id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__oxhlMjOjnSBAI85D | Find the area of a parallelogram with base 30 cm and height 12 cm? Options
A) 290 cm 2
B) 360 cm 2
C) 270 cm 2
D) 280 cm 2
E) 260 cm 2 | <gadget id="calculator">30 * 12</gadget>
<output>360</output>
<result>B</result> | B | 360 | Find the area of a parallelogram with base 30 cm and height 12 cm? | {
"A": "290 cm 2",
"B": "360 cm 2",
"C": "270 cm 2",
"D": "280 cm 2",
"E": "260 cm 2"
} | multiply(30, 12) | multiply(n0,n1)| | "area of a parallelogram = base * height = 30 * 12 = 360 cm 2 answer : b" | geometry |
math_qa__w9rwF1bvI9DGYenm | If 45-[28-{37-(15-*)}]= 57, then * is equal to: Choose the correct choice from the following:
A) - 29
B) - 19
C) 18
D) 29
E) 39 | <gadget id="calculator">28 - 37</gadget>
<output>-9</output>
<gadget id="calculator">(-9) + 15</gadget>
<output>6</output>
<gadget id="calculator">45 - 6</gadget>
<output>39</output>
<gadget id="calculator">57 - 39</gadget>
<output>18</output>
<result>C</result> | C | 18 | If 45-[28-{37-(15-*)}]= 57, then * is equal to: | {
"A": "- 29",
"B": "- 19",
"C": "18",
"D": "29",
"E": "39"
} | subtract(57, subtract(45, add(subtract(28, 37), 15))) | subtract(n1,n2)|add(n3,#0)|subtract(n0,#1)|subtract(n4,#2)| | "45 - [ 28 - { 37 - ( 15 - * ) } ] = 57 = > 45 - [ 28 - { 37 - 15 + * } ] = 57 45 - [ 28 - 37 + 15 - * ] = 57 = > 45 [ 43 - 37 - * ] = 57 45 - [ 6 - * ] = 57 = > 45 - 6 + * = 57 39 + * = 57 = > * = 57 - 39 = 18 answer : c" | general |
math_qa__IYKM0wo1ErcKfFlz | In a kilometer race, A beats B by 51 meters or 11 seconds. What time does A take to complete the race? Choose the correct choice from the following options:
A) 22
B) 190
C) 277
D) 204
E) 208 | <gadget id="calculator">1 * 1_000</gadget>
<output>1_000</output>
<gadget id="calculator">51 / 11</gadget>
<output>51/11 = around 4.636364</output>
<gadget id="calculator">1_000 / (51/11)</gadget>
<output>11_000/51 = around 215.686275</output>
<gadget id="calculator">(11_000/51) - 11</gadget>
<output>10_439/51 = around 204.686275</output>
<result>D</result> | D | 204 | In a kilometer race, A beats B by 51 meters or 11 seconds. What time does A take to complete the race? | {
"A": "22",
"B": "190",
"C": "277",
"D": "204",
"E": "208"
} | subtract(divide(multiply(const_1, const_1000), divide(51, 11)), 11) | divide(n0,n1)|multiply(const_1,const_1000)|divide(#1,#0)|subtract(#2,n1)| | "time taken by b run 1000 meters = ( 1000 * 11 ) / 51 = 215 sec . time taken by a = 215 - 11 = 204 sec . answer : d" | physics |
math_qa__ZIovtuVijsRFozzs | A person borrows Rs.5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 6% p.a for 2 years. Find his gain in the transaction per year.
Choose the correct choice from the following options.
A) 100 B) 150 C) 225 D) 112.5 E) 212.5 | <gadget id="calculator">5_000 * 6</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 * 2</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 100</gadget>
<output>600</output>
<gadget id="calculator">5_000 * 4</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 * 2</gadget>
<output>40_000</output>
<gadget id="calculator">40_000 / 100</gadget>
<output>400</output>
<gadget id="calculator">600 - 400</gadget>
<output>200</output>
<gadget id="calculator">200 / 2</gadget>
<output>100</output>
<result>A</result> | A | 100 | A person borrows Rs.5000 for 2 years at 4% p.a. simple interest. He immediately lends it to another person at 6% p.a for 2 years. Find his gain in the transaction per year. | {
"A": "100",
"B": "150",
"C": "225",
"D": "112.5",
"E": "212.5"
} | divide(subtract(divide(multiply(multiply(5000, 6), 2), const_100), divide(multiply(multiply(5000, 4), 2), const_100)), 2) | multiply(n0,n3)|multiply(n0,n2)|multiply(n1,#0)|multiply(n1,#1)|divide(#2,const_100)|divide(#3,const_100)|subtract(#4,#5)|divide(#6,n1)| | "explanation : the person borrows rs . 5000 for 2 years at 4 % p . a . simple interest simple interest that he needs to pay = prt / 100 = 5000 × 4 × 2 / 100 = 400 he also lends it at 6 % p . a for 2 years simple interest that he gets = prt / 100 = 5000 × 6 × 2 / 100 = 600 his overall gain in 2 years = rs . 600 - rs . 400 = rs . 200 his overall gain in 1 year = 200 / 2 = rs . 100 answer : option a" | gain |
math_qa__MqaQeirDS146uoJG | Shop Offered 25% offer for every Shirt, Smith bought a shirt at Rs. 560. and What was the shop's original selling Price? Choose the correct choice
A) 500 B) 550 C) 746 D) 700 E) 750 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">560 / (3/4)</gadget>
<output>2_240/3 = around 746.666667</output>
<result>C</result> | C | 746 | Shop Offered 25% offer for every Shirt, Smith bought a shirt at Rs. 560. and What was the shop's original selling Price? | {
"A": "500",
"B": "550",
"C": "746",
"D": "700",
"E": "750"
} | divide(560, subtract(const_1, divide(25, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1) | sp * ( 75 / 100 ) = 560 sp = 7.46 * 100 = > cp = 746 answer : c | gain |
math_qa__ycS9ktAWFPyVNdyP | What is the least number of square tiles required to pave the floor of a room 10 m 17 cm long and 9m 9 cm broad? Choose the correct choice from the following choices: A) 724 B) 804 C) 11413 D) 844 E) none | <gadget id="calculator">9 * 100</gadget>
<output>900</output>
<gadget id="calculator">900 + 9</gadget>
<output>909</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">909 * 1_000</gadget>
<output>909_000</output>
<gadget id="calculator">9 ** 2</gadget>
<output>81</output>
<gadget id="calculator">909_000 / 81</gadget>
<output>101_000/9 = around 11_222.222222</output>
<result>C</result> | C | 11,413 | What is the least number of square tiles required to pave the floor of a room 10 m 17 cm long and 9m 9 cm broad? | {
"A": "724",
"B": "804",
"C": "11413",
"D": "844",
"E": "none"
} | divide(multiply(add(multiply(9, const_100), 9), multiply(10, const_100)), power(9, const_2)) | multiply(n2,const_100)|multiply(n0,const_100)|power(n3,const_2)|add(n3,#0)|multiply(#3,#1)|divide(#4,#2)| | "solution length of largest tile = h . c . f . of 1017 cm & 909 cm = 9 cm . area of each tile = ( 9 x 9 ) cm 2 ∴ required number of tiles = [ 1017 x 909 / 9 x 9 ] = 11413 . answer c" | physics |
math_qa__ucQLGIbUzgx02gFK | the sum of 3 consecutive odd natural numbers , each divisible by 3 is 72 . what is the largest among them ?
Pick one: A) 21 B) 24 C) 27 D) 36 E) 45 | <gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">72 - 9</gadget>
<output>63</output>
<gadget id="calculator">63 / 3</gadget>
<output>21</output>
<gadget id="calculator">21 + 6</gadget>
<output>27</output>
<result>C</result> | C | 27 | the sum of 3 consecutive odd natural numbers , each divisible by 3 is 72 . what is the largest among them ? | {
"A": "21",
"B": "24",
"C": "27",
"D": "36",
"E": "45"
} | add(divide(subtract(72, add(add(const_3, const_3), 3)), 3), add(const_3, const_3)) | add(const_3,const_3)|add(n0,#0)|subtract(n2,#1)|divide(#2,n0)|add(#0,#3) | let the 3 consecutive odd numbers each divisible by 3 be x , x + 3 , x + 6 given , x + x + 3 + x + 6 = 72 3 x = 63 x = 21 the numbers are 21 , 24 , 27 therefore the largest number is 27 answer c . | general |
math_qa__3y1ia5znUyJXNV08 | Consider a lady took a loan from a bank at the rate of 12% p.a. simple interest. After 3 years she had to pay Rs. 5400 interest only for the period. The principal amount borrowed by her was
Choose the correct choice from the following choices
A) rs . 2000
B) rs . 10000
C) rs . 15000
D) rs . 20000
E) none of these | <gadget id="calculator">3 * 12</gadget>
<output>36</output>
<gadget id="calculator">36 / 100</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">5_400 / (9/25)</gadget>
<output>15_000</output>
<result>C</result> | C | 15,000 | Consider a lady took a loan from a bank at the rate of 12% p.a. simple interest. After 3 years she had to pay Rs. 5400 interest only for the period. The principal amount borrowed by her was | {
"A": "rs . 2000",
"B": "rs . 10000",
"C": "rs . 15000",
"D": "rs . 20000",
"E": "none of these"
} | divide(5400, divide(multiply(3, 12), const_100)) | multiply(n0,n1)|divide(#0,const_100)|divide(n2,#1)| | "explanation : principal = rs . ( 100 × 5400 / 12 × 3 ) = > rs . 15,000 . answer : c" | gain |
math_qa__GwLzRLkFgVJnJ2uF | A store reported total sales of $385 million for February of this year. If the total sales for the same month last year was $320 million, approximately what was the percent increase Q in sales? Choose the correct choice from the following:
A) 2 % B) 17 % C) 20 % D) 65 % E) 83 % | <gadget id="calculator">385 - 320</gadget>
<output>65</output>
<gadget id="calculator">65 / 320</gadget>
<output>13/64 = around 0.203125</output>
<gadget id="calculator">(13/64) * 100</gadget>
<output>325/16 = around 20.3125</output>
<result>C</result> | C | 20 | A store reported total sales of $385 million for February of this year. If the total sales for the same month last year was $320 million, approximately what was the percent increase Q in sales? | {
"A": "2 %",
"B": "17 %",
"C": "20 %",
"D": "65 %",
"E": "83 %"
} | multiply(divide(subtract(385, 320), 320), const_100) | subtract(n0,n1)|divide(#0,n1)|multiply(#1,const_100)| | "last year ' s sales = $ 320 million ; this year ' s sales = $ 385 million ; increase q = $ 65 million . now , 20 % of $ 320 million is $ 64 million , which is very close to actual increase of $ 65 million . answer : c ." | general |
math_qa__lup2HHqSMrP7mlTw | If N = 3^0.15 and N^b = 9, b must equal Pick.
A) 3 / 80
B) 3 / 5
C) 4
D) 5 / 3
E) 40 / 3 | <gadget id="calculator">log(9)</gadget>
<output>log(9) = around 2.197225</output>
<gadget id="calculator">3 ** 0.15</gadget>
<output>1.179148</output>
<gadget id="calculator">log(1.179148)</gadget>
<output>0.164792</output>
<gadget id="calculator">log(9) / 0.164792</gadget>
<output>6.06825574056993*log(9) = around 13.333321</output>
<result>E</result> | E | 13.333333 | If N = 3^0.15 and N^b = 9, b must equal | {
"A": "3 / 80",
"B": "3 / 5",
"C": "4",
"D": "5 / 3",
"E": "40 / 3"
} | divide(log(9), log(power(3, 0.15))) | log(n2)|power(n0,n1)|log(#1)|divide(#0,#2)| | "15 / 100 = 3 / 20 n = 3 ^ 3 / 20 n ^ b = 3 ^ 2 ( 3 ^ 3 / 20 ) ^ b = 3 ^ 2 b = 40 / 3 answer : e" | general |
math_qa__nabytwb3L4Y1fXQa | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 36 hours and 16 hours respectively. The ratio of their speeds is?
Options:
A) 4 : 5 B) 4 : 3 C) 4 : 6 D) 4 : 9 E) 4 : 2 | <gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<gadget id="calculator">4 / 6</gadget>
<output>2/3 = around 0.666667</output>
<result>C</result> | C | 0.666667 | Two trains, one from Howrah to Patna and the other from Patna to Howrah, start simultaneously. After they meet, the trains reach their destinations after 36 hours and 16 hours respectively. The ratio of their speeds is? | {
"A": "4 : 5",
"B": "4 : 3",
"C": "4 : 6",
"D": "4 : 9",
"E": "4 : 2"
} | divide(sqrt(16), sqrt(36)) | sqrt(n1)|sqrt(n0)|divide(#0,#1)| | "let us name the trains a and b . then , ( a ' s speed ) : ( b ' s speed ) = √ b : √ a = √ 16 : √ 36 = 4 : 6 answer : c" | physics |
math_qa__Eq4F7Dr4TIbfXL2o | John makes $55 a week from his job. He earns a raise andnow makes $60 a week. What is the % increase?
Answers.
A) 16 % B) 9.66 % C) 9.09 % D) 9.98 % E) 17 % | <gadget id="calculator">60 - 55</gadget>
<output>5</output>
<gadget id="calculator">5 / 55</gadget>
<output>1/11 = around 0.090909</output>
<gadget id="calculator">(1/11) * 100</gadget>
<output>100/11 = around 9.090909</output>
<result>C</result> | C | 9.09 | John makes $55 a week from his job. He earns a raise andnow makes $60 a week. What is the % increase? | {
"A": "16 %",
"B": "9.66 %",
"C": "9.09 %",
"D": "9.98 %",
"E": "17 %"
} | multiply(divide(subtract(60, 55), 55), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "increase = ( 5 / 55 ) * 100 = ( 1 / 11 ) * 100 = 9.09 % . c" | gain |
math_qa__VwiA33Nw65wUmh1D | The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8748, its purchase price was Select the correct option: A) rs . 12008 B) rs . 12000 C) rs . 12002 D) rs . 1229 E) rs . 12021 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 3</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">8_748 / (7/10)</gadget>
<output>87_480/7 = around 12_497.142857</output>
<result>B</result> | B | 12,000 | The value of a machine depreciates at the rate of 10% every year. It was purchased 3 years ago. If its present value is Rs. 8748, its purchase price was | {
"A": "rs . 12008",
"B": "rs . 12000",
"C": "rs . 12002",
"D": "rs . 1229",
"E": "rs . 12021"
} | divide(8748, subtract(const_1, multiply(divide(10, const_100), 3))) | divide(n0,const_100)|multiply(n1,#0)|subtract(const_1,#1)|divide(n2,#2) | explanation : = rs . 12000 answer : b | gain |
math_qa__nAI4yjmmmYrJVptE | The price of commodity X increases by 30 cents every year, while the price of commodity Y increases by 20 cents every year. If in 2001, the price of commodity X was $4.20 and the price of commodity Y was $4.40, in which year will commodity X cost 70 cents more than the commodity Y? Choose the correct choice from the following answers:
A) 2010 B) 2011 C) 2012 D) 2013 E) 2014 | <gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">4.4 - 4.2</gadget>
<output>0.2</output>
<gadget id="calculator">(7/10) + 0.2</gadget>
<output>0.9</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) - 0.2</gadget>
<output>0.1</output>
<gadget id="calculator">0.9 / 0.1</gadget>
<output>9</output>
<gadget id="calculator">2_001 + 9</gadget>
<output>2_010</output>
<result>A</result> | A | 2,010 | The price of commodity X increases by 30 cents every year, while the price of commodity Y increases by 20 cents every year. If in 2001, the price of commodity X was $4.20 and the price of commodity Y was $4.40, in which year will commodity X cost 70 cents more than the commodity Y? | {
"A": "2010",
"B": "2011",
"C": "2012",
"D": "2013",
"E": "2014"
} | add(2001, divide(add(divide(70, const_100), subtract(4.40, 4.20)), subtract(divide(30, const_100), subtract(4.40, 4.20)))) | divide(n5,const_100)|divide(n0,const_100)|subtract(n4,n3)|add(#0,#2)|subtract(#1,#2)|divide(#3,#4)|add(n2,#5)| | "the cost of commodity x increases by 10 cents per year relative to commodity y . the price of x must gain 20 + 70 = 90 cents on commodity y , which will take 9 years . the answer is a ." | general |
math_qa__Vurhqa3whLpdYRZN | How many bricks, each measuring 100 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm? Pick one.
