message stringlengths 2 44.5k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 42 109k | cluster float64 5 5 | __index_level_0__ int64 84 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES
Submitted Solution:
```
N,a,b,c,d=map(int, input().split())
N-=1
a,b=0,abs(b-a)
#δΈδΈγnεγ¨γγγ¨γ0<=n<=N//2
if d*N<b:
print('NO')
exit()
for i in range(N//2+1):
e=b-(N-i*2)*d
f=b-(N-i*2)*c
if e<=(d-c)*i and (c-d)*i<=f:
print('YES')
exit()
print('NO')
``` | instruction | 0 | 59,538 | 5 | 119,076 |
Yes | output | 1 | 59,538 | 5 | 119,077 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES
Submitted Solution:
```
def inpl(): return [int(i) for i in input().split()]
N, A, B, C, D = inpl()
for k in range(N+1):
j = N-1-k
if D*k - C*j >= B-A >= C*k - D*j:
print('YES')
break
else:
print('NO')
``` | instruction | 0 | 59,539 | 5 | 119,078 |
Yes | output | 1 | 59,539 | 5 | 119,079 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES
Submitted Solution:
```
N, A, B, C, D = map(int, input().split())
L = A + N * C + D
R = A + N * D + C
for i in range(N):
L -= C + D
R -= C + D
if L <= B <= R:
print('YES')
break
else:
print('NO')
``` | instruction | 0 | 59,540 | 5 | 119,080 |
Yes | output | 1 | 59,540 | 5 | 119,081 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES
Submitted Solution:
```
# Model Difference
N,A,B,C,D = list(map(int, input().split()))
ans = "NO"
for i in range(N-1):
if ( (i*C<=abs(A-B)<=i*D) and (N-1-i)%2==0 ):
ans="YES"
print(ans)
``` | instruction | 0 | 59,541 | 5 | 119,082 |
No | output | 1 | 59,541 | 5 | 119,083 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES
Submitted Solution:
```
import sys
input = sys.stdin.readline
N, A, B, C, D = map(int, input().split())
dp = [0] * N
dp[0] = A
dp[-1] = B
x = -1
def no():
print("NO")
exit(0)
if B < A: A, B = B, A
for i in range(N - 2):
if dp[i] < B:
dp[i + 1] = dp[i] + D
else:
#print(dp[i], (i - 1) * (D - C), B)
f = abs(dp[i] - (i - 1) * (D - C))
if f <= B:
x = i
dp[i] = B
else:
if D - C == 0: no()
x = i + -(-abs(B - f) // (D - C)) * 2
if x >= N: no()
dp[x] = B
break
if x == -1:
if C <= abs(B - dp[-2]) <= D:
x = N - 1
else: no()
#print(x, dp[x])
t = (N - 1 - x)
#print(t)
if t % 2:
if t == 1: no()
if D - C == 0: no()
if -(-C // (D - C)) > t: no()
print("YES")
``` | instruction | 0 | 59,542 | 5 | 119,084 |
No | output | 1 | 59,542 | 5 | 119,085 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES
Submitted Solution:
```
def main():
n, a, b, c, d = map(int, input().split())
last = abs(a-b)
if (n-1)*d < last:
print("NO")
else:
f = False
for i in range(n):
p = d*i
q = (n-1 - i)//2 * (d-c)
if (n-1 - i) % 2 == 1:
if q < c:
if p + c - q <= last <= p + d + q:
f = True
if p - d - q <= last <= p - c + q:
f = True
else:
if p - d - q <= last <= p + d + q:
f = True
else:
if p - q <= last <= p + q:
f = True
if f:
print("YES")
else:
print("NO")
if __name__ == "__main__":
main()
``` | instruction | 0 | 59,543 | 5 | 119,086 |
No | output | 1 | 59,543 | 5 | 119,087 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N squares in a row. The leftmost square contains the integer A, and the rightmost contains the integer B. The other squares are empty.
Aohashi would like to fill the empty squares with integers so that the following condition is satisfied:
* For any two adjacent squares, the (absolute) difference of the two integers in those squares is between C and D (inclusive).
As long as the condition is satisfied, it is allowed to use arbitrarily large or small integers to fill the squares. Determine whether it is possible to fill the squares under the condition.
Constraints
* 3 \leq N \leq 500000
* 0 \leq A \leq 10^9
* 0 \leq B \leq 10^9
* 0 \leq C \leq D \leq 10^9
* All input values are integers.
Input
Input is given from Standard Input in the following format:
N A B C D
Output
Print `YES` if it is possible to fill the squares under the condition; print `NO` otherwise.
Examples
Input
5 1 5 2 4
Output
YES
Input
4 7 6 4 5
Output
NO
Input
48792 105960835 681218449 90629745 90632170
Output
NO
Input
491995 412925347 825318103 59999126 59999339
Output
YES
Submitted Solution:
```
N,A,B,C,D=map(int,input().split())
#print("target:", abs(A-B))
#print("range: ", D-C)
#print("target is larger than D: " ,
# abs(A-B)>D)
#target=abs(A-B)
#print("next target is: ", target-D)
#print("how many? : ", (target-D)//(D-C))
ans=False
def g(a,b,c,d,n):
if (n-1)%2==0:
target=abs(a-b) #γΉγΏγΌγγ―0
gain=d-c
if ((n-1)//2)*gain>=target:
return True
else:
return False
else:
target=abs(a-b)
gain=d-c
if target>d:
if (n-2)//2 * gain >=target-d:
return True
else:
return False
elif target<c:
if (n-2)//2 *gain >= c- target:
return True
else:
return False
elif c<=target<=d:
return True
A,B=min(A,B),max(A,B)
target=B-A
pos=0
for i in range(N+1):
if target>0:
if (target//C )- 1<=N-i and C<=target%C+D<=D:
print("YES")
exit(0)
if g(pos, target, C,D, N-i):
print("YES")
exit(0)
if target >D:
target-=D
elif C <=target<=D:
print("YES")
exit(0)
else:
target=C-target
print("NO")
exit(0)
if g(A,B,C,D,N):
print("YES")
else:
print("NO")
``` | instruction | 0 | 59,544 | 5 | 119,088 |
No | output | 1 | 59,544 | 5 | 119,089 |
Provide a correct Python 3 solution for this coding contest problem.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22 | instruction | 0 | 59,545 | 5 | 119,090 |
"Correct Solution:
```
n=int(input())
a=[0]*n
b=[0]*n
for i in range(n):
a[i],b[i]=map(int,input().split())
ans=0
for i in range(n)[::-1]:
a[i]+=ans
if not a[i]%b[i]==0:
ans+=b[i]-a[i]%b[i]
print(ans)
``` | output | 1 | 59,545 | 5 | 119,091 |
Provide a correct Python 3 solution for this coding contest problem.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22 | instruction | 0 | 59,546 | 5 | 119,092 |
"Correct Solution:
```
N = int(input())
AB = reversed([[int(j) for j in input().split()] for i in range(N)])
ans = 0
for a, b in AB:
a += ans
k = a % b
if k != 0: ans += b - k
