id stringlengths 25 25 | question stringlengths 45 1.01k | chain stringlengths 75 4.11k | result stringclasses 5 values | result_float float64 -4,212 100B | question_without_options stringlengths 6 962 | options dict | annotated_formula stringlengths 7 6.48k | linear_formula stringlengths 8 925 | rationale stringlengths 1 2.74k | category stringclasses 6 values |
|---|---|---|---|---|---|---|---|---|---|---|
math_qa__rhFznzYKUS4MzOaC | A train , 800 meter long is running with a speed of 78 km/hr. It crosses a tunnel in 1 minute. What is the length of the tunnel (in meters)? Select: A) 440 m B) 500 m C) 260 m D) 430 m E) 450 m | <gadget id="calculator">78 * 1_000</gadget>
<output>78_000</output>
<gadget id="calculator">78_000 / 3_600</gadget>
<output>65/3 = around 21.666667</output>
<gadget id="calculator">(65/3) * 60</gadget>
<output>1_300</output>
<gadget id="calculator">1_300 - 800</gadget>
<output>500</output>
<result>B</result> | B | 500 | A train , 800 meter long is running with a speed of 78 km/hr. It crosses a tunnel in 1 minute. What is the length of the tunnel (in meters)? | {
"A": "440 m",
"B": "500 m",
"C": "260 m",
"D": "430 m",
"E": "450 m"
} | subtract(multiply(divide(multiply(78, const_1000), const_3600), const_60), 800) | multiply(n1,const_1000)|divide(#0,const_3600)|multiply(#1,const_60)|subtract(#2,n0)| | "explanation : distance = 800 + x meter where x is the length of the tunnel time = 1 minute = 60 seconds speed = 78 km / hr = 78 × 10 / 36 m / s = 130 / 6 = 65 / 3 m / s distance / time = speed ( 800 + x ) / 60 = 65 / 3 = > 800 + x = 20 × 65 = 1300 = > x = 1300 - 800 = 500 meter answer : option b" | physics |
math_qa__m1uH6EbZooEkPtv3 | A library has an average of 150 visitors on sundays and 120 on other days . The avearge number of visitors per day in a month of 30 days beginning with a sunday is? Choose the correct choice from the following options
A) 50
B) 75
C) 150
D) 125
E) 100 | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">30 / 7</gadget>
<output>30/7 = around 4.285714</output>
<gadget id="calculator">floor(30/7)</gadget>
<output>4</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 150</gadget>
<output>750</output>
<gadget id="calculator">30 - 5</gadget>
<output>25</output>
<gadget id="calculator">25 * 120</gadget>
<output>3_000</output>
<gadget id="calculator">750 + 3_000</gadget>
<output>3_750</output>
<gadget id="calculator">3_750 / 30</gadget>
<output>125</output>
<result>D</result> | D | 125 | A library has an average of 150 visitors on sundays and 120 on other days . The avearge number of visitors per day in a month of 30 days beginning with a sunday is? | {
"A": "50",
"B": "75",
"C": "150",
"D": "125",
"E": "100"
} | divide(add(multiply(add(floor(divide(30, add(const_3, const_4))), const_1), 150), multiply(subtract(30, add(floor(divide(30, add(const_3, const_4))), const_1)), 120)), 30) | add(const_3,const_4)|divide(n2,#0)|floor(#1)|add(#2,const_1)|multiply(n0,#3)|subtract(n2,#3)|multiply(n1,#5)|add(#4,#6)|divide(#7,n2)| | "since the month begin with sunday , so there will be five sundays in the month required average = ( 150 * 5 + 120 * 25 ) / 30 = 3750 / 30 = 125 answer is d" | general |
math_qa__vL1k3uxq4KBUU2h0 | In a company of 200 employees, 120 are females. A total of 100 employees have advanced degrees and the rest have a college degree only. If 40 employees are males with a college degree only, how many employees are females with advanced degrees?
Pick
A) 60 B) 70 C) 80 D) 90 E) 100 | <gadget id="calculator">200 - 120</gadget>
<output>80</output>
<gadget id="calculator">80 - 40</gadget>
<output>40</output>
<gadget id="calculator">100 - 40</gadget>
<output>60</output>
<result>A</result> | A | 60 | In a company of 200 employees, 120 are females. A total of 100 employees have advanced degrees and the rest have a college degree only. If 40 employees are males with a college degree only, how many employees are females with advanced degrees? | {
"A": "60",
"B": "70",
"C": "80",
"D": "90",
"E": "100"
} | subtract(100, subtract(subtract(200, 120), 40)) | subtract(n0,n1)|subtract(#0,n3)|subtract(n2,#1)| | "the number of males is 200 - 120 = 80 . the number of males with advanced degrees is 80 - 40 = 40 . the number of females with advanced degrees is 100 - 40 = 60 . the answer is a ." | geometry |
math_qa__XWJxxXijwfWYUV7F | In what ratio should a variety of rice costing Rs. 4.5 per kg be mixed with another variety of rice costing Rs. 8.75 per kg to obtain a mixture costing Rs. 7.50 per kg? Choose the correct choice from the following options: A) 5 / 6 B) 5 / 9 C) 5 / 1 D) 5 / 3 E) 5 / 12 | <gadget id="calculator">8.75 - 7.5</gadget>
<output>1.25</output>
<gadget id="calculator">8.75 - 4.5</gadget>
<output>4.25</output>
<gadget id="calculator">1.25 / 4.25</gadget>
<output>0.294118</output>
<gadget id="calculator">1 - 0.294118</gadget>
<output>0.705882</output>
<gadget id="calculator">0.294118 / 0.705882</gadget>
<output>0.416667</output>
<result>E</result> | E | 0.416667 | In what ratio should a variety of rice costing Rs. 4.5 per kg be mixed with another variety of rice costing Rs. 8.75 per kg to obtain a mixture costing Rs. 7.50 per kg? | {
"A": "5 / 6",
"B": "5 / 9",
"C": "5 / 1",
"D": "5 / 3",
"E": "5 / 12"
} | divide(divide(subtract(8.75, 7.50), subtract(8.75, 4.5)), subtract(const_1, divide(subtract(8.75, 7.50), subtract(8.75, 4.5)))) | subtract(n1,n2)|subtract(n1,n0)|divide(#0,#1)|subtract(const_1,#2)|divide(#2,#3)| | "let us say the ratio of the quantities of cheaper and dearer varieties = x : y by the rule of allegation , x / y = ( 8.75 - 7.50 ) / ( 7.50 - 4.5 ) = 5 / 12 answer : e" | other |
math_qa__MGnZNeyYyQbUe1bn | In a certain pond, 60 fish were caught, tagged, and returned to the pond. A few days later, 60 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what`s the approximate number of fish in the pond? Choose the correct answer:
A) 400 B) 625 C) 1818 D) 2500 E) 10 000 | <gadget id="calculator">2 / 60</gadget>
<output>1/30 = around 0.033333</output>
<gadget id="calculator">60 / (1/30)</gadget>
<output>1_800</output>
<result>C</result> | C | 1,818 | In a certain pond, 60 fish were caught, tagged, and returned to the pond. A few days later, 60 fish were caught again, of which 2 were found to have been tagged. If the percent of tagged fish in the second catch approximates the percent of tagged fish in the pond, what`s the approximate number of fish in the pond? | {
"A": "400",
"B": "625",
"C": "1818",
"D": "2500",
"E": "10 000"
} | divide(60, divide(2, 60)) | divide(n2,n1)|divide(n0,#0)| | "the percent of tagged fish in the second catch is 2 / 60 * 100 = 3.33 % . we are told that 3.33 % approximates the percent of tagged fish in the pond . since there are 60 tagged fish , then we have 0.033 x = 60 - - > x = 1,818 . answer : c ." | gain |
math_qa__GM8W4aOHzH2JFSwa | Tickets numbered from 1 to 21 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bears a number which is a multiple of 3? Choose one.
A) 1 / 3
B) 2 / 5
C) 3 / 10
D) 3 / 7
E) 1 / 7 | <gadget id="calculator">21 / 3</gadget>
<output>7</output>
<gadget id="calculator">7 / 21</gadget>
<output>1/3 = around 0.333333</output>
<result>A</result> | A | 0.333333 | Tickets numbered from 1 to 21 are mixed and then a ticket is selected randomly. What is the probability that the selected ticket bears a number which is a multiple of 3? | {
"A": "1 / 3",
"B": "2 / 5",
"C": "3 / 10",
"D": "3 / 7",
"E": "1 / 7"
} | divide(divide(21, 3), 21) | divide(n1,n2)|divide(#0,n1)| | "here , s = [ 1 , 2 , 3 , 4 , … . , 19 , 20 , 21 ] let e = event of getting a multiple of 3 = [ 3 , 6 , 9 , 12 , 15 , 18 , 21 ] p ( e ) = n ( e ) / n ( s ) = 7 / 21 = 1 / 3 the answer is a ." | general |
math_qa__JzqGJxccPYAVd53L | A sum was put at simple interest at certain rate for 3 years. Had it been put at 1% higher rate it would have fetched Rs. 63 more. The sum is: A. Rs. 2,400 B. Rs. 2,100 C. Rs. 2,200 D.Rs. 2,480 Choose the most appropriate option: A) 2000 B) 2100 C) 2200 D) 2300 E) 2400 | <gadget id="calculator">63 / 3</gadget>
<output>21</output>
<gadget id="calculator">21 * 100</gadget>
<output>2_100</output>
<result>B</result> | B | 2,100 | A sum was put at simple interest at certain rate for 3 years. Had it been put at 1% higher rate it would have fetched Rs. 63 more. The sum is: A. Rs. 2,400 B. Rs. 2,100 C. Rs. 2,200 D.Rs. 2,480 | {
"A": "2000",
"B": "2100",
"C": "2200",
"D": "2300",
"E": "2400"
} | multiply(divide(63, 3), const_100) | divide(n2,n0)|multiply(#0,const_100)| | "1 percent for 3 years = 63 1 percent for 1 year = 21 = > 100 percent = 2100 answer : b" | gain |
math_qa__CRC2RDZZP7gVsSPM | 128 students represent x percent of the boys at a school. If the boys at the school make up 50% of the total school population of x students, what is x? Choose the most appropriate option:
A) 160 B) 190 C) 225 D) 250 E) 500 | <gadget id="calculator">128 * 100</gadget>
<output>12_800</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">12_800 / (1/2)</gadget>
<output>25_600</output>
<gadget id="calculator">25_600 ** (1/2)</gadget>
<output>160</output>
<result>A</result> | A | 160 | 128 students represent x percent of the boys at a school. If the boys at the school make up 50% of the total school population of x students, what is x? | {
"A": "160",
"B": "190",
"C": "225",
"D": "250",
"E": "500"
} | sqrt(divide(multiply(128, const_100), divide(50, const_100))) | divide(n1,const_100)|multiply(n0,const_100)|divide(#1,#0)|sqrt(#2) | let b be the number of boys in the school . 128 = xb / 100 b = 0.5 x 12800 = 0.5 x ^ 2 x ^ 2 = 25600 x = 160 the answer is a . | gain |
math_qa__2uPlxfgVARu6YlqZ | A basket contains 5 apples, of which 1 is spoiled and the rest are good. If Henry is to select 2 apples from the basket simultaneously and at random, what is the possibility that the 2 apples selected will include the spoiled apple?
Select:
A) 1 / 5 B) 3 / 10 C) 2 / 5 D) 1 / 2 E) 3 / 5 | <gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">binomial(4, 1)</gadget>
<output>4</output>
<gadget id="calculator">binomial(5, 2)</gadget>
<output>10</output>
<gadget id="calculator">4 / 10</gadget>
<output>2/5 = around 0.4</output>
<result>C</result> | C | 0.4 | A basket contains 5 apples, of which 1 is spoiled and the rest are good. If Henry is to select 2 apples from the basket simultaneously and at random, what is the possibility that the 2 apples selected will include the spoiled apple? | {
"A": "1 / 5",
"B": "3 / 10",
"C": "2 / 5",
"D": "1 / 2",
"E": "3 / 5"
} | divide(choose(subtract(5, 1), 1), choose(5, 2)) | choose(n0,n2)|subtract(n0,n1)|choose(#1,n1)|divide(#2,#0)| | "p ( both apples are not spoiled ) = 4 c 2 / 5 c 2 = 4 * 3 / 5 * 4 = 3 / 5 p ( one of the apple spoiled ) = 1 - 3 / 5 = 2 / 5 answer is c ." | general |
math_qa__PaH8Nhd6m98PHFrz | the difference in compound interest earned on a deposit ( compounded annually ) in year 1 and year 2 is $ 40 . had the interest rate been 3 times its present value , the difference w would have been how much ?
Select the correct option
A) 40 / 3 B) 40 C) 120 D) 360 E) 420 | <gadget id="calculator">40 * 3</gadget>
<output>120</output>
<gadget id="calculator">120 * 3</gadget>
<output>360</output>
<result>D</result> | D | 360 | the difference in compound interest earned on a deposit ( compounded annually ) in year 1 and year 2 is $ 40 . had the interest rate been 3 times its present value , the difference w would have been how much ? | {
"A": "40 / 3",
"B": "40",
"C": "120",
"D": "360",
"E": "420"
} | multiply(multiply(40, 3), 3) | multiply(n2,n3)|multiply(n3,#0) | case 1 : deposit = $ x ; rate of increase = r . interest yearned in 1 year = xr . deposit in 1 year = x + xr . interest yearned in 2 year = ( x + xr ) r . the difference w = ( x + xr ) r - xr = xr ^ 2 = 40 . case 2 : deposit = $ x ; rate of increase = 3 r . interest yearned in 1 year = x ( 3 r ) . deposit in 1 year = x + 3 xr . interest yearned in 2 year = ( x + 3 xr ) 3 r . the difference = ( x + 3 xr ) 3 r - 3 xr = 9 xr ^ 2 . since from case 1 we know that xr ^ 2 = 40 , then 9 xr ^ 2 = 9 * 40 = 360 . answer : d . | general |
math_qa__Pp07eFItZUBOivSe | The sides of a rectangular field are in the ratio 3 : 4. If the area of the field is 7500 sq. m, the cost of fencing the field @ 25 paise per metre is Pick:
A) rs . 55.50
B) rs . 67.50
C) rs . 86.50
D) rs . 87.50
E) none of these | <gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">7_500 / 12</gadget>
<output>625</output>
<gadget id="calculator">625 ** (1/2)</gadget>
<output>25</output>
<gadget id="calculator">3 * 25</gadget>
<output>75</output>
<gadget id="calculator">4 * 25</gadget>
<output>100</output>
<gadget id="calculator">2 * (75 + 100)</gadget>
<output>350</output>
<gadget id="calculator">350 * 25</gadget>
<output>8_750</output>
<gadget id="calculator">8_750 / 100</gadget>
<output>175/2 = around 87.5</output>
<result>D</result> | D | 87.5 | The sides of a rectangular field are in the ratio 3 : 4. If the area of the field is 7500 sq. m, the cost of fencing the field @ 25 paise per metre is | {
"A": "rs . 55.50",
"B": "rs . 67.50",
"C": "rs . 86.50",
"D": "rs . 87.50",
"E": "none of these"
} | divide(multiply(rectangle_perimeter(multiply(3, sqrt(divide(7500, multiply(3, 4)))), multiply(4, sqrt(divide(7500, multiply(3, 4))))), 25), const_100) | multiply(n0,n1)|divide(n2,#0)|sqrt(#1)|multiply(n0,#2)|multiply(n1,#2)|rectangle_perimeter(#3,#4)|multiply(n3,#5)|divide(#6,const_100)| | "solution let length = ( 3 x ) metres and breadth = ( 4 x ) metres . then , 3 x × 4 x = 7500 ⇔ 12 x 2 = 7500 ⇔ x 2 = 625 ⇔ x = 25 . so , length = 75 m and breadth = 100 m . perimeter = [ 2 ( 75 + 100 ) ] m = 350 m . ∴ cost of fencing = rs . ( 0.25 × 350 ) = rs . 87.50 . answer d" | physics |
math_qa__G2zS7gni3KDKzmxP | The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is
Choose the correct answer.
