id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__mUBWAuKbnBzp7xBk | A and B invests Rs.3000 and Rs.6000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit?
Choose the correct choice from the following.
A) 9 : 6
B) 3 : 8
C) 3 : 1
D) 9 : 9
E) 3 : 4 | <gadget id="calculator">3_000 * 6</gadget>
<output>18_000</output>
<gadget id="calculator">3_000 * 2</gadget>
<output>6_000</output>
<gadget id="calculator">6_000 * 6</gadget>
<output>36_000</output>
<gadget id="calculator">18_000 + 36_000</gadget>
<output>54_000</output>
<gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">6_000 * 12</gadget>
<output>72_000</output>
<gadget id="calculator">54_000 / 72_000</gadget>
<output>3/4 = around 0.75</output>
<result>E</result> | E | 0.75 | A and B invests Rs.3000 and Rs.6000 respectively in a business. If A doubles his capital after 6 months. In what ratio should A and B divide that year's profit? | {
"A": "9 : 6",
"B": "3 : 8",
"C": "3 : 1",
"D": "9 : 9",
"E": "3 : 4"
} | divide(add(multiply(3000, 6), multiply(multiply(3000, const_2), 6)), multiply(6000, add(6, 6))) | add(n2,n2)|multiply(n0,n2)|multiply(n0,const_2)|multiply(n2,#2)|multiply(n1,#0)|add(#1,#3)|divide(#5,#4)| | "( 3 * 6 + 6 * 6 ) : ( 6 * 12 ) 18 : 24 = > 3 : 4 . answer : e" | gain |
math_qa__6JDw1gZldwDoJC79 | Albert buys 4 horses and 9 cows for Rs. 13,400. If he sells the horses at 10% profit and the cows at 20% profit, then he earns a total profit of Rs. 1880. The cost of a horse is? Choose one:
A) 1299 B) 2788 C) 2000 D) 2981 E) 2881 | <gadget id="calculator">20 * 100</gadget>
<output>2_000</output>
<result>C</result> | C | 2,000 | Albert buys 4 horses and 9 cows for Rs. 13,400. If he sells the horses at 10% profit and the cows at 20% profit, then he earns a total profit of Rs. 1880. The cost of a horse is? | {
"A": "1299",
"B": "2788",
"C": "2000",
"D": "2981",
"E": "2881"
} | multiply(20, const_100) | multiply(n4,const_100) | explanation : let c . p . of each horse be rs . x and c . p . of each cow be rs . y . then , 4 x + 9 y = 13400 - - ( i ) and , 10 % of 4 x + 20 % of 9 y = 1880 2 / 5 x + 9 / 5 y = 1880 = > 2 x + 9 y = 9400 - - ( ii ) solving ( i ) and ( ii ) , we get : x = 2000 and y = 600 . cost price of each horse = rs . 2000 . answer : c | gain |
math_qa__7dWURkOk4DDwx8vy | When positive integer x is divided by positive integer y, the remainder is 8. If x/y = 76.4, what is the value of y? Choose the correct choice from the following answers:
A) 20
B) 22
C) 23
D) 24
E) 25 | <gadget id="calculator">floor(76.4)</gadget>
<output>76</output>
<gadget id="calculator">76.4 - 76</gadget>
<output>0.4</output>
<gadget id="calculator">8 / 0.4</gadget>
<output>20</output>
<result>A</result> | A | 20 | When positive integer x is divided by positive integer y, the remainder is 8. If x/y = 76.4, what is the value of y? | {
"A": "20",
"B": "22",
"C": "23",
"D": "24",
"E": "25"
} | divide(8, subtract(76.4, floor(76.4))) | floor(n1)|subtract(n1,#0)|divide(n0,#1)| | "when positive integer x is divided by positive integer y , the remainder is 8 - - > x = qy + 8 ; x / y = 76.4 - - > x = 76 y + 0.4 y ( so q above equals to 76 ) ; 0.4 y = 8 - - > y = 20 . answer : a ." | general |
math_qa__QJrPpuaDbvYRoxtJ | In a group of 120 people, 90 have an age of more 30 years, and the others have an age of less than 20 years. If a person is selected at random from this group, what is the probability the person's age is less than 20? Pick
A) 60 / 120 B) 15 / 120 C) 30 / 120 D) 80 / 120 E) 40 / 120 | <gadget id="calculator">120 - 90</gadget>
<output>30</output>
<gadget id="calculator">30 / 120</gadget>
<output>1/4 = around 0.25</output>
<result>C</result> | C | 0.25 | In a group of 120 people, 90 have an age of more 30 years, and the others have an age of less than 20 years. If a person is selected at random from this group, what is the probability the person's age is less than 20? | {
"A": "60 / 120",
"B": "15 / 120",
"C": "30 / 120",
"D": "80 / 120",
"E": "40 / 120"
} | divide(subtract(120, 90), 120) | subtract(n0,n1)|divide(#0,n0)| | "number of people whose age is less than 20 is given by 120 - 90 = 30 probability p that a person selected at random from the group is less than 20 is gieven by 30 / 120 = 0.25 correct answer c" | general |
math_qa__Z2LAGqRaOV3C5P9N | Given that 268x74= 19432, find the value of 2.68x.74. Choose the correct option:
A) 1.9432 B) 1.0025 C) 1.5693 D) 1.0266 E) none | <gadget id="calculator">268 / 100</gadget>
<output>67/25 = around 2.68</output>
<gadget id="calculator">74 / 100</gadget>
<output>37/50 = around 0.74</output>
<gadget id="calculator">(67/25) * (37/50)</gadget>
<output>2_479/1_250 = around 1.9832</output>
<result>A</result> | A | 1.9432 | Given that 268x74= 19432, find the value of 2.68x.74. | {
"A": "1.9432",
"B": "1.0025",
"C": "1.5693",
"D": "1.0266",
"E": "none"
} | multiply(divide(268, const_100), divide(74, const_100)) | divide(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)| | "solution sum of decimals places = ( 2 + 2 ) = 4 . therefore , = 2.68 × . 74 = 1.9432 answer a" | general |
math_qa__0SSrio435GUpha9J | Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 300 milliliters of solution X to create a solution that is 22 percent alcohol by volume? Choose the correct answer: A) 300 B) 350 C) 400 D) 450 E) 500 | <gadget id="calculator">22 - 10</gadget>
<output>12</output>
<gadget id="calculator">30 - 22</gadget>
<output>8</output>
<gadget id="calculator">12 / 8</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 300</gadget>
<output>450</output>
<result>D</result> | D | 450 | Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 300 milliliters of solution X to create a solution that is 22 percent alcohol by volume? | {
"A": "300",
"B": "350",
"C": "400",
"D": "450",
"E": "500"
} | multiply(divide(subtract(22, 10), subtract(30, 22)), 300) | subtract(n3,n0)|subtract(n1,n3)|divide(#0,#1)|multiply(n2,#2)| | "22 % is 12 % - points higher than 10 % but 8 % - points lower than 30 % . thus there should be 2 parts of solution x for 3 parts of solution y . we should add 450 ml of solution y . the answer is d ." | general |
math_qa__o3vnuzjssdoZ0Rwc | Find the area of circle whose radius is 7m? Choose the correct choice:
A) 121 sq m B) 184 sq m C) 174 sq m D) 124 sq m E) 154 sq m | <gadget id="calculator">pi * (7 ** 2)</gadget>
<output>49*pi = around 153.93804</output>
<result>E</result> | E | 154 | Find the area of circle whose radius is 7m? | {
"A": "121 sq m",
"B": "184 sq m",
"C": "174 sq m",
"D": "124 sq m",
"E": "154 sq m"
} | circle_area(7) | circle_area(n0) | the area of circle = pie * r ^ 2 = 22 / 7 * 7 * 7 = 154 sq m answer : e | geometry |
math_qa__daUN7tDmyUF9WgUv | Walking at 5/6 of its usual speed, a train is 10 minutes too late. Find its usual time to cover the journey. Choose the correct choice from the following choices.
A) 50 min
B) 20 min
C) 1 hour
D) 30 min
E) 45 min | <gadget id="calculator">5 / 6</gadget>
<output>5/6 = around 0.833333</output>
<gadget id="calculator">1 / (5/6)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) - 1</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">10 / (1/5)</gadget>
<output>50</output>
<result>A</result> | A | 50 | Walking at 5/6 of its usual speed, a train is 10 minutes too late. Find its usual time to cover the journey. | {
"A": "50 min",
"B": "20 min",
"C": "1 hour",
"D": "30 min",
"E": "45 min"
} | divide(10, subtract(inverse(divide(5, 6)), const_1)) | divide(n0,n1)|inverse(#0)|subtract(#1,const_1)|divide(n2,#2)| | "new speed = 5 / 6 of the usual speed new time taken = 6 / 5 of the usual time taken so , ( 6 / 5 of the usual time ) - ( usual time ) = 10 min 1 / 5 of the usual time = 10 min usual time = 10 * 5 = 50 min correct option is a" | physics |
math_qa__QX9thm5xodgZEbXx | In the rectangle below, the line MN cuts the rectangle into two regions. Find x the length of segment NB so that the area of the quadrilateral MNBC is 40% of the total area of the rectangle. Select the correct option
A) 1 meter
B) 2 meter
C) 3 meter
D) 4 meter
E) 5 meter | <gadget id="calculator">40 / 12</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(10/3) - (1/3)</gadget>
<output>3</output>
<gadget id="calculator">3 - 2</gadget>
<output>1</output>
<result>A</result> | A | 1 | In the rectangle below, the line MN cuts the rectangle into two regions. Find x the length of segment NB so that the area of the quadrilateral MNBC is 40% of the total area of the rectangle. | {
"A": "1 meter",
"B": "2 meter",
"C": "3 meter",
"D": "4 meter",
"E": "5 meter"
} | subtract(subtract(divide(40, const_12), const_0_33), const_2) | divide(n0,const_12)|subtract(#0,const_0_33)|subtract(#1,const_2) | solution we first note that mc = 20 - 5 = 15 the quadrilateral mnbc is a trapezoid and its area a is given by a = ( 1 / 2 ) × 10 × ( x + mc ) = 5 ( x + 15 ) 40 % of the area of the rectangle is equal to 40 % × ( 20 × 10 ) = ( 40 / 100 ) × 200 = 80 since the area of mnbc is equal to 40 % the area of the rectangle , we can write 5 ( x + 15 ) = 80 5 x + 75 = 80 5 x = 5 x = 1 meter answer is a | geometry |
math_qa__4ODp7OLoSjkw5mxh | Two trains of equal lengths take 15 sec and 20 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction? Choices.
A) 16 sec B) 12 sec C) 17 sec D) 21 sec E) 23 sec | <gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">120 / 20</gadget>
<output>6</output>
<gadget id="calculator">120 / 15</gadget>
<output>8</output>
<gadget id="calculator">6 + 8</gadget>
<output>14</output>
<gadget id="calculator">240 / 14</gadget>
<output>120/7 = around 17.142857</output>
<result>C</result> | C | 17 | Two trains of equal lengths take 15 sec and 20 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction? | {
"A": "16 sec",
"B": "12 sec",
"C": "17 sec",
"D": "21 sec",
"E": "23 sec"
} | divide(multiply(120, const_2), add(speed(120, 20), speed(120, 15))) | multiply(n2,const_2)|speed(n2,n1)|speed(n2,n0)|add(#1,#2)|divide(#0,#3)| | "speed of the first train = 120 / 15 = 8 m / sec . speed of the second train = 120 / 20 = 6 m / sec . relative speed = 8 + 6 = 14 m / sec . required time = ( 120 + 120 ) / 14 = 17 sec . answer : c" | physics |
math_qa__EhV4MEYpZp7nutTM | The floor of a rectangular room is 20 m long and 12 m wide. The room is surrounded by a veranda of width 2 m on all its sides. The area of the veranda is : Choices:
A) 144 m 2
B) 120 m 2
C) 108 m 2
D) 158 m 2
E) none of these | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 + 20</gadget>
<output>24</output>
<gadget id="calculator">12 + 4</gadget>
<output>16</output>
<gadget id="calculator">24 * 16</gadget>
<output>384</output>
<gadget id="calculator">20 * 12</gadget>
<output>240</output>
<gadget id="calculator">384 - 240</gadget>
<output>144</output>
<result>A</result> | A | 144 | The floor of a rectangular room is 20 m long and 12 m wide. The room is surrounded by a veranda of width 2 m on all its sides. The area of the veranda is : | {
"A": "144 m 2",
"B": "120 m 2",
"C": "108 m 2",
"D": "158 m 2",
"E": "none of these"
} | subtract(rectangle_area(add(multiply(2, 2), 20), add(12, multiply(2, 2))), rectangle_area(20, 12)) | multiply(n2,n2)|rectangle_area(n0,n1)|add(n0,#0)|add(n1,#0)|rectangle_area(#2,#3)|subtract(#4,#1)| | "area of the outer rectangle = 24 ã — 16 = 384 m 2 area of the inner rectangle = 20 ã — 12 = 240 m 2 required area = ( 304 â € “ 180 ) = 144 m 2 answer a" | geometry |
math_qa__ZeOt9ftk2bRaSuZ3 | The average weight of a class is x pounds. When a new student weighing 90 pounds joins the class, the average decreases by 1 pound. In a few months the student’s weight increases to 110 pounds and the average weight of the class becomes x + 4 pounds. None of the other students’ weights changed. What is the value of x? Choose the correct choice from the following options
A) 85 B) 86 C) 88 D) 90 E) 99 | <gadget id="calculator">90 + 4</gadget>
<output>94</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">94 + 5</gadget>
<output>99</output>
<result>E</result> | E | 99 | The average weight of a class is x pounds. When a new student weighing 90 pounds joins the class, the average decreases by 1 pound. In a few months the student’s weight increases to 110 pounds and the average weight of the class becomes x + 4 pounds. None of the other students’ weights changed. What is the value of x? | {
"A": "85",
"B": "86",
"C": "88",
"D": "90",
"E": "99"
} | add(add(90, 4), add(4, 1)) | add(n0,n3)|add(n1,n3)|add(#0,#1) | when the student weighs 90 pounds the average weight is x - 1 pounds ; when the student weighs 110 pounds the average weight is x + 4 pounds . so , the increase in total weight of 110 - 90 = 20 pounds corresponds to the increase in average weight of ( x + 4 ) - ( x - 1 ) = 5 pounds , which means that there are 20 / 5 = 4 students ( including the new one ) . so , initially there were 5 student . total weight = 5 x + 90 = 6 ( x - 1 ) - - > x = 96 pounds . answer : e . | general |
math_qa__azXRaHizU53OmcjT | A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.200 more. What was the Sum? Select the correct option.
