message stringlengths 2 44.5k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the infinite sequence of integers: 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2, 3, 4, 5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains numbers, not digits. For example number 10 first appears in the sequence in position 55 (the elements are numerated from one).
Find the number on the n-th position of the sequence.
Input
The only line contains integer n (1 ≤ n ≤ 1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type.
Output
Print the element in the n-th position of the sequence (the elements are numerated from one).
Examples
Input
3
Output
2
Input
5
Output
2
Input
10
Output
4
Input
55
Output
10
Input
56
Output
1
Submitted Solution:
```
from math import ceil
f = lambda a : (-1+(1+8*a)**0.5)/2
t = lambda a : a*(a-1)/2
n = int(input())
print(n-int(t(ceil(f(n)))))
``` | instruction | 0 | 59,293 | 5 | 118,586 |
Yes | output | 1 | 59,293 | 5 | 118,587 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the infinite sequence of integers: 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2, 3, 4, 5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains numbers, not digits. For example number 10 first appears in the sequence in position 55 (the elements are numerated from one).
Find the number on the n-th position of the sequence.
Input
The only line contains integer n (1 ≤ n ≤ 1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type.
Output
Print the element in the n-th position of the sequence (the elements are numerated from one).
Examples
Input
3
Output
2
Input
5
Output
2
Input
10
Output
4
Input
55
Output
10
Input
56
Output
1
Submitted Solution:
```
import math
number = input()
current = 0
num = int(number)
D = math.sqrt(1 + 8*num)
n = ( D - 1 )/2
n = int(n)
summa = n*(n+1)/2
if num == summa:
n-=1
summa = n*(n+1)/2
if num>summa:
num -= summa
print (num)
``` | instruction | 0 | 59,294 | 5 | 118,588 |
No | output | 1 | 59,294 | 5 | 118,589 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the infinite sequence of integers: 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2, 3, 4, 5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains numbers, not digits. For example number 10 first appears in the sequence in position 55 (the elements are numerated from one).
Find the number on the n-th position of the sequence.
Input
The only line contains integer n (1 ≤ n ≤ 1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type.
Output
Print the element in the n-th position of the sequence (the elements are numerated from one).
Examples
Input
3
Output
2
Input
5
Output
2
Input
10
Output
4
Input
55
Output
10
Input
56
Output
1
Submitted Solution:
```
from math import sqrt
x=int(input())
print(int((x-((-1+sqrt(8*x)/2)))))
``` | instruction | 0 | 59,295 | 5 | 118,590 |
No | output | 1 | 59,295 | 5 | 118,591 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the infinite sequence of integers: 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2, 3, 4, 5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains numbers, not digits. For example number 10 first appears in the sequence in position 55 (the elements are numerated from one).
Find the number on the n-th position of the sequence.
Input
The only line contains integer n (1 ≤ n ≤ 1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type.
Output
Print the element in the n-th position of the sequence (the elements are numerated from one).
Examples
Input
3
Output
2
Input
5
Output
2
Input
10
Output
4
Input
55
Output
10
Input
56
Output
1
Submitted Solution:
```
n=int (input())
i=1
if(n==99999998250180):
print("0")
else:
if(n==100000000000000):
print("1749820")
else:
while(n>0):
n=n-i
i=i+1
if(n==0):
print(i-1)
else:
print(n+i-1)
``` | instruction | 0 | 59,296 | 5 | 118,592 |
No | output | 1 | 59,296 | 5 | 118,593 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider the infinite sequence of integers: 1, 1, 2, 1, 2, 3, 1, 2, 3, 4, 1, 2, 3, 4, 5.... The sequence is built in the following way: at first the number 1 is written out, then the numbers from 1 to 2, then the numbers from 1 to 3, then the numbers from 1 to 4 and so on. Note that the sequence contains numbers, not digits. For example number 10 first appears in the sequence in position 55 (the elements are numerated from one).
Find the number on the n-th position of the sequence.
Input
The only line contains integer n (1 ≤ n ≤ 1014) — the position of the number to find.
Note that the given number is too large, so you should use 64-bit integer type to store it. In C++ you can use the long long integer type and in Java you can use long integer type.
Output
Print the element in the n-th position of the sequence (the elements are numerated from one).
Examples
Input
3
Output
2
Input
5
Output
2
Input
10
Output
4
Input
55
Output
10
Input
56
Output
1
Submitted Solution:
```
from math import ceil
def num_first_position(num):
return (num * (num + 1)) // 2
def binary_search(target_position, num, start, end):
while start < end:
num_position = num_first_position(num)
half = max(1, ((end - start) // 2))
if half == 0:
break
if num_position == target_position:
break
elif num_position < target_position:
start = num + 1
num += half
else:
end = num
num -= half
num_position = num_first_position(num)
if num_position == target_position:
return num
elif num_position > target_position:
start_position = num_position - num + 1
diff = target_position - start_position
return 1 + diff
return num
def solve(position):
return binary_search(position, ceil(pow(10, 8) / 2), 1, pow(10, 8))
assert solve(3) == 2
assert solve(5) == 2
assert solve(10) == 4
assert solve(55) == 10
assert solve(56) == 1
assert solve(57) == 2
position = int(input().strip())
print(solve(position))
``` | instruction | 0 | 59,297 | 5 | 118,594 |
No | output | 1 | 59,297 | 5 | 118,595 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The only line of the input contains a string of digits. The length of the string is between 1 and 10, inclusive.
Output
Output "Yes" or "No".
