id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__0s3Su7Ps5Q8ubo0l | Jacob is now 13 years younger than Michael. If 9 years from now Michael will be twice as old as Jacob, how old will Jacob be in 4 years?
Choose the correct choice from the following choices: A) 8 B) 7 C) 15 D) 21 E) 25 | <gadget id="calculator">13 + 9</gadget>
<output>22</output>
<gadget id="calculator">2 * 9</gadget>
<output>18</output>
<gadget id="calculator">22 - 18</gadget>
<output>4</output>
<gadget id="calculator">4 + 4</gadget>
<output>8</output>
<result>A</result> | A | 8 | Jacob is now 13 years younger than Michael. If 9 years from now Michael will be twice as old as Jacob, how old will Jacob be in 4 years? | {
"A": "8",
"B": "7",
"C": "15",
"D": "21",
"E": "25"
} | add(4, subtract(add(13, 9), multiply(const_2, 9))) | add(n0,n1)|multiply(n1,const_2)|subtract(#0,#1)|add(n2,#2)| | "jacob = x years , michael = x + 13 years 9 years from now , 2 ( x + 9 ) = x + 22 2 x + 18 = x + 22 x = 4 x + 4 = 8 years answer a" | general |
math_qa__vonkJHkKcjQHscJI | A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 86.49, the number of the member is the group is: Choose the correct option.
A) 93 B) 67 C) 77 D) 87 E) 97 | <gadget id="calculator">86.49 * 100</gadget>
<output>8_649</output>
<gadget id="calculator">8_649 ** (1/2)</gadget>
<output>93</output>
<result>A</result> | A | 93 | A group of students decided to collect as many paise from each member of group as is the number of members. If the total collection amounts to Rs. 86.49, the number of the member is the group is: | {
"A": "93",
"B": "67",
"C": "77",
"D": "87",
"E": "97"
} | sqrt(multiply(86.49, const_100)) | multiply(n0,const_100)|sqrt(#0)| | "money collected = ( 86.49 x 100 ) paise = 8649 paise numbers of members = 8649 squareroot = 93 answer a" | general |
math_qa__56aUA8QUPtaA1x6h | The average of 65 numbers is 40. If two numbers, 83 and 30 are discarded, then the average of the remaining numbers is nearly Choose one:
A) 28.32
B) 39
C) 38.78
D) 29
E) 39.47 | <gadget id="calculator">65 * 40</gadget>
<output>2_600</output>
<gadget id="calculator">83 + 30</gadget>
<output>113</output>
<gadget id="calculator">2_600 - 113</gadget>
<output>2_487</output>
<gadget id="calculator">65 - 2</gadget>
<output>63</output>
<gadget id="calculator">2_487 / 63</gadget>
<output>829/21 = around 39.47619</output>
<result>E</result> | E | 39.47 | The average of 65 numbers is 40. If two numbers, 83 and 30 are discarded, then the average of the remaining numbers is nearly | {
"A": "28.32",
"B": "39",
"C": "38.78",
"D": "29",
"E": "39.47"
} | divide(subtract(multiply(65, 40), add(83, 30)), subtract(65, const_2)) | add(n2,n3)|multiply(n0,n1)|subtract(n0,const_2)|subtract(#1,#0)|divide(#3,#2) | explanation : total sum of 63 numbers = ( 65 * 40 ) - ( 83 + 30 ) = 2600 - 113 = 2487 average = 2487 / 63 = 39.47 answer : e | general |
math_qa__rfVL3GFjkbz9XKkh | A+B+C+D=D+E+F+G=G+H+I=17 given A=4. Find value of G and H?
Choose the correct choice from the following answers: A) 29 B) 39 C) 19 D) 49 E) 59 | <gadget id="calculator">17 * 3</gadget>
<output>51</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 + 1</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 9</gadget>
<output>45</output>
<gadget id="calculator">51 - 45</gadget>
<output>6</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">5 + 4</gadget>
<output>9</output>
<gadget id="calculator">10 + 9</gadget>
<output>19</output>
<result>C</result> | C | 19 | A+B+C+D=D+E+F+G=G+H+I=17 given A=4. Find value of G and H? | {
"A": "29",
"B": "39",
"C": "19",
"D": "49",
"E": "59"
} | add(const_10, add(subtract(subtract(multiply(17, const_3), multiply(divide(add(multiply(const_3, const_3), const_1), const_2), multiply(const_3, const_3))), const_1), 4)) | multiply(n0,const_3)|multiply(const_3,const_3)|add(#1,const_1)|divide(#2,const_2)|multiply(#3,#1)|subtract(#0,#4)|subtract(#5,const_1)|add(n1,#6)|add(#7,const_10) | a + b + c + d = 17 4 + 2 + 6 + 5 = 17 d = 5 d + e + f + g = 17 5 + 3 + 8 + 1 = 17 g = 1 g + h + i = 17 1 + 9 + 7 = 17 g = 1 , h = 9 . answer : c | general |
math_qa__KfDMEYThMUfD8SwS | When a merchant imported a certain item, she paid a 7 percent import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that the merchant paid was $111.30, what was the total value of the item?
Answers.
A) $ 2380 B) $ 2590 C) $ 2760 D) $ 2940 E) $ 3150 | <gadget id="calculator">7 / 100</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">111.3 / (7/100)</gadget>
<output>1_590</output>
<gadget id="calculator">1_000 + 1_590</gadget>
<output>2_590</output>
<result>B</result> | B | 2,590 | When a merchant imported a certain item, she paid a 7 percent import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that the merchant paid was $111.30, what was the total value of the item? | {
"A": "$ 2380",
"B": "$ 2590",
"C": "$ 2760",
"D": "$ 2940",
"E": "$ 3150"
} | add(1,000, divide(111.30, divide(7, const_100))) | divide(n0,const_100)|divide(n2,#0)|add(#1,n1)| | "let x be the value of the item . 0.07 * ( x - 1000 ) = 111.30 x = 2590 the answer is b ." | general |
math_qa__wu8cDZecFdKWZ5BJ | 3 candidates in an election and received 2500, 5000 and 20000 votes respectively. What % of the total votes did the winningcandidate got in that election?
Select the correct option: A) 72.72 % B) 50 % C) 57.57 % D) 60 % E) 65 % | <gadget id="calculator">2_500 + 5_000</gadget>
<output>7_500</output>
<gadget id="calculator">7_500 + 20_000</gadget>
<output>27_500</output>
<gadget id="calculator">20_000 / 27_500</gadget>
<output>8/11 = around 0.727273</output>
<gadget id="calculator">(8/11) * 100</gadget>
<output>800/11 = around 72.727273</output>
<result>A</result> | A | 72.72 | 3 candidates in an election and received 2500, 5000 and 20000 votes respectively. What % of the total votes did the winningcandidate got in that election? | {
"A": "72.72 %",
"B": "50 %",
"C": "57.57 %",
"D": "60 %",
"E": "65 %"
} | multiply(divide(20000, add(add(2500, 5000), 20000)), const_100) | add(n1,n2)|add(n3,#0)|divide(n3,#1)|multiply(#2,const_100)| | "total number of votes polled = ( 2500 + 5000 + 20000 ) = 27500 so , required percentage = 20000 / 27500 * 100 = 72.72 % a" | gain |
math_qa__LROKbUiPCUkCgk9O | In a Lake, there is a patch of lily pads. Every day, the patch doubles in size. It takes 25 days for the patch to cover the entire lake, how many days would it take the patch to cover half of the lake? Select
A) 36
B) 2 ^ 4 * 3
C) 24
D) 38
E) 47 | <gadget id="calculator">25 - 1</gadget>
<output>24</output>
<result>C</result> | C | 24 | In a Lake, there is a patch of lily pads. Every day, the patch doubles in size. It takes 25 days for the patch to cover the entire lake, how many days would it take the patch to cover half of the lake? | {
"A": "36",
"B": "2 ^ 4 * 3",
"C": "24",
"D": "38",
"E": "47"
} | subtract(25, const_1) | subtract(n0,const_1)| | "so 24 days answer c = 24" | physics |
math_qa__q9NnTnCaKjReds36 | A 30% alcohol mixture is added to a 50% alcohol mixture to form a 10 litre mixture of 45% alcohol. How much of the 30% mixture was used?
Pick one
A) 1.5 liters
B) 2.5 liters
C) 3.5 liters
D) 4.5 liters
E) 5.5 liters | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 10</gadget>
<output>5</output>
<gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<result>B</result> | B | 2.5 | A 30% alcohol mixture is added to a 50% alcohol mixture to form a 10 litre mixture of 45% alcohol. How much of the 30% mixture was used? | {
"A": "1.5 liters",
"B": "2.5 liters",
"C": "3.5 liters",
"D": "4.5 liters",
"E": "5.5 liters"
} | divide(multiply(divide(50, const_100), 10), const_2) | divide(n1,const_100)|multiply(n2,#0)|divide(#1,const_2) | solution a = 50 % solution solution b = 30 % solution 30 % - 45 % = 15 % solution b 50 % - 45 % = 5 % solution a so the ratio is 3 : 1 for 30 % : 50 % solutions 3 / 4 * 10 liter = 7.5 for 30 % solution and 2.5 for 50 % solution . . answer : b | general |
math_qa__npBkfKmF5e5Q2kYZ | If the charge of staying in a student youth hostel $18.00/day for the first week, and $11.00/day for each additional week, How much does it cost to stay for 23 days?
Choose the most appropriate option
A) $ 160 B) $ 176 C) $ 282 D) $ 302 E) $ 286 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">18 * 7</gadget>
<output>126</output>
<gadget id="calculator">23 - 7</gadget>
<output>16</output>
<gadget id="calculator">11 * 16</gadget>
<output>176</output>
<gadget id="calculator">126 + 176</gadget>
<output>302</output>
<result>D</result> | D | 302 | If the charge of staying in a student youth hostel $18.00/day for the first week, and $11.00/day for each additional week, How much does it cost to stay for 23 days? | {
"A": "$ 160",
"B": "$ 176",
"C": "$ 282",
"D": "$ 302",
"E": "$ 286"
} | add(multiply(18.00, add(const_3, const_4)), multiply(11.00, subtract(23, add(const_3, const_4)))) | add(const_3,const_4)|multiply(n0,#0)|subtract(n2,#0)|multiply(n1,#2)|add(#1,#3)| | "total number of days of stay = 23 charge of staying in first week = 18 * 7 = 126 $ charge of staying for additional days = ( 23 - 7 ) * 11 = 16 * 11 = 176 $ total charge = 126 + 176 = 302 $ answer d" | general |
math_qa__VMqSvwKywCTMYYdJ | Sides of a rectangular park are in the ratio 3: 2 and its area is 5766 sq m, the cost of fencing it at 50 ps per meter is?
Answers
A) 287 B) 1287 C) 125 D) 155 E) 271 | <gadget id="calculator">5_766 * 2</gadget>
<output>11_532</output>
<gadget id="calculator">11_532 / 3</gadget>
<output>3_844</output>
<gadget id="calculator">3_844 ** (1/2)</gadget>
<output>62</output>
<gadget id="calculator">5_766 / 62</gadget>
<output>93</output>
<gadget id="calculator">2 * (62 + 93)</gadget>
<output>310</output>
<gadget id="calculator">50 * 310</gadget>
<output>15_500</output>
<gadget id="calculator">15_500 / 100</gadget>
<output>155</output>
<result>D</result> | D | 155 | Sides of a rectangular park are in the ratio 3: 2 and its area is 5766 sq m, the cost of fencing it at 50 ps per meter is? | {
"A": "287",
"B": "1287",
"C": "125",
"D": "155",
"E": "271"
} | divide(multiply(50, rectangle_perimeter(sqrt(divide(multiply(5766, 2), 3)), divide(5766, sqrt(divide(multiply(5766, 2), 3))))), const_100) | multiply(n1,n2)|divide(#0,n0)|sqrt(#1)|divide(n2,#2)|rectangle_perimeter(#3,#2)|multiply(n3,#4)|divide(#5,const_100)| | "3 x * 2 x = 5766 = > x = 31 2 ( 93 + 62 ) = 310 m 310 * 1 / 2 = rs . 155 answer : d" | physics |
math_qa__lkHKN100dfysa92A | Find the smallest number of 6 digits which is exactly divisible by 111 Pick one: A) 100011 B) 111111 C) 101111 D) 1011111 E) 211111 | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">10 * 10_000</gadget>
<output>100_000</output>
<gadget id="calculator">100_000 - 100</gadget>
<output>99_900</output>
<gadget id="calculator">99_900 + 111</gadget>
<output>100_011</output>
<result>A</result> | A | 100,011 | Find the smallest number of 6 digits which is exactly divisible by 111 | {
"A": "100011",
"B": "111111",
"C": "101111",
"D": "1011111",
"E": "211111"
} | add(subtract(multiply(const_10, multiply(const_100, const_100)), const_100), 111) | multiply(const_100,const_100)|multiply(#0,const_10)|subtract(#1,const_100)|add(n1,#2)| | "smallest number of 6 digits is 100000 . on dividing 100000 by 111 , we get 100 as remainder . number to be added = ( 111 - 100 ) - 11 . hence , required number = 100011 answer a 100011" | general |
math_qa__zJIycRKwJfODyYTj | kareem is 3 times as old as his son . after 10 years , the sum of their ages will be 76 years . find their present ages . Choose the most appropriate option
A) 13 B) 14 C) 15 D) 16 E) 17 | <gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">76 - 20</gadget>
<output>56</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">56 / 4</gadget>
<output>14</output>
<result>B</result> | B | 14 | kareem is 3 times as old as his son . after 10 years , the sum of their ages will be 76 years . find their present ages . | {
"A": "13",
"B": "14",
"C": "15",
"D": "16",
"E": "17"
} | divide(subtract(76, multiply(10, const_2)), add(3, const_1)) | add(n0,const_1)|multiply(n1,const_2)|subtract(n2,#1)|divide(#2,#0) | sol . let the present age of kareem ’ s son be x years . then , kareem ’ s age = 3 x years after 10 years , kareem ’ s age = 3 x + 10 years and kareem ’ s son ’ s age = x + 10 years ∴ ( 3 x + 10 ) + ( x + 10 ) = 76 = > 4 x = 56 = > x = 14 ∴ kareem ’ s present age = 3 x = 3 × 14 = 42 years kareem ’ s son ’ s age = x = 14 years . answer b | general |
math_qa__aJwK1R2dOqFRO4a2 | What is the greatest value of x such that 4^x is a factor of 21! ? Choose the correct answer.
A) 5 B) 6 C) 3 D) 2 E) 4 | <gadget id="calculator">21 - 1</gadget>
<output>20</output>
<gadget id="calculator">20 / 4</gadget>
<output>5</output>
<gadget id="calculator">5 + 1</gadget>
<output>6</output>
<result>B</result> | B | 6 | What is the greatest value of x such that 4^x is a factor of 21! ? | {
"A": "5",
"B": "6",
"C": "3",
"D": "2",
"E": "4"
} | add(divide(subtract(21, const_1), 4), const_1) | subtract(n1,const_1)|divide(#0,n0)|add(#1,const_1) | pretty simple , really . if m = 6 , then 4 m = 24 , which is 12 x 2 , both of which are included in 21 ! since 6 is the largest number here , its the answer . answer is b | other |
math_qa__MxRcbzg4RDbdwtw5 | If 8 spiders make 8 webs in 8 days, then 1 spider will make 1 web in how many days?
Choose the correct choice from the following answers.
