message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
Airport Codes
Airport code
In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification.
Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet:
1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order.
2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code.
For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t.
However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this.
Input
The input consists of 100 or less datasets. Each dataset is given in the following format.
> n
> s1
> ...
> sn
The number of airports n (2 β€ n β€ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 β€ i <j β€ n, si β sj is satisfied.
The end of the input is indicated by a line consisting of only one zero.
Output
For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line.
Sample Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
Four
haneda
honda
hanamaki
hawaii
0
Output for Sample Input
1
Four
-1
3
Example
Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
4
haneda
honda
hanamaki
hawaii
0
Output
1
4
-1
3 | instruction | 0 | 79,888 | 18 | 159,776 |
"Correct Solution:
```
while 1:
n=int(input())
if not n:break
l=[]
m=0
for _ in range(n):
s=input()
a=s[0]
for i,t in enumerate(s[:-1]):
if any(t==c for c in'aiueo'):
a+=s[i+1]
m=max(m,len(a))
l.append(a)
for k in range(m+1):
if len(set(t[:k]for t in l))==n:
print(k)
break
else:
print(-1)
``` | output | 1 | 79,888 | 18 | 159,777 |
Provide a correct Python 3 solution for this coding contest problem.
Airport Codes
Airport code
In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification.
Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet:
1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order.
2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code.
For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t.
However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this.
Input
The input consists of 100 or less datasets. Each dataset is given in the following format.
> n
> s1
> ...
> sn
The number of airports n (2 β€ n β€ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 β€ i <j β€ n, si β sj is satisfied.
The end of the input is indicated by a line consisting of only one zero.
Output
For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line.
Sample Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
Four
haneda
honda
hanamaki
hawaii
0
Output for Sample Input
1
Four
-1
3
Example
Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
4
haneda
honda
hanamaki
hawaii
0
Output
1
4
-1
3 | instruction | 0 | 79,889 | 18 | 159,778 |
"Correct Solution:
```
#!/usr/bin/env python3
while True:
n = int(input())
if n == 0:
break
s = ['a' + input() for _ in range(n)]
m = max(len(x) for x in s)
for i in range(1, m + 1):
dic = dict()
for x in s:
code = ''
for j in range(len(x)):
if len(code) == i:
break
if j > 0 and x[j - 1] in ['a', 'i', 'u', 'e', 'o']:
code += x[j]
if code in dic:
break
dic[code] = True
else:
print(i)
break
else:
print(-1)
``` | output | 1 | 79,889 | 18 | 159,779 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Airport Codes
Airport code
In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification.
Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet:
1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order.
2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code.
For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t.
However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this.
Input
The input consists of 100 or less datasets. Each dataset is given in the following format.
> n
> s1
> ...
> sn
The number of airports n (2 β€ n β€ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 β€ i <j β€ n, si β sj is satisfied.
The end of the input is indicated by a line consisting of only one zero.
Output
For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line.
Sample Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
Four
haneda
honda
hanamaki
hawaii
0
Output for Sample Input
1
Four
-1
3
Example
Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
4
haneda
honda
hanamaki
hawaii
0
Output
1
4
-1
3
Submitted Solution:
```
from collections import defaultdict,deque
import sys,heapq,bisect,math,itertools,string,queue,copy,time
sys.setrecursionlimit(10**8)
INF = float('inf')
mod = 10**9+7
eps = 10**-7
def inp(): return int(input())
def inpl(): return list(map(int, input().split()))
def inpl_str(): return list(input().split())
bo = ['a','e','i','u','o']
while True:
N = inp()
if N == 0:
break
else:
codes = ['']*N
for i in range(N):
S = input()
flag = True
for s in S:
if flag:
codes[i] = codes[i] + s
flag = False
if s in bo:
flag = True
for k in range(1,60):
koho = set()
for code in codes:
koho.add(code[:k])
if len(koho) == N:
print(k)
break
else:
print(-1)
``` | instruction | 0 | 79,890 | 18 | 159,780 |
Yes | output | 1 | 79,890 | 18 | 159,781 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Airport Codes
Airport code
In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification.
Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet:
1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order.
2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code.
For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t.
However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this.
Input
The input consists of 100 or less datasets. Each dataset is given in the following format.
> n
> s1
> ...
> sn
The number of airports n (2 β€ n β€ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 β€ i <j β€ n, si β sj is satisfied.
The end of the input is indicated by a line consisting of only one zero.
Output
For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line.
Sample Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
Four
haneda
honda
hanamaki
hawaii
0
Output for Sample Input
1
Four
-1
3
Example
Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
4
haneda
honda
hanamaki
hawaii
0
Output
1
4
-1
3
Submitted Solution:
```
while 1:
n = int(input())
if n == 0:
break
S = []
for i in range(n):
s = input()
b = []
for j in range(len(s)):
if j < 1 or s[j-1] in "aiueo":
b.append(s[j])
S.append(b)
ans = 0
S.sort()
for i in range(n-1):
A = S[i]; B = S[i+1]
if A == B:
print(-1)
break
res = min(len(A), len(B))
for j in range(res):
if A[j] != B[j]:
res = j
break
ans = max(ans, res+1)
else:
print(ans)
``` | instruction | 0 | 79,891 | 18 | 159,782 |
Yes | output | 1 | 79,891 | 18 | 159,783 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Airport Codes
Airport code
In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification.
Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet:
1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order.
2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code.
For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t.
However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this.
Input
The input consists of 100 or less datasets. Each dataset is given in the following format.
> n
> s1
> ...
> sn
The number of airports n (2 β€ n β€ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 β€ i <j β€ n, si β sj is satisfied.
The end of the input is indicated by a line consisting of only one zero.
Output
For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line.
Sample Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
Four
haneda
honda
hanamaki
hawaii
0
Output for Sample Input
1
Four
-1
3
Example
Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
4
haneda
honda
hanamaki
hawaii
0
Output
1
4
-1
3
Submitted Solution:
```
li_word=["a","i","u","e","o"]
while True :
num=int(input())
if num==0:
break
else:
li=[]
for i in range(num):
name=[]
airport=list(input())
for i in range (len(airport)):
if i==0 or airport[i-1] in li_word:
name.append(airport[i])
li.append(tuple(name))
li_set=list(set(li))
if len(li) != len(li_set):
print(-1)
else:
a=0
while True:
a+=1
check=[]
for i in li:
check.append(i[:a])
if len(check)==len(list(set(check))):
print(a)
break
``` | instruction | 0 | 79,892 | 18 | 159,784 |
Yes | output | 1 | 79,892 | 18 | 159,785 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Airport Codes
Airport code
In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification.
Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet:
1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order.
2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code.
For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t.
However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this.
Input
The input consists of 100 or less datasets. Each dataset is given in the following format.
> n
> s1
> ...
> sn
The number of airports n (2 β€ n β€ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 β€ i <j β€ n, si β sj is satisfied.
The end of the input is indicated by a line consisting of only one zero.
Output
For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line.
Sample Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
Four
haneda
honda
hanamaki
hawaii
0
Output for Sample Input
1
Four
-1
3
Example
Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
4
haneda
honda
hanamaki
hawaii
0
Output
1
4
-1
3
Submitted Solution:
```
while True:
N = int(input())
if N == 0:
break
air = [input() for _ in range(N)]
codes = [''.join(x for i, x in enumerate(s) if i == 0 or s[i-1] in 'aiueo') for s in air]
max_len = max(len(x) for x in codes)
for k in range(1, max_len + 1):
if len(set(x[:k] for x in codes)) == N:
print(k)
break
else:
print(-1)
``` | instruction | 0 | 79,893 | 18 | 159,786 |
Yes | output | 1 | 79,893 | 18 | 159,787 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Airport Codes
Airport code
In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification.
Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet:
1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order.
2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code.
For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t.
However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this.
Input
The input consists of 100 or less datasets. Each dataset is given in the following format.
> n
> s1
> ...
> sn
The number of airports n (2 β€ n β€ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 β€ i <j β€ n, si β sj is satisfied.
The end of the input is indicated by a line consisting of only one zero.
Output
For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line.