A) 38 %
B) 40 %
C) 44 %
D) 48 %
E) 50 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(6/5) * (6/5)</gadget>
<output>36/25 = around 1.44</output>
<gadget id="calculator">(36/25) - 1</gadget>
<output>11/25 = around 0.44</output>
<gadget id="calculator">(11/25) * 100</gadget>
<output>44</output>
<result>C</result> | C | 44 | The percentage increase in the area of a rectangle, if each of its sides is increased by 20% is | {
"A": "38 %",
"B": "40 %",
"C": "44 %",
"D": "48 %",
"E": "50 %"
} | multiply(subtract(multiply(divide(add(const_100, 20), const_100), divide(add(const_100, 20), const_100)), const_1), const_100) | add(n0,const_100)|divide(#0,const_100)|multiply(#1,#1)|subtract(#2,const_1)|multiply(#3,const_100) | let original length = x metres and original breadth = y metres . original area = ( xy ) m 2 . new length = 120 x m = 6 x m . 100 5 new breadth = 120 y m = 6 y m . 100 5 new area = 6 x x 6 y m 2 = 36 xy m 2 . 5 5 25 the difference between the original area = xy and new - area 36 / 25 xy is = ( 36 / 25 ) xy - xy = xy ( 36 / 25 - 1 ) = xy ( 11 / 25 ) or ( 11 / 25 ) xy increase % = 11 xy x 1 x 100 % = 44 % . 25 xy c ) | geometry |
math_qa__tjwl7SjqMxt9reue | Find the area of the quadrilateral of one of its diagonals is 28 cm and its off sets 8 cm and 2 cm? Pick:
A) 140 cm 2 B) 150 cm 2 C) 168 cm 2 D) 182 cm 2 E) 200 cm 2 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">2 + 8</gadget>
<output>10</output>
<gadget id="calculator">(1/2) * 10</gadget>
<output>5</output>
<gadget id="calculator">5 * 28</gadget>
<output>140</output>
<result>A</result> | A | 140 | Find the area of the quadrilateral of one of its diagonals is 28 cm and its off sets 8 cm and 2 cm? | {
"A": "140 cm 2",
"B": "150 cm 2",
"C": "168 cm 2",
"D": "182 cm 2",
"E": "200 cm 2"
} | multiply(multiply(divide(const_1, const_2), add(2, 8)), 28) | add(n1,n2)|divide(const_1,const_2)|multiply(#0,#1)|multiply(n0,#2)| | "1 / 2 * 28 ( 8 + 2 ) = 140 cm 2 answer : a" | geometry |
math_qa__vH3n9sfSqjc4USQn | 3 machines operating independently , simultaneously , and at the same constant rate can fill a certain production order in 44 hours . if one additional machine were used under the same operating conditions , in how manyfewerhours of simultaneous operation could the production order be fulfilled ? Choose the correct choice from the following options
A) 6
B) 9
C) 12
D) 11
E) 48 | <gadget id="calculator">3 * 44</gadget>
<output>132</output>
<gadget id="calculator">3 + 1</gadget>
<output>4</output>
<gadget id="calculator">132 / 4</gadget>
<output>33</output>
<gadget id="calculator">44 - 33</gadget>
<output>11</output>
<result>D</result> | D | 11 | 3 machines operating independently , simultaneously , and at the same constant rate can fill a certain production order in 44 hours . if one additional machine were used under the same operating conditions , in how manyfewerhours of simultaneous operation could the production order be fulfilled ? | {
"A": "6",
"B": "9",
"C": "12",
"D": "11",
"E": "48"
} | subtract(44, divide(multiply(3, 44), add(3, const_1))) | add(n0,const_1)|multiply(n0,n1)|divide(#1,#0)|subtract(n1,#2) | if 3 machines can do the work in 44 hr then 4 machines can do the work in 3 / 4 * 44 = 33 hrs . hence time saved will be 11 hr option d is the correct answer | general |
math_qa__vNN3fwL3UUNIxvbR | In a certain business school class, p students are accounting majors, q students are finance majors, r students are marketing majors, and s students are strategy majors. If pqrs = 1365, and if 1< p < q < r < s, how many students in the class are accounting majors? Choose the correct choice from the following answers:
A) 3
B) 5
C) 8
D) 11
E) 17 | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">5 + 2</gadget>
<output>7</output>
<gadget id="calculator">5 * 7</gadget>
<output>35</output>
<gadget id="calculator">10 + 3</gadget>
<output>13</output>
<gadget id="calculator">35 * 13</gadget>
<output>455</output>
<gadget id="calculator">1_365 / 455</gadget>
<output>3</output>
<result>A</result> | A | 3 | In a certain business school class, p students are accounting majors, q students are finance majors, r students are marketing majors, and s students are strategy majors. If pqrs = 1365, and if 1< p < q < r < s, how many students in the class are accounting majors? | {
"A": "3",
"B": "5",
"C": "8",
"D": "11",
"E": "17"
} | divide(1365, multiply(multiply(add(const_2, const_3), add(add(const_2, const_3), const_2)), add(const_10, const_3))) | add(const_10,const_3)|add(const_2,const_3)|add(#1,const_2)|multiply(#1,#2)|multiply(#0,#3)|divide(n0,#4) | pqrs = 1365 = 3 * 5 * 7 * 13 since 1 < p < q < r < s , the number of students who are accounting majors is p = 3 . the answer is a . | gain |
math_qa__99FB2ZEWQEj93i92 | A train 250 m long is running at a speed of 58 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train? Choose the correct choice from the following answers
A) 5 sec B) 9 sec C) 12 sec D) 18 sec E) 15 sec | <gadget id="calculator">58 - 8</gadget>
<output>50</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">50 * (5/18)</gadget>
<output>125/9 = around 13.888889</output>
<gadget id="calculator">250 / (125/9)</gadget>
<output>18</output>
<result>D</result> | D | 18 | A train 250 m long is running at a speed of 58 kmph. How long does it take to pass a man who is running at 8 kmph in the same direction as the train? | {
"A": "5 sec",
"B": "9 sec",
"C": "12 sec",
"D": "18 sec",
"E": "15 sec"
} | divide(250, multiply(subtract(58, 8), const_0_2778)) | subtract(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "answer : d . speed of the train relative to man = ( 58 - 8 ) kmph = ( 50 * 5 / 18 ) m / sec = ( 125 / 9 ) m / sec time taken by the train to cross the man = time taken by it to cover 250 m at 125 / 9 m / sec = 250 * 9 / 125 sec = 18 sec" | physics |
math_qa__6Hx5J8c76zCWyQF2 | On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars abroad the ship. If 50 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship's passengers held round-trip tickets? Answers
A) 33.3 %
B) 40 %
C) 50 %
D) 60 %
E) 66.6 % | <gadget id="calculator">100 - 50</gadget>
<output>50</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">20 / (1/2)</gadget>
<output>40</output>
<result>B</result> | B | 40 | On a certain transatlantic crossing, 20 percent of a ship's passengers held round-trip tickets and also took their cars abroad the ship. If 50 percent of the passengers with round-trip tickets did not take their cars abroad the ship, what percent of the ship's passengers held round-trip tickets? | {
"A": "33.3 %",
"B": "40 %",
"C": "50 %",
"D": "60 %",
"E": "66.6 %"
} | divide(20, divide(subtract(const_100, 50), const_100)) | subtract(const_100,n1)|divide(#0,const_100)|divide(n0,#1)| | "0.20 p = rt + c 0.5 ( rt ) = no c = > 0.50 ( rt ) had c 0.20 p = 0.50 ( rt ) rt / p = 40 % answer - b" | gain |
math_qa__3Jy2NSS2d8NAI9su | In the fifth grade at Parkway elementary school there are 420 students. 312 students are boys and 250 students are playing soccer. 86% of the students that play soccer are boys. How many girl student are in Parkway that is not playing soccer? Choose the correct choice from the following answers
A) 69 . B) 73 . C) 81 D) 91 E) 108 | <gadget id="calculator">420 - 312</gadget>
<output>108</output>
<gadget id="calculator">250 * 86</gadget>
<output>21_500</output>
<gadget id="calculator">21_500 / 100</gadget>
<output>215</output>
<gadget id="calculator">250 - 215</gadget>
<output>35</output>
<gadget id="calculator">108 - 35</gadget>
<output>73</output>
<result>B</result> | B | 73 | In the fifth grade at Parkway elementary school there are 420 students. 312 students are boys and 250 students are playing soccer. 86% of the students that play soccer are boys. How many girl student are in Parkway that is not playing soccer? | {
"A": "69 .",
"B": "73 .",
"C": "81",
"D": "91",
"E": "108"
} | subtract(subtract(420, 312), subtract(250, divide(multiply(250, 86), const_100))) | multiply(n2,n3)|subtract(n0,n1)|divide(#0,const_100)|subtract(n2,#2)|subtract(#1,#3) | total students = 420 boys = 312 , girls = 108 total playing soccer = 250 86 % of 250 = 215 are boys who play soccer . girls who play soccer = 35 . total girls who do not play soccer = 108 - 35 = 73 . correct option : b | gain |
math_qa__zCPI9m761GIZ5ZNO | A mobile battery in 1 hour charges to 20 percent.How much time (in minute) will it require more to charge to 60 percent. Answers.
A) 145 B) 150 C) 175 D) 180 E) 130 | <gadget id="calculator">60 / 20</gadget>
<output>3</output>
<gadget id="calculator">3 * 60</gadget>
<output>180</output>
<result>D</result> | D | 180 | A mobile battery in 1 hour charges to 20 percent.How much time (in minute) will it require more to charge to 60 percent. | {
"A": "145",
"B": "150",
"C": "175",
"D": "180",
"E": "130"
} | multiply(divide(60, 20), const_60) | divide(n2,n1)|multiply(#0,const_60)| | 1 hr = 20 percent . thus 15 min = 5 percent . now to charge 60 percent 180 min . answer : d | physics |
math_qa__4DoZUjfWkplhZxkJ | If n is an integer, f(n) = f(n-1) - n and f(4)=14. What is the value of f(6)? Choose the correct choice from the following choices:
A) 3 B) 0 C) 1 D) 2 E) 4 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">14 - 5</gadget>
<output>9</output>
<gadget id="calculator">9 - 6</gadget>
<output>3</output>
<result>A</result> | A | 3 | If n is an integer, f(n) = f(n-1) - n and f(4)=14. What is the value of f(6)? | {
"A": "3",
"B": "0",
"C": "1",
"D": "2",
"E": "4"
} | subtract(subtract(14, add(1, 4)), 6) | add(n0,n1)|subtract(n2,#0)|subtract(#1,n3)| | "since f ( n ) = f ( n - 1 ) - n then : f ( 6 ) = f ( 5 ) - 6 and f ( 5 ) = f ( 4 ) - 5 . as given that f ( 4 ) = 14 then f ( 5 ) = 14 - 5 = 9 - - > substitute the value of f ( 5 ) back into the first equation : f ( 6 ) = f ( 5 ) - 6 = 9 - 6 = 3 . answer : a . questions on funtions to practice :" | general |
math_qa__AGYv6B5C3QExDmLL | The banker’s discount of a certain sum of money is Rs. 80 and the true discount on the same sum for the same time is Rs. 70. The sum due is Choose the correct choice from the following answers:
A) 210
B) 280
C) 560
D) 450
E) none | <gadget id="calculator">80 * 70</gadget>
<output>5_600</output>
<gadget id="calculator">80 - 70</gadget>
<output>10</output>
<gadget id="calculator">5_600 / 10</gadget>
<output>560</output>
<result>C</result> | C | 560 | The banker’s discount of a certain sum of money is Rs. 80 and the true discount on the same sum for the same time is Rs. 70. The sum due is | {
"A": "210",
"B": "280",
"C": "560",
"D": "450",
"E": "none"
} | divide(multiply(80, 70), subtract(80, 70)) | multiply(n0,n1)|subtract(n0,n1)|divide(#0,#1)| | "sol . sum = b . d . * t . d . / b . d . - t . d . = rs . [ 80 * 70 / 80 - 70 ] = rs . [ 80 * 70 / 10 ] = rs . 560 answer c" | gain |
math_qa__o5i43pMj1cdomQTT | In what time will a train 150 m long cross an electric pole, it its speed be 144 km/hr? Options:
A) 2.5 sec B) 1.9 sec C) 3.8 sec D) 6.9 sec E) 2.9 sec | <gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">144 * (5/18)</gadget>
<output>40</output>
<gadget id="calculator">150 / 40</gadget>
<output>15/4 = around 3.75</output>
<result>C</result> | C | 3.8 | In what time will a train 150 m long cross an electric pole, it its speed be 144 km/hr? | {
"A": "2.5 sec",
"B": "1.9 sec",
"C": "3.8 sec",
"D": "6.9 sec",
"E": "2.9 sec"
} | divide(150, multiply(144, const_0_2778)) | multiply(n1,const_0_2778)|divide(n0,#0)| | "speed = 144 * 5 / 18 = 40 m / sec time taken = 150 / 40 = 3.8 sec . answer : c" | physics |
math_qa__SSxVU0tuqktHx4Sq | What is the smallest number which, when increased by 9, is divisible by 8, 11, and 24? Choose the correct choice
A) 237 B) 246 C) 255 D) 264 E) 273 | <gadget id="calculator">lcm(24, 11)</gadget>
<output>264</output>
<gadget id="calculator">264 - 9</gadget>
<output>255</output>
<result>C</result> | C | 255 | What is the smallest number which, when increased by 9, is divisible by 8, 11, and 24? | {
"A": "237",
"B": "246",
"C": "255",
"D": "264",
"E": "273"
} | subtract(lcm(24, 11), 9) | lcm(n2,n3)|subtract(#0,n0) | lcm ( 8 , 11,24 ) = 24 x 11 = 264 so the least divisible number is 264 , and the number we are looking for is 264 - 9 = 255 . the answer is c . | general |
math_qa__dCzwD1w74OKKI966 | A glass was filled with 10 ounces of water, and 0.02 ounce of the water evaporated each day during a 20-day period. What percent of the original amount of water evaporated during this period? Choose the correct choice from the following answers.
A) 0.004 % B) 0.02 % C) 0.2 % D) 4 % E) 40 % | <gadget id="calculator">0.02 * 20</gadget>
<output>0.4</output>
<gadget id="calculator">0.4 / 10</gadget>
<output>0.04</output>
<gadget id="calculator">0.04 * 100</gadget>
<output>4</output>
<result>D</result> | D | 4 | A glass was filled with 10 ounces of water, and 0.02 ounce of the water evaporated each day during a 20-day period. What percent of the original amount of water evaporated during this period? | {
"A": "0.004 %",
"B": "0.02 %",
"C": "0.2 %",
"D": "4 %",
"E": "40 %"
} | multiply(divide(multiply(0.02, 20), 10), const_100) | multiply(n1,n2)|divide(#0,n0)|multiply(#1,const_100) | we are given that 0.02 ounces of water evaporated each day . furthermore , we know that this process happened over a 20 - day period . to calculate the total amount of water that evaporated during this time frame we need to multiply 0.02 by 20 . this gives us : 0.02 x 20 = 0.4 ounces finally , we are asked for “ what percent ” of the original amount of water evaporated during this period . to determine this percentage , we have to make sure we translate the expression correctly . we can translate it to : ( amount evaporated / original amount ) x 100 % ( 0.4 / 10 ) x 100 % ( 4 / 100 ) x 100 % = 4 % answer d | gain |
math_qa__SX2zopnr2l3Zp5jh | I sold a book at a profit of 10%. Had I sold it for $140 more, 15% would have been gained. Find the cost price? Select the correct option: A) $ 2000 B) $ 2500 C) $ 3000 D) $ 2800 E) $ 1540 | <gadget id="calculator">140 * 10</gadget>
<output>1_400</output>
<gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">1_400 / 5</gadget>
<output>280</output>
<gadget id="calculator">280 * 100</gadget>
<output>28_000</output>
<gadget id="calculator">28_000 / 10</gadget>
<output>2_800</output>
<result>D</result> | D | 2,800 | I sold a book at a profit of 10%. Had I sold it for $140 more, 15% would have been gained. Find the cost price? | {
"A": "$ 2000",
"B": "$ 2500",
"C": "$ 3000",
"D": "$ 2800",
"E": "$ 1540"
} | divide(multiply(divide(multiply(140, 10), subtract(15, 10)), const_100), 10) | multiply(n0,n1)|subtract(n2,n0)|divide(#0,#1)|multiply(#2,const_100)|divide(#3,n0)| | "115 % of cost - 110 % of cost = $ 140 5 % of cost = $ 140 cost = 140 * 100 / 5 = $ 2800 answer is d" | gain |
math_qa__elABCOByCIC1ZAiN | A glass was filled with 15 ounces of water, and 0.05 ounce of the water evaporated each day during a 15-day period. What percent of the original amount of water evaporated during this period? Choose the correct choice from the following answers: A) 0.005 % B) 0.05 % C) 0.5 % D) 5 % E) 25 % | <gadget id="calculator">0.05 * 15</gadget>
<output>0.75</output>
<gadget id="calculator">0.75 / 15</gadget>
<output>0.05</output>
<gadget id="calculator">0.05 * 100</gadget>
<output>5</output>
<result>D</result> | D | 5 | A glass was filled with 15 ounces of water, and 0.05 ounce of the water evaporated each day during a 15-day period. What percent of the original amount of water evaporated during this period? | {
"A": "0.005 %",
"B": "0.05 %",
"C": "0.5 %",
"D": "5 %",
"E": "25 %"
} | multiply(divide(multiply(0.05, 15), 15), const_100) | multiply(n1,n2)|divide(#0,n0)|multiply(#1,const_100)| | "in 15 days 15 * 0.05 = 0.75 ounces of water evaporated , which is 0.75 / 15 â ˆ — 100 = 5 of the original amount of water . answer : d ." | gain |
math_qa__LpvNDvmrcvjtbPuk | A can do a piece of work in 15 days. A does the work for 5 days only and leaves the job. B does the remaining work in 10 days.In how many days B alone can do the work? Choose one: A) 5 days B) 15 days C) 12 days D) 9 days E) 10 days | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 / 15</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">5 * (1/15)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 - (1/3)</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(1/10) * (2/3)</gadget>
<output>1/15 = around 0.066667</output>
<gadget id="calculator">1 / (1/15)</gadget>
<output>15</output>
<result>B</result> | B | 15 | A can do a piece of work in 15 days. A does the work for 5 days only and leaves the job. B does the remaining work in 10 days.In how many days B alone can do the work? | {
"A": "5 days",
"B": "15 days",
"C": "12 days",
"D": "9 days",
"E": "10 days"
} | inverse(multiply(inverse(10), subtract(const_1, multiply(5, inverse(15))))) | inverse(n2)|inverse(n0)|multiply(n1,#1)|subtract(const_1,#2)|multiply(#0,#3)|inverse(#4)| | "explanation : a ’ s 5 day work = 5 * 1 / 15 = 1 / 3 remaining work = 1 - 1 / 3 = 2 / 3 b completes 2 / 3 work in 6 days b alone can do in x days 2 / 3 * x = 10 x = 15 days answer : option b" | physics |
math_qa__Z9s6ruEh1piDmj5V | In a hostel there were 100 students. To accommodate 25 more students the average is decreased by rupees 10. But total expenditure increased by Rs.500. Find the total expenditure of the hostel now? Options.
