id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__YbYywHIPdwGGbXav | A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 44 now, the son age 5 years back was Pick.
A) 14 B) 17 C) 11 D) 19 E) 99 | <gadget id="calculator">44 / 2</gadget>
<output>22</output>
<gadget id="calculator">22 - 5</gadget>
<output>17</output>
<result>B</result> | B | 17 | A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 44 now, the son age 5 years back was | {
"A": "14",
"B": "17",
"C": "11",
"D": "19",
"E": "99"
} | subtract(divide(44, const_2), 5) | divide(n0,const_2)|subtract(#0,n1)| | "let the son ' s present age be x years . then , ( 44 - x ) = x x = 22 . son ' s age 5 years back = ( 22 - 5 ) = 17 years answer : b" | general |
math_qa__x9BjAkXehv5WRSKt | 4 weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 16 weavers in 16 days? Choose the correct answer
A) 16
B) 32
C) 64
D) 96
E) 128 | <gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">4 / 16</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">16 * (1/4)</gadget>
<output>4</output>
<gadget id="calculator">16 * 4</gadget>
<output>64</output>
<result>C</result> | C | 64 | 4 weavers can weave 4 mats in 4 days. At the same rate, how many mats would be woven by 16 weavers in 16 days? | {
"A": "16",
"B": "32",
"C": "64",
"D": "96",
"E": "128"
} | multiply(16, multiply(16, divide(4, multiply(4, 4)))) | multiply(n0,n0)|divide(n0,#0)|multiply(n3,#1)|multiply(n3,#2)| | "1 weaver can weave 1 mat in 4 days . 16 weavers can weave 16 mats in 4 days . 16 weavers can weave 64 mats in 16 days . the answer is c ." | gain |
math_qa__jVuS9FOUuTA28pOF | A bowl of nuts is prepared for a party. Brand P mixed nuts are 20% almonds and Brand Q's Deluxe nuts are 25% almonds. If a bowl contains a total of 65 ounces of nuts, representing a mixture of both brands, and 15 ounces of the mixture are almonds, how many ounces of Brand Q's Deluxe mixed nuts are used? Choose the correct choice from the following answers:
A) 16
B) 20
C) 32
D) 40
E) 48 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 65</gadget>
<output>13</output>
<gadget id="calculator">15 - 13</gadget>
<output>2</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) - (1/5)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">2 / (1/20)</gadget>
<output>40</output>
<result>D</result> | D | 40 | A bowl of nuts is prepared for a party. Brand P mixed nuts are 20% almonds and Brand Q's Deluxe nuts are 25% almonds. If a bowl contains a total of 65 ounces of nuts, representing a mixture of both brands, and 15 ounces of the mixture are almonds, how many ounces of Brand Q's Deluxe mixed nuts are used? | {
"A": "16",
"B": "20",
"C": "32",
"D": "40",
"E": "48"
} | divide(subtract(15, multiply(divide(20, const_100), 65)), subtract(divide(25, const_100), divide(20, const_100))) | divide(n0,const_100)|divide(n1,const_100)|multiply(n2,#0)|subtract(#1,#0)|subtract(n3,#2)|divide(#4,#3) | lets say x ounces of p is mixed with q . = > 65 - x ounces of q is present in the mixture ( as the total = 65 ounces ) given total almond weight = 15 ounces ( 20 x / 100 ) + ( 25 / 100 ) ( 65 - x ) = 15 = > x = 25 = > 65 - 25 = 40 ounces of q is present in the mixture . answer is d . | general |
math_qa__WzBBlVWpKwaOhkZg | If a number N is chosen at random from the set of two-digit integers whose digits are both prime numbers, what is the probability Q that N is divisible by 3? Choose the correct answer: A) 1 / 3 B) ¼ C) 9 / 25 D) 5 / 16 E) 0 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">5 / 16</gadget>
<output>5/16 = around 0.3125</output>
<result>D</result> | D | 0.3125 | If a number N is chosen at random from the set of two-digit integers whose digits are both prime numbers, what is the probability Q that N is divisible by 3? | {
"A": "1 / 3",
"B": "¼",
"C": "9 / 25",
"D": "5 / 16",
"E": "0"
} | divide(add(3, const_2), multiply(const_4, const_4)) | add(n0,const_2)|multiply(const_4,const_4)|divide(#0,#1)| | "prime digits are : 2 , 3 , 5 , 7 total number of 2 digit # s with both digits prime are : 4 * 4 = 16 out of these numbers divisible by 3 = 33 , 27 , 57 , 72 and 75 . i had to find the numbers manually using the 4 numbers above . = > prob = 5 / 16 . ans d . took me 3 : 20 mins ." | general |
math_qa__Zh6dtZKDeFPFPsPd | A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 330 m long platform? Choose one
A) 37 min
B) 55 min
C) 47 min
D) 67 min
E) 45 min | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 36</gadget>
<output>10</output>
<gadget id="calculator">10 * 12</gadget>
<output>120</output>
<gadget id="calculator">330 + 120</gadget>
<output>450</output>
<gadget id="calculator">450 / 10</gadget>
<output>45</output>
<result>E</result> | E | 45 | A train running at a speed of 36 kmph crosses an electric pole in 12 seconds. In how much time will it cross a 330 m long platform? | {
"A": "37 min",
"B": "55 min",
"C": "47 min",
"D": "67 min",
"E": "45 min"
} | divide(add(330, multiply(multiply(const_0_2778, 36), 12)), multiply(const_0_2778, 36)) | multiply(n0,const_0_2778)|multiply(n1,#0)|add(n2,#1)|divide(#2,#0)| | "e 45 min let the length of the train be x m . when a train crosses an electric pole , the distance covered is its own length . so , x = 12 * 36 * 5 / 18 m = 120 m . time taken to cross the platform = ( 120 + 330 ) / 36 * 5 / 18 = 45 min ." | physics |
math_qa__9DfNyEnRtdAE5n6n | If 3<x<6<y<10, then what is the greatest possible positive integer difference of x and y? Choose the most appropriate option.
A) 3
B) 4
C) 5
D) 6
E) 7 | <gadget id="calculator">10 - 3</gadget>
<output>7</output>
<gadget id="calculator">7 - 1</gadget>
<output>6</output>
<result>D</result> | D | 6 | If 3<x<6<y<10, then what is the greatest possible positive integer difference of x and y? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | subtract(subtract(10, 3), const_1) | subtract(n2,n0)|subtract(#0,const_1)| | "3 < x < 6 < y < 10 ; 3 < x y < 10 3 + y < x + 10 y - x < 7 . positive integer difference is 6 ( for example y = 9.5 and x = 3.5 ) answer : d ." | general |
math_qa__ATaaLw8jHLnuELhC | What is 10-8+6-4+...+(-14)?
Choose the correct choice from the following.
A) 8 B) 10 C) 12 D) 14 E) - 2 | <gadget id="calculator">6 - 8</gadget>
<output>-2</output>
<result>E</result> | E | -2 | What is 10-8+6-4+...+(-14)? | {
"A": "8",
"B": "10",
"C": "12",
"D": "14",
"E": "- 2"
} | subtract(6, 8) | subtract(n2,n1) | the expression considers all even numbers between 10 and - 14 with alternate addition and subtraction of the numbers . the numbers to be used are : 10 , 8 , 6 , 4 , 2 , 0 , - 2 , - 4 , - 6 , - 8 , - 10 , - 12 , and - 14 now , the first term is positive and the next term is subtracted . so , the required expression becomes , 10 - 8 + 6 - 4 + 2 - 0 + ( - 2 ) - ( - 4 ) + ( - 6 ) - ( - 8 ) + ( - 10 ) - ( - 12 ) + ( - 14 ) = 10 - 8 + 6 - 4 + 2 - 0 - 2 + 4 - 6 + 8 - 10 + 12 - 14 = 42 - 44 = - 2 hence the correct answer choice is e . | general |
math_qa__qzyGUflLBico5FxM | The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 1000. What is the manager's monthly salary ? Choose the correct choice from the following answers:
A) rs . 16003 B) rs . 16029 C) rs . 22500 D) rs . 16108 E) rs . 16011 | <gadget id="calculator">1_500 + 1_000</gadget>
<output>2_500</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">2_500 * 21</gadget>
<output>52_500</output>
<gadget id="calculator">1_500 * 20</gadget>
<output>30_000</output>
<gadget id="calculator">52_500 - 30_000</gadget>
<output>22_500</output>
<result>C</result> | C | 22,500 | The average monthly salary of 20 employees in an organisation is Rs. 1500. If the manager's salary is added, then the average salary increases by Rs. 1000. What is the manager's monthly salary ? | {
"A": "rs . 16003",
"B": "rs . 16029",
"C": "rs . 22500",
"D": "rs . 16108",
"E": "rs . 16011"
} | subtract(multiply(add(1500, 1000), add(20, const_1)), multiply(1500, 20)) | add(n1,n2)|add(n0,const_1)|multiply(n0,n1)|multiply(#0,#1)|subtract(#3,#2)| | "explanation : manager ' s monthly salary rs . ( 2500 * 21 - 1500 * 20 ) = rs . 22500 . answer : c" | general |
math_qa__RHzDCSLSsJM9gto2 | Stacy and Heather are 30 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour fast than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?. Options:
A) 15 mile B) 14 mile C) 11 mile D) 10 mile E) 12.5 mile | <gadget id="calculator">1 + 5</gadget>
<output>6</output>
<gadget id="calculator">6 / 60</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">24 * (1/10)</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">30 - (12/5)</gadget>
<output>138/5 = around 27.6</output>
<gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">(138/5) / 11</gadget>
<output>138/55 = around 2.509091</output>
<gadget id="calculator">(138/55) * 5</gadget>
<output>138/11 = around 12.545455</output>
<result>E</result> | E | 12.5 | Stacy and Heather are 30 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour fast than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?. | {
"A": "15 mile",
"B": "14 mile",
"C": "11 mile",
"D": "10 mile",
"E": "12.5 mile"
} | multiply(divide(subtract(30, multiply(24, divide(add(1, 5), const_60))), add(5, add(1, 5))), 5) | add(n1,n2)|add(n2,#0)|divide(#0,const_60)|multiply(n3,#2)|subtract(n0,#3)|divide(#4,#1)|multiply(n2,#5)| | "ss - stacy ' s speed = 6 m / hr sh - heather ' s speed = 5 m / hr in 24 minutes stacy will cover = ( 24 / 60 ) * 6 = 2.4 miles now since both are walking in opposite directions , add their speeds - 6 + 5 = 11 m / hr and distance to cover is 30 - 2.4 = 17.6 time taken = distance / speed = 27.6 / 11 = 2.5 hrs heather will cover = 5 * 2.5 = 12.5 miles . answer e" | physics |
math_qa__7wggL6mxG3CdofmC | In a single throw of a die, what is the probability of getting a number greater than 4? Choose the correct choice from the following choices
A) 1 / 3 B) 1 / 4 C) 2 / 3 D) 2 / 5 E) 3 / 7 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">2 / 6</gadget>
<output>1/3 = around 0.333333</output>
<result>A</result> | A | 0.333333 | In a single throw of a die, what is the probability of getting a number greater than 4? | {
"A": "1 / 3",
"B": "1 / 4",
"C": "2 / 3",
"D": "2 / 5",
"E": "3 / 7"
} | divide(const_2, add(4, const_2)) | add(n0,const_2)|divide(const_2,#0) | s = { 1,2 , 3,4 , 5,6 } e = { 5,6 } probability = 2 / 6 = 1 / 3 answer is a | probability |
math_qa__FVOdUa1C87mVvdIS | The average age of an adult class is 40 years. 12 new students with an avg age of 32 years join the class. Therefore decreasing the average by 6 year. Find what was the original average age of the class? Choices: A) 10 B) 12 C) 16 D) 20 E) 4 | <gadget id="calculator">40 - 6</gadget>
<output>34</output>
<gadget id="calculator">12 * 34</gadget>
<output>408</output>
<gadget id="calculator">12 * 32</gadget>
<output>384</output>
<gadget id="calculator">408 - 384</gadget>
<output>24</output>
<gadget id="calculator">24 / 6</gadget>
<output>4</output>
<result>E</result> | E | 4 | The average age of an adult class is 40 years. 12 new students with an avg age of 32 years join the class. Therefore decreasing the average by 6 year. Find what was the original average age of the class? | {
"A": "10",
"B": "12",
"C": "16",
"D": "20",
"E": "4"
} | divide(subtract(multiply(12, subtract(40, 6)), multiply(12, 32)), 6) | multiply(n1,n2)|subtract(n0,n3)|multiply(n1,#1)|subtract(#2,#0)|divide(#3,n3) | let original strength = y then , 40 y + 12 x 32 = ( y + 12 ) x 34 â ‡ ’ 40 y + 384 = 34 y + 408 â ‡ ’ 6 y = 24 â ˆ ´ y = 4 e | general |
math_qa__vRU3FJLJZMDjdJ8t | A car takes 6 hours to cover a distance of 180 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? Select the correct option:
A) 10 kmph B) 20 kmph C) 15 kmph D) 30 kmph E) 25 kmph | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">180 / 9</gadget>
<output>20</output>
<result>B</result> | B | 20 | A car takes 6 hours to cover a distance of 180 Km. how much should the speed in Kmph be maintained to cover the same direction in 3/2th of the previous time? | {
"A": "10 kmph",
"B": "20 kmph",
"C": "15 kmph",
"D": "30 kmph",
"E": "25 kmph"
} | divide(180, divide(multiply(6, 3), 2)) | multiply(n0,n2)|divide(#0,n3)|divide(n1,#1)| | "time = 6 distance = 280 3 / 2 of 6 hours = 6 * 3 / 2 = 9 hours required speed = 180 / 9 = 20 kmph b )" | physics |
math_qa__iri6PQg4qK86YUl4 | The price of a consumer good increased by pp% during 20122012 and decreased by 1212% during 20132013. If no other change took place in the price of the good and the price of the good at the end of 20132013 was 1010% higher than the price at the beginning of 20122012, what was the value of pp? Choose the correct choice from the following.
