message stringlengths 2 30.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 237 109k | cluster float64 10 10 | __index_level_0__ int64 474 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8
Submitted Solution:
```
N, A, B = map(int, input().split(' '))
print(min(A * N , B))
``` | instruction | 0 | 77,398 | 10 | 154,796 |
Yes | output | 1 | 77,398 | 10 | 154,797 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8
Submitted Solution:
```
N,A,B=map(int,input().split())
x=min([N*A,B])
print(x)
``` | instruction | 0 | 77,399 | 10 | 154,798 |
Yes | output | 1 | 77,399 | 10 | 154,799 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8
Submitted Solution:
```
N,A,B=map(int,input().split())
a=[N*A,B]
print(min(a))
``` | instruction | 0 | 77,400 | 10 | 154,800 |
Yes | output | 1 | 77,400 | 10 | 154,801 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8
Submitted Solution:
```
import sys
args = sys.argv
n = args[1]
a = args[2]
b = args[3]
if n*a > b:
print("b")
else:
print("a")
``` | instruction | 0 | 77,401 | 10 | 154,802 |
No | output | 1 | 77,401 | 10 | 154,803 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8
Submitted Solution:
```
N = int(input())
A = int(input())
B = int(input())
print(min(N*A,B))
``` | instruction | 0 | 77,402 | 10 | 154,804 |
No | output | 1 | 77,402 | 10 | 154,805 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8
Submitted Solution:
```
import sys
A = int(sys.argv[1]) * int(sys.argv[2])
B = int(sys.argv[3])
print(min(A, B))
``` | instruction | 0 | 77,403 | 10 | 154,806 |
No | output | 1 | 77,403 | 10 | 154,807 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
N of us are going on a trip, by train or taxi.
The train will cost each of us A yen (the currency of Japan).
The taxi will cost us a total of B yen.
How much is our minimum total travel expense?
Constraints
* All values in input are integers.
* 1 \leq N \leq 20
* 1 \leq A \leq 50
* 1 \leq B \leq 50
Input
Input is given from Standard Input in the following format:
N A B
Output
Print an integer representing the minimum total travel expense.
Examples
Input
4 2 9
Output
8
Input
4 2 7
Output
7
Input
4 2 8
Output
8
Submitted Solution:
```
import sys
a,b,c=map(int,sys.stdin.readline().split())
print(max(a*b,c))
``` | instruction | 0 | 77,404 | 10 | 154,808 |
No | output | 1 | 77,404 | 10 | 154,809 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day Polycarpus stopped by a supermarket on his way home. It turns out that the supermarket is having a special offer for stools. The offer is as follows: if a customer's shopping cart contains at least one stool, the customer gets a 50% discount on the cheapest item in the cart (that is, it becomes two times cheaper). If there are several items with the same minimum price, the discount is available for only one of them!
Polycarpus has k carts, and he wants to buy up all stools and pencils from the supermarket. Help him distribute the stools and the pencils among the shopping carts, so that the items' total price (including the discounts) is the least possible.
Polycarpus must use all k carts to purchase the items, no shopping cart can remain empty. Each shopping cart can contain an arbitrary number of stools and/or pencils.
Input
The first input line contains two integers n and k (1 ≤ k ≤ n ≤ 103) — the number of items in the supermarket and the number of carts, correspondingly. Next n lines describe the items as "ci ti" (without the quotes), where ci (1 ≤ ci ≤ 109) is an integer denoting the price of the i-th item, ti (1 ≤ ti ≤ 2) is an integer representing the type of item i (1 for a stool and 2 for a pencil). The numbers in the lines are separated by single spaces.
Output
In the first line print a single real number with exactly one decimal place — the minimum total price of the items, including the discounts.
In the following k lines print the descriptions of the items in the carts. In the i-th line print the description of the i-th cart as "t b1 b2 ... bt" (without the quotes), where t is the number of items in the i-th cart, and the sequence b1, b2, ..., bt (1 ≤ bj ≤ n) gives the indices of items to put in this cart in the optimal distribution. All indices of items in all carts should be pairwise different, each item must belong to exactly one cart. You can print the items in carts and the carts themselves in any order. The items are numbered from 1 to n in the order in which they are specified in the input.
If there are multiple optimal distributions, you are allowed to print any of them.
Examples
Input
3 2
2 1
3 2
3 1
Output
5.5
2 1 2
1 3
Input
4 3
4 1
1 2
2 2
3 2
Output
8.0
1 1
2 4 2
1 3
Note
In the first sample case the first cart should contain the 1st and 2nd items, and the second cart should contain the 3rd item. This way each cart has a stool and each cart has a 50% discount for the cheapest item. The total price of all items will be: 2·0.5 + (3 + 3·0.5) = 1 + 4.5 = 5.5.
Submitted Solution:
```
l=input().split()
n=int(l[0])
k=int(l[1])
qofp=[]
qofs=[]
for i in range(n):
l=input().split()
if(int(l[1])==1):
qofs.append((int(l[0]),i+1))
else:
qofp.append((int(l[0]),i+1))
qofs.sort()
qofs.reverse()
fina=[[] for i in range(k)]
if(len(qofs)<k):
price=0
i=0
while(qofs!=[]):
fina[i].append(qofs[0][1])
price+=(qofs[0][0]*0.5)
qofs.pop(0)
i+=1
for j in range(i,k-1):
fina[j].append(qofp[0][1])
price+=qofp[0][0]
qofp.pop(0)
for i in qofp:
fina[k-1].append(i[1])
price+=i[0]
print(price)
for i in fina:
print(len(i),end=" ")
for j in i:
print(j,end=" ")
print()
else:
price=0
for i in range(k-1):
fina[i].append(qofs[0][1])
price+=(0.5*qofs[0][0])
qofs.pop(0)
fool=[]
while(qofs!=[]):
fina[k-1].append(qofs[0][1])
fool.append(qofs[0][0])
price+=qofs[0][0]
qofs.pop(0)
while(qofp!=[]):
fina[k-1].append(qofp[0][1])
fool.append(qofp[0][0])
price+=qofp[0][0]
qofp.pop(0)
z=min(fool)
price-=(z/2)
print(price)
for i in fina:
print(len(i),end=" ")
for j in i:
print(j,end=" ")
print()
``` | instruction | 0 | 77,758 | 10 | 155,516 |
No | output | 1 | 77,758 | 10 | 155,517 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day Polycarpus stopped by a supermarket on his way home. It turns out that the supermarket is having a special offer for stools. The offer is as follows: if a customer's shopping cart contains at least one stool, the customer gets a 50% discount on the cheapest item in the cart (that is, it becomes two times cheaper). If there are several items with the same minimum price, the discount is available for only one of them!
Polycarpus has k carts, and he wants to buy up all stools and pencils from the supermarket. Help him distribute the stools and the pencils among the shopping carts, so that the items' total price (including the discounts) is the least possible.
