id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__eI5BlxSAvCs9nUQ5 | Little John had $5.10. He spent $1.05 on sweets and gave to his two friends $1.00 each. How much money was left?
Answers.
A) $ 2.15 B) $ 2.05 C) $ 2.45 D) $ 2.25 E) $ 2.85 | <gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">1.05 + 2</gadget>
<output>3.05</output>
<gadget id="calculator">5.1 - 3.05</gadget>
<output>2.05</output>
<result>B</result> | B | 2.05 | Little John had $5.10. He spent $1.05 on sweets and gave to his two friends $1.00 each. How much money was left? | {
"A": "$ 2.15",
"B": "$ 2.05",
"C": "$ 2.45",
"D": "$ 2.25",
"E": "$ 2.85"
} | subtract(5.10, add(1.05, add(1.00, 1.00))) | add(n2,n2)|add(n1,#0)|subtract(n0,#1)| | "john spent and gave to his two friends a total of 1.05 + 1.00 + 1.00 = $ 3.05 money left 5.10 - 3.05 = $ 2.05 answer : b" | general |
math_qa__1j2T4Ba7xhrELruG | A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.18900. A's share is?
Answers: A) 6300 B) 2765 C) 6000 D) 1298 E) 1261 | <gadget id="calculator">1 * 12</gadget>
<output>12</output>
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">18_900 / 36</gadget>
<output>525</output>
<gadget id="calculator">12 * 525</gadget>
<output>6_300</output>
<result>A</result> | A | 6,300 | A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.18900. A's share is? | {
"A": "6300",
"B": "2765",
"C": "6000",
"D": "1298",
"E": "1261"
} | multiply(multiply(const_1, const_12), divide(18900, add(add(multiply(const_1, const_12), multiply(subtract(const_12, 6), const_2)), multiply(subtract(const_12, 8), const_3)))) | multiply(const_1,const_12)|subtract(const_12,n0)|subtract(const_12,n1)|multiply(#1,const_2)|multiply(#2,const_3)|add(#0,#3)|add(#5,#4)|divide(n2,#6)|multiply(#7,#0)| | "x * 12 : 2 x * 6 : 3 x * 4 1 : 1 : 1 1 / 3 * 18900 = 6300 answer : a" | gain |
math_qa__x7YF7AY7b25If0Zg | If Albert’s monthly earnings rise by 30%, he would earn $598. If, instead, his earnings rise by only 35%, how much (in $) would he earn this month? Options
A) 621
B) 652
C) 660
D) 690
E) 693 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">598 / (13/10)</gadget>
<output>460</output>
<gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">1 + (7/20)</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">460 * (27/20)</gadget>
<output>621</output>
<result>A</result> | A | 621 | If Albert’s monthly earnings rise by 30%, he would earn $598. If, instead, his earnings rise by only 35%, how much (in $) would he earn this month? | {
"A": "621",
"B": "652",
"C": "660",
"D": "690",
"E": "693"
} | multiply(divide(598, add(const_1, divide(30, const_100))), add(const_1, divide(35, const_100))) | divide(n2,const_100)|divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|divide(n1,#3)|multiply(#2,#4)| | "= 598 / 1.3 ∗ 1.35 = 621 = 621 answer is a" | gain |
math_qa__Rj5wLnUouDCZqdka | Robert is travelling on his cycle andhas calculated to reach point A at 2 PM. if he travels at 10 kmph, he will reach there at 12Pm if he travels at 15 kmph. At what speed musthe travel to reach A at 1 PM? Select
A) 8 kmph
B) 9 kmph
C) 12 kmph
D) 14 kmph
E) 16 kmph | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/10) - (1/15)</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">2 / (1/30)</gadget>
<output>60</output>
<gadget id="calculator">60 / 10</gadget>
<output>6</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<result>C</result> | C | 12 | Robert is travelling on his cycle andhas calculated to reach point A at 2 PM. if he travels at 10 kmph, he will reach there at 12Pm if he travels at 15 kmph. At what speed musthe travel to reach A at 1 PM? | {
"A": "8 kmph",
"B": "9 kmph",
"C": "12 kmph",
"D": "14 kmph",
"E": "16 kmph"
} | divide(divide(2, subtract(divide(const_1, 10), divide(const_1, 15))), subtract(divide(divide(2, subtract(divide(const_1, 10), divide(const_1, 15))), 10), 1)) | divide(const_1,n1)|divide(const_1,n3)|subtract(#0,#1)|divide(n0,#2)|divide(#3,n1)|subtract(#4,n4)|divide(#3,#5) | let the distance travelled by x km . then , x - x = 2 10 15 3 x - 2 x = 60 x = 60 km . time taken to travel 60 km at 10 km / hr = 60 hrs = 6 hrs . 10 so , robert started 6 hours before 2 p . m . i . e . , at 8 a . m . required speed = 60 kmph . = 12 kmph . 5 c | physics |
math_qa__2KV1Bipy8eUEKZYe | Let f(x,y) be defined as the remainder when (x–y)! is divided by x. If x=36, what is the maximum value of y for which f(x,y)=0?
Choose the correct choice from the following answers: A) 9 B) 12 C) 18 D) 20 E) 30 | <gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">18 / 5</gadget>
<output>18/5 = around 3.6</output>
<gadget id="calculator">2 * (18/5)</gadget>
<output>36/5 = around 7.2</output>
<gadget id="calculator">36 - (36/5)</gadget>
<output>144/5 = around 28.8</output>
<result>E</result> | E | 30 | Let f(x,y) be defined as the remainder when (x–y)! is divided by x. If x=36, what is the maximum value of y for which f(x,y)=0? | {
"A": "9",
"B": "12",
"C": "18",
"D": "20",
"E": "30"
} | subtract(36, multiply(const_2, divide(divide(36, const_2), add(const_1, const_4)))) | add(const_1,const_4)|divide(n0,const_2)|divide(#1,#0)|multiply(#2,const_2)|subtract(n0,#3)| | "the question is finding y such that ( 36 - y ) ! is a multiple of 36 . that means we need to have 2 ^ 2 * 3 ^ 2 in ( 36 - y ) ! 6 ! is the smallest factorial number with 2 ^ 2 * 3 ^ 2 as a factor . 36 - y = 6 y = 30 the answer is e ." | general |
math_qa__HFhIHyR4crmvdGtL | A computer factory produces 4032 computers per month at a constant rate, how many computers are built every 30 minutes assuming that there are 28 days in one month? Choose the correct choice from the following:
A) 2.25 .
B) 3.00 .
C) 4.5 .
D) 5.225 .
E) 6.25 . | <gadget id="calculator">4_032 / 28</gadget>
<output>144</output>
<gadget id="calculator">28 - 4</gadget>
<output>24</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">144 / 48</gadget>
<output>3</output>
<result>B</result> | B | 3 | A computer factory produces 4032 computers per month at a constant rate, how many computers are built every 30 minutes assuming that there are 28 days in one month? | {
"A": "2.25 .",
"B": "3.00 .",
"C": "4.5 .",
"D": "5.225 .",
"E": "6.25 ."
} | divide(divide(4032, 28), multiply(subtract(28, const_4), const_2)) | divide(n0,n2)|subtract(n2,const_4)|multiply(#1,const_2)|divide(#0,#2) | number of hours in 28 days = 28 * 24 number of 30 mins in 28 days = 28 * 24 * 2 number of computers built every 30 mins = 4032 / ( 28 * 24 * 2 ) = 3 answer b | physics |
math_qa__SOpPIr2qkulaXwhO | The ratio of the radius of two circles is 1: 4, and then the ratio of their areas is? Choose the correct choice from the following: A) 1 : 16 B) 1 : 6 C) 1 : 9 D) 1 : 3 E) 1 : 2 | <gadget id="calculator">pi * (1 ** 2)</gadget>
<output>pi = around 3.141593</output>
<gadget id="calculator">pi * (4 ** 2)</gadget>
<output>16*pi = around 50.265482</output>
<gadget id="calculator">pi / (16*pi)</gadget>
<output>1/16 = around 0.0625</output>
<result>A</result> | A | 0.0625 | The ratio of the radius of two circles is 1: 4, and then the ratio of their areas is? | {
"A": "1 : 16",
"B": "1 : 6",
"C": "1 : 9",
"D": "1 : 3",
"E": "1 : 2"
} | divide(circle_area(1), circle_area(4)) | circle_area(n0)|circle_area(n1)|divide(#0,#1)| | "r 1 : r 2 = 1 : 4 π r 12 : π r 22 r 12 : r 22 = 1 : 16 answer : a" | geometry |
math_qa__X7kQdcekOmoWEisu | Country X imported approximately $1.44 billion of goods in 1996. If Country X imported $488 million of goods in the first two months of 1997 and continued to import goods at the same rate for the rest of the year, by how much would Country Xs 1997 imports exceed those of 1996? Choose the correct choice from the following answers
A) $ 1124 million B) $ 1120 million C) $ 1144 million D) $ 1240 million E) $ 1488 million | <gadget id="calculator">12 / 2</gadget>
<output>6</output>
<gadget id="calculator">488 * 6</gadget>
<output>2_928</output>
<gadget id="calculator">1.44 * 1_000</gadget>
<output>1_440</output>
<gadget id="calculator">2_928 - 1_440</gadget>
<output>1_488</output>
<result>E</result> | E | 1,488 | Country X imported approximately $1.44 billion of goods in 1996. If Country X imported $488 million of goods in the first two months of 1997 and continued to import goods at the same rate for the rest of the year, by how much would Country Xs 1997 imports exceed those of 1996? | {
"A": "$ 1124 million",
"B": "$ 1120 million",
"C": "$ 1144 million",
"D": "$ 1240 million",
"E": "$ 1488 million"
} | subtract(multiply(488, divide(const_12, const_2)), multiply(1.44, const_1000)) | divide(const_12,const_2)|multiply(n0,const_1000)|multiply(n2,#0)|subtract(#2,#1) | convert units to millions as answer is in millions 1996 imports = $ 1.44 bill = $ 1440 mill i . e . 1440 / 12 = $ 120 mill / month 1997 imports = $ 488 mill / 2 month i . e . $ 244 mill / month difference / month = 244 - 120 = 124 difference / year = $ 124 mill * 12 = $ 1488 mill answer : e | general |
math_qa__Lzfh1uqsJ0gsCXBA | 110 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors? Choose the correct choice from the following:
A) 34 B) 32 C) 30 D) 26 E) 28 | <gadget id="calculator">38 + 1</gadget>
<output>39</output>
<gadget id="calculator">39 + 45</gadget>
<output>84</output>
<gadget id="calculator">110 - 84</gadget>
<output>26</output>
<result>D</result> | D | 26 | 110 people are attending a newspaper conference. 45 of them are writers and more than 38 are editors. Of the people at the conference, x are both writers and editors and 2x are neither. What is the largest possible number of people who are both writers and editors? | {
"A": "34",
"B": "32",
"C": "30",
"D": "26",
"E": "28"
} | subtract(110, add(add(38, const_1), 45)) | add(n2,const_1)|add(n1,#0)|subtract(n0,#1)| | "{ total } = { writers } + { editors } - { both } + { neither } . { total } = 110 ; { writers } = 45 ; { editors } > 38 ; { both } = x ; { neither } = 2 x ; 110 = 45 + { editors } - x + 2 x - - > x = 65 - { editors } . we want to maximize x , thus we should minimize { editors } , minimum possible value of { editors } is 39 , thus x = { both } = 65 - 39 = 26 . answer : d ." | other |
math_qa__zshukwuhg1IKVAKr | one year ago , the ratio of roonie ’ s and ronaldo ’ s age was 6 : 7 respectively . 4 years hence , this ratio would become 7 : 8 . how old is ronaldo ? Pick one: A) 32 B) 33 C) 34 D) 35 E) 36 | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">8 * 5</gadget>
<output>40</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">40 - 35</gadget>
<output>5</output>
<gadget id="calculator">7 * 7</gadget>
<output>49</output>
<gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">49 - 48</gadget>
<output>1</output>
<gadget id="calculator">35 / 1</gadget>
<output>35</output>
<gadget id="calculator">35 + 1</gadget>
<output>36</output>
<result>E</result> | E | 36 | one year ago , the ratio of roonie ’ s and ronaldo ’ s age was 6 : 7 respectively . 4 years hence , this ratio would become 7 : 8 . how old is ronaldo ? | {
"A": "32",
"B": "33",
"C": "34",
"D": "35",
"E": "36"
} | add(divide(multiply(7, subtract(multiply(8, add(4, const_1)), multiply(7, add(4, const_1)))), subtract(multiply(7, 7), multiply(6, 8))), const_1) | add(n2,const_1)|multiply(n1,n1)|multiply(n0,n4)|multiply(n4,#0)|multiply(n1,#0)|subtract(#1,#2)|subtract(#3,#4)|multiply(n1,#6)|divide(#7,#5)|add(#8,const_1) | 7 ( x - 1 ) = 6 ( y - 1 ) = > 7 x - 6 y - 1 = 0 - - - - eq 1 8 ( x + 4 ) = 7 ( y + 4 ) = > 8 x - 7 y + 4 = 0 - - - - eq 2 on solving eq 1 n eq 2 y = 36 answer : e | other |
math_qa__ruWARO51PfElSLKj | The speed at which a man can row a boat in still water is 14 kmph. If he rows downstream, where the speed of current is 2 kmph, what time will he take to cover 40 metres? Choose the correct answer:
A) 16 seconds
B) 34 seconds
C) 9 seconds
D) 12 seconds
E) 15 seconds | <gadget id="calculator">14 + 2</gadget>
<output>16</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">16 * (5/18)</gadget>
<output>40/9 = around 4.444444</output>
<gadget id="calculator">40 / (40/9)</gadget>
<output>9</output>
<result>C</result> | C | 9 | The speed at which a man can row a boat in still water is 14 kmph. If he rows downstream, where the speed of current is 2 kmph, what time will he take to cover 40 metres? | {
"A": "16 seconds",
"B": "34 seconds",
"C": "9 seconds",
"D": "12 seconds",
"E": "15 seconds"
} | divide(40, multiply(add(14, 2), const_0_2778)) | add(n0,n1)|multiply(#0,const_0_2778)|divide(n2,#1)| | "speed of the boat downstream = 14 + 2 = 16 kmph = 16 * 5 / 18 = 40 / 9 m / s hence time taken to cover 40 m = 40 * 9 / 40 = 9 seconds . answer : c" | physics |
math_qa__uhdGGSjG9aQSyY22 | the average of the 5 numbers is 6.8 . if one of the numbers is multiplied by 3 , the average of the numbers increases to 9.2 . which of the 5 numbers is multiplied by 3 ?
Choose the correct choice from the following answers.
