message stringlengths 2 30.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 237 109k | cluster float64 10 10 | __index_level_0__ int64 474 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Tenten runs a weapon shop for ninjas. Today she is willing to sell n shurikens which cost 1, 2, ..., n ryo (local currency). During a day, Tenten will place the shurikens onto the showcase, which is empty at the beginning of the day. Her job is fairly simple: sometimes Tenten places another shuriken (from the available shurikens) on the showcase, and sometimes a ninja comes in and buys a shuriken from the showcase. Since ninjas are thrifty, they always buy the cheapest shuriken from the showcase.
Tenten keeps a record for all events, and she ends up with a list of the following types of records:
* + means that she placed another shuriken on the showcase;
* - x means that the shuriken of price x was bought.
Today was a lucky day, and all shurikens were bought. Now Tenten wonders if her list is consistent, and what could be a possible order of placing the shurikens on the showcase. Help her to find this out!
Input
The first line contains the only integer n (1≤ n≤ 10^5) standing for the number of shurikens.
The following 2n lines describe the events in the format described above. It's guaranteed that there are exactly n events of the first type, and each price from 1 to n occurs exactly once in the events of the second type.
Output
If the list is consistent, print "YES". Otherwise (that is, if the list is contradictory and there is no valid order of shurikens placement), print "NO".
In the first case the second line must contain n space-separated integers denoting the prices of shurikens in order they were placed. If there are multiple answers, print any.
Examples
Input
4
+
+
- 2
+
- 3
+
- 1
- 4
Output
YES
4 2 3 1
Input
1
- 1
+
Output
NO
Input
3
+
+
+
- 2
- 1
- 3
Output
NO
Note
In the first example Tenten first placed shurikens with prices 4 and 2. After this a customer came in and bought the cheapest shuriken which costed 2. Next, Tenten added a shuriken with price 3 on the showcase to the already placed 4-ryo. Then a new customer bought this 3-ryo shuriken. After this she added a 1-ryo shuriken. Finally, the last two customers bought shurikens 1 and 4, respectively. Note that the order [2, 4, 3, 1] is also valid.
In the second example the first customer bought a shuriken before anything was placed, which is clearly impossible.
In the third example Tenten put all her shurikens onto the showcase, after which a customer came in and bought a shuriken with price 2. This is impossible since the shuriken was not the cheapest, we know that the 1-ryo shuriken was also there. | instruction | 0 | 76,907 | 10 | 153,814 |
Tags: data structures, greedy, implementation
Correct Solution:
```
import sys,bisect
input = sys.stdin.readline
n = int(input())
sell = []
pos = [-1 for i in range(n)]
rest_left = [i-1 for i in range(2*n)]
rest_right = [i+1 for i in range(2*n)]
for i in range(2*n):
s = input().split()
if s[0]=="+":
continue
else:
sell.append(i)
pos[int(s[1])-1] = len(sell) - 1
left = [i-1 for i in range(n)]
right = [i+1 for i in range(n)]
res = [-1 for i in range(2*n)]
for i in range(n):
R = sell[pos[i]]
if left[pos[i]]!=-1:
L = sell[left[pos[i]]]
else:
L = -1
sold = rest_left[R]
#print(L,R,sold)
if L<sold:
res[sold] = i + 1
if rest_right[sold]<2*n:
rest_left[rest_right[sold]] = rest_left[sold]
if rest_left[sold]!=-1:
rest_right[rest_left[sold]] = rest_right[sold]
if rest_right[R]<2*n:
rest_left[rest_right[R]] = rest_left[R]
if rest_left[sold]!=-1:
rest_right[rest_left[R]] = rest_right[R]
if right[pos[i]]<n:
left[right[pos[i]]] = left[pos[i]]
if left[pos[i]]!=-1:
right[left[pos[i]]] = right[pos[i]]
else:
exit(print("NO"))
#print(rest_left)
#print(rest_right)
#print(res)
ans = []
for a in res:
if a!=-1:
ans.append(a)
print("YES")
print(*ans)
``` | output | 1 | 76,907 | 10 | 153,815 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tenten runs a weapon shop for ninjas. Today she is willing to sell n shurikens which cost 1, 2, ..., n ryo (local currency). During a day, Tenten will place the shurikens onto the showcase, which is empty at the beginning of the day. Her job is fairly simple: sometimes Tenten places another shuriken (from the available shurikens) on the showcase, and sometimes a ninja comes in and buys a shuriken from the showcase. Since ninjas are thrifty, they always buy the cheapest shuriken from the showcase.
Tenten keeps a record for all events, and she ends up with a list of the following types of records:
* + means that she placed another shuriken on the showcase;
* - x means that the shuriken of price x was bought.
Today was a lucky day, and all shurikens were bought. Now Tenten wonders if her list is consistent, and what could be a possible order of placing the shurikens on the showcase. Help her to find this out!
Input
The first line contains the only integer n (1≤ n≤ 10^5) standing for the number of shurikens.
The following 2n lines describe the events in the format described above. It's guaranteed that there are exactly n events of the first type, and each price from 1 to n occurs exactly once in the events of the second type.
Output
If the list is consistent, print "YES". Otherwise (that is, if the list is contradictory and there is no valid order of shurikens placement), print "NO".
In the first case the second line must contain n space-separated integers denoting the prices of shurikens in order they were placed. If there are multiple answers, print any.
Examples
Input
4
+
+
- 2
+
- 3
+
- 1
- 4
Output
YES
4 2 3 1
Input
1
- 1
+
Output
NO
Input
3
+
+
+
- 2
- 1
- 3
Output
NO
Note
In the first example Tenten first placed shurikens with prices 4 and 2. After this a customer came in and bought the cheapest shuriken which costed 2. Next, Tenten added a shuriken with price 3 on the showcase to the already placed 4-ryo. Then a new customer bought this 3-ryo shuriken. After this she added a 1-ryo shuriken. Finally, the last two customers bought shurikens 1 and 4, respectively. Note that the order [2, 4, 3, 1] is also valid.
In the second example the first customer bought a shuriken before anything was placed, which is clearly impossible.
In the third example Tenten put all her shurikens onto the showcase, after which a customer came in and bought a shuriken with price 2. This is impossible since the shuriken was not the cheapest, we know that the 1-ryo shuriken was also there. | instruction | 0 | 76,908 | 10 | 153,816 |
Tags: data structures, greedy, implementation
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline()
# ------------------------------
def RL(): return map(int, sys.stdin.readline().split())
def RLL(): return list(map(int, sys.stdin.readline().split()))
def N(): return int(input())
def print_list(l):
print(' '.join(map(str,l)))
# sys.setrecursionlimit(300000)
# from heapq import *
# from collections import deque as dq
# from math import ceil,floor,sqrt,pow
# import bisect as bs
# from collections import Counter
# from collections import defaultdict as dc
# from functools import lru_cache
data = [line.strip() for line in sys.stdin.readlines()]
# data = ['4',
# '+',
# '+',
# '- 2',
# '+',
# '- 3',
# '+',
# '- 1',
# '- 4']
n = int(data[0])
res = [0]*(n+2)
d = []
now = 0
flag = True
for i in range(1,2*n+1):
if data[i]=='+':
d.append(now)
now+=1
else:
v = int(data[i][2:])
if not d:
flag = False
break
t = d.pop()
if v<res[t+1]:
flag = False
break
res[t] = v
if not flag:
print('NO')
else:
print('YES')
print_list(res[:n])
``` | output | 1 | 76,908 | 10 | 153,817 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tenten runs a weapon shop for ninjas. Today she is willing to sell n shurikens which cost 1, 2, ..., n ryo (local currency). During a day, Tenten will place the shurikens onto the showcase, which is empty at the beginning of the day. Her job is fairly simple: sometimes Tenten places another shuriken (from the available shurikens) on the showcase, and sometimes a ninja comes in and buys a shuriken from the showcase. Since ninjas are thrifty, they always buy the cheapest shuriken from the showcase.
Tenten keeps a record for all events, and she ends up with a list of the following types of records:
* + means that she placed another shuriken on the showcase;
* - x means that the shuriken of price x was bought.
Today was a lucky day, and all shurikens were bought. Now Tenten wonders if her list is consistent, and what could be a possible order of placing the shurikens on the showcase. Help her to find this out!
Input
The first line contains the only integer n (1≤ n≤ 10^5) standing for the number of shurikens.
The following 2n lines describe the events in the format described above. It's guaranteed that there are exactly n events of the first type, and each price from 1 to n occurs exactly once in the events of the second type.
Output
If the list is consistent, print "YES". Otherwise (that is, if the list is contradictory and there is no valid order of shurikens placement), print "NO".
In the first case the second line must contain n space-separated integers denoting the prices of shurikens in order they were placed. If there are multiple answers, print any.
