answer string | choices dict | id string | kind string | lang string | question string | steps list | subject string | text string | topic string |
|---|---|---|---|---|---|---|---|---|---|
Net force: 6 N. | null | phy_0001 | worked_example | en | A mass of 3 kg accelerates at 2 m/s². Compute the net force. | [
"F = m×a.",
"F = 3 kg × 2 m/s².",
"= 6 N."
] | physics | Answer: Net force: 6 N.
Steps:
1. F = m×a.
2. F = 3 kg × 2 m/s².
3. = 6 N. | mechanics |
Voltage: 12 V. | null | phy_0002 | worked_example | en | A current of 1 A flows through 12 Ω. Compute the voltage. | [
"V = I×R.",
"V = 1 A × 12 Ω.",
"= 12 V."
] | physics | Answer: Voltage: 12 V.
Steps:
1. V = I×R.
2. V = 1 A × 12 Ω.
3. = 12 V. | electromagnetism |
Temperature: 288 K. | null | phy_0003 | worked_example | en | Temperature is 15 °C. Convert it to kelvin. | [
"Add 273.",
"15 + 273.",
"= 288 K."
] | physics | Answer: Temperature: 288 K.
Steps:
1. Add 273.
2. 15 + 273.
3. = 288 K. | thermodynamics |
Light bounces off surfaces with angle in equal to angle out, forming mirror images. | null | phy_0004 | concept | en | What is reflection? | [
"Light bounces off surfaces with angle in equal to angle out, forming mirror images.",
"So the answer stands: Light bounces off surfaces with angle in equal to angle out, forming mirror images."
] | physics | Answer: Light bounces off surfaces with angle in equal to angle out, forming mirror images.
Steps:
1. Light bounces off surfaces with angle in equal to angle out, forming mirror images.
2. So the answer stands: Light bounces off surfaces with angle in equal to angle out, forming mirror images. | optics |
Speed: 600 m/s. | null | phy_0005 | worked_example | en | A string wave has f = 200 Hz and λ = 3 m. Compute its speed. | [
"v = f×λ.",
"v = 200 Hz × 3 m.",
"= 600 m/s."
] | physics | Answer: Speed: 600 m/s.
Steps:
1. v = f×λ.
2. v = 200 Hz × 3 m.
3. = 600 m/s. | waves |
Survivors: 200. | null | phy_0006 | worked_example | en | A sample of 800 atoms undergoes 2 half-lives. Compute the survivors. | [
"Halve: 800 → 400.",
"Halve: 400 → 200.",
"= 200."
] | physics | Answer: Survivors: 200.
Steps:
1. Halve: 800 → 400.
2. Halve: 400 → 200.
3. = 200. | modern |
Net force is 6 N. | {
"A": "6 N",
"B": "3 N",
"C": "9 N",
"D": "12 N"
} | phy_0007 | multiple_choice | en | A mass of 2 kg accelerates at 3 m/s². What is the net force? | [
"F = 2 kg × 3 m/s².",
"F = 6 N.",
"Select option A."
] | physics | Answer: 6 N
Steps:
1. F = 2 kg × 3 m/s².
2. F = 6 N.
3. Select option A.
Answer: (A) | mechanics |
Voltage is 10 V. | {
"A": "10 V",
"B": "5 V",
"C": "15 V",
"D": "20 V"
} | phy_0008 | multiple_choice | en | A current of 2 A flows through 5 Ω. What is the voltage? | [
"V = 2 A × 5 Ω.",
"V = 10 V.",
"Select option A."
] | physics | Answer: 10 V
Steps:
1. V = 2 A × 5 Ω.
2. V = 10 V.
3. Select option A.
Answer: (A) | electromagnetism |
Heat: 8372 J. | null | phy_0009 | worked_example | en | How much heat warms 2 kg of water by 1 K? (c = 4186 J/(kg·K)) | [
"Q = 2 kg × 4186 J/(kg·K) × 1 K.",
"= 8372 J."
] | physics | Answer: Heat: 8372 J.
Steps:
1. Q = 2 kg × 4186 J/(kg·K) × 1 K.
2. = 8372 J. | thermodynamics |
Magnification is 2×. | {
"A": "2×",
"B": "1×",
"C": "3×",
"D": "4×"
} | phy_0010 | multiple_choice | en | An image forms 20 cm from a lens, object at 10 cm. What is the magnification? | [
"M = 20 cm / 10 cm.",
"M = 2×.",
"Select option A."
] | physics | Answer: 2×
Steps:
1. M = 20 cm / 10 cm.
2. M = 2×.
3. Select option A.
Answer: (A) | optics |
Rychlost: 600 m/s. | null | phy_0011 | worked_example | cs | Vlna na struně má f = 200 Hz a λ = 3 m. Spočítej její rychlost. | [
"v = f×λ.",
"v = 200 Hz × 3 m.",
"= 600 m/s."
] | physics | Answer: Rychlost: 600 m/s.
Steps:
1. v = f×λ.
2. v = 200 Hz × 3 m.
3. = 600 m/s. | waves |
100 atoms remain. | {
"A": "100",
"B": "50",
"C": "150",
"D": "200"
} | phy_0012 | multiple_choice | en | A sample of 400 atoms undergoes 2 half-lives. How many remain? | [
"Halve twice: 400 → 200 → 100.",
"Left: 100.",
"Select option A."
] | physics | Answer: 100
Steps:
1. Halve twice: 400 → 200 → 100.
2. Left: 100.
3. Select option A.
Answer: (A) | modern |
Objects keep velocity unless a net force acts, so motion needs no push to continue. | null | phy_0013 | concept | en | What is Newton's first law? | [
"Objects keep velocity unless a net force acts, so motion needs no push to continue.",
"So the answer stands: Objects keep velocity unless a net force acts, so motion needs no push to continue."
] | physics | Answer: Objects keep velocity unless a net force acts, so motion needs no push to continue.
