id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__kCdTO6pIGRDS9WhW | What is the dividend from Tony's stock, if he invested Rs. 3200 at 85 to obtain an income of Rs. 250. Pick one.
A) 4
B) 7.6
C) 6.6
D) 7.6
E) 9.6 | <gadget id="calculator">250 * 85</gadget>
<output>21_250</output>
<gadget id="calculator">21_250 / 3_200</gadget>
<output>425/64 = around 6.640625</output>
<result>C</result> | C | 6.6 | What is the dividend from Tony's stock, if he invested Rs. 3200 at 85 to obtain an income of Rs. 250. | {
"A": "4",
"B": "7.6",
"C": "6.6",
"D": "7.6",
"E": "9.6"
} | divide(multiply(250, 85), 3200) | multiply(n1,n2)|divide(#0,n0) | by investing rs . 3200 , income = rs . 250 by investing rs . 85 , income = 250 ã — 85 / 3200 = 6.6 ie , dividend = 6.6 % answer is c . | gain |
math_qa__R6xRBmfbgbhDtxZf | A test has 160 questions. Each question has 5 options, but only 1 option is correct. If test-takers mark the correct option, they are awarded 1 point. However, if an answer is incorrectly marked, the test-taker loses 0.25 points. No points are awarded or deducted if a question is not attempted. A certain group of test-takers attempted different numbers of questions, but each test-taker still received the same net score of 40. What is the maximum possible number of such test-takers? Answers: A) 23 B) 25 C) 27 D) 29 E) 31 | <gadget id="calculator">160 - 40</gadget>
<output>120</output>
<gadget id="calculator">120 / 5</gadget>
<output>24</output>
<gadget id="calculator">24 + 1</gadget>
<output>25</output>
<gadget id="calculator">25 + 1</gadget>
<output>26</output>
<result>B</result> | B | 25 | A test has 160 questions. Each question has 5 options, but only 1 option is correct. If test-takers mark the correct option, they are awarded 1 point. However, if an answer is incorrectly marked, the test-taker loses 0.25 points. No points are awarded or deducted if a question is not attempted. A certain group of test-takers attempted different numbers of questions, but each test-taker still received the same net score of 40. What is the maximum possible number of such test-takers? | {
"A": "23",
"B": "25",
"C": "27",
"D": "29",
"E": "31"
} | add(add(divide(subtract(160, 40), 5), const_1), const_1) | subtract(n0,n5)|divide(#0,n1)|add(#1,const_1)|add(#2,const_1) | a correct answers get you 1 point , an incorrect answer gets you minus 1 / 4 point and a skipped question gets you 0 points . since there are 200 total questions , there are a variety of ways to get a total of 40 points . let c be the number of correct answers and let i be the number of incorrect answers . to get 40 points , a test taker must have at least 40 correct answers . then c = > 40 . for every correct question above 40 , the test taker has 4 incorrect answers . then , the i = 4 * ( c - 40 ) . also , i + c < = 160 . thus 5 c < = 320 and so c < = 64 . then 40 < = c < = 64 and c can have 25 possible values . the answer is b . | general |
math_qa__BZ7aU9rOqM3CbJia | A glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. If 65 cubic centimeters of the solution were poured into an empty container, how many grams of glucose would be in the container? Choose the correct choice from the following answers:
A) 7.50 B) 8.75 C) 7.75 D) 9.50 E) 9.75 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">65 * (3/20)</gadget>
<output>39/4 = around 9.75</output>
<result>E</result> | E | 9.75 | A glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution. If 65 cubic centimeters of the solution were poured into an empty container, how many grams of glucose would be in the container? | {
"A": "7.50",
"B": "8.75",
"C": "7.75",
"D": "9.50",
"E": "9.75"
} | multiply(65, divide(15, 100)) | divide(n0,n1)|multiply(n2,#0) | we are given that a glucose solution contains 15 grams of glucose per 100 cubic centimeters of solution . since we are dealing with a solution , we know that the grams of glucose is proportional to the number of cubic centimeters of solution . thus , to determine how many grams of glucose would be in the container when we have 45 cubic centimeters of solution , we can set up a proportion . we can say : “ 15 grams of glucose is to 100 cubic centimeters of solution as x grams of glucose is to 65 cubic centimeters of solution . ” let ’ s now set up the proportion and solve for x . 15 / 100 = x / 65 when we cross multiply we obtain : ( 15 ) ( 65 ) = 100 x 975 = 100 x 9.75 = x there are 9.75 grams of glucose in the solution in the container . the answer is e . | physics |
math_qa__BhMUr74GKfgeOMVD | The price of a coat in a certain store is $500. If the price of the coat is to be reduced by $150, by what percent is the price to be reduced?
Choose the correct choice from the following choices
A) 10 % B) 15 % C) 20 % D) 25 % E) 30 % | <gadget id="calculator">150 / 500</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 100</gadget>
<output>30</output>
<result>E</result> | E | 30 | The price of a coat in a certain store is $500. If the price of the coat is to be reduced by $150, by what percent is the price to be reduced? | {
"A": "10 %",
"B": "15 %",
"C": "20 %",
"D": "25 %",
"E": "30 %"
} | multiply(divide(150, 500), const_100) | divide(n1,n0)|multiply(#0,const_100)| | "price of a coat in a certain store = $ 500 the price of the coat is to be reduced by $ 150 % change = ( final value - initial value ) * 100 / initial value % reduction = ( reduction in price ) * 100 / initial value i . e . % reduction = ( 150 ) * 100 / 500 = 30 % answer : option e" | gain |
math_qa__susuFfjN976clSyg | If a man lost 4% by selling oranges at the rate of 60 a rupee at how many a rupee must he sell them to gain 44%? Choose the correct choice.
A) 11 B) 28 C) 39 D) 40 E) 43 | <gadget id="calculator">100 - 4</gadget>
<output>96</output>
<gadget id="calculator">96 * 60</gadget>
<output>5_760</output>
<gadget id="calculator">100 + 44</gadget>
<output>144</output>
<gadget id="calculator">5_760 / 144</gadget>
<output>40</output>
<result>D</result> | D | 40 | If a man lost 4% by selling oranges at the rate of 60 a rupee at how many a rupee must he sell them to gain 44%? | {
"A": "11",
"B": "28",
"C": "39",
"D": "40",
"E": "43"
} | divide(multiply(subtract(const_100, 4), 60), add(const_100, 44)) | add(n2,const_100)|subtract(const_100,n0)|multiply(n1,#1)|divide(#2,#0)| | "96 % - - - - 60 144 % - - - - ? 96 / 144 * 60 = 40 answer : d" | gain |
math_qa__JiMdx4s2KOkvENV7 | A man can row 9 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man?
Choose the correct choice:
A) 6.24 km B) 6 km C) 8.84 km D) 5.66 km E) 10 km | <gadget id="calculator">9 + 1.2</gadget>
<output>10.2</output>
<gadget id="calculator">9 - 1.2</gadget>
<output>7.8</output>
<gadget id="calculator">10.2 * 7.8</gadget>
<output>79.56</output>
<gadget id="calculator">10.2 + 7.8</gadget>
<output>18</output>
<gadget id="calculator">79.56 / 18</gadget>
<output>4.42</output>
<gadget id="calculator">4.42 * 2</gadget>
<output>8.84</output>
<result>C</result> | C | 8.84 | A man can row 9 kmph in still water. When the river is running at 1.2 kmph, it takes him 1 hour to row to a place and back. What is the total distance traveled by the man? | {
"A": "6.24 km",
"B": "6 km",
"C": "8.84 km",
"D": "5.66 km",
"E": "10 km"
} | multiply(divide(multiply(add(9, 1.2), subtract(9, 1.2)), add(add(9, 1.2), subtract(9, 1.2))), const_2) | add(n0,n1)|subtract(n0,n1)|add(#0,#1)|multiply(#0,#1)|divide(#3,#2)|multiply(#4,const_2)| | "m = 9 s = 1.2 ds = 10.2 us = 7.8 x / 10.2 + x / 7.8 = 1 x = 4.42 d = 4.42 * 2 = 8.84 answer : c" | physics |
math_qa__c2jsd3WC5UL25zMj | Two trains 300 m and 450 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
Choose the correct choice from the following options: A) 10.6 B) 27 C) 10.4 D) 10.8 E) 10.1 | <gadget id="calculator">300 + 450</gadget>
<output>750</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">750 / (250/9)</gadget>
<output>27</output>
<result>B</result> | B | 27 | Two trains 300 m and 450 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? | {
"A": "10.6",
"B": "27",
"C": "10.4",
"D": "10.8",
"E": "10.1"
} | divide(add(300, 450), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = 60 + 40 = 100 km / hr . = 100 * 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = 300 + 450 = 750 m . required time = 700 * 9 / 250 = 27 sec . answer : b" | physics |
math_qa__TAtY5nSIwkxh11W3 | A shopkeeper buys mangoes at the rate of 6 a rupee and sells them at 3 a rupee. Find his net profit or loss percent? Choose the correct choice from the following choices: A) 33 4 / 3 % B) 33 1 / 7 % C) 50 % D) 32 1 / 3 % E) 60 % | <gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">300 / 6</gadget>
<output>50</output>
<result>C</result> | C | 50 | A shopkeeper buys mangoes at the rate of 6 a rupee and sells them at 3 a rupee. Find his net profit or loss percent? | {
"A": "33 4 / 3 %",
"B": "33 1 / 7 %",
"C": "50 %",
"D": "32 1 / 3 %",
"E": "60 %"
} | divide(multiply(3, const_100), 6) | multiply(n1,const_100)|divide(#0,n0) | the total number of mangoes bought by the shopkeeper be 18 . if he buys 6 a rupee , his cp = 3 he selling at 3 a rupee , his sp = 6 profit = sp - cp = 6 - 3 = 3 profit percent = 3 / 6 * 100 = 50 % answer : c | gain |
math_qa__TXRG1EMheyf1K206 | If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 15 men in 3 days? Choose the correct choice from the following answers.
A) 65 mtr . B) 52 mtr C) 70 mtr . D) 78 mtr . E) 42 mtr . | <gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">20 * 6</gadget>
<output>120</output>
<gadget id="calculator">45 / 120</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">112 * (3/8)</gadget>
<output>42</output>
<result>E</result> | E | 42 | If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 15 men in 3 days? | {
"A": "65 mtr .",
"B": "52 mtr",
"C": "70 mtr .",
"D": "78 mtr .",
"E": "42 mtr ."
} | multiply(112, divide(multiply(15, 3), multiply(20, 6))) | multiply(n3,n4)|multiply(n0,n2)|divide(#0,#1)|multiply(n1,#2)| | "20 men is 6 days can build 112 metres 15 men in 3 days can build = 112 * ( 15 / 20 ) x ( 3 / 6 ) = 42 meters answer : e ." | physics |
math_qa__eivDjGSI8qt0qQEt | B completes a work in 3 days. A alone can do it in 10 days. If both work together, the work can be completed in how many days? Choose the most appropriate option
A) 2.31 days B) 4.31 days C) 5.31 days D) 6.31 days E) 7.31 days | <gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">3 + 10</gadget>
<output>13</output>
<gadget id="calculator">30 / 13</gadget>
<output>30/13 = around 2.307692</output>
<result>A</result> | A | 2.31 | B completes a work in 3 days. A alone can do it in 10 days. If both work together, the work can be completed in how many days? | {
"A": "2.31 days",
"B": "4.31 days",
"C": "5.31 days",
"D": "6.31 days",
"E": "7.31 days"
} | divide(multiply(10, 3), add(3, 10)) | add(n0,n1)|multiply(n0,n1)|divide(#1,#0) | 1 / 3 + 1 / 10 = 13 / 30 30 / 13 = 2.31 days answer : a | physics |
math_qa__RB95ve21dpeP5SmP | Nick took a bus from home to market, that travels at 80 kmph. While walking back at 8 kmph,
halfway through, he suddenly realized he was getting late and he cycled back the remaining distance in 60 kmph. Find the average speed.
Choose the correct choice from the following answers
A) 49.5 kmph B) 49.0 kmph C) 48.5 kmph D) 48.0 kmph E) none of these | <gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/60) / 2</gadget>
<output>1/120 = around 0.008333</output>
<gadget id="calculator">1 / 80</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">(1/120) + (1/80)</gadget>
<output>1/48 = around 0.020833</output>
<gadget id="calculator">1 / (1/48)</gadget>
<output>48</output>
<result>D</result> | D | 48 | Nick took a bus from home to market, that travels at 80 kmph. While walking back at 8 kmph,
halfway through, he suddenly realized he was getting late and he cycled back the remaining distance in 60 kmph. Find the average speed. | {
"A": "49.5 kmph",
"B": "49.0 kmph",
"C": "48.5 kmph",
"D": "48.0 kmph",
"E": "none of these"
} | inverse(add(divide(inverse(60), const_2), inverse(80))) | inverse(n2)|inverse(n0)|divide(#0,const_2)|add(#2,#1)|inverse(#3) | let the distance be 2 x ( one way ) time taken by bus = 2 x / 80 , by walking = x / 8 , by cycling = x / 60 hours : . average speed = total distance / total time = 8 x / x / 40 + x / 8 + x / 60 = 8 * 60 / 1.5 + 7.5 + 1 = 12.0 answer : d | physics |
math_qa__IdwoYIunRy0hF9ou | A boat having a length 6 m and breadth 3 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is: Choose the correct choice from the following answers: A) 100 kg B) 120 kg C) 89 kg D) 180 kg E) 110 kg | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">18 * (1/100)</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(9/50) * 1_000</gadget>
<output>180</output>
<result>D</result> | D | 180 | A boat having a length 6 m and breadth 3 m is floating on a lake. The boat sinks by 1 cm when a man gets on it. The mass of the man is: | {
"A": "100 kg",
"B": "120 kg",
"C": "89 kg",
"D": "180 kg",
"E": "110 kg"
} | multiply(multiply(multiply(6, 3), divide(1, const_100)), const_1000) | divide(n2,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(#2,const_1000)| | "volume of water displaced = ( 6 x 3 x 0.01 ) m 3 = 0.18 m 3 . mass of man = volume of water displaced x density of water = ( 0.18 x 1000 ) kg = 180 kg . answer : d" | physics |
math_qa__vRlN5tXjZaZZcTIo | A computer is programmed to multiply consecutive even integers 2*4*6*8*…*n until the product is divisible by 1551, What is the value of n?