A) 1.5
B) 3.0
C) 3.9
D) 4.0
E) 6.0 | <gadget id="calculator">9.2 * 5</gadget>
<output>46</output>
<gadget id="calculator">6.8 * 5</gadget>
<output>34</output>
<gadget id="calculator">46 - 34</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>E</result> | E | 6 | the average of the 5 numbers is 6.8 . if one of the numbers is multiplied by 3 , the average of the numbers increases to 9.2 . which of the 5 numbers is multiplied by 3 ? | {
"A": "1.5",
"B": "3.0",
"C": "3.9",
"D": "4.0",
"E": "6.0"
} | divide(subtract(multiply(9.2, 5), multiply(6.8, 5)), const_2) | multiply(n0,n3)|multiply(n0,n1)|subtract(#0,#1)|divide(#2,const_2) | initial avg is 6.8 so the summation of the nos is 6.8 * 5 = 34 now the new avg is 9.2 so summation will be 9.2 * 5 = 46 . so change in summation is 12 . this comes when a number is multiplied by 3 . in the original sum we already have that number added once . to bring additional 12 increment by multiplying by 3 , we get a total increase of 18 . thus , 6 is multiplied by 3 . answer : e | general |
math_qa__GxkYfhSQAIOl5Vv0 | a , b , c subscribe rs . 50000 for a business . a subscribes rs . 4000 more than b and b rs . 5000 more than c . out of a total profit of rs . 30000 , b receives : Pick:
A) s . 10,000 B) s . 10,200 C) s . 10,400 D) s . 10,700 E) s . 10,800 | <gadget id="calculator">5_000 - 4_000</gadget>
<output>1_000</output>
<gadget id="calculator">50_000 + 1_000</gadget>
<output>51_000</output>
<gadget id="calculator">51_000 / 3</gadget>
<output>17_000</output>
<gadget id="calculator">17_000 / 50_000</gadget>
<output>17/50 = around 0.34</output>
<gadget id="calculator">30_000 * (17/50)</gadget>
<output>10_200</output>
<result>B</result> | B | 10,200 | a , b , c subscribe rs . 50000 for a business . a subscribes rs . 4000 more than b and b rs . 5000 more than c . out of a total profit of rs . 30000 , b receives : | {
"A": "s . 10,000",
"B": "s . 10,200",
"C": "s . 10,400",
"D": "s . 10,700",
"E": "s . 10,800"
} | multiply(30000, divide(divide(add(50000, subtract(5000, 4000)), const_3), 50000)) | subtract(n2,n1)|add(n0,#0)|divide(#1,const_3)|divide(#2,n0)|multiply(n3,#3) | let c = x . then , b = x + 5000 and a = x + 5000 + 4000 = x + 9000 . so , x + x + 5000 + x + 9000 = 50000 3 x = 36000 x = 12000 a : b : c = 21000 : 17000 : 12000 = 21 : 17 : 12 . b ' s share = rs . ( 30000 x 17 / 50 ) = rs . 10,200 . b | general |
math_qa__WqX2ObcZHCvFGM4q | A man swims downstream 48 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water? Choices: A) 2 B) 8 C) 9 D) 11 E) 14 | <gadget id="calculator">18 / 3</gadget>
<output>6</output>
<gadget id="calculator">48 / 3</gadget>
<output>16</output>
<gadget id="calculator">6 + 16</gadget>
<output>22</output>
<gadget id="calculator">22 / 2</gadget>
<output>11</output>
<result>D</result> | D | 11 | A man swims downstream 48 km and upstream 18 km taking 3 hours each time, what is the speed of the man in still water? | {
"A": "2",
"B": "8",
"C": "9",
"D": "11",
"E": "14"
} | divide(add(divide(18, 3), divide(48, 3)), const_2) | divide(n1,n2)|divide(n0,n2)|add(#0,#1)|divide(#2,const_2)| | "48 - - - 3 ds = 16 ? - - - - 1 18 - - - - 3 us = 6 ? - - - - 1 m = ? m = ( 16 + 6 ) / 2 = 11 answer : d" | physics |
math_qa__sWlOKJyv5K5HMvFZ | If the population of a certain country increases at the rate of one person every 30 seconds, by how many persons does the population increase in 10 minutes? Choose the correct choice from the following choices:
A) 20
B) 30
C) 15
D) 10
E) 80 | <gadget id="calculator">60 / 30</gadget>
<output>2</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<result>A</result> | A | 20 | If the population of a certain country increases at the rate of one person every 30 seconds, by how many persons does the population increase in 10 minutes? | {
"A": "20",
"B": "30",
"C": "15",
"D": "10",
"E": "80"
} | multiply(divide(const_60, 30), 10) | divide(const_60,n0)|multiply(n1,#0)| | "answer = 2 * 10 = 20 answer = a" | physics |
math_qa__eUhgTNfi5Z9gxPU0 | A meeting has to be conducted with 4 managers. Find the number of ways in which the managers be selected from among 7 managers, if 2 managers will not attend the meeting together? Choose the most appropriate option.
A) 25 B) 20 C) 35 D) 36 E) 38 | <gadget id="calculator">binomial(7, 4)</gadget>
<output>35</output>
<gadget id="calculator">7 - 2</gadget>
<output>5</output>
<gadget id="calculator">binomial(5, 2)</gadget>
<output>10</output>
<gadget id="calculator">35 - 10</gadget>
<output>25</output>
<result>A</result> | A | 25 | A meeting has to be conducted with 4 managers. Find the number of ways in which the managers be selected from among 7 managers, if 2 managers will not attend the meeting together? | {
"A": "25",
"B": "20",
"C": "35",
"D": "36",
"E": "38"
} | subtract(choose(7, 4), choose(subtract(7, 2), 2)) | choose(n1,n0)|subtract(n1,n2)|choose(#1,n2)|subtract(#0,#2)| | "we can either choose all 4 people from 5 manager who have no problems or choose 3 from the 5 and 1 from the 2 managers who have a problem sitting together so 5 c 4 + ( 5 c 3 * 2 c 1 ) this is 5 + 20 = 25 answer : a" | probability |
math_qa__DecEGjYS3XrSFqxY | Two trains each 150m in length each, are running on two parallel lines in opposite directions. If one goes at the speed of 95km/h while the other travels at 85km/h. how long will it take for them to pass each other completely. Options
A) 25 sec B) 23 sec C) 34 sec D) 22 sec E) 6 sec | <gadget id="calculator">150 + 150</gadget>
<output>300</output>
<gadget id="calculator">300 / 1_000</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">95 + 85</gadget>
<output>180</output>
<gadget id="calculator">(3/10) / 180</gadget>
<output>1/600 = around 0.001667</output>
<gadget id="calculator">3_600 * (1/600)</gadget>
<output>6</output>
<result>E</result> | E | 6 | Two trains each 150m in length each, are running on two parallel lines in opposite directions. If one goes at the speed of 95km/h while the other travels at 85km/h. how long will it take for them to pass each other completely. | {
"A": "25 sec",
"B": "23 sec",
"C": "34 sec",
"D": "22 sec",
"E": "6 sec"
} | multiply(const_3600, divide(divide(add(150, 150), const_1000), add(95, 85))) | add(n0,n0)|add(n1,n2)|divide(#0,const_1000)|divide(#2,#1)|multiply(#3,const_3600)| | "explanation : d = 150 m + 150 m = 300 m rs = 95 + 85 = 180 * 5 / 18 = 50 t = 300 * 1 / 50 = 6 sec answer : option e" | physics |
math_qa__BioXAe7DBiWnMaQo | P is 10% more efficient than Q. P can complete a work in 21 days. If P and Q work together, how many days will it take to complete the same work? Choices:
A) 7 B) 9 C) 11 D) 13 E) 15 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) * 21</gadget>
<output>231/10 = around 23.1</output>
<gadget id="calculator">(11/10) + 1</gadget>
<output>21/10 = around 2.1</output>
<gadget id="calculator">(231/10) / (21/10)</gadget>
<output>11</output>
<result>C</result> | C | 11 | P is 10% more efficient than Q. P can complete a work in 21 days. If P and Q work together, how many days will it take to complete the same work? | {
"A": "7",
"B": "9",
"C": "11",
"D": "13",
"E": "15"
} | divide(multiply(add(divide(10, const_100), const_1), 21), add(add(divide(10, const_100), const_1), const_1)) | divide(n0,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(n1,#1)|divide(#3,#2)| | "the work done by p in 1 day = 1 / 21 let work done by q in 1 day = q q × ( 110 / 100 ) = 1 / 21 q = 100 / ( 21 × 110 ) = 10 / ( 21 × 11 ) the work done by p and q in 1 day = 1 / 21 + 10 / ( 21 × 11 ) = 21 / ( 21 × 11 ) = 1 / 11 p and q together can do the work in 11 days . the answer is c ." | physics |
math_qa__r7ysqUO7YgOERUzv | A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 4% of bananas were rotten. Find the percentage of fruits in good condition? Choose the correct answer
A) 92.5 % B) 89.4 % C) 85.2 % D) 96.8 % E) 78.9 % | <gadget id="calculator">600 + 400</gadget>
<output>1_000</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">600 * (3/20)</gadget>
<output>90</output>
<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">400 * (1/25)</gadget>
<output>16</output>
<gadget id="calculator">90 + 16</gadget>
<output>106</output>
<gadget id="calculator">1_000 - 106</gadget>
<output>894</output>
<gadget id="calculator">894 / 1_000</gadget>
<output>447/500 = around 0.894</output>
<gadget id="calculator">(447/500) * 100</gadget>
<output>447/5 = around 89.4</output>
<result>B</result> | B | 89.4 | A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 4% of bananas were rotten. Find the percentage of fruits in good condition? | {
"A": "92.5 %",
"B": "89.4 %",
"C": "85.2 %",
"D": "96.8 %",
"E": "78.9 %"
} | multiply(divide(subtract(add(600, 400), add(multiply(600, divide(15, const_100)), multiply(400, divide(4, const_100)))), add(600, 400)), const_100) | add(n0,n1)|divide(n2,const_100)|divide(n3,const_100)|multiply(n0,#1)|multiply(n1,#2)|add(#3,#4)|subtract(#0,#5)|divide(#6,#0)|multiply(#7,const_100)| | "total number of fruits shopkeeper bought = 600 + 400 = 1000 number of rotten oranges = 15 % of 600 = 15 / 100 × 600 = 9000 / 100 = 90 number of rotten bananas = 4 % of 400 = 16 therefore , total number of rotten fruits = 90 + 16 = 106 therefore number of fruits in good condition = 1000 - 106 = 894 therefore percentage of fruits in good condition = ( 894 / 1000 × 100 ) % = ( 89400 / 1000 ) % = 89.4 % answer : b" | gain |
math_qa__53w323y8LYsA3ViJ | James took a 3-hour bike ride. In the second hour he travlled 18 miles, which was 20 percent farther than he traveled the first hour. If he traveled 25 percent farther in the third hour than he did in the second hour, how many miles did jose travel during the entire ride? Choose the correct choice from the following answers: A) 54.0 B) 54.9 C) 55.5 D) 57.0 E) 63.0 | <gadget id="calculator">1 * 100</gadget>
<output>100</output>
<gadget id="calculator">100 * 18</gadget>
<output>1_800</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">1_800 / 120</gadget>
<output>15</output>
<gadget id="calculator">25 * 18</gadget>
<output>450</output>
<gadget id="calculator">450 / 20</gadget>
<output>45/2 = around 22.5</output>
<gadget id="calculator">15 + (45/2)</gadget>
<output>75/2 = around 37.5</output>
<gadget id="calculator">(75/2) + 18</gadget>
<output>111/2 = around 55.5</output>
<result>C</result> | C | 55.5 | James took a 3-hour bike ride. In the second hour he travlled 18 miles, which was 20 percent farther than he traveled the first hour. If he traveled 25 percent farther in the third hour than he did in the second hour, how many miles did jose travel during the entire ride? | {
"A": "54.0",
"B": "54.9",
"C": "55.5",
"D": "57.0",
"E": "63.0"
} | add(add(divide(multiply(multiply(const_1, const_100), 18), add(multiply(const_1, const_100), 20)), divide(multiply(25, 18), 20)), 18) | multiply(const_1,const_100)|multiply(n1,n3)|add(n2,#0)|divide(#1,n2)|multiply(n1,#0)|divide(#4,#2)|add(#5,#3)|add(n1,#6) | let the distance travelled in the first hour be x . thus , 1.2 x = 18 , x = 15 . now , the distance travelled in the 3 rd hour = 18 + 1 / 4 ∗ 18 = the only option ending with a 0.5 in the decimal place is c . answer : c | physics |
math_qa__93oiRlTLCnjeCBOb | For my anniversary, I decided to surprise my wife. Since she is a voracious reader, I decided to collect a lot of books for her. On the first day of the month, I bought one book, on the second, I bought two and on the third, I bought three. This process went on till the anniversary and on the day, I had 190 books with me to gift her.
Can you calculate, on which day is our anniversary? Choose the correct choice from the following choices.
A) 31 B) 28 C) 19 D) 33 E) 25 | <gadget id="calculator">190 / 10</gadget>
<output>19</output>
<result>C</result> | C | 19 | For my anniversary, I decided to surprise my wife. Since she is a voracious reader, I decided to collect a lot of books for her. On the first day of the month, I bought one book, on the second, I bought two and on the third, I bought three. This process went on till the anniversary and on the day, I had 190 books with me to gift her.
Can you calculate, on which day is our anniversary? | {
"A": "31",
"B": "28",
"C": "19",
"D": "33",
"E": "25"
} | divide(190, const_10) | divide(n0,const_10) | c 19 rd day 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 = 190 thus our anniversary falls on the 19 rd day of the month . you can apply other formulas to shorten the process but that is the simplest way to do it . | physics |
math_qa__ZyBP0CfmS6K61suf | At a tanning salon, customers are charged $10 for their first visit in a calendar month and $3 for each visit after that in the same calendar month. In the last calendar month, 100 customers visited the salon, of which 30 made a second visit, and 10 made a third visit. All other customers made only one visit. If those visits were the only source of revenue for the salon, what was the revenue for the last calendar month at the salon? Choose the correct choice.
A) $ 1220 B) $ 1120 C) $ 1300 D) $ 1340 E) $ 1880 | <gadget id="calculator">10 + 3</gadget>
<output>13</output>
<gadget id="calculator">13 * 30</gadget>
<output>390</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 * 10</gadget>
<output>700</output>
<gadget id="calculator">390 + 700</gadget>
<output>1_090</output>
<result>B</result> | B | 1,120 | At a tanning salon, customers are charged $10 for their first visit in a calendar month and $3 for each visit after that in the same calendar month. In the last calendar month, 100 customers visited the salon, of which 30 made a second visit, and 10 made a third visit. All other customers made only one visit. If those visits were the only source of revenue for the salon, what was the revenue for the last calendar month at the salon? | {
"A": "$ 1220",
"B": "$ 1120",
"C": "$ 1300",
"D": "$ 1340",
"E": "$ 1880"
} | add(multiply(add(10, 3), 30), multiply(subtract(100, 30), 10)) | add(n0,n1)|subtract(n2,n3)|multiply(n3,#0)|multiply(n0,#1)|add(#2,#3)| | "i get b . this question seems too straightforward for 600 + . am i missing something ? 100 first - time visits - - > 100 ( 10 ) = $ 1000 30 + 10 = 40 subsequent visits - - > 40 ( 3 ) = $ 120 total revenue : 1000 + 120 = $ 1120 the answer is b ." | physics |
math_qa__2kxWcmDttb1oUHrm | There are 7 players in a bowling team with an average weight of 94 Kg. If two new players join the team, one weighs 110 Kg and the second weighs 60 Kg, what will be the new average weight? Choose the correct option:
A) 75 kg . B) 80 kg . C) 86 kg . D) 90 kg . E) 92 kg . | <gadget id="calculator">7 * 94</gadget>
<output>658</output>
<gadget id="calculator">110 + 60</gadget>
<output>170</output>
<gadget id="calculator">658 + 170</gadget>
<output>828</output>
<gadget id="calculator">7 + 2</gadget>
<output>9</output>
<gadget id="calculator">828 / 9</gadget>
<output>92</output>
<result>E</result> | E | 92 | There are 7 players in a bowling team with an average weight of 94 Kg. If two new players join the team, one weighs 110 Kg and the second weighs 60 Kg, what will be the new average weight? | {
"A": "75 kg .",
"B": "80 kg .",
"C": "86 kg .",
"D": "90 kg .",
"E": "92 kg ."