A) 7 B) 6 C) 5 D) 8 E) 3 | <gadget id="calculator">1 * 8</gadget>
<output>8</output>
<result>D</result> | D | 8 | If 8 spiders make 8 webs in 8 days, then 1 spider will make 1 web in how many days? | {
"A": "7",
"B": "6",
"C": "5",
"D": "8",
"E": "3"
} | multiply(1, 8) | multiply(n0,n3)| | "let the required number days be x . less spiders , more days ( indirect proportion ) less webs , less days ( direct proportion ) spiders 1 : 8 webs 8 : 1 1 x 8 x x = 8 x 1 x 8 = > x = 8 answer is d" | physics |
math_qa__lGkcqpXuSdgroX3C | Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 25 percent alcohol by volume? Options: A) 250 / 3 B) 500 / 3 C) 400 D) 480 E) 600 | <gadget id="calculator">25 - 10</gadget>
<output>15</output>
<gadget id="calculator">30 - 25</gadget>
<output>5</output>
<gadget id="calculator">15 / 5</gadget>
<output>3</output>
<gadget id="calculator">3 * 200</gadget>
<output>600</output>
<result>E</result> | E | 600 | Solution X is 10 percent alcohol by volume, and solution Y is 30 percent alcohol by volume. How many milliliters of solution Y must be added to 200 milliliters of solution X to create a solution that is 25 percent alcohol by volume? | {
"A": "250 / 3",
"B": "500 / 3",
"C": "400",
"D": "480",
"E": "600"
} | multiply(divide(subtract(25, 10), subtract(30, 25)), 200) | subtract(n3,n0)|subtract(n1,n3)|divide(#0,#1)|multiply(n2,#2) | we know that x is 10 % , y is 30 % and w . avg = 25 % . what does this mean with respect to w . avg technique ? w . avg is 1 portion away from y and 3 portion away from x so for every 1 portion of x we will have to add 3 portions of y . if x = 200 then y = 600 answer : e | general |
math_qa__wN8T9ThGr3dV1Pui | The star running back on our football team got most of his total yardage
running. The rest was catching passes. He caught passes for 60 yards.
His total yardage was 150 yards. The running back for the other team
got 200 yards. How many yards did the star running back on our football
team get running? Choose the correct choice
A) 50 yards B) 60 yards C) 70 yards D) 80 yards E) 90 yards | <gadget id="calculator">150 - 60</gadget>
<output>90</output>
<result>E</result> | E | 90 | The star running back on our football team got most of his total yardage
running. The rest was catching passes. He caught passes for 60 yards.
His total yardage was 150 yards. The running back for the other team
got 200 yards. How many yards did the star running back on our football
team get running? | {
"A": "50 yards",
"B": "60 yards",
"C": "70 yards",
"D": "80 yards",
"E": "90 yards"
} | subtract(150, 60) | subtract(n1,n0) | . the other team is extra information . 150 – 60 = 90 he got 90 yards running . correct answer e | general |
math_qa__xaLwiPQFXpecG8Yr | In what ratio must rice of Rs.30 per kg be mixed with rice of Rs.56per kg so that cost of mixture is Rs.35 per kg? Choose the correct choice from the following answers: A) 28 : 15 B) 6 : 7 C) 7 : 6 D) 5 : 21 E) 21 : 5 | <gadget id="calculator">35 - 56</gadget>
<output>-21</output>
<gadget id="calculator">30 - 56</gadget>
<output>-26</output>
<gadget id="calculator">(-21) / (-26)</gadget>
<output>21/26 = around 0.807692</output>
<gadget id="calculator">1 - (21/26)</gadget>
<output>5/26 = around 0.192308</output>
<gadget id="calculator">(21/26) / (5/26)</gadget>
<output>21/5 = around 4.2</output>
<result>E</result> | E | 4.2 | In what ratio must rice of Rs.30 per kg be mixed with rice of Rs.56per kg so that cost of mixture is Rs.35 per kg? | {
"A": "28 : 15",
"B": "6 : 7",
"C": "7 : 6",
"D": "5 : 21",
"E": "21 : 5"
} | divide(divide(subtract(35, 56), subtract(30, 56)), subtract(const_1, divide(subtract(35, 56), subtract(30, 56)))) | subtract(n2,n1)|subtract(n0,n1)|divide(#0,#1)|subtract(const_1,#2)|divide(#2,#3)| | "( 35 - 56 ) / ( 30 - 35 ) = 6 / 2 = 21 : 5 answer : e" | other |
math_qa__F8imGCjvuRQsl541 | Two cars start from the opposite places of a main road, 113 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point? Choose the correct choice from the following options.
A) 65 B) 38 C) 20 D) 28 E) 21 | <gadget id="calculator">113 - 35</gadget>
<output>78</output>
<gadget id="calculator">25 + 25</gadget>
<output>50</output>
<gadget id="calculator">78 - 50</gadget>
<output>28</output>
<result>D</result> | D | 28 | Two cars start from the opposite places of a main road, 113 km apart. First car runs for 25 km and takes a right turn and then runs 15 km. It then turns left and then runs for another 25 km and then takes the direction back to reach the main road. In the mean time, due to minor break down the other car has run only 35 km along the main road. What would be the distance between two cars at this point? | {
"A": "65",
"B": "38",
"C": "20",
"D": "28",
"E": "21"
} | subtract(subtract(113, 35), add(25, 25)) | add(n1,n1)|subtract(n0,n4)|subtract(#1,#0)| | answer : d ) 28 km | physics |
math_qa__3sDG0P8gk1rubEQn | A straight line in the xy- plane has a slope of 4 and a y-intercept of 4. On this line, what is the x-coordinate of the point whose y-coordinate is 800 ? Select the correct option
A) 233 B) 299 C) 333 D) 199 E) 339 | <gadget id="calculator">800 - 4</gadget>
<output>796</output>
<gadget id="calculator">796 / 4</gadget>
<output>199</output>
<result>D</result> | D | 199 | A straight line in the xy- plane has a slope of 4 and a y-intercept of 4. On this line, what is the x-coordinate of the point whose y-coordinate is 800 ? | {
"A": "233",
"B": "299",
"C": "333",
"D": "199",
"E": "339"
} | divide(subtract(800, 4), 4) | subtract(n2,n0)|divide(#0,n0) | eq of line = y = mx + c m = 4 , c = 4 y = 4 x + 4 , substitute y by 800 as given in question . 800 = 4 x + 4 , x = 199 . correct option is d | general |
math_qa__vjr2RVvyc4Rr3905 | A shop owner sells 25mtr of cloth and gains SP of 10 mtrs. Find the gain %? Pick one: A) 30 % B) 40 % C) 50 % D) 66.67 % E) 70 % | <gadget id="calculator">25 - 10</gadget>
<output>15</output>
<gadget id="calculator">10 / 15</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(2/3) * 100</gadget>
<output>200/3 = around 66.666667</output>
<result>D</result> | D | 66.67 | A shop owner sells 25mtr of cloth and gains SP of 10 mtrs. Find the gain %? | {
"A": "30 %",
"B": "40 %",
"C": "50 %",
"D": "66.67 %",
"E": "70 %"
} | multiply(divide(10, subtract(25, 10)), const_100) | subtract(n0,n1)|divide(n1,#0)|multiply(#1,const_100)| | "here , selling price of 10 m cloth is obtained as profit . profit of 10 m cloth = ( s . p . of 25 m cloth ) – ( c . p . of 25 m cloth ) selling price of 15 m cloth = selling price of 25 m of cloth let cost of each metre be rs . 100 . therefore , cost price of 15 m cloth = rs . 1500 and s . p . of 15 m cloth = rs . rs . 2500 profit % = 10 / 15 × 100 = 66.67 % profit of 66.67 % was made by the merchant . d" | gain |
math_qa__fr3v5bulaohY1nVZ | What number has a 150:1 ratio to the number 2? Pick
A) 130 B) 300 C) 200 D) 30 E) 75 | <gadget id="calculator">2 * 150</gadget>
<output>300</output>
<result>B</result> | B | 300 | What number has a 150:1 ratio to the number 2? | {
"A": "130",
"B": "300",
"C": "200",
"D": "30",
"E": "75"
} | multiply(2, 150) | multiply(n0,n2)| | "150 : 1 = x : 2 x = 150 * 2 x = 300 answer : b" | other |
math_qa__UBWZIF0gexEAxL9K | On a Saturday night, each of the rooms at a certain motel was rented for either $40 or $60. If 10 of the rooms that were rented for $60 had instead been rented for $40, then the total rent the motel charged for that night would have been reduced by 50 percent. What was the total rent the motel actually charged for that night ? Pick one.
A) $ 400 B) $ 800 C) $ 1,000 D) $ 1,600 E) $ 2,400 | <gadget id="calculator">60 - 40</gadget>
<output>20</output>
<gadget id="calculator">10 * 20</gadget>
<output>200</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">200 / (1/2)</gadget>
<output>400</output>
<result>A</result> | A | 400 | On a Saturday night, each of the rooms at a certain motel was rented for either $40 or $60. If 10 of the rooms that were rented for $60 had instead been rented for $40, then the total rent the motel charged for that night would have been reduced by 50 percent. What was the total rent the motel actually charged for that night ? | {
"A": "$ 400",
"B": "$ 800",
"C": "$ 1,000",
"D": "$ 1,600",
"E": "$ 2,400"
} | divide(multiply(10, subtract(60, 40)), divide(50, const_100)) | divide(n5,const_100)|subtract(n1,n0)|multiply(n2,#1)|divide(#2,#0)| | "let total rent the motel charge for all rooms = x if 10 rooms that were rented for 60 $ had instead been rented for 40 $ , then total difference in prices = 20 $ * 10 = 200 $ total rent the motel charged would have been reduced by 50 % . 5 x = 200 = > x = 400 answer a" | gain |
math_qa__DpJWgmgAaiBNPcdM | A sum fetched a total simple interest of Rs. 6016.75 at the rate of 8 p.c.p.a. in 5 years. What is the sum? Choose the correct choice from the following answers:
A) rs . 16241.875 B) rs . 15041.85 C) rs . 15401.875 D) rs . 15041.875 E) none of these | <gadget id="calculator">6_016.75 * 100</gadget>
<output>601_675</output>
<gadget id="calculator">601_675 / 8</gadget>
<output>601_675/8 = around 75_209.375</output>
<gadget id="calculator">(601_675/8) / 5</gadget>
<output>120_335/8 = around 15_041.875</output>
<result>D</result> | D | 15,041.875 | A sum fetched a total simple interest of Rs. 6016.75 at the rate of 8 p.c.p.a. in 5 years. What is the sum? | {
"A": "rs . 16241.875",
"B": "rs . 15041.85",
"C": "rs . 15401.875",
"D": "rs . 15041.875",
"E": "none of these"
} | divide(divide(multiply(6016.75, const_100), 8), 5) | multiply(n0,const_100)|divide(#0,n1)|divide(#1,n2)| | "explanation : principal = rs 100 x 6016.75 / 8 x 5 = rs . 601675 / 40 = rs . 15041.875 answer : option d" | gain |
math_qa__z2aiZrVLnDyu90Io | The owner of a furniture shop charges his customer 15% more than the cost price. If a customer paid Rs. 8325 for a computer table, then what was the cost price of the computer table? Pick: A) rs . 6725 B) rs . 7239.13 C) rs . 6908 D) rs . 6725 E) rs . 6728 | <gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">8_325 / (23/20)</gadget>
<output>166_500/23 = around 7_239.130435</output>
<result>B</result> | B | 7,239.13 | The owner of a furniture shop charges his customer 15% more than the cost price. If a customer paid Rs. 8325 for a computer table, then what was the cost price of the computer table? | {
"A": "rs . 6725",
"B": "rs . 7239.13",
"C": "rs . 6908",
"D": "rs . 6725",
"E": "rs . 6728"
} | divide(8325, add(const_1, divide(15, const_100))) | divide(n0,const_100)|add(#0,const_1)|divide(n1,#1)| | "cp = sp * ( 100 / ( 100 + profit % ) ) = 8325 ( 100 / 115 ) = rs . 7239.13 . answer : b" | gain |
math_qa__8aEouUhDstXmczch | A boat takes 19 hours for travelling downstream from point A to point B and coming back to a point C midway between A and B. If the velocity of the stream is 4 km/h and the speed of the boat in still water is 14 km/h, what is the distance between A and B? Choices
A) 200 km B) 180 km C) 160 km D) 220 km E) none of these | <gadget id="calculator">14 + 4</gadget>
<output>18</output>
<gadget id="calculator">1 / 18</gadget>
<output>1/18 = around 0.055556</output>
<gadget id="calculator">14 - 4</gadget>
<output>10</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/18) + (1/20)</gadget>
<output>19/180 = around 0.105556</output>
<gadget id="calculator">19 / (19/180)</gadget>
<output>180</output>
<result>B</result> | B | 180 | A boat takes 19 hours for travelling downstream from point A to point B and coming back to a point C midway between A and B. If the velocity of the stream is 4 km/h and the speed of the boat in still water is 14 km/h, what is the distance between A and B? | {
"A": "200 km",
"B": "180 km",
"C": "160 km",
"D": "220 km",
"E": "none of these"
} | divide(19, add(divide(const_1, add(14, 4)), divide(const_1, multiply(subtract(14, 4), const_2)))) | add(n1,n2)|subtract(n2,n1)|divide(const_1,#0)|multiply(#1,const_2)|divide(const_1,#3)|add(#2,#4)|divide(n0,#5)| | "speed of boat for downstream = 14 + 4 = 18 km / hr speed of boat for upstream = 14 – 4 = 10 km / hr distance = x x / 18 + ( x / 2 ) / 10 = 19 x = 180 km answer : b" | physics |
math_qa__PsgUwhSDIMyBMTET | If 73! has 16 zeroes at the end, how many zeroes will 80! have at the end? Choose the correct choice from the following options
A) 16 B) 17 C) 18 D) 19 E) 20 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">80 / 5</gadget>
<output>16</output>
<gadget id="calculator">16 + 3</gadget>
<output>19</output>
<result>D</result> | D | 19 | If 73! has 16 zeroes at the end, how many zeroes will 80! have at the end? | {
"A": "16",
"B": "17",
"C": "18",
"D": "19",
"E": "20"
} | add(divide(80, divide(const_10, const_2)), const_3) | divide(const_10,const_2)|divide(n2,#0)|add(#1,const_3) | prime factoring : you need a 2 and a 5 to make a 10 ( a ` ` zero ' ' ) , and there are tons of 2 ' s so let ' s skip these and focus on the ( rarer ) 5 s : 80 ! = 1 * 2 * 3 * 4 * 5 * 6 . . . * 78 * 79 * 80 since there are 80 consecutive numbers , there are 16 multiples of 5 in there , but if we ' re prime factoring , we need to remember that some multiples of 5 actually contain more than just one 5 . which ? 25 comes to mind - - it ' s got two of them ! so all the multiples of 25 actually contain two 5 ' s ( ie : 50 and 75 ) so , to recap , we have 16 of them , plus 3 more ( the additional 5 ' s in 25 , 50 , and 75 ) , so that makes 19 , and since we have more than enough 2 ' s , we know our number will have exactly 19 zeros at the end . answer : d | other |
math_qa__PjrgbWU9ek8Ws5CQ | In 1990 the budgets for projects Q and V were $700,000 and $780,000, respectively. In each of the next 10 years, the budget for Q was increased by $30,000 and the budget for V was decreased by $10,000. In which year was the budget for Q equal to the budget for V ? Select:
A) 1992 B) 1993 C) 1994 D) 1995 E) 1996 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">10 * 6</gadget>
<output>60</output>
<gadget id="calculator">1_990 + 60</gadget>
<output>2_050</output>
<result>A</result> | A | 1,992 | In 1990 the budgets for projects Q and V were $700,000 and $780,000, respectively. In each of the next 10 years, the budget for Q was increased by $30,000 and the budget for V was decreased by $10,000. In which year was the budget for Q equal to the budget for V ? | {
"A": "1992",
"B": "1993",
"C": "1994",
"D": "1995",
"E": "1996"
} | add(1990, multiply(10, multiply(const_2, const_3))) | multiply(const_2,const_3)|multiply(n3,#0)|add(n0,#1)| | "let the no of years it takes is x . 700 + 30 x = 780 - 10 x - - > 40 x = 80 and x = 2 . thus , it happens in 1992 . a ." | general |
math_qa__o0D081x8Y0PyK2JC | 6 bells commence tolling together and toll at the intervals of 24 , 68 , 1012 seconds resp . in 60 minutes how many times they will toll together . Choices.
