message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
problem
For the integer n (1 β€ n), let Pn be a string of n + 1 I's and n O's starting with I and alternating, where I and O are the uppercase Ai and O, respectively. is there.
P1 | IOI
--- | ---
P2 | IOIOI
P3 | IOIOIOI
|. |
|. |
|. |
Pn | IOIOIO ... OI (n O)
Figure 1-1 Character string considered in this question Pn
Given the integer n and the string s consisting only of I and O, write a program that outputs how many Pn's are contained in s.
input
The input consists of multiple datasets. Each dataset is given in the following format.
The integer n (1 β€ n β€ 1000000) is written on the first line.
The second line contains the integer m (1 β€ m β€ 1000000). M represents the number of characters in s.
The string s is written on the third line. S consists of only I and O.
For all scoring data, 2n + 1 β€ m. Of the scoring data, 50% of the scoring data satisfies n β€ 100 and m β€ 10000.
When n is 0, it indicates the end of input. The number of datasets does not exceed 10.
output
For each dataset, print one integer on one line that indicates how many strings Pn are contained in the string s. If s does not contain Pn, print 0 as an integer.
Examples
Input
1
13
OOIOIOIOIIOII
2
13
OOIOIOIOIIOII
0
Output
4
2
Input
None
Output
None | instruction | 0 | 52,114 | 18 | 104,228 |
"Correct Solution:
```
# AOJ 0538: IOIOI
# Python3 2018.7.1 bal4u
while True:
n = int(input())
if n == 0: break
m = int(input())
s = input().strip()
ans = cnt = i = 0
while i < m:
if i+1 < m and s[i:i+2] == 'IO':
cnt += 1
i += 1
elif cnt > 0:
if s[i] == 'O': cnt -= 1
if cnt >= n: ans += cnt-n+1
cnt = 0
i += 1
print(ans)
``` | output | 1 | 52,114 | 18 | 104,229 |
Provide a correct Python 3 solution for this coding contest problem.
problem
For the integer n (1 β€ n), let Pn be a string of n + 1 I's and n O's starting with I and alternating, where I and O are the uppercase Ai and O, respectively. is there.
P1 | IOI
--- | ---
P2 | IOIOI
P3 | IOIOIOI
|. |
|. |
|. |
Pn | IOIOIO ... OI (n O)
Figure 1-1 Character string considered in this question Pn
Given the integer n and the string s consisting only of I and O, write a program that outputs how many Pn's are contained in s.
input
The input consists of multiple datasets. Each dataset is given in the following format.
The integer n (1 β€ n β€ 1000000) is written on the first line.
The second line contains the integer m (1 β€ m β€ 1000000). M represents the number of characters in s.
The string s is written on the third line. S consists of only I and O.
For all scoring data, 2n + 1 β€ m. Of the scoring data, 50% of the scoring data satisfies n β€ 100 and m β€ 10000.
When n is 0, it indicates the end of input. The number of datasets does not exceed 10.
output
For each dataset, print one integer on one line that indicates how many strings Pn are contained in the string s. If s does not contain Pn, print 0 as an integer.
Examples
Input
1
13
OOIOIOIOIIOII
2
13
OOIOIOIOIIOII
0
Output
4
2
Input
None
Output
None | instruction | 0 | 52,116 | 18 | 104,232 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
"""
IOIOI
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0538
"""
import sys
import re
def solve(n, s):
ans = 0
p = '(I(?:OI){' + str(n) + ',})'
for f in re.findall(p, s):
repeat = len(f) // 2
if repeat >= n:
ans += (repeat - n + 1)
return ans
def main(args):
while True:
n = int(input())
if n == 0:
break
_ = input()
s = input()
ans = solve(n, s)
print(ans)
if __name__ == '__main__':
main(sys.argv[1:])
``` | output | 1 | 52,116 | 18 | 104,233 |
Provide a correct Python 3 solution for this coding contest problem.
problem
For the integer n (1 β€ n), let Pn be a string of n + 1 I's and n O's starting with I and alternating, where I and O are the uppercase Ai and O, respectively. is there.
P1 | IOI
--- | ---
P2 | IOIOI
P3 | IOIOIOI
|. |
|. |
|. |
Pn | IOIOIO ... OI (n O)
Figure 1-1 Character string considered in this question Pn
Given the integer n and the string s consisting only of I and O, write a program that outputs how many Pn's are contained in s.
input
The input consists of multiple datasets. Each dataset is given in the following format.
The integer n (1 β€ n β€ 1000000) is written on the first line.
The second line contains the integer m (1 β€ m β€ 1000000). M represents the number of characters in s.
The string s is written on the third line. S consists of only I and O.
For all scoring data, 2n + 1 β€ m. Of the scoring data, 50% of the scoring data satisfies n β€ 100 and m β€ 10000.
When n is 0, it indicates the end of input. The number of datasets does not exceed 10.
output
For each dataset, print one integer on one line that indicates how many strings Pn are contained in the string s. If s does not contain Pn, print 0 as an integer.
Examples
Input
1
13
OOIOIOIOIIOII
2
13
OOIOIOIOIIOII
0
Output
4
2
Input
None
Output
None | instruction | 0 | 52,117 | 18 | 104,234 |
"Correct Solution:
```
while 1:
n=int(input())
if n==0:break
m=int(input())
word=input()
ans=0
pick="IO"*n+"I"
for i in range(m-2*n):
if word[i:i+2*n+1]==pick:ans+=1
print(ans)
``` | output | 1 | 52,117 | 18 | 104,235 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
problem
For the integer n (1 β€ n), let Pn be a string of n + 1 I's and n O's starting with I and alternating, where I and O are the uppercase Ai and O, respectively. is there.
P1 | IOI
--- | ---
P2 | IOIOI
P3 | IOIOIOI
|. |
|. |
|. |
Pn | IOIOIO ... OI (n O)
Figure 1-1 Character string considered in this question Pn
Given the integer n and the string s consisting only of I and O, write a program that outputs how many Pn's are contained in s.
input
The input consists of multiple datasets. Each dataset is given in the following format.
The integer n (1 β€ n β€ 1000000) is written on the first line.
The second line contains the integer m (1 β€ m β€ 1000000). M represents the number of characters in s.
The string s is written on the third line. S consists of only I and O.
For all scoring data, 2n + 1 β€ m. Of the scoring data, 50% of the scoring data satisfies n β€ 100 and m β€ 10000.
When n is 0, it indicates the end of input. The number of datasets does not exceed 10.
output
For each dataset, print one integer on one line that indicates how many strings Pn are contained in the string s. If s does not contain Pn, print 0 as an integer.
Examples
Input
1
13
OOIOIOIOIIOII
2
13
OOIOIOIOIIOII
0
Output
4
2
Input
None
Output
None
Submitted Solution:
```
while 1:
n=int(input())
if n==0:break
a='I'+'OI'*n
b,s,c=int(input()),input(),0
for i in range(b-len(a)):
if s[i:i+len(a)]==a:c+=1
print(c)
``` | instruction | 0 | 52,122 | 18 | 104,244 |
Yes | output | 1 | 52,122 | 18 | 104,245 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
problem
For the integer n (1 β€ n), let Pn be a string of n + 1 I's and n O's starting with I and alternating, where I and O are the uppercase Ai and O, respectively. is there.
P1 | IOI
--- | ---
P2 | IOIOI
P3 | IOIOIOI
|. |
|. |
|. |
Pn | IOIOIO ... OI (n O)
Figure 1-1 Character string considered in this question Pn
Given the integer n and the string s consisting only of I and O, write a program that outputs how many Pn's are contained in s.
input
The input consists of multiple datasets. Each dataset is given in the following format.
The integer n (1 β€ n β€ 1000000) is written on the first line.
The second line contains the integer m (1 β€ m β€ 1000000). M represents the number of characters in s.
The string s is written on the third line. S consists of only I and O.
For all scoring data, 2n + 1 β€ m. Of the scoring data, 50% of the scoring data satisfies n β€ 100 and m β€ 10000.
When n is 0, it indicates the end of input. The number of datasets does not exceed 10.
output
For each dataset, print one integer on one line that indicates how many strings Pn are contained in the string s. If s does not contain Pn, print 0 as an integer.
