id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__TUl5Su2FitTAZur8 | a man owns 2/3 of market reserch beauro buzness,and sells 3/4 of his shares for 45000rs,what is the value of buzness? Select:
A) 150000 B) 90000 C) 85000 D) 190000 E) 250000 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(2/3) * (3/4)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">45_000 / (1/2)</gadget>
<output>90_000</output>
<result>B</result> | B | 90,000 | a man owns 2/3 of market reserch beauro buzness,and sells 3/4 of his shares for 45000rs,what is the value of buzness? | {
"A": "150000",
"B": "90000",
"C": "85000",
"D": "190000",
"E": "250000"
} | divide(45000, multiply(divide(2, 3), divide(3, 4))) | divide(n0,n1)|divide(n1,n3)|multiply(#0,#1)|divide(n4,#2)| | "if value of business = x total sell ( 2 x / 3 ) ( 3 / 4 ) = 45000 - > x = 150000 answer : b" | general |
math_qa__396BJVS0KCXLAHsp | In a certain company, the formula for maximizing profits is P = -25x^2 + 7500x,, where P is profit and x is the number of machines the company operates in its factory. What value for x will maximize P?
This one is from IntegratedLearning.
Here's what I did:
The OA states: To find a maximum or minimum value of an equation with an exponent in it, you take the derivative of the equation, set it to zero, and solve. I dont really get what that means. So whoever solves it, could you plz post explanation of what the above sentence mean as well?
Choose the correct choice: A) 10 B) 50 C) 150 D) 200 E) 300 | <gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">7_500 / 10</gadget>
<output>750</output>
<gadget id="calculator">750 / 5</gadget>
<output>150</output>
<result>C</result> | C | 150 | In a certain company, the formula for maximizing profits is P = -25x^2 + 7500x,, where P is profit and x is the number of machines the company operates in its factory. What value for x will maximize P?
This one is from IntegratedLearning.
Here's what I did:
The OA states: To find a maximum or minimum value of an equation with an exponent in it, you take the derivative of the equation, set it to zero, and solve. I dont really get what that means. So whoever solves it, could you plz post explanation of what the above sentence mean as well? | {
"A": "10",
"B": "50",
"C": "150",
"D": "200",
"E": "300"
} | divide(divide(7500, multiply(const_2, sqrt(25))), sqrt(25)) | sqrt(n0)|multiply(#0,const_2)|divide(n2,#1)|divide(#2,#0) | recognize that 25 is a factor of 7500 . if we take this out , we have two parts to the equation : - x ^ 2300 x one part of the equation brings our value down , whereas the other part brings our value up . at this point , we can test the numbers in the answer choice . notice that they are very straight forward to square , and multiplication by 300 is very easy . a ) 10 - 3000 - 100 = 2900 b ) 50 - 15000 - 2500 = 12500 c ) 150 - 45000 - 22500 = 22500 d ) 200 - 60000 - 40000 = 20000 e ) 300 - recognize that this is zero therefore , answer is 150 . hope this helps those - like myself - who have n ' t thought about calculus for over half a decade . c | general |
math_qa__WCepSM8bVf5YC6MM | What is the smallest number which when diminished by 18, is divisible 8, 14, 26 and 28? Pick
A) 746 B) 750 C) 789 D) 678 E) 897 | <gadget id="calculator">lcm(8, 14)</gadget>
<output>56</output>
<gadget id="calculator">lcm(26, 28)</gadget>
<output>364</output>
<gadget id="calculator">lcm(56, 364)</gadget>
<output>728</output>
<gadget id="calculator">728 + 18</gadget>
<output>746</output>
<result>A</result> | A | 746 | What is the smallest number which when diminished by 18, is divisible 8, 14, 26 and 28? | {
"A": "746",
"B": "750",
"C": "789",
"D": "678",
"E": "897"
} | add(lcm(lcm(8, 14), lcm(26, 28)), 18) | lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|add(n0,#2)| | "required number = ( lcm of 8 , 14 , 26 and 28 ) + 18 = 728 + 18 = 746 option a" | general |
math_qa__D6xyyqTIgYkoRRGu | In a mixture of 45 litres the ratio of milk to water is 4:1. Additional 11 litres of water is added to the mixture. Find the ratio of milk to water in the resulting mixture. Pick one.
A) 2 / 1 B) 4 / 1 C) 2 / 3 D) 9 / 5 E) 3 / 2 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">45 / 5</gadget>
<output>9</output>
<gadget id="calculator">45 - 9</gadget>
<output>36</output>
<gadget id="calculator">9 + 11</gadget>
<output>20</output>
<gadget id="calculator">36 / 20</gadget>
<output>9/5 = around 1.8</output>
<result>D</result> | D | 1.8 | In a mixture of 45 litres the ratio of milk to water is 4:1. Additional 11 litres of water is added to the mixture. Find the ratio of milk to water in the resulting mixture. | {
"A": "2 / 1",
"B": "4 / 1",
"C": "2 / 3",
"D": "9 / 5",
"E": "3 / 2"
} | divide(subtract(45, divide(45, add(4, 1))), add(divide(45, add(4, 1)), 11)) | add(n1,n2)|divide(n0,#0)|add(n3,#1)|subtract(n0,#1)|divide(#3,#2)| | "given that milk / water = 4 x / x and 4 x + x = 45 - - > x = 9 . thus milk = 4 x = 36 liters and water = x = 9 liters . new ratio = 36 / ( 9 + 11 ) = 36 / 20 = 9 / 5 . answer : d ." | general |
math_qa__OMkdnrlPAJC2eAp5 | ?% of 360 = 162
Select the correct option
A) 277 B) 36 C) 45 D) 72 E) none of these | <gadget id="calculator">162 * 100</gadget>
<output>16_200</output>
<gadget id="calculator">16_200 / 360</gadget>
<output>45</output>
<result>C</result> | C | 45 | ?% of 360 = 162 | {
"A": "277",
"B": "36",
"C": "45",
"D": "72",
"E": "none of these"
} | divide(multiply(162, const_100), 360) | multiply(n1,const_100)|divide(#0,n0)| | "? % of 360 = 162 or , ? = 162 × 100 / 360 = 45 answer c" | gain |
math_qa__p5j5EuwNl8gbw1TL | At an elementary school, 60% of the faculty members are women and 60% of the faculty members are married. If 3/4 of the men are single, what fraction of the men are married? Select:
A) 3 / 4
B) 2 / 5
C) 4 / 5
D) 2 / 3
E) 1 / 4 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<result>E</result> | E | 0.25 | At an elementary school, 60% of the faculty members are women and 60% of the faculty members are married. If 3/4 of the men are single, what fraction of the men are married? | {
"A": "3 / 4",
"B": "2 / 5",
"C": "4 / 5",
"D": "2 / 3",
"E": "1 / 4"
} | subtract(const_1, divide(3, 4)) | divide(n2,n3)|subtract(const_1,#0) | - - - - - - - - - - - - - - - - - - - - m - - - - - - w - - - - - - - - total marrried - - - - - - - - - 10 - - - - - 50 - - - - - - - - - 60 not married - - - - - 30 - - - - - 10 - - - - - - - - - 40 total - - - - - - - - - - - - - 40 - - - - - 60 - - - - - - - - 100 need married man / total man , so 10 / 40 = 1 / 4 e | gain |
math_qa__8OJUVxxKB6zrVEWw | P , Q, R enter into a partnership & their share are in the ratio 1/2 : 1/3 : 1/4 , after two months , P withdraws half of the capitals & after 10 months , a profit of Rs 378 is divided among them . What is R's share? Choose the correct choice from the following choices: A) 108 B) 120 C) 134 D) 144 E) none of these | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">378 * 6</gadget>
<output>2_268</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">2_268 / 21</gadget>
<output>108</output>
<result>A</result> | A | 108 | P , Q, R enter into a partnership & their share are in the ratio 1/2 : 1/3 : 1/4 , after two months , P withdraws half of the capitals & after 10 months , a profit of Rs 378 is divided among them . What is R's share? | {
"A": "108",
"B": "120",
"C": "134",
"D": "144",
"E": "none of these"
} | divide(multiply(378, multiply(3, 2)), multiply(add(4, 3), 3)) | add(n3,n5)|multiply(n1,n3)|multiply(n7,#1)|multiply(n3,#0)|divide(#2,#3) | explanation : the ratio of their initial investment = 1 / 2 : 1 / 3 : 1 / 4 = 6 : 4 : 3 let ' s take the initial investment of p , q and r as 6 x , 4 x and 3 x respectively a : b : c = ( 6 x * 2 + 3 x * 10 ) : 4 x * 12 : 3 x * 12 = ( 12 + 30 ) : 4 * 12 : 3 * 12 = ( 4 + 10 ) : 4 * 4 : 12 = 14 : 16 : 12 = 7 : 8 : 6 r ' s share = 378 * ( 6 / 21 ) = 108 . answer : option a | general |
math_qa__j4zUZe4k370MaofI | Light glows for every 18 seconds . How many times did it between 1:57:58 and 3:20:47 am Choose the most appropriate option: A) 281 B) 277 C) 283 D) 384 E) 385 | <gadget id="calculator">2 + 47</gadget>
<output>49</output>
<gadget id="calculator">2 + 60</gadget>
<output>62</output>
<gadget id="calculator">20 + 62</gadget>
<output>82</output>
<gadget id="calculator">82 * 60</gadget>
<output>4_920</output>
<gadget id="calculator">49 + 4_920</gadget>
<output>4_969</output>
<gadget id="calculator">4_969 / 18</gadget>
<output>4_969/18 = around 276.055556</output>
<result>B</result> | B | 277 | Light glows for every 18 seconds . How many times did it between 1:57:58 and 3:20:47 am | {
"A": "281",
"B": "277",
"C": "283",
"D": "384",
"E": "385"
} | divide(add(add(const_2, 47), multiply(add(20, add(const_2, const_60)), const_60)), 18) | add(n6,const_2)|add(const_2,const_60)|add(n5,#1)|multiply(#2,const_60)|add(#0,#3)|divide(#4,n0)| | "the diff in sec between 1 : 57 : 58 and 3 : 20 : 47 is 4969 sec , 4969 / 18 = 276 . so total 277 times light ll glow answer : b" | physics |
math_qa__i7UNJldToWFU55Dh | find the smallest number which leaves 2235 , 48 and 61 as remainders when divided by 26 , 39 , 52 and 65 respectively . Choose the correct option: A) 67 B) 26 C) 99 D) 26 E) 91 | <gadget id="calculator">48 / 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 2</gadget>
<output>26</output>
<result>D</result> | D | 26 | find the smallest number which leaves 2235 , 48 and 61 as remainders when divided by 26 , 39 , 52 and 65 respectively . | {
"A": "67",
"B": "26",
"C": "99",
"D": "26",
"E": "91"
} | add(divide(48, const_2), const_2) | divide(n1,const_2)|add(#0,const_2) | answer : d | general |
math_qa__Psj1rxDkwn46kdZZ | If k^3 is divisible by 168, what is the least possible value of integer k? Choose the correct option.
A) 36 B) 42 C) 48 D) 54 E) 60 | <gadget id="calculator">168 / 2</gadget>
<output>84</output>
<gadget id="calculator">84 / 2</gadget>
<output>42</output>
<result>B</result> | B | 42 | If k^3 is divisible by 168, what is the least possible value of integer k? | {
"A": "36",
"B": "42",
"C": "48",
"D": "54",
"E": "60"
} | divide(divide(168, const_2), const_2) | divide(n1,const_2)|divide(#0,const_2) | k ^ 3 = 168 * x = 2 ^ 3 * 3 * 7 * x the factors of k must at minimum include 2 * 3 * 7 = 42 . the answer is b . | general |
math_qa__wDTNMcNptevpUTcS | A and B can do a work in 20days, B and C in 25days, C and A in 30days. If A,B and C work together , they will complete the work in?
Choose the most appropriate option: A) 10 days B) 12 days C) 16 days D) 20 days E) 25 days | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 / 25</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/20) + (1/25)</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">1 / 30</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">(9/100) + (1/30)</gadget>
<output>37/300 = around 0.123333</output>
<gadget id="calculator">(37/300) / 2</gadget>
<output>37/600 = around 0.061667</output>
<gadget id="calculator">1 / (37/600)</gadget>
<output>600/37 = around 16.216216</output>
<result>C</result> | C | 16 | A and B can do a work in 20days, B and C in 25days, C and A in 30days. If A,B and C work together , they will complete the work in? | {
"A": "10 days",
"B": "12 days",
"C": "16 days",
"D": "20 days",
"E": "25 days"
} | divide(const_1, divide(add(add(inverse(20), inverse(25)), inverse(30)), const_2)) | inverse(n0)|inverse(n1)|inverse(n2)|add(#0,#1)|add(#3,#2)|divide(#4,const_2)|divide(const_1,#5)| | "a + b 1 day work = 1 / 20 b + c 1 day work = 1 / 25 c + a 1 day work = 1 / 30 adding we get 2 ( a + b + c ) = 1 / 20 + 1 / 25 + 1 / 30 = 37 / 300 a + b + c 1 day work = 37 / 600 a , b , c can finish the work in 600 / 37 days = 16 days approximately answer is c" | physics |
math_qa__bcTJNUGXTXvimdl9 | In what time will a train 100 m long cross an electric pole, it its speed be 136 km/hr?
Options
A) 2.6 sec B) 1.9 sec C) 8.9 sec D) 6.9 sec E) 2.9 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">136 * (5/18)</gadget>
<output>340/9 = around 37.777778</output>
<gadget id="calculator">100 / (340/9)</gadget>
<output>45/17 = around 2.647059</output>
<result>A</result> | A | 2.6 | In what time will a train 100 m long cross an electric pole, it its speed be 136 km/hr? | {
"A": "2.6 sec",
"B": "1.9 sec",
"C": "8.9 sec",
"D": "6.9 sec",
"E": "2.9 sec"
} | divide(100, multiply(136, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 136 * 5 / 18 = 37.8 m / sec time taken = 100 / 37.8 = 2.6 sec . answer : a" | physics |
math_qa__7IE7WVfYYkRYsJ34 | The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 126° of the circle, what percentage of MegaTek employees are in manufacturing? Choose the correct answer
A) 20 % B) 25 % C) 30 % D) 35 % E) 70 % | <gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">126 / 360</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(7/20) * 100</gadget>
<output>35</output>
<result>D</result> | D | 35 | The MegaTek Corporation is displaying its distribution of employees by department in a circle graph. The size of each sector of the graph representing a department is proportional to the percentage of total employees in that department. If the section of the circle graph representing the manufacturing department takes up 126° of the circle, what percentage of MegaTek employees are in manufacturing? | {
"A": "20 %",
"B": "25 %",
"C": "30 %",
"D": "35 %",
"E": "70 %"
} | multiply(divide(126, divide(const_3600, const_10)), const_100) | divide(const_3600,const_10)|divide(n0,#0)|multiply(#1,const_100)| | answer : d 126 ° divided by 360 ° equals 0.35 , therefore the sector is equal to 35 % of the total | physics |
math_qa__IJd1UsvFhL85on9u | What is the unit digit in 14^100? Options.
