id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__zihQHTVgc7A17XdJ | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 67 kg. What is the weight of the new person? Choose the correct answer.
A) 75 B) 65 C) 87 D) 95 E) 80 | <gadget id="calculator">8 * 2.5</gadget>
<output>20</output>
<gadget id="calculator">20 + 67</gadget>
<output>87</output>
<result>C</result> | C | 87 | The average weight of 8 person's increases by 2.5 kg when a new person comes in place of one of them weighing 67 kg. What is the weight of the new person? | {
"A": "75",
"B": "65",
"C": "87",
"D": "95",
"E": "80"
} | add(multiply(8, 2.5), 67) | multiply(n0,n1)|add(n2,#0)| | "total increase in weight = 8 × 2.5 = 20 if x is the weight of the new person , total increase in weight = x − 67 = > 20 = x - 67 = > x = 20 + 67 = 87 answer is c ." | general |
math_qa__LzUYYzzvYBW55nTb | If a#b = ab – b + b^2, then 3#8 = Choose the most appropriate option:
A) 80 B) 8 C) 15 D) 21 E) 35 | <gadget id="calculator">3 * 8</gadget>
<output>24</output>
<gadget id="calculator">24 - 8</gadget>
<output>16</output>
<gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">16 + 64</gadget>
<output>80</output>
<result>A</result> | A | 80 | If a#b = ab – b + b^2, then 3#8 = | {
"A": "80",
"B": "8",
"C": "15",
"D": "21",
"E": "35"
} | add(subtract(multiply(3, 8), 8), power(8, 2)) | multiply(n1,n2)|power(n2,n0)|subtract(#0,n2)|add(#1,#2)| | "solution - simply substitute 3 and 8 in equation in the place of a and b respectively . 3 # 8 = 3 * 8 - 8 + 8 ^ 2 = 24 - 8 + 64 = 80 . ans a" | general |
math_qa__xWTTz0it4tPfB2Pe | A marching band of 240 musicians are to march in a rectangular formation with s rows of exactly t musicians each. There can be no less than 8 musicians per row and no more than 30 musicians per row. How many different rectangular formations Z are possible? Choose the correct answer: A) 3 B) z = 4 C) z = 5 D) z = 6 E) z = 8 | <gadget id="calculator">240 / 30</gadget>
<output>8</output>
<result>E</result> | E | 8 | A marching band of 240 musicians are to march in a rectangular formation with s rows of exactly t musicians each. There can be no less than 8 musicians per row and no more than 30 musicians per row. How many different rectangular formations Z are possible? | {
"A": "3",
"B": "z = 4",
"C": "z = 5",
"D": "z = 6",
"E": "z = 8"
} | divide(240, 30) | divide(n0,n2)| | "the combinations could be { ( 1,240 ) , ( 2,120 ) , ( 3,80 ) , ( 4,60 ) , ( 5,48 ) , ( 6,40 ) , ( 8,30 ) , ( 10,24 ) , ( 12,20 ) , ) 15,16 ) , ( 16,15 ) , ( 20,12 ) , ( 24,10 ) , ( 30,8 ) , ( 40,6 ) , ( 48,5 ) , ( 60,4 ) , ( 80,3 ) , ( 120,2 ) , ( 240,1 ) } of these we are told 8 < = t < = 30 so we can remove these pairs , and we are left only with . { ( 8,30 , ( 10,24 ) , ( 12,20 ) , ( 15,16 ) , ( 16,15 ) , ( 20,12 ) , ( 24,10 ) , ( 30,8 ) } hence 8 . e" | general |
math_qa__2SE25i0I53HEWzBC | Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 37 pages per hour. If Tom starts reading a novel at 4:00, and Jan begins reading an identical copy of the same book at 4:56, at what time will they be reading the same page? Choose the correct choice from the following.
A) 7 : 26 B) 7 : 56 C) 8 : 26 D) 8 : 56 E) 9 : 26 | <gadget id="calculator">4 - 4</gadget>
<output>0</output>
<gadget id="calculator">56 - 0</gadget>
<output>56</output>
<gadget id="calculator">56 / 60</gadget>
<output>14/15 = around 0.933333</output>
<gadget id="calculator">0 + (14/15)</gadget>
<output>14/15 = around 0.933333</output>
<gadget id="calculator">(14/15) * 30</gadget>
<output>28</output>
<gadget id="calculator">37 - 30</gadget>
<output>7</output>
<gadget id="calculator">28 / 7</gadget>
<output>4</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<gadget id="calculator">8 / 56</gadget>
<output>1/7 = around 0.142857</output>
<result>D</result> | D | 0.142857 | Tom reads at an average rate of 30 pages per hour, while Jan reads at an average rate of 37 pages per hour. If Tom starts reading a novel at 4:00, and Jan begins reading an identical copy of the same book at 4:56, at what time will they be reading the same page? | {
"A": "7 : 26",
"B": "7 : 56",
"C": "8 : 26",
"D": "8 : 56",
"E": "9 : 26"
} | divide(add(4, divide(multiply(add(subtract(4, 4), divide(subtract(56, 00), const_60)), 30), subtract(37, 30))), 56) | subtract(n5,n3)|subtract(n4,n2)|subtract(n1,n0)|divide(#0,const_60)|add(#3,#1)|multiply(n0,#4)|divide(#5,#2)|add(n4,#6)|divide(#7,n5)| | "since tom reads an average of 1 page every 2 minutes , tom will read 28 pages in the first 56 minutes . jan can catch tom at a rate of 7 pages per hour , so it will take 4 hours to catch tom . the answer is d ." | general |
math_qa__XX5NYsNmNHKEDP5Q | Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 42 years. What is Deepak present age. Pick.
A) 14 B) 15 C) 20 D) 22 E) 27 | <gadget id="calculator">42 - 6</gadget>
<output>36</output>
<gadget id="calculator">36 * 3</gadget>
<output>108</output>
<gadget id="calculator">108 / 4</gadget>
<output>27</output>
<result>E</result> | E | 27 | Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 42 years. What is Deepak present age. | {
"A": "14",
"B": "15",
"C": "20",
"D": "22",
"E": "27"
} | divide(multiply(subtract(42, 6), 3), 4) | subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0)| | "explanation : present age is 4 x and 3 x , = > 4 x + 6 = 42 = > x = 9 so deepak age is = 3 ( 9 ) = 27 option e" | other |
math_qa__zLQmb8JLQeDoCP3c | An outlet pipe can empty 2/3 of a cistern in 20 minutes. In 8 minutes, what part of the cistern will be emptied? Choose the correct choice from the following choices: A) 1 / 2 B) 1 / 3 C) 2 / 9 D) 4 / 15 E) 9 / 20 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">8 * (2/3)</gadget>
<output>16/3 = around 5.333333</output>
<gadget id="calculator">(16/3) / 20</gadget>
<output>4/15 = around 0.266667</output>
<result>D</result> | D | 0.266667 | An outlet pipe can empty 2/3 of a cistern in 20 minutes. In 8 minutes, what part of the cistern will be emptied? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "2 / 9",
"D": "4 / 15",
"E": "9 / 20"
} | divide(multiply(8, divide(2, 3)), 20) | divide(n0,n1)|multiply(n3,#0)|divide(#1,n2)| | "8 / 20 * 2 / 3 = 4 / 15 the answer is d ." | physics |
math_qa__QzhSuPIAJelIjzOU | The number of diagonals of a polygon of n sides is given by the formula f=n(n-3)/2. If a polygon has twice as many diagonals as sides, how many sides does it have? Choose the correct answer:
A) 3
B) 5
C) 6
D) 7
E) 8 | <gadget id="calculator">3 + 2</gadget>
<output>5</output>
<result>B</result> | B | 5 | The number of diagonals of a polygon of n sides is given by the formula f=n(n-3)/2. If a polygon has twice as many diagonals as sides, how many sides does it have? | {
"A": "3",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | add(3, 2) | add(n0,n1)| | "f = n ( n - 3 ) f = 2 * n 2 n = n ( n - 3 ) = > 2 = n - 3 = > n = 5 answer b" | general |
math_qa__17jA5eZvy4xX6n1W | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 16 sec. What is the length of the platform? Choose the correct answer: A) 287 m B) 431.25 m C) 267 m D) 287.25 m E) 656 m | <gadget id="calculator">300 / 16</gadget>
<output>75/4 = around 18.75</output>
<gadget id="calculator">(75/4) * 39</gadget>
<output>2_925/4 = around 731.25</output>
<gadget id="calculator">(2_925/4) - 300</gadget>
<output>1_725/4 = around 431.25</output>
<result>B</result> | B | 431.25 | A 300 m long train crosses a platform in 39 sec while it crosses a signal pole in 16 sec. What is the length of the platform? | {
"A": "287 m",
"B": "431.25 m",
"C": "267 m",
"D": "287.25 m",
"E": "656 m"
} | subtract(multiply(speed(300, 16), 39), 300) | speed(n0,n2)|multiply(n1,#0)|subtract(#1,n0)| | "speed = 300 / 16 = 75 / 4 m / sec . let the length of the platform be x meters . then , ( x + 300 ) / 39 = 75 / 4 = > x = 731.25 m answer : b ( 431.25 )" | physics |
math_qa__5fpDyBDON2942023 | Two poles of height 6 meters and 11 meters stand on a plane ground. If the distance between their feet is 12 meters then find the difference in the distance between their tops: Choose the correct choice from the following:
A) 12 m B) 5 m C) 13 m D) 11 m E) 12 m | <gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">11 - 6</gadget>
<output>5</output>
<gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">144 + 25</gadget>
<output>169</output>
<gadget id="calculator">169 ** (1/2)</gadget>
<output>13</output>
<result>C</result> | C | 13 | Two poles of height 6 meters and 11 meters stand on a plane ground. If the distance between their feet is 12 meters then find the difference in the distance between their tops: | {
"A": "12 m",
"B": "5 m",
"C": "13 m",
"D": "11 m",
"E": "12 m"
} | sqrt(add(power(12, const_2), power(subtract(11, 6), const_2))) | power(n2,const_2)|subtract(n1,n0)|power(#1,const_2)|add(#0,#2)|sqrt(#3) | distance between their tops = sqrt ( 12 ^ 2 + ( 11 - 6 ) ^ 2 ) = sqrt 169 = 13 m answer : c | physics |
math_qa__OUTulABWlfpmvSMF | If Teena is driving at 55 miles per hour and is currently 7.5 miles behind Loe, who is driving at 40 miles per hour in the same direction then in how many minutes will Teena be 15 miles ahead of Loe?
Choose the correct choice from the following options
A) 15 B) 60 C) 75 D) 90 E) 105 | <gadget id="calculator">55 - 40</gadget>
<output>15</output>
<gadget id="calculator">15 + 7.5</gadget>
<output>22.5</output>
<gadget id="calculator">22.5 / 15</gadget>
<output>1.5</output>
<gadget id="calculator">1.5 * 60</gadget>
<output>90</output>
<result>D</result> | D | 90 | If Teena is driving at 55 miles per hour and is currently 7.5 miles behind Loe, who is driving at 40 miles per hour in the same direction then in how many minutes will Teena be 15 miles ahead of Loe? | {
"A": "15",
"B": "60",
"C": "75",
"D": "90",
"E": "105"
} | multiply(divide(add(subtract(55, 40), 7.5), subtract(55, 40)), const_60) | subtract(n0,n2)|add(n1,#0)|divide(#1,#0)|multiply(#2,const_60)| | "this type of questions should be solved without any complex calculations as these questions become imperative in gaining that extra 30 - 40 seconds for a difficult one . teena covers 55 miles in 60 mins . loe covers 40 miles in 60 mins so teena gains 15 miles every 60 mins teena need to cover 7.5 + 15 miles . teena can cover 7.5 miles in 30 mins teena will cover 15 miles in 60 mins so answer 30 + 60 = 90 mins . d" | physics |
math_qa__osoQSLKFMvUlK0KL | A bag contains 4red, 5blue and 3green balls. If 3 ballsare picked at random, what is the probability that both are red? Options.
A) 1 / 33 B) 1 / 22 C) 1 / 12 D) 1 / 44 E) 1 / 55 | <gadget id="calculator">binomial(4, 3)</gadget>
<output>4</output>
<gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">9 + 3</gadget>
<output>12</output>
<gadget id="calculator">binomial(12, 3)</gadget>
<output>220</output>
<gadget id="calculator">4 / 220</gadget>
<output>1/55 = around 0.018182</output>
<result>E</result> | E | 0.018182 | A bag contains 4red, 5blue and 3green balls. If 3 ballsare picked at random, what is the probability that both are red? | {
"A": "1 / 33",
"B": "1 / 22",
"C": "1 / 12",
"D": "1 / 44",
"E": "1 / 55"
} | divide(choose(4, 3), choose(add(add(4, 5), 3), 3)) | add(n0,n1)|choose(n0,n3)|add(n2,#0)|choose(#2,n3)|divide(#1,#3)| | "p ( both are red ) , = 4 c 3 / 12 c 3 = 1 / 55 e" | other |
math_qa__YvrOrUdVqnXNyXdp | The amount of time that three people worked on a special project was in the ratio of 3 to 5 to 6. If the project took 140 hours, how many more hours did the hardest working person work than the person who worked the least?
Choose the correct option
A) 32 hours B) 40 hours C) 35 hours D) 30 hours E) 36 hours | <gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">8 + 6</gadget>
<output>14</output>
<gadget id="calculator">140 / 14</gadget>
<output>10</output>
<gadget id="calculator">10 * 6</gadget>
<output>60</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<gadget id="calculator">60 - 30</gadget>
<output>30</output>
<result>D</result> | D | 30 | The amount of time that three people worked on a special project was in the ratio of 3 to 5 to 6. If the project took 140 hours, how many more hours did the hardest working person work than the person who worked the least? | {
"A": "32 hours",
"B": "40 hours",
"C": "35 hours",
"D": "30 hours",
"E": "36 hours"
} | subtract(multiply(divide(140, add(add(3, 5), 6)), 6), multiply(divide(140, add(add(3, 5), 6)), 3)) | add(n0,n1)|add(n2,#0)|divide(n3,#1)|multiply(n2,#2)|multiply(n0,#2)|subtract(#3,#4)| | "let the persons be a , b , c . hours worked : a = 3 * 140 / 14 = 30 hours b = 5 * 140 / 14 = 50 hours c = 6 * 140 / 14 = 60 hours c is the hardest worker and a worked for the least number of hours . so the difference is 60 - 30 = 30 hours . answer : d" | physics |
math_qa__59tmgy3CHc0HaB9L | A student gets 60% in one subject, 80% in the other. To get an overall of 75% how much should get in third subject.
Choose one:
A) 75 %
B) 25 %
C) 85 %
D) 55 %
E) 65 % | <gadget id="calculator">75 * 3</gadget>
<output>225</output>
<gadget id="calculator">60 + 80</gadget>
<output>140</output>
<gadget id="calculator">225 - 140</gadget>
<output>85</output>
<result>C</result> | C | 85 | A student gets 60% in one subject, 80% in the other. To get an overall of 75% how much should get in third subject. | {
"A": "75 %",
"B": "25 %",
"C": "85 %",
"D": "55 %",
"E": "65 %"
} | subtract(multiply(75, const_3), add(60, 80)) | add(n0,n1)|multiply(n2,const_3)|subtract(#1,#0) | let the 3 rd subject % = x 60 + 80 + x = 3 * 75 140 + x = 225 x = 225 - 140 = 85 answer : c | gain |
math_qa__fAz3LpoxWw9vLNj1 | John and Jane went out for a dinner and they ordered the same dish. Both used a 10% discount coupon. John paid a 15% tip over the original price of the dish, while Jane paid the tip over the discounted price for the coupon. If John paid $0.36 more than Jane, what was the original price of the dish? Select the correct option:
A) 24 B) 34.8 C) 37.8 D) 42 E) 84 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(9/10) * (3/20)</gadget>
<output>27/200 = around 0.135</output>
<gadget id="calculator">(3/20) - (27/200)</gadget>
<output>3/200 = around 0.015</output>
<gadget id="calculator">0.36 / (3/200)</gadget>
<output>24</output>
<result>A</result> | A | 24 | John and Jane went out for a dinner and they ordered the same dish. Both used a 10% discount coupon. John paid a 15% tip over the original price of the dish, while Jane paid the tip over the discounted price for the coupon. If John paid $0.36 more than Jane, what was the original price of the dish? | {
"A": "24",
"B": "34.8",
"C": "37.8",
"D": "42",
"E": "84"
} | divide(0.36, subtract(divide(15, const_100), multiply(subtract(const_1, divide(10, const_100)), divide(15, const_100)))) | divide(n1,const_100)|divide(n0,const_100)|subtract(const_1,#1)|multiply(#0,#2)|subtract(#0,#3)|divide(n2,#4)| | "the difference between the amounts john paid and jane paid is the deference between 15 % of p and 15 % of 0.9 p : 0.15 p - 0.15 * 0.9 p = 0.36 - - > 15 p - 13.5 p = 36 - - > p = 24 . answer : a ." | gain |
math_qa__gAlzt9yyfgIKuIUw | two pumps are connected to an empty tank . pump x fills the tank with water at a constant rate , while pump y drains water out of the tank at a constant rate . the two pumps finish filling the tank in 6 times the duration it would take pump x alone to fill the tank . if pump y alone can empty a whole tank in 48 minutes , then how many minutes does it take pump x alone to fill the tank ? Pick one.