Examples
Input
1
13
OOIOIOIOIIOII
2
13
OOIOIOIOIIOII
0
Output
4
2
Input
None
Output
None
Submitted Solution:
```
while True:
n = int(input())
if not n: break
m = int(input())
s = input()
ind = 0
ans = 0
while ind < m:
if s[ind] == "I":
count = 0
while ind + 2 < m:
if s[ind + 1] == "O" and s[ind + 2] == "I":
count += 1
ind += 2
else:
break
if count - n + 1 >= 0:
ans += (count - n + 1)
ind += 1
print(ans)
``` | instruction | 0 | 52,123 | 18 | 104,246 |
Yes | output | 1 | 52,123 | 18 | 104,247 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
problem
For the integer n (1 β€ n), let Pn be a string of n + 1 I's and n O's starting with I and alternating, where I and O are the uppercase Ai and O, respectively. is there.
P1 | IOI
--- | ---
P2 | IOIOI
P3 | IOIOIOI
|. |
|. |
|. |
Pn | IOIOIO ... OI (n O)
Figure 1-1 Character string considered in this question Pn
Given the integer n and the string s consisting only of I and O, write a program that outputs how many Pn's are contained in s.
input
The input consists of multiple datasets. Each dataset is given in the following format.
The integer n (1 β€ n β€ 1000000) is written on the first line.
The second line contains the integer m (1 β€ m β€ 1000000). M represents the number of characters in s.
The string s is written on the third line. S consists of only I and O.
For all scoring data, 2n + 1 β€ m. Of the scoring data, 50% of the scoring data satisfies n β€ 100 and m β€ 10000.
When n is 0, it indicates the end of input. The number of datasets does not exceed 10.
output
For each dataset, print one integer on one line that indicates how many strings Pn are contained in the string s. If s does not contain Pn, print 0 as an integer.
Examples
Input
1
13
OOIOIOIOIIOII
2
13
OOIOIOIOIIOII
0
Output
4
2
Input
None
Output
None
Submitted Solution:
```
while True:
n = int(input())
if n == 0:
break
p = "I" + "OI" * n
m = int(input())
s = input()
c = 0
i = 0
while True:
try:
i += s[i:].index(p) + 1
c += 1
except:
print(c)
break
``` | instruction | 0 | 52,124 | 18 | 104,248 |
Yes | output | 1 | 52,124 | 18 | 104,249 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
problem
For the integer n (1 β€ n), let Pn be a string of n + 1 I's and n O's starting with I and alternating, where I and O are the uppercase Ai and O, respectively. is there.
P1 | IOI
--- | ---
P2 | IOIOI
P3 | IOIOIOI
|. |
|. |
|. |
Pn | IOIOIO ... OI (n O)
Figure 1-1 Character string considered in this question Pn
Given the integer n and the string s consisting only of I and O, write a program that outputs how many Pn's are contained in s.
input
The input consists of multiple datasets. Each dataset is given in the following format.
The integer n (1 β€ n β€ 1000000) is written on the first line.
The second line contains the integer m (1 β€ m β€ 1000000). M represents the number of characters in s.
The string s is written on the third line. S consists of only I and O.
For all scoring data, 2n + 1 β€ m. Of the scoring data, 50% of the scoring data satisfies n β€ 100 and m β€ 10000.
When n is 0, it indicates the end of input. The number of datasets does not exceed 10.
output
For each dataset, print one integer on one line that indicates how many strings Pn are contained in the string s. If s does not contain Pn, print 0 as an integer.
Examples
Input
1
13
OOIOIOIOIIOII
2
13
OOIOIOIOIIOII
0
Output
4
2
Input
None
Output
None
Submitted Solution:
```
# AOJ 0538: IOIOI
# Python3 2018.7.1 bal4u
import sys
from sys import stdin
input = stdin.readline
while True:
n = int(input())
if n == 0: break
m = int(input())
s = input().strip()
ans = cnt = i = 0
while i < m:
if i+1 < m and s[i:i+2] == 'IO':
cnt += 1
i += 1
elif cnt > 0:
if s[i] == 'O': cnt -= 1
if cnt >= n: ans += cnt-n+1
cnt = 0
i += 1
print(ans)
``` | instruction | 0 | 52,125 | 18 | 104,250 |
Yes | output | 1 | 52,125 | 18 | 104,251 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
problem
For the integer n (1 β€ n), let Pn be a string of n + 1 I's and n O's starting with I and alternating, where I and O are the uppercase Ai and O, respectively. is there.
P1 | IOI
--- | ---
P2 | IOIOI
P3 | IOIOIOI
|. |
|. |
|. |
Pn | IOIOIO ... OI (n O)
Figure 1-1 Character string considered in this question Pn
Given the integer n and the string s consisting only of I and O, write a program that outputs how many Pn's are contained in s.
input
The input consists of multiple datasets. Each dataset is given in the following format.
The integer n (1 β€ n β€ 1000000) is written on the first line.
The second line contains the integer m (1 β€ m β€ 1000000). M represents the number of characters in s.
The string s is written on the third line. S consists of only I and O.
For all scoring data, 2n + 1 β€ m. Of the scoring data, 50% of the scoring data satisfies n β€ 100 and m β€ 10000.
When n is 0, it indicates the end of input. The number of datasets does not exceed 10.
output
For each dataset, print one integer on one line that indicates how many strings Pn are contained in the string s. If s does not contain Pn, print 0 as an integer.
Examples
Input
1
13
OOIOIOIOIIOII
2
13
OOIOIOIOIIOII
0
Output
4
2
Input
None
Output
None
Submitted Solution:
```
n, m, s= int(input()), int(input()), input()
ioi= "IOI" if n==3 else "IOI"+"OI"*(n-1)
n= 2*n+1
print(sum(1 for i in range(m-n+1) if s[i:i+n]==ioi))
``` | instruction | 0 | 52,126 | 18 | 104,252 |
No | output | 1 | 52,126 | 18 | 104,253 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
problem
For the integer n (1 β€ n), let Pn be a string of n + 1 I's and n O's starting with I and alternating, where I and O are the uppercase Ai and O, respectively. is there.
P1 | IOI
--- | ---
P2 | IOIOI
P3 | IOIOIOI
|. |
|. |
|. |
Pn | IOIOIO ... OI (n O)
Figure 1-1 Character string considered in this question Pn
Given the integer n and the string s consisting only of I and O, write a program that outputs how many Pn's are contained in s.
input
The input consists of multiple datasets. Each dataset is given in the following format.
The integer n (1 β€ n β€ 1000000) is written on the first line.
The second line contains the integer m (1 β€ m β€ 1000000). M represents the number of characters in s.
The string s is written on the third line. S consists of only I and O.
For all scoring data, 2n + 1 β€ m. Of the scoring data, 50% of the scoring data satisfies n β€ 100 and m β€ 10000.
When n is 0, it indicates the end of input. The number of datasets does not exceed 10.
output
For each dataset, print one integer on one line that indicates how many strings Pn are contained in the string s. If s does not contain Pn, print 0 as an integer.
Examples
Input
1
13
OOIOIOIOIIOII
2
13
OOIOIOIOIIOII
0
Output
4
2
Input
None
Output
None
Submitted Solution:
```
# AOJ 0538: IOIOI
# Python3 2018.7.1 bal4u
while True:
n = int(input())
if n == 0: break
m = int(input())
s = input().strip()
ans, cnt, w, i = 0, 0, len(s), -1
while i < w:
i += 1
if i+1 < w and s[i:i+2] == 'IO':
cnt += 1
i += 1
elif cnt > 0:
if s[i] == 'O': cnt -= 1
if cnt >= n: ans += cnt-n+1
cnt = 0
print(ans)
``` | instruction | 0 | 52,127 | 18 | 104,254 |
No | output | 1 | 52,127 | 18 | 104,255 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A one-dimensional Japanese crossword can be represented as a binary string of length x. An encoding of this crossword is an array a of size n, where n is the number of segments formed completely of 1's, and ai is the length of i-th segment. No two segments touch or intersect.
For example:
* If x = 6 and the crossword is 111011, then its encoding is an array {3, 2};
* If x = 8 and the crossword is 01101010, then its encoding is an array {2, 1, 1};
* If x = 5 and the crossword is 11111, then its encoding is an array {5};
* If x = 5 and the crossword is 00000, then its encoding is an empty array.
Mishka wants to create a new one-dimensional Japanese crossword. He has already picked the length and the encoding for this crossword. And now he needs to check if there is exactly one crossword such that its length and encoding are equal to the length and encoding he picked. Help him to check it!
Input
The first line contains two integer numbers n and x (1 β€ n β€ 100000, 1 β€ x β€ 109) β the number of elements in the encoding and the length of the crossword Mishka picked.
The second line contains n integer numbers a1, a2, ..., an (1 β€ ai β€ 10000) β the encoding.
Output
Print YES if there exists exaclty one crossword with chosen length and encoding. Otherwise, print NO.