Examples
Input
373
Output
Yes
Input
121
Output
No
Input
436
Output
Yes
Submitted Solution:
```
import sys
s = input()
pairs = [(3, 3), (4, 6), (5, 9), (6, 4), (7, 7), (8, 0), (9, 5), (0, 8)]
for l in range(len(s) // 2 + 1):
r = len(s) - l - 1
if l == r and int(s[l]) not in [3, 7]:
print("No")
sys.exit(0)
elif (int(s[l]), int(s[r])) not in pairs:
print("No")
sys.exit(0)
print("Yes")
``` | instruction | 0 | 59,358 | 5 | 118,716 |
Yes | output | 1 | 59,358 | 5 | 118,717 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The only line of the input contains a string of digits. The length of the string is between 1 and 10, inclusive.
Output
Output "Yes" or "No".
Examples
Input
373
Output
Yes
Input
121
Output
No
Input
436
Output
Yes
Submitted Solution:
```
p = input()
l = len(p) - 1
ans = ""
s=["23", "10", "30", "11", "13", "12", "31", "33", "32","21"]
for x in p:
ans+=s[ord(x) -48]
if ans == ans[::-1]:
print("Yes")
else:
print("No")
``` | instruction | 0 | 59,360 | 5 | 118,720 |
Yes | output | 1 | 59,360 | 5 | 118,721 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The only line of the input contains a string of digits. The length of the string is between 1 and 10, inclusive.
Output
Output "Yes" or "No".
Examples
Input
373
Output
Yes
Input
121
Output
No
Input
436
Output
Yes
Submitted Solution:
```
a = input()
s = 0
for i in a:
s += ord(i) - ord('0')
if s % 13 == 0:
print("Yes")
else:
print("No")
``` | instruction | 0 | 59,361 | 5 | 118,722 |
No | output | 1 | 59,361 | 5 | 118,723 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The only line of the input contains a string of digits. The length of the string is between 1 and 10, inclusive.
Output
Output "Yes" or "No".
Examples
Input
373
Output
Yes
Input
121
Output
No
Input
436
Output
Yes
Submitted Solution:
```
a = input()
tot = 0
for i in a:
tot += int(i)
if (tot % 13 == 0):
print("Yes")
else:
print("No")
``` | instruction | 0 | 59,362 | 5 | 118,724 |
No | output | 1 | 59,362 | 5 | 118,725 |
Provide a correct Python 3 solution for this coding contest problem.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7 | instruction | 0 | 59,481 | 5 | 118,962 |
"Correct Solution:
```
from math import ceil,log
N=int(input())
A=[int(i) for i in input().split()]
def f(A):
dp=[0]*16
L=[0]*N
for i in range(16):
dp[i]=i
for n in range(N-2,-1,-1):
ndp=[0]*16
nx=ceil(log(A[n]/A[n+1])/log(4)) #A
for x in range(16):
dx=nx+x
if dx <=15:
#print(max(0,dx))
ndp[x]=dp[max(0,dx)]+x
else:
ndp[x]=dp[15]+x+(N-1-n)*(dx-15)
dp=ndp
L[n]=dp[0]
return L
K=f(A)+[0]
L=[0]+f(A[::-1])[::-1]
ans=10**22
for i in range(N+1):
ans=min(ans,i+2*L[i]+2*K[i])
print(ans)
``` | output | 1 | 59,481 | 5 | 118,963 |
Provide a correct Python 3 solution for this coding contest problem.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7 | instruction | 0 | 59,482 | 5 | 118,964 |
"Correct Solution:
```
n = int(input())
a = list(map(int,input().split()))
def d4(x,y):
ret = 0
while x > y:
y *= 4
ret += 1
return ret
def cost(ls):
l = len(ls)
ret = [0]*l
stack = [(l-1,10**18)]
for i in range(l-1)[::-1]:
ret[i] = ret[i+1]
if ls[i] <= ls[i+1]:
d = d4(ls[i+1],ls[i])-1
if d > 0:
stack.append((i,d))
else:
d = d4(ls[i],ls[i+1])
while d:
idx,num = stack.pop()
if d > num:
ret[i] += (idx-i)*num
d -= num
else:
ret[i] += (idx-i)*d
num -= d
d = 0
if num:
stack.append((idx,num))
return ret
cp = cost(a)
cn = cost(a[::-1])
for i in range(n):
cp[i] *= 2
cn[i] *= 2
cn[i] += n-i
ansls = [cp[0],cn[0]]
for i in range(1,n):
ansls.append(cp[i]+cn[n-i])
print(min(ansls))
``` | output | 1 | 59,482 | 5 | 118,965 |
Provide a correct Python 3 solution for this coding contest problem.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7 | instruction | 0 | 59,483 | 5 | 118,966 |
"Correct Solution:
```
#
import collections, atexit, math, sys, bisect
sys.setrecursionlimit(1000000)
def getIntList():
return list(map(int, input().split()))
try :
#raise ModuleNotFoundError
import numpy
def dprint(*args, **kwargs):
#print(*args, **kwargs, file=sys.stderr)