Sample Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
Four
haneda
honda
hanamaki
hawaii
0
Output for Sample Input
1
Four
-1
3
Example
Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
4
haneda
honda
hanamaki
hawaii
0
Output
1
4
-1
3
Submitted Solution:
```
# coding: utf-8
import sys
def coding(s):
t = ''
flag = True
for i in s:
if flag:
t += i
flag = False
if i == 'a' or i == 'i' or i == 'u' or i == 'e' or i == 'o':
flag = True;
return t
def possible(ls,k):
flag = True
for i in range(len(ls)):
for j in range(i+1,len(ls)):
if len(ls[i]) < k or len(ls[j]) < k:
if ls[i] == ls[j]:
flag = False
break
else:
continue
if ls[i][0:k] == ls[j][0:k]:
flag = False
break
if flag:
break
return flag
if __name__ == '__main__':
while(1):
n = int(input());
if n == 0:
break
l = []
for i in range(n):
l.append(input())
nl = []
for i in l:
nl.append(coding(i))
sz = min([len(i) for i in l])
ll = 0
hh = 50
if not(possible(nl,hh)):
print(-1)
continue
while True:
mid = (ll + hh) // 2
if ll == mid:
print(hh)
break
if possible(nl,mid):
hh = mid
else:
ll = mid
``` | instruction | 0 | 79,894 | 18 | 159,788 |
No | output | 1 | 79,894 | 18 | 159,789 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Airport Codes
Airport code
In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification.
Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet:
1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order.
2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code.
For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t.
However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this.
Input
The input consists of 100 or less datasets. Each dataset is given in the following format.
> n
> s1
> ...
> sn
The number of airports n (2 β€ n β€ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 β€ i <j β€ n, si β sj is satisfied.
The end of the input is indicated by a line consisting of only one zero.
Output
For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line.
Sample Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
Four
haneda
honda
hanamaki
hawaii
0
Output for Sample Input
1
Four
-1
3
Example
Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
4
haneda
honda
hanamaki
hawaii
0
Output
1
4
-1
3
Submitted Solution:
```
from collections import Counter
def solve(kisoku_S, max_len):
for k in range(1, max_len):
k_s = Counter([s[0:k] for s in kisoku_S])
if all(c == 1 for s, c in k_s.items()):
return k
return -1
if __name__ == "__main__":
while True:
n = int(input())
if n == 0:
break
S = [input() for _ in range(n)]
kisoku_S = []
for i in range(n):
tmp = S[i][0]
for j in range(1, len(S[i])):
if (
S[i][j - 1] == "a"
or S[i][j - 1] == "i"
or S[i][j - 1] == "u"
or S[i][j - 1] == "e"
or S[i][j - 1] == "o"
):
tmp += S[i][j]
kisoku_S.append(tmp)
max_len = 1
for i in kisoku_S:
max_len = max(len(i), max_len)
print(solve(kisoku_S=kisoku_S, max_len=max_len))
``` | instruction | 0 | 79,895 | 18 | 159,790 |
No | output | 1 | 79,895 | 18 | 159,791 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Airport Codes
Airport code
In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification.
Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet:
1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order.
2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code.
For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t.
However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this.
Input
The input consists of 100 or less datasets. Each dataset is given in the following format.
> n
> s1
> ...
> sn
The number of airports n (2 β€ n β€ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 β€ i <j β€ n, si β sj is satisfied.
The end of the input is indicated by a line consisting of only one zero.
Output
For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line.
Sample Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
Four
haneda
honda
hanamaki
hawaii
0
Output for Sample Input
1
Four
-1
3
Example
Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
4
haneda
honda
hanamaki
hawaii
0
Output
1
4
-1
3
Submitted Solution:
```
while 1:
n = int(input())
S = []
for i in range(n):
s = input()
b = []
for j in range(len(s)):
if j < 1 or s[j-1] in "aiueo":
b.append(s[j])
S.append(b)
ans = 0
S.sort()
for i in range(n-1):
A = S[i]; B = S[i+1]
if A == B:
print(-1)
break
res = min(len(A), len(B))
for j in range(res):
if A[j] != B[j]:
res = j
break
ans = max(ans, res+1)
else:
print(ans)
``` | instruction | 0 | 79,896 | 18 | 159,792 |
No | output | 1 | 79,896 | 18 | 159,793 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Airport Codes
Airport code
In the Kingdom of JAG, airport codes are assigned to each domestic airport for identification.
Airport codes are assigned according to the following rules based on the name of the airport in lowercase English alphabet:
1. Extract the first letter of the name and the letter immediately after the vowel (a, i, u, e, o) in order.
2. If the extracted character string is less than k characters, use it as the airport code, and if it is k characters or more, use the first k characters of the extracted character string as the airport code.
For example, when k = 3, haneda is assigned the code hnd, oookayama is assigned the code ooo, and tsu is assigned the code t.
However, with this code assignment method, the same code may be assigned even at airports with different names, which causes confusion. Given a list of airport names, determine if all airport codes can be different, find the minimum k that can make all airport codes different if possible, and if not possible. Create a program to convey this.
Input
The input consists of 100 or less datasets. Each dataset is given in the following format.
> n
> s1
> ...
> sn
The number of airports n (2 β€ n β€ 50) is given as an integer on the first line, and the name si of the airport is given as a string on each of the following n lines. Airport names consist only of lowercase English alphabets from'a'to'z', all with 1 to 50 characters. Also, the names of the airports given are all different. That is, when 1 β€ i <j β€ n, si β sj is satisfied.
The end of the input is indicated by a line consisting of only one zero.
Output
For each dataset, if all airports can be assigned different airport codes, output such a minimum k on one line. If not possible, output -1 on one line.
Sample Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
Four
haneda
honda
hanamaki
hawaii
0
Output for Sample Input
1
Four
-1
3
Example
Input
3
haneda
oookayama
tsu
2
azusa
azishirabe
2
snuke
snake
4
haneda
honda
hanamaki
hawaii
0
Output
1
4
-1
3
Submitted Solution:
```
# coding: utf-8
import sys
def coding(s):
t = ''
flag = True
for i in s:
if flag:
t += i
flag = False
if i == 'a' or i == 'i' or i == 'u' or i == 'e' or i == 'o':
flag = True;
return t
def pre_possible(ls):
flag = False
for i in range(len(ls)):
for j in range(i+1,len(ls)):
if ls[i] == ls[j]:
flag = True
return flag
def possible(ls,k):
flag = True
for i in range(len(ls)):
for j in range(i+1,len(ls)):
if len(ls[i]) < k or len(ls[j]) < k:
if ls[i] == ls[j]:
flag = False
break
else:
continue
if ls[i][0:k] == ls[j][0:k]:
flag = False
break
if flag:
break
return flag
if __name__ == '__main__':
while(1):
n = int(input());
if n == 0:
break
l = []
for i in range(n):
l.append(input())
nl = []
for i in l:
nl.append(coding(i))
sz = min([len(i) for i in l])
ll = 0
hh = 50
if pre_possible(nl):
print(-1)
continue
while True:
mid = (ll + hh) // 2
if ll == mid:
print(hh)
break
if possible(nl,mid):
hh = mid
else:
ll = mid
``` | instruction | 0 | 79,897 | 18 | 159,794 |
No | output | 1 | 79,897 | 18 | 159,795 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a multiset S. Over all pairs of subsets A and B, such that:
* B β A;
* |B| = |A| - 1;
* greatest common divisor of all elements in A is equal to one;
find the sum of β_{x β A}{x} β
β_{x β B}{x}, modulo 998 244 353.
Input
The first line contains one integer m (1 β€ m β€ 10^5): the number of different values in the multiset S.
Each of the next m lines contains two integers a_i, freq_i (1 β€ a_i β€ 10^5, 1 β€ freq_i β€ 10^9). Element a_i appears in the multiset S freq_i times. All a_i are different.
Output
Print the required sum, modulo 998 244 353.
Examples
Input
2
1 1
2 1
Output
9
Input
4
1 1
2 1
3 1
6 1
Output
1207
Input
1
1 5
Output
560
Note
A multiset is a set where elements are allowed to coincide. |X| is the cardinality of a set X, the number of elements in it.
A β B: Set A is a subset of a set B.
In the first example B=\{1\}, A=\{1,2\} and B=\{2\}, A=\{1, 2\} have a product equal to 1β
3 + 2β
3=9. Other pairs of A and B don't satisfy the given constraints.
Submitted Solution:
```
# string capitalize()
# the capitalize() method converts first character of string to uppercases and lowercases all other characters ,if any
# syntax :
# string.capitalize()
# capitalize() parameter
# - the capitalize() function doesn't take any parameter.
# return value from capitalize()
# the capitalize() function return string with first letter capitalized and all characters lowercases .
# it doesn't modify the original String.
# example 1 : capitalize() sentence
string = 'vora Mihir'
capitalize_string = string.capitalize()
#print the old string
print("old string : ",string)
print('capitalize string : ',capitalize_string)
# example 2 : non-alphabetic first character
string = ' + is operator'
non_capitalize = string.capitalize()
print(string)
print(non_capitalize)
``` | instruction | 0 | 80,147 | 18 | 160,294 |
No | output | 1 | 80,147 | 18 | 160,295 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Watto, the owner of a spare parts store, has recently got an order for the mechanism that can process strings in a certain way. Initially the memory of the mechanism is filled with n strings. Then the mechanism should be able to process queries of the following type: "Given string s, determine if the memory of the mechanism contains string t that consists of the same number of characters as s and differs from s in exactly one position".
