id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__upmX0rTeVh3VrMZL | Shopkeeper rise price by 36% and gives successive discount of 10% and 15%. What is overall % gain or loss? Choose the correct answer.
A) 5.04 % B) 4.04 % C) 3.04 % D) 6.04 % E) 7.04 % | <gadget id="calculator">100 + 36</gadget>
<output>136</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">136 * (9/10)</gadget>
<output>612/5 = around 122.4</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">(612/5) * (17/20)</gadget>
<output>2_601/25 = around 104.04</output>
<gadget id="calculator">(2_601/25) - 100</gadget>
<output>101/25 = around 4.04</output>
<result>B</result> | B | 4.04 | Shopkeeper rise price by 36% and gives successive discount of 10% and 15%. What is overall % gain or loss? | {
"A": "5.04 %",
"B": "4.04 %",
"C": "3.04 %",
"D": "6.04 %",
"E": "7.04 %"
} | subtract(multiply(multiply(add(const_100, 36), divide(subtract(const_100, 10), const_100)), divide(subtract(const_100, 15), const_100)), const_100) | add(n0,const_100)|subtract(const_100,n2)|subtract(const_100,n1)|divide(#1,const_100)|divide(#2,const_100)|multiply(#0,#4)|multiply(#3,#5)|subtract(#6,const_100)| | "let d initial price be 100 36 % rise now price = 136 / 100 * 100 = 136 10 % discount then price = 136 * 90 / 100 = 122.4 15 % discount then price = 122.4 * 85 / 100 = 104.04 so gain = 104.04 - 100 = 4.04 gain % = gain * 100 / cp = = > 4.04 * 100 / 100 = 4.04 % answer : b" | gain |
math_qa__O7smkiN8dK77aexK | Suresh and Ramesh started a business investing Rs. 24,000 and Rs. 40,000 respectively. Out of total profit of Rs. 18,000, what is Suresh's share? Select the correct option:
A) s . 6750 B) s . 7750 C) s . 8750 D) s . 9372 E) s . 9750 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 4</gadget>
<output>24</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">24 * 1_000</gadget>
<output>24_000</output>
<gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">18 * 1_000</gadget>
<output>18_000</output>
<gadget id="calculator">4 * 10</gadget>
<output>40</output>
<gadget id="calculator">40 + 2</gadget>
<output>42</output>
<gadget id="calculator">42 * 1_000</gadget>
<output>42_000</output>
<gadget id="calculator">24_000 + 42_000</gadget>
<output>66_000</output>
<gadget id="calculator">18_000 / 66_000</gadget>
<output>3/11 = around 0.272727</output>
<gadget id="calculator">24_000 * (3/11)</gadget>
<output>72_000/11 = around 6_545.454545</output>
<result>A</result> | A | 6,750 | Suresh and Ramesh started a business investing Rs. 24,000 and Rs. 40,000 respectively. Out of total profit of Rs. 18,000, what is Suresh's share? | {
"A": "s . 6750",
"B": "s . 7750",
"C": "s . 8750",
"D": "s . 9372",
"E": "s . 9750"
} | multiply(multiply(multiply(multiply(const_2, const_3), const_4), multiply(multiply(const_2, add(const_2, const_3)), const_100)), divide(multiply(multiply(const_3, multiply(const_2, const_3)), multiply(multiply(const_2, add(const_2, const_3)), const_100)), add(multiply(multiply(multiply(const_2, const_3), const_4), multiply(multiply(const_2, add(const_2, const_3)), const_100)), multiply(add(multiply(const_4, multiply(const_2, add(const_2, const_3))), const_2), multiply(multiply(const_2, add(const_2, const_3)), const_100))))) | add(const_2,const_3)|multiply(const_2,const_3)|multiply(#1,const_3)|multiply(#0,const_2)|multiply(#1,const_4)|multiply(#3,const_100)|multiply(#3,const_4)|add(#6,const_2)|multiply(#2,#5)|multiply(#4,#5)|multiply(#7,#5)|add(#9,#10)|divide(#8,#11)|multiply(#12,#9) | explanation : ratio of suresh and ramesh ' s share = 24,000 : 40,000 = 3 : 5 suresh ' s share = rs . ( 18000 x 3 / 8 ) = rs . 6750 answer : a | gain |
math_qa__15AtaD8UmqUYRX1w | What is the square root of 36, divided by 6? Choose the correct option.
A) 9 B) 36 C) 122 D) 6 E) 1 | <gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<gadget id="calculator">6 / 6</gadget>
<output>1</output>
<result>E</result> | E | 1 | What is the square root of 36, divided by 6? | {
"A": "9",
"B": "36",
"C": "122",
"D": "6",
"E": "1"
} | divide(sqrt(36), 6) | sqrt(n0)|divide(#0,n1)| | "square root is a number times itself square root of 36 = 6 , 6 / 6 = 1 ( e ) 1" | other |
math_qa__UheTlYTCYxpxxWFv | A man swims downstream 32 km and upstream 24 km taking 4 hours each time, what is the speed of the man in still water? Choose the correct option.
A) 9 B) 8 C) 6 D) 7 E) 2 | <gadget id="calculator">24 / 4</gadget>
<output>6</output>
<gadget id="calculator">32 / 4</gadget>
<output>8</output>
<gadget id="calculator">6 + 8</gadget>
<output>14</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<result>D</result> | D | 7 | A man swims downstream 32 km and upstream 24 km taking 4 hours each time, what is the speed of the man in still water? | {
"A": "9",
"B": "8",
"C": "6",
"D": "7",
"E": "2"
} | divide(add(divide(24, 4), divide(32, 4)), const_2) | divide(n1,n2)|divide(n0,n2)|add(#0,#1)|divide(#2,const_2)| | "32 - - - 4 ds = 8 ? - - - - 1 24 - - - - 4 us = 6 ? - - - - 1 m = ? m = ( 8 + 6 ) / 2 = 7 answer : d" | physics |
math_qa__r5S51j6xxfb0zRJM | During a sale, the price of a pair of shoes is marked down 15% from the regular price. After the sale ends, the price goes back to the original price. What is the percent of increase to the nearest percent from the sale price back to the regular price for the shoes?
Choose the correct choice from the following answers.
A) 9 % B) 10 % C) 11 % D) 18 % E) 90 % | <gadget id="calculator">15 * 100</gadget>
<output>1_500</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">1_500 / 85</gadget>
<output>300/17 = around 17.647059</output>
<result>D</result> | D | 18 | During a sale, the price of a pair of shoes is marked down 15% from the regular price. After the sale ends, the price goes back to the original price. What is the percent of increase to the nearest percent from the sale price back to the regular price for the shoes? | {
"A": "9 %",
"B": "10 %",
"C": "11 %",
"D": "18 %",
"E": "90 %"
} | divide(multiply(15, const_100), subtract(const_100, 15)) | multiply(n0,const_100)|subtract(const_100,n0)|divide(#0,#1) | assume the price = 100 price during sale = 85 price after sale = 100 percent increase = 15 / 85 * 100 = 18 % approx . correct option : d | gain |
math_qa__lU1K1vXMFrncj2Ce | A and B can do a piece of work in 18 and 9 days respectively. A does the work for a few days and left, then B continued for 6 days. How many days did A and B work together? Choose the correct choice from the following choices:
A) 1
B) 2
C) 3
D) 4
E) 5 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 / 9</gadget>
<output>2</output>
<result>B</result> | B | 2 | A and B can do a piece of work in 18 and 9 days respectively. A does the work for a few days and left, then B continued for 6 days. How many days did A and B work together? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(multiply(6, const_3), 9) | multiply(n2,const_3)|divide(#0,n1) | a and b work together for 2 days . a 1 day work 1 / 18 b 1 day work 1 / 9 let a work x days . then equation form is ( x / 18 ) + ( ( x + 6 ) / 9 ) = 1 from this equation x value is 2 . answer : b | physics |
math_qa__ammMEQlrv2xvm79N | A and B can finish a work in 10 days while A alone can do the same work in 20 days. In how many days B alone will complete the work? Choose the correct choice.
A) 20 days B) 48 days C) 98 days D) 31 days E) 22 days | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/10) - (1/20)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / (1/20)</gadget>
<output>20</output>
<result>A</result> | A | 20 | A and B can finish a work in 10 days while A alone can do the same work in 20 days. In how many days B alone will complete the work? | {
"A": "20 days",
"B": "48 days",
"C": "98 days",
"D": "31 days",
"E": "22 days"
} | inverse(subtract(inverse(10), inverse(20))) | inverse(n0)|inverse(n1)|subtract(#0,#1)|inverse(#2)| | "b = 1 / 10 – 1 / 20 = 1 / 20 = > 20 days answer : a" | physics |
math_qa__iML7baL738R7RC0I | 8!/(8-2)!=? Choose the correct choice from the following options.
A) 36 B) 46 C) 56 D) 66 E) 96 | <gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">40_320 / 720</gadget>
<output>56</output>
<result>C</result> | C | 56 | 8!/(8-2)!=? | {
"A": "36",
"B": "46",
"C": "56",
"D": "66",
"E": "96"
} | divide(factorial(8), factorial(subtract(8, 2))) | factorial(n0)|subtract(n0,n2)|factorial(#1)|divide(#0,#2)| | 8 ! / ( 8 - 2 ) ! = 8 ! / 6 ! = 8 * 7 = 56 . hence , the correct answer is c . | general |
math_qa__fnk0sVCxAmJa89J8 | sally , mark , sarah , steve and jim are inheriting the money from their grandmother . she left them $ 527500 to split equally between all of them . if the money is split equally , how much money will each person receive ? Choose the correct option.
A) $ 135875 B) $ 52700 C) $ 127900 D) $ 105500 E) $ 105000 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">527_500 / 5</gadget>
<output>105_500</output>
<result>D</result> | D | 105,500 | sally , mark , sarah , steve and jim are inheriting the money from their grandmother . she left them $ 527500 to split equally between all of them . if the money is split equally , how much money will each person receive ? | {
"A": "$ 135875",
"B": "$ 52700",
"C": "$ 127900",
"D": "$ 105500",
"E": "$ 105000"
} | divide(527500, add(const_4, const_1)) | add(const_1,const_4)|divide(n0,#0) | there are 5 people inheriting the money . we have to take the total of the inheritance and divide it by 5 for each person receiving money . $ 527500 / 5 = $ 105500 . therefore the correct answer is d . | general |
math_qa__quOxSqvst5jXlnik | If the cost price of 165 chocolates is equal to the selling price of 150 chocolates, the gain percent is
Answers
A) 8 B) 9 C) 10 D) 11 E) 12 | <gadget id="calculator">165 - 150</gadget>
<output>15</output>
<gadget id="calculator">150 / 15</gadget>
<output>10</output>
<gadget id="calculator">100 / 10</gadget>
<output>10</output>
<result>C</result> | C | 10 | If the cost price of 165 chocolates is equal to the selling price of 150 chocolates, the gain percent is | {
"A": "8",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | divide(const_100, divide(150, subtract(165, 150))) | subtract(n0,n1)|divide(n1,#0)|divide(const_100,#1)| | "let c . p . of each chocolate be re . 1 . then , c . p . of 150 chocolates = rs . 150 ; s . p . of 150 chocolates = rs . 165 . gain % = 15 / 150 * 100 = 10 % answer : c" | gain |
math_qa__eGg8bMhyryhKzHmw | On a trip covering 450 km, a bicyclist travels the first 300 km at 20 km per hour and the remainder of the distance at 15 km per hour. What is the average speed, in km per hour, for the entire trip? Choose the correct choice from the following answers: A) 16.5 B) 17.0 C) 17.5 D) 18.0 E) 18.5 | <gadget id="calculator">300 / 20</gadget>
<output>15</output>
<gadget id="calculator">450 - 300</gadget>
<output>150</output>
<gadget id="calculator">150 / 15</gadget>
<output>10</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">450 / 25</gadget>
<output>18</output>
<result>D</result> | D | 18 | On a trip covering 450 km, a bicyclist travels the first 300 km at 20 km per hour and the remainder of the distance at 15 km per hour. What is the average speed, in km per hour, for the entire trip? | {
"A": "16.5",
"B": "17.0",
"C": "17.5",
"D": "18.0",
"E": "18.5"
} | speed(450, add(divide(300, 20), divide(subtract(450, 300), 15))) | divide(n1,n2)|subtract(n0,n1)|divide(#1,n3)|add(#0,#2)|speed(n0,#3)| | "time 1 = 300 / 20 = 15 hours time 2 = 150 / 15 = 10 hours total time = 25 hours average speed = 450 / 25 = 18 km / hr the answer is d ." | physics |
math_qa__QVNSX8VXFaN7FOGQ | Jack and Jill work at a hospital with 2 other workers. For an internal review, 2 of the 4 workers will be randomly chosen to be interviewed. What is the probability that Jack and Jill will both be chosen? Choose the most appropriate option
A) 1 / 3 B) 1 / 6 C) 1 / 15 D) 3 / 8 E) 2 / 3 | <gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">24 / 4</gadget>
<output>6</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<result>B</result> | B | 0.166667 | Jack and Jill work at a hospital with 2 other workers. For an internal review, 2 of the 4 workers will be randomly chosen to be interviewed. What is the probability that Jack and Jill will both be chosen? | {
"A": "1 / 3",
"B": "1 / 6",
"C": "1 / 15",
"D": "3 / 8",
"E": "2 / 3"
} | inverse(divide(factorial(4), multiply(factorial(2), factorial(2)))) | factorial(n2)|factorial(n1)|factorial(n0)|multiply(#1,#2)|divide(#0,#3)|inverse(#4)| | "1 / 4 c 2 = 1 / 6 . answer : b ." | physics |
math_qa__vnZt1iOf98iw6CYs | If 15% of 30% of 50% of a number is 126, then what is the number? Options: A) 5000 B) 5600 C) 5400 D) 4500 E) none of these | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(1/2) * (3/10)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) * (3/20)</gadget>
<output>9/400 = around 0.0225</output>
<gadget id="calculator">126 / (9/400)</gadget>
<output>5_600</output>
<result>B</result> | B | 5,600 | If 15% of 30% of 50% of a number is 126, then what is the number? | {
"A": "5000",
"B": "5600",
"C": "5400",
"D": "4500",
"E": "none of these"
} | divide(126, multiply(multiply(divide(50, const_100), divide(30, const_100)), divide(15, const_100))) | divide(n0,const_100)|divide(n2,const_100)|divide(n1,const_100)|multiply(#1,#2)|multiply(#0,#3)|divide(n3,#4)| | "let the number be a given , 15 / 100 * 30 / 100 * 50 / 100 * a = 126 = > 3 / 20 * 3 / 10 * 1 / 2 * a = 126 = > a = 10 * 20 * 10 * 2 = 5600 . answer : b" | gain |
math_qa__LuxfJeBEL83KbJkU | A full stationary oil tank that is a right circular cylinder has a radius of 100 feet and a height of 25 feet. Oil is pumped from the stationary tank to an oil truck that has a tank that is a right circular cylinder until the truck's tank is completely filled. If the truck's tank has a radius of 5 feet and a height of 12 feet, how far (in feet) did the oil level drop in the stationary tank? Choose the correct choice from the following answers.
A) 2.5 B) 0.025 C) 0.05 D) 0.03 E) 3 | <gadget id="calculator">pi * (5 ** 2) * 12</gadget>
<output>300*pi = around 942.477796</output>
<gadget id="calculator">pi * (100 ** 2)</gadget>
<output>10000*pi = around 31_415.926536</output>
<gadget id="calculator">(300*pi) / (10000*pi)</gadget>
<output>3/100 = around 0.03</output>
<result>D</result> | D | 0.03 | A full stationary oil tank that is a right circular cylinder has a radius of 100 feet and a height of 25 feet. Oil is pumped from the stationary tank to an oil truck that has a tank that is a right circular cylinder until the truck's tank is completely filled. If the truck's tank has a radius of 5 feet and a height of 12 feet, how far (in feet) did the oil level drop in the stationary tank? | {
"A": "2.5",
"B": "0.025",
"C": "0.05",
"D": "0.03",
"E": "3"
} | divide(volume_cylinder(5, 12), circle_area(100)) | circle_area(n0)|volume_cylinder(n2,n3)|divide(#1,#0)| | "the volume of oil pumped to the tank = the volume of oil taken away from stationary cylinder . pi * 25 * 12 = pi * h * 100 * 100 ( h is distance that the oil level dropped ) h = 300 / 10,000 = 3 / 100 = 0.03 ft the answer is d ." | geometry |
math_qa__BlV2kzldBnRBbXPZ | When the price of an article was reduced by 35% its sale increased by 80%. What was the net effect on the sale? Choose the correct choice from the following answers.
