id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__mj3ooUT6G3eaHIeu | In the rectangular coordinate system, if the line x = 3y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p? Select the correct option:
A) - 2 B) 0 C) 1 / 2 D) 1 E) 2 / 3 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<result>E</result> | E | 0.666667 | In the rectangular coordinate system, if the line x = 3y + 5 passes through points (m,n) and (m + 2,n + p), what is the value of p? | {
"A": "- 2",
"B": "0",
"C": "1 / 2",
"D": "1",
"E": "2 / 3"
} | divide(2, const_3) | divide(n2,const_3) | x = 3 y + 5 , and thus y = x / 3 - 5 / 3 the slope is 1 / 3 . the slope of a line through points ( m , n ) and ( m + 2 , n + p ) is ( n + p - n ) / ( m + 2 - m ) = p / 2 p / 2 = 1 / 3 and thus p = 2 / 3 the answer is e . | general |
math_qa__GXWkCFLNroqYzmhY | What decimal fraction is 30 ml of a litre ? Choices: A) . 3 B) . 0003 C) . 003 D) 0.03 E) none of these | <gadget id="calculator">30 / 1_000</gadget>
<output>3/100 = around 0.03</output>
<result>D</result> | D | 0.03 | What decimal fraction is 30 ml of a litre ? | {
"A": ". 3",
"B": ". 0003",
"C": ". 003",
"D": "0.03",
"E": "none of these"
} | divide(30, const_1000) | divide(n0,const_1000)| | "answer required fraction = 30 / 1000 = 3 / 100 = . 03 correct option : d" | physics |
math_qa__9cGf4vhQmsrZFWbZ | The average of 10 numbers was calculated as 20. It is discovered later on that while calculating the average, one number, namely 86, was incorrectly read as 26. What is the correct average? Choose the correct choice from the following.
A) 22 B) 23 C) 24 D) 25 E) 26 | <gadget id="calculator">10 * 20</gadget>
<output>200</output>
<gadget id="calculator">86 - 26</gadget>
<output>60</output>
<gadget id="calculator">200 + 60</gadget>
<output>260</output>
<gadget id="calculator">260 / 10</gadget>
<output>26</output>
<result>E</result> | E | 26 | The average of 10 numbers was calculated as 20. It is discovered later on that while calculating the average, one number, namely 86, was incorrectly read as 26. What is the correct average? | {
"A": "22",
"B": "23",
"C": "24",
"D": "25",
"E": "26"
} | divide(add(multiply(10, 20), subtract(86, 26)), 10) | multiply(n0,n1)|subtract(n2,n3)|add(#0,#1)|divide(#2,n0)| | "10 * 20 - 26 + 86 = 260 260 / 10 = 26 the answer is e ." | general |
math_qa__shr1lK5AsraLsEkh | Find the compound interest on $1200 for 3 years at 20% p.a. if CI is component yearly? Choose the correct choice from the following choices.
A) $ 120 B) $ 150 C) $ 874 D) $ 250 E) $ 300 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) ** 3</gadget>
<output>216/125 = around 1.728</output>
<gadget id="calculator">1_200 * (216/125)</gadget>
<output>10_368/5 = around 2_073.6</output>
<gadget id="calculator">(10_368/5) - 1_200</gadget>
<output>4_368/5 = around 873.6</output>
<result>C</result> | C | 874 | Find the compound interest on $1200 for 3 years at 20% p.a. if CI is component yearly? | {
"A": "$ 120",
"B": "$ 150",
"C": "$ 874",
"D": "$ 250",
"E": "$ 300"
} | subtract(multiply(1200, power(add(const_1, divide(20, const_100)), 3)), 1200) | divide(n2,const_100)|add(#0,const_1)|power(#1,n1)|multiply(n0,#2)|subtract(#3,n0)| | "a = p ( 1 + r / 100 ) ^ t = 1200 ( 1 + 20 / 100 ) ^ 3 = $ 2074 ci = $ 874 answer is c" | gain |
math_qa__XOVTogsRUmgVYOhF | A cistern which could be filled in 7 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it? Pick one.
A) 76 hrs
B) 70 / 3 hrs
C) 55 hrs
D) 90 hrs
E) 11 hrs | <gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/7) - (1/10)</gadget>
<output>3/70 = around 0.042857</output>
<gadget id="calculator">1 / (3/70)</gadget>
<output>70/3 = around 23.333333</output>
<result>B</result> | B | 23.333333 | A cistern which could be filled in 7 hours takes one hour more to be filled owing to a leak in its bottom. If the cistern is full in what time will the leak empty it? | {
"A": "76 hrs",
"B": "70 / 3 hrs",
"C": "55 hrs",
"D": "90 hrs",
"E": "11 hrs"
} | inverse(subtract(divide(const_1, 7), divide(const_1, const_10))) | divide(const_1,n0)|divide(const_1,const_10)|subtract(#0,#1)|inverse(#2) | 1 / 7 - 1 / x = 1 / 10 = > 70 / 3 hrs answer : b | physics |
math_qa__KsGr9fERmHe1foi9 | pooja travels from A to B a distance of 800 miles in 10 hours. He returns to A in 5 hours. Find his average speed?
Options
A) 123.07 mph B) 100 mph C) 150.07 mph D) 200 mph E) 300 mph | <gadget id="calculator">800 / 10</gadget>
<output>80</output>
<gadget id="calculator">800 / 5</gadget>
<output>160</output>
<gadget id="calculator">80 + 160</gadget>
<output>240</output>
<gadget id="calculator">240 / 2</gadget>
<output>120</output>
<result>A</result> | A | 123.07 | pooja travels from A to B a distance of 800 miles in 10 hours. He returns to A in 5 hours. Find his average speed? | {
"A": "123.07 mph",
"B": "100 mph",
"C": "150.07 mph",
"D": "200 mph",
"E": "300 mph"
} | divide(add(divide(800, 10), divide(800, 5)), const_2) | divide(n0,n1)|divide(n0,n2)|add(#0,#1)|divide(#2,const_2) | speed from a to b = 800 / 8 = 100 mph speed from b to a = 800 / 5 = 160 mph average speed = 2 * 100 * 160 / 260 = 123.07 mph answer is a | physics |
math_qa__9VoMMg0Fh2cYFORB | Find the simple interest on Rs. 68,000 at 16 2/3% per year for 9 months. Answers:
A) 7500 B) 6500 C) 8500 D) 9500 E) none of them | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 * 100</gadget>
<output>60_000</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 100</gadget>
<output>900</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">900 * 10</gadget>
<output>9_000</output>
<gadget id="calculator">60_000 + 9_000</gadget>
<output>69_000</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">48 + 2</gadget>
<output>50</output>
<gadget id="calculator">50 / 3</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">69_000 * (50/3)</gadget>
<output>1_150_000</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1_150_000 * (3/4)</gadget>
<output>862_500</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">862_500 * (1/100)</gadget>
<output>8_625</output>
<result>C</result> | C | 8,500 | Find the simple interest on Rs. 68,000 at 16 2/3% per year for 9 months. | {
"A": "7500",
"B": "6500",
"C": "8500",
"D": "9500",
"E": "none of them"
} | multiply(multiply(multiply(add(multiply(multiply(multiply(2, 3), const_100), const_100), multiply(multiply(multiply(3, 3), const_100), multiply(add(3, 2), 2))), divide(add(multiply(16, 3), 2), 3)), divide(multiply(3, 3), multiply(2, multiply(2, 3)))), divide(const_1, const_100)) | add(n2,n3)|divide(const_1,const_100)|multiply(n3,n3)|multiply(n2,n3)|multiply(n1,n3)|add(n2,#4)|multiply(n2,#3)|multiply(#3,const_100)|multiply(#2,const_100)|multiply(#0,n2)|divide(#2,#6)|divide(#5,n3)|multiply(#7,const_100)|multiply(#8,#9)|add(#12,#13)|multiply(#14,#11)|multiply(#10,#15)|multiply(#1,#16)| | "p = rs . 68000 , r = 50 / 3 % p . a and t = 9 / 12 years = 3 / 4 years . simple interest = ( p * r * t ) / 100 = rs . ( 68,000 * ( 50 / 3 ) * ( 3 / 4 ) * ( 1 / 100 ) ) = rs . 8500 answer is c ." | gain |
math_qa__DU5ORremOAAeojt3 | When Jessica withdrew $400 from her bank account, her account balance decreased by 2/5. If she deposits an amount equal to 1/4 of the remaining balance, what will be the final balance in her bank account? Choose the correct choice.
A) 300 B) 375 C) 400 D) 500 E) 750 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">1 - (3/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">400 / (2/5)</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 - 400</gadget>
<output>600</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 + (1/4)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">600 * (5/4)</gadget>
<output>750</output>
<result>E</result> | E | 750 | When Jessica withdrew $400 from her bank account, her account balance decreased by 2/5. If she deposits an amount equal to 1/4 of the remaining balance, what will be the final balance in her bank account? | {
"A": "300",
"B": "375",
"C": "400",
"D": "500",
"E": "750"
} | multiply(subtract(divide(400, subtract(const_1, divide(const_3, 5))), 400), add(1, divide(1, 4))) | divide(n3,n4)|divide(const_3,n2)|add(n3,#0)|subtract(const_1,#1)|divide(n0,#3)|subtract(#4,n0)|multiply(#2,#5) | as per the question 400 = 2 a / 5 thus - a which is the total amount = 1000 the amount thus left = 600 she then deposited 1 / 4 of 600 = 150 total amount in her account = 750 answer e | general |
math_qa__vhZwZVeg2VqxDzaF | A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 290 m long? Options.
A) 38 sec B) 35 sec C) 44 sec D) 40 sec E) 52 sec | <gadget id="calculator">290 / 1_000</gadget>
<output>29/100 = around 0.29</output>
<gadget id="calculator">360 / 1_000</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(29/100) + (9/25)</gadget>
<output>13/20 = around 0.65</output>
<gadget id="calculator">(13/20) / 45</gadget>
<output>13/900 = around 0.014444</output>
<gadget id="calculator">(13/900) * 3_600</gadget>
<output>52</output>
<result>E</result> | E | 52 | A train 360 m long runs with a speed of 45 km/hr. What time will it take to pass a platform of 290 m long? | {
"A": "38 sec",
"B": "35 sec",
"C": "44 sec",
"D": "40 sec",
"E": "52 sec"
} | multiply(divide(add(divide(290, const_1000), divide(360, const_1000)), 45), const_3600) | divide(n2,const_1000)|divide(n0,const_1000)|add(#0,#1)|divide(#2,n1)|multiply(#3,const_3600)| | "explanation : speed = 45 km / hr = 45 × ( 10 / 36 ) m / s = 150 / 12 = 50 / 4 = 25 / 2 m / s total distance = length of the train + length of the platform = 360 + 290 = 650 meter time taken to cross the platform = 650 / ( 25 / 2 ) = 650 × 2 / 25 = 52 seconds answer : option e" | physics |
math_qa__rWqoldryCI6Yfm4o | The simple interest on a sum of money will be Rs.900 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year? Answers.
A) 1800 B) 2888 C) 1200 D) 2699 E) 2771 | <gadget id="calculator">900 / 10</gadget>
<output>90</output>
<gadget id="calculator">90 * 5</gadget>
<output>450</output>
<gadget id="calculator">450 * 3</gadget>
<output>1_350</output>
<gadget id="calculator">1_350 + 450</gadget>
<output>1_800</output>
<result>A</result> | A | 1,800 | The simple interest on a sum of money will be Rs.900 after 10 years. If the principal is trebled after 5 years what will be the total interest at the end of the tenth year? | {
"A": "1800",
"B": "2888",
"C": "1200",
"D": "2699",
"E": "2771"
} | add(multiply(multiply(divide(900, 10), 5), const_3), multiply(divide(900, 10), 5)) | divide(n0,n1)|multiply(n2,#0)|multiply(#1,const_3)|add(#2,#1)| | "p - - - 10 - - - - 900 p - - - 5 - - - - - 450 3 p - - - 5 - - - - - 1350 - - - - - - = > 1800 answer : a" | general |
math_qa__od75WcKFhPUmLpZD | A number when divided by 6 leaves a remainder 3. When the square of the same number is divided by 6, the remainder is: Choose the correct choice from the following options.
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">18 / 6</gadget>
<output>3</output>
<result>D</result> | D | 3 | A number when divided by 6 leaves a remainder 3. When the square of the same number is divided by 6, the remainder is: | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | divide(multiply(6, 3), 6) | multiply(n0,n1)|divide(#0,n0) | let x = 6 q + 3 . then , x 2 = ( 6 q + 3 ) 2 = 36 q 2 + 36 q + 9 = 6 ( 6 q 2 + 6 q + 1 ) + 3 . so , when 2 n is divided by 4 , remainder = 3 . answer : d | geometry |
math_qa__U8gr8Q2KK0yc96Pz | What is the sum of all possible solutions to |x - 6|^2 + |x - 6| = 20 ?
Select the correct option.
A) - 1 B) 6 C) 7 D) 12 E) 14 | <gadget id="calculator">4 + 6</gadget>
<output>10</output>
<gadget id="calculator">6 - 4</gadget>
<output>2</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<result>D</result> | D | 12 | What is the sum of all possible solutions to |x - 6|^2 + |x - 6| = 20 ? | {
"A": "- 1",
"B": "6",
"C": "7",
"D": "12",
"E": "14"
} | add(add(const_4, 6), subtract(6, const_4)) | add(n0,const_4)|subtract(n0,const_4)|add(#0,#1) | denote | x - 6 | as y : y ^ 2 + y = 20 - - > y = - 5 or y = 4 . discard the first solution since y = | x - 6 | , so it ' s an absolute value and thus can not be negative . y = | x - 6 | = 4 - - > x = 10 or x = - 2 . the sum = 12 . answer : d . | general |
math_qa__D2dWa7C80br9w49D | How many diagonals does a polygon with 15 sides have, if one of its vertices does not connect to any diagonal? Choose the correct choice from the following answers.
A) 80 B) 90 C) 77 D) 88 E) 99 | <gadget id="calculator">15 - 1</gadget>
<output>14</output>
<gadget id="calculator">14 - 3</gadget>
<output>11</output>
<gadget id="calculator">14 * 11</gadget>
<output>154</output>
<gadget id="calculator">154 / 2</gadget>
<output>77</output>
<result>C</result> | C | 77 | How many diagonals does a polygon with 15 sides have, if one of its vertices does not connect to any diagonal? | {
"A": "80",
"B": "90",
"C": "77",
"D": "88",
"E": "99"
} | divide(multiply(subtract(15, const_1), subtract(subtract(15, const_1), const_3)), const_2) | subtract(n0,const_1)|subtract(#0,const_3)|multiply(#0,#1)|divide(#2,const_2) | if i calculate it using the formulae , # diagonals = n ( n - 3 ) / 2 each vertex sends of n - 3 diagonals n = 15 - 1 then 14 * ( 14 - 3 ) / 2 = 77 correct option : c | geometry |
math_qa__U4QGVdhdI0M2Msst | A hall is 18 meters long and 9 meters wide. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, what is the volume of the hall (in cubic meters)? Choose the correct choice from the following answers
A) 640
B) 758
C) 862
D) 972
E) 1024 | <gadget id="calculator">18 * 9</gadget>
<output>162</output>
<gadget id="calculator">162 * 2</gadget>
<output>324</output>
<gadget id="calculator">2 * (18 + 9)</gadget>
<output>54</output>
<gadget id="calculator">324 / 54</gadget>
<output>6</output>
<gadget id="calculator">18 * 9 * 6</gadget>
<output>972</output>
<result>D</result> | D | 972 | A hall is 18 meters long and 9 meters wide. If the sum of the areas of the floor and the ceiling is equal to the sum of the areas of four walls, what is the volume of the hall (in cubic meters)? | {
"A": "640",
"B": "758",
"C": "862",
"D": "972",
"E": "1024"
} | volume_rectangular_prism(18, 9, divide(multiply(rectangle_area(18, 9), const_2), rectangle_perimeter(18, 9))) | rectangle_area(n0,n1)|rectangle_perimeter(n0,n1)|multiply(#0,const_2)|divide(#2,#1)|volume_rectangular_prism(n0,n1,#3)| | "2 hl + 2 hw = 2 lw h = lw / ( l + w ) volume = lwh = ( lw ) ^ 2 / ( l + w ) = 972 the answer is d ." | geometry |
math_qa__zKNl2tzL45fW3NXa | Truck X is 13 miles ahead of Truck Y, which is traveling the same direction along the same route as Truck X. If Truck X is traveling at an average speed of 47 miles per hour and Truck Y is traveling at an average speed of 53 miles per hour, how long will it take Truck Y to overtake and drive 5 miles ahead of Truck X? Choose one
A) 2 hours B) 2 hours 20 minutes C) 2 hours 30 minutes D) 2 hours 45 minutes E) 3 hours | <gadget id="calculator">13 + 5</gadget>
<output>18</output>
<gadget id="calculator">53 - 47</gadget>
<output>6</output>
<gadget id="calculator">18 / 6</gadget>
<output>3</output>
<result>E</result> | E | 3 | Truck X is 13 miles ahead of Truck Y, which is traveling the same direction along the same route as Truck X. If Truck X is traveling at an average speed of 47 miles per hour and Truck Y is traveling at an average speed of 53 miles per hour, how long will it take Truck Y to overtake and drive 5 miles ahead of Truck X? | {
"A": "2 hours",
"B": "2 hours 20 minutes",
"C": "2 hours 30 minutes",
"D": "2 hours 45 minutes",
"E": "3 hours"
} | divide(add(13, 5), subtract(53, 47)) | add(n0,n3)|subtract(n2,n1)|divide(#0,#1) | relative speed = 53 - 47 = 6 miles per hour dist required = 13 + 5 = 18 miles time taken to overtake = 18 / 6 = 3 hours . e is the answer . | physics |
math_qa__GWSaV2q2gQBF1SDa | How many bricks, each measuring 125 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm?