A) s . 550
B) s . 1000
C) s . 600
D) s . 200
E) s . 400 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 10</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">200 / (1/2)</gadget>
<output>400</output>
<result>E</result> | E | 400 | A sum was put at simple interest at a certain rate for 10 years . Had it been put at 5% higher rate , it would have fetched Rs.200 more. What was the Sum? | {
"A": "s . 550",
"B": "s . 1000",
"C": "s . 600",
"D": "s . 200",
"E": "s . 400"
} | divide(200, multiply(divide(5, const_100), 10)) | divide(n1,const_100)|multiply(n0,#0)|divide(n2,#1)| | "at 5 % more rate , the increase in s . i for 10 years = rs . 200 ( given ) so , at 5 % more rate , the increase in si for 1 year = 200 / 10 = rs . 20 / - i . e . rs . 20 is 5 % of the invested sum so , 1 % of the invested sum = 20 / 5 therefore , the invested sum = 20 × 100 / 5 = rs . 400 answer : e" | gain |
math_qa__h6XAz3Dt2QPfJaOU | What is the total number of positive integers that are less than 500 and that have no positive factor in common with 500 other than 1? Choose the correct answer
A) 50 B) 100 C) 200 D) 300 E) 400 | <gadget id="calculator">500 - 1</gadget>
<output>499</output>
<gadget id="calculator">500 - 2</gadget>
<output>498</output>
<gadget id="calculator">498 - 2</gadget>
<output>496</output>
<gadget id="calculator">496 / 2</gadget>
<output>248</output>
<gadget id="calculator">248 + 1</gadget>
<output>249</output>
<gadget id="calculator">500 / 100</gadget>
<output>5</output>
<gadget id="calculator">500 - 5</gadget>
<output>495</output>
<gadget id="calculator">495 - 5</gadget>
<output>490</output>
<gadget id="calculator">490 / 5</gadget>
<output>98</output>
<gadget id="calculator">98 + 1</gadget>
<output>99</output>
<gadget id="calculator">249 + 99</gadget>
<output>348</output>
<gadget id="calculator">500 - 10</gadget>
<output>490</output>
<gadget id="calculator">490 - 10</gadget>
<output>480</output>
<gadget id="calculator">480 / 10</gadget>
<output>48</output>
<gadget id="calculator">48 + 1</gadget>
<output>49</output>
<gadget id="calculator">348 - 49</gadget>
<output>299</output>
<gadget id="calculator">499 - 299</gadget>
<output>200</output>
<result>C</result> | C | 200 | What is the total number of positive integers that are less than 500 and that have no positive factor in common with 500 other than 1? | {
"A": "50",
"B": "100",
"C": "200",
"D": "300",
"E": "400"
} | subtract(subtract(500, const_1), subtract(add(add(divide(subtract(subtract(500, const_2), const_2), const_2), const_1), add(divide(subtract(subtract(500, divide(500, const_100)), divide(500, const_100)), divide(500, const_100)), const_1)), add(divide(subtract(subtract(500, const_10), const_10), const_10), 1))) | divide(n0,const_100)|subtract(n0,const_1)|subtract(n0,const_2)|subtract(n0,const_10)|subtract(#2,const_2)|subtract(n0,#0)|subtract(#3,const_10)|divide(#4,const_2)|divide(#6,const_10)|subtract(#5,#0)|add(#7,const_1)|add(n2,#8)|divide(#9,#0)|add(#12,const_1)|add(#10,#13)|subtract(#14,#11)|subtract(#1,#15) | since 500 = 2 ^ 2 * 5 ^ 3 then a number can not have 2 and / or 5 as a factor . the odd numbers do not have 2 as a factor and there are 250 odd numbers from 1 to 500 . we then need to eliminate the 50 numbers that end with 5 , that is 5 , 15 , 25 , . . . , 495 . there are a total of 250 - 50 = 200 such numbers between 1 and 500 . the answer is c . | general |
math_qa__dfe30m7J3M2NAlVz | A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 8 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled? Choose the most appropriate option: A) 7.5 B) 7.4 C) 7.9 D) 7.2 E) 8.0 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/4) - (1/8)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / (1/8)</gadget>
<output>8</output>
<result>E</result> | E | 8 | A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 8 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled? | {
"A": "7.5",
"B": "7.4",
"C": "7.9",
"D": "7.2",
"E": "8.0"
} | divide(const_1, subtract(divide(const_1, 4), divide(const_1, 8))) | divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|divide(const_1,#2)| | "net part filled in 1 hour = ( 1 / 4 - 1 / 9 ) = 1 / 8 the cistern will be filled in 8 / 1 hrs i . e . , 8 hrs . answer : e" | physics |
math_qa__IkJ6xTr7RsXIrv7L | In a simultaneous throw of pair of dice. Find the probability of getting the total more than 7. Choose one: A) 5 / 19 B) 5 / 12 C) 5 / 28 D) 5 / 10 E) 5 / 11 | <gadget id="calculator">7 + 4</gadget>
<output>11</output>
<gadget id="calculator">11 + 4</gadget>
<output>15</output>
<gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 6</gadget>
<output>36</output>
<gadget id="calculator">15 / 36</gadget>
<output>5/12 = around 0.416667</output>
<result>B</result> | B | 0.416667 | In a simultaneous throw of pair of dice. Find the probability of getting the total more than 7. | {
"A": "5 / 19",
"B": "5 / 12",
"C": "5 / 28",
"D": "5 / 10",
"E": "5 / 11"
} | divide(add(add(7, const_4), const_4), multiply(add(const_4, const_2), add(const_4, const_2))) | add(n0,const_4)|add(const_2,const_4)|add(#0,const_4)|multiply(#1,#1)|divide(#2,#3)| | "explanation : here n ( s ) = ( 6 x 6 ) = 36 let e = event of getting a total more than 7 = { ( 2,6 ) , ( 3,5 ) , ( 3,6 ) , ( 4,4 ) , ( 4,5 ) , ( 4,6 ) , ( 5,3 ) , ( 5,4 ) , ( 5,5 ) , ( 5,6 ) , ( 6,2 ) , ( 6,3 ) , ( 6,4 ) , ( 6,5 ) , ( 6,6 ) } therefore , p ( e ) = n ( e ) / n ( s ) = 15 / 36 = 5 / 12 . answer : b ) 5 / 12" | general |
math_qa__oAMXtrxoVhfvRrAm | krishan and nandan jointly started a business . krishan invested 6 times as nandan did and invested his money for double time as compared to nandan . nandan earned rs . 6000 . if the gain is proportional to the money invested and the time for which the money is invested then the total gain was ? Answers
A) rs . 78000 B) rs . 48000 C) rs . 6000 D) rs . 82000 E) rs . 32000 | <gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 + 1</gadget>
<output>13</output>
<gadget id="calculator">6_000 * 13</gadget>
<output>78_000</output>
<result>A</result> | A | 78,000 | krishan and nandan jointly started a business . krishan invested 6 times as nandan did and invested his money for double time as compared to nandan . nandan earned rs . 6000 . if the gain is proportional to the money invested and the time for which the money is invested then the total gain was ? | {
"A": "rs . 78000",
"B": "rs . 48000",
"C": "rs . 6000",
"D": "rs . 82000",
"E": "rs . 32000"
} | multiply(6000, add(multiply(6, const_2), const_1)) | multiply(n0,const_2)|add(#0,const_1)|multiply(n1,#1) | 6 : 1 2 : 1 - - - - - - 12 : 1 1 - - - - - 6000 13 - - - - - ? = > rs . 78,000 answer : a | general |
math_qa__EJFVmmiPehOKFWH9 | Consider the word ROTOR. Whichever way you read it, from left to right or from right to left, you get the same word. Such a word is known as palindrome. Find the maximum possible number of 5-letter palindromes Answers
A) 1700 B) 7570 C) 1576 D) 17576 E) 500 | <gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 3</gadget>
<output>23</output>
<gadget id="calculator">23 + 3</gadget>
<output>26</output>
<gadget id="calculator">5 - 2</gadget>
<output>3</output>
<gadget id="calculator">26 ** 3</gadget>
<output>17_576</output>
<result>D</result> | D | 17,576 | Consider the word ROTOR. Whichever way you read it, from left to right or from right to left, you get the same word. Such a word is known as palindrome. Find the maximum possible number of 5-letter palindromes | {
"A": "1700",
"B": "7570",
"C": "1576",
"D": "17576",
"E": "500"
} | power(add(add(add(const_10, const_10), const_3), const_3), subtract(5, const_2)) | add(const_10,const_10)|subtract(n0,const_2)|add(#0,const_3)|add(#2,const_3)|power(#3,#1) | the first letter from the right can be chosen in 26 ways because there are 26 alphabets . having chosen this , the second letter can be chosen in 26 ways . = > the first two letters can be chosen in 26 ã — 26 = 67626 ã — 26 = 676 ways having chosen the first two letters , the third letter can be chosen in 26 ways . = > all the three letters can be chosen in 676 ã — 26 = 17576676 ã — 26 = 17576 ways . it implies that the maximum possible number of five letter palindromes is 17576 because the fourth letter is the same as the second letter and the fifth letter is the same as the first letter . answer d | general |
math_qa__ibZ3mdI4bfAREnIM | A glass was filled with 25 ounces of water, and 0.04 ounce of the water evaporated each day during a 10-day period. What percent of the original amount of water evaporated during this period? Choose the correct choice from the following
A) 0.004 % B) 0.04 % C) 0.4 % D) 1.6 % E) 20 % | <gadget id="calculator">0.04 * 10</gadget>
<output>0.4</output>
<gadget id="calculator">0.4 / 25</gadget>
<output>0.016</output>
<gadget id="calculator">0.016 * 100</gadget>
<output>1.6</output>
<result>D</result> | D | 1.6 | A glass was filled with 25 ounces of water, and 0.04 ounce of the water evaporated each day during a 10-day period. What percent of the original amount of water evaporated during this period? | {
"A": "0.004 %",
"B": "0.04 %",
"C": "0.4 %",
"D": "1.6 %",
"E": "20 %"
} | multiply(divide(multiply(0.04, 10), 25), const_100) | multiply(n1,n2)|divide(#0,n0)|multiply(#1,const_100)| | "in 10 days 10 * 0.04 = 0.4 ounces of water evaporated , which is 0.4 / 25 â ˆ — 100 = 1.6 of the original amount of water . answer : d ." | gain |
math_qa__p5YOkQv1qrhCljE9 | Vijay lent out an amount Rs. 10000 into two parts, one at 8% p.a. and the remaining at 10% p.a. both on simple interest. At the end of the year he received Rs. 850 as total interest. What was the amount he lent out at 8% pa.a? Choose one.
A) rs . 15000 B) rs . 6000 C) rs . 25000 D) rs . 10000 E) rs . 18000 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) * 10_000</gadget>
<output>1_000</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">1_000 + (2/25)</gadget>
<output>25_002/25 = around 1_000.08</output>
<gadget id="calculator">(25_002/25) - 850</gadget>
<output>3_752/25 = around 150.08</output>
<gadget id="calculator">(3_752/25) * 100</gadget>
<output>15_008</output>
<result>A</result> | A | 15,000 | Vijay lent out an amount Rs. 10000 into two parts, one at 8% p.a. and the remaining at 10% p.a. both on simple interest. At the end of the year he received Rs. 850 as total interest. What was the amount he lent out at 8% pa.a? | {
"A": "rs . 15000",
"B": "rs . 6000",
"C": "rs . 25000",
"D": "rs . 10000",
"E": "rs . 18000"
} | multiply(subtract(add(multiply(divide(10, const_100), 10000), divide(8, const_100)), 850), const_100) | divide(n1,const_100)|divide(n2,const_100)|multiply(n0,#1)|add(#0,#2)|subtract(#3,n3)|multiply(#4,const_100) | let the amount lent out at 8 % p . a . be rs . a = > ( a * 8 ) / 100 + [ ( 10000 - a ) * 10 ] / 100 = 850 = > a = rs . 15000 . answer : a | gain |
math_qa__Ey2h6MFyWGHbNJbV | Find k if 64 ÷ k = 4. Choose the correct choice from the following:
A) 8 B) 16 C) 24 D) 36 E) 40 | <gadget id="calculator">64 / 4</gadget>
<output>16</output>
<result>B</result> | B | 16 | Find k if 64 ÷ k = 4. | {
"A": "8",
"B": "16",
"C": "24",
"D": "36",
"E": "40"
} | divide(64, 4) | divide(n0,n1)| | "since 64 ÷ k = 4 and 64 ÷ 16 = 4 , then k = 16 correct answer b" | general |
math_qa__v8QXEm0tK5lGwbqB | What is the area of square field whose side of length 12 m?
Choices:
A) 225 sq m B) 144 sq m C) 586 sq m D) 287 sq m E) 296 sq m | <gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<result>B</result> | B | 144 | What is the area of square field whose side of length 12 m? | {
"A": "225 sq m",
"B": "144 sq m",
"C": "586 sq m",
"D": "287 sq m",
"E": "296 sq m"
} | square_area(12) | square_area(n0)| | "12 * 12 = 144 sq m answer : b" | geometry |
math_qa__Pak63JDiHHeIWJrU | The mean of 50 observations is 200. But later he found that there is decrements of 9 from each observations. what is the the updated mean is ? Choose the correct choice from the following answers:
A) 165 B) 185 C) 190 D) 191 E) 199 | <gadget id="calculator">200 - 9</gadget>
<output>191</output>
<result>D</result> | D | 191 | The mean of 50 observations is 200. But later he found that there is decrements of 9 from each observations. what is the the updated mean is ? | {
"A": "165",
"B": "185",
"C": "190",
"D": "191",
"E": "199"
} | subtract(200, 9) | subtract(n1,n2)| | "191 answer is d" | general |
math_qa__hLdPGDptBbmLi9P1 | A couple spent $184.80 in total while dining out and paid this amount using a credit card. The $184.80 figure included a 20 percent tip which was paid on top of the price which already included a sales tax of 10 percent on top of the price of the food. What was the actual price of the food before tax and tip?
Choose the correct choice from the following answers: A) $ 124 B) $ 132 C) $ 140 D) $ 148 E) $ 156 | <gadget id="calculator">184.8 * 100</gadget>
<output>18_480</output>
<gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">18_480 / 120</gadget>
<output>154</output>
<gadget id="calculator">154 * 100</gadget>
<output>15_400</output>
<gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">15_400 / 110</gadget>
<output>140</output>
<result>C</result> | C | 140 | A couple spent $184.80 in total while dining out and paid this amount using a credit card. The $184.80 figure included a 20 percent tip which was paid on top of the price which already included a sales tax of 10 percent on top of the price of the food. What was the actual price of the food before tax and tip? | {
"A": "$ 124",
"B": "$ 132",
"C": "$ 140",
"D": "$ 148",
"E": "$ 156"
} | divide(multiply(divide(multiply(184.80, const_100), add(const_100, 20)), const_100), add(const_100, 10)) | add(n2,const_100)|add(n3,const_100)|multiply(n0,const_100)|divide(#2,#0)|multiply(#3,const_100)|divide(#4,#1)| | "let the price of the meal be x . after a 10 % sales tax addition , the price is 1.1 * x after a 20 % tip on this amount , the total is 1.2 * 1.1 * x = 1.32 x 1.32 x = 184.80 x = 140 the correct answer is c ." | general |
math_qa__R6uAXytXV0vv8Lqa | Running at the same rate, 8 identical machines can produce 560 paperclips a minute. At this rate, how many paperclips could 30 machines produce in 6 minutes?
Choose the correct choice from the following answers: A) 1344 B) 3360 C) 8400 D) 12600 E) 67200 | <gadget id="calculator">30 / 8</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">560 * (15/4)</gadget>
<output>2_100</output>
<gadget id="calculator">2_100 * 6</gadget>
<output>12_600</output>
<result>D</result> | D | 12,600 | Running at the same rate, 8 identical machines can produce 560 paperclips a minute. At this rate, how many paperclips could 30 machines produce in 6 minutes? | {
"A": "1344",
"B": "3360",
"C": "8400",
"D": "12600",
"E": "67200"
} | multiply(multiply(560, divide(30, 8)), 6) | divide(n2,n0)|multiply(n1,#0)|multiply(n3,#1)| | "8 machines produce 560 in 1 min 8 machines produce 560 * 6 in 6 min 30 machine produce 560 * 6 * ( 30 / 8 ) in 6 minutes 560 * 6 * 30 / 8 = 12600 answer is d ." | gain |
math_qa__WirkUz4xWCgQD0fU | A man can do a piece of work in 5days, but with the help of his son, he can do it in 3 days. In what time can the son do it alone? Pick one.
A) 13 / 2 B) 7 C) 15 / 2 D) 8 E) 9 | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">15 / 2</gadget>
<output>15/2 = around 7.5</output>
<result>C</result> | C | 7.5 | A man can do a piece of work in 5days, but with the help of his son, he can do it in 3 days. In what time can the son do it alone? | {
"A": "13 / 2",
"B": "7",
"C": "15 / 2",
"D": "8",
"E": "9"
} | divide(multiply(5, 3), subtract(5, 3)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)| | "son ' s 1 day ' s work = ( 1 / 3 ) - ( 1 / 5 ) = 2 / 5 the son alone can do the work in 15 / 2 days answer is c" | physics |
math_qa__cybOjQYhnv1qK7ko | Annika hikes at a constant rate of 10 minutes per kilometer. She has hiked 2.75 kilometers east from the start of a hiking trail when she realizes that she has to be back at the start of the trail in 45 minutes. If Annika continues east, then turns around and retraces her path to reach the start of the trail in exactly 45 minutes, for how many kilometers total did she hike east?
Choose the correct choice from the following answers
A) 3.625
B) 3.5
C) 4
D) 4.5
E) 5 | <gadget id="calculator">45 / 10</gadget>
<output>9/2 = around 4.5</output>
<gadget id="calculator">(9/2) - 2.75</gadget>
<output>1.75</output>
<gadget id="calculator">1.75 / 2</gadget>
<output>0.875</output>
<gadget id="calculator">0.875 + 2.75</gadget>
<output>3.625</output>
<result>A</result> | A | 3.625 | Annika hikes at a constant rate of 10 minutes per kilometer. She has hiked 2.75 kilometers east from the start of a hiking trail when she realizes that she has to be back at the start of the trail in 45 minutes. If Annika continues east, then turns around and retraces her path to reach the start of the trail in exactly 45 minutes, for how many kilometers total did she hike east? | {
"A": "3.625",
"B": "3.5",
"C": "4",
"D": "4.5",
"E": "5"
} | add(divide(subtract(divide(45, 10), 2.75), const_2), 2.75) | divide(n2,n0)|subtract(#0,n1)|divide(#1,const_2)|add(n1,#2)| | "set up two r x t = d cases . 1 . 1 / 10 km / min x t = 2.75 from which t = 27.5 mins . we know total journey time now is 45 + 27.5 = 72.5 the rate is the same ie 1 / 10 km / min . set up second r x t = d case . 1 / 10 km / min x 72.5 = 7.25 km now the total journey would be halved as distance would be same in each direction . 7.25 / 2 = 3.625 . a ." | physics |
math_qa__HuvbCbP21itmG3xr | The average of 10 numbers is calculated as 20. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is? Choose the correct choice from the following options.
