message stringlengths 2 59.7k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 37 108k | cluster float64 20 20 | __index_level_0__ int64 74 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6 | instruction | 0 | 92,175 | 20 | 184,350 |
Tags: combinatorics, math
Correct Solution:
```
a = input()
print(2 ** (int(a)+1) - 2)
``` | output | 1 | 92,175 | 20 | 184,351 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6 | instruction | 0 | 92,176 | 20 | 184,352 |
Tags: combinatorics, math
Correct Solution:
```
n = int(input())
print(sum(2**(i + 1) for i in range(n)))
``` | output | 1 | 92,176 | 20 | 184,353 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6 | instruction | 0 | 92,177 | 20 | 184,354 |
Tags: combinatorics, math
Correct Solution:
```
num_digits = int(input())
print(sum(2 ** i for i in range(1, num_digits + 1)))
``` | output | 1 | 92,177 | 20 | 184,355 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6 | instruction | 0 | 92,178 | 20 | 184,356 |
Tags: combinatorics, math
Correct Solution:
```
n = 56
lista = [1] * n
lista[0] = 0
lista[1] = 2
for i in range(2, n):
lista[i] = lista[i - 1] + 2 ** i
dig = int(input())
print(lista[dig])
``` | output | 1 | 92,178 | 20 | 184,357 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6
Submitted Solution:
```
n = int(input())
sum = 0
for i in range(1,n+1) :
sum += 2**i
print (sum)
``` | instruction | 0 | 92,179 | 20 | 184,358 |
Yes | output | 1 | 92,179 | 20 | 184,359 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6
Submitted Solution:
```
a = int(input())
a=2**(a+1)-2
print(a)
``` | instruction | 0 | 92,180 | 20 | 184,360 |
Yes | output | 1 | 92,180 | 20 | 184,361 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6
Submitted Solution:
```
n = int(input())
print(2**(n)*2 - 2)
``` | instruction | 0 | 92,181 | 20 | 184,362 |
Yes | output | 1 | 92,181 | 20 | 184,363 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6
Submitted Solution:
```
maxn = int(input())
answer = 0
for i in range(maxn):
a = 1
for j in range(i+1):
a = a*2
answer+=a
print(answer)
``` | instruction | 0 | 92,182 | 20 | 184,364 |
Yes | output | 1 | 92,182 | 20 | 184,365 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6
Submitted Solution:
```
import sys
input = sys.stdin.readline
def list_input():
return list(map(int, input().split()))
def float_compare(a, b):
if abs(a-b) < float(1e-9):
return True
else:
return False
def sub_mod(x, mod):
x = x % mod
if x < 0:
x += mod
return x
def divisor(n):
i = 1
dv = []
while i*i <= n:
if n % i == 0:
dv.append(i)
if i*i != n:
dv.append(n//i)
i += 1
return dv
n = int(input().strip())
print((3**(n-1))*2)
``` | instruction | 0 | 92,183 | 20 | 184,366 |
No | output | 1 | 92,183 | 20 | 184,367 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6
Submitted Solution:
```
n=int(input())
print(2**n+2)
``` | instruction | 0 | 92,184 | 20 | 184,368 |
No | output | 1 | 92,184 | 20 | 184,369 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6
Submitted Solution:
```
first = int(input())
total = 0
for i in range(1,first+1):
total += i*2
#plz
print(total)
``` | instruction | 0 | 92,185 | 20 | 184,370 |
No | output | 1 | 92,185 | 20 | 184,371 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The numbers of all offices in the new building of the Tax Office of IT City will have lucky numbers.
Lucky number is a number that consists of digits 7 and 8 only. Find the maximum number of offices in the new building of the Tax Office given that a door-plate can hold a number not longer than n digits.
Input
The only line of input contains one integer n (1 ≤ n ≤ 55) — the maximum length of a number that a door-plate can hold.
Output
Output one integer — the maximum number of offices, than can have unique lucky numbers not longer than n digits.
Examples
Input
2
Output
6
Submitted Solution:
```
i = 1
n = eval(input())
s = 0
while(i<=n):
s = s + i ** 2
i = i + 1
``` | instruction | 0 | 92,186 | 20 | 184,372 |
No | output | 1 | 92,186 | 20 | 184,373 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Elephant loves numbers.
He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1 ≤ x ≤ 109).
Output
In a single line print an integer — the answer to the problem.
Examples
Input
1
Output
1
Input
10
Output
2 | instruction | 0 | 92,930 | 20 | 185,860 |
Tags: implementation
Correct Solution:
```
import math
def check(s1,s2):
for i in range(len(s1)):
for j in range(len(s2)):
if(s1[i]==s2[j]):
return True
return False
N = int(input())
div = 0
bound = math.floor(math.sqrt(N))
for i in range(bound):
k = i+1
if(N%k==0):
f1 = str(k)
f2 = str(N//k)
if(check(f1,str(N))):
div += 1
if(f1!=f2 and check(f2,str(N))):
div += 1
print (div)
``` | output | 1 | 92,930 | 20 | 185,861 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Elephant loves numbers.
He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1 ≤ x ≤ 109).
Output
In a single line print an integer — the answer to the problem.
Examples
Input
1
Output
1
Input
10
Output
2 | instruction | 0 | 92,931 | 20 | 185,862 |
Tags: implementation
Correct Solution:
```
import math
x=int(input())
digit=""
for i in range(10):
if str(i) in str(x):
digit+=str(i)
counter=0
for i in range(1,int(math.sqrt(x))+1):
if x%i==0:
for j in str(i):
if j in digit:
counter+=1
break
for j in str(x//i):
if (j in digit) and (x//i > i) :
counter+=1
break
print(counter)
``` | output | 1 | 92,931 | 20 | 185,863 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Elephant loves numbers.
He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1 ≤ x ≤ 109).
Output
In a single line print an integer — the answer to the problem.
Examples
Input
1
Output
1
Input
10
Output
2 | instruction | 0 | 92,932 | 20 | 185,864 |
Tags: implementation
Correct Solution:
```
import math
class CodeforcesTask221BSolution:
def __init__(self):
self.result = ''
self.x = 0
def read_input(self):
self.x = int(input())
def process_task(self):
if self.x == 1:
self.result = "1"
else:
numix = 1
repo = str(self.x)
if "1" in repo:
numix += 1
for x in range(2, int(math.sqrt(self.x)) + 1):
if x < self.x:
if not self.x % x:
#print(x, self.x // x)
have = False
for c in str(x):
if c in repo:
have = True
break
if have:
numix += 1
if self.x // x != x:
have = False
for c in str(self.x // x):
if c in repo:
have = True
break
if have:
numix += 1
self.result = str(numix)
def get_result(self):
return self.result
if __name__ == "__main__":
Solution = CodeforcesTask221BSolution()
Solution.read_input()
Solution.process_task()
print(Solution.get_result())
``` | output | 1 | 92,932 | 20 | 185,865 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Elephant loves numbers.
He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1 ≤ x ≤ 109).
Output
In a single line print an integer — the answer to the problem.
