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Let's update our payload. We have two ROP gadgets:
1. 0x0015b456 : pop ebx ; pop esi ; pop edi ; pop ebp ; ret
2. 0x0015c456 : ret
the ROP chain if second gadget is hit ----+
|
the program return address --+ |
V V
+--------------------------------------------------------------------------+
| 0x41414141 | .......... | 0xf015c456 | 0xDEAD | 0xDEAD | 0xDEAD | 0xDEAD |
|--------------------------------------------------------------------------|
| 0xBEEF | 0xBEEF | 0xBEEF | 0xBEEF | .......... | .......... | .......... |
+--------------------------------------------------------------------------+
^
|
+ The ROP chain if first gadget is triggered
Now, let's see what happens when the second gadget is triggered. Since the
second gadget is just a ret, it immediately transfers control to the first
0xDEAD - the start of the next ROP in our chain. If this happens, we know
that libc is mapped at 0xf0000000.
stack pointer after the second gadget-----+
V
+--------------------------------------------------------------------------+
| 0x41414141 | .......... | 0xf015c456 | 0xDEAD | 0xDEAD | 0xDEAD | 0xDEAD |
|--------------------------------------------------------------------------|
| 0xBEEF | 0xBEEF | 0xBEEF | 0xBEEF | .......... | .......... | .......... |
+--------------------------------------------------------------------------+
Now, if instead the first ROP gadget is executed then the stack will look
as follows:
+--------------------------------------------------------------------------+
| 0x41414141 | .......... | 0xf015c456 | 0xDEAD | 0xDEAD | 0xDEAD | 0xDEAD |
|--------------------------------------------------------------------------|
| 0xBEEF | 0xBEEF | 0xBEEF | 0xBEEF | .......... | .......... | .......... |
+--------------------------------------------------------------------------+
^
|
+ stack pointer after the first gadget
This time, because the gadget does four pops before returning, the return
lands somewhere deeper in the payload - in our case, on the first 0xBEEF.
Since this only happens if libc was mapped at 0xf0001000, we have just
confirmed the base address. In either case, we can continue the ROP chain
with the corresponding libc base address.
Quantum ROP offers a simple yet powerful way to boost the success rate of
ret-to-libc attacks under ASLR. By carefully selecting two ROP gadgets
spaced X-pages apart in libc, we effectively create a dual-path exploit.
One gadget triggers if our initial guess is correct, and the other triggers
if it is off by their difference. This method multiplies our chances for
success with a constant payload - and thanks to the subtle difference in
stack adjustments between gadgets, we can detect which one executed and
deduce the actual libc base address in each corresponding exploit.
Let's call each of these gadgets a qgadget, as they serve the purpose of
potentially existing at the same address, but only one may exist at this
address when you actually run the program. We shall also name the actual
guessed address in the return address as qaddress, for obvious reasons.
The method does not stop here: this technique isn't limited to just two
qgadgets. By adding more qgadgets that share the same offset within their
page, we can stack multiple fallback paths into the same payload, increasing
our odds of success per attempt. It is likely to be able to produce a
payload abusing not only two, but eight gadgets, reducing the 8 bits of ASLR
to effectively 5 bits.
In our example, we carefully chose the qgadgets that fit perfectly. Using
one_gadget [3], we were able to produce a working four-gadget-long exploit
that fit exactly with our chosen qgadgets. For cases where you require
longer ROP chains, you can resolve this by using an add/sub esp
gadget, allowing you to create more space for each ROP chain and continue
the chain elsewhere.
4 Qgadget collisions - going further and beyond
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Until now, I only showed how to make it work when qgadgets differ in the
amount by which they move the stack pointer. Now what if I found three
gadgets, but two of them move the stack pointer by the exact same amount?
Am I forced to give up on one of them?
Well, using the same technique as before, we can distinguish between the
two gadgets. Let us assume that the two gadgets are simple "ret" gadgets.
This means that the next pointer after the return address is the next
gadget executed. Consider this real example from my libc:
0x00194063 : pop ebp ; ret
0x00195063 : ret
0x0019d063 : ret
The first gadget's stack shift is unique, but the next two are the same.
We can observe that the difference between the two identical qgadgets is 8
pages. Now, if we find two gadgets of the same difference that move the
stack pointer by a different amount, we can split those two cases:
0x00125417 : pop ebp ; ret