Choose the correct choice from the following:
A) 1280
B) 2400
C) 5500
D) 7400
E) 3400 | <gadget id="calculator">8 * 100</gadget>
<output>800</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">800 * 600</gadget>
<output>480_000</output>
<gadget id="calculator">480_000 * 22.5</gadget>
<output>10_800_000</output>
<gadget id="calculator">125 * 11.25</gadget>
<output>1_406.25</output>
<gadget id="calculator">1_406.25 * 6</gadget>
<output>8_437.5</output>
<gadget id="calculator">10_800_000 / 8_437.5</gadget>
<output>1_280</output>
<result>A</result> | A | 1,280 | How many bricks, each measuring 125 cm x 11.25 cm x 6 cm, will be needed to build a wall of 8 m x 6 m x 22.5 cm? | {
"A": "1280",
"B": "2400",
"C": "5500",
"D": "7400",
"E": "3400"
} | divide(multiply(multiply(multiply(8, const_100), multiply(6, const_100)), 22.5), multiply(multiply(125, 11.25), 6)) | multiply(n3,const_100)|multiply(n4,const_100)|multiply(n0,n1)|multiply(#0,#1)|multiply(n2,#2)|multiply(n5,#3)|divide(#5,#4)| | "number of bricks = volume of the wall / volume of 1 brick = ( 800 x 600 x 22.5 ) / ( 125 x 11.25 x 6 ) = 1280 answer : a" | physics |
math_qa__fdy9HCjusSs4fnED | The number of boxes in a warehouse can be divided evenly into 5 equal shipments by boat or 24 equal shipments by truck. What is the smallest number of boxes that could be in the warehouse?
Choose the correct option:
A) 27
B) 33
C) 54
D) 81
E) 120 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">24 * 5</gadget>
<output>120</output>
<result>E</result> | E | 120 | The number of boxes in a warehouse can be divided evenly into 5 equal shipments by boat or 24 equal shipments by truck. What is the smallest number of boxes that could be in the warehouse? | {
"A": "27",
"B": "33",
"C": "54",
"D": "81",
"E": "120"
} | multiply(multiply(multiply(multiply(const_2, const_2), const_2), const_3), 5) | multiply(const_2,const_2)|multiply(#0,const_2)|multiply(#1,const_3)|multiply(n0,#2) | answer is the lcm of 5 and 24 = 120 answer e | general |
math_qa__jHTMqrfN41tSi1vk | A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 45, what is the total amount? Choose the correct answer:
A) 166 B) 105 C) 175 D) 177 E) 169 | <gadget id="calculator">100 / 45</gadget>
<output>20/9 = around 2.222222</output>
<gadget id="calculator">(20/9) * 45</gadget>
<output>100</output>
<gadget id="calculator">30 / 45</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 45</gadget>
<output>30</output>
<gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">130 + 45</gadget>
<output>175</output>
<result>C</result> | C | 175 | A sun is divided among X, Y and Z in such a way that for each rupee X gets, Y gets 45 paisa and Z gets 30 paisa. If the share of Y is RS. 45, what is the total amount? | {
"A": "166",
"B": "105",
"C": "175",
"D": "177",
"E": "169"
} | add(add(multiply(divide(const_100, 45), 45), multiply(divide(30, 45), 45)), 45) | divide(const_100,n0)|divide(n1,n0)|multiply(n2,#0)|multiply(n2,#1)|add(#2,#3)|add(n2,#4)| | "x : y : z = 100 : 45 : 30 20 : 9 : 6 9 - - - 45 35 - - - ? = > 175 answer : c" | general |
math_qa__DjAOkqMPU9bO2H6u | Without stoppages, a train travels certain distance with an average speed of 100 km/h, and with stoppages, it covers the same distance with an average speed of 95 km/h. How many minutes per hour the train stops ?
Choose the correct option: A) 1 B) 2 C) 3 D) 4 E) 5 | <gadget id="calculator">95 / 100</gadget>
<output>19/20 = around 0.95</output>
<gadget id="calculator">(19/20) * 60</gadget>
<output>57</output>
<gadget id="calculator">60 - 57</gadget>
<output>3</output>
<result>C</result> | C | 3 | Without stoppages, a train travels certain distance with an average speed of 100 km/h, and with stoppages, it covers the same distance with an average speed of 95 km/h. How many minutes per hour the train stops ? | {
"A": "1",
"B": "2",
"C": "3",
"D": "4",
"E": "5"
} | subtract(const_60, multiply(divide(95, 100), const_60)) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1) | due to stoppages , it covers 5 km less . time taken to cover 5 km = 5 â „ 100 h = 1 â „ 20 h = 1 â „ 20 ã — 60 min = 3 min answer c | physics |
math_qa__4KpHQNGhiHPrVKdl | A tank is 25 m long, 12 m wide and 6 m deep. What is the cost of plastering its walls and bottom at the rate of 75 paise per sq.m?
Choose the correct option.
A) 558 B) 502 C) 516 D) 612 E) 700 | <gadget id="calculator">25 + 12</gadget>
<output>37</output>
<gadget id="calculator">37 * 2</gadget>
<output>74</output>
<gadget id="calculator">74 * 6</gadget>
<output>444</output>
<gadget id="calculator">25 * 12</gadget>
<output>300</output>
<gadget id="calculator">444 + 300</gadget>
<output>744</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">744 * (3/4)</gadget>
<output>558</output>
<result>A</result> | A | 558 | A tank is 25 m long, 12 m wide and 6 m deep. What is the cost of plastering its walls and bottom at the rate of 75 paise per sq.m? | {
"A": "558",
"B": "502",
"C": "516",
"D": "612",
"E": "700"
} | multiply(add(multiply(multiply(add(25, 12), const_2), 6), multiply(25, 12)), divide(75, const_100)) | add(n0,n1)|divide(n3,const_100)|multiply(n0,n1)|multiply(#0,const_2)|multiply(n2,#3)|add(#4,#2)|multiply(#5,#1)| | "total surface s = 2 lw + 2 lh + 2 wh = ( 25 * 12 ) + ( 2 * 25 * 6 ) + ( 2 * 12 * 6 ) = 300 + 300 + 144 = 744 m 2 therefore cost of plastering = 744 * 75 = 5800 paise = 558 answer a" | physics |
math_qa__IhIXuUhZ0YYfq75d | A man swims downstream 36 km and upstream 26 km taking 2 hours each time, what is the speed of the man in still water?
Choose the correct choice from the following options: A) 9 B) 18.4 C) 15.5 D) 16.7 E) 13.4 | <gadget id="calculator">26 / 2</gadget>
<output>13</output>
<gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">13 + 18</gadget>
<output>31</output>
<gadget id="calculator">31 / 2</gadget>
<output>31/2 = around 15.5</output>
<result>C</result> | C | 15.5 | A man swims downstream 36 km and upstream 26 km taking 2 hours each time, what is the speed of the man in still water? | {
"A": "9",
"B": "18.4",
"C": "15.5",
"D": "16.7",
"E": "13.4"
} | divide(add(divide(26, 2), divide(36, 2)), const_2) | divide(n1,n2)|divide(n0,n2)|add(#0,#1)|divide(#2,const_2)| | "36 - - - 2 ds = 18 ? - - - - 1 26 - - - - 2 us = 13 ? - - - - 1 m = ? m = ( 18 + 13 ) / 2 = 15.5 answer : c" | physics |
math_qa__HTObBPQvrg00inmE | A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.19200. A's share is? Choose the correct choice from the following options
A) 8876 B) 2765 C) 6400 D) 1298 E) 1261 | <gadget id="calculator">1 * 12</gadget>
<output>12</output>
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 + 12</gadget>
<output>24</output>
<gadget id="calculator">12 - 8</gadget>
<output>4</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">24 + 12</gadget>
<output>36</output>
<gadget id="calculator">19_200 / 36</gadget>
<output>1_600/3 = around 533.333333</output>
<gadget id="calculator">12 * (1_600/3)</gadget>
<output>6_400</output>
<result>C</result> | C | 6,400 | A, B and C enter into partnership. A invests some money at the beginning, B invests double the amount after 6 months, and C invests thrice the amount after 8 months. If the annual gain be Rs.19200. A's share is? | {
"A": "8876",
"B": "2765",
"C": "6400",
"D": "1298",
"E": "1261"
} | multiply(multiply(const_1, const_12), divide(19200, add(add(multiply(const_1, const_12), multiply(subtract(const_12, 6), const_2)), multiply(subtract(const_12, 8), const_3)))) | multiply(const_1,const_12)|subtract(const_12,n0)|subtract(const_12,n1)|multiply(#1,const_2)|multiply(#2,const_3)|add(#0,#3)|add(#5,#4)|divide(n2,#6)|multiply(#7,#0)| | "x * 12 : 2 x * 6 : 3 x * 4 1 : 1 : 1 1 / 3 * 19200 = 6400 answer : c" | gain |
math_qa__KJbwxVGDjU1IW7wp | A student chose a number, multiplied it by 3, then subtracted 220 from the result and got 110. What was the number he chose?
Pick one:
A) 90 B) 100 C) 110 D) 120 E) 130 | <gadget id="calculator">110 + 220</gadget>
<output>330</output>
<gadget id="calculator">330 / 3</gadget>
<output>110</output>
<result>C</result> | C | 110 | A student chose a number, multiplied it by 3, then subtracted 220 from the result and got 110. What was the number he chose? | {
"A": "90",
"B": "100",
"C": "110",
"D": "120",
"E": "130"
} | divide(add(110, 220), 3) | add(n1,n2)|divide(#0,n0)| | "let x be the number he chose , then 3 ⋅ x − 220 = 110 3 x = 330 x = 110 correct answer c" | general |
math_qa__J7DhcMpMHUpUKxGP | A football field is 7200 square yards. If 1200 pounds of fertilizer are spread evenly across the entire field, how many pounds of fertilizer were spread over an area of the field totaling 3600 square yards?
Choose the correct answer.
A) 450 B) 600 C) 750 D) 2400 E) 3200 | <gadget id="calculator">1_200 / 7_200</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">3_600 * (1/6)</gadget>
<output>600</output>
<result>B</result> | B | 600 | A football field is 7200 square yards. If 1200 pounds of fertilizer are spread evenly across the entire field, how many pounds of fertilizer were spread over an area of the field totaling 3600 square yards? | {
"A": "450",
"B": "600",
"C": "750",
"D": "2400",
"E": "3200"
} | multiply(3600, divide(1200, 7200)) | divide(n1,n0)|multiply(n2,#0)| | "answer a ) 9600 yards need 1200 lbs 1 yard will need 1200 / 7200 = 1 / 6 lbs 3600 yards will need 1 / 6 * 3600 yards = 600 lbs b" | geometry |
math_qa__pUYpGZMHroLSf2Dg | {(476 + 424)2 - 4 x 476 x 424} = ? Pick.
A) 2135 B) 6551 C) 2704 D) 6466 E) 1113 | <gadget id="calculator">476 + 424</gadget>
<output>900</output>
<gadget id="calculator">900 ** 2</gadget>
<output>810_000</output>
<gadget id="calculator">4 * 476</gadget>
<output>1_904</output>
<gadget id="calculator">1_904 * 424</gadget>
<output>807_296</output>
<gadget id="calculator">810_000 - 807_296</gadget>
<output>2_704</output>
<result>C</result> | C | 2,704 | {(476 + 424)2 - 4 x 476 x 424} = ? | {
"A": "2135",
"B": "6551",
"C": "2704",
"D": "6466",
"E": "1113"
} | subtract(power(add(476, 424), 2), multiply(multiply(4, 476), 424)) | add(n0,n1)|multiply(n0,n3)|multiply(n1,#1)|power(#0,n2)|subtract(#3,#2) | given exp . = [ ( a + b ) 2 - 4 ab ] , where a = 476 and b = 424 = [ ( 476 + 424 ) 2 - 4 x 476 x 424 ] = [ ( 900 ) 2 - 807296 ] = 810000 - 807296 = 2704 . correct option is c | general |
math_qa__TkQxQCLkQrgnl7pp | A certain telescope increases the visual range at a particular location from 90 kilometers to 150 kilometers. By what percent is the visual range increased by using the telescope ? Select the correct option.
A) 30 % B) 33 1 / 2 % C) 40 % D) 60 % E) 66 2 / 3 % | <gadget id="calculator">150 - 90</gadget>
<output>60</output>
<gadget id="calculator">60 / 90</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 100</gadget>
<output>200/3 = around 66.666667</output>
<result>E</result> | E | 66 | A certain telescope increases the visual range at a particular location from 90 kilometers to 150 kilometers. By what percent is the visual range increased by using the telescope ? | {
"A": "30 %",
"B": "33 1 / 2 %",
"C": "40 %",
"D": "60 %",
"E": "66 2 / 3 %"
} | multiply(divide(subtract(150, 90), 90), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "original visual range = 90 km new visual range = 150 km percent increase in the visual range by using the telescope = ( 150 - 90 ) / 90 * 100 % = 2 / 3 * 100 % = 66.67 % answer e" | general |
math_qa__sPAMWx7zb3I8bSaE | Bill made a profit of 10% by selling a product. If he had purchased that product for 10% less and sold it at a profit of 30%, he would have received $ 35 more. What was his original selling price?
Choose the correct choice from the following choices.
A) $ 180 B) $ 280 C) $ 420 D) $ 550 E) $ 700 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">(9/10) * (13/10)</gadget>
<output>117/100 = around 1.17</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(117/100) - (11/10)</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">35 / (7/100)</gadget>
<output>500</output>
<gadget id="calculator">500 * (11/10)</gadget>
<output>550</output>
<result>D</result> | D | 550 | Bill made a profit of 10% by selling a product. If he had purchased that product for 10% less and sold it at a profit of 30%, he would have received $ 35 more. What was his original selling price? | {
"A": "$ 180",
"B": "$ 280",
"C": "$ 420",
"D": "$ 550",
"E": "$ 700"
} | multiply(divide(35, subtract(multiply(subtract(const_1, divide(10, const_100)), add(const_1, divide(30, const_100))), add(const_1, divide(10, const_100)))), add(const_1, divide(10, const_100))) | divide(n0,const_100)|divide(n2,const_100)|add(#0,const_1)|add(#1,const_1)|subtract(const_1,#0)|multiply(#3,#4)|subtract(#5,#2)|divide(n3,#6)|multiply(#2,#7)| | "let p be the original purchase price of the product . bill originally sold the product for 1.1 * p . in the second scenario , the purchase price is 0.9 * p . a 30 % profit means the selling price would be 1.3 * 0.9 * p = 1.17 * p thus , according to the information in the question , 1.17 p - 1.1 p = 35 0.07 = 35 p = 500 the original selling price was 500 * 1.1 = 550 . the correct answer is d ." | general |
math_qa__k7CzpGOVqJMoS4sI | A car left town A towards town B driving at a speed of V = 32 km/hr. After 3 hours on the road the driver stopped for 15 min in town C. Because of a closed road he had to change his route, making the trip 28 km longer. He increased his speed to V = 40 km/hr but still he was 30 min late. Find the distance the car has covered.