Watto has already compiled the mechanism, all that's left is to write a program for it and check it on the data consisting of n initial lines and m queries. He decided to entrust this job to you.
Input
The first line contains two non-negative numbers n and m (0 β€ n β€ 3Β·105, 0 β€ m β€ 3Β·105) β the number of the initial strings and the number of queries, respectively.
Next follow n non-empty strings that are uploaded to the memory of the mechanism.
Next follow m non-empty strings that are the queries to the mechanism.
The total length of lines in the input doesn't exceed 6Β·105. Each line consists only of letters 'a', 'b', 'c'.
Output
For each query print on a single line "YES" (without the quotes), if the memory of the mechanism contains the required string, otherwise print "NO" (without the quotes).
Examples
Input
2 3
aaaaa
acacaca
aabaa
ccacacc
caaac
Output
YES
NO
NO
Submitted Solution:
```
from sys import stdin
SMALL_P1 = 127
SMALL_P2 = 131
LARGE_P1 = int(1e9 + 7)
LARGE_P2 = int(1e9 + 9)
MAX_N = int(6e5 + 5)
powers1 = [0 for i in range(MAX_N)]
powers2 = [0 for i in range(MAX_N)]
powers1[0] = 1
powers2[0] = 1
for i in range(1, MAX_N):
powers1[i] = (powers1[i - 1] * SMALL_P1) % LARGE_P1
powers2[i] = (powers2[i - 1] * SMALL_P2) % LARGE_P2
def hash_string(string):
hash_value1 = 0
hash_value2 = 0
for i in range(len(string)):
hash_value1 += ord(string[i]) * powers1[i]
hash_value1 %= LARGE_P1
hash_value2 += ord(string[i]) * powers2[i]
hash_value2 %= LARGE_P2
return hash_value1, hash_value2
def adapted_hash(initial_hash1, initial_hash2, pos, orig, subst):
hash_1 = initial_hash1 + (ord(subst) * powers1[pos]) % LARGE_P1 - (ord(orig) * powers1[pos]) % LARGE_P1
hash_2 = initial_hash2 + (ord(subst) * powers2[pos]) % LARGE_P2 - (ord(orig) * powers2[pos]) % LARGE_P2
return (hash_1 % LARGE_P1) * LARGE_P2 + hash_2 % LARGE_P2
n, m = map(int, input().split())
hashes = {}
for _ in range(n):
string = stdin.readline()
initial_hash1, initial_hash2 = hash_string(string)
for i in range(len(string)):
curr_c = string[i]
for poss in ['a', 'b', 'c']:
if poss != curr_c:
hashes[adapted_hash(initial_hash1, initial_hash2, i, curr_c, poss)] = True
for _ in range(m):
curr_string = stdin.readline()
hash1, hash2 = hash_string(curr_string)
if hash1 * LARGE_P2 + hash2 in hashes:
print("YES")
else:
print("NO")
``` | instruction | 0 | 80,395 | 18 | 160,790 |
Yes | output | 1 | 80,395 | 18 | 160,791 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Watto, the owner of a spare parts store, has recently got an order for the mechanism that can process strings in a certain way. Initially the memory of the mechanism is filled with n strings. Then the mechanism should be able to process queries of the following type: "Given string s, determine if the memory of the mechanism contains string t that consists of the same number of characters as s and differs from s in exactly one position".
Watto has already compiled the mechanism, all that's left is to write a program for it and check it on the data consisting of n initial lines and m queries. He decided to entrust this job to you.
Input
The first line contains two non-negative numbers n and m (0 β€ n β€ 3Β·105, 0 β€ m β€ 3Β·105) β the number of the initial strings and the number of queries, respectively.
Next follow n non-empty strings that are uploaded to the memory of the mechanism.
Next follow m non-empty strings that are the queries to the mechanism.
The total length of lines in the input doesn't exceed 6Β·105. Each line consists only of letters 'a', 'b', 'c'.
Output
For each query print on a single line "YES" (without the quotes), if the memory of the mechanism contains the required string, otherwise print "NO" (without the quotes).
Examples
Input
2 3
aaaaa
acacaca
aabaa
ccacacc
caaac
Output
YES
NO
NO
Submitted Solution:
```
def init():
f[0] = 1
for i in range(1, L):
f[i] = (f[i - 1] * a) % table_size
def polyHash(keys):
hashValue = 0
for i in range(len(keys)):
hashValue = (hashValue * a + ord(keys[i]) - 97) % table_size
return hashValue
def check(query):
h = polyHash(query)
leng = len(query)
for i in range(leng):
for c in range(3):
c_char = chr(ord('a') + c)
if c_char == query[i]:
continue
new_hashValue = ((((ord(c_char) - ord(query[i])) * f[leng - i - 1]) % table_size + table_size) + h) % table_size
if new_hashValue in dic:
return True
return False
L = 1000001
table_size = int(1e9) + 7
a = 257
f = [0] * L
init()
n, m = map(int,input().split())
dic = set()
for i in range(n):
keys = input()
dic.add(polyHash(keys))
buf = []
for i in range(m):
t = input()
buf.append('YES' if check(t) else 'NO')
print('\n'.join(buf))
``` | instruction | 0 | 80,396 | 18 | 160,792 |
Yes | output | 1 | 80,396 | 18 | 160,793 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Watto, the owner of a spare parts store, has recently got an order for the mechanism that can process strings in a certain way. Initially the memory of the mechanism is filled with n strings. Then the mechanism should be able to process queries of the following type: "Given string s, determine if the memory of the mechanism contains string t that consists of the same number of characters as s and differs from s in exactly one position".
Watto has already compiled the mechanism, all that's left is to write a program for it and check it on the data consisting of n initial lines and m queries. He decided to entrust this job to you.
Input
The first line contains two non-negative numbers n and m (0 β€ n β€ 3Β·105, 0 β€ m β€ 3Β·105) β the number of the initial strings and the number of queries, respectively.
Next follow n non-empty strings that are uploaded to the memory of the mechanism.
Next follow m non-empty strings that are the queries to the mechanism.
The total length of lines in the input doesn't exceed 6Β·105. Each line consists only of letters 'a', 'b', 'c'.
Output
For each query print on a single line "YES" (without the quotes), if the memory of the mechanism contains the required string, otherwise print "NO" (without the quotes).
Examples
Input
2 3
aaaaa
acacaca
aabaa
ccacacc
caaac
Output
YES
NO
NO
Submitted Solution:
```
N = 9999999999999999999999999999999999999984
n,m=tuple(map(int,input().split()))
memory = set()
for _ in range(n):
su = 0
p = 1
entry = input()
for letter in entry:
su = (su + p*ord(letter))%N
p = (p*203)%N
p = 1
for letter in entry:
for i in ['a','b','c']:
if i != letter:
memory.add((p*(ord(i)-ord(letter))+su)%N)
p = (p*203)%N
answer =[]
for _ in range(m):
su = 0
p = 1
for letter in input():
su = (su + p*ord(letter))%N
p = (p*203)%N
if su in memory:
answer.append('YES')
else:
answer.append('NO')
print('\n'.join(answer))
``` | instruction | 0 | 80,397 | 18 | 160,794 |
Yes | output | 1 | 80,397 | 18 | 160,795 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Watto, the owner of a spare parts store, has recently got an order for the mechanism that can process strings in a certain way. Initially the memory of the mechanism is filled with n strings. Then the mechanism should be able to process queries of the following type: "Given string s, determine if the memory of the mechanism contains string t that consists of the same number of characters as s and differs from s in exactly one position".
Watto has already compiled the mechanism, all that's left is to write a program for it and check it on the data consisting of n initial lines and m queries. He decided to entrust this job to you.
Input
The first line contains two non-negative numbers n and m (0 β€ n β€ 3Β·105, 0 β€ m β€ 3Β·105) β the number of the initial strings and the number of queries, respectively.
Next follow n non-empty strings that are uploaded to the memory of the mechanism.
Next follow m non-empty strings that are the queries to the mechanism.
The total length of lines in the input doesn't exceed 6Β·105. Each line consists only of letters 'a', 'b', 'c'.