A) 1600 B) 2400 C) 5500 D) 7400 E) 3400 | <gadget id="calculator">8 * 100</gadget>
<output>800</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">800 * 600</gadget>
<output>480_000</output>
<gadget id="calculator">480_000 * 22.5</gadget>
<output>10_800_000</output>
<gadget id="calculator">100 * 11.25</gadget>
<output>1_125</output>
<gadget id="calculator">1_125 * 6</gadget>
<output>6_750</output>
<gadget id="calculator">10_800_000 / 6_750</gadget>
<output>1_600</output>
<result>A</result> | A | 1,600 | How many bricks, each measuring 100 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm? | {
"A": "1600",
"B": "2400",
"C": "5500",
"D": "7400",
"E": "3400"
} | divide(multiply(multiply(multiply(8, const_100), multiply(6, const_100)), 22.5), multiply(multiply(100, 11.25), 6)) | multiply(n3,const_100)|multiply(n4,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(n2,#2)|multiply(n5,#3)|divide(#5,#4)| | "number of bricks = volume of the wall / volume of 1 brick = ( 800 x 600 x 22.5 ) / ( 100 x 11.25 x 6 ) = 1600 answer : a" | physics |
math_qa__gnhUPlhyY3nQpDvR | A group of men decided to do a work in 20 days, but 10 of them became absent. If the rest of the group did the work in 40 days, Find the original number of men?
Choices:
A) 20 B) 50 C) 40 D) 100 E) 25 | <gadget id="calculator">10 * 40</gadget>
<output>400</output>
<gadget id="calculator">40 - 20</gadget>
<output>20</output>
<gadget id="calculator">400 / 20</gadget>
<output>20</output>
<result>A</result> | A | 20 | A group of men decided to do a work in 20 days, but 10 of them became absent. If the rest of the group did the work in 40 days, Find the original number of men? | {
"A": "20",
"B": "50",
"C": "40",
"D": "100",
"E": "25"
} | divide(multiply(10, 40), subtract(40, 20)) | multiply(n1,n2)|subtract(n2,n0)|divide(#0,#1)| | "original number of men = 10 * 40 / ( 40 - 20 ) = 20 answer is a" | physics |
math_qa__OojbdBW7VypzDAKo | Mr. Karan borrowed a certain amount at 6% per annum simple interest for 9 years. After 9 years, he returned Rs. 8310/-. Find out the amount that he borrowed. Pick: A) s . 5266 B) s . 5396 C) s . 5228 D) s . 5218 E) s . 52192 | <gadget id="calculator">6 * 9</gadget>
<output>54</output>
<gadget id="calculator">54 / 100</gadget>
<output>27/50 = around 0.54</output>
<gadget id="calculator">1 + (27/50)</gadget>
<output>77/50 = around 1.54</output>
<gadget id="calculator">8_310 / (77/50)</gadget>
<output>415_500/77 = around 5_396.103896</output>
<result>B</result> | B | 5,396 | Mr. Karan borrowed a certain amount at 6% per annum simple interest for 9 years. After 9 years, he returned Rs. 8310/-. Find out the amount that he borrowed. | {
"A": "s . 5266",
"B": "s . 5396",
"C": "s . 5228",
"D": "s . 5218",
"E": "s . 52192"
} | divide(8310, add(const_1, divide(multiply(6, 9), const_100))) | multiply(n0,n1)|divide(#0,const_100)|add(#1,const_1)|divide(n3,#2)| | "explanation : let us assume mr . karan borrowed amount is rs . a . ( the principal ) by formula of simple interest , s . i . = prt / 100 where p = the principal , r = rate of interest as a % , t = time in years s . i . = ( p * 6 * 9 ) / 100 = 54 p / 100 amount = principal + s . i . 8310 = p + ( 54 p / 100 ) 8310 = ( 100 p + 54 p ) / 100 8310 = 154 p / 100 p = ( 8310 * 100 ) / 154 = rs . 5396.104 answer : b" | gain |
math_qa__lPeBettj1E2EjydD | An article is bought for Rs.980 and sold for Rs.788, find the loss percent? Pick:
A) 16 %
B) 19 %
C) 17 %
D) 13 %
E) 12 % | <gadget id="calculator">788 * 100</gadget>
<output>78_800</output>
<gadget id="calculator">78_800 / 980</gadget>
<output>3_940/49 = around 80.408163</output>
<gadget id="calculator">100 - (3_940/49)</gadget>
<output>960/49 = around 19.591837</output>
<result>B</result> | B | 19 | An article is bought for Rs.980 and sold for Rs.788, find the loss percent? | {
"A": "16 %",
"B": "19 %",
"C": "17 %",
"D": "13 %",
"E": "12 %"
} | subtract(const_100, divide(multiply(788, const_100), 980)) | multiply(n1,const_100)|divide(#0,n0)|subtract(const_100,#1)| | "980 - - - - 192 100 - - - - ? = > 19 % answer : b" | gain |
math_qa__aOu3wSBswGBksiCE | Out of 15 students in a class, 7 are from Maharashtra, 5 are from Karnataka, and 3 are from Goa. Four students are to be selected at random. What are the chances that at least one is from Karnataka? Choose the most appropriate option.
A) 12 / 13 B) 11 / 13 C) 10 / 15 D) 1 / 15 E) 4 / 14 | <gadget id="calculator">factorial(15)</gadget>
<output>1_307_674_368_000</output>
<gadget id="calculator">15 - 4</gadget>
<output>11</output>
<gadget id="calculator">factorial(11)</gadget>
<output>39_916_800</output>
<gadget id="calculator">1_307_674_368_000 / 39_916_800</gadget>
<output>32_760</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">32_760 / 24</gadget>
<output>1_365</output>
<gadget id="calculator">15 - 5</gadget>
<output>10</output>
<gadget id="calculator">factorial(10)</gadget>
<output>3_628_800</output>
<gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">3_628_800 / 720</gadget>
<output>5_040</output>
<gadget id="calculator">5_040 / 24</gadget>
<output>210</output>
<gadget id="calculator">1_365 - 210</gadget>
<output>1_155</output>
<gadget id="calculator">1_155 / 1_365</gadget>
<output>11/13 = around 0.846154</output>
<result>B</result> | B | 0.846154 | Out of 15 students in a class, 7 are from Maharashtra, 5 are from Karnataka, and 3 are from Goa. Four students are to be selected at random. What are the chances that at least one is from Karnataka? | {
"A": "12 / 13",
"B": "11 / 13",
"C": "10 / 15",
"D": "1 / 15",
"E": "4 / 14"
} | divide(subtract(divide(divide(factorial(15), factorial(subtract(15, const_4))), factorial(const_4)), divide(divide(factorial(subtract(15, const_5)), factorial(subtract(subtract(15, const_5), const_4))), factorial(const_4))), divide(divide(factorial(15), factorial(subtract(15, const_4))), factorial(const_4))) | factorial(n0)|factorial(const_4)|subtract(n0,const_4)|subtract(n0,const_5)|factorial(#2)|factorial(#3)|subtract(#3,const_4)|divide(#0,#4)|factorial(#6)|divide(#7,#1)|divide(#5,#8)|divide(#10,#1)|subtract(#9,#11)|divide(#12,#9) | total possible ways of selecting 4 students out of 15 = 15 c 4 = ( 15 * 14 * 13 * 12 ) / ( 4 * 3 * 2 * 1 ) = 1365 the number of ways of selecting a 4 students in which no student belongs to karnataka = 10 c 4 number of ways of selecting atleast one student from karnataka = 15 c 4 - 10 c 4 = 1155 probability = 1155 / 1365 = 11 / 13 answer is b | probability |
math_qa__NJVj28TzwD7P6k2P | Suppose that f(x) is a function such that for every real number x,i)f(x)+f(1-x) = 10 and (ii) f(1+x) = 3+f(x). Then f(x)+f(-x)
must equal Choose the correct choice from the following choices:
A) 7
B) 9
C) 10
D) 11
E) 12 | <gadget id="calculator">10 - 3</gadget>
<output>7</output>
<result>A</result> | A | 7 | Suppose that f(x) is a function such that for every real number x,i)f(x)+f(1-x) = 10 and (ii) f(1+x) = 3+f(x). Then f(x)+f(-x)
must equal | {
"A": "7",
"B": "9",
"C": "10",
"D": "11",
"E": "12"
} | subtract(const_10, 3) | subtract(const_10,n3) | since ( ii ) holds for every real number x , it will remain valid if we replace x with - x . therefore , f ( 1 - x ) = 3 + f ( - x ) . now , from ( i ) , 10 = f ( x ) + f ( 1 - x ) = f ( x ) + 3 + f ( - x ) so that f ( x ) + f ( - x ) = 10 - 3 = 7 . ( observe that f ( x ) = 3 x + 4 satisfies the conditions in the problem . ) correct answer a | general |
math_qa__LApzSs2R7lGgJjVs | Each child has 12 crayons and 24 apples. If there are 18 children, how many crayons are there in total? Select the correct option:
A) 220
B) 65
C) 216
D) 219
E) 230 | <gadget id="calculator">18 * 12</gadget>
<output>216</output>
<result>C</result> | C | 216 | Each child has 12 crayons and 24 apples. If there are 18 children, how many crayons are there in total? | {
"A": "220",
"B": "65",
"C": "216",
"D": "219",
"E": "230"
} | multiply(18, 12) | multiply(n0,n2)| | 12 * 18 = 216 . answer is c . | general |
math_qa__j6d9P8hWSWq9Ajct | In a certain warehouse, 90 percent of the packages weigh less than 75 pounds, and a total of 48 packages weigh less than 25 pounds. If 80 percent of the packages weigh at least 25 pounds, how many of the packages weigh at least 25 pounds but less than 75 pounds? Select: A) 8 B) 64 C) 168 D) 102 E) 144 | <gadget id="calculator">100 - 80</gadget>
<output>20</output>
<gadget id="calculator">48 / 20</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 100</gadget>
<output>240</output>
<gadget id="calculator">240 * 90</gadget>
<output>21_600</output>
<gadget id="calculator">21_600 / 100</gadget>
<output>216</output>
<gadget id="calculator">216 - 48</gadget>
<output>168</output>
<result>C</result> | C | 168 | In a certain warehouse, 90 percent of the packages weigh less than 75 pounds, and a total of 48 packages weigh less than 25 pounds. If 80 percent of the packages weigh at least 25 pounds, how many of the packages weigh at least 25 pounds but less than 75 pounds? | {
"A": "8",
"B": "64",
"C": "168",
"D": "102",
"E": "144"
} | subtract(divide(multiply(multiply(divide(48, subtract(const_100, 80)), const_100), 90), const_100), 48) | subtract(const_100,n4)|divide(n2,#0)|multiply(#1,const_100)|multiply(n0,#2)|divide(#3,const_100)|subtract(#4,n2)| | "if 80 % of the packages weigh at least 25 pounds this means that 20 % of the packages weigh less than 25 pounds let t = total number of packages so , 20 % of t = # of packages that weigh less than 25 pounds 48 packages weigh less than 25 pounds great . so , 20 % of t = 48 rewrite to get : 0.2 t = 48 solve : t = 240 90 % of the packages weigh less than 75 pounds so , 90 % oft = number of packages that weigh less than 75 pounds 90 % of 240 = 216 , so 216 packages weigh less than 75 pounds of those 216 packages that weigh less than 75 pounds , 48 packages weigh less than 25 pounds . so , the number of packages that weight between 25 and 75 pounds = 216 - 48 = 168 = c" | general |
math_qa__5VMdsnNpsG6KUukC | If 425/999=0.125, what is the 81st digit to the right of the decimal point in the decimal equivalent of the fraction? Pick one:
A) 0 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<result>E</result> | E | 5 | If 425/999=0.125, what is the 81st digit to the right of the decimal point in the decimal equivalent of the fraction? | {
"A": "0",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | add(const_2, const_3) | add(const_2,const_3) | 0 . [ u ] 125 [ / u = 0.425425425 . . . . . every 3 rd digit is 5 and every multiple of 3 will be the digit 5 . since 81 is multiple of 3 , the 81 st digit is 5 . answer e | general |
math_qa__0raJO2q1JQZNsjqb | If p and q are prime numbers, how many divisors does the product p^2 * q^5 have? Answers.
A) 8
B) 10
C) 12
D) 15
E) 18 | <gadget id="calculator">2 + 1</gadget>
<output>3</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">3 * 6</gadget>
<output>18</output>
<result>E</result> | E | 18 | If p and q are prime numbers, how many divisors does the product p^2 * q^5 have? | {
"A": "8",
"B": "10",
"C": "12",
"D": "15",
"E": "18"
} | multiply(add(2, const_1), add(5, const_1)) | add(n0,const_1)|add(n1,const_1)|multiply(#0,#1)| | "when a number n = a ^ x * b ^ y , where a and b are prime numbers , and x , y are positive integers , the number of divisors of n = ( x + 1 ) ( y + 1 ) therefore , the answer is e . 3 * 6 = 18" | general |
math_qa__AQ6eOvI46t9UbsYL | a factory has 15 machines of equal efficiency in its factory . the annual manufacturing costs are rs . 42000 & establishment charges are rs . 12000 . the annual output of the company is rs . 70000 . the annual output and manufacturing costs are directly proportional to the number of machines . the shareholders get 12 . 512.5 profit , which is directly proportional to the annual output of the company . if 7 . 147.14 machines remain closed throughout the year , then the % decrease in the amountof profit of the shareholders would be ? Choose the correct option
A) 12.5 % B) 13.5 % C) 14 % D) 15 % E) 16 % | <gadget id="calculator">70_000 - 42_000</gadget>
<output>28_000</output>
<gadget id="calculator">28_000 - 12_000</gadget>
<output>16_000</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 28_000</gadget>
<output>14_000</output>
<gadget id="calculator">16_000 - 14_000</gadget>
<output>2_000</output>
<gadget id="calculator">15 + 1</gadget>
<output>16</output>
<gadget id="calculator">2_000 / 16</gadget>
<output>125</output>
<gadget id="calculator">125 / 10</gadget>
<output>25/2 = around 12.5</output>
<result>A</result> | A | 12.5 | a factory has 15 machines of equal efficiency in its factory . the annual manufacturing costs are rs . 42000 & establishment charges are rs . 12000 . the annual output of the company is rs . 70000 . the annual output and manufacturing costs are directly proportional to the number of machines . the shareholders get 12 . 512.5 profit , which is directly proportional to the annual output of the company . if 7 . 147.14 machines remain closed throughout the year , then the % decrease in the amountof profit of the shareholders would be ? | {
"A": "12.5 %",
"B": "13.5 %",
"C": "14 %",
"D": "15 %",
"E": "16 %"
} | divide(divide(subtract(subtract(subtract(70000, 42000), 12000), multiply(divide(const_1, const_2), subtract(70000, 42000))), add(15, const_1)), const_10) | add(n0,const_1)|divide(const_1,const_2)|subtract(n3,n1)|multiply(#1,#2)|subtract(#2,n2)|subtract(#4,#3)|divide(#5,#0)|divide(#6,const_10) | option ( b ) is correct original profit = 70,000 − 42,000 − 12,000 = 16 , 00070,000 − 42,000 − 12,000 = 16,000 if 7.14 % 7.14 % of 14 i . e . one of the machines closed throughout the year , then change in profit will be : = 1314 × [ 70,000 − 42,000 ] = 1314 × [ 70,000 − 42,000 ] = 14,000 = 14,000 thus , decrease in the profit % % = 200016000 × 100 = 200016000 × 100 = 12.5 % a | gain |
math_qa__r9tsvOHv1UJMbSYk | The H.C.F of two numbers is 23 and the other two factors of their L.C.M are 11 and 12. The larger of the two numbers is: Choose the most appropriate option.