Steps:
1. Objects keep velocity unless a net force acts, so motion needs no push to continue.
2. So the answer stands: Objects keep velocity unless a net force acts, so motion needs no push to continue. | mechanics |
Charge is the source of electric force, positive and negative attracting opposites always. | null | phy_0014 | concept | en | What is electric charge? | [
"Charge is the source of electric force, positive and negative attracting opposites always.",
"So the answer stands: Charge is the source of electric force, positive and negative attracting opposites always."
] | physics | Answer: Charge is the source of electric force, positive and negative attracting opposites always.
Steps:
1. Charge is the source of electric force, positive and negative attracting opposites always.
2. So the answer stands: Charge is the source of electric force, positive and negative attracting opposites always. | electromagnetism |
Power: 50 W. | null | phy_0015 | worked_example | en | An engine does 500 J of work in 10 s. Compute its power. | [
"P = W/t.",
"P = 500 J / 10 s.",
"= 50 W."
] | physics | Answer: Power: 50 W.
Steps:
1. P = W/t.
2. P = 500 J / 10 s.
3. = 50 W. | thermodynamics |
Magnification: 3×. | null | phy_0016 | worked_example | en | An image forms 30 cm from a lens, object at 10 cm. Compute the magnification. | [
"M = di/do.",
"M = 30 cm / 10 cm.",
"= 3×."
] | physics | Answer: Magnification: 3×.
Steps:
1. M = di/do.
2. M = 30 cm / 10 cm.
3. = 3×. | optics |
Waves carry energy through oscillation without net matter transport. | null | phy_0017 | concept | en | What is a wave? | [
"Waves carry energy through oscillation without net matter transport.",
"So the answer stands: Waves carry energy through oscillation without net matter transport."
] | physics | Answer: Waves carry energy through oscillation without net matter transport.
Steps:
1. Waves carry energy through oscillation without net matter transport.
2. So the answer stands: Waves carry energy through oscillation without net matter transport. | waves |
Přeživší: 200. | null | phy_0018 | worked_example | cs | Vzorek 800 atomů projde 2 poločasy. Spočítej přeživší. | [
"Půl: 800 → 400.",
"Půl: 400 → 200.",
"= 200."
] | physics | Answer: Přeživší: 200.
Steps:
1. Půl: 800 → 400.
2. Půl: 400 → 200.
3. = 200. | modern |
Výsledná síla je 6 N. | {
"A": "6 N",
"B": "3 N",
"C": "9 N",
"D": "12 N"
} | phy_0019 | multiple_choice | cs | Těleso 2 kg zrychluje 3 m/s². Jaká je výsledná síla? | [
"F = 2 kg × 3 m/s².",
"F = 6 N.",
"Vyber možnost A."
] | physics | Answer: 6 N
Steps:
1. F = 2 kg × 3 m/s².
2. F = 6 N.
3. Vyber možnost A.
Answer: (A) | mechanics |
Energy: 500 J. | null | phy_0020 | worked_example | en | A 100 W heater runs for 5 s. Compute the energy used. | [
"E = P×t.",
"E = 100 W × 5 s.",
"= 500 J."
] | physics | Answer: Energy: 500 J.
Steps:
1. E = P×t.
2. E = 100 W × 5 s.
3. = 500 J. | electromagnetism |
Temperature measures average particle kinetic energy, felt as hot or cold. | null | phy_0021 | concept | en | What is temperature? | [
"Temperature measures average particle kinetic energy, felt as hot or cold.",
"So the answer stands: Temperature measures average particle kinetic energy, felt as hot or cold."
] | physics | Answer: Temperature measures average particle kinetic energy, felt as hot or cold.
Steps:
1. Temperature measures average particle kinetic energy, felt as hot or cold.
2. So the answer stands: Temperature measures average particle kinetic energy, felt as hot or cold. | thermodynamics |
Time is 1 s. | {
"A": "2 s",
"B": "1 s",
"C": "3 s",
"D": "0.5 s"
} | phy_0022 | multiple_choice | en | Light travels 3×10⁸ m. How many seconds does it take? (c = 3×10⁸ m/s) | [
"t = 3×10⁸ m / 3×10⁸ m/s.",
"t = 1 s.",
"Select option B."
] | physics | Answer: 1 s
Steps:
1. t = 3×10⁸ m / 3×10⁸ m/s.
2. t = 1 s.
3. Select option B.
Answer: (B) | optics |
Vzdálenost: 680 m. | null | phy_0023 | worked_example | cs | Hrom je slyšet 2 s po blesku. Jak daleko je bouře? (v = 340 m/s) | [
"d = v×t.",
"d = 340 m/s × 2 s.",
"= 680 m."
] | physics | Answer: Vzdálenost: 680 m.
Steps:
1. d = v×t.
2. d = 340 m/s × 2 s.
3. = 680 m. | waves |
Count: 3. | {
"A": "2",
"B": "3",
"C": "4",
"D": "5"
} | phy_0024 | multiple_choice | en | An atom is excited to level n = 3. How many spectral lines can it emit? | [
"Pairs: 3×2/2.",
"Lines: 3.",
"Select option B."
] | physics | Answer: 3
Steps:
1. Pairs: 3×2/2.
2. Lines: 3.
3. Select option B.
Answer: (B) | modern |
Výsledná síla: 6 N. | null | phy_0025 | worked_example | cs | Těleso 3 kg zrychluje 2 m/s². Spočítej výslednou sílu. | [
"F = m×a.",
"F = 3 kg × 2 m/s².",
"= 6 N."
] | physics | Answer: Výsledná síla: 6 N.
Steps:
1. F = m×a.
2. F = 3 kg × 2 m/s².
3. = 6 N. | mechanics |
Force scales with charges over distance squared, governing all electric pushes exactly. | null | phy_0026 | concept | en | Why Coulomb's law? | [
"Force scales with charges over distance squared, governing all electric pushes exactly.",
"So the answer stands: Force scales with charges over distance squared, governing all electric pushes exactly."
