id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__kFLblvLtAHXVLon6 | One lady has 2 children, one of her child is boy, what is the probability of having both are boys Choices.
A) 1 / 2 B) 1 / 3 C) 1 / 4 D) 1 / 5 E) 3 / 4 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | One lady has 2 children, one of her child is boy, what is the probability of having both are boys | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 4",
"D": "1 / 5",
"E": "3 / 4"
} | divide(const_1, 2) | divide(const_1,n0) | n ( s ) = one of her child is boy out of 2 children = bb , bg = 2 n ( e ) = both are boys = bb = 1 so p = n ( e ) / n ( s ) = 1 / 2 answer : a | other |
math_qa__d9ifLe5YqCahlXhP | 7/10 of the population of the country of Venezia lives in Montague Province, while the rest lives in Capulet Province. In the upcoming election, 80% of Montague residents support Romeo, while 70% of Capulet residents support Juliet; each resident of Venezia supports exactly one of these two candidates. Rounded if necessary to the nearest percent, the probability that a Juliet supporter chosen at random resides in Capulet is
Choose the correct choice.
A) 28 %
B) 41 %
C) 60 %
D) 72 %
E) 78 % | <gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">10 - 7</gadget>
<output>3</output>
<gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(7/10) * (3/10)</gadget>
<output>21/100 = around 0.21</output>
<gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">7 / 10</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(1/5) * (7/10)</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">(7/50) + (21/100)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(21/100) / (7/20)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 100</gadget>
<output>60</output>
<result>C</result> | C | 60 | 7/10 of the population of the country of Venezia lives in Montague Province, while the rest lives in Capulet Province. In the upcoming election, 80% of Montague residents support Romeo, while 70% of Capulet residents support Juliet; each resident of Venezia supports exactly one of these two candidates. Rounded if necessary to the nearest percent, the probability that a Juliet supporter chosen at random resides in Capulet is | {
"A": "28 %",
"B": "41 %",
"C": "60 %",
"D": "72 %",
"E": "78 %"
} | multiply(divide(multiply(divide(70, const_100), divide(subtract(10, 7), 10)), add(multiply(divide(subtract(const_100, 80), const_100), divide(7, 10)), multiply(divide(70, const_100), divide(subtract(10, 7), 10)))), const_100) | divide(n3,const_100)|divide(n0,n1)|subtract(n1,n0)|subtract(const_100,n2)|divide(#2,n1)|divide(#3,const_100)|multiply(#0,#4)|multiply(#5,#1)|add(#7,#6)|divide(#6,#8)|multiply(#9,const_100)| | "total population = 100 ( assume ) . 7 / 10 * 100 = 70 people from montague . 3 / 10 * 100 = 30 people from capulet . 0.2 * 70 = 14 people from montague support juliet . 0.7 * 30 = 21 people from capulet support juliet . the probability that a juliet supporter chosen at random resides in capulet is 21 / ( 14 + 21 ) = ~ 60 . answer : c" | gain |
math_qa__esHQmzRbKxnwwn7r | Car A runs at the speed of 58km/hr & reaches its destination in 8hr. Car B runs at the speed of 70 km/h & reaches its destination in 4h. What is the respective ratio of distances covered by Car A & Car B?
Answers
A) 11 : 6 B) 12 : 7 C) 29 : 18 D) 15 : 6 E) 13 : 6 | <gadget id="calculator">58 * 8</gadget>
<output>464</output>
<gadget id="calculator">70 * 4</gadget>
<output>280</output>
<gadget id="calculator">464 / 280</gadget>
<output>58/35 = around 1.657143</output>
<result>C</result> | C | 1.611111 | Car A runs at the speed of 58km/hr & reaches its destination in 8hr. Car B runs at the speed of 70 km/h & reaches its destination in 4h. What is the respective ratio of distances covered by Car A & Car B? | {
"A": "11 : 6",
"B": "12 : 7",
"C": "29 : 18",
"D": "15 : 6",
"E": "13 : 6"
} | divide(multiply(58, 8), multiply(70, 4)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,#1)| | "sol . distance travelled by car a = 58 ã — 8 = 464 km distance travelled by car b = 70 ã — 4 = 280 km ratio = 464 / 280 = 29 : 18 c" | physics |
math_qa__oAcgHaPFG9ES0KEJ | If n is an integer and 101n^2 is less than or equal to 12100, what is the greatest possible value of n? Choose the correct option: A) 7 B) 8 C) 9 D) 10 E) 11 | <gadget id="calculator">12_100 / 101</gadget>
<output>12_100/101 = around 119.80198</output>
<gadget id="calculator">(12_100/101) ** (1/2)</gadget>
<output>110*sqrt(101)/101 = around 10.945409</output>
<gadget id="calculator">floor(110*sqrt(101)/101)</gadget>
<output>10</output>
<result>D</result> | D | 10 | If n is an integer and 101n^2 is less than or equal to 12100, what is the greatest possible value of n? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | floor(sqrt(divide(12100, 101))) | divide(n2,n0)|sqrt(#0)|floor(#1)| | "101 * n ^ 2 < = 12100 n ^ 2 < = 12100 / 101 which will be less than 121 since 12100 / 100 = 121 which is the square of 9 next closest value of n where n ^ 2 < = 121 is 10 ans d" | general |
math_qa__H3tJwzlHFqTbr4oE | how many minutes is it before 12 noon if 20 minutes ago it was 3 times as many minutes after 9 am ? Choose the correct choice from the following answers.
A) 40
B) 39
C) 42
D) 55
E) 29 | <gadget id="calculator">12 * 60</gadget>
<output>720</output>
<gadget id="calculator">9 * 60</gadget>
<output>540</output>
<gadget id="calculator">720 - 540</gadget>
<output>180</output>
<gadget id="calculator">180 - 20</gadget>
<output>160</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">160 / 4</gadget>
<output>40</output>
<result>A</result> | A | 40 | how many minutes is it before 12 noon if 20 minutes ago it was 3 times as many minutes after 9 am ? | {
"A": "40",
"B": "39",
"C": "42",
"D": "55",
"E": "29"
} | divide(subtract(subtract(multiply(12, const_60), multiply(9, const_60)), 20), add(3, const_1)) | add(n2,const_1)|multiply(n0,const_60)|multiply(n3,const_60)|subtract(#1,#2)|subtract(#3,n1)|divide(#4,#0) | a 40 minutes , or 11.20 am | physics |
math_qa__eRVnjPZ02WEXcPs0 | A train is 360 meter long is running at a speed of 75 km/hour. In what time will it pass a bridge of 140 meter length? Answers
A) 87 B) 69 C) 40 D) 72 E) 24 | <gadget id="calculator">360 + 140</gadget>
<output>500</output>
<gadget id="calculator">75 * 1_000</gadget>
<output>75_000</output>
<gadget id="calculator">75_000 / 3_600</gadget>
<output>125/6 = around 20.833333</output>
<gadget id="calculator">500 / (125/6)</gadget>
<output>24</output>
<result>E</result> | E | 24 | A train is 360 meter long is running at a speed of 75 km/hour. In what time will it pass a bridge of 140 meter length? | {
"A": "87",
"B": "69",
"C": "40",
"D": "72",
"E": "24"
} | divide(add(360, 140), divide(multiply(75, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)| | "speed = 75 km / hr = 75 * ( 5 / 18 ) m / sec = 125 / 6 m / sec total distance = 360 + 140 = 500 meter time = distance / speed = 500 * ( 6 / 125 ) = 24 seconds answer : e" | physics |
math_qa__ZwRXT46kk3yKFut4 | If k^3 is divisible by 120, what is the least possible value of integer k? Answers.
A) 15 B) 30 C) 60 D) 90 E) 120 | <gadget id="calculator">120 / 2</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<result>B</result> | B | 30 | If k^3 is divisible by 120, what is the least possible value of integer k? | {
"A": "15",
"B": "30",
"C": "60",
"D": "90",
"E": "120"
} | divide(divide(120, const_2), const_2) | divide(n1,const_2)|divide(#0,const_2)| | "k ^ 3 = 120 * x = 2 ^ 3 * 3 * 5 * x the factors of k must at minimum include 2 * 3 * 5 = 30 . the answer is b ." | general |
math_qa__qWN8cJ8Eom9uP46h | sony and johnny caught 40 fishes . sony caught 4 times as many as johnny . how many fishes did johnny catch ? Answers.
A) 12 B) 16 C) 34 D) 38 E) 8 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">40 / 5</gadget>
<output>8</output>
<result>E</result> | E | 8 | sony and johnny caught 40 fishes . sony caught 4 times as many as johnny . how many fishes did johnny catch ? | {
"A": "12",
"B": "16",
"C": "34",
"D": "38",
"E": "8"
} | divide(40, add(4, const_1)) | add(n1,const_1)|divide(n0,#0) | s + j = 40 s = 4 * j j = 8 answer : e | general |
math_qa__l7zRDBvkm5ccHIKX | two digits in brother ' s age are the same as the digit in the sister ' s age , but in reverse order . in 20 9 years brother will be twice as old as sister will be then . what is the difference in their current age ? Choose the most appropriate option.
A) 34 B) 50 C) 32 D) 28 E) 45 | <gadget id="calculator">20 + 20</gadget>
<output>40</output>
<gadget id="calculator">9 - 4</gadget>
<output>5</output>
<gadget id="calculator">40 + 5</gadget>
<output>45</output>
<result>E</result> | E | 45 | two digits in brother ' s age are the same as the digit in the sister ' s age , but in reverse order . in 20 9 years brother will be twice as old as sister will be then . what is the difference in their current age ? | {
"A": "34",
"B": "50",
"C": "32",
"D": "28",
"E": "45"
} | add(add(20, 20), subtract(9, const_4)) | add(n0,n0)|subtract(n1,const_4)|add(#0,#1) | brother ' s age = 10 x + y so sister ' s age = 10 y + x . . after 29 years , 10 x + y + 29 = 2 * ( 10 y + x + 29 ) . . . . so 29 + 19 y = 8 x . . . check for odd values of y , y = 1 satisfies the eqn with x = 6 . . . so ages are 61 and 16 and ans as found correctly by u is e . . 45 | general |
math_qa__d9Hwen6zA5NOBGC1 | a man owns 1/3 of market reserch beauro buzness,and sells 3/5 of his shares for 2000rs,what is the value of buzness? Choose the most appropriate option: A) 40000 B) 60000 C) 10000 D) 25000 E) 50000 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(1/3) * (3/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">2_000 / (1/5)</gadget>
<output>10_000</output>
<result>C</result> | C | 10,000 | a man owns 1/3 of market reserch beauro buzness,and sells 3/5 of his shares for 2000rs,what is the value of buzness? | {
"A": "40000",
"B": "60000",
"C": "10000",
"D": "25000",
"E": "50000"
} | divide(2000, multiply(divide(1, 3), divide(3, 5))) | divide(n0,n1)|divide(n1,n3)|multiply(#0,#1)|divide(n4,#2)| | "if value of business = x total sell ( 1 x / 3 ) ( 3 / 5 ) = 2000 - > x = 10000 answer : c" | general |
math_qa__0H3aSGW3KPQ7HhkZ | 15 binders can bind 1400 books in 21 days. How many binders will be required to bind 1600 books in 20 days?
Select: A) 14 B) 18 C) 24 D) 28 E) none of these | <gadget id="calculator">1_600 / 20</gadget>
<output>80</output>
<gadget id="calculator">15 * 21</gadget>
<output>315</output>
<gadget id="calculator">1_400 / 315</gadget>
<output>40/9 = around 4.444444</output>
<gadget id="calculator">80 / (40/9)</gadget>
<output>18</output>
<result>B</result> | B | 18 | 15 binders can bind 1400 books in 21 days. How many binders will be required to bind 1600 books in 20 days? | {
"A": "14",
"B": "18",
"C": "24",
"D": "28",
"E": "none of these"
} | divide(divide(1600, 20), divide(1400, multiply(15, 21))) | divide(n3,n4)|multiply(n0,n2)|divide(n1,#1)|divide(#0,#2)| | "binders books days 15 1400 21 x 1600 20 x / 15 = ( 1600 / 1400 ) * ( 21 / 20 ) = > x = 18 answer : b" | physics |
math_qa__Eyh8wicgeXjf8DHK | What is the smallest number which when increased by 3 is divisible by 18, 70, 100 and 84? Answers
A) 5307 B) 5647 C) 5927 D) 6297 E) 6557 | <gadget id="calculator">lcm(18, 70)</gadget>
<output>630</output>
<gadget id="calculator">lcm(100, 84)</gadget>
<output>2_100</output>
<gadget id="calculator">lcm(630, 2_100)</gadget>
<output>6_300</output>
<gadget id="calculator">6_300 + 3</gadget>
<output>6_303</output>
<result>D</result> | D | 6,297 | What is the smallest number which when increased by 3 is divisible by 18, 70, 100 and 84? | {
"A": "5307",
"B": "5647",
"C": "5927",
"D": "6297",
"E": "6557"
} | add(lcm(lcm(18, 70), lcm(100, 84)), 3) | lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|add(n0,#2)| | "when increased by 3 , the number must include at least 2 ^ 2 * 3 ^ 2 * 5 ^ 2 * 7 = 6300 the answer is d ." | general |
math_qa__iYO2lTqskVTnkFEo | The arithmetic mean and standard deviation of a certain normal distribution are 16.5 and 1.5, respectively. What value is exactly 2 standard deviations less than the mean?
Pick
A) 10.5 B) 11 C) 11.5 D) 12 E) 13.5 | <gadget id="calculator">2 * 1.5</gadget>
<output>3</output>
<gadget id="calculator">16.5 - 3</gadget>
<output>13.5</output>
<result>E</result> | E | 13.5 | The arithmetic mean and standard deviation of a certain normal distribution are 16.5 and 1.5, respectively. What value is exactly 2 standard deviations less than the mean? | {
"A": "10.5",
"B": "11",
"C": "11.5",
"D": "12",
"E": "13.5"
} | subtract(16.5, multiply(2, 1.5)) | multiply(n1,n2)|subtract(n0,#0)| | "the value which isexactlytwo sd less than the mean is : mean - 2 * sd = 16.5 - 2 * 1.5 = 13.5 . answer : e ." | general |
math_qa__FZgn4NgPR47MIziS | Find the value of 3/11 × [(1 + 1/3) (1 + 1/4) …………. (1 + 1/120)] is ?
Select the correct option:
A) 11 B) 12 C) 14 D) 15 E) 16 | <gadget id="calculator">120 + 1</gadget>
<output>121</output>
<gadget id="calculator">121 / 11</gadget>
<output>11</output>
<result>A</result> | A | 11 | Find the value of 3/11 × [(1 + 1/3) (1 + 1/4) …………. (1 + 1/120)] is ? | {
"A": "11",
"B": "12",
"C": "14",
"D": "15",
"E": "16"
} | divide(add(120, 1), 11) | add(n2,n10)|divide(#0,n1)| | "3 / 11 × [ ( 1 + 1 / 3 ) ( 1 + 1 / 4 ) . . . . . . . ( 1 + 1 / 120 ) ] 3 / 11 × [ 4 / 3 + 5 / 4 × . . . . . . . . 121 / 120 ] 3 / 11 × 4 / 3 × 5 / 4 × . . . . 121 / 120 121 / 11 = 11 . a )" | general |
math_qa__S05N68aRyqvitPoM | Two cars are driving towards one another. The first car is traveling at a speed of 120 Km/h, which is 28% faster than the second car. If the distance between the cars is 855 Km, how long will it takes the cars to meet (in hours)? Choose the correct option: A) 2.5 . B) 3 . C) 3.5 D) 4 . E) 4.5 . | <gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 28</gadget>
<output>168/5 = around 33.6</output>
<gadget id="calculator">120 - (168/5)</gadget>
<output>432/5 = around 86.4</output>
<gadget id="calculator">120 + (432/5)</gadget>
<output>1_032/5 = around 206.4</output>
<gadget id="calculator">855 / (1_032/5)</gadget>
<output>1_425/344 = around 4.142442</output>
<result>D</result> | D | 4 | Two cars are driving towards one another. The first car is traveling at a speed of 120 Km/h, which is 28% faster than the second car. If the distance between the cars is 855 Km, how long will it takes the cars to meet (in hours)? | {
"A": "2.5 .",
"B": "3 .",
"C": "3.5",
"D": "4 .",
"E": "4.5 ."