A) 338 B) 276 C) 322 D) 231 E) 121 | <gadget id="calculator">23 * 12</gadget>
<output>276</output>
<result>B</result> | B | 276 | The H.C.F of two numbers is 23 and the other two factors of their L.C.M are 11 and 12. The larger of the two numbers is: | {
"A": "338",
"B": "276",
"C": "322",
"D": "231",
"E": "121"
} | multiply(23, 12) | multiply(n0,n2)| | "clearly , the numbers are ( 23 * 11 ) and ( 23 * 12 ) . larger number = ( 23 * 12 ) = 276 . answer : b" | other |
math_qa__uzhlV5EE0L1EC16D | The average of a batsman for 40 innings is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, his average drops by 2 runs. Find his highest score. Options.
A) 172
B) 173
C) 174
D) 175
E) none of the above | <gadget id="calculator">40 * 50</gadget>
<output>2_000</output>
<gadget id="calculator">40 - 2</gadget>
<output>38</output>
<gadget id="calculator">50 - 2</gadget>
<output>48</output>
<gadget id="calculator">38 * 48</gadget>
<output>1_824</output>
<gadget id="calculator">2_000 - 1_824</gadget>
<output>176</output>
<gadget id="calculator">176 - 172</gadget>
<output>4</output>
<gadget id="calculator">4 / 2</gadget>
<output>2</output>
<gadget id="calculator">172 + 2</gadget>
<output>174</output>
<result>C</result> | C | 174 | The average of a batsman for 40 innings is 50 runs. His highest score exceeds his lowest score by 172 runs. If these two innings are excluded, his average drops by 2 runs. Find his highest score. | {
"A": "172",
"B": "173",
"C": "174",
"D": "175",
"E": "none of the above"
} | add(172, divide(subtract(subtract(multiply(40, 50), multiply(subtract(40, 2), subtract(50, 2))), 172), 2)) | multiply(n0,n1)|subtract(n0,n3)|subtract(n1,n3)|multiply(#1,#2)|subtract(#0,#3)|subtract(#4,n2)|divide(#5,n3)|add(n2,#6) | total runs = 40 × 50 = 2000 let his highest score be = x then his lowest score = x – 172 now 200 − x − ( x − 172 ) / 38 = 48 ⇒ 2 x = 2172 – 1824 ⇒ x = 174 answer c | general |
math_qa__GJ1PhfRgMUfIQEer | The height of the wall is 6 times its width and length of the wall is 7 times its height .if the volume of the wall be 129024 cu.m.its width is
Answers:
A) 4 m B) 5 m C) 6 m D) 7 m E) 8 m | <gadget id="calculator">6 * 7</gadget>
<output>42</output>
<gadget id="calculator">42 * 6</gadget>
<output>252</output>
<gadget id="calculator">129_024 / 252</gadget>
<output>512</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">512 ** (1/3)</gadget>
<output>8</output>
<result>E</result> | E | 8 | The height of the wall is 6 times its width and length of the wall is 7 times its height .if the volume of the wall be 129024 cu.m.its width is | {
"A": "4 m",
"B": "5 m",
"C": "6 m",
"D": "7 m",
"E": "8 m"
} | power(divide(129024, multiply(multiply(6, 7), 6)), divide(const_1, const_3)) | divide(const_1,const_3)|multiply(n0,n1)|multiply(n0,#1)|divide(n2,#2)|power(#3,#0)| | "explanation : let width = x then , height = 6 x and length = 42 x 42 x ã — 6 x ã — x = 129024 x = 8 answer : e" | physics |
math_qa__DQ3KQrshXErqMEPQ | 16 balls are numbered 1 to 16. A ball is drawn and then another ball is drawn without replacement. What is the probability that both balls have even numbers?
Select:
A) 4 / 11 B) 5 / 17 C) 6 / 25 D) 7 / 30 E) 8 / 37 | <gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 / 16</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">16 - 1</gadget>
<output>15</output>
<gadget id="calculator">7 / 15</gadget>
<output>7/15 = around 0.466667</output>
<gadget id="calculator">(1/2) * (7/15)</gadget>
<output>7/30 = around 0.233333</output>
<result>D</result> | D | 0.233333 | 16 balls are numbered 1 to 16. A ball is drawn and then another ball is drawn without replacement. What is the probability that both balls have even numbers? | {
"A": "4 / 11",
"B": "5 / 17",
"C": "6 / 25",
"D": "7 / 30",
"E": "8 / 37"
} | multiply(divide(add(const_4, const_4), 16), divide(subtract(add(const_4, const_4), 1), subtract(16, 1))) | add(const_4,const_4)|subtract(n0,n1)|divide(#0,n0)|subtract(#0,n1)|divide(#3,#1)|multiply(#2,#4)| | "p ( 1 st ball is even ) = 8 / 16 p ( 2 nd ball is also even ) = 7 / 15 p ( both balls are even ) = 8 / 16 * 7 / 15 = 7 / 30 the answer is d ." | other |
math_qa__tcy9WrSr93Xk5G2s | the number of years of service of the 8 employees in a production department are 15 , 10 , 9 , 17 , 6 , 3 , 14 and 16 . what is the range in the number of years of service of the 8 employees ? Select the correct option
A) 10
B) 11
C) 12
D) 13
E) 14 | <gadget id="calculator">17 - 3</gadget>
<output>14</output>
<result>E</result> | E | 14 | the number of years of service of the 8 employees in a production department are 15 , 10 , 9 , 17 , 6 , 3 , 14 and 16 . what is the range in the number of years of service of the 8 employees ? | {
"A": "10",
"B": "11",
"C": "12",
"D": "13",
"E": "14"
} | subtract(17, 3) | subtract(n4,n6) | = 17 - 3 = 14 answer e | general |
math_qa__Pt8IcVM6UAIHGjyy | Annika hikes at a constant rate of 10 minutes per kilometer. She has hiked 2.5 kilometers east from the start of a hiking trail when she realizes that she has to be back at the start of the trail in 35 minutes. If Annika continues east, then turns around and retraces her path to reach the start of the trail in exactly 35 minutes, for how many kilometers total did she hike east? Pick.
A) 3.625 B) 3.5 C) 3 D) 4 E) 4.5 | <gadget id="calculator">35 / 10</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(7/2) - 2.5</gadget>
<output>1</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) + 2.5</gadget>
<output>3</output>
<result>C</result> | C | 3 | Annika hikes at a constant rate of 10 minutes per kilometer. She has hiked 2.5 kilometers east from the start of a hiking trail when she realizes that she has to be back at the start of the trail in 35 minutes. If Annika continues east, then turns around and retraces her path to reach the start of the trail in exactly 35 minutes, for how many kilometers total did she hike east? | {
"A": "3.625",
"B": "3.5",
"C": "3",
"D": "4",
"E": "4.5"
} | add(divide(subtract(divide(35, const_10), 2.5), const_2), 2.5) | divide(n2,const_10)|subtract(#0,n1)|divide(#1,const_2)|add(n1,#2) | set up two r x t = d cases . 1 . 1 / 10 km / min x t = 2.5 from which t = 25 mins . we know total journey time now is 35 + 25 = 60 the rate is the same ie 1 / 10 km / min . set up second r x t = d case . 1 / 10 km / min x 60 = 6 km now the total journey would be halved as distance would be same in each direction . 6 / 2 = 3 c | physics |
math_qa__h6agc27HWTxIJ1FL | the average temperature of the town in the first 4 days of a month was 58 degrees . the average for the second , third , fourth and fifth days was 59 degrees . if the temperatures of the first and fifth days were in the ratio 7 : 8 , then what is the temperature on the fifth day ? Choose the correct option:
A) 62 degrees B) 32 degrees C) 65 degrees D) 66 degrees E) 67 degrees | <gadget id="calculator">4 * 59</gadget>
<output>236</output>
<gadget id="calculator">4 * 58</gadget>
<output>232</output>
<gadget id="calculator">236 - 232</gadget>
<output>4</output>
<gadget id="calculator">8 * 4</gadget>
<output>32</output>
<result>B</result> | B | 32 | the average temperature of the town in the first 4 days of a month was 58 degrees . the average for the second , third , fourth and fifth days was 59 degrees . if the temperatures of the first and fifth days were in the ratio 7 : 8 , then what is the temperature on the fifth day ? | {
"A": "62 degrees",
"B": "32 degrees",
"C": "65 degrees",
"D": "66 degrees",
"E": "67 degrees"
} | multiply(8, subtract(multiply(4, 59), multiply(4, 58))) | multiply(n0,n2)|multiply(n0,n1)|subtract(#0,#1)|multiply(n4,#2) | explanation : sum of temperatures on 1 st , 2 nd , 3 rd and 4 th days = ( 58 * 4 ) = 232 degrees . . . ( 1 ) sum of temperatures on 2 nd , 3 rd , 4 th and 5 th days - ( 59 * 4 ) = 236 degrees . . . . ( 2 ) subtracting ( 1 ) from ( 2 ) , we get : temp , on 5 th day - temp on 1 st day = 4 degrees . let the temperatures on 1 st and 5 th days be 7 x and 8 x degrees respectively . then , 8 x - 7 x = 4 or x = 4 . answer : b temperature on the 5 th day = 8 x = 32 degrees . | physics |
math_qa__JiSskqheWojIsIAg | Reena took a loan of $. 1200 with simple interest for as many years as the rate of interest. If she paid $ 108 as interest at the end of the loan period, what was the rate of interest?
Choose the correct choice from the following options: A) 3.6 B) 6 C) 18 D) 3 E) none of these | <gadget id="calculator">108 * 100</gadget>
<output>10_800</output>
<gadget id="calculator">10_800 / 1_200</gadget>
<output>9</output>
<gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<result>D</result> | D | 3 | Reena took a loan of $. 1200 with simple interest for as many years as the rate of interest. If she paid $ 108 as interest at the end of the loan period, what was the rate of interest? | {
"A": "3.6",
"B": "6",
"C": "18",
"D": "3",
"E": "none of these"
} | sqrt(divide(multiply(108, const_100), 1200)) | multiply(n1,const_100)|divide(#0,n0)|sqrt(#1) | let rate = r % and time = r years . then , 1200 x r x r / 100 = 108 12 r 2 = 108 r 2 = 9 r = 3 . answer : d | gain |
math_qa__xFUU8TKb7CyYbuax | Ana climbs up stairs 20 floors building and back. She takes the exact same route both ways. On the trip up she climbs an average speed of 2 steps per second. On the trip back she climbs down at an average speed of 4 steps per second. What is her approximate average speed for the round trip in miles per hour? Pick.
A) 1 B) 1.25 C) 1.33 D) 1.5 E) 1.75 | <gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">20 / 15</gadget>
<output>4/3 = around 1.333333</output>
<result>C</result> | C | 1.33 | Ana climbs up stairs 20 floors building and back. She takes the exact same route both ways. On the trip up she climbs an average speed of 2 steps per second. On the trip back she climbs down at an average speed of 4 steps per second. What is her approximate average speed for the round trip in miles per hour? | {
"A": "1",
"B": "1.25",
"C": "1.33",
"D": "1.5",
"E": "1.75"
} | divide(20, add(divide(20, 2), divide(20, 4))) | divide(n0,n1)|divide(n0,n2)|add(#0,#1)|divide(n0,#2) | average speed = total distance / total time here number of steps to 20 th floor and back is same as she takes the same route . d = 2 t 1 and d = 4 t 2 therefore , t 1 = d / 2 and t 2 = d / 4 t 1 + t 2 = 3 d / 4 therefore , average speed = 2 d / 3 d / 4 = 2 d * 4 / 3 d answer is 1.3 since , the options are far away we need not solve till the decimal points so correct answer is option c | physics |
math_qa__uzkYBZR0o9aZCvsT | The instructions state that Cheryl needs 4/19 square yards of one type of material and 2/13 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 4/26 square yards left that she did not use. What is the total amount of square yards of material Cheryl used? Choices
A) 4 / 19 B) 1 / 9 C) 2 / 3 D) 1 1 / 9 E) 2 1 / 9 | <gadget id="calculator">4 / 19</gadget>
<output>4/19 = around 0.210526</output>
<gadget id="calculator">2 / 13</gadget>
<output>2/13 = around 0.153846</output>
<gadget id="calculator">(4/19) + (2/13)</gadget>
<output>90/247 = around 0.364372</output>
<gadget id="calculator">4 / 26</gadget>
<output>2/13 = around 0.153846</output>
<gadget id="calculator">(90/247) - (2/13)</gadget>
<output>4/19 = around 0.210526</output>
<result>A</result> | A | 0.210526 | The instructions state that Cheryl needs 4/19 square yards of one type of material and 2/13 square yards of another type of material for a project. She buys exactly that amount. After finishing the project, however, she has 4/26 square yards left that she did not use. What is the total amount of square yards of material Cheryl used? | {
"A": "4 / 19",
"B": "1 / 9",
"C": "2 / 3",
"D": "1 1 / 9",
"E": "2 1 / 9"
} | subtract(add(divide(4, 19), divide(2, 13)), divide(4, 26)) | divide(n0,n1)|divide(n2,n3)|divide(n4,n5)|add(#0,#1)|subtract(#3,#2)| | "total bought = 4 / 19 + 2 / 13 left part 4 / 26 - - - > 2 / 13 so used part 4 / 19 + 2 / 13 - 2 / 13 = 4 / 19 answer : a" | general |
math_qa__OdYfB9aTb3V1H8i3 | Running at the same constant rate,6 identical machines can produce a total of 270 bottles per minute.At this rate,how many bottles could 16 such machines produce in 4 minutes ? Choose the correct choice from the following options: A) 2880 B) 1800 C) 2700 D) 10800 E) none of these | <gadget id="calculator">270 / 6</gadget>
<output>45</output>
<gadget id="calculator">45 * 4</gadget>
<output>180</output>
<gadget id="calculator">180 * 16</gadget>
<output>2_880</output>
<result>A</result> | A | 2,880 | Running at the same constant rate,6 identical machines can produce a total of 270 bottles per minute.At this rate,how many bottles could 16 such machines produce in 4 minutes ? | {
"A": "2880",
"B": "1800",
"C": "2700",
"D": "10800",
"E": "none of these"
} | multiply(multiply(divide(270, 6), 4), 16) | divide(n1,n0)|multiply(n3,#0)|multiply(n2,#1)| | "solution let the required number of bottles be x . more machines , more bottles ( direct proportion ) more minutes , more bottles ( direct proportion ) â ˆ ´ 6 ã — 1 ã — x = 16 ã — 4 ã — 270 â ‡ ” x = 16 x 4 x 270 / 6 = 2880 . answer a" | gain |
math_qa__md6pQBQnNJiln3BK | All the milk in container A which was filled to its brim was poured into two containers B and C. The quantity of milk in container B was 62.5% less than the capacity of container A. If 154 liters was now transferred from C to B, then both the containers would have equal quantities of milk. What was the initial quantity of milk in container A? Choose the most appropriate option.
