message stringlengths 2 59.7k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 37 108k | cluster float64 20 20 | __index_level_0__ int64 74 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
Expression Mining
Consider an arithmetic expression built by combining single-digit positive integers with addition symbols `+`, multiplication symbols `*`, and parentheses `(` `)`, defined by the following grammar rules with the start symbol `E`.
E ::= T | E '+' T
T ::= F | T '*' F
F ::= '1' | '2' | '3' | '4' | '5' | '6' | '7' | '8' | '9' | '(' E ')'
When such an arithmetic expression is viewed as a string, its substring, that is, a contiguous sequence of characters within the string, may again form an arithmetic expression. Given an integer n and a string s representing an arithmetic expression, let us count the number of its substrings that can be read as arithmetic expressions with values computed equal to n.
Input
The input consists of multiple datasets, each in the following format.
> n
> s
>
A dataset consists of two lines. In the first line, the target value n is given. n is an integer satisfying 1 ≤ n ≤ 109. The string s given in the second line is an arithmetic expression conforming to the grammar defined above. The length of s does not exceed 2×106. The nesting depth of the parentheses in the string is at most 1000.
The end of the input is indicated by a line containing a single zero. The sum of the lengths of s in all the datasets does not exceed 5×106.
Output
For each dataset, output in one line the number of substrings of s that conform to the above grammar and have the value n. The same sequence of characters appearing at different positions should be counted separately.
Sample Input
3
(1+2)*3+3
2
1*1*1+1*1*1
587
1*(2*3*4)+5+((6+7*8))*(9)
0
Output for the Sample Input
4
9
2
Example
Input
3
(1+2)*3+3
2
1*1*1+1*1*1
587
1*(2*3*4)+5+((6+7*8))*(9)
0
Output
4
9
2 | instruction | 0 | 95,233 | 20 | 190,466 |
"Correct Solution:
```
import sys
readline = sys.stdin.readline
write = sys.stdout.write
sys.setrecursionlimit(10**5)
def solve():
N = int(readline())
if N == 0:
return False
S = readline().strip() + "$"
L = len(S)
pt = [0]*L
st = []
for i in range(L):
if S[i] == '(':
st.append(i)
elif S[i] == ')':
k = st.pop()
pt[i] = k
pt[k] = i
ans = 0
def parse(cur):
nonlocal ans
ps = []
ls = []
su = 0
while 1:
ms = []
while 1:
if S[cur] == '(':
v = parse(cur+1)
cur = pt[cur]+1
else:
v = int(S[cur])
cur += 1
ms.append(v)
if S[cur] != '*':
break
cur += 1
l = len(ms)
ms_a = [1]*(l+1)
for i in range(l):
ms_a[i+1] = ms_a[i] * ms[i]
ps.append(ms_a)
ls.append(l)
su += ms_a[-1]
if S[cur] != '+':
break
cur += 1
p1 = c1 = 0; s1 = 0
q1 = d1 = 0; t1 = 0; u1 = 0
q2 = d2 = 0; t2 = 0; u2 = 0
s = 0
while p1 < len(ls):
k1 = ps[p1][c1+1]
if s1 + k1 >= N:
break
if c1 + 1 < ls[p1]:
c1 += 1
else:
s1 += ps[p1][-1]
p1 += 1; c1 = 0
while p1 < len(ls):
k1 = ps[p1][c1+1]
while (q1, d1) <= (p1, c1):
k2 = ps[q1][d1]
if p1 == q1:
v = (s1 - t1) + (k1 // k2)
else:
kk = ps[q1][-1]
v = (s1 - t1) + (k1 + kk // k2 - kk)
if v >= N:
if d1 + 1 < ls[q1]:
d1 += 1
else:
t1 += ps[q1][-1]
q1 += 1; d1 = 0
u1 += 1
else:
break
while (q2, d2) <= (p1, c1):
k3 = ps[q2][d2]
if p1 == q2:
v = (s1 - t2) + (k1 // k3)
else:
kk = ps[q2][-1]
v = (s1 - t2) + (k1 + kk // k3 - kk)
if v > N:
if d2 + 1 < ls[q2]:
d2 += 1
else:
t2 += ps[q2][-1]
q2 += 1; d2 = 0
u2 += 1
else:
break
ans += u1 - u2
if c1 + 1 < ls[p1]:
c1 += 1
else:
s1 += ps[p1][-1]
p1 += 1; c1 = 0
return su
parse(0)
write("%d\n" % ans)
return True
while solve():
...
``` | output | 1 | 95,233 | 20 | 190,467 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099. | instruction | 0 | 95,319 | 20 | 190,638 |
Tags: implementation
Correct Solution:
```
res=0
temp=[]
n=int(input())
def getnumber(n):
return int(str(n)[0])
a=getnumber(n)
def process(n):
global res
res=res+1
n=n+1
if n%10==0:
while True:
if n%10!=0:
break
else:
n=n//10
return n
def process1(n):
global a
if n!=a:
process1(process(n))
if a==n:
print(9)
else:
process1(n)
print(res+1)
``` | output | 1 | 95,319 | 20 | 190,639 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099. | instruction | 0 | 95,320 | 20 | 190,640 |
Tags: implementation
Correct Solution:
```
n = input()
n = int(n)
L=[n]
temp = n
while 1:
temp = temp +1
while temp%10==0:
temp=int(temp/10)
if temp in L:
break
else:
L.append(temp)
print(len(L))
``` | output | 1 | 95,320 | 20 | 190,641 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099. | instruction | 0 | 95,321 | 20 | 190,642 |
Tags: implementation
Correct Solution:
```
import math
def na():
n = int(input())
b = [int(x) for x in input().split()]
return n,b
def nab():
n = int(input())
b = [int(x) for x in input().split()]
c = [int(x) for x in input().split()]
return n,b,c
def dv():
n, m = map(int, input().split())
return n,m
def dva():
n, m = map(int, input().split())
a = [int(x) for x in input().split()]
b = [int(x) for x in input().split()]
return n,m,b
def nm():
n = int(input())
b = [int(x) for x in input().split()]
m = int(input())
c = [int(x) for x in input().split()]
return n,b,m,c
def dvs():
n = int(input())
m = int(input())
return n, m
def pr(x):
used = set()
used.add(x)
k = 10 - x % 10
for i in range(x, x + k):
if i % 10 != 0:
used.add(i)
x += k
if x % 10 != 0:
used.add(x)
while x > 1:
knn = 0
while x % 10 == 0:
x //= 10
kn = 10 - x % 10
if x == 1:
for i in range(1, 10):
used.add(i)
used.add(x)
return len(used)
for i in range(x, x + kn):
if i % 10 != 0:
used.add(i)
else:
break
x += kn
k += kn + knn
return len(used)
n = int(input())
print(pr(n))
``` | output | 1 | 95,321 | 20 | 190,643 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099. | instruction | 0 | 95,322 | 20 | 190,644 |
Tags: implementation
Correct Solution:
```
# -*- coding: utf-8 -*-
# @Date : 2019-04-27 08:29:57
# @Author : raj lath (oorja.halt@gmail.com)
# @Link : link
# @Version : 1.0.0
import sys
sys.setrecursionlimit(10**5+1)
inf = int(10 ** 20)
max_val = inf
min_val = -inf
RW = lambda : sys.stdin.readline().strip()
RI = lambda : int(RW())
RMI = lambda : [int(x) for x in sys.stdin.readline().strip().split()]
RWI = lambda : [x for x in sys.stdin.readline().strip().split()]
ins = RI()
reachable = set()
while ins not in reachable:
reachable.add(ins)
ins = int(str(ins + 1).strip("0"))
print(len(reachable))
``` | output | 1 | 95,322 | 20 | 190,645 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099. | instruction | 0 | 95,323 | 20 | 190,646 |
Tags: implementation
Correct Solution:
```
#rOkY
#FuCk
################################## kOpAl #####################################
def ans(a):
a+=1
while(a%10==0):
a//=10
return a
a=set()
n=int(input())
while(not(n in a)):
a.add(n)
n=ans(n)
print(len(a))
``` | output | 1 | 95,323 | 20 | 190,647 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099. | instruction | 0 | 95,324 | 20 | 190,648 |
Tags: implementation
Correct Solution:
```
n=int(input())
L=[]
while(n not in L):
L.append(n)
n+=1
while(n%10==0):
n//=10
print(len(L))
``` | output | 1 | 95,324 | 20 | 190,649 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099. | instruction | 0 | 95,325 | 20 | 190,650 |
Tags: implementation
Correct Solution:
```
def f(x):
x+=1
while x%10==0:
x//=10
return x
base=int(input())
compteur=1
liste=[base]
while f(base) not in liste:
liste.append(f(base))
base=f(base)
compteur+=1
print(compteur)
``` | output | 1 | 95,325 | 20 | 190,651 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099. | instruction | 0 | 95,326 | 20 | 190,652 |
Tags: implementation
Correct Solution:
```
def f(x):
return int(str(x + 1).rstrip('0'))
def main():
x = int(input())
l = set()
while x not in l:
l.add(x)
x = f(x)
print(len(l))
if __name__ == "__main__":
main()
``` | output | 1 | 95,326 | 20 | 190,653 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099.
Submitted Solution:
```
n=int(input())
s=set()
s.add(n)
n+=1
while True:
while n%10==0:
n/=10
# print(n)
n=int(n)
# print(n)
if n not in s:
s.add(n)
else:
break
n+=1
s.add(1)
print(len(s))
``` | instruction | 0 | 95,327 | 20 | 190,654 |
Yes | output | 1 | 95,327 | 20 | 190,655 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099.