} | divide(add(multiply(7, 94), add(110, 60)), add(7, const_2)) | add(n2,n3)|add(n0,const_2)|multiply(n0,n1)|add(#0,#2)|divide(#3,#1)| | "the new average will be = ( 94 * 7 + 110 + 60 ) / 9 = 92 kgs e is the answer" | general |
math_qa__pStl3ARIxSbu1kiu | The average weight of 12 person's increases by 4 kg when a new person comes in place of one of them weighing 58 kg. What is the weight of the new person? Choose the correct choice from the following options.
A) 85 B) 80 C) 95 D) 90 E) 106 | <gadget id="calculator">12 * 4</gadget>
<output>48</output>
<gadget id="calculator">48 + 58</gadget>
<output>106</output>
<result>E</result> | E | 106 | The average weight of 12 person's increases by 4 kg when a new person comes in place of one of them weighing 58 kg. What is the weight of the new person? | {
"A": "85",
"B": "80",
"C": "95",
"D": "90",
"E": "106"
} | add(multiply(12, 4), 58) | multiply(n0,n1)|add(n2,#0)| | "total increase in weight = 12 × 4 = 48 if x is the weight of the new person , total increase in weight = x − 58 = > 48 = x - 58 = > x = 48 + 58 = 106 answer : e" | general |
math_qa__1cKKTnWfOC3lwXSA | 6) A marketing firm determined that , of 180 households surveyed, 80 used neither Brand A nor Brand B soap.60 used only Brand A soap and for every household that used both brands of soap, 3 used only brand B soap.how many of the 200 household surveyed used both brands of soap? Select: A) 15 B) 20 C) 30 D) 10 E) 45 | <gadget id="calculator">180 - 80</gadget>
<output>100</output>
<gadget id="calculator">100 - 60</gadget>
<output>40</output>
<gadget id="calculator">40 / 4</gadget>
<output>10</output>
<result>D</result> | D | 10 | 6) A marketing firm determined that , of 180 households surveyed, 80 used neither Brand A nor Brand B soap.60 used only Brand A soap and for every household that used both brands of soap, 3 used only brand B soap.how many of the 200 household surveyed used both brands of soap? | {
"A": "15",
"B": "20",
"C": "30",
"D": "10",
"E": "45"
} | divide(subtract(subtract(180, 80), 60), const_4) | subtract(n1,n2)|subtract(#0,n3)|divide(#1,const_4) | 100 = at least one of soap a or b both brands = x brand b = 3 x = > 60 + x + 3 x = 100 = > 4 x = 40 = > x = 10 answer - d | other |
math_qa__D3MqBJgY9PK6sa7L | One machine takes 3 minutes to check fault in 100 km fiber optic cable.Another machine does the same job in 3 seconds.What time will it take to do the same job when both machines are put to work? Choose the most appropriate option.
A) 2.00 seconds B) 2.20 seconds C) 2.50 seconds D) 2.95 seconds E) 3.00 seconds | <gadget id="calculator">3 * 60</gadget>
<output>180</output>
<gadget id="calculator">1 / 180</gadget>
<output>1/180 = around 0.005556</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/180) + (1/3)</gadget>
<output>61/180 = around 0.338889</output>
<gadget id="calculator">1 / (61/180)</gadget>
<output>180/61 = around 2.95082</output>
<result>D</result> | D | 2.95 | One machine takes 3 minutes to check fault in 100 km fiber optic cable.Another machine does the same job in 3 seconds.What time will it take to do the same job when both machines are put to work? | {
"A": "2.00 seconds",
"B": "2.20 seconds",
"C": "2.50 seconds",
"D": "2.95 seconds",
"E": "3.00 seconds"
} | inverse(add(inverse(multiply(3, const_60)), inverse(3))) | inverse(n0)|multiply(n0,const_60)|inverse(#1)|add(#2,#0)|inverse(#3) | by guess it is clear that the time taken will be less than 3 seconds and very near to it . therefore , answer 2.95 seconds will be correct . answer - d | physics |
math_qa__TU62M0nOtDvqv6Ey | A certain telescope increases the visual range at a particular location from 60 kilometers to 150 kilometers. By what percent is the visual range increased by using the telescope ? Answers.
A) 30 %
B) 33 1 / 2 %
C) 40 %
D) 60 %
E) 150 % | <gadget id="calculator">150 - 60</gadget>
<output>90</output>
<gadget id="calculator">90 / 60</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 100</gadget>
<output>150</output>
<result>E</result> | E | 150 | A certain telescope increases the visual range at a particular location from 60 kilometers to 150 kilometers. By what percent is the visual range increased by using the telescope ? | {
"A": "30 %",
"B": "33 1 / 2 %",
"C": "40 %",
"D": "60 %",
"E": "150 %"
} | multiply(divide(subtract(150, 60), 60), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "original visual range = 60 km new visual range = 150 km percent increase in the visual range by using the telescope = ( 150 - 60 ) / 60 * 100 % = 3 / 2 * 100 % = 150 % answer e" | general |
math_qa__vCsUgEFGxKDv1nLr | A small company reduced its faculty by approximately 13 percent to 181 employees. What was the original number of employees?
Choose the correct answer: A) 182 B) 208 C) 220 D) 224 E) 302 | <gadget id="calculator">100 - 13</gadget>
<output>87</output>
<gadget id="calculator">87 / 100</gadget>
<output>87/100 = around 0.87</output>
<gadget id="calculator">181 / (87/100)</gadget>
<output>18_100/87 = around 208.045977</output>
<result>B</result> | B | 208 | A small company reduced its faculty by approximately 13 percent to 181 employees. What was the original number of employees? | {
"A": "182",
"B": "208",
"C": "220",
"D": "224",
"E": "302"
} | divide(181, divide(subtract(const_100, 13), const_100)) | subtract(const_100,n0)|divide(#0,const_100)|divide(n1,#1)| | "if x is the original number of employees , then after 13 % reduction in employees number is . 87 x but we are given . 87 x = 181 x = 208 so the original number of employees is 208 correct answer - b" | gain |
math_qa__mwbbrUNEOKtVJZno | 66 small identical cubes are used to form a large cube. How many more cubes are needed to add one top layer of small cube all over the surface of the large cube ?
Select the correct option
A) 64 B) 150 C) 152 D) 216 E) 256 | <gadget id="calculator">66 ** (1/3)</gadget>
<output>66**(1/3) = around 4.04124</output>
<gadget id="calculator">(66**(1/3)) + 2</gadget>
<output>2 + 66**(1/3) = around 6.04124</output>
<gadget id="calculator">(2 + 66**(1/3)) ** 3</gadget>
<output>(2 + 66**(1/3))**3 = around 220.484606</output>
<gadget id="calculator">((2 + 66**(1/3))**3) - 66</gadget>
<output>-66 + (2 + 66**(1/3))**3 = around 154.484606</output>
<result>B</result> | B | 150 | 66 small identical cubes are used to form a large cube. How many more cubes are needed to add one top layer of small cube all over the surface of the large cube ? | {
"A": "64",
"B": "150",
"C": "152",
"D": "216",
"E": "256"
} | subtract(volume_cube(add(cube_edge_by_volume(66), const_2)), 66) | cube_edge_by_volume(n0)|add(#0,const_2)|volume_cube(#1)|subtract(#2,n0)| | "66 small cube will make a large cube with 4 cubes in each line i . e . adding one layer will require one cube at each end and hence new cube will have 6 cubes in each line . total number of small cubes in new cube = 6 ^ 3 = 216 extra cube required = 216 - 66 = 150 hence , b is the answer ." | geometry |
math_qa__5u5Kj55bSRceubnc | 0.9*0.007= _________ Choose the most appropriate option.
A) 0.063
B) 0.0063
C) 0.63
D) 0.00063
E) 63 | <gadget id="calculator">0.9 * 0.007</gadget>
<output>0.0063</output>
<result>B</result> | B | 0.0063 | 0.9*0.007= _________ | {
"A": "0.063",
"B": "0.0063",
"C": "0.63",
"D": "0.00063",
"E": "63"
} | multiply(0.9, 0.007) | multiply(n0,n1) | 9 * 7 = 63 sum of decimal places = 4 so , 0.9 * 0.007 = 0.0063 answer : b | general |
math_qa__B5q8FxkQ4jNh87iD | The length of a rectangular garden is three times its width. If the area of the rectangular garden is 768 square meters, then what is the width of the rectangular garden?
Options: A) 16 B) 17 C) 18 D) 19 E) 20 | <gadget id="calculator">768 / 3</gadget>
<output>256</output>
<gadget id="calculator">256 ** (1/2)</gadget>
<output>16</output>
<result>A</result> | A | 16 | The length of a rectangular garden is three times its width. If the area of the rectangular garden is 768 square meters, then what is the width of the rectangular garden? | {
"A": "16",
"B": "17",
"C": "18",
"D": "19",
"E": "20"
} | sqrt(divide(768, const_3)) | divide(n0,const_3)|sqrt(#0)| | "let x be the width of the garden . 3 x ^ 2 = 768 x ^ 2 = 256 x = 16 the answer is a ." | geometry |
math_qa__Kmd5i2rOXDpx4ufO | Mr. Hernandez, who was a resident of State X for only 9 months last year, had a taxable income of $42,500 for the year. If the state tax rate were 4 percent of the year’s taxable income prorated for the proportion of the year during which the taxpayer was a resident, what would be the amount of Mr. Hernandez’s State X tax for last year?
Pick one.
A) $ 900 B) $ 1275 C) $ 1200 D) $ 1300 E) $ 1060 | <gadget id="calculator">4 * 100</gadget>
<output>400</output>
<gadget id="calculator">400 * 100</gadget>
<output>40_000</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">100 * (1/4)</gadget>
<output>25</output>
<gadget id="calculator">25 * 100</gadget>
<output>2_500</output>
<gadget id="calculator">40_000 + 2_500</gadget>
<output>42_500</output>
<gadget id="calculator">42_500 / 100</gadget>
<output>425</output>
<gadget id="calculator">425 * 4</gadget>
<output>1_700</output>
<gadget id="calculator">1_700 * 9</gadget>
<output>15_300</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">15_300 / 12</gadget>
<output>1_275</output>
<result>B</result> | B | 1,275 | Mr. Hernandez, who was a resident of State X for only 9 months last year, had a taxable income of $42,500 for the year. If the state tax rate were 4 percent of the year’s taxable income prorated for the proportion of the year during which the taxpayer was a resident, what would be the amount of Mr. Hernandez’s State X tax for last year? | {
"A": "$ 900",
"B": "$ 1275",
"C": "$ 1200",
"D": "$ 1300",
"E": "$ 1060"
} | divide(multiply(multiply(divide(add(multiply(multiply(4, const_100), const_100), multiply(multiply(const_100, const_0_25), const_100)), const_100), const_4), 9), multiply(const_3, const_4)) | multiply(n2,const_100)|multiply(const_0_25,const_100)|multiply(const_3,const_4)|multiply(#0,const_100)|multiply(#1,const_100)|add(#3,#4)|divide(#5,const_100)|multiply(#6,const_4)|multiply(n0,#7)|divide(#8,#2) | total tax for the year = 42,500 x 4 % = 1700 as stated annual tax is prorated as per the duration of stay . prorated tax = 1700 ( 9 / 12 ) = 1275 answer b | gain |
math_qa__gdMLyOLNjv5KIRC6 | If a man lost 10% by selling oranges at the rate of 10 a rupee at how many a rupee must he sell them to gain 50%? Choose the correct choice: A) 6 B) 8 C) 7 D) 4 E) 2 | <gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 * 10</gadget>
<output>900</output>
<gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">900 / 150</gadget>
<output>6</output>
<result>A</result> | A | 6 | If a man lost 10% by selling oranges at the rate of 10 a rupee at how many a rupee must he sell them to gain 50%? | {
"A": "6",
"B": "8",
"C": "7",
"D": "4",
"E": "2"
} | divide(multiply(subtract(const_100, 10), 10), add(const_100, 50)) | add(n2,const_100)|subtract(const_100,n0)|multiply(n1,#1)|divide(#2,#0)| | "90 % - - - - 10 150 % - - - - ? 90 / 150 * 10 = 6 answer : a" | gain |
math_qa__JKvfSZd6ozjP3Hff | A candidate appearing for an examination has to secure 42% marks to pass paper I. But he secured only 42 marks and failed by 22 marks. What is the maximum mark for paper I? Choices:
A) 110
B) 120
C) 130
D) 152
E) 150 | <gadget id="calculator">42 + 22</gadget>
<output>64</output>
<gadget id="calculator">42 / 100</gadget>
<output>21/50 = around 0.42</output>
<gadget id="calculator">64 / (21/50)</gadget>
<output>3_200/21 = around 152.380952</output>
<result>D</result> | D | 152 | A candidate appearing for an examination has to secure 42% marks to pass paper I. But he secured only 42 marks and failed by 22 marks. What is the maximum mark for paper I? | {
"A": "110",
"B": "120",
"C": "130",
"D": "152",
"E": "150"
} | divide(add(42, 22), divide(42, const_100)) | add(n1,n2)|divide(n0,const_100)|divide(#0,#1)| | "he secured 42 marks nd fail by 22 marks so total marks for pass the examinatn = 64 let toal marks x x * 42 / 100 = 64 x = 152 answer : d" | gain |
math_qa__KnBvcSBQifHMkNZk | If (-3)^(2x) = 3^(12 - x) and x is an integer, what is the value of x ?
Choices.
A) 5 B) 4 C) 3 D) 2 E) 1 | <gadget id="calculator">12 / 3</gadget>
<output>4</output>
<result>B</result> | B | 4 | If (-3)^(2x) = 3^(12 - x) and x is an integer, what is the value of x ? | {
"A": "5",
"B": "4",
"C": "3",
"D": "2",
"E": "1"
} | divide(12, 3) | divide(n3,n0) | since x is an integer , ( - 3 ) ^ ( 2 x ) is always positive . so , 3 ^ 2 x = 3 ^ ( 12 - x ) 2 x = 12 - x 3 x = 12 x = 4 answer : b | general |
math_qa__5nz5TyALhTqXZF04 | In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, what is the dividend ? Choices:
A) 5336 B) 5242 C) 6524 D) 3526 E) 4526 | <gadget id="calculator">5 * 46</gadget>
<output>230</output>
<gadget id="calculator">230 / 10</gadget>
<output>23</output>
<gadget id="calculator">230 * 23</gadget>
<output>5_290</output>
<result>A</result> | A | 5,336 | In a division sum, the divisor is 10 times the quotient and 5 times the remainder. If the remainder is 46, what is the dividend ? | {
"A": "5336",
"B": "5242",
"C": "6524",
"D": "3526",
"E": "4526"
} | multiply(multiply(5, 46), divide(multiply(5, 46), 10)) | multiply(n1,n2)|divide(#0,n0)|multiply(#1,#0)| | "divisor = ( 5 * 46 ) = 230 10 * quotient = 230 quotient = 230 / 10 = 23 . dividend = ( divisor * quotient ) + remainder = ( 230 * 23 ) + 46 = ( 5290 + 46 ) = 5336 . answer is a" | general |
math_qa__SIuMCnakrrmLdyVh | Find the perimeter and area of a square of side 11 cm. Select:
A) 11 cm ² B) 21 cm ² C) 22 cm ² D) 113 cm ² E) 121 cm ² | <gadget id="calculator">11 ** 2</gadget>
<output>121</output>
<result>E</result> | E | 121 | Find the perimeter and area of a square of side 11 cm. | {
"A": "11 cm ²",
"B": "21 cm ²",
"C": "22 cm ²",
"D": "113 cm ²",
"E": "121 cm ²"
} | square_area(11) | square_area(n0)| | "we know that the perimeter of square = 4 × side side = 11 cm therefore , perimeter = 4 × 11 cm = 44 cm now , area of the square = ( side × side ) sq . units = 11 × 11 cm ² = 121 cm ² answer : option e" | geometry |
math_qa__JJuvKRraZIncRSqe | A company plans to gradually replace its fleet of 20 cars with newer models. At the end of every year starting with 2000 it retires 5 of its old cars and buys 6 new models.How many years did it take before the number of older cars left in the company's fleet was less than 50 percent of the fleet? Select.