A) 0 B) 5 C) 2 D) 3 E) 6 | <gadget id="calculator">14 ** 2</gadget>
<output>196</output>
<gadget id="calculator">196 % 10</gadget>
<output>6</output>
<result>E</result> | E | 6 | What is the unit digit in 14^100? | {
"A": "0",
"B": "5",
"C": "2",
"D": "3",
"E": "6"
} | reminder(power(14, const_2), const_10) | power(n0,const_2)|reminder(#0,const_10)| | unit digit in 14 ^ 100 = unit digit in [ ( 14 ^ 4 ) ^ 25 ] but unit digit in 14 ^ 4 = 6 unit digit 14 ^ 100 = 6 answer is e | general |
math_qa__HA9LAPNba32U7YGj | Tim came second in Math. When his mother asked him how much he had scored, he answered that he got the sum of the first 5 even numbers. His mother immediately worked out the answer. How much had he scored in Math? Choose the correct choice
A) 80
B) 30
C) 40
D) 70
E) 60 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<result>B</result> | B | 30 | Tim came second in Math. When his mother asked him how much he had scored, he answered that he got the sum of the first 5 even numbers. His mother immediately worked out the answer. How much had he scored in Math? | {
"A": "80",
"B": "30",
"C": "40",
"D": "70",
"E": "60"
} | multiply(add(5, const_1), 5) | add(n0,const_1)|multiply(n0,#0)| | "b 30 sum = ( n x n ) + n hence , 5 x 5 = 25 + 5 = 30" | physics |
math_qa__agJjnKugwZ3HrIN2 | The ratio of money with Ram and Gopal is 7 : 17 and that with Gopal and Krishan is 7: 17. If Ram has Rs. 735, Krishan has ?
Answers: A) s . 4335 B) s . 2330 C) s . 1190 D) s . 1620 E) s . 2680 | <gadget id="calculator">735 / 7</gadget>
<output>105</output>
<gadget id="calculator">105 * 17</gadget>
<output>1_785</output>
<gadget id="calculator">1_785 / 7</gadget>
<output>255</output>
<gadget id="calculator">255 * 17</gadget>
<output>4_335</output>
<result>A</result> | A | 4,335 | The ratio of money with Ram and Gopal is 7 : 17 and that with Gopal and Krishan is 7: 17. If Ram has Rs. 735, Krishan has ? | {
"A": "s . 4335",
"B": "s . 2330",
"C": "s . 1190",
"D": "s . 1620",
"E": "s . 2680"
} | multiply(divide(multiply(divide(735, 7), 17), 7), 17) | divide(n4,n0)|multiply(n1,#0)|divide(#1,n0)|multiply(n1,#2) | ram : gopal = 7 : 17 = 49 : 119 gopal : krishan = 7 : 17 = 119 : 289 ram : gopal : krishan = 49 : 119 : 289 ram : krishan = 49 : 289 thus , 49 : 289 = 735 : n & there n = 289 x 735 / 49 = rs . 4335 answer : a | other |
math_qa__CZ3Q6qDWhGmQjnqi | A train 146 m long is running at a speed of 98 kmph. How long does it take to pass a man who is running at 12 kmph in the same direction as the train?
Options: A) 6 sec B) 9 sec C) 12 sec D) 18 sec E) 15 sec | <gadget id="calculator">98 - 12</gadget>
<output>86</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">86 * (5/18)</gadget>
<output>215/9 = around 23.888889</output>
<gadget id="calculator">146 / (215/9)</gadget>
<output>1_314/215 = around 6.111628</output>
<result>A</result> | A | 6 | A train 146 m long is running at a speed of 98 kmph. How long does it take to pass a man who is running at 12 kmph in the same direction as the train? | {
"A": "6 sec",
"B": "9 sec",
"C": "12 sec",
"D": "18 sec",
"E": "15 sec"
} | divide(146, multiply(subtract(98, 12), const_0_2778)) | subtract(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "answer : a . speed of the train relative to man = ( 98 - 12 ) kmph = ( 86 * 5 / 18 ) m / sec = ( 215 / 9 ) m / sec time taken by the train to cross the man = time taken by it to cover 146 m at 219 / 9 m / sec = 146 * 9 / 219 sec = 6 sec" | physics |
math_qa__X8RNBtXH8ITfZLHU | Nails and screws are manufactured at a uniform weight per nail and a uniform weight per screw. If the total weight of one screw and one nail is half that of 6 screws and one nail, then the total weight of 3 screws, and 3 nails is how many times that of 5 screws and 1 nails? Options.
A) a . 4 B) b . 5 / 2 C) c . 2 D) d . 3 / 2 E) e . 5 / 4 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 3</gadget>
<output>15</output>
<gadget id="calculator">15 / 10</gadget>
<output>3/2 = around 1.5</output>
<result>D</result> | D | 1.5 | Nails and screws are manufactured at a uniform weight per nail and a uniform weight per screw. If the total weight of one screw and one nail is half that of 6 screws and one nail, then the total weight of 3 screws, and 3 nails is how many times that of 5 screws and 1 nails? | {
"A": "a . 4",
"B": "b . 5 / 2",
"C": "c . 2",
"D": "d . 3 / 2",
"E": "e . 5 / 4"
} | divide(add(multiply(3, const_4), 3), const_10) | multiply(n1,const_4)|add(n1,#0)|divide(#1,const_10) | let the weight of nail be n and that of screw be s . . so s + w = 1 / 2 * ( 6 s + 1 n ) . . . or 1 n = 4 s . . lets see the weight of 3 s and 3 n = 3 s + 3 * 4 s = 15 s . . and weight of 5 s and 1 n = 5 s + 1 * 5 s = 10 s . . ratio = 15 s / 10 s = 15 / 10 = 3 / 2 d | general |
math_qa__xYnbJOx7KkNUifCW | The average wages of a worker during a fortnight comprising 15 consecutive working days was $90 per day. During the first 7 days, his average wages was $87 per day and the average wages during the last 7 days was $94 per day. What was his wage on the 8th day?
Choose the correct choice from the following options
A) $ 83 B) $ 90 C) $ 92 D) $ 97 E) $ 104 | <gadget id="calculator">90 * 15</gadget>
<output>1_350</output>
<gadget id="calculator">87 * 7</gadget>
<output>609</output>
<gadget id="calculator">94 * 7</gadget>
<output>658</output>
<gadget id="calculator">609 + 658</gadget>
<output>1_267</output>
<gadget id="calculator">1_350 - 1_267</gadget>
<output>83</output>
<result>A</result> | A | 83 | The average wages of a worker during a fortnight comprising 15 consecutive working days was $90 per day. During the first 7 days, his average wages was $87 per day and the average wages during the last 7 days was $94 per day. What was his wage on the 8th day? | {
"A": "$ 83",
"B": "$ 90",
"C": "$ 92",
"D": "$ 97",
"E": "$ 104"
} | subtract(multiply(90, 15), add(multiply(87, 7), multiply(94, 7))) | multiply(n0,n1)|multiply(n2,n3)|multiply(n2,n5)|add(#1,#2)|subtract(#0,#3)| | "average daily wage of a worker for 15 consecutive working days = 90 $ during the first 7 days , the daily average daily wage = 87 $ during the last 7 days , the daily average daily wage = 94 $ wage on 8 th day = 90 * 15 - ( 87 * 7 + 94 * 7 ) = 1350 - ( 609 + 658 ) = 1350 - 1267 = 83 answer a" | physics |
math_qa__WGP4nm84C5JUJZVf | At what rate percent on simple interest will Rs.750 amount to Rs.1200 in 5 years? Choose the correct choice from the following choices: A) 12 B) 3 C) 14 D) 5 E) 6 | <gadget id="calculator">1_200 - 750</gadget>
<output>450</output>
<gadget id="calculator">450 / 750</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) / 5</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(3/25) * 100</gadget>
<output>12</output>
<result>A</result> | A | 12 | At what rate percent on simple interest will Rs.750 amount to Rs.1200 in 5 years? | {
"A": "12",
"B": "3",
"C": "14",
"D": "5",
"E": "6"
} | multiply(divide(divide(subtract(1200, 750), 750), 5), const_100) | subtract(n1,n0)|divide(#0,n0)|divide(#1,n2)|multiply(#2,const_100)| | "450 = ( 750 * 5 * r ) / 100 r = 12 % . answer : a" | gain |
math_qa__0SfxM7mBrcR6DyxH | The difference between simple and compound interest on Rs. 1200 for one year at 10% per annum reckoned half-yearly is?
Choose the correct choice from the following answers:
A) rs . 7 B) rs . 3 C) rs . 8 D) rs . 1 E) rs . 4 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) + 1</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(441/400) - (11/10)</gadget>
<output>1/400 = around 0.0025</output>
<gadget id="calculator">(1/400) * 1_200</gadget>
<output>3</output>
<result>B</result> | B | 3 | The difference between simple and compound interest on Rs. 1200 for one year at 10% per annum reckoned half-yearly is? | {
"A": "rs . 7",
"B": "rs . 3",
"C": "rs . 8",
"D": "rs . 1",
"E": "rs . 4"
} | multiply(subtract(power(add(divide(divide(10, const_2), const_100), const_1), const_2), add(divide(10, const_100), const_1)), 1200) | divide(n1,const_2)|divide(n1,const_100)|add(#1,const_1)|divide(#0,const_100)|add(#3,const_1)|power(#4,const_2)|subtract(#5,#2)|multiply(n0,#6)| | "s . i . = ( 1200 * 10 * 1 ) / 100 = rs . 120 c . i . = [ 1200 * ( 1 + 5 / 100 ) 2 - 1200 ] = rs . 123 difference = ( 123 - 120 ) = rs . 3 . answer : b" | gain |
math_qa__Z0i53hiG7E4bAw88 | Stacy and Heather are 25 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour fast than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?. Pick one
A) 9.0 mile B) 13.0 mile C) 11.0 mile D) 10.2 mile E) 12 mile | <gadget id="calculator">1 + 5</gadget>
<output>6</output>
<gadget id="calculator">6 / 60</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">24 * (1/10)</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">25 - (12/5)</gadget>
<output>113/5 = around 22.6</output>
<gadget id="calculator">5 + 6</gadget>
<output>11</output>
<gadget id="calculator">(113/5) / 11</gadget>
<output>113/55 = around 2.054545</output>
<gadget id="calculator">(113/55) * 5</gadget>
<output>113/11 = around 10.272727</output>
<result>D</result> | D | 10.2 | Stacy and Heather are 25 miles apart and walk towards each other along the same route. Stacy walks at constant rate that is 1 mile per hour fast than heather's constant rate of 5 miles/hour. If Heather starts her journey 24 minutes after Stacy, how far from the original destination has Heather walked when the two meet?. | {
"A": "9.0 mile",
"B": "13.0 mile",
"C": "11.0 mile",
"D": "10.2 mile",
"E": "12 mile"
} | multiply(divide(subtract(25, multiply(24, divide(add(1, 5), const_60))), add(5, add(1, 5))), 5) | add(n1,n2)|add(n2,#0)|divide(#0,const_60)|multiply(n3,#2)|subtract(n0,#3)|divide(#4,#1)|multiply(n2,#5) | ss - stacy ' s speed = 6 m / hr sh - heather ' s speed = 5 m / hr in 24 minutes stacy will cover = ( 24 / 60 ) * 6 = 2.4 miles now since both are walking in opposite directions , add their speeds - 6 + 5 = 11 m / hr and distance to cover is 25 - 2.4 = 22.6 time taken = distance / speed = 22.6 / 11 = 2.05 hrs heather will cover = 5 * 2.4 = 10.2 miles . answer d | physics |
math_qa__ofNa38ssGDAynquk | Ganesh ,Ram and Sohan together can do a work in 16 days. If Ganesh and Ram together can do a the same work in 24 days then, how long will take Sohan to do the same work? Pick one:
A) 48 B) 58 C) 68 D) 78 E) 100 | <gadget id="calculator">1 / 16</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">(1/16) - (1/24)</gadget>
<output>1/48 = around 0.020833</output>
<gadget id="calculator">1 / (1/48)</gadget>
<output>48</output>
<result>A</result> | A | 48 | Ganesh ,Ram and Sohan together can do a work in 16 days. If Ganesh and Ram together can do a the same work in 24 days then, how long will take Sohan to do the same work? | {
"A": "48",
"B": "58",
"C": "68",
"D": "78",
"E": "100"
} | divide(const_1, subtract(divide(const_1, 16), divide(const_1, 24))) | divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|divide(const_1,#2) | solution : work done by three of them together in 1 day = 1 / 16 . . . . . . . . . . . . ( 1 ) work done by ganesh and ram together in 1 day = 1 / 24 . . . . . ( 2 ) so , work done by sohan in one day = ( 1 ) - ( 2 ) = ( 1 / 16 ) - ( 1 / 24 ) = 1 / 48 = > total days taken by sohan to complete the work alone = 48 days . answer a | physics |
math_qa__KPEiVt45jB5Nx23p | One fourth of one third of two fifth of a number is 25. What will be40% of that number
Choose the correct choice from the following
A) 140 B) 150 C) 180 D) 200 E) 300 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/4) * (1/3)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/12) * (2/5)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">25 / (1/30)</gadget>
<output>750</output>
<gadget id="calculator">750 * 40</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 / 100</gadget>
<output>300</output>
<result>E</result> | E | 300 | One fourth of one third of two fifth of a number is 25. What will be40% of that number | {
"A": "140",
"B": "150",
"C": "180",
"D": "200",
"E": "300"
} | divide(multiply(divide(25, multiply(multiply(divide(const_1, const_4), divide(const_1, const_3)), divide(const_2, add(const_2, const_3)))), 40), const_100) | add(const_2,const_3)|divide(const_1,const_4)|divide(const_1,const_3)|divide(const_2,#0)|multiply(#1,#2)|multiply(#3,#4)|divide(n0,#5)|multiply(n1,#6)|divide(#7,const_100)| | "explanation : ( 1 / 4 ) * ( 1 / 3 ) * ( 2 / 5 ) * x = 25 then x = 25 * 30 = 750 40 % of 750 = 300 answer : option e" | gain |
math_qa__xB3PwSj2hxL9HyyB | The cost price of an article is 56% of the marked price. Calculate the gain percent after allowing a discount of 13%.
Choose the correct choice from the following options
A) 23.4 % B) 44.5 % C) 55.3 % D) 57.4 % E) none | <gadget id="calculator">100 - 13</gadget>
<output>87</output>
<gadget id="calculator">87 / 56</gadget>
<output>87/56 = around 1.553571</output>
<gadget id="calculator">(87/56) - 1</gadget>
<output>31/56 = around 0.553571</output>
<gadget id="calculator">(31/56) * 100</gadget>
<output>775/14 = around 55.357143</output>
<result>C</result> | C | 55.3 | The cost price of an article is 56% of the marked price. Calculate the gain percent after allowing a discount of 13%. | {
"A": "23.4 %",
"B": "44.5 %",
"C": "55.3 %",
"D": "57.4 %",
"E": "none"
} | multiply(subtract(divide(subtract(const_100, 13), 56), const_1), const_100) | subtract(const_100,n1)|divide(#0,n0)|subtract(#1,const_1)|multiply(#2,const_100)| | "sol . let marked price = rs . 100 . then , c . p . = rs . 56 . s . p = rs . 87 . â ˆ ´ gain % = [ 31 / 56 * 100 ] % = 55.3 % . answer c" | gain |
math_qa__tgFrAsS6s2riBABk | 1024 people in village 720 speak tamil,562 speak english while 346 speak both. person who don not speack english or tamil speak hindi. what is probibility that person speak hindi
Choose the correct choice from the following options.
