message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A gene is a string consisting of `A`,` T`, `G`,` C`. The genes in this world are strangely known to obey certain syntactic rules.
Syntax rules are given in the following form:
Non-terminal symbol 1: Symbol 1_1 Symbol 1_2 ... Symbol 1_n1
Non-terminal symbol 2: Symbol 2_1 Symbol 2_2 ... Symbol 2_n2
...
Non-terminal symbol m: symbol m_1 symbol m_2 ... symbol m_nm
The symbol is either a nonterminal symbol or a terminal symbol. Non-terminal symbols are represented by lowercase strings, and terminal symbols are some of the characters `A`,` T`, `G`,` C` surrounded by "` [` "and" `]` ". It is represented by a character string.
An example syntax rule looks like this:
dna: a a b b
a: [AT]
b: [GC]
"` Nonterminal symbol i: Symbol i_1 Symbol i_2 ... Symbol i_ni` "is called a rule for nonterminal symbol i, and there is exactly one rule for each nonterminal symbol that appears in the syntax rule.
A string s "` matches `" with the nonterminal i means that there is a substring {sj} of s such that s = s1 + s2 + ... + sni, and sj (1 ≤ j ≤ It means that ni) matches the symbol j in the rule.
When the string s "` matches `" with a terminal symbol, it means that the string consists of one character and that character is included in the string representing the terminal symbol.
A string that follows syntax rules means that it matches nonterminal symbol 1.
Rule i does not include the nonterminal symbol j (j ≤ i) in the symbol.
Given the syntax rules and the four integers Na, Nt, Ng, Nc. According to the syntax rules, find the remainder of the total number of genes that contain exactly Na for A, just Nt for T, just Ng for G, and just Nc for C, divided by 1,000,000,007.
Input
> Na Nt Ng Nc
> m
> Nonterminal 1: Symbol 11 Symbol 12 ... Symbol 1n1
> Non-terminal symbol 2: Symbol 21 Symbol 22 ... Symbol 2n2
> ...
> Non-terminal symbol m: symbol m1 symbol m2 ... symbol mnm
>
0 ≤ Na, Nt, Ng, Nc ≤ 50
1 ≤ m ≤ 50
1 ≤ ni ≤ 10
1 ≤ Length of the character string representing the symbol ≤ 20 (* Note that it is not the length of the character string that matches the symbol)
Output
The remainder of the total number divided by 1,000,000,007
Examples
Input
1 0 1 0
3
dna: a b
a: [AT]
b: [GC]
Output
1
Input
1 1 1 2
1
k: [ATG] [ATG] [ATG] [C] [C]
Output
6
Input
3 1 1 1
3
inv: at b b b
at: [ATG] b
b: [C]
Output
0
Submitted Solution:
```
table= {}
def solve(dict,key):
global table
if key in table:
# print('key=',key)
return table[key]
ret = []
#print(key)
for i in dict[key]:
if i[0] == '[':
ret.append(i[1:-1])
else:
ret += (solve(dict, i))
if len(ret) > 200:
for i in table.keys():
table[i]=''
return ''
table[key] = ret
#print(key)
return ret
Na, Nt, Ng, Nc = [int(i) for i in input().split()]
m = int(input())
dict = {}
for i in range(m):
key, value = [i for i in input().split(': ')]
if i == 0:
aa = key
value = value.split()
dict[key] = value
lis = solve(dict, aa)
if len(lis)==Na+Nt+Ng+Nc:
DP = [[[[0 for i in range(Nc+1)] for j in range(Ng+1)]for k in range(Nt+1)]for l in range(Na+1)]
#DPN = [[[0 for j in range(Ng+1)]for k in range(Nt+1)]for l in range(Na+1)]
#print(DP[4])
DP[0][0][0][0] = 1
# print(DPC)
#print(DP)
for i in range(len(lis)):
hA=hT=hG=hC=False
#print(i)
for char in lis[i]:
if char == 'A':
hA = True
elif char == 'G':
hG = True
elif char == 'T':
hT = True
else:
hC = True
# print(hA,hT,hG,hC)
for a in range(i+1):
if a > Na:
break
for t in range(i-a+1):
if t > Nt:
break
for g in range(i-a-t+1):
if g > Ng:
break
# print(i,a,t,g)
c = i-a-t-g
if c > Nc:
continue
ans = DP[a][t][g][c] % 1000000007
# print(ans)
if hA and a+1 <= Na:
DP[a+1][t][g][c] += ans
# print(DP[i+1][a+1][t][g])
if hT and t+1 <= Nt:
# print(i)
DP[a][t+1][g][c] += ans
if hG and g+1 <= Ng:
#print(i)
DP[a][t][g+1][c] += ans
if hC and c+1 <= Nc:
#print(i)
DP[a][t][g][c+1] += ans
# print(DPC)
#DP[i][a][t][g] = ans % 1000000007
#DPC = DPN
#DPN = [[[0 for j in range(Ng+1)]for k in range(Nt+1)]for l in range(Na+1)]
print(DP[Na][Nt][Ng][Nc]%1000000007)
else:
print(0)
``` | instruction | 0 | 55,557 | 18 | 111,114 |
No | output | 1 | 55,557 | 18 | 111,115 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A gene is a string consisting of `A`,` T`, `G`,` C`. The genes in this world are strangely known to obey certain syntactic rules.
Syntax rules are given in the following form:
Non-terminal symbol 1: Symbol 1_1 Symbol 1_2 ... Symbol 1_n1
Non-terminal symbol 2: Symbol 2_1 Symbol 2_2 ... Symbol 2_n2
...
Non-terminal symbol m: symbol m_1 symbol m_2 ... symbol m_nm
The symbol is either a nonterminal symbol or a terminal symbol. Non-terminal symbols are represented by lowercase strings, and terminal symbols are some of the characters `A`,` T`, `G`,` C` surrounded by "` [` "and" `]` ". It is represented by a character string.
An example syntax rule looks like this:
dna: a a b b
a: [AT]
b: [GC]
"` Nonterminal symbol i: Symbol i_1 Symbol i_2 ... Symbol i_ni` "is called a rule for nonterminal symbol i, and there is exactly one rule for each nonterminal symbol that appears in the syntax rule.
A string s "` matches `" with the nonterminal i means that there is a substring {sj} of s such that s = s1 + s2 + ... + sni, and sj (1 ≤ j ≤ It means that ni) matches the symbol j in the rule.
When the string s "` matches `" with a terminal symbol, it means that the string consists of one character and that character is included in the string representing the terminal symbol.
A string that follows syntax rules means that it matches nonterminal symbol 1.
Rule i does not include the nonterminal symbol j (j ≤ i) in the symbol.
Given the syntax rules and the four integers Na, Nt, Ng, Nc. According to the syntax rules, find the remainder of the total number of genes that contain exactly Na for A, just Nt for T, just Ng for G, and just Nc for C, divided by 1,000,000,007.
Input
> Na Nt Ng Nc
> m
> Nonterminal 1: Symbol 11 Symbol 12 ... Symbol 1n1
> Non-terminal symbol 2: Symbol 21 Symbol 22 ... Symbol 2n2
> ...
> Non-terminal symbol m: symbol m1 symbol m2 ... symbol mnm
>
0 ≤ Na, Nt, Ng, Nc ≤ 50
1 ≤ m ≤ 50
1 ≤ ni ≤ 10
1 ≤ Length of the character string representing the symbol ≤ 20 (* Note that it is not the length of the character string that matches the symbol)
Output
The remainder of the total number divided by 1,000,000,007
Examples
Input
1 0 1 0
3
dna: a b
a: [AT]
b: [GC]
Output
1
Input
1 1 1 2
1
k: [ATG] [ATG] [ATG] [C] [C]
Output
6
Input
3 1 1 1
3
inv: at b b b
at: [ATG] b
b: [C]
Output
0
Submitted Solution:
```
table= {}
def solve(dict,key):
global table
if key in table:
# print('key=',key)
return table[key]
ret = []
#print(key)
for i in dict[key]:
if i[0] == '[':
ret.append(i[1:-1])
else:
ret += (solve(dict, i))
if len(ret) > 200:
for i in table.keys():
table[i]=''
return ''
table[key] = ret
#print(key)
return ret
Na, Nt, Ng, Nc = [int(i) for i in input().split()]
m = int(input())
dict = {}
for i in range(m):
key, value = [i for i in input().split(': ')]
if i == 0:
aa = key
value = value.split()
dict[key] = value
lis = solve(dict, aa)
if len(lis)==Na+Nt+Ng+Nc:
DP = [[[[0 for i in range(Nc+1)]for j in range(Ng+1)]for k in range(N+1)]for l in range(len(lis)+1)]
#print(DP[4])
DP[0][0][0][0] = 1
#print(DP)
for i in range(len(lis)):
str = lis[i]
for a in range(i+1):
if a > Na:
break
for t in range(i-a+1):
if t > Nt:
break
for g in range(i-a-t+1):
if g > Ng:
break
# print(i,a,t,g)
if i-a-t-g > Nc:
continue
ans = DP[a][t][g][c] % 1000000007
# print(ans)
for char in str:
# print(i,a,t,g)
if char == 'A':
if a+1 > Na:
continue
DP[a+1][t][g][c] += ans
elif char == 'T':
if t+1 > Nt:
continue
DP[a][t+1][g][c] += ans
elif char == 'G':
if g+1 > Ng:
continue
DP[a][t][g+1][c] += ans
elif char == 'C':
if i-a-t-g+1> Nc:
continue
DP[a][t][g][c+1] += ans
# print(DP)
#DP[i][a][t][g] = ans % 1000000007
print(DP[len(lis)][Na][Nt][Ng]%1000000007)
else:
print(0)
``` | instruction | 0 | 55,558 | 18 | 111,116 |
No | output | 1 | 55,558 | 18 | 111,117 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A gene is a string consisting of `A`,` T`, `G`,` C`. The genes in this world are strangely known to obey certain syntactic rules.