A) 15 B) 16 C) 30 D) 31 E) none of these | <gadget id="calculator">60 * 60</gadget>
<output>3_600</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 * 10</gadget>
<output>120</output>
<gadget id="calculator">3_600 / 120</gadget>
<output>30</output>
<result>D</result> | D | 31 | 6 bells commence tolling together and toll at the intervals of 24 , 68 , 1012 seconds resp . in 60 minutes how many times they will toll together . | {
"A": "15",
"B": "16",
"C": "30",
"D": "31",
"E": "none of these"
} | divide(multiply(60, const_60), multiply(add(const_10, const_2), const_10)) | add(const_10,const_2)|multiply(n4,const_60)|multiply(#0,const_10)|divide(#1,#2) | explanation : lcm of 2 - 4 - 6 - 8 - 10 - 12 is 120 seconds , that is 2 minutes . now 60 / 2 = 30 adding one bell at the starting it will 30 + 1 = 31 answer : option d | physics |
math_qa__dVer3oqRsOgMyeA1 | In a full deck of 52 cards, there are 13 spades. A game is played whereby a card from is chosen at random from the deck. If the card is a spade, a winner is declared. If the card is not a spade, it is returned to the deck, the deck is reshuffled and another card is drawn. This process is repeated until a spade is drawn. What is the probability that one will pick the first spade on the second draw or later? Select.
A) 1 / 8 B) 1 / 4 C) 1 / 2 D) 3 / 4 E) 7 / 8 | <gadget id="calculator">13 / 52</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<result>D</result> | D | 0.75 | In a full deck of 52 cards, there are 13 spades. A game is played whereby a card from is chosen at random from the deck. If the card is a spade, a winner is declared. If the card is not a spade, it is returned to the deck, the deck is reshuffled and another card is drawn. This process is repeated until a spade is drawn. What is the probability that one will pick the first spade on the second draw or later? | {
"A": "1 / 8",
"B": "1 / 4",
"C": "1 / 2",
"D": "3 / 4",
"E": "7 / 8"
} | subtract(const_1, divide(13, 52)) | divide(n1,n0)|subtract(const_1,#0) | favorable case = the spade is picked in the third draw or later unfavorable case = the spade is picked in either first draw or in second draw probability = favorable outcomes / total out comes also probability = 1 - ( unfavorable outcomes / total out comes ) unfavorable case : probability of spade picked in first draw = 13 / 52 = 1 / 4 i . e . , favorable probability = 1 - ( 1 / 4 ) = 3 / 4 answer option : d | probability |
math_qa__5qpymJ4nYy4tp8ao | Of 600 surveyed students, 20% of those who read book A also read book B and 25% of those who read book B also read book A. If each student read at least one of the books, what is the difference between the number of students who read only book A and the number of students who read only book B? Choose the correct option
A) 20
B) 25
C) 30
D) 35
E) 75 | <gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/4) / (1/5)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) + 1</gadget>
<output>9/4 = around 2.25</output>
<gadget id="calculator">(9/4) - (1/4)</gadget>
<output>2</output>
<gadget id="calculator">600 / 2</gadget>
<output>300</output>
<gadget id="calculator">300 * (5/4)</gadget>
<output>375</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">375 * (4/5)</gadget>
<output>300</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">300 * (3/4)</gadget>
<output>225</output>
<gadget id="calculator">300 - 225</gadget>
<output>75</output>
<result>E</result> | E | 75 | Of 600 surveyed students, 20% of those who read book A also read book B and 25% of those who read book B also read book A. If each student read at least one of the books, what is the difference between the number of students who read only book A and the number of students who read only book B? | {
"A": "20",
"B": "25",
"C": "30",
"D": "35",
"E": "75"
} | subtract(multiply(multiply(divide(600, subtract(add(divide(divide(25, const_100), divide(20, const_100)), const_1), divide(25, const_100))), divide(divide(25, const_100), divide(20, const_100))), subtract(const_1, divide(20, const_100))), multiply(divide(600, subtract(add(divide(divide(25, const_100), divide(20, const_100)), const_1), divide(25, const_100))), subtract(const_1, divide(25, const_100)))) | divide(n2,const_100)|divide(n1,const_100)|divide(#0,#1)|subtract(const_1,#1)|subtract(const_1,#0)|add(#2,const_1)|subtract(#5,#0)|divide(n0,#6)|multiply(#7,#2)|multiply(#7,#4)|multiply(#8,#3)|subtract(#10,#9) | say the number of students who read book a is a and the number of students who read book b is b . given that 20 % of those who read book a also read book b and 25 % of those who read book b also read book a , so the number of students who read both books is 0.2 a = 0.25 b - - > a = 1.25 b . since each student read at least one of the books then { total } = { a } + { b } - { both } - - > 600 = 1.25 b + b - 0.25 b - - > b = 300 , a = 1.25 b = 375 and { both } = 0.25 b = 75 . the number of students who read only book a is { a } - { both } = 375 - 75 = 300 ; the number of students who read only book b is { b } - { both } = 300 - 75 = 225 ; the difference is 300 - 225 = 75 . answer : e . | gain |
math_qa__mcqxmPtR6xG7QQNe | If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 4340 , R will receive Choose the most appropriate option
A) 600 B) 700 C) 840 D) 900 E) none of these | <gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">15 + 10</gadget>
<output>25</output>
<gadget id="calculator">25 + 6</gadget>
<output>31</output>
<gadget id="calculator">6 / 31</gadget>
<output>6/31 = around 0.193548</output>
<gadget id="calculator">4_340 * (6/31)</gadget>
<output>840</output>
<result>C</result> | C | 840 | If 4 (P's Capital ) = 6 ( Q's Capital ) = 10 ( R's Capital ) , then out of the total profit of Rs 4340 , R will receive | {
"A": "600",
"B": "700",
"C": "840",
"D": "900",
"E": "none of these"
} | multiply(4340, divide(6, add(add(add(10, add(4, const_1)), 10), 6))) | add(n0,const_1)|add(n2,#0)|add(n2,#1)|add(n1,#2)|divide(n1,#3)|multiply(n3,#4) | explanation : let p ' s capital = p , q ' s capital = q and r ' s capital = r then 4 p = 6 q = 10 r = > 2 p = 3 q = 5 r = > q = 2 p / 3 r = 2 p / 5 p : q : r = p : 2 p / 3 : 2 p / 5 = 15 : 10 : 6 r ' s share = 4340 * ( 6 / 31 ) = 140 * 6 = 840 . answer : option c | general |
math_qa__qqiV9s8jm5g23QMw | For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 100? Choose the most appropriate option: A) 30 B) 28 C) 27 D) 25 E) 26 | <gadget id="calculator">100 - 7</gadget>
<output>93</output>
<gadget id="calculator">93 / 4</gadget>
<output>93/4 = around 23.25</output>
<gadget id="calculator">floor(93/4)</gadget>
<output>23</output>
<gadget id="calculator">1 - 7</gadget>
<output>-6</output>
<gadget id="calculator">(-6) / 4</gadget>
<output>-3/2 = around -1.5</output>
<gadget id="calculator">floor(-3/2)</gadget>
<output>-2</output>
<gadget id="calculator">23 - (-2)</gadget>
<output>25</output>
<result>D</result> | D | 25 | For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 100? | {
"A": "30",
"B": "28",
"C": "27",
"D": "25",
"E": "26"
} | subtract(floor(divide(subtract(100, 7), 4)), floor(divide(subtract(1, 7), 4))) | subtract(n3,n1)|subtract(n2,n1)|divide(#0,n0)|divide(#1,n0)|floor(#2)|floor(#3)|subtract(#4,#5)| | "4 n + 7 > 1 4 n > - 6 n > - ( 3 / 2 ) n > - 1.5 ( n = - 1 , 0 , 1 , 2 3 . . . . . . . . upto infinity ) from second constraint 4 n + 7 < 100 4 n < 93 n < 23 . 25 n = ( - infinity , . . . . . . . - 3 , - 2 , - 1 , 0 , 1 , 2 , . . . . . . . . . upto 23 ) combining the two - 1.5 < n < 23.25 n = 1 to 23 ( 23 integers ) and n = - 1 and 0 so 25 integers . d is the answer" | general |
math_qa__6fkqmLikQuzKmRD9 | If the arithmetic mean of p and q is 10 and the arithmetic mean of q and r is 25, what is the value of r-p? Choose one:
A) 20
B) 10
C) 30
D) 40
E) 5 | <gadget id="calculator">25 * 2</gadget>
<output>50</output>
<gadget id="calculator">10 * 2</gadget>
<output>20</output>
<gadget id="calculator">50 - 20</gadget>
<output>30</output>
<result>C</result> | C | 30 | If the arithmetic mean of p and q is 10 and the arithmetic mean of q and r is 25, what is the value of r-p? | {
"A": "20",
"B": "10",
"C": "30",
"D": "40",
"E": "5"
} | subtract(multiply(25, const_2), multiply(10, const_2)) | multiply(n1,const_2)|multiply(n0,const_2)|subtract(#0,#1)| | "arithmetic mean expression for p and q : ( p + q ) / 2 = 10 ; p + q = 20 - - - - eq 1 arithmetic mean expression for q and r : ( q + r ) / 2 = 20 ; q + r = 50 - - - - eq 2 subtracting eq 1 from eq 2 we get : r - p = 30 hence , the correct answer is c" | general |
math_qa__VudjgMQjPMGGjnEx | There were two candidates in an election. Winner candidate received 62% of votes and won the election by 300 votes. Find the number of votes casted to the winning candidate? Choose the correct choice from the following choices:
A) 456 B) 744 C) 912 D) 1200 E) 775 | <gadget id="calculator">100 - 62</gadget>
<output>38</output>
<gadget id="calculator">62 - 38</gadget>
<output>24</output>
<gadget id="calculator">24 / 100</gadget>
<output>6/25 = around 0.24</output>
<gadget id="calculator">300 / (6/25)</gadget>
<output>1_250</output>
<gadget id="calculator">1_250 * 62</gadget>
<output>77_500</output>
<gadget id="calculator">77_500 / 100</gadget>
<output>775</output>
<result>E</result> | E | 775 | There were two candidates in an election. Winner candidate received 62% of votes and won the election by 300 votes. Find the number of votes casted to the winning candidate? | {
"A": "456",
"B": "744",
"C": "912",
"D": "1200",
"E": "775"
} | divide(multiply(divide(300, divide(subtract(62, subtract(const_100, 62)), const_100)), 62), const_100) | subtract(const_100,n0)|subtract(n0,#0)|divide(#1,const_100)|divide(n1,#2)|multiply(n0,#3)|divide(#4,const_100)| | "w = 62 % l = 38 % 62 % - 38 % = 24 % 24 % - - - - - - - - 300 62 % - - - - - - - - ? = > 775 answer : e" | gain |
math_qa__ZtK6g0mnjrUVHw1h | 10 percent of ram ' s monthly salary is equal to 8 percent of shyam ' s monthly salary . shyam ' s monthly salary is twice abhinav ' s monthly salary . if abhinav ' s annual salary is rs . 1.92 lakhs , find ram ' s monthly salary ? Choose the correct choice.
A) rs . 18000 B) rs . 20000 C) rs . 25600 D) rs . 32000 E) none of these | <gadget id="calculator">8 * 100</gadget>
<output>800</output>
<gadget id="calculator">1.92 / 12</gadget>
<output>0.16</output>
<gadget id="calculator">0.16 * 2</gadget>
<output>0.32</output>
<gadget id="calculator">800 * 0.32</gadget>
<output>256</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">256 / 1_000</gadget>
<output>32/125 = around 0.256</output>
<gadget id="calculator">(32/125) * 100</gadget>
<output>128/5 = around 25.6</output>
<gadget id="calculator">(128/5) * 1_000</gadget>
<output>25_600</output>
<result>C</result> | C | 25,600 | 10 percent of ram ' s monthly salary is equal to 8 percent of shyam ' s monthly salary . shyam ' s monthly salary is twice abhinav ' s monthly salary . if abhinav ' s annual salary is rs . 1.92 lakhs , find ram ' s monthly salary ? | {
"A": "rs . 18000",
"B": "rs . 20000",
"C": "rs . 25600",
"D": "rs . 32000",
"E": "none of these"
} | multiply(multiply(divide(multiply(multiply(8, const_100), multiply(divide(1.92, const_12), const_2)), multiply(const_100, 10)), const_100), const_1000) | divide(n2,const_12)|multiply(n1,const_100)|multiply(n0,const_100)|multiply(#0,const_2)|multiply(#1,#3)|divide(#4,#2)|multiply(#5,const_100)|multiply(#6,const_1000) | let the monthly salaries of ram and shyam be rs . r and rs . s respectively . 10 / 100 r = 8 / 100 s r = 4 / 5 s monthly salary of abhinav = ( 1.92 lakhs ) / 12 = rs . 0.16 lakhs s = 2 ( 0.16 lakhs ) = 0.32 lakhs r = 4 / 5 ( 0.32 lakhs ) = rs . 25600 answer : c | general |
math_qa__cZRAlEL7LTR4WQ2s | When processing flower-nectar into honey bees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 15% water?
Pick one
A) 1.2 kg
B) 1.5 kg
C) 1.7 kg
D) 1.9 kg
E) none of these | <gadget id="calculator">100 - 15</gadget>
<output>85</output>
<gadget id="calculator">85 / 100</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(17/20) / (1/2)</gadget>
<output>17/10 = around 1.7</output>
<result>C</result> | C | 1.7 | When processing flower-nectar into honey bees' extract, a considerable amount of water gets reduced. How much flower-nectar must be processed to yield 1kg of honey, if nectar contains 50% water, and the honey obtained from this nectar contains 15% water? | {
"A": "1.2 kg",
"B": "1.5 kg",
"C": "1.7 kg",
"D": "1.9 kg",
"E": "none of these"
} | divide(divide(subtract(const_100, 15), const_100), divide(50, const_100)) | divide(n1,const_100)|subtract(const_100,n2)|divide(#1,const_100)|divide(#2,#0)| | "explanation : flower - nectar contains 50 % of non - water part . in honey this non - water part constitutes 85 % ( 100 - 15 ) . therefore 0.5 x amount of flower - nectar = 0.85 x amount of honey = 0.85 x 1 kg therefore amount of flower - nectar needed = ( 0.85 / 0.51 ) kg = 1.7 kgs answer : c" | general |
math_qa__rBiaMgXtHLJDpk8H | A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability W that all 3 jellybeans removed from the bag are blue? Choose the correct option
A) 9 / 100 B) 2 / 19 C) 1 / 8 D) 3 / 20 E) 3 / 10 | <gadget id="calculator">binomial(10, 3)</gadget>
<output>120</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">binomial(20, 3)</gadget>
<output>1_140</output>
<gadget id="calculator">120 / 1_140</gadget>
<output>2/19 = around 0.105263</output>
<result>B</result> | B | 0.105263 | A bag contains 10 red jellybeans and 10 blue jellybeans. If 3 jellybeans are removed one at a time, at random and are not replaced, what is the probability W that all 3 jellybeans removed from the bag are blue? | {
"A": "9 / 100",
"B": "2 / 19",
"C": "1 / 8",
"D": "3 / 20",
"E": "3 / 10"
} | divide(choose(10, 3), choose(add(10, 10), 3)) | add(n0,n0)|choose(n0,n2)|choose(#0,n2)|divide(#1,#2) | method - 1 10 red jellybeans and 10 blue jellybeans total outcomes = no . of ways to choose 3 jelly bean at random out of a total 20 jellybeans = 20 c 3 = 1140 favourable outcomes = no . of ways to choose 3 jelly bean such that they are all blue out of 10 blue = 10 c 3 = 120 probability = favourable outcomes / total outcomes = 10 c 3 / 20 c 3 probability w = 120 / 1140 = 2 / 19 answer : option b method - 2 probability of first jelly bean to be blue = 10 / 20 [ total 10 blue out of total 20 jellybeans ] probability of second jelly bean to be blue = 9 / 19 [ total 9 blue remaining out of total 19 jellybeans remaining ] probability of third jelly bean to be blue = 8 / 18 [ total 8 blue remaining out of total 18 jellybeans remaining ] required probability = ( 10 / 20 ) * ( 9 / 19 ) * ( 8 / 18 ) = 2 / 19 answer : option b | probability |
math_qa__VDp51UA0ZVDOZ2yE | Peter invested a certain sum of money in a simple interest bond whose value grew to $300 at the end of 3 years and further to $400 at the end of another 5 years. What was the rate of interest in which he invested his sum?
