id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__L4AASaBAfmWq1KgC | In a company of 180 employees, 110 are females. A total of 90 employees have advanced degrees and the rest have a college degree only. If 35 employees are males with a college degree only, how many employees are females with advanced degrees? Choose one:
A) 50
B) 55
C) 60
D) 65
E) 70 | <gadget id="calculator">180 - 110</gadget>
<output>70</output>
<gadget id="calculator">70 - 35</gadget>
<output>35</output>
<gadget id="calculator">90 - 35</gadget>
<output>55</output>
<result>B</result> | B | 55 | In a company of 180 employees, 110 are females. A total of 90 employees have advanced degrees and the rest have a college degree only. If 35 employees are males with a college degree only, how many employees are females with advanced degrees? | {
"A": "50",
"B": "55",
"C": "60",
"D": "65",
"E": "70"
} | subtract(90, subtract(subtract(180, 110), 35)) | subtract(n0,n1)|subtract(#0,n3)|subtract(n2,#1)| | "the number of males is 180 - 110 = 70 . the number of males with advanced degrees is 70 - 35 = 35 . the number of females with advanced degrees is 90 - 35 = 55 . the answer is b ." | geometry |
math_qa__50QSD6EOPsWXjrOx | How many positive integers less than 8,000 are there in which the sum of the digits equals 5?
Select the correct option
A) 57 B) 56 C) 55 D) 54 E) 53 | <gadget id="calculator">4 + 5</gadget>
<output>9</output>
<gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">factorial(8)</gadget>
<output>40_320</output>
<gadget id="calculator">factorial(5)</gadget>
<output>120</output>
<gadget id="calculator">4 - 1</gadget>
<output>3</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">120 * 6</gadget>
<output>720</output>
<gadget id="calculator">40_320 / 720</gadget>
<output>56</output>
<result>B</result> | B | 56 | How many positive integers less than 8,000 are there in which the sum of the digits equals 5? | {
"A": "57",
"B": "56",
"C": "55",
"D": "54",
"E": "53"
} | divide(factorial(subtract(add(const_4, 5), const_1)), multiply(factorial(5), factorial(subtract(const_4, const_1)))) | add(n1,const_4)|factorial(n1)|subtract(const_4,const_1)|factorial(#2)|subtract(#0,const_1)|factorial(#4)|multiply(#1,#3)|divide(#5,#6)| | "basically , the question asks how many 4 digit numbers ( including those in the form 0 xxx , 00 xx , and 000 x ) have digits which add up to 5 . think about the question this way : we know that there is a total of 5 to be spread among the 4 digits , we just have to determine the number of ways it can be spread . let x represent a sum of 1 , and | represent a seperator between two digits . as a result , we will have 5 x ' s ( digits add up to the 5 ) , and 3 | ' s ( 3 digit seperators ) . so , for example : xx | x | x | x = 2111 | | xxx | xx = 0032 etc . there are 8 c 3 ways to determine where to place the separators . hence , the answer is 8 c 3 = 56 . b" | general |
math_qa__nxKiQEbZY1VYeDsz | C and D started a business by investing Rs.1000/- and Rs.1500/- respectively. Find the D’s share out of a total profit of Rs.500: Choose the correct choice from the following: A) 400 B) 300 C) 200 D) 100 E) 150 | <gadget id="calculator">1_000 / 500</gadget>
<output>2</output>
<gadget id="calculator">1_500 / 500</gadget>
<output>3</output>
<gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">500 / 5</gadget>
<output>100</output>
<result>D</result> | D | 100 | C and D started a business by investing Rs.1000/- and Rs.1500/- respectively. Find the D’s share out of a total profit of Rs.500: | {
"A": "400",
"B": "300",
"C": "200",
"D": "100",
"E": "150"
} | divide(500, add(divide(1000, 500), divide(1500, 500))) | divide(n0,n2)|divide(n1,n2)|add(#0,#1)|divide(n2,#2) | c = rs . 1000 / - d = rs . 1500 / - c share 2 parts & d share 3 parts total 5 parts - - - - - > rs . 500 / - - - - - > 1 part - - - - - - - > rs . 100 / - d share = 3 parts - - - - - > rs . 300 / - d | general |
math_qa__ZnsNLnXwpjtGKbon | A train 400 meters long completely crosses a 300 meters long bridge in 45 seconds. What is the speed of the train is? Choose the correct choice from the following:
A) 32
B) 56
C) 29
D) 27
E) 21 | <gadget id="calculator">400 + 300</gadget>
<output>700</output>
<gadget id="calculator">700 / 1_000</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">45 / 3_600</gadget>
<output>1/80 = around 0.0125</output>
<gadget id="calculator">(7/10) / (1/80)</gadget>
<output>56</output>
<result>B</result> | B | 56 | A train 400 meters long completely crosses a 300 meters long bridge in 45 seconds. What is the speed of the train is? | {
"A": "32",
"B": "56",
"C": "29",
"D": "27",
"E": "21"
} | divide(divide(add(400, 300), const_1000), divide(45, const_3600)) | add(n0,n1)|divide(n2,const_3600)|divide(#0,const_1000)|divide(#2,#1)| | "s = ( 400 + 300 ) / 45 = 700 / 45 * 18 / 5 = 56 answer : b" | physics |
math_qa__uwZXgAvvSIGiuQbm | Q and R are two-digit positive integers that have the same digits but in reverse order. If the positive difference between Q and R is less than 70, what is the greatest possible value of Q minus R? Choose one
A) 63 B) 64 C) 65 D) 66 E) 67 | <gadget id="calculator">10 - 1</gadget>
<output>9</output>
<gadget id="calculator">70 % 9</gadget>
<output>7</output>
<gadget id="calculator">7 * 9</gadget>
<output>63</output>
<result>A</result> | A | 63 | Q and R are two-digit positive integers that have the same digits but in reverse order. If the positive difference between Q and R is less than 70, what is the greatest possible value of Q minus R? | {
"A": "63",
"B": "64",
"C": "65",
"D": "66",
"E": "67"
} | multiply(reminder(70, subtract(const_10, const_1)), subtract(const_10, const_1)) | subtract(const_10,const_1)|reminder(n0,#0)|multiply(#1,#0)| | "a two - digit integer ` ` ab ' ' can be expressed algebraically as 10 a + b . q - r = ( 10 a + b ) - ( 10 b + a ) = 9 ( a - b ) < 70 . the greatest multiple of 9 which is less than 70 is 63 . the answer is a ." | general |
math_qa__rHtOj4bhXzyXdOkZ | At a certain paint store forest green is made by mixing 4 parts blue paint with 3 parts yellow paint.Verdant green is made by mixing 4 parts yellow paint with 3 parts blue paint.How many liters of yellow paint must be added to 7 liters of forest green to change it to Verdant green? Select the correct option
A) 5 / 3 B) 2 / 7 C) 7 / 3 D) 1 / 7 E) 1 / 4 | <gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">(4/3) * 4</gadget>
<output>16/3 = around 5.333333</output>
<gadget id="calculator">(16/3) - 3</gadget>
<output>7/3 = around 2.333333</output>
<result>C</result> | C | 2.333333 | At a certain paint store forest green is made by mixing 4 parts blue paint with 3 parts yellow paint.Verdant green is made by mixing 4 parts yellow paint with 3 parts blue paint.How many liters of yellow paint must be added to 7 liters of forest green to change it to Verdant green? | {
"A": "5 / 3",
"B": "2 / 7",
"C": "7 / 3",
"D": "1 / 7",
"E": "1 / 4"
} | subtract(multiply(divide(4, 3), 4), 3) | divide(n0,n1)|multiply(n0,#0)|subtract(#1,n1) | 7 liter of forset green have 4 liter of blue and 3 liter of yellow suppose we add x liter of yellow to make it a verdant green so the ratio of blue to yellow in verdant green is ¾ so the equation is blue / yellow = 4 / ( 3 + x ) = ¾ 9 + 3 x = 16 = > x = 7 / 3 answer : c | general |
math_qa__v9d7mFisBe30fx6Y | What will be the difference between simple and compound interest @25% per annum on a sum of $3600 after 2 years?
Choose the correct choice:
A) $ 150 B) $ 220 C) $ 225 D) $ 182 E) $ 189 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 1</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) ** 2</gadget>
<output>25/16 = around 1.5625</output>
<gadget id="calculator">3_600 * (25/16)</gadget>
<output>5_625</output>
<gadget id="calculator">5_625 - 3_600</gadget>
<output>2_025</output>
<gadget id="calculator">3_600 * (1/4)</gadget>
<output>900</output>
<gadget id="calculator">900 * 2</gadget>
<output>1_800</output>
<gadget id="calculator">2_025 - 1_800</gadget>
<output>225</output>
<result>C</result> | C | 225 | What will be the difference between simple and compound interest @25% per annum on a sum of $3600 after 2 years? | {
"A": "$ 150",
"B": "$ 220",
"C": "$ 225",
"D": "$ 182",
"E": "$ 189"
} | subtract(subtract(multiply(3600, power(add(divide(25, const_100), const_1), 2)), 3600), multiply(multiply(3600, divide(25, const_100)), 2)) | divide(n0,const_100)|add(#0,const_1)|multiply(n1,#0)|multiply(n2,#2)|power(#1,n2)|multiply(n1,#4)|subtract(#5,n1)|subtract(#6,#3)| | "s . i . = 3600 * 25 * 2 / 100 = $ 1800 c . i . = 3600 * ( 1 + 25 / 100 ) ^ 2 - 3600 = $ 2025 difference = 2025 - 1800 = $ 225 answer is c" | gain |
math_qa__epSw5lrpkkBv5iFN | If 3 people can do 3 times of a particular work in 3 days, then how many days would it take 8 people to do 8 times of that particular work?
Choose the correct choice from the following choices: A) 1 B) 2 C) 3 D) 8 E) 11 | <gadget id="calculator">8 / 8</gadget>
<output>1</output>
<gadget id="calculator">3 * 1</gadget>
<output>3</output>
<result>C</result> | C | 3 | If 3 people can do 3 times of a particular work in 3 days, then how many days would it take 8 people to do 8 times of that particular work? | {
"A": "1",
"B": "2",
"C": "3",
"D": "8",
"E": "11"
} | multiply(3, divide(8, 8)) | divide(n3,n3)|multiply(n0,#0)| | "3 people can do the work one time in one day . 1 person can do 1 / 3 of the work in one day . 8 people can do 8 / 3 of the work in one day . 8 people can do 8 times the work in 3 days . the answer is c ." | physics |
math_qa__JY0QmUDTxAsR76oA | A is half good a work man as B and together they finish a job in 32 days. In how many days working alone B finish the job? Options:
A) 98 days
B) 21 days
C) 48 days
D) 18 days
E) 19 days | <gadget id="calculator">3 / 2</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">32 * (3/2)</gadget>
<output>48</output>
<result>C</result> | C | 48 | A is half good a work man as B and together they finish a job in 32 days. In how many days working alone B finish the job? | {
"A": "98 days",
"B": "21 days",
"C": "48 days",
"D": "18 days",
"E": "19 days"
} | multiply(32, divide(const_3, const_2)) | divide(const_3,const_2)|multiply(n0,#0)| | "wc = 1 : 2 2 x + x = 1 / 32 = > x = 1 / 96 2 x = 1 / 96 = > 48 days answer : c" | physics |
math_qa__zc1ZozQOzRFr275t | If the sides of a square are multiplied by 10, the area of the original square is how many times as large as the area of the resultant square?
Choose the correct choice from the following options: A) 1 % B) 10 % C) 100 % D) 500 % E) 1000 % | <gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">100 / 100</gadget>
<output>1</output>
<result>A</result> | A | 1 | If the sides of a square are multiplied by 10, the area of the original square is how many times as large as the area of the resultant square? | {
"A": "1 %",
"B": "10 %",
"C": "100 %",
"D": "500 %",
"E": "1000 %"
} | divide(multiply(10, 10), const_100) | multiply(n0,n0)|divide(#0,const_100) | let x be the original length of one side . then the original area is x ^ 2 . the new square has sides of length 10 x , so the area is 100 x ^ 2 . the area of the original square is 1 / 100 = 1 % times the area of the new square . the answer is a . | geometry |
math_qa__cpBiTmZgaMxOBr4Q | Machine T takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine T to make 40 widgets?
Choose the correct choice from the following answers: A) 5 B) 6 C) 8 D) 10 E) 12 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<result>E</result> | E | 12 | Machine T takes 2 more hours than machine B to make 20 widgets. If working together, the machines can make 25 widgets in 3 hours, how long will it take machine T to make 40 widgets? | {
"A": "5",
"B": "6",
"C": "8",
"D": "10",
"E": "12"
} | multiply(2, multiply(const_3, const_2)) | multiply(const_2,const_3)|multiply(n0,#0) | i approached this one by plugging in numbers . . . started with c . if 40 are made in 8 hours , then 20 are made in 4 hours . so time of t is 4 , and time of b is 2 . rate together : 20 / 4 + 20 / 2 = 5 + 10 = 15 . so in 1 hour , together make 15 widgets . in 3 hours = 45 . way too much . we can eliminate right away c , b , and a - because b and t reduces the time - the total # of widgets made will be even higher . now between d and e - > try only one . . if it does n ' t work , then the other one is the answer . i picked e : 12 h to make 40 widgets , and 6 hours to make 20 . this is the time of t . time of b = 4 hours . 20 / 6 + 20 / 4 = 10 / 3 + 20 / 4 find lcm of 3 and 4 = 12 . multiply first by 4 , and second by 3 : 40 + 60 / 12 = 100 / 12 divide by 4 : 25 / 3 so this is the rate given . e is the correct answer | physics |
math_qa__DsobLFU2M7UnAAn3 | Seller selling an apple for Rs.16, a Seller loses 1/6th of what it costs him. The CP of the apple is? Choose the correct choice from the following answers.
A) 10 B) 12 C) 17 D) 18 E) 20 | <gadget id="calculator">16 + 1</gadget>
<output>17</output>
<result>C</result> | C | 17 | Seller selling an apple for Rs.16, a Seller loses 1/6th of what it costs him. The CP of the apple is? | {
"A": "10",
"B": "12",
"C": "17",
"D": "18",
"E": "20"
} | add(16, 1) | add(n0,n1)| | "sp = 16 loss = cp 17 loss = cp − sp = cp − 16 ⇒ cp 17 = cp − 16 ⇒ 16 cp 17 = 16 ⇒ cp 17 = 1 ⇒ cp = 17 c" | general |
math_qa__oeN6ArSuxrswIBrc | What is the smallest number which when increased by 3 is divisible by 9, 70, 25 and 21? Choose the correct choice from the following answers.