A) 13 / 128 B) 12 / 128 C) 11 / 126 D) 11 / 127 E) 11 / 128 | <gadget id="calculator">562 - 346</gadget>
<output>216</output>
<gadget id="calculator">720 - 346</gadget>
<output>374</output>
<gadget id="calculator">216 + 374</gadget>
<output>590</output>
<gadget id="calculator">590 + 346</gadget>
<output>936</output>
<gadget id="calculator">1_024 - 936</gadget>
<output>88</output>
<gadget id="calculator">88 / 1_024</gadget>
<output>11/128 = around 0.085938</output>
<result>E</result> | E | 0.085938 | 1024 people in village 720 speak tamil,562 speak english while 346 speak both. person who don not speack english or tamil speak hindi. what is probibility that person speak hindi | {
"A": "13 / 128",
"B": "12 / 128",
"C": "11 / 126",
"D": "11 / 127",
"E": "11 / 128"
} | divide(subtract(1024, add(add(subtract(562, 346), subtract(720, 346)), 346)), 1024) | subtract(n2,n3)|subtract(n1,n3)|add(#0,#1)|add(n3,#2)|subtract(n0,#3)|divide(#4,n0) | n ( t ) = 720 n ( e ) = 562 n ( t ^ e ) = 346 n ( tue ) = 720 + 562 - 346 = 936 now , n ( h ) = 1024 - 936 = 88 p ( h ) = 88 / 1024 = 11 / 128 = 0.085 answer : e | other |
math_qa__x33Z0UKkRXJIawFE | A train 140 m long passes a man,running at 6 kmph in the direction opposite to that of the train,in 6 seconds.The speed of the train is Select
A) 54 kmph
B) 60 kmph
C) 66 kmph
D) 72 kmph
E) 78 kmph | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">6 * (5/18)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">(5/3) * 6</gadget>
<output>10</output>
<gadget id="calculator">140 - 10</gadget>
<output>130</output>
<gadget id="calculator">130 / 6</gadget>
<output>65/3 = around 21.666667</output>
<gadget id="calculator">(65/3) / (5/18)</gadget>
<output>78</output>
<result>E</result> | E | 78 | A train 140 m long passes a man,running at 6 kmph in the direction opposite to that of the train,in 6 seconds.The speed of the train is | {
"A": "54 kmph",
"B": "60 kmph",
"C": "66 kmph",
"D": "72 kmph",
"E": "78 kmph"
} | divide(divide(subtract(140, multiply(multiply(6, const_0_2778), 6)), 6), const_0_2778) | multiply(n1,const_0_2778)|multiply(n1,#0)|subtract(n0,#1)|divide(#2,n1)|divide(#3,const_0_2778)| | "speed of train relative to man : 140 / 6 * 18 / 5 km / hr = 84 km / hr let speed of train = x therefore x + 6 = 84 x = 84 - 6 x = 78 km / hr answer : e" | physics |
math_qa__uNL2x4HAhz8mluQ2 | The speed of a train is 120 kmph. What is the distance covered by it in 8 minutes?
Choose the correct choice from the following options:
A) 15 kmph
B) 11 kmph
C) 16 kmph
D) 18 kmph
E) 12 kmph | <gadget id="calculator">8 / 60</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(2/15) * 120</gadget>
<output>16</output>
<result>C</result> | C | 16 | The speed of a train is 120 kmph. What is the distance covered by it in 8 minutes? | {
"A": "15 kmph",
"B": "11 kmph",
"C": "16 kmph",
"D": "18 kmph",
"E": "12 kmph"
} | multiply(divide(8, const_60), 120) | divide(n1,const_60)|multiply(n0,#0)| | "120 * 8 / 60 = 16 kmph answer : c" | physics |
math_qa__xgsp4EH0cCReYe0S | A goods train runs at the speed of 72 kmph and crosses a 260 m long platform in 26 seconds. What is the length of the goods train?
Choose the correct option
A) 260 m B) 270 m C) 643 m D) 832 m E) 270 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(5/18) * 72</gadget>
<output>20</output>
<gadget id="calculator">260 / 20</gadget>
<output>13</output>
<gadget id="calculator">26 - 13</gadget>
<output>13</output>
<gadget id="calculator">13 * 20</gadget>
<output>260</output>
<result>A</result> | A | 260 | A goods train runs at the speed of 72 kmph and crosses a 260 m long platform in 26 seconds. What is the length of the goods train? | {
"A": "260 m",
"B": "270 m",
"C": "643 m",
"D": "832 m",
"E": "270 m"
} | multiply(subtract(26, divide(260, multiply(const_0_2778, 72))), multiply(const_0_2778, 72)) | multiply(n0,const_0_2778)|divide(n1,#0)|subtract(n2,#1)|multiply(#0,#2)| | "speed = ( 72 x 5 / 18 ) m / sec = 20 m / sec . time = 26 sec . let the length of the train be x metres . then , x + 260 / 26 = 20 x + 260 = 520 x = 260 . answer : a" | physics |
math_qa__CZN56ofAM820Rs2g | If Albert’s monthly earnings rise by 14%, he would earn $678. If, instead, his earnings rise by only 15%, how much (in $) would he earn this month?
Answers:
A) 643 B) 689 C) 683 D) 690 E) 693 | <gadget id="calculator">14 / 100</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">1 + (7/50)</gadget>
<output>57/50 = around 1.14</output>
<gadget id="calculator">678 / (57/50)</gadget>
<output>11_300/19 = around 594.736842</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(11_300/19) * (23/20)</gadget>
<output>12_995/19 = around 683.947368</output>
<result>C</result> | C | 683 | If Albert’s monthly earnings rise by 14%, he would earn $678. If, instead, his earnings rise by only 15%, how much (in $) would he earn this month? | {
"A": "643",
"B": "689",
"C": "683",
"D": "690",
"E": "693"
} | multiply(divide(678, add(const_1, divide(14, const_100))), add(const_1, divide(15, const_100))) | divide(n2,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|divide(n1,#3)|multiply(#2,#4)| | "= 678 / 1.14 ∗ 1.15 = 683 = 683 answer is c" | gain |
math_qa__4peDfKfckGigf7v4 | A container contains 40 litres of milk.From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container. Select.
A) 26.34 litres B) 27.36 liters C) 28 litres D) 29.16 litres E) can not be determined | <gadget id="calculator">4 / 40</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) ** 3</gadget>
<output>729/1_000 = around 0.729</output>
<gadget id="calculator">(729/1_000) * 40</gadget>
<output>729/25 = around 29.16</output>
<result>D</result> | D | 29.16 | A container contains 40 litres of milk.From this container 4 litres of milk was taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container. | {
"A": "26.34 litres",
"B": "27.36 liters",
"C": "28 litres",
"D": "29.16 litres",
"E": "can not be determined"
} | multiply(power(subtract(const_1, divide(4, 40)), const_3), 40) | divide(n1,n0)|subtract(const_1,#0)|power(#1,const_3)|multiply(n0,#2) | solution amount of milk left after 3 operations [ 40 ( 1 - 4 / 40 ) 3 ] litres = ( 40 x 9 / 10 x 9 / 10 x 9 / 10 ) = 29.16 litres answer d | general |
math_qa__OqH44AEWzRygNm5g | If grapes are 90% water and raisins are 17% water, then how many kilograms did a quantity of raisins, which currently weighs 14 kilograms, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.) Pick
A) 108.6 B) 110.4 C) 112.6 D) 114.8 E) 116.2 | <gadget id="calculator">100 - 17</gadget>
<output>83</output>
<gadget id="calculator">83 / 100</gadget>
<output>83/100 = around 0.83</output>
<gadget id="calculator">(83/100) * 14</gadget>
<output>581/50 = around 11.62</output>
<gadget id="calculator">100 - 90</gadget>
<output>10</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(581/50) / (1/10)</gadget>
<output>581/5 = around 116.2</output>
<result>E</result> | E | 116.2 | If grapes are 90% water and raisins are 17% water, then how many kilograms did a quantity of raisins, which currently weighs 14 kilograms, weigh when all the raisins were grapes? (Assume that the only difference between their raisin-weight and their grape-weight is water that evaporated during their transformation.) | {
"A": "108.6",
"B": "110.4",
"C": "112.6",
"D": "114.8",
"E": "116.2"
} | divide(multiply(divide(subtract(const_100, 17), const_100), 14), divide(subtract(const_100, 90), const_100)) | subtract(const_100,n1)|subtract(const_100,n0)|divide(#0,const_100)|divide(#1,const_100)|multiply(n2,#2)|divide(#4,#3)| | "let x be the original weight of the grapes . the weight of the grape pulp was 0.1 x . since the grape pulp is 83 % of the raisins , 0.1 x = 0.83 ( 14 kg ) . then x = 8.3 * 14 = 116.2 kg . the answer is e ." | general |
math_qa__t88KMPxxV4xwxZqy | On multiplying a number F by 153, the result obtained was 102325. However, it is found that both the 2's are wrong. Find the correct result. Choose the correct choice.
A) 104345 B) 107375 C) 108385 D) 109395 E) 105355 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 10</gadget>
<output>70</output>
<gadget id="calculator">7 * 100</gadget>
<output>700</output>
<gadget id="calculator">700 * 10</gadget>
<output>7_000</output>
<gadget id="calculator">70 + 7_000</gadget>
<output>7_070</output>
<gadget id="calculator">7_070 + 102_325</gadget>
<output>109_395</output>
<result>D</result> | D | 109,395 | On multiplying a number F by 153, the result obtained was 102325. However, it is found that both the 2's are wrong. Find the correct result. | {
"A": "104345",
"B": "107375",
"C": "108385",
"D": "109395",
"E": "105355"
} | add(add(multiply(add(const_3, const_4), const_10), multiply(multiply(add(const_3, const_4), const_100), const_10)), 102325) | add(const_3,const_4)|multiply(#0,const_10)|multiply(#0,const_100)|multiply(#2,const_10)|add(#1,#3)|add(n1,#4) | the only thing you actually know about the correct number f is that it is divisible by 153 and has 5 as a factor . you should immediately try to find the factors of 153 and look for them in the options . 153 = 9 * 17 divisibility by 9 is easy to check . only ( d ) satisfies . | other |
math_qa__FKJnVlAQrdLy1Voc | At an election 2 candidates are participated a candidate got 30% of votes and defeated by 5000 votes. 100 votes are invalid. Find the total polled votes? Choose the correct choice from the following answers:
A) 11520 B) 12600 C) 15000 D) 13560 E) 12560 | <gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 - 30</gadget>
<output>40</output>
<gadget id="calculator">5_000 / 40</gadget>
<output>125</output>
<gadget id="calculator">125 * 100</gadget>
<output>12_500</output>
<gadget id="calculator">100 + 12_500</gadget>
<output>12_600</output>
<result>B</result> | B | 12,600 | At an election 2 candidates are participated a candidate got 30% of votes and defeated by 5000 votes. 100 votes are invalid. Find the total polled votes? | {
"A": "11520",
"B": "12600",
"C": "15000",
"D": "13560",
"E": "12560"
} | add(const_100, multiply(divide(5000, subtract(subtract(100, 30), 30)), const_100)) | subtract(n3,n1)|subtract(#0,n1)|divide(n2,#1)|multiply(#2,const_100)|add(#3,const_100) | winners votes = 100 - 30 = 70 % invalid votes = 100 polled votes = [ ( 100 * 5000 ) / ( 2 * 70 - 100 ) ] + 100 = 12600 answer is b | gain |
math_qa__9E1CIQ12LWt07CKl | The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of?
Choices
A) 6 : 8
B) 6 : 2
C) 6 : 5
D) 6 : 4
E) 6 : 2 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">12 / 10</gadget>
<output>6/5 = around 1.2</output>
<result>C</result> | C | 1.2 | The marks obtained by Vijay and Amith are in the ratio 4:5 and those obtained by Amith and Abhishek in the ratio of 3:2. The marks obtained by Vijay and Abhishek are in the ratio of? | {
"A": "6 : 8",
"B": "6 : 2",
"C": "6 : 5",
"D": "6 : 4",
"E": "6 : 2"
} | divide(multiply(4, 3), multiply(5, 2)) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,#1)| | "4 : 5 3 : 2 - - - - - - - 12 : 15 : 10 12 : 10 6 : 5 answer : c" | other |
math_qa__h1HeIxXm2Xlj6LEg | If a large pizza has a radius that is 10% larger that that of a medium pizza, what is the percent increase in area between a medium and a large pizza?
Answers: A) 15 % B) 21 % C) 25 % D) 30 % E) 36 % | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) ** 2</gadget>
<output>121/100 = around 1.21</output>
<gadget id="calculator">(121/100) - 1</gadget>
<output>21/100 = around 0.21</output>
<gadget id="calculator">(21/100) * 100</gadget>
<output>21</output>
<result>B</result> | B | 21 | If a large pizza has a radius that is 10% larger that that of a medium pizza, what is the percent increase in area between a medium and a large pizza? | {
"A": "15 %",
"B": "21 %",
"C": "25 %",
"D": "30 %",
"E": "36 %"
} | multiply(subtract(power(add(const_1, divide(10, const_100)), const_2), const_1), const_100) | divide(n0,const_100)|add(#0,const_1)|power(#1,const_2)|subtract(#2,const_1)|multiply(#3,const_100)| | "let the radius of medium pizza be r . then the radius of large pizza is 1.1 r . the area of the medium pizza is pi * r ^ 2 the area of the large pizza is pi * ( 1.1 * r ) ^ 2 = 1.21 * pi * r ^ 2 , an increase of 21 % . the answer is b ." | gain |
math_qa__0W6PRdM8xd2672Dj | If a coin is flipped, the probability that the coin will land tails is 1/2. If the coin is flipped 5 times, what is the probability that it will land tails up on the first 2 flips and not on the last 3 flips? Choose the correct choice from the following answers:
A) 3 / 5 B) 1 / 32 C) 1 / 5 D) 1 / 4 E) 1 / 2 | <gadget id="calculator">2 ** 5</gadget>
<output>32</output>
<gadget id="calculator">1 / 32</gadget>
<output>1/32 = around 0.03125</output>
<result>B</result> | B | 0.03125 | If a coin is flipped, the probability that the coin will land tails is 1/2. If the coin is flipped 5 times, what is the probability that it will land tails up on the first 2 flips and not on the last 3 flips? | {
"A": "3 / 5",
"B": "1 / 32",
"C": "1 / 5",
"D": "1 / 4",
"E": "1 / 2"
} | inverse(power(2, 5)) | power(n1,n2)|inverse(#0)| | ( 1 / 2 ) * ( 1 / 2 ) * ( 1 / 2 ) * ( 1 / 2 ) * ( 1 / 2 ) = 1 / 32 answer : b | probability |
math_qa__0Q5jKJIYJENMJhji | 60kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3:2 and alloy B has tin and copper in the ratio 1:4, then the amount of tin in the new alloy is? Select the correct option
A) 24 kg B) 44 kg C) 20 kg D) 30 kg E) 52 kg | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">20 * 1</gadget>
<output>20</output>
<gadget id="calculator">24 + 20</gadget>
<output>44</output>
<result>B</result> | B | 44 | 60kg of an alloy A is mixed with 100 kg of alloy B. If alloy A has lead and tin in the ratio 3:2 and alloy B has tin and copper in the ratio 1:4, then the amount of tin in the new alloy is? | {
"A": "24 kg",
"B": "44 kg",
"C": "20 kg",
"D": "30 kg",
"E": "52 kg"
} | add(multiply(divide(60, add(3, 2)), 2), multiply(divide(100, add(1, 4)), 1)) | add(n2,n3)|add(n4,n5)|divide(n0,#0)|divide(n1,#1)|multiply(n3,#2)|multiply(n4,#3)|add(#4,#5) | quantity of tin in 60 kg of a = 60 * 2 / 5 = 24 kg quantity of tin in 100 kg of b = 100 * 1 / 5 = 20 kg quantity of tin in the new alloy = 24 + 20 = 44 kg answer is b | other |
math_qa__JC5uZNrEowMjrorA | Pipe A can fill a tank in 10 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes? Pick.
