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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`. Constraints * |S|=3 * S consists of `a`, `b` and `c`. Input Input is given from Standard Input in the following format: S Output If S can be obtained by permuting `abc`, print `Yes`; otherwise, print `No`. Examples Input bac Output Yes Input bab Output No Input abc Output Yes Input aaa Output No Submitted Solution: ``` s = input() s = list(s) s.sort() if (s == "abc"): print("Yes") else : print("No") ```
instruction
0
78,957
18
157,914
No
output
1
78,957
18
157,915
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`. Constraints * |S|=3 * S consists of `a`, `b` and `c`. Input Input is given from Standard Input in the following format: S Output If S can be obtained by permuting `abc`, print `Yes`; otherwise, print `No`. Examples Input bac Output Yes Input bab Output No Input abc Output Yes Input aaa Output No Submitted Solution: ``` s = input() m = {} flag = False for c in s: if c not in m: m[c] = 1 else: print('No') flag = True if not flag: print('Yes') ```
instruction
0
78,958
18
157,916
No
output
1
78,958
18
157,917
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`. Constraints * |S|=3 * S consists of `a`, `b` and `c`. Input Input is given from Standard Input in the following format: S Output If S can be obtained by permuting `abc`, print `Yes`; otherwise, print `No`. Examples Input bac Output Yes Input bab Output No Input abc Output Yes Input aaa Output No Submitted Solution: ``` s = input() print("Yes" s.count("a") == 1 and s.count("b") == 1 and s.count("c") == 1 else "No") ```
instruction
0
78,959
18
157,918
No
output
1
78,959
18
157,919
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string S of length 3 consisting of `a`, `b` and `c`. Determine if S can be obtained by permuting `abc`. Constraints * |S|=3 * S consists of `a`, `b` and `c`. Input Input is given from Standard Input in the following format: S Output If S can be obtained by permuting `abc`, print `Yes`; otherwise, print `No`. Examples Input bac Output Yes Input bab Output No Input abc Output Yes Input aaa Output No Submitted Solution: ``` lst1 = list(input()) iflen(lst1) != 3: print("No") exit() for i in ["a","b","c"]: if not i in lst1: print("No") exit() print("Yes") ```
instruction
0
78,960
18
157,920
No
output
1
78,960
18
157,921
Provide a correct Python 3 solution for this coding contest problem. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC
instruction
0
78,993
18
157,986
"Correct Solution: ``` # A s = input() print("A"+ s[8]+ "C") ```
output
1
78,993
18
157,987
Provide a correct Python 3 solution for this coding contest problem. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC
instruction
0
78,994
18
157,988
"Correct Solution: ``` X=input() print(X[0]+X[8]+X[-7]) ```
output
1
78,994
18
157,989
Provide a correct Python 3 solution for this coding contest problem. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC
instruction
0
78,995
18
157,990
"Correct Solution: ``` print("A%sC"%input()[8]) ```
output
1
78,995
18
157,991
Provide a correct Python 3 solution for this coding contest problem. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC
instruction
0
78,996
18
157,992
"Correct Solution: ``` s = input() print("A" + str(s[8]) + "C") ```
output
1
78,996
18
157,993
Provide a correct Python 3 solution for this coding contest problem. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC
instruction
0
78,997
18
157,994
"Correct Solution: ``` s = input()[8] print("A{0}C".format(s)) ```
output
1
78,997
18
157,995
Provide a correct Python 3 solution for this coding contest problem. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC
instruction
0
78,998
18
157,996
"Correct Solution: ``` S = input().split() print('A'+S[1][0]+'C') ```
output
1
78,998
18
157,997
Provide a correct Python 3 solution for this coding contest problem. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC
instruction
0
78,999
18
157,998
"Correct Solution: ``` S = list(str(input())) print('A'+ S[8] +'C') ```
output
1
78,999
18
157,999
Provide a correct Python 3 solution for this coding contest problem. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC
instruction
0
79,000
18
158,000
"Correct Solution: ``` print("A%cC"%input()[8]) ```
output
1
79,000
18
158,001
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC Submitted Solution: ``` S = input() print(S[0]+S[8]+S[-7]) ```
instruction
0
79,001
18
158,002
Yes
output
1
79,001
18
158,003
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC Submitted Solution: ``` a, s, c = input().split() print('A'+s[0]+'C') ```
instruction
0
79,002
18
158,004
Yes
output
1
79,002
18
158,005
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC Submitted Solution: ``` x = input() print('A' + x[8] + 'C') ```
instruction
0
79,003
18
158,006
Yes
output
1
79,003
18
158,007
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC Submitted Solution: ``` s = input().split() print(f"A{s[1][0]}C") ```
instruction
0
79,004
18
158,008
Yes
output
1
79,004
18
158,009
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC Submitted Solution: ``` _, s, _ = input().split() print(s[0].upper()) ```
instruction
0
79,005
18
158,010
No
output
1
79,005
18
158,011
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC Submitted Solution: ``` a, x, c = input().split() print("{}{}{}".format(a, x[0], c)) ```
instruction
0
79,006
18
158,012
No
output
1
79,006
18
158,013
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC Submitted Solution: ``` print(input()[0] + input()[0] + input()[0]) ```
instruction
0
79,007
18
158,014
No
output
1
79,007
18
158,015
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Snuke is going to open a contest named "AtCoder s Contest". Here, s is a string of length 1 or greater, where the first character is an uppercase English letter, and the second and subsequent characters are lowercase English letters. Snuke has decided to abbreviate the name of the contest as "AxC". Here, x is the uppercase English letter at the beginning of s. Given the name of the contest, print the abbreviation of the name. Constraints * The length of s is between 1 and 100, inclusive. * The first character in s is an uppercase English letter. * The second and subsequent characters in s are lowercase English letters. Input The input is given from Standard Input in the following format: AtCoder s Contest Output Print the abbreviation of the name of the contest. Examples Input AtCoder Beginner Contest Output ABC Input AtCoder Snuke Contest Output ASC Input AtCoder X Contest Output AXC Submitted Solution: ``` a, b, c = list(map(str, input().split())) print(a,end='') print(b[0],end ='') print(c) ```
instruction
0
79,008
18
158,016
No
output
1
79,008
18
158,017
Provide a correct Python 3 solution for this coding contest problem. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba
instruction
0
79,046
18
158,092
"Correct Solution: ``` import sys s=sys.stdin while 1: n=int(s.readline()) if n==0:break d={} for _ in[0]*n: k,v=s.readline().strip().split() d[k]=v a='' for _ in[0]*int(s.readline()): e=s.readline().strip() a+=d[e]if e in d else e print(a) ```
output