Submitted Solution:
```
number=input()
length=len(number)
x=length-1
sum=0
b=int(number[x])
a=int(number[x-1])
x-=2
sum=10-b
will_loop=x>0 or len(number)==3
if len(number)==2:
sum=sum+9
elif len(number)==1:
if int(number)==0:
sum=10
else:
sum=9
while x>0:
b=a
a=int(number[x])
sum=sum+9-b
x-=1
if will_loop:
sum=sum+9+9-a
print(sum)
``` | instruction | 0 | 95,328 | 20 | 190,656 |
Yes | output | 1 | 95,328 | 20 | 190,657 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099.
Submitted Solution:
```
n = int(input())
def f(x):
a = x + 1
while (a % 10 == 0):
a = a / 10
return a
S = {n}
while f(n) not in S:
S = S | {f(n)}
n = f(n)
print(len(S))
``` | instruction | 0 | 95,329 | 20 | 190,658 |
Yes | output | 1 | 95,329 | 20 | 190,659 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099.
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Mon Apr 22 16:05:55 2019
@author: Aman Seth
st=input()
le=len(st)
if 'a' in st:
ins=st.rfind('a')
st1=st[0:ins+2]
re=st[ins+2:le]
ans=st1.replace('a','')
if ans==re:
print(st1)
else:
print(":(")
else:
if all(st[i]!=st[i+1] for i in range(le-1)):
print(st[0:int(le/2)])
if all(i!='a' for i in st):
if all(st[i]==st[i+1] for i in range(le-1)):
print(":(")
n,q=map(int,input().split())
a=list(map(int,input().split()))
le=len(a)
#c=['0']*le
#st=''
for i in range(q):
x,y=input().split()
y=int(y)
if x=='>':
for j in range(le):
if a[j]>y:
a[j]=-a[j]
#c[j]=str(a[j])
#st=st+str(a[j])+' '
if x=='<':
for j in range(le):
if a[j]<y:
a[j]=a[j]
#c[j]=str(a[j])
#st=st+str(a[j])+' '
#for j in range(le):
# a[j]=str(a[j])
print(' '.join(map(str,a)))
#print(st)
n,q=map(int,input().split())
a=list(map(int,input().split()))
le=len(a)
for i in range(q):
x,y=input().split()
y=int(y)
if x=='>':
for j in range(le):
if a[j]>y:
a[j]=-a[j]
if x=='<':
for j in range(le):
if a[j]<y:
a[j]=-a[j]
#for j in range(len(a)):
# a[j]=str(a[j])
print(' '.join(map(str,a)))
m,x,y=map(int,input().split())
ans=[]
for i in range(0,m+1):
a=i
count=0
if a+x<=a and a+x>=0 and (a+x and a-y not in ans):
count+=1
ans.append(count)
if a-y<=m and a-y>=0:
count+=1
ans.append(count)
print(ans)
def fun(a,b,n):
#s=a+b
ans=[a,b]
i=0
n=int(n)
s=''
while(len(s)<n):
s=a[i]+a[i+1]
ans.append(s)
print(ans)
for i in range(int(input())):
a,b,n=map(str,input().split())
fun(a,b,n)
"""
n=input()
print(9+sum(9-int(d)for d in n[1:])+(len(n)>1))
``` | instruction | 0 | 95,330 | 20 | 190,660 |
Yes | output | 1 | 95,330 | 20 | 190,661 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099.
Submitted Solution:
```
n=int(input())
c=0
if n//10==0:
print(10-n)
else:
while True:
x=10-n%10-1
c+=(x+1)
n+=(x+1)
while n%10==0:
n//=10
if n//10==0:
break
print(c+9)
``` | instruction | 0 | 95,331 | 20 | 190,662 |
No | output | 1 | 95,331 | 20 | 190,663 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099.
Submitted Solution:
```
x = input()
arr = set()
arr.add(x)
x = str(int(x) + 1)
while str(int(x) + 1) not in arr:
if int(x) % 10 != 0:
arr.add(x)
while int(x) % 10 != 0:
x = str(int(x) + 1)
if int(x) % 10 != 0:
arr.add(x)
while x[-1] == "0":
x = x[:-1]
if int(x) % 10 != 0:
arr.add(x)
print(arr)
print(len(arr))
``` | instruction | 0 | 95,332 | 20 | 190,664 |
No | output | 1 | 95,332 | 20 | 190,665 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099.
Submitted Solution:
```
#!/usr/bin/python3
import sys
def reach(x):
total = 1
while True:
if x < 10:
total += 10 - x
return total
x += 1
while x % 10 == 0:
x /= 10
total += 1
if __name__ == '__main__':
input = sys.stdin.readline().strip()
#arr = []
total = reach(int(input))
print(total)
``` | instruction | 0 | 95,333 | 20 | 190,666 |
No | output | 1 | 95,333 | 20 | 190,667 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's denote a function f(x) in such a way: we add 1 to x, then, while there is at least one trailing zero in the resulting number, we remove that zero. For example,
* f(599) = 6: 599 + 1 = 600 → 60 → 6;
* f(7) = 8: 7 + 1 = 8;
* f(9) = 1: 9 + 1 = 10 → 1;
* f(10099) = 101: 10099 + 1 = 10100 → 1010 → 101.
We say that some number y is reachable from x if we can apply function f to x some (possibly zero) times so that we get y as a result. For example, 102 is reachable from 10098 because f(f(f(10098))) = f(f(10099)) = f(101) = 102; and any number is reachable from itself.
You are given a number n; your task is to count how many different numbers are reachable from n.
Input
The first line contains one integer n (1 ≤ n ≤ 10^9).
Output
Print one integer: the number of different numbers that are reachable from n.
Examples
Input
1098
Output
20
Input
10
Output
19
Note
The numbers that are reachable from 1098 are:
1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 17, 18, 19, 1098, 1099.
Submitted Solution:
```
x=int(input())
l1=[]
y=x+1
l1.append(y)
while(y!=-1):
if(y%10==0):
while(y%10==0):
y=y/10
else:
y=y+1
if (y % 10 == 0):
while (y % 10 == 0):
y = y / 10
if(y in l1):
break
else:
l1.append(y)
print(len(l1)+1)
``` | instruction | 0 | 95,334 | 20 | 190,668 |
No | output | 1 | 95,334 | 20 | 190,669 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After Misha's birthday he had many large numbers left, scattered across the room. Now it's time to clean up and Misha needs to put them in a basket. He ordered this task to his pet robot that agreed to complete the task at certain conditions. Before the robot puts a number x to the basket, Misha should answer the question: is it possible to choose one or multiple numbers that already are in the basket, such that their XOR sum equals x?
If the answer is positive, you also need to give the indexes of these numbers. If there are multiple options of choosing numbers, you are allowed to choose any correct option. After Misha's answer the robot puts the number to the basket.
Initially the basket is empty. Each integer you put in the basket takes some number. The first integer you put into the basket take number 0, the second integer takes number 1 and so on.
Misha needs to clean up the place as soon as possible but unfortunately, he isn't that good at mathematics. He asks you to help him.
Input
The first line contains number m (1 ≤ m ≤ 2000), showing how many numbers are scattered around the room.
The next m lines contain the numbers in the order in which the robot puts them in the basket. Each number is a positive integer strictly less than 10600 that doesn't contain leading zeroes.
Output
For each number either print a 0 on the corresponding line, if the number cannot be represented as a XOR sum of numbers that are in the basket, or print integer k showing how many numbers are in the representation and the indexes of these numbers. Separate the numbers by spaces. Each number can occur in the representation at most once.
Examples
Input
7
7
6
5
4
3
2
1
Output
0
0
0
3 0 1 2
2 1 2
2 0 2
2 0 1
Input
2
5
5
Output
0
1 0
Note
The XOR sum of numbers is the result of bitwise sum of numbers modulo 2. | instruction | 0 | 95,658 | 20 | 191,316 |
Tags: bitmasks
Correct Solution:
```
m = int(input())
values = []
idx = []
for i in range(m):
x = int(input())
ans = 0
for xx,ii in zip(values,idx):
if (xx^x) < x:
x^=xx
ans^=ii
if x == 0:
anss = []
for j in range(i):
if (ans&1)==1:
anss.append(j)
ans>>=1
print(len(anss),*anss)
else:
print(0)
values.append(x)
idx.append(ans^(2**i))
``` | output | 1 | 95,658 | 20 | 191,317 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After Misha's birthday he had many large numbers left, scattered across the room. Now it's time to clean up and Misha needs to put them in a basket. He ordered this task to his pet robot that agreed to complete the task at certain conditions. Before the robot puts a number x to the basket, Misha should answer the question: is it possible to choose one or multiple numbers that already are in the basket, such that their XOR sum equals x?
If the answer is positive, you also need to give the indexes of these numbers. If there are multiple options of choosing numbers, you are allowed to choose any correct option. After Misha's answer the robot puts the number to the basket.
Initially the basket is empty. Each integer you put in the basket takes some number. The first integer you put into the basket take number 0, the second integer takes number 1 and so on.
Misha needs to clean up the place as soon as possible but unfortunately, he isn't that good at mathematics. He asks you to help him.
Input
The first line contains number m (1 ≤ m ≤ 2000), showing how many numbers are scattered around the room.
The next m lines contain the numbers in the order in which the robot puts them in the basket. Each number is a positive integer strictly less than 10600 that doesn't contain leading zeroes.