Examples
Input
1
Output
1
Input
10
Output
2 | instruction | 0 | 92,933 | 20 | 185,866 |
Tags: implementation
Correct Solution:
```
n = int(input())
d = 0
for i in range(1,int(n ** 0.5)+1) :
if n % i == 0 :
for j in str(i) :
if j in str(n) :
d += 1
break
k = n // i
if k != i :
for j in str(k) :
if j in str(n) :
d += 1
break
print(d)
``` | output | 1 | 92,933 | 20 | 185,867 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Elephant loves numbers.
He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1 ≤ x ≤ 109).
Output
In a single line print an integer — the answer to the problem.
Examples
Input
1
Output
1
Input
10
Output
2 | instruction | 0 | 92,935 | 20 | 185,870 |
Tags: implementation
Correct Solution:
```
from sys import stdin,stdout
nmbr = lambda: int(stdin.readline())
lst = lambda: list(map(int,stdin.readline().split()))
def fn(x,fact):
same=0
for ch in str(x):
for ch1 in str(fact):
if ch==ch1:return 1
return 0
for _ in range(1):#nmbr()):
n=nmbr()
p=1;ans=0
while p*p<=n:
if n%p==0:
ans+=fn(n,p)
if p!=n//p:ans+=fn(n,n//p)
p+=1
print(ans)
``` | output | 1 | 92,935 | 20 | 185,871 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Elephant loves numbers.
He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1 ≤ x ≤ 109).
Output
In a single line print an integer — the answer to the problem.
Examples
Input
1
Output
1
Input
10
Output
2 | instruction | 0 | 92,936 | 20 | 185,872 |
Tags: implementation
Correct Solution:
```
a=int(input())
x=0
div=[]
for i in range(1,int(a**0.5)+1):
if a%i==0:
div.append(i)
b=len(div)
for i in div[:b]:
div.append(a//i)
div=list(set(div))
for i in div:
t=0
for j in str(i):
if j in str(a):
t=1
x+=t
print(x)
``` | output | 1 | 92,936 | 20 | 185,873 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Little Elephant loves numbers.
He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1 ≤ x ≤ 109).
Output
In a single line print an integer — the answer to the problem.
Examples
Input
1
Output
1
Input
10
Output
2
Submitted Solution:
```
x, val, i = int(input()), 0, 1
xs = set(str(x))
def dc(n):
return bool(xs & set(str(n)))
while i * i < x:
if x % i == 0:
val += dc(i) + dc(x // i)
i += 1
print(val + (i * i == x and dc(i)))
# Made By Mostafa_Khaled
``` | instruction | 0 | 92,937 | 20 | 185,874 |
Yes | output | 1 | 92,937 | 20 | 185,875 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Little Elephant loves numbers.
He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1 ≤ x ≤ 109).
Output
In a single line print an integer — the answer to the problem.
Examples
Input
1
Output
1
Input
10
Output
2
Submitted Solution:
```
import sys
def fastio():
from io import StringIO
from atexit import register
global input
sys.stdin = StringIO(sys.stdin.read())
input = lambda : sys.stdin.readline().rstrip('\r\n')
sys.stdout = StringIO()
register(lambda : sys.__stdout__.write(sys.stdout.getvalue()))
fastio()
def debug(*var, sep = ' ', end = '\n'):
print(*var, file=sys.stderr, end = end, sep = sep)
INF = 10**20
MOD = 10**9 + 7
I = lambda:list(map(int,input().split()))
from math import gcd
from math import ceil
from collections import defaultdict as dd, Counter
from bisect import bisect_left as bl, bisect_right as br
n, = I()
ans = 0
for i in range(1, int(n ** .5) + 1):
if n % i:
continue
f = str(i)
s = ''
if i ** 2 != n:
s = str(n // i)
for i in range(10):
k = str(i)
if k in f and k in str(n):
ans += 1
break
for i in range(10):
k = str(i)
if k in s and k in str(n):
ans += 1
break
print(ans)
``` | instruction | 0 | 92,939 | 20 | 185,878 |
Yes | output | 1 | 92,939 | 20 | 185,879 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Little Elephant loves numbers.
He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1 ≤ x ≤ 109).
Output
In a single line print an integer — the answer to the problem.
Examples
Input
1
Output
1
Input
10
Output
2
Submitted Solution:
```
import math
n=int(input())
def single(n):
l=[]
while n!=0:
a=n%10
l.append(a)
n=n//10
return l
def simple(n):
l=[]
x=int(math.sqrt(n))
for i in range(1,x+1):
if n%i==0:
if i*i==n:
l.append(i)
else:
l.append(i)
l.append(n//i)
return l
temp=simple(n)
count=0
mlist=single(n)
for i in range(len(temp)):
pink=single(temp[i])
done=0
for j in pink:
if j in mlist:
done=1
if done==1:
count+=1
print(count)
``` | instruction | 0 | 92,940 | 20 | 185,880 |
Yes | output | 1 | 92,940 | 20 | 185,881 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Little Elephant loves numbers.
He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1 ≤ x ≤ 109).
Output
In a single line print an integer — the answer to the problem.
Examples
Input
1
Output
1
Input
10
Output
2
Submitted Solution:
```
import math
n_str = input()
n = int(n_str)
n_set = set(n_str)
ds = []
def has_common_digit(i):
for k in i:
#print(k)
if k in n_set:
return True
return False
for i in range(1,int(math.sqrt(n))):
#for i in range(1,int(n/2)+2):
if n%i == 0:
if has_common_digit(str(i)):
ds.append(i)
if i != n/i:
if has_common_digit(str(int(n/i))):
ds.append(int(n/i))
if n not in ds:
ds.append(n)
print(len(ds))
``` | instruction | 0 | 92,942 | 20 | 185,884 |
No | output | 1 | 92,942 | 20 | 185,885 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Little Elephant loves numbers.
He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1 ≤ x ≤ 109).
Output
In a single line print an integer — the answer to the problem.
Examples
Input
1
Output
1
Input
10
Output
2
Submitted Solution:
```
import math
x=int(input())
num=x
count=1
if x!=1 and str(1) in str(x):
count+=1
for i in range(2,int(math.sqrt(x))+1):
if num%i==0:
#print(i,(num/i))
if str(i) in str(x):
#print('yes1')
count+=1
if str(int(num/i)) in str(x):
#print('yes2')
count+=1
print(count)
``` | instruction | 0 | 92,943 | 20 | 185,886 |
No | output | 1 | 92,943 | 20 | 185,887 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Little Elephant loves numbers.
He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x and d have at least one common (the same) digit in their decimal representations.
Help the Little Elephant to find the described number.
Input
A single line contains a single integer x (1 ≤ x ≤ 109).
Output
In a single line print an integer — the answer to the problem.