Choose the correct choice from the following answers:
A) 22 B) 38 C) 62 D) 94 E) 672 | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">1_551 / 11</gadget>
<output>141</output>
<gadget id="calculator">141 / 3</gadget>
<output>47</output>
<gadget id="calculator">2 * 47</gadget>
<output>94</output>
<result>D</result> | D | 94 | A computer is programmed to multiply consecutive even integers 2*4*6*8*…*n until the product is divisible by 1551, What is the value of n? | {
"A": "22",
"B": "38",
"C": "62",
"D": "94",
"E": "672"
} | multiply(2, divide(divide(1551, add(const_10, const_1)), const_3)) | add(const_1,const_10)|divide(n4,#0)|divide(#1,const_3)|multiply(n0,#2)| | "factorise 1551 . . 3 * 11 * 47 . . so n has to be a multiple of largest prime number , 61 . . so n = 2 * 47 = 94 . . ans : d" | general |
math_qa__3jbI0Chnne8cvVSB | Julie put half of her savings in a savings account that pays an annual simple interest and half in a savings account that pays an annual compound interest. After two years she earned $112 and $120 from the simple interest account and the compound interest account respectively. If the interest rates for both accounts were the same, what was the amount of Julie's initial savings? Choose the correct choice from the following options
A) 600
B) 784
C) 1080
D) 1200
E) 1440 | <gadget id="calculator">120 - 112</gadget>
<output>8</output>
<gadget id="calculator">2 * 8</gadget>
<output>16</output>
<gadget id="calculator">16 / 112</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">112 / (1/7)</gadget>
<output>784</output>
<result>B</result> | B | 784 | Julie put half of her savings in a savings account that pays an annual simple interest and half in a savings account that pays an annual compound interest. After two years she earned $112 and $120 from the simple interest account and the compound interest account respectively. If the interest rates for both accounts were the same, what was the amount of Julie's initial savings? | {
"A": "600",
"B": "784",
"C": "1080",
"D": "1200",
"E": "1440"
} | divide(112, divide(multiply(const_2, subtract(120, 112)), 112)) | subtract(n1,n0)|multiply(#0,const_2)|divide(#1,n0)|divide(n0,#2) | $ 112 for 2 years = $ 56 per year . extra $ 8 yearned with the compound interest is the percent yearned on percent . so , $ 8 is yearned on $ 56 , which means that the interest = 7 % . this on the other hand means that half of the savings = 56 * 7 = $ 392 . twice of that = $ 784 . answer : b . | gain |
math_qa__i0Q5h8TMSeCT071C | if 70% of (x-y) = 30% of (x+y) then what percent of x is y? Choose the most appropriate option: A) 2.5 % B) 40 % C) 5 % D) 15 % E) 25 % | <gadget id="calculator">70 - 30</gadget>
<output>40</output>
<gadget id="calculator">70 + 30</gadget>
<output>100</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>B</result> | B | 40 | if 70% of (x-y) = 30% of (x+y) then what percent of x is y? | {
"A": "2.5 %",
"B": "40 %",
"C": "5 %",
"D": "15 %",
"E": "25 %"
} | multiply(divide(subtract(70, 30), add(70, 30)), const_100) | add(n0,n1)|subtract(n0,n1)|divide(#1,#0)|multiply(#2,const_100)| | "70 % of ( x - y ) = 30 % of ( x + y ) ( 70 / 100 ) ( x - y ) = ( 30 / 100 ) ( x + y ) 7 ( x - y ) = 3 ( x + y ) 4 x = 10 y x = 5 / 2 y therefore required percentage = ( ( y / x ) x 100 ) % = ( ( y / ( 5 / 2 ) y ) x 100 ) = 40 % answer is b ." | general |
math_qa__EPD9S2pJlCotj5Gl | A man spends 1/3rd of his salary on food. he spends 1/4th on rent and 1/5th on cloths. If he is left with 1760, then who much salary does he earn. Choices: A) 8120 B) 8123 C) 8222 D) 8322 E) 8422 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/3) + (1/4)</gadget>
<output>7/12 = around 0.583333</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(7/12) + (1/5)</gadget>
<output>47/60 = around 0.783333</output>
<gadget id="calculator">1 - (47/60)</gadget>
<output>13/60 = around 0.216667</output>
<gadget id="calculator">1_760 / (13/60)</gadget>
<output>105_600/13 = around 8_123.076923</output>
<result>B</result> | B | 8,123 | A man spends 1/3rd of his salary on food. he spends 1/4th on rent and 1/5th on cloths. If he is left with 1760, then who much salary does he earn. | {
"A": "8120",
"B": "8123",
"C": "8222",
"D": "8322",
"E": "8422"
} | divide(1760, subtract(1, add(add(divide(1, 3), divide(1, 4)), divide(1, 5)))) | divide(n0,n1)|divide(n0,n3)|divide(n0,n5)|add(#0,#1)|add(#3,#2)|subtract(n0,#4)|divide(n6,#5)| | "let salary be x total spent = ( x / 3 + x / 4 + x / 5 ) = ( 47 / 60 ) * x left = ( x - 47 x / 60 ) = ( 13 / 60 ) * x given , ( 13 / 60 ) * x = 1760 x = ( 1760 * 60 ) / 13 = 8123.077 = 8123 ( approax ) answer : b" | general |
math_qa__FmuFb6tPyD34YFnO | The length of the ribbon was originally 55cm. It was reduced in the ratio 11 : 7. What is its length now? Options:
A) 6 cm B) 12 cm C) 35 cm D) 44 cm E) none of these | <gadget id="calculator">7 / 11</gadget>
<output>7/11 = around 0.636364</output>
<gadget id="calculator">55 * (7/11)</gadget>
<output>35</output>
<result>C</result> | C | 35 | The length of the ribbon was originally 55cm. It was reduced in the ratio 11 : 7. What is its length now? | {
"A": "6 cm",
"B": "12 cm",
"C": "35 cm",
"D": "44 cm",
"E": "none of these"
} | multiply(55, divide(7, 11)) | divide(n2,n1)|multiply(n0,#0) | explanation : length of ribbon originally = 55 cm let the original length be 11 x and reduced length be 7 x . but 11 x = 55 cm x = 55 / 11 cm = 5 cm therefore , reduced length = 7 x cm = 7 5 cm = 35 cm answer : c | other |
math_qa__MJcfBMQRc3OoEUzx | At 12.00 hours, J starts to walk from his house at 6 kmph. At 13.30, P follows him from J's house on his bicycle at 8 kmph. When will J be 3 km behind P? Select
A) 19.39 B) 19.3 C) 19.32 D) 19.33 E) 19.36 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">6 * (3/2)</gadget>
<output>9</output>
<gadget id="calculator">9 + 3</gadget>
<output>12</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">13.3 + 6</gadget>
<output>19.3</output>
<result>B</result> | B | 19.3 | At 12.00 hours, J starts to walk from his house at 6 kmph. At 13.30, P follows him from J's house on his bicycle at 8 kmph. When will J be 3 km behind P? | {
"A": "19.39",
"B": "19.3",
"C": "19.32",
"D": "19.33",
"E": "19.36"
} | add(13.3, divide(add(multiply(6, divide(const_3, const_2)), 3), subtract(8, 6))) | divide(const_3,const_2)|subtract(n3,n1)|multiply(n1,#0)|add(n4,#2)|divide(#3,#1)|add(n2,#4) | by the time p starts j is 1.5 hr x 6 = 9 km away from his house . j is 3 km behind when p is 3 km ahead of him . ie . , p has to cover 12 km . so he takes 12 / ( 8 - 6 ) = 6 hrs after 13.30 . so the required time is 19.30 hrs answer : b | physics |
math_qa__4pnFFgQHCOeTKcbf | How many seconds will a 800 m long train take to cross a man walking with a speed of 5 km/hr in the direction of the moving train if the speed of the train is 65 km/hr? Choose the correct choice from the following answers: A) 30 B) 50 C) 66 D) 44 E) 48 | <gadget id="calculator">65 - 5</gadget>
<output>60</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">800 / (50/3)</gadget>
<output>48</output>
<result>E</result> | E | 48 | How many seconds will a 800 m long train take to cross a man walking with a speed of 5 km/hr in the direction of the moving train if the speed of the train is 65 km/hr? | {
"A": "30",
"B": "50",
"C": "66",
"D": "44",
"E": "48"
} | divide(800, multiply(subtract(65, 5), const_0_2778)) | subtract(n2,n1)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 65 - 5 = 60 km / hr . = 60 * 5 / 18 = 50 / 3 m / sec . time taken to pass the man = 800 * 3 / 50 = 48 sec . answer : e" | physics |
math_qa__5ghHGkD1AirhJCKx | A and B together can do a piece of work in 6 days and A alone can do it in 14 days. In how many days can B alone can do it?
Choose one.
A) 12 days B) 15 days C) 21 / 2 days D) 21 days E) 22 days | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 14</gadget>
<output>1/14 = around 0.071429</output>
<gadget id="calculator">(1/6) - (1/14)</gadget>
<output>2/21 = around 0.095238</output>
<gadget id="calculator">1 / (2/21)</gadget>
<output>21/2 = around 10.5</output>
<result>C</result> | C | 10.5 | A and B together can do a piece of work in 6 days and A alone can do it in 14 days. In how many days can B alone can do it? | {
"A": "12 days",
"B": "15 days",
"C": "21 / 2 days",
"D": "21 days",
"E": "22 days"
} | inverse(subtract(inverse(6), inverse(14))) | inverse(n0)|inverse(n1)|subtract(#0,#1)|inverse(#2)| | "explanation : a and b can do work 1 / 6 in 1 day a alone can do 1 / 14 work in 1 day b alone can do ( 1 / 6 - 1 / 14 ) = 2 / 21 work in 1 day = > complete work can be done in 21 / 2 days by b answer : option c" | physics |
math_qa__9If4vLCY3TZqwUbW | Triathlete Dan runs along a 2-mile stretch of river and then swims back along the same route. If Dan runs at a rate of 8 miles per hour and swims at a rate of 6 miles per hour, what is his average rate for the entire trip in miles per minute? Select
A) 1 / 9 B) 2 / 15 C) 3 / 15 D) 1 / 4 E) 3 / 8 | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 60</gadget>
<output>20</output>
<gadget id="calculator">2 / 8</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 60</gadget>
<output>15</output>
<gadget id="calculator">20 + 15</gadget>
<output>35</output>
<gadget id="calculator">4 / 35</gadget>
<output>4/35 = around 0.114286</output>
<result>A</result> | A | 0.111111 | Triathlete Dan runs along a 2-mile stretch of river and then swims back along the same route. If Dan runs at a rate of 8 miles per hour and swims at a rate of 6 miles per hour, what is his average rate for the entire trip in miles per minute? | {
"A": "1 / 9",
"B": "2 / 15",
"C": "3 / 15",
"D": "1 / 4",
"E": "3 / 8"
} | divide(add(2, 2), add(multiply(divide(2, 6), const_60), multiply(divide(2, 8), const_60))) | add(n0,n0)|divide(n0,n2)|divide(n0,n1)|multiply(#1,const_60)|multiply(#2,const_60)|add(#3,#4)|divide(#0,#5)| | "dan travels 4 miles round trip . running part : ( 2 / 8 = 1 / 4 * 60 = 15 minutes ) swimming part : ( 2 / 6 = 1 / 3 * 60 = 20 minutes ) 4 miles in ( 15 + 20 ) minutes 4 / 35 = 1 / 9 mile per minute answer : 1 / 9 mile per minute" | physics |
math_qa__hsO9iu3PBTE1QBPm | A man engaged a servant on the condition that he would pay him Rs.600 and a uniform after one year service. He served only for 9 months and received uniform and Rs.400, find the price of the uniform? Choose the correct choice from the following choices: A) s . 80 B) s . 85 C) s . 90 D) s . 100 E) s . 200 | <gadget id="calculator">9 * 600</gadget>
<output>5_400</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 * 400</gadget>
<output>4_800</output>
<gadget id="calculator">5_400 - 4_800</gadget>
<output>600</output>
<gadget id="calculator">12 * 1</gadget>
<output>12</output>
<gadget id="calculator">600 / 12</gadget>
<output>50</output>
<gadget id="calculator">50 * 4</gadget>
<output>200</output>
<result>E</result> | E | 200 | A man engaged a servant on the condition that he would pay him Rs.600 and a uniform after one year service. He served only for 9 months and received uniform and Rs.400, find the price of the uniform? | {
"A": "s . 80",
"B": "s . 85",
"C": "s . 90",
"D": "s . 100",
"E": "s . 200"
} | multiply(divide(subtract(multiply(9, 600), multiply(multiply(const_3, const_4), 400)), multiply(multiply(const_3, const_4), const_1)), const_4) | multiply(n0,n1)|multiply(const_3,const_4)|multiply(n2,#1)|multiply(#1,const_1)|subtract(#0,#2)|divide(#4,#3)|multiply(#5,const_4) | 9 / 12 = 3 / 4 * 600 = 450 400 - - - - - - - - - - - - - 50 1 / 4 - - - - - - - - 50 1 - - - - - - - - - ? = > rs . 200 answer : e | general |
math_qa__XuVF2JaLKOWADQwe | Find the value of y from (12)^1 x 6^4 ÷ 432 = y? Choose the correct option.
A) 2134 B) 2234 C) 2540 D) 2560 E) 36 | <gadget id="calculator">12 ** 1</gadget>
<output>12</output>
<gadget id="calculator">6 ** 4</gadget>
<output>1_296</output>
<gadget id="calculator">12 * 1_296</gadget>
<output>15_552</output>
<gadget id="calculator">15_552 / 432</gadget>
<output>36</output>
<result>E</result> | E | 36 | Find the value of y from (12)^1 x 6^4 ÷ 432 = y? | {
"A": "2134",
"B": "2234",
"C": "2540",
"D": "2560",
"E": "36"
} | divide(multiply(power(12, 1), power(6, 4)), 432) | power(n0,n1)|power(n2,n3)|multiply(#0,#1)|divide(#2,n4)| | "36 e" | general |
math_qa__1JisMKHe0ych8Rg0 | If 1/8 of a pencil is black, 1/2 of the remaining is white and the remaining 3 1/2 cm is blue, find the total length of the pencil.
Choose one.
A) 12 B) 9 C) 8 D) 6 E) 5 | <gadget id="calculator">8 * 1</gadget>
<output>8</output>
<result>C</result> | C | 8 | If 1/8 of a pencil is black, 1/2 of the remaining is white and the remaining 3 1/2 cm is blue, find the total length of the pencil. | {
"A": "12",
"B": "9",
"C": "8",
"D": "6",
"E": "5"
} | multiply(8, 1) | multiply(n0,n1) | let the total length of the pencil be x cm . black part is 1 / 8 of the length so x / 8 . so the remaining part is x - x / 8 = = > 8 x / 8 - x / 8 = = > 7 x / 8 cm . white part = 1 / 2 * 7 x / 8 = 7 x / 16 cm . so the remaining part is 7 x / 8 - 7 x / 16 = = > 14 x / 16 - 7 x / 16 = 7 x / 16 which is equal to 3 1 / 2 . 7 x / 16 = 7 / 2 cross multiply and we get x = 16 / 2 = 8 cm . so the total length of the pencil is 8 cm . the correct answer is option c ) 8 . | general |
math_qa__SMgyYk5yByAEb2Z5 | Marcella has 25 pairs of shoes. If she loses 9 individual shoes, what is the greatest number of matching pairs she could have left? Select:
A) 21 B) 20 C) 19 D) 16 E) 15 | <gadget id="calculator">9 / 2</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">floor(9/2)</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">25 - 5</gadget>
<output>20</output>
<result>B</result> | B | 20 | Marcella has 25 pairs of shoes. If she loses 9 individual shoes, what is the greatest number of matching pairs she could have left? | {
"A": "21",
"B": "20",
"C": "19",
"D": "16",
"E": "15"
} | subtract(25, add(floor(divide(9, const_2)), const_1)) | divide(n1,const_2)|floor(#0)|add(#1,const_1)|subtract(n0,#2)| | "greatest number of paired shoes means greatest number of lost pairs 9 shoes have 4 pairs and 1 extra shoes of a pair . so a otal of 5 pairs she loses leftover pair = 20 answer : b" | general |
math_qa__EvofXxmsU4VXpyBE | The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 180 resolutions? Choose the correct choice from the following answers: A) 724 m B) 704 m C) 287 m D) 278 m E) 253.4 m | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">21 + 1</gadget>
<output>22</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">(22/7) * 22.4</gadget>
<output>70.4</output>
<gadget id="calculator">70.4 * 2</gadget>
<output>140.8</output>
<gadget id="calculator">140.8 * 180</gadget>
<output>25_344</output>
<gadget id="calculator">25_344 / 100</gadget>
<output>6_336/25 = around 253.44</output>
<result>E</result> | E | 253.4 | The radius of a wheel is 22.4 cm. What is the distance covered by the wheel in making 180 resolutions? | {
"A": "724 m",
"B": "704 m",
"C": "287 m",
"D": "278 m",
"E": "253.4 m"
} | divide(multiply(multiply(multiply(divide(add(multiply(add(const_3, const_4), const_3), const_1), add(const_3, const_4)), 22.4), const_2), 180), const_100) | add(const_3,const_4)|multiply(#0,const_3)|add(#1,const_1)|divide(#2,#0)|multiply(n0,#3)|multiply(#4,const_2)|multiply(n1,#5)|divide(#6,const_100)| | "in one resolution , the distance covered by the wheel is its own circumference . distance covered in 180 resolutions . = 180 * 2 * 22 / 7 * 22.4 = 25344 cm = 253.4 m answer : e" | physics |
math_qa__XBNRfwHj4w0bBLkz | A reduction of 20% in the price of oil enables a house wife to obtain 10 kgs more for Rs.1500, what is the reduced price for kg? Choose the correct choice: A) rs . 20 B) rs . 25 C) rs . 30 D) rs . 35 E) rs . 40 | <gadget id="calculator">1_500 * 20</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 / 100</gadget>
<output>300</output>
<gadget id="calculator">300 / 10</gadget>
<output>30</output>
<result>C</result> | C | 30 | A reduction of 20% in the price of oil enables a house wife to obtain 10 kgs more for Rs.1500, what is the reduced price for kg? | {
"A": "rs . 20",
"B": "rs . 25",
"C": "rs . 30",
"D": "rs . 35",
"E": "rs . 40"
} | divide(divide(multiply(1500, 20), const_100), 10) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)| | "explanation : 1500 * ( 20 / 100 ) = 300 - - - - 10 ? - - - - 1 = > rs . 30 answer : c" | gain |
math_qa__GVtvpnWcj8p0BrDB | A fruit drink is made of orange, watermelon, and grape juice, where 25 percent of the drink is orange juice and 40 percent is watermelon juice. If the drink is made with 70 ounces of grape juice, how many ounces is the drink total? Answers.