Output
For each number either print a 0 on the corresponding line, if the number cannot be represented as a XOR sum of numbers that are in the basket, or print integer k showing how many numbers are in the representation and the indexes of these numbers. Separate the numbers by spaces. Each number can occur in the representation at most once.
Examples
Input
7
7
6
5
4
3
2
1
Output
0
0
0
3 0 1 2
2 1 2
2 0 2
2 0 1
Input
2
5
5
Output
0
1 0
Note
The XOR sum of numbers is the result of bitwise sum of numbers modulo 2. | instruction | 0 | 95,659 | 20 | 191,318 |
Tags: bitmasks
Correct Solution:
```
import sys, os
numbs = [int(x) for x in sys.stdin.buffer.read().split()]
n = numbs.pop(0)
base = []
out = []
for i in range(n):
x = numbs[i]
how = 0
for b,rep in base:
if x.bit_length() == b.bit_length():
x ^= b
how ^= rep
if x:
how |= 1 << i
a = 0
b = len(base)
while a < b:
c = a + b >> 1
if base[c][0] > x:
a = c + 1
else:
b = c
base.insert(a, (x, how))
out.append(0)
else:
outind = len(out)
out.append(-1)
y = bin(how).encode('ascii')
ylen = len(y)
for i in range(2,len(y)):
if y[i] == 49:
out.append(ylen - 1 - i)
out[outind] = len(out) - 1 - outind
os.write(1, b'\n'.join(str(x).encode('ascii') for x in out))
``` | output | 1 | 95,659 | 20 | 191,319 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After Misha's birthday he had many large numbers left, scattered across the room. Now it's time to clean up and Misha needs to put them in a basket. He ordered this task to his pet robot that agreed to complete the task at certain conditions. Before the robot puts a number x to the basket, Misha should answer the question: is it possible to choose one or multiple numbers that already are in the basket, such that their XOR sum equals x?
If the answer is positive, you also need to give the indexes of these numbers. If there are multiple options of choosing numbers, you are allowed to choose any correct option. After Misha's answer the robot puts the number to the basket.
Initially the basket is empty. Each integer you put in the basket takes some number. The first integer you put into the basket take number 0, the second integer takes number 1 and so on.
Misha needs to clean up the place as soon as possible but unfortunately, he isn't that good at mathematics. He asks you to help him.
Input
The first line contains number m (1 ≤ m ≤ 2000), showing how many numbers are scattered around the room.
The next m lines contain the numbers in the order in which the robot puts them in the basket. Each number is a positive integer strictly less than 10600 that doesn't contain leading zeroes.
Output
For each number either print a 0 on the corresponding line, if the number cannot be represented as a XOR sum of numbers that are in the basket, or print integer k showing how many numbers are in the representation and the indexes of these numbers. Separate the numbers by spaces. Each number can occur in the representation at most once.
Examples
Input
7
7
6
5
4
3
2
1
Output
0
0
0
3 0 1 2
2 1 2
2 0 2
2 0 1
Input
2
5
5
Output
0
1 0
Note
The XOR sum of numbers is the result of bitwise sum of numbers modulo 2. | instruction | 0 | 95,660 | 20 | 191,320 |
Tags: bitmasks
Correct Solution:
```
m = int(input())
values = []
idx = []
for i in range(m):
x = int(input())
ans = 0
for j,xx in enumerate(values):
if (xx^x) < x:
x^=xx
ans^=idx[j]
if x == 0:
anss = []
for j in range(i):
if (ans&1)!=0:
anss.append(j)
ans>>=1
print(len(anss),*anss)
else:
print(0)
values.append(x)
idx.append(ans^(2**i))
``` | output | 1 | 95,660 | 20 | 191,321 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After Misha's birthday he had many large numbers left, scattered across the room. Now it's time to clean up and Misha needs to put them in a basket. He ordered this task to his pet robot that agreed to complete the task at certain conditions. Before the robot puts a number x to the basket, Misha should answer the question: is it possible to choose one or multiple numbers that already are in the basket, such that their XOR sum equals x?
If the answer is positive, you also need to give the indexes of these numbers. If there are multiple options of choosing numbers, you are allowed to choose any correct option. After Misha's answer the robot puts the number to the basket.
Initially the basket is empty. Each integer you put in the basket takes some number. The first integer you put into the basket take number 0, the second integer takes number 1 and so on.
Misha needs to clean up the place as soon as possible but unfortunately, he isn't that good at mathematics. He asks you to help him.
Input
The first line contains number m (1 ≤ m ≤ 2000), showing how many numbers are scattered around the room.
The next m lines contain the numbers in the order in which the robot puts them in the basket. Each number is a positive integer strictly less than 10600 that doesn't contain leading zeroes.
Output
For each number either print a 0 on the corresponding line, if the number cannot be represented as a XOR sum of numbers that are in the basket, or print integer k showing how many numbers are in the representation and the indexes of these numbers. Separate the numbers by spaces. Each number can occur in the representation at most once.
Examples
Input
7
7
6
5
4
3
2
1
Output
0
0
0
3 0 1 2
2 1 2
2 0 2
2 0 1
Input
2
5
5
Output
0
1 0
Note
The XOR sum of numbers is the result of bitwise sum of numbers modulo 2. | instruction | 0 | 95,661 | 20 | 191,322 |
Tags: bitmasks
Correct Solution:
```
m = int(input())
b = []
k = []
for i in range(m):
x = int(input())
c = 0
for j in range(len(b)):
v = b[j]
d = k[j]
if (x ^ v) < x:
x ^= v
c ^= d
if x != 0:
print(0)
c ^= 2 ** i
b.append(x)
k.append(c)
else:
a = []
for j in range(m):
if c & 1 == 1:
a.append(j)
c >>= 1
print(len(a), end='')
for v in a:
print(' ', v, sep='', end='')
print()
``` | output | 1 | 95,661 | 20 | 191,323 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After Misha's birthday he had many large numbers left, scattered across the room. Now it's time to clean up and Misha needs to put them in a basket. He ordered this task to his pet robot that agreed to complete the task at certain conditions. Before the robot puts a number x to the basket, Misha should answer the question: is it possible to choose one or multiple numbers that already are in the basket, such that their XOR sum equals x?
If the answer is positive, you also need to give the indexes of these numbers. If there are multiple options of choosing numbers, you are allowed to choose any correct option. After Misha's answer the robot puts the number to the basket.
Initially the basket is empty. Each integer you put in the basket takes some number. The first integer you put into the basket take number 0, the second integer takes number 1 and so on.
Misha needs to clean up the place as soon as possible but unfortunately, he isn't that good at mathematics. He asks you to help him.
Input
The first line contains number m (1 ≤ m ≤ 2000), showing how many numbers are scattered around the room.
The next m lines contain the numbers in the order in which the robot puts them in the basket. Each number is a positive integer strictly less than 10600 that doesn't contain leading zeroes.
Output
For each number either print a 0 on the corresponding line, if the number cannot be represented as a XOR sum of numbers that are in the basket, or print integer k showing how many numbers are in the representation and the indexes of these numbers. Separate the numbers by spaces. Each number can occur in the representation at most once.
Examples
Input
7
7
6
5
4
3
2
1
Output
0
0
0
3 0 1 2
2 1 2
2 0 2
2 0 1
Input
2
5
5
Output
0
1 0
Note
The XOR sum of numbers is the result of bitwise sum of numbers modulo 2. | instruction | 0 | 95,662 | 20 | 191,324 |
Tags: bitmasks
Correct Solution:
```
buck = [[0, 0] for i in range(2201)]
m = int(input())
for i in range(m):
a = int(input())
ok = True
br = 0
for j in range(2200, -1, -1):
if a & (1 << j):
if(buck[j][0]):
a ^= buck[j][0]
br ^= buck[j][1]
else:
ok = False
buck[j][0] = a
buck[j][1] = br | (1 << i)
break
if not ok:
print("0")
else:
lst = []
for j in range(2201):
if br & (1 << j):
lst.append(j)
print(len(lst), end = ' ')
for j in lst:
print(j, end = ' ')
print('\n', end='')
``` | output | 1 | 95,662 | 20 | 191,325 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After Misha's birthday he had many large numbers left, scattered across the room. Now it's time to clean up and Misha needs to put them in a basket. He ordered this task to his pet robot that agreed to complete the task at certain conditions. Before the robot puts a number x to the basket, Misha should answer the question: is it possible to choose one or multiple numbers that already are in the basket, such that their XOR sum equals x?
If the answer is positive, you also need to give the indexes of these numbers. If there are multiple options of choosing numbers, you are allowed to choose any correct option. After Misha's answer the robot puts the number to the basket.
Initially the basket is empty. Each integer you put in the basket takes some number. The first integer you put into the basket take number 0, the second integer takes number 1 and so on.
Misha needs to clean up the place as soon as possible but unfortunately, he isn't that good at mathematics. He asks you to help him.
Input
The first line contains number m (1 ≤ m ≤ 2000), showing how many numbers are scattered around the room.
The next m lines contain the numbers in the order in which the robot puts them in the basket. Each number is a positive integer strictly less than 10600 that doesn't contain leading zeroes.
Output
For each number either print a 0 on the corresponding line, if the number cannot be represented as a XOR sum of numbers that are in the basket, or print integer k showing how many numbers are in the representation and the indexes of these numbers. Separate the numbers by spaces. Each number can occur in the representation at most once.