} | divide(855, add(120, subtract(120, multiply(divide(120, const_100), 28)))) | divide(n0,const_100)|multiply(n1,#0)|subtract(n0,#1)|add(n0,#2)|divide(n2,#3) | let s be the speed of the slower car . then the speed of the faster is 1.28 s 1.28 s = 120 s = 120 / 1.28 cumulative speed / rate = s + 1.28 s = 2.28 s time taken to meet = 855 / 2.28 s = 855 / 213.75 = 4 hrs answer : d | physics |
math_qa__mQ40MRYbqtrlhi8i | Which fraction should be added to:
1/(2 × 3) + 1/(3 × 4) + 1/(4 × 5) + ....... + 1/(23 × 24)
so that the result is equal to 1? Select:
A) 7 / 24 B) 11 / 24 C) 13 / 24 D) 17 / 24 E) 19 / 24 | <gadget id="calculator">3 + 10</gadget>
<output>13</output>
<gadget id="calculator">13 / 24</gadget>
<output>13/24 = around 0.541667</output>
<result>C</result> | C | 0.541667 | Which fraction should be added to:
1/(2 × 3) + 1/(3 × 4) + 1/(4 × 5) + ....... + 1/(23 × 24)
so that the result is equal to 1? | {
"A": "7 / 24",
"B": "11 / 24",
"C": "13 / 24",
"D": "17 / 24",
"E": "19 / 24"
} | divide(add(3, const_10), 24) | add(n2,const_10)|divide(#0,n11) | the given expression = 1 / ( 2 ã — 3 ) + 1 / ( 3 ã — 4 ) + 1 / ( 4 ã — 5 ) + . . . . . . + 1 / ( 23 ã — 24 ) = ( 1 / 2 - 1 / 3 ) + ( 1 / 3 - 1 / 4 ) + ( 1 / 4 - 1 / 5 ) + . . . . . . . . . . + ( 1 / 23 - 1 / 24 ) = 1 / 2 - 1 / 24 = 11 / 24 thus , the fraction we should add = 1 - 11 / 24 = 13 / 24 the answer is c . | general |
math_qa__u4rYZbqiNb1N92sx | Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 80 percent was planted with barley and 10 percent of the cleared land was planted with potato. If the remaining 90 acres of cleared land was planted with tomato, how many acres did the farmer own? Select the correct option: A) 850 B) 950 C) 1025 D) 975 E) 1000 | <gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">20 - 10</gadget>
<output>10</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(1/10) * (9/10)</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">90 / (9/100)</gadget>
<output>1_000</output>
<result>E</result> | E | 1,000 | Of the land owned by a farmer, 90 percent was cleared for planting. Of the cleared land, 80 percent was planted with barley and 10 percent of the cleared land was planted with potato. If the remaining 90 acres of cleared land was planted with tomato, how many acres did the farmer own? | {
"A": "850",
"B": "950",
"C": "1025",
"D": "975",
"E": "1000"
} | divide(90, multiply(divide(subtract(subtract(const_100, 80), 10), const_100), divide(90, const_100))) | divide(n0,const_100)|subtract(const_100,n1)|subtract(#1,n2)|divide(#2,const_100)|multiply(#3,#0)|divide(n3,#4)| | 80 % of 90 % = 72 % , 10 % 0 f 90 % = 9 % so the remaining 90 - 72 - 9 = 9 % = 90 acres or 10 % of 90 % = 9 % - - > 90 / 9 * 100 = 1000 acres answer ( e ) | gain |
math_qa__3hjDCmQGzjcgGfoj | If one positive integer is greater than another positive integer by 3, and the difference of their cubes is 63, what is their sum? Choose the correct option: A) 5 B) 4 C) 3 D) 2 E) 1 | <gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">27 ** 2</gadget>
<output>729</output>
<gadget id="calculator">63 - 27</gadget>
<output>36</output>
<gadget id="calculator">36 ** 2</gadget>
<output>1_296</output>
<gadget id="calculator">729 + 1_296</gadget>
<output>2_025</output>
<gadget id="calculator">2_025 ** (1/2)</gadget>
<output>45</output>
<gadget id="calculator">27 + 45</gadget>
<output>72</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<gadget id="calculator">72 / 18</gadget>
<output>4</output>
<gadget id="calculator">4 - 3</gadget>
<output>1</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<result>A</result> | A | 5 | If one positive integer is greater than another positive integer by 3, and the difference of their cubes is 63, what is their sum? | {
"A": "5",
"B": "4",
"C": "3",
"D": "2",
"E": "1"
} | add(divide(add(power(3, const_3), sqrt(add(power(power(3, const_3), const_2), power(subtract(63, power(3, const_3)), const_2)))), multiply(power(3, const_2), const_2)), subtract(divide(add(power(3, const_3), sqrt(add(power(power(3, const_3), const_2), power(subtract(63, power(3, const_3)), const_2)))), multiply(power(3, const_2), const_2)), 3)) | power(n0,const_3)|power(n0,const_2)|multiply(#1,const_2)|power(#0,const_2)|subtract(n1,#0)|power(#4,const_2)|add(#3,#5)|sqrt(#6)|add(#0,#7)|divide(#8,#2)|subtract(#9,n0)|add(#9,#10) | 1 ^ 3 = 1 2 ^ 3 = 8 3 ^ 3 = 27 4 ^ 3 = 64 the two numbers are 1 and 4 . the answer is a . | general |
math_qa__tKHPAyyGkfIefH0b | In a recent election, Geoff received 0.5 percent of the 5,000 votes cast. To win the election, a candidate needed to receive more than x% of the vote. If Geoff needed exactly 2,571 more votes to win the election, what is the value of x ? Choices: A) 50 B) 54 C) 52 D) 60 E) 63 | <gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">50 + 0.5</gadget>
<output>50.5</output>
<result>C</result> | C | 52 | In a recent election, Geoff received 0.5 percent of the 5,000 votes cast. To win the election, a candidate needed to receive more than x% of the vote. If Geoff needed exactly 2,571 more votes to win the election, what is the value of x ? | {
"A": "50",
"B": "54",
"C": "52",
"D": "60",
"E": "63"
} | add(divide(const_100, const_2), 0.5) | divide(const_100,const_2)|add(n0,#0)| | "word problems are tricky in somehow more than other problem because you have the additional step to translate . breaking the problem : geoff how many votes he receives ? ? 25 votes he needs 2571 more votes so : 25 + 2571 = 2596 now what ' s the problem wants ? ? a x % . . . . . . . . 2596 is what % of total votes 5000 . . . . . . . . translating : 2596 = x / 100 * 5000 - - - x = 52 % . . . . . . . . . . c" | gain |
math_qa__w2k3BmQ8Gr7v4r3e | A bus trip of 360 miles would have taken 1 hour less if the average speed V for the trip had been greater by 5 miles per hour. What was the average speed V, in miles per hour, for the trip? Select the correct option:
A) 35 B) 40 C) 45 D) 50 E) 55 | <gadget id="calculator">360 * 5</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 * 4</gadget>
<output>7_200</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">7_200 + 25</gadget>
<output>7_225</output>
<gadget id="calculator">7_225 ** (1/2)</gadget>
<output>85</output>
<gadget id="calculator">85 - 5</gadget>
<output>80</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<result>B</result> | B | 40 | A bus trip of 360 miles would have taken 1 hour less if the average speed V for the trip had been greater by 5 miles per hour. What was the average speed V, in miles per hour, for the trip? | {
"A": "35",
"B": "40",
"C": "45",
"D": "50",
"E": "55"
} | divide(subtract(sqrt(add(multiply(multiply(360, 5), const_4), power(5, const_2))), 5), const_2) | multiply(n0,n2)|power(n2,const_2)|multiply(#0,const_4)|add(#2,#1)|sqrt(#3)|subtract(#4,n2)|divide(#5,const_2)| | "the time is the distance / speed . the time difference is 1 hour . 360 / v - 360 / ( v + 5 ) = 1 360 ( v + 5 ) - 360 v = ( v ) ( v + 5 ) 1800 = ( v ) ( v + 5 ) 40 * 45 = ( v ) ( v + 5 ) v = 40 mph the answer is b ." | physics |
math_qa__gkje6OzxPxRPlWdH | The area of sector of a circle whose radius is 12 metro and whose angle at the center is 41° is? Pick one:
A) 49 m 2 B) 50 m 2 C) 51.5 m 2 D) 53 m 2 E) 59 m 2 | <gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">144 * (22/7)</gadget>
<output>3_168/7 = around 452.571429</output>
<gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">41 / 360</gadget>
<output>41/360 = around 0.113889</output>
<gadget id="calculator">(3_168/7) * (41/360)</gadget>
<output>1_804/35 = around 51.542857</output>
<result>C</result> | C | 51.5 | The area of sector of a circle whose radius is 12 metro and whose angle at the center is 41° is? | {
"A": "49 m 2",
"B": "50 m 2",
"C": "51.5 m 2",
"D": "53 m 2",
"E": "59 m 2"
} | multiply(multiply(power(12, const_2), divide(add(multiply(const_2, const_10), const_2), add(const_4, const_3))), divide(41, divide(const_3600, const_10))) | add(const_3,const_4)|divide(const_3600,const_10)|multiply(const_10,const_2)|power(n0,const_2)|add(#2,const_2)|divide(n1,#1)|divide(#4,#0)|multiply(#6,#3)|multiply(#5,#7)| | "41 / 360 * 22 / 7 * 12 * 12 = 51.5 m 2 answer : c" | geometry |
math_qa__R1NgwJW63ypWxHiX | 10% of employees are women with fair hair. 40% of fair-haired employees are women. What percent of employees have fair hair?
Choose the correct option.
A) 25 B) 30 C) 50 D) 55 E) 60 | <gadget id="calculator">10 / 40</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>A</result> | A | 25 | 10% of employees are women with fair hair. 40% of fair-haired employees are women. What percent of employees have fair hair? | {
"A": "25",
"B": "30",
"C": "50",
"D": "55",
"E": "60"
} | multiply(divide(10, 40), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "i came up with ( a ) 25 think of 100 people total : from the first fact , 10 of these are women with fair hair . from the second fact , these 10 women make up 40 % of the total fair haired population . we can then make a ratio of 60 : 40 fair haired men to fair haired women . this means that ( 60 / 40 ) * 10 equals the number of fair haired men , which is 15 men with fair hair . add this 15 to the 10 women and get 25 fair haired men and women out of 100 total men and women . 25 % a" | gain |
math_qa__zv1hHyQmISBukck7 | A rectangular lawn of dimensions 80 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m? Answers.
A) rs . 3919 B) rs . 3910 C) rs . 3997 D) rs . 3900 E) rs . 3902 | <gadget id="calculator">80 + 60</gadget>
<output>140</output>
<gadget id="calculator">140 - 10</gadget>
<output>130</output>
<gadget id="calculator">130 * 10</gadget>
<output>1_300</output>
<gadget id="calculator">1_300 * 3</gadget>
<output>3_900</output>
<result>D</result> | D | 3,900 | A rectangular lawn of dimensions 80 m * 60 m has two roads each 10 m wide running in the middle of the lawn, one parallel to the length and the other parallel to the breadth. What is the cost of traveling the two roads at Rs.3 per sq m? | {
"A": "rs . 3919",
"B": "rs . 3910",
"C": "rs . 3997",
"D": "rs . 3900",
"E": "rs . 3902"
} | multiply(multiply(subtract(add(80, 60), 10), 10), 3) | add(n0,n1)|subtract(#0,n2)|multiply(n2,#1)|multiply(n3,#2) | area = ( l + b – d ) d ( 80 + 60 – 10 ) 10 = > 1300 m 2 1300 * 3 = rs . 3900 answer : d | geometry |
math_qa__Q0b7ywOiNpbcydLg | A man bought 40 shares of Rs. 60 at 5 discount, the rate of dividend being 1212%The rate of interest obtained is
Select the correct option:
A) 13.64 %
B) 15.5 %
C) 14 %
D) 14.25 %
E) 14.95 % | <gadget id="calculator">40 * 60</gadget>
<output>2_400</output>
<gadget id="calculator">1_212 / 100</gadget>
<output>303/25 = around 12.12</output>
<gadget id="calculator">2_400 * (303/25)</gadget>
<output>29_088</output>
<gadget id="calculator">60 - 5</gadget>
<output>55</output>
<gadget id="calculator">40 * 55</gadget>
<output>2_200</output>
<gadget id="calculator">29_088 / 2_200</gadget>
<output>3_636/275 = around 13.221818</output>
<result>A</result> | A | 13.64 | A man bought 40 shares of Rs. 60 at 5 discount, the rate of dividend being 1212%The rate of interest obtained is | {
"A": "13.64 %",
"B": "15.5 %",
"C": "14 %",
"D": "14.25 %",
"E": "14.95 %"
} | divide(multiply(multiply(40, 60), divide(1212, const_100)), multiply(40, subtract(60, 5))) | divide(n3,const_100)|multiply(n0,n1)|subtract(n1,n2)|multiply(#0,#1)|multiply(n0,#2)|divide(#3,#4) | explanation : face value of a share = rs . 60 he bought each share at rs . 60 - rs . 5 = rs . 55 number of shares = 40 dividend = 12 1 / 2 % = 25 / 2 % dividend per share = 60 × 25 / 2 × 100 = rs . 7.5 total dividend = ( 40 × 7.5 ) ie , he got a dividend of ( 40 × 7.5 ) for an investment of rs . ( 40 × 55 ) interest obtained = 40 × 7.5 × 100 / 40 × 55 = 13.64 % answer : option a | gain |
math_qa__1GMpQLLsEYLTUuRR | a equilateral triangle having one side 5m.in this triangle there is a square of side 2m.calculate the percentage of area outside square in that triangle. Pick one
A) 68 B) 54 C) 63.04 D) 62 E) 60 | <gadget id="calculator">3 ** (1/2)</gadget>
<output>sqrt(3) = around 1.732051</output>
<gadget id="calculator">(sqrt(3)) / 4</gadget>
<output>sqrt(3)/4 = around 0.433013</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">(sqrt(3)/4) * 25</gadget>
<output>25*sqrt(3)/4 = around 10.825318</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">(25*sqrt(3)/4) - 4</gadget>
<output>-4 + 25*sqrt(3)/4 = around 6.825318</output>
<gadget id="calculator">(-4 + 25*sqrt(3)/4) / (25*sqrt(3)/4)</gadget>
<output>4*sqrt(3)*(-4 + 25*sqrt(3)/4)/75 = around 0.630496</output>
<gadget id="calculator">(4*sqrt(3)*(-4 + 25*sqrt(3)/4)/75) * 100</gadget>
<output>16*sqrt(3)*(-4 + 25*sqrt(3)/4)/3 = around 63.049583</output>
<result>C</result> | C | 63.04 | a equilateral triangle having one side 5m.in this triangle there is a square of side 2m.calculate the percentage of area outside square in that triangle. | {
"A": "68",
"B": "54",
"C": "63.04",
"D": "62",
"E": "60"
} | multiply(divide(subtract(multiply(divide(sqrt(const_3), const_4), power(5, const_2)), square_area(2)), multiply(divide(sqrt(const_3), const_4), power(5, const_2))), const_100) | power(n0,const_2)|sqrt(const_3)|square_area(n1)|divide(#1,const_4)|multiply(#3,#0)|subtract(#4,#2)|divide(#5,#4)|multiply(#6,const_100) | area of triangle = â ˆ š 3 a 2 / 4 . = 1.732 * 25 / 4 = 10.825 m 2 . area of square = 2 * 2 = 4 m 2 . rest area after square = 10.825 - 4 = 6.825 m 2 . % rest area after square = 6.825 / 10.825 * 100 = 63.04 % answer c | geometry |
math_qa__vXxlXPgFslu6iITL | One fourth of one third of two fifth of a number is 15. What will be40% of that number Choose the correct choice:
A) 140 B) 150 C) 180 D) 200 E) 220 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/4) * (1/3)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/12) * (2/5)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">15 / (1/30)</gadget>
<output>450</output>
<gadget id="calculator">450 * 40</gadget>
<output>18_000</output>
<gadget id="calculator">18_000 / 100</gadget>
<output>180</output>
<result>C</result> | C | 180 | One fourth of one third of two fifth of a number is 15. What will be40% of that number | {
"A": "140",
"B": "150",
"C": "180",
"D": "200",
"E": "220"
} | divide(multiply(divide(15, multiply(multiply(divide(const_1, const_4), divide(const_1, const_3)), divide(const_2, add(const_2, const_3)))), 40), const_100) | add(const_2,const_3)|divide(const_1,const_4)|divide(const_1,const_3)|divide(const_2,#0)|multiply(#1,#2)|multiply(#3,#4)|divide(n0,#5)|multiply(n1,#6)|divide(#7,const_100)| | "explanation : ( 1 / 4 ) * ( 1 / 3 ) * ( 2 / 5 ) * x = 15 then x = 15 * 30 = 450 40 % of 450 = 180 answer : option c" | gain |
math_qa__FUM1Qq7MCEIrB91F | A certain candy manufacturer reduced the weight of Candy Bar M by 25 percent buy left the price unchanged. What was the resulting percent increase in the price per ounce of Candy Bar M? Select the correct option: A) 20 B) 30 C) 34 D) 35 E) 33.33 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / (3/4)</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) * 100</gadget>
<output>400/3 = around 133.333333</output>
<gadget id="calculator">(400/3) - 100</gadget>
<output>100/3 = around 33.333333</output>
<result>E</result> | E | 33.33 | A certain candy manufacturer reduced the weight of Candy Bar M by 25 percent buy left the price unchanged. What was the resulting percent increase in the price per ounce of Candy Bar M? | {
"A": "20",
"B": "30",
"C": "34",
"D": "35",
"E": "33.33"
} | subtract(multiply(divide(const_1, subtract(const_1, divide(25, const_100))), const_100), const_100) | divide(n0,const_100)|subtract(const_1,#0)|divide(const_1,#1)|multiply(#2,const_100)|subtract(#3,const_100)| | "assume 1 oz candy cost $ 1 before . now price remain same $ 1 but weight of candy reduces to 0.75 oz new price of candy = 1 / 0.75 = 1.3333 price increase 33.33 % e" | gain |
math_qa__tC7ZIcPdhpJ4AOZK | Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 11.67and for 36kgs of Apples is 12.48 then the cost of first 10 kgs of Apples is Answers:
A) 3.69 B) 3.66 C) 3.6 D) 3.62 E) 3.61 | <gadget id="calculator">33 - 30</gadget>
<output>3</output>
<gadget id="calculator">12.48 - 11.67</gadget>
<output>0.81</output>
<gadget id="calculator">36 - 33</gadget>
<output>3</output>
<gadget id="calculator">0.81 / 3</gadget>
