message stringlengths 2 44.5k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
We have N integers. The i-th integer is A_i.
Find \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
What is \mbox{ XOR }?
The XOR of integers A and B, A \mbox{ XOR } B, is defined as follows:
* When A \mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.
For example, 3 \mbox{ XOR } 5 = 6. (In base two: 011 \mbox{ XOR } 101 = 110.)
Constraints
* 2 \leq N \leq 3 \times 10^5
* 0 \leq A_i < 2^{60}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the value \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
Examples
Input
3
1 2 3
Output
6
Input
10
3 1 4 1 5 9 2 6 5 3
Output
237
Input
10
3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820
Output
103715602 | instruction | 0 | 58,687 | 5 | 117,374 |
"Correct Solution:
```
#147_D
n = int(input())
A = list(map(int, input().split()))
ans = 0
mod = 10 ** 9 + 7
for i in range(60):
s = sum([(a >> i) & 1 for a in A])
ans = (ans + s * (n-s) * pow(2,i,mod)) % mod
print(ans)
``` | output | 1 | 58,687 | 5 | 117,375 |
Provide a correct Python 3 solution for this coding contest problem.
We have N integers. The i-th integer is A_i.
Find \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
What is \mbox{ XOR }?
The XOR of integers A and B, A \mbox{ XOR } B, is defined as follows:
* When A \mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.
For example, 3 \mbox{ XOR } 5 = 6. (In base two: 011 \mbox{ XOR } 101 = 110.)
Constraints
* 2 \leq N \leq 3 \times 10^5
* 0 \leq A_i < 2^{60}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the value \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
Examples
Input
3
1 2 3
Output
6
Input
10
3 1 4 1 5 9 2 6 5 3
Output
237
Input
10
3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820
Output
103715602 | instruction | 0 | 58,688 | 5 | 117,376 |
"Correct Solution:
```
n = int(input())
a = list(map(int,input().split()))
mod = 10**9+7
ans = 0
for i in range(60):
keta=1<<i
cnt=0
for j in a:
if keta & j:
cnt+=1
ans+=((keta%mod)*cnt*(n-cnt))%mod
print(ans%mod)
``` | output | 1 | 58,688 | 5 | 117,377 |
Provide a correct Python 3 solution for this coding contest problem.
We have N integers. The i-th integer is A_i.
Find \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
What is \mbox{ XOR }?
The XOR of integers A and B, A \mbox{ XOR } B, is defined as follows:
* When A \mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.
For example, 3 \mbox{ XOR } 5 = 6. (In base two: 011 \mbox{ XOR } 101 = 110.)
Constraints
* 2 \leq N \leq 3 \times 10^5
* 0 \leq A_i < 2^{60}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the value \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
Examples
Input
3
1 2 3
Output
6
Input
10
3 1 4 1 5 9 2 6 5 3
Output
237
Input
10
3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820
Output
103715602 | instruction | 0 | 58,689 | 5 | 117,378 |
"Correct Solution:
```
N = int(input())
A = ''.join(list(map(lambda x: format(int(x), '060b'), input().split(' '))))
mod = 10 ** 9 + 7
ans = 0
for n in range(60):
one = A[59-n::60].count('1')
ans = (ans + 2**n *one*(N-one))%mod
print(ans)
``` | output | 1 | 58,689 | 5 | 117,379 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N integers. The i-th integer is A_i.
Find \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
What is \mbox{ XOR }?
The XOR of integers A and B, A \mbox{ XOR } B, is defined as follows:
* When A \mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.
For example, 3 \mbox{ XOR } 5 = 6. (In base two: 011 \mbox{ XOR } 101 = 110.)
Constraints
* 2 \leq N \leq 3 \times 10^5
* 0 \leq A_i < 2^{60}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the value \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
Examples
Input
3
1 2 3
Output
6
Input
10
3 1 4 1 5 9 2 6 5 3
Output
237
Input
10
3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820
Output
103715602
Submitted Solution:
```
N=int(input())
A=list(map(int,input().split()))
ans=0
mod=10**9+7
for i in range(61):
a=sum([1 for j in A if j>>i & 1])
ans=ans+a*(N-a)*(2**i)
ans=ans%mod
print(ans)
``` | instruction | 0 | 58,690 | 5 | 117,380 |
Yes | output | 1 | 58,690 | 5 | 117,381 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N integers. The i-th integer is A_i.
Find \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
What is \mbox{ XOR }?
The XOR of integers A and B, A \mbox{ XOR } B, is defined as follows:
* When A \mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.
For example, 3 \mbox{ XOR } 5 = 6. (In base two: 011 \mbox{ XOR } 101 = 110.)
Constraints
* 2 \leq N \leq 3 \times 10^5
* 0 \leq A_i < 2^{60}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the value \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
Examples
Input
3
1 2 3
Output
6
Input
10
3 1 4 1 5 9 2 6 5 3
Output
237
Input
10
3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820
Output
103715602
Submitted Solution:
```
mod=10**9+7
N=int(input())
A=list(map(int,input().split()))
ans=0
for i in range(60):
x=0
for j in range(N):
if A[j]>>i&1: x+=1
ans+=x*(N-x)*(2**i)
print(ans%mod)
``` | instruction | 0 | 58,691 | 5 | 117,382 |
Yes | output | 1 | 58,691 | 5 | 117,383 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N integers. The i-th integer is A_i.
Find \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
What is \mbox{ XOR }?
The XOR of integers A and B, A \mbox{ XOR } B, is defined as follows:
* When A \mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.
For example, 3 \mbox{ XOR } 5 = 6. (In base two: 011 \mbox{ XOR } 101 = 110.)
Constraints
* 2 \leq N \leq 3 \times 10^5
* 0 \leq A_i < 2^{60}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the value \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
Examples
Input
3
1 2 3
Output
6
Input
10
3 1 4 1 5 9 2 6 5 3
Output
237
Input
10
3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820
Output
103715602
Submitted Solution:
```
def main():
n,*a=map(int,open(0).read().split())
c=0
for i in range(61):
i=2**i
t=sum(i&b and 1for b in a)
c=(c+t*(n-t)*i)%(10**9+7)
print(c)
main()
``` | instruction | 0 | 58,692 | 5 | 117,384 |
Yes | output | 1 | 58,692 | 5 | 117,385 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N integers. The i-th integer is A_i.
Find \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
What is \mbox{ XOR }?
The XOR of integers A and B, A \mbox{ XOR } B, is defined as follows:
* When A \mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.
For example, 3 \mbox{ XOR } 5 = 6. (In base two: 011 \mbox{ XOR } 101 = 110.)
Constraints
* 2 \leq N \leq 3 \times 10^5
* 0 \leq A_i < 2^{60}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the value \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
Examples
Input
3
1 2 3
Output
6
Input
10
3 1 4 1 5 9 2 6 5 3
Output
237
Input
10
3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820
Output
103715602
Submitted Solution:
```
N = int(input())
A = list(map(int, input().split()))
ans = 0
for i in range(60 + 1):
cnt = 0
for a in A:
if a >> i & 1:
cnt += 1
ans = (ans + 2 ** i * cnt * (N - cnt)) % (10 ** 9 + 7)
print(ans)
``` | instruction | 0 | 58,693 | 5 | 117,386 |
Yes | output | 1 | 58,693 | 5 | 117,387 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N integers. The i-th integer is A_i.
Find \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
What is \mbox{ XOR }?
The XOR of integers A and B, A \mbox{ XOR } B, is defined as follows:
* When A \mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.
For example, 3 \mbox{ XOR } 5 = 6. (In base two: 011 \mbox{ XOR } 101 = 110.)
Constraints
* 2 \leq N \leq 3 \times 10^5
* 0 \leq A_i < 2^{60}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the value \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
Examples
Input
3
1 2 3
Output
6
Input
10
3 1 4 1 5 9 2 6 5 3
Output
237
Input
10
3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820
Output
103715602
Submitted Solution:
```
N = int(input())
A = list(map(int,input().split()))
mod = 10**9+7
lb0 = [0]*60
lb1 = [0]*60
for i in range(N):
bs = format(A[i],"060b")
for j in range(60):
if bs[j] == "0":
lb0[j] += 1
if bs[j] == "1":
lb1[j] += 1
###
ans = 0
for i in range(60):
ans += ((lb0[i]*lb1[i] %mod)*(2**(59-i) %mod)) %mod
ans %= mod
print(ans)
``` | instruction | 0 | 58,694 | 5 | 117,388 |
No | output | 1 | 58,694 | 5 | 117,389 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N integers. The i-th integer is A_i.
Find \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
What is \mbox{ XOR }?
The XOR of integers A and B, A \mbox{ XOR } B, is defined as follows:
* When A \mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.
For example, 3 \mbox{ XOR } 5 = 6. (In base two: 011 \mbox{ XOR } 101 = 110.)
Constraints
* 2 \leq N \leq 3 \times 10^5
* 0 \leq A_i < 2^{60}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the value \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
Examples
Input
3
1 2 3
Output
6
Input
10
3 1 4 1 5 9 2 6 5 3
Output
237
Input
10
3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820
Output
103715602
Submitted Solution:
```
n = int(input())
a = list(map(int,input().split()))
ans = 0
for i in range(n):
for j in range(i,n):
if i != j:
ans += a[i] ^ a[j]
print(ans%1000000007)
``` | instruction | 0 | 58,695 | 5 | 117,390 |
No | output | 1 | 58,695 | 5 | 117,391 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N integers. The i-th integer is A_i.
Find \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
What is \mbox{ XOR }?
The XOR of integers A and B, A \mbox{ XOR } B, is defined as follows:
* When A \mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.
For example, 3 \mbox{ XOR } 5 = 6. (In base two: 011 \mbox{ XOR } 101 = 110.)