A) 32
B) 34
C) 36
D) 38
E) 40 | <gadget id="calculator">48 / 6</gadget>
<output>8</output>
<gadget id="calculator">48 - 8</gadget>
<output>40</output>
<result>E</result> | E | 40 | two pumps are connected to an empty tank . pump x fills the tank with water at a constant rate , while pump y drains water out of the tank at a constant rate . the two pumps finish filling the tank in 6 times the duration it would take pump x alone to fill the tank . if pump y alone can empty a whole tank in 48 minutes , then how many minutes does it take pump x alone to fill the tank ? | {
"A": "32",
"B": "34",
"C": "36",
"D": "38",
"E": "40"
} | subtract(48, divide(48, 6)) | divide(n1,n0)|subtract(n1,#0) | let v be the volume of the tank . let r be the rate per minute that pump x fills the tank . let t be the time it takes pump x to fill the tank . the rate at which pump y empties the tank is v / 48 per minute . ( r - v / 48 ) * 6 t = v = rt . ( r - v / 48 ) * 6 = r 5 r = v / 8 . r = v / 40 . it takes pump x 40 minutes to fill the tank . the answer is e . | physics |
math_qa__LcOsdWnFjmyyVYHi | A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs.16.80 less, he would have gained 30%. Find the cost of the article.
Choose the correct choice from the following answers:
A) 30 B) 40 C) 50 D) 60 E) 80 | <gadget id="calculator">16.8 * 100</gadget>
<output>1_680</output>
<gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">30 + 100</gadget>
<output>130</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">130 * 80</gadget>
<output>10_400</output>
<gadget id="calculator">10_400 / 100</gadget>
<output>104</output>
<gadget id="calculator">125 - 104</gadget>
<output>21</output>
<gadget id="calculator">1_680 / 21</gadget>
<output>80</output>
<result>E</result> | E | 80 | A man sells an article at a profit of 25%. If he had bought it at 20% less and sold it for Rs.16.80 less, he would have gained 30%. Find the cost of the article. | {
"A": "30",
"B": "40",
"C": "50",
"D": "60",
"E": "80"
} | divide(multiply(16.80, const_100), subtract(add(25, const_100), divide(multiply(add(30, const_100), subtract(const_100, 20)), const_100))) | add(n0,const_100)|add(n3,const_100)|multiply(n2,const_100)|subtract(const_100,n1)|multiply(#1,#3)|divide(#4,const_100)|subtract(#0,#5)|divide(#2,#6)| | "let c . p = 100 gain = 25 % s . p = 125 supposed c . p = 80 gain = 30 % s . p = ( 130 * 80 ) / 100 = 104 diff = ( 125 - 104 ) = 21 diff 21 when c . p = 100 then diff 16.80 when c . p = ( 100 * 16.80 ) / 21 = 50 answer : e" | gain |
math_qa__G5LMMFIDiRoqYNtk | given a two - digit number , the unit ' s digit exceeds its 10 ' s digit by 5 and the product of the given number and the sum of its digits is equal to 90 , which of the options is the number ?
Options:
A) 27
B) 16
C) 38
D) 61
E) 83 | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">5 * 11</gadget>
<output>55</output>
<gadget id="calculator">55 + 10</gadget>
<output>65</output>
<gadget id="calculator">65 * 65</gadget>
<output>4_225</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">60 * 4</gadget>
<output>240</output>
<gadget id="calculator">240 + 3</gadget>
<output>243</output>
<gadget id="calculator">25 - 243</gadget>
<output>-218</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">(-218) * 22</gadget>
<output>-4_796</output>
<gadget id="calculator">(-4_796) * 4</gadget>
<output>-19_184</output>
<gadget id="calculator">4_225 - (-19_184)</gadget>
<output>23_409</output>
<gadget id="calculator">23_409 ** (1/2)</gadget>
<output>153</output>
<gadget id="calculator">153 - 65</gadget>
<output>88</output>
<gadget id="calculator">22 * 2</gadget>
<output>44</output>
<gadget id="calculator">88 / 44</gadget>
<output>2</output>
<gadget id="calculator">2 + 5</gadget>
<output>7</output>
<gadget id="calculator">20 + 7</gadget>
<output>27</output>
<result>A</result> | A | 27 | given a two - digit number , the unit ' s digit exceeds its 10 ' s digit by 5 and the product of the given number and the sum of its digits is equal to 90 , which of the options is the number ? | {
"A": "27",
"B": "16",
"C": "38",
"D": "61",
"E": "83"
} | add(multiply(const_2, 10), add(divide(subtract(sqrt(subtract(multiply(add(multiply(5, add(10, const_1)), 10), add(multiply(5, add(10, const_1)), 10)), multiply(multiply(subtract(multiply(5, 5), add(multiply(const_60, const_4), const_3)), multiply(add(10, const_1), const_2)), const_4))), add(multiply(5, add(10, const_1)), 10)), multiply(multiply(add(10, const_1), const_2), const_2)), 5)) | add(n0,const_1)|multiply(n1,n1)|multiply(const_4,const_60)|multiply(n0,const_2)|add(#2,const_3)|multiply(n1,#0)|multiply(#0,const_2)|add(n0,#5)|multiply(#6,const_2)|subtract(#1,#4)|multiply(#7,#7)|multiply(#6,#9)|multiply(#11,const_4)|subtract(#10,#12)|sqrt(#13)|subtract(#14,#7)|divide(#15,#8)|add(n1,#16)|add(#17,#3) | using the elimination method the option that fits this description is 27 7 - 2 = 5 ( unit ' s digit that exceeds its ten ' s digit by 3 ) 27 * 9 = 243 ( the product of the given number and the sum of its digits is equal to 175 ) answer : a | general |
math_qa__dpQ7nxQkwa4gHTiw | If “*†is called “+â€, “/†is called “*â€, “-†is called “/â€, “+†is called “-â€. 240-80 / 60 - 40 * 10 = ? Choices:
A) 14.5
B) 13.5
C) 12.5
D) 17.5
E) 11.5 | <gadget id="calculator">60 / 40</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">240 / 80</gadget>
<output>3</output>
<gadget id="calculator">(3/2) * 3</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">(9/2) + 10</gadget>
<output>29/2 = around 14.5</output>
<result>A</result> | A | 14.5 | If “*†is called “+â€, “/†is called “*â€, “-†is called “/â€, “+†is called “-â€. 240-80 / 60 - 40 * 10 = ? | {
"A": "14.5",
"B": "13.5",
"C": "12.5",
"D": "17.5",
"E": "11.5"
} | add(multiply(divide(60, 40), divide(240, 80)), 10) | divide(n2,n3)|divide(n0,n1)|multiply(#0,#1)|add(n4,#2) | explanation : given : 240 - 80 / 60 - 40 * 10 = ? substituting the coded symbols for mathematical operations , we get , 240 / 80 * 60 / 40 + 10 = ? 3 * 1.5 + 10 = 14.5 answer : a | general |
math_qa__HkeLXdRQfnusJash | A bus covered a distance of 250 km, partly at an average speed of 40 kmph and partly at 60 kmph. If the total time taken is 5.5 hours, then the distance covered at 40 kmph is Choose the correct choice from the following answers:
A) 130 km
B) 160 km
C) 100 km
D) 140 km
E) none of these | <gadget id="calculator">60 * 5.5</gadget>
<output>330</output>
<gadget id="calculator">330 - 250</gadget>
<output>80</output>
<gadget id="calculator">40 - 60</gadget>
<output>-20</output>
<gadget id="calculator">-(-20)</gadget>
<output>20</output>
<gadget id="calculator">80 / 20</gadget>
<output>4</output>
<gadget id="calculator">4 * 40</gadget>
<output>160</output>
<result>B</result> | B | 160 | A bus covered a distance of 250 km, partly at an average speed of 40 kmph and partly at 60 kmph. If the total time taken is 5.5 hours, then the distance covered at 40 kmph is | {
"A": "130 km",
"B": "160 km",
"C": "100 km",
"D": "140 km",
"E": "none of these"
} | multiply(divide(subtract(multiply(60, 5.5), 250), negate(subtract(40, 60))), 40) | multiply(n2,n3)|subtract(n1,n2)|negate(#1)|subtract(#0,n0)|divide(#3,#2)|multiply(n1,#4)| | "let the partial distance covered at 40 kmph be x let the another partial distance covered at 60 kmph be ( 250 - x ) thus , x / 40 - ( 250 - x ) / 60 = 5.5 or , x / 40 + ( 250 - x ) / 60 = 5.5 or , ( 3 x + 500 - 2 x ) / / 120 = 5.5 or 500 + x = 660 x = 160 answer : b" | physics |
math_qa__G7u0L6GyaMOF0LgZ | The least number which when increased by 3 each divisible by each one of 24, 32, 36 and 54 is : Choices
A) 427 B) 859 C) 869 D) 861 E) none of these | <gadget id="calculator">lcm(24, 32)</gadget>
<output>96</output>
<gadget id="calculator">lcm(96, 36)</gadget>
<output>288</output>
<gadget id="calculator">lcm(288, 54)</gadget>
<output>864</output>
<gadget id="calculator">864 - 3</gadget>
<output>861</output>
<result>D</result> | D | 861 | The least number which when increased by 3 each divisible by each one of 24, 32, 36 and 54 is : | {
"A": "427",
"B": "859",
"C": "869",
"D": "861",
"E": "none of these"
} | subtract(lcm(lcm(lcm(24, 32), 36), 54), 3) | lcm(n1,n2)|lcm(n3,#0)|lcm(n4,#1)|subtract(#2,n0)| | "solution required number = ( l . c . m . of 24 , 32 , 36 , 54 ) - 3 = 864 - 3 = 861 . answer d" | general |
math_qa__dzR1HHR3xinepp5i | The cross-section of a water channel is a trapezium in shape. If the channel is 14 meters wide at the top and 8 meters wide at the bottom and the area of cross-section is 770 square meters, what is the depth of the channel (in meters)? Choose one
A) 50 B) 60 C) 70 D) 80 E) 90 | <gadget id="calculator">14 + 8</gadget>
<output>22</output>
<gadget id="calculator">22 / 2</gadget>
<output>11</output>
<gadget id="calculator">770 / 11</gadget>
<output>70</output>
<result>C</result> | C | 70 | The cross-section of a water channel is a trapezium in shape. If the channel is 14 meters wide at the top and 8 meters wide at the bottom and the area of cross-section is 770 square meters, what is the depth of the channel (in meters)? | {
"A": "50",
"B": "60",
"C": "70",
"D": "80",
"E": "90"
} | divide(770, divide(add(14, 8), const_2)) | add(n0,n1)|divide(#0,const_2)|divide(n2,#1)| | "1 / 2 * d * ( 14 + 8 ) = 770 d = 70 the answer is c ." | physics |
math_qa__Xh3pQg7GUAzdocrw | The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25% then determine the value of x. Options:
A) 14 B) 15 C) 16 D) 17 E) 18 | <gadget id="calculator">20 * 4</gadget>
<output>80</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">80 / 5</gadget>
<output>16</output>
<result>C</result> | C | 16 | The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25% then determine the value of x. | {
"A": "14",
"B": "15",
"C": "16",
"D": "17",
"E": "18"
} | divide(multiply(20, const_4), add(const_4, const_1)) | add(const_1,const_4)|multiply(n0,const_4)|divide(#1,#0)| | "explanation : let the cost price 1 article = re 1 cost price of x articles = x s . p of x articles = 20 gain = 20 - x = > 25 = ( 20 − x / x ∗ 100 ) = > 2000 − 100 x = 25 x = > x = 16 option c" | gain |
math_qa__kQFeXxS5mTYweZ5i | The area of sector of a circle whose radius is 10 metro and whose angle at the center is 42° is? Options.
A) 36.7 B) 52.9 C) 52.8 D) 52.1 E) 52.2 | <gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 2</gadget>
<output>22</output>
<gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">100 * (22/7)</gadget>
<output>2_200/7 = around 314.285714</output>
<gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">42 / 360</gadget>
<output>7/60 = around 0.116667</output>
<gadget id="calculator">(2_200/7) * (7/60)</gadget>
<output>110/3 = around 36.666667</output>
<result>A</result> | A | 36.7 | The area of sector of a circle whose radius is 10 metro and whose angle at the center is 42° is? | {
"A": "36.7",
"B": "52.9",
"C": "52.8",
"D": "52.1",
"E": "52.2"
} | multiply(multiply(power(10, const_2), divide(add(multiply(const_2, const_10), const_2), add(const_4, const_3))), divide(42, divide(const_3600, const_10))) | add(const_3,const_4)|divide(const_3600,const_10)|multiply(const_10,const_2)|power(n0,const_2)|add(#2,const_2)|divide(n1,#1)|divide(#4,#0)|multiply(#6,#3)|multiply(#5,#7)| | "42 / 360 * 22 / 7 * 10 * 10 = 36.7 m 2 answer : a" | geometry |
math_qa__wMHbwNoBM0Yyev1G | 120 is what percent of 80? Select the correct option: A) 0.2 % B) 2 % C) 5 % D) 150 % E) 500 % | <gadget id="calculator">120 / 80</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 100</gadget>
<output>150</output>
<result>D</result> | D | 150 | 120 is what percent of 80? | {
"A": "0.2 %",
"B": "2 %",
"C": "5 %",
"D": "150 %",
"E": "500 %"
} | multiply(divide(120, 80), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "120 = x * 80 / 100 x = 150 % ans ; d" | gain |
math_qa__iQwKvcelUJaVXpJl | At a meeting, 25 attendants used a pencil and 15 attendants used a pen. If exactly 20 attendants used only one of the two types of writing tools, how many attendants wrote with both types of writing tools?
Choose the correct choice
A) 10 B) 6 C) 7 D) 4 E) 14 | <gadget id="calculator">25 + 15</gadget>
<output>40</output>
<gadget id="calculator">40 - 20</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>A</result> | A | 10 | At a meeting, 25 attendants used a pencil and 15 attendants used a pen. If exactly 20 attendants used only one of the two types of writing tools, how many attendants wrote with both types of writing tools? | {
"A": "10",
"B": "6",
"C": "7",
"D": "4",
"E": "14"
} | divide(subtract(add(25, 15), 20), const_2) | add(n0,n1)|subtract(#0,n2)|divide(#1,const_2) | say x attendants wrote with both writing tools . ( 25 - x ) + ( 15 - x ) = 20 - - > x = 10 . answer : a . | other |
math_qa__rOuRiP1bQfUpygTX | In the xy-plane the point (-2 -3) is the centre of a circle, the point (-2, 2) lies inside the circle and the point (5, -3) lies outside the circle. If the radius r of the circle r is an integer then r=
Choose the correct choice from the following answers: A) 6 B) 5 C) 4 D) 3 E) 2 | <gadget id="calculator">-2</gadget>
<output>-2</output>
<gadget id="calculator">5 - (-2)</gadget>
<output>7</output>
<gadget id="calculator">7 + 5</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>A</result> | A | 6 | In the xy-plane the point (-2 -3) is the centre of a circle, the point (-2, 2) lies inside the circle and the point (5, -3) lies outside the circle. If the radius r of the circle r is an integer then r= | {
"A": "6",
"B": "5",
"C": "4",
"D": "3",
"E": "2"
} | divide(add(subtract(5, negate(2)), 5), 2) | negate(n0)|subtract(n4,#0)|add(n4,#1)|divide(#2,n0)| | "can be solved without much calculations . you are given that ( - 2 , - 3 ) is the center of the circle . point ( 5 , - 3 ) lies inside the circle - - - > the radius is lesser than distance of ( - 2 , - 3 ) from ( 5 , - 3 ) - - - > lesser than 7 units but the radius will also be greater than the distance of ( - 2 , - 3 ) from ( - 2,2 ) - - - - > greater than 5 units . thus the radius is > 5 but < 7 and as it is an integer , the only possible value of radius = 6 units . a is the correct answer ." | general |
math_qa__jcjQOK8cf57kzQjV | Working together, Tim and Tom can type 15 pages in one hour. If they would be able to type 18 pages in one hour if Tom increases his typing speed by 60%, what is the ratio of Tom's normal typing speed to that of Tim? Choose the correct choice from the following options:
A) 1 / 2 B) 1 / 3 C) 1 / 4 D) 1 / 5 E) 1 / 6 | <gadget id="calculator">18 - 15</gadget>
<output>3</output>
<gadget id="calculator">100 * 1</gadget>
<output>100</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">3 / (3/5)</gadget>
<output>5</output>
<gadget id="calculator">15 - 5</gadget>
<output>10</output>
<gadget id="calculator">5 / 10</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | Working together, Tim and Tom can type 15 pages in one hour. If they would be able to type 18 pages in one hour if Tom increases his typing speed by 60%, what is the ratio of Tom's normal typing speed to that of Tim? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 4",
"D": "1 / 5",
"E": "1 / 6"
} | divide(divide(subtract(18, 15), divide(60, multiply(const_100, const_1))), subtract(15, divide(subtract(18, 15), divide(60, multiply(const_100, const_1))))) | multiply(const_1,const_100)|subtract(n1,n0)|divide(n2,#0)|divide(#1,#2)|subtract(n0,#3)|divide(#3,#4)| | "lets say tim types x pages an hour and tom types y pages an hour . we know that x + y = 15 tom increase speed by 60 % means he will type 1.6 y pages an hour . so we get x + 1.6 y = 18 we need to know the ratio of tom ' s speed to tim ' s speed . this is going to be proportional to the number of pages each can type in an hour , hence ( y / x ) . subtracting both : 0.6 y = 3 so y = 5 . . . so x = 10 ( y / x ) = 5 / 10 = 1 / 2 answer is ( a )" | physics |
math_qa__1mDFqjQGEv7lqNXy | 20 men can complete a piece of work in 30 days. In how many days can 25 men complete that piece of work?