] | physics | Answer: Force scales with charges over distance squared, governing all electric pushes exactly.
Steps:
1. Force scales with charges over distance squared, governing all electric pushes exactly.
2. So the answer stands: Force scales with charges over distance squared, governing all electric pushes exactly. | electromagnetism |
Teplota: 288 K. | null | phy_0027 | worked_example | cs | Teplota je 15 °C. Převeď ji na kelviny. | [
"Přičti 273.",
"15 + 273.",
"= 288 K."
] | physics | Answer: Teplota: 288 K.
Steps:
1. Přičti 273.
2. 15 + 273.
3. = 288 K. | thermodynamics |
Speed change at boundaries bends rays by Snell's law, shifting straws in water. | null | phy_0028 | concept | en | Why refraction? | [
"Speed change at boundaries bends rays by Snell's law, shifting straws in water.",
"So the answer stands: Speed change at boundaries bends rays by Snell's law, shifting straws in water."
] | physics | Answer: Speed change at boundaries bends rays by Snell's law, shifting straws in water.
Steps:
1. Speed change at boundaries bends rays by Snell's law, shifting straws in water.
2. So the answer stands: Speed change at boundaries bends rays by Snell's law, shifting straws in water. | optics |
Speed is 200 m/s. | {
"A": "200 m/s",
"B": "150 m/s",
"C": "250 m/s",
"D": "300 m/s"
} | phy_0029 | multiple_choice | en | A string wave has f = 100 Hz and λ = 2 m. What is its speed? | [
"v = 100 Hz × 2 m.",
"v = 200 m/s.",
"Select option A."
] | physics | Answer: 200 m/s
Steps:
1. v = 100 Hz × 2 m.
2. v = 200 m/s.
3. Select option A.
Answer: (A) | waves |
Motion warps time and space together, keeping light speed fixed for all. | null | phy_0030 | concept | en | What is relativity? | [
"Motion warps time and space together, keeping light speed fixed for all.",
"So the answer stands: Motion warps time and space together, keeping light speed fixed for all."
] | physics | Answer: Motion warps time and space together, keeping light speed fixed for all.
Steps:
1. Motion warps time and space together, keeping light speed fixed for all.
2. So the answer stands: Motion warps time and space together, keeping light speed fixed for all. | modern |
Net force equals mass times acceleration, linking pushes to motion change exactly. | null | phy_0031 | concept | en | Why F equals ma? | [
"Net force equals mass times acceleration, linking pushes to motion change exactly.",
"So the answer stands: Net force equals mass times acceleration, linking pushes to motion change exactly."
] | physics | Answer: Net force equals mass times acceleration, linking pushes to motion change exactly.
Steps:
1. Net force equals mass times acceleration, linking pushes to motion change exactly.
2. So the answer stands: Net force equals mass times acceleration, linking pushes to motion change exactly. | mechanics |
Náboj je zdrojem elektrické síly, opačné se přitahují. | null | phy_0032 | concept | cs | Co je elektrický náboj? | [
"Náboj je zdrojem elektrické síly, opačné se přitahují.",
"Odpověď tedy platí: Náboj je zdrojem elektrické síly, opačné se přitahují."
] | physics | Answer: Náboj je zdrojem elektrické síly, opačné se přitahují.
Steps:
1. Náboj je zdrojem elektrické síly, opačné se přitahují.
2. Odpověď tedy platí: Náboj je zdrojem elektrické síly, opačné se přitahují. | electromagnetism |
Temperature: 289 K. | null | phy_0033 | worked_example | en | Temperature is 16 °C. Convert it to kelvin. | [
"Add 273.",
"16 + 273.",
"= 289 K."
] | physics | Answer: Temperature: 289 K.
Steps:
1. Add 273.
2. 16 + 273.
3. = 289 K. | thermodynamics |
Apparent depth is 20 cm. | {
"A": "15 cm",
"B": "25 cm",
"C": "20 cm",
"D": "30 cm"
} | phy_0034 | multiple_choice | en | An object sits 30 cm deep in glass (n = 1.5). What is the apparent depth? | [
"d' = 30 cm / 1.5.",
"d' = 20 cm.",
"Select option C."
] | physics | Answer: 20 cm
Steps:
1. d' = 30 cm / 1.5.
2. d' = 20 cm.
3. Select option C.
Answer: (C) | optics |
Distance: 680 m. | null | phy_0035 | worked_example | en | Thunder is heard 2 s after lightning. How far away is the storm? (v = 340 m/s) | [
"d = v×t.",
"d = 340 m/s × 2 s.",
"= 680 m."
] | physics | Answer: Distance: 680 m.
Steps:
1. d = v×t.
2. d = 340 m/s × 2 s.
3. = 680 m. | waves |
Moving clocks tick slower as seen from rest, confirmed by muons daily. | null | phy_0036 | concept | en | Why time dilation? | [
"Moving clocks tick slower as seen from rest, confirmed by muons daily.",
"So the answer stands: Moving clocks tick slower as seen from rest, confirmed by muons daily."
] | physics | Answer: Moving clocks tick slower as seen from rest, confirmed by muons daily.
Steps:
1. Moving clocks tick slower as seen from rest, confirmed by muons daily.
2. So the answer stands: Moving clocks tick slower as seen from rest, confirmed by muons daily. | modern |
Work: 40 J. | null | phy_0037 | worked_example | en | A force of 10 N pushes 4 m. Compute the work done. | [
"W = F×d.",
"W = 10 N × 4 m.",
"= 40 J."
] | physics | Answer: Work: 40 J.
Steps:
1. W = F×d.
2. W = 10 N × 4 m.
3. = 40 J. | mechanics |
Power: 12 W. | null | phy_0038 | worked_example | en | A current of 2 A flows through 3 Ω. Compute the dissipated power. | [
"P = I²×R.",
"P = (2 A)² × 3 Ω.",
"= 12 W."