Constraints
* 2 \leq N \leq 3 \times 10^5
* 0 \leq A_i < 2^{60}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the value \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
Examples
Input
3
1 2 3
Output
6
Input
10
3 1 4 1 5 9 2 6 5 3
Output
237
Input
10
3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820
Output
103715602
Submitted Solution:
```
n = int(input())
A = [int(i) for i in input().split()]
s = [0]*61
for a in range(n):
for i in range(61):
if(A[a]>>i&1)==1:
s[i+1] += 1
ans = 0
for i in range(61):
# print("a",2**(i-1)*s.get(i,0)*(n-s.get(i,0)))
# print("b",s.get(i,0))
# print("c",(n-s.get(i,0)))
ans += 2**(i-1)*s[i]*(n-s[i])
ans = ans % (10**9+7)
print(int(ans))
# print(s)
``` | instruction | 0 | 58,696 | 5 | 117,392 |
No | output | 1 | 58,696 | 5 | 117,393 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have N integers. The i-th integer is A_i.
Find \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
What is \mbox{ XOR }?
The XOR of integers A and B, A \mbox{ XOR } B, is defined as follows:
* When A \mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.
For example, 3 \mbox{ XOR } 5 = 6. (In base two: 011 \mbox{ XOR } 101 = 110.)
Constraints
* 2 \leq N \leq 3 \times 10^5
* 0 \leq A_i < 2^{60}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the value \sum_{i=1}^{N-1}\sum_{j=i+1}^{N} (A_i \mbox{ XOR } A_j), modulo (10^9+7).
Examples
Input
3
1 2 3
Output
6
Input
10
3 1 4 1 5 9 2 6 5 3
Output
237
Input
10
3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820
Output
103715602
Submitted Solution:
```
N = input()
a = list(map(int, input().split()))
i = 0
sum = 0
while i < len(a)-1:
for j in range(i+1, len(a)):
#print(i, j)
sum += a[i]^a[j]
while sum >= 1000000007:
sum -= 1000000007
i += 1
print(sum)
``` | instruction | 0 | 58,697 | 5 | 117,394 |
No | output | 1 | 58,697 | 5 | 117,395 |
Provide a correct Python 3 solution for this coding contest problem.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14 | instruction | 0 | 58,767 | 5 | 117,534 |
"Correct Solution:
```
n=int(input())
f=[2]
for x in range(1,501):
f.append(0)
for x in range(1,n+1):
f[x]=f[x-1]*2+2
print (f[n])
``` | output | 1 | 58,767 | 5 | 117,535 |
Provide a correct Python 3 solution for this coding contest problem.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14 | instruction | 0 | 58,768 | 5 | 117,536 |
"Correct Solution:
```
x=int(input())
j=2
for i in range(x):
j*=2
j+=2
print(j)
``` | output | 1 | 58,768 | 5 | 117,537 |
Provide a correct Python 3 solution for this coding contest problem.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14 | instruction | 0 | 58,769 | 5 | 117,538 |
"Correct Solution:
```
x=int(input())
ans=0
for i in range(1,x+2):
ans+=2**i
print(ans)
``` | output | 1 | 58,769 | 5 | 117,539 |
Provide a correct Python 3 solution for this coding contest problem.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14 | instruction | 0 | 58,770 | 5 | 117,540 |
"Correct Solution:
```
x=int(input())
n=2
for i in range(x):
n=n+n+1+1
print(n)
``` | output | 1 | 58,770 | 5 | 117,541 |
Provide a correct Python 3 solution for this coding contest problem.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14 | instruction | 0 | 58,771 | 5 | 117,542 |
"Correct Solution:
```
x=int(input())
l,r=0,100000000000000
while r-l>1:
m=(l+r)//2
t=m
cnt=0
while m>2:
cnt+=1
m=(m-1)//2
if cnt>x:
r=t
else:
l=t
print(l)
``` | output | 1 | 58,771 | 5 | 117,543 |
Provide a correct Python 3 solution for this coding contest problem.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14 | instruction | 0 | 58,772 | 5 | 117,544 |
"Correct Solution:
```
print((4<<int(input()))-2)
``` | output | 1 | 58,772 | 5 | 117,545 |
Provide a correct Python 3 solution for this coding contest problem.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14 | instruction | 0 | 58,773 | 5 | 117,546 |
"Correct Solution:
```
print(2**(int(input())+2)-2)
``` | output | 1 | 58,773 | 5 | 117,547 |
Provide a correct Python 3 solution for this coding contest problem.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14 | instruction | 0 | 58,774 | 5 | 117,548 |
"Correct Solution:
```
X = int(input())
ans = 1
for _ in range(X+1):
ans = 2*ans + 1
print(ans - 1)
``` | output | 1 | 58,774 | 5 | 117,549 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14
Submitted Solution:
```
print(2**(2+int(input()))-2)
``` | instruction | 0 | 58,775 | 5 | 117,550 |
Yes | output | 1 | 58,775 | 5 | 117,551 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14
Submitted Solution:
```
n=int(input())
f=[2]
for x in range(1,n+1):
f.append(f[x-1]*2+2)
print (f[n])
``` | instruction | 0 | 58,776 | 5 | 117,552 |
Yes | output | 1 | 58,776 | 5 | 117,553 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14
Submitted Solution:
```
x = int(input())
def f(x):
if x == 1:
return 7
else:
return f(x-1) * 2 + 1
ans = f(x) - 1
print(ans)
``` | instruction | 0 | 58,777 | 5 | 117,554 |
Yes | output | 1 | 58,777 | 5 | 117,555 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14
Submitted Solution:
```
x = int(input())
now = 3
for _ in range(x):
now = now*2+1
print(now-1)
``` | instruction | 0 | 58,778 | 5 | 117,556 |
Yes | output | 1 | 58,778 | 5 | 117,557 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14
Submitted Solution:
```
print(4<<int(input())-2)
``` | instruction | 0 | 58,779 | 5 | 117,558 |
No | output | 1 | 58,779 | 5 | 117,559 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14
Submitted Solution:
```
print((4<<int(input())+2)-2)
``` | instruction | 0 | 58,780 | 5 | 117,560 |
No | output | 1 | 58,780 | 5 | 117,561 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a cord whose length is a positive integer. We will perform the following condition until the length of the cord becomes at most 2:
* Operation: Cut the rope at two positions to obtain three cords, each with a length of a positive integer. Among these, discard one with the longest length and one with the shortest length, and keep the remaining one.
Let f(N) be the maximum possible number of times to perform this operation, starting with a cord with the length N.
You are given a positive integer X. Find the maximum integer N such that f(N)=X.
Constraints
* 1 \leq X \leq 40
Input
The input is given from Standard Input in the following format:
X
Output
Print the value of the maximum integer N such that f(N)=X.
Example
Input
2
Output
14
Submitted Solution:
```
a=[-1]*10000000
def f(n):
if a[n]!=-1:
return a[n]
if n<=2:
a[n]=0
return a[n]
for i in range(1,n//3+1):
for j in range(n//3,n):
k=n-i-j
if not(i<=k and k<=j):
continue
a[n]=max(a[n],f(k)+1)
return a[n]
x=int(input())
i=3
while f(i)!=x:
i+=1
while f(i)==x:
i+=1
print(i-1)
``` | instruction | 0 | 58,781 | 5 | 117,562 |
No | output | 1 | 58,781 | 5 | 117,563 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
2 10
Warsaw Petersburg
3
Kiev Moscow Petersburg
150 120
3
Moscow Minsk Warsaw
100 150
Output
380 1 | instruction | 0 | 58,801 | 5 | 117,602 |
"Correct Solution:
```
from heapq import heappush, heappop
import sys
def solve():
readline = sys.stdin.readline
write = sys.stdout.write
N, TI = map(int, readline().split())
A, B = readline().split()
S = []; T = []; X = []
L = 0
L = 0
NA = set()
for i in range(N):
a = int(readline())
*Si, = readline().split()
*Ti, = map(int, readline().split())
for s in Si:
NA.add(s)
X.append(a)
S.append(Si); T.append(Ti)
L += a
M = len(NA); L += M
MP = {e: i for i, e in enumerate(NA)}
G = [[] for i in range(L)]
cur = M
INF = 10**18
PN = 10**9
for i in range(N):
a = X[i]; Si = S[i]; Ti = T[i]
prv = v = MP[Si[0]]
G[v].append((cur, 1))
G[cur].append((v, TI*PN))
cur += 1
for j in range(a-1):
v = MP[Si[j+1]]; t = Ti[j]
G[v].append((cur, 1))
G[cur].append((v, TI*PN))
G[cur-1].append((cur, t*PN))
G[cur].append((cur-1, t*PN))
cur += 1
prv = v
D = [INF]*L
s = MP[A]; g = MP[B]
D[s] = 0
que = [(0, s)]
while que:
cost, v = heappop(que)
if D[v] < cost:
continue
for w, d in G[v]:
if cost + d < D[w]:
D[w] = r = cost + d
heappush(que, (r, w))
if D[g] == INF:
write("-1\n")
else:
d, k = divmod(D[g], PN)
write("%d %d\n" % (d-TI, k-1))
solve()
``` | output | 1 | 58,801 | 5 | 117,603 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...
Your task is to print the k-th digit of this sequence.
Input
The first and only line contains integer k (1 ≤ k ≤ 10^{12}) — the position to process (1-based index).
Output
Print the k-th digit of the resulting infinite sequence.