Output
For each query print on a single line "YES" (without the quotes), if the memory of the mechanism contains the required string, otherwise print "NO" (without the quotes).
Examples
Input
2 3
aaaaa
acacaca
aabaa
ccacacc
caaac
Output
YES
NO
NO
Submitted Solution:
```
from sys import stdin
from functools import reduce
from collections import defaultdict
_data = iter(stdin.read().split('\n'))
def input():
while True:
return next(_data)
n, m = [int(x) for x in input().split()]
B = 10007
MOD = 1000000000000000003
h = lambda s: reduce(lambda s, c: (B * s + ord(c)) % MOD, s, 0)
hs = defaultdict(set)
def insert(s):
hs[len(s)].add(h(s))
def find(s):
v = h(s)
b = 1
for c in reversed(s):
for d in 'abc':
if c != d:
u = (v - b * ord(c) + b * ord(d)) % MOD
if u in hs[len(s)]:
return True
b *= B
b %= MOD
return False
for i in range(n):
s = input()
insert(s)
buf = []
for i in range(m):
s = input()
buf.append('YES' if find(s) else 'NO')
print('\n'.join(buf))
``` | instruction | 0 | 80,398 | 18 | 160,796 |
Yes | output | 1 | 80,398 | 18 | 160,797 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Watto, the owner of a spare parts store, has recently got an order for the mechanism that can process strings in a certain way. Initially the memory of the mechanism is filled with n strings. Then the mechanism should be able to process queries of the following type: "Given string s, determine if the memory of the mechanism contains string t that consists of the same number of characters as s and differs from s in exactly one position".
Watto has already compiled the mechanism, all that's left is to write a program for it and check it on the data consisting of n initial lines and m queries. He decided to entrust this job to you.
Input
The first line contains two non-negative numbers n and m (0 β€ n β€ 3Β·105, 0 β€ m β€ 3Β·105) β the number of the initial strings and the number of queries, respectively.
Next follow n non-empty strings that are uploaded to the memory of the mechanism.
Next follow m non-empty strings that are the queries to the mechanism.
The total length of lines in the input doesn't exceed 6Β·105. Each line consists only of letters 'a', 'b', 'c'.
Output
For each query print on a single line "YES" (without the quotes), if the memory of the mechanism contains the required string, otherwise print "NO" (without the quotes).
Examples
Input
2 3
aaaaa
acacaca
aabaa
ccacacc
caaac
Output
YES
NO
NO
Submitted Solution:
```
def one_replace(s1,s2):
found=False
for i in range(len(s1)):
if s1[i]!=s2[i]:
if found==True:
return False
found=True
return True
n,m=map(int,input().split( ))
l=[]
for i in range(n):
s=str(input())
l.append(s)
l=sorted(l,key=len)
for i in range(m):
s=str(input())
ans=False
for j in range(n):
if len(l[j])==len(s):
ans=one_replace(l[j],s)
if ans==True: break
if len(l[j])>len(s):
break
if ans==True:
break
if ans==True: print("YES")
else: print("NO")
``` | instruction | 0 | 80,399 | 18 | 160,798 |
No | output | 1 | 80,399 | 18 | 160,799 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Watto, the owner of a spare parts store, has recently got an order for the mechanism that can process strings in a certain way. Initially the memory of the mechanism is filled with n strings. Then the mechanism should be able to process queries of the following type: "Given string s, determine if the memory of the mechanism contains string t that consists of the same number of characters as s and differs from s in exactly one position".
Watto has already compiled the mechanism, all that's left is to write a program for it and check it on the data consisting of n initial lines and m queries. He decided to entrust this job to you.
Input
The first line contains two non-negative numbers n and m (0 β€ n β€ 3Β·105, 0 β€ m β€ 3Β·105) β the number of the initial strings and the number of queries, respectively.
Next follow n non-empty strings that are uploaded to the memory of the mechanism.
Next follow m non-empty strings that are the queries to the mechanism.
The total length of lines in the input doesn't exceed 6Β·105. Each line consists only of letters 'a', 'b', 'c'.
Output
For each query print on a single line "YES" (without the quotes), if the memory of the mechanism contains the required string, otherwise print "NO" (without the quotes).
Examples
Input
2 3
aaaaa
acacaca
aabaa
ccacacc
caaac
Output
YES
NO
NO
Submitted Solution:
```
n,m=tuple(map(int,input().split()))
pos=set()
num={'a':1,'b':2,'c':3}
def hash1(s):
ans = 0
for ch in s:
ans = ans*10 + num[ch]
return ans
for _ in range(n):
s = input()
sh = hash1(s)
l = len(s)
pos.add(sh)
for i in range(l):
if s[i] == 'a':
pos.add(int('1'+''.join(['0']*(l-i-1))) + sh)
pos.add(int('2'+''.join(['0']*(l-i-1)))+sh)
elif s[i] == 'b':
pos.add(int('1'+''.join(['0']*(l-i-1)))+sh)
pos.add( -int('1'+''.join(['0']*(l-i-1)))+sh)
elif s[i] == 'c':
pos.add(-int('1'+''.join(['0']*(l-i-1)))+sh)
pos.add(-int('2'+''.join(['0']*(l-i-1)))+sh)
canfind = []
for _ in range(m):
if hash1(input()) in pos:
canfind.append('YES')
else:
canfind.append('NO')
print('\n'.join(canfind))
``` | instruction | 0 | 80,400 | 18 | 160,800 |
No | output | 1 | 80,400 | 18 | 160,801 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Watto, the owner of a spare parts store, has recently got an order for the mechanism that can process strings in a certain way. Initially the memory of the mechanism is filled with n strings. Then the mechanism should be able to process queries of the following type: "Given string s, determine if the memory of the mechanism contains string t that consists of the same number of characters as s and differs from s in exactly one position".
Watto has already compiled the mechanism, all that's left is to write a program for it and check it on the data consisting of n initial lines and m queries. He decided to entrust this job to you.
Input
The first line contains two non-negative numbers n and m (0 β€ n β€ 3Β·105, 0 β€ m β€ 3Β·105) β the number of the initial strings and the number of queries, respectively.
Next follow n non-empty strings that are uploaded to the memory of the mechanism.
Next follow m non-empty strings that are the queries to the mechanism.
The total length of lines in the input doesn't exceed 6Β·105. Each line consists only of letters 'a', 'b', 'c'.
Output
For each query print on a single line "YES" (without the quotes), if the memory of the mechanism contains the required string, otherwise print "NO" (without the quotes).
Examples
Input
2 3
aaaaa
acacaca
aabaa
ccacacc
caaac
Output
YES
NO
NO
Submitted Solution:
```
import math
n=list(map(int,input().split()))
x=[]
for i in range(n[0]):
x.append(input())
z=[]
for i in range(n[1]):
z.append(input())
for i in z:
for j in x:
if len(i)==len(j):
total=1
for o,p in zip(i,j):
if o!=p:
total-=1
if total<0:
print ("NO")
else:
print ("YES")
break
``` | instruction | 0 | 80,401 | 18 | 160,802 |
No | output | 1 | 80,401 | 18 | 160,803 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Watto, the owner of a spare parts store, has recently got an order for the mechanism that can process strings in a certain way. Initially the memory of the mechanism is filled with n strings. Then the mechanism should be able to process queries of the following type: "Given string s, determine if the memory of the mechanism contains string t that consists of the same number of characters as s and differs from s in exactly one position".
Watto has already compiled the mechanism, all that's left is to write a program for it and check it on the data consisting of n initial lines and m queries. He decided to entrust this job to you.
Input
The first line contains two non-negative numbers n and m (0 β€ n β€ 3Β·105, 0 β€ m β€ 3Β·105) β the number of the initial strings and the number of queries, respectively.
Next follow n non-empty strings that are uploaded to the memory of the mechanism.
Next follow m non-empty strings that are the queries to the mechanism.
The total length of lines in the input doesn't exceed 6Β·105. Each line consists only of letters 'a', 'b', 'c'.
Output
For each query print on a single line "YES" (without the quotes), if the memory of the mechanism contains the required string, otherwise print "NO" (without the quotes).