A) 125 B) 160 C) 200 D) 250 E) 320 | <gadget id="calculator">70 * 25</gadget>
<output>1_750</output>
<gadget id="calculator">40 + 25</gadget>
<output>65</output>
<gadget id="calculator">100 - 65</gadget>
<output>35</output>
<gadget id="calculator">1_750 / 35</gadget>
<output>50</output>
<gadget id="calculator">70 + 50</gadget>
<output>120</output>
<gadget id="calculator">70 * 40</gadget>
<output>2_800</output>
<gadget id="calculator">2_800 / 35</gadget>
<output>80</output>
<gadget id="calculator">120 + 80</gadget>
<output>200</output>
<result>C</result> | C | 200 | A fruit drink is made of orange, watermelon, and grape juice, where 25 percent of the drink is orange juice and 40 percent is watermelon juice. If the drink is made with 70 ounces of grape juice, how many ounces is the drink total? | {
"A": "125",
"B": "160",
"C": "200",
"D": "250",
"E": "320"
} | add(add(70, divide(multiply(70, 25), subtract(const_100, add(40, 25)))), divide(multiply(70, 40), subtract(const_100, add(40, 25)))) | add(n0,n1)|multiply(n0,n2)|multiply(n1,n2)|subtract(const_100,#0)|divide(#1,#3)|divide(#2,#3)|add(n2,#4)|add(#6,#5)| | "let the total number of ounces in the drink be x . % of orange = 25 % % of watermelon = 40 % % of grape = 100 % - 65 % = 35 % 0.35 x = 70 x = 200 therefore there are a total of 200 ounces in the drink . the answer is c ." | general |
math_qa__LypPlTfgl38ZpITc | The wages earned by Robin is 30% more than that earned by Erica. The wages earned by Charles is 60% more than that earned by Erica. How much percent is the wages earned by Charles more than that earned by Robin? Answers:
A) 18.75 % B) 23 % C) 30 % D) 50 % E) 100 % | <gadget id="calculator">100 + 60</gadget>
<output>160</output>
<gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">160 - 130</gadget>
<output>30</output>
<gadget id="calculator">30 / 130</gadget>
<output>3/13 = around 0.230769</output>
<gadget id="calculator">(3/13) * 100</gadget>
<output>300/13 = around 23.076923</output>
<result>B</result> | B | 23 | The wages earned by Robin is 30% more than that earned by Erica. The wages earned by Charles is 60% more than that earned by Erica. How much percent is the wages earned by Charles more than that earned by Robin? | {
"A": "18.75 %",
"B": "23 %",
"C": "30 %",
"D": "50 %",
"E": "100 %"
} | multiply(divide(subtract(add(const_100, 60), add(const_100, 30)), add(const_100, 30)), const_100) | add(n1,const_100)|add(n0,const_100)|subtract(#0,#1)|divide(#2,#1)|multiply(#3,const_100) | let wage of erica = 10 wage of robin = 1.3 * 10 = 13 wage of charles = 1.6 * 10 = 16 percentage by which wage earned by charles is more than that earned by robin = ( 16 - 13 ) / 13 * 100 % = 3 / 13 * 100 % = 23 % answer b | general |
math_qa__mXTQe6bWgdq4BtoL | Find the surface area of a cuboid 12 m long, 14 m broad and 7 m high
Select the correct option: A) 868 sq . cm B) 600 sq . cm C) 700 sq . cm D) 900 sq . cm E) none of these | <gadget id="calculator">12 * 14</gadget>
<output>168</output>
<gadget id="calculator">12 * 7</gadget>
<output>84</output>
<gadget id="calculator">168 + 84</gadget>
<output>252</output>
<gadget id="calculator">14 * 7</gadget>
<output>98</output>
<gadget id="calculator">252 + 98</gadget>
<output>350</output>
<gadget id="calculator">2 * 350</gadget>
<output>700</output>
<result>C</result> | C | 700 | Find the surface area of a cuboid 12 m long, 14 m broad and 7 m high | {
"A": "868 sq . cm",
"B": "600 sq . cm",
"C": "700 sq . cm",
"D": "900 sq . cm",
"E": "none of these"
} | multiply(const_2, add(add(multiply(12, 14), multiply(12, 7)), multiply(14, 7))) | multiply(n0,n1)|multiply(n0,n2)|multiply(n1,n2)|add(#0,#1)|add(#3,#2)|multiply(#4,const_2) | explanation : surface area = [ 2 ( 12 x 14 + 14 x 7 + 12 x 7 ) ] cm 2 = ( 2 x 350 ) cm 2 = 700 cm 2 . answer : c | geometry |
math_qa__6OnzDK0BZm9EbIAy | The speed of a boat in still water in 42 km/hr and the rate of current is 7 km/hr. The distance travelled downstream in 44 minutes is: Choices.
A) 86.6 km B) 46.6 km C) 35.9 km D) 35.6 km E) 26.6 km | <gadget id="calculator">42 + 7</gadget>
<output>49</output>
<gadget id="calculator">44 / 60</gadget>
<output>11/15 = around 0.733333</output>
<gadget id="calculator">49 * (11/15)</gadget>
<output>539/15 = around 35.933333</output>
<result>C</result> | C | 35.9 | The speed of a boat in still water in 42 km/hr and the rate of current is 7 km/hr. The distance travelled downstream in 44 minutes is: | {
"A": "86.6 km",
"B": "46.6 km",
"C": "35.9 km",
"D": "35.6 km",
"E": "26.6 km"
} | multiply(add(42, 7), divide(44, const_60)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "speed downstream = ( 42 + 7 ) = 49 kmph time = 44 minutes = 44 / 60 hour = 11 / 15 hour distance travelled = time × speed = 11 / 15 × 49 = 35.9 km answer : c" | physics |
math_qa__WHtLjZYyVHPt0cPd | Sides of a rectangular park are in the ratio 2:5 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is? Pick one: A) s . 122 B) s . 129 C) s . 125 D) s . 120 E) s . 130.64 | <gadget id="calculator">3_750 * 5</gadget>
<output>18_750</output>
<gadget id="calculator">18_750 / 2</gadget>
<output>9_375</output>
<gadget id="calculator">9_375 ** (1/2)</gadget>
<output>25*sqrt(15) = around 96.824584</output>
<gadget id="calculator">3_750 / (25*sqrt(15))</gadget>
<output>10*sqrt(15) = around 38.729833</output>
<gadget id="calculator">2 * ((25*sqrt(15)) + (10*sqrt(15)))</gadget>
<output>70*sqrt(15) = around 271.108834</output>
<gadget id="calculator">50 * (70*sqrt(15))</gadget>
<output>3500*sqrt(15) = around 13_555.441712</output>
<gadget id="calculator">(3500*sqrt(15)) / 100</gadget>
<output>35*sqrt(15) = around 135.554417</output>
<result>E</result> | E | 130.64 | Sides of a rectangular park are in the ratio 2:5 and its area is 3750 sq m, the cost of fencing it at 50 ps per meter is? | {
"A": "s . 122",
"B": "s . 129",
"C": "s . 125",
"D": "s . 120",
"E": "s . 130.64"
} | divide(multiply(50, rectangle_perimeter(sqrt(divide(multiply(3750, 5), 2)), divide(3750, sqrt(divide(multiply(3750, 5), 2))))), const_100) | multiply(n1,n2)|divide(#0,n0)|sqrt(#1)|divide(n2,#2)|rectangle_perimeter(#3,#2)|multiply(n3,#4)|divide(#5,const_100)| | "2 x * 5 x = 3750 = > x = 19.36 2 ( 80.64 + 50 ) = 261.28 m 261.28 * 1 / 2 = rs . 130.64 answer : e" | physics |
math_qa__6H6EPqT9ghjyOMly | The sum of ages of 5 children born at the intervals of 3 years each is 60 years. What is the age of the youngest child? Choose the correct choice from the following answers.
A) 3 years B) 4 years C) 6 years D) 7 years E) 8 years | <gadget id="calculator">60 / 5</gadget>
<output>12</output>
<gadget id="calculator">12 - 3</gadget>
<output>9</output>
<gadget id="calculator">9 - 3</gadget>
<output>6</output>
<result>C</result> | C | 6 | The sum of ages of 5 children born at the intervals of 3 years each is 60 years. What is the age of the youngest child? | {
"A": "3 years",
"B": "4 years",
"C": "6 years",
"D": "7 years",
"E": "8 years"
} | subtract(subtract(divide(60, 5), 3), 3) | divide(n2,n0)|subtract(#0,n1)|subtract(#1,n1)| | "let the ages of children be x , ( x + 3 ) , ( x + 6 ) , ( x + 9 ) and ( x + 12 ) years . then , x + ( x + 3 ) + ( x + 6 ) + ( x + 9 ) + ( x + 12 ) = 60 5 x = 30 x = 6 . age of the youngest child = x = 6 years . c )" | general |
math_qa__zvJhkFxmjt0NVODC | A 100-litre mixture of milk and water contains 36 litres of milk. 'x' litres of this mixture is removed and replaced with an equal quantum of water. If the process is repeated once, then the concentration of the milk stands reduced at 9%. What is the value of x? Select the correct option.
A) 57.5 litres B) 56.67 litres C) 57.67 litres D) 56.5 litres E) 50 litres | <gadget id="calculator">9 / 36</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) ** (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 - (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">100 * (1/2)</gadget>
<output>50</output>
<result>E</result> | E | 50 | A 100-litre mixture of milk and water contains 36 litres of milk. 'x' litres of this mixture is removed and replaced with an equal quantum of water. If the process is repeated once, then the concentration of the milk stands reduced at 9%. What is the value of x? | {
"A": "57.5 litres",
"B": "56.67 litres",
"C": "57.67 litres",
"D": "56.5 litres",
"E": "50 litres"
} | multiply(100, subtract(const_1, sqrt(divide(9, 36)))) | divide(n2,n1)|sqrt(#0)|subtract(const_1,#1)|multiply(n0,#2)| | "working formula . . . initial concentration * initial volume = final concentration * final volume . let x is the part removed from 100 lts . 36 % ( 1 - x / 100 ) ^ 2 = 9 % * 100 % ( 1 - x / 100 ) ^ 2 = 9 / 36 - - - - - - > ( 1 - x / 100 ) ^ 2 = ( 3 / 6 ) ^ 2 100 - x = 300 / 6 x = 50 ans e" | general |
math_qa__FB9ljnjpSOBeWg89 | The length of each side of an equilateral triangle having an area of 4√3 cm2 is? Choose the most appropriate option
A) 3 : 4
B) 3 : 9
C) 3 : 7
D) 3 : 1
E) 3 : 2 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<result>A</result> | A | 0.75 | The length of each side of an equilateral triangle having an area of 4√3 cm2 is? | {
"A": "3 : 4",
"B": "3 : 9",
"C": "3 : 7",
"D": "3 : 1",
"E": "3 : 2"
} | divide(3, 4) | divide(n1,n0) | let the speed of the train be x km / hr and that of the car be y km / hr . then , 120 / x + 480 / y = 8 or 1 / x + 4 / y = 1 / 15 - - - ( i ) and , 200 / x + 400 / y = 25 / 3 or 1 / x + 2 / y = 1 / 24 - - - ( ii ) solving ( i ) and ( ii ) , we get x = 60 and y = 80 ratio of speeds = 60 : 80 = 3 : 4 answer : a | geometry |
math_qa__8edNtgD3PEQWCRa4 | Length of a rectangular plot is 24 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr? Select the correct option.
A) 52 m B) 62 m C) 72 m D) 82 m E) 92 m | <gadget id="calculator">5_300 / 26.5</gadget>
<output>200</output>
<gadget id="calculator">2 * 24</gadget>
<output>48</output>
<gadget id="calculator">200 + 48</gadget>
<output>248</output>
<gadget id="calculator">248 / 4</gadget>
<output>62</output>
<result>B</result> | B | 62 | Length of a rectangular plot is 24 mtr more than its breadth. If the cost of fencin gthe plot at 26.50 per meter is Rs. 5300, what is the length of the plot in mtr? | {
"A": "52 m",
"B": "62 m",
"C": "72 m",
"D": "82 m",
"E": "92 m"
} | divide(add(divide(5300, 26.50), multiply(const_2, 24)), const_4) | divide(n2,n1)|multiply(n0,const_2)|add(#0,#1)|divide(#2,const_4)| | "let breadth = x metres . then , length = ( x + 24 ) metres . perimeter = 5300 m = 200 m . 26.50 2 [ ( x + 24 ) + x ] = 200 2 x + 24 = 100 2 x = 76 x = 38 . hence , length = x + 24 = 62 m b" | physics |
math_qa__Sb15ysf0WHq5OnqP | The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 150. What is the manager's monthly salary ? Choices:
A) rs . 6003
B) rs . 6029
C) rs . 4650
D) rs . 6108
E) rs . 6011 | <gadget id="calculator">1_500 + 150</gadget>
<output>1_650</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">1_650 * 21</gadget>
<output>34_650</output>
<gadget id="calculator">1_500 * 20</gadget>
<output>30_000</output>
<gadget id="calculator">34_650 - 30_000</gadget>
<output>4_650</output>
<result>C</result> | C | 4,650 | The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 150. What is the manager's monthly salary ? | {
"A": "rs . 6003",
"B": "rs . 6029",
"C": "rs . 4650",
"D": "rs . 6108",
"E": "rs . 6011"
} | subtract(multiply(add(1500, 150), add(20, const_1)), multiply(1500, 20)) | add(n1,n2)|add(n0,const_1)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "explanation : manager ' s monthly salary rs . ( 1650 * 21 - 1500 * 20 ) = rs . 4650 . answer : c" | general |
math_qa__Kw0o3RMFVh7h4ko8 | The probability of two events A and B are0.25 and 0.30 respectively. The probability that both A and B occur is 0.15. The probability that neither A nor B occur is _________ Select:
A) 0.45 B) 0.4 C) 0.5 D) 0.05 E) 0.6 | <gadget id="calculator">0.25 + 0.3</gadget>
<output>0.55</output>
<gadget id="calculator">0.55 - 0.15</gadget>
<output>0.4</output>
<gadget id="calculator">1 - 0.4</gadget>
<output>0.6</output>
<result>E</result> | E | 0.6 | The probability of two events A and B are0.25 and 0.30 respectively. The probability that both A and B occur is 0.15. The probability that neither A nor B occur is _________ | {
"A": "0.45",
"B": "0.4",
"C": "0.5",
"D": "0.05",
"E": "0.6"
} | subtract(const_1, subtract(add(0.25, 0.3), 0.15)) | add(n0,n1)|subtract(#0,n2)|subtract(const_1,#1) | we are apply that formula . . . . . . . . . . . . . . p ( aorb ) = p ( a ) + p ( b ) - p ( a and b ) = . 25 + . 30 - . 15 = . 40 but the probability of neither a nor b = 1 - . 40 = 0.60 answer : e | other |
math_qa__aHjKaXkR2GZc7073 | The size of a flat-screen tablet is given as the length of the screen’s diagonal. How many square inches greater is the screen of a square 6-inch flat-screen tablet than a square 5 -inch flat-screen tablet? Choices.
A) 5.0 B) 6.0 C) 6.8 D) 5.8 E) 5.5 | <gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">25 / 2</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">18 - (25/2)</gadget>
<output>11/2 = around 5.5</output>
<result>E</result> | E | 5.5 | The size of a flat-screen tablet is given as the length of the screen’s diagonal. How many square inches greater is the screen of a square 6-inch flat-screen tablet than a square 5 -inch flat-screen tablet? | {
"A": "5.0",
"B": "6.0",
"C": "6.8",
"D": "5.8",
"E": "5.5"
} | subtract(divide(power(6, const_2), const_2), divide(power(5, const_2), const_2)) | power(n0,const_2)|power(n1,const_2)|divide(#0,const_2)|divide(#1,const_2)|subtract(#2,#3) | if we take a square with side length x and draw a diagonal , we get two isosceles right triangles . if we focus on one such right triangle , we see that the legs have length x . square 6 - inch flat - screen television the diagonal ( hypotenuse ) = 6 so , we can apply the pythagorean theorem to get x ² + x ² = 6 ² simplify : 2 x ² = 6 ² divide both sides by 2 to get : x ² = 6 ² / 2 since the area of the square = x ² , we can see that the area of this square is 6 ² / 2 square 5 - inch flat - screen television the diagonal ( hypotenuse ) = 5 so , we can apply the pythagorean theorem to get x ² + x ² = 5 ² simplify : 2 x ² = 5 ² divide both sides by 2 to get : x ² = 5 ² / 2 since the area of the square = x ² , we can see that the area of this square is 5 ² / 2 difference in areas = 6 ² / 2 - 5 ² / 2 = ( 6 ² - 5 ² ) / 2 = ( 36 - 25 ) / 2 = 11 / 2 = 5.5 e | geometry |
math_qa__5sHkgpTC2vQ4WnO3 | the sum of 4 consecutive even numbers is 140 . what would be the largest number ?