A) 2927 B) 3147 C) 3387 D) 3567 E) 3797 | <gadget id="calculator">lcm(9, 70)</gadget>
<output>630</output>
<gadget id="calculator">lcm(25, 21)</gadget>
<output>525</output>
<gadget id="calculator">lcm(630, 525)</gadget>
<output>3_150</output>
<gadget id="calculator">3_150 + 3</gadget>
<output>3_153</output>
<result>B</result> | B | 3,147 | What is the smallest number which when increased by 3 is divisible by 9, 70, 25 and 21? | {
"A": "2927",
"B": "3147",
"C": "3387",
"D": "3567",
"E": "3797"
} | add(lcm(lcm(9, 70), lcm(25, 21)), 3) | lcm(n1,n2)|lcm(n3,n4)|lcm(#0,#1)|add(n0,#2)| | "when increased by 3 , the number must include at least 2 * 3 ^ 2 * 5 ^ 2 * 7 = 3150 the answer is b ." | general |
math_qa__e0V2tK3Zy68vOMl3 | Carmen made a sculpture from small pieces of wood. The sculpture is 2 feet 10 inches tall.Carmen places her sculpture on a base that is 8 inches tall. How tall are the sculpture andbase together? Select the correct option:
A) 3.1 feet B) 3.2 feet C) 3.3 feet D) 3.4 feet E) 3.5 feet | <gadget id="calculator">2 + 10</gadget>
<output>12</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">24 + 10</gadget>
<output>34</output>
<gadget id="calculator">34 + 8</gadget>
<output>42</output>
<gadget id="calculator">42 / 12</gadget>
<output>7/2 = around 3.5</output>
<result>E</result> | E | 3.5 | Carmen made a sculpture from small pieces of wood. The sculpture is 2 feet 10 inches tall.Carmen places her sculpture on a base that is 8 inches tall. How tall are the sculpture andbase together? | {
"A": "3.1 feet",
"B": "3.2 feet",
"C": "3.3 feet",
"D": "3.4 feet",
"E": "3.5 feet"
} | divide(add(add(multiply(add(2, 10), 2), 10), 8), add(2, 10)) | add(n0,n1)|multiply(n0,#0)|add(#1,n1)|add(n2,#2)|divide(#3,#0)| | "we know 1 feet = 12 inch then 2 feet = 24 inch 24 + 10 = 34 then 34 + 8 = 42 42 / 12 = 3.5 feet answer : e" | geometry |
math_qa__PN9wOHuTjc61MMpI | An employee whose hourly wage was increased by 25 percent decided to reduce the number of hours worked per week so that the employee's total weekly income would remain unchanged. By what percent should the number of hours worked be reduced? Choices:
A) 9
B) 13
C) 16
D) 20
E) 25 | <gadget id="calculator">25 + 100</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">100 / (5/4)</gadget>
<output>80</output>
<gadget id="calculator">100 - 80</gadget>
<output>20</output>
<result>D</result> | D | 20 | An employee whose hourly wage was increased by 25 percent decided to reduce the number of hours worked per week so that the employee's total weekly income would remain unchanged. By what percent should the number of hours worked be reduced? | {
"A": "9",
"B": "13",
"C": "16",
"D": "20",
"E": "25"
} | subtract(const_100, divide(const_100, divide(add(25, const_100), const_100))) | add(n0,const_100)|divide(#0,const_100)|divide(const_100,#1)|subtract(const_100,#2) | let original hourly wage be x and let the no of hours worked be y total wage will be = x * y after the increment the wage will be = 1.25 x now we need to find number of hours worked so that x * y = 1.25 x * z i . e z = 4 / 5 y % decrease = ( y - 4 / 5 y ) / y * 100 = 100 / 5 = 20 % . thus my answer is d | general |
math_qa__t8PYaJKXl3LHfKLA | 45 men working 8 hours per day dig 40 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day? Choose the correct option.
A) 10
B) 20
C) 30
D) 40
E) 50 | <gadget id="calculator">45 * 8</gadget>
<output>360</output>
<gadget id="calculator">360 / 40</gadget>
<output>9</output>
<gadget id="calculator">9 * 50</gadget>
<output>450</output>
<gadget id="calculator">450 / 6</gadget>
<output>75</output>
<gadget id="calculator">75 - 45</gadget>
<output>30</output>
<result>C</result> | C | 30 | 45 men working 8 hours per day dig 40 m deep. How many extra men should be put to dig to a depth of 50 m working 6 hours per day? | {
"A": "10",
"B": "20",
"C": "30",
"D": "40",
"E": "50"
} | subtract(divide(multiply(divide(multiply(45, 8), 40), 50), 6), 45) | multiply(n0,n1)|divide(#0,n2)|multiply(n3,#1)|divide(#2,n4)|subtract(#3,n0)| | "( 45 * 8 ) / 40 = ( x * 6 ) / 50 = > x = 75 75 – 45 = 30 answer : c" | physics |
math_qa__lE54nBvTWN6rtO2Y | there are 150 ' zeroes ' and 151 ' ones ' written on a black board . a step involves choosing 3 digits and replacing them with a single digit . if all the 3 digits are identical , they are replaced with the same digit . otherwise , the digit that appears twice replaces the 3 chosen digits . what is the minimum number of steps after which there will be no zero written on the blackboard ? Select: A) 11 B) 37 C) 36 D) 76 E) 33 | <gadget id="calculator">150 / 2</gadget>
<output>75</output>
<gadget id="calculator">75 + 1</gadget>
<output>76</output>
<result>D</result> | D | 76 | there are 150 ' zeroes ' and 151 ' ones ' written on a black board . a step involves choosing 3 digits and replacing them with a single digit . if all the 3 digits are identical , they are replaced with the same digit . otherwise , the digit that appears twice replaces the 3 chosen digits . what is the minimum number of steps after which there will be no zero written on the blackboard ? | {
"A": "11",
"B": "37",
"C": "36",
"D": "76",
"E": "33"
} | add(divide(150, const_2), const_1) | divide(n0,const_2)|add(#0,const_1) | if we strike out 3 zeros , we are in effect reducing two zeroes . so we need 74 steps to reduce 148 zeroes . there are 2 zeroes and 151 ones left now . the remaining zeroes can be reduced in 2 steps . hence the answer is 76 . answer : d | general |
math_qa__aq79onRPQ02yBboy | A and B complete a work in 9 days. A alone can do it in 18 days. If both together can do the work in how many days?
Choose the correct choice from the following options
A) 6 days B) 8 days C) 5 days D) 7 days E) 15 days | <gadget id="calculator">1 / 9</gadget>
<output>1/9 = around 0.111111</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">(1/9) + (1/18)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 / (1/6)</gadget>
<output>6</output>
<result>A</result> | A | 6 | A and B complete a work in 9 days. A alone can do it in 18 days. If both together can do the work in how many days? | {
"A": "6 days",
"B": "8 days",
"C": "5 days",
"D": "7 days",
"E": "15 days"
} | inverse(add(inverse(9), inverse(18))) | inverse(n0)|inverse(n1)|add(#0,#1)|inverse(#2)| | "1 / 9 + 1 / 18 = 1 / 6 6 / 1 = 6 days answer : a" | physics |
math_qa__stQjgZdA4Pyt3iSw | If an object travels 200 feet in 4 seconds, what is the object's approximate speed in miles per hour? (Note: 1 mile = 5280 feet) Select the correct option:
A) 36 B) 34 C) 356 D) 12 E) 45 | <gadget id="calculator">200 / 5_280</gadget>
<output>5/132 = around 0.037879</output>
<gadget id="calculator">1 / 3_600</gadget>
<output>1/3_600 = around 0.000278</output>
<gadget id="calculator">4 * (1/3_600)</gadget>
<output>1/900 = around 0.001111</output>
<gadget id="calculator">(5/132) / (1/900)</gadget>
<output>375/11 = around 34.090909</output>
<result>B</result> | B | 34 | If an object travels 200 feet in 4 seconds, what is the object's approximate speed in miles per hour? (Note: 1 mile = 5280 feet) | {
"A": "36",
"B": "34",
"C": "356",
"D": "12",
"E": "45"
} | divide(divide(200, 5280), multiply(4, divide(const_1, const_3600))) | divide(n0,n3)|divide(const_1,const_3600)|multiply(n1,#1)|divide(#0,#2) | 1 mile = 5280 feet = > 1 feet = 1 / 5280 miles if the object travels 200 feet in 4 sec then it travels 200 / 4 * 60 * 60 feet in 1 hour ( 1 hr = 60 min * 60 sec ) = 3600 * 50 feet in 1 hour = 180000 feet in 1 hr = 180000 / 5280 miles in 1 hour = 18000 / 528 miles / hr ~ 34 miles / hr answer - b | physics |
math_qa__Dnxv7ombR9o7BvpS | a hall is 15 m long and 12 m broad . if the sum of the areas of the floor and the ceiling is equal to the sum of the areas of 4 walls , the volume of the hall is :
Pick.
A) 3348 B) 3898 C) 1200 D) 2881 E) 7881 | <gadget id="calculator">15 * 12</gadget>
<output>180</output>
<gadget id="calculator">15 + 12</gadget>
<output>27</output>
<gadget id="calculator">180 / 27</gadget>
<output>20/3 = around 6.666667</output>
<gadget id="calculator">(20/3) * 180</gadget>
<output>1_200</output>
<result>C</result> | C | 1,200 | a hall is 15 m long and 12 m broad . if the sum of the areas of the floor and the ceiling is equal to the sum of the areas of 4 walls , the volume of the hall is : | {
"A": "3348",
"B": "3898",
"C": "1200",
"D": "2881",
"E": "7881"
} | multiply(divide(multiply(15, 12), add(15, 12)), multiply(15, 12)) | add(n0,n1)|multiply(n0,n1)|divide(#1,#0)|multiply(#2,#1) | answer : c ) 1200 | geometry |
math_qa__GaRSgcW7slBlEf0R | If the sides of a triangle are 30 cm, 28 cm and 12 cm, what is its area? Choose one
A) 120 cm 2 B) 112 cm 2 C) 776 cm 2 D) 666 cm 2 E) 168 cm 2 | <gadget id="calculator">28 * 12</gadget>
<output>336</output>
<gadget id="calculator">336 / 2</gadget>
<output>168</output>
<result>E</result> | E | 168 | If the sides of a triangle are 30 cm, 28 cm and 12 cm, what is its area? | {
"A": "120 cm 2",
"B": "112 cm 2",
"C": "776 cm 2",
"D": "666 cm 2",
"E": "168 cm 2"
} | divide(multiply(28, 12), const_2) | multiply(n1,n2)|divide(#0,const_2)| | "the triangle with sides 30 cm , 28 cm and 12 cm is right angled , where the hypotenuse is 30 cm . area of the triangle = 1 / 2 * 28 * 12 = 168 cm 2 answer : e" | geometry |
math_qa__hbBDYLNYlER3vWYS | The avg weight of A,B & C is 84 kg. If D joins the group, the avg weight of the group becomes 80 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 79 kg. What is the weight of A?
Choose the correct option
A) 45
B) 65
C) 75
D) 89
E) 90 | <gadget id="calculator">80 * 4</gadget>
<output>320</output>
<gadget id="calculator">79 * 4</gadget>
<output>316</output>
<gadget id="calculator">84 * 3</gadget>
<output>252</output>
<gadget id="calculator">320 - 252</gadget>
<output>68</output>
<gadget id="calculator">3 + 68</gadget>
<output>71</output>
<gadget id="calculator">316 - 71</gadget>
<output>245</output>
<gadget id="calculator">320 - 245</gadget>
<output>75</output>
<result>C</result> | C | 75 | The avg weight of A,B & C is 84 kg. If D joins the group, the avg weight of the group becomes 80 kg.If another man E who weights is 3 kg more than D Replaces A, Then the avgof B,C,D&E becomes 79 kg. What is the weight of A? | {
"A": "45",
"B": "65",
"C": "75",
"D": "89",
"E": "90"
} | subtract(multiply(80, const_4), subtract(multiply(79, const_4), add(3, subtract(multiply(80, const_4), multiply(84, 3))))) | multiply(n1,const_4)|multiply(n3,const_4)|multiply(n0,n2)|subtract(#0,#2)|add(n2,#3)|subtract(#1,#4)|subtract(#0,#5)| | "a + b + c = 3 * 84 = 252 a + b + c + d = 4 * 80 = 320 - - - - ( i ) so , d = 68 & e = 68 + 3 = 71 b + c + d + e = 79 * 4 = 316 - - - ( ii ) from eq . ( i ) & ( ii ) a - e = 320 – 316 = 4 a = e + 4 = 71 + 4 = 75 c" | general |
math_qa__8ueSrACmT3Tr1Oi7 | If the price of a certain computer increased 30 percent from d dollars to 377 dollars, then 2d = Select the correct option:
A) 540 B) 570 C) 619 D) 649 E) 580 | <gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">130 / 100</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">377 / (13/10)</gadget>
<output>290</output>
<gadget id="calculator">290 * 2</gadget>
<output>580</output>
<result>E</result> | E | 580 | If the price of a certain computer increased 30 percent from d dollars to 377 dollars, then 2d = | {
"A": "540",
"B": "570",
"C": "619",
"D": "649",
"E": "580"
} | multiply(divide(377, divide(add(const_100, 30), const_100)), 2) | add(n0,const_100)|divide(#0,const_100)|divide(n1,#1)|multiply(n2,#2)| | "before price increase price = d after 30 % price increase price = d + ( 30 / 100 ) * d = 1.3 d = 377 ( given ) i . e . d = 377 / 1.3 = $ 290 i . e . 2 d = 2 * 290 = 580 answer : option e" | general |
math_qa__hsBNlzcrGnnuVcHL | You have been given a physical balance and 7 weights of 52, 50, 48, 44, 45, 46, and 78 Kgs.. Keeping weights on one pan and object on the other, what is the maximum you can weigh less than 183 Kgs.?
Choose the correct answer: A) 178 B) 180 C) 181 D) 182 E) 183 | <gadget id="calculator">50 + 48</gadget>
<output>98</output>
<gadget id="calculator">98 + 44</gadget>
<output>142</output>
<gadget id="calculator">142 + 46</gadget>
<output>188</output>
<result>E</result> | E | 183 | You have been given a physical balance and 7 weights of 52, 50, 48, 44, 45, 46, and 78 Kgs.. Keeping weights on one pan and object on the other, what is the maximum you can weigh less than 183 Kgs.? | {
"A": "178",
"B": "180",
"C": "181",
"D": "182",
"E": "183"
} | add(add(add(50, 48), 44), 46) | add(n2,n3)|add(n4,#0)|add(n6,#1)| | "balance = 52 + 50 + 48 + 44 + 45 + 46 + 78 - 183 answer : e" | general |
math_qa__mBXdcE7QPQxqSVjo | On a sum of money, the S.I. for 2 years is $600, while the C.I. is $615, the rate of interest being the same in both the cases. The rate of interest is? Pick one:
A) 4 %
B) 5 %
C) 6 %
D) 7 %
E) 8 % | <gadget id="calculator">615 - 600</gadget>
<output>15</output>
<gadget id="calculator">100 * 15</gadget>
<output>1_500</output>
<gadget id="calculator">600 / 2</gadget>
<output>300</output>
<gadget id="calculator">1_500 / 300</gadget>
<output>5</output>
<result>B</result> | B | 5 | On a sum of money, the S.I. for 2 years is $600, while the C.I. is $615, the rate of interest being the same in both the cases. The rate of interest is? | {
"A": "4 %",
"B": "5 %",
"C": "6 %",
"D": "7 %",
"E": "8 %"
} | divide(multiply(const_100, subtract(615, 600)), divide(600, 2)) | divide(n1,n0)|subtract(n2,n1)|multiply(#1,const_100)|divide(#2,#0)| | "difference in c . i . and s . i for 2 years = $ 615 - $ 600 = $ 15 s . i for one year = $ 300 s . i . on $ 300 for 1 year = $ 15 rate = ( 100 * 15 ) / ( 300 ) = 5 % the answer is b ." | gain |
math_qa__RVGsMVRqPBfdumEX | A is a working partner and B is a sleeping partner in the business. A puts in Rs.2000 and B Rs.3000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is? Choose the correct choice from the following answers: A) 1978 B) 2707 C) 7728 D) 4416 E) 7291 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">9_600 * (9/10)</gadget>
<output>8_640</output>
<gadget id="calculator">2_000 + 3_000</gadget>
<output>5_000</output>
<gadget id="calculator">3_000 / 5_000</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">8_640 * (3/5)</gadget>
<output>5_184</output>
<gadget id="calculator">9_600 - 5_184</gadget>
<output>4_416</output>
<result>D</result> | D | 4,416 | A is a working partner and B is a sleeping partner in the business. A puts in Rs.2000 and B Rs.3000, A receives 10% of the profit for managing the business the rest being divided in proportion of their capitals. Out of a total profit of Rs.9600, money received by A is? | {
"A": "1978",
"B": "2707",
"C": "7728",
"D": "4416",
"E": "7291"
} | subtract(9600, multiply(multiply(9600, subtract(const_1, divide(10, const_100))), divide(3000, add(2000, 3000)))) | add(n0,n1)|divide(n2,const_100)|divide(n1,#0)|subtract(const_1,#1)|multiply(n3,#3)|multiply(#2,#4)|subtract(n3,#5)| | "2 : 3 = > 2 : 3 9600 * 10 / 100 = 960 9600 - 960 = 8640 8640 * 2 / 5 = 3456 + 960 = 4416 answer : d" | gain |
math_qa__r4UownEqPOYtiQeg | find the unknown term 8 , 86 , x , - 4 , - 12 Choose the correct choice from the following options:
A) 2
B) 4
C) 6
D) 8
E) 9 | <gadget id="calculator">12 / 4</gadget>
<output>3</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<result>A</result> | A | 2 | find the unknown term 8 , 86 , x , - 4 , - 12 | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "9"
} | subtract(divide(12, 4), const_1) | divide(n3,n2)|subtract(#0,const_1) | 8 , 86 , x , - 4 , - 12 i guess each differ in d range of 2 8 - 8 = 0 8 - 6 = 2 6 - 2 = 4 2 - 6 = - 4 - 4 - 8 = - 12 answer : a | general |
math_qa__Qtx3AmxcngwaOPG2 | If a train, travelling at a speed of 360 kmph, crosses a pole in 5 sec, then the length of train is? Choose the correct choice from the following answers
A) 381 m B) 112 m C) 500 m D) 125 m E) 433 m | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">360 * (5/18)</gadget>
<output>100</output>
<gadget id="calculator">100 * 5</gadget>
<output>500</output>
<result>C</result> | C | 500 | If a train, travelling at a speed of 360 kmph, crosses a pole in 5 sec, then the length of train is? | {
"A": "381 m",
"B": "112 m",
"C": "500 m",
"D": "125 m",
"E": "433 m"
} | multiply(multiply(360, const_0_2778), 5) | multiply(n0,const_0_2778)|multiply(n1,#0)| | "c c = 360 * 5 / 18 * 5 = 500 m" | physics |
math_qa__VkD6RJbe0POrcz2T | A certain company retirement plan has arule of 70provision that allows an employee to retire when the employee's age plus years of employment with the company total at least 70. In what year could a female employee hired in 1988 on her 32nd birthday first be eligible to retire under this provision? Pick one
A) 2003
B) 2004
C) 2005
D) 2006
E) 2007 | <gadget id="calculator">70 - 32</gadget>
<output>38</output>
<gadget id="calculator">38 / 2</gadget>
<output>19</output>
<gadget id="calculator">1_988 + 19</gadget>
<output>2_007</output>
<result>E</result> | E | 2,007 | A certain company retirement plan has arule of 70provision that allows an employee to retire when the employee's age plus years of employment with the company total at least 70. In what year could a female employee hired in 1988 on her 32nd birthday first be eligible to retire under this provision? | {
"A": "2003",
"B": "2004",
"C": "2005",
"D": "2006",
"E": "2007"
} | add(1988, divide(subtract(70, 32), const_2)) | subtract(n0,n3)|divide(#0,const_2)|add(n2,#1)| | "she must gain at least 70 points , now she has 32 and every year gives her two more points : one for age and one for additional year of employment , so 32 + 2 * ( # of years ) = 70 - - > ( # of years ) = 19 - - > 1988 + 19 = 2007 . answer : e ." | general |
math_qa__UN9JLhHIwUuA3y9w | A coin is tossed 3 times. What is the probability of getting exactly 2 heads?