Syntax rules are given in the following form:
Non-terminal symbol 1: Symbol 1_1 Symbol 1_2 ... Symbol 1_n1
Non-terminal symbol 2: Symbol 2_1 Symbol 2_2 ... Symbol 2_n2
...
Non-terminal symbol m: symbol m_1 symbol m_2 ... symbol m_nm
The symbol is either a nonterminal symbol or a terminal symbol. Non-terminal symbols are represented by lowercase strings, and terminal symbols are some of the characters `A`,` T`, `G`,` C` surrounded by "` [` "and" `]` ". It is represented by a character string.
An example syntax rule looks like this:
dna: a a b b
a: [AT]
b: [GC]
"` Nonterminal symbol i: Symbol i_1 Symbol i_2 ... Symbol i_ni` "is called a rule for nonterminal symbol i, and there is exactly one rule for each nonterminal symbol that appears in the syntax rule.
A string s "` matches `" with the nonterminal i means that there is a substring {sj} of s such that s = s1 + s2 + ... + sni, and sj (1 ≤ j ≤ It means that ni) matches the symbol j in the rule.
When the string s "` matches `" with a terminal symbol, it means that the string consists of one character and that character is included in the string representing the terminal symbol.
A string that follows syntax rules means that it matches nonterminal symbol 1.
Rule i does not include the nonterminal symbol j (j ≤ i) in the symbol.
Given the syntax rules and the four integers Na, Nt, Ng, Nc. According to the syntax rules, find the remainder of the total number of genes that contain exactly Na for A, just Nt for T, just Ng for G, and just Nc for C, divided by 1,000,000,007.
Input
> Na Nt Ng Nc
> m
> Nonterminal 1: Symbol 11 Symbol 12 ... Symbol 1n1
> Non-terminal symbol 2: Symbol 21 Symbol 22 ... Symbol 2n2
> ...
> Non-terminal symbol m: symbol m1 symbol m2 ... symbol mnm
>
0 ≤ Na, Nt, Ng, Nc ≤ 50
1 ≤ m ≤ 50
1 ≤ ni ≤ 10
1 ≤ Length of the character string representing the symbol ≤ 20 (* Note that it is not the length of the character string that matches the symbol)
Output
The remainder of the total number divided by 1,000,000,007
Examples
Input
1 0 1 0
3
dna: a b
a: [AT]
b: [GC]
Output
1
Input
1 1 1 2
1
k: [ATG] [ATG] [ATG] [C] [C]
Output
6
Input
3 1 1 1
3
inv: at b b b
at: [ATG] b
b: [C]
Output
0
Submitted Solution:
```
table= {}
def solve(dict,key):
global table
if key in table:
# print('key=',key)
return table[key]
ret = []
#print(key)
for i in dict[key]:
if i[0] == '[':
ret.append(i[1:-1])
else:
ret += (solve(dict, i))
if len(ret) > 200:
for i in table.keys():
table[i]=''
return ''
table[key] = ret
#print(key)
return ret
Na, Nt, Ng, Nc = [int(i) for i in input().split()]
m = int(input())
dict = {}
for i in range(m):
key, value = [i for i in input().split(': ')]
if i == 0:
aa = key
value = value.split()
dict[key] = value
lis = solve(dict, aa)
if len(lis)==Na+Nt+Ng+Nc:
DPC = [[[0 for j in range(Ng+1)]for k in range(Nt+1)]for l in range(Na+1)]
DPN = [[[0 for j in range(Ng+1)]for k in range(Nt+1)]for l in range(Na+1)]
#print(DP[4])
DPC[0][0][0] = 1
#print(DP)
for i in range(len(lis)):
str = lis[i]
for a in range(i+1):
if a > Na:
break
for t in range(i-a+1):
if t > Nt:
break
for g in range(i-a-t+1):
if g > Ng:
break
# print(i,a,t,g)
if i-a-t-g > Nc:
continue
ans = DPC[a][t][g] % 1000000007
# print(ans)
for char in str:
# print(i,a,t,g)
if char == 'A':
if a+1 > Na:
continue
# print(i,a,t,g)
DPN[a+1][t][g] += ans
# print(DP[i+1][a+1][t][g])
elif char == 'T':
if t+1 > Nt:
continue
# print(i)
DPN[a][t+1][g] += ans
elif char == 'G':
if g+1 > Ng:
continue
#print(i)
DPN[a][t][g+1] += ans
elif char == 'C':
if i-a-t-g+1> Nc:
continue
#print(i)
DPN[a][t][g] += ans
# print(DP)
#DP[i][a][t][g] = ans % 1000000007
DPC = DPN
DPN = [[[0 for j in range(Ng+1)]for k in range(Nt+1)]for l in range(Na+1)]
print(DPC[Na][Nt][Ng]%1000000007)
else:
print(0)
``` | instruction | 0 | 55,559 | 18 | 111,118 |
No | output | 1 | 55,559 | 18 | 111,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium.
The scales is in equilibrium if the total sum of weights on the left pan is equal to the total sum of weights on the right pan.
Input
The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol "|" indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially on the left pan of the scale. All weights that are recorded in the sequence after the delimiter are initially on the right pan of the scale.
The second line contains a non-empty sequence containing uppercase English letters. Each letter indicates a weight which is not used yet.
It is guaranteed that all the English letters in the input data are different. It is guaranteed that the input does not contain any extra characters.
Output
If you cannot put all the weights on the scales so that the scales were in equilibrium, print string "Impossible". Otherwise, print the description of the resulting scales, copy the format of the input.
If there are multiple answers, print any of them.
Examples
Input
AC|T
L
Output
AC|TL
Input
|ABC
XYZ
Output
XYZ|ABC
Input
W|T
F
Output
Impossible
Input
ABC|
D
Output
Impossible
Submitted Solution:
```
s1 = input().split('|')
s2 = input()
for i in s2 :
if len(s1[0]) > len(s1[1]):
s1[1] +=i
else:
s1[0] += i
if len(s1[1]) != len(s1[0]) :
print('Impossible')
else:
print(s1[0] + '|' + s1[1])
``` | instruction | 0 | 55,956 | 18 | 111,912 |
Yes | output | 1 | 55,956 | 18 | 111,913 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium.
The scales is in equilibrium if the total sum of weights on the left pan is equal to the total sum of weights on the right pan.
Input
The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol "|" indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially on the left pan of the scale. All weights that are recorded in the sequence after the delimiter are initially on the right pan of the scale.
The second line contains a non-empty sequence containing uppercase English letters. Each letter indicates a weight which is not used yet.
It is guaranteed that all the English letters in the input data are different. It is guaranteed that the input does not contain any extra characters.
Output
If you cannot put all the weights on the scales so that the scales were in equilibrium, print string "Impossible". Otherwise, print the description of the resulting scales, copy the format of the input.
If there are multiple answers, print any of them.
Examples
Input
AC|T
L
Output
AC|TL
Input
|ABC
XYZ
Output
XYZ|ABC
Input
W|T
F
Output
Impossible
Input
ABC|
D
Output
Impossible
Submitted Solution:
```
def main():
mode="filee"
if mode=="file":f=open("test.txt","r")
#f.readline()
#input()
get = lambda :[str(x) for x in (f.readline()[:-1] if mode=="file" else input()).split("|")]
scale = get()
q = input()
if abs(len(scale[0]) - len(scale[1]))%2 != len(q)%2 or abs(len(scale[0]) - len(scale[1]))>len(q):
print("Impossible")
return
if len(scale[0])<len(scale[1]):
mid = len(scale[1])-len(scale[0])
scale[0]+=q[:mid]
else:
mid = len(scale[0])-len(scale[1])
scale[1]+=q[:mid]
for z in range(mid,len(q),2):
scale[0]+=q[z]
scale[1]+=q[z+1]
print("|".join(scale))
if mode=="file":f.close()
if __name__=="__main__":
main()
``` | instruction | 0 | 55,957 | 18 | 111,914 |
Yes | output | 1 | 55,957 | 18 | 111,915 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium.