Polycarpus must use all k carts to purchase the items, no shopping cart can remain empty. Each shopping cart can contain an arbitrary number of stools and/or pencils.
Input
The first input line contains two integers n and k (1 ≤ k ≤ n ≤ 103) — the number of items in the supermarket and the number of carts, correspondingly. Next n lines describe the items as "ci ti" (without the quotes), where ci (1 ≤ ci ≤ 109) is an integer denoting the price of the i-th item, ti (1 ≤ ti ≤ 2) is an integer representing the type of item i (1 for a stool and 2 for a pencil). The numbers in the lines are separated by single spaces.
Output
In the first line print a single real number with exactly one decimal place — the minimum total price of the items, including the discounts.
In the following k lines print the descriptions of the items in the carts. In the i-th line print the description of the i-th cart as "t b1 b2 ... bt" (without the quotes), where t is the number of items in the i-th cart, and the sequence b1, b2, ..., bt (1 ≤ bj ≤ n) gives the indices of items to put in this cart in the optimal distribution. All indices of items in all carts should be pairwise different, each item must belong to exactly one cart. You can print the items in carts and the carts themselves in any order. The items are numbered from 1 to n in the order in which they are specified in the input.
If there are multiple optimal distributions, you are allowed to print any of them.
Examples
Input
3 2
2 1
3 2
3 1
Output
5.5
2 1 2
1 3
Input
4 3
4 1
1 2
2 2
3 2
Output
8.0
1 1
2 4 2
1 3
Note
In the first sample case the first cart should contain the 1st and 2nd items, and the second cart should contain the 3rd item. This way each cart has a stool and each cart has a 50% discount for the cheapest item. The total price of all items will be: 2·0.5 + (3 + 3·0.5) = 1 + 4.5 = 5.5.
Submitted Solution:
```
#for _ in range(int(input())):
#n=int(input())
n,k= map(int, input().split())
s=[]
p=[]
ex=1e9
for i in range(n):
c,t = map(int, input().split())
if t==1:
s.append((c,i))
ex=min(ex,c)
else:
p.append((c,i))
s.sort(reverse=True)
var=0
cost=0
ans=[[] for i in range(k)]
for i,j in s:
ans[var].append((j+1))
if var<k-1:
cost+=i
var+=1
else:
cost+=2*i
for i,j in p:
ans[var].append((j+1))
if var<k-1:var+=1
cost+=2*i
#print("%.1f"%cost/2)
if len(s)==k:
cost-=ex
cost=cost/2
print("%.1f"%cost)
for i in ans:
print(len(i), *i)
``` | instruction | 0 | 77,759 | 10 | 155,518 |
No | output | 1 | 77,759 | 10 | 155,519 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day Polycarpus stopped by a supermarket on his way home. It turns out that the supermarket is having a special offer for stools. The offer is as follows: if a customer's shopping cart contains at least one stool, the customer gets a 50% discount on the cheapest item in the cart (that is, it becomes two times cheaper). If there are several items with the same minimum price, the discount is available for only one of them!
Polycarpus has k carts, and he wants to buy up all stools and pencils from the supermarket. Help him distribute the stools and the pencils among the shopping carts, so that the items' total price (including the discounts) is the least possible.
Polycarpus must use all k carts to purchase the items, no shopping cart can remain empty. Each shopping cart can contain an arbitrary number of stools and/or pencils.
Input
The first input line contains two integers n and k (1 ≤ k ≤ n ≤ 103) — the number of items in the supermarket and the number of carts, correspondingly. Next n lines describe the items as "ci ti" (without the quotes), where ci (1 ≤ ci ≤ 109) is an integer denoting the price of the i-th item, ti (1 ≤ ti ≤ 2) is an integer representing the type of item i (1 for a stool and 2 for a pencil). The numbers in the lines are separated by single spaces.
Output
In the first line print a single real number with exactly one decimal place — the minimum total price of the items, including the discounts.
In the following k lines print the descriptions of the items in the carts. In the i-th line print the description of the i-th cart as "t b1 b2 ... bt" (without the quotes), where t is the number of items in the i-th cart, and the sequence b1, b2, ..., bt (1 ≤ bj ≤ n) gives the indices of items to put in this cart in the optimal distribution. All indices of items in all carts should be pairwise different, each item must belong to exactly one cart. You can print the items in carts and the carts themselves in any order. The items are numbered from 1 to n in the order in which they are specified in the input.
If there are multiple optimal distributions, you are allowed to print any of them.
Examples
Input
3 2
2 1
3 2
3 1
Output
5.5
2 1 2
1 3
Input
4 3
4 1
1 2
2 2
3 2
Output
8.0
1 1
2 4 2
1 3
Note
In the first sample case the first cart should contain the 1st and 2nd items, and the second cart should contain the 3rd item. This way each cart has a stool and each cart has a 50% discount for the cheapest item. The total price of all items will be: 2·0.5 + (3 + 3·0.5) = 1 + 4.5 = 5.5.
Submitted Solution:
```
l=input().split()
n=int(l[0])
k=int(l[1])
qofp=[]
qofs=[]
for i in range(n):
l=input().split()
if(int(l[1])==1):
qofs.append((int(l[0]),i+1))
else:
qofp.append((int(l[0]),i+1))
qofs.sort()
qofs.reverse()
fina=[[] for i in range(k)]
if(len(qofs)<k):
price=0
i=0
while(qofs!=[]):
fina[i].append(qofs[0][1])
price+=(qofs[0][0]*0.5)
qofs.pop(0)
i+=1
for j in range(i,k-1):
fina[j].append(qofp[0][1])
price+=qofp[0][0]
qofp.pop(0)
for i in qofp:
fina[k-1].append(i[1])
price+=i[0]
print(price)
for i in fina:
print(len(fina),end=" ")
for j in i:
print(j,end=" ")
print()
else:
price=0
for i in range(k-1):
fina[i].append(qofs[0][1])
price+=(0.5*qofs[0][0])
qofs.pop(0)
fool=[]
while(qofs!=[]):
fina[k-1].append(qofs[0][1])
fool.append(qofs[0][0])
price+=qofs[0][0]
qofs.pop(0)
while(qofp!=[]):
fina[k-1].append(qofp[0][1])
fool.append(qofp[0][0])
price+=qofp[0][0]
qofp.pop(0)
z=min(fool)
price-=(z/2)
print(price)
for i in fina:
print(len(i),end=" ")
for j in i:
print(j,end=" ")
print()
``` | instruction | 0 | 77,760 | 10 | 155,520 |
No | output | 1 | 77,760 | 10 | 155,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One day Polycarpus stopped by a supermarket on his way home. It turns out that the supermarket is having a special offer for stools. The offer is as follows: if a customer's shopping cart contains at least one stool, the customer gets a 50% discount on the cheapest item in the cart (that is, it becomes two times cheaper). If there are several items with the same minimum price, the discount is available for only one of them!