Choices: A) 1 / 2 B) 1 / 4 C) 3 / 8 D) 5 / 8 E) 3 / 16 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) ** 2</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">binomial(3, 2)</gadget>
<output>3</output>
<gadget id="calculator">3 * (1/2)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(1/4) * (3/2)</gadget>
<output>3/8 = around 0.375</output>
<result>C</result> | C | 0.375 | A coin is tossed 3 times. What is the probability of getting exactly 2 heads? | {
"A": "1 / 2",
"B": "1 / 4",
"C": "3 / 8",
"D": "5 / 8",
"E": "3 / 16"
} | multiply(power(divide(const_1, const_2), 2), multiply(choose(3, 2), divide(const_1, const_2))) | choose(n0,n1)|divide(const_1,const_2)|multiply(#0,#1)|power(#1,n1)|multiply(#2,#3)| | "the number of possible outcomes is 2 ^ 3 = 8 there are 3 ways to get exactly 2 heads . p ( exactly 2 heads ) = 3 / 8 the answer is c ." | probability |
math_qa__BEHY1GcRMm6f2tNn | A certain protective additive increases from 45 days to 60 days the time between required maintenance checks on an industrial vehicle. By what percent is the time between maintenance checks increased by using the additive?
Choose the most appropriate option: A) 25 % B) 33 1 / 3 % C) 50 % D) 66 2 / 3 % E) 75 % | <gadget id="calculator">60 - 45</gadget>
<output>15</output>
<gadget id="calculator">15 / 45</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(1/3) * 100</gadget>
<output>100/3 = around 33.333333</output>
<result>B</result> | B | 33 | A certain protective additive increases from 45 days to 60 days the time between required maintenance checks on an industrial vehicle. By what percent is the time between maintenance checks increased by using the additive? | {
"A": "25 %",
"B": "33 1 / 3 %",
"C": "50 %",
"D": "66 2 / 3 %",
"E": "75 %"
} | multiply(divide(subtract(60, 45), 45), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100)| | "general formula for percent increase or decrease , ( percent change ) : percent = change / original ∗ 100 so , the time between maintenance checks increased by 60 − 45 / 45 ∗ 100 = 33 1 / 3 answer : b ." | general |
math_qa__UIYLVAChEKkX5AFo | A can run 4.5 km distance in 1 min 30 seconds, while B can run this distance in 3 min. By how much distance can A beat B?
Choose the correct choice from the following answers.
A) 2250 m B) 1000 m C) 1250 m D) 1800 m E) 2000 m | <gadget id="calculator">1 * 60</gadget>
<output>60</output>
<gadget id="calculator">60 + 30</gadget>
<output>90</output>
<gadget id="calculator">4.5 * 1_000</gadget>
<output>4_500</output>
<gadget id="calculator">3 * 60</gadget>
<output>180</output>
<gadget id="calculator">4_500 / 180</gadget>
<output>25</output>
<gadget id="calculator">90 * 25</gadget>
<output>2_250</output>
<result>A</result> | A | 2,250 | A can run 4.5 km distance in 1 min 30 seconds, while B can run this distance in 3 min. By how much distance can A beat B? | {
"A": "2250 m",
"B": "1000 m",
"C": "1250 m",
"D": "1800 m",
"E": "2000 m"
} | multiply(add(multiply(1, const_60), 30), divide(multiply(4.5, const_1000), multiply(3, const_60))) | multiply(n1,const_60)|multiply(n0,const_1000)|multiply(n3,const_60)|add(n2,#0)|divide(#1,#2)|multiply(#3,#4) | a takes time 1.30 minutes = 90 sec b takes time 3 minutes = 180 sec diffrence = 180 - 90 = 90 sec now we are to find distance covered in 90 sec by b 180 sec = 4500 m 1 sec = 25 m 90 sec = 25 x 90 = 2250 m answer : a | physics |
math_qa__gt2OtPgm6keKLjGR | A student got 74% in math and 84% in history. To get an overall average of 75%, how much should the student get in the third subject?
Answers.
A) 61 % B) 63 % C) 65 % D) 67 % E) 69 % | <gadget id="calculator">3 * 75</gadget>
<output>225</output>
<gadget id="calculator">74 + 84</gadget>
<output>158</output>
<gadget id="calculator">225 - 158</gadget>
<output>67</output>
<result>D</result> | D | 67 | A student got 74% in math and 84% in history. To get an overall average of 75%, how much should the student get in the third subject? | {
"A": "61 %",
"B": "63 %",
"C": "65 %",
"D": "67 %",
"E": "69 %"
} | subtract(multiply(const_3, 75), add(74, 84)) | add(n0,n1)|multiply(n2,const_3)|subtract(#1,#0) | 74 + 84 + x = 3 * 75 x = 67 the answer is d . | general |
math_qa__WbtJjZJ3aaxhGLBC | The width of a rectangular hall is ½ of its length. If the area of the hall is 128 sq.m, what is the difference between its length and breadth? Options
A) 8 m
B) 10 m
C) 12 m
D) 15 m
E) 17 m | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">128 / (1/2)</gadget>
<output>256</output>
<gadget id="calculator">256 ** (1/2)</gadget>
<output>16</output>
<gadget id="calculator">16 / 2</gadget>
<output>8</output>
<result>A</result> | A | 8 | The width of a rectangular hall is ½ of its length. If the area of the hall is 128 sq.m, what is the difference between its length and breadth? | {
"A": "8 m",
"B": "10 m",
"C": "12 m",
"D": "15 m",
"E": "17 m"
} | divide(sqrt(divide(128, divide(const_1, const_2))), const_2) | divide(const_1,const_2)|divide(n0,#0)|sqrt(#1)|divide(#2,const_2)| | "let the length of the hall be x m breadth of the hall = 1 x / 2 m area of the hall = length * breadth 128 = x * 1 x / 2 x ² = 256 x = 16 difference between the length and breadth of the hall = x - 1 x / 2 = x / 2 = 16 / 2 = 8 m answer : a" | geometry |
math_qa__RIGqxTxqF9PiHaZN | A train 200 m long running at 80 kmph crosses a platform in 22 sec. What is the length of the platform? Choices: A) 338 B) 277 C) 350 D) 288 E) 271 | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">80 * (5/18)</gadget>
<output>200/9 = around 22.222222</output>
<gadget id="calculator">22 * (200/9)</gadget>
<output>4_400/9 = around 488.888889</output>
<gadget id="calculator">(4_400/9) - 200</gadget>
<output>2_600/9 = around 288.888889</output>
<result>D</result> | D | 288 | A train 200 m long running at 80 kmph crosses a platform in 22 sec. What is the length of the platform? | {
"A": "338",
"B": "277",
"C": "350",
"D": "288",
"E": "271"
} | subtract(multiply(22, multiply(80, const_0_2778)), 200) | multiply(n1,const_0_2778)|multiply(n2,#0)|subtract(#1,n0)| | "d = 80 * 5 / 18 = 22 = 488 – 200 = 288 answer : d" | physics |
math_qa__USvtJtU1ckkKpAIP | A fruit seller sells mangoes at the rate of Rs.9 per kg and thereby loses 20%. At what price per kg, he should have sold them to make a profit of 5%? Choose the correct choice from the following answers:
A) rs . 11.81 B) rs . 12 C) rs . 12.25 D) rs . 12.31 E) none | <gadget id="calculator">100 + 5</gadget>
<output>105</output>
<gadget id="calculator">9 * 105</gadget>
<output>945</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">945 / 80</gadget>
<output>189/16 = around 11.8125</output>
<result>A</result> | A | 11.81 | A fruit seller sells mangoes at the rate of Rs.9 per kg and thereby loses 20%. At what price per kg, he should have sold them to make a profit of 5%? | {
"A": "rs . 11.81",
"B": "rs . 12",
"C": "rs . 12.25",
"D": "rs . 12.31",
"E": "none"
} | divide(multiply(9, add(const_100, 5)), subtract(const_100, 20)) | add(n2,const_100)|subtract(const_100,n1)|multiply(n0,#0)|divide(#2,#1)| | "solution 85 : 9 = 105 : x x = ( 9 × 105 / 80 ) = rs . 11.81 hence , s . p per kg = rs . 11.81 answer a" | gain |
math_qa__XLL2E5vzsSasil7n | If the simple interest on a certain sum of money for 8 years is one–fifth of the sum, then the rate of interest per annum is Options: A) 4.1 % B) 7 % C) 2.5 % D) 2.8 % E) 3 % | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">20 / 8</gadget>
<output>5/2 = around 2.5</output>
<result>C</result> | C | 2.5 | If the simple interest on a certain sum of money for 8 years is one–fifth of the sum, then the rate of interest per annum is | {
"A": "4.1 %",
"B": "7 %",
"C": "2.5 %",
"D": "2.8 %",
"E": "3 %"
} | divide(divide(const_100, add(const_1, const_4)), 8) | add(const_1,const_4)|divide(const_100,#0)|divide(#1,n0) | explanation : let the principal ( p ) be x then , simple interest ( si ) = x / 5 time ( t ) = 8 years rate of interest per annum ( r ) = ( 100 × si ) / pt = ( 100 × ( x / 5 ) / ( x × 8 ) = 20 / 8 = 2.5 % answer : option c | gain |
math_qa__2l1Fhd5EI3nAOX6E | The captain of a cricket team of 11 members is 24 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team? Choose one:
A) 20 years
B) 21 years
C) 22 years
D) 23 years
E) 24 years | <gadget id="calculator">24 + 3</gadget>
<output>27</output>
<gadget id="calculator">24 + 27</gadget>
<output>51</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">51 - 9</gadget>
<output>42</output>
<gadget id="calculator">42 / 2</gadget>
<output>21</output>
<result>B</result> | B | 21 | The captain of a cricket team of 11 members is 24 years old and the wicket keeper is 3 years older. If the ages of these two are excluded, the average age of the remaining players is one year less than the average age of the whole team. What is the average age of the team? | {
"A": "20 years",
"B": "21 years",
"C": "22 years",
"D": "23 years",
"E": "24 years"
} | divide(subtract(add(24, add(24, 3)), multiply(3, 3)), const_2) | add(n1,n2)|multiply(n2,n2)|add(n1,#0)|subtract(#2,#1)|divide(#3,const_2)| | "explanation : let the average age of the whole team by x years . 11 x â € “ ( 24 + 27 ) = 9 ( x - 1 ) 11 x â € “ 9 x = 42 2 x = 42 x = 21 . so , average age of the team is 21 years . answer b" | general |
math_qa__QTYsZdA8a7rDJPQf | According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 28, by how much does the temperature in degrees Celsius (C) increase?
Choose one
A) 9 B) 15.55 C) 47 D) 48 3 / 5 E) 59 | <gadget id="calculator">28 * 5</gadget>
<output>140</output>
<gadget id="calculator">140 / 9</gadget>
<output>140/9 = around 15.555556</output>
<result>B</result> | B | 15.55 | According to the formula F=9/5 (C) +32, if the temperature in degrees Farenheit (F) increases by 28, by how much does the temperature in degrees Celsius (C) increase? | {
"A": "9",
"B": "15.55",
"C": "47",
"D": "48 3 / 5",
"E": "59"
} | divide(multiply(28, 5), 9) | multiply(n1,n3)|divide(#0,n0) | you can plug in values . c = 5 / 9 * ( f - 32 ) f = 32 - - > c = 0 ; f = 32 + 28 = 60 - - > c = 5 / 9 * 28 = 15.55 . increase = 15.55 degrees . answer : b . | general |
math_qa__a1HffHu0pFGQuCrX | Without stoppages, a train travels certain distance with an average speed of 250 km/h, and with stoppages, it covers the same distance with an average speed of 125 km/h. How many minutes per hour the train stops ? Choose the correct choice from the following
A) 25 B) 30 C) 35 D) 40 E) 45 | <gadget id="calculator">125 / 250</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 60</gadget>
<output>30</output>
<gadget id="calculator">60 - 30</gadget>
<output>30</output>
<result>B</result> | B | 30 | Without stoppages, a train travels certain distance with an average speed of 250 km/h, and with stoppages, it covers the same distance with an average speed of 125 km/h. How many minutes per hour the train stops ? | {
"A": "25",
"B": "30",
"C": "35",
"D": "40",
"E": "45"
} | subtract(const_60, multiply(divide(125, 250), const_60)) | divide(n1,n0)|multiply(#0,const_60)|subtract(const_60,#1)| | "due to stoppages , it covers 125 km less . time taken to cover 125 km = 125 â „ 250 h = 1 â „ 2 h = 1 â „ 2 ã — 60 min = 30 min answer b" | physics |
math_qa__cjljMKKvqlsssH6g | Cara took out a charge account at the General Store and agreed to pay 5% simple annual interest. If she charges $54 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments? Choose one.