Examples
Input
7
Output
7
Input
21
Output
5
Submitted Solution:
```
###################### BLOCK 183 ########################
"""import math
lis=[]
def Sieve(n):
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
for p in range(2, n):
if prime[p]:
lis.append(p)
Sieve(3675788)
p=1009
q=3643
n=p*q
phi=(q-1)*(p-1)
for i in range(phi):
if(i in lis):
"""
################################ BLOCK problem 58 ####################
"""lis=[]
def Sieve(n):
prime = [True for i in range(n+1)]
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
for p in range(2, n):
if prime[p]:
lis.append(p)
Sieve(10**6)
def printSpiral(n):
lis1=[]
for i in range(0, n):
for j in range(0, n):
# Finds minimum of four inputs
x = min(min(i, j), min(n-1-i, n-1-j))
# For upper right half
if(i <= j):
lis1.append((n-2*x)*(n-2*x)-(i-x)-(j-x))
# For lower left half
else:
lis1.append((n-2*x-2)*(n-2*x-2)+(i-x)+(j-x))
return lis1
def fun(n):
l=printSpiral(n)
lis3=[]
for i in range(n):
if(i==0):
lis3.append(l[:n])
else:
lis3.append(l[n*i:n*i+n])
count=0
for i in range(n):
for j in range(n):
if((i==j or i+j==n-1) and (lis3[i][j] in lis)):
count+=1
if(count/(2*n-1) *100>10):
return True
return False
for i in range(4,10**6):
if(fun(i)==True):
print(i)
"""
######################## BLOCK PROBLEM 79 ############
"""import re
str = "The rain in Spain"
x = re.findall("[a-m]", str)
print(x)
"""
######################## BLOCK PROBLEM 378 ############
"""k=20
n=k*(k+1)
n//=2
lis=[0]*(n+1)
for i in range(1,n+1):
for j in range(i,n+1,i):
lis[j]+=1
l=[]
for i in range(1,k+1):
l.append(lis[(i*(i+1))//2-1])
co=0
for i in range(1,len(l)):
for j in range(i,len(l)):
for k1 in range(j,len(l)):
if(l[i]>l[j] and l[j]>l[k1]):
co+=1
print(l[i],l[j],l[k1])
print(co)
"""
######################## PROBLEM 345,401, #######################
"""n=10000000
sigma2=[0]*(n+1)
for i in range(1,n+1):
for j in range(i,n+1,i):
sigma2[j]+=i**2
print(sum(sigma2[1:n+1])%10**9)
import random
def is_Prime(n):
Miller-Rabin primality test.
A return value of False means n is certainly not prime. A return value of
True means n is very likely a prime.
if n!=int(n):
return False
n=int(n)
#Miller-Rabin test for prime
if n==0 or n==1 or n==4 or n==6 or n==8 or n==9:
return False
if n==2 or n==3 or n==5 or n==7:
return True
s = 0
d = n-1
while d%2==0:
d>>=1
s+=1
assert(2**s * d == n-1)
def trial_composite(a):
if pow(a, d, n) == 1:
return False
for i in range(s):
if pow(a, 2**i * d, n) == n-1:
return False
return True
for i in range(8):#number of trials
a = random.randrange(2, n)
if trial_composite(a):
return False
return True
"""
############### pronlem 407##########
"""
import math
n=100
su=0
largestprime=[0]*(n+1)
largestprime[1]=1
for i in range(1,n+1):
if(largestprime[i]==1):
for j in range(i,n+1,i):
largestprime[j]=i
print(largestprime)
for i in range(1,n+1):
if(largestprime[i]==i):
su+=1
else:
su+=largestprime[i]
print(su)
"""
###################### PROBLEM 113 ###########
"""def bouncy(n):
lis=[]
while(n):
lis.append(n%10)
n//=10
lis=list(reversed(lis))
slis=list(sorted(lis))
rlis=list(sorted(lis,reverse=True))
if(lis==slis or lis==rlis):
return False
return True
n=10000
num=0
den=100
for i in range(101,n):
#print(i,bouncy(i))
if(bouncy(i)):
num+=1
den+=1
if(num==den):
print(i)
break
print(num)
"""
######################## practice ########
"""
file=open("/Users/VS/Desktop/vij.txt","r")
lis=[]
for line in file:
l=line.split(",")
for i in l:
lis.append(int(i))
print(lis)
"""
############################ practise 145 ########
"""def odd_digit(n):
while(n):
x=n%10
if(x%2==0):
return False
n//=10
return True
n=1000000
lis=[]
for i in range(100000,100000+200):
if(i not in lis and i%10!=0):
a=int(''.join(reversed(str(i))))
if(odd_digit(i+a)):
print(i)
lis.append(i)
lis.append(a)
print(len(lis))
"""
############### PROBLEM 104 ##############
n=int(input())-1
x=1
y=9
while n>x*y:
n-=x*y
x+=1
y*=10
a=str(10**(x-1)+n//x)[n%x]
print(int(a))
``` | instruction | 0 | 58,905 | 5 | 117,810 |
Yes | output | 1 | 58,905 | 5 | 117,811 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...
Your task is to print the k-th digit of this sequence.
Input
The first and only line contains integer k (1 ≤ k ≤ 10^{12}) — the position to process (1-based index).
Output
Print the k-th digit of the resulting infinite sequence.
Examples
Input
7
Output
7
Input
21
Output
5
Submitted Solution:
```
import sys
import bisect
from bisect import bisect_left as lb
from bisect import bisect_right as rb
input_=lambda: sys.stdin.readline().strip("\r\n")
from math import log
from math import gcd
from math import atan2,acos
from random import randint
sa=lambda :input_()
sb=lambda:int(input_())
sc=lambda:input_().split()
sd=lambda:list(map(int,input_().split()))
sflo=lambda:list(map(float,input_().split()))
se=lambda:float(input_())
sf=lambda:list(input_())
flsh=lambda: sys.stdout.flush()
#sys.setrecursionlimit(10**6)
mod=10**9+7
mod1=998244353
gp=[]
cost=[]
dp=[]
mx=[]
ans1=[]
ans2=[]
special=[]
specnode=[]
a=0
kthpar=[]
def dfs2(root,par):
if par!=-1:
dp[root]=dp[par]+1
for i in range(1,20):
if kthpar[root][i-1]!=-1:
kthpar[root][i]=kthpar[kthpar[root][i-1]][i-1]
for child in gp[root]:
if child==par:continue
kthpar[child][0]=root
dfs(child,root)
ans=0
b=[]
vis=[]
tot=0
def dfs(root):
global tot,vis,gp
for child in gp[root]:
if vis[child]==0:
tot+=1
vis[child]=1
dfs(child)
pre=[[] for i in range(3)]
def hnbhai(tc):
n=sb()
d,num=0,1
while num<=n:
num+=9*(d+1)*(10**d)
d+=1
num-=9*(d)*(10**(d-1))
ans=str(10**(d-1)+(n-num)//d)
print(ans[(n-num)%d])
for _ in range(1):
hnbhai(_+1)
``` | instruction | 0 | 58,907 | 5 | 117,814 |
Yes | output | 1 | 58,907 | 5 | 117,815 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...
Your task is to print the k-th digit of this sequence.
Input
The first and only line contains integer k (1 ≤ k ≤ 10^{12}) — the position to process (1-based index).
Output
Print the k-th digit of the resulting infinite sequence.
Examples
Input
7
Output
7
Input
21
Output
5
Submitted Solution:
```
a= int(input())
i=1
amount=a
while amount>(10**i):
amount =amount - i*((10**i)-(10**(i-1)))
i=i+1
x= amount//i
y=amount%i
# print(10**2)
# print(amount)
# print(i)
# print(x)
# print(y)
if y==0:
if i==1:
print(x%10)
else:
print(((10**(i-1)-10**(i-2)) + x)%10)
else:
if i==1:
print(x%10)
else:
print((((10**(i-1)-10**(i-2)) + x + 1)//(10**(y-1)))%10)
``` | instruction | 0 | 58,908 | 5 | 117,816 |
No | output | 1 | 58,908 | 5 | 117,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's write all the positive integer numbers one after another from 1 without any delimiters (i.e. as a single string). It will be the infinite sequence starting with 123456789101112131415161718192021222324252627282930313233343536...
Your task is to print the k-th digit of this sequence.
Input
The first and only line contains integer k (1 ≤ k ≤ 10^{12}) — the position to process (1-based index).
Output
Print the k-th digit of the resulting infinite sequence.
Examples
Input
7
Output
7
Input
21
Output
5
Submitted Solution:
```
k = int(input())
c = 9
s = 1
while k > c * s:
k -= c * s
c *= 10
s += 1
n = (10**(s - 1) if s > 1 else 0) + (k + 1) // s - 1
idx = (k - 1) % s
print(str(n)[idx])
``` | instruction | 0 | 58,910 | 5 | 117,820 |
No | output | 1 | 58,910 | 5 | 117,821 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got an array a, consisting of n integers a1, a2, ..., an. You are allowed to perform two operations on this array:
1. Calculate the sum of current array elements on the segment [l, r], that is, count value al + al + 1 + ... + ar.
2. Apply the xor operation with a given number x to each array element on the segment [l, r], that is, execute <image>. This operation changes exactly r - l + 1 array elements.
Expression <image> means applying bitwise xor operation to numbers x and y. The given operation exists in all modern programming languages, for example in language C++ and Java it is marked as "^", in Pascal — as "xor".
You've got a list of m operations of the indicated type. Your task is to perform all given operations, for each sum query you should print the result you get.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the size of the array. The second line contains space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 106) — the original array.
The third line contains integer m (1 ≤ m ≤ 5·104) — the number of operations with the array. The i-th of the following m lines first contains an integer ti (1 ≤ ti ≤ 2) — the type of the i-th query. If ti = 1, then this is the query of the sum, if ti = 2, then this is the query to change array elements. If the i-th operation is of type 1, then next follow two integers li, ri (1 ≤ li ≤ ri ≤ n). If the i-th operation is of type 2, then next follow three integers li, ri, xi (1 ≤ li ≤ ri ≤ n, 1 ≤ xi ≤ 106). The numbers on the lines are separated by single spaces.
Output
For each query of type 1 print in a single line the sum of numbers on the given segment. Print the answers to the queries in the order in which the queries go in the input.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams, or the %I64d specifier.