1
79,046
18
158,093
Provide a correct Python 3 solution for this coding contest problem. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba
instruction
0
79,047
18
158,094
"Correct Solution: ``` n=int(input()) while(n!=0): list={} sum="" for i in range(n): a,b=input().split() list[a]=b.rstrip() n=int(input()) for i in range(n): s=input().rstrip() if s in list: sum+=list[s] else: sum+=s print(sum) n=int(input()) ```
output
1
79,047
18
158,095
Provide a correct Python 3 solution for this coding contest problem. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba
instruction
0
79,048
18
158,096
"Correct Solution: ``` while True: x = int(input()) if x == 0: break dcl = {} for i in range(x): inp = list(map(str, input().split())) dcl[inp[0]] = inp[1] ans = "" x = int(input()) for i in range(x): y = str(input()[0]) if y in dcl: ans += dcl[y] else: ans += y print(ans) ```
output
1
79,048
18
158,097
Provide a correct Python 3 solution for this coding contest problem. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba
instruction
0
79,049
18
158,098
"Correct Solution: ``` import sys while True: n = int(sys.stdin.readline().rstrip()) if n == 0: break; x = {} for i in range(n): k,v = sys.stdin.readline().rstrip().split() x[k] = v y = [] for i in range(int(sys.stdin.readline().rstrip())): a = sys.stdin.readline().rstrip() if a in x: y.append(x[a]) else: y.append(a) print(''.join(y)) ```
output
1
79,049
18
158,099
Provide a correct Python 3 solution for this coding contest problem. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba
instruction
0
79,050
18
158,100
"Correct Solution: ``` import sys s=sys.stdin f=lambda:s.readline() while 1: n=int(f()) if n==0:break d={} for _ in[0]*n: k,v=f().strip().split() d[k]=v a='' for _ in[0]*int(f()): e=f().strip() a+=d[e]if e in d else e print(a) ```
output
1
79,050
18
158,101
Provide a correct Python 3 solution for this coding contest problem. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba
instruction
0
79,051
18
158,102
"Correct Solution: ``` if __name__ == '__main__': # ??????????????\??? while True: conv_num = int(input().strip()) if conv_num == 0: break conv_dict = {} for i in range(conv_num): from_ch, to_ch = input().strip().split(' ') conv_dict[from_ch] = to_ch text_len = int(input().strip()) orig_txt = [input().strip() for _ in range(text_len)] # ??????????????? converted_txt = [] for c in orig_txt: if c in conv_dict: converted_txt.append(conv_dict[c]) else: converted_txt.append(c) # ???????????¨??? print('{0}'.format(''.join(map(str, converted_txt)))) ```
output
1
79,051
18
158,103
Provide a correct Python 3 solution for this coding contest problem. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba
instruction
0
79,052
18
158,104
"Correct Solution: ``` import math import string import itertools import fractions import heapq import collections import re import array import bisect while(True): after_string_list = [] before_string_list = [] convert_list = {} n = int(input()) if n == 0: break for i in range(n): convert = list(input().split()) convert_list[convert[0]] = convert[1] m = int(input()) for i in range(m): before_string_list.append(input().rstrip()) for c in before_string_list: if c in convert_list: after_string_list.append(convert_list[c]) else: after_string_list.append(c) print("".join(after_string_list)) ```
output
1
79,052
18
158,105
Provide a correct Python 3 solution for this coding contest problem. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba
instruction
0
79,053
18
158,106
"Correct Solution: ``` #!/home/minamo/.pyenv/versions/3.6.1/bin/python # vim: ft=python # coding: utf-8 def registerDictionaryFromTheNumberOf(counts): dictionary = {} for i in range(counts): key, value = input().split(" ") dictionary[key] = value return dictionary def readCharacterBeforeConversionAsManyAs(counts): readString = "" for i in range(counts): readString += input().rstrip() return readString def convertCharactersByThe(dictionary, target): converted = "" for index in range(len(list(target))): if target[index] in dictionary: converted += dictionary[target[index]] else: converted += target[index] return converted while True: dictionaryCounts = int(input()) if dictionaryCounts == 0: break dictionary = registerDictionaryFromTheNumberOf(dictionaryCounts) original = readCharacterBeforeConversionAsManyAs(int(input())) converted = convertCharactersByThe(dictionary, original) print(converted) ```
output
1
79,053
18
158,107
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba Submitted Solution: ``` while 1: n = int(input()) if n == 0: break dic = dict() for i in range(0,n): w1,w2 = input().split() dic[w1] = w2 n = int(input()) s = "" for i in range(0,n): w = input()[0] if dic.get(w) != None: s += dic.get(w) else: s += w print(s) ```
instruction
0
79,054
18
158,108
Yes
output
1
79,054
18
158,109
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba Submitted Solution: ``` import sys while True: n = int(input()) if n == 0: break; x = {} for i in range(n): k,v = sys.stdin.readline().rstrip().split() x[k] = v y = [] for i in range(int(sys.stdin.readline().rstrip())): a = sys.stdin.readline().rstrip() if a in x: y.append(x[a]) else: y.append(a) print(''.join(y)) ```
instruction
0
79,055
18
158,110
Yes
output
1
79,055
18
158,111
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba Submitted Solution: ``` import sys f=lambda:sys.stdin.readline() while 1: n=int(f()) if n==0:break d={} for _ in[0]*n: k,v=f().strip().split() d[k]=v a='' for _ in[0]*int(f()): e=f().strip() a+=d[e]if e in d else e print(a) ```
instruction
0
79,056
18
158,112
Yes
output
1
79,056
18
158,113
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba Submitted Solution: ``` while 1: n=int(input()) if n==0:break d={} for _ in[0]*n: k,v=input().strip().split() d[k]=v a='' for _ in[0]*int(input()): e=input().strip() a+=d[e]if e in d else e print(a) ```
instruction
0
79,057
18
158,114
Yes
output
1
79,057
18
158,115
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba Submitted Solution: ``` import sys while True: n = int(input()) if n == 0: break; x = {} for i in range(n): k,v = sys.stdin.readline().rstrip().split() x[k] = v y = [] for i in range(int(input())): a = input() if a in x: y.append(x[a]) else: y.append(a) print(''.join(y)) ```
instruction
0
79,058
18
158,116
No
output
1
79,058
18
158,117
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba Submitted Solution: ``` import sys f = sys.stdin n = int(f.readline()) converter = {} for _ in range(n): pre, post = f.readline().strip().split() converter[pre] = post m = int(f.readline()) for _ in range(m): c = f.readline().strip() print(converter[c] if c in converter else c, end='') print() ```
instruction
0
79,059
18
158,118
No
output
1
79,059
18
158,119
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba Submitted Solution: ``` while True: n = int(input()) if n == 0: break conversion = {} for i in range(n): before, after = input().split() conversion[before] = after m = int(input()) answer = [] for i in range(m): char = input() if char in conversion: answer.append(conversion[char]) else: answer.append(char) for w in answer: print(w, end="") print() ```
instruction
0