Choose the most appropriate option:
A) 23
B) 27
C) 24
D) 27
E) 11 | <gadget id="calculator">30 * 20</gadget>
<output>600</output>
<gadget id="calculator">600 / 25</gadget>
<output>24</output>
<result>C</result> | C | 24 | 20 men can complete a piece of work in 30 days. In how many days can 25 men complete that piece of work? | {
"A": "23",
"B": "27",
"C": "24",
"D": "27",
"E": "11"
} | divide(multiply(30, 20), 25) | multiply(n0,n1)|divide(#0,n2)| | "20 * 30 = 25 * x = > x = 24 days answer : c" | physics |
math_qa__L68KiYK3FgVKDjFG | A lamp is put on one corner of a square plot of side 50m. It's light reaches 21m. Find the area of that plot that is lit by that lamp? Options
A) 248
B) 312.5
C) 346.5
D) 392.5
E) 424 | <gadget id="calculator">pi * (21 ** 2)</gadget>
<output>441*pi = around 1_385.44236</output>
<gadget id="calculator">(441*pi) / 4</gadget>
<output>441*pi/4 = around 346.36059</output>
<result>C</result> | C | 346.5 | A lamp is put on one corner of a square plot of side 50m. It's light reaches 21m. Find the area of that plot that is lit by that lamp? | {
"A": "248",
"B": "312.5",
"C": "346.5",
"D": "392.5",
"E": "424"
} | divide(circle_area(21), const_4) | circle_area(n1)|divide(#0,const_4) | area covered by lamp = pi * r ^ 2 / 4 ( here we divide by 4 because lamp is put in the corner of the plot and only 1 / 4 part lit is of the plot ) where r = 21 m = length of part lit so area = ( 22 / 7 ) * 21 * 21 / 4 = 346.5 sq m answer : c | geometry |
math_qa__HU2FAcjUifEUWOR9 | Find the mean proportional between 36 & 49? Choose the correct option.
A) 42
B) 61
C) 63
D) 65
E) 67 | <gadget id="calculator">36 + 49</gadget>
<output>85</output>
<gadget id="calculator">85 / 2</gadget>
<output>85/2 = around 42.5</output>
<result>A</result> | A | 42 | Find the mean proportional between 36 & 49? | {
"A": "42",
"B": "61",
"C": "63",
"D": "65",
"E": "67"
} | divide(add(36, 49), const_2) | add(n0,n1)|divide(#0,const_2)| | "formula = √ a × b a = 36 and b = 49 √ 36 × 49 = 6 × 7 = 42 a" | general |
math_qa__7JqeANlyKEAtCwwt | A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 1:3 and B:C = 1:5. If the total runs scored by all of them are 95, the runs scored by C are? Choose the correct choice
A) 20.23 B) 20.13 C) 75 D) 20.93 E) 10.93 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">5 / 1</gadget>
<output>5</output>
<gadget id="calculator">(1/3) + 5</gadget>
<output>16/3 = around 5.333333</output>
<gadget id="calculator">(16/3) + 1</gadget>
<output>19/3 = around 6.333333</output>
<gadget id="calculator">95 / (19/3)</gadget>
<output>15</output>
<gadget id="calculator">15 * 5</gadget>
<output>75</output>
<result>C</result> | C | 75 | A, B and C play a cricket match. The ratio of the runs scored by them in the match is A:B = 1:3 and B:C = 1:5. If the total runs scored by all of them are 95, the runs scored by C are? | {
"A": "20.23",
"B": "20.13",
"C": "75",
"D": "20.93",
"E": "10.93"
} | multiply(divide(95, add(add(divide(1, 3), divide(5, 1)), const_1)), 5) | divide(n0,n1)|divide(n3,n0)|add(#0,#1)|add(#2,const_1)|divide(n4,#3)|multiply(n3,#4) | a : b = 1 : 3 b : c = 1 : 5 a : b : c = 1 : 3 : 15 15 / 19 * 95 = 75 answer : c | general |
math_qa__5pKNLFQLgIU9CEBa | Dacid obtained 61, 65, 82, 67 and 85 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? Choose the correct choice:
A) 29 B) 72 C) 39 D) 37 E) 75 | <gadget id="calculator">61 + 65</gadget>
<output>126</output>
<gadget id="calculator">126 + 82</gadget>
<output>208</output>
<gadget id="calculator">208 + 67</gadget>
<output>275</output>
<gadget id="calculator">275 + 85</gadget>
<output>360</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">360 / 5</gadget>
<output>72</output>
<result>B</result> | B | 72 | Dacid obtained 61, 65, 82, 67 and 85 marks (out of 100) in English, Mathematics, Physics, Chemistry and Biology. What are his average marks? | {
"A": "29",
"B": "72",
"C": "39",
"D": "37",
"E": "75"
} | divide(add(add(add(add(61, 65), 82), 67), 85), divide(const_10, const_2)) | add(n0,n1)|divide(const_10,const_2)|add(n2,#0)|add(n3,#2)|add(n4,#3)|divide(#4,#1)| | "average = ( 61 + 65 + 82 + 67 + 85 ) / 5 = 72 answer : b" | general |
math_qa__NlPtcmMul67LeA8s | 7500 + (1250 / 50) Choose the correct answer
A) 7500
B) 7525
C) 7550
D) 8000
E) none of these | <gadget id="calculator">1_250 / 50</gadget>
<output>25</output>
<gadget id="calculator">7_500 + 25</gadget>
<output>7_525</output>
<result>B</result> | B | 7,525 | 7500 + (1250 / 50) | {
"A": "7500",
"B": "7525",
"C": "7550",
"D": "8000",
"E": "none of these"
} | add(7500, divide(1250, 50)) | divide(n1,n2)|add(n0,#0) | explanation : as per bodmas rule first we will solve the terms in the bracket then other . = 7500 + ( 25 ) = 7525 option b | general |
math_qa__GnXGThBpMsADM6Cx | The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 50/kg. how much did a kg of coffee cost in june ? Select the correct option.
A) 50 B) 60 C) 80 D) 100 E) 120 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(4/5) * (6/5)</gadget>
<output>24/25 = around 0.96</output>
<gadget id="calculator">50 / (24/25)</gadget>
<output>625/12 = around 52.083333</output>
<result>A</result> | A | 50 | The prices of tea and coffee per kg were the same in june. In july the price of coffee shot up by 20% and that of tea dropped by 20%. if in july , a mixture containing equal quantities of tea and coffee costs 50/kg. how much did a kg of coffee cost in june ? | {
"A": "50",
"B": "60",
"C": "80",
"D": "100",
"E": "120"
} | divide(50, multiply(subtract(const_1, divide(20, const_100)), add(divide(20, const_100), const_1))) | divide(n0,const_100)|divide(n1,const_100)|add(#0,const_1)|subtract(const_1,#1)|multiply(#2,#3)|divide(n2,#4)| | "let the price of tea and coffee be x per kg in june . price of tea in july = 1.2 x price of coffee in july = 0.8 x . in july the price of 1 / 2 kg ( 500 gm ) of tea and 1 / 2 kg ( 500 gm ) of coffee ( equal quantities ) = 50 1.2 x ( 1 / 2 ) + 0.8 x ( 1 / 2 ) = 50 = > x = 50 thus proved . . . option a ." | general |
math_qa__VR8KUIO6VEmhHzNP | Solve below question 2x + 1 = -11 Options
A) - 8 B) - 6 C) 9 D) 8 E) - 7 | <gadget id="calculator">11 + 1</gadget>
<output>12</output>
<gadget id="calculator">-12</gadget>
<output>-12</output>
<gadget id="calculator">(-12) / 2</gadget>
<output>-6</output>
<result>B</result> | B | -6 | Solve below question 2x + 1 = -11 | {
"A": "- 8",
"B": "- 6",
"C": "9",
"D": "8",
"E": "- 7"
} | divide(negate(add(11, 1)), 2) | add(n1,n2)|negate(#0)|divide(#1,n0)| | "2 x + 1 = - 11 x = - 6 b" | general |
math_qa__1WrTiKG7Whq1RRJt | If 7/w + 7/x = 7/y and wx = y, then the average (arithmetic mean) of w and x is Choose the correct choice from the following options.
A) 1 / 2 B) 1 C) 2 D) 4 E) 8 | <gadget id="calculator">7 + 7</gadget>
<output>14</output>
<gadget id="calculator">7 / 14</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | If 7/w + 7/x = 7/y and wx = y, then the average (arithmetic mean) of w and x is | {
"A": "1 / 2",
"B": "1",
"C": "2",
"D": "4",
"E": "8"
} | divide(7, add(7, 7)) | add(n0,n0)|divide(n0,#0) | given : 7 / w + 7 / x = 7 / ywx = y find : ( w + x ) / 2 = ? 7 ( 1 / w + 1 / x ) = 7 ( 1 / y ) - divide both sides by 7 ( 1 / w + 1 / x ) = 1 / y ( x + w ) / wx = 1 / wx - sub ' d in y = wx x + w - 1 = 0 x + w = 1 therefore ( w + x ) / 2 = 1 / 2 ans : a | general |
math_qa__rmPieJqKPI2oocoR | Micheal and Adam can do together a piece of work in 20 days. After they have worked together for 16 days Micheal stops and Adam completes the remaining work in 10 days. In how many days Micheal complete the work separately.
Choose the correct option: A) 80 days B) 100 / 3 days C) 120 days D) 110 days E) 90 days | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 16</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 - (4/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / (1/5)</gadget>
<output>5</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">1 / 50</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">(1/20) - (1/50)</gadget>
<output>3/100 = around 0.03</output>
<gadget id="calculator">1 / (3/100)</gadget>
<output>100/3 = around 33.333333</output>
<result>B</result> | B | 33.333333 | Micheal and Adam can do together a piece of work in 20 days. After they have worked together for 16 days Micheal stops and Adam completes the remaining work in 10 days. In how many days Micheal complete the work separately. | {
"A": "80 days",
"B": "100 / 3 days",
"C": "120 days",
"D": "110 days",
"E": "90 days"
} | inverse(subtract(inverse(20), inverse(multiply(inverse(subtract(const_1, multiply(inverse(20), 16))), 10)))) | inverse(n0)|multiply(n1,#0)|subtract(const_1,#1)|inverse(#2)|multiply(n2,#3)|inverse(#4)|subtract(#0,#5)|inverse(#6)| | "rate of both = 1 / 20 together they do = 1 / 20 * 16 = 4 / 5 left work = 1 - 4 / 5 = 1 / 5 adam completes 1 / 5 work in 10 day so he took 10 * 5 = 50 days to complete the left work alone . thus the rate of adam is 1 / 50 rate of micheal = 1 / 20 - 1 / 50 = 1 / ( 100 / 3 ) thus micheal takes 100 / 3 days to complete the whole work . ans . b ." | physics |
math_qa__p1Xfg34AyemBCKjJ | Of the 200 stamps in a collection, 90 are foreign and 50 are more than 10 years old. If 20 stamps are both foreign and more than 10 years old, how many stamps are neither foreign nor more than 10 years old? Select: A) 30 B) 80 C) 100 D) 130 E) 150 | <gadget id="calculator">90 + 50</gadget>
<output>140</output>
<gadget id="calculator">140 - 20</gadget>
<output>120</output>
<gadget id="calculator">200 - 120</gadget>
<output>80</output>
<result>B</result> | B | 80 | Of the 200 stamps in a collection, 90 are foreign and 50 are more than 10 years old. If 20 stamps are both foreign and more than 10 years old, how many stamps are neither foreign nor more than 10 years old? | {
"A": "30",
"B": "80",
"C": "100",
"D": "130",
"E": "150"
} | subtract(200, subtract(add(90, 50), 20)) | add(n1,n2)|subtract(#0,n4)|subtract(n0,#1)| | "20 stamps are both foreign and more than 10 years old . 70 stamps are foreign only . 30 stamps are 10 years old only . the number of remaining stamps is 200 - ( 20 + 70 + 30 ) = 80 the answer is b ." | other |
math_qa__G5zlgqdyGCjuTo31 | After doing 3/5 of the Biology homework on Monday night, Sanjay did 1/3 of the remaining homework on Tuesday night. What fraction of the original homework would Sanjay have to do on Wednesday night to complete the Biology assignment ? Choose the correct option.
A) 1 / 15
B) 2 / 15
C) 4 / 15
D) 2 / 5
E) none of these | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(2/5) * (1/3)</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(3/5) + (2/15)</gadget>
<output>11/15 = around 0.733333</output>
<gadget id="calculator">1 - (11/15)</gadget>
<output>4/15 = around 0.266667</output>
<result>C</result> | C | 0.266667 | After doing 3/5 of the Biology homework on Monday night, Sanjay did 1/3 of the remaining homework on Tuesday night. What fraction of the original homework would Sanjay have to do on Wednesday night to complete the Biology assignment ? | {
"A": "1 / 15",
"B": "2 / 15",
"C": "4 / 15",
"D": "2 / 5",
"E": "none of these"
} | subtract(const_1, add(divide(3, 5), multiply(subtract(const_1, divide(3, 5)), divide(1, 3)))) | divide(n0,n1)|divide(n2,n0)|subtract(const_1,#0)|multiply(#1,#2)|add(#0,#3)|subtract(const_1,#4) | sol . ( c ) remaining homework on monday night = 1 - ( 3 / 5 ) = 2 / 5 work done on tuesday night = 1 / 3 of 2 / 5 = 2 / 15 remaining homework to complete the biology assignment = 2 / 5 - 2 / 15 = ( 6 - 2 ) / 15 = 4 / 15 answer c | physics |
math_qa__Tj2MDTrg5QNUiCve | Difference of two numbers is 1860. If 7.5% of the number is 12.5% of the other number , find the number ? Pick one:
A) 2660 , 1000
B) 3660 , 2000
C) 3000 , 4160
D) 2790 , 4650
E) 4660 , 3000 | <gadget id="calculator">7.5 / 12.5</gadget>
<output>0.6</output>
<gadget id="calculator">1 - 0.6</gadget>
<output>0.4</output>
<gadget id="calculator">1_860 / 0.4</gadget>
<output>4_650</output>
<gadget id="calculator">0.6 * 4_650</gadget>
<output>2_790</output>
<result>D</result> | D | 2,790 | Difference of two numbers is 1860. If 7.5% of the number is 12.5% of the other number , find the number ? | {
"A": "2660 , 1000",
"B": "3660 , 2000",
"C": "3000 , 4160",
"D": "2790 , 4650",
"E": "4660 , 3000"
} | multiply(divide(7.5, 12.5), divide(1860, subtract(const_1, divide(7.5, 12.5)))) | divide(n1,n2)|subtract(const_1,#0)|divide(n0,#1)|multiply(#0,#2)| | "let the numbers be x and y . then , 7.5 % of x = 12.5 % of y x = 125 * y / 75 = 5 * y / 3 . now , x - y = 1860 5 * y / 3 – y = 1860 2 * y / 3 = 1860 y = [ ( 1860 * 3 ) / 2 ] = 2790 . one number = 2790 , second number = 5 * y / 3 = 4650 . answer d ." | gain |
math_qa__3RpwsKdJ9vXDD4XW | a box contains 9 slips that are each labeled with one number : 1 , 2 , 3 , 5 , 8 , 13 , 21 , and 55 . two of the slips are drawn at random from the box without replacement . what is the probability that the sum of the numbers on the two slips is equal to one of the numbers left in the box ?