A) 1232 B) 1723 C) 1129 D) 2613 E) 1372 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">62.5 / 100</gadget>
<output>0.625</output>
<gadget id="calculator">1 - 0.625</gadget>
<output>0.375</output>
<gadget id="calculator">(1/2) - 0.375</gadget>
<output>0.125</output>
<gadget id="calculator">154 / 0.125</gadget>
<output>1_232</output>
<result>A</result> | A | 1,232 | All the milk in container A which was filled to its brim was poured into two containers B and C. The quantity of milk in container B was 62.5% less than the capacity of container A. If 154 liters was now transferred from C to B, then both the containers would have equal quantities of milk. What was the initial quantity of milk in container A? | {
"A": "1232",
"B": "1723",
"C": "1129",
"D": "2613",
"E": "1372"
} | divide(154, subtract(inverse(const_2), subtract(const_1, divide(62.5, const_100)))) | divide(n0,const_100)|inverse(const_2)|subtract(const_1,#0)|subtract(#1,#2)|divide(n1,#3)| | "a b has 62.5 % or ( 5 / 8 ) of the milk in a . therefore , let the quantity of milk in container a ( initially ) be 8 k . quantity of milk in b = 8 k - 5 k = 3 k . quantity of milk in container c = 8 k - 3 k = 5 k container : a b c quantity of milk : 8 k 3 k 5 k it is given that if 154 liters was transferred from container c to container b , then both the containers would have equal quantities of milk . 5 k - 154 = 3 k + 154 = > 2 k = 308 = > k = 154 the initial quantity of milk in a = 8 k = 8 * 154 = 1232 liters ." | general |
math_qa__MGEGKisTd1Slp10R | Of the 170 people at a party, 70 were women, and 30 women tried the appetizer. If 60 people did not try the appetizer, what is the total number of men who tried the appetizer? Choose the correct choice from the following.
A) 40 B) 50 C) 60 D) 70 E) 80 | <gadget id="calculator">170 - 60</gadget>
<output>110</output>
<gadget id="calculator">110 - 30</gadget>
<output>80</output>
<result>E</result> | E | 80 | Of the 170 people at a party, 70 were women, and 30 women tried the appetizer. If 60 people did not try the appetizer, what is the total number of men who tried the appetizer? | {
"A": "40",
"B": "50",
"C": "60",
"D": "70",
"E": "80"
} | subtract(subtract(170, 60), 30) | subtract(n0,n3)|subtract(#0,n2) | total people at party = 170 women = 70 so men 170 - 70 = 100 no . of pple who tried appetizer = 170 - 60 ( given info ) = 110 no of women who tried appetizer = 30 so remaining ppl ( men ) who tried the appetizer = 110 - 30 = 80 correct option e | general |
math_qa__hz9wmI5WHzvkvaLc | On dividing a number by 7, we get 5 as quotient and 0 as remainder. On dividing the same number by 11, what will be the remainder? Choose the correct choice from the following options
A) 2 B) 5 C) 8 D) 1 E) 3 | <gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">35 % 11</gadget>
<output>2</output>
<result>A</result> | A | 2 | On dividing a number by 7, we get 5 as quotient and 0 as remainder. On dividing the same number by 11, what will be the remainder? | {
"A": "2",
"B": "5",
"C": "8",
"D": "1",
"E": "3"
} | reminder(multiply(7, 5), 11) | multiply(n0,n1)|reminder(#0,n3) | number = 7 * 5 + 0 = 35 11 ) 35 ( 3 33 - - - - - - - - 2 required number = 2 . answer : a | general |
math_qa__TtdYRf63ttPhyX1m | If a 10 percent deposit that has been paid toward the purchase of a certain product is $130, how much more remains to be paid? Select
A) $ 880
B) $ 990
C) $ 1,000
D) $ 1,170
E) $ 1,210 | <gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">130 * 10</gadget>
<output>1_300</output>
<gadget id="calculator">1_300 - 130</gadget>
<output>1_170</output>
<result>D</result> | D | 1,170 | If a 10 percent deposit that has been paid toward the purchase of a certain product is $130, how much more remains to be paid? | {
"A": "$ 880",
"B": "$ 990",
"C": "$ 1,000",
"D": "$ 1,170",
"E": "$ 1,210"
} | subtract(multiply(130, divide(const_100, 10)), 130) | divide(const_100,n0)|multiply(n1,#0)|subtract(#1,n1) | 10 / 100 p = 130 > > p = 130 * 100 / 10 = 1300 1300 - 130 = 1170 answer : d | general |
math_qa__pzNXUKaOOqle7YLc | A man swims downstream 36 km and upstream 18 km taking 6 hours each time, what is the speed of the man in still water? Choices
A) 4.5 B) 5.5 C) 6.5 D) 4.8 E) 2 | <gadget id="calculator">18 / 6</gadget>
<output>3</output>
<gadget id="calculator">36 / 6</gadget>
<output>6</output>
<gadget id="calculator">3 + 6</gadget>
<output>9</output>
<gadget id="calculator">9 / 2</gadget>
<output>9/2 = around 4.5</output>
<result>A</result> | A | 4.5 | A man swims downstream 36 km and upstream 18 km taking 6 hours each time, what is the speed of the man in still water? | {
"A": "4.5",
"B": "5.5",
"C": "6.5",
"D": "4.8",
"E": "2"
} | divide(add(divide(18, 6), divide(36, 6)), const_2) | divide(n1,n2)|divide(n0,n2)|add(#0,#1)|divide(#2,const_2)| | "36 - - - 6 ds = 6 ? - - - - 1 18 - - - - 6 us = 3 ? - - - - 1 m = ? m = ( 6 + 3 ) / 2 = 4.5 answer : a" | physics |
math_qa__0BVn0hfL43RcS8pX | A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 3500. The difference between the profit shares of A and C is? Choose one
A) 621 B) 1400 C) 236 D) 600 E) 211 | <gadget id="calculator">12_000 / 10_000</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">8_000 / 10_000</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(6/5) - (4/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 3_500</gadget>
<output>1_400</output>
<result>B</result> | B | 1,400 | A, B and C started a business with capitals of Rs. 8000, Rs. 10000 and Rs. 12000 respectively. At the end of the year, the profit share of B is Rs. 3500. The difference between the profit shares of A and C is? | {
"A": "621",
"B": "1400",
"C": "236",
"D": "600",
"E": "211"
} | multiply(subtract(divide(12000, 10000), divide(8000, 10000)), 3500) | divide(n2,n1)|divide(n0,n1)|subtract(#0,#1)|multiply(n3,#2)| | "explanation : ratio of investments of a , b and c is 8000 : 10000 : 12000 = 4 : 5 : 6 and also given that , profit share of b is rs . 3500 = > 5 parts out of 15 parts is rs . 3500 now , required difference is 6 - 4 = 2 parts required difference = 2 / 5 ( 3500 ) = rs . 1400 answer : b" | gain |
math_qa__3EQZt3sYaj5NZbuT | A particular store purchased a stock of turtleneck sweaters and marked up its cost by 20%. During the New Year season, it further marked up its prices by 25% of the original retail price. In February, the store then offered a discount of 8%. What was its profit on the items sold in February? Choose the correct choice:
A) 27.5 % B) 30 % C) 35 % D) 37.5 % E) 38 % | <gadget id="calculator">100 - 8</gadget>
<output>92</output>
<gadget id="calculator">92 / 100</gadget>
<output>23/25 = around 0.92</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">120 * (5/4)</gadget>
<output>150</output>
<gadget id="calculator">(23/25) * 150</gadget>
<output>138</output>
<gadget id="calculator">138 - 100</gadget>
<output>38</output>
<result>E</result> | E | 38 | A particular store purchased a stock of turtleneck sweaters and marked up its cost by 20%. During the New Year season, it further marked up its prices by 25% of the original retail price. In February, the store then offered a discount of 8%. What was its profit on the items sold in February? | {
"A": "27.5 %",
"B": "30 %",
"C": "35 %",
"D": "37.5 %",
"E": "38 %"
} | subtract(multiply(divide(subtract(const_100, 8), const_100), multiply(add(const_100, 20), divide(add(const_100, 25), const_100))), const_100) | add(n0,const_100)|add(n1,const_100)|subtract(const_100,n2)|divide(#2,const_100)|divide(#1,const_100)|multiply(#0,#4)|multiply(#3,#5)|subtract(#6,const_100)| | "assume the total price = 100 x price after 20 % markup = 120 x price after 25 % further markup = 1.25 * 120 x = 150 x price after the discount = 0.92 * 150 x = 138 x hence total profit = 38 % option e" | gain |
math_qa__lNOTtzCvgaUtcb7e | The diagonals of a rhombus are 15 cm and 12 cm. Find its area?
Choose the correct choice:
A) 70
B) 90
C) 60
D) 80
E) 292 | <gadget id="calculator">(15 * 12) / 2</gadget>
<output>90</output>
<result>B</result> | B | 90 | The diagonals of a rhombus are 15 cm and 12 cm. Find its area? | {
"A": "70",
"B": "90",
"C": "60",
"D": "80",
"E": "292"
} | rhombus_area(15, 12) | rhombus_area(n0,n1)| | "1 / 2 * 15 * 12 = 90 answer : b" | geometry |
math_qa__sDMeeCqTEyvuhFNS | (?)+3699+1985-2047=31111 Options: A) 27488 B) 27424 C) 27474 D) 27784 E) 27468 | <gadget id="calculator">3_699 + 1_985</gadget>
<output>5_684</output>
<gadget id="calculator">5_684 - 2_047</gadget>
<output>3_637</output>
<gadget id="calculator">31_111 - 3_637</gadget>
<output>27_474</output>
<result>C</result> | C | 27,474 | (?)+3699+1985-2047=31111 | {
"A": "27488",
"B": "27424",
"C": "27474",
"D": "27784",
"E": "27468"
} | subtract(31111, subtract(add(3699, 1985), 2047)) | add(n0,n1)|subtract(#0,n2)|subtract(n3,#1) | c 27474 x + 3699 + 1985 - 2047 = 31111 x + 3699 + 1985 = 31111 + 2047 x + 5684 = 33158 x = 33158 - 5684 = 27474 . | general |
math_qa__FZalIgMNaK6zM2SP | Pens, Pencils and Markers in a Jenna's desk are in the ratio of 2: 2 : 5. If there are 10 Pens, the number of Markers in Jenna's desk is: Choose the correct choice from the following answers
A) 30 B) 22 C) 20 D) 25 E) 100 | <gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<result>D</result> | D | 25 | Pens, Pencils and Markers in a Jenna's desk are in the ratio of 2: 2 : 5. If there are 10 Pens, the number of Markers in Jenna's desk is: | {
"A": "30",
"B": "22",
"C": "20",
"D": "25",
"E": "100"
} | divide(multiply(10, 5), 2) | multiply(n2,n3)|divide(#0,n0) | explanation : let pens = 2 x , pencils = 2 x & markers = 5 x . now , 2 x = 10 hence x = 5 . number of markers = 5 x which is 25 . answer : d | other |
math_qa__4WA5QUukt2BkesXt | How many digits are in (8×10^10)(10×10^5)? Choose the correct choice from the following answers
A) 17 B) 25 C) 26 D) 27 E) 28 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">10 + 7</gadget>
<output>17</output>
<result>A</result> | A | 17 | How many digits are in (8×10^10)(10×10^5)? | {
"A": "17",
"B": "25",
"C": "26",
"D": "27",
"E": "28"
} | add(const_10, add(const_3, const_4)) | add(const_3,const_4)|add(#0,const_10) | the question simplfies to ( 8 × 10 ^ 10 ) ( 10 ^ 6 ) = > 8 * 10 ^ 16 = > will contain 16 zeros + 1 digit 8 = > 17 ans a | general |
math_qa__4YTudcq6uoEz3nwf | A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 3:4. The ratio of economy cars to sport utility vehicles is 4:3. What is the ratio of luxury cars to sport utility vehicles? Choose the correct answer:
A) 9 : 8
B) 8 : 9
C) 3 : 2
D) 2 : 3
E) 16 : 9 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">12 / 9</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">12 / 16</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(4/3) / (3/4)</gadget>
<output>16/9 = around 1.777778</output>
<result>E</result> | E | 1.777778 | A certain car dealership sells economy cars, luxury cars, and sport utility vehicles. The ratio of economy to luxury cars is 3:4. The ratio of economy cars to sport utility vehicles is 4:3. What is the ratio of luxury cars to sport utility vehicles? | {
"A": "9 : 8",
"B": "8 : 9",
"C": "3 : 2",
"D": "2 : 3",
"E": "16 : 9"
} | divide(divide(multiply(const_4, 3), multiply(3, 3)), divide(multiply(3, const_4), multiply(4, const_4))) | multiply(n3,const_4)|multiply(n3,n3)|multiply(n1,const_4)|divide(#0,#1)|divide(#0,#2)|divide(#3,#4)| | "the ratio of economy to luxury cars is 3 : 4 - - > e : l = 3 : 4 = 12 : 16 . the ratio of economy cars to sport utility vehicles is 4 : 3 - - > e : s = 4 : 3 = 12 : 9 . thus , l : s = 16 : 9 . answer : e ." | other |
math_qa__rJC3iYmS9iC442wg | A sum of Rs. 1530 has been divided among A, B and C such that A gets of what B gets and B gets of what C gets. B’s share is: Pick
A) rs . 120 B) rs . 160 C) rs . 270 D) rs . 300 E) none | <gadget id="calculator">1_530 / 10</gadget>
<output>153</output>
<gadget id="calculator">153 * 2</gadget>
<output>306</output>
<gadget id="calculator">306 - 12</gadget>
<output>294</output>
<gadget id="calculator">294 - 12</gadget>
<output>282</output>
<result>C</result> | C | 270 | A sum of Rs. 1530 has been divided among A, B and C such that A gets of what B gets and B gets of what C gets. B’s share is: | {
"A": "rs . 120",
"B": "rs . 160",
"C": "rs . 270",
"D": "rs . 300",
"E": "none"
} | subtract(subtract(multiply(divide(1530, const_10), const_2), const_12), const_12) | divide(n0,const_10)|multiply(#0,const_2)|subtract(#1,const_12)|subtract(#2,const_12)| | "explanation let c ’ s share = rs . x then , b ’ s share = rs . x / 4 , a ’ s share = rs . ( 2 / 3 x x / 4 ) = rs . x / 6 = x / 6 + x / 4 + x = 1530 = > 17 x / 12 = 1530 = > 1530 x 12 / 17 = rs . 1080 hence , b ’ s share = rs . ( 1080 / 4 ) = rs . 270 . answer c" | general |
math_qa__eNKtJM9T9qSp4UyO | Two pipes can fill the cistern in 10hr and 12 hr respectively, while the third empty it in 40hr. If all pipes are opened simultaneously, then the cistern will be filled in Choose one.