Examples
Input
2 3
aaaaa
acacaca
aabaa
ccacacc
caaac
Output
YES
NO
NO
Submitted Solution:
```
n,m = input().split()
n,m = int(n),int(m)
memory = []
result = []
#Fill Memory
for i in range(n):
memory.append(input())
for i in range(m):
temp = input()
counter = 100000000
for element in memory:
if len(temp) == len(element):
counter = 0
for k in range(len(element)):
if temp[k] != element[k]:
counter += 1
if counter > 1:
break
if counter < 2:
result.append("YES")
break
if counter > 1:
result.append("NO")
for i in result:
print(i)
``` | instruction | 0 | 80,402 | 18 | 160,804 |
No | output | 1 | 80,402 | 18 | 160,805 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No | instruction | 0 | 80,688 | 18 | 161,376 |
"Correct Solution:
```
S=input()
if len(S)>=4:
if S[:4]=='YAKI':
print('Yes')
exit()
print('No')
``` | output | 1 | 80,688 | 18 | 161,377 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No | instruction | 0 | 80,689 | 18 | 161,378 |
"Correct Solution:
```
S = input()
if len(S) >= 4 and S[:4] == "YAKI":
print("Yes")
else:
print("No")
``` | output | 1 | 80,689 | 18 | 161,379 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No | instruction | 0 | 80,690 | 18 | 161,380 |
"Correct Solution:
```
print("YNeos"["YAKI"!=input()[:4]::2])
``` | output | 1 | 80,690 | 18 | 161,381 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No | instruction | 0 | 80,691 | 18 | 161,382 |
"Correct Solution:
```
#python3
dish = input()
if dish[:4] == 'YAKI':
print('Yes')
else:
print('No')
``` | output | 1 | 80,691 | 18 | 161,383 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No | instruction | 0 | 80,692 | 18 | 161,384 |
"Correct Solution:
```
import re
str = input()
m = re.match("^YAKI",str)
if m:
print("Yes")
else:
print("No")
``` | output | 1 | 80,692 | 18 | 161,385 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No | instruction | 0 | 80,693 | 18 | 161,386 |
"Correct Solution:
```
str=input()
if str[0:4]=="YAKI":
print("Yes")
else:
print("No")
``` | output | 1 | 80,693 | 18 | 161,387 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No | instruction | 0 | 80,694 | 18 | 161,388 |
"Correct Solution:
```
s = input()
if len(s) >= 4 and s[:4] == "YAKI":
print("Yes")
else:
print("No");
``` | output | 1 | 80,694 | 18 | 161,389 |
Provide a correct Python 3 solution for this coding contest problem.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No | instruction | 0 | 80,695 | 18 | 161,390 |
"Correct Solution:
```
S = input()
S = S[0:4]
if S=="YAKI":
print("Yes")
else:
print("No")
``` | output | 1 | 80,695 | 18 | 161,391 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No
Submitted Solution:
```
s = input()
if len(s)>3 and s[:4]=='YAKI':
print('Yes')
else:print('No')
``` | instruction | 0 | 80,696 | 18 | 161,392 |
Yes | output | 1 | 80,696 | 18 | 161,393 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No
Submitted Solution:
```
s = input()
s1 = s[0:4]
if s1 == "YAKI":
print("Yes")
else:
print("No")
``` | instruction | 0 | 80,697 | 18 | 161,394 |
Yes | output | 1 | 80,697 | 18 | 161,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No
Submitted Solution:
```
s=str(input())
print('Yes' if s[:4]=='YAKI' else 'No')
``` | instruction | 0 | 80,698 | 18 | 161,396 |
Yes | output | 1 | 80,698 | 18 | 161,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No
Submitted Solution:
```
i = input()
if i[:4] == "YAKI":
print("Yes")
else:
print("No")
``` | instruction | 0 | 80,699 | 18 | 161,398 |
Yes | output | 1 | 80,699 | 18 | 161,399 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No
Submitted Solution:
```
s= input()
if s[0]=='Y' and s[1]=='A' and s[2]=='K' and s[3]=='I':
print("Yes");
else:
print("No")
``` | instruction | 0 | 80,700 | 18 | 161,400 |
No | output | 1 | 80,700 | 18 | 161,401 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No
Submitted Solution:
```
s=input()
print("Yes" if οΌlen(s)>=4 and s[:4]=="YAKI"οΌelse "No")
``` | instruction | 0 | 80,701 | 18 | 161,402 |
No | output | 1 | 80,701 | 18 | 161,403 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No
Submitted Solution:
```
import fileinput
s = fileinput.input().strip()
print(len(s)>=4 and s[:3] == 'YAKI')
``` | instruction | 0 | 80,702 | 18 | 161,404 |
No | output | 1 | 80,702 | 18 | 161,405 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ringo is giving a present to Snuke.
Ringo has found out that Snuke loves yakiniku (a Japanese term meaning grilled meat. yaki: grilled, niku: meat). He supposes that Snuke likes grilled things starting with `YAKI` in Japanese, and does not like other things.
You are given a string S representing the Japanese name of Ringo's present to Snuke. Determine whether S starts with `YAKI`.
Constraints
* 1 \leq |S| \leq 10
* S consists of uppercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S starts with `YAKI`, print `Yes`; otherwise, print `No`.
Examples
Input
YAKINIKU
Output
Yes
Input
TAKOYAKI
Output
No
Input
YAK
Output
No
Submitted Solution:
```
s = input()
print(s[:-8])
``` | instruction | 0 | 80,703 | 18 | 161,406 |
No | output | 1 | 80,703 | 18 | 161,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of `A`, `B` and `C`, and an integer K which is between 1 and N (inclusive). Print the string S after lowercasing the K-th character in it.
Constraints
* 1 β€ N β€ 50
* 1 β€ K β€ N
* S is a string of length N consisting of `A`, `B` and `C`.
Input
Input is given from Standard Input in the following format:
N K
S
Output
Print the string S after lowercasing the K-th character in it.
Examples
Input
3 1
ABC
Output
aBC
Input
4 3
CABA
Output
CAbA
Submitted Solution:
```
n, k = input().split()
k = int(k)
s = input()
print(s[:k-1] + s[k-1].lower() + s[k:])
``` | instruction | 0 | 81,498 | 18 | 162,996 |
Yes | output | 1 | 81,498 | 18 | 162,997 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of `A`, `B` and `C`, and an integer K which is between 1 and N (inclusive). Print the string S after lowercasing the K-th character in it.
Constraints
* 1 β€ N β€ 50
* 1 β€ K β€ N
* S is a string of length N consisting of `A`, `B` and `C`.
Input
Input is given from Standard Input in the following format:
N K
S
Output
Print the string S after lowercasing the K-th character in it.
Examples
Input
3 1
ABC
Output
aBC
Input
4 3
CABA
Output
CAbA
Submitted Solution:
```
n,k=map(int,input().split())
s=list(input())
s[k-1]=s[k-1].lower()
ss="".join(s)
print(ss)
``` | instruction | 0 | 81,499 | 18 | 162,998 |
Yes | output | 1 | 81,499 | 18 | 162,999 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of `A`, `B` and `C`, and an integer K which is between 1 and N (inclusive). Print the string S after lowercasing the K-th character in it.
Constraints
* 1 β€ N β€ 50
* 1 β€ K β€ N
* S is a string of length N consisting of `A`, `B` and `C`.
Input
Input is given from Standard Input in the following format:
N K
S
Output
Print the string S after lowercasing the K-th character in it.
Examples
Input
3 1
ABC
Output
aBC
Input
4 3
CABA
Output
CAbA
Submitted Solution:
```
N,K=input().split()
K=int(K)
S=input()
print(S[:K-1]+S[K-1].lower()+S[K:])
``` | instruction | 0 | 81,500 | 18 | 163,000 |
Yes | output | 1 | 81,500 | 18 | 163,001 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of `A`, `B` and `C`, and an integer K which is between 1 and N (inclusive). Print the string S after lowercasing the K-th character in it.
Constraints
* 1 β€ N β€ 50
* 1 β€ K β€ N
* S is a string of length N consisting of `A`, `B` and `C`.
Input
Input is given from Standard Input in the following format:
N K
S
Output
Print the string S after lowercasing the K-th character in it.
Examples
Input
3 1
ABC
Output
aBC
Input
4 3
CABA
Output
CAbA
Submitted Solution:
```
_,k=input().split()
s=list(input())
k=int(k)-1
s[k]=s[k].lower()
print(*s,sep='')
``` | instruction | 0 | 81,501 | 18 | 163,002 |
Yes | output | 1 | 81,501 | 18 | 163,003 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of `A`, `B` and `C`, and an integer K which is between 1 and N (inclusive). Print the string S after lowercasing the K-th character in it.
Constraints
* 1 β€ N β€ 50
* 1 β€ K β€ N
* S is a string of length N consisting of `A`, `B` and `C`.
Input
Input is given from Standard Input in the following format:
N K
S
Output
Print the string S after lowercasing the K-th character in it.