Answers: A) 7 / 72 B) 1 / 6 C) 7 / 36 D) 5 / 28 E) 21 / 36 | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">25 + 3</gadget>
<output>28</output>
<gadget id="calculator">5 / 28</gadget>
<output>5/28 = around 0.178571</output>
<result>D</result> | D | 0.178571 | a box contains 9 slips that are each labeled with one number : 1 , 2 , 3 , 5 , 8 , 13 , 21 , and 55 . two of the slips are drawn at random from the box without replacement . what is the probability that the sum of the numbers on the two slips is equal to one of the numbers left in the box ? | {
"A": "7 / 72",
"B": "1 / 6",
"C": "7 / 36",
"D": "5 / 28",
"E": "21 / 36"
} | divide(5, add(add(multiply(3, 5), const_10), const_3)) | multiply(n3,n4)|add(#0,const_10)|add(#1,const_3)|divide(n4,#2) | probability = no : of desired outcomes / total no : of outcomes . you are picking two slips out of 8 slips . so total no : of outcomes = 8 c 2 = 28 desired outcome : sum of the numbers on the two slips is equal to one of the numbers left in the box . how many such outcomes are there ? if you look at the numbers closely , you will see that the following pair of numbers will give you the desired outcome . ( 12 ) ( 23 ) ( 35 ) ( 58 ) ( 813 ) . there are 5 such pairs . if the two numbers which i pick is from any of these 5 pairs , then i get my desired outcome . so no : of desired outcomes = 5 probability = 5 / 28 answer : d | general |
math_qa__zOP7B9ZhtSYGQcGJ | A shopkeeper sold an article offering a discount of 4% and earned a profit of 26%. What would have been the percentage of profit earned if no discount was offered? Choose the correct choice from the following answers:
A) 24 B) 28 C) 31 D) 32 E) 34 | <gadget id="calculator">100 + 26</gadget>
<output>126</output>
<gadget id="calculator">126 * 100</gadget>
<output>12_600</output>
<gadget id="calculator">100 - 4</gadget>
<output>96</output>
<gadget id="calculator">12_600 / 96</gadget>
<output>525/4 = around 131.25</output>
<gadget id="calculator">(525/4) - 100</gadget>
<output>125/4 = around 31.25</output>
<result>C</result> | C | 31 | A shopkeeper sold an article offering a discount of 4% and earned a profit of 26%. What would have been the percentage of profit earned if no discount was offered? | {
"A": "24",
"B": "28",
"C": "31",
"D": "32",
"E": "34"
} | subtract(divide(multiply(add(const_100, 26), const_100), subtract(const_100, 4)), const_100) | add(n1,const_100)|subtract(const_100,n0)|multiply(#0,const_100)|divide(#2,#1)|subtract(#3,const_100)| | "let c . p . be rs . 100 . then , s . p . = rs . 126 let marked price be rs . x . then , 96 / 100 x = 126 x = 12600 / 96 = rs . 131.25 now , s . p . = rs . 131.25 , c . p . = rs . 100 profit % = 31 % . answer : c" | gain |
math_qa__Kz6Qb5hAkRzQxeya | the reciprocal of the hcf and lcm of two are 1/17 and 1/312 .if one of the number is 24 then other no. is Choose the correct choice from the following options.
A) 126 B) 136 C) 146 D) 221 E) 266 | <gadget id="calculator">17 * 312</gadget>
<output>5_304</output>
<gadget id="calculator">5_304 / 24</gadget>
<output>221</output>
<result>D</result> | D | 221 | the reciprocal of the hcf and lcm of two are 1/17 and 1/312 .if one of the number is 24 then other no. is | {
"A": "126",
"B": "136",
"C": "146",
"D": "221",
"E": "266"
} | divide(multiply(17, 312), 24) | multiply(n1,n3)|divide(#0,n4)| | "reciprocal of the hcf and lcm of two are 1 / 17 and 1 / 312 so , hcf = 17 , lcm = 312 lcm * hcf = product of two numbers = a * b = > b = lcm * hcf / a so , other = 17 * 312 / 24 = 221 answer : d" | physics |
math_qa__occFlyQ1nd8okbxu | A man bought 10 crates of mangoes for $160 total. If he lost 2 of the crates, at what price would he have to sell each of the remaining crates in order to earn a total profit of 25 percent of the total cost? Choose the correct answer:
A) $ 35 B) $ 25 C) $ 45 D) $ 50 E) $ 55 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">160 * (1/4)</gadget>
<output>40</output>
<gadget id="calculator">160 + 40</gadget>
<output>200</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">200 / 8</gadget>
<output>25</output>
<result>B</result> | B | 25 | A man bought 10 crates of mangoes for $160 total. If he lost 2 of the crates, at what price would he have to sell each of the remaining crates in order to earn a total profit of 25 percent of the total cost? | {
"A": "$ 35",
"B": "$ 25",
"C": "$ 45",
"D": "$ 50",
"E": "$ 55"
} | divide(add(160, multiply(160, divide(25, const_100))), subtract(10, 2)) | divide(n3,const_100)|subtract(n0,n2)|multiply(n1,#0)|add(n1,#2)|divide(#3,#1)| | "as given , after lost , the remaining 8 crates total cost = $ 160 so , 1 crate cost = 160 / 8 = 20 to get 25 % profit , 1 crate cost should be = 20 + 20 * 25 / 100 = $ 25 answer : b" | gain |
math_qa__thgsnWkokMa64twJ | The speed at which a man can row a boat in still water is 6.5 kmph. If he rows downstream, where the speed of current is 2.5 kmph, what time will he take to cover 90 metres? Pick: A) 90 seconds B) 36 seconds C) 26 seconds D) 18 seconds E) 6.5 seconds | <gadget id="calculator">6.5 + 2.5</gadget>
<output>9</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">9 * (5/18)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">90 / (5/2)</gadget>
<output>36</output>
<result>B</result> | B | 36 | The speed at which a man can row a boat in still water is 6.5 kmph. If he rows downstream, where the speed of current is 2.5 kmph, what time will he take to cover 90 metres? | {
"A": "90 seconds",
"B": "36 seconds",
"C": "26 seconds",
"D": "18 seconds",
"E": "6.5 seconds"
} | divide(90, multiply(add(6.5, 2.5), const_0_2778)) | add(n0,n1)|multiply(#0,const_0_2778)|divide(n2,#1)| | "speed of the boat downstream = 6.5 + 2.5 = 9 kmph = 9 * 5 / 18 = 2.5 m / s hence time taken to cover 90 m = 90 / 2.5 = 36 seconds . answer : b" | physics |
math_qa__qeoSCbFcIZPwwJfQ | If x = 1 + √2, then what is the value of x4 - 4x3 + 4x2 + 4? Answers
A) - 1 B) 0 C) 5 D) 2 E) 3 | <gadget id="calculator">2 ** (1/2)</gadget>
<output>sqrt(2) = around 1.414214</output>
<gadget id="calculator">1 + (sqrt(2))</gadget>
<output>1 + sqrt(2) = around 2.414214</output>
<gadget id="calculator">(1 + sqrt(2)) ** 2</gadget>
<output>(1 + sqrt(2))**2 = around 5.828427</output>
<gadget id="calculator">(1 + sqrt(2)) - 2</gadget>
<output>-1 + sqrt(2) = around 0.414214</output>
<gadget id="calculator">(-1 + sqrt(2)) ** 2</gadget>
<output>(-1 + sqrt(2))**2 = around 0.171573</output>
<gadget id="calculator">((1 + sqrt(2))**2) * ((-1 + sqrt(2))**2)</gadget>
<output>(-1 + sqrt(2))**2*(1 + sqrt(2))**2 = around 1</output>
<gadget id="calculator">((-1 + sqrt(2))**2*(1 + sqrt(2))**2) + 4</gadget>
<output>(-1 + sqrt(2))**2*(1 + sqrt(2))**2 + 4 = around 5</output>
<result>C</result> | C | 5 | If x = 1 + √2, then what is the value of x4 - 4x3 + 4x2 + 4? | {
"A": "- 1",
"B": "0",
"C": "5",
"D": "2",
"E": "3"
} | add(multiply(power(add(1, sqrt(2)), const_2), power(subtract(add(1, sqrt(2)), 2), const_2)), 4) | sqrt(n1)|add(n0,#0)|power(#1,const_2)|subtract(#1,n1)|power(#3,const_2)|multiply(#2,#4)|add(n2,#5) | answer x = 1 + √ 2 ∴ x 4 - 4 x 3 + 4 x 2 + 5 = x 2 ( x 2 - 4 x + 4 ) + 4 = x 2 ( x - 2 ) 2 + 4 = ( 1 + √ 2 ) 2 ( 1 + √ 2 - 2 ) 2 + 4 = ( √ 2 + 1 ) 2 ( √ 2 - 1 ) 2 + 4 = [ ( √ 2 ) 2 - ( 1 ) 2 ] 2 + 4 = ( 2 - 1 ) 2 = 1 + 4 = 5 correct option : c | general |
math_qa__zQLuh3H0iRbNtyys | If the average (arithmetic mean) of a and b is 45 and the average of b and c is 70, what is the value of c − a? Choose the correct choice: A) 25 B) 50 C) 90 D) 140 E) it can not be determined from the information given | <gadget id="calculator">70 * 2</gadget>
<output>140</output>
<gadget id="calculator">45 * 2</gadget>
<output>90</output>
<gadget id="calculator">140 - 90</gadget>
<output>50</output>
<result>B</result> | B | 50 | If the average (arithmetic mean) of a and b is 45 and the average of b and c is 70, what is the value of c − a? | {
"A": "25",
"B": "50",
"C": "90",
"D": "140",
"E": "it can not be determined from the information given"
} | subtract(multiply(70, const_2), multiply(45, const_2)) | multiply(n1,const_2)|multiply(n0,const_2)|subtract(#0,#1)| | "the arithmetic mean of a and b = ( a + b ) / 2 = 45 - - a + b = 90 - - 1 similarly for b + c = 140 - - 2 subtracting 1 from 2 we have c - a = 50 ; answer : b" | general |
math_qa__mMYvjsKjxLSyNtPp | If the wheel is 14 cm then the number of revolutions to cover a distance of 4136 cm is? Choose the correct choice from the following answers.
A) 22 B) 28 C) 17 D) 12 E) 47 | <gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">1 * 10</gadget>
<output>10</output>
<gadget id="calculator">300 + 10</gadget>
<output>310</output>
<gadget id="calculator">310 + 4</gadget>
<output>314</output>
<gadget id="calculator">314 / 100</gadget>
<output>157/50 = around 3.14</output>
<gadget id="calculator">2 * (157/50)</gadget>
<output>157/25 = around 6.28</output>
<gadget id="calculator">(157/25) * 14</gadget>
<output>2_198/25 = around 87.92</output>
<gadget id="calculator">4_136 / (2_198/25)</gadget>
<output>51_700/1_099 = around 47.042766</output>
<result>E</result> | E | 47 | If the wheel is 14 cm then the number of revolutions to cover a distance of 4136 cm is? | {
"A": "22",
"B": "28",
"C": "17",
"D": "12",
"E": "47"
} | divide(4136, multiply(multiply(const_2, divide(add(add(multiply(const_3, const_100), multiply(const_1, const_10)), const_4), const_100)), 14)) | multiply(const_100,const_3)|multiply(const_1,const_10)|add(#0,#1)|add(#2,const_4)|divide(#3,const_100)|multiply(#4,const_2)|multiply(n0,#5)|divide(n1,#6)| | "2 * 22 / 7 * 14 * x = 4136 = > x = 47 answer : e" | physics |
math_qa__G0ovQBIv5z9xIUlK | The parameter of a square is equal to the perimeter of a rectangle of length 36 cm and breadth 20 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)? Choose the correct choice
A) 23.56 B) 23.59 C) 44.0 D) 23.53 E) 23.57 | <gadget id="calculator">2 * (36 + 20)</gadget>
<output>112</output>
<gadget id="calculator">112 / 4</gadget>
<output>28</output>
<gadget id="calculator">28 / 2</gadget>
<output>14</output>
<gadget id="calculator">2 * pi * 14</gadget>
<output>28*pi = around 87.964594</output>
<gadget id="calculator">(28*pi) / 2</gadget>
<output>14*pi = around 43.982297</output>
<result>C</result> | C | 44 | The parameter of a square is equal to the perimeter of a rectangle of length 36 cm and breadth 20 cm. Find the circumference of a semicircle whose diameter is equal to the side of the square. (Round off your answer to two decimal places)? | {
"A": "23.56",
"B": "23.59",
"C": "44.0",
"D": "23.53",
"E": "23.57"
} | divide(circumface(divide(square_edge_by_perimeter(rectangle_perimeter(36, 20)), const_2)), const_2) | rectangle_perimeter(n0,n1)|square_edge_by_perimeter(#0)|divide(#1,const_2)|circumface(#2)|divide(#3,const_2)| | "let the side of the square be a cm . parameter of the rectangle = 2 ( 36 + 20 ) = 112 cm parameter of the square = 112 cm i . e . 4 a = 112 a = 28 diameter of the semicircle = 28 cm circimference of the semicircle = 1 / 2 ( â ˆ ) ( 28 ) = 1 / 2 ( 22 / 7 ) ( 28 ) = 44 cm to two decimal places answer : c" | geometry |
math_qa__V3vls8soChwYmJti | On selling 15 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is: Select
A) s . 45
B) s . 50
C) s . 55
D) s . 60
E) s . 72 | <gadget id="calculator">15 - 5</gadget>
<output>10</output>
<gadget id="calculator">720 / 10</gadget>
<output>72</output>
<result>E</result> | E | 72 | On selling 15 balls at Rs. 720, there is a loss equal to the cost price of 5 balls. The cost price of a ball is: | {
"A": "s . 45",
"B": "s . 50",
"C": "s . 55",
"D": "s . 60",
"E": "s . 72"
} | divide(720, subtract(15, 5)) | subtract(n0,n2)|divide(n1,#0)| | "( c . p . of 15 balls ) - ( s . p . of 15 balls ) = ( c . p . of 5 balls ) c . p . of 10 balls = s . p . of 15 balls = rs . 720 . c . p . of 1 ball = rs . 720 / 10 = rs . 72 . answer : option e" | gain |
math_qa__A4iA7iG4X6HXNiUG | Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 3 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is? Select the correct option: A) 179 : 2 B) 178 : 3 C) 179 : 1 D) 179 : 54 E) 179 : 45 | <gadget id="calculator">62.5 * 3</gadget>
<output>187.5</output>
<gadget id="calculator">187.5 / 100</gadget>
<output>1.875</output>
<gadget id="calculator">87.5 * 4</gadget>
<output>350</output>
<gadget id="calculator">350 / 100</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">1.875 + (7/2)</gadget>
<output>5.375</output>
<gadget id="calculator">3 - 1.875</gadget>
<output>1.125</output>
<gadget id="calculator">4 - (7/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1.125 + (1/2)</gadget>
<output>1.625</output>
<gadget id="calculator">5.375 / 1.625</gadget>
<output>3.307692</output>
<result>D</result> | D | 3.314815 | Two vessels P and Q contain 62.5% and 87.5% of alcohol respectively. If 3 litres from vessel P is mixed with 4 litres from vessel Q, the ratio of alcohol and water in the resulting mixture is? | {
"A": "179 : 2",
"B": "178 : 3",
"C": "179 : 1",
"D": "179 : 54",
"E": "179 : 45"
} | divide(add(divide(multiply(62.5, 3), const_100), divide(multiply(87.5, 4), const_100)), add(subtract(3, divide(multiply(62.5, 3), const_100)), subtract(4, divide(multiply(87.5, 4), const_100)))) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,const_100)|divide(#1,const_100)|add(#2,#3)|subtract(n2,#2)|subtract(n3,#3)|add(#5,#6)|divide(#4,#7)| | "quantity of alcohol in vessel p = 62.5 / 100 * 3 = 15 / 8 litres quantity of alcohol in vessel q = 87.5 / 100 * 4 = 7 / 2 litres quantity of alcohol in the mixture formed = 15 / 8 + 7 / 2 = 43 / 8 = 5.375 litres as 7 litres of mixture is formed , ratio of alcohol and water in the mixture formed = 5.375 : 1.625 = 179 : 54 . answer : d" | other |
math_qa__eS3ITAvta15i6eus | In what time will a train 600 meters long cross an electric pole, if its speed is 144 km/hr Pick one.