Examples
Input
1
Output
1
Input
10
Output
2
Submitted Solution:
```
from math import sqrt,floor
vetor = [0] * 10
n = int(input())
aux = n
while aux != 0:
z = floor(aux % 10)
aux = floor(aux/10)
vetor[z] = 1
cont = 0
for i in range(1, floor(sqrt(n))):
if floor(n % i) == 0:
l = floor(n/i)
v = i
while l != 0:
z = floor(l%10)
l = floor(l/10)
if vetor[z] == 1:
cont += 1
break
while v != 0:
z = floor(v % 10)
v = floor(v / 10)
if vetor[z] == 1:
cont += 1
break
z = floor(sqrt(n))
if floor(z*z) == n:
while z != 0:
u = floor(z % 10)
z = floor(z/10)
if vetor[u] == 1:
cont += 1
break
print(cont)
``` | instruction | 0 | 92,944 | 20 | 185,888 |
No | output | 1 | 92,944 | 20 | 185,889 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs. | instruction | 0 | 93,197 | 20 | 186,394 |
Tags: bitmasks, constructive algorithms
Correct Solution:
```
z = 0
o = 1023
n = int(input())
for i in range(n):
a,b = input().split()
b = int(b)
if(a == "&"):
z = z&b
o = o&b
if (a == "^"):
z = z ^ b
o = o ^ b
if (a == "|"):
z = z | b
o = o | b
z = '{:010b}'.format(z)
o = '{:010b}'.format(o)
an = 0
r = 0
xo = 0
pw = 512
for i in range(10):
an+=pw
if(o[i]=='0' and z[i] == '0'): an-=pw
if (o[i] == '1' and z[i] == '1'): r+=pw
if (o[i] == '0' and z[i] == '1'): xo+=pw
pw//=2
print(3)
print("&",an)
print("|",r)
print("^",xo)
``` | output | 1 | 93,197 | 20 | 186,395 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs. | instruction | 0 | 93,198 | 20 | 186,396 |
Tags: bitmasks, constructive algorithms
Correct Solution:
```
from sys import stdin
data = stdin.readlines()
remain = -10
invert = -20
m = [remain] * 10
for i, st in enumerate(data):
if i == 0: continue
op, x = st.strip().split()
x = int(x)
for j in range(10):
bit = x % 2
if op == '&' and bit == 0:
m[j] = 0
elif op == '|' and bit == 1:
m[j] = 1
elif op == '^' and bit == 1:
if m[j] == 0:
m[j] = 1
elif m[j] == 1:
m[j] = 0
elif m[j] == remain:
m[j] = invert
elif m[j] == invert:
m[j] = remain
x = x // 2
print(3)
and_const = 0
for i, v in enumerate(m):
if v != 0:
and_const += 2**i
or_const = 0
for i, v in enumerate(m):
if v == 1:
or_const += 2**i
xor_const = 0
for i, v in enumerate(m):
if v == invert:
xor_const += 2**i
print('&', and_const)
print('|', or_const)
print('^', xor_const)
``` | output | 1 | 93,198 | 20 | 186,397 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs. | instruction | 0 | 93,199 | 20 | 186,398 |
Tags: bitmasks, constructive algorithms
Correct Solution:
```
from math import*
n = int(input())
x = 0
y = 1023
for i in range(n):
gg = input().split()
if gg[0] == '&':
x &= int(gg[1])
y &= int(gg[1])
if gg[0] == '|':
x |= int(gg[1])
y |= int(gg[1])
if gg[0] == '^':
x ^= int(gg[1])
y ^= int(gg[1])
print(3)
print('|', x & y)
print('&', x | y)
print('^', x & (y ^ 1023))
``` | output | 1 | 93,199 | 20 | 186,399 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs. | instruction | 0 | 93,200 | 20 | 186,400 |
Tags: bitmasks, constructive algorithms
Correct Solution:
```
from sys import stdin
BITCOUNT = 10
xONES = (1 << 10) - 1
xZEROS = 0
n = int(stdin.readline())
for i in range(n):
op, num = stdin.readline().split()
num = int(num)
if op == '&':
xONES &= num
xZEROS &= num
elif op == '|':
xONES |= num
xZEROS |= num
else:
xONES ^= num
xZEROS ^= num
andmask = 0
xormask = 0
mask = 1
for i in range(BITCOUNT):
ONESbit = (xONES >> i) & 1
ZEROSbit = (xZEROS >> i) & 1
if (ONESbit == 1) and (ZEROSbit == 0):
andmask += mask
elif (ONESbit == 0) and (ZEROSbit == 1):
andmask += mask
xormask += mask
elif (ONESbit == 1) and (ZEROSbit == 1):
xormask += mask
mask *= 2
print(2)
print('& {}'.format(andmask))
print('^ {}'.format(xormask))
``` | output | 1 | 93,200 | 20 | 186,401 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs. | instruction | 0 | 93,201 | 20 | 186,402 |
Tags: bitmasks, constructive algorithms
Correct Solution:
```
import sys
input=sys.stdin.readline
import copy
from math import *
n=int(input())
a=[-1 for i in range(10)]
for i in range(n):
p,q=input().split()
qq=(bin(int(q))[2:])
q=list((10-len(qq))*"0"+qq)
if p=='|':
for i in range(9,-1,-1):
if q[i]=='1':
a[i]=1
if p=='&':
for i in range(9,-1,-1):
if q[i]=='0':
a[i]=0
if p=='^':
for i in range(9,-1,-1):
if q[i]=='1' and (a[i]==0 or a[i]==1):
a[i]^=1
elif q[i]=='1' :
if a[i]==-1:
a[i]=-2
else:
a[i]=-1
#print(a)
c=0
for i in range(10):
if a[i]==-2:
c+=(2**(10-i-1))
print(3)
print("^",c)
v=list("0"*10)
for i in range(10):
if a[i]==1:
v[i]='1'
print("|",int("".join(v),2))
u=list("1"*10)
for i in range(10):
if a[i]==0:
u[i]='0'
print("&",int("".join(u),2))
``` | output | 1 | 93,201 | 20 | 186,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs. | instruction | 0 | 93,202 | 20 | 186,404 |
Tags: bitmasks, constructive algorithms
Correct Solution:
```
n = int(input())
queries = list(input().split() for _ in range(n))
a, b = 0, (1<<10) - 1
for c, x in queries:
x = int(x)
if c == '|':
a, b = a | x, b | x
elif c == '&':
a, b = a & x, b & x
elif c == '^':
a, b = a ^ x, b ^ x
x, y, z = 0, (1<<10) - 1, 0
for i in range(10):
a_i = (a >> i) & 1
b_i = (b >> i) & 1
if a_i and b_i:
x |= (1 << i)
if not a_i and not b_i:
y ^= (1 << i)
if a_i and not b_i:
z ^= (1 << i)
print(3)
print('|', x)
print('&', y)
print('^', z)
``` | output | 1 | 93,202 | 20 | 186,405 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs. | instruction | 0 | 93,203 | 20 | 186,406 |
Tags: bitmasks, constructive algorithms
Correct Solution:
```
from sys import *
d = {'|': lambda t: t | k, '&': lambda t: t & k, '^': lambda t: t ^ k}
a, b = 1023, 0
for i in range(int(input())):
s, q = stdin.readline().split()
k = int(q)
a = d[s](a)
b = d[s](b)
t = [2]
for u in range(1024):
for v in range(1024):
if 1023 ^ v == a and u ^ v == b:
print('2\n|', u, '\n^', v)
exit()
``` | output | 1 | 93,203 | 20 | 186,407 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs. | instruction | 0 | 93,204 | 20 | 186,408 |
Tags: bitmasks, constructive algorithms
Correct Solution:
```
n = int(input())
a, b = 1023, 0
for _ in range(n):
c, d = input().split()
d = int(d)
if c == '|':
a, b = a | d, b | d
elif c == '&':
a, b = a & d, b & d
elif c == '^':
a, b = a ^ d, b ^ d
print('2\n| {}\n^ {}'.format(a ^ b ^ 1023, a ^ 1023))
``` | output | 1 | 93,204 | 20 | 186,409 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs.