Pick:
A) 114
B) 115
C) 116
D) 117
E) 118 | <gadget id="calculator">3 * 32</gadget>
<output>96</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<gadget id="calculator">96 + 20</gadget>
<output>116</output>
<result>C</result> | C | 116 | A car left town A towards town B driving at a speed of V = 32 km/hr. After 3 hours on the road the driver stopped for 15 min in town C. Because of a closed road he had to change his route, making the trip 28 km longer. He increased his speed to V = 40 km/hr but still he was 30 min late. Find the distance the car has covered. | {
"A": "114",
"B": "115",
"C": "116",
"D": "117",
"E": "118"
} | add(multiply(const_3, 32), divide(40, const_2)) | divide(n4,const_2)|multiply(n0,const_3)|add(#0,#1) | the driver did not plan the stop at c . suppose it took x hours for him to get from c to b . then the distance is s = 40 ⋅ x km . it took x − 3060 − 1560 = x − 4560 = x − 34 h to drive from c to b . the distance from c to b is 32 ( x − 34 ) km , which is 28 km shorter than 40 ⋅ x , i . e . 32 ( x − 34 ) + 28 = 40 x 32 x − 24 + 28 = 40 x 4 = 8 x x = 12 hr ⋅ x = 30 min . then the time of the trip from c to b was 30 min . the distance covered equals 3 ⋅ 32 + 12 ⋅ 40 = 96 + 20 = 116 km . so answer is c . | physics |
math_qa__LWtGrIQyo1W0lcrT | total num of pupiles in 3 grades of scholl is 333 . the no of pupiles in grades 1 and 2 are un 3:5 ratio and 2 and 3 grades are 7:11 ratio .what is the strength of class that has highest no of pupils Choose the correct choice from the following options
A) 145 B) 155 C) 165 D) 175 E) 185 | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">7 / 11</gadget>
<output>7/11 = around 0.636364</output>
<gadget id="calculator">(3/5) * (7/11)</gadget>
<output>21/55 = around 0.381818</output>
<gadget id="calculator">(21/55) + (7/11)</gadget>
<output>56/55 = around 1.018182</output>
<gadget id="calculator">(56/55) + 1</gadget>
<output>111/55 = around 2.018182</output>
<gadget id="calculator">333 / (111/55)</gadget>
<output>165</output>
<result>C</result> | C | 165 | total num of pupiles in 3 grades of scholl is 333 . the no of pupiles in grades 1 and 2 are un 3:5 ratio and 2 and 3 grades are 7:11 ratio .what is the strength of class that has highest no of pupils | {
"A": "145",
"B": "155",
"C": "165",
"D": "175",
"E": "185"
} | divide(333, add(add(multiply(divide(3, 5), divide(7, 11)), divide(7, 11)), const_1)) | divide(n8,n9)|divide(n0,n5)|multiply(#1,#0)|add(#0,#2)|add(#3,const_1)|divide(n1,#4) | ratio g 1 : g 2 = 3 : 5 and g 2 : g 3 = 7 : 11 so g 1 : g 2 : g 3 = 21 : 35 : 55 let the strength of three classes are 21 x , 35 x and 55 x respectively , then 21 x + 35 x + 55 x = 333 = > 111 x = 333 or x = 3 so strength of the class with highest number of pupils = 55 x = 55 * 3 = 165 answer : c | other |
math_qa__2zLumpAOTUe0ZZXm | A train 150 metres long is moving at a speed of 25 kmph. It will cross a man coming from the opposite direction at a speed of 2 km per hour in :
Options:
A) 20 sec B) 32 sec C) 36 sec D) 38 sec E) 40 sec | <gadget id="calculator">150 / 1_000</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">25 + 2</gadget>
<output>27</output>
<gadget id="calculator">(3/20) / 27</gadget>
<output>1/180 = around 0.005556</output>
<gadget id="calculator">3_600 * (1/180)</gadget>
<output>20</output>
<result>A</result> | A | 20 | A train 150 metres long is moving at a speed of 25 kmph. It will cross a man coming from the opposite direction at a speed of 2 km per hour in : | {
"A": "20 sec",
"B": "32 sec",
"C": "36 sec",
"D": "38 sec",
"E": "40 sec"
} | multiply(const_3600, divide(divide(150, const_1000), add(25, 2))) | add(n1,n2)|divide(n0,const_1000)|divide(#1,#0)|multiply(#2,const_3600) | relative speed = ( 25 + 2 ) km / hr = 27 km / hr = ( 27 × 5 / 18 ) m / sec = 15 / 2 m / sec . time taken by the train to pass the man = ( 150 × 2 / 15 ) sec = 20 sec answer : a | physics |
math_qa__Vcrq08kcGkFRtipO | Initially, the men and women in a room were in the ratio of 4 : 5. Then, 2 men entered the room and 3 women left the room. Then, the number of women doubled. Now there are 14 men in the room. How many D women are currently in the room? Choose the correct choice from the following choices
A) 12 B) 14 C) 15 D) 24 E) 36 | <gadget id="calculator">14 - 2</gadget>
<output>12</output>
<gadget id="calculator">5 * 12</gadget>
<output>60</output>
<gadget id="calculator">60 / 4</gadget>
<output>15</output>
<gadget id="calculator">15 - 3</gadget>
<output>12</output>
<gadget id="calculator">2 * 12</gadget>
<output>24</output>
<result>D</result> | D | 24 | Initially, the men and women in a room were in the ratio of 4 : 5. Then, 2 men entered the room and 3 women left the room. Then, the number of women doubled. Now there are 14 men in the room. How many D women are currently in the room? | {
"A": "12",
"B": "14",
"C": "15",
"D": "24",
"E": "36"
} | multiply(2, subtract(divide(multiply(5, subtract(14, 2)), 4), 3)) | subtract(n4,n2)|multiply(n1,#0)|divide(#1,n0)|subtract(#2,n3)|multiply(n2,#3) | the number of women doubled means that they have become 24 from 12 . . and we have to tell the current strength so 24 is the answer . . let the number be 4 x and 5 x . . given 4 x + 2 = 14 . . so x = 3 . . women number = 5 * 3 - 3 = 12 , then doubled = 24 . . ans d | other |
math_qa__XZokXy4RsLeW0sRR | The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 20% profit? Choose the correct option:
A) 277 B) 960 C) 277 D) 266 E) 768 | <gadget id="calculator">832 - 448</gadget>
<output>384</output>
<gadget id="calculator">384 / 2</gadget>
<output>192</output>
<gadget id="calculator">832 - 192</gadget>
<output>640</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">640 * (6/5)</gadget>
<output>768</output>
<result>E</result> | E | 768 | The profit earned by selling an article for Rs. 832 is equal to the loss incurred when the same article is sold for Rs. 448. What should be the sale price for making 20% profit? | {
"A": "277",
"B": "960",
"C": "277",
"D": "266",
"E": "768"
} | multiply(subtract(832, divide(subtract(832, 448), const_2)), add(const_1, divide(20, const_100))) | divide(n2,const_100)|subtract(n0,n1)|add(#0,const_1)|divide(#1,const_2)|subtract(n0,#3)|multiply(#2,#4)| | "let c . p . = rs . x . then , 832 - x = x - 448 2 x = 1280 = > x = 640 required s . p . = 120 % of rs . 640 = 120 / 100 * 640 = rs . 768 . answer : e" | gain |
math_qa__8rjSEa1jMxhTqLe7 | How many positive integers, from 2 to 100, inclusive, are not divisible by odd integers greater than 1?
Pick: A) 5 B) 6 C) 8 D) 10 E) 50 | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">2 * 8</gadget>
<output>16</output>
<gadget id="calculator">2 * 16</gadget>
<output>32</output>
<gadget id="calculator">32 * 2</gadget>
<output>64</output>
<gadget id="calculator">64 - 4</gadget>
<output>60</output>
<gadget id="calculator">60 / 10</gadget>
<output>6</output>
<result>B</result> | B | 6 | How many positive integers, from 2 to 100, inclusive, are not divisible by odd integers greater than 1? | {
"A": "5",
"B": "6",
"C": "8",
"D": "10",
"E": "50"
} | divide(subtract(multiply(multiply(2, multiply(2, multiply(2, multiply(2, 2)))), 2), const_4), const_10) | multiply(n0,n0)|multiply(n0,#0)|multiply(n0,#1)|multiply(n0,#2)|multiply(n0,#3)|subtract(#4,const_4)|divide(#5,const_10) | the no will be of the form 2 ^ n to achieve this . since any other form will have odd no in the prime factorization . hence we need to find solution of n for equation - 1 < 2 ^ n < 101 . 2 ^ 6 = 64 , 2 ^ 7 - 128 hence n can take values from 1 to 6 . hence answer : b | general |
math_qa__049U8yluvjgwVcOg | A and B finish the job in 15 days.while A,B and C can finish it in 6 days . C alone will finish the job in Options:
A) 10 days B) 30 days C) 60 days D) 70 days E) 50 days | <gadget id="calculator">6 * 15</gadget>
<output>90</output>
<gadget id="calculator">15 - 6</gadget>
<output>9</output>
<gadget id="calculator">90 / 9</gadget>
<output>10</output>
<result>A</result> | A | 10 | A and B finish the job in 15 days.while A,B and C can finish it in 6 days . C alone will finish the job in | {
"A": "10 days",
"B": "30 days",
"C": "60 days",
"D": "70 days",
"E": "50 days"
} | divide(multiply(6, 15), subtract(15, 6)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)| | "explanation : 6 = ( 15 * x ) / ( 15 + x ) 90 + 6 x = 15 x 9 x = 90 x = 10 answer : option a" | physics |
math_qa__MDUzdMP2edTLh1qu | Find avrg speed if a man travels at speed of 16km/hr up and 30km/hr dawn at an altitude of 200m. Choose the correct choice: A) 22.8 B) 21.8 C) 20.8 D) 28.8 E) 29.8 | <gadget id="calculator">2 * 16</gadget>
<output>32</output>
<gadget id="calculator">32 * 30</gadget>
<output>960</output>
<gadget id="calculator">16 + 30</gadget>
<output>46</output>
<gadget id="calculator">960 / 46</gadget>
<output>480/23 = around 20.869565</output>
<result>C</result> | C | 20.8 | Find avrg speed if a man travels at speed of 16km/hr up and 30km/hr dawn at an altitude of 200m. | {
"A": "22.8",
"B": "21.8",
"C": "20.8",
"D": "28.8",
"E": "29.8"
} | divide(multiply(multiply(const_2, 16), 30), add(16, 30)) | add(n0,n1)|multiply(n0,const_2)|multiply(n1,#1)|divide(#2,#0)| | "avg speed = 2 * x * y / ( x + y ) = 2 * 16 * 30 / ( 16 + 30 ) = 20.8 answer : c" | physics |
math_qa__ZL1eNQo7nfdItX9W | Find the sum The difference between the compound and S.I. on a certain sum of money for 2 years at 10% per annum is Rs.20 of money? Select:
A) 1500
B) 1992
C) 9921
D) 2798
E) 2000 | <gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">20 / 20</gadget>
<output>1</output>
<gadget id="calculator">1 * 100</gadget>
<output>100</output>
<gadget id="calculator">100 * 20</gadget>
<output>2_000</output>
<result>E</result> | E | 2,000 | Find the sum The difference between the compound and S.I. on a certain sum of money for 2 years at 10% per annum is Rs.20 of money? | {
"A": "1500",
"B": "1992",
"C": "9921",
"D": "2798",
"E": "2000"
} | multiply(multiply(divide(20, multiply(10, 2)), const_100), multiply(10, 2)) | multiply(n0,n1)|divide(n2,#0)|multiply(#1,const_100)|multiply(#2,#0)| | "p = 20 ( 100 / 10 ) 2 = > p = 2000 answer : e" | general |
math_qa__onL1j7aHqCHbYejm | Find the least number must be added to 433124 so that remaining no.is divisible by 17? Choose the correct choice from the following: A) 3 B) 2 C) 5 D) 6 E) 1 | <gadget id="calculator">433_124 % 17</gadget>
<output>15</output>
<gadget id="calculator">17 - 15</gadget>
<output>2</output>
<result>B</result> | B | 2 | Find the least number must be added to 433124 so that remaining no.is divisible by 17? | {
"A": "3",
"B": "2",
"C": "5",
"D": "6",
"E": "1"
} | subtract(17, reminder(433124, 17)) | reminder(n0,n1)|subtract(n1,#0)| | "on dividing 433124 by 17 we get the remainder 15 , so 2 should be added b" | general |
math_qa__1KZd4bUWhbFO9zVA | A, B and C completed a piece of work, A worked for 6 days, B for 9 days and C for 4 days. Their daily wages were in the ratio of 3:4:5. Find the daily wages of C, if their total earning was Rs.1554?
Choose one.