Examples
Input
3 1
ABC
Output
aBC
Input
4 3
CABA
Output
CAbA
Submitted Solution:
```
X = int(input().split())
N = int(X[0])
K = int(X[1])
S = list(str(input()))
if S[K]=="A":
S[K] = "a"
elif S[K]=="B":
S[K] = "b"
elif S[K]=="C":
S[K] = "c"
for i in S:
print(i, end ="")
``` | instruction | 0 | 81,503 | 18 | 163,006 |
No | output | 1 | 81,503 | 18 | 163,007 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of `A`, `B` and `C`, and an integer K which is between 1 and N (inclusive). Print the string S after lowercasing the K-th character in it.
Constraints
* 1 β€ N β€ 50
* 1 β€ K β€ N
* S is a string of length N consisting of `A`, `B` and `C`.
Input
Input is given from Standard Input in the following format:
N K
S
Output
Print the string S after lowercasing the K-th character in it.
Examples
Input
3 1
ABC
Output
aBC
Input
4 3
CABA
Output
CAbA
Submitted Solution:
```
n,k=map(int,input().split())
a = input()
a = list(a)
a[k - 1] = a[k-1].lower()
a = "".join(a)
print(a)
127
a,b = map(int, input().split(" "))
if a >= 13 :
print(b)
elif a >= 6 :
print(b//2)
else:
print(0)
``` | instruction | 0 | 81,504 | 18 | 163,008 |
No | output | 1 | 81,504 | 18 | 163,009 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string S of length N consisting of `A`, `B` and `C`, and an integer K which is between 1 and N (inclusive). Print the string S after lowercasing the K-th character in it.
Constraints
* 1 β€ N β€ 50
* 1 β€ K β€ N
* S is a string of length N consisting of `A`, `B` and `C`.
Input
Input is given from Standard Input in the following format:
N K
S
Output
Print the string S after lowercasing the K-th character in it.
Examples
Input
3 1
ABC
Output
aBC
Input
4 3
CABA
Output
CAbA
Submitted Solution:
```
N,K = map(int, input().split())
S = str(input())
if(S[K-1]=='A'):
for i in range(N):
if(i==K-1):
print('a',end='')
else:
print(S[i], end='')
elif(S[K-1]=='B'):
for i in range(N):
if(i==K-1):
print('b',end='')
else:
print(S[i],end='')
else:
for i in range(N):
if(i==K-1):
print('a',end='')
else:
print(S[i],end='')
``` | instruction | 0 | 81,505 | 18 | 163,010 |
No | output | 1 | 81,505 | 18 | 163,011 |
Provide a correct Python 3 solution for this coding contest problem.
You gave the twins Ai and Zu a program of games using strings. In this game, Ai and Zu each select a substring from the character string, compare them, and the person who chooses the smaller one will get points. The two competed and played the game many times. However, I got tired of playing games for the same string many times. So you decided to modify the program so that the strings change.
Given a string U of length N and Q statements, write a program that processes the following instructions.
* Replaces all characters in the specified range of string U with the specified characters.
* Compares the two specified substrings S and T of the string U in lexicographical order and outputs their magnitude relations.
Input
The input is given in the following format.
N
U
Q
query1
query2
::
queryQ
The string length N (1 β€ N β€ 200000) is given on the first line, and the string U (string containing only lowercase letters) is given on the second line. The number of instructions Q (1 β€ Q β€ 100000) is given on the third line. The following Q line is given the i-th instruction queryi. Each queryi is given in one of the following formats:
set x y z
Or
comp a b c d
set x y z means to replace the xth to yth characters of the string U with the specified character z. Where 1 β€ x β€ y β€ N and z is lowercase.
comp abcd is a string S and a string, where S is the substring from the a to b of the string U and T is the substring of the string U from the c to the d. Represents comparing T in lexical order. Where 1 β€ a β€ b β€ N and 1 β€ c β€ d β€ N.
Output
For each comp instruction, if S is smaller, "s" is output, if T is smaller, "t" is output, and if both match, "e" is output on one line.
Example
Input
13
aizualgorithm
9
comp 1 1 4 5
comp 2 6 1 5
set 9 12 b
comp 9 9 10 10
comp 5 8 1 4
set 1 10 z
set 11 13 x
comp 8 10 1 5
comp 1 5 1 5
Output
s
t
e
t
s
e | instruction | 0 | 81,634 | 18 | 163,268 |
"Correct Solution:
```
def solve():
from sys import stdin
f_i = stdin
N = int(f_i.readline())
U = f_i.readline()
U
Q = int(f_i.readline())
ans = []
for i in range(Q):
query = f_i.readline().split()
if query[0] == 'set':
x, y = map(int, query[1:3])
x -= 1
z = query[3]
U = U[:x] + z * (y - x) + U[y:]
else:
a, b, c, d = map(int, query[1:])
S = U[a-1:b]
T = U[c-1:d]
if S < T:
ans.append('s')
elif T < S:
ans.append('t')
else:
ans.append('e')
print('\n'.join(ans))
solve()
``` | output | 1 | 81,634 | 18 | 163,269 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You gave the twins Ai and Zu a program of games using strings. In this game, Ai and Zu each select a substring from the character string, compare them, and the person who chooses the smaller one will get points. The two competed and played the game many times. However, I got tired of playing games for the same string many times. So you decided to modify the program so that the strings change.
Given a string U of length N and Q statements, write a program that processes the following instructions.
* Replaces all characters in the specified range of string U with the specified characters.
* Compares the two specified substrings S and T of the string U in lexicographical order and outputs their magnitude relations.
Input
The input is given in the following format.
N
U
Q
query1
query2
::
queryQ
The string length N (1 β€ N β€ 200000) is given on the first line, and the string U (string containing only lowercase letters) is given on the second line. The number of instructions Q (1 β€ Q β€ 100000) is given on the third line. The following Q line is given the i-th instruction queryi. Each queryi is given in one of the following formats:
set x y z
Or
comp a b c d
set x y z means to replace the xth to yth characters of the string U with the specified character z. Where 1 β€ x β€ y β€ N and z is lowercase.
comp abcd is a string S and a string, where S is the substring from the a to b of the string U and T is the substring of the string U from the c to the d. Represents comparing T in lexical order. Where 1 β€ a β€ b β€ N and 1 β€ c β€ d β€ N.
Output
For each comp instruction, if S is smaller, "s" is output, if T is smaller, "t" is output, and if both match, "e" is output on one line.
Example
Input
13
aizualgorithm
9
comp 1 1 4 5
comp 2 6 1 5
set 9 12 b
comp 9 9 10 10
comp 5 8 1 4
set 1 10 z
set 11 13 x
comp 8 10 1 5
comp 1 5 1 5
Output
s
t
e
t
s
e
Submitted Solution:
```
N, U, Q = int(input()), input(), int(input())
for _ in range(Q):
query = input().split()
if query[0] == 'comp':
a, b, c, d = int(query[1]), int(query[2]), int(query[3]), int(query[4])
S, T = U[a-1:b], U[c-1:d]
print('e' if S==T else('t' if S > T else 's'))
else:
x, y, z = int(query[1]), int(query[2]), query[3]
s = [z] * (y-x+1)
U = [U[:x-1]] + s + [U[y:]]
U = ''.join(U)
``` | instruction | 0 | 81,635 | 18 | 163,270 |
No | output | 1 | 81,635 | 18 | 163,271 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You gave the twins Ai and Zu a program of games using strings. In this game, Ai and Zu each select a substring from the character string, compare them, and the person who chooses the smaller one will get points. The two competed and played the game many times. However, I got tired of playing games for the same string many times. So you decided to modify the program so that the strings change.
Given a string U of length N and Q statements, write a program that processes the following instructions.
* Replaces all characters in the specified range of string U with the specified characters.
* Compares the two specified substrings S and T of the string U in lexicographical order and outputs their magnitude relations.
Input
The input is given in the following format.
N
U
Q
query1
query2
::
queryQ
The string length N (1 β€ N β€ 200000) is given on the first line, and the string U (string containing only lowercase letters) is given on the second line. The number of instructions Q (1 β€ Q β€ 100000) is given on the third line. The following Q line is given the i-th instruction queryi. Each queryi is given in one of the following formats:
set x y z
Or
comp a b c d
set x y z means to replace the xth to yth characters of the string U with the specified character z. Where 1 β€ x β€ y β€ N and z is lowercase.
comp abcd is a string S and a string, where S is the substring from the a to b of the string U and T is the substring of the string U from the c to the d. Represents comparing T in lexical order. Where 1 β€ a β€ b β€ N and 1 β€ c β€ d β€ N.