] | physics | Answer: Power: 12 W.
Steps:
1. P = I²×R.
2. P = (2 A)² × 3 Ω.
3. = 12 W. | electromagnetism |
Temperature is 293 K. | {
"A": "293 K",
"B": "292 K",
"C": "294 K",
"D": "295 K"
} | phy_0039 | multiple_choice | en | Room temperature is 20 °C. What is it in kelvin? | [
"20 °C + 273.",
"= 293 K.",
"Select option A."
] | physics | Answer: 293 K
Steps:
1. 20 °C + 273.
2. = 293 K.
3. Select option A.
Answer: (A) | thermodynamics |
Time: 1.3 s. | null | phy_0040 | worked_example | en | Light travels 4×10⁸ m. Compute the travel time. (c = 3×10⁸ m/s) | [
"t = d/c.",
"t = 4×10⁸ / 3×10⁸ s.",
"= 1.3 s."
] | physics | Answer: Time: 1.3 s.
Steps:
1. t = d/c.
2. t = 4×10⁸ / 3×10⁸ s.
3. = 1.3 s. | optics |
3. harmonická: 300 Hz. | null | phy_0041 | worked_example | cs | Základ struny je 100 Hz. Spočítej její 3. harmonickou. | [
"f3 = 3×f1.",
"f3 = 3 × 100 Hz.",
"= 300 Hz."
] | physics | Answer: 3. harmonická: 300 Hz.
Steps:
1. f3 = 3×f1.
2. f3 = 3 × 100 Hz.
3. = 300 Hz. | waves |
Fast objects shorten along motion as measured from rest frames. | null | phy_0042 | concept | en | What is length contraction? | [
"Fast objects shorten along motion as measured from rest frames.",
"So the answer stands: Fast objects shorten along motion as measured from rest frames."
] | physics | Answer: Fast objects shorten along motion as measured from rest frames.
Steps:
1. Fast objects shorten along motion as measured from rest frames.
2. So the answer stands: Fast objects shorten along motion as measured from rest frames. | modern |
Speed is 10 m/s. | {
"A": "9 m/s",
"B": "10 m/s",
"C": "11 m/s",
"D": "12 m/s"
} | phy_0043 | multiple_choice | en | A car travels 100 m in 10 s. What is its speed? | [
"v = 100 m / 10 s.",
"v = 10 m/s.",
"Select option B."
] | physics | Answer: 10 m/s
Steps:
1. v = 100 m / 10 s.
2. v = 10 m/s.
3. Select option B.
Answer: (B) | mechanics |
Voltage: 24 V. | null | phy_0044 | worked_example | en | A current of 2 A flows through 12 Ω. Compute the voltage. | [
"V = I×R.",
"V = 2 A × 12 Ω.",
"= 24 V."
] | physics | Answer: Voltage: 24 V.
Steps:
1. V = I×R.
2. V = 2 A × 12 Ω.
3. = 24 V. | electromagnetism |
Heat needed is 8372 J. | {
"A": "4186 J",
"B": "8372 J",
"C": "12558 J",
"D": "16744 J"
} | phy_0045 | multiple_choice | en | How much heat warms 1 kg of water by 2 K? (c = 4186 J/(kg·K)) | [
"Q = 1 kg × 4186 J/(kg·K) × 2 K.",
"Q = 8372 J.",
"Select option B."
] | physics | Answer: 8372 J
Steps:
1. Q = 1 kg × 4186 J/(kg·K) × 2 K.
2. Q = 8372 J.
3. Select option B.
Answer: (B) | thermodynamics |
Zvětšení: 3×. | null | phy_0046 | worked_example | cs | Obraz vzniká 30 cm od čočky, předmět v 10 cm. Spočítej zvětšení. | [
"M = di/do.",
"M = 30 cm / 10 cm.",
"= 3×."
] | physics | Answer: Zvětšení: 3×.
Steps:
1. M = di/do.
2. M = 30 cm / 10 cm.
3. = 3×. | optics |
Vlny nesou energii kmitáním bez přenosu látky. | null | phy_0047 | concept | cs | Co je vlna? | [
"Vlny nesou energii kmitáním bez přenosu látky.",
"Odpověď tedy platí: Vlny nesou energii kmitáním bez přenosu látky."
] | physics | Answer: Vlny nesou energii kmitáním bez přenosu látky.
Steps:
1. Vlny nesou energii kmitáním bez přenosu látky.
2. Odpověď tedy platí: Vlny nesou energii kmitáním bez přenosu látky. | waves |
Čar: 6. | null | phy_0048 | worked_example | cs | Atom je vybuzen do hladiny n = 4. Spočítej čáry, jež může vyzářit. | [
"Dvojice: 4×3/2.",
"= 12/2.",
"= 6."
] | physics | Answer: Čar: 6.
Steps:
1. Dvojice: 4×3/2.
2. = 12/2.
3. = 6. | modern |
Tělesa drží rychlost bez výsledné síly. | null | phy_0049 | concept | cs | Co je první Newtonův zákon? | [
"Tělesa drží rychlost bez výsledné síly.",
"Odpověď tedy platí: Tělesa drží rychlost bez výsledné síly."
] | physics | Answer: Tělesa drží rychlost bez výsledné síly.
Steps:
1. Tělesa drží rychlost bez výsledné síly.
2. Odpověď tedy platí: Tělesa drží rychlost bez výsledné síly. | mechanics |
Fields map force per charge through space, picturing influence before charges arrive. | null | phy_0050 | concept | en | What is an electric field? | [
"Fields map force per charge through space, picturing influence before charges arrive.",
"So the answer stands: Fields map force per charge through space, picturing influence before charges arrive."
] | physics | Answer: Fields map force per charge through space, picturing influence before charges arrive.