A) 7500
B) 5000
C) 5400
D) 7000
E) 8500 | <gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 * 10</gadget>
<output>1_250</output>
<gadget id="calculator">1_250 + 500</gadget>
<output>1_750</output>
<gadget id="calculator">1_750 / 25</gadget>
<output>70</output>
<gadget id="calculator">70 - 10</gadget>
<output>60</output>
<gadget id="calculator">60 * 125</gadget>
<output>7_500</output>
<result>A</result> | A | 7,500 | In a hostel there were 100 students. To accommodate 25 more students the average is decreased by rupees 10. But total expenditure increased by Rs.500. Find the total expenditure of the hostel now? | {
"A": "7500",
"B": "5000",
"C": "5400",
"D": "7000",
"E": "8500"
} | multiply(subtract(divide(add(multiply(add(100, 25), 10), 500), 25), 10), add(100, 25)) | add(n0,n1)|multiply(n2,#0)|add(n3,#1)|divide(#2,n1)|subtract(#3,n2)|multiply(#0,#4) | let average is x 100 x + 500 = 125 ( x – 10 ) x = 70 100 * 70 + 500 = 7500 answer : a | general |
math_qa__wF5ZF1IKeMtS9HT4 | The area of a square is 4356 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square. Choose the correct option
A) 5 : 28
B) 5 : 19
C) 7 : 12
D) 5 : 13
E) 7 : 22 | <gadget id="calculator">4_356 ** (1/2)</gadget>
<output>66</output>
<gadget id="calculator">66 - 24</gadget>
<output>42</output>
<gadget id="calculator">66 * 2</gadget>
<output>132</output>
<gadget id="calculator">42 / 132</gadget>
<output>7/22 = around 0.318182</output>
<result>E</result> | E | 0.318182 | The area of a square is 4356 sq cm. Find the ratio of the breadth and the length of a rectangle whose length is twice the side of the square and breadth is 24 cm less than the side of the square. | {
"A": "5 : 28",
"B": "5 : 19",
"C": "7 : 12",
"D": "5 : 13",
"E": "7 : 22"
} | divide(subtract(sqrt(4356), 24), multiply(sqrt(4356), const_2)) | sqrt(n0)|multiply(#0,const_2)|subtract(#0,n1)|divide(#2,#1)| | "let the length and the breadth of the rectangle be l cm and b cm respectively . let the side of the square be a cm . a 2 = 4356 a = 66 l = 2 a and b = a - 24 b : l = a - 24 : 2 a = 42 : 132 = 7 : 22 answer : e" | geometry |
math_qa__BCWSlCU9RjQcnubP | Pat, Kate, and Mark charged a total of 144 hours to a certain project. If Pat charged twice as much time to the project as Kate and 1/3 as much time as Mark, how many more hours did Mark charge to the project than Kate? Choose the correct choice: A) 18 B) 80 C) 72 D) 90 E) 108 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 + (1/3)</gadget>
<output>4/3 = around 1.333333</output>
<gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(4/3) + (1/6)</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">144 / (3/2)</gadget>
<output>96</output>
<gadget id="calculator">96 / 6</gadget>
<output>16</output>
<gadget id="calculator">96 - 16</gadget>
<output>80</output>
<result>B</result> | B | 80 | Pat, Kate, and Mark charged a total of 144 hours to a certain project. If Pat charged twice as much time to the project as Kate and 1/3 as much time as Mark, how many more hours did Mark charge to the project than Kate? | {
"A": "18",
"B": "80",
"C": "72",
"D": "90",
"E": "108"
} | subtract(divide(144, add(add(1, divide(1, 3)), divide(1, multiply(3, const_2)))), divide(divide(144, add(add(1, divide(1, 3)), divide(1, multiply(3, const_2)))), multiply(3, const_2))) | divide(n1,n2)|multiply(n2,const_2)|add(n1,#0)|divide(n1,#1)|add(#2,#3)|divide(n0,#4)|divide(#5,#1)|subtract(#5,#6)| | "80 all u do is do 2 : 1 : 6 = > 2 x + x + 6 x = 144 = > x = 16 32 : 16 : 96 96 - 16 = 80 answer b" | general |
math_qa__KJnF7t11kaeAon3s | At the end of the first quarter, the share price of a certain mutual fund was 30 percent higher than it was at the beginning of the year. At the end of the second quarter, the share price was 50 percent higher than it was at the beginning of the year. What was the percent increase in the share price from the end of the first quarter to the end of the second quarter? Choose the most appropriate option
A) 15.3 % B) 25 % C) 30 % D) 33 % E) 40 % | <gadget id="calculator">100 + 50</gadget>
<output>150</output>
<gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">150 / 130</gadget>
<output>15/13 = around 1.153846</output>
<gadget id="calculator">(15/13) - 1</gadget>
<output>2/13 = around 0.153846</output>
<gadget id="calculator">(2/13) * 100</gadget>
<output>200/13 = around 15.384615</output>
<result>A</result> | A | 15.3 | At the end of the first quarter, the share price of a certain mutual fund was 30 percent higher than it was at the beginning of the year. At the end of the second quarter, the share price was 50 percent higher than it was at the beginning of the year. What was the percent increase in the share price from the end of the first quarter to the end of the second quarter? | {
"A": "15.3 %",
"B": "25 %",
"C": "30 %",
"D": "33 %",
"E": "40 %"
} | multiply(subtract(divide(add(const_100, 50), add(const_100, 30)), const_1), const_100) | add(n1,const_100)|add(n0,const_100)|divide(#0,#1)|subtract(#2,const_1)|multiply(#3,const_100)| | "another method is to use the formula for 2 successive percentage changes : total = a + b + ab / 100 50 = 30 + b + 30 b / 100 b = 15.3 answer ( a )" | gain |
math_qa__0A2lq5HdGiyMw7sm | In the graduating class of a certain college, 48 percent of the students are male and 52 percent are female. In this class 50 percent of the male and 20 percent of the female students are 25 years old or older. If one student in the class is randomly selected, approximately what is the probability that he or she will be less than 25 years old? Choose the correct choice
A) 0.9 B) 0.6 C) 0.45 D) 0.3 E) 0.25 | <gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(1/2) * (4/5)</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">1 - (2/5)</gadget>
<output>3/5 = around 0.6</output>
<result>B</result> | B | 0.6 | In the graduating class of a certain college, 48 percent of the students are male and 52 percent are female. In this class 50 percent of the male and 20 percent of the female students are 25 years old or older. If one student in the class is randomly selected, approximately what is the probability that he or she will be less than 25 years old? | {
"A": "0.9",
"B": "0.6",
"C": "0.45",
"D": "0.3",
"E": "0.25"
} | subtract(const_1, multiply(divide(50, const_100), divide(subtract(const_100, 20), const_100))) | divide(n2,const_100)|subtract(const_100,n3)|divide(#1,const_100)|multiply(#0,#2)|subtract(const_1,#3) | percent of students who are 25 years old or older is 0.5 * 48 + 0.2 * 52 = ~ 34 , so percent of people who are less than 25 years old is 100 - 3 = 66 . answer : b . | general |
math_qa__hYbBnlN28jJVnkfi | A grocer has a sale of Rs. 5420, Rs. 5660, Rs. 6200, Rs. 6350 and Rs. 6500 for 5 consecutive months. Find the sale he should have in the sixth month, so that he gets an average sale of Rs. 6200?
Choose the correct choice from the following.
A) rs . 7070
B) rs . 5991
C) rs . 6020
D) rs . 6850
E) none of these | <gadget id="calculator">5 + 1</gadget>
<output>6</output>
<gadget id="calculator">6 * 6_200</gadget>
<output>37_200</output>
<gadget id="calculator">5_420 + 5_660</gadget>
<output>11_080</output>
<gadget id="calculator">11_080 + 6_200</gadget>
<output>17_280</output>
<gadget id="calculator">17_280 + 6_350</gadget>
<output>23_630</output>
<gadget id="calculator">23_630 + 6_500</gadget>
<output>30_130</output>
<gadget id="calculator">37_200 - 30_130</gadget>
<output>7_070</output>
<result>A</result> | A | 7,070 | A grocer has a sale of Rs. 5420, Rs. 5660, Rs. 6200, Rs. 6350 and Rs. 6500 for 5 consecutive months. Find the sale he should have in the sixth month, so that he gets an average sale of Rs. 6200? | {
"A": "rs . 7070",
"B": "rs . 5991",
"C": "rs . 6020",
"D": "rs . 6850",
"E": "none of these"
} | subtract(multiply(add(5, const_1), 6200), add(add(add(add(5420, 5660), 6200), 6350), 6500)) | add(n5,const_1)|add(n0,n1)|add(n2,#1)|multiply(n6,#0)|add(n3,#2)|add(n4,#4)|subtract(#3,#5)| | "explanation : total sale for 5 months = rs . ( 5420 + 5660 + 6200 + 6350 + 6500 ) = rs . 30,130 therefore , required sale = rs . [ ( 6200 * 6 ) – 30,130 ] = rs . ( 37200 – 30,130 ) = rs . 7070 answer a" | general |
math_qa__MH6m0Szl0ZS4wshs | The present worth of Rs.1183 due in 2 years at 4% per annum compound interest is Choices: A) rs . 150.50 B) rs . 154.75 C) rs . 156.25 D) rs . 1093.75 E) none | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) + 1</gadget>
<output>26/25 = around 1.04</output>
<gadget id="calculator">(26/25) ** 2</gadget>
<output>676/625 = around 1.0816</output>
<gadget id="calculator">1_183 / (676/625)</gadget>
<output>4_375/4 = around 1_093.75</output>
<result>D</result> | D | 1,093.75 | The present worth of Rs.1183 due in 2 years at 4% per annum compound interest is | {
"A": "rs . 150.50",
"B": "rs . 154.75",
"C": "rs . 156.25",
"D": "rs . 1093.75",
"E": "none"
} | divide(1183, power(add(divide(4, const_100), const_1), 2)) | divide(n2,const_100)|add(#0,const_1)|power(#1,n1)|divide(n0,#2)| | "solution present worth = rs . [ 1183 / ( 1 + 4 / 100 ) ² ] = rs . ( 1183 x 25 / 26 x 25 / 26 ) = rs . 1093.75 answer d" | gain |
math_qa__L86wqJhVyAZGfjSq | The C.P of 20 pens is equal to the S.P of 12 pens. Find his gain % or loss%? Choose the correct choice: A) 10 % B) 20 % C) 30 % D) 40 % E) 50 % | <gadget id="calculator">20 - 12</gadget>
<output>8</output>
<gadget id="calculator">8 / 20</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 100</gadget>
<output>40</output>
<result>D</result> | D | 40 | The C.P of 20 pens is equal to the S.P of 12 pens. Find his gain % or loss%? | {
"A": "10 %",
"B": "20 %",
"C": "30 %",
"D": "40 %",
"E": "50 %"
} | multiply(divide(subtract(20, 12), 20), const_100) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_100)| | "20 cp = 12 sp 20 - - - 8 cpgain 100 - - - ? = > 40 % answer : d" | gain |
math_qa__Qox6XxZ8YaA7u4pN | How many kg of pure salt must be added to 100kg of 10% solution of salt and water to increase it to a 15% solution?
Choose the most appropriate option
A) 5.8 B) 1.3 C) 9.6 D) 12.5 E) 7.9 | <gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 - (3/20)</gadget>
<output>17/20 = around 0.85</output>
<gadget id="calculator">5 / (17/20)</gadget>
<output>100/17 = around 5.882353</output>
<result>A</result> | A | 5.8 | How many kg of pure salt must be added to 100kg of 10% solution of salt and water to increase it to a 15% solution? | {
"A": "5.8",
"B": "1.3",
"C": "9.6",
"D": "12.5",
"E": "7.9"
} | divide(subtract(15, 10), subtract(const_1, divide(15, 100))) | divide(n2,n0)|subtract(n2,n1)|subtract(const_1,#0)|divide(#1,#2) | amount salt in 100 kg solution = 10 * 100 / 100 = 10 kg let x kg of pure salt be added then ( 10 + x ) / ( 100 + x ) = 15 / 100 200 + 20 x = 300 + 3 x 17 x = 100 x = 5.8 answer is a | general |
math_qa__fnVJ7bm2HEyF5G5M | How many multiples of 4 are there between 16 and 112, inclusive? Choices: A) 21 B) 22 C) 23 D) 24 E) 25 | <gadget id="calculator">112 - 16</gadget>
<output>96</output>
<gadget id="calculator">96 / 4</gadget>
<output>24</output>
<gadget id="calculator">24 + 1</gadget>
<output>25</output>
<result>E</result> | E | 25 | How many multiples of 4 are there between 16 and 112, inclusive? | {
"A": "21",
"B": "22",
"C": "23",
"D": "24",
"E": "25"
} | add(divide(subtract(112, 16), 4), const_1) | subtract(n2,n1)|divide(#0,n0)|add(#1,const_1)| | "the multiples of 4 are from 4 * 4 up to 4 * 28 . 28 - 4 + 1 = 25 . the answer is e ." | general |
math_qa__laEbd5yX6Mhywn39 | Jill has 35 gallons of water stored in quart, half-gallon, and one gallon jars. She has equal numbers of each size jar holding the liquid. What is the total number of water filled jars?
Choose the correct choice from the following choices: A) 3 B) 60 C) 9 D) 12 E) 14 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/4) + (1/2)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 + (3/4)</gadget>
<output>7/4 = around 1.75</output>
<gadget id="calculator">35 / (7/4)</gadget>
<output>20</output>
<gadget id="calculator">20 * 3</gadget>
<output>60</output>
<result>B</result> | B | 60 | Jill has 35 gallons of water stored in quart, half-gallon, and one gallon jars. She has equal numbers of each size jar holding the liquid. What is the total number of water filled jars? | {
"A": "3",
"B": "60",
"C": "9",
"D": "12",
"E": "14"
} | multiply(divide(35, add(const_1, add(const_0_25, divide(const_1, const_2)))), const_3) | divide(const_1,const_2)|add(#0,const_0_25)|add(#1,const_1)|divide(n0,#2)|multiply(#3,const_3)| | let the number of each size of jar = wthen 1 / 4 w + 1 / 2 w + w = 35 1 3 / 4 w = 35 w = 20 the total number of jars = 3 w = 60 answer : b | general |
math_qa__6yhMcwvmmIn6b1zI | A cycle is bought for Rs.850 and sold for Rs.1080, find the gain percent? Choose the correct choice from the following answers.
A) 22 B) 27 C) 99 D) 88 E) 11 | <gadget id="calculator">1_080 - 850</gadget>
<output>230</output>
<gadget id="calculator">230 / 850</gadget>
<output>23/85 = around 0.270588</output>
<gadget id="calculator">(23/85) * 100</gadget>
<output>460/17 = around 27.058824</output>
<result>B</result> | B | 27 | A cycle is bought for Rs.850 and sold for Rs.1080, find the gain percent? | {
"A": "22",
"B": "27",
"C": "99",
"D": "88",
"E": "11"
} | multiply(divide(subtract(1080, 850), 850), const_100) | subtract(n1,n0)|divide(#0,n0)|multiply(#1,const_100) | 850 - - - - 180 100 - - - - ? = > 27 % answer : b | gain |
math_qa__IxUEIkSrhiccVM6R | A person is traveling at 25km/hr and reached his destiny in 5hr find the distance? Choose the correct choice from the following choices.
