text stringlengths 0 8.13M |
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base), we can use the same notation as in the preceeding section. Let n be the |
code for the number n and (n ,n ,...,n ) the code for the d-tuple of numbers |
1 2 d |
(n ,n ,...,n ), then |
1 2 d |
f (n ,n ,...,n )=M(q (n ,n ,...,n ), |
M 1 2 d 1 1 2 d |
if the computation exists, otherwise the function is undefined. |
It is often convenient to simplify the notation somewhat and simply write |
M(n ,n ,...,n ) for M(q (n ,n ,...,n ), so that f (x) and M(x) denotes the |
1 2 d 1 1 2 d M |
same object. |
The blank symbol confusion |
There seems to some confusion in the literature as to how to treat the blank |
symbol. In formal language theory, if one wants to have strings with blanks |
in them, the obvious way is simply to include a special blank symbol among |
the symbols. Since a string is always finite, there is no need to designate the |
beginningandendofastringinanyspecialway. Inparticular,startingastring |
with blanks, or ending it with blanks, makes no sense. Such blanks would be |
trimmed away. |
However, in Turing machine theory, the tape is potentially infinite, and the |
machine needs some way to know where the right and left ends of the actually |
used part of the tape is. The obvious way would be to use the blank symbol as |
suchadesignator. Thisisoftenphrasedas,’... astringwrittenonanotherwise |
blanktape...’. Butthen,iftheblankisinthealphabet,andthestringwrittenon |
thetapecontainsblanks,themachinewillnotknowwhetherablankdesignates |
the end of the actually used tape, or if it is a blank within the string (as in the |
case where the blank separates the numbers n in a d-tuple input). One way |
i |
around this dilemma is to use two consecutive blanks, , to designate tape |
⊔⊔ |
ends. In that case, the languages defined over the alphabet, needs to exclude |
strings with two consecutive blanks, otherwise, the confusion remains. Thus, |
when languages L over the alphabet Σ is mentioned, it is understood that no |
words in the language contain two consecutive blanks. |
Anotherwayistoincludetwodifferent’blank’symbols,forexample ,# , |
{⊔ } |
one # denoting ’string blanks’ or input separators,the other designating the |
⊔ |
’left’ and ’right’ ends of the tape. This is the convention used in the present |
work. Any other’language’blanks playno rolein defining the generalmodelof |
Turing machines and need only be defined in specific examples. |
String processing |
The model is, of course, not restricted to computing numeric functions. In |
general, a Turing machine, performs string processing, taking an input string |
28 |
w from the set of strings Γ , producing an output string w if it halts on the |
i ∗ o |
input. More formally, the Turing machine M defines a partial function |
f :Γ Γ (2.9) |
M ∗ ∗ |
→ |
where |
f (w )=w Γ (2.10) |
M i o ∗ |
∈ |
if M halts on input w , undefined otherwise. |
i |
The state graph |
Since the set of tape expressions is infinite, the space of instantaneous descrip- |
tions,orstates,isalsoinfinite. Acomputationcanbeviewedasadirectedgraph |
in this space. This graph will be denoted with G = (S ,T ) where S (state |
c v e v |
vertices) denotes the setofvertices correspondingto states in the computation, |
and T (transition edges) denotes the set of edges corresponding to transitions, |
e |
i.e. computational steps. Two vertices v and v are connected by an edge if |
i j |
there is a corresponding instruction in the program, taking the machine from |
state v to state v . |
i j |
Note that for a deterministic Turing machine, the state graph is simply a |
path in the state space. For a computation that halts, i.e. a computation that |
starts in a certain state and ends in another state, the path is non-intersecting. |
This can be understood as follows. If the path intersected itself, so that the |
machine returned to an ’earlier’state, then the machine wouldenter aninfinite |
loop, and would not halt. Therefore, terminating computations corresponds to |
linear paths. |
Concluding the formal definition of a Turing machine |
When defined in this way, everything looks static. Where does motion enter? |
Well, the computation, i.e. the series of instantaneous descriptions must be |
computed, at least once for each input d-tuple. Someone or something has to |
do this, human or machine. This is where motion enters. This is obvious if one |
considers doing the calculation with pen and paper. |
AlsonotethatitissometimesconvenienttoworkwithTuringmachineswith |
several tapes with concomitant read/write heads. |
Apart from the question of actually performing the computations, this is |
a formal theory of computation. There are many other models of computa- |
tion. Off the formal ones, we have the (Herbrand-G¨odel) recursive functions, |
Church’s λ-calculus, both contemporary with the Turing model. The RAM |
(Random Access Machine) model is close to an actual computer. Then there |
arelotsofsimplifiedprogramminglanguages,containingjustthebareminimum |
of constructions. A survey of computational models can be found in [22]. |
29 |
2.3.3 Syntax and semantics |
It is interesting in this context to digress slightly and discuss the question of |
syntax vs semantics for this model. The Turing machine model reduces com- |
putation to syntax. Everything written above could easily be phrased in terms |
of a specification of a formal language. No meaning is conferred to the ele- |
ments of the model. One does not need to understand the tape expressions or |
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