Pick one.
A) 33
B) 38
C) 70
D) 123
E) 12 | <gadget id="calculator">140 - 12</gadget>
<output>128</output>
<gadget id="calculator">128 / 4</gadget>
<output>32</output>
<gadget id="calculator">32 + 2</gadget>
<output>34</output>
<gadget id="calculator">34 + 2</gadget>
<output>36</output>
<gadget id="calculator">36 + 2</gadget>
<output>38</output>
<result>B</result> | B | 38 | the sum of 4 consecutive even numbers is 140 . what would be the largest number ? | {
"A": "33",
"B": "38",
"C": "70",
"D": "123",
"E": "12"
} | add(add(add(divide(subtract(140, const_12), 4), const_2), const_2), const_2) | subtract(n1,const_12)|divide(#0,n0)|add(#1,const_2)|add(#2,const_2)|add(#3,const_2) | let the four consecutive even numbers be 2 ( x - 2 ) , 2 ( x - 1 ) , 2 x , 2 ( x + 1 ) their sum = 8 x - 4 = 140 = > x = 18 smallest number is : 2 ( x + 1 ) = 38 . answer : b | physics |
math_qa__Vngl5ImVaKRTfIWA | In a sample of college students, 50 percent are third year students and 70 percent are not second-year students. What fraction of those students who are not third-year students are second-year students? Pick one.
A) 2 / 3
B) 1 / 4
C) 2 / 5
D) 3 / 7
E) 2 / 9 | <gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">50 - 30</gadget>
<output>20</output>
<gadget id="calculator">20 / 30</gadget>
<output>2/3 = around 0.666667</output>
<result>A</result> | A | 0.666667 | In a sample of college students, 50 percent are third year students and 70 percent are not second-year students. What fraction of those students who are not third-year students are second-year students? | {
"A": "2 / 3",
"B": "1 / 4",
"C": "2 / 5",
"D": "3 / 7",
"E": "2 / 9"
} | divide(subtract(subtract(const_100, 50), multiply(const_3, const_10)), multiply(const_3, const_10)) | multiply(const_10,const_3)|subtract(const_100,n0)|subtract(#1,#0)|divide(#2,#0) | required answer = 40 / 60 . = 2 / 3 answer is a | gain |
math_qa__Pm7C1TnvnFiTeFYM | A camera lens filter kit containing 5 filters sells for $75.50. If the filters are purchased individually, 3 of them are priced at $7.35 each, 3 at $12.05 each, 1 at $12.50. The amount saved by purchasing the kit is what percent of the total price of the 5 filters purchased individually?
Options.
A) 5.35 % B) 6.35 % C) 7.35 % D) 8.35 % E) 9.35 % | <gadget id="calculator">3 * 7.35</gadget>
<output>22.05</output>
<gadget id="calculator">3 * 12.05</gadget>
<output>36.15</output>
<gadget id="calculator">22.05 + 36.15</gadget>
<output>58.2</output>
<gadget id="calculator">12.5 + 58.2</gadget>
<output>70.7</output>
<gadget id="calculator">75.5 - 70.7</gadget>
<output>4.8</output>
<gadget id="calculator">4.8 * 100</gadget>
<output>480</output>
<gadget id="calculator">480 / 75.5</gadget>
<output>6.357616</output>
<result>B</result> | B | 6.35 | A camera lens filter kit containing 5 filters sells for $75.50. If the filters are purchased individually, 3 of them are priced at $7.35 each, 3 at $12.05 each, 1 at $12.50. The amount saved by purchasing the kit is what percent of the total price of the 5 filters purchased individually? | {
"A": "5.35 %",
"B": "6.35 %",
"C": "7.35 %",
"D": "8.35 %",
"E": "9.35 %"
} | divide(multiply(subtract(75.50, add(12.50, add(multiply(3, 7.35), multiply(3, 12.05)))), const_100), 75.50) | multiply(n2,n3)|multiply(n2,n5)|add(#0,#1)|add(n7,#2)|subtract(n1,#3)|multiply(#4,const_100)|divide(#5,n1)| | "cost of kit = $ 75.50 if filters are purchased individually - $ 7.35 * 3 + $ 12.05 * 3 + $ 12.50 = $ 70.70 amount saved = $ 75.50 - $ 70.70 = $ 4.80 required % age = ( $ 4.80 / $ 75.50 ) * 100 = 6.35 % so , the correct answer is b ." | general |
math_qa__1JDe1Y3rU3cCGBwk | If a randomly selected positive single digit multiple of 3 is multiplied by a randomly selected prime number less than 20, what is the probability E that this product will be a multiple of 45?
Select.
A) 1 / 32 B) 1 / 28 C) 1 / 24 D) 1 / 16 E) 1 / 14 | <gadget id="calculator">20 + 4</gadget>
<output>24</output>
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<result>C</result> | C | 0.041667 | If a randomly selected positive single digit multiple of 3 is multiplied by a randomly selected prime number less than 20, what is the probability E that this product will be a multiple of 45? | {
"A": "1 / 32",
"B": "1 / 28",
"C": "1 / 24",
"D": "1 / 16",
"E": "1 / 14"
} | divide(const_1, add(20, const_4)) | add(n1,const_4)|divide(const_1,#0)| | "there are 3 single digit multiple of 3 , that is , 3 , 6,9 . there are 8 prime nos less than 20 - 2,3 , 5,7 , 11,13 , 17,19 total outcome - 8 * 3 = 24 favourable outcome = 1 ( 9 * 5 ) hence required probability e = 1 / 24 . answer c ." | general |
math_qa__H7rlmFKNlBHbGe2e | Find the lowest common multiple of 24, 36 and 40. Pick one
A) 360
B) 420
C) 510
D) 320
E) 280 | <gadget id="calculator">lcm(24, 36)</gadget>
<output>72</output>
<gadget id="calculator">lcm(72, 40)</gadget>
<output>360</output>
<result>A</result> | A | 360 | Find the lowest common multiple of 24, 36 and 40. | {
"A": "360",
"B": "420",
"C": "510",
"D": "320",
"E": "280"
} | lcm(lcm(24, 36), 40) | lcm(n0,n1)|lcm(n2,#0)| | "lcm = 2 * 2 * 2 * 3 * 3 * 5 = 360 . answer is a" | general |
math_qa__fbnmIOV8bOM4ttaJ | 14 is what percent of 70? Choices
A) 0.2 % B) 2 % C) 5 % D) 20 % E) 500 % | <gadget id="calculator">14 / 70</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>D</result> | D | 20 | 14 is what percent of 70? | {
"A": "0.2 %",
"B": "2 %",
"C": "5 %",
"D": "20 %",
"E": "500 %"
} | multiply(divide(14, 70), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "14 = x * 70 / 100 x = 20 % ans ; d" | gain |
math_qa__NRVWxr0k14it9wI6 | The perimeter of a semi circle is 140 cm then the radius is? Choices.
A) 27 B) 28 C) 19 D) 11 E) 12 | <gadget id="calculator">2 + pi</gadget>
<output>2 + pi = around 5.141593</output>
<gadget id="calculator">140 / (2 + pi)</gadget>
<output>140/(2 + pi) = around 27.228917</output>
<result>A</result> | A | 27 | The perimeter of a semi circle is 140 cm then the radius is? | {
"A": "27",
"B": "28",
"C": "19",
"D": "11",
"E": "12"
} | divide(140, add(const_2, const_pi)) | add(const_2,const_pi)|divide(n0,#0)| | "36 / 7 r = 140 = > r = 27 answer : a" | physics |
math_qa__QdRCYtyYBgjZird6 | among the members of the malmo family , there are 3 times as many members who do not wear glasses as members who do . half of the malmo family members have blue eyes , and 4 / 5 of the family members who have blue eyes do not wear glasses . what percent of the malmo family members wear glasses and do not have blue eyes ? Answers
A) 10 B) 15 C) 20 D) 25 E) 35 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) / 4</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * 100</gadget>
<output>15</output>
<result>B</result> | B | 15 | among the members of the malmo family , there are 3 times as many members who do not wear glasses as members who do . half of the malmo family members have blue eyes , and 4 / 5 of the family members who have blue eyes do not wear glasses . what percent of the malmo family members wear glasses and do not have blue eyes ? | {
"A": "10",
"B": "15",
"C": "20",
"D": "25",
"E": "35"
} | multiply(divide(divide(3, 5), 4), const_100) | divide(n0,n2)|divide(#0,n1)|multiply(#1,const_100) | number in black are given and in red are calculated . now , since x + 3 x = 100 , then x = 25 and therefore = 25 − 10 = 15 answer : b . | general |
math_qa__3EdcQXWZl0dJcdg6 | A theater charges $12 for seats in the orchestra and $8 for seats in the balcony. On a certain night, a total of 360 tickets were sold for a total cost of $3,320. How many more tickets were sold that night for seats in the balcony than for seats in the orchestra? Choose the correct option
A) 90 B) 110 C) 120 D) 140 E) 220 | <gadget id="calculator">12 * 360</gadget>
<output>4_320</output>
<gadget id="calculator">3 * 1_000</gadget>
<output>3_000</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">3_000 + 300</gadget>
<output>3_300</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">3_300 + 20</gadget>
<output>3_320</output>
<gadget id="calculator">4_320 - 3_320</gadget>
<output>1_000</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">1_000 / 4</gadget>
<output>250</output>
<gadget id="calculator">360 - 250</gadget>
<output>110</output>
<gadget id="calculator">250 - 110</gadget>
<output>140</output>
<result>D</result> | D | 140 | A theater charges $12 for seats in the orchestra and $8 for seats in the balcony. On a certain night, a total of 360 tickets were sold for a total cost of $3,320. How many more tickets were sold that night for seats in the balcony than for seats in the orchestra? | {
"A": "90",
"B": "110",
"C": "120",
"D": "140",
"E": "220"
} | subtract(divide(subtract(multiply(12, 360), add(add(multiply(const_3, const_1000), multiply(const_3, const_100)), multiply(const_2, const_10))), subtract(12, 8)), subtract(360, divide(subtract(multiply(12, 360), add(add(multiply(const_3, const_1000), multiply(const_3, const_100)), multiply(const_2, const_10))), subtract(12, 8)))) | multiply(n0,n2)|multiply(const_1000,const_3)|multiply(const_100,const_3)|multiply(const_10,const_2)|subtract(n0,n1)|add(#1,#2)|add(#5,#3)|subtract(#0,#6)|divide(#7,#4)|subtract(n2,#8)|subtract(#8,#9)| | "orchestra seats - a balcony seats - b a + b = 360 and 12 a + 8 b = 3320 solving equations simultaneously ( multiply equation 1 with 8 and subtract from second equation ) 4 a = 3320 - 8 * 360 = 3320 - 2880 = 440 i . e . a = 110 and b = 360 - 110 = 250 more seats in balcony than orchestra = b - a = 250 - 110 = 140 answer : option d" | general |
math_qa__elfVBwT7AQWoJmTD | A train running at the speed of 36 km/hr crosses a pole in 9 seconds. What is the length of the train? Choose one:
A) 120 metres
B) 180 metres
C) 324 metres
D) 90 metres
E) 100 meters | <gadget id="calculator">36 * 1_000</gadget>
<output>36_000</output>
<gadget id="calculator">36_000 / 3_600</gadget>
<output>10</output>
<gadget id="calculator">10 * 9</gadget>
<output>90</output>
<result>D</result> | D | 90 | A train running at the speed of 36 km/hr crosses a pole in 9 seconds. What is the length of the train? | {
"A": "120 metres",
"B": "180 metres",
"C": "324 metres",
"D": "90 metres",
"E": "100 meters"
} | multiply(divide(multiply(36, const_1000), const_3600), 9) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 36 x 5 / 18 m / sec = 30 / 3 m / sec . length of the train = ( speed x time ) . length of the train = 30 / 3 x 9 m = 90 m . answer : d" | physics |
math_qa__SnUz6w8u3FQ3PREg | Tough and Tricky questions: Arithmetic.
(56^2 + 56^2)/28^2 =
Pick one.
A) 4
B) 18
C) 29
D) 8
E) 116 | <gadget id="calculator">56 ** 2</gadget>
<output>3_136</output>
<gadget id="calculator">3_136 + 3_136</gadget>
<output>6_272</output>
<gadget id="calculator">28 ** 2</gadget>
<output>784</output>
<gadget id="calculator">6_272 / 784</gadget>
<output>8</output>
<result>D</result> | D | 8 | Tough and Tricky questions: Arithmetic.
(56^2 + 56^2)/28^2 = | {
"A": "4",
"B": "18",
"C": "29",
"D": "8",
"E": "116"
} | divide(add(power(56, 2), power(56, 2)), power(28, 2)) | power(n0,n1)|power(n4,n1)|add(#0,#0)|divide(#2,#1) | ans is 8 my approach was : ( 56 ^ 2 + 56 ^ 2 ) / 28 ^ 2 = 56 ( 56 + 56 ) / 28 * 28 = 56 * 112 / 28 * 28 = 2 * 4 = 8 d | general |
math_qa__UOMdPKRm4ADG9Fho | a boy has rs . 480 in the denominations of one - rupee notes , 5 - rupee notes and 10 - rupee notes . the number of notes of each denomination is equal . what is the total number of notes that he has ? Choose the correct choice from the following
A) 90
B) 110
C) 140
D) 130
E) 120 | <gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">480 / 16</gadget>
<output>30</output>
<gadget id="calculator">30 * 3</gadget>
<output>90</output>
<result>A</result> | A | 90 | a boy has rs . 480 in the denominations of one - rupee notes , 5 - rupee notes and 10 - rupee notes . the number of notes of each denomination is equal . what is the total number of notes that he has ? | {
"A": "90",
"B": "110",
"C": "140",
"D": "130",
"E": "120"
} | multiply(divide(480, multiply(const_4, const_4)), const_3) | multiply(const_4,const_4)|divide(n0,#0)|multiply(#1,const_3) | let number of notes of each denomination be x . then x + 5 x + 10 x = 480 16 x = 480 x = 30 . hence , total number of notes = 3 x = 90 . a | general |
math_qa__UcbBUYvUmXnQrrXs | Glen and Hannah drive at constant speeds toward each other on a highway. Glen drives at a constant speed of 37 km per hour. At a certain time they pass by each other, and then keep driving away from each other, maintaining their constant speeds. If Glen is 130 km away from Hannah at 6 am, and also 130 km away from Hannah at 11 am, then how fast is Hannah driving (in kilometers per hour)? Choose the correct choice from the following options.
A) 12
B) 13
C) 14
D) 15
E) 16 | <gadget id="calculator">130 * 2</gadget>
<output>260</output>
<gadget id="calculator">11 - 6</gadget>
<output>5</output>
<gadget id="calculator">260 / 5</gadget>
<output>52</output>
<gadget id="calculator">52 - 37</gadget>
<output>15</output>
<result>D</result> | D | 15 | Glen and Hannah drive at constant speeds toward each other on a highway. Glen drives at a constant speed of 37 km per hour. At a certain time they pass by each other, and then keep driving away from each other, maintaining their constant speeds. If Glen is 130 km away from Hannah at 6 am, and also 130 km away from Hannah at 11 am, then how fast is Hannah driving (in kilometers per hour)? | {
"A": "12",
"B": "13",
"C": "14",
"D": "15",
"E": "16"
} | subtract(divide(multiply(130, const_2), subtract(11, 6)), 37) | multiply(n1,const_2)|subtract(n4,n2)|divide(#0,#1)|subtract(#2,n0) | glen and hannah complete 260 km / 5 hours = 52 km / hour hannah ' s speed is 52 - 37 = 15 km / hour the answer is d . | physics |
math_qa__eoScXubzjsA7vzNL | The output of a factory was increased by 10% to keep up with rising demand. To handle the holiday rush, this new output was increased by 20%. By approximately what percent would the output now have to be decreased in order to restore the original output?