A) 17 % increase B) 44 % decrease C) 60 % increase D) 66 % increase E) 66 % decrease | <gadget id="calculator">80 + 100</gadget>
<output>180</output>
<gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">180 * 65</gadget>
<output>11_700</output>
<gadget id="calculator">11_700 / 100</gadget>
<output>117</output>
<gadget id="calculator">117 - 100</gadget>
<output>17</output>
<result>A</result> | A | 17 | When the price of an article was reduced by 35% its sale increased by 80%. What was the net effect on the sale? | {
"A": "17 % increase",
"B": "44 % decrease",
"C": "60 % increase",
"D": "66 % increase",
"E": "66 % decrease"
} | subtract(divide(multiply(add(80, const_100), subtract(const_100, 35)), const_100), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,#1)|divide(#2,const_100)|subtract(#3,const_100)| | "if n items are sold for $ p each , revenue is $ np . if we reduce the price by 35 % , the new price is 0.65 p . if we increase the number sold by 80 % , the new number sold is 1.8 n . so the new revenue is ( 0.65 p ) ( 1.8 n ) = 1.17 np , which is 1.17 times the old revenue , so is 17 % greater . answer : a" | gain |
math_qa__n47l2pr9n6RCaIwO | Two trains travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 10 seconds. The length of the faster train is
Choose the correct choice from the following choices
A) 225 m
B) 100 m
C) 120 m
D) 180 m
E) none | <gadget id="calculator">36 + 45</gadget>
<output>81</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">81 * (5/18)</gadget>
<output>45/2 = around 22.5</output>
<gadget id="calculator">(45/2) * 10</gadget>
<output>225</output>
<result>A</result> | A | 225 | Two trains travel in opposite directions at 36 kmph and 45 kmph and a man sitting in slower train passes the faster train in 10 seconds. The length of the faster train is | {
"A": "225 m",
"B": "100 m",
"C": "120 m",
"D": "180 m",
"E": "none"
} | multiply(multiply(add(36, 45), const_0_2778), 10) | add(n0,n1)|multiply(#0,const_0_2778)|multiply(n2,#1)| | "solution relative speed = ( 36 + 45 ) km / hr = ( 81 x 5 / 18 ) m / sec = ( 45 / 2 ) m / sec length of the train = ( 45 / 2 x 10 ) m = 225 m . answer a" | physics |
math_qa__fWwgRxyNuQFBqVB5 | s(n) is a n-digit number formed by attaching the first n perfect squares, in order, into one integer. For example, s(1) = 1, s(2) = 14, s(3) = 149, s(4) = 14916, s(5) = 1491625, etc. How many digits R are in s(99)? Select:
A) r = 350
B) r = 353
C) r = 354
D) r = 356
E) 357 | <gadget id="calculator">60 + 4</gadget>
<output>64</output>
<gadget id="calculator">64 + 4</gadget>
<output>68</output>
<gadget id="calculator">68 * 4</gadget>
<output>272</output>
<gadget id="calculator">68 + 272</gadget>
<output>340</output>
<gadget id="calculator">3 * 1</gadget>
<output>3</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">3 + 12</gadget>
<output>15</output>
<gadget id="calculator">340 + 15</gadget>
<output>355</output>
<result>B</result> | B | 353 | s(n) is a n-digit number formed by attaching the first n perfect squares, in order, into one integer. For example, s(1) = 1, s(2) = 14, s(3) = 149, s(4) = 14916, s(5) = 1491625, etc. How many digits R are in s(99)? | {
"A": "r = 350",
"B": "r = 353",
"C": "r = 354",
"D": "r = 356",
"E": "357"
} | add(add(add(add(const_60, 4), 4), multiply(add(add(const_60, 4), 4), 4)), add(multiply(3, 1), multiply(multiply(3, 2), 2))) | add(n6,const_60)|multiply(n0,n4)|multiply(n2,n4)|add(n6,#0)|multiply(n2,#2)|add(#1,#4)|multiply(n6,#3)|add(#3,#6)|add(#7,#5)| | "focus on the points where the number of digits in squares change : 1 , 2 , 3 - single digit squares . first 2 digit number is 10 . 4 , 5 , . . . 9 - two digit squares . to get 9 , the last number with two digit square , think that first 3 digit number is 100 which is 10 ^ 2 . so 9 ^ 2 must be the last 2 digit square . 10 , 11 , 12 , . . . 31 - three digit squares . to get 31 , think of 1000 - the first 4 digit number . it is not a perfect square but 900 is 30 ^ 2 . 32 ^ 2 = 2 ^ 10 = 1024 , the first 4 digit square . 32 - 99 - four digit squares . to get 99 , think of 10,000 - the first 5 digit number which is 100 ^ 2 . so number of digits in s ( 99 ) = 3 * 1 + 6 * 2 + 22 * 3 + 68 * 4 = 3 + 12 + 66 + 272 = r = 353 . b" | general |
math_qa__bVZlRSjo9CTZ4pxl | If a and b are positive integers and (2^a)^b = 2^2, what is the value of 2^a*2^b? Choose the correct choice
A) 8 B) 4 C) 16 D) 32 E) 64 | <gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<result>A</result> | A | 8 | If a and b are positive integers and (2^a)^b = 2^2, what is the value of 2^a*2^b? | {
"A": "8",
"B": "4",
"C": "16",
"D": "32",
"E": "64"
} | multiply(power(2, 2), 2) | power(n0,n0)|multiply(n0,#0)| | "2 ^ ab = 2 ^ 2 therefore ab = 2 either a = 1 or 2 or b = 2 or 1 therefore 2 ^ a * 2 ^ b = 2 ^ ( a + b ) = 2 ^ 3 = 8 a" | general |
math_qa__o367dnpvwO3sfGNS | When 242 is divided by a certain divisor the remainder obtained is 4. When 698 is divided by the same divisor the remainder obtained is 8. However, when the sum of the two numbers 242 and 698 is divided by the divisor, the remainder obtained is 7. What is the value of the divisor? Choose the correct choice: A) 5 B) 17 C) 13 D) 23 E) none of these | <gadget id="calculator">4 + 8</gadget>
<output>12</output>
<gadget id="calculator">12 - 7</gadget>
<output>5</output>
<result>A</result> | A | 5 | When 242 is divided by a certain divisor the remainder obtained is 4. When 698 is divided by the same divisor the remainder obtained is 8. However, when the sum of the two numbers 242 and 698 is divided by the divisor, the remainder obtained is 7. What is the value of the divisor? | {
"A": "5",
"B": "17",
"C": "13",
"D": "23",
"E": "none of these"
} | subtract(add(4, 8), 7) | add(n1,n3)|subtract(#0,n6)| | "let that divisor be x since remainder is 4 or 8 it means divisor is greater than 8 . now 242 - 4 = 238 = kx ( k is an integer and 234 is divisble by x ) similarly 698 - 8 = 690 = lx ( l is an integer and 689 is divisible by x ) adding both 698 and 242 = ( 238 + 690 ) + 4 + 8 = x ( k + l ) + 12 when we divide this number by x then remainder will be equal to remainder of ( 12 divided by x ) = 7 hence x = 12 - 7 = 5 hence a" | general |
math_qa__DaSPzS6mwltdDYI0 | In a college, the ratio of the number of boys to girls is 6 : 5. If there are 200 girls, the total number of students in the college is Choose one:
A) 440
B) 520
C) 620
D) 720
E) 820 | <gadget id="calculator">200 / 5</gadget>
<output>40</output>
<gadget id="calculator">40 * 6</gadget>
<output>240</output>
<gadget id="calculator">200 + 240</gadget>
<output>440</output>
<result>A</result> | A | 440 | In a college, the ratio of the number of boys to girls is 6 : 5. If there are 200 girls, the total number of students in the college is | {
"A": "440",
"B": "520",
"C": "620",
"D": "720",
"E": "820"
} | add(200, multiply(divide(200, 5), 6)) | divide(n2,n1)|multiply(n0,#0)|add(n2,#1)| | "explanation : let the boy are 6 x and girls are 5 x = > 5 x = 200 = > x = 40 total students = 6 x + 5 x = 11 x = 11 ( 40 ) = 440 option a" | other |
math_qa__rZ8IgLMaB9LilTzZ | P, Q and R have Rs.8000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R? Choose the correct option:
A) rs . 3200 B) rs . 3600 C) rs . 2400 D) rs . 4000 E) none of these | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 + (2/3)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">8_000 / (5/3)</gadget>
<output>4_800</output>
<gadget id="calculator">4_800 * (2/3)</gadget>
<output>3_200</output>
<result>A</result> | A | 3,200 | P, Q and R have Rs.8000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R? | {
"A": "rs . 3200",
"B": "rs . 3600",
"C": "rs . 2400",
"D": "rs . 4000",
"E": "none of these"
} | multiply(divide(8000, add(const_1, divide(const_2, const_3))), divide(const_2, const_3)) | divide(const_2,const_3)|add(#0,const_1)|divide(n0,#1)|multiply(#2,#0)| | "let the amount with r be rs . r r = 2 / 3 ( total amount with p and q ) r = 2 / 3 ( 8000 - r ) = > 3 r = 16000 - 2 r = > 5 r = 16000 = > r = 3200 . answer : a" | general |
math_qa__J2gujv0nefKKfoVA | An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is
Choose the correct choice from the following answers:
A) 4.04 % B) 4.00 % C) 4.14 % D) 5.04 % E) none | <gadget id="calculator">100 + 2</gadget>
<output>102</output>
<gadget id="calculator">102 ** 2</gadget>
<output>10_404</output>
<gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">10_404 - 10_000</gadget>
<output>404</output>
<gadget id="calculator">404 * 100</gadget>
<output>40_400</output>
<gadget id="calculator">40_400 / 10_000</gadget>
<output>101/25 = around 4.04</output>
<result>A</result> | A | 4.04 | An error 2% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is | {
"A": "4.04 %",
"B": "4.00 %",
"C": "4.14 %",
"D": "5.04 %",
"E": "none"
} | divide(multiply(subtract(square_area(add(const_100, 2)), square_area(const_100)), const_100), square_area(const_100)) | add(n0,const_100)|square_area(const_100)|square_area(#0)|subtract(#2,#1)|multiply(#3,const_100)|divide(#4,#1)| | "100 cm is read as 102 cm . a 1 = ( 100 x 100 ) cm 2 and a 2 ( 102 x 102 ) cm 2 . ( a 2 - a 1 ) = [ ( 102 ) 2 - ( 100 ) 2 ] = ( 102 + 100 ) x ( 102 - 100 ) = 404 cm 2 . percentage error = 404 x 100 % = 4.04 % 100 x 100 a" | gain |
math_qa__qZH2S8M75Pz5DUyr | In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 1000 m?
Choose the correct option: A) 122.9 m B) 127.5 m . C) 122.2 m D) 222.9 m E) 212.5 m | <gadget id="calculator">1_000 - 100</gadget>
<output>900</output>
<gadget id="calculator">800 - 100</gadget>
<output>700</output>
<gadget id="calculator">900 * 700</gadget>
<output>630_000</output>
<gadget id="calculator">630_000 / 800</gadget>
<output>1_575/2 = around 787.5</output>
<gadget id="calculator">1_000 - (1_575/2)</gadget>
<output>425/2 = around 212.5</output>
<result>E</result> | E | 212.5 | In a race of 1000 m, A can beat by 100 m, in a race of 800m, B can beat C by 100m. By how many meters will A beat C in a race of 1000 m? | {
"A": "122.9 m",
"B": "127.5 m .",
"C": "122.2 m",
"D": "222.9 m",
"E": "212.5 m"
} | subtract(1000, divide(multiply(subtract(1000, 100), subtract(800, 100)), 800)) | subtract(n0,n1)|subtract(n2,n1)|multiply(#0,#1)|divide(#2,n2)|subtract(n0,#3) | when a runs 1000 m , b runs 900 m and when b runs 800 m , c runs 700 m . when b runs 900 m , distance that c runs = ( 900 * 700 ) / 800 = 6300 / 8 = 787.5 m . in a race of 1000 m , a beats c by ( 1000 - 787.5 ) = 212.5 m to c . in a race of 1000 m , the number of meters by which a beats c = ( 1000 * 212.5 ) / 1000 = 212.5 m . answer : e | physics |
math_qa__dMgIYfuEWtXhUxBu | How many positive integers between 1 and 300 are there such that they are multiples of 9? Pick.
A) 31
B) 33
C) 35
D) 36
E) 23 | <gadget id="calculator">300 - 1</gadget>
<output>299</output>
<gadget id="calculator">299 / 9</gadget>
<output>299/9 = around 33.222222</output>
<result>B</result> | B | 33 | How many positive integers between 1 and 300 are there such that they are multiples of 9? | {
"A": "31",
"B": "33",
"C": "35",
"D": "36",
"E": "23"
} | divide(subtract(300, 1), 9) | subtract(n1,n0)|divide(#0,n2)| | "multiples of 9 = 9 , 18,27 , - - - - - 297 number of multiples of 15 = > 9 * 33 = 297 answer is b" | general |
math_qa__AQAYivcsyVnGDomv | A squirrel runs up a cylindrical post , in a perfect spiral path making one circuit for each rise of 5 feet . How many feet does the squirrel travels if the post is 25 feet tall and 3 feet in circumference? Choose the correct choice from the following: A) 10 feet B) 12 feet C) 13 feet D) 15 feet E) 18 feet | <gadget id="calculator">25 / 5</gadget>
<output>5</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<result>D</result> | D | 15 | A squirrel runs up a cylindrical post , in a perfect spiral path making one circuit for each rise of 5 feet . How many feet does the squirrel travels if the post is 25 feet tall and 3 feet in circumference? | {
"A": "10 feet",
"B": "12 feet",
"C": "13 feet",
"D": "15 feet",
"E": "18 feet"
} | multiply(divide(25, 5), 3) | divide(n1,n0)|multiply(n2,#0) | total circuit = 25 / 5 = 5 total feet squirrel travels = 5 * 3 = 15 feet answer : d | geometry |
math_qa__6jIia7MiZYW5GkLk | The average weight of 16 girls in a class is 50.25 kg and that of the remaining 8 girls is 45.15 kg. Find the average weights of all the girls in the class. Choose the correct choice from the following choices: A) 48.55 B) 49 C) 51 D) 61 E) 62 | <gadget id="calculator">16 * 50.25</gadget>
<output>804</output>
<gadget id="calculator">8 * 45.15</gadget>
<output>361.2</output>
<gadget id="calculator">804 + 361.2</gadget>
<output>1_165.2</output>
<gadget id="calculator">16 + 8</gadget>
<output>24</output>
<gadget id="calculator">1_165.2 / 24</gadget>
<output>48.55</output>
<result>A</result> | A | 48.55 | The average weight of 16 girls in a class is 50.25 kg and that of the remaining 8 girls is 45.15 kg. Find the average weights of all the girls in the class. | {
"A": "48.55",
"B": "49",
"C": "51",
"D": "61",
"E": "62"
} | divide(add(multiply(16, 50.25), multiply(8, 45.15)), add(16, 8)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0) | required average = ( 50.25 x 16 + 45.15 x 8 ) / ( 16 + 8 ) = ( 804 + 361.20 ) / 24 = 1165.20 / 24 = 48.55 kg answer is a | general |
math_qa__BDNnsOUChKezMr58 | if rs . 782 is divided into 3 parts , proportional to 1 / 2 : 2 / 3 : 3 / 4 find the first part . Select the correct option:
A) 190 B) 204 C) 220 D) 230 E) none of these | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">6 + 8</gadget>
<output>14</output>
<gadget id="calculator">12 / 4</gadget>
<output>3</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">14 + 9</gadget>
<output>23</output>
<gadget id="calculator">6 / 23</gadget>
<output>6/23 = around 0.26087</output>
<gadget id="calculator">782 * (6/23)</gadget>
<output>204</output>
<result>B</result> | B | 204 | if rs . 782 is divided into 3 parts , proportional to 1 / 2 : 2 / 3 : 3 / 4 find the first part . | {
"A": "190",
"B": "204",
"C": "220",
"D": "230",
"E": "none of these"
} | multiply(782, divide(divide(const_12, 2), add(add(divide(const_12, 2), multiply(divide(const_12, 3), const_2)), multiply(divide(const_12, 4), const_3)))) | divide(const_12,n3)|divide(const_12,n1)|divide(const_12,n7)|multiply(#1,const_2)|multiply(#2,const_3)|add(#0,#3)|add(#5,#4)|divide(#0,#6)|multiply(n0,#7) | explanation : 1 / 2 : 2 / 3 : 3 / 4 = 6 : 8 : 9 first part = 782 ∗ 6 / 23 = 204 option b | general |
math_qa__omqGusY89cbxclIf | The HCF of two numbers is 50 and the other two factors of their LCM are 11 and 12. What is the largest number.