A) $ 55.70 B) $ 56.20 C) $ 56.70 D) $ 57.20 E) $ 57.70 | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) * 54</gadget>
<output>567/10 = around 56.7</output>
<result>C</result> | C | 56.7 | Cara took out a charge account at the General Store and agreed to pay 5% simple annual interest. If she charges $54 on her account in January, how much will she owe a year later, assuming she does not make any additional charges or payments? | {
"A": "$ 55.70",
"B": "$ 56.20",
"C": "$ 56.70",
"D": "$ 57.20",
"E": "$ 57.70"
} | multiply(add(const_1, divide(5, const_100)), 54) | divide(n0,const_100)|add(#0,const_1)|multiply(n1,#1) | 1.05 * $ 54 = $ 56.70 the answer is c . | general |
math_qa__GS0vkNaKAw2oHrQ6 | A can contains a mixture of liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter T of liquid A was contained by the can initially? Choose the correct choice from the following choices
A) 10 B) 20 C) 21 D) 25 E) 27 | <gadget id="calculator">7 + 9</gadget>
<output>16</output>
<gadget id="calculator">7 + 5</gadget>
<output>12</output>
<gadget id="calculator">5 / 12</gadget>
<output>5/12 = around 0.416667</output>
<gadget id="calculator">(5/12) * 9</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">9 - (15/4)</gadget>
<output>21/4 = around 5.25</output>
<gadget id="calculator">16 * (21/4)</gadget>
<output>84</output>
<gadget id="calculator">9 * 7</gadget>
<output>63</output>
<gadget id="calculator">7 * 5</gadget>
<output>35</output>
<gadget id="calculator">63 - 35</gadget>
<output>28</output>
<gadget id="calculator">84 / 28</gadget>
<output>3</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<result>C</result> | C | 21 | A can contains a mixture of liquids A and B is the ratio 7:5. When 9 litres of mixture are drawn off and the can is filled with B, the ratio of A and B becomes 7:9. How many liter T of liquid A was contained by the can initially? | {
"A": "10",
"B": "20",
"C": "21",
"D": "25",
"E": "27"
} | multiply(7, divide(multiply(add(7, 9), subtract(9, multiply(divide(5, add(7, 5)), 9))), subtract(multiply(9, 7), multiply(7, 5)))) | add(n0,n2)|add(n0,n1)|multiply(n0,n2)|multiply(n0,n1)|divide(n1,#1)|subtract(#2,#3)|multiply(n2,#4)|subtract(n2,#6)|multiply(#0,#7)|divide(#8,#5)|multiply(n0,#9)| | "as a : b : : 7 : 5 - - - > only option c is a multiple of 7 and hence it is a good place to start . also a : b : : 7 : 5 means that , a = ( 712 ) * total and b = ( 5 / 12 ) * total if a = 21 , b = 15 - - - > remove 9 litres - - - > you remove ( 7 / 12 ) * 9 of a - - - > a remaining = 21 - ( 7 / 12 ) * 9 = 63 / 4 similarly , for b , you remove ( 5 / 12 ) * 9 - - - > b remaining = 15 - ( 5 / 12 ) * 9 = 45 / 4 and then add 9 more litres of b - - - > 9 + 45 / 4 = 81 / 4 thus a / b ( final ratio ) = ( 45 / 4 ) / ( 81 / 4 ) = 7 : 9 , the same as the final ratio mentioned in the question . hence c is the correct answer . a / b = 7 / 9 = ( 7 x - ( 7 / 12 ) * 9 ) / ( 5 x - ( 5 / 12 ) * 9 + 9 ) , where 7 x and 5 x are initial quantities of a and b respectively . thus , 7 / 9 = ( 7 x - ( 7 / 12 ) * 9 ) / ( 5 x - ( 5 / 12 ) * 9 + 9 ) - - - > giving you x = 3 . thus a ( original ) t = 7 * 3 = 21 . c" | other |
math_qa__zyhed0kehGJL48Eh | The length of a rectangle is double its width. If the length is diminished by 5cm and the width is increased by 5cm then its area is increased by 75cm square. What is the length of the rectangle? Select:
A) 20 B) 30 C) 40 D) 56 E) 65 | <gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">25 + 75</gadget>
<output>100</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">2 * 20</gadget>
<output>40</output>
<result>C</result> | C | 40 | The length of a rectangle is double its width. If the length is diminished by 5cm and the width is increased by 5cm then its area is increased by 75cm square. What is the length of the rectangle? | {
"A": "20",
"B": "30",
"C": "40",
"D": "56",
"E": "65"
} | multiply(const_2, divide(add(multiply(5, 5), 75), 5)) | multiply(n0,n0)|add(n2,#0)|divide(#1,n0)|multiply(#2,const_2) | sol . according to question ( l - 5 ) ( b + 5 ) - lb = 75 and l = 2 b so , b = 20 , l = 40 ans . ( c ) | geometry |
math_qa__VDjcDZ1pCUgJHUHO | A and B go around a circular track of length 1500 m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point? Choose the most appropriate option
A) 120 sec B) 165 sec C) 300 sec D) 167 sec E) 168 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">54 * (5/18)</gadget>
<output>15</output>
<gadget id="calculator">36 * (5/18)</gadget>
<output>10</output>
<gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">1_500 / 5</gadget>
<output>300</output>
<result>C</result> | C | 300 | A and B go around a circular track of length 1500 m on a cycle at speeds of 36 kmph and 54 kmph. After how much time will they meet for the first time at the starting point? | {
"A": "120 sec",
"B": "165 sec",
"C": "300 sec",
"D": "167 sec",
"E": "168 sec"
} | divide(1500, subtract(multiply(54, const_0_2778), multiply(36, const_0_2778))) | multiply(n2,const_0_2778)|multiply(n1,const_0_2778)|subtract(#0,#1)|divide(n0,#2)| | "time taken to meet for the first time at the starting point = lcm { length of the track / speed of a , length of the track / speed of b } = lcm { 1500 / ( 36 * 5 / 18 ) , 1500 / ( 54 * 5 / 18 ) } = lcm ( 150 , 100 ) = 300 sec . answer : c" | physics |
math_qa__oANxwuRPiHCrDAYu | A train 300m long takes 9 sec to cross a man walking at 3kmph in a direction opposite to that of the train. Find the speed of the train? Choose the most appropriate option.
A) 100 kmph B) 90 kmph C) 120 kmph D) 117 kmph E) 125 kmph | <gadget id="calculator">300 / 9</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(100/3) / (5/18)</gadget>
<output>120</output>
<gadget id="calculator">120 - 3</gadget>
<output>117</output>
<result>D</result> | D | 117 | A train 300m long takes 9 sec to cross a man walking at 3kmph in a direction opposite to that of the train. Find the speed of the train? | {
"A": "100 kmph",
"B": "90 kmph",
"C": "120 kmph",
"D": "117 kmph",
"E": "125 kmph"
} | subtract(divide(divide(300, 9), const_0_2778), 3) | divide(n0,n1)|divide(#0,const_0_2778)|subtract(#1,n2)| | "let the speed of the train be x kmph speed of the train relative to man = x + 3 = ( x + 3 ) * 5 / 18 m / sec 300 / [ ( x + 3 ) * 5 / 18 ] = 9 9 ( x + 3 ) = 1080 x = 117 kmph answer is d" | physics |
math_qa__CXNjb8MYnsLRLisc | The perimeters of 2 squares are 40cm and 32cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares? Choose one
A) 20 cm
B) 24 cm
C) 32 cm
D) 28 cm
E) 30 cm | <gadget id="calculator">40 / 4</gadget>
<output>10</output>
<gadget id="calculator">10 ** 2</gadget>
<output>100</output>
<gadget id="calculator">32 / 4</gadget>
<output>8</output>
<gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">100 - 64</gadget>
<output>36</output>
<gadget id="calculator">36 ** (1/2)</gadget>
<output>6</output>
<gadget id="calculator">4 * 6</gadget>
<output>24</output>
<result>B</result> | B | 24 | The perimeters of 2 squares are 40cm and 32cm. Find the perimeter of a third square whose area is equal to the difference of the areas of the two squares? | {
"A": "20 cm",
"B": "24 cm",
"C": "32 cm",
"D": "28 cm",
"E": "30 cm"
} | square_perimeter(sqrt(subtract(square_area(divide(40, const_4)), square_area(divide(32, const_4))))) | divide(n1,const_4)|divide(n2,const_4)|square_area(#0)|square_area(#1)|subtract(#2,#3)|sqrt(#4)|square_perimeter(#5)| | "side of the 1 st square = 40 / 4 = 10 cm side of the 2 nd square = 32 / 4 = 8 cm area of the 3 rd square = 10 ^ 2 - 8 ^ 2 = 36 cm ^ 2 side of the 3 rd square = 6 cm required perimeter = 6 * 4 = 24 cm answer is b" | geometry |
math_qa__MJctxx8gEEeDlPzr | If there are 210 workers in a factory, and on a certain day, 198 were present. Calculate the percentage that showed up for work? (round to the nearest tenth).
Choose the correct option.
A) 94.3 % B) 95.3 % C) 93.3 % D) 92.3 % E) 91.3 % | <gadget id="calculator">198 / 210</gadget>
<output>33/35 = around 0.942857</output>
<gadget id="calculator">(33/35) * 100</gadget>
<output>660/7 = around 94.285714</output>
<result>A</result> | A | 94.3 | If there are 210 workers in a factory, and on a certain day, 198 were present. Calculate the percentage that showed up for work? (round to the nearest tenth). | {
"A": "94.3 %",
"B": "95.3 %",
"C": "93.3 %",
"D": "92.3 %",
"E": "91.3 %"
} | multiply(divide(198, 210), const_100) | divide(n1,n0)|multiply(#0,const_100) | 198 / 210 * 100 = 94.28 94.3 % correct answer a | physics |
math_qa__EUXjiMgzoHUIGSnl | A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 210 kilometers? Choose the correct choice
A) 8.25 gallons B) 7.5 gallons C) 6.55 gallons D) 5.25 gallons E) 4.5 gallons | <gadget id="calculator">210 / 40</gadget>
<output>21/4 = around 5.25</output>
<result>D</result> | D | 5.25 | A car gets 40 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 210 kilometers? | {
"A": "8.25 gallons",
"B": "7.5 gallons",
"C": "6.55 gallons",
"D": "5.25 gallons",
"E": "4.5 gallons"
} | divide(210, 40) | divide(n1,n0)| | "each 40 kilometers , 1 gallon is needed . we need to know how many 40 kilometers are there in 210 kilometers ? 210 / 40 = 5.25 * 1 gallon = 5.25 gallons correct answer d" | physics |
math_qa__F58XK16vQjry5za8 | On a certain farm the ratio of horses to cows is 4:1. If the farm were to sell 15 horses and buy 15 cows, the ratio of horses to cows would then be 7:3. After the transaction, how many more horses than cows would the farm own? Choose the correct option
A) 20 B) 40 C) 50 D) 60 E) 80 | <gadget id="calculator">15 * 7</gadget>
<output>105</output>
<gadget id="calculator">15 * 3</gadget>
<output>45</output>
<gadget id="calculator">105 + 45</gadget>
<output>150</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 - 7</gadget>
<output>5</output>
<gadget id="calculator">150 / 5</gadget>
<output>30</output>
<gadget id="calculator">4 * 30</gadget>
<output>120</output>
<gadget id="calculator">120 - 15</gadget>
<output>105</output>
<gadget id="calculator">30 + 15</gadget>
<output>45</output>
<gadget id="calculator">105 - 45</gadget>
<output>60</output>
<result>D</result> | D | 60 | On a certain farm the ratio of horses to cows is 4:1. If the farm were to sell 15 horses and buy 15 cows, the ratio of horses to cows would then be 7:3. After the transaction, how many more horses than cows would the farm own? | {
"A": "20",
"B": "40",
"C": "50",
"D": "60",
"E": "80"
} | subtract(subtract(multiply(4, divide(add(multiply(15, 7), multiply(15, 3)), subtract(multiply(4, 3), 7))), 15), add(divide(add(multiply(15, 7), multiply(15, 3)), subtract(multiply(4, 3), 7)), 15)) | multiply(n2,n4)|multiply(n2,n5)|multiply(n0,n5)|add(#0,#1)|subtract(#2,n4)|divide(#3,#4)|add(n2,#5)|multiply(n0,#5)|subtract(#7,n2)|subtract(#8,#6)| | "originally , there were 4 k horses and k cows . 3 ( 4 k - 15 ) = 7 ( k + 15 ) 12 k - 7 k = 105 + 45 5 k = 150 k = 30 the difference between horses and cows is ( 4 k - 15 ) - ( k + 15 ) = 3 k - 30 = 60 the answer is d ." | other |
math_qa__fbcehNB8xX3D7FuG | Rani bought more apples than oranges. She sells apples at ₹23 apiece and makes 15% profit. She sells oranges at ₹10 apiece and makes 25% profit. If she gets ₹653 after selling all the apples and oranges, find her profit percentage Q. Choices:
A) 16.8 %
B) 17.4 %
C) 17.9 %
D) 18.5 %
E) 19.1 % | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">20 * 21</gadget>
<output>420</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 1</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">10 / (5/4)</gadget>
<output>8</output>
<gadget id="calculator">15 + 2</gadget>
<output>17</output>
<gadget id="calculator">8 * 17</gadget>
<output>136</output>
<gadget id="calculator">420 + 136</gadget>
<output>556</output>
<gadget id="calculator">653 - 556</gadget>
<output>97</output>
<gadget id="calculator">97 / 556</gadget>
<output>97/556 = around 0.17446</output>
<gadget id="calculator">(97/556) * 100</gadget>
<output>2_425/139 = around 17.446043</output>
<result>B</result> | B | 17.4 | Rani bought more apples than oranges. She sells apples at ₹23 apiece and makes 15% profit. She sells oranges at ₹10 apiece and makes 25% profit. If she gets ₹653 after selling all the apples and oranges, find her profit percentage Q. | {
"A": "16.8 %",
"B": "17.4 %",
"C": "17.9 %",
"D": "18.5 %",
"E": "19.1 %"
} | multiply(divide(subtract(653, add(multiply(multiply(const_2, 10), add(multiply(const_2, 10), const_1)), multiply(divide(10, add(divide(25, const_100), const_1)), add(15, const_2)))), add(multiply(multiply(const_2, 10), add(multiply(const_2, 10), const_1)), multiply(divide(10, add(divide(25, const_100), const_1)), add(15, const_2)))), const_100) | add(n1,const_2)|divide(n3,const_100)|multiply(n2,const_2)|add(#2,const_1)|add(#1,const_1)|divide(n2,#4)|multiply(#3,#2)|multiply(#0,#5)|add(#6,#7)|subtract(n4,#8)|divide(#9,#8)|multiply(#10,const_100) | given : selling price of an apple = 23 - - > cost price = 23 / 1.15 = 20 selling price of an orange = 10 - - > cost price = 10 / 1.25 = 8 a > o 23 * ( a ) + 10 * ( o ) = 653 653 - 23 * ( a ) has to be divisible by 10 - - > units digit has to be 0 values of a can be 1 , 11 , 21 , 31 , . . . . - - > 1 can not be the value between 11 and 21 , if a = 11 , o = 30 - - > not possible if a = 21 , o = 17 - - > possible cost price = 20 * 21 + 8 * 17 = 420 + 136 = 556 profit = 653 - 556 = 97 profit % q = ( 97 / 556 ) * 100 = 17.4 % answer : b | gain |
math_qa__fgiPyKwLZZ3rnTij | The sale price of a trolley bag including the sale tax is Rs. 420. The rate of sale tax is 12% . If the shopkeeper has made a profit of 25%, the cost price of the trolley bag is: Choose the correct choice from the following answers.
A) rs 625 B) rs 300 C) rs 350 D) rs 375 E) none of these | <gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">420 * (3/25)</gadget>
<output>252/5 = around 50.4</output>
<gadget id="calculator">420 - (252/5)</gadget>
<output>1_848/5 = around 369.6</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 1</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(1_848/5) / (5/4)</gadget>
<output>7_392/25 = around 295.68</output>
<result>B</result> | B | 300 | The sale price of a trolley bag including the sale tax is Rs. 420. The rate of sale tax is 12% . If the shopkeeper has made a profit of 25%, the cost price of the trolley bag is: | {
"A": "rs 625",
"B": "rs 300",
"C": "rs 350",
"D": "rs 375",
"E": "none of these"
} | divide(subtract(420, multiply(420, divide(12, const_100))), add(divide(25, const_100), const_1)) | divide(n1,const_100)|divide(n2,const_100)|add(#1,const_1)|multiply(n0,#0)|subtract(n0,#3)|divide(#4,#2) | explanation : 112 % of s . p . = 420 s . p . = rs . ( 420 x 100 / 112 ) = rs . 375 . c . p . = rs ( 100 / 125 x 375 ) = rs 300 answer : b | gain |
math_qa__KtPvZT3J94DPsNAy | How many bricks each measuring 20cm x 13.25cm x 8cm, will be needed to build a wall 7m x 8m x 15.5m Answers.