The scales is in equilibrium if the total sum of weights on the left pan is equal to the total sum of weights on the right pan.
Input
The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol "|" indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially on the left pan of the scale. All weights that are recorded in the sequence after the delimiter are initially on the right pan of the scale.
The second line contains a non-empty sequence containing uppercase English letters. Each letter indicates a weight which is not used yet.
It is guaranteed that all the English letters in the input data are different. It is guaranteed that the input does not contain any extra characters.
Output
If you cannot put all the weights on the scales so that the scales were in equilibrium, print string "Impossible". Otherwise, print the description of the resulting scales, copy the format of the input.
If there are multiple answers, print any of them.
Examples
Input
AC|T
L
Output
AC|TL
Input
|ABC
XYZ
Output
XYZ|ABC
Input
W|T
F
Output
Impossible
Input
ABC|
D
Output
Impossible
Submitted Solution:
```
l=[ele for ele in input().split('|')]
s=input()
for i in range(0,len(s)):
left,right=len(l[0]),len(l[1])
if left>right:l[1]+=s[i]
elif right>left:l[0]+=s[i]
else:l[0]+=s[i]
if len(l[0])!=len(l[1]):print('Impossible')
else:
opt=''
l.insert(1,'|')
for e in l:
opt+=e
print(opt)
``` | instruction | 0 | 55,958 | 18 | 111,916 |
Yes | output | 1 | 55,958 | 18 | 111,917 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium.
The scales is in equilibrium if the total sum of weights on the left pan is equal to the total sum of weights on the right pan.
Input
The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol "|" indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially on the left pan of the scale. All weights that are recorded in the sequence after the delimiter are initially on the right pan of the scale.
The second line contains a non-empty sequence containing uppercase English letters. Each letter indicates a weight which is not used yet.
It is guaranteed that all the English letters in the input data are different. It is guaranteed that the input does not contain any extra characters.
Output
If you cannot put all the weights on the scales so that the scales were in equilibrium, print string "Impossible". Otherwise, print the description of the resulting scales, copy the format of the input.
If there are multiple answers, print any of them.
Examples
Input
AC|T
L
Output
AC|TL
Input
|ABC
XYZ
Output
XYZ|ABC
Input
W|T
F
Output
Impossible
Input
ABC|
D
Output
Impossible
Submitted Solution:
```
s = input().split('|')
x = input()
a = len(s[0])
b = len(s[1])
c = len(x)
f = True
if a < b:
d = b - a
if c>=d:
s[0] += x[:d]
c -= d
x = x[d:]
if a > b:
d = a - b
if c>=d:
s[1] += x[:d]
c -= d
x = x[d:]
s[0] += x[:c//2]
s[1] += x[c//2:]
if len(s[0]) == len(s[1]):
print('|'.join(s))
else:
print("Impossible")
``` | instruction | 0 | 55,959 | 18 | 111,918 |
Yes | output | 1 | 55,959 | 18 | 111,919 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium.
The scales is in equilibrium if the total sum of weights on the left pan is equal to the total sum of weights on the right pan.
Input
The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol "|" indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially on the left pan of the scale. All weights that are recorded in the sequence after the delimiter are initially on the right pan of the scale.
The second line contains a non-empty sequence containing uppercase English letters. Each letter indicates a weight which is not used yet.
It is guaranteed that all the English letters in the input data are different. It is guaranteed that the input does not contain any extra characters.
Output
If you cannot put all the weights on the scales so that the scales were in equilibrium, print string "Impossible". Otherwise, print the description of the resulting scales, copy the format of the input.
If there are multiple answers, print any of them.
Examples
Input
AC|T
L
Output
AC|TL
Input
|ABC
XYZ
Output
XYZ|ABC
Input
W|T
F
Output
Impossible
Input
ABC|
D
Output
Impossible
Submitted Solution:
```
s= input()
left = s.index("|")
right = len(s)-left-1
t = input()
if abs(left-right)!=len(t):
print("Impossible")
else:
if left>right:
print(s+t)
else:
print(t+s)
``` | instruction | 0 | 55,960 | 18 | 111,920 |
No | output | 1 | 55,960 | 18 | 111,921 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium.
The scales is in equilibrium if the total sum of weights on the left pan is equal to the total sum of weights on the right pan.
Input
The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol "|" indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially on the left pan of the scale. All weights that are recorded in the sequence after the delimiter are initially on the right pan of the scale.
The second line contains a non-empty sequence containing uppercase English letters. Each letter indicates a weight which is not used yet.
It is guaranteed that all the English letters in the input data are different. It is guaranteed that the input does not contain any extra characters.
Output
If you cannot put all the weights on the scales so that the scales were in equilibrium, print string "Impossible". Otherwise, print the description of the resulting scales, copy the format of the input.
If there are multiple answers, print any of them.
Examples
Input
AC|T
L
Output
AC|TL
Input
|ABC
XYZ
Output
XYZ|ABC
Input
W|T
F
Output
Impossible
Input
ABC|
D
Output
Impossible
Submitted Solution:
```
s = input().split("|")
a1 = len(s[0])
a2 = len(s[1])
p = input()
a3 = len(p)
i = 0
while(a1 != a2 and i < a3):
if a1 < a2:
s[0] = s[0]+p[i]
a1 += 1
else:
s[1] = s[1]+p[i]
a2 += 1
i += 1
a3 = len(p[i:])
s1 = p[i:]
if a1 == a2:
if a3 % 2 == 0:
if a3 == 0:
print(s[0]+"|"+s[1])
else:
print(s[0]+p[0:len(p)//2]+"|"+s[1]+p[len(p)//2:])
else:
print("Impossible")
else:
print("Impossible")
``` | instruction | 0 | 55,961 | 18 | 111,922 |
No | output | 1 | 55,961 | 18 | 111,923 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium.
The scales is in equilibrium if the total sum of weights on the left pan is equal to the total sum of weights on the right pan.
Input
The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol "|" indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially on the left pan of the scale. All weights that are recorded in the sequence after the delimiter are initially on the right pan of the scale.
The second line contains a non-empty sequence containing uppercase English letters. Each letter indicates a weight which is not used yet.
It is guaranteed that all the English letters in the input data are different. It is guaranteed that the input does not contain any extra characters.
Output
If you cannot put all the weights on the scales so that the scales were in equilibrium, print string "Impossible". Otherwise, print the description of the resulting scales, copy the format of the input.
If there are multiple answers, print any of them.
Examples
Input
AC|T
L
Output
AC|TL
Input
|ABC
XYZ
Output
XYZ|ABC
Input
W|T
F
Output
Impossible
Input
ABC|
D
Output
Impossible
Submitted Solution:
```
def checkG(g):
return g%2==0
x=input()
g=input()
n=len(g)
l=x.find('|')
r=len(x)-x.find('|')-1
if r==l:
if checkG(n):
print(x[:l]+g[:int(n/2)]+'|'+x[l+1:]+g[int(n/2):])
else:
print("Impossible")
else:
d=abs(r-l)
if n<d:
print("Impossible")
exit()
if checkG(n-abs(l-r)):
if l<r:
print(x[:l]+g[:d+int(n/2)]+'|'+x[l+1:]+g[d+int(n/2):])
else:
print(x[:l]+g[:int((n-d)/2)]+'|'+x[l+1:]+g[int(n-(d/2)):])
else:
print("Impossible")
``` | instruction | 0 | 55,962 | 18 | 111,924 |
No | output | 1 | 55,962 | 18 | 111,925 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ksenia has ordinary pan scales and several weights of an equal mass. Ksenia has already put some weights on the scales, while other weights are untouched. Ksenia is now wondering whether it is possible to put all the remaining weights on the scales so that the scales were in equilibrium.
The scales is in equilibrium if the total sum of weights on the left pan is equal to the total sum of weights on the right pan.
Input
The first line has a non-empty sequence of characters describing the scales. In this sequence, an uppercase English letter indicates a weight, and the symbol "|" indicates the delimiter (the character occurs in the sequence exactly once). All weights that are recorded in the sequence before the delimiter are initially on the left pan of the scale. All weights that are recorded in the sequence after the delimiter are initially on the right pan of the scale.
The second line contains a non-empty sequence containing uppercase English letters. Each letter indicates a weight which is not used yet.
It is guaranteed that all the English letters in the input data are different. It is guaranteed that the input does not contain any extra characters.
Output
If you cannot put all the weights on the scales so that the scales were in equilibrium, print string "Impossible". Otherwise, print the description of the resulting scales, copy the format of the input.
If there are multiple answers, print any of them.