Examples
Input
4
+
+
- 2
+
- 3
+
- 1
- 4
Output
YES
4 2 3 1
Input
1
- 1
+
Output
NO
Input
3
+
+
+
- 2
- 1
- 3
Output
NO
Note
In the first example Tenten first placed shurikens with prices 4 and 2. After this a customer came in and bought the cheapest shuriken which costed 2. Next, Tenten added a shuriken with price 3 on the showcase to the already placed 4-ryo. Then a new customer bought this 3-ryo shuriken. After this she added a 1-ryo shuriken. Finally, the last two customers bought shurikens 1 and 4, respectively. Note that the order [2, 4, 3, 1] is also valid.
In the second example the first customer bought a shuriken before anything was placed, which is clearly impossible.
In the third example Tenten put all her shurikens onto the showcase, after which a customer came in and bought a shuriken with price 2. This is impossible since the shuriken was not the cheapest, we know that the 1-ryo shuriken was also there. | instruction | 0 | 76,909 | 10 | 153,818 |
Tags: data structures, greedy, implementation
Correct Solution:
```
import sys
import os
from io import BytesIO, IOBase
#Fast IO Region
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
from collections import deque
N = int(input())
ans = [None] * N
empty_pos, ok = deque(), False
monoidx = 0
for tt in range(2*N):
inp = input()
if inp[0] == '+':
empty_pos.append(monoidx)
monoidx += 1
else:
_, num = inp.split()
num = int(num)
if not empty_pos:
break
idx = empty_pos.pop()
if idx < N-1 and (ans[idx + 1] is not None and ans[idx+1] > num):
break
ans[idx] = num
else:
ok = True and all(ans) and len(set(ans)) == N
if not ok:
print('NO')
else:
print('YES')
print(*ans)
``` | output | 1 | 76,909 | 10 | 153,819 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tenten runs a weapon shop for ninjas. Today she is willing to sell n shurikens which cost 1, 2, ..., n ryo (local currency). During a day, Tenten will place the shurikens onto the showcase, which is empty at the beginning of the day. Her job is fairly simple: sometimes Tenten places another shuriken (from the available shurikens) on the showcase, and sometimes a ninja comes in and buys a shuriken from the showcase. Since ninjas are thrifty, they always buy the cheapest shuriken from the showcase.
Tenten keeps a record for all events, and she ends up with a list of the following types of records:
* + means that she placed another shuriken on the showcase;
* - x means that the shuriken of price x was bought.
Today was a lucky day, and all shurikens were bought. Now Tenten wonders if her list is consistent, and what could be a possible order of placing the shurikens on the showcase. Help her to find this out!
Input
The first line contains the only integer n (1≤ n≤ 10^5) standing for the number of shurikens.
The following 2n lines describe the events in the format described above. It's guaranteed that there are exactly n events of the first type, and each price from 1 to n occurs exactly once in the events of the second type.
Output
If the list is consistent, print "YES". Otherwise (that is, if the list is contradictory and there is no valid order of shurikens placement), print "NO".
In the first case the second line must contain n space-separated integers denoting the prices of shurikens in order they were placed. If there are multiple answers, print any.
Examples
Input
4
+
+
- 2
+
- 3
+
- 1
- 4
Output
YES
4 2 3 1
Input
1
- 1
+
Output
NO
Input
3
+
+
+
- 2
- 1
- 3
Output
NO
Note
In the first example Tenten first placed shurikens with prices 4 and 2. After this a customer came in and bought the cheapest shuriken which costed 2. Next, Tenten added a shuriken with price 3 on the showcase to the already placed 4-ryo. Then a new customer bought this 3-ryo shuriken. After this she added a 1-ryo shuriken. Finally, the last two customers bought shurikens 1 and 4, respectively. Note that the order [2, 4, 3, 1] is also valid.
In the second example the first customer bought a shuriken before anything was placed, which is clearly impossible.
In the third example Tenten put all her shurikens onto the showcase, after which a customer came in and bought a shuriken with price 2. This is impossible since the shuriken was not the cheapest, we know that the 1-ryo shuriken was also there. | instruction | 0 | 76,910 | 10 | 153,820 |
Tags: data structures, greedy, implementation
Correct Solution:
```
import sys
input = sys.stdin.readline
n=int(input())
events=[]
for i in range(2*n):
x=input()
if x=="+\n":
events.append([0])
else:
x,y=x.split()
events.append([1,int(y)])
poss=True
shelf=[]
placed=[]
while len(events)>0:
ev=events.pop()
if ev[0]==0:
if len(shelf)==0:
poss=False
break
x=shelf.pop()
placed.append(x)
else:
x=ev[1]
if len(shelf)>0 and shelf[-1]<x:
poss=False
break
shelf.append(x)
if poss:
cpl=[0]*n
for i in range(n):
cpl[i]=placed[-i-1]
print("YES")
print(*cpl)
else:
print("NO")
``` | output | 1 | 76,910 | 10 | 153,821 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tenten runs a weapon shop for ninjas. Today she is willing to sell n shurikens which cost 1, 2, ..., n ryo (local currency). During a day, Tenten will place the shurikens onto the showcase, which is empty at the beginning of the day. Her job is fairly simple: sometimes Tenten places another shuriken (from the available shurikens) on the showcase, and sometimes a ninja comes in and buys a shuriken from the showcase. Since ninjas are thrifty, they always buy the cheapest shuriken from the showcase.
Tenten keeps a record for all events, and she ends up with a list of the following types of records:
* + means that she placed another shuriken on the showcase;
* - x means that the shuriken of price x was bought.
Today was a lucky day, and all shurikens were bought. Now Tenten wonders if her list is consistent, and what could be a possible order of placing the shurikens on the showcase. Help her to find this out!
Input
The first line contains the only integer n (1≤ n≤ 10^5) standing for the number of shurikens.
The following 2n lines describe the events in the format described above. It's guaranteed that there are exactly n events of the first type, and each price from 1 to n occurs exactly once in the events of the second type.
Output
If the list is consistent, print "YES". Otherwise (that is, if the list is contradictory and there is no valid order of shurikens placement), print "NO".
In the first case the second line must contain n space-separated integers denoting the prices of shurikens in order they were placed. If there are multiple answers, print any.
Examples
Input
4
+
+
- 2
+
- 3
+
- 1
- 4
Output
YES
4 2 3 1
Input
1
- 1
+
Output
NO
Input
3
+
+
+
- 2
- 1
- 3
Output
NO
Note
In the first example Tenten first placed shurikens with prices 4 and 2. After this a customer came in and bought the cheapest shuriken which costed 2. Next, Tenten added a shuriken with price 3 on the showcase to the already placed 4-ryo. Then a new customer bought this 3-ryo shuriken. After this she added a 1-ryo shuriken. Finally, the last two customers bought shurikens 1 and 4, respectively. Note that the order [2, 4, 3, 1] is also valid.
In the second example the first customer bought a shuriken before anything was placed, which is clearly impossible.
In the third example Tenten put all her shurikens onto the showcase, after which a customer came in and bought a shuriken with price 2. This is impossible since the shuriken was not the cheapest, we know that the 1-ryo shuriken was also there. | instruction | 0 | 76,911 | 10 | 153,822 |
Tags: data structures, greedy, implementation
Correct Solution:
```
import heapq
import sys
input = sys.stdin.readline
n = int(input())
qe = []
hq = []
res = []
for i in range(n * 2):
qe.append(input())
qe.reverse()
for q in qe:
if len(q) >= 3:
t, b = q.split()
if len(hq) > 0 and int(b) > hq[0]:
print('NO')
exit(0)
heapq.heappush(hq, int(b))
else:
if len(hq) == 0:
print('NO')
exit(0)
res.append(heapq.heappop(hq))
print('YES')
print(*reversed(res))
``` | output | 1 | 76,911 | 10 | 153,823 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tenten runs a weapon shop for ninjas. Today she is willing to sell n shurikens which cost 1, 2, ..., n ryo (local currency). During a day, Tenten will place the shurikens onto the showcase, which is empty at the beginning of the day. Her job is fairly simple: sometimes Tenten places another shuriken (from the available shurikens) on the showcase, and sometimes a ninja comes in and buys a shuriken from the showcase. Since ninjas are thrifty, they always buy the cheapest shuriken from the showcase.
Tenten keeps a record for all events, and she ends up with a list of the following types of records:
* + means that she placed another shuriken on the showcase;
* - x means that the shuriken of price x was bought.
Today was a lucky day, and all shurikens were bought. Now Tenten wonders if her list is consistent, and what could be a possible order of placing the shurikens on the showcase. Help her to find this out!
Input
The first line contains the only integer n (1≤ n≤ 10^5) standing for the number of shurikens.
The following 2n lines describe the events in the format described above. It's guaranteed that there are exactly n events of the first type, and each price from 1 to n occurs exactly once in the events of the second type.