Polycarpus has k carts, and he wants to buy up all stools and pencils from the supermarket. Help him distribute the stools and the pencils among the shopping carts, so that the items' total price (including the discounts) is the least possible.
Polycarpus must use all k carts to purchase the items, no shopping cart can remain empty. Each shopping cart can contain an arbitrary number of stools and/or pencils.
Input
The first input line contains two integers n and k (1 ≤ k ≤ n ≤ 103) — the number of items in the supermarket and the number of carts, correspondingly. Next n lines describe the items as "ci ti" (without the quotes), where ci (1 ≤ ci ≤ 109) is an integer denoting the price of the i-th item, ti (1 ≤ ti ≤ 2) is an integer representing the type of item i (1 for a stool and 2 for a pencil). The numbers in the lines are separated by single spaces.
Output
In the first line print a single real number with exactly one decimal place — the minimum total price of the items, including the discounts.
In the following k lines print the descriptions of the items in the carts. In the i-th line print the description of the i-th cart as "t b1 b2 ... bt" (without the quotes), where t is the number of items in the i-th cart, and the sequence b1, b2, ..., bt (1 ≤ bj ≤ n) gives the indices of items to put in this cart in the optimal distribution. All indices of items in all carts should be pairwise different, each item must belong to exactly one cart. You can print the items in carts and the carts themselves in any order. The items are numbered from 1 to n in the order in which they are specified in the input.
If there are multiple optimal distributions, you are allowed to print any of them.
Examples
Input
3 2
2 1
3 2
3 1
Output
5.5
2 1 2
1 3
Input
4 3
4 1
1 2
2 2
3 2
Output
8.0
1 1
2 4 2
1 3
Note
In the first sample case the first cart should contain the 1st and 2nd items, and the second cart should contain the 3rd item. This way each cart has a stool and each cart has a 50% discount for the cheapest item. The total price of all items will be: 2·0.5 + (3 + 3·0.5) = 1 + 4.5 = 5.5.
Submitted Solution:
```
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
##########################################################
#print('%d %d' %ans)
from collections import Counter
import math
#for _ in range(int(input())):
#n=int(input())
n,k= map(int, input().split())
s=[]
p=[]
ex=1e9
for i in range(n):
c,t = map(int, input().split())
ex = min(ex, c)
if t==1:
s.append((c,i))
else:
p.append((c,i))
s.sort(reverse=True)
var=0
cost=0
ans=[[] for i in range(k)]
for i,j in s:
ans[var].append((j+1))
if var<k-1:
cost+=i
var+=1
else:
cost+=2*i
for i,j in p:
ans[var].append((j+1))
if var<k-1:var+=1
cost+=2*i
#print("%.1f"%cost/2)
if len(s)==k:
cost-=ex
cost=cost/2
print("%.1f"%cost)
for i in ans:
print(len(i), *i)
``` | instruction | 0 | 77,761 | 10 | 155,522 |
No | output | 1 | 77,761 | 10 | 155,523 |
Provide a correct Python 3 solution for this coding contest problem.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes | instruction | 0 | 78,095 | 10 | 156,190 |
"Correct Solution:
```
a, b, c = map(int, input().split())
print(['No', 'Yes'][a+b>=c])
``` | output | 1 | 78,095 | 10 | 156,191 |
Provide a correct Python 3 solution for this coding contest problem.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes | instruction | 0 | 78,096 | 10 | 156,192 |
"Correct Solution:
```
A,B,C= map(int,input().split())
print(['No','Yes'][A+B>=C])
``` | output | 1 | 78,096 | 10 | 156,193 |
Provide a correct Python 3 solution for this coding contest problem.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes | instruction | 0 | 78,097 | 10 | 156,194 |
"Correct Solution:
```
a, b, c = (int(x) for x in input().split())
print('Yes' if a+b >= c else 'No')
``` | output | 1 | 78,097 | 10 | 156,195 |
Provide a correct Python 3 solution for this coding contest problem.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes | instruction | 0 | 78,098 | 10 | 156,196 |
"Correct Solution:
```
A,B,C=[int(x) for x in input().split()]
print(["No","Yes"][A+B>=C])
``` | output | 1 | 78,098 | 10 | 156,197 |
Provide a correct Python 3 solution for this coding contest problem.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes | instruction | 0 | 78,099 | 10 | 156,198 |
"Correct Solution:
```
a,b,c = (int(i) for i in input().split())
if a+b<c: print("No")
else: print("Yes")
``` | output | 1 | 78,099 | 10 | 156,199 |
Provide a correct Python 3 solution for this coding contest problem.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes | instruction | 0 | 78,100 | 10 | 156,200 |
"Correct Solution:
```
a,b,c=input().split()
print('Yes' if int(a)+int(b)>=int(c) else 'No')
``` | output | 1 | 78,100 | 10 | 156,201 |
Provide a correct Python 3 solution for this coding contest problem.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes | instruction | 0 | 78,101 | 10 | 156,202 |
"Correct Solution:
```
a,b,c=map(int,input().split());print('No'if a+b<c else'Yes')
``` | output | 1 | 78,101 | 10 | 156,203 |
Provide a correct Python 3 solution for this coding contest problem.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes | instruction | 0 | 78,102 | 10 | 156,204 |
"Correct Solution:
```
a,b,c=[int(s) for s in input().split()]
if a+b<c:
print("No")
else:
print("Yes")
``` | output | 1 | 78,102 | 10 | 156,205 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes
Submitted Solution:
```
a,b,c = list(map(int,input().split()))
print(['No','Yes'][int(a+b>=c)])
``` | instruction | 0 | 78,103 | 10 | 156,206 |
Yes | output | 1 | 78,103 | 10 | 156,207 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes
Submitted Solution:
```
A,B,C=map(int,input().split())
if (A+B>=C):
print ("Yes")
else:
print ("No")
``` | instruction | 0 | 78,104 | 10 | 156,208 |
Yes | output | 1 | 78,104 | 10 | 156,209 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes
Submitted Solution:
```
a,b,c=map(int,input().split())
print(["No","Yes"][a+b>=c])
``` | instruction | 0 | 78,105 | 10 | 156,210 |
Yes | output | 1 | 78,105 | 10 | 156,211 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes
Submitted Solution:
```
A,B,C = list(map(int,input().split()))
print('Yes' if A+B>=C else 'No')
``` | instruction | 0 | 78,106 | 10 | 156,212 |
Yes | output | 1 | 78,106 | 10 | 156,213 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes
Submitted Solution:
```
a, b, c = map(int, input().split())
if a + b > c:
print("No")
else:
print("Yes")
``` | instruction | 0 | 78,107 | 10 | 156,214 |
No | output | 1 | 78,107 | 10 | 156,215 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes
Submitted Solution:
```
a,b,c = input()
if(a + b < c):
print(Yes)
else:
print(No)
``` | instruction | 0 | 78,108 | 10 | 156,216 |
No | output | 1 | 78,108 | 10 | 156,217 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes
Submitted Solution:
```
N = int(input())
r = []
b = []
for i in range(N):
r.append([int(i) for i in input().split()])
for i in range(N):
b.append([int(i) for i in input().split()])
sorted_r = sorted(r, key=lambda r:r[0], reverse=True)
sorted_b = sorted(b)
ans = 0
for e1 in sorted_b:
for e2 in sorted_r:
if e2[0] < e1[0] and e2[1] < e1[1]:
ans += 1
sorted_r.remove(e2)
break
print(ans)
``` | instruction | 0 | 78,109 | 10 | 156,218 |
No | output | 1 | 78,109 | 10 | 156,219 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An elementary school student Takahashi has come to a variety store.