<output>0.27</output>
<gadget id="calculator">3 * 0.27</gadget>
<output>0.81</output>
<gadget id="calculator">11.67 - 0.81</gadget>
<output>10.86</output>
<gadget id="calculator">10.86 / 30</gadget>
<output>0.362</output>
<gadget id="calculator">0.362 * 10</gadget>
<output>3.62</output>
<result>D</result> | D | 3.62 | Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 11.67and for 36kgs of Apples is 12.48 then the cost of first 10 kgs of Apples is | {
"A": "3.69",
"B": "3.66",
"C": "3.6",
"D": "3.62",
"E": "3.61"
} | multiply(divide(subtract(11.67, multiply(subtract(33, 30), divide(subtract(12.48, 11.67), subtract(36, 33)))), 30), 10) | subtract(n4,n2)|subtract(n3,n1)|subtract(n1,n0)|divide(#0,#1)|multiply(#3,#2)|subtract(n2,#4)|divide(#5,n0)|multiply(n5,#6)| | "ans : by framing equations we get 30 l + 3 q = 11.67 30 l + 6 q = 12.48 eliminate q by multiplying the first equation by 2 and subtracting second equation from the first then we get l = 0.362 cost of 10 kgs of apples = 0.362 x 10 = 3.62 answer : d" | other |
math_qa__ndTkj6x4MjIwwMwd | Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.76800? Options: A) 81000 B) 97200 C) 27772 D) 29889 E) 22312 | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 76_800</gadget>
<output>9_600</output>
<gadget id="calculator">76_800 + 9_600</gadget>
<output>86_400</output>
<gadget id="calculator">(1/8) * 86_400</gadget>
<output>10_800</output>
<gadget id="calculator">86_400 + 10_800</gadget>
<output>97_200</output>
<result>B</result> | B | 97,200 | Every year an amount increases by 1/8th of itself. How much will it be after two years if its present value is Rs.76800? | {
"A": "81000",
"B": "97200",
"C": "27772",
"D": "29889",
"E": "22312"
} | add(add(76800, multiply(divide(1, 8), 76800)), multiply(divide(1, 8), add(76800, multiply(divide(1, 8), 76800)))) | divide(n0,n1)|multiply(n2,#0)|add(n2,#1)|multiply(#2,#0)|add(#2,#3)| | 76800 * 9 / 8 * 9 / 8 = 97200 . answer : b | general |
math_qa__uF4zkqknE36kFquV | Kamal obtained 96, 65, 82, 67 and 85 marks(out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? Choose the correct choice from the following answers:
A) 65 B) 69 C) 72 D) 79 E) none | <gadget id="calculator">96 + 65</gadget>
<output>161</output>
<gadget id="calculator">161 + 82</gadget>
<output>243</output>
<gadget id="calculator">243 + 67</gadget>
<output>310</output>
<gadget id="calculator">310 + 85</gadget>
<output>395</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">395 / 5</gadget>
<output>79</output>
<result>D</result> | D | 79 | Kamal obtained 96, 65, 82, 67 and 85 marks(out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? | {
"A": "65",
"B": "69",
"C": "72",
"D": "79",
"E": "none"
} | divide(add(add(add(add(96, 65), 82), 67), 85), add(const_1, const_4)) | add(n0,n1)|add(const_1,const_4)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "sol . average = 96 + 65 + 82 + 67 + 85 / 5 ) = ( 395 / 5 ) = 79 . answer d" | general |
math_qa__ovsJPJJqgQ8mKl4P | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 32, then how old is B?
Choose the most appropriate option:
A) 17 years
B) 19 years
C) 29 years
D) 10 years
E) 12 years | <gadget id="calculator">32 - 2</gadget>
<output>30</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<result>E</result> | E | 12 | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 32, then how old is B? | {
"A": "17 years",
"B": "19 years",
"C": "29 years",
"D": "10 years",
"E": "12 years"
} | divide(multiply(subtract(32, const_2), const_2), add(const_4, const_1)) | add(const_1,const_4)|subtract(n0,const_2)|multiply(#1,const_2)|divide(#2,#0)| | "let c ' s age be x years . then , b ' s age = 2 x years . a ' s age = ( 2 x + 2 ) years . ( 2 x + 2 ) + 2 x + x = 32 5 x = 30 = > x = 6 hence , b ' s age = 2 x = 12 years . answer : e" | general |
math_qa__iSwOvbbRgqjSZwGw | It is the New Year and Mandy has made a resolution to lose weight this year. She plans to exercise and do yoga. For exercise she plans to workout at the gym and ride her bicycle in the ratio of 2:3 everyday. She will also do yoga in the ratio, yoga:exercise = 2:3. If she rides her bike for 12 minutes, how much time will she spend doing yoga? (rounded to minutes)
Choose the correct option:
A) 10 min .
B) 41 min .
C) 17 min .
D) 23 min .
E) 20 min . | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">12 * (3/5)</gadget>
<output>36/5 = around 7.2</output>
<gadget id="calculator">(3/5) * (3/5)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(36/5) / (9/25)</gadget>
<output>20</output>
<result>E</result> | E | 20 | It is the New Year and Mandy has made a resolution to lose weight this year. She plans to exercise and do yoga. For exercise she plans to workout at the gym and ride her bicycle in the ratio of 2:3 everyday. She will also do yoga in the ratio, yoga:exercise = 2:3. If she rides her bike for 12 minutes, how much time will she spend doing yoga? (rounded to minutes) | {
"A": "10 min .",
"B": "41 min .",
"C": "17 min .",
"D": "23 min .",
"E": "20 min ."
} | divide(multiply(12, divide(3, add(2, 3))), multiply(divide(3, add(2, 3)), divide(3, add(2, 3)))) | add(n0,n1)|divide(n1,#0)|multiply(n4,#1)|multiply(#1,#1)|divide(#2,#3) | the ratio is 2 : 3 = gym : ride , so ( 12 ) ( 3 / 2 ) = 18 minutes at the gym , and 18 + 12 = 30 minutes exercise , so ( 2 / 3 ) ( 30 ) = 20 minutes yoga . answer : e | physics |
math_qa__7Ld3c32USsit6Ta9 | A man spends 2/5 of his salary on house rent, 3/10 of his salary on food, and 1/8 of his salary on conveyance. if he has Rs 1400 left with him, find his expenditure on food and conveyance Select the correct option: A) 3200 B) 3400 C) 3600 D) 3800 E) 4000 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(2/5) + (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(7/10) + (1/8)</gadget>
<output>33/40 = around 0.825</output>
<gadget id="calculator">1 - (33/40)</gadget>
<output>7/40 = around 0.175</output>
<gadget id="calculator">1_400 / (7/40)</gadget>
<output>8_000</output>
<gadget id="calculator">8_000 * (3/10)</gadget>
<output>2_400</output>
<gadget id="calculator">8_000 * (1/8)</gadget>
<output>1_000</output>
<gadget id="calculator">2_400 + 1_000</gadget>
<output>3_400</output>
<result>B</result> | B | 3,400 | A man spends 2/5 of his salary on house rent, 3/10 of his salary on food, and 1/8 of his salary on conveyance. if he has Rs 1400 left with him, find his expenditure on food and conveyance | {
"A": "3200",
"B": "3400",
"C": "3600",
"D": "3800",
"E": "4000"
} | add(multiply(divide(1400, subtract(1, add(add(divide(2, 5), divide(3, 10)), divide(1, 8)))), divide(3, 10)), multiply(divide(1400, subtract(1, add(add(divide(2, 5), divide(3, 10)), divide(1, 8)))), divide(1, 8))) | divide(n0,n1)|divide(n2,n3)|divide(n4,n5)|add(#0,#1)|add(#3,#2)|subtract(n4,#4)|divide(n6,#5)|multiply(#6,#1)|multiply(#6,#2)|add(#7,#8)| | "if his salary is x , then x - x * ( 2 / 5 + 3 / 10 + 1 / 8 ) = 1400 x ( 1 - 33 / 40 ) = 1400 x = 1400 * 40 / 7 = rs 8000 expenditure on food and conveyance = 8000 * 3 / 10 + 8000 * 1 / 8 = 2400 + 1000 = 3400 answer : b" | general |
math_qa__IWCHymxPTSXBAKKf | A certain bus driver is paid a regular rate of $14 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $976 in total compensation, how many total hours did he work that week? Select the correct option: A) 54 B) 51 C) 59 D) 55 E) 52 | <gadget id="calculator">14 * 40</gadget>
<output>560</output>
<gadget id="calculator">976 - 560</gadget>
<output>416</output>
<gadget id="calculator">100 + 75</gadget>
<output>175</output>
<gadget id="calculator">14 * 175</gadget>
<output>2_450</output>
<gadget id="calculator">2_450 / 100</gadget>
<output>49/2 = around 24.5</output>
<gadget id="calculator">416 / (49/2)</gadget>
<output>832/49 = around 16.979592</output>
<gadget id="calculator">40 + (832/49)</gadget>
<output>2_792/49 = around 56.979592</output>
<result>C</result> | C | 59 | A certain bus driver is paid a regular rate of $14 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $976 in total compensation, how many total hours did he work that week? | {
"A": "54",
"B": "51",
"C": "59",
"D": "55",
"E": "52"
} | add(40, divide(subtract(976, multiply(14, 40)), divide(multiply(14, add(const_100, 75)), const_100))) | add(n3,const_100)|multiply(n0,n1)|multiply(n0,#0)|subtract(n4,#1)|divide(#2,const_100)|divide(#3,#4)|add(n1,#5)| | "for 40 hrs = 40 * 14 = 560 excess = 976 - 560 = 416 for extra hours = . 75 ( 14 ) = 10.5 + 14 = 24.5 number of extra hrs = 416 / 24.5 = 18.82 = 19 approx . total hrs = 40 + 19 = 59 answer c 59" | general |
math_qa__URQAxu6deVuZzLe3 | The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum Answers:
A) rs . 17037 B) rs . 17000 C) rs . 17276 D) rs . 170287 E) rs . 171881 | <gadget id="calculator">100 * 10_200</gadget>
<output>1_020_000</output>
<gadget id="calculator">11_730 - 10_200</gadget>
<output>1_530</output>
<gadget id="calculator">1_530 * 100</gadget>
<output>153_000</output>
<gadget id="calculator">10_200 / 2</gadget>
<output>5_100</output>
<gadget id="calculator">153_000 / 5_100</gadget>
<output>30</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">1_020_000 / 60</gadget>
<output>17_000</output>
<result>B</result> | B | 17,000 | The compound and the simple interests on a certain sum at the same rate of interest for two years are Rs.11730 and Rs.10200 respectively. Find the sum | {
"A": "rs . 17037",
"B": "rs . 17000",
"C": "rs . 17276",
"D": "rs . 170287",
"E": "rs . 171881"
} | divide(multiply(const_100, 10200), multiply(divide(multiply(subtract(11730, 10200), const_100), divide(10200, const_2)), const_2)) | divide(n1,const_2)|multiply(n1,const_100)|subtract(n0,n1)|multiply(#2,const_100)|divide(#3,#0)|multiply(#4,const_2)|divide(#1,#5) | explanation : the simple interest for the first year is 10200 / 2 is rs . 5100 and compound interest for first year also is rs . 5100 . the compound interest for second year on rs . 5100 for one year so rate of the interest = ( 100 * 1530 ) / ( 5100 * 1 ) = 30 % p . a . so p = ( 100 * 10200 ) / ( 30 * 2 ) = rs . 17000 answer : b | gain |
math_qa__LZraj3gDa3YQEzZH | The sum of two numbers is 8 and the sum of their squares is 120. Find the product of the two numbers. Pick:
A) 25
B) 24
C) 23
D) 21
E) 28 | <gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">120 - 64</gadget>
<output>56</output>
<gadget id="calculator">56 / 2</gadget>
<output>28</output>
<result>E</result> | E | 28 | The sum of two numbers is 8 and the sum of their squares is 120. Find the product of the two numbers. | {
"A": "25",
"B": "24",
"C": "23",
"D": "21",
"E": "28"
} | divide(subtract(120, power(8, const_2)), const_2) | power(n0,const_2)|subtract(n1,#0)|divide(#1,const_2)| | let a and b be the two numbers ( a + b ) ^ 2 = a ^ 2 + 2 ab + b ^ 2 given ( a + b ) = 8 a ^ 2 + b ^ 2 = 120 so , 8 ^ 2 = 120 + 2 ab 2 ab = 120 - 64 2 ab = 56 ab = 28 ans e | general |
math_qa__5RHiwH0wfD0mKa16 | If the cost price of 121 chocolates is equal to the selling price of 77 chocolates, the gain percent is : Choose the correct choice from the following answers
A) 56.14 %
B) 57.44 %
C) 57.14 %
D) 56.34 %
E) 57.87 % | <gadget id="calculator">121 - 77</gadget>
<output>44</output>
<gadget id="calculator">77 / 44</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">100 / (7/4)</gadget>
<output>400/7 = around 57.142857</output>
<result>C</result> | C | 57.14 | If the cost price of 121 chocolates is equal to the selling price of 77 chocolates, the gain percent is : | {
"A": "56.14 %",
"B": "57.44 %",
"C": "57.14 %",
"D": "56.34 %",
"E": "57.87 %"
} | divide(const_100, divide(77, subtract(121, 77))) | subtract(n0,n1)|divide(n1,#0)|divide(const_100,#1)| | "explanation : solution : let c . p . of each chocolate be re . 1 . then , c . p . of 77 chocolates = rs . 77 ; s . p . of 77 chocolates = rs . 121 . . ' . gain % = 44 * 100 / 77 = 57.14 % answer : c" | gain |
math_qa__jtpPHgrs0TkXVG6R | A library has an average of 500 visitors on Sundays and 140 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is : Choose one: A) 100 B) 200 C) 300 D) 400 E) 550 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">30 / 7</gadget>
<output>30/7 = around 4.285714</output>
<gadget id="calculator">floor(30/7)</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 500</gadget>
<output>2_500</output>
<gadget id="calculator">30 - 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 140</gadget>
<output>3_500</output>
<gadget id="calculator">2_500 + 3_500</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 30</gadget>
<output>200</output>
<result>B</result> | B | 200 | A library has an average of 500 visitors on Sundays and 140 on other days. The average number of visitors per day in a month of 30 days beginning with a Sunday is : | {
"A": "100",
"B": "200",
"C": "300",
"D": "400",
"E": "550"
} | divide(add(multiply(add(floor(divide(30, add(const_3, const_4))), const_1), 500), multiply(subtract(30, add(floor(divide(30, add(const_3, const_4))), const_1)), 140)), 30) | add(const_3,const_4)|divide(n2,#0)|floor(#1)|add(#2,const_1)|multiply(n0,#3)|subtract(n2,#3)|multiply(n1,#5)|add(#4,#6)|divide(#7,n2)| | "explanation : since the month begins with a sunday , so there will be five sundays in the month , required average = ( 500 * 5 + 140 * 25 ) / 30 = 6000 / 30 = 200 answer : b ) 200" | general |
math_qa__Y8aHpCNTLyYfkEgP | A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man's rate is? Pick one:
A) 1 B) 2 C) 3 D) 5 E) 7 | <gadget id="calculator">6 - 4</gadget>
<output>2</output>
<gadget id="calculator">2 / 2</gadget>
<output>1</output>
<result>A</result> | A | 1 | A man can row his boat with the stream at 6 km/h and against the stream in 4 km/h. The man's rate is? | {
"A": "1",
"B": "2",
"C": "3",
"D": "5",
"E": "7"
} | divide(subtract(6, 4), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "ds = 6 us = 4 s = ? s = ( 6 - 4 ) / 2 = 1 kmph answer : a" | gain |
math_qa__EFDOSq5nJ5LZIRTu | A man buys 100 lts of liquid which contains 25% of the liquid and the rest is water. He then mixes it with 90 lts of another mixture with 30% of liquid. What is the % of water in the new mixture? Pick one
A) 81
B) 75
C) 72.63
D) 73
E) 76 | <gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">100 * 75</gadget>
<output>7_500</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">90 * 70</gadget>
<output>6_300</output>
<gadget id="calculator">7_500 + 6_300</gadget>
<output>13_800</output>
<gadget id="calculator">100 + 90</gadget>
<output>190</output>
<gadget id="calculator">13_800 / 190</gadget>
<output>1_380/19 = around 72.631579</output>
<result>C</result> | C | 72.63 | A man buys 100 lts of liquid which contains 25% of the liquid and the rest is water. He then mixes it with 90 lts of another mixture with 30% of liquid. What is the % of water in the new mixture? | {
"A": "81",
"B": "75",
"C": "72.63",
"D": "73",
"E": "76"
} | divide(add(multiply(100, subtract(const_100, 25)), multiply(90, subtract(const_100, 30))), add(100, 90)) | add(n0,n2)|subtract(const_100,n1)|subtract(const_100,n3)|multiply(n0,#1)|multiply(n2,#2)|add(#3,#4)|divide(#5,#0) | 25 % in 100 lts is 25 . so water = 100 - 25 = 75 lts . 30 % of 90 lts = 27 . so water in 2 nd mixture = 90 - 27 = 63 lts . now total quantity = 100 + 90 = 190 lts . total water in it will be 75 + 63 = 138 lts . % of water = ( 100 * 138 ) / 190 = 72.63 answer : c | gain |
math_qa__FBQ5oObZTJzoIoYy | A train running at the speed of 60 km/hr crosses a pole in 3 seconds. Find the length of the train? Choose the correct choice
A) 150 meter B) 170 meter C) 156 meter D) 168 meter E) 50 meter | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 3</gadget>
<output>50</output>
<result>E</result> | E | 50 | A train running at the speed of 60 km/hr crosses a pole in 3 seconds. Find the length of the train? | {
"A": "150 meter",
"B": "170 meter",
"C": "156 meter",
"D": "168 meter",
"E": "50 meter"
} | multiply(divide(multiply(60, const_1000), const_3600), 3) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 60 * ( 5 / 18 ) m / sec = 50 / 3 m / sec length of train ( distance ) = speed * time ( 50 / 3 ) * 3 = 50 meter answer : e" | physics |
math_qa__yRCa8sDPOXkXRGxI | he average weight of 8 persons increases by 3.5 kg when a new person comes in place of one of them weighing 62 kg. What might be the weight of the new person ? Choose the correct choice.