A) 100 km
B) 95 km
C) 135 km
D) 80 km
E) 125 km | <gadget id="calculator">25 * 5</gadget>
<output>125</output>
<result>E</result> | E | 125 | A person is traveling at 25km/hr and reached his destiny in 5hr find the distance? | {
"A": "100 km",
"B": "95 km",
"C": "135 km",
"D": "80 km",
"E": "125 km"
} | multiply(25, 5) | multiply(n0,n1) | speed = 25 km / hr time = 5 hr distance = 25 * 5 = 125 km answer is e | physics |
math_qa__T9llnOjjjXN1yY5E | In a theater, the first row has 14 seats and each row has 3 more seats than previous row. If the last row has 50 seats, what is the total number of seats in the theater? Choose one:
A) 404 B) 408 C) 412 D) 416 E) 420 | <gadget id="calculator">14 + 50</gadget>
<output>64</output>
<gadget id="calculator">64 / 2</gadget>
<output>32</output>
<gadget id="calculator">50 - 14</gadget>
<output>36</output>
<gadget id="calculator">36 + 3</gadget>
<output>39</output>
<gadget id="calculator">39 / 3</gadget>
<output>13</output>
<gadget id="calculator">32 * 13</gadget>
<output>416</output>
<result>D</result> | D | 416 | In a theater, the first row has 14 seats and each row has 3 more seats than previous row. If the last row has 50 seats, what is the total number of seats in the theater? | {
"A": "404",
"B": "408",
"C": "412",
"D": "416",
"E": "420"
} | multiply(divide(add(14, 50), const_2), divide(add(subtract(50, 14), 3), 3)) | add(n0,n2)|subtract(n2,n0)|add(n1,#1)|divide(#0,const_2)|divide(#2,n1)|multiply(#3,#4) | the number of seats in the theater is 14 + ( 14 + 3 ) + . . . + ( 14 + 36 ) = 13 ( 14 ) + 3 ( 1 + 2 + . . . + 12 ) = 13 ( 14 ) + 3 ( 12 ) ( 13 ) / 2 = 13 ( 14 + 18 ) = 13 ( 32 ) = 416 the answer is d . | general |
math_qa__hSigK6oncFSa5Pnr | A train 200m long takes 6 sec to cross a man walking at 5kmph in a direction opposite to that of the train. Find the speed of the train? Choices: A) 85 kmph B) 115 kmph C) 105 kmph D) 95 kmph E) 125 kmph | <gadget id="calculator">200 / 6</gadget>
<output>100/3 = around 33.333333</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">(100/3) / (5/18)</gadget>
<output>120</output>
<gadget id="calculator">120 - 5</gadget>
<output>115</output>
<result>B</result> | B | 115 | A train 200m long takes 6 sec to cross a man walking at 5kmph in a direction opposite to that of the train. Find the speed of the train? | {
"A": "85 kmph",
"B": "115 kmph",
"C": "105 kmph",
"D": "95 kmph",
"E": "125 kmph"
} | subtract(divide(divide(200, 6), const_0_2778), 5) | divide(n0,n1)|divide(#0,const_0_2778)|subtract(#1,n2)| | "let the speed of the train be x kmph speed of the train relative to man = x + 5 = ( x + 5 ) * 5 / 18 m / sec 200 / [ ( x + 5 ) * 5 / 18 ] = 6 30 ( x + 5 ) = 3600 x = 115 kmph answer is b" | physics |
math_qa__VHGLA2GA597YACLH | A student scored an average of 80 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics? Choose the most appropriate option.
A) 21 B) 27 C) 26 D) 80 E) 28 | <gadget id="calculator">90 * 2</gadget>
<output>180</output>
<gadget id="calculator">70 * 2</gadget>
<output>140</output>
<gadget id="calculator">180 + 140</gadget>
<output>320</output>
<gadget id="calculator">80 * 3</gadget>
<output>240</output>
<gadget id="calculator">320 - 240</gadget>
<output>80</output>
<result>D</result> | D | 80 | A student scored an average of 80 marks in 3 subjects: Physics, Chemistry and Mathematics. If the average marks in Physics and Mathematics is 90 and that in Physics and Chemistry is 70, what are the marks in Physics? | {
"A": "21",
"B": "27",
"C": "26",
"D": "80",
"E": "28"
} | subtract(add(multiply(90, const_2), multiply(70, const_2)), multiply(80, 3)) | multiply(n2,const_2)|multiply(n3,const_2)|multiply(n0,n1)|add(#0,#1)|subtract(#3,#2)| | "given m + p + c = 80 * 3 = 240 - - - ( 1 ) m + p = 90 * 2 = 180 - - - ( 2 ) p + c = 70 * 2 = 140 - - - ( 3 ) where m , p and c are marks obtained by the student in mathematics , physics and chemistry . p = ( 2 ) + ( 3 ) - ( 1 ) = 180 + 140 - 240 = 80 . answer : d" | general |
math_qa__DOHzrSbPLsaC7GvR | In an election, candidate Douglas won 54 percent of the total vote in Counties X and Y. He won 62 percent of the vote in County X. If the ratio of people who voted in County X to County Y is 2: 1, what percent of the vote did candidate Douglas win in County Y?
Choices.
A) 25 % B) 28 % C) 32 % D) 38 % E) 40 % | <gadget id="calculator">54 / 100</gadget>
<output>27/50 = around 0.54</output>
<gadget id="calculator">62 / 100</gadget>
<output>31/50 = around 0.62</output>
<gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">(31/50) * (2/3)</gadget>
<output>31/75 = around 0.413333</output>
<gadget id="calculator">(27/50) - (31/75)</gadget>
<output>19/150 = around 0.126667</output>
<gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">(19/150) / (1/3)</gadget>
<output>19/50 = around 0.38</output>
<gadget id="calculator">(19/50) * 100</gadget>
<output>38</output>
<result>D</result> | D | 38 | In an election, candidate Douglas won 54 percent of the total vote in Counties X and Y. He won 62 percent of the vote in County X. If the ratio of people who voted in County X to County Y is 2: 1, what percent of the vote did candidate Douglas win in County Y? | {
"A": "25 %",
"B": "28 %",
"C": "32 %",
"D": "38 %",
"E": "40 %"
} | multiply(divide(subtract(divide(54, const_100), multiply(divide(62, const_100), divide(2, const_3))), divide(1, const_3)), const_100) | divide(n0,const_100)|divide(n1,const_100)|divide(n2,const_3)|divide(n3,const_3)|multiply(#1,#2)|subtract(#0,#4)|divide(#5,#3)|multiply(#6,const_100)| | "given voters in ratio 2 : 1 let x has 200 votersy has 100 voters for x 62 % voted means 62 * 200 = 124 votes combined for xy has 300 voters and voted 54 % so total votes = 162 balance votes = 162 - 124 = 38 as y has 100 voters so 38 votes means 38 % of votes required ans d" | general |
math_qa__EOsaH3vkETv30Wq5 | The radius of a wheel is 14.6 cm. What is the distance covered by the wheel in making 100 resolutions?
Select the correct option.
A) 754 m B) 704 m C) 90.524 m D) 706 m E) 91.688 m | <gadget id="calculator">3 + 4</gadget>
<output>7</output>
<gadget id="calculator">7 * 3</gadget>
<output>21</output>
<gadget id="calculator">21 + 1</gadget>
<output>22</output>
<gadget id="calculator">22 / 7</gadget>
<output>22/7 = around 3.142857</output>
<gadget id="calculator">(22/7) * 14.6</gadget>
<output>45.885714</output>
<gadget id="calculator">45.885714 * 2</gadget>
<output>91.771428</output>
<gadget id="calculator">91.771428 * 100</gadget>
<output>9_177.1428</output>
<gadget id="calculator">9_177.1428 / 100</gadget>
<output>91.771428</output>
<result>E</result> | E | 91.688 | The radius of a wheel is 14.6 cm. What is the distance covered by the wheel in making 100 resolutions? | {
"A": "754 m",
"B": "704 m",
"C": "90.524 m",
"D": "706 m",
"E": "91.688 m"
} | divide(multiply(multiply(multiply(divide(add(multiply(add(const_3, const_4), const_3), const_1), add(const_3, const_4)), 14.6), const_2), 100), const_100) | add(const_3,const_4)|multiply(#0,const_3)|add(#1,const_1)|divide(#2,#0)|multiply(n0,#3)|multiply(#4,const_2)|multiply(n1,#5)|divide(#6,const_100)| | "in one resolution , the distance covered by the wheel is its own circumference . distance covered in 100 resolutions . = 100 * 2 * 22 / 7 * 14.6 = 9168.8 cm = 91.688 m answer : e" | physics |
math_qa__C1G5LrVhJLBDKHlo | Harold and Millicent are getting married and need to combine their already-full libraries. If Harold, who has 1/2 as many books as Millicent, brings 1/3 of his books to their new home, then Millicent will have enough room to bring 1/2 of her books to their new home. What fraction of Millicent's old library capacity is the new home's library capacity Answers.
A) 1 / 2
B) 2 / 3
C) 3 / 4
D) 4 / 5
E) 5 / 6 | <gadget id="calculator">1 / 3</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/3) * (1/2)</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">1 - (1/6)</gadget>
<output>5/6 = around 0.833333</output>
<result>E</result> | E | 0.833333 | Harold and Millicent are getting married and need to combine their already-full libraries. If Harold, who has 1/2 as many books as Millicent, brings 1/3 of his books to their new home, then Millicent will have enough room to bring 1/2 of her books to their new home. What fraction of Millicent's old library capacity is the new home's library capacity | {
"A": "1 / 2",
"B": "2 / 3",
"C": "3 / 4",
"D": "4 / 5",
"E": "5 / 6"
} | subtract(const_1, multiply(divide(1, 3), divide(1, 2))) | divide(n0,n3)|divide(n0,n1)|multiply(#0,#1)|subtract(const_1,#2) | because we see h willbring 1 / 3 of his booksto the new home - - > try to pick a number that isdivisible by 3 . before : assume h = 30 books h = 1 / 2 m - - > m = 60 books after : h ' = 1 / 3 h = 10 books m ' = 1 / 2 m = 30 books total = 40 books m ' = 40 = 5 / 6 * 60 ratio : 5 / 6 ans : e | general |
math_qa__8ihGmeLgUmwF6rMc | On dividing a number by 8, we get 8 as quotient and 0 as remainder. On dividing the same number by 5, what will be the remainder?
Choose the most appropriate option
A) 10 B) 4 C) 8 D) 6 E) 5 | <gadget id="calculator">8 * 8</gadget>
<output>64</output>
<gadget id="calculator">64 % 5</gadget>
<output>4</output>
<result>B</result> | B | 4 | On dividing a number by 8, we get 8 as quotient and 0 as remainder. On dividing the same number by 5, what will be the remainder? | {
"A": "10",
"B": "4",
"C": "8",
"D": "6",
"E": "5"
} | reminder(multiply(8, 8), 5) | multiply(n0,n1)|reminder(#0,n3)| | "number = 8 * 8 + 0 = 64 5 ) 64 ( 12 60 - - - - - - - - 4 required number = 4 . answer : b" | general |
math_qa__bcAsl4CVfnqjA6db | The number of sailors on a ship is 82% more than the number of officers. The ratio of sailors to officers would be Pick:
A) 33 : 25 B) 47 : 20 C) 47 : 25 D) 22 : 25 E) 91 : 50 | <gadget id="calculator">82 + 100</gadget>
<output>182</output>
<gadget id="calculator">182 / 100</gadget>
<output>91/50 = around 1.82</output>
<result>E</result> | E | 1.82 | The number of sailors on a ship is 82% more than the number of officers. The ratio of sailors to officers would be | {
"A": "33 : 25",
"B": "47 : 20",
"C": "47 : 25",
"D": "22 : 25",
"E": "91 : 50"
} | divide(add(82, const_100), const_100) | add(n0,const_100)|divide(#0,const_100)| | "sailor = 1.82 * officer sailor / officer = 1.82 / 1 = 182 / 100 = 91 / 50 answer will be e" | other |
math_qa__yykFO0WBMaeACweH | Let f(x,y) be defined as the remainder when (x–y)! is divided by x. If x=50, what is the maximum value of y for which f(x,y)=0? Choose the correct choice from the following answers:
A) 35 B) 36 C) 40 D) 42 E) 45 | <gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">25 / 5</gadget>
<output>5</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">50 - 10</gadget>
<output>40</output>
<result>C</result> | C | 40 | Let f(x,y) be defined as the remainder when (x–y)! is divided by x. If x=50, what is the maximum value of y for which f(x,y)=0? | {
"A": "35",
"B": "36",
"C": "40",
"D": "42",
"E": "45"
} | subtract(50, multiply(const_2, divide(divide(50, const_2), add(const_1, const_4)))) | add(const_1,const_4)|divide(n0,const_2)|divide(#1,#0)|multiply(#2,const_2)|subtract(n0,#3) | the question is finding y such that ( 50 - y ) ! is a multiple of 50 . that means we need to have 2 * 5 ^ 2 in ( 50 - y ) ! 10 ! is the smallest factorial number with 2 * 5 ^ 2 as a factor . 50 - y = 10 y = 40 the answer is c . | general |
math_qa__56fesGNoMg6a6pvx | The speed of a railway engine is 84 Km per hour when no compartment is attached, and the reduction in speed is directly proportional to the square root of the number of compartments attached. If the speed of the train carried by this engine is 24 Km per hour when 9 compartments are attached, the maximum number of compartments that can be carried by the engine is:
Pick one.
A) 19 B) 18 C) 16 D) 17 E) 14 | <gadget id="calculator">84 - 24</gadget>
<output>60</output>
<gadget id="calculator">9 ** (1/2)</gadget>
<output>3</output>
<gadget id="calculator">60 / 3</gadget>
<output>20</output>
<gadget id="calculator">84 / 20</gadget>
<output>21/5 = around 4.2</output>
<gadget id="calculator">(21/5) ** 2</gadget>
<output>441/25 = around 17.64</output>
<result>D</result> | D | 17 | The speed of a railway engine is 84 Km per hour when no compartment is attached, and the reduction in speed is directly proportional to the square root of the number of compartments attached. If the speed of the train carried by this engine is 24 Km per hour when 9 compartments are attached, the maximum number of compartments that can be carried by the engine is: | {
"A": "19",
"B": "18",
"C": "16",
"D": "17",
"E": "14"
} | power(divide(84, divide(subtract(84, 24), sqrt(9))), const_2) | sqrt(n2)|subtract(n0,n1)|divide(#1,#0)|divide(n0,#2)|power(#3,const_2)| | "the reduction in speed is directly proportional to the square root of the number of compartments attached doesreductionmean amount subtracted ? or percentage decrease ? there are at least two interpretations , and the wording does not provide a clear interpretation between them . evidently what the question intends is the subtraction interpretation . what is subtracted from the speed is directly proportional to the square root of the number of compartments attached . in other words , if s = speed , and n = number of compartments , then s = 84 - k * sqrt ( n ) wherekis a constant of the proportionality . in general , if a is directly proportional to b , we can write a = k * b and solve for k . if n = 9 , then s = 24 24 = 84 - k * sqrt ( 9 ) = 84 - 3 k k = 20 now , we need to know : what value of n makes s go to zero ? 0 = 84 - 20 * sqrt ( n ) 20 * sqrt ( n ) = 84 sqrt ( n ) = 4.2 n = 4.2 ^ 2 > 17 with 18 compartments , the train does not budge . therefore , it would budge if there were one fewer cars . thus , 17 is the maximum number of cars the engine can pull and still move . d" | physics |
math_qa__qSCRBPOAo3uEBnOn | 3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 3 men and 2 women will do that task.
Choose the correct choice from the following options:
A) 4 / 7 B) 3 / 10 C) 3 / 18 D) 13 / 16 E) 4 / 11 | <gadget id="calculator">8 - 2</gadget>
<output>6</output>
<gadget id="calculator">6 - 3</gadget>
<output>3</output>
<gadget id="calculator">6 / 3</gadget>
<output>2</output>
<gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 + 2</gadget>
<output>8</output>
<gadget id="calculator">6 * 2</gadget>
<output>12</output>
<gadget id="calculator">12 + 2</gadget>
<output>14</output>
<gadget id="calculator">8 / 14</gadget>
<output>4/7 = around 0.571429</output>
<result>A</result> | A | 0.571429 | 3 men and 8 women complete a task in same time as 6 men and 2 women do. How much fraction of work will be finished in same time if 3 men and 2 women will do that task. | {
"A": "4 / 7",
"B": "3 / 10",
"C": "3 / 18",
"D": "13 / 16",
"E": "4 / 11"
} | divide(add(multiply(divide(subtract(8, 2), subtract(6, 3)), 3), 2), add(multiply(6, divide(subtract(8, 2), subtract(6, 3))), 2)) | subtract(n1,n3)|subtract(n2,n0)|divide(#0,#1)|multiply(n4,#2)|multiply(n2,#2)|add(n5,#3)|add(n3,#4)|divide(#5,#6)| | "3 m + 8 w = 6 m + 2 w 3 m = 6 w 1 m = 2 w therefore 3 m + 8 w = 14 w 3 m + 2 w = 8 w answer is 8 / 14 = 4 / 7 answer : a" | physics |
math_qa__92rngFbK4uG40GsY | In an NGO the daily average wages of 20 illiterate employees is decreased from Rs.25 to Rs.10, thus the average salary of all the literate and illiterate employees is decreased Rs.10 per day. The No. of educated employees working in the NGO is ? Select the correct option.