Choose the correct choice from the following answers
A) 12 % B) 12.5 % C) 6.67 % D) 6.25 % E) 8.33 % | <gadget id="calculator">400 - 300</gadget>
<output>100</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<gadget id="calculator">300 - 60</gadget>
<output>240</output>
<gadget id="calculator">20 / 240</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">(1/12) * 100</gadget>
<output>25/3 = around 8.333333</output>
<result>E</result> | E | 8.33 | Peter invested a certain sum of money in a simple interest bond whose value grew to $300 at the end of 3 years and further to $400 at the end of another 5 years. What was the rate of interest in which he invested his sum? | {
"A": "12 %",
"B": "12.5 %",
"C": "6.67 %",
"D": "6.25 %",
"E": "8.33 %"
} | multiply(divide(divide(subtract(400, 300), 5), subtract(300, multiply(divide(subtract(400, 300), 5), 3))), const_100) | subtract(n2,n0)|divide(#0,n3)|multiply(n1,#1)|subtract(n0,#2)|divide(#1,#3)|multiply(#4,const_100) | answer initial amount invested = $ x amount at the end of year 3 = $ 300 amount at the end of year 8 ( another 5 years ) = $ 400 therefore , the interest earned for the 5 year period between the 3 rd year and 8 th year = $ 400 - $ 300 = $ 100 as the simple interest earned for a period of 5 years is $ 100 , interest earned per year = $ 20 . therefore , interest earned for 3 years = 3 * 20 = $ 60 . hence , initial amount invested x = amount after 3 years - interest for 3 years = 300 - 60 = $ 240 . rate of interest = ( interest per year / principal ) * 100 = 20 / 240 * 100 = 8.33 % choice is ( e ) | gain |
math_qa__GGHKRXuV6oMN2FI2 | 28 buckets of water fill a tank when the capacity of each bucket is 13.5 litres. How many buckets will be required to fill the same tank if the capacity of each bucket is 9 litres? Choose the correct choice from the following choices
A) 30 B) 42 C) 60 D) data inadequate E) none of these | <gadget id="calculator">13.5 * 28</gadget>
<output>378</output>
<gadget id="calculator">378 / 9</gadget>
<output>42</output>
<result>B</result> | B | 42 | 28 buckets of water fill a tank when the capacity of each bucket is 13.5 litres. How many buckets will be required to fill the same tank if the capacity of each bucket is 9 litres? | {
"A": "30",
"B": "42",
"C": "60",
"D": "data inadequate",
"E": "none of these"
} | divide(multiply(13.5, 28), 9) | multiply(n0,n1)|divide(#0,n2)| | "capacity of the tank = 28 ã — 13.5 = 378 litres when the capacity of each bucket = 9 litres , then the required no . of buckets = 378 â „ 9 = 42 answer b" | physics |
math_qa__fEtJh0d5UJhHqUdv | the average ( arithmetic mean ) of 4 different positive integers is 16 . if the first of these integers in 3 times the second integer and the second integer is 2 less than the third integer , what is the least possible value of the fourth integer ? Choose the correct option.
A) 5 B) 4 C) 3 D) 2 E) 1 | <gadget id="calculator">16 * 4</gadget>
<output>64</output>
<gadget id="calculator">64 - 2</gadget>
<output>62</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">12 * 5</gadget>
<output>60</output>
<gadget id="calculator">62 - 60</gadget>
<output>2</output>
<result>D</result> | D | 2 | the average ( arithmetic mean ) of 4 different positive integers is 16 . if the first of these integers in 3 times the second integer and the second integer is 2 less than the third integer , what is the least possible value of the fourth integer ? | {
"A": "5",
"B": "4",
"C": "3",
"D": "2",
"E": "1"
} | subtract(subtract(multiply(16, 4), 2), multiply(const_12, add(3, 2))) | add(n2,n3)|multiply(n0,n1)|multiply(#0,const_12)|subtract(#1,n3)|subtract(#3,#2) | let the second integer be x and the fourth be a . then [ 3 x + x + ( x + 2 ) + a ] / 4 = 16 = > 5 x + 2 + a = 64 = > 5 x + a = 62 = > a = 62 - 5 x from the above equation we can see that a is minimum when x is maximum , provided both are positive the maximum value that x can take in the above equation while still keeping a positive is x = 12 this gives us a = 62 - 60 = 2 therefore the minimum value that the fourth integer can have is 2 . option d . | general |
math_qa__qDbJTYmOO79A4pUE | 36 welders work at a constant rate they complete an order in 3 days. If after the first day, 12 welders start to work on the other project, how many more days the remaining welders will need to complete the rest of the order?
Choose the correct option:
A) 3 B) 2 C) 8 D) 4 E) 6 | <gadget id="calculator">36 * 3</gadget>
<output>108</output>
<gadget id="calculator">1 / 108</gadget>
<output>1/108 = around 0.009259</output>
<gadget id="calculator">(1/108) * 36</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">36 - 12</gadget>
<output>24</output>
<gadget id="calculator">(2/3) / 24</gadget>
<output>1/36 = around 0.027778</output>
<gadget id="calculator">(1/36) / (1/108)</gadget>
<output>3</output>
<result>A</result> | A | 3 | 36 welders work at a constant rate they complete an order in 3 days. If after the first day, 12 welders start to work on the other project, how many more days the remaining welders will need to complete the rest of the order? | {
"A": "3",
"B": "2",
"C": "8",
"D": "4",
"E": "6"
} | divide(divide(subtract(const_1, multiply(divide(const_1, multiply(36, 3)), 36)), subtract(36, 12)), divide(const_1, multiply(36, 3))) | multiply(n0,n1)|subtract(n0,n2)|divide(const_1,#0)|multiply(n0,#2)|subtract(const_1,#3)|divide(#4,#1)|divide(#5,#2)| | "1 . we need to find out the time taken by 24 workers after day 1 . 2 . total no . of wokers * total time taken = time taken by 1 worker 3 . time taken by 1 worker = 36 * 3 = 108 days 4 . but on day 1 thirty - six workers had already worked finishing 1 / 3 of the job . so 24 workers have to finish only 2 / 3 of the job . 5 . total time taken by 24 workers can be got from formula used at ( 2 ) . i . e . , 24 * total time taken = 108 . total time taken by 6 workers to finish the complete job is 108 / 24 = 4.5 days . 6 . time taken by 24 workers to finish 2 / 3 of the job is 2 / 3 * 4.5 = 3 days . the answer is choice a" | physics |
math_qa__1ejv4otOVGp1ey5d | Frank the Fencemaker needs to fence in a rectangular yard. He fences in the entire yard, except for one full side of the yard, which equals 40 feet. The yard has an area of 200 square feet. How many feet offence does Frank use? Choose the correct option:
A) 14
B) 47
C) 50
D) 180
E) 240 | <gadget id="calculator">200 / 40</gadget>
<output>5</output>
<gadget id="calculator">5 + 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 40</gadget>
<output>50</output>
<result>C</result> | C | 50 | Frank the Fencemaker needs to fence in a rectangular yard. He fences in the entire yard, except for one full side of the yard, which equals 40 feet. The yard has an area of 200 square feet. How many feet offence does Frank use? | {
"A": "14",
"B": "47",
"C": "50",
"D": "180",
"E": "240"
} | add(add(divide(200, 40), divide(200, 40)), 40) | divide(n1,n0)|add(#0,#0)|add(n0,#1)| | "area = length x breadth 200 = 40 x breadth so , breadth = 5 units fencing required is - breadth + breadth + length 5 + 5 + 40 = > 50 feet answer must be ( c ) 50" | geometry |
math_qa__m7wKSvgoxV91muxA | In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 60 questions and secures 120 marks, the no of questions he attempts correctly is : Choose the correct choice
A) 35
B) 36
C) 40
D) 42
E) 44 | <gadget id="calculator">120 + 60</gadget>
<output>180</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">180 / 5</gadget>
<output>36</output>
<result>B</result> | B | 36 | In an examination, a student scores 4 marks for every correct answer and loses 1 mark for every wrong answer. If he attempts all 60 questions and secures 120 marks, the no of questions he attempts correctly is : | {
"A": "35",
"B": "36",
"C": "40",
"D": "42",
"E": "44"
} | divide(add(120, 60), add(4, 1)) | add(n2,n3)|add(n0,n1)|divide(#0,#1)| | "explanation : let the number of correct answers be x . number of incorrect answers = ( 60 – x ) . 4 x – ( 60 – x ) = 120 = > 5 x = 180 = > x = 36 answer : b" | physics |
math_qa__lwVl4RjRB2jWKfKK | An engineer undertakes a project to build a road 10 km long in 15 days and employs 30 men for the purpose. After 5 days, he finds only 2 km of the road has been completed. Find the (approximate) number of extra men he must employ to finish the work in time.
Choose the correct choice
A) 15 B) 20 C) 25 D) 28 E) 30 | <gadget id="calculator">10 - 2</gadget>
<output>8</output>
<gadget id="calculator">30 * 8</gadget>
<output>240</output>
<gadget id="calculator">240 * 5</gadget>
<output>1_200</output>
<gadget id="calculator">15 - 5</gadget>
<output>10</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">1_200 / 20</gadget>
<output>60</output>
<gadget id="calculator">60 - 30</gadget>
<output>30</output>
<result>E</result> | E | 30 | An engineer undertakes a project to build a road 10 km long in 15 days and employs 30 men for the purpose. After 5 days, he finds only 2 km of the road has been completed. Find the (approximate) number of extra men he must employ to finish the work in time. | {
"A": "15",
"B": "20",
"C": "25",
"D": "28",
"E": "30"
} | subtract(divide(multiply(multiply(30, subtract(10, 2)), 5), multiply(2, subtract(15, 5))), 30) | subtract(n0,n4)|subtract(n1,n3)|multiply(n2,#0)|multiply(n4,#1)|multiply(n3,#2)|divide(#4,#3)|subtract(#5,n2)| | "30 workers working already let x be the total men required to finish the task in next 10 days 2 km done hence remaining is 8 km also , work has to be completed in next 10 days ( 15 - 10 = 5 ) we know that , proportion of men to distance is direct proportion and , proportion of men to days is inverse proportion hence , x = ( 30 * 8 * 5 ) / ( 2 * 10 ) thus , x = 60 thus , more men needed to finish the task = 60 - 30 = 30 answer : e" | physics |
math_qa__13M6FcokVB2SlHv6 | Chandigarh express of 100 m runs at a speed of 60 km/hr. What will be the time taken to cross a platform of 150 meters long? Choose the correct answer: A) 11.00 sec B) 12.50 sec C) 15.00 sec D) 15.23 sec E) 5.23 sec | <gadget id="calculator">100 + 150</gadget>
<output>250</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">250 / (50/3)</gadget>
<output>15</output>
<result>C</result> | C | 15 | Chandigarh express of 100 m runs at a speed of 60 km/hr. What will be the time taken to cross a platform of 150 meters long? | {
"A": "11.00 sec",
"B": "12.50 sec",
"C": "15.00 sec",
"D": "15.23 sec",
"E": "5.23 sec"
} | divide(add(100, 150), multiply(60, const_0_2778)) | add(n0,n2)|multiply(n1,const_0_2778)|divide(#0,#1) | explanation : given : length of train = 100 m , speed of train = 60 km / hr , length of platform = 150 m 1 ) always remember first step is the conversion of units . convert 60 km / hr into m / s by multiplying it with ( 5 / 18 ) speed of the train = 60 x 5 / 18 = 16.66 m / s 2 ) distance covered by the train in passing the platform = ( length of train + length of platform ) = ( 100 + 150 ) = 250 m therefore , the time taken = distance / speed = 250 / 16.66 = 15 sec answer is c | physics |
math_qa__k1QQdW86r0j2PDhn | A cube is painted red on all faces. It is then cut into 27 equal smaller cubes. How many P cubes are painted on only 2 faces? Choose the correct choice from the following choices:
A) 12 B) 8 C) 6 D) 10 E) 16 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">27 ** (1/3)</gadget>
<output>3</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<result>A</result> | A | 12 | A cube is painted red on all faces. It is then cut into 27 equal smaller cubes. How many P cubes are painted on only 2 faces? | {
"A": "12",
"B": "8",
"C": "6",
"D": "10",
"E": "16"
} | multiply(const_4, power(27, divide(const_1, const_3))) | divide(const_1,const_3)|power(n0,#0)|multiply(#1,const_4)| | "1 ) draw a simple cube 2 ) draw 9 squares on each face of the cube ( so that it looks like a rubik ' s cube ) - this is what the cube will look like when it ' s cut into 27 equal smaller cubes . 3 ) remember that the outside of the cube is the part that ' s painted . . . . the mini - cubes with 2 painted sides are all on the edge of the cube , in themiddleof the edge . there are 4 in front , 4 in back and 4 more on thestripthat runs around the left / top / right / bottom of the cube . p = 4 + 4 + 4 = 12 . answer a" | geometry |
math_qa__cSI6BObIsg3MU8ZF | In a school 50% of the students are younger than 10, 1/20 are 10 years old and 1/10 are older than 10 but younger than 12, the remaining 70 students are 12 years or older. How many students are 10 years old? Choose the correct choice from the following options: A) 50 B) 60 C) 10 D) 20 E) 30 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 - (1/2)</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/2) - (1/20)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(9/20) - (1/10)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">70 / (7/20)</gadget>
<output>200</output>
<gadget id="calculator">200 / 20</gadget>
<output>10</output>
<result>C</result> | C | 10 | In a school 50% of the students are younger than 10, 1/20 are 10 years old and 1/10 are older than 10 but younger than 12, the remaining 70 students are 12 years or older. How many students are 10 years old? | {
"A": "50",
"B": "60",
"C": "10",
"D": "20",
"E": "30"
} | divide(divide(70, subtract(subtract(subtract(const_1, divide(50, const_100)), divide(1, 20)), divide(1, 10))), 20) | divide(n0,const_100)|divide(n2,n3)|divide(n2,n1)|subtract(const_1,#0)|subtract(#3,#1)|subtract(#4,#2)|divide(n9,#5)|divide(#6,n3) | let us write the fraction for each group of students group a : younger than 10 : 50 % = 50 / 100 = 1 / 2 group b : 10 years old : 1 / 20 group c : older that 10 but younger than 12 : 1 / 10 group d : 12 years or older : 70 students the fraction for group a , b and c together is given by 1 / 2 + 1 / 20 + 1 / 10 = 10 / 20 + 1 / 20 + 2 / 20 , common denominator = 13 / 20 , add numerators the fraction for group d is given by 20 / 20 - 13 / 20 = 7 / 20 and corresponds to 70 students if x is the total number of students , then 7 / 20 of x = 70 or ( 7 / 20 ) * x = 70 solve for x x = 70 * ( 20 / 7 ) = 200 students who are 10 years old have a fraction of 1 / 20 of the total x and their number is equal to ( 1 / 20 ) of 200 = 10 students correct answer c | gain |
math_qa__F4kF1Y99f9ETBZzo | A train passes a man standing on a platform in 8 seconds and also crosses the platform which is 270 metres long in 20 seconds. The length of the train (in metres) is: Choose the correct choice from the following options.
A) 180 B) 176 C) 175 D) 96 E) none of these | <gadget id="calculator">20 - 8</gadget>
<output>12</output>
<gadget id="calculator">270 / 12</gadget>
<output>45/2 = around 22.5</output>
<gadget id="calculator">(45/2) * 8</gadget>
<output>180</output>
<result>A</result> | A | 180 | A train passes a man standing on a platform in 8 seconds and also crosses the platform which is 270 metres long in 20 seconds. The length of the train (in metres) is: | {
"A": "180",
"B": "176",
"C": "175",
"D": "96",
"E": "none of these"
} | multiply(divide(270, subtract(20, 8)), 8) | subtract(n2,n0)|divide(n1,#0)|multiply(n0,#1)| | "explanation : let the length of train be l m . acc . to question ( 270 + l ) / 20 = l / 8 2160 + 8 l = 20 l l = 2160 / 12 = 180 m answer a" | physics |
math_qa__OTa5uLzyJwaqcfOX | If the operation € is defined for all x and y by the equation x € y = 2*x*y, then 7 € (4 € 5) =
Select the correct option.