A) 6 B) 3 C) 2 D) 4 E) 5 | <gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">20 / 11</gadget>
<output>20/11 = around 1.818182</output>
<gadget id="calculator">(20/11) + 1</gadget>
<output>31/11 = around 2.818182</output>
<gadget id="calculator">floor(31/11)</gadget>
<output>2</output>
<result>C</result> | C | 2 | A company plans to gradually replace its fleet of 20 cars with newer models. At the end of every year starting with 2000 it retires 5 of its old cars and buys 6 new models.How many years did it take before the number of older cars left in the company's fleet was less than 50 percent of the fleet? | {
"A": "6",
"B": "3",
"C": "2",
"D": "4",
"E": "5"
} | floor(add(divide(20, add(const_10, const_1)), const_1)) | add(const_1,const_10)|divide(n0,#0)|add(#1,const_1)|floor(#2) | total fleet - - 20 end of year 2000 - - ( retires 5 and buys 6 ) total fleet - - 21 ( 15 old 6 new ) . end of year 2001 - - ( retires 5 and buys 6 ) total fleet - - 22 ( 10 old 12 new ) . answer is c - - after 2 years the company has a total of 22 cars ( 10 old 12 new ) , the old cars are already less than 50 % of its fleet . | gain |
math_qa__nHybn8tx0NYvFKhz | The ratio of radius of a circle and the side of a square is 2 : 3. Find the ratio of their areas: Answers.
A) 2 : 1 B) 4 : 9 C) 8 : 77 D) 4 : 121 E) none | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) ** 2</gadget>
<output>4/9 = around 0.444444</output>
<result>B</result> | B | 0.444444 | The ratio of radius of a circle and the side of a square is 2 : 3. Find the ratio of their areas: | {
"A": "2 : 1",
"B": "4 : 9",
"C": "8 : 77",
"D": "4 : 121",
"E": "none"
} | power(divide(2, 3), 2) | divide(n0,n1)|power(#0,n0)| | "radius / side = 2 / 3 â ‡ ’ area of circle / area of square = 4 / 9 answer : b" | geometry |
math_qa__akVwOjude2GNhfSC | Find the compound interest on $500 in 5years at 5% per annum, the interest being compounded yearly? Choose the correct choice from the following answers
A) $ 138.14 B) $ 150.12 C) $ 142.65 D) $ 152 E) $ 164.12 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 5</gadget>
<output>4_084_101/3_200_000 = around 1.276282</output>
<gadget id="calculator">500 * (4_084_101/3_200_000)</gadget>
<output>4_084_101/6_400 = around 638.140781</output>
<gadget id="calculator">(4_084_101/6_400) - 500</gadget>
<output>884_101/6_400 = around 138.140781</output>
<result>A</result> | A | 138.14 | Find the compound interest on $500 in 5years at 5% per annum, the interest being compounded yearly? | {
"A": "$ 138.14",
"B": "$ 150.12",
"C": "$ 142.65",
"D": "$ 152",
"E": "$ 164.12"
} | subtract(multiply(500, power(add(const_1, divide(5, const_100)), 5)), 500) | divide(n2,const_100)|add(#0,const_1)|power(#1,n1)|multiply(n0,#2)|subtract(#3,n0)| | "principle = $ 500 rate = 5 % yearly amount = 500 * ( 1 + 5 / 100 ) ^ 5 = 500 * 21 / 20 * 21 / 20 * 21 / 20 * 21 / 20 * 21 / 20 = $ 638.14 c . i . = 638.14 - 500 = $ 138.14 answer is a" | gain |
math_qa__zXs2eb6Xwym1hePr | The sum of two numbers is 45. Their difference is 5. The bigger number is Choose the correct choice from the following options
A) 20
B) 25
C) 30
D) 35
E) 45 | <gadget id="calculator">45 + 5</gadget>
<output>50</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<result>B</result> | B | 25 | The sum of two numbers is 45. Their difference is 5. The bigger number is | {
"A": "20",
"B": "25",
"C": "30",
"D": "35",
"E": "45"
} | divide(add(45, 5), const_2) | add(n0,n1)|divide(#0,const_2) | x + y = 45 x - y = 5 adding 2 x = 50 = = > x = 25 and y = 45 - 25 = 20 bigger number is x = 25 answer b . | general |
math_qa__cWgX05NAkZpmZowz | The present worth of Rs.338 due in 2 years at 4% per annum compound interest is Choose the correct option:
A) rs . 312.5
B) rs . 154.75
C) rs . 156.25
D) rs . 158
E) none | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) + 1</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) ** 2</gadget>
<output>676/625 = around 1.0816</output>
<gadget id="calculator">338 / (676/625)</gadget>
<output>625/2 = around 312.5</output>
<result>A</result> | A | 312.5 | The present worth of Rs.338 due in 2 years at 4% per annum compound interest is | {
"A": "rs . 312.5",
"B": "rs . 154.75",
"C": "rs . 156.25",
"D": "rs . 158",
"E": "none"
} | divide(338, power(add(divide(4, const_100), const_1), 2)) | divide(n2,const_100)|add(#0,const_1)|power(#1,n1)|divide(n0,#2)| | "solution present worth = rs . [ 338 / ( 1 + 4 / 100 ) ² ] = rs . ( 338 x 25 / 26 x 25 / 26 ) = rs . 312.5 answer a" | gain |
math_qa__u09eaXaN4cGOhq5R | The average of 6 observations is 11. A new observation is included and the new average is decreased by 1. The seventh observation is? Select the correct option:
A) 4
B) 3
C) 5
D) 6
E) 7 | <gadget id="calculator">11 - 1</gadget>
<output>10</output>
<gadget id="calculator">6 + 1</gadget>
<output>7</output>
<gadget id="calculator">10 * 7</gadget>
<output>70</output>
<gadget id="calculator">11 * 6</gadget>
<output>66</output>
<gadget id="calculator">70 - 66</gadget>
<output>4</output>
<result>A</result> | A | 4 | The average of 6 observations is 11. A new observation is included and the new average is decreased by 1. The seventh observation is? | {
"A": "4",
"B": "3",
"C": "5",
"D": "6",
"E": "7"
} | subtract(multiply(subtract(11, 1), add(6, 1)), multiply(11, 6)) | add(n0,n2)|multiply(n0,n1)|subtract(n1,n2)|multiply(#0,#2)|subtract(#3,#1)| | "let seventh observation = x . then , according to the question we have = > ( 66 + x ) / 7 = 10 = > x = 4 . hence , the seventh observation is 4 . answer : a" | general |
math_qa__QawJbaNyVbpL31XU | A company wants to spend equal amounts of money for the purchase of two types of computer printers costing $350 and $200 per unit, respectively. What is the fewest number of computer printers that the company can purchase? Select the correct option:
A) 9 B) 10 C) 11 D) 12 E) 13 | <gadget id="calculator">lcm(350, 200)</gadget>
<output>1_400</output>
<gadget id="calculator">1_400 / 350</gadget>
<output>4</output>
<gadget id="calculator">1_400 / 200</gadget>
<output>7</output>
<gadget id="calculator">4 + 7</gadget>
<output>11</output>
<result>C</result> | C | 11 | A company wants to spend equal amounts of money for the purchase of two types of computer printers costing $350 and $200 per unit, respectively. What is the fewest number of computer printers that the company can purchase? | {
"A": "9",
"B": "10",
"C": "11",
"D": "12",
"E": "13"
} | add(divide(lcm(350, 200), 350), divide(lcm(350, 200), 200)) | lcm(n0,n1)|divide(#0,n0)|divide(#0,n1)|add(#1,#2)| | "the smallest amount that the company can spend is the lcm of 350 and 200 , which is 1400 for each , which is total 2800 . the number of 1 st type of computers which costing $ 350 = 1400 / 350 = 4 . the number of 2 nd type of computers which costing $ 200 = 1400 / 200 = 7 . total = 4 + 7 = 11 answer is c ." | general |
math_qa__7G38dm1MIKpUfeVf | If the height of a cone is increased by 120% then its volume is increased by? Choices: A) 100 B) 777 C) 998 D) 729 E) 120 | <gadget id="calculator">120 * 1</gadget>
<output>120</output>
<result>E</result> | E | 120 | If the height of a cone is increased by 120% then its volume is increased by? | {
"A": "100",
"B": "777",
"C": "998",
"D": "729",
"E": "120"
} | rectangle_area(120, const_1) | rectangle_area(n0,const_1)| | "120 % answer : e" | geometry |
math_qa__eSslHHbDMd3ZoEP7 | After decreasing 40% in the price of an article costs Rs.1050. Find the actual cost of an article? Choose the correct option:
A) 1200 B) 1750 C) 1050 D) 1570 E) 1005 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1_050 / (3/5)</gadget>
<output>1_750</output>
<result>B</result> | B | 1,750 | After decreasing 40% in the price of an article costs Rs.1050. Find the actual cost of an article? | {
"A": "1200",
"B": "1750",
"C": "1050",
"D": "1570",
"E": "1005"
} | divide(1050, subtract(const_1, divide(40, const_100))) | divide(n0,const_100)|subtract(const_1,#0)|divide(n1,#1)| | "cp * ( 60 / 100 ) = 1050 cp = 17.5 * 100 = > cp = 1750 answer : b" | gain |
math_qa__jX0xcBrAG2U5Fd2P | A fair sided dice labeled 1 to 6 is tossed 2 times. What is the probability the sum of the 2 throws is 5? Choose the correct choice from the following choices: A) 1 / 6 B) 7 / 216 C) 4 / 36 D) 9 / 216 E) 11 / 216 | <gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">4 / 36</gadget>
<output>1/9 = around 0.111111</output>
<result>C</result> | C | 0.111111 | A fair sided dice labeled 1 to 6 is tossed 2 times. What is the probability the sum of the 2 throws is 5? | {
"A": "1 / 6",
"B": "7 / 216",
"C": "4 / 36",
"D": "9 / 216",
"E": "11 / 216"
} | divide(subtract(5, const_1), power(6, 2)) | power(n1,n2)|subtract(n4,const_1)|divide(#1,#0) | the total possible number of combination if the dice is thrown 2 times is 36 . there are 4 possible outcomes that the sum of the number is 5 which is ( 2 + 3 ) ( 3 + 2 ) ( 1 + 4 ) and ( 4 + 1 ) answer : c | general |
math_qa__6a4eylLJBs2Ne38G | A merchant marks his goods up by 50% and then offers a discount of 10% on the marked price. What % profit does the merchant make after the discount?
Choose one:
A) 21 % B) 25 % C) 69 % D) 35 % E) 19 % | <gadget id="calculator">50 + 100</gadget>
<output>150</output>
<gadget id="calculator">150 * 10</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 / 100</gadget>
<output>15</output>
<gadget id="calculator">150 - 15</gadget>
<output>135</output>
<gadget id="calculator">135 - 100</gadget>
<output>35</output>
<result>D</result> | D | 35 | A merchant marks his goods up by 50% and then offers a discount of 10% on the marked price. What % profit does the merchant make after the discount? | {
"A": "21 %",
"B": "25 %",
"C": "69 %",
"D": "35 %",
"E": "19 %"
} | subtract(subtract(add(50, const_100), divide(multiply(add(50, const_100), 10), const_100)), const_100) | add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|subtract(#0,#2)|subtract(#3,const_100)| | "let the price be 100 . the price becomes 150 after a 50 % markup . now a discount of 10 % on 150 . profit = 135 - 100 35 % answer d" | gain |
math_qa__k9VgU8rqH5pPL25V | I bought two books; for Rs.460. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss? Answers.
A) 337.33 B) 280.33 C) 299.33 D) 268.33 E) 289.33 | <gadget id="calculator">100 + 19</gadget>
<output>119</output>
<gadget id="calculator">460 * 119</gadget>
<output>54_740</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 + 119</gadget>
<output>204</output>
<gadget id="calculator">54_740 / 204</gadget>
<output>805/3 = around 268.333333</output>
<result>D</result> | D | 268.33 | I bought two books; for Rs.460. I sold one at a loss of 15% and other at a gain of 19% and then I found each book was sold at the same price. Find the cost of the book sold at a loss? | {
"A": "337.33",
"B": "280.33",
"C": "299.33",
"D": "268.33",
"E": "289.33"
} | divide(multiply(460, add(const_100, 19)), add(subtract(const_100, 15), add(const_100, 19))) | add(n2,const_100)|subtract(const_100,n1)|add(#0,#1)|multiply(n0,#0)|divide(#3,#2)| | "x * ( 85 / 100 ) = ( 460 - x ) 119 / 100 x = 280 answer : d" | gain |
math_qa__LdVvLBezeHUUuxK8 | In how many years will a sum of money doubles itself at 5% per annum simple interest Choose the correct choice
A) 25 years B) 28 years C) 10 years D) 20 years E) 21 years | <gadget id="calculator">100 / 5</gadget>
<output>20</output>
<result>D</result> | D | 20 | In how many years will a sum of money doubles itself at 5% per annum simple interest | {
"A": "25 years",
"B": "28 years",
"C": "10 years",
"D": "20 years",
"E": "21 years"
} | divide(const_100, 5) | divide(const_100,n0)| | "let the initial sum be x then , amount = 2 x ( because sum will be double ) amount = principal + s . i 2 x = x + s . i s . i = x s . i = ( p * r * t ) / 100 x = ( x * 5 * t ) / 100 therefore , t = 20 years answer : d" | gain |
math_qa__rNGkKeYY6FGWGfIM | In a race where 8 cars are running, the chance that car X will win is 1/2, that Y will win is 1/4 and that Z will win is 1/3. Assuming that a dead heat is impossible, find the chance that one of them will win.
Choose the correct choice from the following answers.