Steps:
1. Fields map force per charge through space, picturing influence before charges arrive.
2. So the answer stands: Fields map force per charge through space, picturing influence before charges arrive. | electromagnetism |
Heat: 16744 J. | null | phy_0051 | worked_example | en | How much heat warms 2 kg of water by 2 K? (c = 4186 J/(kg·K)) | [
"Q = 2 kg × 4186 J/(kg·K) × 2 K.",
"= 16744 J."
] | physics | Answer: Heat: 16744 J.
Steps:
1. Q = 2 kg × 4186 J/(kg·K) × 2 K.
2. = 16744 J. | thermodynamics |
n₁sinθ₁ equals n₂sinθ₂, predicting bend amounts exactly at interfaces. | null | phy_0052 | concept | en | What is Snell's law? | [
"n₁sinθ₁ equals n₂sinθ₂, predicting bend amounts exactly at interfaces.",
"So the answer stands: n₁sinθ₁ equals n₂sinθ₂, predicting bend amounts exactly at interfaces."
] | physics | Answer: n₁sinθ₁ equals n₂sinθ₂, predicting bend amounts exactly at interfaces.
Steps:
1. n₁sinθ₁ equals n₂sinθ₂, predicting bend amounts exactly at interfaces.
2. So the answer stands: n₁sinθ₁ equals n₂sinθ₂, predicting bend amounts exactly at interfaces. | optics |
3rd harmonic: 300 Hz. | null | phy_0053 | worked_example | en | A string's fundamental is 100 Hz. Compute its 3rd harmonic. | [
"f3 = 3×f1.",
"f3 = 3 × 100 Hz.",
"= 300 Hz."
] | physics | Answer: 3rd harmonic: 300 Hz.
Steps:
1. f3 = 3×f1.
2. f3 = 3 × 100 Hz.
3. = 300 Hz. | waves |
Mass number is 4. | {
"A": "3",
"B": "5",
"C": "4",
"D": "6"
} | phy_0054 | multiple_choice | en | A nucleus has 2 protons and 2 neutrons. What is its mass number? | [
"A = 2 + 2.",
"A = 4.",
"Select option C."
] | physics | Answer: 4
Steps:
1. A = 2 + 2.
2. A = 4.
3. Select option C.
Answer: (C) | modern |
Kinetic energy is 16 J. | {
"A": "12 J",
"B": "20 J",
"C": "16 J",
"D": "24 J"
} | phy_0055 | multiple_choice | en | A 2 kg ball moves at 4 m/s. What is its kinetic energy? | [
"KE = ½×2 kg×(4 m/s)².",
"KE = 16 J.",
"Select option C."
] | physics | Answer: 16 J
Steps:
1. KE = ½×2 kg×(4 m/s)².
2. KE = 16 J.
3. Select option C.
Answer: (C) | mechanics |
Energy: 600 J. | null | phy_0056 | worked_example | en | A 100 W heater runs for 6 s. Compute the energy used. | [
"E = P×t.",
"E = 100 W × 6 s.",
"= 600 J."
] | physics | Answer: Energy: 600 J.
Steps:
1. E = P×t.
2. E = 100 W × 6 s.
3. = 600 J. | electromagnetism |
Power: 60 W. | null | phy_0057 | worked_example | en | An engine does 600 J of work in 10 s. Compute its power. | [
"P = W/t.",
"P = 600 J / 10 s.",
"= 60 W."
] | physics | Answer: Power: 60 W.
Steps:
1. P = W/t.
2. P = 600 J / 10 s.
3. = 60 W. | thermodynamics |
Světlo se odráží pod stejným úhlem. | null | phy_0058 | concept | cs | Co je odraz? | [
"Světlo se odráží pod stejným úhlem.",
"Odpověď tedy platí: Světlo se odráží pod stejným úhlem."
] | physics | Answer: Světlo se odráží pod stejným úhlem.
Steps:
1. Světlo se odráží pod stejným úhlem.
2. Odpověď tedy platí: Světlo se odráží pod stejným úhlem. | optics |
It is the length of one full cycle, linking speed and frequency. | null | phy_0059 | concept | en | Why wavelength? | [
"It is the length of one full cycle, linking speed and frequency.",
"So the answer stands: It is the length of one full cycle, linking speed and frequency."
] | physics | Answer: It is the length of one full cycle, linking speed and frequency.
Steps:
1. It is the length of one full cycle, linking speed and frequency.
2. So the answer stands: It is the length of one full cycle, linking speed and frequency. | waves |
Mass is frozen energy convertible in nuclei and stars. | null | phy_0060 | concept | en | Why E equals mc²? | [
"Mass is frozen energy convertible in nuclei and stars.",
"So the answer stands: Mass is frozen energy convertible in nuclei and stars."
] | physics | Answer: Mass is frozen energy convertible in nuclei and stars.
Steps:
1. Mass is frozen energy convertible in nuclei and stars.
2. So the answer stands: Mass is frozen energy convertible in nuclei and stars. | modern |
The answer is Zero net force. | {
"A": "Big friction",
"B": "Strong wind",
"C": "Loud noise",
"D": "Zero net force"
} | phy_0061 | multiple_choice | en | Choose: what keeps velocity? | [
"First law rules.",
"So: Zero net force.",
"Select option D."
] | physics | Answer: Zero net force
Steps:
1. First law rules.
2. So: Zero net force.
3. Select option D.
Answer: (D) | mechanics |
Power: 27 W. | null | phy_0062 | worked_example | en | A current of 3 A flows through 3 Ω. Compute the dissipated power. | [
"P = I²×R.",
"P = (3 A)² × 3 Ω.",
"= 27 W."
] | physics | Answer: Power: 27 W.
Steps:
1. P = I²×R.
2. P = (3 A)² × 3 Ω.
3. = 27 W. | electromagnetism |
Teplota je 293 K. | {
"A": "293 K",
"B": "292 K",
"C": "294 K",
"D": "295 K"
} | phy_0063 | multiple_choice | cs | Pokojová teplota je 20 °C. Kolik je to kelvinů? | [
"20 °C + 273.",
"= 293 K.",
"Vyber možnost A."