Examples
Input
AC|T
L
Output
AC|TL
Input
|ABC
XYZ
Output
XYZ|ABC
Input
W|T
F
Output
Impossible
Input
ABC|
D
Output
Impossible
Submitted Solution:
```
import sys
import math
arr = (sys.stdin.readline()).split("|")
st = sys.stdin.readline()
la = len(arr[0])
ra = len(arr[1]) - 1
ls = len(st) - 1
t = (ls - math.fabs(la - ra))
if(t % 2 == 0 and t >= 0):
ss1 = []
ss2 = []
ss1.extend(arr[1][:ra])
ss2.extend(arr[0])
kl = 0
if(la > ra):
ss1.extend(st[:la - ra])
kl = la - ra
elif(ra > la):
ss2.extend(st[:ra - la])
kl = ra - la
ss1.extend(st[kl:int(t / 2)])
ss2.extend(st[int(t / 2): ls - kl])
print("".join(ss2) + "|" + "".join(ss1))
else:
print("Impossible")
``` | instruction | 0 | 55,963 | 18 | 111,926 |
No | output | 1 | 55,963 | 18 | 111,927 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes.
Input
The first line contains two integers, n and m (1 ≤ n ≤ 3000, 1 ≤ m ≤ 3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following m lines contain the words. The i-th line contains two strings ai, bi meaning that the word ai belongs to the first language, the word bi belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains n space-separated strings c1, c2, ..., cn — the text of the lecture. It is guaranteed that each of the strings ci belongs to the set of strings {a1, a2, ... am}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters.
Output
Output exactly n words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input.
Examples
Input
4 3
codeforces codesecrof
contest round
letter message
codeforces contest letter contest
Output
codeforces round letter round
Input
5 3
joll wuqrd
euzf un
hbnyiyc rsoqqveh
hbnyiyc joll joll euzf joll
Output
hbnyiyc joll joll un joll
Submitted Solution:
```
n,m =map(int,input().split())
d = {}
for i in range(m):
a,b = map(str,input().split())
d [a] = b
c = list(map(str,input().split()))
for i in c:
y = d[i]
if len(y)<len(i):
print(y,end = ' ')
else:
print(i,end = ' ')
``` | instruction | 0 | 56,011 | 18 | 112,022 |
Yes | output | 1 | 56,011 | 18 | 112,023 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes.
Input
The first line contains two integers, n and m (1 ≤ n ≤ 3000, 1 ≤ m ≤ 3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following m lines contain the words. The i-th line contains two strings ai, bi meaning that the word ai belongs to the first language, the word bi belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains n space-separated strings c1, c2, ..., cn — the text of the lecture. It is guaranteed that each of the strings ci belongs to the set of strings {a1, a2, ... am}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters.
Output
Output exactly n words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input.
Examples
Input
4 3
codeforces codesecrof
contest round
letter message
codeforces contest letter contest
Output
codeforces round letter round
Input
5 3
joll wuqrd
euzf un
hbnyiyc rsoqqveh
hbnyiyc joll joll euzf joll
Output
hbnyiyc joll joll un joll
Submitted Solution:
```
s = str(input()).split()
s[0] = int(s[0])
s[1] = int(s[1])
l = [[], []]
for i in range(s[1]):
p = str(input()).split()
l[0].append(p[0])
l[1].append(p[1])
s = str(input()).split()
for i in range(len(s)):
j = l[0].index(s[i])
if len(l[0][j]) <= len(l[1][j]):
print(l[0][j], end=' ')
else:
print(l[1][j], end=' ')
``` | instruction | 0 | 56,012 | 18 | 112,024 |
Yes | output | 1 | 56,012 | 18 | 112,025 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes.
Input
The first line contains two integers, n and m (1 ≤ n ≤ 3000, 1 ≤ m ≤ 3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following m lines contain the words. The i-th line contains two strings ai, bi meaning that the word ai belongs to the first language, the word bi belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains n space-separated strings c1, c2, ..., cn — the text of the lecture. It is guaranteed that each of the strings ci belongs to the set of strings {a1, a2, ... am}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters.
Output
Output exactly n words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input.
Examples
Input
4 3
codeforces codesecrof
contest round
letter message
codeforces contest letter contest
Output
codeforces round letter round
Input
5 3
joll wuqrd
euzf un
hbnyiyc rsoqqveh
hbnyiyc joll joll euzf joll
Output
hbnyiyc joll joll un joll
Submitted Solution:
```
n, m = map(int, input().split())
d = {}
for i in range(m):
text = input().split()
if len(text[0]) <= len(text[1]):
d[text[0]] = text[0]
else:
d[text[0]] = text[1]
num = list(map(str,input().split()))
for i in range(0,n):
print(d[num[i]],end=" ")
``` | instruction | 0 | 56,013 | 18 | 112,026 |
Yes | output | 1 | 56,013 | 18 | 112,027 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes.
Input
The first line contains two integers, n and m (1 ≤ n ≤ 3000, 1 ≤ m ≤ 3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following m lines contain the words. The i-th line contains two strings ai, bi meaning that the word ai belongs to the first language, the word bi belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains n space-separated strings c1, c2, ..., cn — the text of the lecture. It is guaranteed that each of the strings ci belongs to the set of strings {a1, a2, ... am}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters.
Output
Output exactly n words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input.
Examples
Input
4 3
codeforces codesecrof
contest round
letter message
codeforces contest letter contest
Output
codeforces round letter round
Input
5 3
joll wuqrd
euzf un
hbnyiyc rsoqqveh
hbnyiyc joll joll euzf joll
Output
hbnyiyc joll joll un joll
Submitted Solution:
```
from collections import defaultdict
if __name__ == '__main__':
n, m = map(int, input().split())
d = defaultdict(list)
for i in range(m):
X = input().split()
A = X[0]
B = X[1]
if len(A) > len(B):
d[A] = B
d[B] = B
else:
d[A] = A
d[B] = A
string = list(input().split())
for word in string:
print(d[word],end=" ")
``` | instruction | 0 | 56,014 | 18 | 112,028 |
Yes | output | 1 | 56,014 | 18 | 112,029 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes.
Input
The first line contains two integers, n and m (1 ≤ n ≤ 3000, 1 ≤ m ≤ 3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following m lines contain the words. The i-th line contains two strings ai, bi meaning that the word ai belongs to the first language, the word bi belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains n space-separated strings c1, c2, ..., cn — the text of the lecture. It is guaranteed that each of the strings ci belongs to the set of strings {a1, a2, ... am}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters.
Output
Output exactly n words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input.
Examples
Input
4 3
codeforces codesecrof
contest round
letter message
codeforces contest letter contest
Output
codeforces round letter round
Input
5 3
joll wuqrd
euzf un
hbnyiyc rsoqqveh
hbnyiyc joll joll euzf joll
Output
hbnyiyc joll joll un joll
Submitted Solution:
```
n,m = map(int,input().split())
d = {}
for i in range(m):
x,y = input().split()
d[x] = y
s = list(input().split())
p = ''
for i in s:
if(len(i) < len(d[i])):
p += i + ' '
else:
p += d[i] + ' '
print(p)
``` | instruction | 0 | 56,015 | 18 | 112,030 |
No | output | 1 | 56,015 | 18 | 112,031 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes.
Input
The first line contains two integers, n and m (1 ≤ n ≤ 3000, 1 ≤ m ≤ 3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following m lines contain the words. The i-th line contains two strings ai, bi meaning that the word ai belongs to the first language, the word bi belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains n space-separated strings c1, c2, ..., cn — the text of the lecture. It is guaranteed that each of the strings ci belongs to the set of strings {a1, a2, ... am}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters.
Output
Output exactly n words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input.
Examples
Input
4 3
codeforces codesecrof
contest round
letter message
codeforces contest letter contest
Output
codeforces round letter round
Input
5 3
joll wuqrd
euzf un
hbnyiyc rsoqqveh
hbnyiyc joll joll euzf joll
Output
hbnyiyc joll joll un joll
Submitted Solution:
```
#!/usr/bin/env python3
n, m = [int(i) for i in input().split()]
dic = {}
for i in range(m):
a, b = input().split()
dic[a] = b
c = [s for s in input().split()]
for i in range(n):
s = c[i]
t = dic[s]
if len(s) < len(t):
print(s, end=" ")
else:
print(t, end=" ")
print()
``` | instruction | 0 | 56,016 | 18 | 112,032 |
No | output | 1 | 56,016 | 18 | 112,033 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes.
Input
The first line contains two integers, n and m (1 ≤ n ≤ 3000, 1 ≤ m ≤ 3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following m lines contain the words. The i-th line contains two strings ai, bi meaning that the word ai belongs to the first language, the word bi belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains n space-separated strings c1, c2, ..., cn — the text of the lecture. It is guaranteed that each of the strings ci belongs to the set of strings {a1, a2, ... am}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters.
Output
Output exactly n words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input.