A) 75 kg
B) 55 kg
C) 45 kg
D) 85 kg
E) 90 kg | <gadget id="calculator">3.5 * 8</gadget>
<output>28</output>
<gadget id="calculator">28 + 62</gadget>
<output>90</output>
<result>E</result> | E | 90 | he average weight of 8 persons increases by 3.5 kg when a new person comes in place of one of them weighing 62 kg. What might be the weight of the new person ? | {
"A": "75 kg",
"B": "55 kg",
"C": "45 kg",
"D": "85 kg",
"E": "90 kg"
} | add(multiply(3.5, 8), 62) | multiply(n0,n1)|add(n2,#0)| | "explanation : total weight increased = ( 8 x 3.5 ) kg = 28 kg . weight of new person = ( 62 + 28 ) kg = 90 kg . answer : e" | general |
math_qa__YlngXYVQ6wAnpoV9 | The price of a jacket is reduced by 20%. During a special sale the price of the jacket is reduced another 25%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount? Choose the correct choice from the following answers
A) 32.5 B) 35 C) 48.1 D) 65 E) 66.67 | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">80 * (1/4)</gadget>
<output>20</output>
<gadget id="calculator">80 - 20</gadget>
<output>60</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">40 / 60</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">100 * (2/3)</gadget>
<output>200/3 = around 66.666667</output>
<result>E</result> | E | 66.67 | The price of a jacket is reduced by 20%. During a special sale the price of the jacket is reduced another 25%. By approximately what percent must the price of the jacket now be increased in order to restore it to its original amount? | {
"A": "32.5",
"B": "35",
"C": "48.1",
"D": "65",
"E": "66.67"
} | multiply(const_100, divide(subtract(const_100, subtract(subtract(const_100, 20), multiply(subtract(const_100, 20), divide(25, const_100)))), subtract(subtract(const_100, 20), multiply(subtract(const_100, 20), divide(25, const_100))))) | divide(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|subtract(#1,#2)|subtract(const_100,#3)|divide(#4,#3)|multiply(#5,const_100)| | "1 ) let the price of jacket initially be $ 100 . 2 ) then it is decreased by 20 % , therefore bringing down the price to $ 80 . 3 ) again it is further discounted by 25 % , therefore bringing down the price to $ 60 . 4 ) now 60 has to be added byx % in order to equal the original price . 60 + ( x % ) 60 = 100 . solving this eq for x , we get x = 66.67 ans is e ." | gain |
math_qa__HE0FQ8C1XV7Q3Itp | A grocer purchased a quantity of bananas at 3 pounds for $0.50 and sold the entire quantity at 4 pounds for $1.00. How many pounds did the grocer purchase if the profit from selling the bananas was $9.00? Choose the correct choice: A) 40 B) 60 C) 90 D) 120 E) 108 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">0.5 / 3</gadget>
<output>0.166667</output>
<gadget id="calculator">(1/4) - 0.166667</gadget>
<output>0.083333</output>
<gadget id="calculator">9 / 0.083333</gadget>
<output>108.000432</output>
<result>E</result> | E | 108 | A grocer purchased a quantity of bananas at 3 pounds for $0.50 and sold the entire quantity at 4 pounds for $1.00. How many pounds did the grocer purchase if the profit from selling the bananas was $9.00? | {
"A": "40",
"B": "60",
"C": "90",
"D": "120",
"E": "108"
} | divide(9.00, subtract(divide(1.00, 4), divide(0.50, 3))) | divide(n3,n2)|divide(n1,n0)|subtract(#0,#1)|divide(n4,#2)| | "cost price of 1 pound of bananas = 0.5 / 3 = 1 / 6 selling price of 1 pound of bananas = 1 / 4 profit per pound = ( 1 / 4 - 1 / 6 ) = ( 1 / 12 ) total profit is given as 9 ( 1 / 12 ) * x = 9 x = 108 answer : e" | gain |
math_qa__B2CwiGu45mUrRFqs | The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 98, what is the difference between the ages of Patrick and Monica? Answers:
A) 32 B) 48 C) 45 D) 72 E) 18 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">9 + 15</gadget>
<output>24</output>
<gadget id="calculator">24 + 25</gadget>
<output>49</output>
<gadget id="calculator">98 / 49</gadget>
<output>2</output>
<gadget id="calculator">25 * 2</gadget>
<output>50</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<gadget id="calculator">50 - 18</gadget>
<output>32</output>
<result>A</result> | A | 32 | The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 98, what is the difference between the ages of Patrick and Monica? | {
"A": "32",
"B": "48",
"C": "45",
"D": "72",
"E": "18"
} | subtract(multiply(multiply(5, 5), divide(98, add(add(multiply(3, 3), multiply(3, 5)), multiply(5, 5)))), multiply(multiply(3, 3), divide(98, add(add(multiply(3, 3), multiply(3, 5)), multiply(5, 5))))) | multiply(n0,n0)|multiply(n1,n0)|multiply(n1,n3)|add(#0,#1)|add(#3,#2)|divide(n4,#4)|multiply(#5,#2)|multiply(#5,#0)|subtract(#6,#7)| | "ages of p and mi = 3 x : 5 x ages of mi and mo = 3 x : 5 x rationalizing their ages . ratio of their ages will be 9 x : 15 x : 25 x sum = 49 x = 98 x = 2 difference if ages of pa and mo = 25 x - 9 x = 16 x = 16 * 2 = 32 answer a" | general |
math_qa__pSwocd2mcfsuqC62 | Six dots are evenly spaced on the circumference of a circle. How many combinations of three dots can we make from these 6 dots that do not form an equilateral triangle?
Select:
A) 18 B) 17 C) 16 D) 15 E) 14 | <gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">720 / 36</gadget>
<output>20</output>
<gadget id="calculator">20 - 2</gadget>
<output>18</output>
<result>A</result> | A | 18 | Six dots are evenly spaced on the circumference of a circle. How many combinations of three dots can we make from these 6 dots that do not form an equilateral triangle? | {
"A": "18",
"B": "17",
"C": "16",
"D": "15",
"E": "14"
} | subtract(divide(factorial(6), multiply(factorial(const_3), factorial(const_3))), const_2) | factorial(n0)|factorial(const_3)|multiply(#1,#1)|divide(#0,#2)|subtract(#3,const_2) | the total number of ways we can choose three dots is 6 c 3 = 20 . we can form two equilateral triangles from these six dots . there are 20 - 2 = 18 combinations which do not form an equilateral triangle . the answer is a . | geometry |
math_qa__zgBI8027bwC7pIV1 | nd the area of trapezium whose parallel sides are 20 cm and 16 cm long, and the distance between them is 15 cm? Pick one:
A) 270 cm 2
B) 275 cm 2
C) 280 cm 2
D) 285 cm 2
E) 290 cm 2 | <gadget id="calculator">20 + 16</gadget>
<output>36</output>
<gadget id="calculator">15 * 36</gadget>
<output>540</output>
<gadget id="calculator">540 / 2</gadget>
<output>270</output>
<result>A</result> | A | 270 | nd the area of trapezium whose parallel sides are 20 cm and 16 cm long, and the distance between them is 15 cm? | {
"A": "270 cm 2",
"B": "275 cm 2",
"C": "280 cm 2",
"D": "285 cm 2",
"E": "290 cm 2"
} | divide(multiply(15, add(20, 16)), const_2) | add(n0,n1)|multiply(n2,#0)|divide(#1,const_2)| | "area of a trapezium = 1 / 2 ( sum of parallel sides ) * ( perpendicular distance between them ) = 1 / 2 ( 20 + 16 ) * ( 15 ) = 270 cm 2 answer : a" | physics |
math_qa__SPPgqlHfX7BNw9It | If all the 6 are replaced by 9, then the algebraic sum of all the numbers from 1 to 100 (both inclusive) varies by how much? Pick one:
A) 330
B) 360
C) 380
D) 400
E) 420 | <gadget id="calculator">9 - 6</gadget>
<output>3</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">30 * 10</gadget>
<output>300</output>
<gadget id="calculator">300 + 30</gadget>
<output>330</output>
<result>A</result> | A | 330 | If all the 6 are replaced by 9, then the algebraic sum of all the numbers from 1 to 100 (both inclusive) varies by how much? | {
"A": "330",
"B": "360",
"C": "380",
"D": "400",
"E": "420"
} | add(multiply(multiply(subtract(9, 6), const_10), const_10), multiply(subtract(9, 6), const_10)) | subtract(n1,n0)|multiply(#0,const_10)|multiply(#1,const_10)|add(#2,#1)| | "unit place increased by 3 . so 6 , 16,26 , . . . . 96 . total 10 * 3 = 30 increased . ten ' s place increased by 30 . so 60,61 , . . . 69 . total 10 * 30 = 300 increased . so total varies = 300 + 30 = 330 . answer : a" | general |
math_qa__1bbUhZvcKqLcaYzJ | A train 130 meters long takes 6 seconds to cross a man walking at 5 kmph in the direction opposite to that of the train. Find the speed of the train. Choose one: A) 45 kmph B) 50 kmph C) 55 kmph D) 60 kmph E) 73 kmph | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">6 * (5/18)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">130 / (5/3)</gadget>
<output>78</output>
<gadget id="calculator">78 - 5</gadget>
<output>73</output>
<result>E</result> | E | 73 | A train 130 meters long takes 6 seconds to cross a man walking at 5 kmph in the direction opposite to that of the train. Find the speed of the train. | {
"A": "45 kmph",
"B": "50 kmph",
"C": "55 kmph",
"D": "60 kmph",
"E": "73 kmph"
} | subtract(divide(130, multiply(6, const_0_2778)), 5) | multiply(n1,const_0_2778)|divide(n0,#0)|subtract(#1,n2)| | "explanation : let the speed of the train be x kmph . speed of the train relative to man = ( x + 5 ) kmph = ( x + 5 ) × 5 / 18 m / sec . therefore 130 / ( ( x + 5 ) × 5 / 18 ) = 6 < = > 30 ( x + 5 ) = 2340 < = > x = 73 speed of the train is 73 kmph . answer : option e" | physics |
math_qa__B8bVmz37zrMizTN5 | If y is 80% greater than x, than x is what % less than y? Pick.
A) 20 B) 25 C) 33 1 / 3 D) 44 4 / 9 E) 80 | <gadget id="calculator">80 + 100</gadget>
<output>180</output>
<gadget id="calculator">80 / 180</gadget>
<output>4/9 = around 0.444444</output>
<gadget id="calculator">(4/9) * 100</gadget>
<output>400/9 = around 44.444444</output>
<result>D</result> | D | 44 | If y is 80% greater than x, than x is what % less than y? | {
"A": "20",
"B": "25",
"C": "33 1 / 3",
"D": "44 4 / 9",
"E": "80"
} | multiply(divide(80, add(80, const_100)), const_100) | add(n0,const_100)|divide(n0,#0)|multiply(#1,const_100)| | "let x = 100 so y = 180 we want percentage change . so , ( 100 - 180 ) / 180 = - 44.44 % = 44 4 / 9 % lesser than y . hence option ( d ) ." | general |
math_qa__6qLNYgBgKedCTYbm | Every disk in a bag is either blue, yellow or green. The ratio of blue disks to yellow disks to green disks in this bag is 3 : 7 : 8. If the total number of disks in the bag is 108, how many more green disks than blue disks are in the bag? Select the correct option.