# in python 3.4 **kwargs is invalid???
print(*args, file=sys.stderr)
dprint('debug mode')
except Exception:
def dprint(*args, **kwargs):
pass
inId = 0
outId = 0
if inId>0:
dprint('use input', inId)
sys.stdin = open('input'+ str(inId) + '.txt', 'r') #标准输出重定向至文件
if outId>0:
dprint('use output', outId)
sys.stdout = open('stdout'+ str(outId) + '.txt', 'w') #标准输出重定向至文件
atexit.register(lambda :sys.stdout.close()) #idle 中不会执行 atexit
if True:
N, = getIntList()
#print(N)
za = getIntList()
else:
N = 1000
import random
za = [random.randint(1, 1000000000) for i in range(N) ]
dprint('begin')
zleft = [0 for i in range(N+1)]
zright = [0 for i in range(N+1)]
def getwork(zr, za):
zr[0] = 0
st = []
for i in range(N):
if i%10000 ==0:
dprint('---', i)
nt = [[za[i],0], [za[i],0], 1]
st.append(nt)
nr = zr[i]
#dprint(st)
while len(st)>1:
b_2 = st[-2][1][1]
b_1 = st[-1][0][1]
bb = min(b_1,b_2)
b_1 -=bb
b_2 -=bb
b_1p = 4 ** b_1
b_2p = 4 ** b_2
t2 = st[-2][1][0] * b_2p
t1 = st[-1][0][0] * b_1p
if t2 < t1:
nr+= 2* st[-2][2]
st[-2][0][1] +=1
st[-2][1][1] +=1
elif t2 < t1 * 4:
ttt = [ st[-2][0], st[-1][1], st[-2][2] + st[-1][2] ]
st[-2] = ttt
st.pop()
else:
break
#dprint(st)
zr[i+1] = nr
#dprint(nr)
#dprint(st)
assert nr < 1000000000000000
getwork(zleft, za)
dprint('!!!!')
getwork(zright, za[::-1])
#dprint(zleft)
#dprint(zright)
r = zright[N]
for i in range(N+1):
tr = i + zleft[i] + zright[N-i]
r = min(r,tr)
print(r)
dprint('end')
``` | output | 1 | 59,483 | 5 | 118,967 |
Provide a correct Python 3 solution for this coding contest problem.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7 | instruction | 0 | 59,484 | 5 | 118,968 |
"Correct Solution:
```
mod = 1000000007
eps = 10**-9
def main():
import sys
input = sys.stdin.readline
def f(a, b):
ret = 0
while a > b:
ret += 2
b *= 4
return ret
N = int(input())
A = list(map(int, input().split()))
right = [0] * (N+1)
st = [(1, A[-1], A[-1])]
for i in range(N-2, -1, -1):
a = A[i]
st.append((1, a, a))
right[i] = right[i+1]
while True:
if len(st) == 1:
break
if st[-1][2] > st[-2][1]:
na, amin, amax = st.pop()
nb, bmin, bmax = st.pop()
k = f(amax, bmin)
right[i] += nb * k
if st:
st.append((na+nb, amin, bmax << k))
else:
st.append((na+nb, amin, float("inf")))
else:
break
left = [0] * (N+1)
left[1] = 1
st = [(1, A[0], A[0])]
for i in range(2, N+1):
a = A[i-1]
st.append((1, a, a))
left[i] = left[i-1] + 1
while True:
if len(st) == 1:
break
if st[-1][2] > st[-2][1]:
na, amin, amax = st.pop()
nb, bmin, bmax = st.pop()
k = f(amax, bmin)
left[i] += nb * k
if st:
st.append((na + nb, amin, bmax << k))
else:
st.append((na+nb, amin, float("inf")))
else:
break
ans = float("inf")
for i in range(N+1):
ans = min(ans, left[i] + right[i])
print(ans)
if __name__ == '__main__':
main()
``` | output | 1 | 59,484 | 5 | 118,969 |
Provide a correct Python 3 solution for this coding contest problem.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7 | instruction | 0 | 59,485 | 5 | 118,970 |
"Correct Solution:
```
import sys
read = sys.stdin.buffer.read
readline = sys.stdin.buffer.readline
readlines = sys.stdin.buffer.readlines
"""
・正、負の部分に分けて。本質的には正の場合ができればよい
・4A_i > A_{i+1} となってるものはまとめる。運命共同体の区間たちができる
・一番弱い区間と勝負する。成長すると次の区間とマージできる
"""
N,*A = map(int,read().split())
def calc_positive_case(N,A):
INF = 1<<32
# ある場所を始点として、そこから全部positiveにしたい場合
dp = [0] * N
left_end = []
right_end = []
items = []
mult_cnt = 0
for i,x in enumerate(A[::-1]):
left_end.append(x); right_end.append(x); items.append(1)
# 最小の矛盾を解消
while len(items) >= 2:
l2,l1 = left_end[-2:]
r2,r1 = right_end[-2:]
n2,n1 = items[-2:]
if r1*4<=l2:
# mergeせず
break
while r1>l2:
l2 *= 4; r2 *= 4; mult_cnt += n2
left_end.pop(); left_end[-1]=l1
right_end.pop(); right_end[-1]=r2
items.pop(); items[-1] += n1
if right_end[0] > INF:
right_end[0] = INF
dp[i] = mult_cnt
return dp[::-1]
pos = calc_positive_case(N,A) # ある点を正の始点としたときに必要な、4倍の回数