A) 5600 B) 4600 C) 4094 D) 7200 E) none of these | <gadget id="calculator">7 * 8</gadget>
<output>56</output>
<gadget id="calculator">56 * 15.5</gadget>
<output>868</output>
<gadget id="calculator">20 * 13.25</gadget>
<output>265</output>
<gadget id="calculator">265 * 8</gadget>
<output>2_120</output>
<gadget id="calculator">2_120 / 100</gadget>
<output>106/5 = around 21.2</output>
<gadget id="calculator">(106/5) / 100</gadget>
<output>53/250 = around 0.212</output>
<gadget id="calculator">868 / (53/250)</gadget>
<output>217_000/53 = around 4_094.339623</output>
<result>C</result> | C | 4,094 | How many bricks each measuring 20cm x 13.25cm x 8cm, will be needed to build a wall 7m x 8m x 15.5m | {
"A": "5600",
"B": "4600",
"C": "4094",
"D": "7200",
"E": "none of these"
} | divide(multiply(multiply(7, 8), 15.5), divide(divide(multiply(multiply(20, 13.25), 8), const_100), const_100)) | multiply(n3,n4)|multiply(n0,n1)|multiply(n5,#0)|multiply(n2,#1)|divide(#3,const_100)|divide(#4,const_100)|divide(#2,#5)| | "explanation : no . of bricks = volume of the wall / volume of 1 brick = ( 700 x 800 x 15.5 ) / ( 20 x 13.25 x 8 ) = 4094 answer : c" | physics |
math_qa__8jXYMiFPvWeNomVi | One-tenth of the students at a nursery school are 4 years old or older. If 20 students have not yet reached their third birthday, and a total of 50 students are not between 3 years old and 4 years old, how many children are in the nursery school? Choose the correct choice from the following answers:
A) 150
B) 300
C) 450
D) 490
E) 620 | <gadget id="calculator">50 - 20</gadget>
<output>30</output>
<gadget id="calculator">30 * 10</gadget>
<output>300</output>
<result>B</result> | B | 300 | One-tenth of the students at a nursery school are 4 years old or older. If 20 students have not yet reached their third birthday, and a total of 50 students are not between 3 years old and 4 years old, how many children are in the nursery school? | {
"A": "150",
"B": "300",
"C": "450",
"D": "490",
"E": "620"
} | multiply(subtract(50, 20), const_10) | subtract(n2,n1)|multiply(#0,const_10) | x / 10 students are > 4 yrs 20 students are < 3 yrs x / 10 + 20 = 50 x / 10 = 30 x = 300 answer : b | general |
math_qa__cndxploBl17i6E5d | if p/q=3/4
then3p+4q=? Choose the correct choice from the following
A) 25 / 4 B) 25 / 2 C) 20 / 4 D) 35 / 4 E) 25 / 3 | <gadget id="calculator">4 / 3</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">3 * (4/3)</gadget>
<output>4</output>
<gadget id="calculator">4 * 4</gadget>
<output>16</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">16 + 9</gadget>
<output>25</output>
<gadget id="calculator">25 / 4</gadget>
<output>25/4 = around 6.25</output>
<result>A</result> | A | 6.25 | if p/q=3/4
then3p+4q=? | {
"A": "25 / 4",
"B": "25 / 2",
"C": "20 / 4",
"D": "35 / 4",
"E": "25 / 3"
} | divide(add(multiply(multiply(3, divide(4, 3)), multiply(3, divide(4, 3))), multiply(3, 3)), multiply(3, divide(4, 3))) | divide(n1,n0)|multiply(n0,n0)|multiply(n0,#0)|multiply(#2,#2)|add(#3,#1)|divide(#4,#2) | 3 p + 4 q = ? divided by q , 3 ( p / q ) + 4 = x 3 * ( 3 / 4 ) + 4 = 25 / 4 answer : a | general |
math_qa__x4QddrvDeIQmnxiL | X and Y started a business by investing Rs.36000 and Rs.42000 respectively after 4 months Z joined in the business with an investment of Rs.48000, then find share of Z in the profit of Rs.13970 ? Choose the most appropriate option
A) 3200 B) 4064 C) 3250 D) 3825 E) 3985 | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 - 4</gadget>
<output>8</output>
<gadget id="calculator">48_000 * 8</gadget>
<output>384_000</output>
<gadget id="calculator">36_000 * 12</gadget>
<output>432_000</output>
<gadget id="calculator">42_000 * 12</gadget>
<output>504_000</output>
<gadget id="calculator">432_000 + 504_000</gadget>
<output>936_000</output>
<gadget id="calculator">936_000 + 384_000</gadget>
<output>1_320_000</output>
<gadget id="calculator">13_970 / 1_320_000</gadget>
<output>127/12_000 = around 0.010583</output>
<gadget id="calculator">384_000 * (127/12_000)</gadget>
<output>4_064</output>
<result>B</result> | B | 4,064 | X and Y started a business by investing Rs.36000 and Rs.42000 respectively after 4 months Z joined in the business with an investment of Rs.48000, then find share of Z in the profit of Rs.13970 ? | {
"A": "3200",
"B": "4064",
"C": "3250",
"D": "3825",
"E": "3985"
} | multiply(multiply(48000, subtract(multiply(const_3, 4), 4)), divide(13970, add(add(multiply(36000, multiply(const_3, 4)), multiply(42000, multiply(const_3, 4))), multiply(48000, subtract(multiply(const_3, 4), 4))))) | multiply(const_3,n2)|multiply(n0,#0)|multiply(n1,#0)|subtract(#0,n2)|add(#1,#2)|multiply(n3,#3)|add(#4,#5)|divide(n4,#6)|multiply(#7,#5)| | "ratio of investment , as investments is for different time . investment x number of units of time . ratio of investments x : y : z = 36000 : 42000 : 48000 = > 6 : 7 : 8 . x = 6 x 12 months = 72 , y = 7 x 12 = 84 , z = 8 x 8 = 64 = > 18 : 21 : 16 . ratio of investments = > x : y : z = 18 : 21 : 16 . investment ratio = profit sharing ratio . z = 13970 ã — 16 / 55 = rs . 4064 . share of z in the profit is rs . 4064 . option b" | gain |
math_qa__5je8ZF049dkm6ahD | The banker’s discount of a certain sum of money is Rs. 42 and the true discount on the same sum for the same time is Rs. 36. The sum due is Choose the correct choice from the following choices
A) 252
B) 280
C) 360
D) 450
E) none | <gadget id="calculator">42 * 36</gadget>
<output>1_512</output>
<gadget id="calculator">42 - 36</gadget>
<output>6</output>
<gadget id="calculator">1_512 / 6</gadget>
<output>252</output>
<result>A</result> | A | 252 | The banker’s discount of a certain sum of money is Rs. 42 and the true discount on the same sum for the same time is Rs. 36. The sum due is | {
"A": "252",
"B": "280",
"C": "360",
"D": "450",
"E": "none"
} | divide(multiply(42, 36), subtract(42, 36)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)| | "sol . sum = b . d . * t . d . / b . d . - t . d . = rs . [ 42 * 36 / 42 - 36 ] = rs . [ 42 * 36 / 6 ] = rs . 252 answer a" | gain |
math_qa__7q1breDLfp51eC66 | Two trains of equal lengths take 10 sec and 15 sec, respectively, to cross a telegraph post. If the length of each train is 120 m, in what time will they cross each other, travelling in opposite directions? Choose the correct choice from the following choices: A) 17 sec B) 12 sec C) 18 sec D) 19 sec E) 52 sec | <gadget id="calculator">120 + 120</gadget>
<output>240</output>
<gadget id="calculator">120 / 10</gadget>
<output>12</output>
<gadget id="calculator">120 / 15</gadget>
<output>8</output>
<gadget id="calculator">12 + 8</gadget>
<output>20</output>
<gadget id="calculator">240 / 20</gadget>
<output>12</output>
<result>B</result> | B | 12 | Two trains of equal lengths take 10 sec and 15 sec, respectively, to cross a telegraph post. If the length of each train is 120 m, in what time will they cross each other, travelling in opposite directions? | {
"A": "17 sec",
"B": "12 sec",
"C": "18 sec",
"D": "19 sec",
"E": "52 sec"
} | divide(add(120, 120), add(divide(120, 10), divide(120, 15))) | add(n2,n2)|divide(n2,n0)|divide(n2,n1)|add(#1,#2)|divide(#0,#3) | speed of the first train = 120 / 10 = 12 m / sec . speed of the second train = 120 / 5 = 8 m / sec . relative speed = 12 + 8 = 20 m / sec . required time = ( 120 + 120 ) / 20 = 12 sec . answer : b | physics |
math_qa__4pZmDHF6lYFEbsUd | 2 men and 3 women are lined up in a row. What is the number of cases where they stand with each other in turn? (The number of cases in which men (or women) do not stand next to each other) Choose the correct choice:
A) 12
B) 15
C) 18
D) 21
E) 24 | <gadget id="calculator">factorial(2)</gadget>
<output>2</output>
<gadget id="calculator">factorial(3)</gadget>
<output>6</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<result>A</result> | A | 12 | 2 men and 3 women are lined up in a row. What is the number of cases where they stand with each other in turn? (The number of cases in which men (or women) do not stand next to each other) | {
"A": "12",
"B": "15",
"C": "18",
"D": "21",
"E": "24"
} | multiply(factorial(2), factorial(3)) | factorial(n0)|factorial(n1)|multiply(#0,#1)| | "first arrange 3 women . 3 women can be arranged in 3 places in 3 ! ways . now w blank w blankw we have to fill the two blanks with 2 men . we can arrange 2 persons in 2 places in 2 ! ways . 3 ! * 2 ! = 12 ways . a is the answer" | general |
math_qa__UsWeUyD8KWo3hJzI | A constructor estimates that 3 people can paint Mr khans house in 4 days. If he uses 4 people instead of 3,how long will they take to complete the job? Choices:
A) 2
B) 8
C) 1
D) 3
E) 4 | <gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">1 / 12</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/12) * 4</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / (1/3)</gadget>
<output>3</output>
<result>D</result> | D | 3 | A constructor estimates that 3 people can paint Mr khans house in 4 days. If he uses 4 people instead of 3,how long will they take to complete the job? | {
"A": "2",
"B": "8",
"C": "1",
"D": "3",
"E": "4"
} | divide(const_1, multiply(divide(const_1, multiply(4, 3)), 4)) | multiply(n0,n1)|divide(const_1,#0)|multiply(n1,#1)|divide(const_1,#2) | explanation : use formula for a work members × days = constant 3 × 4 = 4 × a a = 3 so answer is 3 days answer : d | physics |
math_qa__vfHrHbC4LCoIr0OD | (0.82)(power 3) - (0.1)(power 3)/ (0.82)(power 2) + 0.082 + (0.1)(power 2) is: Choose the correct answer.
A) 0.86
B) 0.68
C) 0.96
D) 0.69
E) 0.72 | <gadget id="calculator">0.82 ** 3</gadget>
<output>0.551368</output>
<gadget id="calculator">0.1 ** 3</gadget>
<output>0.001</output>
<gadget id="calculator">0.551368 - 0.001</gadget>
<output>0.550368</output>
<gadget id="calculator">0.82 ** 2</gadget>
<output>0.6724</output>
<gadget id="calculator">0.6724 + 0.082</gadget>
<output>0.7544</output>
<gadget id="calculator">0.1 ** 2</gadget>
<output>0.01</output>
<gadget id="calculator">0.7544 + 0.01</gadget>
<output>0.7644</output>
<gadget id="calculator">0.550368 / 0.7644</gadget>
<output>0.72</output>
<result>E</result> | E | 0.72 | (0.82)(power 3) - (0.1)(power 3)/ (0.82)(power 2) + 0.082 + (0.1)(power 2) is: | {
"A": "0.86",
"B": "0.68",
"C": "0.96",
"D": "0.69",
"E": "0.72"
} | divide(subtract(power(0.82, 3), power(0.1, 3)), add(add(power(0.82, 2), 0.082), power(0.1, 2))) | power(n0,n1)|power(n2,n1)|power(n0,n5)|power(n2,n5)|add(n6,#2)|subtract(#0,#1)|add(#4,#3)|divide(#5,#6)| | "given expression = ( 0.82 ) ( power 3 ) - ( 0.1 ) ( power 3 ) / ( 0.82 ) ( power 2 ) + ( 0.82 x 0.1 ) + ( 0.1 ) ( power 2 ) = a ( power 3 ) - b ( power 3 ) / a ( power 2 ) + ab + b ( power 2 ) = ( a - b ) = ( 0.82 - 0.1 ) = 0.72 answer is e" | general |
math_qa__Q4hNsAkyejvkDvwl | For every X, the action [X] is defined: [X] is the greatest integer less than or equal to X. What is the value of [6.5] x [2/3] + [2] x 7.2 + [8.4] - 6.6? Select the correct option:
A) 12.6 . B) 14.4 . C) 15.8 . D) 16.2 . E) 16.4 | <gadget id="calculator">2 * 7.2</gadget>
<output>14.4</output>
<gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">8.4 - (2/5)</gadget>
<output>8</output>
<gadget id="calculator">14.4 + 8</gadget>
<output>22.4</output>
<gadget id="calculator">22.4 - 6.6</gadget>
<output>15.8</output>
<result>C</result> | C | 15.8 | For every X, the action [X] is defined: [X] is the greatest integer less than or equal to X. What is the value of [6.5] x [2/3] + [2] x 7.2 + [8.4] - 6.6? | {
"A": "12.6 .",
"B": "14.4 .",
"C": "15.8 .",
"D": "16.2 .",
"E": "16.4"
} | subtract(add(multiply(2, 7.2), subtract(8.4, divide(const_4, const_10))), 6.6) | divide(const_4,const_10)|multiply(n1,n4)|subtract(n5,#0)|add(#1,#2)|subtract(#3,n6) | [ 6.5 ] x [ 2 / 3 ] + [ 2 ] x 7.2 + [ 8.4 ] - 6.6 = 6 * 0 + 2 * 7.2 + 8 - 6.6 = 0 + 14.4 + 1.4 15.8 answer c | general |
math_qa__d5IU3Ihsjl5O1nzV | At 1:00 pm, there were 10.0 grams of bacteria. The bacteria increased to x grams at 4:00 pm, and 25.6 grams at 7:00 pm. If the amount of bacteria present increased by the same fraction during each of the 3-hour periods, how many grams of bacteria were present at 4:00 pm? Choose one
A) 15.1
B) 15.4
C) 15.7
D) 16.0
E) 16.3 | <gadget id="calculator">25.6 / 10</gadget>
<output>2.56</output>
<gadget id="calculator">2.56 ** (1/2)</gadget>
<output>1.6</output>
<gadget id="calculator">1.6 * 10</gadget>
<output>16</output>
<result>D</result> | D | 16 | At 1:00 pm, there were 10.0 grams of bacteria. The bacteria increased to x grams at 4:00 pm, and 25.6 grams at 7:00 pm. If the amount of bacteria present increased by the same fraction during each of the 3-hour periods, how many grams of bacteria were present at 4:00 pm? | {
"A": "15.1",
"B": "15.4",
"C": "15.7",
"D": "16.0",
"E": "16.3"
} | multiply(sqrt(divide(25.6, const_10)), const_10) | divide(n5,const_10)|sqrt(#0)|multiply(#1,const_10) | let x be the factor by which the bacteria increases every three hours . at 4 : 00 pm , the amount of bacteria was 10 x and at 7 : 00 pm it was 10 x ^ 2 . 10 x ^ 2 = 25.6 x ^ 2 = 2.56 x = 1.6 at 4 : 00 pm , the amount of bacteria was 10 ( 1.6 ) = 16 grams . the answer is d . | general |
math_qa__O7Tli06aXxzdMFYU | A bag contains 6 red, 4 blue and 2 green balls. If 2 ballsare picked at random, what is the probability that both are red?
Pick one.
A) 1 / 13 B) 2 / 23 C) 5 / 26 D) 5 / 22 E) 3 / 23 | <gadget id="calculator">binomial(6, 2)</gadget>
<output>15</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">binomial(12, 2)</gadget>
<output>66</output>
<gadget id="calculator">15 / 66</gadget>
<output>5/22 = around 0.227273</output>
<result>D</result> | D | 0.227273 | A bag contains 6 red, 4 blue and 2 green balls. If 2 ballsare picked at random, what is the probability that both are red? | {
"A": "1 / 13",
"B": "2 / 23",
"C": "5 / 26",
"D": "5 / 22",
"E": "3 / 23"
} | divide(choose(6, 2), choose(add(add(6, 4), 2), 2)) | add(n0,n1)|choose(n0,n3)|add(n2,#0)|choose(#2,n3)|divide(#1,#3)| | "p ( both are red ) , = 6 c 212 c 2 = 6 c 212 c 2 = 15 / 66 = 5 / 22 d" | other |
math_qa__XpEeeLDDVPZ1ZbB8 | The true discount on a bill of Rs. 2560 is Rs. 360. What is the banker's discount?
Choose the correct choice from the following.