A) 18 B) 27 C) 98 D) 27 E) 48 | <gadget id="calculator">30 / 10</gadget>
<output>3</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 24</gadget>
<output>48</output>
<result>E</result> | E | 48 | Pipe A can fill a tank in 10 minutes and pipe B cam empty it in 24 minutes. If both the pipes are opened together after how many minutes should pipe B be closed, so that the tank is filled in 30 minutes? | {
"A": "18",
"B": "27",
"C": "98",
"D": "27",
"E": "48"
} | multiply(subtract(divide(30, 10), const_1), 24) | divide(n2,n0)|subtract(#0,const_1)|multiply(n1,#1)| | "let the pipe b be closed after x minutes . 30 / 10 - x / 24 = 1 = > x / 24 = 30 / 10 - 1 = 2 = > x = 2 * 24 = 48 . answer : e" | physics |
math_qa__F2fqaZDRqnLx4mkx | if price of t.v set is reduced by 18%, then its sale increases by 88%, find net effect on sale value Choices.
A) 44
B) 54
C) 46
D) 47
E) 48 | <gadget id="calculator">100 - 18</gadget>
<output>82</output>
<gadget id="calculator">82 / 100</gadget>
<output>41/50 = around 0.82</output>
<gadget id="calculator">100 + 88</gadget>
<output>188</output>
<gadget id="calculator">188 / 100</gadget>
<output>47/25 = around 1.88</output>
<gadget id="calculator">(41/50) * (47/25)</gadget>
<output>1_927/1_250 = around 1.5416</output>
<gadget id="calculator">(1_927/1_250) - 1</gadget>
<output>677/1_250 = around 0.5416</output>
<gadget id="calculator">(677/1_250) * 100</gadget>
<output>1_354/25 = around 54.16</output>
<result>B</result> | B | 54 | if price of t.v set is reduced by 18%, then its sale increases by 88%, find net effect on sale value | {
"A": "44",
"B": "54",
"C": "46",
"D": "47",
"E": "48"
} | multiply(subtract(multiply(divide(subtract(const_100, 18), const_100), divide(add(const_100, 88), const_100)), const_1), const_100) | add(n1,const_100)|subtract(const_100,n0)|divide(#1,const_100)|divide(#0,const_100)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "- a + b + ( ( - a ) ( b ) / 100 ) = - 18 + 88 + ( - 18 * 88 ) / 100 = - 18 + 88 - 16 = 54 answer : b" | gain |
math_qa__HL2mxsR06Cc1HXHE | A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 38 now, the son age 5 years back was : Pick.
A) 14 B) 19 C) 33 D) 38 E) 56 | <gadget id="calculator">38 / 2</gadget>
<output>19</output>
<gadget id="calculator">19 - 5</gadget>
<output>14</output>
<result>A</result> | A | 14 | A father said his son , " I was as old as you are at present at the time of your birth. " If the father age is 38 now, the son age 5 years back was : | {
"A": "14",
"B": "19",
"C": "33",
"D": "38",
"E": "56"
} | subtract(divide(38, const_2), 5) | divide(n0,const_2)|subtract(#0,n1)| | "explanation : let the son ' s present age be x years . then , ( 38 - x ) = x x = 19 . son ' s age 5 years back = ( 19 - 5 ) = 14 years . answer : a" | general |
math_qa__GQ109b8nQlhmT1gI | 20 machines can do a work in 5days. How many machines are needed to complete the work in 10days? Choose the correct choice from the following answers.
A) 10 B) 15 C) 8 D) 12 E) 20 | <gadget id="calculator">20 * 5</gadget>
<output>100</output>
<gadget id="calculator">100 / 10</gadget>
<output>10</output>
<result>A</result> | A | 10 | 20 machines can do a work in 5days. How many machines are needed to complete the work in 10days? | {
"A": "10",
"B": "15",
"C": "8",
"D": "12",
"E": "20"
} | divide(multiply(20, 5), 10) | multiply(n0,n1)|divide(#0,n2)| | "required number of machines = 20 * 5 / 10 = 10 answer is a" | physics |
math_qa__L1uUc74rtVtMPaEk | In x-y plane, there is a right triangle ABC (∠B=90o). If the length of AC is 225 and the slope of line segment AC is 4/3, what is the length of AB? Select the correct option:
A) 12 B) 180 C) 24 D) 28 E) 40 | <gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">16 + 9</gadget>
<output>25</output>
<gadget id="calculator">25 ** (1/2)</gadget>
<output>5</output>
<gadget id="calculator">225 / 5</gadget>
<output>45</output>
<gadget id="calculator">4 * 45</gadget>
<output>180</output>
<result>B</result> | B | 180 | In x-y plane, there is a right triangle ABC (∠B=90o). If the length of AC is 225 and the slope of line segment AC is 4/3, what is the length of AB? | {
"A": "12",
"B": "180",
"C": "24",
"D": "28",
"E": "40"
} | multiply(4, divide(225, sqrt(add(power(4, const_2), power(3, const_2))))) | power(n2,const_2)|power(n3,const_2)|add(#0,#1)|sqrt(#2)|divide(n1,#3)|multiply(n2,#4)| | "slope = change in vertical direction / change in horizontal direction = 4 / 3 change in vertical direction = 4 x = ab change in horizontal direction = 3 x = bc ab ^ 2 + bc ^ 2 = 225 ^ 2 16 x ^ 2 + 9 x ^ 2 = 225 ^ 2 25 x ^ 2 = 225 ^ 2 x ^ 2 = 25 * 9 ^ 2 x = 45 therefore ab = 45 * 4 = 180 answer : b" | general |
math_qa__D0FCymXoWvz9naeX | What is the total cost of 2 sandwiches at $3.49 each and 4 sodas at $0.87 each? Select:
A) $ 3.36 B) $ 6.85 C) $ 8.46 D) $ 10.46 E) $ 11.85 | <gadget id="calculator">2 * 3.49</gadget>
<output>6.98</output>
<gadget id="calculator">4 * 0.87</gadget>
<output>3.48</output>
<gadget id="calculator">6.98 + 3.48</gadget>
<output>10.46</output>
<result>D</result> | D | 10.46 | What is the total cost of 2 sandwiches at $3.49 each and 4 sodas at $0.87 each? | {
"A": "$ 3.36",
"B": "$ 6.85",
"C": "$ 8.46",
"D": "$ 10.46",
"E": "$ 11.85"
} | add(multiply(2, 3.49), multiply(4, 0.87)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)| | "answer = d 2 * 3.49 + 4 * 0.87 = 2 ( 3.50 - 0.01 ) + 4 ( 1.00 - 0.13 ) = 7 + 4 - 0.02 - 0.52 = 11 - 0.54 = 10.46" | general |
math_qa__ouUIcxxkfoN4amWt | Gold is 10 times as heavy as water and copper is 5 times as heavy as water. In what ratio should these be mixed to get an alloy 7 times as heavy as water?
Choose the correct answer:
A) 3 : 2 B) 1 : 2 C) 3 : 1 D) 5 : 2 E) 2 : 3 | <gadget id="calculator">7 - 5</gadget>
<output>2</output>
<gadget id="calculator">10 - 7</gadget>
<output>3</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<result>E</result> | E | 0.666667 | Gold is 10 times as heavy as water and copper is 5 times as heavy as water. In what ratio should these be mixed to get an alloy 7 times as heavy as water? | {
"A": "3 : 2",
"B": "1 : 2",
"C": "3 : 1",
"D": "5 : 2",
"E": "2 : 3"
} | divide(subtract(7, 5), subtract(10, 7)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)| | "g = 10 w c = 5 w let 1 gm of gold mixed with x gm of copper to get 1 + x gm of the alloy 1 gm gold + x gm copper = x + 1 gm of alloy 10 w + 5 wx = x + 1 * 7 w 10 + 5 x = 7 ( x + 1 ) x = 3 / 2 ratio of gold with copper = 1 : 3 / 2 = 2 : 3 answer is e" | general |
math_qa__k833eIzncJlLQFqS | Find the ratio in which rice at Rs.7.00 a kg be mixed with rice at Rs.5.70 a kg to produce a mixture worth Rs.6.30 a kg? Choose the correct choice from the following options
A) 1 : 3 B) 2 : 3 C) 3 : 4 D) 6 : 7 E) none of these | <gadget id="calculator">6.3 - 5.7</gadget>
<output>0.6</output>
<gadget id="calculator">7 - 6.3</gadget>
<output>0.7</output>
<gadget id="calculator">0.6 / 0.7</gadget>
<output>0.857143</output>
<result>D</result> | D | 0.857143 | Find the ratio in which rice at Rs.7.00 a kg be mixed with rice at Rs.5.70 a kg to produce a mixture worth Rs.6.30 a kg? | {
"A": "1 : 3",
"B": "2 : 3",
"C": "3 : 4",
"D": "6 : 7",
"E": "none of these"
} | divide(subtract(6.30, 5.70), subtract(7.00, 6.30)) | subtract(n2,n1)|subtract(n0,n2)|divide(#0,#1)| | "solution required ratio = 60 : 70 = 6 : 7 answer d" | other |
math_qa__hROKwIYUw5PDAeuN | A water tank is one-fifth full. Pipe A can fill a tank in 15 minutes and pipe B can empty it in 6 minutes. If both the pipes are open, how many minutes will it take to empty or fill the tank completely? Pick one
A) 2 B) 4 C) 6 D) 8 E) 10 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/6) - (1/15)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / (1/10)</gadget>
<output>10</output>
<gadget id="calculator">(1/5) * 10</gadget>
<output>2</output>
<result>A</result> | A | 2 | A water tank is one-fifth full. Pipe A can fill a tank in 15 minutes and pipe B can empty it in 6 minutes. If both the pipes are open, how many minutes will it take to empty or fill the tank completely? | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "10"
} | multiply(divide(const_1, add(const_1, const_4)), divide(const_1, subtract(divide(const_1, 6), divide(const_1, 15)))) | add(const_1,const_4)|divide(const_1,n1)|divide(const_1,n0)|divide(const_1,#0)|subtract(#1,#2)|divide(const_1,#4)|multiply(#3,#5)| | "the combined rate of filling / emptying the tank = 1 / 15 - 1 / 6 = - 1 / 10 since the rate is negative , the tank will be emptied . a full tank would take 10 minutes to empty . since the tank is only one - fifth full , the time is ( 1 / 5 ) * 10 = 2 minutes the answer is a ." | physics |
math_qa__hVcNQ6L5NNeEMK2S | A can do a work in 3 days. B can do the same work in 6 days. If both A & B are working together in how many days they will finish the work?
Choose one:
A) 3
B) 5
C) 4
D) 2
E) 6 | <gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">3 + 6</gadget>
<output>9</output>
<gadget id="calculator">18 / 9</gadget>
<output>2</output>
<result>D</result> | D | 2 | A can do a work in 3 days. B can do the same work in 6 days. If both A & B are working together in how many days they will finish the work? | {
"A": "3",
"B": "5",
"C": "4",
"D": "2",
"E": "6"
} | divide(multiply(3, 6), add(3, 6)) | add(n0,n1)|multiply(n0,n1)|divide(#1,#0)| | "a rate = 1 / 3 b rate = 1 / 6 ( a + b ) rate = ( 1 / 3 ) + ( 1 / 6 ) = 1 / 2 a & b finish the work in 2 days correct option is d" | physics |
math_qa__xv9DGGBmDD6pvTR0 | In a certain town, the ratio of NY Yankees fans to NY Mets fans is 3:2, and the ratio of NY Mets fans to Boston Red Sox fans is 4:5. If there are 390 baseball fans in the town, each of whom is a fan of exactly one of those three teams, how many NY Mets fans are there in this town? Choices
A) 84 B) 96 C) 104 D) 112 E) 120 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">390 / 15</gadget>
<output>26</output>
<gadget id="calculator">26 * 4</gadget>
<output>104</output>
<result>C</result> | C | 104 | In a certain town, the ratio of NY Yankees fans to NY Mets fans is 3:2, and the ratio of NY Mets fans to Boston Red Sox fans is 4:5. If there are 390 baseball fans in the town, each of whom is a fan of exactly one of those three teams, how many NY Mets fans are there in this town? | {
"A": "84",
"B": "96",
"C": "104",
"D": "112",
"E": "120"
} | multiply(divide(390, add(add(multiply(3, 2), 4), 5)), 4) | multiply(n0,n1)|add(n2,#0)|add(n3,#1)|divide(n4,#2)|multiply(n2,#3)| | "the ratio of yankees : mets : red sox = 6 : 4 : 5 the mets fans are 4 / 15 of the population . ( 4 / 15 ) * 390 = 104 the answer is c ." | other |
math_qa__LM4Yf1zlyp0AoT8r | A train 280 m long, running with a speed of 36 km / hr will pass a tree in
Choose the correct choice from the following
A) 12 sec B) 15 sec C) 16 sec D) 28 sec E) none | <gadget id="calculator">36 * 1_000</gadget>
<output>36_000</output>
<gadget id="calculator">280 / 36_000</gadget>
<output>7/900 = around 0.007778</output>
<gadget id="calculator">(7/900) * 3_600</gadget>
<output>28</output>
<result>D</result> | D | 28 | A train 280 m long, running with a speed of 36 km / hr will pass a tree in | {
"A": "12 sec",
"B": "15 sec",
"C": "16 sec",
"D": "28 sec",
"E": "none"
} | multiply(divide(280, multiply(36, const_1000)), const_3600) | multiply(n1,const_1000)|divide(n0,#0)|multiply(#1,const_3600)| | "sol . speed = ( 36 x 5 / 18 ) m / sec . = 10 m / sec . time taken = ( 280 x 1 / 10 ) sec = 28 sec answer d" | physics |
math_qa__HHBOgtYe22LEyDRE | For all real numbers v, an operation is defined by the equation v* = v - v/3. If (v*)* = 4, then v= Choices:
A) 6 B) 9 C) 12 D) 15 E) 18 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">4 / (2/3)</gadget>
<output>6</output>
<gadget id="calculator">6 / (2/3)</gadget>
<output>9</output>
<result>B</result> | B | 9 | For all real numbers v, an operation is defined by the equation v* = v - v/3. If (v*)* = 4, then v= | {
"A": "6",
"B": "9",
"C": "12",
"D": "15",
"E": "18"
} | divide(divide(4, subtract(const_1, divide(const_1, 3))), subtract(const_1, divide(const_1, 3))) | divide(const_1,n0)|subtract(const_1,#0)|divide(n1,#1)|divide(#2,#1)| | "( v * ) * = ( v - v / 3 ) - ( v - v / 3 ) / 3 4 = 2 v / 3 - 2 v / 9 = 4 v / 9 v = 9 the answer is b ." | general |
math_qa__m7n93gkIFDVXDS2O | A person buys an article at Rs.340. At what price should he sell the article so as to make a profit of 10%?