A) 12
B) 26
C) 16
D) 97
E) 20 | <gadget id="calculator">36 - 26</gadget>
<output>10</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<result>E</result> | E | 20 | The average of 10 numbers is calculated as 20. It is discovered later on that while calculating the average, one number namely 36 was wrongly read as 26. The correct average is? | {
"A": "12",
"B": "26",
"C": "16",
"D": "97",
"E": "20"
} | add(20, divide(subtract(36, 26), 10)) | subtract(n2,n3)|divide(#0,n0)|add(n1,#1)| | "10 * 20 + 36 – 26 = 200 / 10 = 20 answer : e" | general |
math_qa__Rs5iwCUUNtglinH2 | Two trains 161 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet? Answers:
A) 6.18 B) 7.12 C) 7.1 D) 8.09 E) 8.11 | <gadget id="calculator">161 + 165</gadget>
<output>326</output>
<gadget id="calculator">80 + 65</gadget>
<output>145</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">145 * (5/18)</gadget>
<output>725/18 = around 40.277778</output>
<gadget id="calculator">326 / (725/18)</gadget>
<output>5_868/725 = around 8.093793</output>
<result>D</result> | D | 8.09 | Two trains 161 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet? | {
"A": "6.18",
"B": "7.12",
"C": "7.1",
"D": "8.09",
"E": "8.11"
} | divide(add(161, 165), multiply(add(80, 65), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "t = ( 161 + 165 ) / ( 80 + 65 ) * 18 / 5 t = 8.09 answer : d" | physics |
math_qa__DlsyUrrt96ZrxIhz | The average weight of 8 person's increases by 4.2 kg when a new person comes in place of one of them weighing 65 kg. What is the weight of the new person? Choose the correct choice from the following
A) 75 kg
B) 50 kg
C) 85 kg
D) 80 kg
E) 98.6 kg | <gadget id="calculator">8 * 4.2</gadget>
<output>33.6</output>
<gadget id="calculator">33.6 + 65</gadget>
<output>98.6</output>
<result>E</result> | E | 98.6 | The average weight of 8 person's increases by 4.2 kg when a new person comes in place of one of them weighing 65 kg. What is the weight of the new person? | {
"A": "75 kg",
"B": "50 kg",
"C": "85 kg",
"D": "80 kg",
"E": "98.6 kg"
} | add(multiply(8, 4.2), 65) | multiply(n0,n1)|add(n2,#0)| | "explanation : total increase in weight = 8 ã — 4.2 = 33.6 if x is the weight of the new person , total increase in weight = x â ˆ ’ 65 = > 33.6 = x - 65 = > x = 33.6 + 65 = 98.6 answer : option e" | general |
math_qa__QR4R6wHM7noKUJkY | on sunday morning , pugsley and wednesday are trading pet spiders . if pugsley were to give wednesday two of his spiders , wednesday would then have 9 times as many spiders as pugsley does . but , if wednesday were to give pugsley 6 of her spiders , pugsley would now have 6 fewer spiders than wednesday had before they traded . how many pet spiders does pugsley have before the trading game commences ? Options.
A) 4 B) 6 C) 8 D) 10 E) 20 | <gadget id="calculator">6 + 6</gadget>
<output>12</output>
<gadget id="calculator">12 + 6</gadget>
<output>18</output>
<gadget id="calculator">12 * 9</gadget>
<output>108</output>
<gadget id="calculator">18 + 108</gadget>
<output>126</output>
<gadget id="calculator">126 + 2</gadget>
<output>128</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">128 / 8</gadget>
<output>16</output>
<gadget id="calculator">16 - 12</gadget>
<output>4</output>
<result>A</result> | A | 4 | on sunday morning , pugsley and wednesday are trading pet spiders . if pugsley were to give wednesday two of his spiders , wednesday would then have 9 times as many spiders as pugsley does . but , if wednesday were to give pugsley 6 of her spiders , pugsley would now have 6 fewer spiders than wednesday had before they traded . how many pet spiders does pugsley have before the trading game commences ? | {
"A": "4",
"B": "6",
"C": "8",
"D": "10",
"E": "20"
} | subtract(divide(add(add(add(add(6, 6), 6), multiply(add(6, 6), 9)), const_2), add(6, const_2)), add(6, 6)) | add(n1,n1)|add(n1,const_2)|add(n1,#0)|multiply(n0,#0)|add(#2,#3)|add(#4,const_2)|divide(#5,#1)|subtract(#6,#0) | if pugsley were to give wednesday two of his spiders , wednesday would then have nine times as many spiders as pugsley does : ( w + 2 ) = 9 ( p - 2 ) if wednesday were to give pugsley six of her spiders , pugsley would now have six fewer spiders than wednesday had before they traded : p + 6 = w - 6 solving gives p = 4 and w = 16 . answer : a . | physics |
math_qa__gTPIU73nutjLr6LU | Rates for having a manuscript typed at a certain typing service are $10 per page for the first time a page is typed and $5 per page each time a page is revised. If a certain manuscript has 100 pages, of which 30 were revised only once, 20 were revised twice, and the rest required no revisions, what was the total cost of having the manuscript typed?
Select the correct option.
A) $ 1250 B) $ 1350 C) $ 1150 D) $ 1360 E) $ 1370 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">30 * 5</gadget>
<output>150</output>
<gadget id="calculator">1_000 + 150</gadget>
<output>1_150</output>
<gadget id="calculator">20 * 5</gadget>
<output>100</output>
<gadget id="calculator">100 * 2</gadget>
<output>200</output>
<gadget id="calculator">1_150 + 200</gadget>
<output>1_350</output>
<result>B</result> | B | 1,350 | Rates for having a manuscript typed at a certain typing service are $10 per page for the first time a page is typed and $5 per page each time a page is revised. If a certain manuscript has 100 pages, of which 30 were revised only once, 20 were revised twice, and the rest required no revisions, what was the total cost of having the manuscript typed? | {
"A": "$ 1250",
"B": "$ 1350",
"C": "$ 1150",
"D": "$ 1360",
"E": "$ 1370"
} | add(add(multiply(100, 10), multiply(30, 5)), multiply(multiply(20, 5), const_2)) | multiply(n0,n2)|multiply(n1,n3)|multiply(n1,n4)|add(#0,#1)|multiply(#2,const_2)|add(#3,#4)| | "50 pages typed 1 x 30 pages typed 2 x ( original + one revision ) 20 pages typed 3 x ( original + two revisions ) 50 ( 10 ) + 30 ( 10 + 5 ) + 20 ( 10 + 5 + 5 ) = 500 + 450 + 400 = 1350 answer - b" | general |
math_qa__Jy7P3TBbmA2BzsGk | Shekhar started a business investing Rs. 25,000 in 1999. In 2000, he invested an additional amount of Rs. 10,000 and Rajeev joined him with an amount of Rs. 35,000. In 2001, Shekhar invested another additional amount of Rs. 10,000 and Jatin joined them with an amount of Rs. 35,000. What will be Rajeev’s share in the profit of Rs. 1,50,000 earned at the end of 3 years from the start of the business in 1999?. Pick one.
A) rs . 10000 B) rs . 20000 C) rs . 30000 D) rs . 40000 E) rs . 50000 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">10 * 100</gadget>
<output>1_000</output>
<gadget id="calculator">35 * 1_000</gadget>
<output>35_000</output>
<gadget id="calculator">35_000 * 2</gadget>
<output>70_000</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">10 * 1_000</gadget>
<output>10_000</output>
<gadget id="calculator">15 * 10_000</gadget>
<output>150_000</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 1_000</gadget>
<output>25_000</output>
<gadget id="calculator">25_000 * 3</gadget>
<output>75_000</output>
<gadget id="calculator">75_000 + 70_000</gadget>
<output>145_000</output>
<gadget id="calculator">10_000 * 2</gadget>
<output>20_000</output>
<gadget id="calculator">145_000 + 20_000</gadget>
<output>165_000</output>
<gadget id="calculator">165_000 + 10_000</gadget>
<output>175_000</output>
<gadget id="calculator">175_000 + 35_000</gadget>
<output>210_000</output>
<gadget id="calculator">150_000 / 210_000</gadget>
<output>5/7 = around 0.714286</output>
<gadget id="calculator">70_000 * (5/7)</gadget>
<output>50_000</output>
<result>E</result> | E | 50,000 | Shekhar started a business investing Rs. 25,000 in 1999. In 2000, he invested an additional amount of Rs. 10,000 and Rajeev joined him with an amount of Rs. 35,000. In 2001, Shekhar invested another additional amount of Rs. 10,000 and Jatin joined them with an amount of Rs. 35,000. What will be Rajeev’s share in the profit of Rs. 1,50,000 earned at the end of 3 years from the start of the business in 1999?. | {
"A": "rs . 10000",
"B": "rs . 20000",
"C": "rs . 30000",
"D": "rs . 40000",
"E": "rs . 50000"
} | multiply(multiply(multiply(multiply(add(const_3, const_4), add(const_2, const_3)), multiply(multiply(add(const_2, const_3), const_2), const_100)), const_2), divide(multiply(multiply(const_3, add(const_2, const_3)), multiply(multiply(add(const_2, const_3), const_2), multiply(multiply(add(const_2, const_3), const_2), const_100))), add(add(add(add(multiply(multiply(multiply(add(const_2, const_3), add(const_2, const_3)), multiply(multiply(add(const_2, const_3), const_2), const_100)), const_3), multiply(multiply(multiply(add(const_3, const_4), add(const_2, const_3)), multiply(multiply(add(const_2, const_3), const_2), const_100)), const_2)), multiply(multiply(multiply(add(const_2, const_3), const_2), multiply(multiply(add(const_2, const_3), const_2), const_100)), const_2)), multiply(multiply(add(const_2, const_3), const_2), multiply(multiply(add(const_2, const_3), const_2), const_100))), multiply(multiply(add(const_3, const_4), add(const_2, const_3)), multiply(multiply(add(const_2, const_3), const_2), const_100))))) | add(const_2,const_3)|add(const_3,const_4)|multiply(#0,const_3)|multiply(#0,const_2)|multiply(#0,#0)|multiply(#1,#0)|multiply(#3,const_100)|multiply(#3,#6)|multiply(#4,#6)|multiply(#5,#6)|multiply(#2,#7)|multiply(#8,const_3)|multiply(#9,const_2)|multiply(#7,const_2)|add(#11,#12)|add(#14,#13)|add(#15,#7)|add(#16,#9)|divide(#10,#17)|multiply(#18,#12) | shekhar : rajeev : jatin = ( 25000 x 12 + 35000 x 12 + 45000 x 12 ) : ( 35000 x 24 ) : ( 35000 x 12 ) = 1260000 : 840000 : 420000 = 3 : 2 : 1 . rajeev ’ s share = rs . ( 150000 × 2 / 6 ) = rs . 50000 answer e | gain |
math_qa__1BAlnocPpXQl3NK1 | If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $74. If $2,000 is the total amount invested, how much is invested at 8 percent? Choose the correct answer:
A) $ 600
B) $ 700
C) $ 800
D) $ 900
E) $ 1000 | <gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">1_000 * 2</gadget>
<output>2_000</output>
<gadget id="calculator">10 * 8</gadget>
<output>80</output>
<gadget id="calculator">80 * 2</gadget>
<output>160</output>
<gadget id="calculator">160 + 74</gadget>
<output>234</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">8 / 100</gadget>
<output>2/25 = around 0.08</output>
<gadget id="calculator">(1/10) + (2/25)</gadget>
<output>9/50 = around 0.18</output>
<gadget id="calculator">234 / (9/50)</gadget>
<output>1_300</output>
<gadget id="calculator">2_000 - 1_300</gadget>
<output>700</output>
<result>B</result> | B | 700 | If x dollars is invested at 10 percent for one year and y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will exceed the annual income from the 8 percent investment by $74. If $2,000 is the total amount invested, how much is invested at 8 percent? | {
"A": "$ 600",
"B": "$ 700",
"C": "$ 800",
"D": "$ 900",
"E": "$ 1000"
} | subtract(multiply(multiply(const_100, 10), const_2), divide(add(multiply(multiply(10, 8), const_2), 74), add(divide(10, const_100), divide(8, const_100)))) | divide(n0,const_100)|divide(n1,const_100)|multiply(n0,const_100)|multiply(n0,n1)|add(#0,#1)|multiply(#2,const_2)|multiply(#3,const_2)|add(n4,#6)|divide(#7,#4)|subtract(#5,#8)| | "0.1 x = 0.08 ( 2000 - x ) + 74 0.18 x = 234 x = 1300 then the amount invested at 8 % is $ 2000 - $ 1300 = $ 700 the answer is b ." | general |
math_qa__STAau3TVXeQc1Gj8 | At the opening of a trading day at a certain stock exchange, the price per share of stock K was $28. If the price per share of stock K was $29 at the closing of the day, what was the percent increase in the price per share of stock K for that day? Choose the correct option.
A) 3.57 % B) 5.9 % C) 11.1 % D) 12.5 % E) 23.6 % | <gadget id="calculator">29 / 28</gadget>
<output>29/28 = around 1.035714</output>
<gadget id="calculator">(29/28) - 1</gadget>
<output>1/28 = around 0.035714</output>
<gadget id="calculator">(1/28) * 100</gadget>
<output>25/7 = around 3.571429</output>
<result>A</result> | A | 3.57 | At the opening of a trading day at a certain stock exchange, the price per share of stock K was $28. If the price per share of stock K was $29 at the closing of the day, what was the percent increase in the price per share of stock K for that day? | {
"A": "3.57 %",
"B": "5.9 %",
"C": "11.1 %",
"D": "12.5 %",
"E": "23.6 %"
} | multiply(subtract(divide(29, 28), const_1), const_100) | divide(n1,n0)|subtract(#0,const_1)|multiply(#1,const_100)| | "opening = 28 closing = 29 rise in price = 1 so , percent increase = 1 / 28 * 100 = 3.57 answer : a" | general |
math_qa__iPEd3rkca49EdvCU | The population of a town is 20000. It increases annually at the rate of 20% p.a. What will be its population after 2 years? Select.
A) 24440 B) 24800 C) 28400 D) 28800 E) 28600 | <gadget id="calculator">20_000 * 20</gadget>
<output>400_000</output>
<gadget id="calculator">400_000 / 100</gadget>
<output>4_000</output>
<gadget id="calculator">4_000 * 2</gadget>
<output>8_000</output>
<gadget id="calculator">20_000 + 8_000</gadget>
<output>28_000</output>
<result>D</result> | D | 28,800 | The population of a town is 20000. It increases annually at the rate of 20% p.a. What will be its population after 2 years? | {
"A": "24440",
"B": "24800",
"C": "28400",
"D": "28800",
"E": "28600"
} | add(20000, multiply(divide(multiply(20000, 20), const_100), 2)) | multiply(n0,n1)|divide(#0,const_100)|multiply(#1,n2)|add(n0,#2)| | "explanation : formula : ( after = 100 denominator ago = 100 numerator ) 20000 * 120 / 100 * 120 / 100 = 120 * 120 * 2 = 28800 answer : option d" | gain |
math_qa__TEJvEgMKmXqiW5vT | Bookman purchased 55 copies of a new book released recently, 10 of which are hardback and sold for $20 each, and rest are paperback and sold for $10 each. If 14 copies were sold and the total value of the remaining books was 360, how many paperback copies were sold? Answers.