Output
For each comp instruction, if S is smaller, "s" is output, if T is smaller, "t" is output, and if both match, "e" is output on one line.
Example
Input
13
aizualgorithm
9
comp 1 1 4 5
comp 2 6 1 5
set 9 12 b
comp 9 9 10 10
comp 5 8 1 4
set 1 10 z
set 11 13 x
comp 8 10 1 5
comp 1 5 1 5
Output
s
t
e
t
s
e
Submitted Solution:
```
n = int(raw_input())
u = raw_input()
q = int(raw_input())
def cmd_set(q,u):
x = int(q[0])
y = int(q[1])
z = q[2]
h = u[:x-1]
t = u[y:]
zz= z*(y-x+1)
return h+zz+t
def cmd_comp(q, u):
a = int(q[0])
b = int(q[1])
c = int(q[2])
d = int(q[3])
s = u[a-1:b]
t = u[c-1:d]
if s < t:
print "s"
elif s > t:
print "t"
else:
print "e"
for i in range(q):
q = raw_input().split()
cmd = q[0]
q.pop(0)
if cmd == 'comp':
cmd_comp(q, u)
elif cmd == 'set':
u = cmd_set(q, u)
``` | instruction | 0 | 81,636 | 18 | 163,272 |
No | output | 1 | 81,636 | 18 | 163,273 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You gave the twins Ai and Zu a program of games using strings. In this game, Ai and Zu each select a substring from the character string, compare them, and the person who chooses the smaller one will get points. The two competed and played the game many times. However, I got tired of playing games for the same string many times. So you decided to modify the program so that the strings change.
Given a string U of length N and Q statements, write a program that processes the following instructions.
* Replaces all characters in the specified range of string U with the specified characters.
* Compares the two specified substrings S and T of the string U in lexicographical order and outputs their magnitude relations.
Input
The input is given in the following format.
N
U
Q
query1
query2
::
queryQ
The string length N (1 β€ N β€ 200000) is given on the first line, and the string U (string containing only lowercase letters) is given on the second line. The number of instructions Q (1 β€ Q β€ 100000) is given on the third line. The following Q line is given the i-th instruction queryi. Each queryi is given in one of the following formats:
set x y z
Or
comp a b c d
set x y z means to replace the xth to yth characters of the string U with the specified character z. Where 1 β€ x β€ y β€ N and z is lowercase.
comp abcd is a string S and a string, where S is the substring from the a to b of the string U and T is the substring of the string U from the c to the d. Represents comparing T in lexical order. Where 1 β€ a β€ b β€ N and 1 β€ c β€ d β€ N.
Output
For each comp instruction, if S is smaller, "s" is output, if T is smaller, "t" is output, and if both match, "e" is output on one line.
Example
Input
13
aizualgorithm
9
comp 1 1 4 5
comp 2 6 1 5
set 9 12 b
comp 9 9 10 10
comp 5 8 1 4
set 1 10 z
set 11 13 x
comp 8 10 1 5
comp 1 5 1 5
Output
s
t
e
t
s
e
Submitted Solution:
```
N, U, Q= int(input()), input(), int(input())
for _ in range(Q):
query= input().split()
if query[0]== "comp":
a,b,c,d= map(int, query[1:])
S,T= U[a-1:b],U[c-1:d]
print('e' if S==T else('s' if sorted([S,T])==[S,T] else 't'))
else:
x,y= map(int, query[1:3])
z= query[3]
U= U.replace(U[x-1:y], z*len(U[x-1:y]))
``` | instruction | 0 | 81,637 | 18 | 163,274 |
No | output | 1 | 81,637 | 18 | 163,275 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp came up with a new programming language. There are only two types of statements in it:
* "x := s": assign the variable named x the value s (where s is a string). For example, the statement var := hello assigns the variable named var the value hello. Note that s is the value of a string, not the name of a variable. Between the variable name, the := operator and the string contains exactly one space each.
* "x = a + b": assign the variable named x the concatenation of values of two variables a and b. For example, if the program consists of three statements a := hello, b := world, c = a + b, then the variable c will contain the string helloworld. It is guaranteed that the program is correct and the variables a and b were previously defined. There is exactly one space between the variable names and the = and + operators.
All variable names and strings only consist of lowercase letters of the English alphabet and do not exceed 5 characters.
The result of the program is the number of occurrences of string haha in the string that was written to the variable in the last statement.
Polycarp was very tired while inventing that language. He asks you to implement it. Your task is β for given program statements calculate the number of occurrences of string haha in the last assigned variable.
Input
The first line contains an integer t (1 β€ t β€ 10^3). Then t test cases follow.
The first line of each test case contains a single integer n (1 β€ n β€ 50) β the number of statements in the program. All variable names and strings are guaranteed to consist only of lowercase letters of the English alphabet and do not exceed 5 characters.
This is followed by n lines describing the statements in the format described above. It is guaranteed that the program is correct.
Output
For each set of input data, output the number of occurrences of the haha substring in the string that was written to the variable in the last statement.
Example
Input
4
6
a := h
b := aha
c = a + b
c = c + c
e = c + c
d = a + c
15
x := haha
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
1
haha := hah
5
haahh := aaaha
ahhhh = haahh + haahh
haahh = haahh + haahh
ahhhh = ahhhh + haahh
ahhaa = haahh + ahhhh
Output
3
32767
0
0
Note
In the first test case the resulting value of d is hhahahaha.
Submitted Solution:
```
def count(s):
val = 0
for i in range(len(s)-3):
if s[i:i+4] == "haha":
val += 1
return val
t = int(input())
for i in range(t):
n = int(input())
dic = {}
ans = {}
for j in range(n):
cmd = input()
if ":=" in cmd:
var, inp = cmd.split(" := ")
var = var.strip()
inp = inp.strip()
dic[var] = inp
ans[var] = 0
else:
var, inp = cmd.split(" = ")
var = var.strip()
var1, var2 = inp.split(' + ')
var1 = var1.strip()
var2 = var2.strip()
fs = dic[var1]+dic[var2]
# print("Initial: ", fs)
if len(fs) > 6:
ans[var] = ans.get(var1,0)+ans.get(var2,0)+count(fs)
fs = fs[0:3]+'-'+fs[-3:]
# print("final fs:", fs, ans)
dic[var] = fs
if j == n-1:
if '-' in dic[var]:
print(ans.get(var, 0))
else:
print(count(dic[var]))
``` | instruction | 0 | 81,990 | 18 | 163,980 |
Yes | output | 1 | 81,990 | 18 | 163,981 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp came up with a new programming language. There are only two types of statements in it:
* "x := s": assign the variable named x the value s (where s is a string). For example, the statement var := hello assigns the variable named var the value hello. Note that s is the value of a string, not the name of a variable. Between the variable name, the := operator and the string contains exactly one space each.
* "x = a + b": assign the variable named x the concatenation of values of two variables a and b. For example, if the program consists of three statements a := hello, b := world, c = a + b, then the variable c will contain the string helloworld. It is guaranteed that the program is correct and the variables a and b were previously defined. There is exactly one space between the variable names and the = and + operators.
All variable names and strings only consist of lowercase letters of the English alphabet and do not exceed 5 characters.
The result of the program is the number of occurrences of string haha in the string that was written to the variable in the last statement.
Polycarp was very tired while inventing that language. He asks you to implement it. Your task is β for given program statements calculate the number of occurrences of string haha in the last assigned variable.
Input
The first line contains an integer t (1 β€ t β€ 10^3). Then t test cases follow.
The first line of each test case contains a single integer n (1 β€ n β€ 50) β the number of statements in the program. All variable names and strings are guaranteed to consist only of lowercase letters of the English alphabet and do not exceed 5 characters.
This is followed by n lines describing the statements in the format described above. It is guaranteed that the program is correct.
Output
For each set of input data, output the number of occurrences of the haha substring in the string that was written to the variable in the last statement.
Example
Input
4
6
a := h
b := aha
c = a + b
c = c + c
e = c + c
d = a + c
15
x := haha
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
1
haha := hah
5
haahh := aaaha
ahhhh = haahh + haahh
haahh = haahh + haahh
ahhhh = ahhhh + haahh
ahhaa = haahh + ahhhh
Output
3
32767
0
0
Note
In the first test case the resulting value of d is hhahahaha.