Examples
Input
5
4 10 3 13 7
8
1 2 4
2 1 3 3
1 2 4
1 3 3
2 2 5 5
1 1 5
2 1 2 10
1 2 3
Output
26
22
0
34
11
Input
6
4 7 4 0 7 3
5
2 2 3 8
1 1 5
2 3 5 1
2 4 5 6
1 2 3
Output
38
28
Submitted Solution:
```
import math
arraySize = int(input())
sqrtSize = math.ceil((math.sqrt(arraySize)))
array = list(map(int, input().split()))
listOfLists = []
listofSums = []
base = 0
cap = sqrtSize
for x in range(sqrtSize):
tempList = array[base:cap]
if len(tempList) < sqrtSize:
diff = sqrtSize - len(tempList)
tempList.extend([0]*diff)
listOfLists.append(tempList)
listofSums.append(sum(tempList))
base = cap
cap = cap + sqrtSize
numQueries = int(input())
for x in range(numQueries):
command = list(map(int, input().split()))
total = 0
if command[0] == 1:
left = command[1]
leftShift = math.ceil(left/sqrtSize) - 1
right = command[2]
rightShift = math.ceil(right/sqrtSize) - 1
if int(left%sqrtSize) != 0:
leftIndex = int(left%sqrtSize) - 1
else:
leftIndex = sqrtSize - 1
if int(right%sqrtSize) != 0:
rightIndex = int(right%sqrtSize) - 1
else:
rightIndex = sqrtSize - 1
if leftShift != rightShift:
total = sum(listofSums[leftShift+1:rightShift]) + sum(listOfLists[leftShift][leftIndex:]) + sum(listOfLists[rightShift][:rightIndex + 1])
else:
total = sum(listOfLists[leftShift][int(leftIndex):int(rightIndex) + 1])
print(total)
else:
left = command[1]
right = command[2]
xorVal = command[3]
leftShift = math.ceil(left/sqrtSize) - 1
rightShift = math.ceil(right/sqrtSize) - 1
if int(left%sqrtSize) != 0:
leftIndex = int(left%sqrtSize) - 1
else:
leftIndex = sqrtSize - 1
if int(right%sqrtSize) != 0:
rightIndex = int(right%sqrtSize) - 1
else:
rightIndex = sqrtSize - 1
if leftShift != rightShift:
for k in range(len(listOfLists[leftShift][leftIndex:])):
listOfLists[leftShift][leftIndex + k] = listOfLists[leftShift][leftIndex + k] ^ xorVal
else:
listofSums[leftShift] = sum(listOfLists[leftShift])
for j in range(len(listOfLists[rightShift][:rightIndex + 1])):
listOfLists[rightShift][j] = listOfLists[rightShift][j] ^ xorVal
else:
listofSums[rightShift] = sum(listOfLists[rightShift])
for i in listOfLists[leftShift + 1:rightShift]:
for h in range(len(i)):
i[h] = i[h] ^ xorVal
else:
for g in range(len(listOfLists[leftShift][int(leftIndex):int(rightIndex) + 1])):
listOfLists[leftShift][leftIndex + g] = listOfLists[leftShift][leftIndex + g] ^ xorVal
``` | instruction | 0 | 59,143 | 5 | 118,286 |
No | output | 1 | 59,143 | 5 | 118,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got an array a, consisting of n integers a1, a2, ..., an. You are allowed to perform two operations on this array:
1. Calculate the sum of current array elements on the segment [l, r], that is, count value al + al + 1 + ... + ar.
2. Apply the xor operation with a given number x to each array element on the segment [l, r], that is, execute <image>. This operation changes exactly r - l + 1 array elements.
Expression <image> means applying bitwise xor operation to numbers x and y. The given operation exists in all modern programming languages, for example in language C++ and Java it is marked as "^", in Pascal — as "xor".
You've got a list of m operations of the indicated type. Your task is to perform all given operations, for each sum query you should print the result you get.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the size of the array. The second line contains space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 106) — the original array.
The third line contains integer m (1 ≤ m ≤ 5·104) — the number of operations with the array. The i-th of the following m lines first contains an integer ti (1 ≤ ti ≤ 2) — the type of the i-th query. If ti = 1, then this is the query of the sum, if ti = 2, then this is the query to change array elements. If the i-th operation is of type 1, then next follow two integers li, ri (1 ≤ li ≤ ri ≤ n). If the i-th operation is of type 2, then next follow three integers li, ri, xi (1 ≤ li ≤ ri ≤ n, 1 ≤ xi ≤ 106). The numbers on the lines are separated by single spaces.
Output
For each query of type 1 print in a single line the sum of numbers on the given segment. Print the answers to the queries in the order in which the queries go in the input.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams, or the %I64d specifier.
Examples
Input
5
4 10 3 13 7
8
1 2 4
2 1 3 3
1 2 4
1 3 3
2 2 5 5
1 1 5
2 1 2 10
1 2 3
Output
26
22
0
34
11
Input
6
4 7 4 0 7 3
5
2 2 3 8
1 1 5
2 3 5 1
2 4 5 6
1 2 3
Output
38
28
Submitted Solution:
```
import math
arraySize = int(input())
sqrtSize = math.ceil((math.sqrt(arraySize)))
array = list(map(int, input().split()))
listOfLists = []
listofSums = []
base = 0
cap = sqrtSize
for x in range(sqrtSize):
tempList = array[base:cap]
if len(tempList) < sqrtSize:
diff = sqrtSize - len(tempList)
tempList.extend([0]*diff)
listOfLists.append(tempList)
listofSums.append(sum(tempList))
base = cap
cap = cap + sqrtSize
numQueries = int(input())
for x in range(numQueries):
command = list(map(int, input().split()))
total = 0
if command[0] == 1:
left = command[1]
leftShift = math.ceil(left/sqrtSize) - 1
right = command[2]
rightShift = math.ceil(right/sqrtSize) - 1
if int(left%sqrtSize) != 0:
leftIndex = int(left%sqrtSize) - 1
else:
leftIndex = sqrtSize - 1
if int(right%sqrtSize) != 0:
rightIndex = int(right%sqrtSize) - 1
else:
rightIndex = sqrtSize - 1
if leftShift != rightShift:
total = sum(listofSums[leftShift+1:rightShift])
for x in listOfLists[leftShift][leftIndex:]:
total += x
for y in listOfLists[rightShift][:rightIndex + 1]:
total += y
else:
total = sum(listOfLists[leftShift][int(leftIndex):int(rightIndex) + 1])
print(total)
else:
left = command[1]
right = command[2]
xorVal = command[3]
leftShift = math.ceil(left/sqrtSize) - 1
rightShift = math.ceil(right/sqrtSize) - 1
if int(left%sqrtSize) != 0:
leftIndex = int(left%sqrtSize) - 1
else:
leftIndex = sqrtSize - 1
if int(right%sqrtSize) != 0:
rightIndex = int(right%sqrtSize) - 1
else:
rightIndex = sqrtSize - 1
if leftShift != rightShift:
for k in range(len(listOfLists[leftShift][leftIndex:])):
listOfLists[leftShift][leftIndex + k] = listOfLists[leftShift][leftIndex + k] ^ xorVal
for j in range(len(listOfLists[rightShift][:rightIndex + 1])):
listOfLists[rightShift][j] = listOfLists[rightShift][j] ^ xorVal
for i in listOfLists[leftShift + 1:rightShift]:
for h in range(len(i)):
i[h] = i[h] ^ xorVal
else:
for g in range(len(listOfLists[leftShift][int(leftIndex):int(rightIndex) + 1])):
listOfLists[leftShift][leftIndex + g] = listOfLists[leftShift][leftIndex + g] ^ xorVal
``` | instruction | 0 | 59,144 | 5 | 118,288 |
No | output | 1 | 59,144 | 5 | 118,289 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got an array a, consisting of n integers a1, a2, ..., an. You are allowed to perform two operations on this array:
1. Calculate the sum of current array elements on the segment [l, r], that is, count value al + al + 1 + ... + ar.
2. Apply the xor operation with a given number x to each array element on the segment [l, r], that is, execute <image>. This operation changes exactly r - l + 1 array elements.
Expression <image> means applying bitwise xor operation to numbers x and y. The given operation exists in all modern programming languages, for example in language C++ and Java it is marked as "^", in Pascal — as "xor".
You've got a list of m operations of the indicated type. Your task is to perform all given operations, for each sum query you should print the result you get.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the size of the array. The second line contains space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 106) — the original array.
The third line contains integer m (1 ≤ m ≤ 5·104) — the number of operations with the array. The i-th of the following m lines first contains an integer ti (1 ≤ ti ≤ 2) — the type of the i-th query. If ti = 1, then this is the query of the sum, if ti = 2, then this is the query to change array elements. If the i-th operation is of type 1, then next follow two integers li, ri (1 ≤ li ≤ ri ≤ n). If the i-th operation is of type 2, then next follow three integers li, ri, xi (1 ≤ li ≤ ri ≤ n, 1 ≤ xi ≤ 106). The numbers on the lines are separated by single spaces.
Output
For each query of type 1 print in a single line the sum of numbers on the given segment. Print the answers to the queries in the order in which the queries go in the input.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams, or the %I64d specifier.
Examples
Input
5
4 10 3 13 7
8
1 2 4
2 1 3 3
1 2 4
1 3 3
2 2 5 5
1 1 5
2 1 2 10
1 2 3
Output
26
22
0
34
11
Input
6
4 7 4 0 7 3
5
2 2 3 8
1 1 5
2 3 5 1
2 4 5 6
1 2 3
Output
38
28
Submitted Solution:
```
if __name__=="__main__":
n = int(input())
a = [int(x) for x in input().split()]
q = int(input())
for i in range(q):
t = [int(x) for x in input().split()]
l=t[0]
r=t[1]
if(len(t)==3):
sum=0
for i in range(l-1,r):
sum+=a[i]
print(sum)
else:
k = t[2]
for i in range(l-1,r):
a[i]^=k
``` | instruction | 0 | 59,145 | 5 | 118,290 |
No | output | 1 | 59,145 | 5 | 118,291 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got an array a, consisting of n integers a1, a2, ..., an. You are allowed to perform two operations on this array:
1. Calculate the sum of current array elements on the segment [l, r], that is, count value al + al + 1 + ... + ar.
2. Apply the xor operation with a given number x to each array element on the segment [l, r], that is, execute <image>. This operation changes exactly r - l + 1 array elements.