neg = calc_positive_case(N,A[::-1])[::-1] # ある点を負の始点としたときの～～
pos = [2*x for x in pos] + [0]
neg = [0] + [2*x+i for i,x in enumerate(neg,1)] # -2倍の初期コストが乗る
answer = min(x+y for x,y in zip(pos,neg))
print(answer)
``` | output | 1 | 59,485 | 5 | 118,971 |
Provide a correct Python 3 solution for this coding contest problem.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7 | instruction | 0 | 59,486 | 5 | 118,972 |
"Correct Solution:
```
import sys
input = lambda : sys.stdin.readline().rstrip()
sys.setrecursionlimit(max(1000, 10**9))
write = lambda x: sys.stdout.write(x+"\n")
n = int(input())
a = list(map(int, input().split()))
def sub(a, minus=False):
m = 20
inf = 10**15
dp = [[inf]*m for _ in range(n)] # i以降、a[i]に4^jをかけたところからソート
for j in range(m):
dp[-1][j] = j
for i in range(n-2, -1, -1):
if a[i]>a[i+1]:
v = 0
ai = a[i]; ai1 = a[i+1]
while ai>ai1:
ai1 *= 4
v += 1
for j in range(m):
if j+v<m:
dp[i][j] = j + dp[i+1][j+v]
else:
dp[i][j] = j + dp[i+1][m-1] + (n-i-1)*(j+v-m+1)
else:
v = 0
ai = a[i]; ai1 = a[i+1]
while True:
ai *= 4
if ai<=ai1:
v += 1
else:
break
for j in range(m):
dp[i][j] = j + dp[i+1][max(0, j-v)]
if minus:
ans = [(2*min(dp[i][j] for j in range(m))+(n-i)) for i in range(n)]
else:
ans = [2*min(dp[i][j] for j in range(m)) for i in range(n)]
return ans
dp0 = sub(list(a))
dp1 = sub([item for item in a[::-1]], minus=True)[::-1]
dp0.append(0)
dp1.insert(0,0)
ans = min((dp0[i]+dp1[i]) for i in range(n+1))
print(ans)
``` | output | 1 | 59,486 | 5 | 118,973 |
Provide a correct Python 3 solution for this coding contest problem.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7 | instruction | 0 | 59,487 | 5 | 118,974 |
"Correct Solution:
```
import sys
readline = sys.stdin.readline
def f(a, b):
return (1+(-(-a//b)-1).bit_length())//2
N = int(readline())
A = list(map(int, readline().split()))
dpr = [0]*N
Ar = A[:]
cnt = 0
for i in range(1, N):
res = 0
idx = i-1
while cnt <= idx:
k = f(Ar[idx+1], Ar[idx])
if k:
Ar[idx] *= 4**k
res += k
idx -= 1
if not k:
break
else:
dpr[i] += cnt*k
dpr[i] += dpr[i-1] + res
while cnt < i:
if Ar[cnt] < Ar[cnt+1]*4:
cnt += 1
else:
break
dpl = [0]*N
Al = A[:]
cnt = N-1
for i in range(N-2, -1, -1):
res = 0
idx = i+1
while cnt >= idx:
k = f(Al[idx-1], Al[idx])
if k:
Al[idx] *= 4**k
res += k
idx += 1
if not k:
break
else:
dpl[i] += (N-1-cnt)*k
dpl[i] += dpl[i+1] + res
while cnt > i:
if Al[cnt] < Al[cnt-1]*4:
cnt -= 1
else:
break
dpl = [2*dpl[i] for i in range(N)]
dpr = [0] + [i+1+2*dpr[i] for i in range(N)]
inf = 10**20
ans = inf
for i in range(N):
ans = min(ans, dpr[i] + dpl[i])
print(ans)
``` | output | 1 | 59,487 | 5 | 118,975 |
Provide a correct Python 3 solution for this coding contest problem.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7 | instruction | 0 | 59,488 | 5 | 118,976 |
"Correct Solution:
```
N = int(input())
A = list(map(int, input().split()))
R = [0] * (N+1)
L = [0] * (N+1)
l = 0
ap = A[-1]#float("inf")
P = [0] * 20
stack = [0]
for i in range(N):
a = A[-1-i]
#cnt = 0
while ap < a:
#cnt += 2
l += (i-stack[-1])<<1
if stack[-1] != 0: del stack[-1]
ap <<= 2
a4 = a<<2
while ap >= a4:
ap >>= 2
stack.append(i)
R[-(i+2)] = l
ap = a
ap = -A[0]
l = 0
stack = [0]
for i in range(N):
l += 1
a = -A[i]
#cnt = 0
while ap > a:
#cnt += 2
l += (i-stack[-1])<<1
if stack[-1] != 0: del stack[-1]
ap <<= 2
a4 = a << 2
while ap <= a4:
ap >>= 2
stack.append(i)
#l += i * cnt
L[i+1] = l
ap = a
#print(L, R)
ans = float("inf")
for l, r in zip(L, R):
ans = min(ans, l+r)
print(ans)
``` | output | 1 | 59,488 | 5 | 118,977 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7
Submitted Solution:
```
from math import ceil, log
log_2 = log(2)
def max2(x, y): return x if x >= y else y
def getNums(As, N):
dp = list(range(16))
nums = [0] * N
for i in reversed(range(N - 1)):
dx = ceil( log( As[i] / As[i+1] ) / log_2 / 2 )
dp2 = [0] * 16
for x in range(16):
nx = x + dx
if nx <= 15:
dp2[x] = dp[max2(0, nx)] + x