A) 5 seconds B) 4.5 seconds C) 3 seconds D) 15 seconds E) none of these | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">144 * (5/18)</gadget>
<output>40</output>
<gadget id="calculator">600 / 40</gadget>
<output>15</output>
<result>D</result> | D | 15 | In what time will a train 600 meters long cross an electric pole, if its speed is 144 km/hr | {
"A": "5 seconds",
"B": "4.5 seconds",
"C": "3 seconds",
"D": "15 seconds",
"E": "none of these"
} | divide(600, multiply(144, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "explanation : first convert speed into m / sec speed = 144 * ( 5 / 18 ) = 40 m / sec time = distance / speed = 600 / 40 = 15 seconds answer : d" | physics |
math_qa__fy5iFHAdhtQMpnWW | A certain class of students is being divided into teams. The class can either be divided into 10 teams with an equal number of players on each team or 24 teams with an equal number of players on each team. What is the lowest possible number of students in the class? Pick: A) 6 B) 36 C) 120 D) 60 E) 72 | <gadget id="calculator">lcm(10, 24)</gadget>
<output>120</output>
<result>C</result> | C | 120 | A certain class of students is being divided into teams. The class can either be divided into 10 teams with an equal number of players on each team or 24 teams with an equal number of players on each team. What is the lowest possible number of students in the class? | {
"A": "6",
"B": "36",
"C": "120",
"D": "60",
"E": "72"
} | lcm(10, 24) | lcm(n0,n1)| | "let total no of students in the class be n so , we are told that n is divisible by both 10 24 so , lets find the least common multiple of 10 24 , ie 120 so our answer is ( c ) 120" | general |
math_qa__SBIOX88nHdCqtNDa | How many positive integers between 5 and 5000(both are inclusive) are there such that they are multiples of 5? Choose the most appropriate option
A) 1500 B) 1000 C) 999 D) 1001 E) 1005 | <gadget id="calculator">5_000 - 5</gadget>
<output>4_995</output>
<gadget id="calculator">4_995 / 5</gadget>
<output>999</output>
<result>B</result> | B | 1,000 | How many positive integers between 5 and 5000(both are inclusive) are there such that they are multiples of 5? | {
"A": "1500",
"B": "1000",
"C": "999",
"D": "1001",
"E": "1005"
} | divide(subtract(5000, 5), 5) | subtract(n1,n0)|divide(#0,n2)| | "multiples of 5 = 5 , 10,15 - - - - - , 5000 number of multiples of 5 = > 5000 - 5 / 5 + 1 = 1000 answer is b" | other |
math_qa__TfkmgpUEJICizcgD | The sale price sarees listed for Rs.528 after successive discount is 20% and 10% is? Choose the correct option:
A) 288
B) 277
C) 380
D) 290
E) 262 | <gadget id="calculator">528 * 20</gadget>
<output>10_560</output>
<gadget id="calculator">10_560 / 100</gadget>
<output>528/5 = around 105.6</output>
<gadget id="calculator">528 - (528/5)</gadget>
<output>2_112/5 = around 422.4</output>
<gadget id="calculator">(2_112/5) * 10</gadget>
<output>4_224</output>
<gadget id="calculator">4_224 / 100</gadget>
<output>1_056/25 = around 42.24</output>
<gadget id="calculator">(2_112/5) - (1_056/25)</gadget>
<output>9_504/25 = around 380.16</output>
<result>C</result> | C | 380 | The sale price sarees listed for Rs.528 after successive discount is 20% and 10% is? | {
"A": "288",
"B": "277",
"C": "380",
"D": "290",
"E": "262"
} | subtract(subtract(528, divide(multiply(528, 20), const_100)), divide(multiply(subtract(528, divide(multiply(528, 20), const_100)), 10), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "528 * ( 80 / 100 ) * ( 90 / 100 ) = 380 answer : c" | gain |
math_qa__zBSeD8GJgILHB3u5 | The ratio of the number of red cars in a certain parking lot to the number of black cars is 3 to 8. If there are 52 black cars in the lot, how many red cars are there in the lot?
Choose the correct choice from the following answers:
A) 11 B) 20 C) 24 D) 27 E) 32 | <gadget id="calculator">3 / 8</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(3/8) * 52</gadget>
<output>39/2 = around 19.5</output>
<gadget id="calculator">floor(39/2)</gadget>
<output>19</output>
<result>B</result> | B | 20 | The ratio of the number of red cars in a certain parking lot to the number of black cars is 3 to 8. If there are 52 black cars in the lot, how many red cars are there in the lot? | {
"A": "11",
"B": "20",
"C": "24",
"D": "27",
"E": "32"
} | floor(multiply(divide(3, 8), 52)) | divide(n0,n1)|multiply(n2,#0)|floor(#1)| | "b is correct r / b = 3 / 8 and b = 52 r = 52 * 3 / 8 = 20" | other |
math_qa__fvzlfZB9eq6EIrzQ | In a certain pet shop, the ratio of dogs to cats to bunnies in stock is 3 : 5 : 9. If the shop carries 204 dogs and bunnies total in stock, how many dogs are there? Choose the correct answer: A) 51 B) 66 C) 98 D) 112 E) 154 | <gadget id="calculator">3 + 9</gadget>
<output>12</output>
<gadget id="calculator">204 / 12</gadget>
<output>17</output>
<gadget id="calculator">17 * 3</gadget>
<output>51</output>
<result>A</result> | A | 51 | In a certain pet shop, the ratio of dogs to cats to bunnies in stock is 3 : 5 : 9. If the shop carries 204 dogs and bunnies total in stock, how many dogs are there? | {
"A": "51",
"B": "66",
"C": "98",
"D": "112",
"E": "154"
} | multiply(divide(204, add(3, 9)), 3) | add(n0,n2)|divide(n3,#0)|multiply(n0,#1) | let us assume the number of dogs , cats and bunnies to be 3 x , 5 x and 9 x total dogs and bunnies = 12 x . and we are given that 12 x = 204 . hence x = 17 . dogs = 3 x = 3 * 17 = 51 ( option a ) | other |
math_qa__M7Ir2z4j9RTrJJDs | there are 5 guys who have equal number of bullets . all of them shoot 4 bullets . the remaining bullets are equal to the total number of bullets remaining is equal to the bullets each had after division . what was the original number of bullets each one had ? Select.
A) 18 B) 19 C) 20 D) 21 E) 25 | <gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<result>E</result> | E | 25 | there are 5 guys who have equal number of bullets . all of them shoot 4 bullets . the remaining bullets are equal to the total number of bullets remaining is equal to the bullets each had after division . what was the original number of bullets each one had ? | {
"A": "18",
"B": "19",
"C": "20",
"D": "21",
"E": "25"
} | multiply(divide(multiply(4, 5), subtract(5, const_1)), 5) | multiply(n0,n1)|subtract(n0,const_1)|divide(#0,#1)|multiply(n0,#2) | let initially each was having x bullets they shot 4 bullets so 5 x - 20 = x x = 5 so each was having 5 bullets . total was 25 . answer : e | general |
math_qa__xAVRD1ZPPfLUOxnP | The cost price of an article is 55% of the marked price. Calculate the gain percent after allowing a discount of 15%. Choose the correct choice from the following choices.
A) 40.5 % B) 48.7 % C) 54.5 % D) 55.6 % % E) none | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 55</gadget>
<output>17/11 = around 1.545455</output>
<gadget id="calculator">(17/11) - 1</gadget>
<output>6/11 = around 0.545455</output>
<gadget id="calculator">(6/11) * 100</gadget>
<output>600/11 = around 54.545455</output>
<result>C</result> | C | 54.5 | The cost price of an article is 55% of the marked price. Calculate the gain percent after allowing a discount of 15%. | {
"A": "40.5 %",
"B": "48.7 %",
"C": "54.5 %",
"D": "55.6 % %",
"E": "none"
} | multiply(subtract(divide(subtract(const_100, 15), 55), const_1), const_100) | subtract(const_100,n1)|divide(#0,n0)|subtract(#1,const_1)|multiply(#2,const_100) | sol . let marked price = rs . 100 . then , c . p . = rs . 55 . s . p = rs . 85 . â ˆ ´ gain % = [ 30 / 55 * 100 ] % = 54.5 % . answer c | gain |
math_qa__YHgVnEpIArLVbZLO | A full stationary oil tank that is a right circular cylinder has a radius of 100 feet and a height of 25 feet. Oil is pumped from the stationary tank to an oil truck that has a tank that is a right circular cylinder until the truck's tank is completely filled. If the truck's tank has a radius of 4 feet and a height of 10 feet, how far (in feet) did the oil level drop in the stationary tank? Choose the correct choice from the following answers.
A) 1.6 B) 1 C) 0.4 D) 0.16 E) 0.016 | <gadget id="calculator">pi * (4 ** 2) * 10</gadget>
<output>160*pi = around 502.654825</output>
<gadget id="calculator">pi * (100 ** 2)</gadget>
<output>10000*pi = around 31_415.926536</output>
<gadget id="calculator">(160*pi) / (10000*pi)</gadget>
<output>2/125 = around 0.016</output>
<result>E</result> | E | 0.016 | A full stationary oil tank that is a right circular cylinder has a radius of 100 feet and a height of 25 feet. Oil is pumped from the stationary tank to an oil truck that has a tank that is a right circular cylinder until the truck's tank is completely filled. If the truck's tank has a radius of 4 feet and a height of 10 feet, how far (in feet) did the oil level drop in the stationary tank? | {
"A": "1.6",
"B": "1",
"C": "0.4",
"D": "0.16",
"E": "0.016"
} | divide(volume_cylinder(4, 10), circle_area(100)) | circle_area(n0)|volume_cylinder(n2,n3)|divide(#1,#0)| | "the volume of oil pumped to the tank = the volume of oil taken away from stationary cylinder . pi * 16 * 10 = pi * h * 100 * 100 ( h is distance that the oil level dropped ) h = 160 / 10,000 = 16 / 1000 = 0.016 ft the answer is e ." | geometry |
math_qa__PXmEkhKUw3PxfZKy | Peter and Tom shared the driving on a certain trip. If Peter and Tom both drove for the same amount of time, but Peter only drove 2/5 of the total distance, what was the ratio of Tom's average speed to Peter's average speed? Choose the correct choice from the following choices
A) 1 : 5 B) 2 : 5 C) 1 : 2 D) 3 : 2 E) 2 : 3 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) / (2/5)</gadget>
<output>3/2 = around 1.5</output>
<result>D</result> | D | 1.5 | Peter and Tom shared the driving on a certain trip. If Peter and Tom both drove for the same amount of time, but Peter only drove 2/5 of the total distance, what was the ratio of Tom's average speed to Peter's average speed? | {
"A": "1 : 5",
"B": "2 : 5",
"C": "1 : 2",
"D": "3 : 2",
"E": "2 : 3"
} | divide(subtract(const_1, divide(2, 5)), divide(2, 5)) | divide(n0,n1)|subtract(const_1,#0)|divide(#1,#0) | the answer is suppose to be d . 3 : 2 . it ' s from the gmatprep option d is answer | general |
math_qa__OZbYdasNdHK3xuBv | A grocery shop has a sale of Rs. 6735, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500? Pick one:
A) 4857 B) 4184 C) 4012 D) 4691 E) 5291 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6_500 * 6</gadget>
<output>39_000</output>
<gadget id="calculator">6_735 + 6_927</gadget>
<output>13_662</output>
<gadget id="calculator">6_855 + 13_662</gadget>
<output>20_517</output>
<gadget id="calculator">20_517 + 7_230</gadget>
<output>27_747</output>
<gadget id="calculator">27_747 + 6_562</gadget>
<output>34_309</output>
<gadget id="calculator">39_000 - 34_309</gadget>
<output>4_691</output>
<result>D</result> | D | 4,691 | A grocery shop has a sale of Rs. 6735, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 6500? | {
"A": "4857",
"B": "4184",
"C": "4012",
"D": "4691",
"E": "5291"
} | subtract(multiply(6500, add(5, const_1)), add(add(add(6855, add(6735, 6927)), 7230), 6562)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "let the sale in the sixth month = x then ( 6735 + 6927 + 6855 + 7230 + 6562 + x ) / 6 = 6500 = > 6735 + 6927 + 6855 + 7230 + 6562 + x = 6 × 6500 = > 34309 + x = 39000 = > x = 39000 − 34309 = 4691 answer : d" | general |
math_qa__OFPlEUYM4Daw4Fhw | A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 12km?