Examples
Input
7
7
6
5
4
3
2
1
Output
0
0
0
3 0 1 2
2 1 2
2 0 2
2 0 1
Input
2
5
5
Output
0
1 0
Note
The XOR sum of numbers is the result of bitwise sum of numbers modulo 2. | instruction | 0 | 95,663 | 20 | 191,326 |
Tags: bitmasks
Correct Solution:
```
n = int(input())
b = []
bb =[]
for i in range(n):
x=int(input())
idx = 0
for j in range(len(b)):
nxt = b[j] ^ x
if nxt < x :
x = nxt
idx ^= bb[j]
if x == 0:
cnt = 0
v = []
for k in range(2000):
if idx & (1 << k) :
v.append(k)
print(len(v),end=' ')
for e in v:
print(e,end=' ')
print()
else :
print(0)
idx ^= 1 << i
b.append(x)
bb.append(idx)
``` | output | 1 | 95,663 | 20 | 191,327 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After Misha's birthday he had many large numbers left, scattered across the room. Now it's time to clean up and Misha needs to put them in a basket. He ordered this task to his pet robot that agreed to complete the task at certain conditions. Before the robot puts a number x to the basket, Misha should answer the question: is it possible to choose one or multiple numbers that already are in the basket, such that their XOR sum equals x?
If the answer is positive, you also need to give the indexes of these numbers. If there are multiple options of choosing numbers, you are allowed to choose any correct option. After Misha's answer the robot puts the number to the basket.
Initially the basket is empty. Each integer you put in the basket takes some number. The first integer you put into the basket take number 0, the second integer takes number 1 and so on.
Misha needs to clean up the place as soon as possible but unfortunately, he isn't that good at mathematics. He asks you to help him.
Input
The first line contains number m (1 ≤ m ≤ 2000), showing how many numbers are scattered around the room.
The next m lines contain the numbers in the order in which the robot puts them in the basket. Each number is a positive integer strictly less than 10600 that doesn't contain leading zeroes.
Output
For each number either print a 0 on the corresponding line, if the number cannot be represented as a XOR sum of numbers that are in the basket, or print integer k showing how many numbers are in the representation and the indexes of these numbers. Separate the numbers by spaces. Each number can occur in the representation at most once.
Examples
Input
7
7
6
5
4
3
2
1
Output
0
0
0
3 0 1 2
2 1 2
2 0 2
2 0 1
Input
2
5
5
Output
0
1 0
Note
The XOR sum of numbers is the result of bitwise sum of numbers modulo 2. | instruction | 0 | 95,664 | 20 | 191,328 |
Tags: bitmasks
Correct Solution:
```
n = int(input())
t = [0 for i in range(2000)]
c = [0 for i in range(2000)]
for i in range(n) :
x = int(input())
r = 0
ok = False
for j in range(2000) :
if x >> j & 1 :
if t[j] != 0 :
x ^= t[j]
r ^= c[j]
else :
t[j] = x
c[j] = r ^ (1 << i)
ok = True
break
if ok :
print(0)
continue
a = []
for j in range(2000) :
if r >> j & 1 :
a.append(j)
print(len(a))
for y in a :
print(y)
``` | output | 1 | 95,664 | 20 | 191,329 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After Misha's birthday he had many large numbers left, scattered across the room. Now it's time to clean up and Misha needs to put them in a basket. He ordered this task to his pet robot that agreed to complete the task at certain conditions. Before the robot puts a number x to the basket, Misha should answer the question: is it possible to choose one or multiple numbers that already are in the basket, such that their XOR sum equals x?
If the answer is positive, you also need to give the indexes of these numbers. If there are multiple options of choosing numbers, you are allowed to choose any correct option. After Misha's answer the robot puts the number to the basket.
Initially the basket is empty. Each integer you put in the basket takes some number. The first integer you put into the basket take number 0, the second integer takes number 1 and so on.
Misha needs to clean up the place as soon as possible but unfortunately, he isn't that good at mathematics. He asks you to help him.
Input
The first line contains number m (1 ≤ m ≤ 2000), showing how many numbers are scattered around the room.
The next m lines contain the numbers in the order in which the robot puts them in the basket. Each number is a positive integer strictly less than 10600 that doesn't contain leading zeroes.
Output
For each number either print a 0 on the corresponding line, if the number cannot be represented as a XOR sum of numbers that are in the basket, or print integer k showing how many numbers are in the representation and the indexes of these numbers. Separate the numbers by spaces. Each number can occur in the representation at most once.
Examples
Input
7
7
6
5
4
3
2
1
Output
0
0
0
3 0 1 2
2 1 2
2 0 2
2 0 1
Input
2
5
5
Output
0
1 0
Note
The XOR sum of numbers is the result of bitwise sum of numbers modulo 2. | instruction | 0 | 95,665 | 20 | 191,330 |
Tags: bitmasks
Correct Solution:
```
m = int(input())
values = []
idx = []
for i in range(m):
x = int(input())
ans = 0
for xx,ii in zip(values,idx):
if (xx^x) < x:
x^=xx
ans^=ii
if x == 0:
anss = []
for j in range(i):
if (ans&1)!=0:
anss.append(j)
ans>>=1
print(len(anss),*anss)
else:
print(0)
values.append(x)
idx.append(ans^(2**i))
``` | output | 1 | 95,665 | 20 | 191,331 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After Misha's birthday he had many large numbers left, scattered across the room. Now it's time to clean up and Misha needs to put them in a basket. He ordered this task to his pet robot that agreed to complete the task at certain conditions. Before the robot puts a number x to the basket, Misha should answer the question: is it possible to choose one or multiple numbers that already are in the basket, such that their XOR sum equals x?
If the answer is positive, you also need to give the indexes of these numbers. If there are multiple options of choosing numbers, you are allowed to choose any correct option. After Misha's answer the robot puts the number to the basket.
Initially the basket is empty. Each integer you put in the basket takes some number. The first integer you put into the basket take number 0, the second integer takes number 1 and so on.
Misha needs to clean up the place as soon as possible but unfortunately, he isn't that good at mathematics. He asks you to help him.
Input
The first line contains number m (1 ≤ m ≤ 2000), showing how many numbers are scattered around the room.
The next m lines contain the numbers in the order in which the robot puts them in the basket. Each number is a positive integer strictly less than 10600 that doesn't contain leading zeroes.
Output
For each number either print a 0 on the corresponding line, if the number cannot be represented as a XOR sum of numbers that are in the basket, or print integer k showing how many numbers are in the representation and the indexes of these numbers. Separate the numbers by spaces. Each number can occur in the representation at most once.
Examples
Input
7
7
6
5
4
3
2
1
Output
0
0
0
3 0 1 2
2 1 2
2 0 2
2 0 1
Input
2
5
5
Output
0
1 0
Note
The XOR sum of numbers is the result of bitwise sum of numbers modulo 2.
Submitted Solution:
```
m = int(input())
b = []
k = []
for i in range(m):
x = int(input())
c = 0
for i in range(len(b)):
v = b[i]
d = k[i]
if (x ^ v) < x:
x ^= v
c ^= d
if x != 0:
print(0)
c ^= 2 ** i
b.append(x)
k.append(c)
else:
a = []
for j in range(m):
if c & 1 == 1:
a.append(j)
c >>= 1
print(len(a), end='')
for v in a:
print(' ', v, sep='', end='')
print()
``` | instruction | 0 | 95,666 | 20 | 191,332 |
No | output | 1 | 95,666 | 20 | 191,333 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After Misha's birthday he had many large numbers left, scattered across the room. Now it's time to clean up and Misha needs to put them in a basket. He ordered this task to his pet robot that agreed to complete the task at certain conditions. Before the robot puts a number x to the basket, Misha should answer the question: is it possible to choose one or multiple numbers that already are in the basket, such that their XOR sum equals x?
If the answer is positive, you also need to give the indexes of these numbers. If there are multiple options of choosing numbers, you are allowed to choose any correct option. After Misha's answer the robot puts the number to the basket.
Initially the basket is empty. Each integer you put in the basket takes some number. The first integer you put into the basket take number 0, the second integer takes number 1 and so on.
Misha needs to clean up the place as soon as possible but unfortunately, he isn't that good at mathematics. He asks you to help him.
Input
The first line contains number m (1 ≤ m ≤ 2000), showing how many numbers are scattered around the room.
The next m lines contain the numbers in the order in which the robot puts them in the basket. Each number is a positive integer strictly less than 10600 that doesn't contain leading zeroes.
Output
For each number either print a 0 on the corresponding line, if the number cannot be represented as a XOR sum of numbers that are in the basket, or print integer k showing how many numbers are in the representation and the indexes of these numbers. Separate the numbers by spaces. Each number can occur in the representation at most once.
Examples
Input
7
7
6
5
4
3
2
1
Output
0
0
0
3 0 1 2
2 1 2
2 0 2
2 0 1
Input
2
5
5
Output
0
1 0
Note
The XOR sum of numbers is the result of bitwise sum of numbers modulo 2.
Submitted Solution:
```
buck = [[0, 0] for i in range(2500)]
m = int(input())
for i in range(m):
a = int(input())
lst = []
for j in range(2500):
if a & (1 << j):
if(buck[j][0]):
a ^= buck[j][0]
lst.append(buck[j][1])
else:
lst = [0]
buck[j][0] = a
buck[j][1] = i+1
break
if len(lst) == 1 and lst[0] == 0:
print(0)
else:
print(len(lst), end = ' ')
for ind in lst:
print(ind, end=' ')
print('\n', end='')
``` | instruction | 0 | 95,667 | 20 | 191,334 |
No | output | 1 | 95,667 | 20 | 191,335 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After Misha's birthday he had many large numbers left, scattered across the room. Now it's time to clean up and Misha needs to put them in a basket. He ordered this task to his pet robot that agreed to complete the task at certain conditions. Before the robot puts a number x to the basket, Misha should answer the question: is it possible to choose one or multiple numbers that already are in the basket, such that their XOR sum equals x?