A) 1 / 140 B) 11 / 12 C) 14 / 8 D) 13 / 12 E) 57 / 120 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/2) + (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(3/4) + (1/3)</gadget>
<output>13/12 = around 1.083333</output>
<result>D</result> | D | 1.083333 | In a race where 8 cars are running, the chance that car X will win is 1/2, that Y will win is 1/4 and that Z will win is 1/3. Assuming that a dead heat is impossible, find the chance that one of them will win. | {
"A": "1 / 140",
"B": "11 / 12",
"C": "14 / 8",
"D": "13 / 12",
"E": "57 / 120"
} | add(add(divide(1, 2), divide(1, 4)), divide(1, 3)) | divide(n1,n2)|divide(n1,n4)|divide(n1,n6)|add(#0,#1)|add(#3,#2) | required probability = p ( x ) + p ( y ) + p ( z ) ( all the events are mutually exclusive ) . = 1 / 2 + 1 / 4 + 1 / 3 = 13 / 12 answer : d | general |
math_qa__dqOuFFC6vG6T380X | At a tanning salon, customers are charged $10 for their first visit in a calendar month and $4 for each visit after that in the same calendar month. In the last calendar month, 100 customers visited the salon, of which 30 made a second visit, and 10 made a third visit. All other customers made only one visit. If those visits were the only source of revenue for the salon, what was the revenue for the last calendar month at the salon? Choose the correct choice from the following choices
A) $ 1220 B) $ 1160 C) $ 1300 D) $ 1340 E) $ 1880 | <gadget id="calculator">10 + 4</gadget>
<output>14</output>
<gadget id="calculator">14 * 30</gadget>
<output>420</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 * 10</gadget>
<output>700</output>
<gadget id="calculator">420 + 700</gadget>
<output>1_120</output>
<result>B</result> | B | 1,160 | At a tanning salon, customers are charged $10 for their first visit in a calendar month and $4 for each visit after that in the same calendar month. In the last calendar month, 100 customers visited the salon, of which 30 made a second visit, and 10 made a third visit. All other customers made only one visit. If those visits were the only source of revenue for the salon, what was the revenue for the last calendar month at the salon? | {
"A": "$ 1220",
"B": "$ 1160",
"C": "$ 1300",
"D": "$ 1340",
"E": "$ 1880"
} | add(multiply(add(10, 4), 30), multiply(subtract(100, 30), 10)) | add(n0,n1)|subtract(n2,n3)|multiply(n3,#0)|multiply(n0,#1)|add(#2,#3)| | "i get b . this question seems too straightforward for 600 + . am i missing something ? 100 first - time visits - - > 100 ( 10 ) = $ 1000 30 + 10 = 40 subsequent visits - - > 40 ( 4 ) = $ 160 total revenue : 1000 + 160 = $ 1160 the answer is b ." | physics |
math_qa__MEIF67G6AWaJjZg5 | 3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day should 4 pumps work in order to empty the tank in 1 day? Pick:
A) 10
B) 12
C) 8
D) 15
E) 18 | <gadget id="calculator">3 * 8</gadget>
<output>24</output>
<gadget id="calculator">24 * 2</gadget>
<output>48</output>
<gadget id="calculator">48 / 4</gadget>
<output>12</output>
<result>B</result> | B | 12 | 3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day should 4 pumps work in order to empty the tank in 1 day? | {
"A": "10",
"B": "12",
"C": "8",
"D": "15",
"E": "18"
} | divide(multiply(multiply(3, 8), 2), 4) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,n3)| | "explanation : let the required hours needed be x more pumps , less hours ( indirect proportion ) more days , less hours ( indirect proportion ) hence we can write as ( pumps ) 3 : 4 ( days ) 2 : 1 } : : x : 8 ⇒ 3 × 2 × 8 = 4 × 1 × x ⇒ 3 × 2 × 2 = x ⇒ x = 12 answer : option b" | physics |
math_qa__jHeFjc8vZiVy3HbX | In what ratio must rice of Rs.54per kg be mixed with rice of Rs.35 per kg so that cost of mixture is Rs.42 per kg? Choose the correct answer: A) 9 : 7 B) 7 : 12 C) 12 : 7 D) 5 : 6 E) 7 : 9 | <gadget id="calculator">42 - 35</gadget>
<output>7</output>
<gadget id="calculator">54 - 35</gadget>
<output>19</output>
<gadget id="calculator">7 / 19</gadget>
<output>7/19 = around 0.368421</output>
<gadget id="calculator">1 - (7/19)</gadget>
<output>12/19 = around 0.631579</output>
<gadget id="calculator">(7/19) / (12/19)</gadget>
<output>7/12 = around 0.583333</output>
<result>B</result> | B | 0.583333 | In what ratio must rice of Rs.54per kg be mixed with rice of Rs.35 per kg so that cost of mixture is Rs.42 per kg? | {
"A": "9 : 7",
"B": "7 : 12",
"C": "12 : 7",
"D": "5 : 6",
"E": "7 : 9"
} | divide(divide(subtract(42, 35), subtract(54, 35)), subtract(const_1, divide(subtract(42, 35), subtract(54, 35)))) | subtract(n2,n1)|subtract(n0,n1)|divide(#0,#1)|subtract(const_1,#2)|divide(#2,#3) | ( 42 - 35 ) / ( 54 - 42 ) = 7 / 12 = 7 : 12 answer : b | other |
math_qa__Pw46ti04u3ZqHzeB | The sum of the numbers is 264. If the first number be twice the second and third number be one-third of the first, then the second number is: Select the correct option:
A) 48
B) 54
C) 72
D) 84
E) 27 | <gadget id="calculator">264 * 3</gadget>
<output>792</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">792 / 11</gadget>
<output>72</output>
<result>C</result> | C | 72 | The sum of the numbers is 264. If the first number be twice the second and third number be one-third of the first, then the second number is: | {
"A": "48",
"B": "54",
"C": "72",
"D": "84",
"E": "27"
} | divide(multiply(264, const_3), add(const_10, const_1)) | add(const_1,const_10)|multiply(n0,const_3)|divide(#1,#0) | let the second number be x . then , first number = 2 x and third number = 2 x / 3 . 2 x + x + 2 x / 3 = 264 11 x / 3 = 264 x = 72 answer : c | general |
math_qa__4NyugGdP0FseuepC | nd the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 12 cm? Select.
A) 243 cm 2
B) 239 cm 2
C) 267 cm 2
D) 230 cm 2
E) 228 cm 2 | <gadget id="calculator">20 + 18</gadget>
<output>38</output>
<gadget id="calculator">12 * 38</gadget>
<output>456</output>
<gadget id="calculator">456 / 2</gadget>
<output>228</output>
<result>E</result> | E | 228 | nd the area of trapezium whose parallel sides are 20 cm and 18 cm long, and the distance between them is 12 cm? | {
"A": "243 cm 2",
"B": "239 cm 2",
"C": "267 cm 2",
"D": "230 cm 2",
"E": "228 cm 2"
} | divide(multiply(12, add(20, 18)), const_2) | add(n0,n1)|multiply(n2,#0)|divide(#1,const_2)| | "area of a trapezium = 1 / 2 ( sum of parallel sides ) * ( perpendicular distance between them ) = 1 / 2 ( 20 + 18 ) * ( 12 ) = 228 cm 2 answer : e" | physics |
math_qa__FUMOCc3bcGn5YBYg | A digital wristwatch was set accurately at 8.30 a.m and then lost 2 seconds every 5 minutes. What time was indicated on the watch at 6.30 p.m of the same day if the watch operated continuously that time ? Pick one:
A) 5.56 B) 5.58 C) 6.0 D) 6.23 E) 6.26 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 + 6.3</gadget>
<output>18.3</output>
<gadget id="calculator">18.3 - 8.3</gadget>
<output>10</output>
<gadget id="calculator">10 * 60</gadget>
<output>600</output>
<gadget id="calculator">600 / 5</gadget>
<output>120</output>
<gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">240 / 60</gadget>
<output>4</output>
<gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">6.3 - (1/25)</gadget>
<output>6.26</output>
<result>E</result> | E | 6.26 | A digital wristwatch was set accurately at 8.30 a.m and then lost 2 seconds every 5 minutes. What time was indicated on the watch at 6.30 p.m of the same day if the watch operated continuously that time ? | {
"A": "5.56",
"B": "5.58",
"C": "6.0",
"D": "6.23",
"E": "6.26"
} | subtract(6.3, divide(divide(multiply(divide(multiply(subtract(add(multiply(const_3, const_4), 6.3), 8.3), const_60), 5), 2), const_60), const_100)) | multiply(const_3,const_4)|add(n3,#0)|subtract(#1,n0)|multiply(#2,const_60)|divide(#3,n2)|multiply(n1,#4)|divide(#5,const_60)|divide(#6,const_100)|subtract(n3,#7) | for every 5 min watch looses 2 secs , so for 60 ms it looses 24 sec , i . e . , for 1 hr it looses 24 secs 8.30 amto 6.30 pm = 10 hr it looses 240 secs i . e . , 4 mins , hence d watch will show 6.26 answer : e | physics |
math_qa__xkVsmx9LYsVztBzq | What is the remainder of W=3^19 when divided by 10? Choose the correct choice from the following choices: A) 0 B) 1 C) 5 D) 7 E) 9 | <gadget id="calculator">19 % 4</gadget>
<output>3</output>
<gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">27 % 10</gadget>
<output>7</output>
<result>D</result> | D | 7 | What is the remainder of W=3^19 when divided by 10? | {
"A": "0",
"B": "1",
"C": "5",
"D": "7",
"E": "9"
} | reminder(power(3, reminder(19, const_4)), 10) | reminder(n1,const_4)|power(n0,#0)|reminder(#1,n2)| | "i looked for patterns : ^ 2 - units digit 9 ^ 3 - units digit 7 ^ 4 - units digit 1 ^ 5 - units digit 3 hence , we can see that when raised to a power which is multiple of 4 , the units digit is 1 , and when to an even power not multiple of 4 , the units digit is 9 and we can then see : ^ 16 - units digit 1 , or ^ 18 - units digit 9 and ^ 19 - units digit 7 therefore , w = when divided by 10 , the remainder must be 7 . d" | general |
math_qa__HMo74K3M9yL8C1nG | If each edge of cube increased by 10%, the percentage increase in surface area is: Answers: A) 33.1 B) 33.5 C) 33.7 D) 33.2 E) 33.9 | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">110 ** 3</gadget>
<output>1_331_000</output>
<gadget id="calculator">100 ** 3</gadget>
<output>1_000_000</output>
<gadget id="calculator">1_331_000 - 1_000_000</gadget>
<output>331_000</output>
<gadget id="calculator">331_000 / 1_000_000</gadget>
<output>331/1_000 = around 0.331</output>
<gadget id="calculator">100 * (331/1_000)</gadget>
<output>331/10 = around 33.1</output>
<result>A</result> | A | 33.1 | If each edge of cube increased by 10%, the percentage increase in surface area is: | {
"A": "33.1",
"B": "33.5",
"C": "33.7",
"D": "33.2",
"E": "33.9"
} | multiply(const_100, divide(subtract(power(add(const_100, 10), const_3), power(const_100, const_3)), power(const_100, const_3))) | add(n0,const_100)|power(const_100,const_3)|power(#0,const_3)|subtract(#2,#1)|divide(#3,#1)|multiply(#4,const_100) | 100 × ( 110 ) / 100 × ( 110 ) / 100 × ( 110 ) / 100 = > 1331 / 100 = 33.1 % answer is a . | geometry |
math_qa__VsjpbPeiywU17EfI | A train 110 m long is running with a speed of 56 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going?
Pick: A) 5 B) 6.4 C) 7 D) 8 E) 9 | <gadget id="calculator">56 + 6</gadget>
<output>62</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">62 * (5/18)</gadget>
<output>155/9 = around 17.222222</output>
<gadget id="calculator">110 / (155/9)</gadget>
<output>198/31 = around 6.387097</output>
<result>B</result> | B | 6.4 | A train 110 m long is running with a speed of 56 km/hr. In what time will it pass a man who is running at 6 km/hr in the direction opposite to that in which the train is going? | {
"A": "5",
"B": "6.4",
"C": "7",
"D": "8",
"E": "9"
} | divide(110, multiply(add(56, 6), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of train relative to man = 56 + 6 = 62 km / hr . = 62 * 5 / 18 = 155 / 9 m / sec . time taken to pass the men = 110 * 9 / 155 = 6.4 sec . answer : option b" | physics |
math_qa__m190wcyMBDsRab7b | 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.105 only. Men’s wages are? Choose the correct answer:
A) 6 rs B) 7 rs C) 8 rs D) 4 rs E) 1 rs | <gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">105 / 15</gadget>
<output>7</output>
<result>B</result> | B | 7 | 5 men are equal to as many women as are equal to 8 boys. All of them earn Rs.105 only. Men’s wages are? | {
"A": "6 rs",
"B": "7 rs",
"C": "8 rs",
"D": "4 rs",
"E": "1 rs"
} | divide(105, multiply(const_3, 5)) | multiply(n0,const_3)|divide(n2,#0)| | "5 m = xw = 8 b 5 m + xw + 8 b - - - - - 105 rs . 5 m + 5 m + 5 m - - - - - 105 rs . 15 m - - - - - - 105 rs . = > 1 m = 7 rs . answer : b" | general |
math_qa__kd7z09b0wB6q5LLj | The pilot of a small aircraft with a 40-gallon fuel tank wants to fly to Cleveland, which is 520 miles away. The pilot recognizes that the current engine, which can fly only 8 miles per gallon, will not get him there. By how many miles per gallon must the aircraft’s fuel efficiency be improved to make the flight to Cleveland possible? Choose the correct choice from the following answers.
A) 5
B) 4
C) 12
D) 40
E) 160 | <gadget id="calculator">520 / 40</gadget>
<output>13</output>
<gadget id="calculator">13 - 8</gadget>
<output>5</output>
<result>A</result> | A | 5 | The pilot of a small aircraft with a 40-gallon fuel tank wants to fly to Cleveland, which is 520 miles away. The pilot recognizes that the current engine, which can fly only 8 miles per gallon, will not get him there. By how many miles per gallon must the aircraft’s fuel efficiency be improved to make the flight to Cleveland possible? | {
"A": "5",
"B": "4",
"C": "12",
"D": "40",
"E": "160"
} | subtract(divide(520, 40), 8) | divide(n1,n0)|subtract(#0,n2)| | "actual miles / gallon is = 520 / 40 = 13 miles / gallon . current engine miles / gallon is 8 miles / gallon . additional 5 miles / gallon is required to match the actual mileage . imo option a ." | physics |
math_qa__myCk0I3lh7uNe8UG | Car A runs at the speed of 65km/hr & reaches its destination in 8hr. Car B runs at the speed of 75 km/h & reaches its destination in 4h. What is the respective ratio of distances covered by Car A & Car B? Pick one
A) 26 : 15 B) 12 : 7 C) 13 : 7 D) 15 : 6 E) 13 : 6 | <gadget id="calculator">65 * 8</gadget>
<output>520</output>
<gadget id="calculator">75 * 4</gadget>
<output>300</output>
<gadget id="calculator">520 / 300</gadget>
<output>26/15 = around 1.733333</output>
<result>A</result> | A | 1.733333 | Car A runs at the speed of 65km/hr & reaches its destination in 8hr. Car B runs at the speed of 75 km/h & reaches its destination in 4h. What is the respective ratio of distances covered by Car A & Car B? | {
"A": "26 : 15",
"B": "12 : 7",
"C": "13 : 7",
"D": "15 : 6",
"E": "13 : 6"
} | divide(multiply(65, 8), multiply(75, 4)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,#1)| | "sol . distance travelled by car a = 65 ã — 8 = 520 km distance travelled by car b = 75 ã — 4 = 300 km ratio = 520 / 300 = 26 : 15 a" | physics |
math_qa__c8AYkYyZ5YdcyrUe | A boat can travel with a speed of 25km/hr in still water. If the speed of the stream is 5km/hr, find the time taken by the boat to go 120km downstream. Choose the correct answer.
A) 1 hr B) 2 hrs C) 3 hrs D) 4 hrs E) 5 hrs | <gadget id="calculator">25 + 5</gadget>
<output>30</output>
<gadget id="calculator">120 / 30</gadget>
<output>4</output>
<result>D</result> | D | 4 | A boat can travel with a speed of 25km/hr in still water. If the speed of the stream is 5km/hr, find the time taken by the boat to go 120km downstream. | {
"A": "1 hr",
"B": "2 hrs",
"C": "3 hrs",
"D": "4 hrs",
"E": "5 hrs"
} | divide(120, add(25, 5)) | add(n0,n1)|divide(n2,#0)| | "speed downstream = ( 25 + 5 ) km / hr = 30 km / hr . time taken to travel 120 km downstream = 120 / 30 hrs = 4 hrs . answer : d" | physics |
math_qa__tzPH9fUJLSUHFb7l | The banker’s gain on a sum due 3 years hence at 17% per annum is Rs. 100. The banker’s discount is Options
A) rs . 960
B) rs . 840
C) rs . 296
D) rs . 760
E) none | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">3 * 17</gadget>
<output>51</output>
<gadget id="calculator">10_000 / 51</gadget>
<output>10_000/51 = around 196.078431</output>
<gadget id="calculator">(10_000/51) + 100</gadget>
<output>15_100/51 = around 296.078431</output>
<result>C</result> | C | 296 | The banker’s gain on a sum due 3 years hence at 17% per annum is Rs. 100. The banker’s discount is | {
"A": "rs . 960",
"B": "rs . 840",
"C": "rs . 296",
"D": "rs . 760",
"E": "none"
} | add(divide(multiply(100, const_100), multiply(3, 17)), 100) | multiply(n2,const_100)|multiply(n0,n1)|divide(#0,#1)|add(n2,#2)| | "solution t . d = ( b . g x 100 / r x t ) = rs . ( 100 x 100 / 17 x 3 ) = rs . 196 . b . d = rs ( 196 + 100 ) = rs . 296 . answer c" | gain |
math_qa__0C25xWPKNdOV3yf2 | An error 4% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is:
Choices.