Examples
Input
4 3
codeforces codesecrof
contest round
letter message
codeforces contest letter contest
Output
codeforces round letter round
Input
5 3
joll wuqrd
euzf un
hbnyiyc rsoqqveh
hbnyiyc joll joll euzf joll
Output
hbnyiyc joll joll un joll
Submitted Solution:
```
n,m = input().split()
m = int(m)
lang = dict()
for i in range(m):
l1,l2 = input().split()
lang[l1] = l1 if len(l1)<=len(l2) else l2
lecture = input().split()
notes=''
for word in lecture:
notes+=lang[word]
print(notes)
``` | instruction | 0 | 56,017 | 18 | 112,034 |
No | output | 1 | 56,017 | 18 | 112,035 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have a new professor of graph theory and he speaks very quickly. You come up with the following plan to keep up with his lecture and make notes.
You know two languages, and the professor is giving the lecture in the first one. The words in both languages consist of lowercase English characters, each language consists of several words. For each language, all words are distinct, i.e. they are spelled differently. Moreover, the words of these languages have a one-to-one correspondence, that is, for each word in each language, there exists exactly one word in the other language having has the same meaning.
You can write down every word the professor says in either the first language or the second language. Of course, during the lecture you write down each word in the language in which the word is shorter. In case of equal lengths of the corresponding words you prefer the word of the first language.
You are given the text of the lecture the professor is going to read. Find out how the lecture will be recorded in your notes.
Input
The first line contains two integers, n and m (1 ≤ n ≤ 3000, 1 ≤ m ≤ 3000) — the number of words in the professor's lecture and the number of words in each of these languages.
The following m lines contain the words. The i-th line contains two strings ai, bi meaning that the word ai belongs to the first language, the word bi belongs to the second language, and these two words have the same meaning. It is guaranteed that no word occurs in both languages, and each word occurs in its language exactly once.
The next line contains n space-separated strings c1, c2, ..., cn — the text of the lecture. It is guaranteed that each of the strings ci belongs to the set of strings {a1, a2, ... am}.
All the strings in the input are non-empty, each consisting of no more than 10 lowercase English letters.
Output
Output exactly n words: how you will record the lecture in your notebook. Output the words of the lecture in the same order as in the input.
Examples
Input
4 3
codeforces codesecrof
contest round
letter message
codeforces contest letter contest
Output
codeforces round letter round
Input
5 3
joll wuqrd
euzf un
hbnyiyc rsoqqveh
hbnyiyc joll joll euzf joll
Output
hbnyiyc joll joll un joll
Submitted Solution:
```
n,m=input().split(' ')
n=int(n)
m=int(m)
mylib={}
for i in range(m):
string=input().split(' ')
mylib.update({string[0]:string[1]})
letter=input().split(' ')
for i in range(len(letter)):
if len(letter[i])<len(mylib.get(letter[i])):
print(letter[i],end=' ')
else: print(mylib.get(letter[i]),end=' ')
``` | instruction | 0 | 56,018 | 18 | 112,036 |
No | output | 1 | 56,018 | 18 | 112,037 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves hockey very much. One day, as he was watching a hockey match, he fell asleep. Petya dreamt of being appointed to change a hockey team's name. Thus, Petya was given the original team name w and the collection of forbidden substrings s1, s2, ..., sn. All those strings consist of uppercase and lowercase Latin letters. String w has the length of |w|, its characters are numbered from 1 to |w|.
First Petya should find all the occurrences of forbidden substrings in the w string. During the search of substrings the case of letter shouldn't be taken into consideration. That is, strings "aBC" and "ABc" are considered equal.
After that Petya should perform the replacement of all letters covered by the occurrences. More formally: a letter in the position i should be replaced by any other one if for position i in string w there exist pair of indices l, r (1 ≤ l ≤ i ≤ r ≤ |w|) such that substring w[l ... r] is contained in the collection s1, s2, ..., sn, when using case insensitive comparison. During the replacement the letter's case should remain the same. Petya is not allowed to replace the letters that aren't covered by any forbidden substring.
Letter letter (uppercase or lowercase) is considered lucky for the hockey players. That's why Petya should perform the changes so that the letter occurred in the resulting string as many times as possible. Help Petya to find such resulting string. If there are several such strings, find the one that comes first lexicographically.
Note that the process of replacements is not repeated, it occurs only once. That is, if after Petya's replacements the string started to contain new occurrences of bad substrings, Petya pays no attention to them.
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of forbidden substrings in the collection. Next n lines contain these substrings. The next line contains string w. All those n + 1 lines are non-empty strings consisting of uppercase and lowercase Latin letters whose length does not exceed 100. The last line contains a lowercase letter letter.
Output
Output the only line — Petya's resulting string with the maximum number of letters letter. If there are several answers then output the one that comes first lexicographically.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if a is a prefix of b, or there exists such an i (1 ≤ i ≤ |a|), that ai < bi, and for any j (1 ≤ j < i) aj = bj. |a| stands for the length of string a.
Examples
Input
3
bers
ucky
elu
PetrLoveLuckyNumbers
t
Output
PetrLovtTttttNumtttt
Input
4
hello
party
abefglghjdhfgj
IVan
petrsmatchwin
a
Output
petrsmatchwin
Input
2
aCa
cba
abAcaba
c
Output
abCacba
Submitted Solution:
```
#------------------------template--------------------------#
import os
import sys
from math import *
from collections import *
from fractions import *
from bisect import *
from heapq import*
from io import BytesIO, IOBase
def vsInput():
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
ALPHA='abcdefghijklmnopqrstuvwxyz'
M=10**9+7
EPS=1e-6
def value():return tuple(map(int,input().split()))
def array():return [int(i) for i in input().split()]
def Int():return int(input())
def Str():return input()
def arrayS():return [i for i in input().split()]
#-------------------------code---------------------------#
# vsInput()
n=Int()
strings=[]
for i in range(n): strings.append(input().lower())
w=input()
letter=input().lower()
n=len(w)
smallest='a'
if(letter=='a'): smallest='b'
Count=[0]*(n+1)
for s in strings:
l=len(s)
for j in range(n):
if(w[j:j+l].lower()==s):
# print(w[j:j+l],s)
Count[j]+=1
Count[j+l]-=1
# print(Count)
count=[Count[0]]
cur=Count[0]
for i in range(1,n):
cur+=Count[i]
count.append(cur)
ans=[]
# print(count)
for i in range(n):
if(count[i]>0):
if(w[i].lower()==letter):
ans.append(smallest)
else:
ans.append(letter)
else: ans.append(w[i])
for i in range(n):
if(w[i].islower()):
print(ans[i].lower(),end="")
else:
print(ans[i].upper(),end="")
``` | instruction | 0 | 56,158 | 18 | 112,316 |
Yes | output | 1 | 56,158 | 18 | 112,317 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves hockey very much. One day, as he was watching a hockey match, he fell asleep. Petya dreamt of being appointed to change a hockey team's name. Thus, Petya was given the original team name w and the collection of forbidden substrings s1, s2, ..., sn. All those strings consist of uppercase and lowercase Latin letters. String w has the length of |w|, its characters are numbered from 1 to |w|.
First Petya should find all the occurrences of forbidden substrings in the w string. During the search of substrings the case of letter shouldn't be taken into consideration. That is, strings "aBC" and "ABc" are considered equal.
After that Petya should perform the replacement of all letters covered by the occurrences. More formally: a letter in the position i should be replaced by any other one if for position i in string w there exist pair of indices l, r (1 ≤ l ≤ i ≤ r ≤ |w|) such that substring w[l ... r] is contained in the collection s1, s2, ..., sn, when using case insensitive comparison. During the replacement the letter's case should remain the same. Petya is not allowed to replace the letters that aren't covered by any forbidden substring.
Letter letter (uppercase or lowercase) is considered lucky for the hockey players. That's why Petya should perform the changes so that the letter occurred in the resulting string as many times as possible. Help Petya to find such resulting string. If there are several such strings, find the one that comes first lexicographically.
Note that the process of replacements is not repeated, it occurs only once. That is, if after Petya's replacements the string started to contain new occurrences of bad substrings, Petya pays no attention to them.
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of forbidden substrings in the collection. Next n lines contain these substrings. The next line contains string w. All those n + 1 lines are non-empty strings consisting of uppercase and lowercase Latin letters whose length does not exceed 100. The last line contains a lowercase letter letter.
Output
Output the only line — Petya's resulting string with the maximum number of letters letter. If there are several answers then output the one that comes first lexicographically.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if a is a prefix of b, or there exists such an i (1 ≤ i ≤ |a|), that ai < bi, and for any j (1 ≤ j < i) aj = bj. |a| stands for the length of string a.