else:
dp2[x] = dp[15] + x + (N - 1 - i) * (nx - 15)
dp = dp2
nums[i] = dp[0]
return nums
N = int(input())
As = list(map(int, input().split()))
numPstvs = getNums(As, N)
numNgtvs = getNums(As[::-1], N)[::-1]
ans = float('inf')
for i, (p, m) in enumerate(zip(numPstvs + [0], [0] + numNgtvs)):
ans = min(ans, 2 * p + 2 * m + i)
print(ans)
``` | instruction | 0 | 59,489 | 5 | 118,978 |
Yes | output | 1 | 59,489 | 5 | 118,979 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7
Submitted Solution:
```
from collections import deque
n = int(input())
a = list(map(int,input().split()))
p = [0] * (n-1)
m = [0] * (n-1)
for i in range(n-1):
x,y = a[i:i+2]
cnt = 0
if(x > y):
while(x>y):
y *= 4
cnt += 2
else:
x *= 4
while(x<=y):
x*=4
cnt -= 2
p[i] = cnt
for i in range(n-1):
x,y = a[i:i+2]
cnt = 0
if(x < y):
while(x<y):
x *= 4
cnt += 2
else:
y *= 4
while(x>=y):
y*=4
cnt -= 2
m[i] = cnt
cumsum_p = [0] * (n+1)
cumsum_m = [0] * (n+1)
d = deque()
for i in range(n-2,-1,-1):
cumsum_p[i] = cumsum_p[i+1]
if(p[i] < 0):
d.appendleft((i,p[i]))
elif(p[i] > 0):
cnt = p[i]
while(d):
j,rem_j = d.popleft()
if(cnt + rem_j <= 0):
cumsum_p[i] += (j-i) * cnt
if(cnt + rem_j < 0):
d.appendleft((j,cnt + rem_j))
cnt = 0
break
else:
cumsum_p[i] += (j-i) * (-1 * rem_j)
cnt = cnt + rem_j
cumsum_p[i] += (n-i-1) * cnt
d = deque()
cumsum_m[1] = 1
for i in range(n-1):
cumsum_m[i+2] = cumsum_m[i+1] + 1
if(m[i] < 0):
d.appendleft((i,m[i]))
elif(m[i] > 0):
cnt = m[i]
while(d):
j,rem_j = d.popleft()
if( cnt + rem_j <= 0 ):
cumsum_m[i+2] += (i-j) * cnt
if( cnt + rem_j < 0):
d.appendleft((j,cnt + rem_j))
cnt = 0
break
else:
cumsum_m[i+2] += (i-j) * (-1*rem_j)
cnt = cnt + rem_j
cumsum_m[i+2] += (i+1) * cnt
ans = cumsum_p[0]
for i in range(n+1):
ans = min(ans, cumsum_p[i] + cumsum_m[i])
print(ans)
``` | instruction | 0 | 59,490 | 5 | 118,980 |
Yes | output | 1 | 59,490 | 5 | 118,981 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7
Submitted Solution:
```
from math import ceil, log2
def getNums(As, N):
dp = list(range(16))
nums = [0] * N
for i in reversed(range(N - 1)):
dx = ceil( log2( As[i] / As[i+1] ) / 2 )
if dx <= 0:
dp0 = dp[0]
dp = [dp0] * (-dx) + dp[:16+dx]
else:
dp15 = dp[15]
k = N - 1 - i
dp = dp[dx:] + list(range(dp15 + k, dp15 + k * dx + 1, k))
dp = [dpx + x for x, dpx in enumerate(dp)]
nums[i] = dp[0]
return nums
N = int(input())
As = list(map(int, input().split()))
numPstvs = getNums(As, N)
numNgtvs = getNums(As[::-1], N)[::-1]
ans = min([2 * p + 2 * m + i for i, (p, m) in enumerate(zip(numPstvs + [0], [0] + numNgtvs))])
print(ans)
``` | instruction | 0 | 59,491 | 5 | 118,982 |
Yes | output | 1 | 59,491 | 5 | 118,983 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7
Submitted Solution:
```
from collections import deque
q = deque([])
def ct(a,b):
ans = 0
while abs(a)<abs(b):
ans += 2
a *= 4
return ans
N = int(input())
A = [int(a) for a in input().split()]
# A = [3, 1, 4, 1]
# N = len(A)
X = [0] * (N)
Y = [0] * (N)
a = -1
for i in range(N):
b = a
if i > 0:
X[i] = X[i-1]
else:
X[i] = 0
a = A[i]
t = 0
if a > 0:
X[i] += 1
a *= -2
if i > 0:
t = 0
r = b/a
while r >= 4:
q.append(i)
r /= 4
while abs(a)>abs(b):
if len(q) == 0:
X[i] += 2 * i
else:
X[i] += 2 * (i - q.pop())
b *= 4
q = deque([])
a = -1
for i in range(N):
b = a
if i > 0:
Y[i] = Y[i-1]
else:
Y[i] = 0
a = A[N-1-i]
t = 0
if a < 0:
Y[i] += 1
a *= -2
if i > 0:
t = 0
r = b/a
while r >= 4:
q.append(i)
r /= 4
while abs(a)>abs(b):
if len(q) == 0:
Y[i] += 2 * i
else:
Y[i] += 2 * (i - q.pop())
b *= 4
mi = min(X[-1], Y[-1])
for i in range(N-1):
if X[i]+Y[-2-i] < mi:
mi = X[i]+Y[-2-i]
print(mi)
``` | instruction | 0 | 59,492 | 5 | 118,984 |
Yes | output | 1 | 59,492 | 5 | 118,985 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7
Submitted Solution:
```
class SegTree:
"""
init(init_val, ide_ele): 配列init_valで初期化 O(N)
update(k, x): k番目の値をxに更新 O(logN)
query(l, r): 区間[l, r)をsegfuncしたものを返す O(logN)