Choose the correct choice from the following.
A) 600 B) 882 C) 374 D) 356 E) 521 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">340 * (1/10)</gadget>
<output>34</output>
<gadget id="calculator">340 + 34</gadget>
<output>374</output>
<result>C</result> | C | 374 | A person buys an article at Rs.340. At what price should he sell the article so as to make a profit of 10%? | {
"A": "600",
"B": "882",
"C": "374",
"D": "356",
"E": "521"
} | add(340, multiply(340, divide(10, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)| | "cost price = rs . 340 profit = 10 % of 340 = rs . 34 selling price = cost price + profit = 340 + 34 = 374 answer : c" | gain |
math_qa__rHFcIGN9V3WtZMxb | On dividing 12401 by a certain number, we get 76 as quotient and 13 as remainder. What is the divisor?
Choose the correct choice from the following:
A) 163 B) 785 C) 852 D) 456 E) 852 | <gadget id="calculator">12_401 - 13</gadget>
<output>12_388</output>
<gadget id="calculator">12_388 / 76</gadget>
<output>163</output>
<result>A</result> | A | 163 | On dividing 12401 by a certain number, we get 76 as quotient and 13 as remainder. What is the divisor? | {
"A": "163",
"B": "785",
"C": "852",
"D": "456",
"E": "852"
} | divide(subtract(12401, 13), 76) | subtract(n0,n2)|divide(#0,n1)| | "divisor * quotient + remainder = dividend divisor = ( dividend ) - ( remainder ) / quotient ( 12401 - 13 ) / 76 = 163 answer ( a )" | general |
math_qa__A8oofhV3JkskNDtz | The average of the marks of 10 students in a class is 40. If the marks of each student are doubled, find the new average? Pick.
A) 78
B) 56
C) 80
D) 27
E) 40 | <gadget id="calculator">40 * 2</gadget>
<output>80</output>
<result>C</result> | C | 80 | The average of the marks of 10 students in a class is 40. If the marks of each student are doubled, find the new average? | {
"A": "78",
"B": "56",
"C": "80",
"D": "27",
"E": "40"
} | multiply(40, const_2) | multiply(n1,const_2)| | "sum of the marks for the 10 students = 10 * 40 = 400 . the marks of each student are doubled , the sum also will be doubled . the new sum = 400 * 2 = 800 . so , the new average = 800 / 10 = 80 . answer : c" | general |
math_qa__PWS1CDwfRx5cs1Ju | At 1:00 pm, there were 10.0 grams of bacteria. The bacteria increased to x grams at 4:00 pm, and 19.6 grams at 7:00 pm. If the amount of bacteria present increased by the same fraction during each of the 3-hour periods, how many grams of bacteria were present at 4:00 pm? Select:
A) 13.7 B) 14.0 C) 14.3 D) 14.6 E) 14.9 | <gadget id="calculator">19.6 / 10</gadget>
<output>1.96</output>
<gadget id="calculator">1.96 ** (1/2)</gadget>
<output>1.4</output>
<gadget id="calculator">1.4 * 10</gadget>
<output>14</output>
<result>B</result> | B | 14 | At 1:00 pm, there were 10.0 grams of bacteria. The bacteria increased to x grams at 4:00 pm, and 19.6 grams at 7:00 pm. If the amount of bacteria present increased by the same fraction during each of the 3-hour periods, how many grams of bacteria were present at 4:00 pm? | {
"A": "13.7",
"B": "14.0",
"C": "14.3",
"D": "14.6",
"E": "14.9"
} | multiply(sqrt(divide(19.6, 10.0)), 10.0) | divide(n5,n2)|sqrt(#0)|multiply(#1,n2)| | "let x be the factor by which the bacteria increases every three hours . at 4 : 00 pm , the amount of bacteria was 10 x and at 7 : 00 pm it was 10 x ^ 2 . 10 x ^ 2 = 19.6 x ^ 2 = 1.96 x = 1.4 at 4 : 00 pm , the amount of bacteria was 10 ( 1.4 ) = 14 grams . the answer is b ." | general |
math_qa__dcEpg4FsrrGPQuLp | A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 350. Find the total worth of the stock? Choose the correct choice: A) 20029 B) 20000 C) 20289 D) 17500 E) 20026 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(1/20) * (4/5)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/10) * (1/5)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/25) - (1/50)</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">350 / (1/50)</gadget>
<output>17_500</output>
<result>D</result> | D | 17,500 | A shopkeeper sells 20% of his stock at 10% profit ans sells the remaining at a loss of 5%. He incurred an overall loss of Rs. 350. Find the total worth of the stock? | {
"A": "20029",
"B": "20000",
"C": "20289",
"D": "17500",
"E": "20026"
} | divide(350, subtract(multiply(divide(5, const_100), divide(subtract(const_100, 20), const_100)), multiply(divide(10, const_100), divide(20, const_100)))) | divide(n2,const_100)|divide(n1,const_100)|divide(n0,const_100)|subtract(const_100,n0)|divide(#3,const_100)|multiply(#1,#2)|multiply(#0,#4)|subtract(#6,#5)|divide(n3,#7)| | "let the total worth of the stock be rs . x . the sp of 20 % of the stock = 1 / 5 * x * 1.1 = 11 x / 50 the sp of 80 % of the stock = 4 / 5 * x * 0.95 = 19 x / 25 = 38 x / 50 total sp = 11 x / 50 + 38 x / 50 = 49 x / 50 overall loss = x - 49 x / 50 = x / 50 x / 50 = 350 = > x = 17500 answer : d" | gain |
math_qa__cTiQ9FnU7XR0yVzn | If 3 spiders make 3 webs in 3 days, then 1 spider will make 1 web in how many days? Choose the correct choice from the following answers.
A) 7 B) 6 C) 5 D) 4 E) 3 | <gadget id="calculator">1 * 3</gadget>
<output>3</output>
<result>E</result> | E | 3 | If 3 spiders make 3 webs in 3 days, then 1 spider will make 1 web in how many days? | {
"A": "7",
"B": "6",
"C": "5",
"D": "4",
"E": "3"
} | multiply(1, 3) | multiply(n0,n3)| | "let the required number days be x . less spiders , more days ( indirect proportion ) less webs , less days ( direct proportion ) spiders 1 : 3 webs 3 : 1 1 x 3 x x = 3 x 1 x 3 = > x = 3 answer is e" | physics |
math_qa__4i30LT9unZklGiC0 | Light glows for every 30 seconds . How many max. times did it glow between 1:57:58 and 3:20:47 am.
Options:
A) 380 times
B) 142 times
C) 382 times
D) 392 times
E) 165 times | <gadget id="calculator">2 + 47</gadget>
<output>49</output>
<gadget id="calculator">2 + 60</gadget>
<output>62</output>
<gadget id="calculator">20 + 62</gadget>
<output>82</output>
<gadget id="calculator">82 * 60</gadget>
<output>4_920</output>
<gadget id="calculator">49 + 4_920</gadget>
<output>4_969</output>
<gadget id="calculator">4_969 / 30</gadget>
<output>4_969/30 = around 165.633333</output>
<result>E</result> | E | 165 | Light glows for every 30 seconds . How many max. times did it glow between 1:57:58 and 3:20:47 am. | {
"A": "380 times",
"B": "142 times",
"C": "382 times",
"D": "392 times",
"E": "165 times"
} | divide(add(add(const_2, 47), multiply(add(20, add(const_2, const_60)), const_60)), 30) | add(n6,const_2)|add(const_2,const_60)|add(n5,#1)|multiply(#2,const_60)|add(#0,#3)|divide(#4,n0)| | "time difference is 1 hr , 22 min , 49 sec = 4969 sec . so , light glows floor ( 4969 / 30 ) = 165 times . answer : e" | general |
math_qa__Ju8iEkWmem2d3BPL | A man is 35 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is: Choices:
A) 14 years
B) 18 years
C) 20 years
D) 22 years
E) 33 years | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">35 - 2</gadget>
<output>33</output>
<gadget id="calculator">2 - 1</gadget>
<output>1</output>
<gadget id="calculator">33 / 1</gadget>
<output>33</output>
<result>E</result> | E | 33 | A man is 35 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is: | {
"A": "14 years",
"B": "18 years",
"C": "20 years",
"D": "22 years",
"E": "33 years"
} | divide(subtract(35, subtract(multiply(const_2, const_2), const_2)), subtract(const_2, const_1)) | multiply(const_2,const_2)|subtract(const_2,const_1)|subtract(#0,const_2)|subtract(n0,#2)|divide(#3,#1)| | "let the son ' s present age be x years . then , man ' s present age = ( x + 24 ) years . ( x + 35 ) + 2 = 2 ( x + 2 ) x + 37 = 2 x + 4 x = 33 . answer : e" | general |
math_qa__3qVpx1YVe0hyIeTN | P and Q invested in a business. The profit earned was divided in the ratio 4 : 6. If P invested Rs 60000, the amount invested by Q is Choose the correct choice from the following answers: A) 30000 B) 50000 C) 90000 D) 20000 E) 60000 | <gadget id="calculator">60_000 / 4</gadget>
<output>15_000</output>
<gadget id="calculator">15_000 * 6</gadget>
<output>90_000</output>
<result>C</result> | C | 90,000 | P and Q invested in a business. The profit earned was divided in the ratio 4 : 6. If P invested Rs 60000, the amount invested by Q is | {
"A": "30000",
"B": "50000",
"C": "90000",
"D": "20000",
"E": "60000"
} | multiply(divide(60000, 4), 6) | divide(n2,n0)|multiply(n1,#0)| | "let the amount invested by q = q 60000 : q = 4 : 6 ⇒ 60000 × 6 = 4 q ⇒ q = ( 60000 × 6 ) / 4 = 90000 answer is c ." | gain |
math_qa__DxHeBqM0rxelEioz | On Charlie's cell phone plan, he signed up for 8GB of data per 4 week period. If he went over the 8GB per month, it would cost him an extra $10.00 per GB.
In the first week, he used 2 GB; in the 2nd week, he used 3 GB; in the 3rd week, he used 5 GB; and in the 4th week, he used a whopping 10GB.
How much extra did Charlie need to pay on his cell phone bill? Choose the correct choice from the following choices: A) $ 120 B) $ 40 C) $ 80 D) $ 100 E) $ 140 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 + 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">20 - 8</gadget>
<output>12</output>
<gadget id="calculator">12 * 10</gadget>
<output>120</output>
<result>A</result> | A | 120 | On Charlie's cell phone plan, he signed up for 8GB of data per 4 week period. If he went over the 8GB per month, it would cost him an extra $10.00 per GB.
In the first week, he used 2 GB; in the 2nd week, he used 3 GB; in the 3rd week, he used 5 GB; and in the 4th week, he used a whopping 10GB.
How much extra did Charlie need to pay on his cell phone bill? | {
"A": "$ 120",
"B": "$ 40",
"C": "$ 80",
"D": "$ 100",
"E": "$ 140"
} | multiply(subtract(add(add(add(2, 3), 5), 10), 8), 10) | add(n4,n6)|add(n8,#0)|add(n3,#1)|subtract(#2,n0)|multiply(n3,#3) | to determine how much extra he would need to pay , you have to add all 4 weeks of gb usage ( 2 + 3 + 5 + 10 = 20 ) . to determine the extra amount of gb usage , you have to subtract the the original amount of gb ( 8 ) allowed on his plan . 20 - 8 = 12 to determine the extra cost on his cell phone plan , you have to multiply $ 10.00 per extra usage ( 12 ) for a total of $ 120.00 . the correct answer is a | general |
math_qa__S5w1peG37LnV4cTd | A pipe can fill a cistern in 44 minutes. Find the time in which 1/11 part of the cistern will be filled?
Choose the correct answer: A) 4 min B) 2 min C) 3 min D) 1 min E) 10 min | <gadget id="calculator">1 / 11</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">44 * (1/11)</gadget>
<output>4</output>
<result>A</result> | A | 4 | A pipe can fill a cistern in 44 minutes. Find the time in which 1/11 part of the cistern will be filled? | {
"A": "4 min",
"B": "2 min",
"C": "3 min",
"D": "1 min",
"E": "10 min"
} | multiply(44, divide(1, 11)) | divide(n1,n2)|multiply(n0,#0)| | "full cistern filled in = 44 minutes 1 / 11 part filled in = 44 * 1 / 11 = 4 minutes answer is a" | physics |
math_qa__pBZdmSNVa9OoUhTz | The weight of a hollow sphere is directly dependent on its surface area. The surface area of a sphere is 4π·R^2, where R is the radius of the sphere. If a hollow sphere of radius 0.15 cm made of a certain metal weighs 8 grams, a hollow sphere of radius 0.3 cm made of the same metal would weigh how many grams E? Choose the correct choice from the following options
A) e = 16 B) e = 32 C) e = 64 D) 128 E) 512 | <gadget id="calculator">8 * 4</gadget>
<output>32</output>
<result>B</result> | B | 32 | The weight of a hollow sphere is directly dependent on its surface area. The surface area of a sphere is 4π·R^2, where R is the radius of the sphere. If a hollow sphere of radius 0.15 cm made of a certain metal weighs 8 grams, a hollow sphere of radius 0.3 cm made of the same metal would weigh how many grams E? | {
"A": "e = 16",
"B": "e = 32",
"C": "e = 64",
"D": "128",
"E": "512"
} | multiply(8, 4) | multiply(n0,n3)| | "weight directly proportional to 4 pi r ^ 2 now , 4 pi is constant , so , weight is directly proportional to r ^ 2 . when radius = 0.15 , weight = 8 , so ( 0.15 ) ^ 2 proportional to 8 ; ( 0.15 ) ^ 2 * 4 proportional to 8 * 4 , solving further ( 0.15 ) ^ 2 * 2 ^ 2 = ( 0.15 * 2 ) ^ 2 = 0.3 ^ 2 ; so answer = 32 ( b )" | geometry |
math_qa__3j4Uupj4HlBTVCN3 | A train running at the speed of 54 km/hr crosses a pole in 7 seconds. Find the length of the train. Options
A) 150 meter B) 105 meter C) 140 meter D) 135 meter E) none of these | <gadget id="calculator">54 * 1_000</gadget>
<output>54_000</output>
<gadget id="calculator">54_000 / 3_600</gadget>
<output>15</output>
<gadget id="calculator">15 * 7</gadget>
<output>105</output>
<result>B</result> | B | 105 | A train running at the speed of 54 km/hr crosses a pole in 7 seconds. Find the length of the train. | {
"A": "150 meter",
"B": "105 meter",
"C": "140 meter",
"D": "135 meter",
"E": "none of these"
} | multiply(divide(multiply(54, const_1000), const_3600), 7) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "explanation : speed = 54 * ( 5 / 18 ) m / sec = 15 m / sec length of train ( distance ) = speed * time = 15 * 7 = 105 meter option b" | physics |
math_qa__WcSsV7Po3lyxD5VC | An order was placed for a carpet whose length and width were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and width were in the ratio 4 : 1 but were was no change in its perimeter. What is the ratio of the areas of the carpets? Choices.