A) 11 B) 82 C) 10 D) 28 E) 23 | <gadget id="calculator">20 - 10</gadget>
<output>10</output>
<result>C</result> | C | 10 | In an NGO the daily average wages of 20 illiterate employees is decreased from Rs.25 to Rs.10, thus the average salary of all the literate and illiterate employees is decreased Rs.10 per day. The No. of educated employees working in the NGO is ? | {
"A": "11",
"B": "82",
"C": "10",
"D": "28",
"E": "23"
} | subtract(20, 10) | subtract(n0,n2)| | "explanation : total employees = \ inline \ frac { ( 25 - 10 ) \ times 20 } { 10 } = 30 hence number of educated employees = 30 - 20 = 10 answer : c" | general |
math_qa__wURS842Qra5we1MG | In the fifth grade at Parkway elementary school there are 500 students. 350 students are boys and 250 students are playing soccer. 86% of the students that play soccer are boys. How many girl student are in Parkway that is not playing soccer?
Select the correct option
A) 69 .
B) 73 .
C) 81 .
D) 91 .
E) 115 . | <gadget id="calculator">500 - 350</gadget>
<output>150</output>
<gadget id="calculator">250 * 86</gadget>
<output>21_500</output>
<gadget id="calculator">21_500 / 100</gadget>
<output>215</output>
<gadget id="calculator">250 - 215</gadget>
<output>35</output>
<gadget id="calculator">150 - 35</gadget>
<output>115</output>
<result>E</result> | E | 115 | In the fifth grade at Parkway elementary school there are 500 students. 350 students are boys and 250 students are playing soccer. 86% of the students that play soccer are boys. How many girl student are in Parkway that is not playing soccer? | {
"A": "69 .",
"B": "73 .",
"C": "81 .",
"D": "91 .",
"E": "115 ."
} | subtract(subtract(500, 350), subtract(250, divide(multiply(250, 86), const_100))) | multiply(n2,n3)|subtract(n0,n1)|divide(#0,const_100)|subtract(n2,#2)|subtract(#1,#3)| | "total students = 500 boys = 350 , girls = 150 total playing soccer = 250 86 % of 250 = 215 are boys who play soccer . girls who play soccer = 35 . total girls who do not play soccer = 150 - 35 = 115 . correct option : e" | gain |
math_qa__YLWbAvankYRhw31G | What positive number, when squared, is equal to the cube of the positive square root of 16? Choose the correct choice from the following choices
A) 64 B) 32 C) 8 D) 4 E) 2 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">16 ** (1/2)</gadget>
<output>4</output>
<gadget id="calculator">4 ** 3</gadget>
<output>64</output>
<gadget id="calculator">64 ** (1/2)</gadget>
<output>8</output>
<result>C</result> | C | 8 | What positive number, when squared, is equal to the cube of the positive square root of 16? | {
"A": "64",
"B": "32",
"C": "8",
"D": "4",
"E": "2"
} | sqrt(power(power(16, divide(const_1, const_2)), const_3)) | divide(const_1,const_2)|power(n0,#0)|power(#1,const_3)|sqrt(#2)| | "let the positive number be x x ^ 2 = ( ( 16 ) ^ ( 1 / 2 ) ) ^ 3 = > x ^ 2 = 4 ^ 3 = 64 = > x = 8 answer c" | geometry |
math_qa__2NZNqM2zeLA2EGEU | The difference of two numbers is 1515. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ? Choose the correct choice from the following answers
A) 270 B) 280 C) 290 D) 300 E) 310 | <gadget id="calculator">1_515 + 15</gadget>
<output>1_530</output>
<gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">1_530 / 5</gadget>
<output>306</output>
<result>D</result> | D | 300 | The difference of two numbers is 1515. On dividing the larger number by the smaller, we get 6 as quotient and the 15 as remainder. What is the smaller number ? | {
"A": "270",
"B": "280",
"C": "290",
"D": "300",
"E": "310"
} | divide(add(1515, 15), subtract(6, const_1)) | add(n0,n2)|subtract(n1,const_1)|divide(#0,#1)| | "let the smaller number be x . then larger number = ( x + 1515 ) . x + 1515 = 6 x + 15 5 x = 1500 x = 300 smaller number = 300 . d )" | general |
math_qa__sEwsOGZ50gu4lUOU | Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 115 mangoes. Answers: A) 360 B) 383 C) 400 D) 406 E) 412 | <gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">1 - (1/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">360 / (9/10)</gadget>
<output>400</output>
<gadget id="calculator">400 - 360</gadget>
<output>40</output>
<gadget id="calculator">40 / 12</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">(10/3) * 115</gadget>
<output>1_150/3 = around 383.333333</output>
<result>B</result> | B | 383 | Mr. John used to purchase certain number of mangoes for $360 Since the price of mangoes is reduced by 10% he got 12 more mangoes today. Find the original price of 115 mangoes. | {
"A": "360",
"B": "383",
"C": "400",
"D": "406",
"E": "412"
} | multiply(divide(subtract(divide(360, subtract(const_1, divide(const_1, 10))), 360), 12), 115) | divide(const_1,n1)|subtract(const_1,#0)|divide(n0,#1)|subtract(#2,n0)|divide(#3,n2)|multiply(n3,#4)| | "mr . john used to purchase certain number of mangoes for $ 360 since the price of mangoes is reduced by 10 % he got 12 more mangoes today . find the original price of 120 mangoes . method 1 : let price per mango = x . let number of mangoes be n . then , nx = 360 . now price = 0.9 x ; number of mangoes = n + 12 . total amount = 0.9 x * ( n + 12 ) = 360 . nx = 0.9 nx + 10.8 x = > 0.1 nx = 10.8 x = > n = 108 = > x = 360 / 108 = 3.33 original price of 115 mangoes = 115 * 3.33 = 383 . answer b" | gain |
math_qa__MEUUPARueK4TXaG0 | If a randomly selected positive single digit multiple of 3 is multiplied by a randomly selected prime number less than 20, what is the probability R that this product will be a multiple of 45? Select: A) 1 / 32 B) 1 / 28 C) 1 / 24 D) 1 / 16 E) 1 / 14 | <gadget id="calculator">20 + 4</gadget>
<output>24</output>
<gadget id="calculator">1 / 24</gadget>
<output>1/24 = around 0.041667</output>
<result>C</result> | C | 0.041667 | If a randomly selected positive single digit multiple of 3 is multiplied by a randomly selected prime number less than 20, what is the probability R that this product will be a multiple of 45? | {
"A": "1 / 32",
"B": "1 / 28",
"C": "1 / 24",
"D": "1 / 16",
"E": "1 / 14"
} | divide(const_1, add(20, const_4)) | add(n1,const_4)|divide(const_1,#0)| | "there are 3 single digit multiple of 3 , that is , 3 , 6,9 . there are 8 prime nos less than 20 - 2,3 , 5,7 , 11,13 , 17,19 total outcome - 8 * 3 = 24 favourable outcome = 1 ( 9 * 5 ) hence required probability r = 1 / 24 . answer c ." | general |
math_qa__3Xbns2GGl5pCoHK7 | There are 9 pairs of socks and 2 socks are worn from that such that the pair of socks worn are not of the same pair. what is the number of pair that can be formed. Options.
A) 62
B) 70
C) 72
D) 71
E) 76 | <gadget id="calculator">binomial(9, 2)</gadget>
<output>36</output>
<gadget id="calculator">36 + 36</gadget>
<output>72</output>
<result>C</result> | C | 72 | There are 9 pairs of socks and 2 socks are worn from that such that the pair of socks worn are not of the same pair. what is the number of pair that can be formed. | {
"A": "62",
"B": "70",
"C": "72",
"D": "71",
"E": "76"
} | add(choose(9, 2), choose(9, 2)) | choose(n0,n1)|add(#0,#0)| | "first of all you should remember that there is a difference in left and right sock . now no . of way to select any of the sock = 9 and for second = 8 so total methods = 9 * 8 = 72 answer : c" | probability |
math_qa__Jbqu9tQ0rOzDtasi | A volume of 10976 l water is in a container of sphere. How many hemisphere of volume 4l each will be required to transfer all the water into the small hemispheres? Select the correct option:
A) 2812
B) 8231
C) 2734
D) 2744
E) 4254 | <gadget id="calculator">10_976 / 4</gadget>
<output>2_744</output>
<result>D</result> | D | 2,744 | A volume of 10976 l water is in a container of sphere. How many hemisphere of volume 4l each will be required to transfer all the water into the small hemispheres? | {
"A": "2812",
"B": "8231",
"C": "2734",
"D": "2744",
"E": "4254"
} | divide(10976, 4) | divide(n0,n1)| | "a volume of 4 l can be kept in 1 hemisphere therefore , a volume of 10976 l can be kept in ( 10976 / 4 ) hemispheres ans . 2744 answer : d" | geometry |
math_qa__JSaDzTkf8lf9UYSf | At the end of the day, February 14th, a florist had 150 roses left in his shop, all of which were red, white or pink in color and either long or short-stemmed. A third of the roses were short-stemmed, 20 of which were white and 15 of which were pink. The percentage of pink roses that were short-stemmed equaled the percentage of red roses that were short-stemmed. If none of the long-stemmed roses were white, what percentage of the long-stemmed roses were red? Pick one.
A) 50 % B) 25 % C) 250 % D) 75 % E) 80 % | <gadget id="calculator">150 / 3</gadget>
<output>50</output>
<gadget id="calculator">150 - 50</gadget>
<output>100</output>
<gadget id="calculator">50 - 20</gadget>
<output>30</output>
<gadget id="calculator">30 - 15</gadget>
<output>15</output>
<gadget id="calculator">100 * 15</gadget>
<output>1_500</output>
<gadget id="calculator">15 + 15</gadget>
<output>30</output>
<gadget id="calculator">1_500 / 30</gadget>
<output>50</output>
<gadget id="calculator">50 / 100</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(1/2) * 100</gadget>
<output>50</output>
<result>A</result> | A | 50 | At the end of the day, February 14th, a florist had 150 roses left in his shop, all of which were red, white or pink in color and either long or short-stemmed. A third of the roses were short-stemmed, 20 of which were white and 15 of which were pink. The percentage of pink roses that were short-stemmed equaled the percentage of red roses that were short-stemmed. If none of the long-stemmed roses were white, what percentage of the long-stemmed roses were red? | {
"A": "50 %",
"B": "25 %",
"C": "250 %",
"D": "75 %",
"E": "80 %"
} | multiply(divide(divide(multiply(subtract(150, divide(150, const_3)), subtract(subtract(divide(150, const_3), 20), 15)), add(15, subtract(subtract(divide(150, const_3), 20), 15))), subtract(150, divide(150, const_3))), const_100) | divide(n1,const_3)|subtract(n1,#0)|subtract(#0,n2)|subtract(#2,n3)|add(n3,#3)|multiply(#1,#3)|divide(#5,#4)|divide(#6,#1)|multiply(#7,const_100)| | "r + w + p = 150 s + l = 150 1 / 3 * 150 = 50 short - stemmed white = 20 short - stemmed pink = 15 = > short - stemmed red = 15 15 / p = 15 / r = > r = p so total long stemmed = 100 and long stemmed red + long stemmed pink = 100 so long stemmed red / long stemmed = ? total white = 20 ( as no long stemmed white ) = > r + r + 20 = 150 = > r = 130 and r = 65 long stemmed r = 65 - 15 = 50 so long stemmed red / r = 50 / 100 = 50 % answer - a" | general |
math_qa__6OibPXaAwuaaLCVO | carl bought 16 gumballs , lewis bought 12 gumballs , and carey bought x gumballs . the average ( arithmetic mean ) number of gumballs the 3 bought is between 19 and 25 , inclusive . what is the difference between the greatest number and the smallest number of gumballs carey could have bought ? Select the correct option:
A) 20 B) 16 C) 22 D) 18 E) 24 | <gadget id="calculator">25 * 3</gadget>
<output>75</output>
<gadget id="calculator">19 * 3</gadget>
<output>57</output>
<gadget id="calculator">75 - 57</gadget>
<output>18</output>
<result>D</result> | D | 18 | carl bought 16 gumballs , lewis bought 12 gumballs , and carey bought x gumballs . the average ( arithmetic mean ) number of gumballs the 3 bought is between 19 and 25 , inclusive . what is the difference between the greatest number and the smallest number of gumballs carey could have bought ? | {
"A": "20",
"B": "16",
"C": "22",
"D": "18",
"E": "24"
} | subtract(multiply(25, 3), multiply(19, 3)) | multiply(n2,n4)|multiply(n2,n3)|subtract(#0,#1) | smallest gumballs = ( 19 - 16 ) + ( 19 - 12 ) + 19 = 29 largest gumballs = ( 25 - 16 ) + ( 25 - 12 ) + 25 = 47 difference = 47 - 29 = 18 d | general |
math_qa__n73KZsWxE1hZJdoJ | X can do a piece of work in 40days. He works at it for 8days and then Y finished it in 28 days. How long will Y take to complete the work? Choose one
A) 10 B) 12 C) 15 D) 18 E) 35 | <gadget id="calculator">8 / 40</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">1 / (4/5)</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">28 * (5/4)</gadget>
<output>35</output>
<result>E</result> | E | 35 | X can do a piece of work in 40days. He works at it for 8days and then Y finished it in 28 days. How long will Y take to complete the work? | {
"A": "10",
"B": "12",
"C": "15",
"D": "18",
"E": "35"
} | multiply(28, inverse(subtract(const_1, divide(8, 40)))) | divide(n1,n0)|subtract(const_1,#0)|inverse(#1)|multiply(n2,#2)| | "work done by x in 8 days = 8 * 1 / 40 = 1 / 5 remaining work = 1 - 1 / 5 = 4 / 5 4 / 5 work is done by y in 28 days whole work will be done by y in 28 * 5 / 4 = 35 days answer is e" | physics |
math_qa__IYXLBldE4PmNdvDJ | Find the principle on a certain sum of money at 7% per annum for 2 2/5 years if the amount being Rs.1120?
Choose the correct choice from the following choices.
A) 939.6 B) 958.9 C) 927.78 D) 926.82 E) 902.1 | <gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 + 2</gadget>
<output>12</output>
<gadget id="calculator">12 / 5</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 7</gadget>
<output>84/5 = around 16.8</output>
<gadget id="calculator">(84/5) / 100</gadget>
<output>21/125 = around 0.168</output>
<gadget id="calculator">(21/125) + 1</gadget>
<output>146/125 = around 1.168</output>
<gadget id="calculator">1_120 / (146/125)</gadget>
<output>70_000/73 = around 958.90411</output>
<result>B</result> | B | 958.9 | Find the principle on a certain sum of money at 7% per annum for 2 2/5 years if the amount being Rs.1120? | {
"A": "939.6",
"B": "958.9",
"C": "927.78",
"D": "926.82",
"E": "902.1"
} | divide(1120, add(divide(multiply(divide(add(multiply(2, 5), 2), 5), 7), const_100), const_1)) | multiply(n1,n3)|add(n1,#0)|divide(#1,n3)|multiply(n0,#2)|divide(#3,const_100)|add(#4,const_1)|divide(n4,#5)| | "1120 = p [ 1 + ( 7 * 12 / 5 ) / 100 ] p = 958.90 answer : b" | general |
math_qa__9PhARsk9FBhXltEN | Find the simple interest on Rs. 69,600 at 16 2/3% per annum for 9 months. Choose the correct option
A) s . 8500 B) s . 8700 C) s . 7500 D) s . 7000 E) s . 6500 | <gadget id="calculator">2 * 3</gadget>
<output>6</output>
<gadget id="calculator">6 * 100</gadget>
<output>600</output>
<gadget id="calculator">600 * 100</gadget>
<output>60_000</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 * 100</gadget>
<output>900</output>
<gadget id="calculator">3 + 2</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">900 * 10</gadget>
<output>9_000</output>
<gadget id="calculator">60_000 + 9_000</gadget>
<output>69_000</output>
<gadget id="calculator">16 * 3</gadget>
<output>48</output>
<gadget id="calculator">48 + 2</gadget>
<output>50</output>
<gadget id="calculator">50 / 3</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">69_000 * (50/3)</gadget>
<output>1_150_000</output>
<gadget id="calculator">2 * 6</gadget>
<output>12</output>
<gadget id="calculator">9 / 12</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1_150_000 * (3/4)</gadget>
<output>862_500</output>
<gadget id="calculator">1 / 100</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">862_500 * (1/100)</gadget>
<output>8_625</output>
<result>B</result> | B | 8,700 | Find the simple interest on Rs. 69,600 at 16 2/3% per annum for 9 months. | {
"A": "s . 8500",
"B": "s . 8700",
"C": "s . 7500",
"D": "s . 7000",
"E": "s . 6500"
} | multiply(multiply(multiply(add(multiply(multiply(multiply(2, 3), const_100), const_100), multiply(multiply(multiply(3, 3), const_100), multiply(add(3, 2), 2))), divide(add(multiply(16, 3), 2), 3)), divide(multiply(3, 3), multiply(2, multiply(2, 3)))), divide(const_1, const_100)) | add(n2,n3)|divide(const_1,const_100)|multiply(n3,n3)|multiply(n2,n3)|multiply(n1,n3)|add(n2,#4)|multiply(n2,#3)|multiply(#3,const_100)|multiply(#2,const_100)|multiply(#0,n2)|divide(#2,#6)|divide(#5,n3)|multiply(#7,const_100)|multiply(#8,#9)|add(#12,#13)|multiply(#14,#11)|multiply(#10,#15)|multiply(#1,#16)| | "p = rs . 69600 , r = 50 / 3 % p . a and t = 9 / 12 years = 3 / 4 years . s . i . = ( p * r * t ) / 100 = rs . ( 69,600 * ( 50 / 3 ) * ( 3 / 4 ) * ( 1 / 100 ) ) = rs . 8700 answer is b ." | gain |
math_qa__zLnEh8GiwD5HucAv | Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? Answers.