If the answer is positive, you also need to give the indexes of these numbers. If there are multiple options of choosing numbers, you are allowed to choose any correct option. After Misha's answer the robot puts the number to the basket.
Initially the basket is empty. Each integer you put in the basket takes some number. The first integer you put into the basket take number 0, the second integer takes number 1 and so on.
Misha needs to clean up the place as soon as possible but unfortunately, he isn't that good at mathematics. He asks you to help him.
Input
The first line contains number m (1 ≤ m ≤ 2000), showing how many numbers are scattered around the room.
The next m lines contain the numbers in the order in which the robot puts them in the basket. Each number is a positive integer strictly less than 10600 that doesn't contain leading zeroes.
Output
For each number either print a 0 on the corresponding line, if the number cannot be represented as a XOR sum of numbers that are in the basket, or print integer k showing how many numbers are in the representation and the indexes of these numbers. Separate the numbers by spaces. Each number can occur in the representation at most once.
Examples
Input
7
7
6
5
4
3
2
1
Output
0
0
0
3 0 1 2
2 1 2
2 0 2
2 0 1
Input
2
5
5
Output
0
1 0
Note
The XOR sum of numbers is the result of bitwise sum of numbers modulo 2.
Submitted Solution:
```
m = int(input())
values = []
idx = []
for i in range(m):
x = int(input())
ans = 0
for j,xx in enumerate(values):
if (xx^x) < x:
x^=xx
ans^=idx[j]
if x == 0:
anss = []
for j,xx in enumerate(values):
if (ans&1)!=0:
anss.append(j)
ans>>=1
print(len(anss),*anss)
else:
print(0)
values.append(x)
idx.append(ans^(2**i))
``` | instruction | 0 | 95,668 | 20 | 191,336 |
No | output | 1 | 95,668 | 20 | 191,337 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After Misha's birthday he had many large numbers left, scattered across the room. Now it's time to clean up and Misha needs to put them in a basket. He ordered this task to his pet robot that agreed to complete the task at certain conditions. Before the robot puts a number x to the basket, Misha should answer the question: is it possible to choose one or multiple numbers that already are in the basket, such that their XOR sum equals x?
If the answer is positive, you also need to give the indexes of these numbers. If there are multiple options of choosing numbers, you are allowed to choose any correct option. After Misha's answer the robot puts the number to the basket.
Initially the basket is empty. Each integer you put in the basket takes some number. The first integer you put into the basket take number 0, the second integer takes number 1 and so on.
Misha needs to clean up the place as soon as possible but unfortunately, he isn't that good at mathematics. He asks you to help him.
Input
The first line contains number m (1 ≤ m ≤ 2000), showing how many numbers are scattered around the room.
The next m lines contain the numbers in the order in which the robot puts them in the basket. Each number is a positive integer strictly less than 10600 that doesn't contain leading zeroes.
Output
For each number either print a 0 on the corresponding line, if the number cannot be represented as a XOR sum of numbers that are in the basket, or print integer k showing how many numbers are in the representation and the indexes of these numbers. Separate the numbers by spaces. Each number can occur in the representation at most once.
Examples
Input
7
7
6
5
4
3
2
1
Output
0
0
0
3 0 1 2
2 1 2
2 0 2
2 0 1
Input
2
5
5
Output
0
1 0
Note
The XOR sum of numbers is the result of bitwise sum of numbers modulo 2.
Submitted Solution:
```
buck = [[0, 0] for i in range(2500)]
m = int(input())
for i in range(m):
a = int(input())
ok = True
br = 1
for j in range(2500, -1, -1):
if a & (1 << j):
if(buck[j][0]):
a ^= buck[j][0]
br ^= buck[j][1]
else:
ok = False
buck[j][0] = a
buck[j][1] = br | (1 << i)
break
if not ok:
print("0")
else:
lst = []
for j in range(2501):
if br & (1 << j):
lst.append(j)
print(len(lst), end = ' ')
for j in lst:
print(j, end = ' ')
print('\n', end='')
``` | instruction | 0 | 95,669 | 20 | 191,338 |
No | output | 1 | 95,669 | 20 | 191,339 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: See you again? What kind of silly invention is this time?
Dr .: I finally came up with a revolutionary way to process mathematical formulas on a computer. Look at this table.
Ordinary notation | Dr.'s "breakthrough" notation
--- | ---
1 + 2 | 1 2 +
3 * 4 + 7 | 3 4 * 7 +
10 / (2 --12) | 10 2 12-/
(3-4) * (7 + 2 * 3) | 3 4 --7 2 3 * + *
Peter: Yeah.
Dr .: Fufufu. This alone won't tell you what it means to an inexperienced person. It's important from here.
Peter: I mean ...
Dr .: You know that computers have a data structure called a stack. Look, that's "first in, then out".
Peter: Yes. I know, that ...
Dr .: This groundbreaking notation uses that stack. For example, this 10 2 12-/, but process as follows.
Processing target | 10 | 2 | 12 |-| /
--- | --- | --- | --- | --- | ---
| ↓ | ↓ | ↓ | ↓ 2-12 | ↓ 10 / -10
Stack | |.
---
..
Ten
| ..
---
2
Ten
| 12
---
2
Ten
| ..
---
-Ten
Ten
| ..
---
..
-1
Dr .: How is it? You don't have to worry about parentheses or operator precedence, right? The word order is also "10 divided by 2 minus 12", which is somewhat similar to his Far Eastern island nation, Japanese. With this epoch-making invention, our laboratory is safe. Fafafa.
Peter: I mean, Doctor. I learned this in the basic course at the University of Aizu when I was in Japan. Everyone had a simple program called "Reverse Polish Notation".
Dr .: ...
So, instead of Peter, I decided to teach this program to the doctor. Create a program that inputs the formula written in "Reverse Polish Notation" and outputs the calculation result.
input
Given multiple datasets. For each dataset, a formula in Reverse Polish Notation (a string of up to 80 characters with integers and arithmetic symbols separated by one blank character (half-width)) is given on one line. No formula is given that divides a value by 0 or a value that is as close to 0 as possible.
The number of datasets does not exceed 50.
output
Output the calculation result (real number) on one line for each data set. The calculation result may include an error of 0.00001 or less.
Example
Input
10 2 12 - /
3 4 - 7 2 3 * + *
-1 -2 3 + +
Output
-1.000000
-13.000000
0.000000 | instruction | 0 | 95,982 | 20 | 191,964 |
"Correct Solution:
```
while True:
try:
L = input().split()
except:
break
S = []
for i in L:
if i not in "+-*/":
S.append(int(i))
elif i == "+":
S.append(S.pop()+S.pop())
elif i == "-":
t = S.pop()
S.append(S.pop()-t)
elif i == "*":
S.append(S.pop()*S.pop())
else:
t = S.pop()
S.append(S.pop() / t)
print("{:.6f}".format(S[0]))
``` | output | 1 | 95,982 | 20 | 191,965 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: See you again? What kind of silly invention is this time?
Dr .: I finally came up with a revolutionary way to process mathematical formulas on a computer. Look at this table.
Ordinary notation | Dr.'s "breakthrough" notation
--- | ---
1 + 2 | 1 2 +
3 * 4 + 7 | 3 4 * 7 +
10 / (2 --12) | 10 2 12-/
(3-4) * (7 + 2 * 3) | 3 4 --7 2 3 * + *
Peter: Yeah.
Dr .: Fufufu. This alone won't tell you what it means to an inexperienced person. It's important from here.
Peter: I mean ...
Dr .: You know that computers have a data structure called a stack. Look, that's "first in, then out".
Peter: Yes. I know, that ...
Dr .: This groundbreaking notation uses that stack. For example, this 10 2 12-/, but process as follows.
Processing target | 10 | 2 | 12 |-| /
--- | --- | --- | --- | --- | ---
| ↓ | ↓ | ↓ | ↓ 2-12 | ↓ 10 / -10
Stack | |.
---
..
Ten
| ..
---
2
Ten
| 12
---
2
Ten
| ..
---
-Ten
Ten
| ..
---
..
-1
Dr .: How is it? You don't have to worry about parentheses or operator precedence, right? The word order is also "10 divided by 2 minus 12", which is somewhat similar to his Far Eastern island nation, Japanese. With this epoch-making invention, our laboratory is safe. Fafafa.
Peter: I mean, Doctor. I learned this in the basic course at the University of Aizu when I was in Japan. Everyone had a simple program called "Reverse Polish Notation".
Dr .: ...
So, instead of Peter, I decided to teach this program to the doctor. Create a program that inputs the formula written in "Reverse Polish Notation" and outputs the calculation result.
input
Given multiple datasets. For each dataset, a formula in Reverse Polish Notation (a string of up to 80 characters with integers and arithmetic symbols separated by one blank character (half-width)) is given on one line. No formula is given that divides a value by 0 or a value that is as close to 0 as possible.
The number of datasets does not exceed 50.
output
Output the calculation result (real number) on one line for each data set. The calculation result may include an error of 0.00001 or less.