A) 5 : 8 B) 3 : 2 C) 6 : 1 D) 8 : 7 E) 5 : 6 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">2 * (3 + 2)</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 / 5</gadget>
<output>1</output>
<gadget id="calculator">1 * 4</gadget>
<output>4</output>
<gadget id="calculator">6 / 4</gadget>
<output>3/2 = around 1.5</output>
<result>B</result> | B | 1.5 | An order was placed for a carpet whose length and width were in the ratio of 3 : 2. Subsequently, the dimensions of the carpet were altered such that its length and width were in the ratio 4 : 1 but were was no change in its perimeter. What is the ratio of the areas of the carpets? | {
"A": "5 : 8",
"B": "3 : 2",
"C": "6 : 1",
"D": "8 : 7",
"E": "5 : 6"
} | divide(rectangle_area(3, 2), rectangle_area(divide(divide(rectangle_perimeter(3, 2), const_2), add(4, 1)), multiply(divide(divide(rectangle_perimeter(3, 2), const_2), add(4, 1)), 4))) | add(n2,n3)|rectangle_area(n0,n1)|rectangle_perimeter(n0,n1)|divide(#2,const_2)|divide(#3,#0)|multiply(n2,#4)|rectangle_area(#4,#5)|divide(#1,#6) | let the length and width of one carpet be 3 x and 2 x . let the length and width of the other carpet be 4 y and y . 2 ( 3 x + 2 x ) = 2 ( 4 y + y ) 5 x = 5 y x = y the ratio of the areas of the carpet in both cases : = 3 x * 2 x : 4 y * y = 6 x ^ 2 : 4 y ^ 2 = 6 x ^ 2 : 4 x ^ 2 = 6 : 4 = 3 : 2 the answer is b . | geometry |
math_qa__KIRcTobLdcfQypLC | If the sides of a triangle are 26 cm, 24 cm and 20 cm, what is its area? Choices: A) 120 B) 772 C) 288 D) 266 E) 240 | <gadget id="calculator">24 * 20</gadget>
<output>480</output>
<gadget id="calculator">480 / 2</gadget>
<output>240</output>
<result>E</result> | E | 240 | If the sides of a triangle are 26 cm, 24 cm and 20 cm, what is its area? | {
"A": "120",
"B": "772",
"C": "288",
"D": "266",
"E": "240"
} | divide(multiply(24, 20), const_2) | multiply(n1,n2)|divide(#0,const_2)| | "the triangle with sides 26 cm , 24 cm and 20 cm is right angled , where the hypotenuse is 26 cm . area of the triangle = 1 / 2 * 24 * 20 = 240 cm 2 answer : e" | geometry |
math_qa__7a14L7qTrBtAIUUz | A metallic sheet is of rectangular shape with dimensions 48 m x 38 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is: Answers
A) 4830 B) 5632 C) 6420 D) 7500 E) 8960 | <gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">48 - 16</gadget>
<output>32</output>
<gadget id="calculator">38 - 16</gadget>
<output>22</output>
<gadget id="calculator">32 * 22 * 8</gadget>
<output>5_632</output>
<result>B</result> | B | 5,632 | A metallic sheet is of rectangular shape with dimensions 48 m x 38 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 8 m, the volume of the box (in m3) is: | {
"A": "4830",
"B": "5632",
"C": "6420",
"D": "7500",
"E": "8960"
} | volume_rectangular_prism(subtract(48, multiply(8, const_2)), subtract(38, multiply(8, const_2)), 8) | multiply(n2,const_2)|subtract(n0,#0)|subtract(n1,#0)|volume_rectangular_prism(n2,#1,#2)| | "l = ( 48 - 16 ) m = 32 m , b = ( 38 - 16 ) m = 22 m , h = 8 m . volume of the box = ( 32 x 22 x 8 ) m 3 = 5632 m 3 . answer : option b" | geometry |
math_qa__tDYjchD3CzYPklJI | It takes 40 identical printing presses 9 hours to print 500,000 papers. How many hours would it take 30 of these printing presses to print 500,000 papers? Answers
A) 9 B) 10 C) 11 D) 12 E) 13 | <gadget id="calculator">1_000 / 2</gadget>
<output>500</output>
<gadget id="calculator">500 * 1_000</gadget>
<output>500_000</output>
<gadget id="calculator">500_000 / 40</gadget>
<output>12_500</output>
<gadget id="calculator">12_500 / 9</gadget>
<output>12_500/9 = around 1_388.888889</output>
<gadget id="calculator">(12_500/9) * 30</gadget>
<output>125_000/3 = around 41_666.666667</output>
<gadget id="calculator">500_000 / (125_000/3)</gadget>
<output>12</output>
<result>D</result> | D | 12 | It takes 40 identical printing presses 9 hours to print 500,000 papers. How many hours would it take 30 of these printing presses to print 500,000 papers? | {
"A": "9",
"B": "10",
"C": "11",
"D": "12",
"E": "13"
} | divide(multiply(divide(const_1000, const_2), const_1000), multiply(divide(divide(multiply(divide(const_1000, const_2), const_1000), 40), 9), 30)) | divide(const_1000,const_2)|multiply(#0,const_1000)|divide(#1,n0)|divide(#2,n1)|multiply(n3,#3)|divide(#1,#4)| | "40 printing presses can do 1 / 9 of the job each hour . 30 printing presses can do 3 / 4 * 1 / 9 = 1 / 12 of the job each hour . the answer is d ." | physics |
math_qa__NGQOhbvVJWNtUKBE | How many numbers between 100 and 600 are divisible by 2, 3, and 7 together? Choose the correct choice from the following options
A) 11 B) 12 C) 14 D) 16 E) 18 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 7</gadget>
<output>42</output>
<gadget id="calculator">600 / 42</gadget>
<output>100/7 = around 14.285714</output>
<gadget id="calculator">100 / 42</gadget>
<output>50/21 = around 2.380952</output>
<gadget id="calculator">(100/7) - (50/21)</gadget>
<output>250/21 = around 11.904762</output>
<result>B</result> | B | 12 | How many numbers between 100 and 600 are divisible by 2, 3, and 7 together? | {
"A": "11",
"B": "12",
"C": "14",
"D": "16",
"E": "18"
} | subtract(divide(600, multiply(multiply(2, 3), 7)), divide(100, multiply(multiply(2, 3), 7))) | multiply(n2,n3)|multiply(n4,#0)|divide(n1,#1)|divide(n0,#1)|subtract(#2,#3)| | "explanation : as the division is by 2 , 3 , 7 together , the numbers are to be divisible by : 2 * 3 * 7 = 42 the limits are 100 and 600 the first number divisible is 42 * 3 = 126 to find out the last number divisible by 42 within 600 : 600 / 42 = 14.28 hence , 42 * 14 = 588 is the last number divisible by 42 within 600 hence , total numbers divisible by 2 , 3 , 7 together are ( 14 – 2 ) = 12 answer : b" | general |
math_qa__dwkxxytnMbbg0Szh | A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/5 hours to fill the tank. The leak can drain all the water of the tank in? Choose the most appropriate option
A) 17 hr B) 19 hr C) 22 hr D) 24 hr E) 26 hr | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 / 5</gadget>
<output>11/5 = around 2.2</output>
<gadget id="calculator">1 / (11/5)</gadget>
<output>5/11 = around 0.454545</output>
<gadget id="calculator">(1/2) - (5/11)</gadget>
<output>1/22 = around 0.045455</output>
<gadget id="calculator">1 / (1/22)</gadget>
<output>22</output>
<result>C</result> | C | 22 | A pump can fill a tank with water in 2 hours. Because of a leak, it took 2 1/5 hours to fill the tank. The leak can drain all the water of the tank in? | {
"A": "17 hr",
"B": "19 hr",
"C": "22 hr",
"D": "24 hr",
"E": "26 hr"
} | inverse(subtract(divide(1, 2), inverse(divide(add(multiply(2, 5), 1), 5)))) | divide(n2,n0)|multiply(n0,n3)|add(n2,#1)|divide(#2,n3)|inverse(#3)|subtract(#0,#4)|inverse(#5) | work done by the tank in 1 hour = ( 1 / 2 - 2 1 / 5 ) = 1 / 22 leak will empty the tank in 22 hrs . answer : c | physics |
math_qa__K2PmRoqGCjbM15tS | The Salary of a Labourer increase consistently by 40% per year. If his present salary is Rs. 3000 then what will his salary be after 3 years ?
Choices:
A) 8232 B) 3282 C) 4282 D) 8242 E) 2382 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 + (2/5)</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(7/5) ** 3</gadget>
<output>343/125 = around 2.744</output>
<gadget id="calculator">3_000 * (343/125)</gadget>
<output>8_232</output>
<result>A</result> | A | 8,232 | The Salary of a Labourer increase consistently by 40% per year. If his present salary is Rs. 3000 then what will his salary be after 3 years ? | {
"A": "8232",
"B": "3282",
"C": "4282",
"D": "8242",
"E": "2382"
} | multiply(3000, power(add(const_1, divide(40, const_100)), 3)) | divide(n0,const_100)|add(#0,const_1)|power(#1,n2)|multiply(n1,#2) | explanation : salary = 3000 x 1.4 x 1.4 x 1.4 = 8232 answer : option a | gain |
math_qa__m5IPOuDNV9EhGkQe | In country Z, 10% of the people do not have a university diploma but have the job of their choice, and 30% of the people who do not have the job of their choice have a university diploma. If 40% of the people have the job of their choice, what percent of the people have a university diploma?
Choose one:
A) 35 %
B) 48 %
C) 55 %
D) 65 %
E) 75 % | <gadget id="calculator">100 - 40</gadget>
<output>60</output>
<gadget id="calculator">30 * 60</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 100</gadget>
<output>18</output>
<gadget id="calculator">40 - 10</gadget>
<output>30</output>
<gadget id="calculator">18 + 30</gadget>
<output>48</output>
<result>B</result> | B | 48 | In country Z, 10% of the people do not have a university diploma but have the job of their choice, and 30% of the people who do not have the job of their choice have a university diploma. If 40% of the people have the job of their choice, what percent of the people have a university diploma? | {
"A": "35 %",
"B": "48 %",
"C": "55 %",
"D": "65 %",
"E": "75 %"
} | add(divide(multiply(30, subtract(const_100, 40)), const_100), subtract(40, 10)) | subtract(const_100,n2)|subtract(n2,n0)|multiply(n1,#0)|divide(#2,const_100)|add(#3,#1) | setting up a matrix is how i solve this one . diploma no diploma totals job of choice w / diploma job of choice w / o diploma = 10 % job of choice total = 40 % not job of choice with diploma = . 3 x not job of choice w / o diploma = . 7 x total not job of choice = x total with diploma total without diploma total citizen = 100 if 40 % of people have their job of choice , then 60 % of people do not have their job of choice . 30 % of 60 % = 18 % . we can also see that 30 % of the people have their job of choice and a diploma ( 40 % - 10 % = 30 % ) . 30 % + 18 % = 48 % . therefore 48 % of the people in country z have a diploma . ans b | gain |
math_qa__vLniXbhpUkVHbnB3 | In a house a hall is 20 m long, 15m wide and 5m high. Its interior has to be covered with mat. What will be the total expenditure if it costs Rs. 50 per square m? Choose the most appropriate option
A) s . 43000 B) s . 50000 C) s . 57000 D) s . 60000 E) s . 47500 | <gadget id="calculator">20 * 15</gadget>
<output>300</output>
<gadget id="calculator">300 * 2</gadget>
<output>600</output>
<gadget id="calculator">600 * 50</gadget>
<output>30_000</output>
<gadget id="calculator">20 * 5</gadget>
<output>100</output>
<gadget id="calculator">100 * 2</gadget>
<output>200</output>
<gadget id="calculator">200 * 50</gadget>
<output>10_000</output>
<gadget id="calculator">30_000 + 10_000</gadget>
<output>40_000</output>
<gadget id="calculator">15 * 5</gadget>
<output>75</output>
<gadget id="calculator">75 * 2</gadget>
<output>150</output>
<gadget id="calculator">150 * 50</gadget>
<output>7_500</output>
<gadget id="calculator">40_000 + 7_500</gadget>
<output>47_500</output>
<result>E</result> | E | 47,500 | In a house a hall is 20 m long, 15m wide and 5m high. Its interior has to be covered with mat. What will be the total expenditure if it costs Rs. 50 per square m? | {
"A": "s . 43000",
"B": "s . 50000",
"C": "s . 57000",
"D": "s . 60000",
"E": "s . 47500"
} | add(add(multiply(multiply(multiply(20, 15), const_2), 50), multiply(multiply(multiply(20, 5), const_2), 50)), multiply(multiply(multiply(15, 5), const_2), 50)) | multiply(n0,n1)|multiply(n0,n2)|multiply(n1,n2)|multiply(#0,const_2)|multiply(#1,const_2)|multiply(#2,const_2)|multiply(n3,#3)|multiply(n3,#4)|multiply(n3,#5)|add(#6,#7)|add(#9,#8)| | "length ( l ) = 20 m , breadth ( b ) = 15 m and height ( h ) = 5 m total area of the hall to be covered with mat = 2 ( lb + bh + hl ) = 2 ( 20 * 15 + 15 * 5 + 5 * 20 ) = 2 ( 300 + 75 + 100 ) = 2 * 475 = 950 sq . m total expenditure = 50 * 950 = rs . 47500 e" | general |
math_qa__nL2fgrfgYuzqk9WQ | There is a 55 cm line marked at each centimeter and an insect is placed at every centimeter. 9 frogs are trained to jump a constant distance. The first one jumps 2 cm in every leap, the second one jumps 3 cm and so on until the 9th one jumps 10 cm in every leap and they eat any insect that is available at that spot. If all of them start from start line and finish the entire 55 cm, how many insects were still left after the race was over? Choose the correct choice: A) 0 B) 3 C) 6 D) 9 E) 12 | <gadget id="calculator">10 + 2</gadget>
<output>12</output>
<result>E</result> | E | 12 | There is a 55 cm line marked at each centimeter and an insect is placed at every centimeter. 9 frogs are trained to jump a constant distance. The first one jumps 2 cm in every leap, the second one jumps 3 cm and so on until the 9th one jumps 10 cm in every leap and they eat any insect that is available at that spot. If all of them start from start line and finish the entire 55 cm, how many insects were still left after the race was over? | {
"A": "0",
"B": "3",
"C": "6",
"D": "9",
"E": "12"
} | add(10, 2) | add(n2,n5) | only the prime numbers greater than 10 and less than 55 were left . that is 11 , 13 , 17 , 19 , 23 , 29 , 31 , 37 , 41 , 43 , 47 , and 53 . the total is 12 . the answer is e . | physics |
math_qa__bDlbO9TKbtYXdb8f | There is enough provisions for 600 men in an army camp for 35 days. If there were 300 men less, how long will the provision last? Select the correct option: A) 40 days B) 50 days C) 60 days D) 70 days E) 80 days | <gadget id="calculator">600 * 35</gadget>
<output>21_000</output>
<gadget id="calculator">21_000 / 300</gadget>
<output>70</output>
<result>D</result> | D | 70 | There is enough provisions for 600 men in an army camp for 35 days. If there were 300 men less, how long will the provision last? | {
"A": "40 days",
"B": "50 days",
"C": "60 days",
"D": "70 days",
"E": "80 days"
} | divide(multiply(600, 35), 300) | multiply(n0,n1)|divide(#0,n2)| | "exp : we have , m 1 d 1 = m 2 d 2 600 * 35 = 300 * d 2 d 2 = 600 * 35 / 300 = 70 days . answer : d" | physics |
math_qa__3aLCBLqS1gCAH4vx | If 8 parallel lines in a plane is intersected by a family of another 8 parallel lines, how many parallelograms are there in the network thus formed?