Answers:
A) 20 %
B) 24 %
C) 30 %
D) 32 %
E) 79 % | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">110 * (1/5)</gadget>
<output>22</output>
<gadget id="calculator">110 + 22</gadget>
<output>132</output>
<gadget id="calculator">132 - 100</gadget>
<output>32</output>
<gadget id="calculator">32 * 100</gadget>
<output>3_200</output>
<gadget id="calculator">3_200 / 132</gadget>
<output>800/33 = around 24.242424</output>
<result>B</result> | B | 24 | The output of a factory was increased by 10% to keep up with rising demand. To handle the holiday rush, this new output was increased by 20%. By approximately what percent would the output now have to be decreased in order to restore the original output? | {
"A": "20 %",
"B": "24 %",
"C": "30 %",
"D": "32 %",
"E": "79 %"
} | divide(multiply(subtract(add(add(const_100, 10), multiply(add(const_100, 10), divide(20, const_100))), const_100), const_100), add(add(const_100, 10), multiply(add(const_100, 10), divide(20, const_100)))) | add(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)|add(#0,#2)|subtract(#3,const_100)|multiply(#4,const_100)|divide(#5,#3)| | "let initial output is o then after 10 % increase it will be 1.1 o and after 20 % increase on this new output the latest output will be 1.1 o * 1.20 = 1.32 o now we have to decrease the output by some percentage so that the new output is same as the starting output ( o ) so , 1.32 o * ( 1 - x / 100 ) = o = > x = 24.24 % so , answer will be b" | general |
math_qa__MHzj0EqCguvmJUN0 | Integer d is the product of the integers a,b, and c and 1<a<b<c. If the remainder when 233 is divided by d is 79, what is the value of a+c? Choose one
A) 7
B) 9
C) 13
D) 14
E) 18 | <gadget id="calculator">233 - 79</gadget>
<output>154</output>
<gadget id="calculator">154 / 2</gadget>
<output>77</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">77 / 7</gadget>
<output>11</output>
<gadget id="calculator">2 + 11</gadget>
<output>13</output>
<result>C</result> | C | 13 | Integer d is the product of the integers a,b, and c and 1<a<b<c. If the remainder when 233 is divided by d is 79, what is the value of a+c? | {
"A": "7",
"B": "9",
"C": "13",
"D": "14",
"E": "18"
} | add(const_2, divide(divide(subtract(233, 79), const_2), add(const_3, const_4))) | add(const_3,const_4)|subtract(n1,n2)|divide(#1,const_2)|divide(#2,#0)|add(#3,const_2) | 79 is the remainder , therefore the number ( a * b * c ) or multiple of the number we need is 79 less than 233 hence 233 - 79 = 154 therefore , 154 is either a number we want or it is a multiple of the number we want but the largest factor of 154 is 77 because 77 * 2 = 154 but 77 is less than 79 hence it can not be a number thus 154 is the number we want a * b * c = 154 now factorize 154 = 1 * 2 * 7 * 11 all are prime also we know 1 < a < b < c thus a = 2 and c = 11 therefore a + c = 2 + 11 = 13 answer : c | general |
math_qa__w62yVa52Cg0yXOYv | Each of the 20 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and the average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the average weight of the boxes in the shipment is to be reduced to 15 pounds by removing some of the 20-pound boxes, how many 20-pound boxes must be removed? Answers:
A) 10
B) 12
C) 14
D) 16
E) 18 | <gadget id="calculator">20 * 20</gadget>
<output>400</output>
<gadget id="calculator">20 * 18</gadget>
<output>360</output>
<gadget id="calculator">400 - 360</gadget>
<output>40</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">40 / 10</gadget>
<output>4</output>
<gadget id="calculator">10 * 4</gadget>
<output>40</output>
<gadget id="calculator">20 - 4</gadget>
<output>16</output>
<gadget id="calculator">20 * 16</gadget>
<output>320</output>
<gadget id="calculator">40 + 320</gadget>
<output>360</output>
<gadget id="calculator">20 * 15</gadget>
<output>300</output>
<gadget id="calculator">360 - 300</gadget>
<output>60</output>
<gadget id="calculator">20 - 15</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<result>B</result> | B | 12 | Each of the 20 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and the average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the average weight of the boxes in the shipment is to be reduced to 15 pounds by removing some of the 20-pound boxes, how many 20-pound boxes must be removed? | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | divide(subtract(add(multiply(10, divide(subtract(multiply(20, 20), multiply(20, 18)), subtract(20, 10))), multiply(20, subtract(20, divide(subtract(multiply(20, 20), multiply(20, 18)), subtract(20, 10))))), multiply(20, 15)), subtract(20, 15)) | multiply(n0,n2)|multiply(n0,n3)|multiply(n0,n4)|subtract(n2,n1)|subtract(n2,n4)|subtract(#0,#1)|divide(#5,#3)|multiply(n1,#6)|subtract(n0,#6)|multiply(n2,#8)|add(#7,#9)|subtract(#10,#2)|divide(#11,#4)| | "if the average of 10 - pound and 20 - pound boxes is 18 , the ratio of 10 - pound boxes : 20 - pound boxes is 1 : 4 . so out of 20 boxes , 4 are 10 - pound boxes and 16 are 20 - pound boxes . if the average of 10 and 20 - pound boxes is to be 15 , the ratio of 10 - pound boxes : 20 - pound boxes should be 1 : 1 . the number of 10 pound boxes remains the same so we still have 4 of them . to get a ratio of 1 : 1 , the number of 20 - pound boxes must be 4 . we need to remove 12 of the 20 - pound boxes . the answer is b ." | general |
math_qa__SJn1oST3OgXNsqJX | The monthly rent of a shop of dimension 18feet × 20feet is Rs.3600. What is the annual rent per square foot of the shop? Choose the correct choice from the following answers:
A) 120 B) 56 C) 68 D) 87 E) 92 | <gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">18 * 20</gadget>
<output>360</output>
<gadget id="calculator">3_600 / 360</gadget>
<output>10</output>
<gadget id="calculator">12 * 10</gadget>
<output>120</output>
<result>A</result> | A | 120 | The monthly rent of a shop of dimension 18feet × 20feet is Rs.3600. What is the annual rent per square foot of the shop? | {
"A": "120",
"B": "56",
"C": "68",
"D": "87",
"E": "92"
} | multiply(add(const_10, const_2), divide(3600, rectangle_area(18, 20))) | add(const_10,const_2)|rectangle_area(n0,n1)|divide(n2,#1)|multiply(#0,#2)| | "sol . monthly rent per square feet = 3600 / ( 18 * 20 ) = 10 & annual rent per square feet = 12 * 10 = 120 answer : a" | geometry |
math_qa__pbIHvSmT4G0vc5P1 | A van takes 6 hours to cover a distance of 378 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? Answers:
A) 50 kmph B) 60 kmph C) 70 kmph D) 42 kmph E) 90 kmph | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 6</gadget>
<output>9</output>
<gadget id="calculator">378 / 9</gadget>
<output>42</output>
<result>D</result> | D | 42 | A van takes 6 hours to cover a distance of 378 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "50 kmph",
"B": "60 kmph",
"C": "70 kmph",
"D": "42 kmph",
"E": "90 kmph"
} | divide(378, multiply(divide(3, 2), 6)) | divide(n2,n3)|multiply(n0,#0)|divide(n1,#1)| | "time = 6 distence = 378 3 / 2 of 6 hours = 6 * 3 / 2 = 9 hours required speed = 378 / 9 = 42 kmph d" | physics |
math_qa__kF7ClNeBuEULHvej | Country X taxes each of its citizens an amount equal to 14 percent of the first $40,000 of income, plus 20 percent of all income in excess of $40,000. If a citizen of Country X is taxed a total of $8,000, what is her income? Choose the correct answer.
A) $ 40,000 B) $ 52,000 C) $ 64,000 D) $ 66,667 E) $ 80,000 | <gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">40 * 1_000</gadget>
<output>40_000</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 1_000</gadget>
<output>8_000</output>
<gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">(7/50) * 40_000</gadget>
<output>5_600</output>
<gadget id="calculator">8_000 - 5_600</gadget>
<output>2_400</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">2_400 / (1/5)</gadget>
<output>12_000</output>
<gadget id="calculator">40_000 + 12_000</gadget>
<output>52_000</output>
<result>B</result> | B | 52,000 | Country X taxes each of its citizens an amount equal to 14 percent of the first $40,000 of income, plus 20 percent of all income in excess of $40,000. If a citizen of Country X is taxed a total of $8,000, what is her income? | {
"A": "$ 40,000",
"B": "$ 52,000",
"C": "$ 64,000",
"D": "$ 66,667",
"E": "$ 80,000"
} | add(multiply(multiply(const_4, const_10), const_1000), divide(subtract(multiply(multiply(const_4, const_2), const_1000), multiply(divide(14, const_100), multiply(multiply(const_4, const_10), const_1000))), divide(20, const_100))) | divide(n0,const_100)|divide(n2,const_100)|multiply(const_2,const_4)|multiply(const_10,const_4)|multiply(#2,const_1000)|multiply(#3,const_1000)|multiply(#0,#5)|subtract(#4,#6)|divide(#7,#1)|add(#8,#5)| | "equation is correct , so math must be a problem . 0.14 * 40,000 + 0.2 * ( x - 40,000 ) = 8,000 - - > 5,600 + 0.2 x - 8,000 = 8,000 - - > 0.2 x = 10,400 - - > x = 52,000 . answer : b ." | general |
math_qa__NL5Nei5sYVN4cfAG | A shopkeeper sold an article offering a discount of 5% and earned a profit of 18.75%. What would have been the percentage of profit earned if no discount was offered?
Pick
A) 60 % B) 23 % C) 25 % D) 56 % E) 73 % | <gadget id="calculator">100 + 18.75</gadget>
<output>118.75</output>
<gadget id="calculator">118.75 * 100</gadget>
<output>11_875</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">11_875 / 95</gadget>
<output>125</output>
<gadget id="calculator">125 - 100</gadget>
<output>25</output>
<result>C</result> | C | 25 | A shopkeeper sold an article offering a discount of 5% and earned a profit of 18.75%. What would have been the percentage of profit earned if no discount was offered? | {
"A": "60 %",
"B": "23 %",
"C": "25 %",
"D": "56 %",
"E": "73 %"
} | subtract(divide(multiply(add(const_100, 18.75), const_100), subtract(const_100, 5)), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,const_100)|divide(#2,#1)|subtract(#3,const_100)| | "let c . p . be rs . 100 . then , s . p . = rs . 118.75 let marked price be rs . x . then , 95 / 100 x = 118.75 x = 11875 / 95 = rs . 125 now , s . p . = rs . 125 , c . p . = rs . 100 profit % = 25 % . answer : c" | gain |
math_qa__eGmgX98xzf9lPHDj | A tank holds x gallons of a saltwater solution that is 20% salt by volume. One Fourth of the water is evaporated, leaving all of the salt. When 8 Gallons of water and 16 gallons of salt are added, the resulting mixture is 33 1/3 % salt by volume. What is the value of x?
Choose the correct choice from the following.
A) 120
B) 75
C) 100
D) 150
E) 175 | <gadget id="calculator">16 * 2</gadget>
<output>32</output>
<gadget id="calculator">32 - 8</gadget>
<output>24</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(4/5) * (1/4)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(4/5) - (1/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">2 * (1/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/5) - (2/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">24 / (1/5)</gadget>
<output>120</output>
<result>A</result> | A | 120 | A tank holds x gallons of a saltwater solution that is 20% salt by volume. One Fourth of the water is evaporated, leaving all of the salt. When 8 Gallons of water and 16 gallons of salt are added, the resulting mixture is 33 1/3 % salt by volume. What is the value of x? | {
"A": "120",
"B": "75",
"C": "100",
"D": "150",
"E": "175"
} | divide(subtract(multiply(16, const_2), 8), subtract(subtract(subtract(1, divide(20, const_100)), multiply(subtract(1, divide(20, const_100)), divide(1, const_4))), multiply(const_2, divide(20, const_100)))) | divide(n0,const_100)|divide(n4,const_4)|multiply(n2,const_2)|multiply(#0,const_2)|subtract(#2,n1)|subtract(n4,#0)|multiply(#1,#5)|subtract(#5,#6)|subtract(#7,#3)|divide(#4,#8)| | "nope , 150 . i can only get it by following pr ' s backsolving explanation . i hate that . original mixture has 20 % salt and 80 % water . total = x out of which salt = 0.2 x and water = 0.8 x now , 1 / 4 water evaporates and all salt remains . so what remains is 0.2 x salt and 0.6 x water . now 16 gallons salt is added and 8 gallons of water is added . so salt now becomes - > ( 0.2 x + 16 ) and water - - > ( 0.6 x + 8 ) amount of salt is 33.33 % of total . so amount of water is 66.66 % . so salt is half of the volume of water . so ( 0.2 x + 16 ) = ( 0.6 x + 8 ) / 2 = > 0.2 x = 24 solving , x = 120 answer : a" | general |
math_qa__JTP483UyF21Wrhd8 | Rs. 6000 is lent out in two parts. One part is lent at 7% p.a simple interest and the other is lent at 8% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest?
Choose the correct choice from the following choices.
A) 5 : 1 B) 5 : 5 C) 5 : 8 D) 5 : 4 E) 5 : 2 | <gadget id="calculator">450 * 100</gadget>
<output>45_000</output>
<gadget id="calculator">6_000 * 7</gadget>
<output>42_000</output>
<gadget id="calculator">45_000 - 42_000</gadget>
<output>3_000</output>
<gadget id="calculator">8 - 7</gadget>
<output>1</output>
<gadget id="calculator">3_000 / 1</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 3_000</gadget>
<output>1</output>
<result>B</result> | B | 1 | Rs. 6000 is lent out in two parts. One part is lent at 7% p.a simple interest and the other is lent at 8% p.a simple interest. The total interest at the end of one year was Rs. 450. Find the ratio of the amounts lent at the lower rate and higher rate of interest? | {
"A": "5 : 1",
"B": "5 : 5",
"C": "5 : 8",
"D": "5 : 4",
"E": "5 : 2"
} | divide(divide(subtract(multiply(450, const_100), multiply(6000, 7)), subtract(8, 7)), divide(subtract(multiply(450, const_100), multiply(6000, 7)), subtract(8, 7))) | multiply(n3,const_100)|multiply(n0,n1)|subtract(n2,n1)|subtract(#0,#1)|divide(#3,#2)|divide(#4,#4)| | "let the amount lent at 7 % be rs . x amount lent at 8 % is rs . ( 6000 - x ) total interest for one year on the two sums lent = 7 / 100 x + 8 / 100 ( 6000 - x ) = 480 - x / 100 = > 480 - 1 / 100 x = 450 = > x = 3000 amount lent at 10 % = 3000 required ratio = 3000 : 3000 = 5 : 5 answer : b" | gain |
math_qa__eFwTPBT16enDhnCR | We invested a total of $1,000. We invested one part of the money at 4% and the rest of the money at 6%. The total investment with interest at the end of the year was $1,046. How much money did we invest at 4%?
Choose the correct choice
A) $ 600 B) $ 650 C) $ 700 D) $ 750 E) $ 800 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) + 1</gadget>
<output>53/50 = around 1.06</output>
<gadget id="calculator">1_000 * (53/50)</gadget>
<output>1_060</output>
<gadget id="calculator">10 * 4</gadget>
<output>40</output>
<gadget id="calculator">1_000 + 40</gadget>
<output>1_040</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">1_040 + 6</gadget>
<output>1_046</output>
<gadget id="calculator">1_060 - 1_046</gadget>
<output>14</output>
<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) + 1</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(53/50) - (26/25)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">14 / (1/50)</gadget>
<output>700</output>
<result>C</result> | C | 700 | We invested a total of $1,000. We invested one part of the money at 4% and the rest of the money at 6%. The total investment with interest at the end of the year was $1,046. How much money did we invest at 4%? | {
"A": "$ 600",
"B": "$ 650",
"C": "$ 700",
"D": "$ 750",
"E": "$ 800"
} | divide(subtract(multiply(multiply(const_100, multiply(add(const_2, const_3), const_2)), add(divide(6, const_100), const_1)), add(add(multiply(const_100, multiply(add(const_2, const_3), const_2)), multiply(multiply(add(const_2, const_3), const_2), const_4)), multiply(const_2, const_3))), subtract(add(divide(6, const_100), const_1), add(divide(4, const_100), const_1))) | add(const_2,const_3)|divide(n2,const_100)|divide(n1,const_100)|multiply(const_2,const_3)|add(#1,const_1)|add(#2,const_1)|multiply(#0,const_2)|multiply(#6,const_100)|multiply(#6,const_4)|subtract(#4,#5)|add(#7,#8)|multiply(#4,#7)|add(#10,#3)|subtract(#11,#12)|divide(#13,#9) | let x be the money invested at 4 % . 1.04 x + 1.06 ( 1000 - x ) = 1046 . 0.02 x = 1060 - 1046 . 0.02 x = 14 . 2 x = 1400 . x = 700 . the answer is c . | gain |
math_qa__QhDk8VAjjQDwKayk | The volume of a box with a square base is 128 cubic cm. The area of the base of the box is 8 inches more than the height. What is the length of the base of the box? Choose one.