Example
Input
10 2 12 - /
3 4 - 7 2 3 * + *
-1 -2 3 + +
Output
-1.000000
-13.000000
0.000000 | instruction | 0 | 95,983 | 20 | 191,966 |
"Correct Solution:
```
def get_input():
while True:
try:
yield ''.join(input())
except EOFError:
break
N = list(get_input())
for l in range(len(N)):
p = N[l].split()
s = []
for i in range(len(p)):
if p[i] == "+":
a = float(s.pop())
b = float(s.pop())
s.append(str(b+a))
elif p[i] == "-":
a = float(s.pop())
b = float(s.pop())
s.append(str(b-a))
elif p[i] == "*":
a = float(s.pop())
b = float(s.pop())
s.append(str(b*a))
elif p[i] == "/":
a = float(s.pop())
b = float(s.pop())
s.append(str(b/a))
else:
s.append(p[i])
print(s[0])
``` | output | 1 | 95,983 | 20 | 191,967 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: See you again? What kind of silly invention is this time?
Dr .: I finally came up with a revolutionary way to process mathematical formulas on a computer. Look at this table.
Ordinary notation | Dr.'s "breakthrough" notation
--- | ---
1 + 2 | 1 2 +
3 * 4 + 7 | 3 4 * 7 +
10 / (2 --12) | 10 2 12-/
(3-4) * (7 + 2 * 3) | 3 4 --7 2 3 * + *
Peter: Yeah.
Dr .: Fufufu. This alone won't tell you what it means to an inexperienced person. It's important from here.
Peter: I mean ...
Dr .: You know that computers have a data structure called a stack. Look, that's "first in, then out".
Peter: Yes. I know, that ...
Dr .: This groundbreaking notation uses that stack. For example, this 10 2 12-/, but process as follows.
Processing target | 10 | 2 | 12 |-| /
--- | --- | --- | --- | --- | ---
| ↓ | ↓ | ↓ | ↓ 2-12 | ↓ 10 / -10
Stack | |.
---
..
Ten
| ..
---
2
Ten
| 12
---
2
Ten
| ..
---
-Ten
Ten
| ..
---
..
-1
Dr .: How is it? You don't have to worry about parentheses or operator precedence, right? The word order is also "10 divided by 2 minus 12", which is somewhat similar to his Far Eastern island nation, Japanese. With this epoch-making invention, our laboratory is safe. Fafafa.
Peter: I mean, Doctor. I learned this in the basic course at the University of Aizu when I was in Japan. Everyone had a simple program called "Reverse Polish Notation".
Dr .: ...
So, instead of Peter, I decided to teach this program to the doctor. Create a program that inputs the formula written in "Reverse Polish Notation" and outputs the calculation result.
input
Given multiple datasets. For each dataset, a formula in Reverse Polish Notation (a string of up to 80 characters with integers and arithmetic symbols separated by one blank character (half-width)) is given on one line. No formula is given that divides a value by 0 or a value that is as close to 0 as possible.
The number of datasets does not exceed 50.
output
Output the calculation result (real number) on one line for each data set. The calculation result may include an error of 0.00001 or less.
Example
Input
10 2 12 - /
3 4 - 7 2 3 * + *
-1 -2 3 + +
Output
-1.000000
-13.000000
0.000000 | instruction | 0 | 95,984 | 20 | 191,968 |
"Correct Solution:
```
import re
while True:
try:
f = input().split()
except:
break
stack = []
for c in f:
if re.match("-*[0-9]", c) is None:
b, a = str(stack.pop()), str(stack.pop())
stack.append(float(eval(a+c+b)))
else:
stack.append(c)
print(stack[0])
``` | output | 1 | 95,984 | 20 | 191,969 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: See you again? What kind of silly invention is this time?
Dr .: I finally came up with a revolutionary way to process mathematical formulas on a computer. Look at this table.
Ordinary notation | Dr.'s "breakthrough" notation
--- | ---
1 + 2 | 1 2 +
3 * 4 + 7 | 3 4 * 7 +
10 / (2 --12) | 10 2 12-/
(3-4) * (7 + 2 * 3) | 3 4 --7 2 3 * + *
Peter: Yeah.
Dr .: Fufufu. This alone won't tell you what it means to an inexperienced person. It's important from here.
Peter: I mean ...
Dr .: You know that computers have a data structure called a stack. Look, that's "first in, then out".
Peter: Yes. I know, that ...
Dr .: This groundbreaking notation uses that stack. For example, this 10 2 12-/, but process as follows.
Processing target | 10 | 2 | 12 |-| /
--- | --- | --- | --- | --- | ---
| ↓ | ↓ | ↓ | ↓ 2-12 | ↓ 10 / -10
Stack | |.
---
..
Ten
| ..
---
2
Ten
| 12
---
2
Ten
| ..
---
-Ten
Ten
| ..
---
..
-1
Dr .: How is it? You don't have to worry about parentheses or operator precedence, right? The word order is also "10 divided by 2 minus 12", which is somewhat similar to his Far Eastern island nation, Japanese. With this epoch-making invention, our laboratory is safe. Fafafa.
Peter: I mean, Doctor. I learned this in the basic course at the University of Aizu when I was in Japan. Everyone had a simple program called "Reverse Polish Notation".
Dr .: ...
So, instead of Peter, I decided to teach this program to the doctor. Create a program that inputs the formula written in "Reverse Polish Notation" and outputs the calculation result.
input
Given multiple datasets. For each dataset, a formula in Reverse Polish Notation (a string of up to 80 characters with integers and arithmetic symbols separated by one blank character (half-width)) is given on one line. No formula is given that divides a value by 0 or a value that is as close to 0 as possible.
The number of datasets does not exceed 50.
output
Output the calculation result (real number) on one line for each data set. The calculation result may include an error of 0.00001 or less.
Example
Input
10 2 12 - /
3 4 - 7 2 3 * + *
-1 -2 3 + +
Output
-1.000000
-13.000000
0.000000 | instruction | 0 | 95,985 | 20 | 191,970 |
"Correct Solution:
```
d = []
while True:
try:
lst = list(input().split())
for i in lst:
if i == '+':
num = d.pop()
d[-1] = d[-1] + num
elif i == '-':
num = d.pop()
d[-1] = d[-1] - num
elif i == '*':
num = d.pop()
d[-1] = d[-1] * num
elif i == '/':
num = d.pop()
d[-1] = d[-1] / num
else:
d.append(int(i))
print(d.pop())
except EOFError:
break
``` | output | 1 | 95,985 | 20 | 191,971 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: See you again? What kind of silly invention is this time?
Dr .: I finally came up with a revolutionary way to process mathematical formulas on a computer. Look at this table.
Ordinary notation | Dr.'s "breakthrough" notation
--- | ---
1 + 2 | 1 2 +
3 * 4 + 7 | 3 4 * 7 +
10 / (2 --12) | 10 2 12-/
(3-4) * (7 + 2 * 3) | 3 4 --7 2 3 * + *
Peter: Yeah.
Dr .: Fufufu. This alone won't tell you what it means to an inexperienced person. It's important from here.
Peter: I mean ...
Dr .: You know that computers have a data structure called a stack. Look, that's "first in, then out".
Peter: Yes. I know, that ...
Dr .: This groundbreaking notation uses that stack. For example, this 10 2 12-/, but process as follows.
Processing target | 10 | 2 | 12 |-| /
--- | --- | --- | --- | --- | ---
| ↓ | ↓ | ↓ | ↓ 2-12 | ↓ 10 / -10
Stack | |.
---
..
Ten
| ..
---
2
Ten
| 12
---
2
Ten
| ..
---
-Ten
Ten
| ..
---
..
-1
Dr .: How is it? You don't have to worry about parentheses or operator precedence, right? The word order is also "10 divided by 2 minus 12", which is somewhat similar to his Far Eastern island nation, Japanese. With this epoch-making invention, our laboratory is safe. Fafafa.
Peter: I mean, Doctor. I learned this in the basic course at the University of Aizu when I was in Japan. Everyone had a simple program called "Reverse Polish Notation".
Dr .: ...
So, instead of Peter, I decided to teach this program to the doctor. Create a program that inputs the formula written in "Reverse Polish Notation" and outputs the calculation result.
input
Given multiple datasets. For each dataset, a formula in Reverse Polish Notation (a string of up to 80 characters with integers and arithmetic symbols separated by one blank character (half-width)) is given on one line. No formula is given that divides a value by 0 or a value that is as close to 0 as possible.
The number of datasets does not exceed 50.
output
Output the calculation result (real number) on one line for each data set. The calculation result may include an error of 0.00001 or less.
Example
Input
10 2 12 - /
3 4 - 7 2 3 * + *
-1 -2 3 + +
Output
-1.000000
-13.000000
0.000000 | instruction | 0 | 95,986 | 20 | 191,972 |
"Correct Solution:
```
while True :
try :
lst = list(input().split())
except EOFError :
break
stack = []
for i in lst :
if i == '+' :
b = stack.pop(-1)
a = stack.pop(-1)
stack.append(a+b)
elif i == '-' :
b = stack.pop(-1)
a = stack.pop(-1)
stack.append(a-b)
elif i == '*' :
b = stack.pop(-1)
a = stack.pop(-1)
stack.append(a*b)
elif i == '/' :
b = stack.pop(-1)
a = stack.pop(-1)
stack.append(a/b)
else :
stack.append(int(i))
print('{:.8f}'.format(stack[0]))
``` | output | 1 | 95,986 | 20 | 191,973 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: See you again? What kind of silly invention is this time?
Dr .: I finally came up with a revolutionary way to process mathematical formulas on a computer. Look at this table.