A) 6.32 hr
B) 8 hr
C) 8.5 hr
D) 10 hr
E) none of these | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/10) + (1/12)</gadget>
<output>11/60 = around 0.183333</output>
<gadget id="calculator">1 / 40</gadget>
<output>1/40 = around 0.025</output>
<gadget id="calculator">(11/60) - (1/40)</gadget>
<output>19/120 = around 0.158333</output>
<gadget id="calculator">1 / (19/120)</gadget>
<output>120/19 = around 6.315789</output>
<result>A</result> | A | 6.32 | Two pipes can fill the cistern in 10hr and 12 hr respectively, while the third empty it in 40hr. If all pipes are opened simultaneously, then the cistern will be filled in | {
"A": "6.32 hr",
"B": "8 hr",
"C": "8.5 hr",
"D": "10 hr",
"E": "none of these"
} | inverse(subtract(add(divide(const_1, 10), divide(const_1, 12)), divide(const_1, 40))) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|subtract(#3,#2)|inverse(#4)| | "solution : work done by all the tanks working together in 1 hour . 1 / 10 + 1 / 12 − 1 / 40 = 3 / 19 hence , tank will be filled in 19 / 3 = 6.32 hour option ( a )" | physics |
math_qa__luI3SnCfDf8qwQ3u | If 5 men undertook a piece of construction work and finished half the job in 15 days. If two men drop out, then the job will be completed in Select:
A) 5 days B) 15 days C) 10 days D) 25 days E) 20 days | <gadget id="calculator">15 * 5</gadget>
<output>75</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">75 / 3</gadget>
<output>25</output>
<result>D</result> | D | 25 | If 5 men undertook a piece of construction work and finished half the job in 15 days. If two men drop out, then the job will be completed in | {
"A": "5 days",
"B": "15 days",
"C": "10 days",
"D": "25 days",
"E": "20 days"
} | divide(multiply(15, 5), subtract(5, const_2)) | multiply(n0,n1)|subtract(n0,const_2)|divide(#0,#1) | that is , half the work done = 5 * 15 * 1 / 2 then , 5 * 15 * 1 / 2 = 3 * ? * 1 / 2 i . e . 5 * 15 = 3 * ? = 5 * 15 / 3 = 25 day d | physics |
math_qa__I1BBskmoHyhuhKiN | A child want to buy 3 new toys. If there are 10 toys that satisfy the child's criteria,in how many different ways can the child select the 3 new toys if the order of selection doesn't matter. Answers.
A) 20
B) 120
C) 210
D) 15
E) 45 | <gadget id="calculator">binomial(10, 3)</gadget>
<output>120</output>
<result>B</result> | B | 120 | A child want to buy 3 new toys. If there are 10 toys that satisfy the child's criteria,in how many different ways can the child select the 3 new toys if the order of selection doesn't matter. | {
"A": "20",
"B": "120",
"C": "210",
"D": "15",
"E": "45"
} | choose(10, 3) | choose(n1,n0)| | "the number of ways of choosing 3 toys out of 10 are counted by = 10 c 3 ways = 120 answer : option b" | probability |
math_qa__SPMpeJACjndmG0bk | Find the remainder of the division (3^15)/7. Choose the most appropriate option:
A) 7
B) 6
C) 15
D) 8
E) 2 | <gadget id="calculator">3 ** 15</gadget>
<output>14_348_907</output>
<gadget id="calculator">14_348_907 % 7</gadget>
<output>6</output>
<result>B</result> | B | 6 | Find the remainder of the division (3^15)/7. | {
"A": "7",
"B": "6",
"C": "15",
"D": "8",
"E": "2"
} | reminder(power(3, 15), 7) | power(n0,n1)|reminder(#0,n2)| | "find the pattern of the remainders after each power : ( 3 ^ 1 ) / 7 remainder 3 ( 3 ^ 2 ) / 7 remainder 2 ( 3 ^ 3 ) / 7 remainder 6 ( 3 ^ 4 ) / 7 remainder 4 ( 3 ^ 5 ) / 7 remainder 5 ( 3 ^ 6 ) / 7 remainder 1 - - > this is where the cycle ends ( 3 ^ 7 ) / 7 remainder 3 - - > this is where the cycle begins again ( 3 ^ 8 ) / 7 remainder 2 continuing the pattern to ( 3 ^ 15 ) / 7 gives us a remainder of 6 final answer : b ) 6" | general |
math_qa__x8kjtzsUsQinjra0 | In what ratio mental A at Rs.68 per kg be mixed with another metal at Rs.96 per kg so that cost of alloy (mixture) is Rs.76 per kg? Choose the correct choice from the following options
A) 5 : 8 B) 4 : 7 C) 3 : 7 D) 9 : 5 E) 5 : 2 | <gadget id="calculator">96 - 76</gadget>
<output>20</output>
<gadget id="calculator">96 - 68</gadget>
<output>28</output>
<gadget id="calculator">20 / 28</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">1 - (5/7)</gadget>
<output>2/7 = around 0.285714</output>
<gadget id="calculator">(5/7) / (2/7)</gadget>
<output>5/2 = around 2.5</output>
<result>E</result> | E | 2.5 | In what ratio mental A at Rs.68 per kg be mixed with another metal at Rs.96 per kg so that cost of alloy (mixture) is Rs.76 per kg? | {
"A": "5 : 8",
"B": "4 : 7",
"C": "3 : 7",
"D": "9 : 5",
"E": "5 : 2"
} | divide(divide(subtract(96, 76), subtract(96, 68)), subtract(const_1, divide(subtract(96, 76), subtract(96, 68)))) | subtract(n1,n2)|subtract(n1,n0)|divide(#0,#1)|subtract(const_1,#2)|divide(#2,#3)| | "( 96 - 76 ) / ( 76 - 68 ) = 20 / 8 = 5 / 2 answer : e" | other |
math_qa__oZ4Gee4DVxtIDrLk | What is the ratio between perimeters of two squares one having 3 times the diagonal then the other? Choose the correct choice from the following options.
A) 3 : 2 B) 3 : 0 C) 4 : 1 D) 3 : 1 E) 2 : 2 | <gadget id="calculator">3 / 3</gadget>
<output>1</output>
<gadget id="calculator">3 / 1</gadget>
<output>3</output>
<result>D</result> | D | 3 | What is the ratio between perimeters of two squares one having 3 times the diagonal then the other? | {
"A": "3 : 2",
"B": "3 : 0",
"C": "4 : 1",
"D": "3 : 1",
"E": "2 : 2"
} | divide(3, divide(3, const_3)) | divide(n0,const_3)|divide(n0,#0) | d = 3 d d = d a √ 2 = 3 d a √ 2 = d a = 3 d / √ 2 a = d / √ 2 = > 3 : 1 answer : d | geometry |
math_qa__0f8RYGRScO82IeFU | The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 72% of the required amount. What is the net difference in the expenditure on that product? Choose the correct choice.
A) 12.5 % B) 10 % C) 15 % D) 17 % E) 19 % | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 * 72</gadget>
<output>9_000</output>
<gadget id="calculator">10_000 - 9_000</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 100</gadget>
<output>100_000</output>
<gadget id="calculator">100_000 / 10_000</gadget>
<output>10</output>
<result>B</result> | B | 10 | The Shopkeeper increased the price of a product by 25% so that customer finds it difficult to purchase the required amount. But somehow the customer managed to purchase only 72% of the required amount. What is the net difference in the expenditure on that product? | {
"A": "12.5 %",
"B": "10 %",
"C": "15 %",
"D": "17 %",
"E": "19 %"
} | divide(multiply(subtract(multiply(const_100, const_100), multiply(add(const_100, 25), 72)), const_100), multiply(const_100, const_100)) | add(n0,const_100)|multiply(const_100,const_100)|multiply(n1,#0)|subtract(#1,#2)|multiply(#3,const_100)|divide(#4,#1)| | "quantity x rate = price 1 x 1 = 1 0.72 x 1.25 = 0.9 decrease in price = ( 0.1 / 1 ) × 100 = 10 % b )" | general |
math_qa__MysLrHUbmcczhq6I | Two trains 140 m and 150 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? Choose one: A) 10.9 sec B) 13.8 sec C) 53.8 sec D) 10.44 sec E) 10.4 sec | <gadget id="calculator">140 + 150</gadget>
<output>290</output>
<gadget id="calculator">60 + 40</gadget>
<output>100</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">100 * (5/18)</gadget>
<output>250/9 = around 27.777778</output>
<gadget id="calculator">290 / (250/9)</gadget>
<output>261/25 = around 10.44</output>
<result>D</result> | D | 10.44 | Two trains 140 m and 150 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time which they take to cross each other is? | {
"A": "10.9 sec",
"B": "13.8 sec",
"C": "53.8 sec",
"D": "10.44 sec",
"E": "10.4 sec"
} | divide(add(140, 150), multiply(add(60, 40), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "relative speed = 60 + 40 = 100 km / hr . = 100 * 5 / 18 = 250 / 9 m / sec . distance covered in crossing each other = 140 + 150 = 290 m . required time = 290 * 9 / 250 = 10.44 sec . answer : d :" | physics |
math_qa__tlYj8ZYe3k1ycItb | A glass was filled with 10 ounces of water, and 0.06 ounce of the water evaporated each day during a 20-day period. What percent of the original amount of water evaporated during this period? Choose the correct choice from the following answers
A) 0.002 % B) 0.02 % C) 0.2 % D) 12 % E) 20 % | <gadget id="calculator">0.06 * 20</gadget>
<output>1.2</output>
<gadget id="calculator">1.2 / 10</gadget>
<output>0.12</output>
<gadget id="calculator">0.12 * 100</gadget>
<output>12</output>
<result>D</result> | D | 12 | A glass was filled with 10 ounces of water, and 0.06 ounce of the water evaporated each day during a 20-day period. What percent of the original amount of water evaporated during this period? | {
"A": "0.002 %",
"B": "0.02 %",
"C": "0.2 %",
"D": "12 %",
"E": "20 %"
} | multiply(divide(multiply(0.06, 20), 10), const_100) | multiply(n1,n2)|divide(#0,n0)|multiply(#1,const_100)| | "we are given that 0.06 ounces of water evaporated each day . furthermore , we know that this process happened over a 20 - day period . to calculate the total amount of water that evaporated during this time frame we need to multiply 0.06 by 20 . this gives us : 0.06 x 20 = 1.2 ounces finally , we are asked for “ what percent ” of the original amount of water evaporated during this period . to determine this percentage , we have to make sure we translate the expression correctly . we can translate it to : ( amount evaporated / original amount ) x 100 % ( 1.2 / 10 ) x 100 % ( 12 / 100 ) x 100 % = 12 % answer d" | gain |
math_qa__r3k1ks2BX4H85jic | If two painters can complete two rooms in two hours, how many painters would it take to do 18 rooms in 6 hours?
Choose the correct choice from the following:
A) 8 B) 6 C) 5 D) 4 E) 1 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 * 3</gadget>
<output>54</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">54 / 9</gadget>
<output>6</output>
<result>B</result> | B | 6 | If two painters can complete two rooms in two hours, how many painters would it take to do 18 rooms in 6 hours? | {
"A": "8",
"B": "6",
"C": "5",
"D": "4",
"E": "1"
} | divide(multiply(multiply(6, const_3), const_3), multiply(const_3, const_3)) | multiply(n1,const_3)|multiply(const_3,const_3)|multiply(#0,const_3)|divide(#2,#1)| | "explanation : two painters can complete two rooms in two hours . so 18 rooms can be painted in 6 hrs by 6 painters answer : b ) 6 painters" | physics |
math_qa__0rQVpltNmeD7Vo7r | According to a recent survey report issued by the Commerce Ministry, Government of India, 30% of the total FDI goes to Gujarat and 20% of this goes to rural areas. If the FDI in Gujarat, which goes to urban areas, is $72 m, then find the size of FDI in rural Andhra Pradesh, which attracts 50% of the FDI that comes to Andhra Pradesh, which accounts For 20% of the total FDI?