79,060
18
158,120
No
output
1
79,060
18
158,121
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Create a program that converts data based on the given conversion table. The characters used in the data are letters or numbers, and the letters are case sensitive. There is no regularity in the order of the characters that appear in the conversion table. The conversion table has two characters (not a string), one before and one after, with a space in between. The conversion method is to convert the character before the line in the conversion table to the character after each time it appears in the data and output it. It is converted only once, and even if the converted character becomes the character to be converted again, it is not converted. Characters that do not appear in the conversion table are not converted and are output as they are. In the input file, the conversion table (first n + 1 line) is followed by the data to be converted (n + 2nd line and after). The number of lines in the conversion table is n on the first line, each line of the following n lines is two characters with a blank, and then the number of lines of data to be converted on the n + second line m, and each line of the following m lines. Is a single character. Let m ≤ 105. Output should be one line without blanks or line breaks as in the output example. Input example --- 3 A a 0 5 5 4 Ten A B C 0 1 Four Five a b b A Output example aBC5144aba input The input consists of multiple datasets. Input ends when n is 0. The number of datasets does not exceed 5. output For each data set, the converted character string is output on one line. Example Input 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 3 A a 0 5 5 4 10 A B C 0 1 4 5 a b A 0 Output aBC5144aba aBC5144aba Submitted Solution: ``` while True: n = int(input()) if n == 0: break pre = "" post = "" for _ in range(n): l = input().split() pre += l[0] post += l[1] m = int(input()) data = "" for _ in range(m): data += input() print(data.translate(str.maketrans(pre, post)), end="") ```
instruction
0
79,061
18
158,122
No
output
1
79,061
18
158,123
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This problem is different with hard version only by constraints on total answers length It is an interactive problem Venya joined a tour to the madhouse, in which orderlies play with patients the following game. Orderlies pick a string s of length n, consisting only of lowercase English letters. The player can ask two types of queries: * ? l r – ask to list all substrings of s[l..r]. Substrings will be returned in random order, and in every substring, all characters will be randomly shuffled. * ! s – guess the string picked by the orderlies. This query can be asked exactly once, after that the game will finish. If the string is guessed correctly, the player wins, otherwise he loses. The player can ask no more than 3 queries of the first type. To make it easier for the orderlies, there is an additional limitation: the total number of returned substrings in all queries of the first type must not exceed (n+1)^2. Venya asked you to write a program, which will guess the string by interacting with the orderlies' program and acting by the game's rules. Your program should immediately terminate after guessing the string using a query of the second type. In case your program guessed the string incorrectly, or it violated the game rules, it will receive verdict Wrong answer. Note that in every test case the string is fixed beforehand and will not change during the game, which means that the interactor is not adaptive. Input First line contains number n (1 ≤ n ≤ 100) — the length of the picked string. Interaction You start the interaction by reading the number n. To ask a query about a substring from l to r inclusively (1 ≤ l ≤ r ≤ n), you should output ? l r on a separate line. After this, all substrings of s[l..r] will be returned in random order, each substring exactly once. In every returned substring all characters will be randomly shuffled. In the case, if you ask an incorrect query, ask more than 3 queries of the first type or there will be more than (n+1)^2 substrings returned in total, you will receive verdict Wrong answer. To guess the string s, you should output ! s on a separate line. After printing each query, do not forget to flush the output. Otherwise, you will get Idleness limit exceeded. To flush the output, you can use: * fflush(stdout) or cout.flush() in C++; * System.out.flush() in Java; * flush(output) in Pascal; * stdout.flush() in Python; * see documentation for other languages. If you received - (dash) as an answer to any query, you need to terminate your program with exit code 0 (for example, by calling exit(0)). This means that there was an error in the interaction protocol. If you don't terminate with exit code 0, you can receive any unsuccessful verdict. Hack format To hack a solution, use the following format: The first line should contain one integer n (1 ≤ n ≤ 100) — the length of the string, and the following line should contain the string s. Example Input 4 a aa a cb b c c Output ? 1 2 ? 3 4 ? 4 4 ! aabc Submitted Solution: ``` from sys import stdout class String2: def __init__(self, s, b=None): if b is not None: self.b = b return self.b = [0] * 26 for i in s: self.b[ord(i) - ord('a')] += 1 def __add__(self, other): b = self.b.copy() for i in range(26): b[i] += other.b[i] return String2('', b) def __sub__(self, other): b = self.b.copy() for i in range(26): b[i] -= other.b[i] return b def __mul__(self, other): ans = String2('', self.b) for i in range(26): ans.b[i] *= other return ans def req(l, r, k=0): print('?', l, r) v = [''.join(sorted(input())) for i in range((r - l + 1) * (r - l + 2) // 2)] stdout.flush() return v def compute(v): bukvi = [[0] * (n + 2) for _ in range(26)] for el in v: cur = len(el) for e in el: bukvi[ord(e) - ord('a')][cur] += 1 return bukvi def compute2(bukvi): bukvis = [set() for i in range(n + 2)] for i in range(26): prev = bukvi[i][1] for j in range(1, n // 2 + n % 2 + 1): while bukvi[i][j] != prev: bukvis[j].add(chr(ord('a') + i)) prev += 1 return bukvis def solve(va, va2): for i in va2: va.remove(i) va.sort(key=len) s = va[0] for i in range(1, len(va)): for j in range(26): if va[i].count(chr(ord('a') + j)) != va[i - 1].count(chr(ord('a') + j)): s += chr(ord('a') + j) return s def check(v, s, s2, f): s3 = String2(v[0]) for i in range(1, len(v)): s3 = s3 + String2(v[i]) le = len(v[0]) cur = String2('', String2('', f - String2(s)) - String2(s2)) * le for i in range(le - 2): cur = cur + (String2(s[i]) * (i + 1)) + (String2(s2[-i]) * (i + 1)) cur = cur + (String2(s[le - 2]) * (le - 1)) + (String2(s[le - 1]) * le) e = cur - s3 for i in range(26): if e[i]: return chr(ord('a') + i) def main(): if n == 1: va = req(1, 1) print('!', va[0]) return elif n == 2: va2 = req(1, 1) va3 = req(2, 2) print('!', va2[0] + va3[0]) return elif n == 3: va = req(1, 1) va2 = req(2, 2) va3 = req(3, 3) print('!', va[0] + va2[0] + va3[0]) return va = req(1, n) va2 = req(1, max(n // 2 + n % 2, 2)) va3 = req(2, max(n // 2 + n % 2, 2)) # bukvi2 = compute(va2) # bukvi3 = compute(va3) ma = [[] for i in range(n * 2)] for i in va: ma[len(i)].append(i) a = String2(''.join(ma[1])) s = solve(va2, va3) s2 = '' for i in range(2, n // 2 + 1): s2 = check(ma[i], s, s2, a) + s2 se = String2('', a - String2(s)) - String2(s2) for i in range(len(se)): if se[i]: s += chr(ord('a') + i) break print('!', s + s2) n = int(input()) main() ```