Expression <image> means applying bitwise xor operation to numbers x and y. The given operation exists in all modern programming languages, for example in language C++ and Java it is marked as "^", in Pascal — as "xor".
You've got a list of m operations of the indicated type. Your task is to perform all given operations, for each sum query you should print the result you get.
Input
The first line contains integer n (1 ≤ n ≤ 105) — the size of the array. The second line contains space-separated integers a1, a2, ..., an (0 ≤ ai ≤ 106) — the original array.
The third line contains integer m (1 ≤ m ≤ 5·104) — the number of operations with the array. The i-th of the following m lines first contains an integer ti (1 ≤ ti ≤ 2) — the type of the i-th query. If ti = 1, then this is the query of the sum, if ti = 2, then this is the query to change array elements. If the i-th operation is of type 1, then next follow two integers li, ri (1 ≤ li ≤ ri ≤ n). If the i-th operation is of type 2, then next follow three integers li, ri, xi (1 ≤ li ≤ ri ≤ n, 1 ≤ xi ≤ 106). The numbers on the lines are separated by single spaces.
Output
For each query of type 1 print in a single line the sum of numbers on the given segment. Print the answers to the queries in the order in which the queries go in the input.
Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams, or the %I64d specifier.
Examples
Input
5
4 10 3 13 7
8
1 2 4
2 1 3 3
1 2 4
1 3 3
2 2 5 5
1 1 5
2 1 2 10
1 2 3
Output
26
22
0
34
11
Input
6
4 7 4 0 7 3
5
2 2 3 8
1 1 5
2 3 5 1
2 4 5 6
1 2 3
Output
38
28
Submitted Solution:
```
import math
n = "yes"
arraySize = int(input())
sqrtSize = math.ceil((math.sqrt(arraySize)))
array = list(map(int, input().split()))
listOfLists = []
listofSums = []
base = 0
cap = sqrtSize
for x in range(sqrtSize):
tempList = array[base:cap]
if len(tempList) < sqrtSize:
diff = sqrtSize - len(tempList)
tempList.extend([0]*diff)
listOfLists.append(tempList)
listofSums.append(sum(tempList))
base = cap
cap = cap + sqrtSize
numQueries = int(input())
for x in range(numQueries):
command = list(map(int, input().split()))
total = 0
if command[0] == 1:
left = command[1]
leftShift = math.ceil(left/sqrtSize) - 1
right = command[2]
rightShift = math.ceil(right/sqrtSize) - 1
if int(left%sqrtSize) != 0:
leftIndex = int(left%sqrtSize) - 1
else:
leftIndex = sqrtSize - 1
if int(right%sqrtSize) != 0:
rightIndex = int(right%sqrtSize) - 1
else:
rightIndex = sqrtSize - 1
if leftShift != rightShift:
total = sum(listofSums[leftShift+1:rightShift]) + sum(listOfLists[leftShift][leftIndex:]) + sum(listOfLists[rightShift][:rightIndex + 1])
else:
total = sum(listOfLists[leftShift][int(leftIndex):int(rightIndex) + 1])
print(total)
else:
left = command[1]
right = command[2]
xorVal = command[3]
leftShift = math.ceil(left/sqrtSize) - 1
rightShift = math.ceil(right/sqrtSize) - 1
if int(left%sqrtSize) != 0:
leftIndex = int(left%sqrtSize) - 1
else:
leftIndex = sqrtSize - 1
if int(right%sqrtSize) != 0:
rightIndex = int(right%sqrtSize) - 1
else:
rightIndex = sqrtSize - 1
if leftShift != rightShift:
for k in range(len(listOfLists[leftShift][leftIndex:])):
listOfLists[leftShift][leftIndex + k] = listOfLists[leftShift][leftIndex + k] ^ xorVal
else:
listofSums[leftShift] = sum(listOfLists[leftShift])
for j in range(len(listOfLists[rightShift][:rightIndex + 1])):
listOfLists[rightShift][j] = listOfLists[rightShift][j] ^ xorVal
else:
listofSums[rightShift] = sum(listOfLists[rightShift])
for i in listOfLists[leftShift + 1:rightShift]:
for h in range(len(i)):
i[h] = i[h] ^ xorVal
else:
for g in range(len(listOfLists[leftShift][int(leftIndex):int(rightIndex) + 1])):
listOfLists[leftShift][leftIndex + g] = listOfLists[leftShift][leftIndex + g] ^ xorVal
``` | instruction | 0 | 59,146 | 5 | 118,292 |
No | output | 1 | 59,146 | 5 | 118,293 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Chris is very keen on his toy blocks. His teacher, however, wants Chris to solve more problems, so he decided to play a trick on Chris.
There are exactly s blocks in Chris's set, each block has a unique number from 1 to s. Chris's teacher picks a subset of blocks X and keeps it to himself. He will give them back only if Chris can pick such a non-empty subset Y from the remaining blocks, that the equality holds:
<image> "Are you kidding me?", asks Chris.
For example, consider a case where s = 8 and Chris's teacher took the blocks with numbers 1, 4 and 5. One way for Chris to choose a set is to pick the blocks with numbers 3 and 6, see figure. Then the required sums would be equal: (1 - 1) + (4 - 1) + (5 - 1) = (8 - 3) + (8 - 6) = 7.
<image>
However, now Chris has exactly s = 106 blocks. Given the set X of blocks his teacher chooses, help Chris to find the required set Y!
Input
The first line of input contains a single integer n (1 ≤ n ≤ 5·105), the number of blocks in the set X. The next line contains n distinct space-separated integers x1, x2, ..., xn (1 ≤ xi ≤ 106), the numbers of the blocks in X.
Note: since the size of the input and output could be very large, don't use slow output techniques in your language. For example, do not use input and output streams (cin, cout) in C++.
Output
In the first line of output print a single integer m (1 ≤ m ≤ 106 - n), the number of blocks in the set Y. In the next line output m distinct space-separated integers y1, y2, ..., ym (1 ≤ yi ≤ 106), such that the required equality holds. The sets X and Y should not intersect, i.e. xi ≠ yj for all i, j (1 ≤ i ≤ n; 1 ≤ j ≤ m). It is guaranteed that at least one solution always exists. If there are multiple solutions, output any of them.
Examples
Input
3
1 4 5
Output
2
999993 1000000
Input
1
1
Output
1
1000000
Submitted Solution:
```
import sys
input = sys.stdin.readline
I = lambda : list(map(int,input().split()))
n,=I()
x=I()
an=[]
su=sum(x)-n
vi=[0]*(10**6+1)
for i in range(n):
vi[x[i]]=1
rs=0
i=1
while rs<su and i<10**6+1:
if vi[i]==0:
vi[i]=1
rs+=10**6-i
an.append(i)
if rs>su:
rs-=10**6-i
an.pop()
break
i+=1
i=10**6
while rs<=su and i>0:
if vi[i]==0:
vi[i]=1
rs+=10**6-i
an.append(i)
if rs==su:
break
if rs>su or (su-rs)<(10**6-i):
rs-=10**6-i
an.pop()
i-=1
print(len(an))
print(*an)
``` | instruction | 0 | 59,199 | 5 | 118,398 |
No | output | 1 | 59,199 | 5 | 118,399 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Chris is very keen on his toy blocks. His teacher, however, wants Chris to solve more problems, so he decided to play a trick on Chris.
There are exactly s blocks in Chris's set, each block has a unique number from 1 to s. Chris's teacher picks a subset of blocks X and keeps it to himself. He will give them back only if Chris can pick such a non-empty subset Y from the remaining blocks, that the equality holds:
<image> "Are you kidding me?", asks Chris.
For example, consider a case where s = 8 and Chris's teacher took the blocks with numbers 1, 4 and 5. One way for Chris to choose a set is to pick the blocks with numbers 3 and 6, see figure. Then the required sums would be equal: (1 - 1) + (4 - 1) + (5 - 1) = (8 - 3) + (8 - 6) = 7.
<image>
However, now Chris has exactly s = 106 blocks. Given the set X of blocks his teacher chooses, help Chris to find the required set Y!
Input
The first line of input contains a single integer n (1 ≤ n ≤ 5·105), the number of blocks in the set X. The next line contains n distinct space-separated integers x1, x2, ..., xn (1 ≤ xi ≤ 106), the numbers of the blocks in X.
Note: since the size of the input and output could be very large, don't use slow output techniques in your language. For example, do not use input and output streams (cin, cout) in C++.
Output
In the first line of output print a single integer m (1 ≤ m ≤ 106 - n), the number of blocks in the set Y. In the next line output m distinct space-separated integers y1, y2, ..., ym (1 ≤ yi ≤ 106), such that the required equality holds. The sets X and Y should not intersect, i.e. xi ≠ yj for all i, j (1 ≤ i ≤ n; 1 ≤ j ≤ m). It is guaranteed that at least one solution always exists. If there are multiple solutions, output any of them.
Examples
Input
3
1 4 5
Output
2
999993 1000000
Input
1
1
Output
1
1000000
Submitted Solution:
```
n = int(input())
a = input().split()
s = 0
for i in range(n):
a[i] = int(a[i])
s += a[i]-1
a.sort()
print(s)
def search(k, a):
l = 0
r = n-1
if k > a[r] or k < a[l]:
return -1
while l<=r:
m = (l+r)//2
if k < a[m]:
r = m-1
elif k > a[m]:
l = m+1
else:
return m
return -1
c = [s]
while s >= 1:
check = True
for i in c:
if search(1000000-i, a) != -1:
check = False
if check:
for i in c:
print(1000000-i, end=' ')
exit()
else:
b = []
for i in a:
b.append(i//2)
c = b
if s == 0:
print(1000000)
``` | instruction | 0 | 59,200 | 5 | 118,400 |
No | output | 1 | 59,200 | 5 | 118,401 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Chris is very keen on his toy blocks. His teacher, however, wants Chris to solve more problems, so he decided to play a trick on Chris.