Output
If the list is consistent, print "YES". Otherwise (that is, if the list is contradictory and there is no valid order of shurikens placement), print "NO".
In the first case the second line must contain n space-separated integers denoting the prices of shurikens in order they were placed. If there are multiple answers, print any.
Examples
Input
4
+
+
- 2
+
- 3
+
- 1
- 4
Output
YES
4 2 3 1
Input
1
- 1
+
Output
NO
Input
3
+
+
+
- 2
- 1
- 3
Output
NO
Note
In the first example Tenten first placed shurikens with prices 4 and 2. After this a customer came in and bought the cheapest shuriken which costed 2. Next, Tenten added a shuriken with price 3 on the showcase to the already placed 4-ryo. Then a new customer bought this 3-ryo shuriken. After this she added a 1-ryo shuriken. Finally, the last two customers bought shurikens 1 and 4, respectively. Note that the order [2, 4, 3, 1] is also valid.
In the second example the first customer bought a shuriken before anything was placed, which is clearly impossible.
In the third example Tenten put all her shurikens onto the showcase, after which a customer came in and bought a shuriken with price 2. This is impossible since the shuriken was not the cheapest, we know that the 1-ryo shuriken was also there.
Submitted Solution:
```
from bisect import bisect_right, bisect_left
import sys
input = sys.stdin.readline
def main():
n = int(input())
pm = 0
lst = []
for _ in range(2 * n):
s = input().strip().split()
if s[0] == "+":
pm += 1
lst.append(-1)
else:
pm -= 1
lst.append(int(s[1]))
if pm < 0:
print("NO")
return
ans = []
que = []
for i in lst[::-1]:
if i == -1:
ans.append(que.pop())
else:
if que and que[-1] < i:
print("NO")
return
que.append(i)
print("YES")
print(*ans[::-1])
main()
``` | instruction | 0 | 76,912 | 10 | 153,824 |
Yes | output | 1 | 76,912 | 10 | 153,825 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tenten runs a weapon shop for ninjas. Today she is willing to sell n shurikens which cost 1, 2, ..., n ryo (local currency). During a day, Tenten will place the shurikens onto the showcase, which is empty at the beginning of the day. Her job is fairly simple: sometimes Tenten places another shuriken (from the available shurikens) on the showcase, and sometimes a ninja comes in and buys a shuriken from the showcase. Since ninjas are thrifty, they always buy the cheapest shuriken from the showcase.
Tenten keeps a record for all events, and she ends up with a list of the following types of records:
* + means that she placed another shuriken on the showcase;
* - x means that the shuriken of price x was bought.
Today was a lucky day, and all shurikens were bought. Now Tenten wonders if her list is consistent, and what could be a possible order of placing the shurikens on the showcase. Help her to find this out!
Input
The first line contains the only integer n (1≤ n≤ 10^5) standing for the number of shurikens.
The following 2n lines describe the events in the format described above. It's guaranteed that there are exactly n events of the first type, and each price from 1 to n occurs exactly once in the events of the second type.
Output
If the list is consistent, print "YES". Otherwise (that is, if the list is contradictory and there is no valid order of shurikens placement), print "NO".
In the first case the second line must contain n space-separated integers denoting the prices of shurikens in order they were placed. If there are multiple answers, print any.
Examples
Input
4
+
+
- 2
+
- 3
+
- 1
- 4
Output
YES
4 2 3 1
Input
1
- 1
+
Output
NO
Input
3
+
+
+
- 2
- 1
- 3
Output
NO
Note
In the first example Tenten first placed shurikens with prices 4 and 2. After this a customer came in and bought the cheapest shuriken which costed 2. Next, Tenten added a shuriken with price 3 on the showcase to the already placed 4-ryo. Then a new customer bought this 3-ryo shuriken. After this she added a 1-ryo shuriken. Finally, the last two customers bought shurikens 1 and 4, respectively. Note that the order [2, 4, 3, 1] is also valid.
In the second example the first customer bought a shuriken before anything was placed, which is clearly impossible.
In the third example Tenten put all her shurikens onto the showcase, after which a customer came in and bought a shuriken with price 2. This is impossible since the shuriken was not the cheapest, we know that the 1-ryo shuriken was also there.
Submitted Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline()
# ------------------------------
def RL(): return map(int, sys.stdin.readline().split())
def RLL(): return list(map(int, sys.stdin.readline().split()))
def N(): return int(input())
def print_list(l):
print(' '.join(map(str,l)))
# sys.setrecursionlimit(300000)
# from heapq import *
# from collections import deque as dq
# from math import ceil,floor,sqrt,pow
# import bisect as bs
# from collections import Counter
# from collections import defaultdict as dc
# from functools import lru_cache
n = N()
res = [0]*(n+2)
d = []
now = 0
flag = True
for _ in range(2*n):
s = input().strip()
# print(len(s))
if s=='+':
d.append(now)
now+=1
else:
v = int(s[2:])
if not d:
flag = False
break
t = d.pop()
if v<res[t+1]:
flag = False
break
res[t] = v
if not flag:
print('NO')
else:
print('YES')
print_list(res[:n])
``` | instruction | 0 | 76,913 | 10 | 153,826 |
Yes | output | 1 | 76,913 | 10 | 153,827 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tenten runs a weapon shop for ninjas. Today she is willing to sell n shurikens which cost 1, 2, ..., n ryo (local currency). During a day, Tenten will place the shurikens onto the showcase, which is empty at the beginning of the day. Her job is fairly simple: sometimes Tenten places another shuriken (from the available shurikens) on the showcase, and sometimes a ninja comes in and buys a shuriken from the showcase. Since ninjas are thrifty, they always buy the cheapest shuriken from the showcase.
Tenten keeps a record for all events, and she ends up with a list of the following types of records:
* + means that she placed another shuriken on the showcase;
* - x means that the shuriken of price x was bought.
Today was a lucky day, and all shurikens were bought. Now Tenten wonders if her list is consistent, and what could be a possible order of placing the shurikens on the showcase. Help her to find this out!
Input
The first line contains the only integer n (1≤ n≤ 10^5) standing for the number of shurikens.
The following 2n lines describe the events in the format described above. It's guaranteed that there are exactly n events of the first type, and each price from 1 to n occurs exactly once in the events of the second type.
Output
If the list is consistent, print "YES". Otherwise (that is, if the list is contradictory and there is no valid order of shurikens placement), print "NO".
In the first case the second line must contain n space-separated integers denoting the prices of shurikens in order they were placed. If there are multiple answers, print any.
Examples
Input
4
+
+
- 2
+
- 3
+
- 1
- 4
Output
YES
4 2 3 1
Input
1
- 1
+
Output
NO
Input
3
+
+
+
- 2
- 1
- 3
Output
NO
Note
In the first example Tenten first placed shurikens with prices 4 and 2. After this a customer came in and bought the cheapest shuriken which costed 2. Next, Tenten added a shuriken with price 3 on the showcase to the already placed 4-ryo. Then a new customer bought this 3-ryo shuriken. After this she added a 1-ryo shuriken. Finally, the last two customers bought shurikens 1 and 4, respectively. Note that the order [2, 4, 3, 1] is also valid.
In the second example the first customer bought a shuriken before anything was placed, which is clearly impossible.
In the third example Tenten put all her shurikens onto the showcase, after which a customer came in and bought a shuriken with price 2. This is impossible since the shuriken was not the cheapest, we know that the 1-ryo shuriken was also there.
Submitted Solution:
```
import io
import os
from collections import Counter, defaultdict, deque
# https://raw.githubusercontent.com/cheran-senthil/PyRival/master/pyrival/data_structures/SortedList.py
class SortedList:
def __init__(self, iterable=[], _load=200):
"""Initialize sorted list instance."""
values = sorted(iterable)
self._len = _len = len(values)
self._load = _load
self._lists = _lists = [values[i : i + _load] for i in range(0, _len, _load)]
self._list_lens = [len(_list) for _list in _lists]
self._mins = [_list[0] for _list in _lists]
self._fen_tree = []
self._rebuild = True
def _fen_build(self):
"""Build a fenwick tree instance."""
self._fen_tree[:] = self._list_lens
_fen_tree = self._fen_tree
for i in range(len(_fen_tree)):
if i | i + 1 < len(_fen_tree):
_fen_tree[i | i + 1] += _fen_tree[i]
self._rebuild = False
def _fen_update(self, index, value):
"""Update `fen_tree[index] += value`."""
if not self._rebuild:
_fen_tree = self._fen_tree
while index < len(_fen_tree):
_fen_tree[index] += value
index |= index + 1
def _fen_query(self, end):
"""Return `sum(_fen_tree[:end])`."""
if self._rebuild:
self._fen_build()
_fen_tree = self._fen_tree
x = 0
while end:
x += _fen_tree[end - 1]
end &= end - 1
return x
def _fen_findkth(self, k):
"""Return a pair of (the largest `idx` such that `sum(_fen_tree[:idx]) <= k`, `k - sum(_fen_tree[:idx])`)."""