A) − 2 % B) 2 % C) 22 % D) 25 % E) can not be determined | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1 - (3/25)</gadget>
<output>22/25 = around 0.88</output>
<gadget id="calculator">(11/10) / (22/25)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) - 1</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">100 * (1/4)</gadget>
<output>25</output>
<result>D</result> | D | 25 | The price of a consumer good increased by pp% during 20122012 and decreased by 1212% during 20132013. If no other change took place in the price of the good and the price of the good at the end of 20132013 was 1010% higher than the price at the beginning of 20122012, what was the value of pp? | {
"A": "− 2 %",
"B": "2 %",
"C": "22 %",
"D": "25 %",
"E": "can not be determined"
} | multiply(const_100, subtract(divide(add(const_1, divide(const_10, const_100)), subtract(const_1, divide(const_12, const_100))), const_1)) | divide(const_10,const_100)|divide(const_12,const_100)|add(#0,const_1)|subtract(const_1,#1)|divide(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100) | as per question = > price was simple 10 percent greater hence x [ 1 + 10 / 100 ] must be the final price . equating the two we get = > x [ 110 / 100 ] = x [ 1 + p / 100 ] [ 88 / 100 ] = > 44 p + 4400 = 5500 = > 44 p = 1100 = > p = 1100 / 44 = > 100 / 4 = > 25 . so p must be 25 answer : d | general |
math_qa__pMFgK3ij5v2SI86Y | Two integers are in the ratio of 1 to 4. If 6 is added to the smaller number, the ratio becomes 1 to 2. Find the larger integer. Choose the correct choice from the following options:
A) 4 B) 6 C) 12 D) 24 E) 30 | <gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<result>D</result> | D | 24 | Two integers are in the ratio of 1 to 4. If 6 is added to the smaller number, the ratio becomes 1 to 2. Find the larger integer. | {
"A": "4",
"B": "6",
"C": "12",
"D": "24",
"E": "30"
} | multiply(divide(multiply(2, 6), subtract(4, 2)), 4) | multiply(n2,n4)|subtract(n1,n4)|divide(#0,#1)|multiply(n1,#2)| | "assume the integers to be x and y , where x < y given x / y = 1 / 4 - ( i ) or y = 4 x and x + 6 / y = 1 / 2 - ( ii ) or y = 2 x + 12 substituting the value of y from ( i ) , 4 x = 2 x + 12 x = 6 hence y = 4 * 6 = 24 answer d" | other |
math_qa__HO04zQSGoDO5LhXZ | In a garment industry, 12 men working 8 hours per day complete a piece of work in 10 days. To complete the same work in 12 days, working 16 hours a day, the number of men required is: Choose the correct answer.
A) 4 B) 5 C) 6 D) 8 E) 9 | <gadget id="calculator">12 * 8</gadget>
<output>96</output>
<gadget id="calculator">96 * 10</gadget>
<output>960</output>
<gadget id="calculator">960 / 16</gadget>
<output>60</output>
<gadget id="calculator">60 / 12</gadget>
<output>5</output>
<result>B</result> | B | 5 | In a garment industry, 12 men working 8 hours per day complete a piece of work in 10 days. To complete the same work in 12 days, working 16 hours a day, the number of men required is: | {
"A": "4",
"B": "5",
"C": "6",
"D": "8",
"E": "9"
} | divide(divide(multiply(multiply(12, 8), 10), 16), 12) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,n4)|divide(#2,n3)| | "explanation : let the required number of men be x . less days , more men ( indirect proportion ) more working hrs per day , less men ( indirect proportion ) days 8 : 10 working hrs 16 : 8 : : 12 : x = > 12 x 16 x x = 10 x 8 x 12 = > x = 10 x 8 x 12 / ( 12 x 16 ) = > x = 5 answer : b" | physics |
math_qa__TeDsadoFGeVqkc5P | What is the unit digit in (4137)754? Choose the correct choice from the following answers:
A) 6 B) 5 C) 9 D) 13 E) 15 | <gadget id="calculator">4_137 ** 2</gadget>
<output>17_114_769</output>
<gadget id="calculator">17_114_769 % 10</gadget>
<output>9</output>
<result>C</result> | C | 9 | What is the unit digit in (4137)754? | {
"A": "6",
"B": "5",
"C": "9",
"D": "13",
"E": "15"
} | reminder(power(4137, const_2), const_10) | power(n0,const_2)|reminder(#0,const_10)| | "explanation : unit digit in ( 4137 ) 754 = unit digit in { [ ( 4137 ) 4 ] 188 x ( 4137 ) 2 } = unit digit in { 292915317923361 x 17114769 } = ( 1 x 9 ) = 9 c" | general |
math_qa__DS7NgT2lG8YGiHmZ | Find the volume , curved surface area and the total surface area of a cylinder with diameter of base 7 cm and height 40 cm. Options
A) 952 cm ^ 2 B) 957 cm ^ 2 C) 954 cm ^ 2 D) 958 cm ^ 2 E) none of them | <gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(7/2) ** 2</gadget>
<output>49/4 = around 12.25</output>
<gadget id="calculator">(49/4) * pi</gadget>
<output>49*pi/4 = around 38.48451</output>
<gadget id="calculator">(49*pi/4) * 2</gadget>
<output>49*pi/2 = around 76.96902</output>
<gadget id="calculator">7 * pi</gadget>
<output>7*pi = around 21.991149</output>
<gadget id="calculator">(7*pi) * 40</gadget>
<output>280*pi = around 879.645943</output>
<gadget id="calculator">(49*pi/2) + (280*pi)</gadget>
<output>609*pi/2 = around 956.614963</output>
<result>B</result> | B | 957 | Find the volume , curved surface area and the total surface area of a cylinder with diameter of base 7 cm and height 40 cm. | {
"A": "952 cm ^ 2",
"B": "957 cm ^ 2",
"C": "954 cm ^ 2",
"D": "958 cm ^ 2",
"E": "none of them"
} | add(multiply(multiply(power(divide(7, const_2), const_2), const_pi), const_2), multiply(multiply(7, const_pi), 40)) | divide(n0,const_2)|multiply(n0,const_pi)|multiply(n1,#1)|power(#0,const_2)|multiply(#3,const_pi)|multiply(#4,const_2)|add(#5,#2) | volume = ∏ r 2 h = ( ( 22 / 7 ) x ( 7 / 2 ) x ( 7 / 2 ) x 40 ) = 1540 cm ^ 3 . . curved surface area = 2 ∏ rh = ( 2 x ( 22 / 7 ) x ( 7 / 2 ) x 40 ) = 880 cm ^ 2 . total surface area = 2 ∏ rh + 2 ∏ r 2 = 2 ∏ r ( h + r ) = ( 2 x ( 22 / 7 ) x ( 7 / 2 ) x ( 40 + 3.5 ) ) cm 2 = 957 cm ^ 2 answer is b | geometry |
math_qa__BHiiwcXLGidlkm9s | An investment yields an interest payment of $234 each month. If the simple annual interest rate is 9%, what is the amount of the investment?
Choose the correct choice from the following options
A) $ 28,300
B) $ 30,400
C) $ 31,300
D) $ 31,200
E) $ 35,100 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">234 / (3/4)</gadget>
<output>312</output>
<gadget id="calculator">312 * 100</gadget>
<output>31_200</output>
<result>D</result> | D | 31,200 | An investment yields an interest payment of $234 each month. If the simple annual interest rate is 9%, what is the amount of the investment? | {
"A": "$ 28,300",
"B": "$ 30,400",
"C": "$ 31,300",
"D": "$ 31,200",
"E": "$ 35,100"
} | multiply(divide(234, divide(9, multiply(const_3, const_4))), const_100) | multiply(const_3,const_4)|divide(n1,#0)|divide(n0,#1)|multiply(#2,const_100) | let the principal amount = p simple annual interest = 9 % simple monthly interest = ( 9 / 12 ) = ( 3 / 4 ) % ( 3 / 4 ) * ( p / 100 ) = 234 = > p = ( 234 * 4 * 10 ^ 2 ) / 3 = 78 * 4 * 10 ^ 2 = 312 * 10 ^ 2 = 31200 answer d | gain |
math_qa__2ZqHRUkn4jjnqubX | A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 80, how many horses are there ? Select the correct option.
A) 10
B) 12
C) 14
D) 16
E) 18 | <gadget id="calculator">2 / 2</gadget>
<output>1</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">80 / 5</gadget>
<output>16</output>
<result>D</result> | D | 16 | A certain number of horses and an equal number of men are going somewhere. Half of the owners are on their horses' back while the remaining ones are walking along leading their horses. If the number of legs walking on the ground is 80, how many horses are there ? | {
"A": "10",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | divide(80, add(const_4, divide(const_2, const_2))) | divide(const_2,const_2)|add(#0,const_4)|divide(n0,#1)| | "legs 16 * 4 = 64 now half on their horses so remaining on the walk so 8 men 8 men has 16 legs so , 16 + 64 = 80 legs walking answer : d" | general |
math_qa__CHVsrAxNJtEcc1kJ | 54 is to be divided into two parts such that the sum of 10 times the first and 22 times the second is 780. The bigger part is : Pick one.
A) 33 B) 34 C) 26 D) 28 E) 19 | <gadget id="calculator">54 * 10</gadget>
<output>540</output>
<gadget id="calculator">780 - 540</gadget>
<output>240</output>
<gadget id="calculator">22 - 10</gadget>
<output>12</output>
<gadget id="calculator">240 / 12</gadget>
<output>20</output>
<gadget id="calculator">54 - 20</gadget>
<output>34</output>
<result>B</result> | B | 34 | 54 is to be divided into two parts such that the sum of 10 times the first and 22 times the second is 780. The bigger part is : | {
"A": "33",
"B": "34",
"C": "26",
"D": "28",
"E": "19"
} | subtract(54, divide(subtract(780, multiply(54, 10)), subtract(22, 10))) | multiply(n0,n1)|subtract(n2,n1)|subtract(n3,#0)|divide(#2,#1)|subtract(n0,#3)| | "explanation : let the two parts be ( 54 - x ) and x . then , 10 ( 54 - x ) + 22 x = 780 = > 12 x = 240 = > x = 20 . bigger part = ( 54 - x ) = 34 . answer : b ) 34" | general |
math_qa__PXIH5vzxBqX92tzw | A cistern is filled by pipe A in 10 hours and the full cistern can be leaked out by an exhaust pipe B in 15 hours. If both the pipes are opened, in what time the cistern is full? Choose the correct choice from the following answers.
A) 50 hrs B) 30 hrs C) 70 hrs D) 80 hrs E) 90 hrs | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) - (1/15)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">1 / (1/30)</gadget>
<output>30</output>
<result>B</result> | B | 30 | A cistern is filled by pipe A in 10 hours and the full cistern can be leaked out by an exhaust pipe B in 15 hours. If both the pipes are opened, in what time the cistern is full? | {
"A": "50 hrs",
"B": "30 hrs",
"C": "70 hrs",
"D": "80 hrs",
"E": "90 hrs"
} | divide(const_1, subtract(divide(const_1, 10), divide(const_1, 15))) | divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|divide(const_1,#2)| | "time taken to full the cistern = ( 1 / 10 - 1 / 15 ) hrs = 1 / 30 = 30 hrs answer : b" | physics |
math_qa__edQP8EuzQsZMnQ7j | All the students of class are told to sit in circle shape. Here the boy at the 10 th position is exactly opposite to 45 th boy. Total number of boys in the class? Choose the correct answer.
A) 65 B) 68 C) 72 D) 70 E) 58 | <gadget id="calculator">45 - 10</gadget>
<output>35</output>
<gadget id="calculator">35 * 2</gadget>
<output>70</output>
<result>D</result> | D | 70 | All the students of class are told to sit in circle shape. Here the boy at the 10 th position is exactly opposite to 45 th boy. Total number of boys in the class? | {
"A": "65",
"B": "68",
"C": "72",
"D": "70",
"E": "58"
} | multiply(subtract(45, 10), const_2) | subtract(n1,n0)|multiply(#0,const_2)| | "as half the circle shape consist of 45 - 10 = 35 boys , so total number of boys in full circle = 2 * 35 = 70 answer : d" | general |
math_qa__EsCLK9sOwiRF9Ykx | How many integers between 2000 and 3000 that have distinct digits and increase from left to right ? Pick
A) 10 B) 20 C) 60 D) 120 E) 600 | <gadget id="calculator">2_000 / 1_000</gadget>
<output>2</output>
<gadget id="calculator">3_000 / 1_000</gadget>
<output>3</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">720 / 36</gadget>
<output>20</output>
<result>B</result> | B | 20 | How many integers between 2000 and 3000 that have distinct digits and increase from left to right ? | {
"A": "10",
"B": "20",
"C": "60",
"D": "120",
"E": "600"
} | divide(factorial(multiply(divide(2000, const_1000), divide(3000, const_1000))), multiply(factorial(divide(3000, const_1000)), factorial(divide(3000, const_1000)))) | divide(n0,const_1000)|divide(n1,const_1000)|factorial(#1)|multiply(#0,#1)|factorial(#3)|multiply(#2,#2)|divide(#4,#5) | since the numbers must be distinct and increasing from left to right , the only arrangements we could come - up with are : 245 _ - - > 4 246 _ - - > 3 247 _ - - > 2 248 _ - - > 1 256 _ - - > 3 257 _ - - > 2 258 _ - - > 1 267 _ - - > 2 268 _ - - > 1 number of integers = 20 b | general |
math_qa__fQNjz0DENHSbo5J3 | The speed of a car is 70 km in the first hour and 90 km in the second hour. What is the average speed of the car? Choose the correct choice from the following answers:
A) 79 kmph B) 80 kmph C) 34 kmph D) 23 kmph E) 14 kmph | <gadget id="calculator">70 + 90</gadget>
<output>160</output>
<gadget id="calculator">160 / 2</gadget>
<output>80</output>
<result>B</result> | B | 80 | The speed of a car is 70 km in the first hour and 90 km in the second hour. What is the average speed of the car? | {
"A": "79 kmph",
"B": "80 kmph",
"C": "34 kmph",
"D": "23 kmph",
"E": "14 kmph"
} | divide(add(70, 90), const_2) | add(n0,n1)|divide(#0,const_2)| | "s = ( 70 + 90 ) / 2 = 80 kmph answer : b" | physics |
math_qa__ajCFYPgrP83TGoKU | Pascal has 96 miles remaining to complete his cycling trip. If he reduced his current speed by 4 miles per hour, the remainder of the trip would take him 16 hours longer than it would if he increased his speed by 50%. What is his current speed Z? Choose the correct choice from the following choices
A) 6 B) 8 C) 10 D) 12 E) 16 | <gadget id="calculator">96 / 16</gadget>
<output>6</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">6 / (3/2)</gadget>
<output>4</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">16 * 4</gadget>
<output>64</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">64 + 36</gadget>
<output>100</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<gadget id="calculator">6 + 10</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>B</result> | B | 8 | Pascal has 96 miles remaining to complete his cycling trip. If he reduced his current speed by 4 miles per hour, the remainder of the trip would take him 16 hours longer than it would if he increased his speed by 50%. What is his current speed Z? | {
"A": "6",
"B": "8",
"C": "10",
"D": "12",
"E": "16"
} | divide(add(divide(96, 16), sqrt(add(multiply(multiply(divide(divide(96, 16), add(const_1, divide(50, const_100))), 4), 4), power(divide(96, 16), const_2)))), const_2) | divide(n0,n2)|divide(n3,const_100)|add(#1,const_1)|power(#0,const_2)|divide(#0,#2)|multiply(n1,#4)|multiply(#5,n1)|add(#6,#3)|sqrt(#7)|add(#0,#8)|divide(#9,const_2)| | "let the current speed be x miles per hour . time taken if speed is 50 % faster ( i . e . 3 x / 2 = 1.5 x ) = 96 / 1.5 x time taken if speed is reduced by 4 miles / hr ( i . e . ( x - 4 ) ) = 96 / ( x - 4 ) as per question , 96 / ( x - 4 ) - 96 / 1.5 x = 16 solving this z we get x = 8 . b ." | physics |
math_qa__BvvMj0M1dTtxiM1O | The length of the bridge, which a train 475 metres long and travelling at 90 km/hr can cross in 30 seconds, is: Options.