instruction
0
79,286
18
158,572
No
output
1
79,286
18
158,573
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This problem is different with hard version only by constraints on total answers length It is an interactive problem Venya joined a tour to the madhouse, in which orderlies play with patients the following game. Orderlies pick a string s of length n, consisting only of lowercase English letters. The player can ask two types of queries: * ? l r – ask to list all substrings of s[l..r]. Substrings will be returned in random order, and in every substring, all characters will be randomly shuffled. * ! s – guess the string picked by the orderlies. This query can be asked exactly once, after that the game will finish. If the string is guessed correctly, the player wins, otherwise he loses. The player can ask no more than 3 queries of the first type. To make it easier for the orderlies, there is an additional limitation: the total number of returned substrings in all queries of the first type must not exceed (n+1)^2. Venya asked you to write a program, which will guess the string by interacting with the orderlies' program and acting by the game's rules. Your program should immediately terminate after guessing the string using a query of the second type. In case your program guessed the string incorrectly, or it violated the game rules, it will receive verdict Wrong answer. Note that in every test case the string is fixed beforehand and will not change during the game, which means that the interactor is not adaptive. Input First line contains number n (1 ≤ n ≤ 100) — the length of the picked string. Interaction You start the interaction by reading the number n. To ask a query about a substring from l to r inclusively (1 ≤ l ≤ r ≤ n), you should output ? l r on a separate line. After this, all substrings of s[l..r] will be returned in random order, each substring exactly once. In every returned substring all characters will be randomly shuffled. In the case, if you ask an incorrect query, ask more than 3 queries of the first type or there will be more than (n+1)^2 substrings returned in total, you will receive verdict Wrong answer. To guess the string s, you should output ! s on a separate line. After printing each query, do not forget to flush the output. Otherwise, you will get Idleness limit exceeded. To flush the output, you can use: * fflush(stdout) or cout.flush() in C++; * System.out.flush() in Java; * flush(output) in Pascal; * stdout.flush() in Python; * see documentation for other languages. If you received - (dash) as an answer to any query, you need to terminate your program with exit code 0 (for example, by calling exit(0)). This means that there was an error in the interaction protocol. If you don't terminate with exit code 0, you can receive any unsuccessful verdict. Hack format To hack a solution, use the following format: The first line should contain one integer n (1 ≤ n ≤ 100) — the length of the string, and the following line should contain the string s. Example Input 4 a aa a cb b c c Output ? 1 2 ? 3 4 ? 4 4 ! aabc Submitted Solution: ``` #!usr/bin/env python3 from collections import defaultdict,deque from heapq import heappush, heappop from itertools import permutations import sys import math import bisect import random def LI(): return [int(x) for x in sys.stdin.readline().split()] def I(): return int(sys.stdin.readline()) def LS():return [list(x) for x in sys.stdin.readline().split()] def S(): res = list(sys.stdin.readline()) if res[-1] == "\n": return res[:-1] return res def IR(n): return [I() for i in range(n)] def LIR(n): return [LI() for i in range(n)] def SR(n): return [S() for i in range(n)] def LSR(n): return [LS() for i in range(n)] sys.setrecursionlimit(1000000) mod = 1000000007 def solve(): n = I() l = 1 r = n print("?",l,r) sys.stdin.flush() if n == 1: print("!",input()) return s1 = defaultdict(lambda : 0) for i in range((n*(n+1))>>1): s = input() s1[s] += 1 r = n >> 1 m = r-l+1 print("?",l,r) sys.stdin.flush() for i in range((m*(m+1))>>1): s = input() s1[s] -= 1 l = r + 1 r = n m = r-l+1 print("?",l,r) sys.stdin.flush() for i in range((m*(m+1))>>1): s = input() s1[s] -= 1 l = (n >> 1)-1 r = l+1 t = [[] for i in range(n+1)] for i,j in s1.items(): if j: t[len(i)].append(i) print("!",t[1]) ans = t[2][0][0]+t[2][0][1] for k in range(3,n+1): for s in t[k]: if s[1:] == ans: ans = s[0]+ans elif s[:-1] == ans: ans += s[-1] print("!",ans) return #Solve if __name__ == "__main__": solve() ```
instruction
0
79,287
18
158,574
No
output
1
79,287
18
158,575
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This problem is different with hard version only by constraints on total answers length It is an interactive problem Venya joined a tour to the madhouse, in which orderlies play with patients the following game. Orderlies pick a string s of length n, consisting only of lowercase English letters. The player can ask two types of queries: * ? l r – ask to list all substrings of s[l..r]. Substrings will be returned in random order, and in every substring, all characters will be randomly shuffled. * ! s – guess the string picked by the orderlies. This query can be asked exactly once, after that the game will finish. If the string is guessed correctly, the player wins, otherwise he loses. The player can ask no more than 3 queries of the first type. To make it easier for the orderlies, there is an additional limitation: the total number of returned substrings in all queries of the first type must not exceed (n+1)^2. Venya asked you to write a program, which will guess the string by interacting with the orderlies' program and acting by the game's rules. Your program should immediately terminate after guessing the string using a query of the second type. In case your program guessed the string incorrectly, or it violated the game rules, it will receive verdict Wrong answer. Note that in every test case the string is fixed beforehand and will not change during the game, which means that the interactor is not adaptive. Input First line contains number n (1 ≤ n ≤ 100) — the length of the picked string. Interaction You start the interaction by reading the number n. To ask a query about a substring from l to r inclusively (1 ≤ l ≤ r ≤ n), you should output ? l r on a separate line. After this, all substrings of s[l..r] will be returned in random order, each substring exactly once. In every returned substring all characters will be randomly shuffled. In the case, if you ask an incorrect query, ask more than 3 queries of the first type or there will be more than (n+1)^2 substrings returned in total, you will receive verdict Wrong answer. To guess the string s, you should output ! s on a separate line. After printing each query, do not forget to flush the output. Otherwise, you will get Idleness limit exceeded. To flush the output, you can use: * fflush(stdout) or cout.flush() in C++; * System.out.flush() in Java; * flush(output) in Pascal; * stdout.flush() in Python; * see documentation for other languages. If you received - (dash) as an answer to any query, you need to terminate your program with exit code 0 (for example, by calling exit(0)). This means that there was an error in the interaction protocol. If you don't terminate with exit code 0, you can receive any unsuccessful verdict. Hack format To hack a solution, use the following format: The first line should contain one integer n (1 ≤ n ≤ 100) — the length of the string, and the following line should contain the string s. Example Input 4 a aa a cb b c c Output ? 