Submitted Solution:
```
import sys
input=sys.stdin.readline
n=int(input())
a=1023
b=0
for _ in range(n):
s,num=input().rstrip().split()
num=int(num)
if s=="|":
a,b=a|num,b|num
elif s=="&":
a,b=a&num,b&num
else:
a,b=a^num,b^num
print("2\n| {}\n^ {}".format(a^b^1023,a^1023))
``` | instruction | 0 | 93,205 | 20 | 186,410 |
Yes | output | 1 | 93,205 | 20 | 186,411 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs.
Submitted Solution:
```
import queue
def readTuple():
return input().split()
def readInts():
return tuple(map(int, readTuple()))
def to_int(x):
x=x[::-1]
res = 0
for i in x:
res <<= 1
res |= i
return res
def solve():
res = ['X']*10
n, = readInts()
a,b = 0, 1023
for _ in range(n):
char, num = readTuple()
num = int(num)
if char == '|':
a |= num
b |= num
if char == '&':
a &= num
b &= num
if char == '^':
a ^= num
b ^= num
XOR, OR = [],[]
for i in range(10):
b1 = a&(1<<i)
b2 = b&(1<<i)
if b1 and b2:
OR.append(1)
XOR.append(0)
if not b1 and not b2:
OR.append(1)
XOR.append(1)
if b1 and not b2:
OR.append(0)
XOR.append(1)
if not b1 and b2:
OR.append(0)
XOR.append(0)
print(2)
print(f"| {to_int(OR)}")
print(f"^ {to_int(XOR)}")
if __name__ == '__main__':
solve()
``` | instruction | 0 | 93,206 | 20 | 186,412 |
Yes | output | 1 | 93,206 | 20 | 186,413 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs.
Submitted Solution:
```
import sys
input = sys.stdin.readline
n = int(input())
com = []
for _ in range(n):
l = input().split()
com.append((l[0], int(l[1])))
AND, OR, XOR = [], [], []
for i in range(10):
res1 = 0
res2 = 1
for s, n in com:
b = (n>>i)&1
if s=='&':
res1 &= b
res2 &= b
elif s=='|':
res1 |= b
res2 |= b
elif s=='^':
res1 ^= b
res2 ^= b
if (res1, res2)==(0, 0):
AND.append(i)
elif (res1, res2)==(1, 1):
OR.append(i)
elif (res1, res2)==(1, 0):
XOR.append(i)
AND_n = 0
for i in range(10):
if i not in AND:
AND_n += 2**i
OR_n = 0
for i in OR:
OR_n += 2**i
XOR_n = 0
for i in XOR:
XOR_n += 2**i
print(3)
print('&', AND_n)
print('|', OR_n)
print('^', XOR_n)
"""
for i in range(1024):
res1 = i
for s, n in com:
if s=='&':
res1 &= n
elif s=='|':
res1 |= n
elif s=='^':
res1 ^= n
res2 = i
res2 &= AND_n
res2 |= OR_n
res2 ^= XOR_n
if res1!=res2:
1/0
"""
``` | instruction | 0 | 93,207 | 20 | 186,414 |
Yes | output | 1 | 93,207 | 20 | 186,415 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs.
Submitted Solution:
```
a, b = 0, 1023
# commands = []
for i in range(int(input())):
cmd = input()
# commands.append(cmd)
c, x = cmd.split()
x = int(x)
if c == "|":
a, b = a | x, b | x
elif c == "&":
a, b = a & x, b & x
else:
a, b = a ^ x, b ^ x
# a, b = eval("a " + cmd), eval("b " + cmd)
x = 0
y = 1023
z = 0
for i in range(10):
a_i = (a >> i) & 1
b_i = (b >> i) & 1
if a_i and b_i:
x |= 1 << i
if (not a_i) and (not b_i):
y ^= 1 << i
if a_i and (not b_i):
z ^= 1 << i
print("3\n| {}\n& {}\n^ {}".format(x, y, z))
# for i in range(1024):
# t1 = i
# for cmd in commands:
# t1 = eval("t1 " + cmd)
# t2 = eval("(((i | x) & y) ^ z)")
# if t1 != t2:
# print("Neq on ", i)
``` | instruction | 0 | 93,208 | 20 | 186,416 |
Yes | output | 1 | 93,208 | 20 | 186,417 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs.
Submitted Solution:
```
n = int(input())
for i in range(n):
x, y = input().split()
y = int(y)
if i == 0:
b = x
m = y
else:
if x == '^':
m = m ^ y
elif x == '|':
m = m | y
else:
m = m & y
if m == 0:
if b == '&':
print(1)
print(b, 0)
else:
print(0)
else:
print(1)
print(b, m)
``` | instruction | 0 | 93,209 | 20 | 186,418 |
No | output | 1 | 93,209 | 20 | 186,419 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs.
Submitted Solution:
```
n = int(input())
action = [0, 1, 2, 3] # reverse, don't do anything, set to zero, set to one
byte = [action[1], action[1], action[1], action[1], action[1], action[1], action[1], action[1], action[1], action[1]]
for i in range(n):
operator, operand = input().split(' ')
operand = int(operand)
binary = []
while operand:
binary.append(operand % 2)
operand //= 2
binary.reverse()
if operator == '^':
for i in range(len(binary)):
if binary[-i - 1] == 0:
continue
if binary[-i - 1] == 1:
if byte[-i - 1] == action[0]:
byte[-i - 1] = action[1]
elif byte[-i - 1] == action[1]:
byte[-i - 1] = action[0]
elif byte[-i - 1] == action[2]:
byte[-i - 1] = action[3]
elif byte[-i - 1] == action[3]:
byte[-i - 1] = action[2]
elif operator == '&':
for i in range(len(binary)):
if binary[-i - 1] == 0:
byte[-i - 1] = action[2]
elif binary[-i - 1] == 1:
continue
elif operator == '|':
for i in range(len(binary)):
if binary[-i - 1] == 0:
continue
elif binary[-i - 1] == 1:
byte[-i - 1] = action[3]
toSwap = 0
for i in range(len(byte)):
if byte[i] == action[0]:
toSwap += 2 ** (9 - i)
toZero = 1023
for i in range(len(byte)):
if byte[i] == action[2]:
toZero -= 2 ** (9 - i)
toOne = 0
for i in range(len(byte)):
if byte[i] == action[3]:
toOne += 2 ** (9 - i)
print(3)
print(*['^', toSwap])
print(*['&', toZero])
print(*['|', toOne])
``` | instruction | 0 | 93,210 | 20 | 186,420 |
No | output | 1 | 93,210 | 20 | 186,421 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs.
