task stringclasses 5
values | input stringlengths 89 339 |
|---|---|
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
c1(onc(n1)-c1nccnc1)C(N[C@H](C)c1ccccc1)=O
### Response:
C[C@@H](NC(=O)c1nc(-c2cnccn2)no1)c1ccccc1 |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [3*]OCC
Fragment 2: [5*]N1CCCC1
### Response:
CCOc1cc(C=O)ccc1N1CCCC1 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
n1cc(cn1CC(=O)Nc1nn(c2c1cccc2)C)-c1cncc(OC)c1
### Response:
COc1cncc(-c2cnn(CC(=O)Nc3nn(C)c4ccccc34)c2)c1 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
c1ccc(cc1)/C=C/C=N/NC(COc1c(cc(C)cc1)C)=O
### Response:
Cc1ccc(OCC(=O)N/N=C/C=C/c2ccccc2)c(C)c1 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
Cc1cn2c3c(nc2n1-c1cc(C)c(C)cc1)n(c(n(CCC(OC)=O)c3=O)=O)C
### Response:
COC(=O)CCn1c(=O)c2c(nc3n(-c4ccc(C)c(C)c4)c(C)cn23)n(C)c1=O |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [1*]C(=O)[C@H]1CCCCO1
Fragment 2: [5*]N1CCO[C@H](/C(N)=N\O)C1
### Response:
N/C(=N/O)[C@@H]1CN(C(=O)[C@H]2CCCCO2)CCO1 |
functional_group | ### Instruction:
Does the molecule contain a ester group?
C[C@@H](OC(=O)c1occc1-c1ccccc1)C(=O)Nc1ccc(F)cc1F
### Response:
Yes |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
C[C@@H](CS(C)(=O)=O)N(C)Cc1csc(-c2ccc(C(N)=O)cc2)n1
### Response:
3 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
C([C@@H](n1c2c(cccc2)nn1)C[C@H](CCl)C)=C
### Response:
C=C[C@H](C[C@@H](C)CCl)n1nnc2ccccc21 |
ring_counting | ### Instruction:
Count the five-membered rings in the following molecule.
CC[C@H]1CN(C)c2ccccc2CN1C(=O)[C@@H](C)NC(=O)C1CCC1
### Response:
0 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
Cc1ccc(C(=O)N(C)C)cc1OC(=O)c1cc(F)ccc1NC(=O)[C@H]1C[C@H]1C
### Response:
1 |
ring_counting | ### Instruction:
Count the six-membered rings in the following molecule.
COc1ccccc1/C=c1\s/c(=C(/C#N)C(=O)N[C@@H]2CCCC[C@@H]2C)n(-c2ccc(F)cc2)c1=O
### Response:
3 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
COCCSc1ccc([C@@H](C)NC(=O)c2ccc[nH]2)cc1
### Response:
2 |
ring_counting | ### Instruction:
Count the six-membered rings in the following molecule.
COc1cccc(NC(=O)CN(C)c2nc3c(OC)cccc3s2)c1
### Response:
2 |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [1*]C(=O)C1=C(C)N(C)C(=O)N[C@H]1[13*]
Fragment 2: [16*]c1cccc([N+](=O)[O-])c1
### Response:
CCCOC(=O)C1=C(C)N(C)C(=O)N[C@H]1c1cccc([N+](=O)[O-])c1 |
functional_group | ### Instruction:
Does the molecule contain a amide group?
CC(C)CCNC(=O)c1ccc(/C=C2/Sc3ccccc3NC2=O)cc1
### Response:
Yes |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
C1C(C1)[C@@H](N(C(NCCNC(C)=O)=O)C)C
### Response:
CC(=O)NCCNC(=O)N(C)[C@@H](C)C1CC1 |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [11*]Sc1nnc([14*])n1N
Fragment 2: [1*]C(=O)[C@@H]([4*])C
### Response:
Cc1ccc(-c2nnc(S[C@@H](C)C(=O)Nc3nc(-c4ccccc4)cs3)n2N)cc1 |
ring_counting | ### Instruction:
Count the five-membered rings in the following molecule.
CCc1ccc(OCC(=O)Nc2ccc(OC)c(OC)c2)cc1
### Response:
0 |
functional_group | ### Instruction:
Does the molecule contain a aromatic_ring group?