A) 25 B) 28 C) 30 D) 35 E) 40 | <gadget id="calculator">3 + 7</gadget>
<output>10</output>
<gadget id="calculator">10 + 8</gadget>
<output>18</output>
<gadget id="calculator">108 / 18</gadget>
<output>6</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<result>C</result> | C | 30 | Every disk in a bag is either blue, yellow or green. The ratio of blue disks to yellow disks to green disks in this bag is 3 : 7 : 8. If the total number of disks in the bag is 108, how many more green disks than blue disks are in the bag? | {
"A": "25",
"B": "28",
"C": "30",
"D": "35",
"E": "40"
} | multiply(divide(108, add(add(3, 7), 8)), subtract(8, 3)) | add(n0,n1)|subtract(n2,n0)|add(n2,#0)|divide(n3,#2)|multiply(#3,#1)| | "let b : y : g = 3 x : 7 x : 8 x . 3 x + 7 x + 8 x = 18 x = 108 - - > x = 6 . g - b = 8 x - 3 x = 5 x = 30 . the answer is c ." | general |
math_qa__XZWGYc9ZBtA379kt | A room is 7 meters 20 centimeters in length and 4 meters 32 centimeters in Width. Find the least number of square tiles of equal size required to cover the entire floor of the room. Answers: A) 10 B) 15 C) 17 D) 19 E) 21 | <gadget id="calculator">7 * 100</gadget>
<output>700</output>
<gadget id="calculator">700 + 20</gadget>
<output>720</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">400 + 32</gadget>
<output>432</output>
<gadget id="calculator">720 * 432</gadget>
<output>311_040</output>
<gadget id="calculator">gcd(720, 432)</gadget>
<output>144</output>
<gadget id="calculator">144 * 144</gadget>
<output>20_736</output>
<gadget id="calculator">311_040 / 20_736</gadget>
<output>15</output>
<result>B</result> | B | 15 | A room is 7 meters 20 centimeters in length and 4 meters 32 centimeters in Width. Find the least number of square tiles of equal size required to cover the entire floor of the room. | {
"A": "10",
"B": "15",
"C": "17",
"D": "19",
"E": "21"
} | divide(multiply(add(multiply(7, const_100), 20), add(multiply(4, const_100), 32)), multiply(gcd(add(multiply(7, const_100), 20), add(multiply(4, const_100), 32)), gcd(add(multiply(7, const_100), 20), add(multiply(4, const_100), 32)))) | multiply(n0,const_100)|multiply(n2,const_100)|add(n1,#0)|add(n3,#1)|gcd(#2,#3)|multiply(#2,#3)|multiply(#4,#4)|divide(#5,#6)| | "let us calculate both the length and width of the room in centimeters . length = 7 meters and 20 centimeters = 720 cm width = 4 meters and 32 centimeters = 432 cm as we want the least number of square tiles required , it means the length of each square tile should be as large as possible . further , the length of each square tile should be a factor of both the length and width of the room . hence , the length of each square tile will be equal to the hcf of the length and width of the room = hcf of 720 and 432 = 144 thus , the number of square tiles required = ( 720 x 432 ) / ( 144 x 144 ) = 5 x 3 = 15 answer : b" | general |
math_qa__BI0dmGSd09Mw4rp8 | A number is greater than 3 but less than 8. Also the number is greater than 6 but less than 10. What is the number? Choices
A) 5 B) 7 C) 6 D) 8 E) 9 | <gadget id="calculator">8 - 1</gadget>
<output>7</output>
<result>B</result> | B | 7 | A number is greater than 3 but less than 8. Also the number is greater than 6 but less than 10. What is the number? | {
"A": "5",
"B": "7",
"C": "6",
"D": "8",
"E": "9"
} | subtract(8, const_1) | subtract(n1,const_1) | b 7 | general |
math_qa__5pkNEUXyzxBsFvj3 | Efrida and Frazer who live 13 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is two miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home? Choose the correct choice from the following options.
A) 6 B) 7 C) 8 D) 10 E) 11 | <gadget id="calculator">13 ** 2</gadget>
<output>169</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">169 - 4</gadget>
<output>165</output>
<gadget id="calculator">165 / 2</gadget>
<output>165/2 = around 82.5</output>
<gadget id="calculator">(165/2) ** (1/2)</gadget>
<output>sqrt(330)/2 = around 9.082951</output>
<gadget id="calculator">(sqrt(330)/2) + 2</gadget>
<output>2 + sqrt(330)/2 = around 11.082951</output>
<result>E</result> | E | 11 | Efrida and Frazer who live 13 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is two miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home? | {
"A": "6",
"B": "7",
"C": "8",
"D": "10",
"E": "11"
} | add(sqrt(divide(subtract(power(13, const_2), power(const_2, const_2)), const_2)), const_2) | power(n0,const_2)|power(const_2,const_2)|subtract(#0,#1)|divide(#2,const_2)|sqrt(#3)|add(#4,const_2)| | "it ' s a simple geometry problem . look at the diagram below : answer : e ." | physics |
math_qa__deDkhhndBtUObs1U | Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 54 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him? Options:
A) 15 seconds B) 18 seconds C) 25 seconds D) 27 seconds E) 45 seconds | <gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">54 / 2</gadget>
<output>27</output>
<result>D</result> | D | 27 | Nicky and Cristina are running a race. Since Cristina is faster than Nicky, she gives him a 54 meter head start. If Cristina runs at a pace of 5 meters per second and Nicky runs at a pace of only 3 meters per second, how many seconds will Nicky have run before Cristina catches up to him? | {
"A": "15 seconds",
"B": "18 seconds",
"C": "25 seconds",
"D": "27 seconds",
"E": "45 seconds"
} | divide(54, subtract(5, 3)) | subtract(n1,n2)|divide(n0,#0)| | "used pluging in method say t is the time for cristina to catch up with nicky , the equation will be as under : for nicky = n = 3 * t + 54 for cristina = c = 5 * t @ t = 27 , n = 135 c = 135 right answer ans : d" | physics |
math_qa__oDuYQ7z1y1gEmMV4 | Susan can type 10 pages in 5 minutes. Mary can type 5 pages in 10 minutes. Working together, how many pages can they type in 30 minutes? Answers:
A) 15 B) 20 C) 25 D) 65 E) 75 | <gadget id="calculator">30 / 10</gadget>
<output>3</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">30 / 5</gadget>
<output>6</output>
<gadget id="calculator">10 * 6</gadget>
<output>60</output>
<gadget id="calculator">15 + 60</gadget>
<output>75</output>
<result>E</result> | E | 75 | Susan can type 10 pages in 5 minutes. Mary can type 5 pages in 10 minutes. Working together, how many pages can they type in 30 minutes? | {
"A": "15",
"B": "20",
"C": "25",
"D": "65",
"E": "75"
} | add(multiply(divide(30, 10), 5), multiply(10, divide(30, 5))) | divide(n4,n0)|divide(n4,n1)|multiply(n1,#0)|multiply(n0,#1)|add(#2,#3) | susan can type 2 pages in 1 min mary can type 0.5 pages in 1 min so , both of them work together they type 2.5 pages in 1 min so , in 30 min they type ( 30 * 2.5 ) = 75 pages answer : e | physics |
math_qa__7XLBy83HR1t0mSjX | (178% of 1265) ÷ 5.96 = ? Pick one:
A) 125 B) 175 C) 225 D) 375 E) 524 | <gadget id="calculator">178 / 100</gadget>
<output>89/50 = around 1.78</output>
<gadget id="calculator">(89/50) * 1_265</gadget>
<output>22_517/10 = around 2_251.7</output>
<gadget id="calculator">(22_517/10) / 5.96</gadget>
<output>377.802013</output>
<result>D</result> | D | 375 | (178% of 1265) ÷ 5.96 = ? | {
"A": "125",
"B": "175",
"C": "225",
"D": "375",
"E": "524"
} | divide(multiply(divide(178, const_100), 1265), 5.96) | divide(n0,const_100)|multiply(n1,#0)|divide(#1,n2) | explanation : ? = ( 178 x 1265 / 100 ) ÷ 6 = 2250 / 600 = 375 answer : option d | general |
math_qa__LLnp6k8Xw87g26dx | At the faculty of Aerospace Engineering, 312 students study Random-processing methods, 234 students study Scramjet rocket engines and 112 students study them both. If every student in the faculty has to study one of the two subjects, how many students are there in the faculty of Aerospace Engineering? Choose one:
A) 430
B) 434
C) 438
D) 444
E) 446 | <gadget id="calculator">112 / 2</gadget>
<output>56</output>
<gadget id="calculator">312 - 56</gadget>
<output>256</output>
<gadget id="calculator">234 - 56</gadget>
<output>178</output>
<gadget id="calculator">256 + 178</gadget>
<output>434</output>
<result>B</result> | B | 434 | At the faculty of Aerospace Engineering, 312 students study Random-processing methods, 234 students study Scramjet rocket engines and 112 students study them both. If every student in the faculty has to study one of the two subjects, how many students are there in the faculty of Aerospace Engineering? | {
"A": "430",
"B": "434",
"C": "438",
"D": "444",
"E": "446"
} | add(subtract(312, divide(112, const_2)), subtract(234, divide(112, const_2))) | divide(n2,const_2)|subtract(n0,#0)|subtract(n1,#0)|add(#1,#2)| | "312 + 234 - 112 ( since 112 is counted twice ) = 434 b is the answer" | other |
math_qa__d1HVtuza0XGN7rkF | After spending Rs. 5000 on rent, Rs. 1500 on milk, Rs. 4500 on groceries, Rs.2500 On childrens education Rs. 2000 on petrol and Rs. 6100 on miscellaneous expenses, Mr. Kishore saved 10% of his monthly salary. How much did he save in Rs. ? Pick:
A) 2160 B) 2350 C) 2000 D) 2300 E) 2400 | <gadget id="calculator">5_000 + 1_500</gadget>
<output>6_500</output>
<gadget id="calculator">6_500 + 4_500</gadget>
<output>11_000</output>
<gadget id="calculator">11_000 + 2_500</gadget>
<output>13_500</output>
<gadget id="calculator">13_500 + 2_000</gadget>
<output>15_500</output>
<gadget id="calculator">15_500 + 6_100</gadget>
<output>21_600</output>
<gadget id="calculator">21_600 * 100</gadget>
<output>2_160_000</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">2_160_000 / 90</gadget>
<output>24_000</output>
<gadget id="calculator">24_000 - 21_600</gadget>
<output>2_400</output>
<result>E</result> | E | 2,400 | After spending Rs. 5000 on rent, Rs. 1500 on milk, Rs. 4500 on groceries, Rs.2500 On childrens education Rs. 2000 on petrol and Rs. 6100 on miscellaneous expenses, Mr. Kishore saved 10% of his monthly salary. How much did he save in Rs. ? | {
"A": "2160",
"B": "2350",
"C": "2000",
"D": "2300",
"E": "2400"
} | subtract(divide(multiply(add(add(add(add(add(5000, 1500), 4500), 2500), 2000), 6100), const_100), subtract(const_100, 10)), add(add(add(add(add(5000, 1500), 4500), 2500), 2000), 6100)) | add(n0,n1)|subtract(const_100,n6)|add(n2,#0)|add(n3,#2)|add(n4,#3)|add(n5,#4)|multiply(#5,const_100)|divide(#6,#1)|subtract(#7,#5)| | "explanation : total exp = 5000 + 1500 + 4500 + 2500 + 2000 + 6100 = 21600 exp in % = 100 - 10 = 90 % , 21600 = 90 % saving = 10 % = 21600 x 10 / 90 = rs . 2400 answer : e" | general |
math_qa__iexiwD65bFsn8fpp | In a hostel, the number of students decreased by 10% and the price of food increased by 20% over the previous year. If each student consumes the same amount of food then By how much should the consumption of food be cut short by every student, so that the total cost of the food remains the same as that of the previous year? Answers
A) 19 %
B) 15 %
C) 25 %
D) 40 %
E) 7.4 % | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">90 * 120</gadget>
<output>10_800</output>
<gadget id="calculator">10_000 / 10_800</gadget>
<output>25/27 = around 0.925926</output>
<gadget id="calculator">1 - (25/27)</gadget>
<output>2/27 = around 0.074074</output>
<gadget id="calculator">(2/27) * 100</gadget>
<output>200/27 = around 7.407407</output>
<result>E</result> | E | 7.4 | In a hostel, the number of students decreased by 10% and the price of food increased by 20% over the previous year. If each student consumes the same amount of food then By how much should the consumption of food be cut short by every student, so that the total cost of the food remains the same as that of the previous year? | {
"A": "19 %",
"B": "15 %",
"C": "25 %",
"D": "40 %",
"E": "7.4 %"
} | multiply(subtract(const_1, divide(multiply(const_100, const_100), multiply(subtract(const_100, 10), add(const_100, 20)))), const_100) | add(n1,const_100)|multiply(const_100,const_100)|subtract(const_100,n0)|multiply(#0,#2)|divide(#1,#3)|subtract(const_1,#4)|multiply(#5,const_100)| | "cost of food ( c ) = food consumed per student ( f ) * number of students ( n ) * price of food ( p ) originally , c = fnp when number of students decrease by 8 % , and the price of food increases by 20 % , c = f ( new ) * ( 0.9 n ) * ( 1.2 p ) = > f ( new ) = f / ( 0.9 * 1.2 ) = > f ( new ) = 0.9259 f therefore the new cost of food must be 92.59 % of the old cost , or the cost of food must decrease by 7.4 % ( option e )" | general |
math_qa__uq2iWrl9kmjFwuek | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 63 kmph, find the speed of the stream? Pick
A) 15
B) 19
C) 14
D) 21
E) 16 | <gadget id="calculator">63 * 2</gadget>
<output>126</output>
<gadget id="calculator">126 / 3</gadget>
<output>42</output>
<gadget id="calculator">63 - 42</gadget>
<output>21</output>
<result>D</result> | D | 21 | The time taken by a man to row his boat upstream is twice the time taken by him to row the same distance downstream. If the speed of the boat in still water is 63 kmph, find the speed of the stream? | {
"A": "15",
"B": "19",
"C": "14",
"D": "21",
"E": "16"
} | subtract(63, divide(multiply(63, const_2), const_3)) | multiply(n0,const_2)|divide(#0,const_3)|subtract(n0,#1)| | "the ratio of the times taken is 2 : 1 . the ratio of the speed of the boat in still water to the speed of the stream = ( 2 + 1 ) / ( 2 - 1 ) = 3 / 1 = 3 : 1 speed of the stream = 63 / 3 = 21 kmph . answer : d" | physics |
math_qa__LphCwQIXVx5wKM2C | If the sales tax reduced from 3 1/2 % to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 6600 ? Choose the correct choice from the following choices: A) 11 B) 13 C) 14 D) 18 E) 10 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) + 3</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) + 3</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">(7/2) - (10/3)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/6) * 6_600</gadget>
<output>1_100</output>
<gadget id="calculator">1_100 / 100</gadget>
<output>11</output>
<result>A</result> | A | 11 | If the sales tax reduced from 3 1/2 % to 3 1/3%, then what difference does it make to a person who purchases an article with market price of Rs. 6600 ? | {
"A": "11",
"B": "13",
"C": "14",
"D": "18",
"E": "10"
} | divide(multiply(subtract(add(divide(1, 2), 3), add(divide(1, 3), 3)), 6600), const_100) | divide(n1,n2)|divide(n1,n0)|add(n0,#0)|add(n0,#1)|subtract(#2,#3)|multiply(n6,#4)|divide(#5,const_100)| | "required difference = [ 3 ½ % of rs . 6600 ] – [ 3 1 / 3 % of rs . 6600 ] = [ ( 7 / 20 - ( 10 / 3 ) ] % of rs . 6600 = 1 / 6 % of rs . 6600 = rs . [ ( 1 / 6 ) 8 ( 1 / 100 ) * 6600 ] = rs . 11 . answer is a ." | general |
math_qa__dFuyVFf8ie6ZQX06 | Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 7x boxes? Choices: A) 3 minutes B) 4 minutes C) 5 minutes D) 14 minutes E) 12 minutes | <gadget id="calculator">7 * 10</gadget>
<output>70</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">70 / 5</gadget>
<output>14</output>
<result>D</result> | D | 14 | Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 7x boxes? | {
"A": "3 minutes",
"B": "4 minutes",
"C": "5 minutes",
"D": "14 minutes",
"E": "12 minutes"
} | divide(multiply(7, 10), add(speed(10, 10), speed(multiply(2, 10), 5))) | multiply(n0,n3)|multiply(n0,n1)|speed(n0,n0)|speed(#1,n2)|add(#2,#3)|divide(#0,#4)| | "rate = work / time given rate of machine a = x / 10 min machine b produces 2 x boxes in 5 min hence , machine b produces 4 x boxes in 10 min . rate of machine b = 4 x / 10 we need tofind the combined time that machines a and b , working simultaneouslytakeat their respective constant rates let ' s first find the combined rate of machine a and b rate of machine a = x / 10 min + rate of machine b = 4 x / 10 = 5 x / 10 now combine time = combine work needs to be done / combine rate = 7 x / 5 x * 10 = 14 min ans : d" | physics |
math_qa__xbLHpIbuQKC4ukDh | In a Shop, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit?
