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EvenifthepreviousIsingtransformationhasinterestingproperties,thisuni- |
tary transformation has to be simulated using quantum measurements only, in |
order to get a relevant comparison between the one-way quantum computer |
andthemodelbasedonstatetransfers.Sinceanyunitarytransformationcanbe |
simulatedusingquantummeasurementsonly,eachC whichcomposestheIsing |
Z |
transformation can be simulated with measurements, but this simulation needs |
an additional auxiliary qubit [6]. Therefore one may wonder if the transforma- |
tion which creates the initial cluster state can be simulated without additional |
auxiliary qubits. |
4.1 Simulation of CZ on |φi⊗|+i without auxiliary qubit |
Figure 9 - Simulation of CZ on |φi⊗|+i without auxiliary qubit |
6 |
Lemma 1. For a given qubit a in an unknown state |φi and a given qubit b |
in the state |+i, the sequence of measurements {Z(b),Z(a) ⊗X(b)} (see fig. 9) |
simulates the unitary transformation C on |φi⊗|+i up to a two-qubit Pauli |
Z |
operator. |
Proof. If |φi = α|0i+β|1i and if the outcome of Z(b) is i ∈ {−1,1}, then the |
state |ψ i of the register a,b after this measurement is: |
1 |
1−i |
|ψ i=(I ⊗σ 2 )[α|00i+β|10i]. |
1 x |
IftheoutcomeofZ(a)⊗X(b) isj ∈{−1,1},thenthestate|ψ ioftheregister |
2 |
a,b after this measurement is: |
1−i 1−j |
|ψ i= 1 (σ 2 ⊗σ 2 )[α|00i+α|01i+β|10i−β|11i]. |
2 √2 z z |
Since C (|φi⊗|+i) = α|00i+α|01i+β|10i−β|11i, the 2-qubit unitary |
Z |
transformation C is simulated on |φi⊗|+i up to a 2-qubit Pauli operator. (cid:3) |
Z |
4.2 Creation of a one-dimensional Cluster State |
In order to create the initial cluster state on a one-dimensional n-qubit lattice |
composed of a unique input qubit, a cascade of C can be performed as follow: |
Z |
Figure 10 - Cascade of CZ for creating the initial cluster state |φCi |
For each C of the previous cascade the state of the second input qubit is |
Z |
|+i, thus, according to Lemma 1, the previous cascade of C is simulated by |
Z |
the following cascade of measurements. Note that this simulation requires no |
additional auxiliary qubit. |
Figure 11 - Cascade of measurements for creating the initial cluster state |φCi up to a |
Pauli operator |
7 |
5 Executions on a One-Way Quantum Computer |
An execution on a one-way quantum computer is a sequence of one-qubit mea- |
surements on a cluster state. For instance, for a given five-qubit cluster state, if |
the first qubit is considered as an input qubit |φi and if the sequence of mea- |
surements{X,Y,Y,Y}isperformedonthefirstfourqubits(seefig12),thenthe |
state of the last qubit is σH|φi. Thus the one-way quantum computer of figure |
12 simulates the Hadamard transformation. |
Figure 12 - Simulation of the Hadamard transformation |
Ifthephaseofpreparationoftheclusterstateandthephaseofexecutionare |
bothrepresented(seefig13a),thenthemeasurementsimpliedinthepreparation |
of the cluster state and those implied in the execution can be decomposed into |
a succession of generalized state transfers (see fig 13b). |
(a) (b) (c) |
Figure 13 - Execution on a one-way quantum computer |
This decomposition offers a natural translation from any one-dimensional |
one-way quantum computer to quantum computation via projective measure- |
ments only. Moreover a straightforwardinterpretation of the action of any one- |
dimensional one-way quantum computer is obtained. For instance, the one-way |
quantum computer of figure 12 can be decomposed (see fig 13c) into a step of |
simulation of H (fig 4), and three steps of simulation of HS (fig 5), thus the |
† |
actionU ofthisone-wayquantumcomputerisU =(HS )(HS )(HS )(H)=H. |
† † † |
Figure 14 - Simulation of S† |
Similarly,theactionU oftheone-wayquantumcomputerpresentedinfigure |
14 is U =(H)(HS )(H)(H)=S . |
† † |
8 |
More generally, the measurements allowed in a one-way quantum compu- |
tation are in the basis B(ϕ) = {|0 i+eiϕ |1 i,|0 i−eiϕ |1 i} for all ϕ. The observable |
√2 √2 |
associatedwithB(ϕ)isO(ϕ)=cos(ϕ)X+sin(ϕ)Y.EachO(ϕ)-measurementis |
associatedwith a generalizedstate transfer with V =R (−ϕ) and V =H (see |
1 zˆ 2 |
fig 8). |
Thus the action U of the one-way quantum computer of figure 15 is U = |
HR (−ζ)HR (−η)HR (−ξ)H. |
zˆ zˆ zˆ |
Figure 15 - Simulation of a general one-qubit unitary transformation |
The connexions between the one-way quantum computer and generalized |
state transfer may also be used for designing new one-way quantum computers. |
For instance the one-way quantum computers introduced in figure 16 simulate |
respectivelyH andS whilerequiringlessqubitsthanthoseintroducedbyBriegel |
and Raussendorf [7,8]. |
Figure 16 - Left: simulation of H - Right: simulation of (HS†)(HS†)(H)=S |
6 Conclusion |
In this paper, we have introduced an exact quantum universal family of ob- |
servables including only one two-qubit observable, while others are one-qubit |
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