_list_lens = self._list_lens
if k < _list_lens[0]:
return 0, k
if k >= self._len - _list_lens[-1]:
return len(_list_lens) - 1, k + _list_lens[-1] - self._len
if self._rebuild:
self._fen_build()
_fen_tree = self._fen_tree
idx = -1
for d in reversed(range(len(_fen_tree).bit_length())):
right_idx = idx + (1 << d)
if right_idx < len(_fen_tree) and k >= _fen_tree[right_idx]:
idx = right_idx
k -= _fen_tree[idx]
return idx + 1, k
def _delete(self, pos, idx):
"""Delete value at the given `(pos, idx)`."""
_lists = self._lists
_mins = self._mins
_list_lens = self._list_lens
self._len -= 1
self._fen_update(pos, -1)
del _lists[pos][idx]
_list_lens[pos] -= 1
if _list_lens[pos]:
_mins[pos] = _lists[pos][0]
else:
del _lists[pos]
del _list_lens[pos]
del _mins[pos]
self._rebuild = True
def _loc_left(self, value):
"""Return an index pair that corresponds to the first position of `value` in the sorted list."""
if not self._len:
return 0, 0
_lists = self._lists
_mins = self._mins
lo, pos = -1, len(_lists) - 1
while lo + 1 < pos:
mi = (lo + pos) >> 1
if value <= _mins[mi]:
pos = mi
else:
lo = mi
if pos and value <= _lists[pos - 1][-1]:
pos -= 1
_list = _lists[pos]
lo, idx = -1, len(_list)
while lo + 1 < idx:
mi = (lo + idx) >> 1
if value <= _list[mi]:
idx = mi
else:
lo = mi
return pos, idx
def _loc_right(self, value):
"""Return an index pair that corresponds to the last position of `value` in the sorted list."""
if not self._len:
return 0, 0
_lists = self._lists
_mins = self._mins
pos, hi = 0, len(_lists)
while pos + 1 < hi:
mi = (pos + hi) >> 1
if value < _mins[mi]:
hi = mi
else:
pos = mi
_list = _lists[pos]
lo, idx = -1, len(_list)
while lo + 1 < idx:
mi = (lo + idx) >> 1
if value < _list[mi]:
idx = mi
else:
lo = mi
return pos, idx
def add(self, value):
"""Add `value` to sorted list."""
_load = self._load
_lists = self._lists
_mins = self._mins
_list_lens = self._list_lens
self._len += 1
if _lists:
pos, idx = self._loc_right(value)
self._fen_update(pos, 1)
_list = _lists[pos]
_list.insert(idx, value)
_list_lens[pos] += 1
_mins[pos] = _list[0]
if _load + _load < len(_list):
_lists.insert(pos + 1, _list[_load:])
_list_lens.insert(pos + 1, len(_list) - _load)
_mins.insert(pos + 1, _list[_load])
_list_lens[pos] = _load
del _list[_load:]
self._rebuild = True
else:
_lists.append([value])
_mins.append(value)
_list_lens.append(1)
self._rebuild = True
def discard(self, value):
"""Remove `value` from sorted list if it is a member."""
_lists = self._lists
if _lists:
pos, idx = self._loc_right(value)
if idx and _lists[pos][idx - 1] == value:
self._delete(pos, idx - 1)
def remove(self, value):
"""Remove `value` from sorted list; `value` must be a member."""
_len = self._len
self.discard(value)
if _len == self._len:
raise ValueError("{0!r} not in list".format(value))
def pop(self, index=-1):
"""Remove and return value at `index` in sorted list."""
pos, idx = self._fen_findkth(self._len + index if index < 0 else index)
value = self._lists[pos][idx]
self._delete(pos, idx)
return value
def bisect_left(self, value):
"""Return the first index to insert `value` in the sorted list."""
pos, idx = self._loc_left(value)
return self._fen_query(pos) + idx
def bisect_right(self, value):
"""Return the last index to insert `value` in the sorted list."""
pos, idx = self._loc_right(value)
return self._fen_query(pos) + idx
def count(self, value):
"""Return number of occurrences of `value` in the sorted list."""
return self.bisect_right(value) - self.bisect_left(value)
def __len__(self):
"""Return the size of the sorted list."""
return self._len
def __getitem__(self, index):
"""Lookup value at `index` in sorted list."""
pos, idx = self._fen_findkth(self._len + index if index < 0 else index)
return self._lists[pos][idx]
def __delitem__(self, index):
"""Remove value at `index` from sorted list."""
pos, idx = self._fen_findkth(self._len + index if index < 0 else index)
self._delete(pos, idx)
def __contains__(self, value):
"""Return true if `value` is an element of the sorted list."""
_lists = self._lists
if _lists:
pos, idx = self._loc_left(value)
return idx < len(_lists[pos]) and _lists[pos][idx] == value
return False
def __iter__(self):
"""Return an iterator over the sorted list."""
return (value for _list in self._lists for value in _list)
def __reversed__(self):
"""Return a reverse iterator over the sorted list."""
return (value for _list in reversed(self._lists) for value in reversed(_list))
def __repr__(self):
"""Return string representation of sorted list."""
return "SortedList({0})".format(list(self))
def solve(N, events):
assert len(events) == 2 * N
ans = [-1 for i in range(2 * N)]
place = SortedList()
for i, e in enumerate(events):
if e == -1:
place.add(i)
order = list(range(len(events)))
order.sort(key=lambda i: events[i])
for i in order:
if events[i] > 0:
# place lowest cost with last place slot
index = place.bisect_left(i) - 1
if index >= 0:
j = place[index]
del place[index]
assert events[j] == -1
ans[j] = events[i]
else:
return "NO"
if place:
return "NO" # everything should be sold
# place.clear()
for i, e in enumerate(events):
if e == -1:
place.add(ans[i])
else:
x = place.pop(0)
if x != e:
return "NO"
return "YES\n" + " ".join(str(x) for x in ans if x != -1)
if __name__ == "__main__":
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
(N,) = [int(x) for x in input().split()]
events = []
for i in range(2 * N):
event = input().decode().strip()
if event[0] == "+":
events.append(-1)
else:
events.append(int(event.split(" ")[-1]))
ans = solve(N, events)
print(ans)
``` | instruction | 0 | 76,914 | 10 | 153,828 |
Yes | output | 1 | 76,914 | 10 | 153,829 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tenten runs a weapon shop for ninjas. Today she is willing to sell n shurikens which cost 1, 2, ..., n ryo (local currency). During a day, Tenten will place the shurikens onto the showcase, which is empty at the beginning of the day. Her job is fairly simple: sometimes Tenten places another shuriken (from the available shurikens) on the showcase, and sometimes a ninja comes in and buys a shuriken from the showcase. Since ninjas are thrifty, they always buy the cheapest shuriken from the showcase.
Tenten keeps a record for all events, and she ends up with a list of the following types of records:
* + means that she placed another shuriken on the showcase;
* - x means that the shuriken of price x was bought.
Today was a lucky day, and all shurikens were bought. Now Tenten wonders if her list is consistent, and what could be a possible order of placing the shurikens on the showcase. Help her to find this out!
Input
The first line contains the only integer n (1≤ n≤ 10^5) standing for the number of shurikens.
The following 2n lines describe the events in the format described above. It's guaranteed that there are exactly n events of the first type, and each price from 1 to n occurs exactly once in the events of the second type.
Output
If the list is consistent, print "YES". Otherwise (that is, if the list is contradictory and there is no valid order of shurikens placement), print "NO".
In the first case the second line must contain n space-separated integers denoting the prices of shurikens in order they were placed. If there are multiple answers, print any.
Examples
Input
4
+
+
- 2
+
- 3
+
- 1
- 4
Output
YES
4 2 3 1
Input
1
- 1
+
Output
NO
Input
3
+
+
+
- 2
- 1
- 3
Output
NO
Note
In the first example Tenten first placed shurikens with prices 4 and 2. After this a customer came in and bought the cheapest shuriken which costed 2. Next, Tenten added a shuriken with price 3 on the showcase to the already placed 4-ryo. Then a new customer bought this 3-ryo shuriken. After this she added a 1-ryo shuriken. Finally, the last two customers bought shurikens 1 and 4, respectively. Note that the order [2, 4, 3, 1] is also valid.
In the second example the first customer bought a shuriken before anything was placed, which is clearly impossible.
In the third example Tenten put all her shurikens onto the showcase, after which a customer came in and bought a shuriken with price 2. This is impossible since the shuriken was not the cheapest, we know that the 1-ryo shuriken was also there.