He has two coins, A-yen and B-yen coins (yen is the currency of Japan), and wants to buy a toy that costs C yen. Can he buy it?
Note that he lives in Takahashi Kingdom, and may have coins that do not exist in Japan.
Constraints
* All input values are integers.
* 1 \leq A, B \leq 500
* 1 \leq C \leq 1000
Input
Input is given from Standard Input in the following format:
A B C
Output
If Takahashi can buy the toy, print `Yes`; if he cannot, print `No`.
Examples
Input
50 100 120
Output
Yes
Input
500 100 1000
Output
No
Input
19 123 143
Output
No
Input
19 123 142
Output
Yes
Submitted Solution:
```
import functools
import os
INF = float('inf')
def inp():
return int(input())
def inpf():
return float(input())
def inps():
return input()
def inl():
return list(map(int, input().split()))
def inlf():
return list(map(float, input().split()))
def inls():
return input().split()
def debug(fn):
if not os.getenv('LOCAL'):
return fn
@functools.wraps(fn)
def wrapper(*args, **kwargs):
print('DEBUG: {}({}) -> '.format(
fn.__name__,
', '.join(
list(map(str, args)) +
['{}={}'.format(k, str(v)) for k, v in kwargs.items()]
)
), end='')
ret = fn(*args, **kwargs)
print(ret)
return ret
return wrapper
a, b, c = inl()
if a + b == c:
print('Yes')
else:
print('No')
``` | instruction | 0 | 78,110 | 10 | 156,220 |
No | output | 1 | 78,110 | 10 | 156,221 |
Provide a correct Python 3 solution for this coding contest problem.
Hint
In solving this problem, the following may be referred to. Shows how to convert an integer value to a string. Assign value as a string to str.
For C
include <stdio.h>
int main () {
int value = 123; // Convert this value to a string
char str [6]; // This variable contains a string of value
sprintf (str, "% d", value);
return 0;
}
For C ++
include <sstream>
using namespace std;
int main () {
int value = 123; // Convert this value to a string
string str; // This variable contains a string of value
stringstream ss;
ss << value;
ss >> str;
return 0;
}
For JAVA
class Main {
public static void main (String args []) {
int value = 123; // Convert this value to a string
String str = new Integer (value) .toString (); // This variable contains a string of value
}
}
Constraints
The input satisfies the following conditions.
* 1 ≤ n ≤ 5
* 0 ≤ m ≤ 500
* 1 ≤ ci ≤ 1000 (0 ≤ i ≤ 9)
Input
n m
c0 c1 c2 ... c9
Two integers n and m are given on the first line, separated by blanks. n is the number of plates to purchase, and m is the amount of money you have.
On the second line, 10 integers are given, separated by blanks. ci (i is 0 or more and 9 or less) represents the price of the plate with i written in the table.
Output
Buy n plates and put them in any order to output the minimum number of values you can.
If some 0s are included at the beginning, output as it is. (For example, if the answer is 0019, output 0019 as it is instead of removing the leading 0 to make it 19.) If you cannot purchase n plates with the amount of money you have, output "NA".
Examples
Input
1 10
1 2 3 4 5 6 7 8 9 10
Output
0
Input
3 10
8 4 5 3 5 6 9 10 11 2
Output
119
Input
5 30
25 51 32 9 2 1 10 2 5 10
Output
04555
Input
5 100
101 101 101 101 101 101 101 101 101 101
Output
NA | instruction | 0 | 79,076 | 10 | 158,152 |
"Correct Solution:
```
from itertools import combinations_with_replacement as cwr
n, m = map(int, input().split())
c_lst = list(map(int, input().split()))
for t in cwr((0, 1, 2, 3, 4, 5, 6, 7, 8, 9), n):
out = ""
cost = 0
for n in t:
cost += c_lst[n]
out += str(n)
if cost <= m:
print(out)
break
else:
print("NA")
``` | output | 1 | 79,076 | 10 | 158,153 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet. | instruction | 0 | 79,110 | 10 | 158,220 |
Tags: implementation
Correct Solution:
```
n, m = map(int, input().split(' '))
prices = list(map(int, input().split(' ')))
money = list(map(int, input().split(' ')))
i = 0
j = 0
ans = 0
while i < n and j < m:
if money[j] >= prices[i]:
ans += 1
i += 1
j += 1
else:
i += 1
print(ans)
``` | output | 1 | 79,110 | 10 | 158,221 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet. | instruction | 0 | 79,111 | 10 | 158,222 |
Tags: implementation
Correct Solution:
```
n,m=map(int,input().split())
c=list(map(int,input().split()))
a=list(map(int,input().split()))
buy=0
i=0
j=0
while i<m and j<n:
if a[i]>=c[j]:
buy+=1
i+=1
j+=1
else:
j+=1
print(buy)
``` | output | 1 | 79,111 | 10 | 158,223 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet. | instruction | 0 | 79,112 | 10 | 158,224 |
Tags: implementation
Correct Solution:
```
n,m=map(int,input().split())
ci=list(map(int,input().split()))
ai=list(map(int,input().split()))
toys=0
j=0
for i in range(n):
if j>m-1:
break
if ci[i]<=ai[j]:
toys+=1
j+=1
print(toys)
``` | output | 1 | 79,112 | 10 | 158,225 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet. | instruction | 0 | 79,113 | 10 | 158,226 |
Tags: implementation
Correct Solution:
```
n, m = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
j = 0
k = 0
for i in range(n):
if j < m and b[j] >= a[i]:
k+=1
j+=1
print(k)
``` | output | 1 | 79,113 | 10 | 158,227 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet. | instruction | 0 | 79,114 | 10 | 158,228 |
Tags: implementation
Correct Solution:
```
n, m = map(int, input().split())
c = list(map(int, input().split()))
a = list(map(int, input().split()))
i = k = j = 0
while j < n and i <m:
if a[i] >= c[j]:
k += 1
i += 1
j += 1
else:
j += 1
print(k)
``` | output | 1 | 79,114 | 10 | 158,229 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet. | instruction | 0 | 79,115 | 10 | 158,230 |
Tags: implementation
Correct Solution:
```
totalGames, totalBills = list(map(int, input().split(" ")))
games = list(map(int, input().split(" ")))
bills = list(map(int, input().split(" ")))
bought, game, bill = 0, 0, 0
while bill < totalBills and game < totalGames:
if games[game] <= bills[bill]:
bought += 1
bill += 1
game += 1
print(bought)
``` | output | 1 | 79,115 | 10 | 158,231 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet. | instruction | 0 | 79,116 | 10 | 158,232 |
Tags: implementation
Correct Solution:
```
res, _ = 0, input()
n = [int(x) for x in input().split()]
m = [int(x) for x in input().split()]+[0]
for row in n: res += row<=m[res]
print(res)
``` | output | 1 | 79,116 | 10 | 158,233 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet. | instruction | 0 | 79,117 | 10 | 158,234 |
Tags: implementation
Correct Solution:
```
c, a = (int(i) for i in input().split())
C = [int(i) for i in input().split()]
A = [int(i) for i in input().split()]
k = 0
for i in range(c):
if A != [] and C[i] <= A[0]:
k += 1
A.pop(0)
print(k)
``` | output | 1 | 79,117 | 10 | 158,235 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet.