A) 8 B) 10 C) 12 D) 19 E) 16 | <gadget id="calculator">55 - 10</gadget>
<output>45</output>
<gadget id="calculator">45 * 10</gadget>
<output>450</output>
<gadget id="calculator">10 * 20</gadget>
<output>200</output>
<gadget id="calculator">450 + 200</gadget>
<output>650</output>
<gadget id="calculator">650 - 360</gadget>
<output>290</output>
<gadget id="calculator">gcd(55, 10)</gadget>
<output>5</output>
<gadget id="calculator">5 * 20</gadget>
<output>100</output>
<gadget id="calculator">290 - 100</gadget>
<output>190</output>
<gadget id="calculator">190 / 10</gadget>
<output>19</output>
<result>D</result> | D | 19 | Bookman purchased 55 copies of a new book released recently, 10 of which are hardback and sold for $20 each, and rest are paperback and sold for $10 each. If 14 copies were sold and the total value of the remaining books was 360, how many paperback copies were sold? | {
"A": "8",
"B": "10",
"C": "12",
"D": "19",
"E": "16"
} | divide(subtract(subtract(add(multiply(subtract(55, 10), 10), multiply(10, 20)), 360), multiply(gcd(55, 10), 20)), 10) | gcd(n0,n1)|multiply(n1,n2)|subtract(n0,n1)|multiply(n1,#2)|multiply(n2,#0)|add(#3,#1)|subtract(#5,n5)|subtract(#6,#4)|divide(#7,n1) | the bookman had 10 hardback ad 55 - 10 = 45 paperback copies ; 14 copies were sold , hence 55 - 14 = 41 copies were left . let # of paperback copies left be p then 10 p + 20 ( 41 - p ) = 560 - - > 10 p = 260 - - > p = 26 # of paperback copies sold is 45 - 26 = 19 answer : d | general |
math_qa__DoMQ0DBKixrOCDNL | In a company with 48 employees, some part-time and some full-time, exactly (1/3) of the part-time employees and (1/4) of the full-time employees take the subway to work. What is the greatest possible number R of employees who take the subway to work? Options: A) 12 B) 13 C) 14 D) 15 E) 16 | <gadget id="calculator">48 * 3</gadget>
<output>144</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">144 / 12</gadget>
<output>12</output>
<gadget id="calculator">48 - 12</gadget>
<output>36</output>
<gadget id="calculator">36 / 12</gadget>
<output>3</output>
<gadget id="calculator">12 + 3</gadget>
<output>15</output>
<result>D</result> | D | 15 | In a company with 48 employees, some part-time and some full-time, exactly (1/3) of the part-time employees and (1/4) of the full-time employees take the subway to work. What is the greatest possible number R of employees who take the subway to work? | {
"A": "12",
"B": "13",
"C": "14",
"D": "15",
"E": "16"
} | add(divide(multiply(48, 3), multiply(3, 4)), divide(subtract(48, multiply(3, 4)), divide(multiply(48, 3), multiply(3, 4)))) | multiply(n0,n2)|multiply(n2,n4)|divide(#0,#1)|subtract(n0,#1)|divide(#3,#2)|add(#2,#4)| | "p / 3 + f / 4 = p / 3 + ( 48 - p ) / 4 = 12 + p / 2 p / 3 + f / 3 = ( p + f ) / 3 = 48 / 3 = 16 p / 4 + f / 4 = 12 p / 3 + f / 3 > p / 3 + f / 4 > p / 4 + f / 4 - - > 16 > 12 + p / 12 > 12 greatest possible r : 12 + p / 12 = 15 - - > p = 36 ( integer - - > good ) 15 or d is the answer" | general |
math_qa__377X8OmRx4BmfJhS | In an electric circuit, three resistors with resistances 2 ohms, 5 ohms and 6 ohms are connected in parallel. In this case, if R is the combined resistance of these three resistors, then the reciprocal of R is equal to the sum of the reciprocals resistors. What is R value? Choose the correct choice from the following answers
A) 13 / 15 ohms B) 15 / 13 ohms C) 5 / 8 ohms D) 3 / 7 ohms E) 45 / 18 ohms | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/2) + (1/5)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(1/6) + (7/10)</gadget>
<output>13/15 = around 0.866667</output>
<result>A</result> | A | 0.866667 | In an electric circuit, three resistors with resistances 2 ohms, 5 ohms and 6 ohms are connected in parallel. In this case, if R is the combined resistance of these three resistors, then the reciprocal of R is equal to the sum of the reciprocals resistors. What is R value? | {
"A": "13 / 15 ohms",
"B": "15 / 13 ohms",
"C": "5 / 8 ohms",
"D": "3 / 7 ohms",
"E": "45 / 18 ohms"
} | add(divide(const_1, 6), add(divide(const_1, 2), divide(const_1, 5))) | divide(const_1,n0)|divide(const_1,n1)|divide(const_1,n2)|add(#0,#1)|add(#3,#2) | the wording is a bit confusing , though basically we are told that 1 / r = 1 / 2 + 1 / 5 + 1 / 6 , from which it follows that r = 13 / 15 ohms option : a | geometry |
math_qa__gqWK1nbwrJaYfTFO | If the weight of 13 meters long rod is 23.4 kg. What is the weight of 6 meters long rod ? Choose the correct choice from the following options: A) 7.2 kg . B) 10.8 kg . C) 12.4 kg . D) 18.0 kg E) none | <gadget id="calculator">6 * 23.4</gadget>
<output>140.4</output>
<gadget id="calculator">140.4 / 13</gadget>
<output>10.8</output>
<result>B</result> | B | 10.8 | If the weight of 13 meters long rod is 23.4 kg. What is the weight of 6 meters long rod ? | {
"A": "7.2 kg .",
"B": "10.8 kg .",
"C": "12.4 kg .",
"D": "18.0 kg",
"E": "none"
} | divide(multiply(6, 23.4), 13) | multiply(n1,n2)|divide(#0,n0)| | "answer ∵ weight of 13 m long rod = 23.4 kg ∴ weight of 1 m long rod = 23.4 / 13 kg ∴ weight of 6 m long rod = 23.4 x 6 / 13 = 10.8 kg option : b" | physics |
math_qa__IwfqvqmcJ9MAAUsZ | If the simple interest on a certain sum of money for 7 years is one–fifth of the sum, then the rate of interest per annum is Pick.
A) 4 % B) 2.50 % C) 6.20 % D) 5 % E) 2.85 % | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">20 / 7</gadget>
<output>20/7 = around 2.857143</output>
<result>E</result> | E | 2.85 | If the simple interest on a certain sum of money for 7 years is one–fifth of the sum, then the rate of interest per annum is | {
"A": "4 %",
"B": "2.50 %",
"C": "6.20 %",
"D": "5 %",
"E": "2.85 %"
} | divide(divide(const_100, add(const_1, const_4)), 7) | add(const_1,const_4)|divide(const_100,#0)|divide(#1,n0)| | "explanation : let the principal ( p ) be x then , simple interest ( si ) = x / 5 time ( t ) = 7 years rate of interest per annum ( r ) = ( 100 × si ) / pt = ( 100 × ( x / 5 ) / ( x × 7 ) = 20 / 7 = 2.85 % answer : option e" | gain |
math_qa__gsijHSNwt3IAVoNj | alex has to take a quiz , which has 10 true false - type question each carry 1 mark . what is the probability that alex ' s can score more than 8 mark in the quiz . given that he decides to guess randomly on the quiz . Select the correct option:
A) 12 / 1024
B) 11 / 1024
C) 11 / 256
D) 12 / 256
E) 14 / 256 | <gadget id="calculator">2 ** 10</gadget>
<output>1_024</output>
<gadget id="calculator">1 / 1_024</gadget>
<output>1/1_024 = around 0.000977</output>
<gadget id="calculator">10 / 1_024</gadget>
<output>5/512 = around 0.009766</output>
<gadget id="calculator">(1/1_024) + (5/512)</gadget>
<output>11/1_024 = around 0.010742</output>
<result>B</result> | B | 0.010742 | alex has to take a quiz , which has 10 true false - type question each carry 1 mark . what is the probability that alex ' s can score more than 8 mark in the quiz . given that he decides to guess randomly on the quiz . | {
"A": "12 / 1024",
"B": "11 / 1024",
"C": "11 / 256",
"D": "12 / 256",
"E": "14 / 256"
} | add(divide(const_1, power(const_2, 10)), divide(10, power(const_2, 10))) | power(const_2,n0)|divide(const_1,#0)|divide(n0,#0)|add(#1,#2) | each question has 2 options ( true or false ) . total number of ways of answering all 10 questions = ( 2 ) 10 ( 2 ) 10 more than 8 correct means either 9 correct or all correct . number of ways such that 9 correct = 10 ! / 9 ! = 10 number of ways of all correct = 1 therefore , probability of more than 8 correct = 11 / ( 2 ) 1011 / ( 2 ) 10 = 11 / 1024 answer : b | general |
math_qa__kMqBZR45OkLpjRll | the average earning of a mechanic for the first - 4 days of a week is rs . 18 and for the last 4 days is rs . 22 . if he earns rs . 13 on the fourth day , his average earning for the whole week is ? Select:
A) rs . 18.95
B) rs 16
C) rs . 21
D) rs . 25.71
E) none of these | <gadget id="calculator">4 * 18</gadget>
<output>72</output>
<gadget id="calculator">4 * 22</gadget>
<output>88</output>
<gadget id="calculator">72 + 88</gadget>
<output>160</output>
<gadget id="calculator">160 - 13</gadget>
<output>147</output>
<gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">147 / 7</gadget>
<output>21</output>
<result>C</result> | C | 21 | the average earning of a mechanic for the first - 4 days of a week is rs . 18 and for the last 4 days is rs . 22 . if he earns rs . 13 on the fourth day , his average earning for the whole week is ? | {
"A": "rs . 18.95",
"B": "rs 16",
"C": "rs . 21",
"D": "rs . 25.71",
"E": "none of these"
} | divide(subtract(add(multiply(4, 18), multiply(4, 22)), 13), add(const_3, const_4)) | add(const_3,const_4)|multiply(n0,n1)|multiply(n0,n3)|add(#1,#2)|subtract(#3,n4)|divide(#4,#0) | answer total earning for the week = sum of earning of first four days + sum of earning of last four days - earning of 4 th day = 4 x 18 + 4 x 22 - 13 = rs . 147 â ˆ ´ average earning = 147 / 7 = rs . 21 correct option : c | general |
math_qa__VYu3TpF2UW1zTCPX | what is the unit digit in the product (3^68 x 6^59 x 7^71) ? Options
A) 1 B) 2 C) 4 D) 6 E) none of them | <gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">18 * 3</gadget>
<output>54</output>
<gadget id="calculator">54 - 4</gadget>
<output>50</output>
<gadget id="calculator">54 - 50</gadget>
<output>4</output>
<result>C</result> | C | 4 | what is the unit digit in the product (3^68 x 6^59 x 7^71) ? | {
"A": "1",
"B": "2",
"C": "4",
"D": "6",
"E": "none of them"
} | subtract(multiply(multiply(3, 6), 3), subtract(multiply(multiply(3, 6), 3), const_4)) | multiply(n0,n2)|multiply(n0,#0)|subtract(#1,const_4)|subtract(#1,#2)| | "unit digit in 3 ^ 4 = 1 = > unit digit in ( 3 ^ 4 ) ^ 16 = 1 therefore , unit digit in 3 ^ 65 = unit digit in [ ( 3 ^ 4 ) ^ 16 x 3 ] = ( 1 x 3 ) = 3 unit digit in 6 ^ 59 = 6 unit digit in 7 ^ 4 = 1 = > unit digit in ( 7 ^ 4 ) ^ 17 is 1 unit digit in 7 ^ 71 = unit digit in [ ( 7 ^ 4 ) ^ 17 x 7 ^ 3 ] = ( ( 1 x 3 ) = 3 therefore , required digit = unit digit in ( 3 x 6 x 3 ) = 4 answer is c" | general |
math_qa__WTJsB5LUvRzaVLAM | Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 15 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one?
Select the correct option.
A) 78 B) 60 C) 26 D) 23 E) 12 | <gadget id="calculator">45 + 15</gadget>
<output>60</output>
<result>B</result> | B | 60 | Two goods trains each 500 m long are running in opposite directions on parallel tracks. Their speeds are 45 km/hr and 15 km/hr respectively. Find the time taken by the slower train to pass the driver of the faster one? | {
"A": "78",
"B": "60",
"C": "26",
"D": "23",
"E": "12"
} | add(45, 15) | add(n1,n2)| | "relative speed = 45 + 15 = 60 km / hr . 60 * 5 / 18 = 50 / 3 m / sec . distance covered = 500 + 500 = 1000 m . required time = 1000 * 3 / 50 = 60 sec . answer : b" | physics |
math_qa__gdp16YFOOVggZB19 | An empty fuel tank with a capacity of 200 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 24 gallons of ethanol, how many gallons of fuel A were added? Choose the correct option.
A) 160 B) 150 C) 100 D) 80 E) 200 | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">200 * (4/25)</gadget>
<output>32</output>
<gadget id="calculator">32 - 24</gadget>
<output>8</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(4/25) - (3/25)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">8 / (1/25)</gadget>
<output>200</output>
<result>E</result> | E | 200 | An empty fuel tank with a capacity of 200 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 24 gallons of ethanol, how many gallons of fuel A were added? | {
"A": "160",
"B": "150",
"C": "100",
"D": "80",
"E": "200"
} | divide(subtract(multiply(200, divide(16, const_100)), 24), subtract(divide(16, const_100), divide(12, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|subtract(#0,#1)|subtract(#2,n3)|divide(#4,#3)| | "say there are a gallons of fuel a in the tank , then there would be 200 - a gallons of fuel b . the amount of ethanol in a gallons of fuel a is 0.12 a ; the amount of ethanol in 200 - a gallons of fuel b is 0.16 ( 200 - a ) ; since the total amount of ethanol is 24 gallons then 0.12 a + 0.16 ( 200 - a ) = 24 - - > a = 200 . answer : e ." | gain |
math_qa__Uu8SkDqAN0sA4Pqm | A circle in the coordinate plane passes through points (-3, -2) and (1, 3). What is the smallest possible area of that circle?
Choose the correct choice from the following:
A) 10.5 π
B) 26 π
C) 262 √ π
D) 52 π
E) 64 π | <gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">16 + 25</gadget>
<output>41</output>
<gadget id="calculator">41 ** (1/2)</gadget>
<output>sqrt(41) = around 6.403124</output>
<gadget id="calculator">(sqrt(41)) / 2</gadget>
<output>sqrt(41)/2 = around 3.201562</output>
<gadget id="calculator">(sqrt(41)/2) ** 2</gadget>
<output>41/4 = around 10.25</output>
<result>A</result> | A | 10.5 | A circle in the coordinate plane passes through points (-3, -2) and (1, 3). What is the smallest possible area of that circle? | {
"A": "10.5 π",
"B": "26 π",
"C": "262 √ π",
"D": "52 π",
"E": "64 π"
} | square_area(divide(sqrt(add(multiply(add(3, 1), add(3, 1)), multiply(add(2, 3), add(2, 3)))), 2)) | add(n0,n2)|add(n1,n3)|multiply(#0,#0)|multiply(#1,#1)|add(#2,#3)|sqrt(#4)|divide(#5,n1)|square_area(#6)| | "the distance between the two points is sqrt ( 41 ) . radius = sqrt ( 41 ) / 2 area = pi * ( sqrt ( 41 ) / 2 ) ^ 2 a . 10.5 π" | geometry |
math_qa__gdVlywLM9pHfEp0W | A certain candy manufacturer reduced the weight of Candy Bar M by 10 percent buy left the price unchanged. What was the resulting percent increase in the price per ounce of Candy Bar M? Choose the correct choice from the following answers.
A) 10 B) 11 C) 12 D) 14 E) 9 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">1 / (9/10)</gadget>
<output>10/9 = around 1.111111</output>
<gadget id="calculator">(10/9) * 100</gadget>
<output>1_000/9 = around 111.111111</output>
<gadget id="calculator">(1_000/9) - 100</gadget>
<output>100/9 = around 11.111111</output>
<result>B</result> | B | 11 | A certain candy manufacturer reduced the weight of Candy Bar M by 10 percent buy left the price unchanged. What was the resulting percent increase in the price per ounce of Candy Bar M? | {
"A": "10",
"B": "11",
"C": "12",
"D": "14",
"E": "9"
} | subtract(multiply(divide(const_1, subtract(const_1, divide(10, const_100))), const_100), const_100) | divide(n0,const_100)|subtract(const_1,#0)|divide(const_1,#1)|multiply(#2,const_100)|subtract(#3,const_100)| | "assume 1 oz candy cost $ 1 before . now price remain same $ 1 but weight of candy reduces to 0.9 oz new price of candy = 1 / 0.9 = 1.11 price increase 11 % b" | gain |
math_qa__4FMRseGK09RbuI42 | A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 60%? Options
A) 800 B) 882 C) 772 D) 652 E) 271 | <gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">500 * (3/5)</gadget>
<output>300</output>
<gadget id="calculator">500 + 300</gadget>
<output>800</output>
<result>A</result> | A | 800 | A person buys an article at Rs.500. At what price should he sell the article so as to make a profit of 60%? | {
"A": "800",
"B": "882",
"C": "772",
"D": "652",
"E": "271"
} | add(500, multiply(500, divide(60, const_100))) | divide(n1,const_100)|multiply(n0,#0)|add(n0,#1)| | "cost price = rs . 500 profit = 60 % of 500 = rs . 300 selling price = cost price + profit = 500 + 300 = 800 answer : a" | gain |
math_qa__CO6yiS1YijSCcg5c | A man purchased 2 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets?