A) 200 m B) 225 m C) 245 m D) 250 m E) 275 m | <gadget id="calculator">1_000 / 1</gadget>
<output>1_000</output>
<gadget id="calculator">90 * 1_000</gadget>
<output>90_000</output>
<gadget id="calculator">3_600 / 1</gadget>
<output>3_600</output>
<gadget id="calculator">90_000 / 3_600</gadget>
<output>25</output>
<gadget id="calculator">25 * 30</gadget>
<output>750</output>
<gadget id="calculator">750 - 475</gadget>
<output>275</output>
<result>E</result> | E | 275 | The length of the bridge, which a train 475 metres long and travelling at 90 km/hr can cross in 30 seconds, is: | {
"A": "200 m",
"B": "225 m",
"C": "245 m",
"D": "250 m",
"E": "275 m"
} | subtract(multiply(divide(multiply(90, speed(const_1000, const_1)), speed(const_3600, const_1)), 30), 475) | speed(const_1000,const_1)|speed(const_3600,const_1)|multiply(n1,#0)|divide(#2,#1)|multiply(n2,#3)|subtract(#4,n0)| | "speed = [ 90 x 5 / 18 ] m / sec = [ 25 ] m / sec time = 30 sec let the length of bridge be x metres . then , ( 475 + x ) / 30 = 25 = > 475 + x = 750 = > x = 275 answer : e" | physics |
math_qa__RNjbogfA1371ccqe | Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 80 ps per meter is? Choose one:
A) 287
B) 369
C) 125
D) 200
E) 361 | <gadget id="calculator">3_750 * 2</gadget>
<output>7_500</output>
<gadget id="calculator">7_500 / 3</gadget>
<output>2_500</output>
<gadget id="calculator">2_500 ** (1/2)</gadget>
<output>50</output>
<gadget id="calculator">3_750 / 50</gadget>
<output>75</output>
<gadget id="calculator">2 * (50 + 75)</gadget>
<output>250</output>
<gadget id="calculator">80 * 250</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 / 100</gadget>
<output>200</output>
<result>D</result> | D | 200 | Sides of a rectangular park are in the ratio 3: 2 and its area is 3750 sq m, the cost of fencing it at 80 ps per meter is? | {
"A": "287",
"B": "369",
"C": "125",
"D": "200",
"E": "361"
} | divide(multiply(80, rectangle_perimeter(sqrt(divide(multiply(3750, 2), 3)), divide(3750, sqrt(divide(multiply(3750, 2), 3))))), const_100) | multiply(n1,n2)|divide(#0,n0)|sqrt(#1)|divide(n2,#2)|rectangle_perimeter(#3,#2)|multiply(n3,#4)|divide(#5,const_100)| | "3 x * 2 x = 3750 = > x = 25 2 ( 75 + 50 ) = 250 m 250 * 0.80 = rs . 200 answer : d" | physics |
math_qa__EixBepWYoqns2GZ6 | what is the smallest positive integer x , such that 1152 x is a perfect cube ? Choices:
A) 4
B) 6
C) 8
D) 12
E) 18 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1_152 ** (1/3)</gadget>
<output>4*18**(1/3) = around 10.482966</output>
<gadget id="calculator">(4*18**(1/3)) + 2</gadget>
<output>2 + 4*18**(1/3) = around 12.482966</output>
<gadget id="calculator">floor(2 + 4*18**(1/3))</gadget>
<output>12</output>
<result>D</result> | D | 12 | what is the smallest positive integer x , such that 1152 x is a perfect cube ? | {
"A": "4",
"B": "6",
"C": "8",
"D": "12",
"E": "18"
} | floor(add(power(1152, divide(const_1, const_3)), const_2)) | divide(const_1,const_3)|power(n0,#0)|add(#1,const_2)|floor(#2) | we need to make 1152 x a perfect cube , hence we need to have the powers a multiple of 3 1152 = 2 ^ 7 * 3 ^ 2 the minimum value of x for which 1152 x is a perfect cube = 2 ^ 2 * 3 = 12 correct option : d | geometry |
math_qa__Pif4PUrZX7T70PdB | An association of mathematics teachers has 1,600 members. Only 525 of these members cast votes in the election for president of the association. What percent of the total membership voted for the winning candidate if the winning candidate received 60 percent of the votes cast? Pick
A) 75 % B) 58 % C) 42 % D) 14.5 % E) 19.6 % | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 525</gadget>
<output>315</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">100 * 16</gadget>
<output>1_600</output>
<gadget id="calculator">315 / 1_600</gadget>
<output>63/320 = around 0.196875</output>
<gadget id="calculator">(63/320) * 100</gadget>
<output>315/16 = around 19.6875</output>
<result>E</result> | E | 19.6 | An association of mathematics teachers has 1,600 members. Only 525 of these members cast votes in the election for president of the association. What percent of the total membership voted for the winning candidate if the winning candidate received 60 percent of the votes cast? | {
"A": "75 %",
"B": "58 %",
"C": "42 %",
"D": "14.5 %",
"E": "19.6 %"
} | multiply(divide(multiply(divide(60, const_100), 525), multiply(const_100, power(const_4, const_2))), const_100) | divide(n2,const_100)|power(const_4,const_2)|multiply(n1,#0)|multiply(#1,const_100)|divide(#2,#3)|multiply(#4,const_100) | total umber of members = 1600 number of members that cast votes = 525 since , winning candidate received 60 percent of the votes cast number of votes for winning candidate = ( 60 / 100 ) * 525 = 315 percent of total membership that voted for winning candidate = ( 315 / 1600 ) * 100 = 19.6 % answer e | gain |
math_qa__1oH4lsIeJbeaakvQ | A no.when divided by 125 gives a remainder 40, what remainder will be obtainedby dividingthe same no.15?
Choose the correct choice from the following options.
A) 10 B) 11 C) 12 D) 13 E) 14 | <gadget id="calculator">125 + 40</gadget>
<output>165</output>
<gadget id="calculator">165 / 15</gadget>
<output>11</output>
<result>B</result> | B | 11 | A no.when divided by 125 gives a remainder 40, what remainder will be obtainedby dividingthe same no.15? | {
"A": "10",
"B": "11",
"C": "12",
"D": "13",
"E": "14"
} | divide(add(125, 40), 15) | add(n0,n1)|divide(#0,n2)| | "125 + 40 = 165 / 15 = 11 ( remainder ) b" | general |
math_qa__B4n5vOgHV9PH3vy0 | A certain company has records stored with a record storage firm in 15-inch by 12-inch by 10-inch boxes. The boxes occupy 1.08 million cubic inches of space. If the company pays $0.5 per box per month for the record storage, what is the total amount that the company pays each month for record storage?
Choose the most appropriate option:
A) a . 150 B) b . 300 C) c . 600 D) d . 1,200 E) e . 2,400 | <gadget id="calculator">15 * 12</gadget>
<output>180</output>
<gadget id="calculator">180 * 10</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 100</gadget>
<output>18</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(9/50) / 100</gadget>
<output>9/5_000 = around 0.0018</output>
<gadget id="calculator">1.08 / (9/5_000)</gadget>
<output>600</output>
<gadget id="calculator">0.5 * 600</gadget>
<output>300</output>
<result>B</result> | B | 300 | A certain company has records stored with a record storage firm in 15-inch by 12-inch by 10-inch boxes. The boxes occupy 1.08 million cubic inches of space. If the company pays $0.5 per box per month for the record storage, what is the total amount that the company pays each month for record storage? | {
"A": "a . 150",
"B": "b . 300",
"C": "c . 600",
"D": "d . 1,200",
"E": "e . 2,400"
} | multiply(0.5, divide(1.08, divide(divide(divide(multiply(multiply(15, 12), 10), const_100), const_100), const_100))) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,const_100)|divide(#2,const_100)|divide(#3,const_100)|divide(n3,#4)|multiply(n4,#5)| | "volume per box : 15 x 12 x 10 = 1,800 total volume : 1 , 080,000 number of boxes : total volume / volume per box = 1 , 080,000 / 1,800 = 600 price per month : number of boxes * price per box = 600 * 0.5 = 300 answer : b" | general |
math_qa__809biUfF1SQq3qhs | If 7 parallel lines in a plane is intersected by a family of another 8 parallel lines, how many parallelograms are there in the network thus formed? Choose the most appropriate option:
A) 588
B) 263
C) 120
D) 160
E) 1260 | <gadget id="calculator">7 - 1</gadget>
<output>6</output>
<gadget id="calculator">7 * 6</gadget>
<output>42</output>
<gadget id="calculator">42 / 2</gadget>
<output>21</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">8 * 7</gadget>
<output>56</output>
<gadget id="calculator">56 / 2</gadget>
<output>28</output>
<gadget id="calculator">21 * 28</gadget>
<output>588</output>
<result>A</result> | A | 588 | If 7 parallel lines in a plane is intersected by a family of another 8 parallel lines, how many parallelograms are there in the network thus formed? | {
"A": "588",
"B": "263",
"C": "120",
"D": "160",
"E": "1260"
} | multiply(divide(multiply(7, subtract(7, const_1)), const_2), divide(multiply(8, subtract(8, const_1)), const_2)) | subtract(n0,const_1)|subtract(n1,const_1)|multiply(n0,#0)|multiply(n1,#1)|divide(#2,const_2)|divide(#3,const_2)|multiply(#4,#5)| | "parallelogram can formed by 2 horizontal and 2 vertical lines for horizontal 7 c 2 for vertical 8 c 2 total parallelogram is 7 c 2 * 8 c 2 = 21 * 28 = 588 answer : a" | physics |
math_qa__vB12h0lPQQ0JCkg6 | If the a radio is sold for rs 490 and sold for rs 465.50.find loss percentage. Choose the correct answer.
A) 3 B) 5 C) 7 D) 9 E) none of them | <gadget id="calculator">490 - 465.5</gadget>
<output>24.5</output>
<gadget id="calculator">24.5 / 490</gadget>
<output>0.05</output>
<gadget id="calculator">0.05 * 100</gadget>
<output>5</output>
<result>B</result> | B | 5 | If the a radio is sold for rs 490 and sold for rs 465.50.find loss percentage. | {
"A": "3",
"B": "5",
"C": "7",
"D": "9",
"E": "none of them"
} | multiply(divide(subtract(490, 465.5), 490), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100) | cost price = rs 490 , selling price = 465.50 . loss = rs ( 490 - 465.50 ) = rs 24.50 . loss % = [ ( 24.50 / 490 ) * 100 ] % = 5 % answer is b | gain |
math_qa__0XYxZGOm8cfJUp2X | If a certain coin is flipped, the probability that the coin will land heads is 1/2. If the coin is flipped 5 times, what is the probability that it will land heads up on the first flip but not on the last 4 flips? Choose the correct choice from the following answers
A) 1 / 4
B) 1 / 8
C) 1 / 16
D) 1 / 32
E) 1 / 64 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 5</gadget>
<output>1/32 = around 0.03125</output>
<result>D</result> | D | 0.03125 | If a certain coin is flipped, the probability that the coin will land heads is 1/2. If the coin is flipped 5 times, what is the probability that it will land heads up on the first flip but not on the last 4 flips? | {
"A": "1 / 4",
"B": "1 / 8",
"C": "1 / 16",
"D": "1 / 32",
"E": "1 / 64"
} | power(divide(1, 2), 5) | divide(n0,n1)|power(#0,n2)| | "p ( htttt ) = 1 / 2 * 1 / 2 * 1 / 2 * 1 / 2 * 1 / 2 = 1 / 32 the answer is d ." | probability |
math_qa__cATxERr6gOEQeXM0 | A person distributed 20% of his income to his 3 children each. He deposited 30% of his income to his wife's account. He donated 5% of remaining amount to an orphan house.Finally he has $50000. Find his total income? Choose the correct choice from the following options:
A) 452000
B) 562000
C) 800000
D) 1000000
E) 652000 | <gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">60 + 30</gadget>
<output>90</output>
<gadget id="calculator">90 + 5</gadget>
<output>95</output>
<gadget id="calculator">100 - 95</gadget>
<output>5</output>
<gadget id="calculator">50_000 / 5</gadget>
<output>10_000</output>
<gadget id="calculator">10_000 * 100</gadget>
<output>1_000_000</output>
<result>D</result> | D | 1,000,000 | A person distributed 20% of his income to his 3 children each. He deposited 30% of his income to his wife's account. He donated 5% of remaining amount to an orphan house.Finally he has $50000. Find his total income? | {
"A": "452000",
"B": "562000",
"C": "800000",
"D": "1000000",
"E": "652000"
} | multiply(divide(50000, subtract(const_100, add(add(multiply(20, 3), 30), 5))), const_100) | multiply(n0,n1)|add(n2,#0)|add(n3,#1)|subtract(const_100,#2)|divide(n4,#3)|multiply(#4,const_100)| | "3 children got = 3 * 20 % = 60 % wife got = 30 % orphan house = 5 % total = 60 + 30 + 5 = 95 % remaining = 100 - 95 = 5 % 5 % = 50000 100 % = 50000 * 100 / 5 = $ 1000000 answer is d" | gain |
math_qa__nYz64DpvNvUr70sh | A train 200 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 10 km/hr in the direction opposite to that in which the train is going? Choose the correct choice from the following answers: A) 5 B) 6 C) 10 D) 9 E) 5 | <gadget id="calculator">60 + 10</gadget>
<output>70</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">70 * (5/18)</gadget>
<output>175/9 = around 19.444444</output>
<gadget id="calculator">200 / (175/9)</gadget>
<output>72/7 = around 10.285714</output>
<result>C</result> | C | 10 | A train 200 m long is running with a speed of 60 km/hr. In what time will it pass a man who is running at 10 km/hr in the direction opposite to that in which the train is going? | {
"A": "5",
"B": "6",
"C": "10",
"D": "9",
"E": "5"
} | divide(200, multiply(add(60, 10), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 60 + 10 = 70 km / hr . = 70 * 5 / 18 = 175 / 9 m / sec . time taken to pass the men = 200 * 9 / 175 = 10 sec . answer : c" | physics |
math_qa__aMHQS9vlOCcRCyWf | On dividing number by 357, we get 39 as remainder. On dividing the same number by 17, what will be the remainder? Choose the correct choice from the following options: A) 0 B) 3 C) 5 D) 11 E) 13 | <gadget id="calculator">39 % 17</gadget>
<output>5</output>
<result>C</result> | C | 5 | On dividing number by 357, we get 39 as remainder. On dividing the same number by 17, what will be the remainder? | {
"A": "0",
"B": "3",
"C": "5",
"D": "11",
"E": "13"
} | reminder(39, 17) | reminder(n1,n2)| | "let the number be x and on dividing x by 5 , we get k as quotient and 3 as remainder . x = 5 k + 3 x 2 = ( 5 k + 3 ) 2 = ( 25 k 2 + 30 k + 9 ) = 5 ( 5 k 2 + 6 k + 1 ) + 4 on dividing x 2 by 5 , we get 4 as remainder . answer : c" | general |
math_qa__LLAGIUH7EU2ciibM | How many even number in the range between 10 to 150 inclusive are not divisible by 3 Options: A) 15 B) 30 C) 31 D) 33 E) 47 | <gadget id="calculator">150 - 10</gadget>
<output>140</output>
<gadget id="calculator">140 - 2</gadget>
<output>138</output>
<gadget id="calculator">138 / 2</gadget>
<output>69</output>
<gadget id="calculator">150 - 2</gadget>
<output>148</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">148 - 12</gadget>
<output>136</output>
<gadget id="calculator">136 - 3</gadget>
<output>133</output>
<gadget id="calculator">133 - 3</gadget>
<output>130</output>
<gadget id="calculator">130 / 3</gadget>
<output>130/3 = around 43.333333</output>
<gadget id="calculator">(130/3) / 2</gadget>
<output>65/3 = around 21.666667</output>
<gadget id="calculator">69 - (65/3)</gadget>
<output>142/3 = around 47.333333</output>
<result>E</result> | E | 47 | How many even number in the range between 10 to 150 inclusive are not divisible by 3 | {
"A": "15",
"B": "30",
"C": "31",
"D": "33",
"E": "47"
} | subtract(divide(subtract(subtract(150, 10), const_2), const_2), divide(divide(subtract(subtract(subtract(subtract(150, const_2), multiply(3, const_4)), 3), 3), 3), const_2)) | multiply(n2,const_4)|subtract(n1,n0)|subtract(n1,const_2)|subtract(#1,const_2)|subtract(#2,#0)|divide(#3,const_2)|subtract(#4,n2)|subtract(#6,n2)|divide(#7,n2)|divide(#8,const_2)|subtract(#5,#9)| | "we have to find the number of terms that are divisible by 2 but not by 6 ( as the question asks for the even numbers only which are not divisible by 3 ) for 2 , 10 , 12,14 . . . 150 using ap formula , we can say 150 = 10 + ( n - 1 ) * 2 or n = 71 . for 6 , 12,18 , . . . 96 using ap formula , we can say 150 = 12 + ( n - 1 ) * 6 or n = 24 . hence , only divisible by 2 but not 3 = 71 - 24 = 47 . hence , answer e" | general |
math_qa__8bpZ3vlmf0vrnyUH | A is twice as good as B. And together they finish a piece of work in 20days. In how many days will A alone finish the work
Choose the correct answer: A) 30 B) 25 C) 12 D) 10 E) 32 | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">(1/20) / 3</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">(1/60) * 2</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">1 / (1/30)</gadget>
<output>30</output>
<result>A</result> | A | 30 | A is twice as good as B. And together they finish a piece of work in 20days. In how many days will A alone finish the work | {
"A": "30",
"B": "25",
"C": "12",
"D": "10",
"E": "32"
} | inverse(multiply(divide(inverse(20), add(const_2, const_1)), const_2)) | add(const_1,const_2)|inverse(n0)|divide(#1,#0)|multiply(#2,const_2)|inverse(#3)| | "( a ' s 1 day work ) : ( b ' s 1 day work ) = 2 : 1 a + b 1 day work = 1 / 20 a ' s 1 day work = ( 1 / 20 ) * ( 2 / 3 ) = 1 / 30 a alone can finish the work in 30 days answer is a" | physics |
math_qa__igBoTOhzFFmE83m4 | A tradesman sold an article at a loss of 20%. If the selling price had been increased by $100, there would have been a gain of 5%. What was the cost price of the article ? Options.