1 2 ? 3 4 ? 4 4 ! aabc Submitted Solution: ``` mod = 1000000007 eps = 10**-9 def main(): import sys from collections import Counter input = sys.stdin.readline def ask(l, r): print(*["?", l, r]) sys.stdout.flush() N = int(input()) ask(1, N) ret1 = [] for _ in range(N * (N+1) // 2): s = input().rstrip('\n') if s == "-": exit() ret1.append("".join(sorted(s))) if N == 1: ans = ret1[0] print("!", ans) sys.stdout.flush() exit() ask(1, N-1) ret2 = [] for _ in range(N * (N - 1) // 2): s = input().rstrip('\n') if s == "-": exit() ret2.append("".join(sorted(s))) dic1 = [{} for _ in range(N+1)] dic2 = [{} for _ in range(N+1)] for s in ret1: L = len(s) if L == N: S_all = s if s in dic1[L]: dic1[L][s] += 1 else: dic1[L][s] = 1 for s in ret2: L = len(s) if s in dic2[L]: dic2[L][s] += 1 else: dic2[L][s] = 1 right = [""] * (N+1) for L in range(N-1, 0, -1): for s in dic1[L]: if s not in dic2[L]: right[L] = s break if dic1[L][s] != dic2[L][s]: right[L] = s break ans = [""] * N dic = {chr(i+97): 0 for i in range(26)} for L in range(1, N): C = Counter(right[L]) for i in range(26): s = chr(i+97) if dic[s] != C[s]: ans[-L] = s dic[s] += 1 break #print(ans, L, right[L]) C = Counter(S_all) for i in range(26): s = chr(i + 97) if dic[s] != C[s]: ans[0] = s dic[s] += 1 break print("!", "".join(ans)) sys.stdout.flush() if __name__ == '__main__': main() ```
instruction
0
79,288
18
158,576
No
output
1
79,288
18
158,577
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. This problem is different with hard version only by constraints on total answers length It is an interactive problem Venya joined a tour to the madhouse, in which orderlies play with patients the following game. Orderlies pick a string s of length n, consisting only of lowercase English letters. The player can ask two types of queries: * ? l r – ask to list all substrings of s[l..r]. Substrings will be returned in random order, and in every substring, all characters will be randomly shuffled. * ! s – guess the string picked by the orderlies. This query can be asked exactly once, after that the game will finish. If the string is guessed correctly, the player wins, otherwise he loses. The player can ask no more than 3 queries of the first type. To make it easier for the orderlies, there is an additional limitation: the total number of returned substrings in all queries of the first type must not exceed (n+1)^2. Venya asked you to write a program, which will guess the string by interacting with the orderlies' program and acting by the game's rules. Your program should immediately terminate after guessing the string using a query of the second type. In case your program guessed the string incorrectly, or it violated the game rules, it will receive verdict Wrong answer. Note that in every test case the string is fixed beforehand and will not change during the game, which means that the interactor is not adaptive. Input First line contains number n (1 ≤ n ≤ 100) — the length of the picked string. Interaction You start the interaction by reading the number n. To ask a query about a substring from l to r inclusively (1 ≤ l ≤ r ≤ n), you should output ? l r on a separate line. After this, all substrings of s[l..r] will be returned in random order, each substring exactly once. In every returned substring all characters will be randomly shuffled. In the case, if you ask an incorrect query, ask more than 3 queries of the first type or there will be more than (n+1)^2 substrings returned in total, you will receive verdict Wrong answer. To guess the string s, you should output ! s on a separate line. After printing each query, do not forget to flush the output. Otherwise, you will get Idleness limit exceeded. To flush the output, you can use: * fflush(stdout) or cout.flush() in C++; * System.out.flush() in Java; * flush(output) in Pascal; * stdout.flush() in Python; * see documentation for other languages. If you received - (dash) as an answer to any query, you need to terminate your program with exit code 0 (for example, by calling exit(0)). This means that there was an error in the interaction protocol. If you don't terminate with exit code 0, you can receive any unsuccessful verdict. Hack format To hack a solution, use the following format: The first line should contain one integer n (1 ≤ n ≤ 100) — the length of the string, and the following line should contain the string s. Example Input 4 a aa a cb b c c Output ? 1 2 ? 3 4 ? 4 4 ! aabc Submitted Solution: ``` #!usr/bin/env python3 from collections import defaultdict,deque from heapq import heappush, heappop from itertools import permutations import sys import math import bisect import random def LI(): return [int(x) for x in sys.stdin.readline().split()] def I(): return int(sys.stdin.readline()) def LS():return [list(x) for x in sys.stdin.readline().split()] def S(): res = list(sys.stdin.readline()) if res[-1] == "\n": return res[:-1] return res def IR(n): return [I() for i in range(n)] def LIR(n): return [LI() for i in range(n)] def SR(n): return [S() for i in range(n)] def LSR(n): return [LS() for i in range(n)] sys.setrecursionlimit(1000000) mod = 1000000007 def solve(): n = I() l = 1 r = n print("?",l,r) sys.stdin.flush() if n == 1: print("!",input()) return s1 = defaultdict(lambda : 0) for i in range((n*(n+1))>>1): s = input() s1[s] += 1 r = n >> 1 m = r-l+1 print("?",l,r) sys.stdin.flush() for i in range((m*(m+1))>>1): s = input() s1[s] -= 1 l = r + 1 r = n m = r-l+1 print("?",l,r) sys.stdin.flush() for i in range((m*(m+1))>>1): s = input() s1[s] -= 1 print("!",s1) l = (n >> 1)-1 r = l+1 t = [[] for i in range(n+1)] for i,j in s1.items(): if j: t[len(i)].append(i) ans = t[2][0][0]+t[2][0][1] for k in range(3,n+1): for s in t[k]: if s[1:] == ans: ans = s[0]+ans elif s[:-1] == ans: ans += s[-1] print("!",ans) return #Solve if __name__ == "__main__": solve() ```
instruction
0
79,289
18
158,578
No
output
1
79,289
18
158,579