] | physics | Answer: 293 K
Steps:
1. 20 °C + 273.
2. = 293 K.
3. Vyber možnost A.
Answer: (A) | thermodynamics |
Čas: 1,3 s. | null | phy_0064 | worked_example | cs | Světlo letí 4×10⁸ m. Spočítej dobu letu. (c = 3×10⁸ m/s) | [
"t = d/c.",
"t = 4×10⁸ / 3×10⁸ s.",
"= 1,3 s."
] | physics | Answer: Čas: 1,3 s.
Steps:
1. t = d/c.
2. t = 4×10⁸ / 3×10⁸ s.
3. = 1,3 s. | optics |
Period is 0.5 s. | {
"A": "0.33 s",
"B": "0.5 s",
"C": "0.25 s",
"D": "1 s"
} | phy_0065 | multiple_choice | en | A wave has frequency 2 Hz. What is its period? | [
"T = 1 / 2 Hz.",
"T = 0.5 s.",
"Select option B."
] | physics | Answer: 0.5 s
Steps:
1. T = 1 / 2 Hz.
2. T = 0.5 s.
3. Select option B.
Answer: (B) | waves |
Lines: 6. | null | phy_0066 | worked_example | en | An atom is excited to level n = 4. Count the spectral lines it can emit. | [
"Pairs: 4×3/2.",
"= 12/2.",
"= 6."
] | physics | Answer: Lines: 6.
Steps:
1. Pairs: 4×3/2.
2. = 12/2.
3. = 6. | modern |
The answer is Centripetal force. | {
"A": "Centripetal force",
"B": "Friction",
"C": "Weight",
"D": "Buoyancy"
} | phy_0067 | multiple_choice | en | Choose: what bends circles? | [
"Inward net pulls.",
"So: Centripetal force.",
"Select option A."
] | physics | Answer: Centripetal force
Steps:
1. Inward net pulls.
2. So: Centripetal force.
3. Select option A.
Answer: (A) | mechanics |
Voltage: 36 V. | null | phy_0068 | worked_example | en | A current of 3 A flows through 12 Ω. Compute the voltage. | [
"V = I×R.",
"V = 3 A × 12 Ω.",
"= 36 V."
] | physics | Answer: Voltage: 36 V.
Steps:
1. V = I×R.
2. V = 3 A × 12 Ω.
3. = 36 V. | electromagnetism |
Kelvin starts at absolute zero where motion stops, suiting gas laws exactly. | null | phy_0069 | concept | en | Why Kelvin scale? | [
"Kelvin starts at absolute zero where motion stops, suiting gas laws exactly.",
"So the answer stands: Kelvin starts at absolute zero where motion stops, suiting gas laws exactly."
] | physics | Answer: Kelvin starts at absolute zero where motion stops, suiting gas laws exactly.
Steps:
1. Kelvin starts at absolute zero where motion stops, suiting gas laws exactly.
2. So the answer stands: Kelvin starts at absolute zero where motion stops, suiting gas laws exactly. | thermodynamics |
Apparent depth: 30 cm. | null | phy_0070 | worked_example | en | An object sits 45 cm deep in glass (n = 1.5). Compute the apparent depth. | [
"d' = d/n.",
"d' = 45 cm / 1.5.",
"= 30 cm."
] | physics | Answer: Apparent depth: 30 cm.
Steps:
1. d' = d/n.
2. d' = 45 cm / 1.5.
3. = 30 cm. | optics |
3rd harmonic is 330 Hz. | {
"A": "300 Hz",
"B": "360 Hz",
"C": "330 Hz",
"D": "390 Hz"
} | phy_0071 | multiple_choice | en | A string's fundamental is 110 Hz. What is its 3rd harmonic? | [
"f3 = 3 × 110 Hz.",
"f3 = 330 Hz.",
"Select option C."
] | physics | Answer: 330 Hz
Steps:
1. f3 = 3 × 110 Hz.
2. f3 = 330 Hz.
3. Select option C.
Answer: (C) | waves |
Mass number: 7. | null | phy_0072 | worked_example | en | A nucleus has 3 protons and 4 neutrons. Compute its mass number. | [
"A = Z+N.",
"A = 3 + 4.",
"= 7."
] | physics | Answer: Mass number: 7.
Steps:
1. A = Z+N.
2. A = 3 + 4.
3. = 7. | modern |
Momentum: 15 kg·m/s. | null | phy_0073 | worked_example | en | A mass of 5 kg moves at 3 m/s. Compute its momentum. | [
"p = m×v.",
"p = 5 kg × 3 m/s.",
"= 15 kg·m/s."
] | physics | Answer: Momentum: 15 kg·m/s.
Steps:
1. p = m×v.
2. p = 5 kg × 3 m/s.
3. = 15 kg·m/s. | mechanics |
Napětí: 12 V. | null | phy_0074 | worked_example | cs | Proud 1 A teče přes 12 Ω. Spočítej napětí. | [
"U = I×R.",
"U = 1 A × 12 Ω.",
"= 12 V."
] | physics | Answer: Napětí: 12 V.
Steps:
1. U = I×R.
2. U = 1 A × 12 Ω.
3. = 12 V. | electromagnetism |
Heat is energy flowing from hot to cold spontaneously, measured in joules. | null | phy_0075 | concept | en | What is heat? | [
"Heat is energy flowing from hot to cold spontaneously, measured in joules.",
"So the answer stands: Heat is energy flowing from hot to cold spontaneously, measured in joules."
] | physics | Answer: Heat is energy flowing from hot to cold spontaneously, measured in joules.