"""
def __init__(self, segfunc, ide_ele):
"""
init_val: 配列の初期値
segfunc: 区間にしたい操作
ide_ele: 単位元
n: 要素数
num: n以上の最小の2のべき乗
tree: セグメント木(1-index)
"""
n = ide_ele
self.segfunc = segfunc
self.ide_ele = ide_ele
self.num = 1 << (n - 1).bit_length()
self.tree = [ide_ele] * 2 * self.num
# 配列の値を葉にセット
for i in range(n):
self.tree[self.num + i] = i
# 構築していく
for i in range(self.num - 1, 0, -1):
self.tree[i] = self.segfunc(self.tree[2 * i], self.tree[2 * i + 1])
def query(self, l, r):
"""
[l, r)のsegfuncしたものを得る
l: index(0-index)
r: index(0-index)
"""
res = self.ide_ele
l += self.num
r += self.num
while l < r:
if l & 1:
res = self.segfunc(res, self.tree[l])
l += 1
if r & 1:
res = self.segfunc(res, self.tree[r - 1])
l >>= 1
r >>= 1
return res
def main():
import random
from math import log,ceil
N=int(input())
n=N
A=[random.randint(1,10**9) for i in range(N)]
A=[log(A[i],4) for i in range(N)]
B=[A[-i-1] for i in range(N)]
memo=[0]*(N-1)
ans=10**25
ope=[0 for i in range(N+1)]
ope[N]=10**20
def segfunc(x,y):
if ope[x]>ope[y]:
return y
elif ope[y]>ope[x]:
return x
else:
return min(x,y)
#####ide_ele#####
ide_ele = N
#################
for i in range(1,N):
ope[i]=max(0,ceil(A[i-1]-A[i]))
A[i]+=ope[i]
rmq=SegTree(segfunc,ide_ele)
S=sum(ope[i] for i in range(N))
ans=min(ans,2*S)
zero=[N]
#A1 ... AnのBIT(1-indexed)
BIT = [0]*(n+1)
#A1 ~ Aiまでの和 O(logN)
def BIT_query(idx):
res_sum = 0
while idx > 0:
res_sum += BIT[idx]
idx -= idx&(-idx)
return res_sum
#Ai += x O(logN)
def BIT_update(idx,x):
while idx <= n:
BIT[idx] += x
idx += idx&(-idx)
return
for i in range(1,N):
while i!=zero[-1]:
k=rmq.query(i,zero[-1])
val=ope[k]+BIT_query(k+1)
S-=val*(zero[-1]-i)
BIT_update(i+1,-val)
BIT_update(zero[-1]+1,val)
zero.append(k)
zero.pop()
memo[i-1]+=2*S
ope=[0 for i in range(N+1)]
ope[N]=10**20
S=0
for i in range(1,N):
ope[i]=max(0,ceil(B[i-1]-B[i]))
S+=ope[i]
B[i]+=ope[i]
#print(time.time()-start)
rmq=SegTree(segfunc,ide_ele)
#print(time.time()-start)
ans=min(ans,2*S+N)
zero=[N]
BIT=[0]*(n+1)
for i in range(1,N):
while i!=zero[-1]:
k=rmq.query(i,zero[-1])
val=ope[k]+BIT_query(k+1)
S-=val*(zero[-1]-i)
BIT_update(i+1,-val)
BIT_update(zero[-1]+1,val)
zero.append(k)
zero.pop()
memo[N-1-i]+=2*S+(N-i)
#print(time.time()-start)
test=min(memo)
print(min(test,ans))
if __name__=="__main__":
main()
``` | instruction | 0 | 59,493 | 5 | 118,986 |
No | output | 1 | 59,493 | 5 | 118,987 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7
Submitted Solution:
```
# try:
n = int(input())
a = list(map(int, input().split()))
i = 0
count = 0
while (i < n - 1):
if a[i] <= a[i+1]:
i += 1
elif i == 0:
a[i] = a[i] * -2
count += 1
else:
if a[i+1] * -2 > 10 **9:
count = -1
break
else:
a[i+1] = a[i+1] * -2
count += 1
print(count)
# except EOFError:
# pass
``` | instruction | 0 | 59,494 | 5 | 118,988 |
No | output | 1 | 59,494 | 5 | 118,989 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7
Submitted Solution:
```
N = int(input())
A = list(map(int, input().split()))
num = float("inf")
for i in range(N):
tmp = 0
pre = A[i]
for j in range(i + 1, N):
q = A[j]
while pre > q:
q *= 4
tmp += 2
pre = q
pre = A[i]
for j in range(i - 1, -1, -1):
q = A[j]
while pre < q:
q *= -2
tmp += 1
pre = q
num = min(tmp, num)
print(num)
``` | instruction | 0 | 59,495 | 5 | 118,990 |
No | output | 1 | 59,495 | 5 | 118,991 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N positive integers A_1, A_2, ..., A_N. Takahashi can perform the following operation on these integers any number of times:
* Choose 1 \leq i \leq N and multiply the value of A_i by -2.
Notice that he multiplies it by minus two.
He would like to make A_1 \leq A_2 \leq ... \leq A_N holds. Find the minimum number of operations required. If it is impossible, print `-1`.
Constraints
* 1 \leq N \leq 200000
* 1 \leq A_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
A_1 A_2 ... A_N
Output
Print the answer.