A) 4 cm B) 8 cm C) 16 cm D) 24 cm E) none of the above | <gadget id="calculator">4 * 128</gadget>
<output>512</output>
<gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">512 + 64</gadget>
<output>576</output>
<gadget id="calculator">576 ** (1/2)</gadget>
<output>24</output>
<gadget id="calculator">8 + 24</gadget>
<output>32</output>
<gadget id="calculator">32 / 2</gadget>
<output>16</output>
<gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<result>A</result> | A | 4 | The volume of a box with a square base is 128 cubic cm. The area of the base of the box is 8 inches more than the height. What is the length of the base of the box? | {
"A": "4 cm",
"B": "8 cm",
"C": "16 cm",
"D": "24 cm",
"E": "none of the above"
} | sqrt(divide(add(8, sqrt(add(multiply(const_4, 128), power(8, const_2)))), const_2)) | multiply(n0,const_4)|power(n1,const_2)|add(#0,#1)|sqrt(#2)|add(n1,#3)|divide(#4,const_2)|sqrt(#5) | l x w x h = 64 l x w - 8 = h l = w solving the 3 equations we get area of base = 16 square cm and height = 8 cm , which means length = 4 cm and width = 4 cm correct answer : a | geometry |
math_qa__UptBumoMoam7AhIG | Subtracting 6% of A from A is equivalent to multiplying A by how much ?
Choose the correct choice from the following answers
A) 0.94 B) 9.4 C) 0.094 D) 94 E) none | <gadget id="calculator">100 - 6</gadget>
<output>94</output>
<gadget id="calculator">94 / 100</gadget>
<output>47/50 = around 0.94</output>
<result>A</result> | A | 0.94 | Subtracting 6% of A from A is equivalent to multiplying A by how much ? | {
"A": "0.94",
"B": "9.4",
"C": "0.094",
"D": "94",
"E": "none"
} | divide(subtract(const_100, 6), const_100) | subtract(const_100,n0)|divide(#0,const_100)| | "answer let a - 6 % of a = ab . ⇒ ( 94 x a ) / 100 = ab ∴ b = 0.94 correct option : a" | general |
math_qa__7MhVB61xvbruOCcr | In 140 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by: Choose the correct choice from the following options
A) 20 m B) 28 m C) 22.5 m D) 9 m E) 12 m | <gadget id="calculator">140 / 45</gadget>
<output>28/9 = around 3.111111</output>
<gadget id="calculator">45 - 36</gadget>
<output>9</output>
<gadget id="calculator">(28/9) * 9</gadget>
<output>28</output>
<result>B</result> | B | 28 | In 140 m race, A covers the distance in 36 seconds and B in 45 seconds. In this race A beats B by: | {
"A": "20 m",
"B": "28 m",
"C": "22.5 m",
"D": "9 m",
"E": "12 m"
} | multiply(divide(140, 45), subtract(45, 36)) | divide(n0,n2)|subtract(n2,n1)|multiply(#0,#1)| | "distance covered by b in 9 sec . = 140 / 45 x 9 m = 28 m . a beats b by 28 metres . answer : option b" | physics |
math_qa__vmF8n4JMaeZXeBLt | The visitors of a modern art museum who watched a certain Picasso painting were asked to fill in a short questionnaire indicating whether they had enjoyed looking at the picture and whether they felt they had understood it. According to the results of the survey, all 140 visitors who did not enjoy the painting also did not feel they had understood the painting, and the number of visitors who enjoyed the painting was equal to the number of visitors who felt they had understood the painting. If 3/4 of the visitors who answered the questionnaire both enjoyed the painting and felt they had understood the painting, then how many visitors answered the questionnaire? Choices.
A) 90 B) 120 C) 160 D) 360 E) 560 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">140 / (1/4)</gadget>
<output>560</output>
<result>E</result> | E | 560 | The visitors of a modern art museum who watched a certain Picasso painting were asked to fill in a short questionnaire indicating whether they had enjoyed looking at the picture and whether they felt they had understood it. According to the results of the survey, all 140 visitors who did not enjoy the painting also did not feel they had understood the painting, and the number of visitors who enjoyed the painting was equal to the number of visitors who felt they had understood the painting. If 3/4 of the visitors who answered the questionnaire both enjoyed the painting and felt they had understood the painting, then how many visitors answered the questionnaire? | {
"A": "90",
"B": "120",
"C": "160",
"D": "360",
"E": "560"
} | divide(140, subtract(const_1, divide(3, 4))) | divide(n1,n2)|subtract(const_1,#0)|divide(n0,#1)| | "if we exclude those cases and take the question at face value , then it seems straightforward . group # 1 = ( did n ' t like , did n ' t understand ) = 120 group # 2 = ( likeunderstood ) = 3 / 4 ( 1 / 4 ) n = 560 n = 480 answer = ( e )" | general |
math_qa__HsFwUegdF4u7ETj4 | The average monthly salary of 8 workers and one supervisor in a factory was 430.@SSWhen@SSthe@SSsupervisor@CC@SSwhose@SSsalary@SSwas@SS430.@SSWhen@SSthe@SSsupervisor@CC@SSwhose@SSsalary@SSwas@SS430.Whenthesupervisor,whosesalarywas430. When the supervisor, whose salary was 870 per month, retired, a new person was appointed and then the average salary of 9 people was $$430 per month. The salary of the new supervisor is: Choose the correct option.
A) 870 B) 600 C) 287 D) 771 E) 191 | <gadget id="calculator">430 * 9</gadget>
<output>3_870</output>
<gadget id="calculator">3_870 - 870</gadget>
<output>3_000</output>
<gadget id="calculator">3_870 - 3_000</gadget>
<output>870</output>
<result>A</result> | A | 870 | The average monthly salary of 8 workers and one supervisor in a factory was 430.@SSWhen@SSthe@SSsupervisor@CC@SSwhose@SSsalary@SSwas@SS430.@SSWhen@SSthe@SSsupervisor@CC@SSwhose@SSsalary@SSwas@SS430.Whenthesupervisor,whosesalarywas430. When the supervisor, whose salary was 870 per month, retired, a new person was appointed and then the average salary of 9 people was $$430 per month. The salary of the new supervisor is: | {
"A": "870",
"B": "600",
"C": "287",
"D": "771",
"E": "191"
} | subtract(multiply(430, 9), subtract(multiply(430, 9), 870)) | multiply(n6,n7)|multiply(n1,n6)|subtract(#1,n5)|subtract(#0,#2)| | "explanation : total salary of 8 workers and supervisor together = 9 ã — 430 = 3870 now total salary of 8 workers = 3870 â ˆ ’ 870 = 3000 total salary of 9 workers including the new supervisor = 9 ã — 430 = 3870 salary of the new supervisor = 3870 â ˆ ’ 3000 = 870 answer : a" | general |
math_qa__2k1OAfBd2H8T7a99 | 3 men and 2 women are lined up in a row. What is the number of cases where they stand with each other in turn? (The number of cases in which men (or women) do not stand next to each other) Options:
A) 12
B) 15
C) 18
D) 21
E) 24 | <gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<result>A</result> | A | 12 | 3 men and 2 women are lined up in a row. What is the number of cases where they stand with each other in turn? (The number of cases in which men (or women) do not stand next to each other) | {
"A": "12",
"B": "15",
"C": "18",
"D": "21",
"E": "24"
} | multiply(factorial(3), factorial(2)) | factorial(n0)|factorial(n1)|multiply(#0,#1) | the list should be wmwmw . hence , from women 2 ! and men 3 ! , we get ( 2 ! ) ( 3 ! ) = 12 . therefore , the correct answer is a . | general |
math_qa__5N6NAeb8vYGJTXaS | Darcy lives 1.5 miles from work. She can walk to work at a constant rate of 3 miles per hour, or she can ride the train to work at a constant rate of 20 miles per hour. If she rides the train, there is an additional x minutes spent walking to the nearest train station, waiting for the train, and walking from the final train station to her work. If it takes Darcy a total of 25 more minutes to commute to work by walking than it takes her to commute to work by riding the train, what is the value of x? Answers: A) 10.5 B) 0.5 C) 25.5 D) 30 E) 60 | <gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 - 25</gadget>
<output>5</output>
<gadget id="calculator">20 / 1.5</gadget>
<output>13.333333</output>
<gadget id="calculator">60 / 13.333333</gadget>
<output>4.5</output>
<gadget id="calculator">5 - 4.5</gadget>
<output>0.5</output>
<result>B</result> | B | 0.5 | Darcy lives 1.5 miles from work. She can walk to work at a constant rate of 3 miles per hour, or she can ride the train to work at a constant rate of 20 miles per hour. If she rides the train, there is an additional x minutes spent walking to the nearest train station, waiting for the train, and walking from the final train station to her work. If it takes Darcy a total of 25 more minutes to commute to work by walking than it takes her to commute to work by riding the train, what is the value of x? | {
"A": "10.5",
"B": "0.5",
"C": "25.5",
"D": "30",
"E": "60"
} | subtract(subtract(divide(const_60, const_2), 25), divide(const_60, divide(20, 1.5))) | divide(const_60,const_2)|divide(n2,n0)|divide(const_60,#1)|subtract(#0,n3)|subtract(#3,#2)| | "the time it takes darcy to walk to work is ( 1.5 / 3 ) * 60 = 30 minutes the time it takes darcy to take the train is ( 1.5 / 20 ) * 60 + x = 4.5 + x minutes it takes 15 minutes longer to walk , so 30 = 4.5 + x + 25 x = 0.5 minutes answer : b" | physics |
math_qa__5moRxrzQgv4jm3LV | If 5^21 x 8^7 = 10^n what is the value of n? Choose the correct answer.
A) 26 B) 24 C) 21 D) 28 E) 20 | <gadget id="calculator">8 ** 7</gadget>
<output>2_097_152</output>
<gadget id="calculator">5 ** 21</gadget>
<output>476_837_158_203_125</output>
<gadget id="calculator">2_097_152 * 476_837_158_203_125</gadget>
<output>1_000_000_000_000_000_000_000</output>
<gadget id="calculator">log(1_000_000_000_000_000_000_000)</gadget>
<output>log(1000000000000000000000) = around 48.354287</output>
<gadget id="calculator">log(10)</gadget>
<output>log(10) = around 2.302585</output>
<gadget id="calculator">log(1000000000000000000000) / log(10)</gadget>
<output>log(1000000000000000000000)/log(10) = around 21</output>
<result>C</result> | C | 21 | If 5^21 x 8^7 = 10^n what is the value of n? | {
"A": "26",
"B": "24",
"C": "21",
"D": "28",
"E": "20"
} | divide(log(multiply(power(8, 7), power(5, 21))), log(const_10)) | log(const_10)|power(n2,n3)|power(n0,n1)|multiply(#1,#2)|log(#3)|divide(#4,#0) | 5 ^ 21 * ( 2 ^ 3 ) ^ 7 = 10 ^ n or 5 ^ 21 * 2 ^ 21 = 10 ^ n or 10 ^ 21 = 10 ^ n n = 21 c | general |
math_qa__spebA6Vvc9mefSF6 | The wages of 24 men and 16 women amounts to Rs.11600 per day. Half the number of men and 37 women earn the same amount per day. What is the daily wage of a man? Choose the correct choice from the following answers.
A) 2378 B) 277 C) 208 D) 270 E) 350 | <gadget id="calculator">11_600 * 2</gadget>
<output>23_200</output>
<gadget id="calculator">23_200 - 11_600</gadget>
<output>11_600</output>
<gadget id="calculator">37 * 2</gadget>
<output>74</output>
<gadget id="calculator">74 - 16</gadget>
<output>58</output>
<gadget id="calculator">11_600 / 58</gadget>
<output>200</output>
<gadget id="calculator">16 * 200</gadget>
<output>3_200</output>
<gadget id="calculator">11_600 - 3_200</gadget>
<output>8_400</output>
<gadget id="calculator">8_400 / 24</gadget>
<output>350</output>
<result>E</result> | E | 350 | The wages of 24 men and 16 women amounts to Rs.11600 per day. Half the number of men and 37 women earn the same amount per day. What is the daily wage of a man? | {
"A": "2378",
"B": "277",
"C": "208",
"D": "270",
"E": "350"
} | divide(subtract(11600, multiply(16, divide(subtract(multiply(11600, const_2), 11600), subtract(multiply(37, const_2), 16)))), 24) | multiply(n2,const_2)|multiply(n3,const_2)|subtract(#0,n2)|subtract(#1,n1)|divide(#2,#3)|multiply(n1,#4)|subtract(n2,#5)|divide(#6,n0) | let the wage of a man is m and woman be w . 24 m + 16 w = 11600 12 m + 37 w = 11600 solving we get m = 350 answer : e | physics |
math_qa__8oMGkZj7bfA4fp5l | Find the expenditure on digging a well 14m deep and of 3m diameter at Rs.18 per cubic meter? Options:
A) 2998 B) 2799 C) 1782 D) 1485 E) 2780 | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">pi * ((3/2) ** 2) * 14</gadget>
<output>63*pi/2 = around 98.960169</output>
<gadget id="calculator">(63*pi/2) * 18</gadget>
<output>567*pi = around 1_781.283035</output>
<result>C</result> | C | 1,782 | Find the expenditure on digging a well 14m deep and of 3m diameter at Rs.18 per cubic meter? | {
"A": "2998",
"B": "2799",
"C": "1782",
"D": "1485",
"E": "2780"
} | multiply(volume_cylinder(divide(3, const_2), 14), 18) | divide(n1,const_2)|volume_cylinder(#0,n0)|multiply(n2,#1) | 22 / 7 * 14 * 3 / 2 * 3 / 2 = 99 m 2 99 * 18 = 1782 answer : c | physics |
math_qa__KbIAO2xFVYj4Hz8V | The ratio of the ages of Mini and Minakshi is 4 : 3. The sum of their ages is 14 years. The ratio of their ages after 8 years will be Choose the most appropriate option:
A) 5 : 3
B) 8 : 11
C) 8 : 7
D) 6 : 5
E) 3 : 11 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">14 / 7</gadget>
<output>2</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 8</gadget>
<output>16</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 8</gadget>
<output>14</output>
<gadget id="calculator">16 / 14</gadget>
<output>8/7 = around 1.142857</output>
<result>C</result> | C | 1.142857 | The ratio of the ages of Mini and Minakshi is 4 : 3. The sum of their ages is 14 years. The ratio of their ages after 8 years will be | {
"A": "5 : 3",
"B": "8 : 11",
"C": "8 : 7",
"D": "6 : 5",
"E": "3 : 11"
} | divide(add(multiply(4, divide(14, add(4, 3))), 8), add(multiply(3, divide(14, add(4, 3))), 8)) | add(n0,n1)|divide(n2,#0)|multiply(n0,#1)|multiply(n1,#1)|add(n3,#2)|add(n3,#3)|divide(#4,#5)| | "let mini ’ s age = 4 x and minakshi ’ s age = 3 x then 4 x + 3 x = 14 x = 2 mini ’ s age = 8 years and minakshi ’ s age = 6 years ratio of their ages after 8 years = ( 8 + 8 ) : ( 6 + 8 ) = 16 : 14 = 8 : 7 answer : c" | general |
math_qa__5tuGzy1gB1AGCkZS | The purchase price of an article is $48. In order to include 30% of cost for overhead and to provide $12 of net profit, the markup should be Choices:
A) 15 % B) 25 % C) 35 % D) 40 % E) 55 % | <gadget id="calculator">12 / 48</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<gadget id="calculator">25 + 30</gadget>
<output>55</output>
<result>E</result> | E | 55 | The purchase price of an article is $48. In order to include 30% of cost for overhead and to provide $12 of net profit, the markup should be | {
"A": "15 %",
"B": "25 %",
"C": "35 %",
"D": "40 %",
"E": "55 %"
} | add(multiply(divide(12, 48), const_100), 30) | divide(n2,n0)|multiply(#0,const_100)|add(n1,#1)| | "cost price of article = 48 $ % of overhead cost = 30 net profit = 12 $ we need to calculate % markup net profit as % of cost price = ( 12 / 48 ) * 100 = 25 % total markup should be = 25 + 30 = 55 % answer e" | gain |
math_qa__SxnRGbeSFFJsrCbT | How many diagonals does a polygon with 23 sides have, if one of its vertices does not connect to any diagonal?
Choose the most appropriate option:
A) 201 B) 159 C) 179 D) 189 E) 209 | <gadget id="calculator">23 - 1</gadget>
<output>22</output>
<gadget id="calculator">22 - 3</gadget>
<output>19</output>
<gadget id="calculator">22 * 19</gadget>
<output>418</output>
<gadget id="calculator">418 / 2</gadget>
<output>209</output>
<result>E</result> | E | 209 | How many diagonals does a polygon with 23 sides have, if one of its vertices does not connect to any diagonal? | {
"A": "201",
"B": "159",
"C": "179",
"D": "189",
"E": "209"
} | divide(multiply(subtract(23, const_1), subtract(subtract(23, const_1), const_3)), const_2) | subtract(n0,const_1)|subtract(#0,const_3)|multiply(#0,#1)|divide(#2,const_2)| | "if i calculate it using the formulae , # diagonals = n ( n - 3 ) / 2 each vertex sends of n - 3 diagonals n = 23 - 1 then 22 * ( 22 - 3 ) / 2 = 209 correct option : e" | geometry |
math_qa__dH2pFdhUlpmmV3AR | Mary invested a certain sum of money in a bank that paid simple interest. The amount grew to $260 at the end of 2 years. She waited for another 3 years and got a final amount of $350. What was the principal amount that she invested at the beginning?