A) 4.16 B) 5.16 C) 7.16 D) 8.16 E) 9.16 | <gadget id="calculator">100 + 4</gadget>
<output>104</output>
<gadget id="calculator">104 ** 2</gadget>
<output>10_816</output>
<gadget id="calculator">100 ** 2</gadget>
<output>10_000</output>
<gadget id="calculator">10_816 - 10_000</gadget>
<output>816</output>
<gadget id="calculator">816 * 100</gadget>
<output>81_600</output>
<gadget id="calculator">81_600 / 10_000</gadget>
<output>204/25 = around 8.16</output>
<result>D</result> | D | 8.16 | An error 4% in excess is made while measuring the side of a square. The percentage of error in the calculated area of the square is: | {
"A": "4.16",
"B": "5.16",
"C": "7.16",
"D": "8.16",
"E": "9.16"
} | divide(multiply(subtract(square_area(add(const_100, 4)), square_area(const_100)), const_100), square_area(const_100)) | add(n0,const_100)|square_area(const_100)|square_area(#0)|subtract(#2,#1)|multiply(#3,const_100)|divide(#4,#1)| | "explanation : 100 cm is read as 104 cm . a 1 = ( 100 × 100 ) cm 2 = 10000 and a 2 = ( 104 × 104 ) cm 2 = 10816 ( a 2 - a 1 ) = 10816 - 10000 = 816 = > 816 / 10000 * 100 = 8.16 answer : d" | gain |
math_qa__AfoHPg1eUrYTXi0a | A 90-liter solution of cool-drink is made from 5% jasmine water. If 8 liters of jasmine and 2 liters of water were added to the solution, what percent of the solution is jasmine? Choose the correct choice from the following answers: A) 6.5 % B) 8.5 % C) 10.5 % D) 12.5 % E) 14.5 % | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 90</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">8 + (9/2)</gadget>
<output>25/2 = around 12.5</output>
<result>D</result> | D | 12.5 | A 90-liter solution of cool-drink is made from 5% jasmine water. If 8 liters of jasmine and 2 liters of water were added to the solution, what percent of the solution is jasmine? | {
"A": "6.5 %",
"B": "8.5 %",
"C": "10.5 %",
"D": "12.5 %",
"E": "14.5 %"
} | add(8, multiply(divide(5, const_100), 90)) | divide(n1,const_100)|multiply(n0,#0)|add(n2,#1) | the percent of jasmine in the resulting solution is : ( amount of jasmine ) / ( total volume ) ( 0.05 ( 90 ) + 8 ) / 100 = 12.5 / 100 = 12.5 % the answer is d . | gain |
math_qa__fp1FiUs17JefEXVu | if the ratio of two number is 4:6 and LCM of the number is 280 then what is the number. Pick one
A) 12 B) 20 C) 25 D) 30 E) 35 | <gadget id="calculator">4 * 6</gadget>
<output>24</output>
<gadget id="calculator">280 / 24</gadget>
<output>35/3 = around 11.666667</output>
<result>A</result> | A | 12 | if the ratio of two number is 4:6 and LCM of the number is 280 then what is the number. | {
"A": "12",
"B": "20",
"C": "25",
"D": "30",
"E": "35"
} | divide(280, multiply(4, 6)) | multiply(n0,n1)|divide(n2,#0) | product of two no = lcm * hcf 4 x * 6 x = 280 * x x = 12 answer : a | other |
math_qa__rARQlv8lepcUddEa | By how much does the larger root of the equation 2b^2+5b = 12 exceed the smaller root? Choose the most appropriate option.
A) 5 / 2 B) 10 / 3 C) 7 / 2 D) 14 / 3 E) 11 / 2 | <gadget id="calculator">5 ** 2</gadget>
<output>25</output>
<gadget id="calculator">2 * 12</gadget>
<output>24</output>
<gadget id="calculator">24 * 4</gadget>
<output>96</output>
<gadget id="calculator">25 + 96</gadget>
<output>121</output>
<gadget id="calculator">121 ** (1/2)</gadget>
<output>11</output>
<gadget id="calculator">5 + 11</gadget>
<output>16</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">16 / 4</gadget>
<output>4</output>
<gadget id="calculator">5 - 11</gadget>
<output>-6</output>
<gadget id="calculator">(-6) / 4</gadget>
<output>-3/2 = around -1.5</output>
<gadget id="calculator">4 - (-3/2)</gadget>
<output>11/2 = around 5.5</output>
<result>E</result> | E | 5.5 | By how much does the larger root of the equation 2b^2+5b = 12 exceed the smaller root? | {
"A": "5 / 2",
"B": "10 / 3",
"C": "7 / 2",
"D": "14 / 3",
"E": "11 / 2"
} | subtract(divide(add(5, sqrt(add(power(5, 2), multiply(multiply(2, 12), const_4)))), multiply(2, 2)), divide(subtract(5, sqrt(add(power(5, 2), multiply(multiply(2, 12), const_4)))), multiply(2, 2))) | multiply(n0,n3)|multiply(n0,n0)|power(n2,n0)|multiply(#0,const_4)|add(#3,#2)|sqrt(#4)|add(n2,#5)|subtract(n2,#5)|divide(#6,#1)|divide(#7,#1)|subtract(#8,#9)| | "for 2 b ^ 2 + 5 b = 12 roots are [ - 5 + sqrt ( 25 + 96 ) ] / 4 or [ - 5 - sqrt ( 25 + 96 ) ] / 4 = 1.5 or - 4 hence larger root 1.5 is 1.5 - ( - 4 ) = 5.5 = 11 / 2 greater than smaller root ( - 4 ) . hence option ( e ) ." | general |
math_qa__5zOVCTicFRus3au4 | between 100 to 200 how many no are divisible by both 3 and 2 and 100,200 are inclusive? Choose the correct option.
A) 77 B) 78 C) 79 D) 80 E) 81 | <gadget id="calculator">100 / 2</gadget>
<output>50</output>
<gadget id="calculator">50 / 3</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">floor(50/3)</gadget>
<output>16</output>
<gadget id="calculator">100 - 16</gadget>
<output>84</output>
<gadget id="calculator">84 - 2</gadget>
<output>82</output>
<result>C</result> | C | 79 | between 100 to 200 how many no are divisible by both 3 and 2 and 100,200 are inclusive? | {
"A": "77",
"B": "78",
"C": "79",
"D": "80",
"E": "81"
} | subtract(subtract(100, floor(divide(divide(100, const_2), const_3))), const_2) | divide(n0,const_2)|divide(#0,const_3)|floor(#1)|subtract(n0,#2)|subtract(#3,const_2) | prime numbers are 21 so 100 - 21 = 79 answer : c | other |
math_qa__qxRrcoLkDbUnFLvL | Martin has to secure 80% marks to clear his exam of class 9th.
He got 200 marks and failed by 200 marks.
What is the maximum marks ? Select
A) 500 B) 505 C) 510 D) 515 E) 525 | <gadget id="calculator">200 + 200</gadget>
<output>400</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">400 / (4/5)</gadget>
<output>500</output>
<result>A</result> | A | 500 | Martin has to secure 80% marks to clear his exam of class 9th.
He got 200 marks and failed by 200 marks.
What is the maximum marks ? | {
"A": "500",
"B": "505",
"C": "510",
"D": "515",
"E": "525"
} | divide(add(200, 200), divide(80, const_100)) | add(n2,n2)|divide(n0,const_100)|divide(#0,#1) | a 500 to pass the exam ravish needs 200 + 200 = 400 marks . = > ( 400 / 80 ) * 100 = 500 | gain |
math_qa__LmtClDpS0rr5ojuz | The length of each side of square A is increased by 100 percent to make square B. If the length of the side of square B is increased by 60 percent to make square C, by what percent is the area of square C greater than the sum of the areas of squares A and B?
Choose the most appropriate option.
A) 75 %
B) 80 %
C) 104.8 %
D) 150.5 %
E) 180 % | <gadget id="calculator">100 / 100</gadget>
<output>1</output>
<gadget id="calculator">1 + 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 60</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">2 + (6/5)</gadget>
<output>16/5 = around 3.2</output>
<gadget id="calculator">(16/5) ** 2</gadget>
<output>256/25 = around 10.24</output>
<gadget id="calculator">(256/25) - 1</gadget>
<output>231/25 = around 9.24</output>
<gadget id="calculator">(231/25) - 4</gadget>
<output>131/25 = around 5.24</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">(131/25) / 5</gadget>
<output>131/125 = around 1.048</output>
<gadget id="calculator">(131/125) * 100</gadget>
<output>524/5 = around 104.8</output>
<result>C</result> | C | 104.8 | The length of each side of square A is increased by 100 percent to make square B. If the length of the side of square B is increased by 60 percent to make square C, by what percent is the area of square C greater than the sum of the areas of squares A and B? | {
"A": "75 %",
"B": "80 %",
"C": "104.8 %",
"D": "150.5 %",
"E": "180 %"
} | multiply(divide(subtract(subtract(square_area(add(add(const_1, divide(100, 100)), divide(multiply(add(const_1, divide(100, 100)), 60), 100))), const_1), const_4), add(const_1, square_area(add(const_1, divide(100, 100))))), 100) | divide(n0,n0)|add(#0,const_1)|multiply(n1,#1)|square_area(#1)|add(#3,const_1)|divide(#2,n0)|add(#1,#5)|square_area(#6)|subtract(#7,const_1)|subtract(#8,const_4)|divide(#9,#4)|multiply(n0,#10)| | "let length of each side of square a be 10 area of a = 10 ^ 2 = 100 since , length of each side of square a is increased by 100 percent to make square b length of each side of square b = 2 * 10 = 20 area of b = 20 ^ 2 = 400 since , length of the side of square b is increased by 60 percent to make square c length of each side of square c = 1.6 * 20 = 32 area of c = 32 ^ 2 = 1024 difference in areas of c and cummulative areas of a and b = 1024 - ( 400 + 100 ) = 524 percent is the area of square c greater than the sum of the areas of squares a and b = ( 524 / 500 ) * 100 % = 104.8 % answer c" | geometry |
math_qa__hiWdww9qGtIHEof4 | Find the perimeter and area of a square of side 15 cm. Options
A) 144 B) 169 C) 196 D) 121 E) 225 | <gadget id="calculator">15 ** 2</gadget>
<output>225</output>
<result>E</result> | E | 225 | Find the perimeter and area of a square of side 15 cm. | {
"A": "144",
"B": "169",
"C": "196",
"D": "121",
"E": "225"
} | square_area(15) | square_area(n0)| | "we know that the perimeter of square = 4 ã — side side = 15 cm therefore , perimeter = 4 ã — 15 cm = 60 cm now , area of the square = ( side ã — side ) sq . units = 15 ã — 15 cm â ² = 225 cm â ² answer : e" | geometry |
math_qa__jgfoZtjHHKpE5pz5 | A pizzeria in Castroville creates its own special blend of shredded cheese at a cost of $696.05 per kilogram. The blend includes Mozzarella, at $504.35 per kilogram, and Romano cheese, at $887.75 per kilogram. If the employees have already shredded 19 kilograms of Mozzarella cheese, how many kilograms of Romano cheese will they need to shred now? Choose the correct option:
A) 19 kg B) 13 kg C) 10 kg D) 23 kg E) 15 kg | <gadget id="calculator">696.05 - 504.35</gadget>
<output>191.7</output>
<gadget id="calculator">887.75 - 504.35</gadget>
<output>383.4</output>
<gadget id="calculator">191.7 / 383.4</gadget>
<output>0.5</output>
<gadget id="calculator">1 - 0.5</gadget>
<output>0.5</output>
<gadget id="calculator">0.5 / 0.5</gadget>
<output>1</output>
<gadget id="calculator">1 * 19</gadget>
<output>19</output>
<result>A</result> | A | 19 | A pizzeria in Castroville creates its own special blend of shredded cheese at a cost of $696.05 per kilogram. The blend includes Mozzarella, at $504.35 per kilogram, and Romano cheese, at $887.75 per kilogram. If the employees have already shredded 19 kilograms of Mozzarella cheese, how many kilograms of Romano cheese will they need to shred now? | {
"A": "19 kg",
"B": "13 kg",
"C": "10 kg",
"D": "23 kg",
"E": "15 kg"
} | multiply(divide(divide(subtract(696.05, 504.35), subtract(887.75, 504.35)), subtract(const_1, divide(subtract(696.05, 504.35), subtract(887.75, 504.35)))), 19) | subtract(n0,n1)|subtract(n2,n1)|divide(#0,#1)|subtract(const_1,#2)|divide(#2,#3)|multiply(n3,#4) | 504.35 ( 19 ) + 887.75 x = 696.05 ( 19 + x ) solve the equation . 504.35 ( 19 ) + 887.75 x = 696.05 ( 19 + x ) 9 , 582.65 + 887.75 x = 13 , 224.95 + 696.05 x 9 , 582.65 + 191.7 x = 13 , 224.95 191.7 x = 3 , 642.3 x = 19 . answer is a . | other |
math_qa__C31bwFrQZm9CuDNK | Product of two natural numbers is 17. Then, the sum of reciprocals of their squares is Choose the correct choice:
A) 290 / 289 B) 1 / 289 C) 290 / 90 D) 290 / 19 E) none of these | <gadget id="calculator">1 / 1</gadget>
<output>1</output>
<gadget id="calculator">1 ** 2</gadget>
<output>1</output>
<gadget id="calculator">1 / 17</gadget>
<output>1/17 = around 0.058824</output>
<gadget id="calculator">(1/17) ** 2</gadget>
<output>1/289 = around 0.00346</output>
<gadget id="calculator">1 + (1/289)</gadget>
<output>290/289 = around 1.00346</output>
<result>A</result> | A | 1.00346 | Product of two natural numbers is 17. Then, the sum of reciprocals of their squares is | {
"A": "290 / 289",
"B": "1 / 289",
"C": "290 / 90",
"D": "290 / 19",
"E": "none of these"
} | add(power(divide(const_1, const_1), const_2), power(divide(const_1, 17), const_2)) | divide(const_1,const_1)|divide(const_1,n0)|power(#0,const_2)|power(#1,const_2)|add(#2,#3)| | "explanation : if the numbers are a , b , then ab = 17 , as 17 is a prime number , so a = 1 , b = 17 . 1 / a 2 + 1 / b 2 = 1 / 1 ( 2 ) + 1 / 17 ( 2 ) = 290 / 289 option a" | general |
math_qa__NAuvV2Em9q8pSjz4 | The perimeter of an isosceles right triangle is 10 + 10 sq rt 2. What is the length of the hypotenuse of the triangle? Choose the correct choice from the following choices.