Examples
Input
2 4
1 3
Output
NO
Input
3 10
3 3 2
Output
YES
Input
2 10
1 3
Output
NO
Submitted Solution:
```
def main():
(n, x) = (int(y) for y in input().split())
A = [int(x) for x in input().split()]
solver(n, x, A)
def solver(n, x, A):
if sum(A) + n - 1 == x:
print("YES")
else:
print("NO")
main()
``` | instruction | 0 | 52,781 | 18 | 105,562 |
Yes | output | 1 | 52,781 | 18 | 105,563 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A one-dimensional Japanese crossword can be represented as a binary string of length x. An encoding of this crossword is an array a of size n, where n is the number of segments formed completely of 1's, and ai is the length of i-th segment. No two segments touch or intersect.
For example:
* If x = 6 and the crossword is 111011, then its encoding is an array {3, 2};
* If x = 8 and the crossword is 01101010, then its encoding is an array {2, 1, 1};
* If x = 5 and the crossword is 11111, then its encoding is an array {5};
* If x = 5 and the crossword is 00000, then its encoding is an empty array.
Mishka wants to create a new one-dimensional Japanese crossword. He has already picked the length and the encoding for this crossword. And now he needs to check if there is exactly one crossword such that its length and encoding are equal to the length and encoding he picked. Help him to check it!
Input
The first line contains two integer numbers n and x (1 β€ n β€ 100000, 1 β€ x β€ 109) β the number of elements in the encoding and the length of the crossword Mishka picked.
The second line contains n integer numbers a1, a2, ..., an (1 β€ ai β€ 10000) β the encoding.
Output
Print YES if there exists exaclty one crossword with chosen length and encoding. Otherwise, print NO.
Examples
Input
2 4
1 3
Output
NO
Input
3 10
3 3 2
Output
YES
Input
2 10
1 3
Output
NO
Submitted Solution:
```
n,x=map(int,input().split())
a=[int(c) for c in input().split()]
su=0
for i in range(n):
su+=a[i]
if x-su==n-1:
print('YES')
else:
print('NO')
``` | instruction | 0 | 52,782 | 18 | 105,564 |
Yes | output | 1 | 52,782 | 18 | 105,565 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A one-dimensional Japanese crossword can be represented as a binary string of length x. An encoding of this crossword is an array a of size n, where n is the number of segments formed completely of 1's, and ai is the length of i-th segment. No two segments touch or intersect.
For example:
* If x = 6 and the crossword is 111011, then its encoding is an array {3, 2};
* If x = 8 and the crossword is 01101010, then its encoding is an array {2, 1, 1};
* If x = 5 and the crossword is 11111, then its encoding is an array {5};
* If x = 5 and the crossword is 00000, then its encoding is an empty array.
Mishka wants to create a new one-dimensional Japanese crossword. He has already picked the length and the encoding for this crossword. And now he needs to check if there is exactly one crossword such that its length and encoding are equal to the length and encoding he picked. Help him to check it!
Input
The first line contains two integer numbers n and x (1 β€ n β€ 100000, 1 β€ x β€ 109) β the number of elements in the encoding and the length of the crossword Mishka picked.
The second line contains n integer numbers a1, a2, ..., an (1 β€ ai β€ 10000) β the encoding.
Output
Print YES if there exists exaclty one crossword with chosen length and encoding. Otherwise, print NO.
Examples
Input
2 4
1 3
Output
NO
Input
3 10
3 3 2
Output
YES
Input
2 10
1 3
Output
NO
Submitted Solution:
```
n,x = [int(i) for i in input().split()]
l = [int(i) for i in input().split()]
if x - sum(l) == n-1:
print('YES')
else:
print('NO')
``` | instruction | 0 | 52,783 | 18 | 105,566 |
Yes | output | 1 | 52,783 | 18 | 105,567 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A one-dimensional Japanese crossword can be represented as a binary string of length x. An encoding of this crossword is an array a of size n, where n is the number of segments formed completely of 1's, and ai is the length of i-th segment. No two segments touch or intersect.
For example:
* If x = 6 and the crossword is 111011, then its encoding is an array {3, 2};
* If x = 8 and the crossword is 01101010, then its encoding is an array {2, 1, 1};
* If x = 5 and the crossword is 11111, then its encoding is an array {5};
* If x = 5 and the crossword is 00000, then its encoding is an empty array.
Mishka wants to create a new one-dimensional Japanese crossword. He has already picked the length and the encoding for this crossword. And now he needs to check if there is exactly one crossword such that its length and encoding are equal to the length and encoding he picked. Help him to check it!
Input
The first line contains two integer numbers n and x (1 β€ n β€ 100000, 1 β€ x β€ 109) β the number of elements in the encoding and the length of the crossword Mishka picked.
The second line contains n integer numbers a1, a2, ..., an (1 β€ ai β€ 10000) β the encoding.
Output
Print YES if there exists exaclty one crossword with chosen length and encoding. Otherwise, print NO.
Examples
Input
2 4
1 3
Output
NO
Input
3 10
3 3 2
Output
YES
Input
2 10
1 3
Output
NO
Submitted Solution:
```
line1 = input().split()
n = int(line1[0])
x = int(line1[1])
line2 = input().split()
length = n-1
for i in range(n):
length += int(line2[i])
if x != length:
print('NO')
else:
print('YES')
``` | instruction | 0 | 52,784 | 18 | 105,568 |
Yes | output | 1 | 52,784 | 18 | 105,569 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A one-dimensional Japanese crossword can be represented as a binary string of length x. An encoding of this crossword is an array a of size n, where n is the number of segments formed completely of 1's, and ai is the length of i-th segment. No two segments touch or intersect.
For example:
* If x = 6 and the crossword is 111011, then its encoding is an array {3, 2};
* If x = 8 and the crossword is 01101010, then its encoding is an array {2, 1, 1};
* If x = 5 and the crossword is 11111, then its encoding is an array {5};
* If x = 5 and the crossword is 00000, then its encoding is an empty array.
Mishka wants to create a new one-dimensional Japanese crossword. He has already picked the length and the encoding for this crossword. And now he needs to check if there is exactly one crossword such that its length and encoding are equal to the length and encoding he picked. Help him to check it!
Input
The first line contains two integer numbers n and x (1 β€ n β€ 100000, 1 β€ x β€ 109) β the number of elements in the encoding and the length of the crossword Mishka picked.
The second line contains n integer numbers a1, a2, ..., an (1 β€ ai β€ 10000) β the encoding.
Output
Print YES if there exists exaclty one crossword with chosen length and encoding. Otherwise, print NO.
Examples
Input
2 4
1 3
Output
NO
Input
3 10
3 3 2
Output
YES
Input
2 10
1 3
Output
NO
Submitted Solution:
```
n,m=map(int,input().split(' '))
a=list(map(int,input().split(' ')))
if sum(a)+(n-1)<=m and m-(sum(a)+(n-1))<=2:
print('Yes')
else:
print('NO')
``` | instruction | 0 | 52,785 | 18 | 105,570 |
No | output | 1 | 52,785 | 18 | 105,571 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A one-dimensional Japanese crossword can be represented as a binary string of length x. An encoding of this crossword is an array a of size n, where n is the number of segments formed completely of 1's, and ai is the length of i-th segment. No two segments touch or intersect.
For example:
* If x = 6 and the crossword is 111011, then its encoding is an array {3, 2};
* If x = 8 and the crossword is 01101010, then its encoding is an array {2, 1, 1};
* If x = 5 and the crossword is 11111, then its encoding is an array {5};
* If x = 5 and the crossword is 00000, then its encoding is an empty array.
Mishka wants to create a new one-dimensional Japanese crossword. He has already picked the length and the encoding for this crossword. And now he needs to check if there is exactly one crossword such that its length and encoding are equal to the length and encoding he picked. Help him to check it!
Input
The first line contains two integer numbers n and x (1 β€ n β€ 100000, 1 β€ x β€ 109) β the number of elements in the encoding and the length of the crossword Mishka picked.
The second line contains n integer numbers a1, a2, ..., an (1 β€ ai β€ 10000) β the encoding.
Output
Print YES if there exists exaclty one crossword with chosen length and encoding. Otherwise, print NO.
Examples
Input
2 4
1 3
Output
NO
Input
3 10
3 3 2
Output
YES
Input
2 10
1 3
Output
NO
Submitted Solution:
```
fl=input()
sl=input()
fl=fl.split()
sl=sl.split()
n=int(fl[0])
x=int(fl[1])
num=0
for i in range(n):
num+=int(sl[i])
if num>=x-n-1 and num<=x-n+1:
print('YES')
else:
print('NO')
``` | instruction | 0 | 52,786 | 18 | 105,572 |
No | output | 1 | 52,786 | 18 | 105,573 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A one-dimensional Japanese crossword can be represented as a binary string of length x. An encoding of this crossword is an array a of size n, where n is the number of segments formed completely of 1's, and ai is the length of i-th segment. No two segments touch or intersect.