N#Cc1cccc(CSc2nnc(C3CC3)n2Cc2ccccc2)c1
### Response:
Yes |
functional_group | ### Instruction:
Does the molecule contain a ether group?
CCC(CC)Oc1ccc(C)nc1CCl
### Response:
Yes |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
COc1ccc(/C=C/C(=O)N[C@@H](C)C(=O)N(C)C2CC2)cc1
### Response:
3 |
ring_counting | ### Instruction:
Count the five-membered rings in the following molecule.
O=C(Nc1ccc(Cl)c(Cl)c1)N1CC[NH+](C[C@@H]2CCCO2)CC1
### Response:
1 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
O=S(c1cccc(c1)CNC(=O)c1n(C)c(C)cc1)(N)=O
### Response:
Cc1ccc(C(=O)NCc2cccc(S(N)(=O)=O)c2)n1C |
functional_group | ### Instruction:
Does the molecule contain a aromatic_ring group?
COc1ccccc1/C=C/C[NH+]1CCN(CCO)CC1
### Response:
Yes |
functional_group | ### Instruction:
Does the molecule contain a hydroxyl group?
CCN(CC)c1ncc(CN(C)C[C@@H]2CCC[NH+](C)C2)s1
### Response:
No |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
c1c(C)c(NC(=O)c2cc(nc3c2cnn3CC)-c2sccc2)cc(c1)C
### Response:
CCn1ncc2c(C(=O)Nc3cc(C)ccc3C)cc(-c3cccs3)nc21 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
C[C@H](NCC(=O)N[C@H](C)c1ccc2c(c1)CCCC2)c1ccc2c(c1)OCCO2
### Response:
2 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
CCOc1ccc(CNC(=O)[C@H](CC)N2C(=O)CCn3nc(C)cc32)cc1
### Response:
4 |
ring_counting | ### Instruction:
Count the six-membered rings in the following molecule.
CC(C)CCNC(=O)[C@@H](NC(=O)[C@@H]1Cc2c([nH]c3ccccc23)[C@H]2c3ccccc3C(=O)N21)C(C)C
### Response:
3 |
ring_counting | ### Instruction:
Count the six-membered rings in the following molecule.
C#CCNC(=O)c1ccc(NC[C@@H](C)Oc2cccc(F)c2)nc1
### Response:
2 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
COCCOc1ccc(NC(=O)C2C[C@H](C)O[C@@H](C)C2)c(C)c1
### Response:
2 |
ring_counting | ### Instruction:
Count the five-membered rings in the following molecule.
COc1ccc(CCn2c(C)cc(-c3csc(CC(=O)N4CCOCC4)n3)c2C)cc1
### Response:
2 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
C[C@@H](Nc1ccc(OCC(F)(F)F)cc1)C(=O)N1CCNC1=O
### Response:
3 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
O=S1(=O)C[C@@H]2[NH+]=C([S-])N(c3cccc(Br)c3)[C@H]2C1
### Response:
0 |
ring_counting | ### Instruction:
Count the six-membered rings in the following molecule.
O=C(c1nc(C2CC2)n2ccccc12)N1CCOc2cccc(F)c21
### Response:
3 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
c1(F)ccc(F)cc1[C@]1(C)C(N(C[C@@H]2OCCCC2)C(=O)N1)=O
### Response:
C[C@]1(c2cc(F)ccc2F)NC(=O)N(C[C@H]2CCCCO2)C1=O |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
CC[C@H]1CCCN(C(=O)[C@H](C)NS(=O)(=O)c2ccc(OC)cc2)C1
### Response:
3 |
functional_group | ### Instruction:
Does the molecule contain a phenol group?
N#C[C@H]1COCCN1C(=O)[C@@H]1C[C@@H]1c1ccc(C(F)(F)F)cc1
### Response:
No |
functional_group | ### Instruction:
Does the molecule contain a ether group?
O=C1/C(=C\c2cc3ccccc3o2)SC(=S)N1c1ccc(F)cc1
### Response:
No |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [1*]C(=O)[C@H]1C=C(C)N=N1
Fragment 2: [6*]C(=O)c1cccc([16*])c1
### Response:
CC1=C[C@H](C(=O)N2CCC[C@H](C(=O)c3cccc(C(F)(F)F)c3)C2)N=N1 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
Cc1ccc(O[C@H](C)C(=O)Nc2ccccc2Br)c(C)c1
### Response:
3 |
functional_group | ### Instruction:
Does the molecule contain a nitrile group?