A) 9 B) 10 C) 12 D) 20 E) 22 | <gadget id="calculator">54 - 45</gadget>
<output>9</output>
<gadget id="calculator">9 / 54</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">60 * (1/6)</gadget>
<output>10</output>
<result>B</result> | B | 10 | Excluding stoppages, the speed of a bus is 54 kmph and including stoppages, it is 45 kmph. For how many minutes does the bus stop per hour? | {
"A": "9",
"B": "10",
"C": "12",
"D": "20",
"E": "22"
} | multiply(const_60, divide(subtract(54, 45), 54)) | subtract(n0,n1)|divide(#0,n0)|multiply(#1,const_60)| | "due to stoppages , it covers 9 km less . time taken to cover 9 km = ( 9 / 54 x 60 ) min = 10 min . answer : b" | physics |
math_qa__kcultJdX5bYXctZK | How many liters of a 40% iodine solution need to be mixed with 35 liters of a 20% iodine solution to create a 33% iodine solution? Choose the correct choice from the following
A) 35 B) 49 C) 100 D) 105 E) 122 | <gadget id="calculator">35 * 20</gadget>
<output>700</output>
<gadget id="calculator">700 / 100</gadget>
<output>7</output>
<gadget id="calculator">7 * 33</gadget>
<output>231</output>
<gadget id="calculator">7 * 20</gadget>
<output>140</output>
<gadget id="calculator">231 - 140</gadget>
<output>91</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">20 * (2/5)</gadget>
<output>8</output>
<gadget id="calculator">8 - 7</gadget>
<output>1</output>
<gadget id="calculator">91 / 1</gadget>
<output>91</output>
<gadget id="calculator">91 + 35</gadget>
<output>126</output>
<result>E</result> | E | 122 | How many liters of a 40% iodine solution need to be mixed with 35 liters of a 20% iodine solution to create a 33% iodine solution? | {
"A": "35",
"B": "49",
"C": "100",
"D": "105",
"E": "122"
} | add(divide(subtract(multiply(divide(multiply(35, 20), const_100), 33), multiply(divide(multiply(35, 20), const_100), 20)), subtract(multiply(20, divide(40, const_100)), divide(multiply(35, 20), const_100))), 35) | divide(n0,const_100)|multiply(n1,n2)|divide(#1,const_100)|multiply(n2,#0)|multiply(n3,#2)|multiply(n2,#2)|subtract(#3,#2)|subtract(#4,#5)|divide(#7,#6)|add(n1,#8) | solution 1 : assume the iodine solution to be mixed = x lts . iodine = 0.4 x lts , water = 0.6 x lts . solution 2 : 35 liters of a 20 % iodine solution iodine = 7 lts , water = 28 lts . total iodine = 0.4 x + 7 total water = 0.6 x + 28 the resultant is a 35 % idoine solution . hence ( 0.4 x + 7 ) / ( x + 35 ) = 33 / 100 40 x + 700 = 33 x + 1155 7 x = 855 x = 122 lts correct option : e | gain |
math_qa__Qv1adAGV6UOL3087 | Each day a man meets his wife at the train station after work, and then she drives him home. She always arrives exactly on time to pick him up. One day he catches an earlier train and arrives at the station an hour early. He immediately begins walking home along the same route the wife drives. Eventually his wife sees him on her way to the station and drives him the rest of the way home. When they arrive home the man notices that they arrived 16 minutes earlier than usual. How much time did the man spend walking? Choose the correct option.
A) 45 minutes B) 50 minutes C) 40 minutes D) 55 minutes E) 52 minutes | <gadget id="calculator">16 / 2</gadget>
<output>8</output>
<gadget id="calculator">60 - 8</gadget>
<output>52</output>
<result>E</result> | E | 52 | Each day a man meets his wife at the train station after work, and then she drives him home. She always arrives exactly on time to pick him up. One day he catches an earlier train and arrives at the station an hour early. He immediately begins walking home along the same route the wife drives. Eventually his wife sees him on her way to the station and drives him the rest of the way home. When they arrive home the man notices that they arrived 16 minutes earlier than usual. How much time did the man spend walking? | {
"A": "45 minutes",
"B": "50 minutes",
"C": "40 minutes",
"D": "55 minutes",
"E": "52 minutes"
} | subtract(const_60, divide(16, const_2)) | divide(n0,const_2)|subtract(const_60,#0)| | "as they arrived 16 minutes earlier than usual , they saved 16 minutes on round trip from home to station ( home - station - home ) - - > 8 minutes in each direction ( home - station ) - - > wife meets husband 8 minutes earlier the usual meeting time - - > husband arrived an hour earlier the usual meeting time , so he must have spent waking the rest of the time before their meeting , which is hour - 8 minutes = 52 minutes . answer : e" | physics |
math_qa__1BpQWCsukT9ErceF | On a map, 1.5 inches represent 24 miles. How many miles approximately is the distance if you measured 49 centimeters assuming that 1-inch is 2.54 centimeters?
Choose the correct choice from the following answers:
A) 174.2
B) 212
C) 288.1
D) 296
E) 308 | <gadget id="calculator">49 / 2.54</gadget>
<output>19.291339</output>
<gadget id="calculator">24 / 1.5</gadget>
<output>16</output>
<gadget id="calculator">19.291339 * 16</gadget>
<output>308.661424</output>
<result>E</result> | E | 308 | On a map, 1.5 inches represent 24 miles. How many miles approximately is the distance if you measured 49 centimeters assuming that 1-inch is 2.54 centimeters? | {
"A": "174.2",
"B": "212",
"C": "288.1",
"D": "296",
"E": "308"
} | multiply(divide(49, 2.54), divide(24, 1.5)) | divide(n2,n4)|divide(n1,n0)|multiply(#0,#1)| | "1.5 inch = 2.54 * 1.5 cm . so , 2.54 * 1.5 represents 24 miles . so for 49 cm . : 49 / ( 2.54 * 1.5 ) = x / 24 - - - > x = 24 * 49 / ( 3.81 ) = 308 answer will be e ." | physics |
math_qa__qaontvIWXktjlQlI | If three painters can complete three rooms in three hours, how many painters would it take to do 27 rooms in 9 hours? Choose the correct choice from the following answers
A) 10 B) 8 C) 7 D) 9 E) 11 | <gadget id="calculator">9 * 3</gadget>
<output>27</output>
<gadget id="calculator">27 * 3</gadget>
<output>81</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">81 / 9</gadget>
<output>9</output>
<result>D</result> | D | 9 | If three painters can complete three rooms in three hours, how many painters would it take to do 27 rooms in 9 hours? | {
"A": "10",
"B": "8",
"C": "7",
"D": "9",
"E": "11"
} | divide(multiply(multiply(9, const_3), const_3), multiply(const_3, const_3)) | multiply(n1,const_3)|multiply(const_3,const_3)|multiply(#0,const_3)|divide(#2,#1) | explanation : three painters can complete three rooms in three hours . so 27 rooms can be painted in 9 hrs by 9 painters answer : d ) 9 painters | physics |
math_qa__xFyCPW2OgyaF9t2j | How much is 80% of 40 is greater than 2/5 of 25? Pick:
A) 22 B) 27 C) 18 D) 12 E) 81 | <gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">40 * (4/5)</gadget>
<output>32</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 25</gadget>
<output>10</output>
<gadget id="calculator">32 - 10</gadget>
<output>22</output>
<result>A</result> | A | 22 | How much is 80% of 40 is greater than 2/5 of 25? | {
"A": "22",
"B": "27",
"C": "18",
"D": "12",
"E": "81"
} | subtract(multiply(40, divide(80, const_100)), multiply(divide(2, 5), 25)) | divide(n0,const_100)|divide(n2,n3)|multiply(n1,#0)|multiply(n4,#1)|subtract(#2,#3)| | "( 80 / 100 ) * 40 â € “ ( 2 / 5 ) * 25 32 - 10 = 22 answer : a" | general |
math_qa__aQ3IGpvSU34gydUu | The average age of applicants for a new job is 30, with a standard deviation of 7. The hiring manager is only willing to accept applications whose age is within one standard deviation of the average age. What is the maximum number of different ages of the applicants? Pick: A) 8 B) 14 C) 15 D) 18 E) 30 | <gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">14 + 1</gadget>
<output>15</output>
<result>C</result> | C | 15 | The average age of applicants for a new job is 30, with a standard deviation of 7. The hiring manager is only willing to accept applications whose age is within one standard deviation of the average age. What is the maximum number of different ages of the applicants? | {
"A": "8",
"B": "14",
"C": "15",
"D": "18",
"E": "30"
} | add(multiply(7, const_2), const_1) | multiply(n1,const_2)|add(#0,const_1)| | "within one standard deviation of the average age means 31 + / - 7 23 - - 30 - - 37 number of dif . ages - 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 total = 15 c" | general |
math_qa__6sPWaTDsdnkUqUQF | A worker can load one truck in 5 hours. A second worker can load the same truck in 4 hours. If both workers load one truck simultaneously while maintaining their constant rates, approximately how long, in hours, will it take them to fill one truck? Select:
A) 1.8
B) 2.0
C) 2.2
D) 2.4
E) 2.6 | <gadget id="calculator">1 / 5</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(1/5) + (1/4)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">1 / (9/20)</gadget>
<output>20/9 = around 2.222222</output>
<result>C</result> | C | 2.2 | A worker can load one truck in 5 hours. A second worker can load the same truck in 4 hours. If both workers load one truck simultaneously while maintaining their constant rates, approximately how long, in hours, will it take them to fill one truck? | {
"A": "1.8",
"B": "2.0",
"C": "2.2",
"D": "2.4",
"E": "2.6"
} | inverse(add(divide(const_1, 5), divide(const_1, 4))) | divide(const_1,n0)|divide(const_1,n1)|add(#0,#1)|inverse(#2)| | "the workers fill the truck at a rate of 1 / 5 + 1 / 4 = 9 / 20 of the truck per hour . then the time to fill one truck is 20 / 9 which is about 2.2 hours . the answer is c ." | physics |
math_qa__EkkHZcnVgKxZ1uS3 | Little John had $8.50. He spent $1.25 on sweets and gave to his two friends $1.20 each. How much money was left? Choose the correct choice from the following answers.
A) $ 3.85 B) $ 4.85 C) $ 5.85 D) $ 2.85 E) $ 1.85 | <gadget id="calculator">1.2 + 1.2</gadget>
<output>2.4</output>
<gadget id="calculator">1.25 + 2.4</gadget>
<output>3.65</output>
<gadget id="calculator">8.5 - 3.65</gadget>
<output>4.85</output>
<result>B</result> | B | 4.85 | Little John had $8.50. He spent $1.25 on sweets and gave to his two friends $1.20 each. How much money was left? | {
"A": "$ 3.85",
"B": "$ 4.85",
"C": "$ 5.85",
"D": "$ 2.85",
"E": "$ 1.85"
} | subtract(8.50, add(1.25, add(1.20, 1.20))) | add(n2,n2)|add(n1,#0)|subtract(n0,#1)| | "john spent and gave to his two friends a total of 1.25 + 1.20 + 1.20 = $ 3.65 money left 8.50 - 3.65 = $ 4.85 correct answer is b ) $ 4.85" | general |
math_qa__DVD4quXpv8ThazDN | The ratio of buses to cars on River Road is 1 to 17. If there are 80 fewer buses than cars on River Road, how many cars are on River Road? Choose the correct choice
A) 40 B) 85 C) 60 D) 30 E) 20 | <gadget id="calculator">17 - 1</gadget>
<output>16</output>
<gadget id="calculator">80 / 16</gadget>
<output>5</output>
<gadget id="calculator">5 * 17</gadget>
<output>85</output>
<result>B</result> | B | 85 | The ratio of buses to cars on River Road is 1 to 17. If there are 80 fewer buses than cars on River Road, how many cars are on River Road? | {
"A": "40",
"B": "85",
"C": "60",
"D": "30",
"E": "20"
} | multiply(divide(80, subtract(17, 1)), 17) | subtract(n1,n0)|divide(n2,#0)|multiply(n1,#1) | b / c = 1 / 17 c - b = 80 . . . . . . . . . > b = c - 80 ( c - 80 ) / c = 1 / 17 testing answers . clearly eliminate acde put c = 85 . . . . . . . . . > ( 85 - 80 ) / 85 = 5 / 85 = 1 / 17 answer : b | other |
math_qa__DmjrGmuhbN0XstSS | A car averages 55 mph for the first 4 hours of a trip and averages 70 mph for each additional hour. The average speed for the entire trip was 60 mph. How many hours long is the trip?
Pick one
A) 6 B) 8 C) 11 D) 12 E) 14 | <gadget id="calculator">60 * 4</gadget>
<output>240</output>
<gadget id="calculator">55 * 4</gadget>
<output>220</output>
<gadget id="calculator">240 - 220</gadget>
<output>20</output>
<gadget id="calculator">70 - 60</gadget>
<output>10</output>
<gadget id="calculator">20 / 10</gadget>
<output>2</output>
<gadget id="calculator">2 + 4</gadget>
<output>6</output>
<result>A</result> | A | 6 | A car averages 55 mph for the first 4 hours of a trip and averages 70 mph for each additional hour. The average speed for the entire trip was 60 mph. How many hours long is the trip? | {
"A": "6",
"B": "8",
"C": "11",
"D": "12",
"E": "14"
} | add(divide(subtract(multiply(60, 4), multiply(55, 4)), subtract(70, 60)), 4) | multiply(n3,n1)|multiply(n0,n1)|subtract(n2,n3)|subtract(#0,#1)|divide(#3,#2)|add(n1,#4)| | "in 4 hr journey = 55 * 4 = 220 mph let in the next additional hour journey = 70 * x = 70 x mph so , ( 220 + 70 x ) / ( 4 + x ) = 60 = > 220 + 70 x = 240 + 60 x = > 10 x = 20 = > x = 2 h so the trip is ( 4 + x ) = > 6 hours long answer : a" | general |
math_qa__L0gIwKlbGVhyJ8ep | Arnold and Danny are two twin brothers that are celebrating their birthday. The product of their ages today is smaller by 11 from the product of their ages a year from today. What is their age today? Pick:
A) 2 . B) 4 . C) 5 . D) 7 . E) 9 . | <gadget id="calculator">11 - 1</gadget>
<output>10</output>
<gadget id="calculator">10 / 2</gadget>
<output>5</output>
<result>C</result> | C | 5 | Arnold and Danny are two twin brothers that are celebrating their birthday. The product of their ages today is smaller by 11 from the product of their ages a year from today. What is their age today? | {
"A": "2 .",
"B": "4 .",
"C": "5 .",
"D": "7 .",
"E": "9 ."
} | divide(subtract(11, const_1), const_2) | subtract(n0,const_1)|divide(#0,const_2)| | "ad = ( a + 1 ) ( d + 1 ) - 11 0 = a + d - 10 a + d = 10 a = d ( as they are twin brothers ) a = d = 5 c is the answer" | general |
math_qa__G9wm4ic7NOFRmCnr | one men and three women working 7 hours a day finish a work in 5 days. Four men and four women working 3 hours a day complete the work in 7 days. The number of days in which only 7 men working 4 hours a day will finish the work is? Choose the correct choice from the following choices.