For example:
* If x = 6 and the crossword is 111011, then its encoding is an array {3, 2};
* If x = 8 and the crossword is 01101010, then its encoding is an array {2, 1, 1};
* If x = 5 and the crossword is 11111, then its encoding is an array {5};
* If x = 5 and the crossword is 00000, then its encoding is an empty array.
Mishka wants to create a new one-dimensional Japanese crossword. He has already picked the length and the encoding for this crossword. And now he needs to check if there is exactly one crossword such that its length and encoding are equal to the length and encoding he picked. Help him to check it!
Input
The first line contains two integer numbers n and x (1 β€ n β€ 100000, 1 β€ x β€ 109) β the number of elements in the encoding and the length of the crossword Mishka picked.
The second line contains n integer numbers a1, a2, ..., an (1 β€ ai β€ 10000) β the encoding.
Output
Print YES if there exists exaclty one crossword with chosen length and encoding. Otherwise, print NO.
Examples
Input
2 4
1 3
Output
NO
Input
3 10
3 3 2
Output
YES
Input
2 10
1 3
Output
NO
Submitted Solution:
```
n, x = list(map(int, input().split()))
a = list(map(int, input().split()))
t = sum(a)
if t >= x:
print('NO')
else:
if x - n <= t:
print('YES')
else:
print('NO')
``` | instruction | 0 | 52,787 | 18 | 105,574 |
No | output | 1 | 52,787 | 18 | 105,575 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A one-dimensional Japanese crossword can be represented as a binary string of length x. An encoding of this crossword is an array a of size n, where n is the number of segments formed completely of 1's, and ai is the length of i-th segment. No two segments touch or intersect.
For example:
* If x = 6 and the crossword is 111011, then its encoding is an array {3, 2};
* If x = 8 and the crossword is 01101010, then its encoding is an array {2, 1, 1};
* If x = 5 and the crossword is 11111, then its encoding is an array {5};
* If x = 5 and the crossword is 00000, then its encoding is an empty array.
Mishka wants to create a new one-dimensional Japanese crossword. He has already picked the length and the encoding for this crossword. And now he needs to check if there is exactly one crossword such that its length and encoding are equal to the length and encoding he picked. Help him to check it!
Input
The first line contains two integer numbers n and x (1 β€ n β€ 100000, 1 β€ x β€ 109) β the number of elements in the encoding and the length of the crossword Mishka picked.
The second line contains n integer numbers a1, a2, ..., an (1 β€ ai β€ 10000) β the encoding.
Output
Print YES if there exists exaclty one crossword with chosen length and encoding. Otherwise, print NO.
Examples
Input
2 4
1 3
Output
NO
Input
3 10
3 3 2
Output
YES
Input
2 10
1 3
Output
NO
Submitted Solution:
```
a=input().split(' ')
n=int(a[0])
x=int(a[1])
a=input().split(' ')
a=[int(i) for i in a]
if len(a)+sum(a)==x:
print("YES")
exit()
print("NO")
``` | instruction | 0 | 52,788 | 18 | 105,576 |
No | output | 1 | 52,788 | 18 | 105,577 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string of length N. Calculate the number of distinct substrings of S.
Constraints
* 1 \leq N \leq 500,000
* S consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
Print the answer.
Examples
Input
abcbcba
Output
21
Input
mississippi
Output
53
Input
ababacaca
Output
33
Input
aaaaa
Output
5
Submitted Solution:
```
s=input()
c=0
l=[]
for i in range(len(s)):
for j in range(i+1,len(s)+1):
if s[i:j] not in l:
l.append((s[i:j]))
c+=1
print(c)
``` | instruction | 0 | 52,837 | 18 | 105,674 |
No | output | 1 | 52,837 | 18 | 105,675 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice has written a program and now tries to improve its readability. One of the ways to improve readability is to give sensible names to the variables, so now Alice wants to rename some variables in her program. In her IDE there is a command called "massive refactoring", which can replace names of many variable in just one run. To use it, Alice needs to select two strings s and t and after that for each variable the following algorithm is performed: if the variable's name contains s as a substring, then the first (and only first) occurrence of s is replaced with t. If the name doesn't contain s, then this variable's name stays the same.
The list of variables is known and for each variable both the initial name and the name Alice wants this variable change to are known. Moreover, for each variable the lengths of the initial name and the target name are equal (otherwise the alignment of the code could become broken). You need to perform renaming of all variables in exactly one run of the massive refactoring command or determine that it is impossible.
Input
The first line contains the only integer n (1 β€ n β€ 3000) β the number of variables in Alice's program.
The following n lines contain the initial names of variables w_1, w_2, β¦, w_n, one per line. After that, n more lines go, the i-th of them contains the target name w'_i for the i-th variable. It is guaranteed that 1 β€ |w_i| = |w'_i| β€ 3000.
It is guaranteed that there is at least one variable having its target name different from the initial name. Both initial and target names consist of lowercase English letters only. For each variable the length of its initial name is equal to the length of its target name.
Output
If it is impossible to rename all variables with one call of "massive refactoring", print "NO" (quotes for clarity).
Otherwise, on the first line print "YES" (quotes for clarity) and on the following lines print s and t (1 β€ |s|, |t| β€ 5000), which should be used for replacement. Strings s and t should consist only of lowercase letters of English alphabet.
If there are multiple ways to perform a "massive refactoring", you can use any of them.
Examples
Input
1
topforces
codecoder
Output
YES
topforces
codecoder
Input
3
bab
cac
cdc
bdb
cdc
cdc
Output
YES
a
d
Input
2
you
shal
not
pass
Output
NO
Submitted Solution:
```
n = int(input())
a = [0] * n
ansA =ansB = ''
for i in range(n):
a[i] = input()
for i in range(n):
s = input()
cntF=0
cntS=len(s)-1
while cntF<len(s) and s[cntF]==a[i][cntF]:
cntF+=1
while cntS>=0 and s[cntS]==a[i][cntS]:
cntS-=1
if cntF<=cntS:
diffA = a[i][cntF:cntS+1]
diffB = s[cntF:cntS+1]
else:
diffA = diffB = ''
if ansA=='' and ansB=='':
ansA = diffA
ansB = diffB
if diffA!='':
if diffA!=ansA:
print('NO')
exit()
#print(diffA,diffB)
print('YES')
print(ansA,ansB,sep='\n')
``` | instruction | 0 | 53,063 | 18 | 106,126 |
No | output | 1 | 53,063 | 18 | 106,127 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice has written a program and now tries to improve its readability. One of the ways to improve readability is to give sensible names to the variables, so now Alice wants to rename some variables in her program. In her IDE there is a command called "massive refactoring", which can replace names of many variable in just one run. To use it, Alice needs to select two strings s and t and after that for each variable the following algorithm is performed: if the variable's name contains s as a substring, then the first (and only first) occurrence of s is replaced with t. If the name doesn't contain s, then this variable's name stays the same.
The list of variables is known and for each variable both the initial name and the name Alice wants this variable change to are known. Moreover, for each variable the lengths of the initial name and the target name are equal (otherwise the alignment of the code could become broken). You need to perform renaming of all variables in exactly one run of the massive refactoring command or determine that it is impossible.
Input
The first line contains the only integer n (1 β€ n β€ 3000) β the number of variables in Alice's program.
The following n lines contain the initial names of variables w_1, w_2, β¦, w_n, one per line. After that, n more lines go, the i-th of them contains the target name w'_i for the i-th variable. It is guaranteed that 1 β€ |w_i| = |w'_i| β€ 3000.
It is guaranteed that there is at least one variable having its target name different from the initial name. Both initial and target names consist of lowercase English letters only. For each variable the length of its initial name is equal to the length of its target name.
Output
If it is impossible to rename all variables with one call of "massive refactoring", print "NO" (quotes for clarity).
Otherwise, on the first line print "YES" (quotes for clarity) and on the following lines print s and t (1 β€ |s|, |t| β€ 5000), which should be used for replacement. Strings s and t should consist only of lowercase letters of English alphabet.
If there are multiple ways to perform a "massive refactoring", you can use any of them.