A) s . 109
B) s . 108
C) s . 100
D) s . 103
E) s . 105 | <gadget id="calculator">6 * 3</gadget>
<output>18</output>
<gadget id="calculator">9 * 4</gadget>
<output>36</output>
<gadget id="calculator">18 + 36</gadget>
<output>54</output>
<gadget id="calculator">4 * 5</gadget>
<output>20</output>
<gadget id="calculator">54 + 20</gadget>
<output>74</output>
<gadget id="calculator">1_554 / 74</gadget>
<output>21</output>
<gadget id="calculator">5 * 21</gadget>
<output>105</output>
<result>E</result> | E | 105 | A, B and C completed a piece of work, A worked for 6 days, B for 9 days and C for 4 days. Their daily wages were in the ratio of 3:4:5. Find the daily wages of C, if their total earning was Rs.1554? | {
"A": "s . 109",
"B": "s . 108",
"C": "s . 100",
"D": "s . 103",
"E": "s . 105"
} | multiply(5, divide(1554, add(add(multiply(6, 3), multiply(9, 4)), multiply(4, 5)))) | multiply(n0,n3)|multiply(n1,n2)|multiply(n2,n5)|add(#0,#1)|add(#3,#2)|divide(n6,#4)|multiply(n5,#5)| | "3 x 4 x 5 x 6 9 4 18 x + 36 x + 20 x = 1554 74 x = 1554 = > x = 21 5 x = 105 rs . answer : e" | physics |
math_qa__o10yc24gaekERQIJ | The average weight of 25 girls increases by 1 kg when a new girl comes in place of one of them weighing 55 kg. What might be the weight of the new girl? Choose the correct choice from the following choices:
A) 85 kg B) 90 kg C) 83 kg D) 80 kg E) 82 kg | <gadget id="calculator">25 * 1</gadget>
<output>25</output>
<gadget id="calculator">25 + 55</gadget>
<output>80</output>
<result>D</result> | D | 80 | The average weight of 25 girls increases by 1 kg when a new girl comes in place of one of them weighing 55 kg. What might be the weight of the new girl? | {
"A": "85 kg",
"B": "90 kg",
"C": "83 kg",
"D": "80 kg",
"E": "82 kg"
} | add(multiply(25, 1), 55) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = 25 x 1 kg = 25 kg . weight of new person = 55 + 25 kg = 80 kg answer : d" | general |
math_qa__JeDNFwgDOIOJ7MZ9 | The average salary of the employees in a office is Rs.120/month.The avg salary of officers is Rs.470 and of non officers is Rs 110. If the no.of officers is 15,then find the No of nonofficers in the office. Choose the correct choice from the following options:
A) 400
B) 420
C) 430
D) 450
E) 525 | <gadget id="calculator">15 * 470</gadget>
<output>7_050</output>
<gadget id="calculator">15 * 120</gadget>
<output>1_800</output>
<gadget id="calculator">7_050 - 1_800</gadget>
<output>5_250</output>
<gadget id="calculator">120 - 110</gadget>
<output>10</output>
<gadget id="calculator">5_250 / 10</gadget>
<output>525</output>
<result>E</result> | E | 525 | The average salary of the employees in a office is Rs.120/month.The avg salary of officers is Rs.470 and of non officers is Rs 110. If the no.of officers is 15,then find the No of nonofficers in the office. | {
"A": "400",
"B": "420",
"C": "430",
"D": "450",
"E": "525"
} | divide(subtract(multiply(15, 470), multiply(15, 120)), subtract(120, 110)) | multiply(n1,n3)|multiply(n0,n3)|subtract(n0,n2)|subtract(#0,#1)|divide(#3,#2)| | "let no . of non - officers be x 15 * 470 + x * 110 = ( x + 15 ) 120 x = 525 e" | general |
math_qa__btYfnNaRx9HBvVVK | Find the least number which when divided by 31 and 9 leaves a remainder of 3 in each case. Choose the correct choice from the following answers: A) 280 B) 282 C) 284 D) 286 E) 288 | <gadget id="calculator">lcm(31, 9)</gadget>
<output>279</output>
<gadget id="calculator">3 + 279</gadget>
<output>282</output>
<result>B</result> | B | 282 | Find the least number which when divided by 31 and 9 leaves a remainder of 3 in each case. | {
"A": "280",
"B": "282",
"C": "284",
"D": "286",
"E": "288"
} | add(3, lcm(31, 9)) | lcm(n0,n1)|add(n2,#0)| | "the least number which when divided by different divisors leaving the same remainder in each case = lcm ( different divisors ) + remainder left in each case . hence the required least number = lcm ( 31 , 9 ) + 3 = 282 . answer : b" | general |
math_qa__AJIScytMYOn9x898 | Two train each 500 m long, are running in opposite directions on parallel tracks. If their speeds are 45 km/hr and 30 km/hr respectively, the time taken by the slower train to pass the driver of the faster one is? Choose the correct choice from the following
A) 20 s
B) 24 s
C) 22 s
D) 23 s
E) 21 s | <gadget id="calculator">45 + 30</gadget>
<output>75</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">75 * (5/18)</gadget>
<output>125/6 = around 20.833333</output>
<gadget id="calculator">500 / (125/6)</gadget>
<output>24</output>
<result>B</result> | B | 24 | Two train each 500 m long, are running in opposite directions on parallel tracks. If their speeds are 45 km/hr and 30 km/hr respectively, the time taken by the slower train to pass the driver of the faster one is? | {
"A": "20 s",
"B": "24 s",
"C": "22 s",
"D": "23 s",
"E": "21 s"
} | divide(500, multiply(add(45, 30), const_0_2778)) | add(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1) | relative speed = 45 + 30 = 75 km / hr = 750 / 36 m / s = 125 / 6 m / s we are calculating the time taken by the slower train to pass the driver of the faster one . hence the distance = length of the smaller train = 500 m time = distance / speed = 500 / ( 125 / 6 ) = 24 s answer is b . | physics |
math_qa__MM57bM8lFMHQ5ZA2 | Mohit sold an article for $21000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article? Choose the correct choice from the following answers: A) 16000 B) 25000 C) 15000 D) 18000 E) 17500 | <gadget id="calculator">21_000 * 10</gadget>
<output>210_000</output>
<gadget id="calculator">210_000 / 100</gadget>
<output>2_100</output>
<gadget id="calculator">21_000 - 2_100</gadget>
<output>18_900</output>
<gadget id="calculator">100 + 8</gadget>
<output>108</output>
<gadget id="calculator">18_900 / 108</gadget>
<output>175</output>
<gadget id="calculator">175 * 100</gadget>
<output>17_500</output>
<result>E</result> | E | 17,500 | Mohit sold an article for $21000. Had he offered a discount of 10% on the selling price, he would have earned a profit of 8%. What is the cost price of the article? | {
"A": "16000",
"B": "25000",
"C": "15000",
"D": "18000",
"E": "17500"
} | multiply(divide(subtract(21000, divide(multiply(21000, 10), const_100)), add(const_100, 8)), const_100) | add(n2,const_100)|multiply(n0,n1)|divide(#1,const_100)|subtract(n0,#2)|divide(#3,#0)|multiply(#4,const_100)| | "let the cp be $ x . had he offered 10 % discount , profit = 8 % profit = 8 / 100 x and hence his sp = x + 8 / 100 x = $ 1.08 x = 21000 - 10 / 100 ( 21000 ) = 21000 - 2100 = $ 18900 = > 1.08 x = 18900 = > x = 17500 e" | gain |
math_qa__VXz1jx3AOW0xQ1lt | A shopkeeper cheats to the extent of 10% while buying and selling, by using false weights. His total gain is. Choices
A) 22 B) 21 C) 8 D) 9 E) 81 | <gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<result>B</result> | B | 21 | A shopkeeper cheats to the extent of 10% while buying and selling, by using false weights. His total gain is. | {
"A": "22",
"B": "21",
"C": "8",
"D": "9",
"E": "81"
} | add(multiply(10, const_2), const_1) | multiply(n0,const_2)|add(#0,const_1) | answer : b ) 21 % | gain |
math_qa__qLcXkRR7zfAvRDAp | The number of singles that a baseball player hit increased 15 percent from her first season to her second season, and the number of doubles that she hit in the same time period decreased by 5 percent. If the total number of singles and doubles that she hit increased 4 percent from her first season to her second season, what is the ratio of the number of singles she hit in her first season to the number of doubles she hit in her first season? Pick one
A) 3 : 5
B) 5 : 7
C) 7 : 11
D) 9 : 11
E) 11 : 15 | <gadget id="calculator">100 - 5</gadget>
<output>95</output>
<gadget id="calculator">100 + 15</gadget>
<output>115</output>
<gadget id="calculator">95 / 115</gadget>
<output>19/23 = around 0.826087</output>
<result>D</result> | D | 0.818182 | The number of singles that a baseball player hit increased 15 percent from her first season to her second season, and the number of doubles that she hit in the same time period decreased by 5 percent. If the total number of singles and doubles that she hit increased 4 percent from her first season to her second season, what is the ratio of the number of singles she hit in her first season to the number of doubles she hit in her first season? | {
"A": "3 : 5",
"B": "5 : 7",
"C": "7 : 11",
"D": "9 : 11",
"E": "11 : 15"
} | divide(subtract(const_100, 5), add(const_100, 15)) | add(n0,const_100)|subtract(const_100,n1)|divide(#1,#0) | soln : - 1.15 s + 0.95 d = 1.04 [ s + d ] 0.11 s = 0.09 d s / d = 9 / 11 answer : d | general |
math_qa__8QW1xqCVqilDNZWC | the average of first 6 prime numbers which are between 60 and 90 is Select the correct option:
A) 35.4 B) 42 C) 45.7 D) 57 E) 72.33 | <gadget id="calculator">60 + 3</gadget>
<output>63</output>
<gadget id="calculator">63 + 4</gadget>
<output>67</output>
<gadget id="calculator">67 + 4</gadget>
<output>71</output>
<result>E</result> | E | 72.33 | the average of first 6 prime numbers which are between 60 and 90 is | {
"A": "35.4",
"B": "42",
"C": "45.7",
"D": "57",
"E": "72.33"
} | add(add(add(60, const_3), const_4), const_4) | add(n1,const_3)|add(#0,const_4)|add(#1,const_4) | explanation : first six prime numbers which are between 60 and 90 = 61 , 67 , 71 , 73 , 79 , 83 average = ( 61 + 67 + 71 + 73 + 79 + 83 ) / 6 = 72.33 answer : e | general |
math_qa__NJySE9sTM6b9Q6hC | A rectangular grass field is 95 m * 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m? Select:
A) 1350
B) 1550
C) 9676
D) 1679
E) 2691 | <gadget id="calculator">2.5 * 2</gadget>
<output>5</output>
<gadget id="calculator">95 + 5</gadget>
<output>100</output>
<gadget id="calculator">55 + 5</gadget>
<output>60</output>
<gadget id="calculator">100 * 60</gadget>
<output>6_000</output>
<gadget id="calculator">95 * 55</gadget>
<output>5_225</output>
<gadget id="calculator">6_000 - 5_225</gadget>
<output>775</output>
<gadget id="calculator">775 * 2</gadget>
<output>1_550</output>
<result>B</result> | B | 1,550 | A rectangular grass field is 95 m * 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m? | {
"A": "1350",
"B": "1550",
"C": "9676",
"D": "1679",
"E": "2691"
} | multiply(subtract(rectangle_area(add(95, multiply(2.5, 2)), add(55, multiply(2.5, 2))), rectangle_area(95, 55)), 2) | multiply(n2,n3)|rectangle_area(n0,n1)|add(n0,#0)|add(n1,#0)|rectangle_area(#2,#3)|subtract(#4,#1)|multiply(n3,#5)| | "area = ( l + b + 2 d ) 2 d = ( 95 + 55 + 2.5 * 2 ) 2 * 2.5 = > 775 775 * 2 = rs . 1550 answer : b" | geometry |
math_qa__UetSPTTDSUgW7P3F | The sale price sarees listed for Rs.350 after successive discount is 20% and 5% is? Select:
A) 266
B) 278
C) 342
D) 787
E) 191 | <gadget id="calculator">350 * 20</gadget>
<output>7_000</output>
<gadget id="calculator">7_000 / 100</gadget>
<output>70</output>
<gadget id="calculator">350 - 70</gadget>
<output>280</output>
<gadget id="calculator">280 * 5</gadget>
<output>1_400</output>
<gadget id="calculator">1_400 / 100</gadget>
<output>14</output>
<gadget id="calculator">280 - 14</gadget>
<output>266</output>
<result>A</result> | A | 266 | The sale price sarees listed for Rs.350 after successive discount is 20% and 5% is? | {
"A": "266",
"B": "278",
"C": "342",
"D": "787",
"E": "191"
} | subtract(subtract(350, divide(multiply(350, 20), const_100)), divide(multiply(subtract(350, divide(multiply(350, 20), const_100)), 5), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "350 * ( 80 / 100 ) * ( 95 / 100 ) = 266 answer : a" | gain |
math_qa__CIPhmUw8Xd8Ef4dc | A train is 360 meter long is running at a speed of 56 km/hour. In what time will it pass a bridge of 140 meter length. Choose the correct choice: A) 20.14 seconds B) 12.14 seconds C) 22.14 seconds D) 32.14 seconds E) none of these | <gadget id="calculator">360 + 140</gadget>
<output>500</output>
<gadget id="calculator">56 * 1_000</gadget>
<output>56_000</output>
<gadget id="calculator">56_000 / 3_600</gadget>
<output>140/9 = around 15.555556</output>
<gadget id="calculator">500 / (140/9)</gadget>
<output>225/7 = around 32.142857</output>
<result>D</result> | D | 32.14 | A train is 360 meter long is running at a speed of 56 km/hour. In what time will it pass a bridge of 140 meter length. | {
"A": "20.14 seconds",
"B": "12.14 seconds",
"C": "22.14 seconds",
"D": "32.14 seconds",
"E": "none of these"
} | divide(add(360, 140), divide(multiply(56, const_1000), const_3600)) | add(n0,n2)|multiply(n1,const_1000)|divide(#1,const_3600)|divide(#0,#2)| | "explanation : speed = 56 km / hr = 56 * ( 5 / 18 ) m / sec = 140 / 9 m / sec total distance = 360 + 140 = 500 meter time = distance / speed = 500 / 140 / 9 = 32.14 seconds answer : d" | physics |
math_qa__1iPuhGvRrIrS2JuH | A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.1100, what is the reduced price for kg?
Choose the correct choice from the following choices
A) s . 40 B) s . 46 C) s . 55 D) s . 41 E) s . 42 | <gadget id="calculator">1_100 * 25</gadget>
<output>27_500</output>
<gadget id="calculator">27_500 / 100</gadget>
<output>275</output>
<gadget id="calculator">275 / 5</gadget>
<output>55</output>
<result>C</result> | C | 55 | A reduction of 25% in the price of oil enables a house wife to obtain 5kgs more for Rs.1100, what is the reduced price for kg? | {
"A": "s . 40",
"B": "s . 46",
"C": "s . 55",
"D": "s . 41",
"E": "s . 42"
} | divide(divide(multiply(1100, 25), const_100), 5) | multiply(n0,n2)|divide(#0,const_100)|divide(#1,n1)| | "800 * ( 25 / 100 ) = 275 - - - - 5 ? - - - - 1 = > rs . 55 answer : c" | gain |
math_qa__cwVuxKRa5ooohsiK | in a college , 280 students study hindi , 254 students study sanskrit and 280 students study english . 97 students study hindi as well as physics , 138 students study sanskrit as well as english and 152 students study hindi as well as english . 73 students study all the 3 languages . how many total number of students are there in that college ?
Choose the correct choice from the following answers.
A) 350 B) 500 C) 650 D) 235 E) 450 | <gadget id="calculator">280 + 254</gadget>
<output>534</output>
<gadget id="calculator">534 + 280</gadget>
<output>814</output>
<gadget id="calculator">814 - 97</gadget>
<output>717</output>
<gadget id="calculator">717 - 138</gadget>
<output>579</output>
<gadget id="calculator">579 - 152</gadget>
<output>427</output>
<gadget id="calculator">427 + 73</gadget>
<output>500</output>
<result>B</result> | B | 500 | in a college , 280 students study hindi , 254 students study sanskrit and 280 students study english . 97 students study hindi as well as physics , 138 students study sanskrit as well as english and 152 students study hindi as well as english . 73 students study all the 3 languages . how many total number of students are there in that college ? | {
"A": "350",
"B": "500",
"C": "650",
"D": "235",
"E": "450"
} | add(subtract(subtract(subtract(add(add(280, 254), 280), 97), 138), 152), 73) | add(n0,n1)|add(n0,#0)|subtract(#1,n3)|subtract(#2,n4)|subtract(#3,n5)|add(n6,#4) | b | general |
math_qa__4ibIhzmpRNQCsgYl | 20 men shake hands with each other. Maximum no of handshakes without cyclic handshakes. Choose the correct choice from the following choices:
A) 190
B) 200
C) 210
D) 220
E) 230 | <gadget id="calculator">20 - 1</gadget>
<output>19</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">19 * 10</gadget>
<output>190</output>
<result>A</result> | A | 190 | 20 men shake hands with each other. Maximum no of handshakes without cyclic handshakes. | {
"A": "190",
"B": "200",
"C": "210",
"D": "220",
"E": "230"
} | multiply(subtract(20, const_1), divide(20, const_2)) | divide(n0,const_2)|subtract(n0,const_1)|multiply(#0,#1)| | "1 st person will shake hand with 19 people 2 nd person will shake hand with 18 people 3 rd person will shake hand with 17 people . . . . . . total no . of handshakes = 19 + 18 + 17 + . . . + 3 + 2 + 1 = 19 * ( 19 + 1 ) / 2 = 190 or , if there are n persons then no . of shakehands = nc 2 = 20 c 2 = 190 answer : a" | general |
math_qa__l1qecKLctk0Wgxz9 | A and B complete a work in 8 days. A alone can do it in 16 days. If both together can do the work in how many days? Choose the correct answer.
A) 3.75 days B) 3.78 days C) 5.3 days D) 3.15 days E) 2.75 days | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 16</gadget>
<output>1/16 = around 0.0625</output>
<gadget id="calculator">(1/8) + (1/16)</gadget>
<output>3/16 = around 0.1875</output>
<gadget id="calculator">1 / (3/16)</gadget>
<output>16/3 = around 5.333333</output>
<result>C</result> | C | 5.3 | A and B complete a work in 8 days. A alone can do it in 16 days. If both together can do the work in how many days? | {
"A": "3.75 days",
"B": "3.78 days",
"C": "5.3 days",
"D": "3.15 days",
"E": "2.75 days"
} | inverse(add(inverse(8), inverse(16))) | inverse(n0)|inverse(n1)|add(#0,#1)|inverse(#2)| | "1 / 8 + 1 / 16 = 3 / 16 16 / 3 = 5.3 days answer : c" | physics |
math_qa__vDXghXmUxGzwk5zy | Suppose 8 monkeys take 8 minutes to eat 8 bananas. How many monkeys would it take to eat 48 bananas in 48 minutes Choose the correct choice from the following options:
A) 5 monkeys B) 6 monkeys C) 7 monkeys D) 8 monkeys E) 9 monkeys | <gadget id="calculator">48 / 8</gadget>
<output>6</output>
<gadget id="calculator">48 / 6</gadget>
<output>8</output>
<result>D</result> | D | 8 | Suppose 8 monkeys take 8 minutes to eat 8 bananas. How many monkeys would it take to eat 48 bananas in 48 minutes | {
"A": "5 monkeys",
"B": "6 monkeys",
"C": "7 monkeys",
"D": "8 monkeys",
"E": "9 monkeys"
} | divide(48, divide(48, 8)) | divide(n3,n0)|divide(n3,#0)| | "8 monkeys take 8 minutes to eat 8 bananas means each monkey takes 8 min for 1 banana in 48 mins one monkey can eat 6 bananas . . . . which means that 8 monkeys can eat 48 bananas in 48 minutes so answer is 8 monkeys answer : d" | physics |
math_qa__Q1pQOjEBmXyejTl3 | A certain company has records stored with a record storage firm in 15-inch by 12-inch by 10-inch boxes. The boxes occupy 1.08 million cubic inches of space. If the company pays $0.2 per box per month for the record storage, what is the total amount that the company pays each month for record storage? Choose the correct answer.
