let us first show that this is true for the case of the mirror, that this simple |
prineiple contains both the law of straight-line propagation and the law for the |
mirror. So, we are growing in our understandingl Let us try to ñnd the solution |
to the following problem. In Eig. 26-3 are shown two points, A and Ö, and a |
plane mirror, 1ƒ“. What is the way to get rom A to in the shortest time? |
The answer is to go straight from 4 to Bƒ But if we add the extra rule that the |
light has to sfứrike the mưrror and come back in the shortest time, the answer is |
not so easy. QÔne way would be to go as quickly as possible to the mirror and |
then go to Ö, on the path AJD2B. Of course, we then have a long path 2Ö. If we |
move over a little to the right, to 2, we slipghtly increase the first distance, but |
we greatly decrease the second one, and so the total path length, and therefore |
--- Trang 457 --- |
A __===—— Z |
ụ _+Z : |
Ẫ ` ZZ ⁄ |
LÀ<z ~ |
M—*^ _< E—M |
XI ÔNG Ộ |
Fig. 26-3. lllustration of the principle of least time. |
the travel time, is less. How can we find the point Œ for which the time is the |
shortest? We can fñnd it very nicely by a geometrical trick. |
W© construct on the other side of MƒÄ⁄” an artifcial point ”, which is the |
same distance below the plane ăĔ as the point Ö is above the plane. Then |
we draw the line #Z/. Now because ÖƑ'ÄM is a right angle and ÐF'= F'B', ⁄B |
is equal to #'. Therefore the sum of the bwo distances, A4 + EB, which is |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.