Choose the correct choice from the following answers
A) 3 B) 5 C) 8 D) 9 E) 6 | <gadget id="calculator">4 - 2</gadget>
<output>2</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>E</result> | E | 6 | A person can swim in still water at 4 km/h. If the speed of water 2 km/h, how many hours will the man take to swim back against the current for 12km? | {
"A": "3",
"B": "5",
"C": "8",
"D": "9",
"E": "6"
} | divide(12, subtract(4, 2)) | subtract(n0,n1)|divide(n2,#0)| | "m = 4 s = 2 us = 4 - 2 = 2 d = 12 t = 12 / 2 = 6 answer : e" | physics |
math_qa__ZnA2G2xRFszcmcR3 | 1/4 of all the juniors and 2/3 of all the seniors are going on a trip. If there are 2/3 as many juniors as seniors, what fraction of the students are not going on the trip? Choose the correct choice from the following options: A) 4 / 9 B) 1 / 2 C) 2 / 3 D) 1 / 3 E) 5 / 6 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">(2/3) * 12</gadget>
<output>8</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">8 * (1/4)</gadget>
<output>2</output>
<gadget id="calculator">8 + 2</gadget>
<output>10</output>
<gadget id="calculator">12 + 8</gadget>
<output>20</output>
<gadget id="calculator">10 / 20</gadget>
<output>1/2 = around 0.5</output>
<result>B</result> | B | 0.5 | 1/4 of all the juniors and 2/3 of all the seniors are going on a trip. If there are 2/3 as many juniors as seniors, what fraction of the students are not going on the trip? | {
"A": "4 / 9",
"B": "1 / 2",
"C": "2 / 3",
"D": "1 / 3",
"E": "5 / 6"
} | divide(add(multiply(divide(2, 3), multiply(4, 3)), multiply(multiply(divide(2, 3), multiply(4, 3)), divide(1, 4))), add(multiply(4, 3), multiply(divide(2, 3), multiply(4, 3)))) | divide(n2,n3)|divide(n0,n1)|multiply(n1,n3)|multiply(#0,#2)|add(#2,#3)|multiply(#1,#3)|add(#3,#5)|divide(#6,#4) | j be the number of juniors and s be the number of seniors . there are 2 / 3 as many juniors as seniors 23 ∗ s = j j / s = 23 going on trip = j 4 + 23 ∗ s fraction = ( j 4 + 23 s ) / ( j + s ) = ( 2 / 3 * 1 / 4 + 2 / 3 ) / ( 2 / 3 + 1 ) = 1 / 2 fraction not on trip = 1 / 2 answer : b | general |
math_qa__YuvzzCjJzR03lvdI | Sonika deposited Rs.4500 which amounted to Rs.8400 after 2 years at simple interest. Had the interest been 4% more. She would get how much? Choose the correct choice from the following answers:
A) 9680
B) 8790
C) 8760
D) 9020
E) 5000 | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">8_400 - 4_500</gadget>
<output>3_900</output>
<gadget id="calculator">3_900 / 2</gadget>
<output>1_950</output>
<gadget id="calculator">1_950 / 4_500</gadget>
<output>13/30 = around 0.433333</output>
<gadget id="calculator">(1/25) + (13/30)</gadget>
<output>71/150 = around 0.473333</output>
<gadget id="calculator">(71/150) * 4_500</gadget>
<output>2_130</output>
<gadget id="calculator">2_130 * 2</gadget>
<output>4_260</output>
<gadget id="calculator">4_260 + 4_500</gadget>
<output>8_760</output>
<result>C</result> | C | 8,760 | Sonika deposited Rs.4500 which amounted to Rs.8400 after 2 years at simple interest. Had the interest been 4% more. She would get how much? | {
"A": "9680",
"B": "8790",
"C": "8760",
"D": "9020",
"E": "5000"
} | add(multiply(multiply(add(divide(4, const_100), divide(divide(subtract(8400, 4500), 2), 4500)), 4500), 2), 4500) | divide(n3,const_100)|subtract(n1,n0)|divide(#1,n2)|divide(#2,n0)|add(#0,#3)|multiply(n0,#4)|multiply(n2,#5)|add(n0,#6)| | "( 4500 * 2 * 4 ) / 100 = 360 8400 - - - - - - - - 8760 answer : c" | gain |
math_qa__eBG7LXXCH8bIrxlu | A grocer has a sale of Rs. 4000, Rs. 6524, Rs. 5689, Rs. 7230 and Rs. 6000 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 7000? Choose the correct option:
A) s . 12557 B) s . 14993 C) s . 15560 D) s . 12589 E) s . 12500 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 7_000</gadget>
<output>42_000</output>
<gadget id="calculator">4_000 + 6_524</gadget>
<output>10_524</output>
<gadget id="calculator">10_524 + 5_689</gadget>
<output>16_213</output>
<gadget id="calculator">16_213 + 7_230</gadget>
<output>23_443</output>
<gadget id="calculator">23_443 + 6_000</gadget>
<output>29_443</output>
<gadget id="calculator">42_000 - 29_443</gadget>
<output>12_557</output>
<result>A</result> | A | 12,557 | A grocer has a sale of Rs. 4000, Rs. 6524, Rs. 5689, Rs. 7230 and Rs. 6000 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 7000? | {
"A": "s . 12557",
"B": "s . 14993",
"C": "s . 15560",
"D": "s . 12589",
"E": "s . 12500"
} | subtract(multiply(add(5, const_1), 7000), add(add(add(add(4000, 6524), 5689), 7230), 6000)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "total sale for 5 months = rs . ( 4000 + 6524 + 5689 + 7230 + 6000 ) = rs . 29443 required sale = rs . [ ( 7000 x 6 ) - 29443 ] = rs . ( 42000 - 29443 ) = rs . 12557 . option a" | general |
math_qa__Lezmm3r5EU5lwnWZ | At a contest with 2000 participants, 1/2 of the people are aged 16 to 18. Next year, the number of people aged 16 to 18 will increase by 1/4. After this change, what percentage of the total 2000 people will the 16- to 18- year-olds represent? Choose the correct choice:
A) 62.50 % B) 60 % C) 70 % D) 65 % E) 66 / 3 % | <gadget id="calculator">2_000 / 2</gadget>
<output>1_000</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">1_000 * (5/4)</gadget>
<output>1_250</output>
<gadget id="calculator">1_250 / 2_000</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">(5/8) * 100</gadget>
<output>125/2 = around 62.5</output>
<result>A</result> | A | 62.5 | At a contest with 2000 participants, 1/2 of the people are aged 16 to 18. Next year, the number of people aged 16 to 18 will increase by 1/4. After this change, what percentage of the total 2000 people will the 16- to 18- year-olds represent? | {
"A": "62.50 %",
"B": "60 %",
"C": "70 %",
"D": "65 %",
"E": "66 / 3 %"
} | multiply(divide(multiply(divide(2000, const_2), add(const_1, divide(1, 4))), 2000), const_100) | divide(n1,n8)|divide(n0,const_2)|add(#0,const_1)|multiply(#2,#1)|divide(#3,n0)|multiply(#4,const_100) | i just wanted to mention a couple of things here : * this is a pure ratio question ; the number 2000 is completely irrelevant , and you can ignore it if you like . when we increase something by 1 / 4 , we are multiplying it by 1 + 1 / 4 = 5 / 4 , so the answer here must be ( 1 / 2 ) * ( 5 / 4 ) = 5 / 8 = 62.50 % . answer : a | general |
math_qa__OROv8QQSBy6saBwC | The closest approximation of F(69.28 × 0.004)/0.03 is
Choose the correct choice from the following answers:
A) 0.092
B) 0.92
C) 9.2
D) 92
E) 920 | <gadget id="calculator">0.004 / 0.03</gadget>
<output>0.133333</output>
<gadget id="calculator">0.133333 * 69.28</gadget>
<output>9.23731</output>
<result>C</result> | C | 9.2 | The closest approximation of F(69.28 × 0.004)/0.03 is | {
"A": "0.092",
"B": "0.92",
"C": "9.2",
"D": "92",
"E": "920"
} | multiply(divide(0.004, 0.03), 69.28) | divide(n1,n2)|multiply(n0,#0) | f ( 69.28 × 0.004 ) / 0.03 1 . 0.004 = 4 × 10 ^ ( - 3 ) 2 . 0.03 = 3 × 10 ^ ( - 2 ) 3 . ( a × b ) / c = a × ( b / c ) 4 . 0.004 / 0.03 = 4 × 10 ^ ( - 3 ) / ( 3 × 10 ^ ( - 2 ) ) = 4 × 10 ^ ( - 3 - ( - 2 ) ) / 3 = 4 × 10 ^ ( - 1 ) / 3 = ( 4 / 3 ) × 10 ^ ( - 1 ) = 1.333 × 10 ^ ( - 1 ) therefore , ( 69.28 × 0.004 ) / 0.03 = 69.28 × ( 0.004 / 0.03 ) = 69.28 × 1.33 × 10 ^ ( - 1 ) = 69.28 × 1.33 / 10 = 6.928 * 1.33 now , 7 × 2 = 14 7 × 1 = 7 or better : 6.9 × 1 = 6.9 6.9 × 2 = 13.8 hence , 6.9 < 6.928 × 1.33 < 13.8 9.2 is the only answer that satisfies this condition . c | general |
math_qa__orKDpT1YtA7sbXun | There are 9 executives, including the CEO and CFO, that are asked to form a small team of 4 members. However, the CEO and CFO may not both be assigned to the team. Given this constraint, how many ways are there to form the team? Choose one: A) 97 B) 99 C) 101 D) 103 E) 105 | <gadget id="calculator">9 - 4</gadget>
<output>5</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 + 3</gadget>
<output>15</output>
<gadget id="calculator">120 - 15</gadget>
<output>105</output>
<result>E</result> | E | 105 | There are 9 executives, including the CEO and CFO, that are asked to form a small team of 4 members. However, the CEO and CFO may not both be assigned to the team. Given this constraint, how many ways are there to form the team? | {
"A": "97",
"B": "99",
"C": "101",
"D": "103",
"E": "105"
} | subtract(factorial(subtract(9, 4)), add(multiply(4, const_3), const_3)) | multiply(n1,const_3)|subtract(n0,n1)|add(#0,const_3)|factorial(#1)|subtract(#3,#2) | the total number of ways to form a team of 4 is 9 c 4 = 126 . we need to subtract the number of teams that have both the ceo and the cfo . the number of teams with both the ceo and cfo is 7 c 2 = 21 . the number of ways to form an acceptable team is 126 - 21 = 105 . the answer is e . | other |
math_qa__4pvQpCR7Up9066lD | If 12 men or 20 women can do a piece of work in 108 days, then in how many days can 9 men and 12 women together do the work? Choose the correct choice from the following choices.
A) 10 days B) 30 days C) 20 days D) 80 days E) 40 days | <gadget id="calculator">12 * 108</gadget>
<output>1_296</output>
<gadget id="calculator">9 / 1_296</gadget>
<output>1/144 = around 0.006944</output>
<gadget id="calculator">20 * 108</gadget>
<output>2_160</output>
<gadget id="calculator">12 / 2_160</gadget>
<output>1/180 = around 0.005556</output>
<gadget id="calculator">(1/144) + (1/180)</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">1 / (1/80)</gadget>
<output>80</output>
<result>D</result> | D | 80 | If 12 men or 20 women can do a piece of work in 108 days, then in how many days can 9 men and 12 women together do the work? | {
"A": "10 days",
"B": "30 days",
"C": "20 days",
"D": "80 days",
"E": "40 days"
} | inverse(add(divide(9, multiply(12, 108)), divide(12, multiply(20, 108)))) | multiply(n0,n2)|multiply(n1,n2)|divide(n3,#0)|divide(n4,#1)|add(#2,#3)|inverse(#4)| | "d 80 days given that 12 m = 20 w = > 3 m = 5 w 9 men + 12 women = 15 women + 12 women = 27 women 20 women can do the work in 108 days . so , 27 women can do it in ( 20 * 108 ) / 27 = 80 days ." | physics |
math_qa__9OE4yPTqbYcxCk7g | The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 7500, brokerage being 1/4%, is:
Choose the correct choice:
A) 103.92
B) 114
C) 114.75
D) 124
E) 124.75 | <gadget id="calculator">7_500 / 756</gadget>
<output>625/63 = around 9.920635</output>
<gadget id="calculator">(625/63) * 10.5</gadget>
<output>104.166667</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">104.166667 - (1/4)</gadget>
<output>103.916667</output>
<result>A</result> | A | 103.92 | The market value of a 10.5% stock, in which an income of Rs. 756 is derived by investing Rs. 7500, brokerage being 1/4%, is: | {
"A": "103.92",
"B": "114",
"C": "114.75",
"D": "124",
"E": "124.75"
} | subtract(multiply(divide(7500, 756), 10.5), divide(1, 4)) | divide(n2,n1)|divide(n3,n4)|multiply(n0,#0)|subtract(#2,#1)| | "face value = rs . 7500 . dividend = 10.5 % . annual income = rs . 756 . brokerage per rs . 100 = rs . 0.25 . dividend is always paid on the face value of a share . face value * dividend / ( market value + brokerage per rs . 100 ) = annual income . = 7500 * 10.5 / 756 = market value of rs . 100 stock + brokerage per rs . 100 . = market value of rs . 100 stock + brokerage per rs . 100 = rs . 104.17 = market value of rs . 100 stock = rs . 104.17 - re . 0.25 . = market value of rs . 100 stock = rs . 103.92 . answer : a" | gain |
math_qa__11rmcfXv7c2vLNlc | A bag contains 6 black and 5 white balls. One ball is drawn at random. What is the probability that the ball drawn is white? Choose the correct answer:
A) 3 / 4
B) 5 / 11
C) 1 / 7
D) 1 / 8
E) 4 / 3 | <gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">120 / 6</gadget>
<output>20</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">720 / 24</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">10 + 15</gadget>
<output>25</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">factorial(11)</gadget>
<output>39_916_800</output>
<gadget id="calculator">11 - 2</gadget>
<output>9</output>
<gadget id="calculator">factorial(9)</gadget>
<output>362_880</output>
<gadget id="calculator">39_916_800 / 362_880</gadget>
<output>110</output>
<gadget id="calculator">110 / 2</gadget>
<output>55</output>
<gadget id="calculator">25 / 55</gadget>
<output>5/11 = around 0.454545</output>
<result>B</result> | B | 0.454545 | A bag contains 6 black and 5 white balls. One ball is drawn at random. What is the probability that the ball drawn is white? | {
"A": "3 / 4",
"B": "5 / 11",
"C": "1 / 7",
"D": "1 / 8",
"E": "4 / 3"
} | divide(add(divide(divide(factorial(5), factorial(subtract(5, const_2))), factorial(const_2)), divide(divide(factorial(6), factorial(subtract(6, const_2))), factorial(const_2))), divide(divide(factorial(add(6, 5)), factorial(subtract(add(6, 5), const_2))), factorial(const_2))) | add(n0,n1)|factorial(n1)|factorial(const_2)|factorial(n0)|subtract(n1,const_2)|subtract(n0,const_2)|factorial(#4)|factorial(#5)|factorial(#0)|subtract(#0,const_2)|divide(#1,#6)|divide(#3,#7)|factorial(#9)|divide(#10,#2)|divide(#11,#2)|divide(#8,#12)|add(#13,#14)|divide(#15,#2)|divide(#16,#17)| | "let number of balls = ( 6 + 5 ) = 11 . number of white balls = 5 p ( drawing a white ball ) = 5 / 11 option b ." | probability |
math_qa__JFfqKS0zCNoupD2I | In what ratio water be mixed with milk costing Rs.12 per liter to obtain a mixture worth of Rs.8 per litre? Select:
A) 2 : 7 B) 1 : 2 C) 2 : 9 D) 2 : 2 E) 2 : 6 | <gadget id="calculator">8 / 12</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) / (2/3)</gadget>
<output>1/2 = around 0.5</output>
<result>B</result> | B | 0.5 | In what ratio water be mixed with milk costing Rs.12 per liter to obtain a mixture worth of Rs.8 per litre? | {
"A": "2 : 7",
"B": "1 : 2",
"C": "2 : 9",
"D": "2 : 2",
"E": "2 : 6"
} | divide(subtract(const_1, divide(8, 12)), divide(8, 12)) | divide(n1,n0)|subtract(const_1,#0)|divide(#1,#0) | answer with explanation : by the rule of allegation , i . c . p of 1 liter of water = 0 ii . c . p of 1 liter of milk = 12 iii . mean price ( p ) = 8 iv . d – m = 12 - 8 = 4 v . m – c = 8 - 0 = 8 ratio of water and milk = 4 : 8 = 1 : 2 answer : b | other |
math_qa__eDow4F92xRl8NaAi | find the largest number of 4 digits which is exactly divisible by 2718 , 1615 Choose the correct choice from the following answers:
A) 8600 B) 8610 C) 8620 D) 8630 E) 8640 | <gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">1_615 % 100</gadget>
<output>15</output>
<gadget id="calculator">1_615 - 15</gadget>
<output>1_600</output>
<gadget id="calculator">1_600 / 100</gadget>
<output>16</output>
<gadget id="calculator">2_718 % 100</gadget>
<output>18</output>
<gadget id="calculator">2_718 - 18</gadget>
<output>2_700</output>
<gadget id="calculator">2_700 / 100</gadget>
<output>27</output>
<gadget id="calculator">lcm(16, 27)</gadget>
<output>432</output>
<gadget id="calculator">lcm(432, 15)</gadget>
<output>2_160</output>
<gadget id="calculator">lcm(2_160, 18)</gadget>
<output>2_160</output>
<gadget id="calculator">10_000 / 2_160</gadget>
<output>125/27 = around 4.62963</output>
<gadget id="calculator">floor(125/27)</gadget>
<output>4</output>
<gadget id="calculator">4 * 2_160</gadget>
<output>8_640</output>
<result>E</result> | E | 8,640 | find the largest number of 4 digits which is exactly divisible by 2718 , 1615 | {
"A": "8600",
"B": "8610",
"C": "8620",
"D": "8630",
"E": "8640"
} | multiply(floor(divide(multiply(const_10, const_1000), lcm(lcm(lcm(divide(subtract(1615, reminder(1615, const_100)), const_100), divide(subtract(2718, reminder(2718, const_100)), const_100)), reminder(1615, const_100)), reminder(2718, const_100)))), lcm(lcm(lcm(divide(subtract(1615, reminder(1615, const_100)), const_100), divide(subtract(2718, reminder(2718, const_100)), const_100)), reminder(1615, const_100)), reminder(2718, const_100))) | multiply(const_10,const_1000)|reminder(n2,const_100)|reminder(n1,const_100)|subtract(n2,#1)|subtract(n1,#2)|divide(#3,const_100)|divide(#4,const_100)|lcm(#5,#6)|lcm(#7,#1)|lcm(#8,#2)|divide(#0,#9)|floor(#10)|multiply(#11,#9) | explanation : lcm of 27 - 18 - 16 - 15 is 2160 . after dividing 9999 by 2160 we get 1359 remainder . so answer will be 9999 - 1359 = 8640 option e | general |
math_qa__wzzfIQecNtGX02rO | A reindeer chased by a Cheetah passed a certain tree at a constant speed of 50 miles per hour while being chased by a Cheetah. Then, 2 minutes later, the Cheetah passed the same tree at a constant speed of 60 miles per hour. If both animals maintained their speeds, how long after the Cheetah passed the tree did the Cheetah catch up with the reindeer? Pick.
A) 30 min
B) 45 min
C) 1 hr
D) 3 min
E) 1 min | <gadget id="calculator">60 - 50</gadget>
<output>10</output>
<gadget id="calculator">2 / 60</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">50 * (1/30)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">10 / (5/3)</gadget>
<output>6</output>
<gadget id="calculator">6 / 2</gadget>
<output>3</output>
<result>D</result> | D | 3 | A reindeer chased by a Cheetah passed a certain tree at a constant speed of 50 miles per hour while being chased by a Cheetah. Then, 2 minutes later, the Cheetah passed the same tree at a constant speed of 60 miles per hour. If both animals maintained their speeds, how long after the Cheetah passed the tree did the Cheetah catch up with the reindeer? | {
"A": "30 min",
"B": "45 min",
"C": "1 hr",
"D": "3 min",
"E": "1 min"
} | divide(divide(subtract(60, 50), multiply(50, divide(2, const_60))), const_2) | divide(n1,const_60)|subtract(n2,n0)|multiply(n0,#0)|divide(#1,#2)|divide(#3,const_2) | when the cheetah is at the tree , the reindeer is 50 / 30 miles ahead on the highway . ( the distance covered in 2 min ) every hour , cheetah runs 10 miles more than the deer . how many hours will it takes it to cover 50 / 30 miles more ? the answer is ( 50 / 30 ) / 10 = 1 / 60 = 1 min answer e | physics |
math_qa__wPj3FqIP9LH5S9G3 | If the numbers 1 to 100 are written on 100 pieces of paper, (one on each) and one piece is picked at random, then What is the probability that the number drawn is neither prime nor composite?