Ordinary notation | Dr.'s "breakthrough" notation
--- | ---
1 + 2 | 1 2 +
3 * 4 + 7 | 3 4 * 7 +
10 / (2 --12) | 10 2 12-/
(3-4) * (7 + 2 * 3) | 3 4 --7 2 3 * + *
Peter: Yeah.
Dr .: Fufufu. This alone won't tell you what it means to an inexperienced person. It's important from here.
Peter: I mean ...
Dr .: You know that computers have a data structure called a stack. Look, that's "first in, then out".
Peter: Yes. I know, that ...
Dr .: This groundbreaking notation uses that stack. For example, this 10 2 12-/, but process as follows.
Processing target | 10 | 2 | 12 |-| /
--- | --- | --- | --- | --- | ---
| ↓ | ↓ | ↓ | ↓ 2-12 | ↓ 10 / -10
Stack | |.
---
..
Ten
| ..
---
2
Ten
| 12
---
2
Ten
| ..
---
-Ten
Ten
| ..
---
..
-1
Dr .: How is it? You don't have to worry about parentheses or operator precedence, right? The word order is also "10 divided by 2 minus 12", which is somewhat similar to his Far Eastern island nation, Japanese. With this epoch-making invention, our laboratory is safe. Fafafa.
Peter: I mean, Doctor. I learned this in the basic course at the University of Aizu when I was in Japan. Everyone had a simple program called "Reverse Polish Notation".
Dr .: ...
So, instead of Peter, I decided to teach this program to the doctor. Create a program that inputs the formula written in "Reverse Polish Notation" and outputs the calculation result.
input
Given multiple datasets. For each dataset, a formula in Reverse Polish Notation (a string of up to 80 characters with integers and arithmetic symbols separated by one blank character (half-width)) is given on one line. No formula is given that divides a value by 0 or a value that is as close to 0 as possible.
The number of datasets does not exceed 50.
output
Output the calculation result (real number) on one line for each data set. The calculation result may include an error of 0.00001 or less.
Example
Input
10 2 12 - /
3 4 - 7 2 3 * + *
-1 -2 3 + +
Output
-1.000000
-13.000000
0.000000 | instruction | 0 | 95,987 | 20 | 191,974 |
"Correct Solution:
```
while True:
try:
a = input().split()
stack = []
for inp in a:
if inp == "+":
x = stack.pop()
y = stack.pop()
stack.append(x+y)
elif inp == "-":
x = stack.pop()
y = stack.pop()
stack.append(y-x)
elif inp == "*":
x = stack.pop()
y = stack.pop()
stack.append(x*y)
elif inp == "/":
x = stack.pop()
y = stack.pop()
stack.append(y/x)
else:
stack.append(float(inp))
print(*stack)
except:
break
``` | output | 1 | 95,987 | 20 | 191,975 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: See you again? What kind of silly invention is this time?
Dr .: I finally came up with a revolutionary way to process mathematical formulas on a computer. Look at this table.
Ordinary notation | Dr.'s "breakthrough" notation
--- | ---
1 + 2 | 1 2 +
3 * 4 + 7 | 3 4 * 7 +
10 / (2 --12) | 10 2 12-/
(3-4) * (7 + 2 * 3) | 3 4 --7 2 3 * + *
Peter: Yeah.
Dr .: Fufufu. This alone won't tell you what it means to an inexperienced person. It's important from here.
Peter: I mean ...
Dr .: You know that computers have a data structure called a stack. Look, that's "first in, then out".
Peter: Yes. I know, that ...
Dr .: This groundbreaking notation uses that stack. For example, this 10 2 12-/, but process as follows.
Processing target | 10 | 2 | 12 |-| /
--- | --- | --- | --- | --- | ---
| ↓ | ↓ | ↓ | ↓ 2-12 | ↓ 10 / -10
Stack | |.
---
..
Ten
| ..
---
2
Ten
| 12
---
2
Ten
| ..
---
-Ten
Ten
| ..
---
..
-1
Dr .: How is it? You don't have to worry about parentheses or operator precedence, right? The word order is also "10 divided by 2 minus 12", which is somewhat similar to his Far Eastern island nation, Japanese. With this epoch-making invention, our laboratory is safe. Fafafa.
Peter: I mean, Doctor. I learned this in the basic course at the University of Aizu when I was in Japan. Everyone had a simple program called "Reverse Polish Notation".
Dr .: ...
So, instead of Peter, I decided to teach this program to the doctor. Create a program that inputs the formula written in "Reverse Polish Notation" and outputs the calculation result.
input
Given multiple datasets. For each dataset, a formula in Reverse Polish Notation (a string of up to 80 characters with integers and arithmetic symbols separated by one blank character (half-width)) is given on one line. No formula is given that divides a value by 0 or a value that is as close to 0 as possible.
The number of datasets does not exceed 50.
output
Output the calculation result (real number) on one line for each data set. The calculation result may include an error of 0.00001 or less.
Example
Input
10 2 12 - /
3 4 - 7 2 3 * + *
-1 -2 3 + +
Output
-1.000000
-13.000000
0.000000 | instruction | 0 | 95,988 | 20 | 191,976 |
"Correct Solution:
```
import sys
def isNum(a) :
try:
int(a)
except:
return False
return True
for line in sys.stdin:
stack = []
task = line.strip().split(" ") ;
for i in range(0, len(task) ) :
if isNum(task[i]) :
stack.append(task[i])
elif len(stack) != 0 :
stack.append( str( eval( stack.pop(-2) + task[i] + stack.pop(-1) ) ) )
print("{:6f}".format(float(stack[0])))
``` | output | 1 | 95,988 | 20 | 191,977 |
Provide a correct Python 3 solution for this coding contest problem.
Dr .: Peter, I've finally done it.
Peter: See you again? What kind of silly invention is this time?
Dr .: I finally came up with a revolutionary way to process mathematical formulas on a computer. Look at this table.
Ordinary notation | Dr.'s "breakthrough" notation
--- | ---
1 + 2 | 1 2 +
3 * 4 + 7 | 3 4 * 7 +
10 / (2 --12) | 10 2 12-/
(3-4) * (7 + 2 * 3) | 3 4 --7 2 3 * + *
Peter: Yeah.
Dr .: Fufufu. This alone won't tell you what it means to an inexperienced person. It's important from here.
Peter: I mean ...
Dr .: You know that computers have a data structure called a stack. Look, that's "first in, then out".
Peter: Yes. I know, that ...
Dr .: This groundbreaking notation uses that stack. For example, this 10 2 12-/, but process as follows.
Processing target | 10 | 2 | 12 |-| /
--- | --- | --- | --- | --- | ---
| ↓ | ↓ | ↓ | ↓ 2-12 | ↓ 10 / -10
Stack | |.
---
..
Ten
| ..
---
2
Ten
| 12
---
2
Ten
| ..
---
-Ten
Ten
| ..
---
..
-1
Dr .: How is it? You don't have to worry about parentheses or operator precedence, right? The word order is also "10 divided by 2 minus 12", which is somewhat similar to his Far Eastern island nation, Japanese. With this epoch-making invention, our laboratory is safe. Fafafa.
Peter: I mean, Doctor. I learned this in the basic course at the University of Aizu when I was in Japan. Everyone had a simple program called "Reverse Polish Notation".
Dr .: ...
So, instead of Peter, I decided to teach this program to the doctor. Create a program that inputs the formula written in "Reverse Polish Notation" and outputs the calculation result.
input
Given multiple datasets. For each dataset, a formula in Reverse Polish Notation (a string of up to 80 characters with integers and arithmetic symbols separated by one blank character (half-width)) is given on one line. No formula is given that divides a value by 0 or a value that is as close to 0 as possible.
The number of datasets does not exceed 50.
output
Output the calculation result (real number) on one line for each data set. The calculation result may include an error of 0.00001 or less.