A) a . 150
B) b . 300
C) c . 600
D) d . 120
E) e . 200 | <gadget id="calculator">15 * 12</gadget>
<output>180</output>
<gadget id="calculator">180 * 10</gadget>
<output>1_800</output>
<gadget id="calculator">1_800 / 100</gadget>
<output>18</output>
<gadget id="calculator">18 / 100</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">(9/50) / 100</gadget>
<output>9/5_000 = around 0.0018</output>
<gadget id="calculator">1.08 / (9/5_000)</gadget>
<output>600</output>
<gadget id="calculator">0.2 * 600</gadget>
<output>120</output>
<result>D</result> | D | 120 | A certain company has records stored with a record storage firm in 15-inch by 12-inch by 10-inch boxes. The boxes occupy 1.08 million cubic inches of space. If the company pays $0.2 per box per month for the record storage, what is the total amount that the company pays each month for record storage? | {
"A": "a . 150",
"B": "b . 300",
"C": "c . 600",
"D": "d . 120",
"E": "e . 200"
} | multiply(0.2, divide(1.08, divide(divide(divide(multiply(multiply(15, 12), 10), const_100), const_100), const_100))) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,const_100)|divide(#2,const_100)|divide(#3,const_100)|divide(n3,#4)|multiply(n4,#5) | volume per box : 15 x 12 x 10 = 1,800 total volume : 1 , 080,000 number of boxes : total volume / volume per box = 1 , 080,000 / 1,800 = 600 price per month : number of boxes * price per box = 600 * 0.2 = 120 answer : d | general |
math_qa__hVYjYZTlRqr8398w | Two employees X and Y are paid a total of Rs. 528 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Select:
A) s . 250
B) s . 280
C) s . 290
D) s . 299
E) s . 240 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">528 * 10</gadget>
<output>5_280</output>
<gadget id="calculator">10 + 1</gadget>
<output>11</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">5_280 / 22</gadget>
<output>240</output>
<result>E</result> | E | 240 | Two employees X and Y are paid a total of Rs. 528 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week? | {
"A": "s . 250",
"B": "s . 280",
"C": "s . 290",
"D": "s . 299",
"E": "s . 240"
} | divide(multiply(528, multiply(add(const_1, const_4), const_2)), multiply(add(multiply(add(const_1, const_4), const_2), const_1), const_2)) | add(const_1,const_4)|multiply(#0,const_2)|add(#1,const_1)|multiply(n0,#1)|multiply(#2,const_2)|divide(#3,#4)| | "let the amount paid to x per week = x and the amount paid to y per week = y then x + y = 528 but x = 120 % of y = 120 y / 100 = 12 y / 10 ∴ 12 y / 10 + y = 528 ⇒ y [ 12 / 10 + 1 ] = 528 ⇒ 22 y / 10 = 528 ⇒ 22 y = 5280 ⇒ y = 5280 / 22 = 480 / 2 = rs . 240 e" | general |
math_qa__q3aSAViG3SPaIG8i | 8 identical machines, working alone and at their constant rates, take 6 hours to complete a job lot. How long would it take for 2 such machines to perform the same job? Choose the most appropriate option:
A) 2.25 hours B) 8.75 hours C) 12 hours D) 24 hours E) 16 hours | <gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">48 / 2</gadget>
<output>24</output>
<result>D</result> | D | 24 | 8 identical machines, working alone and at their constant rates, take 6 hours to complete a job lot. How long would it take for 2 such machines to perform the same job? | {
"A": "2.25 hours",
"B": "8.75 hours",
"C": "12 hours",
"D": "24 hours",
"E": "16 hours"
} | divide(multiply(6, 8), 2) | multiply(n0,n1)|divide(#0,n2)| | "let each machine do 1 unit of work for 1 hour 8 machines - - > 8 units of work in 1 hour for 6 hours = 8 * 6 = 48 units of total work is done . now this 48 units of total work must be done by 2 machines 2 units of work ( 2 machines ) - - - > 1 hour for 48 units of work 2 * 24 - - - > 1 * 24 hours d 24 hours" | physics |
math_qa__cBHyueBR4qNkFkqa | In a Lake, there is a patch of lily pads. Every day, the patch doubles in size. It takes 50 days for the patch to cover the entire lake, how many days would it take the patch to cover half of the lake? Pick:
A) 36 B) 2 ^ 4 * 3 C) 24 D) 49 E) 47 | <gadget id="calculator">50 - 1</gadget>
<output>49</output>
<result>D</result> | D | 49 | In a Lake, there is a patch of lily pads. Every day, the patch doubles in size. It takes 50 days for the patch to cover the entire lake, how many days would it take the patch to cover half of the lake? | {
"A": "36",
"B": "2 ^ 4 * 3",
"C": "24",
"D": "49",
"E": "47"
} | subtract(50, const_1) | subtract(n0,const_1)| | "working backward from the day it ' s covered : day 50 : fully covered day 49 : half covered so 49 days answer : d" | physics |
math_qa__WpRYBF2o0lIyLtuc | Fox jeans regularly sell for $15 a pair and Pony jeans regularly sell for $18 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $8.64 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discount rates is 22 percent, what is the discount rate on Pony jeans? Choose one
A) 8 %
B) 10 %
C) 11 %
D) 12 %
E) 14 % | <gadget id="calculator">22 / 100</gadget>
<output>11/50 = around 0.22</output>
<gadget id="calculator">18 * 2</gadget>
<output>36</output>
<gadget id="calculator">(11/50) * 36</gadget>
<output>198/25 = around 7.92</output>
<gadget id="calculator">8.64 - (198/25)</gadget>
<output>0.72</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">45 - 36</gadget>
<output>9</output>
<gadget id="calculator">0.72 / 9</gadget>
<output>0.08</output>
<gadget id="calculator">(11/50) - 0.08</gadget>
<output>0.14</output>
<gadget id="calculator">0.14 * 100</gadget>
<output>14</output>
<result>E</result> | E | 14 | Fox jeans regularly sell for $15 a pair and Pony jeans regularly sell for $18 a pair. During a sale these regular unit prices are discounted at different rates so that a total of $8.64 is saved by purchasing 5 pairs of jeans: 3 pairs of Fox jeans and 2 pairs of Pony jeans. If the sum of the two discount rates is 22 percent, what is the discount rate on Pony jeans? | {
"A": "8 %",
"B": "10 %",
"C": "11 %",
"D": "12 %",
"E": "14 %"
} | multiply(subtract(divide(22, const_100), divide(subtract(8.64, multiply(divide(22, const_100), multiply(18, const_2))), subtract(multiply(15, const_3), multiply(18, const_2)))), const_100) | divide(n6,const_100)|multiply(n1,const_2)|multiply(n0,const_3)|multiply(#0,#1)|subtract(#2,#1)|subtract(n2,#3)|divide(#5,#4)|subtract(#0,#6)|multiply(#7,const_100) | let x be the discount on pony jeans . then 0.22 - x is the discount on fox jeans . 3 ( 0.22 - x ) ( 15 ) + 2 x ( 18 ) = 8.64 9.9 - 45 x + 36 x = 8.64 9 x = 1.26 x = 0.14 the answer is e . | gain |
math_qa__vIBRcQC9MekFY6Vq | The perimeter of a triangle is 36 cm and the in radius of the triangle is 2.5 cm. What is the area of the triangle?
Pick:
A) 38 cm 2 B) 27 cm 2 C) 45 cm 2 D) 25 cm 2 E) 35 cm 2 | <gadget id="calculator">(2.5 * 36) / 2</gadget>
<output>45</output>
<result>C</result> | C | 45 | The perimeter of a triangle is 36 cm and the in radius of the triangle is 2.5 cm. What is the area of the triangle? | {
"A": "38 cm 2",
"B": "27 cm 2",
"C": "45 cm 2",
"D": "25 cm 2",
"E": "35 cm 2"
} | triangle_area(2.5, 36) | triangle_area(n0,n1)| | "area of a triangle = r * s where r is the inradius and s is the semi perimeter of the triangle . area of triangle = 2.5 * 36 / 2 = 45 cm 2 answer : c" | geometry |
math_qa__q7SUb96tysl8TadR | Sum of the squares of 3 no.'s is 222 and the sum of their products taken two at a time is 131. Find the sum?
Choose the correct choice from the following choices
A) 22 B) 24 C) 26 D) 28 E) 30 | <gadget id="calculator">131 * 2</gadget>
<output>262</output>
<gadget id="calculator">262 + 222</gadget>
<output>484</output>
<gadget id="calculator">484 ** (1/2)</gadget>
<output>22</output>
<result>A</result> | A | 22 | Sum of the squares of 3 no.'s is 222 and the sum of their products taken two at a time is 131. Find the sum? | {
"A": "22",
"B": "24",
"C": "26",
"D": "28",
"E": "30"
} | sqrt(add(multiply(131, const_2), 222)) | multiply(n2,const_2)|add(n1,#0)|sqrt(#1)| | "( a + b + c ) 2 = a 2 + b 2 + c 2 + 2 ( ab + bc + ca ) = 222 + 2 * 131 a + b + c = √ 484 = 22 a" | general |
math_qa__B41S03vWb2rk5yQI | A salesman's income consists of a commission and a base salary of $450 per week. Over the past 5 weeks, his weekly income totals have been $406, $413, $420, $436 and $395. What must his average (arithmetic mean) commission be per week over the next two weeks so that his average weekly income is $500 over the 7-week period? Select the correct option
A) $ 150 B) $ 245 C) $ 365 D) $ 715 E) $ 265 | <gadget id="calculator">500 * 7</gadget>
<output>3_500</output>
<gadget id="calculator">406 + 413</gadget>
<output>819</output>
<gadget id="calculator">436 + 420</gadget>
<output>856</output>
<gadget id="calculator">819 + 856</gadget>
<output>1_675</output>
<gadget id="calculator">1_675 + 395</gadget>
<output>2_070</output>
<gadget id="calculator">3_500 - 2_070</gadget>
<output>1_430</output>
<gadget id="calculator">1_430 / 2</gadget>
<output>715</output>
<gadget id="calculator">715 - 450</gadget>
<output>265</output>
<result>E</result> | E | 265 | A salesman's income consists of a commission and a base salary of $450 per week. Over the past 5 weeks, his weekly income totals have been $406, $413, $420, $436 and $395. What must his average (arithmetic mean) commission be per week over the next two weeks so that his average weekly income is $500 over the 7-week period? | {
"A": "$ 150",
"B": "$ 245",
"C": "$ 365",
"D": "$ 715",
"E": "$ 265"
} | subtract(divide(subtract(multiply(500, 7), add(add(add(406, 413), add(436, 420)), 395)), const_2), 450) | add(n2,n3)|add(n4,n5)|multiply(n7,n8)|add(#0,#1)|add(n6,#3)|subtract(#2,#4)|divide(#5,const_2)|subtract(#6,n0)| | "total weekly income over 5 weeks = $ 406 + $ 413 + $ 420 + $ 436 + $ 395 = $ 2070 for avg weekly income to be $ 500 over 7 weeks , we need total weekly income over 7 weeks = $ 3500 now , $ 3500 - $ 2070 = $ 1430 from this , we subtract base salary for 2 weeks i . e $ 450 * 2 = $ 900 therefore , commission = $ 1430 - $ 900 = $ 530 for 2 weeks avg weekly commission = $ 265 answer e" | general |
math_qa__YoifILf2rL8tc04V | An art gallery has only paintings and sculptures. Currently, 1/3 of the pieces of art are displayed, and 1/6 of the pieces on display are sculptures. If 1/3 of the pieces not on display are paintings, and 400 sculptures are not on display, how many pieces of art does the gallery have? Choose the correct choice from the following choices: A) 360 B) 900 C) 540 D) 640 E) 720 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">400 / (2/3)</gadget>
<output>600</output>
<gadget id="calculator">600 / (2/3)</gadget>
<output>900</output>
<result>B</result> | B | 900 | An art gallery has only paintings and sculptures. Currently, 1/3 of the pieces of art are displayed, and 1/6 of the pieces on display are sculptures. If 1/3 of the pieces not on display are paintings, and 400 sculptures are not on display, how many pieces of art does the gallery have? | {
"A": "360",
"B": "900",
"C": "540",
"D": "640",
"E": "720"
} | divide(divide(400, subtract(1, divide(1, 3))), subtract(1, divide(1, 3))) | divide(n0,n1)|subtract(n0,#0)|divide(n6,#1)|divide(#2,#1)| | "too many words and redundant info there . ( i ) 1 / 3 of the pieces of art are displayed , hence 2 / 3 of the pieces of art are not displayed . ( ii ) 1 / 6 of the pieces on display are sculptures , hence 5 / 6 of the pieces on display are paintings . ( iii ) 1 / 3 of the pieces not on display are paintings , hence 2 / 3 of the pieces not on display are sculptures . 400 sculptures are not on display , so according to ( iii ) 2 / 3 * { not on display } = 400 - - > { not on display } = 600 . according to ( i ) 2 / 3 * { total } = 600 - - > { total } = 900 . answer : b ." | general |
math_qa__2qSAhldYffocNkFz | What is (25^7+25) / 25? Choose the correct choice from the following answers:
A) 244140626 B) 243120617 C) 242580531 D) 241230438 E) 240760355 | <gadget id="calculator">25 ** 7</gadget>
<output>6_103_515_625</output>
<gadget id="calculator">6_103_515_625 + 25</gadget>
<output>6_103_515_650</output>
<gadget id="calculator">6_103_515_650 / 25</gadget>
<output>244_140_626</output>
<result>A</result> | A | 244,140,626 | What is (25^7+25) / 25? | {
"A": "244140626",
"B": "243120617",
"C": "242580531",
"D": "241230438",
"E": "240760355"
} | divide(add(power(25, 7), 25), 25) | power(n0,n1)|add(n0,#0)|divide(#1,n0)| | "( 25 ^ 7 + 25 ) / 25 = 25 * ( 25 ^ 6 + 1 ) / 25 = 25 ^ 6 + 1 clearly this is a number which ends with a 6 in the units place . the answer is a ." | general |
math_qa__mDiatt7LknzJiCWV | Chris mixed 5 pounds of raisins with 4 pounds of nuts. If a pound of nuts costs 3 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture?
Options
A) 5 / 17
B) 1 / 5
C) 1 / 4
D) 1 / 3
E) 3 / 7 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 + 5</gadget>
<output>17</output>
<gadget id="calculator">5 / 17</gadget>
<output>5/17 = around 0.294118</output>
<result>A</result> | A | 0.294118 | Chris mixed 5 pounds of raisins with 4 pounds of nuts. If a pound of nuts costs 3 times as much as a pound of raisins, then the total cost of the raisins was what fraction of the total cost of the mixture? | {
"A": "5 / 17",
"B": "1 / 5",
"C": "1 / 4",
"D": "1 / 3",
"E": "3 / 7"
} | divide(5, add(multiply(4, 3), 5)) | multiply(n1,n2)|add(n0,#0)|divide(n0,#1)| | "1 lbs of raisin = $ 1 5 lbs of raisin = $ 5 1 lbs of nuts = $ 3 4 lbs of nuts = $ 12 total value of mixture = 12 + 5 = 17 fraction of the value of raisin = 5 / 17 = 1 / 5 ans : a" | general |
math_qa__PRdM4yBNjmLAG8yF | A train running at the speed of 60 km/hr crosses a pole in 18 sec. What is the length of the train? Choices.
A) 118 B) 150 C) 300 D) 258 E) 191 | <gadget id="calculator">60 * 1_000</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 3_600</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(50/3) * 18</gadget>
<output>300</output>
<result>C</result> | C | 300 | A train running at the speed of 60 km/hr crosses a pole in 18 sec. What is the length of the train? | {
"A": "118",
"B": "150",
"C": "300",
"D": "258",
"E": "191"
} | multiply(divide(multiply(60, const_1000), const_3600), 18) | multiply(n0,const_1000)|divide(#0,const_3600)|multiply(n1,#1)| | "speed = 60 * 5 / 18 = 50 / 3 m / sec length of the train = speed * time = 50 / 3 * 18 = 300 m answer : c" | physics |
math_qa__tTtlmFB2OHgHpyP0 | If an average hard drive had a capacity of 0.7 TB in 2000, and average hard drive capacities double every 5 years, what will be the average hard drive capacity in 2050? Answers.