Submitted Solution:
```
import sys
input = sys.stdin.readline
import heapq
n=int(input())
Q=[input().split() for i in range(2*n)]
ANS=[]
H=[]
for T in Q[::-1]:
if T[0]=="+":
if len(H)==0:
print("NO")
sys.exit()
else:
h=heapq.heappop(H)
ANS.append(h)
else:
_,x=T
heapq.heappush(H,int(x))
ANS.reverse()
i=0
H=[]
for T in Q:
#print(T)
if T[0]=="+":
heapq.heappush(H,ANS[i])
i+=1
else:
_,x=T
h=heapq.heappop(H)
if h!=int(x):
print("NO")
sys.exit()
print("YES")
print(*ANS)
``` | instruction | 0 | 76,915 | 10 | 153,830 |
Yes | output | 1 | 76,915 | 10 | 153,831 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys. | instruction | 0 | 77,167 | 10 | 154,334 |
Tags: greedy, implementation
Correct Solution:
```
n,m = map(int,input().split())
already = list(map(int,input().strip().split()))
already_ = [0]*200001
for i in already:
if i < 200001:
already_[i] = 1
res = []
cnt = 0
for i in range(1,len(already_)):
if already_[i] == 0:
m -= i
if m >= 0:
res.append(i)
cnt += 1
else:
break
print(cnt)
for i in res:
print(i,end = ' ')
``` | output | 1 | 77,167 | 10 | 154,335 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys. | instruction | 0 | 77,168 | 10 | 154,336 |
Tags: greedy, implementation
Correct Solution:
```
n,m=[int(i) for i in input().split()]
l=[int(i) for i in input().split()]
ans=[]
from collections import Counter
c=Counter(l)
for x in range(1,10**9):
if m<x:
break
if not c[x]:
ans.append(x)
m-=x
print(len(ans))
print(*ans)
``` | output | 1 | 77,168 | 10 | 154,337 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys. | instruction | 0 | 77,169 | 10 | 154,338 |
Tags: greedy, implementation
Correct Solution:
```
from math import sqrt
def sn(awal, akhir):
n = akhir - awal + 1
return n * (2*awal + (n - 1)) // 2
def binary_search(a, start, end, search):
if start == end:
if sn(a, start) <= search:
return start
else:
return -1
mid = start + (end - start) // 2
if search < sn(a, mid):
return binary_search(a, start, mid, search)
ret = binary_search(a, mid + 1, end, search)
if ret == -1:
return mid
else:
return ret
n, m = map(int, input().split())
t = [0] + sorted(list(map(int, input().split()))) + [10**9]
ans = []
for i in range(1, len(t)):
mulai = t[i - 1] + 1
akhir = t[i] - 1
if mulai <= akhir:
#print(f'Sisa uang adalah {m}, berapa paling banyak yang bisa kita beli dari {mulai} sampai {akhir}')
x = binary_search(mulai, mulai, akhir, m) - mulai# beli dari awal ... awal + x
#print(f'Beli {x + 1}, dari {mulai} sampai {akhir}')
m -= sn(mulai, mulai + x)
ans.extend([j for j in range(mulai, mulai + x + 1)])
if mulai + x != akhir:
break
print(len(ans))
print(*ans)
``` | output | 1 | 77,169 | 10 | 154,339 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys. | instruction | 0 | 77,170 | 10 | 154,340 |
Tags: greedy, implementation
Correct Solution:
```
num_doll, money = map(int, input().split())
dolls = set(list(map(int, input().split())))
counter = 1
dolls_to_buy = []
while money >= counter:
if counter not in dolls:
dolls_to_buy.append(counter)
money -= counter
counter += 1
print(len(dolls_to_buy))
print(*dolls_to_buy)
``` | output | 1 | 77,170 | 10 | 154,341 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys. | instruction | 0 | 77,171 | 10 | 154,342 |
Tags: greedy, implementation
Correct Solution:
```
(n, m) = map(int, input().split())
used = set(map(int, input().split()))
cur = 1
ans = []
while cur <= m:
if not cur in used:
ans += [cur]
m -= cur
cur += 1
print(len(ans))
print(*ans)
``` | output | 1 | 77,171 | 10 | 154,343 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys. | instruction | 0 | 77,172 | 10 | 154,344 |
Tags: greedy, implementation
Correct Solution:
```
N,M = map(int, input().split(" "))
alreadyOwned = set(sorted(map(int, input().split(" "))))
def solve(toys, change):
path=[]
for x in range(1, change + 1):
if change - x < 0:
return path
if x not in alreadyOwned:
path.append(str(x))
change -= x
return path
result = solve(N,M)
print(len(result))
print(" ".join(result))
``` | output | 1 | 77,172 | 10 | 154,345 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys. | instruction | 0 | 77,173 | 10 | 154,346 |
Tags: greedy, implementation
Correct Solution:
```
n, m = map(int, input().split())
a = set(map(int, input().split()))
i = 1
cnt = 0
b = []
while i <= m:
if i not in a:
m -= i
b.append(str(i))
cnt += 1
i += 1
print(cnt)
print(' '.join(b))
``` | output | 1 | 77,173 | 10 | 154,347 |
Provide tags and a correct Python 3 solution for this coding contest problem.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys. | instruction | 0 | 77,174 | 10 | 154,348 |
Tags: greedy, implementation
Correct Solution:
```
'''
n, m = list(map(int, input().split()))
a = list(map(int, input().split()))
a.sort()
igr = []
a1 = 0
for item in a:
if item - a1 == 1:
a1 = item
else:
if ((a1 + item) * (item - a1 - 1)) // 2 > m:
kolvo = int(-a1 - 0.5 + (pow(4*a1*a1 + 4*a1 + 1 + 8*m, 1/2)) / 2)
m = 0
for i in range(a1+1, a1+kolvo+1):
igr.append(i)
break
else:
m -= ((a1 + item) * (item - a1 - 1)) // 2
for i in range(a1+1, item):
igr.append(i)
a1 = item
if m <= item:
break
if igr:
a1 = max(igr[-1], a[-1])
else:
a1 = a[-1]
if m > a1:
kolvo = int(-a1 - 0.5 + (pow(4*a1*a1 + 4*a1 + 1 + 8*m, 1/2)) / 2)
for i in range(a1+1, a1+kolvo+1):
igr.append(i)
print(len(igr))
print(' '.join(str(i) for i in igr))
'''
n, m = list(map(int, input().split()))
a = list(map(int, input().split()))
a.sort()
igr = []
a1 = 0
fl = False
for item in a:
for j in range(a1+1,item):
if m >= j:
igr.append(j)
m -= j
else:
fl = True
break
a1 = item
if fl:
break
for j in range(a1+1, 10000000000):
if m >= j:
igr.append(j)
m -= j
else:
break
print(len(igr))
print(' '.join(str(i) for i in igr))
``` | output | 1 | 77,174 | 10 | 154,349 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys.
Submitted Solution:
```
n_m = input().split()
N = int(n_m[0])
money = int(n_m[1])
tanya_toys = sorted(int(toy) for toy in input().split())
new_toys = []
toy_index = 1
tanya_toy_index = 0
while True:
if money >= toy_index:
if tanya_toy_index < len(tanya_toys) and tanya_toys[tanya_toy_index] == toy_index:
tanya_toy_index += 1
toy_index += 1
else:
money -= toy_index
new_toys.append(toy_index)
toy_index += 1
else:
break
print(len(new_toys))
for toy in new_toys:
print(toy, end=" ")
print()
``` | instruction | 0 | 77,175 | 10 | 154,350 |
Yes | output | 1 | 77,175 | 10 | 154,351 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys.
Submitted Solution:
```
n,k=map(int,input().split())
a=set(list(map(int,input().split())))
l=[]
for i in range(1,20000000):
if i not in a and i<=k:
l.append(i)
k-=i
if(i>k):
break
print(len(l))
print(*l)
``` | instruction | 0 | 77,176 | 10 | 154,352 |
Yes | output | 1 | 77,176 | 10 | 154,353 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys.
Submitted Solution:
```
a,b=input().split()
a=int(a)
b=int(b)
h=[0]*10000000
l=list(map(int,input().split()))
for i in range(len(l)):
if l[i]<len(h):
h[l[i]]+=1
sum=0
i=1
p=[]
for i in range(1,b+1):
if h[i]:
continue
else:
if (sum+i > b):
break
sum += i;
h[i]+=1
p.append(i)
print(len(p))
p=map(str,p)
print(" ".join(p))
``` | instruction | 0 | 77,177 | 10 | 154,354 |
Yes | output | 1 | 77,177 | 10 | 154,355 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys.