A) 80 B) 120 C) 160 D) 240 E) 560 | <gadget id="calculator">2 * 7</gadget>
<output>14</output>
<gadget id="calculator">2 * 4</gadget>
<output>8</output>
<gadget id="calculator">8 * 5</gadget>
<output>40</output>
<gadget id="calculator">14 * 40</gadget>
<output>560</output>
<result>E</result> | E | 560 | If the operation € is defined for all x and y by the equation x € y = 2*x*y, then 7 € (4 € 5) = | {
"A": "80",
"B": "120",
"C": "160",
"D": "240",
"E": "560"
} | multiply(multiply(2, 7), multiply(multiply(2, 4), 5)) | multiply(n0,n1)|multiply(n0,n2)|multiply(n3,#1)|multiply(#0,#2)| | "working inside out , ( 4 € 5 ) = 2 * 4 * 5 = 40 7 € 40 = 2 * 3 * 40 = 560 hence , answer is e" | general |
math_qa__jbD0Ar3gVWta4puM | If a farmer wants to plough a farm field on time, he must plough 90 hectares a day. For technical reasons he ploughed only 85 hectares a day, hence he had to plough 2 more days than he planned and he still has 40 hectares left. What is the area of the farm field and how many days the farmer planned to work initially? Choose the most appropriate option:
A) 1600
B) 2490
C) 3780
D) 4235
E) 6179 | <gadget id="calculator">2 * 85</gadget>
<output>170</output>
<gadget id="calculator">40 + 170</gadget>
<output>210</output>
<gadget id="calculator">90 - 85</gadget>
<output>5</output>
<gadget id="calculator">210 / 5</gadget>
<output>42</output>
<gadget id="calculator">42 * 90</gadget>
<output>3_780</output>
<result>C</result> | C | 3,780 | If a farmer wants to plough a farm field on time, he must plough 90 hectares a day. For technical reasons he ploughed only 85 hectares a day, hence he had to plough 2 more days than he planned and he still has 40 hectares left. What is the area of the farm field and how many days the farmer planned to work initially? | {
"A": "1600",
"B": "2490",
"C": "3780",
"D": "4235",
"E": "6179"
} | multiply(divide(add(40, multiply(2, 85)), subtract(90, 85)), 90) | multiply(n1,n2)|subtract(n0,n1)|add(n3,#0)|divide(#2,#1)|multiply(n0,#3)| | "let x be the number of days in the initial plan . therefore , the whole field is 90 â ‹ … x hectares . the farmer had to work for x + 2 days , and he ploughed 85 ( x + 2 ) hectares , leaving 40 hectares unploughed . then we have the equation : 90 x = 85 ( x + 2 ) + 40 5 x = 210 x = 42 so the farmer planned to have the work done in 6 days , and the area of the farm field is 90 ( 42 ) = 3780 hectares correct answer c" | physics |
math_qa__oiHwSH1R1ugkDSJn | The workforce of Company X is 60% female. The company hired 30 additional male workers, and as a result, the percent of female workers dropped to 55%.How many employees did the company have after hiring the additional male workers? Choices.
A) 160 B) 220 C) 240 D) 360 E) 420 | <gadget id="calculator">55 / 100</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">(11/20) * 30</gadget>
<output>33/2 = around 16.5</output>
<gadget id="calculator">60 / 100</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) - (11/20)</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(33/2) / (1/20)</gadget>
<output>330</output>
<gadget id="calculator">330 + 30</gadget>
<output>360</output>
<result>D</result> | D | 360 | The workforce of Company X is 60% female. The company hired 30 additional male workers, and as a result, the percent of female workers dropped to 55%.How many employees did the company have after hiring the additional male workers? | {
"A": "160",
"B": "220",
"C": "240",
"D": "360",
"E": "420"
} | add(divide(multiply(divide(55, const_100), 30), subtract(divide(60, const_100), divide(55, const_100))), 30) | divide(n2,const_100)|divide(n0,const_100)|multiply(n1,#0)|subtract(#1,#0)|divide(#2,#3)|add(n1,#4)| | "let ' s xx be total quantity of employees 0.6 x = females before adding men 0.55 ( x + 30 ) = females after adding men as quantity of women does n ' t change we can make an equation : 0.6 x = 0.55 ( x + 30 ) 0.05 x = 16.5 x = 330 - this is quantity of employees before adding 30 men so after adding it will be 360 answer is d" | gain |
math_qa__eyIWK7mXnpRIuLEO | 20 litres of mixture contains 20% alcohol and the rest water. If 3litres of water be mixed with it, the percentage of alcohol in the new mixture would be? Choose the correct choice from the following answers:
A) 16.67 % B) 23 % C) 18.3 % D) 19.75 % E) 17.4 % | <gadget id="calculator">20 + 3</gadget>
<output>23</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 20</gadget>
<output>16</output>
<gadget id="calculator">16 + 3</gadget>
<output>19</output>
<gadget id="calculator">23 - 19</gadget>
<output>4</output>
<gadget id="calculator">4 / 23</gadget>
<output>4/23 = around 0.173913</output>
<gadget id="calculator">(4/23) * 100</gadget>
<output>400/23 = around 17.391304</output>
<result>E</result> | E | 17.4 | 20 litres of mixture contains 20% alcohol and the rest water. If 3litres of water be mixed with it, the percentage of alcohol in the new mixture would be? | {
"A": "16.67 %",
"B": "23 %",
"C": "18.3 %",
"D": "19.75 %",
"E": "17.4 %"
} | multiply(divide(subtract(add(20, 3), add(multiply(divide(subtract(const_100, 20), const_100), 20), 3)), add(20, 3)), const_100) | add(n0,n2)|subtract(const_100,n1)|divide(#1,const_100)|multiply(n0,#2)|add(n2,#3)|subtract(#0,#4)|divide(#5,#0)|multiply(#6,const_100)| | "alcohol in the 20 litres of mix . = 20 % of 20 litres = ( 20 * 20 / 100 ) = 4 litres water in it = 20 - 3 = 17 litres new quantity of mix . = 20 + 3 = 23 litres quantity of alcohol in it = 4 litres percentage of alcohol in new mix . = 4 * 100 / 23 = 17.4 % answer is e" | gain |
math_qa__noHZINGycitFSzkq | the heights of a wall is 6 times its width and the length of the wall is 7 times its height . if volume of the wall be 16128 cu . m , its width is Choose the correct answer:
A) 4 m B) 4.5 m C) 5 m D) 6 m E) none | <gadget id="calculator">6 * 7</gadget>
<output>42</output>
<gadget id="calculator">42 * 6</gadget>
<output>252</output>
<gadget id="calculator">16_128 / 252</gadget>
<output>64</output>
<gadget id="calculator">64 ** (1/2)</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>A</result> | A | 4 | the heights of a wall is 6 times its width and the length of the wall is 7 times its height . if volume of the wall be 16128 cu . m , its width is | {
"A": "4 m",
"B": "4.5 m",
"C": "5 m",
"D": "6 m",
"E": "none"
} | divide(sqrt(divide(16128, multiply(multiply(6, 7), 6))), const_2) | multiply(n0,n1)|multiply(n0,#0)|divide(n2,#1)|sqrt(#2)|divide(#3,const_2) | solution let the width of the wall be x metres . then , height = ( 6 x ) m and length = ( 42 x ) m . 42 x × x × 6 x = 16128 x 3 ‹ = › ( 16128 / 42 × 6 ) = 64 ‹ = › x = 4 . answer a | physics |
math_qa__uyHxOPslfBBlfnSS | (9^5.6x 9^10.3) ÷ 9^2.56256 = 9^? Select
A) 11.34 B) 12.34 C) 13.34 D) 14.34 E) 15.34 | <gadget id="calculator">5.6 + 10.3</gadget>
<output>15.9</output>
<gadget id="calculator">15.9 - 2.56256</gadget>
<output>13.33744</output>
<result>C</result> | C | 13.34 | (9^5.6x 9^10.3) ÷ 9^2.56256 = 9^? | {
"A": "11.34",
"B": "12.34",
"C": "13.34",
"D": "14.34",
"E": "15.34"
} | subtract(add(5.6, 10.3), 2.56256) | add(n1,n3)|subtract(#0,n5) | 5.6 + 10.3 = 15.9 i . e . . 15.9 - 2.56 = 13.34 so ur answer is 9 ^ 13.34 answer : c | general |
math_qa__kUdWRCbT2k6zESba | Equal amount of water were poured into two empty jars of different capacities, which made one jar 1/8 full and other jar 1/6 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water? Options.
A) 1 / 7 B) 2 / 7 C) 1 / 2 D) 7 / 12 E) 1 / 4 | <gadget id="calculator">2 / 8</gadget>
<output>1/4 = around 0.25</output>
<result>E</result> | E | 0.25 | Equal amount of water were poured into two empty jars of different capacities, which made one jar 1/8 full and other jar 1/6 full. If the water in the jar with lesser capacity is then poured into the jar with greater capacity, what fraction of the larger jar will be filled with water? | {
"A": "1 / 7",
"B": "2 / 7",
"C": "1 / 2",
"D": "7 / 12",
"E": "1 / 4"
} | divide(const_2, 8) | divide(const_2,n1)| | "same amount of water made bigger jar 1 / 8 full , then the same amount of water ( stored for a while in smaller jar ) were added to bigger jar , so bigger jar is 1 / 8 + 1 / 8 = 1 / 4 full . answer : e ." | general |
math_qa__Dc8l9nRI12oRvmse | A certain bus driver is paid a regular rate of $20 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $1000 in total compensation, how many total hours did he work that week? Select.
A) 46 B) 40 C) 44 D) 48 E) 49 | <gadget id="calculator">20 * 40</gadget>
<output>800</output>
<gadget id="calculator">1_000 - 800</gadget>
<output>200</output>
<gadget id="calculator">100 + 75</gadget>
<output>175</output>
<gadget id="calculator">20 * 175</gadget>
<output>3_500</output>
<gadget id="calculator">3_500 / 100</gadget>
<output>35</output>
<gadget id="calculator">200 / 35</gadget>
<output>40/7 = around 5.714286</output>
<gadget id="calculator">40 + (40/7)</gadget>
<output>320/7 = around 45.714286</output>
<result>A</result> | A | 46 | A certain bus driver is paid a regular rate of $20 per hour for any number of hours that does not exceed 40 hours per week. For any overtime hours worked in excess of 40 hours per week, the bus driver is paid a rate that is 75% higher than his regular rate. If last week the bus driver earned $1000 in total compensation, how many total hours did he work that week? | {
"A": "46",
"B": "40",
"C": "44",
"D": "48",
"E": "49"
} | add(40, divide(subtract(1000, multiply(20, 40)), divide(multiply(20, add(const_100, 75)), const_100))) | add(n3,const_100)|multiply(n0,n1)|multiply(n0,#0)|subtract(n4,#1)|divide(#2,const_100)|divide(#3,#4)|add(n1,#5)| | "for 40 hrs = 40 * 20 = 800 excess = 1000 - 800 = 200 for extra hours = . 75 ( 20 ) = 15 + 20 = 35 number of extra hrs = 200 / 35 = 5.71 = 6 approx . total hrs = 40 + 6 = 46 answer a 46" | general |
math_qa__RGONwL41zRzqmaPc | A cistern normally takes 6 hours to be filled by a tap but because of a leak, 2 hours more. In how many hours will the leak empty a full cistern ? Pick one
A) 20 hours
B) 24 hours
C) 26 hours
D) 18 hours
E) none of these | <gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">2 + 6</gadget>
<output>8</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/6) - (1/8)</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">1 / (1/24)</gadget>
<output>24</output>
<result>B</result> | B | 24 | A cistern normally takes 6 hours to be filled by a tap but because of a leak, 2 hours more. In how many hours will the leak empty a full cistern ? | {
"A": "20 hours",
"B": "24 hours",
"C": "26 hours",
"D": "18 hours",
"E": "none of these"
} | inverse(subtract(inverse(6), inverse(add(2, 6)))) | add(n0,n1)|inverse(n0)|inverse(#0)|subtract(#1,#2)|inverse(#3) | ∵ cistern fill in 6 hours . ∴ in 1 hour , filled part = 1 ⁄ 6 th now , due to leakage , filled part in 1 hour = 1 ⁄ 8 th part of the cistern emptied , due to leakage in 1 hour = 1 ⁄ 6 - 1 ⁄ 8 = 1 ⁄ 24 th ∴ the leakage will empty the full cistern in 24 hrs . answer b | physics |
math_qa__0Z5TXaIFMjWiyuEY | What is the greatest integer m for which the number 20!/10^m is an integer?
Choices: A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">floor(4)</gadget>
<output>4</output>
<result>B</result> | B | 4 | What is the greatest integer m for which the number 20!/10^m is an integer? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | floor(divide(20, divide(10, const_2))) | divide(n1,const_2)|divide(n0,#0)|floor(#1)| | "10 ^ m = 2 ^ m * 5 ^ m . let ' s figure out how many 5 ' s are in the prime factorization of 20 ! the multiples of 5 are : 5 , 10 , 15 , 20 . thus 5 ^ 4 will divide 20 ! but 5 ^ 5 will not . clearly 2 ^ 4 will divide 20 ! so m = 4 is the largest possible integer . the answer is b ." | general |
math_qa__Qtbaspw4PJ582u6W | Doughnuts, Cookies and Muffins in a pastry shop are in the ratio of 5: 3 : 1. If there are 50 Doughnuts, the number of Muffins in the shop is:.
Answers:
A) 25 B) 30 C) 10 D) 15 E) 20 | <gadget id="calculator">50 / 5</gadget>
<output>10</output>
<result>C</result> | C | 10 | Doughnuts, Cookies and Muffins in a pastry shop are in the ratio of 5: 3 : 1. If there are 50 Doughnuts, the number of Muffins in the shop is:. | {
"A": "25",
"B": "30",
"C": "10",
"D": "15",
"E": "20"
} | divide(50, 5) | divide(n3,n0) | explanation : let doughnuts = 5 x , cookies = 3 x & muffins = 1 x . now , 5 x = 50 hence x = 10 . number of muffins = 1 x which is 10 . answer : c | other |
math_qa__Uy1vabhs6UgFUDDO | What least number must be subtracted from 9679 so that the remaining number is divisible by 15? Choose the correct choice.
A) 3
B) 1
C) 16
D) 4
E) 15 | <gadget id="calculator">9_679 / 15</gadget>
<output>9_679/15 = around 645.266667</output>
<gadget id="calculator">floor(9_679/15)</gadget>
<output>645</output>
<gadget id="calculator">645 * 15</gadget>
<output>9_675</output>
<gadget id="calculator">9_679 - 9_675</gadget>
<output>4</output>
<result>D</result> | D | 4 | What least number must be subtracted from 9679 so that the remaining number is divisible by 15? | {
"A": "3",
"B": "1",
"C": "16",
"D": "4",
"E": "15"
} | subtract(9679, multiply(floor(divide(9679, 15)), 15)) | divide(n0,n1)|floor(#0)|multiply(n1,#1)|subtract(n0,#2)| | "on dividing 9679 by 15 , we get remainder = 4 . required number be subtracted = 4 answer : d" | general |
math_qa__kJnP5dXvvRJjdrFX | The ages of two person differ by 20 years. If 8 years ago, the elder one be 5 times as old as the younger one, their present ages(in years) are respectively Choose the correct choice from the following choices:
A) 33 , 13
B) 25 , 5
C) 29 , 9
D) 50 , 30
E) 20,10 | <gadget id="calculator">5 * 8</gadget>
<output>40</output>
<gadget id="calculator">20 - 8</gadget>
<output>12</output>
<gadget id="calculator">40 + 12</gadget>
<output>52</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">52 / 4</gadget>
<output>13</output>
<gadget id="calculator">13 + 20</gadget>
<output>33</output>
<result>A</result> | A | 33 | The ages of two person differ by 20 years. If 8 years ago, the elder one be 5 times as old as the younger one, their present ages(in years) are respectively | {
"A": "33 , 13",
"B": "25 , 5",
"C": "29 , 9",
"D": "50 , 30",
"E": "20,10"
} | add(divide(add(multiply(5, 8), subtract(20, 8)), subtract(5, const_1)), 20) | multiply(n1,n2)|subtract(n0,n1)|subtract(n2,const_1)|add(#0,#1)|divide(#3,#2)|add(n0,#4) | let their ages be x and ( x + 20 ) years . then , 5 ( x - 8 ) = ( x + 20 - 8 ) = > 4 x = 52 = > x = 13 their present ages are 33 years and 13 year . answer : a | general |
math_qa__I0GJeXrcJGRaRgRW | A case of 12 rolls of paper towels sells for $9. The cost of one roll sold individually is $1.What is the percent of savings per roll for the 12-roll package over the cost of 12 rolls purchased individually? Choose the correct answer: A) 9 % B) 11 % C) 15 % D) 25 % E) 90 % | <gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(3/4) * 100</gadget>
<output>75</output>
<gadget id="calculator">100 - 75</gadget>
<output>25</output>
<result>D</result> | D | 25 | A case of 12 rolls of paper towels sells for $9. The cost of one roll sold individually is $1.What is the percent of savings per roll for the 12-roll package over the cost of 12 rolls purchased individually? | {
"A": "9 %",
"B": "11 %",
"C": "15 %",
"D": "25 %",
"E": "90 %"
} | subtract(const_100, multiply(divide(9, 12), const_100)) | divide(n1,n0)|multiply(#0,const_100)|subtract(const_100,#1)| | "cost of 12 paper towels individually = 1 * 12 = 12 cost of a set of 12 paper towels = 9 cost of one roll = 9 / 12 = 3 / 4 = 0.75 savings per roll = 1 - . 75 = 0.25 % of savings is = . 25 / 1 * 100 = 25 % d is the answer ." | general |
math_qa__XOzvM6GoO224dUsb | The difference between compound interest and simple interest on a certain amount of money at 5% per annum for 2 years is 17. Find the sum : Choose the correct choice from the following options.