Provide a correct Python 3 solution for this coding contest problem. You have obtained the Izua Japanese dictionary, which is the official language of Izua, and the Izua alphabet (list of letters). There are N types of letters in the Izua alphabet. The order of the words that appear in the Izua Japanese dictionary is in the alphabetical order of Izua. Looking at the dictionary, I found that every word in the dictionary is N letters and contains N kinds of letters one by one. Upon further investigation, I found that the dictionary contained all possible arrangements of the N characters. From this discovery, you can see what number a word appears in the dictionary. Use this knowledge to surprise people in Izua. First, arrange the N types of letters one by one in alphabetical order. Next, ask them to repeat the operation of changing the order of any two characters R times. You can guess the number of the finished word in the Izua Japanese dictionary. In preparation for that, create a program that finds the location of words in the Japanese dictionary. However, the first word in alphabetical order is the 0th word. input The input consists of multiple datasets. The end of the input is indicated by a single zero line. Each dataset is given in the following format. N R s1 t1 s2 t2 :: sR tR The first line is given the number of characters that make up the alphabet N (1 ≤ N ≤ 100000), and the second line is given the number of times R (0 ≤ R ≤ 50) to have the characters replaced. The following R line is given the set of character positions to be swapped. si and ti (1 ≤ si <ti ≤ N) represent the i-th swapping of the si and ti characters counting from the beginning. si and ti are separated by a single space. The number of datasets does not exceed 100. output For each data set, the number indicating the number of the word obtained at the end of the replacement in the Japanese dictionary is output on one line. However, the value to be output can be very large, so instead output the remainder divided by 1,000,000,007. Example Input 3 2 1 2 2 3 4 2 2 3 2 4 0 Output 3 4
instruction
0
79,849
18
159,698
"Correct Solution: ``` import sys readline = sys.stdin.readline write = sys.stdout.write def main(): MOD = 10**9 + 7 def query(k0): s = 0 k = k0 while k: s += data[k] k -= k & -k k = k0 while k <= N: data[k] += 1 k += k & -k return s % MOD L = 100000 fact = [1]*(L+1) rfact = [1]*(L+1) r = 1 for i in range(2, L+1): fact[i] = r = i * r % MOD rfact[i] = r = pow(fact[i], MOD-2, MOD) for i in range(L, 0, -1): rfact[i-1] = r = i * r % MOD while 1: N = int(readline()) if N == 0: break R = int(readline()) *S, = range(N) for i in range(R): s, t = map(int, readline().split()); s -= 1; t -= 1 S[s], S[t] = S[t], S[s] data = [0]*(N+1) write("%d\n" % (sum(fact[N-1-i] * (e - query(e+1)) % MOD for i, e in enumerate(S)) % MOD)) main() ```
output
1
79,849
18
159,699
Provide a correct Python 3 solution for this coding contest problem. You have obtained the Izua Japanese dictionary, which is the official language of Izua, and the Izua alphabet (list of letters). There are N types of letters in the Izua alphabet. The order of the words that appear in the Izua Japanese dictionary is in the alphabetical order of Izua. Looking at the dictionary, I found that every word in the dictionary is N letters and contains N kinds of letters one by one. Upon further investigation, I found that the dictionary contained all possible arrangements of the N characters. From this discovery, you can see what number a word appears in the dictionary. Use this knowledge to surprise people in Izua. First, arrange the N types of letters one by one in alphabetical order. Next, ask them to repeat the operation of changing the order of any two characters R times. You can guess the number of the finished word in the Izua Japanese dictionary. In preparation for that, create a program that finds the location of words in the Japanese dictionary. However, the first word in alphabetical order is the 0th word. input The input consists of multiple datasets. The end of the input is indicated by a single zero line. Each dataset is given in the following format. N R s1 t1 s2 t2 :: sR tR The first line is given the number of characters that make up the alphabet N (1 ≤ N ≤ 100000), and the second line is given the number of times R (0 ≤ R ≤ 50) to have the characters replaced. The following R line is given the set of character positions to be swapped. si and ti (1 ≤ si <ti ≤ N) represent the i-th swapping of the si and ti characters counting from the beginning. si and ti are separated by a single space. The number of datasets does not exceed 100. output For each data set, the number indicating the number of the word obtained at the end of the replacement in the Japanese dictionary is output on one line. However, the value to be output can be very large, so instead output the remainder divided by 1,000,000,007. Example Input 3 2 1 2 2 3 4 2 2 3 2 4 0 Output 3 4
instruction
0
79,850
18
159,700
"Correct Solution: ``` def solve(): from sys import stdin m = 1000000007 f_i = stdin while True: N = int(f_i.readline()) if N == 0: break w = list(range(N)) R = int(f_i.readline()) for i in range(R): s, t = map(int, f_i.readline().split()) s -= 1 t -= 1 w[s], w[t] = w[t], w[s] s = [(i, c) for i, c in enumerate(w) if i != c] s.sort(reverse=True) a = 1 f = 1 cnt = 0 for c1, i in zip(w[::-1], range(N - 1, -1, -1)): if c1 > i: l = c1 n = c1 - i - 1 else: l = i n = 0 for j, c2 in s: if j <= i: break else: if j < l: n -= 1 if c2 < c1: n += 1 cnt = (cnt + (n * a) % m) % m a = (a * f) % m f += 1 print(cnt) solve() ```
output
1
79,850
18
159,701
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You have obtained the Izua Japanese dictionary, which is the official language of Izua, and the Izua alphabet (list of letters). There are N types of letters in the Izua alphabet. The order of the words that appear in the Izua Japanese dictionary is in the alphabetical order of Izua. Looking at the dictionary, I found that every word in the dictionary is N letters and contains N kinds of letters one by one. Upon further investigation, I found that the dictionary contained all possible arrangements of the N characters. From this discovery, you can see what number a word appears in the dictionary. Use this knowledge to surprise people in Izua. First, arrange the N types of letters one by one in alphabetical order. Next, ask them to repeat the operation of changing the order of any two characters R times. You can guess the number of the finished word in the Izua Japanese dictionary. In preparation for that, create a program that finds the location of words in the Japanese dictionary. However, the first word in alphabetical order is the 0th word. input The input consists of multiple datasets. The end of the input is indicated by a single zero line. Each dataset is given in the following format. N R s1 t1 s2 t2 :: sR tR The first line is given the number of characters that make up the alphabet N (1 ≤ N ≤ 100000), and the second line is given the number of times R (0 ≤ R ≤ 50) to have the characters replaced. The following R line is given the set of character positions to be swapped. si and ti (1 ≤ si <ti ≤ N) represent the i-th swapping of the si and ti characters counting from the beginning. si and ti are separated by a single space. The number of datasets does not exceed 100. output For each data set, the number indicating the number of the word obtained at the end of the replacement in the Japanese dictionary is output on one line. However, the value to be output can be very large, so instead output the remainder divided by 1,000,000,007. Example Input 3 2 1 2 2 3 4 2 2 3 2 4 0 Output 3 4 Submitted Solution: ``` class BIT: MAX_IDX = 100001 def __init__(self): self.bit = [0 for i in range(self.MAX_IDX+1)] def update(self,idx,v): while idx <= self.MAX_IDX: self.bit[idx] += v idx += idx & (-idx) def sum(self,idx): res = 0 while idx > 0: res += self.bit[idx] idx -= idx & (-idx) return res MAX_IDX = 100001 MOD_V = 1000000007 dp = [0 for i in range(MAX_IDX)] dp[0] = 1 while 1: N = int(input()) if N == 0:break bit = BIT() izua=[i for i in range(N+1)] for i in range(1,N+1): if dp[i] == 0: dp[i] = (dp[i-1]*i) % MOD_V R = int(input()) for i in range(R):#swap s,t = list(map(int,input().split())) w = izua[t] izua[t] = izua[s] izua[s] = w res = 0 for i in range(N,0,-1): res += (bit.sum(izua[i])*dp[N-i]) % MOD_V bit.update(izua[i],1) print (res%MOD_V) ```