Pick one:
A) 30 m B) 40 m C) 35 m D) 38 m E) 50 m | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(3/10) * (4/5)</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">72 / (6/25)</gadget>
<output>300</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/2) * (1/5)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">300 * (1/10)</gadget>
<output>30</output>
<result>A</result> | A | 30 | According to a recent survey report issued by the Commerce Ministry, Government of India, 30% of the total FDI goes to Gujarat and 20% of this goes to rural areas. If the FDI in Gujarat, which goes to urban areas, is $72 m, then find the size of FDI in rural Andhra Pradesh, which attracts 50% of the FDI that comes to Andhra Pradesh, which accounts For 20% of the total FDI? | {
"A": "30 m",
"B": "40 m",
"C": "35 m",
"D": "38 m",
"E": "50 m"
} | multiply(divide(72, multiply(divide(30, const_100), divide(subtract(const_100, 20), const_100))), multiply(divide(50, const_100), divide(20, const_100))) | divide(n0,const_100)|divide(n3,const_100)|divide(n1,const_100)|subtract(const_100,n1)|divide(#3,const_100)|multiply(#1,#2)|multiply(#0,#4)|divide(n2,#6)|multiply(#7,#5) | 30 % of total fdi given to gujarat is $ 90 m . so , 100 % is $ 300 m . 20 % of 300 m = 60 m . 50 % of 60 m = 30 m . answer : a | gain |
math_qa__gzYIVsbt5RzKv4v3 | Triangle ATriangle B are similar triangles with areas 1792 units square and 2527 units square respectively. The ratio of there corresponding height would be Select:
A) 9 : 10
B) 17 : 19
C) 23 : 27
D) 16 : 19
E) 15 : 23 | <gadget id="calculator">1_792 / 2_527</gadget>
<output>256/361 = around 0.709141</output>
<gadget id="calculator">(256/361) ** (1/2)</gadget>
<output>16/19 = around 0.842105</output>
<result>D</result> | D | 0.842105 | Triangle ATriangle B are similar triangles with areas 1792 units square and 2527 units square respectively. The ratio of there corresponding height would be | {
"A": "9 : 10",
"B": "17 : 19",
"C": "23 : 27",
"D": "16 : 19",
"E": "15 : 23"
} | sqrt(divide(1792, 2527)) | divide(n0,n1)|sqrt(#0)| | "let x be the height of triangle a and y be the height of triangle of b . since triangles are similar , ratio of area of a and b is in the ratio of x ^ 2 / y ^ 2 therefore , ( x ^ 2 / y ^ 2 ) = 1792 / 2527 ( x ^ 2 / y ^ 2 ) = ( 16 * 16 * 7 ) / ( 19 * 19 * 7 ) ( x ^ 2 / y ^ 2 ) = 16 ^ 2 / 19 ^ 2 x / y = 16 / 19 ans = d" | geometry |
math_qa__YTTRhFOzcfkLZKsO | A and B together have $ 1210. If 4/15 of A's amount is equal to 2/5 of B's amount, how much amount does B have? Choose one
A) $ 310
B) $ 395
C) $ 484
D) $ 512
E) $ 542 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">4 / 15</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">(2/5) / (4/15)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) + 1</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">1_210 / (5/2)</gadget>
<output>484</output>
<result>C</result> | C | 484 | A and B together have $ 1210. If 4/15 of A's amount is equal to 2/5 of B's amount, how much amount does B have? | {
"A": "$ 310",
"B": "$ 395",
"C": "$ 484",
"D": "$ 512",
"E": "$ 542"
} | divide(1210, add(divide(divide(2, 5), divide(4, 15)), const_1)) | divide(n3,n4)|divide(n1,n2)|divide(#0,#1)|add(#2,const_1)|divide(n0,#3) | 4 / 15 a = 2 / 5 b a = 2 / 5 * 15 / 4 b a = 3 / 2 b a / b = 3 / 2 a : b = 3 : 2 b ' s share = 1210 * 2 / 5 = $ 484 answer is c | general |
math_qa__saOMg5oeO1wST655 | The speed of a boat in still water is 12 km/hr and the rate of current is 4 km/hr. The distance travelled downstream in 18 minutes is Choose one
A) 1.6 km B) 2 km C) 3.6 km D) 4.8 km E) none of these | <gadget id="calculator">18 / 60</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">12 + 4</gadget>
<output>16</output>
<gadget id="calculator">(3/10) * 16</gadget>
<output>24/5 = around 4.8</output>
<result>D</result> | D | 4.8 | The speed of a boat in still water is 12 km/hr and the rate of current is 4 km/hr. The distance travelled downstream in 18 minutes is | {
"A": "1.6 km",
"B": "2 km",
"C": "3.6 km",
"D": "4.8 km",
"E": "none of these"
} | multiply(divide(18, const_60), add(12, 4)) | add(n0,n1)|divide(n2,const_60)|multiply(#0,#1)| | "explanation : speed downstreams = ( 12 + 4 ) kmph = 16 kmph . distance travelled = ( 16 x 18 / 60 ) km = 4.8 km option d" | physics |
math_qa__YTHw5ZadJ44dfZS6 | A boat covers a certain distance downstream in 1 hour, while it comes back in 1½ hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water? Answers: A) 12 kmph B) 13 kmph C) 14 kmph D) 15 kmph E) none | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 3</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">(9/2) + 3</gadget>
<output>15/2 = around 7.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(15/2) / (1/2)</gadget>
<output>15</output>
<result>D</result> | D | 15 | A boat covers a certain distance downstream in 1 hour, while it comes back in 1½ hours. If the speed of the stream be 3 kmph, what is the speed of the boat in still water? | {
"A": "12 kmph",
"B": "13 kmph",
"C": "14 kmph",
"D": "15 kmph",
"E": "none"
} | divide(add(multiply(divide(const_3, const_2), 3), 3), subtract(divide(const_3, const_2), 1)) | divide(const_3,const_2)|multiply(n2,#0)|subtract(#0,n0)|add(n2,#1)|divide(#3,#2) | sol . let the speed of the boat in still water be x kmph . then , speed downstream = ( x + 3 ) kmph , speed upstream = ( x - 3 ) kmph . ∴ ( x + 3 ) * 1 = ( x - 3 ) * 3 / 2 ⇔ 2 x + 6 = 3 x - 9 ⇔ x = 15 kmph . answer d | physics |
math_qa__BztQKKodaXmHASPO | Simplify: 0.3*0.8+0.1*0.5
Select.
A) 0.52 B) 0.29 C) 0.48 D) 0.64 E) 0.46 | <gadget id="calculator">0.3 * 0.8</gadget>
<output>0.24</output>
<gadget id="calculator">0.1 * 0.5</gadget>
<output>0.05</output>
<gadget id="calculator">0.24 + 0.05</gadget>
<output>0.29</output>
<result>B</result> | B | 0.29 | Simplify: 0.3*0.8+0.1*0.5 | {
"A": "0.52",
"B": "0.29",
"C": "0.48",
"D": "0.64",
"E": "0.46"
} | add(multiply(0.3, 0.8), multiply(0.1, 0.5)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)| | "given exp . = 0.3 * 0.8 + ( 0.1 * 0.5 ) = 0.24 + 0.05 = 0.29 answer is b ." | general |
math_qa__vXmK73HMuyYHdgL5 | Working alone, pump A can empty a pool in 4 hours. Working alone, pump B can empty the same pool in 2 hours. Working together, how many minutes will it take pump A and pump B to empty the pool?
Pick: A) 65 B) 70 C) 75 D) 80 E) 85 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/4) + (1/2)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / (3/4)</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) * 60</gadget>
<output>80</output>
<result>D</result> | D | 80 | Working alone, pump A can empty a pool in 4 hours. Working alone, pump B can empty the same pool in 2 hours. Working together, how many minutes will it take pump A and pump B to empty the pool? | {
"A": "65",
"B": "70",
"C": "75",
"D": "80",
"E": "85"
} | multiply(inverse(add(divide(const_1, 4), divide(const_1, 2))), const_60) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|inverse(#2)|multiply(#3,const_60)| | "pump a can empty ( 1 / 4 ) of the pool per hour . pump b can empty ( 1 / 2 ) of the pool per hour . together the pumps can empty 1 / 4 + 1 / 2 = 3 / 4 of the pool per hour . 1 pool / ( 3 / 4 ) pool per hour = 4 / 3 hours = 80 minutes . the answer is d ." | physics |
math_qa__RpHNoWgi0pXf9RV1 | A garrison of 2000 men has provisions for 62 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement? Select:
A) 1977 B) 1893 C) 2700 D) 1900 E) 1278 | <gadget id="calculator">2_000 * 62</gadget>
<output>124_000</output>
<gadget id="calculator">2_000 * 15</gadget>
<output>30_000</output>
<gadget id="calculator">124_000 - 30_000</gadget>
<output>94_000</output>
<gadget id="calculator">94_000 / 20</gadget>
<output>4_700</output>
<gadget id="calculator">4_700 - 2_000</gadget>
<output>2_700</output>
<result>C</result> | C | 2,700 | A garrison of 2000 men has provisions for 62 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement? | {
"A": "1977",
"B": "1893",
"C": "2700",
"D": "1900",
"E": "1278"
} | subtract(divide(subtract(multiply(2000, 62), multiply(2000, 15)), 20), 2000) | multiply(n0,n1)|multiply(n0,n2)|subtract(#0,#1)|divide(#2,n3)|subtract(#3,n0)| | "2000 - - - - 62 2000 - - - - 47 x - - - - - 20 x * 20 = 2000 * 47 x = 4700 2000 - - - - - - - 2700 answer : c" | physics |
math_qa__6UXf3Tw112BLCuB6 | If P(A) = 6/17, P(B) = 5/17, and P(A ∪ B) = 4/17 Find P(B|A)? Choices.
A) 2 / 3 B) 3 / 5 C) 2 / 7 D) 3 / 7 E) 4 / 9 | <gadget id="calculator">4 / 17</gadget>
<output>4/17 = around 0.235294</output>
<gadget id="calculator">6 / 17</gadget>
<output>6/17 = around 0.352941</output>
<gadget id="calculator">(4/17) / (6/17)</gadget>
<output>2/3 = around 0.666667</output>
<result>A</result> | A | 0.666667 | If P(A) = 6/17, P(B) = 5/17, and P(A ∪ B) = 4/17 Find P(B|A)? | {
"A": "2 / 3",
"B": "3 / 5",
"C": "2 / 7",
"D": "3 / 7",
"E": "4 / 9"
} | divide(divide(4, 17), divide(6, 17)) | divide(n4,n1)|divide(n0,n1)|divide(#0,#1)| | "p ( b | a ) = p ( a ∪ b ) / p ( a ) p ( b | a ) = ( 4 / 17 ) / ( 6 / 17 ) = 4 / 6 = 2 / 3 . a" | general |
math_qa__BI6DGKX1pxCc6zFY | Last year Elaine spent 20% of her annual earnings on rent. This year she earned 15% more than last year and she spent 25% of her annual earnings on rent. The amount she spent on rent this year is what percent of the amount spent on rent last year? Choose the correct choice from the following choices:
A) 152.5 B) 143.75 C) 155.5 D) 165.5 E) 117.5 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/20) + 1</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(23/20) * 25</gadget>
<output>115/4 = around 28.75</output>
<gadget id="calculator">(115/4) / 20</gadget>
<output>23/16 = around 1.4375</output>
<gadget id="calculator">(23/16) * 100</gadget>
<output>575/4 = around 143.75</output>
<result>B</result> | B | 143.75 | Last year Elaine spent 20% of her annual earnings on rent. This year she earned 15% more than last year and she spent 25% of her annual earnings on rent. The amount she spent on rent this year is what percent of the amount spent on rent last year? | {
"A": "152.5",
"B": "143.75",
"C": "155.5",
"D": "165.5",
"E": "117.5"
} | multiply(divide(multiply(add(divide(15, const_100), const_1), 25), 20), const_100) | divide(n1,const_100)|add(#0,const_1)|multiply(n2,#1)|divide(#2,n0)|multiply(#3,const_100) | for this it is easiest to use simple numbers . let ' s assume that elaine ' s annual earnings last year were $ 100 . she would ' ve spent $ 20 of this on rent . this year she earned 15 % more , or $ 115 . she would ' ve spent 25 % of this on rent , or $ 28.75 do $ 34.5 / $ 20 this will give you 143.75 % b is the correct answer . | gain |
math_qa__iMrY65v1FC2oGIod | If $5,000 is invested in an account at a simple annual rate of r percent, the interest is $250. When $20,000 is invested at the same interest rate, what is the interest from the investment? Pick one.
A) $ 700 B) $ 750 C) $ 800 D) $ 1000 E) $ 900 | <gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">200 * 100</gadget>
<output>20_000</output>
<gadget id="calculator">250 * 20_000</gadget>
<output>5_000_000</output>
<gadget id="calculator">20_000 / 4</gadget>
<output>5_000</output>
<gadget id="calculator">5_000_000 / 5_000</gadget>
<output>1_000</output>
<result>D</result> | D | 1,000 | If $5,000 is invested in an account at a simple annual rate of r percent, the interest is $250. When $20,000 is invested at the same interest rate, what is the interest from the investment? | {
"A": "$ 700",
"B": "$ 750",
"C": "$ 800",
"D": "$ 1000",
"E": "$ 900"
} | divide(multiply(250, multiply(multiply(const_2, const_100), const_100)), divide(multiply(multiply(const_2, const_100), const_100), const_4)) | multiply(const_100,const_2)|multiply(#0,const_100)|divide(#1,const_4)|multiply(n1,#1)|divide(#3,#2) | - > 250 / 5,000 = 5 % and 20,000 * 5 % = 1000 . thus , d is the answer . | gain |
math_qa__Ucf2Snfz38DepB8C | A train running at the speed of 180 km/hr crosses a pole in 18 seconds. What is the length of the train? Options:
A) 800 B) 900 C) 950 D) 1000 E) 1050 | <gadget id="calculator">180 * 1_000</gadget>
<output>180_000</output>
<gadget id="calculator">180_000 / 3_600</gadget>
<output>50</output>
<gadget id="calculator">50 * 18</gadget>
<output>900</output>
<result>B</result> | B | 900 | A train running at the speed of 180 km/hr crosses a pole in 18 seconds. What is the length of the train? | {
"A": "800",
"B": "900",
"C": "950",
"D": "1000",
"E": "1050"
} | multiply(divide(multiply(180, const_1000), const_3600), 18) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = ( 180 x ( 5 / 18 ) m / sec = ( 50 ) m / sec . length of the train = ( speed x time ) . length of the train = ( ( 50 ) x 18 ) m = 900 m b" | physics |
math_qa__nDLBy6AMNVw63sz3 | A 18% stock yielding 8% is quoted at? Choose the correct choice from the following answers.
A) 165 B) 170 C) 175 D) 180 E) 225 | <gadget id="calculator">100 / 8</gadget>
<output>25/2 = around 12.5</output>
<gadget id="calculator">(25/2) * 18</gadget>
<output>225</output>
<result>E</result> | E | 225 | A 18% stock yielding 8% is quoted at? | {
"A": "165",
"B": "170",
"C": "175",
"D": "180",
"E": "225"
} | multiply(divide(const_100, 8), 18) | divide(const_100,n1)|multiply(n0,#0)| | "assume that face value = rs . 100 as it is not given to earn rs . 8 , money invested = rs . 100 to earn rs . 18 , money invested = 100 × 18 / 8 = rs . 225 ie , market value of the stock = rs . 175 answer is e ." | gain |
math_qa__d3OVE9UOhZR7BFGg | P works 25% more efficiently than Q and Q works 50% more efficiently than R. To complete a certain project, P alone takes 50 days less than Q alone. If, in this project P alone works for 60 days and then Q alone works for 145 days, in how many days can R alone complete the remaining work? Choose one.
A) 50 days
B) 110.6 days
C) 100 days
D) 150 days
E) 80 days | <gadget id="calculator">4 * 50</gadget>
<output>200</output>
<gadget id="calculator">145 / 100</gadget>
<output>29/20 = around 1.45</output>
<gadget id="calculator">(29/20) * 60</gadget>
<output>87</output>
<gadget id="calculator">200 - 87</gadget>
<output>113</output>
<result>B</result> | B | 110.6 | P works 25% more efficiently than Q and Q works 50% more efficiently than R. To complete a certain project, P alone takes 50 days less than Q alone. If, in this project P alone works for 60 days and then Q alone works for 145 days, in how many days can R alone complete the remaining work? | {
"A": "50 days",
"B": "110.6 days",
"C": "100 days",
"D": "150 days",
"E": "80 days"
} | subtract(multiply(const_4, 50), multiply(divide(145, const_100), 60)) | divide(n4,const_100)|multiply(n1,const_4)|multiply(n3,#0)|subtract(#1,#2) | p works 25 % more efficiently than q : something that takes q 5 days , takes p 4 days q works 50 % more efficiently than r : something that takes r 7.5 days , takes q 5 days p alone takes 50 days less than q : for every 4 days p works , q has to work an extra day . hence p alone can do it in 200 days and q alone in 250 days and hence r alone in 395 days p works for 60 days - - > 60 / 200 work done = > 30 % q works for 145 days - - > 145 / 250 work done = > 58 % 28 % work left . . . r alone will take 28 % * 395 = 110.6 days answer is ( b ) | physics |
math_qa__Cy5z8pfUzild3AkD | A jar full of whisky contains 40% alcohol. A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is: Choose the correct answer
A) 1 / 3
B) 2 / 3
C) 2 / 5
D) 3 / 5
E) 4 / 5 | <gadget id="calculator">40 - 26</gadget>
<output>14</output>
<gadget id="calculator">40 - 19</gadget>
<output>21</output>
<gadget id="calculator">14 / 21</gadget>
<output>2/3 = around 0.666667</output>
<result>B</result> | B | 0.666667 | A jar full of whisky contains 40% alcohol. A part of this whisky is replaced by another containing 19% alcohol and now the percentage of alcohol was found to be 26%. The quantity of whisky replaced is: | {
"A": "1 / 3",
"B": "2 / 3",
"C": "2 / 5",
"D": "3 / 5",
"E": "4 / 5"
} | divide(subtract(40, 26), subtract(40, 19)) | subtract(n0,n2)|subtract(n0,n1)|divide(#0,#1)| | "explanation : by the rule of alligation , we have : so , ratio of 1 st and 2 nd quantities = 7 : 14 = 1 : 2 required quantity replaced = 2 / 3 . answer is b" | gain |
math_qa__4LztzuYYG8HjVVap | The speed of a train is 60 kmph. What is the distance covered by it in 20 minutes? Choose the correct choice from the following:
A) 21 kmph
B) 22 kmph
C) 20 kmph
D) 23 kmph
E) 24 kmph | <gadget id="calculator">20 / 60</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 60</gadget>
<output>20</output>
<result>C</result> | C | 20 | The speed of a train is 60 kmph. What is the distance covered by it in 20 minutes? | {
"A": "21 kmph",
"B": "22 kmph",
"C": "20 kmph",
"D": "23 kmph",
"E": "24 kmph"
} | multiply(divide(20, const_60), 60) | divide(n1,const_60)|multiply(n0,#0)| | "60 * 20 / 60 = 20 kmph answer : c" | physics |
math_qa__VLjN0jEvrgwGMy8u | Find the average of all the numbers between 9 and 26 which are divisible by 5.