A) 256
B) 512
C) 768
D) 1024
E) 7168 | <gadget id="calculator">0.7 * 2</gadget>
<output>1.4</output>
<gadget id="calculator">1.4 * 2</gadget>
<output>2.8</output>
<gadget id="calculator">2.8 * 2</gadget>
<output>5.6</output>
<gadget id="calculator">5.6 * 2</gadget>
<output>11.2</output>
<gadget id="calculator">11.2 * 2</gadget>
<output>22.4</output>
<gadget id="calculator">22.4 * 2</gadget>
<output>44.8</output>
<gadget id="calculator">44.8 * 2</gadget>
<output>89.6</output>
<gadget id="calculator">89.6 * 2</gadget>
<output>179.2</output>
<gadget id="calculator">179.2 * 2</gadget>
<output>358.4</output>
<gadget id="calculator">358.4 * 2</gadget>
<output>716.8</output>
<gadget id="calculator">716.8 + 0.7</gadget>
<output>717.5</output>
<gadget id="calculator">717.5 * 10</gadget>
<output>7_175</output>
<result>E</result> | E | 7,168 | If an average hard drive had a capacity of 0.7 TB in 2000, and average hard drive capacities double every 5 years, what will be the average hard drive capacity in 2050? | {
"A": "256",
"B": "512",
"C": "768",
"D": "1024",
"E": "7168"
} | multiply(add(multiply(multiply(multiply(multiply(multiply(multiply(multiply(multiply(multiply(multiply(0.7, const_2), const_2), const_2), const_2), const_2), const_2), const_2), const_2), const_2), const_2), 0.7), const_10) | multiply(n0,const_2)|multiply(#0,const_2)|multiply(#1,const_2)|multiply(#2,const_2)|multiply(#3,const_2)|multiply(#4,const_2)|multiply(#5,const_2)|multiply(#6,const_2)|multiply(#7,const_2)|multiply(#8,const_2)|add(n0,#9)|multiply(#10,const_10) | 0.7 * 2 ^ 10 = 0.7 * 1024 = 716.8 the answer is e . | general |
math_qa__YAHCkARGsrqocHMq | 9 men went to a hotel . 8 of them spent rs . 3 each over their meals and the ninth spent rs . 2 more than the average expenditure of all the 9 . determine the total money spent by them ? a . rs . 29.25
Choose the correct choice from the following answers:
A) 29.25
B) 29.28
C) 29.27
D) 29.22
E) 29.21 | <gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">9 * 2</gadget>
<output>18</output>
<gadget id="calculator">18 + 24</gadget>
<output>42</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">42 / 8</gadget>
<output>21/4 = around 5.25</output>
<gadget id="calculator">24 + (21/4)</gadget>
<output>117/4 = around 29.25</output>
<result>A</result> | A | 29.25 | 9 men went to a hotel . 8 of them spent rs . 3 each over their meals and the ninth spent rs . 2 more than the average expenditure of all the 9 . determine the total money spent by them ? a . rs . 29.25 | {
"A": "29.25",
"B": "29.28",
"C": "29.27",
"D": "29.22",
"E": "29.21"
} | add(multiply(8, 3), divide(add(multiply(9, 2), multiply(8, 3)), subtract(9, const_1))) | multiply(n0,n3)|multiply(n1,n2)|subtract(n0,const_1)|add(#0,#1)|divide(#3,#2)|add(#4,#1) | average of 9 = x 9 x = 8 * 3 + x * 2 x = 3.25 total = 9 * 3.25 = 29.25 . answer : a | general |
math_qa__pK6huw4yWcK07DRJ | Find the average of all the numbers between 6 and 34 which are divisible by 5 Choose the correct choice.
A) 18 B) 20 C) 24 D) 30 E) 40 | <gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">34 - 4</gadget>
<output>30</output>
<gadget id="calculator">10 + 30</gadget>
<output>40</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<result>B</result> | B | 20 | Find the average of all the numbers between 6 and 34 which are divisible by 5 | {
"A": "18",
"B": "20",
"C": "24",
"D": "30",
"E": "40"
} | divide(add(add(6, const_4), subtract(34, const_4)), const_2) | add(n0,const_4)|subtract(n1,const_4)|add(#0,#1)|divide(#2,const_2)| | "exp . multiples of 5 between 6 and 34 are 10 , 15,20 , 25,30 average = ( 10 + 15 + 20 + 25 + 30 ) / 5 = 5 ( 10 + 30 ) / 2 * 5 = 40 / 2 = 20 answer : b" | general |
math_qa__tLvkMpLr4DJbX6ef | How much time will a train of length 420 m moving at a speed of 72 kmph take to cross another train of length 640 m, moving at 36 kmph in the same direction? Choose the correct option.
A) 50 B) 99 C) 88 D) 76 E) 106 | <gadget id="calculator">420 + 640</gadget>
<output>1_060</output>
<gadget id="calculator">72 - 36</gadget>
<output>36</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">1_060 / 10</gadget>
<output>106</output>
<result>E</result> | E | 106 | How much time will a train of length 420 m moving at a speed of 72 kmph take to cross another train of length 640 m, moving at 36 kmph in the same direction? | {
"A": "50",
"B": "99",
"C": "88",
"D": "76",
"E": "106"
} | divide(add(420, 640), multiply(subtract(72, 36), const_0_2778)) | add(n0,n2)|subtract(n1,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "the distance to be covered = sum of their lengths = 420 + 640 = 1060 m . relative speed = 72 - 36 = 36 kmph = 36 * 5 / 18 = 10 mps . time required = d / s = 1060 / 10 = 106 sec . answer : e" | physics |
math_qa__a0McpIjCz9Z5BOXG | Machine P and Machine Q are each used to manufacture 110 sprockets. It takes Machine P 10 hours longer to produce 110 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce? Pick one:
A) 5
B) 15
C) 55
D) 95
E) 1 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">110 / (11/10)</gadget>
<output>100</output>
<gadget id="calculator">110 - 100</gadget>
<output>10</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<result>E</result> | E | 1 | Machine P and Machine Q are each used to manufacture 110 sprockets. It takes Machine P 10 hours longer to produce 110 sprockets than Machine Q. Machine Q produces 10% more sprockets per hour than Machine A. How many sprockets per hour does Machine A produce? | {
"A": "5",
"B": "15",
"C": "55",
"D": "95",
"E": "1"
} | divide(subtract(110, divide(110, add(divide(10, const_100), const_1))), 10) | divide(n1,const_100)|add(#0,const_1)|divide(n0,#1)|subtract(n0,#2)|divide(#3,n1) | p makes x sprockets per hour . then q makes 1.1 x sprockets per hour . 10 / x = 110 / 1.1 x + 10 1.1 ( 110 ) = 110 + 11 x 11 x = 11 x = 1 the answer is e | gain |
math_qa__O4lrEwtewMZ7ny6a | a spider web consists of 3 concurrent lines forming radial support for 20 concentric regular hexagon .the hexagon vertices are 5mm from their immidiate neighbour. if the innermost hexagon has a side length 3mm how many meters is the length of the entire web including the 3 diagonals ?
Choose the most appropriate option: A) 7.354 m B) 8.354 m C) 6.354 m D) 9.354 m E) 5.354 m | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">3 / 1_000</gadget>
<output>3/1_000 = around 0.003</output>
<gadget id="calculator">5 / 1_000</gadget>
<output>1/200 = around 0.005</output>
<gadget id="calculator">(3/1_000) + (1/200)</gadget>
<output>1/125 = around 0.008</output>
<gadget id="calculator">(3/1_000) + (1/125)</gadget>
<output>11/1_000 = around 0.011</output>
<gadget id="calculator">(1/200) + (1/125)</gadget>
<output>13/1_000 = around 0.013</output>
<gadget id="calculator">(11/1_000) + (13/1_000)</gadget>
<output>3/125 = around 0.024</output>
<gadget id="calculator">(1/200) + (13/1_000)</gadget>
<output>9/500 = around 0.018</output>
<gadget id="calculator">(3/125) + (9/500)</gadget>
<output>21/500 = around 0.042</output>
<gadget id="calculator">(1/200) + (9/500)</gadget>
<output>23/1_000 = around 0.023</output>
<gadget id="calculator">(21/500) + (23/1_000)</gadget>
<output>13/200 = around 0.065</output>
<gadget id="calculator">(1/200) + (23/1_000)</gadget>
<output>7/250 = around 0.028</output>
<gadget id="calculator">(13/200) + (7/250)</gadget>
<output>93/1_000 = around 0.093</output>
<gadget id="calculator">(1/200) + (7/250)</gadget>
<output>33/1_000 = around 0.033</output>
<gadget id="calculator">(93/1_000) + (33/1_000)</gadget>
<output>63/500 = around 0.126</output>
<gadget id="calculator">(1/200) + (33/1_000)</gadget>
<output>19/500 = around 0.038</output>
<gadget id="calculator">(63/500) + (19/500)</gadget>
<output>41/250 = around 0.164</output>
<gadget id="calculator">(1/200) + (19/500)</gadget>
<output>43/1_000 = around 0.043</output>
<gadget id="calculator">(41/250) + (43/1_000)</gadget>
<output>207/1_000 = around 0.207</output>
<gadget id="calculator">(1/200) + (43/1_000)</gadget>
<output>6/125 = around 0.048</output>
<gadget id="calculator">(207/1_000) + (6/125)</gadget>
<output>51/200 = around 0.255</output>
<gadget id="calculator">(1/200) + (6/125)</gadget>
<output>53/1_000 = around 0.053</output>
<gadget id="calculator">(51/200) + (53/1_000)</gadget>
<output>77/250 = around 0.308</output>
<gadget id="calculator">(1/200) + (53/1_000)</gadget>
<output>29/500 = around 0.058</output>
<gadget id="calculator">(77/250) + (29/500)</gadget>
<output>183/500 = around 0.366</output>
<gadget id="calculator">(1/200) + (29/500)</gadget>
<output>63/1_000 = around 0.063</output>
<gadget id="calculator">(183/500) + (63/1_000)</gadget>
<output>429/1_000 = around 0.429</output>
<gadget id="calculator">(1/200) + (63/1_000)</gadget>
<output>17/250 = around 0.068</output>
<gadget id="calculator">(429/1_000) + (17/250)</gadget>
<output>497/1_000 = around 0.497</output>
<gadget id="calculator">(1/200) + (17/250)</gadget>
<output>73/1_000 = around 0.073</output>
<gadget id="calculator">(497/1_000) + (73/1_000)</gadget>
<output>57/100 = around 0.57</output>
<gadget id="calculator">(1/200) + (73/1_000)</gadget>
<output>39/500 = around 0.078</output>
<gadget id="calculator">(57/100) + (39/500)</gadget>
<output>81/125 = around 0.648</output>
<gadget id="calculator">(1/200) + (39/500)</gadget>
<output>83/1_000 = around 0.083</output>
<gadget id="calculator">(81/125) + (83/1_000)</gadget>
<output>731/1_000 = around 0.731</output>
<gadget id="calculator">(1/200) + (83/1_000)</gadget>
<output>11/125 = around 0.088</output>
<gadget id="calculator">(731/1_000) + (11/125)</gadget>
<output>819/1_000 = around 0.819</output>
<gadget id="calculator">(1/200) + (11/125)</gadget>
<output>93/1_000 = around 0.093</output>
<gadget id="calculator">(819/1_000) + (93/1_000)</gadget>
<output>114/125 = around 0.912</output>
<gadget id="calculator">(1/200) + (93/1_000)</gadget>
<output>49/500 = around 0.098</output>
<gadget id="calculator">(114/125) + (49/500)</gadget>
<output>101/100 = around 1.01</output>
<gadget id="calculator">6 * (101/100)</gadget>
<output>303/50 = around 6.06</output>
<gadget id="calculator">(49/500) * 3</gadget>
<output>147/500 = around 0.294</output>
<gadget id="calculator">(303/50) + (147/500)</gadget>
<output>3_177/500 = around 6.354</output>
<result>C</result> | C | 6.354 | a spider web consists of 3 concurrent lines forming radial support for 20 concentric regular hexagon .the hexagon vertices are 5mm from their immidiate neighbour. if the innermost hexagon has a side length 3mm how many meters is the length of the entire web including the 3 diagonals ? | {
"A": "7.354 m",
"B": "8.354 m",
"C": "6.354 m",
"D": "9.354 m",
"E": "5.354 m"
} | add(multiply(multiply(3, const_2), add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(add(divide(3, const_1000), add(divide(3, const_1000), divide(5, const_1000))), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000)))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000)))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000)))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000))))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000)))))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000))))))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000)))))))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000))))))))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000)))))))))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000))))))))))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000)))))))))))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000))))))))))))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000)))))))))))))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000))))))))))))))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000)))))))))))))))))))), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000)))))))))))))))))))))), multiply(add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(5, const_1000), add(divide(3, const_1000), divide(5, const_1000)))))))))))))))))))), 3)) | divide(n0,const_1000)|divide(n2,const_1000)|multiply(n0,const_2)|add(#0,#1)|add(#3,#0)|add(#3,#1)|add(#4,#5)|add(#5,#1)|add(#6,#7)|add(#7,#1)|add(#8,#9)|add(#9,#1)|add(#10,#11)|add(#11,#1)|add(#12,#13)|add(#13,#1)|add(#14,#15)|add(#15,#1)|add(#16,#17)|add(#17,#1)|add(#18,#19)|add(#19,#1)|add(#20,#21)|add(#21,#1)|add(#22,#23)|add(#23,#1)|add(#24,#25)|add(#25,#1)|add(#26,#27)|add(#27,#1)|add(#28,#29)|add(#29,#1)|add(#30,#31)|add(#31,#1)|add(#32,#33)|add(#33,#1)|add(#34,#35)|add(#35,#1)|add(#36,#37)|add(#37,#1)|add(#38,#39)|multiply(n0,#39)|multiply(#40,#2)|add(#42,#41) | for perimeter of all hexagon = 6 * ( 3 + 8 + 13 + . . . . . . . . . . . 20 th term . ) sum will be 6060 mm and for length of one diagonal find 20 th term = 98 so total length = 6060 + 294 = 6354 mm = 6.354 m answer : c | physics |
math_qa__86EhtKRNVitZxGPU | When processing flower-nectar into honey bees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 25% water? Choose one.