instruction
0
79,851
18
159,702
No
output
1
79,851
18
159,703
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You have obtained the Izua Japanese dictionary, which is the official language of Izua, and the Izua alphabet (list of letters). There are N types of letters in the Izua alphabet. The order of the words that appear in the Izua Japanese dictionary is in the alphabetical order of Izua. Looking at the dictionary, I found that every word in the dictionary is N letters and contains N kinds of letters one by one. Upon further investigation, I found that the dictionary contained all possible arrangements of the N characters. From this discovery, you can see what number a word appears in the dictionary. Use this knowledge to surprise people in Izua. First, arrange the N types of letters one by one in alphabetical order. Next, ask them to repeat the operation of changing the order of any two characters R times. You can guess the number of the finished word in the Izua Japanese dictionary. In preparation for that, create a program that finds the location of words in the Japanese dictionary. However, the first word in alphabetical order is the 0th word. input The input consists of multiple datasets. The end of the input is indicated by a single zero line. Each dataset is given in the following format. N R s1 t1 s2 t2 :: sR tR The first line is given the number of characters that make up the alphabet N (1 ≤ N ≤ 100000), and the second line is given the number of times R (0 ≤ R ≤ 50) to have the characters replaced. The following R line is given the set of character positions to be swapped. si and ti (1 ≤ si <ti ≤ N) represent the i-th swapping of the si and ti characters counting from the beginning. si and ti are separated by a single space. The number of datasets does not exceed 100. output For each data set, the number indicating the number of the word obtained at the end of the replacement in the Japanese dictionary is output on one line. However, the value to be output can be very large, so instead output the remainder divided by 1,000,000,007. Example Input 3 2 1 2 2 3 4 2 2 3 2 4 0 Output 3 4 Submitted Solution: ``` class BIT: MAX_IDX = 100001 def __init__(self): self.bit = [0 for i in range(self.MAX_IDX+1)] def update(self,idx,v): while idx <= self.MAX_IDX: self.bit[idx] += v idx += idx & (-idx) def sum(self,idx): res = 0 while idx > 0: res += self.bit[idx] idx -= idx & (-idx) return res MAX_IDX = 100001 dp = [0 for i in range(MAX_IDX)] dp[0] = 1 while 1: N = int(input()) if N == 0:break bit = BIT() izua=[i for i in range(N+1)] for i in range(1,N+1): if dp[i] == 0: dp[i] = (dp[i-1]*i) #% 1000000007 R = int(input()) for i in range(R):#swap s,t = list(map(int,input().split())) w = izua[t] izua[t] = izua[s] izua[s] = w res = 0 for i in range(N,0,-1): res += (bit.sum(izua[i])*dp[N-i]) % 1000000007 bit.update(izua[i],1) print (res) ```
instruction
0
79,852
18
159,704
No
output
1
79,852
18
159,705
Provide a correct Python 3 solution for this coding contest problem. Airport Codes Airport code In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification. Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet: 1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order. 2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code. For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t. However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this. Input The input consists of 100 or less datasets. Each dataset is given in the following format. > n > s1 > ... > sn The number of airports n (2 ≤ n ≤ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 ≤ i <j ≤ n, si ≠ sj is satisfied. The end of the input is indicated by a line consisting of only one zero. Output For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line. Sample Input 3 haneda oookayama tsu 2 azusa azishirabe 2 snuke snake Four haneda honda hanamaki hawaii 0 Output for Sample Input 1 Four -1 3 Example Input 3 haneda oookayama tsu 2 azusa azishirabe 2 snuke snake 4 haneda honda hanamaki hawaii 0 Output 1 4 -1 3
instruction
0
79,882
18
159,764
"Correct Solution: ``` boin = set(['a', 'i', 'u', 'e', 'o']) def convert(name): s = name[0] for i, c in enumerate(name[1:], 1): if name[i - 1] in boin: s += name[i] return s while True: n = int(input()) if n == 0: break names = [input() for _ in range(n)] conv = [convert(n) for n in names] l = sum([len(c) for c in conv]) ans = -1 for k in range(1, l + 1): short = set([c[:k] for c in conv]) if len(short) == n: ans = k break print(ans) ```
output
1
79,882
18
159,765
Provide a correct Python 3 solution for this coding contest problem. Airport Codes Airport code In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification. Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet: 1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order. 2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code. For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t. However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this. Input The input consists of 100 or less datasets. Each dataset is given in the following format. > n > s1 > ... > sn The number of airports n (2 ≤ n ≤ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 ≤ i <j ≤ n, si ≠ sj is satisfied. The end of the input is indicated by a line consisting of only one zero. Output For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line. Sample Input 3 haneda oookayama tsu 2 azusa azishirabe 2 snuke snake Four haneda honda hanamaki hawaii 0 Output for Sample Input 1 Four -1 3 Example Input 3 haneda oookayama tsu 2 azusa azishirabe 2 snuke snake 4 haneda honda hanamaki hawaii 0 Output 1 4 -1 3
instruction
0
79,883
18
159,766
"Correct Solution: ``` #!/usr/bin/env python3 # -*- coding: utf-8 -*- import re def enc(s): repatter = re.compile(r"[aiueo]") ans = s[0] for i in range(len(s)): if i < len(s)-1 and repatter.match(s[i]): ans += s[i+1] return ans def max_str(s): ans = len(s[0]) for i in s: ans = max(ans, len(i)) return ans def func(s, mn, k): if mn < k: return -1 ss = [] for i in s: ss.append(i[:k]) for i in range(len(ss)-1): pp = ss.pop(0) if pp in ss: return func(s, mn, k+1) return k if __name__ == "__main__": while True: n = int(input()) if n is 0: break s = [] for i in range(n): s.append(enc(input())) print(func(s, max_str(s), 1)) ```
output
1
79,883
18
159,767