Submitted Solution:
```
import io, os
input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
# input = io.StringIO(os.read(0, os.fstat(0).st_size).decode()).readline
ii=lambda:int(input())
kk=lambda:map(int, input().split())
ll=lambda:list(kk())
# xor + 0 --> unchanged(2)
# xor + 1 --> flip(3)
# or + 0 --> unchanged(2)
# or + 1 --> 1(1)
# and + 0 --> 0(0)
# and + 1 --> unchanged(2)
arr = [2]*10
for _ in range(ii()):
s,v=input().split()
v = int(v)
if s == b"|":
for i in range(10):
if v&(2**i):
arr[i]= 1
elif s == b"^":
for i in range(10):
if v&(2**i):
arr[i]^=1
elif s == b"|":
for i in range(10):
if not (v&(2**i)):
arr[i]=0
else:
print(s)
print(3)
x=o=a= 0
for i in range(10):
if arr[i]==3: x += 2**i
elif arr[i]==0: a+=2**i
elif arr[i]==1:o+=2**i
print('|',o)
print('^',x)
print('&',2**10 - a - 1)
``` | instruction | 0 | 93,211 | 20 | 186,422 |
No | output | 1 | 93,211 | 20 | 186,423 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well.
In the language, there are only three commands: apply a bitwise operation AND, OR or XOR with a given constant to the current integer. A program can contain an arbitrary sequence of these operations with arbitrary constants from 0 to 1023. When the program is run, all operations are applied (in the given order) to the argument and in the end the result integer is returned.
Petya wrote a program in this language, but it turned out to be too long. Write a program in CALPAS that does the same thing as the Petya's program, and consists of no more than 5 lines. Your program should return the same integer as Petya's program for all arguments from 0 to 1023.
Input
The first line contains an integer n (1 ≤ n ≤ 5·105) — the number of lines.
Next n lines contain commands. A command consists of a character that represents the operation ("&", "|" or "^" for AND, OR or XOR respectively), and the constant xi 0 ≤ xi ≤ 1023.
Output
Output an integer k (0 ≤ k ≤ 5) — the length of your program.
Next k lines must contain commands in the same format as in the input.
Examples
Input
3
| 3
^ 2
| 1
Output
2
| 3
^ 2
Input
3
& 1
& 3
& 5
Output
1
& 1
Input
3
^ 1
^ 2
^ 3
Output
0
Note
You can read about bitwise operations in <https://en.wikipedia.org/wiki/Bitwise_operation>.
Second sample:
Let x be an input of the Petya's program. It's output is ((x&1)&3)&5 = x&(1&3&5) = x&1. So these two programs always give the same outputs.
Submitted Solution:
```
n = int( input() )
first = True
A1, A2 = 0, 1023
O1, O2 = 0, 1023
X1, X2 = 0, 1023
for i in range( n ):
s, d = input().split()
d = int( d )
if s == '|':
O1 |= d
elif s == '&':
if first == True:
A1 = d
first = False
else:
A1 &= d
A2 &= d
elif s == '^':
X1 ^= d
X2 ^= d
#print( s, d )
ans = []
O = O1 & O2
A = A1 & A2
X = X1 & (1023^X2)
if O:
ans.append( ('|', O) )
if X:
ans.append( ('^', X) )
if A:
ans.append( ('&', A) )
#print( A, O, X )
print( len(ans) )
for i in range( len(ans) ):
print( ans[i][0] + " " + str(ans[i][1]) )
``` | instruction | 0 | 93,212 | 20 | 186,424 |
No | output | 1 | 93,212 | 20 | 186,425 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a string S consisting of digits `1`, `2`, ..., `9`. Lunlun, the Dachshund, will take out three consecutive digits from S, treat them as a single integer X and bring it to her master. (She cannot rearrange the digits.)
The master's favorite number is 753. The closer to this number, the better. What is the minimum possible (absolute) difference between X and 753?
Constraints
* S is a string of length between 4 and 10 (inclusive).
* Each character in S is `1`, `2`, ..., or `9`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum possible difference between X and 753.
Examples
Input
1234567876
Output
34
Input
35753
Output
0
Input
1111111111
Output
642
Submitted Solution:
```
s=input()
import math
xlist=[math.abs(int(s[i:i+2])-753) for i in range(0,len(s)-3)]
print(min(xlist))
``` | instruction | 0 | 93,335 | 20 | 186,670 |
No | output | 1 | 93,335 | 20 | 186,671 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a string S consisting of digits `1`, `2`, ..., `9`. Lunlun, the Dachshund, will take out three consecutive digits from S, treat them as a single integer X and bring it to her master. (She cannot rearrange the digits.)
The master's favorite number is 753. The closer to this number, the better. What is the minimum possible (absolute) difference between X and 753?
Constraints
* S is a string of length between 4 and 10 (inclusive).
* Each character in S is `1`, `2`, ..., or `9`.
Input
Input is given from Standard Input in the following format:
S
Output
Print the minimum possible difference between X and 753.
Examples
Input
1234567876
Output
34
Input
35753
Output
0
Input
1111111111
Output
642
Submitted Solution:
```
S=list(input())
X=753
ans=0
for i in range(0,8,1) :
for j in range(0,8,1) :
if int(S[i]) == j :
demo = int(S[i]+S[i+1]+S[i+2])
if demo >= ans :
ans = demo
print(abs(X-ans))
``` | instruction | 0 | 93,336 | 20 | 186,672 |
No | output | 1 | 93,336 | 20 | 186,673 |
Provide a correct Python 3 solution for this coding contest problem.
Champernown constant is an irrational number represented in decimal by "0." followed by concatenation of all positive integers in the increasing order. The first few digits of this constant are: 0.123456789101112...
Your task is to write a program that outputs the K digits of Chapnernown constant starting at the N-th place for given two natural numbers K and N.
Input
The input has multiple lines. Each line has two positive integers N and K (N ≤ 109, K ≤ 100) separated by a space.
The end of input is indicated by a line with two zeros. This line should not be processed.
Output
For each line, output a line that contains the K digits.