A) $ 100 B) $ 200 C) $ 300 D) $ 400 E) $ 500 | <gadget id="calculator">20 + 5</gadget>
<output>25</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">100 / (1/4)</gadget>
<output>400</output>
<result>D</result> | D | 400 | A tradesman sold an article at a loss of 20%. If the selling price had been increased by $100, there would have been a gain of 5%. What was the cost price of the article ? | {
"A": "$ 100",
"B": "$ 200",
"C": "$ 300",
"D": "$ 400",
"E": "$ 500"
} | divide(100, divide(add(20, 5), const_100)) | add(n0,n2)|divide(#0,const_100)|divide(n1,#1)| | "let c . p . be $ x then , ( 105 % of x ) - ( 80 % of x ) = 100 or 25 % of x = 100 x / 4 = 100 x = 400 c . p . = $ 400 correct option is d" | gain |
math_qa__Iq3UhYHIEmD0lkwW | A shop keeper marked 20% above the cost price and offered 15% discount then find it's net profit? Choose the correct choice from the following
A) 2 % B) 5 % C) 8 % D) 10 % E) 15 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 * 15</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 100</gadget>
<output>18</output>
<gadget id="calculator">120 - 18</gadget>
<output>102</output>
<gadget id="calculator">102 - 100</gadget>
<output>2</output>
<result>A</result> | A | 2 | A shop keeper marked 20% above the cost price and offered 15% discount then find it's net profit? | {
"A": "2 %",
"B": "5 %",
"C": "8 %",
"D": "10 %",
"E": "15 %"
} | subtract(subtract(add(const_100, 20), divide(multiply(add(const_100, 20), 15), const_100)), const_100) | add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|subtract(#0,#2)|subtract(#3,const_100) | net profit = 20 - 15 + ( 20 * ( - 15 ) / 100 ) = 2 % answer is a | gain |
math_qa__vlu7JTXFlzAEqucl | If 0.5% of A =65 paise, then the value of A is ?
Select the correct option
A) rs . 130 B) rs . 17 C) rs . 1.70 D) rs . 4.25 E) none | <gadget id="calculator">65 / 0.5</gadget>
<output>130</output>
<result>A</result> | A | 130 | If 0.5% of A =65 paise, then the value of A is ? | {
"A": "rs . 130",
"B": "rs . 17",
"C": "rs . 1.70",
"D": "rs . 4.25",
"E": "none"
} | divide(65, 0.5) | divide(n1,n0) | answer ∵ 0.5 / 100 of a = 65 / 100 ∴ a = rs . ( 65 / 0.5 ) = rs . 130 correct option : a | gain |
math_qa__nUaG1slrRXuUIWTp | Suppose a, b, and c are positive integers with a < b < c such that
1/a
+
1/b
+
1/c
= 1. What is
a + b + c? Choose one:
A) 1 B) 4 C) 9 D) 11 E) no such integers exist | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<result>D</result> | D | 11 | Suppose a, b, and c are positive integers with a < b < c such that
1/a
+
1/b
+
1/c
= 1. What is
a + b + c? | {
"A": "1",
"B": "4",
"C": "9",
"D": "11",
"E": "no such integers exist"
} | add(multiply(add(add(1, 1), 1), add(1, 1)), add(add(1, 1), add(add(1, 1), 1))) | add(n0,n0)|add(n0,#0)|add(#0,#1)|multiply(#1,#0)|add(#2,#3) | first note that we must have 1 / a < 1 , so a > 1 . since 1 / a > 1 / b > 1 / c , we must also have 1 / a > 1 / 3 ; so a < 3 . thus , a / 2 . now 1 / b + 1 / c = 1 / 2 where 2 < b < c . similar to before , 1 / b > 1 / 4 , so b < 4 . thus , b = 3 . with a = 2 and b = 3 we have 1 / 2 + 1 / 3 + 1 / c = 1 , which is satisfied when c = 6 . to conclude , a + b + c = 2 + 3 + 6 = 11 . correct answer d | general |
math_qa__xS0J0KP9nFGBdGhD | What is the smallest number which when diminished by 24, is divisible 5, 10, 15 and 20? Choose the correct choice from the following answers.
A) 276 B) 84 C) 88 D) 90 E) 342 | <gadget id="calculator">lcm(5, 10)</gadget>
<output>10</output>
<gadget id="calculator">lcm(15, 20)</gadget>
<output>60</output>
<gadget id="calculator">lcm(10, 60)</gadget>
<output>60</output>
<gadget id="calculator">60 + 24</gadget>
<output>84</output>
<result>B</result> | B | 84 | What is the smallest number which when diminished by 24, is divisible 5, 10, 15 and 20? | {
"A": "276",
"B": "84",
"C": "88",
"D": "90",
"E": "342"
} | add(lcm(lcm(5, 10), lcm(15, 20)), 24) | lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|add(n0,#2)| | "required number = ( lcm of 5 , 10 , 15 and 20 ) + 24 = 60 + 24 = 84 option b" | general |
math_qa__XKuKvVLITPey62oe | A 6-meter long wire is cut into two pieces. If the longer piece is then used to form a perimeter of a square, what is the probability that the area of the square will be more than 1 if the original wire was cut at an arbitrary point? Answers.
A) 2 / 3 B) 3 / 4 C) 4 / 5 D) 5 / 6 E) 6 / 7 | <gadget id="calculator">4 * 1</gadget>
<output>4</output>
<gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>
<result>A</result> | A | 0.666667 | A 6-meter long wire is cut into two pieces. If the longer piece is then used to form a perimeter of a square, what is the probability that the area of the square will be more than 1 if the original wire was cut at an arbitrary point? | {
"A": "2 / 3",
"B": "3 / 4",
"C": "4 / 5",
"D": "5 / 6",
"E": "6 / 7"
} | divide(square_perimeter(1), 6) | square_perimeter(n1)|divide(#0,n0) | the longer wire will form a square with an area more than 1 if the wire is cut at a point within two meters of either end . the probability of this is 4 / 6 = 2 / 3 . the answer is a . | geometry |
math_qa__wZfVHU6MbQXIci2I | In a certain boys camp, 20% of the total boys are from school A and 30% of those study science. If there are 42 boys in the camp that are from school A but do not study science then what is the total number of boys in the camp?
Select the correct option:
A) 70 B) 245 C) 150 D) 300 E) 350 | <gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(7/10) * (1/5)</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">42 / (7/50)</gadget>
<output>300</output>
<result>D</result> | D | 300 | In a certain boys camp, 20% of the total boys are from school A and 30% of those study science. If there are 42 boys in the camp that are from school A but do not study science then what is the total number of boys in the camp? | {
"A": "70",
"B": "245",
"C": "150",
"D": "300",
"E": "350"
} | divide(42, multiply(divide(subtract(const_100, 30), const_100), divide(20, const_100))) | divide(n0,const_100)|subtract(const_100,n1)|divide(#1,const_100)|multiply(#2,#0)|divide(n2,#3)| | "since 30 % of the boys from school a study science , then 70 % of the boys from school a do not study science and since 20 % of the total number of boys are from school a , then 0.2 * 0.7 = 0.14 , or 14 % of the boys in the camp are from school a and do not study science . we are told that this number equals to 42 , so 0.14 * { total } = 42 - - > { total } = 300 . answer : d ." | gain |
math_qa__CQsEK0IKeMFHWAED | A goods train runs at the speed of 72 km/hr and crosses a 300 m long platform in 26 sec. What is the length of the goods train? Choose one:
A) 382 B) 782 C) 278 D) 270 E) 220 | <gadget id="calculator">72 / 3_600</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/50) * 1_000</gadget>
<output>20</output>
<gadget id="calculator">20 * 26</gadget>
<output>520</output>
<gadget id="calculator">520 - 300</gadget>
<output>220</output>
<result>E</result> | E | 220 | A goods train runs at the speed of 72 km/hr and crosses a 300 m long platform in 26 sec. What is the length of the goods train? | {
"A": "382",
"B": "782",
"C": "278",
"D": "270",
"E": "220"
} | subtract(multiply(multiply(divide(72, const_3600), const_1000), 26), 300) | divide(n0,const_3600)|multiply(#0,const_1000)|multiply(n2,#1)|subtract(#2,n1)| | "speed = 72 * 5 / 18 = 20 m / sec . time = 26 sec . let the length of the train be x meters . then , ( x + 300 ) / 26 = 20 x = 220 m . answer : e" | physics |
math_qa__WlvyBaVkAaxeKLoY | The average mark of the students of a class in a particular exam is 60. If 5 students whose average mark in that exam is 44 are excluded, the average mark of the remaining will be 80. Find the number of students who wrote the exam? Pick one
A) 12
B) 10
C) 7
D) 9
E) 8 | <gadget id="calculator">80 * 5</gadget>
<output>400</output>
<gadget id="calculator">5 * 44</gadget>
<output>220</output>
<gadget id="calculator">400 - 220</gadget>
<output>180</output>
<gadget id="calculator">80 - 60</gadget>
<output>20</output>
<gadget id="calculator">180 / 20</gadget>
<output>9</output>
<result>D</result> | D | 9 | The average mark of the students of a class in a particular exam is 60. If 5 students whose average mark in that exam is 44 are excluded, the average mark of the remaining will be 80. Find the number of students who wrote the exam? | {
"A": "12",
"B": "10",
"C": "7",
"D": "9",
"E": "8"
} | divide(subtract(multiply(80, 5), multiply(5, 44)), subtract(80, 60)) | multiply(n1,n3)|multiply(n1,n2)|subtract(n3,n0)|subtract(#0,#1)|divide(#3,#2)| | "let the number of students who wrote the exam be x . total marks of students = 60 x . total marks of ( x - 5 ) students = 90 ( x - 5 ) 60 x - ( 5 * 44 ) = 80 ( x - 5 ) 180 = 20 x = > x = 9 answer : d" | general |
math_qa__UG5ADB4rEr8USFOJ | In how many years will a sum of money doubles itself at 18% per annum on simple interest? Select the correct option
A) 5.9 % B) 5.5 % C) 6 % D) 6.4 % E) 7.5 % | <gadget id="calculator">100 / 18</gadget>
<output>50/9 = around 5.555556</output>
<result>B</result> | B | 5.5 | In how many years will a sum of money doubles itself at 18% per annum on simple interest? | {
"A": "5.9 %",
"B": "5.5 %",
"C": "6 %",
"D": "6.4 %",
"E": "7.5 %"
} | divide(const_100, 18) | divide(const_100,n0)| | "p = ( p * 18 * r ) / 100 r = 5.5 % answer : b" | gain |
math_qa__mgFYXCtwbYfQIrXk | a merchant gains or loses , in a bargain , a certain sum . in a second bargain , he gains 380 dollars , and , in a third , loses 70 . in the end he finds he has gained 250 dollars , by the 3 together . how much did he gain or lose bv the first ? Options:
A) 80 B) 60 C) - 60 D) - 70 E) none | <gadget id="calculator">380 - 70</gadget>
<output>310</output>
<gadget id="calculator">250 - 310</gadget>
<output>-60</output>
<result>C</result> | C | -60 | a merchant gains or loses , in a bargain , a certain sum . in a second bargain , he gains 380 dollars , and , in a third , loses 70 . in the end he finds he has gained 250 dollars , by the 3 together . how much did he gain or lose bv the first ? | {
"A": "80",
"B": "60",
"C": "- 60",
"D": "- 70",
"E": "none"
} | subtract(250, subtract(380, 70)) | subtract(n0,n1)|subtract(n2,#0) | in this sum , as the profit and loss are opposite in their nature , they must be distinguished by contrary signs . if the profit is marked + , the loss must be - . let x = the sum required . then according to the statement x + 380 - 70 = 250 and x = - 60 . answer c | general |
math_qa__E75IiFLhLZgBba5N | population is 20000. Pop increases by 10% every year, then the pop after 3 years is? Choose the correct choice from the following options:
A) 26630 B) 26640 C) 36620 D) 26620 E) 26820 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">20_000 * (1/10)</gadget>
<output>2_000</output>
<gadget id="calculator">20_000 + 2_000</gadget>
<output>22_000</output>
<gadget id="calculator">22_000 * (1/10)</gadget>
<output>2_200</output>
<gadget id="calculator">22_000 + 2_200</gadget>
<output>24_200</output>
<gadget id="calculator">24_200 * (1/10)</gadget>
<output>2_420</output>
<gadget id="calculator">24_200 + 2_420</gadget>
<output>26_620</output>
<result>D</result> | D | 26,620 | population is 20000. Pop increases by 10% every year, then the pop after 3 years is? | {
"A": "26630",
"B": "26640",
"C": "36620",
"D": "26620",
"E": "26820"
} | add(add(add(20000, multiply(20000, divide(10, const_100))), multiply(add(20000, multiply(20000, divide(10, const_100))), divide(10, const_100))), multiply(add(add(20000, multiply(20000, divide(10, const_100))), multiply(add(20000, multiply(20000, divide(10, const_100))), divide(10, const_100))), divide(10, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)|multiply(#2,#0)|add(#2,#3)|multiply(#4,#0)|add(#4,#5) | population after 1 st year = 20000 * 10 / 100 = 2000 = = = > 20000 + 2000 = 22000 population after 2 nd year = 22000 * 10 / 100 = 2200 = = = > 22000 + 2200 = 24200 population after 3 rd year = 24200 * 10 / 100 = 2420 = = = > 24200 + 2420 = 26620 answer : d | gain |
math_qa__dmGYomW7XPfODhbB | Find the number of different prime factors of 6440
Choose the correct choice.
