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proportional to the time it wiïll take ïf the light travels with constant velocity, |
1s also the sum of the bwo lengths A4 + B7. Therefore the problem becomes, |
when is the sum of these two lengths the least? 'Phe answer is easy: when the |
line goes through point Œ as a sfraight line from A to PT In other words, we |
have to fnd the point where we go toward the artificial point, and that will be |
the correct one. NÑow if AC” is a straight line, then angle TP" is equal to |
angle EỚP and thence to angle AC. Thus the statement that the angle of |
Ineidence equals the angle of refection is equivalent to the statement that the |
light goes to the mirror in such a way that it comes back to the point Ö in the |
least possible time. Originally, the statement was made by Hero of Alexandria |
that the light travels in such a way that it goes 0o the mirror and to the other |
point in the shortest possible đZs#ønce, so 1t 1s not a modern theory. It was this |
that inspired Eermat to suggest to himself that perhaps refraction operated on a |
similar basis. But for refraction, light obviously does not use the path of shortest |
đistance, so Fermat tried the idea that it takes the shortest #zme. |
Before we go on to analyze refraction, we should make one more remark about |
the mirror. IÝ we have a source of light at the point and ït sends light to |
ward the mirror, then we see that the light which goes to A from the point |
comes to .4 in exactly the same manner as it would have come to A ïf there were |
--- Trang 458 --- |
an object at , and no mirror. NÑow of course the eye detects only the light |
which enters it physically, so if we have an object at and a mirror which makes |
the light come into the eye in exactly the same manner as iÿ would have come |
into the eye ïf the object were at ”, then the eye-brain system interprets that, |
assuming i% does not know too mụch, as Öe#ng an object at 7. So the illusion |
that there is an object behind the mirror is merely due to the fact that the light |
which is entering the eye is entering in exactly the same manner, physically, as it |
would have entered had there been an object back there (except for the dir on |
the mirror, and our knowledge of the existence of the mirror, and so on, which is |
corrected in the brain). |
Now let us demonstrate that the principle of least time will give 5nells law |
of refraction. We must, however, make an assumption about the speed of light in |
water. We shall assume that the speed of light in water is lower than the speed |
of light in air by a certain factor, 0ø. |
`" ` E |
AIR ` C |
WATER = x |
X À N |
N ) B |
Fig. 26-4. lllustration of Fermat's principle for refraction. |
In Eig. 26-4, our problem is again to go from A to Ð ¡in he shortest từmne. |
To illustrate that the best thíng to do is no just to go in a straight line, let us |
imagine that a beautiful girl has fallen out of a boat, and she is screaming for |
help in the water at point Ø. The line marked zø is the shoreline. We are at |
point 4 on land, and we see the accident, and we can run and can also swim. |
But we can run faster than we can swim. What do we do? Do we go in a straight |
line? (Yes, no doubtl) However, by using a little more intelligence we would |
realize that it would be advantageous to travel a little greater distance on land |
--- Trang 459 --- |
Fig. 26-5. The minimum time corresponds to point C, but nearby |
points correspond to nearly the same time. |
in order to decrease the distance in the water, because we øo so mụch sÌower In |
the water. (Following this line of reasoning out, we would say the right thing |
to do is to compu‡Èe very carefully what should be donel) At any rate, let us try |
to show that the ñnal solution to the problem is the path AC, and that this |
path takes the shortest time of all possible ones. Tf it is the shortest path, that |
means that if we take any other, it will be longer. So, If we were to plot the time |
1t takes against the position of point X, we would get a curve something like |
that shown in Fig. 26-5, where point corresponds to the shortest of all possible |
times. 'This means that if we move the point à to points near Œ, in the first |
approximation there is essentially no change in time because the sÌope is Zero |
at the bottom of the curve. So our way of ñnding the law will be to consider |
that we move the place by a very small amount, and 0o demand that there be |
essentially no change in tỉme. (Of course there is an infinitesimal change oŸ a |
second order; we ought to have a positive increase for displacements in either |
direction from Œ.) So we consider a nearby point X and we calculate how long |
it would take to go from A to by the two paths, and compare the new path |
with the old path. It is very easy to do. We want the diference, oŸ course, to be |
nearly zero If the distance XƠ is short. Eirst, look at the path on land. lf we |
draw a perpendicular à F7, we see that this path ¡is shortened by the amount EŒ. |
Let us say we gain by not having to go that extra distance. Ôn the other hand, |
in the water, by drawing a corresponding perpendicular, TP", we fnd that we |
have to go the extra distance X”', and that is what we lose. Ôr, in #mne, we |
gain the time it would have taken to go the distance EŒ, but we lose the tỉme it |
would have taken to go the distance X#'. Those times must be equal since, in |
the fñrst approximation, there is to be no change in time. But supposing that in |
--- Trang 460 --- |
the water the speed is 1/n times as fast as in air, then we must have |
ĐC =n- XƑ. (26.3) |
'Therefore we see that when we have the right point, XỚ sin ⁄XỨ = n- XC sin XŒT" |
or, cancelling the common hypotenuse length XŒ and noting that |
EXC = ECN =0, and XCF~ BƠN ' =0, (when X is near C), |
we have |
sin Ø; = nsin Ø„. (26.4) |
So we see that to get from one point to another in the least time when the ratio |
of speeds is nø, the light should enter at such an angle that the ratio of the sines |
of the angles Ø, and đ, is the ratio of the speeds in the two media. |
26-4 Applications of Fermat”s principle |
Now let us consider some of the interesting consequences of the principle of |
least tìme. First is the prineiple of reciprocity. Ifto go from 4 to we have found |
the path of the least time, then to go in the opposite direction (assuming that |
light goes at the same speed in any direction), the shortest time will be the same |
path, and therefore, If light can be sent one way, it can be sent the other way. |
An example of interest is a glass block with plane parallel faces, set at an |
angle to a light beam. Light, in going through the block from a point A to a |
point Ö (Eig. 26-6) does not go throuph in a straight line, but instead it decreases |
the time in the block by making the angle in the bloeck less inclined, although it |
loses a little bit in the aïir. The beam is simply displaced parallel to itself because |
the angles in and out are the same. |
A third interesting phenomenon is the fact that when we see the sun setting, |
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