Submitted Solution:
```
len_games, len_bills = [int(x) for x in input().split()]
costArrays = [int(x) for x in input().split()]
billsArrays = [int(x) for x in input().split()]
gameCounts = 0
index = 0
for bills in billsArrays:
while index < len_games:
if bills >= costArrays[index]:
index += 1
gameCounts += 1
break
index += 1
print(gameCounts)
``` | instruction | 0 | 79,118 | 10 | 158,236 |
Yes | output | 1 | 79,118 | 10 | 158,237 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet.
Submitted Solution:
```
n,m=map(int,input().split())
n1=list(map(int,input().split()))
m1=list(map(int,input().split()))
count=0
for i in range(len(n1)):
if len(m1)==0:
break
elif m1[0]>=n1[i]:
count+=1
m1.remove(m1[0])
print(count)
``` | instruction | 0 | 79,119 | 10 | 158,238 |
Yes | output | 1 | 79,119 | 10 | 158,239 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet.
Submitted Solution:
```
c=0
n,m=map(int,input().split())
a=[int(i) for i in input().split()]
b=[int(i) for i in input().split()]
for i in range(n):
if len(b)>0:
if b[0]>=a[i]:
del b[0]
c+=1
else:
break
print(c)
``` | instruction | 0 | 79,120 | 10 | 158,240 |
Yes | output | 1 | 79,120 | 10 | 158,241 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet.
Submitted Solution:
```
done = False
def solve(c, a):
ans = 0
tempJ = -1
for i in a:
done = False
j = tempJ + 1
while j < len(c):
if i >= c[j]:
ans += 1
done = True
tempJ = j
break
j += 1
if done == False:
break
return ans;
#end function
# Main
def main():
n, m = map(int, input().split())
c = list(map(int, input().split()))
a = list(map(int, input().split()))
print(solve(c, a))
#end main
#Program Start
if __name__ == "__main__":
main()
``` | instruction | 0 | 79,121 | 10 | 158,242 |
Yes | output | 1 | 79,121 | 10 | 158,243 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet.
Submitted Solution:
```
input()
games = [int(x) for x in input().split()]
wallet = [int(x) for x in input().split()]
numgames = 0
for game in games:
for i in range(len(wallet)):
bill = wallet[i]
if game < bill:
#print(bill)
del wallet[i]
#print(wallet)
numgames += 1
break
print(numgames)
``` | instruction | 0 | 79,122 | 10 | 158,244 |
No | output | 1 | 79,122 | 10 | 158,245 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet.
Submitted Solution:
```
fixed = set(['0', '2'])
def buy(games, bills):
print(games)
print(bills)
count = 0
inda = 0
indb = 0
while inda < len(games):
if indb == len(bills):
break
if games[inda] <= bills[indb]:
count += 1
indb += 1
inda += 1
return count
# print(buy([2, 4, 5, 2, 4], [5, 3, 4, 6]))
# print(buy(list(map(int, '20 40 50 20 40'.split(' '))), list(map(int, '19 20'.split(' ')))))
# print(buy(list(map(int, '4 8 15 16 23 42'.split(' '))), list(map(int, '1000 1000 1000 1000'.split(' ')))))
input()
print(buy(list(map(int, input().split(' '))), list(map(int, input().split(' ')))))
``` | instruction | 0 | 79,123 | 10 | 158,246 |
No | output | 1 | 79,123 | 10 | 158,247 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet.
Submitted Solution:
```
answer = 0
n,m=map(int,input("").split(" "))
games=input("").split(" ")
wallet=input("").split(" ")
for i in range(m):
if int(games[i])<=int(wallet[i]):
answer+=1
else:
del games[i]
games.append(1001)
i-=1
print(answer)
``` | instruction | 0 | 79,124 | 10 | 158,248 |
No | output | 1 | 79,124 | 10 | 158,249 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Maxim wants to buy some games at the local game shop. There are n games in the shop, the i-th game costs c_i.
Maxim has a wallet which can be represented as an array of integers. His wallet contains m bills, the j-th bill has value a_j.
Games in the shop are ordered from left to right, Maxim tries to buy every game in that order.
When Maxim stands at the position i in the shop, he takes the first bill from his wallet (if his wallet is empty then he proceeds to the next position immediately) and tries to buy the i-th game using this bill. After Maxim tried to buy the n-th game, he leaves the shop.
Maxim buys the i-th game if and only if the value of the first bill (which he takes) from his wallet is greater or equal to the cost of the i-th game. If he successfully buys the i-th game, the first bill from his wallet disappears and the next bill becomes first. Otherwise Maxim leaves the first bill in his wallet (this bill still remains the first one) and proceeds to the next game.
For example, for array c = [2, 4, 5, 2, 4] and array a = [5, 3, 4, 6] the following process takes place: Maxim buys the first game using the first bill (its value is 5), the bill disappears, after that the second bill (with value 3) becomes the first one in Maxim's wallet, then Maxim doesn't buy the second game because c_2 > a_2, the same with the third game, then he buys the fourth game using the bill of value a_2 (the third bill becomes the first one in Maxim's wallet) and buys the fifth game using the bill of value a_3.
Your task is to get the number of games Maxim will buy.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 1000) — the number of games and the number of bills in Maxim's wallet.
The second line of the input contains n integers c_1, c_2, ..., c_n (1 ≤ c_i ≤ 1000), where c_i is the cost of the i-th game.
The third line of the input contains m integers a_1, a_2, ..., a_m (1 ≤ a_j ≤ 1000), where a_j is the value of the j-th bill from the Maxim's wallet.