A) 4
B) 2
C) 3
D) 5
E) 6 | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<result>A</result> | A | 4 | Find the number of different prime factors of 6440 | {
"A": "4",
"B": "2",
"C": "3",
"D": "5",
"E": "6"
} | add(const_2, const_2) | add(const_2,const_2)| | "explanation : l . c . m of 6440 = 2 x 2 x 2 x 5 x 7 x 23 2 , 5 , 7,23 number of different prime factors is 4 . answer : option a" | other |
math_qa__gFjMSo7wbDKy9TqM | A train traveling at 72 kmph crosses a platform in 31 seconds and a man standing on the platform in 18 seconds. What is the length of the platform in meters? Select.
A) 240 meters B) 260 meters C) 420 meters D) 600 meters E) can not be determined | <gadget id="calculator">72 * 1_000</gadget>
<output>72_000</output>
<gadget id="calculator">72_000 / 3_600</gadget>
<output>20</output>
<gadget id="calculator">20 * 31</gadget>
<output>620</output>
<gadget id="calculator">20 * 18</gadget>
<output>360</output>
<gadget id="calculator">620 - 360</gadget>
<output>260</output>
<result>B</result> | B | 260 | A train traveling at 72 kmph crosses a platform in 31 seconds and a man standing on the platform in 18 seconds. What is the length of the platform in meters? | {
"A": "240 meters",
"B": "260 meters",
"C": "420 meters",
"D": "600 meters",
"E": "can not be determined"
} | subtract(multiply(divide(multiply(72, const_1000), const_3600), 31), multiply(divide(multiply(72, const_1000), const_3600), 18)) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)|multiply(n2,#1)|subtract(#2,#3)| | "speed of train = 72 * ( 5 / 18 ) = 20 m / s lets consider the man as a stationery point on the platform . crossing the point gives us the length of the train . lt = 20 * 18 = 360 m . crossing the platform gives us the length of trainlength of platform . l ( t + p ) = 20 * 31 = 620 m . so , length of platform = 620 - 360 = 260 m imo , answer b" | physics |
math_qa__Nne6C53M7jGduFzQ | WINK, Inc. follows a certain procedure that requires two tasks to be finished independently in order for a job to be done. On any given day, there is a 5/8 probability that task 1 will be completed on time, and a 3/5 probability that task 2 will be completed on time. On a certain day, what is the probability that task 1 will be completed on time, but task 2 will not?
Choose the correct choice from the following answers
A) 1 / 4 B) 3 / 40 C) 13 / 40 D) 7 / 20 E) 13 / 22 | <gadget id="calculator">5 / 8</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(5/8) * (2/5)</gadget>
<output>1/4 = around 0.25</output>
<result>A</result> | A | 0.25 | WINK, Inc. follows a certain procedure that requires two tasks to be finished independently in order for a job to be done. On any given day, there is a 5/8 probability that task 1 will be completed on time, and a 3/5 probability that task 2 will be completed on time. On a certain day, what is the probability that task 1 will be completed on time, but task 2 will not? | {
"A": "1 / 4",
"B": "3 / 40",
"C": "13 / 40",
"D": "7 / 20",
"E": "13 / 22"
} | multiply(divide(5, 8), subtract(const_1, divide(3, 5))) | divide(n0,n1)|divide(n3,n0)|subtract(const_1,#1)|multiply(#0,#2) | p ( 1 and not 2 ) = 5 / 8 * ( 1 - 3 / 5 ) = 1 / 4 answer : a . | probability |
math_qa__cKfgjTQDp7L2Wx0O | Joe’s average (arithmetic mean) test score across 4 equally weighted tests was 35. He was allowed to drop his lowest score. After doing so, his average test score improved to 40. What is the lowest test score that was dropped?
Choose the correct choice from the following options:
A) 20 B) 25 C) 55 D) 65 E) 80 | <gadget id="calculator">35 * 4</gadget>
<output>140</output>
<gadget id="calculator">40 * 3</gadget>
<output>120</output>
<gadget id="calculator">140 - 120</gadget>
<output>20</output>
<result>A</result> | A | 20 | Joe’s average (arithmetic mean) test score across 4 equally weighted tests was 35. He was allowed to drop his lowest score. After doing so, his average test score improved to 40. What is the lowest test score that was dropped? | {
"A": "20",
"B": "25",
"C": "55",
"D": "65",
"E": "80"
} | subtract(multiply(35, 4), multiply(40, const_3)) | multiply(n0,n1)|multiply(n2,const_3)|subtract(#0,#1) | the arithmetic mean of 4 equally weighted tests was 35 . so what we can assume is that we have 4 test scores , each 35 . he dropped his lowest score and the avg went to 40 . this means that the lowest score was not 35 and other three scores had given the lowest score 5 each to make it up to 35 too . when the lowest score was removed , the other 3 scores got their 5 back . so the lowest score was 3 * 5 = 15 less than 35 . so the lowest score = 35 - 15 = 20 answer ( a ) | general |
math_qa__BxWdajrg1zThc1Y5 | There is food for 760 men for 22 days. How many more men should join after two days so that the same food may last for 10 days more? Choose the correct choice from the following answers: A) 220 B) 760 C) 990 D) 880 E) 660 | <gadget id="calculator">22 - 2</gadget>
<output>20</output>
<gadget id="calculator">760 * 20</gadget>
<output>15_200</output>
<gadget id="calculator">15_200 / 10</gadget>
<output>1_520</output>
<gadget id="calculator">1_520 - 760</gadget>
<output>760</output>
<result>B</result> | B | 760 | There is food for 760 men for 22 days. How many more men should join after two days so that the same food may last for 10 days more? | {
"A": "220",
"B": "760",
"C": "990",
"D": "880",
"E": "660"
} | subtract(divide(multiply(760, subtract(22, const_2)), 10), 760) | subtract(n1,const_2)|multiply(n0,#0)|divide(#1,n2)|subtract(#2,n0)| | "760 - - - - 22 760 - - - - 20 x - - - - - 10 x * 10 = 760 * 20 x = 1520 760 - - - - - - - 760 answer : b" | physics |
math_qa__jwRQjHt7ra3lu1rN | The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 15 metres?
Select
A) 5 B) 10 C) 3 D) 12 E) 6 | <gadget id="calculator">15 + 3</gadget>
<output>18</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">18 * (5/18)</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<result>C</result> | C | 3 | The speed at which a man can row a boat in still water is 15 kmph. If he rows downstream, where the speed of current is 3 kmph, what time will he take to cover 15 metres? | {
"A": "5",
"B": "10",
"C": "3",
"D": "12",
"E": "6"
} | divide(15, multiply(add(15, 3), const_0_2778)) | add(n0,n1)|multiply(#0,const_0_2778)|divide(n2,#1)| | "speed of the boat downstream = 15 + 3 = 18 kmph = 18 * 5 / 18 = 5 m / s hence time taken to cover 60 m = 15 / 5 = 3 seconds . answer : c" | physics |
math_qa__b6OCB8RANmCALHR1 | A dishonest dealer professes to sell goods at the cost price but uses a weight of 723 grams per kg, what is his percent? Choose the correct option:
A) 38.3 %
B) 25 %
C) 77 %
D) 99 %
E) 12 % | <gadget id="calculator">100 / 723</gadget>
<output>100/723 = around 0.138313</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">(100/723) * 1_000</gadget>
<output>100_000/723 = around 138.312586</output>
<gadget id="calculator">(100_000/723) - 100</gadget>
<output>27_700/723 = around 38.312586</output>
<result>A</result> | A | 38.3 | A dishonest dealer professes to sell goods at the cost price but uses a weight of 723 grams per kg, what is his percent? | {
"A": "38.3 %",
"B": "25 %",
"C": "77 %",
"D": "99 %",
"E": "12 %"
} | subtract(multiply(divide(const_100, 723), multiply(const_100, multiply(add(const_3, const_2), const_2))), const_100) | add(const_2,const_3)|divide(const_100,n0)|multiply(#0,const_2)|multiply(#2,const_100)|multiply(#1,#3)|subtract(#4,const_100)| | "723 - - - 277 100 - - - ? = > 38.3 % answer : a" | gain |
math_qa__YVfiouFl7rI19R6D | An error 4% in excess is made while measuring the side of a square. What is the percentage of error in the calculated area of the square? Choose the correct choice from the following answers.
A) 4.05 % B) 4.02 % C) 8.16 % D) 3 % E) 2 % | <gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">104 ** 2</gadget>
<output>10_816</output>
<gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">10_816 - 10_000</gadget>
<output>816</output>
<gadget id="calculator">816 * 100</gadget>
<output>81_600</output>
<gadget id="calculator">81_600 / 10_000</gadget>
<output>204/25 = around 8.16</output>
<result>C</result> | C | 8.16 | An error 4% in excess is made while measuring the side of a square. What is the percentage of error in the calculated area of the square? | {
"A": "4.05 %",
"B": "4.02 %",
"C": "8.16 %",
"D": "3 %",
"E": "2 %"
} | divide(multiply(subtract(square_area(add(const_100, 4)), square_area(const_100)), const_100), square_area(const_100)) | add(n0,const_100)|square_area(const_100)|square_area(#0)|subtract(#2,#1)|multiply(#3,const_100)|divide(#4,#1)| | "percentage error in calculated area = ( 4 + 4 + ( 4 ã — 4 ) / 100 ) % = 8.16 % answer : c" | gain |
math_qa__CwxH5jKxizHspGam | If the ratio of apples to bananas is 4 to 3 and the ratio of bananas to cucumbers is 1 to 5, what is the ratio of apples to cucumbers? Choose one: A) 4 : 15 B) 1 : 3 C) 2 : 5 D) 4 : 5 E) 7 : 6 | <gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) / 5</gadget>
<output>4/15 = around 0.266667</output>
<result>A</result> | A | 0.266667 | If the ratio of apples to bananas is 4 to 3 and the ratio of bananas to cucumbers is 1 to 5, what is the ratio of apples to cucumbers? | {
"A": "4 : 15",
"B": "1 : 3",
"C": "2 : 5",
"D": "4 : 5",
"E": "7 : 6"
} | divide(divide(4, 3), 5) | divide(n0,n1)|divide(#0,n3)| | "apples : bananas = 4 : 3 bananas : cucumbers = 1 : 5 = 3 : 15 so if i have bananas , i ' d have 4 apples and 15 cucumbers apples : cucumbers = 4 : 15 answer : a" | other |
math_qa__lXos5EC5WSn3Ix8h | P alone can complete a job in 4 days. The work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together? Choose the correct choice from the following choices.
A) 1.5 B) 2.0 C) 2.5 D) 3.0 E) 3.5 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) / 3</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/4) + (1/12)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / (1/3)</gadget>
<output>3</output>
<result>D</result> | D | 3 | P alone can complete a job in 4 days. The work done by Q alone in one day is equal to one-third of the work done by P alone in one day. In how many days can the work be completed if P and Q work together? | {
"A": "1.5",
"B": "2.0",
"C": "2.5",
"D": "3.0",
"E": "3.5"
} | divide(const_1, add(divide(const_1, 4), divide(divide(const_1, 4), const_3))) | divide(const_1,n0)|divide(#0,const_3)|add(#0,#1)|divide(const_1,#2) | p ' s rate is 1 / 4 q ' s rate is 1 / 12 the combined rate is 1 / 4 + 1 / 12 = 1 / 3 if they work together , the job will take 3 days . the answer is d . | physics |
math_qa__jWRkPtU76qDHPHdP | A man's speed with the current is 12 km/hr and the speed of the current is 2 km/hr. The man's speed against the current is Choose the correct choice from the following choices
A) 8 B) 10 C) 11 D) 12 E) 13 | <gadget id="calculator">12 - 2</gadget>
<output>10</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<result>A</result> | A | 8 | A man's speed with the current is 12 km/hr and the speed of the current is 2 km/hr. The man's speed against the current is | {
"A": "8",
"B": "10",
"C": "11",
"D": "12",
"E": "13"
} | subtract(subtract(12, 2), 2) | subtract(n0,n1)|subtract(#0,n1)| | "man ' s rate in still water = ( 12 - 2 ) km / hr = 10 km / hr . man ' s rate against the current = ( 10 - 2 ) km / hr = 8 km / hr . answer : a" | gain |
math_qa__U1A62CseHg30IlFI | In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the rate in the remaining 40 overs to reach the target of 242 runs? Choose the correct choice from the following answers: A) 6.25 B) 5.25 C) 6.29 D) 6.39 E) 6.13 | <gadget id="calculator">10 * 3.2</gadget>
<output>32</output>
<gadget id="calculator">242 - 32</gadget>
<output>210</output>
<gadget id="calculator">210 / 40</gadget>
<output>21/4 = around 5.25</output>
<result>B</result> | B | 5.25 | In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the rate in the remaining 40 overs to reach the target of 242 runs? | {
"A": "6.25",
"B": "5.25",
"C": "6.29",
"D": "6.39",
"E": "6.13"
} | divide(subtract(242, multiply(10, 3.2)), 40) | multiply(n0,n1)|subtract(n3,#0)|divide(#1,n2)| | "required run rate = [ 242 - ( 3.2 * 10 ) ] / 40 = 210 / 40 = 5.25 answer : b" | gain |
math_qa__53qyrXGySVYrc0rd | How many positive integers less than 5,000 are there in which the sum of the digits equals 5? Choose the correct choice from the following answers.