A) 1.2 kg
B) 1.5 kg
C) 1.7 kg
D) 1.9 kg
E) none of these | <gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(3/4) / (1/2)</gadget>
<output>3/2 = around 1.5</output>
<result>B</result> | B | 1.5 | When processing flower-nectar into honey bees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 25% water? | {
"A": "1.2 kg",
"B": "1.5 kg",
"C": "1.7 kg",
"D": "1.9 kg",
"E": "none of these"
} | divide(divide(subtract(const_100, 25), const_100), divide(50, const_100)) | divide(n1,const_100)|subtract(const_100,n2)|divide(#1,const_100)|divide(#2,#0)| | "explanation : flower - nectar contains 50 % of non - water part . in honey this non - water part constitutes 75 % ( 100 - 25 ) . therefore 0.5 x amount of flower - nectar = 0.75 x amount of honey = 0.75 x 1 kg therefore amount of flower - nectar needed = ( 0.75 / 0.51 ) kg = 1.5 kgs answer : b" | general |
math_qa__5BG5vW3rybSZiqik | In a certain company, a third of the workers do not have a retirement plan. 20% of the workers who do not have a retirement plan are women, and 40% of the workers who do have a retirement plan are men. If 144 of the workers of that company are men, how many of the workers are women? Choose the correct option: A) 80 B) 95 C) 105 D) 120 E) 126 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/3) * (1/5)</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">(1/3) - (1/15)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/3) * (2/5)</gadget>
<output>4/15 = around 0.266667</output>
<gadget id="calculator">(4/15) + (4/15)</gadget>
<output>8/15 = around 0.533333</output>
<gadget id="calculator">144 / (8/15)</gadget>
<output>270</output>
<gadget id="calculator">(2/3) - (4/15)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/15) + (2/5)</gadget>
<output>7/15 = around 0.466667</output>
<gadget id="calculator">270 * (7/15)</gadget>
<output>126</output>
<result>E</result> | E | 126 | In a certain company, a third of the workers do not have a retirement plan. 20% of the workers who do not have a retirement plan are women, and 40% of the workers who do have a retirement plan are men. If 144 of the workers of that company are men, how many of the workers are women? | {
"A": "80",
"B": "95",
"C": "105",
"D": "120",
"E": "126"
} | multiply(divide(144, add(subtract(divide(const_1, const_3), multiply(divide(const_1, const_3), divide(20, const_100))), multiply(subtract(const_1, divide(const_1, const_3)), divide(40, const_100)))), add(multiply(divide(const_1, const_3), divide(20, const_100)), subtract(subtract(const_1, divide(const_1, const_3)), multiply(subtract(const_1, divide(const_1, const_3)), divide(40, const_100))))) | divide(const_1,const_3)|divide(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)|subtract(const_1,#0)|multiply(#2,#4)|subtract(#0,#3)|add(#5,#6)|subtract(#4,#5)|add(#3,#8)|divide(n2,#7)|multiply(#9,#10)| | "set up equation : x = total number of workers 144 = 0,4 * 2 / 3 * x + 0,8 * 1 / 3 * x 144 = 16 / 30 x x = 270 270 - 144 = 126 answer e" | gain |
math_qa__ULULk8Sd2Ey14Zae | 95 white and black tiles will be used to form a 10x10 square pattern. If there must be at least one black tile in every row and at least one white tile in every column, what is the maximum difference between the number of black and white tiles that can be used? Answers
A) 75
B) 80
C) 85
D) 90
E) 95 | <gadget id="calculator">95 - 10</gadget>
<output>85</output>
<result>C</result> | C | 85 | 95 white and black tiles will be used to form a 10x10 square pattern. If there must be at least one black tile in every row and at least one white tile in every column, what is the maximum difference between the number of black and white tiles that can be used? | {
"A": "75",
"B": "80",
"C": "85",
"D": "90",
"E": "95"
} | subtract(95, 10) | subtract(n0,n1) | answer = c please refer diagram below 95 - 10 = 85 | general |
math_qa__O8xTh1pBEZBMkyK5 | In what time will a railway train 20 m long moving at the rate of 36 kmph pass a telegraph post on its way? Select the correct option
A) 6 sec B) 7 sec C) 8 sec D) 9 sec E) 2 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">20 / 10</gadget>
<output>2</output>
<result>E</result> | E | 2 | In what time will a railway train 20 m long moving at the rate of 36 kmph pass a telegraph post on its way? | {
"A": "6 sec",
"B": "7 sec",
"C": "8 sec",
"D": "9 sec",
"E": "2 sec"
} | divide(20, multiply(36, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "t = 60 / 36 * 18 / 5 = 2 sec answer : e" | physics |
math_qa__CSnxLzVfBoOMsXM2 | What is the rate percent when the simple interest on Rs.800 amount to Rs.400 in 2 Years? Pick one
A) 5 % B) 6 % C) 2 % D) 25 % E) 1 % | <gadget id="calculator">100 * 400</gadget>
<output>40_000</output>
<gadget id="calculator">800 * 2</gadget>
<output>1_600</output>
<gadget id="calculator">40_000 / 1_600</gadget>
<output>25</output>
<result>D</result> | D | 25 | What is the rate percent when the simple interest on Rs.800 amount to Rs.400 in 2 Years? | {
"A": "5 %",
"B": "6 %",
"C": "2 %",
"D": "25 %",
"E": "1 %"
} | divide(multiply(const_100, 400), multiply(800, 2)) | multiply(n1,const_100)|multiply(n0,n2)|divide(#0,#1) | interest for 2 yrs = 400 interest for 1 yr = 200 interest rate = 200 / 800 x 100 = 25 % answer : d | gain |
math_qa__NQcxTYG3Lm9f0JA9 | If the area of a square with sides of length 9 centimeters is equal to the area of a rectangle with a width of 3 centimeters, what is the length of the rectangle, in centimeters? Choose the correct choice from the following:
A) 4 B) 27 C) 12 D) 16 E) 18 | <gadget id="calculator">9 ** 2</gadget>
<output>81</output>
<gadget id="calculator">81 / 3</gadget>
<output>27</output>
<result>B</result> | B | 27 | If the area of a square with sides of length 9 centimeters is equal to the area of a rectangle with a width of 3 centimeters, what is the length of the rectangle, in centimeters? | {
"A": "4",
"B": "27",
"C": "12",
"D": "16",
"E": "18"
} | divide(power(9, const_2), const_3) | power(n0,const_2)|divide(#0,const_3) | let length of rectangle = l 9 ^ 2 = l * 3 = > l = 81 / 3 = 27 answer b | geometry |
math_qa__Nlj7IJpQBYuf6mFG | taequan is playing a dice game where he rolls two , fair , 6 - sided dice twice . if he gets the same roll on his second try as his first , he wins . if he rolled an 8 on his first try , what is the probability that he will win with his second roll ? Pick.
A) 1 / 18 B) 1 / 12 C) 1 / 9 D) 1 / 6 E) 5 / 36 | <gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">5 / 36</gadget>
<output>5/36 = around 0.138889</output>
<result>E</result> | E | 0.138889 | taequan is playing a dice game where he rolls two , fair , 6 - sided dice twice . if he gets the same roll on his second try as his first , he wins . if he rolled an 8 on his first try , what is the probability that he will win with his second roll ? | {
"A": "1 / 18",
"B": "1 / 12",
"C": "1 / 9",
"D": "1 / 6",
"E": "5 / 36"
} | divide(subtract(6, const_1), multiply(6, 6)) | multiply(n0,n0)|subtract(n0,const_1)|divide(#1,#0) | there are 5 ways to roll an 8 : 2 and 6 , 6 and 2 , 3 and 5 , 5 and 3 , 4 and 4 ( 4 and 4 is counted just once ) . there are 6 * 6 = 36 ways to roll two six - sided dice . the dice are fair , so the probability of rolling an 8 is 5 / 36 . e | general |
math_qa__ilvMufEXAaQ4rn1c | Car A runs at the speed of 100km/hr & reaches its destination in 5hr. Car B runs at the speed of 80 km/h & reaches its destination in 6h. What is the respective ratio of distances covered by Car A & Car B? Answers: A) 11 : 5 B) 11 : 8 C) 13 : 7 D) 25 : 24 E) 16 : 9 | <gadget id="calculator">100 * 5</gadget>
<output>500</output>
<gadget id="calculator">80 * 6</gadget>
<output>480</output>
<gadget id="calculator">500 / 480</gadget>
<output>25/24 = around 1.041667</output>
<result>D</result> | D | 1.041667 | Car A runs at the speed of 100km/hr & reaches its destination in 5hr. Car B runs at the speed of 80 km/h & reaches its destination in 6h. What is the respective ratio of distances covered by Car A & Car B? | {
"A": "11 : 5",
"B": "11 : 8",
"C": "13 : 7",
"D": "25 : 24",
"E": "16 : 9"
} | divide(multiply(100, 5), multiply(80, 6)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,#1)| | "sol . distance travelled by car a = 100 × 5 = 500 km distance travelled by car b = 80 × 6 = 480 km ratio = 500 / 480 = 25 : 24 answer : d" | physics |
math_qa__UKecTu9JuJxg1UmY | Pipe A usually fills a tank in 2 hours. On account of a leak at the bottom of the tank, it takes pipe A 30 more minutes to fill the tank. How long will the leak take to empty a full tank if pipe A is shut? Choose the correct answer:
A) 7 hours B) 8 hours C) 9 hours D) 10 hours E) 11 hours | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 + (1/2)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">1 / (5/2)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(1/2) - (2/5)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 100</gadget>
<output>10</output>
<result>D</result> | D | 10 | Pipe A usually fills a tank in 2 hours. On account of a leak at the bottom of the tank, it takes pipe A 30 more minutes to fill the tank. How long will the leak take to empty a full tank if pipe A is shut? | {
"A": "7 hours",
"B": "8 hours",
"C": "9 hours",
"D": "10 hours",
"E": "11 hours"
} | multiply(subtract(divide(const_1, 2), divide(const_1, add(2, divide(const_1, 2)))), const_100) | divide(const_1,n0)|add(n0,#0)|divide(const_1,#1)|subtract(#0,#2)|multiply(#3,const_100) | pipe a fills the tank normally in 2 hours . therefore , it will fill ½ of the tank in an hour . let the leak take x hours to empty a full tank when pipe a is shut . therefore , the leak will empty of the tank in an hour . the net amount of water that gets filled in the tank in an hour when pipe a is open and when there is a leak = of the tank . — ( 1 ) when there is a leak , the problem states that pipe a takes two and a half hours to fill the tank . i . e . hours . therefore , in an hour , of the tank gets filled . – ( 2 ) equating ( 1 ) and ( 2 ) , we get = > = > x = 10 hours . the problem can also be mentally done as follows . pipe a takes 2 hours to fill the tank . therefore , it fills half the tank in an hour or 50 % of the tank in an hour . when there is a leak it takes 2 hours 30 minutes for the tank to fill . i . e hours to fill the tank or or 40 % of the tank gets filled . on account of the leak , ( 50 - 40 ) % = 10 % of the water gets wasted every hour . therefore , the leak will take 10 hours to drain a full tank . answer : d | physics |
math_qa__0DCEzLSht999ewXG | Walking at 5/6th of its usual speed a cab is 5mnts late. Find its usual time to cover the journey?
Choose the correct choice from the following options
A) 25 m B) 45 m C) 32 m D) 50 m E) 62 m | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<result>A</result> | A | 25 | Walking at 5/6th of its usual speed a cab is 5mnts late. Find its usual time to cover the journey? | {
"A": "25 m",
"B": "45 m",
"C": "32 m",
"D": "50 m",
"E": "62 m"
} | multiply(5, 5) | multiply(n0,n2)| | "new speed = 5 / 6 th of usual speed new time = 6 / 5 th of usual time 6 / 5 ut - ut = 5 m ut / 5 = 5 m ut = 25 m answer is a" | physics |
math_qa__Cc7ipwoQVgqG6Q6C | Find the value of X: 3x^2-6x+3 = 0 Choose the correct choice from the following:
A) - 1
B) 1
C) 2
D) 3
E) 4 | <gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">3 ** 2</gadget>
<output>9</output>
<gadget id="calculator">9 / 9</gadget>
<output>1</output>
<result>B</result> | B | 1 | Find the value of X: 3x^2-6x+3 = 0 | {
"A": "- 1",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | divide(add(6, 3), power(3, 2)) | add(n0,n2)|power(n0,n1)|divide(#0,#1) | a = 3 , b = - 6 , c = 3 x 1,2 = ( 6 ± √ ( ( - 6 ) 2 - 4 × 3 × 3 ) ) / ( 2 × 3 ) = ( 6 ± √ ( 36 - 36 ) ) / 6 = ( 6 ± 0 ) / 6 x 1 = x 2 = 1 b | general |
math_qa__YsGa7SBasXJhFnXs | What is the smallest number which when increased by 3 is divisible by 27, 35, 25, & 21 ? Choose the correct answer.
A) 4722 B) 4725 C) 4728 D) 4731 E) 4733 | <gadget id="calculator">lcm(27, 35)</gadget>
<output>945</output>
<gadget id="calculator">lcm(25, 21)</gadget>
<output>525</output>
<gadget id="calculator">lcm(945, 525)</gadget>
<output>4_725</output>
<gadget id="calculator">4_725 + 3</gadget>
<output>4_728</output>
<result>A</result> | A | 4,722 | What is the smallest number which when increased by 3 is divisible by 27, 35, 25, & 21 ? | {
"A": "4722",
"B": "4725",
"C": "4728",
"D": "4731",
"E": "4733"
} | add(lcm(lcm(27, 35), lcm(25, 21)), 3) | lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|add(n0,#2)| | "here smallest number means lcm hence lcm of 27,35 , 25,21 = 3 ^ 3 x 5 ^ 2 x 7 = 4725 therefore required number is 4725 - 3 = 4722 ans - a" | general |
math_qa__O6OZJf4Zhx2N8cWm | The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 245, what is the difference between the ages of Patrick and Monica? Select
A) 27 B) 48 C) 80 D) 72 E) 18 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">9 + 15</gadget>
<output>24</output>
<gadget id="calculator">24 + 25</gadget>
<output>49</output>
<gadget id="calculator">245 / 49</gadget>
<output>5</output>
<gadget id="calculator">25 * 5</gadget>
<output>125</output>
<gadget id="calculator">9 * 5</gadget>
<output>45</output>
<gadget id="calculator">125 - 45</gadget>
<output>80</output>
<result>C</result> | C | 80 | The ages of Patrick and Michael are in the ratio of 3 : 5 and that of Michael and Monica are in the ratio of 3 : 5. If the sum of their ages is 245, what is the difference between the ages of Patrick and Monica? | {
"A": "27",
"B": "48",
"C": "80",
"D": "72",
"E": "18"
} | subtract(multiply(multiply(5, 5), divide(245, add(add(multiply(3, 3), multiply(3, 5)), multiply(5, 5)))), multiply(multiply(3, 3), divide(245, add(add(multiply(3, 3), multiply(3, 5)), multiply(5, 5))))) | multiply(n0,n0)|multiply(n1,n0)|multiply(n1,n3)|add(#0,#1)|add(#3,#2)|divide(n4,#4)|multiply(#5,#2)|multiply(#5,#0)|subtract(#6,#7)| | "ages of p and mi = 3 x : 5 x ages of mi and mo = 3 x : 5 x rationalizing their ages . ratio of their ages will be 9 x : 15 x : 25 x sum = 49 x = 245 x = 5 difference if ages of pa and mo = 25 x - 9 x = 16 x = 16 * 5 = 80 answer c" | general |
math_qa__R0zSp18YlxtkGqJE | Pipe A can fill a tank in 4 hours. Due to a leak at the bottom, it takes 8 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank?
Select:
A) 13 B) 17 C) 18 D) 8 E) 12 | <gadget id="calculator">8 * 4</gadget>
<output>32</output>
<gadget id="calculator">8 - 4</gadget>
<output>4</output>
<gadget id="calculator">32 / 4</gadget>
<output>8</output>
<result>D</result> | D | 8 | Pipe A can fill a tank in 4 hours. Due to a leak at the bottom, it takes 8 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank? | {
"A": "13",
"B": "17",
"C": "18",
"D": "8",
"E": "12"
} | divide(multiply(8, 4), subtract(8, 4)) | multiply(n0,n1)|subtract(n1,n0)|divide(#0,#1)| | "let the leak can empty the full tank in x hours 1 / 4 - 1 / x = 1 / 8 = > 1 / x = 1 / 4 - 1 / 8 = ( 2 - 1 ) / 8 = 1 / 8 = > x = 8 . answer : d" | physics |
math_qa__7w8gzrqFyLFDPNCc | how many two - element subsets of < 1 , 23 , 45 , 67 > are there that do not contain the pair of elements 2 and 4 ? Choose the correct option
A) 11 B) 12 C) 14 D) 15 E) 20 | <gadget id="calculator">23 - 3</gadget>
<output>20</output>
<result>E</result> | E | 20 | how many two - element subsets of < 1 , 23 , 45 , 67 > are there that do not contain the pair of elements 2 and 4 ? | {
"A": "11",
"B": "12",
"C": "14",
"D": "15",
"E": "20"
} | subtract(23, const_3) | subtract(n1,const_3) | 7 c 2 - 1 = 20 answer is e | general |
math_qa__0Pwkbe4IOSlUnj8t | There is a sufficient food for 200 men for 20 days after 15 days 100 men leave the place. For how many days will the rest of the food last for the rest of the men? Choose the correct choice from the following choices.
A) 10 days B) 5 days C) 15 days D) 12 days E) 10 days | <gadget id="calculator">20 - 15</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<result>A</result> | A | 10 | There is a sufficient food for 200 men for 20 days after 15 days 100 men leave the place. For how many days will the rest of the food last for the rest of the men? | {
"A": "10 days",
"B": "5 days",
"C": "15 days",
"D": "12 days",
"E": "10 days"
} | multiply(subtract(20, 15), const_2) | subtract(n1,n2)|multiply(#0,const_2) | explanation : after 13 days , 100 men left , therefore 5 days * 200 men = x days * 100 men x = 10 days answer : option a | physics |
math_qa__Ot9YRgbxXCtqtXoe | A motorcyclist started riding at highway marker A, drove 120 miles to highway marker B, and then, without pausing, continued to highway marker C, where she stopped. The average speed of the motorcyclist, over the course of the entire trip, was 30 miles per hour. If the ride from marker A to marker B lasted 3 times as many hours as the rest of the ride, and the distance from marker B to marker C was half of the distance from marker A to marker B, what was the average speed, in miles per hour, of the motorcyclist while driving from marker B to marker C?