Options
A) 462 B) 450 C) 480 D) 504 E) 600 | <gadget id="calculator">50 * 12</gadget>
<output>600</output>
<result>E</result> | E | 600 | The HCF of two numbers is 50 and the other two factors of their LCM are 11 and 12. What is the largest number. | {
"A": "462",
"B": "450",
"C": "480",
"D": "504",
"E": "600"
} | multiply(50, 12) | multiply(n0,n2)| | "explanation : hcf of the two numbers = 50 hcf will be always a factor of lcm 50 is factor of lcm other two factors are 11 & 12 then the numbers are ( 50 * 11 ) and ( 50 x 12 ) = 550 and 600 answer : option e" | other |
math_qa__fMaKY7l9uF4w7uct | Find the value for m?
21(m + n) + 21 = 21(-m + n) + 21 Choose the correct option
A) 0 B) - 1 C) 1 D) 2 E) 3 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">21 - 20</gadget>
<output>1</output>
<result>C</result> | C | 1 | Find the value for m?
21(m + n) + 21 = 21(-m + n) + 21 | {
"A": "0",
"B": "- 1",
"C": "1",
"D": "2",
"E": "3"
} | subtract(21, multiply(const_2, const_10)) | multiply(const_10,const_2)|subtract(n0,#0) | 21 m + 21 n - 21 = - 21 m + 21 n + 21 42 m = 42 = > m = 1 c | general |
math_qa__iw9ahMjNm4mbRFME | A certain telescope increases the visual range at a particular location from 50 kilometers to 150 kilometers. By what percent is the visual range increased by using the telescope ? Choose the correct option.
A) 30 % B) 33 1 / 2 % C) 40 % D) 60 % E) 200 % | <gadget id="calculator">150 - 50</gadget>
<output>100</output>
<gadget id="calculator">100 / 50</gadget>
<output>2</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<result>E</result> | E | 200 | A certain telescope increases the visual range at a particular location from 50 kilometers to 150 kilometers. By what percent is the visual range increased by using the telescope ? | {
"A": "30 %",
"B": "33 1 / 2 %",
"C": "40 %",
"D": "60 %",
"E": "200 %"
} | multiply(divide(subtract(150, 50), 50), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100) | original visual range = 50 km new visual range = 150 km percent increase in the visual range by using the telescope = ( 150 - 50 ) / 50 * 100 % = 2 * 100 % = 200 % answer e | general |
math_qa__6FsbO6v31XjdGnK9 | A contractor undertakes to built a walls in 50 days. He employs 60 peoples for the same. However after 25 days he finds that only 40% of the work is complete. How many more man need to be employed to complete the work in time? Choose the correct choice from the following answers
A) 25 B) 90 C) 35 D) 20 E) none of these | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">60 * (3/5)</gadget>
<output>36</output>
<gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">36 / (2/5)</gadget>
<output>90</output>
<result>B</result> | B | 90 | A contractor undertakes to built a walls in 50 days. He employs 60 peoples for the same. However after 25 days he finds that only 40% of the work is complete. How many more man need to be employed to complete the work in time? | {
"A": "25",
"B": "90",
"C": "35",
"D": "20",
"E": "none of these"
} | divide(multiply(60, divide(subtract(const_100, 40), const_100)), divide(const_4, const_10)) | divide(const_4,const_10)|subtract(const_100,n3)|divide(#1,const_100)|multiply(n1,#2)|divide(#3,#0)| | "60 men complete 0.4 work in 25 days . applying the work rule , m 1 × d 1 × w 2 = m 2 × d 2 × w 1 we have , 60 × 25 × 0.6 = m 2 × 25 × 0.4 or m 2 = 60 × 25 × 0.6 / 25 × 0.4 = 90 men answerb" | physics |
math_qa__S93fQe7zzM0kXwCh | Excluding stoppages, the average speed of a bus is 50 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour? Choose the most appropriate option:
A) 12 min B) 18 min C) 16 min D) 20 min E) 26 min | <gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">40 / 50</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 60</gadget>
<output>48</output>
<gadget id="calculator">60 - 48</gadget>
<output>12</output>
<result>A</result> | A | 12 | Excluding stoppages, the average speed of a bus is 50 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour? | {
"A": "12 min",
"B": "18 min",
"C": "16 min",
"D": "20 min",
"E": "26 min"
} | subtract(multiply(const_1, const_60), multiply(divide(40, 50), const_60)) | divide(n1,n0)|multiply(const_1,const_60)|multiply(#0,const_60)|subtract(#1,#2)| | "in 1 hr , the bus covers 50 km without stoppages and 40 km with stoppages . stoppage time = time take to travel ( 50 - 40 ) km i . e 10 km at 50 km / hr . stoppage time = 10 / 50 hrs = 12 min answer : a" | general |
math_qa__bE4yG51rzyXlTA9r | The total marks obtained by a student in Mathematics and Physics is 20 and his score in Chemistry is 20 marks more than that in Physics. Find the average marks scored in Mathamatics and Chemistry together. Choose the correct choice from the following answers.
A) 40 B) 26 C) 20 D) 28 E) 22 | <gadget id="calculator">20 + 20</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<result>C</result> | C | 20 | The total marks obtained by a student in Mathematics and Physics is 20 and his score in Chemistry is 20 marks more than that in Physics. Find the average marks scored in Mathamatics and Chemistry together. | {
"A": "40",
"B": "26",
"C": "20",
"D": "28",
"E": "22"
} | divide(add(20, 20), const_2) | add(n0,n1)|divide(#0,const_2)| | "let the marks obtained by the student in mathematics , physics and chemistry be m , p and c respectively . given , m + c = 20 and c - p = 20 m + c / 2 = [ ( m + p ) + ( c - p ) ] / 2 = ( 20 + 20 ) / 2 = 20 . answer : c" | general |
math_qa__DPeEoq0go2xLpng2 | How many numbers from 10 to 10000 are exactly divisible by 9? Choose the correct choice
A) 900
B) 1000
C) 1110
D) 1200
E) 1400 | <gadget id="calculator">10_000 / 9</gadget>
<output>10_000/9 = around 1_111.111111</output>
<gadget id="calculator">floor(10_000/9)</gadget>
<output>1_111</output>
<gadget id="calculator">1_111 * 9</gadget>
<output>9_999</output>
<gadget id="calculator">10 / 9</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">floor(10/9)</gadget>
<output>1</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 9</gadget>
<output>18</output>
<gadget id="calculator">9_999 - 18</gadget>
<output>9_981</output>
<gadget id="calculator">9_981 / 9</gadget>
<output>1_109</output>
<gadget id="calculator">1_109 + 1</gadget>
<output>1_110</output>
<result>C</result> | C | 1,110 | How many numbers from 10 to 10000 are exactly divisible by 9? | {
"A": "900",
"B": "1000",
"C": "1110",
"D": "1200",
"E": "1400"
} | add(divide(subtract(multiply(floor(divide(10000, 9)), 9), multiply(add(floor(divide(10, 9)), const_1), 9)), 9), const_1) | divide(n1,n2)|divide(n0,n2)|floor(#0)|floor(#1)|add(#3,const_1)|multiply(n2,#2)|multiply(n2,#4)|subtract(#5,#6)|divide(#7,n2)|add(#8,const_1)| | "10 / 9 = 1 and 10000 / 9 = 1111 = = > 1111 - 1 = 1110 . therefore 1110 answer : c" | general |
math_qa__zKtDOzkdZ9hXyrFg | Find the principle on a certain sum of money at 5% per annum for 4 years if the amount being Rs.1120? Options: A) 933 B) 1067 C) 1977 D) 1056 E) 1097 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">1_120 / (6/5)</gadget>
<output>2_800/3 = around 933.333333</output>
<result>A</result> | A | 933 | Find the principle on a certain sum of money at 5% per annum for 4 years if the amount being Rs.1120? | {
"A": "933",
"B": "1067",
"C": "1977",
"D": "1056",
"E": "1097"
} | divide(1120, add(const_1, divide(multiply(5, 4), const_100))) | multiply(n0,n1)|divide(#0,const_100)|add(#1,const_1)|divide(n2,#2)| | "1120 = p [ 1 + ( 5 * 4 ) / 100 ] p = 933 answer : a" | gain |
math_qa__PIwNq75EvGpEQOCi | Out of 10 students in a class, 4 are from Maharashtra, 3 are from Karnataka, and 3 are from Goa. Four students are to be selected at random. What are the chances that at least one is from Karnataka? Choose one: A) 1 / 3 B) 4 / 9 C) 5 / 6 D) 3 / 7 E) 1 / 4 | <gadget id="calculator">factorial(10)</gadget>
<output>3_628_800</output>
<gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">3_628_800 / 720</gadget>
<output>5_040</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">5_040 / 24</gadget>
<output>210</output>
<gadget id="calculator">10 - 3</gadget>
<output>7</output>
<gadget id="calculator">factorial(7)</gadget>
<output>5_040</output>
<gadget id="calculator">7 - 4</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">5_040 / 6</gadget>
<output>840</output>
<gadget id="calculator">840 / 24</gadget>
<output>35</output>
<gadget id="calculator">210 - 35</gadget>
<output>175</output>
<gadget id="calculator">175 / 210</gadget>
<output>5/6 = around 0.833333</output>
<result>C</result> | C | 0.833333 | Out of 10 students in a class, 4 are from Maharashtra, 3 are from Karnataka, and 3 are from Goa. Four students are to be selected at random. What are the chances that at least one is from Karnataka? | {
"A": "1 / 3",
"B": "4 / 9",
"C": "5 / 6",
"D": "3 / 7",
"E": "1 / 4"
} | divide(subtract(divide(divide(factorial(10), factorial(subtract(10, const_4))), factorial(const_4)), divide(divide(factorial(subtract(10, 3)), factorial(subtract(subtract(10, 3), const_4))), factorial(const_4))), divide(divide(factorial(10), factorial(subtract(10, const_4))), factorial(const_4))) | factorial(n0)|factorial(const_4)|subtract(n0,const_4)|subtract(n0,n2)|factorial(#2)|factorial(#3)|subtract(#3,const_4)|divide(#0,#4)|factorial(#6)|divide(#7,#1)|divide(#5,#8)|divide(#10,#1)|subtract(#9,#11)|divide(#12,#9)| | "total possible ways of selecting 4 students out of 10 = 10 c 4 = ( 10 * 9 * 8 * 7 ) / ( 4 * 3 * 2 * 1 ) = 210 the number of ways of selecting a 4 students in which no student belongs to karnataka = 7 c 4 number of ways of selecting atleast one student from karnataka = 15 c 4 - 7 c 4 = 175 probability = 175 / 210 = 5 / 6 answer is c" | probability |
math_qa__pVhuKzVIXgP2GBJO | A sum was put at simple interest at a certain rate for 3 years Had it been put at 3% higher rate, it would have fetched 81 more. Find the sum. Choose the correct option
A) 500 B) 600 C) 700 D) 800 E) 900 | <gadget id="calculator">3 / 100</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">(3/100) * 3</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">81 / (9/100)</gadget>
<output>900</output>
<result>E</result> | E | 900 | A sum was put at simple interest at a certain rate for 3 years Had it been put at 3% higher rate, it would have fetched 81 more. Find the sum. | {
"A": "500",
"B": "600",
"C": "700",
"D": "800",
"E": "900"
} | divide(81, multiply(divide(3, const_100), 3)) | divide(n1,const_100)|multiply(n0,#0)|divide(n2,#1)| | "difference in s . i . = p × t / 100 ( r 1 − r 2 ) ⇒ 81 = p × 3 x 3 / 100 ( ∵ r 1 - r 2 = 2 ) ⇒ p = 81 × 100 / 3 x 3 = 900 answer e" | gain |
math_qa__Yze0kr0A0Yy2Kpcp | The least whole number which when subtracted from both the terms of the ratio 6 : 7 to give a ratio less than 16 : 21, is Select: A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">21 * 6</gadget>
<output>126</output>
<gadget id="calculator">7 * 16</gadget>
<output>112</output>
<gadget id="calculator">126 - 112</gadget>
<output>14</output>
<gadget id="calculator">21 - 16</gadget>
<output>5</output>
<gadget id="calculator">14 / 5</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">2 / 10</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(14/5) + (1/5)</gadget>
<output>3</output>
<result>A</result> | A | 3 | The least whole number which when subtracted from both the terms of the ratio 6 : 7 to give a ratio less than 16 : 21, is | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | add(divide(subtract(multiply(21, 6), multiply(7, 16)), subtract(21, 16)), divide(const_2, const_10)) | divide(const_2,const_10)|multiply(n0,n3)|multiply(n1,n2)|subtract(n3,n2)|subtract(#1,#2)|divide(#4,#3)|add(#5,#0)| | "explanation : let x is subtracted . then , ( 6 − x ) / ( 7 − x ) < 16 / 21 21 ( 6 — x ) < 16 ( 7 — x ) = > 5 x > 14 = x > 2.8 least such number is 3 option a" | other |
math_qa__rFyXz54TUVPgOhmR | The total cost of 100 paper plates and 200 paper cups is $6.00 At the same rates what is the total cost of 20 of the plates and 40 of the cups? Select
A) $ . 90 B) $ 1.00 C) $ 1.20 D) $ 1.50 E) $ 1.60 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 6</gadget>
<output>6/5 = around 1.2</output>
<result>C</result> | C | 1.2 | The total cost of 100 paper plates and 200 paper cups is $6.00 At the same rates what is the total cost of 20 of the plates and 40 of the cups? | {
"A": "$ . 90",
"B": "$ 1.00",
"C": "$ 1.20",
"D": "$ 1.50",
"E": "$ 1.60"
} | multiply(divide(20, 100), 6) | divide(n3,n0)|multiply(n2,#0) | u dont need to go through all this what u have with u is 100 p + 200 c = $ 6.00 just divide the equation by 5 and you will get what u are looking for 20 p + 40 c = $ 1.20 therefore oa is c | gain |
math_qa__26QTZnv2FaY7uJS8 | If the price of sugar rises from Rs. 3 per kg to Rs. 5 per kg, a person, to have no increase in the expenditure on sugar, will have to reduce his consumption of sugar by Pick one: A) 15 % B) 20 % C) 25 % D) 30 % E) 40 % | <gadget id="calculator">1 * 3</gadget>
<output>3</output>
<gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>E</result> | E | 40 | If the price of sugar rises from Rs. 3 per kg to Rs. 5 per kg, a person, to have no increase in the expenditure on sugar, will have to reduce his consumption of sugar by | {
"A": "15 %",
"B": "20 %",
"C": "25 %",
"D": "30 %",
"E": "40 %"
} | multiply(subtract(const_1, divide(multiply(const_1, 3), 5)), const_100) | multiply(n0,const_1)|divide(#0,n1)|subtract(const_1,#1)|multiply(#2,const_100) | sol . let the original consumption = 100 kg and new consumption = x kg . so , 100 x 3 = x × 5 = x = 60 kg . ∴ reduction in consumption = 40 % . answer e | general |
math_qa__TxdYW8PXr5YsGrHH | A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 300 m long? Choose the correct choice from the following answers
A) 176 sec B) 190 sec C) 178 sec D) 150 sec E) 276 sec | <gadget id="calculator">1_200 + 300</gadget>
<output>1_500</output>
<gadget id="calculator">1_200 / 120</gadget>
<output>10</output>
<gadget id="calculator">1_500 / 10</gadget>
<output>150</output>
<result>D</result> | D | 150 | A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 300 m long? | {
"A": "176 sec",
"B": "190 sec",
"C": "178 sec",
"D": "150 sec",
"E": "276 sec"
} | divide(add(1200, 300), divide(1200, 120)) | add(n0,n2)|divide(n0,n1)|divide(#0,#1)| | "l = s * t s = 1200 / 120 s = 10 m / sec . total length ( d ) = 1500 m t = d / s t = 1500 / 10 t = 150 sec answer : d" | physics |
math_qa__smvLP3z62BwqVR0O | There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability W that the both positions will be taken by members of just one party? Choose one
A) 1 / 25 B) 12 / 49 C) 1 / 4 D) 24 / 49 E) 1 / 2 | <gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">25 - 1</gadget>
<output>24</output>
<gadget id="calculator">50 - 1</gadget>
<output>49</output>
<gadget id="calculator">24 / 49</gadget>
<output>24/49 = around 0.489796</output>
<gadget id="calculator">25 / 50</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(24/49) * (1/2)</gadget>
<output>12/49 = around 0.244898</output>
<gadget id="calculator">(12/49) * 2</gadget>
<output>24/49 = around 0.489796</output>
<result>D</result> | D | 0.489796 | There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability W that the both positions will be taken by members of just one party? | {
"A": "1 / 25",
"B": "12 / 49",
"C": "1 / 4",
"D": "24 / 49",
"E": "1 / 2"
} | multiply(multiply(divide(subtract(divide(50, 2), const_1), subtract(50, const_1)), divide(divide(50, 2), 50)), 2) | divide(n1,n0)|subtract(n1,const_1)|divide(#0,n1)|subtract(#0,const_1)|divide(#3,#1)|multiply(#4,#2)|multiply(n0,#5)| | "w probability of one party having both spots : ( 1 / 2 ) * ( 24 / 49 ) = 12 / 49 ( 1 / 2 ) or ( 25 / 50 ) because it does not matter which party or which person gets the first spot . ( 24 / 49 ) because after one person from a particular party is chosen , there are 24 members of the same party left out of 49 total candidates . since this result can happen for both parties , ( 12 / 49 ) + ( 12 / 49 ) = ( 24 / 49 ) answer : d" | other |