Examples
Input
3
bers
ucky
elu
PetrLoveLuckyNumbers
t
Output
PetrLovtTttttNumtttt
Input
4
hello
party
abefglghjdhfgj
IVan
petrsmatchwin
a
Output
petrsmatchwin
Input
2
aCa
cba
abAcaba
c
Output
abCacba
Submitted Solution:
```
import sys
f = sys.stdin
#f = open("input.txt")
n = int(f.readline())
fbs = []
for i in range(n):
fbs.append(f.readline().strip())
s = f.readline().strip()
ch = f.readline().strip()
bChange = [0] * len(s)
for i in range(n):
idx = s.lower().find(fbs[i].lower())
if idx != -1:
bChange[idx:idx+len(fbs[i])] = [1] * len(fbs[i])
#print(bChange)
result = ['']*len(s)
for i in range(len(s)):
if bChange[i] == 1:
result[i] = ch
if result[i].upper() == s[i].upper():
if result[i] == 'A':
result[i] = 'B'
else:
result[i] = 'A'
if s[i].isupper():
result[i] = result[i].upper()
else:
result[i] = result[i].lower()
else:
result[i] = s[i]
print("".join(result))
``` | instruction | 0 | 56,159 | 18 | 112,318 |
No | output | 1 | 56,159 | 18 | 112,319 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves hockey very much. One day, as he was watching a hockey match, he fell asleep. Petya dreamt of being appointed to change a hockey team's name. Thus, Petya was given the original team name w and the collection of forbidden substrings s1, s2, ..., sn. All those strings consist of uppercase and lowercase Latin letters. String w has the length of |w|, its characters are numbered from 1 to |w|.
First Petya should find all the occurrences of forbidden substrings in the w string. During the search of substrings the case of letter shouldn't be taken into consideration. That is, strings "aBC" and "ABc" are considered equal.
After that Petya should perform the replacement of all letters covered by the occurrences. More formally: a letter in the position i should be replaced by any other one if for position i in string w there exist pair of indices l, r (1 ≤ l ≤ i ≤ r ≤ |w|) such that substring w[l ... r] is contained in the collection s1, s2, ..., sn, when using case insensitive comparison. During the replacement the letter's case should remain the same. Petya is not allowed to replace the letters that aren't covered by any forbidden substring.
Letter letter (uppercase or lowercase) is considered lucky for the hockey players. That's why Petya should perform the changes so that the letter occurred in the resulting string as many times as possible. Help Petya to find such resulting string. If there are several such strings, find the one that comes first lexicographically.
Note that the process of replacements is not repeated, it occurs only once. That is, if after Petya's replacements the string started to contain new occurrences of bad substrings, Petya pays no attention to them.
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of forbidden substrings in the collection. Next n lines contain these substrings. The next line contains string w. All those n + 1 lines are non-empty strings consisting of uppercase and lowercase Latin letters whose length does not exceed 100. The last line contains a lowercase letter letter.
Output
Output the only line — Petya's resulting string with the maximum number of letters letter. If there are several answers then output the one that comes first lexicographically.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if a is a prefix of b, or there exists such an i (1 ≤ i ≤ |a|), that ai < bi, and for any j (1 ≤ j < i) aj = bj. |a| stands for the length of string a.
Examples
Input
3
bers
ucky
elu
PetrLoveLuckyNumbers
t
Output
PetrLovtTttttNumtttt
Input
4
hello
party
abefglghjdhfgj
IVan
petrsmatchwin
a
Output
petrsmatchwin
Input
2
aCa
cba
abAcaba
c
Output
abCacba
Submitted Solution:
```
#from bisect import bisect_left as bl #c++ lowerbound bl(array,element)
#from bisect import bisect_right as br #c++ upperbound br(array,element)
#from __future__ import print_function, division #while using python2
# from itertools import accumulate
# from collections import defaultdict, Counter
def modinv(n,p):
return pow(n,p-2,p)
def main():
#sys.stdin = open('input.txt', 'r')
#sys.stdout = open('output.txt', 'w')
n = int(input())
forbidden = []
for i in range(n):
forbidden.append(input())
parent = input()
c = input()
to_be_replaced = set()
for key in forbidden:
s = parent.lower()
while s.find(key.lower()) != -1:
i = s.find(key.lower())
for j in range(i, i+len(key)):
to_be_replaced.add(j)
s = s[i+1:]
# print("after key", key)
# print(to_be_replaced)
ans = []
for i in range(len(parent)):
cur = parent[i]
if i in to_be_replaced:
# print("cur =", cur)
if cur == c.lower() or cur == c.upper():
if c in 'aA':
if cur.islower():
ans.append('b')
else:
ans.append('B')
else:
if cur.islower():
ans.append('a')
else:
ans.append('A')
elif cur == cur.upper():
ans.append(c.upper())
elif cur == cur.lower():
ans.append(c.lower())
else:
ans.append(cur)
print("".join(ans))
#------------------ Python 2 and 3 footer by Pajenegod and c1729-----------------------------------------
py2 = round(0.5)
if py2:
from future_builtins import ascii, filter, hex, map, oct, zip
range = xrange
import os, sys
from io import IOBase, BytesIO
BUFSIZE = 8192
class FastIO(BytesIO):
newlines = 0
def __init__(self, file):
self._file = file
self._fd = file.fileno()
self.writable = "x" in file.mode or "w" in file.mode
self.write = super(FastIO, self).write if self.writable else None
def _fill(self):
s = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.seek((self.tell(), self.seek(0,2), super(FastIO, self).write(s))[0])
return s
def read(self):
while self._fill(): pass
return super(FastIO,self).read()
def readline(self):
while self.newlines == 0:
s = self._fill(); self.newlines = s.count(b"\n") + (not s)
self.newlines -= 1
return super(FastIO, self).readline()
def flush(self):
if self.writable:
os.write(self._fd, self.getvalue())
self.truncate(0), self.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
if py2:
self.write = self.buffer.write
self.read = self.buffer.read
self.readline = self.buffer.readline
else:
self.write = lambda s:self.buffer.write(s.encode('ascii'))
self.read = lambda:self.buffer.read().decode('ascii')
self.readline = lambda:self.buffer.readline().decode('ascii')
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip('\r\n')
if __name__ == '__main__':
main()
``` | instruction | 0 | 56,160 | 18 | 112,320 |
No | output | 1 | 56,160 | 18 | 112,321 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves hockey very much. One day, as he was watching a hockey match, he fell asleep. Petya dreamt of being appointed to change a hockey team's name. Thus, Petya was given the original team name w and the collection of forbidden substrings s1, s2, ..., sn. All those strings consist of uppercase and lowercase Latin letters. String w has the length of |w|, its characters are numbered from 1 to |w|.
First Petya should find all the occurrences of forbidden substrings in the w string. During the search of substrings the case of letter shouldn't be taken into consideration. That is, strings "aBC" and "ABc" are considered equal.
After that Petya should perform the replacement of all letters covered by the occurrences. More formally: a letter in the position i should be replaced by any other one if for position i in string w there exist pair of indices l, r (1 ≤ l ≤ i ≤ r ≤ |w|) such that substring w[l ... r] is contained in the collection s1, s2, ..., sn, when using case insensitive comparison. During the replacement the letter's case should remain the same. Petya is not allowed to replace the letters that aren't covered by any forbidden substring.
Letter letter (uppercase or lowercase) is considered lucky for the hockey players. That's why Petya should perform the changes so that the letter occurred in the resulting string as many times as possible. Help Petya to find such resulting string. If there are several such strings, find the one that comes first lexicographically.
Note that the process of replacements is not repeated, it occurs only once. That is, if after Petya's replacements the string started to contain new occurrences of bad substrings, Petya pays no attention to them.
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of forbidden substrings in the collection. Next n lines contain these substrings. The next line contains string w. All those n + 1 lines are non-empty strings consisting of uppercase and lowercase Latin letters whose length does not exceed 100. The last line contains a lowercase letter letter.
Output
Output the only line — Petya's resulting string with the maximum number of letters letter. If there are several answers then output the one that comes first lexicographically.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if a is a prefix of b, or there exists such an i (1 ≤ i ≤ |a|), that ai < bi, and for any j (1 ≤ j < i) aj = bj. |a| stands for the length of string a.
Examples
Input
3
bers
ucky
elu
PetrLoveLuckyNumbers
t
Output
PetrLovtTttttNumtttt
Input
4
hello
party
abefglghjdhfgj
IVan
petrsmatchwin
a
Output
petrsmatchwin
Input
2
aCa
cba
abAcaba
c
Output
abCacba
Submitted Solution:
```
import sys
f = sys.stdin
#f = open("input.txt")
n = int(f.readline())
fbs = []
for i in range(n):
fbs.append(f.readline().strip())
s = f.readline().strip()
ch = f.readline().strip()
bChange = [0] * len(s)
for i in range(n):
idx = s.lower().find(fbs[i].lower())
if idx != -1:
bChange[idx:idx+len(fbs[i])] = [1] * len(fbs[i])
#print(bChange)
result = ['']*len(s)
for i in range(len(s)):
if bChange[i] == 1:
result[i] = ch
if result[i].upper() == s[i].upper():
if result[i].upper() == 'A':
result[i] = 'B'
else:
result[i] = 'A'
if s[i].isupper():
result[i] = result[i].upper()
else:
result[i] = result[i].lower()
else:
result[i] = s[i]
print("".join(result))
``` | instruction | 0 | 56,161 | 18 | 112,322 |
No | output | 1 | 56,161 | 18 | 112,323 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya loves hockey very much. One day, as he was watching a hockey match, he fell asleep. Petya dreamt of being appointed to change a hockey team's name. Thus, Petya was given the original team name w and the collection of forbidden substrings s1, s2, ..., sn. All those strings consist of uppercase and lowercase Latin letters. String w has the length of |w|, its characters are numbered from 1 to |w|.