print(ans)
``` | output | 1 | 59,546 | 5 | 119,093 |
Provide a correct Python 3 solution for this coding contest problem.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22 | instruction | 0 | 59,547 | 5 | 119,094 |
"Correct Solution:
```
N = int(input())
ABs = [list(map(int, input().split())) for _ in range(N)]
rlt = 0
for ab in ABs[::-1]:
ext = (ab[0]+rlt) % ab[1]
if ext != 0:
rlt += (ab[1] - ext)
print(rlt)
``` | output | 1 | 59,547 | 5 | 119,095 |
Provide a correct Python 3 solution for this coding contest problem.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22 | instruction | 0 | 59,548 | 5 | 119,096 |
"Correct Solution:
```
ans = 0
for A, B in [map(int, input().split()) for _ in range(int(input()))][::-1]:
ans += (B - A - ans) % B
print(ans)
``` | output | 1 | 59,548 | 5 | 119,097 |
Provide a correct Python 3 solution for this coding contest problem.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22 | instruction | 0 | 59,549 | 5 | 119,098 |
"Correct Solution:
```
n = int(input())
x = [[int(i) for i in input().split()] for i in range(n)]
answer = 0
for i in range(n-1,-1,-1):
if (x[i][0]+answer)%x[i][1]!=0: answer+=x[i][1]-((x[i][0]+answer)%x[i][1])
print(answer)
``` | output | 1 | 59,549 | 5 | 119,099 |
Provide a correct Python 3 solution for this coding contest problem.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22 | instruction | 0 | 59,550 | 5 | 119,100 |
"Correct Solution:
```
from math import ceil
n = int(input())
ab = reversed([list(map(int, input().split())) for _ in range(n)])
count = 0
for a, b in ab:
a += count
tb = ceil(a / b) * b
count += tb - a
print(count)
``` | output | 1 | 59,550 | 5 | 119,101 |
Provide a correct Python 3 solution for this coding contest problem.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22 | instruction | 0 | 59,551 | 5 | 119,102 |
"Correct Solution:
```
n=int(input())
A,B=[],[]
for i in range(n):
a,b=map(int,input().split())
A.append(a)
B.append(b)
ans=0
for i in range(n):
a,b=A[-(i+1)],B[-(i+1)]
ans+=((a+ans-1)//b+1)*b-(a+ans)
print(ans)
``` | output | 1 | 59,551 | 5 | 119,103 |
Provide a correct Python 3 solution for this coding contest problem.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22 | instruction | 0 | 59,552 | 5 | 119,104 |
"Correct Solution:
```
n = int(input())
a, b = [0] * n, [0] * n
for i in range(n):
a[i], b[i] = map(int, input().split())
ans = 0
for i in range(n - 1, -1, -1):
ans += (b[i] - (a[i] + ans) % b[i]) % b[i]
print(ans)
``` | output | 1 | 59,552 | 5 | 119,105 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22
Submitted Solution:
```
n = int(input())
AB = [list(map(int, input().split())) for _ in range(n)]
num = 0
for i in range(n):
a, b = AB[n - i - 1]
if (num + a) % b != 0:
num += b - (num + a) % b
print(num)
``` | instruction | 0 | 59,553 | 5 | 119,106 |
Yes | output | 1 | 59,553 | 5 | 119,107 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22
Submitted Solution:
```
N=int(input())
L=[list(map(int,input().split(' '))) for i in range(N)]
ans = 0
for a,b in L[::-1]:
a+=ans
ans += (b-a)%b
print(ans)
``` | instruction | 0 | 59,554 | 5 | 119,108 |
Yes | output | 1 | 59,554 | 5 | 119,109 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22
Submitted Solution:
```
n=int(input())
s=[list(map(int,input().split()))for i in range(n)]
c=0
for i in range(n-1,-1,-1):
p=(s[i][0]+c)%s[i][1]
if p!=0:
c+=s[i][1]-p
print(c)
``` | instruction | 0 | 59,555 | 5 | 119,110 |
Yes | output | 1 | 59,555 | 5 | 119,111 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22
Submitted Solution:
```
n=int(input())
ab=[]
for i in range(n):
tmp=list(map(int,input().split()))
ab.append(tmp)
tmp=0
for a,b in ab[::-1]:
a+=tmp
if a%b!=0:
tmp+=(b-a%b)
print(tmp)
``` | instruction | 0 | 59,556 | 5 | 119,112 |
Yes | output | 1 | 59,556 | 5 | 119,113 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22
Submitted Solution:
```
n = int(input())
a_input = [0]*n
b_input = [0]*n
for i in range(n):
a_input[i],b_input[i]=map(int,input().split())
ans=0
for i in range(n-1,-1,-1):
if a_input[i]%b_input[i]==0:
continue
tmp = b_input[i]-a_input[i]%b_input[i]
ans += tmp
for j in range(i+1):
a_input[j]+=tmp
print(ans)
``` | instruction | 0 | 59,557 | 5 | 119,114 |
No | output | 1 | 59,557 | 5 | 119,115 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22
Submitted Solution:
```
import numpy as np
count = 0
N = int(input())
a = []
b = []
for num in range(N):
x = input().split()
a.append(int(x[0]))
b.append(int(x[1]))
a = np.array(a)
b = np.array(b)
for i in range(len(a)-1, -1, -1):
while a[i] % b[i] != 0:
a[:i+1] += 1
count += 1
print(count)
``` | instruction | 0 | 59,558 | 5 | 119,116 |
No | output | 1 | 59,558 | 5 | 119,117 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22
Submitted Solution:
```
n = int(input())
ab = [map(int, input().split()) for _ in range(n)]
a, b = [list(i) for i in zip(*ab)]
a.reverse()
b.reverse()
ans = 0
num = 0
ruisekiwa = 0
for j in range(n):
a[j] += ruisekiwa
syou = a[j]//b[j]
if a[j] == 0:
num = 0
elif b[j] == 1:
num = 0
elif a[j] == b[j]:
num = 0
else:
num = b[j]*(syou+1) - a[j]
ruisekiwa += num
ans += num
print(ans)
``` | instruction | 0 | 59,559 | 5 | 119,118 |
No | output | 1 | 59,559 | 5 | 119,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are an integer sequence A_1,...,A_N consisting of N terms, and N buttons. When the i-th (1 β¦ i β¦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.
There is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.
Find the minimum number of times Takahashi will press the buttons.
Constraints
* All input values are integers.
* 1 β¦ N β¦ 10^5
* 0 β¦ A_i β¦ 10^9(1 β¦ i β¦ N)
* 1 β¦ B_i β¦ 10^9(1 β¦ i β¦ N)
Input
The input is given from Standard Input in the following format:
N
A_1 B_1
:
A_N B_N
Output
Print an integer representing the minimum number of times Takahashi will press the buttons.