Submitted Solution:
```
import math
from collections import defaultdict
def r():
return int(input())
def rm():
return map(int,input().split())
def rl():
return list(map(int,input().split()))
n,m=rm()
a=defaultdict(int)
b=rl()
for i in b:
a[i]=1
res=0
resa=[]
for j in range(1,10**9+1):
if m<=0 or m<j:
break
if a[j]!=1:
if m>=j:
res+=1
resa.append(j)
m-=j
print(res)
print(*resa)
``` | instruction | 0 | 77,178 | 10 | 154,356 |
Yes | output | 1 | 77,178 | 10 | 154,357 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys.
Submitted Solution:
```
I=lambda:map(int,input().split())
n,m=I()
a=set(I())
b=[]
i=1
while i<=m:
if i not in a:b.append(str(i));m-=i
i+=1
print(len(a),'\n'+' '.join(b))
``` | instruction | 0 | 77,179 | 10 | 154,358 |
No | output | 1 | 77,179 | 10 | 154,359 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys.
Submitted Solution:
```
n,m = (int(i) for i in input().split())
q = list(map(int,input().split()))
m+=sum(q)
q = set(q)
l = 0
r = 10**9
while r-l>1:
d = (l+r)//2
if (1+d)*d/2 > m:
r = d
else:
l = d
if (1+r)*r/2 <=m:
print(r-n)
c = r-n
else:
print(l-n)
c = l - n
t = 0
k = 1
ans = []
while t < c:
if not k in q:
ans+=[k]
t+=1
k+=1
print(' '.join(list(map(str,ans))))
``` | instruction | 0 | 77,180 | 10 | 154,360 |
No | output | 1 | 77,180 | 10 | 154,361 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys.
Submitted Solution:
```
inputs1st = list(map(int, input().split(' ')))
inputs2nd = list(map(int, input().split(' ')))
def solve(bourles, xs):
ys = sorted(xs)
ans = []
for i in range(1, 10^5 + 1):
if i > bourles:
break
if len(ys) > 0 and i == ys[0]:
ys = ys[1:]
continue
ans.append(i)
bourles -= i
return ans
ans = solve(inputs1st[1], inputs2nd)
print(len(ans))
print(' '.join(list(map(str, ans))))
``` | instruction | 0 | 77,181 | 10 | 154,362 |
No | output | 1 | 77,181 | 10 | 154,363 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In Berland recently a new collection of toys went on sale. This collection consists of 109 types of toys, numbered with integers from 1 to 109. A toy from the new collection of the i-th type costs i bourles.
Tania has managed to collect n different types of toys a1, a2, ..., an from the new collection. Today is Tanya's birthday, and her mother decided to spend no more than m bourles on the gift to the daughter. Tanya will choose several different types of toys from the new collection as a gift. Of course, she does not want to get a type of toy which she already has.
Tanya wants to have as many distinct types of toys in her collection as possible as the result. The new collection is too diverse, and Tanya is too little, so she asks you to help her in this.
Input
The first line contains two integers n (1 ≤ n ≤ 100 000) and m (1 ≤ m ≤ 109) — the number of types of toys that Tanya already has and the number of bourles that her mom is willing to spend on buying new toys.
The next line contains n distinct integers a1, a2, ..., an (1 ≤ ai ≤ 109) — the types of toys that Tanya already has.
Output
In the first line print a single integer k — the number of different types of toys that Tanya should choose so that the number of different types of toys in her collection is maximum possible. Of course, the total cost of the selected toys should not exceed m.
In the second line print k distinct space-separated integers t1, t2, ..., tk (1 ≤ ti ≤ 109) — the types of toys that Tanya should choose.
If there are multiple answers, you may print any of them. Values of ti can be printed in any order.
Examples
Input
3 7
1 3 4
Output
2
2 5
Input
4 14
4 6 12 8
Output
4
7 2 3 1
Note
In the first sample mom should buy two toys: one toy of the 2-nd type and one toy of the 5-th type. At any other purchase for 7 bourles (assuming that the toys of types 1, 3 and 4 have already been bought), it is impossible to buy two and more toys.
Submitted Solution:
```
n, m = map(int, input().split())
from math import sqrt
a = [int(s) for s in input().split()]
a.sort()
j = 0
sum = 0
s = ''
k = 0
for i in range(1, m):
if i == a[j] and j < n - 1:
j += 1
else:
sum += i
if sum > m:
break
else:
if k == 0:
s += str(i)
else:
s += ' ' + str(i)
k += 1
print(k)
print(s)
``` | instruction | 0 | 77,182 | 10 | 154,364 |
No | output | 1 | 77,182 | 10 | 154,365 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04 | instruction | 0 | 77,189 | 10 | 154,378 |
Tags: expression parsing, implementation, strings
Correct Solution:
```
s = input()
t = ""
for i in s:
if i.isalpha():
t += ' '
else:
t += i
a = t.split()
ans1 = 0
ans2 = 0
for i in a:
b = i.split('.')
part = None
cur = 0
for j in range(len(b)):
if len(b[j]) == 2 and j > 0:
part = int(b[j])
else:
cur *= 1000
cur += int(b[j])
if not (part is None):
ans2 += part
ans1 += cur
cnt = ans2 // 100
ans1 += cnt
ans2 -= cnt * 100
tmp = str(ans1)[::-1]
tmp2 = ""
for i in range(len(tmp)):
tmp2 += tmp[i]
if i % 3 == 2 and i != len(tmp) - 1:
tmp2 += '.'
ans1 = tmp2[::-1]
if ans2 == 0:
print(ans1)
else:
ans2 = str(ans2)
if len(ans2) == 1:
ans2 = "0" + ans2
print("%s.%s" % (ans1, ans2))
``` | output | 1 | 77,189 | 10 | 154,379 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04 | instruction | 0 | 77,190 | 10 | 154,380 |
Tags: expression parsing, implementation, strings
Correct Solution:
```
s = input()
import itertools
nums = ["".join(x) for is_number, x in itertools.groupby(s, key=lambda x: x == '.' or str.isdigit(x)) if is_number is True]
total = 0
for num in nums:
idx = num.rfind('.')
dec = 0.0
if idx != -1 and idx == len(num) - 3:
dec = '0' + num[idx:]
num = num[:idx]
num = num.replace('.','')
total += int(num)
total += float(dec)
p = ''
if int(total) != total:
idx = str('%.2f' % total).rfind('.')
dec = str('%.2f' % total)[idx+1:]
p = '.' + dec
l = []
t_s = str(int(total))
for idx, val in enumerate(reversed(t_s)):
l.append(val)
if idx != 0 and idx % 3 == 2 and idx != len(t_s) - 1:
l.append('.')
print(''.join(reversed(l)) + p)
``` | output | 1 | 77,190 | 10 | 154,381 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04 | instruction | 0 | 77,191 | 10 | 154,382 |
Tags: expression parsing, implementation, strings
Correct Solution:
```
import re
def spnum(s):
a = s.split(".")
if len(a[-1]) == 2:
a.append(a[-1])
a[-2] = '.'
return eval("".join(a))
s = input()
dollars = re.findall(r"[.0-9]+", s)
for i in range(len(dollars)):
if "." in dollars[i]:
dollars[i] = spnum(dollars[i])
else:
dollars[i] = eval(dollars[i])
#print(dollars)
ans = eval("%0.2f"%(sum(dollars)))
if ans - int(ans) == 0:
ans = int(ans)
ans = str(ans)
anss = []
cur = 0
#print(ans)
if "." in ans:
anss.append(ans[-3:len(ans)])
#print(anss)
for i in range(4, len(ans)+1):
cur += 1
anss.append(ans[-i])
if cur % 3 == 0 and i != len(ans):
cur = 0
anss.append(".")