Examples
Input
1
topforces
codecoder
Output
YES
topforces
codecoder
Input
3
bab
cac
cdc
bdb
cdc
cdc
Output
YES
a
d
Input
2
you
shal
not
pass
Output
NO
Submitted Solution:
```
n = int(input())
p = []
q = []
for i in range(n):
p.append(input())
for j in range(n):
q.append(input())
s = []
t = []
if n==1:
print("YES")
print(p[0])
print(q[0])
else:
for g in range(n):
for h in range(len(p[g])):
if p[g][h]==q[g][h]:
continue
else:
s.append(p[g][h])
t.append(q[g][h])
for k in range(len(s)-1):
if s[k]!=s[k+1] and t[k]!=t[k-1]:
print("NO")
break
else:
print("YES")
print(s[0])
print(t[0])
``` | instruction | 0 | 53,064 | 18 | 106,128 |
No | output | 1 | 53,064 | 18 | 106,129 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice has written a program and now tries to improve its readability. One of the ways to improve readability is to give sensible names to the variables, so now Alice wants to rename some variables in her program. In her IDE there is a command called "massive refactoring", which can replace names of many variable in just one run. To use it, Alice needs to select two strings s and t and after that for each variable the following algorithm is performed: if the variable's name contains s as a substring, then the first (and only first) occurrence of s is replaced with t. If the name doesn't contain s, then this variable's name stays the same.
The list of variables is known and for each variable both the initial name and the name Alice wants this variable change to are known. Moreover, for each variable the lengths of the initial name and the target name are equal (otherwise the alignment of the code could become broken). You need to perform renaming of all variables in exactly one run of the massive refactoring command or determine that it is impossible.
Input
The first line contains the only integer n (1 β€ n β€ 3000) β the number of variables in Alice's program.
The following n lines contain the initial names of variables w_1, w_2, β¦, w_n, one per line. After that, n more lines go, the i-th of them contains the target name w'_i for the i-th variable. It is guaranteed that 1 β€ |w_i| = |w'_i| β€ 3000.
It is guaranteed that there is at least one variable having its target name different from the initial name. Both initial and target names consist of lowercase English letters only. For each variable the length of its initial name is equal to the length of its target name.
Output
If it is impossible to rename all variables with one call of "massive refactoring", print "NO" (quotes for clarity).
Otherwise, on the first line print "YES" (quotes for clarity) and on the following lines print s and t (1 β€ |s|, |t| β€ 5000), which should be used for replacement. Strings s and t should consist only of lowercase letters of English alphabet.
If there are multiple ways to perform a "massive refactoring", you can use any of them.
Examples
Input
1
topforces
codecoder
Output
YES
topforces
codecoder
Input
3
bab
cac
cdc
bdb
cdc
cdc
Output
YES
a
d
Input
2
you
shal
not
pass
Output
NO
Submitted Solution:
```
a=int(input())
b=[]
c=[]
for i in range(a):
b.append(input())
for i in range(a):
c.append(input())
if a==1 or b==c:
print('YES')
print(b[0])
print(c[0])
else:
for i in range(a):
if b[i]!=c[i]:
l1=0
l2=0
kk=len(b[i])
for j1 in range(kk):
if b[i][j1]!=c[i][j1]:
l1=j1
break
for j in range(kk-1,-1,-1):
if b[i][j]!=c[i][j]:
l2=j
break
m=i
break
s=b[m][l1:l2+1]
t=c[m][l1:l2+1]
f=0
lol=len(s)
for i in range(m+1,a):
b[i]=b[i].replace(s,t,1)
if (b[i]!=c[i]):
f=1
break
if f==1:
print('NO')
else:
print('YES')
print(s)
print(t)
``` | instruction | 0 | 53,065 | 18 | 106,130 |
No | output | 1 | 53,065 | 18 | 106,131 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Alice has written a program and now tries to improve its readability. One of the ways to improve readability is to give sensible names to the variables, so now Alice wants to rename some variables in her program. In her IDE there is a command called "massive refactoring", which can replace names of many variable in just one run. To use it, Alice needs to select two strings s and t and after that for each variable the following algorithm is performed: if the variable's name contains s as a substring, then the first (and only first) occurrence of s is replaced with t. If the name doesn't contain s, then this variable's name stays the same.
The list of variables is known and for each variable both the initial name and the name Alice wants this variable change to are known. Moreover, for each variable the lengths of the initial name and the target name are equal (otherwise the alignment of the code could become broken). You need to perform renaming of all variables in exactly one run of the massive refactoring command or determine that it is impossible.
Input
The first line contains the only integer n (1 β€ n β€ 3000) β the number of variables in Alice's program.
The following n lines contain the initial names of variables w_1, w_2, β¦, w_n, one per line. After that, n more lines go, the i-th of them contains the target name w'_i for the i-th variable. It is guaranteed that 1 β€ |w_i| = |w'_i| β€ 3000.
It is guaranteed that there is at least one variable having its target name different from the initial name. Both initial and target names consist of lowercase English letters only. For each variable the length of its initial name is equal to the length of its target name.
Output
If it is impossible to rename all variables with one call of "massive refactoring", print "NO" (quotes for clarity).
Otherwise, on the first line print "YES" (quotes for clarity) and on the following lines print s and t (1 β€ |s|, |t| β€ 5000), which should be used for replacement. Strings s and t should consist only of lowercase letters of English alphabet.
If there are multiple ways to perform a "massive refactoring", you can use any of them.
Examples
Input
1
topforces
codecoder
Output
YES
topforces
codecoder
Input
3
bab
cac
cdc
bdb
cdc
cdc
Output
YES
a
d
Input
2
you
shal
not
pass
Output
NO
Submitted Solution:
```
# -*- coding:utf-8 -*-
"""
created by shuangquan.huang at 11/13/18
Alice has written a program and now tries to improve its readability.
One of the ways to improve readability is to give sensible names to the variables,
so now Alice wants to rename some variables in her program. In her IDE there is a command called "massive refactoring",
which can replace names of many variable in just one run. To use it, Alice needs to select two strings π and π‘
and after that for each variable the following algorithm is performed:
if the variable's name contains π as a substring, then the first (and only first) occurrence of π is replaced with π‘.
If the name doesn't contain π , then this variable's name stays the same.
The list of variables is known and for each variable both the initial name and the name Alice wants this variable
change to are known. Moreover, for each variable the lengths of the initial name and the target name are equal
(otherwise the alignment of the code could become broken). You need to perform renaming of all variables in exactly one
run of the massive refactoring command or determine that it is impossible.
Input
The first line contains the only integer π (1β€πβ€3000) β the number of variables in Alice's program.
The following π lines contain the initial names of variables π€1,π€2,β¦,π€π, one per line.
After that, π more lines go, the π-th of them contains the target name π€β²π for the π-th variable.
It is guaranteed that 1β€|π€π|=|π€β²π|β€3000.
It is guaranteed that there is at least one variable having its target name different from the initial name.
Both initial and target names consist of lowercase English letters only.
For each variable the length of its initial name is equal to the length of its target name.
Output
If it is impossible to rename all variables with one call of "massive refactoring", print "NO" (quotes for clarity).
Otherwise, on the first line print "YES" (quotes for clarity) and on the following lines print π and π‘ (1β€|π |,|π‘|β€5000),
which should be used for replacement. Strings π and π‘ should consist only of lowercase letters of English alphabet.
If there are multiple ways to perform a "massive refactoring", you can use any of them.
"""
N = int(input())
A, B = [], []
for i in range(N):
A.append(input())
for i in range(N):
B.append(input())
st = []
same = []
for i in range(N):
if A[i] != B[i]:
st.append((A[i], B[i]))
else:
same.append((A[i], B[i]))
s, t = '', ''
for i in range(len(st)):
a, b = st[i]
l, r = 0, len(a)-1
while l < len(a) and a[l] == b[l]:
l += 1
while r >= 0 and a[r] == b[r]:
r -= 1
ts = a[l: r+1]
tt = b[l: r+1]
if len(ts) > len(s):
s = ts
t = tt
left, right = '', ''
for i in range(len(st)):
a, b = st[i]
ai = a.find(s)
if ai < 0:
print('NO')
exit(0)
if a[:ai] + t + a[ai+len(s):] != b:
print('NO')
exit(0)
if left == '':
left = a[:ai][::-1]
else:
x, y = left, a[:ai][::-1]
xi = 0
while xi < len(x) and xi < len(y) and x[xi] == y[xi]:
xi += 1
left = x[:xi]
if right == '':
right = a[ai+len(s):]
else:
x, y = right, a[ai+len(s):]
xi = 0
while xi < len(x) and xi < len(y) and x[xi] == y[xi]:
xi += 1
right = x[:xi]
left = left[::-1]
s = left + s + right
t = left + t + right
if any([a.find(s) >= 0 for a, b in same]):
print('NO')
exit(0)
print('YES')
print(s)
print(t)
``` | instruction | 0 | 53,066 | 18 | 106,132 |
No | output | 1 | 53,066 | 18 | 106,133 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob has a string s consisting of lowercase English letters. He defines s' to be the string after removing all "a" characters from s (keeping all other characters in the same order). He then generates a new string t by concatenating s and s'. In other words, t=s+s' (look at notes for an example).