Output
Print a single integer — the number of games Maxim will buy.
Examples
Input
5 4
2 4 5 2 4
5 3 4 6
Output
3
Input
5 2
20 40 50 20 40
19 20
Output
0
Input
6 4
4 8 15 16 23 42
1000 1000 1000 1000
Output
4
Note
The first example is described in the problem statement.
In the second example Maxim cannot buy any game because the value of the first bill in his wallet is smaller than the cost of any game in the shop.
In the third example the values of the bills in Maxim's wallet are large enough to buy any game he encounter until he runs out of bills in his wallet.
Submitted Solution:
```
R=lambda:map(int,input().split())
R()
c,a=R(),R()
r=0
try:
for x in a:r+=next(1 for y in c if y<=x)
except:print(r)
``` | instruction | 0 | 79,125 | 10 | 158,250 |
No | output | 1 | 79,125 | 10 | 158,251 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
Ivan plays a computer game that contains some microtransactions to make characters look cooler. Since Ivan wants his character to be really cool, he wants to use some of these microtransactions — and he won't start playing until he gets all of them.
Each day (during the morning) Ivan earns exactly one burle.
There are n types of microtransactions in the game. Each microtransaction costs 2 burles usually and 1 burle if it is on sale. Ivan has to order exactly k_i microtransactions of the i-th type (he orders microtransactions during the evening).
Ivan can order any (possibly zero) number of microtransactions of any types during any day (of course, if he has enough money to do it). If the microtransaction he wants to order is on sale then he can buy it for 1 burle and otherwise he can buy it for 2 burles.
There are also m special offers in the game shop. The j-th offer (d_j, t_j) means that microtransactions of the t_j-th type are on sale during the d_j-th day.
Ivan wants to order all microtransactions as soon as possible. Your task is to calculate the minimum day when he can buy all microtransactions he want and actually start playing.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 2 ⋅ 10^5) — the number of types of microtransactions and the number of special offers in the game shop.
The second line of the input contains n integers k_1, k_2, ..., k_n (0 ≤ k_i ≤ 2 ⋅ 10^5), where k_i is the number of copies of microtransaction of the i-th type Ivan has to order. It is guaranteed that sum of all k_i is not less than 1 and not greater than 2 ⋅ 10^5.
The next m lines contain special offers. The j-th of these lines contains the j-th special offer. It is given as a pair of integers (d_j, t_j) (1 ≤ d_j ≤ 2 ⋅ 10^5, 1 ≤ t_j ≤ n) and means that microtransactions of the t_j-th type are on sale during the d_j-th day.
Output
Print one integer — the minimum day when Ivan can order all microtransactions he wants and actually start playing.
Examples
Input
5 6
1 2 0 2 0
2 4
3 3
1 5
1 2
1 5
2 3
Output
8
Input
5 3
4 2 1 3 2
3 5
4 2
2 5
Output
20 | instruction | 0 | 79,216 | 10 | 158,432 |
Tags: binary search, greedy, implementation
Correct Solution:
```
import collections
def main():
from sys import stdin, stdout
def read():
return stdin.readline().rstrip('\n')
def read_array(sep=None, maxsplit=-1):
return read().split(sep, maxsplit)
def read_int():
return int(read())
def read_int_array(sep=None, maxsplit=-1):
return [int(a) for a in read_array(sep, maxsplit)]
def write(*args, **kwargs):
sep = kwargs.get('sep', ' ')
end = kwargs.get('end', '\n')
stdout.write(sep.join(str(a) for a in args) + end)
def write_array(array, **kwargs):
sep = kwargs.get('sep', ' ')
end = kwargs.get('end', '\n')
stdout.write(sep.join(str(a) for a in array) + end)
def enough(days):
bought = [] # (type, amount)
bought_total = 0
used_from = days
for d in range(days, 0, -1):
used_from = min(d, used_from)
for t in offers.get(d, []):
if K[t] > 0:
x = min(K[t], used_from)
K[t] -= x
bought.append((t, x))
bought_total += x
used_from -= x
if not used_from:
break
remaining_money = days - bought_total
ans = (total_transaction - bought_total) * 2 <= remaining_money
for t, a in bought:
K[t] += a
return ans
n, m = read_int_array()
K = read_int_array()
total_transaction = sum(K)
offers = collections.defaultdict(list)
for _ in range(m):
d, t = read_int_array()
offers[d].append(t-1)
low = total_transaction
high = low * 2
ans = high
while low <= high:
mid = (low + high) // 2
if enough(mid):
ans = mid
high = mid - 1
else:
low = mid + 1
write(ans)
main()
``` | output | 1 | 79,216 | 10 | 158,433 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
Ivan plays a computer game that contains some microtransactions to make characters look cooler. Since Ivan wants his character to be really cool, he wants to use some of these microtransactions — and he won't start playing until he gets all of them.
Each day (during the morning) Ivan earns exactly one burle.
There are n types of microtransactions in the game. Each microtransaction costs 2 burles usually and 1 burle if it is on sale. Ivan has to order exactly k_i microtransactions of the i-th type (he orders microtransactions during the evening).
Ivan can order any (possibly zero) number of microtransactions of any types during any day (of course, if he has enough money to do it). If the microtransaction he wants to order is on sale then he can buy it for 1 burle and otherwise he can buy it for 2 burles.
There are also m special offers in the game shop. The j-th offer (d_j, t_j) means that microtransactions of the t_j-th type are on sale during the d_j-th day.
Ivan wants to order all microtransactions as soon as possible. Your task is to calculate the minimum day when he can buy all microtransactions he want and actually start playing.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 2 ⋅ 10^5) — the number of types of microtransactions and the number of special offers in the game shop.
The second line of the input contains n integers k_1, k_2, ..., k_n (0 ≤ k_i ≤ 2 ⋅ 10^5), where k_i is the number of copies of microtransaction of the i-th type Ivan has to order. It is guaranteed that sum of all k_i is not less than 1 and not greater than 2 ⋅ 10^5.
The next m lines contain special offers. The j-th of these lines contains the j-th special offer. It is given as a pair of integers (d_j, t_j) (1 ≤ d_j ≤ 2 ⋅ 10^5, 1 ≤ t_j ≤ n) and means that microtransactions of the t_j-th type are on sale during the d_j-th day.
Output
Print one integer — the minimum day when Ivan can order all microtransactions he wants and actually start playing.