#print(anss)
else:
for i in range(1, len(ans)+1):
cur += 1
anss.append(ans[-i])
if cur % 3 == 0 and i != len(ans):
cur = 0
anss.append(".")
ans = "".join(anss[::-1])
if (len(ans) >= 3 and ans[-2] == "."):
print(ans+"0")
else:
print(ans)
``` | output | 1 | 77,191 | 10 | 154,383 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04 | instruction | 0 | 77,192 | 10 | 154,384 |
Tags: expression parsing, implementation, strings
Correct Solution:
```
def check():
ch = input()
prices = []
p = ''
i = 0
while i < len(ch):
if ch[i].isdigit():
while i < len(ch) and not ch[i].isalpha():
p += ch[i]
i += 1
else:
if p != '':
prices.append(p)
p = ''
i += 1
rub = 0
kop = 0
for p in prices:
if len(p) > 3:
if '.' in p[-1:-4:-1]:
kop += int((p[-1:-3:-1])[::-1])
p = p[:-3]
p = p.split('.')
p = int(''.join(p))
rub += p
if kop > 99:
rub, kop = rub+(kop//100), kop % 100
kop = str(kop)
if len(kop) == 1: kop = '0' + kop
rub = str(rub)[::-1]
c = 3
while c < len(rub):
rub = rub[:c] + '.' + rub[c:]
c += 4
rub = rub[::-1]
if int(kop) != 0:
return rub+'.'+kop
else: return rub
print(check())
``` | output | 1 | 77,192 | 10 | 154,385 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04 | instruction | 0 | 77,193 | 10 | 154,386 |
Tags: expression parsing, implementation, strings
Correct Solution:
```
s = input()
name = False
s2 = '0'
cnt = 0
pointsPresent = False
sum = 0
for i in range(len(s)):
if s[i] in "1234567890.":
name = False
else:
name = True
if name:
if cnt == 3 or not pointsPresent:
sum += int(s2) * 100
else:
sum += int(s2)
s2 = "0"
cnt = 0
pointsPresent = False
else:
if s[i] != '.':
s2 += s[i]
cnt += 1
else:
cnt = 0
pointsPresent = True
if cnt == 3 or not pointsPresent:
sum += int(s2) * 100
else:
sum += int(s2)
if sum < 10:
print("0.0" + str(sum))
elif sum < 100:
print("0." + str(sum))
else:
if sum % 100 == 0:
sum //= 100
c = -1
else:
c = 0
s3 = str(sum)
for i in range(len(s3) - 1, -1, -1):
c += 1
if c == 3:
c = 0
s3 = s3[:i + 1] + '.' + s3[i + 1:]
print(s3)
``` | output | 1 | 77,193 | 10 | 154,387 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04 | instruction | 0 | 77,194 | 10 | 154,388 |
Tags: expression parsing, implementation, strings
Correct Solution:
```
ii=lambda:int(input())
kk=lambda:map(int,input().split())
ll=lambda:list(kk())
s = input()
i=0;
t,comma=0,0
while i < len(s):
while s[i].isalpha(): i+=1
c = 0
while 1:
while i<len(s) and '0' <= s[i] <= '9':
c= c*10+int(s[i])
i+=1
if i == len(s) or s[i] != ".":
if i>3 and s[i-3]=='.': pass
else: c*=100
t+=c
break
else: i+=1
comma = t%100
t = t//100
t2 = "{:,}".format(t).replace(",", ".")
if comma != 0:
t2 += ".{:0>2}".format(comma)
print(t2)
``` | output | 1 | 77,194 | 10 | 154,389 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04 | instruction | 0 | 77,195 | 10 | 154,390 |
Tags: expression parsing, implementation, strings
Correct Solution:
```
a = input()
n = ''
summ = 0
def obr(n):
summ = 0
p = 0
for i in range(-1, -len(n) - 1, -1):
if n[i] !='.' and i == -3 or len(n) < 3:
summ *= 100
p += 2
if n[i] != '.':
summ += int(n[i]) * (10 ** p)
p += 1
return summ
for i in a:
if 'a' <= i <= 'z':
if n != '':
summ += obr(n)
n = ''
else:
n += i
if n != '':
summ += obr(n)
ans = str(summ)
if summ < 100:
while len(ans) < 3:
ans = '0' + ans
n = len(ans)
if ans[-2:] == '00':
ans = ans[:-2]
n -= 2
i = -3
l = 0
else:
ans = ans[:-2] + '.' + ans[-2:]
l = 1
i = -6
while i > -n - l:
ans = ans[:i] + '.' + ans[i:]
i -= 4
l += 1
print(ans)
``` | output | 1 | 77,195 | 10 | 154,391 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04 | instruction | 0 | 77,196 | 10 | 154,392 |
Tags: expression parsing, implementation, strings
Correct Solution:
```
s = input()
for i in range(ord("a"), ord("z") + 1):
s = s.replace(chr(i), "_")
a = s.split("_")
r = c = 0
for i in a:
if not i: continue
b = [j for j in i.split('.')]
if len(b[-1]) == 2:
c += int(b[-1])
b = b[:len(b)-1]
r += int("".join(b)) + c // 100
c %= 100
r = str(r)
print(r[:(len(r)%3 if len(r)%3 != 0 else 3)], end="")
r = r[(len(r)%3 if len(r)%3 != 0 else 3):]
for i in range(len(r) // 3):
print(".", r[3 * i:3 * i + 3], sep="", end="")
if c:
print(".", str(c).rjust(2,"0"), sep="")
``` | output | 1 | 77,196 | 10 | 154,393 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04
Submitted Solution:
```
import re
line = input()
line = re.findall(r"[0-9.]+", line)
# for i in range(0,26):
# p = str(chr(ord('a')+i))
# # print p
# line="".join(line).split(p)
a=0
b=0
# print (line)
for val in line:
n = len(val)
if n<=2:
a+=int(val)
continue
j = n
if val[n-3]=='.':
b+=int(val[n-2:])
j = n-2
curr = 0
i = 0
while i<j:
if val[i]!='.':
curr=curr*10+int(val[i])
i+=1
a+=curr
a+=b//100
b=b%100
a=str(a)
n=len(a)
for i in range(n):
if (n-i)%3==0 and i!=0:
print ('.',end="")
print (a[i],end="")
if b!=0:
print ('.',end="")
if b<10:
print ('0',end="")
print (b,end="")
``` | instruction | 0 | 77,197 | 10 | 154,394 |
Yes | output | 1 | 77,197 | 10 | 154,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04
Submitted Solution:
```
import sys
import math
def is_digit(ch):
if ch == '.' or ch <= '9' and ch >= '0':
return True
return False
def norm(s):
ss = s
while len(ss) < 3:
ss = '0' + ss
return ss
def num(chop):
kop = 0
rub = 0
arr = chop.split('.')
if len(arr) > 1 and len(arr[-1]) == 2:
kop = int(arr[-1])
arr = arr[:-1]
mn = 1
ind = len(arr) - 1
while ind >= 0:
rub += mn * int(norm(arr[ind]))
ind -= 1
mn *= 1000
return 100 * rub + kop
ans = 0
res = ""
chops = []
s = sys.stdin.readline().strip()
i = 0
while i < len(s):
chop = ""
while i < len(s) and is_digit(s[i]):
chop += s[i]
i += 1
if chop:
chops.append(chop)
i += 1
for chop in chops:
ans += num(chop)
if ans % 100:
res = '.' + norm(str(ans % 100))[1:]
if ans // 100 == 0:
print('0' + res)
exit()
ans //= 100
while ans > 0:
temp = ans % 1000
ans //= 1000
if ans > 0:
res = '.' + norm(str(temp)) + res
else:
res = str(temp) + res
print(res)
``` | instruction | 0 | 77,198 | 10 | 154,396 |
Yes | output | 1 | 77,198 | 10 | 154,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04
Submitted Solution:
```
s = input()
a = ''
prices = []
for i in s:
if ord(i) >= ord('a') and ord(i) <= ord('z'):
if (len(a) > 0):
prices.append(a)
a = ''
else:
a += i
prices.append(a)
sum = 0
for price in prices:
pos = price.rfind('.')
g = True
if (len(price) - pos - 1 == 2):
g = False
nprice = price.replace('.', '')
if g:
nprice += '00'
sum += int(nprice)
sum = str(sum)
#print(sum)
rubles = sum[:-2]
kop = sum[-2:]
if len(kop) == 0:
kop = '00'
elif len(kop) == 1:
kop = '0' + kop
rubles = rubles[::-1]
l = []
i = 0
while i < len(rubles):
if (i + 3 <= len(rubles)):
l.append(rubles[i:i+3])
else:
l.append(rubles[i:])
i += 3
rubles = '.'.join(l)
rubles = rubles[::-1]
if rubles == '':
rubles = '0'
if (kop == '00'):
print(rubles)
else:
print(rubles+'.'+kop)
``` | instruction | 0 | 77,199 | 10 | 154,398 |
Yes | output | 1 | 77,199 | 10 | 154,399 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04
Submitted Solution:
```
import math
def tr(s):
x = list(s.split('.'))
if len(x) > 1:
if len(x[-1]) == 2:
a = ''
for i in range(len(x) - 1):
a += x[i]
a = int(a) + int(x[-1]) * 0.01
else:
a = ''
for i in range(len(x)):
a += x[i]
a = int(a)
else:
a = int(s)
return a
def out(a):
a = str(a)
y = a.rfind('.')
z = a[y + 1:]
#print(z)
if int(z) == 0:
z = ''
else:
if len(str(z)) == 2:
z = '.' + str(z)
else:
z = '.' + str(z) + '0'
b = [str(z)]
i = y - 1
c = -1
while i > -1:
c += 1
if c == 3:
c = 0
b.append('.')