You are given a string t. Your task is to find some s that Bob could have used to generate t. It can be shown that if an answer exists, it will be unique.
Input
The first line of input contains a string t (1 β€ |t| β€ 10^5) consisting of lowercase English letters.
Output
Print a string s that could have generated t. It can be shown if an answer exists, it is unique. If no string exists, print ":(" (without double quotes, there is no space between the characters).
Examples
Input
aaaaa
Output
aaaaa
Input
aacaababc
Output
:(
Input
ababacacbbcc
Output
ababacac
Input
baba
Output
:(
Note
In the first example, we have s = "aaaaa", and s' = "".
In the second example, no such s can work that will generate the given t.
In the third example, we have s = "ababacac", and s' = "bbcc", and t = s + s' = "ababacacbbcc".
Submitted Solution:
```
def hate_a(t: str):
t_without_a = remove_a(t)
len_t = len(t_without_a)
s_ = t_without_a[:len_t//2] # s'
if len(t_without_a) % 2 != 0:
return ':('
else:
if t_without_a[:len_t//2] != s_:
return ':('
else:
s = t[:len(t)-len(s_)]
# print(t, s, s_)
return s if s+s_ == t else ':('
def remove_a(str_a: str):
str_without_a = ''.join([s for s in str_a if s != 'a'])
# print(str_without_a)
return str_without_a
if __name__ == '__main__':
t = input()
print(hate_a(t))
``` | instruction | 0 | 53,110 | 18 | 106,220 |
Yes | output | 1 | 53,110 | 18 | 106,221 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob has a string s consisting of lowercase English letters. He defines s' to be the string after removing all "a" characters from s (keeping all other characters in the same order). He then generates a new string t by concatenating s and s'. In other words, t=s+s' (look at notes for an example).
You are given a string t. Your task is to find some s that Bob could have used to generate t. It can be shown that if an answer exists, it will be unique.
Input
The first line of input contains a string t (1 β€ |t| β€ 10^5) consisting of lowercase English letters.
Output
Print a string s that could have generated t. It can be shown if an answer exists, it is unique. If no string exists, print ":(" (without double quotes, there is no space between the characters).
Examples
Input
aaaaa
Output
aaaaa
Input
aacaababc
Output
:(
Input
ababacacbbcc
Output
ababacac
Input
baba
Output
:(
Note
In the first example, we have s = "aaaaa", and s' = "".
In the second example, no such s can work that will generate the given t.
In the third example, we have s = "ababacac", and s' = "bbcc", and t = s + s' = "ababacacbbcc".
Submitted Solution:
```
a=input()
s=""
for t in a:
if(t!='a'):
s+=t
k=int(len(s)/2)
if(s==""):
print(a)
elif(s[:k]==s[k:]):
if(a[-k:].count('a')==0):
print(a[:-k])
else:
print(":(")
else:
print(":(")
``` | instruction | 0 | 53,111 | 18 | 106,222 |
Yes | output | 1 | 53,111 | 18 | 106,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob has a string s consisting of lowercase English letters. He defines s' to be the string after removing all "a" characters from s (keeping all other characters in the same order). He then generates a new string t by concatenating s and s'. In other words, t=s+s' (look at notes for an example).
You are given a string t. Your task is to find some s that Bob could have used to generate t. It can be shown that if an answer exists, it will be unique.
Input
The first line of input contains a string t (1 β€ |t| β€ 10^5) consisting of lowercase English letters.
Output
Print a string s that could have generated t. It can be shown if an answer exists, it is unique. If no string exists, print ":(" (without double quotes, there is no space between the characters).
Examples
Input
aaaaa
Output
aaaaa
Input
aacaababc
Output
:(
Input
ababacacbbcc
Output
ababacac
Input
baba
Output
:(
Note
In the first example, we have s = "aaaaa", and s' = "".
In the second example, no such s can work that will generate the given t.
In the third example, we have s = "ababacac", and s' = "bbcc", and t = s + s' = "ababacacbbcc".
Submitted Solution:
```
s=input()
b=''
l=len(s)
flag=0
for i in range(l):
if s[i]!='a':
b=b+s[i]
l1=len(b)
if l1%2==0:
t=l1//2
d=b[:t]
c=s[l-t:]
for j in range(t):
if c[j]!=d[j] or c[j]=='a':
flag=1
break
else:
flag=1
if flag==0:
print(s[:l-t])
else:
print(':(')
``` | instruction | 0 | 53,112 | 18 | 106,224 |
Yes | output | 1 | 53,112 | 18 | 106,225 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob has a string s consisting of lowercase English letters. He defines s' to be the string after removing all "a" characters from s (keeping all other characters in the same order). He then generates a new string t by concatenating s and s'. In other words, t=s+s' (look at notes for an example).
You are given a string t. Your task is to find some s that Bob could have used to generate t. It can be shown that if an answer exists, it will be unique.
Input
The first line of input contains a string t (1 β€ |t| β€ 10^5) consisting of lowercase English letters.
Output
Print a string s that could have generated t. It can be shown if an answer exists, it is unique. If no string exists, print ":(" (without double quotes, there is no space between the characters).
Examples
Input
aaaaa
Output
aaaaa
Input
aacaababc
Output
:(
Input
ababacacbbcc
Output
ababacac
Input
baba
Output
:(
Note
In the first example, we have s = "aaaaa", and s' = "".
In the second example, no such s can work that will generate the given t.
In the third example, we have s = "ababacac", and s' = "bbcc", and t = s + s' = "ababacacbbcc".
Submitted Solution:
```
a=input("")
len_a=0
len_tot=0
flg=False
no_a=dict()
mid=0
for c in a:
if c!='a':
no_a[len_a]=len_tot
len_a+=1
len_tot+=1
if len_a==0:
pass
elif len_a%2!=0:
flg=True
else:
if a[len_tot-1]=='a':
flg=True
else:
mid=len_a//2
mid_index=no_a[mid]
for i in range(mid_index):
if a[i]!='a':
if a[i]!=a[mid_index]:
flg=True
break
mid_index+=1
if flg:
print(":(")
else:
len_s=len_tot-mid
print(a[:len_s])
``` | instruction | 0 | 53,113 | 18 | 106,226 |
Yes | output | 1 | 53,113 | 18 | 106,227 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob has a string s consisting of lowercase English letters. He defines s' to be the string after removing all "a" characters from s (keeping all other characters in the same order). He then generates a new string t by concatenating s and s'. In other words, t=s+s' (look at notes for an example).
You are given a string t. Your task is to find some s that Bob could have used to generate t. It can be shown that if an answer exists, it will be unique.
Input
The first line of input contains a string t (1 β€ |t| β€ 10^5) consisting of lowercase English letters.
Output
Print a string s that could have generated t. It can be shown if an answer exists, it is unique. If no string exists, print ":(" (without double quotes, there is no space between the characters).
Examples
Input
aaaaa
Output
aaaaa
Input
aacaababc
Output
:(
Input
ababacacbbcc
Output
ababacac
Input
baba
Output
:(
Note
In the first example, we have s = "aaaaa", and s' = "".
In the second example, no such s can work that will generate the given t.
In the third example, we have s = "ababacac", and s' = "bbcc", and t = s + s' = "ababacacbbcc".
Submitted Solution:
```
t=input()
a=t.replace("a","");b=len(a)//2
s=a[0:b]
p=len(t)-len(s)
q=t[0:p]
x= len(t)/2;y=(b)+2
if x!=y:
print(":c")
else:
print(q)
``` | instruction | 0 | 53,114 | 18 | 106,228 |
No | output | 1 | 53,114 | 18 | 106,229 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob has a string s consisting of lowercase English letters. He defines s' to be the string after removing all "a" characters from s (keeping all other characters in the same order). He then generates a new string t by concatenating s and s'. In other words, t=s+s' (look at notes for an example).
You are given a string t. Your task is to find some s that Bob could have used to generate t. It can be shown that if an answer exists, it will be unique.
Input
The first line of input contains a string t (1 β€ |t| β€ 10^5) consisting of lowercase English letters.
Output
Print a string s that could have generated t. It can be shown if an answer exists, it is unique. If no string exists, print ":(" (without double quotes, there is no space between the characters).
Examples
Input
aaaaa
Output
aaaaa
Input
aacaababc
Output
:(
Input
ababacacbbcc
Output
ababacac
Input
baba
Output
:(
Note
In the first example, we have s = "aaaaa", and s' = "".