There are exactly s blocks in Chris's set, each block has a unique number from 1 to s. Chris's teacher picks a subset of blocks X and keeps it to himself. He will give them back only if Chris can pick such a non-empty subset Y from the remaining blocks, that the equality holds:
<image> "Are you kidding me?", asks Chris.
For example, consider a case where s = 8 and Chris's teacher took the blocks with numbers 1, 4 and 5. One way for Chris to choose a set is to pick the blocks with numbers 3 and 6, see figure. Then the required sums would be equal: (1 - 1) + (4 - 1) + (5 - 1) = (8 - 3) + (8 - 6) = 7.
<image>
However, now Chris has exactly s = 106 blocks. Given the set X of blocks his teacher chooses, help Chris to find the required set Y!
Input
The first line of input contains a single integer n (1 ≤ n ≤ 5·105), the number of blocks in the set X. The next line contains n distinct space-separated integers x1, x2, ..., xn (1 ≤ xi ≤ 106), the numbers of the blocks in X.
Note: since the size of the input and output could be very large, don't use slow output techniques in your language. For example, do not use input and output streams (cin, cout) in C++.
Output
In the first line of output print a single integer m (1 ≤ m ≤ 106 - n), the number of blocks in the set Y. In the next line output m distinct space-separated integers y1, y2, ..., ym (1 ≤ yi ≤ 106), such that the required equality holds. The sets X and Y should not intersect, i.e. xi ≠ yj for all i, j (1 ≤ i ≤ n; 1 ≤ j ≤ m). It is guaranteed that at least one solution always exists. If there are multiple solutions, output any of them.
Examples
Input
3
1 4 5
Output
2
999993 1000000
Input
1
1
Output
1
1000000
Submitted Solution:
```
import sys
from math import gcd,sqrt,ceil
from collections import defaultdict,Counter,deque
import math
# input=sys.stdin.readline
# def print(x):
# sys.stdout.write(str(x)+"\n")
# sys.stdout=open("CP1/output.txt",'w')
# sys.stdin=open("CP1/input.txt",'r')
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# import sys
# import io, os
# input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
def get_sum(bit,i):
s = 0
i+=1
while i>0:
s+=bit[i]
i-=i&(-i)
return s
def update(bit,n,i,v):
i+=1
while i<=n:
bit[i]+=v
i+=i&(-i)
def modInverse(b,m):
g = math.gcd(b, m)
if (g != 1):
return -1
else:
return pow(b, m - 2, m)
n = int(input())
l = list(map(int,input().split()))
ha = 0
for i in range(n):
ha+=l[i]-1
lo = 0
seti = set(l)
ans = []
s = 10**6
for i in range(1,10**6+1):
if i not in seti:
if s-i + lo<=ha:
lo+=s-i
ans.append(i)
if lo == ha:
break
# print(lo,ha)
ans.sort()
if lo!=ha:
z = ha-lo
sa = set(ans)
for i in range(len(ans)):
if 0<ans[i]-z<=s and ans[i]-z not in seti and ans[i]-z not in sa:
ans[i]-=z
break
print(len(ans))
print(*ans)
``` | instruction | 0 | 59,201 | 5 | 118,402 |
No | output | 1 | 59,201 | 5 | 118,403 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Chris is very keen on his toy blocks. His teacher, however, wants Chris to solve more problems, so he decided to play a trick on Chris.
There are exactly s blocks in Chris's set, each block has a unique number from 1 to s. Chris's teacher picks a subset of blocks X and keeps it to himself. He will give them back only if Chris can pick such a non-empty subset Y from the remaining blocks, that the equality holds:
<image> "Are you kidding me?", asks Chris.
For example, consider a case where s = 8 and Chris's teacher took the blocks with numbers 1, 4 and 5. One way for Chris to choose a set is to pick the blocks with numbers 3 and 6, see figure. Then the required sums would be equal: (1 - 1) + (4 - 1) + (5 - 1) = (8 - 3) + (8 - 6) = 7.
<image>
However, now Chris has exactly s = 106 blocks. Given the set X of blocks his teacher chooses, help Chris to find the required set Y!
Input
The first line of input contains a single integer n (1 ≤ n ≤ 5·105), the number of blocks in the set X. The next line contains n distinct space-separated integers x1, x2, ..., xn (1 ≤ xi ≤ 106), the numbers of the blocks in X.
Note: since the size of the input and output could be very large, don't use slow output techniques in your language. For example, do not use input and output streams (cin, cout) in C++.
Output
In the first line of output print a single integer m (1 ≤ m ≤ 106 - n), the number of blocks in the set Y. In the next line output m distinct space-separated integers y1, y2, ..., ym (1 ≤ yi ≤ 106), such that the required equality holds. The sets X and Y should not intersect, i.e. xi ≠ yj for all i, j (1 ≤ i ≤ n; 1 ≤ j ≤ m). It is guaranteed that at least one solution always exists. If there are multiple solutions, output any of them.
Examples
Input
3
1 4 5
Output
2
999993 1000000
Input
1
1
Output
1
1000000
Submitted Solution:
```
import sys
from math import gcd,sqrt,ceil
from collections import defaultdict,Counter,deque
import math
# input=sys.stdin.readline
# def print(x):
# sys.stdout.write(str(x)+"\n")
# sys.stdout=open("CP1/output.txt",'w')
# sys.stdin=open("CP1/input.txt",'r')
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# import sys
# import io, os
# input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
def get_sum(bit,i):
s = 0
i+=1
while i>0:
s+=bit[i]
i-=i&(-i)
return s
def update(bit,n,i,v):
i+=1
while i<=n:
bit[i]+=v
i+=i&(-i)
def modInverse(b,m):
g = math.gcd(b, m)
if (g != 1):
return -1
else:
return pow(b, m - 2, m)
n = int(input())
l = list(map(int,input().split()))
ha = 0
for i in range(n):
ha+=l[i]-1
lo = 0
seti = set(l)
ans = []
s = 10**6
for i in range(1,10**6+1):
if i not in seti:
if s-i + lo<=ha:
lo+=s-i
ans.append(i)
if lo == ha:
break
# print(lo,ha)
ans.sort()
if lo!=ha:
z = ha-lo
# ans.reverse()
if ans[-1] == s:
ans.pop()
sa = set(ans)
for i in range(len(ans)):
if 0<ans[i]-z<=s and ans[i]-z not in seti and ans[i]-z not in sa:
ans[i]-=z
break
print(len(ans))
print(*ans)
``` | instruction | 0 | 59,202 | 5 | 118,404 |
No | output | 1 | 59,202 | 5 | 118,405 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We all know that GukiZ often plays with arrays.
Now he is thinking about this problem: how many arrays a, of length n, with non-negative elements strictly less then 2l meet the following condition: <image>? Here operation <image> means bitwise AND (in Pascal it is equivalent to and, in C/C++/Java/Python it is equivalent to &), operation <image> means bitwise OR (in Pascal it is equivalent to <image>, in C/C++/Java/Python it is equivalent to |).
Because the answer can be quite large, calculate it modulo m. This time GukiZ hasn't come up with solution, and needs you to help him!
Input
First and the only line of input contains four integers n, k, l, m (2 ≤ n ≤ 1018, 0 ≤ k ≤ 1018, 0 ≤ l ≤ 64, 1 ≤ m ≤ 109 + 7).
Output
In the single line print the number of arrays satisfying the condition above modulo m.
Examples
Input
2 1 2 10
Output
3
Input
2 1 1 3
Output
1
Input
3 3 2 10
Output
9
Note
In the first sample, satisfying arrays are {1, 1}, {3, 1}, {1, 3}.
In the second sample, only satisfying array is {1, 1}.
In the third sample, satisfying arrays are {0, 3, 3}, {1, 3, 2}, {1, 3, 3}, {2, 3, 1}, {2, 3, 3}, {3, 3, 0}, {3, 3, 1}, {3, 3, 2}, {3, 3, 3}.
Submitted Solution:
```
# -*- coding: utf-8 -*-
from collections import deque
def calc(n, m):
if n == 1:
return [[1, 0], [0, 1]]
a = calc(n // 2, m)
if n % 2 == 0:
res00 = (a[0][0] * a[0][0]) % m
res00 = (res00 + a[0][0] * a[1][0]) % m
res00 = (res00 + a[0][1] * a[0][0]) % m
res01 = (a[0][0] * a[0][1]) % m
res01 = (res01 + a[0][0] * a[1][1]) % m
res01 = (res01 + a[0][1] * a[0][1]) % m
res10 = (a[1][0] * a[0][0]) % m
res10 = (res10 + a[1][0] * a[1][0]) % m
res10 = (res10 + a[1][1] * a[0][0]) % m
res11 = (a[1][0] * a[0][1]) % m
res11 = (res11 + a[1][0] * a[1][1]) % m
res11 = (res11 + a[1][1] * a[0][1]) % m
return [[res00, res01], [res10, res11]]
else:
res00 = (a[0][0] * a[0][0] * 2) % m
res00 = (res00 + a[0][0] * a[1][0]) % m
res00 = (res00 + a[0][1] * a[0][0]) % m
res00 = (res00 + a[0][1] * a[1][0]) % m
res01 = (a[0][0] * a[0][1] * 2) % m
res01 = (res01 + a[0][0] * a[1][1]) % m
res01 = (res01 + a[0][1] * a[0][1]) % m
res01 = (res01 + a[0][1] * a[1][1]) % m
res10 = (a[1][0] * a[0][0] * 2) % m
res10 = (res10 + a[1][0] * a[1][0]) % m
res10 = (res10 + a[1][1] * a[0][0]) % m
res10 = (res10 + a[1][1] * a[1][0]) % m
res11 = (a[1][0] * a[0][1] * 2) % m
res11 = (res11 + a[1][0] * a[1][1]) % m
res11 = (res11 + a[1][1] * a[0][1]) % m
res11 = (res11 + a[1][1] * a[1][1]) % m
return [[res00, res01], [res10, res11]]
def binpow(a, p, m):
if p == 0:
return 1 % m
if p == 1:
return a % m
ans = binpow(a, p // 2, m)
ans = (ans * ans) % m
if p % 2 == 1:
ans = (ans * a) % m
return ans
n, k, l, m = map(int, input().split())
ans = [0, 0]
x = calc(n, m)
ans[0] = (x[0][0] + x[0][1] + x[1][0] + x[1][1]) % m
ans[1] = ((binpow(2, n, m) - ans[0]) % m + m) % m
res = 1
for i in range(l):
res = (res * ans[k & 1]) % m
k >>= 1
if k > 0:
res = 0
print(res % m)
``` | instruction | 0 | 59,257 | 5 | 118,514 |
Yes | output | 1 | 59,257 | 5 | 118,515 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We all know that GukiZ often plays with arrays.