CCOc1ccccc1[C@H]1C(C#N)=C(SC)NC2=C1C(=O)CCC2
### Response:
Yes |
ring_counting | ### Instruction:
Count the five-membered rings in the following molecule.
Cn1nc(C(=O)N[C@H]2CC[C@H]([NH+](C)C)C2)ccc1=O
### Response:
1 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
CC(C)N1C[C@@H](CC1=O)C(=O)Oc1cccc(C(F)(F)F)c1
### Response:
CC(C)N1C[C@H](C(=O)Oc2cccc(C(F)(F)F)c2)CC1=O |
functional_group | ### Instruction:
Does the molecule contain a aromatic_ring group?
CC(=O)N1CCC(C(=O)Nc2sc(C)c(-c3ccccc3)c2C#N)CC1
### Response:
Yes |
ring_counting | ### Instruction:
Count the six-membered rings in the following molecule.
C[C@@H]1CCC[NH+](C(C)(C)CNC(=O)NC2CCCCC2)C1
### Response:
2 |
ring_counting | ### Instruction:
Count the six-membered rings in the following molecule.
CCC(CC)n1nccc1C(=O)N[C@@H](CO)c1ccco1
### Response:
0 |
ring_counting | ### Instruction:
Count the five-membered rings in the following molecule.
CCOc1cc(/C=C2\SC(=N)NC2=O)cc(Br)c1OC
### Response:
1 |
functional_group | ### Instruction:
Does the molecule contain a halide group?
O=C(NCc1ccccc1F)NC1CCN(C(=O)c2ccco2)CC1
### Response:
Yes |
ring_counting | ### Instruction:
Count the six-membered rings in the following molecule.
CC(C)C1(CNC(=O)N(C)C[C@H](C)O)CC1
### Response:
0 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
CCC1(CNC(=O)N2CCC(C(=O)Nc3ccc(C)cn3)CC2)CC1
### Response:
2 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
CC(=O)CCc1ccc(OC(=O)[C@@H]2C[C@@H]2C)cc1
### Response:
4 |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [1*]C(=O)CO[3*]
Fragment 2: [5*]N([5*])CC
### Response:
CCN(C(=O)COC(=O)c1cc(=O)c2ccccc2o1)[C@H]1CCS(=O)(=O)C1 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
COc1ccc(O[C@H](C)C(=O)Nc2sc3c(c2C#N)CCC3)cc1
### Response:
3 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
c1cccc(c1)[C@@H]1[C@@H](C[NH+]2[C@H]3CCCC[C@@H]3NC(=O)C2)C1
### Response:
O=C1C[NH+](C[C@H]2C[C@@H]2c2ccccc2)[C@H]2CCCC[C@@H]2N1 |
ring_counting | ### Instruction:
Count the five-membered rings in the following molecule.
C[C@@H](SCCOc1cccc(Cl)c1)C(N)=O
### Response:
0 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
CCC(CC)(CC)NC(=O)N[C@@H](C)CSC
### Response:
5 |
functional_group | ### Instruction:
Does the molecule contain a phenol group?
CC(=O)N[C@H]1CCCN(C(=O)c2ccccc2OCc2ccccc2Cl)C1
### Response:
No |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
N([C@H](c1cc(c(cc1)Cl)F)CO)C(=O)Nc1cnccc1
### Response:
O=C(Nc1cccnc1)N[C@@H](CO)c1ccc(Cl)c(F)c1 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
c1c(N2CCOCC2)ccc(c1)C[NH+]1CCS[C@H](C)[C@H]1C
### Response:
C[C@@H]1[C@@H](C)SCC[NH+]1Cc1ccc(N2CCOCC2)cc1 |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [1*]C(=O)c1ccc(C)c(C)c1
Fragment 2: [5*]N1CCCc2cc(C)ccc21
### Response:
Cc1ccc2c(c1)CCCN2C(=O)c1ccc(C)c(C)c1 |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [5*]NS(=O)(=O)c1ccc(C)cc1F
Fragment 2: [5*]N1CCOCC1
### Response:
Cc1cccc([C@@H](CNS(=O)(=O)c2ccc(C)cc2F)N2CCOCC2)c1 |
functional_group | ### Instruction:
Does the molecule contain a sulfonyl group?