Choose the most appropriate option
A) $ 220 B) $ 230 C) $ 240 D) $ 200 E) $ 250 | <gadget id="calculator">350 - 260</gadget>
<output>90</output>
<gadget id="calculator">90 / 3</gadget>
<output>30</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">260 - 60</gadget>
<output>200</output>
<result>D</result> | D | 200 | Mary invested a certain sum of money in a bank that paid simple interest. The amount grew to $260 at the end of 2 years. She waited for another 3 years and got a final amount of $350. What was the principal amount that she invested at the beginning? | {
"A": "$ 220",
"B": "$ 230",
"C": "$ 240",
"D": "$ 200",
"E": "$ 250"
} | subtract(260, multiply(divide(subtract(350, 260), 3), 2)) | subtract(n3,n0)|divide(#0,n2)|multiply(n1,#1)|subtract(n0,#2) | what shall be the rate of interest . ? does that is not required for the calculation ? not really ! keep in mind that the interest earned each year will be the same in simple interest . at the end of 2 years , amount = $ 260 at the end of 5 years , amount = $ 350 this means she earned an interest of $ 90 in 3 years . or $ 30 in each year . we know that the interest earned each year will be the same . therefore she must have earned $ 60 in 2 years . hence principal amount = $ 260 - $ 60 = $ 200 option d | gain |
math_qa__HfwgkxVbtOwKXzYw | Heinz produces tomato puree by boiling tomato juice. The tomato puree has only 20% water while the tomato juice has 90% water. How many liters of tomato puree will be obtained from 50 litres of tomato juice? Choose the correct choice from the following: A) 2.8 liters . B) 2.5 liters . C) 8.5 liters . D) 6.25 liters . E) 2.1 liters . | <gadget id="calculator">100 - 90</gadget>
<output>10</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 50</gadget>
<output>5</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">5 / (4/5)</gadget>
<output>25/4 = around 6.25</output>
<result>D</result> | D | 6.25 | Heinz produces tomato puree by boiling tomato juice. The tomato puree has only 20% water while the tomato juice has 90% water. How many liters of tomato puree will be obtained from 50 litres of tomato juice? | {
"A": "2.8 liters .",
"B": "2.5 liters .",
"C": "8.5 liters .",
"D": "6.25 liters .",
"E": "2.1 liters ."
} | divide(multiply(divide(subtract(const_100, 90), const_100), 50), divide(subtract(const_100, 20), const_100)) | subtract(const_100,n1)|subtract(const_100,n0)|divide(#0,const_100)|divide(#1,const_100)|multiply(n2,#2)|divide(#4,#3)| | "answer : explanation : in each of the solutions , there is a pure tomato component and some water . so while boiling , water evaporates but tomato not . so we equate tomato part in the both equations . â ‡ ’ â ‡ ’ 10 % ( 50 ) = 80 % ( x ) â ‡ ’ â ‡ ’ x = 6.25 liters . answer : d" | gain |
math_qa__d51mfQSYFIqPavRq | Laxmi and Prasanna set on a journey. Laxmi moves northwards at a speed of 22 kmph and Prasanna moves southward at a speed of 24 kmph. How far will be Prasanna from Laxmi after 60 minutes ?
Pick.
A) 44 B) 50 C) 28 D) 27 E) 18 | <gadget id="calculator">22 + 24</gadget>
<output>46</output>
<result>A</result> | A | 44 | Laxmi and Prasanna set on a journey. Laxmi moves northwards at a speed of 22 kmph and Prasanna moves southward at a speed of 24 kmph. How far will be Prasanna from Laxmi after 60 minutes ? | {
"A": "44",
"B": "50",
"C": "28",
"D": "27",
"E": "18"
} | add(22, 24) | add(n0,n1)| | "explanation : we know 60 min = 1 hr total northward laxmi ' s distance = 22 kmph x 1 hr = 22 km total southward prasanna ' s distance = 24 kmph x 1 hr = 24 km total distance between prasanna and laxmi is = 22 + 24 = 44 km . answer : a" | physics |
math_qa__OASv1t9SmdckAVOd | A good train and a passenger train are running on parallel tracks in the same direction. The driver of the goods train observes that the passenger train coming from behind overtakes and crosses his train completely in 60 sec. Whereas a passenger on the passenger train marks that he crosses the goods train in 40 sec. If the speeds of the trains be in the ratio 1:2. Find the ratio of their lengths. Answers:
A) 2 : 1
B) 3 : 1
C) 5 : 2
D) 1 : 1
E) none of these | <gadget id="calculator">60 / 40</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / (1/2)</gadget>
<output>2</output>
<result>A</result> | A | 2 | A good train and a passenger train are running on parallel tracks in the same direction. The driver of the goods train observes that the passenger train coming from behind overtakes and crosses his train completely in 60 sec. Whereas a passenger on the passenger train marks that he crosses the goods train in 40 sec. If the speeds of the trains be in the ratio 1:2. Find the ratio of their lengths. | {
"A": "2 : 1",
"B": "3 : 1",
"C": "5 : 2",
"D": "1 : 1",
"E": "none of these"
} | divide(1, subtract(divide(60, 40), 1)) | divide(n0,n1)|subtract(#0,n2)|divide(n2,#1) | explanation : let , the speeds of the two trains be s and 2 s m / s respectively . also , suppose that the lengths of the two trains are p and q metres respectively . then , = > ( p + q ) / ( 2 s − s ) = 60 . - - - - - - - - - - - - - - ( 1 ) and , = > p / ( 2 s − s ) = 40 . - - - - - - - - - - - - - - ( 2 ) on dividing ( 1 ) by ( 2 ) , we get : - = > ( p + q ) / p = 60 / 40 . the required ratio is p : q = 2 : 1 . answer : a | physics |
math_qa__nc9rh2rjFjul4kY8 | A prize of $600 is to be distributed among 15 winners, each of whom must be awarded at least $15. If 2/5 of the prize will be distributed to 3/5 of the winners, what is the greatest possible individual award? Choose the correct option:
A) $ 200
B) $ 220
C) $ 285
D) $ 300
E) $ 360 | <gadget id="calculator">600 * 2</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 5</gadget>
<output>240</output>
<gadget id="calculator">600 - 240</gadget>
<output>360</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">45 / 5</gadget>
<output>9</output>
<gadget id="calculator">15 - 9</gadget>
<output>6</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 15</gadget>
<output>75</output>
<gadget id="calculator">360 - 75</gadget>
<output>285</output>
<result>C</result> | C | 285 | A prize of $600 is to be distributed among 15 winners, each of whom must be awarded at least $15. If 2/5 of the prize will be distributed to 3/5 of the winners, what is the greatest possible individual award? | {
"A": "$ 200",
"B": "$ 220",
"C": "$ 285",
"D": "$ 300",
"E": "$ 360"
} | subtract(subtract(600, divide(multiply(600, 2), 5)), multiply(subtract(subtract(15, divide(multiply(15, 3), 5)), const_1), 15)) | multiply(n0,n3)|multiply(n1,n5)|divide(#0,n4)|divide(#1,n4)|subtract(n0,#2)|subtract(n1,#3)|subtract(#5,const_1)|multiply(n1,#6)|subtract(#4,#7)| | "total value of the prize = $ 600 number of people = 15 2 / 5 of 600 ( = $ 240 ) should be distributed among 3 / 5 of 15 ( = 9 people ) with each getting $ 15 each . remaining money = 600 - 240 = $ 360 . now in order to ' maximize ' 1 prize , we need to minimise the others and we have been given that each should get $ 15 . thus , minimising the remaining 5 people ( = 15 - 9 - 1 . ' - 1 ' to exclude 1 that needs to be maximised ) = 5 * 15 = 75 . thus the maximum award can be = 360 - 75 = $ 285 , hence c is the correct answer ." | general |
math_qa__7Emk76Ue0m7jpd6p | Evaluate (51 + 52 + 53 + ... + 100) Select
A) 3775 B) 3665 C) 3456 D) 3459 E) 3569 | <gadget id="calculator">100 + 51</gadget>
<output>151</output>
<gadget id="calculator">151 / 2</gadget>
<output>151/2 = around 75.5</output>
<gadget id="calculator">51 - 1</gadget>
<output>50</output>
<gadget id="calculator">(151/2) * 50</gadget>
<output>3_775</output>
<result>A</result> | A | 3,775 | Evaluate (51 + 52 + 53 + ... + 100) | {
"A": "3775",
"B": "3665",
"C": "3456",
"D": "3459",
"E": "3569"
} | multiply(divide(add(100, 51), const_2), subtract(51, const_1)) | add(n0,n3)|subtract(n0,const_1)|divide(#0,const_2)|multiply(#2,#1) | sn = ( 1 + 2 + 3 + . . . + 50 + 51 + 52 + . . . + 100 ) - ( 1 + 2 + 3 + . . . + 50 ) = ( 50 x 101 ) - ( 25 x 51 ) = ( 5050 - 1275 ) = 3775 . option a | general |
math_qa__U6ZEkJBjyAKtwDdy | 90 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors? Choose the correct choice from the following answers.
A) 18 B) 16 C) 12 D) 10 E) 6 | <gadget id="calculator">38 + 1</gadget>
<output>39</output>
<gadget id="calculator">39 + 45</gadget>
<output>84</output>
<gadget id="calculator">90 - 84</gadget>
<output>6</output>
<result>E</result> | E | 6 | 90 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors? | {
"A": "18",
"B": "16",
"C": "12",
"D": "10",
"E": "6"
} | subtract(90, add(add(38, const_1), 45)) | add(n2,const_1)|add(n1,#0)|subtract(n0,#1) | { total } = { writers } + { editors } - { both } + { neither } . { total } = 90 ; { writers } = 45 ; { editors } > 38 ; { both } = x ; { neither } = 2 x ; 90 = 45 + { editors } - x + 2 x - - > x = 45 - { editors } . we want to maximize x , thus we should minimize { editors } , minimum possible value of { editors } is 39 , thus x = { both } = 45 - 39 = 6 . answer : e . | other |
math_qa__Vr3nvuGpTtmQARqC | In an examination, 34% of total students failed in Hindi, 44% failed in English and 22% in both. The percentage of these who passed in both the subjects is : Choose the correct choice.
A) 23 B) 37 C) 28 D) 44 E) 81 | <gadget id="calculator">34 + 44</gadget>
<output>78</output>
<gadget id="calculator">78 - 22</gadget>
<output>56</output>
<gadget id="calculator">100 - 56</gadget>
<output>44</output>
<result>D</result> | D | 44 | In an examination, 34% of total students failed in Hindi, 44% failed in English and 22% in both. The percentage of these who passed in both the subjects is : | {
"A": "23",
"B": "37",
"C": "28",
"D": "44",
"E": "81"
} | subtract(const_100, subtract(add(34, 44), 22)) | add(n0,n1)|subtract(#0,n2)|subtract(const_100,#1) | explanation : formula n ( a â ˆ ª b ) = n ( a ) + n ( b ) â ˆ ’ n ( a â ˆ © b ) fail in hindi or english = 34 + 44 â € “ 22 = 56 therefore students who passed = 100 â € “ 56 = 44 . answer : d | general |
math_qa__83yAndZ9gW1B1RyF | Nicky and Cristina are running a 500 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him? Options.
A) 50 B) 45 C) 40 D) 35 E) 30 | <gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">36 / 3</gadget>
<output>12</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">12 + 18</gadget>
<output>30</output>
<result>E</result> | E | 30 | Nicky and Cristina are running a 500 meter race. Since Cristina is faster than Nicky, she gives him a 12 second head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him? | {
"A": "50",
"B": "45",
"C": "40",
"D": "35",
"E": "30"
} | add(divide(multiply(3, 12), 3), divide(multiply(3, 12), subtract(5, 3))) | multiply(n1,n3)|subtract(n2,n3)|divide(#0,n3)|divide(#0,#1)|add(#2,#3)| | "the distance traveled by both of them is the same at the time of overtaking . 3 ( t + 12 ) = 5 t t = 18 . cristina will catch up nicky in 18 seconds . so in 18 seconds cristina would cover = 18 * 5 = 90 meter . now time taken my nicky to cover 90 meter = 90 / 3 = 30 seconds . e" | physics |
math_qa__KLbuJf44zdzbCUpo | In 1990 the budgets for projects Q and V were $540,000 and $780,000, respectively. In each of the next 10 years, the budget for Q was increased by $30,000 and the budget for V was decreased by $10,000. In which year was the budget for Q equal to the budget for V ? Pick one: A) 1992 B) 1993 C) 1994 D) 1995 E) 1996 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">10 * 6</gadget>
<output>60</output>
<gadget id="calculator">1_990 + 60</gadget>
<output>2_050</output>
<result>E</result> | E | 1,996 | In 1990 the budgets for projects Q and V were $540,000 and $780,000, respectively. In each of the next 10 years, the budget for Q was increased by $30,000 and the budget for V was decreased by $10,000. In which year was the budget for Q equal to the budget for V ? | {
"A": "1992",
"B": "1993",
"C": "1994",
"D": "1995",
"E": "1996"
} | add(1990, multiply(10, multiply(const_2, const_3))) | multiply(const_2,const_3)|multiply(n3,#0)|add(n0,#1) | let the no of years it takes is x . 540 + 30 x = 780 - 10 x - - > 40 x = 240 and x = 6 . thus , it happens in 1996 . e . | general |
math_qa__mparhZn2WuGvJAD0 | Youseff lives x blocks from his office. It takes him 1 minute per block to walk to work and 20 seconds per block to ride his bike to work. It is takes him exactly 12 minutes more to walk to work than to ride his bike to work, then x equals? Choose the correct choice from the following choices.
A) 4 B) 7 C) 10 D) 15 E) 18 | <gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<result>E</result> | E | 18 | Youseff lives x blocks from his office. It takes him 1 minute per block to walk to work and 20 seconds per block to ride his bike to work. It is takes him exactly 12 minutes more to walk to work than to ride his bike to work, then x equals? | {
"A": "4",
"B": "7",
"C": "10",
"D": "15",
"E": "18"
} | divide(multiply(12, const_3), const_2) | multiply(n2,const_3)|divide(#0,const_2)| | "please follow posting guidelines , link is in my signatures . as for your question , x / 60 = blocks / time / block = block ^ 2 / time . this is not what you want . you are given x blocks and 60 seconds per block . thus you need to put it as 60 * x to give you units of seconds as you are equating this to 720 ( which is time in seconds . ) . thus the correct equation is : 60 * x - 20 * x = 7200 - - - - > 40 x = 720 - - > x = 18 . option e" | physics |
math_qa__lF1sVHh9upXBvhwO | A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1400. The difference between the profit shares of A and C is? Choose the correct choice from the following answers: A) 288 B) 560 C) 155 D) 600 E) 441 | <gadget id="calculator">12_000 / 10_000</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">8_000 / 10_000</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(6/5) - (4/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 1_400</gadget>
<output>560</output>
<result>B</result> | B | 560 | A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 1400. The difference between the profit shares of A and C is? | {
"A": "288",
"B": "560",
"C": "155",
"D": "600",
"E": "441"
} | multiply(subtract(divide(12000, 10000), divide(8000, 10000)), 1400) | divide(n2,n1)|divide(n0,n1)|subtract(#0,#1)|multiply(n3,#2)| | "ratio of investments of a , b and c is 8000 : 10000 : 12000 = 4 : 5 : 6 and also given that , profit share of b is rs . 1400 = > 5 parts out of 15 parts is rs . 1400 now , required difference is 6 - 4 = 2 parts required difference = 2 / 5 ( 1400 ) = rs . 560 answer : b" | gain |
math_qa__Mz1D7xqhKqHxChA2 | Of all the students in a certain dormitory, 1/2 are first-year students and the rest are second-year students. If 4/5 of the first-year students have not declared a major and if the fraction of second-year students who have declared a major is 1/3 times the fraction of first-year students who have declared a major, what fraction of all the students in the dormitory are second-year students who have not declared a major? Choices
A) 7 / 15 B) 1 / 5 C) 4 / 15 D) 1 / 3 E) 2 / 5 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(1/2) - (1/30)</gadget>
<output>7/15 = around 0.466667</output>
<result>A</result> | A | 0.466667 | Of all the students in a certain dormitory, 1/2 are first-year students and the rest are second-year students. If 4/5 of the first-year students have not declared a major and if the fraction of second-year students who have declared a major is 1/3 times the fraction of first-year students who have declared a major, what fraction of all the students in the dormitory are second-year students who have not declared a major? | {
"A": "7 / 15",
"B": "1 / 5",
"C": "4 / 15",
"D": "1 / 3",
"E": "2 / 5"
} | subtract(divide(1, 2), divide(const_1, multiply(3, const_10))) | divide(n0,n1)|multiply(n5,const_10)|divide(const_1,#1)|subtract(#0,#2) | tot students = x 1 st year student = x / 2 - - - - > non majaor = 4 / 5 ( x / 2 ) - - - - - > maj = 1 / 5 ( x / 2 ) 2 nd year student = x / 2 - - - - > maj = 1 / 3 ( 1 / 5 ( x / 2 ) ) = 1 / 30 ( x ) - - - > non major = x / 2 - 1 / 30 ( x ) = 7 / 15 ( x ) hence 7 / 15 a | general |
math_qa__Ke7Fz678Y3qhPZJd | A sum of money deposited at C.I. amounts to Rs.9000 in 10 years and to Rs.9990 in 11 years. Find the rate percent?