Options:
A) 278 B) 277 C) 278 D) 450 E) 550 | <gadget id="calculator">10 * 150</gadget>
<output>1_500</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">5 * 150</gadget>
<output>750</output>
<gadget id="calculator">200 + 750</gadget>
<output>950</output>
<gadget id="calculator">1_500 - 950</gadget>
<output>550</output>
<result>E</result> | E | 550 | A man purchased 2 blankets @ Rs.100 each, 5 blankets @ Rs.150 each and two blankets at a certain rate which is now slipped off from his memory. But he remembers that the average price of the blankets was Rs.150. Find the unknown rate of two blankets? | {
"A": "278",
"B": "277",
"C": "278",
"D": "450",
"E": "550"
} | subtract(multiply(const_10, 150), add(multiply(2, 100), multiply(5, 150))) | multiply(n3,const_10)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|subtract(#0,#3)| | "10 * 150 = 1500 2 * 100 + 5 * 150 = 950 1500 – 1050 = 550 answer : e" | general |
math_qa__xL4qGpVVXvvq4g0C | What will be the difference between simple and compound interest at 6% per annum on a sum of Rs. 1000 after 4 years? Select: A) 24.19 B) 24.12 C) 22.1 D) 24.1 E) 22.5 | <gadget id="calculator">6 / 100</gadget>
<output>3/50 = around 0.06</output>
<gadget id="calculator">(3/50) + 1</gadget>
<output>53/50 = around 1.06</output>
<gadget id="calculator">(53/50) ** 4</gadget>
<output>7_890_481/6_250_000 = around 1.262477</output>
<gadget id="calculator">1_000 * (7_890_481/6_250_000)</gadget>
<output>7_890_481/6_250 = around 1_262.47696</output>
<gadget id="calculator">(7_890_481/6_250) - 1_000</gadget>
<output>1_640_481/6_250 = around 262.47696</output>
<gadget id="calculator">1_000 * (3/50)</gadget>
<output>60</output>
<gadget id="calculator">60 * 4</gadget>
<output>240</output>
<gadget id="calculator">(1_640_481/6_250) - 240</gadget>
<output>140_481/6_250 = around 22.47696</output>
<result>E</result> | E | 22.5 | What will be the difference between simple and compound interest at 6% per annum on a sum of Rs. 1000 after 4 years? | {
"A": "24.19",
"B": "24.12",
"C": "22.1",
"D": "24.1",
"E": "22.5"
} | subtract(subtract(multiply(1000, power(add(divide(6, const_100), const_1), 4)), 1000), multiply(multiply(1000, divide(6, const_100)), 4)) | divide(n0,const_100)|add(#0,const_1)|multiply(n1,#0)|multiply(n2,#2)|power(#1,n2)|multiply(n1,#4)|subtract(#5,n1)|subtract(#6,#3)| | "s . i . = ( 1000 * 6 * 4 ) / 100 = rs . 240 c . i . = [ 1000 * ( 1 + 6 / 100 ) 4 - 1000 ] = rs . 262.5 difference = ( 262.5 - 240 ) = rs . 22.5 answer : e" | gain |
math_qa__Cs2kCg2VWCXsIhAm | Zinc and copper are melted together in the ratio 9 : 11. What is the weight of melted mixture, if 28.8 kg of zinc has been consumed in it? Select the correct option: A) 58 kg B) 60 kg C) 64 kg D) 70 kg E) none | <gadget id="calculator">11 / 9</gadget>
<output>11/9 = around 1.222222</output>
<gadget id="calculator">(11/9) * 28.8</gadget>
<output>35.2</output>
<gadget id="calculator">35.2 + 28.8</gadget>
<output>64</output>
<result>C</result> | C | 64 | Zinc and copper are melted together in the ratio 9 : 11. What is the weight of melted mixture, if 28.8 kg of zinc has been consumed in it? | {
"A": "58 kg",
"B": "60 kg",
"C": "64 kg",
"D": "70 kg",
"E": "none"
} | add(multiply(divide(11, 9), 28.8), 28.8) | divide(n1,n0)|multiply(n2,#0)|add(n2,#1) | sol . for 9 kg zinc , mixture melted = ( 9 + 11 ) kg . for 28.8 kg zinc , mixture , melted = [ 20 / 9 x 28.8 ] kg = 64 kg . answer c | general |
math_qa__rbmlL2wR2a41EOv5 | What is the speed of the stream if a canoe rows upstream at 9 km/hr and downstream at 12km/hr
Select: A) 1 kmph B) 4 kmph C) 3 kmph D) 2 kmph E) 1.5 kmph | <gadget id="calculator">12 - 9</gadget>
<output>3</output>
<gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<result>E</result> | E | 1.5 | What is the speed of the stream if a canoe rows upstream at 9 km/hr and downstream at 12km/hr | {
"A": "1 kmph",
"B": "4 kmph",
"C": "3 kmph",
"D": "2 kmph",
"E": "1.5 kmph"
} | divide(subtract(12, 9), const_2) | subtract(n1,n0)|divide(#0,const_2)| | "sol . speed of stream = 1 / 2 ( 12 - 9 ) kmph = 1.5 kmph . answer e" | physics |
math_qa__ynhTOuiAS219js9S | . A car covers a distance of 495 km in 5 hours. Find its speed?
Choose the correct choice from the following answers:
A) 99 B) 100 C) 102 D) 288 E) 2761 | <gadget id="calculator">495 / 5</gadget>
<output>99</output>
<result>A</result> | A | 99 | . A car covers a distance of 495 km in 5 hours. Find its speed? | {
"A": "99",
"B": "100",
"C": "102",
"D": "288",
"E": "2761"
} | divide(495, 5) | divide(n0,n1)| | "495 / 5 = 99 kmph answer : a" | physics |
math_qa__iA3R1UfOrhAoFzuE | The average weight of 5 person's increases by 5.5 kg when a new person comes in place of one of them weighing 68 kg. What might be the weight of the new person?
Choose the correct choice from the following answers.
A) 60 kg B) 95.5 kg C) 80 kg D) 85 kg E) 90 kg | <gadget id="calculator">5 * 5.5</gadget>
<output>27.5</output>
<gadget id="calculator">27.5 + 68</gadget>
<output>95.5</output>
<result>B</result> | B | 95.5 | The average weight of 5 person's increases by 5.5 kg when a new person comes in place of one of them weighing 68 kg. What might be the weight of the new person? | {
"A": "60 kg",
"B": "95.5 kg",
"C": "80 kg",
"D": "85 kg",
"E": "90 kg"
} | add(multiply(5, 5.5), 68) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = ( 5 x 5.5 ) kg = 27.5 kg . weight of new person = ( 68 + 27.5 ) kg = 95.5 kg option b" | general |
math_qa__Q9ta5S36bONzer8w | In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the rate in the remaining 40 overs to reach the target of 292 runs? Select:
A) 6.5 B) 6.22 C) 6.29 D) 6.39 E) 6.13 | <gadget id="calculator">10 * 3.2</gadget>
<output>32</output>
<gadget id="calculator">292 - 32</gadget>
<output>260</output>
<gadget id="calculator">260 / 40</gadget>
<output>13/2 = around 6.5</output>
<result>A</result> | A | 6.5 | In the first 10 overs of a cricket game, the run rate was only 3.2. What should be the rate in the remaining 40 overs to reach the target of 292 runs? | {
"A": "6.5",
"B": "6.22",
"C": "6.29",
"D": "6.39",
"E": "6.13"
} | divide(subtract(292, multiply(10, 3.2)), 40) | multiply(n0,n1)|subtract(n3,#0)|divide(#1,n2)| | "required run rate = [ 292 - ( 3.2 * 10 ) ] / 40 = 260 / 40 = 6.5 answer : a" | gain |
math_qa__OWosroA0sV9tgpOl | The radius of a semi circle is 5.2 cm then its perimeter is? Choose the correct choice:
A) 32.52 B) 32.48 C) 26.74 D) 32.9 E) 32.31 | <gadget id="calculator">2 * pi * 5.2</gadget>
<output>10.4*pi = around 32.672564</output>
<gadget id="calculator">(10.4*pi) / 2</gadget>
<output>5.2*pi = around 16.336282</output>
<gadget id="calculator">5.2 * 2</gadget>
<output>10.4</output>
<gadget id="calculator">(5.2*pi) + 10.4</gadget>
<output>10.4 + 5.2*pi = around 26.736282</output>
<result>C</result> | C | 26.74 | The radius of a semi circle is 5.2 cm then its perimeter is? | {
"A": "32.52",
"B": "32.48",
"C": "26.74",
"D": "32.9",
"E": "32.31"
} | add(divide(circumface(5.2), const_2), multiply(5.2, const_2)) | circumface(n0)|multiply(n0,const_2)|divide(#0,const_2)|add(#2,#1)| | "36 / 7 r = 5.2 = 26.74 answer : c" | physics |
math_qa__ibnGrHYk1Sde5uri | If log102 = 0.3010, log10 3 = 0.4771, then the number of zeros between the decimal point and the first
significant figure in (0.0432)10 is? Select the correct option
A) 10
B) 13
C) 14
D) 15
E) 16 | <gadget id="calculator">3 * 0.4771</gadget>
<output>1.4313</output>
<gadget id="calculator">4 * 0.301</gadget>
<output>1.204</output>
<gadget id="calculator">1.4313 + 1.204</gadget>
<output>2.6353</output>
<gadget id="calculator">2.6353 - 4</gadget>
<output>-1.3647</output>
<gadget id="calculator">(-1.3647) * 10</gadget>
<output>-13.647</output>
<gadget id="calculator">-(-13.647)</gadget>
<output>13.647</output>
<result>B</result> | B | 13 | If log102 = 0.3010, log10 3 = 0.4771, then the number of zeros between the decimal point and the first
significant figure in (0.0432)10 is? | {
"A": "10",
"B": "13",
"C": "14",
"D": "15",
"E": "16"
} | negate(multiply(subtract(add(multiply(3, 0.4771), multiply(const_4, 0.301)), const_4), 10)) | multiply(n3,n4)|multiply(n1,const_4)|add(#0,#1)|subtract(#2,const_4)|multiply(n2,#3)|negate(#4) | x = ( 0.0432 ) 10 = ( 432 / 10000 ) 10 = ( 33.24 / 104 ) 10 therefore , log 10 x = 10 ( log 103 + 4 log 102 - 4 ) = 10 ( 1.4313 + 1.2040 - 4 ) = 10 ( - 1.3647 ) = - 13.647 = - 14.353 therefore , x = antilog ( - 14.053 ) thus , number of zeros between the decimal and the first significant figure = 13 answer : b | other |
math_qa__gfn8wLLnedcaBuAN | Eden drove an average speed of 15 miles per hour for the first 20 miles of a tripthen at a average speed of 30 miles/hr for the remaining 20 miles of the trip if she made no stops during the trip what was eden's avg speed in miles/hr for the entire trip Answers:
A) 35
B) 20
C) 45
D) 50
E) 55 | <gadget id="calculator">20 + 20</gadget>
<output>40</output>
<gadget id="calculator">20 / 15</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">20 / 30</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(4/3) + (2/3)</gadget>
<output>2</output>
<gadget id="calculator">40 / 2</gadget>
<output>20</output>
<result>B</result> | B | 20 | Eden drove an average speed of 15 miles per hour for the first 20 miles of a tripthen at a average speed of 30 miles/hr for the remaining 20 miles of the trip if she made no stops during the trip what was eden's avg speed in miles/hr for the entire trip | {
"A": "35",
"B": "20",
"C": "45",
"D": "50",
"E": "55"
} | divide(add(20, 20), add(divide(20, 15), divide(20, 30))) | add(n1,n1)|divide(n1,n0)|divide(n1,n2)|add(#1,#2)|divide(#0,#3) | avg . speed = total distance / total time total distance = 40 miles total time = 20 / 15 + 15 / 30 = 2 avg . speed = 20 . answer - b | physics |
math_qa__fvtWZYhotDQa2T5m | The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 44 degrees. Find the temperature on Friday? Choose the correct choice from the following choices: A) 65 degrees B) 73 degrees C) 36 degrees D) 34 degrees E) 74 degrees | <gadget id="calculator">48 * 4</gadget>
<output>192</output>
<gadget id="calculator">46 * 4</gadget>
<output>184</output>
<gadget id="calculator">192 - 184</gadget>
<output>8</output>
<gadget id="calculator">44 - 8</gadget>
<output>36</output>
<result>C</result> | C | 36 | The average temperature for Monday, Tuesday, Wednesday and Thursday was 48 degrees and for Tuesday, Wednesday, Thursday and Friday was 46 degrees. If the temperature on Monday was 44 degrees. Find the temperature on Friday? | {
"A": "65 degrees",
"B": "73 degrees",
"C": "36 degrees",
"D": "34 degrees",
"E": "74 degrees"
} | subtract(44, subtract(multiply(48, const_4), multiply(46, const_4))) | multiply(n0,const_4)|multiply(n1,const_4)|subtract(#0,#1)|subtract(n2,#2)| | "m + tu + w + th = 4 * 48 = 192 tu + w + th + f = 4 * 46 = 184 m = 44 tu + w + th = 192 - 44 = 148 f = 184 – 148 = 36 answer : c" | general |
math_qa__GEkCqeWkBg5KoolW | If W is the set of all the integers between 49 and 88, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers? Choices:
A) 11
B) 44
C) 48
D) 28
E) 26 | <gadget id="calculator">88 - 49</gadget>
<output>39</output>
<gadget id="calculator">39 / 3</gadget>
<output>13</output>
<gadget id="calculator">floor(13)</gadget>
<output>13</output>
<gadget id="calculator">39 / 2</gadget>
<output>39/2 = around 19.5</output>
<gadget id="calculator">13 + (39/2)</gadget>
<output>65/2 = around 32.5</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">39 / 6</gadget>
<output>13/2 = around 6.5</output>
<gadget id="calculator">floor(13/2)</gadget>
<output>6</output>
<gadget id="calculator">(65/2) - 6</gadget>
<output>53/2 = around 26.5</output>
<result>E</result> | E | 26 | If W is the set of all the integers between 49 and 88, inclusive, that are either multiples of 3 or multiples of 2 or multiples of both, then W contains how many numbers? | {
"A": "11",
"B": "44",
"C": "48",
"D": "28",
"E": "26"
} | subtract(add(floor(divide(subtract(88, 49), 3)), divide(subtract(88, 49), 2)), floor(divide(subtract(88, 49), multiply(2, 3)))) | multiply(n3,n2)|subtract(n1,n0)|divide(#1,n3)|divide(#1,n2)|divide(#1,#0)|floor(#3)|floor(#4)|add(#2,#5)|subtract(#7,#6)| | "official solution : number of multiples of 3 step 1 . subtract the extreme multiples of 3 within the range ( the greatest is 87 , the smallest is 51 ) : 87 - 51 = 36 step 2 . divide by 3 : 36 / 3 = 12 step 3 . add 1 : 12 + 1 = 13 . so there are 13 multiples of 3 within the range : examples are 51 , 54 , 57 , 60 , etc . number of multiples of 2 step 1 . subtract the extreme multiples of 2 within the range ( the greatest is 88 , the smallest is 50 ) : 88 - 50 = 38 step 2 . divide by 2 : 38 / 2 = 19 step 3 . add 1 : 19 + 1 = 20 . so there are 19 multiples of 2 within the range : examples are 50 , 52 , 54 , 56 , 58 , 60 etc . add the 13 multiples of 3 and the 19 multiples of 2 : 13 + 19 = 32 . however , by adding the multiples of 2 and the multiples of 3 , we are effectively counting several numbers twice : for example , 54 and 60 are parts of both the lists above . so we ca n ' t just take 13 + 19 = 32 . find the number of multiples of 6 ( which are the double counted , as 6 is divisible by both 2 and 3 ) , and subtract it from 32 : step 1 . subtract the extreme multiples of 6 within the range ( the greatest is 72 , the smallest is 54 ) : 84 - 54 = 30 step 2 . divide by 6 : 30 / 6 = 5 step 3 . add 1 : 5 + 1 = 6 . so there are 6 multiples of 6 within the range : we counted 6 numbers twice . subtract the 6 multiples of 6 from the sum of the multiples of 2 and 3 : = 13 + 19 - 6 = 32 - 6 = 26 therefore , the final number of multiples of 2 , 3 or 6 is 26 . hence , this is the correct answer . ( e )" | other |
math_qa__FCvqlBCc06bnPJ8r | Two numbers N and 16 have LCM = 52 and GCF = 8. Find N. Choose the correct answer:
A) 35
B) 26
C) 76
D) 87
E) 24 | <gadget id="calculator">52 * 8</gadget>
<output>416</output>
<gadget id="calculator">416 / 16</gadget>
<output>26</output>
<result>B</result> | B | 26 | Two numbers N and 16 have LCM = 52 and GCF = 8. Find N. | {
"A": "35",
"B": "26",
"C": "76",
"D": "87",
"E": "24"
} | divide(multiply(52, 8), 16) | multiply(n1,n2)|divide(#0,n0)| | "the product of two integers is equal to the product of their lcm and gcf . hence . 16 * n = 52 * 8 n = 52 * 8 / 16 = 26 correct answer b" | physics |
math_qa__MczfQ0wEQYgAWbni | An ant walks an average of 1000 meters in 30 minutes. A beetle walks 10% less distance at the same time on the average. Assuming the beetle walks at her regular rate, what is its speed in km/h?