Choose the correct choice from the following: A) 70 % B) 50 % C) 100 % D) 60 % E) 55 % | <gadget id="calculator">320 + 100</gadget>
<output>420</output>
<gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">420 - 125</gadget>
<output>295</output>
<gadget id="calculator">295 / 420</gadget>
<output>59/84 = around 0.702381</output>
<gadget id="calculator">(59/84) * 100</gadget>
<output>1_475/21 = around 70.238095</output>
<result>A</result> | A | 70 | In a Shop, the profit is 320% of the cost. If the cost increases by 25% but the selling price remains constant, approximately what percentage of the selling price is the profit? | {
"A": "70 %",
"B": "50 %",
"C": "100 %",
"D": "60 %",
"E": "55 %"
} | multiply(divide(subtract(add(320, const_100), add(25, const_100)), add(320, const_100)), const_100) | add(n0,const_100)|add(n1,const_100)|subtract(#0,#1)|divide(#2,#0)|multiply(#3,const_100)| | "cp . = rs . 100 . = > profit = rs . 320 , s . p . = rs . 420 . new c . p . = 125 % of rs . 100 = rs . 125 new s . p . = rs . 420 . profit = rs . ( 420 - 125 ) = rs . 295 . req = ( 295 / 420 * 100 ) = = > 70 % answer a" | gain |
math_qa__Bd9wM6O6ZtGBlY34 | 2 trains in same direction at 50km/hr,32 km/hr.A man in slower train observes 15 sec elapse before the faster train completely passed by him what is length of faster train? Select
A) 65 meters B) 75 meters C) 85 meters D) 95 meters E) 55 meters | <gadget id="calculator">50 - 32</gadget>
<output>18</output>
<gadget id="calculator">18 * 1_000</gadget>
<output>18_000</output>
<gadget id="calculator">18_000 / 3_600</gadget>
<output>5</output>
<gadget id="calculator">5 * 15</gadget>
<output>75</output>
<result>B</result> | B | 75 | 2 trains in same direction at 50km/hr,32 km/hr.A man in slower train observes 15 sec elapse before the faster train completely passed by him what is length of faster train? | {
"A": "65 meters",
"B": "75 meters",
"C": "85 meters",
"D": "95 meters",
"E": "55 meters"
} | multiply(divide(multiply(subtract(50, 32), const_1000), const_3600), 15) | subtract(n1,n2)|multiply(#0,const_1000)|divide(#1,const_3600)|multiply(n3,#2) | relative speed = 18 k / hr = 5 m / sec distance covered = length of faster train = 5 * 15 = 75 meters answer : b | physics |
math_qa__CL0MaDXKZYmFCx67 | X and Y started a business by investing Rs.36000 and Rs.42000 respectively after 4 months Z joined in the business with an investment of Rs.48000, then find share of Z in the profit of Rs.13860 ? Pick one
A) 4032
B) 4000
C) 3250
D) 3825
E) 3985 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">48_000 * 8</gadget>
<output>384_000</output>
<gadget id="calculator">36_000 * 12</gadget>
<output>432_000</output>
<gadget id="calculator">42_000 * 12</gadget>
<output>504_000</output>
<gadget id="calculator">432_000 + 504_000</gadget>
<output>936_000</output>
<gadget id="calculator">936_000 + 384_000</gadget>
<output>1_320_000</output>
<gadget id="calculator">13_860 / 1_320_000</gadget>
<output>21/2_000 = around 0.0105</output>
<gadget id="calculator">384_000 * (21/2_000)</gadget>
<output>4_032</output>
<result>A</result> | A | 4,032 | X and Y started a business by investing Rs.36000 and Rs.42000 respectively after 4 months Z joined in the business with an investment of Rs.48000, then find share of Z in the profit of Rs.13860 ? | {
"A": "4032",
"B": "4000",
"C": "3250",
"D": "3825",
"E": "3985"
} | multiply(multiply(48000, subtract(multiply(const_3, 4), 4)), divide(13860, add(add(multiply(36000, multiply(const_3, 4)), multiply(42000, multiply(const_3, 4))), multiply(48000, subtract(multiply(const_3, 4), 4))))) | multiply(const_3,n2)|multiply(n0,#0)|multiply(n1,#0)|subtract(#0,n2)|add(#1,#2)|multiply(n3,#3)|add(#4,#5)|divide(n4,#6)|multiply(#7,#5)| | "ratio of investment , as investments is for different time . investment x number of units of time . ratio of investments x : y : z = 36000 : 42000 : 48000 = > 6 : 7 : 8 . x = 6 x 12 months = 72 , y = 7 x 12 = 84 , z = 8 x 8 = 64 = > 18 : 21 : 16 . ratio of investments = > x : y : z = 18 : 21 : 16 . investment ratio = profit sharing ratio . z = 13860 ã — 16 / 55 = rs . 4032 . share of z in the profit is rs . 4032 . option a" | gain |
math_qa__6IJgTdKQnVlpqqmg | From the digits 2, 3, 4, 5, 6 and 7, how many 5-digit numbers can be formed that have distinct digits and are multiples of 12? Pick one:
A) 36 B) 60 C) 84 D) 72 E) 86 | <gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">36 + 24</gadget>
<output>60</output>
<result>B</result> | B | 60 | From the digits 2, 3, 4, 5, 6 and 7, how many 5-digit numbers can be formed that have distinct digits and are multiples of 12? | {
"A": "36",
"B": "60",
"C": "84",
"D": "72",
"E": "86"
} | add(multiply(factorial(subtract(5, const_2)), multiply(const_2, const_3)), multiply(const_4, factorial(subtract(5, const_2)))) | multiply(const_2,const_3)|subtract(n3,const_2)|factorial(#1)|multiply(#2,#0)|multiply(#2,const_4)|add(#3,#4) | detailed solution any multiple of 12 should be a multiple of 4 and 3 . first , let us look at the constraint for a number being a multiple of 3 . sum of the digits should be a multiple of 3 . sum of all numbers from 2 to 7 is 27 . so , if we have to drop a digit and still retain a multiple of 3 , we should drop either 3 or 6 . so , the possible 5 digits are 2 , 4 , 5 , 6 , 7 or 2 , 3 , 4 , 5 , 7 . when the digits are 2 , 4 , 5 , 6 , 7 . the last two digits possible for the number to be a multiple of 4 are 24 , 64 , 52 , 72 , 56 , 76 . for each of these combinations , there are 6 different numbers possible . so , with this set of 5 digits we can have 36 different numbers . when the digits are 2 , 3 , 4 , 5 , 7 . the last two digits possible for the number to be a multiple of 4 are 32 , 52 , 72 , 24 . for each of these combinations , there are 6 different numbers possible . so , with this set of 5 digits we can have 24 different numbers . overall , there are 60 different 5 - digit numbers possible . correct answer : b | general |
math_qa__2R5ZcrkQp9JGLM2G | The difference between the local value and the face value of 8 in the numeral 96348621 is
Choose the correct choice from the following:
A) 6992 B) 6982 C) 7982 D) 7972 E) 7992 | <gadget id="calculator">8 * 1_000</gadget>
<output>8_000</output>
<gadget id="calculator">8_000 - 8</gadget>
<output>7_992</output>
<result>E</result> | E | 7,992 | The difference between the local value and the face value of 8 in the numeral 96348621 is | {
"A": "6992",
"B": "6982",
"C": "7982",
"D": "7972",
"E": "7992"
} | subtract(multiply(8, const_1000), 8) | multiply(n0,const_1000)|subtract(#0,n0)| | "explanation : ( local value of 8 ) - ( face value of 8 ) = ( 8000 - 8 ) = 7992 e )" | general |
math_qa__5os0KyuzdM20koRf | Find the ratio in which rice at Rs.7.20 a kg be mixed with rice at Rs.5.80 a kg to produce a mixture worth Rs.6.30 a kg? Choose the correct answer: A) 5 : 9 B) 2 : 3 C) 3 : 4 D) 4 : 5 E) none of these | <gadget id="calculator">6.3 - 5.8</gadget>
<output>0.5</output>
<gadget id="calculator">7.2 - 6.3</gadget>
<output>0.9</output>
<gadget id="calculator">0.5 / 0.9</gadget>
<output>0.555556</output>
<result>A</result> | A | 0.555556 | Find the ratio in which rice at Rs.7.20 a kg be mixed with rice at Rs.5.80 a kg to produce a mixture worth Rs.6.30 a kg? | {
"A": "5 : 9",
"B": "2 : 3",
"C": "3 : 4",
"D": "4 : 5",
"E": "none of these"
} | divide(subtract(6.30, 5.80), subtract(7.20, 6.30)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)| | "solution required ratio = 50 : 90 = 5 : 9 answer a" | other |
math_qa__habyI0TpjNjxGCYT | Three pipes, A, B, & C are attached to a tank. A & B can fill it in 20 & 30 minutes respectively while C can empty it in 15 minutes. If A, B & C are kept open successively for 4 minute each, how soon will the tank be filled? Choose the correct choice: A) 2 hours B) 12 hours C) 3 hours D) 5 hours E) 6 hours | <gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<result>B</result> | B | 12 | Three pipes, A, B, & C are attached to a tank. A & B can fill it in 20 & 30 minutes respectively while C can empty it in 15 minutes. If A, B & C are kept open successively for 4 minute each, how soon will the tank be filled? | {
"A": "2 hours",
"B": "12 hours",
"C": "3 hours",
"D": "5 hours",
"E": "6 hours"
} | add(add(4, 4), 4) | add(n3,n3)|add(n3,#0) | in three minute 1 / 20 + 1 / 30 - 1 / 15 = 1 / 60 part is filled 12 min - - - - - - - - 1 / 60 parts x min - - - - - - - - - 1 part ( full ) x = 720 min = 12 hours answer : b | physics |
math_qa__osIksYyeR8IUB7di | When positive integer x is divided by 8, the quotient is y and the remainder is 2. When 2x is divided by 7, the quotient is 2y and the remainder is 4. What is the value of 6y – x? Options.
A) - 1 B) 1 C) - 2 D) 2 E) - 3 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 4</gadget>
<output>0</output>
<gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">2 * 8</gadget>
<output>16</output>
<gadget id="calculator">14 - 16</gadget>
<output>-2</output>
<gadget id="calculator">0 / (-2)</gadget>
<output>0</output>
<gadget id="calculator">6 * 0</gadget>
<output>0</output>
<gadget id="calculator">8 * 0</gadget>
<output>0</output>
<gadget id="calculator">0 + 2</gadget>
<output>2</output>
<gadget id="calculator">0 - 2</gadget>
<output>-2</output>
<result>C</result> | C | -2 | When positive integer x is divided by 8, the quotient is y and the remainder is 2. When 2x is divided by 7, the quotient is 2y and the remainder is 4. What is the value of 6y – x? | {
"A": "- 1",
"B": "1",
"C": "- 2",
"D": "2",
"E": "- 3"
} | subtract(multiply(6, divide(subtract(multiply(2, 2), 4), subtract(multiply(7, 2), multiply(2, 8)))), add(multiply(8, divide(subtract(multiply(2, 2), 4), subtract(multiply(7, 2), multiply(2, 8)))), 2)) | multiply(n1,n2)|multiply(n3,n4)|multiply(n0,n2)|subtract(#0,n5)|subtract(#1,#2)|divide(#3,#4)|multiply(n6,#5)|multiply(n0,#5)|add(n1,#7)|subtract(#6,#8)| | "( 1 ) x = 8 y + 2 ( 2 ) 2 x = 14 y + 4 ( 2 ) - ( 1 ) : x = 6 y + 2 6 y - x = - 2 the answer is c ." | general |
math_qa__412uk8iVx0blZl5x | If N = 2^0.15 and N^b = 32, b must equal Choose the correct option.
A) 3 / 80 B) 3 / 5 C) 4 D) 100 / 3 E) 80 / 3 | <gadget id="calculator">log(32)</gadget>
<output>log(32) = around 3.465736</output>
<gadget id="calculator">2 ** 0.15</gadget>
<output>1.109569</output>
<gadget id="calculator">log(1.109569)</gadget>
<output>0.103972</output>
<gadget id="calculator">log(32) / 0.103972</gadget>
<output>9.61797406994191*log(32) = around 33.333358</output>
<result>D</result> | D | 33.333333 | If N = 2^0.15 and N^b = 32, b must equal | {
"A": "3 / 80",
"B": "3 / 5",
"C": "4",
"D": "100 / 3",
"E": "80 / 3"
} | divide(log(32), log(power(2, 0.15))) | log(n2)|power(n0,n1)|log(#1)|divide(#0,#2)| | "15 / 100 = 3 / 20 n = 2 ^ 3 / 20 n ^ b = 2 ^ 5 ( 2 ^ 3 / 20 ) ^ b = 2 ^ 5 b = 100 / 3 answer : d" | general |
math_qa__kYtlkJB9NwyxYvAb | A man is 25 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is Select
A) 21 B) 22 C) 20 D) 18 E) 23 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">25 - 2</gadget>
<output>23</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">23 / 1</gadget>
<output>23</output>
<result>E</result> | E | 23 | A man is 25 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is | {
"A": "21",
"B": "22",
"C": "20",
"D": "18",
"E": "23"
} | divide(subtract(25, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1)) | multiply(const_2,const_2)|subtract(const_2,const_1)|subtract(#0,const_2)|subtract(n0,#2)|divide(#3,#1)| | "explanation : let the son ' s present age be x years . then , man ' s present age = ( x + 25 ) years = > ( x + 25 ) + 2 = 2 ( x + 2 ) = > x + 27 = 2 x + 4 so , x = 23 . answer : e" | general |
math_qa__64GamVPYBtiwb7J6 | If m is a positive integer and m^2 is divisible by 54, then the largest positive integer that must divide m is?
Options: A) 3 B) 6 C) 18 D) 12 E) 16 | <gadget id="calculator">54 / 3</gadget>
<output>18</output>
<gadget id="calculator">18 / 3</gadget>
<output>6</output>
<gadget id="calculator">3 * 6</gadget>
<output>18</output>
<result>C</result> | C | 18 | If m is a positive integer and m^2 is divisible by 54, then the largest positive integer that must divide m is? | {
"A": "3",
"B": "6",
"C": "18",
"D": "12",
"E": "16"
} | multiply(const_3, divide(divide(54, const_3), const_3)) | divide(n1,const_3)|divide(#0,const_3)|multiply(#1,const_3) | m ^ 2 is divisible by 48 so m ^ 2 must be multiple of 48 . if the value of m is multiples of 18 then it will satisfy the condition . if we if m is 12 or 24 or 36 then it ans is c but if m = 54 then answer should be 16 . is the question right ? or am i missing some thing ? c | general |
math_qa__BPBTEqaFU7xj2ui1 | If 24 lines are drawn in a plane such that no two of them are parallel and no three are concurrent, then in how many points do they intersect?