A) 5 B) 6 C) 7.07 D) 8 E) 9 | <gadget id="calculator">2 ** (1/2)</gadget>
<output>sqrt(2) = around 1.414214</output>
<gadget id="calculator">10 * (sqrt(2))</gadget>
<output>10*sqrt(2) = around 14.142136</output>
<gadget id="calculator">(10*sqrt(2)) / 2</gadget>
<output>5*sqrt(2) = around 7.071068</output>
<result>C</result> | C | 7.07 | The perimeter of an isosceles right triangle is 10 + 10 sq rt 2. What is the length of the hypotenuse of the triangle? | {
"A": "5",
"B": "6",
"C": "7.07",
"D": "8",
"E": "9"
} | divide(multiply(10, sqrt(2)), 2) | sqrt(n2)|multiply(n0,#0)|divide(#1,n2)| | "side of triangle is a then perimeter = a + a + a . sqrt 2 ( right angle and pythagorus ) = 2 a + a . sqrt 2 = 10 + 10 sqrt 2 or , a . ( 2 + sqrt 2 ) = 10 ( 1 + sqrt 2 ) , a = 10 * ( 1 + sqrt 2 ) / 2 + sqrt 2 = 10 * 2.414 / 3.414 = 0.707 * 10 then hypotenuse = 7.07 c" | geometry |
math_qa__gaGWb1frMyT8F990 | The average of 10 numbers is 40.2. Later it is found that two numbers have been wrongly copied. The first is 15 greater than the actual number and the second number added is 13 instead of 31. Find the correct average. Choose the most appropriate option.
A) 40.2
B) 40.4
C) 40.5
D) 40.8
E) none of the above | <gadget id="calculator">40.2 * 10</gadget>
<output>402</output>
<gadget id="calculator">13 + 15</gadget>
<output>28</output>
<gadget id="calculator">402 + 28</gadget>
<output>430</output>
<gadget id="calculator">430 - 31</gadget>
<output>399</output>
<gadget id="calculator">399 / 10</gadget>
<output>399/10 = around 39.9</output>
<result>C</result> | C | 40.5 | The average of 10 numbers is 40.2. Later it is found that two numbers have been wrongly copied. The first is 15 greater than the actual number and the second number added is 13 instead of 31. Find the correct average. | {
"A": "40.2",
"B": "40.4",
"C": "40.5",
"D": "40.8",
"E": "none of the above"
} | divide(subtract(add(multiply(40.2, 10), add(13, 15)), 31), 10) | add(n2,n3)|multiply(n0,n1)|add(#0,#1)|subtract(#2,n4)|divide(#3,n0)| | "sum of 10 numbers = 402 corrected sum of 10 numbers = 402 – 13 + 31 – 15 = 405 hence , new average = 405 ⁄ 10 = 40.5 answer c" | general |
math_qa__bixVEefdwzSVqCAl | A straight line in the xy-plane has a slope of 2 and a y-intercept of 2. On this line, what is the x-coordinate of the point whose y-coordinate is 998 ? Answers: A) 249 B) 498 C) 676 D) 823 E) 1,002 | <gadget id="calculator">998 - 2</gadget>
<output>996</output>
<gadget id="calculator">996 / 2</gadget>
<output>498</output>
<result>B</result> | B | 498 | A straight line in the xy-plane has a slope of 2 and a y-intercept of 2. On this line, what is the x-coordinate of the point whose y-coordinate is 998 ? | {
"A": "249",
"B": "498",
"C": "676",
"D": "823",
"E": "1,002"
} | divide(subtract(998, 2), 2) | subtract(n2,n0)|divide(#0,n0)| | "slope of 2 and a y - intercept of 2 y - coordinate is 998 y = 2 x + 2 996 = 2 x x = 498 answer : b . 498" | general |
math_qa__RLf2PNFYbvWQwxHl | If two-third of a bucket is filled in 2 minutes then the time taken to fill the bucket completely will be . Choose the most appropriate option: A) 3 minutes B) 70 seconds C) 60 seconds D) 100 seconds E) 120 seconds | <gadget id="calculator">2 / 2</gadget>
<output>1</output>
<gadget id="calculator">1 * 3</gadget>
<output>3</output>
<result>A</result> | A | 3 | If two-third of a bucket is filled in 2 minutes then the time taken to fill the bucket completely will be . | {
"A": "3 minutes",
"B": "70 seconds",
"C": "60 seconds",
"D": "100 seconds",
"E": "120 seconds"
} | multiply(divide(2, const_2), const_3) | divide(n0,const_2)|multiply(#0,const_3)| | "2 / 3 filled in 2 mint 1 / 3 filled in 1 mint then 2 / 3 + 1 / 3 = 2 + 1 = 3 minutes answer : a" | physics |
math_qa__TRnTlVKuz4osvOde | Marla is hanging a banner diagonally across a rectangular room. The length of the room is 3 feet shorter than its width. If the total area of the room is 130 square feet, what is the length of the banner (in feet)? Select:
A) between 16 and 17 B) between 17 and 18 C) between 18 and 19 D) between 19 and 20 E) between 20 and 21 | <gadget id="calculator">4 * 130</gadget>
<output>520</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">520 + 9</gadget>
<output>529</output>
<gadget id="calculator">529 ** (1/2)</gadget>
<output>23</output>
<gadget id="calculator">3 + 23</gadget>
<output>26</output>
<gadget id="calculator">26 / 2</gadget>
<output>13</output>
<gadget id="calculator">13 - 3</gadget>
<output>10</output>
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">13 ** 2</gadget>
<output>169</output>
<gadget id="calculator">100 + 169</gadget>
<output>269</output>
<gadget id="calculator">269 ** (1/2)</gadget>
<output>sqrt(269) = around 16.401219</output>
<result>A</result> | A | 16 | Marla is hanging a banner diagonally across a rectangular room. The length of the room is 3 feet shorter than its width. If the total area of the room is 130 square feet, what is the length of the banner (in feet)? | {
"A": "between 16 and 17",
"B": "between 17 and 18",
"C": "between 18 and 19",
"D": "between 19 and 20",
"E": "between 20 and 21"
} | sqrt(add(power(subtract(divide(add(3, sqrt(add(multiply(const_4, 130), power(3, const_2)))), const_2), 3), const_2), power(divide(add(3, sqrt(add(multiply(const_4, 130), power(3, const_2)))), const_2), const_2))) | multiply(n1,const_4)|power(n0,const_2)|add(#0,#1)|sqrt(#2)|add(n0,#3)|divide(#4,const_2)|power(#5,const_2)|subtract(#5,n0)|power(#7,const_2)|add(#8,#6)|sqrt(#9) | to solve this , we first need to set up an equation for the area of the room . if x is the width , then we have x ( x - 3 ) = 130 . by putting the equation in standard form , we get x ^ 2 - 3 x - 130 = 0 . by using the quadratic formula , we get roots of - 10 and 13 . we know that x is the width , and x - 3 is the length , so by using the roots , we get 13 as the width ( x ) , and 10 as the length ( x - 3 ) . once we have this , we can use the pythagorean theorem to solve for the diagonal . plugging in the length and width , we will get d ^ 2 = 13 ^ 2 + 10 ^ 2 = 169 + 100 = 269 the square root of 269 is less than 17 , since 17 ^ 2 = 289 . going down a number , we can compute 16 ^ 2 = 256 < 269 . therefore , the length of the diagonal must be between 16 and 17 . the correct answer is a . | geometry |
math_qa__PacOrvQIGxjVXVjz | If P gets 25% more than Q, then by what percent does Q get less than P?
Answers
A) 45 B) 34 C) 20 D) 76 E) 54 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 1</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(1/4) / (5/4)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<result>C</result> | C | 20 | If P gets 25% more than Q, then by what percent does Q get less than P? | {
"A": "45",
"B": "34",
"C": "20",
"D": "76",
"E": "54"
} | multiply(divide(divide(25, const_100), add(divide(25, const_100), const_1)), const_100) | divide(n0,const_100)|add(#0,const_1)|divide(#0,#1)|multiply(#2,const_100) | let q get 1 unit . 25 % of 1 unit = 1 / 4 = 0.25 p gets ( 1 + 0.25 ) i . e . , 1.25 units . difference = ( 1.25 - 1 ) = 0.25 required percentage = 0.25 / 1.25 * 100 = 1 / 5 * 100 = 20 answer : c | gain |
math_qa__Gs5Y1mG5BBc9MUgi | The number of people who purchased book A is twice the number of people who purchased book B. The number of people who purchased both books A and B is 500, which is twice the number of people who purchased only book B. What is the number of people B who purchased only book A? Choose the correct choice from the following options:
A) 250 B) 500 C) 750 D) 1000 E) 1500 | <gadget id="calculator">500 / 2</gadget>
<output>250</output>
<gadget id="calculator">500 + 250</gadget>
<output>750</output>
<gadget id="calculator">750 * 2</gadget>
<output>1_500</output>
<gadget id="calculator">1_500 - 500</gadget>
<output>1_000</output>
<result>D</result> | D | 1,000 | The number of people who purchased book A is twice the number of people who purchased book B. The number of people who purchased both books A and B is 500, which is twice the number of people who purchased only book B. What is the number of people B who purchased only book A? | {
"A": "250",
"B": "500",
"C": "750",
"D": "1000",
"E": "1500"
} | subtract(multiply(add(500, divide(500, const_2)), const_2), 500) | divide(n0,const_2)|add(n0,#0)|multiply(#1,const_2)|subtract(#2,n0) | this is best solved using overlapping sets or a venn diagram . we know that a = 2 b , and that 500 people purchased both a and b . further , those purchasing both was double those purchasing b only . this gives us 250 people purchasing b only . with the 500 that pruchased both , we have a total of 750 that purchased b and this is 1 / 2 of those that purchased a . so , 1500 purchased a . less the 500 that purchased both , b = 1000 purchased a only . ( this is much simpler to solve using the venn diagram ) . correct answer is d . 1000 | other |
math_qa__77T8fJGgizEVUf5F | Of 70 players on a football team, 37 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? Pick one.
A) 54 B) 59 C) 63 D) 71 E) 92 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">70 - 37</gadget>
<output>33</output>
<gadget id="calculator">(2/3) * 33</gadget>
<output>22</output>
<gadget id="calculator">22 + 37</gadget>
<output>59</output>
<result>B</result> | B | 59 | Of 70 players on a football team, 37 are throwers. The rest of the team is divided so one third are left- handed and the rest are right handed. Assuming that all throwers are right handed, how many right- handed players are there total? | {
"A": "54",
"B": "59",
"C": "63",
"D": "71",
"E": "92"
} | add(multiply(subtract(const_1, divide(const_1, const_3)), subtract(70, 37)), 37) | divide(const_1,const_3)|subtract(n0,n1)|subtract(const_1,#0)|multiply(#2,#1)|add(n1,#3)| | "37 are throwers and right handed 1 / 3 of remaining 33 , i . e 11 are left handed and remaining are right handed . basically , out of 70 , only 11 are left handed and remaining 70 - 11 = 59 are right handed . b is the answer" | general |
math_qa__nLWtcXv6vnB70P2Y | Paul's income is 40% less than Rex's income, Quentin's income is 20% less than Paul's income, and Sam's income is 40% less than Paul's income. If Rex gave 60% of his income to Sam and 40% of his income to Quentin, sam's new income would be what fraction of Quentin's new income? Choose the correct answer
A) 11 / 12 B) 12 / 11 C) 13 / 19 D) 12 / 19 E) 11 / 19 | <gadget id="calculator">40 * 100</gadget>
<output>4_000</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">40 * 80</gadget>
<output>3_200</output>
<gadget id="calculator">4_000 + 3_200</gadget>
<output>7_200</output>
<gadget id="calculator">40 + 20</gadget>
<output>60</output>
<gadget id="calculator">60 * 40</gadget>
<output>2_400</output>
<gadget id="calculator">4_000 + 2_400</gadget>
<output>6_400</output>
<gadget id="calculator">7_200 / 6_400</gadget>
<output>9/8 = around 1.125</output>
<result>B</result> | B | 1.090909 | Paul's income is 40% less than Rex's income, Quentin's income is 20% less than Paul's income, and Sam's income is 40% less than Paul's income. If Rex gave 60% of his income to Sam and 40% of his income to Quentin, sam's new income would be what fraction of Quentin's new income? | {
"A": "11 / 12",
"B": "12 / 11",
"C": "13 / 19",
"D": "12 / 19",
"E": "11 / 19"
} | divide(add(multiply(40, const_100), multiply(40, subtract(const_100, 20))), add(multiply(40, const_100), multiply(add(40, 20), 40))) | add(n0,n1)|multiply(n4,const_100)|multiply(n0,const_100)|subtract(const_100,n1)|multiply(n4,#3)|multiply(n4,#0)|add(#1,#4)|add(#2,#5)|divide(#6,#7)| | "make r = 10 p = 0.6 r = 6 q = 0.8 p = 4.8 s = 0.6 p = 3.6 for that we get s = 9.6 and q 8.8 so 9.6 / 8.8 = 1.2 / 1.1 ans : b" | general |
math_qa__opf6KtBeYMkA7mku | There are 200 female managers in a certain company. Find the total number of female employees Q in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers. Pick
A) q = 300 B) q = 400 C) q = 500 D) q = 600 E) none of these | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">200 / (2/5)</gadget>
<output>500</output>
<result>C</result> | C | 500 | There are 200 female managers in a certain company. Find the total number of female employees Q in the company, if 2/5 of all the employees are managers and 2/5 of all male employees are managers. | {
"A": "q = 300",
"B": "q = 400",
"C": "q = 500",
"D": "q = 600",
"E": "none of these"
} | divide(200, divide(2, 5)) | divide(n1,n2)|divide(n0,#0) | { managers } = { female managers } + { male managers } ; we are told that the total number of managers in the company is 2 / 5 of all the employees , thus { managers } = 2 / 5 ( m + f ) , where m and f are number of female and male employees , respectively . also , we know that 2 / 5 of all male employees are managers : { male managers } = 2 / 5 * mas well as there are total of 200 female managers : { female managers } = 200 ; thus : 2 / 5 ( m + f ) = 200 + 2 / 5 * m - - > f = 500 . answer : c . | general |
math_qa__AYXi0CqA0clJMtHN | If the sum of two numbers is 24 and the sum of their squares is 404, then the product of the numbers is Choose the most appropriate option: A) 40 B) 44 C) 80 D) 86 E) 90 | <gadget id="calculator">24 ** 2</gadget>
<output>576</output>
<gadget id="calculator">576 - 404</gadget>
<output>172</output>
<gadget id="calculator">172 / 2</gadget>
<output>86</output>
<result>D</result> | D | 86 | If the sum of two numbers is 24 and the sum of their squares is 404, then the product of the numbers is | {
"A": "40",
"B": "44",
"C": "80",
"D": "86",
"E": "90"
} | divide(subtract(power(24, const_2), 404), const_2) | power(n0,const_2)|subtract(#0,n1)|divide(#1,const_2)| | "sol . let the numbers be x and y . then , ( x + y ) = 24 and x 2 + y 2 = 404 . now , 2 xy = ( x + y ) 2 - ( x 2 + y 2 ) = ( 24 ) 2 - 404 = 576 - 404 = 172 xy = 86 . answer d" | general |
math_qa__cWln67M4c03xa384 | Product of two natural numbers is 3. Then, the sum of reciprocals of their squares is Choose the correct option.