Choose the correct answer.
A) 1.8 B) 1.6 C) 2.775 . D) 1.9 E) 3.5 . | <gadget id="calculator">1_000 / 1_000</gadget>
<output>1</output>
<gadget id="calculator">30 / 60</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / (1/2)</gadget>
<output>2</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">2 * (9/10)</gadget>
<output>9/5 = around 1.8</output>
<result>A</result> | A | 1.8 | An ant walks an average of 1000 meters in 30 minutes. A beetle walks 10% less distance at the same time on the average. Assuming the beetle walks at her regular rate, what is its speed in km/h? | {
"A": "1.8",
"B": "1.6",
"C": "2.775 .",
"D": "1.9",
"E": "3.5 ."
} | multiply(divide(divide(1000, const_1000), divide(30, const_60)), subtract(const_1, divide(10, const_100))) | divide(n0,const_1000)|divide(n1,const_60)|divide(n2,const_100)|divide(#0,#1)|subtract(const_1,#2)|multiply(#3,#4) | the ant walks an average of 1000 meters in 30 minutes 1000 meters in 1 / 2 hours the beetle walks 10 % less distance = 1000 - 10 = 900 meters in 30 minutes 0.900 km in 30 / 60 = 1 / 2 hours speed = 0.900 * 2 = 1.8 km / h i guess option a should be 1.8 | general |
math_qa__8kS5j8andUotsxsM | Two trains 151 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet? Select the correct option
A) 7.19 B) 7.18 C) 7.16 D) 7.84 E) 7.12 | <gadget id="calculator">151 + 165</gadget>
<output>316</output>
<gadget id="calculator">80 + 65</gadget>
<output>145</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">145 * (5/18)</gadget>
<output>725/18 = around 40.277778</output>
<gadget id="calculator">316 / (725/18)</gadget>
<output>5_688/725 = around 7.845517</output>
<result>D</result> | D | 7.84 | Two trains 151 meters and 165 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet? | {
"A": "7.19",
"B": "7.18",
"C": "7.16",
"D": "7.84",
"E": "7.12"
} | divide(add(151, 165), multiply(add(80, 65), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "t = ( 151 + 165 ) / ( 80 + 65 ) * 18 / 5 t = 7.84 answer : d" | physics |
math_qa__qcJz3rxFfjPJVq1a | Joe has candys on his pocket, 4 of those candies have lemon flavor, and 3 have caramel flavor. If Joe take one, what is the probability that he picks one caramel flavor? Choose one:
A) 1
B) 2
C) none
D) 3 / 7
E) 3 / 4 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">3 / 7</gadget>
<output>3/7 = around 0.428571</output>
<result>D</result> | D | 0.428571 | Joe has candys on his pocket, 4 of those candies have lemon flavor, and 3 have caramel flavor. If Joe take one, what is the probability that he picks one caramel flavor? | {
"A": "1",
"B": "2",
"C": "none",
"D": "3 / 7",
"E": "3 / 4"
} | divide(3, add(4, 3)) | add(n0,n1)|divide(n1,#0) | the total number of candies is 7 and the number of candies with lemon flavor is 3 then , in one chance the probability to pick one candie with lemon flavor is 3 / 7 answer d | probability |
math_qa__LEoeeQEdxokl6cRH | An automobile parts supplier charges $20 per package of gaskets. When a customer orders more than 10 packages of gaskets, the supplier charges 4/5 the price for each package in excess of 10. During a certain week, the supplier sold 60 packages of gaskets. If 20 percent of the gaskets went to Company X, 15 percent to Company Y, and the rest to Company Z, what was the total amount, in dollars, that the parts supplier received in payment for the gaskets? Select.
A) 1005 B) 1045 C) 1075 D) 1015 E) 1096 | <gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">20 * (4/5)</gadget>
<output>16</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">60 * (1/5)</gadget>
<output>12</output>
<gadget id="calculator">60 - 12</gadget>
<output>48</output>
<gadget id="calculator">48 - 12</gadget>
<output>36</output>
<gadget id="calculator">36 - 10</gadget>
<output>26</output>
<gadget id="calculator">16 * 26</gadget>
<output>416</output>
<gadget id="calculator">20 * 10</gadget>
<output>200</output>
<gadget id="calculator">416 + 200</gadget>
<output>616</output>
<gadget id="calculator">20 * 12</gadget>
<output>240</output>
<gadget id="calculator">240 + 240</gadget>
<output>480</output>
<gadget id="calculator">616 + 480</gadget>
<output>1_096</output>
<result>E</result> | E | 1,096 | An automobile parts supplier charges $20 per package of gaskets. When a customer orders more than 10 packages of gaskets, the supplier charges 4/5 the price for each package in excess of 10. During a certain week, the supplier sold 60 packages of gaskets. If 20 percent of the gaskets went to Company X, 15 percent to Company Y, and the rest to Company Z, what was the total amount, in dollars, that the parts supplier received in payment for the gaskets? | {
"A": "1005",
"B": "1045",
"C": "1075",
"D": "1015",
"E": "1096"
} | add(add(multiply(multiply(20, divide(4, 5)), subtract(subtract(subtract(60, multiply(60, divide(20, const_100))), multiply(60, divide(20, const_100))), 10)), multiply(20, 10)), add(multiply(20, multiply(60, divide(20, const_100))), multiply(20, multiply(60, divide(20, const_100))))) | divide(n2,n3)|divide(n6,const_100)|multiply(n0,n1)|multiply(n0,#0)|multiply(n5,#1)|multiply(n0,#4)|subtract(n5,#4)|add(#5,#5)|subtract(#6,#4)|subtract(#8,n1)|multiply(#3,#9)|add(#10,#2)|add(#11,#7)| | "$ 25 per packet of gasket in case a customer orders less than 10 in case a customer orders > 10 price per gasket = 20 * 4 / 5 = 16 a certain week the supplier sold 60 gasket 1 . he sold 20 % of the gaskets to x = 12 gaskets = 20 * 10 + 16 * 2 = 200 + 32 = 232 2 . he sold 15 % of the gaskets to y = 9 gaskets = 20 * 9 = 180 3 . he sold remaining 65 % to z = 39 gaskets = 20 * 10 = 200 + 16 * 29 = 684 thus , total money earned 232 + 180 + 684 = 1096 answer is e" | general |
math_qa__yK1nzu8CKk98q2FB | The length of a rectangle is increased by 25% and its breadth is decreased by 15%. What is the effect on its area? Choose the correct choice from the following answers:
A) 1288
B) 1299
C) 10625
D) 10000
E) 2887 | <gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">125 * 85</gadget>
<output>10_625</output>
<result>C</result> | C | 10,625 | The length of a rectangle is increased by 25% and its breadth is decreased by 15%. What is the effect on its area? | {
"A": "1288",
"B": "1299",
"C": "10625",
"D": "10000",
"E": "2887"
} | multiply(add(25, const_100), subtract(const_100, 15)) | add(n0,const_100)|subtract(const_100,n1)|multiply(#0,#1)| | "100 * 100 = 10000 125 * 85 = 10625 answer : c" | geometry |
math_qa__M658I416FXsbB8HA | Suraj has a certain average of runs for 8 innings. In the 9th innings he scores 90 runs thereby increasing his average by 6 runs. What is his average after the 9th innings?
Choose the correct option: A) 42 B) 64 C) 36 D) 72 E) 27 | <gadget id="calculator">8 * 6</gadget>
<output>48</output>
<gadget id="calculator">90 - 48</gadget>
<output>42</output>
<gadget id="calculator">9 - 8</gadget>
<output>1</output>
<gadget id="calculator">42 / 1</gadget>
<output>42</output>
<result>A</result> | A | 42 | Suraj has a certain average of runs for 8 innings. In the 9th innings he scores 90 runs thereby increasing his average by 6 runs. What is his average after the 9th innings? | {
"A": "42",
"B": "64",
"C": "36",
"D": "72",
"E": "27"
} | divide(subtract(90, multiply(8, 6)), subtract(9, 8)) | multiply(n0,n3)|subtract(n1,n0)|subtract(n2,#0)|divide(#2,#1)| | "to improve his average by 6 runs per innings he has to contribute 8 x 6 = 48 runs for the previous 8 innings . thus , the average after the 9 th innings = 90 - 48 = 42 . answer : a" | general |
math_qa__RdBSUxUFp1UuKnvo | 20 men or 25 women can finish a work in 25 days. How many days 38 men and 15 women will take to finish this job?
Choose the most appropriate option:
A) 12 days
B) 10 days
C) 5 days
D) 6 days
E) 15 days | <gadget id="calculator">25 * 25</gadget>
<output>625</output>
<gadget id="calculator">25 / 20</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 38</gadget>
<output>95/2 = around 47.5</output>
<gadget id="calculator">(95/2) + 15</gadget>
<output>125/2 = around 62.5</output>
<gadget id="calculator">625 / (125/2)</gadget>
<output>10</output>
<result>B</result> | B | 10 | 20 men or 25 women can finish a work in 25 days. How many days 38 men and 15 women will take to finish this job? | {
"A": "12 days",
"B": "10 days",
"C": "5 days",
"D": "6 days",
"E": "15 days"
} | divide(multiply(25, 25), add(multiply(divide(25, 20), 38), 15)) | divide(n1,n0)|multiply(n1,n1)|multiply(n3,#0)|add(n4,#2)|divide(#1,#3) | 20 men = 25 women therefore , 1 women = 20 / 25 men = 4 / 5 men 15 women = 4 / 5 * 15 men = 12 men i . e . 38 men + 15 women = 38 men + 12 men = 50 men 1 work done by men = 20 * 25 20 * 25 = 50 * ? number of days = 20 * 25 / 50 = 10 days . b | physics |
math_qa__NphJ7p4XHFBoyAwK | Two heavily loaded sixteen-wheeler transport trucks are 940 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway? Select the correct option:
A) 90 B) 130 C) 150 D) 140 E) 450 | <gadget id="calculator">940 - 90</gadget>
<output>850</output>
<gadget id="calculator">90 + 80</gadget>
<output>170</output>
<gadget id="calculator">850 / 170</gadget>
<output>5</output>
<gadget id="calculator">90 - 80</gadget>
<output>10</output>
<gadget id="calculator">5 * 10</gadget>
<output>50</output>
<gadget id="calculator">90 + 50</gadget>
<output>140</output>
<result>D</result> | D | 140 | Two heavily loaded sixteen-wheeler transport trucks are 940 kilometers apart, sitting at two rest stops on opposite sides of the same highway. Driver A begins heading down the highway driving at an average speed of 90 kilometers per hour. Exactly one hour later, Driver B starts down the highway toward Driver A, maintaining an average speed of 80 kilometers per hour. How many kilometers farther than Driver B, will Driver A have driven when they meet and pass each other on the highway? | {
"A": "90",
"B": "130",
"C": "150",
"D": "140",
"E": "450"
} | add(90, multiply(divide(subtract(940, 90), add(90, 80)), subtract(90, 80))) | add(n1,n2)|subtract(n0,n1)|subtract(n1,n2)|divide(#1,#0)|multiply(#3,#2)|add(n1,#4)| | "i ' ve been reading the website for a while and i ' m always keen to see different approaches so i would like to share one that works for me : short version : truck a travels for an hour . distance remaining = 940 - 90 = 850 k ratio of speeds 9 : 8 - > 850 / 17 = 50 truck a = 90 + 50 * 9 = 540 truck b = 50 * 8 = 400 delta = 140 km answer d" | general |
math_qa__IxZzaj4yPKEPvf2P | In an examination, 32% of total students failed in Hindi, 56% failed in English and 12% in both. The percentage of these who passed in both the subjects is : Choose the correct choice from the following options: A) 24 B) 37 C) 28 D) 40 E) 81 | <gadget id="calculator">32 + 56</gadget>
<output>88</output>
<gadget id="calculator">88 - 12</gadget>
<output>76</output>
<gadget id="calculator">100 - 76</gadget>
<output>24</output>
<result>A</result> | A | 24 | In an examination, 32% of total students failed in Hindi, 56% failed in English and 12% in both. The percentage of these who passed in both the subjects is : | {
"A": "24",
"B": "37",
"C": "28",
"D": "40",
"E": "81"
} | subtract(const_100, subtract(add(32, 56), 12)) | add(n0,n1)|subtract(#0,n2)|subtract(const_100,#1)| | "explanation : formula n ( a â ˆ ª b ) = n ( a ) + n ( b ) â ˆ ’ n ( a â ˆ © b ) fail in hindi or english = 32 + 56 â € “ 12 = 76 therefore students who passed = 100 â € “ 76 = 24 . answer : a" | general |
math_qa__qLzIgM8ZCC5me8iL | A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 221, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala? Choose the correct choice from the following answers.
A) 22 B) 33 C) 55 D) 77 E) 39 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(1/10) + (3/4)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">221 / (17/20)</gadget>
<output>260</output>
<gadget id="calculator">260 - 221</gadget>
<output>39</output>
<result>E</result> | E | 39 | A farmer has an apple orchard consisting of Fuji and Gala apple trees. Due to high winds this year 10% of his trees cross pollinated. The number of his trees that are pure Fuji plus the cross-pollinated ones totals 221, while 3/4 of all his trees are pure Fuji. How many of his trees are pure Gala? | {
"A": "22",
"B": "33",
"C": "55",
"D": "77",
"E": "39"
} | subtract(divide(221, add(divide(10, const_100), divide(3, 4))), 221) | divide(n0,const_100)|divide(n2,n3)|add(#0,#1)|divide(n1,#2)|subtract(#3,n1)| | "let f = pure fuji , g = pure gala and c - cross pollinated . c = 10 % of x where x is total trees . c = . 1 x also 3 x / 4 = f and c + f = 221 = > . 1 x + 3 / 4 x = 221 = > x = 260 260 - 221 = pure gala = 39 . e" | general |
math_qa__pgGKwvJc2pzXbbpb | The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle? Pick one
A) 18 cm B) 20 cm C) 22 cm D) 24 cm E) 25 cm | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">216 * (3/2)</gadget>
<output>324</output>
<gadget id="calculator">324 ** (1/2)</gadget>
<output>18</output>
<result>A</result> | A | 18 | The ratio between the perimeter and the breadth of a rectangle is 5 : 1. If the area of the rectangle is 216 sq. cm, what is the length of the rectangle? | {
"A": "18 cm",
"B": "20 cm",
"C": "22 cm",
"D": "24 cm",
"E": "25 cm"
} | sqrt(multiply(216, divide(const_3, const_2))) | divide(const_3,const_2)|multiply(n2,#0)|sqrt(#1) | 2 ( l + b ) = 5 b 1 2 l + 2 b = 5 b 3 b = 2 l b = 2 l 3 then , area = 216 cm 2 l x b = 216 l x 2 l = 216 3 l 2 = 324 l = 18 cm . a | geometry |
math_qa__wpYNZVPlj5IWw9mC | On a two-dimensional coordinate plane, the line q = x^2 - x^3 touches the x-axis in how many places?
Choose the correct answer.
A) 0 B) 1 C) 2 D) 3 E) 4 | <gadget id="calculator">max(3, 2)</gadget>
<output>3</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<result>C</result> | C | 2 | On a two-dimensional coordinate plane, the line q = x^2 - x^3 touches the x-axis in how many places? | {
"A": "0",
"B": "1",
"C": "2",
"D": "3",
"E": "4"
} | subtract(max(3, 2), const_1) | max(n0,n1)|subtract(#0,const_1)| | "apparently it ' s q = x ^ 2 - x ^ 3 instead of q = x ^ 2 - q ^ 3 . in this case : the x - intercept is the value ( s ) of x for q = 0 . 0 = x ^ 2 - x ^ 3 ; 0 = x ^ 2 ( 1 - x ) ; x = 0 or x = 1 . answer : c ." | general |
math_qa__XrHBZ3F4SffULvKd | There is 60 lit of milk and water in which milk forms 84%.Howmuch water must be added to this solution to make it solution in which milk forms 60% Select.