Now he is thinking about this problem: how many arrays a, of length n, with non-negative elements strictly less then 2l meet the following condition: <image>? Here operation <image> means bitwise AND (in Pascal it is equivalent to and, in C/C++/Java/Python it is equivalent to &), operation <image> means bitwise OR (in Pascal it is equivalent to <image>, in C/C++/Java/Python it is equivalent to |).
Because the answer can be quite large, calculate it modulo m. This time GukiZ hasn't come up with solution, and needs you to help him!
Input
First and the only line of input contains four integers n, k, l, m (2 ≤ n ≤ 1018, 0 ≤ k ≤ 1018, 0 ≤ l ≤ 64, 1 ≤ m ≤ 109 + 7).
Output
In the single line print the number of arrays satisfying the condition above modulo m.
Examples
Input
2 1 2 10
Output
3
Input
2 1 1 3
Output
1
Input
3 3 2 10
Output
9
Note
In the first sample, satisfying arrays are {1, 1}, {3, 1}, {1, 3}.
In the second sample, only satisfying array is {1, 1}.
In the third sample, satisfying arrays are {0, 3, 3}, {1, 3, 2}, {1, 3, 3}, {2, 3, 1}, {2, 3, 3}, {3, 3, 0}, {3, 3, 1}, {3, 3, 2}, {3, 3, 3}.
Submitted Solution:
```
def multiply(x, y):
global m
a = (x[0][0] * y[0][0] + x[0][1] * y[1][0]) % m
b = (x[0][0] * y[0][1] + x[0][1] * y[1][1]) % m
c = (x[1][0] * y[0][0] + x[1][1] * y[1][0]) % m
d = (x[1][0] * y[0][1] + x[1][1] * y[1][1]) % m
return [[a, b], [c, d]]
def seqs(n):
f = [[1, 1], [1, 0]]
result = [[1, 0], [0, 1]]
while n > 0:
if n % 2 == 1:
result = multiply(result, f)
n -= 1
f = multiply(f, f)
n //= 2
return result[0][1]
def power(n):
global m
result = 1
base = 2
while n > 0:
if n % 2 == 1:
result *= base
n -= 1
base *= base
base %= m
result %= m
n //= 2
return result
n, k, l, m = tuple(map(int, input().split()))
if k >= 2 ** l:
print(0)
else:
if k != 0 and l == 0:
answer = 0
else:
answer = 1 % m
s = seqs(n + 2)
total = power(n)
while l > 0:
if k % 2 == 0:
answer *= s
else:
answer *= total - s
answer %= m
k //= 2
l -= 1
print(answer)
``` | instruction | 0 | 59,258 | 5 | 118,516 |
Yes | output | 1 | 59,258 | 5 | 118,517 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We all know that GukiZ often plays with arrays.
Now he is thinking about this problem: how many arrays a, of length n, with non-negative elements strictly less then 2l meet the following condition: <image>? Here operation <image> means bitwise AND (in Pascal it is equivalent to and, in C/C++/Java/Python it is equivalent to &), operation <image> means bitwise OR (in Pascal it is equivalent to <image>, in C/C++/Java/Python it is equivalent to |).
Because the answer can be quite large, calculate it modulo m. This time GukiZ hasn't come up with solution, and needs you to help him!
Input
First and the only line of input contains four integers n, k, l, m (2 ≤ n ≤ 1018, 0 ≤ k ≤ 1018, 0 ≤ l ≤ 64, 1 ≤ m ≤ 109 + 7).
Output
In the single line print the number of arrays satisfying the condition above modulo m.
Examples
Input
2 1 2 10
Output
3
Input
2 1 1 3
Output
1
Input
3 3 2 10
Output
9
Note
In the first sample, satisfying arrays are {1, 1}, {3, 1}, {1, 3}.
In the second sample, only satisfying array is {1, 1}.
In the third sample, satisfying arrays are {0, 3, 3}, {1, 3, 2}, {1, 3, 3}, {2, 3, 1}, {2, 3, 3}, {3, 3, 0}, {3, 3, 1}, {3, 3, 2}, {3, 3, 3}.
Submitted Solution:
```
n,k,l,m=map(int,input().split())
fc={1:1,2:1}
def f(n):
if n not in fc: k=n//2;fc[n]=(f(k+1)**2+f(k)**2 if n%2 else f(k)*(2*f(k+1)-f(k)))%m
return fc[n]
s=int(k<2**l)
for i in range(l): s*=pow(2,n,m)-f(n+2) if (k>>i)%2 else f(n+2)
print(s%m)
``` | instruction | 0 | 59,259 | 5 | 118,518 |
Yes | output | 1 | 59,259 | 5 | 118,519 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We all know that GukiZ often plays with arrays.
Now he is thinking about this problem: how many arrays a, of length n, with non-negative elements strictly less then 2l meet the following condition: <image>? Here operation <image> means bitwise AND (in Pascal it is equivalent to and, in C/C++/Java/Python it is equivalent to &), operation <image> means bitwise OR (in Pascal it is equivalent to <image>, in C/C++/Java/Python it is equivalent to |).
Because the answer can be quite large, calculate it modulo m. This time GukiZ hasn't come up with solution, and needs you to help him!
Input
First and the only line of input contains four integers n, k, l, m (2 ≤ n ≤ 1018, 0 ≤ k ≤ 1018, 0 ≤ l ≤ 64, 1 ≤ m ≤ 109 + 7).
Output
In the single line print the number of arrays satisfying the condition above modulo m.
Examples
Input
2 1 2 10
Output
3
Input
2 1 1 3
Output
1
Input
3 3 2 10
Output
9
Note
In the first sample, satisfying arrays are {1, 1}, {3, 1}, {1, 3}.
In the second sample, only satisfying array is {1, 1}.
In the third sample, satisfying arrays are {0, 3, 3}, {1, 3, 2}, {1, 3, 3}, {2, 3, 1}, {2, 3, 3}, {3, 3, 0}, {3, 3, 1}, {3, 3, 2}, {3, 3, 3}.
Submitted Solution:
```
fc={0:0,1:1,2:1}
n,k,l,m=map(int,input().split())
def f(n):
if n not in fc:
k=n//2
fc[n]=(f(k+1)**2+f(k)**2 if n%2 else f(k)*(2*f(k+1)-f(k)))%m
return fc[n]
if k>=2**l: print(0), exit(0)
s=1
for i in range(l):
s*=pow(2,n,m)-f(n+2) if (k>>i)%2 else f(n+2)
print(s%m)
``` | instruction | 0 | 59,260 | 5 | 118,520 |
Yes | output | 1 | 59,260 | 5 | 118,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We all know that GukiZ often plays with arrays.
Now he is thinking about this problem: how many arrays a, of length n, with non-negative elements strictly less then 2l meet the following condition: <image>? Here operation <image> means bitwise AND (in Pascal it is equivalent to and, in C/C++/Java/Python it is equivalent to &), operation <image> means bitwise OR (in Pascal it is equivalent to <image>, in C/C++/Java/Python it is equivalent to |).
Because the answer can be quite large, calculate it modulo m. This time GukiZ hasn't come up with solution, and needs you to help him!
Input
First and the only line of input contains four integers n, k, l, m (2 ≤ n ≤ 1018, 0 ≤ k ≤ 1018, 0 ≤ l ≤ 64, 1 ≤ m ≤ 109 + 7).
Output
In the single line print the number of arrays satisfying the condition above modulo m.
Examples
Input
2 1 2 10
Output
3
Input
2 1 1 3
Output
1
Input
3 3 2 10
Output
9
Note
In the first sample, satisfying arrays are {1, 1}, {3, 1}, {1, 3}.
In the second sample, only satisfying array is {1, 1}.
In the third sample, satisfying arrays are {0, 3, 3}, {1, 3, 2}, {1, 3, 3}, {2, 3, 1}, {2, 3, 3}, {3, 3, 0}, {3, 3, 1}, {3, 3, 2}, {3, 3, 3}.
Submitted Solution:
```
n, k, l, BASE = map(int,input().split())
d = {0:1, 1:1, 2:(2 % BASE)}
def power(n):
if n == 0: return 1
if n & 1 > 0:
return (power(n-1) << 1) % BASE
u = power(n >> 1) % BASE
return u * u % BASE
def fib(n):
if d.get(n) != None:
return d[n]
if n & 1 < 1:
d[n] = (fib((n >> 1) - 1)*fib((n >> 1) - 1)+fib(n >> 1)*fib(n >> 1))%BASE
else:
d[n] = (fib((n >> 1) )*fib((n >> 1) + 1)+fib((n >> 1) - 1)*fib(n >> 1))%BASE
return d[n]
u = fib(n+1)
v = (power(n) + BASE - u) % BASE
a = 1
for i in range(l):
if k & 1 == 0:
a *= u
else:
a *= v
a %= BASE
k >>= 1
if k > 0:
a = 0
print(a)
``` | instruction | 0 | 59,261 | 5 | 118,522 |
No | output | 1 | 59,261 | 5 | 118,523 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We all know that GukiZ often plays with arrays.