First Petya should find all the occurrences of forbidden substrings in the w string. During the search of substrings the case of letter shouldn't be taken into consideration. That is, strings "aBC" and "ABc" are considered equal.
After that Petya should perform the replacement of all letters covered by the occurrences. More formally: a letter in the position i should be replaced by any other one if for position i in string w there exist pair of indices l, r (1 ≤ l ≤ i ≤ r ≤ |w|) such that substring w[l ... r] is contained in the collection s1, s2, ..., sn, when using case insensitive comparison. During the replacement the letter's case should remain the same. Petya is not allowed to replace the letters that aren't covered by any forbidden substring.
Letter letter (uppercase or lowercase) is considered lucky for the hockey players. That's why Petya should perform the changes so that the letter occurred in the resulting string as many times as possible. Help Petya to find such resulting string. If there are several such strings, find the one that comes first lexicographically.
Note that the process of replacements is not repeated, it occurs only once. That is, if after Petya's replacements the string started to contain new occurrences of bad substrings, Petya pays no attention to them.
Input
The first line contains the only integer n (1 ≤ n ≤ 100) — the number of forbidden substrings in the collection. Next n lines contain these substrings. The next line contains string w. All those n + 1 lines are non-empty strings consisting of uppercase and lowercase Latin letters whose length does not exceed 100. The last line contains a lowercase letter letter.
Output
Output the only line — Petya's resulting string with the maximum number of letters letter. If there are several answers then output the one that comes first lexicographically.
The lexicographical comparison is performed by the standard < operator in modern programming languages. The line a is lexicographically smaller than the line b, if a is a prefix of b, or there exists such an i (1 ≤ i ≤ |a|), that ai < bi, and for any j (1 ≤ j < i) aj = bj. |a| stands for the length of string a.
Examples
Input
3
bers
ucky
elu
PetrLoveLuckyNumbers
t
Output
PetrLovtTttttNumtttt
Input
4
hello
party
abefglghjdhfgj
IVan
petrsmatchwin
a
Output
petrsmatchwin
Input
2
aCa
cba
abAcaba
c
Output
abCacba
Submitted Solution:
```
from math import*
a=[list(input().lower()) for i in range(int(input()))]
s=input()
s0=list(s)
s=list(s.lower())
c=input()
C=chr(ord(c)-ord('a')+ord('A'))
r=['.']*len(s)
for t in a:
for i in range(len(s)-len(t)+1):
#print(s[i:i+len(t)],t)
if(s[i:i+len(t)]==t):
r[i:i+len(t)]=t
s=s0
for i in range(len(s)):
if r[i]!='.':
if ord(s[i])<=ord('Z'):
if s[i]==C:
s[i]='A'
else:
s[i]=C
else:
if s[i]==c:
s[i]='a'
else:
s[i]=c
print(*s,sep='')
``` | instruction | 0 | 56,162 | 18 | 112,324 |
No | output | 1 | 56,162 | 18 | 112,325 |
Provide a correct Python 3 solution for this coding contest problem.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16 | instruction | 0 | 56,312 | 18 | 112,624 |
"Correct Solution:
```
s = input()
ans = "CODEFESTIVAL2016"
cnt = 0
for i in range(len(s)):
cnt += s[i] != ans[i]
print(cnt)
``` | output | 1 | 56,312 | 18 | 112,625 |
Provide a correct Python 3 solution for this coding contest problem.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16 | instruction | 0 | 56,313 | 18 | 112,626 |
"Correct Solution:
```
s=input()
org="CODEFESTIVAL2016"
cnt=0
for i in range(len(s)):
if s[i]!=org[i]:
cnt+=1
print(cnt)
``` | output | 1 | 56,313 | 18 | 112,627 |
Provide a correct Python 3 solution for this coding contest problem.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16 | instruction | 0 | 56,314 | 18 | 112,628 |
"Correct Solution:
```
s = input()
tmp = 'CODEFESTIVAL2016'
res = 0
for i in range(16):
if s[i] != tmp[i]:
res += 1
print(res)
``` | output | 1 | 56,314 | 18 | 112,629 |
Provide a correct Python 3 solution for this coding contest problem.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16 | instruction | 0 | 56,315 | 18 | 112,630 |
"Correct Solution:
```
n = input()
a = "CODEFESTIVAL2016"
c = 0
for i in range(len(a)):
if a[i]!=n[i]:
c+=1
print(c)
``` | output | 1 | 56,315 | 18 | 112,631 |
Provide a correct Python 3 solution for this coding contest problem.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16 | instruction | 0 | 56,316 | 18 | 112,632 |
"Correct Solution:
```
print(sum(c1 != c2 for c1, c2 in zip('CODEFESTIVAL2016', input())))
``` | output | 1 | 56,316 | 18 | 112,633 |
Provide a correct Python 3 solution for this coding contest problem.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16 | instruction | 0 | 56,317 | 18 | 112,634 |
"Correct Solution:
```
s=input()
t="CODEFESTIVAL2016"
print(sum(1 for i in range(len(s)) if s[i]!=t[i]))
``` | output | 1 | 56,317 | 18 | 112,635 |
Provide a correct Python 3 solution for this coding contest problem.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16 | instruction | 0 | 56,318 | 18 | 112,636 |
"Correct Solution:
```
a = input()
s = 0
for i,j in zip(a,"CODEFESTIVAL2016"):
if i!=j:s+=1
print(s)
``` | output | 1 | 56,318 | 18 | 112,637 |
Provide a correct Python 3 solution for this coding contest problem.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16 | instruction | 0 | 56,319 | 18 | 112,638 |
"Correct Solution:
```
s=input();a=0
for i in range(16):a+=[0,1][s[i]!='CODEFESTIVAL2016'[i]]
print(a)
``` | output | 1 | 56,319 | 18 | 112,639 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16
Submitted Solution:
```
s=input()
c='CODEFESTIVAL2016'
ans=0
for i in range(len(s)):
if s[i]!=c[i]:
ans+=1
print(ans)
``` | instruction | 0 | 56,320 | 18 | 112,640 |
Yes | output | 1 | 56,320 | 18 | 112,641 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16
Submitted Solution:
```
a = 'CODEFESTIVAL2016'
cnt = 0
for x, y in zip(input(), a):
if x != y:
cnt += 1
print(cnt)
``` | instruction | 0 | 56,321 | 18 | 112,642 |
Yes | output | 1 | 56,321 | 18 | 112,643 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16
Submitted Solution:
```
s = input()
t = 'CODEFESTIVAL2016'
ans = 0
for i, j in zip(s, t):
if i != j:
ans += 1
print(ans)
``` | instruction | 0 | 56,322 | 18 | 112,644 |
Yes | output | 1 | 56,322 | 18 | 112,645 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16
Submitted Solution:
```
truth = 'CODEFESTIVAL2016'
S = input()
ans = 0
for i in range(16):
ans += (S[i] != truth[i])
print(ans)
``` | instruction | 0 | 56,323 | 18 | 112,646 |
Yes | output | 1 | 56,323 | 18 | 112,647 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16
Submitted Solution:
```
S=list(str(input().split()))
G='CODEFESTIVAL2016'
t=0
for i in range(16):
if S[i]!=G[i]:
t+=1
print(t)
``` | instruction | 0 | 56,324 | 18 | 112,648 |
No | output | 1 | 56,324 | 18 | 112,649 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16
Submitted Solution:
```
import difflib;print(difflib.SequenceMatcher(None,'CODEFESTIVAL2016',input())*100//16)
``` | instruction | 0 | 56,325 | 18 | 112,650 |
No | output | 1 | 56,325 | 18 | 112,651 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16
Submitted Solution:
```
s=input()
a='CODEFESTIVAL2016'
cnt=0
for i in range(len(s)):
if s[i]!=a[i]:
cnt+=1
print(ans)
``` | instruction | 0 | 56,326 | 18 | 112,652 |
No | output | 1 | 56,326 | 18 | 112,653 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
CODE FESTIVAL 2016 is going to be held. For the occasion, Mr. Takahashi decided to make a signboard.
He intended to write `CODEFESTIVAL2016` on it, but he mistakenly wrote a different string S. Fortunately, the string he wrote was the correct length.
So Mr. Takahashi decided to perform an operation that replaces a certain character with another in the minimum number of iterations, changing the string to `CODEFESTIVAL2016`.
Find the minimum number of iterations for the rewrite operation.
Constraints
* S is 16 characters long.
* S consists of uppercase and lowercase alphabet letters and numerals.
Input
Inputs are provided from Standard Input in the following form.
S
Output
Output an integer representing the minimum number of iterations needed for the rewrite operation.