A) rs . 432 B) rs . 422 C) rs . 419 D) rs . 442 E) none of these | <gadget id="calculator">2_560 - 360</gadget>
<output>2_200</output>
<gadget id="calculator">360 / 2_200</gadget>
<output>9/55 = around 0.163636</output>
<gadget id="calculator">(9/55) * 2_560</gadget>
<output>4_608/11 = around 418.909091</output>
<result>C</result> | C | 419 | The true discount on a bill of Rs. 2560 is Rs. 360. What is the banker's discount? | {
"A": "rs . 432",
"B": "rs . 422",
"C": "rs . 419",
"D": "rs . 442",
"E": "none of these"
} | multiply(divide(360, subtract(2560, 360)), 2560) | subtract(n0,n1)|divide(n1,#0)|multiply(n0,#1)| | "explanation : f = rs . 2560 td = rs . 360 pw = f - td = 2560 - 360 = rs . 2200 true discount is the simple interest on the present value for unexpired time = > simple interest on rs . 2200 for unexpired time = rs . 360 banker ' s discount is the simple interest on the face value of the bill for unexpired time = simple interest on rs . 2160 for unexpired time = 360 / 2200 × 2560 = 0.16 × 2560 = rs . 419 answer : option c" | gain |
math_qa__ZPyOguNgPBRR5J3z | A man took loan from a bank at the rate of 4 % p.a. S.I. After 10 years he had to pay Rs. 2000 interest only for the period. The principal amount borrowed by him was? Choose one
A) 5000 B) 4500 C) 3200 D) 6000 E) 1592 | <gadget id="calculator">2_000 * 100</gadget>
<output>200_000</output>
<gadget id="calculator">200_000 / 10</gadget>
<output>20_000</output>
<gadget id="calculator">20_000 / 4</gadget>
<output>5_000</output>
<result>A</result> | A | 5,000 | A man took loan from a bank at the rate of 4 % p.a. S.I. After 10 years he had to pay Rs. 2000 interest only for the period. The principal amount borrowed by him was? | {
"A": "5000",
"B": "4500",
"C": "3200",
"D": "6000",
"E": "1592"
} | divide(divide(multiply(2000, const_100), 10), 4) | multiply(n2,const_100)|divide(#0,n1)|divide(#1,n0)| | "principal = ( 100 * 2000 ) / ( 4 * 10 ) = rs . 5000 answer : a" | gain |
math_qa__B73nkYdwqezWRVEn | The mean of 50 observations was 36. It was found later that an observation 46 was wrongly taken as 23. The corrected new mean is Pick
A) 35.24 B) 36.16 C) 36.24 D) 36.46 E) none | <gadget id="calculator">36 * 50</gadget>
<output>1_800</output>
<gadget id="calculator">50 - 2</gadget>
<output>48</output>
<gadget id="calculator">48 - 23</gadget>
<output>25</output>
<gadget id="calculator">1_800 + 25</gadget>
<output>1_825</output>
<gadget id="calculator">1_825 / 50</gadget>
<output>73/2 = around 36.5</output>
<result>D</result> | D | 36.46 | The mean of 50 observations was 36. It was found later that an observation 46 was wrongly taken as 23. The corrected new mean is | {
"A": "35.24",
"B": "36.16",
"C": "36.24",
"D": "36.46",
"E": "none"
} | divide(add(multiply(36, 50), subtract(subtract(50, const_2), 23)), 50) | multiply(n0,n1)|subtract(n0,const_2)|subtract(#1,n3)|add(#0,#2)|divide(#3,n0)| | "solution correct sum = ( 36 x 50 + 46 - 23 ) = 1823 . â ˆ ´ correct mean = 1823 / 50 = 36.46 . answer d" | general |
math_qa__YutaQekl1QGThw9q | Average weight of 15 boys in a class is 48 kgs. The average weight of the class of 25 students is 45 kgs. What is the average weight of the 15 girls in the class? Pick one.
A) 45 B) 47.3 C) 39.8 D) 45.5 E) 40.5 | <gadget id="calculator">25 * 45</gadget>
<output>1_125</output>
<gadget id="calculator">15 * 48</gadget>
<output>720</output>
<gadget id="calculator">1_125 - 720</gadget>
<output>405</output>
<gadget id="calculator">405 / 10</gadget>
<output>81/2 = around 40.5</output>
<result>E</result> | E | 40.5 | Average weight of 15 boys in a class is 48 kgs. The average weight of the class of 25 students is 45 kgs. What is the average weight of the 15 girls in the class? | {
"A": "45",
"B": "47.3",
"C": "39.8",
"D": "45.5",
"E": "40.5"
} | divide(subtract(multiply(25, 45), multiply(15, 48)), const_10) | multiply(n2,n3)|multiply(n0,n1)|subtract(#0,#1)|divide(#2,const_10) | total weight of boys in class 15 x 48 = 720 kg total weight of all student in the class room 25 x 45 = 1125 kg total no of girls in the class 1125 - 720 = 405 kg average weight of girls 405 / 10 = 40.5 kg correct ans is e | general |
math_qa__gILcoiYno67dZrF9 | The sum of two numbers is 84, and one of them is 12 more than the other. What are the two numbers?
Choose the correct answer
A) 48 , 36 B) 36 , 48 C) 32 , 48 D) 48 , 32 E) 32 , 42 | <gadget id="calculator">84 - 12</gadget>
<output>72</output>
<gadget id="calculator">72 / 2</gadget>
<output>36</output>
<result>B</result> | B | 36 | The sum of two numbers is 84, and one of them is 12 more than the other. What are the two numbers? | {
"A": "48 , 36",
"B": "36 , 48",
"C": "32 , 48",
"D": "48 , 32",
"E": "32 , 42"
} | divide(subtract(84, 12), const_2) | subtract(n0,n1)|divide(#0,const_2) | 2 x = 84 − 12 = 72 . x = 72 / 2 = 36 . this is the first number . therefore the other number is x + 12 = 36 + 12 = 48 . the sum of 36 + 48 is 84 . answer is b . | general |
math_qa__X4MxbKcl0hKDYDk7 | A man started driving at a constant speed, from the site of a blast, the moment he heard the blast. He heard a second blast after a time of 30 mins and 25 seconds. If the second blast occurred exactly 30 mins after the first, how many meters was he from the site when he heard the second blast? ( speed of sound = 330 m/s)
Pick one:
A) 8250 B) 9350 C) 10,450 D) 11,550 E) 12,650 | <gadget id="calculator">330 * 25</gadget>
<output>8_250</output>
<result>A</result> | A | 8,250 | A man started driving at a constant speed, from the site of a blast, the moment he heard the blast. He heard a second blast after a time of 30 mins and 25 seconds. If the second blast occurred exactly 30 mins after the first, how many meters was he from the site when he heard the second blast? ( speed of sound = 330 m/s) | {
"A": "8250",
"B": "9350",
"C": "10,450",
"D": "11,550",
"E": "12,650"
} | multiply(330, 25) | multiply(n1,n3)| | "the distance the sound traveled to the man is 25 * 330 = 8250 meters the answer is a ." | physics |
math_qa__DiifcDL2wECigouA | John had a stock of 1400 books in his bookshop. He sold 62 on Monday, 62 on Tuesday, 60 on Wednesday, 48 on Thursday and 40 on Friday. What percentage of the books were not sold? Choose the correct answer.
A) 81.57 % B) 36.5 % C) 80.67 % D) 56.5 % E) 80.57 % | <gadget id="calculator">62 + 62</gadget>
<output>124</output>
<gadget id="calculator">60 + 48</gadget>
<output>108</output>
<gadget id="calculator">124 + 108</gadget>
<output>232</output>
<gadget id="calculator">232 + 40</gadget>
<output>272</output>
<gadget id="calculator">1_400 - 272</gadget>
<output>1_128</output>
<gadget id="calculator">1_128 / 1_400</gadget>
<output>141/175 = around 0.805714</output>
<gadget id="calculator">(141/175) * 100</gadget>
<output>564/7 = around 80.571429</output>
<result>E</result> | E | 80.57 | John had a stock of 1400 books in his bookshop. He sold 62 on Monday, 62 on Tuesday, 60 on Wednesday, 48 on Thursday and 40 on Friday. What percentage of the books were not sold? | {
"A": "81.57 %",
"B": "36.5 %",
"C": "80.67 %",
"D": "56.5 %",
"E": "80.57 %"
} | multiply(divide(subtract(1400, add(add(add(62, 62), add(60, 48)), 40)), 1400), const_100) | add(n1,n2)|add(n3,n4)|add(#0,#1)|add(n5,#2)|subtract(n0,#3)|divide(#4,n0)|multiply(#5,const_100)| | "let n be the total number of books sold . hence n = 62 + 62 + 60 + 48 + 40 = 272 let m be the books not sold m = 1400 - n = 1400 - 272 = 1128 percentage books not sold / total number of books = 1128 / 1200 = 0.81 = 80.57 % correct answer e" | gain |
math_qa__ansQusXOmSP5DwRW | A train 250 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train? Choose the correct choice from the following options: A) 15 sec B) 9 sec C) 12 sec D) 15 sec E) 18 sec | <gadget id="calculator">68 - 8</gadget>
<output>60</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">250 / (50/3)</gadget>
<output>15</output>
<result>A</result> | A | 15 | A train 250 m long is running at a speed of 68 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train? | {
"A": "15 sec",
"B": "9 sec",
"C": "12 sec",
"D": "15 sec",
"E": "18 sec"
} | divide(250, multiply(subtract(68, 8), const_0_2778)) | subtract(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "speed of the train relative to man = ( 68 - 8 ) kmph = ( 60 * 5 / 18 ) m / sec = ( 50 / 3 ) m / sec time taken by the train to cross the man = time taken by it to cover 250 m at 50 / 3 m / sec = 250 * 3 / 50 sec = 15 sec answer : a ." | physics |
math_qa__faj743FUwZz1xF6p | In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 30 percent, but profits were 20 percent of revenues. The profits in 1999 were what percent of the profits in 1998? Choose one: A) 80 % B) 105 % C) 140 % D) 124.2 % E) 138 % | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(7/10) * (1/5)</gadget>
<output>7/50 = around 0.14</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(7/50) / (1/10)</gadget>
<output>7/5 = around 1.4</output>
<gadget id="calculator">(7/5) * 100</gadget>
<output>140</output>
<result>C</result> | C | 140 | In 1998 the profits of company N were 10 percent of revenues. In 1999, the revenues of company N fell by 30 percent, but profits were 20 percent of revenues. The profits in 1999 were what percent of the profits in 1998? | {
"A": "80 %",
"B": "105 %",
"C": "140 %",
"D": "124.2 %",
"E": "138 %"
} | multiply(divide(multiply(subtract(const_1, divide(30, const_100)), divide(20, const_100)), divide(10, const_100)), const_100) | divide(n4,const_100)|divide(n3,const_100)|divide(n1,const_100)|subtract(const_1,#1)|multiply(#0,#3)|divide(#4,#2)|multiply(#5,const_100)| | "0,14 r = x / 100 * 0.1 r answer c" | gain |
math_qa__AE25zeIiy3V45IPC | The sum of two numbers is 96, and one of them is 12 more than the other. What are the two numbers? Options
A) 36 - 48 B) 50 - 34 C) 60 - 24 D) 42 - 54 E) 21 - 63 | <gadget id="calculator">96 - 12</gadget>
<output>84</output>
<gadget id="calculator">84 / 2</gadget>
<output>42</output>
<result>D</result> | D | 42 | The sum of two numbers is 96, and one of them is 12 more than the other. What are the two numbers? | {
"A": "36 - 48",
"B": "50 - 34",
"C": "60 - 24",
"D": "42 - 54",
"E": "21 - 63"
} | divide(subtract(96, 12), const_2) | subtract(n0,n1)|divide(#0,const_2)| | "in this problem , we are asked to find two numbers . therefore , we must let x be one of them . let x , then , be the first number . we are told that the other number is 12 more , x + 12 . the problem states that their sum is 96 : word problem = 96 the line over x + 12 is a grouping symbol called a vinculum . it saves us writing parentheses . we have : 2 x = 96 â ˆ ’ 12 = 84 . x = 84 / 2 = 42 . this is the first number . therefore the other number is x + 12 = 42 + 12 = 54 . the sum of 42 + 54 is 96 . d" | general |
math_qa__1i4xRfMJlBVITwEx | In a certain game, each player scores either 2 points or 5 points. If n players score 2 points and m players score 5 points, and the total number of points scored is 50, what is the least possible positive difference Q between n and m?
Select the correct option: A) 1 B) 3 C) 5 D) 7 E) 9 | <gadget id="calculator">5 - 2</gadget>
<output>3</output>
<result>B</result> | B | 3 | In a certain game, each player scores either 2 points or 5 points. If n players score 2 points and m players score 5 points, and the total number of points scored is 50, what is the least possible positive difference Q between n and m? | {
"A": "1",
"B": "3",
"C": "5",
"D": "7",
"E": "9"
} | subtract(5, 2) | subtract(n1,n0)| | "we have equation 2 n + 5 m = 50 we have factor 2 in first number and we have factor 5 in second number . lcm ( 2 , 5 ) = 10 so we can try some numbers and we should start from 5 because it will be less list than for 2 2 * 5 = 10 and n should be equal 20 4 * 5 = 20 and n should be equal 15 6 * 5 = 30 and n should be equal 10 8 * 5 = 40 and n should be equal 5 10 * 5 = 50 and n should be equal 0 third variant give us the mininal difference n - m = 10 - 6 = 4 and there is some mistake in my way of thinking because we do n ' t have such answer ) if we change the task and will seek for difference between m and n than minimal result q will be 8 - 5 = 3 and answer b" | general |
math_qa__jUPa3XQOq4DmBPXa | A motorcyclist started riding at highway marker A, drove 120 miles to highway marker B, and then, without pausing, continued to highway marker C, where she stopped. The average speed of the motorcyclist, over the course of the entire trip, was 20 miles per hour. If the ride from marker A to marker B lasted 3 times as many hours as the rest of the ride, and the distance from marker B to marker C was half of the distance from marker A to marker B, what was the average speed, in miles per hour, of the motorcyclist while driving from marker B to marker C?
Choose the correct option.
A) 40
B) 135
C) 50
D) 55
E) 60 | <gadget id="calculator">120 / 2</gadget>
<output>60</output>
<gadget id="calculator">60 + 120</gadget>
<output>180</output>
<gadget id="calculator">180 / 20</gadget>
<output>9</output>
<gadget id="calculator">9 / 4</gadget>
<output>9/4 = around 2.25</output>
<gadget id="calculator">(9/4) * 60</gadget>
<output>135</output>
<result>B</result> | B | 135 | A motorcyclist started riding at highway marker A, drove 120 miles to highway marker B, and then, without pausing, continued to highway marker C, where she stopped. The average speed of the motorcyclist, over the course of the entire trip, was 20 miles per hour. If the ride from marker A to marker B lasted 3 times as many hours as the rest of the ride, and the distance from marker B to marker C was half of the distance from marker A to marker B, what was the average speed, in miles per hour, of the motorcyclist while driving from marker B to marker C? | {
"A": "40",
"B": "135",
"C": "50",
"D": "55",
"E": "60"
} | multiply(divide(divide(add(divide(120, const_2), 120), 20), const_4), divide(120, const_2)) | divide(n0,const_2)|add(n0,#0)|divide(#1,n1)|divide(#2,const_4)|multiply(#3,#0) | a - b = 120 miles b - c = 60 miles avg speed = 20 miles time taken for a - b 3 t and b - c be t avg speed = ( 120 + 60 ) / total time 20 = 180 / 4 t t = 135 b - c = 135 mph answer b | physics |
math_qa__jvusRnWUwtgJAAvc | Mary is expected to pay back a total sum of $819200 to her bank as mortgage. If she is expected to make a payment which is double of the previous months amount, how long will it take her to fully repay the loan if her initial payment was $400. Choose the correct choice from the following.