Choose the correct answer:
A) 784 B) 763 C) 120 D) 160 E) 1260 | <gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">8 * 7</gadget>
<output>56</output>
<gadget id="calculator">56 / 2</gadget>
<output>28</output>
<gadget id="calculator">28 * 28</gadget>
<output>784</output>
<result>A</result> | A | 784 | If 8 parallel lines in a plane is intersected by a family of another 8 parallel lines, how many parallelograms are there in the network thus formed? | {
"A": "784",
"B": "763",
"C": "120",
"D": "160",
"E": "1260"
} | multiply(divide(multiply(8, subtract(8, const_1)), const_2), divide(multiply(8, subtract(8, const_1)), const_2)) | subtract(n0,const_1)|subtract(n1,const_1)|multiply(n0,#0)|multiply(n1,#1)|divide(#2,const_2)|divide(#3,const_2)|multiply(#4,#5)| | "parallelogram can formed by 2 horizontal and 2 vertical lines for horizontal 8 c 2 for vertical 8 c 2 total parallelogram is 10 c 2 * 8 c 2 = 28 * 28 = 784 answer : a" | physics |
math_qa__y7Ux3cGnkhBfAxG7 | There are 100 lights which are functional and each is controlled by a separate On/Off switch. Two children A and B start playing with the switches. A starts by pressing every third switch till he reaches the end. B, thereafter, presses every fifth switch till he too reaches the end. If all switches were in Off position at the beggining, How many lights are switched On by the end of this operation? Choose the correct option:
A) 13
B) 41
C) 47
D) 48
E) 53 | <gadget id="calculator">100 / 3</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">floor(100/3)</gadget>
<output>33</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">floor(20)</gadget>
<output>20</output>
<gadget id="calculator">33 + 20</gadget>
<output>53</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">100 / 15</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">floor(20/3)</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">53 - 12</gadget>
<output>41</output>
<result>B</result> | B | 41 | There are 100 lights which are functional and each is controlled by a separate On/Off switch. Two children A and B start playing with the switches. A starts by pressing every third switch till he reaches the end. B, thereafter, presses every fifth switch till he too reaches the end. If all switches were in Off position at the beggining, How many lights are switched On by the end of this operation? | {
"A": "13",
"B": "41",
"C": "47",
"D": "48",
"E": "53"
} | subtract(add(floor(divide(100, const_3)), floor(divide(100, add(const_1, const_4)))), multiply(floor(divide(100, multiply(const_3, add(const_1, const_4)))), const_2)) | add(const_1,const_4)|divide(n0,const_3)|divide(n0,#0)|floor(#1)|multiply(#0,const_3)|divide(n0,#4)|floor(#2)|add(#3,#6)|floor(#5)|multiply(#8,const_2)|subtract(#7,#9)| | "number of switches = 100 number of switches turned on by a : 3 , 6 , . . . 99 = 33 number of switches turned on by b : 5 , 10 , . . . . 100 = 20 few switches are turned on by a and later turned off by b : lcm ( 3,5 ) = 15 x = 15 , 30 , . . . . 90 = 6 . subtract the above 6 switches from both a and b as they are turned off . number of switches that are turned on = ( 33 - 6 ) + ( 20 - 6 ) = 41 answer : b" | other |
math_qa__x4SEUAMp9BAA9tLP | At a certain committee meeting only associate professors and assistant professors are present. Each associate professor has brought 2 pencils and 1 chart to the meeting, while each assistant professor has brought 1 pencil and 2 charts. If a total of 10 pencils and 14 charts have been brought to the meeting, how many people are present? Choices
A) 6 B) 7 C) 8 D) 9 E) 10 | <gadget id="calculator">14 + 10</gadget>
<output>24</output>
<gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">24 / 3</gadget>
<output>8</output>
<result>C</result> | C | 8 | At a certain committee meeting only associate professors and assistant professors are present. Each associate professor has brought 2 pencils and 1 chart to the meeting, while each assistant professor has brought 1 pencil and 2 charts. If a total of 10 pencils and 14 charts have been brought to the meeting, how many people are present? | {
"A": "6",
"B": "7",
"C": "8",
"D": "9",
"E": "10"
} | divide(add(14, 10), add(2, 1)) | add(n4,n5)|add(n0,n1)|divide(#0,#1) | say there are ' a ' associate professors . so we have 2 a pencils and a charts . say there are ' b ' assistant professors . so we have b pencils and 2 b charts . total pencils are 10 so 2 a + b = 10 total charts are 11 so a + 2 b = 14 add both : 3 a + 3 b = 24 so a + b = 8 total number of people = 8 c | general |
math_qa__HDfZzUVUh7jsRUX3 | I gain 70 paise on Rs.70. My gain percent is Options
A) 0.1 % B) 1 % C) 7 % D) 10 % E) none | <gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 100</gadget>
<output>70</output>
<gadget id="calculator">70 / 70</gadget>
<output>1</output>
<result>B</result> | B | 1 | I gain 70 paise on Rs.70. My gain percent is | {
"A": "0.1 %",
"B": "1 %",
"C": "7 %",
"D": "10 %",
"E": "none"
} | divide(multiply(divide(70, const_100), const_100), 70) | divide(n0,const_100)|multiply(#0,const_100)|divide(#1,n0)| | "solution gain % = ( 0.70 / 70 × 100 ) % = 1 % . answer b" | gain |
math_qa__7BDFFcwm6jwET2bL | 50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is 4 , then the rise in the water level in the tank will be: Choose the most appropriate option.
A) 22 B) 25 C) 32 D) 99 E) 88 | <gadget id="calculator">50 * 4</gadget>
<output>200</output>
<gadget id="calculator">40 * 20</gadget>
<output>800</output>
<gadget id="calculator">200 / 800</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) * 100</gadget>
<output>25</output>
<result>B</result> | B | 25 | 50 men took a dip in a water tank 40 m long and 20 m broad on a religious day. If the average displacement of water by a man is 4 , then the rise in the water level in the tank will be: | {
"A": "22",
"B": "25",
"C": "32",
"D": "99",
"E": "88"
} | multiply(divide(multiply(50, 4), multiply(40, 20)), const_100) | multiply(n0,n3)|multiply(n1,n2)|divide(#0,#1)|multiply(#2,const_100) | explanation : total volume of water displaced = ( 4 x 50 ) = 200 rise in water level = = 0.25 m = 25 cm answer : b ) 25 cm | physics |
math_qa__T2n4sXtaRF480uUz | The price of a T.V. set worth Rs. 10000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be? Choose one: A) 9000 B) 26699 C) 96000 D) 19000 E) 26711 | <gadget id="calculator">10_000 - 1_000</gadget>
<output>9_000</output>
<result>A</result> | A | 9,000 | The price of a T.V. set worth Rs. 10000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be? | {
"A": "9000",
"B": "26699",
"C": "96000",
"D": "19000",
"E": "26711"
} | subtract(10000, 1000) | subtract(n0,n2)| | "money paid in cash = rs . 1000 balance payment = ( 10000 - 1000 ) = rs . 9000 answer : a" | gain |
math_qa__8BlfUG3AN2W4UvR2 | Find the principle on a certain sum of money at 5% per annum for 3 years if the amount being Rs.1120? Answers: A) 974 B) 1067 C) 1977 D) 1056 E) 1097 | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">1_120 / (23/20)</gadget>
<output>22_400/23 = around 973.913043</output>
<result>A</result> | A | 974 | Find the principle on a certain sum of money at 5% per annum for 3 years if the amount being Rs.1120? | {
"A": "974",
"B": "1067",
"C": "1977",
"D": "1056",
"E": "1097"
} | divide(1120, add(const_1, divide(multiply(5, 3), const_100))) | multiply(n0,n1)|divide(#0,const_100)|add(#1,const_1)|divide(n2,#2)| | "1120 = p [ 1 + ( 5 * 3 ) / 100 ] p = 974 answer : a" | gain |
math_qa__xghYCS1HVYEGdTjd | How many two digit prime numbers are there in which both digits are prime numbers? (For
example, 23 is one of these numbers but 31 is not, since 1 is not a prime number.)
Pick:
A) 3 B) 4 C) 5 D) 8 E) 15 | <gadget id="calculator">31 % 23</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>B</result> | B | 4 | How many two digit prime numbers are there in which both digits are prime numbers? (For
example, 23 is one of these numbers but 31 is not, since 1 is not a prime number.) | {
"A": "3",
"B": "4",
"C": "5",
"D": "8",
"E": "15"
} | divide(reminder(31, 23), const_2) | reminder(n1,n0)|divide(#0,const_2) | the second digit can only be 3 or 7 , so the choice quickly narrows down to 23 , 27 , 33 , 37 , 53 , 57 , 73 , and 77 . of these , 27 , 33 , and 57 are divisible by 3 , and 77 by 7 , leaving 23 , 37 , 53 , and 73 . it is easy to see that none of these is divisible by 2 , 3 , 5 , or 7 , and there is no need to look at greater prime divisors since root 77 < 11 . correct answer b | other |
math_qa__gqllghA6GelrjUzB | A candidate got 35% of the votes polled and he lost to his rival by 2460 votes. How many votes were cast?
Options: A) 7500 B) 3388 C) 2665 D) 8200 E) 2661 | <gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">1 - (7/20)</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">(13/20) - (7/20)</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">2_460 / (3/10)</gadget>
<output>8_200</output>
<result>D</result> | D | 8,200 | A candidate got 35% of the votes polled and he lost to his rival by 2460 votes. How many votes were cast? | {
"A": "7500",
"B": "3388",
"C": "2665",
"D": "8200",
"E": "2661"
} | divide(2460, subtract(subtract(const_1, divide(35, const_100)), divide(35, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|subtract(#1,#0)|divide(n1,#2)| | "35 % - - - - - - - - - - - l 65 % - - - - - - - - - - - w - - - - - - - - - - - - - - - - - - 30 % - - - - - - - - - - 2460 100 % - - - - - - - - - ? = > 8200 answer : d" | gain |
math_qa__Ea4GZ2dq0XaQLfJi | { 8 , 46 , 53 , 127 } what number should be inserted in the set of 7 values to get a median of 9 ? Select:
A) 20
B) 14
C) 16
D) 5
E) 8 | <gadget id="calculator">127 / 9</gadget>
<output>127/9 = around 14.111111</output>
<result>B</result> | B | 14 | { 8 , 46 , 53 , 127 } what number should be inserted in the set of 7 values to get a median of 9 ? | {
"A": "20",
"B": "14",
"C": "16",
"D": "5",
"E": "8"
} | divide(127, 9) | divide(n3,n5) | median is the middle number of a sorted distribution . in case of even number of items , median will be the average of middle two values . the question asks fora new number that will cause the median of new set at 9 . mentionable that given set is already sorted and number of items of new set will be 7 + 1 = 8 . to get median 9 , the sum of 4 th 5 th term should be 18 and it ' s 5 + 14 . so to keep the median 9 , the new item should be > = 14 . the answer is b | general |
math_qa__BoSGxm1JzxqJ5EUQ | The ratio 2 : 3 expressed as a percent equals
Choose the most appropriate option.
A) 12.5 % B) 40 % C) 67 % D) 125 % E) none | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 100</gadget>
<output>200/3 = around 66.666667</output>
<result>C</result> | C | 67 | The ratio 2 : 3 expressed as a percent equals | {
"A": "12.5 %",
"B": "40 %",
"C": "67 %",
"D": "125 %",
"E": "none"
} | multiply(divide(2, 3), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "solution 2 : 3 = 2 / 3 = ( 2 / 3 x 100 ) % . = 66.6 % . answer c" | general |
math_qa__UJShL6qHJYVPUrrL | Two brother X and Y appeared for an exam. The probability of selection of X is 1/7 and that of B is 2/5. Find the probability that both of them are selected.