Pick
A) 276 B) 350 C) 425 D) 512 E) 648 | <gadget id="calculator">factorial(24)</gadget>
<output>620_448_401_733_239_439_360_000</output>
<gadget id="calculator">24 - 2</gadget>
<output>22</output>
<gadget id="calculator">factorial(22)</gadget>
<output>1_124_000_727_777_607_680_000</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">1_124_000_727_777_607_680_000 * 2</gadget>
<output>2_248_001_455_555_215_360_000</output>
<gadget id="calculator">620_448_401_733_239_439_360_000 / 2_248_001_455_555_215_360_000</gadget>
<output>276</output>
<result>A</result> | A | 276 | If 24 lines are drawn in a plane such that no two of them are parallel and no three are concurrent, then in how many points do they intersect? | {
"A": "276",
"B": "350",
"C": "425",
"D": "512",
"E": "648"
} | divide(factorial(24), multiply(factorial(subtract(24, const_2)), factorial(const_2))) | factorial(n0)|factorial(const_2)|subtract(n0,const_2)|factorial(#2)|multiply(#3,#1)|divide(#0,#4)| | "if two lines are not parallel , then they will intersect in exactly one point . lines can be extended infinitely on both ends so somewhere they will intersect with each other if they are not parallel . we are also given that no three lines are concurrent . this means that no three lines intersect at the same point . so every pair of two lines we select will have a unique point of intersection which they will not share with any third line . the number of ways to select 2 lines from 24 lines is 24 c 2 = 276 the answer is a ." | physics |
math_qa__2r9v5tsbgMLhPJ98 | A marching band of 240 musicians are to march in a rectangular formation with s rows of exactly t musicians each. There can be no less than 8 musicians per row and no more than 30 musicians per row. How many different rectangular formations P are possible? Pick one:
A) 3 B) 4 C) 5 D) 6 E) p = 8 | <gadget id="calculator">240 / 30</gadget>
<output>8</output>
<result>E</result> | E | 8 | A marching band of 240 musicians are to march in a rectangular formation with s rows of exactly t musicians each. There can be no less than 8 musicians per row and no more than 30 musicians per row. How many different rectangular formations P are possible? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "p = 8"
} | divide(240, 30) | divide(n0,n2)| | "the combinations could be p { ( 1,240 ) , ( 2,120 ) , ( 3,80 ) , ( 4,60 ) , ( 5,48 ) , ( 6,40 ) , ( 8,30 ) , ( 10,24 ) , ( 12,20 ) , ) 15,16 ) , ( 16,15 ) , ( 20,12 ) , ( 24,10 ) , ( 30,8 ) , ( 40,6 ) , ( 48,5 ) , ( 60,4 ) , ( 80,3 ) , ( 120,2 ) , ( 240,1 ) } of these we are told 8 < = t < = 30 so we can remove these pairs , and we are left only with . { ( 8,30 , ( 10,24 ) , ( 12,20 ) , ( 15,16 ) , ( 16,15 ) , ( 20,12 ) , ( 24,10 ) , ( 30,8 ) } hence 8 . e" | general |
math_qa__BhLn7qYBO0zc6vnf | For every X, the action [X] is defined: [X] is the greatest integer less than or equal to X. What is the value of [6.5] x [2/3] + [2] x 7.2 + [8.4] - 6.2? Choose the correct choice from the following choices.
A) 12.6 . B) 14.4 . C) 15.8 . D) 16.2 . E) 16.4 . | <gadget id="calculator">2 * 7.2</gadget>
<output>14.4</output>
<gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">8.4 - (2/5)</gadget>
<output>8</output>
<gadget id="calculator">14.4 + 8</gadget>
<output>22.4</output>
<gadget id="calculator">22.4 - 6.2</gadget>
<output>16.2</output>
<result>D</result> | D | 16.2 | For every X, the action [X] is defined: [X] is the greatest integer less than or equal to X. What is the value of [6.5] x [2/3] + [2] x 7.2 + [8.4] - 6.2? | {
"A": "12.6 .",
"B": "14.4 .",
"C": "15.8 .",
"D": "16.2 .",
"E": "16.4 ."
} | subtract(add(multiply(2, 7.2), subtract(8.4, divide(const_4, const_10))), 6.2) | divide(const_4,const_10)|multiply(n1,n4)|subtract(n5,#0)|add(#1,#2)|subtract(#3,n6)| | "[ 6.5 ] x [ 2 / 3 ] + [ 2 ] x 7.2 + [ 8.4 ] - 6.2 = 6 * 0 + 2 * 7.2 + 8 - 6.2 = 0 + 14.4 + 1.8 16.2 answer d" | general |
math_qa__9OffdFd3ifTs2nQ0 | Efrida and Frazer who live 12 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is two miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home?
Options:
A) 6 B) 7 C) 8 D) 10 E) 11 | <gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">144 - 4</gadget>
<output>140</output>
<gadget id="calculator">140 / 2</gadget>
<output>70</output>
<gadget id="calculator">70 ** (1/2)</gadget>
<output>sqrt(70) = around 8.3666</output>
<gadget id="calculator">(sqrt(70)) + 2</gadget>
<output>2 + sqrt(70) = around 10.3666</output>
<result>D</result> | D | 10 | Efrida and Frazer who live 12 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is two miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home? | {
"A": "6",
"B": "7",
"C": "8",
"D": "10",
"E": "11"
} | add(sqrt(divide(subtract(power(12, const_2), power(const_2, const_2)), const_2)), const_2) | power(n0,const_2)|power(const_2,const_2)|subtract(#0,#1)|divide(#2,const_2)|sqrt(#3)|add(#4,const_2)| | "it ' s a simple geometry problem . look at the diagram below : answer : d ." | physics |
math_qa__WBoz4L9NBZfNXbUq | A full stationary oil tank that is a right circular cylinder has a radius of 100 feet and a height of 25 feet. Oil is pumped from the stationary tank to an oil truck that has a tank that is a right circular cylinder until the truck's tank is completely filled. If the truck's tank has a radius of 7 feet and a height of 10 feet, how far (in feet) did the oil level drop in the stationary tank? Choose the correct choice from the following choices: A) 0.07 B) 0.049 C) 0.7 D) 0.49 E) 4.9 | <gadget id="calculator">pi * (7 ** 2) * 10</gadget>
<output>490*pi = around 1_539.3804</output>
<gadget id="calculator">pi * (100 ** 2)</gadget>
<output>10000*pi = around 31_415.926536</output>
<gadget id="calculator">(490*pi) / (10000*pi)</gadget>
<output>49/1_000 = around 0.049</output>
<result>B</result> | B | 0.049 | A full stationary oil tank that is a right circular cylinder has a radius of 100 feet and a height of 25 feet. Oil is pumped from the stationary tank to an oil truck that has a tank that is a right circular cylinder until the truck's tank is completely filled. If the truck's tank has a radius of 7 feet and a height of 10 feet, how far (in feet) did the oil level drop in the stationary tank? | {
"A": "0.07",
"B": "0.049",
"C": "0.7",
"D": "0.49",
"E": "4.9"
} | divide(volume_cylinder(7, 10), circle_area(100)) | circle_area(n0)|volume_cylinder(n2,n3)|divide(#1,#0)| | "the volume of oil pumped to the tank = the volume of oil taken away from stationary cylinder . pi * 49 * 10 = pi * h * 100 * 100 ( h is distance that the oil level dropped ) h = 490 / 10,000 = 49 / 1000 = 0.049 ft the answer is b ." | geometry |
math_qa__REsJorMo6gOGbcpS | At the end of the first quarter, the share price of a certain mutual fund was 25 percent higher than it was at the beginning of the year. At the end of the second quarter, the share price was 80 percent higher than it was at the beginning of the year. What was the percent increase in the share price from the end of the first quarter to the end of the second quarter? Pick one.
A) 20 % B) 25 % C) 30 % D) 33 % E) 44 % | <gadget id="calculator">100 + 80</gadget>
<output>180</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">180 / 125</gadget>
<output>36/25 = around 1.44</output>
<gadget id="calculator">(36/25) - 1</gadget>
<output>11/25 = around 0.44</output>
<gadget id="calculator">(11/25) * 100</gadget>
<output>44</output>
<result>E</result> | E | 44 | At the end of the first quarter, the share price of a certain mutual fund was 25 percent higher than it was at the beginning of the year. At the end of the second quarter, the share price was 80 percent higher than it was at the beginning of the year. What was the percent increase in the share price from the end of the first quarter to the end of the second quarter? | {
"A": "20 %",
"B": "25 %",
"C": "30 %",
"D": "33 %",
"E": "44 %"
} | multiply(subtract(divide(add(const_100, 80), add(const_100, 25)), const_1), const_100) | add(n1,const_100)|add(n0,const_100)|divide(#0,#1)|subtract(#2,const_1)|multiply(#3,const_100)| | "another method is to use the formula for 2 successive percentage changes : total = a + b + ab / 100 80 = 25 + b + 25 b / 100 b = 44 answer ( e )" | gain |
math_qa__qLf1aJmRuDeMYoYR | By selling an article for $100 a man gains $20 then his gain%? Options: A) 25 % B) 30 % C) 50 % D) 20 % E) 10 % | <gadget id="calculator">20 * 100</gadget>
<output>2_000</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">2_000 / 80</gadget>
<output>25</output>
<result>A</result> | A | 25 | By selling an article for $100 a man gains $20 then his gain%? | {
"A": "25 %",
"B": "30 %",
"C": "50 %",
"D": "20 %",
"E": "10 %"
} | divide(multiply(20, const_100), subtract(100, 20)) | multiply(n1,const_100)|subtract(n0,n1)|divide(#0,#1)| | "s . p . = $ 100 gain = $ 20 c . p . = 100 - 20 = 80 gain % = 20 / 80 * 100 = 25 % answer is a" | gain |
math_qa__OANHfGv3p34DIH8V | John traveled 80% of the way from Yellow-town to Green-fields by train at an average speed of 80 miles per hour. The rest of the way John traveled by car at an average speed of v miles per hour. If the average speed for the entire trip was 50 miles per hour, what is v in miles per hour? Select: A) 20 B) 40 C) 50 D) 55 E) 70 | <gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">100 / 50</gadget>
<output>2</output>
<gadget id="calculator">80 / 80</gadget>
<output>1</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">20 * 1</gadget>
<output>20</output>
<result>A</result> | A | 20 | John traveled 80% of the way from Yellow-town to Green-fields by train at an average speed of 80 miles per hour. The rest of the way John traveled by car at an average speed of v miles per hour. If the average speed for the entire trip was 50 miles per hour, what is v in miles per hour? | {
"A": "20",
"B": "40",
"C": "50",
"D": "55",
"E": "70"
} | multiply(subtract(const_100, 80), subtract(divide(const_100, 50), divide(80, 80))) | divide(const_100,n2)|divide(n0,n0)|subtract(const_100,n0)|subtract(#0,#1)|multiply(#2,#3) | hibunuel the question seems incorrect . it should not be 80 % at the speed of 80 . however if it ' s 20 % at the speed of 80 , answer comes out 55 . the question is correct . here ' s the explanation : let distance be d . we can find the total timeequate it , which comes as : 0.8 d / 80 + 0.2 d / v = d / 50 = > v = 20 ( option a ) . | physics |
math_qa__FQszNrDN6ged7rTh | John purchased a grinder and a mobile for Rs. 15000 &Rs. 8000 respectively. He sold the grinder at a loss of 5% and the mobile phone at a profit of 10%. Overall how much he make a profit. Choices:
A) s . 90 B) s . 120 C) s . 200 D) s . 50 E) s . 290 | <gadget id="calculator">8_000 / 100</gadget>
<output>80</output>
<gadget id="calculator">10 * 80</gadget>
<output>800</output>
<gadget id="calculator">15_000 / 100</gadget>
<output>150</output>
<gadget id="calculator">5 * 150</gadget>
<output>750</output>
<gadget id="calculator">800 - 750</gadget>
<output>50</output>
<result>D</result> | D | 50 | John purchased a grinder and a mobile for Rs. 15000 &Rs. 8000 respectively. He sold the grinder at a loss of 5% and the mobile phone at a profit of 10%. Overall how much he make a profit. | {
"A": "s . 90",
"B": "s . 120",
"C": "s . 200",
"D": "s . 50",
"E": "s . 290"
} | subtract(multiply(10, divide(8000, const_100)), multiply(5, divide(15000, const_100))) | divide(n1,const_100)|divide(n0,const_100)|multiply(n3,#0)|multiply(n2,#1)|subtract(#2,#3) | let the sp of the refrigerator and the mobile phone be rs . r and rs . m respectively . r = 15000 ( 1 - 5 / 100 ) = 15000 - 750 m = 8000 ( 1 + 10 / 100 ) = 8000 + 800 total sp - total cp = r + m - ( 15000 + 8000 ) = - 750 + 800 = rs . 50 as this is positive , an overall profit of rs . 50 was made . d | gain |
math_qa__PeQygdMnlagOkaVy | The manufacturing cost of a shoe is Rs.230 and the transportation lost is Rs.500 for 100 shoes. What will be the selling price if it is sold at 20% gains Options.
A) s 282 B) s 216 C) s 220 D) s 210 E) s 217 | <gadget id="calculator">500 / 100</gadget>
<output>5</output>
<gadget id="calculator">230 + 5</gadget>
<output>235</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 235</gadget>
<output>47</output>
<gadget id="calculator">235 + 47</gadget>
<output>282</output>
<result>A</result> | A | 282 | The manufacturing cost of a shoe is Rs.230 and the transportation lost is Rs.500 for 100 shoes. What will be the selling price if it is sold at 20% gains | {
"A": "s 282",
"B": "s 216",
"C": "s 220",
"D": "s 210",
"E": "s 217"
} | add(add(230, divide(500, 100)), multiply(divide(20, 100), add(230, divide(500, 100)))) | divide(n1,n2)|divide(n3,n2)|add(n0,#0)|multiply(#2,#1)|add(#2,#3)| | "explanation : total cost of a watch = 230 + ( 500 / 100 ) = 235 . gain = 20 % = > sp = 1.2 cp = 1.2 x 235 = 282 answer : a" | gain |
math_qa__2hvC4Q4MzPFyhQNn | We have boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If we dispose of one blue box for one additional red box, the total number of berries would increase by 15, and the difference between the total number of strawberries and the total number of blueberries would increase by 87. Each blue box contains how many blueberries?
Choose the correct choice from the following choices
A) 28 B) 30 C) 32 D) 34 E) 36 | <gadget id="calculator">87 - 15</gadget>
<output>72</output>
<gadget id="calculator">72 / 2</gadget>
<output>36</output>
<result>E</result> | E | 36 | We have boxes colored either red or blue. In each blue box there is a fixed number of blueberries. In each red box there is a fixed number of strawberries. If we dispose of one blue box for one additional red box, the total number of berries would increase by 15, and the difference between the total number of strawberries and the total number of blueberries would increase by 87. Each blue box contains how many blueberries? | {
"A": "28",
"B": "30",
"C": "32",
"D": "34",
"E": "36"
} | divide(subtract(87, 15), const_2) | subtract(n1,n0)|divide(#0,const_2)| | "let x be the number of blueberries in each blue box . then there are x + 15 strawberries in each red box . x + ( x + 15 ) = 87 x = 36 the answer is e ." | general |
math_qa__pUiCoHtrqTlmGZIU | Suppose you work for a manufacturing plant that pays you $12.50 an hour plus $0.16 for each widget you make. How many widgets must you produce in a 40 hour week to earn $700 (before payroll deductions)? Choose the correct option.
A) 1220 B) 1250 C) 1280 D) 1310 E) 1340 | <gadget id="calculator">12.5 * 40</gadget>
<output>500</output>
<gadget id="calculator">700 - 500</gadget>
<output>200</output>
<gadget id="calculator">200 / 0.16</gadget>
<output>1_250</output>
<result>B</result> | B | 1,250 | Suppose you work for a manufacturing plant that pays you $12.50 an hour plus $0.16 for each widget you make. How many widgets must you produce in a 40 hour week to earn $700 (before payroll deductions)? | {
"A": "1220",
"B": "1250",
"C": "1280",
"D": "1310",
"E": "1340"
} | divide(subtract(700, multiply(12.50, 40)), 0.16) | multiply(n0,n2)|subtract(n3,#0)|divide(#1,n1)| | "total pay = 40 * $ 12.50 + $ 0.16 * x = 700 x = 200 / 0.16 = 1250 the answer is b ." | physics |
math_qa__P7KA9PWSrElP0RlI | By selling 22 pencils for a rupee a man loses 40%. How many for a rupee should he sell in order to gain 40%? Choose the correct choice from the following answers
A) 8.56 B) 9.35 C) 9.43 D) 6.56 E) 5.5 | <gadget id="calculator">100 + 40</gadget>
<output>140</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">1 / 60</gadget>
<output>1/60 = around 0.016667</output>
<gadget id="calculator">140 * (1/60)</gadget>
<output>7/3 = around 2.333333</output>
<gadget id="calculator">1 / (7/3)</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(3/7) * 22</gadget>
<output>66/7 = around 9.428571</output>
<result>C</result> | C | 9.43 | By selling 22 pencils for a rupee a man loses 40%. How many for a rupee should he sell in order to gain 40%? | {
"A": "8.56",
"B": "9.35",
"C": "9.43",
"D": "6.56",
"E": "5.5"
} | multiply(divide(const_1, multiply(add(const_100, 40), divide(const_1, subtract(const_100, 40)))), 22) | add(n2,const_100)|subtract(const_100,n1)|divide(const_1,#1)|multiply(#0,#2)|divide(const_1,#3)|multiply(n0,#4)| | "60 % - - - 22 140 % - - - ? 60 / 140 * 22 = 9.43 answer : c" | gain |
math_qa__Ies5szZ3duzhNZ5s | If m = 3^n, what is the greatest value of n for which m is a factor of 22! Pick one.