Examples
Input
5 6
1 2 0 2 0
2 4
3 3
1 5
1 2
1 5
2 3
Output
8
Input
5 3
4 2 1 3 2
3 5
4 2
2 5
Output
20 | instruction | 0 | 79,217 | 10 | 158,434 |
Tags: binary search, greedy, implementation
Correct Solution:
```
import sys
import bisect
import copy
input = sys.stdin.readline
n,m=map(int,input().split())
K=[0]+list(map(int,input().split()))
SP=[list(map(int,input().split())) for i in range(m)]
SP2=[[] for i in range(n+1)]
for d,t in SP:
SP2[t].append(d)
for i in range(n+1):
SP2[i].sort()
SUM=sum(K)
MIN=SUM
MAX=SUM*2
MAXBUY=0
while MIN!=MAX:
day=(MIN+MAX)//2
DAYS=[[] for i in range(day+1)]
for i in range(n+1):
x=bisect.bisect_right(SP2[i],day)-1
if x>=0:
DAYS[SP2[i][x]].append(i)
GOLD=0
SUMK=SUM
K2=copy.deepcopy(K)
for d in range(1,day+1):
GOLD+=1
for t in DAYS[d]:
DBUY=min(K2[t],GOLD,SUMK)
K2[t]-=DBUY
GOLD-=DBUY
if GOLD>=sum(K2)*2:
MAX=day
else:
MIN=day+1
print(MIN)
``` | output | 1 | 79,217 | 10 | 158,435 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
Ivan plays a computer game that contains some microtransactions to make characters look cooler. Since Ivan wants his character to be really cool, he wants to use some of these microtransactions — and he won't start playing until he gets all of them.
Each day (during the morning) Ivan earns exactly one burle.
There are n types of microtransactions in the game. Each microtransaction costs 2 burles usually and 1 burle if it is on sale. Ivan has to order exactly k_i microtransactions of the i-th type (he orders microtransactions during the evening).
Ivan can order any (possibly zero) number of microtransactions of any types during any day (of course, if he has enough money to do it). If the microtransaction he wants to order is on sale then he can buy it for 1 burle and otherwise he can buy it for 2 burles.
There are also m special offers in the game shop. The j-th offer (d_j, t_j) means that microtransactions of the t_j-th type are on sale during the d_j-th day.
Ivan wants to order all microtransactions as soon as possible. Your task is to calculate the minimum day when he can buy all microtransactions he want and actually start playing.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 2 ⋅ 10^5) — the number of types of microtransactions and the number of special offers in the game shop.
The second line of the input contains n integers k_1, k_2, ..., k_n (0 ≤ k_i ≤ 2 ⋅ 10^5), where k_i is the number of copies of microtransaction of the i-th type Ivan has to order. It is guaranteed that sum of all k_i is not less than 1 and not greater than 2 ⋅ 10^5.
The next m lines contain special offers. The j-th of these lines contains the j-th special offer. It is given as a pair of integers (d_j, t_j) (1 ≤ d_j ≤ 2 ⋅ 10^5, 1 ≤ t_j ≤ n) and means that microtransactions of the t_j-th type are on sale during the d_j-th day.
Output
Print one integer — the minimum day when Ivan can order all microtransactions he wants and actually start playing.
Examples
Input
5 6
1 2 0 2 0
2 4
3 3
1 5
1 2
1 5
2 3
Output
8
Input
5 3
4 2 1 3 2
3 5
4 2
2 5
Output
20 | instruction | 0 | 79,218 | 10 | 158,436 |
Tags: binary search, greedy, implementation
Correct Solution:
```
import sys
from array import array # noqa: F401
from typing import List, Tuple, TypeVar, Generic, Sequence, Union # noqa: F401
def input():
return sys.stdin.buffer.readline().decode('utf-8')
def main():
n, m = map(int, input().split())
k = array('i', [0] + list(map(int, input().split())))
sale = sorted((tuple(map(int, input().split())) for _ in range(m)), reverse=True)
total = sum(k)
ok, ng = total * 2 + 1, total - 1
while abs(ok - ng) > 1:
mid = (ok + ng) >> 1
visited = [0] * (n + 1)
bought, money = 0, mid
for di, ti in sale:
if di > mid or visited[ti]:
continue
visited[ti] = 1
if money > di:
money = di
x = k[ti] if k[ti] <= money else money
bought += x
money -= x
if 2 * total - bought <= mid:
ok = mid
else:
ng = mid
print(ok)
if __name__ == '__main__':
main()
``` | output | 1 | 79,218 | 10 | 158,437 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
Ivan plays a computer game that contains some microtransactions to make characters look cooler. Since Ivan wants his character to be really cool, he wants to use some of these microtransactions — and he won't start playing until he gets all of them.
Each day (during the morning) Ivan earns exactly one burle.
There are n types of microtransactions in the game. Each microtransaction costs 2 burles usually and 1 burle if it is on sale. Ivan has to order exactly k_i microtransactions of the i-th type (he orders microtransactions during the evening).
Ivan can order any (possibly zero) number of microtransactions of any types during any day (of course, if he has enough money to do it). If the microtransaction he wants to order is on sale then he can buy it for 1 burle and otherwise he can buy it for 2 burles.
There are also m special offers in the game shop. The j-th offer (d_j, t_j) means that microtransactions of the t_j-th type are on sale during the d_j-th day.
Ivan wants to order all microtransactions as soon as possible. Your task is to calculate the minimum day when he can buy all microtransactions he want and actually start playing.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 2 ⋅ 10^5) — the number of types of microtransactions and the number of special offers in the game shop.
The second line of the input contains n integers k_1, k_2, ..., k_n (0 ≤ k_i ≤ 2 ⋅ 10^5), where k_i is the number of copies of microtransaction of the i-th type Ivan has to order. It is guaranteed that sum of all k_i is not less than 1 and not greater than 2 ⋅ 10^5.
The next m lines contain special offers. The j-th of these lines contains the j-th special offer. It is given as a pair of integers (d_j, t_j) (1 ≤ d_j ≤ 2 ⋅ 10^5, 1 ≤ t_j ≤ n) and means that microtransactions of the t_j-th type are on sale during the d_j-th day.
Output
Print one integer — the minimum day when Ivan can order all microtransactions he wants and actually start playing.
Examples
Input
5 6
1 2 0 2 0
2 4
3 3
1 5
1 2
1 5
2 3
Output
8
Input
5 3
4 2 1 3 2
3 5
4 2
2 5
Output
20 | instruction | 0 | 79,219 | 10 | 158,438 |
Tags: binary search, greedy, implementation
Correct Solution:
```
import sys
import copy
DEBUG = False
if DEBUG:
inf = open("input.txt")
else:
inf = sys.stdin
N, M = list(map(int, inf.readline().split(' ')))
n_items = list(map(int, inf.readline().split(' ')))
sales = []
for _ in range(M):
sale = list(map(int, inf.readline().split(' ')))
sales.append(sale) # sale_day, sale_type
sales = sorted(sales, key=lambda x: x[0], reverse=True) # sort by day
def can_buy_in(dday):
used = 0
money_left = dday
items = n_items[:]
for sale_day, sale_type in sales:
if sale_day > dday:
continue
if money_left > sale_day:
money_left = sale_day
can_buy = min(items[sale_type-1], money_left)
# buy it
used += can_buy
items[sale_type-1] -= can_buy
money_left -= can_buy
if money_left == 0:
break
need_money_for_rest = sum(items) * 2
return need_money_for_rest + used <= dday
total_items = sum(n_items)
low = total_items
high = total_items * 2
# find minimum can_buy day
while low <= high:
mid = (low + high) // 2
if can_buy_in(mid):
high = mid-1
else:
low = mid+1
print(low)
``` | output | 1 | 79,219 | 10 | 158,439 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
Ivan plays a computer game that contains some microtransactions to make characters look cooler. Since Ivan wants his character to be really cool, he wants to use some of these microtransactions — and he won't start playing until he gets all of them.