Steps:
1. Heat is energy flowing from hot to cold spontaneously, measured in joules.
2. So the answer stands: Heat is energy flowing from hot to cold spontaneously, measured in joules. | thermodynamics |
The answer is Reflection. | {
"A": "Refraction",
"B": "Diffusion",
"C": "Absorption",
"D": "Reflection"
} | phy_0076 | multiple_choice | en | Choose: what bounces equal? | [
"Angles matched.",
"So: Reflection.",
"Select option D."
] | physics | Answer: Reflection
Steps:
1. Angles matched.
2. So: Reflection.
3. Select option D.
Answer: (D) | optics |
Speed: 750 m/s. | null | phy_0077 | worked_example | en | A string wave has f = 250 Hz and λ = 3 m. Compute its speed. | [
"v = f×λ.",
"v = 250 Hz × 3 m.",
"= 750 m/s."
] | physics | Answer: Speed: 750 m/s.
Steps:
1. v = f×λ.
2. v = 250 Hz × 3 m.
3. = 750 m/s. | waves |
Survivors: 400. | null | phy_0078 | worked_example | en | A sample of 1600 atoms undergoes 2 half-lives. Compute the survivors. | [
"Halve: 1600 → 800.",
"Halve: 800 → 400.",
"= 400."
] | physics | Answer: Survivors: 400.
Steps:
1. Halve: 1600 → 800.
2. Halve: 800 → 400.
3. = 400. | modern |
Výsledná síla rovná se hmotnosti krát zrychlení. | null | phy_0079 | concept | cs | Proč F rovno ma? | [
"Výsledná síla rovná se hmotnosti krát zrychlení.",
"Odpověď tedy platí: Výsledná síla rovná se hmotnosti krát zrychlení."
] | physics | Answer: Výsledná síla rovná se hmotnosti krát zrychlení.
Steps:
1. Výsledná síla rovná se hmotnosti krát zrychlení.
2. Odpověď tedy platí: Výsledná síla rovná se hmotnosti krát zrychlení. | mechanics |
Lines show direction and crowding strength, making invisible forces visible neatly. | null | phy_0080 | concept | en | Why field lines? | [
"Lines show direction and crowding strength, making invisible forces visible neatly.",
"So the answer stands: Lines show direction and crowding strength, making invisible forces visible neatly."
] | physics | Answer: Lines show direction and crowding strength, making invisible forces visible neatly.
Steps:
1. Lines show direction and crowding strength, making invisible forces visible neatly.
2. So the answer stands: Lines show direction and crowding strength, making invisible forces visible neatly. | electromagnetism |
Efficiency is 20%. | {
"A": "10%",
"B": "30%",
"C": "20%",
"D": "40%"
} | phy_0081 | multiple_choice | en | An engine turns 200 J of 1000 J heat into work. What is its efficiency? | [
"200 J / 1000 J.",
"= 20%.",
"Select option C."
] | physics | Answer: 20%
Steps:
1. 200 J / 1000 J.
2. = 20%.
3. Select option C.
Answer: (C) | thermodynamics |
Magnification: 4×. | null | phy_0082 | worked_example | en | An image forms 40 cm from a lens, object at 10 cm. Compute the magnification. | [
"M = di/do.",
"M = 40 cm / 10 cm.",
"= 4×."
] | physics | Answer: Magnification: 4×.
Steps:
1. M = di/do.
2. M = 40 cm / 10 cm.
3. = 4×. | optics |
Distance: 1020 m. | null | phy_0083 | worked_example | en | Thunder is heard 3 s after lightning. How far away is the storm? (v = 340 m/s) | [
"d = v×t.",
"d = 340 m/s × 3 s.",
"= 1020 m."
] | physics | Answer: Distance: 1020 m.
Steps:
1. d = v×t.
2. d = 340 m/s × 3 s.
3. = 1020 m. | waves |
Lines: 10. | null | phy_0084 | worked_example | en | An atom is excited to level n = 5. Count the spectral lines it can emit. | [
"Pairs: 5×4/2.",
"= 20/2.",
"= 10."
] | physics | Answer: Lines: 10.
Steps:
1. Pairs: 5×4/2.
2. = 20/2.
3. = 10. | modern |
Net force is 9 N. | {
"A": "6 N",
"B": "9 N",
"C": "12 N",
"D": "15 N"
} | phy_0085 | multiple_choice | en | A mass of 3 kg accelerates at 3 m/s². What is the net force? | [
"F = 3 kg × 3 m/s².",
"F = 9 N.",
"Select option B."
] | physics | Answer: 9 N
Steps:
1. F = 3 kg × 3 m/s².
2. F = 9 N.
3. Select option B.
Answer: (B) | mechanics |
Voltage is energy per charge in volts, pushing current through circuits. | null | phy_0086 | concept | en | What is voltage? | [
"Voltage is energy per charge in volts, pushing current through circuits.",
"So the answer stands: Voltage is energy per charge in volts, pushing current through circuits."
] | physics | Answer: Voltage is energy per charge in volts, pushing current through circuits.
Steps:
1. Voltage is energy per charge in volts, pushing current through circuits.
2. So the answer stands: Voltage is energy per charge in volts, pushing current through circuits. | electromagnetism |
It is energy per mass per degree, high for water that buffers climate. | null | phy_0087 | concept | en | Why specific heat? | [
"It is energy per mass per degree, high for water that buffers climate.",
"So the answer stands: It is energy per mass per degree, high for water that buffers climate."
] | physics | Answer: It is energy per mass per degree, high for water that buffers climate.
Steps:
1. It is energy per mass per degree, high for water that buffers climate.
2. So the answer stands: It is energy per mass per degree, high for water that buffers climate. | thermodynamics |
The answer is Prism. | {
"A": "Prism",
"B": "Mirror",
"C": "Lens",
"D": "Screen"
} | phy_0088 | multiple_choice | en | Choose: what splits white? | [
"Colours fanned.",
"So: Prism.",
"Select option A."