Choose the correct choice from the following options: A) 1 / 50 B) 1 / 25 C) 1 / 100 D) 1 E) 2 | <gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<result>C</result> | C | 0.01 | If the numbers 1 to 100 are written on 100 pieces of paper, (one on each) and one piece is picked at random, then What is the probability that the number drawn is neither prime nor composite? | {
"A": "1 / 50",
"B": "1 / 25",
"C": "1 / 100",
"D": "1",
"E": "2"
} | divide(1, 100) | divide(n0,n1)| | "there are 25 primes , 74 composite numbers from 1 to 100 . the number which is neither prime nor composite is 1 . therefore , required probability = 1 / 100 . answer : c" | other |
math_qa__mA01pPppaf5c8mAe | A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. Find out the number of days for which the remaining food will last Choose the correct option:
A) 44
B) 42
C) 40
D) 38
E) 36 | <gadget id="calculator">25 + 10</gadget>
<output>35</output>
<gadget id="calculator">150 * 35</gadget>
<output>5_250</output>
<gadget id="calculator">150 - 25</gadget>
<output>125</output>
<gadget id="calculator">5_250 / 125</gadget>
<output>42</output>
<result>B</result> | B | 42 | A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. Find out the number of days for which the remaining food will last | {
"A": "44",
"B": "42",
"C": "40",
"D": "38",
"E": "36"
} | divide(multiply(150, add(25, 10)), subtract(150, 25)) | add(n2,n3)|subtract(n0,n3)|multiply(n0,#0)|divide(#2,#1)| | "explanation : given that fort had provision of food for 150 men for 45 days hence , after 10 days , the remaining food is sufficient for 150 men for 35 days remaining men after 10 days = 150 - 25 = 125 assume that after 10 days , the remaining food is sufficient for 125 men for x days more men , less days ( indirect proportion ) ⇒ men 150 : 125 } : : x : 35 ⇒ 150 × 35 = 125 x ⇒ 6 × 35 = 5 x ⇒ x = 6 × 7 = 42 ⇒ the remaining food is sufficient for 125 men for 42 days . answer : option b" | physics |
math_qa__3YcUuBGA5KqUEIfb | A basketball team composed of 12 players scored 100 points in a particular contest. If none of the individual players scored fewer than 7 points, what is the greatest number of points W that an individual player might have scored?
Choose the correct choice from the following options:
A) 7
B) 13
C) 16
D) 21
E) 23 | <gadget id="calculator">12 * 7</gadget>
<output>84</output>
<gadget id="calculator">100 - 84</gadget>
<output>16</output>
<gadget id="calculator">16 + 7</gadget>
<output>23</output>
<result>E</result> | E | 23 | A basketball team composed of 12 players scored 100 points in a particular contest. If none of the individual players scored fewer than 7 points, what is the greatest number of points W that an individual player might have scored? | {
"A": "7",
"B": "13",
"C": "16",
"D": "21",
"E": "23"
} | add(subtract(100, multiply(12, 7)), 7) | multiply(n0,n2)|subtract(n1,#0)|add(n2,#1)| | "general rule for such kind of problems : to maximize one quantity , minimize the others ; to minimize one quantity , maximize the others . thus to maximize the number of points of one particular player minimize the number of points of all other 11 players . minimum number of points for a player is 7 , so the minimum number of points of 11 players is 7 * 11 = 77 . therefore , the maximum number of points w for 12 th player is 100 - 77 = 23 . answer : e ." | general |
math_qa__aAddzXuNWPtsOtsl | The average length of 6 strings is 80 cm. If the average length of one third of the strings is 70 cm, what is the average of the other strings? Pick: A) 75 . B) 85 . C) 90 . D) 94 . E) 100 . | <gadget id="calculator">80 * 6</gadget>
<output>480</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<gadget id="calculator">2 * 70</gadget>
<output>140</output>
<gadget id="calculator">480 - 140</gadget>
<output>340</output>
<gadget id="calculator">6 - 2</gadget>
<output>4</output>
<gadget id="calculator">340 / 4</gadget>
<output>85</output>
<result>B</result> | B | 85 | The average length of 6 strings is 80 cm. If the average length of one third of the strings is 70 cm, what is the average of the other strings? | {
"A": "75 .",
"B": "85 .",
"C": "90 .",
"D": "94 .",
"E": "100 ."
} | divide(subtract(multiply(80, 6), multiply(divide(6, const_3), 70)), subtract(6, divide(6, const_3))) | divide(n0,const_3)|multiply(n0,n1)|multiply(n2,#0)|subtract(n0,#0)|subtract(#1,#2)|divide(#4,#3) | edit : given ( x 1 + x 2 . . . + x 6 ) / 6 = 80 ( x 1 + x 2 . . . + x 6 ) = 480 - - > eq 1 . now given avg length of one third strings is 70 . that means out 6 / 3 = 2 strings . let the avg length of two strings be ( x 1 + x 2 ) / 2 = 70 . ( x 1 + x 2 ) = 140 . - - > eq 2 . now we are asked to find the average of the remaining i . e . ( x 3 + x 4 + x 5 + x 6 ) substitute eq 2 in eq 1 then we get 140 + x 3 + x 4 + x 5 + x 6 = 480 = > x 3 + x 4 + x 5 + x 6 = 340 now divide 340 by 4 we get 85 . = > ( x 3 + x 4 + x 5 + x 6 ) / 4 = 85 = avg length of remaining strings . imo correct option is b . | general |
math_qa__fu1RDKfc5xnfnmpy | a palindrome is a number that reads the same forward and backward , such as 242 . how many even 9 - digit numbers are palindromes ? Answers
A) 40
B) 40000
C) 500
D) 5,000
E) 100,000 | <gadget id="calculator">9 / 2</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">floor(9/2)</gadget>
<output>4</output>
<gadget id="calculator">10 ** 4</gadget>
<output>10_000</output>
<gadget id="calculator">4 * 10_000</gadget>
<output>40_000</output>
<result>B</result> | B | 40,000 | a palindrome is a number that reads the same forward and backward , such as 242 . how many even 9 - digit numbers are palindromes ? | {
"A": "40",
"B": "40000",
"C": "500",
"D": "5,000",
"E": "100,000"
} | multiply(const_4, power(const_10, floor(divide(9, const_2)))) | divide(n1,const_2)|floor(#0)|power(const_10,#1)|multiply(#2,const_4) | if the palindrome must be even , it must begin and end in 2,4 6 and 8 ( 4 ways ) e . g 222212222,444414444 . the middle number in the nine - digit could be 0 - 9 ( 10 ways ) , e . g 22522 , 22822 the 2 nd and fourth numbers , the 3 rd and 5 th and 4 th and 6 th could must also be same i . e 0 - 9 ( 10 ways ) e . g 242343242 , 648565846 we thus have , 4 * 10 * 10 * 10 * 10 = 40000 b | general |
math_qa__AkDufcVi6tKywSO3 | At an upscale fast-food restaurant, Shin can buy 3 burgers, 7 shakes, and one cola for $110. At the same place it would cost $164.50 for 4 burgers, 10 shakes, and one cola. How much would it cost for a meal of one burger, one shake, and one cola? Pick one:
A) $ 1 B) $ 27 C) $ 31 D) $ 41 E) it can not be determined | <gadget id="calculator">164.5 - 110</gadget>
<output>54.5</output>
<gadget id="calculator">110 + 54.5</gadget>
<output>164.5</output>
<gadget id="calculator">54.5 * 3</gadget>
<output>163.5</output>
<gadget id="calculator">164.5 - 163.5</gadget>
<output>1</output>
<result>A</result> | A | 1 | At an upscale fast-food restaurant, Shin can buy 3 burgers, 7 shakes, and one cola for $110. At the same place it would cost $164.50 for 4 burgers, 10 shakes, and one cola. How much would it cost for a meal of one burger, one shake, and one cola? | {
"A": "$ 1",
"B": "$ 27",
"C": "$ 31",
"D": "$ 41",
"E": "it can not be determined"
} | subtract(add(110, subtract(164.5, 110)), multiply(subtract(164.5, 110), const_3)) | subtract(n3,n2)|add(n2,#0)|multiply(#0,const_3)|subtract(#1,#2) | let ' s suppose that the price of a burger is bb , of a shake - ss and that of a cola is cc . we can then construct these equations : 3 b + 7 s + c = 110 4 b + 10 s + c = 164.5 subtracting the first equation from the second gives us b + 3 s = 54.5 now if we subtract the new equation two times from first or 3 times from second we will get b + s + c = 11 . in any case , there is no necessity to know each item ' s price , just the sum . answer : a | general |
math_qa__f63qUZTu3rFj6zWS | Find the cost of fencing around a circular field of diameter 30 m at the rate of Rs.2 a meter? Select
A) 100.5 B) 188.5 C) 190.5 D) 168.5 E) 175.5 | <gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">2 * pi * 15</gadget>
<output>30*pi = around 94.24778</output>
<gadget id="calculator">(30*pi) * 2</gadget>
<output>60*pi = around 188.495559</output>
<result>B</result> | B | 188.5 | Find the cost of fencing around a circular field of diameter 30 m at the rate of Rs.2 a meter? | {
"A": "100.5",
"B": "188.5",
"C": "190.5",
"D": "168.5",
"E": "175.5"
} | multiply(circumface(divide(30, const_2)), 2) | divide(n0,const_2)|circumface(#0)|multiply(n1,#1)| | "2 * 22 / 7 * 15 = 94.25 94.25 * 2 = rs . 188.5 answer : b" | physics |
math_qa__HVQru3mDRd8D5p15 | What is the ratio whose term differ by 40 and the measure of which is 2/7? Pick.
A) 32 : 23 B) 16 : 56 C) 71 : 85 D) 32 : 39 E) 41 : 52 | <gadget id="calculator">40 * 2</gadget>
<output>80</output>
<gadget id="calculator">7 - 2</gadget>
<output>5</output>
<gadget id="calculator">80 / 5</gadget>
<output>16</output>
<gadget id="calculator">40 + 16</gadget>
<output>56</output>
<gadget id="calculator">16 / 56</gadget>
<output>2/7 = around 0.285714</output>
<result>B</result> | B | 0.285714 | What is the ratio whose term differ by 40 and the measure of which is 2/7? | {
"A": "32 : 23",
"B": "16 : 56",
"C": "71 : 85",
"D": "32 : 39",
"E": "41 : 52"
} | divide(divide(multiply(40, 2), subtract(7, 2)), add(40, divide(multiply(40, 2), subtract(7, 2)))) | multiply(n0,n1)|subtract(n2,n1)|divide(#0,#1)|add(n0,#2)|divide(#2,#3) | let the ratio be x : ( x + 40 ) then , x / ( x + 40 ) = 2 / 7 x = 16 required ratio = 16 : 56 answer is b | other |
math_qa__0qHJuYJqIqONiREv | In how many ways 4 boys and 2 girls can be seated in a row so that they are alternate. Choose the correct choice.
A) 48 B) 288 C) 12 D) 256 E) none | <gadget id="calculator">factorial(4)</gadget>
<output>24</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<result>A</result> | A | 48 | In how many ways 4 boys and 2 girls can be seated in a row so that they are alternate. | {
"A": "48",
"B": "288",
"C": "12",
"D": "256",
"E": "none"
} | multiply(factorial(4), factorial(2)) | factorial(n0)|factorial(n1)|multiply(#0,#1)| | "solution : let the arrangement be , b g b g b b 4 boys can be seated in 4 ! ways . girl can be seated in 2 ! ways . required number of ways , = 4 ! * 2 ! = 48 answer : option a" | probability |
math_qa__Fg7bUbxTNc3rRtzA | The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 13 is: Choose one: A) 448 B) 553 C) 542 D) 548 E) 560 | <gadget id="calculator">54 * 10</gadget>
<output>540</output>
<result>B</result> | B | 553 | The least number, which when divided by 12, 15, 20 and 54 leaves in each case a remainder of 13 is: | {
"A": "448",
"B": "553",
"C": "542",
"D": "548",
"E": "560"
} | multiply(54, const_10) | multiply(n3,const_10)| | "required number = ( l . c . m . of 12 , 15 , 20 , 54 ) + 13 = 540 + 13 = 553 . answer : b" | general |
math_qa__kybTjgFms0WMweYt | Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/4 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent? Choose the correct choice from the following answers.
A) 7 / 12
B) 29 / 60
C) 17 / 30
D) 19 / 30
E) 11 / 15 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/3) * (1/2)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/6) + (1/4)</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">1 - (5/12)</gadget>
<output>7/12 = around 0.583333</output>
<result>A</result> | A | 0.583333 | Sally has a gold credit card with a certain spending limit, and a platinum card with twice the spending limit of the gold card. Currently, she has a balance on her gold card that is 1/3 of the spending limit on that card, and she has a balance on her platinum card that is 1/4 of the spending limit on that card. If Sally transfers the entire balance on her gold card to her platinum card, what portion of her limit on the platinum card will remain unspent? | {
"A": "7 / 12",
"B": "29 / 60",
"C": "17 / 30",
"D": "19 / 30",
"E": "11 / 15"
} | subtract(1, add(multiply(inverse(3), inverse(const_2)), inverse(4))) | inverse(n3)|inverse(n1)|inverse(const_2)|multiply(#1,#2)|add(#0,#3)|subtract(n0,#4)| | "let s assume the platinum card spending limit = x gold card spending limit will be = x / 2 balance on gold card is = x / 2 * 1 / 3 = x / 6 platinum card unspent limit is = x - 1 / 4 x = 3 / 4 x so if gold card balance is transferred then the rest unspent will be 3 / 4 x - x / 6 = 7 / 12 x so the ans is a" | general |
math_qa__tcBq38QwX1opM9lm | At a certain food stand, the price of each apple is 40¢ and the price of each orange is 60¢. Mary selects a total of 10 apples and oranges from the food stand, and the average (arithmetic mean) price of the 10 pieces of fruit is 52¢. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is 44¢? Choose the most appropriate option:
A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">60 * 10</gadget>
<output>600</output>
<gadget id="calculator">52 * 10</gadget>
<output>520</output>
<gadget id="calculator">600 - 520</gadget>
<output>80</output>
<gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">80 / 20</gadget>
<output>4</output>
<gadget id="calculator">4 * 40</gadget>
<output>160</output>
<gadget id="calculator">10 - 4</gadget>
<output>6</output>
<gadget id="calculator">6 * 60</gadget>
<output>360</output>
<gadget id="calculator">160 + 360</gadget>
<output>520</output>
<gadget id="calculator">44 * 10</gadget>
<output>440</output>
<gadget id="calculator">520 - 440</gadget>
<output>80</output>
<gadget id="calculator">60 - 44</gadget>
<output>16</output>
<gadget id="calculator">80 / 16</gadget>
<output>5</output>
<result>E</result> | E | 5 | At a certain food stand, the price of each apple is 40¢ and the price of each orange is 60¢. Mary selects a total of 10 apples and oranges from the food stand, and the average (arithmetic mean) price of the 10 pieces of fruit is 52¢. How many oranges must Mary put back so that the average price of the pieces of fruit that she keeps is 44¢? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | divide(subtract(add(multiply(divide(subtract(multiply(60, 10), multiply(52, 10)), subtract(60, 40)), 40), multiply(subtract(10, divide(subtract(multiply(60, 10), multiply(52, 10)), subtract(60, 40))), 60)), multiply(44, 10)), subtract(60, 44)) | multiply(n1,n2)|multiply(n2,n4)|multiply(n2,n5)|subtract(n1,n0)|subtract(n1,n5)|subtract(#0,#1)|divide(#5,#3)|multiply(n0,#6)|subtract(n2,#6)|multiply(n1,#8)|add(#7,#9)|subtract(#10,#2)|divide(#11,#4) | if the average price is 52 , then mary has 6 oranges and 4 apples ( a ratio of 3 : 2 ) . for the average price to be 44 , the ratio should be 1 : 4 . mary must put back 5 oranges . the answer is e . | general |
math_qa__bofedOivm5hgFLlP | There were 35 students in a hostel. Due to the admission of 7 new students the expenses of the mess were increased by Rs.42 per day while the average expenditure per head diminished by Re 1. What was the original expenditure of the mess? Choose one:
A) rs . 450 B) rs . 320 C) rs . 550 D) rs . 420 E) none | <gadget id="calculator">35 + 7</gadget>
<output>42</output>
<gadget id="calculator">42 + 42</gadget>
<output>84</output>
<gadget id="calculator">84 / 7</gadget>
<output>12</output>
<gadget id="calculator">12 * 35</gadget>
<output>420</output>
<result>D</result> | D | 420 | There were 35 students in a hostel. Due to the admission of 7 new students the expenses of the mess were increased by Rs.42 per day while the average expenditure per head diminished by Re 1. What was the original expenditure of the mess? | {
"A": "rs . 450",
"B": "rs . 320",
"C": "rs . 550",
"D": "rs . 420",
"E": "none"
} | multiply(divide(add(42, add(35, 7)), 7), 35) | add(n0,n1)|add(n2,#0)|divide(#1,n1)|multiply(n0,#2)| | "solution : let the original average expenditure be rs . x then , 42 ( x - 1 ) - 35 x = 42 . = > 7 x = 84 = > x = 12 therefore original expenditure , = rs . ( 35 × 12 ) = rs . 420 . answer : option d" | general |
math_qa__zy1Tupl2uxPbusTS | Excluding stoppages, the speed of a bus is 54 km/hr and including stoppages, it is 45 km/hr. For how many minutes does the bus stop per hour? Select.