Examples
Input
3
3 5
2 7
9 4
Output
7
Input
7
3 1
4 1
5 9
2 6
5 3
5 8
9 7
Output
22
Submitted Solution:
```
N = int(input())
A = [list(map(int,input().split())) for k in range(N)]
ans = 0
for k in range(N):
A[N-1-k][0] += ans
while A[N-1-k][0]%A[N-1-k][1]!=0:
A[N-1-k][0] += 1
ans += 1
print(ans)
``` | instruction | 0 | 59,560 | 5 | 119,120 |
No | output | 1 | 59,560 | 5 | 119,121 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
2
1 2
Output
2 | instruction | 0 | 59,669 | 5 | 119,338 |
"Correct Solution:
```
N = int(input())
A = [int(x) for x in input().split()]
ans = -1
for i in range(N):
for j in range(i + 1, N):
num = [int(x) for x in str(A[i] * A[j])]
if all(num[i] + 1 == num[i + 1] for i in range(len(num) - 1)) and ans < A[i] * A[j]:
ans = A[i] * A[j]
print(ans)
``` | output | 1 | 59,669 | 5 | 119,339 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
2
1 2
Output
2 | instruction | 0 | 59,670 | 5 | 119,340 |
"Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
safe = list()
for i in range(n - 1):
for j in range(i + 1, n):
pro = a[i] * a[j]
digit = [pro % (10 ** k) // (10 ** (k - 1)) for k in range(1, 10)]
while digit[-1] == 0:
digit = digit[:-1]
if len(digit) == 1:
safe.append(pro)
continue
flag = True
for k in range(len(digit) - 1):
if digit[k + 1] - digit[k] != -1:
flag = False
break
if flag:
safe.append(pro)
if safe:
safe.sort()
print(safe[-1])
else:
print(-1)
``` | output | 1 | 59,670 | 5 | 119,341 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
2
1 2
Output
2 | instruction | 0 | 59,671 | 5 | 119,342 |
"Correct Solution:
```
def is_increasing(n):
for c1,c2 in zip(str(n),str(n)[1:]):
if int(c1) + 1 != int(c2):
return False
return True
N = int(input())
src = list(map(int,input().split()))
ans = -1
for i in range(N-1):
for j in range(i+1,N):
if is_increasing(src[i] * src[j]):
ans = max(ans, src[i] * src[j])
print(ans)
``` | output | 1 | 59,671 | 5 | 119,343 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
2
1 2
Output
2 | instruction | 0 | 59,672 | 5 | 119,344 |
"Correct Solution:
```
import itertools
def check(x: int) -> bool:
s = str(x)
prev = ord(s[0])
for c in s[1:]:
if ord(c) != prev+1:
return False
prev = ord(c)
return True
def main() -> None:
n = int(input())
v = list(map(int, input().split(' ')))
max_ = -1
for c in itertools.combinations(sorted(v), 2):
p = c[0] * c[1]
if check(p):
max_ = max(max_, p)
print(max_)
if __name__ == '__main__':
main()
``` | output | 1 | 59,672 | 5 | 119,345 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
2
1 2
Output
2 | instruction | 0 | 59,673 | 5 | 119,346 |
"Correct Solution:
```
I=input;n=int(I())
def f(x):
a=x%10;x//=10
while x:
if x%10+1!=a:return 0
a=x%10;x//=10
return 1
a=list(map(int,I().split()))
b=-1
for i in range(n):
for j in a[i+1:]:
c=a[i]*j
if(f(c) and b<c):b=c
print(b)
``` | output | 1 | 59,673 | 5 | 119,347 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
2
1 2
Output
2 | instruction | 0 | 59,674 | 5 | 119,348 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
while True:
n = I()
a = LI()
r = -1
for i in range(n):
b = a[i]
for c in a[i+1:]:
t = b*c
if r >= t:
continue
s = str(t)
if all([int(s[k]) == int(s[k+1])-1 for k in range(len(s)-1)]):
r = t
rr.append(r)
break
return '\n'.join(map(str, rr))
print(main())
``` | output | 1 | 59,674 | 5 | 119,349 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
2
1 2
Output
2 | instruction | 0 | 59,675 | 5 | 119,350 |
"Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
ma = -1
for i in range(n - 1):
for j in range(i + 1, n):
pro = a[i] * a[j]
digit = [pro % (10 ** k) // (10 ** (k - 1)) for k in range(1, 10)]
while digit[-1] == 0:
digit = digit[:-1]
if len(digit) == 1:
ma = max(ma, pro)
continue
flag = True
for k in range(len(digit) - 1):
if digit[k + 1] - digit[k] != -1:
flag = False
break
if flag:
ma = max(ma, pro)
print(ma)
``` | output | 1 | 59,675 | 5 | 119,351 |
Provide a correct Python 3 solution for this coding contest problem.
Example
Input
2
1 2
Output
2 | instruction | 0 | 59,676 | 5 | 119,352 |
"Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
safe = set()
for i in range(n - 1):
for j in range(i + 1, n):
pro = a[i] * a[j]
digit = [pro % (10 ** k) // (10 ** (k - 1)) for k in range(1, 10)]
while digit[-1] == 0:
digit = digit[:-1]
if len(digit) == 1:
safe.add(pro)
continue
flag = True
for k in range(len(digit) - 1):
if digit[k + 1] - digit[k] != -1:
flag = False
break
if flag:
safe.add(pro)
if safe:
print(max(safe))
else:
print(-1)
``` | output | 1 | 59,676 | 5 | 119,353 |
Provide a correct Python 3 solution for this coding contest problem.
C: Prayer (Pray)
Some twins are famous for praying before the contest.
There are four integers $ H, W, X, Y $, and it seems unlucky if $ H \ times W $ and $ x + y $ are both odd numbers.
input
Four integers $ H, W, X, Y $ are given, separated by spaces.
output
Output "No" if you are unlucky, or "Yes" if not. But don't forget the last line break.
Constraint
* $ H, W, X, Y $ are integers greater than or equal to $ 1 $ and less than or equal to $ 100 $
Input example 1
3 5 1 4
Output example 1
No
$ 3 \ times 5 = 15 $, $ 1 + 4 = 5 $, both odd numbers, so it's unlucky.
Input example 2
3 5 2 4
Output example 2
Yes
$ 3 \ times 5 = 15 $ is odd, but $ 2 + 4 = 6 $ is even, so good luck isn't bad.
Example
Input
3 5 1 4
Output
No | instruction | 0 | 59,678 | 5 | 119,356 |
"Correct Solution:
```
h,w,x,y = map(int ,input().split())
if (h*w) % 2 + (x + y) % 2 == 2:
print('No')
else:
print('Yes')
``` | output | 1 | 59,678 | 5 | 119,357 |
Provide a correct Python 3 solution for this coding contest problem.
C: Prayer (Pray)
Some twins are famous for praying before the contest.
There are four integers $ H, W, X, Y $, and it seems unlucky if $ H \ times W $ and $ x + y $ are both odd numbers.
input
Four integers $ H, W, X, Y $ are given, separated by spaces.
output
Output "No" if you are unlucky, or "Yes" if not. But don't forget the last line break.
Constraint
* $ H, W, X, Y $ are integers greater than or equal to $ 1 $ and less than or equal to $ 100 $
Input example 1
3 5 1 4
Output example 1
No
$ 3 \ times 5 = 15 $, $ 1 + 4 = 5 $, both odd numbers, so it's unlucky.
Input example 2
3 5 2 4
Output example 2
Yes
$ 3 \ times 5 = 15 $ is odd, but $ 2 + 4 = 6 $ is even, so good luck isn't bad.
Example
Input
3 5 1 4
Output
No | instruction | 0 | 59,679 | 5 | 119,358 |
"Correct Solution:
```
h,w,x,y = map(int,input().split())
print('No' if (h*w)%2==1 and (x+y)%2==1 else 'Yes')
``` | output | 1 | 59,679 | 5 | 119,359 |
Provide a correct Python 3 solution for this coding contest problem.
C: Prayer (Pray)
Some twins are famous for praying before the contest.