A) 4 days B) 5 days C) 6 days D) 7 days E) 8 days | <gadget id="calculator">4 * 7</gadget>
<output>28</output>
<gadget id="calculator">3 * 7</gadget>
<output>21</output>
<gadget id="calculator">3 / 21</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">5 * 7</gadget>
<output>35</output>
<gadget id="calculator">4 / 35</gadget>
<output>4/35 = around 0.114286</output>
<gadget id="calculator">(1/7) - (4/35)</gadget>
<output>1/35 = around 0.028571</output>
<gadget id="calculator">(1/35) / 4</gadget>
<output>1/140 = around 0.007143</output>
<gadget id="calculator">28 * (1/140)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 / (1/5)</gadget>
<output>5</output>
<result>B</result> | B | 5 | one men and three women working 7 hours a day finish a work in 5 days. Four men and four women working 3 hours a day complete the work in 7 days. The number of days in which only 7 men working 4 hours a day will finish the work is? | {
"A": "4 days",
"B": "5 days",
"C": "6 days",
"D": "7 days",
"E": "8 days"
} | divide(const_1, multiply(multiply(4, 7), divide(subtract(divide(3, multiply(3, 7)), divide(4, multiply(5, 7))), 4))) | multiply(n0,n2)|multiply(n0,n1)|multiply(n0,n5)|divide(n2,#0)|divide(n5,#1)|subtract(#3,#4)|divide(#5,n5)|multiply(#6,#2)|divide(const_1,#7)| | "1 m + 3 w - - - - - 35 h 4 m + 4 w - - - - - - - 21 h 7 m - - - - - - - ? d 35 m + 105 w = 84 m + 84 m 21 w = 49 m 4 * 35 = 7 * x = > x = 20 hours 20 / 4 = 5 days answer : b" | physics |
math_qa__AvopmAEsOByTFDe5 | Fresh grapes contain 90% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 40 kg of fresh grapes? Choose the correct choice from the following answers:
A) 5 kg B) 2.4 kg C) 2.5 kg D) 10 kg E) none of these | <gadget id="calculator">100 - 90</gadget>
<output>10</output>
<gadget id="calculator">10 * 40</gadget>
<output>400</output>
<gadget id="calculator">400 / 100</gadget>
<output>4</output>
<gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">4 / 80</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(1/20) * 100</gadget>
<output>5</output>
<result>A</result> | A | 5 | Fresh grapes contain 90% by weight while dried grapes contain 20% water by weight. What is the weight of dry grapes available from 40 kg of fresh grapes? | {
"A": "5 kg",
"B": "2.4 kg",
"C": "2.5 kg",
"D": "10 kg",
"E": "none of these"
} | multiply(divide(divide(multiply(subtract(const_100, 90), 40), const_100), subtract(const_100, 20)), const_100) | subtract(const_100,n0)|subtract(const_100,n1)|multiply(n2,#0)|divide(#2,const_100)|divide(#3,#1)|multiply(#4,const_100)| | "the weight of non - water in 20 kg of fresh grapes ( which is 100 - 90 = 10 % of whole weight ) will be the same as the weight of non - water in x kg of dried grapes ( which is 100 - 20 = 80 % of whole weight ) , so 40 â ˆ — 0.1 = x â ˆ — 0.8 - - > x = 5 answer : a" | gain |
math_qa__724Gg56nhChVS1YO | A man engaged a servant on the condition that he would pay him Rs.500 and a uniform after one year service. He served only for 9 months and received uniform and Rs.250, find the price of the uniform?
Choices:
A) s . 80 B) s . 85 C) s . 90 D) s . 500 E) s . 120 | <gadget id="calculator">9 * 500</gadget>
<output>4_500</output>
<gadget id="calculator">3 * 4</gadget>
<output>12</output>
<gadget id="calculator">12 * 250</gadget>
<output>3_000</output>
<gadget id="calculator">4_500 - 3_000</gadget>
<output>1_500</output>
<gadget id="calculator">12 * 1</gadget>
<output>12</output>
<gadget id="calculator">1_500 / 12</gadget>
<output>125</output>
<gadget id="calculator">125 * 4</gadget>
<output>500</output>
<result>D</result> | D | 500 | A man engaged a servant on the condition that he would pay him Rs.500 and a uniform after one year service. He served only for 9 months and received uniform and Rs.250, find the price of the uniform? | {
"A": "s . 80",
"B": "s . 85",
"C": "s . 90",
"D": "s . 500",
"E": "s . 120"
} | multiply(divide(subtract(multiply(9, 500), multiply(multiply(const_3, const_4), 250)), multiply(multiply(const_3, const_4), const_1)), const_4) | multiply(n0,n1)|multiply(const_3,const_4)|multiply(n2,#1)|multiply(#1,const_1)|subtract(#0,#2)|divide(#4,#3)|multiply(#5,const_4)| | "9 / 12 = 3 / 4 * 500 = 375 250 - - - - - - - - - - - - - 125 1 / 4 - - - - - - - - 125 1 - - - - - - - - - ? = > rs . 500 answer : d" | general |
math_qa__UWlZOxT3AIItRTTQ | Shannon and Maxine work in the same building and leave work at the same time. Shannon lives due north of work and Maxine lives due south. The distance between Maxine's house and Shannon's house is 60 miles. If they both drive home at the rate 2R miles per hour, Maxine arrives home 40 minutes after Shannon. If Maxine rider her bike home at the rate of R per hour and Shannon still drives at a rate of 2R miles per hour, Shannon arrives home 2 hours before Maxine. How far does maxine live from work? Choose the correct choice: A) 20 B) 34 C) 38 D) 40 E) 46 | <gadget id="calculator">3 * 60</gadget>
<output>180</output>
<gadget id="calculator">180 - 60</gadget>
<output>120</output>
<gadget id="calculator">120 / 3</gadget>
<output>40</output>
<result>D</result> | D | 40 | Shannon and Maxine work in the same building and leave work at the same time. Shannon lives due north of work and Maxine lives due south. The distance between Maxine's house and Shannon's house is 60 miles. If they both drive home at the rate 2R miles per hour, Maxine arrives home 40 minutes after Shannon. If Maxine rider her bike home at the rate of R per hour and Shannon still drives at a rate of 2R miles per hour, Shannon arrives home 2 hours before Maxine. How far does maxine live from work? | {
"A": "20",
"B": "34",
"C": "38",
"D": "40",
"E": "46"
} | divide(subtract(multiply(const_3, 60), 60), const_3) | multiply(n0,const_3)|subtract(#0,n0)|divide(#1,const_3) | we have that x / 24 - ( 60 - x ) / 2 r = 40 also x / r - ( 60 - x ) / 2 r = 120 so we get that 2 x - 60 = 80 r 3 x - 60 = 240 r get rid of r 120 = 3 x x = 40 hence answer is d | physics |
math_qa__izIMlrBuMw7KzzSK | A and B undertake to do a piece of work for Rs. 1200. A alone can do it in 6 days while B alone can do it in 8 days. With the help of C, they finish it in 3 days. Find the share of C. Choose the correct choice from the following options: A) 150 B) 450 C) 750 D) 800 E) none of them | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">7 + 1</gadget>
<output>8</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 1_200</gadget>
<output>150</output>
<result>A</result> | A | 150 | A and B undertake to do a piece of work for Rs. 1200. A alone can do it in 6 days while B alone can do it in 8 days. With the help of C, they finish it in 3 days. Find the share of C. | {
"A": "150",
"B": "450",
"C": "750",
"D": "800",
"E": "none of them"
} | multiply(divide(const_1, add(add(const_4, 3), const_1)), 1200) | add(n3,const_4)|add(#0,const_1)|divide(const_1,#1)|multiply(n0,#2)| | "c ' s 1 day ' s work = 1 / 3 - ( 1 / 6 + 1 / 8 ) = 24 a : b : c = ratio of their 1 day ' s work = 1 / 6 : 1 / 8 : 1 / 24 = 4 : 3 : 1 . a ’ s share = rs . ( 1200 * 4 / 8 ) = rs . 600 , b ' s share = rs . ( 1200 * 3 / 8 ) = rs . 450 c ' s share = rs . [ 1200 - ( 300 + 225 » ) = rs . 150 . answer is a" | physics |
math_qa__4b2DOfHAMqzX2i8c | A big container is 30% full with water. If 27 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container? Choose the correct choice:
A) 36 liters
B) 40 liters
C) 45 liters
D) 54 liters
E) 60 liters | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/4) - (3/10)</gadget>
<output>9/20 = around 0.45</output>
<gadget id="calculator">27 / (9/20)</gadget>
<output>60</output>
<result>E</result> | E | 60 | A big container is 30% full with water. If 27 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container? | {
"A": "36 liters",
"B": "40 liters",
"C": "45 liters",
"D": "54 liters",
"E": "60 liters"
} | divide(27, subtract(divide(3, 4), divide(30, const_100))) | divide(n2,n3)|divide(n0,const_100)|subtract(#0,#1)|divide(n1,#2)| | "a big container is 30 % full with water and after 27 liters of water is added , the container becomes 75 % full . hence these 27 liters account for 45 % of the container , which means that the capacity of it is 27 / 0.45 = 60 liters . or : if the capacity of the container is x liters then : 0.3 x + 27 = 0.75 x - - > x = 60 liters . answer : e ." | general |
math_qa__Vht0vUDP4Beh0cB5 | A computer store offers employees a 15% discount off the retail price. If the store purchased a computer from the manufacturer for $500 dollars and marked up the price 15% to the final retail price, how much would an employee save if he purchased the computer at the employee discount (15% off retail price) as opposed to the final retail price. Choose the correct choice from the following answers: A) 52.5 B) 54.5 C) 55.5 D) 57.5 E) 59.5 | <gadget id="calculator">500 * 15</gadget>
<output>7_500</output>
<gadget id="calculator">7_500 / 100</gadget>
<output>75</output>
<gadget id="calculator">75 + 500</gadget>
<output>575</output>
<gadget id="calculator">500 / 100</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">575 / 10</gadget>
<output>115/2 = around 57.5</output>
<result>D</result> | D | 57.5 | A computer store offers employees a 15% discount off the retail price. If the store purchased a computer from the manufacturer for $500 dollars and marked up the price 15% to the final retail price, how much would an employee save if he purchased the computer at the employee discount (15% off retail price) as opposed to the final retail price. | {
"A": "52.5",
"B": "54.5",
"C": "55.5",
"D": "57.5",
"E": "59.5"
} | divide(add(divide(multiply(500, 15), const_100), 500), multiply(divide(500, const_100), const_2)) | divide(n1,const_100)|multiply(n0,n1)|divide(#1,const_100)|multiply(#0,const_2)|add(n1,#2)|divide(#4,#3) | cost price = 500 profit = 15 % = 15 % of 500 = 75 selling price = cp + profit sp = 575 a discount of 10 % to employees means 10 % off on 575 so 10 % of 575 = 57.5 ans d | gain |
math_qa__CdxntZGl8hazjNHn | a box contains 9 slips that are each labeled with one number : 1 , 3 , 5 , 8 , 13 , 21 , 34 and 55 . two of the slips are drawn at random from the box without replacement . what is the probability that the sum of the numbers on the two slips is equal to one of the numbers left in the box ? Choose the correct choice from the following answers.
A) 7 / 72
B) 1 / 6
C) 5 / 28
D) 15 / 36
E) 21 / 36 | <gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">8 * 7</gadget>
<output>56</output>
<gadget id="calculator">56 / 2</gadget>
<output>28</output>
<gadget id="calculator">5 / 28</gadget>
<output>5/28 = around 0.178571</output>
<result>C</result> | C | 0.178571 | a box contains 9 slips that are each labeled with one number : 1 , 3 , 5 , 8 , 13 , 21 , 34 and 55 . two of the slips are drawn at random from the box without replacement . what is the probability that the sum of the numbers on the two slips is equal to one of the numbers left in the box ? | {
"A": "7 / 72",
"B": "1 / 6",
"C": "5 / 28",
"D": "15 / 36",
"E": "21 / 36"
} | divide(subtract(8, 3), divide(multiply(8, subtract(8, 1)), const_2)) | subtract(n4,n2)|subtract(n4,n1)|multiply(n4,#1)|divide(#2,const_2)|divide(#0,#3) | probability = no : of desired outcomes / total no : of outcomes . you are picking two slips out of 8 slips . so total no : of outcomes = 8 c 2 = 28 desired outcome : sum of the numbers on the two slips is equal to one of the numbers left in the box . how many such outcomes are there ? if you look at the numbers closely , you will see that the following pair of numbers will give you the desired outcome . ( 3,5 ) ( 5,8 ) ( 8,13 ) ( 13,21 ) ( 21,34 ) . there are 7 such pairs . if the two numbers which i pick is from any of these 5 pairs , then i get my desired outcome . so no : of desired outcomes = 5 probability = 5 / 28 answer : c | general |
math_qa__zTJ1G9gAsCVGxGz2 | The operation is defined for all integers a and b by the equation ab = (a - 1)(b - 1). If x9 = 160, what is the value of x ? Choose the correct option:
A) 18
B) 15
C) 17
D) 19
E) 21 | <gadget id="calculator">9 - 1</gadget>
<output>8</output>
<gadget id="calculator">160 / 8</gadget>
<output>20</output>
<gadget id="calculator">20 + 1</gadget>
<output>21</output>
<result>E</result> | E | 21 | The operation is defined for all integers a and b by the equation ab = (a - 1)(b - 1). If x9 = 160, what is the value of x ? | {
"A": "18",
"B": "15",
"C": "17",
"D": "19",
"E": "21"
} | add(divide(160, subtract(9, 1)), 1) | subtract(n2,n0)|divide(n3,#0)|add(n0,#1)| | "ab = ( a - 1 ) ( b - 1 ) x 9 = ( x - 1 ) ( 9 - 1 ) = 160 - - > x - 1 = 20 - - > x = 21 answer : e" | general |
math_qa__MB8PwtiGd5707s3R | John began driving from home on a trip averaging 30 miles per hour. How many miles per hour must Carla drive on average to catch up to him in exactly 3 hours if she leaves 30 minutes after John? Pick
A) 35 B) 55 C) 39 D) 40 E) 60 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">3 + (1/2)</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">30 * (7/2)</gadget>
<output>105</output>
<gadget id="calculator">105 / 3</gadget>
<output>35</output>
<result>A</result> | A | 35 | John began driving from home on a trip averaging 30 miles per hour. How many miles per hour must Carla drive on average to catch up to him in exactly 3 hours if she leaves 30 minutes after John? | {
"A": "35",
"B": "55",
"C": "39",
"D": "40",
"E": "60"
} | divide(multiply(30, add(3, divide(const_1, const_2))), 3) | divide(const_1,const_2)|add(n1,#0)|multiply(n0,#1)|divide(#2,n1) | carla starts 30 minutes later and it takes 3 hr for carla to meet john so john total time travelled = 3 hr + 30 minutes john distance = 30 * ( 3 1 / 2 ) = 105 so carla need to travle 105 to meet john in 3 hrs speed of carla = 105 / 3 = 35 miles per hour answer is a | physics |
math_qa__rYgZiqjm9N7GJzhE | Two brother X and Y appeared for an exam. Let A be the event that X is selected and B is the event that Y
is selected.
The probability of A
is 17 and that of B is 29. Find the probability that both of them are selected. Choose the correct option.
A) 2 / 63 B) 2 / 67 C) 2 D) 3 / 31 E) 4 | <gadget id="calculator">17 % 10</gadget>
<output>7</output>
<gadget id="calculator">1 / 7</gadget>
<output>1/7 = around 0.142857</output>
<gadget id="calculator">29 % 10</gadget>
<output>9</output>
<gadget id="calculator">2 / 9</gadget>
<output>2/9 = around 0.222222</output>
<gadget id="calculator">(1/7) * (2/9)</gadget>
<output>2/63 = around 0.031746</output>
<result>A</result> | A | 0.031746 | Two brother X and Y appeared for an exam. Let A be the event that X is selected and B is the event that Y
is selected.
The probability of A
is 17 and that of B is 29. Find the probability that both of them are selected. | {
"A": "2 / 63",
"B": "2 / 67",
"C": "2",
"D": "3 / 31",
"E": "4"
} | multiply(divide(const_1, reminder(17, const_10)), divide(const_2, reminder(29, const_10))) | reminder(n0,const_10)|reminder(n1,const_10)|divide(const_1,#0)|divide(const_2,#1)|multiply(#2,#3) | given , a be the event that x is selected and b is the event that y is selected . p ( a ) = 17 , p ( b ) = 29 . let c be the event that both are selected . p ( c ) = p ( a ) × p ( b ) as a and b are independent events : = ( 17 ) × ( 29 ) = 2 / 63 answer is a | other |
math_qa__fCrx4QkhfOTydI1w | Sandy is younger than Molly by 12 years. If the ratio of their ages is 7:9, how old is Sandy? Pick.