A) 64 B) 62 C) 63 D) 61 E) 56 | <gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">120 * 6</gadget>
<output>720</output>
<gadget id="calculator">40_320 / 720</gadget>
<output>56</output>
<result>E</result> | E | 56 | How many positive integers less than 5,000 are there in which the sum of the digits equals 5? | {
"A": "64",
"B": "62",
"C": "63",
"D": "61",
"E": "56"
} | divide(factorial(subtract(add(const_4, 5), const_1)), multiply(factorial(5), factorial(subtract(const_4, const_1)))) | add(n1,const_4)|factorial(n1)|subtract(const_4,const_1)|factorial(#2)|subtract(#0,const_1)|factorial(#4)|multiply(#1,#3)|divide(#5,#6)| | "basically , the question asks how many 4 digit numbers ( including those in the form 0 xxx , 00 xx , and 000 x ) have digits which add up to 5 . think about the question this way : we know that there is a total of 5 to be spread among the 4 digits , we just have to determine the number of ways it can be spread . let x represent a sum of 1 , and | represent a seperator between two digits . as a result , we will have 5 x ' s ( digits add up to the 5 ) , and 3 | ' s ( 3 digit seperators ) . so , for example : xx | x | x | x = 2111 | | xxx | xx = 0032 etc . there are 8 c 3 ways to determine where to place the separators . hence , the answer is 8 c 3 = 56 . e" | general |
math_qa__ktTKvItZH2n5kd2T | What is the rate percent when the simple interest on Rs.5000 amount to Rs.2500 in 5 Years? Choose the correct choice: A) 9 % B) 8 % C) 10 % D) 10.5 % E) 7.5 % | <gadget id="calculator">100 * 2_500</gadget>
<output>250_000</output>
<gadget id="calculator">5_000 * 5</gadget>
<output>25_000</output>
<gadget id="calculator">250_000 / 25_000</gadget>
<output>10</output>
<result>C</result> | C | 10 | What is the rate percent when the simple interest on Rs.5000 amount to Rs.2500 in 5 Years? | {
"A": "9 %",
"B": "8 %",
"C": "10 %",
"D": "10.5 %",
"E": "7.5 %"
} | divide(multiply(const_100, 2500), multiply(5000, 5)) | multiply(n1,const_100)|multiply(n0,n2)|divide(#0,#1)| | "interest for 1 year = 2500 / 5 = 500 interest on rs 5000 p / a = 500 interest rate = 500 / 5000 * 100 = 10 % answer : c" | gain |
math_qa__tI9YG4yQgCRlQdSP | On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction Q of the total distance did he cover while the sun was shining on him? Choose the correct choice from the following options:
A) 1 / 4
B) 4 / 5
C) 1 / 5
D) 1 / 6
E) 1 / 7 | <gadget id="calculator">lcm(2, 3)</gadget>
<output>6</output>
<gadget id="calculator">6 / 2.8</gadget>
<output>2.142857</output>
<gadget id="calculator">2.142857 - 2</gadget>
<output>0.142857</output>
<result>E</result> | E | 0.142857 | On a partly cloudy day, Derek decides to walk back from work. When it is sunny, he walks at a speed of s miles/hr (s is an integer) and when it gets cloudy, he increases his speed to (s + 1) miles/hr. If his average speed for the entire distance is 2.8 miles/hr, what fraction Q of the total distance did he cover while the sun was shining on him? | {
"A": "1 / 4",
"B": "4 / 5",
"C": "1 / 5",
"D": "1 / 6",
"E": "1 / 7"
} | subtract(divide(lcm(const_2, const_3), 2.8), const_2) | lcm(const_2,const_3)|divide(#0,n1)|subtract(#1,const_2)| | if s is an integer and we know that the average speed is 2.8 , s must be = 2 . that meanss + 1 = 3 . this implies that the ratio of time for s = 2 is 1 / 4 of the total time . the formula for distance / rate is d = rt . . . so the distance travelled when s = 2 is 2 t . the distance travelled for s + 1 = 3 is 3 * 4 t or 12 t . therefore , total distance covered while the sun was shining over him is q = 2 / 14 = 1 / 7 . answer : e | general |
math_qa__PDgyraFSCWBE6TL6 | Given the two equations 3x + 2y = 16 and 5x + 3y = 26, by how much does r exceed s? Select the correct option: A) 3 B) 4 C) 5 D) 1 E) 2 | <gadget id="calculator">16 * 2</gadget>
<output>32</output>
<gadget id="calculator">32 / 16</gadget>
<output>2</output>
<result>E</result> | E | 2 | Given the two equations 3x + 2y = 16 and 5x + 3y = 26, by how much does r exceed s? | {
"A": "3",
"B": "4",
"C": "5",
"D": "1",
"E": "2"
} | divide(multiply(16, 2), 16) | multiply(n1,n2)|divide(#0,n2) | solve by simultaneous equations . my answer is e . x = 4 y = 2 | general |
math_qa__N4loMKMVGELEUzhv | The parameter of a square is equal to the perimeter of a rectangle of length 18 cm and breadth 10 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)? Choose the correct choice from the following answers:
A) 22.51
B) 22.0
C) 22.15
D) 22.17
E) 22.63 | <gadget id="calculator">2 * (18 + 10)</gadget>
<output>56</output>
<gadget id="calculator">56 / 4</gadget>
<output>14</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<gadget id="calculator">2 * pi * 7</gadget>
<output>14*pi = around 43.982297</output>
<gadget id="calculator">(14*pi) / 2</gadget>
<output>7*pi = around 21.991149</output>
<result>B</result> | B | 22 | The parameter of a square is equal to the perimeter of a rectangle of length 18 cm and breadth 10 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)? | {
"A": "22.51",
"B": "22.0",
"C": "22.15",
"D": "22.17",
"E": "22.63"
} | divide(circumface(divide(square_edge_by_perimeter(rectangle_perimeter(18, 10)), const_2)), const_2) | rectangle_perimeter(n0,n1)|square_edge_by_perimeter(#0)|divide(#1,const_2)|circumface(#2)|divide(#3,const_2)| | "let the side of the square be a cm . parameter of the rectangle = 2 ( 18 + 10 ) = 56 cm parameter of the square = 56 cm i . e . 4 a = 56 a = 14 diameter of the semicircle = 15 cm circimference of the semicircle = 1 / 2 ( â ˆ ) ( 14 ) = 1 / 2 ( 22 / 7 ) ( 14 ) = 308 / 14 = 22 cm to two decimal places answer : b" | geometry |
math_qa__A7mdFo208i6pTrHh | How many integers are divisible by 5 between 10! and 10! + 20 inclusive? Choose the correct choice from the following answers:
A) 5
B) 7
C) 8
D) 9
E) 10 | <gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<result>A</result> | A | 5 | How many integers are divisible by 5 between 10! and 10! + 20 inclusive? | {
"A": "5",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | add(divide(20, 5), const_1) | divide(n3,n0)|add(#0,const_1) | a - 7 10 ! is divisible by 5 there are 4 numbers between 10 ! and 10 ! + 20 that are divisible by 5 . hence 5 | general |
math_qa__LtHsRHzUAtEMwAZM | If 11.25 m of a uniform steel rod weighs 42.75 kg. what will be the weight of 9 m of the same rod? Choose the correct answer.
A) 22.8 kg
B) 34.2 kg
C) 28 kg
D) 26.5 kg
E) none of these | <gadget id="calculator">9 * 42.75</gadget>
<output>384.75</output>
<gadget id="calculator">384.75 / 11.25</gadget>
<output>34.2</output>
<result>B</result> | B | 34.2 | If 11.25 m of a uniform steel rod weighs 42.75 kg. what will be the weight of 9 m of the same rod? | {
"A": "22.8 kg",
"B": "34.2 kg",
"C": "28 kg",
"D": "26.5 kg",
"E": "none of these"
} | divide(multiply(9, 42.75), 11.25) | multiply(n1,n2)|divide(#0,n0)| | "explanation : let the required weight be x kg . then , less length , less weight ( direct proportion ) = > 11.25 : 9 : : 42.75 : x = > 11.25 x x = 9 x 42.75 = > x = ( 9 x 42.75 ) / 11.25 = > x = 34.2 answer : b" | physics |
math_qa__QtWYQod2XXfabXuQ | If paint costs $3.20 per quart, and a quart covers 120 square feet, how much will it cost to paint the outside of a cube 10 feet on each edge?
Choose the correct choice
A) $ 1.60
B) $ 16.00
C) $ 96.00
D) $ 108.00
E) $ 196.00 | <gadget id="calculator">3.2 / 120</gadget>
<output>0.026667</output>
<gadget id="calculator">6 * (10 ** 2)</gadget>
<output>600</output>
<gadget id="calculator">0.026667 * 600</gadget>
<output>16.0002</output>
<result>B</result> | B | 16 | If paint costs $3.20 per quart, and a quart covers 120 square feet, how much will it cost to paint the outside of a cube 10 feet on each edge? | {
"A": "$ 1.60",
"B": "$ 16.00",
"C": "$ 96.00",
"D": "$ 108.00",
"E": "$ 196.00"
} | multiply(divide(3.20, 120), surface_cube(10)) | divide(n0,n1)|surface_cube(n2)|multiply(#0,#1)| | "total surface area = 6 a ^ 2 = 6 * 10 * 10 = 600 each quart covers 20 sqr ft thus total number of quarts = 600 / 120 = 5 cost will be 5 * 3.2 = $ 16 ans : b" | geometry |
math_qa__Eq4jLW9veMcpeZSk | If 3/p=6 & 3/q=18 then p-q=? Choose the correct choice from the following answers
A) 5 / 24 B) 6 / 24 C) 7 / 24 D) 8 / 24 E) 1 / 3 | <gadget id="calculator">3 / 6</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 / 18</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/2) - (1/6)</gadget>
<output>1/3 = around 0.333333</output>
<result>E</result> | E | 0.333333 | If 3/p=6 & 3/q=18 then p-q=? | {
"A": "5 / 24",
"B": "6 / 24",
"C": "7 / 24",
"D": "8 / 24",
"E": "1 / 3"
} | subtract(divide(3, 6), divide(3, 18)) | divide(n0,n1)|divide(n0,n3)|subtract(#0,#1)| | "p = 3 / 6 , q = 3 / 18 = > q = 1 / 6 therefore p - q = ( 1 / 2 ) - ( 1 / 6 ) = 1 / 3 answer : e" | general |
math_qa__NnKrUqIieaAqoR7E | Two trains 150 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is?
Choices.
A) 10.16 sec B) 18.8 sec C) 14.8 sec D) 10.8 sec E) 11.16 sec | <gadget id="calculator">150 + 160</gadget>
<output>310</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">310 / (250/9)</gadget>
<output>279/25 = around 11.16</output>
<result>E</result> | E | 11.16 | Two trains 150 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? | {
"A": "10.16 sec",
"B": "18.8 sec",
"C": "14.8 sec",
"D": "10.8 sec",
"E": "11.16 sec"
} | divide(add(150, 160), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = 60 + 40 = 100 km / hr . = 100 * 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = 150 + 160 = 310 m . required time = 310 * 9 / 250 = 279 / 25 = 11.16 sec . answer : e" | physics |
math_qa__YY9skwbfkCD79VfQ | A company that ships boxes to a total of 12 distribution centers uses color coding to identify each center. If either a single color or a pair of two different colors is chosen to represent each center and if each center is uniquely represented by that choice of one or two colors, what is the minimum number of colors needed for the coding? (assume that the order of colors in a pair does not matter) Choose one
A) 4 B) 5 C) 6 D) 12 E) 24 | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">120 / 12</gadget>
<output>10</output>
<gadget id="calculator">10 - 5</gadget>
<output>5</output>
<result>B</result> | B | 5 | A company that ships boxes to a total of 12 distribution centers uses color coding to identify each center. If either a single color or a pair of two different colors is chosen to represent each center and if each center is uniquely represented by that choice of one or two colors, what is the minimum number of colors needed for the coding? (assume that the order of colors in a pair does not matter) | {
"A": "4",
"B": "5",
"C": "6",
"D": "12",
"E": "24"
} | subtract(divide(factorial(subtract(divide(12, const_2), const_1)), multiply(factorial(const_3), factorial(const_2))), subtract(divide(12, const_2), const_1)) | divide(n0,const_2)|factorial(const_3)|factorial(const_2)|multiply(#1,#2)|subtract(#0,const_1)|factorial(#4)|divide(#5,#3)|subtract(#6,#4) | let # of colors needed be nn , then it must be true that n + c 2 n ≥ 12 n + cn 2 - # of ways to choose the pair of different colors from nn colors when order does n ' t matter ) - - > n + n ( n − 1 ) / 2 ≥ 12 - - > 2 n + n ( n − 1 ) ≥ 24 - - > n is an integer ( it represents # of colors ) n ≥ 5 - - > nmin = 5 answer : b . | general |
math_qa__gezqSBrhidy5GmwX | the average of 5 numbers is 27 . if one number is excluded the average become 25 . the excluded number is : Choose the correct choice from the following answers
A) 25
B) 27
C) 30
D) 35
E) 37 | <gadget id="calculator">5 * 27</gadget>
<output>135</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">4 * 25</gadget>
<output>100</output>
<gadget id="calculator">135 - 100</gadget>
<output>35</output>
<result>D</result> | D | 35 | the average of 5 numbers is 27 . if one number is excluded the average become 25 . the excluded number is : | {
"A": "25",
"B": "27",
"C": "30",
"D": "35",
"E": "37"
} | subtract(multiply(5, 27), multiply(subtract(5, const_1), 25)) | multiply(n0,n1)|subtract(n0,const_1)|multiply(n2,#1)|subtract(#0,#2) | solution excluded number = ( 27 × 5 ) - ( 25 × 4 ) = 135 - 100 = 35 . answer d | general |
math_qa__UDiaRa0WpgnocObe | A train 200 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Choose the most appropriate option: A) 11 B) 10 C) 5 D) 9 E) 8 | <gadget id="calculator">200 / 1_000</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">60 + 6</gadget>
<output>66</output>
<gadget id="calculator">(1/5) / 66</gadget>
<output>1/330 = around 0.00303</output>
<gadget id="calculator">3_600 * (1/330)</gadget>
<output>120/11 = around 10.909091</output>
<result>A</result> | A | 11 | A train 200 meters long is running with a speed of 60 kmph. In what time will it pass a man who is running at 6 kmph in the direction opposite to that in which the train is going? | {
"A": "11",
"B": "10",
"C": "5",
"D": "9",
"E": "8"
} | multiply(const_3600, divide(divide(200, const_1000), add(60, 6))) | add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_3600)| | "speed of train relative to man = ( 60 + 6 ) km / hr = 66 km / hr [ 66 * 5 / 18 ] m / sec = [ 55 / 3 ] m / sec . time taken to pass the man = [ 200 * 3 / 55 ] sec = 11 sec answer : a" | physics |
math_qa__PcjVF2GZEZn8ByJP | A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9% p.a. in 5 years. What is the sum? Choose the correct choice from the following:
A) 3888
B) 2988
C) 2777
D) 8925
E) 288 | <gadget id="calculator">4_016.25 * 100</gadget>
<output>401_625</output>
<gadget id="calculator">401_625 / 9</gadget>
<output>44_625</output>
<gadget id="calculator">44_625 / 5</gadget>
<output>8_925</output>
<result>D</result> | D | 8,925 | A sum fetched a total simple interest of Rs. 4016.25 at the rate of 9% p.a. in 5 years. What is the sum? | {
"A": "3888",
"B": "2988",
"C": "2777",
"D": "8925",
"E": "288"
} | divide(divide(multiply(4016.25, const_100), 9), 5) | multiply(n0,const_100)|divide(#0,n1)|divide(#1,n2)| | principal = ( 100 * 4016.25 ) / ( 9 * 5 ) = rs . 8925 . answer : d | gain |
math_qa__3hZOrETNkFLgVuza | The captain of a cricket team of 11 members is 24 years old and the wicket keeper is 7 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team? Choose the correct choice from the following answers.