math_qa__Bwn26PdhuUM2BEhp | A gambler bought $3,000 worth of chips at a casino in denominations of $30 and $100. That evening, the gambler lost 16 chips, and then cashed in the remainder. If the number of $30 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back? Choose the correct choice from the following answers
A) $ 2,040 B) $ 2,120 C) $ 1,960 D) $ 1,920 E) $ 2,030 | <gadget id="calculator">3 * 1_000</gadget>
<output>3_000</output>
<gadget id="calculator">16 + 2</gadget>
<output>18</output>
<gadget id="calculator">18 / 2</gadget>
<output>9</output>
<gadget id="calculator">9 * 30</gadget>
<output>270</output>
<gadget id="calculator">9 - 2</gadget>
<output>7</output>
<gadget id="calculator">7 * 100</gadget>
<output>700</output>
<gadget id="calculator">270 + 700</gadget>
<output>970</output>
<gadget id="calculator">3_000 - 970</gadget>
<output>2_030</output>
<result>E</result> | E | 2,030 | A gambler bought $3,000 worth of chips at a casino in denominations of $30 and $100. That evening, the gambler lost 16 chips, and then cashed in the remainder. If the number of $30 chips lost was 2 more or 2 less than the number of $100 chips lost, what is the largest amount of money that the gambler could have received back? | {
"A": "$ 2,040",
"B": "$ 2,120",
"C": "$ 1,960",
"D": "$ 1,920",
"E": "$ 2,030"
} | subtract(multiply(const_3, const_1000), add(multiply(divide(add(16, 2), 2), 30), multiply(subtract(divide(add(16, 2), 2), 2), 100))) | add(n3,n5)|multiply(const_1000,const_3)|divide(#0,n5)|multiply(n1,#2)|subtract(#2,n5)|multiply(n2,#4)|add(#3,#5)|subtract(#1,#6)| | "in order to maximize the amount of money that the gambler kept , we should maximize # of $ 30 chips lost and minimize # of $ 100 chips lost , which means that # of $ 30 chips lost must be 2 more than # of $ 100 chips lost . so , if # of $ 30 chips lost is x then # of $ 100 chips lost should be x - 2 . now , given that total # of chips lost is 16 : x + x - 2 = 16 - - > x = 9 : 9 $ 30 chips were lost and 9 - 2 = 7 $ 100 chips were lost . total worth of chips lost is 9 * 30 + 7 * 100 = $ 970 , so the gambler kept $ 3,000 - $ 970 = $ 2,030 . answer : e" | general |
math_qa__f7S82QmdNAa3kZ5r | A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 6 litres a minute. When the tank is full, the inlet is opened and due to the leak, the tank is empty in 12 hours. How many litres does the cistern hold? Choose the correct choice from the following
A) 7580 B) 7960 C) 8290 D) 4320 E) none | <gadget id="calculator">12 * 60</gadget>
<output>720</output>
<gadget id="calculator">6 * 720</gadget>
<output>4_320</output>
<gadget id="calculator">6 * 60</gadget>
<output>360</output>
<gadget id="calculator">720 / 360</gadget>
<output>2</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">4_320 / 1</gadget>
<output>4_320</output>
<result>D</result> | D | 4,320 | A leak in the bottom of a tank can empty the full tank in 6 hours. An inlet pipe fills water at the rate of 6 litres a minute. When the tank is full, the inlet is opened and due to the leak, the tank is empty in 12 hours. How many litres does the cistern hold? | {
"A": "7580",
"B": "7960",
"C": "8290",
"D": "4320",
"E": "none"
} | divide(multiply(6, multiply(12, const_60)), subtract(divide(multiply(12, const_60), multiply(6, const_60)), const_1)) | multiply(n2,const_60)|multiply(n0,const_60)|divide(#0,#1)|multiply(n1,#0)|subtract(#2,const_1)|divide(#3,#4)| | "solution work done by the inlet in 1 hour = ( 1 / 6 - 1 / 12 ) = 1 / 12 . work done by the inlet in 1 min . = ( 1 / 12 × 1 / 60 ) = 0.001389 volume of 0.001389 part = 6 litres . therefore , volume of whole = 1 / 0.001389 x 6 ‹ = › 4320 litres . answer d" | physics |
math_qa__3LSKkQKiBju9F6aS | Maxwell leaves his home and walks toward Brad's house. One hour later, Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 24 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h. What is the total time it takes Maxwell before he meets up with Brad? Choose the correct choice from the following answers:
A) 3 B) 4 C) 5 D) 6 E) 8 | <gadget id="calculator">24 + 6</gadget>
<output>30</output>
<gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">30 / 10</gadget>
<output>3</output>
<result>A</result> | A | 3 | Maxwell leaves his home and walks toward Brad's house. One hour later, Brad leaves his home and runs toward Maxwell's house. If the distance between their homes is 24 kilometers, Maxwell's walking speed is 4 km/h, and Brad's running speed is 6 km/h. What is the total time it takes Maxwell before he meets up with Brad? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "8"
} | divide(add(24, 6), add(4, 6)) | add(n0,n2)|add(n1,n2)|divide(#0,#1)| | "total distance = 24 kms maxwell speed = 4 kms / hr maxwell travelled for 1 hour before brad started , therefore maxwell traveled for 4 kms in 1 hour . time taken = total distance / relative speed total distance after brad started = 20 kms relative speed ( opposite side ) ( as they are moving towards each other speed would be added ) = 6 + 4 = 10 kms / hr time taken to meet brad after brad started = 20 / 10 = 2 hrs distance traveled by maxwell = maxwell ' s speed * time taken = 4 * 2 = 8 + 4 = 12 kms . . . therefore total time taken by maxwell to meet brad = distance travelled by maxwell / maxwell ' s speed = 12 / 4 = 3 hrs . . . answer a" | physics |
math_qa__7lNIzVT6rL6uu9CU | If 20 percent of the students at a certain school went to a camping trip and took more than $100, and 75 percent of the students who went to the camping trip did not take more than $100, what percentage of the students at the school went to the camping trip? Choose the correct choice from the following options
A) 95
B) 90
C) 85
D) 80
E) 75 | <gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">20 / (1/4)</gadget>
<output>80</output>
<result>D</result> | D | 80 | If 20 percent of the students at a certain school went to a camping trip and took more than $100, and 75 percent of the students who went to the camping trip did not take more than $100, what percentage of the students at the school went to the camping trip? | {
"A": "95",
"B": "90",
"C": "85",
"D": "80",
"E": "75"
} | divide(20, divide(subtract(100, 75), 100)) | subtract(n1,n2)|divide(#0,n1)|divide(n0,#1)| | "let x be the number of students in the school . 0.2 x students went to the trip and took more than 100 $ . they compose ( 100 - 75 ) = 25 % of all students who went to the trip . therefore the toal of 0.2 x / 0.25 = 0.8 x students went to the camping which is 80 % . the answer is d" | general |
math_qa__cre2lcAF5nGjUjrq | In a group of 400 readers who read science fiction or literacy works or both, 250 read science fiction and 230 read literacy works. How many read both science fiction and literacy works? Choose the correct choice from the following answers.
A) 70 B) 80 C) 90 D) 100 E) 110 | <gadget id="calculator">250 + 230</gadget>
<output>480</output>
<gadget id="calculator">480 - 400</gadget>
<output>80</output>
<result>B</result> | B | 80 | In a group of 400 readers who read science fiction or literacy works or both, 250 read science fiction and 230 read literacy works. How many read both science fiction and literacy works? | {
"A": "70",
"B": "80",
"C": "90",
"D": "100",
"E": "110"
} | subtract(add(250, 230), 400) | add(n1,n2)|subtract(#0,n0)| | "consider total number of reader n ( s u l ) = 400 people who read science fiction n ( s ) = 250 people who read literacy works n ( l ) = 230 both science fiction and literacy n ( s ∩ l ) = ? n ( s u l ) = n ( s ) + n ( l ) - n ( s ∩ l ) 400 = 250 + 230 - n ( s ∩ l ) n ( s ∩ l ) = 480 - 400 n ( s ∩ l ) = 80 so people read both science fiction and literacy works are 80 answer : b" | other |
math_qa__UUnsWviWxtNjICxi | If 12 men and 16 boys can do a piece of work in 5 days and 13 men together will 24 boys can do it in 4 days. Compare the daily work done by a man with that of a boy? Pick.
A) 2 : 5 B) 2 : 9 C) 2 : 4 D) 2 : 1 E) 2 : 2 | <gadget id="calculator">4 * 24</gadget>
<output>96</output>
<gadget id="calculator">5 * 16</gadget>
<output>80</output>
<gadget id="calculator">96 - 80</gadget>
<output>16</output>
<gadget id="calculator">5 * 12</gadget>
<output>60</output>
<gadget id="calculator">4 * 13</gadget>
<output>52</output>
<gadget id="calculator">60 - 52</gadget>
<output>8</output>
<gadget id="calculator">16 / 8</gadget>
<output>2</output>
<result>D</result> | D | 2 | If 12 men and 16 boys can do a piece of work in 5 days and 13 men together will 24 boys can do it in 4 days. Compare the daily work done by a man with that of a boy? | {
"A": "2 : 5",
"B": "2 : 9",
"C": "2 : 4",
"D": "2 : 1",
"E": "2 : 2"
} | divide(subtract(multiply(4, 24), multiply(5, 16)), subtract(multiply(5, 12), multiply(4, 13))) | multiply(n4,n5)|multiply(n1,n2)|multiply(n0,n2)|multiply(n3,n5)|subtract(#0,#1)|subtract(#2,#3)|divide(#4,#5) | 12 m + 16 b - - - - - 5 days 13 m + 24 b - - - - - - - 4 days 60 m + 80 b = 52 m + 96 b 8 m = 16 b = > 1 m = 2 b m : b = 2 : 1 answer : d | physics |
math_qa__jpwd1Dmt3YW36v07 | The pilot of a small aircraft with a 40-gallon fuel tank wants to fly to Cleveland, which is 480 miles away. The pilot recognizes that the current engine, which can fly only 10 miles per gallon, will not get him there. By how many miles per gallon must the aircraft’s fuel efficiency be improved to make the flight to Cleveland possible? Choose the correct choice from the following answers: A) 2 B) 4 C) 12 D) 40 E) 160 | <gadget id="calculator">480 / 40</gadget>
<output>12</output>
<gadget id="calculator">12 - 10</gadget>
<output>2</output>
<result>A</result> | A | 2 | The pilot of a small aircraft with a 40-gallon fuel tank wants to fly to Cleveland, which is 480 miles away. The pilot recognizes that the current engine, which can fly only 10 miles per gallon, will not get him there. By how many miles per gallon must the aircraft’s fuel efficiency be improved to make the flight to Cleveland possible? | {
"A": "2",
"B": "4",
"C": "12",
"D": "40",
"E": "160"
} | subtract(divide(480, 40), 10) | divide(n1,n0)|subtract(#0,n2)| | "actual miles / gallon is = 480 / 40 = 12 miles / gallon . current engine miles / gallon is 10 miles / gallon . additional 2 miles / gallon is required to match the actual mileage . imo option a ." | physics |
math_qa__T8tLNoayaQQUKVdA | A certain bus driver is paid a regular rate of $12 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $976 in total compensation, how many total hours did he work that week? Choose the correct choice
A) 60 B) 68 C) 65 D) 64 E) 61 | <gadget id="calculator">12 * 40</gadget>
<output>480</output>
<gadget id="calculator">976 - 480</gadget>
<output>496</output>
<gadget id="calculator">100 + 75</gadget>
<output>175</output>
<gadget id="calculator">12 * 175</gadget>
<output>2_100</output>
<gadget id="calculator">2_100 / 100</gadget>
<output>21</output>
<gadget id="calculator">496 / 21</gadget>
<output>496/21 = around 23.619048</output>
<gadget id="calculator">40 + (496/21)</gadget>
<output>1_336/21 = around 63.619048</output>
<result>D</result> | D | 64 | A certain bus driver is paid a regular rate of $12 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $976 in total compensation, how many total hours did he work that week? | {
"A": "60",
"B": "68",
"C": "65",
"D": "64",
"E": "61"
} | add(40, divide(subtract(976, multiply(12, 40)), divide(multiply(12, add(const_100, 75)), const_100))) | add(n3,const_100)|multiply(n0,n1)|multiply(n0,#0)|subtract(n4,#1)|divide(#2,const_100)|divide(#3,#4)|add(n1,#5)| | "for 40 hrs = 40 * 12 = 480 excess = 976 - 480 = 496 for extra hours = . 75 ( 12 ) = 9 + 12 = 21 number of extra hrs = 496 / 21 = 23.62 total hrs = 40 + 23.62 = 63.62 = 64 approx . answer d 64" | general |
math_qa__SnvrD5Zi9LGWD1YM | 5 cats can catch 5 mice in 5 minutes. How many cats does it take to catch 100 mice in 100 minutes? Choose the correct choice from the following
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">5 * 4</gadget>
<output>20</output>
<gadget id="calculator">100 / 20</gadget>
<output>5</output>
<result>E</result> | E | 5 | 5 cats can catch 5 mice in 5 minutes. How many cats does it take to catch 100 mice in 100 minutes? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(100, multiply(5, const_4)) | multiply(n0,const_4)|divide(n3,#0) | let x be no . of cat 5 cat catch 5 mice in 5 min 5 cat catch 1 mice in ( 5 / 5 = 1 min ) 1 cat catch 1 mice in 1 * 5 = 5 min 1 cat catch 100 mice in 5 * 100 min x cat catch 100 mice in ( 5 * 100 ) / x min a / q ( 5 * 100 ) / x = 100 = > 5 * 100 = x * 100 = > x = 5 answer : e | physics |
math_qa__zbJH9UtHZZb0tLLG | The tax on a commodity is diminished by 19% and its consumption increased by 15%. The effect on revenue is? Pick one
A) 2 % B) 8.85 % C) 5.85 % D) 6.85 % E) 1 % | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">19 / 100</gadget>
<output>19/100 = around 0.19</output>
<gadget id="calculator">1 - (19/100)</gadget>
<output>81/100 = around 0.81</output>
<gadget id="calculator">(23/20) * (81/100)</gadget>
<output>1_863/2_000 = around 0.9315</output>
<gadget id="calculator">(1_863/2_000) * 100</gadget>
<output>1_863/20 = around 93.15</output>
<gadget id="calculator">100 - (1_863/20)</gadget>
<output>137/20 = around 6.85</output>
<result>D</result> | D | 6.85 | The tax on a commodity is diminished by 19% and its consumption increased by 15%. The effect on revenue is? | {
"A": "2 %",
"B": "8.85 %",
"C": "5.85 %",
"D": "6.85 %",
"E": "1 %"
} | subtract(const_100, multiply(multiply(add(const_1, divide(15, const_100)), subtract(const_1, divide(19, const_100))), const_100)) | divide(n1,const_100)|divide(n0,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|multiply(#4,const_100)|subtract(const_100,#5)| | "100 * 100 = 10000 81 * 115 = 9315 - - - - - - - - - - - 10000 - - - - - - - - - - - 685 100 - - - - - - - - - - - ? = > 6.85 % decrease answer : d" | general |
math_qa__VSDNH4gBSYU8lja7 | If x is less than y by 40% then y exceed x by: Choose the most appropriate option:
A) 33.33 % B) 25 % C) 75 % D) 66.66 % E) none of these | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">100 / 60</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) - 1</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 100</gadget>
<output>200/3 = around 66.666667</output>
<result>D</result> | D | 66.66 | If x is less than y by 40% then y exceed x by: | {
"A": "33.33 %",
"B": "25 %",
"C": "75 %",
"D": "66.66 %",
"E": "none of these"
} | multiply(subtract(divide(const_100, subtract(const_100, 40)), const_1), const_100) | subtract(const_100,n0)|divide(const_100,#0)|subtract(#1,const_1)|multiply(#2,const_100)| | "using formula ( x / ( 100 - x ) * 100 ) where x is percentage decrease ( here it is 40 % ) = > 40 / ( 100 - 40 ) * 100 = 66.66 % answer : d" | general |
math_qa__0gae1JEjwkkqe7d5 | P is 20% more efficient than Q. P can complete a work in 22 days. If P and Q work together, how many days will it take to complete the same work? Choose the correct choice from the following options
A) 8 B) 11 C) 12 D) 15 E) 16 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * 22</gadget>
<output>132/5 = around 26.4</output>
<gadget id="calculator">(6/5) + 1</gadget>
<output>11/5 = around 2.2</output>
<gadget id="calculator">(132/5) / (11/5)</gadget>
<output>12</output>
<result>C</result> | C | 12 | P is 20% more efficient than Q. P can complete a work in 22 days. If P and Q work together, how many days will it take to complete the same work? | {
"A": "8",
"B": "11",
"C": "12",
"D": "15",
"E": "16"
} | divide(multiply(add(divide(20, const_100), const_1), 22), add(add(divide(20, const_100), const_1), const_1)) | divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(n1,#1)|divide(#3,#2)| | "the work done by p in 1 day = 1 / 22 let work done by q in 1 day = q q × ( 120 / 100 ) = 1 / 22 q = 100 / ( 22 × 120 ) = 10 / ( 22 × 12 ) the work done by p and q in 1 day = 1 / 22 + 10 / ( 22 × 12 ) = 22 / ( 22 × 12 ) = 1 / 12 p and q together can do the work in 12 days . the answer is c ." | physics |
math_qa__ZVmt3EUS2NXqMhuI | A school has 4 section of Chemistry in Class X having 55, 35, 45 and 42 students. The mean marks obtained in Chemistry test are 50, 60, 55 and 45 respectively for the 4 sections. Determine the overall average of marks per student.