Example
Input
4 5
6 7
0 0
Output
45678
6789101 | instruction | 0 | 94,369 | 20 | 188,738 |
"Correct Solution:
```
#!usr/bin/env python3
from collections import defaultdict
from collections import deque
from heapq import heappush, heappop
import sys
import math
import bisect
import random
def LI(): return list(map(int, sys.stdin.readline().split()))
def I(): return int(sys.stdin.readline())
def LS():return list(map(list, sys.stdin.readline().split()))
def S(): return list(sys.stdin.readline())[:-1]
def IR(n):
l = [None for i in range(n)]
for i in range(n):l[i] = I()
return l
def LIR(n):
l = [None for i in range(n)]
for i in range(n):l[i] = LI()
return l
def SR(n):
l = [None for i in range(n)]
for i in range(n):l[i] = S()
return l
def LSR(n):
l = [None for i in range(n)]
for i in range(n):l[i] = LS()
return l
sys.setrecursionlimit(1000000)
mod = 1000000007
#A
def A():
n = I()
li = list("ixcm")
k = [1,10,100,1000]
d = {"i":1,"x":10,"c":100,"m":1000}
f = ["i","x","c","m"]
for _ in range(n):
a,b = LS()
s = 0
for i in range(len(a)):
if a[i] in li:
a[i] = d[a[i]]
if i > 0 and a[i-1] not in k:
s += a[i-1]*a[i]
else:
s += a[i]
else:
a[i] = int(a[i])
for i in range(len(b)):
if b[i] in li:
b[i] = d[b[i]]
if i > 0 and b[i-1] not in k:
s += b[i-1]*b[i]
else:
s += b[i]
else:
b[i] = int(b[i])
ans = []
while s != 0:
i = int(math.log(s+0.1,10))
m = s//k[i]
s %= k[i]
if m != 1:
ans.append(m)
ans.append(f[i])
for i in ans:
print(i,end="")
print()
return
#B
def B():
d = [(0,1),(0,-1),(1,0),(-1,0),(1,1),(-1,-1)]
while 1:
t,n = LI()
if t == n == 0:
break
f = defaultdict(lambda : 1)
for i in range(n):
x,y = LI()
f[(x,y)] = 0
x,y = LI()
bfs = defaultdict(lambda : 1)
q = deque()
q.append((x,y,0))
bfs[(x,y)] = 0
ans = 1
while q:
x,y,turn = q.popleft()
if turn < t:
for dx,dy in d:
x2 = x+dx
y2 = y+dy
if bfs[(x2,y2)]:
if f[(x2,y2)]:
ans += 1
bfs[(x2,y2)] = 0
q.append((x2,y2,turn+1))
print(ans)
return
#C
def C():
return
#D
def D():
def f(n):
if d[n] != None:
return d[n]
else:
i = int(math.log(n+0.1,10))
d[n] = d[10**i]
m = n-10**i
d[n] += (i+1)*m
return d[n]
lis = [1]
for i in range(10):
lis.append(lis[-1]+(i+1)*9*10**i)
d = defaultdict(lambda : None)
for i in range(11):
d[10**i] = lis[i]
while 1:
n,k = LI()
if n == k == 0:
break
l = 0
r = 1000000000
while r-l > 1:
m = (r+l)//2
if n < f(m):
r = m
else:
l = m
s = str(l)[n-f(l):]
n = l
while len(s) <= k:
k -= len(s)
print(s,end="")
n += 1
s = str(n)
print(s[:k])
return
#E
def E():
return
#F
def F():
return
#G
def G():
return
#H
def H():
return
#I
def I_():
return
#J
def J():
return
#Solve
if __name__ == "__main__":
D()
``` | output | 1 | 94,369 | 20 | 188,739 |
Provide a correct Python 3 solution for this coding contest problem.
Champernown constant is an irrational number represented in decimal by "0." followed by concatenation of all positive integers in the increasing order. The first few digits of this constant are: 0.123456789101112...
Your task is to write a program that outputs the K digits of Chapnernown constant starting at the N-th place for given two natural numbers K and N.
Input
The input has multiple lines. Each line has two positive integers N and K (N ≤ 109, K ≤ 100) separated by a space.
The end of input is indicated by a line with two zeros. This line should not be processed.
Output
For each line, output a line that contains the K digits.
Example
Input
4 5
6 7
0 0
Output
45678
6789101 | instruction | 0 | 94,370 | 20 | 188,740 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**13
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
def f(n,m):
n -= 1
i = 1
l = 1
for k in range(1,10):
if n > 10**(k-1) * 9 * k:
n -= 10**(k-1) * 9 * k
i = 10 ** k
l = k + 1
else:
break
i += n // l
n %= l
r = ''
for j in range(i,i+101):
r += str(j)
return r[n:n+m]
while True:
n,m = LI()
if n == 0 and m == 0:
break
rr.append(f(n,m))
return '\n'.join(map(str,rr))
print(main())
``` | output | 1 | 94,370 | 20 | 188,741 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Champernown constant is an irrational number represented in decimal by "0." followed by concatenation of all positive integers in the increasing order. The first few digits of this constant are: 0.123456789101112...
Your task is to write a program that outputs the K digits of Chapnernown constant starting at the N-th place for given two natural numbers K and N.
Input
The input has multiple lines. Each line has two positive integers N and K (N ≤ 109, K ≤ 100) separated by a space.
The end of input is indicated by a line with two zeros. This line should not be processed.
Output
For each line, output a line that contains the K digits.
Example
Input
4 5
6 7
0 0
Output
45678
6789101
Submitted Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**13
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
def f(n,m):
n -= 1
i = 1
l = 1
for k in range(1,10):
if n > 10**(k-1) * 9 * k:
n -= 10**(k-1) * 9 * k
i = 10 ** k
l = k
else:
break
i += n // l
n %= l
r = ''
for j in range(i,i+101):
r += str(j)
return r[n:n+m]
while True:
n,m = LI()
if n == 0 and m == 0:
break
rr.append(f(n,m))
return '\n'.join(map(str,rr))
print(main())
``` | instruction | 0 | 94,371 | 20 | 188,742 |
No | output | 1 | 94,371 | 20 | 188,743 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let a and b be some non-negative integers. Let's define strange addition of a and b as following:
1. write down the numbers one under another and align them by their least significant digit;
2. add them up digit by digit and concatenate the respective sums together.
Assume that both numbers have an infinite number of leading zeros.
For example, let's take a look at a strange addition of numbers 3248 and 908:
<image>
You are given a string c, consisting of n digits from 0 to 9. You are also given m updates of form:
* x~d — replace the digit at the x-th position of c with a digit d.
Note that string c might have leading zeros at any point of time.
After each update print the number of pairs (a, b) such that both a and b are non-negative integers and the result of a strange addition of a and b is equal to c.
Note that the numbers of pairs can be quite large, so print them modulo 998244353.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 5 ⋅ 10^5) — the length of the number c and the number of updates.
The second line contains a string c, consisting of exactly n digits from 0 to 9.
Each of the next m lines contains two integers x and d (1 ≤ x ≤ n, 0 ≤ d ≤ 9) — the descriptions of updates.
Output
Print m integers — the i-th value should be equal to the number of pairs (a, b) such that both a and b are non-negative integers and the result of a strange addition of a and b is equal to c after i updates are applied.
Note that the numbers of pairs can be quite large, so print them modulo 998244353.
Example
Input
2 3
14
2 4
2 1
1 0
Output
15
12
2
Note
After the first update c is equal to 14. The pairs that sum up to 14 are: (0, 14), (1, 13), (2, 12), (3, 11), (4, 10), (5, 9), (6, 8), (7, 7), (8, 6), (9, 5), (10, 4), (11, 3), (12, 2), (13, 1), (14, 0).
After the second update c is equal to 11.