A) 18.75 B) 19.75 C) 20.75 D) 21.75 E) 24 | <gadget id="calculator">100 / 60</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">60 * 84</gadget>
<output>5_040</output>
<gadget id="calculator">5_040 / 100</gadget>
<output>252/5 = around 50.4</output>
<gadget id="calculator">(5/3) * (252/5)</gadget>
<output>84</output>
<gadget id="calculator">84 - 60</gadget>
<output>24</output>
<result>E</result> | E | 24 | There is 60 lit of milk and water in which milk forms 84%.Howmuch water must be added to this solution to make it solution in which milk forms 60% | {
"A": "18.75",
"B": "19.75",
"C": "20.75",
"D": "21.75",
"E": "24"
} | subtract(multiply(divide(const_100, 60), divide(multiply(60, 84), const_100)), 60) | divide(const_100,n2)|multiply(n0,n1)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,n0)| | "60 * 84 / 100 = 50.40 lit milk that is 9.60 lit water let x lit water will be added then ( 60 + x ) * 60 / 100 = 50.40 so x = 18.75 answer : e" | gain |
math_qa__TNgkSnKoLTG1qRW9 | The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 10, and k < m < r < s < t. If t is 20, what is the greatest possible value of the median of the 5 integers? Choose the correct choice from the following options
A) 16
B) 18
C) 13
D) 20
E) 22 | <gadget id="calculator">10 * 5</gadget>
<output>50</output>
<gadget id="calculator">50 - 20</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">15 - 2</gadget>
<output>13</output>
<result>C</result> | C | 13 | The average (arithmetic mean) of the 5 positive integers k, m, r, s, and t is 10, and k < m < r < s < t. If t is 20, what is the greatest possible value of the median of the 5 integers? | {
"A": "16",
"B": "18",
"C": "13",
"D": "20",
"E": "22"
} | subtract(divide(subtract(multiply(10, 5), 20), const_2), const_2) | multiply(n0,n1)|subtract(#0,n2)|divide(#1,const_2)|subtract(#2,const_2)| | "we need to find the median which is the third value when the numbers are in increasing order . since k < m < r < s < t , the median would be r . the average of the positive integers is 10 which means that in effect , all numbers are equal to 10 . if the largest number is 20 , it is 10 more than 20 . we need r to be maximum so k and m should be as small as possible to get the average of 10 . since all the numbers are positive integers , k and m can not be less than 1 and 2 respectively . 1 is 9 less than 10 and 2 is 8 less than 10 which means k and m combined are 17 less than the average . 20 is already 10 more than 10 and hence we only have 17 - 10 = 7 extra to distribute between r and s . since s must be greater than r , r can be 10 + 3 = 13 and s can be 10 + 4 = 14 . so r is 13 . answer ( c )" | general |
math_qa__8pQIHqY1djvyThCP | If a person walks at 15 km/hr instead of 10 km/hr, he would have walked 15 km more. The actual distance traveled by him is? Pick one
A) 30 B) 50 C) 15 D) 12 E) 20 | <gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">10 * 3</gadget>
<output>30</output>
<result>A</result> | A | 30 | If a person walks at 15 km/hr instead of 10 km/hr, he would have walked 15 km more. The actual distance traveled by him is? | {
"A": "30",
"B": "50",
"C": "15",
"D": "12",
"E": "20"
} | multiply(10, divide(15, subtract(15, 10))) | subtract(n0,n1)|divide(n2,#0)|multiply(n1,#1)| | "let the actual distance traveled be x km . then , x / 10 = ( x + 15 ) / 15 x - 30 = > x = 30 km . answer : a" | general |
math_qa__EoCVNDuzrGkFt2Cs | A rectangular tiled patio is composed of 48 square tiles. The rectangular patio will be rearranged so that there will be 2 fewer columns of tiles and 4 more rows of tiles. After the change in layout, the patio will still have 48 tiles, and it will still be rectangular. How many rows are in the tile patio before the change in layout? Choose the correct answer.
A) 5 B) 6 C) 10 D) 13 E) 28 | <gadget id="calculator">-4</gadget>
<output>-4</output>
<gadget id="calculator">4 ** 2</gadget>
<output>16</output>
<gadget id="calculator">48 * 2</gadget>
<output>96</output>
<gadget id="calculator">4 * 96</gadget>
<output>384</output>
<gadget id="calculator">16 + 384</gadget>
<output>400</output>
<gadget id="calculator">400 ** (1/2)</gadget>
<output>20</output>
<gadget id="calculator">(-4) + 20</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">48 / 8</gadget>
<output>6</output>
<result>B</result> | B | 6 | A rectangular tiled patio is composed of 48 square tiles. The rectangular patio will be rearranged so that there will be 2 fewer columns of tiles and 4 more rows of tiles. After the change in layout, the patio will still have 48 tiles, and it will still be rectangular. How many rows are in the tile patio before the change in layout? | {
"A": "5",
"B": "6",
"C": "10",
"D": "13",
"E": "28"
} | divide(48, divide(add(negate(4), sqrt(add(power(4, 2), multiply(4, multiply(48, 2))))), 2)) | multiply(n0,n1)|negate(n2)|power(n2,n1)|multiply(n2,#0)|add(#3,#2)|sqrt(#4)|add(#1,#5)|divide(#6,n1)|divide(n0,#7)| | "suppose there are c columns and there are r rows original situation so , number of tiles = c * r = 48 also . reach column has r tiles and each row has c tiles new situation number of tiles in each column is r - 2 and number of tiles in each row is c + 4 so , number of rows = r - 2 and number of columns is c + 4 so , number of tiles = ( r - 2 ) * ( c + 4 ) = 48 comparing both of them we get c * r = ( r - 2 ) * ( c + 4 ) = > 4 r - 2 c = 8 c = 2 r - 4 putting it in c * r = 48 ( 2 r - 4 ) * r = 48 2 r ^ 2 - 4 r - 48 = 0 r can not be negative so r = 6 and c = 8 so , answer will be b" | geometry |
math_qa__NAArItcOkW9L6Zgk | A shopkeeper loses 15%,if an article is sold for Rs. 119. What should be the selling price of the article to gain 20%? Choose the correct choice from the following answers.
A) s . 177 B) s . 168 C) s . 144 D) s . 129 E) s . 112 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (3/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">119 / (17/20)</gadget>
<output>140</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">140 * (1/5)</gadget>
<output>28</output>
<gadget id="calculator">140 + 28</gadget>
<output>168</output>
<result>B</result> | B | 168 | A shopkeeper loses 15%,if an article is sold for Rs. 119. What should be the selling price of the article to gain 20%? | {
"A": "s . 177",
"B": "s . 168",
"C": "s . 144",
"D": "s . 129",
"E": "s . 112"
} | add(divide(119, subtract(const_1, divide(15, const_100))), multiply(divide(119, subtract(const_1, divide(15, const_100))), divide(20, const_100))) | divide(n0,const_100)|divide(n2,const_100)|subtract(const_1,#0)|divide(n1,#2)|multiply(#3,#1)|add(#3,#4)| | "given that sp = rs . 119 and loss = 15 % cp = [ 100 ( sp ) ] / ( 100 - l % ) = ( 100 * 119 ) / 85 = rs . 140 . to get 20 % profit , new sp = [ ( 100 + p % ) cp ] / 100 = ( 140 * 120 ) / 100 = rs . 168 answer : b" | gain |
math_qa__IJhaFFdDNquN1vXX | The sides of a cube measures 6.5cm. If the surface area of the cube is the same as a ball, what is the radius of the ball? Round to the nearest whole number. Choose the correct choice from the following choices.
A) 9 B) 7 C) 4 D) 8 E) 6 | <gadget id="calculator">6 * (6.5 ** 2)</gadget>
<output>253.5</output>
<gadget id="calculator">253.5 / 4</gadget>
<output>63.375</output>
<gadget id="calculator">63.375 / pi</gadget>
<output>63.375/pi = around 20.172889</output>
<gadget id="calculator">(63.375/pi) ** (1/2)</gadget>
<output>7.96084166404533/sqrt(pi) = around 4.491424</output>
<gadget id="calculator">floor(7.96084166404533/sqrt(pi))</gadget>
<output>4</output>
<result>C</result> | C | 4 | The sides of a cube measures 6.5cm. If the surface area of the cube is the same as a ball, what is the radius of the ball? Round to the nearest whole number. | {
"A": "9",
"B": "7",
"C": "4",
"D": "8",
"E": "6"
} | floor(sqrt(divide(divide(surface_cube(6.5), const_4), const_pi))) | surface_cube(n0)|divide(#0,const_4)|divide(#1,const_pi)|sqrt(#2)|floor(#3) | first calculate the surface area of the cube . the cube is made of 6 squares with the sides measuring 6.5 cm each . the surface area of 1 side of the cube is 42.25 cm . multiply the surface area of the 1 side by 6 will give you the cube ' s total surface area . the cubes surface area is 253.5 cm . now we know that the surface area of the ball is 253.5 cm . to find out the surface area of a sphere you need to square the radius , then multiply by pi , and multiply by the number 4 . going backwards to find the radius - you will need to dived the surface area by 4 . then divide by pi . then determine the square root of the answer . the radius is 4.460 . rounding to the nearest whole number the radius is 4 . the correct answer is ( c ) . | geometry |
math_qa__tqyvCttmTj9Jmg7S | A, B and C have Rs.1000 between them, A and C together have Rs.700 and B and C Rs.600. How much does C have? Options: A) 100 B) 200 C) 300 D) 400 E) 500 | <gadget id="calculator">700 + 600</gadget>
<output>1_300</output>
<gadget id="calculator">1_300 - 1_000</gadget>
<output>300</output>
<result>C</result> | C | 300 | A, B and C have Rs.1000 between them, A and C together have Rs.700 and B and C Rs.600. How much does C have? | {
"A": "100",
"B": "200",
"C": "300",
"D": "400",
"E": "500"
} | subtract(add(700, 600), 1000) | add(n1,n2)|subtract(#0,n0)| | "a + b + c = 1000 a + c = 700 b + c = 600 - - - - - - - - - - - - - - a + b + 2 c = 1300 a + b + c = 1000 - - - - - - - - - - - - - - - - c = 300 answer : c" | general |
math_qa__8EjcUnyKlwUoMmVl | If (1/2)^18 (1/81)^k = 1/18^18, then k = Choose one.
A) 9 B) 12 C) 16 D) 24 E) 36 | <gadget id="calculator">18 * 2</gadget>
<output>36</output>
<gadget id="calculator">36 / 4</gadget>
<output>9</output>
<result>A</result> | A | 9 | If (1/2)^18 (1/81)^k = 1/18^18, then k = | {
"A": "9",
"B": "12",
"C": "16",
"D": "24",
"E": "36"
} | divide(multiply(18, 2), const_4) | multiply(n1,n2)|divide(#0,const_4)| | "i ' m going to focus on denominator only . . ( 2 ^ 18 ) . ( ( 3 ^ 4 ) ^ k = 18 ^ 18 ( 2 ^ 18 ) . ( ( 3 ^ 4 k ) = ( 2 . 3 ^ 2 ) ^ 18 ( 2 ^ 18 ) . ( ( 3 ^ 4 k ) = ( 2 ^ 24 ) . ( 3 ^ 2 ) ^ 18 hence 4 k = 36 k = 9 answer a i hope it ' s quite clear" | general |
math_qa__Ofdk8ovENrPHDYOC | In a college, the ratio of the number of boys to girls is 8 : 5. If there are 300 girls, the total number of students in the college is Choices: A) 420 B) 520 C) 620 D) 780 E) 820 | <gadget id="calculator">300 / 5</gadget>
<output>60</output>
<gadget id="calculator">60 * 8</gadget>
<output>480</output>
<gadget id="calculator">300 + 480</gadget>
<output>780</output>
<result>D</result> | D | 780 | In a college, the ratio of the number of boys to girls is 8 : 5. If there are 300 girls, the total number of students in the college is | {
"A": "420",
"B": "520",
"C": "620",
"D": "780",
"E": "820"
} | add(300, multiply(divide(300, 5), 8)) | divide(n2,n1)|multiply(n0,#0)|add(n2,#1)| | "explanation : let the boy are 8 x and girls are 5 x = > 5 x = 300 = > x = 60 total students = 8 x + 5 x = 13 x = 13 ( 60 ) = 780 option d" | other |
math_qa__tZ2CxKtK8TKAzuSe | The sale price sarees listed for Rs.390 after successive discount is 15% and 25% is? Options
A) 298 B) 237 C) 248 D) 876 E) 291 | <gadget id="calculator">390 * 15</gadget>
<output>5_850</output>
<gadget id="calculator">5_850 / 100</gadget>
<output>117/2 = around 58.5</output>
<gadget id="calculator">390 - (117/2)</gadget>
<output>663/2 = around 331.5</output>
<gadget id="calculator">(663/2) * 25</gadget>
<output>16_575/2 = around 8_287.5</output>
<gadget id="calculator">(16_575/2) / 100</gadget>
<output>663/8 = around 82.875</output>
<gadget id="calculator">(663/2) - (663/8)</gadget>
<output>1_989/8 = around 248.625</output>
<result>C</result> | C | 248 | The sale price sarees listed for Rs.390 after successive discount is 15% and 25% is? | {
"A": "298",
"B": "237",
"C": "248",
"D": "876",
"E": "291"
} | subtract(subtract(390, divide(multiply(390, 15), const_100)), divide(multiply(subtract(390, divide(multiply(390, 15), const_100)), 25), const_100)) | multiply(n0,n1)|divide(#0,const_100)|subtract(n0,#1)|multiply(n2,#2)|divide(#3,const_100)|subtract(#2,#4)| | "390 * ( 85 / 100 ) * ( 75 / 100 ) = 248 answer : c" | gain |
math_qa__1FIgxxWp5lK4PD87 | a student finds the average of 9 positive integers . each integer contains two digits . by mistake , the boy interchanges the digits of one number say pq for qp . due to this , the average becomes 1 less than the previous one . what was the difference of the two digits p and q ? Choose the correct answer:
A) 8 B) 6 C) 1 D) 4 E) 2 | <gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">(1/9) * 9</gadget>
<output>1</output>
<result>C</result> | C | 1 | a student finds the average of 9 positive integers . each integer contains two digits . by mistake , the boy interchanges the digits of one number say pq for qp . due to this , the average becomes 1 less than the previous one . what was the difference of the two digits p and q ? | {
"A": "8",
"B": "6",
"C": "1",
"D": "4",
"E": "2"
} | multiply(divide(1, 9), 9) | divide(n1,n0)|multiply(n0,#0) | explanation : let the original number be pq i . e . , ( 10 p + q ) . after interchanging the digits , the new number becomes qp i . e . , ( 10 q + p ) . the question states that the average of 9 numbers has become 1 less than the original average . therefore , the sum of the original 9 numbers will be 9 * 1 more than the sum of the 9 numbers with the digits interchanged . i . e . , 10 p + q = 10 q + p + 9 = > 9 a - 9 b = 9 = > a - b = 1 . answer : c | general |
math_qa__mvJVmprj7P4wr1Wf | A man can row a distance of 5 km in 60 min with the help of the tide. The direction of the tide reverses with the same speed. Now he travels a further 25 km in 10 hours. How much time he would have saved if the direction of tide has not changed? Choose the correct choice from the following answers
A) 2
B) 5
C) 1
D) 6
E) 7 | <gadget id="calculator">25 / 5</gadget>
<output>5</output>
<gadget id="calculator">10 - 5</gadget>
<output>5</output>
<result>B</result> | B | 5 | A man can row a distance of 5 km in 60 min with the help of the tide. The direction of the tide reverses with the same speed. Now he travels a further 25 km in 10 hours. How much time he would have saved if the direction of tide has not changed? | {
"A": "2",
"B": "5",
"C": "1",
"D": "6",
"E": "7"
} | subtract(10, divide(25, 5)) | divide(n2,n0)|subtract(n3,#0)| | "explanation : he covered 5 km in 1 hour , so he might cover 25 km in 5 hours . but he took 10 hours . he would have saved 10 â € “ 5 = 5 hours . answer : b" | physics |
math_qa__j4QJMf2PCpmXgwbE | A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 7000? Choose the correct option.