Choose the correct choice from the following answers.
A) 50.15
B) 52.06
C) 51.25
D) 53.06
E) none of the above | <gadget id="calculator">55 * 50</gadget>
<output>2_750</output>
<gadget id="calculator">35 * 60</gadget>
<output>2_100</output>
<gadget id="calculator">2_750 + 2_100</gadget>
<output>4_850</output>
<gadget id="calculator">45 * 55</gadget>
<output>2_475</output>
<gadget id="calculator">4_850 + 2_475</gadget>
<output>7_325</output>
<gadget id="calculator">42 * 45</gadget>
<output>1_890</output>
<gadget id="calculator">7_325 + 1_890</gadget>
<output>9_215</output>
<gadget id="calculator">55 + 35</gadget>
<output>90</output>
<gadget id="calculator">90 + 45</gadget>
<output>135</output>
<gadget id="calculator">135 + 42</gadget>
<output>177</output>
<gadget id="calculator">9_215 / 177</gadget>
<output>9_215/177 = around 52.062147</output>
<result>B</result> | B | 52.06 | A school has 4 section of Chemistry in Class X having 55, 35, 45 and 42 students. The mean marks obtained in Chemistry test are 50, 60, 55 and 45 respectively for the 4 sections. Determine the overall average of marks per student. | {
"A": "50.15",
"B": "52.06",
"C": "51.25",
"D": "53.06",
"E": "none of the above"
} | divide(add(add(add(multiply(55, 50), multiply(35, 60)), multiply(45, 55)), multiply(42, 45)), add(add(add(55, 35), 45), 42)) | add(n1,n2)|multiply(n1,n5)|multiply(n2,n6)|multiply(n3,n7)|multiply(n3,n4)|add(#1,#2)|add(n3,#0)|add(#5,#3)|add(n4,#6)|add(#7,#4)|divide(#9,#8)| | "required average marks = 55 ã — 50 + 35 ã — 60 + 45 ã — 55 + 42 ã — 45 / 55 + 35 + 45 + 42 = 2750 + 2100 + 2475 + 1890 / 162 = 9215 â „ 177 = 52.06 answer b" | general |
math_qa__rzOB4B3f98qz3ETe | Rs.2600 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share?
Choose the correct option.
A) s . 1200 B) s . 1542 C) s . 1528 D) s . 1540 E) s . 1549 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">2_600 / 9</gadget>
<output>2_600/9 = around 288.888889</output>
<gadget id="calculator">4 * (2_600/9)</gadget>
<output>10_400/9 = around 1_155.555556</output>
<result>A</result> | A | 1,200 | Rs.2600 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share? | {
"A": "s . 1200",
"B": "s . 1542",
"C": "s . 1528",
"D": "s . 1540",
"E": "s . 1549"
} | multiply(4, divide(2600, add(add(4, 2), const_3))) | add(n1,n2)|add(#0,const_3)|divide(n0,#1)|multiply(n1,#2)| | "a + b + c = 2600 4 a = 3 b = 2 c = x a : b : c = 1 / 4 : 1 / 3 : 1 / 2 = 3 : 4 : 6 6 / 13 * 2600 = rs . 1200 answer : a" | general |
math_qa__0B7S3spvnQEhND06 | The difference of two numbers is 1355. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ? Options.
A) 240 B) 270 C) 295 D) 268 E) 252 | <gadget id="calculator">1_355 + 15</gadget>
<output>1_370</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">1_370 / 5</gadget>
<output>274</output>
<result>D</result> | D | 268 | The difference of two numbers is 1355. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ? | {
"A": "240",
"B": "270",
"C": "295",
"D": "268",
"E": "252"
} | divide(add(1355, 15), subtract(6, const_1)) | add(n0,n2)|subtract(n1,const_1)|divide(#0,#1)| | "let the smaller number be x . then larger number = ( x + 1355 ) . x + 1355 = 6 x + 15 5 x = 1340 x = 268 smaller number = 270 . answer d" | general |
math_qa__vfSqEs2zYGiTt3K3 | If a radio is purchased for Rs 490 and sold for Rs 465.50 Find the loss%? Choose the correct choice from the following: A) 5 % B) 4 % C) 6 % D) 8 % E) 7 % | <gadget id="calculator">490 - 465.5</gadget>
<output>24.5</output>
<gadget id="calculator">24.5 * 100</gadget>
<output>2_450</output>
<gadget id="calculator">2_450 / 490</gadget>
<output>5</output>
<result>A</result> | A | 5 | If a radio is purchased for Rs 490 and sold for Rs 465.50 Find the loss%? | {
"A": "5 %",
"B": "4 %",
"C": "6 %",
"D": "8 %",
"E": "7 %"
} | divide(multiply(subtract(490, 465.5), const_100), 490) | subtract(n0,n1)|multiply(#0,const_100)|divide(#1,n0) | c . p = rs 490 s . p = rs 465.50 loss = c . p - s . p = 490 - 465.50 = rs 24.50 loss % = ( loss * 100 ) / c . p % = ( 24.50 * 100 ) / 490 % = 5 % answer a 5 % | gain |
math_qa__90KaeycVQOIHzqRc | if a person cover 3/5 part of his journey by train,7/20 part of his journey by bus and rest 6.5 km. by walk.what is total distance of his journey? Options:
A) 65 km
B) 100 km
C) 120 km
D) 130 km
E) 75 km | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">7 / 20</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(3/5) + (7/20)</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">1 - (19/20)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">6.5 / (1/20)</gadget>
<output>130</output>
<result>D</result> | D | 130 | if a person cover 3/5 part of his journey by train,7/20 part of his journey by bus and rest 6.5 km. by walk.what is total distance of his journey? | {
"A": "65 km",
"B": "100 km",
"C": "120 km",
"D": "130 km",
"E": "75 km"
} | divide(6.5, subtract(const_1, add(divide(3, 5), divide(7, 20)))) | divide(n0,n1)|divide(n2,n3)|add(#0,#1)|subtract(const_1,#2)|divide(n4,#3) | let total distance be = x km . then , 3 x / 5 + 7 x / 20 + 6.5 = x ; 12 x + 7 x + 130 = 20 x ; x = 130 hence total distance = 130 km . answer d | general |
math_qa__h7RLrSA40JPLKLuO | The H.C.F. of two numbers is 16 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is: Choose the correct choice from the following choices
A) 276 B) 299 C) 224 D) 345 E) 365 | <gadget id="calculator">16 * 14</gadget>
<output>224</output>
<result>C</result> | C | 224 | The H.C.F. of two numbers is 16 and the other two factors of their L.C.M. are 13 and 14. The larger of the two numbers is: | {
"A": "276",
"B": "299",
"C": "224",
"D": "345",
"E": "365"
} | multiply(16, 14) | multiply(n0,n2)| | "clearly , the numbers are ( 16 x 13 ) and ( 16 x 14 ) . larger number = ( 23 x 14 ) = 224 . answer : option c" | other |
math_qa__ZEeWg5MhEQUoEPVI | At a certain resort, each of the 39 food service employees is trained to work in a minimum of 1 restaurant and a maximum of 3 restaurants. The 3 restaurants are the family buffet, the dining room, and the snack bar. Exactly 21 employees are trained to work in the family buffet, 18 are trained to work in the dining room, and 12 are trained to work in the snack bar. If 4 employees are trained to work in exactly 2 restaurants, how many employees are trained to work in all 3 restaurants? Choose the correct choice
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">21 + 18</gadget>
<output>39</output>
<gadget id="calculator">39 + 12</gadget>
<output>51</output>
<gadget id="calculator">51 - 4</gadget>
<output>47</output>
<gadget id="calculator">47 - 39</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>C</result> | C | 4 | At a certain resort, each of the 39 food service employees is trained to work in a minimum of 1 restaurant and a maximum of 3 restaurants. The 3 restaurants are the family buffet, the dining room, and the snack bar. Exactly 21 employees are trained to work in the family buffet, 18 are trained to work in the dining room, and 12 are trained to work in the snack bar. If 4 employees are trained to work in exactly 2 restaurants, how many employees are trained to work in all 3 restaurants? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | divide(subtract(subtract(add(add(21, 18), 12), 4), 39), 2) | add(n4,n5)|add(n6,#0)|subtract(#1,n7)|subtract(#2,n0)|divide(#3,n8)| | "39 = 21 + 18 + 12 - 4 - 2 x 2 x = 21 + 18 + 12 - 4 - 39 = 47 - 39 = 8 x = 4 c" | physics |
math_qa__OtMjcOEP9ERUZ1y9 | A bookstore has a shelf that contains biographies which normally sell for $20 each and mysteries that normally sell for $12 each. During a sale, the biographies and mysteries are discounted at different rates so that a customer saves a total of $19 from the normal price by buying 5 discounted biographies and 3 discounted mysteries. If the sum of the discount rates for the two types of books is 43 percent, what is the discount rate on mysteries?
Select the correct option: A) 24 % B) 25 % C) 30 % D) 37.5 % E) 40 % | <gadget id="calculator">20 * 2</gadget>
<output>40</output>
<gadget id="calculator">20 + 43</gadget>
<output>63</output>
<gadget id="calculator">63 + 1</gadget>
<output>64</output>
<gadget id="calculator">40 / 64</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">1 - (5/8)</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(3/8) * 100</gadget>
<output>75/2 = around 37.5</output>
<result>D</result> | D | 37.5 | A bookstore has a shelf that contains biographies which normally sell for $20 each and mysteries that normally sell for $12 each. During a sale, the biographies and mysteries are discounted at different rates so that a customer saves a total of $19 from the normal price by buying 5 discounted biographies and 3 discounted mysteries. If the sum of the discount rates for the two types of books is 43 percent, what is the discount rate on mysteries? | {
"A": "24 %",
"B": "25 %",
"C": "30 %",
"D": "37.5 %",
"E": "40 %"
} | multiply(subtract(const_1, divide(multiply(20, const_2), add(add(20, 43), const_1))), const_100) | add(n0,n5)|multiply(n0,const_2)|add(#0,const_1)|divide(#1,#2)|subtract(const_1,#3)|multiply(#4,const_100) | let b be the discount on biographies and m be the discount on mysteries so . , b + m = 0.435 - - - - - ( 1 ) and ( 20 * 5 + 12 * 3 ) - ( 20 * 5 * ( 1 - b ) + 12 * 3 * ( 1 - m ) ) = 19 - - > 100 ( 1 - ( 1 - b ) ) + 36 ( 1 - ( 1 - m ) = 19 100 b + 36 m = 19 - - - - - - ( 2 ) solving 12 . , we get m = 0.375 = 37.5 % d | gain |
math_qa__GOZb8P4U6S75O2RJ | Calculate the average of all the numbers between 15 and 55 which are divisible by 4. Choose one: A) 39 B) 33 C) 34 D) 30 E) 36 | <gadget id="calculator">15 / 4</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">floor(15/4)</gadget>
<output>3</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">55 / 4</gadget>
<output>55/4 = around 13.75</output>
<gadget id="calculator">floor(55/4)</gadget>
<output>13</output>
<gadget id="calculator">4 + 13</gadget>
<output>17</output>
<gadget id="calculator">17 / 2</gadget>
<output>17/2 = around 8.5</output>
<gadget id="calculator">(17/2) * 4</gadget>
<output>34</output>
<result>C</result> | C | 34 | Calculate the average of all the numbers between 15 and 55 which are divisible by 4. | {
"A": "39",
"B": "33",
"C": "34",
"D": "30",
"E": "36"
} | multiply(divide(add(add(floor(divide(15, 4)), const_1), floor(divide(55, 4))), const_2), 4) | divide(n0,n2)|divide(n1,n2)|floor(#0)|floor(#1)|add(#2,const_1)|add(#4,#3)|divide(#5,const_2)|multiply(n2,#6) | explanation : numbers divisible by 4 are 16,20 , 24,28 , 32,36 , 40,44 , 48,52 , , , average = ( 16 + 20 + 24 + 28 + 32 + 36 + 40 + 44 + 48 + 52 ) / 10 = 340 / 10 = 34 answer : c | general |
math_qa__Mu3TLxMjdw6Vfohl | What is the remainder when 9^1 + 9^2 + 9^3 +...+ 9^9 is divided by 9? Choose the correct choice from the following choices:
A) 2 B) 3 C) 0 D) 5 E) none of the above | <gadget id="calculator">9 ** 1</gadget>
<output>9</output>
<gadget id="calculator">9 - 9</gadget>
<output>0</output>
<gadget id="calculator">0 / 9</gadget>
<output>0</output>
<result>C</result> | C | 0 | What is the remainder when 9^1 + 9^2 + 9^3 +...+ 9^9 is divided by 9? | {
"A": "2",
"B": "3",
"C": "0",
"D": "5",
"E": "none of the above"
} | divide(subtract(power(9, 1), power(9, 1)), 9) | power(n0,n1)|power(n2,n1)|subtract(#0,#1)|divide(#2,n4)| | "notice that in the brackets we have the sum of 9 odd multiples of 9 , which yields remainder of 0 upon division by 9 . answer : c" | general |
math_qa__7dhnmbcaeMyHusEc | By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%?