Examples
Input
4
3 1 4 1
Output
3
Input
5
1 2 3 4 5
Output
0
Input
8
657312726 129662684 181537270 324043958 468214806 916875077 825989291 319670097
Output
7
Submitted Solution:
```
import sys
import heapq
hpush = heapq.heappush
hpop = heapq.heappop
input = sys.stdin.readline
N = int(input())
a = list(map(int, input().split()))
dpl = [0] * (N + 1)
h = []
for i in range(N):
x = a[i] * 2
if len(h):
while h[0] < x:
hpush(h, hpop(h) * 4)
dpl[i + 1] += 2
hpush(h, x)
dpl[i + 1] += dpl[i] + 1
a.reverse()
dpr = [0] * (N + 1)
h = []
for i in range(N):
x = a[i]
if len(h):
while -h[0] > x:
x *= 4
dpr[i + 1] += 2
hpush(h, -x)
dpr[i + 1] += 1
res = float("inf")
for i in range(N):
res = min(res, dpl[i] + dpr[N - i])
print(res)
``` | instruction | 0 | 59,496 | 5 | 118,992 |
No | output | 1 | 59,496 | 5 | 118,993 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0 | instruction | 0 | 59,497 | 5 | 118,994 |
"Correct Solution:
```
# AGC024A
a,b,c,k = map(int, input().split())
if k%2:
print(b-a)
else:
print(a-b)
``` | output | 1 | 59,497 | 5 | 118,995 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0 | instruction | 0 | 59,498 | 5 | 118,996 |
"Correct Solution:
```
A,B,C,K=map(int,input().split())
M=K%2
print((A-B)*(-1)**(M))
``` | output | 1 | 59,498 | 5 | 118,997 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0 | instruction | 0 | 59,499 | 5 | 118,998 |
"Correct Solution:
```
A, B, C, K = map(int, input().split())
if K%2 == 0:
r = A-B
else:
r = B-A
print(r)
``` | output | 1 | 59,499 | 5 | 118,999 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0 | instruction | 0 | 59,500 | 5 | 119,000 |
"Correct Solution:
```
a, b, c, k = map(int, input().split())
ans = a-b
if k%2: ans *= -1
print(ans)
``` | output | 1 | 59,500 | 5 | 119,001 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0 | instruction | 0 | 59,501 | 5 | 119,002 |
"Correct Solution:
```
a,b,c,d = map(int,input().split(" "))
if d % 2 == 0:
print(a-b)
else:
print(b-a)
``` | output | 1 | 59,501 | 5 | 119,003 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0 | instruction | 0 | 59,502 | 5 | 119,004 |
"Correct Solution:
```
A,B,C,K=map(int,input().split())
print(B-A if K%2 else A-B)
``` | output | 1 | 59,502 | 5 | 119,005 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0 | instruction | 0 | 59,503 | 5 | 119,006 |
"Correct Solution:
```
a,b,c,k = map(int,input().split())
ans = a-b
if k%2==0:
print(ans)
else:
print(ans*(-1))
``` | output | 1 | 59,503 | 5 | 119,007 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0 | instruction | 0 | 59,504 | 5 | 119,008 |
"Correct Solution:
```
A, B, C, K = map(int, input().split())
o = B - A
e = A - B
if K % 2 == 0:
r = e
else:
r = o
print(r)
``` | output | 1 | 59,504 | 5 | 119,009 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0
Submitted Solution:
```
a,b,c,k = map(int ,input().split())
s = b-a
if (k%2 == 0):
s *= -1
print(s)
``` | instruction | 0 | 59,505 | 5 | 119,010 |
Yes | output | 1 | 59,505 | 5 | 119,011 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0
Submitted Solution:
```
a,b,c,k=map(int,input().split())
print("Unfair" if abs(a-b)>10**18 else a-b if k%2==0 else b-a)
``` | instruction | 0 | 59,506 | 5 | 119,012 |
Yes | output | 1 | 59,506 | 5 | 119,013 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0
Submitted Solution:
```
a, b, c, k = map(int, input().split())
ans = a - b if k % 2 == 0 else b - a
print(ans)
``` | instruction | 0 | 59,507 | 5 | 119,014 |
Yes | output | 1 | 59,507 | 5 | 119,015 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0
Submitted Solution:
```
a, b, _, k = map(int, input().split())
print((a - b)*((-1)**(k % 2)))
``` | instruction | 0 | 59,508 | 5 | 119,016 |
Yes | output | 1 | 59,508 | 5 | 119,017 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0
Submitted Solution:
```
a, b, c, k = map(int,input().split())
if a==b==c:
print(0)
exit()
for i in range(k):
a_=b+c
b_=a+c
c_=a+b
if abs(a_-b_) > 10**18:
print('Unfair')
exit()
a=a_
b=b_
c=c_
if k==0:
print(a-b)
else:
print(a_-b_)
``` | instruction | 0 | 59,509 | 5 | 119,018 |
No | output | 1 | 59,509 | 5 | 119,019 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0
Submitted Solution:
```
A, B, C, K = map(int, input().split())
for i in range(K):
temp_a = A
temp_b = B
temp_c = C
print(A, B, C)
A = temp_b + temp_c
B = temp_a + temp_c
C = temp_a + temp_b
if abs(A - B) <= 10 ** 18:
print(A - B)
else:
print("unfair")
``` | instruction | 0 | 59,510 | 5 | 119,020 |
No | output | 1 | 59,510 | 5 | 119,021 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0
Submitted Solution:
```
import copy
A,B,C,k = map(float,input().split())
if k%2 == 0:
if k == 0:
print(int(A-B))
else:
print(int((A-B)*k))
elif k%2 == 1:
print(-int((A-B)*k))
``` | instruction | 0 | 59,511 | 5 | 119,022 |
No | output | 1 | 59,511 | 5 | 119,023 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively. After repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:
* Each of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.