CS(=O)(=O)/N=C(\[O-])CCCSc1ccccc1
### Response:
Yes |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [5*]N[C@H]([8*])C
Fragment 2: [1*]C(=O)[C@H]([4*])C
### Response:
Cc1nnc(S[C@H](C)C(=O)N[C@@H](C)c2ccc3c(c2)CCCC3)s1 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
CNC(=O)c1ccc(NC(=O)C[C@H](C)CC(C)C)cc1
### Response:
6 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
c1c(cccc1C(Nc1ccccc1)=O)OC(c1ncn(-c2ccccc2)n1)=O
### Response:
O=C(Nc1ccccc1)c1cccc(OC(=O)c2ncn(-c3ccccc3)n2)c1 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
c1c(c(cc2c1nc(s2)NC(=O)CC(C)C)C)Cl
### Response:
Cc1cc2sc(NC(=O)CC(C)C)nc2cc1Cl |
functional_group | ### Instruction:
Does the molecule contain a ester group?
CCOc1c(Cl)cc(/C=C/C(=O)c2ccc3c(c2)NC(=O)CO3)cc1OC
### Response:
No |
ring_counting | ### Instruction:
Count the five-membered rings in the following molecule.
O=C([O-])C[C@@H]1COc2ccccc2N1Cc1ccccc1
### Response:
0 |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [5*]N[C@@H]([8*])c1ccccc1
Fragment 2: [16*]c1ccccc1
### Response:
O=C(CSc1nncs1)N[C@H](c1ccccc1)c1ccccn1 |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [7*]C1C(=O)NN([10*])C1=O
Fragment 2: [7*]Cc1ccc(F)cc1
### Response:
Cc1ccc(N2NC(=O)/C(=C/c3ccc(F)cc3)C2=O)cc1C |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
C([NH2+]Cc1nc(C)sc1)c1ccc(c(c1)Cl)OCC=C
### Response:
C=CCOc1ccc(C[NH2+]Cc2csc(C)n2)cc1Cl |
ring_counting | ### Instruction:
Count the six-membered rings in the following molecule.
COc1cccc(C[C@@H]2C[C@@H](C)CC[C@H]2O)n1
### Response:
2 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
c1(ccc(cc1)[N+](=O)[O-])-c1csc(NC(c2c(cccc2)S(=O)(=O)C)=O)n1
### Response:
CS(=O)(=O)c1ccccc1C(=O)Nc1nc(-c2ccc([N+](=O)[O-])cc2)cs1 |
ring_counting | ### Instruction:
Count the six-membered rings in the following molecule.
OCCOc1cccc2cc[nH]c12
### Response:
1 |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [9*]n1ccc2nc3ncnn3c([14*])c2c1=O
Fragment 2: [16*]c1ccccc1
### Response:
O=c1c2c(-c3ccccc3)n3ncnc3nc2ccn1-c1ccccn1 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
CCC1(CC)[C@@H](Oc2cccnc2C)C[C@@H]1[O-]
### Response:
2 |
ring_counting | ### Instruction:
Count the six-membered rings in the following molecule.
Cc1cc(C)c(NC(=O)CNC(=O)c2ccc(Cl)c(Cl)c2)c(C)c1
### Response:
2 |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [1*]C(=O)c1ccc2[nH]c3c(c2c1)CCCC3
Fragment 2: [5*]NCc1ccc(F)cc1
### Response:
O=C(NCc1ccc(F)cc1)c1ccc2[nH]c3c(c2c1)CCCC3 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
Cc1cc(C)c(C(=O)COc2cccc([N+](=O)[O-])c2C)cc1C
### Response:
2 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
CCC[C@@H]1NC(=O)N(CC(=O)Nc2ccccc2Oc2ccccc2)C1=O
### Response:
3 |
functional_group | ### Instruction:
Does the molecule contain a thiol group?
O=C(NCC[S@](=O)Cc1ccccc1)NCc1ccc(F)cc1
### Response:
No |
ring_counting | ### Instruction:
Count the six-membered rings in the following molecule.