] | physics | Answer: Prism
Steps:
1. Colours fanned.
2. So: Prism.
3. Select option A.
Answer: (A) | optics |
Rychlost je 200 m/s. | {
"A": "200 m/s",
"B": "150 m/s",
"C": "250 m/s",
"D": "300 m/s"
} | phy_0089 | multiple_choice | cs | Vlna na struně má f = 100 Hz a λ = 2 m. Jaká je její rychlost? | [
"v = 100 Hz × 2 m.",
"v = 200 m/s.",
"Vyber možnost A."
] | physics | Answer: 200 m/s
Steps:
1. v = 100 Hz × 2 m.
2. v = 200 m/s.
3. Vyber možnost A.
Answer: (A) | waves |
The answer is Spacetime. | {
"A": "Spacecraft",
"B": "Timetable",
"C": "Workbench",
"D": "Spacetime"
} | phy_0090 | multiple_choice | en | Choose: what warps together? | [
"c fixed for all.",
"So: Spacetime.",
"Select option D."
] | physics | Answer: Spacetime
Steps:
1. c fixed for all.
2. So: Spacetime.
3. Select option D.
Answer: (D) | modern |
Net force: 8 N. | null | phy_0091 | worked_example | en | A mass of 4 kg accelerates at 2 m/s². Compute the net force. | [
"F = m×a.",
"F = 4 kg × 2 m/s².",
"= 8 N."
] | physics | Answer: Net force: 8 N.
Steps:
1. F = m×a.
2. F = 4 kg × 2 m/s².
3. = 8 N. | mechanics |
V equals IR for resistors, linking push, flow, and opposition simply. | null | phy_0092 | concept | en | Why Ohm's law? | [
"V equals IR for resistors, linking push, flow, and opposition simply.",
"So the answer stands: V equals IR for resistors, linking push, flow, and opposition simply."
] | physics | Answer: V equals IR for resistors, linking push, flow, and opposition simply.
Steps:
1. V equals IR for resistors, linking push, flow, and opposition simply.
2. So the answer stands: V equals IR for resistors, linking push, flow, and opposition simply. | electromagnetism |
Heated particles spread apart, lengthening bridges and loosening lids. | null | phy_0093 | concept | en | What is thermal expansion? | [
"Heated particles spread apart, lengthening bridges and loosening lids.",
"So the answer stands: Heated particles spread apart, lengthening bridges and loosening lids."
] | physics | Answer: Heated particles spread apart, lengthening bridges and loosening lids.
Steps:
1. Heated particles spread apart, lengthening bridges and loosening lids.
2. So the answer stands: Heated particles spread apart, lengthening bridges and loosening lids. | thermodynamics |
Time: 2.3 s. | null | phy_0094 | worked_example | en | Light travels 7×10⁸ m. Compute the travel time. (c = 3×10⁸ m/s) | [
"t = d/c.",
"t = 7×10⁸ / 3×10⁸ s.",
"= 2.3 s."
] | physics | Answer: Time: 2.3 s.
Steps:
1. t = d/c.
2. t = 7×10⁸ / 3×10⁸ s.
3. = 2.3 s. | optics |
Je délka jednoho cyklu. | null | phy_0095 | concept | cs | Proč vlnová délka? | [
"Je délka jednoho cyklu.",
"Odpověď tedy platí: Je délka jednoho cyklu."
] | physics | Answer: Je délka jednoho cyklu.
Steps:
1. Je délka jednoho cyklu.
2. Odpověď tedy platí: Je délka jednoho cyklu. | waves |
Time joins space as one four-dimensional fabric curved by mass. | null | phy_0096 | concept | en | What is spacetime? | [
"Time joins space as one four-dimensional fabric curved by mass.",
"So the answer stands: Time joins space as one four-dimensional fabric curved by mass."
] | physics | Answer: Time joins space as one four-dimensional fabric curved by mass.
Steps:
1. Time joins space as one four-dimensional fabric curved by mass.
2. So the answer stands: Time joins space as one four-dimensional fabric curved by mass. | modern |
Inertia is mass resisting velocity change, so heavier objects need bigger forces to speed. | null | phy_0097 | concept | en | What is inertia? | [
"Inertia is mass resisting velocity change, so heavier objects need bigger forces to speed.",
"So the answer stands: Inertia is mass resisting velocity change, so heavier objects need bigger forces to speed."
] | physics | Answer: Inertia is mass resisting velocity change, so heavier objects need bigger forces to speed.
Steps:
1. Inertia is mass resisting velocity change, so heavier objects need bigger forces to speed.
2. So the answer stands: Inertia is mass resisting velocity change, so heavier objects need bigger forces to speed. | mechanics |
Energy: 700 J. | null | phy_0098 | worked_example | en | A 100 W heater runs for 7 s. Compute the energy used. | [
"E = P×t.",
"E = 100 W × 7 s.",
"= 700 J."
] | physics | Answer: Energy: 700 J.
Steps:
1. E = P×t.
2. E = 100 W × 7 s.
3. = 700 J. | electromagnetism |
The answer is Temperature. | {
"A": "Pressure",
"B": "Volume",
"C": "Mass",
"D": "Temperature"
} | phy_0099 | multiple_choice | en | Choose: what measures jiggle? | [
"Mean energy read.",
"So: Temperature.",
"Select option D."
] | physics | Answer: Temperature
Steps:
1. Mean energy read.
2. So: Temperature.
3. Select option D.
Answer: (D) | thermodynamics |
Beyond the critical angle no transmission fits, so all light reflects inside gems. | null | phy_0100 | concept | en | Why total internal reflection? | [
"Beyond the critical angle no transmission fits, so all light reflects inside gems.",
"So the answer stands: Beyond the critical angle no transmission fits, so all light reflects inside gems."
] | physics | Answer: Beyond the critical angle no transmission fits, so all light reflects inside gems.
Steps:
1. Beyond the critical angle no transmission fits, so all light reflects inside gems.
2. So the answer stands: Beyond the critical angle no transmission fits, so all light reflects inside gems. | optics |
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