A) 10 / 9 B) 1 / 289 C) 290 / 90 D) 290 / 19 E) none of these | <gadget id="calculator">1 / 1</gadget>
<output>1</output>
<gadget id="calculator">1 ** 2</gadget>
<output>1</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) ** 2</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">1 + (1/9)</gadget>
<output>10/9 = around 1.111111</output>
<result>A</result> | A | 1.111111 | Product of two natural numbers is 3. Then, the sum of reciprocals of their squares is | {
"A": "10 / 9",
"B": "1 / 289",
"C": "290 / 90",
"D": "290 / 19",
"E": "none of these"
} | add(power(divide(const_1, const_1), const_2), power(divide(const_1, 3), const_2)) | divide(const_1,const_1)|divide(const_1,n0)|power(#0,const_2)|power(#1,const_2)|add(#2,#3)| | "explanation : if the numbers are a , b , then ab = 3 , as 3 is a prime number , so a = 1 , b = 3 . 1 / a 2 + 1 / b 2 = 1 / 1 ( 2 ) + 1 / 3 ( 2 ) = 10 / 9 option a" | general |
math_qa__90NdSyt312mISlFM | If the least common multiple of two prime numbers x and y is 10, where x > y, then the value of 2x + y is
Choose the correct choice.
A) 7 B) 9 C) 11 D) 12 E) 21 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<result>D</result> | D | 12 | If the least common multiple of two prime numbers x and y is 10, where x > y, then the value of 2x + y is | {
"A": "7",
"B": "9",
"C": "11",
"D": "12",
"E": "21"
} | add(multiply(divide(10, const_2), 2), const_2) | divide(n0,const_2)|multiply(n1,#0)|add(#1,const_2) | lcm of two prime numbers will basically be multiple of those numbers . lcm = 10 = 2 * 5 , both of which are prime . now we know x > y , so x = 5 and y = 2 . 2 x + y = 2 * 5 + 2 = 10 + 2 = 12 . answer : d | general |
math_qa__wOqOx4PAJ0NHj92H | If the cost price is 96% of selling price then what is the profit percentage. Choose the most appropriate option
A) 7.14 B) 7.41 C) 4.71 D) 4.17 E) none of them | <gadget id="calculator">100 - 96</gadget>
<output>4</output>
<gadget id="calculator">4 / 96</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">(1/24) * 100</gadget>
<output>25/6 = around 4.166667</output>
<result>D</result> | D | 4.17 | If the cost price is 96% of selling price then what is the profit percentage. | {
"A": "7.14",
"B": "7.41",
"C": "4.71",
"D": "4.17",
"E": "none of them"
} | multiply(divide(subtract(const_100, 96), 96), const_100) | subtract(const_100,n0)|divide(#0,n0)|multiply(#1,const_100)| | "selling price = rs 100 : then cost price = rs 96 : profit = rs 4 . profit = { ( 4 / 96 ) * 100 } % = 4.17 % answer is d ." | gain |
math_qa__2bRp9i7lK4cVHFPL | Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 50 years. What is Deepak present age Choose the correct choice
A) 14 B) 15 C) 33 D) 22 E) 23 | <gadget id="calculator">50 - 6</gadget>
<output>44</output>
<gadget id="calculator">44 * 3</gadget>
<output>132</output>
<gadget id="calculator">132 / 4</gadget>
<output>33</output>
<result>C</result> | C | 33 | Ratio between Rahul and Deepak is 4:3, After 6 Years Rahul age will be 50 years. What is Deepak present age | {
"A": "14",
"B": "15",
"C": "33",
"D": "22",
"E": "23"
} | divide(multiply(subtract(50, 6), 3), 4) | subtract(n3,n2)|multiply(n1,#0)|divide(#1,n0)| | "explanation : present age is 4 x and 3 x , = > 4 x + 6 = 50 = > x = 11 so deepak age is = 3 ( 11 ) = 33 answer : option c" | other |
math_qa__i4AnEV032Rdlqt3N | A man buys a cycle for Rs. 1750 and sells it at a loss of 8%. What is the selling price of the cycle? Choose the correct choice from the following answers:
A) s . 1090 B) s . 1610 C) s . 1190 D) s . 1202 E) s . 1092 | <gadget id="calculator">100 - 8</gadget>
<output>92</output>
<gadget id="calculator">92 * 1_750</gadget>
<output>161_000</output>
<gadget id="calculator">161_000 / 100</gadget>
<output>1_610</output>
<result>B</result> | B | 1,610 | A man buys a cycle for Rs. 1750 and sells it at a loss of 8%. What is the selling price of the cycle? | {
"A": "s . 1090",
"B": "s . 1610",
"C": "s . 1190",
"D": "s . 1202",
"E": "s . 1092"
} | divide(multiply(subtract(const_100, 8), 1750), const_100) | subtract(const_100,n1)|multiply(n0,#0)|divide(#1,const_100)| | "s . p . = 92 % of rs . 1750 = rs . 92 x 1750 / 100 = rs . 1610 answer : option b" | gain |
math_qa__UvU7QmroRBSw5r7A | A metallic sheet is of rectangular shape with dimensions 100 m x 50 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 10 m, the volume of the box (in m cube) is: Select: A) 42500 m cube B) 20000 m cube C) 44140 m cube D) 24000 m cube E) none of these | <gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">50 - 20</gadget>
<output>30</output>
<gadget id="calculator">80 * 30 * 10</gadget>
<output>24_000</output>
<result>D</result> | D | 24,000 | A metallic sheet is of rectangular shape with dimensions 100 m x 50 m. From each of its corners, a square is cut off so as to make an open box. If the length of the square is 10 m, the volume of the box (in m cube) is: | {
"A": "42500 m cube",
"B": "20000 m cube",
"C": "44140 m cube",
"D": "24000 m cube",
"E": "none of these"
} | volume_rectangular_prism(subtract(100, multiply(10, const_2)), subtract(50, multiply(10, const_2)), 10) | multiply(n2,const_2)|subtract(n0,#0)|subtract(n1,#0)|volume_rectangular_prism(n2,#1,#2)| | "explanation : l = ( 100 - 20 ) m = 80 m , [ because 10 + 10 = 20 ] b = ( 50 - 20 ) m = 30 m , h = 10 m . volume of the box = ( 80 x 30 x 8 ) m cube = 24000 m cube . option d" | geometry |
math_qa__mT3inDoLUzj7d2n7 | A trader marked the selling price of an article at 50% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of :
Choose the correct choice from the following:
A) 7.3 % B) 10.5 % C) 11 % D) 12.5 % E) none | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">11 / 150</gadget>
<output>11/150 = around 0.073333</output>
<gadget id="calculator">100 * (11/150)</gadget>
<output>22/3 = around 7.333333</output>
<result>A</result> | A | 7.3 | A trader marked the selling price of an article at 50% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed a discount of : | {
"A": "7.3 %",
"B": "10.5 %",
"C": "11 %",
"D": "12.5 %",
"E": "none"
} | multiply(const_100, divide(add(multiply(add(const_2, const_3), const_2), 1), add(const_100, 50))) | add(const_2,const_3)|add(n0,const_100)|multiply(#0,const_2)|add(#2,n1)|divide(#3,#1)|multiply(#4,const_100)| | "sol . let c . p . = rs . 100 . then , marked price = rs . 110 , s . p . = rs . 99 . ∴ discount % = [ 11 / 150 * 100 ] % = 7.3 % answer a" | gain |
math_qa__5oFRetaydOuoedwm | 72 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day?
Choose the correct option.
A) 77
B) 99
C) 66
D) 55
E) 88 | <gadget id="calculator">72 * 8</gadget>
<output>576</output>
<gadget id="calculator">576 / 30</gadget>
<output>96/5 = around 19.2</output>
<gadget id="calculator">(96/5) * 50</gadget>
<output>960</output>
<gadget id="calculator">960 / 6</gadget>
<output>160</output>
<gadget id="calculator">160 - 72</gadget>
<output>88</output>
<result>E</result> | E | 88 | 72 men working 8 hours per day dig 30 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day? | {
"A": "77",
"B": "99",
"C": "66",
"D": "55",
"E": "88"
} | subtract(divide(multiply(divide(multiply(72, 8), 30), 50), 6), 72) | multiply(n0,n1)|divide(#0,n2)|multiply(n3,#1)|divide(#2,n4)|subtract(#3,n0)| | "( 72 * 8 ) / 30 = ( x * 6 ) / 50 = > x = 160 160 – 72 = 88 answer : e" | physics |
math_qa__3Kz4Bk2O7stbNDIL | How many of the positive divisors of 120 are also multiples of 4 not including 120? Pick.
A) 3 . B) 4 . C) 5 . D) 7 . E) 8 . | <gadget id="calculator">120 / 4</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">15 / 3</gadget>
<output>5</output>
<result>C</result> | C | 5 | How many of the positive divisors of 120 are also multiples of 4 not including 120? | {
"A": "3 .",
"B": "4 .",
"C": "5 .",
"D": "7 .",
"E": "8 ."
} | divide(divide(divide(120, 4), const_2), const_3) | divide(n0,n1)|divide(#0,const_2)|divide(#1,const_3) | given to find the positive divisors of 120 and condition is that divisors have to be multiple of 4 but not including 120 . consider factors of 120 4 * 30 6 * 20 15 * 8 24 * 5 60 * 2 total we get 5 different ways and all are part of 4 . answer : c is correct option . | general |
math_qa__bqlWlqcxiawcfytR | The sale price sarees listed for Rs.400 after successive discount is 15% and 5% is? Choose the correct choice: A) 297 B) 879 C) 323 D) 762 E) 269 | <gadget id="calculator">400 * 15</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 / 100</gadget>
<output>60</output>
<gadget id="calculator">400 - 60</gadget>
<output>340</output>
<gadget id="calculator">340 * 5</gadget>
<output>1_700</output>
<gadget id="calculator">1_700 / 100</gadget>
<output>17</output>
<gadget id="calculator">340 - 17</gadget>
<output>323</output>
<result>C</result> | C | 323 | The sale price sarees listed for Rs.400 after successive discount is 15% and 5% is? | {
"A": "297",
"B": "879",
"C": "323",
"D": "762",
"E": "269"
} | subtract(subtract(400, divide(multiply(400, 15), const_100)), divide(multiply(subtract(400, divide(multiply(400, 15), const_100)), 5), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "400 * ( 85 / 100 ) * ( 95 / 100 ) = 323 answer : c" | gain |
math_qa__aE7MQ59CcvM0a2FV | Efrida and Frazer who live 15 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is two miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home? Choose the most appropriate option: A) 6 B) 7 C) 8 D) 10 E) 13 | <gadget id="calculator">15 ** 2</gadget>
<output>225</output>
<gadget id="calculator">2 ** 2</gadget>
<output>4</output>
<gadget id="calculator">225 - 4</gadget>
<output>221</output>
<gadget id="calculator">221 / 2</gadget>
<output>221/2 = around 110.5</output>
<gadget id="calculator">(221/2) ** (1/2)</gadget>
<output>sqrt(442)/2 = around 10.511898</output>
<gadget id="calculator">(sqrt(442)/2) + 2</gadget>
<output>2 + sqrt(442)/2 = around 12.511898</output>
<result>E</result> | E | 13 | Efrida and Frazer who live 15 miles apart, meet at a restaurant that is directly north of Efrida's home and directly east of Frazer's home. If the restaurant is two miles closer to Efrida's home, than to Frazer's home, how many miles is the restaurant from Frazer's home? | {
"A": "6",
"B": "7",
"C": "8",
"D": "10",
"E": "13"
} | add(sqrt(divide(subtract(power(15, const_2), power(const_2, const_2)), const_2)), const_2) | power(n0,const_2)|power(const_2,const_2)|subtract(#0,#1)|divide(#2,const_2)|sqrt(#3)|add(#4,const_2) | it ' s a simple geometry problem . look at the diagram below : answer : e . | physics |
math_qa__bm7p6UGIDCoiQth2 | A space shuttle orbits the earth at about 2 kilometers per second. This speed is equal to how many kilometers per hour? Select:
A) 7,200
B) 8,880
C) 10,800
D) 28,800
E) 48,000 | <gadget id="calculator">2 * 3_600</gadget>
<output>7_200</output>
<result>A</result> | A | 7,200 | A space shuttle orbits the earth at about 2 kilometers per second. This speed is equal to how many kilometers per hour? | {
"A": "7,200",
"B": "8,880",
"C": "10,800",
"D": "28,800",
"E": "48,000"
} | multiply(2, const_3600) | multiply(n0,const_3600)| | "seconds in 1 hours : 60 s in 1 min 60 min in 1 hr 60 * 60 = 3600 sec in 1 hr 2 * 3600 = 28,800 answer : a" | physics |
math_qa__B3MzRoeKoh5RfSEu | In what time will a railway train 80 m long moving at the rate of 36 kmph pass a telegraph post on its way? Pick:
A) 4 sec
B) 7 sec
C) 2 sec
D) 6 sec
E) 8 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">80 / 10</gadget>
<output>8</output>
<result>E</result> | E | 8 | In what time will a railway train 80 m long moving at the rate of 36 kmph pass a telegraph post on its way? | {
"A": "4 sec",
"B": "7 sec",
"C": "2 sec",
"D": "6 sec",
"E": "8 sec"
} | divide(80, multiply(36, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "t = 80 / 36 * 18 / 5 = 8 sec answer : e" | physics |
math_qa__T1xd0psay5dWAKHI | Two equilateral triangles of side 12cm are placed one on top of another, such that a 6 pointed star is formed .if the six verticals lie on a circle what is the area of the circle not enclosed by the star ? Choose the correct choice
A) 68 B) 83 C) 57 D) 61 E) 62 | <gadget id="calculator">3 ** (1/2)</gadget>
<output>sqrt(3) = around 1.732051</output>
<gadget id="calculator">(sqrt(3)) / 2</gadget>
<output>sqrt(3)/2 = around 0.866025</output>
<gadget id="calculator">(sqrt(3)/2) * 12</gadget>
<output>6*sqrt(3) = around 10.392305</output>
<gadget id="calculator">(6*sqrt(3)) * 2</gadget>
<output>12*sqrt(3) = around 20.78461</output>
<gadget id="calculator">(12*sqrt(3)) / 3</gadget>
<output>4*sqrt(3) = around 6.928203</output>
<gadget id="calculator">pi * ((4*sqrt(3)) ** 2)</gadget>
<output>48*pi = around 150.796447</output>
<gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">16 * (sqrt(3))</gadget>
<output>16*sqrt(3) = around 27.712813</output>
<gadget id="calculator">(16*sqrt(3)) / 4</gadget>
<output>4*sqrt(3) = around 6.928203</output>
<gadget id="calculator">(4*sqrt(3)) * 12</gadget>
<output>48*sqrt(3) = around 83.138439</output>
<gadget id="calculator">(48*pi) - (48*sqrt(3))</gadget>
<output>-48*sqrt(3) + 48*pi = around 67.658009</output>
<result>A</result> | A | 68 | Two equilateral triangles of side 12cm are placed one on top of another, such that a 6 pointed star is formed .if the six verticals lie on a circle what is the area of the circle not enclosed by the star ? | {
"A": "68",
"B": "83",
"C": "57",
"D": "61",
"E": "62"
} | subtract(circle_area(divide(multiply(multiply(divide(sqrt(const_3), const_2), 12), const_2), const_3)), multiply(divide(multiply(power(divide(12, const_3), const_2), sqrt(const_3)), const_4), 12)) | divide(n0,const_3)|sqrt(const_3)|divide(#1,const_2)|power(#0,const_2)|multiply(n0,#2)|multiply(#3,#1)|divide(#5,const_4)|multiply(#4,const_2)|divide(#7,const_3)|multiply(n0,#6)|circle_area(#8)|subtract(#10,#9) | area of star = √ 3 / 4 * ( 12 ) ^ 2 + 3 * √ 3 / 4 * ( 12 / 3 ) ^ 2 = 48 √ 3 if r be radius of circle then r = 6 / cos 30 = > r = 12 / √ 3 = > r ^ 2 = 48 area of circle = pi * 48 area of the circle not enclosed by the star = 48 * pi - 48 √ 3 = 48 ( 3.14 - 1.732 ) = 68 ( approax ) answer : a | geometry |
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