Answers:
A) 90 B) 45 C) 50 D) 55 E) 60 | <gadget id="calculator">120 / 2</gadget>
<output>60</output>
<gadget id="calculator">60 + 120</gadget>
<output>180</output>
<gadget id="calculator">180 / 30</gadget>
<output>6</output>
<gadget id="calculator">6 / 4</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 60</gadget>
<output>90</output>
<result>A</result> | A | 90 | A motorcyclist started riding at highway marker A, drove 120 miles to highway marker B, and then, without pausing, continued to highway marker C, where she stopped. The average speed of the motorcyclist, over the course of the entire trip, was 30 miles per hour. If the ride from marker A to marker B lasted 3 times as many hours as the rest of the ride, and the distance from marker B to marker C was half of the distance from marker A to marker B, what was the average speed, in miles per hour, of the motorcyclist while driving from marker B to marker C? | {
"A": "90",
"B": "45",
"C": "50",
"D": "55",
"E": "60"
} | multiply(divide(divide(add(divide(120, const_2), 120), 30), const_4), divide(120, const_2)) | divide(n0,const_2)|add(n0,#0)|divide(#1,n1)|divide(#2,const_4)|multiply(#3,#0)| | "a - b = 120 miles b - c = 60 miles avg speed = 30 miles time taken for a - b 3 t and b - c be t avg speed = ( 120 + 60 ) / total time 30 = 180 / 4 t t = 90 b - c = 90 mph answer a" | physics |
math_qa__nBNW5FYLXYeqRC9Z | How much 60% of 50 is greater than 30% of 30? Choices
A) 21 B) 91 C) 11 D) 17 E) 12 | <gadget id="calculator">60 * 50</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 100</gadget>
<output>30</output>
<gadget id="calculator">30 * 30</gadget>
<output>900</output>
<gadget id="calculator">900 / 100</gadget>
<output>9</output>
<gadget id="calculator">30 - 9</gadget>
<output>21</output>
<result>A</result> | A | 21 | How much 60% of 50 is greater than 30% of 30? | {
"A": "21",
"B": "91",
"C": "11",
"D": "17",
"E": "12"
} | subtract(divide(multiply(60, 50), const_100), divide(multiply(30, 30), const_100)) | multiply(n0,n1)|multiply(n2,n3)|divide(#0,const_100)|divide(#1,const_100)|subtract(#2,#3)| | "( 60 / 100 ) * 50 – ( 30 / 100 ) * 30 30 - 9 = 21 answer : a" | gain |
math_qa__gbqUWghH0Y3YsCb1 | The average of 50 numbers id 50. If two numbers, namely 45 and 55 are discarded, the average of the remaining numbers is : Choose the most appropriate option
A) 22 B) 33 C) 22 D) 41 E) 50 | <gadget id="calculator">50 * 50</gadget>
<output>2_500</output>
<gadget id="calculator">45 + 55</gadget>
<output>100</output>
<gadget id="calculator">2_500 - 100</gadget>
<output>2_400</output>
<gadget id="calculator">50 - 2</gadget>
<output>48</output>
<gadget id="calculator">2_400 / 48</gadget>
<output>50</output>
<result>E</result> | E | 50 | The average of 50 numbers id 50. If two numbers, namely 45 and 55 are discarded, the average of the remaining numbers is : | {
"A": "22",
"B": "33",
"C": "22",
"D": "41",
"E": "50"
} | divide(subtract(multiply(50, 50), add(45, 55)), subtract(50, const_2)) | add(n2,n3)|multiply(n0,n1)|subtract(n0,const_2)|subtract(#1,#0)|divide(#3,#2)| | "explanation : total of 50 numbers = ( 50 × 50 ) = 2500 total of 48 numbers = ( 2500 - ( 45 + 55 ) ] = 2400 required average = 2400 / 48 = 50 answer : e" | general |
math_qa__0vgHggANgQERxqCE | A can do a work in 9 days. B can do the same work in 18 days. If both A & B are working together in how many days they will finish the work?
Choose the correct choice from the following choices
A) 3
B) 5
C) 4
D) 2
E) 6 | <gadget id="calculator">9 * 18</gadget>
<output>162</output>
<gadget id="calculator">9 + 18</gadget>
<output>27</output>
<gadget id="calculator">162 / 27</gadget>
<output>6</output>
<result>E</result> | E | 6 | A can do a work in 9 days. B can do the same work in 18 days. If both A & B are working together in how many days they will finish the work? | {
"A": "3",
"B": "5",
"C": "4",
"D": "2",
"E": "6"
} | divide(multiply(9, 18), add(9, 18)) | add(n0,n1)|multiply(n0,n1)|divide(#1,#0)| | "a rate = 1 / 9 b rate = 1 / 18 ( a + b ) rate = ( 1 / 9 ) + ( 1 / 18 ) = 1 / 6 a & b finish the work in 6 days correct option is e" | physics |
math_qa__Es3mgZXrOFggLOUU | How many numbers between 100 and 672 are divisible by 2, 3, and 7 together? Choose the most appropriate option:
A) 112
B) 77
C) 267
D) 14
E) 99 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 7</gadget>
<output>42</output>
<gadget id="calculator">672 / 42</gadget>
<output>16</output>
<gadget id="calculator">100 / 42</gadget>
<output>50/21 = around 2.380952</output>
<gadget id="calculator">16 - (50/21)</gadget>
<output>286/21 = around 13.619048</output>
<result>D</result> | D | 14 | How many numbers between 100 and 672 are divisible by 2, 3, and 7 together? | {
"A": "112",
"B": "77",
"C": "267",
"D": "14",
"E": "99"
} | subtract(divide(672, multiply(multiply(2, 3), 7)), divide(100, multiply(multiply(2, 3), 7))) | multiply(n2,n3)|multiply(n4,#0)|divide(n1,#1)|divide(n0,#1)|subtract(#2,#3)| | "explanation : as the division is by 2 , 3 , 7 together , the numbers are to be divisible by : 2 * 3 * 7 = 42 the limits are 100 and 672 the first number divisible is 42 * 3 = 126 to find out the last number divisible by 42 within 672 : 672 / 42 = 14 hence , 42 * 16 = 672 is the last number divisible by 42 within 672 hence , total numbers divisible by 2 , 3 , 7 together are ( 16 â € “ 2 ) = 14 answer : d" | general |
math_qa__HkAabfxg1rFZxAWi | A girl scout was selling boxes of cookies. In a month, she sold both boxes of chocolate chip cookies ($1.25 each) and boxes of plain cookies ($0.75 each). Altogether, she sold 1,585 boxes for a combined value of $1,586.75. How many boxes of plain cookies did she sell? Answers:
A) 0 B) 233 C) 500 D) 695 E) 789 | <gadget id="calculator">1_000 + 586.75</gadget>
<output>1_586.75</output>
<gadget id="calculator">1_586.75 / 2</gadget>
<output>793.375</output>
<result>E</result> | E | 789 | A girl scout was selling boxes of cookies. In a month, she sold both boxes of chocolate chip cookies ($1.25 each) and boxes of plain cookies ($0.75 each). Altogether, she sold 1,585 boxes for a combined value of $1,586.75. How many boxes of plain cookies did she sell? | {
"A": "0",
"B": "233",
"C": "500",
"D": "695",
"E": "789"
} | divide(add(const_1000, 586.75), const_2) | add(n4,const_1000)|divide(#0,const_2)| | "let # plain cookies sold be x then # chocolate cookies = ( total cookies - x ) equating for x ( 0.75 ) * x + ( 1.25 ) * ( 1585 - x ) = 1586.75 = > x = 789" | other |
math_qa__5Hi1egk9dpng7XSW | A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability T that all 3 jellybeans removed from the bag are blue?
Choose the correct answer
A) 9 / 100 B) 2 / 19 C) 1 / 8 D) 3 / 20 E) 3 / 10 | <gadget id="calculator">binomial(10, 3)</gadget>
<output>120</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">binomial(20, 3)</gadget>
<output>1_140</output>
<gadget id="calculator">120 / 1_140</gadget>
<output>2/19 = around 0.105263</output>
<result>B</result> | B | 0.105263 | A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability T that all 3 jellybeans removed from the bag are blue? | {
"A": "9 / 100",
"B": "2 / 19",
"C": "1 / 8",
"D": "3 / 20",
"E": "3 / 10"
} | divide(choose(10, 3), choose(add(10, 10), 3)) | add(n0,n0)|choose(n0,n2)|choose(#0,n2)|divide(#1,#2)| | "method - 1 10 red jellybeans and 10 blue jellybeans total outcomes = no . of ways to choose 3 jelly bean at random out of a total 20 jellybeans = 20 c 3 = 1140 favourable outcomes = no . of ways to choose 3 jelly bean such that they are all blue out of 10 blue = 10 c 3 = 120 probability = favourable outcomes / total outcomes = 10 c 3 / 20 c 3 probability t = 120 / 1140 = 2 / 19 answer : option b method - 2 probability of first jelly bean to be blue = 10 / 20 [ total 10 blue out of total 20 jellybeans ] probability of second jelly bean to be blue = 9 / 19 [ total 9 blue remaining out of total 19 jellybeans remaining ] probability of third jelly bean to be blue = 8 / 18 [ total 8 blue remaining out of total 18 jellybeans remaining ] required probability = ( 10 / 20 ) * ( 9 / 19 ) * ( 8 / 18 ) = 2 / 19 answer : option b" | probability |
math_qa__teZqatzx2r7qPHrx | The length of a rectangle is reduced by 25%. By what % would the width have to be increased to maintainthe original area? Options: A) 15 % B) 20 % C) 25 % D) 33 % E) 40 % | <gadget id="calculator">100 - 25</gadget>
<output>75</output>
<gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) / (3/4)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>D</result> | D | 33 | The length of a rectangle is reduced by 25%. By what % would the width have to be increased to maintainthe original area? | {
"A": "15 %",
"B": "20 %",
"C": "25 %",
"D": "33 %",
"E": "40 %"
} | multiply(divide(subtract(const_1, divide(subtract(const_100, 25), const_100)), divide(subtract(const_100, 25), const_100)), const_100) | subtract(const_100,n0)|divide(#0,const_100)|subtract(const_1,#1)|divide(#2,#1)|multiply(#3,const_100)| | "sol . required change = ( 25 * 100 ) / ( 100 - 25 ) = 25 % d" | geometry |
math_qa__ChsvajFxUtGbGxnr | tough and tricky questions : word problems . ak car company wants to manufacture a new car known as model x , and it is trying to determine how many cars it needs to sell in order to make an annual profit of $ 30 , 500000 . the annual fixed costs for model x total $ 50 , 200000 . in addition , each model x car has an average cost of $ 5000 per vehicle to manufacture . if the company forecasts it will sell 20000 model x cars this year , at what price must the company sell the car to achieve the desired annual profit ? Choose the correct choice from the following answers:
A) $ 4035 B) $ 4036 C) $ 9035 D) $ 16140 E) $ 36140 | <gadget id="calculator">1_000 * 1_000</gadget>
<output>1_000_000</output>
<gadget id="calculator">50 * 1_000_000</gadget>
<output>50_000_000</output>
<gadget id="calculator">50_000_000 + 200_000</gadget>
<output>50_200_000</output>
<gadget id="calculator">20_000 * 5_000</gadget>
<output>100_000_000</output>
<gadget id="calculator">50_200_000 + 100_000_000</gadget>
<output>150_200_000</output>
<gadget id="calculator">30 * 1_000_000</gadget>
<output>30_000_000</output>
<gadget id="calculator">30_000_000 + 500_000</gadget>
<output>30_500_000</output>
<gadget id="calculator">150_200_000 + 30_500_000</gadget>
<output>180_700_000</output>
<gadget id="calculator">180_700_000 / 20_000</gadget>
<output>9_035</output>
<result>C</result> | C | 9,035 | tough and tricky questions : word problems . ak car company wants to manufacture a new car known as model x , and it is trying to determine how many cars it needs to sell in order to make an annual profit of $ 30 , 500000 . the annual fixed costs for model x total $ 50 , 200000 . in addition , each model x car has an average cost of $ 5000 per vehicle to manufacture . if the company forecasts it will sell 20000 model x cars this year , at what price must the company sell the car to achieve the desired annual profit ? | {
"A": "$ 4035",
"B": "$ 4036",
"C": "$ 9035",
"D": "$ 16140",
"E": "$ 36140"
} | divide(add(add(add(multiply(50, multiply(const_1000, const_1000)), 200000), multiply(20000, 5000)), add(multiply(30, multiply(const_1000, const_1000)), 500000)), 20000) | multiply(const_1000,const_1000)|multiply(n4,n5)|multiply(n2,#0)|multiply(n0,#0)|add(n3,#2)|add(n1,#3)|add(#4,#1)|add(#6,#5)|divide(#7,n5) | the ak company plans to make a profit of $ 30 , 500000 and it needs to earn the fixed costs of $ 50 , 200000 , so it needs to earn $ 80 , 700000 on top of the costs for the production of the 20000 cars . therefore , price of each car needs to be the unit costs plus $ 80 , 700000 / 20000 . after removing the 0 ' s , we end with the unit costs plus $ 8070 / 2 , which is $ 5000 plus $ 4035 . therefore , answer c is correct . | general |
math_qa__0HJLaqXH3xtuDiM7 | According to the directions on a packet of smoothie mix, 1 3-ounce packet of smoothie mix is to be combined with 15 ounces of water to make a smoothie. How many 3-ounce packets of smoothie mix are required to prepare 150 12-ounce smoothies? Choose the correct choice.
A) 120 B) 150 C) 180 D) 240 E) 600 | <gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">150 + 30</gadget>
<output>180</output>
<result>C</result> | C | 180 | According to the directions on a packet of smoothie mix, 1 3-ounce packet of smoothie mix is to be combined with 15 ounces of water to make a smoothie. How many 3-ounce packets of smoothie mix are required to prepare 150 12-ounce smoothies? | {
"A": "120",
"B": "150",
"C": "180",
"D": "240",
"E": "600"
} | add(150, multiply(3, const_10)) | multiply(n1,const_10)|add(n4,#0)| | "this question was n ' t particularly grueling , but i think it ' s the first where i had the opportunity to solve it via theory andinspectionthat many on this board suggest as strategy on the gmat . it actually came to me by accident . basically , if we thought that the 3 packets of powder were included in the 12 ounces of water , that would mean we would need 150 packets of smoothie mix ( along with 12 ( 150 ) ounces of water for a total of 150 packets . however , we know , after a more careful reading of the stimulus , that the 3 ounces are not included in the 12 ounces . as such , the answer has to be less than 150 packets , since 150 would be too much powder considering you already have 150 ( 12 ) ounces of water and need less packets than water to make a smoothie . as such , the only answer less than 150 is 120 , a . does this make sense ? or am i way off base ? c" | general |
math_qa__QBjjWRncdRH4rLbp | how many 3 - digit numbers are divisible by 6 in all ?
Choose the correct choice
A) 149 B) 150 C) 151 D) 166 E) none | <gadget id="calculator">1_000 / 6</gadget>
<output>500/3 = around 166.666667</output>
<gadget id="calculator">100 / 6</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">(500/3) - (50/3)</gadget>
<output>150</output>
<result>B</result> | B | 150 | how many 3 - digit numbers are divisible by 6 in all ? | {
"A": "149",
"B": "150",
"C": "151",
"D": "166",
"E": "none"
} | subtract(divide(const_1000, 6), divide(const_100, 6)) | divide(const_1000,n1)|divide(const_100,n1)|subtract(#0,#1) | solution required numbers are 102 , 018114 , . . . . 996 . this is an a . p with a = 102 , d = 6 . let the number of its terms be n . then a + ( n - 1 ) d ‹ = › 102 + ( n - 1 ) × 6 = 996 ‹ = › n = 150 . answer b | general |
math_qa__iLMBPW7mVEefMnS2 | If 7^k = 2, then 7^(4k+2) =
Choose the correct choice from the following answers: A) 729 B) 754 C) 784 D) 783 E) 108 | <gadget id="calculator">2 ** 4</gadget>
<output>16</output>
<gadget id="calculator">7 ** 2</gadget>
<output>49</output>
<gadget id="calculator">16 * 49</gadget>
<output>784</output>
<result>C</result> | C | 784 | If 7^k = 2, then 7^(4k+2) = | {
"A": "729",
"B": "754",
"C": "784",
"D": "783",
"E": "108"
} | multiply(power(2, 4), power(7, 2)) | power(n1,n3)|power(n0,n4)|multiply(#0,#1)| | "7 ^ k = 2 7 ^ 4 k = 2 ^ 4 7 ^ 4 k = 16 7 ^ ( 4 k + 2 ) = 7 ^ 4 k * 7 ^ 2 = 16 * 49 = 784 answer : c" | general |
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