Cc1cccc([C@@H]2C[C@H](C(=O)NCc3ccccc3F)CN(C(=O)c3ccccc3)C2)c1
### Response:
4 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
O=C(Nc1cc(ccc1)SC)C(=O)NCc1nncn1C1CC1
### Response:
CSc1cccc(NC(=O)C(=O)NCc2nncn2C2CC2)c1 |
chain_length | ### Instruction:
What is the length of the longest acyclic carbon chain in the molecule?
NC(=O)C1CC[NH+](CC(=O)Nc2ncc(Cc3ccccc3Cl)s2)CC1
### Response:
2 |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [4*]CC([6*])=O
Fragment 2: [16*]c1ccc(OC)cc1OC
### Response:
COc1ccc(C(=O)COc2ncnc3c(Cl)cc(Cl)cc23)c(OC)c1 |
functional_group | ### Instruction:
Does the molecule contain a hydroxyl group?
Cc1ccc(N2CC[NH2+][C@H](C)C2)c(C)n1
### Response:
No |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
O(C)c1ccc2c([C@H]([C@@H](CC2)[NH+](CC)CC)NCC)c1
### Response:
CCN[C@@H]1c2cc(OC)ccc2CC[C@H]1[NH+](CC)CC |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [5*]N1CCCC1
Fragment 2: [13*][C@H]1NC(=O)c2ccccc2N1
### Response:
O=C1N[C@H](c2ccc(N3CCCC3)c([N+](=O)[O-])c2)Nc2ccccc21 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
C(/C(=O)Nc1ccc(cc1)C)=C1\SC(=O)N(CC(Nc2cc(ccc2)C)=O)C1=O
### Response:
Cc1ccc(NC(=O)/C=C2/SC(=O)N(CC(=O)Nc3cccc(C)c3)C2=O)cc1 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
O1CCOc2ccc(S(/N=C(\[O-])c3cc(ccc3C)F)(=O)=O)cc21
### Response:
Cc1ccc(F)cc1/C([O-])=N/S(=O)(=O)c1ccc2c(c1)OCCO2 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
[O-][N+](=O)c1cnc(O[C@H]2C[C@@H](CCC2)[NH3+])cc1
### Response:
[NH3+][C@@H]1CCC[C@@H](Oc2ccc([N+](=O)[O-])cn2)C1 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
C(CSc1nnc(Cc2cccs2)n1C1CC1)(=O)Nc1ccc2CCCc2c1
### Response:
O=C(CSc1nnc(Cc2cccs2)n1C1CC1)Nc1ccc2c(c1)CCC2 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
N(CCN(CC#C)[C@@H]1CCS(=O)(=O)C1)(C)c1ccccc1
### Response:
C#CCN(CCN(C)c1ccccc1)[C@@H]1CCS(=O)(=O)C1 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
c1cccc2c1c(c[nH]2)C[C@@H](C(=O)OC)NS(c1c2nonc2ccc1)(=O)=O
### Response:
COC(=O)[C@H](Cc1c[nH]c2ccccc12)NS(=O)(=O)c1cccc2nonc12 |
canonicalization | ### Instruction:
Canonicalize the following SMILES string.
S(=O)(NCCc1n(cnn1)CC)(c1c(C)cc(C)cc1)=O
### Response:
CCn1cnnc1CCNS(=O)(=O)c1ccc(C)cc1C |
fragment_assembly | ### Instruction:
Assemble these two molecular fragments into a single molecule.
Fragment 1: [1*]C(=O)c1csc(C#CCN)c1
Fragment 2: [5*]NCc1cccc(C#N)c1
### Response:
N#Cc1cccc(CNC(=O)c2csc(C#CCN)c2)c1 |
functional_group | ### Instruction:
Does the molecule contain a ketone group?
O=C(c1ccc(F)cc1)N1CCN(c2ccc([N+](=O)[O-])c(NC[C@@H]3CCCO3)c2)CC1
### Response:
No |
functional_group | ### Instruction:
Does the molecule contain a aromatic_ring group?
COc1ccc(CC(=O)N2CC[C@H]3[C@H](CCCN3C(=O)C3=CCCCC3)C2)cc1
### Response:
Yes |
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