Answers:
A) 15 B) 19 C) 18 D) 22 E) none | <gadget id="calculator">9 + 4</gadget>
<output>13</output>
<gadget id="calculator">26 - 4</gadget>
<output>22</output>
<gadget id="calculator">13 + 22</gadget>
<output>35</output>
<gadget id="calculator">35 / 2</gadget>
<output>35/2 = around 17.5</output>
<result>C</result> | C | 18 | Find the average of all the numbers between 9 and 26 which are divisible by 5. | {
"A": "15",
"B": "19",
"C": "18",
"D": "22",
"E": "none"
} | divide(add(add(9, const_4), subtract(26, const_4)), const_2) | add(n0,const_4)|subtract(n1,const_4)|add(#0,#1)|divide(#2,const_2)| | "sol . average = ( 10 + 15 + 20 + 25 / 4 ) = 70 / 4 = 17.5 answer c" | general |
math_qa__5FBvHvziC93b9qtQ | given a spinner with 4 sections of equal size labeled e , b , c , and d , what is the probability of not getting an e after spinning the spinner two times ? Pick one
A) 15 / 16 B) 9 / 16 C) 1 / 2 D) 1 / 4 E) 1 / 8 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) ** 2</gadget>
<output>9/16 = around 0.5625</output>
<result>B</result> | B | 0.5625 | given a spinner with 4 sections of equal size labeled e , b , c , and d , what is the probability of not getting an e after spinning the spinner two times ? | {
"A": "15 / 16",
"B": "9 / 16",
"C": "1 / 2",
"D": "1 / 4",
"E": "1 / 8"
} | power(divide(const_3, 4), const_2) | divide(const_3,n0)|power(#0,const_2) | the probability of not getting an e after spinning the spinner two times is 3 / 4 * 3 / 4 = 9 / 16 ( so getting any of the remaining 3 letters out of 4 ) . answer : b . | general |
math_qa__Q6l46XWTuAiyfLoF | Find the area of the quadrilateral of one of its diagonals is 30 cm and its off sets 10 cm and 6 cm? Pick.
A) 189 cm 2 B) 150 cm 2 C) 240 cm 2 D) 177 cm 2 E) 187 cm 2 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">6 + 10</gadget>
<output>16</output>
<gadget id="calculator">(1/2) * 16</gadget>
<output>8</output>
<gadget id="calculator">8 * 30</gadget>
<output>240</output>
<result>C</result> | C | 240 | Find the area of the quadrilateral of one of its diagonals is 30 cm and its off sets 10 cm and 6 cm? | {
"A": "189 cm 2",
"B": "150 cm 2",
"C": "240 cm 2",
"D": "177 cm 2",
"E": "187 cm 2"
} | multiply(multiply(divide(const_1, const_2), add(6, 10)), 30) | add(n1,n2)|divide(const_1,const_2)|multiply(#0,#1)|multiply(n0,#2)| | "1 / 2 * 30 ( 10 + 6 ) = 240 cm 2 answer : c" | geometry |
math_qa__4qKYfyt8QgiaKvt8 | Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.65 km respectively. The time taken by the slower train to cross the faster train in seconds is? Choose the correct choice from the following answers
A) 42 B) 77 C) 48 D) 99 E) 11 | <gadget id="calculator">1.1 * 1_000</gadget>
<output>1_100</output>
<gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">1_100 / (50/3)</gadget>
<output>66</output>
<gadget id="calculator">0.65 * 1_000</gadget>
<output>650</output>
<gadget id="calculator">90 * 1_000</gadget>
<output>90_000</output>
<gadget id="calculator">90_000 / 3_600</gadget>
<output>25</output>
<gadget id="calculator">650 / 25</gadget>
<output>26</output>
<gadget id="calculator">66 - 26</gadget>
<output>40</output>
<result>A</result> | A | 42 | Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.65 km respectively. The time taken by the slower train to cross the faster train in seconds is? | {
"A": "42",
"B": "77",
"C": "48",
"D": "99",
"E": "11"
} | subtract(divide(multiply(1.1, const_1000), divide(multiply(60, const_1000), const_3600)), divide(multiply(0.65, const_1000), divide(multiply(90, const_1000), const_3600))) | multiply(n2,const_1000)|multiply(n0,const_1000)|multiply(n3,const_1000)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#3,const_3600)|divide(#0,#4)|divide(#2,#5)|subtract(#6,#7) | relative speed = 60 + 90 = 150 km / hr . = 150 * 5 / 18 = 125 / 3 m / sec . distance covered = 1.10 + 0.65 = 1.75 km = 1750 m . required time = 1750 * 3 / 125 = 42 sec . answer : a | physics |
math_qa__WOQtXU32DDvq2hBf | The sum of the fourth and twelfth term of an arithmetic progression is 20. What is the sum of the first 10 terms of the arithmetic progression?
Choose the correct choice from the following answers
A) 300 B) 100 C) 150 D) 170 E) 270 | <gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">200 / 2</gadget>
<output>100</output>
<result>B</result> | B | 100 | The sum of the fourth and twelfth term of an arithmetic progression is 20. What is the sum of the first 10 terms of the arithmetic progression? | {
"A": "300",
"B": "100",
"C": "150",
"D": "170",
"E": "270"
} | divide(multiply(20, 10), const_2) | multiply(n0,n1)|divide(#0,const_2) | n th term of a . p . is given by a + ( n - 1 ) d 4 th term = a + 3 d 12 th term = a + 11 d given a + 3 d + a + 11 d = 20 - - > 2 a + 14 d = 20 - - > a + 7 d = 10 sum of n term of a . p = n / 2 [ 2 a + ( n - 1 ) d ] subsitiuing n = 10 . . . we get 10 / 2 [ 2 a + 14 d ] = 10 [ a + 7 d ] = 10 * 10 = 100 . . . answer is b . . . | general |
math_qa__Dw82iOGUrobo6Tyf | A salt manufacturing company produced a total of 3000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its ave66rage daily production for that year? Choose the correct choice from the following choices:
A) 119 B) 185 C) 190 D) 116 E) 200 | <gadget id="calculator">3_000 * 2</gadget>
<output>6_000</output>
<gadget id="calculator">12 - 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 100</gadget>
<output>1_100</output>
<gadget id="calculator">6_000 + 1_100</gadget>
<output>7_100</output>
<gadget id="calculator">7_100 * 12</gadget>
<output>85_200</output>
<gadget id="calculator">85_200 / 2</gadget>
<output>42_600</output>
<gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 10</gadget>
<output>60</output>
<gadget id="calculator">300 + 60</gadget>
<output>360</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">360 + 5</gadget>
<output>365</output>
<gadget id="calculator">42_600 / 365</gadget>
<output>8_520/73 = around 116.712329</output>
<result>D</result> | D | 116 | A salt manufacturing company produced a total of 3000 tonnes of salt in January of a particular year. Starting from February its production increased by 100 tonnes every month over the previous months until the end of the year. Find its ave66rage daily production for that year? | {
"A": "119",
"B": "185",
"C": "190",
"D": "116",
"E": "200"
} | divide(divide(multiply(add(multiply(3000, const_2), multiply(subtract(const_12, const_1), 100)), const_12), const_2), add(add(multiply(const_3, 100), multiply(multiply(const_2, const_3), const_10)), add(const_2, const_3))) | add(const_2,const_3)|multiply(n0,const_2)|multiply(n1,const_3)|multiply(const_2,const_3)|subtract(const_12,const_1)|multiply(n1,#4)|multiply(#3,const_10)|add(#1,#5)|add(#2,#6)|add(#8,#0)|multiply(#7,const_12)|divide(#10,const_2)|divide(#11,#9)| | "total production of salt by the company in that year = 3000 + 3100 + 3200 + . . . . + 4100 = 42600 . average monthly production of salt for that year = 42600 / 365 â ‰ ˆ 116 answer : d" | general |
math_qa__rQas4qydmpMmStTD | In a class of boys and girls Vikas's rank is 9th and Tanvi's rank is 17th . Vikas's rank among the boys in that class is 4th from the top and 18th from the bottom and Tanvi's rank among the girls is 8th from top and 21st from bottom. In the order of rank, how many girls are there between Tanvi and Vikas? Options
A) 29 B) 8 C) 2 D) 4 E) 6 | <gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">7 - 5</gadget>
<output>2</output>
<result>C</result> | C | 2 | In a class of boys and girls Vikas's rank is 9th and Tanvi's rank is 17th . Vikas's rank among the boys in that class is 4th from the top and 18th from the bottom and Tanvi's rank among the girls is 8th from top and 21st from bottom. In the order of rank, how many girls are there between Tanvi and Vikas? | {
"A": "29",
"B": "8",
"C": "2",
"D": "4",
"E": "6"
} | subtract(subtract(8, const_1), subtract(subtract(9, const_1), subtract(4, const_1))) | subtract(n4,const_1)|subtract(n0,const_1)|subtract(n2,const_1)|subtract(#1,#2)|subtract(#0,#3) | explanation : vikas ' s rank in the class is 9 . so there are 8 people before him . his rank among boys is 4 . so 3 boys are before him . so there are 8 – 3 = 5 girls before him . tanvi ' s rank among the girls is 8 . so there are 7 girls before her . so number of girls between vikas and tanvi is 7 – 5 = 2 answer : c | other |
math_qa__sfRIcoWNBOfRYICn | A certain company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio Q of revenue from car sales in 1996 to revenue from truck sales in 1996? Pick: A) 1 : 2 B) 4 : 5 C) 1 : 1 D) 3 : 2 E) 5 : 3 | <gadget id="calculator">100 + 7</gadget>
<output>107</output>
<gadget id="calculator">100 + 1</gadget>
<output>101</output>
<gadget id="calculator">107 - 101</gadget>
<output>6</output>
<gadget id="calculator">100 - 11</gadget>
<output>89</output>
<gadget id="calculator">101 - 89</gadget>
<output>12</output>
<gadget id="calculator">6 / 12</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | A certain company that sells only cars and trucks reported that revenues from car sales in 1997 were down 11 percent from 1996 and revenues from truck sales were up 7 percent from 1996. If total revenues from car sales and truck sales in 1997 were up 1 percent from 1996, what is the ratio Q of revenue from car sales in 1996 to revenue from truck sales in 1996? | {
"A": "1 : 2",
"B": "4 : 5",
"C": "1 : 1",
"D": "3 : 2",
"E": "5 : 3"
} | divide(subtract(add(const_100, 7), add(const_100, 1)), subtract(add(const_100, 1), subtract(const_100, 11))) | add(n3,const_100)|add(n6,const_100)|subtract(const_100,n1)|subtract(#0,#1)|subtract(#1,#2)|divide(#3,#4) | a . . i have probably solved this question 3 - 4 times by now . . remember the answer . . 1 : 2 | other |
math_qa__GIUfsfblqhG4eHVh | What least number must be subtracted from 652543 so that remaining no.is divisible by 12
Choose one:
A) 3 B) 5 C) 7 D) 8 E) 9 | <gadget id="calculator">652_543 / 12</gadget>
<output>652_543/12 = around 54_378.583333</output>
<gadget id="calculator">floor(652_543/12)</gadget>
<output>54_378</output>
<gadget id="calculator">54_378 * 12</gadget>
<output>652_536</output>
<gadget id="calculator">652_543 - 652_536</gadget>
<output>7</output>
<result>C</result> | C | 7 | What least number must be subtracted from 652543 so that remaining no.is divisible by 12 | {
"A": "3",
"B": "5",
"C": "7",
"D": "8",
"E": "9"
} | subtract(652543, multiply(floor(divide(652543, 12)), 12)) | divide(n0,n1)|floor(#0)|multiply(n1,#1)|subtract(n0,#2)| | "explanation : on dividing 652543 by 12 we get the remainder 7 , so 7 should be subtracted option c" | general |
math_qa__CgxW6c4TN8SabyBu | If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 25 men in 3 days?
Choose the most appropriate option:
A) 65 mtr . B) 52 mtr C) 70 mtr . D) 78 mtr . E) 17 mtr . | <gadget id="calculator">25 * 3</gadget>
<output>75</output>
<gadget id="calculator">20 * 6</gadget>
<output>120</output>
<gadget id="calculator">75 / 120</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">112 * (5/8)</gadget>
<output>70</output>
<result>C</result> | C | 70 | If 20 men can build a wall 112 metres long in 6 days, what length of a similar wall can be built by 25 men in 3 days? | {
"A": "65 mtr .",
"B": "52 mtr",
"C": "70 mtr .",
"D": "78 mtr .",
"E": "17 mtr ."
} | multiply(112, divide(multiply(25, 3), multiply(20, 6))) | multiply(n3,n4)|multiply(n0,n2)|divide(#0,#1)|multiply(n1,#2)| | "20 men is 6 days can build 112 metres 25 men in 3 days can build = 112 * ( 25 / 20 ) x ( 3 / 6 ) = 70 meters answer : c ." | physics |
math_qa__YWrndvdlyIrCpphf | If the sides of a triangle are 26 cm, 24 cm and 12 cm, what is its area? Choose the correct choice.
A) 144 B) 772 C) 288 D) 266 E) 2848 | <gadget id="calculator">24 * 12</gadget>
<output>288</output>
<gadget id="calculator">288 / 2</gadget>
<output>144</output>
<result>A</result> | A | 144 | If the sides of a triangle are 26 cm, 24 cm and 12 cm, what is its area? | {
"A": "144",
"B": "772",
"C": "288",
"D": "266",
"E": "2848"
} | divide(multiply(24, 12), const_2) | multiply(n1,n2)|divide(#0,const_2)| | "the triangle with sides 26 cm , 24 cm and 12 cm is right angled , where the hypotenuse is 26 cm . area of the triangle = 1 / 2 * 24 * 12 = 144 cm 2 answer : a" | geometry |
math_qa__Rs50I6vXcyrNY82G | In a certain candy store, 22% of the customers are caught sampling the candy and are charged a small fine, but 10% of the customers who sample the candy are not caught. What is the total percent of all customers who sample candy? Choices
A) 22 % B) 23 % C) 24.4 % D) 25 % E) 34 % | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">22 / (9/10)</gadget>
<output>220/9 = around 24.444444</output>
<result>C</result> | C | 24.4 | In a certain candy store, 22% of the customers are caught sampling the candy and are charged a small fine, but 10% of the customers who sample the candy are not caught. What is the total percent of all customers who sample candy? | {
"A": "22 %",
"B": "23 %",
"C": "24.4 %",
"D": "25 %",
"E": "34 %"
} | divide(22, divide(subtract(const_100, 10), const_100)) | subtract(const_100,n1)|divide(#0,const_100)|divide(n0,#1)| | "since 10 % of the customers who sample the candyare notcaught , then 90 % of the customers who sample the candyarecaught : { % of customers who sample candy } * 0.90 = 0.22 ; { % of customers who sample candy } = 0.25 . answer : c ." | gain |
math_qa__I5dgoIhRtS9oLkqb | Each month, after Jill pays for rent, utilities, food, and other necessary expenses, she has one fifth of her net monthly salary left as discretionary income. Of this discretionary income, she puts 30% into a vacation fund, 20% into savings, and spends 35% on eating out and socializing. This leaves her with $108 dollar, which she typically uses for gifts and charitable causes. What is Jill’s net monthly salary?