b.append(a[i])
i -= 1
b = reversed(b)
x = ''
for elem in b:
x += elem
return x
s = input()
num = ''
a = []
i = 0
while i < len(s):
if s[i].isdigit() or s[i] == '.':
num += s[i]
else:
if num != '':
a.append(num)
num = ''
i += 1
if num != '':
a.append(num)
num = ''
ans = 0
for elem in a:
ans += tr(elem)
#print(ans)
ans = round(ans * 100) / 100
#print(ans)
if ans < 1000:
ans = str(ans)
print(out(ans))
else:
print(out(ans))
``` | instruction | 0 | 77,200 | 10 | 154,400 |
Yes | output | 1 | 77,200 | 10 | 154,401 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04
Submitted Solution:
```
def num(a):
if len(a) < 4:
return int(a) * 100
q = 1
if a[-3] != '.':
q = 100
b = ''
for i in a:
if i != '.':
b += i
print
return int(b) * q
a = input()
b = 0
nn = ''
q = 2
for i in a:
if i not in '1234567890.':
if len(nn) > 0:
b += num(nn)
nn = ''
else:
nn += i
if len(nn) > 0:
b += num(nn)
a = [str(b % 100 // 10) + str(b % 10)]
b //= 100
while b != 0:
a = [b % 1000] + a
b //= 1000
if len(a) == 1:
print('0.' + a[0])
else:
print('.'.join(map(str, a)))
``` | instruction | 0 | 77,201 | 10 | 154,402 |
No | output | 1 | 77,201 | 10 | 154,403 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04
Submitted Solution:
```
inpt = input()
string = inpt + 'z'
number = ''
summa = 0
for i in string:
if i.isdigit() or i == '.':
number += i
elif number:
splo = number.split('.')
if len(splo)>1:
if len(splo[-1])==2:
number = number[:-3].replace('.', '') + '.' + splo[-1]
else:
number = number.replace('.', '')
summa += float(number)
number = ''
dop = 0
wStr = str(round(summa,2))
if '.' in wStr:
dop = wStr[-3:]
wStr = wStr[:-3]
ln = len(wStr)
else:
ln = len(wStr)
nvar = 4 - ln % 3
readyStr = ''
for i in range(ln):
readyStr += wStr[i]
if (i+nvar) % 3 == 0 and i != ln-1: readyStr += '.'
if dop: readyStr += dop
print(readyStr)
``` | instruction | 0 | 77,202 | 10 | 154,404 |
No | output | 1 | 77,202 | 10 | 154,405 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04
Submitted Solution:
```
from heapq import *
contest = True
if not contest:
fin = open("in", "r")
inp = input if contest else lambda: fin.readline()[:-1]
read = lambda: tuple(map(int, inp().split()))
s = inp()+"s"
na = "1234567890."
acc = ""
k = 0
l = []
wasd = False
for c in s:
if not c in na:
if len(acc) > 0:
if k == 2:
#print(acc[:-2].replace(".", "") + "." + acc[-2:])
l += [int(acc[:-2].replace(".", "")) + int(acc[-2:])/100]
else:
#print(acc.replace(".", ""))
l += [int(acc.replace(".", ""))]
k = 0
acc = ""
wasd = False
else:
if wasd: k += 1
if c == ".":
k = 0
wasd = True
acc += c
ans = str(sum(l))[::-1]
d = ""
if "." in ans:
i = ans.index(".")
d = ans[:i]
d = ("0"*max(0,2-len(d)) + d)[:2]
ans = ans[i+1:]
ans1 = []
if len(d) > 0: ans1 += [d]
for i in range(0, len(ans), 3):
ans1 += [ans[i:min(i+3, len(ans))]]
ans1 = ".".join(ans1)
print(ans1[::-1])
``` | instruction | 0 | 77,203 | 10 | 154,406 |
No | output | 1 | 77,203 | 10 | 154,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasily exited from a store and now he wants to recheck the total price of all purchases in his bill. The bill is a string in which the names of the purchases and their prices are printed in a row without any spaces. Check has the format "name1price1name2price2...namenpricen", where namei (name of the i-th purchase) is a non-empty string of length not more than 10, consisting of lowercase English letters, and pricei (the price of the i-th purchase) is a non-empty string, consisting of digits and dots (decimal points). It is possible that purchases with equal names have different prices.
The price of each purchase is written in the following format. If the price is an integer number of dollars then cents are not written.
Otherwise, after the number of dollars a dot (decimal point) is written followed by cents in a two-digit format (if number of cents is between 1 and 9 inclusively, there is a leading zero).
Also, every three digits (from less significant to the most) in dollars are separated by dot (decimal point). No extra leading zeroes are allowed. The price always starts with a digit and ends with a digit.
For example:
* "234", "1.544", "149.431.10", "0.99" and "123.05" are valid prices,
* ".333", "3.33.11", "12.00", ".33", "0.1234" and "1.2" are not valid.
Write a program that will find the total price of all purchases in the given bill.
Input
The only line of the input contains a non-empty string s with length not greater than 1000 — the content of the bill.
It is guaranteed that the bill meets the format described above. It is guaranteed that each price in the bill is not less than one cent and not greater than 106 dollars.
Output
Print the total price exactly in the same format as prices given in the input.
Examples
Input
chipsy48.32televizor12.390
Output
12.438.32
Input
a1b2c3.38
Output
6.38
Input
aa0.01t0.03
Output
0.04
Submitted Solution:
```
s = input()
nums = []
curr = ''
for i in range(len(s)):
if 'a' <= s[i] <= 'z':
if curr != '':
nums.append(curr)
curr = ''
else:
curr += s[i]
if curr != '':
nums.append(curr)
rubl = 0
kop = 0
for elem in nums:
elem = elem.split('.')
if len(elem[-1]) == 2 and len(elem) > 1:
kop += int(elem[-1])
elem.pop()
rubl += int(''.join(elem))
rubl = str(rubl)
kop = str(kop)
if kop == '0':
kop = ''
elif len(kop) == 1:
kop = '0' + kop
if kop != '':
kop = '.' + kop
x = len(rubl) % 3
while x < len(rubl):
rubl = rubl[:x] + '.' + rubl[x:]
x += 4
if rubl[0] == '.':
rubl = rubl[1:]
if rubl[-1] == '.':
rubl = rubl[:-1]
print(rubl + kop)
``` | instruction | 0 | 77,204 | 10 | 154,408 |
No | output | 1 | 77,204 | 10 | 154,409 |
Provide a correct Python 3 solution for this coding contest problem.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8 | instruction | 0 | 77,389 | 10 | 154,778 |
"Correct Solution:
```
n,a,b=map(int, input().split())
box = [n*a,b]
print(min(box))
``` | output | 1 | 77,389 | 10 | 154,779 |
Provide a correct Python 3 solution for this coding contest problem.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8 | instruction | 0 | 77,390 | 10 | 154,780 |
"Correct Solution:
```
n,a,b =map(int,input().split())
print(b if b< n*a else n*a)
``` | output | 1 | 77,390 | 10 | 154,781 |
Provide a correct Python 3 solution for this coding contest problem.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8 | instruction | 0 | 77,391 | 10 | 154,782 |
"Correct Solution:
```
n,a,b=[int(x) for x in input().split()]
print(min(n*a,b))
``` | output | 1 | 77,391 | 10 | 154,783 |
Provide a correct Python 3 solution for this coding contest problem.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8 | instruction | 0 | 77,392 | 10 | 154,784 |
"Correct Solution:
```
n,a,b=map(int,input().split())
print(str(min(n*a,b)))
``` | output | 1 | 77,392 | 10 | 154,785 |
Provide a correct Python 3 solution for this coding contest problem.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8 | instruction | 0 | 77,393 | 10 | 154,786 |
"Correct Solution:
```
N,A,B=map(int,input().split())
print(min((N*A),B))
``` | output | 1 | 77,393 | 10 | 154,787 |
Provide a correct Python 3 solution for this coding contest problem.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8 | instruction | 0 | 77,394 | 10 | 154,788 |
"Correct Solution:
```
a=list(map(int,input().split()))
print(min(a[0]*a[1],a[2]))
``` | output | 1 | 77,394 | 10 | 154,789 |
Provide a correct Python 3 solution for this coding contest problem.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8 | instruction | 0 | 77,395 | 10 | 154,790 |
"Correct Solution:
```
a,b,c=map(int,input().split());print(c if c<=a*b else a*b)
``` | output | 1 | 77,395 | 10 | 154,791 |
Provide a correct Python 3 solution for this coding contest problem.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8 | instruction | 0 | 77,396 | 10 | 154,792 |
"Correct Solution:
```
n, a, b = map(int, input().split())
p = min(n*a, b)
print(p)
``` | output | 1 | 77,396 | 10 | 154,793 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8
Submitted Solution:
```
N,A,B=map(int,input().split());print(min(N*A,B))
``` | instruction | 0 | 77,397 | 10 | 154,794 |
Yes | output | 1 | 77,397 | 10 | 154,795 |
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