Pick one.
A) rs . 488 B) rs . 480 C) rs . 482 D) rs . 487 E) rs . 481 | <gadget id="calculator">800 * 100</gadget>
<output>80_000</output>
<gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">80_000 / 125</gadget>
<output>640</output>
<gadget id="calculator">640 * 25</gadget>
<output>16_000</output>
<gadget id="calculator">16_000 / 100</gadget>
<output>160</output>
<gadget id="calculator">640 - 160</gadget>
<output>480</output>
<result>B</result> | B | 480 | By selling an article at Rs.800, a shopkeeper makes a profit of 25%. At what price should he sell the article so as to make a loss of 25%? | {
"A": "rs . 488",
"B": "rs . 480",
"C": "rs . 482",
"D": "rs . 487",
"E": "rs . 481"
} | subtract(divide(multiply(800, const_100), add(25, const_100)), divide(multiply(divide(multiply(800, const_100), add(25, const_100)), 25), const_100)) | add(n1,const_100)|multiply(n0,const_100)|divide(#1,#0)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "sp = 800 profit = 25 % cp = ( sp ) * [ 100 / ( 100 + p ) ] = 800 * [ 100 / 125 ] = 640 loss = 25 % = 25 % of 640 = rs . 160 sp = cp - loss = 640 - 160 = rs . 480 answer : b" | gain |
math_qa__ZNpaz70mSCQHaqKK | If (A+B) = 16, (B+C) = 9 and (C+D) = 3, what is the value of (A+D)? Select the correct option.
A) 10 . B) 8 . C) 7 . D) 2 . E) - 2 . | <gadget id="calculator">16 + 3</gadget>
<output>19</output>
<gadget id="calculator">19 - 9</gadget>
<output>10</output>
<result>A</result> | A | 10 | If (A+B) = 16, (B+C) = 9 and (C+D) = 3, what is the value of (A+D)? | {
"A": "10 .",
"B": "8 .",
"C": "7 .",
"D": "2 .",
"E": "- 2 ."
} | subtract(add(16, 3), 9) | add(n0,n2)|subtract(#0,n1)| | "given a + b = 16 = > a = 16 - b - - > eq 1 b + c = 9 c + d = 3 = > d = 3 - c - - > eq 2 then eqs 1 + 2 = > a + d = 16 - b + 3 - c = > 19 - ( b + c ) = > 19 - 9 = 10 . option a . . ." | general |
math_qa__EkK3porOo6XLNj44 | Rs.880 is divided amongst A, B, C so that 4 times A's share, 5 times B's share and 10 times C's share are all equal. Find C's share? Choose one: A) 177 B) 150 C) 817 D) 160 E) 616 | <gadget id="calculator">10 / 4</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">10 / 5</gadget>
<output>2</output>
<gadget id="calculator">(5/2) + 2</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">(9/2) + 1</gadget>
<output>11/2 = around 5.5</output>
<gadget id="calculator">880 / (11/2)</gadget>
<output>160</output>
<result>D</result> | D | 160 | Rs.880 is divided amongst A, B, C so that 4 times A's share, 5 times B's share and 10 times C's share are all equal. Find C's share? | {
"A": "177",
"B": "150",
"C": "817",
"D": "160",
"E": "616"
} | divide(880, add(add(divide(10, 4), divide(10, 5)), const_1)) | divide(n3,n1)|divide(n3,n2)|add(#0,#1)|add(#2,const_1)|divide(n0,#3) | a + b + c = 880 4 a = 5 b = 10 c = x a : b : c = 1 / 4 : 1 / 5 : 1 / 10 = 5 : 4 : 2 2 / 11 * 880 = rs . 160 answer : d | general |
math_qa__bMeE05M5HhacEjeG | in a certain aquarium , the number of red fish is 3 times the number of the green fish , and the number of blue fish is half the number of the red fish . if the ratio of green fish to red fish were to be doubled , and the ratio of red fish to blue fish were to be doubled , then the ratio of blue fish to green fish in that aquarium would be
Choose the correct choice from the following answers
A) 3 : 2
B) 1 : 1
C) 1 : 2
D) 3 : 4
E) 3 : 8 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">2 * (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 / (2/3)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(1/4) * (3/2)</gadget>
<output>3/8 = around 0.375</output>
<result>E</result> | E | 0.375 | in a certain aquarium , the number of red fish is 3 times the number of the green fish , and the number of blue fish is half the number of the red fish . if the ratio of green fish to red fish were to be doubled , and the ratio of red fish to blue fish were to be doubled , then the ratio of blue fish to green fish in that aquarium would be | {
"A": "3 : 2",
"B": "1 : 1",
"C": "1 : 2",
"D": "3 : 4",
"E": "3 : 8"
} | multiply(inverse(multiply(const_2, const_2)), inverse(multiply(const_2, divide(const_1, 3)))) | divide(const_1,n0)|multiply(const_2,const_2)|inverse(#1)|multiply(#0,const_2)|inverse(#3)|multiply(#2,#4) | lots of little places to make a mistake or panic here . = ) r = 3 g b = r / 2 g / r = 1 / 3 - - - - > doubled g / r = 2 / 3 r / b = 2 - - - - > doubled r / b = 4 b / g = ( b / r ) * ( r / g ) = ( 1 / 4 ) * ( 3 / 2 ) = 3 / 8 answer : e | general |
math_qa__F7tZmh1znCI8sCg8 | A car drives 90 miles on local roads at 30 mph, and 75 miles on the highway at 60 mph, what is the average speed of the entire trip? Pick
A) 36 mph B) 40 mph C) 39 mph D) 42 mph E) 38 mph | <gadget id="calculator">90 + 75</gadget>
<output>165</output>
<gadget id="calculator">90 / 30</gadget>
<output>3</output>
<gadget id="calculator">75 / 60</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">3 + (5/4)</gadget>
<output>17/4 = around 4.25</output>
<gadget id="calculator">165 / (17/4)</gadget>
<output>660/17 = around 38.823529</output>
<result>C</result> | C | 39 | A car drives 90 miles on local roads at 30 mph, and 75 miles on the highway at 60 mph, what is the average speed of the entire trip? | {
"A": "36 mph",
"B": "40 mph",
"C": "39 mph",
"D": "42 mph",
"E": "38 mph"
} | divide(add(90, 75), add(divide(90, 30), divide(75, 60))) | add(n0,n2)|divide(n0,n1)|divide(n2,n3)|add(#1,#2)|divide(#0,#3) | so the answer is plainly c . . . . we have a general relation for speed , time and distance : v ( velocity ) * t ( time ) = d ( distance ) for first part we have d = 90 miles , and v = 30 mph so we can obtain time : 30 * t = 90 or t = 90 / 30 = 3 hours the needed time to cover 90 miles in the same way we should divide 75 to 60 to find the needed time to cover 75 miles , so t = 1.25 hours so the total time for covering total distance would be 3 + 1.25 = 4.25 hours and total distance is 90 + 75 = 165 miles final stage : average speed is total distance divide to total time : 165 / 4.25 = 38.8 miles per hour rounded up to 39 mph . . . . | physics |
math_qa__2PlZMxTnQMuqouxz | In a mixture of 45 litres the ratio of milk to water is 4:1. Additional 18 litres of water is added to the mixture. Find the ratio of milk to water in the resulting mixture. Choose the correct choice from the following answers: A) 2 / 1 B) 4 / 3 C) 2 / 3 D) 3 / 4 E) 3 / 2 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">45 / 5</gadget>
<output>9</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">9 + 18</gadget>
<output>27</output>
<gadget id="calculator">36 / 27</gadget>
<output>4/3 = around 1.333333</output>
<result>B</result> | B | 1.333333 | In a mixture of 45 litres the ratio of milk to water is 4:1. Additional 18 litres of water is added to the mixture. Find the ratio of milk to water in the resulting mixture. | {
"A": "2 / 1",
"B": "4 / 3",
"C": "2 / 3",
"D": "3 / 4",
"E": "3 / 2"
} | divide(subtract(45, divide(45, add(4, 1))), add(divide(45, add(4, 1)), 18)) | add(n1,n2)|divide(n0,#0)|add(n3,#1)|subtract(n0,#1)|divide(#3,#2) | given that milk / water = 4 x / x and 4 x + x = 45 - - > x = 9 . thus milk = 4 x = 36 liters and water = x = 9 liters . new ratio = 36 / ( 9 + 18 ) = 36 / 27 = 4 / 3 . answer : b . | general |
math_qa__k6PwcbelZEkEA5WP | John left home and drove at the rate of 55 mph for 2 hours. He stopped for lunch then drove for another 3 hours at the rate of 55 mph to reach his destination. How many miles did John drive? Choose the correct option
A) 235 miles . B) 245 miles . C) 255 miles . D) 265 miles . E) 275 miles . | <gadget id="calculator">55 * 2</gadget>
<output>110</output>
<gadget id="calculator">3 * 55</gadget>
<output>165</output>
<gadget id="calculator">110 + 165</gadget>
<output>275</output>
<result>E</result> | E | 275 | John left home and drove at the rate of 55 mph for 2 hours. He stopped for lunch then drove for another 3 hours at the rate of 55 mph to reach his destination. How many miles did John drive? | {
"A": "235 miles .",
"B": "245 miles .",
"C": "255 miles .",
"D": "265 miles .",
"E": "275 miles ."
} | add(multiply(55, 2), multiply(3, 55)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)| | "the total distance d traveled by john is given by d = 55 * 2 + 3 * 55 = 275 miles . answer e" | physics |
math_qa__ezlZcOqGBCQoa801 | A circular well with a diameter of 4 metres , is dug to a depth of 14 metres. What is the volume of the earth dug out? Choose the correct choice from the following answers: A) 32 m 3 B) 36 m 3 C) 40 m 3 D) 44 m 3 E) 176 m 3 | <gadget id="calculator">4 / 2</gadget>
<output>2</output>
<gadget id="calculator">pi * (2 ** 2) * 14</gadget>
<output>56*pi = around 175.929189</output>
<result>E</result> | E | 176 | A circular well with a diameter of 4 metres , is dug to a depth of 14 metres. What is the volume of the earth dug out? | {
"A": "32 m 3",
"B": "36 m 3",
"C": "40 m 3",
"D": "44 m 3",
"E": "176 m 3"
} | volume_cylinder(divide(4, const_2), 14) | divide(n0,const_2)|volume_cylinder(#0,n1)| | "solution volume = π r 2 h ‹ = › ( 22 / 7 × 2 × 2 × 14 ) m 3 ‹ = › 176 m 3 . answer e" | geometry |
math_qa__GaiUWiW4hQNXigMU | A man cycling along the road noticed that every 6 minutes a bus overtakes him and every 2 minutes he meets an oncoming bus. If all buses and the cyclist move at a constant speed, what is the time interval between consecutive buses?
Choose one: A) 3 minutes B) 6 minutes C) 8 minutes D) 9 minutes E) 10 minutes | <gadget id="calculator">2 + 6</gadget>
<output>8</output>
<gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">8 / 4</gadget>
<output>2</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">3 / 1</gadget>
<output>3</output>
<result>A</result> | A | 3 | A man cycling along the road noticed that every 6 minutes a bus overtakes him and every 2 minutes he meets an oncoming bus. If all buses and the cyclist move at a constant speed, what is the time interval between consecutive buses? | {
"A": "3 minutes",
"B": "6 minutes",
"C": "8 minutes",
"D": "9 minutes",
"E": "10 minutes"
} | divide(subtract(6, divide(6, divide(add(2, 6), subtract(6, 2)))), const_1) | add(n0,n1)|subtract(n0,n1)|divide(#0,#1)|divide(n0,#2)|subtract(n0,#3)|divide(#4,const_1)| | "let ' s say the distance between the buses is d . we want to determine interval = \ frac { d } { b } , where b is the speed of bus . let the speed of cyclist be c . every 6 minutes a bus overtakes cyclist : \ frac { d } { b - c } = 6 , d = 6 b - 6 c ; every 2 minutes cyclist meets an oncoming bus : \ frac { d } { b + c } = 2 , d = 2 b + 2 c ; d = 6 b - 6 c = 2 b + 2 c , - - > b = 2 c , - - > d = 6 b - 3 b = 3 b . interval = \ frac { d } { b } = \ frac { 3 b } { b } = 3 answer : a ( 3 minutes ) ." | physics |
math_qa__qn3AgZ29SKJYvC6t | What is the area of a square field whose diagonal of length 30 m? Choose the correct answer
A) 287
B) 269
C) 450
D) 200
E) 230 | <gadget id="calculator">30 ** 2</gadget>
<output>900</output>
<gadget id="calculator">900 / 2</gadget>
<output>450</output>
<result>C</result> | C | 450 | What is the area of a square field whose diagonal of length 30 m? | {
"A": "287",
"B": "269",
"C": "450",
"D": "200",
"E": "230"
} | divide(square_area(30), const_2) | square_area(n0)|divide(#0,const_2)| | "d 2 / 2 = ( 30 * 30 ) / 2 = 450 answer : c" | geometry |
math_qa__bfVnGorUYxR03CuM | What is the least number should be added to 1056, so the sum of the number is completely divisible by 25?
Answers.