Provide a correct Python 3 solution for this coding contest problem. Airport Codes Airport code In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification. Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet: 1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order. 2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code. For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t. However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this. Input The input consists of 100 or less datasets. Each dataset is given in the following format. > n > s1 > ... > sn The number of airports n (2 ≤ n ≤ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 ≤ i <j ≤ n, si ≠ sj is satisfied. The end of the input is indicated by a line consisting of only one zero. Output For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line. Sample Input 3 haneda oookayama tsu 2 azusa azishirabe 2 snuke snake Four haneda honda hanamaki hawaii 0 Output for Sample Input 1 Four -1 3 Example Input 3 haneda oookayama tsu 2 azusa azishirabe 2 snuke snake 4 haneda honda hanamaki hawaii 0 Output 1 4 -1 3
instruction
0
79,884
18
159,768
"Correct Solution: ``` # coding: utf-8 import sys def coding(s): t = '' flag = True for i in s: if flag: t += i flag = False if i == 'a' or i == 'i' or i == 'u' or i == 'e' or i == 'o': flag = True; return t def pre_possible(ls): flag = False for i in range(len(ls)): for j in range(i+1,len(ls)): if ls[i] == ls[j]: flag = True return flag def possible(ls,k): flag = True for i in range(len(ls)): for j in range(i+1,len(ls)): if len(ls[i]) < k or len(ls[j]) < k: if ls[i] == ls[j]: flag = False break else: continue if ls[i][0:k] == ls[j][0:k]: flag = False break if not(flag): break return flag if __name__ == '__main__': while(1): n = int(input()); if n == 0: break l = [] for i in range(n): l.append(input()) nl = [] for i in l: nl.append(coding(i)) sz = min([len(i) for i in l]) ll = 0 hh = 50 if pre_possible(nl): print(-1) continue while True: mid = (ll + hh) // 2 if ll == mid: print(hh) break if possible(nl,mid): hh = mid else: ll = mid ```
output
1
79,884
18
159,769
Provide a correct Python 3 solution for this coding contest problem. Airport Codes Airport code In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification. Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet: 1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order. 2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code. For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t. However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this. Input The input consists of 100 or less datasets. Each dataset is given in the following format. > n > s1 > ... > sn The number of airports n (2 ≤ n ≤ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 ≤ i <j ≤ n, si ≠ sj is satisfied. The end of the input is indicated by a line consisting of only one zero. Output For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line. Sample Input 3 haneda oookayama tsu 2 azusa azishirabe 2 snuke snake Four haneda honda hanamaki hawaii 0 Output for Sample Input 1 Four -1 3 Example Input 3 haneda oookayama tsu 2 azusa azishirabe 2 snuke snake 4 haneda honda hanamaki hawaii 0 Output 1 4 -1 3
instruction
0
79,885
18
159,770
"Correct Solution: ``` V = {"a", "i", "u", "e", "o"} while True: N = int(input()) if N==0: exit() L = [] maxs = 0 for _ in range(N): s = input() s_ = s[0] for i in range(len(s)-1): if s[i] in V: s_ += s[i+1] maxs = max(maxs, len(s_)) L.append(s_ + "."*(51-len(s_))) L.sort() k = 1 for s1, s2 in zip(L[:-1], L[1:]): while k != 51 and s1[:k] == s2[:k]: k += 1 if k==51: print(-1) else: print(k) ```
output
1
79,885
18
159,771
Provide a correct Python 3 solution for this coding contest problem. Airport Codes Airport code In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification. Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet: 1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order. 2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code. For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t. However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this. Input The input consists of 100 or less datasets. Each dataset is given in the following format. > n > s1 > ... > sn The number of airports n (2 ≤ n ≤ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 ≤ i <j ≤ n, si ≠ sj is satisfied. The end of the input is indicated by a line consisting of only one zero. Output For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line. Sample Input 3 haneda oookayama tsu 2 azusa azishirabe 2 snuke snake Four haneda honda hanamaki hawaii 0 Output for Sample Input 1 Four -1 3 Example Input 3 haneda oookayama tsu 2 azusa azishirabe 2 snuke snake 4 haneda honda hanamaki hawaii 0 Output 1 4 -1 3
instruction
0
79,886
18
159,772
"Correct Solution: ``` import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools sys.setrecursionlimit(10**7) inf = 10**20 eps = 1.0 / 10**10 mod = 998244353 def LI(): return [int(x) for x in sys.stdin.readline().split()] def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()] def LF(): return [float(x) for x in sys.stdin.readline().split()] def LS(): return sys.stdin.readline().split() def I(): return int(sys.stdin.readline()) def F(): return float(sys.stdin.readline()) def S(): return input() def pf(s): return print(s, flush=True) def main(): rr = [] while True: n = I() if n == 0: break a = [S() for _ in range(n)] b = [] for s in a: t = s[0] for i in range(len(s)-1): if s[i] in 'aiueo': t += s[i+1] b.append(t) r = -1 for k in range(1,51): s = set() f = True for t in b: if t[:k] in s: f = False break s.add(t[:k]) if f: r = k break rr.append(r) return '\n'.join(map(str, rr)) print(main()) ```
output
1
79,886
18
159,773
Provide a correct Python 3 solution for this coding contest problem. Airport Codes Airport code In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification. Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet: 1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order. 2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code. For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t. However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this. Input The input consists of 100 or less datasets. Each dataset is given in the following format. > n > s1 > ... > sn The number of airports n (2 ≤ n ≤ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 ≤ i <j ≤ n, si ≠ sj is satisfied. The end of the input is indicated by a line consisting of only one zero. Output For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line. Sample Input 3 haneda oookayama tsu 2 azusa azishirabe 2 snuke snake Four haneda honda hanamaki hawaii 0 Output for Sample Input 1 Four -1 3 Example Input 3 haneda oookayama tsu 2 azusa azishirabe 2 snuke snake 4 haneda honda hanamaki hawaii 0 Output 1 4 -1 3
instruction
0
79,887
18
159,774
"Correct Solution: ``` while True: n = int(input()) if n==0: break s = [] maxlen = 0 for i in range(n): st = input() stt = "" for j in range(len(st)): if j==0 or st[j-1] in "aiueo": stt += st[j] s.append(stt) maxlen = max(maxlen, len(stt)) ans = -1 k = 1 while k<=maxlen: code = set() for e in s: code.add(e[:k]) if len(code)==len(s): ans = k break k += 1 print(ans) ```
output
1
79,887
18
159,775