There are four integers $ H, W, X, Y $, and it seems unlucky if $ H \ times W $ and $ x + y $ are both odd numbers.
input
Four integers $ H, W, X, Y $ are given, separated by spaces.
output
Output "No" if you are unlucky, or "Yes" if not. But don't forget the last line break.
Constraint
* $ H, W, X, Y $ are integers greater than or equal to $ 1 $ and less than or equal to $ 100 $
Input example 1
3 5 1 4
Output example 1
No
$ 3 \ times 5 = 15 $, $ 1 + 4 = 5 $, both odd numbers, so it's unlucky.
Input example 2
3 5 2 4
Output example 2
Yes
$ 3 \ times 5 = 15 $ is odd, but $ 2 + 4 = 6 $ is even, so good luck isn't bad.
Example
Input
3 5 1 4
Output
No | instruction | 0 | 59,680 | 5 | 119,360 |
"Correct Solution:
```
H,W,x,y=map(int,input().split())
if (H*W)%2==1 and (x+y)%2==1:
print("No")
else:
print("Yes")
``` | output | 1 | 59,680 | 5 | 119,361 |
Provide a correct Python 3 solution for this coding contest problem.
C: Prayer (Pray)
Some twins are famous for praying before the contest.
There are four integers $ H, W, X, Y $, and it seems unlucky if $ H \ times W $ and $ x + y $ are both odd numbers.
input
Four integers $ H, W, X, Y $ are given, separated by spaces.
output
Output "No" if you are unlucky, or "Yes" if not. But don't forget the last line break.
Constraint
* $ H, W, X, Y $ are integers greater than or equal to $ 1 $ and less than or equal to $ 100 $
Input example 1
3 5 1 4
Output example 1
No
$ 3 \ times 5 = 15 $, $ 1 + 4 = 5 $, both odd numbers, so it's unlucky.
Input example 2
3 5 2 4
Output example 2
Yes
$ 3 \ times 5 = 15 $ is odd, but $ 2 + 4 = 6 $ is even, so good luck isn't bad.
Example
Input
3 5 1 4
Output
No | instruction | 0 | 59,681 | 5 | 119,362 |
"Correct Solution:
```
a,b,c,d = map(int,input().split())
if a*b%2==1 and (c+d)%2 == 1:
print("No")
else:
print("Yes")
``` | output | 1 | 59,681 | 5 | 119,363 |
Provide a correct Python 3 solution for this coding contest problem.
C: Prayer (Pray)
Some twins are famous for praying before the contest.
There are four integers $ H, W, X, Y $, and it seems unlucky if $ H \ times W $ and $ x + y $ are both odd numbers.
input
Four integers $ H, W, X, Y $ are given, separated by spaces.
output
Output "No" if you are unlucky, or "Yes" if not. But don't forget the last line break.
Constraint
* $ H, W, X, Y $ are integers greater than or equal to $ 1 $ and less than or equal to $ 100 $
Input example 1
3 5 1 4
Output example 1
No
$ 3 \ times 5 = 15 $, $ 1 + 4 = 5 $, both odd numbers, so it's unlucky.
Input example 2
3 5 2 4
Output example 2
Yes
$ 3 \ times 5 = 15 $ is odd, but $ 2 + 4 = 6 $ is even, so good luck isn't bad.
Example
Input
3 5 1 4
Output
No | instruction | 0 | 59,682 | 5 | 119,364 |
"Correct Solution:
```
H, W, X, Y = [int(x) for x in input().split()]
ans = 'No' if (H * W) % 2 + (X + Y) % 2 == 2 else 'Yes'
print(ans)
``` | output | 1 | 59,682 | 5 | 119,365 |
Provide a correct Python 3 solution for this coding contest problem.
C: Prayer (Pray)
Some twins are famous for praying before the contest.
There are four integers $ H, W, X, Y $, and it seems unlucky if $ H \ times W $ and $ x + y $ are both odd numbers.
input
Four integers $ H, W, X, Y $ are given, separated by spaces.
output
Output "No" if you are unlucky, or "Yes" if not. But don't forget the last line break.
Constraint
* $ H, W, X, Y $ are integers greater than or equal to $ 1 $ and less than or equal to $ 100 $
Input example 1
3 5 1 4
Output example 1
No
$ 3 \ times 5 = 15 $, $ 1 + 4 = 5 $, both odd numbers, so it's unlucky.
Input example 2
3 5 2 4
Output example 2
Yes
$ 3 \ times 5 = 15 $ is odd, but $ 2 + 4 = 6 $ is even, so good luck isn't bad.
Example
Input
3 5 1 4
Output
No | instruction | 0 | 59,683 | 5 | 119,366 |
"Correct Solution:
```
h,w,x,y=map(int,input().split())
print(["No","Yes"][h*w%2==0 or(x+y)%2==0])
``` | output | 1 | 59,683 | 5 | 119,367 |
Provide a correct Python 3 solution for this coding contest problem.
C: Prayer (Pray)
Some twins are famous for praying before the contest.
There are four integers $ H, W, X, Y $, and it seems unlucky if $ H \ times W $ and $ x + y $ are both odd numbers.
input
Four integers $ H, W, X, Y $ are given, separated by spaces.
output
Output "No" if you are unlucky, or "Yes" if not. But don't forget the last line break.
Constraint
* $ H, W, X, Y $ are integers greater than or equal to $ 1 $ and less than or equal to $ 100 $
Input example 1
3 5 1 4
Output example 1
No
$ 3 \ times 5 = 15 $, $ 1 + 4 = 5 $, both odd numbers, so it's unlucky.
Input example 2
3 5 2 4
Output example 2
Yes
$ 3 \ times 5 = 15 $ is odd, but $ 2 + 4 = 6 $ is even, so good luck isn't bad.
Example
Input
3 5 1 4
Output
No | instruction | 0 | 59,684 | 5 | 119,368 |
"Correct Solution:
```
H,W,x,y=map(int,input().split())
if H*W%2==1 and (x+y)%2==1:
print("No")
else:
print("Yes")
``` | output | 1 | 59,684 | 5 | 119,369 |
Provide a correct Python 3 solution for this coding contest problem.
C: Prayer (Pray)
Some twins are famous for praying before the contest.
There are four integers $ H, W, X, Y $, and it seems unlucky if $ H \ times W $ and $ x + y $ are both odd numbers.
input
Four integers $ H, W, X, Y $ are given, separated by spaces.
output
Output "No" if you are unlucky, or "Yes" if not. But don't forget the last line break.
Constraint
* $ H, W, X, Y $ are integers greater than or equal to $ 1 $ and less than or equal to $ 100 $
Input example 1
3 5 1 4
Output example 1
No
$ 3 \ times 5 = 15 $, $ 1 + 4 = 5 $, both odd numbers, so it's unlucky.
Input example 2
3 5 2 4
Output example 2
Yes
$ 3 \ times 5 = 15 $ is odd, but $ 2 + 4 = 6 $ is even, so good luck isn't bad.
Example
Input
3 5 1 4
Output
No | instruction | 0 | 59,685 | 5 | 119,370 |
"Correct Solution:
```
a,b,c,d=map(int,input().split())
print("No" if ((a*b)%2)*((c+d)%2)==1 else "Yes")
``` | output | 1 | 59,685 | 5 | 119,371 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
C: Prayer (Pray)
Some twins are famous for praying before the contest.