Choose the correct choice from the following answers: A) $ 2400 B) $ 3200 C) $ 6000 D) $ 3600 E) $ 9600 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">100 * 5</gadget>
<output>500</output>
<gadget id="calculator">30 + 20</gadget>
<output>50</output>
<gadget id="calculator">50 + 35</gadget>
<output>85</output>
<gadget id="calculator">100 - 85</gadget>
<output>15</output>
<gadget id="calculator">108 / 15</gadget>
<output>36/5 = around 7.2</output>
<gadget id="calculator">500 * (36/5)</gadget>
<output>3_600</output>
<result>D</result> | D | 3,600 | Each month, after Jill pays for rent, utilities, food, and other necessary expenses, she has one fifth of her net monthly salary left as discretionary income. Of this discretionary income, she puts 30% into a vacation fund, 20% into savings, and spends 35% on eating out and socializing. This leaves her with $108 dollar, which she typically uses for gifts and charitable causes. What is Jill’s net monthly salary? | {
"A": "$ 2400",
"B": "$ 3200",
"C": "$ 6000",
"D": "$ 3600",
"E": "$ 9600"
} | multiply(multiply(const_100, add(const_3, const_2)), divide(108, subtract(const_100, add(add(30, 20), 35)))) | add(n0,n1)|add(const_2,const_3)|add(n2,#0)|multiply(#1,const_100)|subtract(const_100,#2)|divide(n3,#4)|multiply(#5,#3)| | "let x be the monthly salary 15 % of 1 / 5 * x = 108 x = 3600 answer d" | gain |
math_qa__FEmzLYzsJjQv9Lfs | A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2475? Choose the correct answer.
A) s . 800
B) s . 810
C) s . 825
D) s . 900
E) s . 920 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">2_475 * (1/3)</gadget>
<output>825</output>
<result>C</result> | C | 825 | A, B, C and D enter into partnership. A subscribes 1/3 of the capital B 1/4, C 1/5 and D the rest. How much share did A get in a profit of Rs.2475? | {
"A": "s . 800",
"B": "s . 810",
"C": "s . 825",
"D": "s . 900",
"E": "s . 920"
} | multiply(2475, divide(1, 3)) | divide(n0,n1)|multiply(n6,#0)| | "2475 * 1 / 3 = 825 option c" | general |
math_qa__PMvM1sRBfCRPRRaZ | A rectangular tank measuring 5 m × 4.5 m × 2.1 m is dug in the centre of the field measuring 13.5 m × 2.5. The earth dug out is spread evenly over the remaining portion of a field. How much is the level of the field raised ? Choose the correct choice from the following choices:
A) 4.0 m
B) 4.1 m
C) 4.2 m
D) 4.3 m
E) none of these | <gadget id="calculator">5 * 4.5</gadget>
<output>22.5</output>
<gadget id="calculator">22.5 * 2.1</gadget>
<output>47.25</output>
<gadget id="calculator">13.5 * 2.5</gadget>
<output>33.75</output>
<gadget id="calculator">33.75 - 22.5</gadget>
<output>11.25</output>
<gadget id="calculator">47.25 / 11.25</gadget>
<output>4.2</output>
<result>C</result> | C | 4.2 | A rectangular tank measuring 5 m × 4.5 m × 2.1 m is dug in the centre of the field measuring 13.5 m × 2.5. The earth dug out is spread evenly over the remaining portion of a field. How much is the level of the field raised ? | {
"A": "4.0 m",
"B": "4.1 m",
"C": "4.2 m",
"D": "4.3 m",
"E": "none of these"
} | divide(multiply(multiply(5, 4.5), 2.1), subtract(multiply(13.5, 2.5), multiply(5, 4.5))) | multiply(n0,n1)|multiply(n3,n4)|multiply(n2,#0)|subtract(#1,#0)|divide(#2,#3) | area of the field = 13.5 × 2.5 = 33.75 m 2 area covered by the rectangular tank = 5 × 4.5 = 22.50 m 2 area of the field on which the earth dug out is to be spread = 33.75 – 22.50 = 11.25 m 2 let the required height be h . then , 11.25 × h = 5 × 4.5 × 2.1 or h = 4.2 m answer c | physics |
math_qa__e76sKSWRAqx5ipDq | A batsman makes a score of 80 runs in the 11th inning and thus increases his average by 5. Find his average after 11th inning. Choose the correct choice.
A) 40 B) 50 C) 62 D) 30 E) 56 | <gadget id="calculator">11 * 5</gadget>
<output>55</output>
<gadget id="calculator">80 - 55</gadget>
<output>25</output>
<gadget id="calculator">25 + 5</gadget>
<output>30</output>
<result>D</result> | D | 30 | A batsman makes a score of 80 runs in the 11th inning and thus increases his average by 5. Find his average after 11th inning. | {
"A": "40",
"B": "50",
"C": "62",
"D": "30",
"E": "56"
} | add(subtract(80, multiply(11, 5)), 5) | multiply(n1,n2)|subtract(n0,#0)|add(n2,#1)| | "let the average after 11 th inning = x then , average after 10 th inning = x - 5 10 ( x - 5 ) + 80 = 11 x x = 80 - 50 = 30 answer is d" | general |
math_qa__GWSkBGGY3PQplEkd | Paul has to secure 50% marks to clear his exam of class 7th.
He got 50 marks and failed by 10 marks.
What is the maximum marks ? Choose the correct choice
A) 100
B) 110
C) 120
D) 210
E) 200 | <gadget id="calculator">50 + 10</gadget>
<output>60</output>
<gadget id="calculator">60 * 100</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 50</gadget>
<output>120</output>
<result>C</result> | C | 120 | Paul has to secure 50% marks to clear his exam of class 7th.
He got 50 marks and failed by 10 marks.
What is the maximum marks ? | {
"A": "100",
"B": "110",
"C": "120",
"D": "210",
"E": "200"
} | divide(multiply(add(50, 10), const_100), 50) | add(n0,n3)|multiply(#0,const_100)|divide(#1,n0) | c 120 to pass the exam ravish needs 50 + 10 = 60 marks . = > ( 60 / 50 ) * 100 = 120 | gain |
math_qa__DVDwnXHJLuT6ZO7l | On a two-dimensional coordinate plane, the line s = x^2 - x^3 touches the x-axis in how many places? Choose the most appropriate option:
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">max(3, 2)</gadget>
<output>3</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<result>C</result> | C | 2 | On a two-dimensional coordinate plane, the line s = x^2 - x^3 touches the x-axis in how many places? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | subtract(max(3, 2), const_1) | max(n0,n1)|subtract(#0,const_1)| | "apparently it ' s s = x ^ 2 - x ^ 3 instead of s = x ^ 2 - s ^ 3 . in this case : the x - intercept is the value ( s ) of x for s = 0 . 0 = x ^ 2 - x ^ 3 ; 0 = x ^ 2 ( 1 - x ) ; x = 0 or x = 1 . answer : c ." | general |
math_qa__2ve6uTu54YgI00Gd | Two vertical ladders length of 6 m and 11 m are kept vertically at a distance of 12 m. Find the top distance of both ladders?
Choose one
A) 22 B) 27 C) 13 D) 19 E) 17 | <gadget id="calculator">11 - 6</gadget>
<output>5</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">25 + 144</gadget>
<output>169</output>
<gadget id="calculator">169 ** (1/2)</gadget>
<output>13</output>
<result>C</result> | C | 13 | Two vertical ladders length of 6 m and 11 m are kept vertically at a distance of 12 m. Find the top distance of both ladders? | {
"A": "22",
"B": "27",
"C": "13",
"D": "19",
"E": "17"
} | sqrt(add(power(subtract(11, 6), const_2), power(12, const_2))) | power(n2,const_2)|subtract(n1,n0)|power(#1,const_2)|add(#2,#0)|sqrt(#3) | so distance between the top points = ad = 122 + 52 − − − − − − − √ = 13122 + 52 = 13 so in paper b he did well . answer : c | physics |
math_qa__hAecL52NCzm14yZ5 | The volume of a certain substance is always directly proportional to its weight. If 48 cubic inches of the substance weigh 112 ounces, what is the volume, in cubic inches, of 84 ounces of this substance?
Choose the correct choice from the following choices: A) 27 B) 36 C) 42 D) 64 E) 147 | <gadget id="calculator">48 / 112</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(3/7) * 84</gadget>
<output>36</output>
<result>B</result> | B | 36 | The volume of a certain substance is always directly proportional to its weight. If 48 cubic inches of the substance weigh 112 ounces, what is the volume, in cubic inches, of 84 ounces of this substance? | {
"A": "27",
"B": "36",
"C": "42",
"D": "64",
"E": "147"
} | multiply(divide(48, 112), 84) | divide(n0,n1)|multiply(n2,#0) | 112 ounces of a substance has a volume of 48 cubic inches 84 ounces of a substance has a volume of ( 48 / 112 ) * 84 = 36 cubic inches answer b | geometry |
math_qa__JoP9CDtfPBgpWfV7 | A batsman makes a score of 95 runs in the 11th inning and thus increases his average by 5. Find his average after 11th inning.
Select:
A) 40
B) 50
C) 62
D) 45
E) 56 | <gadget id="calculator">11 * 5</gadget>
<output>55</output>
<gadget id="calculator">95 - 55</gadget>
<output>40</output>
<gadget id="calculator">40 + 5</gadget>
<output>45</output>
<result>D</result> | D | 45 | A batsman makes a score of 95 runs in the 11th inning and thus increases his average by 5. Find his average after 11th inning. | {
"A": "40",
"B": "50",
"C": "62",
"D": "45",
"E": "56"
} | add(subtract(95, multiply(11, 5)), 5) | multiply(n1,n2)|subtract(n0,#0)|add(n2,#1)| | "let the average after 11 th inning = x then , average after 10 th inning = x - 5 10 ( x - 5 ) + 95 = 11 x x = 95 - 50 = 45 answer is d" | general |
math_qa__9aU9qHzBSEjitQRY | A cistern can be filled by a tap in 7 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled ? Select:
A) 4.5 hrs
B) 5 hrs
C) 6.5 hrs
D) 17.2 hrs
E) 31.5 hrs | <gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/7) - (1/9)</gadget>
<output>2/63 = around 0.031746</output>
<gadget id="calculator">1 / (2/63)</gadget>
<output>63/2 = around 31.5</output>
<result>E</result> | E | 31.5 | A cistern can be filled by a tap in 7 hours while it can be emptied by another tap in 9 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled ? | {
"A": "4.5 hrs",
"B": "5 hrs",
"C": "6.5 hrs",
"D": "17.2 hrs",
"E": "31.5 hrs"
} | divide(const_1, subtract(divide(const_1, 7), divide(const_1, 9))) | divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|divide(const_1,#2)| | "net part filled in 1 hour = 1 / 7 - 1 / 9 = 2 / 63 therefore the cistern will be filled in 63 / 2 hours or 31.5 hours . answer : e" | physics |
math_qa__eptYEx4jjqHR2p36 | 16.036 divided by 0.04 gives : Options: A) 40.09 B) 4.06 C) 40.06 D) 400.9 E) 400.6 | <gadget id="calculator">16.036 / 0.04</gadget>
<output>400.9</output>
<result>D</result> | D | 400.9 | 16.036 divided by 0.04 gives : | {
"A": "40.09",
"B": "4.06",
"C": "40.06",
"D": "400.9",
"E": "400.6"
} | divide(16.036, 0.04) | divide(n0,n1) | = 16.036 / 0.04 = 1603.6 / 4 = 400.9 answer is d . | general |
math_qa__sQ7ez3QuYwP2L0TJ | A canoe has two oars, left and right. Each oar either works or breaks. The failure or non-failure of each oar is independent of the failure or non-failure of the other. You can still row the canoe with one oar. The probability that the left oar works is 3/5. The probability that the right oar works is also 3/5. What is the probability R that you can still row the canoe? Choose the correct choice from the following choices: A) 9 / 25 B) 10 / 25 C) 6 / 10 D) 2 / 3 E) 21 / 25 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * (3/5)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/5) * (2/5)</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">(6/25) + (6/25)</gadget>
<output>12/25 = around 0.48</output>
<gadget id="calculator">(9/25) + (12/25)</gadget>
<output>21/25 = around 0.84</output>
<result>E</result> | E | 0.84 | A canoe has two oars, left and right. Each oar either works or breaks. The failure or non-failure of each oar is independent of the failure or non-failure of the other. You can still row the canoe with one oar. The probability that the left oar works is 3/5. The probability that the right oar works is also 3/5. What is the probability R that you can still row the canoe? | {
"A": "9 / 25",
"B": "10 / 25",
"C": "6 / 10",
"D": "2 / 3",
"E": "21 / 25"
} | add(multiply(divide(3, 5), divide(3, 5)), add(multiply(divide(3, 5), divide(const_2, 5)), multiply(divide(3, 5), divide(const_2, 5)))) | divide(n0,n1)|divide(const_2,n1)|multiply(#0,#1)|multiply(#0,#0)|add(#2,#2)|add(#4,#3)| | "simply look at the question from the other side . what is the probability that you can ’ t row the canoe ? this would be 2 / 5 x 2 / 5 = 4 / 25 . using the idea that the probability of something happening is 1 – the probability that it doesn ’ t happen , you can use the following equation to reach the right answer r : 1 – 4 / 25 = 21 / 25 . answer choice e ." | general |
math_qa__0OpKEgX5NL0aXvvJ | A is the average (arithmetic mean) of the first 7 positive multiples of 8 and B is the median of the first 3 positive multiples of positive integer n. If the value of A^2 – B^2 is zero, what is the value of n? Choose the correct option
A) 10 B) 12 C) 16 D) 24 E) 32 | <gadget id="calculator">8 * 4</gadget>
<output>32</output>
<gadget id="calculator">32 / 2</gadget>
<output>16</output>
<result>C</result> | C | 16 | A is the average (arithmetic mean) of the first 7 positive multiples of 8 and B is the median of the first 3 positive multiples of positive integer n. If the value of A^2 – B^2 is zero, what is the value of n? | {
"A": "10",
"B": "12",
"C": "16",
"D": "24",
"E": "32"
} | divide(multiply(8, const_4), 2) | multiply(n1,const_4)|divide(#0,n3)| | "if a ^ 2 - b ^ 2 = 0 , then let ' s assume that a = b . a must equal the 4 th positive multiple of 4 , thus a = 32 , which also equals b . b is the second positive multiple of n , thus n = 32 / 2 = 16 . the answer is c ." | general |
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