After the third update c is equal to 01. | instruction | 0 | 94,570 | 20 | 189,140 |
Tags: data structures, dp, matrices
Correct Solution:
```
from sys import stdin
import sys
class LazySegTree:
def __init__(self,N,first):
self.LV = (N-1).bit_length()
self.NO = 2**self.LV
self.First = first
self.data = [first] * (2*self.NO)
self.lazy = [None] * (2*self.NO)
def calc(self,l,r):
return min(l,r)
def gindex(self,l,r):
L = l + self.NO
R = r + self.NO
lm = (L // (L & -L)) >> 1
rm = (R // (R & -R)) >> 1
while L < R:
if R <= rm:
yield R
if L <= lm:
yield L
L >>= 1; R >>= 1
while L:
yield L
L >>= 1
def propagates(self,*ids):
for i in reversed(ids):
v = self.lazy[i-1]
if v is None:
continue
self.lazy[2*i-1] = self.data[2*i-1] = self.lazy[2*i] = self.data[2*i] = v
self.lazy[i-1] = None
def update(self , l, r, x):
*ids, = self.gindex(l, r)
self.propagates(*ids)
L = self.NO + l; R = self.NO + r
while L < R:
if R & 1:
R -= 1
self.lazy[R-1] = self.data[R-1] = x
if L & 1:
self.lazy[L-1] = self.data[L-1] = x
L += 1
L >>= 1; R >>= 1
for i in ids:
self.data[i-1] = self.calc(self.data[2*i-1], self.data[2*i])
def query(self , l, r):
self.propagates(*self.gindex(l, r))
L = self.NO + l; R = self.NO + r
s = self.First
while L < R:
if R & 1:
R -= 1
s = self.calc(s, self.data[R-1])
if L & 1:
s = self.calc(s, self.data[L-1])
L += 1
L >>= 1; R >>= 1
return s
def inverse(a,mod):
return pow(a,mod-2,mod)
def calc(tmpR):
ret = dp[tmpR-Lside[tmpR]] * dnum[c[tmpR]]
if tmpR - Lside[tmpR] > 0:
ret += dp[tmpR-Lside[tmpR]-1] * dnum[c[tmpR] + 10]
return ret
mod = 998244353
n,m = map(int,stdin.readline().split())
c = list(stdin.readline()[:-1])
c = list(map(int,c))
c = [0] + c + [9]
#divide
dnum = [0] * 20
for i in range(10):
for j in range(10):
dnum[i+j] += 1
#dp
dp = [0] * (n+10)
dp[0] = 1
for i in range(n+8):
dp[i+1] += dp[i] * 2
dp[i+1] %= mod
dp[i+2] += dp[i] * 8
dp[i+2] %= mod
#construct
ST = LazySegTree(len(c),float("inf"))
Lside = [None] * len(c)
tmpR = None
ans = 1
for i in range(len(c)-1,-1,-1):
if c[i] != 1:
if tmpR != None:
ST.update(i+1,tmpR+1,tmpR)
Lside[tmpR] = i+1
#now = dp[tmpR-i-1] * dnum[c[tmpR]]
#if tmpR-i-1 > 0:
# now += dp[tmpR-i-2] * dnum[c[tmpR] + 10]
ans *= calc(tmpR)
ans %= mod
tmpR = i
print (ans * inverse(dnum[9] , mod) % mod , file=sys.stderr)
anss = []
vvv = inverse(dnum[9] , mod)
for loop in range(m):
x,d = map(int,stdin.readline().split())
if d == 1:
if c[x] != 1:
now = 1
newR = ST.query(x+1,x+2)
now *= inverse(calc(x) * calc(newR),mod)
ST.update(Lside[x],x+1,newR)
c[x] = d
Lside[newR] = Lside[x]
now *= calc(newR)
ans *= now
else:
if c[x] != 1:
now = 1
now *= inverse(calc(x) , mod)
c[x] = d
now *= calc(x)
ans *= now
else:
now = 1
oldR = ST.query(x,x+1)
now *= inverse(calc(oldR) , mod)
c[x] = d
Lside[x] = Lside[oldR]
Lside[oldR] = x+1
ST.update(Lside[x],x+1,x)
now *= calc(oldR) * calc(x)
ans *= now
ans %= mod
#print (ans * inverse(dnum[9] , mod) % mod )
anss.append(ans * vvv % mod)
print ("\n".join(map(str,anss)))
``` | output | 1 | 94,570 | 20 | 189,141 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let a and b be some non-negative integers. Let's define strange addition of a and b as following:
1. write down the numbers one under another and align them by their least significant digit;
2. add them up digit by digit and concatenate the respective sums together.
Assume that both numbers have an infinite number of leading zeros.
For example, let's take a look at a strange addition of numbers 3248 and 908:
<image>
You are given a string c, consisting of n digits from 0 to 9. You are also given m updates of form:
* x~d — replace the digit at the x-th position of c with a digit d.
Note that string c might have leading zeros at any point of time.
After each update print the number of pairs (a, b) such that both a and b are non-negative integers and the result of a strange addition of a and b is equal to c.
Note that the numbers of pairs can be quite large, so print them modulo 998244353.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 5 ⋅ 10^5) — the length of the number c and the number of updates.
The second line contains a string c, consisting of exactly n digits from 0 to 9.
Each of the next m lines contains two integers x and d (1 ≤ x ≤ n, 0 ≤ d ≤ 9) — the descriptions of updates.
Output
Print m integers — the i-th value should be equal to the number of pairs (a, b) such that both a and b are non-negative integers and the result of a strange addition of a and b is equal to c after i updates are applied.
Note that the numbers of pairs can be quite large, so print them modulo 998244353.
Example
Input
2 3
14
2 4
2 1
1 0
Output
15
12
2
Note
After the first update c is equal to 14. The pairs that sum up to 14 are: (0, 14), (1, 13), (2, 12), (3, 11), (4, 10), (5, 9), (6, 8), (7, 7), (8, 6), (9, 5), (10, 4), (11, 3), (12, 2), (13, 1), (14, 0).
After the second update c is equal to 11.
After the third update c is equal to 01.
Submitted Solution:
```
no_d,test=map(int,input().split())
n=input()
n=list(n)
for t in range(test):
p,d=map(int,input().split())
n[p-1]=d
number=0
for i in n:
number=number*10+int(i)
else:
print((number%998244353)+1)
``` | instruction | 0 | 94,571 | 20 | 189,142 |
No | output | 1 | 94,571 | 20 | 189,143 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let a and b be some non-negative integers. Let's define strange addition of a and b as following:
1. write down the numbers one under another and align them by their least significant digit;
2. add them up digit by digit and concatenate the respective sums together.
Assume that both numbers have an infinite number of leading zeros.
For example, let's take a look at a strange addition of numbers 3248 and 908:
<image>
You are given a string c, consisting of n digits from 0 to 9. You are also given m updates of form:
* x~d — replace the digit at the x-th position of c with a digit d.
Note that string c might have leading zeros at any point of time.
After each update print the number of pairs (a, b) such that both a and b are non-negative integers and the result of a strange addition of a and b is equal to c.
Note that the numbers of pairs can be quite large, so print them modulo 998244353.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 5 ⋅ 10^5) — the length of the number c and the number of updates.
The second line contains a string c, consisting of exactly n digits from 0 to 9.
Each of the next m lines contains two integers x and d (1 ≤ x ≤ n, 0 ≤ d ≤ 9) — the descriptions of updates.
Output
Print m integers — the i-th value should be equal to the number of pairs (a, b) such that both a and b are non-negative integers and the result of a strange addition of a and b is equal to c after i updates are applied.
Note that the numbers of pairs can be quite large, so print them modulo 998244353.
Example
Input
2 3
14
2 4
2 1
1 0
Output
15
12
2
Note
After the first update c is equal to 14. The pairs that sum up to 14 are: (0, 14), (1, 13), (2, 12), (3, 11), (4, 10), (5, 9), (6, 8), (7, 7), (8, 6), (9, 5), (10, 4), (11, 3), (12, 2), (13, 1), (14, 0).
After the second update c is equal to 11.
After the third update c is equal to 01.