A) s . 4991 B) s . 5991 C) s . 6001 D) s . 6991 E) s . 7991 | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 7_000</gadget>
<output>42_000</output>
<gadget id="calculator">6_435 + 6_927</gadget>
<output>13_362</output>
<gadget id="calculator">13_362 + 6_855</gadget>
<output>20_217</output>
<gadget id="calculator">20_217 + 7_230</gadget>
<output>27_447</output>
<gadget id="calculator">27_447 + 6_562</gadget>
<output>34_009</output>
<gadget id="calculator">42_000 - 34_009</gadget>
<output>7_991</output>
<result>E</result> | E | 7,991 | A grocer has a sale of Rs. 6435, Rs. 6927, Rs. 6855, Rs. 7230 and Rs. 6562 for 5 consecutive months. How much sale must he have in the sixth month so that he gets an average sale of Rs. 7000? | {
"A": "s . 4991",
"B": "s . 5991",
"C": "s . 6001",
"D": "s . 6991",
"E": "s . 7991"
} | subtract(multiply(add(5, const_1), 7000), add(add(add(add(6435, 6927), 6855), 7230), 6562)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "total fr 5 mnths = ( 6435 + 6927 + 6855 + 7230 + 6562 ) = rs 34009 . reqd . sale = rs . [ ( 7000 * 6 ) - 34009 ] = rs . ( 42000 - 34009 ) = rs . 7991 . answer : e" | general |
math_qa__fLc404GXZXcMo8QU | During the first two weeks of January, the total rainfall in Springdale was 30 inches. If the rainfall during the second week was 1.5 times the rainfall during the first week, what was the rainfall during the second week of January?
Select:
A) 5 inches
B) 6 inches
C) 9 inches
D) 10 inches
E) 18 inches | <gadget id="calculator">1 + 1.5</gadget>
<output>2.5</output>
<gadget id="calculator">1.5 / 2.5</gadget>
<output>0.6</output>
<gadget id="calculator">30 * 0.6</gadget>
<output>18</output>
<result>E</result> | E | 18 | During the first two weeks of January, the total rainfall in Springdale was 30 inches. If the rainfall during the second week was 1.5 times the rainfall during the first week, what was the rainfall during the second week of January? | {
"A": "5 inches",
"B": "6 inches",
"C": "9 inches",
"D": "10 inches",
"E": "18 inches"
} | multiply(30, divide(1.5, add(const_1, 1.5))) | add(n1,const_1)|divide(n1,#0)|multiply(n0,#1)| | "total rainfall in 2 weeks = 18 inches . assume the rainfall in second week = 1 . x rainfall in first week = x total rainfall = 2.5 x = 18 inches x = 12 and 1.5 x = 18 rainfall during second week = 18 inches option e" | general |
math_qa__zsqHMkfnAkGbNmeC | What is the minimum value of |x-4| + |x+2| + |x-5| ?
Choose the correct choice: A) - 3 B) 3 C) 5 D) 7 E) 8 | <gadget id="calculator">2 + 5</gadget>
<output>7</output>
<result>D</result> | D | 7 | What is the minimum value of |x-4| + |x+2| + |x-5| ? | {
"A": "- 3",
"B": "3",
"C": "5",
"D": "7",
"E": "8"
} | add(2, 5) | add(n1,n2)| | "a can not be the answer as all the three terms are in modulus and hence the answer will be non negative . | x - 4 | > = 0 - - > minimum occurs at x = 4 | x + 2 | > = 0 - - > minimum occurs at x = - 2 | x - 5 | > = 0 - - > minimum occurs at x = 5 x = - 2 - - > result = 6 + 0 + 7 = 13 . also any negative value will push the combined value of | x - 4 | + | x - 5 | to a value > 9 . x = 4 - - > result = 0 + 6 + 1 = 7 x = 5 - - > result = 1 + 7 + 0 = 8 x = 2 - - > result = 2 + 4 + 3 = 9 so minimum value of the expression occurs at x = 4 and the resultant value = 7 answer : d" | general |
math_qa__KNPLx8sH0TKHxDnv | The average weight of 8 persons increases by 4 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ? Choices.
A) 75 kg
B) 65 kg
C) 55 kg
D) 97 kg
E) 25 kg | <gadget id="calculator">8 * 4</gadget>
<output>32</output>
<gadget id="calculator">65 + 32</gadget>
<output>97</output>
<result>D</result> | D | 97 | The average weight of 8 persons increases by 4 kg when a new person comes in place of one of them weighing 65 kg. What might be the weight of the new person ? | {
"A": "75 kg",
"B": "65 kg",
"C": "55 kg",
"D": "97 kg",
"E": "25 kg"
} | add(65, multiply(8, 4)) | multiply(n0,n1)|add(n2,#0)| | "total weight increased = ( 8 x 4 ) kg = 32 kg . weight of new person = ( 65 + 32 ) kg = 97 kg . answer : d" | general |
math_qa__lhx6Yl31yhDON8TU | If p and q are positive integers each greater than 1, and 17(p+1)=25(q+1), what is the least possible value of p+q? Choose the correct option: A) 36 B) 42 C) 40 D) 46 E) none | <gadget id="calculator">25 + 17</gadget>
<output>42</output>
<gadget id="calculator">42 - 2</gadget>
<output>40</output>
<result>C</result> | C | 40 | If p and q are positive integers each greater than 1, and 17(p+1)=25(q+1), what is the least possible value of p+q? | {
"A": "36",
"B": "42",
"C": "40",
"D": "46",
"E": "none"
} | subtract(add(25, 17), const_2) | add(n1,n3)|subtract(#0,const_2)| | "17 ( p + 1 ) = 29 ( q + 1 ) - - > ( p + 1 ) / ( q + 1 ) = 29 / 17 - - > the least positive value of p + 1 is 25 , so the least value of p is 24 and the least positive value of q + 1 is 17 , so the least value of q is 16 - - > the least value of p + q is 24 + 16 = 40 . answer : c ." | general |
math_qa__hjycr661k3qGBVA4 | What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 54? Choose the correct choice: A) 3672 B) 920 C) 7290 D) 6928 E) 3729 | <gadget id="calculator">289 ** (1/2)</gadget>
<output>17</output>
<gadget id="calculator">4 * 17</gadget>
<output>68</output>
<gadget id="calculator">68 * 54</gadget>
<output>3_672</output>
<result>A</result> | A | 3,672 | What will be the cost of building a fence around a square plot with area equal to 289 sq ft, if the price per foot of building the fence is Rs. 54? | {
"A": "3672",
"B": "920",
"C": "7290",
"D": "6928",
"E": "3729"
} | multiply(square_perimeter(sqrt(289)), 54) | sqrt(n0)|square_perimeter(#0)|multiply(n1,#1)| | "explanation : let the side of the square plot be a ft . a 2 = 289 = > a = 17 length of the fence = perimeter of the plot = 4 a = 68 ft . cost of building the fence = 68 * 54 = rs . 3672 . answer : option a" | geometry |
math_qa__XpQAGBUtZZzcKRov | Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 33 kmph. Of how many minutes does the train stop per hour? Choose the correct choice from the following answers:
A) 73 B) 83 C) 16 D) 83 E) 28 | <gadget id="calculator">33 / 45</gadget>
<output>11/15 = around 0.733333</output>
<gadget id="calculator">60 * (11/15)</gadget>
<output>44</output>
<gadget id="calculator">60 - 44</gadget>
<output>16</output>
<result>C</result> | C | 16 | Excluding stoppages, the speed of a train is 45 kmph and including stoppages it is 33 kmph. Of how many minutes does the train stop per hour? | {
"A": "73",
"B": "83",
"C": "16",
"D": "83",
"E": "28"
} | subtract(const_60, multiply(const_60, divide(33, 45))) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)| | "explanation : t = 12 / 45 * 60 = 16 answer : option c" | physics |
math_qa__PRsemDyJZOXEVso0 | Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the same Job.How long should it take both A and B, working together but independently, to do the same job?
Choose the correct answer:
A) 70 hours B) 40 / 9 hours C) 9 hours D) 16 hours E) 20 hours | <gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/8) + (1/10)</gadget>
<output>9/40 = around 0.225</output>
<gadget id="calculator">1 / (9/40)</gadget>
<output>40/9 = around 4.444444</output>
<result>B</result> | B | 4.444444 | Worker A takes 8 hours to do a job. Worker B takes 10 hours to do the same Job.How long should it take both A and B, working together but independently, to do the same job? | {
"A": "70 hours",
"B": "40 / 9 hours",
"C": "9 hours",
"D": "16 hours",
"E": "20 hours"
} | divide(const_1, add(divide(const_1, 8), divide(const_1, 10))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|divide(const_1,#2)| | "a ’ s 1 hour ' s work = 1 / 8 b ' s 1 hour ' s work = 1 / 10 ( a + b ) ' s 1 hour ' s work = ( 1 / 8 ) + ( 1 / 10 ) = 9 / 40 both a and b will finish the work in 40 / 9 days . answer b 40 / 9 hours" | physics |
math_qa__vRppTFrLvnoJunPZ | rectangle dimensions were given,2 doors dimensions given, 2 windows dimensions given. 70cm wide wallpaper to be covered on the walls of this room. Cost of wallpaper is 60 per meter.. calculate total cost Pick:
A) 20 B) 25 C) 30 D) 60 E) 70 | <gadget id="calculator">60 * 1</gadget>
<output>60</output>
<result>D</result> | D | 60 | rectangle dimensions were given,2 doors dimensions given, 2 windows dimensions given. 70cm wide wallpaper to be covered on the walls of this room. Cost of wallpaper is 60 per meter.. calculate total cost | {
"A": "20",
"B": "25",
"C": "30",
"D": "60",
"E": "70"
} | multiply(60, const_1) | multiply(n3,const_1) | area of room = ( l * b ) m ^ 2 area of door + window = ( d + w ) m ^ 2 remaining area = ( ( l * b ) - ( d + w ) ) m ^ 2 so length = remaining area / 0.70 m total cost = length * 60 - - - ans and total cost = 60 answer : d | physics |
math_qa__z0p60JjwHdSs7uqY | set s consists of integers { 12 , 34 } . if two numbers are chosen from set s at random , what is the probability that the sum of 2 numbers is more than 6 ? Choose the correct option
A) 1 / 3 B) 1 / 6 C) 2 / 3 D) 2 / 5 E) 3 / 7 | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<result>B</result> | B | 0.166667 | set s consists of integers { 12 , 34 } . if two numbers are chosen from set s at random , what is the probability that the sum of 2 numbers is more than 6 ? | {
"A": "1 / 3",
"B": "1 / 6",
"C": "2 / 3",
"D": "2 / 5",
"E": "3 / 7"
} | inverse(6) | inverse(n3) | number of ways you can choose 2 from 4 = 4 c 2 = 6 e = event of getting the 2 numbers is more than 6 = ( 3,4 ) = 1 probability = 1 / 6 answer is b | general |
math_qa__FuXEwrGwI7D32h2l | In a sample of 800 high school students in which all students are either freshmen, sophomores, juniors, or seniors, 23 percent are juniors and 75 percent are not sophomores. If there are 160 seniors, how many more freshmen than sophomores are there among the sample of students? Choose the correct option:
A) 42
B) 48
C) 56
D) 64
E) 72 | <gadget id="calculator">160 / 800</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 100</gadget>
<output>20</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 - 23</gadget>
<output>57</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<gadget id="calculator">57 - 25</gadget>
<output>32</output>
<gadget id="calculator">32 * 800</gadget>
<output>25_600</output>
<gadget id="calculator">25_600 / 100</gadget>
<output>256</output>
<gadget id="calculator">25 * 800</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 / 100</gadget>
<output>200</output>
<gadget id="calculator">256 - 200</gadget>
<output>56</output>
<result>C</result> | C | 56 | In a sample of 800 high school students in which all students are either freshmen, sophomores, juniors, or seniors, 23 percent are juniors and 75 percent are not sophomores. If there are 160 seniors, how many more freshmen than sophomores are there among the sample of students? | {
"A": "42",
"B": "48",
"C": "56",
"D": "64",
"E": "72"
} | subtract(divide(multiply(subtract(subtract(subtract(const_100, multiply(divide(160, 800), const_100)), 23), subtract(const_100, 75)), 800), const_100), divide(multiply(subtract(const_100, 75), 800), const_100)) | divide(n3,n0)|subtract(const_100,n2)|multiply(#0,const_100)|multiply(n0,#1)|divide(#3,const_100)|subtract(const_100,#2)|subtract(#5,n1)|subtract(#6,#1)|multiply(n0,#7)|divide(#8,const_100)|subtract(#9,#4) | 200 are sophomores . the number of freshmen is 600 - 160 - 0.23 ( 800 ) = 256 the answer is c . | gain |
math_qa__ov21K5Xh31aHpZsH | The manager of a produce market purchased a quantity of tomatoes for $0.80 per pound. Due to improper handling, 10 percent of the tomatoes, by weight, were ruined and discarded. At what price per pound should the manager sell the remaining tomatoes if she wishes to make a profit on the sale of the tomatoes equal to 9 percent of the cost of the tomatoes.
Choose the correct choice from the following choices: A) $ 0.94 B) $ 0.97 C) $ 0.98 D) $ 1.00 E) $ 1.20 | <gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">1 + (9/100)</gadget>
<output>109/100 = around 1.09</output>
<gadget id="calculator">100 - 10</gadget>
<output>90</output>
<gadget id="calculator">90 / 100</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">0.8 / (9/10)</gadget>
<output>0.888889</output>
<gadget id="calculator">(109/100) * 0.888889</gadget>
<output>0.968889</output>
<result>B</result> | B | 0.97 | The manager of a produce market purchased a quantity of tomatoes for $0.80 per pound. Due to improper handling, 10 percent of the tomatoes, by weight, were ruined and discarded. At what price per pound should the manager sell the remaining tomatoes if she wishes to make a profit on the sale of the tomatoes equal to 9 percent of the cost of the tomatoes. | {
"A": "$ 0.94",
"B": "$ 0.97",
"C": "$ 0.98",
"D": "$ 1.00",
"E": "$ 1.20"
} | multiply(add(const_1, divide(9, const_100)), divide(0.80, divide(subtract(const_100, 10), const_100))) | divide(n2,const_100)|subtract(const_100,n1)|add(#0,const_1)|divide(#1,const_100)|divide(n0,#3)|multiply(#2,#4)| | "assume the manager bought 100 tomatoes . cost price = 80 given : 10 % are damaged - - > available tomatoes to sell = 90 90 * x - 80 = 0.09 * 80 90 x - 80 = 7.2 90 x = 87.2 x = 87.2 / 90 = 0.968 x is slightly under 0.9688 = 0.97 answer : b" | gain |
math_qa__KGZ1NiWkjwh2MU3v | If a coin has an equal probability of landing heads up or tails up each time it is flipped , what is the probability that the coin will land heads up exactly once in 3 consecutive flips ? Options.
A) 0.125 B) 0.25 C) 0.75 D) 0.375 E) 0.666 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 3</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 3</gadget>
<output>3/8 = around 0.375</output>
<result>D</result> | D | 0.375 | If a coin has an equal probability of landing heads up or tails up each time it is flipped , what is the probability that the coin will land heads up exactly once in 3 consecutive flips ? | {
"A": "0.125",
"B": "0.25",
"C": "0.75",
"D": "0.375",
"E": "0.666"
} | multiply(power(divide(const_1, const_2), 3), 3) | divide(const_1,const_2)|power(#0,n0)|multiply(n0,#1)| | "total number of ways in which h or t can appear in 3 tosses of coin is = 2 * 2 * 2 = 8 ways for 2 t and 1 h thus probability is = p ( htt ) + p ( tth ) + p ( tht ) = 1 / 8 + 1 / 8 + 1 / 8 = 3 / 8 = . 375 answer : d" | probability |
math_qa__x0Xm664AoFJ1Wekd | The average weight of 10 person's increases by 2.5 kg when a new person comes in place of one of them weighing 50 kg. What might be the weight of the new person? Choose the correct option.
A) 76 kg B) 76.5 kg C) 75 kg D) data inadequate E) none of these | <gadget id="calculator">10 * 2.5</gadget>
<output>25</output>
<gadget id="calculator">25 + 50</gadget>
<output>75</output>
<result>C</result> | C | 75 | The average weight of 10 person's increases by 2.5 kg when a new person comes in place of one of them weighing 50 kg. What might be the weight of the new person? | {
"A": "76 kg",
"B": "76.5 kg",
"C": "75 kg",
"D": "data inadequate",
"E": "none of these"
} | add(multiply(10, 2.5), 50) | multiply(n0,n1)|add(n2,#0)| | "explanation : total weight increased = ( 10 x 2.5 ) kg = 25 kg . weight of new person = ( 50 + 25 ) kg = 75 kg . answer : c" | general |
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