There are four integers $ H, W, X, Y $, and it seems unlucky if $ H \ times W $ and $ x + y $ are both odd numbers.
input
Four integers $ H, W, X, Y $ are given, separated by spaces.
output
Output "No" if you are unlucky, or "Yes" if not. But don't forget the last line break.
Constraint
* $ H, W, X, Y $ are integers greater than or equal to $ 1 $ and less than or equal to $ 100 $
Input example 1
3 5 1 4
Output example 1
No
$ 3 \ times 5 = 15 $, $ 1 + 4 = 5 $, both odd numbers, so it's unlucky.
Input example 2
3 5 2 4
Output example 2
Yes
$ 3 \ times 5 = 15 $ is odd, but $ 2 + 4 = 6 $ is even, so good luck isn't bad.
Example
Input
3 5 1 4
Output
No
Submitted Solution:
```
h, w, x, y = map(int, input().split())
print('No' if h*w % 2 == 1 and (x+y) % 2 == 1 else 'Yes')
``` | instruction | 0 | 59,686 | 5 | 119,372 |
Yes | output | 1 | 59,686 | 5 | 119,373 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
C: Prayer (Pray)
Some twins are famous for praying before the contest.
There are four integers $ H, W, X, Y $, and it seems unlucky if $ H \ times W $ and $ x + y $ are both odd numbers.
input
Four integers $ H, W, X, Y $ are given, separated by spaces.
output
Output "No" if you are unlucky, or "Yes" if not. But don't forget the last line break.
Constraint
* $ H, W, X, Y $ are integers greater than or equal to $ 1 $ and less than or equal to $ 100 $
Input example 1
3 5 1 4
Output example 1
No
$ 3 \ times 5 = 15 $, $ 1 + 4 = 5 $, both odd numbers, so it's unlucky.
Input example 2
3 5 2 4
Output example 2
Yes
$ 3 \ times 5 = 15 $ is odd, but $ 2 + 4 = 6 $ is even, so good luck isn't bad.
Example
Input
3 5 1 4
Output
No
Submitted Solution:
```
h, w, x, y = map(int, input().split())
if h * w % 2 == 1 and (x+y) % 2 == 1:
print("No")
else:
print("Yes")
``` | instruction | 0 | 59,687 | 5 | 119,374 |
Yes | output | 1 | 59,687 | 5 | 119,375 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
C: Prayer (Pray)
Some twins are famous for praying before the contest.
There are four integers $ H, W, X, Y $, and it seems unlucky if $ H \ times W $ and $ x + y $ are both odd numbers.
input
Four integers $ H, W, X, Y $ are given, separated by spaces.
output
Output "No" if you are unlucky, or "Yes" if not. But don't forget the last line break.
Constraint
* $ H, W, X, Y $ are integers greater than or equal to $ 1 $ and less than or equal to $ 100 $
Input example 1
3 5 1 4
Output example 1
No
$ 3 \ times 5 = 15 $, $ 1 + 4 = 5 $, both odd numbers, so it's unlucky.
Input example 2
3 5 2 4
Output example 2
Yes
$ 3 \ times 5 = 15 $ is odd, but $ 2 + 4 = 6 $ is even, so good luck isn't bad.
Example
Input
3 5 1 4
Output
No
Submitted Solution:
```
H, W, X, Y = map(int, input().split())
if ((H * W) * (X + Y)) % 2:
print('No')
else:
print('Yes')
``` | instruction | 0 | 59,688 | 5 | 119,376 |
Yes | output | 1 | 59,688 | 5 | 119,377 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
C: Prayer (Pray)
Some twins are famous for praying before the contest.
There are four integers $ H, W, X, Y $, and it seems unlucky if $ H \ times W $ and $ x + y $ are both odd numbers.
input
Four integers $ H, W, X, Y $ are given, separated by spaces.
output
Output "No" if you are unlucky, or "Yes" if not. But don't forget the last line break.
Constraint
* $ H, W, X, Y $ are integers greater than or equal to $ 1 $ and less than or equal to $ 100 $
Input example 1
3 5 1 4
Output example 1
No
$ 3 \ times 5 = 15 $, $ 1 + 4 = 5 $, both odd numbers, so it's unlucky.
Input example 2
3 5 2 4
Output example 2
Yes
$ 3 \ times 5 = 15 $ is odd, but $ 2 + 4 = 6 $ is even, so good luck isn't bad.
Example
Input
3 5 1 4
Output
No
Submitted Solution:
```
h,w,x,y=map(int,input().split());print(["Yes","No"][h*w%2*(x+y)%2])
``` | instruction | 0 | 59,689 | 5 | 119,378 |
Yes | output | 1 | 59,689 | 5 | 119,379 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three sequences: a_1, a_2, β¦, a_n; b_1, b_2, β¦, b_n; c_1, c_2, β¦, c_n.
For each i, a_i β b_i, a_i β c_i, b_i β c_i.
Find a sequence p_1, p_2, β¦, p_n, that satisfy the following conditions:
* p_i β \\{a_i, b_i, c_i\}
* p_i β p_{(i mod n) + 1}.
In other words, for each element, you need to choose one of the three possible values, such that no two adjacent elements (where we consider elements i,i+1 adjacent for i<n and also elements 1 and n) will have equal value.
It can be proved that in the given constraints solution always exists. You don't need to minimize/maximize anything, you need to find any proper sequence.
Input
The first line of input contains one integer t (1 β€ t β€ 100): the number of test cases.
The first line of each test case contains one integer n (3 β€ n β€ 100): the number of elements in the given sequences.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 100).
The third line contains n integers b_1, b_2, β¦, b_n (1 β€ b_i β€ 100).
The fourth line contains n integers c_1, c_2, β¦, c_n (1 β€ c_i β€ 100).
It is guaranteed that a_i β b_i, a_i β c_i, b_i β c_i for all i.
Output
For each test case, print n integers: p_1, p_2, β¦, p_n (p_i β \\{a_i, b_i, c_i\}, p_i β p_{i mod n + 1}).
If there are several solutions, you can print any.
Example
Input
5
3
1 1 1
2 2 2
3 3 3
4
1 2 1 2
2 1 2 1
3 4 3 4
7
1 3 3 1 1 1 1
2 4 4 3 2 2 4
4 2 2 2 4 4 2
3
1 2 1
2 3 3
3 1 2
10
1 1 1 2 2 2 3 3 3 1
2 2 2 3 3 3 1 1 1 2
3 3 3 1 1 1 2 2 2 3
Output
1 2 3
1 2 1 2
1 3 4 3 2 4 2
1 3 2
1 2 3 1 2 3 1 2 3 2
Note
In the first test case p = [1, 2, 3].
It is a correct answer, because:
* p_1 = 1 = a_1, p_2 = 2 = b_2, p_3 = 3 = c_3
* p_1 β p_2 , p_2 β p_3 , p_3 β p_1
All possible correct answers to this test case are: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1].
In the second test case p = [1, 2, 1, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = a_3, p_4 = a_4. Also we can see, that no two adjacent elements of the sequence are equal.
In the third test case p = [1, 3, 4, 3, 2, 4, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = b_3, p_4 = b_4, p_5 = b_5, p_6 = c_6, p_7 = c_7. Also we can see, that no two adjacent elements of the sequence are equal.