A) 4500 B) 7500 C) 5000 D) 6800 E) none of these | <gadget id="calculator">5 / 100</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">1 + (1/20)</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">(21/20) ** 2</gadget>
<output>441/400 = around 1.1025</output>
<gadget id="calculator">2 * (1/20)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(441/400) - (11/10)</gadget>
<output>1/400 = around 0.0025</output>
<gadget id="calculator">17 / (1/400)</gadget>
<output>6_800</output>
<result>D</result> | D | 6,800 | The difference between compound interest and simple interest on a certain amount of money at 5% per annum for 2 years is 17. Find the sum : | {
"A": "4500",
"B": "7500",
"C": "5000",
"D": "6800",
"E": "none of these"
} | divide(17, subtract(power(add(const_1, divide(5, const_100)), 2), add(const_1, multiply(2, divide(5, const_100))))) | divide(n0,const_100)|add(#0,const_1)|multiply(n1,#0)|add(#2,const_1)|power(#1,n1)|subtract(#4,#3)|divide(n2,#5) | sol . ( d ) let the sum be 100 . therefore , si = 100 × 5 × 2100 = 10100 × 5 × 2100 = 10 and ci = 100 ( 1 + 5100 ) 2 − 100100 ( 1 + 5100 ) 2 − 100 ∴ = 100 × 21 × 2120 × 20 − 100 = 414 = 100 × 21 × 2120 × 20 − 100 = 414 difference of ci and si = 41 ⁄ 4 - 10 = 1 ⁄ 4 if the difference is 1 ⁄ 4 , the sum = 100 = > if the difference is 17 , the sum = 400 × 17 = 6800 answer d | gain |
math_qa__UhhNlX75IbtTthBo | John left home and drove at the rate of 45 mph for 2 hours. He stopped for lunch then drove for another 3 hours at the rate of 50 mph to reach his destination. How many miles did John drive? Answers:
A) 235 miles .
B) 245 miles .
C) 240 miles .
D) 265 miles .
E) 275 miles . | <gadget id="calculator">45 * 2</gadget>
<output>90</output>
<gadget id="calculator">3 * 50</gadget>
<output>150</output>
<gadget id="calculator">90 + 150</gadget>
<output>240</output>
<result>C</result> | C | 240 | John left home and drove at the rate of 45 mph for 2 hours. He stopped for lunch then drove for another 3 hours at the rate of 50 mph to reach his destination. How many miles did John drive? | {
"A": "235 miles .",
"B": "245 miles .",
"C": "240 miles .",
"D": "265 miles .",
"E": "275 miles ."
} | add(multiply(45, 2), multiply(3, 50)) | multiply(n0,n1)|multiply(n2,n3)|add(#0,#1) | the total distance d traveled by john is given by d = 45 * 2 + 3 * 50 = 240 miles . answer c | physics |
math_qa__tBwtyE7aQM8rJyh1 | What least number must be subtracted from 3830 so that the remaining number is divisible by 15?
Choose the correct choice from the following answers.
A) 3 B) 1 C) 5 D) 11 E) 15 | <gadget id="calculator">3_830 / 15</gadget>
<output>766/3 = around 255.333333</output>
<gadget id="calculator">floor(766/3)</gadget>
<output>255</output>
<gadget id="calculator">255 * 15</gadget>
<output>3_825</output>
<gadget id="calculator">3_830 - 3_825</gadget>
<output>5</output>
<result>C</result> | C | 5 | What least number must be subtracted from 3830 so that the remaining number is divisible by 15? | {
"A": "3",
"B": "1",
"C": "5",
"D": "11",
"E": "15"
} | subtract(3830, multiply(floor(divide(3830, 15)), 15)) | divide(n0,n1)|floor(#0)|multiply(n1,#1)|subtract(n0,#2)| | "on dividing 3830 by 15 , we get remainder = 5 . required number be subtracted = 5 answer : c" | general |
math_qa__zdl3Vt1aZWZbMKFA | In a bag containing 3balls, a white ball was placed and then 1ball was taken out at random. What is the probability that the extracted ball would turn on to be white, if all possible hypothesis concerning the color of theballs that initiallyin the bag were equally possible ?
Select: A) 2 / 3 B) 5 / 8 C) 3 / 5 D) 4 / 7 E) 5 / 8 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">(1/4) + (3/4)</gadget>
<output>1</output>
<gadget id="calculator">(1/2) + 1</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">1 + (3/2)</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) / 4</gadget>
<output>5/8 = around 0.625</output>
<result>B</result> | B | 0.625 | In a bag containing 3balls, a white ball was placed and then 1ball was taken out at random. What is the probability that the extracted ball would turn on to be white, if all possible hypothesis concerning the color of theballs that initiallyin the bag were equally possible ? | {
"A": "2 / 3",
"B": "5 / 8",
"C": "3 / 5",
"D": "4 / 7",
"E": "5 / 8"
} | divide(add(1, add(divide(1, const_2), add(divide(1, add(1, 3)), divide(3, add(1, 3))))), add(1, 3)) | add(n0,n1)|divide(n1,const_2)|divide(n1,#0)|divide(n0,#0)|add(#2,#3)|add(#4,#1)|add(n1,#5)|divide(#6,#0)| | "since , all possible hypothesis regarding the colour of the balls are equally likely , therefore these could be 3 white balls , initially in the bag . ∴ required probability = 1 / 4 [ 1 + 3 / 4 + 1 / 2 + 1 / 4 ] = 1 / 4 [ ( 4 + 3 + 2 + 1 ) / 4 ] = 5 / 8 b" | probability |
math_qa__gCmfjnOnlYeglnQ6 | A flagpole 18 meters high casts a shadow of length 45 meters. If a building under similar conditions casts a shadow of length 50 meters, what is the height of the building (in meters)?
Choose the correct choice from the following options: A) 16 B) 20 C) 24 D) 28 E) 32 | <gadget id="calculator">18 / 45</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">50 * (2/5)</gadget>
<output>20</output>
<result>B</result> | B | 20 | A flagpole 18 meters high casts a shadow of length 45 meters. If a building under similar conditions casts a shadow of length 50 meters, what is the height of the building (in meters)? | {
"A": "16",
"B": "20",
"C": "24",
"D": "28",
"E": "32"
} | multiply(50, divide(18, 45)) | divide(n0,n1)|multiply(n2,#0)| | "the height : length ratio will be equal in both cases . 18 / 45 = x / 50 x = 20 the answer is b ." | physics |
math_qa__NCgbeiD5XqT5nQdW | If 7^(x - y) = 343 and 7^(x + y) = 16807, what is the value of x? Choose the most appropriate option.
A) 3
B) 4
C) 2
D) 1
E) 7 | <gadget id="calculator">7 - 4</gadget>
<output>3</output>
<gadget id="calculator">7 - 2</gadget>
<output>5</output>
<gadget id="calculator">3 + 5</gadget>
<output>8</output>
<gadget id="calculator">8 / 2</gadget>
<output>4</output>
<result>B</result> | B | 4 | If 7^(x - y) = 343 and 7^(x + y) = 16807, what is the value of x? | {
"A": "3",
"B": "4",
"C": "2",
"D": "1",
"E": "7"
} | divide(add(subtract(7, const_4), subtract(7, const_2)), const_2) | subtract(n0,const_4)|subtract(n0,const_2)|add(#0,#1)|divide(#2,const_2) | 7 ^ ( x - y ) = 343 = 7 ^ 3 = > x - y = 3 - - - - - - - - - - - - - - - - - - - - - - - - - - - ( equation 1 ) 7 ^ ( x + y ) = 16807 = 7 ^ 5 = > x + y = 5 - - - - - - - - - - - - - - - - - - - - - - - - - - - ( equation 2 ) ( equation 1 ) + ( equation 2 ) = > 2 x = 3 + 5 = 8 = > x = 8 / 2 = 4 answer is b | general |
math_qa__BtVz4jxPzx3av5yh | 242 students represent x percent of the boys at a school. If the boys at the school make up 50% of the total school population of x students, what is x? Select the correct option
A) 120 B) 150 C) 180 D) 200 E) 220 | <gadget id="calculator">242 * 100</gadget>
<output>24_200</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">24_200 / (1/2)</gadget>
<output>48_400</output>
<gadget id="calculator">48_400 ** (1/2)</gadget>
<output>220</output>
<result>E</result> | E | 220 | 242 students represent x percent of the boys at a school. If the boys at the school make up 50% of the total school population of x students, what is x? | {
"A": "120",
"B": "150",
"C": "180",
"D": "200",
"E": "220"
} | sqrt(divide(multiply(242, const_100), divide(50, const_100))) | divide(n1,const_100)|multiply(n0,const_100)|divide(#1,#0)|sqrt(#2)| | "let b be the number of boys in the school . 242 = xb / 100 b = 0.5 x 24200 = 0.5 x ^ 2 x ^ 2 = 48400 x = 220 the answer is e ." | gain |
math_qa__j1xOALCXAXw62ZcD | A certain number of workers can do a work in 75 days. If there were 10 workers more it could be finished in 10 days less. How many workers are there? Choices:
A) 65 B) 30 C) 28 D) 24 E) 32 | <gadget id="calculator">75 - 10</gadget>
<output>65</output>
<gadget id="calculator">65 * 10</gadget>
<output>650</output>
<gadget id="calculator">75 - 65</gadget>
<output>10</output>
<gadget id="calculator">650 / 10</gadget>
<output>65</output>
<result>A</result> | A | 65 | A certain number of workers can do a work in 75 days. If there were 10 workers more it could be finished in 10 days less. How many workers are there? | {
"A": "65",
"B": "30",
"C": "28",
"D": "24",
"E": "32"
} | divide(multiply(subtract(75, 10), 10), subtract(75, subtract(75, 10))) | subtract(n0,n1)|multiply(n1,#0)|subtract(n0,#0)|divide(#1,#2)| | "number of workers = 10 * ( 75 - 10 ) / 10 = 65 answer is a" | physics |
math_qa__ArNxw8jRmkBpKLO4 | A man spends 2/5 of his salary on house rent, 3/10 of his salary on food and 1/8 of his salary on Conveyance. If he has $1400 left with him,find his expenditure on food and Conveyance. Answers.
A) $ 8600 B) $ 2400 C) $ 1000 D) $ 3000 E) $ 3400 | <gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(2/5) + (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(7/10) + (1/8)</gadget>
<output>33/40 = around 0.825</output>
<gadget id="calculator">1 - (33/40)</gadget>
<output>7/40 = around 0.175</output>
<gadget id="calculator">1_400 / (7/40)</gadget>
<output>8_000</output>
<gadget id="calculator">8_000 * (3/10)</gadget>
<output>2_400</output>
<gadget id="calculator">8_000 * (1/8)</gadget>
<output>1_000</output>
<gadget id="calculator">2_400 + 1_000</gadget>
<output>3_400</output>
<result>E</result> | E | 3,400 | A man spends 2/5 of his salary on house rent, 3/10 of his salary on food and 1/8 of his salary on Conveyance. If he has $1400 left with him,find his expenditure on food and Conveyance. | {
"A": "$ 8600",
"B": "$ 2400",
"C": "$ 1000",
"D": "$ 3000",
"E": "$ 3400"
} | add(multiply(divide(1400, subtract(1, add(add(divide(2, 5), divide(3, 10)), divide(1, 8)))), divide(3, 10)), multiply(divide(1400, subtract(1, add(add(divide(2, 5), divide(3, 10)), divide(1, 8)))), divide(1, 8))) | divide(n0,n1)|divide(n2,n3)|divide(n4,n5)|add(#0,#1)|add(#3,#2)|subtract(n4,#4)|divide(n6,#5)|multiply(#6,#1)|multiply(#6,#2)|add(#7,#8) | remaining part of salary left = 1 - ( 2 / 5 + 3 / 10 + 1 / 8 ) = 1 - ( 33 / 40 ) = 7 / 40 let the monthly salary be $ x then , 7 / 40 of x = $ 1400 x = ( 1400 * 40 / 7 ) = $ 8600 expenditure on food = $ ( 3 / 10 * 800 ) = $ 2400 expenditure on conveyance = $ ( 1 / 8 * 8000 ) = $ 1000 $ 2400 + $ 1000 = $ 3400 so the answer is option e ) $ 3400 | general |
math_qa__Iv3VjSQNNpktrfoz | Some of 15%-intensity red paint is replaced with 25% solution of red paint such that the new paint intensity is 30%. What fraction of the original paint was replaced?
Choose the correct choice from the following answers
A) 1 / 5 B) 1 / 3 C) 1 / 2 D) 3 / 2 E) 3 / 5 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">(3/10) - (3/20)</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">25 / 100</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) - (3/20)</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(3/20) / (1/10)</gadget>
<output>3/2 = around 1.5</output>
<result>D</result> | D | 1.5 | Some of 15%-intensity red paint is replaced with 25% solution of red paint such that the new paint intensity is 30%. What fraction of the original paint was replaced? | {
"A": "1 / 5",
"B": "1 / 3",
"C": "1 / 2",
"D": "3 / 2",
"E": "3 / 5"
} | divide(subtract(divide(30, const_100), divide(15, const_100)), subtract(divide(25, const_100), divide(15, const_100))) | divide(n2,const_100)|divide(n0,const_100)|divide(n1,const_100)|subtract(#0,#1)|subtract(#2,#1)|divide(#3,#4)| | "let total paint = 1 let amount replaced = x 15 ( 1 - x ) + 25 x = 30 x = 3 / 2 answer : d" | gain |
math_qa__BujZlGSzh4DapiN1 | Find the compound interest on $1200 for 2 years at 20% p.a. if CI is component yearly?
Choose the most appropriate option: A) $ 120 B) $ 150 C) $ 548 D) $ 250 E) $ 300 | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 + (1/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) ** 2</gadget>
<output>36/25 = around 1.44</output>
<gadget id="calculator">1_200 * (36/25)</gadget>
<output>1_728</output>
<gadget id="calculator">1_728 - 1_200</gadget>
<output>528</output>
<result>C</result> | C | 548 | Find the compound interest on $1200 for 2 years at 20% p.a. if CI is component yearly? | {
"A": "$ 120",
"B": "$ 150",
"C": "$ 548",
"D": "$ 250",
"E": "$ 300"
} | subtract(multiply(1200, power(add(const_1, divide(20, const_100)), 2)), 1200) | divide(n2,const_100)|add(#0,const_1)|power(#1,n1)|multiply(n0,#2)|subtract(#3,n0) | a = p ( 1 + r / 100 ) ^ t = 1200 ( 1 + 20 / 100 ) ^ 2 = $ 1728 ci = $ 548 answer is c | gain |
math_qa__bmxjlZtrq5qrUy8z | It takes Avery 2 hours to build a brick wall while Tom can do it in 4 hour. If the two start working together and after an hour Avery leaves, how much time will it take Tom to complete the wall on his own? Select the correct option: A) 70 B) 20 C) 50 D) 60 E) 30 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/2) + (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 - (3/4)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/4) / (1/4)</gadget>
<output>1</output>
<gadget id="calculator">1 * 60</gadget>
<output>60</output>
<result>D</result> | D | 60 | It takes Avery 2 hours to build a brick wall while Tom can do it in 4 hour. If the two start working together and after an hour Avery leaves, how much time will it take Tom to complete the wall on his own? | {
"A": "70",
"B": "20",
"C": "50",
"D": "60",
"E": "30"
} | multiply(divide(subtract(const_1, add(divide(const_1, 2), divide(const_1, 4))), divide(const_1, 4)), const_60) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|subtract(const_1,#2)|divide(#3,#1)|multiply(#4,const_60) | avery takes 2 hours tom takes 4 hours efficiency of avery is 1 / 2 units / hr efficiency of tom is 1 / 4 units / hr combined efficiency of tom and avery is 1 / 2 + 1 / 4 = 3 / 4 units / hr since they worked for 1 hour they completed 3 / 4 units of work and 1 / 4 units of work is left which is to be completed by tom ( since avery left ) so time taken by tom to complete the remaining work will be 1 / 4 / 1 / 4 hours = > 1 * 60 = 60 minutes . . . answer will be ( d ) | physics |
math_qa__1qyB8RvYJcy2wGM1 | How many of the integers between 25 and 45 are even ?