Examples
Input
C0DEFESTIVAL2O16
Output
2
Input
FESTIVAL2016CODE
Output
16
Submitted Solution:
```
x = list(map(int, input().split()))
s = list(input())
y = len(s)
for i in (0,y - 1):
if s[i] == "c":
print("NO")
elif s[i] == "b":
if i < x[1] + x[2] and i < x[2]:
print("YES")
else:
print("NO")
else:
if i < x[1] + x[2]:
print("YES")
else:
print("NO")
``` | instruction | 0 | 56,327 | 18 | 112,654 |
No | output | 1 | 56,327 | 18 | 112,655 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word s from Berlandish into Birlandish as t. Help him: find out if he translated the word correctly.
Input
The first line contains word s, the second line contains word t. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
Output
If the word t is a word s, written reversely, print YES, otherwise print NO.
Examples
Input
code
edoc
Output
YES
Input
abb
aba
Output
NO
Input
code
code
Output
NO
Submitted Solution:
```
a=list(input())
a.reverse()
b=""
for i in range(len(a)):b+=a[i]
if b==input():print("YES")
else:print("NO")
``` | instruction | 0 | 56,697 | 18 | 113,394 |
Yes | output | 1 | 56,697 | 18 | 113,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word s from Berlandish into Birlandish as t. Help him: find out if he translated the word correctly.
Input
The first line contains word s, the second line contains word t. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
Output
If the word t is a word s, written reversely, print YES, otherwise print NO.
Examples
Input
code
edoc
Output
YES
Input
abb
aba
Output
NO
Input
code
code
Output
NO
Submitted Solution:
```
s=input()
t=input()
s=list(s)
t=list(t)
t.reverse()
if s==t:
print('YES')
else:
print('NO')
``` | instruction | 0 | 56,698 | 18 | 113,396 |
Yes | output | 1 | 56,698 | 18 | 113,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word s from Berlandish into Birlandish as t. Help him: find out if he translated the word correctly.
Input
The first line contains word s, the second line contains word t. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
Output
If the word t is a word s, written reversely, print YES, otherwise print NO.
Examples
Input
code
edoc
Output
YES
Input
abb
aba
Output
NO
Input
code
code
Output
NO
Submitted Solution:
```
a=str(input())
b=str(input())
if a[::-1]==b:
print ('YES')
else:
print ('NO')
``` | instruction | 0 | 56,699 | 18 | 113,398 |
Yes | output | 1 | 56,699 | 18 | 113,399 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word s from Berlandish into Birlandish as t. Help him: find out if he translated the word correctly.
Input
The first line contains word s, the second line contains word t. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
Output
If the word t is a word s, written reversely, print YES, otherwise print NO.
Examples
Input
code
edoc
Output
YES
Input
abb
aba
Output
NO
Input
code
code
Output
NO
Submitted Solution:
```
n=input()
m=input()
n1=[]
for x in n:
n1.insert(0, x)
n="".join(n1)
if m==n:
print("YES")
else:
print("NO")
``` | instruction | 0 | 56,700 | 18 | 113,400 |
Yes | output | 1 | 56,700 | 18 | 113,401 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word s from Berlandish into Birlandish as t. Help him: find out if he translated the word correctly.
Input
The first line contains word s, the second line contains word t. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
Output
If the word t is a word s, written reversely, print YES, otherwise print NO.
Examples
Input
code
edoc
Output
YES
Input
abb
aba
Output
NO
Input
code
code
Output
NO
Submitted Solution:
```
print(list(reversed(input()))==list(input()))
``` | instruction | 0 | 56,701 | 18 | 113,402 |
No | output | 1 | 56,701 | 18 | 113,403 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word s from Berlandish into Birlandish as t. Help him: find out if he translated the word correctly.
Input
The first line contains word s, the second line contains word t. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
Output
If the word t is a word s, written reversely, print YES, otherwise print NO.
Examples
Input
code
edoc
Output
YES
Input
abb
aba
Output
NO
Input
code
code
Output
NO
Submitted Solution:
```
x = input()
k = input()
lst = []
lstO = []
cnt = 0
if(len(x) == len(k)):
for i in range(len(x)):
lst.append(x[i])
if(lst[i] == 't'):
lst[i] = 's'
else:
pass
lst.reverse()
for i in range(len(x)):
lstO.append((k[i]))
for i in range(0, len(x)):
if(lstO[i] != lst[i]):
print("NO")
break
else:
cnt +=1
if(cnt == len(x)):
print("YES")
else:
print("NO")
``` | instruction | 0 | 56,702 | 18 | 113,404 |
No | output | 1 | 56,702 | 18 | 113,405 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word s from Berlandish into Birlandish as t. Help him: find out if he translated the word correctly.
Input
The first line contains word s, the second line contains word t. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
Output
If the word t is a word s, written reversely, print YES, otherwise print NO.
Examples
Input
code
edoc
Output
YES
Input
abb
aba
Output
NO
Input
code
code
Output
NO
Submitted Solution:
```
print(['YES','NO'][input()!=input()[::-1]::2])
``` | instruction | 0 | 56,703 | 18 | 113,406 |
No | output | 1 | 56,703 | 18 | 113,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The translation from the Berland language into the Birland language is not an easy task. Those languages are very similar: a berlandish word differs from a birlandish word with the same meaning a little: it is spelled (and pronounced) reversely. For example, a Berlandish word code corresponds to a Birlandish word edoc. However, it's easy to make a mistake during the «translation». Vasya translated word s from Berlandish into Birlandish as t. Help him: find out if he translated the word correctly.
Input
The first line contains word s, the second line contains word t. The words consist of lowercase Latin letters. The input data do not consist unnecessary spaces. The words are not empty and their lengths do not exceed 100 symbols.
Output
If the word t is a word s, written reversely, print YES, otherwise print NO.
Examples
Input
code
edoc
Output
YES
Input
abb
aba
Output
NO
Input
code
code
Output
NO
Submitted Solution:
```
x=input()
c=x[::-1]
f=0
print(c)
if x==c:
f=f+1
if f==1:
print("no")
else:
print("yes")
``` | instruction | 0 | 56,704 | 18 | 113,408 |
No | output | 1 | 56,704 | 18 | 113,409 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gives this string to C and he appends some number of letters 'c' to the end of the string. However, since C is a good friend of A and B, the number of letters 'c' he appends is equal to the number of 'a' or to the number of 'b' in the string. It is also possible that the number of letters 'c' equals both to the number of letters 'a' and to the number of letters 'b' at the same time.
You have a string in your hands, and you want to check if it is possible to obtain the string in this way or not. If it is possible to obtain the string, print "YES", otherwise print "NO" (without the quotes).
Input
The first and only line consists of a string S ( 1 ≤ |S| ≤ 5 000 ). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'.
Output
Print "YES" or "NO", according to the condition.
Examples
Input
aaabccc
Output
YES
Input
bbacc
Output
NO
Input
aabc
Output
YES
Note
Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'.
Submitted Solution:
```
s = input()
a, b, c = s.count('a'), s.count('b'), s.count('c')
if a + b + c == len(s) and (c == a or c == b) and set(s[:a]) == {'a'} and set(s[a: a + b]) == {'b'}:
print("YES")
else:
print("NO")
``` | instruction | 0 | 56,916 | 18 | 113,832 |
Yes | output | 1 | 56,916 | 18 | 113,833 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A has a string consisting of some number of lowercase English letters 'a'. He gives it to his friend B who appends some number of letters 'b' to the end of this string. Since both A and B like the characters 'a' and 'b', they have made sure that at this point, at least one 'a' and one 'b' exist in the string.
B now gives this string to C and he appends some number of letters 'c' to the end of the string. However, since C is a good friend of A and B, the number of letters 'c' he appends is equal to the number of 'a' or to the number of 'b' in the string. It is also possible that the number of letters 'c' equals both to the number of letters 'a' and to the number of letters 'b' at the same time.
You have a string in your hands, and you want to check if it is possible to obtain the string in this way or not. If it is possible to obtain the string, print "YES", otherwise print "NO" (without the quotes).
Input
The first and only line consists of a string S ( 1 ≤ |S| ≤ 5 000 ). It is guaranteed that the string will only consist of the lowercase English letters 'a', 'b', 'c'.
Output
Print "YES" or "NO", according to the condition.
Examples
Input
aaabccc
Output
YES
Input
bbacc
Output
NO
Input
aabc
Output
YES
Note
Consider first example: the number of 'c' is equal to the number of 'a'.
Consider second example: although the number of 'c' is equal to the number of the 'b', the order is not correct.
Consider third example: the number of 'c' is equal to the number of 'b'.
Submitted Solution:
```
s=input()
t=sorted(s)
t=''.join(t)
if 'a' in s and 'b' in s and 'c' in s:
if t==s:
if t.count('c')==t.count('b') or t.count('a')==t.count('c'):
print ("YES")
else:
print ("NO")
else:
print ("NO")
else:
print ("NO")
``` | instruction | 0 | 56,917 | 18 | 113,834 |
Yes | output | 1 | 56,917 | 18 | 113,835 |
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