A) 22
B) 10
C) 99
D) 77
E) 29 | <gadget id="calculator">54 - 45</gadget>
<output>9</output>
<gadget id="calculator">9 / 54</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">60 * (1/6)</gadget>
<output>10</output>
<result>B</result> | B | 10 | Excluding stoppages, the speed of a bus is 54 km/hr and including stoppages, it is 45 km/hr. For how many minutes does the bus stop per hour? | {
"A": "22",
"B": "10",
"C": "99",
"D": "77",
"E": "29"
} | multiply(const_60, divide(subtract(54, 45), 54)) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_60)| | "due to stoppages , it covers 9 km less . time taken to cover 9 km = 9 / 54 * 60 = 10 min . answer : b" | physics |
math_qa__Ay8TEvk5uSvZWig3 | A man two flats for $675958 each. On one he gains 15% while on the other he loses 15%. How much does he gain or lose in the whole transaction? Choose the correct choice from the following choices.
A) 2 % B) 2.25 % C) 3.12 % D) 4.65 % E) 5.12 % | <gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">100 / 115</gadget>
<output>20/23 = around 0.869565</output>
<gadget id="calculator">(20/23) * 675_958</gadget>
<output>13_519_160/23 = around 587_789.565217</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">100 / 85</gadget>
<output>20/17 = around 1.176471</output>
<gadget id="calculator">(20/17) * 675_958</gadget>
<output>13_519_160/17 = around 795_244.705882</output>
<gadget id="calculator">(13_519_160/23) + (13_519_160/17)</gadget>
<output>540_766_400/391 = around 1_383_034.2711</output>
<gadget id="calculator">675_958 + 675_958</gadget>
<output>1_351_916</output>
<gadget id="calculator">(540_766_400/391) - 1_351_916</gadget>
<output>12_167_244/391 = around 31_118.2711</output>
<gadget id="calculator">(12_167_244/391) / (540_766_400/391)</gadget>
<output>9/400 = around 0.0225</output>
<gadget id="calculator">(9/400) * 100</gadget>
<output>9/4 = around 2.25</output>
<result>B</result> | B | 2.25 | A man two flats for $675958 each. On one he gains 15% while on the other he loses 15%. How much does he gain or lose in the whole transaction? | {
"A": "2 %",
"B": "2.25 %",
"C": "3.12 %",
"D": "4.65 %",
"E": "5.12 %"
} | multiply(divide(subtract(add(multiply(divide(const_100, add(const_100, 15)), 675958), multiply(divide(const_100, subtract(const_100, 15)), 675958)), add(675958, 675958)), add(multiply(divide(const_100, add(const_100, 15)), 675958), multiply(divide(const_100, subtract(const_100, 15)), 675958))), const_100) | add(n1,const_100)|add(n0,n0)|subtract(const_100,n1)|divide(const_100,#0)|divide(const_100,#2)|multiply(n0,#3)|multiply(n0,#4)|add(#5,#6)|subtract(#7,#1)|divide(#8,#7)|multiply(#9,const_100)| | "in such a case there is always a loss loss % = ( 15 / 10 ) ^ 2 = 9 / 4 = 2.25 % answer is b" | gain |
math_qa__UNkzxhpsHCyb6Fdn | 61 + 5 * 12 / (180/3) = ? Select:
A) 22 B) 77 C) 29 D) 62 E) 21 | <gadget id="calculator">5 * 12</gadget>
<output>60</output>
<gadget id="calculator">180 / 3</gadget>
<output>60</output>
<gadget id="calculator">60 / 60</gadget>
<output>1</output>
<gadget id="calculator">61 + 1</gadget>
<output>62</output>
<result>D</result> | D | 62 | 61 + 5 * 12 / (180/3) = ? | {
"A": "22",
"B": "77",
"C": "29",
"D": "62",
"E": "21"
} | add(61, divide(multiply(5, 12), divide(180, 3))) | divide(n3,n4)|multiply(n1,n2)|divide(#1,#0)|add(n0,#2)| | "61 + 5 * 12 / ( 180 / 3 ) = 61 + 5 * 12 / ( 60 ) = 61 + ( 5 * 12 ) / 60 = 61 + 1 = 62 . answer : d" | general |
math_qa__UCOU0DLBWiYu5Odn | There is enough provisions for 600 men in an army camp for 25 days. If there were 100 men less, how long will the provision last? Options:
A) 10 days B) 50 days C) 100 days D) 150 days E) 200 days | <gadget id="calculator">600 * 25</gadget>
<output>15_000</output>
<gadget id="calculator">15_000 / 100</gadget>
<output>150</output>
<result>D</result> | D | 150 | There is enough provisions for 600 men in an army camp for 25 days. If there were 100 men less, how long will the provision last? | {
"A": "10 days",
"B": "50 days",
"C": "100 days",
"D": "150 days",
"E": "200 days"
} | divide(multiply(600, 25), 100) | multiply(n0,n1)|divide(#0,n2)| | "exp : we have , m 1 d 1 = m 2 d 2 600 * 25 = 100 * d 2 d 2 = 600 * 25 / 100 = 150 days . answer : d" | physics |
math_qa__c0mX9PNZrgfE2MKA | What is the number of integers from 1 to 1000 (inclusive) that are divisible by neither 11 nor by 34? Choose the correct choice from the following answers.
A) 884
B) 890
C) 892
D) 910
E) 945 | <gadget id="calculator">1_000 / 11</gadget>
<output>1_000/11 = around 90.909091</output>
<gadget id="calculator">1_000 / 34</gadget>
<output>500/17 = around 29.411765</output>
<gadget id="calculator">(1_000/11) + (500/17)</gadget>
<output>22_500/187 = around 120.320856</output>
<gadget id="calculator">11 * 34</gadget>
<output>374</output>
<gadget id="calculator">1_000 / 374</gadget>
<output>500/187 = around 2.673797</output>
<gadget id="calculator">(22_500/187) - (500/187)</gadget>
<output>2_000/17 = around 117.647059</output>
<gadget id="calculator">1_000 - (2_000/17)</gadget>
<output>15_000/17 = around 882.352941</output>
<result>B</result> | B | 890 | What is the number of integers from 1 to 1000 (inclusive) that are divisible by neither 11 nor by 34? | {
"A": "884",
"B": "890",
"C": "892",
"D": "910",
"E": "945"
} | subtract(1000, subtract(add(divide(1000, 11), divide(1000, 34)), divide(1000, multiply(11, 34)))) | divide(n1,n2)|divide(n1,n3)|multiply(n2,n3)|add(#0,#1)|divide(n1,#2)|subtract(#3,#4)|subtract(n1,#5)| | "normally , i would use the method used by bunuel . it ' s the most accurate . but if you are looking for a speedy solution , you can use another method which will sometimes give you an estimate . looking at the options ( most of them are spread out ) , i wont mind trying it . ( mind you , the method is accurate here since the numbers start from 1 . ) in 1000 consecutive numbers , number of multiples of 11 = 1000 / 11 = 90 ( ignore decimals ) in 1000 consecutive numbers , number of multiples of 35 = 1000 / 35 = 28 number of multiples of 11 * 35 i . e . 385 = 1000 / 385 = 2 number of integers from 1 to 1000 that are divisible by neither 11 nor by 35 = 1000 - ( 90 + 28 - 2 ) { using the concept of sets here ) = 890 think : why did i say the method is approximate in some cases ? think what happens if the given range is 11 to 1010 both inclusive ( again 1000 numbers ) what is the number of multiples in this case ? b" | other |
math_qa__xiL9sznYUBg4HKut | Veena ranks 79rd from the top in a class of 182. What is her rank from the bottom if 22 students have failed the examination?
Choose the correct choice: A) 88 B) 108 C) 82 D) 90 E) 93 | <gadget id="calculator">182 - 22</gadget>
<output>160</output>
<gadget id="calculator">79 - 1</gadget>
<output>78</output>
<gadget id="calculator">160 - 78</gadget>
<output>82</output>
<gadget id="calculator">82 - 4</gadget>
<output>78</output>
<result>C</result> | C | 82 | Veena ranks 79rd from the top in a class of 182. What is her rank from the bottom if 22 students have failed the examination? | {
"A": "88",
"B": "108",
"C": "82",
"D": "90",
"E": "93"
} | subtract(subtract(subtract(182, 22), subtract(79, const_1)), const_4) | subtract(n1,n2)|subtract(n0,const_1)|subtract(#0,#1)|subtract(#2,const_4) | total student = 182 failed = 22 paasd student = 182 - 22 = 160 from bottom her rank is = 160 - 79 + 1 = 82 answer : c | other |
math_qa__v1pFM6WjrQrWl6xq | A certain telescope increases the visual range at a particular location from 100 kilometers to 150 kilometers. By what percent is the visual range increased by using the telescope ? Select the correct option:
A) 30 % B) 33 1 / 2 % C) 40 % D) 60 % E) 50 % | <gadget id="calculator">150 - 100</gadget>
<output>50</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>E</result> | E | 50 | A certain telescope increases the visual range at a particular location from 100 kilometers to 150 kilometers. By what percent is the visual range increased by using the telescope ? | {
"A": "30 %",
"B": "33 1 / 2 %",
"C": "40 %",
"D": "60 %",
"E": "50 %"
} | multiply(divide(subtract(150, 100), 100), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "original visual range = 100 km new visual range = 150 km percent increase in the visual range by using the telescope = ( 150 - 100 ) / 100 * 100 % = 1 / 2 * 100 % = 50 % answer e" | general |
math_qa__ZjYZrvfknTsbs99k | What is the area of a square field whose diagonal of length 10 m? Choose the correct choice from the following answers.
A) 50 B) 70 C) 60 D) 20 E) 25 | <gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<result>A</result> | A | 50 | What is the area of a square field whose diagonal of length 10 m? | {
"A": "50",
"B": "70",
"C": "60",
"D": "20",
"E": "25"
} | divide(square_area(10), const_2) | square_area(n0)|divide(#0,const_2)| | "d 2 / 2 = ( 10 * 10 ) / 2 = 50 answer : a" | geometry |
math_qa__Nf4gI9uuemSwemNK | If 2994 ÷ 14.5 = 175, then 29.94 ÷ 1.45 = ? Choose the correct answer
A) 17.1 B) 17.3 C) 17.5 D) 17.7 E) 17.2 | <gadget id="calculator">14.5 / 1.45</gadget>
<output>10</output>
<gadget id="calculator">175 / 10</gadget>
<output>35/2 = around 17.5</output>
<result>C</result> | C | 17.5 | If 2994 ÷ 14.5 = 175, then 29.94 ÷ 1.45 = ? | {
"A": "17.1",
"B": "17.3",
"C": "17.5",
"D": "17.7",
"E": "17.2"
} | divide(175, divide(14.5, 1.45)) | divide(n1,n4)|divide(n2,#0)| | "29.94 / 1.45 = 299.4 / 14.5 = ( 2994 / 14.5 ) x 1 / 10 ) [ here , substitute 175 in the place of 2994 / 14.5 ] = 175 / 10 = 17.5 answer is c ." | general |
math_qa__TZf6nVevJ67hqBad | There are 50 students in a class. If 2 % are absent on a particular day, find the number of students present in the class. Choose the correct option:
A) 43 B) 36 C) 28 D) 49 E) 11 | <gadget id="calculator">2 / 50</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">1 - (1/25)</gadget>
<output>24/25 = around 0.96</output>
<gadget id="calculator">(24/25) * 50</gadget>
<output>48</output>
<result>D</result> | D | 49 | There are 50 students in a class. If 2 % are absent on a particular day, find the number of students present in the class. | {
"A": "43",
"B": "36",
"C": "28",
"D": "49",
"E": "11"
} | multiply(subtract(const_1, divide(2, 50)), 50) | divide(n1,n0)|subtract(const_1,#0)|multiply(#1,n0)| | "number of students absent on a particular day = 1 % of 50 i . e . , 2 / 100 × 50 = 1 therefore , the number of students present = 50 - 1 = 49 students . answer : d" | gain |
math_qa__tmD0xb1rfyUCvBwY | Jim drove 215 miles of a 1200 miles journey. How many more miles does he need to drive to finish his journey? Choose the correct answer: A) 113 miles B) 432 miles C) 456 miles D) 887 miles E) 985 miles | <gadget id="calculator">1_200 - 215</gadget>
<output>985</output>
<result>E</result> | E | 985 | Jim drove 215 miles of a 1200 miles journey. How many more miles does he need to drive to finish his journey? | {
"A": "113 miles",
"B": "432 miles",
"C": "456 miles",
"D": "887 miles",
"E": "985 miles"
} | subtract(1200, 215) | subtract(n1,n0)| | "the number of miles to drive to finish his journey is given by 1200 - 215 = 985 miles correct answer e" | physics |
math_qa__KhvfblkG6s9jaQLI | For a certain alarm system, each code is comprised of 5 digits, but no digit can be used more than twice. How many codes can be made? Choose one:
A) 30240 B) 60480 C) 91440 D) 98240 E) 101040 | <gadget id="calculator">factorial(10)</gadget>
<output>3_628_800</output>
<gadget id="calculator">10 - 5</gadget>
<output>5</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">3_628_800 / 120</gadget>
<output>30_240</output>
<gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">factorial(9)</gadget>
<output>362_880</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">9 - 3</gadget>
<output>6</output>
<gadget id="calculator">factorial(6)</gadget>
<output>720</output>
<gadget id="calculator">6 * 720</gadget>
<output>4_320</output>
<gadget id="calculator">362_880 / 4_320</gadget>
<output>84</output>
<gadget id="calculator">10 * 84</gadget>
<output>840</output>
<gadget id="calculator">120 / 2</gadget>
<output>60</output>
<gadget id="calculator">840 * 60</gadget>
<output>50_400</output>
<gadget id="calculator">30_240 + 50_400</gadget>
<output>80_640</output>
<gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">40_320 * 2</gadget>
<output>80_640</output>
<gadget id="calculator">3_628_800 / 80_640</gadget>
<output>45</output>
<gadget id="calculator">45 * 8</gadget>
<output>360</output>
<gadget id="calculator">120 / 4</gadget>
<output>30</output>
<gadget id="calculator">360 * 30</gadget>
<output>10_800</output>
<gadget id="calculator">80_640 + 10_800</gadget>
<output>91_440</output>
<result>C</result> | C | 91,440 | For a certain alarm system, each code is comprised of 5 digits, but no digit can be used more than twice. How many codes can be made? | {
"A": "30240",
"B": "60480",
"C": "91440",
"D": "98240",
"E": "101040"
} | add(add(divide(factorial(const_10), factorial(subtract(const_10, 5))), multiply(multiply(const_10, divide(factorial(subtract(const_10, const_1)), multiply(factorial(const_3), factorial(subtract(subtract(const_10, const_1), const_3))))), divide(factorial(5), const_2))), multiply(multiply(divide(factorial(const_10), multiply(factorial(subtract(const_10, const_2)), factorial(const_2))), subtract(const_10, const_2)), divide(factorial(5), const_4))) | factorial(const_10)|factorial(n0)|factorial(const_3)|factorial(const_2)|subtract(const_10,n0)|subtract(const_10,const_1)|subtract(const_10,const_2)|divide(#1,const_2)|divide(#1,const_4)|factorial(#4)|factorial(#5)|factorial(#6)|subtract(#5,const_3)|divide(#0,#9)|factorial(#12)|multiply(#11,#3)|divide(#0,#15)|multiply(#2,#14)|divide(#10,#17)|multiply(#16,#6)|multiply(#18,const_10)|multiply(#8,#19)|multiply(#7,#20)|add(#13,#22)|add(#23,#21) | case 1 : all digits distinct select 5 digits out of 10 in 10 c 5 ways and arrange them in 5 ! ways which gives us 10 c 5 x 5 ! = 30240 case 2 : two digits are same , other 3 are distinct e . g . 45722 select a digit which is to be repeated in 10 c 1 ways , select other 3 digits in 9 c 3 ways and arrange them in 5 ! / 2 ! ways to get 10 c 1 x 9 c 3 x 5 ! / 2 ! = 50400 ways case 3 : two digits repeated and one other digit e . g . 33448 select 2 digits to be repeated in 10 c 2 ways , select the single digit in 8 c 1 ways and arrange them all in 5 ! / 2 ! . 2 ! ways to get 10 c 2 x 8 c 1 x 5 ! / 2 ! . 2 ! = 10800 sum of all = 30240 + 50400 + 10800 = 91440 ways ans : c | general |
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