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8.13M
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⊆
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The function ∆ can therefore be written as
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1, if i P
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∆:I 0,1 where ∆(i)= ∈ M . (2.5)
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→{ } (cid:26)0, if i / P M
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∈
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Note that in this way∆ is naturallydefined as a totalfunction onthe finite
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set of instructions I.
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Data
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A tape expression is an expression consisting entirely of symbols from the set
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Γ. Denoting generic tape expressions by calligraphic letters, for example , we
|
T
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canconsidertape expressionsas split inleft andright parts,and = .
|
L R T LR
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By convention, we always mark tape ends by the symbol = , so that the tape
|
⊔
|
actually looks as .
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⊔LR⊔
|
Executing Turing Machine
|
An instantaneous description α of TM is an expression satisfying the following
|
requirements
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8Thepowerset (I)ofI isthesetofallTuringmachineprogramsforthegivenalphabet
|
P
|
andconfigurationset. SowecouldalsowritePM (I).
|
∈P
|
24
|
1. it contains exactly one q
|
i
|
2. this q is not the rightmost token
|
i
|
3. it does not contain R or L
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4. for all the symbols S in α , S Γ.
|
k k
|
∈
|
The state q is called the instantaneous internal configuration at α. The
|
i
|
symbol S immediately to the rightof q inα is calledthe scanned tape symbol.
|
k i
|
In practice, an instantaneous description is a tape expression with exactly one
|
configuration symbol q inserted directly to the left of the scanned symbol.
|
i
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Sincetheremustalwaysbeascannedsymbol,q cannotbetherightmosttoken.
|
i
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Formally,ageneralinstantaneousdescriptioncanbe writtenas q wherethe
|
i
|
L R
|
right tape expression must be non-empty.
|
R
|
So far everything is static. In order for the Turing machine to actually
|
perform a computation we need a computation relation or a set of rewrite rules
|
α β, allowing us to pass from one instantaneous description to another. In
|
→
|
thefollowing, and denotestapeexpressions,possiblyjuststringsofblanks.
|
X Y
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The computation relation α β is defined by
|
→
|
1. If α = q S and q S S q R P then β = S q
|
i k i k l j M l j
|
X Y ∈ X Y
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//print and move right
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2. If α = q S and q S S q R P then β = S q S
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i 0 i 0 l j M l j 0
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X ∈ X
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//print and right move at right end of tape, insert blank
|
3. If α = S q S and q S S q L P then β = q S S
|
m i k i k l j M j m l
|
X Y ∈ X Y
|
//print and move left
|
4. If α = q S and q S S q L P then β = q S S .
|
i 0 i 0 l j M j 0 l
|
Y ∈ Y
|
//print and left move at left end of tape, insert blank
|
In practice, the rewrite rules are applied by searching for an instruction
|
having the first two symbols matching the machine state and the scanned tape
|
symbol. Then, at each step in the computation, the machine scans the symbol
|
on the tape, prints a new symbol and performs a move according to the rules.
|
An instantaneous description is terminal if none of the rewrite rules apply.
|
Acomputationisafinitesequenceα ,α ,...,α ofinstantaneousdescriptions
|
1 2 p
|
such that α α for 1 i < p and such that α is terminal. The result of
|
i i+1 p
|
→ ≤
|
the computation is written M(α ) which we define as α . Using the notation
|
1 p
|
to denote a computation in several steps, we have
|
∗
|
→
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α α =M(α ). (2.6)
|
1 ∗ p 1
|
→
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This is the formal definition. Some comments are obviously in order. The
|
question of whether the Turing machine halts or not is the same as whether
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there exists a computation or not. The tape is considered to be potentially
|
infinite. This is taken care of by the computation rules (2) and (4) which have
|
25
|
the effect of inserting blank squares at the ends of the tape when the machine
|
is about to run off the tape. In any computation, only a finite amount of tape
|
is ever used.
|
In orderto getsomething donewith this model, a few morechoicesmust be
|
made. We needa wayto representinput data astape expressionsand a wayto
|
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