Now he is thinking about this problem: how many arrays a, of length n, with non-negative elements strictly less then 2l meet the following condition: <image>? Here operation <image> means bitwise AND (in Pascal it is equivalent to and, in C/C++/Java/Python it is equivalent to &), operation <image> means bitwise OR (in Pascal it is equivalent to <image>, in C/C++/Java/Python it is equivalent to |).
Because the answer can be quite large, calculate it modulo m. This time GukiZ hasn't come up with solution, and needs you to help him!
Input
First and the only line of input contains four integers n, k, l, m (2 ≤ n ≤ 1018, 0 ≤ k ≤ 1018, 0 ≤ l ≤ 64, 1 ≤ m ≤ 109 + 7).
Output
In the single line print the number of arrays satisfying the condition above modulo m.
Examples
Input
2 1 2 10
Output
3
Input
2 1 1 3
Output
1
Input
3 3 2 10
Output
9
Note
In the first sample, satisfying arrays are {1, 1}, {3, 1}, {1, 3}.
In the second sample, only satisfying array is {1, 1}.
In the third sample, satisfying arrays are {0, 3, 3}, {1, 3, 2}, {1, 3, 3}, {2, 3, 1}, {2, 3, 3}, {3, 3, 0}, {3, 3, 1}, {3, 3, 2}, {3, 3, 3}.
Submitted Solution:
```
import math
import sys
def fib(n,m):
if n==0:
return 0
if n==1 or n==2:
return 1%m
b=n.bit_length()-1
X=1
Y=0
Z=1
k=n
while b>=0:
x=1
y=1
z=0
t=1
for i in range(0,b):
x1=x
y1=y
x=(x1*x1+y1*y1)%m
y=(x1*y1+y1*z)%m
z=(y1*y1+z*z)%m
t*=2
Y2=Y
X=(X*x+Y*y)%m
Y=(x*Y+y*Z)%m
Z=(y*Y2+z*Z)%m
k=k-t
b=k.bit_length()-1
return Y
def two(n,m):
if n==0:
return 1%m
if n==1:
return 2%m
T=1
b=n.bit_length()-1
k=n
while b>=0:
t2=1
t1=2
for i in range(0,b):
t2*=2
t1=(t1*t1)%m
k=k-t2
b=k.bit_length()-1
T*=t1
T=T%m
return T
inp=list(map(int,input().split()))
n=inp[0]
k=inp[1]
l=inp[2]
m=inp[3]
if k>=2**l:
print(0)
else:
t=1
ans=1
for i in range(0,l):
b=(k-k%t)%(2*t)
t*=2
if b==0:
ans*=fib(n+2,m)
ans=ans%m
else:
ans*=two(n,m)-fib(n+2,m)
ans=ans%m
print(ans)
``` | instruction | 0 | 59,262 | 5 | 118,524 |
No | output | 1 | 59,262 | 5 | 118,525 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We all know that GukiZ often plays with arrays.
Now he is thinking about this problem: how many arrays a, of length n, with non-negative elements strictly less then 2l meet the following condition: <image>? Here operation <image> means bitwise AND (in Pascal it is equivalent to and, in C/C++/Java/Python it is equivalent to &), operation <image> means bitwise OR (in Pascal it is equivalent to <image>, in C/C++/Java/Python it is equivalent to |).
Because the answer can be quite large, calculate it modulo m. This time GukiZ hasn't come up with solution, and needs you to help him!
Input
First and the only line of input contains four integers n, k, l, m (2 ≤ n ≤ 1018, 0 ≤ k ≤ 1018, 0 ≤ l ≤ 64, 1 ≤ m ≤ 109 + 7).
Output
In the single line print the number of arrays satisfying the condition above modulo m.
Examples
Input
2 1 2 10
Output
3
Input
2 1 1 3
Output
1
Input
3 3 2 10
Output
9
Note
In the first sample, satisfying arrays are {1, 1}, {3, 1}, {1, 3}.
In the second sample, only satisfying array is {1, 1}.
In the third sample, satisfying arrays are {0, 3, 3}, {1, 3, 2}, {1, 3, 3}, {2, 3, 1}, {2, 3, 3}, {3, 3, 0}, {3, 3, 1}, {3, 3, 2}, {3, 3, 3}.
Submitted Solution:
```
n,k,l,m=list(map(int,input().split()))
if n==5135:
print("lskjdalkjs")
else:
max = 2**l
ans =0
for i in range(max,0,-1):
for j in range(max,0,-1):
if(i&j == k):
ans = i*j;
break
print(ans)
``` | instruction | 0 | 59,263 | 5 | 118,526 |
No | output | 1 | 59,263 | 5 | 118,527 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We all know that GukiZ often plays with arrays.
Now he is thinking about this problem: how many arrays a, of length n, with non-negative elements strictly less then 2l meet the following condition: <image>? Here operation <image> means bitwise AND (in Pascal it is equivalent to and, in C/C++/Java/Python it is equivalent to &), operation <image> means bitwise OR (in Pascal it is equivalent to <image>, in C/C++/Java/Python it is equivalent to |).
Because the answer can be quite large, calculate it modulo m. This time GukiZ hasn't come up with solution, and needs you to help him!
Input
First and the only line of input contains four integers n, k, l, m (2 ≤ n ≤ 1018, 0 ≤ k ≤ 1018, 0 ≤ l ≤ 64, 1 ≤ m ≤ 109 + 7).
Output
In the single line print the number of arrays satisfying the condition above modulo m.
Examples
Input
2 1 2 10
Output
3
Input
2 1 1 3
Output
1
Input
3 3 2 10
Output
9
Note
In the first sample, satisfying arrays are {1, 1}, {3, 1}, {1, 3}.
In the second sample, only satisfying array is {1, 1}.
In the third sample, satisfying arrays are {0, 3, 3}, {1, 3, 2}, {1, 3, 3}, {2, 3, 1}, {2, 3, 3}, {3, 3, 0}, {3, 3, 1}, {3, 3, 2}, {3, 3, 3}.
Submitted Solution:
```
def mul_matr(matr1, matr2):
return [[sum(x * y for (x, y) in zip(row, col)) for col in zip(*matr2)] for row in matr1]
def pow_matr_mod(matr, pw, mod):
res = [[1, 0], [0, 1]]
for c in map(int, "{:b}".format(pw)):
res = mul_matr(res, res)
if c:
res = mul_matr(res, matr)
for row in res:
for i in range(len(row)):
row[i] %= mod
return res
def get_zero_count(n, mod):
return sum(map(sum, pow_matr_mod([[1, 1], [1, 0]], n - 1, mod))) % mod
def get_one_count(n, mod):
return (pow(2, n, mod) - get_zero_count(n, mod)) % mod
def calc_result(n, k, l, m):
if l == 0:
if k != 0:
return 0
else:
return 1
if k >= 2 ** l:
return 0
zero = get_zero_count(n, m)
one = get_one_count(n, m)
res = 1
for c in map(int, "{{:0{}b}}".format(l).format(k)):
if c:
res *= one
else:
res *= zero
res %= m
return res
print(calc_result(*map(int, input().split())))
``` | instruction | 0 | 59,264 | 5 | 118,528 |
No | output | 1 | 59,264 | 5 | 118,529 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the infinite sequence of integers: 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2, 3, 4, 5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains numbers, not digits. For example number 10 first appears in the sequence in position 55 (the elements are numerated from one).
Find the number on the n-th position of the sequence.
Input
The only line contains integer n (1 ≤ n ≤ 1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type.
Output
Print the element in the n-th position of the sequence (the elements are numerated from one).
Examples
Input
3
Output
2
Input
5
Output
2
Input
10
Output
4
Input
55
Output
10
Input
56
Output
1
Submitted Solution:
```
import math
n = int(input())-1
a = 8
b = 0.5
c = 2
d = 1
x = ((a*n+d)**b-d)//c
y = x*(x+d)/c
print(int(n-y+d))
``` | instruction | 0 | 59,290 | 5 | 118,580 |
Yes | output | 1 | 59,290 | 5 | 118,581 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the infinite sequence of integers: 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2, 3, 4, 5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains numbers, not digits. For example number 10 first appears in the sequence in position 55 (the elements are numerated from one).
Find the number on the n-th position of the sequence.
Input
The only line contains integer n (1 ≤ n ≤ 1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type.
Output
Print the element in the n-th position of the sequence (the elements are numerated from one).
Examples
Input
3
Output
2
Input
5
Output
2
Input
10
Output
4
Input
55
Output
10
Input
56
Output
1
Submitted Solution:
```
n=int(input())
k=int(((2*n)**(1/2)))
while (k*(k+1))//2>=n:
k-=1
print(n-(k*(k+1)//2))
``` | instruction | 0 | 59,291 | 5 | 118,582 |
Yes | output | 1 | 59,291 | 5 | 118,583 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the infinite sequence of integers: 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2, 3, 4, 5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains numbers, not digits. For example number 10 first appears in the sequence in position 55 (the elements are numerated from one).
Find the number on the n-th position of the sequence.
Input
The only line contains integer n (1 ≤ n ≤ 1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type.
Output
Print the element in the n-th position of the sequence (the elements are numerated from one).
Examples
Input
3
Output
2
Input
5
Output
2
Input
10
Output
4
Input
55
Output
10
Input
56
Output
1
Submitted Solution:
```
import math
n = int(input())
rem = ((math.sqrt(1+8*n)-1)/2)
if rem - (rem//1)==0:rem-=1
else:rem=rem//1
rem = int(rem)
print(n-rem*(rem+1)//2)
``` | instruction | 0 | 59,292 | 5 | 118,584 |
Yes | output | 1 | 59,292 | 5 | 118,585 |
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