A) 19 B) 20 C) 32 D) 41 E) 53 | <gadget id="calculator">1_056 / 25</gadget>
<output>1_056/25 = around 42.24</output>
<gadget id="calculator">floor(1_056/25)</gadget>
<output>42</output>
<gadget id="calculator">42 + 1</gadget>
<output>43</output>
<gadget id="calculator">43 * 25</gadget>
<output>1_075</output>
<gadget id="calculator">1_075 - 1_056</gadget>
<output>19</output>
<result>A</result> | A | 19 | What is the least number should be added to 1056, so the sum of the number is completely divisible by 25? | {
"A": "19",
"B": "20",
"C": "32",
"D": "41",
"E": "53"
} | subtract(multiply(add(floor(divide(1056, 25)), const_1), 25), 1056) | divide(n0,n1)|floor(#0)|add(#1,const_1)|multiply(n1,#2)|subtract(#3,n0)| | "( 1056 / 25 ) gives remainder 6 19 + 6 = 23 , so we need to add 19 a" | general |
math_qa__XiT5eEhZjRc33P9d | A rectangular grassy plot 110 m. by 65 m has a gravel path 2.5 m wide all round it on the inside. Find the cost of gravelling the path at 50 paise per sq. metre Choose one: A) s 425 B) s 780 C) s 880 D) s 480 E) s 980 | <gadget id="calculator">110 * 65</gadget>
<output>7_150</output>
<gadget id="calculator">2.5 * 2</gadget>
<output>5</output>
<gadget id="calculator">110 - 5</gadget>
<output>105</output>
<gadget id="calculator">65 - 5</gadget>
<output>60</output>
<gadget id="calculator">105 * 60</gadget>
<output>6_300</output>
<gadget id="calculator">7_150 - 6_300</gadget>
<output>850</output>
<gadget id="calculator">850 * 50</gadget>
<output>42_500</output>
<gadget id="calculator">42_500 / 100</gadget>
<output>425</output>
<result>A</result> | A | 425 | A rectangular grassy plot 110 m. by 65 m has a gravel path 2.5 m wide all round it on the inside. Find the cost of gravelling the path at 50 paise per sq. metre | {
"A": "s 425",
"B": "s 780",
"C": "s 880",
"D": "s 480",
"E": "s 980"
} | divide(multiply(subtract(multiply(110, 65), multiply(subtract(110, multiply(2.5, const_2)), subtract(65, multiply(2.5, const_2)))), 50), const_100) | multiply(n0,n1)|multiply(n2,const_2)|subtract(n0,#1)|subtract(n1,#1)|multiply(#2,#3)|subtract(#0,#4)|multiply(n3,#5)|divide(#6,const_100)| | "area of the plot = 110 m * 65 m = 7150 sq . m area of plot excluding gravel = 105 m * 60 m = 6300 sq . m area of gravel = 7150 sq . m - 6300 sq . m = 850 sq . m cost of building it = 850 sq . m * 50 = 42500 p in rs = 42500 / 100 = rs 425 answer : a" | physics |
math_qa__SmnjcyS63XuzyyPi | A man bought 40 shares of Rs. 60 at 7 discount, the rate of dividend being 1212%The rate of interest obtained is Choose the correct choice from the following:
A) 13.64 % B) 15.5 % C) 14 % D) 14.15 % E) 14.95 % | <gadget id="calculator">40 * 60</gadget>
<output>2_400</output>
<gadget id="calculator">1_212 / 100</gadget>
<output>303/25 = around 12.12</output>
<gadget id="calculator">2_400 * (303/25)</gadget>
<output>29_088</output>
<gadget id="calculator">60 - 7</gadget>
<output>53</output>
<gadget id="calculator">40 * 53</gadget>
<output>2_120</output>
<gadget id="calculator">29_088 / 2_120</gadget>
<output>3_636/265 = around 13.720755</output>
<result>D</result> | D | 14.15 | A man bought 40 shares of Rs. 60 at 7 discount, the rate of dividend being 1212%The rate of interest obtained is | {
"A": "13.64 %",
"B": "15.5 %",
"C": "14 %",
"D": "14.15 %",
"E": "14.95 %"
} | divide(multiply(multiply(40, 60), divide(1212, const_100)), multiply(40, subtract(60, 7))) | divide(n3,const_100)|multiply(n0,n1)|subtract(n1,n2)|multiply(#0,#1)|multiply(n0,#2)|divide(#3,#4)| | "explanation : face value of a share = rs . 60 he bought each share at rs . 60 - rs . 7 = rs . 53 number of shares = 40 dividend = 12 1 / 2 % = 25 / 2 % dividend per share = 60 × 25 / 2 × 100 = rs . 7.5 total dividend = ( 40 × 7.5 ) ie , he got a dividend of ( 40 × 7.5 ) for an investment of rs . ( 40 × 53 ) interest obtained = 40 × 7.5 × 100 / 40 × 53 = 14.15 % answer : option d" | gain |
math_qa__MjpwmEOI9wtQ7C2E | A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m^3) is:
Choose the correct choice from the following choices
A) 2130 B) 3620 C) 4512 D) 5620 E) 5120 | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">48 - 16</gadget>
<output>32</output>
<gadget id="calculator">36 - 16</gadget>
<output>20</output>
<gadget id="calculator">32 * 20 * 8</gadget>
<output>5_120</output>
<result>E</result> | E | 5,120 | A metallic sheet is of rectangular shape with dimensions 48 m x 36 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m^3) is: | {
"A": "2130",
"B": "3620",
"C": "4512",
"D": "5620",
"E": "5120"
} | volume_rectangular_prism(subtract(48, multiply(8, const_2)), subtract(36, multiply(8, const_2)), 8) | multiply(n2,const_2)|subtract(n0,#0)|subtract(n1,#0)|volume_rectangular_prism(n2,#1,#2)| | "clearly , l = ( 48 - 16 ) m = 32 m , b = ( 36 - 16 ) m = 20 m , h = 8 m . volume of the box = ( 32 x 20 x 8 ) m 3 = 5120 m ^ 3 . answer e" | geometry |
math_qa__hMZmfvDPsKBxpiwp | if 853845 bars of chocolate need to be placed in little boxes and each box can contain at most 9 bars of chocolate . how many bars of chocolate will be in the last unfilled box ? Choose the correct answer:
A) 1 B) 3 C) 5 D) 6 E) 7 | <gadget id="calculator">853_845 / 9</gadget>
<output>284_615/3 = around 94_871.666667</output>
<gadget id="calculator">floor(284_615/3)</gadget>
<output>94_871</output>
<gadget id="calculator">94_871 * 9</gadget>
<output>853_839</output>
<gadget id="calculator">853_845 - 853_839</gadget>
<output>6</output>
<result>D</result> | D | 6 | if 853845 bars of chocolate need to be placed in little boxes and each box can contain at most 9 bars of chocolate . how many bars of chocolate will be in the last unfilled box ? | {
"A": "1",
"B": "3",
"C": "5",
"D": "6",
"E": "7"
} | subtract(853845, multiply(floor(divide(853845, 9)), 9)) | divide(n0,n1)|floor(#0)|multiply(n1,#1)|subtract(n0,#2) | the number of bars of chocolate that can be placed in the little boxes of 9 bars is the first number that is divisible by 9 that occurs before 853845 . in order to divide the sum in 9 parts , the amount must be divisible by 9 divisibility rule of 9 : the sum of the digits must be divisible by 9 sum of digits of 853845 = 33 and 27 is divisible by 9 . hence , we need to remove 6 to this number for it to be divisible by 9 correct option : d | general |
math_qa__fXw8McinPah9AQo6 | The length of a bridge in meters, which a train 110-meters long and traveling at 45 km/hr can cross in 30 seconds is? Answers.
A) 245 B) 265 C) 295 D) 325 E) 375 | <gadget id="calculator">45 * 1_000</gadget>
<output>45_000</output>
<gadget id="calculator">45_000 / 3_600</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 30</gadget>
<output>375</output>
<gadget id="calculator">375 - 110</gadget>
<output>265</output>
<result>B</result> | B | 265 | The length of a bridge in meters, which a train 110-meters long and traveling at 45 km/hr can cross in 30 seconds is? | {
"A": "245",
"B": "265",
"C": "295",
"D": "325",
"E": "375"
} | subtract(multiply(divide(multiply(45, const_1000), const_3600), 30), 110) | multiply(n1,const_1000)|divide(#0,const_3600)|multiply(n2,#1)|subtract(#2,n0)| | "45 km / h = 45000 m / 3600 s = 12.5 m / s in 30 seconds , the train can go 30 ( 12.5 ) = 375 meters let x be the length of the bridge . x + 110 = 375 meters x = 265 meters the answer is b ." | physics |
math_qa__KwxS2YIvjyWFeBAG | Income and expenditure of a person are in the ratio 9 : 8. If the income of the person is Rs. 36000, then find his savings? Choose the correct choice from the following.
A) 2000 B) 3000 C) 4000 D) 5000 E) 6000 | <gadget id="calculator">8 / 9</gadget>
<output>8/9 = around 0.888889</output>
<gadget id="calculator">(8/9) * 36_000</gadget>
<output>32_000</output>
<gadget id="calculator">36_000 - 32_000</gadget>
<output>4_000</output>
<result>C</result> | C | 4,000 | Income and expenditure of a person are in the ratio 9 : 8. If the income of the person is Rs. 36000, then find his savings? | {
"A": "2000",
"B": "3000",
"C": "4000",
"D": "5000",
"E": "6000"
} | subtract(36000, multiply(divide(8, 9), 36000)) | divide(n1,n0)|multiply(n2,#0)|subtract(n2,#1)| | "let the income and the expenditure of the person be rs . 9 x and rs . 7 x respectively . income , 9 x = 36000 = > x = 4000 savings = income - expenditure = 9 x - 8 x = x so , savings = rs . 4000 . answer : c" | other |
math_qa__kcrhMnQiCuoFgzAE | Light glows for every 16 seconds . How many times did it between 1:57:58 and 3:20:47 am Choose the correct choice from the following answers:
A) 311
B) 322
C) 313
D) 314
E) 385 | <gadget id="calculator">2 + 47</gadget>
<output>49</output>
<gadget id="calculator">2 + 60</gadget>
<output>62</output>
<gadget id="calculator">20 + 62</gadget>
<output>82</output>
<gadget id="calculator">82 * 60</gadget>
<output>4_920</output>
<gadget id="calculator">49 + 4_920</gadget>
<output>4_969</output>
<gadget id="calculator">4_969 / 16</gadget>
<output>4_969/16 = around 310.5625</output>
<result>A</result> | A | 311 | Light glows for every 16 seconds . How many times did it between 1:57:58 and 3:20:47 am | {
"A": "311",
"B": "322",
"C": "313",
"D": "314",
"E": "385"
} | divide(add(add(const_2, 47), multiply(add(20, add(const_2, const_60)), const_60)), 16) | add(n6,const_2)|add(const_2,const_60)|add(n5,#1)|multiply(#2,const_60)|add(#0,#3)|divide(#4,n0)| | "the diff in sec between 1 : 57 : 58 and 3 : 20 : 47 is 4969 sec , 4969 / 16 = 310 . so total 311 times light ll glow answer : a" | physics |
math_qa__Nl8Y63V6rKjgJEYi | A class is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the class room ? Pick one:
A) 115 B) 117 C) 116 D) 114 E) 112 | <gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 + 24</gadget>
<output>624</output>
<gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">400 + 32</gadget>
<output>432</output>
<gadget id="calculator">624 * 432</gadget>
<output>269_568</output>
<gadget id="calculator">24 + 24</gadget>
<output>48</output>
<gadget id="calculator">48 * 48</gadget>
<output>2_304</output>
<gadget id="calculator">269_568 / 2_304</gadget>
<output>117</output>
<result>B</result> | B | 117 | A class is 6 meters 24 centimeters in length and 4 meters 32 centimeters in width. Find the least number of square tiles of equal size required to cover the entire floor of the class room ? | {
"A": "115",
"B": "117",
"C": "116",
"D": "114",
"E": "112"
} | divide(multiply(add(multiply(6, const_100), 24), add(multiply(4, const_100), 32)), multiply(add(24, 24), add(24, 24))) | add(n1,n1)|multiply(n0,const_100)|multiply(n2,const_100)|add(n1,#1)|add(n3,#2)|multiply(#0,#0)|multiply(#3,#4)|divide(#6,#5) | explanation : length = 6 m 24 cm = 624 cm width = 4 m 32 cm = 432 cm hcf of 624 and 432 = 48 number of square tiles required = ( 624 x 432 ) / ( 48 x 48 ) = 13 x 9 = 117 . answer is b | general |
math_qa__ojAX1YOmECNelEId | mixture contains alcohol and water in the ratio 4 : 3. If 4 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture. Options.
A) 20
B) 99
C) 27
D) 22
E) 29 | <gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">16 - 12</gadget>
<output>4</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<gadget id="calculator">5 * 4</gadget>
<output>20</output>
<result>A</result> | A | 20 | mixture contains alcohol and water in the ratio 4 : 3. If 4 liters of water is added to the mixture, the ratio becomes 4: 5. Find the quantity of alcohol in the given mixture. | {
"A": "20",
"B": "99",
"C": "27",
"D": "22",
"E": "29"
} | multiply(divide(multiply(4, 5), subtract(multiply(4, 4), multiply(3, 4))), 4) | multiply(n0,n4)|multiply(n0,n2)|multiply(n0,n1)|subtract(#1,#2)|divide(#0,#3)|multiply(n0,#4)| | "let the quantity of alcohol and water be 4 x litres and 3 x litres respectively 16 x = 4 ( 3 x + 5 ) 4 x = 20 x = 5 quantity of alcohol = ( 4 x 5 ) litres = 20 litres . answer : a" | general |
math_qa__GMoTJrfFDuJstCqp | The sum of the fourth and twelfth term of an arithmetic progression is 20. What is the sum of the first 12 terms of the arithmetic progression? Choose the correct choice from the following choices
A) 300 B) 120 C) 150 D) 170 E) 270 | <gadget id="calculator">20 * 12</gadget>
<output>240</output>
<gadget id="calculator">240 / 2</gadget>
<output>120</output>
<result>B</result> | B | 120 | The sum of the fourth and twelfth term of an arithmetic progression is 20. What is the sum of the first 12 terms of the arithmetic progression? | {
"A": "300",
"B": "120",
"C": "150",
"D": "170",
"E": "270"
} | divide(multiply(20, 12), const_2) | multiply(n0,n1)|divide(#0,const_2)| | "n th term of a . p . is given by a + ( n - 1 ) d 4 th term = a + 3 d 12 th term = a + 11 d given a + 3 d + a + 11 d = 20 - - > 2 a + 14 d = 20 - - > a + 7 d = 10 sum of n term of a . p = n / 2 [ 2 a + ( n - 1 ) d ] subsitiuing n = 12 . . . we get 12 / 2 [ 2 a + 14 d ] = 15 [ a + 7 d ] = 12 * 10 = 120 . . . answer is b . . ." | general |
math_qa__xnKWc1ulKNswmpet | If the speed of a man is 54 km per hour, then what is the distance traveled by him in 25 seconds ? Choices:
A) 275 m
B) 360 m
C) 375 m
D) 420 m
E) 440 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">54 * (5/18)</gadget>
<output>15</output>
<gadget id="calculator">15 * 25</gadget>
<output>375</output>
<result>C</result> | C | 375 | If the speed of a man is 54 km per hour, then what is the distance traveled by him in 25 seconds ? | {
"A": "275 m",
"B": "360 m",
"C": "375 m",
"D": "420 m",
"E": "440 m"
} | multiply(multiply(54, const_0_2778), 25) | multiply(n0,const_0_2778)|multiply(n1,#0) | the distance traveled in 25 sec = 54 * ( 5 / 18 ) * 25 = 375 m answer : c | physics |
math_qa__bCfsqTxcWtJBXvoH | Soja finished 2/3 of a book. She calculated that she finished 100 more pages than she has yet to read. How long is her book? Options
A) 300 B) 150 C) 130 D) 90 E) 210 | <gadget id="calculator">100 * 3</gadget>
<output>300</output>
<result>A</result> | A | 300 | Soja finished 2/3 of a book. She calculated that she finished 100 more pages than she has yet to read. How long is her book? | {
"A": "300",
"B": "150",
"C": "130",
"D": "90",
"E": "210"
} | multiply(100, 3) | multiply(n1,n2) | let x be the total number of pages in the book , then she finished 2 / 3 * x pages . then she has x − 2 / 3 * x = 1 / 3 * x pages left . 2 / 3 * x − 1 / 3 * x = 100 1 / 3 * x = 100 x = 300 so the book is 300 pages long . answer is a . | general |
math_qa__cUEVG7wahJuY7q2f | The average score of a cricketer in 10 matches is 60 and in other 15 matches is 70. Then find the average score in all the 25 matches? Select the correct option: A) 50 B) 48 C) 65 D) 66 E) 72 | <gadget id="calculator">10 * 60</gadget>
<output>600</output>
<gadget id="calculator">15 * 70</gadget>
<output>1_050</output>
<gadget id="calculator">600 + 1_050</gadget>
<output>1_650</output>
<gadget id="calculator">1_650 / 25</gadget>
<output>66</output>
<result>D</result> | D | 66 | The average score of a cricketer in 10 matches is 60 and in other 15 matches is 70. Then find the average score in all the 25 matches? | {
"A": "50",
"B": "48",
"C": "65",
"D": "66",
"E": "72"
} | divide(add(multiply(10, 60), multiply(15, 70)), 25) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)|divide(#2,n4)| | "average in 25 matches = ( 10 * 60 + 15 * 70 ) / 10 + 15 = 66 answer is d" | general |
math_qa__3YKZecWdRvQ8IXnE | One-third less than 30% of 180 is equal to:
Choose the correct choice from the following answers.