In the second example, no such s can work that will generate the given t.
In the third example, we have s = "ababacac", and s' = "bbcc", and t = s + s' = "ababacacbbcc".
Submitted Solution:
```
a=input("")
len_l=0
len_tot=0
no_a=[]
flg=False
for c in a:
if c!='a':
no_a.append(c)
len_l+=1
len_tot+=1
if len_l%2!=0:
print(":(")
else:
mid=len_l//2
for i in range(mid):
if no_a[i]!=no_a[i+mid]:
print(":(")
flg=True
break
if not flg:
len_s=len_tot-mid
print(a[:len_s])
``` | instruction | 0 | 53,115 | 18 | 106,230 |
No | output | 1 | 53,115 | 18 | 106,231 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob has a string s consisting of lowercase English letters. He defines s' to be the string after removing all "a" characters from s (keeping all other characters in the same order). He then generates a new string t by concatenating s and s'. In other words, t=s+s' (look at notes for an example).
You are given a string t. Your task is to find some s that Bob could have used to generate t. It can be shown that if an answer exists, it will be unique.
Input
The first line of input contains a string t (1 β€ |t| β€ 10^5) consisting of lowercase English letters.
Output
Print a string s that could have generated t. It can be shown if an answer exists, it is unique. If no string exists, print ":(" (without double quotes, there is no space between the characters).
Examples
Input
aaaaa
Output
aaaaa
Input
aacaababc
Output
:(
Input
ababacacbbcc
Output
ababacac
Input
baba
Output
:(
Note
In the first example, we have s = "aaaaa", and s' = "".
In the second example, no such s can work that will generate the given t.
In the third example, we have s = "ababacac", and s' = "bbcc", and t = s + s' = "ababacacbbcc".
Submitted Solution:
```
s = input()
n = 0
for ch in s:
if ch == 'a':
n += 1
i = 0
j = (len(s) - n) // 2 + n
k = j
while i < k:
if s[i] == 'a':
i += 1
continue
if s[i] != s[j]:
break
i += 1
j += 1
if i == k:
print(s[:k])
else:
print(':(')
``` | instruction | 0 | 53,116 | 18 | 106,232 |
No | output | 1 | 53,116 | 18 | 106,233 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Bob has a string s consisting of lowercase English letters. He defines s' to be the string after removing all "a" characters from s (keeping all other characters in the same order). He then generates a new string t by concatenating s and s'. In other words, t=s+s' (look at notes for an example).
You are given a string t. Your task is to find some s that Bob could have used to generate t. It can be shown that if an answer exists, it will be unique.
Input
The first line of input contains a string t (1 β€ |t| β€ 10^5) consisting of lowercase English letters.
Output
Print a string s that could have generated t. It can be shown if an answer exists, it is unique. If no string exists, print ":(" (without double quotes, there is no space between the characters).
Examples
Input
aaaaa
Output
aaaaa
Input
aacaababc
Output
:(
Input
ababacacbbcc
Output
ababacac
Input
baba
Output
:(
Note
In the first example, we have s = "aaaaa", and s' = "".
In the second example, no such s can work that will generate the given t.
In the third example, we have s = "ababacac", and s' = "bbcc", and t = s + s' = "ababacacbbcc".
Submitted Solution:
```
s=input()
li=s.replace('a','')
if(s[-1]=='a'):
if(s!='a'*len(s)):
print(':(')
else:
print(s)
elif(len(li)%2!=0):
print(':(')
else:
if(li[:int(len(li)/2)]!=li[int(len(li)/2):]):
print(':(')
else:
dob=li[:int(len(li)/2)]
print(s.replace(dob,''))
``` | instruction | 0 | 53,117 | 18 | 106,234 |
No | output | 1 | 53,117 | 18 | 106,235 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM | instruction | 0 | 53,687 | 18 | 107,374 |
"Correct Solution:
```
N=int(input())
S=input()
ANS=""
for i in range(len(S)):
ANS+=chr(65+((ord(S[i])+N)-65)%26)
print(ANS)
``` | output | 1 | 53,687 | 18 | 107,375 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM | instruction | 0 | 53,688 | 18 | 107,376 |
"Correct Solution:
```
n = int(input())
s = input()
print(''.join([chr(65+(ord(t)+n)%65%26) for t in s]))
``` | output | 1 | 53,688 | 18 | 107,377 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM | instruction | 0 | 53,689 | 18 | 107,378 |
"Correct Solution:
```
n = int(input())
s = input()
print(''.join([chr((ord(c)+n)-26*(ord(c)+n>90)) for c in s]))
``` | output | 1 | 53,689 | 18 | 107,379 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM | instruction | 0 | 53,690 | 18 | 107,380 |
"Correct Solution:
```
N=int(input())
S=input()
T=""
for i in S:
T=T+chr((((ord(i)-65)+N)%26)+65)
print(T)
``` | output | 1 | 53,690 | 18 | 107,381 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM | instruction | 0 | 53,691 | 18 | 107,382 |
"Correct Solution:
```
N = int(input())
S = input()
for s in S:
print(chr(65+(ord(s)+N-65)%26),end="")
``` | output | 1 | 53,691 | 18 | 107,383 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM | instruction | 0 | 53,692 | 18 | 107,384 |
"Correct Solution:
```
n=int(input())
s=input()
ans=''
for i in range(len(s)):
ans+=chr((ord(s[i])-65+n)%26+65)
print(ans)
``` | output | 1 | 53,692 | 18 | 107,385 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM | instruction | 0 | 53,693 | 18 | 107,386 |
"Correct Solution:
```
n = int(input())
print(''.join([chr(((ord(c) - ord('A') + n) % 26) + ord('A')) for c in input()]))
``` | output | 1 | 53,693 | 18 | 107,387 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM | instruction | 0 | 53,694 | 18 | 107,388 |
"Correct Solution:
```
N = int(input())
S = input()
ans = [chr((ord(i)-65 +N) % 26 + 65) for i in S]
print(''.join(ans))
``` | output | 1 | 53,694 | 18 | 107,389 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM
Submitted Solution:
```
n = int(input())
print(''.join(map(lambda x: chr((ord(x) + n + 13) % 26 + 65), input())))
``` | instruction | 0 | 53,695 | 18 | 107,390 |
Yes | output | 1 | 53,695 | 18 | 107,391 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM
Submitted Solution:
```
n=int(input())
s=input()
ans=""
for i in range(len(s)):
ans+=chr((ord(s[i])+n-65)%26+65)
print(ans)
``` | instruction | 0 | 53,696 | 18 | 107,392 |
Yes | output | 1 | 53,696 | 18 | 107,393 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM
Submitted Solution:
```
n = int(input())
s = input()
S=""
for i in range(len(s)):
S+=chr((ord(s[i])+n-65)%26+65)
print(S)
``` | instruction | 0 | 53,697 | 18 | 107,394 |
Yes | output | 1 | 53,697 | 18 | 107,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM
Submitted Solution:
```
N = int(input())
S = input()
print(''.join(chr((ord(c) - ord('A') + N) % 26 + ord('A')) for c in S))
``` | instruction | 0 | 53,698 | 18 | 107,396 |
Yes | output | 1 | 53,698 | 18 | 107,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM
Submitted Solution:
```
A=['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O',
'P','Q','R','S','T','U','V','W','X','Y','Z']
N=int(input())
x=input()
X=[j for j in x]
for i in range(0,len(X)):
n=(A.index(X[i])+N)%26
X[i]=A[n]
print(X)
``` | instruction | 0 | 53,699 | 18 | 107,398 |
No | output | 1 | 53,699 | 18 | 107,399 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM
Submitted Solution:
```
rot = int(input())
strlist = list(input())
def shift(char, rot):
str = ["A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K",
"L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V",
"W", "X", "Y", "Z"]
index = str.index(char)
index = (index + rot) % 25
return str[index]
ret = []
for c in strlist:
ret.append(shift(c, rot))
print("".join(ret))
``` | instruction | 0 | 53,700 | 18 | 107,400 |
No | output | 1 | 53,700 | 18 | 107,401 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM
Submitted Solution:
```
n = int(input())
moji = str(input())
alphabet = ["A", "B", "C", "D", "E", "F", "G", "H", "I", "J", "K", "L", "M", "N", "O", "P", "Q", "R", "S", "T", "U", "V", "W", "X", "Y", "Z"]
lst = list(moji)
for i in range(len(lst)):
num = alphabet.index(lst[i])
if i + n > 25:
lst[i] = alphabet[i+n-26]
else:
lst[i] = alphabet[i+n]
ans = ""
for j in range(len(lst)):
ans += lst[j]
print(ans)
``` | instruction | 0 | 53,701 | 18 | 107,402 |
No | output | 1 | 53,701 | 18 | 107,403 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string S consisting of uppercase English letters. Additionally, an integer N will be given.