Choose the correct answer.
A) 9 % B) 10 % C) 11 % D) 12 % E) 13 % | <gadget id="calculator">9_990 - 9_000</gadget>
<output>990</output>
<gadget id="calculator">990 / 9_000</gadget>
<output>11/100 = around 0.11</output>
<gadget id="calculator">(11/100) * 100</gadget>
<output>11</output>
<result>C</result> | C | 11 | A sum of money deposited at C.I. amounts to Rs.9000 in 10 years and to Rs.9990 in 11 years. Find the rate percent? | {
"A": "9 %",
"B": "10 %",
"C": "11 %",
"D": "12 %",
"E": "13 %"
} | multiply(divide(subtract(9990, 9000), 9000), const_100) | subtract(n2,n0)|divide(#0,n0)|multiply(#1,const_100)| | "9000 - - - 990 100 - - - ? = > 11 % answer : c" | gain |
math_qa__WP9TWftOcC1Y84s8 | In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 250 more than the correct answer. Find the number. Options:
A) 125
B) 280
C) 384
D) 480
E) 500 | <gadget id="calculator">250 * 16</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 * 6</gadget>
<output>24_000</output>
<gadget id="calculator">5 * 16</gadget>
<output>80</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">80 - 30</gadget>
<output>50</output>
<gadget id="calculator">24_000 / 50</gadget>
<output>480</output>
<result>D</result> | D | 480 | In a maths test, students were asked to find 5/16 of a certain number. One of the students by mistake found 5/6th of that number and his answer was 250 more than the correct answer. Find the number. | {
"A": "125",
"B": "280",
"C": "384",
"D": "480",
"E": "500"
} | divide(multiply(multiply(250, 16), 6), subtract(multiply(5, 16), multiply(5, 6))) | multiply(n1,n4)|multiply(n0,n1)|multiply(n0,n3)|multiply(n3,#0)|subtract(#1,#2)|divide(#3,#4)| | "explanation : let the number be x . 5 * x / 6 = 5 * x / 16 + 250 25 * x / 48 = 250 x = 480 answer d" | general |
math_qa__QXTK17CifKk3sIOm | If 2^5, 3^3, and 11^2 are all factors of the product of 936 and w where w is a positive integer, what is the smallest possible value of w?
Options
A) 132 B) 39 C) 42 D) 65 E) 156 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">11 / 2</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">12 * (11/2)</gadget>
<output>66</output>
<gadget id="calculator">66 * 2</gadget>
<output>132</output>
<result>A</result> | A | 132 | If 2^5, 3^3, and 11^2 are all factors of the product of 936 and w where w is a positive integer, what is the smallest possible value of w? | {
"A": "132",
"B": "39",
"C": "42",
"D": "65",
"E": "156"
} | multiply(multiply(multiply(power(2, 2), 3), divide(11, 2)), 2) | divide(n4,n0)|power(n0,n0)|multiply(n2,#1)|multiply(#0,#2)|multiply(n0,#3)| | "here 156 has three two ' s two three ' s and one 11 rest of them must be in w so w = 11 * 3 * 4 = 132 smash a" | general |
math_qa__2AkFABAnOx18agEd | Water boils at 212°F or 100°C and ice melts at 32°F or 0°C . If the temperature of a pot of water is 60°C, what is the temperature of the pot of water in °F? Choose the correct choice from the following:
A) 132 ° f B) 140 ° f C) 148 ° f D) 156 ° f E) 164 ° f | <gadget id="calculator">212 - 32</gadget>
<output>180</output>
<gadget id="calculator">180 / 100</gadget>
<output>9/5 = around 1.8</output>
<gadget id="calculator">(9/5) * 60</gadget>
<output>108</output>
<gadget id="calculator">108 + 32</gadget>
<output>140</output>
<result>B</result> | B | 140 | Water boils at 212°F or 100°C and ice melts at 32°F or 0°C . If the temperature of a pot of water is 60°C, what is the temperature of the pot of water in °F? | {
"A": "132 ° f",
"B": "140 ° f",
"C": "148 ° f",
"D": "156 ° f",
"E": "164 ° f"
} | add(multiply(divide(subtract(212, 32), 100), 60), 32) | subtract(n0,n2)|divide(#0,n1)|multiply(n4,#1)|add(n2,#2)| | "let f and c denote the temperature in fahrenheit and celsius respectively . ( f - 32 ) / ( 212 - 32 ) = ( c - 0 ) / ( 100 - 0 ) f = 9 c / 5 + 32 f = 9 ( 60 ) / 5 + 32 = 140 ° f the answer is b ." | physics |
math_qa__YIYUqHdCgPQULpr6 | xy=1 then what is (4^(x+y)^2) / (4^(x-y)^2) Choose the correct choice from the following options:
A) 2
B) 4
C) 8
D) 256
E) 32 | <gadget id="calculator">4 * 1</gadget>
<output>4</output>
<gadget id="calculator">4 ** 4</gadget>
<output>256</output>
<result>D</result> | D | 256 | xy=1 then what is (4^(x+y)^2) / (4^(x-y)^2) | {
"A": "2",
"B": "4",
"C": "8",
"D": "256",
"E": "32"
} | power(4, multiply(const_4, 1)) | multiply(n0,const_4)|power(n1,#0)| | "( x + y ) ^ 2 - ( x - y ) ^ 2 ( x + y + x - y ) ( x + y - x + y ) ( 2 x ) ( 2 y ) 4 xy 4 4 ^ 4 = 256 answer d" | general |
math_qa__OuWn0yMg6ot3V055 | On my sister's birthday, she was 154 cm in height, having grown 10% since the year before. How tall was she the previous year? Choose the correct choice
A) 150 cm B) 140 cm C) 142 cm D) 148 cm E) 146 cm | <gadget id="calculator">154 * 10</gadget>
<output>1_540</output>
<gadget id="calculator">1_540 / 100</gadget>
<output>77/5 = around 15.4</output>
<gadget id="calculator">154 - (77/5)</gadget>
<output>693/5 = around 138.6</output>
<result>B</result> | B | 140 | On my sister's birthday, she was 154 cm in height, having grown 10% since the year before. How tall was she the previous year? | {
"A": "150 cm",
"B": "140 cm",
"C": "142 cm",
"D": "148 cm",
"E": "146 cm"
} | subtract(154, divide(multiply(154, 10), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)| | "let the previous year ' s height be x . 1.1 x = 154 x = 140 the answer is b ." | physics |
math_qa__dVhamQD61mQgXYXW | An empty wooden vessel weighs 16% of its total weight when filled with paint. If the weight of a partially filled vessel is one half that of a completely filled vessel, what fraction of the vessel is filled.
Choose the correct choice from the following answers.
A) 3 / 5 B) 5 / 9 C) 1 / 24 D) 4 / 9 E) 7 / 15 | <gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">16 - 1</gadget>
<output>15</output>
<gadget id="calculator">7 / 15</gadget>
<output>7/15 = around 0.466667</output>
<result>E</result> | E | 0.466667 | An empty wooden vessel weighs 16% of its total weight when filled with paint. If the weight of a partially filled vessel is one half that of a completely filled vessel, what fraction of the vessel is filled. | {
"A": "3 / 5",
"B": "5 / 9",
"C": "1 / 24",
"D": "4 / 9",
"E": "7 / 15"
} | divide(subtract(divide(16, const_2), const_1), subtract(16, const_1)) | divide(n0,const_2)|subtract(n0,const_1)|subtract(#0,const_1)|divide(#2,#1)| | "an empty wooden vessel weighs 16 % of its total weight when filled with paint : vessel = 0.16 ( vessel + paint ) ; 16 v = v + p ( so the weight of completely filled vessel is 16 v ) p = 15 v ( so the weight of the paint when the vessels is completely filled is 15 v ) . the weight of a partially filled vessel is one half that of a completely filled vessel : v + p ' = 1 / 2 * 16 v ; p ' = 7 v ( so the weight of the paint when the vessels is partially filled is 7 v ) . what fraction of the vessel is filled ? so , we need to find the ratio of the weight of the paint when the vessel iscompletely filledto the weight of the paint when the vessel ispartially filled : p ' / p = 7 v / 15 v = 7 / 15 . answer : e ." | gain |
math_qa__2lODJqIKzk7C7xKc | In what time will a train 120 meters long cross an electric pole, if its speed is 184 km/hr
Options.
A) 5 seconds B) 4.5 seconds C) 3 seconds D) 2.3 seconds E) none of these | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">184 * (5/18)</gadget>
<output>460/9 = around 51.111111</output>
<gadget id="calculator">120 / (460/9)</gadget>
<output>54/23 = around 2.347826</output>
<result>D</result> | D | 2.3 | In what time will a train 120 meters long cross an electric pole, if its speed is 184 km/hr | {
"A": "5 seconds",
"B": "4.5 seconds",
"C": "3 seconds",
"D": "2.3 seconds",
"E": "none of these"
} | divide(120, multiply(184, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "explanation : first convert speed into m / sec speed = 184 * ( 5 / 18 ) = 51 m / sec time = distance / speed = 120 / 51 = 2.3 seconds option d" | physics |
math_qa__OLS1vvzie4IaBQ2P | If x is a positive integer with fewer than 3 digits, what is the probability R that x*(x + 1) is a multiple of either 4 or 5?
Select.
A) 4 / 99 B) 2 / 25 C) 8 / 99 D) 49 / 100 E) 86 / 99 | <gadget id="calculator">100 / 4</gadget>
<output>25</output>
<gadget id="calculator">25 * 2</gadget>
<output>50</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">50 + 40</gadget>
<output>90</output>
<gadget id="calculator">90 - 4</gadget>
<output>86</output>
<gadget id="calculator">100 - 1</gadget>
<output>99</output>
<gadget id="calculator">86 / 99</gadget>
<output>86/99 = around 0.868687</output>
<result>E</result> | E | 0.868687 | If x is a positive integer with fewer than 3 digits, what is the probability R that x*(x + 1) is a multiple of either 4 or 5? | {
"A": "4 / 99",
"B": "2 / 25",
"C": "8 / 99",
"D": "49 / 100",
"E": "86 / 99"
} | divide(subtract(add(multiply(divide(const_100, 4), const_2), multiply(divide(const_100, 5), const_2)), 4), subtract(const_100, 1)) | divide(const_100,n2)|divide(const_100,n3)|subtract(const_100,n1)|multiply(#0,const_2)|multiply(#1,const_2)|add(#3,#4)|subtract(#5,n2)|divide(#6,#2)| | "interesting question ! also one that we should be able to answer very quickly be keeping an eye on our best friends , the answer choices . we know that x belongs to the set { 1 , 2 , 3 , . . . , 99 } . we want to know the probability r that x ( x + 1 ) is a multiple of either 4 or 5 . when will this happen ? if either x or ( x + 1 ) is a multiple of 4 or 5 . since 4 * 5 is 20 , let ' s look at the first 20 numbers to get a rough idea of how often this happens . out of the numbers from 1 to 20 : 4 , 5 , 6 , 8 , 9 , 10 , 11 , 12 , 13 , 15 , 16 , 17 , 20 so , 14 out of the first 20 numbers match our criteria . since : probability = ( # of desired outcomes ) / ( total # of possibilities ) , we guesstimate the answer to be 14 / 20 . since ( e ) is the only answer greater than 1 / 2 , we go with ( e ) ." | general |
math_qa__Lf543g7CLUdBthyg | The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle? Pick one
A) 432 B) 288 C) 376 D) 397 E) 592 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">1 * 2</gadget>
<output>2</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">96 / 8</gadget>
<output>12</output>
<gadget id="calculator">12 * 3</gadget>
<output>36</output>
<gadget id="calculator">36 * 12</gadget>
<output>432</output>
<result>A</result> | A | 432 | The length of rectangle is thrice its breadth and its perimeter is 96 m, find the area of the rectangle? | {
"A": "432",
"B": "288",
"C": "376",
"D": "397",
"E": "592"
} | multiply(multiply(divide(96, add(multiply(const_3, const_2), multiply(const_1, const_2))), const_3), divide(96, add(multiply(const_3, const_2), multiply(const_1, const_2)))) | multiply(const_2,const_3)|multiply(const_1,const_2)|add(#0,#1)|divide(n0,#2)|multiply(#3,const_3)|multiply(#3,#4)| | "2 ( 3 x + x ) = 96 l = 36 b = 12 lb = 36 * 12 = 432 answer : a" | geometry |
math_qa__CxNrFVk3bPSpuevz | There are 12 pieces of radioactive metal A that look identical. 11 of the pieces give the same radiation count when measured, the 12th piece is a counterfeit and gives a different radiation level, which may be more or less than the other 11. We are given a radiation scale, which can take 2 sets of samples and compare their added up radiation levels to tell us if the sums are the same or if different, which set has the higher level of radiation. What is the minimum number of comparisons we need on this scale to identify the counterfeit sample and to also determine whether it has more or less radiation than the other samples ? Pick
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">12 - 11</gadget>
<output>1</output>
<gadget id="calculator">1 + 2</gadget>
<output>3</output>
<result>B</result> | B | 3 | There are 12 pieces of radioactive metal A that look identical. 11 of the pieces give the same radiation count when measured, the 12th piece is a counterfeit and gives a different radiation level, which may be more or less than the other 11. We are given a radiation scale, which can take 2 sets of samples and compare their added up radiation levels to tell us if the sums are the same or if different, which set has the higher level of radiation. What is the minimum number of comparisons we need on this scale to identify the counterfeit sample and to also determine whether it has more or less radiation than the other samples ? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | add(subtract(12, 11), 2) | subtract(n0,n1)|add(n4,#0) | first of all if you are down to just 3 pieces and you know that if the offending piece is less or more active , then it takes exactly 1 measurement to find out the offending piece . so you know you have to reduce the problem to three . now when you are down to either a or b after measurement 1 , you need the next measurement to ( a ) reduce the problem set to 3 and ( b ) to know whether anser is more or less . now you can not compare a group of 4 to 4 , as in the best case it will only reduce the problem to 4 elements which is not good enough . if you have to choose a set of 3 to compare , you can not pick any 3 on the same side from the same set ( a or b ) because if you do this , a quick check will show you that in every choice there is a case where you can only get down to 4 elements . eg . if you weighed { 1 , 23 } v / s { 5 , 910 } and they were equal you ' re problem would only reduce to { 46 , 78 } the easiest way to solve this then is to compare 3 to 3 , and make sure each side has elements from both ab such that whatever the measurement outcome in the worst case the problem reduces to 3 elements only . which is why the sets { 1 , 59 } and { 2 , 67 } or { a , b , c } { a , b , b } . the extra element from c is just taken to make the problem symmetric so to say , we have 8 elements and we make it 9 , to compose 3 sets of 3 each . = b | general |
math_qa__cBpcw4L5Y0pzMan5 | A certain school implemented a reading program for its students, with the goal of getting each student to read 5 books per month year-round. If the school has c classes made up of s students in each class, how many books will the entire student body read in one year? Choices:
A) 20 cs B) cs / 2 C) 60 cs D) ( 2 cs ) / 12 E) ( 24 c ) / s | <gadget id="calculator">5 * 12</gadget>
<output>60</output>
<result>C</result> | C | 60 | A certain school implemented a reading program for its students, with the goal of getting each student to read 5 books per month year-round. If the school has c classes made up of s students in each class, how many books will the entire student body read in one year? | {
"A": "20 cs",
"B": "cs / 2",
"C": "60 cs",
"D": "( 2 cs ) / 12",
"E": "( 24 c ) / s"
} | multiply(5, const_12) | multiply(n0,const_12)| | "ans : c solution : simple multiplication s students , c classes , 5 books / month = 60 books a year total number of books = 60 cs" | general |
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