A) 8
B) 10
C) 9
D) 14
E) 16 | <gadget id="calculator">22 / 3</gadget>
<output>22/3 = around 7.333333</output>
<gadget id="calculator">floor(22/3)</gadget>
<output>7</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">22 / 9</gadget>
<output>22/9 = around 2.444444</output>
<gadget id="calculator">floor(22/9)</gadget>
<output>2</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<result>C</result> | C | 9 | If m = 3^n, what is the greatest value of n for which m is a factor of 22! | {
"A": "8",
"B": "10",
"C": "9",
"D": "14",
"E": "16"
} | add(floor(divide(22, 3)), floor(divide(22, power(3, const_2)))) | divide(n1,n0)|power(n0,const_2)|divide(n1,#1)|floor(#0)|floor(#2)|add(#3,#4)| | "solution - consider multiples of 25 ! = > 3 , 6,9 , 12,15 , 18,21 count no . of 3 in each multiple . 3 = 3 x 1 - > 1 6 = 3 x 2 - > 1 9 = 3 x 3 - > 2 12 = 3 x 4 - > 1 15 = 3 x 5 - > 1 18 = 3 x 3 x 2 - > 2 21 = 3 x 7 - > 1 - - - - count 3 ' s = 9 so answer is 9 answer : c" | other |
math_qa__3QmejvzSjTslPNI3 | A shopkeeper sold an book offering a discount of 5% and earned a profit of 14%. What would have been the percentage of profit earned if no discount was offered? Choose the correct answer.
A) 140
B) 120
C) 130
D) 110
E) 150 | <gadget id="calculator">100 + 14</gadget>
<output>114</output>
<gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">114 / 95</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">100 * (6/5)</gadget>
<output>120</output>
<result>B</result> | B | 120 | A shopkeeper sold an book offering a discount of 5% and earned a profit of 14%. What would have been the percentage of profit earned if no discount was offered? | {
"A": "140",
"B": "120",
"C": "130",
"D": "110",
"E": "150"
} | multiply(const_100, divide(add(const_100, 14), subtract(const_100, 5))) | add(n1,const_100)|subtract(const_100,n0)|divide(#0,#1)|multiply(#2,const_100)| | "let c . p . be $ 100 . then , s . p . = $ 114 let marked price be $ x . then , 95 / 100 x = 114 x = 114 / 95 = $ 120 now , s . p . = $ 120 , c . p . = $ 100 profit % = 20 % . b" | gain |
math_qa__K4tyIgeW7cjQKpkm | Three table runners have a combined area of 212 square inches. By overlapping the runners to cover 80% of a table of area 175 square inches, the area that is covered by exactly two layers of runner is 24 square inches. What is the area of the table that is covered with three layers of runner? Select the correct option: A) 18 square inches B) 20 square inches C) 24 square inches D) 28 square inches E) 30 square inches | <gadget id="calculator">212 - 24</gadget>
<output>188</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">175 * (4/5)</gadget>
<output>140</output>
<gadget id="calculator">188 - 140</gadget>
<output>48</output>
<gadget id="calculator">48 / 2</gadget>
<output>24</output>
<result>C</result> | C | 24 | Three table runners have a combined area of 212 square inches. By overlapping the runners to cover 80% of a table of area 175 square inches, the area that is covered by exactly two layers of runner is 24 square inches. What is the area of the table that is covered with three layers of runner? | {
"A": "18 square inches",
"B": "20 square inches",
"C": "24 square inches",
"D": "28 square inches",
"E": "30 square inches"
} | divide(subtract(subtract(212, 24), multiply(175, divide(80, const_100))), const_2) | divide(n1,const_100)|subtract(n0,n3)|multiply(n2,#0)|subtract(#1,#2)|divide(#3,const_2)| | "total = a + b + c - ( sum of exactly 2 - group overlaps ) - 2 * ( all three ) + neither 80 % * 175 = 212 - 24 - 2 * ( all three ) + 0 2 * ( all three ) = 212 - 24 - 140 all three = 24 answer : c" | geometry |
math_qa__Jr18kKrKtINnMurO | Patty ran a marathon at an average speed of 3 mph for some time and then at an average speed of 6 mph for the rest of the marathon. If she made no stops during the run and her average speed for the entire marathon was 5 mph, for what fraction of the total time did she run at 3 mph? Choose the correct answer: A) 1 / 5 B) 2 / 3 C) 2 / 5 D) 3 / 5 E) 1 / 3 | <gadget id="calculator">6 - 5</gadget>
<output>1</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<result>E</result> | E | 0.333333 | Patty ran a marathon at an average speed of 3 mph for some time and then at an average speed of 6 mph for the rest of the marathon. If she made no stops during the run and her average speed for the entire marathon was 5 mph, for what fraction of the total time did she run at 3 mph? | {
"A": "1 / 5",
"B": "2 / 3",
"C": "2 / 5",
"D": "3 / 5",
"E": "1 / 3"
} | divide(subtract(6, 5), subtract(6, 3)) | subtract(n1,n2)|subtract(n1,n0)|divide(#0,#1) | we do n ' t need to get into calculations for solving this question . we can use the concept of weighted averages . we know that if the average speed for the entire marathon was 5 mph , she ran at 6 mph for a longer duration . 2 1 3 - - 5 - - - - 6 this shows that you can divide the entire journey in 3 equal parts . thus , 2 / 3 part she ran at 6 mph and 1 / 3 part she ran at 3 mph . answer : e | general |
math_qa__kvjsns2urgcAVh4j | Kamal obtained 66, 65, 77, 62 and 75 marks(out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks?
Choose one
A) 65 B) 69 C) 72 D) 75 E) none | <gadget id="calculator">66 + 65</gadget>
<output>131</output>
<gadget id="calculator">131 + 77</gadget>
<output>208</output>
<gadget id="calculator">208 + 62</gadget>
<output>270</output>
<gadget id="calculator">270 + 75</gadget>
<output>345</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">345 / 5</gadget>
<output>69</output>
<result>B</result> | B | 69 | Kamal obtained 66, 65, 77, 62 and 75 marks(out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? | {
"A": "65",
"B": "69",
"C": "72",
"D": "75",
"E": "none"
} | divide(add(add(add(add(66, 65), 77), 62), 75), add(const_1, const_4)) | add(n0,n1)|add(const_1,const_4)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1) | sol . average = 66 + 65 + 77 + 62 + 75 / 5 ) = ( 345 / 5 ) = 69 . answer b | general |
math_qa__BTA3DPmhDw8k7xZd | A furniture store owner decided to drop the price of her recliners by 20% to spur business. By the end of the week she had sold 25% more recliners. What is the percentage increase of the gross? Choose the correct choice
A) 00 % B) 15 % C) 20 % D) 25 % E) 50 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(4/5) * (5/4)</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<gadget id="calculator">100 - 100</gadget>
<output>0</output>
<result>A</result> | A | 0 | A furniture store owner decided to drop the price of her recliners by 20% to spur business. By the end of the week she had sold 25% more recliners. What is the percentage increase of the gross? | {
"A": "00 %",
"B": "15 %",
"C": "20 %",
"D": "25 %",
"E": "50 %"
} | subtract(multiply(multiply(subtract(const_1, divide(20, const_100)), add(const_1, divide(25, const_100))), const_100), const_100) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|multiply(#4,const_100)|subtract(#5,const_100)| | "say a recliner is actually worth $ 100 if she sells 100 recliners then she earns $ 10000 after the discount of 20 % , she will earn $ 80 per recliner and she sells 25 % more ie . , 125 recliners hence her sales tields 125 * 80 = $ 10000 increase in sales = 10000 - 10000 = $ 0 so % increase = 0 * 100 / 10000 = 0 % a is the answer" | general |
math_qa__61jpeyyochxacljf | What ratio must a shopkeepermix Peas and Soybean of Rs.16 and Rs. 25/kg, As to obtain a mixture of Rs.22? Select the correct option: A) 10 : 7 B) 9 : 8 C) 1 : 2 D) 13 : 11 E) 14 : 8 | <gadget id="calculator">25 - 22</gadget>
<output>3</output>
<gadget id="calculator">22 - 16</gadget>
<output>6</output>
<gadget id="calculator">3 / 6</gadget>
<output>1/2 = around 0.5</output>
<result>C</result> | C | 0.5 | What ratio must a shopkeepermix Peas and Soybean of Rs.16 and Rs. 25/kg, As to obtain a mixture of Rs.22? | {
"A": "10 : 7",
"B": "9 : 8",
"C": "1 : 2",
"D": "13 : 11",
"E": "14 : 8"
} | divide(subtract(25, 22), subtract(22, 16)) | subtract(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "correct option : ( c ) use rule of alligation , to determine the ratio the required ratio of soybean and peas = 3 : 6 = 1 : 2" | general |
math_qa__tyzsaqOQuquyGZ6K | Calculate how long it will take a swimmer to swim a distance of 7km against the current of a river which flows at 2.5km/hr, given that he can swim in still water at 4.4km/h
Choose the correct choice from the following answers.
A) 6.67
B) 1.67
C) 2.67
D) 3.67
E) 4.67 | <gadget id="calculator">4.4 - 2.5</gadget>
<output>1.9</output>
<gadget id="calculator">7 / 1.9</gadget>
<output>3.684211</output>
<result>D</result> | D | 3.67 | Calculate how long it will take a swimmer to swim a distance of 7km against the current of a river which flows at 2.5km/hr, given that he can swim in still water at 4.4km/h | {
"A": "6.67",
"B": "1.67",
"C": "2.67",
"D": "3.67",
"E": "4.67"
} | divide(7, subtract(4.4, 2.5)) | subtract(n2,n1)|divide(n0,#0)| | "swim in still water at = 4.4 speed of river = 2.5 us = 4.4 - 2.5 = 1.9 distance = 7 t = 7 / 1.9 = 3.67 answer : d" | gain |
math_qa__ZLU1AkCW2J6codgr | A sporting good store sells one type of baseball bat and one type of baseball. The cost for 2 bats and 4 balls is $200. The cost for 1 bat and 6 balls is $220, as well. If someone were to buy an equal number of bats and balls, at most how many bats can he purchase if he has a budget of $210 for the purchase?
Choose the correct option: A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">200 / 2</gadget>
<output>100</output>
<gadget id="calculator">220 - 100</gadget>
<output>120</output>
<gadget id="calculator">120 / 4</gadget>
<output>30</output>
<gadget id="calculator">6 * 30</gadget>
<output>180</output>
<gadget id="calculator">220 - 180</gadget>
<output>40</output>
<gadget id="calculator">40 + 30</gadget>
<output>70</output>
<gadget id="calculator">210 / 70</gadget>
<output>3</output>
<result>C</result> | C | 3 | A sporting good store sells one type of baseball bat and one type of baseball. The cost for 2 bats and 4 balls is $200. The cost for 1 bat and 6 balls is $220, as well. If someone were to buy an equal number of bats and balls, at most how many bats can he purchase if he has a budget of $210 for the purchase? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(210, add(subtract(220, multiply(6, divide(subtract(220, divide(200, const_2)), 4))), divide(subtract(220, divide(200, const_2)), 4))) | divide(n2,const_2)|subtract(n5,#0)|divide(#1,n1)|multiply(n4,#2)|subtract(n5,#3)|add(#2,#4)|divide(n6,#5) | imo it should be c that is 3 reason : formed an equation . . . bat = b ball = c 2 b + 4 c = 200 1 b + 6 c = 220 solving both we get b that is bat = 40 and c that is ball = 30 new equation 210 to be divided in equal 3 b + 3 c = 210 3 * 40 + 3 * 30 = 210 120 + 90 = 210 | geometry |
math_qa__NGNS6qo0YjEUyfJn | Find the area of a parallelogram with base 12 cm and height 18 cm.
Choose the correct choice from the following answers: A) 200 B) 216 C) 345 D) 244 E) 242 | <gadget id="calculator">12 * 18</gadget>
<output>216</output>
<result>B</result> | B | 216 | Find the area of a parallelogram with base 12 cm and height 18 cm. | {
"A": "200",
"B": "216",
"C": "345",
"D": "244",
"E": "242"
} | multiply(12, 18) | multiply(n0,n1)| | "area of a parallelogram = base * height = 12 * 18 = 216 cm 2 answer : option b" | geometry |
math_qa__Ll6jQsGPMnmzXSuB | If a number p is prime, and 2p+4 = q, where q is also prime, then the decimal expansion of 1/q will produce a decimal with q-1 digits. If this method produces a decimal with 166 digits, what is the units digit of the product of p and q? Options
A) 1 B) 3 C) 5 D) 7 E) 9 | <gadget id="calculator">166 + 1</gadget>
<output>167</output>
<gadget id="calculator">167 - 4</gadget>
<output>163</output>
<gadget id="calculator">163 / 2</gadget>
<output>163/2 = around 81.5</output>
<gadget id="calculator">(163/2) - 1</gadget>
<output>161/2 = around 80.5</output>
<gadget id="calculator">(163/2) - (161/2)</gadget>
<output>1</output>
<result>A</result> | A | 1 | If a number p is prime, and 2p+4 = q, where q is also prime, then the decimal expansion of 1/q will produce a decimal with q-1 digits. If this method produces a decimal with 166 digits, what is the units digit of the product of p and q? | {
"A": "1",
"B": "3",
"C": "5",
"D": "7",
"E": "9"
} | subtract(divide(subtract(add(166, 1), 4), 2), subtract(divide(subtract(add(166, 1), 4), 2), 1)) | add(n2,n4)|subtract(#0,n1)|divide(#1,n0)|subtract(#2,n2)|subtract(#2,#3)| | "1 / 6 = 0.1666666 . . . ( a repeating pattern one digit long ) a" | general |
math_qa__oWahAb20eOBloeeQ | A train 110 m long passes a man,running at 6 kmph in the direction opposite to that of the train,in 6 seconds.The speed of the train is Choose the correct choice from the following options
A) 54 kmph B) 60 kmph C) 66 kmph D) 72 kmph E) 82 kmph | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">6 * (5/18)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) * 6</gadget>
<output>10</output>
<gadget id="calculator">110 - 10</gadget>
<output>100</output>
<gadget id="calculator">100 / 6</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) / (5/18)</gadget>
<output>60</output>
<result>B</result> | B | 60 | A train 110 m long passes a man,running at 6 kmph in the direction opposite to that of the train,in 6 seconds.The speed of the train is | {
"A": "54 kmph",
"B": "60 kmph",
"C": "66 kmph",
"D": "72 kmph",
"E": "82 kmph"
} | divide(divide(subtract(110, multiply(multiply(6, const_0_2778), 6)), 6), const_0_2778) | multiply(n1,const_0_2778)|multiply(n1,#0)|subtract(n0,#1)|divide(#2,n1)|divide(#3,const_0_2778) | speed of train relative to man : 110 / 6 * 18 / 5 km / hr = 66 km / hr let speed of train = x therefore x + 6 = 66 x = 66 - 6 x = 60 km / hr answer : b | physics |
math_qa__rrup6yAc9HOvIpMW | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 32, the how old is B? Options: A) 10 years B) 12 years C) 14 years D) 15 years E) 16 years | <gadget id="calculator">32 - 2</gadget>
<output>30</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<result>B</result> | B | 12 | A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 32, the how old is B? | {
"A": "10 years",
"B": "12 years",
"C": "14 years",
"D": "15 years",
"E": "16 years"
} | divide(multiply(subtract(32, const_2), const_2), add(const_4, const_1)) | add(const_1,const_4)|subtract(n0,const_2)|multiply(#1,const_2)|divide(#2,#0)| | "let c ' s age be x years . then , b ' s age = 2 x years . a ' s age = ( 2 x + 2 ) years . ( 2 x + 2 ) + 2 x + x = 32 5 x = 30 x = 6 . hence , b ' s age = 2 x = 12 years . b )" | general |
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