Shift each character of S by N in alphabetical order (see below), and print the resulting string.
We assume that `A` follows `Z`. For example, shifting `A` by 2 results in `C` (`A` \to `B` \to `C`), and shifting `Y` by 3 results in `B` (`Y` \to `Z` \to `A` \to `B`).
Constraints
* 0 \leq N \leq 26
* 1 \leq |S| \leq 10^4
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
N
S
Output
Print the string resulting from shifting each character of S by N in alphabetical order.
Examples
Input
2
ABCXYZ
Output
CDEZAB
Input
0
ABCXYZ
Output
ABCXYZ
Input
13
ABCDEFGHIJKLMNOPQRSTUVWXYZ
Output
NOPQRSTUVWXYZABCDEFGHIJKLM
Submitted Solution:
```
a=int(input())
alp=input()
x=""
for i in range(len(alp)):
f=a+ord(alp[i])
x+=chr(f)
print(x)
``` | instruction | 0 | 53,702 | 18 | 107,404 |
No | output | 1 | 53,702 | 18 | 107,405 |
Provide a correct Python 3 solution for this coding contest problem.
ABC Gene
There is a gene sequence represented by the string `ABC`. You can rewrite this gene sequence by performing the following operations several times.
* Choose one of the letters `A`,` B`, `C`. Let this be x. Replace all x in the gene sequence with `ABC` at the same time.
Given a string S consisting only of `A`,` B`, and `C`. Determine if the gene sequence can be matched to S.
Constraints
* 1 β€ | S | β€ 5,000
* S consists only of `A`,` B`, and `C`.
Input Format
Input is given from standard input in the following format.
S
Output Format
Output `Yes` if the gene sequence can be matched to S, and` No` if it cannot be matched.
Sample Input 1
ABC
Sample Output 1
Yes
The gene sequence is `ABC` from the beginning.
Sample Input 2
AABCC
Sample Output 2
Yes
If you select `B` and perform the operation, it becomes` ABC` β `AABCC`.
Sample Input 3
AABCABC
Sample Output 3
No
For example, even if you select `C` and perform an operation, it does not change from` AABCC` to `AABCABC`. Since all `C`s are replaced with` ABC` at the same time, the actual result is `AABCC` β` AABABCABC`.
Example
Input
ABC
Output
Yes | instruction | 0 | 53,881 | 18 | 107,762 |
"Correct Solution:
```
# coding: utf-8
moto=input()
s=moto
gene='ABC'
f=True
log=[]
while len(s)>3 and f:
f=False
if s[:3]=='ABC':
s=s.replace('ABC','A')
log.append('A')
f=True
elif s[len(s)-3:]=='ABC':
s=s.replace('ABC','C')
log.append('C')
f=True
elif 'ABC' in s:
s=s.replace('ABC','B')
log.append('B')
f=True
if s!=gene:
print('No')
exit()
l=len(log)
for i in range(l):
s=s.replace(log[l-1-i],'ABC')
if s==moto:
print('Yes')
else:
print('No')
``` | output | 1 | 53,881 | 18 | 107,763 |
Provide a correct Python 3 solution for this coding contest problem.
ABC Gene
There is a gene sequence represented by the string `ABC`. You can rewrite this gene sequence by performing the following operations several times.
* Choose one of the letters `A`,` B`, `C`. Let this be x. Replace all x in the gene sequence with `ABC` at the same time.
Given a string S consisting only of `A`,` B`, and `C`. Determine if the gene sequence can be matched to S.
Constraints
* 1 β€ | S | β€ 5,000
* S consists only of `A`,` B`, and `C`.
Input Format
Input is given from standard input in the following format.
S
Output Format
Output `Yes` if the gene sequence can be matched to S, and` No` if it cannot be matched.
Sample Input 1
ABC
Sample Output 1
Yes
The gene sequence is `ABC` from the beginning.
Sample Input 2
AABCC
Sample Output 2
Yes
If you select `B` and perform the operation, it becomes` ABC` β `AABCC`.
Sample Input 3
AABCABC
Sample Output 3
No
For example, even if you select `C` and perform an operation, it does not change from` AABCC` to `AABCABC`. Since all `C`s are replaced with` ABC` at the same time, the actual result is `AABCC` β` AABABCABC`.
Example
Input
ABC
Output
Yes | instruction | 0 | 53,882 | 18 | 107,764 |
"Correct Solution:
```
target=input()
list_abc=["A","B","C"]
old=[]
new=[]
check=[]
flag=False
if "ABC" in target:
old.append([target,[]])
while old !=[] and flag==False:
for i in old:
if i[0]=="ABC":
check.append(i[1])
flag=True
break
for j in list_abc:
element=i[0].replace("ABC",j)
if "ABC" in element:
new.append([element,i[1]+[j]])
else:
old=new[:]
new=[]
flag=False
for i in check:
abc="ABC"
li=i
li.reverse()
for j in li:
abc=abc.replace(j,"ABC")
if abc==target:
flag=True
print("Yes" if flag==True else "No")
``` | output | 1 | 53,882 | 18 | 107,765 |
Provide a correct Python 3 solution for this coding contest problem.
ABC Gene
There is a gene sequence represented by the string `ABC`. You can rewrite this gene sequence by performing the following operations several times.
* Choose one of the letters `A`,` B`, `C`. Let this be x. Replace all x in the gene sequence with `ABC` at the same time.
Given a string S consisting only of `A`,` B`, and `C`. Determine if the gene sequence can be matched to S.
Constraints
* 1 β€ | S | β€ 5,000
* S consists only of `A`,` B`, and `C`.
Input Format
Input is given from standard input in the following format.
S
Output Format
Output `Yes` if the gene sequence can be matched to S, and` No` if it cannot be matched.
Sample Input 1
ABC
Sample Output 1
Yes
The gene sequence is `ABC` from the beginning.
Sample Input 2
AABCC
Sample Output 2
Yes
If you select `B` and perform the operation, it becomes` ABC` β `AABCC`.
Sample Input 3
AABCABC
Sample Output 3
No
For example, even if you select `C` and perform an operation, it does not change from` AABCC` to `AABCABC`. Since all `C`s are replaced with` ABC` at the same time, the actual result is `AABCC` β` AABABCABC`.
Example
Input
ABC
Output
Yes | instruction | 0 | 53,883 | 18 | 107,766 |
"Correct Solution:
```
s = input()
end = "ABC"
while True:
if s == end:
print("Yes")
break
s = s.replace(end, "X")
if ("X" not in s) or sum((c in s for c in end)) != 2:
print("No")
break
for c in end:
if c not in s:
s = s.replace("X", c)
break
``` | output | 1 | 53,883 | 18 | 107,767 |
Provide a correct Python 3 solution for this coding contest problem.
ABC Gene
There is a gene sequence represented by the string `ABC`. You can rewrite this gene sequence by performing the following operations several times.
* Choose one of the letters `A`,` B`, `C`. Let this be x. Replace all x in the gene sequence with `ABC` at the same time.
Given a string S consisting only of `A`,` B`, and `C`. Determine if the gene sequence can be matched to S.
Constraints
* 1 β€ | S | β€ 5,000
* S consists only of `A`,` B`, and `C`.
Input Format
Input is given from standard input in the following format.
S
Output Format
Output `Yes` if the gene sequence can be matched to S, and` No` if it cannot be matched.
Sample Input 1
ABC
Sample Output 1
Yes
The gene sequence is `ABC` from the beginning.
Sample Input 2
AABCC
Sample Output 2
Yes
If you select `B` and perform the operation, it becomes` ABC` β `AABCC`.
Sample Input 3
AABCABC
Sample Output 3
No
For example, even if you select `C` and perform an operation, it does not change from` AABCC` to `AABCABC`. Since all `C`s are replaced with` ABC` at the same time, the actual result is `AABCC` β` AABABCABC`.
Example
Input
ABC
Output
Yes | instruction | 0 | 53,884 | 18 | 107,768 |
"Correct Solution:
```
s = input()
end = "ABC"
while True:
if s == end:
print("Yes")
break
s = s.replace("ABC", "X")
if ("X" not in s) or ("A" in s) + ("B" in s) + ("C" in s) != 2:
print("No")
break
for c in "ABC":
if c not in s:
s = s.replace("X", c)
break
``` | output | 1 | 53,884 | 18 | 107,769 |
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