Choose the correct choice from the following answers: A) 21 B) 20 C) 11 D) 10 E) 9 | <gadget id="calculator">45 - 25</gadget>
<output>20</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<result>D</result> | D | 10 | How many of the integers between 25 and 45 are even ? | {
"A": "21",
"B": "20",
"C": "11",
"D": "10",
"E": "9"
} | divide(subtract(45, 25), const_2) | subtract(n1,n0)|divide(#0,const_2) | number start between 25 to 45 is 20 numbers half of them is even . . which is 10 answer : d | general |
math_qa__S2iurYKF0WWbwfcu | Bill made a profit of 10% by selling a product. If he had purchased that product for 10% less and sold it at a profit of 30%, he would have received $28 more. What was his original selling price? Select the correct option.
A) $ 200 B) $ 260 C) $ 320 D) $ 380 E) $ 440 | <gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 + (3/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">(9/10) * (13/10)</gadget>
<output>117/100 = around 1.17</output>
<gadget id="calculator">1 + (1/10)</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(117/100) - (11/10)</gadget>
<output>7/100 = around 0.07</output>
<gadget id="calculator">28 / (7/100)</gadget>
<output>400</output>
<gadget id="calculator">400 * (11/10)</gadget>
<output>440</output>
<result>E</result> | E | 440 | Bill made a profit of 10% by selling a product. If he had purchased that product for 10% less and sold it at a profit of 30%, he would have received $28 more. What was his original selling price? | {
"A": "$ 200",
"B": "$ 260",
"C": "$ 320",
"D": "$ 380",
"E": "$ 440"
} | multiply(divide(28, subtract(multiply(subtract(const_1, divide(10, const_100)), add(const_1, divide(30, const_100))), add(const_1, divide(10, const_100)))), add(const_1, divide(10, const_100))) | divide(n0,const_100)|divide(n2,const_100)|add(#0,const_1)|add(#1,const_1)|subtract(const_1,#0)|multiply(#3,#4)|subtract(#5,#2)|divide(n3,#6)|multiply(#2,#7)| | "let p be the original purchase price of the product . bill originally sold the product for 1.1 * p . in the second scenario , the purchase price is 0.9 * p . a 30 % profit means the selling price would be 1.3 * 0.9 * p = 1.17 * p thus , according to the information in the question , 1.17 p - 1.1 p = 28 0.07 = 28 p = 400 the original selling price was 400 * 1.1 = 440 . the correct answer is e ." | general |
math_qa__111MJ7XjF0E2rUPX | If 0.4 of a number is equal to 0.07 of another number, the ratio of the numbers i Choose the correct option
A) 2 : 3
B) 7 : 40
C) 3 : 20
D) 20 : 3
E) none | <gadget id="calculator">0.07 * 100</gadget>
<output>7</output>
<gadget id="calculator">0.4 * 100</gadget>
<output>40</output>
<gadget id="calculator">7 / 40</gadget>
<output>7/40 = around 0.175</output>
<result>B</result> | B | 0.175 | If 0.4 of a number is equal to 0.07 of another number, the ratio of the numbers i | {
"A": "2 : 3",
"B": "7 : 40",
"C": "3 : 20",
"D": "20 : 3",
"E": "none"
} | divide(multiply(0.07, const_100), multiply(0.4, const_100)) | multiply(n1,const_100)|multiply(n0,const_100)|divide(#0,#1)| | "sol . 0.4 a = 0.08 b â ‡ ” a / b = 0.07 / 0.40 = 7 / 40 . â ˆ ´ a : b = 7 : 40 . answer b" | other |
math_qa__v4BO3bFl8bbfeVfd | sixty 5 percent of a number is 21 less than 4 fifth of that number . what is the number Choose the most appropriate option
A) 140 B) 165 C) 150 D) 142 E) 174 | <gadget id="calculator">21 * 100</gadget>
<output>2_100</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">2_100 / 15</gadget>
<output>140</output>
<result>A</result> | A | 140 | sixty 5 percent of a number is 21 less than 4 fifth of that number . what is the number | {
"A": "140",
"B": "165",
"C": "150",
"D": "142",
"E": "174"
} | divide(multiply(21, const_100), multiply(const_3, 5)) | multiply(n1,const_100)|multiply(n0,const_3)|divide(#0,#1) | let the number be x . then , 4 * x / 5 – ( 65 % of x ) = 21 4 x / 5 – 65 x / 100 = 21 5 x = 2100 x = 140 . answer a 140 | general |
math_qa__fnTdjoYQqPbUort6 | The speed of a car is 140 km in the first hour and 40 km in the second hour. What is the average speed of the car? Choose the correct choice from the following answers.
A) 72 kmph B) 75 kmph C) 30 kmph D) 90 kmph E) 82 kmph | <gadget id="calculator">140 + 40</gadget>
<output>180</output>
<gadget id="calculator">180 / 2</gadget>
<output>90</output>
<result>D</result> | D | 90 | The speed of a car is 140 km in the first hour and 40 km in the second hour. What is the average speed of the car? | {
"A": "72 kmph",
"B": "75 kmph",
"C": "30 kmph",
"D": "90 kmph",
"E": "82 kmph"
} | divide(add(140, 40), const_2) | add(n0,n1)|divide(#0,const_2)| | "s = ( 140 + 40 ) / 2 = 90 kmph answer : d" | physics |
math_qa__fcqqJYjV0lLsI1mX | A train of 50 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long? Choose the correct choice from the following options.
A) 6
B) 3
C) 4
D) 4.5
E) 2 | <gadget id="calculator">50 + 1</gadget>
<output>51</output>
<gadget id="calculator">51 * 60</gadget>
<output>3_060</output>
<gadget id="calculator">3_060 / 1_000</gadget>
<output>153/50 = around 3.06</output>
<gadget id="calculator">(153/50) + 1.5</gadget>
<output>4.56</output>
<result>D</result> | D | 4.5 | A train of 50 carriages, each of 60 meters length, when an engine also of 60 meters length is running at a speed of 60 kmph. In what time will the train cross a bridge 1.5 km long? | {
"A": "6",
"B": "3",
"C": "4",
"D": "4.5",
"E": "2"
} | add(divide(multiply(add(50, const_1), 60), const_1000), 1.5) | add(n0,const_1)|multiply(n1,#0)|divide(#1,const_1000)|add(n4,#2)| | "d = 50 * 60 + 1500 = 3000 m t = 4500 / 60 * 18 / 5 = 270 sec = 4.5 mins answer : d" | physics |
math_qa__qNmFBbjkTfIT1TCg | 12 buckets of water fill a tank when the capacity of each bucket is 49 litres. How many buckets will be needed to fill the same tank, if the capacity of each bucket is 7 litres? Select:
A) 39
B) 84
C) 80
D) 82
E) 86 | <gadget id="calculator">49 * 12</gadget>
<output>588</output>
<gadget id="calculator">588 / 7</gadget>
<output>84</output>
<result>B</result> | B | 84 | 12 buckets of water fill a tank when the capacity of each bucket is 49 litres. How many buckets will be needed to fill the same tank, if the capacity of each bucket is 7 litres? | {
"A": "39",
"B": "84",
"C": "80",
"D": "82",
"E": "86"
} | divide(multiply(49, 12), 7) | multiply(n0,n1)|divide(#0,n2) | capacity of the tank = ( 12 ã — 49 ) litre number of buckets required of capacity of each bucket is 17 litre = 12 ã — 49 / 7 = 12 ã — 7 = 84 answer is b | physics |
math_qa__RRQk6FvON3iQXJxd | If n is an integer and 101n^2 is less than or equal to 8100, what is the greatest possible value of n? Choose the correct choice from the following options:
A) 7
B) 8
C) 9
D) 10
E) 11 | <gadget id="calculator">8_100 / 101</gadget>
<output>8_100/101 = around 80.19802</output>
<gadget id="calculator">(8_100/101) ** (1/2)</gadget>
<output>90*sqrt(101)/101 = around 8.955335</output>
<gadget id="calculator">floor(90*sqrt(101)/101)</gadget>
<output>8</output>
<result>B</result> | B | 8 | If n is an integer and 101n^2 is less than or equal to 8100, what is the greatest possible value of n? | {
"A": "7",
"B": "8",
"C": "9",
"D": "10",
"E": "11"
} | floor(sqrt(divide(8100, 101))) | divide(n2,n0)|sqrt(#0)|floor(#1)| | "101 * n ^ 2 < = 8100 n ^ 2 < = 8100 / 101 which will be less than 81 since 8100 / 100 = 81 which is the square of 9 next closest value of n where n ^ 2 < = 81 is 8 ans b" | general |
math_qa__bRRlIRSCGL7zB8rR | If the perimeter of a rectangular garden is 950 m, its length when its breadth is 100 m is? Choose the correct choice from the following.
A) 338 m B) 778 m C) 375 m D) 276 m E) 971 m | <gadget id="calculator">950 / 2</gadget>
<output>475</output>
<gadget id="calculator">475 - 100</gadget>
<output>375</output>
<result>C</result> | C | 375 | If the perimeter of a rectangular garden is 950 m, its length when its breadth is 100 m is? | {
"A": "338 m",
"B": "778 m",
"C": "375 m",
"D": "276 m",
"E": "971 m"
} | subtract(divide(950, const_2), 100) | divide(n0,const_2)|subtract(#0,n1)| | "2 ( l + 100 ) = 950 = > l = 375 m answer : c" | physics |
math_qa__ZYWdbDpI7guEPfXg | a certain league has two divisions . the respective divisions had 11 and 13 teams qualify for the playoffs . each division held its own double - elimination tournament - - where a team is eliminated from the tournament upon losing two games - - in order to determine its champion . the 4 division champions then played in a single - elimination tournament - - where a team is eliminated upon losing one game - - in order to determine the overall league champion . assuming that there were no ties and no forfeits , what is the maximum number of games that could have been played in order to determine the overall league champion ? Choose one:
A) 41
B) 42
C) 45
D) 47
E) 49 | <gadget id="calculator">13 * 2</gadget>
<output>26</output>
<gadget id="calculator">26 - 1</gadget>
<output>25</output>
<gadget id="calculator">11 * 2</gadget>
<output>22</output>
<gadget id="calculator">22 - 1</gadget>
<output>21</output>
<gadget id="calculator">25 + 21</gadget>
<output>46</output>
<result>D</result> | D | 47 | a certain league has two divisions . the respective divisions had 11 and 13 teams qualify for the playoffs . each division held its own double - elimination tournament - - where a team is eliminated from the tournament upon losing two games - - in order to determine its champion . the 4 division champions then played in a single - elimination tournament - - where a team is eliminated upon losing one game - - in order to determine the overall league champion . assuming that there were no ties and no forfeits , what is the maximum number of games that could have been played in order to determine the overall league champion ? | {
"A": "41",
"B": "42",
"C": "45",
"D": "47",
"E": "49"
} | add(subtract(multiply(13, const_2), const_1), subtract(multiply(11, const_2), const_1)) | multiply(n1,const_2)|multiply(n0,const_2)|subtract(#0,const_1)|subtract(#1,const_1)|add(#2,#3) | overall , there can be 47 minuses . tus , it is d . | general |
math_qa__WzysoILqyUHtQJpr | If the ratio of a to b is 5 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c? Choose the correct option: A) 4 / 15 B) 1 / 3 C) 2 / 5 D) 4 / 5 E) 7 / 6 | <gadget id="calculator">5 * 1</gadget>
<output>5</output>
<gadget id="calculator">3 * 5</gadget>
<output>15</output>
<gadget id="calculator">5 / 15</gadget>
<output>1/3 = around 0.333333</output>
<result>B</result> | B | 0.333333 | If the ratio of a to b is 5 to 3 and the ratio of b to c is 1 to 5, what is the ratio of a to c? | {
"A": "4 / 15",
"B": "1 / 3",
"C": "2 / 5",
"D": "4 / 5",
"E": "7 / 6"
} | divide(multiply(5, 1), multiply(3, 5)) | multiply(n0,n2)|multiply(n1,n3)|divide(#0,#1)| | "a : b = 5 : 3 - - 1 b : c = 1 : 5 = > b : c = 3 : 15 - - 2 from 1 and 2 , we get a : c = 4 : 15 answer b" | other |
math_qa__lHqmAwnolZTZi4HU | It takes printer A 4 more minutes more than printer B to print 40 pages. Working together, the two printers can print 50 pages in 6 minutes. How long will it take Printer A to print 100 pages? Choices:
A) 12 B) 18 C) 20 D) 24 E) 30 | <gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 + 4</gadget>
<output>12</output>
<gadget id="calculator">100 * 12</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 40</gadget>
<output>30</output>
<result>E</result> | E | 30 | It takes printer A 4 more minutes more than printer B to print 40 pages. Working together, the two printers can print 50 pages in 6 minutes. How long will it take Printer A to print 100 pages? | {
"A": "12",
"B": "18",
"C": "20",
"D": "24",
"E": "30"
} | divide(multiply(100, add(multiply(4, const_2), 4)), 40) | multiply(n0,const_2)|add(n0,#0)|multiply(n4,#1)|divide(#2,n1)| | "if it takes 4 more minutes for a to print 40 pages than it takes b , it takes 5 more minutes for a to print 50 pages than it takes b . thus if b is the number of minutes than b takes to print 50 pages , we can write : 1 / b + 1 / ( b + 5 ) = 1 / 6 ( since in 1 minute , they print 1 / 6 th of the 50 page job ) 6 ( 2 b + 5 ) = b ( b + 5 ) b ^ 2 - 7 b - 30 = 0 ( b - 10 ) ( b + 3 ) = 0 b = 10 thus it takes a 15 minutes to print 50 pages and 15 * 100 / 50 = 30 minutes to print 100 pages ( answer e )" | physics |
math_qa__xJ8qjdgHC4ftfiBX | What does the hexa number E78 in radix 7. Choose one.
A) 12455 B) 14153 C) 14256 D) 13541 E) 14541 | <gadget id="calculator">78 * 7</gadget>
<output>546</output>
<gadget id="calculator">10 + 3</gadget>
<output>13</output>
<gadget id="calculator">100 * 10</gadget>
<output>1_000</output>
<gadget id="calculator">13 * 1_000</gadget>
<output>13_000</output>
<gadget id="calculator">546 + 13_000</gadget>
<output>13_546</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">13_546 - 5</gadget>
<output>13_541</output>
<result>D</result> | D | 13,541 | What does the hexa number E78 in radix 7. | {
"A": "12455",
"B": "14153",
"C": "14256",
"D": "13541",
"E": "14541"
} | subtract(add(multiply(78, 7), multiply(add(const_10, const_3), multiply(const_100, const_10))), add(const_4, const_1)) | add(const_10,const_3)|add(const_1,const_4)|multiply(n0,n1)|multiply(const_10,const_100)|multiply(#0,#3)|add(#2,#4)|subtract(#5,#1) | conversion of hexa decimal to decimal ( e 78 ) = ( 8 * 16 ^ 0 ) + ( 7 * 16 ^ 1 ) + ( 14 * 16 ^ 2 ) = 8 + 112 + 3584 = 3704 conversion of decimal to radix 7 3704 / 7 : reminder : 1 and dividend : 529 529 / 7 : reminder : 4 and dividend : 75 75 / 7 : reminder : 5 and dividend : 10 10 / 7 : reminder : 3 and dividend : 1 1 / 7 : reminder 1 then finally result is : 13541 answer : d | general |
math_qa__fGmDE0OzZKHHtPhN | Rs.1170 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share? Choose one:
A) rs . 720 B) rs . 920 C) rs . 537 D) rs . 540 E) rs . 637 | <gadget id="calculator">4 + 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 3</gadget>
<output>9</output>
<gadget id="calculator">1_170 / 9</gadget>
<output>130</output>
<gadget id="calculator">4 * 130</gadget>
<output>520</output>
<result>D</result> | D | 540 | Rs.1170 is divided so that 4 times the first share, thrice the 2nd share and twice the third share amount to the same. What is the value of the third share? | {
"A": "rs . 720",
"B": "rs . 920",
"C": "rs . 537",
"D": "rs . 540",
"E": "rs . 637"
} | multiply(4, divide(1170, add(add(4, 2), const_3))) | add(n1,n2)|add(#0,const_3)|divide(n0,#1)|multiply(n1,#2) | a + b + c = 1170 4 a = 3 b = 2 c = x a : b : c = 1 / 4 : 1 / 3 : 1 / 2 = 3 : 4 : 6 6 / 13 * 1170 = rs . 540 answer : d | general |
math_qa__SdNhZn1kCLJUiT4h | How much is 55% of 40 is greater than 4/5 of 25?