A) 21
B) 22
C) 23
D) 24
E) 25 | <gadget id="calculator">24 + 7</gadget>
<output>31</output>
<gadget id="calculator">24 + 31</gadget>
<output>55</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">55 - 9</gadget>
<output>46</output>
<gadget id="calculator">46 / 2</gadget>
<output>23</output>
<result>C</result> | C | 23 | The captain of a cricket team of 11 members is 24 years old and the wicket keeper is 7 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team? | {
"A": "21",
"B": "22",
"C": "23",
"D": "24",
"E": "25"
} | divide(subtract(add(24, add(24, 7)), multiply(const_3.0, const_3.0)), const_2) | add(n1,n2)|multiply(const_3.0,const_3.0)|add(n1,#0)|subtract(#2,#1)|divide(#3,const_2)| | "let the average age of the whole team be x years . 11 x - ( 24 + 31 ) = 9 ( x - 1 ) 11 x - 9 x = 46 2 x = 46 x = 23 . the average age of the team is 23 years . the answer is c ." | general |
math_qa__U2nqkktigBG8Oh4V | In a box of 16 pens, a total of 3 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?
Select:
A) 1 / 6
B) 2 / 9
C) 6 / 20
D) 13 / 20
E) 3 / 4 | <gadget id="calculator">16 - 3</gadget>
<output>13</output>
<gadget id="calculator">13 / 16</gadget>
<output>13/16 = around 0.8125</output>
<gadget id="calculator">13 - 1</gadget>
<output>12</output>
<gadget id="calculator">16 - 1</gadget>
<output>15</output>
<gadget id="calculator">12 / 15</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(13/16) * (4/5)</gadget>
<output>13/20 = around 0.65</output>
<result>D</result> | D | 0.65 | In a box of 16 pens, a total of 3 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective? | {
"A": "1 / 6",
"B": "2 / 9",
"C": "6 / 20",
"D": "13 / 20",
"E": "3 / 4"
} | multiply(divide(subtract(16, 3), 16), divide(subtract(subtract(16, 3), const_1), subtract(16, const_1))) | subtract(n0,n1)|subtract(n0,const_1)|divide(#0,n0)|subtract(#0,const_1)|divide(#3,#1)|multiply(#2,#4)| | "method - 1 there are 9 fine pieces of pen and 3 defective in a lot of 16 pens i . e . probability of first pen not being defective = ( 13 / 16 ) i . e . probability of second pen not being defective = ( 12 / 15 ) [ 15 pen remaining with 12 defective remaining considering that first was defective ] probability of both pen being non - defective = ( 12 / 15 ) * ( 13 / 16 ) = 13 / 20 answer : option d" | general |
math_qa__sOKSLD8B4nS7xgTH | during a pizza buffet where a eats more times 2.6 than b , and b eats 4 times less than c . find the least number of times all the 3 has to eat Choose the correct choice from the following answers: A) 250 B) 260 C) 270 D) 280 E) 285 | <gadget id="calculator">2.6 * 10</gadget>
<output>26</output>
<gadget id="calculator">26 / 2</gadget>
<output>13</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">lcm(13, 20)</gadget>
<output>260</output>
<result>B</result> | B | 260 | during a pizza buffet where a eats more times 2.6 than b , and b eats 4 times less than c . find the least number of times all the 3 has to eat | {
"A": "250",
"B": "260",
"C": "270",
"D": "280",
"E": "285"
} | lcm(divide(multiply(2.6, const_10), const_2), divide(multiply(4, const_10), const_2)) | multiply(n0,const_10)|multiply(n1,const_10)|divide(#0,const_2)|divide(#1,const_2)|lcm(#2,#3) | a eats more than b if b eats 1 times than the ratio of a and b is a : b is 2.6 : 1 or 13 : 5 and as b eat 4 times less the c the the ratio of b : c is 5 : 20 the the least number of times all three has eat is the lcm of a , b , c that is 260 . . answer : b | general |
math_qa__knB8jlVGZFvpc2we | If the mean of numbers 28, x, 42, 78 and 104 is 62, what is the mean of 48, 62, 98, 124 and x? Choices: A) 78 B) 58 C) 390 D) 310 E) 66 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">62 * 5</gadget>
<output>310</output>
<gadget id="calculator">28 + 42</gadget>
<output>70</output>
<gadget id="calculator">70 + 78</gadget>
<output>148</output>
<gadget id="calculator">148 + 104</gadget>
<output>252</output>
<gadget id="calculator">310 - 252</gadget>
<output>58</output>
<gadget id="calculator">58 + 48</gadget>
<output>106</output>
<gadget id="calculator">106 + 62</gadget>
<output>168</output>
<gadget id="calculator">168 + 98</gadget>
<output>266</output>
<gadget id="calculator">266 + 124</gadget>
<output>390</output>
<gadget id="calculator">390 / 5</gadget>
<output>78</output>
<result>A</result> | A | 78 | If the mean of numbers 28, x, 42, 78 and 104 is 62, what is the mean of 48, 62, 98, 124 and x? | {
"A": "78",
"B": "58",
"C": "390",
"D": "310",
"E": "66"
} | divide(add(add(add(add(subtract(multiply(62, add(const_4, const_1)), add(add(add(28, 42), 78), 104)), 48), 62), 98), 124), add(const_4, const_1)) | add(const_1,const_4)|add(n0,n1)|add(n2,#1)|multiply(n4,#0)|add(n3,#2)|subtract(#3,#4)|add(n5,#5)|add(n6,#6)|add(n7,#7)|add(n8,#8)|divide(#9,#0)| | "x is common to both the series . so , x is not going to make a difference to the average . only the remaining 4 numbers will contribute to the difference in average between the two series . sum of the 4 numbers , excluding x , of the first series is 28 + 42 + 78 + 104 = 252 sum of the 4 numbers , excluding x , of the second series is 48 + 62 + 98 + 124 = 332 the difference between the sum of the two sets of numbers = 332 - 252 = 80 the sum of the second series is 80 more than the sum of the first series . if the sum of the second series is 80 more , the average of the second series will be 80 / 5 = 16 more than the first series . therefore , the average of the second series = 62 + 16 = 78 . answer a" | general |
math_qa__e1kjuVne8TXHEeTp | Company P had 15 percent more employees in December than it had in January. If Company P had 450 employees in December, how many employees did it have in January? Choose the correct choice from the following.
A) 391 B) 392 C) 410 D) 423 E) 445 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">450 / (23/20)</gadget>
<output>9_000/23 = around 391.304348</output>
<result>B</result> | B | 392 | Company P had 15 percent more employees in December than it had in January. If Company P had 450 employees in December, how many employees did it have in January? | {
"A": "391",
"B": "392",
"C": "410",
"D": "423",
"E": "445"
} | divide(450, add(const_1, divide(15, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "d = number of employees in december j = number of employees in january j x 1.15 = d j x 1.15 = 450 j = 450 / 1.15 j = 45,000 / 115 = 392 thus b is the correct answer ." | gain |
math_qa__sXI8OnLB1VUDQ84T | Salley's internet provider offers unlimited traffic which costs $0.5 per day charged off at 12 a.m. The service is discontinued when client's debt exceeds $5. If today in the morning Salley makes a payment of $7, for how many days, including today, will she be connected to the internet without any additional payments, given her initial balance was $0?
Select: A) 15 B) 24 C) 25 D) 26 E) 13 | <gadget id="calculator">7 + 5</gadget>
<output>12</output>
<gadget id="calculator">12 / 0.5</gadget>
<output>24</output>
<result>C</result> | C | 25 | Salley's internet provider offers unlimited traffic which costs $0.5 per day charged off at 12 a.m. The service is discontinued when client's debt exceeds $5. If today in the morning Salley makes a payment of $7, for how many days, including today, will she be connected to the internet without any additional payments, given her initial balance was $0? | {
"A": "15",
"B": "24",
"C": "25",
"D": "26",
"E": "13"
} | divide(add(7, 5), 0.5) | add(n2,n3)|divide(#0,n0) | day 0 - payment of $ 7 is made in the morning ( after 12 am midnight ) day 1 onwards ( after 12 am midnight ) internet service will begin and will run for 7 * 2 = 14 days i . e . at the end of day 15 balance will be zero . now salley can still use the internet till her debt reaches $ 5 which means total of 5 * 2 = 10 days . now the question states for how many days , including today , will she be connected to the internet without any additional paymentsi . e . we will have to include day 0 also in our final answer . therefore total no . of days = 1 + 14 + 10 = 25 = c | physics |
math_qa__zkItkbMVoF9xy79S | 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.150 only. Men’s wages are? Choose the correct choice from the following answers
A) 6 rs B) 2 rs C) 4 rs D) 9 rs E) 10 rs | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">150 / 15</gadget>
<output>10</output>
<result>E</result> | E | 10 | 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.150 only. Men’s wages are? | {
"A": "6 rs",
"B": "2 rs",
"C": "4 rs",
"D": "9 rs",
"E": "10 rs"
} | divide(150, multiply(const_3, 5)) | multiply(n0,const_3)|divide(n2,#0)| | "5 m = xw = 8 b 5 m + xw + 8 b - - - - - 150 rs . 5 m + 5 m + 5 m - - - - - 150 rs . 15 m - - - - - - 150 rs . = > 1 m = 10 rs . answer : e" | general |
math_qa__HCEHdCuCUvmU0vhx | If a: b :: 3 : 4, then what is (5a+6b): (a-2b)? Choose the correct answer: A) 57 : 11 B) - 57 : 11 C) 11 : 10 D) - 39 : 5 E) - 1 : 10 | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">15 + 24</gadget>
<output>39</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">3 - 8</gadget>
<output>-5</output>
<gadget id="calculator">39 / (-5)</gadget>
<output>-39/5 = around -7.8</output>
<result>D</result> | D | -7.8 | If a: b :: 3 : 4, then what is (5a+6b): (a-2b)? | {
"A": "57 : 11",
"B": "- 57 : 11",
"C": "11 : 10",
"D": "- 39 : 5",
"E": "- 1 : 10"
} | divide(add(multiply(5, 3), multiply(4, 6)), subtract(3, multiply(2, 4))) | multiply(n0,n2)|multiply(n1,n3)|multiply(n1,n4)|add(#0,#1)|subtract(n0,#2)|divide(#3,#4)| | "a / b = 3 / 4 dividing numerator & denominator of ' ( 5 a + 6 b ) / ( a - 2 b ) ' by b , [ 5 ( a / b ) + 6 ] / [ ( a / b ) - 2 ] = [ 5 * ( 3 / 4 ) + 6 ] / [ ( 3 / 4 ) - 2 ] = - 39 / 5 answer : d" | general |
math_qa__2g38X2EUTOiEGh4g | Two trains of length 160 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? Pick one:
A) 28 B) 266 C) 990 D) 20 E) 22 | <gadget id="calculator">160 + 280</gadget>
<output>440</output>
<gadget id="calculator">42 + 30</gadget>
<output>72</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">72 * (5/18)</gadget>
<output>20</output>
<gadget id="calculator">440 / 20</gadget>
<output>22</output>
<result>E</result> | E | 22 | Two trains of length 160 m and 280 m are running towards each other on parallel lines at 42 kmph and 30 kmph respectively. In what time will they be clear of each other from the moment they meet? | {
"A": "28",
"B": "266",
"C": "990",
"D": "20",
"E": "22"
} | divide(add(160, 280), multiply(add(42, 30), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = ( 42 + 30 ) * 5 / 18 = 4 * 5 = 20 mps . distance covered in passing each other = 160 + 280 = 440 m . the time required = d / s = 440 / 20 = 22 sec . answer : e" | physics |
math_qa__ELHcKFZ4gAiEDNOh | The parameter of a square is equal to the perimeter of a rectangle of length 20 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)
Choose the correct choice.
A) 77.14 cm
B) 47.14 cm
C) 26.71 cm
D) 94.94 cm
E) 23.57 cm | <gadget id="calculator">2 * (20 + 14)</gadget>
<output>68</output>
<gadget id="calculator">68 / 4</gadget>
<output>17</output>
<gadget id="calculator">17 / 2</gadget>
<output>17/2 = around 8.5</output>
<gadget id="calculator">2 * pi * (17/2)</gadget>
<output>17*pi = around 53.407075</output>
<gadget id="calculator">(17*pi) / 2</gadget>
<output>17*pi/2 = around 26.703538</output>
<result>C</result> | C | 26.71 | The parameter of a square is equal to the perimeter of a rectangle of length 20 cm and breadth 14 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places) | {
"A": "77.14 cm",
"B": "47.14 cm",
"C": "26.71 cm",
"D": "94.94 cm",
"E": "23.57 cm"
} | divide(circumface(divide(square_edge_by_perimeter(rectangle_perimeter(20, 14)), const_2)), const_2) | rectangle_perimeter(n0,n1)|square_edge_by_perimeter(#0)|divide(#1,const_2)|circumface(#2)|divide(#3,const_2)| | "let the side of the square be a cm . parameter of the rectangle = 2 ( 20 + 14 ) = 68 cm parameter of the square = 68 cm i . e . 4 a = 68 a = 17 diameter of the semicircle = 17 cm circimference of the semicircle = 1 / 2 ( ∏ ) ( 17 ) = 1 / 2 ( 22 / 7 ) ( 17 ) = 374 / 14 = 26.71 cm to two decimal places answer : c" | geometry |
math_qa__Y3dHHutWCnsRPP1M | If x > 0, x/10 + x/25 is what percent of x? Choose the correct choice from the following choices:
A) 6 % B) 14 % C) 37 1 / 2 % D) 60 % E) 75 % | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 25</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/10) + (1/25)</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">(7/50) * 100</gadget>
<output>14</output>
<result>B</result> | B | 14 | If x > 0, x/10 + x/25 is what percent of x? | {
"A": "6 %",
"B": "14 %",
"C": "37 1 / 2 %",
"D": "60 %",
"E": "75 %"
} | multiply(add(divide(const_1, 10), divide(const_1, 25)), const_100) | divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|multiply(#2,const_100)| | "just plug and chug . since the question asks for percents , pick 100 . ( but any number will do . ) 100 / 10 + 100 / 25 = 10 + 4 = 14 14 is 14 % of 100 = b" | general |
math_qa__UEfyPGQeJfx7wBaA | One day, Raviraj left home and cycled 20 Km southwards, turned right and cycled 10 km and turned right and cycled 20 Km and turned left and cycled 20 Km. How many kilometres will he have to cycle to reach his home straight ? Choose the correct option.