Choose the correct option
A) 2 / 69 B) 2 / 60 C) 2 / 63 D) 2 / 35 E) 2 / 38 | <gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/7) * (2/5)</gadget>
<output>2/35 = around 0.057143</output>
<result>D</result> | D | 0.057143 | Two brother X and Y appeared for an exam. The probability of selection of X is 1/7 and that of B is 2/5. Find the probability that both of them are selected. | {
"A": "2 / 69",
"B": "2 / 60",
"C": "2 / 63",
"D": "2 / 35",
"E": "2 / 38"
} | multiply(divide(1, 7), divide(2, 5)) | divide(n0,n1)|divide(n2,n3)|multiply(#0,#1)| | "explanation : let a be the event that x is selected and b is the event that y is selected . p ( a ) = 1 / 7 , p ( b ) = 2 / 5 . let c be the event that both are selected . p ( c ) = p ( a ) ã — p ( b ) as a and b are independent events : = ( 1 / 7 ) ã — ( 2 / 5 ) = 2 / 35 answer : d ) 2 / 35" | general |
math_qa__Pb8g59fCog97H4oW | 3 consecutive odd integers are in increasing order such that the sum of the last two integers is 17 more than the first integer . find the 3 integers ? Choose the correct answer
A) 11 , 1315 B) 7 , 2 , 10 C) 7 , 9 , 10 D) 7 , 9 , 11 E) 7 , 9 , 29 | <gadget id="calculator">17 - 1</gadget>
<output>16</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">16 - 4</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<result>A</result> | A | 11 | 3 consecutive odd integers are in increasing order such that the sum of the last two integers is 17 more than the first integer . find the 3 integers ? | {
"A": "11 , 1315",
"B": "7 , 2 , 10",
"C": "7 , 9 , 10",
"D": "7 , 9 , 11",
"E": "7 , 9 , 29"
} | subtract(multiply(divide(subtract(subtract(17, const_1), add(3, const_1)), const_2), const_2), const_1) | add(n0,const_1)|subtract(n1,const_1)|subtract(#1,#0)|divide(#2,const_2)|multiply(#3,const_2)|subtract(#4,const_1) | explanation : let the three consecutive odd integers be x , x + 2 and x + 4 respectively . x + 4 + x + 2 = x + 17 = > x = 11 hence three consecutive odd integers are 11 , 13 and 15 answer : a | general |
math_qa__3qiXJ8Xy7vI4dReG | What is the area of square field whose side of length 15 m? Choose the correct answer:
A) 225 sq m B) 186 sq m C) 586 sq m D) 287 sq m E) 296 sq m | <gadget id="calculator">15 ** 2</gadget>
<output>225</output>
<result>A</result> | A | 225 | What is the area of square field whose side of length 15 m? | {
"A": "225 sq m",
"B": "186 sq m",
"C": "586 sq m",
"D": "287 sq m",
"E": "296 sq m"
} | square_area(15) | square_area(n0) | 15 * 15 = 225 sq m answer : a | geometry |
math_qa__KlYBvF99eawOgpQ6 | At what rate percent per annum will a sum of money double in 16years?
Choose the correct choice from the following answers.
A) 10.6 % B) 3.65 % C) 6.25 % D) 8.32 % E) 11 % | <gadget id="calculator">100 / 16</gadget>
<output>25/4 = around 6.25</output>
<result>C</result> | C | 6.25 | At what rate percent per annum will a sum of money double in 16years? | {
"A": "10.6 %",
"B": "3.65 %",
"C": "6.25 %",
"D": "8.32 %",
"E": "11 %"
} | divide(const_100, 16) | divide(const_100,n0)| | "let principle = p s . i . = p t = 16 yrs rate = 100 * p / p * 16 = 25 / 4 % = 6.25 % answer is c" | gain |
math_qa__vKt5CeW1ao0Zitd8 | 10 business executives and 7 chairmen meet at a conference. If each business executive shakes the hand of every other business executive and every chairman once, and each chairman shakes the hand of each of the business executives but not the other chairmen, how many handshakes would take place? Choose the most appropriate option
A) 144 B) 131 C) 115 D) 90 E) 45 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">10 * 9</gadget>
<output>90</output>
<gadget id="calculator">90 / 2</gadget>
<output>45</output>
<gadget id="calculator">10 * 7</gadget>
<output>70</output>
<gadget id="calculator">45 + 70</gadget>
<output>115</output>
<result>C</result> | C | 115 | 10 business executives and 7 chairmen meet at a conference. If each business executive shakes the hand of every other business executive and every chairman once, and each chairman shakes the hand of each of the business executives but not the other chairmen, how many handshakes would take place? | {
"A": "144",
"B": "131",
"C": "115",
"D": "90",
"E": "45"
} | add(divide(multiply(10, subtract(10, const_1)), const_2), multiply(10, 7)) | multiply(n0,n1)|subtract(n0,const_1)|multiply(n0,#1)|divide(#2,const_2)|add(#3,#0)| | "there are 10 business exec and in each handshake 2 business execs are involved . hence 10 c 2 = 45 also , each of 10 exec will shake hand with every 7 other chairmen for total of 70 handshake . total = 45 + 70 = 115 ans : c" | geometry |
math_qa__7T09clsYQ4tAIh3n | In what ratio must water be mixed with milk to gain 16(2/3)% on selling the mixture at cost price? Choose the correct choice from the following options.
A) 1 : 6 B) 6 : 1 C) 2 : 3 D) 4 : 3 E) 3 : 2 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">16 + (2/3)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) / 100</gadget>
<output>1/6 = around 0.166667</output>
<result>A</result> | A | 0.166667 | In what ratio must water be mixed with milk to gain 16(2/3)% on selling the mixture at cost price? | {
"A": "1 : 6",
"B": "6 : 1",
"C": "2 : 3",
"D": "4 : 3",
"E": "3 : 2"
} | divide(add(16, divide(2, 3)), const_100) | divide(n1,n2)|add(n0,#0)|divide(#1,const_100)| | "explanation : let c . p . of 1 litre milk be re . 1 . s . p . of 1 litre of mixture = re . 1 , gain = 50 / 3 % c . p . of 1 litre of mixture = ( 100 x 3 / 350 x 1 ) = 6 / 7 by the rule of alligation , we have : ratio of water and milk = 1 / 7 : 6 / 7 = 1 : 6 . answer is a" | gain |
math_qa__qORULGtOFFrMVCXF | There are 6 people in the elevator. Their average weight is 154 lbs. Another person enters the elevator, and increases the average weight to 151 lbs. What is the weight of the 7th person. Choose the correct choice.
A) 133 B) 168 C) 189 D) 190 E) 200 | <gadget id="calculator">151 * 7</gadget>
<output>1_057</output>
<gadget id="calculator">6 * 154</gadget>
<output>924</output>
<gadget id="calculator">1_057 - 924</gadget>
<output>133</output>
<result>A</result> | A | 133 | There are 6 people in the elevator. Their average weight is 154 lbs. Another person enters the elevator, and increases the average weight to 151 lbs. What is the weight of the 7th person. | {
"A": "133",
"B": "168",
"C": "189",
"D": "190",
"E": "200"
} | subtract(multiply(151, 7), multiply(6, 154)) | multiply(n2,n3)|multiply(n0,n1)|subtract(#0,#1)| | "solution average of 7 people after the last one enters = 151 . â ˆ ´ required weight = ( 7 x 151 ) - ( 6 x 154 ) = 1057 - 924 = 133 . answer a" | general |
math_qa__2cofMvuSKUfYunkU | For any number Z, Z* is defined as the greatest positive even integer less than or equal to y. What is the value of 6.25 – 6.25*? Options: A) 1.5 B) 0.5 C) 6.25 D) 0.25 E) 6.0 | <gadget id="calculator">floor(6.25)</gadget>
<output>6</output>
<gadget id="calculator">6.25 - 6</gadget>
<output>0.25</output>
<result>D</result> | D | 0.25 | For any number Z, Z* is defined as the greatest positive even integer less than or equal to y. What is the value of 6.25 – 6.25*? | {
"A": "1.5",
"B": "0.5",
"C": "6.25",
"D": "0.25",
"E": "6.0"
} | subtract(6.25, floor(6.25)) | floor(n0)|subtract(n0,#0)| | "since z * is defined as the greatest positive even integer less than or equal to z , then 6.25 * = 6 ( the greatest positive even integer less than or equal to 6.25 is 6 ) . hence , 6.25 – 6.25 * = 6.25 - 6 = 0.25 answer : d ." | general |
math_qa__YZXNKSO4xVTlBCYD | A river boat leaves Silver Town and travels upstream to Gold Town at an average speed of 3 kilometers per hour. It returns by the same route at an average speed of 7 kilometers per hour. What is the average speed for the round-trip in kilometers per hour? Choose the most appropriate option.
A) 4.2
B) 7.1
C) 7.2
D) 7.5
E) 8.0 | <gadget id="calculator">3 * 7</gadget>
<output>21</output>
<gadget id="calculator">21 * 2</gadget>
<output>42</output>
<gadget id="calculator">3 + 7</gadget>
<output>10</output>
<gadget id="calculator">42 / 10</gadget>
<output>21/5 = around 4.2</output>
<result>A</result> | A | 4.2 | A river boat leaves Silver Town and travels upstream to Gold Town at an average speed of 3 kilometers per hour. It returns by the same route at an average speed of 7 kilometers per hour. What is the average speed for the round-trip in kilometers per hour? | {
"A": "4.2",
"B": "7.1",
"C": "7.2",
"D": "7.5",
"E": "8.0"
} | divide(multiply(multiply(3, 7), const_2), add(3, 7)) | add(n0,n1)|multiply(n0,n1)|multiply(#1,const_2)|divide(#2,#0) | pick a number which is lcm of 7 and 3 = 21 . upstream time = 21 / 3 = 7 hrs downstream time = 21 / 7 = 3 hrs total time = 10 hrs total distance = 42 average speed = 42 / 10 = 4.2 km / hr | physics |
math_qa__pydlo6aGLmz9hfpW | 6 friends visited a book stall and brought 6 books, and everyone decided to contribute equally to the total bill of $400. If one of the friends had a coupon for 5% off the total bill, and if each friend still contributed equally after the coupon was applied to the bill, how much did each friend pay? Choose the correct choice from the following answers
A) 62.12 B) 63 C) 63.33 D) 64 E) 65 | <gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">12 + 5</gadget>
<output>17</output>
<gadget id="calculator">400 / 17</gadget>
<output>400/17 = around 23.529412</output>
<gadget id="calculator">(400/17) * 3</gadget>
<output>1_200/17 = around 70.588235</output>
<gadget id="calculator">(1_200/17) - 4</gadget>
<output>1_132/17 = around 66.588235</output>
<gadget id="calculator">(1_132/17) - 3</gadget>
<output>1_081/17 = around 63.588235</output>
<result>C</result> | C | 63.33 | 6 friends visited a book stall and brought 6 books, and everyone decided to contribute equally to the total bill of $400. If one of the friends had a coupon for 5% off the total bill, and if each friend still contributed equally after the coupon was applied to the bill, how much did each friend pay? | {
"A": "62.12",
"B": "63",
"C": "63.33",
"D": "64",
"E": "65"
} | subtract(subtract(multiply(divide(400, add(add(6, 6), 5)), const_3), const_4), const_3) | add(n0,n0)|add(n3,#0)|divide(n2,#1)|multiply(#2,const_3)|subtract(#3,const_4)|subtract(#4,const_3) | at the non - discounted price , each friend would pay $ 66.66 , as $ 400 divided by 6 friends is $ 66.66 per friend . but if the bill is 5 % off , then each friend would pay 5 % less . 5 % of $ 66.66 is $ 3.33 , so each friend saves $ 3.33 and pays the remaining $ 63.33 correct option : option c | general |
math_qa__Eo5ssWbBuZ4A6ira | The average weight of 8 person's increases by 5 kg when a new person comes in place of one of them weighing 35 kg. What might be the weight of the new person? Choose the correct choice:
A) 80 kg B) 85 kg C) 75 kg D) 100 kg E) 110 kg | <gadget id="calculator">8 * 5</gadget>
<output>40</output>
<gadget id="calculator">40 + 35</gadget>
<output>75</output>
<result>C</result> | C | 75 | The average weight of 8 person's increases by 5 kg when a new person comes in place of one of them weighing 35 kg. What might be the weight of the new person? | {
"A": "80 kg",
"B": "85 kg",
"C": "75 kg",
"D": "100 kg",
"E": "110 kg"
} | add(multiply(8, 5), 35) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = ( 8 x 5 ) kg = 40 kg . weight of new person = ( 35 + 40 ) kg = 75 kg . answer : c" | general |
math_qa__1xly2bsqWWIq7SPY | The average marks of a class of 22 students is 40 and that of another class of 28 students is 60. Find the average marks of all the students? Options: A) 51.2 B) 59.5 C) 52.8 D) 52.5 E) 52.1 | <gadget id="calculator">22 * 40</gadget>
<output>880</output>
<gadget id="calculator">28 * 60</gadget>
<output>1_680</output>
<gadget id="calculator">880 + 1_680</gadget>
<output>2_560</output>
<gadget id="calculator">22 + 28</gadget>
<output>50</output>
<gadget id="calculator">2_560 / 50</gadget>
<output>256/5 = around 51.2</output>
<result>A</result> | A | 51.2 | The average marks of a class of 22 students is 40 and that of another class of 28 students is 60. Find the average marks of all the students? | {
"A": "51.2",
"B": "59.5",
"C": "52.8",
"D": "52.5",
"E": "52.1"
} | divide(add(multiply(22, 40), multiply(28, 60)), add(22, 28)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)| | "sum of the marks for the class of 22 students = 22 * 40 = 880 sum of the marks for the class of 28 students = 28 * 60 = 1680 sum of the marks for the class of 50 students = 880 + 1680 = 2560 average marks of all the students = 2560 / 50 = 51.2 answer : a" | general |
math_qa__3WO0fajW96gdfgpg | y = x^2 + bx + 512 cuts the x axis at (h, 0) and (k, 0). If h and k are integers, what is the least value of b? Choose the correct choice from the following answers
A) - 512
B) - 257
C) - 256
D) - 513
E) 128 | <gadget id="calculator">-512</gadget>
<output>-512</output>
<gadget id="calculator">(-512) - 1</gadget>
<output>-513</output>
<result>D</result> | D | -513 | y = x^2 + bx + 512 cuts the x axis at (h, 0) and (k, 0). If h and k are integers, what is the least value of b? | {
"A": "- 512",
"B": "- 257",
"C": "- 256",
"D": "- 513",
"E": "128"
} | subtract(negate(512), const_1) | negate(n1)|subtract(#0,const_1) | as the curve cuts the x - axis at ( h , 0 ) and ( k , 0 ) . therefore h , k are the roots of the quadratic equation . for the quadratic equation is in the form of ax ^ 2 + bx + c = 0 , the product of the roots = c / a = 512 / 1 = 256 and the sum of the roots = - b / a = - b 512 can be expressed as product of two numbers in the following ways : 1 * 512 2 * 256 4 * 128 8 * 64 16 * 32 the sum of the roots is maximum when the roots are 1 and 256 and the maximum sum is 1 + 512 = 513 . the least value possible for b is therefore - 513 . d | general |
math_qa__I10nJJbV7dZFEHMg | The slant height of a cone is 10 cm and radius of the base is 5 cm, find the curved surface of the cone. Choose the correct choice from the following answers:
A) 250 B) 170 C) 148 D) 157 E) 150 | <gadget id="calculator">pi * 5</gadget>
<output>5*pi = around 15.707963</output>
<gadget id="calculator">(5*pi) * 10</gadget>
<output>50*pi = around 157.079633</output>
<result>D</result> | D | 157 | The slant height of a cone is 10 cm and radius of the base is 5 cm, find the curved surface of the cone. | {
"A": "250",
"B": "170",
"C": "148",
"D": "157",
"E": "150"
} | multiply(multiply(const_pi, 5), 10) | multiply(n1,const_pi)|multiply(n0,#0)| | "π * 5 * 10 = 157 answer : d" | geometry |
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