Submitted Solution:
```
testcases = int(input())
for testcase in range(testcases):
n = int(input())
arra = []
arrb = []
arrc = []
temparr = input()
temparr = temparr.split()
for i in temparr:
arra.append(int(i))
temparr = input()
temparr = temparr.split()
for i in temparr:
arrb.append(int(i))
temparr = input()
temparr = temparr.split()
for i in temparr:
arrc.append(int(i))
ans = []
for i in range(n):
if i == 0 :
ans.append(arra[i])
continue
elif i != n-1:
if arra[i] != ans[-1]:
ans.append(arra[i])
continue
elif arrb[i] != ans[-1]:
ans.append(arrb[i])
continue
else:
ans.append(arrc[i])
else:
if arra[i] != ans[-1] and arra[i] != ans[0]:
ans.append(arra[i])
elif arrb[i] != ans[-1] and arrb[i] != ans[0]:
ans.append(arrb[i])
else:
ans.append(arrc[i])
sans = []
for i in ans:
sans.append(str(i))
print(" ".join(sans))
``` | instruction | 0 | 59,908 | 5 | 119,816 |
Yes | output | 1 | 59,908 | 5 | 119,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three sequences: a_1, a_2, β¦, a_n; b_1, b_2, β¦, b_n; c_1, c_2, β¦, c_n.
For each i, a_i β b_i, a_i β c_i, b_i β c_i.
Find a sequence p_1, p_2, β¦, p_n, that satisfy the following conditions:
* p_i β \\{a_i, b_i, c_i\}
* p_i β p_{(i mod n) + 1}.
In other words, for each element, you need to choose one of the three possible values, such that no two adjacent elements (where we consider elements i,i+1 adjacent for i<n and also elements 1 and n) will have equal value.
It can be proved that in the given constraints solution always exists. You don't need to minimize/maximize anything, you need to find any proper sequence.
Input
The first line of input contains one integer t (1 β€ t β€ 100): the number of test cases.
The first line of each test case contains one integer n (3 β€ n β€ 100): the number of elements in the given sequences.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 100).
The third line contains n integers b_1, b_2, β¦, b_n (1 β€ b_i β€ 100).
The fourth line contains n integers c_1, c_2, β¦, c_n (1 β€ c_i β€ 100).
It is guaranteed that a_i β b_i, a_i β c_i, b_i β c_i for all i.
Output
For each test case, print n integers: p_1, p_2, β¦, p_n (p_i β \\{a_i, b_i, c_i\}, p_i β p_{i mod n + 1}).
If there are several solutions, you can print any.
Example
Input
5
3
1 1 1
2 2 2
3 3 3
4
1 2 1 2
2 1 2 1
3 4 3 4
7
1 3 3 1 1 1 1
2 4 4 3 2 2 4
4 2 2 2 4 4 2
3
1 2 1
2 3 3
3 1 2
10
1 1 1 2 2 2 3 3 3 1
2 2 2 3 3 3 1 1 1 2
3 3 3 1 1 1 2 2 2 3
Output
1 2 3
1 2 1 2
1 3 4 3 2 4 2
1 3 2
1 2 3 1 2 3 1 2 3 2
Note
In the first test case p = [1, 2, 3].
It is a correct answer, because:
* p_1 = 1 = a_1, p_2 = 2 = b_2, p_3 = 3 = c_3
* p_1 β p_2 , p_2 β p_3 , p_3 β p_1
All possible correct answers to this test case are: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1].
In the second test case p = [1, 2, 1, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = a_3, p_4 = a_4. Also we can see, that no two adjacent elements of the sequence are equal.
In the third test case p = [1, 3, 4, 3, 2, 4, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = b_3, p_4 = b_4, p_5 = b_5, p_6 = c_6, p_7 = c_7. Also we can see, that no two adjacent elements of the sequence are equal.
Submitted Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
#New Imports
def solution():
n = int(input())
a = list(map(int,input().split()))
b = list(map(int,input().split()))
c = list(map(int,input().split()))
p = [0]*n
p[-1] = a[-1]
for i in reversed(range(n-1)):
if a[i] != p[i+1]:
p[i] = a[i]
elif b[i] != p[i+1]:
p[i] = b[i]
else:
p[i] = c[i]
if p[n-1] == p[0]:
if a[n-1] != p[0] and p[n-2] != a[n-1]:
p[n-1] = a[n-1]
elif b[n-1] != p[0] and p[n-2] != b[n-1]:
p[n-1] = b[n-1]
else:
p[n-1] = c[n-1]
print(*p)
def main():
testcases = 1
testcases = int(input())
for _ in range(testcases):
solution()
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
main()
``` | instruction | 0 | 59,909 | 5 | 119,818 |
Yes | output | 1 | 59,909 | 5 | 119,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three sequences: a_1, a_2, β¦, a_n; b_1, b_2, β¦, b_n; c_1, c_2, β¦, c_n.
For each i, a_i β b_i, a_i β c_i, b_i β c_i.
Find a sequence p_1, p_2, β¦, p_n, that satisfy the following conditions:
* p_i β \\{a_i, b_i, c_i\}
* p_i β p_{(i mod n) + 1}.
In other words, for each element, you need to choose one of the three possible values, such that no two adjacent elements (where we consider elements i,i+1 adjacent for i<n and also elements 1 and n) will have equal value.
It can be proved that in the given constraints solution always exists. You don't need to minimize/maximize anything, you need to find any proper sequence.
Input
The first line of input contains one integer t (1 β€ t β€ 100): the number of test cases.
The first line of each test case contains one integer n (3 β€ n β€ 100): the number of elements in the given sequences.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 100).
The third line contains n integers b_1, b_2, β¦, b_n (1 β€ b_i β€ 100).
The fourth line contains n integers c_1, c_2, β¦, c_n (1 β€ c_i β€ 100).
It is guaranteed that a_i β b_i, a_i β c_i, b_i β c_i for all i.
Output
For each test case, print n integers: p_1, p_2, β¦, p_n (p_i β \\{a_i, b_i, c_i\}, p_i β p_{i mod n + 1}).
If there are several solutions, you can print any.
Example
Input
5
3
1 1 1
2 2 2
3 3 3
4
1 2 1 2
2 1 2 1
3 4 3 4
7
1 3 3 1 1 1 1
2 4 4 3 2 2 4
4 2 2 2 4 4 2
3
1 2 1
2 3 3
3 1 2
10
1 1 1 2 2 2 3 3 3 1
2 2 2 3 3 3 1 1 1 2
3 3 3 1 1 1 2 2 2 3
Output
1 2 3
1 2 1 2
1 3 4 3 2 4 2
1 3 2
1 2 3 1 2 3 1 2 3 2
Note
In the first test case p = [1, 2, 3].
It is a correct answer, because:
* p_1 = 1 = a_1, p_2 = 2 = b_2, p_3 = 3 = c_3
* p_1 β p_2 , p_2 β p_3 , p_3 β p_1
All possible correct answers to this test case are: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1].
In the second test case p = [1, 2, 1, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = a_3, p_4 = a_4. Also we can see, that no two adjacent elements of the sequence are equal.
In the third test case p = [1, 3, 4, 3, 2, 4, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = b_3, p_4 = b_4, p_5 = b_5, p_6 = c_6, p_7 = c_7. Also we can see, that no two adjacent elements of the sequence are equal.