A) 42 B) 49 C) 56 D) 63 E) 70 | <gadget id="calculator">9 - 7</gadget>
<output>2</output>
<gadget id="calculator">7 / 2</gadget>
<output>7/2 = around 3.5</output>
<gadget id="calculator">(7/2) * 12</gadget>
<output>42</output>
<result>A</result> | A | 42 | Sandy is younger than Molly by 12 years. If the ratio of their ages is 7:9, how old is Sandy? | {
"A": "42",
"B": "49",
"C": "56",
"D": "63",
"E": "70"
} | multiply(divide(7, subtract(9, 7)), 12) | subtract(n2,n1)|divide(n1,#0)|multiply(n0,#1) | let sandy ' s age be 7 x and let molly ' s age be 9 x . 9 x - 7 x = 12 x = 6 sandy is 42 years old . the answer is a . | other |
math_qa__pyMOh9d0CzEi1WsX | The sum of the first 50 positive even integers is 2550. What is the sum of the even integers from 302 to 400 inclusive? Choose the correct choice from the following answers
A) 11,550 B) 14,550 C) 17,550 D) 20,550 E) 23,550 | <gadget id="calculator">400 + 302</gadget>
<output>702</output>
<gadget id="calculator">702 / 2</gadget>
<output>351</output>
<gadget id="calculator">400 - 302</gadget>
<output>98</output>
<gadget id="calculator">98 / 2</gadget>
<output>49</output>
<gadget id="calculator">49 + 1</gadget>
<output>50</output>
<gadget id="calculator">351 * 50</gadget>
<output>17_550</output>
<result>C</result> | C | 17,550 | The sum of the first 50 positive even integers is 2550. What is the sum of the even integers from 302 to 400 inclusive? | {
"A": "11,550",
"B": "14,550",
"C": "17,550",
"D": "20,550",
"E": "23,550"
} | multiply(divide(add(400, 302), const_2), add(divide(subtract(400, 302), const_2), const_1)) | add(n2,n3)|subtract(n3,n2)|divide(#1,const_2)|divide(#0,const_2)|add(#2,const_1)|multiply(#4,#3)| | "2 + 4 + 6 + 8 + . . . + 100 = 2550 302 + 304 + . . . + 400 = 50 ( 300 ) + ( 2 + 4 + . . . + 100 ) = 15,000 + 2550 = 17,550 the answer is c ." | general |
math_qa__Dlra1pivK7NlD4Tc | Walking at the rate of 8 kmph a man cover certain distance in 3 hrs.. Running at a speed of 16 kmph the man will cover the same distance in. Select the correct option:
A) 1.2 hr B) 2.5 hr C) 1.5 hr D) 48 min E) 58 min | <gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">24 / 16</gadget>
<output>3/2 = around 1.5</output>
<result>C</result> | C | 1.5 | Walking at the rate of 8 kmph a man cover certain distance in 3 hrs.. Running at a speed of 16 kmph the man will cover the same distance in. | {
"A": "1.2 hr",
"B": "2.5 hr",
"C": "1.5 hr",
"D": "48 min",
"E": "58 min"
} | divide(multiply(8, 3), 16) | multiply(n0,n1)|divide(#0,n2) | distance = speed * time 8 * 3 = 24 km new speed = 16 kmph therefore time = d / s = 24 / 16 = 1.5 hr . answer : c . | physics |
math_qa__8JgiIYApTC7ULQG7 | A man can row 3.3 km/hr in still water. It takes him twice as long to row upstream as to row downstream. What is the rate of the current ?
Choose the correct option: A) 1.9 B) 1.7 C) 1.2 D) 1.5 E) 1.1 | <gadget id="calculator">3.3 * 2</gadget>
<output>6.6</output>
<gadget id="calculator">6.6 - 3.3</gadget>
<output>3.3</output>
<gadget id="calculator">3.3 / 3</gadget>
<output>1.1</output>
<result>E</result> | E | 1.1 | A man can row 3.3 km/hr in still water. It takes him twice as long to row upstream as to row downstream. What is the rate of the current ? | {
"A": "1.9",
"B": "1.7",
"C": "1.2",
"D": "1.5",
"E": "1.1"
} | divide(subtract(multiply(3.3, const_2), 3.3), const_3) | multiply(n0,const_2)|subtract(#0,n0)|divide(#1,const_3) | speed of boat in still water ( b ) = 3.3 km / hr . speed of boat with stream ( down stream ) , d = b + u speed of boat against stream ( up stream ) , u = b – u it is given upstream time is twice to that of down stream . ⇒ downstream speed is twice to that of upstream . so b + u = 2 ( b – u ) ⇒ u = b / 3 = 1.1 km / hr . answer : e | general |
math_qa__0xNDBVqrNo7mKSkn | Two different primes may be said torhymearound an integer if they are the same distance from the integer on the number line. For instance, 3 and 7 rhyme around 5. What integer Q between 1 and 20, inclusive, has the greatest number of distinct rhyming primes around it? Choose the correct choice from the following choices:
A) q = 12
B) q = 15
C) q = 17
D) q . 18
E) q = 20 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 * 3</gadget>
<output>18</output>
<result>D</result> | D | 18 | Two different primes may be said torhymearound an integer if they are the same distance from the integer on the number line. For instance, 3 and 7 rhyme around 5. What integer Q between 1 and 20, inclusive, has the greatest number of distinct rhyming primes around it? | {
"A": "q = 12",
"B": "q = 15",
"C": "q = 17",
"D": "q . 18",
"E": "q = 20"
} | multiply(multiply(3, const_2), 3) | multiply(const_2,n0)|multiply(n0,#0)| | "since we are concerned with integers between 1 and 20 , write down the primes till 40 . 2 , 3 , 5 , 7 , 11 , 13 , 17 , 19 , 23 , 29 , 31 , 37 ( you should be very comfortable with the first few primes . . . ) 2 , 3 , 5 , 7 , 11,12 , 13 , 17 , 19 , 23 , 29 , 31 , 37 - three pairs ( 11,13 ) , ( 7,17 ) , ( 5 , 19 ) 2 , 3 , 5 , 7 , 11 , 13 , 15,17 , 19 , 23 , 29 , 31 , 37 - three pairs ( 13 , 17 ) , ( 11 , 19 ) , ( 7 , 23 ) 2 , 3 , 5 , 7 , 11 , 13,17 , 19 , 23 , 29 , 31 , 37 - three pairs ( 11 , 23 ) , ( 5 , 29 ) , ( 3 , 31 ) 2 , 3 , 5 , 7 , 11 , 13 , 17 , 18,19 , 23 , 29 , 31 , 37 - four pairs ( 17 , 19 ) , ( 13 , 23 ) , ( 7 , 29 ) , ( 5 , 31 ) 2 , 3 , 5 , 7 , 11 , 13 , 17 , 19 , 20,23 , 29 , 31 , 37 - definitely can not be more than 4 since there are only 4 primes more than 20 . so must be less than 4 pairs . ignore . answer ( d ) ." | physics |
math_qa__Hw1PV4gZn8ODuWDZ | If three numbers in the ratio 3 : 2: 5 be such that the sum of their squares is 1862, the middle number will be Choose the correct choice from the following choices:
A) 10
B) 14
C) 18
D) 22
E) 24 | <gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">9 + 4</gadget>
<output>13</output>
<gadget id="calculator">5 * 5</gadget>
<output>25</output>
<gadget id="calculator">13 + 25</gadget>
<output>38</output>
<gadget id="calculator">1_862 / 38</gadget>
<output>49</output>
<gadget id="calculator">49 ** (1/2)</gadget>
<output>7</output>
<gadget id="calculator">7 * 2</gadget>
<output>14</output>
<result>B</result> | B | 14 | If three numbers in the ratio 3 : 2: 5 be such that the sum of their squares is 1862, the middle number will be | {
"A": "10",
"B": "14",
"C": "18",
"D": "22",
"E": "24"
} | multiply(sqrt(divide(1862, add(add(multiply(3, 3), multiply(2, 2)), multiply(5, 5)))), 2) | multiply(n0,n0)|multiply(n1,n1)|multiply(n2,n2)|add(#0,#1)|add(#3,#2)|divide(n3,#4)|sqrt(#5)|multiply(n1,#6) | explanation : let the numbers be 3 x , 2 x and 5 x . then , 9 x + 4 x + 25 x = 1862 ⇒ 38 x = 1862 ⇒ x = 49 ⇒ x = 7 . middle number = 2 x = 14 option b | other |
math_qa__D0l218o8D35pHRrb | Factory X's bulbs work for over 5000 hours in 79% of cases, whereas factory Y's bulbs work for over 5000 hours in 85% of cases. It is known that factory X supplies 80% of the total bulbs available. What is the chance that a purchased bulb will work for longer than 5000 hours? Choose the correct choice from the following answers:
A) 80.2 % B) 88 % C) 87.4 % D) 85 % E) 83.9 % | <gadget id="calculator">79 + 85</gadget>
<output>164</output>
<gadget id="calculator">164 / 2</gadget>
<output>82</output>
<result>A</result> | A | 80.2 | Factory X's bulbs work for over 5000 hours in 79% of cases, whereas factory Y's bulbs work for over 5000 hours in 85% of cases. It is known that factory X supplies 80% of the total bulbs available. What is the chance that a purchased bulb will work for longer than 5000 hours? | {
"A": "80.2 %",
"B": "88 %",
"C": "87.4 %",
"D": "85 %",
"E": "83.9 %"
} | divide(add(79, 85), const_2) | add(n1,n3)|divide(#0,const_2) | for x , 80 % of 79 % will work . for y , 20 % of 85 % will work . * 20 % is the rest of the bulb supply in the market . so , the probability that a purchased bulb will work is : 0.80 ( 0.79 ) = . 632 0.20 ( 0.85 ) = 0.17 the combined probability then is 63.2 + 17 = 80.2 % ans a | physics |
math_qa__f2qRkrvf7ul30wbI | The units digit of (10)^(87) + (5)^(46) is: Choose the correct choice from the following answers:
A) 2 B) 4 C) 6 D) 8 E) 0 | <gadget id="calculator">46 % 4</gadget>
<output>2</output>
<gadget id="calculator">2 * 5</gadget>
<output>10</output>
<gadget id="calculator">10 % 10</gadget>
<output>0</output>
<gadget id="calculator">0 + 0</gadget>
<output>0</output>
<result>E</result> | E | 0 | The units digit of (10)^(87) + (5)^(46) is: | {
"A": "2",
"B": "4",
"C": "6",
"D": "8",
"E": "0"
} | add(reminder(multiply(reminder(46, const_4), 5), const_10), reminder(10, const_10)) | reminder(n3,const_4)|reminder(n0,const_10)|multiply(n2,#0)|reminder(#2,const_10)|add(#3,#1)| | "any power of anything ending in 5 always has a units digit of 5 . so the first term has a units digit of 5 . done . the second term anything power to 10 unit digit will be zero then 5 + 0 = 5 , e" | general |
math_qa__FTsuH0JjOURDOP6D | Double of Quarter of 4 percent written as a decimal is : Options
A) 0.003
B) 0.0005
C) 0.25
D) 0.02
E) none of these | <gadget id="calculator">4 / 100</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(1/25) / 4</gadget>
<output>1/100 = around 0.01</output>
<gadget id="calculator">(1/100) * 2</gadget>
<output>1/50 = around 0.02</output>
<result>D</result> | D | 0.02 | Double of Quarter of 4 percent written as a decimal is : | {
"A": "0.003",
"B": "0.0005",
"C": "0.25",
"D": "0.02",
"E": "none of these"
} | multiply(divide(divide(4, const_100), const_4), const_2) | divide(n0,const_100)|divide(#0,const_4)|multiply(#1,const_2) | explanation : solution : ( 2 ) * ( 1 / 4 ) * 4 % = 2 * ( 1 / 4 * 1 / 100 ) = 0.02 . answer : d | gain |
math_qa__i2SuvYGsdAuqm2cr | A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 1100 m long? Choose one:
A) 200 sec
B) 230 sec
C) 167 sec
D) 197 sec
E) 179 sec | <gadget id="calculator">1_200 + 1_100</gadget>
<output>2_300</output>
<gadget id="calculator">1_200 / 120</gadget>
<output>10</output>
<gadget id="calculator">2_300 / 10</gadget>
<output>230</output>
<result>B</result> | B | 230 | A 1200 m long train crosses a tree in 120 sec, how much time will I take to pass a platform 1100 m long? | {
"A": "200 sec",
"B": "230 sec",
"C": "167 sec",
"D": "197 sec",
"E": "179 sec"
} | divide(add(1200, 1100), divide(1200, 120)) | add(n0,n2)|divide(n0,n1)|divide(#0,#1)| | "l = s * t s = 1200 / 120 s = 10 m / sec . total length ( d ) = 2300 m t = d / s t = 2300 / 10 t = 230 sec answer : b" | physics |
math_qa__lOlc6nRRpCGoB0fM | A, B and C rents a pasture for Rs.841. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should B pay? Choose the correct choice:
A) 270
B) 279
C) 348
D) 371
E) 372 | <gadget id="calculator">12 * 8</gadget>
<output>96</output>
<gadget id="calculator">16 * 9</gadget>
<output>144</output>
<gadget id="calculator">96 + 144</gadget>
<output>240</output>
<gadget id="calculator">18 * 6</gadget>
<output>108</output>
<gadget id="calculator">240 + 108</gadget>
<output>348</output>
<gadget id="calculator">841 / 348</gadget>
<output>29/12 = around 2.416667</output>
<gadget id="calculator">(29/12) * 144</gadget>
<output>348</output>
<result>C</result> | C | 348 | A, B and C rents a pasture for Rs.841. A put in 12 horses for 8 months, B 16 horses for 9 months and 18 horses for 6 months. How much should B pay? | {
"A": "270",
"B": "279",
"C": "348",
"D": "371",
"E": "372"
} | multiply(divide(841, add(add(multiply(12, 8), multiply(16, 9)), multiply(18, 6))), multiply(16, 9)) | multiply(n1,n2)|multiply(n3,n4)|multiply(n5,n6)|add(#0,#1)|add(#3,#2)|divide(n0,#4)|multiply(#5,#1)| | "12 * 8 : 16 * 9 = 18 * 6 8 : 12 : 9 12 / 29 * 841 = 348 answer : c" | general |
math_qa__1rFYE2cB4VUT0rZm | The curved surface area of a cylindrical pillar is 264 sq.m and its volume is 924 cub.m. Find the ratio of its diameter to its height
Answers:
A) 7 : 9 B) 7 : 3 C) 7 : 7 D) 7 : 6 E) 7 : 1 | <gadget id="calculator">264 / pi</gadget>
<output>264/pi = around 84.03381</output>
<gadget id="calculator">(264/pi) / 2</gadget>
<output>132/pi = around 42.016905</output>
<gadget id="calculator">924 / (132/pi)</gadget>
<output>7*pi = around 21.991149</output>
<gadget id="calculator">(7*pi) / pi</gadget>
<output>7</output>
<gadget id="calculator">7 * 2</gadget>
<output>14</output>
<gadget id="calculator">(132/pi) / 7</gadget>
<output>132/(7*pi) = around 6.002415</output>
<gadget id="calculator">14 / (132/(7*pi))</gadget>
<output>49*pi/66 = around 2.332395</output>
<result>B</result> | B | 2.333333 | The curved surface area of a cylindrical pillar is 264 sq.m and its volume is 924 cub.m. Find the ratio of its diameter to its height | {
"A": "7 : 9",
"B": "7 : 3",
"C": "7 : 7",
"D": "7 : 6",
"E": "7 : 1"
} | divide(multiply(divide(divide(924, divide(divide(264, const_pi), const_2)), const_pi), const_2), divide(divide(divide(264, const_pi), const_2), divide(divide(924, divide(divide(264, const_pi), const_2)), const_pi))) | divide(n0,const_pi)|divide(#0,const_2)|divide(n1,#1)|divide(#2,const_pi)|divide(#1,#3)|multiply(#3,const_2)|divide(#5,#4) | explanation : { \ color { black } \ frac { \ prod r ^ { 2 } h } { 2 \ prod rh } = \ frac { 924 } { 264 } } { \ color { black } \ rightarrow r = \ frac { 924 } { 264 } \ times 2 = 7 m } { \ color { black } and \ ; \ ; 2 \ prod rh = 264 \ rightarrow h = ( 264 \ times \ frac { 7 } { 22 } \ times \ frac { 1 } { 2 } \ times \ frac { 1 } { 7 } ) = 6 m } { \ color { black } \ therefore } required rato = { \ color { black } \ frac { 2 r } { h } } = { \ color { black } \ frac { 14 } { 6 } = 7 : 3 } answer : b ) 7 : 3 | geometry |
math_qa__puijriee27AiJ8K6 | A can run 128 metre in 28 seconds and B in 32 seconds. By what distance A beat B?
Choose the most appropriate option: A) 38 metre B) 28 metre C) 23 metre D) 16 metre E) 28 metre | <gadget id="calculator">128 / 32</gadget>
<output>4</output>
<gadget id="calculator">4 * 28</gadget>
<output>112</output>
<gadget id="calculator">128 - 112</gadget>
<output>16</output>
<result>D</result> | D | 16 | A can run 128 metre in 28 seconds and B in 32 seconds. By what distance A beat B? | {
"A": "38 metre",
"B": "28 metre",
"C": "23 metre",
"D": "16 metre",
"E": "28 metre"
} | subtract(128, multiply(divide(128, 32), 28)) | divide(n0,n2)|multiply(n1,#0)|subtract(n0,#1) | clearly , a beats b by 4 seconds now find out how much b will run in these 4 seconds speed of b = distance / time taken by b = 128 / 32 = 4 m / s distance covered by b in 4 seconds = speed ã — time = 4 ã — 4 = 16 metre i . e . , a beat b by 16 metre answer is d | physics |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.