However, if the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Constraints
* 1 \leq A,B,C \leq 10^9
* 0 \leq K \leq 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B C K
Output
Print the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times. If the absolute value of the answer exceeds 10^{18}, print `Unfair` instead.
Examples
Input
1 2 3 1
Output
1
Input
2 3 2 0
Output
-1
Input
1000000000 1000000000 1000000000 1000000000000000000
Output
0
Submitted Solution:
```
A,B,C,K = map(int,input().split())
for i in range(min(K, 100000)):
A,B,C = B+C,C+A,A+B
if A - B > 10**18:
print("Unfair")
exit()
print(A-B)
``` | instruction | 0 | 59,512 | 5 | 119,024 |
No | output | 1 | 59,512 | 5 | 119,025 |
Provide a correct Python 3 solution for this coding contest problem.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES | instruction | 0 | 59,529 | 5 | 119,058 |
"Correct Solution:
```
N, A, B, C, D = map(int, input().split())
dif = B - A
ans = "NO"
for i in range(N):
pos = i
neg = N - i - 1
high = D * pos - C * neg
low = C * pos - D * neg
if low <= dif <= high:
ans = "YES"
break
print(ans)
``` | output | 1 | 59,529 | 5 | 119,059 |
Provide a correct Python 3 solution for this coding contest problem.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES | instruction | 0 | 59,530 | 5 | 119,060 |
"Correct Solution:
```
n,a,b,c,d=map(int,input().split())
l=r=a
for i in range(n-1):
if l+r<b*2:
l+=c
r+=d
else:
l-=d
r-=c
if l<=b<=r:print('YES')
else:print('NO')
``` | output | 1 | 59,530 | 5 | 119,061 |
Provide a correct Python 3 solution for this coding contest problem.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES | instruction | 0 | 59,531 | 5 | 119,062 |
"Correct Solution:
```
n, a, b, m, M = map(int, input().split())
n -= 1
l, r = -1, n + 1
while r - l > 1:
mid = (l + r) // 2
t = (n - 2 * mid) * (m + M)
if abs(t - 2 * (b - a)) <= n * (M - m):
print("YES")
exit()
if t > 2 * (b - a):
l = mid
else:
r = mid
print("NO")
``` | output | 1 | 59,531 | 5 | 119,063 |
Provide a correct Python 3 solution for this coding contest problem.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES | instruction | 0 | 59,532 | 5 | 119,064 |
"Correct Solution:
```
import sys
readline = sys.stdin.readline
MOD = 10 ** 9 + 7
INF = float('INF')
sys.setrecursionlimit(10 ** 5)
def main():
n, a, b, c, d = map(int, readline().split())
diff = a - b
for i in range(n - 1):
l = i * c - (n - 1 - i) * d
r = i * d - (n - 1 - i) * c
if l <= diff <= r:
return print("YES")
print("NO")
if __name__ == '__main__':
main()
``` | output | 1 | 59,532 | 5 | 119,065 |
Provide a correct Python 3 solution for this coding contest problem.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES | instruction | 0 | 59,533 | 5 | 119,066 |
"Correct Solution:
```
n,a,b,c,d=map(int,input().split())
for i in range(n-1):
if c*i-d*(n-1-i)<=abs(a-b)<=d*i-c*(n-1-i):
print("YES")
break
else:
print("NO")
``` | output | 1 | 59,533 | 5 | 119,067 |
Provide a correct Python 3 solution for this coding contest problem.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES | instruction | 0 | 59,534 | 5 | 119,068 |
"Correct Solution:
```
import sys
N,A,B,C,D = map(int,input().split())
num = abs(A-B)
nmax = (N-1) * D
nmin = (N-1) * C
flag = False
for i in range(N-1):
if nmax >= num and num >= nmin:
flag = True
break
nmax -= D + C
nmin -= C + D
if flag:
print ("YES")
else:
print ("NO")
``` | output | 1 | 59,534 | 5 | 119,069 |
Provide a correct Python 3 solution for this coding contest problem.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES | instruction | 0 | 59,535 | 5 | 119,070 |
"Correct Solution:
```
n,a,b,c,d = map(int,input().split())
if a > b:
a,b = b,a
b -= a
n -= 1
dif = d-c
for i in range(n%2,n+1,2):
if c*i-dif*((n-i)//2) <= b <= d*i+dif*((n-i)//2):
print("YES")
exit()
print("NO")
``` | output | 1 | 59,535 | 5 | 119,071 |
Provide a correct Python 3 solution for this coding contest problem.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES | instruction | 0 | 59,536 | 5 | 119,072 |
"Correct Solution:
```
import sys
sys.setrecursionlimit(2147483647)
INF=float("inf")
MOD=10**9+7
input=lambda:sys.stdin.readline().rstrip()
def resolve():
n,a,b,c,d=map(int,input().split())
for k in range(n): # k 右に行った回数
L=a+k*c-(n-k-1)*d
R=a+k*d-(n-k-1)*c
if(L<=b<=R):
print("YES")
return
print("NO")
resolve()
``` | output | 1 | 59,536 | 5 | 119,073 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES
Submitted Solution:
```
p=print
n,a,b,c,d=map(int,input().split())
for i in range(n):
if i*c-d*(n-i-1)<=b-a<=i*d-c*(n-i-1):exit(p("YES"))
p("NO")
``` | instruction | 0 | 59,537 | 5 | 119,074 |
Yes | output | 1 | 59,537 | 5 | 119,075 |
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