A) 15
B) 30
C) 36
D) 40
E) 45 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 180</gadget>
<output>54</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 54</gadget>
<output>18</output>
<gadget id="calculator">54 - 18</gadget>
<output>36</output>
<result>C</result> | C | 36 | One-third less than 30% of 180 is equal to: | {
"A": "15",
"B": "30",
"C": "36",
"D": "40",
"E": "45"
} | subtract(multiply(divide(30, const_100), 180), multiply(divide(const_1, const_3), multiply(divide(30, const_100), 180))) | divide(n0,const_100)|divide(const_1,const_3)|multiply(n1,#0)|multiply(#1,#2)|subtract(#2,#3)| | "lots of ways to tackle this . 30 % of 180 = 54 1 / 3 of 45 = 18 so , 1 / 3 less than 54 is equal to 54 - 18 = 36 answer : c" | general |
math_qa__mqmCuW28wgJciDss | The average of marks obtained by 120 boys was 35. If the average of marks of passed boys was 39 and that of failed boys was 15, the number of boys who passed the examination is? Choose the correct option: A) 100 B) 110 C) 120 D) 130 E) 140 | <gadget id="calculator">35 * 120</gadget>
<output>4_200</output>
<gadget id="calculator">120 * 15</gadget>
<output>1_800</output>
<gadget id="calculator">4_200 - 1_800</gadget>
<output>2_400</output>
<gadget id="calculator">39 - 15</gadget>
<output>24</output>
<gadget id="calculator">2_400 / 24</gadget>
<output>100</output>
<result>A</result> | A | 100 | The average of marks obtained by 120 boys was 35. If the average of marks of passed boys was 39 and that of failed boys was 15, the number of boys who passed the examination is? | {
"A": "100",
"B": "110",
"C": "120",
"D": "130",
"E": "140"
} | divide(subtract(multiply(35, 120), multiply(120, 15)), subtract(39, 15)) | multiply(n0,n1)|multiply(n0,n3)|subtract(n2,n3)|subtract(#0,#1)|divide(#3,#2)| | "let the number of boys who passed = x . then , 39 x x + 15 x ( 120 - x ) = 120 x 35 24 x = 4200 - 1800 = > x = 2400 / 24 x = 100 . hence , the number of boys passed = 100 . answer : a" | general |
math_qa__WGhX8ZMULF0MVEJQ | A whale goes on a feeding frenzy that lasts for 5 hours. For the first hour he catches and eats x kilos of plankton. In every hour after the first, it consumes 3 kilos of plankton more than it consumed in the previous hour. If by the end of the frenzy the whale will have consumed a whopping accumulated total 450 kilos of plankton, how many kilos did he consume on the third hour? Choose the correct choice from the following options: A) 38 B) 47 C) 50 D) 53 E) 93 | <gadget id="calculator">450 / 5</gadget>
<output>90</output>
<gadget id="calculator">90 + 3</gadget>
<output>93</output>
<result>E</result> | E | 93 | A whale goes on a feeding frenzy that lasts for 5 hours. For the first hour he catches and eats x kilos of plankton. In every hour after the first, it consumes 3 kilos of plankton more than it consumed in the previous hour. If by the end of the frenzy the whale will have consumed a whopping accumulated total 450 kilos of plankton, how many kilos did he consume on the third hour? | {
"A": "38",
"B": "47",
"C": "50",
"D": "53",
"E": "93"
} | add(divide(450, 5), 3) | divide(n2,n0)|add(n1,#0)| | "if you list the amount eaten each hour , you ' ll get an equally spaced list , increasing by 3 each hour . in any equally spaced list , the median equals the mean . here , the mean is 450 / 5 = 90 , so the median is also 90 , and that is the amount eaten in the 2 nd hour . we need to add 3 to find the total eaten in the next hour , so the answer is 93 option e" | general |
math_qa__UcUyDs083RWQCZwf | If 5 spiders make 5 webs in 5 days, then 1 spider will make 1 web in how many days? Choose the most appropriate option:
A) 7
B) 6
C) 5
D) 4
E) 3 | <gadget id="calculator">1 * 5</gadget>
<output>5</output>
<result>C</result> | C | 5 | If 5 spiders make 5 webs in 5 days, then 1 spider will make 1 web in how many days? | {
"A": "7",
"B": "6",
"C": "5",
"D": "4",
"E": "3"
} | multiply(1, 5) | multiply(n0,n3)| | "let the required number days be x . less spiders , more days ( indirect proportion ) less webs , less days ( direct proportion ) spiders 1 : 5 webs 5 : 1 1 x 5 x x = 5 x 1 x 5 = > x = 5 answer is c" | physics |
math_qa__qtgb7CTSd7zJM0Fo | 10 camels cost as much as 24 horses, 16 horses cost as much as 4 oxen and 6 oxen as much as 4 elephants. If the cost of 10 elephants is Rs.150000, find the cost of a camel? Choices: A) s . 9800 B) s . 3800 C) s . 9800 D) s . 6000 E) s . 6880 | <gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">96 * 4</gadget>
<output>384</output>
<gadget id="calculator">384 * 150_000</gadget>
<output>57_600_000</output>
<gadget id="calculator">10 * 16</gadget>
<output>160</output>
<gadget id="calculator">160 * 6</gadget>
<output>960</output>
<gadget id="calculator">960 * 10</gadget>
<output>9_600</output>
<gadget id="calculator">57_600_000 / 9_600</gadget>
<output>6_000</output>
<result>D</result> | D | 6,000 | 10 camels cost as much as 24 horses, 16 horses cost as much as 4 oxen and 6 oxen as much as 4 elephants. If the cost of 10 elephants is Rs.150000, find the cost of a camel? | {
"A": "s . 9800",
"B": "s . 3800",
"C": "s . 9800",
"D": "s . 6000",
"E": "s . 6880"
} | divide(multiply(multiply(multiply(24, 4), 4), 150000), multiply(multiply(multiply(10, 16), 6), 10)) | multiply(n1,n3)|multiply(n0,n2)|multiply(n3,#0)|multiply(n4,#1)|multiply(n7,#2)|multiply(n0,#3)|divide(#4,#5)| | "cost of the camel = p 10 camels = 24 horses 16 horses = 4 oxen 6 oxen = 4 elephants 10 elephants = rs . 150000 p = rs . [ ( 24 * 4 * 4 * 150000 ) / ( 10 * 16 * 6 * 10 ) ] p = rs . ( 57600000 / 9600 ) = > p = rs . 6000 answer : d" | general |
math_qa__XF9CwJKEsW4euNjZ | A candidate got 31% of the votes polled and he lost to his rival by 2451 votes. How many votes were cast?
Choose the correct answer:
A) 6150 B) 6250 C) 6350 D) 6450 E) 6550 | <gadget id="calculator">31 / 100</gadget>
<output>31/100 = around 0.31</output>
<gadget id="calculator">1 - (31/100)</gadget>
<output>69/100 = around 0.69</output>
<gadget id="calculator">(69/100) - (31/100)</gadget>
<output>19/50 = around 0.38</output>
<gadget id="calculator">2_451 / (19/50)</gadget>
<output>6_450</output>
<result>D</result> | D | 6,450 | A candidate got 31% of the votes polled and he lost to his rival by 2451 votes. How many votes were cast? | {
"A": "6150",
"B": "6250",
"C": "6350",
"D": "6450",
"E": "6550"
} | divide(2451, subtract(subtract(const_1, divide(31, const_100)), divide(31, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|subtract(#1,#0)|divide(n1,#2)| | "let x be the total number of votes . 0.31 x + 2451 = 0.69 x 0.38 x = 2451 x = 2451 / 0.38 = 6450 the answer is d ." | gain |
math_qa__SgSPVe2hvoe7IhnV | An inspector rejects 10% of the meters as defective. How many will he examine to reject 10? Choices: A) 100 B) 120 C) 250 D) 200 E) 160 | <gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 / 10</gadget>
<output>100</output>
<result>A</result> | A | 100 | An inspector rejects 10% of the meters as defective. How many will he examine to reject 10? | {
"A": "100",
"B": "120",
"C": "250",
"D": "200",
"E": "160"
} | divide(multiply(10, const_100), 10) | multiply(n1,const_100)|divide(#0,n0)| | "then , 10 % of x = 10 ( 10 / 100 ) x = 10 x = ( 10 * 100 * ) / 10 = 100 answer is a" | gain |
math_qa__upjHdq4RMiCcJftV | The mean of 50 observations was 36. It was found later that an observation 29 was wrongly taken as 23. The corrected new mean is : Choose the correct choice from the following answers.
A) 36.1
B) 36.5
C) 36.22
D) 36.12
E) 36.18 | <gadget id="calculator">36 * 50</gadget>
<output>1_800</output>
<gadget id="calculator">50 - 2</gadget>
<output>48</output>
<gadget id="calculator">48 - 23</gadget>
<output>25</output>
<gadget id="calculator">1_800 + 25</gadget>
<output>1_825</output>
<gadget id="calculator">1_825 / 50</gadget>
<output>73/2 = around 36.5</output>
<result>D</result> | D | 36.12 | The mean of 50 observations was 36. It was found later that an observation 29 was wrongly taken as 23. The corrected new mean is : | {
"A": "36.1",
"B": "36.5",
"C": "36.22",
"D": "36.12",
"E": "36.18"
} | divide(add(multiply(36, 50), subtract(subtract(50, const_2), 23)), 50) | multiply(n0,n1)|subtract(n0,const_2)|subtract(#1,n3)|add(#0,#2)|divide(#3,n0)| | "explanation : correct sum = ( 36 * 50 + 29 - 23 ) = 1806 . correct mean = = 1806 / 50 = 36.12 answer : d ) 36.12" | general |
math_qa__3bQJGxUxSH0iV88O | Shawn invested one half of his savings in a bond that paid simple interest for 2 years and received $550 as interest. He invested the remaining in a bond that paid compound interest, interest being compounded annually, for the same 2 years at the same rate of interest and received $605 as interest. What was the value of his total savings before investing in these two bonds?
Choose the correct choice from the following.
A) $ 2,750 B) $ 5,500 C) $ 11,000 D) $ 22,000 E) $ 44,000 | <gadget id="calculator">550 / 2</gadget>
<output>275</output>
<gadget id="calculator">275 * 275</gadget>
<output>75_625</output>
<gadget id="calculator">605 - 550</gadget>
<output>55</output>
<gadget id="calculator">75_625 / 55</gadget>
<output>1_375</output>
<gadget id="calculator">1_375 * 2</gadget>
<output>2_750</output>
<result>A</result> | A | 2,750 | Shawn invested one half of his savings in a bond that paid simple interest for 2 years and received $550 as interest. He invested the remaining in a bond that paid compound interest, interest being compounded annually, for the same 2 years at the same rate of interest and received $605 as interest. What was the value of his total savings before investing in these two bonds? | {
"A": "$ 2,750",
"B": "$ 5,500",
"C": "$ 11,000",
"D": "$ 22,000",
"E": "$ 44,000"
} | multiply(divide(multiply(divide(550, 2), divide(550, 2)), subtract(605, 550)), 2) | divide(n1,n0)|subtract(n3,n1)|multiply(#0,#0)|divide(#2,#1)|multiply(n0,#3)| | "si for 1 st year = 550 / 2 = 275 275 + 275 + si on ( 275 ) = 605 = = > si on 275 = 55 = = > si on 275 = 275 * r * 1 / 100 = 55 r = 20 % now using si for 2 years on t / 2 of the money ( t / 2 ) * 20 * 2 / 100 = 550 t = 550 * 5 = 2750 answer : a" | gain |
math_qa__DN34xwVOnMujaxVc | 7 people average age is 30. youngest person age is 3. find average of the people when youngest was born. Choose the correct choice from the following options:
A) 23 B) 24 C) 25 D) 26 E) 27 | <gadget id="calculator">30 * 7</gadget>
<output>210</output>
<gadget id="calculator">3 * 7</gadget>
<output>21</output>
<gadget id="calculator">210 - 21</gadget>
<output>189</output>
<gadget id="calculator">189 / 7</gadget>
<output>27</output>
<result>E</result> | E | 27 | 7 people average age is 30. youngest person age is 3. find average of the people when youngest was born. | {
"A": "23",
"B": "24",
"C": "25",
"D": "26",
"E": "27"
} | divide(subtract(multiply(30, 7), multiply(3, 7)), 7) | multiply(n0,n1)|multiply(n0,n2)|subtract(#0,#1)|divide(#2,n0)| | "average age of people = 30 so have total age = 210 before 7 years we have to deduct each person age by seven years 210 - 21 = 189 so average age would be 189 / 7 = 27 answer : e" | general |
math_qa__YjoduUqmleXn8mru | What is value of ((2^5)*(9^2))/((8^2)*(3^5))=? Choose the correct choice
A) 1 / 6
B) 1 / 3
C) 2 / 3
D) 1 / 4
E) 4 | <gadget id="calculator">2 ** 5</gadget>
<output>32</output>
<gadget id="calculator">9 ** 2</gadget>
<output>81</output>
<gadget id="calculator">32 * 81</gadget>
<output>2_592</output>
<gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">3 ** 5</gadget>
<output>243</output>
<gadget id="calculator">64 * 243</gadget>
<output>15_552</output>
<gadget id="calculator">2_592 / 15_552</gadget>
<output>1/6 = around 0.166667</output>
<result>A</result> | A | 0.166667 | What is value of ((2^5)*(9^2))/((8^2)*(3^5))=? | {
"A": "1 / 6",
"B": "1 / 3",
"C": "2 / 3",
"D": "1 / 4",
"E": "4"
} | divide(multiply(power(2, 5), power(9, 2)), multiply(power(8, 2), power(3, 5))) | power(n0,n1)|power(n2,n0)|power(n4,n0)|power(n6,n1)|multiply(#0,#1)|multiply(#2,#3)|divide(#4,#5) | = > ( ( 2 ^ 5 ) * ( ( 3 ^ 2 ) ^ 2 ) / ( ( 2 ^ 3 ) ^ 2 ) * ( 3 ^ 5 ) ) = > ( ( 2 ^ 5 ) * ( 3 ^ 4 ) ) / ( ( 2 ^ 6 ) * ( 3 ^ 5 ) ) = > 1 / ( 2 * 3 ) = > 1 / 6 option a is answer | general |
math_qa__iIyfOfjwcUgxZbTO | Two circular frames are kept one above the other. Frame X has a diameter of 16 cm and Frame Y has a diameter of 12 cm. What fraction of the surface of Frame X is not covered by Frame Y?
Select the correct option.
A) 3 / 5 B) 7 / 16 C) 12 / 16 D) 24 / 12 E) 2 / 3 | <gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">pi * (8 ** 2)</gadget>
<output>64*pi = around 201.06193</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">pi * (6 ** 2)</gadget>
<output>36*pi = around 113.097336</output>
<gadget id="calculator">(64*pi) - (36*pi)</gadget>
<output>28*pi = around 87.964594</output>
<gadget id="calculator">(28*pi) / (64*pi)</gadget>
<output>7/16 = around 0.4375</output>
<result>B</result> | B | 0.4375 | Two circular frames are kept one above the other. Frame X has a diameter of 16 cm and Frame Y has a diameter of 12 cm. What fraction of the surface of Frame X is not covered by Frame Y? | {
"A": "3 / 5",
"B": "7 / 16",
"C": "12 / 16",
"D": "24 / 12",
"E": "2 / 3"
} | divide(subtract(circle_area(divide(16, const_2)), circle_area(divide(12, const_2))), circle_area(divide(16, const_2))) | divide(n0,const_2)|divide(n1,const_2)|circle_area(#0)|circle_area(#1)|subtract(#2,#3)|divide(#4,#2) | the questions asks us to find the surface which is not covered by the frame y i . e . , area of the surface not covered . where as circumference is the length along the edge of the circle , 2 * pi * r implies the length of the curve pi * r ^ 2 implies area enclosed by that curve . . hence area of the circle is considered for this problem area of the frame y = pi * r ^ 2 , where r = 6 = > pi * 36 area of the frame x = pi * 64 surface not covered by the frame y = pi * 64 - pi * 36 = pi * 28 fraction of frame x ' s surface is not covered by a frame y = pi * 28 / total area of the frame x = 28 / 64 = 7 / 16 answer is b | geometry |
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