A) 50 B) 30 C) 40 D) 60 E) 80 | <gadget id="calculator">20 + 10</gadget>
<output>30</output>
<result>B</result> | B | 30 | One day, Raviraj left home and cycled 20 Km southwards, turned right and cycled 10 km and turned right and cycled 20 Km and turned left and cycled 20 Km. How many kilometres will he have to cycle to reach his home straight ? | {
"A": "50",
"B": "30",
"C": "40",
"D": "60",
"E": "80"
} | add(20, 10) | add(n0,n1) | raviraj starts from home at a , moves 20 km in south upto b . then he turns right and moves 10 km upto c , then he turns right and moves 20 km upto d , then he turns lefts and moves 20 km upto e . so from image it is clear that , if he moves straight then he will have to move ad + de , ad = bc = 10 km so , he will have to move 10 + 20 = 30 km answer b | physics |
math_qa__9O7Wf1prEBLTZSGz | A train running at a speed of 36 km/h passes an electric pole in 14 seconds. In how many seconds will the whole train pass a 370-meter long platform?
Answers
A) 45 B) 47 C) 49 D) 51 E) 53 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">10 * 14</gadget>
<output>140</output>
<gadget id="calculator">140 + 370</gadget>
<output>510</output>
<gadget id="calculator">510 / 10</gadget>
<output>51</output>
<result>D</result> | D | 51 | A train running at a speed of 36 km/h passes an electric pole in 14 seconds. In how many seconds will the whole train pass a 370-meter long platform? | {
"A": "45",
"B": "47",
"C": "49",
"D": "51",
"E": "53"
} | divide(add(multiply(multiply(36, const_0_2778), 14), 370), multiply(36, const_0_2778)) | multiply(n0,const_0_2778)|multiply(n1,#0)|add(n2,#1)|divide(#2,#0) | let the length of the train be x meters . when a train crosses an electric pole , the distance covered is its own length x . speed = 36 km / h = 36000 m / 3600 s = 10 m / s x = 14 * 10 = 140 m . the time taken to pass the platform = ( 140 + 370 ) / 10 = 51 seconds the answer is d . | physics |
math_qa__pTavDbFQ5NSimkdK | A train is 360 meter long is running at a speed of 50 km/hour. In what time will it pass a bridge of 140 meter length. Choices
A) 26 seconds B) 36 seconds C) 46 seconds D) 56 seconds E) none of these | <gadget id="calculator">360 + 140</gadget>
<output>500</output>
<gadget id="calculator">50 * 1_000</gadget>
<output>50_000</output>
<gadget id="calculator">50_000 / 3_600</gadget>
<output>125/9 = around 13.888889</output>
<gadget id="calculator">500 / (125/9)</gadget>
<output>36</output>
<result>B</result> | B | 36 | A train is 360 meter long is running at a speed of 50 km/hour. In what time will it pass a bridge of 140 meter length. | {
"A": "26 seconds",
"B": "36 seconds",
"C": "46 seconds",
"D": "56 seconds",
"E": "none of these"
} | divide(add(360, 140), divide(multiply(50, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)| | "explanation : speed = 50 km / hr = 50 * ( 5 / 18 ) m / sec = 125 / 9 m / sec total distance = 360 + 140 = 500 meter time = distance / speed = 500 / 125 / 9 = 36 seconds answer : b" | physics |
math_qa__L5JcsC0AzAiMNfhG | If 50% of x is 30 less than 25% of 1500, then x is? Choose the correct choice from the following options:
A) 690 B) 860 C) 560 D) 875 E) 880 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1_500 * (1/4)</gadget>
<output>375</output>
<gadget id="calculator">375 - 30</gadget>
<output>345</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">345 / (1/2)</gadget>
<output>690</output>
<result>A</result> | A | 690 | If 50% of x is 30 less than 25% of 1500, then x is? | {
"A": "690",
"B": "860",
"C": "560",
"D": "875",
"E": "880"
} | divide(subtract(multiply(1500, divide(25, const_100)), 30), divide(50, const_100)) | divide(n2,const_100)|divide(n0,const_100)|multiply(n3,#0)|subtract(#2,n1)|divide(#3,#1)| | "50 % of x = x / 2 ; 25 % of 1500 = 25 / 100 * 1500 = 375 given that , x / 2 = 375 - 30 = > x / 2 = 345 = > x = 690 . answer : a" | general |
math_qa__nWUrtkatRxSYp6ZT | An investor can sell her MicroTron stock for 36$ per share and her Dynaco stock for 44$ per share, If she sells 300 shares altogether, some of each stock, at an average price per share of 40$, how many shares of Dynaco stock has she sold? Answers.
A) 52 B) 75 C) 92 D) 136 E) 150 | <gadget id="calculator">44 - 36</gadget>
<output>8</output>
<gadget id="calculator">40 / 8</gadget>
<output>5</output>
<gadget id="calculator">300 * 5</gadget>
<output>1_500</output>
<gadget id="calculator">36 + 44</gadget>
<output>80</output>
<gadget id="calculator">80 / 8</gadget>
<output>10</output>
<gadget id="calculator">1_500 / 10</gadget>
<output>150</output>
<result>E</result> | E | 150 | An investor can sell her MicroTron stock for 36$ per share and her Dynaco stock for 44$ per share, If she sells 300 shares altogether, some of each stock, at an average price per share of 40$, how many shares of Dynaco stock has she sold? | {
"A": "52",
"B": "75",
"C": "92",
"D": "136",
"E": "150"
} | divide(multiply(300, divide(40, subtract(44, 36))), divide(add(36, 44), subtract(44, 36))) | add(n0,n1)|subtract(n1,n0)|divide(n3,#1)|divide(#0,#1)|multiply(n2,#2)|divide(#4,#3) | w 1 / w 2 = ( a 2 - aavg ) / ( aavg - a 1 ) = ( 44 - 40 ) / ( 40 - 36 ) = 4 / 4 = 1 / 1 = number of microtron stocks / number of dynaco stocks so for every 1 microtron stock , she sold 1 dynaco stock . so out of 300 total stocks , ( 1 / 1 ) th i . e . 300 / 2 = 150 must be dynaco stock . answer ( e ) | general |
math_qa__8reT2AOiE1y7hZqi | A man is 35 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is Answers.
A) 78 years B) 22 years C) 33 years D) 66 years E) 65 years | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">35 - 2</gadget>
<output>33</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">33 / 1</gadget>
<output>33</output>
<result>C</result> | C | 33 | A man is 35 years older than his son. In two years, his age will be twice the age of his son. The present age of this son is | {
"A": "78 years",
"B": "22 years",
"C": "33 years",
"D": "66 years",
"E": "65 years"
} | divide(subtract(35, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1)) | multiply(const_2,const_2)|subtract(const_2,const_1)|subtract(#0,const_2)|subtract(n0,#2)|divide(#3,#1)| | "let ' s son age is x , then father age is x + 35 . = > 2 ( x + 2 ) = ( x + 35 + 2 ) = > 2 x + 4 = x + 37 = > x = 33 years answer : c" | general |
math_qa__RnYr2si0azpURYAv | A jogger running at 9 km/hr along side a railway track is 120 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger? Select:
A) 89 B) 20 C) 36 D) 24 E) 34 | <gadget id="calculator">120 + 120</gadget>
<output>240</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">5 / 18</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">240 / 10</gadget>
<output>24</output>
<result>D</result> | D | 24 | A jogger running at 9 km/hr along side a railway track is 120 m ahead of the engine of a 120 m long train running at 45 km/hr in the same direction. In how much time will the train pass the jogger? | {
"A": "89",
"B": "20",
"C": "36",
"D": "24",
"E": "34"
} | divide(add(120, 120), multiply(subtract(45, 9), divide(divide(const_10, const_2), divide(subtract(45, 9), const_2)))) | add(n1,n2)|divide(const_10,const_2)|subtract(n3,n0)|divide(#2,const_2)|divide(#1,#3)|multiply(#4,#2)|divide(#0,#5)| | "speed of train relative to jogger = 45 - 9 = 36 km / hr . = 36 * 5 / 18 = 10 m / sec . distance to be covered = 120 + 120 = 360 m . time taken = 240 / 10 = 24 sec . answer : option d" | general |
math_qa__SuYr4vFIFKkfR1tn | The width of a rectangular hall is ½ of its length. If the area of the hall is 200 sq.m, what is the difference between its length and breadth? Select the correct option
A) 8 m B) 10 m C) 12 m D) 15 m E) 17 m | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">200 / (1/2)</gadget>
<output>400</output>
<gadget id="calculator">400 ** (1/2)</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>B</result> | B | 10 | The width of a rectangular hall is ½ of its length. If the area of the hall is 200 sq.m, what is the difference between its length and breadth? | {
"A": "8 m",
"B": "10 m",
"C": "12 m",
"D": "15 m",
"E": "17 m"
} | divide(sqrt(divide(200, divide(const_1, const_2))), const_2) | divide(const_1,const_2)|divide(n0,#0)|sqrt(#1)|divide(#2,const_2) | let the length of the hall be x m breadth of the hall = 1 x / 2 m area of the hall = length * breadth 200 = x * 1 x / 2 x ² = 400 x = 20 difference between the length and breadth of the hall = x - 1 x / 2 = x / 2 = 20 / 2 = 10 m answer : b | geometry |
math_qa__1AszPz9hVXeqy3ZF | A work which could be finished in 10 days was finished 3 days earlier after 10 more men joined. The number of men employed was? Choose the correct choice from the following:
A) 15 B) 20 C) 88 D) 71 E) 11 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">10 - 6</gadget>
<output>4</output>
<gadget id="calculator">60 / 4</gadget>
<output>15</output>
<result>A</result> | A | 15 | A work which could be finished in 10 days was finished 3 days earlier after 10 more men joined. The number of men employed was? | {
"A": "15",
"B": "20",
"C": "88",
"D": "71",
"E": "11"
} | divide(multiply(multiply(3, const_2), 10), subtract(10, multiply(3, const_2))) | multiply(n1,const_2)|multiply(n2,#0)|subtract(n0,#0)|divide(#1,#2)| | "x - - - - - - - 10 ( x + 10 ) - - - - 6 x * 10 = ( x + 10 ) 6 x = 15 \ answer : a" | physics |
math_qa__v9c1pGTH1HP42MOj | In a dairy farm, 30 cows eat 30 bags of husk in 30 days. In how many days one cow will eat one bag of husk?
Choose the correct answer
A) 1
B) 40
C) 20
D) 26
E) 30 | <gadget id="calculator">30 / 30</gadget>
<output>1</output>
<gadget id="calculator">1 * 30</gadget>
<output>30</output>
<result>E</result> | E | 30 | In a dairy farm, 30 cows eat 30 bags of husk in 30 days. In how many days one cow will eat one bag of husk? | {
"A": "1",
"B": "40",
"C": "20",
"D": "26",
"E": "30"
} | multiply(divide(30, 30), 30) | divide(n0,n0)|multiply(n0,#0)| | "explanation : one bag of husk = 30 cows per day ⇒ 30 × 1 × 30 = 1 × 30 × x for one cow = 30 days answer : e" | physics |
math_qa__Ej9tkDDwK1GC50Sr | If x/y = 2/7, then (x + y)/(x - y) = ?
Choose the correct choice from the following choices.
A) 5 B) 1 / 5 C) - 1 / 6 D) - 9 / 5 E) - 5 | <gadget id="calculator">2 + 7</gadget>
<output>9</output>
<gadget id="calculator">2 - 7</gadget>
<output>-5</output>
<gadget id="calculator">9 / (-5)</gadget>
<output>-9/5 = around -1.8</output>
<result>D</result> | D | -1.8 | If x/y = 2/7, then (x + y)/(x - y) = ? | {
"A": "5",
"B": "1 / 5",
"C": "- 1 / 6",
"D": "- 9 / 5",
"E": "- 5"
} | divide(add(2, 7), subtract(2, 7)) | add(n0,n1)|subtract(n0,n1)|divide(#0,#1)| | "any x and y satisfying x / y = 2 / 7 should give the same value for ( x + y ) / ( x - y ) . say x = 2 and y = 7 , then ( x + y ) / ( x - y ) = ( 2 + 7 ) / ( 2 - 7 ) = - 9 / 5 . answer : d ." | general |
math_qa__WVzUys3c8PCFfsV2 | K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ?
Choose the correct choice from the following answers:
A) 12 pm
B) 22 pm
C) 72 pm
D) 92 pm
E) 23 pm | <gadget id="calculator">300 - 50</gadget>
<output>250</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 50</gadget>
<output>75</output>
<gadget id="calculator">75 + 50</gadget>
<output>125</output>
<gadget id="calculator">250 / 125</gadget>
<output>2</output>
<gadget id="calculator">2 + 10</gadget>
<output>12</output>
<result>A</result> | A | 12 | K is 50% faster than L. If L starts at 9 A.M. and K starts at 10 A.M. L travels at a speed of 50 km/hr. If L and K are 300 kms apart, The time when they meet when they travel in opposite direction is ? | {
"A": "12 pm",
"B": "22 pm",
"C": "72 pm",
"D": "92 pm",
"E": "23 pm"
} | add(divide(subtract(300, 50), add(multiply(add(const_1, divide(50, const_100)), 50), 50)), 10) | divide(n0,const_100)|subtract(n4,n0)|add(#0,const_1)|multiply(n0,#2)|add(n0,#3)|divide(#1,#4)|add(n2,#5) | explanation : let ' t ' be the time after which they met since l starts . given k is 50 % faster than l 50 t + 1.5 * 50 ( t - 1 ) = 300 50 t + 75 t = 300 + 75 t = 375 / 125 = 3 hrs past the time that l starts so they meet at ( 9 + 3 ) hrs = 12 : 00 noon . answer : a | physics |
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