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Wed Sep 30 20:34:22 2020
@author: Dark Soul
"""
t=int(input(''))
for i in range(t):
n=int(input(''))
a=list(map(int,input().split()))
b=list(map(int,input().split()))
c=list(map(int,input().split()))
sol=[0]*n
sol[0]=a[0]
for i in range(1,n):
if a[i]!=sol[i-1]:
sol[i]=a[i]
elif b[i]!=sol[i-1]:
sol[i]=b[i]
else:
sol[i]=c[i]
if sol[0]==sol[n-1]:
if a[i]!=sol[0] and a[i]!=sol[n-2]:
sol[i]=a[i]
elif b[i]!=sol[0] and b[i]!=sol[n-2]:
sol[i]=b[i]
else:
sol[i]=c[i]
print(*sol)
``` | instruction | 0 | 59,910 | 5 | 119,820 |
Yes | output | 1 | 59,910 | 5 | 119,821 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three sequences: a_1, a_2, β¦, a_n; b_1, b_2, β¦, b_n; c_1, c_2, β¦, c_n.
For each i, a_i β b_i, a_i β c_i, b_i β c_i.
Find a sequence p_1, p_2, β¦, p_n, that satisfy the following conditions:
* p_i β \\{a_i, b_i, c_i\}
* p_i β p_{(i mod n) + 1}.
In other words, for each element, you need to choose one of the three possible values, such that no two adjacent elements (where we consider elements i,i+1 adjacent for i<n and also elements 1 and n) will have equal value.
It can be proved that in the given constraints solution always exists. You don't need to minimize/maximize anything, you need to find any proper sequence.
Input
The first line of input contains one integer t (1 β€ t β€ 100): the number of test cases.
The first line of each test case contains one integer n (3 β€ n β€ 100): the number of elements in the given sequences.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 100).
The third line contains n integers b_1, b_2, β¦, b_n (1 β€ b_i β€ 100).
The fourth line contains n integers c_1, c_2, β¦, c_n (1 β€ c_i β€ 100).
It is guaranteed that a_i β b_i, a_i β c_i, b_i β c_i for all i.
Output
For each test case, print n integers: p_1, p_2, β¦, p_n (p_i β \\{a_i, b_i, c_i\}, p_i β p_{i mod n + 1}).
If there are several solutions, you can print any.
Example
Input
5
3
1 1 1
2 2 2
3 3 3
4
1 2 1 2
2 1 2 1
3 4 3 4
7
1 3 3 1 1 1 1
2 4 4 3 2 2 4
4 2 2 2 4 4 2
3
1 2 1
2 3 3
3 1 2
10
1 1 1 2 2 2 3 3 3 1
2 2 2 3 3 3 1 1 1 2
3 3 3 1 1 1 2 2 2 3
Output
1 2 3
1 2 1 2
1 3 4 3 2 4 2
1 3 2
1 2 3 1 2 3 1 2 3 2
Note
In the first test case p = [1, 2, 3].
It is a correct answer, because:
* p_1 = 1 = a_1, p_2 = 2 = b_2, p_3 = 3 = c_3
* p_1 β p_2 , p_2 β p_3 , p_3 β p_1
All possible correct answers to this test case are: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1].
In the second test case p = [1, 2, 1, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = a_3, p_4 = a_4. Also we can see, that no two adjacent elements of the sequence are equal.
In the third test case p = [1, 3, 4, 3, 2, 4, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = b_3, p_4 = b_4, p_5 = b_5, p_6 = c_6, p_7 = c_7. Also we can see, that no two adjacent elements of the sequence are equal.
Submitted Solution:
```
import sys
#import math
#from queue import *
#import random
#sys.setrecursionlimit(int(1e6))
input = sys.stdin.readline
############ ---- USER DEFINED INPUT FUNCTIONS ---- ############
def inp():
return(int(input()))
def inara():
return(list(map(int,input().split())))
def insr():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
################################################################
############ ---- THE ACTUAL CODE STARTS BELOW ---- ############
t=inp()
for _ in range(t):
n=inp()
a=inara()
b=inara()
c=inara()
ans=[]
ans.append(a[0])
for i in range(1,n):
if ans[i-1]!=a[i]:
ans.append(a[i])
elif ans[i-1]!=b[i]:
ans.append(b[i])
else:
ans.append[c[i]]
for i in range(n-1):
print(ans[i],end=" ")
if ans[-1]==ans[0]:
if (ans[0]!=a[-1]) and (ans[-2]!=a[-1]):
print(a[-1])
elif (ans[0]!=b[-1]) and (ans[-2]!=b[-1]):
print(b[-1])
else:
print(c[-1])
else:
print(ans[-1])
``` | instruction | 0 | 59,911 | 5 | 119,822 |
Yes | output | 1 | 59,911 | 5 | 119,823 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three sequences: a_1, a_2, β¦, a_n; b_1, b_2, β¦, b_n; c_1, c_2, β¦, c_n.
For each i, a_i β b_i, a_i β c_i, b_i β c_i.
Find a sequence p_1, p_2, β¦, p_n, that satisfy the following conditions:
* p_i β \\{a_i, b_i, c_i\}
* p_i β p_{(i mod n) + 1}.
In other words, for each element, you need to choose one of the three possible values, such that no two adjacent elements (where we consider elements i,i+1 adjacent for i<n and also elements 1 and n) will have equal value.
It can be proved that in the given constraints solution always exists. You don't need to minimize/maximize anything, you need to find any proper sequence.
Input
The first line of input contains one integer t (1 β€ t β€ 100): the number of test cases.
The first line of each test case contains one integer n (3 β€ n β€ 100): the number of elements in the given sequences.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 100).
The third line contains n integers b_1, b_2, β¦, b_n (1 β€ b_i β€ 100).
The fourth line contains n integers c_1, c_2, β¦, c_n (1 β€ c_i β€ 100).
It is guaranteed that a_i β b_i, a_i β c_i, b_i β c_i for all i.
Output
For each test case, print n integers: p_1, p_2, β¦, p_n (p_i β \\{a_i, b_i, c_i\}, p_i β p_{i mod n + 1}).
If there are several solutions, you can print any.
Example
Input
5
3
1 1 1
2 2 2
3 3 3
4
1 2 1 2
2 1 2 1
3 4 3 4
7
1 3 3 1 1 1 1
2 4 4 3 2 2 4
4 2 2 2 4 4 2
3
1 2 1
2 3 3
3 1 2
10
1 1 1 2 2 2 3 3 3 1
2 2 2 3 3 3 1 1 1 2
3 3 3 1 1 1 2 2 2 3
Output
1 2 3
1 2 1 2
1 3 4 3 2 4 2
1 3 2
1 2 3 1 2 3 1 2 3 2
Note
In the first test case p = [1, 2, 3].
It is a correct answer, because:
* p_1 = 1 = a_1, p_2 = 2 = b_2, p_3 = 3 = c_3
* p_1 β p_2 , p_2 β p_3 , p_3 β p_1
All possible correct answers to this test case are: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1].
In the second test case p = [1, 2, 1, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = a_3, p_4 = a_4. Also we can see, that no two adjacent elements of the sequence are equal.
In the third test case p = [1, 3, 4, 3, 2, 4, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = b_3, p_4 = b_4, p_5 = b_5, p_6 = c_6, p_7 = c_7. Also we can see, that no two adjacent elements of the sequence are equal.