Submitted Solution:
```
from bisect import bisect_left as bl
from bisect import bisect_right as br
from heapq import heappush,heappop,heapify
import math
from collections import *
from functools import reduce,cmp_to_key
import sys
input = sys.stdin.readline
M = mod = 998244353
def factors(n):return sorted(set(reduce(list.__add__, ([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0))))
def inv_mod(n):return pow(n, mod - 2, mod)
def li():return [int(i) for i in input().rstrip('\n').split()]
def st():return input().rstrip('\n')
def val():return int(input().rstrip('\n'))
def li2():return [i for i in input().rstrip('\n')]
def li3():return [int(i) for i in input().rstrip('\n')]
n, m = li()
c = li3()
i = mi = n - 1
ans = 0
for i in range(n):
ans = (ans + c[i] * pow(10,n - i - 1,mod))%mod
for i in range(m):
x, d = li()
x -= 1
temp = c[x]
c[x] = d
ans = (mod + ans - temp * pow(10,n - 1 - x,mod))%mod
ans = (ans + mod + d * pow(10,n - 1 - x,mod))%mod
print((ans + 1)%mod)
``` | instruction | 0 | 94,572 | 20 | 189,144 |
No | output | 1 | 94,572 | 20 | 189,145 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let a and b be some non-negative integers. Let's define strange addition of a and b as following:
1. write down the numbers one under another and align them by their least significant digit;
2. add them up digit by digit and concatenate the respective sums together.
Assume that both numbers have an infinite number of leading zeros.
For example, let's take a look at a strange addition of numbers 3248 and 908:
<image>
You are given a string c, consisting of n digits from 0 to 9. You are also given m updates of form:
* x~d — replace the digit at the x-th position of c with a digit d.
Note that string c might have leading zeros at any point of time.
After each update print the number of pairs (a, b) such that both a and b are non-negative integers and the result of a strange addition of a and b is equal to c.
Note that the numbers of pairs can be quite large, so print them modulo 998244353.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 5 ⋅ 10^5) — the length of the number c and the number of updates.
The second line contains a string c, consisting of exactly n digits from 0 to 9.
Each of the next m lines contains two integers x and d (1 ≤ x ≤ n, 0 ≤ d ≤ 9) — the descriptions of updates.
Output
Print m integers — the i-th value should be equal to the number of pairs (a, b) such that both a and b are non-negative integers and the result of a strange addition of a and b is equal to c after i updates are applied.
Note that the numbers of pairs can be quite large, so print them modulo 998244353.
Example
Input
2 3
14
2 4
2 1
1 0
Output
15
12
2
Note
After the first update c is equal to 14. The pairs that sum up to 14 are: (0, 14), (1, 13), (2, 12), (3, 11), (4, 10), (5, 9), (6, 8), (7, 7), (8, 6), (9, 5), (10, 4), (11, 3), (12, 2), (13, 1), (14, 0).
After the second update c is equal to 11.
After the third update c is equal to 01.
Submitted Solution:
```
def comb(t2, t1):
a, b, c, d = t1
aa, bb, cc, dd = t2
return (a * aa + b * cc, a * bb + b * dd, c*aa + d * cc, c * bb + d * dd)
class SegmentTree:
def __init__(self, data, default=(1,0,0,1), func=comb):
"""initialize the segment tree with data"""
self._default = default
self._func = func
self._len = len(data)
self._size = _size = 1 << (self._len - 1).bit_length()
self.data = [default] * (2 * _size)
self.data[_size:_size + self._len] = data
for i in reversed(range(_size)):
self.data[i] = func(self.data[i + i], self.data[i + i + 1])
def __delitem__(self, idx):
self[idx] = self._default
def __getitem__(self, idx):
return self.data[idx + self._size]
def __setitem__(self, idx, value):
idx += self._size
self.data[idx] = value
idx >>= 1
while idx:
self.data[idx] = self._func(self.data[2 * idx], self.data[2 * idx + 1])
idx >>= 1
def __len__(self):
return self._len
def query(self, start, stop):
"""func of data[start, stop)"""
start += self._size
stop += self._size
res_left = res_right = self._default
while start < stop:
if start & 1:
res_left = self._func(res_left, self.data[start])
start += 1
if stop & 1:
stop -= 1
res_right = self._func(self.data[stop], res_right)
start >>= 1
stop >>= 1
return self._func(res_left, res_right)
def __repr__(self):
return "SegmentTree({0})".format(self.data)
import sys
input = sys.stdin.readline
base = [0] * 10
base[0] = (1, 9, 0, 0)
base[1] = (2, 8, 1, 0)
base[2] = (3, 7, 0, 0)
base[3] = (4, 6, 0, 0)
base[4] = (5, 5, 0, 0)
base[5] = (6, 4, 0, 0)
base[6] = (7, 3, 0, 0)
base[7] = (8, 2, 0, 0)
base[8] = (9, 1, 0, 0)
base[9] = (10,0, 0, 0)
n, m = map(int, input().split())
c = list(map(int, list(input().strip())))
based = [base[v] for v in c]
seg = SegmentTree(based)
out = [-1] * m
for q in range(m):
x, d = map(int, input().split())
seg[x-1] = base[d]
out[q] = seg.query(0, n)[0]
print('\n'.join(map(str,out)))
``` | instruction | 0 | 94,573 | 20 | 189,146 |
No | output | 1 | 94,573 | 20 | 189,147 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let a and b be some non-negative integers. Let's define strange addition of a and b as following:
1. write down the numbers one under another and align them by their least significant digit;
2. add them up digit by digit and concatenate the respective sums together.
Assume that both numbers have an infinite number of leading zeros.
For example, let's take a look at a strange addition of numbers 3248 and 908:
<image>
You are given a string c, consisting of n digits from 0 to 9. You are also given m updates of form:
* x~d — replace the digit at the x-th position of c with a digit d.
Note that string c might have leading zeros at any point of time.
After each update print the number of pairs (a, b) such that both a and b are non-negative integers and the result of a strange addition of a and b is equal to c.
Note that the numbers of pairs can be quite large, so print them modulo 998244353.
Input
The first line contains two integers n and m (1 ≤ n, m ≤ 5 ⋅ 10^5) — the length of the number c and the number of updates.
The second line contains a string c, consisting of exactly n digits from 0 to 9.
Each of the next m lines contains two integers x and d (1 ≤ x ≤ n, 0 ≤ d ≤ 9) — the descriptions of updates.
Output
Print m integers — the i-th value should be equal to the number of pairs (a, b) such that both a and b are non-negative integers and the result of a strange addition of a and b is equal to c after i updates are applied.
Note that the numbers of pairs can be quite large, so print them modulo 998244353.
Example
Input
2 3
14
2 4
2 1
1 0
Output
15
12
2
Note
After the first update c is equal to 14. The pairs that sum up to 14 are: (0, 14), (1, 13), (2, 12), (3, 11), (4, 10), (5, 9), (6, 8), (7, 7), (8, 6), (9, 5), (10, 4), (11, 3), (12, 2), (13, 1), (14, 0).
After the second update c is equal to 11.
After the third update c is equal to 01.
Submitted Solution:
```
n, m = map(int, input().split())
c = input()
for i in range(m):
x, d = map(int, input().split())
c = c[:x-1] + str(d) + c[x:]
result = int(c)
print((result + 1)%998244353)
``` | instruction | 0 | 94,574 | 20 | 189,148 |
No | output | 1 | 94,574 | 20 | 189,149 |
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