Pick one:
A) 29 B) 776 C) 2 D) 12 E) 99 | <gadget id="calculator">55 / 100</gadget>
<output>11/20 = around 0.55</output>
<gadget id="calculator">40 * (11/20)</gadget>
<output>22</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 25</gadget>
<output>20</output>
<gadget id="calculator">22 - 20</gadget>
<output>2</output>
<result>C</result> | C | 2 | How much is 55% of 40 is greater than 4/5 of 25? | {
"A": "29",
"B": "776",
"C": "2",
"D": "12",
"E": "99"
} | subtract(multiply(40, divide(55, const_100)), multiply(divide(4, 5), 25)) | divide(n0,const_100)|divide(n2,n3)|multiply(n1,#0)|multiply(n4,#1)|subtract(#2,#3)| | "( 55 / 100 ) * 40 – ( 4 / 5 ) * 25 22 - 20 = 2 answer : c" | general |
math_qa__Z1sI69dDJodpcpdv | Find large number from below question The difference of two numbers is 1515. On dividing the larger number by the smaller, we get 16 as quotient and the 15 as remainder Choose the correct option:
A) 1209
B) 1615
C) 1245
D) 1300
E) 1635 | <gadget id="calculator">1_515 - 15</gadget>
<output>1_500</output>
<gadget id="calculator">16 - 1</gadget>
<output>15</output>
<gadget id="calculator">1_500 / 15</gadget>
<output>100</output>
<gadget id="calculator">100 * 16</gadget>
<output>1_600</output>
<result>B</result> | B | 1,615 | Find large number from below question The difference of two numbers is 1515. On dividing the larger number by the smaller, we get 16 as quotient and the 15 as remainder | {
"A": "1209",
"B": "1615",
"C": "1245",
"D": "1300",
"E": "1635"
} | multiply(divide(subtract(1515, 15), subtract(16, const_1)), 16) | subtract(n0,n2)|subtract(n1,const_1)|divide(#0,#1)|multiply(n1,#2)| | "let the smaller number be x . then larger number = ( x + 1515 ) . x + 1515 = 16 x + 15 15 x = 1500 x = 100 large number = 100 + 1515 = 1615 answer : b" | general |
math_qa__DmuZEMMflNdg3PGa | The price of a T.V. set worth Rs. 60000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be?
Choose one
A) 22678 B) 59000 C) 26788 D) 19000 E) 26711 | <gadget id="calculator">60_000 - 1_000</gadget>
<output>59_000</output>
<result>B</result> | B | 59,000 | The price of a T.V. set worth Rs. 60000 is to be paid in 20 installments of Rs. 1000 each. If the rate of interest be 6% per annum, and the first installment be paid at the time of purchase, then the value of the last installment covering the interest as well will be? | {
"A": "22678",
"B": "59000",
"C": "26788",
"D": "19000",
"E": "26711"
} | subtract(60000, 1000) | subtract(n0,n2)| | "money paid in cash = rs . 1000 balance payment = ( 60000 - 1000 ) = rs . 59000 answer : b" | gain |
math_qa__GViaPByL7XZRlCpA | A rectangular grass field is 65 m * 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m?
Pick:
A) 1350 B) 1971 C) 9676 D) 1679 E) 1250 | <gadget id="calculator">2.5 * 2</gadget>
<output>5</output>
<gadget id="calculator">65 + 5</gadget>
<output>70</output>
<gadget id="calculator">55 + 5</gadget>
<output>60</output>
<gadget id="calculator">70 * 60</gadget>
<output>4_200</output>
<gadget id="calculator">65 * 55</gadget>
<output>3_575</output>
<gadget id="calculator">4_200 - 3_575</gadget>
<output>625</output>
<gadget id="calculator">625 * 2</gadget>
<output>1_250</output>
<result>E</result> | E | 1,250 | A rectangular grass field is 65 m * 55 m, it has a path of 2.5 m wide all round it on the outside. Find the area of the path and the cost of constructing it at Rs.2 per sq m? | {
"A": "1350",
"B": "1971",
"C": "9676",
"D": "1679",
"E": "1250"
} | multiply(subtract(rectangle_area(add(65, multiply(2.5, 2)), add(55, multiply(2.5, 2))), rectangle_area(65, 55)), 2) | multiply(n2,n3)|rectangle_area(n0,n1)|add(n0,#0)|add(n1,#0)|rectangle_area(#2,#3)|subtract(#4,#1)|multiply(n3,#5)| | "area = ( l + b + 2 d ) 2 d = ( 65 + 55 + 2.5 * 2 ) 2 * 2.5 = > 625 625 * 2 = rs . 1250 answer : e" | geometry |
math_qa__ZJhMfTgiCt4boDKk | David spends $350 buying his favorite dolls. If he buys only small LemonHead dolls, which are $2 cheaper than the large LemonHead dolls, he could buy 20 more dolls than if he were to buy only large LemonHead dolls. How much does a large LemonHead doll cost? Choose the correct choice from the following.
A) $ 5 B) $ 7 C) $ 6 D) $ 8 E) $ 9 | <gadget id="calculator">350 / 10</gadget>
<output>35</output>
<gadget id="calculator">20 - 2</gadget>
<output>18</output>
<gadget id="calculator">18 + 10</gadget>
<output>28</output>
<gadget id="calculator">35 - 28</gadget>
<output>7</output>
<result>B</result> | B | 7 | David spends $350 buying his favorite dolls. If he buys only small LemonHead dolls, which are $2 cheaper than the large LemonHead dolls, he could buy 20 more dolls than if he were to buy only large LemonHead dolls. How much does a large LemonHead doll cost? | {
"A": "$ 5",
"B": "$ 7",
"C": "$ 6",
"D": "$ 8",
"E": "$ 9"
} | subtract(divide(350, const_10), add(subtract(20, 2), const_10)) | divide(n0,const_10)|subtract(n2,n1)|add(#1,const_10)|subtract(#0,#2) | if large doll costs $ 5 , then he can buy 350 / 5 = 70 large dolls and 350 / 3 = 116 small dolls . difference is more than 20 . discard . if large doll costs $ 7 , then he can buy 350 / 7 = 50 large dolls and 350 / 5 = 70 small dolls . difference is 20 , which is we wanted . answer b . | general |
math_qa__2YZAjillfuoepjhx | If 12!/3^x is an integer, what is the greatest possible value of x? Pick:
A) 3 B) 4 C) 5 D) 6 E) 7 | <gadget id="calculator">12 / 3</gadget>
<output>4</output>
<gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">4 + (3/4)</gadget>
<output>19/4 = around 4.75</output>
<result>C</result> | C | 5 | If 12!/3^x is an integer, what is the greatest possible value of x? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | add(divide(12, 3), divide(3, divide(12, 3))) | divide(n0,n1)|divide(n1,#0)|add(#0,#1)| | "this question is asking how many power of 3 exists in 12 ! easiest way is to identify factor of three 12 - > 4 * 3 = > 1 power of 3 9 - > 3 * 3 = > 2 power of 3 6 - > 2 * 3 = > 1 power of 3 3 - > 1 * 3 = > 1 power of 3 total equal 5 answer : c" | general |
math_qa__hDSYNkuYBtZe75Py | Arnold and Danny are two twin brothers that are celebrating their birthday. The product of their ages today is smaller by 13 from the product of their ages a year from today. What is their age today? Choose the correct answer.
A) 2 . B) 6 . C) 5 . D) 7 . E) 9 . | <gadget id="calculator">13 - 1</gadget>
<output>12</output>
<gadget id="calculator">12 / 2</gadget>
<output>6</output>
<result>B</result> | B | 6 | Arnold and Danny are two twin brothers that are celebrating their birthday. The product of their ages today is smaller by 13 from the product of their ages a year from today. What is their age today? | {
"A": "2 .",
"B": "6 .",
"C": "5 .",
"D": "7 .",
"E": "9 ."
} | divide(subtract(13, const_1), const_2) | subtract(n0,const_1)|divide(#0,const_2) | ad = ( a + 1 ) ( d + 1 ) - 13 0 = a + d - 12 a + d = 12 a = d ( as they are twin brothers ) a = d = 6 b is the answer | general |
math_qa__86RM7K0IMB2n72fd | A metal company's old machine makes bolts at a constant rate of 100 bolts per hour. The company's new machine makes bolts at a constant rate of 150 bolts per hour. If both machines start at the same time and continue making bolts simultaneously, how many minutes will it take the two machines to make a total of 350 bolts? Choose one:
A) 84 B) 72 C) 120 D) 144 E) 180 | <gadget id="calculator">100 / 60</gadget>
<output>5/3 = around 1.666667</output>
<gadget id="calculator">150 / 60</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/3) + (5/2)</gadget>
<output>25/6 = around 4.166667</output>
<gadget id="calculator">350 / (25/6)</gadget>
<output>84</output>
<result>A</result> | A | 84 | A metal company's old machine makes bolts at a constant rate of 100 bolts per hour. The company's new machine makes bolts at a constant rate of 150 bolts per hour. If both machines start at the same time and continue making bolts simultaneously, how many minutes will it take the two machines to make a total of 350 bolts? | {
"A": "84",
"B": "72",
"C": "120",
"D": "144",
"E": "180"
} | divide(350, add(divide(100, const_60), divide(150, const_60))) | divide(n0,const_60)|divide(n1,const_60)|add(#0,#1)|divide(n2,#2) | old machine 100 bolts in 60 mins so , 5 / 3 bolts in 1 min new machine 150 bolts in 60 mins so , 5 / 2 bolts in 1 min together , 5 / 3 + 5 / 2 = 25 / 6 bolts in 1 min so , for 350 bolts 350 * 6 / 25 = 84 mins ans a | physics |
math_qa__wExR4Jmdf8lkP5rq | what is the minimum possible range in scores of the 3 test - takers ? 3 people each took 5 tests . if the ranges of their scores in the 5 practice tests were 18 , 26 and 32 . Choose the correct option.
A) 26 B) 32 C) 18 D) 20 E) 30 | <gadget id="calculator">32 - 26</gadget>
<output>6</output>
<gadget id="calculator">6 * 5</gadget>
<output>30</output>
<result>E</result> | E | 30 | what is the minimum possible range in scores of the 3 test - takers ? 3 people each took 5 tests . if the ranges of their scores in the 5 practice tests were 18 , 26 and 32 . | {
"A": "26",
"B": "32",
"C": "18",
"D": "20",
"E": "30"
} | multiply(subtract(32, 26), 5) | subtract(n6,n5)|multiply(n2,#0) | i simply looked at the 3 different possible scores for each individual test : 18 , 32,26 we have to find the minimum range : 32 - 18 = 14 32 - 26 = 6 26 - 18 = 8 the find the minimum range , you have to make the set of the 5 scores as small as possible . which means that 4 of the 5 scores of each individual person is zero . 6 * 5 = 30 answer : e | general |
math_qa__EBF8ZB7sco5Gccmy | A leak in the bottom of a tank can empty the full tank in 8 hours. An inlet pipe fills water at the rate of 6 litres a minute. When the tank is full, the inlet is opened and due to the leak, the tank is empty in 12 hours. How many litres does the cistern hold? Choose the correct choice from the following answers:
A) 7580 B) 7960 C) 8290 D) 8640 E) none | <gadget id="calculator">12 * 60</gadget>
<output>720</output>
<gadget id="calculator">6 * 720</gadget>
<output>4_320</output>
<gadget id="calculator">8 * 60</gadget>
<output>480</output>
<gadget id="calculator">720 / 480</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) - 1</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">4_320 / (1/2)</gadget>
<output>8_640</output>
<result>D</result> | D | 8,640 | A leak in the bottom of a tank can empty the full tank in 8 hours. An inlet pipe fills water at the rate of 6 litres a minute. When the tank is full, the inlet is opened and due to the leak, the tank is empty in 12 hours. How many litres does the cistern hold? | {
"A": "7580",
"B": "7960",
"C": "8290",
"D": "8640",
"E": "none"
} | divide(multiply(6, multiply(12, const_60)), subtract(divide(multiply(12, const_60), multiply(8, const_60)), const_1)) | multiply(n2,const_60)|multiply(n0,const_60)|divide(#0,#1)|multiply(n1,#0)|subtract(#2,const_1)|divide(#3,#4)| | "solution work done by the inlet in 1 hour = ( 1 / 8 - 1 / 12 ) = 1 / 24 . work done by the inlet in 1 min . = ( 1 / 24 × 1 / 60 ) = 1 / 1440 . volume of 1 / 1440 part = 6 litres . therefore , volume of whole = ( 1440 × 6 ) ‹ = › 8640 litres . answer d" | physics |
math_qa__b45hnXqUFHLa6Csh | How many hours in one year?
Choose the correct choice from the following answers.
A) 365 B) 52 C) 1024 D) 8760 E) no one knows | <gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">360 + 5</gadget>
<output>365</output>
<gadget id="calculator">4 * 3</gadget>
<output>12</output>
<gadget id="calculator">12 * 2</gadget>
<output>24</output>
<gadget id="calculator">365 * 24</gadget>
<output>8_760</output>
<result>D</result> | D | 8,760 | How many hours in one year? | {
"A": "365",
"B": "52",
"C": "1024",
"D": "8760",
"E": "no one knows"
} | multiply(add(divide(const_3600, const_10), divide(const_10, const_2)), multiply(multiply(const_4, const_3), const_2)) | divide(const_3600,const_10)|divide(const_10,const_2)|multiply(const_3,const_4)|add(#0,#1)|multiply(#2,const_2)|multiply(#3,#4) | the day has 24 hours , and the year contains 365 days . so the hours exist in one year is the multiplication of 24 by 365 . so the answer = 365 * 24 = 8760 hours so the correct answer is d | physics |
math_qa__pF80TgOSsw00OuyO | If k is a non-negative integer and 15^k is a divisor of 759,325 then 3^k - k^3 = Choose the correct choice from the following choices: A) 0 B) 1 C) 37 D) 118 E) 513 | <gadget id="calculator">1 - 1</gadget>
<output>0</output>
<gadget id="calculator">3 ** 0</gadget>
<output>1</output>
<gadget id="calculator">0 ** 3</gadget>
<output>0</output>
<gadget id="calculator">1 - 0</gadget>
<output>1</output>
<result>B</result> | B | 1 | If k is a non-negative integer and 15^k is a divisor of 759,325 then 3^k - k^3 = | {
"A": "0",
"B": "1",
"C": "37",
"D": "118",
"E": "513"
} | subtract(power(3, subtract(const_1, const_1)), power(subtract(const_1, const_1), 3)) | subtract(const_1,const_1)|power(n2,#0)|power(#0,n2)|subtract(#1,#2)| | "at first we should understand whether 759325 divisible by 15 . 15 is equal to 3 * 5 so 759325 should be divisible on these integers 759325 is divisible by 5 because of last digit 5 but not divisible by 3 because sum of its digits does n ' t divisible by 3 : 7 + 5 + 9 + 3 + 2 + 5 = 31 and 31 does n ' t divisible by 3 so 759325 can be divisible by 15 ^ k only if k = 0 and 15 ^ k = 1 so 3 ^ k - k ^ 3 = 1 - 0 = 1 answer is b" | general |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.