Example
Input
10 2 12 - /
3 4 - 7 2 3 * + *
-1 -2 3 + +
Output
-1.000000
-13.000000
0.000000 | instruction | 0 | 95,989 | 20 | 191,978 |
"Correct Solution:
```
def invpol(f):
s = []
for c in f:
if c == '+':
a = s.pop()
s.append(s.pop() + a)
elif c == '-':
a = s.pop()
s.append(s.pop() - a)
elif c == '*':
a = s.pop()
s.append(s.pop() * a)
elif c == '/':
a = s.pop()
s.append(s.pop() / a)
else:
s.append(int(c))
return(s[0])
while True:
try:
f = input().strip().split()
print("%.6f" % invpol(f))
except EOFError:
break
``` | output | 1 | 95,989 | 20 | 191,979 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22 | instruction | 0 | 96,125 | 20 | 192,250 |
Tags: greedy, strings
Correct Solution:
```
for _ in range(int(input())):
n = int(input())
s = input()
x = int(s[0])
cnt = 0
for i in range(1,n-1):
if int(s[i]) > 0:
cnt += 1
if cnt or int(s[0]) < int(s[n-1]):
print("YES")
print(2)
print(s[0],s[1:])
else:
print("NO")
``` | output | 1 | 96,125 | 20 | 192,251 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22 | instruction | 0 | 96,126 | 20 | 192,252 |
Tags: greedy, strings
Correct Solution:
```
t=int(input())
for i in range (t):
# print(i,"fun")
n=int(input())
s=input()
if n==2:
s=int(s)
if s%10>s//10:
print("YES")
print(2)
print(s//10,s%10)
else:
print("NO")
else:
f_half=n//2
if n%2==0:
f_half-=1
f_s=int(s[:f_half])
s_s=int(s[f_half:])
print("YES")
print(2)
print(f_s,s_s)
``` | output | 1 | 96,126 | 20 | 192,253 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22 | instruction | 0 | 96,127 | 20 | 192,254 |
Tags: greedy, strings
Correct Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Sun Aug 16 16:23:36 2020
@author: MridulSachdeva
"""
CASES = int(input())
for i in range(CASES):
n = int(input())
s = input()
#print(s)
if int(s[0]) >= int(s[1:]):
print('NO')
else:
print('YES')
print(2)
print(s[0], s[1:])
``` | output | 1 | 96,127 | 20 | 192,255 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22 | instruction | 0 | 96,128 | 20 | 192,256 |
Tags: greedy, strings
Correct Solution:
```
Input=lambda:map(int,input().split())
for i in range(int(input())):
n = int(input())
number = input()
if n == 2:
if number[0] < number[1]:
print("YES")
print(2)
print(number[0],number[1])
else:
print("NO")
else:
print("YES")
print(2)
print(number[0],number[1:])
'''
openvpn
vpnbook
sEN6DC9
'''
``` | output | 1 | 96,128 | 20 | 192,257 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22 | instruction | 0 | 96,129 | 20 | 192,258 |
Tags: greedy, strings
Correct Solution:
```
q = int(input())
for qq in range(q):
n = int(input())
s = input()
if n == 2 and s[0] >= s[1]:
print('NO')
else:
print('YES')
print('2')
print(s[0] , s[1 : ])
``` | output | 1 | 96,129 | 20 | 192,259 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22 | instruction | 0 | 96,130 | 20 | 192,260 |
Tags: greedy, strings
Correct Solution:
```
q = int(input())
for i in range(q):
n = int(input())
x = list(input())
if n == 2 and x[0] >= x[1]:
print('NO')
else:
print('YES')
print(2)
print(*x[0] + ' ', *x[1:], sep='')
``` | output | 1 | 96,130 | 20 | 192,261 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22 | instruction | 0 | 96,131 | 20 | 192,262 |
Tags: greedy, strings
Correct Solution:
```
t=int(input())
for i in range(t):
n=int(input())
s=input()
k1=int(s[0])
k2=int(s[1])
if n==2 and k1>=k2:
print('NO')
else:
print('YES')
print('2')
print(s[0],s[1:],end=" ")
print()
``` | output | 1 | 96,131 | 20 | 192,263 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a sequence s consisting of n digits from 1 to 9.
You have to divide it into at least two segments (segment — is a consecutive sequence of elements) (in other words, you have to place separators between some digits of the sequence) in such a way that each element belongs to exactly one segment and if the resulting division will be represented as an integer numbers sequence then each next element of this sequence will be strictly greater than the previous one.
More formally: if the resulting division of the sequence is t_1, t_2, ..., t_k, where k is the number of element in a division, then for each i from 1 to k-1 the condition t_{i} < t_{i + 1} (using numerical comparing, it means that the integer representations of strings are compared) should be satisfied.
For example, if s=654 then you can divide it into parts [6, 54] and it will be suitable division. But if you will divide it into parts [65, 4] then it will be bad division because 65 > 4. If s=123 then you can divide it into parts [1, 23], [1, 2, 3] but not into parts [12, 3].
Your task is to find any suitable division for each of the q independent queries.
Input
The first line of the input contains one integer q (1 ≤ q ≤ 300) — the number of queries.
The first line of the i-th query contains one integer number n_i (2 ≤ n_i ≤ 300) — the number of digits in the i-th query.
The second line of the i-th query contains one string s_i of length n_i consisting only of digits from 1 to 9.
Output
If the sequence of digits in the i-th query cannot be divided into at least two parts in a way described in the problem statement, print the single line "NO" for this query.
Otherwise in the first line of the answer to this query print "YES", on the second line print k_i — the number of parts in your division of the i-th query sequence and in the third line print k_i strings t_{i, 1}, t_{i, 2}, ..., t_{i, k_i} — your division. Parts should be printed in order of the initial string digits. It means that if you write the parts one after another without changing their order then you'll get the string s_i.
See examples for better understanding.
Example
Input
4
6
654321
4
1337
2
33
4
2122
Output
YES
3
6 54 321
YES
3
1 3 37
NO
YES
2
21 22 | instruction | 0 | 96,132 | 20 | 192,264 |
Tags: greedy, strings
Correct Solution:
```
n=int(input())
for i in range(n):
d=int(input())
s=input()
if len(s)==2:
if int(s[0])>=int(s[1]):
print('NO')
else:
print('YES')
print(2)
print(s[0],s[1])
else:
print('YES')
print(2)
print(s[0],s[1:])
``` | output | 1 | 96,132 | 20 | 192,265 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (ai, bi). How many operations will be performed for each of them?
Input
The first line contains the number of pairs n (1 ≤ n ≤ 1000). Then follow n lines, each line contains a pair of positive integers ai, bi (1 ≤ ai, bi ≤ 109).
Output
Print the sought number of operations for each pair on a single line.
Examples
Input
2
4 17
7 987654321
Output
8
141093479 | instruction | 0 | 96,422 | 20 | 192,844 |
Tags: math, number theory
Correct Solution:
```
import math
def countSteps(x, y):
# If y divides x, then simply
# return x/y.
if (x % y == 0):
return math.floor(x / y)
# Else recur. Note that this function
# works even if x is smaller than y
# because in that case first recursive
# call exchanges roles of x and y.
return math.floor((x / y) +
countSteps(y, x % y))
n = int(input())
c = []
for i in range(0,n):
x,y = map(int, input().rstrip().split())
count = countSteps(x,y)
c.append(count)
for i in range(0,len(c)):
print(c[i])
``` | output | 1 | 96,422 | 20 | 192,845 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (ai, bi). How many operations will be performed for each of them?
Input
The first line contains the number of pairs n (1 ≤ n ≤ 1000). Then follow n lines, each line contains a pair of positive integers ai, bi (1 ≤ ai, bi ≤ 109).
Output
Print the sought number of operations for each pair on a single line.
Examples
Input
2
4 17
7 987654321
Output
8
141093479 | instruction | 0 | 96,423 | 20 | 192,846 |
Tags: math, number theory
Correct Solution:
```
"""
A. Subtractions
time limit per test1 second
memory limit per test256 megabytes
inputstandard input
outputstandard output
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (ai, bi). How many operations will be performed for each of them?
Input
The first line contains the number of pairs n (1 ≤ n ≤ 1000). Then follow n lines, each line contains a pair of positive integers ai, bi (1 ≤ ai, bi ≤ 109).
Output
Print the sought number of operations for each pair on a single line.
"""
def subs(a,b):
if a > b:
a , b = b, a
if (b % a) == 0:
return b//a
else:
return b//a + subs(b % a, a)
count = int(input())
for _ in range(count):
a,b = input().split()
a = int(a)
b = int(b)
print(subs(a,b))
``` | output | 1 | 96,423 | 20 | 192,847 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (ai, bi). How many operations will be performed for each of them?
Input
The first line contains the number of pairs n (1 ≤ n ≤ 1000). Then follow n lines, each line contains a pair of positive integers ai, bi (1 ≤ ai, bi ≤ 109).
Output
Print the sought number of operations for each pair on a single line.
Examples
Input
2
4 17
7 987654321
Output
8
141093479 | instruction | 0 | 96,424 | 20 | 192,848 |
Tags: math, number theory
Correct Solution:
```
cases = int(input())
for i in range(cases):
a, b = map(int, input().split())
total = 0
while a > 0 and b > 0:
total += max(a, b) // min(a, b)
if a >= b:
a %= b
else:
b %= a
print(total)
``` | output | 1 | 96,424 | 20 | 192,849 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (ai, bi). How many operations will be performed for each of them?
Input
The first line contains the number of pairs n (1 ≤ n ≤ 1000). Then follow n lines, each line contains a pair of positive integers ai, bi (1 ≤ ai, bi ≤ 109).
Output
Print the sought number of operations for each pair on a single line.
Examples
Input
2
4 17
7 987654321
Output
8
141093479 | instruction | 0 | 96,425 | 20 | 192,850 |
Tags: math, number theory
Correct Solution:
```
for i in range(int(input())):
a, b = map(int, input().split())
operations = 0
a, b = max(a,b), min(a,b)
while b != 0:
operations += a//b
a -= a//b*b
a, b = max(a,b), min(a,b)
print(operations)
``` | output | 1 | 96,425 | 20 | 192,851 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got two numbers. As long as they are both larger than zero, they go through the same operation: subtract the lesser number from the larger one. If they equal substract one number from the another. For example, one operation transforms pair (4,17) to pair (4,13), it transforms (5,5) to (0,5).
You've got some number of pairs (ai, bi). How many operations will be performed for each of them?
Input
The first line contains the number of pairs n (1 ≤ n ≤ 1000). Then follow n lines, each line contains a pair of positive integers ai, bi (1 ≤ ai, bi ≤ 109).
Output
Print the sought number of operations for each pair on a single line.
Examples
Input
2
4 17
7 987654321
Output
8
141093479 | instruction | 0 | 96,426 | 20 | 192,852 |
Tags: math, number theory
Correct Solution:
```
for i in range(int(input())):
a, b = map(int, input().split())
if a > b: a, b = b, a
s = 0
if a > 0:
s = b // a
a, b = b - s * a, a
while a > 0:
k = b // a
a, b = b - k * a, a
s += k
print(s)
``` | output | 1 | 96,426 | 20 | 192,853 |
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