A) 13 B) 15 C) 12 D) 10 E) 11 | <gadget id="calculator">819_200 / 100</gadget>
<output>8_192</output>
<gadget id="calculator">8_192 / 2</gadget>
<output>4_096</output>
<gadget id="calculator">4_096 / 2</gadget>
<output>2_048</output>
<gadget id="calculator">2_048 / 4</gadget>
<output>512</output>
<gadget id="calculator">512 - 10</gadget>
<output>502</output>
<gadget id="calculator">502 - 100</gadget>
<output>402</output>
<gadget id="calculator">402 - 10</gadget>
<output>392</output>
<gadget id="calculator">392 - 4</gadget>
<output>388</output>
<gadget id="calculator">388 + 1</gadget>
<output>389</output>
<gadget id="calculator">400 - 389</gadget>
<output>11</output>
<result>E</result> | E | 11 | Mary is expected to pay back a total sum of $819200 to her bank as mortgage. If she is expected to make a payment which is double of the previous months amount, how long will it take her to fully repay the loan if her initial payment was $400. | {
"A": "13",
"B": "15",
"C": "12",
"D": "10",
"E": "11"
} | subtract(400, add(subtract(subtract(subtract(subtract(divide(divide(divide(divide(819200, const_100), const_2), const_2), const_4), const_10), const_100), const_10), const_4), const_1)) | divide(n0,const_100)|divide(#0,const_2)|divide(#1,const_2)|divide(#2,const_4)|subtract(#3,const_10)|subtract(#4,const_100)|subtract(#5,const_10)|subtract(#6,const_4)|add(#7,const_1)|subtract(n1,#8) | first payment - - $ 400 total amount to be repaid - - $ 819200 first month payment - - $ 400 second month payment - - $ 400 * 2 = $ 800 third month payment - - $ 800 * 2 = $ 1600 fourth month payment - - $ 1600 * 2 = $ 3200 fifth month payment - - $ 3200 * 2 = $ 6400 sixth month payment - - $ 6400 * 2 = $ 12800 seventh month payment - - $ 25600 * 2 = $ 51200 eight month payment - - $ 51200 * 2 = $ 102400 ninth month payment - - $ 102400 * 2 = $ 204800 tenth month payment - - $ 204800 * 2 = $ 409600 eleventh month payment - - $ 409600 * 2 = $ 819200 answer is e | general |
math_qa__79eTYX6nmNRAJnvH | A Jar contains a mixture of AB in the ratio 4:1. When 30 L of Mixture is replaced with liquid B, ratio becomes 2:3. How many liters of liquid A was present in mixture initially. Select the correct option:
A) 12
B) 48
C) 16
D) 20
E) 25 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">30 / 5</gadget>
<output>6</output>
<gadget id="calculator">10 * 6</gadget>
<output>60</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">60 / 5</gadget>
<output>12</output>
<gadget id="calculator">12 * 4</gadget>
<output>48</output>
<result>B</result> | B | 48 | A Jar contains a mixture of AB in the ratio 4:1. When 30 L of Mixture is replaced with liquid B, ratio becomes 2:3. How many liters of liquid A was present in mixture initially. | {
"A": "12",
"B": "48",
"C": "16",
"D": "20",
"E": "25"
} | multiply(divide(multiply(add(multiply(3, 2), multiply(2, 2)), divide(30, subtract(multiply(3, 2), 1))), add(4, 1)), 4) | add(n0,n1)|multiply(n4,n3)|multiply(n3,n3)|add(#1,#2)|subtract(#1,n1)|divide(n2,#4)|multiply(#3,#5)|divide(#6,#0)|multiply(n0,#7)| | "30 litres of mixture that is replaced will contain 24 litres of a and 6 litres of b ( as a : b = 4 : 1 ) let the initial volume of the mixture be 4 k + 1 k = 5 k so by condition , [ 4 k - 24 ] / [ k - 6 + 30 ] = 2 / 3 = > 12 k - 72 = 2 k - 12 + 60 = > 10 k = 120 solve for k which is k = 12 so initial volume of liquid a = 4 k = 48 litres answer : b" | other |
math_qa__SdZf1b7QEiYISJ3r | If there are 56 laborers in a crew, and on a certain day, 30 were present. Calculate the percentage that showed up for work? (round to the nearest tenth). Choices: A) 53.6 % B) 52.6 % C) 54.6 % D) 55.6 % E) 59.6 % | <gadget id="calculator">30 * 100</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 / 56</gadget>
<output>375/7 = around 53.571429</output>
<result>A</result> | A | 53.6 | If there are 56 laborers in a crew, and on a certain day, 30 were present. Calculate the percentage that showed up for work? (round to the nearest tenth). | {
"A": "53.6 %",
"B": "52.6 %",
"C": "54.6 %",
"D": "55.6 %",
"E": "59.6 %"
} | divide(multiply(30, const_100), 56) | multiply(n1,const_100)|divide(#0,n0) | 30 / 56 * 100 = 53.57 53.6 % correct answer a | physics |
math_qa__auUrFuHfvflLopO3 | The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 13 runs. Find his average in all the 30 matches? Choose the correct choice from the following options: A) 31 B) 67 C) 88 D) 69 E) 12 | <gadget id="calculator">40 * 20</gadget>
<output>800</output>
<gadget id="calculator">13 * 10</gadget>
<output>130</output>
<gadget id="calculator">800 + 130</gadget>
<output>930</output>
<gadget id="calculator">20 + 10</gadget>
<output>30</output>
<gadget id="calculator">930 / 30</gadget>
<output>31</output>
<result>A</result> | A | 31 | The average runs scored by a batsman in 20 matches is 40. In the next 10 matches the batsman scored an average of 13 runs. Find his average in all the 30 matches? | {
"A": "31",
"B": "67",
"C": "88",
"D": "69",
"E": "12"
} | divide(add(multiply(40, 20), multiply(13, 10)), add(20, 10)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0) | total score of the batsman in 20 matches = 800 . total score of the batsman in the next 10 matches = 130 . total score of the batsman in the 30 matches = 930 . average score of the batsman = 930 / 30 = 31 . answer : a | general |
math_qa__4R1PF6ipZyRvsykN | P, Q and R have Rs.9000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R?
Choose the correct choice from the following answers.
A) rs . 3000 B) rs . 3600 C) rs . 2400 D) rs . 4000 E) none of these | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 + (2/3)</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">9_000 / (5/3)</gadget>
<output>5_400</output>
<gadget id="calculator">5_400 * (2/3)</gadget>
<output>3_600</output>
<result>B</result> | B | 3,600 | P, Q and R have Rs.9000 among themselves. R has two-thirds of the total amount with P and Q. Find the amount with R? | {
"A": "rs . 3000",
"B": "rs . 3600",
"C": "rs . 2400",
"D": "rs . 4000",
"E": "none of these"
} | multiply(divide(9000, add(const_1, divide(const_2, const_3))), divide(const_2, const_3)) | divide(const_2,const_3)|add(#0,const_1)|divide(n0,#1)|multiply(#2,#0)| | "let the amount with r be rs . r r = 2 / 3 ( total amount with p and q ) r = 2 / 3 ( 9000 - r ) = > 3 r = 18000 - 2 r = > 5 r = 18000 = > r = 3600 . answer : b" | general |
math_qa__g6pTLROT5hH2vZsP | A car gets 60 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 170 kilometers? Choose the correct choice.
A) 3.5 gallons B) 2.37 gallons C) 5.7 gallons D) 4.25 gallons E) 2.83 gallons | <gadget id="calculator">170 / 60</gadget>
<output>17/6 = around 2.833333</output>
<result>E</result> | E | 2.83 | A car gets 60 kilometers per gallon of gasoline. How many gallons of gasoline would the car need to travel 170 kilometers? | {
"A": "3.5 gallons",
"B": "2.37 gallons",
"C": "5.7 gallons",
"D": "4.25 gallons",
"E": "2.83 gallons"
} | divide(170, 60) | divide(n1,n0)| | "each 60 kilometers , 1 gallon is needed . we need to know how many 60 kilometers are there in 170 kilometers ? 60 ã · 170 = 2.83 ã — 1 gallon = 2.83 gallons correct answer is e ) 2.83 gallons" | physics |
math_qa__6btN3fnzA9eCB6kZ | If Jake loses 8 pounds, he will weigh twice as much as his sister Kendra. Together they now weigh 293 pounds. What is Jake’s present weight, in pounds? Select:
A) 182 B) 186 C) 190 D) 194 E) 198 | <gadget id="calculator">293 - 8</gadget>
<output>285</output>
<gadget id="calculator">285 / 3</gadget>
<output>95</output>
<gadget id="calculator">95 * 2</gadget>
<output>190</output>
<gadget id="calculator">190 + 8</gadget>
<output>198</output>
<result>E</result> | E | 198 | If Jake loses 8 pounds, he will weigh twice as much as his sister Kendra. Together they now weigh 293 pounds. What is Jake’s present weight, in pounds? | {
"A": "182",
"B": "186",
"C": "190",
"D": "194",
"E": "198"
} | add(multiply(divide(subtract(293, 8), const_3), const_2), 8) | subtract(n1,n0)|divide(#0,const_3)|multiply(#1,const_2)|add(n0,#2)| | "j + k = 293 and so k = 293 - j j - 8 = 2 k j - 8 = 2 ( 293 - j ) 3 j = 594 j = 198 the answer is e ." | general |
math_qa__HepxBwE9y5eDHgZC | The radius of a circle is 4/π cm then its perimeter is? Options:
A) 10 B) 9 C) 8 D) 12 E) 15 | <gadget id="calculator">4 / pi</gadget>
<output>4/pi = around 1.27324</output>
<gadget id="calculator">pi * (4/pi)</gadget>
<output>4</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<result>C</result> | C | 8 | The radius of a circle is 4/π cm then its perimeter is? | {
"A": "10",
"B": "9",
"C": "8",
"D": "12",
"E": "15"
} | multiply(const_2, multiply(const_pi, divide(4, const_pi))) | divide(n0,const_pi)|multiply(#0,const_pi)|multiply(#1,const_2) | perimeter = 2 π r 2 π * 4 / π = 8 cm answer : c | physics |
math_qa__tDgUOfzDsVYXFpVs | The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is?
Choose the correct choice:
A) 6.99 %
B) 6.89 %
C) 6.08 %
D) 6.09 %
E) 6.19 % | <gadget id="calculator">6 / 2</gadget>
<output>3</output>
<gadget id="calculator">3 + 3</gadget>
<output>6</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">6 + (9/100)</gadget>
<output>609/100 = around 6.09</output>
<result>D</result> | D | 6.09 | The effective annual rate of interest corresponding to a nominal rate of 6% per annum payable half-yearly is? | {
"A": "6.99 %",
"B": "6.89 %",
"C": "6.08 %",
"D": "6.09 %",
"E": "6.19 %"
} | add(add(divide(6, const_2), divide(6, const_2)), divide(multiply(divide(6, const_2), divide(6, const_2)), const_100)) | divide(n0,const_2)|add(#0,#0)|multiply(#0,#0)|divide(#2,const_100)|add(#1,#3)| | "amount of rs . 100 for 1 year when compounded half - yearly = [ 100 * ( 1 + 3 / 100 ) 2 ] = rs . 106.09 effective rate = ( 106.09 - 100 ) = 6.09 % answer : d" | gain |
math_qa__zJt1ipOOIzC8X0xz | Two trains of equal are running on parallel lines in the same direction at 44 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is? Pick one
A) 40 m B) 72 m C) 80 m D) 82 m E) 84 m | <gadget id="calculator">44 - 36</gadget>
<output>8</output>
<gadget id="calculator">8 * 1_000</gadget>
<output>8_000</output>
<gadget id="calculator">8_000 / 3_600</gadget>
<output>20/9 = around 2.222222</output>
<gadget id="calculator">36 * (20/9)</gadget>
<output>80</output>
<gadget id="calculator">80 / 2</gadget>
<output>40</output>
<result>A</result> | A | 40 | Two trains of equal are running on parallel lines in the same direction at 44 km/hr and 36 km/hr. The faster train passes the slower train in 36 sec. The length of each train is? | {
"A": "40 m",
"B": "72 m",
"C": "80 m",
"D": "82 m",
"E": "84 m"
} | divide(multiply(36, divide(multiply(subtract(44, 36), const_1000), const_3600)), const_2) | subtract(n0,n1)|multiply(#0,const_1000)|divide(#1,const_3600)|multiply(n2,#2)|divide(#3,const_2)| | "let the length of each train be x m . then , distance covered = 2 x m . relative speed = 44 - 36 = 8 km / hr . = 8 * 5 / 18 = 20 / 9 m / sec . 2 x / 36 = 20 / 9 = > x = 40 . answer : a" | general |
math_qa__pUmK0BhfhAJH6EDH | each of the 59 members in lourdes school class is required to sign up for a minimum of one and a maximum of 3 academic clubs . the 3 clubs to choose from are the poetry club , the history club , and the writing club . a total of 22 students sign up for the poetry club , 27 students for the history club , and 28 students for the writing club . if 6 students sign up for exactly two clubs , how many students sign up for all 3 clubs ? Choose the correct choice from the following answers
A) 2 B) 5 C) 6 D) 8 E) 9 | <gadget id="calculator">22 + 27</gadget>
<output>49</output>
<gadget id="calculator">49 + 28</gadget>
<output>77</output>
<gadget id="calculator">77 - 59</gadget>
<output>18</output>
<gadget id="calculator">18 - 6</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>C</result> | C | 6 | each of the 59 members in lourdes school class is required to sign up for a minimum of one and a maximum of 3 academic clubs . the 3 clubs to choose from are the poetry club , the history club , and the writing club . a total of 22 students sign up for the poetry club , 27 students for the history club , and 28 students for the writing club . if 6 students sign up for exactly two clubs , how many students sign up for all 3 clubs ? | {
"A": "2",
"B": "5",
"C": "6",
"D": "8",
"E": "9"
} | divide(subtract(subtract(add(add(22, 27), 28), 59), 6), const_2) | add(n3,n4)|add(n5,#0)|subtract(#1,n0)|subtract(#2,n6)|divide(#3,const_2) | each of the 59 members in lourdes school class is required to sign up for a minimum of one and a maximum of three academic clubs . total = g 1 + g 2 + g 3 - ( # in exactly 2 ) - 2 * ( # in 3 sets ) 59 = 22 + 27 + 28 - ( 6 ) - 2 x so , # in 3 sets = 6 = c | general |
math_qa__Ust0PspmioacN5uO | Bruce and Bhishma are running on a circular track of length 600m. Speed of Bruce is 30 m/s and that of Bhishma is 20 m/s .They start fro the same point at the same time in the same direction. When will they meet again for the first time? Answers.
A) 60 sec
B) 70 sec
C) 80 sec
D) 90 sec
E) 100 sec | <gadget id="calculator">30 - 20</gadget>
<output>10</output>
<gadget id="calculator">600 / 10</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">60 + 30</gadget>
<output>90</output>
<result>D</result> | D | 90 | Bruce and Bhishma are running on a circular track of length 600m. Speed of Bruce is 30 m/s and that of Bhishma is 20 m/s .They start fro the same point at the same time in the same direction. When will they meet again for the first time? | {
"A": "60 sec",
"B": "70 sec",
"C": "80 sec",
"D": "90 sec",
"E": "100 sec"
} | add(divide(600, subtract(30, 20)), divide(divide(600, subtract(30, 20)), const_2)) | subtract(n1,n2)|divide(n0,#0)|divide(#1,const_2)|add(#1,#2) | actually arjun has to make a lead of 600 m , because when arjun will be 600 m ahead of bhishma , they will be together again as a person when completes the total length it starts retracing he same path and thus arjun and bhishma can be together again . since , they make a difference of 10 m in 1 second . so , he will create 600 m difference in 60 second . d | physics |
math_qa__kYsun77bRWlU6FCo | If a certain computer is capable of printing 4700 monthly credit card bills per hour, while a new model is capable of printing at a rate of 6800 per hour, the old model will take approximately how much longer than the new model to print 10000 bills? Select:
A) 19 mins B) 29 mins C) 39 mins D) 38 mins E) 37 mins | <gadget id="calculator">10_000 / 4_700</gadget>
<output>100/47 = around 2.12766</output>
<gadget id="calculator">10_000 / 6_800</gadget>
<output>25/17 = around 1.470588</output>
<gadget id="calculator">(100/47) - (25/17)</gadget>
<output>525/799 = around 0.657071</output>
<gadget id="calculator">(525/799) * 60</gadget>
<output>31_500/799 = around 39.42428</output>
<result>C</result> | C | 39 | If a certain computer is capable of printing 4700 monthly credit card bills per hour, while a new model is capable of printing at a rate of 6800 per hour, the old model will take approximately how much longer than the new model to print 10000 bills? | {
"A": "19 mins",
"B": "29 mins",
"C": "39 mins",
"D": "38 mins",
"E": "37 mins"
} | multiply(subtract(divide(10000, 4700), divide(10000, 6800)), const_60) | divide(n2,n0)|divide(n2,n1)|subtract(#0,#1)|multiply(#2,const_60) | old model ' s 1 hr work = 4700 new model ' s 1 hr work = 6800 old model ' time taken to print 10000 cards for 1 hr - - 4700 cards x - - 10000 x = 10000 / 4700 = 100 / 47 new model ' time taken to print 10000 cards for 1 hr - - 6800 cards y - - 10000 y = 10000 / 6800 = 100 / 68 x = 10000 / 4700 = 100 / 47 = 2 6 / 47 hr difference is 100 / 47 - 100 / 68 = 6800 - 4700 / ( 47 * 68 ) 2100 / 3196 = 0.66 hrs = > 39 minutes old model ll take 39 minutes longer to print 10000 cards than new model ans : 39 mins answer : c | general |
math_qa__K6KabU4sApIp0M6L | In a graduating class of 232 students, 144 took geometry and 119 took biology. What is the difference between the greatest possible number W and the smallest possible number of students that could have taken both geometry and biology?