Each day (during the morning) Ivan earns exactly one burle.
There are n types of microtransactions in the game. Each microtransaction costs 2 burles usually and 1 burle if it is on sale. Ivan has to order exactly k_i microtransactions of the i-th type (he orders microtransactions during the evening).
Ivan can order any (possibly zero) number of microtransactions of any types during any day (of course, if he has enough money to do it). If the microtransaction he wants to order is on sale then he can buy it for 1 burle and otherwise he can buy it for 2 burles.
There are also m special offers in the game shop. The j-th offer (d_j, t_j) means that microtransactions of the t_j-th type are on sale during the d_j-th day.
Ivan wants to order all microtransactions as soon as possible. Your task is to calculate the minimum day when he can buy all microtransactions he want and actually start playing.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 2 ⋅ 10^5) — the number of types of microtransactions and the number of special offers in the game shop.
The second line of the input contains n integers k_1, k_2, ..., k_n (0 ≤ k_i ≤ 2 ⋅ 10^5), where k_i is the number of copies of microtransaction of the i-th type Ivan has to order. It is guaranteed that sum of all k_i is not less than 1 and not greater than 2 ⋅ 10^5.
The next m lines contain special offers. The j-th of these lines contains the j-th special offer. It is given as a pair of integers (d_j, t_j) (1 ≤ d_j ≤ 2 ⋅ 10^5, 1 ≤ t_j ≤ n) and means that microtransactions of the t_j-th type are on sale during the d_j-th day.
Output
Print one integer — the minimum day when Ivan can order all microtransactions he wants and actually start playing.
Examples
Input
5 6
1 2 0 2 0
2 4
3 3
1 5
1 2
1 5
2 3
Output
8
Input
5 3
4 2 1 3 2
3 5
4 2
2 5
Output
20 | instruction | 0 | 79,220 | 10 | 158,440 |
Tags: binary search, greedy, implementation
Correct Solution:
```
import sys
import os
from io import BytesIO
DEBUG = False
if DEBUG:
inf = open("input.txt")
else:
# inf = sys.stdin
inf = BytesIO(os.read(0, os.fstat(0).st_size))
N, M = list(map(int, inf.readline().split()))
n_items = list(map(int, inf.readline().split()))
sales = []
for _ in range(M):
sale = list(map(int, inf.readline().split()))
sales.append(sale) # sale_day, sale_type
sales = sorted(sales, key=lambda x: x[0], reverse=True) # sort by day
def can_buy_in(dday):
used = 0
money_left = dday
items = n_items[:]
for sale_day, sale_type in sales:
if sale_day > dday:
continue
if money_left > sale_day:
money_left = sale_day
can_buy = min(items[sale_type-1], money_left)
# buy it
used += can_buy
items[sale_type-1] -= can_buy
money_left -= can_buy
if money_left == 0:
break
need_money_for_rest = sum(items) * 2
return need_money_for_rest + used <= dday
total_items = sum(n_items)
low = total_items
high = total_items * 2
# find minimum can_buy day
while low <= high:
mid = (low + high) // 2
if can_buy_in(mid):
high = mid-1
else:
low = mid+1
print(low)
``` | output | 1 | 79,220 | 10 | 158,441 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
Ivan plays a computer game that contains some microtransactions to make characters look cooler. Since Ivan wants his character to be really cool, he wants to use some of these microtransactions — and he won't start playing until he gets all of them.
Each day (during the morning) Ivan earns exactly one burle.
There are n types of microtransactions in the game. Each microtransaction costs 2 burles usually and 1 burle if it is on sale. Ivan has to order exactly k_i microtransactions of the i-th type (he orders microtransactions during the evening).
Ivan can order any (possibly zero) number of microtransactions of any types during any day (of course, if he has enough money to do it). If the microtransaction he wants to order is on sale then he can buy it for 1 burle and otherwise he can buy it for 2 burles.
There are also m special offers in the game shop. The j-th offer (d_j, t_j) means that microtransactions of the t_j-th type are on sale during the d_j-th day.
Ivan wants to order all microtransactions as soon as possible. Your task is to calculate the minimum day when he can buy all microtransactions he want and actually start playing.
Input
The first line of the input contains two integers n and m (1 ≤ n, m ≤ 2 ⋅ 10^5) — the number of types of microtransactions and the number of special offers in the game shop.
The second line of the input contains n integers k_1, k_2, ..., k_n (0 ≤ k_i ≤ 2 ⋅ 10^5), where k_i is the number of copies of microtransaction of the i-th type Ivan has to order. It is guaranteed that sum of all k_i is not less than 1 and not greater than 2 ⋅ 10^5.
The next m lines contain special offers. The j-th of these lines contains the j-th special offer. It is given as a pair of integers (d_j, t_j) (1 ≤ d_j ≤ 2 ⋅ 10^5, 1 ≤ t_j ≤ n) and means that microtransactions of the t_j-th type are on sale during the d_j-th day.
Output
Print one integer — the minimum day when Ivan can order all microtransactions he wants and actually start playing.
Examples
Input
5 6
1 2 0 2 0
2 4
3 3
1 5
1 2
1 5
2 3
Output
8
Input
5 3
4 2 1 3 2
3 5
4 2
2 5
Output
20 | instruction | 0 | 79,221 | 10 | 158,442 |
Tags: binary search, greedy, implementation
Correct Solution:
```
def check(mid):
l = [0 for i in range(n)]
for i in b:
if(i[0] > mid): break
l[i[1]-1] = i[0]
v = [0 for i in range(mid+1)]
for i in range(n):
v[l[i]] += a[i]
ct = 0
for i in range(1,mid+1):
ct += 1
if(ct >= v[i]):
ct -= v[i]
v[i] = 0
else:
v[i] -= ct
ct = 0
return ct >= 2*sum(v)
def bs():
l = 0
r = 5*10**5
while(l <= r):
mid = (l+r)//2
if(check(mid)):
r = mid-1
else:
l = mid+1
return r+1
n,m = map(int,input().split())
a = list(map(int,input().split()))
b = []
for i in range(m):
b.append(list(map(int,input().split())))
b.sort()
print(bs())
``` | output | 1 | 79,221 | 10 | 158,443 |
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