Submitted Solution:
```
cases = int(input())
while cases:
cases -= 1
num = int(input())
ans = [1]
a = list(map(int, input().split()))
b = list(map(int, input().split()))
c = list(map(int, input().split()))
for i in range(num):
if a[i] != ans[-1]:
ans.append(a[i])
else:
ans.append(b[i])
ans = ans[1:]
if ans[0] == ans[-1]:
ans[-1] = c[-1]
print(*ans)
``` | instruction | 0 | 59,912 | 5 | 119,824 |
No | output | 1 | 59,912 | 5 | 119,825 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three sequences: a_1, a_2, β¦, a_n; b_1, b_2, β¦, b_n; c_1, c_2, β¦, c_n.
For each i, a_i β b_i, a_i β c_i, b_i β c_i.
Find a sequence p_1, p_2, β¦, p_n, that satisfy the following conditions:
* p_i β \\{a_i, b_i, c_i\}
* p_i β p_{(i mod n) + 1}.
In other words, for each element, you need to choose one of the three possible values, such that no two adjacent elements (where we consider elements i,i+1 adjacent for i<n and also elements 1 and n) will have equal value.
It can be proved that in the given constraints solution always exists. You don't need to minimize/maximize anything, you need to find any proper sequence.
Input
The first line of input contains one integer t (1 β€ t β€ 100): the number of test cases.
The first line of each test case contains one integer n (3 β€ n β€ 100): the number of elements in the given sequences.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 100).
The third line contains n integers b_1, b_2, β¦, b_n (1 β€ b_i β€ 100).
The fourth line contains n integers c_1, c_2, β¦, c_n (1 β€ c_i β€ 100).
It is guaranteed that a_i β b_i, a_i β c_i, b_i β c_i for all i.
Output
For each test case, print n integers: p_1, p_2, β¦, p_n (p_i β \\{a_i, b_i, c_i\}, p_i β p_{i mod n + 1}).
If there are several solutions, you can print any.
Example
Input
5
3
1 1 1
2 2 2
3 3 3
4
1 2 1 2
2 1 2 1
3 4 3 4
7
1 3 3 1 1 1 1
2 4 4 3 2 2 4
4 2 2 2 4 4 2
3
1 2 1
2 3 3
3 1 2
10
1 1 1 2 2 2 3 3 3 1
2 2 2 3 3 3 1 1 1 2
3 3 3 1 1 1 2 2 2 3
Output
1 2 3
1 2 1 2
1 3 4 3 2 4 2
1 3 2
1 2 3 1 2 3 1 2 3 2
Note
In the first test case p = [1, 2, 3].
It is a correct answer, because:
* p_1 = 1 = a_1, p_2 = 2 = b_2, p_3 = 3 = c_3
* p_1 β p_2 , p_2 β p_3 , p_3 β p_1
All possible correct answers to this test case are: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1].
In the second test case p = [1, 2, 1, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = a_3, p_4 = a_4. Also we can see, that no two adjacent elements of the sequence are equal.
In the third test case p = [1, 3, 4, 3, 2, 4, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = b_3, p_4 = b_4, p_5 = b_5, p_6 = c_6, p_7 = c_7. Also we can see, that no two adjacent elements of the sequence are equal.
Submitted Solution:
```
t=int(input())
for z in range(t):
n=int(input())
a=[int(x) for x in input().split()]
b=[int(x) for x in input().split()]
c=[int(x) for x in input().split()]
temp=[]
ans=[]
temp.append(a[0])
temp.append(b[0])
temp.append(c[0])
temp=sorted(temp)
ans.append(temp[0])
for i in range(1,n):
temp=[]
temp.append(a[i])
temp.append(b[i])
temp.append(c[i])
temp=sorted(temp)
if temp[0]!=ans[i-1]:
ans.append(temp[0])
else:
ans.append(temp[1])
print(ans)
``` | instruction | 0 | 59,913 | 5 | 119,826 |
No | output | 1 | 59,913 | 5 | 119,827 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given three sequences: a_1, a_2, β¦, a_n; b_1, b_2, β¦, b_n; c_1, c_2, β¦, c_n.
For each i, a_i β b_i, a_i β c_i, b_i β c_i.
Find a sequence p_1, p_2, β¦, p_n, that satisfy the following conditions:
* p_i β \\{a_i, b_i, c_i\}
* p_i β p_{(i mod n) + 1}.
In other words, for each element, you need to choose one of the three possible values, such that no two adjacent elements (where we consider elements i,i+1 adjacent for i<n and also elements 1 and n) will have equal value.
It can be proved that in the given constraints solution always exists. You don't need to minimize/maximize anything, you need to find any proper sequence.
Input
The first line of input contains one integer t (1 β€ t β€ 100): the number of test cases.
The first line of each test case contains one integer n (3 β€ n β€ 100): the number of elements in the given sequences.
The second line contains n integers a_1, a_2, β¦, a_n (1 β€ a_i β€ 100).
The third line contains n integers b_1, b_2, β¦, b_n (1 β€ b_i β€ 100).
The fourth line contains n integers c_1, c_2, β¦, c_n (1 β€ c_i β€ 100).
It is guaranteed that a_i β b_i, a_i β c_i, b_i β c_i for all i.
Output
For each test case, print n integers: p_1, p_2, β¦, p_n (p_i β \\{a_i, b_i, c_i\}, p_i β p_{i mod n + 1}).
If there are several solutions, you can print any.
Example
Input
5
3
1 1 1
2 2 2
3 3 3
4
1 2 1 2
2 1 2 1
3 4 3 4
7
1 3 3 1 1 1 1
2 4 4 3 2 2 4
4 2 2 2 4 4 2
3
1 2 1
2 3 3
3 1 2
10
1 1 1 2 2 2 3 3 3 1
2 2 2 3 3 3 1 1 1 2
3 3 3 1 1 1 2 2 2 3
Output
1 2 3
1 2 1 2
1 3 4 3 2 4 2
1 3 2
1 2 3 1 2 3 1 2 3 2
Note
In the first test case p = [1, 2, 3].
It is a correct answer, because:
* p_1 = 1 = a_1, p_2 = 2 = b_2, p_3 = 3 = c_3
* p_1 β p_2 , p_2 β p_3 , p_3 β p_1
All possible correct answers to this test case are: [1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1, 2], [3, 2, 1].
In the second test case p = [1, 2, 1, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = a_3, p_4 = a_4. Also we can see, that no two adjacent elements of the sequence are equal.
In the third test case p = [1, 3, 4, 3, 2, 4, 2].
In this sequence p_1 = a_1, p_2 = a_2, p_3 = b_3, p_4 = b_4, p_5 = b_5, p_6 = c_6, p_7 = c_7. Also we can see, that no two adjacent elements of the sequence are equal.
Submitted Solution:
```
# import os
# import sys
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
for i1 in range(int(input())):
n=int(input())
a=[int(i) for i in input().split()]
b=[int(i) for i in input().split()]
c=[int(i) for i in input().split()]
ans=a
for i in range(1,n):
if(ans[i]==a[i-1]): ans[i]=b[i]
if(ans[-1]==a[0]): ans[-1]=b[-1]
print(*ans)
``` | instruction | 0 | 59,914 | 5 | 119,828 |
No | output | 1 | 59,914 | 5 | 119,829 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.