Submitted Solution:
```
T = int(input())
t = 1
while t<=T:
n = int(input())
dic = {}
hahanum = {}
for i in range(n):
s = input()
s = s.split(" ")
newv = s[0]
if len(s)==3:
dic[newv] = [s[2],s[2]]
if "haha" in s[2]: hahanum[newv] = 1
else: hahanum[newv] = 0
elif len(s)==5:
fronts = dic[s[2]]
rears = dic[s[4]]
# print(fronts,rears)
if len(fronts[0])>=5 and len(rears[1])>=5:
newfront = fronts[0]
newrear = rears[1]
elif len(fronts[0])<5 and len(rears[1])<5:
news = fronts[0]+rears[1]
newfront = news[:5]
newrear = news[-5:]
elif len(fronts[0])==5 and len(rears[1])<5:
newfront = fronts[0]
newrear = fronts[1][-(5-len(rears[1])):] + rears[1]
elif len(fronts[0])< 5 and len(rears[1])==5:
newrear = rears[1]
newfront = fronts[0] + rears[0][:(5-len(fronts[0]))]
base = 0
for i in [1,2,3]:
if fronts[1][-i:] + rears[0][:(4-i)] == "haha":
base += 1
base += hahanum[s[2]]
base += hahanum[s[4]]
dic[newv] = [newfront,newrear]
hahanum[newv] = base
# print(newv,dic[newv],hahanum[newv])
print(hahanum[newv])
t += 1
``` | instruction | 0 | 81,991 | 18 | 163,982 |
Yes | output | 1 | 81,991 | 18 | 163,983 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp came up with a new programming language. There are only two types of statements in it:
* "x := s": assign the variable named x the value s (where s is a string). For example, the statement var := hello assigns the variable named var the value hello. Note that s is the value of a string, not the name of a variable. Between the variable name, the := operator and the string contains exactly one space each.
* "x = a + b": assign the variable named x the concatenation of values of two variables a and b. For example, if the program consists of three statements a := hello, b := world, c = a + b, then the variable c will contain the string helloworld. It is guaranteed that the program is correct and the variables a and b were previously defined. There is exactly one space between the variable names and the = and + operators.
All variable names and strings only consist of lowercase letters of the English alphabet and do not exceed 5 characters.
The result of the program is the number of occurrences of string haha in the string that was written to the variable in the last statement.
Polycarp was very tired while inventing that language. He asks you to implement it. Your task is β for given program statements calculate the number of occurrences of string haha in the last assigned variable.
Input
The first line contains an integer t (1 β€ t β€ 10^3). Then t test cases follow.
The first line of each test case contains a single integer n (1 β€ n β€ 50) β the number of statements in the program. All variable names and strings are guaranteed to consist only of lowercase letters of the English alphabet and do not exceed 5 characters.
This is followed by n lines describing the statements in the format described above. It is guaranteed that the program is correct.
Output
For each set of input data, output the number of occurrences of the haha substring in the string that was written to the variable in the last statement.
Example
Input
4
6
a := h
b := aha
c = a + b
c = c + c
e = c + c
d = a + c
15
x := haha
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
1
haha := hah
5
haahh := aaaha
ahhhh = haahh + haahh
haahh = haahh + haahh
ahhhh = ahhhh + haahh
ahhaa = haahh + ahhhh
Output
3
32767
0
0
Note
In the first test case the resulting value of d is hhahahaha.
Submitted Solution:
```
def basic_count_occurences(t, p = "haha"):
cnt = 0; n = len(t); m = len(p)
for i in range(n - m + 1):
if t[i : i + m] == p:
cnt += 1
return cnt
def get_s(s0):
if len(s0) >= 6:
s = s0[:3] + s0[-3:]
else:
s = s0
return s
def solve(n):
latest = None; v = {}
for i in range(n):
#print(v)
exp = input().split(" ")
if len(exp) == 3:
latest = exp[0]
occs = basic_count_occurences(exp[2])
s = get_s(exp[2])
v[exp[0]] = [s, occs]
else:
target, var1, var2 = exp[0], exp[2], exp[4]
latest = target
old_occs = v[var1][1] + v[var2][1]
new_occs = basic_count_occurences(v[var1][0][-3:] + v[var2][0][:3])
occs = old_occs + new_occs
s = get_s(v[var1][0] + v[var2][0])
v[target] = [s, occs]
return v[latest][1]
def main():
t = int(input())
for _ in range(t):
n = int(input())
print(solve(n))
main()
``` | instruction | 0 | 81,992 | 18 | 163,984 |
Yes | output | 1 | 81,992 | 18 | 163,985 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp came up with a new programming language. There are only two types of statements in it:
* "x := s": assign the variable named x the value s (where s is a string). For example, the statement var := hello assigns the variable named var the value hello. Note that s is the value of a string, not the name of a variable. Between the variable name, the := operator and the string contains exactly one space each.
* "x = a + b": assign the variable named x the concatenation of values of two variables a and b. For example, if the program consists of three statements a := hello, b := world, c = a + b, then the variable c will contain the string helloworld. It is guaranteed that the program is correct and the variables a and b were previously defined. There is exactly one space between the variable names and the = and + operators.
All variable names and strings only consist of lowercase letters of the English alphabet and do not exceed 5 characters.
The result of the program is the number of occurrences of string haha in the string that was written to the variable in the last statement.
Polycarp was very tired while inventing that language. He asks you to implement it. Your task is β for given program statements calculate the number of occurrences of string haha in the last assigned variable.
Input
The first line contains an integer t (1 β€ t β€ 10^3). Then t test cases follow.
The first line of each test case contains a single integer n (1 β€ n β€ 50) β the number of statements in the program. All variable names and strings are guaranteed to consist only of lowercase letters of the English alphabet and do not exceed 5 characters.
This is followed by n lines describing the statements in the format described above. It is guaranteed that the program is correct.
Output
For each set of input data, output the number of occurrences of the haha substring in the string that was written to the variable in the last statement.
Example
Input
4
6
a := h
b := aha
c = a + b
c = c + c
e = c + c
d = a + c
15
x := haha
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
1
haha := hah
5
haahh := aaaha
ahhhh = haahh + haahh
haahh = haahh + haahh
ahhhh = ahhhh + haahh
ahhaa = haahh + ahhhh
Output
3
32767
0
0
Note
In the first test case the resulting value of d is hhahahaha.
Submitted Solution:
```
import sys
# sys.setrecursionlimit(10**5)
int1 = lambda x: int(x)-1
p2D = lambda x: print(*x, sep="\n")
def II(): return int(sys.stdin.buffer.readline())
def LI(): return list(map(int, sys.stdin.buffer.readline().split()))
def LI1(): return list(map(int1, sys.stdin.buffer.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def LLI1(rows_number): return [LI1() for _ in range(rows_number)]
def BI(): return sys.stdin.buffer.readline().rstrip()
def SI(): return sys.stdin.buffer.readline().rstrip().decode()
# dij = [(0, 1), (-1, 0), (0, -1), (1, 0)]
dij = [(0, 1), (-1, 0), (0, -1), (1, 0), (1, 1), (1, -1), (-1, 1), (-1, -1)]
inf = 10**16
md = 998244353
# md = 10**9+7
class haha:
def __init__(self, s=""):
self.val = self.cnt(s)
self.pre = s[:3]
self.suf = s[-3:]
self.size = len(s)
def cnt(self, s):
res = 0
for i in range(len(s)-3):
if s[i:i+4] == "haha": res += 1
return res
def __add__(self, other):
if self.size < 6 and other.size < 6:
s = self.pre if self.size < 4 else self.pre+self.suf[6-self.size:]
t = other.pre if other.size < 4 else other.pre+other.suf[6-other.size:]
return haha(s+t)
res = haha()
if self.size < 6:
s = self.pre if self.size < 4 else self.pre+self.suf[6-self.size:]
res.pre = (s+other.pre)[:3]
res.suf = other.suf
elif other.size < 6:
t = other.pre if other.size < 4 else other.pre+other.suf[6-other.size:]
res.pre = self.pre
res.suf = (self.suf+t)[-3:]
else:
res.pre = self.pre
res.suf = other.suf
res.val = self.cnt(self.suf+other.pre)+self.val+other.val
res.size = self.size+other.size
return res
for testcase in range(II()):
n = II()
var = {}
last = ""
for _ in range(n):
task = SI().split()
if task[1] == ":=":
var[task[0]] = haha(task[2])
else:
var[task[0]] = var[task[2]]+var[task[4]]
last = task[0]
# print(var)
print(var[last].val)
``` | instruction | 0 | 81,993 | 18 | 163,986 |
Yes | output | 1 | 81,993 | 18 | 163,987 |
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