Answers
A) 144 B) 119 C) 113 D) 88 E) 31 | <gadget id="calculator">144 + 119</gadget>
<output>263</output>
<gadget id="calculator">263 - 232</gadget>
<output>31</output>
<gadget id="calculator">119 - 31</gadget>
<output>88</output>
<result>D</result> | D | 88 | In a graduating class of 232 students, 144 took geometry and 119 took biology. What is the difference between the greatest possible number W and the smallest possible number of students that could have taken both geometry and biology? | {
"A": "144",
"B": "119",
"C": "113",
"D": "88",
"E": "31"
} | subtract(119, subtract(add(144, 119), 232)) | add(n1,n2)|subtract(#0,n0)|subtract(n2,#1)| | "official solution : first of all , notice that since 144 took geometry and 119 took biology , then the number of students who took both geometry and biology can not be greater than 119 . { total } = { geometry } + { biology } - { both } + { neither } ; 232 = 144 + 119 - { both } + { neither } ; { both } = 31 + { neither } . { both } is minimized when { neither } is 0 . in this case { both } = 31 . the greatest possible number w of students that could have taken both geometry and biology , is 119 . thus , the answer is 119 - 31 = 88 . answer : d ." | other |
math_qa__yauT2lsvZ8Kdhes2 | Rani bought more apples than oranges. She sells apples at ₹23 apiece and makes 15% profit. She sells oranges at ₹10 apiece and makes 25% profit. If she gets ₹653 after selling all the apples and oranges, find her profit percentage.
Choose the correct choice from the following answers.
A) 16.8 %
B) 17.4 %
C) 17.9 %
D) 18.5 %
E) 19.1 % | <gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<gadget id="calculator">20 * 21</gadget>
<output>420</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) + 1</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">10 / (5/4)</gadget>
<output>8</output>
<gadget id="calculator">15 + 2</gadget>
<output>17</output>
<gadget id="calculator">8 * 17</gadget>
<output>136</output>
<gadget id="calculator">420 + 136</gadget>
<output>556</output>
<gadget id="calculator">653 - 556</gadget>
<output>97</output>
<gadget id="calculator">97 / 556</gadget>
<output>97/556 = around 0.17446</output>
<gadget id="calculator">(97/556) * 100</gadget>
<output>2_425/139 = around 17.446043</output>
<result>B</result> | B | 17.4 | Rani bought more apples than oranges. She sells apples at ₹23 apiece and makes 15% profit. She sells oranges at ₹10 apiece and makes 25% profit. If she gets ₹653 after selling all the apples and oranges, find her profit percentage. | {
"A": "16.8 %",
"B": "17.4 %",
"C": "17.9 %",
"D": "18.5 %",
"E": "19.1 %"
} | multiply(divide(subtract(653, add(multiply(multiply(const_2, 10), add(multiply(const_2, 10), const_1)), multiply(divide(10, add(divide(25, const_100), const_1)), add(15, const_2)))), add(multiply(multiply(const_2, 10), add(multiply(const_2, 10), const_1)), multiply(divide(10, add(divide(25, const_100), const_1)), add(15, const_2)))), const_100) | add(n1,const_2)|divide(n3,const_100)|multiply(n2,const_2)|add(#2,const_1)|add(#1,const_1)|divide(n2,#4)|multiply(#3,#2)|multiply(#0,#5)|add(#6,#7)|subtract(n4,#8)|divide(#9,#8)|multiply(#10,const_100)| | "given : selling price of an apple = 23 - - > cost price = 23 / 1.15 = 20 selling price of an orange = 10 - - > cost price = 10 / 1.25 = 8 a > o 23 * ( a ) + 10 * ( o ) = 653 653 - 23 * ( a ) has to be divisible by 10 - - > units digit has to be 0 values of a can be 1 , 11 , 21 , 31 , . . . . - - > 1 can not be the value between 11 and 21 , if a = 11 , o = 30 - - > not possible if a = 21 , o = 17 - - > possible cost price = 20 * 21 + 8 * 17 = 420 + 136 = 556 profit = 653 - 556 = 97 profit % = ( 97 / 556 ) * 100 = 17.4 % answer : b" | gain |
math_qa__z1v3gEjBfSDQHJDx | A student took 6 courses last year and received an average (arithmetic mean) grade of 100 points. The year before, the student took 5 courses and received an average grade of 70 points. To the nearest tenth of a point, what was the student’s average grade for the entire two-year period? Choose the correct option: A) 79 B) 89 C) 95 D) 86.36 E) 97.2 | <gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">5 * 70</gadget>
<output>350</output>
<gadget id="calculator">600 + 350</gadget>
<output>950</output>
<gadget id="calculator">6 + 5</gadget>
<output>11</output>
<gadget id="calculator">950 / 11</gadget>
<output>950/11 = around 86.363636</output>
<gadget id="calculator">floor(950/11)</gadget>
<output>86</output>
<result>D</result> | D | 86.36 | A student took 6 courses last year and received an average (arithmetic mean) grade of 100 points. The year before, the student took 5 courses and received an average grade of 70 points. To the nearest tenth of a point, what was the student’s average grade for the entire two-year period? | {
"A": "79",
"B": "89",
"C": "95",
"D": "86.36",
"E": "97.2"
} | floor(divide(add(multiply(6, 100), multiply(5, 70)), add(6, 5))) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)|floor(#4)| | "let the 6 courses that were taken last year be a 1 , a 2 , a 3 , a 4 , a 5 , a 6 a 1 + a 2 + a 3 + a 4 + a 5 + a 6 = 100 * 6 = 600 the year before , the 5 courses be b 1 , b 2 , b 3 , b 4 , b 5 b 1 + b 2 + b 3 + b 4 + b 5 = 70 * 5 = 350 student ' s average = ( 600 + 350 ) / 11 = 86.36 answer d" | general |
math_qa__GaTB1Qhldd7NmkH9 | If M:N is 3:9 and N:P is 9:12 then M:P is equal to
Choose the correct option.
A) 1 : 5 B) 1 : 4 C) 1 : 6 D) 1 : 8 E) 1 : 7 | <gadget id="calculator">3 / 12</gadget>
<output>1/4 = around 0.25</output>
<result>B</result> | B | 0.25 | If M:N is 3:9 and N:P is 9:12 then M:P is equal to | {
"A": "1 : 5",
"B": "1 : 4",
"C": "1 : 6",
"D": "1 : 8",
"E": "1 : 7"
} | divide(3, 12) | divide(n0,n3)| | "the two ratios given are having the same number 9 for n in both the ratios . hence - m : n = 3 : 9 n : p = 9 : 12 = > m : p = 3 : 12 = > 1 : 4 answer b" | physics |
math_qa__16S7qeGoXicbt5lf | The ration of the number of boys and girls in a college is 7:8. If the percentage is increase in the number of boys and girls be 20% and 10% respectively. What will be the new ration? Choose one.
A) 5 : 7 B) 15 : 21 C) 21 : 22 D) 13 : 17 E) 23 : 42 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) + 1</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">7 * (6/5)</gadget>
<output>42/5 = around 8.4</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(1/10) + 1</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">8 * (11/10)</gadget>
<output>44/5 = around 8.8</output>
<gadget id="calculator">(42/5) / (44/5)</gadget>
<output>21/22 = around 0.954545</output>
<result>C</result> | C | 0.954545 | The ration of the number of boys and girls in a college is 7:8. If the percentage is increase in the number of boys and girls be 20% and 10% respectively. What will be the new ration? | {
"A": "5 : 7",
"B": "15 : 21",
"C": "21 : 22",
"D": "13 : 17",
"E": "23 : 42"
} | divide(multiply(7, add(divide(20, const_100), const_1)), multiply(8, add(divide(10, const_100), const_1))) | divide(n2,const_100)|divide(n3,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(n0,#2)|multiply(n1,#3)|divide(#4,#5) | let the number of boys and girls be 7 x and 8 x their increased number is 120 % of 7 x and 110 % of 8 x 7 x * 120 / 100 and 8 x * 110 / 100 42 x / 5 and 44 x / 5 required ratio = 42 x / 5 : 44 x / 5 = 21 : 22 answer is c | gain |
math_qa__XvFNfw9hjteeFKxH | Of all the homes on Gotham Street, 1/3 are termite-ridden, and 2/5 of these are collapsing. What fraction of the homes are termite-ridden, but NOT collapsing?
Choose one:
A) 2 / 15
B) 3 / 15
C) 4 / 5
D) 2 / 5
E) 1 / 5 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">3 / 15</gadget>
<output>1/5 = around 0.2</output>
<result>E</result> | E | 0.2 | Of all the homes on Gotham Street, 1/3 are termite-ridden, and 2/5 of these are collapsing. What fraction of the homes are termite-ridden, but NOT collapsing? | {
"A": "2 / 15",
"B": "3 / 15",
"C": "4 / 5",
"D": "2 / 5",
"E": "1 / 5"
} | divide(add(1, 2), multiply(3, 5)) | add(n0,n2)|multiply(n1,n3)|divide(#0,#1) | let total homes be 15 termite ridden = 1 / 3 ( 15 ) = 5 termite ridden and collapsing = 2 / 5 ( 5 ) = 2 thus homes that are termite ridden , but not collapsing = 5 - 2 = 3 thus required ratio = 3 / 15 = 1 / 5 answer e | general |
math_qa__XX3muYs6GSVJ3lzi | A certain mixture of nuts consists of 5 parts almonds to 1 parts walnuts, by weight. What is the number of pounds of almonds in 140 pounds of the mixture ? Select the correct option
A) 116
B) 84
C) 40
D) 28
E) 20 | <gadget id="calculator">5 * 140</gadget>
<output>700</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">700 / 6</gadget>
<output>350/3 = around 116.666667</output>
<result>A</result> | A | 116 | A certain mixture of nuts consists of 5 parts almonds to 1 parts walnuts, by weight. What is the number of pounds of almonds in 140 pounds of the mixture ? | {
"A": "116",
"B": "84",
"C": "40",
"D": "28",
"E": "20"
} | divide(multiply(5, 140), add(5, 1)) | add(n0,n1)|multiply(n0,n2)|divide(#1,#0)| | "almonds : walnuts = 5 : 1 total mixture has 6 parts in a 140 pound mixture , almonds are 5 / 6 ( total mixture ) = 5 / 6 * 140 = 116 pounds answer ( a )" | general |
math_qa__8iZQC8yv4bsEcSgz | A certain number of workers can do a work in 45 days. If there were 10 workers more it could be finished in 10 days less. How many workers are there? Choose the correct choice from the following choices.
A) 25
B) 30
C) 28
D) 24
E) 35 | <gadget id="calculator">45 - 10</gadget>
<output>35</output>
<gadget id="calculator">35 * 10</gadget>
<output>350</output>
<gadget id="calculator">45 - 35</gadget>
<output>10</output>
<gadget id="calculator">350 / 10</gadget>
<output>35</output>
<result>E</result> | E | 35 | A certain number of workers can do a work in 45 days. If there were 10 workers more it could be finished in 10 days less. How many workers are there? | {
"A": "25",
"B": "30",
"C": "28",
"D": "24",
"E": "35"
} | divide(multiply(subtract(45, 10), 10), subtract(45, subtract(45, 10))) | subtract(n0,n1)|multiply(n1,#0)|subtract(n0,#0)|divide(#1,#2)| | "number of workers = 10 * ( 45 - 10 ) / 10 = 35 answer is e" | physics |
math_qa__UcpEZke2r5oDMHJg | Sheela deposits Rs. 4500 in bank savings account. If this is 28% of her monthly income. What is her monthly income in? Choose the correct choice: A) 22000 B) 27000 C) 16071 D) 16789 E) none of these | <gadget id="calculator">4_500 * 100</gadget>
<output>450_000</output>
<gadget id="calculator">450_000 / 28</gadget>
<output>112_500/7 = around 16_071.428571</output>
<result>C</result> | C | 16,071 | Sheela deposits Rs. 4500 in bank savings account. If this is 28% of her monthly income. What is her monthly income in? | {
"A": "22000",
"B": "27000",
"C": "16071",
"D": "16789",
"E": "none of these"
} | divide(multiply(4500, const_100), 28) | multiply(n0,const_100)|divide(#0,n1)| | "explanation : 28 % of income = rs . 4500 100 % of income = 4500 x 100 / 28 = rs . 16071 answer : c" | gain |
math_qa__b883tsQsQQivOj9Z | Two tests had the same maximum mark. The pass percentages in the first and the second test were 40% and 45% respectively. A candidate scored 216 marks in the second test and failed by 75 marks in that test. Find the pass mark in the first test? Choose the correct choice:
A) 768 B) 243 C) 246 D) 288 E) 224 | <gadget id="calculator">216 + 75</gadget>
<output>291</output>
<result>D</result> | D | 288 | Two tests had the same maximum mark. The pass percentages in the first and the second test were 40% and 45% respectively. A candidate scored 216 marks in the second test and failed by 75 marks in that test. Find the pass mark in the first test? | {
"A": "768",
"B": "243",
"C": "246",
"D": "288",
"E": "224"
} | add(216, 75) | add(n2,n3) | let the maximum mark in each test be m . the candidate failed by 75 marks in the second test . pass mark in the second test = 249 + 75 = 324 45 / 100 m = 324 pass mark in the first test = 40 / 100 m = 40 / 45 * 324 = 288 . answer : d | gain |
math_qa__VjXNkAqgUrrLuf1Z | Simplify: 0.4*0.5+0.3*0.2 Select.
A) 0.52 B) 0.26 C) 0.48 D) 0.64 E) 0.46 | <gadget id="calculator">0.4 * 0.5</gadget>
<output>0.2</output>
<gadget id="calculator">0.3 * 0.2</gadget>
<output>0.06</output>
<gadget id="calculator">0.2 + 0.06</gadget>
<output>0.26</output>
<result>B</result> | B | 0.26 | Simplify: 0.4*0.5+0.3*0.2 | {
"A": "0.52",
"B": "0.26",
"C": "0.48",
"D": "0.64",
"E": "0.46"
} | add(multiply(0.4, 0.5), multiply(0.3, 0.2)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1)| | "given exp . = 0.4 * 0.5 + ( 0.3 * 0.2 ) = 0.2 + 0.06 = 0.26 answer is b ." | general |
math_qa__VHJq0CxzsfD4ijGt | Elena purchased Brand X pens for $4.00 apiece and brand Y for $2.80 apiece. If Elena purchased a total of 12 of these pens for $40.00, how many brand X pens did she purchase? Choose the correct choice from the following options
A) 4
B) 5
C) 6
D) 7
E) 8 | <gadget id="calculator">4 * 12</gadget>
<output>48</output>
<gadget id="calculator">48 - 40</gadget>
<output>8</output>
<result>E</result> | E | 8 | Elena purchased Brand X pens for $4.00 apiece and brand Y for $2.80 apiece. If Elena purchased a total of 12 of these pens for $40.00, how many brand X pens did she purchase? | {
"A": "4",
"B": "5",
"C": "6",
"D": "7",
"E": "8"
} | subtract(multiply(4.00, 12), 40.00) | multiply(n0,n2)|subtract(#0,n3)| | "4 x + 2.8 y = 42 - - > multiply by 2.5 ( to get the integers ) - - > 10 x + 7 y = 105 - - > only one positive integers solutions x = 8 and y = 5 ( how to solve : 7 y must have the last digit of 5 in order the last digit of the sum to be 5 ) . answer : e ." | general |
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